contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
678 | A | Johny Likes Numbers | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*. | The only line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=109). | Print the smallest integer *x*<=><=*n*, so it is divisible by the number *k*. | [
"5 3\n",
"25 13\n",
"26 13\n"
] | [
"6\n",
"26\n",
"39\n"
] | none | 0 | [
{
"input": "5 3",
"output": "6"
},
{
"input": "25 13",
"output": "26"
},
{
"input": "26 13",
"output": "39"
},
{
"input": "1 1",
"output": "2"
},
{
"input": "8 8",
"output": "16"
},
{
"input": "14 15",
"output": "15"
},
{
"input": "197 894"... | 1,500,005,385 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 62 | 5,529,600 | import math
string = input()
numbers = string.split()
a, b = int(numbers[0]), int(numbers[1])
print((math.floor(a / b) + 1) * b) | Title: Johny Likes Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*.
Input Specification:
The only line contains two integers *n* and *... | ```python
import math
string = input()
numbers = string.split()
a, b = int(numbers[0]), int(numbers[1])
print((math.floor(a / b) + 1) * b)
``` | 3 | |
344 | A | Magnets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets are put together at a close distance, then the like poles will repel each other and the oppo... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100000) — the number of magnets. Then *n* lines follow. The *i*-th line (1<=≤<=*i*<=≤<=*n*) contains either characters "01", if Mike put the *i*-th magnet in the "plus-minus" position, or characters "10", if Mike put the magnet in the "minus-plus" posit... | On the single line of the output print the number of groups of magnets. | [
"6\n10\n10\n10\n01\n10\n10\n",
"4\n01\n01\n10\n10\n"
] | [
"3\n",
"2\n"
] | The first testcase corresponds to the figure. The testcase has three groups consisting of three, one and two magnets.
The second testcase has two groups, each consisting of two magnets. | 500 | [
{
"input": "6\n10\n10\n10\n01\n10\n10",
"output": "3"
},
{
"input": "4\n01\n01\n10\n10",
"output": "2"
},
{
"input": "1\n10",
"output": "1"
},
{
"input": "2\n01\n10",
"output": "2"
},
{
"input": "2\n10\n10",
"output": "1"
},
{
"input": "3\n10\n01\n10",... | 1,694,571,475 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | n= int(input())
mag_seq = []
for i in range(n):
mag_seq.append(input())
point = 0
for j in range(n - 1):
if mag_seq[j] == mag_seq[j + 1]:
point += 1
print(point + 1) | Title: Magnets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets... | ```python
n= int(input())
mag_seq = []
for i in range(n):
mag_seq.append(input())
point = 0
for j in range(n - 1):
if mag_seq[j] == mag_seq[j + 1]:
point += 1
print(point + 1)
``` | 0 | |
749 | A | Bachgold Problem | PROGRAMMING | 800 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer *k* is called prime if it is greater than 1 and has exactly two positive integer ... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000). | The first line of the output contains a single integer *k* — maximum possible number of primes in representation.
The second line should contain *k* primes with their sum equal to *n*. You can print them in any order. If there are several optimal solution, print any of them. | [
"5\n",
"6\n"
] | [
"2\n2 3\n",
"3\n2 2 2\n"
] | none | 500 | [
{
"input": "5",
"output": "2\n2 3"
},
{
"input": "6",
"output": "3\n2 2 2"
},
{
"input": "2",
"output": "1\n2"
},
{
"input": "3",
"output": "1\n3"
},
{
"input": "99999",
"output": "49999\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,675,780,687 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<bits/stdc++.h>
using namespace std;
int main()
{
int k;
cin>>k;
cout<<k/2<<endl;
if(k%2==0)
{
for(int i=0;i<(k/2);i++)
{
cout<<"2"<<" ";
}
}
else
{
for(int i=0;i<((k/2)-1);i++){
cout<<"2"<<" ";
... | Title: Bachgold Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
... | ```python
#include<bits/stdc++.h>
using namespace std;
int main()
{
int k;
cin>>k;
cout<<k/2<<endl;
if(k%2==0)
{
for(int i=0;i<(k/2);i++)
{
cout<<"2"<<" ";
}
}
else
{
for(int i=0;i<((k/2)-1);i++){
cout<<"2"<<... | -1 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,611,783,328 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 122 | 307,200 | n = int(input())
lstx = []
lsty = []
lstz = []
for i in range(n) :
x, y, z = map(int, input().strip().split())
lstx.append(x)
lsty.append(y)
lstz.append(z)
u = eval('+'.join(lstx))
v = eval('+'.join(lsty))
w = eval('+'.join(lstz))
if u == 0 and v == 0 and w == 0 :
print("YES")
else :
print("NO... | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. S... | ```python
n = int(input())
lstx = []
lsty = []
lstz = []
for i in range(n) :
x, y, z = map(int, input().strip().split())
lstx.append(x)
lsty.append(y)
lstz.append(z)
u = eval('+'.join(lstx))
v = eval('+'.join(lsty))
w = eval('+'.join(lstz))
if u == 0 and v == 0 and w == 0 :
print("YES")
else :
... | -1 |
967 | A | Mind the Gap | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | These days Arkady works as an air traffic controller at a large airport. He controls a runway which is usually used for landings only. Thus, he has a schedule of planes that are landing in the nearest future, each landing lasts $1$ minute.
He was asked to insert one takeoff in the schedule. The takeoff takes $1$ minut... | The first line of input contains two integers $n$ and $s$ ($1 \le n \le 100$, $1 \le s \le 60$) — the number of landings on the schedule and the minimum allowed time (in minutes) between a landing and a takeoff.
Each of next $n$ lines contains two integers $h$ and $m$ ($0 \le h \le 23$, $0 \le m \le 59$) — the time, i... | Print two integers $h$ and $m$ — the hour and the minute from the current moment of the earliest time Arkady can insert the takeoff. | [
"6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40\n",
"16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59\n",
"3 17\n0 30\n1 0\n12 0\n"
] | [
"6 1\n",
"24 50\n",
"0 0\n"
] | In the first example note that there is not enough time between 1:20 and 3:21, because each landing and the takeoff take one minute.
In the second example there is no gaps in the schedule, so Arkady can only add takeoff after all landings. Note that it is possible that one should wait more than $24$ hours to insert th... | 500 | [
{
"input": "6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40",
"output": "6 1"
},
{
"input": "16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59",
"output": "24 50"
},
{
"input": "3 17\n0 30\n1 0\n12 0",
"output": "0 0"
},
{
... | 1,525,348,542 | 642 | PyPy 3 | OK | TESTS | 34 | 124 | 21,401,600 | n,s=map(int,input().split())
v=[tuple(map(int,input().split())) for _ in range(n)]
v.sort()
cur=0
for a,b in v:
t=a*60+b
if t>=cur+1+s: print(cur//60,cur%60);break
cur=t+1+s
if cur>v[-1][0]*60+v[-1][1]: print(cur//60,cur%60) | Title: Mind the Gap
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
These days Arkady works as an air traffic controller at a large airport. He controls a runway which is usually used for landings only. Thus, he has a schedule of planes that are landing in the nearest future, each landing ... | ```python
n,s=map(int,input().split())
v=[tuple(map(int,input().split())) for _ in range(n)]
v.sort()
cur=0
for a,b in v:
t=a*60+b
if t>=cur+1+s: print(cur//60,cur%60);break
cur=t+1+s
if cur>v[-1][0]*60+v[-1][1]: print(cur//60,cur%60)
``` | 3 | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,649,540,492 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | x=input()
y=input()
l1=[]
l2=[]
for i in x:
l1.append(i)
for j in y:
l2.append(j)
l1.reverse()
if l1==l2:
print("Yes")
else:
print('No') | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
x=input()
y=input()
l1=[]
l2=[]
for i in x:
l1.append(i)
for j in y:
l2.append(j)
l1.reverse()
if l1==l2:
print("Yes")
else:
print('No')
``` | 0 |
939 | A | Love Triangle | PROGRAMMING | 800 | [
"graphs"
] | null | null | As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with number *f**i*, where 1<=≤<=*f**i*<=≤<=*n* and *f**i*<=≠<=*i*.
We call a love triangle a situation ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=5000) — the number of planes.
The second line contains *n* integers *f*1,<=*f*2,<=...,<=*f**n* (1<=≤<=*f**i*<=≤<=*n*, *f**i*<=≠<=*i*), meaning that the *i*-th plane likes the *f**i*-th. | Output «YES» if there is a love triangle consisting of planes on Earth. Otherwise, output «NO».
You can output any letter in lower case or in upper case. | [
"5\n2 4 5 1 3\n",
"5\n5 5 5 5 1\n"
] | [
"YES\n",
"NO\n"
] | In first example plane 2 likes plane 4, plane 4 likes plane 1, plane 1 likes plane 2 and that is a love triangle.
In second example there are no love triangles. | 500 | [
{
"input": "5\n2 4 5 1 3",
"output": "YES"
},
{
"input": "5\n5 5 5 5 1",
"output": "NO"
},
{
"input": "3\n3 1 2",
"output": "YES"
},
{
"input": "10\n4 10 9 5 3 1 5 10 6 4",
"output": "NO"
},
{
"input": "10\n5 5 4 9 10 9 9 5 3 1",
"output": "YES"
},
{
"... | 1,657,857,135 | 735 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 |
n = int( input() )
p = list( map(int, input().split()) ) # Convierte texto con espacios a lista de enteros
def nxt(p, i):
n = p[i]
if n == i:
return -1
return n
for i in range(n):
fin = nxt(p, nxt(p, nxt(p, i)))
if fin == i:
print("YES")
break
else:
p... | Title: Love Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with ... | ```python
n = int( input() )
p = list( map(int, input().split()) ) # Convierte texto con espacios a lista de enteros
def nxt(p, i):
n = p[i]
if n == i:
return -1
return n
for i in range(n):
fin = nxt(p, nxt(p, nxt(p, i)))
if fin == i:
print("YES")
break
el... | -1 | |
235 | A | LCM Challenge | PROGRAMMING | 1,600 | [
"number theory"
] | null | null | Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive integers (they don't have to be distinct) which are not greater than *n*. Can you help me to find ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the *n* mentioned in the statement. | Print a single integer — the maximum possible LCM of three not necessarily distinct positive integers that are not greater than *n*. | [
"9\n",
"7\n"
] | [
"504\n",
"210\n"
] | The least common multiple of some positive integers is the least positive integer which is multiple for each of them.
The result may become very large, 32-bit integer won't be enough. So using 64-bit integers is recommended.
For the last example, we can chose numbers 7, 6, 5 and the LCM of them is 7·6·5 = 210. It is ... | 500 | [
{
"input": "9",
"output": "504"
},
{
"input": "7",
"output": "210"
},
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "60"
},
{
"input": "33",
"output": "32736"
},
{
"input": "21",
"output": ... | 1,695,420,753 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 31 | 124 | 0 | from math import lcm
n = int(input())
if n<=2:
print(n)
else:
print(lcm(n,n-1,n-2))
| Title: LCM Challenge
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive... | ```python
from math import lcm
n = int(input())
if n<=2:
print(n)
else:
print(lcm(n,n-1,n-2))
``` | 0 | |
803 | C | Maximal GCD | PROGRAMMING | 1,900 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | You are given positive integer number *n*. You should create such strictly increasing sequence of *k* positive numbers *a*1,<=*a*2,<=...,<=*a**k*, that their sum is equal to *n* and greatest common divisor is maximal.
Greatest common divisor of sequence is maximum of such numbers that every element of sequence is divi... | The first line consists of two numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1010). | If the answer exists then output *k* numbers — resulting sequence. Otherwise output -1. If there are multiple answers, print any of them. | [
"6 3\n",
"8 2\n",
"5 3\n"
] | [
"1 2 3\n",
"2 6\n",
"-1\n"
] | none | 0 | [
{
"input": "6 3",
"output": "1 2 3"
},
{
"input": "8 2",
"output": "2 6"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "2 1",
"output": "2"
},
{
"input": "2 10000000... | 1,498,840,442 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 20 | 1,000 | 5,529,600 | n,k=list(map(int,input().strip().split(' ')))
L=n//k
if k*(k+1)//2>n:
print(-1)
else:
temp=(k*(k+1))//2
L=n//temp
while(n%L!=0):
L-=1
T=(n-((temp)*L))//L
ans=[]
for i in range(1,k+1):
if i!=k:
ans+=[i*L]
else:
ans+=[(i+T)*L]
... | Title: Maximal GCD
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given positive integer number *n*. You should create such strictly increasing sequence of *k* positive numbers *a*1,<=*a*2,<=...,<=*a**k*, that their sum is equal to *n* and greatest common divisor is maximal.
Grea... | ```python
n,k=list(map(int,input().strip().split(' ')))
L=n//k
if k*(k+1)//2>n:
print(-1)
else:
temp=(k*(k+1))//2
L=n//temp
while(n%L!=0):
L-=1
T=(n-((temp)*L))//L
ans=[]
for i in range(1,k+1):
if i!=k:
ans+=[i*L]
else:
ans+=[(i+... | 0 | |
287 | A | IQ Test | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In the city of Ultima Thule job applicants are often offered an IQ test.
The test is as follows: the person gets a piece of squared paper with a 4<=×<=4 square painted on it. Some of the square's cells are painted black and others are painted white. Your task is to repaint at most one cell the other color so that the... | Four lines contain four characters each: the *j*-th character of the *i*-th line equals "." if the cell in the *i*-th row and the *j*-th column of the square is painted white, and "#", if the cell is black. | Print "YES" (without the quotes), if the test can be passed and "NO" (without the quotes) otherwise. | [
"####\n.#..\n####\n....\n",
"####\n....\n####\n....\n"
] | [
"YES\n",
"NO\n"
] | In the first test sample it is enough to repaint the first cell in the second row. After such repainting the required 2 × 2 square is on the intersection of the 1-st and 2-nd row with the 1-st and 2-nd column. | 500 | [
{
"input": "###.\n...#\n###.\n...#",
"output": "NO"
},
{
"input": ".##.\n#..#\n.##.\n#..#",
"output": "NO"
},
{
"input": ".#.#\n#.#.\n.#.#\n#.#.",
"output": "NO"
},
{
"input": "##..\n..##\n##..\n..##",
"output": "NO"
},
{
"input": "#.#.\n#.#.\n.#.#\n.#.#",
"ou... | 1,587,036,627 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 16 | 155 | 0 | l=[]
for i in range(4):
l.append(input())
b=1
for i in range(2):
k=0
for j in range(2):
if l[i][j]==l[i+1][j]:
k+=1
if l[i][j]==l[i][j+1]:
k+=1
if l[i][j]==l[i+1][j+1]:
k+=1
if k>2:
print("YES")
b=0
b... | Title: IQ Test
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the city of Ultima Thule job applicants are often offered an IQ test.
The test is as follows: the person gets a piece of squared paper with a 4<=×<=4 square painted on it. Some of the square's cells are painted black and o... | ```python
l=[]
for i in range(4):
l.append(input())
b=1
for i in range(2):
k=0
for j in range(2):
if l[i][j]==l[i+1][j]:
k+=1
if l[i][j]==l[i][j+1]:
k+=1
if l[i][j]==l[i+1][j+1]:
k+=1
if k>2:
print("YES")
b=0
... | 0 | |
900 | B | Position in Fraction | PROGRAMMING | 1,300 | [
"math",
"number theory"
] | null | null | You have a fraction . You need to find the first occurrence of digit *c* into decimal notation of the fraction after decimal point. | The first contains three single positive integers *a*, *b*, *c* (1<=≤<=*a*<=<<=*b*<=≤<=105, 0<=≤<=*c*<=≤<=9). | Print position of the first occurrence of digit *c* into the fraction. Positions are numbered from 1 after decimal point. It there is no such position, print -1. | [
"1 2 0\n",
"2 3 7\n"
] | [
"2",
"-1"
] | The fraction in the first example has the following decimal notation: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/896357459a466614a0542f34c9cfb0cef1afc9ed.png" style="max-width: 100.0%;max-height: 100.0%;"/>. The first zero stands on second position.
The fraction in the second example ... | 1,000 | [
{
"input": "1 2 0",
"output": "2"
},
{
"input": "2 3 7",
"output": "-1"
},
{
"input": "1 100000 1",
"output": "5"
},
{
"input": "1 7 7",
"output": "6"
},
{
"input": "99999 100000 8",
"output": "-1"
},
{
"input": "44102 73848 2",
"output": "132"
}... | 1,634,453,086 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | a,b,c=map(int,input().split())
t="{:.15f}".format(a/b)
print(t[t.find("."):13].find(str(c)))
| Title: Position in Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a fraction . You need to find the first occurrence of digit *c* into decimal notation of the fraction after decimal point.
Input Specification:
The first contains three single positive integers *a*, *b*, ... | ```python
a,b,c=map(int,input().split())
t="{:.15f}".format(a/b)
print(t[t.find("."):13].find(str(c)))
``` | 0 | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,673,421,634 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | # LUOGU_RID: 99361177
def input_mz_fs():
num = 0
mz,fs=input().split()
if abs(int(fs))<=1000 and len(mz)<=32:
li_mz.append(mz)
li_fs.append(int(fs))
for i in li_fs:
if mz==i:
li_mz.insert(0,mz)
li_mz.remove(i)
if l... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
# LUOGU_RID: 99361177
def input_mz_fs():
num = 0
mz,fs=input().split()
if abs(int(fs))<=1000 and len(mz)<=32:
li_mz.append(mz)
li_fs.append(int(fs))
for i in li_fs:
if mz==i:
li_mz.insert(0,mz)
li_mz.remove(i)
... | 0 |
825 | C | Multi-judge Solving | PROGRAMMING | 1,600 | [
"greedy",
"implementation"
] | null | null | Makes solves problems on Decoforces and lots of other different online judges. Each problem is denoted by its difficulty — a positive integer number. Difficulties are measured the same across all the judges (the problem with difficulty *d* on Decoforces is as hard as the problem with difficulty *d* on any other judge).... | The first line contains two integer numbers *n*, *k* (1<=≤<=*n*<=≤<=103, 1<=≤<=*k*<=≤<=109).
The second line contains *n* space-separated integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print minimum number of problems Makes should solve on other judges in order to solve all chosen problems on Decoforces. | [
"3 3\n2 1 9\n",
"4 20\n10 3 6 3\n"
] | [
"1\n",
"0\n"
] | In the first example Makes at first solves problems 1 and 2. Then in order to solve the problem with difficulty 9, he should solve problem with difficulty no less than 5. The only available are difficulties 5 and 6 on some other judge. Solving any of these will give Makes opportunity to solve problem 3.
In the second ... | 0 | [
{
"input": "3 3\n2 1 9",
"output": "1"
},
{
"input": "4 20\n10 3 6 3",
"output": "0"
},
{
"input": "1 1000000000\n1",
"output": "0"
},
{
"input": "1 1\n3",
"output": "1"
},
{
"input": "50 100\n74 55 33 5 83 24 75 59 30 36 13 4 62 28 96 17 6 35 45 53 33 11 37 93 34... | 1,634,831,430 | 2,130 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 77 | 19,763,200 | n,k = map(int, input().split())
A = list(map(int, input().split()))
q1 = []
q2 = []
for a in A:
if 2*k >= a:
q1.append(-a)
else:
q2.append(-a)
import heapq
heapq.heapify(q1)
heapq.heapify(q2)
cur = k
ans = 0
for i in range(n):
if q1:
a = -heapq.heappop(q1)
cu... | Title: Multi-judge Solving
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Makes solves problems on Decoforces and lots of other different online judges. Each problem is denoted by its difficulty — a positive integer number. Difficulties are measured the same across all the judges (the pro... | ```python
n,k = map(int, input().split())
A = list(map(int, input().split()))
q1 = []
q2 = []
for a in A:
if 2*k >= a:
q1.append(-a)
else:
q2.append(-a)
import heapq
heapq.heapify(q1)
heapq.heapify(q2)
cur = k
ans = 0
for i in range(n):
if q1:
a = -heapq.heappop(q1)
... | 0 | |
950 | B | Intercepted Message | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Hacker Zhorik wants to decipher two secret messages he intercepted yesterday. Yeah message is a sequence of encrypted blocks, each of them consists of several bytes of information.
Zhorik knows that each of the messages is an archive containing one or more files. Zhorik knows how each of these archives was transferred... | The first line contains two integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of blocks in the first and in the second messages.
The second line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=106) — the length of the blocks that form the first message.
The third line contains *m* integers *... | Print the maximum number of files the intercepted array could consist of. | [
"7 6\n2 5 3 1 11 4 4\n7 8 2 4 1 8\n",
"3 3\n1 10 100\n1 100 10\n",
"1 4\n4\n1 1 1 1\n"
] | [
"3\n",
"2\n",
"1\n"
] | In the first example the maximum number of files in the archive is 3. For example, it is possible that in the archive are three files of sizes 2 + 5 = 7, 15 = 3 + 1 + 11 = 8 + 2 + 4 + 1 and 4 + 4 = 8.
In the second example it is possible that the archive contains two files of sizes 1 and 110 = 10 + 100 = 100 + 10. Not... | 1,000 | [
{
"input": "7 6\n2 5 3 1 11 4 4\n7 8 2 4 1 8",
"output": "3"
},
{
"input": "3 3\n1 10 100\n1 100 10",
"output": "2"
},
{
"input": "1 4\n4\n1 1 1 1",
"output": "1"
},
{
"input": "1 1\n1000000\n1000000",
"output": "1"
},
{
"input": "3 5\n2 2 9\n2 1 4 2 4",
"outp... | 1,521,119,885 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 187 | 9,113,600 | n, m = (int(x) for x in input().split())
a = [int(x) for x in input().split()]
b = [int(x) for x in input().split()]
s1=0
s2=0
j=0
cnt=0
for i in range(0,n):
s1+=a[i]
while(s1>s2):
s2+=b[j]
j+=1
if (s1==s2):
cnt+=1
s1=0
s2=0
print(cnt)
| Title: Intercepted Message
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hacker Zhorik wants to decipher two secret messages he intercepted yesterday. Yeah message is a sequence of encrypted blocks, each of them consists of several bytes of information.
Zhorik knows that each of the mes... | ```python
n, m = (int(x) for x in input().split())
a = [int(x) for x in input().split()]
b = [int(x) for x in input().split()]
s1=0
s2=0
j=0
cnt=0
for i in range(0,n):
s1+=a[i]
while(s1>s2):
s2+=b[j]
j+=1
if (s1==s2):
cnt+=1
s1=0
s2=0
print(cnt)
... | 3 | |
760 | B | Frodo and pillows | PROGRAMMING | 1,500 | [
"binary search",
"greedy"
] | null | null | *n* hobbits are planning to spend the night at Frodo's house. Frodo has *n* beds standing in a row and *m* pillows (*n*<=≤<=*m*). Each hobbit needs a bed and at least one pillow to sleep, however, everyone wants as many pillows as possible. Of course, it's not always possible to share pillows equally, but any hobbit ge... | The only line contain three integers *n*, *m* and *k* (1<=≤<=*n*<=≤<=*m*<=≤<=109, 1<=≤<=*k*<=≤<=*n*) — the number of hobbits, the number of pillows and the number of Frodo's bed. | Print single integer — the maximum number of pillows Frodo can have so that no one is hurt. | [
"4 6 2\n",
"3 10 3\n",
"3 6 1\n"
] | [
"2\n",
"4\n",
"3\n"
] | In the first example Frodo can have at most two pillows. In this case, he can give two pillows to the hobbit on the first bed, and one pillow to each of the hobbits on the third and the fourth beds.
In the second example Frodo can take at most four pillows, giving three pillows to each of the others.
In the third exa... | 1,000 | [
{
"input": "4 6 2",
"output": "2"
},
{
"input": "3 10 3",
"output": "4"
},
{
"input": "3 6 1",
"output": "3"
},
{
"input": "3 3 3",
"output": "1"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 1000000000 1",
"output": "1000000000"
},
{
... | 1,485,281,847 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 16 | 62 | 4,608,000 | def codeforces(n, m, k):
m -= n
l = k - 1
r = n - k
l_empty = l * (l + 1) // 2
r_empty = r * (r + 1) // 2
total = (m + l_empty + r_empty) // (l + r + 1)
x = total + 1
if l > x - 1:
tl = (x - 1) * x // 2 + l - x + 1
else:
tl = (x - 1 + x - l) * l // 2
... | Title: Frodo and pillows
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* hobbits are planning to spend the night at Frodo's house. Frodo has *n* beds standing in a row and *m* pillows (*n*<=≤<=*m*). Each hobbit needs a bed and at least one pillow to sleep, however, everyone wants as ma... | ```python
def codeforces(n, m, k):
m -= n
l = k - 1
r = n - k
l_empty = l * (l + 1) // 2
r_empty = r * (r + 1) // 2
total = (m + l_empty + r_empty) // (l + r + 1)
x = total + 1
if l > x - 1:
tl = (x - 1) * x // 2 + l - x + 1
else:
tl = (x - 1 + x - l) *... | 0 | |
868 | C | Qualification Rounds | PROGRAMMING | 1,500 | [
"bitmasks",
"brute force",
"constructive algorithms",
"dp"
] | null | null | Snark and Philip are preparing the problemset for the upcoming pre-qualification round for semi-quarter-finals. They have a bank of *n* problems, and they want to select any non-empty subset of it as a problemset.
*k* experienced teams are participating in the contest. Some of these teams already know some of the prob... | The first line contains two integers *n*, *k* (1<=≤<=*n*<=≤<=105, 1<=≤<=*k*<=≤<=4) — the number of problems and the number of experienced teams.
Each of the next *n* lines contains *k* integers, each equal to 0 or 1. The *j*-th number in the *i*-th line is 1 if *j*-th team knows *i*-th problem and 0 otherwise. | Print "YES" (quotes for clarity), if it is possible to make an interesting problemset, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"5 3\n1 0 1\n1 1 0\n1 0 0\n1 0 0\n1 0 0\n",
"3 2\n1 0\n1 1\n0 1\n"
] | [
"NO\n",
"YES\n"
] | In the first example you can't make any interesting problemset, because the first team knows all problems.
In the second example you can choose the first and the third problems. | 1,000 | [
{
"input": "5 3\n1 0 1\n1 1 0\n1 0 0\n1 0 0\n1 0 0",
"output": "NO"
},
{
"input": "3 2\n1 0\n1 1\n0 1",
"output": "YES"
},
{
"input": "10 2\n1 0\n1 0\n0 0\n1 1\n0 0\n1 1\n0 0\n1 1\n0 1\n0 1",
"output": "YES"
},
{
"input": "10 3\n1 0 0\n0 1 1\n1 0 0\n0 1 0\n0 0 1\n1 0 1\n0 1 1... | 1,651,665,814 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 2 | 77 | 2,969,600 | n,k = map(int,input().split())
a = set()
dit = {}
for i in range(1,15):
dit[i] = []
for j in range(1,15):
f = True
for p in range(3):
if (i>>p)&(j>>p)!=0:
f = False
break
if f:
dit[i].append(j)
f = False ... | Title: Qualification Rounds
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Snark and Philip are preparing the problemset for the upcoming pre-qualification round for semi-quarter-finals. They have a bank of *n* problems, and they want to select any non-empty subset of it as a problemset.
... | ```python
n,k = map(int,input().split())
a = set()
dit = {}
for i in range(1,15):
dit[i] = []
for j in range(1,15):
f = True
for p in range(3):
if (i>>p)&(j>>p)!=0:
f = False
break
if f:
dit[i].append(j)
f... | -1 | |
822 | A | I'm bored with life | PROGRAMMING | 800 | [
"implementation",
"math",
"number theory"
] | null | null | Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopo... | The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12). | Print a single integer denoting the greatest common divisor of integers *A*! and *B*!. | [
"4 3\n"
] | [
"6\n"
] | Consider the sample.
4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6. | 500 | [
{
"input": "4 3",
"output": "6"
},
{
"input": "10 399603090",
"output": "3628800"
},
{
"input": "6 973151934",
"output": "720"
},
{
"input": "2 841668075",
"output": "2"
},
{
"input": "7 415216919",
"output": "5040"
},
{
"input": "3 283733059",
"ou... | 1,652,892,126 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 46 | 4,300,800 | import math
m,n = map(int,input().split())
print(math.factorial(min(m,n))) | Title: I'm bored with life
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormi... | ```python
import math
m,n = map(int,input().split())
print(math.factorial(min(m,n)))
``` | 3 | |
855 | A | Tom Riddle's Diary | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants to know the different people who had ever possessed the diary to make sure they ... | First line of input contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of names in the list.
Next *n* lines each contain a string *s**i*, consisting of lowercase English letters. The length of each string is between 1 and 100. | Output *n* lines each containing either "YES" or "NO" (without quotes), depending on whether this string was already present in the stream or not.
You can print each letter in any case (upper or lower). | [
"6\ntom\nlucius\nginny\nharry\nginny\nharry\n",
"3\na\na\na\n"
] | [
"NO\nNO\nNO\nNO\nYES\nYES\n",
"NO\nYES\nYES\n"
] | In test case 1, for *i* = 5 there exists *j* = 3 such that *s*<sub class="lower-index">*i*</sub> = *s*<sub class="lower-index">*j*</sub> and *j* < *i*, which means that answer for *i* = 5 is "YES". | 500 | [
{
"input": "6\ntom\nlucius\nginny\nharry\nginny\nharry",
"output": "NO\nNO\nNO\nNO\nYES\nYES"
},
{
"input": "3\na\na\na",
"output": "NO\nYES\nYES"
},
{
"input": "1\nzn",
"output": "NO"
},
{
"input": "9\nliyzmbjwnzryjokufuxcqtzwworjeoxkbaqrujrhdidqdvwdfzilwszgnzglnnbogaclckfnb... | 1,691,166,233 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 46 | 0 | n=int(input())
name_set=set()
for i in range(n):
name=input().strip()
if name in name_set:
print("YES")
else:
print("NO")
name_set.add(name)
| Title: Tom Riddle's Diary
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber ... | ```python
n=int(input())
name_set=set()
for i in range(n):
name=input().strip()
if name in name_set:
print("YES")
else:
print("NO")
name_set.add(name)
``` | 3 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,661,976,071 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | word = input()
i = 0
l = 0
u = 0
while i<len(word):
if word[i].islower():
l+=1
else:
u+=1
i+=1
if u>l:
word = word.upper()
else:
word = word.lower()
print(word) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
word = input()
i = 0
l = 0
u = 0
while i<len(word):
if word[i].islower():
l+=1
else:
u+=1
i+=1
if u>l:
word = word.upper()
else:
word = word.lower()
print(word)
``` | 3.977 |
486 | A | Calculating Function | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*. | The single line contains the positive integer *n* (1<=≤<=*n*<=≤<=1015). | Print *f*(*n*) in a single line. | [
"4\n",
"5\n"
] | [
"2\n",
"-3\n"
] | *f*(4) = - 1 + 2 - 3 + 4 = 2
*f*(5) = - 1 + 2 - 3 + 4 - 5 = - 3 | 500 | [
{
"input": "4",
"output": "2"
},
{
"input": "5",
"output": "-3"
},
{
"input": "1000000000",
"output": "500000000"
},
{
"input": "1000000001",
"output": "-500000001"
},
{
"input": "1000000000000000",
"output": "500000000000000"
},
{
"input": "100",
... | 1,693,745,348 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 46 | 0 | # import sys
# sys.stdin = open("/Users/swasti/Desktop/coding/cp/codeforces/input.txt", "r")
# sys.stdout = open("/Users/swasti/Desktop/coding/cp/codeforces/output.txt", "w")
n = int(input())
if n%2==0:
print( n//2)
else:
prev = (n-1)//2
print(prev-n)
| Title: Calculating Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*.
Input Specification:
The single line... | ```python
# import sys
# sys.stdin = open("/Users/swasti/Desktop/coding/cp/codeforces/input.txt", "r")
# sys.stdout = open("/Users/swasti/Desktop/coding/cp/codeforces/output.txt", "w")
n = int(input())
if n%2==0:
print( n//2)
else:
prev = (n-1)//2
print(prev-n)
``` | 3 | |
496 | A | Minimum Difficulty | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Mike is trying rock climbing but he is awful at it.
There are *n* holds on the wall, *i*-th hold is at height *a**i* off the ground. Besides, let the sequence *a**i* increase, that is, *a**i*<=<<=*a**i*<=+<=1 for all *i* from 1 to *n*<=-<=1; we will call such sequence a track. Mike thinks that the track *a*1, ...,... | The first line contains a single integer *n* (3<=≤<=*n*<=≤<=100) — the number of holds.
The next line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=1000), where *a**i* is the height where the hold number *i* hangs. The sequence *a**i* is increasing (i.e. each element except for the first one is strict... | Print a single number — the minimum difficulty of the track after removing a single hold. | [
"3\n1 4 6\n",
"5\n1 2 3 4 5\n",
"5\n1 2 3 7 8\n"
] | [
"5\n",
"2\n",
"4\n"
] | In the first sample you can remove only the second hold, then the sequence looks like (1, 6), the maximum difference of the neighboring elements equals 5.
In the second test after removing every hold the difficulty equals 2.
In the third test you can obtain sequences (1, 3, 7, 8), (1, 2, 7, 8), (1, 2, 3, 8), for whic... | 500 | [
{
"input": "3\n1 4 6",
"output": "5"
},
{
"input": "5\n1 2 3 4 5",
"output": "2"
},
{
"input": "5\n1 2 3 7 8",
"output": "4"
},
{
"input": "3\n1 500 1000",
"output": "999"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "2"
},
{
"input": "10\n1 4 9... | 1,634,520,558 | 2,147,483,647 | PyPy 3 | OK | TESTS | 19 | 93 | 0 | n, lst, res, bd = int(input()), list(map(int, input().split())), 10000000, 0
for x in range(n - 1): bd = max(bd, lst[x + 1] - lst[x])
for x in range(1, n - 1): res = min(res, max(bd, lst[x + 1] - lst[x - 1]))
print(res) | Title: Minimum Difficulty
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mike is trying rock climbing but he is awful at it.
There are *n* holds on the wall, *i*-th hold is at height *a**i* off the ground. Besides, let the sequence *a**i* increase, that is, *a**i*<=<<=*a**i*<=+<=1 fo... | ```python
n, lst, res, bd = int(input()), list(map(int, input().split())), 10000000, 0
for x in range(n - 1): bd = max(bd, lst[x + 1] - lst[x])
for x in range(1, n - 1): res = min(res, max(bd, lst[x + 1] - lst[x - 1]))
print(res)
``` | 3 | |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers ex... | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at... | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 ... | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,687,043,612 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 71 | 218 | 1,945,600 | s=int(input())
c=0
v=[]
for i in range(s):
b=list(map(int,input().split()))
c+=b[1]-b[0]
v+=[c]
print(max(v)) | Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it ... | ```python
s=int(input())
c=0
v=[]
for i in range(s):
b=list(map(int,input().split()))
c+=b[1]-b[0]
v+=[c]
print(max(v))
``` | 3 | |
137 | A | Postcards and photos | PROGRAMMING | 900 | [
"implementation"
] | null | null | Polycarpus has postcards and photos hung in a row on the wall. He decided to put them away to the closet and hang on the wall a famous painter's picture. Polycarpus does it like that: he goes from the left to the right and removes the objects consecutively. As Polycarpus doesn't want any mix-ups to happen, he will not ... | The only line of the input data contains a non-empty string consisting of letters "С" and "P" whose length does not exceed 100 characters. If the *i*-th character in the string is the letter "С", that means that the *i*-th object (the numbering goes from the left to the right) on Polycarpus' wall is a postcard. And if ... | Print the only number — the minimum number of times Polycarpus has to visit the closet. | [
"CPCPCPC\n",
"CCCCCCPPPPPP\n",
"CCCCCCPPCPPPPPPPPPP\n",
"CCCCCCCCCC\n"
] | [
"7\n",
"4\n",
"6\n",
"2\n"
] | In the first sample Polycarpus needs to take one item to the closet 7 times.
In the second sample Polycarpus can first take 3 postcards to the closet; then 3 more. He can take the 6 photos that are left in the similar way, going to the closet twice.
In the third sample Polycarpus can visit the closet twice, both time... | 500 | [
{
"input": "CPCPCPC",
"output": "7"
},
{
"input": "CCCCCCPPPPPP",
"output": "4"
},
{
"input": "CCCCCCPPCPPPPPPPPPP",
"output": "6"
},
{
"input": "CCCCCCCCCC",
"output": "2"
},
{
"input": "CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC... | 1,596,038,216 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 280 | 20,172,800 | s=input()
a=len(s)
s=s+'0'
p=0
c=s[0]
i=1
cnt = 0
while p < a:
p+=1#pointer of string
i+=1
if s[p] != c:
cnt += 1
i=0#number of stuff on his hands
c=s[p]
if i==5:
i=0
cnt+=1
c=s[p+1]
if i != 0:
cnt+=1
print(cnt) | Title: Postcards and photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has postcards and photos hung in a row on the wall. He decided to put them away to the closet and hang on the wall a famous painter's picture. Polycarpus does it like that: he goes from the left to the r... | ```python
s=input()
a=len(s)
s=s+'0'
p=0
c=s[0]
i=1
cnt = 0
while p < a:
p+=1#pointer of string
i+=1
if s[p] != c:
cnt += 1
i=0#number of stuff on his hands
c=s[p]
if i==5:
i=0
cnt+=1
c=s[p+1]
if i != 0:
cnt+=1
print(cnt)
``` | 0 | |
239 | A | Two Bags of Potatoes | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, first... | The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). | Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1. | [
"10 1 10\n",
"10 6 40\n"
] | [
"-1\n",
"2 8 14 20 26 \n"
] | none | 500 | [
{
"input": "10 1 10",
"output": "-1"
},
{
"input": "10 6 40",
"output": "2 8 14 20 26 "
},
{
"input": "10 1 20",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "1 10000 1000000000",
"output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 12999... | 1,541,151,343 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 686 | 3,276,800 | y, k, n = map(int,input().split())
s = 1
l = []
while k*s <= n :
if k*s-y > 0 :
l.append(k*s-y)
s += 1
if l :
print(*l)
else :
print(-1) | Title: Two Bags of Potatoes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* pota... | ```python
y, k, n = map(int,input().split())
s = 1
l = []
while k*s <= n :
if k*s-y > 0 :
l.append(k*s-y)
s += 1
if l :
print(*l)
else :
print(-1)
``` | 3 | |
492 | B | Vanya and Lanterns | PROGRAMMING | 1,200 | [
"binary search",
"implementation",
"math",
"sortings"
] | null | null | Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the point *l*. Then the *i*-th lantern is at the point *a**i*. The lantern lights all points of the street that... | The first line contains two integers *n*, *l* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*l*<=≤<=109) — the number of lanterns and the length of the street respectively.
The next line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=*l*). Multiple lanterns can be located at the same point. The lanterns may be located at the ends of th... | Print the minimum light radius *d*, needed to light the whole street. The answer will be considered correct if its absolute or relative error doesn't exceed 10<=-<=9. | [
"7 15\n15 5 3 7 9 14 0\n",
"2 5\n2 5\n"
] | [
"2.5000000000\n",
"2.0000000000\n"
] | Consider the second sample. At *d* = 2 the first lantern will light the segment [0, 4] of the street, and the second lantern will light segment [3, 5]. Thus, the whole street will be lit. | 1,000 | [
{
"input": "7 15\n15 5 3 7 9 14 0",
"output": "2.5000000000"
},
{
"input": "2 5\n2 5",
"output": "2.0000000000"
},
{
"input": "46 615683844\n431749087 271781274 274974690 324606253 480870261 401650581 13285442 478090364 266585394 425024433 588791449 492057200 391293435 563090494 317950 1... | 1,699,894,288 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 8 | 62 | 0 | import math
import sys
n,l = map(int,input().split())
ls = list(map(int,input().split()))
ls.sort()
maxi = 0
for i in range(n-1):
maxi = max(maxi,ls[i+1]-ls[i])
maxi=maxi/2
if ls[0]==0:
print(maxi)
else:
a = ls[0]
print(max(maxi,a))
| Title: Vanya and Lanterns
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the poi... | ```python
import math
import sys
n,l = map(int,input().split())
ls = list(map(int,input().split()))
ls.sort()
maxi = 0
for i in range(n-1):
maxi = max(maxi,ls[i+1]-ls[i])
maxi=maxi/2
if ls[0]==0:
print(maxi)
else:
a = ls[0]
print(max(maxi,a))
``` | 0 | |
724 | A | Checking the Calendar | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | You are given names of two days of the week.
Please, determine whether it is possible that during some non-leap year the first day of some month was equal to the first day of the week you are given, while the first day of the next month was equal to the second day of the week you are given. Both months should belong t... | The input consists of two lines, each of them containing the name of exactly one day of the week. It's guaranteed that each string in the input is from the set "monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday". | Print "YES" (without quotes) if such situation is possible during some non-leap year. Otherwise, print "NO" (without quotes). | [
"monday\ntuesday\n",
"sunday\nsunday\n",
"saturday\ntuesday\n"
] | [
"NO\n",
"YES\n",
"YES\n"
] | In the second sample, one can consider February 1 and March 1 of year 2015. Both these days were Sundays.
In the third sample, one can consider July 1 and August 1 of year 2017. First of these two days is Saturday, while the second one is Tuesday. | 500 | [
{
"input": "monday\ntuesday",
"output": "NO"
},
{
"input": "sunday\nsunday",
"output": "YES"
},
{
"input": "saturday\ntuesday",
"output": "YES"
},
{
"input": "tuesday\nthursday",
"output": "YES"
},
{
"input": "friday\nwednesday",
"output": "NO"
},
{
"i... | 1,628,799,208 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 6,758,400 | days = ["monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday"]
d1 = input()
d2 = input()
d = days.index(d2) - days.index(d1)
print(d)
if d < 0:
d = d + 7
if d == 0 or d == 2 or d == 3:
print('YES')
else:
print('NO') | Title: Checking the Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given names of two days of the week.
Please, determine whether it is possible that during some non-leap year the first day of some month was equal to the first day of the week you are given, while the fir... | ```python
days = ["monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday"]
d1 = input()
d2 = input()
d = days.index(d2) - days.index(d1)
print(d)
if d < 0:
d = d + 7
if d == 0 or d == 2 or d == 3:
print('YES')
else:
print('NO')
``` | 0 | |
892 | A | Greed | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not! | The first line of the input contains one integer *n* (2<=≤<=*n*<=≤<=100<=000) — number of cola cans.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — volume of remaining cola in cans.
The third line contains *n* space-separated integers that *b*1,<=*b*2,<=...,<... | Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).
You can print each letter in any case (upper or lower). | [
"2\n3 5\n3 6\n",
"3\n6 8 9\n6 10 12\n",
"5\n0 0 5 0 0\n1 1 8 10 5\n",
"4\n4 1 0 3\n5 2 2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"YES\n"
] | In the first sample, there are already 2 cans, so the answer is "YES". | 500 | [
{
"input": "2\n3 5\n3 6",
"output": "YES"
},
{
"input": "3\n6 8 9\n6 10 12",
"output": "NO"
},
{
"input": "5\n0 0 5 0 0\n1 1 8 10 5",
"output": "YES"
},
{
"input": "4\n4 1 0 3\n5 2 2 3",
"output": "YES"
},
{
"input": "10\n9 10 24 11 1 7 8 3 28 14\n86 20 34 11 22 9... | 1,510,934,187 | 4,887 | Python 3 | OK | TESTS | 39 | 171 | 7,168,000 | n=int(input())
v=0
for i in input().split(' '):
v+=int(i)
a,b,c=0,0,0
for i in input().split(' '):
c=int(i)
if c>=a:
b=a
a=c
elif c>b:
b=c
if v <= a+b:
print("YES")
else:
print("NO") | Title: Greed
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he c... | ```python
n=int(input())
v=0
for i in input().split(' '):
v+=int(i)
a,b,c=0,0,0
for i in input().split(' '):
c=int(i)
if c>=a:
b=a
a=c
elif c>b:
b=c
if v <= a+b:
print("YES")
else:
print("NO")
``` | 3 | |
294 | A | Shaass and Oskols | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Shaass has decided to hunt some birds. There are *n* horizontal electricity wires aligned parallel to each other. Wires are numbered 1 to *n* from top to bottom. On each wire there are some oskols sitting next to each other. Oskol is the name of a delicious kind of birds in Shaass's territory. Supposed there are *a**i*... | The first line of the input contains an integer *n*, (1<=≤<=*n*<=≤<=100). The next line contains a list of space-separated integers *a*1,<=*a*2,<=...,<=*a**n*, (0<=≤<=*a**i*<=≤<=100).
The third line contains an integer *m*, (0<=≤<=*m*<=≤<=100). Each of the next *m* lines contains two integers *x**i* and *y**i*. The i... | On the *i*-th line of the output print the number of birds on the *i*-th wire. | [
"5\n10 10 10 10 10\n5\n2 5\n3 13\n2 12\n1 13\n4 6\n",
"3\n2 4 1\n1\n2 2\n"
] | [
"0\n12\n5\n0\n16\n",
"3\n0\n3\n"
] | none | 500 | [
{
"input": "5\n10 10 10 10 10\n5\n2 5\n3 13\n2 12\n1 13\n4 6",
"output": "0\n12\n5\n0\n16"
},
{
"input": "3\n2 4 1\n1\n2 2",
"output": "3\n0\n3"
},
{
"input": "5\n58 51 45 27 48\n5\n4 9\n5 15\n4 5\n5 8\n1 43",
"output": "0\n66\n57\n7\n0"
},
{
"input": "10\n48 53 10 28 91 56 8... | 1,683,456,932 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | n=int(input())
a=list(map(int,input().split()))
m=int(input())
w=[[0]*2 for i in range(m)]
for i in range(m):
w[i][0],w[i][1]=map(int,input().split())
for i in range(m):
left=w[i][1]-1
right=a[w[i][0]-1]-w[i][1]
if w[i][0]!=1:
a[w[i][0]-2]+=left
if w[i][0]!=n:
... | Title: Shaass and Oskols
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Shaass has decided to hunt some birds. There are *n* horizontal electricity wires aligned parallel to each other. Wires are numbered 1 to *n* from top to bottom. On each wire there are some oskols sitting next to each... | ```python
n=int(input())
a=list(map(int,input().split()))
m=int(input())
w=[[0]*2 for i in range(m)]
for i in range(m):
w[i][0],w[i][1]=map(int,input().split())
for i in range(m):
left=w[i][1]-1
right=a[w[i][0]-1]-w[i][1]
if w[i][0]!=1:
a[w[i][0]-2]+=left
if w[i][0]!=n... | 3 | |
946 | A | Partition | PROGRAMMING | 800 | [
"greedy"
] | null | null | You are given a sequence *a* consisting of *n* integers. You may partition this sequence into two sequences *b* and *c* in such a way that every element belongs exactly to one of these sequences.
Let *B* be the sum of elements belonging to *b*, and *C* be the sum of elements belonging to *c* (if some of these sequenc... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (<=-<=100<=≤<=*a**i*<=≤<=100) — the elements of sequence *a*. | Print the maximum possible value of *B*<=-<=*C*, where *B* is the sum of elements of sequence *b*, and *C* is the sum of elements of sequence *c*. | [
"3\n1 -2 0\n",
"6\n16 23 16 15 42 8\n"
] | [
"3\n",
"120\n"
] | In the first example we may choose *b* = {1, 0}, *c* = { - 2}. Then *B* = 1, *C* = - 2, *B* - *C* = 3.
In the second example we choose *b* = {16, 23, 16, 15, 42, 8}, *c* = {} (an empty sequence). Then *B* = 120, *C* = 0, *B* - *C* = 120. | 0 | [
{
"input": "3\n1 -2 0",
"output": "3"
},
{
"input": "6\n16 23 16 15 42 8",
"output": "120"
},
{
"input": "1\n-1",
"output": "1"
},
{
"input": "100\n-100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -10... | 1,657,284,820 | 2,147,483,647 | PyPy 3 | OK | TESTS | 72 | 77 | 0 | # problem D
n = int(input())
elements = list(map(int, input().split()))
a = []
b = []
for x in elements:
if x < 0:
a.append(x)
else:
b.append(x)
A = sum(a)
B = sum(b)
print(B - A)
| Title: Partition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence *a* consisting of *n* integers. You may partition this sequence into two sequences *b* and *c* in such a way that every element belongs exactly to one of these sequences.
Let *B* be the sum of eleme... | ```python
# problem D
n = int(input())
elements = list(map(int, input().split()))
a = []
b = []
for x in elements:
if x < 0:
a.append(x)
else:
b.append(x)
A = sum(a)
B = sum(b)
print(B - A)
``` | 3 | |
1,006 | D | Two Strings Swaps | PROGRAMMING | 1,700 | [
"implementation"
] | null | null | You are given two strings $a$ and $b$ consisting of lowercase English letters, both of length $n$. The characters of both strings have indices from $1$ to $n$, inclusive.
You are allowed to do the following changes:
- Choose any index $i$ ($1 \le i \le n$) and swap characters $a_i$ and $b_i$; - Choose any index $... | The first line of the input contains one integer $n$ ($1 \le n \le 10^5$) — the length of strings $a$ and $b$.
The second line contains the string $a$ consisting of exactly $n$ lowercase English letters.
The third line contains the string $b$ consisting of exactly $n$ lowercase English letters. | Print a single integer — the minimum number of preprocess moves to apply before changes, so that it is possible to make the string $a$ equal to string $b$ with a sequence of changes from the list above. | [
"7\nabacaba\nbacabaa\n",
"5\nzcabd\ndbacz\n"
] | [
"4\n",
"0\n"
] | In the first example preprocess moves are as follows: $a_1 := $'b', $a_3 := $'c', $a_4 := $'a' and $a_5:=$'b'. Afterwards, $a = $"bbcabba". Then we can obtain equal strings by the following sequence of changes: $swap(a_2, b_2)$ and $swap(a_2, a_6)$. There is no way to use fewer than $4$ preprocess moves before a sequen... | 0 | [
{
"input": "7\nabacaba\nbacabaa",
"output": "4"
},
{
"input": "5\nzcabd\ndbacz",
"output": "0"
},
{
"input": "1\na\nb",
"output": "1"
},
{
"input": "5\nahmad\nyogaa",
"output": "3"
}
] | 1,650,454,682 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 23 | 78 | 3,584,000 | n=int(input())
a=input()
b=input()
ans=0
for i in range(n//2):
seen=set()
if b[i]==b[n-i-1]:
if a[i]==a[n-i-1]:
ans+=0
else:
ans+=1
else :
seen.add(b[i])
if b[n-i-1] in seen:
seen.remove(b[n-i-1])
else :
... | Title: Two Strings Swaps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two strings $a$ and $b$ consisting of lowercase English letters, both of length $n$. The characters of both strings have indices from $1$ to $n$, inclusive.
You are allowed to do the following changes:... | ```python
n=int(input())
a=input()
b=input()
ans=0
for i in range(n//2):
seen=set()
if b[i]==b[n-i-1]:
if a[i]==a[n-i-1]:
ans+=0
else:
ans+=1
else :
seen.add(b[i])
if b[n-i-1] in seen:
seen.remove(b[n-i-1])
else :
... | 3 | |
230 | B | T-primes | PROGRAMMING | 1,300 | [
"binary search",
"implementation",
"math",
"number theory"
] | null | null | We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an array of *n* positive integers. For each of them determine whether it is Т-prime or not. | The first line contains a single positive integer, *n* (1<=≤<=*n*<=≤<=105), showing how many numbers are in the array. The next line contains *n* space-separated integers *x**i* (1<=≤<=*x**i*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout st... | Print *n* lines: the *i*-th line should contain "YES" (without the quotes), if number *x**i* is Т-prime, and "NO" (without the quotes), if it isn't. | [
"3\n4 5 6\n"
] | [
"YES\nNO\nNO\n"
] | The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO". | 500 | [
{
"input": "3\n4 5 6",
"output": "YES\nNO\nNO"
},
{
"input": "2\n48 49",
"output": "NO\nYES"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "NO\nYES\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO"
},
{
"input": "1\n36",
"output": "NO"
},
{
"input": "1\n999966000289",
"... | 1,697,040,065 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 2,000 | 1,331,200 | import math
def judge(a):#生成10^6以内质数表
b=False
for i in range(2,math.ceil(math.sqrt(a))+1):#平方数是上限
if a%i==0:
b=True
break
if b==False:
l.append(a)
l=[]
l.append(2)
for a in range(3,1000001):
judge(a)
def ch(i):
if math.sqrt(i)%1==0 and i!=1 :
q=int(ma... | Title: T-primes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an ar... | ```python
import math
def judge(a):#生成10^6以内质数表
b=False
for i in range(2,math.ceil(math.sqrt(a))+1):#平方数是上限
if a%i==0:
b=True
break
if b==False:
l.append(a)
l=[]
l.append(2)
for a in range(3,1000001):
judge(a)
def ch(i):
if math.sqrt(i)%1==0 and i!=1 :
... | 0 | |
920 | C | Swap Adjacent Elements | PROGRAMMING | 1,400 | [
"dfs and similar",
"greedy",
"math",
"sortings",
"two pointers"
] | null | null | You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array.
For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<=1)-th, for other indices it is not possible. You may perform any number of swapping operations any order. T... | The first line contains one integer *n* (2<=≤<=*n*<=≤<=200000) — the number of elements in the array.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=200000) — the elements of the array. Each integer from 1 to *n* appears exactly once.
The third line contains a string of *n*<=-<=1 char... | If it is possible to sort the array in ascending order using any sequence of swaps you are allowed to make, print YES. Otherwise, print NO. | [
"6\n1 2 5 3 4 6\n01110\n",
"6\n1 2 5 3 4 6\n01010\n"
] | [
"YES\n",
"NO\n"
] | In the first example you may swap *a*<sub class="lower-index">3</sub> and *a*<sub class="lower-index">4</sub>, and then swap *a*<sub class="lower-index">4</sub> and *a*<sub class="lower-index">5</sub>. | 0 | [
{
"input": "6\n1 2 5 3 4 6\n01110",
"output": "YES"
},
{
"input": "6\n1 2 5 3 4 6\n01010",
"output": "NO"
},
{
"input": "6\n1 6 3 4 5 2\n01101",
"output": "NO"
},
{
"input": "6\n2 3 1 4 5 6\n01111",
"output": "NO"
},
{
"input": "4\n2 3 1 4\n011",
"output": "NO... | 1,517,589,288 | 7,188 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 5,632,000 | n = int(input())
l = [int(x) for x in input().split()]
a = input()
p = [0] * n
s = set()
k = 0
for i in range(n-1):
if a[i] == '1':
s.add(l[i])
s.add(l[i+1])
else:
if k < l[i]:
if k < min(s) and max(s) < l[i]:
k = l[i]
else:
... | Title: Swap Adjacent Elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array.
For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<... | ```python
n = int(input())
l = [int(x) for x in input().split()]
a = input()
p = [0] * n
s = set()
k = 0
for i in range(n-1):
if a[i] == '1':
s.add(l[i])
s.add(l[i+1])
else:
if k < l[i]:
if k < min(s) and max(s) < l[i]:
k = l[i]
else:
... | -1 | |
960 | A | Check the string | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gi... | The first and only line consists of a string $S$ ($ 1 \le |S| \le 5\,000 $). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'. | Print "YES" or "NO", according to the condition. | [
"aaabccc\n",
"bbacc\n",
"aabc\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'. | 500 | [
{
"input": "aaabccc",
"output": "YES"
},
{
"input": "bbacc",
"output": "NO"
},
{
"input": "aabc",
"output": "YES"
},
{
"input": "aabbcc",
"output": "YES"
},
{
"input": "aaacccbb",
"output": "NO"
},
{
"input": "abc",
"output": "YES"
},
{
"in... | 1,661,967,931 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 33 | 46 | 0 | s = input()
def func(s):
ca = 0
cb = 0
cc = 0
for i in range(1, len(s)):
if s[i-1] > s[i]:
return "NO"
for i in range(0, len(s)):
if s[i]=="a":
ca += 1
if s[i]=="b":
cb += 1
if s[i]=="c":
cc += 1
... | Title: Check the string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b... | ```python
s = input()
def func(s):
ca = 0
cb = 0
cc = 0
for i in range(1, len(s)):
if s[i-1] > s[i]:
return "NO"
for i in range(0, len(s)):
if s[i]=="a":
ca += 1
if s[i]=="b":
cb += 1
if s[i]=="c":
cc... | 0 | |
505 | B | Mr. Kitayuta's Colorful Graph | PROGRAMMING | 1,400 | [
"dfs and similar",
"dp",
"dsu",
"graphs"
] | null | null | Mr. Kitayuta has just bought an undirected graph consisting of *n* vertices and *m* edges. The vertices of the graph are numbered from 1 to *n*. Each edge, namely edge *i*, has a color *c**i*, connecting vertex *a**i* and *b**i*.
Mr. Kitayuta wants you to process the following *q* queries.
In the *i*-th query, he giv... | The first line of the input contains space-separated two integers — *n* and *m* (2<=≤<=*n*<=≤<=100,<=1<=≤<=*m*<=≤<=100), denoting the number of the vertices and the number of the edges, respectively.
The next *m* lines contain space-separated three integers — *a**i*, *b**i* (1<=≤<=*a**i*<=<<=*b**i*<=≤<=*n*) and *c*... | For each query, print the answer in a separate line. | [
"4 5\n1 2 1\n1 2 2\n2 3 1\n2 3 3\n2 4 3\n3\n1 2\n3 4\n1 4\n",
"5 7\n1 5 1\n2 5 1\n3 5 1\n4 5 1\n1 2 2\n2 3 2\n3 4 2\n5\n1 5\n5 1\n2 5\n1 5\n1 4\n"
] | [
"2\n1\n0\n",
"1\n1\n1\n1\n2\n"
] | Let's consider the first sample.
- Vertex 1 and vertex 2 are connected by color 1 and 2. - Vertex 3 and vertex 4 are connected by color 3. - Vertex 1 and vertex 4 are not connected by any single color. | 1,000 | [
{
"input": "4 5\n1 2 1\n1 2 2\n2 3 1\n2 3 3\n2 4 3\n3\n1 2\n3 4\n1 4",
"output": "2\n1\n0"
},
{
"input": "5 7\n1 5 1\n2 5 1\n3 5 1\n4 5 1\n1 2 2\n2 3 2\n3 4 2\n5\n1 5\n5 1\n2 5\n1 5\n1 4",
"output": "1\n1\n1\n1\n2"
},
{
"input": "2 1\n1 2 1\n1\n1 2",
"output": "1"
},
{
"input... | 1,655,623,951 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 29 | 78 | 3,993,600 | def make_set(color, v):
if (parent[color][v] != -1):
return
parent[color][v] = v
rank[color][v] = 0
def find_set(color, v):
if (parent[color][v] == -1):
return -1
if (v == parent[color][v]):
return v
parent[color][v] = find_set(color, parent[color][v])
return parent[... | Title: Mr. Kitayuta's Colorful Graph
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Kitayuta has just bought an undirected graph consisting of *n* vertices and *m* edges. The vertices of the graph are numbered from 1 to *n*. Each edge, namely edge *i*, has a color *c**i*, connecting v... | ```python
def make_set(color, v):
if (parent[color][v] != -1):
return
parent[color][v] = v
rank[color][v] = 0
def find_set(color, v):
if (parent[color][v] == -1):
return -1
if (v == parent[color][v]):
return v
parent[color][v] = find_set(color, parent[color][v])
retu... | 3 | |
385 | B | Bear and Strings | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation",
"math",
"strings"
] | null | null | The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|), that string *x*(*i*,<=*j*)<==<=*s**i**s**i*<=+<=1... *s**j* contains at least one string... | The first line contains a non-empty string *s* (1<=≤<=|*s*|<=≤<=5000). It is guaranteed that the string only consists of lowercase English letters. | Print a single number — the answer to the problem. | [
"bearbtear\n",
"bearaabearc\n"
] | [
"6\n",
"20\n"
] | In the first sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9).
In the second sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (1, 11), (2, 10), (2, 11), (3, 10), (3, 11), (4, 10), (4, 11), (5, 10), (5, 11)... | 1,000 | [
{
"input": "bearbtear",
"output": "6"
},
{
"input": "bearaabearc",
"output": "20"
},
{
"input": "pbearbearhbearzqbearjkterasjhy",
"output": "291"
},
{
"input": "pbearjbearbebearnbabcffbearbearwubearjezpiorrbearbearjbdlbearbearqbearjbearwipmsbearoaftrsebearzsnqb",
"output"... | 1,393,943,163 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 62 | 307,200 | # input part
string = input()
# solution
result = 0
pos = string.find("bear")
while pos >= 0:
result += len(string) - (pos + 3)
string = string[1:]
pos = string.find("bear")
print(result) | Title: Bear and Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j... | ```python
# input part
string = input()
# solution
result = 0
pos = string.find("bear")
while pos >= 0:
result += len(string) - (pos + 3)
string = string[1:]
pos = string.find("bear")
print(result)
``` | 3 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,577,713,285 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 124 | 307,200 | word = input()
try:
h_index = word.index("h")
e_index = word[h_index + 1:].index("e") + len(word) - len(word[h_index + 1:])
l1_index = word[e_index + 1:].index("l") + len(word) - len(word[e_index + 1:])
l2_index = word[l1_index + 1:].index("l") + len(word) - len(word[l1_index + 1:])
o_index ... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
word = input()
try:
h_index = word.index("h")
e_index = word[h_index + 1:].index("e") + len(word) - len(word[h_index + 1:])
l1_index = word[e_index + 1:].index("l") + len(word) - len(word[e_index + 1:])
l2_index = word[l1_index + 1:].index("l") + len(word) - len(word[l1_index + 1:])
... | 3.937428 |
277 | A | Learning Languages | PROGRAMMING | 1,400 | [
"dfs and similar",
"dsu"
] | null | null | The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have the list of languages, which he knows. This list could be empty, i. e. an employee may know no official la... | The first line contains two integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=100) — the number of employees and the number of languages.
Then *n* lines follow — each employee's language list. At the beginning of the *i*-th line is integer *k**i* (0<=≤<=*k**i*<=≤<=*m*) — the number of languages the *i*-th employee knows. Next... | Print a single integer — the minimum amount of money to pay so that in the end every employee could write a letter to every other one (other employees can help out translating). | [
"5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5\n",
"8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1\n",
"2 2\n1 2\n0\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the second sample the employee 1 can learn language 2, and employee 8 can learn language 4.
In the third sample employee 2 must learn language 2. | 500 | [
{
"input": "5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5",
"output": "0"
},
{
"input": "8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1",
"output": "2"
},
{
"input": "2 2\n1 2\n0",
"output": "1"
},
{
"input": "2 2\n0\n0",
"output": "2"
},
{
"input": "5 5\n1 3\n0\n0\n2 4... | 1,664,008,718 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 19 | 248 | 3,584,000 | from collections import defaultdict
n, m = list(map(int, input().split()))
language_speakers = defaultdict(set)
total_languages_spoken = set()
zero_speakers = 0
for i in range(n):
li = input().split()
if li[0] == '0':
zero_speakers += 1
for j in li[1:]:
language_speakers[j].add... | Title: Learning Languages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have th... | ```python
from collections import defaultdict
n, m = list(map(int, input().split()))
language_speakers = defaultdict(set)
total_languages_spoken = set()
zero_speakers = 0
for i in range(n):
li = input().split()
if li[0] == '0':
zero_speakers += 1
for j in li[1:]:
language_speak... | 0 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,684,774,852 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | s=input()
k=set()
for i in s:
k.add(i)
if len(k)%2!=0:
print("IGNORE HIM!")
else:
print("CHAT WITH HER!")
| Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
s=input()
k=set()
for i in s:
k.add(i)
if len(k)%2!=0:
print("IGNORE HIM!")
else:
print("CHAT WITH HER!")
``` | 0 |
931 | A | Friends Meeting | PROGRAMMING | 800 | [
"brute force",
"greedy",
"implementation",
"math"
] | null | null | Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes acco... | The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1000) — the initial position of the first friend.
The second line contains a single integer *b* (1<=≤<=*b*<=≤<=1000) — the initial position of the second friend.
It is guaranteed that *a*<=≠<=*b*. | Print the minimum possible total tiredness if the friends meet in the same point. | [
"3\n4\n",
"101\n99\n",
"5\n10\n"
] | [
"1\n",
"2\n",
"9\n"
] | In the first example the first friend should move by one to the right (then the meeting happens at point 4), or the second friend should move by one to the left (then the meeting happens at point 3). In both cases, the total tiredness becomes 1.
In the second example the first friend should move by one to the left, an... | 500 | [
{
"input": "3\n4",
"output": "1"
},
{
"input": "101\n99",
"output": "2"
},
{
"input": "5\n10",
"output": "9"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "1\n1000",
"output": "250000"
},
{
"input": "999\n1000",
"output": "1"
},
{
"inpu... | 1,525,461,682 | 142 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
#define ll long long int
#define inf 0x3f3f3f3f
#define pb push_back
#define mk make_pair
#define fi first
#define se second
#define ii pair<int, int>
#define all(x) (x).begin(), (x).end()
#define N 1000007 // 10e6 + 7
int main(int argc, char const *argv[])... | Title: Friends Meeting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in... | ```python
#include <bits/stdc++.h>
using namespace std;
#define ll long long int
#define inf 0x3f3f3f3f
#define pb push_back
#define mk make_pair
#define fi first
#define se second
#define ii pair<int, int>
#define all(x) (x).begin(), (x).end()
#define N 1000007 // 10e6 + 7
int main(int argc, char cons... | -1 | |
479 | A | Expression | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resul... | The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10). | Print the maximum value of the expression that you can obtain. | [
"1\n2\n3\n",
"2\n10\n3\n"
] | [
"9\n",
"60\n"
] | none | 500 | [
{
"input": "1\n2\n3",
"output": "9"
},
{
"input": "2\n10\n3",
"output": "60"
},
{
"input": "1\n1\n1",
"output": "3"
},
{
"input": "1\n2\n1",
"output": "4"
},
{
"input": "10\n10\n10",
"output": "1000"
},
{
"input": "5\n1\n3",
"output": "20"
},
{... | 1,694,877,986 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 29 | 62 | 0 | a,b,c = int(input()),int(input()),int(input())
ans = a * b * c
ans = max(ans, a + b + c, (a + b) * c, a * (b + c), a * b + c, a + b * c)
print(ans)
| Title: Expression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of ... | ```python
a,b,c = int(input()),int(input()),int(input())
ans = a * b * c
ans = max(ans, a + b + c, (a + b) * c, a * (b + c), a * b + c, a + b * c)
print(ans)
``` | 3 | |
837 | A | Text Volume | PROGRAMMING | 800 | [
"implementation"
] | null | null | You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the text.
Calculate the volume of the given text. | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200) — length of the text.
The second line contains text of single-space separated words *s*1,<=*s*2,<=...,<=*s**i*, consisting only of small and capital Latin letters. | Print one integer number — volume of text. | [
"7\nNonZERO\n",
"24\nthis is zero answer text\n",
"24\nHarbour Space University\n"
] | [
"5\n",
"0\n",
"1\n"
] | In the first example there is only one word, there are 5 capital letters in it.
In the second example all of the words contain 0 capital letters. | 0 | [
{
"input": "7\nNonZERO",
"output": "5"
},
{
"input": "24\nthis is zero answer text",
"output": "0"
},
{
"input": "24\nHarbour Space University",
"output": "1"
},
{
"input": "2\nWM",
"output": "2"
},
{
"input": "200\nLBmJKQLCKUgtTxMoDsEerwvLOXsxASSydOqWyULsRcjMYDWd... | 1,631,708,384 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 62 | 6,758,400 | x=input()
n=input().split(' ')
ans=0
for i in n:
cur=0
for j in i:
if j>='A' and j<='Z':
cur+=1
ans=max(ans,cur)
print(ans) | Title: Text Volume
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the tex... | ```python
x=input()
n=input().split(' ')
ans=0
for i in n:
cur=0
for j in i:
if j>='A' and j<='Z':
cur+=1
ans=max(ans,cur)
print(ans)
``` | 3 | |
489 | B | BerSU Ball | PROGRAMMING | 1,200 | [
"dfs and similar",
"dp",
"graph matchings",
"greedy",
"sortings",
"two pointers"
] | null | null | The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! *n* boys and *m* girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves.
We know that several boy&girl pairs are going to be invited to the ball. However, the partners' dancing skill in eac... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of boys. The second line contains sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is the *i*-th boy's dancing skill.
Similarly, the third line contains an integer *m* (1<=≤<=*m*<=≤<=100) — the number of girls. The fourth l... | Print a single number — the required maximum possible number of pairs. | [
"4\n1 4 6 2\n5\n5 1 5 7 9\n",
"4\n1 2 3 4\n4\n10 11 12 13\n",
"5\n1 1 1 1 1\n3\n1 2 3\n"
] | [
"3\n",
"0\n",
"2\n"
] | none | 1,000 | [
{
"input": "4\n1 4 6 2\n5\n5 1 5 7 9",
"output": "3"
},
{
"input": "4\n1 2 3 4\n4\n10 11 12 13",
"output": "0"
},
{
"input": "5\n1 1 1 1 1\n3\n1 2 3",
"output": "2"
},
{
"input": "1\n1\n1\n1",
"output": "1"
},
{
"input": "2\n1 10\n1\n9",
"output": "1"
},
{... | 1,693,323,376 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | import sys
def main():
n, m, pairs = int(sys.stdin.readline()), int(sys.stdin.readline()), 0
a = list(map(int, sys.stdin.readline().split()))
b = list(map(int, sys.stdin.readline().split()))
a.sort()
b.sort()
for i in range(n):
for j in range(m):
if abs(a[i] - b[j]) ... | Title: BerSU Ball
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! *n* boys and *m* girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves.
We know that several boy... | ```python
import sys
def main():
n, m, pairs = int(sys.stdin.readline()), int(sys.stdin.readline()), 0
a = list(map(int, sys.stdin.readline().split()))
b = list(map(int, sys.stdin.readline().split()))
a.sort()
b.sort()
for i in range(n):
for j in range(m):
if abs(a[i... | -1 | |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't w... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't e... | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,694,876,605 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 122 | 0 | n = int(input())
a = [int(i) for i in input().split()]
a.sort()
s = sum(a)
tek = 0
for i in range(len(a)):
el = a[i]
tek += el
s -= el
if tek > s:
print(i + 1)
break
| Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very w... | ```python
n = int(input())
a = [int(i) for i in input().split()]
a.sort()
s = sum(a)
tek = 0
for i in range(len(a)):
el = a[i]
tek += el
s -= el
if tek > s:
print(i + 1)
break
``` | 0 | |
961 | D | Pair Of Lines | PROGRAMMING | 2,000 | [
"geometry"
] | null | null | You are given *n* points on Cartesian plane. Every point is a lattice point (i.<=e. both of its coordinates are integers), and all points are distinct.
You may draw two straight lines (not necessarily distinct). Is it possible to do this in such a way that every point lies on at least one of these lines? | The first line contains one integer *n* (1<=≤<=*n*<=≤<=105) — the number of points you are given.
Then *n* lines follow, each line containing two integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109)— coordinates of *i*-th point. All *n* points are distinct. | If it is possible to draw two straight lines in such a way that each of given points belongs to at least one of these lines, print YES. Otherwise, print NO. | [
"5\n0 0\n0 1\n1 1\n1 -1\n2 2\n",
"5\n0 0\n1 0\n2 1\n1 1\n2 3\n"
] | [
"YES\n",
"NO\n"
] | In the first example it is possible to draw two lines, the one containing the points 1, 3 and 5, and another one containing two remaining points. | 0 | [
{
"input": "5\n0 0\n0 1\n1 1\n1 -1\n2 2",
"output": "YES"
},
{
"input": "5\n0 0\n1 0\n2 1\n1 1\n2 3",
"output": "NO"
},
{
"input": "1\n-1000000000 1000000000",
"output": "YES"
},
{
"input": "5\n2 -1\n-4 1\n0 -9\n5 -9\n9 -10",
"output": "NO"
},
{
"input": "5\n6 1\n... | 1,615,294,148 | 2,948 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 93 | 0 | import os,io
input=io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
n=int(input())
if n==1:
print('YES')
exit()
points=[]
for _ in range(n):
x,y=map(int,input().split())
points.append((x,y))
x1,y1=points[0]
x2,y2=points[1]
flag=0
for i in range(2,n):
xk,yk=points[i]
if (xk-x2)*... | Title: Pair Of Lines
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* points on Cartesian plane. Every point is a lattice point (i.<=e. both of its coordinates are integers), and all points are distinct.
You may draw two straight lines (not necessarily distinct). Is it po... | ```python
import os,io
input=io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
n=int(input())
if n==1:
print('YES')
exit()
points=[]
for _ in range(n):
x,y=map(int,input().split())
points.append((x,y))
x1,y1=points[0]
x2,y2=points[1]
flag=0
for i in range(2,n):
xk,yk=points[i]
i... | 0 | |
295 | B | Greg and Graph | PROGRAMMING | 1,700 | [
"dp",
"graphs",
"shortest paths"
] | null | null | Greg has a weighed directed graph, consisting of *n* vertices. In this graph any pair of distinct vertices has an edge between them in both directions. Greg loves playing with the graph and now he has invented a new game:
- The game consists of *n* steps. - On the *i*-th step Greg removes vertex number *x**i* from t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=500) — the number of vertices in the graph.
Next *n* lines contain *n* integers each — the graph adjacency matrix: the *j*-th number in the *i*-th line *a**ij* (1<=≤<=*a**ij*<=≤<=105,<=*a**ii*<==<=0) represents the weight of the edge that goes from vertex *i* to verte... | Print *n* integers — the *i*-th number equals the required sum before the *i*-th step.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier. | [
"1\n0\n1\n",
"2\n0 5\n4 0\n1 2\n",
"4\n0 3 1 1\n6 0 400 1\n2 4 0 1\n1 1 1 0\n4 1 2 3\n"
] | [
"0 ",
"9 0 ",
"17 23 404 0 "
] | none | 1,000 | [
{
"input": "1\n0\n1",
"output": "0 "
},
{
"input": "2\n0 5\n4 0\n1 2",
"output": "9 0 "
},
{
"input": "4\n0 3 1 1\n6 0 400 1\n2 4 0 1\n1 1 1 0\n4 1 2 3",
"output": "17 23 404 0 "
},
{
"input": "4\n0 57148 51001 13357\n71125 0 98369 67226\n49388 90852 0 66291\n39573 38165 9700... | 1,668,503,308 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 25 | 3,000 | 10,956,800 | #from pyrival import *
import math
import sys
input = lambda: sys.stdin.readline().rstrip("\r\n")
n = int(input())
dist = [[0]*n for _ in range(n)]
for i in range(n):
dist[i] = list(map(int, input().split()))
x = list(map(int, input().split()))
x = [xi - 1 for xi in x]
x.reverse()
totals = []
for pos in range(n... | Title: Greg and Graph
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg has a weighed directed graph, consisting of *n* vertices. In this graph any pair of distinct vertices has an edge between them in both directions. Greg loves playing with the graph and now he has invented a new game... | ```python
#from pyrival import *
import math
import sys
input = lambda: sys.stdin.readline().rstrip("\r\n")
n = int(input())
dist = [[0]*n for _ in range(n)]
for i in range(n):
dist[i] = list(map(int, input().split()))
x = list(map(int, input().split()))
x = [xi - 1 for xi in x]
x.reverse()
totals = []
for pos ... | 0 | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,673,939,067 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 1,000 | 1,331,200 | l=0
a,b=map(int,input().split())
while True:
l+=1
if a%10==b:
break
else:
a+=a
print(l) | Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
l=0
a,b=map(int,input().split())
while True:
l+=1
if a%10==b:
break
else:
a+=a
print(l)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Slastyona and her loyal dog Pushok are playing a meaningless game that is indeed very interesting.
The game consists of multiple rounds. Its rules are very simple: in each round, a natural number *k* is chosen. Then, the one who says (or barks) it faster than the other wins the round. After that, the winner's score is... | In the first string, the number of games *n* (1<=≤<=*n*<=≤<=350000) is given.
Each game is represented by a pair of scores *a*, *b* (1<=≤<=*a*,<=*b*<=≤<=109) – the results of Slastyona and Pushok, correspondingly. | For each pair of scores, answer "Yes" if it's possible for a game to finish with given score, and "No" otherwise.
You can output each letter in arbitrary case (upper or lower). | [
"6\n2 4\n75 45\n8 8\n16 16\n247 994\n1000000000 1000000\n"
] | [
"Yes\nYes\nYes\nNo\nNo\nYes\n"
] | First game might have been consisted of one round, in which the number 2 would have been chosen and Pushok would have won.
The second game needs exactly two rounds to finish with such result: in the first one, Slastyona would have said the number 5, and in the second one, Pushok would have barked the number 3. | 0 | [
{
"input": "6\n2 4\n75 45\n8 8\n16 16\n247 994\n1000000000 1000000",
"output": "Yes\nYes\nYes\nNo\nNo\nYes"
},
{
"input": "3\n1 1\n8 27\n1000 1331",
"output": "Yes\nNo\nNo"
},
{
"input": "1\n12004 18012002",
"output": "Yes"
},
{
"input": "1\n3331 11095561",
"output": "Yes... | 1,679,714,161 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 1,433,600 | for i in range(int(input())):
a,b=map(int,input().split())
c=2
while a>1:
if (a%(c**2)==0 and b%c==0):
a//=c**2
b//=c
elif (b%(c**2)==0 and a%c==0):
b//=c**2
a//=c
elif (a%c!=0 and b%c!=0):
c+=1
else:
a=0
break
if a==0 or b>1:
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Slastyona and her loyal dog Pushok are playing a meaningless game that is indeed very interesting.
The game consists of multiple rounds. Its rules are very simple: in each round, a natural number *k* is chosen. Then, the one who ... | ```python
for i in range(int(input())):
a,b=map(int,input().split())
c=2
while a>1:
if (a%(c**2)==0 and b%c==0):
a//=c**2
b//=c
elif (b%(c**2)==0 and a%c==0):
b//=c**2
a//=c
elif (a%c!=0 and b%c!=0):
c+=1
else:
a=0
break
if a==0 ... | 0 | |
231 | A | Team | PROGRAMMING | 800 | [
"brute force",
"greedy"
] | null | null | One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution.... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second numbe... | Print a single integer — the number of problems the friends will implement on the contest. | [
"3\n1 1 0\n1 1 1\n1 0 0\n",
"2\n1 0 0\n0 1 1\n"
] | [
"2\n",
"1\n"
] | In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't ta... | 500 | [
{
"input": "3\n1 1 0\n1 1 1\n1 0 0",
"output": "2"
},
{
"input": "2\n1 0 0\n0 1 1",
"output": "1"
},
{
"input": "1\n1 0 0",
"output": "0"
},
{
"input": "2\n1 0 0\n1 1 1",
"output": "1"
},
{
"input": "5\n1 0 0\n0 1 0\n1 1 1\n0 0 1\n0 0 0",
"output": "1"
},
... | 1,699,008,976 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 21 | 156 | 1,740,800 | t = int(input())
count = 0
for i in range(t):
a, b, c = map(int, input().split())
views = [a, b, c]
# Count the number of friends sure about the solution for each problem
sure_count = views.count(1)
# If at least two friends are sure, increment the total count of problems
i... | Title: Team
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decid... | ```python
t = int(input())
count = 0
for i in range(t):
a, b, c = map(int, input().split())
views = [a, b, c]
# Count the number of friends sure about the solution for each problem
sure_count = views.count(1)
# If at least two friends are sure, increment the total count of probl... | 3 | |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,614,603,045 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 62 | 409,600 | a,b,n=map(int,input().split())
digits=[0,1,2,3,4,5,6,7,8,9]
length,prev=1,1
flag=False
if a%b==0:
print(str(a)+"0"*n)
for i in range(10):
cum=str(a)+str(digits[i])
if int(cum)%b==0:
a=cum
break
else:
print(-1)
flag=True
if flag==False:
print(str(a)+"0"*(n-1))
| Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
a,b,n=map(int,input().split())
digits=[0,1,2,3,4,5,6,7,8,9]
length,prev=1,1
flag=False
if a%b==0:
print(str(a)+"0"*n)
for i in range(10):
cum=str(a)+str(digits[i])
if int(cum)%b==0:
a=cum
break
else:
print(-1)
flag=True
if flag==False:
print(str(a)+"0... | 0 | |
862 | B | Mahmoud and Ehab and the bipartiteness | PROGRAMMING | 1,300 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a graph, whose vertices can be partitioned into 2 sets in such a way, that for each edge (*u*,<=*v*) that belongs to the graph, *... | The first line of input contains an integer *n* — the number of nodes in the tree (1<=≤<=*n*<=≤<=105).
The next *n*<=-<=1 lines contain integers *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*) — the description of the edges of the tree.
It's guaranteed that the given graph is a tree. | Output one integer — the maximum number of edges that Mahmoud and Ehab can add to the tree while fulfilling the conditions. | [
"3\n1 2\n1 3\n",
"5\n1 2\n2 3\n3 4\n4 5\n"
] | [
"0\n",
"2\n"
] | Tree definition: [https://en.wikipedia.org/wiki/Tree_(graph_theory)](https://en.wikipedia.org/wiki/Tree_(graph_theory))
Bipartite graph definition: [https://en.wikipedia.org/wiki/Bipartite_graph](https://en.wikipedia.org/wiki/Bipartite_graph)
In the first test case the only edge that can be added in such a way, that ... | 1,000 | [
{
"input": "3\n1 2\n1 3",
"output": "0"
},
{
"input": "5\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10\n3 8\n6 2\n9 7\n10 1\n3 5\n1 3\n6 7\n5 4\n3 6",
"output": "16"
},
{
"input": "10\n7 6\n2 7\n4 1\n8 5\n9 4\n5 3\n8 7\n10 8\n10 4",
"output": "16"
},
{
"in... | 1,695,281,631 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n = int(input())
g = [[] for i in range(n+1)]
for _ in range(n-1):
u, v = map(int, input().split())
g[u].append(v)
g[v].append(u)
visited = [False for _ in range(n+1)]
def dfs(node, prev):
if prev:
visited[node] = 1
else:
visited[node] = 2
for w in g[node]:
... | Title: Mahmoud and Ehab and the bipartiteness
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a gra... | ```python
n = int(input())
g = [[] for i in range(n+1)]
for _ in range(n-1):
u, v = map(int, input().split())
g[u].append(v)
g[v].append(u)
visited = [False for _ in range(n+1)]
def dfs(node, prev):
if prev:
visited[node] = 1
else:
visited[node] = 2
for w in g[node... | 0 | |
262 | B | Roma and Changing Signs | PROGRAMMING | 1,200 | [
"greedy"
] | null | null | Roma works in a company that sells TVs. Now he has to prepare a report for the last year.
Roma has got a list of the company's incomes. The list is a sequence that consists of *n* integers. The total income of the company is the sum of all integers in sequence. Roma decided to perform exactly *k* changes of signs of s... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=105), showing, how many numbers are in the sequence and how many swaps are to be made.
The second line contains a non-decreasing sequence, consisting of *n* integers *a**i* (|*a**i*|<=≤<=104).
The numbers in the lines are separated by single spaces... | In the single line print the answer to the problem — the maximum total income that we can obtain after exactly *k* changes. | [
"3 2\n-1 -1 1\n",
"3 1\n-1 -1 1\n"
] | [
"3\n",
"1\n"
] | In the first sample we can get sequence [1, 1, 1], thus the total income equals 3.
In the second test, the optimal strategy is to get sequence [-1, 1, 1], thus the total income equals 1. | 1,000 | [
{
"input": "3 2\n-1 -1 1",
"output": "3"
},
{
"input": "3 1\n-1 -1 1",
"output": "1"
},
{
"input": "17 27\n257 320 676 1136 2068 2505 2639 4225 4951 5786 7677 7697 7851 8337 8429 8469 9343",
"output": "81852"
},
{
"input": "69 28\n-9822 -9264 -9253 -9221 -9139 -9126 -9096 -89... | 1,637,566,061 | 2,147,483,647 | PyPy 3 | OK | TESTS | 56 | 248 | 8,294,400 | import sys,os,io
import math
from bisect import bisect_left as bl
from collections import defaultdict
def ii():
return int(input())
def li():
return list(map(int,input().split()))
if(os.path.exists('input.txt')):
sys.stdin = open("input.txt","r") ; sys.stdout = open("output.txt","w")
else:
... | Title: Roma and Changing Signs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Roma works in a company that sells TVs. Now he has to prepare a report for the last year.
Roma has got a list of the company's incomes. The list is a sequence that consists of *n* integers. The total income of ... | ```python
import sys,os,io
import math
from bisect import bisect_left as bl
from collections import defaultdict
def ii():
return int(input())
def li():
return list(map(int,input().split()))
if(os.path.exists('input.txt')):
sys.stdin = open("input.txt","r") ; sys.stdout = open("output.txt","w")
e... | 3 | |
462 | B | Appleman and Card Game | PROGRAMMING | 1,300 | [
"greedy"
] | null | null | Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally, for each Toastman's card *i* you should calculate how much Toastman's cards have the letter equal to lette... | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The next line contains *n* uppercase letters without spaces — the *i*-th letter describes the *i*-th card of the Appleman. | Print a single integer – the answer to the problem. | [
"15 10\nDZFDFZDFDDDDDDF\n",
"6 4\nYJSNPI\n"
] | [
"82\n",
"4\n"
] | In the first test example Toastman can choose nine cards with letter D and one additional card with any letter. For each card with D he will get 9 coins and for the additional card he will get 1 coin. | 1,000 | [
{
"input": "15 10\nDZFDFZDFDDDDDDF",
"output": "82"
},
{
"input": "6 4\nYJSNPI",
"output": "4"
},
{
"input": "5 3\nAOWBY",
"output": "3"
},
{
"input": "1 1\nV",
"output": "1"
},
{
"input": "2 1\nWT",
"output": "1"
},
{
"input": "2 2\nBL",
"output":... | 1,620,149,153 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 77 | 409,600 | from collections import *
n,k=map(int,input().split())
s=input()
l=dict(Counter(s))
l=sorted(l.items(),reverse=True,key=lambda x:(x[1],x[0]))
c=0
for x,y in l:
if k>=y:
k=k-y
c=c+y*y
else:
c=c+k*k
break
print(c)
| Title: Appleman and Card Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally... | ```python
from collections import *
n,k=map(int,input().split())
s=input()
l=dict(Counter(s))
l=sorted(l.items(),reverse=True,key=lambda x:(x[1],x[0]))
c=0
for x,y in l:
if k>=y:
k=k-y
c=c+y*y
else:
c=c+k*k
break
print(c)
``` | 3 | |
383 | C | Propagating tree | PROGRAMMING | 2,000 | [
"data structures",
"dfs and similar",
"trees"
] | null | null | Iahub likes trees very much. Recently he discovered an interesting tree named propagating tree. The tree consists of *n* nodes numbered from 1 to *n*, each node *i* having an initial value *a**i*. The root of the tree is node 1.
This tree has a special property: when a value *val* is added to a value of node *i*, the ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200000). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=1000). Each of the next *n*–1 lines contains two integers *v**i* and *u**i* (1<=≤<=*v**i*,<=*u**i*<=≤<=*n*), meaning that there is an edge between nodes *v**i* a... | For each query of type two (print the value of node *x*) you must print the answer to the query on a separate line. The queries must be answered in the order given in the input. | [
"5 5\n1 2 1 1 2\n1 2\n1 3\n2 4\n2 5\n1 2 3\n1 1 2\n2 1\n2 2\n2 4\n"
] | [
"3\n3\n0\n"
] | The values of the nodes are [1, 2, 1, 1, 2] at the beginning.
Then value 3 is added to node 2. It propagates and value -3 is added to it's sons, node 4 and node 5. Then it cannot propagate any more. So the values of the nodes are [1, 5, 1, - 2, - 1].
Then value 2 is added to node 1. It propagates and value -2 is ad... | 1,500 | [
{
"input": "5 5\n1 2 1 1 2\n1 2\n1 3\n2 4\n2 5\n1 2 3\n1 1 2\n2 1\n2 2\n2 4",
"output": "3\n3\n0"
},
{
"input": "10 10\n137 197 856 768 825 894 86 174 218 326\n7 8\n4 7\n8 9\n7 10\n1 2\n2 4\n3 6\n3 5\n2 3\n1 9 624\n2 1\n2 4\n1 6 505\n1 8 467\n1 3 643\n2 1\n1 8 631\n2 4\n1 7 244",
"output": "137\... | 1,675,839,000 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 54 | 1,107 | 130,252,800 | class BIT():
"""区間加算、一点取得クエリをそれぞれO(logN)で応えるデータ構造を構築する
add: 区間[begin, end)にvalを加える
get_val: i番目(0-indexed)の値を求める
"""
def __init__(self, n):
self.n = n
self.bit = [0] * (n + 1)
def get_val(self, i):
i = i + 1
s = 0
while i <= self.n:
... | Title: Propagating tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes trees very much. Recently he discovered an interesting tree named propagating tree. The tree consists of *n* nodes numbered from 1 to *n*, each node *i* having an initial value *a**i*. The root of the tree ... | ```python
class BIT():
"""区間加算、一点取得クエリをそれぞれO(logN)で応えるデータ構造を構築する
add: 区間[begin, end)にvalを加える
get_val: i番目(0-indexed)の値を求める
"""
def __init__(self, n):
self.n = n
self.bit = [0] * (n + 1)
def get_val(self, i):
i = i + 1
s = 0
while i <= self.n:
... | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Pupils decided to go to amusement park. Some of them were with parents. In total, *n* people came to the park and they all want to get to the most extreme attraction and roll on it exactly once.
Tickets for group of *x* people are sold on the attraction, there should be at least one adult in each group (it is possible... | The first line contains three integers *n*, *c*1 and *c*2 (1<=≤<=*n*<=≤<=200<=000, 1<=≤<=*c*1,<=*c*2<=≤<=107) — the number of visitors and parameters for determining the ticket prices for a group.
The second line contains the string of length *n*, which consists of zeros and ones. If the *i*-th symbol of the string is... | Print the minimum price of visiting the most extreme attraction for all pupils and their parents. Each of them should roll on the attraction exactly once. | [
"3 4 1\n011\n",
"4 7 2\n1101\n"
] | [
"8\n",
"18\n"
] | In the first test one group of three people should go to the attraction. Then they have to pay 4 + 1 * (3 - 1)<sup class="upper-index">2</sup> = 8.
In the second test it is better to go to the attraction in two groups. The first group should consist of two adults (for example, the first and the second person), the sec... | 0 | [
{
"input": "3 4 1\n011",
"output": "8"
},
{
"input": "4 7 2\n1101",
"output": "18"
},
{
"input": "1 2 2\n1",
"output": "2"
},
{
"input": "2 3 10\n01",
"output": "13"
},
{
"input": "5 10 3\n11100",
"output": "35"
},
{
"input": "10 2 2\n1111101111",
... | 1,491,502,834 | 2,147,483,647 | PyPy 3 | OK | TESTS | 31 | 202 | 27,340,800 | # import sys
i=lambda:map(int,input().split())
n,c1,c2=i()
s=input()
co=0
for j in range(0 , n):
if(s[j]=='1'):
co=co+1
# ans=sys.maxsize
ans = c1*1
ans += c2*(n-1)*(n-1)*1
for j in range(2,co+1):
a=int(c1*j)
b=int((n-j)/j)
c=int((n-j)%j)
a=int(a+(c2*(b*b)*(j-c))+(c2*(b+1)*(b+1)*c))
ans=min(a,an... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pupils decided to go to amusement park. Some of them were with parents. In total, *n* people came to the park and they all want to get to the most extreme attraction and roll on it exactly once.
Tickets for group of *x* people ar... | ```python
# import sys
i=lambda:map(int,input().split())
n,c1,c2=i()
s=input()
co=0
for j in range(0 , n):
if(s[j]=='1'):
co=co+1
# ans=sys.maxsize
ans = c1*1
ans += c2*(n-1)*(n-1)*1
for j in range(2,co+1):
a=int(c1*j)
b=int((n-j)/j)
c=int((n-j)%j)
a=int(a+(c2*(b*b)*(j-c))+(c2*(b+1)*(b+1)*c))
an... | 3 | |
928 | C | Dependency management | PROGRAMMING | 1,900 | [
"*special",
"graphs",
"implementation"
] | null | null | Polycarp is currently developing a project in Vaja language and using a popular dependency management system called Vamen. From Vamen's point of view both Vaja project and libraries are treated projects for simplicity.
A project in Vaja has its own uniqie non-empty name consisting of lowercase latin letters with lengt... | The first line contains an only integer *n* (1<=≤<=*n*<=≤<=1<=000) — the number of projects in Vaja.
The following lines contain the project descriptions. Each project is described by a line consisting of its name and version separated by space. The next line gives the number of direct dependencies (from 0 to *n*<=-<=... | Output all Polycarp's project's dependencies in lexicographical order. | [
"4\na 3\n2\nb 1\nc 1\n \nb 2\n0\n \nb 1\n1\nb 2\n \nc 1\n1\nb 2\n",
"9\ncodehorses 5\n3\nwebfrmk 6\nmashadb 1\nmashadb 2\n \ncommons 2\n0\n \nmashadb 3\n0\n \nwebfrmk 6\n2\nmashadb 3\ncommons 2\n \nextra 4\n1\nextra 3\n \nextra 3\n0\n \nextra 1\n0\n \nmashadb 1\n1\nextra 3\n \nmashadb 2\n1\nextra 1\n",
"3\nabc ... | [
"2\nb 1\nc 1\n",
"4\ncommons 2\nextra 1\nmashadb 2\nwebfrmk 6\n",
"1\ncba 2\n"
] | The first sample is given in the pic below. Arrow from *A* to *B* means that *B* directly depends on *A*. Projects that Polycarp's project «a» (version 3) depends on are painted black.
The second sample is again given in the pic below. Arrow from *A* to *B* means that *B* directly depends on *A*. Projects that Polycar... | 2,000 | [
{
"input": "4\na 3\n2\nb 1\nc 1\n\nb 2\n0\n\nb 1\n1\nb 2\n\nc 1\n1\nb 2",
"output": "2\nb 1\nc 1"
},
{
"input": "9\ncodehorses 5\n3\nwebfrmk 6\nmashadb 1\nmashadb 2\n\ncommons 2\n0\n\nmashadb 3\n0\n\nwebfrmk 6\n2\nmashadb 3\ncommons 2\n\nextra 4\n1\nextra 3\n\nextra 3\n0\n\nextra 1\n0\n\nmashadb 1\n... | 1,519,567,700 | 81,200 | PyPy 3 | WRONG_ANSWER | PRETESTS | 0 | 62 | 19,968,000 | # python3
# utf-8
projs_nr = int(input())
proj___deps = {}
start_proj = None
for proj_idx in range(projs_nr):
name, version = input().split()
version = int(version)
deps_nr = int(input())
proj = (name, version)
if proj_idx == 0:
start_proj = proj
proj___deps[proj] = []
for dep_idx ... | Title: Dependency management
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is currently developing a project in Vaja language and using a popular dependency management system called Vamen. From Vamen's point of view both Vaja project and libraries are treated projects for simpli... | ```python
# python3
# utf-8
projs_nr = int(input())
proj___deps = {}
start_proj = None
for proj_idx in range(projs_nr):
name, version = input().split()
version = int(version)
deps_nr = int(input())
proj = (name, version)
if proj_idx == 0:
start_proj = proj
proj___deps[proj] = []
fo... | 0 | |
798 | A | Mike and palindrome | PROGRAMMING | 1,000 | [
"brute force",
"constructive algorithms",
"strings"
] | null | null | Mike has a string *s* consisting of only lowercase English letters. He wants to change exactly one character from the string so that the resulting one is a palindrome.
A palindrome is a string that reads the same backward as forward, for example strings "z", "aaa", "aba", "abccba" are palindromes, but strings "codefo... | The first and single line contains string *s* (1<=≤<=|*s*|<=≤<=15). | Print "YES" (without quotes) if Mike can change exactly one character so that the resulting string is palindrome or "NO" (without quotes) otherwise. | [
"abccaa\n",
"abbcca\n",
"abcda\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "abccaa",
"output": "YES"
},
{
"input": "abbcca",
"output": "NO"
},
{
"input": "abcda",
"output": "YES"
},
{
"input": "kyw",
"output": "YES"
},
{
"input": "fccf",
"output": "NO"
},
{
"input": "mnlm",
"output": "YES"
},
{
"input":... | 1,671,299,483 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | s = str(input())
l = len(s)
for i in range(l):
if s[i] != s[(l - 1) - i]:
print("no")
break
else:
print("yes")
| Title: Mike and palindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mike has a string *s* consisting of only lowercase English letters. He wants to change exactly one character from the string so that the resulting one is a palindrome.
A palindrome is a string that reads the same ... | ```python
s = str(input())
l = len(s)
for i in range(l):
if s[i] != s[(l - 1) - i]:
print("no")
break
else:
print("yes")
``` | 0 | |
770 | A | New Password | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
- the length of the password must be equal to *n*, - the password should cons... | The first line contains two positive integers *n* and *k* (2<=≤<=*n*<=≤<=100, 2<=≤<=*k*<=≤<=*min*(*n*,<=26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists. | Print any password which satisfies all conditions given by Innokentiy. | [
"4 3\n",
"6 6\n",
"5 2\n"
] | [
"java\n",
"python\n",
"phphp\n"
] | In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letter... | 500 | [
{
"input": "4 3",
"output": "abca"
},
{
"input": "6 6",
"output": "abcdef"
},
{
"input": "5 2",
"output": "ababa"
},
{
"input": "3 2",
"output": "aba"
},
{
"input": "10 2",
"output": "ababababab"
},
{
"input": "26 13",
"output": "abcdefghijklmabcde... | 1,626,121,707 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 140 | 23,040,000 | from itertools import product
from math import ceil
import string
def binary_table(string_with_all_characters, length_to_make):
return [''.join(x) for x in product(string_with_all_characters, repeat=length_to_make)]
def all_possible_substrings(string):
return [int(string[i: j]) for i in range(len(st... | Title: New Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the foll... | ```python
from itertools import product
from math import ceil
import string
def binary_table(string_with_all_characters, length_to_make):
return [''.join(x) for x in product(string_with_all_characters, repeat=length_to_make)]
def all_possible_substrings(string):
return [int(string[i: j]) for i in ra... | -1 | |
1,009 | B | Minimum Ternary String | PROGRAMMING | 1,400 | [
"greedy",
"implementation"
] | null | null | You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecutive) characters '1' and '2' (i.e. replace "12" with "21" or vice versa).
For e... | The first line of the input contains the string $s$ consisting only of characters '0', '1' and '2', its length is between $1$ and $10^5$ (inclusive). | Print a single string — the minimum possible (lexicographically) string you can obtain by using the swaps described above arbitrary number of times (possibly, zero). | [
"100210\n",
"11222121\n",
"20\n"
] | [
"001120\n",
"11112222\n",
"20\n"
] | none | 0 | [
{
"input": "100210",
"output": "001120"
},
{
"input": "11222121",
"output": "11112222"
},
{
"input": "20",
"output": "20"
},
{
"input": "1002",
"output": "0012"
},
{
"input": "10",
"output": "01"
},
{
"input": "000021",
"output": "000012"
},
{
... | 1,532,610,311 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 5 | 124 | 307,200 | s, t, k = input(), '', 0
for i in s:
if i != '1':
t += i
else:
k += 1
i = t.index('2')
print (t[:i] + '1' * k + t[i:]) | Title: Minimum Ternary String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) ... | ```python
s, t, k = input(), '', 0
for i in s:
if i != '1':
t += i
else:
k += 1
i = t.index('2')
print (t[:i] + '1' * k + t[i:])
``` | -1 | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,696,801,733 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 154 | 2,764,800 | t=[0]*4
necessity=0
for i in range (4):
x=int(input())
if x in t:
necessity+=1
t[i]=x
print(necessity) | Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
t=[0]*4
necessity=0
for i in range (4):
x=int(input())
if x in t:
necessity+=1
t[i]=x
print(necessity)
``` | -1 | |
108 | A | Palindromic Times | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | A. Palindromic Times | 2 | 256 | Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling asleep, he was staring at the digital watch around Saher's wrist. He noticed that the digits on th... | The first and only line of the input starts with a string with the format "HH:MM" where "HH" is from "00" to "23" and "MM" is from "00" to "59". Both "HH" and "MM" have exactly two digits. | Print the palindromic time of day that comes soonest after the time given in the input. If the input time is palindromic, output the soonest palindromic time after the input time. | [
"12:21\n",
"23:59\n"
] | [
"13:31\n",
"00:00\n"
] | none | 500 | [
{
"input": "12:21",
"output": "13:31"
},
{
"input": "23:59",
"output": "00:00"
},
{
"input": "15:51",
"output": "20:02"
},
{
"input": "10:44",
"output": "11:11"
},
{
"input": "04:02",
"output": "04:40"
},
{
"input": "02:11",
"output": "02:20"
},
... | 1,679,373,415 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 92 | 0 | h,m=map(int,input().split(':'))
while 1:
m+=1
if m==60:h+=1;m=0
if h==24:h=0
a=str(h);a='0'*(2-len(a))+a
b=str(m);a+=':'+'0'*(2-len(b))+b
if(a==a[::-1]):print(a);exit()
| Title: Palindromic Times
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling... | ```python
h,m=map(int,input().split(':'))
while 1:
m+=1
if m==60:h+=1;m=0
if h==24:h=0
a=str(h);a='0'*(2-len(a))+a
b=str(m);a+=':'+'0'*(2-len(b))+b
if(a==a[::-1]):print(a);exit()
``` | 3.977 |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,645,457,989 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | x=int(input())
y=int(input())
z=(x*y)/2
print(z) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
x=int(input())
y=int(input())
z=(x*y)/2
print(z)
``` | -1 |
907 | A | Masha and Bears | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son bear can climb into the smallest car and he likes it. It's known that the largest car is strictly larg... | You are given four integers *V*1, *V*2, *V*3, *V**m*(1<=≤<=*V**i*<=≤<=100) — sizes of father bear, mother bear, son bear and Masha, respectively. It's guaranteed that *V*1<=><=*V*2<=><=*V*3. | Output three integers — sizes of father bear's car, mother bear's car and son bear's car, respectively.
If there are multiple possible solutions, print any.
If there is no solution, print "-1" (without quotes). | [
"50 30 10 10\n",
"100 50 10 21\n"
] | [
"50\n30\n10\n",
"-1\n"
] | In first test case all conditions for cars' sizes are satisfied.
In second test case there is no answer, because Masha should be able to climb into smallest car (so size of smallest car in not less than 21), but son bear should like it, so maximum possible size of it is 20. | 500 | [
{
"input": "50 30 10 10",
"output": "50\n30\n10"
},
{
"input": "100 50 10 21",
"output": "-1"
},
{
"input": "100 50 19 10",
"output": "100\n50\n19"
},
{
"input": "99 50 25 49",
"output": "100\n99\n49"
},
{
"input": "3 2 1 1",
"output": "4\n3\n1"
},
{
"... | 1,612,132,770 | 570 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 93 | 0 | V = list(map(int, input().split()))
R = [0]*3
L = [0]*3
for i in range(3):
if i != 2:
R[i] = 2*V[i]
L[i] = max(V[i], 2*V[3]+1)
else:
R[i] = min(V[i], V[3])
L[i] = max(V[i], V[3])
#print(R)
#print(L)
ans = [-1]*3
for i in range(3):
if R[i] >= L[i]:
ans[i] = L[i]
el... | Title: Masha and Bears
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son b... | ```python
V = list(map(int, input().split()))
R = [0]*3
L = [0]*3
for i in range(3):
if i != 2:
R[i] = 2*V[i]
L[i] = max(V[i], 2*V[3]+1)
else:
R[i] = min(V[i], V[3])
L[i] = max(V[i], V[3])
#print(R)
#print(L)
ans = [-1]*3
for i in range(3):
if R[i] >= L[i]:
ans[i] = L... | 0 | |
88 | B | Keyboard | PROGRAMMING | 1,500 | [
"implementation"
] | B. Keyboard | 1 | 256 | Vasya learns to type. He has an unusual keyboard at his disposal: it is rectangular and it has *n* rows of keys containing *m* keys in each row. Besides, the keys are of two types. Some of the keys have lowercase Latin letters on them and some of the keys work like the "Shift" key on standard keyboards, that is, they m... | The first line contains three integers *n*, *m*, *x* (1<=≤<=*n*,<=*m*<=≤<=30,<=1<=≤<=*x*<=≤<=50).
Next *n* lines contain descriptions of all the keyboard keys. Each line contains the descriptions of exactly *m* keys, without spaces. The letter keys are marked with the corresponding lowercase letters. The "Shift" keys ... | If Vasya can type the text, then print the minimum number of times he will have to use his other hand. Otherwise, print "-1" (without the quotes). | [
"2 2 1\nab\ncd\n1\nA\n",
"2 2 1\nab\ncd\n1\ne\n",
"2 2 1\nab\ncS\n5\nabcBA\n",
"3 9 4\nqwertyuio\nasdfghjkl\nSzxcvbnmS\n35\nTheQuIcKbRoWnFOXjummsovertHeLazYDOG\n"
] | [
"-1\n",
"-1\n",
"1\n",
"2\n"
] | In the first sample the symbol "A" is impossible to print as there's no "Shift" key on the keyboard.
In the second sample the symbol "e" is impossible to print as there's no such key on the keyboard.
In the fourth sample the symbols "T", "G" are impossible to print with one hand. The other letters that are on the key... | 1,000 | [
{
"input": "2 2 1\nab\ncd\n1\nA",
"output": "-1"
},
{
"input": "2 2 1\nab\ncd\n1\ne",
"output": "-1"
},
{
"input": "2 2 1\nab\ncS\n5\nabcBA",
"output": "1"
},
{
"input": "3 9 4\nqwertyuio\nasdfghjkl\nSzxcvbnmS\n35\nTheQuIcKbRoWnFOXjummsovertHeLazYDOG",
"output": "2"
},
... | 1,651,276,535 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 12 | 46 | 0 | import math
n, m, x = map(int, input().split())
dec={}
S=[]
for i in range(n):
s=input()
for j in range(m):
if s[j]=='S':
S.append([i+1,j+1])
else:
dec[s[j]]=[i+1,j+1]
dec[s[j].upper()] = [i + 1, j + 1]
k=int(input())
tst=input()
f = 1
count... | Title: Keyboard
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya learns to type. He has an unusual keyboard at his disposal: it is rectangular and it has *n* rows of keys containing *m* keys in each row. Besides, the keys are of two types. Some of the keys have lowercase Latin letters on ... | ```python
import math
n, m, x = map(int, input().split())
dec={}
S=[]
for i in range(n):
s=input()
for j in range(m):
if s[j]=='S':
S.append([i+1,j+1])
else:
dec[s[j]]=[i+1,j+1]
dec[s[j].upper()] = [i + 1, j + 1]
k=int(input())
tst=input()
f ... | 0 |
424 | A | Squats | PROGRAMMING | 900 | [
"implementation"
] | null | null | Pasha has many hamsters and he makes them work out. Today, *n* hamsters (*n* is even) came to work out. The hamsters lined up and each hamster either sat down or stood up.
For another exercise, Pasha needs exactly hamsters to stand up and the other hamsters to sit down. In one minute, Pasha can make some hamster ethe... | The first line contains integer *n* (2<=≤<=*n*<=≤<=200; *n* is even). The next line contains *n* characters without spaces. These characters describe the hamsters' position: the *i*-th character equals 'X', if the *i*-th hamster in the row is standing, and 'x', if he is sitting. | In the first line, print a single integer — the minimum required number of minutes. In the second line, print a string that describes the hamsters' position after Pasha makes the required changes. If there are multiple optimal positions, print any of them. | [
"4\nxxXx\n",
"2\nXX\n",
"6\nxXXxXx\n"
] | [
"1\nXxXx\n",
"1\nxX\n",
"0\nxXXxXx\n"
] | none | 500 | [
{
"input": "4\nxxXx",
"output": "1\nXxXx"
},
{
"input": "2\nXX",
"output": "1\nxX"
},
{
"input": "6\nxXXxXx",
"output": "0\nxXXxXx"
},
{
"input": "4\nxXXX",
"output": "1\nxxXX"
},
{
"input": "2\nXx",
"output": "0\nXx"
},
{
"input": "22\nXXxXXxxXxXxXXXX... | 1,501,350,965 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 62 | 4,608,000 | n = int(input())
global s
s = input()
a, b = s.count("x"), s.count("X")
p = abs(a - b) // 2
def change(a, b):
global s
q = 0
for x in range(n):
if q == p:
break
if s[x] == a:
s = s[:x] + b + s[x + 1:]
q += 1
print(p)
if a > b:
change("x... | Title: Squats
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has many hamsters and he makes them work out. Today, *n* hamsters (*n* is even) came to work out. The hamsters lined up and each hamster either sat down or stood up.
For another exercise, Pasha needs exactly hamsters to ... | ```python
n = int(input())
global s
s = input()
a, b = s.count("x"), s.count("X")
p = abs(a - b) // 2
def change(a, b):
global s
q = 0
for x in range(n):
if q == p:
break
if s[x] == a:
s = s[:x] + b + s[x + 1:]
q += 1
print(p)
if a > b:
... | 3 | |
699 | B | One Bomb | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | You are given a description of a depot. It is a rectangular checkered field of *n*<=×<=*m* size. Each cell in a field can be empty (".") or it can be occupied by a wall ("*").
You have one bomb. If you lay the bomb at the cell (*x*,<=*y*), then after triggering it will wipe out all walls in the row *x* and all walls ... | The first line contains two positive integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and columns in the depot field.
The next *n* lines contain *m* symbols "." and "*" each — the description of the field. *j*-th symbol in *i*-th of them stands for cell (*i*,<=*j*). If the symbol is equal to ".", ... | If it is impossible to wipe out all walls by placing and triggering exactly one bomb, then print "NO" in the first line (without quotes).
Otherwise print "YES" (without quotes) in the first line and two integers in the second line — the coordinates of the cell at which the bomb should be laid. If there are multiple an... | [
"3 4\n.*..\n....\n.*..\n",
"3 3\n..*\n.*.\n*..\n",
"6 5\n..*..\n..*..\n*****\n..*..\n..*..\n..*..\n"
] | [
"YES\n1 2\n",
"NO\n",
"YES\n3 3\n"
] | none | 1,000 | [
{
"input": "3 4\n.*..\n....\n.*..",
"output": "YES\n1 2"
},
{
"input": "3 3\n..*\n.*.\n*..",
"output": "NO"
},
{
"input": "6 5\n..*..\n..*..\n*****\n..*..\n..*..\n..*..",
"output": "YES\n3 3"
},
{
"input": "1 10\n**********",
"output": "YES\n1 1"
},
{
"input": "10... | 1,571,120,230 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 109 | 0 | n, m = map(int, input().split())
counter = 0
b = -1
for i in range(n):
a = input()
x, y = a.find("*"), a.count("*")
if b != x + 1 and y == 1 and b != -1:
exit(print("NO"))
if y > 1 and counter != 0:
exit(print("NO"))
if y > 1:
counter = i + 1
if y == 1:
... | Title: One Bomb
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a description of a depot. It is a rectangular checkered field of *n*<=×<=*m* size. Each cell in a field can be empty (".") or it can be occupied by a wall ("*").
You have one bomb. If you lay the bomb at the ce... | ```python
n, m = map(int, input().split())
counter = 0
b = -1
for i in range(n):
a = input()
x, y = a.find("*"), a.count("*")
if b != x + 1 and y == 1 and b != -1:
exit(print("NO"))
if y > 1 and counter != 0:
exit(print("NO"))
if y > 1:
counter = i + 1
if y ==... | 0 | |
225 | B | Well-known Numbers | PROGRAMMING | 1,600 | [
"binary search",
"greedy",
"number theory"
] | null | null | Numbers *k*-bonacci (*k* is integer, *k*<=><=1) are a generalization of Fibonacci numbers and are determined as follows:
- *F*(*k*,<=*n*)<==<=0, for integer *n*, 1<=≤<=*n*<=<<=*k*; - *F*(*k*,<=*k*)<==<=1; - *F*(*k*,<=*n*)<==<=*F*(*k*,<=*n*<=-<=1)<=+<=*F*(*k*,<=*n*<=-<=2)<=+<=...<=+<=*F*(*k*,<=*n*<=-<=*k*), fo... | The first line contains two integers *s* and *k* (1<=≤<=*s*,<=*k*<=≤<=109; *k*<=><=1). | In the first line print an integer *m* (*m*<=≥<=2) that shows how many numbers are in the found representation. In the second line print *m* distinct integers *a*1,<=*a*2,<=...,<=*a**m*. Each printed integer should be a *k*-bonacci number. The sum of printed integers must equal *s*.
It is guaranteed that the answer ex... | [
"5 2\n",
"21 5\n"
] | [
"3\n0 2 3\n",
"3\n4 1 16\n"
] | none | 1,000 | [
{
"input": "5 2",
"output": "3\n0 2 3"
},
{
"input": "21 5",
"output": "3\n4 1 16"
},
{
"input": "1 1000",
"output": "2\n1 0 "
},
{
"input": "1000000000 1000000000",
"output": "14\n536870912 268435456 134217728 33554432 16777216 8388608 1048576 524288 131072 32768 16384 2... | 1,580,751,142 | 6,742 | PyPy 3 | OK | TESTS | 70 | 498 | 14,131,200 | from bisect import bisect_left as bl
from bisect import bisect_right as br
import heapq
import math
from collections import *
from functools import reduce,cmp_to_key
import sys
input = sys.stdin.readline
# M = mod = 998244353
# def factors(n):return sorted(set(reduce(list.__add__, ([i, n//i] for i in range(... | Title: Well-known Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Numbers *k*-bonacci (*k* is integer, *k*<=><=1) are a generalization of Fibonacci numbers and are determined as follows:
- *F*(*k*,<=*n*)<==<=0, for integer *n*, 1<=≤<=*n*<=<<=*k*; - *F*(*k*,<=*k*)<==<=1; - ... | ```python
from bisect import bisect_left as bl
from bisect import bisect_right as br
import heapq
import math
from collections import *
from functools import reduce,cmp_to_key
import sys
input = sys.stdin.readline
# M = mod = 998244353
# def factors(n):return sorted(set(reduce(list.__add__, ([i, n//i] for i... | 3 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,602,956,622 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | /******** All Required Header Files ********/
#include <iostream>
#include <vector>
#include <set>
#include <map>
#include <algorithm>
#include <string>
/******** For Loops ********/
#define rep(i,n) for(int i=0;i<(n);i++)
/******** Using ********/
using namespace std;
/******** Type Defs ********/
type... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
/******** All Required Header Files ********/
#include <iostream>
#include <vector>
#include <set>
#include <map>
#include <algorithm>
#include <string>
/******** For Loops ********/
#define rep(i,n) for(int i=0;i<(n);i++)
/******** Using ********/
using namespace std;
/******** Type Defs ****... | -1 |
912 | B | New Year's Eve | PROGRAMMING | 1,300 | [
"bitmasks",
"constructive algorithms",
"number theory"
] | null | null | Since Grisha behaved well last year, at New Year's Eve he was visited by Ded Moroz who brought an enormous bag of gifts with him! The bag contains *n* sweet candies from the good ol' bakery, each labeled from 1 to *n* corresponding to its tastiness. No two candies have the same tastiness.
The choice of candies has a d... | The sole string contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=1018). | Output one number — the largest possible xor-sum. | [
"4 3\n",
"6 6\n"
] | [
"7\n",
"7\n"
] | In the first sample case, one optimal answer is 1, 2 and 4, giving the xor-sum of 7.
In the second sample case, one can, for example, take all six candies and obtain the xor-sum of 7. | 1,000 | [
{
"input": "4 3",
"output": "7"
},
{
"input": "6 6",
"output": "7"
},
{
"input": "2 2",
"output": "3"
},
{
"input": "1022 10",
"output": "1023"
},
{
"input": "415853337373441 52",
"output": "562949953421311"
},
{
"input": "75 12",
"output": "127"
... | 1,537,293,229 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 19 | 124 | 0 | from math import log2
str = input('')
lst = [int(s) for s in str.split() if s.isdigit()]
n = lst[0]
print(2 ** (int(log2(n)) + 1) - 1)
| Title: New Year's Eve
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Since Grisha behaved well last year, at New Year's Eve he was visited by Ded Moroz who brought an enormous bag of gifts with him! The bag contains *n* sweet candies from the good ol' bakery, each labeled from 1 to *n* co... | ```python
from math import log2
str = input('')
lst = [int(s) for s in str.split() if s.isdigit()]
n = lst[0]
print(2 ** (int(log2(n)) + 1) - 1)
``` | 0 | |
466 | C | Number of Ways | PROGRAMMING | 1,700 | [
"binary search",
"brute force",
"data structures",
"dp",
"two pointers"
] | null | null | You've got array *a*[1],<=*a*[2],<=...,<=*a*[*n*], consisting of *n* integers. Count the number of ways to split all the elements of the array into three contiguous parts so that the sum of elements in each part is the same.
More formally, you need to find the number of such pairs of indices *i*,<=*j* (2<=≤<=*i*<=≤<=... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5·105), showing how many numbers are in the array. The second line contains *n* integers *a*[1], *a*[2], ..., *a*[*n*] (|*a*[*i*]|<=≤<=<=109) — the elements of array *a*. | Print a single integer — the number of ways to split the array into three parts with the same sum. | [
"5\n1 2 3 0 3\n",
"4\n0 1 -1 0\n",
"2\n4 1\n"
] | [
"2\n",
"1\n",
"0\n"
] | none | 1,500 | [
{
"input": "5\n1 2 3 0 3",
"output": "2"
},
{
"input": "4\n0 1 -1 0",
"output": "1"
},
{
"input": "2\n4 1",
"output": "0"
},
{
"input": "9\n0 0 0 0 0 0 0 0 0",
"output": "28"
},
{
"input": "10\n2 5 -2 2 -3 -2 3 5 -5 -2",
"output": "0"
},
{
"input": "1\... | 1,699,878,658 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 61 | 8,294,400 | n=int(input())
a=[int(i) for i in input().split()]
summ=0
x=0
y=0
sumn=sum(a)
z=int(sumn/3)
if(z!=0):
for i in range(n):
summ+=a[i]
if(summ==z):
x+=1
elif(summ==2*z):
y+=1
print(x*y)
else:
for i in range(n):
summ+=a[i]
if(... | Title: Number of Ways
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got array *a*[1],<=*a*[2],<=...,<=*a*[*n*], consisting of *n* integers. Count the number of ways to split all the elements of the array into three contiguous parts so that the sum of elements in each part is the s... | ```python
n=int(input())
a=[int(i) for i in input().split()]
summ=0
x=0
y=0
sumn=sum(a)
z=int(sumn/3)
if(z!=0):
for i in range(n):
summ+=a[i]
if(summ==z):
x+=1
elif(summ==2*z):
y+=1
print(x*y)
else:
for i in range(n):
summ+=a[i]
... | 0 | |
462 | B | Appleman and Card Game | PROGRAMMING | 1,300 | [
"greedy"
] | null | null | Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally, for each Toastman's card *i* you should calculate how much Toastman's cards have the letter equal to lette... | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The next line contains *n* uppercase letters without spaces — the *i*-th letter describes the *i*-th card of the Appleman. | Print a single integer – the answer to the problem. | [
"15 10\nDZFDFZDFDDDDDDF\n",
"6 4\nYJSNPI\n"
] | [
"82\n",
"4\n"
] | In the first test example Toastman can choose nine cards with letter D and one additional card with any letter. For each card with D he will get 9 coins and for the additional card he will get 1 coin. | 1,000 | [
{
"input": "15 10\nDZFDFZDFDDDDDDF",
"output": "82"
},
{
"input": "6 4\nYJSNPI",
"output": "4"
},
{
"input": "5 3\nAOWBY",
"output": "3"
},
{
"input": "1 1\nV",
"output": "1"
},
{
"input": "2 1\nWT",
"output": "1"
},
{
"input": "2 2\nBL",
"output":... | 1,604,599,571 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 155 | 614,400 | def maxim():
m = 0
index = 0
for i in range(26):
if(not visited[i] and arr[i] > m):
m = arr[i]
index = i
visited[index] = True
return m
n, k = map(int, input().split())
s = input()
arr = [0]*26
for i in range(n):
arr[ord(s[i])-ord("A")] += 1
i = 0
visited = [False]*26
m = maxim()
count... | Title: Appleman and Card Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally... | ```python
def maxim():
m = 0
index = 0
for i in range(26):
if(not visited[i] and arr[i] > m):
m = arr[i]
index = i
visited[index] = True
return m
n, k = map(int, input().split())
s = input()
arr = [0]*26
for i in range(n):
arr[ord(s[i])-ord("A")] += 1
i = 0
visited = [False]*26
m = maxi... | 3 | |
959 | A | Mahmoud and Ehab and the even-odd game | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a* and subtract it from *n* such that:
- 1<=≤<=*a*<=≤<=*n*. - If it's Mahmoud's turn, *a* has to be even, but if it's Ehab'... | The only line contains an integer *n* (1<=≤<=*n*<=≤<=109), the number at the beginning of the game. | Output "Mahmoud" (without quotes) if Mahmoud wins and "Ehab" (without quotes) otherwise. | [
"1\n",
"2\n"
] | [
"Ehab",
"Mahmoud"
] | In the first sample, Mahmoud can't choose any integer *a* initially because there is no positive even integer less than or equal to 1 so Ehab wins.
In the second sample, Mahmoud has to choose *a* = 2 and subtract it from *n*. It's Ehab's turn and *n* = 0. There is no positive odd integer less than or equal to 0 so Mah... | 500 | [
{
"input": "1",
"output": "Ehab"
},
{
"input": "2",
"output": "Mahmoud"
},
{
"input": "10000",
"output": "Mahmoud"
},
{
"input": "33333",
"output": "Ehab"
},
{
"input": "5",
"output": "Ehab"
},
{
"input": "1000000000",
"output": "Mahmoud"
},
{
... | 1,652,559,104 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 4,300,800 | n=input()
if n%2==0:
print('Mahmoud')
else:
print('Ehab')
# Sat May 14 2022 20:08:03 GMT+0000 (Coordinated Universal Time)
# Sat May 14 2022 20:08:09 GMT+0000 (Coordinated Universal Time)
# Sat May 14 2022 20:11:24 GMT+0000 (Coordinated Universal Time)
| Title: Mahmoud and Ehab and the even-odd game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a*... | ```python
n=input()
if n%2==0:
print('Mahmoud')
else:
print('Ehab')
# Sat May 14 2022 20:08:03 GMT+0000 (Coordinated Universal Time)
# Sat May 14 2022 20:08:09 GMT+0000 (Coordinated Universal Time)
# Sat May 14 2022 20:11:24 GMT+0000 (Coordinated Universal Time)
``` | -1 | |
583 | A | Asphalting Roads | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers of the roads that form them.
Sand roads have long been recognized out of date, so the decision was ma... | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of vertical and horizontal roads in the city.
Next *n*2 lines contain the order of intersections in the schedule. The *i*-th of them contains two numbers *h**i*,<=*v**i* (1<=≤<=*h**i*,<=*v**i*<=≤<=*n*), separated by a space, and meaning that the inte... | In the single line print the numbers of the days when road works will be in progress in ascending order. The days are numbered starting from 1. | [
"2\n1 1\n1 2\n2 1\n2 2\n",
"1\n1 1\n"
] | [
"1 4 \n",
"1 \n"
] | In the sample the brigade acts like that:
1. On the first day the brigade comes to the intersection of the 1-st horizontal and the 1-st vertical road. As none of them has been asphalted, the workers asphalt the 1-st vertical and the 1-st horizontal road; 1. On the second day the brigade of the workers comes to the i... | 500 | [
{
"input": "2\n1 1\n1 2\n2 1\n2 2",
"output": "1 4 "
},
{
"input": "1\n1 1",
"output": "1 "
},
{
"input": "2\n1 1\n2 2\n1 2\n2 1",
"output": "1 2 "
},
{
"input": "2\n1 2\n2 2\n2 1\n1 1",
"output": "1 3 "
},
{
"input": "3\n2 2\n1 2\n3 2\n3 3\n1 1\n2 3\n1 3\n3 1\n2 ... | 1,605,500,696 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 108 | 0 | n = int(input())
arr = []
for i in range(1,n**2+1):
h,v = map(int,input().split())
if h==v:
if h not in arr:
arr.append(h)
print(i,end=' ')
else:
if h not in arr and v not in arr:
arr.extend([h,v])
print(i,end= ' ')
| Title: Asphalting Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers ... | ```python
n = int(input())
arr = []
for i in range(1,n**2+1):
h,v = map(int,input().split())
if h==v:
if h not in arr:
arr.append(h)
print(i,end=' ')
else:
if h not in arr and v not in arr:
arr.extend([h,v])
print(i,end= ' ')
``` | 0 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,692,416,768 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | for i in range(int(input())):
word = str(input())
length = len(word)
if (length > 10):
abbreviations = str(length-2)
print(word[0]+abbreviations+word[length-1])
else :
print(word) | Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
for i in range(int(input())):
word = str(input())
length = len(word)
if (length > 10):
abbreviations = str(length-2)
print(word[0]+abbreviations+word[length-1])
else :
print(word)
``` | 3.977 |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,658,994,281 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 21 | 62 | 0 | a, b, c = map(int, input(). split())
q = a + b + c
w = (a * 2) + (b * 2)
e = (a * 2) + (c * 2)
r = (b * 2) + (c * 2)
print(min(q, w, e, r))
| Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
a, b, c = map(int, input(). split())
q = a + b + c
w = (a * 2) + (b * 2)
e = (a * 2) + (c * 2)
r = (b * 2) + (c * 2)
print(min(q, w, e, r))
``` | 3 | |
508 | A | Pasha and Pixels | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row with *m* pixels in each row. Initially, all the pixels are colored white. In one move, Pasha can choos... | The first line of the input contains three integers *n*,<=*m*,<=*k* (1<=≤<=*n*,<=*m*<=≤<=1000, 1<=≤<=*k*<=≤<=105) — the number of rows, the number of columns and the number of moves that Pasha is going to perform.
The next *k* lines contain Pasha's moves in the order he makes them. Each line contains two integers *i*... | If Pasha loses, print the number of the move when the 2<=×<=2 square consisting of black pixels is formed.
If Pasha doesn't lose, that is, no 2<=×<=2 square consisting of black pixels is formed during the given *k* moves, print 0. | [
"2 2 4\n1 1\n1 2\n2 1\n2 2\n",
"2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1\n",
"5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2\n"
] | [
"4\n",
"5\n",
"0\n"
] | none | 500 | [
{
"input": "2 2 4\n1 1\n1 2\n2 1\n2 2",
"output": "4"
},
{
"input": "2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1",
"output": "5"
},
{
"input": "5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2",
"output": "0"
},
{
"input": "3 3 11\n2 1\n3 1\n1 1\n1 3\n1 2\n2 3\n3 3\n3 2\n2 2\n1 3\n3 3",
... | 1,663,827,778 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | n,m,k=map(int,input().split())
a=[[0]*(m+1) for i in range(n+1)]
for x in range(k):
i,j=map(int,input().split())
a[i][j]=1
if a[i][j+1]==1 and a[i+1][j]==1 and a[i+1][j+1]==1:
print(x+1)
break
elif a[i][j-1]==1 and a[i-1][j]==1 and a[i-1][j-1]==1:
print(x+1)
bre... | Title: Pasha and Pixels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row ... | ```python
n,m,k=map(int,input().split())
a=[[0]*(m+1) for i in range(n+1)]
for x in range(k):
i,j=map(int,input().split())
a[i][j]=1
if a[i][j+1]==1 and a[i+1][j]==1 and a[i+1][j+1]==1:
print(x+1)
break
elif a[i][j-1]==1 and a[i-1][j]==1 and a[i-1][j-1]==1:
print(x+1)
... | -1 | |
515 | C | Drazil and Factorial | PROGRAMMING | 1,400 | [
"greedy",
"math",
"sortings"
] | null | null | Drazil is playing a math game with Varda.
Let's define for positive integer *x* as a product of factorials of its digits. For example, .
First, they choose a decimal number *a* consisting of *n* digits that contains at least one digit larger than 1. This number may possibly start with leading zeroes. Then they shoul... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=15) — the number of digits in *a*.
The second line contains *n* digits of *a*. There is at least one digit in *a* that is larger than 1. Number *a* may possibly contain leading zeroes. | Output a maximum possible integer satisfying the conditions above. There should be no zeroes and ones in this number decimal representation. | [
"4\n1234\n",
"3\n555\n"
] | [
"33222\n",
"555\n"
] | In the first case, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/f5a4207f23215fddce977ab5ea9e9d2e7578fb52.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "4\n1234",
"output": "33222"
},
{
"input": "3\n555",
"output": "555"
},
{
"input": "15\n012345781234578",
"output": "7777553333222222222222"
},
{
"input": "1\n8",
"output": "7222"
},
{
"input": "10\n1413472614",
"output": "75333332222222"
},
{
... | 1,656,827,635 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n = int(input())
s=input()
def prime_check(x):
for i in range(2,x//2+1):
if x%i==0:
return False
return True
def fact(x):
l=[]
i = 2
while True:
if not prime_check(x):
if x%i==0:
x//=i
l.append(i)
... | Title: Drazil and Factorial
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Drazil is playing a math game with Varda.
Let's define for positive integer *x* as a product of factorials of its digits. For example, .
First, they choose a decimal number *a* consisting of *n* digits that cont... | ```python
n = int(input())
s=input()
def prime_check(x):
for i in range(2,x//2+1):
if x%i==0:
return False
return True
def fact(x):
l=[]
i = 2
while True:
if not prime_check(x):
if x%i==0:
x//=i
l.append(i)
... | 0 | |
522 | A | Reposts | PROGRAMMING | 1,200 | [
"*special",
"dfs and similar",
"dp",
"graphs",
"trees"
] | null | null | One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
These events are given as a sequence of strings "name1 reposted name2", where name1 is the n... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=200) — the number of reposts. Next follow the reposts in the order they were made. Each of them is written on a single line and looks as "name1 reposted name2". All the names in the input consist of lowercase or uppercase English letters and/or digits and ... | Print a single integer — the maximum length of a repost chain. | [
"5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya\n",
"6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforces reposted Polycarp\n",
"1\nSoMeStRaNgEgUe repos... | [
"6\n",
"2\n",
"2\n"
] | none | 500 | [
{
"input": "5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya",
"output": "6"
},
{
"input": "6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforc... | 1,605,897,076 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 140 | 0 | def add_vertex(graph,v,incidence):
if v not in graph:
incidence[v]=0
graph[v] = []
def add_edge(graph,v1, v2):
graph[v1].append(v2)
su=0
m=0
def dfs(visited, graph, node):
global su,m
if node not in visited:
visited.add(node)
su+=1
m=max(su,m)
for ne... | Title: Reposts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
... | ```python
def add_vertex(graph,v,incidence):
if v not in graph:
incidence[v]=0
graph[v] = []
def add_edge(graph,v1, v2):
graph[v1].append(v2)
su=0
m=0
def dfs(visited, graph, node):
global su,m
if node not in visited:
visited.add(node)
su+=1
m=max(su,m)
... | 0 | |
708 | A | Letters Cyclic Shift | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"implementation",
"strings"
] | null | null | You are given a non-empty string *s* consisting of lowercase English letters. You have to pick exactly one non-empty substring of *s* and shift all its letters 'z' 'y' 'x' 'b' 'a' 'z'. In other words, each character is replaced with the previous character of English alphabet and 'a' is replaced with 'z'.
What is ... | The only line of the input contains the string *s* (1<=≤<=|*s*|<=≤<=100<=000) consisting of lowercase English letters. | Print the lexicographically minimum string that can be obtained from *s* by shifting letters of exactly one non-empty substring. | [
"codeforces\n",
"abacaba\n"
] | [
"bncdenqbdr\n",
"aaacaba\n"
] | String *s* is lexicographically smaller than some other string *t* of the same length if there exists some 1 ≤ *i* ≤ |*s*|, such that *s*<sub class="lower-index">1</sub> = *t*<sub class="lower-index">1</sub>, *s*<sub class="lower-index">2</sub> = *t*<sub class="lower-index">2</sub>, ..., *s*<sub class="lower-index">*i*... | 500 | [
{
"input": "codeforces",
"output": "bncdenqbdr"
},
{
"input": "abacaba",
"output": "aaacaba"
},
{
"input": "babbbabaababbaa",
"output": "aabbbabaababbaa"
},
{
"input": "bcbacaabcababaccccaaaabacbbcbbaa",
"output": "abaacaabcababaccccaaaabacbbcbbaa"
},
{
"input": "... | 1,655,259,905 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 46 | 204,800 | x=input()
a1=x.find('a')
if a1==-1:
for t in x:
print(chr(ord(t)-1),end='')
else:
if a1!=0:
for i in range(a1):
print(chr(ord(x[i])-1),end='')
print(x[a1:]);
else:
if len(x)==1:
print('z')
else:
a2=-1
for ... | Title: Letters Cyclic Shift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a non-empty string *s* consisting of lowercase English letters. You have to pick exactly one non-empty substring of *s* and shift all its letters 'z' 'y' 'x' 'b' 'a' 'z'. In other words, each cha... | ```python
x=input()
a1=x.find('a')
if a1==-1:
for t in x:
print(chr(ord(t)-1),end='')
else:
if a1!=0:
for i in range(a1):
print(chr(ord(x[i])-1),end='')
print(x[a1:]);
else:
if len(x)==1:
print('z')
else:
a2=-1
... | 0 | |
479 | B | Towers | PROGRAMMING | 1,400 | [
"brute force",
"constructive algorithms",
"greedy",
"implementation",
"sortings"
] | null | null | As you know, all the kids in Berland love playing with cubes. Little Petya has *n* towers consisting of cubes of the same size. Tower with number *i* consists of *a**i* cubes stacked one on top of the other. Petya defines the instability of a set of towers as a value equal to the difference between the heights of the h... | The first line contains two space-separated positive integers *n* and *k* (1<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000) — the number of towers in the given set and the maximum number of operations Petya can perform. The second line contains *n* space-separated positive integers *a**i* (1<=≤<=*a**i*<=≤<=104) — the towers' ini... | In the first line print two space-separated non-negative integers *s* and *m* (*m*<=≤<=*k*). The first number is the value of the minimum possible instability that can be obtained after performing at most *k* operations, the second number is the number of operations needed for that.
In the next *m* lines print the des... | [
"3 2\n5 8 5\n",
"3 4\n2 2 4\n",
"5 3\n8 3 2 6 3\n"
] | [
"0 2\n2 1\n2 3\n",
"1 1\n3 2\n",
"3 3\n1 3\n1 2\n1 3\n"
] | In the first sample you need to move the cubes two times, from the second tower to the third one and from the second one to the first one. Then the heights of the towers are all the same and equal to 6. | 1,000 | [
{
"input": "3 2\n5 8 5",
"output": "0 2\n2 1\n2 3"
},
{
"input": "3 4\n2 2 4",
"output": "1 4\n3 1\n1 2\n2 1\n1 2"
},
{
"input": "5 3\n8 3 2 6 3",
"output": "3 3\n1 3\n1 2\n1 3"
},
{
"input": "4 6\n1 10 8 2",
"output": "2 6\n2 1\n2 1\n2 4\n3 1\n2 4\n3 1"
},
{
"inp... | 1,687,668,828 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 45 | 93 | 3,276,800 | import sys
def main():
read = sys.stdin.readline
n, moves = (int(i) for i in read().split())
values = [(int(val), i) for i, val in enumerate(read().split())]
diff = float('inf')
last_move = (-1, -1)
num_moves = 0
history = []
if n == 1:
print(0, 0)
return
... | Title: Towers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you know, all the kids in Berland love playing with cubes. Little Petya has *n* towers consisting of cubes of the same size. Tower with number *i* consists of *a**i* cubes stacked one on top of the other. Petya defines the in... | ```python
import sys
def main():
read = sys.stdin.readline
n, moves = (int(i) for i in read().split())
values = [(int(val), i) for i, val in enumerate(read().split())]
diff = float('inf')
last_move = (-1, -1)
num_moves = 0
history = []
if n == 1:
print(0, 0)
... | 0 | |
479 | A | Expression | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resul... | The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10). | Print the maximum value of the expression that you can obtain. | [
"1\n2\n3\n",
"2\n10\n3\n"
] | [
"9\n",
"60\n"
] | none | 500 | [
{
"input": "1\n2\n3",
"output": "9"
},
{
"input": "2\n10\n3",
"output": "60"
},
{
"input": "1\n1\n1",
"output": "3"
},
{
"input": "1\n2\n1",
"output": "4"
},
{
"input": "10\n10\n10",
"output": "1000"
},
{
"input": "5\n1\n3",
"output": "20"
},
{... | 1,693,598,990 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | a=int(input())
b=int(input())
c=int(input())
d=[]
d.append(a*b*c)
d.append(a*(b+c))
d.append(b*(a+c))
d.append(c*(a+b))
print(max(d)) | Title: Expression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of ... | ```python
a=int(input())
b=int(input())
c=int(input())
d=[]
d.append(a*b*c)
d.append(a*(b+c))
d.append(b*(a+c))
d.append(c*(a+b))
print(max(d))
``` | 0 | |
758 | A | Holiday Of Equality | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens, the welfare of each of them is estimated as the integer in *a**i* burles (burle is the currency in Berl... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100) — the number of citizens in the kingdom.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (0<=≤<=*a**i*<=≤<=106) — the welfare of the *i*-th citizen. | In the only line print the integer *S* — the minimum number of burles which are had to spend. | [
"5\n0 1 2 3 4\n",
"5\n1 1 0 1 1\n",
"3\n1 3 1\n",
"1\n12\n"
] | [
"10",
"1",
"4",
"0"
] | In the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.
In the second example it is enough to give one burle to the third citizen.
In the third example it is necessary to give two burles to the first and the thi... | 500 | [
{
"input": "5\n0 1 2 3 4",
"output": "10"
},
{
"input": "5\n1 1 0 1 1",
"output": "1"
},
{
"input": "3\n1 3 1",
"output": "4"
},
{
"input": "1\n12",
"output": "0"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "14\n52518 718438 358883 462189 853... | 1,682,848,212 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 0 | n = int(input())
lst = [int(i) for i in input().split()]
m = lst[0]
s = 0
for i in range(1, len(lst)):
if lst[i] >= m:
m = lst[i]
for i in range(len(lst)):
s += m - lst[i]
lst[i]+= m - lst[i]
print(s) | Title: Holiday Of Equality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens... | ```python
n = int(input())
lst = [int(i) for i in input().split()]
m = lst[0]
s = 0
for i in range(1, len(lst)):
if lst[i] >= m:
m = lst[i]
for i in range(len(lst)):
s += m - lst[i]
lst[i]+= m - lst[i]
print(s)
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, if there are no such splittings.
An integer greater than 1 is composite, if it is not prim... | The first line contains single integer *q* (1<=≤<=*q*<=≤<=105) — the number of queries.
*q* lines follow. The (*i*<=+<=1)-th line contains single integer *n**i* (1<=≤<=*n**i*<=≤<=109) — the *i*-th query. | For each query print the maximum possible number of summands in a valid splitting to composite summands, or -1, if there are no such splittings. | [
"1\n12\n",
"2\n6\n8\n",
"3\n1\n2\n3\n"
] | [
"3\n",
"1\n2\n",
"-1\n-1\n-1\n"
] | 12 = 4 + 4 + 4 = 4 + 8 = 6 + 6 = 12, but the first splitting has the maximum possible number of summands.
8 = 4 + 4, 6 can't be split into several composite summands.
1, 2, 3 are less than any composite number, so they do not have valid splittings. | 0 | [
{
"input": "1\n12",
"output": "3"
},
{
"input": "2\n6\n8",
"output": "1\n2"
},
{
"input": "3\n1\n2\n3",
"output": "-1\n-1\n-1"
},
{
"input": "6\n1\n2\n3\n5\n7\n11",
"output": "-1\n-1\n-1\n-1\n-1\n-1"
},
{
"input": "3\n4\n6\n9",
"output": "1\n1\n1"
},
{
... | 1,524,503,926 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 77 | 7,065,600 | t = int(input())
while t>0:
a = int(input())
if a == 1 or a ==2 or a == 3 or a == 5 or a == 7 or a == 9 or a == 11:
print(-1)
else:
temp = a%4
if temp == 0:
print(a//4)
elif temp == 1:
print(a//4-2+1)
elif temp == 2:
pri... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, i... | ```python
t = int(input())
while t>0:
a = int(input())
if a == 1 or a ==2 or a == 3 or a == 5 or a == 7 or a == 9 or a == 11:
print(-1)
else:
temp = a%4
if temp == 0:
print(a//4)
elif temp == 1:
print(a//4-2+1)
elif temp == 2:
... | 0 | |
834 | B | The Festive Evening | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | It's the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here are not supposed to be disclosed to the general public: the information can cause discord in the kingdom... | Two integers are given in the first string: the number of guests *n* and the number of guards *k* (1<=≤<=*n*<=≤<=106, 1<=≤<=*k*<=≤<=26).
In the second string, *n* uppercase English letters *s*1*s*2... *s**n* are given, where *s**i* is the entrance used by the *i*-th guest. | Output «YES» if at least one door was unguarded during some time, and «NO» otherwise.
You can output each letter in arbitrary case (upper or lower). | [
"5 1\nAABBB\n",
"5 1\nABABB\n"
] | [
"NO\n",
"YES\n"
] | In the first sample case, the door A is opened right before the first guest's arrival and closed when the second guest enters the castle. The door B is opened right before the arrival of the third guest, and closed after the fifth one arrives. One guard can handle both doors, as the first one is closed before the secon... | 1,000 | [
{
"input": "5 1\nAABBB",
"output": "NO"
},
{
"input": "5 1\nABABB",
"output": "YES"
},
{
"input": "26 1\nABCDEFGHIJKLMNOPQRSTUVWXYZ",
"output": "NO"
},
{
"input": "27 1\nABCDEFGHIJKLMNOPQRSTUVWXYZA",
"output": "YES"
},
{
"input": "5 2\nABACA",
"output": "NO"
... | 1,598,051,060 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 6,656,000 | from sys import stdin
def unguarded_door(n, k, entrances):
open_entrances = set()
for entrance in entrances:
open_entrances.add(entrance)
if len(open_entrances) > k:
return "YES"
return "NO"
if __name__ == "__main__":
n, k = [int(c) for c in stdin.readline().split(" ")]
... | Title: The Festive Evening
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here... | ```python
from sys import stdin
def unguarded_door(n, k, entrances):
open_entrances = set()
for entrance in entrances:
open_entrances.add(entrance)
if len(open_entrances) > k:
return "YES"
return "NO"
if __name__ == "__main__":
n, k = [int(c) for c in stdin.readline().spl... | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Natasha is going to fly on a rocket to Mars and return to Earth. Also, on the way to Mars, she will land on $n - 2$ intermediate planets. Formally: we number all the planets from $1$ to $n$. $1$ is Earth, $n$ is Mars. Natasha will make exactly $n$ flights: $1 \to 2 \to \ldots n \to 1$.
Flight from $x$ to $y$ consists ... | The first line contains a single integer $n$ ($2 \le n \le 1000$) — number of planets.
The second line contains the only integer $m$ ($1 \le m \le 1000$) — weight of the payload.
The third line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 1000$), where $a_i$ is the number of tons, which can be lifted... | If Natasha can fly to Mars through $(n - 2)$ planets and return to Earth, print the minimum mass of fuel (in tons) that Natasha should take. Otherwise, print a single number $-1$.
It is guaranteed, that if Natasha can make a flight, then it takes no more than $10^9$ tons of fuel.
The answer will be considered correct... | [
"2\n12\n11 8\n7 5\n",
"3\n1\n1 4 1\n2 5 3\n",
"6\n2\n4 6 3 3 5 6\n2 6 3 6 5 3\n"
] | [
"10.0000000000\n",
"-1\n",
"85.4800000000\n"
] | Let's consider the first example.
Initially, the mass of a rocket with fuel is $22$ tons.
- At take-off from Earth one ton of fuel can lift off $11$ tons of cargo, so to lift off $22$ tons you need to burn $2$ tons of fuel. Remaining weight of the rocket with fuel is $20$ tons.- During landing on Mars, one ton of fu... | 0 | [
{
"input": "2\n12\n11 8\n7 5",
"output": "10.0000000000"
},
{
"input": "3\n1\n1 4 1\n2 5 3",
"output": "-1"
},
{
"input": "6\n2\n4 6 3 3 5 6\n2 6 3 6 5 3",
"output": "85.4800000000"
},
{
"input": "3\n3\n1 2 1\n2 2 2",
"output": "-1"
},
{
"input": "4\n4\n2 3 2 2\n2... | 1,561,221,802 | 2,842 | PyPy 3 | OK | TESTS | 76 | 140 | 1,331,200 |
n = int(input())
m = float(input())
a = list(map(int, input().strip().split()))
b = list(map(int, input().strip().split()))
if min(a) == 1 or min(b) == 1:
print(-1)
else:
C = 1.0
for i in a:
C *= i
C /= (i-1)
for i in b:
C *= i
C /= (i-1)
print(m * (... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Natasha is going to fly on a rocket to Mars and return to Earth. Also, on the way to Mars, she will land on $n - 2$ intermediate planets. Formally: we number all the planets from $1$ to $n$. $1$ is Earth, $n$ is Mars. Natasha will... | ```python
n = int(input())
m = float(input())
a = list(map(int, input().strip().split()))
b = list(map(int, input().strip().split()))
if min(a) == 1 or min(b) == 1:
print(-1)
else:
C = 1.0
for i in a:
C *= i
C /= (i-1)
for i in b:
C *= i
C /= (i-1)
p... | 3 | |
984 | A | Game | PROGRAMMING | 800 | [
"sortings"
] | null | null | Two players play a game.
Initially there are $n$ integers $a_1, a_2, \ldots, a_n$ written on the board. Each turn a player selects one number and erases it from the board. This continues until there is only one number left on the board, i. e. $n - 1$ turns are made. The first player makes the first move, then players ... | The first line contains one integer $n$ ($1 \le n \le 1000$) — the number of numbers on the board.
The second line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 10^6$). | Print one number that will be left on the board. | [
"3\n2 1 3\n",
"3\n2 2 2\n"
] | [
"2",
"2"
] | In the first sample, the first player erases $3$ and the second erases $1$. $2$ is left on the board.
In the second sample, $2$ is left on the board regardless of the actions of the players. | 500 | [
{
"input": "3\n2 1 3",
"output": "2"
},
{
"input": "3\n2 2 2",
"output": "2"
},
{
"input": "9\n44 53 51 80 5 27 74 79 94",
"output": "53"
},
{
"input": "10\n38 82 23 37 96 4 81 60 67 86",
"output": "60"
},
{
"input": "10\n58 26 77 15 53 81 68 48 22 65",
"outpu... | 1,624,247,740 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 46 | 0 | n=int(input())
a=list(map(int,input().split()))
if n%2==0:
for i in range(0, n//2):
a.remove(max(a))
a.remove(min(a))
else:
for k in range(0, (n-1)//2):
a.remove(max(a))
a.remove(min(a))
print(a[0])
| Title: Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two players play a game.
Initially there are $n$ integers $a_1, a_2, \ldots, a_n$ written on the board. Each turn a player selects one number and erases it from the board. This continues until there is only one number left on the... | ```python
n=int(input())
a=list(map(int,input().split()))
if n%2==0:
for i in range(0, n//2):
a.remove(max(a))
a.remove(min(a))
else:
for k in range(0, (n-1)//2):
a.remove(max(a))
a.remove(min(a))
print(a[0])
``` | -1 | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,539,565,560 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 109 | 0 | D = ["Sheldon", "Leonard", "Penny", "Rajesh", "Howard"]
n = int(input())
if n < 6:
print(D[n-1])
exit()
i = 0
while (1 << i) * 5 < n:
n -= (1 << i) * 5
i += 1
print(D[n // (1 << i)]) | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
D = ["Sheldon", "Leonard", "Penny", "Rajesh", "Howard"]
n = int(input())
if n < 6:
print(D[n-1])
exit()
i = 0
while (1 << i) * 5 < n:
n -= (1 << i) * 5
i += 1
print(D[n // (1 << i)])
``` | 3.9455 |
2 | B | The least round way | PROGRAMMING | 2,000 | [
"dp",
"math"
] | B. The least round way | 2 | 64 | There is a square matrix *n*<=×<=*n*, consisting of non-negative integer numbers. You should find such a way on it that
- starts in the upper left cell of the matrix; - each following cell is to the right or down from the current cell; - the way ends in the bottom right cell.
Moreover, if we multiply together all... | The first line contains an integer number *n* (2<=≤<=*n*<=≤<=1000), *n* is the size of the matrix. Then follow *n* lines containing the matrix elements (non-negative integer numbers not exceeding 109). | In the first line print the least number of trailing zeros. In the second line print the correspondent way itself. | [
"3\n1 2 3\n4 5 6\n7 8 9\n"
] | [
"0\nDDRR\n"
] | none | 0 | [
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "0\nDDRR"
},
{
"input": "2\n7 6\n3 8",
"output": "0\nDR"
},
{
"input": "3\n4 10 5\n10 9 4\n6 5 3",
"output": "1\nDRRD"
},
{
"input": "4\n1 1 9 9\n3 4 7 3\n7 9 1 7\n1 7 1 5",
"output": "0\nDDDRRR"
},
{
"input": "5\n8 3... | 1,467,908,414 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 61 | 204,800 | #!/usr/bin/python
def get25(n):
t = n
c2 = 0
while t%2 == 0:
c2 += 1
t /= 2
t = n
c5 = 0
while t%5 == 0:
c5 += 1
t /= 5
return [c2, c5]
def main():
n = int(input())
a = [None] * n
f = [None] * n
for i in range... | Title: The least round way
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
There is a square matrix *n*<=×<=*n*, consisting of non-negative integer numbers. You should find such a way on it that
- starts in the upper left cell of the matrix; - each following cell is to the right or down fro... | ```python
#!/usr/bin/python
def get25(n):
t = n
c2 = 0
while t%2 == 0:
c2 += 1
t /= 2
t = n
c5 = 0
while t%5 == 0:
c5 += 1
t /= 5
return [c2, c5]
def main():
n = int(input())
a = [None] * n
f = [None] * n
for ... | 0 |
120 | A | Elevator | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"math"
] | null | null | A sky scraper with 1000 floors has been built in the city of N. It has modern superfast elevators to help to travel from one floor to another. Each elevator has two doors, the front one and the back one. If one goes in through the front door, he goes out through the back one and vice versa. The elevator has two rails n... | The first line indicates the door through which the very important person entered the elevator. It contains "front" if the person enters the elevator through the front door and "back" if he entered the elevator through the back door. The second line contains integer *a* (1<=≤<=*a*<=≤<=2) which denotes the number of the... | Print character "R" if the VIP is right-handed or "L" if he is left-handed. | [
"front\n1\n"
] | [
"L\n"
] | none | 0 | [
{
"input": "front\n1",
"output": "L"
},
{
"input": "back\n1",
"output": "R"
},
{
"input": "front\n2",
"output": "R"
},
{
"input": "back\n2",
"output": "L"
}
] | 1,554,385,733 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 374 | 1,024,000 | """""""""""""""""""""""""""""""""""""""""""""
| author: mr.math - Hakimov Rahimjon |
| e-mail: [email protected] |
"""""""""""""""""""""""""""""""""""""""""""""
#inp = open("lepus.in", "r"); input = inp.readline; out = open("lepus.out", "w"); print = out.write
TN = 1
# =====================... | Title: Elevator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A sky scraper with 1000 floors has been built in the city of N. It has modern superfast elevators to help to travel from one floor to another. Each elevator has two doors, the front one and the back one. If one goes in through... | ```python
"""""""""""""""""""""""""""""""""""""""""""""
| author: mr.math - Hakimov Rahimjon |
| e-mail: [email protected] |
"""""""""""""""""""""""""""""""""""""""""""""
#inp = open("lepus.in", "r"); input = inp.readline; out = open("lepus.out", "w"); print = out.write
TN = 1
# ===========... | -1 | |
837 | B | Flag of Berland | PROGRAMMING | 1,600 | [
"brute force",
"implementation"
] | null | null | The flag of Berland is such rectangular field *n*<=×<=*m* that satisfies following conditions:
- Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. - Flag consists of three equal in width and height stripes, parralel to each other and to sides of the flag. Each stripe has exactly one color. ... | The first line contains two integer numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the sizes of the field.
Each of the following *n* lines consisting of *m* characters 'R', 'G' and 'B' — the description of the field. | Print "YES" (without quotes) if the given field corresponds to correct flag of Berland . Otherwise, print "NO" (without quotes). | [
"6 5\nRRRRR\nRRRRR\nBBBBB\nBBBBB\nGGGGG\nGGGGG\n",
"4 3\nBRG\nBRG\nBRG\nBRG\n",
"6 7\nRRRGGGG\nRRRGGGG\nRRRGGGG\nRRRBBBB\nRRRBBBB\nRRRBBBB\n",
"4 4\nRRRR\nRRRR\nBBBB\nGGGG\n"
] | [
"YES\n",
"YES\n",
"NO\n",
"NO\n"
] | The field in the third example doesn't have three parralel stripes.
Rows of the field in the fourth example are parralel to each other and to borders. But they have different heights — 2, 1 and 1. | 0 | [
{
"input": "6 5\nRRRRR\nRRRRR\nBBBBB\nBBBBB\nGGGGG\nGGGGG",
"output": "YES"
},
{
"input": "4 3\nBRG\nBRG\nBRG\nBRG",
"output": "YES"
},
{
"input": "6 7\nRRRGGGG\nRRRGGGG\nRRRGGGG\nRRRBBBB\nRRRBBBB\nRRRBBBB",
"output": "NO"
},
{
"input": "4 4\nRRRR\nRRRR\nBBBB\nGGGG",
"out... | 1,600,576,587 | 687 | PyPy 3 | WRONG_ANSWER | TESTS | 66 | 155 | 1,638,400 | import sys
n, m = map(int, input().split())
flag = [list(input()) for _ in range(n)]
if len(set(flag[0])) > 1:
_flag = [['']*n for _ in range(m)]
for i in range(n):
for j in range(m):
_flag[j][i] = flag[i][j]
flag = _flag
n, m = m, n
if not all(len(set(row)) == 1 for ... | Title: Flag of Berland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The flag of Berland is such rectangular field *n*<=×<=*m* that satisfies following conditions:
- Flag consists of three colors which correspond to letters 'R', 'G' and 'B'. - Flag consists of three equal in width and... | ```python
import sys
n, m = map(int, input().split())
flag = [list(input()) for _ in range(n)]
if len(set(flag[0])) > 1:
_flag = [['']*n for _ in range(m)]
for i in range(n):
for j in range(m):
_flag[j][i] = flag[i][j]
flag = _flag
n, m = m, n
if not all(len(set(row))... | 0 | |
621 | C | Wet Shark and Flowers | PROGRAMMING | 1,700 | [
"combinatorics",
"math",
"number theory",
"probabilities"
] | null | null | There are *n* sharks who grow flowers for Wet Shark. They are all sitting around the table, such that sharks *i* and *i*<=+<=1 are neighbours for all *i* from 1 to *n*<=-<=1. Sharks *n* and 1 are neighbours too.
Each shark will grow some number of flowers *s**i*. For *i*-th shark value *s**i* is random integer equipro... | The first line of the input contains two space-separated integers *n* and *p* (3<=≤<=*n*<=≤<=100<=000,<=2<=≤<=*p*<=≤<=109) — the number of sharks and Wet Shark's favourite prime number. It is guaranteed that *p* is prime.
The *i*-th of the following *n* lines contains information about *i*-th shark — two space-separat... | Print a single real number — the expected number of dollars that the sharks receive in total. You answer will be considered correct if its absolute or relative error does not exceed 10<=-<=6.
Namely: let's assume that your answer is *a*, and the answer of the jury is *b*. The checker program will consider your answer... | [
"3 2\n1 2\n420 421\n420420 420421\n",
"3 5\n1 4\n2 3\n11 14\n"
] | [
"4500.0\n",
"0.0\n"
] | A prime number is a positive integer number that is divisible only by 1 and itself. 1 is not considered to be prime.
Consider the first sample. First shark grows some number of flowers from 1 to 2, second sharks grows from 420 to 421 flowers and third from 420420 to 420421. There are eight cases for the quantities of ... | 1,500 | [
{
"input": "3 2\n1 2\n420 421\n420420 420421",
"output": "4500.0"
},
{
"input": "3 5\n1 4\n2 3\n11 14",
"output": "0.0"
},
{
"input": "3 3\n3 3\n2 4\n1 1",
"output": "4666.666666666667"
},
{
"input": "5 5\n5 204\n420 469\n417 480\n442 443\n44 46",
"output": "3451.25"
},... | 1,680,587,089 | 2,089 | PyPy 3-64 | OK | TESTS | 94 | 655 | 11,980,800 | n,p=map(int,input().split())
num=[]
for _ in range(n):
l,r=map(int,input().split())
right=r//p
left=(l-1)//p
num.append((right-left,r-l+1))
ans=0
for i,(p,q) in enumerate(num):
p1=(p/q)
i+=1
i%=n
p,q=num[i]
p2=p/q
t=p1+p2-p1*p2
ans+=t*2000
print(ans) | Title: Wet Shark and Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* sharks who grow flowers for Wet Shark. They are all sitting around the table, such that sharks *i* and *i*<=+<=1 are neighbours for all *i* from 1 to *n*<=-<=1. Sharks *n* and 1 are neighbours too.
... | ```python
n,p=map(int,input().split())
num=[]
for _ in range(n):
l,r=map(int,input().split())
right=r//p
left=(l-1)//p
num.append((right-left,r-l+1))
ans=0
for i,(p,q) in enumerate(num):
p1=(p/q)
i+=1
i%=n
p,q=num[i]
p2=p/q
t=p1+p2-p1*p2
ans+=t*2000
print(ans)... | 3 | |
4 | B | Before an Exam | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy"
] | B. Before an Exam | 0 | 64 | Tomorrow Peter has a Biology exam. He does not like this subject much, but *d* days ago he learnt that he would have to take this exam. Peter's strict parents made him prepare for the exam immediately, for this purpose he has to study not less than *minTime**i* and not more than *maxTime**i* hours per each *i*-th day. ... | The first input line contains two integer numbers *d*,<=*sumTime* (1<=≤<=*d*<=≤<=30,<=0<=≤<=*sumTime*<=≤<=240) — the amount of days, during which Peter studied, and the total amount of hours, spent on preparation. Each of the following *d* lines contains two integer numbers *minTime**i*,<=*maxTime**i* (0<=≤<=*minTime**... | In the first line print YES, and in the second line print *d* numbers (separated by a space), each of the numbers — amount of hours, spent by Peter on preparation in the corresponding day, if he followed his parents' instructions; or print NO in the unique line. If there are many solutions, print any of them. | [
"1 48\n5 7\n",
"2 5\n0 1\n3 5\n"
] | [
"NO\n",
"YES\n1 4 "
] | none | 0 | [
{
"input": "1 48\n5 7",
"output": "NO"
},
{
"input": "2 5\n0 1\n3 5",
"output": "YES\n1 4 "
},
{
"input": "1 1\n5 6",
"output": "NO"
},
{
"input": "1 4\n2 4",
"output": "YES\n4 "
},
{
"input": "2 5\n4 6\n0 0",
"output": "YES\n5 0 "
},
{
"input": "27 97... | 1,696,377,069 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 15 | 77 | 0 | d, time = map(int, input().split())
minTime = []
maxTime = []
for i in range(d):
mn, mx = map(int, input().split())
minTime.append(mn)
maxTime.append(mx)
minSum = sum(minTime)
maxSum = sum(maxTime)
if minSum <= time <= maxSum:
print("YES")
for i in range(d):
temp = min(minTime[i]... | Title: Before an Exam
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
Tomorrow Peter has a Biology exam. He does not like this subject much, but *d* days ago he learnt that he would have to take this exam. Peter's strict parents made him prepare for the exam immediately, for this purpose he has... | ```python
d, time = map(int, input().split())
minTime = []
maxTime = []
for i in range(d):
mn, mx = map(int, input().split())
minTime.append(mn)
maxTime.append(mx)
minSum = sum(minTime)
maxSum = sum(maxTime)
if minSum <= time <= maxSum:
print("YES")
for i in range(d):
temp = min(... | 3 |
109 | A | Lucky Sum of Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | A. Lucky Sum of Digits | 2 | 256 | Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya wonders eagerly what minimum lucky number has the sum of digits equal to *n*. Help him cope wi... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the sum of digits of the required lucky number. | Print on the single line the result — the minimum lucky number, whose sum of digits equals *n*. If such number does not exist, print -1. | [
"11\n",
"10\n"
] | [
"47\n",
"-1\n"
] | none | 500 | [
{
"input": "11",
"output": "47"
},
{
"input": "10",
"output": "-1"
},
{
"input": "64",
"output": "4477777777"
},
{
"input": "1",
"output": "-1"
},
{
"input": "4",
"output": "4"
},
{
"input": "7",
"output": "7"
},
{
"input": "12",
"outpu... | 1,540,615,420 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 216 | 0 | n = int(input())
for x in range(n//7,0,-1):
if (n-x*7)%4 == 0:
print ('4'*((n-x*7)//4 )+ '7'*x)
break
else:
print (-1) | Title: Lucky Sum of Digits
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n = int(input())
for x in range(n//7,0,-1):
if (n-x*7)%4 == 0:
print ('4'*((n-x*7)//4 )+ '7'*x)
break
else:
print (-1)
``` | 0 |
893 | A | Chess For Three | PROGRAMMING | 900 | [
"implementation"
] | null | null | Alex, Bob and Carl will soon participate in a team chess tournament. Since they are all in the same team, they have decided to practise really hard before the tournament. But it's a bit difficult for them because chess is a game for two players, not three.
So they play with each other according to following rules:
- ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of games Alex, Bob and Carl played.
Then *n* lines follow, describing the game log. *i*-th line contains one integer *a**i* (1<=≤<=*a**i*<=≤<=3) which is equal to 1 if Alex won *i*-th game, to 2 if Bob won *i*-th game and 3 if Carl won *i*-th gam... | Print YES if the situation described in the log was possible. Otherwise print NO. | [
"3\n1\n1\n2\n",
"2\n1\n2\n"
] | [
"YES\n",
"NO\n"
] | In the first example the possible situation is:
1. Alex wins, Carl starts playing instead of Bob; 1. Alex wins, Bob replaces Carl; 1. Bob wins.
The situation in the second example is impossible because Bob loses the first game, so he cannot win the second one. | 0 | [
{
"input": "3\n1\n1\n2",
"output": "YES"
},
{
"input": "2\n1\n2",
"output": "NO"
},
{
"input": "100\n2\n3\n1\n2\n3\n3\n3\n1\n1\n1\n1\n3\n3\n3\n3\n1\n2\n3\n3\n3\n3\n3\n3\n3\n1\n2\n2\n2\n3\n1\n1\n3\n3\n3\n3\n3\n3\n3\n3\n1\n2\n3\n3\n3\n1\n1\n1\n1\n3\n3\n3\n3\n1\n2\n3\n1\n2\n2\n2\n3\n3\n2\n1... | 1,673,407,867 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 46 | 0 | import sys
L=[]
b=int(input())
for i in range(b):
c=int(input())
L.append(c)
A=1
B=1
C=0
if L[0]==1:
A=1
B=0
C=1
else:
A=0
B=1
C=1
for i in range(1,b):
if L[i]==1 and A==0:
print("NO")
sys.exit()
elif L[i]==2 and B==0:
print("NO")
... | Title: Chess For Three
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex, Bob and Carl will soon participate in a team chess tournament. Since they are all in the same team, they have decided to practise really hard before the tournament. But it's a bit difficult for them because chess ... | ```python
import sys
L=[]
b=int(input())
for i in range(b):
c=int(input())
L.append(c)
A=1
B=1
C=0
if L[0]==1:
A=1
B=0
C=1
else:
A=0
B=1
C=1
for i in range(1,b):
if L[i]==1 and A==0:
print("NO")
sys.exit()
elif L[i]==2 and B==0:
print... | 0 | |
588 | B | Duff in Love | PROGRAMMING | 1,300 | [
"math"
] | null | null | Duff is in love with lovely numbers! A positive integer *x* is called lovely if and only if there is no such positive integer *a*<=><=1 such that *a*2 is a divisor of *x*.
Malek has a number store! In his store, he has only divisors of positive integer *n* (and he has all of them). As a birthday present, Malek want... | The first and only line of input contains one integer, *n* (1<=≤<=*n*<=≤<=1012). | Print the answer in one line. | [
"10\n",
"12\n"
] | [
"10\n",
"6\n"
] | In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 2<sup class="upper-index">2</sup>, so 12 is not lovely, while 6 is indeed lovely. | 1,000 | [
{
"input": "10",
"output": "10"
},
{
"input": "12",
"output": "6"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "2"
},
{
"input": "4",
"output": "2"
},
{
"input": "8",
"output": "2"
},
{
"input": "3",
"output": "3"
},
... | 1,667,364,818 | 2,147,483,647 | Python 3 | OK | TESTS | 53 | 514 | 0 | n = int(input())
for i in range(2,10**6):
while(n%i**2 == 0):
n //= i
print(n) | Title: Duff in Love
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Duff is in love with lovely numbers! A positive integer *x* is called lovely if and only if there is no such positive integer *a*<=><=1 such that *a*2 is a divisor of *x*.
Malek has a number store! In his store, he has... | ```python
n = int(input())
for i in range(2,10**6):
while(n%i**2 == 0):
n //= i
print(n)
``` | 3 | |
572 | A | Arrays | PROGRAMMING | 900 | [
"sortings"
] | null | null | You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the first array is strictly less than any number chosen in the second array. | The first line contains two integers *n**A*,<=*n**B* (1<=≤<=*n**A*,<=*n**B*<=≤<=105), separated by a space — the sizes of arrays *A* and *B*, correspondingly.
The second line contains two integers *k* and *m* (1<=≤<=*k*<=≤<=*n**A*,<=1<=≤<=*m*<=≤<=*n**B*), separated by a space.
The third line contains *n**A* numbers *... | Print "YES" (without the quotes), if you can choose *k* numbers in array *A* and *m* numbers in array *B* so that any number chosen in array *A* was strictly less than any number chosen in array *B*. Otherwise, print "NO" (without the quotes). | [
"3 3\n2 1\n1 2 3\n3 4 5\n",
"3 3\n3 3\n1 2 3\n3 4 5\n",
"5 2\n3 1\n1 1 1 1 1\n2 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample test you can, for example, choose numbers 1 and 2 from array *A* and number 3 from array *B* (1 < 3 and 2 < 3).
In the second sample test the only way to choose *k* elements in the first array and *m* elements in the second one is to choose all numbers in both arrays, but then not all the num... | 500 | [
{
"input": "3 3\n2 1\n1 2 3\n3 4 5",
"output": "YES"
},
{
"input": "3 3\n3 3\n1 2 3\n3 4 5",
"output": "NO"
},
{
"input": "5 2\n3 1\n1 1 1 1 1\n2 2",
"output": "YES"
},
{
"input": "3 5\n1 1\n5 5 5\n5 5 5 5 5",
"output": "NO"
},
{
"input": "1 1\n1 1\n1\n1",
"ou... | 1,621,020,225 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 77 | 0 | na, nb = map(int, input().split())
k, m = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
m_min = min(b)
m_max = max(b)
count = 0
if k == na and m == nb :
for i in range(k):
if a[i] < m_min:
count += 1
if count >= k:
pri... | Title: Arrays
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the fi... | ```python
na, nb = map(int, input().split())
k, m = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
m_min = min(b)
m_max = max(b)
count = 0
if k == na and m == nb :
for i in range(k):
if a[i] < m_min:
count += 1
if count >= k:
... | 0 | |
479 | A | Expression | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resul... | The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10). | Print the maximum value of the expression that you can obtain. | [
"1\n2\n3\n",
"2\n10\n3\n"
] | [
"9\n",
"60\n"
] | none | 500 | [
{
"input": "1\n2\n3",
"output": "9"
},
{
"input": "2\n10\n3",
"output": "60"
},
{
"input": "1\n1\n1",
"output": "3"
},
{
"input": "1\n2\n1",
"output": "4"
},
{
"input": "10\n10\n10",
"output": "1000"
},
{
"input": "5\n1\n3",
"output": "20"
},
{... | 1,694,379,178 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 31 | 0 | max=0
min=0
mid=0
count=0
number_index=0
mid_index=0
max_index=0
min_index=0
for i in range(3):
number=int(input())
number_index=i+1
if(number==1):
count+=1
if(i==0):
mid=number
mid_index=number_index
max=number
max_index=number_index
min=number
m... | Title: Expression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of ... | ```python
max=0
min=0
mid=0
count=0
number_index=0
mid_index=0
max_index=0
min_index=0
for i in range(3):
number=int(input())
number_index=i+1
if(number==1):
count+=1
if(i==0):
mid=number
mid_index=number_index
max=number
max_index=number_index
min=numbe... | 0 | |
678 | A | Johny Likes Numbers | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*. | The only line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=109). | Print the smallest integer *x*<=><=*n*, so it is divisible by the number *k*. | [
"5 3\n",
"25 13\n",
"26 13\n"
] | [
"6\n",
"26\n",
"39\n"
] | none | 0 | [
{
"input": "5 3",
"output": "6"
},
{
"input": "25 13",
"output": "26"
},
{
"input": "26 13",
"output": "39"
},
{
"input": "1 1",
"output": "2"
},
{
"input": "8 8",
"output": "16"
},
{
"input": "14 15",
"output": "15"
},
{
"input": "197 894"... | 1,681,317,133 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | import math
n,k=input().split()
n=int(n)
k=int(k)
print(n+k) | Title: Johny Likes Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*.
Input Specification:
The only line contains two integers *n* and *... | ```python
import math
n,k=input().split()
n=int(n)
k=int(k)
print(n+k)
``` | 0 | |
339 | A | Helpful Maths | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings",
"strings"
] | null | null | Xenia the beginner mathematician is a third year student at elementary school. She is now learning the addition operation.
The teacher has written down the sum of multiple numbers. Pupils should calculate the sum. To make the calculation easier, the sum only contains numbers 1, 2 and 3. Still, that isn't enough for Xe... | The first line contains a non-empty string *s* — the sum Xenia needs to count. String *s* contains no spaces. It only contains digits and characters "+". Besides, string *s* is a correct sum of numbers 1, 2 and 3. String *s* is at most 100 characters long. | Print the new sum that Xenia can count. | [
"3+2+1\n",
"1+1+3+1+3\n",
"2\n"
] | [
"1+2+3\n",
"1+1+1+3+3\n",
"2\n"
] | none | 500 | [
{
"input": "3+2+1",
"output": "1+2+3"
},
{
"input": "1+1+3+1+3",
"output": "1+1+1+3+3"
},
{
"input": "2",
"output": "2"
},
{
"input": "2+2+1+1+3",
"output": "1+1+2+2+3"
},
{
"input": "2+1+2+2+2+3+1+3+1+2",
"output": "1+1+1+2+2+2+2+2+3+3"
},
{
"input": ... | 1,698,065,860 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | s = input()
numbers = s.split("+")
numbers.sort()
numbers="+".join(numbers)
print(numbers)
| Title: Helpful Maths
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the beginner mathematician is a third year student at elementary school. She is now learning the addition operation.
The teacher has written down the sum of multiple numbers. Pupils should calculate the sum. To mak... | ```python
s = input()
numbers = s.split("+")
numbers.sort()
numbers="+".join(numbers)
print(numbers)
``` | 3 | |
417 | C | Football | PROGRAMMING | 1,400 | [
"constructive algorithms",
"graphs",
"implementation"
] | null | null | One day, at the "Russian Code Cup" event it was decided to play football as an out of competition event. All participants was divided into *n* teams and played several matches, two teams could not play against each other more than once.
The appointed Judge was the most experienced member — Pavel. But since he was the ... | The first line contains two integers — *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1000). | In the first line print an integer *m* — number of the played games. The following *m* lines should contain the information about all the matches, one match per line. The *i*-th line should contain two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*; *a**i*<=≠<=*b**i*). The numbers *a**i* and *b**i* mean, tha... | [
"3 1\n"
] | [
"3\n1 2\n2 3\n3 1\n"
] | none | 1,500 | [
{
"input": "3 1",
"output": "3\n1 2\n2 3\n3 1"
},
{
"input": "7 3",
"output": "21\n1 2\n1 3\n1 4\n2 3\n2 4\n2 5\n3 4\n3 5\n3 6\n4 5\n4 6\n4 7\n5 6\n5 7\n5 1\n6 7\n6 1\n6 2\n7 1\n7 2\n7 3"
},
{
"input": "4 1",
"output": "4\n1 2\n2 3\n3 4\n4 1"
},
{
"input": "5 2",
"output"... | 1,613,771,830 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 33 | 1,000 | 307,200 | # Collaborated with No One
input1 = list(map(int, input().split(" ")))
n = input1[0]
k = input1[1]
m = n-1
totalGamesPlayed = m+(m*(m-1))//2
if(k*n>totalGamesPlayed):
print("-1")
else:
print(n*k)
for i in range(1,n+1):
j=i+1
while(j<=i+k):
if(j>n):
print(str(i) + ... | Title: Football
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, at the "Russian Code Cup" event it was decided to play football as an out of competition event. All participants was divided into *n* teams and played several matches, two teams could not play against each other more ... | ```python
# Collaborated with No One
input1 = list(map(int, input().split(" ")))
n = input1[0]
k = input1[1]
m = n-1
totalGamesPlayed = m+(m*(m-1))//2
if(k*n>totalGamesPlayed):
print("-1")
else:
print(n*k)
for i in range(1,n+1):
j=i+1
while(j<=i+k):
if(j>n):
print... | 0 | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,542,019,234 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 280 | 0 | n=input()
m=n.split()
a=int(m[0])
b=int(m[1])
def isPrime(n):
for i in range(2,n):
if n%i==0 : return False
return True
if isPrime(b)==False : print("NO")
else :
j=a+1
while isPrime(j)==False:
j+=1
if j==b : print("YES")
else : print("NO")
| Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
n=input()
m=n.split()
a=int(m[0])
b=int(m[1])
def isPrime(n):
for i in range(2,n):
if n%i==0 : return False
return True
if isPrime(b)==False : print("NO")
else :
j=a+1
while isPrime(j)==False:
j+=1
if j==b : print("YES")
else : print("NO")
``... | 3.93 |
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