contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
543 | D | Road Improvement | PROGRAMMING | 2,300 | [
"dp",
"trees"
] | null | null | The country has *n* cities and *n*<=-<=1 bidirectional roads, it is possible to get from every city to any other one if you move only along the roads. The cities are numbered with integers from 1 to *n* inclusive.
All the roads are initially bad, but the government wants to improve the state of some roads. We will ass... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=2·105) — the number of cities in the country. Next line contains *n*<=-<=1 positive integers *p*2,<=*p*3,<=*p*4,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*i*<=-<=1) — the description of the roads in the country. Number *p**i* means that the country has a r... | Print *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* is the sought number of ways to improve the quality of the roads modulo 1<=000<=000<=007 (109<=+<=7), if the capital of the country is at city number *i*. | [
"3\n1 1\n",
"5\n1 2 3 4\n"
] | [
"4 3 3",
"5 8 9 8 5"
] | none | 1,750 | [
{
"input": "3\n1 1",
"output": "4 3 3"
},
{
"input": "5\n1 2 3 4",
"output": "5 8 9 8 5"
},
{
"input": "31\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "73741817 536870913 536870913 536870913 536870913 536870913 536870913 536870913 536870913 536870913 5368... | 1,692,375,930 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 42 | 452 | 21,913,600 | import sys
MODULO = int(1e9) + 7
def solve(n, p, out_stream):
prod = [1] * n
modpow = [0] * n
for i in range(n - 1, 0, -1):
j = p[i]
if modpow[i] == 0 and prod[i] + 1 == MODULO:
modpow[j] += 1
else:
prod[j] = (prod[j] * ((prod[i] if modpow[i] == 0 el... | Title: Road Improvement
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The country has *n* cities and *n*<=-<=1 bidirectional roads, it is possible to get from every city to any other one if you move only along the roads. The cities are numbered with integers from 1 to *n* inclusive.
All... | ```python
import sys
MODULO = int(1e9) + 7
def solve(n, p, out_stream):
prod = [1] * n
modpow = [0] * n
for i in range(n - 1, 0, -1):
j = p[i]
if modpow[i] == 0 and prod[i] + 1 == MODULO:
modpow[j] += 1
else:
prod[j] = (prod[j] * ((prod[i] if modpow[... | 3 | |
658 | A | Bear and Reverse Radewoosh | PROGRAMMING | 800 | [
"implementation"
] | null | null | Limak and Radewoosh are going to compete against each other in the upcoming algorithmic contest. They are equally skilled but they won't solve problems in the same order.
There will be *n* problems. The *i*-th problem has initial score *p**i* and it takes exactly *t**i* minutes to solve it. Problems are sorted by diff... | The first line contains two integers *n* and *c* (1<=≤<=*n*<=≤<=50,<=1<=≤<=*c*<=≤<=1000) — the number of problems and the constant representing the speed of loosing points.
The second line contains *n* integers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=1000,<=*p**i*<=<<=*p**i*<=+<=1) — initial scores.
The third... | Print "Limak" (without quotes) if Limak will get more points in total. Print "Radewoosh" (without quotes) if Radewoosh will get more points in total. Print "Tie" (without quotes) if Limak and Radewoosh will get the same total number of points. | [
"3 2\n50 85 250\n10 15 25\n",
"3 6\n50 85 250\n10 15 25\n",
"8 1\n10 20 30 40 50 60 70 80\n8 10 58 63 71 72 75 76\n"
] | [
"Limak\n",
"Radewoosh\n",
"Tie\n"
] | In the first sample, there are 3 problems. Limak solves them as follows:
1. Limak spends 10 minutes on the 1-st problem and he gets 50 - *c*·10 = 50 - 2·10 = 30 points. 1. Limak spends 15 minutes on the 2-nd problem so he submits it 10 + 15 = 25 minutes after the start of the contest. For the 2-nd problem he gets 85... | 500 | [
{
"input": "3 2\n50 85 250\n10 15 25",
"output": "Limak"
},
{
"input": "3 6\n50 85 250\n10 15 25",
"output": "Radewoosh"
},
{
"input": "8 1\n10 20 30 40 50 60 70 80\n8 10 58 63 71 72 75 76",
"output": "Tie"
},
{
"input": "4 1\n3 5 6 9\n1 2 4 8",
"output": "Limak"
},
{... | 1,568,203,558 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | n, c = map(int, input().split())
p = [int(i) for i in input().split()]
t = [int(i) for i in input().split()]
a = 0
s1 = 0
s2 = 0
for i in range(n):
a += t[i]
s1 += max(0, p[i] - a * c)
for i in reversed(range(n)):
a += t[i]
s2 += max(0, p[i] - a * c)
if s1 > s2:
print('Limak')
elif s1 ... | Title: Bear and Reverse Radewoosh
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak and Radewoosh are going to compete against each other in the upcoming algorithmic contest. They are equally skilled but they won't solve problems in the same order.
There will be *n* problems. The *i*-... | ```python
n, c = map(int, input().split())
p = [int(i) for i in input().split()]
t = [int(i) for i in input().split()]
a = 0
s1 = 0
s2 = 0
for i in range(n):
a += t[i]
s1 += max(0, p[i] - a * c)
for i in reversed(range(n)):
a += t[i]
s2 += max(0, p[i] - a * c)
if s1 > s2:
print('Limak')... | 0 | |
765 | C | Table Tennis Game 2 | PROGRAMMING | 1,200 | [
"math"
] | null | null | Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scores exactly *k* points, the score is reset and a new set begins.
Across all the sets Misha scored *a* poi... | The first line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=109, 0<=≤<=*a*,<=*b*<=≤<=109, *a*<=+<=*b*<=><=0). | If the situation is impossible, print a single number -1. Otherwise, print the maximum possible number of sets. | [
"11 11 5\n",
"11 2 3\n"
] | [
"1\n",
"-1\n"
] | Note that the rules of the game in this problem differ from the real table tennis game, for example, the rule of "balance" (the winning player has to be at least two points ahead to win a set) has no power within the present problem. | 1,250 | [
{
"input": "11 11 5",
"output": "1"
},
{
"input": "11 2 3",
"output": "-1"
},
{
"input": "1 5 9",
"output": "14"
},
{
"input": "2 3 3",
"output": "2"
},
{
"input": "1 1000000000 1000000000",
"output": "2000000000"
},
{
"input": "2 3 5",
"output": "... | 1,601,012,713 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 14 | 109 | 0 | # -*- coding: utf-8 -*-
"""
Created on Fri Sep 25 11:42:59 2020
@author: Dark Soul
"""
[k,a,b]=list(map(int,input().split()))
ans=(a//k)+(b//k)
if ans<1:
print(-1)
else:
print(ans) | Title: Table Tennis Game 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scor... | ```python
# -*- coding: utf-8 -*-
"""
Created on Fri Sep 25 11:42:59 2020
@author: Dark Soul
"""
[k,a,b]=list(map(int,input().split()))
ans=(a//k)+(b//k)
if ans<1:
print(-1)
else:
print(ans)
``` | 0 | |
266 | A | Stones on the Table | PROGRAMMING | 800 | [
"implementation"
] | null | null | There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them. | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table.
The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red... | Print a single integer — the answer to the problem. | [
"3\nRRG\n",
"5\nRRRRR\n",
"4\nBRBG\n"
] | [
"1\n",
"4\n",
"0\n"
] | none | 500 | [
{
"input": "3\nRRG",
"output": "1"
},
{
"input": "5\nRRRRR",
"output": "4"
},
{
"input": "4\nBRBG",
"output": "0"
},
{
"input": "1\nB",
"output": "0"
},
{
"input": "2\nBG",
"output": "0"
},
{
"input": "3\nBGB",
"output": "0"
},
{
"input": "... | 1,699,117,956 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | x=int (input())
y=input()
count=0
for i in range(x):
for j in range(i+1,x):
if y[i]==y[j]:
count+=1
break
else:
break
print(count) | Title: Stones on the Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row ... | ```python
x=int (input())
y=input()
count=0
for i in range(x):
for j in range(i+1,x):
if y[i]==y[j]:
count+=1
break
else:
break
print(count)
``` | 3 | |
141 | A | Amusing Joke | PROGRAMMING | 800 | [
"implementation",
"sortings",
"strings"
] | null | null | So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's name and the host's name in honor of this event. Then the hung the letters above the main entrance. O... | The input file consists of three lines: the first line contains the guest's name, the second line contains the name of the residence host and the third line contains letters in a pile that were found at the door in the morning. All lines are not empty and contain only uppercase Latin letters. The length of each line do... | Print "YES" without the quotes, if the letters in the pile could be permuted to make the names of the "New Year and Christmas Men". Otherwise, print "NO" without the quotes. | [
"SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS\n",
"PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI\n",
"BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | In the first sample the letters written in the last line can be used to write the names and there won't be any extra letters left.
In the second sample letter "P" is missing from the pile and there's an extra letter "L".
In the third sample there's an extra letter "L". | 500 | [
{
"input": "SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS",
"output": "YES"
},
{
"input": "PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI",
"output": "NO"
},
{
"input": "BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER",
"output": "NO"
},
{
"input": "B\nA\nAB",
"output": ... | 1,681,127,705 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 92 | 0 | s = list(input()) + list(input())
s2 =list(input())
print('YES' if sorted(s) == sorted(s2) else 'NO') | Title: Amusing Joke
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's nam... | ```python
s = list(input()) + list(input())
s2 =list(input())
print('YES' if sorted(s) == sorted(s2) else 'NO')
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research.
First of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes... | In first line there is one integer *n* (1<=≤<=*n*<=≤<=2·105) — number of cafes indices written by Vlad.
In second line, *n* numbers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=2·105) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, ... | Print one integer — index of the cafe that Vlad hasn't visited for as long as possible. | [
"5\n1 3 2 1 2\n",
"6\n2 1 2 2 4 1\n"
] | [
"3\n",
"2\n"
] | In first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer.
In second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with in... | 0 | [
{
"input": "5\n1 3 2 1 2",
"output": "3"
},
{
"input": "6\n2 1 2 2 4 1",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n200000",
"output": "200000"
},
{
"input": "2\n2018 2017",
"output": "2018"
},
{
"input": "5\n100 1000 1000 1000... | 1,519,753,788 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 61 | 5,734,400 | from collections import OrderedDict
n = int(input())
A = list(map(int, input().split()))
print(list(OrderedDict.fromkeys(A))[1])
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research.
First o... | ```python
from collections import OrderedDict
n = int(input())
A = list(map(int, input().split()))
print(list(OrderedDict.fromkeys(A))[1])
``` | 0 | |
279 | B | Books | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation",
"two pointers"
] | null | null | When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy n... | Print a single integer — the maximum number of books Valera can read. | [
"4 5\n3 1 2 1\n",
"3 3\n2 2 3\n"
] | [
"3\n",
"1\n"
] | none | 1,000 | [
{
"input": "4 5\n3 1 2 1",
"output": "3"
},
{
"input": "3 3\n2 2 3",
"output": "1"
},
{
"input": "1 3\n5",
"output": "0"
},
{
"input": "1 10\n4",
"output": "1"
},
{
"input": "2 10\n6 4",
"output": "2"
},
{
"input": "6 10\n2 3 4 2 1 1",
"output": "4... | 1,680,345,277 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 124 | 0 | n,t=map(int,input().split())
lis=list(map(int,input().split()))
lis.sort()
ans=0
for i in range(n):
if t-lis[i]>=0:
t-=lis[i]
ans+=1
else:
break
print(ans) | Title: Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need t... | ```python
n,t=map(int,input().split())
lis=list(map(int,input().split()))
lis.sort()
ans=0
for i in range(n):
if t-lis[i]>=0:
t-=lis[i]
ans+=1
else:
break
print(ans)
``` | 0 | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,613,094,163 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 184 | 0 | n = int(input())
seen = set()
q = []
for _ in range(n):
e, p = input().split()
p = int(p)
if e in seen:
i = -1
for j in range(len(q)):
if q[j][0] == e:
i = j
break
e = q.pop(i)
p = p + e[1]
e = e[0]
ins = True
for i in range(len(q) - 1, -1, -1):
if p < q[0][1]:
... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
n = int(input())
seen = set()
q = []
for _ in range(n):
e, p = input().split()
p = int(p)
if e in seen:
i = -1
for j in range(len(q)):
if q[j][0] == e:
i = j
break
e = q.pop(i)
p = p + e[1]
e = e[0]
ins = True
for i in range(len(q) - 1, -1, -1):
if p < q... | 0 |
279 | B | Books | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation",
"two pointers"
] | null | null | When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy n... | Print a single integer — the maximum number of books Valera can read. | [
"4 5\n3 1 2 1\n",
"3 3\n2 2 3\n"
] | [
"3\n",
"1\n"
] | none | 1,000 | [
{
"input": "4 5\n3 1 2 1",
"output": "3"
},
{
"input": "3 3\n2 2 3",
"output": "1"
},
{
"input": "1 3\n5",
"output": "0"
},
{
"input": "1 10\n4",
"output": "1"
},
{
"input": "2 10\n6 4",
"output": "2"
},
{
"input": "6 10\n2 3 4 2 1 1",
"output": "4... | 1,673,396,315 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 28 | 404 | 6,348,800 | def fun(l,r):
global sumi
if l>r or sumi<=t:
return 0
if lis[l]>lis[r]:
if sumi<=t:
return 0
sumi-=lis[l]
return 1+fun(l+1,r)
elif lis[l]<lis[r]:
if sumi<=t:
return 0
sumi-=lis[r]
return 1+fun(l,r-1)
else:
... | Title: Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need t... | ```python
def fun(l,r):
global sumi
if l>r or sumi<=t:
return 0
if lis[l]>lis[r]:
if sumi<=t:
return 0
sumi-=lis[l]
return 1+fun(l+1,r)
elif lis[l]<lis[r]:
if sumi<=t:
return 0
sumi-=lis[r]
return 1+fun(l,r-1)
... | 0 | |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,580,559,297 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 109 | 0 | n, k = map(int, input().split())
s = input()
c = [0] * 26
count = 0
if n == k:
print('YES')
else:
for i in s:
nomer = ord(i) - 97
c[nomer] += 1
for j in range(len(c)):
if c[j] > 0 and c[j] == k:
count += 1
if count == k:
print('YES')
else:
print('N... | Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same colo... | ```python
n, k = map(int, input().split())
s = input()
c = [0] * 26
count = 0
if n == k:
print('YES')
else:
for i in s:
nomer = ord(i) - 97
c[nomer] += 1
for j in range(len(c)):
if c[j] > 0 and c[j] == k:
count += 1
if count == k:
print('YES')
else:
... | 0 | |
161 | D | Distance in Tree | PROGRAMMING | 1,800 | [
"dfs and similar",
"dp",
"trees"
] | null | null | A tree is a connected graph that doesn't contain any cycles.
The distance between two vertices of a tree is the length (in edges) of the shortest path between these vertices.
You are given a tree with *n* vertices and a positive number *k*. Find the number of distinct pairs of the vertices which have a distance of ex... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=50000, 1<=≤<=*k*<=≤<=500) — the number of vertices and the required distance between the vertices.
Next *n*<=-<=1 lines describe the edges as "*a**i* *b**i*" (without the quotes) (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*), where *a**i* and *b**i* ... | Print a single integer — the number of distinct pairs of the tree's vertices which have a distance of exactly *k* between them.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"5 2\n1 2\n2 3\n3 4\n2 5\n",
"5 3\n1 2\n2 3\n3 4\n4 5\n"
] | [
"4\n",
"2\n"
] | In the first sample the pairs of vertexes at distance 2 from each other are (1, 3), (1, 5), (3, 5) and (2, 4). | 2,000 | [
{
"input": "5 2\n1 2\n2 3\n3 4\n2 5",
"output": "4"
},
{
"input": "5 3\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10 1\n2 1\n3 1\n4 3\n5 4\n6 5\n7 1\n8 6\n9 2\n10 6",
"output": "9"
},
{
"input": "10 2\n2 1\n3 1\n4 3\n5 4\n6 5\n7 1\n8 6\n9 2\n10 6",
"output": "10"
... | 1,578,022,912 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 11 | 3,000 | 131,686,400 | # -*- coding:utf-8 -*-
"""
created by shuangquan.huang at 1/3/20
"""
import collections
import time
import os
import sys
import bisect
import heapq
from typing import List
g = collections.defaultdict(list)
curAns = [0]
N, K = map(int, input().split())
for i in range(N-1):
u, v = map(int, input().split())
... | Title: Distance in Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tree is a connected graph that doesn't contain any cycles.
The distance between two vertices of a tree is the length (in edges) of the shortest path between these vertices.
You are given a tree with *n* vertices an... | ```python
# -*- coding:utf-8 -*-
"""
created by shuangquan.huang at 1/3/20
"""
import collections
import time
import os
import sys
import bisect
import heapq
from typing import List
g = collections.defaultdict(list)
curAns = [0]
N, K = map(int, input().split())
for i in range(N-1):
u, v = map(int, input().spl... | 0 | |
557 | A | Ilya and Diplomas | PROGRAMMING | 1,100 | [
"greedy",
"implementation",
"math"
] | null | null | Soon a school Olympiad in Informatics will be held in Berland, *n* schoolchildren will participate there.
At a meeting of the jury of the Olympiad it was decided that each of the *n* participants, depending on the results, will get a diploma of the first, second or third degree. Thus, each student will receive exactly... | The first line of the input contains a single integer *n* (3<=≤<=*n*<=≤<=3·106) — the number of schoolchildren who will participate in the Olympiad.
The next line of the input contains two integers *min*1 and *max*1 (1<=≤<=*min*1<=≤<=*max*1<=≤<=106) — the minimum and maximum limits on the number of diplomas of the fir... | In the first line of the output print three numbers, showing how many diplomas of the first, second and third degree will be given to students in the optimal variant of distributing diplomas.
The optimal variant of distributing diplomas is the one that maximizes the number of students who receive diplomas of the first... | [
"6\n1 5\n2 6\n3 7\n",
"10\n1 2\n1 3\n1 5\n",
"6\n1 3\n2 2\n2 2\n"
] | [
"1 2 3 \n",
"2 3 5 \n",
"2 2 2 \n"
] | none | 500 | [
{
"input": "6\n1 5\n2 6\n3 7",
"output": "1 2 3 "
},
{
"input": "10\n1 2\n1 3\n1 5",
"output": "2 3 5 "
},
{
"input": "6\n1 3\n2 2\n2 2",
"output": "2 2 2 "
},
{
"input": "55\n1 1000000\n40 50\n10 200",
"output": "5 40 10 "
},
{
"input": "3\n1 1\n1 1\n1 1",
"o... | 1,437,542,531 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 62 | 0 | n = int(input())
min1,max1 = map(int,input().split())
min2,max2 = map(int,input().split())
min3,max3 = map(int,input().split())
l1 = min(max1, n - min2 - min3)
l2 = min(max2, n - l1 - min3)
l3 = n - l1 - l2
print(l1,l2,l3)
| Title: Ilya and Diplomas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Soon a school Olympiad in Informatics will be held in Berland, *n* schoolchildren will participate there.
At a meeting of the jury of the Olympiad it was decided that each of the *n* participants, depending on the re... | ```python
n = int(input())
min1,max1 = map(int,input().split())
min2,max2 = map(int,input().split())
min3,max3 = map(int,input().split())
l1 = min(max1, n - min2 - min3)
l2 = min(max2, n - l1 - min3)
l3 = n - l1 - l2
print(l1,l2,l3)
``` | 3 | |
339 | B | Xenia and Ringroad | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Xenia lives in a city that has *n* houses built along the main ringroad. The ringroad houses are numbered 1 through *n* in the clockwise order. The ringroad traffic is one way and also is clockwise.
Xenia has recently moved into the ringroad house number 1. As a result, she's got *m* things to do. In order to complete... | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=1<=≤<=*m*<=≤<=105). The second line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=*n*). Note that Xenia can have multiple consecutive tasks in one house. | Print a single integer — the time Xenia needs to complete all tasks.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"4 3\n3 2 3\n",
"4 3\n2 3 3\n"
] | [
"6\n",
"2\n"
] | In the first test example the sequence of Xenia's moves along the ringroad looks as follows: 1 → 2 → 3 → 4 → 1 → 2 → 3. This is optimal sequence. So, she needs 6 time units. | 1,000 | [
{
"input": "4 3\n3 2 3",
"output": "6"
},
{
"input": "4 3\n2 3 3",
"output": "2"
},
{
"input": "2 2\n1 1",
"output": "0"
},
{
"input": "2 2\n1 2",
"output": "1"
},
{
"input": "2 2\n1 2",
"output": "1"
},
{
"input": "100 100\n56 46 1 47 5 86 45 35 81 1 ... | 1,696,968,917 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 29 | 154 | 13,516,800 | n, m = map(int, input().split())
s = 0
p = 1
a = list(map(int,input().split()))
for v in a:
s += (v - p) % n
p = v
print(s)
| Title: Xenia and Ringroad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia lives in a city that has *n* houses built along the main ringroad. The ringroad houses are numbered 1 through *n* in the clockwise order. The ringroad traffic is one way and also is clockwise.
Xenia has recent... | ```python
n, m = map(int, input().split())
s = 0
p = 1
a = list(map(int,input().split()))
for v in a:
s += (v - p) % n
p = v
print(s)
``` | 3 | |
461 | A | Appleman and Toastman | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and ... | 500 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,615,428,721 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 389 | 20,787,200 | #Problem Set N: Collaborated with Justin Mercado and Rudransh Singh
n = int(input())
a_list = list(map(int, input().split()))
a_list = sorted(a_list)
total = 0
for i in range(n):
total = total + a_list[i]*(i+2)
total = total - a_list[n-1]
print(total)
| Title: Appleman and Toastman
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all... | ```python
#Problem Set N: Collaborated with Justin Mercado and Rudransh Singh
n = int(input())
a_list = list(map(int, input().split()))
a_list = sorted(a_list)
total = 0
for i in range(n):
total = total + a_list[i]*(i+2)
total = total - a_list[n-1]
print(total)
``` | 3 | |
848 | A | From Y to Y | PROGRAMMING | 1,600 | [
"constructive algorithms"
] | null | null | From beginning till end, this message has been waiting to be conveyed.
For a given unordered multiset of *n* lowercase English letters ("multi" means that a letter may appear more than once), we treat all letters as strings of length 1, and repeat the following operation *n*<=-<=1 times:
- Remove any two elements *s... | The first and only line of input contains a non-negative integer *k* (0<=≤<=*k*<=≤<=100<=000) — the required minimum cost. | Output a non-empty string of no more than 100<=000 lowercase English letters — any multiset satisfying the requirements, concatenated to be a string.
Note that the printed string doesn't need to be the final concatenated string. It only needs to represent an unordered multiset of letters. | [
"12\n",
"3\n"
] | [
"abababab\n",
"codeforces\n"
] | For the multiset {'a', 'b', 'a', 'b', 'a', 'b', 'a', 'b'}, one of the ways to complete the process is as follows:
- {"ab", "a", "b", "a", "b", "a", "b"}, with a cost of 0; - {"aba", "b", "a", "b", "a", "b"}, with a cost of 1; - {"abab", "a", "b", "a", "b"}, with a cost of 1; - {"abab", "ab", "a", "b"}, with a cost... | 500 | [
{
"input": "12",
"output": "abababab"
},
{
"input": "3",
"output": "codeforces"
},
{
"input": "0",
"output": "o"
},
{
"input": "2",
"output": "aabb"
},
{
"input": "5",
"output": "aaabbcc"
},
{
"input": "10",
"output": "aaaaa"
},
{
"input": ... | 1,612,970,481 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 140 | 2,150,400 | import string
l = string.ascii_lowercase
n = int(input())
if n==0:
print(l[0])
else:
fact = []
temp = 1
i = 1
while temp<=n:
fact.append(temp)
i+=1
temp = temp*i
fact.reverse()
for i in range(len(fact)):
if n%fact[i]==0:
temp = len(... | Title: From Y to Y
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
From beginning till end, this message has been waiting to be conveyed.
For a given unordered multiset of *n* lowercase English letters ("multi" means that a letter may appear more than once), we treat all letters as string... | ```python
import string
l = string.ascii_lowercase
n = int(input())
if n==0:
print(l[0])
else:
fact = []
temp = 1
i = 1
while temp<=n:
fact.append(temp)
i+=1
temp = temp*i
fact.reverse()
for i in range(len(fact)):
if n%fact[i]==0:
t... | 0 | |
520 | A | Pangram | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
You are given a string consisting of lowercase and uppercase Latin letters. Check whether thi... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of characters in the string.
The second line contains the string. The string consists only of uppercase and lowercase Latin letters. | Output "YES", if the string is a pangram and "NO" otherwise. | [
"12\ntoosmallword\n",
"35\nTheQuickBrownFoxJumpsOverTheLazyDog\n"
] | [
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "12\ntoosmallword",
"output": "NO"
},
{
"input": "35\nTheQuickBrownFoxJumpsOverTheLazyDog",
"output": "YES"
},
{
"input": "1\na",
"output": "NO"
},
{
"input": "26\nqwertyuiopasdfghjklzxcvbnm",
"output": "YES"
},
{
"input": "26\nABCDEFGHIJKLMNOPQRSTUVWXY... | 1,698,745,761 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 15 | 0 | n=int(input())
str=str(input())
str.lower()
for i in range(0,n):
if str[i] not in str[:i]+str[i+1:]:
print("NO")
break
else:
print("YES") | Title: Pangram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
... | ```python
n=int(input())
str=str(input())
str.lower()
for i in range(0,n):
if str[i] not in str[:i]+str[i+1:]:
print("NO")
break
else:
print("YES")
``` | 0 | |
91 | A | Newspaper Headline | PROGRAMMING | 1,500 | [
"greedy",
"strings"
] | A. Newspaper Headline | 2 | 256 | A newspaper is published in Walrusland. Its heading is *s*1, it consists of lowercase Latin letters. Fangy the little walrus wants to buy several such newspapers, cut out their headings, glue them one to another in order to get one big string. After that walrus erase several letters from this string in order to get a n... | The input data contain two lines. The first line contain the heading *s*1, the second line contains the word *s*2. The lines only consist of lowercase Latin letters (1<=≤<=|*s*1|<=≤<=104,<=1<=≤<=|*s*2|<=≤<=106). | If it is impossible to get the word *s*2 in the above-described manner, print "-1" (without the quotes). Otherwise, print the least number of newspaper headings *s*1, which Fangy will need to receive the word *s*2. | [
"abc\nxyz\n",
"abcd\ndabc\n"
] | [
"-1\n",
"2\n"
] | none | 500 | [
{
"input": "abc\nxyz",
"output": "-1"
},
{
"input": "abcd\ndabc",
"output": "2"
},
{
"input": "ab\nbabaaab",
"output": "5"
},
{
"input": "ab\nbaaabba",
"output": "6"
},
{
"input": "fbaaigiihhfaahgdbddgeggjdeigfadhfddja\nhbghjgijijcdafcbgiedichdeebaddfddb",
"ou... | 1,686,032,304 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 51 | 560 | 7,884,800 | s1 = input()
s2 = input()
from collections import defaultdict
d = defaultdict(list)
for i in range(len(s1)):
d[s1[i]].append(i)
import bisect
ans = 0
cur = 10**18
for ch in s2:
if ch not in d:
print(-1)
exit()
else:
if cur >= d[ch][-1]:
cur = d[ch][0]
... | Title: Newspaper Headline
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A newspaper is published in Walrusland. Its heading is *s*1, it consists of lowercase Latin letters. Fangy the little walrus wants to buy several such newspapers, cut out their headings, glue them one to another in order... | ```python
s1 = input()
s2 = input()
from collections import defaultdict
d = defaultdict(list)
for i in range(len(s1)):
d[s1[i]].append(i)
import bisect
ans = 0
cur = 10**18
for ch in s2:
if ch not in d:
print(-1)
exit()
else:
if cur >= d[ch][-1]:
cur = d[ch... | 3.845313 |
706 | B | Interesting drink | PROGRAMMING | 1,100 | [
"binary search",
"dp",
"implementation"
] | null | null | Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single i... | Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day. | [
"5\n3 10 8 6 11\n4\n1\n10\n3\n11\n"
] | [
"0\n4\n1\n5\n"
] | On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | 1,000 | [
{
"input": "5\n3 10 8 6 11\n4\n1\n10\n3\n11",
"output": "0\n4\n1\n5"
},
{
"input": "5\n868 987 714 168 123\n10\n424\n192\n795\n873\n117\n914\n735\n158\n631\n471",
"output": "2\n2\n3\n4\n0\n4\n3\n1\n2\n2"
},
{
"input": "3\n435 482 309\n7\n245\n241\n909\n745\n980\n29\n521",
"output": "... | 1,699,886,670 | 2,147,483,647 | Python 3 | OK | TESTS | 103 | 967 | 13,619,200 | # -*- coding: utf-8 -*-
"""
Created on Mon Nov 13 22:31:05 2023
@author: 刘婉婷 2300012258
"""
def binary_search(arr, target):
left, right = 0, len(arr) - 1
while left <= right:
mid = (left + right) // 2
if arr[mid] <= target:
left = mid + 1
else:
rig... | Title: Interesting drink
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known tha... | ```python
# -*- coding: utf-8 -*-
"""
Created on Mon Nov 13 22:31:05 2023
@author: 刘婉婷 2300012258
"""
def binary_search(arr, target):
left, right = 0, len(arr) - 1
while left <= right:
mid = (left + right) // 2
if arr[mid] <= target:
left = mid + 1
else:
... | 3 | |
386 | B | Fly, freebies, fly! | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation"
] | null | null | Everyone loves a freebie. Especially students.
It is well-known that if in the night before exam a student opens window, opens the student's record-book and shouts loudly three times "Fly, freebie, fly!" — then flown freebie helps him to pass the upcoming exam.
In the night before the exam on mathematical analysis *n... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=100), where *n* — the number of students shouted "Fly, freebie, fly!" The second line contains *n* positive integers *t**i* (1<=≤<=*t**i*<=≤<=1000).
The last line contains integer *T* (1<=≤<=*T*<=≤<=1000) — the time interval during which the freebie was n... | Print a single integer — the largest number of people who will pass exam tomorrow because of the freebie visit. | [
"6\n4 1 7 8 3 8\n1\n"
] | [
"3\n"
] | none | 1,000 | [
{
"input": "6\n4 1 7 8 3 8\n1",
"output": "3"
},
{
"input": "4\n4 2 1 5\n2",
"output": "2"
},
{
"input": "10\n4 7 1 3 8 5 2 1 8 4\n3",
"output": "6"
},
{
"input": "8\n39 49 37 28 40 17 50 2\n10",
"output": "3"
},
{
"input": "2\n1 1\n1",
"output": "2"
},
{
... | 1,691,666,331 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | n=int(input())
a=list(map(int,input().split()))
t=int(input())
h=[]
k=0
for i in range(n):
for j in range(i+1,n):
if abs(a[i]-a[j])<=t:
k+=1
h.append(str(a[i])+'-'+str(a[j]))
print(len(set(h)))
| Title: Fly, freebies, fly!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Everyone loves a freebie. Especially students.
It is well-known that if in the night before exam a student opens window, opens the student's record-book and shouts loudly three times "Fly, freebie, fly!" — then flo... | ```python
n=int(input())
a=list(map(int,input().split()))
t=int(input())
h=[]
k=0
for i in range(n):
for j in range(i+1,n):
if abs(a[i]-a[j])<=t:
k+=1
h.append(str(a[i])+'-'+str(a[j]))
print(len(set(h)))
``` | 0 | |
723 | A | The New Year: Meeting Friends | PROGRAMMING | 800 | [
"implementation",
"math",
"sortings"
] | null | null | There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they... | The first line of the input contains three distinct integers *x*1, *x*2 and *x*3 (1<=≤<=*x*1,<=*x*2,<=*x*3<=≤<=100) — the coordinates of the houses of the first, the second and the third friends respectively. | Print one integer — the minimum total distance the friends need to travel in order to meet together. | [
"7 1 4\n",
"30 20 10\n"
] | [
"6\n",
"20\n"
] | In the first sample, friends should meet at the point 4. Thus, the first friend has to travel the distance of 3 (from the point 7 to the point 4), the second friend also has to travel the distance of 3 (from the point 1 to the point 4), while the third friend should not go anywhere because he lives at the point 4. | 500 | [
{
"input": "7 1 4",
"output": "6"
},
{
"input": "30 20 10",
"output": "20"
},
{
"input": "1 4 100",
"output": "99"
},
{
"input": "100 1 91",
"output": "99"
},
{
"input": "1 45 100",
"output": "99"
},
{
"input": "1 2 3",
"output": "2"
},
{
"... | 1,698,146,650 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | s=input().split()
s=sorted(s)
s=int(s[2])-int(s[0])
print(s)
| Title: The New Year: Meeting Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They ... | ```python
s=input().split()
s=sorted(s)
s=int(s[2])-int(s[0])
print(s)
``` | 0 | |
831 | A | Unimodal Array | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Array of integers is unimodal, if:
- it is strictly increasing in the beginning; - after that it is constant; - after that it is strictly decreasing.
The first block (increasing) and the last block (decreasing) may be absent. It is allowed that both of this blocks are absent.
For example, the following three arra... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1<=000) — the elements of the array. | Print "YES" if the given array is unimodal. Otherwise, print "NO".
You can output each letter in any case (upper or lower). | [
"6\n1 5 5 5 4 2\n",
"5\n10 20 30 20 10\n",
"4\n1 2 1 2\n",
"7\n3 3 3 3 3 3 3\n"
] | [
"YES\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example the array is unimodal, because it is strictly increasing in the beginning (from position 1 to position 2, inclusively), that it is constant (from position 2 to position 4, inclusively) and then it is strictly decreasing (from position 4 to position 6, inclusively). | 500 | [
{
"input": "6\n1 5 5 5 4 2",
"output": "YES"
},
{
"input": "5\n10 20 30 20 10",
"output": "YES"
},
{
"input": "4\n1 2 1 2",
"output": "NO"
},
{
"input": "7\n3 3 3 3 3 3 3",
"output": "YES"
},
{
"input": "6\n5 7 11 11 2 1",
"output": "YES"
},
{
"input":... | 1,640,632,518 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | a=int(input())
b=list(map(int,input().split()))
i=1
while i<b and b[i-1]<b[i]:
i+=1
while i<b and b[i-1]==b[i]:
i+=1
while i<b and b[i-1]>b[i]:
i+=1
if i==a:
print('YES')
else:
print('NO') | Title: Unimodal Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Array of integers is unimodal, if:
- it is strictly increasing in the beginning; - after that it is constant; - after that it is strictly decreasing.
The first block (increasing) and the last block (decreasing) may ... | ```python
a=int(input())
b=list(map(int,input().split()))
i=1
while i<b and b[i-1]<b[i]:
i+=1
while i<b and b[i-1]==b[i]:
i+=1
while i<b and b[i-1]>b[i]:
i+=1
if i==a:
print('YES')
else:
print('NO')
``` | -1 | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,436,561,250 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 49,971,200 | a=int(input(""))
b=c=["Sheldon","Leonard","Penny","Rajesh","Howard"]
o=2
for i in range(0,(a-1)):
for j in range (0,5):
for x in range (0,o):
b.append(c[j])
o += 1
if b[a-1] == "Sheldon" :
print("Sheldon")
elif b[a-1] == "Leonard" :
print("Leonard")
elif b[a-1] == "Penn... | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
a=int(input(""))
b=c=["Sheldon","Leonard","Penny","Rajesh","Howard"]
o=2
for i in range(0,(a-1)):
for j in range (0,5):
for x in range (0,o):
b.append(c[j])
o += 1
if b[a-1] == "Sheldon" :
print("Sheldon")
elif b[a-1] == "Leonard" :
print("Leonard")
elif b[a-1... | 0 |
365 | A | Good Number | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number every time it occurs in array *a*). | The first line contains integers *n* and *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=9). The *i*-th of the following *n* lines contains integer *a**i* without leading zeroes (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the number of *k*-good numbers in *a*. | [
"10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n",
"2 1\n1\n10\n"
] | [
"10\n",
"1\n"
] | none | 500 | [
{
"input": "10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560",
"output": "10"
},
{
"input": "2 1\n1\n10",
"output": "1"
},
{
"input": "1 0\n1000000000",
"output": "1"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
... | 1,673,420,741 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | a, k = map(int,input().split())
count = 0
k_list = [str(i) for i in range(k)]
k_list.append(str(k))
str_k = ''.join(k_list)
for x in range(a):
list_a = [(x) for x in input()]
list_a.sort()
str_a = "".join(list_a)
if str_a == str_k:
count += 1
print(count)
print(k_list)
print(str_k... | Title: Good Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number eve... | ```python
a, k = map(int,input().split())
count = 0
k_list = [str(i) for i in range(k)]
k_list.append(str(k))
str_k = ''.join(k_list)
for x in range(a):
list_a = [(x) for x in input()]
list_a.sort()
str_a = "".join(list_a)
if str_a == str_k:
count += 1
print(count)
print(k_list)
p... | 0 | |
443 | A | Anton and Letters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to ti... | The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space. | Print a single number — the number of distinct letters in Anton's set. | [
"{a, b, c}\n",
"{b, a, b, a}\n",
"{}\n"
] | [
"3\n",
"2\n",
"0\n"
] | none | 500 | [
{
"input": "{a, b, c}",
"output": "3"
},
{
"input": "{b, a, b, a}",
"output": "2"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{a, a, c, b, b, b, c, c, c, c}",
"output": "3"
},
{
"input": "{a, c, b, b}",
"output": "3"
},
{
"input": "{a, b}",
"o... | 1,689,743,801 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 46 | 0 | # cook your dish here
s = input()
se = set()
for i in range(len(s)):
if s[i].isalpha():
se.add(s[i])
print(len(se)) | Title: Anton and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the begi... | ```python
# cook your dish here
s = input()
se = set()
for i in range(len(s)):
if s[i].isalpha():
se.add(s[i])
print(len(se))
``` | 3 | |
595 | A | Vitaly and Night | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vitaly sees a building of *n* floors and 2·*m* windows on each floor. On each floor there are *m* flats num... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of floors in the house and the number of flats on each floor respectively.
Next *n* lines describe the floors from top to bottom and contain 2·*m* characters each. If the *i*-th window of the given floor has lights on,... | Print a single integer — the number of flats that have lights on in at least one window, that is, the flats where, according to Vitaly, people aren't sleeping. | [
"2 2\n0 0 0 1\n1 0 1 1\n",
"1 3\n1 1 0 1 0 0\n"
] | [
"3\n",
"2\n"
] | In the first test case the house has two floors, two flats on each floor. That is, in total there are 4 flats. The light isn't on only on the second floor in the left flat. That is, in both rooms of the flat the light is off.
In the second test case the house has one floor and the first floor has three flats. The ligh... | 500 | [
{
"input": "2 2\n0 0 0 1\n1 0 1 1",
"output": "3"
},
{
"input": "1 3\n1 1 0 1 0 0",
"output": "2"
},
{
"input": "3 3\n1 1 1 1 1 1\n1 1 0 1 1 0\n1 0 0 0 1 1",
"output": "8"
},
{
"input": "1 5\n1 0 1 1 1 0 1 1 1 1",
"output": "5"
},
{
"input": "1 100\n1 1 1 1 1 1 1 ... | 1,583,172,794 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 124 | 102,400 | n, m = input().split()
awake = 0
for x in range(int(n)):
windows = list(map(int, input().split()))
for y in range(0,len(windows),2):
if windows[y] == 1 or windows[y+1] == 1:
awake += 1
print(awake) | Title: Vitaly and Night
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vital... | ```python
n, m = input().split()
awake = 0
for x in range(int(n)):
windows = list(map(int, input().split()))
for y in range(0,len(windows),2):
if windows[y] == 1 or windows[y+1] == 1:
awake += 1
print(awake)
``` | 3 | |
911 | C | Three Garlands | PROGRAMMING | 1,400 | [
"brute force",
"constructive algorithms"
] | null | null | Mishka is decorating the Christmas tree. He has got three garlands, and all of them will be put on the tree. After that Mishka will switch these garlands on.
When a garland is switched on, it periodically changes its state — sometimes it is lit, sometimes not. Formally, if *i*-th garland is switched on during *x*-th s... | The first line contains three integers *k*1, *k*2 and *k*3 (1<=≤<=*k**i*<=≤<=1500) — time intervals of the garlands. | If Mishka can choose moments of time to switch on the garlands in such a way that each second after switching the garlands on at least one garland will be lit, print YES.
Otherwise, print NO. | [
"2 2 3\n",
"4 2 3\n"
] | [
"YES\n",
"NO\n"
] | In the first example Mishka can choose *x*<sub class="lower-index">1</sub> = 1, *x*<sub class="lower-index">2</sub> = 2, *x*<sub class="lower-index">3</sub> = 1. The first garland will be lit during seconds 1, 3, 5, 7, ..., the second — 2, 4, 6, 8, ..., which already cover all the seconds after the 2-nd one. It doesn't... | 0 | [
{
"input": "2 2 3",
"output": "YES"
},
{
"input": "4 2 3",
"output": "NO"
},
{
"input": "1499 1498 1500",
"output": "NO"
},
{
"input": "1500 1500 1500",
"output": "NO"
},
{
"input": "100 4 1",
"output": "YES"
},
{
"input": "4 2 4",
"output": "YES"
... | 1,672,304,233 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 20 | 46 | 0 | dta = [int(i) for i in input().split()]
if 1 in dta or dta.count(2) == 2 or dta.count(3) == 3 or sorted(dta) == [2, 4, 4]:
print("YES")
else:
print("NO") | Title: Three Garlands
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka is decorating the Christmas tree. He has got three garlands, and all of them will be put on the tree. After that Mishka will switch these garlands on.
When a garland is switched on, it periodically changes its st... | ```python
dta = [int(i) for i in input().split()]
if 1 in dta or dta.count(2) == 2 or dta.count(3) == 3 or sorted(dta) == [2, 4, 4]:
print("YES")
else:
print("NO")
``` | 0 | |
985 | C | Liebig's Barrels | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | You have *m*<==<=*n*·*k* wooden staves. The *i*-th stave has length *a**i*. You have to assemble *n* barrels consisting of *k* staves each, you can use any *k* staves to construct a barrel. Each stave must belong to exactly one barrel.
Let volume *v**j* of barrel *j* be equal to the length of the minimal stave in it.
... | The first line contains three space-separated integers *n*, *k* and *l* (1<=≤<=*n*,<=*k*<=≤<=105, 1<=≤<=*n*·*k*<=≤<=105, 0<=≤<=*l*<=≤<=109).
The second line contains *m*<==<=*n*·*k* space-separated integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=109) — lengths of staves. | Print single integer — maximal total sum of the volumes of barrels or 0 if it's impossible to construct exactly *n* barrels satisfying the condition |*v**x*<=-<=*v**y*|<=≤<=*l* for any 1<=≤<=*x*<=≤<=*n* and 1<=≤<=*y*<=≤<=*n*. | [
"4 2 1\n2 2 1 2 3 2 2 3\n",
"2 1 0\n10 10\n",
"1 2 1\n5 2\n",
"3 2 1\n1 2 3 4 5 6\n"
] | [
"7\n",
"20\n",
"2\n",
"0\n"
] | In the first example you can form the following barrels: [1, 2], [2, 2], [2, 3], [2, 3].
In the second example you can form the following barrels: [10], [10].
In the third example you can form the following barrels: [2, 5].
In the fourth example difference between volumes of barrels in any partition is at least 2 so... | 0 | [
{
"input": "4 2 1\n2 2 1 2 3 2 2 3",
"output": "7"
},
{
"input": "2 1 0\n10 10",
"output": "20"
},
{
"input": "1 2 1\n5 2",
"output": "2"
},
{
"input": "3 2 1\n1 2 3 4 5 6",
"output": "0"
},
{
"input": "10 3 189\n267 697 667 4 52 128 85 616 142 344 413 660 962 194... | 1,669,888,969 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 78 | 14,540,800 | n, k, r = map(int, input().split())
a = sorted(list(map(int, input().split())))
if (a[n - 1] - a[0]) > r:
print(0)
else:
w = 0
for i in range(n):
w += a[i]
print(w)
| Title: Liebig's Barrels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *m*<==<=*n*·*k* wooden staves. The *i*-th stave has length *a**i*. You have to assemble *n* barrels consisting of *k* staves each, you can use any *k* staves to construct a barrel. Each stave must belong to ex... | ```python
n, k, r = map(int, input().split())
a = sorted(list(map(int, input().split())))
if (a[n - 1] - a[0]) > r:
print(0)
else:
w = 0
for i in range(n):
w += a[i]
print(w)
``` | 0 | |
245 | A | System Administrator | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus is a system administrator. There are two servers under his strict guidance — *a* and *b*. To stay informed about the servers' performance, Polycarpus executes commands "ping a" and "ping b". Each ping command sends exactly ten packets to the server specified in the argument of the command. Executing a progra... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=1000) — the number of commands Polycarpus has fulfilled. Each of the following *n* lines contains three integers — the description of the commands. The *i*-th of these lines contains three space-separated integers *t**i*, *x**i*, *y**i* (1<=≤<=*t**i*<=≤<=2; *x... | In the first line print string "LIVE" (without the quotes) if server *a* is "alive", otherwise print "DEAD" (without the quotes).
In the second line print the state of server *b* in the similar format. | [
"2\n1 5 5\n2 6 4\n",
"3\n1 0 10\n2 0 10\n1 10 0\n"
] | [
"LIVE\nLIVE\n",
"LIVE\nDEAD\n"
] | Consider the first test case. There 10 packets were sent to server *a*, 5 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network. Overall there were 10 packets sent to server *b*, 6 of them reached it. Therefore, at least half of all packets sent to t... | 0 | [
{
"input": "2\n1 5 5\n2 6 4",
"output": "LIVE\nLIVE"
},
{
"input": "3\n1 0 10\n2 0 10\n1 10 0",
"output": "LIVE\nDEAD"
},
{
"input": "10\n1 3 7\n2 4 6\n1 2 8\n2 5 5\n2 10 0\n2 10 0\n1 8 2\n2 2 8\n2 10 0\n1 1 9",
"output": "DEAD\nLIVE"
},
{
"input": "11\n1 8 2\n1 6 4\n1 9 1\n1... | 1,588,135,055 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 404 | 2,150,400 | a=0
b=0
success_a=0
success_b=0
for _ in range(int(input())):
x,t1,t2=map(int(input()))
if x==1:
success_a+=t1
a+=10
else:
success_b+=t1
b+=1
if success_a>=a//2:
print("LIVE")
else:
print("DEAD")
if success_b>=b//2:
print("LIVE")
else:
print... | Title: System Administrator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus is a system administrator. There are two servers under his strict guidance — *a* and *b*. To stay informed about the servers' performance, Polycarpus executes commands "ping a" and "ping b". Each ping co... | ```python
a=0
b=0
success_a=0
success_b=0
for _ in range(int(input())):
x,t1,t2=map(int(input()))
if x==1:
success_a+=t1
a+=10
else:
success_b+=t1
b+=1
if success_a>=a//2:
print("LIVE")
else:
print("DEAD")
if success_b>=b//2:
print("LIVE")
else:
... | -1 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,634,039,791 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 124 | 6,758,400 | # -*- coding: utf-8 -*-
"""domino.ipynb
Automatically generated by Colaboratory.
Original file is located at
https://colab.research.google.com/drive/1SuTcCGTisxqY5IGxKwxt8NeBDjsKoz-t
"""
m, n = map(int, input().split())
if m == 1 and n == 1:
print(0)
else:
print(int(m * n) // 2) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
# -*- coding: utf-8 -*-
"""domino.ipynb
Automatically generated by Colaboratory.
Original file is located at
https://colab.research.google.com/drive/1SuTcCGTisxqY5IGxKwxt8NeBDjsKoz-t
"""
m, n = map(int, input().split())
if m == 1 and n == 1:
print(0)
else:
print(int(m * n) // 2)
``` | 3.956411 |
127 | A | Wasted Time | PROGRAMMING | 900 | [
"geometry"
] | null | null | Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count the time he has wasted signing papers.
Mr. Scrooge's signature can be represented as a polyline ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). Each of the following *n* lines contains the coordinates of the polyline's endpoints. The *i*-th one contains coordinates of the point *A**i* — integers *x**i* and *y**i*, separated by a space.
All points *A**i* are different. Th... | Print one real number — the total time Scrooges wastes on signing the papers in seconds. The absolute or relative error should not exceed 10<=-<=6. | [
"2 1\n0 0\n10 0\n",
"5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0\n",
"6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0\n"
] | [
"0.200000000",
"6.032163204",
"3.000000000"
] | none | 500 | [
{
"input": "2 1\n0 0\n10 0",
"output": "0.200000000"
},
{
"input": "5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0",
"output": "6.032163204"
},
{
"input": "6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0",
"output": "3.000000000"
},
{
"input": "10 95\n-20 -5\n2 -8\n14 13\n10 3\n17 11\n13 -12\n-6 11\n1... | 1,659,891,398 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | import math
n,k = map(int, input().split())
dis = 0
path = []
past = None
for _ in range(n):
x,y = map(int, input().split())
if past:
dis += math.sqrt((x-past[0])**2 + (y-past[1])**2)
past = [x,y]
print(k*(dis/50))
| Title: Wasted Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count ... | ```python
import math
n,k = map(int, input().split())
dis = 0
path = []
past = None
for _ in range(n):
x,y = map(int, input().split())
if past:
dis += math.sqrt((x-past[0])**2 + (y-past[1])**2)
past = [x,y]
print(k*(dis/50))
``` | 3 | |
485 | A | Factory | PROGRAMMING | 1,400 | [
"implementation",
"math",
"matrices"
] | null | null | One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the factory has to produce (remainder after dividing *x* by *m*) more details. Unfortunately, no cu... | The first line contains two integers *a* and *m* (1<=≤<=*a*,<=*m*<=≤<=105). | Print "Yes" (without quotes) if the production will eventually stop, otherwise print "No". | [
"1 5\n",
"3 6\n"
] | [
"No\n",
"Yes\n"
] | none | 1,000 | [
{
"input": "1 5",
"output": "No"
},
{
"input": "3 6",
"output": "Yes"
},
{
"input": "1 8",
"output": "Yes"
},
{
"input": "2 3",
"output": "No"
},
{
"input": "3 24",
"output": "Yes"
},
{
"input": "1 1",
"output": "Yes"
},
{
"input": "100000 ... | 1,661,563,429 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 1,000 | 0 | a, m = map(int, input().split())
c = a%m
detail = a +c
while True:
check = detail%m
if not check:
print('Yes')
break
elif check == c:
print('No')
break
detail += check | Title: Factory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the fac... | ```python
a, m = map(int, input().split())
c = a%m
detail = a +c
while True:
check = detail%m
if not check:
print('Yes')
break
elif check == c:
print('No')
break
detail += check
``` | 0 | |
242 | B | Big Segment | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all oth... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of segments. Next *n* lines contain the descriptions of the segments. The *i*-th line contains two space-separated integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109) — the borders of the *i*-th segment.
It is guaranteed that no two segments c... | Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input. | [
"3\n1 1\n2 2\n3 3\n",
"6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10\n"
] | [
"-1\n",
"3\n"
] | none | 1,000 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "-1"
},
{
"input": "6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10",
"output": "3"
},
{
"input": "4\n1 5\n2 2\n2 4\n2 5",
"output": "1"
},
{
"input": "5\n3 3\n1 3\n2 2\n2 3\n1 2",
"output": "2"
},
{
"input": "7\n7 7\n8 8\n3 7\n1 6\n1 ... | 1,691,994,442 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 45 | 1,372 | 12,288,000 | a = []
b = []
n = int(input())
for _ in range(n):
x,y = map(int,input().split());a.append(x);b.append(y)
mn = min(a)
mx = max(b)
for i in range(n):
if a[i] <= mn and b[i] >= mx:print(i + 1);exit()
else:print(-1)
| Title: Big Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments ... | ```python
a = []
b = []
n = int(input())
for _ in range(n):
x,y = map(int,input().split());a.append(x);b.append(y)
mn = min(a)
mx = max(b)
for i in range(n):
if a[i] <= mn and b[i] >= mx:print(i + 1);exit()
else:print(-1)
``` | 3 | |
612 | B | HDD is Outdated Technology | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | HDD hard drives group data by sectors. All files are split to fragments and each of them are written in some sector of hard drive. Note the fragments can be written in sectors in arbitrary order.
One of the problems of HDD hard drives is the following: the magnetic head should move from one sector to another to read s... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of fragments.
The second line contains *n* different integers *f**i* (1<=≤<=*f**i*<=≤<=*n*) — the number of the fragment written in the *i*-th sector. | Print the only integer — the number of time units needed to read the file. | [
"3\n3 1 2\n",
"5\n1 3 5 4 2\n"
] | [
"3\n",
"10\n"
] | In the second example the head moves in the following way:
- 1->2 means movement from the sector 1 to the sector 5, i.e. it takes 4 time units - 2->3 means movement from the sector 5 to the sector 2, i.e. it takes 3 time units - 3->4 means movement from the sector 2 to the sector 4, i.e. it takes 2 time un... | 0 | [
{
"input": "3\n3 1 2",
"output": "3"
},
{
"input": "5\n1 3 5 4 2",
"output": "10"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "10\n8 2 10 3 4 6 1 7 9 5",
"output": "40"
... | 1,681,453,815 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 24 | 140 | 28,672,000 | n = int(input())
lst = list(map(int, input().split()))
dc = {x:i for i, x in enumerate(lst)}
res, pos = 0, dc[1]
for i in range(2, n+1):
nextPos = dc[i]
res += abs(pos-nextPos)
pos = nextPos
print(res) | Title: HDD is Outdated Technology
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HDD hard drives group data by sectors. All files are split to fragments and each of them are written in some sector of hard drive. Note the fragments can be written in sectors in arbitrary order.
One of the ... | ```python
n = int(input())
lst = list(map(int, input().split()))
dc = {x:i for i, x in enumerate(lst)}
res, pos = 0, dc[1]
for i in range(2, n+1):
nextPos = dc[i]
res += abs(pos-nextPos)
pos = nextPos
print(res)
``` | 3 | |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,602,516,143 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 218 | 307,200 | s=input('')
n,m=s.split(' ')
n=int(n)
m=int(m)
l=[]
for i in range(n):
s1=input('')
l.append(list(s1))
l1=[]
for i in range(n):
# print(l[i])
temp=l[i].count('S')
# print(temp)
if(temp==0):
for j in range(m):
l1.append([i,j])
l2=(list(map(list,zip(*l))))
# prin... | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
s=input('')
n,m=s.split(' ')
n=int(n)
m=int(m)
l=[]
for i in range(n):
s1=input('')
l.append(list(s1))
l1=[]
for i in range(n):
# print(l[i])
temp=l[i].count('S')
# print(temp)
if(temp==0):
for j in range(m):
l1.append([i,j])
l2=(list(map(list,zip(*l))... | 3 | |
620 | A | Professor GukiZ's Robot | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of them) by one (decrease or increase). So the robot can move in one of the 8 directions. Find the minimal numbe... | The first line contains two integers *x*1,<=*y*1 (<=-<=109<=≤<=*x*1,<=*y*1<=≤<=109) — the start position of the robot.
The second line contains two integers *x*2,<=*y*2 (<=-<=109<=≤<=*x*2,<=*y*2<=≤<=109) — the finish position of the robot. | Print the only integer *d* — the minimal number of steps to get the finish position. | [
"0 0\n4 5\n",
"3 4\n6 1\n"
] | [
"5\n",
"3\n"
] | In the first example robot should increase both of its coordinates by one four times, so it will be in position (4, 4). After that robot should simply increase its *y* coordinate and get the finish position.
In the second example robot should simultaneously increase *x* coordinate and decrease *y* coordinate by one th... | 0 | [
{
"input": "0 0\n4 5",
"output": "5"
},
{
"input": "3 4\n6 1",
"output": "3"
},
{
"input": "0 0\n4 6",
"output": "6"
},
{
"input": "1 1\n-3 -5",
"output": "6"
},
{
"input": "-1 -1\n-10 100",
"output": "101"
},
{
"input": "1 -1\n100 -100",
"output":... | 1,654,083,381 | 381 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 61 | 3,379,200 | n = int(input())
a=[i for i in range(1,n+1,2)]
print(str(*a)) | Title: Professor GukiZ's Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of ... | ```python
n = int(input())
a=[i for i in range(1,n+1,2)]
print(str(*a))
``` | -1 | |
990 | A | Commentary Boxes | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation should get the same number of the commentary boxes. If any box is left unoccupied then the delegations wil... | The only line contains four integer numbers $n$, $m$, $a$ and $b$ ($1 \le n, m \le 10^{12}$, $1 \le a, b \le 100$), where $n$ is the initial number of the commentary boxes, $m$ is the number of delegations to come, $a$ is the fee to build a box and $b$ is the fee to demolish a box. | Output the minimal amount of burles organizers should pay to satisfy all the delegations (i.e. to make the number of the boxes be divisible by $m$). It is allowed that the final number of the boxes is equal to $0$. | [
"9 7 3 8\n",
"2 7 3 7\n",
"30 6 17 19\n"
] | [
"15\n",
"14\n",
"0\n"
] | In the first example organizers can build $5$ boxes to make the total of $14$ paying $3$ burles for the each of them.
In the second example organizers can demolish $2$ boxes to make the total of $0$ paying $7$ burles for the each of them.
In the third example organizers are already able to distribute all the boxes eq... | 0 | [
{
"input": "9 7 3 8",
"output": "15"
},
{
"input": "2 7 3 7",
"output": "14"
},
{
"input": "30 6 17 19",
"output": "0"
},
{
"input": "500000000001 1000000000000 100 100",
"output": "49999999999900"
},
{
"input": "1000000000000 750000000001 10 100",
"output": "... | 1,528,630,733 | 5,633 | Python 3 | OK | TESTS | 109 | 108 | 0 | n,m,a,b=map(int,input().split())
if(n%m==0):
print(0)
elif(n>m):
d=n%m
c=(n//m+1)*m-n
t1=c*a
t2=d*b
print(min(t1,t2))
elif(m>n):
c=m-n
d=n-m*(n//m)
t1=c*a
t2=d*b
print(min(t1,t2))
| Title: Commentary Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation shou... | ```python
n,m,a,b=map(int,input().split())
if(n%m==0):
print(0)
elif(n>m):
d=n%m
c=(n//m+1)*m-n
t1=c*a
t2=d*b
print(min(t1,t2))
elif(m>n):
c=m-n
d=n-m*(n//m)
t1=c*a
t2=d*b
print(min(t1,t2))
``` | 3 | |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. E... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match di... | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,653,477,191 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 62 | 0 | l = []
for _ in range(int(input())):
z = input()
l.append(z)
la = set(l)
la = [i for i in la]
po = [0 for i in range(len(la))]
for _ in range(len(la)):
for j in l:
if la[_] == j:
po[_]+=1
z = max(po)
for _ in range(len(la)):
if z == po[_]:
print(la[_])
... | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process... | ```python
l = []
for _ in range(int(input())):
z = input()
l.append(z)
la = set(l)
la = [i for i in la]
po = [0 for i in range(len(la))]
for _ in range(len(la)):
for j in l:
if la[_] == j:
po[_]+=1
z = max(po)
for _ in range(len(la)):
if z == po[_]:
print(la[_])
... | 3.9845 |
897 | B | Chtholly's request | PROGRAMMING | 1,300 | [
"brute force"
] | null | null | — I experienced so many great things.
— You gave me memories like dreams... But I have to leave now...
— One last request, can you...
— Help me solve a Codeforces problem?
— ......
— What?
Chtholly has been thinking about a problem for days:
If a number is palindrome and length of its decimal representation with... | The first line contains two integers *k* and *p* (1<=≤<=*k*<=≤<=105,<=1<=≤<=*p*<=≤<=109). | Output single integer — answer to the problem. | [
"2 100\n",
"5 30\n"
] | [
"33\n",
"15\n"
] | In the first example, the smallest zcy number is 11, and the second smallest zcy number is 22.
In the second example, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/68fffad54395f7d920ad0384e07c6215ddc64141.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 1,000 | [
{
"input": "2 100",
"output": "33"
},
{
"input": "5 30",
"output": "15"
},
{
"input": "42147 412393322",
"output": "251637727"
},
{
"input": "77809 868097296",
"output": "440411873"
},
{
"input": "5105 443422097",
"output": "363192634"
},
{
"input": "7... | 1,666,356,526 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 108 | 0 | def get_zcy(n:int) -> int:
str_n = str(n)
res = str_n + str_n[::-1]
return int(res)
def main():
res = 0
inp = input().split()
k = int(inp[0])
p = int(inp[1])
s = 0
for i in range(1, k + 1):
s += get_zcy(i)
print(s % p)
if __name__ == "__main__":
main()
| Title: Chtholly's request
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
— I experienced so many great things.
— You gave me memories like dreams... But I have to leave now...
— One last request, can you...
— Help me solve a Codeforces problem?
— ......
— What?
Chtholly has been thi... | ```python
def get_zcy(n:int) -> int:
str_n = str(n)
res = str_n + str_n[::-1]
return int(res)
def main():
res = 0
inp = input().split()
k = int(inp[0])
p = int(inp[1])
s = 0
for i in range(1, k + 1):
s += get_zcy(i)
print(s % p)
if __name__ == "__main__":
main()
`... | 3 | |
259 | B | Little Elephant and Magic Square | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table are equal. The figure below shows the magic square, the sum of integers in all its rows, columns and diagonals equals ... | The first three lines of the input contain the Little Elephant's notes. The first line contains elements of the first row of the magic square. The second line contains the elements of the second row, the third line is for the third row. The main diagonal elements that have been forgotten by the Elephant are represented... | Print three lines, in each line print three integers — the Little Elephant's magic square. If there are multiple magic squares, you are allowed to print any of them. Note that all numbers you print must be positive and not exceed 105.
It is guaranteed that there exists at least one magic square that meets the conditio... | [
"0 1 1\n1 0 1\n1 1 0\n",
"0 3 6\n5 0 5\n4 7 0\n"
] | [
"1 1 1\n1 1 1\n1 1 1\n",
"6 3 6\n5 5 5\n4 7 4\n"
] | none | 1,000 | [
{
"input": "0 1 1\n1 0 1\n1 1 0",
"output": "1 1 1\n1 1 1\n1 1 1"
},
{
"input": "0 3 6\n5 0 5\n4 7 0",
"output": "6 3 6\n5 5 5\n4 7 4"
},
{
"input": "0 4 4\n4 0 4\n4 4 0",
"output": "4 4 4\n4 4 4\n4 4 4"
},
{
"input": "0 54 48\n36 0 78\n66 60 0",
"output": "69 54 48\n36 5... | 1,661,352,028 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 404 | 0 | r11, r12, r13 = map(int, input().split())
r21, r22, r23 = map(int, input().split())
r31, r32, r33 = map(int, input().split())
r1 = r12+r11+r13
r2 = r22+r21+r23
r3 = r31+r32+r33
c1 = r11+r21+r31
c2 = r12+r22+r32
c3 = r13+r23+r33
d1 = r11+r22+r33
d2 = r13+r22+r31
maxx = max(r1, r2, r3, c1, c2, c3, d1, d2)
for... | Title: Little Elephant and Magic Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table ... | ```python
r11, r12, r13 = map(int, input().split())
r21, r22, r23 = map(int, input().split())
r31, r32, r33 = map(int, input().split())
r1 = r12+r11+r13
r2 = r22+r21+r23
r3 = r31+r32+r33
c1 = r11+r21+r31
c2 = r12+r22+r32
c3 = r13+r23+r33
d1 = r11+r22+r33
d2 = r13+r22+r31
maxx = max(r1, r2, r3, c1, c2, c3, d1... | 0 | |
136 | A | Presents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift.... | Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*. | [
"4\n2 3 4 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"4 1 2 3\n",
"1 3 2\n",
"1 2\n"
] | none | 500 | [
{
"input": "4\n2 3 4 1",
"output": "4 1 2 3"
},
{
"input": "3\n1 3 2",
"output": "1 3 2"
},
{
"input": "2\n1 2",
"output": "1 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 3 2 6 4 5 7 9 8 10",
"output": "1 3 2 5 6 4 7 9 8 10"
},
{
"input"... | 1,691,357,546 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 5 | 122 | 0 | n = input()
friends_num = input()
l_f_n = friends_num.split()
l = []
for i in l_f_n:
l.insert(int(i)-1, str(l_f_n.index(i)+1))
s = " ".join(l)
print(s) | Title: Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on t... | ```python
n = input()
friends_num = input()
l_f_n = friends_num.split()
l = []
for i in l_f_n:
l.insert(int(i)-1, str(l_f_n.index(i)+1))
s = " ".join(l)
print(s)
``` | 0 | |
467 | A | George and Accommodation | PROGRAMMING | 800 | [
"implementation"
] | null | null | George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want to live in the same room. The dormitory has *n* rooms in total. At the moment the *i*-th room has *p**i* peopl... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of rooms.
The *i*-th of the next *n* lines contains two integers *p**i* and *q**i* (0<=≤<=*p**i*<=≤<=*q**i*<=≤<=100) — the number of people who already live in the *i*-th room and the room's capacity. | Print a single integer — the number of rooms where George and Alex can move in. | [
"3\n1 1\n2 2\n3 3\n",
"3\n1 10\n0 10\n10 10\n"
] | [
"0\n",
"2\n"
] | none | 500 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "0"
},
{
"input": "3\n1 10\n0 10\n10 10",
"output": "2"
},
{
"input": "2\n36 67\n61 69",
"output": "2"
},
{
"input": "3\n21 71\n10 88\n43 62",
"output": "3"
},
{
"input": "3\n1 2\n2 3\n3 4",
"output": "0"
},
{
"... | 1,687,022,353 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 0 | 0 | test_c = int(input())
p = []
q = []
for i in range(test_c):
s = input()
a, b = tuple(map(int, s.split()))
p.append(a)
q.append(b)
c = 0
for i in range(len(p)):
if p[i] + 2 <= p[j]:
c += 1
print(c)
| Title: George and Accommodation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want ... | ```python
test_c = int(input())
p = []
q = []
for i in range(test_c):
s = input()
a, b = tuple(map(int, s.split()))
p.append(a)
q.append(b)
c = 0
for i in range(len(p)):
if p[i] + 2 <= p[j]:
c += 1
print(c)
``` | -1 | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,686,052,043 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 14 | 1,000 | 0 | a,b = (int(i) for i in input().split())
counter=1
if a%5==0:
while True:
if (((a*counter)%10))==0:
break
counter+=1
else:
while True:
if (((a*counter)%10)-b)==0:
break
counter+=1
print(counter) | Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
a,b = (int(i) for i in input().split())
counter=1
if a%5==0:
while True:
if (((a*counter)%10))==0:
break
counter+=1
else:
while True:
if (((a*counter)%10)-b)==0:
break
counter+=1
print(counter)
``` | 0 | |
443 | A | Anton and Letters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to ti... | The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space. | Print a single number — the number of distinct letters in Anton's set. | [
"{a, b, c}\n",
"{b, a, b, a}\n",
"{}\n"
] | [
"3\n",
"2\n",
"0\n"
] | none | 500 | [
{
"input": "{a, b, c}",
"output": "3"
},
{
"input": "{b, a, b, a}",
"output": "2"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{a, a, c, b, b, b, c, c, c, c}",
"output": "3"
},
{
"input": "{a, c, b, b}",
"output": "3"
},
{
"input": "{a, b}",
"o... | 1,689,434,565 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 31 | 0 | a = list(input())
del a[0]
del a[-1]
if ',' in a:
a = ''.join(a).split(', ')
print(len(set(a)))
else:
print(len(a)) | Title: Anton and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the begi... | ```python
a = list(input())
del a[0]
del a[-1]
if ',' in a:
a = ''.join(a).split(', ')
print(len(set(a)))
else:
print(len(a))
``` | 3 | |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahed... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (withou... | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,673,795,714 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 265 | 0 | n=int(input())
count=0
for i in range(0,n):
s=input()
if s== "Tetrahedron":
count+=4
elif s== "Cube":
count+=6
elif s== "Octahedron":
count+=8
elif s== "Dodecahedron":
count+=12
elif s== "Icosahedron":
count+=20
print(count) | Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahe... | ```python
n=int(input())
count=0
for i in range(0,n):
s=input()
if s== "Tetrahedron":
count+=4
elif s== "Cube":
count+=6
elif s== "Octahedron":
count+=8
elif s== "Dodecahedron":
count+=12
elif s== "Icosahedron":
count+=20
print(count)
``` | 3 | |
998 | B | Cutting | PROGRAMMING | 1,200 | [
"dp",
"greedy",
"sortings"
] | null | null | There are a lot of things which could be cut — trees, paper, "the rope". In this problem you are going to cut a sequence of integers.
There is a sequence of integers, which contains the equal number of even and odd numbers. Given a limited budget, you need to make maximum possible number of cuts such that each resulti... | First line of the input contains an integer $n$ ($2 \le n \le 100$) and an integer $B$ ($1 \le B \le 100$) — the number of elements in the sequence and the number of bitcoins you have.
Second line contains $n$ integers: $a_1$, $a_2$, ..., $a_n$ ($1 \le a_i \le 100$) — elements of the sequence, which contains the equal... | Print the maximum possible number of cuts which can be made while spending no more than $B$ bitcoins. | [
"6 4\n1 2 5 10 15 20\n",
"4 10\n1 3 2 4\n",
"6 100\n1 2 3 4 5 6\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample the optimal answer is to split sequence between $2$ and $5$. Price of this cut is equal to $3$ bitcoins.
In the second sample it is not possible to make even one cut even with unlimited number of bitcoins.
In the third sample the sequence should be cut between $2$ and $3$, and between $4$ and $5$.... | 1,000 | [
{
"input": "6 4\n1 2 5 10 15 20",
"output": "1"
},
{
"input": "4 10\n1 3 2 4",
"output": "0"
},
{
"input": "6 100\n1 2 3 4 5 6",
"output": "2"
},
{
"input": "2 100\n13 78",
"output": "0"
},
{
"input": "10 1\n56 56 98 2 11 64 97 41 95 53",
"output": "0"
},
... | 1,530,517,573 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 124 | 307,200 | n,b=[int(x) for x in input().split()]
a=[int(x) for x in input().split()]
seg=[0]
odd,ev,i=0,0,0
while(i<n):
if(a[i]%2==0):
ev+=1
else:
odd+=1
if ev==odd:
seg.append(i)
i+=1
ans=0
k=b
if len(seg)>2:
for i in range(len(seg)-1):
temp=0
k=b... | Title: Cutting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are a lot of things which could be cut — trees, paper, "the rope". In this problem you are going to cut a sequence of integers.
There is a sequence of integers, which contains the equal number of even and odd numbers. Gi... | ```python
n,b=[int(x) for x in input().split()]
a=[int(x) for x in input().split()]
seg=[0]
odd,ev,i=0,0,0
while(i<n):
if(a[i]%2==0):
ev+=1
else:
odd+=1
if ev==odd:
seg.append(i)
i+=1
ans=0
k=b
if len(seg)>2:
for i in range(len(seg)-1):
temp=0
... | 0 | |
436 | A | Feed with Candy | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | The hero of the Cut the Rope game is a little monster named Om Nom. He loves candies. And what a coincidence! He also is the hero of today's problem.
One day, Om Nom visited his friend Evan. Evan has *n* candies of two types (fruit drops and caramel drops), the *i*-th candy hangs at the height of *h**i* centimeters ab... | The first line contains two integers, *n* and *x* (1<=≤<=*n*,<=*x*<=≤<=2000) — the number of sweets Evan has and the initial height of Om Nom's jump.
Each of the following *n* lines contains three integers *t**i*,<=*h**i*,<=*m**i* (0<=≤<=*t**i*<=≤<=1; 1<=≤<=*h**i*,<=*m**i*<=≤<=2000) — the type, height and the mass of... | Print a single integer — the maximum number of candies Om Nom can eat. | [
"5 3\n0 2 4\n1 3 1\n0 8 3\n0 20 10\n1 5 5\n"
] | [
"4\n"
] | One of the possible ways to eat 4 candies is to eat them in the order: 1, 5, 3, 2. Let's assume the following scenario:
1. Initially, the height of Om Nom's jump equals 3. He can reach candies 1 and 2. Let's assume that he eats candy 1. As the mass of this candy equals 4, the height of his jump will rise to 3 + 4 = 7... | 1,000 | [
{
"input": "5 3\n0 2 4\n1 3 1\n0 8 3\n0 20 10\n1 5 5",
"output": "4"
},
{
"input": "5 2\n1 15 2\n1 11 2\n0 17 2\n0 16 1\n1 18 2",
"output": "0"
},
{
"input": "6 2\n1 17 3\n1 6 1\n0 4 2\n1 10 1\n1 7 3\n1 5 1",
"output": "0"
},
{
"input": "7 2\n1 14 1\n1 9 2\n0 6 3\n0 20 2\n0 4... | 1,402,675,096 | 1,696 | Python 3 | WRONG_ANSWER | PRETESTS | 6 | 62 | 0 | n,x=map(int,input().split())
a0=[]
a1=[]
for i in range(n):
b=list(map(int,input().split()))
if b[0]:
a1.append(b[1:])
else:
a0.append(b[1:])
a0.sort()
a1.sort()
k=0
i=0
l0=len(a0)
l1=len(a1)
y=x
if a0[0][0]<=y:
while i<l0 and i<l1:
if a0[i][0]<=y:
... | Title: Feed with Candy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The hero of the Cut the Rope game is a little monster named Om Nom. He loves candies. And what a coincidence! He also is the hero of today's problem.
One day, Om Nom visited his friend Evan. Evan has *n* candies of two... | ```python
n,x=map(int,input().split())
a0=[]
a1=[]
for i in range(n):
b=list(map(int,input().split()))
if b[0]:
a1.append(b[1:])
else:
a0.append(b[1:])
a0.sort()
a1.sort()
k=0
i=0
l0=len(a0)
l1=len(a1)
y=x
if a0[0][0]<=y:
while i<l0 and i<l1:
if a0[i][0]<=y:
... | 0 | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,693,126,435 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | y = int(input())
print(2013 if y == 1987 else y+1) | Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
y = int(input())
print(2013 if y == 1987 else y+1)
``` | 0 | |
796 | A | Buying A House | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Zane the wizard had never loved anyone before, until he fell in love with a girl, whose name remains unknown to us.
The girl lives in house *m* of a village. There are *n* houses in that village, lining in a straight line from left to right: house 1, house 2, ..., house *n*. The village is also well-structured: house ... | The first line contains three integers *n*, *m*, and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*m*<=≤<=*n*, 1<=≤<=*k*<=≤<=100) — the number of houses in the village, the house where the girl lives, and the amount of money Zane has (in dollars), respectively.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=... | Print one integer — the minimum distance, in meters, from the house where the girl Zane likes lives to the house Zane can buy. | [
"5 1 20\n0 27 32 21 19\n",
"7 3 50\n62 0 0 0 99 33 22\n",
"10 5 100\n1 0 1 0 0 0 0 0 1 1\n"
] | [
"40",
"30",
"20"
] | In the first sample, with *k* = 20 dollars, Zane can buy only house 5. The distance from house *m* = 1 to house 5 is 10 + 10 + 10 + 10 = 40 meters.
In the second sample, Zane can buy houses 6 and 7. It is better to buy house 6 than house 7, since house *m* = 3 and house 6 are only 30 meters away, while house *m* = 3 a... | 500 | [
{
"input": "5 1 20\n0 27 32 21 19",
"output": "40"
},
{
"input": "7 3 50\n62 0 0 0 99 33 22",
"output": "30"
},
{
"input": "10 5 100\n1 0 1 0 0 0 0 0 1 1",
"output": "20"
},
{
"input": "5 3 1\n1 1 0 0 1",
"output": "10"
},
{
"input": "5 5 5\n1 0 5 6 0",
"outpu... | 1,493,313,711 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 62 | 5,529,600 | n,m,k=map(int,input().split())
a=list(map(int,input().split()))
b=n
for i in range(n):
if a[i]!=0 and a[i]<=k:
c=abs(m - (i+1))
if c<b:
b = c
print(b * 10) | Title: Buying A House
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Zane the wizard had never loved anyone before, until he fell in love with a girl, whose name remains unknown to us.
The girl lives in house *m* of a village. There are *n* houses in that village, lining in a straight li... | ```python
n,m,k=map(int,input().split())
a=list(map(int,input().split()))
b=n
for i in range(n):
if a[i]!=0 and a[i]<=k:
c=abs(m - (i+1))
if c<b:
b = c
print(b * 10)
``` | 3 | |
20 | C | Dijkstra? | PROGRAMMING | 1,900 | [
"graphs",
"shortest paths"
] | C. Dijkstra? | 1 | 64 | You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*. | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105), where *n* is the number of vertices and *m* is the number of edges. Following *m* lines contain one edge each in form *a**i*, *b**i* and *w**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=1<=≤<=*w**i*<=≤<=106), where *a**i*,<=*b**i* are edge... | Write the only integer -1 in case of no path. Write the shortest path in opposite case. If there are many solutions, print any of them. | [
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n",
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n"
] | [
"1 4 3 5 ",
"1 4 3 5 "
] | none | 1,500 | [
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "2 1\n1 2 1",
"output": "1 2 "
},
{
"input": "3 1\n1 2 1",
"output": "-1"
},
{
"input... | 1,569,156,722 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | class Graph:
def __init__(self):
self.nodes = set()
self.edges = defaultdict(list)
self.distances = {}
def add_node(self, value):
self.nodes.add(value)
def add_edge(self, from_node, to_node, distance):
self.edges[from_node].append(to_node)
self.edges[to_node].append(from_node)... | Title: Dijkstra?
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*.
Input Specification:
The first line contains two integers *n* a... | ```python
class Graph:
def __init__(self):
self.nodes = set()
self.edges = defaultdict(list)
self.distances = {}
def add_node(self, value):
self.nodes.add(value)
def add_edge(self, from_node, to_node, distance):
self.edges[from_node].append(to_node)
self.edges[to_node].append(... | 0 |
68 | E | Contact | PROGRAMMING | 2,900 | [
"geometry"
] | E. Contact | 3 | 256 | Little Petya is preparing for the first contact with aliens. He knows that alien spaceships have shapes of non-degenerate triangles and there will be exactly 4 ships. Landing platform for a ship can be made of 3 special columns located at some points of a Cartesian plane such that these 3 points form a triangle equal t... | Each of 4 lines will contain 6 integers *x*1 *y*1 *x*2 *y*2 *x*3 *y*3 (0<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2,<=*x*3,<=*y*3<=≤<=20), representing 3 points that describe the shape of each of 4 ships. It is guaranteed that 3 points in each line will represent a non-degenerate triangle. | First line should contain minimum number of columns enough to land all spaceships. | [
"0 0 1 0 1 2\n0 0 0 2 2 2\n0 0 3 0 1 2\n0 0 3 0 2 2\n",
"0 0 0 1 1 1\n0 0 0 2 2 2\n0 0 0 5 5 5\n0 0 0 17 17 17\n"
] | [
"4\n",
"9\n"
] | In the first test case columns can be put in these points: (0, 0), (1, 0), (3, 0), (1, 2). Note that the second ship can land using last 3 columns.
In the second test case following points can be chosen: (0, 0), (0, 1), (1, 0), (0, 2), (2, 0), (0, 5), (5, 0), (0, 17), (17, 0). It is impossible to use less than 9 colum... | 2,500 | [] | 1,689,420,682 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | print("_RANDOM_GUESS_1689420680.5839827")# 1689420680.5840013 | Title: Contact
Time Limit: 3 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya is preparing for the first contact with aliens. He knows that alien spaceships have shapes of non-degenerate triangles and there will be exactly 4 ships. Landing platform for a ship can be made of 3 special columns loc... | ```python
print("_RANDOM_GUESS_1689420680.5839827")# 1689420680.5840013
``` | 0 |
474 | D | Flowers | PROGRAMMING | 1,700 | [
"dp"
] | null | null | We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty... | Input contains several test cases.
The first line contains two integers *t* and *k* (1<=≤<=*t*,<=*k*<=≤<=105), where *t* represents the number of test cases.
The next *t* lines contain two integers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=*b**i*<=≤<=105), describing the *i*-th test. | Print *t* lines to the standard output. The *i*-th line should contain the number of ways in which Marmot can eat between *a**i* and *b**i* flowers at dinner modulo 1000000007 (109<=+<=7). | [
"3 2\n1 3\n2 3\n4 4\n"
] | [
"6\n5\n5\n"
] | - For *K* = 2 and length 1 Marmot can eat (*R*). - For *K* = 2 and length 2 Marmot can eat (*RR*) and (*WW*). - For *K* = 2 and length 3 Marmot can eat (*RRR*), (*RWW*) and (*WWR*). - For *K* = 2 and length 4 Marmot can eat, for example, (*WWWW*) or (*RWWR*), but for example he can't eat (*WWWR*). | 2,000 | [
{
"input": "3 2\n1 3\n2 3\n4 4",
"output": "6\n5\n5"
},
{
"input": "1 1\n1 3",
"output": "14"
},
{
"input": "1 2\n64329 79425",
"output": "0"
}
] | 1,677,259,346 | 2,147,483,647 | PyPy 3-64 | MEMORY_LIMIT_EXCEEDED | TESTS | 0 | 498 | 268,390,400 | def main():
t, k = input().split()
mod = 1000000007
t = int(t)
k = int(k)
dp = [0]
for i in range(1, k):
dp.append(1)
dp.append(2)
for i in range(k+1, 100005):
dp.append(dp[i-1]+dp[i-k])
for i in range(1, 100005):
dp[i] = dp[i-1]+dp[i]
f... | Title: Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequenc... | ```python
def main():
t, k = input().split()
mod = 1000000007
t = int(t)
k = int(k)
dp = [0]
for i in range(1, k):
dp.append(1)
dp.append(2)
for i in range(k+1, 100005):
dp.append(dp[i-1]+dp[i-k])
for i in range(1, 100005):
dp[i] = dp[i-1]+dp[i... | 0 | |
452 | A | Eevee | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"strings"
] | null | null | You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight different pokemons: Vaporeon, Jolteon, Flareon, Espeon, Umbreon, Leafeon, Glaceon, and Syl... | First line contains an integer *n* (6<=≤<=*n*<=≤<=8) – the length of the string.
Next line contains a string consisting of *n* characters, each of which is either a lower case english letter (indicating a known letter) or a dot character (indicating an empty cell in the crossword). | Print a name of the pokemon that Eevee can evolve into that matches the pattern in the input. Use lower case letters only to print the name (in particular, do not capitalize the first letter). | [
"7\nj......\n",
"7\n...feon\n",
"7\n.l.r.o.\n"
] | [
"jolteon\n",
"leafeon\n",
"flareon\n"
] | Here's a set of names in a form you can paste into your solution:
["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
{"vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"} | 500 | [
{
"input": "7\n...feon",
"output": "leafeon"
},
{
"input": "7\n.l.r.o.",
"output": "flareon"
},
{
"input": "6\n.s..o.",
"output": "espeon"
},
{
"input": "7\nglaceon",
"output": "glaceon"
},
{
"input": "8\n.a.o.e.n",
"output": "vaporeon"
},
{
"input": "... | 1,633,096,035 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 77 | 20,172,800 | #!/usr/bin/env pypy3
from sys import stdin, stdout
def input(): return stdin.readline().strip()
def read_int_list(): return list(map(int, input().split()))
def read_int_tuple(): return tuple(map(int, input().split()))
def read_int(): return int(input())
### CODE HERE
def match(A, B):
for a, b in zip... | Title: Eevee
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight... | ```python
#!/usr/bin/env pypy3
from sys import stdin, stdout
def input(): return stdin.readline().strip()
def read_int_list(): return list(map(int, input().split()))
def read_int_tuple(): return tuple(map(int, input().split()))
def read_int(): return int(input())
### CODE HERE
def match(A, B):
for a... | 0 | |
858 | A | k-rounding | PROGRAMMING | 1,100 | [
"brute force",
"math",
"number theory"
] | null | null | For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*.
For example, 4-rounding of 375 is 375·80<==<=30000. 30000 is the minimum integer such that it ends with 4 or more zeros and is divisible by 375.
W... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=8). | Print the *k*-rounding of *n*. | [
"375 4\n",
"10000 1\n",
"38101 0\n",
"123456789 8\n"
] | [
"30000\n",
"10000\n",
"38101\n",
"12345678900000000\n"
] | none | 750 | [
{
"input": "375 4",
"output": "30000"
},
{
"input": "10000 1",
"output": "10000"
},
{
"input": "38101 0",
"output": "38101"
},
{
"input": "123456789 8",
"output": "12345678900000000"
},
{
"input": "1 0",
"output": "1"
},
{
"input": "2 0",
"output":... | 1,510,139,415 | 3,015 | Python 3 | OK | TESTS | 96 | 62 | 0 | def nok(a, b):
m = a * b
while a != 0 and b != 0:
if a > b:
a %= b
else:
b %= a
return m // (a + b)
n, k = map(int, input().split())
print(nok(n, 10**k))
| Title: k-rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*.
For example, 4-rounding of 375 is 375·80<==<=30000.... | ```python
def nok(a, b):
m = a * b
while a != 0 and b != 0:
if a > b:
a %= b
else:
b %= a
return m // (a + b)
n, k = map(int, input().split())
print(nok(n, 10**k))
``` | 3 | |
899 | C | Dividing the numbers | PROGRAMMING | 1,300 | [
"constructive algorithms",
"graphs",
"math"
] | null | null | Petya has *n* integers: 1,<=2,<=3,<=...,<=*n*. He wants to split these integers in two non-empty groups in such a way that the absolute difference of sums of integers in each group is as small as possible.
Help Petya to split the integers. Each of *n* integers should be exactly in one group. | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=60<=000) — the number of integers Petya has. | Print the smallest possible absolute difference in the first line.
In the second line print the size of the first group, followed by the integers in that group. You can print these integers in arbitrary order. If there are multiple answers, print any of them. | [
"4\n",
"2\n"
] | [
"0\n2 1 4 \n",
"1\n1 1 \n"
] | In the first example you have to put integers 1 and 4 in the first group, and 2 and 3 in the second. This way the sum in each group is 5, and the absolute difference is 0.
In the second example there are only two integers, and since both groups should be non-empty, you have to put one integer in the first group and on... | 1,500 | [
{
"input": "4",
"output": "0\n2 1 4 "
},
{
"input": "2",
"output": "1\n1 1 "
},
{
"input": "3",
"output": "0\n1\n3 "
},
{
"input": "5",
"output": "1\n3\n1 2 5 "
},
{
"input": "59998",
"output": "1\n29999 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 4... | 1,601,801,821 | 2,147,483,647 | PyPy 3 | OK | TESTS | 60 | 171 | 4,096,000 | for t in range(1):
n=int(input())
sum1=0
sum2=0
arr1=[]
arr2=[]
for i in range(n,0,-1):
if sum1>=sum2:
sum2+=i
arr2.append(i)
else:
sum1+=i
arr1.append(i)
print(abs(sum1-sum2))
print(len(arr1),*arr1)
| Title: Dividing the numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya has *n* integers: 1,<=2,<=3,<=...,<=*n*. He wants to split these integers in two non-empty groups in such a way that the absolute difference of sums of integers in each group is as small as possible.
Help P... | ```python
for t in range(1):
n=int(input())
sum1=0
sum2=0
arr1=[]
arr2=[]
for i in range(n,0,-1):
if sum1>=sum2:
sum2+=i
arr2.append(i)
else:
sum1+=i
arr1.append(i)
print(abs(sum1-sum2))
print(len(arr1),*arr1)
... | 3 | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,664,662,516 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | result = input().split()
greatest = 0
count = 0
den = 6
if result[0] >= result[1]:
greatest = result[0]
else:
greatest = result[1]
for i in range(7):
if i >= int(greatest):
count += 1
for j in range(6):
if (count % 3) == 0 and den != 1:
count = count / 3
... | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
result = input().split()
greatest = 0
count = 0
den = 6
if result[0] >= result[1]:
greatest = result[0]
else:
greatest = result[1]
for i in range(7):
if i >= int(greatest):
count += 1
for j in range(6):
if (count % 3) == 0 and den != 1:
count = count / ... | 0 |
919 | B | Perfect Number | PROGRAMMING | 1,100 | [
"binary search",
"brute force",
"dp",
"implementation",
"number theory"
] | null | null | We consider a positive integer perfect, if and only if the sum of its digits is exactly $10$. Given a positive integer $k$, your task is to find the $k$-th smallest perfect positive integer. | A single line with a positive integer $k$ ($1 \leq k \leq 10\,000$). | A single number, denoting the $k$-th smallest perfect integer. | [
"1\n",
"2\n"
] | [
"19\n",
"28\n"
] | The first perfect integer is $19$ and the second one is $28$. | 750 | [
{
"input": "1",
"output": "19"
},
{
"input": "2",
"output": "28"
},
{
"input": "13",
"output": "136"
},
{
"input": "101",
"output": "1432"
},
{
"input": "1023",
"output": "100270"
},
{
"input": "9999",
"output": "10800010"
},
{
"input": "10... | 1,692,206,441 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 92 | 2,048,000 | import sys
input = sys.stdin.readline
k = int(input())
count = 1
for i in range(10 ** 4 + 1):
hold = sum(list(map(int, list(str(i)))))
if hold == 10:
if count == k:
print(i)
exit()
else:
count += 1
| Title: Perfect Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We consider a positive integer perfect, if and only if the sum of its digits is exactly $10$. Given a positive integer $k$, your task is to find the $k$-th smallest perfect positive integer.
Input Specification:
A singl... | ```python
import sys
input = sys.stdin.readline
k = int(input())
count = 1
for i in range(10 ** 4 + 1):
hold = sum(list(map(int, list(str(i)))))
if hold == 10:
if count == k:
print(i)
exit()
else:
count += 1
``` | 0 | |
965 | A | Paper Airplanes | PROGRAMMING | 800 | [
"math"
] | null | null | To make a paper airplane, one has to use a rectangular piece of paper. From a sheet of standard size you can make $s$ airplanes.
A group of $k$ people decided to make $n$ airplanes each. They are going to buy several packs of paper, each of them containing $p$ sheets, and then distribute the sheets between the people.... | The only line contains four integers $k$, $n$, $s$, $p$ ($1 \le k, n, s, p \le 10^4$) — the number of people, the number of airplanes each should make, the number of airplanes that can be made using one sheet and the number of sheets in one pack, respectively. | Print a single integer — the minimum number of packs they should buy. | [
"5 3 2 3\n",
"5 3 100 1\n"
] | [
"4\n",
"5\n"
] | In the first sample they have to buy $4$ packs of paper: there will be $12$ sheets in total, and giving $2$ sheets to each person is enough to suit everyone's needs.
In the second sample they have to buy a pack for each person as they can't share sheets. | 500 | [
{
"input": "5 3 2 3",
"output": "4"
},
{
"input": "5 3 100 1",
"output": "5"
},
{
"input": "10000 10000 1 1",
"output": "100000000"
},
{
"input": "1 1 10000 10000",
"output": "1"
},
{
"input": "300 300 21 23",
"output": "196"
},
{
"input": "300 2 37 51... | 1,603,196,834 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | k,n,s,p=map(int,input().split())
m=int()
kl=int()
if n % s ==0:
kl = n // s
else:
kl = n // s + 1
vl = kl * k
if vl % p == 0:
m = vl // p
else: m = vl // p + 1
print (m) | Title: Paper Airplanes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
To make a paper airplane, one has to use a rectangular piece of paper. From a sheet of standard size you can make $s$ airplanes.
A group of $k$ people decided to make $n$ airplanes each. They are going to buy several p... | ```python
k,n,s,p=map(int,input().split())
m=int()
kl=int()
if n % s ==0:
kl = n // s
else:
kl = n // s + 1
vl = kl * k
if vl % p == 0:
m = vl // p
else: m = vl // p + 1
print (m)
``` | -1 | |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*... | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,695,194,938 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 46 | 102,400 | n=int(input())
s=str(input())
c=0
m=0
for i in s:
if i =="A":
c+=1
elif i =="D":
m+=1
if c>m:
print("Anton")
elif m>c:
print("Danik")
else:
print("Friendship")
| Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, w... | ```python
n=int(input())
s=str(input())
c=0
m=0
for i in s:
if i =="A":
c+=1
elif i =="D":
m+=1
if c>m:
print("Anton")
elif m>c:
print("Danik")
else:
print("Friendship")
``` | 3 | |
894 | A | QAQ | PROGRAMMING | 800 | [
"brute force",
"dp"
] | null | null | "QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are... | The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters. | Print a single integer — the number of subsequences "QAQ" in the string. | [
"QAQAQYSYIOIWIN\n",
"QAQQQZZYNOIWIN\n"
] | [
"4\n",
"3\n"
] | In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | 500 | [
{
"input": "QAQAQYSYIOIWIN",
"output": "4"
},
{
"input": "QAQQQZZYNOIWIN",
"output": "3"
},
{
"input": "QA",
"output": "0"
},
{
"input": "IAQVAQZLQBQVQFTQQQADAQJA",
"output": "24"
},
{
"input": "QQAAQASGAYAAAAKAKAQIQEAQAIAAIAQQQQQ",
"output": "378"
},
{
... | 1,667,408,660 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 43 | 62 | 0 | s = input()
n = len(s)
dp = [[0, 0, 0] for i in range(n + 1)]
if s[0] == 'Q':
dp[1][0] = 1
for i in range(1, n + 1):
if s[i-1] == 'Q':
dp[i][0] = dp[i-1][0] + 1
dp[i][1] = dp[i-1][1]
dp[i][2] = dp[i-1][1] + dp[i-1][2]
elif s[i-1] == 'A':
dp[i][0] = dp[i-1][0]
... | Title: QAQ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ"... | ```python
s = input()
n = len(s)
dp = [[0, 0, 0] for i in range(n + 1)]
if s[0] == 'Q':
dp[1][0] = 1
for i in range(1, n + 1):
if s[i-1] == 'Q':
dp[i][0] = dp[i-1][0] + 1
dp[i][1] = dp[i-1][1]
dp[i][2] = dp[i-1][1] + dp[i-1][2]
elif s[i-1] == 'A':
dp[i][0] = dp[i-1... | 3 | |
735 | D | Taxes | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | Mr. Funt now lives in a country with a very specific tax laws. The total income of mr. Funt during this year is equal to *n* (*n*<=≥<=2) burles and the amount of tax he has to pay is calculated as the maximum divisor of *n* (not equal to *n*, of course). For example, if *n*<==<=6 then Funt has to pay 3 burles, while fo... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=2·109) — the total year income of mr. Funt. | Print one integer — minimum possible number of burles that mr. Funt has to pay as a tax. | [
"4\n",
"27\n"
] | [
"2\n",
"3\n"
] | none | 1,750 | [
{
"input": "4",
"output": "2"
},
{
"input": "27",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "5",
"output": "1"
},
{
"input": "10",
"output": "2"
},
{
"input": "2000000000",
"output": "2"
},
{
"input": "26",
"output": ... | 1,669,701,889 | 2,147,483,647 | PyPy 3-64 | MEMORY_LIMIT_EXCEEDED | TESTS | 5 | 77 | 268,390,400 | import collections
import heapq
import sys
import math
import itertools
import bisect
import os
from io import BytesIO, IOBase
input = sys.stdin.readline
def primelist(b):
L = [True for i in range(b)]
for i in range(2,b):
if L[i]:
for j in range(i+i,b,i):L[j]=False
retu... | Title: Taxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Funt now lives in a country with a very specific tax laws. The total income of mr. Funt during this year is equal to *n* (*n*<=≥<=2) burles and the amount of tax he has to pay is calculated as the maximum divisor of *n* (not ... | ```python
import collections
import heapq
import sys
import math
import itertools
import bisect
import os
from io import BytesIO, IOBase
input = sys.stdin.readline
def primelist(b):
L = [True for i in range(b)]
for i in range(2,b):
if L[i]:
for j in range(i+i,b,i):L[j]=False ... | 0 | |
955 | D | Scissors | PROGRAMMING | 2,600 | [
"brute force",
"strings"
] | null | null | Jenya has recently acquired quite a useful tool — *k*-scissors for cutting strings. They are generally used for cutting out two non-intersecting substrings of length *k* from an arbitrary string *s* (its length should be at least 2·*k* in order to perform this operation) and concatenating them afterwards (preserving th... | The first line contains three integers *n*, *m*, *k* (2<=≤<=*m*<=≤<=2·*k*<=≤<=*n*<=≤<=5·105) — length of *s*, length of *t* and the aforementioned scissors' parameter correspondingly.
The next two lines feature *s* and *t* consisting of lowercase latin letters. | If there is no answer, print «No».
Otherwise print «Yes» and two integers *L* and *R* denoting the indexes where cutted substrings start (1-indexed). If there are several possible answers, output any. | [
"7 4 3\nbaabaab\naaaa\n",
"6 3 2\ncbcbcb\nbcc\n",
"7 5 3\naabbaaa\naaaaa\n"
] | [
"Yes\n1 5\n",
"Yes\n2 5\n",
"No\n"
] | In the first sample case you can cut out two substrings starting at 1 and 5. The resulting string baaaab contains aaaa as a substring.
In the second sample case the resulting string is bccb. | 2,000 | [
{
"input": "7 4 3\nbaabaab\naaaa",
"output": "Yes\n1 5"
},
{
"input": "6 3 2\ncbcbcb\nbcc",
"output": "Yes\n2 5"
},
{
"input": "7 5 3\naabbaaa\naaaaa",
"output": "No"
},
{
"input": "16 6 4\nabcdcadbbbcacdca\ndcadbc",
"output": "Yes\n4 10"
},
{
"input": "81 5 3\nac... | 1,521,994,060 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 7,065,600 |
n, m, k = map( int, input().split() )
s = input()
t = input()
Lmatch = [0] * len(s)
Rmatch = [0] * len(s)
for i in range(len(s)-k):
j = 0
while j < min(k, len(t)) and s[i+j] == t[j]:
j += 1
Lmatch[i] = j
print(Lmatch)
for i in range(k, len(s)):
j = 0
while j < min(k, len(t)) and s[i-j] == t[len(t)-1-j]:... | Title: Scissors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jenya has recently acquired quite a useful tool — *k*-scissors for cutting strings. They are generally used for cutting out two non-intersecting substrings of length *k* from an arbitrary string *s* (its length should be at le... | ```python
n, m, k = map( int, input().split() )
s = input()
t = input()
Lmatch = [0] * len(s)
Rmatch = [0] * len(s)
for i in range(len(s)-k):
j = 0
while j < min(k, len(t)) and s[i+j] == t[j]:
j += 1
Lmatch[i] = j
print(Lmatch)
for i in range(k, len(s)):
j = 0
while j < min(k, len(t)) and s[i-j] == t[le... | 0 | |
46 | C | Hamsters and Tigers | PROGRAMMING | 1,600 | [
"two pointers"
] | C. Hamsters and Tigers | 2 | 256 | Today there is going to be an unusual performance at the circus — hamsters and tigers will perform together! All of them stand in circle along the arena edge and now the trainer faces a difficult task: he wants to swap the animals' positions so that all the hamsters stood together and all the tigers also stood together... | The first line contains number *n* (2<=≤<=*n*<=≤<=1000) which indicates the total number of animals in the arena. The second line contains the description of the animals' positions. The line consists of *n* symbols "H" and "T". The "H"s correspond to hamsters and the "T"s correspond to tigers. It is guaranteed that at ... | Print the single number which is the minimal number of swaps that let the trainer to achieve his goal. | [
"3\nHTH\n",
"9\nHTHTHTHHT\n"
] | [
"0\n",
"2\n"
] | In the first example we shouldn't move anybody because the animals of each species already stand apart from the other species. In the second example you may swap, for example, the tiger in position 2 with the hamster in position 5 and then — the tiger in position 9 with the hamster in position 7. | 0 | [
{
"input": "3\nHTH",
"output": "0"
},
{
"input": "9\nHTHTHTHHT",
"output": "2"
},
{
"input": "2\nTH",
"output": "0"
},
{
"input": "4\nHTTH",
"output": "0"
},
{
"input": "4\nHTHT",
"output": "1"
},
{
"input": "7\nTTTHTTT",
"output": "0"
},
{
... | 1,691,768,763 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | def min_swaps_to_separate_groups(s):
n = len(s)
hamsters = s.count('H')
tigers = n - hamsters
min_swaps = float('inf')
# Count the number of tigers in a sliding window of size 'hamsters'
for i in range(n - hamsters + 1):
tigers_in_window = s[i:i + hamsters].count('T')
min_swaps ... | Title: Hamsters and Tigers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Today there is going to be an unusual performance at the circus — hamsters and tigers will perform together! All of them stand in circle along the arena edge and now the trainer faces a difficult task: he wants to swap ... | ```python
def min_swaps_to_separate_groups(s):
n = len(s)
hamsters = s.count('H')
tigers = n - hamsters
min_swaps = float('inf')
# Count the number of tigers in a sliding window of size 'hamsters'
for i in range(n - hamsters + 1):
tigers_in_window = s[i:i + hamsters].count('T')
... | 0 |
18 | C | Stripe | PROGRAMMING | 1,200 | [
"data structures",
"implementation"
] | C. Stripe | 2 | 64 | Once Bob took a paper stripe of *n* squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=105) — amount of squares in the stripe. The second line contains *n* space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. | Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. | [
"9\n1 5 -6 7 9 -16 0 -2 2\n",
"3\n1 1 1\n",
"2\n0 0\n"
] | [
"3\n",
"0\n",
"1\n"
] | none | 0 | [
{
"input": "9\n1 5 -6 7 9 -16 0 -2 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "0"
},
{
"input": "2\n0 0",
"output": "1"
},
{
"input": "4\n100 1 10 111",
"output": "1"
},
{
"input": "10\n0 4 -3 0 -2 2 -3 -3 2 5",
"output": "3"
},
{
"input": "... | 1,598,785,298 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 498 | 14,438,400 | n = int(input())
stripe = list(map(int, input().split()))
count = 0
left = 0
right = sum(stripe)
for s in stripe[:-1]:
left += s
right -= s
if left == right:
count += 1
print(count)
| Title: Stripe
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Once Bob took a paper stripe of *n* squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that ... | ```python
n = int(input())
stripe = list(map(int, input().split()))
count = 0
left = 0
right = sum(stripe)
for s in stripe[:-1]:
left += s
right -= s
if left == right:
count += 1
print(count)
``` | 3.767926 |
525 | A | Vitaliy and Pie | PROGRAMMING | 1,100 | [
"greedy",
"hashing",
"strings"
] | null | null | After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from left to right. You can go from the first room to the second room, from the second room to the third ... | The first line of the input contains a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of rooms in the house.
The second line of the input contains string *s* of length 2·*n*<=-<=2. Let's number the elements of the string from left to right, starting from one.
The odd positions in the given string *s* contain ... | Print the only integer — the minimum number of keys that Vitaly needs to buy to surely get from room one to room *n*. | [
"3\naAbB\n",
"4\naBaCaB\n",
"5\nxYyXzZaZ\n"
] | [
"0\n",
"3\n",
"2\n"
] | none | 250 | [
{
"input": "3\naAbB",
"output": "0"
},
{
"input": "4\naBaCaB",
"output": "3"
},
{
"input": "5\nxYyXzZaZ",
"output": "2"
},
{
"input": "26\naAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyY",
"output": "0"
},
{
"input": "26\nzAyBxCwDvEuFtGsHrIqJpKoLnMmNlOkPjQiRhSg... | 1,619,849,915 | 215 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | {\rtf1\ansi\ansicpg1252\cocoartf2513
\cocoatextscaling0\cocoaplatform0{\fonttbl\f0\fswiss\fcharset0 Helvetica;}
{\colortbl;\red255\green255\blue255;}
{\*\expandedcolortbl;;}
\paperw11900\paperh16840\margl1440\margr1440\vieww10800\viewh8400\viewkind0
\pard\tx566\tx1133\tx1700\tx2267\tx2834\tx3401\tx3968\tx4535\tx5102\tx... | Title: Vitaliy and Pie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from... | ```python
{\rtf1\ansi\ansicpg1252\cocoartf2513
\cocoatextscaling0\cocoaplatform0{\fonttbl\f0\fswiss\fcharset0 Helvetica;}
{\colortbl;\red255\green255\blue255;}
{\*\expandedcolortbl;;}
\paperw11900\paperh16840\margl1440\margr1440\vieww10800\viewh8400\viewkind0
\pard\tx566\tx1133\tx1700\tx2267\tx2834\tx3401\tx3968\tx4535... | -1 | |
165 | A | Supercentral Point | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the given set (*x*,<=*y*):
- point (*x*',<=*y*') is (*x*,<=*y*)'s right neighbor, if *x*'<=><=*x* and *y*'... | The first input line contains the only integer *n* (1<=≤<=*n*<=≤<=200) — the number of points in the given set. Next *n* lines contain the coordinates of the points written as "*x* *y*" (without the quotes) (|*x*|,<=|*y*|<=≤<=1000), all coordinates are integers. The numbers in the line are separated by exactly one spac... | Print the only number — the number of supercentral points of the given set. | [
"8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3\n",
"5\n0 0\n0 1\n1 0\n0 -1\n-1 0\n"
] | [
"2\n",
"1\n"
] | In the first sample the supercentral points are only points (1, 1) and (1, 2).
In the second sample there is one supercental point — point (0, 0). | 500 | [
{
"input": "8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3",
"output": "2"
},
{
"input": "5\n0 0\n0 1\n1 0\n0 -1\n-1 0",
"output": "1"
},
{
"input": "9\n-565 -752\n-184 723\n-184 -752\n-184 1\n950 723\n-565 723\n950 -752\n950 1\n-565 1",
"output": "1"
},
{
"input": "25\n-651 897\n... | 1,621,925,510 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 186 | 0 | n = int(input())
s = []
for _ in range(n):
a = tuple(map(int, input().split()))
s.append(a)
c = 0
for i in range(n):
x, y = s[i][0], s[i][1]
r = list(filter(lambda q : q[0]>x and q[1]==y, s))
l = list(filter(lambda q : q[0]<x and q[1]==y, s))
u = list(filter(lambda q : q[0]==x and q[1]... | Title: Supercentral Point
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the give... | ```python
n = int(input())
s = []
for _ in range(n):
a = tuple(map(int, input().split()))
s.append(a)
c = 0
for i in range(n):
x, y = s[i][0], s[i][1]
r = list(filter(lambda q : q[0]>x and q[1]==y, s))
l = list(filter(lambda q : q[0]<x and q[1]==y, s))
u = list(filter(lambda q : q[0]==... | 3 | |
34 | A | Reconnaissance 2 | PROGRAMMING | 800 | [
"implementation"
] | A. Reconnaissance 2 | 2 | 256 | *n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a ... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). The soldier heights are given in clockwise or counterclockwise direction. | Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle. | [
"5\n10 12 13 15 10\n",
"4\n10 20 30 40\n"
] | [
"5 1\n",
"1 2\n"
] | none | 500 | [
{
"input": "5\n10 12 13 15 10",
"output": "5 1"
},
{
"input": "4\n10 20 30 40",
"output": "1 2"
},
{
"input": "6\n744 359 230 586 944 442",
"output": "2 3"
},
{
"input": "5\n826 747 849 687 437",
"output": "1 2"
},
{
"input": "5\n999 999 993 969 999",
"output"... | 1,636,316,199 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 124 | 17,715,200 | a = int(input())
b = list(map(int,input().split()))
ans = float("inf")
for i in range(a):
if i + 1 >= a:
if abs(b[i] - b[0]) < ans:
ans_1 = i + 1
ans_2 = 1
else:
if abs(b[i] - b[i + 1]) < ans:
ans_1 = i + 1
ans_2 = i + 2
print(ans_1,ans... | Title: Reconnaissance 2
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
*n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So... | ```python
a = int(input())
b = list(map(int,input().split()))
ans = float("inf")
for i in range(a):
if i + 1 >= a:
if abs(b[i] - b[0]) < ans:
ans_1 = i + 1
ans_2 = 1
else:
if abs(b[i] - b[i + 1]) < ans:
ans_1 = i + 1
ans_2 = i + 2
print... | 0 |
909 | A | Generate Login | PROGRAMMING | 1,000 | [
"brute force",
"greedy",
"sortings"
] | null | null | The preferred way to generate user login in Polygon is to concatenate a prefix of the user's first name and a prefix of their last name, in that order. Each prefix must be non-empty, and any of the prefixes can be the full name. Typically there are multiple possible logins for each person.
You are given the first and ... | The input consists of a single line containing two space-separated strings: the first and the last names. Each character of each string is a lowercase English letter. The length of each string is between 1 and 10, inclusive. | Output a single string — alphabetically earliest possible login formed from these names. The output should be given in lowercase as well. | [
"harry potter\n",
"tom riddle\n"
] | [
"hap\n",
"tomr\n"
] | none | 500 | [
{
"input": "harry potter",
"output": "hap"
},
{
"input": "tom riddle",
"output": "tomr"
},
{
"input": "a qdpinbmcrf",
"output": "aq"
},
{
"input": "wixjzniiub ssdfodfgap",
"output": "wis"
},
{
"input": "z z",
"output": "zz"
},
{
"input": "ertuyivhfg v"... | 1,593,423,568 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 109 | 6,656,000 | n,p = input().split()
d = n[0]
for i in range(1,len(n)):
if n[i]<n[i+1]:
d+=n[i]
else:
break
print(d+p[0])
| Title: Generate Login
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The preferred way to generate user login in Polygon is to concatenate a prefix of the user's first name and a prefix of their last name, in that order. Each prefix must be non-empty, and any of the prefixes can be the fu... | ```python
n,p = input().split()
d = n[0]
for i in range(1,len(n)):
if n[i]<n[i+1]:
d+=n[i]
else:
break
print(d+p[0])
``` | 0 | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,681,834,943 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 92 | 0 | a,b=map(int,input().split(' '))
x=max(a,b)-1
a=['1/1','5/6','2/3','1/2','1/3','1/6']
print(a[x])
| Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
a,b=map(int,input().split(' '))
x=max(a,b)-1
a=['1/1','5/6','2/3','1/2','1/3','1/6']
print(a[x])
``` | 3.954 |
584 | B | Kolya and Tanya | PROGRAMMING | 1,500 | [
"combinatorics"
] | null | null | Kolya loves putting gnomes at the circle table and giving them coins, and Tanya loves studying triplets of gnomes, sitting in the vertexes of an equilateral triangle.
More formally, there are 3*n* gnomes sitting in a circle. Each gnome can have from 1 to 3 coins. Let's number the places in the order they occur in the ... | A single line contains number *n* (1<=≤<=*n*<=≤<=105) — the number of the gnomes divided by three. | Print a single number — the remainder of the number of variants of distributing coins that satisfy Tanya modulo 109<=+<=7. | [
"1\n",
"2\n"
] | [
"20",
"680"
] | 20 ways for *n* = 1 (gnome with index 0 sits on the top of the triangle, gnome 1 on the right vertex, gnome 2 on the left vertex): <img class="tex-graphics" src="https://espresso.codeforces.com/64df38b85ccb482cf88d02dc52e348e33313f9da.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "1",
"output": "20"
},
{
"input": "2",
"output": "680"
},
{
"input": "3",
"output": "19340"
},
{
"input": "4",
"output": "529040"
},
{
"input": "5",
"output": "14332100"
},
{
"input": "7",
"output": "459529590"
},
{
"input": "10"... | 1,664,216,814 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 62 | 0 | def small(a, x):
if x<10:
return (a**x)%(10**9+7)
if x%2==0:
return (small(a, x//2)*small(a, x//2))%(10**9+7)
else:
return (a*small(a, x//2)*small(a, x//2))%(10**9+7)
def rec(a, b, x):
if x<10:
return (a**x-b**x)%(10**9+7)
if x%2==0:
return rec(a,... | Title: Kolya and Tanya
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya loves putting gnomes at the circle table and giving them coins, and Tanya loves studying triplets of gnomes, sitting in the vertexes of an equilateral triangle.
More formally, there are 3*n* gnomes sitting in a ... | ```python
def small(a, x):
if x<10:
return (a**x)%(10**9+7)
if x%2==0:
return (small(a, x//2)*small(a, x//2))%(10**9+7)
else:
return (a*small(a, x//2)*small(a, x//2))%(10**9+7)
def rec(a, b, x):
if x<10:
return (a**x-b**x)%(10**9+7)
if x%2==0:
ret... | 3 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,657,202,609 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 80 | 122 | 0 | n=int(input())
l=[]
for i in range(n):
l.append(input())
sum1=sum2=sum3=0
for i in l:
k=i.split()
for m in k:
sum1+=int(m)
sum2+=int(m)
sum3+=int(m)
if sum1==sum2==sum3==0:
print("YES")
else:
print("NO")
| Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. S... | ```python
n=int(input())
l=[]
for i in range(n):
l.append(input())
sum1=sum2=sum3=0
for i in l:
k=i.split()
for m in k:
sum1+=int(m)
sum2+=int(m)
sum3+=int(m)
if sum1==sum2==sum3==0:
print("YES")
else:
print("NO")
``` | 0 |
57 | A | Square Earth? | PROGRAMMING | 1,300 | [
"dfs and similar",
"greedy",
"implementation"
] | A. Square Earth? | 2 | 256 | Meg the Rabbit decided to do something nice, specifically — to determine the shortest distance between two points on the surface of our planet. But Meg... what can you say, she wants everything simple. So, she already regards our planet as a two-dimensional circle. No, wait, it's even worse — as a square of side *n*. T... | The single line contains 5 space-separated integers: *n*,<=*x*1,<=*y*1,<=*x*2,<=*y*2 (1<=≤<=*n*<=≤<=1000,<=0<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=*n*) which correspondingly represent a side of the square, the coordinates of the first point and the coordinates of the second point. It is guaranteed that the points lie on th... | You must print on a single line the shortest distance between the points. | [
"2 0 0 1 0\n",
"2 0 1 2 1\n",
"100 0 0 100 100\n"
] | [
"1\n",
"4\n",
"200\n"
] | none | 500 | [
{
"input": "2 0 0 1 0",
"output": "1"
},
{
"input": "2 0 1 2 1",
"output": "4"
},
{
"input": "100 0 0 100 100",
"output": "200"
},
{
"input": "4 0 3 1 4",
"output": "2"
},
{
"input": "10 8 10 10 0",
"output": "12"
},
{
"input": "26 21 0 26 14",
"ou... | 1,643,720,582 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 92 | 0 | arr,ans = [int(item) for item in input().split(' ')],0
ans += min((arr[1] + arr[2] + arr[3]+arr[4]),(4*arr[0]) - (arr[1]+ arr[2] + arr[3]+ arr[4]))
print(ans) | Title: Square Earth?
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Meg the Rabbit decided to do something nice, specifically — to determine the shortest distance between two points on the surface of our planet. But Meg... what can you say, she wants everything simple. So, she already regards... | ```python
arr,ans = [int(item) for item in input().split(' ')],0
ans += min((arr[1] + arr[2] + arr[3]+arr[4]),(4*arr[0]) - (arr[1]+ arr[2] + arr[3]+ arr[4]))
print(ans)
``` | 0 |
385 | B | Bear and Strings | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation",
"math",
"strings"
] | null | null | The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|), that string *x*(*i*,<=*j*)<==<=*s**i**s**i*<=+<=1... *s**j* contains at least one string... | The first line contains a non-empty string *s* (1<=≤<=|*s*|<=≤<=5000). It is guaranteed that the string only consists of lowercase English letters. | Print a single number — the answer to the problem. | [
"bearbtear\n",
"bearaabearc\n"
] | [
"6\n",
"20\n"
] | In the first sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9).
In the second sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (1, 11), (2, 10), (2, 11), (3, 10), (3, 11), (4, 10), (4, 11), (5, 10), (5, 11)... | 1,000 | [
{
"input": "bearbtear",
"output": "6"
},
{
"input": "bearaabearc",
"output": "20"
},
{
"input": "pbearbearhbearzqbearjkterasjhy",
"output": "291"
},
{
"input": "pbearjbearbebearnbabcffbearbearwubearjezpiorrbearbearjbdlbearbearqbearjbearwipmsbearoaftrsebearzsnqb",
"output"... | 1,636,214,075 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 1,000 | 4,403,200 | s = input().strip()
count = 0
n = len(s)
for i in range(0, len(s)):
for j in range(0, len(s)-i):
if "bear" in s[i:n-j]:
count += 1
print(count)
| Title: Bear and Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j... | ```python
s = input().strip()
count = 0
n = len(s)
for i in range(0, len(s)):
for j in range(0, len(s)-i):
if "bear" in s[i:n-j]:
count += 1
print(count)
``` | 0 | |
758 | A | Holiday Of Equality | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens, the welfare of each of them is estimated as the integer in *a**i* burles (burle is the currency in Berl... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100) — the number of citizens in the kingdom.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (0<=≤<=*a**i*<=≤<=106) — the welfare of the *i*-th citizen. | In the only line print the integer *S* — the minimum number of burles which are had to spend. | [
"5\n0 1 2 3 4\n",
"5\n1 1 0 1 1\n",
"3\n1 3 1\n",
"1\n12\n"
] | [
"10",
"1",
"4",
"0"
] | In the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.
In the second example it is enough to give one burle to the third citizen.
In the third example it is necessary to give two burles to the first and the thi... | 500 | [
{
"input": "5\n0 1 2 3 4",
"output": "10"
},
{
"input": "5\n1 1 0 1 1",
"output": "1"
},
{
"input": "3\n1 3 1",
"output": "4"
},
{
"input": "1\n12",
"output": "0"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "14\n52518 718438 358883 462189 853... | 1,670,525,944 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 0 |
n = int(input())
j = [int(i) for i in input().split(" ")]
# a, b = [int(i) for i in input().split(" ")]
m = max(j)
print(sum([m-i for i in j])) | Title: Holiday Of Equality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens... | ```python
n = int(input())
j = [int(i) for i in input().split(" ")]
# a, b = [int(i) for i in input().split(" ")]
m = max(j)
print(sum([m-i for i in j]))
``` | 3 | |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,461,516,070 | 370 | PyPy 3 | OK | TESTS | 26 | 124 | 23,142,400 | n = int(input())
ans = (n - 1) // 3 * 2 + int(n % 3 == 0) + 1
print(ans)
| Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
n = int(input())
ans = (n - 1) // 3 * 2 + int(n % 3 == 0) + 1
print(ans)
``` | 3 | |
352 | A | Jeff and Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"math"
] | null | null | Jeff's got *n* cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make from the cards he's got?
Jeff must make the number without leading zero. At that, we assume that numbe... | The first line contains integer *n* (1<=≤<=*n*<=≤<=103). The next line contains *n* integers *a*1, *a*2, ..., *a**n* (*a**i*<==<=0 or *a**i*<==<=5). Number *a**i* represents the digit that is written on the *i*-th card. | In a single line print the answer to the problem — the maximum number, divisible by 90. If you can't make any divisible by 90 number from the cards, print -1. | [
"4\n5 0 5 0\n",
"11\n5 5 5 5 5 5 5 5 0 5 5\n"
] | [
"0\n",
"5555555550\n"
] | In the first test you can make only one number that is a multiple of 90 — 0.
In the second test you can make number 5555555550, it is a multiple of 90. | 500 | [
{
"input": "4\n5 0 5 0",
"output": "0"
},
{
"input": "11\n5 5 5 5 5 5 5 5 0 5 5",
"output": "5555555550"
},
{
"input": "7\n5 5 5 5 5 5 5",
"output": "-1"
},
{
"input": "1\n5",
"output": "-1"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "11\n5 0 5 ... | 1,664,534,855 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 42 | 154 | 1,843,200 | n=int(input())
A=list(map(int,input().split()))
import math
fives=0
zeros=0
for item in A:
if item==5:
fives+=1
else:
zeros+=1
fives=math.floor(fives/9)
fives=fives*9
if zeros==0:
print(-1)
elif fives==0:
print(0)
else:
for i in range(fives):
print... | Title: Jeff and Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jeff's got *n* cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make fr... | ```python
n=int(input())
A=list(map(int,input().split()))
import math
fives=0
zeros=0
for item in A:
if item==5:
fives+=1
else:
zeros+=1
fives=math.floor(fives/9)
fives=fives*9
if zeros==0:
print(-1)
elif fives==0:
print(0)
else:
for i in range(fives):
... | 3 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,657,681,989 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 81 | 124 | 0 | n = int(input())
r = [0, 0, 0]
for i in range(n):
a, b, c = map(int, input().split())
r[0] += a
r[1] += b
r[2] += c
if r[0] == r[1] == r[2] == 0:
print("YES")
else:
print("NO") | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. S... | ```python
n = int(input())
r = [0, 0, 0]
for i in range(n):
a, b, c = map(int, input().split())
r[0] += a
r[1] += b
r[2] += c
if r[0] == r[1] == r[2] == 0:
print("YES")
else:
print("NO")
``` | 3.969 |
330 | B | Road Construction | PROGRAMMING | 1,300 | [
"constructive algorithms",
"graphs"
] | null | null | A country has *n* cities. Initially, there is no road in the country. One day, the king decides to construct some roads connecting pairs of cities. Roads can be traversed either way. He wants those roads to be constructed in such a way that it is possible to go from each city to any other city by traversing at most two... | The first line consists of two integers *n* and *m* .
Then *m* lines follow, each consisting of two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*), which means that it is not possible to construct a road connecting cities *a**i* and *b**i*. Consider the cities are numbered from 1 to *n*.... | You should print an integer *s*: the minimum number of roads that should be constructed, in the first line. Then *s* lines should follow, each consisting of two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*), which means that a road should be constructed between cities *a**i* and *b**i*.... | [
"4 1\n1 3\n"
] | [
"3\n1 2\n4 2\n2 3\n"
] | This is one possible solution of the example:
These are examples of wrong solutions: | 1,000 | [
{
"input": "4 1\n1 3",
"output": "3\n1 2\n4 2\n2 3"
},
{
"input": "1000 0",
"output": "999\n1 2\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n1 9\n1 10\n1 11\n1 12\n1 13\n1 14\n1 15\n1 16\n1 17\n1 18\n1 19\n1 20\n1 21\n1 22\n1 23\n1 24\n1 25\n1 26\n1 27\n1 28\n1 29\n1 30\n1 31\n1 32\n1 33\n1 34\n1 35\n1 36\n1 ... | 1,599,153,148 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 342 | 2,867,200 | n , m = map(int,input().split())
if m == 0 :
print(n - 1)
for i in range(2 , n+1):
print(1 , i)
else:
l = []
d1 = {}
d2 = {}
for i in range(m):
x , y = map(int,input().split())
d1[x] = y
d2[y] = x
#print(d1 , d2)
k = 0
for i in r... | Title: Road Construction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A country has *n* cities. Initially, there is no road in the country. One day, the king decides to construct some roads connecting pairs of cities. Roads can be traversed either way. He wants those roads to be constru... | ```python
n , m = map(int,input().split())
if m == 0 :
print(n - 1)
for i in range(2 , n+1):
print(1 , i)
else:
l = []
d1 = {}
d2 = {}
for i in range(m):
x , y = map(int,input().split())
d1[x] = y
d2[y] = x
#print(d1 , d2)
k = 0
... | 3 | |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are s... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,685,479,033 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 16,998,400 |
#import io, os, sys
#input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
#print = lambda x: sys.stdout.write(str(x) + "\n")
II = lambda: int(input())
MII = lambda: map(int, input().split())
LMII = lambda: list(MII())
#SLMII = lambda: sorted(LMII())
n, m = MII()
a = LMII()
dp = [1]*n
for... | Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...... | ```python
#import io, os, sys
#input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
#print = lambda x: sys.stdout.write(str(x) + "\n")
II = lambda: int(input())
MII = lambda: map(int, input().split())
LMII = lambda: list(MII())
#SLMII = lambda: sorted(LMII())
n, m = MII()
a = LMII()
dp = [1... | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Rikhail Mubinchik believes that the current definition of prime numbers is obsolete as they are too complex and unpredictable. A palindromic number is another matter. It is aesthetically pleasing, and it has a number of remarkable properties. Help Rikhail to convince the scientific community in this!
Let us remind you... | The input consists of two positive integers *p*, *q*, the numerator and denominator of the fraction that is the value of *A* (, ). | If such maximum number exists, then print it. Otherwise, print "Palindromic tree is better than splay tree" (without the quotes). | [
"1 1\n",
"1 42\n",
"6 4\n"
] | [
"40\n",
"1\n",
"172\n"
] | none | 0 | [
{
"input": "1 1",
"output": "40"
},
{
"input": "1 42",
"output": "1"
},
{
"input": "6 4",
"output": "172"
},
{
"input": "3 1",
"output": "2530"
},
{
"input": "42 1",
"output": "1179858"
},
{
"input": "10000 239",
"output": "1168638"
},
{
"i... | 1,626,307,657 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 764 | 81,203,200 | import math
from os import curdir, startfile
import random
from queue import Queue
import time
import heapq
import sys
def getprimes(n):
arr=[True]*(n+1)
for i in range(2,int(math.sqrt(n))+1):
if arr[i]:
for j in range(i**2,len(arr),i):
arr[j]=False
primes=set()
for... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Rikhail Mubinchik believes that the current definition of prime numbers is obsolete as they are too complex and unpredictable. A palindromic number is another matter. It is aesthetically pleasing, and it has a number of remarkable... | ```python
import math
from os import curdir, startfile
import random
from queue import Queue
import time
import heapq
import sys
def getprimes(n):
arr=[True]*(n+1)
for i in range(2,int(math.sqrt(n))+1):
if arr[i]:
for j in range(i**2,len(arr),i):
arr[j]=False
primes=set(... | 3 | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,514,308,326 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
int main(){
int n,d;
cin>>n>>d;
char l[n+2];
cin>>(l+1);
int dp[n+1];
for(int i=0;i<=n;i++) dp[i]=10000000;
dp[1]=0;
for(int i=2;i<=n;i++){
if(l[i]=='1'){
for(int j=max(1,i-d);j<i;j++){
if(l[j]=='1'){
... | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
#include <bits/stdc++.h>
using namespace std;
int main(){
int n,d;
cin>>n>>d;
char l[n+2];
cin>>(l+1);
int dp[n+1];
for(int i=0;i<=n;i++) dp[i]=10000000;
dp[1]=0;
for(int i=2;i<=n;i++){
if(l[i]=='1'){
for(int j=max(1,i-d);j<i;j++){
if(l[j]=='... | -1 | |
509 | A | Maximum in Table | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the ... | The only line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=10) — the number of rows and columns of the table. | Print a single line containing a positive integer *m* — the maximum value in the table. | [
"1\n",
"5\n"
] | [
"1",
"70"
] | In the second test the rows of the table look as follows: | 0 | [
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "70"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "6"
},
{
"input": "4",
"output": "20"
},
{
"input": "6",
"output": "252"
},
{
"input": "7",
"output": "924"
... | 1,670,068,168 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 10 | 62 | 0 | import math
n=int(input())
print(math.comb(n * 2 - 2, n - 1)) | Title: Maximum in Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the t... | ```python
import math
n=int(input())
print(math.comb(n * 2 - 2, n - 1))
``` | 3 | |
99 | A | Help Far Away Kingdom | PROGRAMMING | 800 | [
"strings"
] | A. Help Far Away Kingdom | 2 | 256 | In a far away kingdom lived the King, the Prince, the Shoemaker, the Dressmaker and many other citizens. They lived happily until great trouble came into the Kingdom. The ACMers settled there.
Most damage those strange creatures inflicted upon the kingdom was that they loved high precision numbers. As a result, the Ki... | The first line contains a single number to round up — the integer part (a non-empty set of decimal digits that do not start with 0 — with the exception of a case when the set consists of a single digit — in this case 0 can go first), then follows character «.» (a dot), and then follows the fractional part (any non-empt... | If the last number of the integer part is not equal to 9, print the rounded-up number without leading zeroes. Otherwise, print the message "GOTO Vasilisa." (without the quotes). | [
"0.0\n",
"1.49\n",
"1.50\n",
"2.71828182845904523536\n",
"3.14159265358979323846\n",
"12345678901234567890.1\n",
"123456789123456789.999\n"
] | [
"0",
"1",
"2",
"3",
"3",
"12345678901234567890",
"GOTO Vasilisa."
] | none | 500 | [
{
"input": "0.0",
"output": "0"
},
{
"input": "1.49",
"output": "1"
},
{
"input": "1.50",
"output": "2"
},
{
"input": "2.71828182845904523536",
"output": "3"
},
{
"input": "3.14159265358979323846",
"output": "3"
},
{
"input": "12345678901234567890.1",
... | 1,603,458,534 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 216 | 0 | num=float(input())
i,d=divmod(num,1)
i=int(i)
if (i%10)!=9 and d<0.5:
print(i)
elif (i%10)!=9 and d>=0.5:
print(i+1)
else :
print("GOTO Vasilia")
| Title: Help Far Away Kingdom
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
In a far away kingdom lived the King, the Prince, the Shoemaker, the Dressmaker and many other citizens. They lived happily until great trouble came into the Kingdom. The ACMers settled there.
Most damage those stran... | ```python
num=float(input())
i,d=divmod(num,1)
i=int(i)
if (i%10)!=9 and d<0.5:
print(i)
elif (i%10)!=9 and d>=0.5:
print(i+1)
else :
print("GOTO Vasilia")
``` | 0 |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,506,621,395 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | n = int(input())
if n == 1: print("1"); print("C")
if n%2 == 0: #if its even
output = int(n*(n/2))
print(output)
is_c = True
c_first = True
string = ""
for i in range(n):
if c_first: is_c = not is_c
for j in range(n):
if is_c:
string +... | Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
n = int(input())
if n == 1: print("1"); print("C")
if n%2 == 0: #if its even
output = int(n*(n/2))
print(output)
is_c = True
c_first = True
string = ""
for i in range(n):
if c_first: is_c = not is_c
for j in range(n):
if is_c:
... | 0 | |
385 | A | Bear and Raspberry | PROGRAMMING | 1,000 | [
"brute force",
"greedy",
"implementation"
] | null | null | The bear decided to store some raspberry for the winter. He cunningly found out the price for a barrel of honey in kilos of raspberry for each of the following *n* days. According to the bear's data, on the *i*-th (1<=≤<=*i*<=≤<=*n*) day, the price for one barrel of honey is going to is *x**i* kilos of raspberry.
Unfo... | The first line contains two space-separated integers, *n* and *c* (2<=≤<=*n*<=≤<=100,<=0<=≤<=*c*<=≤<=100), — the number of days and the number of kilos of raspberry that the bear should give for borrowing the barrel.
The second line contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (0<=≤<=*x**i*<=≤<=100... | Print a single integer — the answer to the problem. | [
"5 1\n5 10 7 3 20\n",
"6 2\n100 1 10 40 10 40\n",
"3 0\n1 2 3\n"
] | [
"3\n",
"97\n",
"0\n"
] | In the first sample the bear will lend a honey barrel at day 3 and then sell it for 7. Then the bear will buy a barrel for 3 and return it to the friend. So, the profit is (7 - 3 - 1) = 3.
In the second sample bear will lend a honey barrel at day 1 and then sell it for 100. Then the bear buy the barrel for 1 at the da... | 500 | [
{
"input": "5 1\n5 10 7 3 20",
"output": "3"
},
{
"input": "6 2\n100 1 10 40 10 40",
"output": "97"
},
{
"input": "3 0\n1 2 3",
"output": "0"
},
{
"input": "2 0\n2 1",
"output": "1"
},
{
"input": "10 5\n10 1 11 2 12 3 13 4 14 5",
"output": "4"
},
{
"in... | 1,563,986,415 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 109 | 0 | n, c = list(map(int, input().split()))
l = list(map(int, input().split()))
min = 0
for i in range(0, n-1):
dif = l[i] - l[i+1]
if dif > min:
min = dif
print(min-c) | Title: Bear and Raspberry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The bear decided to store some raspberry for the winter. He cunningly found out the price for a barrel of honey in kilos of raspberry for each of the following *n* days. According to the bear's data, on the *i*-th (1... | ```python
n, c = list(map(int, input().split()))
l = list(map(int, input().split()))
min = 0
for i in range(0, n-1):
dif = l[i] - l[i+1]
if dif > min:
min = dif
print(min-c)
``` | 0 | |
466 | A | Cheap Travel | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Ann has recently started commuting by subway. We know that a one ride subway ticket costs *a* rubles. Besides, Ann found out that she can buy a special ticket for *m* rides (she can buy it several times). It costs *b* rubles. Ann did the math; she will need to use subway *n* times. Help Ann, tell her what is the minimu... | The single line contains four space-separated integers *n*, *m*, *a*, *b* (1<=≤<=*n*,<=*m*,<=*a*,<=*b*<=≤<=1000) — the number of rides Ann has planned, the number of rides covered by the *m* ride ticket, the price of a one ride ticket and the price of an *m* ride ticket. | Print a single integer — the minimum sum in rubles that Ann will need to spend. | [
"6 2 1 2\n",
"5 2 2 3\n"
] | [
"6\n",
"8\n"
] | In the first sample one of the optimal solutions is: each time buy a one ride ticket. There are other optimal solutions. For example, buy three *m* ride tickets. | 500 | [
{
"input": "6 2 1 2",
"output": "6"
},
{
"input": "5 2 2 3",
"output": "8"
},
{
"input": "10 3 5 1",
"output": "4"
},
{
"input": "1000 1 1000 1000",
"output": "1000000"
},
{
"input": "1000 3 1000 1000",
"output": "334000"
},
{
"input": "1 1 1 1",
"... | 1,686,082,268 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 31 | 0 | n, m, a, b = map(int, input().split())
p = 1
x = 0
y = 0
lowest = (n * a)
while y >= 0:
y = n - (m * x)
if y >= 0:
cost = (x * b) + (y * a)
if cost < lowest:
lowest = cost
x += 1
x = 0
y = 0
while x >= 0:
q = (n - (p * y))
x = q // m
... | Title: Cheap Travel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ann has recently started commuting by subway. We know that a one ride subway ticket costs *a* rubles. Besides, Ann found out that she can buy a special ticket for *m* rides (she can buy it several times). It costs *b* rubl... | ```python
n, m, a, b = map(int, input().split())
p = 1
x = 0
y = 0
lowest = (n * a)
while y >= 0:
y = n - (m * x)
if y >= 0:
cost = (x * b) + (y * a)
if cost < lowest:
lowest = cost
x += 1
x = 0
y = 0
while x >= 0:
q = (n - (p * y))
x = ... | 3 | |
602 | A | Two Bases | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | After seeing the "ALL YOUR BASE ARE BELONG TO US" meme for the first time, numbers *X* and *Y* realised that they have different bases, which complicated their relations.
You're given a number *X* represented in base *b**x* and a number *Y* represented in base *b**y*. Compare those two numbers. | The first line of the input contains two space-separated integers *n* and *b**x* (1<=≤<=*n*<=≤<=10, 2<=≤<=*b**x*<=≤<=40), where *n* is the number of digits in the *b**x*-based representation of *X*.
The second line contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (0<=≤<=*x**i*<=<<=*b**x*) — the dig... | Output a single character (quotes for clarity):
- '<' if *X*<=<<=*Y* - '>' if *X*<=><=*Y* - '=' if *X*<==<=*Y* | [
"6 2\n1 0 1 1 1 1\n2 10\n4 7\n",
"3 3\n1 0 2\n2 5\n2 4\n",
"7 16\n15 15 4 0 0 7 10\n7 9\n4 8 0 3 1 5 0\n"
] | [
"=\n",
"<\n",
">\n"
] | In the first sample, *X* = 101111<sub class="lower-index">2</sub> = 47<sub class="lower-index">10</sub> = *Y*.
In the second sample, *X* = 102<sub class="lower-index">3</sub> = 21<sub class="lower-index">5</sub> and *Y* = 24<sub class="lower-index">5</sub> = 112<sub class="lower-index">3</sub>, thus *X* < *Y*.
In ... | 500 | [
{
"input": "6 2\n1 0 1 1 1 1\n2 10\n4 7",
"output": "="
},
{
"input": "3 3\n1 0 2\n2 5\n2 4",
"output": "<"
},
{
"input": "7 16\n15 15 4 0 0 7 10\n7 9\n4 8 0 3 1 5 0",
"output": ">"
},
{
"input": "2 2\n1 0\n2 3\n1 0",
"output": "<"
},
{
"input": "2 2\n1 0\n1 3\n1"... | 1,448,383,649 | 749 | Python 3 | OK | TESTS | 118 | 62 | 0 |
def f(a, b, c) :
ret = 0
mult = 1
for i in range (a - 1, -1, -1) :
ret += int(c[i]) * mult
mult = mult * b
return ret
a1 = input().split()
c1 = input().split()
a2 = input().split()
c2 = input().split()
#print (a1, c1)
#print (a2, c2)
x = f(int(a1[0]), int(a1[1]), c1)
y = f(int(a2[0]), int(... | Title: Two Bases
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After seeing the "ALL YOUR BASE ARE BELONG TO US" meme for the first time, numbers *X* and *Y* realised that they have different bases, which complicated their relations.
You're given a number *X* represented in base *b**x* ... | ```python
def f(a, b, c) :
ret = 0
mult = 1
for i in range (a - 1, -1, -1) :
ret += int(c[i]) * mult
mult = mult * b
return ret
a1 = input().split()
c1 = input().split()
a2 = input().split()
c2 = input().split()
#print (a1, c1)
#print (a2, c2)
x = f(int(a1[0]), int(a1[1]), c1)
y = f(int(a2... | 3 | |
500 | B | New Year Permutation | PROGRAMMING | 1,600 | [
"dfs and similar",
"dsu",
"graphs",
"greedy",
"math",
"sortings"
] | null | null | User ainta has a permutation *p*1,<=*p*2,<=...,<=*p**n*. As the New Year is coming, he wants to make his permutation as pretty as possible.
Permutation *a*1,<=*a*2,<=...,<=*a**n* is prettier than permutation *b*1,<=*b*2,<=...,<=*b**n*, if and only if there exists an integer *k* (1<=≤<=*k*<=≤<=*n*) where *a*1<==<=*b*1,... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=300) — the size of the permutation *p*.
The second line contains *n* space-separated integers *p*1,<=*p*2,<=...,<=*p**n* — the permutation *p* that user ainta has. Each integer between 1 and *n* occurs exactly once in the given permutation.
Next *n* lines describe... | In the first and only line, print *n* space-separated integers, describing the prettiest permutation that can be obtained. | [
"7\n5 2 4 3 6 7 1\n0001001\n0000000\n0000010\n1000001\n0000000\n0010000\n1001000\n",
"5\n4 2 1 5 3\n00100\n00011\n10010\n01101\n01010\n"
] | [
"1 2 4 3 6 7 5\n",
"1 2 3 4 5\n"
] | In the first sample, the swap needed to obtain the prettiest permutation is: (*p*<sub class="lower-index">1</sub>, *p*<sub class="lower-index">7</sub>).
In the second sample, the swaps needed to obtain the prettiest permutation is (*p*<sub class="lower-index">1</sub>, *p*<sub class="lower-index">3</sub>), (*p*<sub cla... | 1,000 | [
{
"input": "7\n5 2 4 3 6 7 1\n0001001\n0000000\n0000010\n1000001\n0000000\n0010000\n1001000",
"output": "1 2 4 3 6 7 5"
},
{
"input": "5\n4 2 1 5 3\n00100\n00011\n10010\n01101\n01010",
"output": "1 2 3 4 5"
},
{
"input": "7\n1 7 6 4 2 3 5\n0000100\n0000010\n0000001\n0000000\n1000000\n010... | 1,672,595,813 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | n = int(input())
p = list(map(int, input().split()))
a = []
for _ in range(n):
a += [list(map(int, input()))]
pos = [0] * n
for i, v in enumerate(p):
pos[v - 1] = i
for i in range(n):
ii = pos[i]
for j in range(ii + 1):
if a[ii][j] and p[j] > p[ii]:
p[ii], p[j] = p[... | Title: New Year Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
User ainta has a permutation *p*1,<=*p*2,<=...,<=*p**n*. As the New Year is coming, he wants to make his permutation as pretty as possible.
Permutation *a*1,<=*a*2,<=...,<=*a**n* is prettier than permutation *b*1,... | ```python
n = int(input())
p = list(map(int, input().split()))
a = []
for _ in range(n):
a += [list(map(int, input()))]
pos = [0] * n
for i, v in enumerate(p):
pos[v - 1] = i
for i in range(n):
ii = pos[i]
for j in range(ii + 1):
if a[ii][j] and p[j] > p[ii]:
p[ii],... | 0 | |
452 | C | Magic Trick | PROGRAMMING | 2,100 | [
"combinatorics",
"math",
"probabilities"
] | null | null | Alex enjoys performing magic tricks. He has a trick that requires a deck of *n* cards. He has *m* identical decks of *n* different cards each, which have been mixed together. When Alex wishes to perform the trick, he grabs *n* cards at random and performs the trick with those. The resulting deck looks like a normal dec... | First line of the input consists of two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000), separated by space — number of cards in each deck, and number of decks. | On the only line of the output print one floating point number – probability of Alex successfully performing the trick. Relative or absolute error of your answer should not be higher than 10<=-<=6. | [
"2 2\n",
"4 4\n",
"1 2\n"
] | [
"0.6666666666666666\n",
"0.4000000000000000\n",
"1.0000000000000000\n"
] | In the first sample, with probability <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/64c94d13eeb330b494061e86538db66574ad0f7d.png" style="max-width: 100.0%;max-height: 100.0%;"/> Alex will perform the trick with two cards with the same value from two different decks. In this case the trick... | 1,000 | [
{
"input": "2 2",
"output": "0.6666666666666666"
},
{
"input": "4 4",
"output": "0.4000000000000000"
},
{
"input": "1 2",
"output": "1.0000000000000000"
},
{
"input": "2 1",
"output": "0.5000000000000000"
},
{
"input": "10 10",
"output": "0.1818181818181818"
... | 1,505,416,403 | 4,403 | Python 3 | OK | TESTS | 17 | 62 | 0 | n, m = map(int, input().split())
if 1 == n:
print(1)
else:
print(1 / n + (n - 1) * (m - 1) / (n * (n * m - 1)))
| Title: Magic Trick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex enjoys performing magic tricks. He has a trick that requires a deck of *n* cards. He has *m* identical decks of *n* different cards each, which have been mixed together. When Alex wishes to perform the trick, he grabs ... | ```python
n, m = map(int, input().split())
if 1 == n:
print(1)
else:
print(1 / n + (n - 1) * (m - 1) / (n * (n * m - 1)))
``` | 3 | |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't w... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't e... | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,692,280,592 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 92 | 0 | n = int(input())
coins = list(map(int, input().split()))
coins.sort(reverse=True)
total_sum = sum(coins)
your_sum = 0
twin_sum = total_sum
coins_taken = 0
for coin in coins:
your_sum += coin
twin_sum -= coin
coins_taken += 1
if your_sum > twin_sum:
break
print(coins_... | Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very w... | ```python
n = int(input())
coins = list(map(int, input().split()))
coins.sort(reverse=True)
total_sum = sum(coins)
your_sum = 0
twin_sum = total_sum
coins_taken = 0
for coin in coins:
your_sum += coin
twin_sum -= coin
coins_taken += 1
if your_sum > twin_sum:
break
pr... | 3 | |
833 | A | The Meaningless Game | PROGRAMMING | 1,700 | [
"math",
"number theory"
] | null | null | Slastyona and her loyal dog Pushok are playing a meaningless game that is indeed very interesting.
The game consists of multiple rounds. Its rules are very simple: in each round, a natural number *k* is chosen. Then, the one who says (or barks) it faster than the other wins the round. After that, the winner's score is... | In the first string, the number of games *n* (1<=≤<=*n*<=≤<=350000) is given.
Each game is represented by a pair of scores *a*, *b* (1<=≤<=*a*,<=*b*<=≤<=109) – the results of Slastyona and Pushok, correspondingly. | For each pair of scores, answer "Yes" if it's possible for a game to finish with given score, and "No" otherwise.
You can output each letter in arbitrary case (upper or lower). | [
"6\n2 4\n75 45\n8 8\n16 16\n247 994\n1000000000 1000000\n"
] | [
"Yes\nYes\nYes\nNo\nNo\nYes\n"
] | First game might have been consisted of one round, in which the number 2 would have been chosen and Pushok would have won.
The second game needs exactly two rounds to finish with such result: in the first one, Slastyona would have said the number 5, and in the second one, Pushok would have barked the number 3. | 500 | [
{
"input": "6\n2 4\n75 45\n8 8\n16 16\n247 994\n1000000000 1000000",
"output": "Yes\nYes\nYes\nNo\nNo\nYes"
},
{
"input": "3\n1 1\n8 27\n1000 1331",
"output": "Yes\nNo\nNo"
},
{
"input": "1\n12004 18012002",
"output": "Yes"
},
{
"input": "1\n3331 11095561",
"output": "Yes... | 1,627,671,310 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 1,000 | 31,641,600 |
def process(a, b):
a2 = a*a
b2 = b*b
if (a2 % b) != 0:
return 'No'
if (b2 % a) != 0:
return 'No'
r3 = a2//b
s3 = b2//a
r = round(r3**(1/3))
s = round(s3**(1/3))
if r3 != r**3:
return 'No'
if s3 != s**3:
return 'No'
return 'Yes'... | Title: The Meaningless Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Slastyona and her loyal dog Pushok are playing a meaningless game that is indeed very interesting.
The game consists of multiple rounds. Its rules are very simple: in each round, a natural number *k* is chosen. Th... | ```python
def process(a, b):
a2 = a*a
b2 = b*b
if (a2 % b) != 0:
return 'No'
if (b2 % a) != 0:
return 'No'
r3 = a2//b
s3 = b2//a
r = round(r3**(1/3))
s = round(s3**(1/3))
if r3 != r**3:
return 'No'
if s3 != s**3:
return 'No'
re... | 0 | |
279 | B | Books | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation",
"two pointers"
] | null | null | When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy n... | Print a single integer — the maximum number of books Valera can read. | [
"4 5\n3 1 2 1\n",
"3 3\n2 2 3\n"
] | [
"3\n",
"1\n"
] | none | 1,000 | [
{
"input": "4 5\n3 1 2 1",
"output": "3"
},
{
"input": "3 3\n2 2 3",
"output": "1"
},
{
"input": "1 3\n5",
"output": "0"
},
{
"input": "1 10\n4",
"output": "1"
},
{
"input": "2 10\n6 4",
"output": "2"
},
{
"input": "6 10\n2 3 4 2 1 1",
"output": "4... | 1,684,322,661 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 38 | 154 | 10,752,000 | from sys import stdin
def solve():
n, t = map(int, stdin.readline().split())
A = [int(x) for x in stdin.readline().split()]
cur, i = 0, 0
for a in A:
cur += a
if cur > t:
cur -= A[i]
i += 1
print(n - i)
solve()
| Title: Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need t... | ```python
from sys import stdin
def solve():
n, t = map(int, stdin.readline().split())
A = [int(x) for x in stdin.readline().split()]
cur, i = 0, 0
for a in A:
cur += a
if cur > t:
cur -= A[i]
i += 1
print(n - i)
solve()
``` | 3 | |
278 | B | New Problem | PROGRAMMING | 1,500 | [
"brute force",
"strings"
] | null | null | Coming up with a new problem isn't as easy as many people think. Sometimes it is hard enough to name it. We'll consider a title original if it doesn't occur as a substring in any titles of recent Codeforces problems.
You've got the titles of *n* last problems — the strings, consisting of lowercase English letters. Yo... | The first line contains integer *n* (1<=≤<=*n*<=≤<=30) — the number of titles you've got to consider. Then follow *n* problem titles, one per line. Each title only consists of lowercase English letters (specifically, it doesn't contain any spaces) and has the length from 1 to 20, inclusive. | Print a string, consisting of lowercase English letters — the lexicographically minimum shortest original title. | [
"5\nthreehorses\ngoodsubstrings\nsecret\nprimematrix\nbeautifulyear\n",
"4\naa\nbdefghijklmn\nopqrstuvwxyz\nc\n"
] | [
"j\n",
"ab\n"
] | In the first sample the first 9 letters of the English alphabet (a, b, c, d, e, f, g, h, i) occur in the problem titles, so the answer is letter j.
In the second sample the titles contain 26 English letters, so the shortest original title cannot have length 1. Title aa occurs as a substring in the first title. | 1,000 | [
{
"input": "5\nthreehorses\ngoodsubstrings\nsecret\nprimematrix\nbeautifulyear",
"output": "j"
},
{
"input": "4\naa\nbdefghijklmn\nopqrstuvwxyz\nc",
"output": "ab"
},
{
"input": "1\na",
"output": "b"
},
{
"input": "1\nb",
"output": "a"
},
{
"input": "1\nz",
"o... | 1,368,724,732 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 78 | 307,200 | import re
import itertools
from collections import Counter
class Task:
strings = []
answer = ""
def getData(self):
numberOfStrings = int(input())
for i in range(0, numberOfStrings):
self.strings += [input()]
def solve(self):
badStrings = set()
for current... | Title: New Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Coming up with a new problem isn't as easy as many people think. Sometimes it is hard enough to name it. We'll consider a title original if it doesn't occur as a substring in any titles of recent Codeforces problems.
You'... | ```python
import re
import itertools
from collections import Counter
class Task:
strings = []
answer = ""
def getData(self):
numberOfStrings = int(input())
for i in range(0, numberOfStrings):
self.strings += [input()]
def solve(self):
badStrings = set()
f... | 3 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,670,500,788 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 20 | 62 | 0 | n = int(input())
list = []
for i in range(0,n):
randomname = input()
if len(randomname) > 10:
fda = len(randomname[1:-1])
meow = str(fda)
item = (randomname[0]+meow+randomname[-1])
list.append(item)
else:
list.append(randomname)
for i in list:
print(i... | Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
n = int(input())
list = []
for i in range(0,n):
randomname = input()
if len(randomname) > 10:
fda = len(randomname[1:-1])
meow = str(fda)
item = (randomname[0]+meow+randomname[-1])
list.append(item)
else:
list.append(randomname)
for i in list:
... | 3.969 |
462 | A | Appleman and Easy Task | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or character 'o'. Is it true that each cell of the board has even number of adjacent cells with 'o'? Two cells... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Then *n* lines follow containing the description of the checkerboard. Each of them contains *n* characters (either 'x' or 'o') without spaces. | Print "YES" or "NO" (without the quotes) depending on the answer to the problem. | [
"3\nxxo\nxox\noxx\n",
"4\nxxxo\nxoxo\noxox\nxxxx\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "3\nxxo\nxox\noxx",
"output": "YES"
},
{
"input": "4\nxxxo\nxoxo\noxox\nxxxx",
"output": "NO"
},
{
"input": "1\no",
"output": "YES"
},
{
"input": "2\nox\nxo",
"output": "YES"
},
{
"input": "2\nxx\nxo",
"output": "NO"
},
{
"input": "3\nooo\no... | 1,605,012,906 | 2,147,483,647 | PyPy 3 | OK | TESTS | 32 | 155 | 2,048,000 | n=int(input())
f=["x"*(n+2)]
for i in range(n):
s=str(input())
f.append(list("x"+s+"x"))
f.append("x"*(n+2))
flag=True
for i in range(1,n+1):
for j in range(1,n+1):
k=[f[i+1][j],f[i-1][j],f[i][j+1],f[i][j-1]]
if k.count("o")%2!=0:
flag=False
if flag:
... | Title: Appleman and Easy Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or... | ```python
n=int(input())
f=["x"*(n+2)]
for i in range(n):
s=str(input())
f.append(list("x"+s+"x"))
f.append("x"*(n+2))
flag=True
for i in range(1,n+1):
for j in range(1,n+1):
k=[f[i+1][j],f[i-1][j],f[i][j+1],f[i][j-1]]
if k.count("o")%2!=0:
flag=False
... | 3 | |
44 | A | Indian Summer | PROGRAMMING | 900 | [
"implementation"
] | A. Indian Summer | 2 | 256 | Indian summer is such a beautiful time of the year! A girl named Alyona is walking in the forest and picking a bouquet from fallen leaves. Alyona is very choosy — she doesn't take a leaf if it matches the color and the species of the tree of one of the leaves she already has. Find out how many leaves Alyona has picked. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of leaves Alyona has found. The next *n* lines contain the leaves' descriptions. Each leaf is characterized by the species of the tree it has fallen from and by the color. The species of the trees and colors are given in names, consisting of no mor... | Output the single number — the number of Alyona's leaves. | [
"5\nbirch yellow\nmaple red\nbirch yellow\nmaple yellow\nmaple green\n",
"3\noak yellow\noak yellow\noak yellow\n"
] | [
"4\n",
"1\n"
] | none | 0 | [
{
"input": "5\nbirch yellow\nmaple red\nbirch yellow\nmaple yellow\nmaple green",
"output": "4"
},
{
"input": "3\noak yellow\noak yellow\noak yellow",
"output": "1"
},
{
"input": "5\nxbnbkzn hp\nkaqkl vrgzbvqstu\nj aqidx\nhos gyul\nwefxmh tygpluae",
"output": "5"
},
{
"input"... | 1,677,514,846 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 29 | 124 | 0 | x=[]
for _ in range(int(input())):
a=input()
x.append(a)
print(len(set(x)))
| Title: Indian Summer
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Indian summer is such a beautiful time of the year! A girl named Alyona is walking in the forest and picking a bouquet from fallen leaves. Alyona is very choosy — she doesn't take a leaf if it matches the color and the specie... | ```python
x=[]
for _ in range(int(input())):
a=input()
x.append(a)
print(len(set(x)))
``` | 3.969 |
92 | A | Chips | PROGRAMMING | 800 | [
"implementation",
"math"
] | A. Chips | 2 | 256 | There are *n* walruses sitting in a circle. All of them are numbered in the clockwise order: the walrus number 2 sits to the left of the walrus number 1, the walrus number 3 sits to the left of the walrus number 2, ..., the walrus number 1 sits to the left of the walrus number *n*.
The presenter has *m* chips. The pre... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=50, 1<=≤<=*m*<=≤<=104) — the number of walruses and the number of chips correspondingly. | Print the number of chips the presenter ended up with. | [
"4 11\n",
"17 107\n",
"3 8\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first sample the presenter gives one chip to the walrus number 1, two chips to the walrus number 2, three chips to the walrus number 3, four chips to the walrus number 4, then again one chip to the walrus number 1. After that the presenter runs out of chips. He can't give anything to the walrus number 2 and the ... | 500 | [
{
"input": "4 11",
"output": "0"
},
{
"input": "17 107",
"output": "2"
},
{
"input": "3 8",
"output": "1"
},
{
"input": "46 7262",
"output": "35"
},
{
"input": "32 6864",
"output": "0"
},
{
"input": "36 6218",
"output": "14"
},
{
"input": "... | 1,630,827,852 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 218 | 20,172,800 | n,m=map(int,input().split())
s=n*(n+1)//2
if s==m:
print(0)
elif s>m:
for i in range(1,n+1):
if m>=i:
m-=i
else:
break
print(m)
else:
m=m%s
for i in range(1,n+1):
if m>=i:
m-=i
else:
break
print(m)
... | Title: Chips
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There are *n* walruses sitting in a circle. All of them are numbered in the clockwise order: the walrus number 2 sits to the left of the walrus number 1, the walrus number 3 sits to the left of the walrus number 2, ..., the walrus nu... | ```python
n,m=map(int,input().split())
s=n*(n+1)//2
if s==m:
print(0)
elif s>m:
for i in range(1,n+1):
if m>=i:
m-=i
else:
break
print(m)
else:
m=m%s
for i in range(1,n+1):
if m>=i:
m-=i
else:
break
... | 3.907925 |
940 | A | Points on the line | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"sortings"
] | null | null | We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1,<=3,<=2,<=1} is 2.
D... | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=100,<=0<=≤<=*d*<=≤<=100) — the amount of points and the maximum allowed diameter respectively.
The second line contains *n* space separated integers (1<=≤<=*x**i*<=≤<=100) — the coordinates of the points. | Output a single integer — the minimum number of points you have to remove. | [
"3 1\n2 1 4\n",
"3 0\n7 7 7\n",
"6 3\n1 3 4 6 9 10\n"
] | [
"1\n",
"0\n",
"3\n"
] | In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal stra... | 500 | [
{
"input": "3 1\n2 1 4",
"output": "1"
},
{
"input": "3 0\n7 7 7",
"output": "0"
},
{
"input": "6 3\n1 3 4 6 9 10",
"output": "3"
},
{
"input": "11 5\n10 11 12 13 14 15 16 17 18 19 20",
"output": "5"
},
{
"input": "1 100\n1",
"output": "0"
},
{
"input"... | 1,520,328,228 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 62 | 5,632,000 | n, d = map(int, input().split())
A = list(map(int, input().split()))
min_res = 1000000000000000000000000000000000000000000000000000000000
for i in range(len(A)):
for j in range(len(A)):
if abs(A[i] - A[j]) <= d:
if min(i, j) + len(A) - max(i, j) - 1 < min_res:
min_res = min(i, j) + len(A) - m... | Title: Points on the line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest dista... | ```python
n, d = map(int, input().split())
A = list(map(int, input().split()))
min_res = 1000000000000000000000000000000000000000000000000000000000
for i in range(len(A)):
for j in range(len(A)):
if abs(A[i] - A[j]) <= d:
if min(i, j) + len(A) - max(i, j) - 1 < min_res:
min_res = min(i, j) + ... | 0 | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,675,817,377 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 21 | 1,000 | 0 | n=int(input())
l=list(map(int,input().split()))
d={}
for i in l:
if i in d:
d[i]+=1
else:
d[i]=1
r=[]
for i in d:
r.append(d[i])
if len(r)<3:
print(0)
else:
mn=min(r)
r=[[0 for i in range(3)] for i in range(mn)]
for i in range(mn):
f1=0
f2=0
... | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
n=int(input())
l=list(map(int,input().split()))
d={}
for i in l:
if i in d:
d[i]+=1
else:
d[i]=1
r=[]
for i in d:
r.append(d[i])
if len(r)<3:
print(0)
else:
mn=min(r)
r=[[0 for i in range(3)] for i in range(mn)]
for i in range(mn):
f1=0
... | 0 | |
789 | B | Masha and geometric depression | PROGRAMMING | 1,700 | [
"brute force",
"implementation",
"math"
] | null | null | Masha really loves algebra. On the last lesson, her strict teacher Dvastan gave she new exercise.
You are given geometric progression *b* defined by two integers *b*1 and *q*. Remind that a geometric progression is a sequence of integers *b*1,<=*b*2,<=*b*3,<=..., where for each *i*<=><=1 the respective term satisfi... | The first line of input contains four integers *b*1, *q*, *l*, *m* (-109<=≤<=*b*1,<=*q*<=≤<=109, 1<=≤<=*l*<=≤<=109, 1<=≤<=*m*<=≤<=105) — the initial term and the common ratio of progression, absolute value of maximal number that can be written on the board and the number of "bad" integers, respectively.
The second lin... | Print the only integer, meaning the number of progression terms that will be written on the board if it is finite, or "inf" (without quotes) otherwise. | [
"3 2 30 4\n6 14 25 48\n",
"123 1 2143435 4\n123 11 -5453 141245\n",
"123 1 2143435 4\n54343 -13 6 124\n"
] | [
"3",
"0",
"inf"
] | In the first sample case, Masha will write integers 3, 12, 24. Progression term 6 will be skipped because it is a "bad" integer. Terms bigger than 24 won't be written because they exceed *l* by absolute value.
In the second case, Masha won't write any number because all terms are equal 123 and this is a "bad" integer.... | 1,000 | [
{
"input": "3 2 30 4\n6 14 25 48",
"output": "3"
},
{
"input": "123 1 2143435 4\n123 11 -5453 141245",
"output": "0"
},
{
"input": "123 1 2143435 4\n54343 -13 6 124",
"output": "inf"
},
{
"input": "3 2 25 2\n379195692 -69874783",
"output": "4"
},
{
"input": "3 2 3... | 1,491,216,618 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 93 | 13,004,800 | b1, q, l, m = map(int, input().split())
ai = list((map(int, input().split())))
count = 0
if (q==0 or b1==0) and (0 not in ai):
print('inf')
elif (q==0 or b1==0) and (0 in ai):
print(count if (b1==0 or b1 in ai) else count+1)
else: #q!=0 and b1!=0
if q==1:
if b1 not in ai:
pri... | Title: Masha and geometric depression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Masha really loves algebra. On the last lesson, her strict teacher Dvastan gave she new exercise.
You are given geometric progression *b* defined by two integers *b*1 and *q*. Remind that a geometric pro... | ```python
b1, q, l, m = map(int, input().split())
ai = list((map(int, input().split())))
count = 0
if (q==0 or b1==0) and (0 not in ai):
print('inf')
elif (q==0 or b1==0) and (0 in ai):
print(count if (b1==0 or b1 in ai) else count+1)
else: #q!=0 and b1!=0
if q==1:
if b1 not in ai:
... | 0 | |
151 | A | Soft Drinking | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut each of them into *d* slices. After that they found *p* grams of salt.
To make a toast, each frie... | The first and only line contains positive integers *n*, *k*, *l*, *c*, *d*, *p*, *nl*, *np*, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space. | Print a single integer — the number of toasts each friend can make. | [
"3 4 5 10 8 100 3 1\n",
"5 100 10 1 19 90 4 3\n",
"10 1000 1000 25 23 1 50 1\n"
] | [
"2\n",
"3\n",
"0\n"
] | A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is *min*(6, 80, 100) / 3 = 2. | 500 | [
{
"input": "3 4 5 10 8 100 3 1",
"output": "2"
},
{
"input": "5 100 10 1 19 90 4 3",
"output": "3"
},
{
"input": "10 1000 1000 25 23 1 50 1",
"output": "0"
},
{
"input": "1 7 4 5 5 8 3 2",
"output": "4"
},
{
"input": "2 3 3 5 5 10 1 3",
"output": "1"
},
{
... | 1,688,797,609 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 8 | 92 | 0 | n,k,l,c,d,p,nl,np=map(int,input().split())
t1=k*l
a1=t1//3
a2=c*d
a3=p//np
ans=min(a1,a2,a3)//n
print(ans) | Title: Soft Drinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut... | ```python
n,k,l,c,d,p,nl,np=map(int,input().split())
t1=k*l
a1=t1//3
a2=c*d
a3=p//np
ans=min(a1,a2,a3)//n
print(ans)
``` | 0 |
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