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1.01k
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values | name
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11
| title
stringclasses 522
values | time-limit
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values | memory-limit
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2.05k
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| creationTimeSeconds
int64 1.37B
1.7B
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stringlengths 262
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stringlengths 17
65.5k
| score
float64 -1
3.99
|
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
624
|
B
|
Making a String
|
PROGRAMMING
| 1,100
|
[
"greedy",
"sortings"
] | null | null |
You are given an alphabet consisting of *n* letters, your task is to make a string of the maximum possible length so that the following conditions are satisfied:
- the *i*-th letter occurs in the string no more than *a**i* times; - the number of occurrences of each letter in the string must be distinct for all the letters that occurred in the string at least once.
|
The first line of the input contains a single integer *n* (2<=<=≤<=<=*n*<=<=≤<=<=26) — the number of letters in the alphabet.
The next line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — *i*-th of these integers gives the limitation on the number of occurrences of the *i*-th character in the string.
|
Print a single integer — the maximum length of the string that meets all the requirements.
|
[
"3\n2 5 5\n",
"3\n1 1 2\n"
] |
[
"11\n",
"3\n"
] |
For convenience let's consider an alphabet consisting of three letters: "a", "b", "c". In the first sample, some of the optimal strings are: "cccaabbccbb", "aabcbcbcbcb". In the second sample some of the optimal strings are: "acc", "cbc".
| 1,000
|
[
{
"input": "3\n2 5 5",
"output": "11"
},
{
"input": "3\n1 1 2",
"output": "3"
},
{
"input": "2\n1 1",
"output": "1"
},
{
"input": "3\n1 1000000000 2",
"output": "1000000003"
},
{
"input": "26\n1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000",
"output": "25999999675"
},
{
"input": "2\n559476582 796461544",
"output": "1355938126"
},
{
"input": "2\n257775227 621811272",
"output": "879586499"
},
{
"input": "10\n876938317 219479349 703839299 977218449 116819315 752405530 393874852 286326991 592978634 155758306",
"output": "5075639042"
},
{
"input": "26\n72 49 87 47 94 96 36 91 43 11 19 83 36 38 10 93 95 81 4 96 60 38 97 37 36 41",
"output": "1478"
},
{
"input": "26\n243 364 768 766 633 535 502 424 502 283 592 877 137 891 837 990 681 898 831 487 595 604 747 856 805 688",
"output": "16535"
},
{
"input": "26\n775 517 406 364 548 951 680 984 466 141 960 513 660 849 152 250 176 601 199 370 971 554 141 224 724 543",
"output": "13718"
},
{
"input": "26\n475 344 706 807 925 813 974 166 578 226 624 591 419 894 574 909 544 597 170 990 893 785 399 172 792 748",
"output": "16115"
},
{
"input": "26\n130 396 985 226 487 671 188 706 106 649 38 525 210 133 298 418 953 431 577 69 12 982 264 373 283 266",
"output": "10376"
},
{
"input": "26\n605 641 814 935 936 547 524 702 133 674 173 102 318 620 248 523 77 718 318 635 322 362 306 86 8 442",
"output": "11768"
},
{
"input": "26\n220 675 725 888 725 654 546 806 379 182 604 667 734 394 889 731 572 193 850 651 844 734 163 671 820 887",
"output": "16202"
},
{
"input": "26\n1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000",
"output": "25675"
},
{
"input": "26\n1001 1001 1000 1000 1001 1000 1001 1001 1001 1000 1000 1001 1001 1000 1000 1000 1000 1001 1000 1001 1001 1000 1001 1001 1001 1000",
"output": "25701"
},
{
"input": "26\n1000 1001 1000 1001 1000 1001 1001 1000 1001 1002 1002 1000 1001 1000 1000 1000 1001 1002 1001 1000 1000 1001 1000 1002 1001 1002",
"output": "25727"
},
{
"input": "26\n1003 1002 1002 1003 1000 1000 1000 1003 1000 1001 1003 1003 1000 1002 1002 1002 1001 1003 1000 1001 1000 1001 1001 1000 1003 1003",
"output": "25753"
},
{
"input": "26\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "1"
},
{
"input": "26\n8717 9417 1409 7205 3625 6247 8626 9486 464 4271 1698 8449 4551 1528 7456 9198 4886 2889 7534 506 7867 9410 1635 4955 2580 2580",
"output": "137188"
},
{
"input": "26\n197464663 125058028 622449215 11119637 587496049 703992162 219591040 965159268 229879004 278894000 841629744 616893922 218779915 362575332 844188865 342411376 369680019 43823059 921419789 999588082 943769007 35365522 301907919 758302419 427454397 807507709",
"output": "12776400142"
},
{
"input": "26\n907247856 970380443 957324066 929910532 947150618 944189007 998282297 988343406 981298600 943026596 953932265 972691398 950024048 923033790 996423650 972134755 946404759 918183059 902987271 965507679 906967700 982106487 933997242 972594441 977736332 928874832",
"output": "24770753129"
},
{
"input": "26\n999999061 999999688 999999587 999999429 999999110 999999563 999999120 999999111 999999794 999999890 999999004 999999448 999999770 999999543 999999460 999999034 999999361 999999305 999999201 999999778 999999432 999999844 999999133 999999342 999999600 999999319",
"output": "25999984927"
},
{
"input": "3\n587951561 282383259 612352726",
"output": "1482687546"
},
{
"input": "4\n111637338 992238139 787658714 974622806",
"output": "2866156997"
},
{
"input": "5\n694257603 528073418 726928894 596328666 652863391",
"output": "3198451972"
},
{
"input": "6\n217943380 532900593 902234882 513005821 369342573 495810412",
"output": "3031237661"
},
{
"input": "7\n446656860 478792281 77541870 429682977 85821755 826122363 563802405",
"output": "2908420511"
},
{
"input": "8\n29278125 778590752 252847858 51388836 802299938 215370803 901540149 242074772",
"output": "3273391233"
},
{
"input": "9\n552962902 724482439 133182550 673093696 518779120 604618242 534250189 847695567 403066553",
"output": "4992131258"
},
{
"input": "10\n600386086 862479376 284190454 781950823 672077209 5753052 145701234 680334621 497013634 35429365",
"output": "4565315854"
},
{
"input": "11\n183007351 103343359 164525146 698627979 388556391 926007595 483438978 580927711 659384363 201890880 920750904",
"output": "5310460657"
},
{
"input": "12\n706692128 108170535 339831134 320333838 810063277 20284739 821176722 481520801 467848308 604388203 881959821 874133307",
"output": "6436402813"
},
{
"input": "13\n525349200 54062222 810108418 237010994 821513756 409532178 158915465 87142595 630219037 770849718 843168738 617993222 504443485",
"output": "6470309028"
},
{
"input": "14\n812998169 353860693 690443110 153688149 537992938 798779618 791624505 282706982 733654279 468319337 568341847 597888944 649703235 667623671",
"output": "8107625477"
},
{
"input": "15\n336683946 299752380 865749098 775393009 959499824 893055762 365399057 419335880 896025008 575845364 529550764 341748859 30999793 464432689 19445239",
"output": "7772916672"
},
{
"input": "16\n860368723 540615364 41056086 692070164 970950302 282304201 998108096 24957674 999460249 37279175 490759681 26673285 412295352 671298115 627182888 90740349",
"output": "7766119704"
},
{
"input": "17\n148018692 545442539 980325266 313776023 687429485 376580345 40875544 925549764 161831978 144805202 451968598 475560904 262583806 468107133 60900936 281546097 912565045",
"output": "7237867357"
},
{
"input": "18\n966674765 786305522 860659958 935480883 108937371 60800080 673584584 826142855 560238516 606238013 413177515 455456626 643879364 969943855 963609881 177380550 544192822 864797474",
"output": "11417500634"
},
{
"input": "19\n490360541 496161402 330938242 852158038 120387849 686083328 247359135 431764649 427637949 8736336 843378328 435352349 494167818 766752874 161292122 368186298 470791896 813444279 170758124",
"output": "8615711557"
},
{
"input": "20\n654616375 542649443 729213190 188364665 238384327 726353863 974350390 526804424 601329631 886592063 734805196 275562411 861801362 374466292 119830901 403120565 670982545 63210795 130397643 601611646",
"output": "10304447727"
},
{
"input": "21\n942265343 252505322 904519178 810069524 954862509 115602302 548124942 132426218 999736168 584061682 696014113 960485837 712089816 581331718 317512142 593926314 302610323 716885305 477125514 813997503 535631456",
"output": "12951783229"
},
{
"input": "22\n465951120 788339601 784853870 726746679 376370396 504849742 180834982 33019308 867135601 455551901 657223030 940381560 93386374 378140736 161286599 548696254 934237100 75589518 764917898 731412064 205669368 630662937",
"output": "11305256638"
},
{
"input": "23\n989635897 498195481 255132154 643423835 387820874 894097181 223601429 228583694 265543138 153021520 618431947 684241474 943673829 174949754 358967839 444530707 801900686 965299835 347682577 648826625 406714384 129525158 958578251",
"output": "12022378269"
},
{
"input": "24\n277285866 739058464 135466846 265129694 104300056 519381429 856310469 834204489 132942572 260547547 343605057 664137197 619941683 676786476 497713592 635336455 138557168 618975345 635474960 861212482 76752297 923357675 517046816 274123722",
"output": "11607648357"
},
{
"input": "25\n95942939 979921447 310772834 181806850 525806942 613657573 194049213 734797579 531349109 721980358 304813974 113025815 470230137 473595494 695394833 590106396 770183946 567622150 218239639 778627043 41761505 127248600 134450869 860350034 901937574",
"output": "11937672853"
},
{
"input": "26\n619627716 984748623 486078822 98484005 537257421 2906012 62795060 635390669 103777246 829506385 971050595 92921538 851525695 680460920 893076074 780912144 401811723 221297659 269996214 991012900 242806521 626109821 987889730 682613155 209557740 806895799",
"output": "14070510187"
},
{
"input": "26\n10 1 20 2 23 3 14 6 7 13 26 21 11 8 16 25 12 15 19 9 17 22 24 18 5 4",
"output": "351"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "5\n5 3 3 3 1",
"output": "11"
},
{
"input": "5\n2 2 2 2 2",
"output": "3"
},
{
"input": "10\n10 10 10 10 10 10 10 10 1 1",
"output": "53"
},
{
"input": "10\n100 100 10 10 10 10 10 1 1 1",
"output": "240"
},
{
"input": "6\n5 3 3 3 3 1",
"output": "11"
},
{
"input": "4\n4 3 2 1",
"output": "10"
},
{
"input": "5\n1 1 1 1 1",
"output": "1"
}
] | 1,454,606,388
| 888
|
Python 3
|
CHALLENGED
|
CHALLENGES
| 8
| 61
| 0
|
n=int(input())
a=[int(i) for i in input().split()]
a=sorted(a)[::-1]
t=a[0]+1
s=0
for i in a:
if t>i:
s+=i
t=i
else:
t-=1
s+=t
print(s)
|
Title: Making a String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an alphabet consisting of *n* letters, your task is to make a string of the maximum possible length so that the following conditions are satisfied:
- the *i*-th letter occurs in the string no more than *a**i* times; - the number of occurrences of each letter in the string must be distinct for all the letters that occurred in the string at least once.
Input Specification:
The first line of the input contains a single integer *n* (2<=<=≤<=<=*n*<=<=≤<=<=26) — the number of letters in the alphabet.
The next line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — *i*-th of these integers gives the limitation on the number of occurrences of the *i*-th character in the string.
Output Specification:
Print a single integer — the maximum length of the string that meets all the requirements.
Demo Input:
['3\n2 5 5\n', '3\n1 1 2\n']
Demo Output:
['11\n', '3\n']
Note:
For convenience let's consider an alphabet consisting of three letters: "a", "b", "c". In the first sample, some of the optimal strings are: "cccaabbccbb", "aabcbcbcbcb". In the second sample some of the optimal strings are: "acc", "cbc".
|
```python
n=int(input())
a=[int(i) for i in input().split()]
a=sorted(a)[::-1]
t=a[0]+1
s=0
for i in a:
if t>i:
s+=i
t=i
else:
t-=1
s+=t
print(s)
```
| -1
|
|
873
|
B
|
Balanced Substring
|
PROGRAMMING
| 1,500
|
[
"dp",
"implementation"
] | null | null |
You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called balanced if the number of zeroes (0) equals to the number of ones in this substring.
You have to determine the length of the longest balanced substring of *s*.
|
The first line contains *n* (1<=≤<=*n*<=≤<=100000) — the number of characters in *s*.
The second line contains a string *s* consisting of exactly *n* characters. Only characters 0 and 1 can appear in *s*.
|
If there is no non-empty balanced substring in *s*, print 0. Otherwise, print the length of the longest balanced substring.
|
[
"8\n11010111\n",
"3\n111\n"
] |
[
"4\n",
"0\n"
] |
In the first example you can choose the substring [3, 6]. It is balanced, and its length is 4. Choosing the substring [2, 5] is also possible.
In the second example it's impossible to find a non-empty balanced substring.
| 0
|
[
{
"input": "8\n11010111",
"output": "4"
},
{
"input": "3\n111",
"output": "0"
},
{
"input": "11\n00001000100",
"output": "2"
},
{
"input": "10\n0100000000",
"output": "2"
},
{
"input": "13\n0001000011010",
"output": "6"
},
{
"input": "14\n00000100101011",
"output": "10"
},
{
"input": "14\n01111101111111",
"output": "2"
},
{
"input": "18\n110010101101111111",
"output": "10"
},
{
"input": "11\n00010000011",
"output": "4"
},
{
"input": "10\n1000010110",
"output": "6"
},
{
"input": "15\n100000100000011",
"output": "4"
},
{
"input": "18\n011010101110111101",
"output": "8"
},
{
"input": "10\n0011011111",
"output": "6"
},
{
"input": "3\n011",
"output": "2"
},
{
"input": "14\n11111111111111",
"output": "0"
},
{
"input": "65\n11001000110001001011011110111100000000101001001010101111000100010",
"output": "48"
},
{
"input": "10\n0011111000",
"output": "10"
},
{
"input": "13\n1110000001110",
"output": "12"
},
{
"input": "3\n110",
"output": "2"
},
{
"input": "4\n1110",
"output": "2"
},
{
"input": "9\n001011001",
"output": "8"
},
{
"input": "2\n10",
"output": "2"
},
{
"input": "2\n01",
"output": "2"
},
{
"input": "12\n110000110000",
"output": "8"
},
{
"input": "3\n001",
"output": "2"
},
{
"input": "14\n11000011000000",
"output": "8"
},
{
"input": "19\n0000011111111100000",
"output": "18"
},
{
"input": "45\n011010001100001111110001011100000001101100111",
"output": "44"
},
{
"input": "18\n000001111111100000",
"output": "16"
},
{
"input": "4\n0101",
"output": "4"
},
{
"input": "12\n000101011001",
"output": "10"
}
] | 1,669,713,515
| 2,147,483,647
|
PyPy 3-64
|
WRONG_ANSWER
|
TESTS
| 5
| 62
| 0
|
import sys
from math import *
from collections import Counter,defaultdict,deque
input=sys.stdin.readline
mod=10**9+7
ma=defaultdict(lambda:-inf)
mi=defaultdict(lambda:inf)
x,y=0,0
n=int(input())
a=input()
for i in range(n):
ma[x-y]=max(ma[x-y],i)
mi[x-y]=min(mi[x-y],i)
if a[i]=='0':
x+=1
else:
y+=1
ma[x-y]=max(ma[x-y],i)
mi[x-y]=min(mi[x-y],i)
ans=0
for i in ma:
ans=max(ans,ma[i]-mi[i])
print(ans)
|
Title: Balanced Substring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called balanced if the number of zeroes (0) equals to the number of ones in this substring.
You have to determine the length of the longest balanced substring of *s*.
Input Specification:
The first line contains *n* (1<=≤<=*n*<=≤<=100000) — the number of characters in *s*.
The second line contains a string *s* consisting of exactly *n* characters. Only characters 0 and 1 can appear in *s*.
Output Specification:
If there is no non-empty balanced substring in *s*, print 0. Otherwise, print the length of the longest balanced substring.
Demo Input:
['8\n11010111\n', '3\n111\n']
Demo Output:
['4\n', '0\n']
Note:
In the first example you can choose the substring [3, 6]. It is balanced, and its length is 4. Choosing the substring [2, 5] is also possible.
In the second example it's impossible to find a non-empty balanced substring.
|
```python
import sys
from math import *
from collections import Counter,defaultdict,deque
input=sys.stdin.readline
mod=10**9+7
ma=defaultdict(lambda:-inf)
mi=defaultdict(lambda:inf)
x,y=0,0
n=int(input())
a=input()
for i in range(n):
ma[x-y]=max(ma[x-y],i)
mi[x-y]=min(mi[x-y],i)
if a[i]=='0':
x+=1
else:
y+=1
ma[x-y]=max(ma[x-y],i)
mi[x-y]=min(mi[x-y],i)
ans=0
for i in ma:
ans=max(ans,ma[i]-mi[i])
print(ans)
```
| 0
|
|
371
|
D
|
Vessels
|
PROGRAMMING
| 1,800
|
[
"data structures",
"dsu",
"implementation",
"trees"
] | null | null |
There is a system of *n* vessels arranged one above the other as shown in the figure below. Assume that the vessels are numbered from 1 to *n*, in the order from the highest to the lowest, the volume of the *i*-th vessel is *a**i* liters.
Initially, all the vessels are empty. In some vessels water is poured. All the water that overflows from the *i*-th vessel goes to the (*i*<=+<=1)-th one. The liquid that overflows from the *n*-th vessel spills on the floor.
Your task is to simulate pouring water into the vessels. To do this, you will need to handle two types of queries:
1. Add *x**i* liters of water to the *p**i*-th vessel; 1. Print the number of liters of water in the *k**i*-th vessel.
When you reply to the second request you can assume that all the water poured up to this point, has already overflown between the vessels.
|
The first line contains integer *n* — the number of vessels (1<=≤<=*n*<=≤<=2·105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* — the vessels' capacities (1<=≤<=*a**i*<=≤<=109). The vessels' capacities do not necessarily increase from the top vessels to the bottom ones (see the second sample). The third line contains integer *m* — the number of queries (1<=≤<=*m*<=≤<=2·105). Each of the next *m* lines contains the description of one query. The query of the first type is represented as "1 *p**i* *x**i*", the query of the second type is represented as "2 *k**i*" (1<=≤<=*p**i*<=≤<=*n*, 1<=≤<=*x**i*<=≤<=109, 1<=≤<=*k**i*<=≤<=*n*).
|
For each query, print on a single line the number of liters of water in the corresponding vessel.
|
[
"2\n5 10\n6\n1 1 4\n2 1\n1 2 5\n1 1 4\n2 1\n2 2\n",
"3\n5 10 8\n6\n1 1 12\n2 2\n1 1 6\n1 3 2\n2 2\n2 3\n"
] |
[
"4\n5\n8\n",
"7\n10\n5\n"
] |
none
| 2,000
|
[
{
"input": "2\n5 10\n6\n1 1 4\n2 1\n1 2 5\n1 1 4\n2 1\n2 2",
"output": "4\n5\n8"
},
{
"input": "3\n5 10 8\n6\n1 1 12\n2 2\n1 1 6\n1 3 2\n2 2\n2 3",
"output": "7\n10\n5"
},
{
"input": "10\n71 59 88 55 18 98 38 73 53 58\n20\n1 5 93\n1 7 69\n2 3\n1 1 20\n2 10\n1 6 74\n1 7 100\n1 9 14\n2 3\n2 4\n2 7\n1 3 31\n2 4\n1 6 64\n2 2\n2 2\n1 3 54\n2 9\n2 1\n1 6 86",
"output": "0\n0\n0\n0\n38\n0\n0\n0\n53\n20"
},
{
"input": "10\n3 7 10 1 5 4 4 3 3 1\n20\n2 4\n2 4\n1 1 10\n1 1 10\n2 4\n2 3\n1 4 2\n1 4 6\n2 2\n1 8 9\n2 2\n2 5\n2 9\n1 2 1\n1 6 9\n1 1 6\n2 5\n2 2\n2 3\n1 4 10",
"output": "0\n0\n0\n10\n7\n7\n5\n3\n5\n7\n10"
},
{
"input": "50\n57 63 98 44 22 63 5 65 36 69 49 54 61 15 29 79 50 30 43 93 18 94 46 92 72 67 67 51 34 40 50 77 58 53 79 72 72 34 91 75 83 67 71 80 11 51 85 20 6 3\n20\n2 40\n1 14 102\n2 22\n2 15\n2 43\n1 29 532\n2 27\n2 47\n1 24 107\n1 20 720\n1 21 315\n2 20\n1 2 787\n1 27 532\n2 38\n1 32 445\n1 38 17\n1 26 450\n2 40\n1 45 192",
"output": "0\n0\n29\n0\n0\n0\n93\n34\n75"
},
{
"input": "1\n1\n1\n2 1",
"output": "0"
}
] | 1,690,531,754
| 2,147,483,647
|
PyPy 3-64
|
TIME_LIMIT_EXCEEDED
|
TESTS
| 39
| 2,000
| 28,057,600
|
class UnionSet:
def __init__(self,n):
self.val=list(range(n+1))
def find(self,x):
tmp=x
while x!=self.val[x]:
x=self.val[x]
self.val[x]=self.val[self.val[x]]
x=self.val[x]
return self.val[x]
def merge(self,x,y):
xz=self.find(x);yz=self.find(y)
self.val[xz]=yz
pyin=lambda:map(int,input().split())
n=int(input());v1=list(pyin())
m=int(input());v2=[0]*(n+1)
US=UnionSet(n)
for _ in range(m):
arr=list(pyin());t=arr[0]
if t==2:
print(v2[arr[1]])
elif t==1:
i,ad=US.find(arr[1]),arr[2]
while i<=n and ad!=0:
if v2[i]+ad<=v1[i-1]:
v2[i]+=ad;break
ad-=v1[i-1]-v2[i];v2[i]=v1[i-1]
US.merge(i,min(i+1,n));i+=1
|
Title: Vessels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a system of *n* vessels arranged one above the other as shown in the figure below. Assume that the vessels are numbered from 1 to *n*, in the order from the highest to the lowest, the volume of the *i*-th vessel is *a**i* liters.
Initially, all the vessels are empty. In some vessels water is poured. All the water that overflows from the *i*-th vessel goes to the (*i*<=+<=1)-th one. The liquid that overflows from the *n*-th vessel spills on the floor.
Your task is to simulate pouring water into the vessels. To do this, you will need to handle two types of queries:
1. Add *x**i* liters of water to the *p**i*-th vessel; 1. Print the number of liters of water in the *k**i*-th vessel.
When you reply to the second request you can assume that all the water poured up to this point, has already overflown between the vessels.
Input Specification:
The first line contains integer *n* — the number of vessels (1<=≤<=*n*<=≤<=2·105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* — the vessels' capacities (1<=≤<=*a**i*<=≤<=109). The vessels' capacities do not necessarily increase from the top vessels to the bottom ones (see the second sample). The third line contains integer *m* — the number of queries (1<=≤<=*m*<=≤<=2·105). Each of the next *m* lines contains the description of one query. The query of the first type is represented as "1 *p**i* *x**i*", the query of the second type is represented as "2 *k**i*" (1<=≤<=*p**i*<=≤<=*n*, 1<=≤<=*x**i*<=≤<=109, 1<=≤<=*k**i*<=≤<=*n*).
Output Specification:
For each query, print on a single line the number of liters of water in the corresponding vessel.
Demo Input:
['2\n5 10\n6\n1 1 4\n2 1\n1 2 5\n1 1 4\n2 1\n2 2\n', '3\n5 10 8\n6\n1 1 12\n2 2\n1 1 6\n1 3 2\n2 2\n2 3\n']
Demo Output:
['4\n5\n8\n', '7\n10\n5\n']
Note:
none
|
```python
class UnionSet:
def __init__(self,n):
self.val=list(range(n+1))
def find(self,x):
tmp=x
while x!=self.val[x]:
x=self.val[x]
self.val[x]=self.val[self.val[x]]
x=self.val[x]
return self.val[x]
def merge(self,x,y):
xz=self.find(x);yz=self.find(y)
self.val[xz]=yz
pyin=lambda:map(int,input().split())
n=int(input());v1=list(pyin())
m=int(input());v2=[0]*(n+1)
US=UnionSet(n)
for _ in range(m):
arr=list(pyin());t=arr[0]
if t==2:
print(v2[arr[1]])
elif t==1:
i,ad=US.find(arr[1]),arr[2]
while i<=n and ad!=0:
if v2[i]+ad<=v1[i-1]:
v2[i]+=ad;break
ad-=v1[i-1]-v2[i];v2[i]=v1[i-1]
US.merge(i,min(i+1,n));i+=1
```
| 0
|
|
870
|
C
|
Maximum splitting
|
PROGRAMMING
| 1,300
|
[
"dp",
"greedy",
"math",
"number theory"
] | null | null |
You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, if there are no such splittings.
An integer greater than 1 is composite, if it is not prime, i.e. if it has positive divisors not equal to 1 and the integer itself.
|
The first line contains single integer *q* (1<=≤<=*q*<=≤<=105) — the number of queries.
*q* lines follow. The (*i*<=+<=1)-th line contains single integer *n**i* (1<=≤<=*n**i*<=≤<=109) — the *i*-th query.
|
For each query print the maximum possible number of summands in a valid splitting to composite summands, or -1, if there are no such splittings.
|
[
"1\n12\n",
"2\n6\n8\n",
"3\n1\n2\n3\n"
] |
[
"3\n",
"1\n2\n",
"-1\n-1\n-1\n"
] |
12 = 4 + 4 + 4 = 4 + 8 = 6 + 6 = 12, but the first splitting has the maximum possible number of summands.
8 = 4 + 4, 6 can't be split into several composite summands.
1, 2, 3 are less than any composite number, so they do not have valid splittings.
| 1,500
|
[
{
"input": "1\n12",
"output": "3"
},
{
"input": "2\n6\n8",
"output": "1\n2"
},
{
"input": "3\n1\n2\n3",
"output": "-1\n-1\n-1"
},
{
"input": "6\n1\n2\n3\n5\n7\n11",
"output": "-1\n-1\n-1\n-1\n-1\n-1"
},
{
"input": "3\n4\n6\n9",
"output": "1\n1\n1"
},
{
"input": "20\n8\n13\n20\n12\n9\n16\n4\n19\n7\n15\n10\n6\n14\n11\n3\n2\n5\n17\n18\n1",
"output": "2\n2\n5\n3\n1\n4\n1\n3\n-1\n2\n2\n1\n3\n-1\n-1\n-1\n-1\n3\n4\n-1"
},
{
"input": "100\n611\n513\n544\n463\n38\n778\n347\n317\n848\n664\n382\n108\n718\n33\n334\n876\n234\n22\n944\n305\n159\n245\n513\n691\n639\n135\n308\n324\n813\n459\n304\n116\n331\n993\n184\n224\n853\n769\n121\n687\n93\n930\n751\n308\n485\n914\n400\n695\n95\n981\n175\n972\n121\n654\n242\n610\n617\n999\n237\n548\n742\n767\n613\n172\n223\n391\n102\n907\n673\n116\n230\n355\n189\n552\n399\n493\n903\n201\n985\n459\n776\n641\n693\n919\n253\n540\n427\n394\n655\n101\n461\n854\n417\n249\n66\n380\n213\n906\n212\n528",
"output": "151\n127\n136\n114\n9\n194\n85\n78\n212\n166\n95\n27\n179\n7\n83\n219\n58\n5\n236\n75\n38\n60\n127\n171\n158\n32\n77\n81\n202\n113\n76\n29\n81\n247\n46\n56\n212\n191\n29\n170\n22\n232\n186\n77\n120\n228\n100\n172\n22\n244\n42\n243\n29\n163\n60\n152\n153\n248\n58\n137\n185\n190\n152\n43\n54\n96\n25\n225\n167\n29\n57\n87\n46\n138\n98\n122\n224\n49\n245\n113\n194\n159\n172\n228\n62\n135\n105\n98\n162\n24\n114\n213\n103\n61\n16\n95\n52\n226\n53\n132"
},
{
"input": "1\n10000001",
"output": "2499999"
}
] | 1,541,933,648
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 5
| 108
| 0
|
H = [0, 0, 0, 0, 1, 0, 1, 0, 2, 1, 2, 0, 3, 0, 3, 2]
q = int(input())
for i in range(q):
n = int(input())
if n <= 15:
if H[n] == 0:
print(-1)
else:
print(H[n])
else:
c_4 = 0
while n > 15:
n -= 4
c_4 += 1
while n > 0 and H[n] == 0:
n -= 4
c_4 += 1
if n < 0:
print(-1)
else:
print(H[n] + c_4)
|
Title: Maximum splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, if there are no such splittings.
An integer greater than 1 is composite, if it is not prime, i.e. if it has positive divisors not equal to 1 and the integer itself.
Input Specification:
The first line contains single integer *q* (1<=≤<=*q*<=≤<=105) — the number of queries.
*q* lines follow. The (*i*<=+<=1)-th line contains single integer *n**i* (1<=≤<=*n**i*<=≤<=109) — the *i*-th query.
Output Specification:
For each query print the maximum possible number of summands in a valid splitting to composite summands, or -1, if there are no such splittings.
Demo Input:
['1\n12\n', '2\n6\n8\n', '3\n1\n2\n3\n']
Demo Output:
['3\n', '1\n2\n', '-1\n-1\n-1\n']
Note:
12 = 4 + 4 + 4 = 4 + 8 = 6 + 6 = 12, but the first splitting has the maximum possible number of summands.
8 = 4 + 4, 6 can't be split into several composite summands.
1, 2, 3 are less than any composite number, so they do not have valid splittings.
|
```python
H = [0, 0, 0, 0, 1, 0, 1, 0, 2, 1, 2, 0, 3, 0, 3, 2]
q = int(input())
for i in range(q):
n = int(input())
if n <= 15:
if H[n] == 0:
print(-1)
else:
print(H[n])
else:
c_4 = 0
while n > 15:
n -= 4
c_4 += 1
while n > 0 and H[n] == 0:
n -= 4
c_4 += 1
if n < 0:
print(-1)
else:
print(H[n] + c_4)
```
| 0
|
|
909
|
C
|
Python Indentation
|
PROGRAMMING
| 1,800
|
[
"dp"
] | null | null |
In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python with only two types of statements.
Simple statements are written in a single line, one per line. An example of a simple statement is assignment.
For statements are compound statements: they contain one or several other statements. For statement consists of a header written in a separate line which starts with "for" prefix, and loop body. Loop body is a block of statements indented one level further than the header of the loop. Loop body can contain both types of statements. Loop body can't be empty.
You are given a sequence of statements without indentation. Find the number of ways in which the statements can be indented to form a valid Python program.
|
The first line contains a single integer *N* (1<=≤<=*N*<=≤<=5000) — the number of commands in the program. *N* lines of the program follow, each line describing a single command. Each command is either "f" (denoting "for statement") or "s" ("simple statement"). It is guaranteed that the last line is a simple statement.
|
Output one line containing an integer - the number of ways the given sequence of statements can be indented modulo 109<=+<=7.
|
[
"4\ns\nf\nf\ns\n",
"4\nf\ns\nf\ns\n"
] |
[
"1\n",
"2\n"
] |
In the first test case, there is only one way to indent the program: the second for statement must be part of the body of the first one.
In the second test case, there are two ways to indent the program: the second for statement can either be part of the first one's body or a separate statement following the first one.
or
| 1,500
|
[
{
"input": "4\ns\nf\nf\ns",
"output": "1"
},
{
"input": "4\nf\ns\nf\ns",
"output": "2"
},
{
"input": "156\nf\ns\nf\ns\nf\ns\ns\ns\ns\nf\ns\ns\nf\nf\ns\nf\nf\nf\nf\ns\ns\ns\nf\ns\ns\nf\nf\nf\nf\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\nf\nf\nf\ns\ns\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\ns\ns\ns\nf\ns\ns\nf\ns\nf\nf\ns\ns\ns\nf\nf\nf\nf\ns\ns\nf\nf\nf\nf\nf\nf\nf\ns\nf\ns\ns\ns\nf\nf\ns\ns\ns\ns\ns\nf\nf\nf\nf\ns\nf\nf\ns\nf\ns\ns\nf\nf\nf\ns\ns\ns\nf\ns\ns\nf\ns\nf\nf\nf\ns\nf\nf\ns\ns\nf\ns\nf\nf\ns\ns\ns\ns\nf\ns\nf\nf\ns\ns\nf\nf\nf\ns\ns\nf\nf\nf\ns\nf\ns\nf\nf\ns",
"output": "666443222"
},
{
"input": "4\nf\nf\ns\ns",
"output": "3"
},
{
"input": "2\nf\ns",
"output": "1"
},
{
"input": "1\ns",
"output": "1"
},
{
"input": "3\nf\nf\ns",
"output": "1"
},
{
"input": "2\ns\ns",
"output": "1"
},
{
"input": "156\ns\nf\ns\ns\ns\ns\nf\ns\ns\ns\nf\nf\ns\nf\nf\ns\nf\nf\nf\ns\nf\nf\ns\nf\nf\ns\ns\nf\nf\ns\nf\nf\nf\nf\nf\ns\ns\nf\ns\nf\nf\nf\ns\nf\nf\nf\ns\ns\ns\nf\ns\ns\nf\nf\ns\ns\nf\ns\nf\nf\ns\nf\nf\nf\ns\ns\nf\nf\ns\nf\ns\ns\ns\ns\ns\ns\ns\nf\ns\nf\nf\nf\ns\ns\ns\ns\nf\nf\ns\nf\nf\ns\ns\nf\ns\nf\ns\ns\nf\nf\nf\nf\nf\ns\nf\ns\ns\nf\nf\ns\nf\nf\ns\ns\ns\nf\ns\ns\ns\ns\nf\nf\ns\nf\nf\nf\nf\ns\nf\ns\ns\nf\nf\ns\nf\ns\nf\nf\nf\nf\ns\ns\nf\nf\nf\nf\ns\nf\ns\nf\ns\ns\ns\nf\nf\ns",
"output": "479461584"
},
{
"input": "66\ns\nf\ns\ns\nf\ns\ns\ns\ns\nf\ns\ns\nf\nf\ns\ns\nf\ns\ns\nf\ns\ns\nf\nf\ns\ns\nf\nf\ns\ns\nf\ns\ns\ns\ns\nf\nf\ns\ns\nf\nf\ns\ns\nf\ns\ns\nf\ns\ns\nf\ns\ns\nf\nf\ns\nf\ns\ns\nf\nf\ns\nf\ns\nf\nf\ns",
"output": "392847498"
}
] | 1,634,044,345
| 2,147,483,647
|
Python 3
|
TIME_LIMIT_EXCEEDED
|
TESTS
| 4
| 2,000
| 141,107,200
|
n=int(input())
f=0
mod=10**9+7
s=[]
dp=[[0]*5010 for p in range(5010)]
for p in range(n):
s.append(input())
if s[-1][0] == 'f':
f += 1
sum=[0]*5010
dp[0][0]=1
for i in range(1, n):
#print(s[i-1])
if s[i-1][0] == "f":
#print('xsxs')
for j in range(1, f+1):
dp[i][j]=dp[i-1][j-1]
else:
j=f
ss = 0
while j >= 0:
ss += dp[i-1][j]
dp[i][j]=ss
j -= 1
ans=0
for i in range(f+1):
ans += dp[n-1][i]
print(ans%mod)
|
Title: Python Indentation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python with only two types of statements.
Simple statements are written in a single line, one per line. An example of a simple statement is assignment.
For statements are compound statements: they contain one or several other statements. For statement consists of a header written in a separate line which starts with "for" prefix, and loop body. Loop body is a block of statements indented one level further than the header of the loop. Loop body can contain both types of statements. Loop body can't be empty.
You are given a sequence of statements without indentation. Find the number of ways in which the statements can be indented to form a valid Python program.
Input Specification:
The first line contains a single integer *N* (1<=≤<=*N*<=≤<=5000) — the number of commands in the program. *N* lines of the program follow, each line describing a single command. Each command is either "f" (denoting "for statement") or "s" ("simple statement"). It is guaranteed that the last line is a simple statement.
Output Specification:
Output one line containing an integer - the number of ways the given sequence of statements can be indented modulo 109<=+<=7.
Demo Input:
['4\ns\nf\nf\ns\n', '4\nf\ns\nf\ns\n']
Demo Output:
['1\n', '2\n']
Note:
In the first test case, there is only one way to indent the program: the second for statement must be part of the body of the first one.
In the second test case, there are two ways to indent the program: the second for statement can either be part of the first one's body or a separate statement following the first one.
or
|
```python
n=int(input())
f=0
mod=10**9+7
s=[]
dp=[[0]*5010 for p in range(5010)]
for p in range(n):
s.append(input())
if s[-1][0] == 'f':
f += 1
sum=[0]*5010
dp[0][0]=1
for i in range(1, n):
#print(s[i-1])
if s[i-1][0] == "f":
#print('xsxs')
for j in range(1, f+1):
dp[i][j]=dp[i-1][j-1]
else:
j=f
ss = 0
while j >= 0:
ss += dp[i-1][j]
dp[i][j]=ss
j -= 1
ans=0
for i in range(f+1):
ans += dp[n-1][i]
print(ans%mod)
```
| 0
|
|
356
|
D
|
Bags and Coins
|
PROGRAMMING
| 2,700
|
[
"bitmasks",
"constructive algorithms",
"dp",
"greedy"
] | null | null |
When you were a child you must have been told a puzzle of bags and coins. Anyway, here's one of its versions:
A horse has three bags. The first bag has one coin, the second bag has one coin and the third bag has three coins. In total, the horse has three coins in the bags. How is that possible?
The answer is quite simple. The third bag contains a coin and two other bags.
This problem is a generalization of the childhood puzzle. You have *n* bags. You know that the first bag contains *a*1 coins, the second bag contains *a*2 coins, ..., the *n*-th bag contains *a**n* coins. In total, there are *s* coins. Find the way to arrange the bags and coins so that they match the described scenario or else state that it is impossible to do.
|
The first line contains two integers *n* and *s* (1<=≤<=*n*,<=*s*<=≤<=70000) — the number of bags and the total number of coins. The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=70000), where *a**i* shows the number of coins in the *i*-th bag.
|
If the answer doesn't exist, print -1.
Otherwise, print *n* lines, on the *i*-th line print the contents of the *i*-th bag. The first number in the line, *c**i* (0<=≤<=*c**i*<=≤<=*a**i*), must represent the number of coins lying directly in the *i*-th bag (the coins in the bags that are in the *i*-th bag are not taken into consideration). The second number in the line, *k**i* (0<=≤<=*k**i*<=<<=*n*) must represent the number of bags that lie directly in the *i*-th bag (the bags that are inside the bags lying in the *i*-th bag are not taken into consideration). Next, the line must contain *k**i* integers — the numbers of the bags that are lying directly in the *i*-th bag.
The total number of coins in the solution must equal *s*. If we count the total number of coins the *i*-th bag in the solution has, we should get *a**i*.
No bag can directly lie in more than one bag. The bags can be nested in more than one level (see the second test case). If there are multiple correct answers, you can print any of them.
|
[
"3 3\n1 3 1\n",
"3 3\n1 3 1\n",
"1 2\n1\n",
"8 10\n2 7 3 4 1 3 1 2\n"
] |
[
"1 0\n1 2 3 1\n1 0\n",
"1 0\n2 1 3\n0 1 1\n",
"-1\n",
"2 0\n1 2 1 4\n0 2 7 8\n0 2 5 6\n1 0\n3 0\n1 0\n2 0\n"
] |
The pictures below show two possible ways to solve one test case from the statement. The left picture corresponds to the first test case, the right picture corresponds to the second one.
| 2,000
|
[] | 1,689,604,106
| 2,147,483,647
|
PyPy 3-64
|
WRONG_ANSWER
|
TESTS
| 0
| 30
| 0
|
print("_RANDOM_GUESS_1689604106.734583")# 1689604106.7346056
|
Title: Bags and Coins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When you were a child you must have been told a puzzle of bags and coins. Anyway, here's one of its versions:
A horse has three bags. The first bag has one coin, the second bag has one coin and the third bag has three coins. In total, the horse has three coins in the bags. How is that possible?
The answer is quite simple. The third bag contains a coin and two other bags.
This problem is a generalization of the childhood puzzle. You have *n* bags. You know that the first bag contains *a*1 coins, the second bag contains *a*2 coins, ..., the *n*-th bag contains *a**n* coins. In total, there are *s* coins. Find the way to arrange the bags and coins so that they match the described scenario or else state that it is impossible to do.
Input Specification:
The first line contains two integers *n* and *s* (1<=≤<=*n*,<=*s*<=≤<=70000) — the number of bags and the total number of coins. The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=70000), where *a**i* shows the number of coins in the *i*-th bag.
Output Specification:
If the answer doesn't exist, print -1.
Otherwise, print *n* lines, on the *i*-th line print the contents of the *i*-th bag. The first number in the line, *c**i* (0<=≤<=*c**i*<=≤<=*a**i*), must represent the number of coins lying directly in the *i*-th bag (the coins in the bags that are in the *i*-th bag are not taken into consideration). The second number in the line, *k**i* (0<=≤<=*k**i*<=<<=*n*) must represent the number of bags that lie directly in the *i*-th bag (the bags that are inside the bags lying in the *i*-th bag are not taken into consideration). Next, the line must contain *k**i* integers — the numbers of the bags that are lying directly in the *i*-th bag.
The total number of coins in the solution must equal *s*. If we count the total number of coins the *i*-th bag in the solution has, we should get *a**i*.
No bag can directly lie in more than one bag. The bags can be nested in more than one level (see the second test case). If there are multiple correct answers, you can print any of them.
Demo Input:
['3 3\n1 3 1\n', '3 3\n1 3 1\n', '1 2\n1\n', '8 10\n2 7 3 4 1 3 1 2\n']
Demo Output:
['1 0\n1 2 3 1\n1 0\n', '1 0\n2 1 3\n0 1 1\n', '-1\n', '2 0\n1 2 1 4\n0 2 7 8\n0 2 5 6\n1 0\n3 0\n1 0\n2 0\n']
Note:
The pictures below show two possible ways to solve one test case from the statement. The left picture corresponds to the first test case, the right picture corresponds to the second one.
|
```python
print("_RANDOM_GUESS_1689604106.734583")# 1689604106.7346056
```
| 0
|
|
13
|
A
|
Numbers
|
PROGRAMMING
| 1,000
|
[
"implementation",
"math"
] |
A. Numbers
|
1
|
64
|
Little Petya likes numbers a lot. He found that number 123 in base 16 consists of two digits: the first is 7 and the second is 11. So the sum of digits of 123 in base 16 is equal to 18.
Now he wonders what is an average value of sum of digits of the number *A* written in all bases from 2 to *A*<=-<=1.
Note that all computations should be done in base 10. You should find the result as an irreducible fraction, written in base 10.
|
Input contains one integer number *A* (3<=≤<=*A*<=≤<=1000).
|
Output should contain required average value in format «X/Y», where X is the numerator and Y is the denominator.
|
[
"5\n",
"3\n"
] |
[
"7/3\n",
"2/1\n"
] |
In the first sample number 5 written in all bases from 2 to 4 looks so: 101, 12, 11. Sums of digits are 2, 3 and 2, respectively.
| 0
|
[
{
"input": "5",
"output": "7/3"
},
{
"input": "3",
"output": "2/1"
},
{
"input": "1000",
"output": "90132/499"
},
{
"input": "927",
"output": "155449/925"
},
{
"input": "260",
"output": "6265/129"
},
{
"input": "131",
"output": "3370/129"
},
{
"input": "386",
"output": "857/12"
},
{
"input": "277",
"output": "2864/55"
},
{
"input": "766",
"output": "53217/382"
},
{
"input": "28",
"output": "85/13"
},
{
"input": "406",
"output": "7560/101"
},
{
"input": "757",
"output": "103847/755"
},
{
"input": "6",
"output": "9/4"
},
{
"input": "239",
"output": "10885/237"
},
{
"input": "322",
"output": "2399/40"
},
{
"input": "98",
"output": "317/16"
},
{
"input": "208",
"output": "4063/103"
},
{
"input": "786",
"output": "55777/392"
},
{
"input": "879",
"output": "140290/877"
},
{
"input": "702",
"output": "89217/700"
},
{
"input": "948",
"output": "7369/43"
},
{
"input": "537",
"output": "52753/535"
},
{
"input": "984",
"output": "174589/982"
},
{
"input": "934",
"output": "157951/932"
},
{
"input": "726",
"output": "95491/724"
},
{
"input": "127",
"output": "3154/125"
},
{
"input": "504",
"output": "23086/251"
},
{
"input": "125",
"output": "3080/123"
},
{
"input": "604",
"output": "33178/301"
},
{
"input": "115",
"output": "2600/113"
},
{
"input": "27",
"output": "167/25"
},
{
"input": "687",
"output": "85854/685"
},
{
"input": "880",
"output": "69915/439"
},
{
"input": "173",
"output": "640/19"
},
{
"input": "264",
"output": "6438/131"
},
{
"input": "785",
"output": "111560/783"
},
{
"input": "399",
"output": "29399/397"
},
{
"input": "514",
"output": "6031/64"
},
{
"input": "381",
"output": "26717/379"
},
{
"input": "592",
"output": "63769/590"
},
{
"input": "417",
"output": "32002/415"
},
{
"input": "588",
"output": "62723/586"
},
{
"input": "852",
"output": "131069/850"
},
{
"input": "959",
"output": "5059/29"
},
{
"input": "841",
"output": "127737/839"
},
{
"input": "733",
"output": "97598/731"
},
{
"input": "692",
"output": "87017/690"
},
{
"input": "69",
"output": "983/67"
},
{
"input": "223",
"output": "556/13"
},
{
"input": "93",
"output": "246/13"
},
{
"input": "643",
"output": "75503/641"
},
{
"input": "119",
"output": "2833/117"
},
{
"input": "498",
"output": "1459/16"
},
{
"input": "155",
"output": "4637/153"
},
{
"input": "305",
"output": "17350/303"
},
{
"input": "454",
"output": "37893/452"
},
{
"input": "88",
"output": "1529/86"
},
{
"input": "850",
"output": "32645/212"
},
{
"input": "474",
"output": "20581/236"
},
{
"input": "309",
"output": "17731/307"
},
{
"input": "762",
"output": "105083/760"
},
{
"input": "591",
"output": "63761/589"
},
{
"input": "457",
"output": "38317/455"
},
{
"input": "141",
"output": "3832/139"
},
{
"input": "385",
"output": "27232/383"
},
{
"input": "387",
"output": "27628/385"
},
{
"input": "469",
"output": "40306/467"
},
{
"input": "624",
"output": "35285/311"
},
{
"input": "330",
"output": "487/8"
},
{
"input": "31",
"output": "222/29"
},
{
"input": "975",
"output": "171679/973"
},
{
"input": "584",
"output": "62183/582"
},
{
"input": "668",
"output": "81127/666"
},
{
"input": "331",
"output": "20297/329"
},
{
"input": "189",
"output": "6789/187"
},
{
"input": "251",
"output": "11939/249"
},
{
"input": "876",
"output": "69196/437"
},
{
"input": "615",
"output": "68987/613"
},
{
"input": "451",
"output": "37258/449"
},
{
"input": "499",
"output": "45727/497"
},
{
"input": "699",
"output": "89117/697"
},
{
"input": "619",
"output": "70019/617"
},
{
"input": "413",
"output": "10515/137"
},
{
"input": "197",
"output": "7399/195"
},
{
"input": "794",
"output": "14281/99"
},
{
"input": "659",
"output": "79403/657"
},
{
"input": "653",
"output": "77695/651"
},
{
"input": "23",
"output": "45/7"
},
{
"input": "430",
"output": "16985/214"
},
{
"input": "249",
"output": "11659/247"
},
{
"input": "837",
"output": "126869/835"
},
{
"input": "258",
"output": "12373/256"
},
{
"input": "995",
"output": "59665/331"
},
{
"input": "102",
"output": "504/25"
},
{
"input": "989",
"output": "177124/987"
},
{
"input": "376",
"output": "13008/187"
},
{
"input": "657",
"output": "15715/131"
},
{
"input": "746",
"output": "50509/372"
},
{
"input": "602",
"output": "13177/120"
}
] | 1,670,690,581
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 99
| 92
| 0
|
import math
a = int(input())
s = 0
for i in range(2, a):
tmpA = a
while tmpA != 0:
s = s + (tmpA % i)
tmpA = (tmpA // i)
d = math.gcd(s, a-2)
print(f"{s//d}/{(a-2)//d}")
|
Title: Numbers
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Little Petya likes numbers a lot. He found that number 123 in base 16 consists of two digits: the first is 7 and the second is 11. So the sum of digits of 123 in base 16 is equal to 18.
Now he wonders what is an average value of sum of digits of the number *A* written in all bases from 2 to *A*<=-<=1.
Note that all computations should be done in base 10. You should find the result as an irreducible fraction, written in base 10.
Input Specification:
Input contains one integer number *A* (3<=≤<=*A*<=≤<=1000).
Output Specification:
Output should contain required average value in format «X/Y», where X is the numerator and Y is the denominator.
Demo Input:
['5\n', '3\n']
Demo Output:
['7/3\n', '2/1\n']
Note:
In the first sample number 5 written in all bases from 2 to 4 looks so: 101, 12, 11. Sums of digits are 2, 3 and 2, respectively.
|
```python
import math
a = int(input())
s = 0
for i in range(2, a):
tmpA = a
while tmpA != 0:
s = s + (tmpA % i)
tmpA = (tmpA // i)
d = math.gcd(s, a-2)
print(f"{s//d}/{(a-2)//d}")
```
| 3.954
|
830
|
A
|
Office Keys
|
PROGRAMMING
| 1,800
|
[
"binary search",
"brute force",
"dp",
"greedy",
"sortings"
] | null | null |
There are *n* people and *k* keys on a straight line. Every person wants to get to the office which is located on the line as well. To do that, he needs to reach some point with a key, take the key and then go to the office. Once a key is taken by somebody, it couldn't be taken by anybody else.
You are to determine the minimum time needed for all *n* people to get to the office with keys. Assume that people move a unit distance per 1 second. If two people reach a key at the same time, only one of them can take the key. A person can pass through a point with a key without taking it.
|
The first line contains three integers *n*, *k* and *p* (1<=≤<=*n*<=≤<=1<=000, *n*<=≤<=*k*<=≤<=2<=000, 1<=≤<=*p*<=≤<=109) — the number of people, the number of keys and the office location.
The second line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — positions in which people are located initially. The positions are given in arbitrary order.
The third line contains *k* distinct integers *b*1,<=*b*2,<=...,<=*b**k* (1<=≤<=*b**j*<=≤<=109) — positions of the keys. The positions are given in arbitrary order.
Note that there can't be more than one person or more than one key in the same point. A person and a key can be located in the same point.
|
Print the minimum time (in seconds) needed for all *n* to reach the office with keys.
|
[
"2 4 50\n20 100\n60 10 40 80\n",
"1 2 10\n11\n15 7\n"
] |
[
"50\n",
"7\n"
] |
In the first example the person located at point 20 should take the key located at point 40 and go with it to the office located at point 50. He spends 30 seconds. The person located at point 100 can take the key located at point 80 and go to the office with it. He spends 50 seconds. Thus, after 50 seconds everybody is in office with keys.
| 500
|
[
{
"input": "2 4 50\n20 100\n60 10 40 80",
"output": "50"
},
{
"input": "1 2 10\n11\n15 7",
"output": "7"
},
{
"input": "2 5 15\n10 4\n29 23 21 22 26",
"output": "23"
},
{
"input": "3 10 1500\n106 160 129\n1333 1532 1181 1091 1656 1698 1291 1741 1242 1163",
"output": "1394"
},
{
"input": "5 20 1\n314 316 328 323 321\n30 61 11 83 19 63 97 87 14 79 43 57 75 48 47 95 41 27 8 88",
"output": "327"
},
{
"input": "20 20 1000000000\n911196469 574676950 884047241 984218701 641693148 352743122 616364857 455260052 702604347 921615943 671695009 544819698 768892858 254148055 379968391 65297129 178692403 575557323 307174510 63022600\n1621 106 6866 6420 9307 6985 2741 9477 9837 5909 6757 3085 6139 1876 3726 9334 4321 1531 8534 560",
"output": "1984199027"
},
{
"input": "40 45 1000\n6 55 34 32 20 76 2 84 47 68 31 60 14 70 99 72 21 61 81 79 26 51 96 86 10 1 43 69 87 78 13 11 80 67 50 52 9 29 94 12\n1974 1232 234 28 1456 626 408 1086 1525 1209 1096 940 795 1867 548 1774 1993 1199 1112 1087 1923 1156 876 1715 1815 1027 1658 955 398 910 620 1164 749 996 113 109 500 328 800 826 766 518 1474 1038 1029",
"output": "2449"
},
{
"input": "50 55 2000\n9518 9743 9338 9956 9827 9772 9094 9644 9242 9292 9148 9205 9907 9860 9530 9814 9662 9482 9725 9227 9105 9424 9268 9427 9470 9578 9808 9976 9143 9070 9079 9896 9367 9235 9925 9009 9619 9012 9669 9077 9870 9766 9479 9598 9055 9988 9792 9197 9377 9610\n828 656 345 412 69 506 274 994 384 766 587 126 720 227 66 839 997 602 646 955 256 262 243 676 459 83 507 88 559 595 71 154 867 276 487 895 857 888 368 179 813 407 973 780 588 112 815 290 554 230 768 804 974 3 745",
"output": "10833"
},
{
"input": "1 1 1\n1\n1000000000",
"output": "1999999998"
},
{
"input": "1 1 1\n1000000000\n1",
"output": "999999999"
},
{
"input": "1 1 1000000000\n1000000000\n1",
"output": "1999999998"
},
{
"input": "1 1 1000000000\n1\n1000000000",
"output": "999999999"
},
{
"input": "2 2 4\n3 4\n5 6",
"output": "4"
},
{
"input": "2 2 5\n1 2\n3 1000000000",
"output": "1999999993"
},
{
"input": "1 1 1000000000\n1000000000\n1",
"output": "1999999998"
},
{
"input": "2 2 1\n2 3\n4 100",
"output": "196"
},
{
"input": "2 2 10\n3 12\n1 9",
"output": "11"
},
{
"input": "3 3 1\n1 2 3\n999 1000000000 1",
"output": "1999999996"
},
{
"input": "1 1 1\n1\n1",
"output": "0"
},
{
"input": "1 1 1\n1\n1000000000",
"output": "1999999998"
},
{
"input": "1 1 1000000000\n1000000000\n10",
"output": "1999999980"
},
{
"input": "2 2 7122\n123 456\n1 4444",
"output": "7243"
},
{
"input": "1 1 10\n5\n15",
"output": "15"
},
{
"input": "2 4 1000\n1000 999\n1 1000 2 999",
"output": "1"
},
{
"input": "2 2 1000\n10 1010\n1 1001",
"output": "1008"
},
{
"input": "1 1 1\n2\n1000000000",
"output": "1999999997"
},
{
"input": "2 2 3\n1 5\n5 1",
"output": "2"
},
{
"input": "2 2 5\n2 3\n4 6",
"output": "4"
},
{
"input": "2 2 10\n5 6\n4 6",
"output": "7"
},
{
"input": "3 4 10\n5 7 9\n6 8 14 4",
"output": "7"
},
{
"input": "1 1 10\n10\n10",
"output": "0"
},
{
"input": "1 1 50\n1\n1000000000",
"output": "1999999949"
},
{
"input": "1 1 42\n666\n1337",
"output": "1966"
},
{
"input": "2 2 10\n9 11\n11 8",
"output": "3"
},
{
"input": "3 10 5\n1 2 3\n10000 9999 9998 9997 9996 9995 9994 7 6 5",
"output": "6"
},
{
"input": "1 1 2\n1\n1000000000",
"output": "1999999997"
},
{
"input": "2 2 100\n99 150\n1 150",
"output": "197"
},
{
"input": "3 3 4\n1 101 102\n2 3 100",
"output": "99"
}
] | 1,500,363,395
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 59
| 607
| 5,222,400
|
n, k, p = (int(x) for x in input().split())
a = sorted([int(x) for x in input().split()])
b = sorted([int(x) for x in input().split()])
time = min([max([abs(a[j] - b[i + j]) + abs(b[i + j] - p) for j in range(n)]) for i in range(k-n+1)])
print(time)
|
Title: Office Keys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* people and *k* keys on a straight line. Every person wants to get to the office which is located on the line as well. To do that, he needs to reach some point with a key, take the key and then go to the office. Once a key is taken by somebody, it couldn't be taken by anybody else.
You are to determine the minimum time needed for all *n* people to get to the office with keys. Assume that people move a unit distance per 1 second. If two people reach a key at the same time, only one of them can take the key. A person can pass through a point with a key without taking it.
Input Specification:
The first line contains three integers *n*, *k* and *p* (1<=≤<=*n*<=≤<=1<=000, *n*<=≤<=*k*<=≤<=2<=000, 1<=≤<=*p*<=≤<=109) — the number of people, the number of keys and the office location.
The second line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — positions in which people are located initially. The positions are given in arbitrary order.
The third line contains *k* distinct integers *b*1,<=*b*2,<=...,<=*b**k* (1<=≤<=*b**j*<=≤<=109) — positions of the keys. The positions are given in arbitrary order.
Note that there can't be more than one person or more than one key in the same point. A person and a key can be located in the same point.
Output Specification:
Print the minimum time (in seconds) needed for all *n* to reach the office with keys.
Demo Input:
['2 4 50\n20 100\n60 10 40 80\n', '1 2 10\n11\n15 7\n']
Demo Output:
['50\n', '7\n']
Note:
In the first example the person located at point 20 should take the key located at point 40 and go with it to the office located at point 50. He spends 30 seconds. The person located at point 100 can take the key located at point 80 and go to the office with it. He spends 50 seconds. Thus, after 50 seconds everybody is in office with keys.
|
```python
n, k, p = (int(x) for x in input().split())
a = sorted([int(x) for x in input().split()])
b = sorted([int(x) for x in input().split()])
time = min([max([abs(a[j] - b[i + j]) + abs(b[i + j] - p) for j in range(n)]) for i in range(k-n+1)])
print(time)
```
| 3
|
|
645
|
E
|
Intellectual Inquiry
|
PROGRAMMING
| 2,200
|
[
"dp",
"greedy",
"strings"
] | null | null |
After getting kicked out of her reporting job for not knowing the alphabet, Bessie has decided to attend school at the Fillet and Eggs Eater Academy. She has been making good progress with her studies and now knows the first *k* English letters.
Each morning, Bessie travels to school along a sidewalk consisting of *m*<=+<=*n* tiles. In order to help Bessie review, Mr. Moozing has labeled each of the first *m* sidewalk tiles with one of the first *k* lowercase English letters, spelling out a string *t*. Mr. Moozing, impressed by Bessie's extensive knowledge of farm animals, plans to let her finish labeling the last *n* tiles of the sidewalk by herself.
Consider the resulting string *s* (|*s*|<==<=*m*<=+<=*n*) consisting of letters labeled on tiles in order from home to school. For any sequence of indices *p*1<=<<=*p*2<=<<=...<=<<=*p**q* we can define subsequence of the string *s* as string *s**p*1*s**p*2... *s**p**q*. Two subsequences are considered to be distinct if they differ as strings. Bessie wants to label the remaining part of the sidewalk such that the number of distinct subsequences of tiles is maximum possible. However, since Bessie hasn't even finished learning the alphabet, she needs your help!
Note that empty subsequence also counts.
|
The first line of the input contains two integers *n* and *k* (0<=≤<=*n*<=≤<=1<=000<=000, 1<=≤<=*k*<=≤<=26).
The second line contains a string *t* (|*t*|<==<=*m*,<=1<=≤<=*m*<=≤<=1<=000<=000) consisting of only first *k* lowercase English letters.
|
Determine the maximum number of distinct subsequences Bessie can form after labeling the last *n* sidewalk tiles each with one of the first *k* lowercase English letters. Since this number can be rather large, you should print it modulo 109<=+<=7.
Please note, that you are not asked to maximize the remainder modulo 109<=+<=7! The goal is to maximize the initial value and then print the remainder.
|
[
"1 3\nac\n",
"0 2\naaba\n"
] |
[
"8\n",
"10\n"
] |
In the first sample, the optimal labeling gives 8 different subsequences: "" (the empty string), "a", "c", "b", "ac", "ab", "cb", and "acb".
In the second sample, the entire sidewalk is already labeled. The are 10 possible different subsequences: "" (the empty string), "a", "b", "aa", "ab", "ba", "aaa", "aab", "aba", and "aaba". Note that some strings, including "aa", can be obtained with multiple sequences of tiles, but are only counted once.
| 2,500
|
[] | 1,460,534,622
| 2,147,483,647
|
Python 3
|
TIME_LIMIT_EXCEEDED
|
TESTS
| 9
| 2,000
| 3,072,000
|
import operator
s = list(map(int,input().split()))
n = s[0]
k = s[1]
s = input()
base = 10 ** 9 + 7
start = ord('a')
substrings = [0 for i in range(k + 1)]
positions = [[i, 0] for i in range(k)]
heap = [[i, 0] for i in range(k)]
substrings[k] = 1
counter = 0
def Insert(heap, size, number, comparator = operator.lt):
heap[size] = number
i = size
while True:
if i == 0 or comparator(heap[(i + 1) // 2 - 1], heap[i]):
break
else:
heap[i], heap[(i + 1) // 2 - 1] = heap[(i + 1) // 2 - 1], heap[i]
i = (i + 1) // 2 - 1
def Extract(heap, size, comparator = operator.lt):
result = heap[0]
heap[0] = heap[size - 1]
size -= 1
i = 0
while True:
if (i + 1) * 2 - 1 > size:
break
else:
if comparator(heap[i], heap[(i + 1) * 2 - 1]):
if (i + 1) * 2 > size or comparator(heap[i], heap[(i + 1) * 2]):
break
else:
heap[i], heap[(i + 1) * 2] = heap[(i + 1) * 2], heap[i]
i = (i + 1) * 2
else:
if (i + 1) * 2 > size or comparator(heap[i], heap[(i + 1) * 2]):
heap[i], heap[(i + 1) * 2 - 1] = heap[(i + 1) * 2 - 1], heap[i]
i = (i + 1) * 2 - 1
else:
if comparator(heap[(i + 1) * 2 - 1], heap[(i + 1) * 2]):
heap[i], heap[(i + 1) * 2 - 1] = heap[(i + 1) * 2 - 1], heap[i]
i = (i + 1) * 2 - 1
else:
heap[i], heap[(i + 1) * 2] = heap[(i + 1) * 2], heap[i]
i = (i + 1) * 2
return result
for c in s:
num = ord(c) - start
new = substrings[k] - substrings[num]
substrings[num] = substrings[k]
substrings[k] += new
substrings[k] %= base
positions[num][1] = counter
counter += 1
for i in range(k):
Insert(heap, i, positions[i], lambda x, y: x[1] < y[1])
for i in range(k):
positions[i] = Extract(heap, k - i, lambda x, y: x[1] < y[1])
for i in range(n):
num_char = positions[i % k][0]
new = substrings[k] - substrings[num_char]
substrings[num_char] = substrings[k]
substrings[k] += new
substrings[k] %= base
print(substrings[k])
|
Title: Intellectual Inquiry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After getting kicked out of her reporting job for not knowing the alphabet, Bessie has decided to attend school at the Fillet and Eggs Eater Academy. She has been making good progress with her studies and now knows the first *k* English letters.
Each morning, Bessie travels to school along a sidewalk consisting of *m*<=+<=*n* tiles. In order to help Bessie review, Mr. Moozing has labeled each of the first *m* sidewalk tiles with one of the first *k* lowercase English letters, spelling out a string *t*. Mr. Moozing, impressed by Bessie's extensive knowledge of farm animals, plans to let her finish labeling the last *n* tiles of the sidewalk by herself.
Consider the resulting string *s* (|*s*|<==<=*m*<=+<=*n*) consisting of letters labeled on tiles in order from home to school. For any sequence of indices *p*1<=<<=*p*2<=<<=...<=<<=*p**q* we can define subsequence of the string *s* as string *s**p*1*s**p*2... *s**p**q*. Two subsequences are considered to be distinct if they differ as strings. Bessie wants to label the remaining part of the sidewalk such that the number of distinct subsequences of tiles is maximum possible. However, since Bessie hasn't even finished learning the alphabet, she needs your help!
Note that empty subsequence also counts.
Input Specification:
The first line of the input contains two integers *n* and *k* (0<=≤<=*n*<=≤<=1<=000<=000, 1<=≤<=*k*<=≤<=26).
The second line contains a string *t* (|*t*|<==<=*m*,<=1<=≤<=*m*<=≤<=1<=000<=000) consisting of only first *k* lowercase English letters.
Output Specification:
Determine the maximum number of distinct subsequences Bessie can form after labeling the last *n* sidewalk tiles each with one of the first *k* lowercase English letters. Since this number can be rather large, you should print it modulo 109<=+<=7.
Please note, that you are not asked to maximize the remainder modulo 109<=+<=7! The goal is to maximize the initial value and then print the remainder.
Demo Input:
['1 3\nac\n', '0 2\naaba\n']
Demo Output:
['8\n', '10\n']
Note:
In the first sample, the optimal labeling gives 8 different subsequences: "" (the empty string), "a", "c", "b", "ac", "ab", "cb", and "acb".
In the second sample, the entire sidewalk is already labeled. The are 10 possible different subsequences: "" (the empty string), "a", "b", "aa", "ab", "ba", "aaa", "aab", "aba", and "aaba". Note that some strings, including "aa", can be obtained with multiple sequences of tiles, but are only counted once.
|
```python
import operator
s = list(map(int,input().split()))
n = s[0]
k = s[1]
s = input()
base = 10 ** 9 + 7
start = ord('a')
substrings = [0 for i in range(k + 1)]
positions = [[i, 0] for i in range(k)]
heap = [[i, 0] for i in range(k)]
substrings[k] = 1
counter = 0
def Insert(heap, size, number, comparator = operator.lt):
heap[size] = number
i = size
while True:
if i == 0 or comparator(heap[(i + 1) // 2 - 1], heap[i]):
break
else:
heap[i], heap[(i + 1) // 2 - 1] = heap[(i + 1) // 2 - 1], heap[i]
i = (i + 1) // 2 - 1
def Extract(heap, size, comparator = operator.lt):
result = heap[0]
heap[0] = heap[size - 1]
size -= 1
i = 0
while True:
if (i + 1) * 2 - 1 > size:
break
else:
if comparator(heap[i], heap[(i + 1) * 2 - 1]):
if (i + 1) * 2 > size or comparator(heap[i], heap[(i + 1) * 2]):
break
else:
heap[i], heap[(i + 1) * 2] = heap[(i + 1) * 2], heap[i]
i = (i + 1) * 2
else:
if (i + 1) * 2 > size or comparator(heap[i], heap[(i + 1) * 2]):
heap[i], heap[(i + 1) * 2 - 1] = heap[(i + 1) * 2 - 1], heap[i]
i = (i + 1) * 2 - 1
else:
if comparator(heap[(i + 1) * 2 - 1], heap[(i + 1) * 2]):
heap[i], heap[(i + 1) * 2 - 1] = heap[(i + 1) * 2 - 1], heap[i]
i = (i + 1) * 2 - 1
else:
heap[i], heap[(i + 1) * 2] = heap[(i + 1) * 2], heap[i]
i = (i + 1) * 2
return result
for c in s:
num = ord(c) - start
new = substrings[k] - substrings[num]
substrings[num] = substrings[k]
substrings[k] += new
substrings[k] %= base
positions[num][1] = counter
counter += 1
for i in range(k):
Insert(heap, i, positions[i], lambda x, y: x[1] < y[1])
for i in range(k):
positions[i] = Extract(heap, k - i, lambda x, y: x[1] < y[1])
for i in range(n):
num_char = positions[i % k][0]
new = substrings[k] - substrings[num_char]
substrings[num_char] = substrings[k]
substrings[k] += new
substrings[k] %= base
print(substrings[k])
```
| 0
|
|
580
|
B
|
Kefa and Company
|
PROGRAMMING
| 1,500
|
[
"binary search",
"sortings",
"two pointers"
] | null | null |
Kefa wants to celebrate his first big salary by going to restaurant. However, he needs company.
Kefa has *n* friends, each friend will agree to go to the restaurant if Kefa asks. Each friend is characterized by the amount of money he has and the friendship factor in respect to Kefa. The parrot doesn't want any friend to feel poor compared to somebody else in the company (Kefa doesn't count). A friend feels poor if in the company there is someone who has at least *d* units of money more than he does. Also, Kefa wants the total friendship factor of the members of the company to be maximum. Help him invite an optimal company!
|
The first line of the input contains two space-separated integers, *n* and *d* (1<=≤<=*n*<=≤<=105, ) — the number of Kefa's friends and the minimum difference between the amount of money in order to feel poor, respectively.
Next *n* lines contain the descriptions of Kefa's friends, the (*i*<=+<=1)-th line contains the description of the *i*-th friend of type *m**i*, *s**i* (0<=≤<=*m**i*,<=*s**i*<=≤<=109) — the amount of money and the friendship factor, respectively.
|
Print the maximum total friendship factir that can be reached.
|
[
"4 5\n75 5\n0 100\n150 20\n75 1\n",
"5 100\n0 7\n11 32\n99 10\n46 8\n87 54\n"
] |
[
"100\n",
"111\n"
] |
In the first sample test the most profitable strategy is to form a company from only the second friend. At all other variants the total degree of friendship will be worse.
In the second sample test we can take all the friends.
| 1,250
|
[
{
"input": "4 5\n75 5\n0 100\n150 20\n75 1",
"output": "100"
},
{
"input": "5 100\n0 7\n11 32\n99 10\n46 8\n87 54",
"output": "111"
},
{
"input": "1 1000000000\n15 12",
"output": "12"
},
{
"input": "5 1\n5 9\n2 10\n8 5\n18 12\n1 1",
"output": "12"
},
{
"input": "3 3\n4 15\n0 17\n9 11",
"output": "17"
},
{
"input": "5 10\n8 90\n1009 1000000\n9 121\n10 298\n0 109092",
"output": "1000000"
},
{
"input": "5 9\n0 98\n2 1000000000\n8 1000000000\n5 999999999\n3 989898989",
"output": "3989899086"
},
{
"input": "4 2\n10909234 9\n10909236 8\n10909237 10\n10909235 98",
"output": "107"
},
{
"input": "3 1\n801 10101\n802 134509124\n801 1",
"output": "134509124"
},
{
"input": "4 1\n2 4\n2 2\n3 3\n3 3",
"output": "6"
},
{
"input": "8 5\n3 227589091\n12 131068951\n8 492784630\n20 918918112\n11 6972428\n20 585402296\n12 220234661\n1 225083234",
"output": "1504320408"
},
{
"input": "15 1234\n2738 322313356\n1160 970909702\n2594 902749351\n3126 324754476\n3151 177963947\n3424 396145897\n5578 737768323\n3423 687640543\n381 848813098\n1058 197211286\n936 650181776\n1025 776492538\n3598 142176544\n3595 680519527\n1191 32199940",
"output": "3634263641"
},
{
"input": "5 6\n5 11\n10 11\n11 11\n12 11\n100 1",
"output": "33"
},
{
"input": "7 6\n5 11\n9 11\n10 11\n11 11\n12 11\n13 11\n100 1",
"output": "55"
},
{
"input": "4 2\n1 1\n2 100\n3 100\n4 1",
"output": "200"
}
] | 1,695,918,421
| 2,147,483,647
|
PyPy 3-64
|
WRONG_ANSWER
|
TESTS
| 7
| 62
| 0
|
import sys
# sys.setrecursionlimit(100000)
input=lambda:sys.stdin.readline().strip()
# write=lambda x:sys.stdout.write(str(x)+'\n')
# from decimal import Decimal
# from datetime import datetime,timedelta
# from random import randint
# from copy import deepcopy
# from collections import deque,Counter
# from heapq import heapify,heappush,heappop
# from bisect import bisect_left,bisect,insort
# from math import inf,sqrt,gcd,pow,ceil,floor,log,log2,log10,pi,sin,cos,tan,asin,acos,atan
# from functools import cmp_to_key,reduce
# from operator import or_,xor,add,mul
# from itertools import permutations,combinations,accumulate
def solve():
n,d=map(int,input().split())
c=[]
for i in range(n):
m,s=map(int,input().split())
c.append([m,s])
c.sort()
# print(c)
l=0;r=0
ans=0
while l<n:
res=0
while r<n and c[l][0]+d>=c[r][0]:
res+=c[r][1]
r+=1
ans=max(ans,res)
l=r;r=l
print(ans)
# t=int(input())
# for _ in range(t):
# solve()
solve()
|
Title: Kefa and Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kefa wants to celebrate his first big salary by going to restaurant. However, he needs company.
Kefa has *n* friends, each friend will agree to go to the restaurant if Kefa asks. Each friend is characterized by the amount of money he has and the friendship factor in respect to Kefa. The parrot doesn't want any friend to feel poor compared to somebody else in the company (Kefa doesn't count). A friend feels poor if in the company there is someone who has at least *d* units of money more than he does. Also, Kefa wants the total friendship factor of the members of the company to be maximum. Help him invite an optimal company!
Input Specification:
The first line of the input contains two space-separated integers, *n* and *d* (1<=≤<=*n*<=≤<=105, ) — the number of Kefa's friends and the minimum difference between the amount of money in order to feel poor, respectively.
Next *n* lines contain the descriptions of Kefa's friends, the (*i*<=+<=1)-th line contains the description of the *i*-th friend of type *m**i*, *s**i* (0<=≤<=*m**i*,<=*s**i*<=≤<=109) — the amount of money and the friendship factor, respectively.
Output Specification:
Print the maximum total friendship factir that can be reached.
Demo Input:
['4 5\n75 5\n0 100\n150 20\n75 1\n', '5 100\n0 7\n11 32\n99 10\n46 8\n87 54\n']
Demo Output:
['100\n', '111\n']
Note:
In the first sample test the most profitable strategy is to form a company from only the second friend. At all other variants the total degree of friendship will be worse.
In the second sample test we can take all the friends.
|
```python
import sys
# sys.setrecursionlimit(100000)
input=lambda:sys.stdin.readline().strip()
# write=lambda x:sys.stdout.write(str(x)+'\n')
# from decimal import Decimal
# from datetime import datetime,timedelta
# from random import randint
# from copy import deepcopy
# from collections import deque,Counter
# from heapq import heapify,heappush,heappop
# from bisect import bisect_left,bisect,insort
# from math import inf,sqrt,gcd,pow,ceil,floor,log,log2,log10,pi,sin,cos,tan,asin,acos,atan
# from functools import cmp_to_key,reduce
# from operator import or_,xor,add,mul
# from itertools import permutations,combinations,accumulate
def solve():
n,d=map(int,input().split())
c=[]
for i in range(n):
m,s=map(int,input().split())
c.append([m,s])
c.sort()
# print(c)
l=0;r=0
ans=0
while l<n:
res=0
while r<n and c[l][0]+d>=c[r][0]:
res+=c[r][1]
r+=1
ans=max(ans,res)
l=r;r=l
print(ans)
# t=int(input())
# for _ in range(t):
# solve()
solve()
```
| 0
|
|
439
|
A
|
Devu, the Singer and Churu, the Joker
|
PROGRAMMING
| 900
|
[
"greedy",
"implementation"
] | null | null |
Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited.
Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* song will take *t**i* minutes exactly.
The Comedian, Churu will crack jokes. All his jokes are of 5 minutes exactly.
People have mainly come to listen Devu. But you know that he needs rest of 10 minutes after each song. On the other hand, Churu being a very active person, doesn't need any rest.
You as one of the organizers should make an optimal sсhedule for the event. For some reasons you must follow the conditions:
- The duration of the event must be no more than *d* minutes; - Devu must complete all his songs; - With satisfying the two previous conditions the number of jokes cracked by Churu should be as many as possible.
If it is not possible to find a way to conduct all the songs of the Devu, output -1. Otherwise find out maximum number of jokes that Churu can crack in the grand event.
|
The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100).
|
If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event.
|
[
"3 30\n2 2 1\n",
"3 20\n2 1 1\n"
] |
[
"5\n",
"-1\n"
] |
Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way:
- First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now finally Devu will perform his last song in 1 minutes.
Total time spent is 5 + 2 + 10 + 2 + 10 + 1 = 30 minutes.
Consider the second example. There is no way of organizing Devu's all songs. Hence the answer is -1.
| 500
|
[
{
"input": "3 30\n2 2 1",
"output": "5"
},
{
"input": "3 20\n2 1 1",
"output": "-1"
},
{
"input": "50 10000\n5 4 10 9 9 6 7 7 7 3 3 7 7 4 7 4 10 10 1 7 10 3 1 4 5 7 2 10 10 10 2 3 4 7 6 1 8 4 7 3 8 8 4 10 1 1 9 2 6 1",
"output": "1943"
},
{
"input": "50 10000\n4 7 15 9 11 12 20 9 14 14 10 13 6 13 14 17 6 8 20 12 10 15 13 17 5 12 13 11 7 5 5 2 3 15 13 7 14 14 19 2 13 14 5 15 3 19 15 16 4 1",
"output": "1891"
},
{
"input": "100 9000\n5 2 3 1 1 3 4 9 9 6 7 10 10 10 2 10 6 8 8 6 7 9 9 5 6 2 1 10 10 9 4 5 9 2 4 3 8 5 6 1 1 5 3 6 2 6 6 6 5 8 3 6 7 3 1 10 9 1 8 3 10 9 5 6 3 4 1 1 10 10 2 3 4 8 10 10 5 1 5 3 6 8 10 6 10 2 1 8 10 1 7 6 9 10 5 2 3 5 3 2",
"output": "1688"
},
{
"input": "100 8007\n5 19 14 18 9 6 15 8 1 14 11 20 3 17 7 12 2 6 3 17 7 20 1 14 20 17 2 10 13 7 18 18 9 10 16 8 1 11 11 9 13 18 9 20 12 12 7 15 12 17 11 5 11 15 9 2 15 1 18 3 18 16 15 4 10 5 18 13 13 12 3 8 17 2 12 2 13 3 1 13 2 4 9 10 18 10 14 4 4 17 12 19 2 9 6 5 5 20 18 12",
"output": "1391"
},
{
"input": "39 2412\n1 1 1 1 1 1 26 1 1 1 99 1 1 1 1 1 1 1 1 1 1 88 7 1 1 1 1 76 1 1 1 93 40 1 13 1 68 1 32",
"output": "368"
},
{
"input": "39 2617\n47 1 1 1 63 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 70 1 99 63 1 1 1 1 1 1 1 1 64 1 1",
"output": "435"
},
{
"input": "39 3681\n83 77 1 94 85 47 1 98 29 16 1 1 1 71 96 85 31 97 96 93 40 50 98 1 60 51 1 96 100 72 1 1 1 89 1 93 1 92 100",
"output": "326"
},
{
"input": "45 894\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 28 28 1 1 1 1 1 1 1 1 1 1 1 1 1 1 99 3 1 1",
"output": "139"
},
{
"input": "45 4534\n1 99 65 99 4 46 54 80 51 30 96 1 28 30 44 70 78 1 1 100 1 62 1 1 1 85 1 1 1 61 1 46 75 1 61 77 97 26 67 1 1 63 81 85 86",
"output": "514"
},
{
"input": "72 3538\n52 1 8 1 1 1 7 1 1 1 1 48 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 40 1 1 38 1 1 1 1 1 1 1 1 1 1 1 35 1 93 79 1 1 1 1 1 1 1 1 1 51 1 1 1 1 1 1 1 1 1 1 1 1 96 1",
"output": "586"
},
{
"input": "81 2200\n1 59 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 93 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 50 1 1 1 1 1 1 1 1 1 1 1",
"output": "384"
},
{
"input": "81 2577\n85 91 1 1 2 1 1 100 1 80 1 1 17 86 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 37 1 66 24 1 1 96 49 1 66 1 44 1 1 1 1 98 1 1 1 1 35 1 37 3 35 1 1 87 64 1 24 1 58 1 1 42 83 5 1 1 1 1 1 95 1 94 1 50 1 1",
"output": "174"
},
{
"input": "81 4131\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 16 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "807"
},
{
"input": "81 6315\n1 1 67 100 1 99 36 1 92 5 1 96 42 12 1 57 91 1 1 66 41 30 74 95 1 37 1 39 91 69 1 52 77 47 65 1 1 93 96 74 90 35 85 76 71 92 92 1 1 67 92 74 1 1 86 76 35 1 56 16 27 57 37 95 1 40 20 100 51 1 80 60 45 79 95 1 46 1 25 100 96",
"output": "490"
},
{
"input": "96 1688\n1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 45 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 25 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 71 1 1 1 30 1 1 1",
"output": "284"
},
{
"input": "96 8889\n1 1 18 1 1 1 1 1 1 1 1 1 99 1 1 1 1 88 1 45 1 1 1 1 1 1 1 1 1 1 1 1 1 1 96 1 1 1 1 21 1 1 1 1 1 1 1 73 1 1 1 1 1 10 1 1 1 1 1 1 1 46 43 1 1 1 1 1 98 1 1 1 1 1 1 6 1 1 1 1 1 74 1 25 1 55 1 1 1 13 1 1 54 1 1 1",
"output": "1589"
},
{
"input": "10 100\n1 1 1 1 1 1 1 1 1 1",
"output": "18"
},
{
"input": "100 10000\n54 46 72 94 79 83 91 54 73 3 24 55 54 31 28 20 19 6 25 19 47 23 1 70 15 87 51 39 54 77 55 5 60 3 15 99 56 88 22 78 79 21 38 27 28 86 7 88 12 59 55 70 25 1 70 49 1 45 69 72 50 17 4 56 8 100 90 34 35 20 61 76 88 79 4 74 65 68 75 26 40 72 59 94 10 67 96 85 29 90 47 24 44 1 66 93 55 36 1 99",
"output": "1017"
},
{
"input": "100 6000\n41 31 23 17 24 78 26 96 93 48 46 2 49 33 35 9 73 100 34 48 83 36 33 69 43 24 3 74 8 81 27 33 94 38 77 9 76 90 62 90 21 67 22 22 12 2 17 27 61 18 72 85 59 65 71 38 90 75 74 66 60 47 58 50 90 95 75 10 5 100 97 29 83 88 65 26 93 90 22 98 36 55 70 38 50 92 88 72 99 96 25 14 74 16 25 92 67 94 77 96",
"output": "-1"
},
{
"input": "1 1\n1",
"output": "0"
},
{
"input": "1 6\n1",
"output": "1"
},
{
"input": "1 5\n1",
"output": "0"
},
{
"input": "1 3\n4",
"output": "-1"
},
{
"input": "3 24\n2 1 2",
"output": "-1"
}
] | 1,562,784,913
| 2,147,483,647
|
PyPy 3
|
COMPILATION_ERROR
|
TESTS
| 0
| 0
| 0
|
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n, minutes;
cin >> n >> minutes;
vector<int> songs(n);
for(auto &i: songs)
{
cin >> i;
}
sort(songs.begin(), songs.end(), greater<int>());
int breaks =0;
for (int i = 0; i < n-1; i++)
{
minutes-=(songs[i]+10);
breaks++;
}
minutes-=songs[n-1];
if(minutes < 0)
cout << "-1\n";
else
{
cout << breaks*2+ floor(minutes/5) << "\n";
}
}
|
Title: Devu, the Singer and Churu, the Joker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited.
Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* song will take *t**i* minutes exactly.
The Comedian, Churu will crack jokes. All his jokes are of 5 minutes exactly.
People have mainly come to listen Devu. But you know that he needs rest of 10 minutes after each song. On the other hand, Churu being a very active person, doesn't need any rest.
You as one of the organizers should make an optimal sсhedule for the event. For some reasons you must follow the conditions:
- The duration of the event must be no more than *d* minutes; - Devu must complete all his songs; - With satisfying the two previous conditions the number of jokes cracked by Churu should be as many as possible.
If it is not possible to find a way to conduct all the songs of the Devu, output -1. Otherwise find out maximum number of jokes that Churu can crack in the grand event.
Input Specification:
The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100).
Output Specification:
If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event.
Demo Input:
['3 30\n2 2 1\n', '3 20\n2 1 1\n']
Demo Output:
['5\n', '-1\n']
Note:
Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way:
- First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now finally Devu will perform his last song in 1 minutes.
Total time spent is 5 + 2 + 10 + 2 + 10 + 1 = 30 minutes.
Consider the second example. There is no way of organizing Devu's all songs. Hence the answer is -1.
|
```python
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n, minutes;
cin >> n >> minutes;
vector<int> songs(n);
for(auto &i: songs)
{
cin >> i;
}
sort(songs.begin(), songs.end(), greater<int>());
int breaks =0;
for (int i = 0; i < n-1; i++)
{
minutes-=(songs[i]+10);
breaks++;
}
minutes-=songs[n-1];
if(minutes < 0)
cout << "-1\n";
else
{
cout << breaks*2+ floor(minutes/5) << "\n";
}
}
```
| -1
|
|
80
|
A
|
Panoramix's Prediction
|
PROGRAMMING
| 800
|
[
"brute force"
] |
A. Panoramix's Prediction
|
2
|
256
|
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note that there is exactly one next prime number after each number. So 5 is not the next prime number for 2.
One cold April morning Panoramix predicted that soon Kakofonix will break free from his straitjacket, and this will be a black day for the residents of the Gallic countryside.
Panoramix's prophecy tells that if some day Asterix and Obelix beat exactly *x* Roman soldiers, where *x* is a prime number, and next day they beat exactly *y* Roman soldiers, where *y* is the next prime number after *x*, then it's time to wait for Armageddon, for nothing can shut Kakofonix up while he sings his infernal song.
Yesterday the Gauls beat *n* Roman soldiers and it turned out that the number *n* was prime! Today their victims were a troop of *m* Romans (*m*<=><=*n*). Determine whether the Gauls should wait for the black day after today's victory of Asterix and Obelix?
|
The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4.
|
Print YES, if *m* is the next prime number after *n*, or NO otherwise.
|
[
"3 5\n",
"7 11\n",
"7 9\n"
] |
[
"YES",
"YES",
"NO"
] |
none
| 500
|
[
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
"output": "YES"
},
{
"input": "5 7",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "11 13",
"output": "YES"
},
{
"input": "13 17",
"output": "YES"
},
{
"input": "17 19",
"output": "YES"
},
{
"input": "19 23",
"output": "YES"
},
{
"input": "23 29",
"output": "YES"
},
{
"input": "29 31",
"output": "YES"
},
{
"input": "31 37",
"output": "YES"
},
{
"input": "37 41",
"output": "YES"
},
{
"input": "41 43",
"output": "YES"
},
{
"input": "43 47",
"output": "YES"
},
{
"input": "2 5",
"output": "NO"
},
{
"input": "2 7",
"output": "NO"
},
{
"input": "2 6",
"output": "NO"
},
{
"input": "2 11",
"output": "NO"
},
{
"input": "3 6",
"output": "NO"
},
{
"input": "3 7",
"output": "NO"
},
{
"input": "3 9",
"output": "NO"
},
{
"input": "5 6",
"output": "NO"
},
{
"input": "5 9",
"output": "NO"
},
{
"input": "5 11",
"output": "NO"
},
{
"input": "5 13",
"output": "NO"
},
{
"input": "5 15",
"output": "NO"
},
{
"input": "7 8",
"output": "NO"
},
{
"input": "7 13",
"output": "NO"
},
{
"input": "13 15",
"output": "NO"
},
{
"input": "13 17",
"output": "YES"
},
{
"input": "19 21",
"output": "NO"
},
{
"input": "13 20",
"output": "NO"
},
{
"input": "41 49",
"output": "NO"
},
{
"input": "43 49",
"output": "NO"
},
{
"input": "47 50",
"output": "NO"
},
{
"input": "47 49",
"output": "NO"
},
{
"input": "47 48",
"output": "NO"
},
{
"input": "23 25",
"output": "NO"
},
{
"input": "2 50",
"output": "NO"
},
{
"input": "31 33",
"output": "NO"
}
] | 1,676,553,168
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 0
| 30
| 0
|
n,p=map(int,input().split())
s=0
t=0
for i in range(2,int(n/2)+1):
if n%i==0:
s=0
break
else:
s=1
for j in range(2,int(p/2)+1):
if p%j==0:
t=0
break
else:
t=1
if ((t==1) and (s==1)):
print("YES")
else:
print("NO")
|
Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note that there is exactly one next prime number after each number. So 5 is not the next prime number for 2.
One cold April morning Panoramix predicted that soon Kakofonix will break free from his straitjacket, and this will be a black day for the residents of the Gallic countryside.
Panoramix's prophecy tells that if some day Asterix and Obelix beat exactly *x* Roman soldiers, where *x* is a prime number, and next day they beat exactly *y* Roman soldiers, where *y* is the next prime number after *x*, then it's time to wait for Armageddon, for nothing can shut Kakofonix up while he sings his infernal song.
Yesterday the Gauls beat *n* Roman soldiers and it turned out that the number *n* was prime! Today their victims were a troop of *m* Romans (*m*<=><=*n*). Determine whether the Gauls should wait for the black day after today's victory of Asterix and Obelix?
Input Specification:
The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4.
Output Specification:
Print YES, if *m* is the next prime number after *n*, or NO otherwise.
Demo Input:
['3 5\n', '7 11\n', '7 9\n']
Demo Output:
['YES', 'YES', 'NO']
Note:
none
|
```python
n,p=map(int,input().split())
s=0
t=0
for i in range(2,int(n/2)+1):
if n%i==0:
s=0
break
else:
s=1
for j in range(2,int(p/2)+1):
if p%j==0:
t=0
break
else:
t=1
if ((t==1) and (s==1)):
print("YES")
else:
print("NO")
```
| 0
|
263
|
A
|
Beautiful Matrix
|
PROGRAMMING
| 800
|
[
"implementation"
] | null | null |
You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix:
1. Swap two neighboring matrix rows, that is, rows with indexes *i* and *i*<=+<=1 for some integer *i* (1<=≤<=*i*<=<<=5). 1. Swap two neighboring matrix columns, that is, columns with indexes *j* and *j*<=+<=1 for some integer *j* (1<=≤<=*j*<=<<=5).
You think that a matrix looks beautiful, if the single number one of the matrix is located in its middle (in the cell that is on the intersection of the third row and the third column). Count the minimum number of moves needed to make the matrix beautiful.
|
The input consists of five lines, each line contains five integers: the *j*-th integer in the *i*-th line of the input represents the element of the matrix that is located on the intersection of the *i*-th row and the *j*-th column. It is guaranteed that the matrix consists of 24 zeroes and a single number one.
|
Print a single integer — the minimum number of moves needed to make the matrix beautiful.
|
[
"0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n",
"0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n"
] |
[
"3\n",
"1\n"
] |
none
| 500
|
[
{
"input": "0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 1 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "0"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 1",
"output": "4"
},
{
"input": "0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "1 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "4"
},
{
"input": "0 0 1 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 1 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "4"
},
{
"input": "0 0 0 0 0\n1 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 1 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 1 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n1 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 1 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n1 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 1 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 1 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n1 0 0 0 0",
"output": "4"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 1 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 1 0",
"output": "3"
}
] | 1,695,922,418
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 25
| 92
| 0
|
index = None
l = []
for o in range(5):
l.append(input().split())
for i, x in enumerate(l):
for j, y in enumerate(x):
if y == '1':
print(abs(i - 2) + abs(j - 2))
|
Title: Beautiful Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix:
1. Swap two neighboring matrix rows, that is, rows with indexes *i* and *i*<=+<=1 for some integer *i* (1<=≤<=*i*<=<<=5). 1. Swap two neighboring matrix columns, that is, columns with indexes *j* and *j*<=+<=1 for some integer *j* (1<=≤<=*j*<=<<=5).
You think that a matrix looks beautiful, if the single number one of the matrix is located in its middle (in the cell that is on the intersection of the third row and the third column). Count the minimum number of moves needed to make the matrix beautiful.
Input Specification:
The input consists of five lines, each line contains five integers: the *j*-th integer in the *i*-th line of the input represents the element of the matrix that is located on the intersection of the *i*-th row and the *j*-th column. It is guaranteed that the matrix consists of 24 zeroes and a single number one.
Output Specification:
Print a single integer — the minimum number of moves needed to make the matrix beautiful.
Demo Input:
['0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n', '0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n']
Demo Output:
['3\n', '1\n']
Note:
none
|
```python
index = None
l = []
for o in range(5):
l.append(input().split())
for i, x in enumerate(l):
for j, y in enumerate(x):
if y == '1':
print(abs(i - 2) + abs(j - 2))
```
| 3
|
|
58
|
A
|
Chat room
|
PROGRAMMING
| 1,000
|
[
"greedy",
"strings"
] |
A. Chat room
|
1
|
256
|
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
|
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
|
If Vasya managed to say hello, print "YES", otherwise print "NO".
|
[
"ahhellllloou\n",
"hlelo\n"
] |
[
"YES\n",
"NO\n"
] |
none
| 500
|
[
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymedasloqbq",
"output": "NO"
},
{
"input": "yehluhlkwo",
"output": "NO"
},
{
"input": "hatlevhhalrohairnolsvocafgueelrqmlqlleello",
"output": "YES"
},
{
"input": "hhhtehdbllnhwmbyhvelqqyoulretpbfokflhlhreeflxeftelziclrwllrpflflbdtotvlqgoaoqldlroovbfsq",
"output": "YES"
},
{
"input": "rzlvihhghnelqtwlexmvdjjrliqllolhyewgozkuovaiezgcilelqapuoeglnwmnlftxxiigzczlouooi",
"output": "YES"
},
{
"input": "pfhhwctyqdlkrwhebfqfelhyebwllhemtrmeblgrynmvyhioesqklclocxmlffuormljszllpoo",
"output": "YES"
},
{
"input": "lqllcolohwflhfhlnaow",
"output": "NO"
},
{
"input": "heheeellollvoo",
"output": "YES"
},
{
"input": "hellooo",
"output": "YES"
},
{
"input": "o",
"output": "NO"
},
{
"input": "hhqhzeclohlehljlhtesllylrolmomvuhcxsobtsckogdv",
"output": "YES"
},
{
"input": "yoegfuzhqsihygnhpnukluutocvvwuldiighpogsifealtgkfzqbwtmgghmythcxflebrkctlldlkzlagovwlstsghbouk",
"output": "YES"
},
{
"input": "uatqtgbvrnywfacwursctpagasnhydvmlinrcnqrry",
"output": "NO"
},
{
"input": "tndtbldbllnrwmbyhvqaqqyoudrstpbfokfoclnraefuxtftmgzicorwisrpfnfpbdtatvwqgyalqtdtrjqvbfsq",
"output": "NO"
},
{
"input": "rzlvirhgemelnzdawzpaoqtxmqucnahvqnwldklrmjiiyageraijfivigvozgwngiulttxxgzczptusoi",
"output": "YES"
},
{
"input": "kgyelmchocojsnaqdsyeqgnllytbqietpdlgknwwumqkxrexgdcnwoldicwzwofpmuesjuxzrasscvyuqwspm",
"output": "YES"
},
{
"input": "pnyvrcotjvgynbeldnxieghfltmexttuxzyac",
"output": "NO"
},
{
"input": "dtwhbqoumejligbenxvzhjlhosqojetcqsynlzyhfaevbdpekgbtjrbhlltbceobcok",
"output": "YES"
},
{
"input": "crrfpfftjwhhikwzeedrlwzblckkteseofjuxjrktcjfsylmlsvogvrcxbxtffujqshslemnixoeezivksouefeqlhhokwbqjz",
"output": "YES"
},
{
"input": "jhfbndhyzdvhbvhmhmefqllujdflwdpjbehedlsqfdsqlyelwjtyloxwsvasrbqosblzbowlqjmyeilcvotdlaouxhdpoeloaovb",
"output": "YES"
},
{
"input": "hwlghueoemiqtjhhpashjsouyegdlvoyzeunlroypoprnhlyiwiuxrghekaylndhrhllllwhbebezoglydcvykllotrlaqtvmlla",
"output": "YES"
},
{
"input": "wshiaunnqnqxodholbipwhhjmyeblhgpeleblklpzwhdunmpqkbuzloetmwwxmeltkrcomulxauzlwmlklldjodozxryghsnwgcz",
"output": "YES"
},
{
"input": "shvksednttggehroewuiptvvxtrzgidravtnjwuqrlnnkxbplctzkckinpkgjopjfoxdbojtcvsuvablcbkrzajrlhgobkcxeqti",
"output": "YES"
},
{
"input": "hyyhddqhxhekehkwfhlnlsihzefwchzerevcjtokefplholrbvxlltdlafjxrfhleglrvlolojoqaolagtbeyogxlbgfolllslli",
"output": "YES"
},
{
"input": "iaagrdhhelxpdegueiulflquvlzidoprzkehthkldaytrjwhyhprwjxlltinxvuilxohqgjqcvkkdcuoliekcnlilwgqlnlzouoo",
"output": "YES"
},
{
"input": "wfluaeseldgxyvxpwuhkptdmlflnlhktwxiabsvkolsquymrmhzczzoybvlilhmvsuunggvgxzgyyffk",
"output": "NO"
},
{
"input": "loee",
"output": "NO"
},
{
"input": "izdipwylefqmjbuoznfglgcfvedeouflkeehxbasaqmiooppfsqlhprospqgxvzrcpwlfdddngoqvpwvggsnvvxhmjoslwjudjlo",
"output": "NO"
},
{
"input": "pplynflbjlseflaegzqpdxswgunhnlglqhycrbcwdfhclmcrwekkzsoosmfblljeenwfjyifcvxihhhbyhmhlkvtskeglaovjnsi",
"output": "YES"
},
{
"input": "xqjqmenkodmlhzyzmmvofdngktygbbxbzpluzcohohmalkoeuwfikblltaaigv",
"output": "NO"
},
{
"input": "hello",
"output": "YES"
},
{
"input": "oohell",
"output": "NO"
},
{
"input": "hell",
"output": "NO"
},
{
"input": "eloellohoelo",
"output": "NO"
},
{
"input": "helllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllo",
"output": "YES"
}
] | 1,697,020,419
| 2,147,483,647
|
PyPy 3-64
|
WRONG_ANSWER
|
TESTS
| 1
| 46
| 0
|
s = input()
if s.rindex("o") > s.rindex("l") > s.rindex("e") > s.rindex("h") != -1 or -1 != s.index("h") < s.index("e") < s.index(
"l") < s.index("o") and s.count("l") >= 2:
print("YES")
exit()
print("NO")
|
Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
Input Specification:
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
Output Specification:
If Vasya managed to say hello, print "YES", otherwise print "NO".
Demo Input:
['ahhellllloou\n', 'hlelo\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none
|
```python
s = input()
if s.rindex("o") > s.rindex("l") > s.rindex("e") > s.rindex("h") != -1 or -1 != s.index("h") < s.index("e") < s.index(
"l") < s.index("o") and s.count("l") >= 2:
print("YES")
exit()
print("NO")
```
| 0
|
798
|
A
|
Mike and palindrome
|
PROGRAMMING
| 1,000
|
[
"brute force",
"constructive algorithms",
"strings"
] | null | null |
Mike has a string *s* consisting of only lowercase English letters. He wants to change exactly one character from the string so that the resulting one is a palindrome.
A palindrome is a string that reads the same backward as forward, for example strings "z", "aaa", "aba", "abccba" are palindromes, but strings "codeforces", "reality", "ab" are not.
|
The first and single line contains string *s* (1<=≤<=|*s*|<=≤<=15).
|
Print "YES" (without quotes) if Mike can change exactly one character so that the resulting string is palindrome or "NO" (without quotes) otherwise.
|
[
"abccaa\n",
"abbcca\n",
"abcda\n"
] |
[
"YES\n",
"NO\n",
"YES\n"
] |
none
| 500
|
[
{
"input": "abccaa",
"output": "YES"
},
{
"input": "abbcca",
"output": "NO"
},
{
"input": "abcda",
"output": "YES"
},
{
"input": "kyw",
"output": "YES"
},
{
"input": "fccf",
"output": "NO"
},
{
"input": "mnlm",
"output": "YES"
},
{
"input": "gqrk",
"output": "NO"
},
{
"input": "glxlg",
"output": "YES"
},
{
"input": "czhfc",
"output": "YES"
},
{
"input": "broon",
"output": "NO"
},
{
"input": "rmggmr",
"output": "NO"
},
{
"input": "wvxxzw",
"output": "YES"
},
{
"input": "ukvciu",
"output": "NO"
},
{
"input": "vrnwnrv",
"output": "YES"
},
{
"input": "vlkjkav",
"output": "YES"
},
{
"input": "guayhmg",
"output": "NO"
},
{
"input": "lkvhhvkl",
"output": "NO"
},
{
"input": "ffdsslff",
"output": "YES"
},
{
"input": "galjjtyw",
"output": "NO"
},
{
"input": "uosgwgsou",
"output": "YES"
},
{
"input": "qjwmjmljq",
"output": "YES"
},
{
"input": "ustrvrodf",
"output": "NO"
},
{
"input": "a",
"output": "YES"
},
{
"input": "qjfyjjyfjq",
"output": "NO"
},
{
"input": "ysxibbixsq",
"output": "YES"
},
{
"input": "howfslfwmh",
"output": "NO"
},
{
"input": "ekhajrjahke",
"output": "YES"
},
{
"input": "ucnolsloncw",
"output": "YES"
},
{
"input": "jrzsfrrkrtj",
"output": "NO"
},
{
"input": "typayzzyapyt",
"output": "NO"
},
{
"input": "uwdhkzokhdwu",
"output": "YES"
},
{
"input": "xokxpyyuafij",
"output": "NO"
},
{
"input": "eusneioiensue",
"output": "YES"
},
{
"input": "fuxpuajabpxuf",
"output": "YES"
},
{
"input": "guvggtfhlgruy",
"output": "NO"
},
{
"input": "cojhkhxxhkhjoc",
"output": "NO"
},
{
"input": "mhifbmmmmbmihm",
"output": "YES"
},
{
"input": "kxfqqncnebpami",
"output": "NO"
},
{
"input": "scfwrjevejrwfcs",
"output": "YES"
},
{
"input": "thdaonpepdoadht",
"output": "YES"
},
{
"input": "jsfzcbnhsccuqsj",
"output": "NO"
},
{
"input": "nn",
"output": "NO"
},
{
"input": "nm",
"output": "YES"
},
{
"input": "jdj",
"output": "YES"
},
{
"input": "bbcaa",
"output": "NO"
},
{
"input": "abcde",
"output": "NO"
},
{
"input": "abcdf",
"output": "NO"
},
{
"input": "aa",
"output": "NO"
},
{
"input": "abecd",
"output": "NO"
},
{
"input": "abccacb",
"output": "NO"
},
{
"input": "aabc",
"output": "NO"
},
{
"input": "anpqb",
"output": "NO"
},
{
"input": "c",
"output": "YES"
},
{
"input": "abcdefg",
"output": "NO"
},
{
"input": "aanbb",
"output": "NO"
},
{
"input": "aabbb",
"output": "NO"
},
{
"input": "aaabbab",
"output": "NO"
},
{
"input": "ab",
"output": "YES"
},
{
"input": "aabbc",
"output": "NO"
},
{
"input": "ecabd",
"output": "NO"
},
{
"input": "abcdrty",
"output": "NO"
},
{
"input": "abcdmnp",
"output": "NO"
},
{
"input": "bbbbbb",
"output": "NO"
},
{
"input": "abcxuio",
"output": "NO"
},
{
"input": "abcdabcde",
"output": "NO"
},
{
"input": "abcxpoi",
"output": "NO"
},
{
"input": "aba",
"output": "YES"
},
{
"input": "aacbb",
"output": "NO"
},
{
"input": "abcedca",
"output": "NO"
},
{
"input": "abcdd",
"output": "NO"
},
{
"input": "abbcs",
"output": "NO"
},
{
"input": "aaabccc",
"output": "NO"
},
{
"input": "paxkxbq",
"output": "NO"
},
{
"input": "z",
"output": "YES"
},
{
"input": "b",
"output": "YES"
},
{
"input": "abcdefghi",
"output": "NO"
},
{
"input": "abcqr",
"output": "NO"
},
{
"input": "abcdc",
"output": "NO"
},
{
"input": "abcb",
"output": "NO"
},
{
"input": "aabcd",
"output": "NO"
},
{
"input": "abbba",
"output": "YES"
},
{
"input": "aaabbb",
"output": "NO"
},
{
"input": "bb",
"output": "NO"
},
{
"input": "aaacbbb",
"output": "NO"
},
{
"input": "abbzcca",
"output": "NO"
},
{
"input": "abxab",
"output": "NO"
},
{
"input": "bbb",
"output": "YES"
},
{
"input": "abcrtyu",
"output": "NO"
},
{
"input": "cbacb",
"output": "NO"
},
{
"input": "acbb",
"output": "NO"
},
{
"input": "ww",
"output": "NO"
},
{
"input": "aaaaaa",
"output": "NO"
},
{
"input": "jizzz",
"output": "NO"
},
{
"input": "aaakcba",
"output": "NO"
},
{
"input": "acbak",
"output": "NO"
},
{
"input": "bddeffd",
"output": "NO"
},
{
"input": "aaa",
"output": "YES"
},
{
"input": "afghqwe",
"output": "NO"
},
{
"input": "abcdfga",
"output": "NO"
}
] | 1,697,515,226
| 2,147,483,647
|
PyPy 3-64
|
WRONG_ANSWER
|
TESTS
| 4
| 62
| 132,096,000
|
import bisect
import sys
from collections import Counter, OrderedDict, defaultdict
from functools import lru_cache
from itertools import permutations, combinations
from heapq import heapify
from math import sqrt, gcd
sys.setrecursionlimit(10**5)
def input(): return sys.stdin.readline().strip('\r\n')
def pyint(): return int(input())
def pyline(): return map(int, input().split())
def pylist(): return list(map(int, input().split()))
def solve(string):
for i in range(len(string)):
if string[i] == string[(i+1) * -1]:
continue
tmp = string[(i+1) * -1]
string[(i+1) * -1] = string[i]
if string == list(reversed(string)):
return "YES"
string[(i+1) * -1] = tmp
string[i] = tmp
if string == list(reversed(string)):
return "YES"
return "NO"
return "YES"
string = list(input())
print(solve(string))
|
Title: Mike and palindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mike has a string *s* consisting of only lowercase English letters. He wants to change exactly one character from the string so that the resulting one is a palindrome.
A palindrome is a string that reads the same backward as forward, for example strings "z", "aaa", "aba", "abccba" are palindromes, but strings "codeforces", "reality", "ab" are not.
Input Specification:
The first and single line contains string *s* (1<=≤<=|*s*|<=≤<=15).
Output Specification:
Print "YES" (without quotes) if Mike can change exactly one character so that the resulting string is palindrome or "NO" (without quotes) otherwise.
Demo Input:
['abccaa\n', 'abbcca\n', 'abcda\n']
Demo Output:
['YES\n', 'NO\n', 'YES\n']
Note:
none
|
```python
import bisect
import sys
from collections import Counter, OrderedDict, defaultdict
from functools import lru_cache
from itertools import permutations, combinations
from heapq import heapify
from math import sqrt, gcd
sys.setrecursionlimit(10**5)
def input(): return sys.stdin.readline().strip('\r\n')
def pyint(): return int(input())
def pyline(): return map(int, input().split())
def pylist(): return list(map(int, input().split()))
def solve(string):
for i in range(len(string)):
if string[i] == string[(i+1) * -1]:
continue
tmp = string[(i+1) * -1]
string[(i+1) * -1] = string[i]
if string == list(reversed(string)):
return "YES"
string[(i+1) * -1] = tmp
string[i] = tmp
if string == list(reversed(string)):
return "YES"
return "NO"
return "YES"
string = list(input())
print(solve(string))
```
| 0
|
|
5
|
C
|
Longest Regular Bracket Sequence
|
PROGRAMMING
| 1,900
|
[
"constructive algorithms",
"data structures",
"dp",
"greedy",
"sortings",
"strings"
] |
C. Longest Regular Bracket Sequence
|
2
|
256
|
This is yet another problem dealing with regular bracket sequences.
We should remind you that a bracket sequence is called regular, if by inserting «+» and «1» into it we can get a correct mathematical expression. For example, sequences «(())()», «()» and «(()(()))» are regular, while «)(», «(()» and «(()))(» are not.
You are given a string of «(» and «)» characters. You are to find its longest substring that is a regular bracket sequence. You are to find the number of such substrings as well.
|
The first line of the input file contains a non-empty string, consisting of «(» and «)» characters. Its length does not exceed 106.
|
Print the length of the longest substring that is a regular bracket sequence, and the number of such substrings. If there are no such substrings, write the only line containing "0 1".
|
[
")((())))(()())\n",
"))(\n"
] |
[
"6 2\n",
"0 1\n"
] |
none
| 0
|
[
{
"input": ")((())))(()())",
"output": "6 2"
},
{
"input": "))(",
"output": "0 1"
},
{
"input": "()(())()",
"output": "8 1"
},
{
"input": "((((()(((",
"output": "2 1"
},
{
"input": "))))()())))",
"output": "4 1"
},
{
"input": "(()())()(())()()())())()((()(()(())()()())((()(())()(()()()()))()(())()(((()())()(()((())()(())(()))",
"output": "28 1"
},
{
"input": ")(()(((((())))))(((()))))))((()(((((((())())()))))((((((((())))((((((())))))(()((((()))))(()))))))))",
"output": "68 1"
},
{
"input": "())(((((())())((((()))(())))())())(((()(()()()())(())()))((()(())())()()))()(()())))))(()))((())((((",
"output": "80 1"
},
{
"input": "))(((((((()((((())(((((((((()()))))(()())()((())())))((((()))(()()()))))(()()))())))))((())())()))((",
"output": "92 1"
}
] | 1,649,337,834
| 2,147,483,647
|
PyPy 3
|
WRONG_ANSWER
|
TESTS
| 1
| 154
| 0
|
import sys
input:lambda:sys.readline()
n=input()
stack=[]
judge=[False]*len(n)
end=-1
for i in range(len(n)):
if n[i]=='(':
stack.append(i)
end+=1
else:
if end!=-1 and n[stack[end]]=='(':
judge[stack[end]]=True
judge[i]=True
stack.pop()
end-=1
else:
stack.append(i)
end+=1
#print(n,judge,sep='\n')
cnt=0
maxnum=0
max_cnt=1
for i in range(len(n)):
if judge[i]==True:
cnt+=1
else:
if cnt > maxnum:
maxnum=cnt
max_cnt=1
elif cnt==maxnum:
max_cnt+=1
cnt=0
if cnt > maxnum:
maxnum=cnt
max_cnt=1
elif cnt==maxnum:
max_cnt+=1
print(maxnum,max_cnt)
|
Title: Longest Regular Bracket Sequence
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
This is yet another problem dealing with regular bracket sequences.
We should remind you that a bracket sequence is called regular, if by inserting «+» and «1» into it we can get a correct mathematical expression. For example, sequences «(())()», «()» and «(()(()))» are regular, while «)(», «(()» and «(()))(» are not.
You are given a string of «(» and «)» characters. You are to find its longest substring that is a regular bracket sequence. You are to find the number of such substrings as well.
Input Specification:
The first line of the input file contains a non-empty string, consisting of «(» and «)» characters. Its length does not exceed 106.
Output Specification:
Print the length of the longest substring that is a regular bracket sequence, and the number of such substrings. If there are no such substrings, write the only line containing "0 1".
Demo Input:
[')((())))(()())\n', '))(\n']
Demo Output:
['6 2\n', '0 1\n']
Note:
none
|
```python
import sys
input:lambda:sys.readline()
n=input()
stack=[]
judge=[False]*len(n)
end=-1
for i in range(len(n)):
if n[i]=='(':
stack.append(i)
end+=1
else:
if end!=-1 and n[stack[end]]=='(':
judge[stack[end]]=True
judge[i]=True
stack.pop()
end-=1
else:
stack.append(i)
end+=1
#print(n,judge,sep='\n')
cnt=0
maxnum=0
max_cnt=1
for i in range(len(n)):
if judge[i]==True:
cnt+=1
else:
if cnt > maxnum:
maxnum=cnt
max_cnt=1
elif cnt==maxnum:
max_cnt+=1
cnt=0
if cnt > maxnum:
maxnum=cnt
max_cnt=1
elif cnt==maxnum:
max_cnt+=1
print(maxnum,max_cnt)
```
| 0
|
0
|
none
|
none
|
none
| 0
|
[
"none"
] | null | null |
Dr. Moriarty is about to send a message to Sherlock Holmes. He has a string *s*.
String *p* is called a substring of string *s* if you can read it starting from some position in the string *s*. For example, string "aba" has six substrings: "a", "b", "a", "ab", "ba", "aba".
Dr. Moriarty plans to take string *s* and cut out some substring from it, let's call it *t*. Then he needs to change the substring *t* zero or more times. As a result, he should obtain a fixed string *u* (which is the string that should be sent to Sherlock Holmes). One change is defined as making one of the following actions:
- Insert one letter to any end of the string. - Delete one letter from any end of the string. - Change one letter into any other one.
Moriarty is very smart and after he chooses some substring *t*, he always makes the minimal number of changes to obtain *u*.
Help Moriarty choose the best substring *t* from all substrings of the string *s*. The substring *t* should minimize the number of changes Moriarty should make to obtain the string *u* from it.
|
The first line contains a non-empty string *s*, consisting of lowercase Latin letters. The second line contains a non-empty string *u*, consisting of lowercase Latin letters. The lengths of both strings are in the range from 1 to 2000, inclusive.
|
Print the only integer — the minimum number of changes that Dr. Moriarty has to make with the string that you choose.
|
[
"aaaaa\naaa\n",
"abcabc\nbcd\n",
"abcdef\nklmnopq\n"
] |
[
"0\n",
"1\n",
"7\n"
] |
In the first sample Moriarty can take any substring of length 3, and it will be equal to the required message *u*, so Moriarty won't have to make any changes.
In the second sample you should take a substring consisting of characters from second to fourth ("bca") or from fifth to sixth ("bc"). Then you will only have to make one change: to change or to add the last character.
In the third sample the initial string *s* doesn't contain any character that the message should contain, so, whatever string you choose, you will have to make at least 7 changes to obtain the required message.
| 0
|
[
{
"input": "aaaaa\naaa",
"output": "0"
},
{
"input": "abcabc\nbcd",
"output": "1"
},
{
"input": "abcdef\nklmnopq",
"output": "7"
},
{
"input": "aaabbbaaa\naba",
"output": "1"
},
{
"input": "a\na",
"output": "0"
},
{
"input": "z\nz",
"output": "0"
},
{
"input": "a\nz",
"output": "1"
},
{
"input": "d\nt",
"output": "1"
},
{
"input": "o\nu",
"output": "1"
},
{
"input": "a\nm",
"output": "1"
},
{
"input": "t\nv",
"output": "1"
},
{
"input": "n\ng",
"output": "1"
},
{
"input": "c\nh",
"output": "1"
},
{
"input": "r\ni",
"output": "1"
},
{
"input": "h\nb",
"output": "1"
},
{
"input": "r\na",
"output": "1"
},
{
"input": "c\np",
"output": "1"
},
{
"input": "wbdbzf\nfpvlerhsuf",
"output": "9"
},
{
"input": "zafsqbsu\nhl",
"output": "2"
},
{
"input": "juhlp\nycqugugk",
"output": "7"
},
{
"input": "ladfasxt\ncpvtd",
"output": "4"
},
{
"input": "ally\ncjidwuj",
"output": "7"
},
{
"input": "rgug\npgqwslo",
"output": "6"
},
{
"input": "wmjwu\nrfew",
"output": "3"
},
{
"input": "cpnwcdqff\nq",
"output": "0"
},
{
"input": "dkwh\nm",
"output": "1"
},
{
"input": "zfinrlju\nwiiegborjl",
"output": "9"
},
{
"input": "swconajiqpgziitbpwjsfcalqvmwbfed\nridfnsyumichlhpnurrnwkyjcdzchznpmno",
"output": "32"
},
{
"input": "vfjofvgkdwgqdlomtmcvedtmimdnxavhfirienxfdflldkbwjsynablhdvgaipvcghgaxipotwmmlzxekipgbvpfivlgzfwqz\njkdfjnessjfgcqpnxgtqdxtqimolbdlnipkoqht",
"output": "34"
},
{
"input": "dtvxepnxfkzcaoh\nkpdzbtwjitzlyzvsbwcsrfglaycrhzwsdtidrelndsq",
"output": "41"
},
{
"input": "sweaucynwsnduofyaqunoxttbipgrbfpssplfp\nuifmuxmczznobefdsyoclwzekewxmcwfqryuevnxxlgxsuhoytkaddorbdaygo",
"output": "57"
},
{
"input": "eohztfsxoyhirnzxgwaevfqstinlxeiyywmpmlbedkjihaxfdtsocof\nbloqrjbidxiqozvwregxxgmxuqcvhwzhytfckbafd",
"output": "37"
},
{
"input": "ybshzefoxkqdigcjafs\nnffvaxdmditsolfxbyquira",
"output": "19"
},
{
"input": "ytfqnuhqzbjjheejjbzcaorilcyvuxvviaiba\nxnhgkdfceialuujgcxmrhjbzvibcoknofafmdjnhij",
"output": "37"
},
{
"input": "ibdjtvgaveujdyidqldrxgwhsammmfpgxwljkptmeyejdvudhctmqjazalyzmzfgebetyqncu\nercdngwctdarcennbuqhsjlwfwrcqjbcjxqftycoulrhrimwhznogjmrrqdygtmllottpjgmkndraearezvxxmdhcuokhyngu",
"output": "90"
},
{
"input": "bwhvaanyxupicwobeevcwewhcriwowfovnylalpuhxzqxtzyjrzlxcmejujvliomdfedgtaioauwrcluhfxtzu\nplinvtsvytepojsecnjisxlmqkfhgknitvuw",
"output": "28"
},
{
"input": "sjxykdmrzpescabubcjflhnpckgytklc\nsxirpuqnmjqhlnvdeyvxvzzcygkpsujyifzgzmtvxsimddjahiephqlgfzngrzjtcrgrimewsxipczsgu",
"output": "76"
},
{
"input": "ksmbytfyhhnstlecripupiwdhbkhfpfmimrbqgszohcqnezcybvwasxmkxfupvuecsctcpadccnqexsglwaiyxcoyheefcjmdedesgjqdtqgrvfjonzesffousooutsjumrxl\nhgjqihcfbnmgufonaiudbjegexexthrzcdkuimwogpbyovemztzcmqnrbhabxyyxyfuzpyhjgnioexbezzupcxlyzuuncstiiqsjzdtqppqhxilvqimlpjejiqbwpeekzweeyvthvjffgfvqauqrugajjjzibgzhxphcvtncjzecbtupwkehcrgsgfgkvwwnifglyamjkzfvabybsstwrwugnmiwflhemgnfbrtskzfxcepqhtelgiowzeuujpkuzsfsipcvtfoeshawvryaubilcbwukdhlwamsqenzvr",
"output": "287"
},
{
"input": "abcd\ndabc",
"output": "1"
},
{
"input": "medxx\nahmed",
"output": "2"
},
{
"input": "ab\ndab",
"output": "1"
},
{
"input": "nasldkfnsb\nyyyynasld",
"output": "4"
},
{
"input": "abcde\ncabc",
"output": "1"
},
{
"input": "a\nzzzzzzzzzza",
"output": "10"
},
{
"input": "abcde\nabde",
"output": "2"
},
{
"input": "bac\ntbdca",
"output": "3"
},
{
"input": "abcdef\nxyzabc",
"output": "3"
},
{
"input": "abcdef\nbctsf",
"output": "2"
},
{
"input": "xxxabaxxx\nxxxaaxxx",
"output": "2"
},
{
"input": "bcd\nabc",
"output": "1"
},
{
"input": "d\nabcdef",
"output": "5"
}
] | 1,499,437,057
| 2,147,483,647
|
Python 3
|
TIME_LIMIT_EXCEEDED
|
TESTS
| 4
| 2,000
| 4,608,000
|
s, u, ans = str(input()), str(input()), 999999
s = '#' * (len(u) - 1) + s + '#' * (len(u) - 1)
for i in range(len(s) - len(u) + 1):
ans = min(ans, sum([s[i + j] != u[j] for j in range(len(u))]))
print(ans)
|
Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Moriarty is about to send a message to Sherlock Holmes. He has a string *s*.
String *p* is called a substring of string *s* if you can read it starting from some position in the string *s*. For example, string "aba" has six substrings: "a", "b", "a", "ab", "ba", "aba".
Dr. Moriarty plans to take string *s* and cut out some substring from it, let's call it *t*. Then he needs to change the substring *t* zero or more times. As a result, he should obtain a fixed string *u* (which is the string that should be sent to Sherlock Holmes). One change is defined as making one of the following actions:
- Insert one letter to any end of the string. - Delete one letter from any end of the string. - Change one letter into any other one.
Moriarty is very smart and after he chooses some substring *t*, he always makes the minimal number of changes to obtain *u*.
Help Moriarty choose the best substring *t* from all substrings of the string *s*. The substring *t* should minimize the number of changes Moriarty should make to obtain the string *u* from it.
Input Specification:
The first line contains a non-empty string *s*, consisting of lowercase Latin letters. The second line contains a non-empty string *u*, consisting of lowercase Latin letters. The lengths of both strings are in the range from 1 to 2000, inclusive.
Output Specification:
Print the only integer — the minimum number of changes that Dr. Moriarty has to make with the string that you choose.
Demo Input:
['aaaaa\naaa\n', 'abcabc\nbcd\n', 'abcdef\nklmnopq\n']
Demo Output:
['0\n', '1\n', '7\n']
Note:
In the first sample Moriarty can take any substring of length 3, and it will be equal to the required message *u*, so Moriarty won't have to make any changes.
In the second sample you should take a substring consisting of characters from second to fourth ("bca") or from fifth to sixth ("bc"). Then you will only have to make one change: to change or to add the last character.
In the third sample the initial string *s* doesn't contain any character that the message should contain, so, whatever string you choose, you will have to make at least 7 changes to obtain the required message.
|
```python
s, u, ans = str(input()), str(input()), 999999
s = '#' * (len(u) - 1) + s + '#' * (len(u) - 1)
for i in range(len(s) - len(u) + 1):
ans = min(ans, sum([s[i + j] != u[j] for j in range(len(u))]))
print(ans)
```
| 0
|
|
846
|
E
|
Chemistry in Berland
|
PROGRAMMING
| 2,300
|
[
"dfs and similar",
"greedy",
"trees"
] | null | null |
Igor is a post-graduate student of chemistry faculty in Berland State University (BerSU). He needs to conduct a complicated experiment to write his thesis, but laboratory of BerSU doesn't contain all the materials required for this experiment.
Fortunately, chemical laws allow material transformations (yes, chemistry in Berland differs from ours). But the rules of transformation are a bit strange.
Berland chemists are aware of *n* materials, numbered in the order they were discovered. Each material can be transformed into some other material (or vice versa). Formally, for each *i* (2<=≤<=*i*<=≤<=*n*) there exist two numbers *x**i* and *k**i* that denote a possible transformation: *k**i* kilograms of material *x**i* can be transformed into 1 kilogram of material *i*, and 1 kilogram of material *i* can be transformed into 1 kilogram of material *x**i*. Chemical processing equipment in BerSU allows only such transformation that the amount of resulting material is always an integer number of kilograms.
For each *i* (1<=≤<=*i*<=≤<=*n*) Igor knows that the experiment requires *a**i* kilograms of material *i*, and the laboratory contains *b**i* kilograms of this material. Is it possible to conduct an experiment after transforming some materials (or none)?
|
The first line contains one integer number *n* (1<=≤<=*n*<=≤<=105) — the number of materials discovered by Berland chemists.
The second line contains *n* integer numbers *b*1,<=*b*2... *b**n* (1<=≤<=*b**i*<=≤<=1012) — supplies of BerSU laboratory.
The third line contains *n* integer numbers *a*1,<=*a*2... *a**n* (1<=≤<=*a**i*<=≤<=1012) — the amounts required for the experiment.
Then *n*<=-<=1 lines follow. *j*-th of them contains two numbers *x**j*<=+<=1 and *k**j*<=+<=1 that denote transformation of (*j*<=+<=1)-th material (1<=≤<=*x**j*<=+<=1<=≤<=*j*,<=1<=≤<=*k**j*<=+<=1<=≤<=109).
|
Print YES if it is possible to conduct an experiment. Otherwise print NO.
|
[
"3\n1 2 3\n3 2 1\n1 1\n1 1\n",
"3\n3 2 1\n1 2 3\n1 1\n1 2\n"
] |
[
"YES\n",
"NO\n"
] |
none
| 0
|
[
{
"input": "3\n1 2 3\n3 2 1\n1 1\n1 1",
"output": "YES"
},
{
"input": "3\n3 2 1\n1 2 3\n1 1\n1 2",
"output": "NO"
},
{
"input": "5\n2 1 1 2 3\n1 2 2 2 1\n1 2\n1 3\n2 4\n1 4",
"output": "NO"
},
{
"input": "10\n2 8 6 1 2 7 6 9 2 8\n4 9 4 3 5 2 9 3 7 3\n1 8\n2 8\n3 8\n4 10\n5 1\n6 4\n7 3\n8 10\n9 2",
"output": "YES"
},
{
"input": "5\n27468 7465 74275 40573 40155\n112071 76270 244461 264202 132397\n1 777133331\n2 107454154\n3 652330694\n4 792720519",
"output": "NO"
},
{
"input": "5\n78188 56310 79021 70050 65217\n115040 5149 128449 98357 36580\n1 451393770\n2 574046602\n3 590130784\n4 112514248",
"output": "NO"
},
{
"input": "7\n1 1 1 1 1 1 1\n1 3000000000 3000000000 3000000000 1000000000 1000000000 1000000000\n1 1000000000\n1 1000000000\n1 1000000000\n1 1000000000\n1 1000000000\n1 1000000000",
"output": "NO"
},
{
"input": "11\n1 1 1 1 1 1 1 1 1 1 1\n1 1000000001 1000000001 1000000001 1000000001 1000000001 1000000001 1000000001 1000000001 1000000001 1000000001\n1 1000000000\n1 1000000000\n1 1000000000\n1 1000000000\n1 1000000000\n1 1000000000\n1 1000000000\n1 1000000000\n1 1000000000\n1 1000000000",
"output": "NO"
}
] | 1,638,036,873
| 2,147,483,647
|
PyPy 3-64
|
OK
|
TESTS
| 42
| 561
| 25,190,400
|
import sys
input = sys.stdin.readline
n = int(input())
b = [0] + list(map(int, input().split()))
a = [0] + list(map(int, input().split()))
G = [[] for _ in range(n + 1)]
x0, k0 = [0] * (n + 1), [0] * (n + 1)
for y in range(2, n + 1):
x, k = map(int, input().split())
G[x].append((y, k))
x0[y] = x
k0[y] = k
dp = [0] * (n + 1)
inf = pow(2, 63)
for i in range(n, 0, -1):
c = b[i] - a[i]
s = 0
for j, k in G[i]:
s += k * dp[j]
if s > inf:
ans = "NO"
print(ans)
exit()
c0 = max(0, min(c, s))
s -= c0
b[i] -= c0
dp[i] = s + max(a[i] - b[i], 0)
c = b[i] - a[i]
if c > 0 and i > 1:
b[x0[i]] += c
ans = "YES" if not dp[1] else "NO"
print(ans)
|
Title: Chemistry in Berland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Igor is a post-graduate student of chemistry faculty in Berland State University (BerSU). He needs to conduct a complicated experiment to write his thesis, but laboratory of BerSU doesn't contain all the materials required for this experiment.
Fortunately, chemical laws allow material transformations (yes, chemistry in Berland differs from ours). But the rules of transformation are a bit strange.
Berland chemists are aware of *n* materials, numbered in the order they were discovered. Each material can be transformed into some other material (or vice versa). Formally, for each *i* (2<=≤<=*i*<=≤<=*n*) there exist two numbers *x**i* and *k**i* that denote a possible transformation: *k**i* kilograms of material *x**i* can be transformed into 1 kilogram of material *i*, and 1 kilogram of material *i* can be transformed into 1 kilogram of material *x**i*. Chemical processing equipment in BerSU allows only such transformation that the amount of resulting material is always an integer number of kilograms.
For each *i* (1<=≤<=*i*<=≤<=*n*) Igor knows that the experiment requires *a**i* kilograms of material *i*, and the laboratory contains *b**i* kilograms of this material. Is it possible to conduct an experiment after transforming some materials (or none)?
Input Specification:
The first line contains one integer number *n* (1<=≤<=*n*<=≤<=105) — the number of materials discovered by Berland chemists.
The second line contains *n* integer numbers *b*1,<=*b*2... *b**n* (1<=≤<=*b**i*<=≤<=1012) — supplies of BerSU laboratory.
The third line contains *n* integer numbers *a*1,<=*a*2... *a**n* (1<=≤<=*a**i*<=≤<=1012) — the amounts required for the experiment.
Then *n*<=-<=1 lines follow. *j*-th of them contains two numbers *x**j*<=+<=1 and *k**j*<=+<=1 that denote transformation of (*j*<=+<=1)-th material (1<=≤<=*x**j*<=+<=1<=≤<=*j*,<=1<=≤<=*k**j*<=+<=1<=≤<=109).
Output Specification:
Print YES if it is possible to conduct an experiment. Otherwise print NO.
Demo Input:
['3\n1 2 3\n3 2 1\n1 1\n1 1\n', '3\n3 2 1\n1 2 3\n1 1\n1 2\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none
|
```python
import sys
input = sys.stdin.readline
n = int(input())
b = [0] + list(map(int, input().split()))
a = [0] + list(map(int, input().split()))
G = [[] for _ in range(n + 1)]
x0, k0 = [0] * (n + 1), [0] * (n + 1)
for y in range(2, n + 1):
x, k = map(int, input().split())
G[x].append((y, k))
x0[y] = x
k0[y] = k
dp = [0] * (n + 1)
inf = pow(2, 63)
for i in range(n, 0, -1):
c = b[i] - a[i]
s = 0
for j, k in G[i]:
s += k * dp[j]
if s > inf:
ans = "NO"
print(ans)
exit()
c0 = max(0, min(c, s))
s -= c0
b[i] -= c0
dp[i] = s + max(a[i] - b[i], 0)
c = b[i] - a[i]
if c > 0 and i > 1:
b[x0[i]] += c
ans = "YES" if not dp[1] else "NO"
print(ans)
```
| 3
|
|
946
|
A
|
Partition
|
PROGRAMMING
| 800
|
[
"greedy"
] | null | null |
You are given a sequence *a* consisting of *n* integers. You may partition this sequence into two sequences *b* and *c* in such a way that every element belongs exactly to one of these sequences.
Let *B* be the sum of elements belonging to *b*, and *C* be the sum of elements belonging to *c* (if some of these sequences is empty, then its sum is 0). What is the maximum possible value of *B*<=-<=*C*?
|
The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (<=-<=100<=≤<=*a**i*<=≤<=100) — the elements of sequence *a*.
|
Print the maximum possible value of *B*<=-<=*C*, where *B* is the sum of elements of sequence *b*, and *C* is the sum of elements of sequence *c*.
|
[
"3\n1 -2 0\n",
"6\n16 23 16 15 42 8\n"
] |
[
"3\n",
"120\n"
] |
In the first example we may choose *b* = {1, 0}, *c* = { - 2}. Then *B* = 1, *C* = - 2, *B* - *C* = 3.
In the second example we choose *b* = {16, 23, 16, 15, 42, 8}, *c* = {} (an empty sequence). Then *B* = 120, *C* = 0, *B* - *C* = 120.
| 0
|
[
{
"input": "3\n1 -2 0",
"output": "3"
},
{
"input": "6\n16 23 16 15 42 8",
"output": "120"
},
{
"input": "1\n-1",
"output": "1"
},
{
"input": "100\n-100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100",
"output": "10000"
},
{
"input": "2\n-1 5",
"output": "6"
},
{
"input": "3\n-2 0 1",
"output": "3"
},
{
"input": "12\n-1 -2 -3 4 4 -6 -6 56 3 3 -3 3",
"output": "94"
},
{
"input": "4\n1 -1 1 -1",
"output": "4"
},
{
"input": "4\n100 -100 100 -100",
"output": "400"
},
{
"input": "3\n-2 -5 10",
"output": "17"
},
{
"input": "5\n1 -2 3 -4 5",
"output": "15"
},
{
"input": "3\n-100 100 -100",
"output": "300"
},
{
"input": "6\n1 -1 1 -1 1 -1",
"output": "6"
},
{
"input": "6\n2 -2 2 -2 2 -2",
"output": "12"
},
{
"input": "9\n12 93 -2 0 0 0 3 -3 -9",
"output": "122"
},
{
"input": "6\n-1 2 4 -5 -3 55",
"output": "70"
},
{
"input": "6\n-12 8 68 -53 1 -15",
"output": "157"
},
{
"input": "2\n-2 1",
"output": "3"
},
{
"input": "3\n100 -100 100",
"output": "300"
},
{
"input": "5\n100 100 -1 -100 2",
"output": "303"
},
{
"input": "6\n-5 -4 -3 -2 -1 0",
"output": "15"
},
{
"input": "6\n4 4 4 -3 -3 2",
"output": "20"
},
{
"input": "2\n-1 2",
"output": "3"
},
{
"input": "1\n100",
"output": "100"
},
{
"input": "5\n-1 -2 3 1 2",
"output": "9"
},
{
"input": "5\n100 -100 100 -100 100",
"output": "500"
},
{
"input": "5\n1 -1 1 -1 1",
"output": "5"
},
{
"input": "4\n0 0 0 -1",
"output": "1"
},
{
"input": "5\n100 -100 -1 2 100",
"output": "303"
},
{
"input": "2\n75 0",
"output": "75"
},
{
"input": "4\n55 56 -59 -58",
"output": "228"
},
{
"input": "2\n9 71",
"output": "80"
},
{
"input": "2\n9 70",
"output": "79"
},
{
"input": "2\n9 69",
"output": "78"
},
{
"input": "2\n100 -100",
"output": "200"
},
{
"input": "4\n-9 4 -9 5",
"output": "27"
},
{
"input": "42\n91 -27 -79 -56 80 -93 -23 10 80 94 61 -89 -64 81 34 99 31 -32 -69 92 79 -9 73 66 -8 64 99 99 58 -19 -40 21 1 -33 93 -23 -62 27 55 41 57 36",
"output": "2348"
},
{
"input": "7\n-1 2 2 2 -1 2 -1",
"output": "11"
},
{
"input": "6\n-12 8 17 -69 7 -88",
"output": "201"
},
{
"input": "3\n1 -2 5",
"output": "8"
},
{
"input": "6\n-2 3 -4 5 6 -1",
"output": "21"
},
{
"input": "2\n-5 1",
"output": "6"
},
{
"input": "4\n2 2 -2 4",
"output": "10"
},
{
"input": "68\n21 47 -75 -25 64 83 83 -21 89 24 43 44 -35 34 -42 92 -96 -52 -66 64 14 -87 25 -61 -78 83 -96 -18 95 83 -93 -28 75 49 87 65 -93 -69 -2 95 -24 -36 -61 -71 88 -53 -93 -51 -81 -65 -53 -46 -56 6 65 58 19 100 57 61 -53 44 -58 48 -8 80 -88 72",
"output": "3991"
},
{
"input": "5\n5 5 -10 -1 1",
"output": "22"
},
{
"input": "3\n-1 2 3",
"output": "6"
},
{
"input": "76\n57 -38 -48 -81 93 -32 96 55 -44 2 38 -46 42 64 71 -73 95 31 -39 -62 -1 75 -17 57 28 52 12 -11 82 -84 59 -86 73 -97 34 97 -57 -85 -6 39 -5 -54 95 24 -44 35 -18 9 91 7 -22 -61 -80 54 -40 74 -90 15 -97 66 -52 -49 -24 65 21 -93 -29 -24 -4 -1 76 -93 7 -55 -53 1",
"output": "3787"
},
{
"input": "5\n-1 -2 1 2 3",
"output": "9"
},
{
"input": "4\n2 2 -2 -2",
"output": "8"
},
{
"input": "6\n100 -100 100 -100 100 -100",
"output": "600"
},
{
"input": "100\n-59 -33 34 0 69 24 -22 58 62 -36 5 45 -19 -73 61 -9 95 42 -73 -64 91 -96 2 53 -8 82 -79 16 18 -5 -53 26 71 38 -31 12 -33 -1 -65 -6 3 -89 22 33 -27 -36 41 11 -47 -32 47 -56 -38 57 -63 -41 23 41 29 78 16 -65 90 -58 -12 6 -60 42 -36 -52 -54 -95 -10 29 70 50 -94 1 93 48 -71 -77 -16 54 56 -60 66 76 31 8 44 -61 -74 23 37 38 18 -18 29 41",
"output": "4362"
},
{
"input": "2\n-1 1",
"output": "2"
},
{
"input": "3\n1 -2 100",
"output": "103"
},
{
"input": "5\n1 -2 3 1 2",
"output": "9"
},
{
"input": "10\n100 -10 -100 10 10 10 10 10 10 10",
"output": "280"
},
{
"input": "4\n2 0 -2 4",
"output": "8"
},
{
"input": "4\n3 -3 1 -1",
"output": "8"
},
{
"input": "3\n1 -1 1",
"output": "3"
},
{
"input": "4\n2 5 -2 4",
"output": "13"
},
{
"input": "2\n-2 2",
"output": "4"
},
{
"input": "3\n1 -2 1",
"output": "4"
},
{
"input": "5\n-1 -2 1 1 -1",
"output": "6"
},
{
"input": "4\n-2 0 2 4",
"output": "8"
},
{
"input": "8\n-42 7 87 -16 -5 65 -88 1",
"output": "311"
},
{
"input": "3\n1 -3 4",
"output": "8"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n0 1",
"output": "1"
},
{
"input": "3\n-1 2 -1",
"output": "4"
},
{
"input": "18\n-21 12 65 66 -24 62 82 35 -45 -47 28 37 5 -32 22 -14 -69 -95",
"output": "761"
},
{
"input": "4\n-1 1 -1 1",
"output": "4"
},
{
"input": "5\n-1 2 1 1 1",
"output": "6"
},
{
"input": "3\n1 1 1",
"output": "3"
}
] | 1,590,714,047
| 2,147,483,647
|
PyPy 3
|
OK
|
TESTS
| 72
| 140
| 0
|
# import sys
# sys.stdin = open('input.txt', 'r')
n = int(input())
arr = list(map(int, input().split()))
result = 0
for i in arr:
if i>0: result+= i
else: result -= i
print(result)
|
Title: Partition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence *a* consisting of *n* integers. You may partition this sequence into two sequences *b* and *c* in such a way that every element belongs exactly to one of these sequences.
Let *B* be the sum of elements belonging to *b*, and *C* be the sum of elements belonging to *c* (if some of these sequences is empty, then its sum is 0). What is the maximum possible value of *B*<=-<=*C*?
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (<=-<=100<=≤<=*a**i*<=≤<=100) — the elements of sequence *a*.
Output Specification:
Print the maximum possible value of *B*<=-<=*C*, where *B* is the sum of elements of sequence *b*, and *C* is the sum of elements of sequence *c*.
Demo Input:
['3\n1 -2 0\n', '6\n16 23 16 15 42 8\n']
Demo Output:
['3\n', '120\n']
Note:
In the first example we may choose *b* = {1, 0}, *c* = { - 2}. Then *B* = 1, *C* = - 2, *B* - *C* = 3.
In the second example we choose *b* = {16, 23, 16, 15, 42, 8}, *c* = {} (an empty sequence). Then *B* = 120, *C* = 0, *B* - *C* = 120.
|
```python
# import sys
# sys.stdin = open('input.txt', 'r')
n = int(input())
arr = list(map(int, input().split()))
result = 0
for i in arr:
if i>0: result+= i
else: result -= i
print(result)
```
| 3
|
|
0
|
none
|
none
|
none
| 0
|
[
"none"
] | null | null |
The last stage of Football World Cup is played using the play-off system.
There are *n* teams left in this stage, they are enumerated from 1 to *n*. Several rounds are held, in each round the remaining teams are sorted in the order of their ids, then the first in this order plays with the second, the third — with the fourth, the fifth — with the sixth, and so on. It is guaranteed that in each round there is even number of teams. The winner of each game advances to the next round, the loser is eliminated from the tournament, there are no draws. In the last round there is the only game with two remaining teams: the round is called the Final, the winner is called the champion, and the tournament is over.
Arkady wants his two favorite teams to play in the Final. Unfortunately, the team ids are already determined, and it may happen that it is impossible for teams to meet in the Final, because they are to meet in some earlier stage, if they are strong enough. Determine, in which round the teams with ids *a* and *b* can meet.
|
The only line contains three integers *n*, *a* and *b* (2<=≤<=*n*<=≤<=256, 1<=≤<=*a*,<=*b*<=≤<=*n*) — the total number of teams, and the ids of the teams that Arkady is interested in.
It is guaranteed that *n* is such that in each round an even number of team advance, and that *a* and *b* are not equal.
|
In the only line print "Final!" (without quotes), if teams *a* and *b* can meet in the Final.
Otherwise, print a single integer — the number of the round in which teams *a* and *b* can meet. The round are enumerated from 1.
|
[
"4 1 2\n",
"8 2 6\n",
"8 7 5\n"
] |
[
"1\n",
"Final!\n",
"2\n"
] |
In the first example teams 1 and 2 meet in the first round.
In the second example teams 2 and 6 can only meet in the third round, which is the Final, if they win all their opponents in earlier rounds.
In the third example the teams with ids 7 and 5 can meet in the second round, if they win their opponents in the first round.
| 0
|
[
{
"input": "4 1 2",
"output": "1"
},
{
"input": "8 2 6",
"output": "Final!"
},
{
"input": "8 7 5",
"output": "2"
},
{
"input": "128 30 98",
"output": "Final!"
},
{
"input": "256 128 256",
"output": "Final!"
},
{
"input": "256 2 127",
"output": "7"
},
{
"input": "2 1 2",
"output": "Final!"
},
{
"input": "2 2 1",
"output": "Final!"
},
{
"input": "4 1 3",
"output": "Final!"
},
{
"input": "4 1 4",
"output": "Final!"
},
{
"input": "4 2 1",
"output": "1"
},
{
"input": "4 2 3",
"output": "Final!"
},
{
"input": "4 2 4",
"output": "Final!"
},
{
"input": "4 3 1",
"output": "Final!"
},
{
"input": "4 3 2",
"output": "Final!"
},
{
"input": "4 3 4",
"output": "1"
},
{
"input": "4 4 1",
"output": "Final!"
},
{
"input": "4 4 2",
"output": "Final!"
},
{
"input": "4 4 3",
"output": "1"
},
{
"input": "8 8 7",
"output": "1"
},
{
"input": "8 8 5",
"output": "2"
},
{
"input": "8 8 1",
"output": "Final!"
},
{
"input": "16 4 3",
"output": "1"
},
{
"input": "16 2 4",
"output": "2"
},
{
"input": "16 14 11",
"output": "3"
},
{
"input": "16 3 11",
"output": "Final!"
},
{
"input": "32 10 9",
"output": "1"
},
{
"input": "32 25 28",
"output": "2"
},
{
"input": "32 22 18",
"output": "3"
},
{
"input": "32 17 25",
"output": "4"
},
{
"input": "32 18 3",
"output": "Final!"
},
{
"input": "64 40 39",
"output": "1"
},
{
"input": "64 60 58",
"output": "2"
},
{
"input": "64 34 37",
"output": "3"
},
{
"input": "64 26 24",
"output": "4"
},
{
"input": "64 50 43",
"output": "5"
},
{
"input": "64 17 42",
"output": "Final!"
},
{
"input": "128 116 115",
"output": "1"
},
{
"input": "128 35 33",
"output": "2"
},
{
"input": "128 61 59",
"output": "3"
},
{
"input": "128 116 123",
"output": "4"
},
{
"input": "128 17 15",
"output": "5"
},
{
"input": "128 124 77",
"output": "6"
},
{
"input": "128 4 80",
"output": "Final!"
},
{
"input": "256 224 223",
"output": "1"
},
{
"input": "256 24 22",
"output": "2"
},
{
"input": "256 199 196",
"output": "3"
},
{
"input": "256 148 159",
"output": "4"
},
{
"input": "256 178 166",
"output": "5"
},
{
"input": "256 75 97",
"output": "6"
},
{
"input": "256 185 200",
"output": "7"
},
{
"input": "256 3 238",
"output": "Final!"
},
{
"input": "256 128 129",
"output": "Final!"
},
{
"input": "256 255 129",
"output": "7"
},
{
"input": "256 255 128",
"output": "Final!"
},
{
"input": "256 129 256",
"output": "7"
},
{
"input": "128 98 69",
"output": "6"
},
{
"input": "128 47 83",
"output": "Final!"
},
{
"input": "16 2 3",
"output": "2"
},
{
"input": "64 32 30",
"output": "2"
},
{
"input": "8 4 5",
"output": "Final!"
},
{
"input": "8 7 8",
"output": "1"
},
{
"input": "8 2 3",
"output": "2"
},
{
"input": "8 2 5",
"output": "Final!"
}
] | 1,520,153,218
| 418
|
Python 3
|
OK
|
TESTS
| 64
| 77
| 5,632,000
|
n, a, b = map(int, input().split())
a -= 1
b -= 1
a += n
b += n
res = 0
while a != b:
# print(a, b)
a //= 2
b //= 2
res += 1
if a == 1:
print('Final!')
else:
print(res)
|
Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The last stage of Football World Cup is played using the play-off system.
There are *n* teams left in this stage, they are enumerated from 1 to *n*. Several rounds are held, in each round the remaining teams are sorted in the order of their ids, then the first in this order plays with the second, the third — with the fourth, the fifth — with the sixth, and so on. It is guaranteed that in each round there is even number of teams. The winner of each game advances to the next round, the loser is eliminated from the tournament, there are no draws. In the last round there is the only game with two remaining teams: the round is called the Final, the winner is called the champion, and the tournament is over.
Arkady wants his two favorite teams to play in the Final. Unfortunately, the team ids are already determined, and it may happen that it is impossible for teams to meet in the Final, because they are to meet in some earlier stage, if they are strong enough. Determine, in which round the teams with ids *a* and *b* can meet.
Input Specification:
The only line contains three integers *n*, *a* and *b* (2<=≤<=*n*<=≤<=256, 1<=≤<=*a*,<=*b*<=≤<=*n*) — the total number of teams, and the ids of the teams that Arkady is interested in.
It is guaranteed that *n* is such that in each round an even number of team advance, and that *a* and *b* are not equal.
Output Specification:
In the only line print "Final!" (without quotes), if teams *a* and *b* can meet in the Final.
Otherwise, print a single integer — the number of the round in which teams *a* and *b* can meet. The round are enumerated from 1.
Demo Input:
['4 1 2\n', '8 2 6\n', '8 7 5\n']
Demo Output:
['1\n', 'Final!\n', '2\n']
Note:
In the first example teams 1 and 2 meet in the first round.
In the second example teams 2 and 6 can only meet in the third round, which is the Final, if they win all their opponents in earlier rounds.
In the third example the teams with ids 7 and 5 can meet in the second round, if they win their opponents in the first round.
|
```python
n, a, b = map(int, input().split())
a -= 1
b -= 1
a += n
b += n
res = 0
while a != b:
# print(a, b)
a //= 2
b //= 2
res += 1
if a == 1:
print('Final!')
else:
print(res)
```
| 3
|
|
0
|
none
|
none
|
none
| 0
|
[
"none"
] | null | null |
Greg has an array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n* and *m* operations. Each operation looks as: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). To apply operation *i* to the array means to increase all array elements with numbers *l**i*,<=*l**i*<=+<=1,<=...,<=*r**i* by value *d**i*.
Greg wrote down *k* queries on a piece of paper. Each query has the following form: *x**i*, *y**i*, (1<=≤<=*x**i*<=≤<=*y**i*<=≤<=*m*). That means that one should apply operations with numbers *x**i*,<=*x**i*<=+<=1,<=...,<=*y**i* to the array.
Now Greg is wondering, what the array *a* will be after all the queries are executed. Help Greg.
|
The first line contains integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=105). The second line contains *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=105) — the initial array.
Next *m* lines contain operations, the operation number *i* is written as three integers: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*), (0<=≤<=*d**i*<=≤<=105).
Next *k* lines contain the queries, the query number *i* is written as two integers: *x**i*, *y**i*, (1<=≤<=*x**i*<=≤<=*y**i*<=≤<=*m*).
The numbers in the lines are separated by single spaces.
|
On a single line print *n* integers *a*1,<=*a*2,<=...,<=*a**n* — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
|
[
"3 3 3\n1 2 3\n1 2 1\n1 3 2\n2 3 4\n1 2\n1 3\n2 3\n",
"1 1 1\n1\n1 1 1\n1 1\n",
"4 3 6\n1 2 3 4\n1 2 1\n2 3 2\n3 4 4\n1 2\n1 3\n2 3\n1 2\n1 3\n2 3\n"
] |
[
"9 18 17\n",
"2\n",
"5 18 31 20\n"
] |
none
| 0
|
[
{
"input": "3 3 3\n1 2 3\n1 2 1\n1 3 2\n2 3 4\n1 2\n1 3\n2 3",
"output": "9 18 17"
},
{
"input": "1 1 1\n1\n1 1 1\n1 1",
"output": "2"
},
{
"input": "4 3 6\n1 2 3 4\n1 2 1\n2 3 2\n3 4 4\n1 2\n1 3\n2 3\n1 2\n1 3\n2 3",
"output": "5 18 31 20"
},
{
"input": "1 1 1\n0\n1 1 0\n1 1",
"output": "0"
}
] | 1,596,741,799
| 2,147,483,647
|
PyPy 3
|
COMPILATION_ERROR
|
TESTS
| 0
| 0
| 0
|
// Author : ps41
#include <bits/stdc++.h>
using namespace std;
#define ll int64_t
const ll M = 1e9 + 7, N = 1e6 + 5;
ll a[N], f[N], op[N][3], ans[N];
int main()
{
ios::sync_with_stdio(false), cin.tie(nullptr);
ll n, m, k;
cin >> n >> m >> k;
for (ll i = 1; i <= n; i++) cin >> a[i];
for (ll i = 1; i <= m; i++) cin >> op[i][0] >> op[i][1] >> op[i][2];
for (ll i = 1; i <= k; i++)
{
ll x, y;
cin >> x >> y;
f[x] += 1, f[y + 1] -= 1;
}
for (ll i = 1; i <= m; i++) f[i] += f[i - 1];
for (ll i = 1; i <= m; i++)
{
ll l = op[i][0], r = op[i][1], d = op[i][2] * f[i];
ans[l] += d, ans[r + 1] -= d;
}
for (ll i = 1; i <= n; i++) ans[i] += ans[i - 1], cout << a[i] + ans[i] << " ";
}
|
Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg has an array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n* and *m* operations. Each operation looks as: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). To apply operation *i* to the array means to increase all array elements with numbers *l**i*,<=*l**i*<=+<=1,<=...,<=*r**i* by value *d**i*.
Greg wrote down *k* queries on a piece of paper. Each query has the following form: *x**i*, *y**i*, (1<=≤<=*x**i*<=≤<=*y**i*<=≤<=*m*). That means that one should apply operations with numbers *x**i*,<=*x**i*<=+<=1,<=...,<=*y**i* to the array.
Now Greg is wondering, what the array *a* will be after all the queries are executed. Help Greg.
Input Specification:
The first line contains integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=105). The second line contains *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=105) — the initial array.
Next *m* lines contain operations, the operation number *i* is written as three integers: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*), (0<=≤<=*d**i*<=≤<=105).
Next *k* lines contain the queries, the query number *i* is written as two integers: *x**i*, *y**i*, (1<=≤<=*x**i*<=≤<=*y**i*<=≤<=*m*).
The numbers in the lines are separated by single spaces.
Output Specification:
On a single line print *n* integers *a*1,<=*a*2,<=...,<=*a**n* — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.
Demo Input:
['3 3 3\n1 2 3\n1 2 1\n1 3 2\n2 3 4\n1 2\n1 3\n2 3\n', '1 1 1\n1\n1 1 1\n1 1\n', '4 3 6\n1 2 3 4\n1 2 1\n2 3 2\n3 4 4\n1 2\n1 3\n2 3\n1 2\n1 3\n2 3\n']
Demo Output:
['9 18 17\n', '2\n', '5 18 31 20\n']
Note:
none
|
```python
// Author : ps41
#include <bits/stdc++.h>
using namespace std;
#define ll int64_t
const ll M = 1e9 + 7, N = 1e6 + 5;
ll a[N], f[N], op[N][3], ans[N];
int main()
{
ios::sync_with_stdio(false), cin.tie(nullptr);
ll n, m, k;
cin >> n >> m >> k;
for (ll i = 1; i <= n; i++) cin >> a[i];
for (ll i = 1; i <= m; i++) cin >> op[i][0] >> op[i][1] >> op[i][2];
for (ll i = 1; i <= k; i++)
{
ll x, y;
cin >> x >> y;
f[x] += 1, f[y + 1] -= 1;
}
for (ll i = 1; i <= m; i++) f[i] += f[i - 1];
for (ll i = 1; i <= m; i++)
{
ll l = op[i][0], r = op[i][1], d = op[i][2] * f[i];
ans[l] += d, ans[r + 1] -= d;
}
for (ll i = 1; i <= n; i++) ans[i] += ans[i - 1], cout << a[i] + ans[i] << " ";
}
```
| -1
|
|
731
|
A
|
Night at the Museum
|
PROGRAMMING
| 800
|
[
"implementation",
"strings"
] | null | null |
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character. The device consists of a wheel with a lowercase English letters written in a circle, static pointer to the current letter and a button that print the chosen letter. At one move it's allowed to rotate the alphabetic wheel one step clockwise or counterclockwise. Initially, static pointer points to letter 'a'. Other letters are located as shown on the picture:
After Grigoriy add new item to the base he has to print its name on the plastic tape and attach it to the corresponding exhibit. It's not required to return the wheel to its initial position with pointer on the letter 'a'.
Our hero is afraid that some exhibits may become alive and start to attack him, so he wants to print the names as fast as possible. Help him, for the given string find the minimum number of rotations of the wheel required to print it.
|
The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters.
|
Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input.
|
[
"zeus\n",
"map\n",
"ares\n"
] |
[
"18\n",
"35\n",
"34\n"
] |
To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations).
| 500
|
[
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"output": "99"
},
{
"input": "gngvi",
"output": "44"
},
{
"input": "aaaaa",
"output": "0"
},
{
"input": "a",
"output": "0"
},
{
"input": "z",
"output": "1"
},
{
"input": "vyadeehhikklnoqrs",
"output": "28"
},
{
"input": "jjiihhhhgggfedcccbazyxx",
"output": "21"
},
{
"input": "fyyptqqxuciqvwdewyppjdzur",
"output": "117"
},
{
"input": "fqcnzmzmbobmancqcoalzmanaobpdse",
"output": "368"
},
{
"input": "zzzzzaaaaaaazzzzzzaaaaaaazzzzzzaaaazzzza",
"output": "8"
},
{
"input": "aucnwhfixuruefkypvrvnvznwtjgwlghoqtisbkhuwxmgzuljvqhmnwzisnsgjhivnjmbknptxatdkelhzkhsuxzrmlcpeoyukiy",
"output": "644"
},
{
"input": "sssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss",
"output": "8"
},
{
"input": "nypjygrdtpzpigzyrisqeqfriwgwlengnezppgttgtndbrryjdl",
"output": "421"
},
{
"input": "pnllnnmmmmoqqqqqrrtssssuuvtsrpopqoonllmonnnpppopnonoopooqpnopppqppqstuuuwwwwvxzxzzaa",
"output": "84"
},
{
"input": "btaoahqgxnfsdmzsjxgvdwjukcvereqeskrdufqfqgzqfsftdqcthtkcnaipftcnco",
"output": "666"
},
{
"input": "eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeerrrrrrrrrrrrrrrrwwwwwwwwww",
"output": "22"
},
{
"input": "uyknzcrwjyzmscqucclvacmorepdgmnyhmakmmnygqwglrxkxhkpansbmruwxdeoprxzmpsvwackopujxbbkpwyeggsvjykpxh",
"output": "643"
},
{
"input": "gzwpooohffcxwtpjgfzwtooiccxsrrokezutoojdzwsrmmhecaxwrojcbyrqlfdwwrliiib",
"output": "245"
},
{
"input": "dbvnkktasjdwqsrzfwwtmjgbcxggdxsoeilecihduypktkkbwfbruxzzhlttrssicgdwqruddwrlbtxgmhdbatzvdxbbro",
"output": "468"
},
{
"input": "mdtvowlktxzzbuaeiuebfeorgbdczauxsovbucactkvyvemsknsjfhifqgycqredzchipmkvzbxdjkcbyukomjlzvxzoswumned",
"output": "523"
},
{
"input": "kkkkkkkaaaaxxaaaaaaaxxxxxxxxaaaaaaxaaaaaaaaaakkkkkkkkkaaaaaaannnnnxxxxkkkkkkkkaannnnnnna",
"output": "130"
},
{
"input": "dffiknqqrsvwzcdgjkmpqtuwxadfhkkkmpqrtwxyadfggjmpppsuuwyyzcdgghhknnpsvvvwwwyabccffiloqruwwyyzabeeehh",
"output": "163"
},
{
"input": "qpppmmkjihgecbyvvsppnnnkjiffeebaaywutrrqpmkjhgddbzzzywtssssqnmmljheddbbaxvusrqonmlifedbbzyywwtqnkheb",
"output": "155"
},
{
"input": "wvvwwwvvwxxxyyyxxwwvwwvuttttttuvvwxxwxxyxxwwwwwvvuttssrssstsssssrqpqqppqrssrsrrssrssssrrsrqqrrqpppqp",
"output": "57"
},
{
"input": "dqcpcobpcobnznamznamzlykxkxlxlylzmaobnaobpbnanbpcoaobnboaoboanzlymzmykylymylzlylymanboanaocqdqesfrfs",
"output": "1236"
},
{
"input": "nnnnnnnnnnnnnnnnnnnnaaaaaaaaaaaaaaaaaaaakkkkkkkkkkkkkkkkkkkkkkaaaaaaaaaaaaaaaaaaaaxxxxxxxxxxxxxxxxxx",
"output": "49"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa",
"output": "0"
},
{
"input": "cgilqsuwzaffilptwwbgmnttyyejkorxzflqvzbddhmnrvxchijpuwaeiimosxyycejlpquuwbfkpvbgijkqvxybdjjjptxcfkqt",
"output": "331"
},
{
"input": "ufsepwgtzgtgjssxaitgpailuvgqweoppszjwhoxdhhhpwwdorwfrdjwcdekxiktwziqwbkvbknrtvajpyeqbjvhiikxxaejjpte",
"output": "692"
},
{
"input": "uhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuhuh",
"output": "1293"
},
{
"input": "vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvgggggggggggggggggggggggggggggggggggggggggggggggggg",
"output": "16"
},
{
"input": "lyidmjyzbszgiwkxhhpnnthfwcvvstueionspfrvqgkvngmwyhezlosrpdnbvtcjjxxsykixwnepbumaacdzadlqhnjlcejovple",
"output": "616"
},
{
"input": "etzqqbaveffalkdguunfmyyrzkccnxmlluxeasqmopxzfvlkbhipqdwjgrttoemruohgwukfisdhznqyvhswbbypoxgtxyappcrl",
"output": "605"
},
{
"input": "lizussgedcbdjhrbeskhgatyozvwwekanlggcstijrniivupmcoofbaxfqrxddyzzptwxcftlhajsmmkkriarrqtkoauhcqefyud",
"output": "549"
},
{
"input": "dvjuvgfdogpknmbowlsfjzcimnygbtjiucyeeroqwhmzwpjqxlbjkqawrdtmvxbiqufllfuqibxvmtdrwaqkjblxqjpwzmhwqore",
"output": "688"
},
{
"input": "eeycuijtbgynmiczjfslwobmnkpgodfgvujvduyfeqchuaoktqrrairkkmmsjahltfcxwtpzzyddxrqfxabfoocmpuviinrjitsc",
"output": "604"
},
{
"input": "cgglnakewwvzoytaghksebrhjdbcdegssuzilrcppayxtgxopybbwshvyqnzhdsifkuwghourmeottrgjwdqpihbklvfzxpomqsa",
"output": "572"
},
{
"input": "aexullmxncckzryymfnuugdklaffevabqqztelpvojecljnhqldazdcaamubpenwxikysxxjjctvbndprsolzehywmgnvkgqvrfp",
"output": "609"
},
{
"input": "psnoieutsvvcwfhtnnphhxkwigzsbzyjmdiyl",
"output": "223"
},
{
"input": "aa",
"output": "0"
}
] | 1,678,268,506
| 2,147,483,647
|
PyPy 3-64
|
OK
|
TESTS
| 44
| 61
| 0
|
x=input()
y="a"
z=y+x
n=len(z)
# print(z)
c=0
v=[]
for i in range(n-1):
a=abs(ord(z[i+1])-ord(z[i]))
if a<=13:
c=a
v.append(c)
elif a>13:
c=26-a
v.append(c)
print(sum(v))
|
Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character. The device consists of a wheel with a lowercase English letters written in a circle, static pointer to the current letter and a button that print the chosen letter. At one move it's allowed to rotate the alphabetic wheel one step clockwise or counterclockwise. Initially, static pointer points to letter 'a'. Other letters are located as shown on the picture:
After Grigoriy add new item to the base he has to print its name on the plastic tape and attach it to the corresponding exhibit. It's not required to return the wheel to its initial position with pointer on the letter 'a'.
Our hero is afraid that some exhibits may become alive and start to attack him, so he wants to print the names as fast as possible. Help him, for the given string find the minimum number of rotations of the wheel required to print it.
Input Specification:
The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters.
Output Specification:
Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input.
Demo Input:
['zeus\n', 'map\n', 'ares\n']
Demo Output:
['18\n', '35\n', '34\n']
Note:
To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations).
|
```python
x=input()
y="a"
z=y+x
n=len(z)
# print(z)
c=0
v=[]
for i in range(n-1):
a=abs(ord(z[i+1])-ord(z[i]))
if a<=13:
c=a
v.append(c)
elif a>13:
c=26-a
v.append(c)
print(sum(v))
```
| 3
|
|
574
|
A
|
Bear and Elections
|
PROGRAMMING
| 1,200
|
[
"greedy",
"implementation"
] | null | null |
Limak is a grizzly bear who desires power and adoration. He wants to win in upcoming elections and rule over the Bearland.
There are *n* candidates, including Limak. We know how many citizens are going to vote for each candidate. Now *i*-th candidate would get *a**i* votes. Limak is candidate number 1. To win in elections, he must get strictly more votes than any other candidate.
Victory is more important than everything else so Limak decided to cheat. He will steal votes from his opponents by bribing some citizens. To bribe a citizen, Limak must give him or her one candy - citizens are bears and bears like candies. Limak doesn't have many candies and wonders - how many citizens does he have to bribe?
|
The first line contains single integer *n* (2<=≤<=*n*<=≤<=100) - number of candidates.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) - number of votes for each candidate. Limak is candidate number 1.
Note that after bribing number of votes for some candidate might be zero or might be greater than 1000.
|
Print the minimum number of citizens Limak must bribe to have strictly more votes than any other candidate.
|
[
"5\n5 1 11 2 8\n",
"4\n1 8 8 8\n",
"2\n7 6\n"
] |
[
"4\n",
"6\n",
"0\n"
] |
In the first sample Limak has 5 votes. One of the ways to achieve victory is to bribe 4 citizens who want to vote for the third candidate. Then numbers of votes would be 9, 1, 7, 2, 8 (Limak would have 9 votes). Alternatively, Limak could steal only 3 votes from the third candidate and 1 vote from the second candidate to get situation 9, 0, 8, 2, 8.
In the second sample Limak will steal 2 votes from each candidate. Situation will be 7, 6, 6, 6.
In the third sample Limak is a winner without bribing any citizen.
| 500
|
[
{
"input": "5\n5 1 11 2 8",
"output": "4"
},
{
"input": "4\n1 8 8 8",
"output": "6"
},
{
"input": "2\n7 6",
"output": "0"
},
{
"input": "2\n1 1",
"output": "1"
},
{
"input": "10\n100 200 57 99 1 1000 200 200 200 500",
"output": "451"
},
{
"input": "16\n7 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000",
"output": "932"
},
{
"input": "100\n47 64 68 61 68 66 69 61 69 65 69 63 62 60 68 65 64 65 65 62 63 68 60 70 63 63 65 67 70 69 68 69 61 65 63 60 60 65 61 60 70 66 66 65 62 60 65 68 61 62 67 64 66 65 67 68 60 69 70 63 65 62 64 65 67 67 69 68 66 69 70 67 65 70 60 66 70 67 67 64 69 69 66 68 60 64 62 62 68 69 67 69 60 70 69 68 62 63 68 66",
"output": "23"
},
{
"input": "2\n96 97",
"output": "1"
},
{
"input": "2\n1000 1000",
"output": "1"
},
{
"input": "3\n999 1000 1000",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "2"
},
{
"input": "7\n10 940 926 990 946 980 985",
"output": "817"
},
{
"input": "10\n5 3 4 5 5 2 1 8 4 1",
"output": "2"
},
{
"input": "15\n17 15 17 16 13 17 13 16 14 14 17 17 13 15 17",
"output": "1"
},
{
"input": "20\n90 5 62 9 50 7 14 43 44 44 56 13 71 22 43 35 52 60 73 54",
"output": "0"
},
{
"input": "30\n27 85 49 7 77 38 4 68 23 28 81 100 40 9 78 38 1 60 60 49 98 44 45 92 46 39 98 24 37 39",
"output": "58"
},
{
"input": "51\n90 47 100 12 21 96 2 68 84 60 2 9 33 8 45 13 59 50 100 93 22 97 4 81 51 2 3 78 19 16 25 63 52 34 79 32 34 87 7 42 96 93 30 33 33 43 69 8 63 58 57",
"output": "8"
},
{
"input": "77\n1000 2 2 3 1 1 1 3 3 2 1 1 3 2 2 2 3 2 3 1 3 1 1 2 2 2 3 1 1 2 2 2 3 2 1 3 3 1 2 3 3 3 2 1 3 2 1 3 3 2 3 3 2 1 3 1 1 1 2 3 2 3 1 3 1 2 1 2 2 2 1 2 2 3 2 2 2",
"output": "0"
},
{
"input": "91\n3 92 89 83 85 80 91 94 95 82 92 95 80 88 90 85 81 90 87 86 94 88 90 87 88 82 95 84 84 93 83 95 91 85 89 88 88 85 87 90 93 80 89 95 94 92 93 86 83 82 86 84 91 80 90 95 84 86 84 85 84 92 82 84 83 91 87 95 94 95 90 95 86 92 86 80 95 86 88 80 82 87 84 83 91 93 81 81 91 89 88",
"output": "89"
},
{
"input": "100\n1 3 71 47 64 82 58 61 61 35 52 36 57 62 63 54 52 21 78 100 24 94 4 80 99 62 43 72 21 70 90 4 23 14 72 4 76 49 71 96 96 99 78 7 32 11 14 61 19 69 1 68 100 77 86 54 14 86 47 53 30 88 67 66 61 70 17 63 40 5 99 53 38 31 91 18 41 5 77 61 53 30 87 21 23 54 52 17 23 75 58 99 99 63 20 1 78 72 28 11",
"output": "90"
},
{
"input": "100\n1 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100",
"output": "99"
},
{
"input": "94\n3 100 100 99 99 99 100 99 99 99 99 99 100 99 100 100 99 100 99 99 100 99 100 99 100 100 100 99 100 99 100 99 100 99 99 99 100 99 99 99 99 99 100 99 100 100 99 100 99 99 99 99 100 99 100 99 99 99 100 100 99 100 100 99 99 100 100 100 99 100 99 99 99 99 99 100 100 100 100 100 100 100 100 100 99 99 99 99 100 99 100 99 100 100",
"output": "97"
},
{
"input": "97\n99 99 98 98 100 98 99 99 98 100 100 100 99 99 100 99 99 98 99 99 98 98 98 100 100 99 98 99 100 98 99 98 98 100 98 99 100 98 98 99 98 98 99 98 100 99 99 99 99 98 98 98 100 99 100 100 99 99 100 99 99 98 98 98 100 100 98 100 100 99 98 99 100 98 98 98 98 99 99 98 98 99 100 100 98 98 99 98 99 100 98 99 100 98 99 99 100",
"output": "2"
},
{
"input": "100\n100 55 70 81 73 51 6 75 45 85 33 61 98 63 11 59 1 8 14 28 78 74 44 80 7 69 7 5 90 73 43 78 64 64 43 92 59 70 80 19 33 39 31 70 38 85 24 23 86 79 98 56 92 63 92 4 36 8 79 74 2 81 54 13 69 44 49 63 17 76 78 99 42 36 47 71 19 90 9 58 83 53 27 2 35 51 65 59 90 51 74 87 84 48 98 44 84 100 84 93",
"output": "1"
},
{
"input": "100\n100 637 498 246 615 901 724 673 793 33 282 908 477 185 185 969 34 859 90 70 107 492 227 918 919 131 620 182 802 703 779 184 403 891 448 499 628 553 905 392 70 396 8 575 66 908 992 496 792 174 667 355 836 610 855 377 244 827 836 808 667 354 800 114 746 556 75 894 162 367 99 718 394 273 833 776 151 433 315 470 759 12 552 613 85 793 775 649 225 86 296 624 557 201 209 595 697 527 282 168",
"output": "749"
},
{
"input": "100\n107 172 549 883 564 56 399 970 173 990 224 217 601 381 948 631 159 958 512 136 61 584 633 202 652 355 26 723 663 237 410 721 688 552 699 24 748 186 461 88 34 243 872 205 471 298 654 693 244 33 359 533 471 116 386 653 654 887 531 303 335 829 319 340 827 89 602 191 422 289 361 200 593 421 592 402 256 813 606 589 741 9 148 893 3 142 50 169 219 360 642 45 810 818 507 624 561 743 303 111",
"output": "729"
},
{
"input": "90\n670 694 651 729 579 539 568 551 707 638 604 544 502 531 775 805 558 655 506 729 802 778 653 737 591 770 594 535 588 604 658 713 779 705 504 563 513 651 529 572 505 553 515 750 621 574 727 774 714 725 665 798 670 747 751 635 755 798 635 717 583 682 517 546 740 802 743 507 658 700 645 671 533 594 506 633 768 584 672 666 703 522 530 501 592 528 678 708 619 786",
"output": "111"
},
{
"input": "90\n10 265 429 431 343 305 806 746 284 313 503 221 594 351 83 653 232 431 427 610 458 88 255 215 529 205 492 549 55 694 535 104 45 327 816 432 595 549 454 141 216 557 250 415 531 494 190 749 718 380 78 447 784 347 196 814 16 780 262 462 776 315 160 307 593 694 692 41 528 725 376 777 337 44 438 630 345 502 384 184 742 429 570 361 394 267 820 778 662 377",
"output": "714"
},
{
"input": "95\n800 280 176 472 587 763 588 838 760 378 667 231 566 278 713 305 354 815 140 220 188 409 109 180 251 268 474 590 853 143 235 691 313 785 386 92 783 471 43 342 718 592 678 404 256 362 239 504 163 85 521 81 356 73 754 589 380 159 196 862 838 509 149 42 366 630 467 292 698 123 187 796 576 37 689 800 186 518 488 432 159 860 349 799 282 304 880 283 23 312 55 507 734 370 490",
"output": "52"
},
{
"input": "100\n95 88 84 85 74 97 100 52 91 94 62 66 90 56 86 66 95 73 79 68 54 67 99 52 82 62 81 71 93 85 72 72 95 52 72 63 57 90 92 89 88 77 84 78 95 59 72 86 98 64 89 64 80 70 54 93 88 86 79 78 94 64 89 66 50 90 54 82 52 96 99 54 81 66 83 79 69 80 51 73 81 69 93 82 76 52 58 87 93 92 52 67 78 63 63 87 77 95 58 78",
"output": "4"
},
{
"input": "100\n1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000",
"output": "1"
},
{
"input": "100\n999 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000",
"output": "2"
},
{
"input": "100\n901 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000",
"output": "99"
},
{
"input": "4\n8 5 11 3",
"output": "2"
},
{
"input": "3\n3 10 1",
"output": "4"
}
] | 1,442,851,728
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 35
| 62
| 0
|
n = int(input())
a = input().split()
a = list(map(int, a))
votes = 0;
while(a[0] <= max(a[1:])):
votes += 1
a[0] += 1
a[a[1:].index(max(a[1:])) + 1] -= 1
print(votes)
|
Title: Bear and Elections
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a grizzly bear who desires power and adoration. He wants to win in upcoming elections and rule over the Bearland.
There are *n* candidates, including Limak. We know how many citizens are going to vote for each candidate. Now *i*-th candidate would get *a**i* votes. Limak is candidate number 1. To win in elections, he must get strictly more votes than any other candidate.
Victory is more important than everything else so Limak decided to cheat. He will steal votes from his opponents by bribing some citizens. To bribe a citizen, Limak must give him or her one candy - citizens are bears and bears like candies. Limak doesn't have many candies and wonders - how many citizens does he have to bribe?
Input Specification:
The first line contains single integer *n* (2<=≤<=*n*<=≤<=100) - number of candidates.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) - number of votes for each candidate. Limak is candidate number 1.
Note that after bribing number of votes for some candidate might be zero or might be greater than 1000.
Output Specification:
Print the minimum number of citizens Limak must bribe to have strictly more votes than any other candidate.
Demo Input:
['5\n5 1 11 2 8\n', '4\n1 8 8 8\n', '2\n7 6\n']
Demo Output:
['4\n', '6\n', '0\n']
Note:
In the first sample Limak has 5 votes. One of the ways to achieve victory is to bribe 4 citizens who want to vote for the third candidate. Then numbers of votes would be 9, 1, 7, 2, 8 (Limak would have 9 votes). Alternatively, Limak could steal only 3 votes from the third candidate and 1 vote from the second candidate to get situation 9, 0, 8, 2, 8.
In the second sample Limak will steal 2 votes from each candidate. Situation will be 7, 6, 6, 6.
In the third sample Limak is a winner without bribing any citizen.
|
```python
n = int(input())
a = input().split()
a = list(map(int, a))
votes = 0;
while(a[0] <= max(a[1:])):
votes += 1
a[0] += 1
a[a[1:].index(max(a[1:])) + 1] -= 1
print(votes)
```
| 3
|
|
471
|
A
|
MUH and Sticks
|
PROGRAMMING
| 1,100
|
[
"implementation"
] | null | null |
Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an elephant or a bear from those sticks. They can make an animal from sticks in the following way:
- Four sticks represent the animal's legs, these sticks should have the same length. - Two remaining sticks represent the animal's head and body. The bear's head stick must be shorter than the body stick. The elephant, however, has a long trunk, so his head stick must be as long as the body stick. Note that there are no limits on the relations between the leg sticks and the head and body sticks.
Your task is to find out which animal can be made from the given stick set. The zoo keeper wants the sticks back after the game, so they must never be broken, even bears understand it.
|
The single line contains six space-separated integers *l**i* (1<=≤<=*l**i*<=≤<=9) — the lengths of the six sticks. It is guaranteed that the input is such that you cannot make both animals from the sticks.
|
If you can make a bear from the given set, print string "Bear" (without the quotes). If you can make an elephant, print string "Elephant" (wıthout the quotes). If you can make neither a bear nor an elephant, print string "Alien" (without the quotes).
|
[
"4 2 5 4 4 4\n",
"4 4 5 4 4 5\n",
"1 2 3 4 5 6\n"
] |
[
"Bear",
"Elephant",
"Alien"
] |
If you're out of creative ideas, see instructions below which show how to make a bear and an elephant in the first two samples. The stick of length 2 is in red, the sticks of length 4 are in green, the sticks of length 5 are in blue.
| 500
|
[
{
"input": "4 2 5 4 4 4",
"output": "Bear"
},
{
"input": "4 4 5 4 4 5",
"output": "Elephant"
},
{
"input": "1 2 3 4 5 6",
"output": "Alien"
},
{
"input": "5 5 5 5 5 5",
"output": "Elephant"
},
{
"input": "1 1 1 2 3 5",
"output": "Alien"
},
{
"input": "1 1 1 1 1 1",
"output": "Elephant"
},
{
"input": "9 9 9 9 9 9",
"output": "Elephant"
},
{
"input": "1 8 9 1 1 1",
"output": "Bear"
},
{
"input": "9 9 9 1 9 9",
"output": "Bear"
},
{
"input": "1 2 3 8 9 7",
"output": "Alien"
},
{
"input": "5 5 5 6 6 6",
"output": "Alien"
},
{
"input": "1 1 2 2 3 4",
"output": "Alien"
},
{
"input": "4 4 4 4 4 2",
"output": "Bear"
},
{
"input": "2 2 3 3 4 4",
"output": "Alien"
},
{
"input": "4 4 4 4 4 5",
"output": "Bear"
},
{
"input": "1 1 2 2 2 2",
"output": "Elephant"
},
{
"input": "1 2 5 5 5 5",
"output": "Bear"
},
{
"input": "4 4 2 2 2 2",
"output": "Elephant"
},
{
"input": "1 1 1 1 1 2",
"output": "Bear"
},
{
"input": "2 2 4 4 4 4",
"output": "Elephant"
},
{
"input": "4 4 4 4 4 3",
"output": "Bear"
},
{
"input": "4 4 5 6 7 8",
"output": "Alien"
},
{
"input": "4 4 4 4 2 2",
"output": "Elephant"
},
{
"input": "1 1 1 1 2 2",
"output": "Elephant"
},
{
"input": "1 1 3 3 3 5",
"output": "Alien"
},
{
"input": "1 2 2 3 3 3",
"output": "Alien"
},
{
"input": "1 2 2 2 2 2",
"output": "Bear"
},
{
"input": "1 3 3 3 4 5",
"output": "Alien"
},
{
"input": "5 1 1 1 1 1",
"output": "Bear"
}
] | 1,530,015,693
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 29
| 93
| 204,800
|
from collections import Counter
c = Counter(input().split()).values()
if max(c) < 4:
print('Alien')
elif min(c) in (2, 6):
print('Elephant')
else:
print('Bear')
|
Title: MUH and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an elephant or a bear from those sticks. They can make an animal from sticks in the following way:
- Four sticks represent the animal's legs, these sticks should have the same length. - Two remaining sticks represent the animal's head and body. The bear's head stick must be shorter than the body stick. The elephant, however, has a long trunk, so his head stick must be as long as the body stick. Note that there are no limits on the relations between the leg sticks and the head and body sticks.
Your task is to find out which animal can be made from the given stick set. The zoo keeper wants the sticks back after the game, so they must never be broken, even bears understand it.
Input Specification:
The single line contains six space-separated integers *l**i* (1<=≤<=*l**i*<=≤<=9) — the lengths of the six sticks. It is guaranteed that the input is such that you cannot make both animals from the sticks.
Output Specification:
If you can make a bear from the given set, print string "Bear" (without the quotes). If you can make an elephant, print string "Elephant" (wıthout the quotes). If you can make neither a bear nor an elephant, print string "Alien" (without the quotes).
Demo Input:
['4 2 5 4 4 4\n', '4 4 5 4 4 5\n', '1 2 3 4 5 6\n']
Demo Output:
['Bear', 'Elephant', 'Alien']
Note:
If you're out of creative ideas, see instructions below which show how to make a bear and an elephant in the first two samples. The stick of length 2 is in red, the sticks of length 4 are in green, the sticks of length 5 are in blue.
|
```python
from collections import Counter
c = Counter(input().split()).values()
if max(c) < 4:
print('Alien')
elif min(c) in (2, 6):
print('Elephant')
else:
print('Bear')
```
| 3
|
|
214
|
A
|
System of Equations
|
PROGRAMMING
| 800
|
[
"brute force"
] | null | null |
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of integers (*a*,<=*b*) (0<=≤<=*a*,<=*b*) which satisfy the system.
|
A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space.
|
On a single line print the answer to the problem.
|
[
"9 3\n",
"14 28\n",
"4 20\n"
] |
[
"1\n",
"1\n",
"0\n"
] |
In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair.
| 500
|
[
{
"input": "9 3",
"output": "1"
},
{
"input": "14 28",
"output": "1"
},
{
"input": "4 20",
"output": "0"
},
{
"input": "18 198",
"output": "1"
},
{
"input": "22 326",
"output": "1"
},
{
"input": "26 104",
"output": "1"
},
{
"input": "14 10",
"output": "0"
},
{
"input": "8 20",
"output": "0"
},
{
"input": "2 8",
"output": "0"
},
{
"input": "20 11",
"output": "0"
},
{
"input": "57 447",
"output": "1"
},
{
"input": "1 1",
"output": "2"
},
{
"input": "66 296",
"output": "1"
},
{
"input": "75 683",
"output": "1"
},
{
"input": "227 975",
"output": "1"
},
{
"input": "247 499",
"output": "1"
},
{
"input": "266 116",
"output": "1"
},
{
"input": "286 916",
"output": "1"
},
{
"input": "307 341",
"output": "1"
},
{
"input": "451 121",
"output": "1"
},
{
"input": "471 921",
"output": "1"
},
{
"input": "502 346",
"output": "1"
},
{
"input": "535 59",
"output": "1"
},
{
"input": "555 699",
"output": "1"
},
{
"input": "747 351",
"output": "1"
},
{
"input": "790 64",
"output": "1"
},
{
"input": "810 704",
"output": "1"
},
{
"input": "855 225",
"output": "1"
},
{
"input": "902 34",
"output": "1"
},
{
"input": "922 514",
"output": "1"
},
{
"input": "971 131",
"output": "1"
},
{
"input": "991 931",
"output": "1"
},
{
"input": "840 780",
"output": "0"
},
{
"input": "102 595",
"output": "0"
},
{
"input": "139 433",
"output": "0"
},
{
"input": "968 288",
"output": "0"
},
{
"input": "563 354",
"output": "0"
},
{
"input": "994 975",
"output": "0"
},
{
"input": "456 221",
"output": "0"
},
{
"input": "205 210",
"output": "0"
},
{
"input": "1 11",
"output": "0"
},
{
"input": "1000 1000",
"output": "0"
},
{
"input": "3 3",
"output": "0"
},
{
"input": "11 99",
"output": "0"
},
{
"input": "2 2",
"output": "1"
},
{
"input": "11 1",
"output": "0"
},
{
"input": "6 6",
"output": "1"
},
{
"input": "100 452",
"output": "0"
},
{
"input": "420 380",
"output": "0"
},
{
"input": "31 31",
"output": "0"
},
{
"input": "2 6",
"output": "0"
},
{
"input": "112 134",
"output": "0"
},
{
"input": "13 13",
"output": "0"
},
{
"input": "1 571",
"output": "0"
}
] | 1,643,035,656
| 2,147,483,647
|
PyPy 3-64
|
WRONG_ANSWER
|
TESTS
| 11
| 186
| 2,355,200
|
import math
def main_function():
n, m = [int(u) for u in input().split(" ")]
counter = 0
for i in range(1001):
for j in range(min(n, m)):
if i ** 2 + j == n and i + j ** 2 == m:
counter += 1
print(counter)
main_function()
|
Title: System of Equations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of integers (*a*,<=*b*) (0<=≤<=*a*,<=*b*) which satisfy the system.
Input Specification:
A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space.
Output Specification:
On a single line print the answer to the problem.
Demo Input:
['9 3\n', '14 28\n', '4 20\n']
Demo Output:
['1\n', '1\n', '0\n']
Note:
In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair.
|
```python
import math
def main_function():
n, m = [int(u) for u in input().split(" ")]
counter = 0
for i in range(1001):
for j in range(min(n, m)):
if i ** 2 + j == n and i + j ** 2 == m:
counter += 1
print(counter)
main_function()
```
| 0
|
|
365
|
A
|
Good Number
|
PROGRAMMING
| 1,100
|
[
"implementation"
] | null | null |
Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number every time it occurs in array *a*).
|
The first line contains integers *n* and *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=9). The *i*-th of the following *n* lines contains integer *a**i* without leading zeroes (1<=≤<=*a**i*<=≤<=109).
|
Print a single integer — the number of *k*-good numbers in *a*.
|
[
"10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n",
"2 1\n1\n10\n"
] |
[
"10\n",
"1\n"
] |
none
| 500
|
[
{
"input": "10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560",
"output": "10"
},
{
"input": "2 1\n1\n10",
"output": "1"
},
{
"input": "1 0\n1000000000",
"output": "1"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
"input": "6 0\n10\n102\n120\n1032\n1212103\n1999999",
"output": "5"
},
{
"input": "1 3\n1000000000",
"output": "0"
},
{
"input": "1 9\n1000000000",
"output": "0"
},
{
"input": "1 0\n1",
"output": "0"
},
{
"input": "1 1\n1",
"output": "0"
},
{
"input": "1 3\n1",
"output": "0"
},
{
"input": "1 9\n1",
"output": "0"
},
{
"input": "2 8\n123456780\n123",
"output": "1"
},
{
"input": "2 8\n12345678\n1230",
"output": "0"
},
{
"input": "6 1\n10\n102\n120\n1032\n1212103\n1999999",
"output": "5"
},
{
"input": "6 2\n10\n102\n120\n1032\n1212103\n1999999",
"output": "4"
},
{
"input": "6 3\n10\n102\n120\n1032\n1212103\n1999999",
"output": "2"
},
{
"input": "6 9\n10\n102\n120\n1032\n1212103\n1999999",
"output": "0"
},
{
"input": "1 2\n2220",
"output": "0"
}
] | 1,676,567,777
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 2
| 46
| 0
|
s=list(map(int,input().split()))
n=0
x=0
z=0
for i in range(s[1]+1):
n+=1
for j in range(s[0]):
x=0
b=input()
c=sorted(b)
for k in c:
x+=1
if x==n:
z+=1
print(z)
|
Title: Good Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number every time it occurs in array *a*).
Input Specification:
The first line contains integers *n* and *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=9). The *i*-th of the following *n* lines contains integer *a**i* without leading zeroes (1<=≤<=*a**i*<=≤<=109).
Output Specification:
Print a single integer — the number of *k*-good numbers in *a*.
Demo Input:
['10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n', '2 1\n1\n10\n']
Demo Output:
['10\n', '1\n']
Note:
none
|
```python
s=list(map(int,input().split()))
n=0
x=0
z=0
for i in range(s[1]+1):
n+=1
for j in range(s[0]):
x=0
b=input()
c=sorted(b)
for k in c:
x+=1
if x==n:
z+=1
print(z)
```
| 0
|
|
34
|
A
|
Reconnaissance 2
|
PROGRAMMING
| 800
|
[
"implementation"
] |
A. Reconnaissance 2
|
2
|
256
|
*n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a reconnaissance unit.
|
The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). The soldier heights are given in clockwise or counterclockwise direction.
|
Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle.
|
[
"5\n10 12 13 15 10\n",
"4\n10 20 30 40\n"
] |
[
"5 1\n",
"1 2\n"
] |
none
| 500
|
[
{
"input": "5\n10 12 13 15 10",
"output": "5 1"
},
{
"input": "4\n10 20 30 40",
"output": "1 2"
},
{
"input": "6\n744 359 230 586 944 442",
"output": "2 3"
},
{
"input": "5\n826 747 849 687 437",
"output": "1 2"
},
{
"input": "5\n999 999 993 969 999",
"output": "1 2"
},
{
"input": "5\n4 24 6 1 15",
"output": "3 4"
},
{
"input": "2\n511 32",
"output": "1 2"
},
{
"input": "3\n907 452 355",
"output": "2 3"
},
{
"input": "4\n303 872 764 401",
"output": "4 1"
},
{
"input": "10\n684 698 429 694 956 812 594 170 937 764",
"output": "1 2"
},
{
"input": "20\n646 840 437 946 640 564 936 917 487 752 844 734 468 969 674 646 728 642 514 695",
"output": "7 8"
},
{
"input": "30\n996 999 998 984 989 1000 996 993 1000 983 992 999 999 1000 979 992 987 1000 996 1000 1000 989 981 996 995 999 999 989 999 1000",
"output": "12 13"
},
{
"input": "50\n93 27 28 4 5 78 59 24 19 134 31 128 118 36 90 32 32 1 44 32 33 13 31 10 12 25 38 50 25 12 4 22 28 53 48 83 4 25 57 31 71 24 8 7 28 86 23 80 101 58",
"output": "16 17"
},
{
"input": "88\n1000 1000 1000 1000 1000 998 998 1000 1000 1000 1000 999 999 1000 1000 1000 999 1000 997 999 997 1000 999 998 1000 999 1000 1000 1000 999 1000 999 999 1000 1000 999 1000 999 1000 1000 998 1000 1000 1000 998 998 1000 1000 999 1000 1000 1000 1000 1000 1000 1000 998 1000 1000 1000 999 1000 1000 999 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 998 1000 1000 1000 998 1000 1000 998 1000 999 1000 1000 1000 1000",
"output": "1 2"
},
{
"input": "99\n4 4 21 6 5 3 13 2 6 1 3 4 1 3 1 9 11 1 6 17 4 5 20 4 1 9 5 11 3 4 14 1 3 3 1 4 3 5 27 1 1 2 10 7 11 4 19 7 11 6 11 13 3 1 10 7 2 1 16 1 9 4 29 13 2 12 14 2 21 1 9 8 26 12 12 5 2 14 7 8 8 8 9 4 12 2 6 6 7 16 8 14 2 10 20 15 3 7 4",
"output": "1 2"
},
{
"input": "100\n713 572 318 890 577 657 646 146 373 783 392 229 455 871 20 593 573 336 26 381 280 916 907 732 820 713 111 840 570 446 184 711 481 399 788 647 492 15 40 530 549 506 719 782 126 20 778 996 712 761 9 74 812 418 488 175 103 585 900 3 604 521 109 513 145 708 990 361 682 827 791 22 596 780 596 385 450 643 158 496 876 975 319 783 654 895 891 361 397 81 682 899 347 623 809 557 435 279 513 438",
"output": "86 87"
},
{
"input": "100\n31 75 86 68 111 27 22 22 26 30 54 163 107 75 160 122 14 23 17 26 27 20 43 58 59 71 21 148 9 32 43 91 133 286 132 70 90 156 84 14 77 93 23 18 13 72 18 131 33 28 72 175 30 86 249 20 14 208 28 57 63 199 6 10 24 30 62 267 43 479 60 28 138 1 45 3 19 47 7 166 116 117 50 140 28 14 95 85 93 43 61 15 2 70 10 51 7 95 9 25",
"output": "7 8"
},
{
"input": "100\n896 898 967 979 973 709 961 968 806 967 896 967 826 975 936 903 986 856 851 931 852 971 786 837 949 978 686 936 952 909 965 749 908 916 943 973 983 975 939 886 964 928 960 976 907 788 994 773 949 871 947 980 945 985 726 981 887 943 907 990 931 874 840 867 948 951 961 904 888 901 976 967 994 921 828 970 972 722 755 970 860 855 914 869 714 899 969 978 898 862 642 939 904 936 819 934 884 983 955 964",
"output": "1 2"
},
{
"input": "100\n994 927 872 970 815 986 952 996 965 1000 877 986 978 999 950 990 936 997 993 960 921 860 895 869 943 998 983 968 973 953 999 990 995 871 853 979 973 963 953 938 997 989 993 964 960 973 946 975 1000 962 920 746 989 957 904 965 920 979 966 961 1000 993 975 952 846 971 991 979 985 969 984 973 956 1000 952 778 983 974 956 927 995 997 980 997 1000 970 960 970 988 983 947 904 935 972 1000 863 992 996 932 967",
"output": "81 82"
},
{
"input": "100\n48 108 63 21 27 8 49 21 75 8 24 42 149 18 8 28 21 18 25 35 59 70 59 33 40 1 67 34 120 82 4 115 72 87 3 15 15 63 37 12 40 27 83 14 38 20 14 58 93 10 31 3 39 6 197 77 54 16 31 146 9 49 14 8 77 82 5 11 80 116 8 61 50 24 7 103 29 11 3 3 1 12 46 24 21 131 39 29 36 2 107 40 16 99 31 41 29 48 17 17",
"output": "36 37"
}
] | 1,580,485,066
| 2,147,483,647
|
PyPy 3
|
WRONG_ANSWER
|
TESTS
| 5
| 278
| 0
|
n=int(input())
A=list(map(int,input().split()))
Min=abs(A[1]-A[0])
index=[1,2]
for i in range(1,n):
if abs(A[i]-A[i-1])<Min:
Min=A[i]-A[i-1]
index[0]=i
index[1]=i+1
if abs(A[n-1]-A[0])<Min:
Min=A[i]-A[i-1]
index[0]=n
index[1]=1
for i in index:
print(i,end=' ')
|
Title: Reconnaissance 2
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
*n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a reconnaissance unit.
Input Specification:
The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). The soldier heights are given in clockwise or counterclockwise direction.
Output Specification:
Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle.
Demo Input:
['5\n10 12 13 15 10\n', '4\n10 20 30 40\n']
Demo Output:
['5 1\n', '1 2\n']
Note:
none
|
```python
n=int(input())
A=list(map(int,input().split()))
Min=abs(A[1]-A[0])
index=[1,2]
for i in range(1,n):
if abs(A[i]-A[i-1])<Min:
Min=A[i]-A[i-1]
index[0]=i
index[1]=i+1
if abs(A[n-1]-A[0])<Min:
Min=A[i]-A[i-1]
index[0]=n
index[1]=1
for i in index:
print(i,end=' ')
```
| 0
|
609
|
A
|
USB Flash Drives
|
PROGRAMMING
| 800
|
[
"greedy",
"implementation",
"sortings"
] | null | null |
Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives.
|
The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of USB flash drives.
The second line contains positive integer *m* (1<=≤<=*m*<=≤<=105) — the size of Sean's file.
Each of the next *n* lines contains positive integer *a**i* (1<=≤<=*a**i*<=≤<=1000) — the sizes of USB flash drives in megabytes.
It is guaranteed that the answer exists, i. e. the sum of all *a**i* is not less than *m*.
|
Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives.
|
[
"3\n5\n2\n1\n3\n",
"3\n6\n2\n3\n2\n",
"2\n5\n5\n10\n"
] |
[
"2\n",
"3\n",
"1\n"
] |
In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second.
| 0
|
[
{
"input": "3\n5\n2\n1\n3",
"output": "2"
},
{
"input": "3\n6\n2\n3\n2",
"output": "3"
},
{
"input": "2\n5\n5\n10",
"output": "1"
},
{
"input": "5\n16\n8\n1\n3\n4\n9",
"output": "2"
},
{
"input": "10\n121\n10\n37\n74\n56\n42\n39\n6\n68\n8\n100",
"output": "2"
},
{
"input": "12\n4773\n325\n377\n192\n780\n881\n816\n839\n223\n215\n125\n952\n8",
"output": "7"
},
{
"input": "15\n7758\n182\n272\n763\n910\n24\n359\n583\n890\n735\n819\n66\n992\n440\n496\n227",
"output": "15"
},
{
"input": "30\n70\n6\n2\n10\n4\n7\n10\n5\n1\n8\n10\n4\n3\n5\n9\n3\n6\n6\n4\n2\n6\n5\n10\n1\n9\n7\n2\n1\n10\n7\n5",
"output": "8"
},
{
"input": "40\n15705\n702\n722\n105\n873\n417\n477\n794\n300\n869\n496\n572\n232\n456\n298\n473\n584\n486\n713\n934\n121\n303\n956\n934\n840\n358\n201\n861\n497\n131\n312\n957\n96\n914\n509\n60\n300\n722\n658\n820\n103",
"output": "21"
},
{
"input": "50\n18239\n300\n151\n770\n9\n200\n52\n247\n753\n523\n263\n744\n463\n540\n244\n608\n569\n771\n32\n425\n777\n624\n761\n628\n124\n405\n396\n726\n626\n679\n237\n229\n49\n512\n18\n671\n290\n768\n632\n739\n18\n136\n413\n117\n83\n413\n452\n767\n664\n203\n404",
"output": "31"
},
{
"input": "70\n149\n5\n3\n3\n4\n6\n1\n2\n9\n8\n3\n1\n8\n4\n4\n3\n6\n10\n7\n1\n10\n8\n4\n9\n3\n8\n3\n2\n5\n1\n8\n6\n9\n10\n4\n8\n6\n9\n9\n9\n3\n4\n2\n2\n5\n8\n9\n1\n10\n3\n4\n3\n1\n9\n3\n5\n1\n3\n7\n6\n9\n8\n9\n1\n7\n4\n4\n2\n3\n5\n7",
"output": "17"
},
{
"input": "70\n2731\n26\n75\n86\n94\n37\n25\n32\n35\n92\n1\n51\n73\n53\n66\n16\n80\n15\n81\n100\n87\n55\n48\n30\n71\n39\n87\n77\n25\n70\n22\n75\n23\n97\n16\n75\n95\n61\n61\n28\n10\n78\n54\n80\n51\n25\n24\n90\n58\n4\n77\n40\n54\n53\n47\n62\n30\n38\n71\n97\n71\n60\n58\n1\n21\n15\n55\n99\n34\n88\n99",
"output": "35"
},
{
"input": "70\n28625\n34\n132\n181\n232\n593\n413\n862\n887\n808\n18\n35\n89\n356\n640\n339\n280\n975\n82\n345\n398\n948\n372\n91\n755\n75\n153\n948\n603\n35\n694\n722\n293\n363\n884\n264\n813\n175\n169\n646\n138\n449\n488\n828\n417\n134\n84\n763\n288\n845\n801\n556\n972\n332\n564\n934\n699\n842\n942\n644\n203\n406\n140\n37\n9\n423\n546\n675\n491\n113\n587",
"output": "45"
},
{
"input": "80\n248\n3\n9\n4\n5\n10\n7\n2\n6\n2\n2\n8\n2\n1\n3\n7\n9\n2\n8\n4\n4\n8\n5\n4\n4\n10\n2\n1\n4\n8\n4\n10\n1\n2\n10\n2\n3\n3\n1\n1\n8\n9\n5\n10\n2\n8\n10\n5\n3\n6\n1\n7\n8\n9\n10\n5\n10\n10\n2\n10\n1\n2\n4\n1\n9\n4\n7\n10\n8\n5\n8\n1\n4\n2\n2\n3\n9\n9\n9\n10\n6",
"output": "27"
},
{
"input": "80\n2993\n18\n14\n73\n38\n14\n73\n77\n18\n81\n6\n96\n65\n77\n86\n76\n8\n16\n81\n83\n83\n34\n69\n58\n15\n19\n1\n16\n57\n95\n35\n5\n49\n8\n15\n47\n84\n99\n94\n93\n55\n43\n47\n51\n61\n57\n13\n7\n92\n14\n4\n83\n100\n60\n75\n41\n95\n74\n40\n1\n4\n95\n68\n59\n65\n15\n15\n75\n85\n46\n77\n26\n30\n51\n64\n75\n40\n22\n88\n68\n24",
"output": "38"
},
{
"input": "80\n37947\n117\n569\n702\n272\n573\n629\n90\n337\n673\n589\n576\n205\n11\n284\n645\n719\n777\n271\n567\n466\n251\n402\n3\n97\n288\n699\n208\n173\n530\n782\n266\n395\n957\n159\n463\n43\n316\n603\n197\n386\n132\n799\n778\n905\n784\n71\n851\n963\n883\n705\n454\n275\n425\n727\n223\n4\n870\n833\n431\n463\n85\n505\n800\n41\n954\n981\n242\n578\n336\n48\n858\n702\n349\n929\n646\n528\n993\n506\n274\n227",
"output": "70"
},
{
"input": "90\n413\n5\n8\n10\n7\n5\n7\n5\n7\n1\n7\n8\n4\n3\n9\n4\n1\n10\n3\n1\n10\n9\n3\n1\n8\n4\n7\n5\n2\n9\n3\n10\n10\n3\n6\n3\n3\n10\n7\n5\n1\n1\n2\n4\n8\n2\n5\n5\n3\n9\n5\n5\n3\n10\n2\n3\n8\n5\n9\n1\n3\n6\n5\n9\n2\n3\n7\n10\n3\n4\n4\n1\n5\n9\n2\n6\n9\n1\n1\n9\n9\n7\n7\n7\n8\n4\n5\n3\n4\n6\n9",
"output": "59"
},
{
"input": "90\n4226\n33\n43\n83\n46\n75\n14\n88\n36\n8\n25\n47\n4\n96\n19\n33\n49\n65\n17\n59\n72\n1\n55\n94\n92\n27\n33\n39\n14\n62\n79\n12\n89\n22\n86\n13\n19\n77\n53\n96\n74\n24\n25\n17\n64\n71\n81\n87\n52\n72\n55\n49\n74\n36\n65\n86\n91\n33\n61\n97\n38\n87\n61\n14\n73\n95\n43\n67\n42\n67\n22\n12\n62\n32\n96\n24\n49\n82\n46\n89\n36\n75\n91\n11\n10\n9\n33\n86\n28\n75\n39",
"output": "64"
},
{
"input": "90\n40579\n448\n977\n607\n745\n268\n826\n479\n59\n330\n609\n43\n301\n970\n726\n172\n632\n600\n181\n712\n195\n491\n312\n849\n722\n679\n682\n780\n131\n404\n293\n387\n567\n660\n54\n339\n111\n833\n612\n911\n869\n356\n884\n635\n126\n639\n712\n473\n663\n773\n435\n32\n973\n484\n662\n464\n699\n274\n919\n95\n904\n253\n589\n543\n454\n250\n349\n237\n829\n511\n536\n36\n45\n152\n626\n384\n199\n877\n941\n84\n781\n115\n20\n52\n726\n751\n920\n291\n571\n6\n199",
"output": "64"
},
{
"input": "100\n66\n7\n9\n10\n5\n2\n8\n6\n5\n4\n10\n10\n6\n5\n2\n2\n1\n1\n5\n8\n7\n8\n10\n5\n6\n6\n5\n9\n9\n6\n3\n8\n7\n10\n5\n9\n6\n7\n3\n5\n8\n6\n8\n9\n1\n1\n1\n2\n4\n5\n5\n1\n1\n2\n6\n7\n1\n5\n8\n7\n2\n1\n7\n10\n9\n10\n2\n4\n10\n4\n10\n10\n5\n3\n9\n1\n2\n1\n10\n5\n1\n7\n4\n4\n5\n7\n6\n10\n4\n7\n3\n4\n3\n6\n2\n5\n2\n4\n9\n5\n3",
"output": "7"
},
{
"input": "100\n4862\n20\n47\n85\n47\n76\n38\n48\n93\n91\n81\n31\n51\n23\n60\n59\n3\n73\n72\n57\n67\n54\n9\n42\n5\n32\n46\n72\n79\n95\n61\n79\n88\n33\n52\n97\n10\n3\n20\n79\n82\n93\n90\n38\n80\n18\n21\n43\n60\n73\n34\n75\n65\n10\n84\n100\n29\n94\n56\n22\n59\n95\n46\n22\n57\n69\n67\n90\n11\n10\n61\n27\n2\n48\n69\n86\n91\n69\n76\n36\n71\n18\n54\n90\n74\n69\n50\n46\n8\n5\n41\n96\n5\n14\n55\n85\n39\n6\n79\n75\n87",
"output": "70"
},
{
"input": "100\n45570\n14\n881\n678\n687\n993\n413\n760\n451\n426\n787\n503\n343\n234\n530\n294\n725\n941\n524\n574\n441\n798\n399\n360\n609\n376\n525\n229\n995\n478\n347\n47\n23\n468\n525\n749\n601\n235\n89\n995\n489\n1\n239\n415\n122\n671\n128\n357\n886\n401\n964\n212\n968\n210\n130\n871\n360\n661\n844\n414\n187\n21\n824\n266\n713\n126\n496\n916\n37\n193\n755\n894\n641\n300\n170\n176\n383\n488\n627\n61\n897\n33\n242\n419\n881\n698\n107\n391\n418\n774\n905\n87\n5\n896\n835\n318\n373\n916\n393\n91\n460",
"output": "78"
},
{
"input": "100\n522\n1\n5\n2\n4\n2\n6\n3\n4\n2\n10\n10\n6\n7\n9\n7\n1\n7\n2\n5\n3\n1\n5\n2\n3\n5\n1\n7\n10\n10\n4\n4\n10\n9\n10\n6\n2\n8\n2\n6\n10\n9\n2\n7\n5\n9\n4\n6\n10\n7\n3\n1\n1\n9\n5\n10\n9\n2\n8\n3\n7\n5\n4\n7\n5\n9\n10\n6\n2\n9\n2\n5\n10\n1\n7\n7\n10\n5\n6\n2\n9\n4\n7\n10\n10\n8\n3\n4\n9\n3\n6\n9\n10\n2\n9\n9\n3\n4\n1\n10\n2",
"output": "74"
},
{
"input": "100\n32294\n414\n116\n131\n649\n130\n476\n630\n605\n213\n117\n757\n42\n109\n85\n127\n635\n629\n994\n410\n764\n204\n161\n231\n577\n116\n936\n537\n565\n571\n317\n722\n819\n229\n284\n487\n649\n304\n628\n727\n816\n854\n91\n111\n549\n87\n374\n417\n3\n868\n882\n168\n743\n77\n534\n781\n75\n956\n910\n734\n507\n568\n802\n946\n891\n659\n116\n678\n375\n380\n430\n627\n873\n350\n930\n285\n6\n183\n96\n517\n81\n794\n235\n360\n551\n6\n28\n799\n226\n996\n894\n981\n551\n60\n40\n460\n479\n161\n318\n952\n433",
"output": "42"
},
{
"input": "100\n178\n71\n23\n84\n98\n8\n14\n4\n42\n56\n83\n87\n28\n22\n32\n50\n5\n96\n90\n1\n59\n74\n56\n96\n77\n88\n71\n38\n62\n36\n85\n1\n97\n98\n98\n32\n99\n42\n6\n81\n20\n49\n57\n71\n66\n9\n45\n41\n29\n28\n32\n68\n38\n29\n35\n29\n19\n27\n76\n85\n68\n68\n41\n32\n78\n72\n38\n19\n55\n83\n83\n25\n46\n62\n48\n26\n53\n14\n39\n31\n94\n84\n22\n39\n34\n96\n63\n37\n42\n6\n78\n76\n64\n16\n26\n6\n79\n53\n24\n29\n63",
"output": "2"
},
{
"input": "100\n885\n226\n266\n321\n72\n719\n29\n121\n533\n85\n672\n225\n830\n783\n822\n30\n791\n618\n166\n487\n922\n434\n814\n473\n5\n741\n947\n910\n305\n998\n49\n945\n588\n868\n809\n803\n168\n280\n614\n434\n634\n538\n591\n437\n540\n445\n313\n177\n171\n799\n778\n55\n617\n554\n583\n611\n12\n94\n599\n182\n765\n556\n965\n542\n35\n460\n177\n313\n485\n744\n384\n21\n52\n879\n792\n411\n614\n811\n565\n695\n428\n587\n631\n794\n461\n258\n193\n696\n936\n646\n756\n267\n55\n690\n730\n742\n734\n988\n235\n762\n440",
"output": "1"
},
{
"input": "100\n29\n9\n2\n10\n8\n6\n7\n7\n3\n3\n10\n4\n5\n2\n5\n1\n6\n3\n2\n5\n10\n10\n9\n1\n4\n5\n2\n2\n3\n1\n2\n2\n9\n6\n9\n7\n8\n8\n1\n5\n5\n3\n1\n5\n6\n1\n9\n2\n3\n8\n10\n8\n3\n2\n7\n1\n2\n1\n2\n8\n10\n5\n2\n3\n1\n10\n7\n1\n7\n4\n9\n6\n6\n4\n7\n1\n2\n7\n7\n9\n9\n7\n10\n4\n10\n8\n2\n1\n5\n5\n10\n5\n8\n1\n5\n6\n5\n1\n5\n6\n8",
"output": "3"
},
{
"input": "100\n644\n94\n69\n43\n36\n54\n93\n30\n74\n56\n95\n70\n49\n11\n36\n57\n30\n59\n3\n52\n59\n90\n82\n39\n67\n32\n8\n80\n64\n8\n65\n51\n48\n89\n90\n35\n4\n54\n66\n96\n68\n90\n30\n4\n13\n97\n41\n90\n85\n17\n45\n94\n31\n58\n4\n39\n76\n95\n92\n59\n67\n46\n96\n55\n82\n64\n20\n20\n83\n46\n37\n15\n60\n37\n79\n45\n47\n63\n73\n76\n31\n52\n36\n32\n49\n26\n61\n91\n31\n25\n62\n90\n65\n65\n5\n94\n7\n15\n97\n88\n68",
"output": "7"
},
{
"input": "100\n1756\n98\n229\n158\n281\n16\n169\n149\n239\n235\n182\n147\n215\n49\n270\n194\n242\n295\n289\n249\n19\n12\n144\n157\n92\n270\n122\n212\n97\n152\n14\n42\n12\n198\n98\n295\n154\n229\n191\n294\n5\n156\n43\n185\n184\n20\n125\n23\n10\n257\n244\n264\n79\n46\n277\n13\n22\n97\n212\n77\n293\n20\n51\n17\n109\n37\n68\n117\n51\n248\n10\n149\n179\n192\n239\n161\n13\n173\n297\n73\n43\n109\n288\n198\n81\n70\n254\n187\n277\n1\n295\n113\n95\n291\n293\n119\n205\n191\n37\n34\n116",
"output": "6"
},
{
"input": "100\n20562\n721\n452\n11\n703\n376\n183\n197\n203\n406\n642\n346\n446\n256\n760\n201\n360\n702\n707\n388\n779\n653\n610\n497\n768\n670\n134\n780\n306\n661\n180\n259\n256\n362\n6\n121\n415\n747\n170\n67\n439\n728\n193\n622\n481\n38\n225\n343\n303\n253\n436\n305\n68\n794\n247\n291\n600\n750\n188\n199\n757\n28\n776\n749\n253\n351\n53\n629\n129\n578\n209\n89\n651\n262\n638\n353\n469\n31\n144\n460\n176\n535\n562\n366\n639\n234\n577\n364\n761\n617\n303\n450\n778\n311\n289\n221\n274\n239\n626\n194\n36",
"output": "30"
},
{
"input": "100\n32630\n548\n21\n756\n138\n56\n719\n97\n86\n599\n531\n464\n137\n737\n239\n626\n179\n170\n271\n335\n178\n298\n597\n616\n104\n190\n216\n333\n606\n621\n310\n70\n286\n593\n655\n472\n556\n77\n625\n744\n395\n487\n762\n316\n469\n258\n475\n596\n651\n180\n737\n101\n511\n708\n163\n713\n475\n557\n649\n705\n583\n97\n447\n119\n91\n372\n194\n394\n667\n384\n635\n611\n746\n758\n613\n54\n508\n405\n188\n570\n254\n28\n599\n767\n115\n737\n194\n148\n686\n705\n236\n762\n613\n770\n633\n401\n773\n448\n274\n141\n718",
"output": "52"
},
{
"input": "1\n1\n1",
"output": "1"
}
] | 1,625,492,705
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 34
| 77
| 0
|
if __name__=="__main__":
n=int(input())
m=int(input())
li=[]
for i in range(n):
num=int(input())
li.append(num)
li.sort(reverse=True)
c=0
for i in li:
if m>0:
m=m-i
c+=1
print(c)
|
Title: USB Flash Drives
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives.
Input Specification:
The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of USB flash drives.
The second line contains positive integer *m* (1<=≤<=*m*<=≤<=105) — the size of Sean's file.
Each of the next *n* lines contains positive integer *a**i* (1<=≤<=*a**i*<=≤<=1000) — the sizes of USB flash drives in megabytes.
It is guaranteed that the answer exists, i. e. the sum of all *a**i* is not less than *m*.
Output Specification:
Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives.
Demo Input:
['3\n5\n2\n1\n3\n', '3\n6\n2\n3\n2\n', '2\n5\n5\n10\n']
Demo Output:
['2\n', '3\n', '1\n']
Note:
In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second.
|
```python
if __name__=="__main__":
n=int(input())
m=int(input())
li=[]
for i in range(n):
num=int(input())
li.append(num)
li.sort(reverse=True)
c=0
for i in li:
if m>0:
m=m-i
c+=1
print(c)
```
| 3
|
|
275
|
A
|
Lights Out
|
PROGRAMMING
| 900
|
[
"implementation"
] | null | null |
Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be switched off, if it was switched off then it will be switched on.
Lenny has spent some time playing with the grid and by now he has pressed each light a certain number of times. Given the number of times each light is pressed, you have to print the current state of each light.
|
The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed.
|
Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0".
|
[
"1 0 0\n0 0 0\n0 0 1\n",
"1 0 1\n8 8 8\n2 0 3\n"
] |
[
"001\n010\n100\n",
"010\n011\n100\n"
] |
none
| 500
|
[
{
"input": "1 0 0\n0 0 0\n0 0 1",
"output": "001\n010\n100"
},
{
"input": "1 0 1\n8 8 8\n2 0 3",
"output": "010\n011\n100"
},
{
"input": "13 85 77\n25 50 45\n65 79 9",
"output": "000\n010\n000"
},
{
"input": "96 95 5\n8 84 74\n67 31 61",
"output": "011\n011\n101"
},
{
"input": "24 54 37\n60 63 6\n1 84 26",
"output": "110\n101\n011"
},
{
"input": "23 10 40\n15 6 40\n92 80 77",
"output": "101\n100\n000"
},
{
"input": "62 74 80\n95 74 93\n2 47 95",
"output": "010\n001\n110"
},
{
"input": "80 83 48\n26 0 66\n47 76 37",
"output": "000\n000\n010"
},
{
"input": "32 15 65\n7 54 36\n5 51 3",
"output": "111\n101\n001"
},
{
"input": "22 97 12\n71 8 24\n100 21 64",
"output": "100\n001\n100"
},
{
"input": "46 37 13\n87 0 50\n90 8 55",
"output": "111\n011\n000"
},
{
"input": "57 43 58\n20 82 83\n66 16 52",
"output": "111\n010\n110"
},
{
"input": "45 56 93\n47 51 59\n18 51 63",
"output": "101\n011\n100"
},
{
"input": "47 66 67\n14 1 37\n27 81 69",
"output": "001\n001\n110"
},
{
"input": "26 69 69\n85 18 23\n14 22 74",
"output": "110\n001\n010"
},
{
"input": "10 70 65\n94 27 25\n74 66 30",
"output": "111\n010\n100"
},
{
"input": "97 1 74\n15 99 1\n88 68 86",
"output": "001\n011\n000"
},
{
"input": "36 48 42\n45 41 66\n26 64 1",
"output": "001\n111\n010"
},
{
"input": "52 81 97\n29 77 71\n66 11 2",
"output": "100\n100\n111"
},
{
"input": "18 66 33\n19 49 49\n48 46 26",
"output": "011\n100\n000"
},
{
"input": "68 79 52\n51 39 100\n29 14 26",
"output": "110\n000\n111"
},
{
"input": "91 69 77\n91 26 64\n91 88 57",
"output": "001\n011\n110"
},
{
"input": "16 69 64\n48 21 80\n81 51 51",
"output": "010\n101\n111"
},
{
"input": "96 14 2\n100 18 12\n65 34 89",
"output": "111\n010\n010"
},
{
"input": "93 95 90\n8 59 42\n53 13 19",
"output": "100\n001\n111"
},
{
"input": "71 84 18\n100 19 67\n9 76 15",
"output": "010\n010\n001"
},
{
"input": "38 93 85\n21 88 64\n4 96 25",
"output": "111\n011\n000"
},
{
"input": "75 20 20\n60 5 78\n77 4 69",
"output": "011\n001\n000"
},
{
"input": "65 70 96\n19 6 83\n33 37 82",
"output": "100\n000\n011"
},
{
"input": "11 13 60\n17 13 46\n42 21 39",
"output": "000\n011\n101"
},
{
"input": "0 0 0\n0 0 0\n0 0 0",
"output": "111\n111\n111"
},
{
"input": "0 0 0\n0 1 0\n0 0 0",
"output": "101\n000\n101"
},
{
"input": "0 0 0\n0 0 0\n0 0 1",
"output": "111\n110\n100"
}
] | 1,622,297,154
| 2,147,483,647
|
Python 3
|
RUNTIME_ERROR
|
TESTS
| 0
| 30
| 0
|
l=[[1,1,1,1,1],
[1,1,1,1,1],
[1,1,1,1,1],
[1,1,1,1,1],
[1,1,1,1,1]]
for i in range(1,4):
for j in range(1,4):
a=int(input())
if(a%2==1):
l[i][j]=abs(1-l[i][j])
l[i+1][j]=abs(1-l[i+1][j])
l[i][j+1]=abs(1-l[i][j+1])
l[i-1][j]=abs(1-l[i-1][j])
l[i][j-1]=abs(1-l[i][j-1])
for k in range(1,4):
for p in range(1,4):
print(l[k][p],end=" ")
print("")
|
Title: Lights Out
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be switched off, if it was switched off then it will be switched on.
Lenny has spent some time playing with the grid and by now he has pressed each light a certain number of times. Given the number of times each light is pressed, you have to print the current state of each light.
Input Specification:
The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed.
Output Specification:
Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0".
Demo Input:
['1 0 0\n0 0 0\n0 0 1\n', '1 0 1\n8 8 8\n2 0 3\n']
Demo Output:
['001\n010\n100\n', '010\n011\n100\n']
Note:
none
|
```python
l=[[1,1,1,1,1],
[1,1,1,1,1],
[1,1,1,1,1],
[1,1,1,1,1],
[1,1,1,1,1]]
for i in range(1,4):
for j in range(1,4):
a=int(input())
if(a%2==1):
l[i][j]=abs(1-l[i][j])
l[i+1][j]=abs(1-l[i+1][j])
l[i][j+1]=abs(1-l[i][j+1])
l[i-1][j]=abs(1-l[i-1][j])
l[i][j-1]=abs(1-l[i][j-1])
for k in range(1,4):
for p in range(1,4):
print(l[k][p],end=" ")
print("")
```
| -1
|
|
69
|
A
|
Young Physicist
|
PROGRAMMING
| 1,000
|
[
"implementation",
"math"
] |
A. Young Physicist
|
2
|
256
|
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
|
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
|
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
|
[
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] |
[
"NO",
"YES"
] |
none
| 500
|
[
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10\n25 -33 43\n-27 -42 28\n-35 -20 19\n41 -42 -1\n49 -39 -4\n-49 -22 7\n-19 29 41\n8 -27 -43\n8 34 9\n-11 -3 33",
"output": "NO"
},
{
"input": "10\n-6 21 18\n20 -11 -8\n37 -11 41\n-5 8 33\n29 23 32\n30 -33 -11\n39 -49 -36\n28 34 -49\n22 29 -34\n-18 -6 7",
"output": "NO"
},
{
"input": "10\n47 -2 -27\n0 26 -14\n5 -12 33\n2 18 3\n45 -30 -49\n4 -18 8\n-46 -44 -41\n-22 -10 -40\n-35 -21 26\n33 20 38",
"output": "NO"
},
{
"input": "13\n-3 -36 -46\n-11 -50 37\n42 -11 -15\n9 42 44\n-29 -12 24\n3 9 -40\n-35 13 50\n14 43 18\n-13 8 24\n-48 -15 10\n50 9 -50\n21 0 -50\n0 0 -6",
"output": "YES"
},
{
"input": "14\n43 23 17\n4 17 44\n5 -5 -16\n-43 -7 -6\n47 -48 12\n50 47 -45\n2 14 43\n37 -30 15\n4 -17 -11\n17 9 -45\n-50 -3 -8\n-50 0 0\n-50 0 0\n-16 0 0",
"output": "YES"
},
{
"input": "13\n29 49 -11\n38 -11 -20\n25 1 -40\n-11 28 11\n23 -19 1\n45 -41 -17\n-3 0 -19\n-13 -33 49\n-30 0 28\n34 17 45\n-50 9 -27\n-50 0 0\n-37 0 0",
"output": "YES"
},
{
"input": "12\n3 28 -35\n-32 -44 -17\n9 -25 -6\n-42 -22 20\n-19 15 38\n-21 38 48\n-1 -37 -28\n-10 -13 -50\n-5 21 29\n34 28 50\n50 11 -49\n34 0 0",
"output": "YES"
},
{
"input": "37\n-64 -79 26\n-22 59 93\n-5 39 -12\n77 -9 76\n55 -86 57\n83 100 -97\n-70 94 84\n-14 46 -94\n26 72 35\n14 78 -62\n17 82 92\n-57 11 91\n23 15 92\n-80 -1 1\n12 39 18\n-23 -99 -75\n-34 50 19\n-39 84 -7\n45 -30 -39\n-60 49 37\n45 -16 -72\n33 -51 -56\n-48 28 5\n97 91 88\n45 -82 -11\n-21 -15 -90\n-53 73 -26\n-74 85 -90\n-40 23 38\n100 -13 49\n32 -100 -100\n0 -100 -70\n0 -100 0\n0 -100 0\n0 -100 0\n0 -100 0\n0 -37 0",
"output": "YES"
},
{
"input": "4\n68 3 100\n68 21 -100\n-100 -24 0\n-36 0 0",
"output": "YES"
},
{
"input": "33\n-1 -46 -12\n45 -16 -21\n-11 45 -21\n-60 -42 -93\n-22 -45 93\n37 96 85\n-76 26 83\n-4 9 55\n7 -52 -9\n66 8 -85\n-100 -54 11\n-29 59 74\n-24 12 2\n-56 81 85\n-92 69 -52\n-26 -97 91\n54 59 -51\n58 21 -57\n7 68 56\n-47 -20 -51\n-59 77 -13\n-85 27 91\n79 60 -56\n66 -80 5\n21 -99 42\n-31 -29 98\n66 93 76\n-49 45 61\n100 -100 -100\n100 -100 -100\n66 -75 -100\n0 0 -100\n0 0 -87",
"output": "YES"
},
{
"input": "3\n1 2 3\n3 2 1\n0 0 0",
"output": "NO"
},
{
"input": "2\n5 -23 12\n0 0 0",
"output": "NO"
},
{
"input": "1\n0 0 0",
"output": "YES"
},
{
"input": "1\n1 -2 0",
"output": "NO"
},
{
"input": "2\n-23 77 -86\n23 -77 86",
"output": "YES"
},
{
"input": "26\n86 7 20\n-57 -64 39\n-45 6 -93\n-44 -21 100\n-11 -49 21\n73 -71 -80\n-2 -89 56\n-65 -2 7\n5 14 84\n57 41 13\n-12 69 54\n40 -25 27\n-17 -59 0\n64 -91 -30\n-53 9 42\n-54 -8 14\n-35 82 27\n-48 -59 -80\n88 70 79\n94 57 97\n44 63 25\n84 -90 -40\n-100 100 -100\n-92 100 -100\n0 10 -100\n0 0 -82",
"output": "YES"
},
{
"input": "42\n11 27 92\n-18 -56 -57\n1 71 81\n33 -92 30\n82 83 49\n-87 -61 -1\n-49 45 49\n73 26 15\n-22 22 -77\n29 -93 87\n-68 44 -90\n-4 -84 20\n85 67 -6\n-39 26 77\n-28 -64 20\n65 -97 24\n-72 -39 51\n35 -75 -91\n39 -44 -8\n-25 -27 -57\n91 8 -46\n-98 -94 56\n94 -60 59\n-9 -95 18\n-53 -37 98\n-8 -94 -84\n-52 55 60\n15 -14 37\n65 -43 -25\n94 12 66\n-8 -19 -83\n29 81 -78\n-58 57 33\n24 86 -84\n-53 32 -88\n-14 7 3\n89 97 -53\n-5 -28 -91\n-100 100 -6\n-84 100 0\n0 100 0\n0 70 0",
"output": "YES"
},
{
"input": "3\n96 49 -12\n2 -66 28\n-98 17 -16",
"output": "YES"
},
{
"input": "5\n70 -46 86\n-100 94 24\n-27 63 -63\n57 -100 -47\n0 -11 0",
"output": "YES"
},
{
"input": "18\n-86 -28 70\n-31 -89 42\n31 -48 -55\n95 -17 -43\n24 -95 -85\n-21 -14 31\n68 -18 81\n13 31 60\n-15 28 99\n-42 15 9\n28 -61 -62\n-16 71 29\n-28 75 -48\n-77 -67 36\n-100 83 89\n100 100 -100\n57 34 -100\n0 0 -53",
"output": "YES"
},
{
"input": "44\n52 -54 -29\n-82 -5 -94\n-54 43 43\n91 16 71\n7 80 -91\n3 15 29\n-99 -6 -77\n-3 -77 -64\n73 67 34\n25 -10 -18\n-29 91 63\n-72 86 -16\n-68 85 -81\n-3 36 44\n-74 -14 -80\n34 -96 -97\n-76 -78 -33\n-24 44 -58\n98 12 77\n95 -63 -6\n-51 3 -90\n-92 -10 72\n7 3 -68\n57 -53 71\n29 57 -48\n35 -60 10\n79 -70 -61\n-20 77 55\n-86 -15 -35\n84 -88 -18\n100 -42 77\n-20 46 8\n-41 -43 -65\n38 -98 -23\n-100 65 45\n-7 -91 -63\n46 88 -85\n48 59 100\n0 0 100\n0 0 100\n0 0 100\n0 0 100\n0 0 100\n0 0 1",
"output": "YES"
},
{
"input": "18\n-14 -64 -91\n-8 -66 -86\n-23 92 -40\n6 -3 -53\n57 41 78\n-79 42 -22\n-88 -17 45\n4 -45 44\n83 -18 -25\n34 86 -92\n75 -30 12\n44 99 11\n-67 -13 72\n22 83 -56\n-37 71 72\n-9 -100 100\n0 -100 31\n0 -58 0",
"output": "YES"
},
{
"input": "23\n-70 37 78\n42 84 6\n28 -94 -24\n-49 76 95\n-67 18 84\n-53 78 -5\n65 -63 -64\n-66 -64 -69\n81 -93 95\n10 52 -79\n-89 -61 -64\n-64 -47 43\n-81 -35 55\n80 82 73\n-60 -81 -18\n49 -10 -19\n-58 70 12\n-24 -15 -93\n98 -93 -54\n-28 -75 11\n100 100 -63\n100 100 0\n56 34 0",
"output": "YES"
},
{
"input": "3\n0 2 -2\n1 -1 3\n-3 0 0",
"output": "NO"
}
] | 1,499,060,423
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 80
| 124
| 5,529,600
|
n=int(input())
a=0
b=0
c=0
for i in range(n):
x,y,z=(int(j) for j in input().split())
a,b,c=a+x,b+y,c+z
if a+b+c==0:
print('YES')
else:
print('NO')
|
Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none
|
```python
n=int(input())
a=0
b=0
c=0
for i in range(n):
x,y,z=(int(j) for j in input().split())
a,b,c=a+x,b+y,c+z
if a+b+c==0:
print('YES')
else:
print('NO')
```
| 0
|
334
|
B
|
Eight Point Sets
|
PROGRAMMING
| 1,400
|
[
"sortings"
] | null | null |
Gerald is very particular to eight point sets. He thinks that any decent eight point set must consist of all pairwise intersections of three distinct integer vertical straight lines and three distinct integer horizontal straight lines, except for the average of these nine points. In other words, there must be three integers *x*1,<=*x*2,<=*x*3 and three more integers *y*1,<=*y*2,<=*y*3, such that *x*1<=<<=*x*2<=<<=*x*3, *y*1<=<<=*y*2<=<<=*y*3 and the eight point set consists of all points (*x**i*,<=*y**j*) (1<=≤<=*i*,<=*j*<=≤<=3), except for point (*x*2,<=*y*2).
You have a set of eight points. Find out if Gerald can use this set?
|
The input consists of eight lines, the *i*-th line contains two space-separated integers *x**i* and *y**i* (0<=≤<=*x**i*,<=*y**i*<=≤<=106). You do not have any other conditions for these points.
|
In a single line print word "respectable", if the given set of points corresponds to Gerald's decency rules, and "ugly" otherwise.
|
[
"0 0\n0 1\n0 2\n1 0\n1 2\n2 0\n2 1\n2 2\n",
"0 0\n1 0\n2 0\n3 0\n4 0\n5 0\n6 0\n7 0\n",
"1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2\n"
] |
[
"respectable\n",
"ugly\n",
"ugly\n"
] |
none
| 1,000
|
[
{
"input": "0 0\n0 1\n0 2\n1 0\n1 2\n2 0\n2 1\n2 2",
"output": "respectable"
},
{
"input": "0 0\n1 0\n2 0\n3 0\n4 0\n5 0\n6 0\n7 0",
"output": "ugly"
},
{
"input": "1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2",
"output": "ugly"
},
{
"input": "0 0\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0",
"output": "ugly"
},
{
"input": "1000000 1000000\n1000000 999999\n1000000 999998\n999999 1000000\n999999 999998\n999998 1000000\n999998 999999\n999998 999998",
"output": "respectable"
},
{
"input": "0 0\n1 0\n0 1\n1 1\n0 2\n1 2\n0 3\n1 3",
"output": "ugly"
},
{
"input": "0 0\n2 1\n1 0\n0 2\n2 2\n1 0\n2 1\n0 2",
"output": "ugly"
},
{
"input": "0 0\n2 1\n1 0\n0 2\n2 2\n1 0\n2 1\n0 2",
"output": "ugly"
},
{
"input": "791649 383826\n10864 260573\n504506 185571\n899991 511500\n503197 876976\n688727 569035\n343255 961333\n439355 759581",
"output": "ugly"
},
{
"input": "750592 335292\n226387 434036\n299976 154633\n593197 600998\n62014 689355\n566268 571630\n381455 222817\n50555 288617",
"output": "ugly"
},
{
"input": "716334 42808\n211710 645370\n515258 96837\n14392 766713\n439265 939607\n430602 918570\n845044 187545\n957977 441674",
"output": "ugly"
},
{
"input": "337873 813442\n995185 863182\n375545 263618\n310042 130019\n358572 560779\n305725 729179\n377381 267545\n41376 312626",
"output": "ugly"
},
{
"input": "803784 428886\n995691 328351\n211844 386054\n375491 74073\n692402 660275\n366073 536431\n485832 941417\n96032 356022",
"output": "ugly"
},
{
"input": "999231 584954\n246553 267441\n697080 920011\n173593 403511\n58535 101909\n131124 924182\n779830 204560\n684576 533111",
"output": "ugly"
},
{
"input": "666888 741208\n685852 578759\n211123 826453\n244759 601804\n670436 748132\n976425 387060\n587850 804554\n430242 805528",
"output": "ugly"
},
{
"input": "71768 834717\n13140 834717\n13140 991083\n880763 386898\n71768 386898\n880763 991083\n880763 834717\n13140 386898",
"output": "ugly"
},
{
"input": "941532 913025\n941532 862399\n686271 913025\n686271 862399\n686271 461004\n941532 461004\n908398 862399\n908398 913025",
"output": "ugly"
},
{
"input": "251515 680236\n761697 669947\n251515 669947\n761697 680236\n251515 476629\n761697 476629\n453296 669947\n453296 476629",
"output": "ugly"
},
{
"input": "612573 554036\n195039 655769\n472305 655769\n612573 655769\n195039 160740\n472305 160740\n472305 554036\n612573 160740",
"output": "ugly"
},
{
"input": "343395 788566\n171702 674699\n171702 788566\n971214 788566\n343395 9278\n971214 9278\n343395 674699\n971214 674699",
"output": "ugly"
},
{
"input": "38184 589856\n281207 447136\n281207 42438\n38184 42438\n38184 447136\n880488 589856\n281207 589856\n880488 42438",
"output": "ugly"
},
{
"input": "337499 89260\n337499 565883\n603778 89260\n603778 565883\n234246 89260\n603778 17841\n337499 17841\n234246 17841",
"output": "ugly"
},
{
"input": "180952 311537\n180952 918548\n126568 918548\n180952 268810\n732313 918548\n126568 311537\n126568 268810\n732313 311537",
"output": "ugly"
},
{
"input": "323728 724794\n265581 165113\n323728 146453\n265581 146453\n591097 146453\n265581 724794\n323728 165113\n591097 165113",
"output": "ugly"
},
{
"input": "642921 597358\n922979 597358\n127181 616833\n642921 828316\n922979 828316\n127181 597358\n922979 616833\n127181 828316",
"output": "respectable"
},
{
"input": "69586 260253\n74916 203798\n985457 203798\n74916 943932\n985457 943932\n69586 943932\n985457 260253\n69586 203798",
"output": "respectable"
},
{
"input": "57930 637387\n883991 573\n57930 573\n57930 499963\n399327 573\n399327 637387\n883991 637387\n883991 499963",
"output": "respectable"
},
{
"input": "52820 216139\n52820 999248\n290345 216139\n290345 999248\n308639 216139\n308639 999248\n52820 477113\n308639 477113",
"output": "respectable"
},
{
"input": "581646 464672\n493402 649074\n581646 649074\n214619 649074\n581646 252709\n214619 252709\n214619 464672\n493402 252709",
"output": "respectable"
},
{
"input": "787948 77797\n421941 615742\n421941 77797\n400523 77797\n400523 111679\n787948 615742\n400523 615742\n787948 111679",
"output": "respectable"
},
{
"input": "583956 366985\n759621 567609\n756846 567609\n759621 176020\n583956 567609\n583956 176020\n759621 366985\n756846 176020",
"output": "respectable"
},
{
"input": "0 50000\n0 0\n0 1000000\n50000 0\n50000 1000000\n1000000 0\n1000000 50000\n1000000 1000000",
"output": "respectable"
},
{
"input": "0 8\n0 9\n0 10\n1 8\n3 8\n3 8\n3 9\n3 10",
"output": "ugly"
},
{
"input": "0 1\n0 1\n0 2\n1 1\n1 2\n2 1\n2 1\n2 2",
"output": "ugly"
},
{
"input": "1 2\n1 3\n1 4\n2 2\n2 4\n4 2\n4 2\n4 4",
"output": "ugly"
},
{
"input": "0 0\n0 1\n0 2\n0 0\n1 2\n2 0\n2 1\n2 2",
"output": "ugly"
},
{
"input": "0 0\n0 0\n0 0\n1 1\n1 1\n2 2\n2 2\n2 2",
"output": "ugly"
},
{
"input": "0 0\n0 0\n0 2\n1 1\n1 2\n2 0\n2 1\n2 2",
"output": "ugly"
},
{
"input": "0 0\n0 1\n0 3\n1 0\n1 3\n2 0\n2 2\n2 3",
"output": "ugly"
},
{
"input": "0 0\n0 1\n0 2\n1 0\n1 2\n3 0\n3 1\n3 2",
"output": "respectable"
},
{
"input": "1 1\n1 2\n1 5\n2 1\n2 5\n5 1\n5 2\n5 5",
"output": "respectable"
},
{
"input": "1 1\n1 2\n1 2\n2 3\n2 1\n3 3\n3 1\n3 3",
"output": "ugly"
},
{
"input": "0 0\n0 0\n1 0\n0 1\n2 1\n1 2\n2 2\n2 2",
"output": "ugly"
},
{
"input": "1 1\n1 1\n1 3\n2 1\n2 3\n3 2\n3 2\n3 3",
"output": "ugly"
},
{
"input": "1 0\n1 0\n1 0\n2 3\n2 3\n3 4\n3 4\n3 4",
"output": "ugly"
}
] | 1,660,878,689
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 0
| 124
| 7,884,800
|
fre_x = [False] * (10 ** 6 + 5)
fre_y = [False] * (10 ** 6 + 5)
unique_x = []
unique_y = []
points = []
for _ in range(8):
x, y = map(int, input().split())
points.append((x, y))
if not fre_x[x]:
fre_x[x] = True
unique_x.append(x)
if not fre_y[y]:
fre_y[y] = True
unique_y.append(y)
if len(unique_x) != 3 or len(unique_y) != 3:
print('ugly')
exit()
unique_x.sort()
unique_y.sort()
points.sort()
index = 0
count = 0
for i in range(3):
for j in range(3):
if i == j == 1:
continue
count += 1
if unique_x[i] == points[index][0] and unique_y[j] == points[index][1]:
index += 1
else:
print('ugly')
exit()
print(count)
print('respectable')
|
Title: Eight Point Sets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald is very particular to eight point sets. He thinks that any decent eight point set must consist of all pairwise intersections of three distinct integer vertical straight lines and three distinct integer horizontal straight lines, except for the average of these nine points. In other words, there must be three integers *x*1,<=*x*2,<=*x*3 and three more integers *y*1,<=*y*2,<=*y*3, such that *x*1<=<<=*x*2<=<<=*x*3, *y*1<=<<=*y*2<=<<=*y*3 and the eight point set consists of all points (*x**i*,<=*y**j*) (1<=≤<=*i*,<=*j*<=≤<=3), except for point (*x*2,<=*y*2).
You have a set of eight points. Find out if Gerald can use this set?
Input Specification:
The input consists of eight lines, the *i*-th line contains two space-separated integers *x**i* and *y**i* (0<=≤<=*x**i*,<=*y**i*<=≤<=106). You do not have any other conditions for these points.
Output Specification:
In a single line print word "respectable", if the given set of points corresponds to Gerald's decency rules, and "ugly" otherwise.
Demo Input:
['0 0\n0 1\n0 2\n1 0\n1 2\n2 0\n2 1\n2 2\n', '0 0\n1 0\n2 0\n3 0\n4 0\n5 0\n6 0\n7 0\n', '1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2\n']
Demo Output:
['respectable\n', 'ugly\n', 'ugly\n']
Note:
none
|
```python
fre_x = [False] * (10 ** 6 + 5)
fre_y = [False] * (10 ** 6 + 5)
unique_x = []
unique_y = []
points = []
for _ in range(8):
x, y = map(int, input().split())
points.append((x, y))
if not fre_x[x]:
fre_x[x] = True
unique_x.append(x)
if not fre_y[y]:
fre_y[y] = True
unique_y.append(y)
if len(unique_x) != 3 or len(unique_y) != 3:
print('ugly')
exit()
unique_x.sort()
unique_y.sort()
points.sort()
index = 0
count = 0
for i in range(3):
for j in range(3):
if i == j == 1:
continue
count += 1
if unique_x[i] == points[index][0] and unique_y[j] == points[index][1]:
index += 1
else:
print('ugly')
exit()
print(count)
print('respectable')
```
| 0
|
|
707
|
A
|
Brain's Photos
|
PROGRAMMING
| 800
|
[
"implementation"
] | null | null |
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a lot of colourful pictures on colored and black-and-white film. Then he developed and translated it into a digital form. But now, color and black-and-white photos are in one folder, and to sort them, one needs to spend more than one hour!
As soon as Brain is a photographer not programmer now, he asks you to help him determine for a single photo whether it is colored or black-and-white.
Photo can be represented as a matrix sized *n*<=×<=*m*, and each element of the matrix stores a symbol indicating corresponding pixel color. There are only 6 colors:
- 'C' (cyan)- 'M' (magenta)- 'Y' (yellow)- 'W' (white)- 'G' (grey)- 'B' (black)
The photo is considered black-and-white if it has only white, black and grey pixels in it. If there are any of cyan, magenta or yellow pixels in the photo then it is considered colored.
|
The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line is one of the 'C', 'M', 'Y', 'W', 'G' or 'B'.
|
Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line.
|
[
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] |
[
"#Color",
"#Black&White",
"#Black&White"
] |
none
| 500
|
[
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "5 5\nW G B Y M\nG B Y M C\nB Y M C W\nY M C W G\nM C W G B",
"output": "#Color"
},
{
"input": "1 6\nC M Y W G B",
"output": "#Color"
},
{
"input": "1 3\nW G B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "5 5\nW G B W G\nG B W G B\nB W G B W\nW G B W G\nG B W G B",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G C",
"output": "#Color"
},
{
"input": "2 3\nW W W\nB G M",
"output": "#Color"
},
{
"input": "3 3\nC B W\nB Y M\nB B W",
"output": "#Color"
},
{
"input": "1 3\nW C W",
"output": "#Color"
},
{
"input": "3 3\nB W B\nB C W\nB W W",
"output": "#Color"
},
{
"input": "1 2\nW Y",
"output": "#Color"
},
{
"input": "1 1\nG",
"output": "#Black&White"
},
{
"input": "1 3\nB G W",
"output": "#Black&White"
},
{
"input": "2 2\nW W\nB C",
"output": "#Color"
},
{
"input": "1 1\nM",
"output": "#Color"
},
{
"input": "1 2\nW C",
"output": "#Color"
},
{
"input": "2 3\nW W M\nW W M",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB C",
"output": "#Color"
},
{
"input": "2 3\nW W C\nW W W",
"output": "#Color"
},
{
"input": "1 3\nG G G",
"output": "#Black&White"
},
{
"input": "1 1\nC",
"output": "#Color"
},
{
"input": "1 2\nC W",
"output": "#Color"
},
{
"input": "1 3\nW W C",
"output": "#Color"
},
{
"input": "2 2\nW B\nB G",
"output": "#Black&White"
},
{
"input": "2 2\nB B\nY Y",
"output": "#Color"
},
{
"input": "2 2\nG G\nC C",
"output": "#Color"
},
{
"input": "1 2\nB C",
"output": "#Color"
},
{
"input": "1 4\nG G G C",
"output": "#Color"
},
{
"input": "1 1\nB",
"output": "#Black&White"
},
{
"input": "2 1\nY\nB",
"output": "#Color"
}
] | 1,655,476,180
| 2,147,483,647
|
Python 3
|
COMPILATION_ERROR
|
TESTS
| 0
| 0
| 0
|
n, m = map(int, input().split())
bw = 0
c = 0
for i in range(n):
color = list(map(str, input().split()))
for i in range(m):
if color[i] == "W" or color[0] == "B" or color[0] == "G":
bw += 1
else:
c += 1
if c>bw:
print("#Color")
else:
c<bw:
print("#Black&White")
|
Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a lot of colourful pictures on colored and black-and-white film. Then he developed and translated it into a digital form. But now, color and black-and-white photos are in one folder, and to sort them, one needs to spend more than one hour!
As soon as Brain is a photographer not programmer now, he asks you to help him determine for a single photo whether it is colored or black-and-white.
Photo can be represented as a matrix sized *n*<=×<=*m*, and each element of the matrix stores a symbol indicating corresponding pixel color. There are only 6 colors:
- 'C' (cyan)- 'M' (magenta)- 'Y' (yellow)- 'W' (white)- 'G' (grey)- 'B' (black)
The photo is considered black-and-white if it has only white, black and grey pixels in it. If there are any of cyan, magenta or yellow pixels in the photo then it is considered colored.
Input Specification:
The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line is one of the 'C', 'M', 'Y', 'W', 'G' or 'B'.
Output Specification:
Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line.
Demo Input:
['2 2\nC M\nY Y\n', '3 2\nW W\nW W\nB B\n', '1 1\nW\n']
Demo Output:
['#Color', '#Black&White', '#Black&White']
Note:
none
|
```python
n, m = map(int, input().split())
bw = 0
c = 0
for i in range(n):
color = list(map(str, input().split()))
for i in range(m):
if color[i] == "W" or color[0] == "B" or color[0] == "G":
bw += 1
else:
c += 1
if c>bw:
print("#Color")
else:
c<bw:
print("#Black&White")
```
| -1
|
|
729
|
C
|
Road to Cinema
|
PROGRAMMING
| 1,700
|
[
"binary search",
"greedy",
"sortings"
] | null | null |
Vasya is currently at a car rental service, and he wants to reach cinema. The film he has bought a ticket for starts in *t* minutes. There is a straight road of length *s* from the service to the cinema. Let's introduce a coordinate system so that the car rental service is at the point 0, and the cinema is at the point *s*.
There are *k* gas stations along the road, and at each of them you can fill a car with any amount of fuel for free! Consider that this operation doesn't take any time, i.e. is carried out instantly.
There are *n* cars in the rental service, *i*-th of them is characterized with two integers *c**i* and *v**i* — the price of this car rent and the capacity of its fuel tank in liters. It's not allowed to fuel a car with more fuel than its tank capacity *v**i*. All cars are completely fueled at the car rental service.
Each of the cars can be driven in one of two speed modes: normal or accelerated. In the normal mode a car covers 1 kilometer in 2 minutes, and consumes 1 liter of fuel. In the accelerated mode a car covers 1 kilometer in 1 minutes, but consumes 2 liters of fuel. The driving mode can be changed at any moment and any number of times.
Your task is to choose a car with minimum price such that Vasya can reach the cinema before the show starts, i.e. not later than in *t* minutes. Assume that all cars are completely fueled initially.
|
The first line contains four positive integers *n*, *k*, *s* and *t* (1<=≤<=*n*<=≤<=2·105, 1<=≤<=*k*<=≤<=2·105, 2<=≤<=*s*<=≤<=109, 1<=≤<=*t*<=≤<=2·109) — the number of cars at the car rental service, the number of gas stations along the road, the length of the road and the time in which the film starts.
Each of the next *n* lines contains two positive integers *c**i* and *v**i* (1<=≤<=*c**i*,<=*v**i*<=≤<=109) — the price of the *i*-th car and its fuel tank capacity.
The next line contains *k* distinct integers *g*1,<=*g*2,<=...,<=*g**k* (1<=≤<=*g**i*<=≤<=*s*<=-<=1) — the positions of the gas stations on the road in arbitrary order.
|
Print the minimum rent price of an appropriate car, i.e. such car that Vasya will be able to reach the cinema before the film starts (not later than in *t* minutes). If there is no appropriate car, print -1.
|
[
"3 1 8 10\n10 8\n5 7\n11 9\n3\n",
"2 2 10 18\n10 4\n20 6\n5 3\n"
] |
[
"10\n",
"20\n"
] |
In the first sample, Vasya can reach the cinema in time using the first or the third cars, but it would be cheaper to choose the first one. Its price is equal to 10, and the capacity of its fuel tank is 8. Then Vasya can drive to the first gas station in the accelerated mode in 3 minutes, spending 6 liters of fuel. After that he can full the tank and cover 2 kilometers in the normal mode in 4 minutes, spending 2 liters of fuel. Finally, he drives in the accelerated mode covering the remaining 3 kilometers in 3 minutes and spending 6 liters of fuel.
| 1,750
|
[
{
"input": "3 1 8 10\n10 8\n5 7\n11 9\n3",
"output": "10"
},
{
"input": "2 2 10 18\n10 4\n20 6\n5 3",
"output": "20"
},
{
"input": "2 1 1000000000 2000000000\n111 1000000000\n101 1000000000\n5",
"output": "101"
},
{
"input": "2 1 1000000000 2000000000\n111 999999998\n101 999999998\n1",
"output": "-1"
},
{
"input": "2 1 1000000000 2000000000\n111 999999999\n101 999999998\n1",
"output": "111"
},
{
"input": "1 15 100 200\n283 8\n30 58 16 45 80 82 55 95 24 23 86 28 51 47 20",
"output": "-1"
},
{
"input": "3 2 300 400\n24 68\n13 65\n15 113\n127 177",
"output": "-1"
},
{
"input": "4 13 400 600\n13 30\n1 19\n1 160\n1 113\n58 73 15 319 194 362 128 157 336 162 77 90 96",
"output": "1"
},
{
"input": "1 1 2 2\n1000000000 1000000000\n1",
"output": "1000000000"
},
{
"input": "1 1 2 1\n1 10\n1",
"output": "-1"
},
{
"input": "1 1 1000000000 1000000000\n1 1000000000\n1",
"output": "-1"
},
{
"input": "1 1 1000000000 1000000000\n100 1000000000\n1",
"output": "-1"
},
{
"input": "4 2 7 15\n10 9\n4 4\n9 3\n4 10\n1 6",
"output": "4"
},
{
"input": "1 1 10 18\n5 6\n5",
"output": "5"
}
] | 1,479,638,435
| 5,735
|
Python 3
|
WRONG_ANSWER
|
PRETESTS
| 2
| 46
| 204,800
|
ans=-1
n,k,s,t=[int(i) for i in input().split()]
cars=[]
minV=2000000000
maxV=0
for i in range(n):
cars.append([int(i) for i in input().split()])
if cars[i][1]>maxV:
maxV=cars[i][1]
if cars[i][1]<minV:
minV=cars[i][1]
g=[int(i) for i in input().split()]
g.sort()
g+=[s-g[-1]]
maxG=g[0]
for i in range(1,k):
g[i]-=g[i-1]
if g[i]>maxG: maxG=g[i]
if g[-1]>maxG: maxG=g[-1]
r=maxV+1
l=minV
while l+1<r:
dif=(l+r)//2
if dif<maxG:
l=dif
continue
time=0
for i in g:
time+=i*2-min((dif-i),i)
if time<=t:
r=dif
else:
l=dif
minC=2000000000
for i in range(0,n):
if cars[i][1]>=r:
if cars[i][0]<minC:
minC=cars[i][0]
print(minC)
|
Title: Road to Cinema
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya is currently at a car rental service, and he wants to reach cinema. The film he has bought a ticket for starts in *t* minutes. There is a straight road of length *s* from the service to the cinema. Let's introduce a coordinate system so that the car rental service is at the point 0, and the cinema is at the point *s*.
There are *k* gas stations along the road, and at each of them you can fill a car with any amount of fuel for free! Consider that this operation doesn't take any time, i.e. is carried out instantly.
There are *n* cars in the rental service, *i*-th of them is characterized with two integers *c**i* and *v**i* — the price of this car rent and the capacity of its fuel tank in liters. It's not allowed to fuel a car with more fuel than its tank capacity *v**i*. All cars are completely fueled at the car rental service.
Each of the cars can be driven in one of two speed modes: normal or accelerated. In the normal mode a car covers 1 kilometer in 2 minutes, and consumes 1 liter of fuel. In the accelerated mode a car covers 1 kilometer in 1 minutes, but consumes 2 liters of fuel. The driving mode can be changed at any moment and any number of times.
Your task is to choose a car with minimum price such that Vasya can reach the cinema before the show starts, i.e. not later than in *t* minutes. Assume that all cars are completely fueled initially.
Input Specification:
The first line contains four positive integers *n*, *k*, *s* and *t* (1<=≤<=*n*<=≤<=2·105, 1<=≤<=*k*<=≤<=2·105, 2<=≤<=*s*<=≤<=109, 1<=≤<=*t*<=≤<=2·109) — the number of cars at the car rental service, the number of gas stations along the road, the length of the road and the time in which the film starts.
Each of the next *n* lines contains two positive integers *c**i* and *v**i* (1<=≤<=*c**i*,<=*v**i*<=≤<=109) — the price of the *i*-th car and its fuel tank capacity.
The next line contains *k* distinct integers *g*1,<=*g*2,<=...,<=*g**k* (1<=≤<=*g**i*<=≤<=*s*<=-<=1) — the positions of the gas stations on the road in arbitrary order.
Output Specification:
Print the minimum rent price of an appropriate car, i.e. such car that Vasya will be able to reach the cinema before the film starts (not later than in *t* minutes). If there is no appropriate car, print -1.
Demo Input:
['3 1 8 10\n10 8\n5 7\n11 9\n3\n', '2 2 10 18\n10 4\n20 6\n5 3\n']
Demo Output:
['10\n', '20\n']
Note:
In the first sample, Vasya can reach the cinema in time using the first or the third cars, but it would be cheaper to choose the first one. Its price is equal to 10, and the capacity of its fuel tank is 8. Then Vasya can drive to the first gas station in the accelerated mode in 3 minutes, spending 6 liters of fuel. After that he can full the tank and cover 2 kilometers in the normal mode in 4 minutes, spending 2 liters of fuel. Finally, he drives in the accelerated mode covering the remaining 3 kilometers in 3 minutes and spending 6 liters of fuel.
|
```python
ans=-1
n,k,s,t=[int(i) for i in input().split()]
cars=[]
minV=2000000000
maxV=0
for i in range(n):
cars.append([int(i) for i in input().split()])
if cars[i][1]>maxV:
maxV=cars[i][1]
if cars[i][1]<minV:
minV=cars[i][1]
g=[int(i) for i in input().split()]
g.sort()
g+=[s-g[-1]]
maxG=g[0]
for i in range(1,k):
g[i]-=g[i-1]
if g[i]>maxG: maxG=g[i]
if g[-1]>maxG: maxG=g[-1]
r=maxV+1
l=minV
while l+1<r:
dif=(l+r)//2
if dif<maxG:
l=dif
continue
time=0
for i in g:
time+=i*2-min((dif-i),i)
if time<=t:
r=dif
else:
l=dif
minC=2000000000
for i in range(0,n):
if cars[i][1]>=r:
if cars[i][0]<minC:
minC=cars[i][0]
print(minC)
```
| 0
|
|
600
|
B
|
Queries about less or equal elements
|
PROGRAMMING
| 1,300
|
[
"binary search",
"data structures",
"sortings",
"two pointers"
] | null | null |
You are given two arrays of integers *a* and *b*. For each element of the second array *b**j* you should find the number of elements in array *a* that are less than or equal to the value *b**j*.
|
The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=2·105) — the sizes of arrays *a* and *b*.
The second line contains *n* integers — the elements of array *a* (<=-<=109<=≤<=*a**i*<=≤<=109).
The third line contains *m* integers — the elements of array *b* (<=-<=109<=≤<=*b**j*<=≤<=109).
|
Print *m* integers, separated by spaces: the *j*-th of which is equal to the number of such elements in array *a* that are less than or equal to the value *b**j*.
|
[
"5 4\n1 3 5 7 9\n6 4 2 8\n",
"5 5\n1 2 1 2 5\n3 1 4 1 5\n"
] |
[
"3 2 1 4\n",
"4 2 4 2 5\n"
] |
none
| 0
|
[
{
"input": "5 4\n1 3 5 7 9\n6 4 2 8",
"output": "3 2 1 4"
},
{
"input": "5 5\n1 2 1 2 5\n3 1 4 1 5",
"output": "4 2 4 2 5"
},
{
"input": "1 1\n-1\n-2",
"output": "0"
},
{
"input": "1 1\n-80890826\n686519510",
"output": "1"
},
{
"input": "11 11\n237468511 -779187544 -174606592 193890085 404563196 -71722998 -617934776 170102710 -442808289 109833389 953091341\n994454001 322957429 216874735 -606986750 -455806318 -663190696 3793295 41395397 -929612742 -787653860 -684738874",
"output": "11 9 8 2 2 1 5 5 0 0 1"
},
{
"input": "20 22\n858276994 -568758442 -918490847 -983345984 -172435358 389604931 200224783 486556113 413281867 -258259500 -627945379 -584563643 444685477 -602481243 -370745158 965672503 630955806 -626138773 -997221880 633102929\n-61330638 -977252080 -212144219 385501731 669589742 954357160 563935906 584468977 -895883477 405774444 853372186 186056475 -964575261 -952431965 632332084 -388829939 -23011650 310957048 -770695392 977376693 321435214 199223897",
"output": "11 2 10 12 18 19 16 16 3 13 18 11 2 2 17 8 11 12 3 20 12 11"
},
{
"input": "5 9\n1 3 5 7 9\n1 2 3 4 5 6 7 8 9",
"output": "1 1 2 2 3 3 4 4 5"
},
{
"input": "22 1\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22\n1",
"output": "1"
},
{
"input": "5 1\n1 3 3 3 5\n3",
"output": "4"
},
{
"input": "4 5\n1 1 1 4\n1 5 5 4 3",
"output": "3 4 4 4 3"
},
{
"input": "5 4\n0 5 5 5 6\n5 1 6 3",
"output": "4 1 5 1"
},
{
"input": "1 3\n0\n-1 0 1",
"output": "0 1 1"
},
{
"input": "96 1\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n1",
"output": "96"
},
{
"input": "7 1\n1 2 3 4 5 6 7\n1",
"output": "1"
},
{
"input": "13 13\n-1000000000 1000000000 -1000000000 1000000000 -1000000000 1000000000 -1000000000 1000000000 -1000000000 1000000000 -1000000000 1000000000 -1000000000\n-1000000000 1000000000 -1000000000 1000000000 -1000000000 1000000000 -1000000000 1000000000 -1000000000 1000000000 -1000000000 1000000000 -1000000000",
"output": "7 13 7 13 7 13 7 13 7 13 7 13 7"
},
{
"input": "9 5\n1 2 3 4 5 6 7 8 9\n1 2 3 4 5",
"output": "1 2 3 4 5"
},
{
"input": "3 8\n1 1 1\n1 1 1 1 1 1 1 1",
"output": "3 3 3 3 3 3 3 3"
},
{
"input": "1 1\n-11111\n-5938",
"output": "1"
},
{
"input": "1 1\n1\n400000009",
"output": "1"
},
{
"input": "1 1\n1\n300000009",
"output": "1"
},
{
"input": "1 1\n1\n200000009",
"output": "1"
},
{
"input": "1 1\n1\n200000003",
"output": "1"
}
] | 1,680,513,263
| 2,147,483,647
|
PyPy 3-64
|
WRONG_ANSWER
|
TESTS
| 4
| 46
| 0
|
a,b = map(int,input().split())
arr1 = list(map(int,input().split()))
arr2 = list(map(int,input().split()))
# arr1.sort()
# arr2.sort()
count=0
if(arr2[-1]<arr1[0]):
print(count)
else:
for i in arr2:
count=0
for j in arr1:
if(j<=i):
count+=1
print(count,end=" ")
|
Title: Queries about less or equal elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays of integers *a* and *b*. For each element of the second array *b**j* you should find the number of elements in array *a* that are less than or equal to the value *b**j*.
Input Specification:
The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=2·105) — the sizes of arrays *a* and *b*.
The second line contains *n* integers — the elements of array *a* (<=-<=109<=≤<=*a**i*<=≤<=109).
The third line contains *m* integers — the elements of array *b* (<=-<=109<=≤<=*b**j*<=≤<=109).
Output Specification:
Print *m* integers, separated by spaces: the *j*-th of which is equal to the number of such elements in array *a* that are less than or equal to the value *b**j*.
Demo Input:
['5 4\n1 3 5 7 9\n6 4 2 8\n', '5 5\n1 2 1 2 5\n3 1 4 1 5\n']
Demo Output:
['3 2 1 4\n', '4 2 4 2 5\n']
Note:
none
|
```python
a,b = map(int,input().split())
arr1 = list(map(int,input().split()))
arr2 = list(map(int,input().split()))
# arr1.sort()
# arr2.sort()
count=0
if(arr2[-1]<arr1[0]):
print(count)
else:
for i in arr2:
count=0
for j in arr1:
if(j<=i):
count+=1
print(count,end=" ")
```
| 0
|
|
389
|
A
|
Fox and Number Game
|
PROGRAMMING
| 1,000
|
[
"greedy",
"math"
] | null | null |
Fox Ciel is playing a game with numbers now.
Ciel has *n* positive integers: *x*1, *x*2, ..., *x**n*. She can do the following operation as many times as needed: select two different indexes *i* and *j* such that *x**i* > *x**j* hold, and then apply assignment *x**i* = *x**i* - *x**j*. The goal is to make the sum of all numbers as small as possible.
Please help Ciel to find this minimal sum.
|
The first line contains an integer *n* (2<=≤<=*n*<=≤<=100). Then the second line contains *n* integers: *x*1, *x*2, ..., *x**n* (1<=≤<=*x**i*<=≤<=100).
|
Output a single integer — the required minimal sum.
|
[
"2\n1 2\n",
"3\n2 4 6\n",
"2\n12 18\n",
"5\n45 12 27 30 18\n"
] |
[
"2\n",
"6\n",
"12\n",
"15\n"
] |
In the first example the optimal way is to do the assignment: *x*<sub class="lower-index">2</sub> = *x*<sub class="lower-index">2</sub> - *x*<sub class="lower-index">1</sub>.
In the second example the optimal sequence of operations is: *x*<sub class="lower-index">3</sub> = *x*<sub class="lower-index">3</sub> - *x*<sub class="lower-index">2</sub>, *x*<sub class="lower-index">2</sub> = *x*<sub class="lower-index">2</sub> - *x*<sub class="lower-index">1</sub>.
| 500
|
[
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n2 4 6",
"output": "6"
},
{
"input": "2\n12 18",
"output": "12"
},
{
"input": "5\n45 12 27 30 18",
"output": "15"
},
{
"input": "2\n1 1",
"output": "2"
},
{
"input": "2\n100 100",
"output": "200"
},
{
"input": "2\n87 58",
"output": "58"
},
{
"input": "39\n52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52 52",
"output": "2028"
},
{
"input": "59\n96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96 96",
"output": "5664"
},
{
"input": "100\n100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100",
"output": "10000"
},
{
"input": "100\n70 70 77 42 98 84 56 91 35 21 7 70 77 77 56 63 14 84 56 14 77 77 63 70 14 7 28 91 63 49 21 84 98 56 77 98 98 84 98 14 7 56 49 28 91 98 7 56 14 91 14 98 49 28 98 14 98 98 14 70 35 28 63 28 49 63 63 56 91 98 35 42 42 35 63 35 42 14 63 21 77 56 42 77 35 91 56 21 28 84 56 70 70 91 98 70 84 63 21 98",
"output": "700"
},
{
"input": "39\n63 21 21 42 21 63 21 84 42 21 84 63 42 63 84 84 84 42 42 84 21 63 42 63 42 42 63 42 42 63 84 42 21 84 21 63 42 21 42",
"output": "819"
},
{
"input": "59\n70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70 70",
"output": "4130"
},
{
"input": "87\n44 88 88 88 88 66 88 22 22 88 88 44 88 22 22 22 88 88 88 88 66 22 88 88 88 88 66 66 44 88 44 44 66 22 88 88 22 44 66 44 88 66 66 22 22 22 22 88 22 22 44 66 88 22 22 88 66 66 88 22 66 88 66 88 66 44 88 44 22 44 44 22 44 88 44 44 44 44 22 88 88 88 66 66 88 44 22",
"output": "1914"
},
{
"input": "15\n63 63 63 63 63 63 63 63 63 63 63 63 63 63 63",
"output": "945"
},
{
"input": "39\n63 77 21 14 14 35 21 21 70 42 21 70 28 77 28 77 7 42 63 7 98 49 98 84 35 70 70 91 14 42 98 7 42 7 98 42 56 35 91",
"output": "273"
},
{
"input": "18\n18 18 18 36 36 36 54 72 54 36 72 54 36 36 36 36 18 36",
"output": "324"
},
{
"input": "46\n71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71 71",
"output": "3266"
},
{
"input": "70\n66 11 66 11 44 11 44 99 55 22 88 11 11 22 55 44 22 77 44 77 77 22 44 55 88 11 99 99 88 22 77 77 66 11 11 66 99 55 55 44 66 44 77 44 44 55 33 55 44 88 77 77 22 66 33 44 11 22 55 44 22 66 77 33 33 44 44 44 22 33",
"output": "770"
},
{
"input": "10\n60 12 96 48 60 24 60 36 60 60",
"output": "120"
},
{
"input": "20\n51 51 51 51 51 51 51 51 51 51 51 51 51 51 51 51 51 51 51 51",
"output": "1020"
},
{
"input": "50\n58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58 58",
"output": "2900"
},
{
"input": "98\n70 60 100 30 70 20 30 50 50 30 90 40 30 40 60 80 60 60 80 50 10 80 20 10 20 10 50 70 30 80 30 50 60 90 90 100 60 30 90 20 30 60 90 80 60 60 10 90 10 50 40 40 80 90 100 40 70 40 30 50 60 50 60 30 40 20 90 60 20 20 20 70 60 70 50 100 90 50 20 40 80 60 10 60 50 40 40 10 50 10 40 10 80 100 100 90 10 90",
"output": "980"
},
{
"input": "100\n82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82 82",
"output": "8200"
},
{
"input": "100\n11 87 77 93 3 54 21 93 9 71 37 23 69 85 74 3 48 99 51 31 56 19 21 96 39 6 4 4 29 69 100 42 1 22 81 53 48 49 81 61 10 7 40 61 7 71 51 59 79 44 50 35 95 80 83 8 98 40 18 94 84 49 52 74 66 69 39 37 100 44 38 62 2 80 46 31 35 53 5 60 21 49 63 55 20 53 80 53 66 34 23 92 77 50 86 63 65 24 12 70",
"output": "100"
},
{
"input": "2\n100 1",
"output": "2"
},
{
"input": "2\n18 30",
"output": "12"
},
{
"input": "2\n3 5",
"output": "2"
},
{
"input": "2\n1 10",
"output": "2"
},
{
"input": "2\n8 5",
"output": "2"
},
{
"input": "5\n2 3 5 8 18",
"output": "5"
},
{
"input": "5\n2 4 1 6 8",
"output": "5"
},
{
"input": "3\n12 10 5",
"output": "3"
},
{
"input": "3\n6 10 15",
"output": "3"
}
] | 1,616,650,342
| 2,147,483,647
|
PyPy 3
|
OK
|
TESTS
| 34
| 233
| 9,625,600
|
import fractions
n=int(input())
a=0
for x in input().split():
a=fractions.gcd(a,int(x))
print(a*n)
|
Title: Fox and Number Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel is playing a game with numbers now.
Ciel has *n* positive integers: *x*1, *x*2, ..., *x**n*. She can do the following operation as many times as needed: select two different indexes *i* and *j* such that *x**i* > *x**j* hold, and then apply assignment *x**i* = *x**i* - *x**j*. The goal is to make the sum of all numbers as small as possible.
Please help Ciel to find this minimal sum.
Input Specification:
The first line contains an integer *n* (2<=≤<=*n*<=≤<=100). Then the second line contains *n* integers: *x*1, *x*2, ..., *x**n* (1<=≤<=*x**i*<=≤<=100).
Output Specification:
Output a single integer — the required minimal sum.
Demo Input:
['2\n1 2\n', '3\n2 4 6\n', '2\n12 18\n', '5\n45 12 27 30 18\n']
Demo Output:
['2\n', '6\n', '12\n', '15\n']
Note:
In the first example the optimal way is to do the assignment: *x*<sub class="lower-index">2</sub> = *x*<sub class="lower-index">2</sub> - *x*<sub class="lower-index">1</sub>.
In the second example the optimal sequence of operations is: *x*<sub class="lower-index">3</sub> = *x*<sub class="lower-index">3</sub> - *x*<sub class="lower-index">2</sub>, *x*<sub class="lower-index">2</sub> = *x*<sub class="lower-index">2</sub> - *x*<sub class="lower-index">1</sub>.
|
```python
import fractions
n=int(input())
a=0
for x in input().split():
a=fractions.gcd(a,int(x))
print(a*n)
```
| 3
|
|
48
|
A
|
Rock-paper-scissors
|
PROGRAMMING
| 900
|
[
"implementation",
"schedules"
] |
A. Rock-paper-scissors
|
2
|
256
|
Uncle Fyodor, Matroskin the Cat and Sharic the Dog live their simple but happy lives in Prostokvashino. Sometimes they receive parcels from Uncle Fyodor’s parents and sometimes from anonymous benefactors, in which case it is hard to determine to which one of them the package has been sent. A photographic rifle is obviously for Sharic who loves hunting and fish is for Matroskin, but for whom was a new video game console meant? Every one of the three friends claimed that the present is for him and nearly quarreled. Uncle Fyodor had an idea how to solve the problem justly: they should suppose that the console was sent to all three of them and play it in turns. Everybody got relieved but then yet another burning problem popped up — who will play first? This time Matroskin came up with a brilliant solution, suggesting the most fair way to find it out: play rock-paper-scissors together. The rules of the game are very simple. On the count of three every player shows a combination with his hand (or paw). The combination corresponds to one of three things: a rock, scissors or paper. Some of the gestures win over some other ones according to well-known rules: the rock breaks the scissors, the scissors cut the paper, and the paper gets wrapped over the stone. Usually there are two players. Yet there are three friends, that’s why they decided to choose the winner like that: If someone shows the gesture that wins over the other two players, then that player wins. Otherwise, another game round is required. Write a program that will determine the winner by the gestures they have shown.
|
The first input line contains the name of the gesture that Uncle Fyodor showed, the second line shows which gesture Matroskin showed and the third line shows Sharic’s gesture.
|
Print "F" (without quotes) if Uncle Fyodor wins. Print "M" if Matroskin wins and "S" if Sharic wins. If it is impossible to find the winner, print "?".
|
[
"rock\nrock\nrock\n",
"paper\nrock\nrock\n",
"scissors\nrock\nrock\n",
"scissors\npaper\nrock\n"
] |
[
"?\n",
"F\n",
"?\n",
"?\n"
] |
none
| 0
|
[
{
"input": "rock\nrock\nrock",
"output": "?"
},
{
"input": "paper\nrock\nrock",
"output": "F"
},
{
"input": "scissors\nrock\nrock",
"output": "?"
},
{
"input": "scissors\npaper\nrock",
"output": "?"
},
{
"input": "paper\npaper\nrock",
"output": "?"
},
{
"input": "rock\npaper\nrock",
"output": "M"
},
{
"input": "rock\nscissors\nrock",
"output": "?"
},
{
"input": "paper\nscissors\nrock",
"output": "?"
},
{
"input": "scissors\nscissors\nrock",
"output": "S"
},
{
"input": "rock\nrock\npaper",
"output": "S"
},
{
"input": "paper\nrock\npaper",
"output": "?"
},
{
"input": "scissors\nrock\npaper",
"output": "?"
},
{
"input": "rock\npaper\npaper",
"output": "?"
},
{
"input": "paper\npaper\npaper",
"output": "?"
},
{
"input": "scissors\npaper\npaper",
"output": "F"
},
{
"input": "rock\nscissors\npaper",
"output": "?"
},
{
"input": "paper\nscissors\npaper",
"output": "M"
},
{
"input": "scissors\nscissors\npaper",
"output": "?"
},
{
"input": "rock\nrock\nscissors",
"output": "?"
},
{
"input": "paper\nrock\nscissors",
"output": "?"
},
{
"input": "scissors\nrock\nscissors",
"output": "M"
},
{
"input": "rock\npaper\nscissors",
"output": "?"
},
{
"input": "paper\npaper\nscissors",
"output": "S"
},
{
"input": "scissors\npaper\nscissors",
"output": "?"
},
{
"input": "rock\nscissors\nscissors",
"output": "F"
},
{
"input": "paper\nscissors\nscissors",
"output": "?"
},
{
"input": "scissors\nscissors\nscissors",
"output": "?"
}
] | 1,620,477,496
| 2,147,483,647
|
PyPy 3
|
WRONG_ANSWER
|
TESTS
| 8
| 216
| 20,172,800
|
words=[]
def find_person(n):
if(n==0):
print("F")
elif(n==1):
print("M")
elif(n==2):
print("S")
for i in range(3):
game_word=input()
words.append(game_word)
if(words.count("rock")==1 and words.count("scissor")==2):
index=words.index("rock")
find_person(index)
elif(words.count("scissor")==1 and words.count("paper")==1):
index=words.index("paper")
find_person(index)
elif(words.count("paper")==1 and words.count("rock")==2):
index=words.index("paper")
find_person(index)
else:
print("?")
|
Title: Rock-paper-scissors
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Uncle Fyodor, Matroskin the Cat and Sharic the Dog live their simple but happy lives in Prostokvashino. Sometimes they receive parcels from Uncle Fyodor’s parents and sometimes from anonymous benefactors, in which case it is hard to determine to which one of them the package has been sent. A photographic rifle is obviously for Sharic who loves hunting and fish is for Matroskin, but for whom was a new video game console meant? Every one of the three friends claimed that the present is for him and nearly quarreled. Uncle Fyodor had an idea how to solve the problem justly: they should suppose that the console was sent to all three of them and play it in turns. Everybody got relieved but then yet another burning problem popped up — who will play first? This time Matroskin came up with a brilliant solution, suggesting the most fair way to find it out: play rock-paper-scissors together. The rules of the game are very simple. On the count of three every player shows a combination with his hand (or paw). The combination corresponds to one of three things: a rock, scissors or paper. Some of the gestures win over some other ones according to well-known rules: the rock breaks the scissors, the scissors cut the paper, and the paper gets wrapped over the stone. Usually there are two players. Yet there are three friends, that’s why they decided to choose the winner like that: If someone shows the gesture that wins over the other two players, then that player wins. Otherwise, another game round is required. Write a program that will determine the winner by the gestures they have shown.
Input Specification:
The first input line contains the name of the gesture that Uncle Fyodor showed, the second line shows which gesture Matroskin showed and the third line shows Sharic’s gesture.
Output Specification:
Print "F" (without quotes) if Uncle Fyodor wins. Print "M" if Matroskin wins and "S" if Sharic wins. If it is impossible to find the winner, print "?".
Demo Input:
['rock\nrock\nrock\n', 'paper\nrock\nrock\n', 'scissors\nrock\nrock\n', 'scissors\npaper\nrock\n']
Demo Output:
['?\n', 'F\n', '?\n', '?\n']
Note:
none
|
```python
words=[]
def find_person(n):
if(n==0):
print("F")
elif(n==1):
print("M")
elif(n==2):
print("S")
for i in range(3):
game_word=input()
words.append(game_word)
if(words.count("rock")==1 and words.count("scissor")==2):
index=words.index("rock")
find_person(index)
elif(words.count("scissor")==1 and words.count("paper")==1):
index=words.index("paper")
find_person(index)
elif(words.count("paper")==1 and words.count("rock")==2):
index=words.index("paper")
find_person(index)
else:
print("?")
```
| 0
|
37
|
A
|
Towers
|
PROGRAMMING
| 1,000
|
[
"sortings"
] |
A. Towers
|
2
|
256
|
Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct the minimal number of towers from the bars. Help Vasya to use the bars in the best way possible.
|
The first line contains an integer *N* (1<=≤<=*N*<=≤<=1000) — the number of bars at Vasya’s disposal. The second line contains *N* space-separated integers *l**i* — the lengths of the bars. All the lengths are natural numbers not exceeding 1000.
|
In one line output two numbers — the height of the largest tower and their total number. Remember that Vasya should use all the bars.
|
[
"3\n1 2 3\n",
"4\n6 5 6 7\n"
] |
[
"1 3\n",
"2 3\n"
] |
none
| 500
|
[
{
"input": "3\n1 2 3",
"output": "1 3"
},
{
"input": "4\n6 5 6 7",
"output": "2 3"
},
{
"input": "4\n3 2 1 1",
"output": "2 3"
},
{
"input": "4\n1 2 3 3",
"output": "2 3"
},
{
"input": "3\n20 22 36",
"output": "1 3"
},
{
"input": "25\n47 30 94 41 45 20 96 51 110 129 24 116 9 47 32 82 105 114 116 75 154 151 70 42 162",
"output": "2 23"
},
{
"input": "45\n802 664 442 318 318 827 417 878 711 291 231 414 807 553 657 392 279 202 386 606 465 655 658 112 887 15 25 502 95 44 679 775 942 609 209 871 31 234 4 231 150 110 22 823 193",
"output": "2 43"
},
{
"input": "63\n93 180 116 7 8 179 268 279 136 94 221 153 264 190 278 19 19 63 153 26 158 225 25 49 89 218 111 149 255 225 197 122 243 80 3 224 107 178 202 17 53 92 69 42 228 24 81 205 95 8 265 82 228 156 127 241 172 159 106 60 67 155 111",
"output": "2 57"
},
{
"input": "83\n246 535 994 33 390 927 321 97 223 922 812 705 79 80 977 457 476 636 511 137 6 360 815 319 717 674 368 551 714 628 278 713 761 553 184 414 623 753 428 214 581 115 439 61 677 216 772 592 187 603 658 310 439 559 870 376 109 321 189 337 277 26 70 734 796 907 979 693 570 227 345 650 737 633 701 914 134 403 972 940 371 6 642",
"output": "2 80"
},
{
"input": "105\n246 57 12 204 165 123 246 68 191 310 3 152 386 333 374 257 158 104 333 50 80 290 8 340 101 76 221 316 388 289 138 359 316 26 93 290 105 178 81 195 41 196 218 180 244 292 187 97 315 323 174 119 248 239 92 312 31 2 101 180 307 170 338 314 163 281 217 31 142 238 280 190 190 156 70 74 329 113 151 8 141 313 366 40 253 116 168 124 135 230 294 266 353 389 371 359 195 200 183 237 93 102 315 118 188",
"output": "2 92"
},
{
"input": "123\n112 277 170 247 252 115 157 293 256 143 196 90 12 164 164 42 8 223 167 109 175 232 239 111 148 51 9 254 93 32 268 162 231 91 47 162 161 191 195 145 247 292 129 199 230 94 144 217 18 205 176 20 143 198 121 243 211 262 230 277 195 255 108 290 220 275 158 2 286 200 60 267 278 207 123 150 123 116 131 13 12 226 33 244 30 275 263 45 158 192 254 149 242 176 62 224 221 288 250 160 155 225 132 143 276 293 218 145 197 175 33 129 79 206 210 192 222 262 190 52 274 243 233",
"output": "3 101"
},
{
"input": "5\n5 5 5 5 5",
"output": "5 1"
},
{
"input": "3\n1000 1000 1000",
"output": "3 1"
},
{
"input": "1\n1000",
"output": "1 1"
},
{
"input": "1\n1",
"output": "1 1"
},
{
"input": "5\n1 1000 1000 1000 1000",
"output": "4 2"
},
{
"input": "5\n1000 1000 1000 8 7",
"output": "3 3"
}
] | 1,658,751,815
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 5
| 92
| 0
|
n = int(input())
k = list(map(int, input().split()))
l = []
s = 1
z = 0
for i in k:
if i not in l:
l.append(i)
z += 1
else:
s += 1
print(s, len(l))
|
Title: Towers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct the minimal number of towers from the bars. Help Vasya to use the bars in the best way possible.
Input Specification:
The first line contains an integer *N* (1<=≤<=*N*<=≤<=1000) — the number of bars at Vasya’s disposal. The second line contains *N* space-separated integers *l**i* — the lengths of the bars. All the lengths are natural numbers not exceeding 1000.
Output Specification:
In one line output two numbers — the height of the largest tower and their total number. Remember that Vasya should use all the bars.
Demo Input:
['3\n1 2 3\n', '4\n6 5 6 7\n']
Demo Output:
['1 3\n', '2 3\n']
Note:
none
|
```python
n = int(input())
k = list(map(int, input().split()))
l = []
s = 1
z = 0
for i in k:
if i not in l:
l.append(i)
z += 1
else:
s += 1
print(s, len(l))
```
| 0
|
618
|
A
|
Slime Combining
|
PROGRAMMING
| 800
|
[
"implementation"
] | null | null |
Your friend recently gave you some slimes for your birthday. You have *n* slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other *n*<=-<=1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value *v*, you combine them together to create a slime with value *v*<=+<=1.
You would like to see what the final state of the row is after you've added all *n* slimes. Please print the values of the slimes in the row from left to right.
|
The first line of the input will contain a single integer, *n* (1<=≤<=*n*<=≤<=100<=000).
|
Output a single line with *k* integers, where *k* is the number of slimes in the row after you've finished the procedure described in the problem statement. The *i*-th of these numbers should be the value of the *i*-th slime from the left.
|
[
"1\n",
"2\n",
"3\n",
"8\n"
] |
[
"1\n",
"2\n",
"2 1\n",
"4\n"
] |
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1 1. 2 1. 2 1 1. 3 1. 3 1 1. 3 2 1. 3 2 1 1. 4
| 500
|
[
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "2 1"
},
{
"input": "8",
"output": "4"
},
{
"input": "100000",
"output": "17 16 11 10 8 6"
},
{
"input": "12345",
"output": "14 13 6 5 4 1"
},
{
"input": "32",
"output": "6"
},
{
"input": "70958",
"output": "17 13 11 9 6 4 3 2"
},
{
"input": "97593",
"output": "17 15 14 13 12 11 9 6 5 4 1"
},
{
"input": "91706",
"output": "17 15 14 11 10 6 5 4 2"
},
{
"input": "85371",
"output": "17 15 12 11 9 7 6 5 4 2 1"
},
{
"input": "97205",
"output": "17 15 14 13 12 10 9 8 6 5 3 1"
},
{
"input": "34768",
"output": "16 11 10 9 8 7 5"
},
{
"input": "12705",
"output": "14 13 9 8 6 1"
},
{
"input": "30151",
"output": "15 14 13 11 9 8 7 3 2 1"
},
{
"input": "4974",
"output": "13 10 9 7 6 4 3 2"
},
{
"input": "32728",
"output": "15 14 13 12 11 10 9 8 7 5 4"
},
{
"input": "8192",
"output": "14"
},
{
"input": "65536",
"output": "17"
},
{
"input": "32",
"output": "6"
},
{
"input": "256",
"output": "9"
},
{
"input": "4096",
"output": "13"
},
{
"input": "33301",
"output": "16 10 5 3 1"
},
{
"input": "16725",
"output": "15 9 7 5 3 1"
},
{
"input": "149",
"output": "8 5 3 1"
},
{
"input": "16277",
"output": "14 13 12 11 10 9 8 5 3 1"
},
{
"input": "99701",
"output": "17 16 11 9 7 6 5 3 1"
}
] | 1,669,546,647
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 27
| 108
| 0
|
n = int(input())
i = 1
res_board = []
while i <= n:
res_board.append(1)
while True:
if len(res_board)>1:
if res_board[-2] == res_board[-1]:
res_board[-2] += 1
res_board.pop(-1)
else:
break
else:
break
i += 1
res_board = ' '.join([str(x) for x in res_board])
print(res_board)
|
Title: Slime Combining
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend recently gave you some slimes for your birthday. You have *n* slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other *n*<=-<=1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value *v*, you combine them together to create a slime with value *v*<=+<=1.
You would like to see what the final state of the row is after you've added all *n* slimes. Please print the values of the slimes in the row from left to right.
Input Specification:
The first line of the input will contain a single integer, *n* (1<=≤<=*n*<=≤<=100<=000).
Output Specification:
Output a single line with *k* integers, where *k* is the number of slimes in the row after you've finished the procedure described in the problem statement. The *i*-th of these numbers should be the value of the *i*-th slime from the left.
Demo Input:
['1\n', '2\n', '3\n', '8\n']
Demo Output:
['1\n', '2\n', '2 1\n', '4\n']
Note:
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1 1. 2 1. 2 1 1. 3 1. 3 1 1. 3 2 1. 3 2 1 1. 4
|
```python
n = int(input())
i = 1
res_board = []
while i <= n:
res_board.append(1)
while True:
if len(res_board)>1:
if res_board[-2] == res_board[-1]:
res_board[-2] += 1
res_board.pop(-1)
else:
break
else:
break
i += 1
res_board = ' '.join([str(x) for x in res_board])
print(res_board)
```
| 3
|
|
915
|
A
|
Garden
|
PROGRAMMING
| 900
|
[
"implementation"
] | null | null |
Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each hour. Luba can't water any parts of the garden that were already watered, also she can't water the ground outside the garden.
Luba has to choose one of the buckets in order to water the garden as fast as possible (as mentioned above, each hour she will water some continuous subsegment of length *a**i* if she chooses the *i*-th bucket). Help her to determine the minimum number of hours she has to spend watering the garden. It is guaranteed that Luba can always choose a bucket so it is possible water the garden.
See the examples for better understanding.
|
The first line of input contains two integer numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of buckets and the length of the garden, respectively.
The second line of input contains *n* integer numbers *a**i* (1<=≤<=*a**i*<=≤<=100) — the length of the segment that can be watered by the *i*-th bucket in one hour.
It is guaranteed that there is at least one bucket such that it is possible to water the garden in integer number of hours using only this bucket.
|
Print one integer number — the minimum number of hours required to water the garden.
|
[
"3 6\n2 3 5\n",
"6 7\n1 2 3 4 5 6\n"
] |
[
"2\n",
"7\n"
] |
In the first test the best option is to choose the bucket that allows to water the segment of length 3. We can't choose the bucket that allows to water the segment of length 5 because then we can't water the whole garden.
In the second test we can choose only the bucket that allows us to water the segment of length 1.
| 0
|
[
{
"input": "3 6\n2 3 5",
"output": "2"
},
{
"input": "6 7\n1 2 3 4 5 6",
"output": "7"
},
{
"input": "5 97\n1 10 50 97 2",
"output": "1"
},
{
"input": "5 97\n1 10 50 100 2",
"output": "97"
},
{
"input": "100 100\n2 46 24 18 86 90 31 38 84 49 58 28 15 80 14 24 87 56 62 87 41 87 55 71 87 32 41 56 91 32 24 75 43 42 35 30 72 53 31 26 54 61 87 85 36 75 44 31 7 38 77 57 61 54 70 77 45 96 39 57 11 8 91 42 52 15 42 30 92 41 27 26 34 27 3 80 32 86 26 97 63 91 30 75 14 7 19 23 45 11 8 43 44 73 11 56 3 55 63 16",
"output": "50"
},
{
"input": "100 91\n13 13 62 96 74 47 81 46 78 21 20 42 4 73 25 30 76 74 58 28 25 52 42 48 74 40 82 9 25 29 17 22 46 64 57 95 81 39 47 86 40 95 97 35 31 98 45 98 47 78 52 63 58 14 89 97 17 95 28 22 20 36 68 38 95 16 2 26 54 47 42 31 31 81 21 21 65 40 82 53 60 71 75 33 96 98 6 22 95 12 5 48 18 27 58 62 5 96 36 75",
"output": "7"
},
{
"input": "8 8\n8 7 6 5 4 3 2 1",
"output": "1"
},
{
"input": "3 8\n4 3 2",
"output": "2"
},
{
"input": "3 8\n2 4 2",
"output": "2"
},
{
"input": "3 6\n1 3 2",
"output": "2"
},
{
"input": "3 6\n3 2 5",
"output": "2"
},
{
"input": "3 8\n4 2 1",
"output": "2"
},
{
"input": "5 6\n2 3 5 1 2",
"output": "2"
},
{
"input": "2 6\n5 3",
"output": "2"
},
{
"input": "4 12\n6 4 3 1",
"output": "2"
},
{
"input": "3 18\n1 9 6",
"output": "2"
},
{
"input": "3 9\n3 2 1",
"output": "3"
},
{
"input": "3 6\n5 3 2",
"output": "2"
},
{
"input": "2 10\n5 2",
"output": "2"
},
{
"input": "2 18\n6 3",
"output": "3"
},
{
"input": "4 12\n1 2 12 3",
"output": "1"
},
{
"input": "3 7\n3 2 1",
"output": "7"
},
{
"input": "3 6\n3 2 1",
"output": "2"
},
{
"input": "5 10\n5 4 3 2 1",
"output": "2"
},
{
"input": "5 16\n8 4 2 1 7",
"output": "2"
},
{
"input": "6 7\n6 5 4 3 7 1",
"output": "1"
},
{
"input": "2 6\n3 2",
"output": "2"
},
{
"input": "2 4\n4 1",
"output": "1"
},
{
"input": "6 8\n2 4 1 3 5 7",
"output": "2"
},
{
"input": "6 8\n6 5 4 3 2 1",
"output": "2"
},
{
"input": "6 15\n5 2 3 6 4 3",
"output": "3"
},
{
"input": "4 8\n2 4 8 1",
"output": "1"
},
{
"input": "2 5\n5 1",
"output": "1"
},
{
"input": "4 18\n3 1 1 2",
"output": "6"
},
{
"input": "2 1\n2 1",
"output": "1"
},
{
"input": "3 10\n2 10 5",
"output": "1"
},
{
"input": "5 12\n12 4 4 4 3",
"output": "1"
},
{
"input": "3 6\n6 3 2",
"output": "1"
},
{
"input": "2 2\n2 1",
"output": "1"
},
{
"input": "3 18\n1 9 3",
"output": "2"
},
{
"input": "3 8\n7 2 4",
"output": "2"
},
{
"input": "2 100\n99 1",
"output": "100"
},
{
"input": "4 12\n1 3 4 2",
"output": "3"
},
{
"input": "3 6\n2 3 1",
"output": "2"
},
{
"input": "4 6\n3 2 5 12",
"output": "2"
},
{
"input": "4 97\n97 1 50 10",
"output": "1"
},
{
"input": "3 12\n1 12 2",
"output": "1"
},
{
"input": "4 12\n1 4 3 2",
"output": "3"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "3 19\n7 1 1",
"output": "19"
},
{
"input": "5 12\n12 4 3 4 4",
"output": "1"
},
{
"input": "3 8\n8 4 2",
"output": "1"
},
{
"input": "3 3\n3 2 1",
"output": "1"
},
{
"input": "5 6\n3 2 4 2 2",
"output": "2"
},
{
"input": "2 16\n8 4",
"output": "2"
},
{
"input": "3 6\n10 2 3",
"output": "2"
},
{
"input": "5 3\n2 4 5 3 6",
"output": "1"
},
{
"input": "11 99\n1 2 3 6 5 4 7 8 99 33 66",
"output": "1"
},
{
"input": "3 12\n3 12 2",
"output": "1"
},
{
"input": "5 25\n24 5 15 25 23",
"output": "1"
},
{
"input": "2 4\n8 1",
"output": "4"
},
{
"input": "4 100\n2 50 4 1",
"output": "2"
},
{
"input": "3 28\n7 14 1",
"output": "2"
},
{
"input": "4 8\n2 8 4 1",
"output": "1"
},
{
"input": "4 6\n6 1 2 3",
"output": "1"
},
{
"input": "2 12\n4 3",
"output": "3"
},
{
"input": "4 12\n1 2 4 3",
"output": "3"
},
{
"input": "5 12\n2 3 12 6 4",
"output": "1"
},
{
"input": "4 4\n1 2 2 4",
"output": "1"
},
{
"input": "3 6\n2 3 2",
"output": "2"
},
{
"input": "4 21\n21 20 21 2",
"output": "1"
},
{
"input": "3 8\n3 4 2",
"output": "2"
},
{
"input": "1 25\n25",
"output": "1"
},
{
"input": "99 12\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99",
"output": "1"
},
{
"input": "98 12\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98",
"output": "1"
},
{
"input": "79 12\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79",
"output": "1"
},
{
"input": "4 32\n1 1 1 1",
"output": "32"
},
{
"input": "1 100\n1",
"output": "100"
},
{
"input": "2 100\n7 1",
"output": "100"
},
{
"input": "7 24\n1 3 6 4 5 2 7",
"output": "4"
},
{
"input": "6 87\n1 2 8 4 5 7",
"output": "87"
},
{
"input": "1 88\n1",
"output": "88"
},
{
"input": "1 89\n1",
"output": "89"
}
] | 1,651,633,304
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 1
| 31
| 0
|
n,k = map(int,input().split())
l = list(map(int,input().split()))
ans = 100
print(min(l))
|
Title: Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each hour. Luba can't water any parts of the garden that were already watered, also she can't water the ground outside the garden.
Luba has to choose one of the buckets in order to water the garden as fast as possible (as mentioned above, each hour she will water some continuous subsegment of length *a**i* if she chooses the *i*-th bucket). Help her to determine the minimum number of hours she has to spend watering the garden. It is guaranteed that Luba can always choose a bucket so it is possible water the garden.
See the examples for better understanding.
Input Specification:
The first line of input contains two integer numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of buckets and the length of the garden, respectively.
The second line of input contains *n* integer numbers *a**i* (1<=≤<=*a**i*<=≤<=100) — the length of the segment that can be watered by the *i*-th bucket in one hour.
It is guaranteed that there is at least one bucket such that it is possible to water the garden in integer number of hours using only this bucket.
Output Specification:
Print one integer number — the minimum number of hours required to water the garden.
Demo Input:
['3 6\n2 3 5\n', '6 7\n1 2 3 4 5 6\n']
Demo Output:
['2\n', '7\n']
Note:
In the first test the best option is to choose the bucket that allows to water the segment of length 3. We can't choose the bucket that allows to water the segment of length 5 because then we can't water the whole garden.
In the second test we can choose only the bucket that allows us to water the segment of length 1.
|
```python
n,k = map(int,input().split())
l = list(map(int,input().split()))
ans = 100
print(min(l))
```
| 0
|
|
102
|
B
|
Sum of Digits
|
PROGRAMMING
| 1,000
|
[
"implementation"
] |
B. Sum of Digits
|
2
|
265
|
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-digit?
|
The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes.
|
Print the number of times a number can be replaced by the sum of its digits until it only contains one digit.
|
[
"0\n",
"10\n",
"991\n"
] |
[
"0\n",
"1\n",
"3\n"
] |
In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transformations take place: 991 → 19 → 10 → 1. After three transformations the number becomes one-digit.
| 1,000
|
[
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output": "1"
},
{
"input": "86",
"output": "2"
},
{
"input": "2",
"output": "0"
},
{
"input": "8",
"output": "0"
},
{
"input": "34",
"output": "1"
},
{
"input": "13",
"output": "1"
},
{
"input": "28",
"output": "2"
},
{
"input": "23",
"output": "1"
},
{
"input": "57",
"output": "2"
},
{
"input": "29",
"output": "2"
},
{
"input": "353869285",
"output": "3"
},
{
"input": "549548646",
"output": "2"
},
{
"input": "858893424",
"output": "2"
},
{
"input": "644818852",
"output": "3"
},
{
"input": "360322525",
"output": "3"
},
{
"input": "122937520",
"output": "2"
},
{
"input": "288403032",
"output": "2"
},
{
"input": "677257481",
"output": "3"
},
{
"input": "58059561",
"output": "3"
},
{
"input": "211288847",
"output": "2"
},
{
"input": "339900034079539584",
"output": "2"
},
{
"input": "784084029310269952",
"output": "3"
},
{
"input": "774730557264864000",
"output": "3"
},
{
"input": "478233807148352256",
"output": "3"
},
{
"input": "165646874056812544",
"output": "3"
},
{
"input": "477533739511673792",
"output": "3"
},
{
"input": "660119944377002240",
"output": "3"
},
{
"input": "448375218506078080",
"output": "3"
},
{
"input": "77213334785795616",
"output": "3"
},
{
"input": "165767221702271872",
"output": "3"
},
{
"input": "1",
"output": "0"
},
{
"input": "5",
"output": "0"
},
{
"input": "8",
"output": "0"
},
{
"input": "156161456146164104103460452045416165146141414651641564105461465156445621465146514562146145465165145145614561465145614561",
"output": "3"
},
{
"input": "9",
"output": "0"
}
] | 1,657,731,122
| 2,147,483,647
|
PyPy 3
|
OK
|
TESTS
| 51
| 186
| 1,945,600
|
n = input()
count =0
while len(n) > 1 :
sum =0
for x in n:
sum+= int(x)
n = str(sum)
count+=1
print(count)
|
Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-digit?
Input Specification:
The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes.
Output Specification:
Print the number of times a number can be replaced by the sum of its digits until it only contains one digit.
Demo Input:
['0\n', '10\n', '991\n']
Demo Output:
['0\n', '1\n', '3\n']
Note:
In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transformations take place: 991 → 19 → 10 → 1. After three transformations the number becomes one-digit.
|
```python
n = input()
count =0
while len(n) > 1 :
sum =0
for x in n:
sum+= int(x)
n = str(sum)
count+=1
print(count)
```
| 3.949999
|
899
|
A
|
Splitting in Teams
|
PROGRAMMING
| 800
|
[
"constructive algorithms",
"greedy",
"math"
] | null | null |
There were *n* groups of students which came to write a training contest. A group is either one person who can write the contest with anyone else, or two people who want to write the contest in the same team.
The coach decided to form teams of exactly three people for this training. Determine the maximum number of teams of three people he can form. It is possible that he can't use all groups to form teams. For groups of two, either both students should write the contest, or both should not. If two students from a group of two will write the contest, they should be in the same team.
|
The first line contains single integer *n* (2<=≤<=*n*<=≤<=2·105) — the number of groups.
The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2), where *a**i* is the number of people in group *i*.
|
Print the maximum number of teams of three people the coach can form.
|
[
"4\n1 1 2 1\n",
"2\n2 2\n",
"7\n2 2 2 1 1 1 1\n",
"3\n1 1 1\n"
] |
[
"1\n",
"0\n",
"3\n",
"1\n"
] |
In the first example the coach can form one team. For example, he can take students from the first, second and fourth groups.
In the second example he can't make a single team.
In the third example the coach can form three teams. For example, he can do this in the following way:
- The first group (of two people) and the seventh group (of one person), - The second group (of two people) and the sixth group (of one person), - The third group (of two people) and the fourth group (of one person).
| 500
|
[
{
"input": "4\n1 1 2 1",
"output": "1"
},
{
"input": "2\n2 2",
"output": "0"
},
{
"input": "7\n2 2 2 1 1 1 1",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "3\n2 2 2",
"output": "0"
},
{
"input": "3\n1 2 1",
"output": "1"
},
{
"input": "5\n2 2 1 1 1",
"output": "2"
},
{
"input": "7\n1 1 2 2 1 2 1",
"output": "3"
},
{
"input": "10\n1 2 2 1 2 2 1 2 1 1",
"output": "5"
},
{
"input": "5\n2 2 2 1 2",
"output": "1"
},
{
"input": "43\n1 2 2 2 1 1 2 2 1 1 2 2 2 2 1 2 2 2 2 2 1 2 1 2 1 2 2 2 2 2 2 2 2 1 2 2 2 2 2 2 2 2 2",
"output": "10"
},
{
"input": "72\n1 2 1 2 2 1 2 1 1 1 1 2 2 1 2 1 2 1 2 2 2 2 1 2 2 2 2 1 2 1 1 2 2 1 1 2 2 2 2 2 1 1 1 1 2 2 1 1 2 1 1 1 1 2 2 1 2 2 1 2 1 1 2 1 2 2 1 1 1 2 2 2",
"output": "34"
},
{
"input": "64\n2 2 1 1 1 2 1 1 1 2 2 1 2 2 2 1 2 2 2 1 1 1 1 2 1 2 1 2 1 1 2 2 1 1 2 2 1 1 1 1 2 2 1 1 1 2 1 2 2 2 2 2 2 2 1 1 2 1 1 1 2 2 1 2",
"output": "32"
},
{
"input": "20\n1 1 1 1 2 1 2 2 2 1 2 1 2 1 2 1 1 2 1 2",
"output": "9"
},
{
"input": "23\n1 1 1 1 2 1 2 1 1 1 2 2 2 2 2 2 1 2 1 2 2 1 1",
"output": "11"
},
{
"input": "201\n1 1 2 2 2 2 1 1 1 2 2 1 2 1 2 1 2 2 2 1 1 2 1 1 1 2 1 2 1 1 1 2 1 1 2 1 2 2 1 1 1 1 2 1 1 2 1 1 1 2 2 2 2 1 2 1 2 2 2 2 2 2 1 1 1 2 2 1 1 1 1 2 2 1 2 1 1 2 2 1 1 2 2 2 1 1 1 2 1 1 2 1 2 2 1 2 2 2 2 1 1 1 2 1 2 2 2 2 2 1 2 1 1 1 2 2 2 2 2 1 2 1 1 2 2 2 1 1 2 2 1 2 2 2 1 1 1 2 1 1 1 2 1 1 2 2 2 1 2 1 1 1 2 2 1 1 2 2 2 2 2 2 1 2 2 1 2 2 2 1 1 2 2 1 1 2 1 1 1 1 2 1 1 1 2 2 1 2 1 1 2 2 1 1 2 1 2 1 1 1 2",
"output": "100"
},
{
"input": "247\n2 2 1 2 1 2 2 2 2 2 2 1 1 2 2 1 2 1 1 1 2 1 1 1 1 2 1 1 2 2 1 2 1 1 1 2 2 2 1 1 2 1 1 2 1 1 1 2 1 2 1 2 2 1 1 2 1 2 2 1 2 1 2 1 1 2 1 1 1 2 2 1 1 2 2 1 1 2 1 1 1 2 2 2 2 1 2 2 2 2 2 2 1 2 2 2 2 1 1 1 1 1 1 1 1 1 2 1 2 2 1 2 1 2 2 2 1 2 2 2 1 1 2 2 1 1 1 2 1 1 1 1 2 2 1 2 2 1 1 1 2 1 2 2 1 2 1 1 1 2 2 2 2 2 1 2 2 2 1 1 1 2 1 2 1 1 2 2 2 2 1 1 2 2 2 1 2 2 2 1 2 1 1 2 2 2 2 1 2 2 1 1 1 2 1 2 1 1 1 2 2 1 1 2 1 1 2 1 2 1 1 2 1 1 1 1 2 1 1 1 1 2 2 1 2 1 1 2 1 2 2 1 2 2 2 1 2 2 1 2 2 1 1 1 2 2 2",
"output": "123"
},
{
"input": "4\n2 2 2 2",
"output": "0"
},
{
"input": "4\n1 1 1 1",
"output": "1"
},
{
"input": "2\n1 1",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "2\n1 2",
"output": "1"
},
{
"input": "3\n1 1 2",
"output": "1"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n2 1 1",
"output": "1"
},
{
"input": "3\n2 1 2",
"output": "1"
},
{
"input": "3\n2 2 1",
"output": "1"
},
{
"input": "4\n1 1 1 2",
"output": "1"
},
{
"input": "4\n1 1 2 2",
"output": "2"
},
{
"input": "4\n1 2 2 2",
"output": "1"
},
{
"input": "4\n2 1 1 1",
"output": "1"
},
{
"input": "5\n1 1 1 1 2",
"output": "2"
},
{
"input": "14\n1 2 2 2 2 2 2 2 2 2 2 2 2 2",
"output": "1"
},
{
"input": "38\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 1",
"output": "1"
},
{
"input": "30\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 1",
"output": "1"
},
{
"input": "20\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 1",
"output": "1"
},
{
"input": "26\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 1 2 2 2 2",
"output": "1"
},
{
"input": "6\n1 1 1 2 2 2",
"output": "3"
},
{
"input": "5\n2 1 1 1 1",
"output": "2"
},
{
"input": "9\n1 1 1 1 1 1 2 2 2",
"output": "4"
},
{
"input": "10\n2 2 1 1 1 1 1 1 1 1",
"output": "4"
},
{
"input": "6\n1 1 1 1 1 1",
"output": "2"
}
] | 1,581,362,682
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 67
| 202
| 3,788,800
|
n = int(input())
numbers = input().split()
twos = []
ones = []
for i in range(n):
if(numbers[i] == '2'):
twos.append(numbers[i])
else:
ones.append(numbers[i])
count = 0
while(len(twos) != 0):
if(len(ones) != 0):
ones.pop()
twos.pop()
count += 1
else:
break
if(len(ones) // 3 != 0):
count += len(ones) // 3
print(count)
|
Title: Splitting in Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There were *n* groups of students which came to write a training contest. A group is either one person who can write the contest with anyone else, or two people who want to write the contest in the same team.
The coach decided to form teams of exactly three people for this training. Determine the maximum number of teams of three people he can form. It is possible that he can't use all groups to form teams. For groups of two, either both students should write the contest, or both should not. If two students from a group of two will write the contest, they should be in the same team.
Input Specification:
The first line contains single integer *n* (2<=≤<=*n*<=≤<=2·105) — the number of groups.
The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2), where *a**i* is the number of people in group *i*.
Output Specification:
Print the maximum number of teams of three people the coach can form.
Demo Input:
['4\n1 1 2 1\n', '2\n2 2\n', '7\n2 2 2 1 1 1 1\n', '3\n1 1 1\n']
Demo Output:
['1\n', '0\n', '3\n', '1\n']
Note:
In the first example the coach can form one team. For example, he can take students from the first, second and fourth groups.
In the second example he can't make a single team.
In the third example the coach can form three teams. For example, he can do this in the following way:
- The first group (of two people) and the seventh group (of one person), - The second group (of two people) and the sixth group (of one person), - The third group (of two people) and the fourth group (of one person).
|
```python
n = int(input())
numbers = input().split()
twos = []
ones = []
for i in range(n):
if(numbers[i] == '2'):
twos.append(numbers[i])
else:
ones.append(numbers[i])
count = 0
while(len(twos) != 0):
if(len(ones) != 0):
ones.pop()
twos.pop()
count += 1
else:
break
if(len(ones) // 3 != 0):
count += len(ones) // 3
print(count)
```
| 3
|
|
883
|
M
|
Quadcopter Competition
|
PROGRAMMING
| 1,100
|
[
"greedy",
"math"
] | null | null |
Polycarp takes part in a quadcopter competition. According to the rules a flying robot should:
- start the race from some point of a field, - go around the flag, - close cycle returning back to the starting point.
Polycarp knows the coordinates of the starting point (*x*1,<=*y*1) and the coordinates of the point where the flag is situated (*x*2,<=*y*2). Polycarp’s quadcopter can fly only parallel to the sides of the field each tick changing exactly one coordinate by 1. It means that in one tick the quadcopter can fly from the point (*x*,<=*y*) to any of four points: (*x*<=-<=1,<=*y*), (*x*<=+<=1,<=*y*), (*x*,<=*y*<=-<=1) or (*x*,<=*y*<=+<=1).
Thus the quadcopter path is a closed cycle starting and finishing in (*x*1,<=*y*1) and containing the point (*x*2,<=*y*2) strictly inside.
What is the minimal length of the quadcopter path?
|
The first line contains two integer numbers *x*1 and *y*1 (<=-<=100<=≤<=*x*1,<=*y*1<=≤<=100) — coordinates of the quadcopter starting (and finishing) point.
The second line contains two integer numbers *x*2 and *y*2 (<=-<=100<=≤<=*x*2,<=*y*2<=≤<=100) — coordinates of the flag.
It is guaranteed that the quadcopter starting point and the flag do not coincide.
|
Print the length of minimal path of the quadcopter to surround the flag and return back.
|
[
"1 5\n5 2\n",
"0 1\n0 0\n"
] |
[
"18\n",
"8\n"
] |
none
| 0
|
[
{
"input": "1 5\n5 2",
"output": "18"
},
{
"input": "0 1\n0 0",
"output": "8"
},
{
"input": "-100 -100\n100 100",
"output": "804"
},
{
"input": "-100 -100\n-100 100",
"output": "406"
},
{
"input": "-100 -100\n100 -100",
"output": "406"
},
{
"input": "100 -100\n-100 -100",
"output": "406"
},
{
"input": "100 -100\n-100 100",
"output": "804"
},
{
"input": "100 -100\n100 100",
"output": "406"
},
{
"input": "-100 100\n-100 -100",
"output": "406"
},
{
"input": "-100 100\n100 -100",
"output": "804"
},
{
"input": "-100 100\n100 100",
"output": "406"
},
{
"input": "100 100\n-100 -100",
"output": "804"
},
{
"input": "100 100\n-100 100",
"output": "406"
},
{
"input": "100 100\n100 -100",
"output": "406"
},
{
"input": "45 -43\n45 -44",
"output": "8"
},
{
"input": "76 76\n75 75",
"output": "8"
},
{
"input": "-34 -56\n-35 -56",
"output": "8"
},
{
"input": "56 -7\n55 -6",
"output": "8"
},
{
"input": "43 -11\n43 -10",
"output": "8"
},
{
"input": "1 -3\n2 -2",
"output": "8"
},
{
"input": "55 71\n56 71",
"output": "8"
},
{
"input": "54 -87\n55 -88",
"output": "8"
},
{
"input": "22 98\n100 33",
"output": "290"
},
{
"input": "37 84\n-83 5",
"output": "402"
},
{
"input": "52 74\n-73 -39",
"output": "480"
},
{
"input": "66 51\n51 -71",
"output": "278"
},
{
"input": "-31 44\n73 86",
"output": "296"
},
{
"input": "-20 34\n-9 55",
"output": "68"
},
{
"input": "-5 19\n-91 -86",
"output": "386"
},
{
"input": "-82 5\n28 -17",
"output": "268"
},
{
"input": "-90 -100\n55 48",
"output": "590"
},
{
"input": "-75 -14\n-32 8",
"output": "134"
},
{
"input": "-53 -28\n-13 -28",
"output": "86"
},
{
"input": "-42 -46\n10 -64",
"output": "144"
},
{
"input": "55 -42\n25 2",
"output": "152"
},
{
"input": "70 -64\n-54 70",
"output": "520"
},
{
"input": "93 -78\n-32 -75",
"output": "260"
},
{
"input": "8 -93\n79 -6",
"output": "320"
},
{
"input": "50 43\n54 10",
"output": "78"
},
{
"input": "65 32\n-37 71",
"output": "286"
},
{
"input": "80 18\n-15 -58",
"output": "346"
},
{
"input": "94 92\n4 -1",
"output": "370"
},
{
"input": "-10 96\n27 64",
"output": "142"
},
{
"input": "-96 78\n-56 32",
"output": "176"
},
{
"input": "-81 64\n-37 -8",
"output": "236"
},
{
"input": "-58 49\n74 -40",
"output": "446"
},
{
"input": "-62 -55\n1 18",
"output": "276"
},
{
"input": "-51 -69\n-78 86",
"output": "368"
},
{
"input": "-29 -80\n-56 -47",
"output": "124"
},
{
"input": "-14 -94\n55 -90",
"output": "150"
},
{
"input": "83 -2\n82 83",
"output": "176"
},
{
"input": "98 -16\n-96 40",
"output": "504"
},
{
"input": "17 -34\n-86 -93",
"output": "328"
},
{
"input": "32 -48\n33 -37",
"output": "28"
},
{
"input": "74 87\n3 92",
"output": "156"
},
{
"input": "89 73\n-80 49",
"output": "390"
},
{
"input": "4 58\n-61 -80",
"output": "410"
},
{
"input": "15 48\n50 -20",
"output": "210"
},
{
"input": "-82 45\n81 46",
"output": "332"
},
{
"input": "-68 26\n-2 6",
"output": "176"
},
{
"input": "-53 4\n-92 -31",
"output": "152"
},
{
"input": "-30 94\n31 -58",
"output": "430"
},
{
"input": "-38 -11\n58 99",
"output": "416"
},
{
"input": "-27 -25\n-28 68",
"output": "192"
},
{
"input": "-5 -39\n-10 -77",
"output": "90"
},
{
"input": "-90 -54\n9 -9",
"output": "292"
},
{
"input": "7 -57\n28 61",
"output": "282"
},
{
"input": "18 -67\n-51 21",
"output": "318"
},
{
"input": "41 -82\n-33 -15",
"output": "286"
},
{
"input": "56 -8\n91 -55",
"output": "168"
},
{
"input": "-23 -13\n-24 -12",
"output": "8"
},
{
"input": "1 32\n1 33",
"output": "8"
},
{
"input": "25 76\n24 76",
"output": "8"
},
{
"input": "-29 -78\n-28 -79",
"output": "8"
},
{
"input": "-77 19\n-76 19",
"output": "8"
},
{
"input": "-53 63\n-53 62",
"output": "8"
},
{
"input": "86 12\n86 11",
"output": "8"
},
{
"input": "14 56\n13 56",
"output": "8"
},
{
"input": "63 41\n62 40",
"output": "8"
},
{
"input": "0 -4\n1 -4",
"output": "8"
},
{
"input": "24 41\n24 42",
"output": "8"
},
{
"input": "48 85\n49 86",
"output": "8"
},
{
"input": "0 0\n0 1",
"output": "8"
},
{
"input": "0 0\n1 0",
"output": "8"
},
{
"input": "0 0\n1 1",
"output": "8"
},
{
"input": "0 1\n0 0",
"output": "8"
},
{
"input": "0 1\n1 0",
"output": "8"
},
{
"input": "0 1\n1 1",
"output": "8"
},
{
"input": "1 0\n0 0",
"output": "8"
},
{
"input": "1 0\n0 1",
"output": "8"
},
{
"input": "1 0\n1 1",
"output": "8"
},
{
"input": "1 1\n0 0",
"output": "8"
},
{
"input": "1 1\n0 1",
"output": "8"
},
{
"input": "1 1\n1 0",
"output": "8"
},
{
"input": "100 100\n99 -100",
"output": "406"
},
{
"input": "100 100\n-100 99",
"output": "406"
},
{
"input": "-100 -100\n-99 100",
"output": "406"
},
{
"input": "-100 -100\n100 -99",
"output": "406"
},
{
"input": "0 0\n1 2",
"output": "10"
},
{
"input": "0 0\n2 1",
"output": "10"
}
] | 1,600,092,063
| 2,147,483,647
|
PyPy 3
|
OK
|
TESTS
| 100
| 140
| 0
|
x1,y1 = map(int,input().split())
x2,y2 = map(int,input().split())
upperx = x2-1
lowerx = x2+1
uppery = y2-1
lowery = y2+1
cnt = 4 + abs(upperx - x1) + abs(lowerx - x1) + abs(uppery - y1) + abs(lowery - y1)
print(cnt)
|
Title: Quadcopter Competition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp takes part in a quadcopter competition. According to the rules a flying robot should:
- start the race from some point of a field, - go around the flag, - close cycle returning back to the starting point.
Polycarp knows the coordinates of the starting point (*x*1,<=*y*1) and the coordinates of the point where the flag is situated (*x*2,<=*y*2). Polycarp’s quadcopter can fly only parallel to the sides of the field each tick changing exactly one coordinate by 1. It means that in one tick the quadcopter can fly from the point (*x*,<=*y*) to any of four points: (*x*<=-<=1,<=*y*), (*x*<=+<=1,<=*y*), (*x*,<=*y*<=-<=1) or (*x*,<=*y*<=+<=1).
Thus the quadcopter path is a closed cycle starting and finishing in (*x*1,<=*y*1) and containing the point (*x*2,<=*y*2) strictly inside.
What is the minimal length of the quadcopter path?
Input Specification:
The first line contains two integer numbers *x*1 and *y*1 (<=-<=100<=≤<=*x*1,<=*y*1<=≤<=100) — coordinates of the quadcopter starting (and finishing) point.
The second line contains two integer numbers *x*2 and *y*2 (<=-<=100<=≤<=*x*2,<=*y*2<=≤<=100) — coordinates of the flag.
It is guaranteed that the quadcopter starting point and the flag do not coincide.
Output Specification:
Print the length of minimal path of the quadcopter to surround the flag and return back.
Demo Input:
['1 5\n5 2\n', '0 1\n0 0\n']
Demo Output:
['18\n', '8\n']
Note:
none
|
```python
x1,y1 = map(int,input().split())
x2,y2 = map(int,input().split())
upperx = x2-1
lowerx = x2+1
uppery = y2-1
lowery = y2+1
cnt = 4 + abs(upperx - x1) + abs(lowerx - x1) + abs(uppery - y1) + abs(lowery - y1)
print(cnt)
```
| 3
|
|
899
|
C
|
Dividing the numbers
|
PROGRAMMING
| 1,300
|
[
"constructive algorithms",
"graphs",
"math"
] | null | null |
Petya has *n* integers: 1,<=2,<=3,<=...,<=*n*. He wants to split these integers in two non-empty groups in such a way that the absolute difference of sums of integers in each group is as small as possible.
Help Petya to split the integers. Each of *n* integers should be exactly in one group.
|
The first line contains a single integer *n* (2<=≤<=*n*<=≤<=60<=000) — the number of integers Petya has.
|
Print the smallest possible absolute difference in the first line.
In the second line print the size of the first group, followed by the integers in that group. You can print these integers in arbitrary order. If there are multiple answers, print any of them.
|
[
"4\n",
"2\n"
] |
[
"0\n2 1 4 \n",
"1\n1 1 \n"
] |
In the first example you have to put integers 1 and 4 in the first group, and 2 and 3 in the second. This way the sum in each group is 5, and the absolute difference is 0.
In the second example there are only two integers, and since both groups should be non-empty, you have to put one integer in the first group and one in the second. This way the absolute difference of sums of integers in each group is 1.
| 1,500
|
[
{
"input": "4",
"output": "0\n2 1 4 "
},
{
"input": "2",
"output": "1\n1 1 "
},
{
"input": "3",
"output": "0\n1\n3 "
},
{
"input": "5",
"output": "1\n3\n1 2 5 "
},
{
"input": "59998",
"output": "1\n29999 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 ..."
},
{
"input": "60000",
"output": "0\n30000 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 ..."
},
{
"input": "59991",
"output": "0\n29995\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..."
},
{
"input": "59989",
"output": "1\n29995\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..."
},
{
"input": "6",
"output": "1\n3 1 4 5 "
},
{
"input": "7",
"output": "0\n3\n1 6 7 "
},
{
"input": "8",
"output": "0\n4 1 4 5 8 "
},
{
"input": "9",
"output": "1\n5\n1 2 3 8 9 "
},
{
"input": "10",
"output": "1\n5 1 4 5 8 9 "
},
{
"input": "11",
"output": "0\n5\n1 2 9 10 11 "
},
{
"input": "12",
"output": "0\n6 1 4 5 8 9 12 "
},
{
"input": "13",
"output": "1\n7\n1 2 3 4 11 12 13 "
},
{
"input": "14",
"output": "1\n7 1 4 5 8 9 12 13 "
},
{
"input": "15",
"output": "0\n7\n1 2 3 12 13 14 15 "
},
{
"input": "16",
"output": "0\n8 1 4 5 8 9 12 13 16 "
},
{
"input": "17",
"output": "1\n9\n1 2 3 4 5 14 15 16 17 "
},
{
"input": "18",
"output": "1\n9 1 4 5 8 9 12 13 16 17 "
},
{
"input": "19",
"output": "0\n9\n1 2 3 4 15 16 17 18 19 "
},
{
"input": "20",
"output": "0\n10 1 4 5 8 9 12 13 16 17 20 "
},
{
"input": "21",
"output": "1\n11\n1 2 3 4 5 6 17 18 19 20 21 "
},
{
"input": "22",
"output": "1\n11 1 4 5 8 9 12 13 16 17 20 21 "
},
{
"input": "23",
"output": "0\n11\n1 2 3 4 5 18 19 20 21 22 23 "
},
{
"input": "24",
"output": "0\n12 1 4 5 8 9 12 13 16 17 20 21 24 "
},
{
"input": "59999",
"output": "0\n29999\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..."
},
{
"input": "59997",
"output": "1\n29999\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..."
},
{
"input": "59996",
"output": "0\n29998 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 ..."
},
{
"input": "59995",
"output": "0\n29997\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..."
},
{
"input": "59994",
"output": "1\n29997 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 ..."
},
{
"input": "59993",
"output": "1\n29997\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..."
},
{
"input": "59992",
"output": "0\n29996 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 ..."
},
{
"input": "59990",
"output": "1\n29995 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 ..."
},
{
"input": "100",
"output": "0\n50 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 "
},
{
"input": "1000",
"output": "0\n500 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 28..."
},
{
"input": "10001",
"output": "1\n5001\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 15..."
},
{
"input": "103",
"output": "0\n51\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 "
},
{
"input": "1002",
"output": "1\n501 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 28..."
},
{
"input": "31724",
"output": "0\n15862 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 ..."
},
{
"input": "2032",
"output": "0\n1016 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 2..."
},
{
"input": "42620",
"output": "0\n21310 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 ..."
},
{
"input": "18076",
"output": "0\n9038 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 2..."
},
{
"input": "53520",
"output": "0\n26760 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 ..."
},
{
"input": "37193",
"output": "1\n18597\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..."
},
{
"input": "12645",
"output": "1\n6323\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 15..."
},
{
"input": "53237",
"output": "1\n26619\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..."
},
{
"input": "28693",
"output": "1\n14347\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..."
},
{
"input": "4145",
"output": "1\n2073\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 15..."
},
{
"input": "36042",
"output": "1\n18021 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 ..."
},
{
"input": "16646",
"output": "1\n8323 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 2..."
},
{
"input": "57238",
"output": "1\n28619 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 ..."
},
{
"input": "27542",
"output": "1\n13771 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 ..."
},
{
"input": "8146",
"output": "1\n4073 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 41 44 45 48 49 52 53 56 57 60 61 64 65 68 69 72 73 76 77 80 81 84 85 88 89 92 93 96 97 100 101 104 105 108 109 112 113 116 117 120 121 124 125 128 129 132 133 136 137 140 141 144 145 148 149 152 153 156 157 160 161 164 165 168 169 172 173 176 177 180 181 184 185 188 189 192 193 196 197 200 201 204 205 208 209 212 213 216 217 220 221 224 225 228 229 232 233 236 237 240 241 244 245 248 249 252 253 256 257 260 261 264 265 268 269 272 273 276 277 2..."
},
{
"input": "46659",
"output": "0\n23329\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..."
},
{
"input": "27259",
"output": "0\n13629\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..."
},
{
"input": "2715",
"output": "0\n1357\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 15..."
},
{
"input": "38159",
"output": "0\n19079\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 1..."
},
{
"input": "18759",
"output": "0\n9379\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 15..."
}
] | 1,513,546,400
| 2,147,483,647
|
PyPy 3
|
OK
|
TESTS
| 60
| 171
| 27,545,600
|
N = int(input())
List = list()
K, curr = (N * (N+1)) / 2, 0
want = K // 2
if K % 2 == 0:
print(0)
else:
print(1)
while N != 0:
if curr + N <= want:
curr += N
List.append(N)
N -= 1
print(len(List), end=" ")
for num in List:
print(num, end=" ")
|
Title: Dividing the numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya has *n* integers: 1,<=2,<=3,<=...,<=*n*. He wants to split these integers in two non-empty groups in such a way that the absolute difference of sums of integers in each group is as small as possible.
Help Petya to split the integers. Each of *n* integers should be exactly in one group.
Input Specification:
The first line contains a single integer *n* (2<=≤<=*n*<=≤<=60<=000) — the number of integers Petya has.
Output Specification:
Print the smallest possible absolute difference in the first line.
In the second line print the size of the first group, followed by the integers in that group. You can print these integers in arbitrary order. If there are multiple answers, print any of them.
Demo Input:
['4\n', '2\n']
Demo Output:
['0\n2 1 4 \n', '1\n1 1 \n']
Note:
In the first example you have to put integers 1 and 4 in the first group, and 2 and 3 in the second. This way the sum in each group is 5, and the absolute difference is 0.
In the second example there are only two integers, and since both groups should be non-empty, you have to put one integer in the first group and one in the second. This way the absolute difference of sums of integers in each group is 1.
|
```python
N = int(input())
List = list()
K, curr = (N * (N+1)) / 2, 0
want = K // 2
if K % 2 == 0:
print(0)
else:
print(1)
while N != 0:
if curr + N <= want:
curr += N
List.append(N)
N -= 1
print(len(List), end=" ")
for num in List:
print(num, end=" ")
```
| 3
|
|
844
|
B
|
Rectangles
|
PROGRAMMING
| 1,300
|
[
"combinatorics",
"math"
] | null | null |
You are given *n*<=×<=*m* table. Each cell of the table is colored white or black. Find the number of non-empty sets of cells such that:
1. All cells in a set have the same color. 1. Every two cells in a set share row or column.
|
The first line of input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the number of rows and the number of columns correspondingly.
The next *n* lines of input contain descriptions of rows. There are *m* integers, separated by spaces, in each line. The number equals 0 if the corresponding cell is colored white and equals 1 if the corresponding cell is colored black.
|
Output single integer — the number of non-empty sets from the problem description.
|
[
"1 1\n0\n",
"2 3\n1 0 1\n0 1 0\n"
] |
[
"1\n",
"8\n"
] |
In the second example, there are six one-element sets. Additionally, there are two two-element sets, the first one consists of the first and the third cells of the first row, the second one consists of the first and the third cells of the second row. To sum up, there are 8 sets.
| 1,000
|
[
{
"input": "1 1\n0",
"output": "1"
},
{
"input": "2 3\n1 0 1\n0 1 0",
"output": "8"
},
{
"input": "2 2\n1 1\n1 1",
"output": "8"
},
{
"input": "1 10\n0 0 0 0 0 0 0 0 0 0",
"output": "1023"
},
{
"input": "11 1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1",
"output": "2047"
},
{
"input": "10 11\n1 1 0 1 1 0 0 0 1 0 0\n1 0 0 1 1 1 0 0 1 1 0\n0 0 1 0 1 1 0 1 0 1 1\n0 1 1 1 0 1 0 1 0 0 0\n1 1 1 1 1 1 1 0 1 0 0\n1 1 0 1 1 1 1 0 0 1 1\n1 0 1 0 1 0 0 1 1 1 0\n1 1 0 0 0 0 0 1 0 1 1\n1 1 0 1 1 1 0 0 1 1 0\n1 0 1 1 0 0 1 0 0 1 1",
"output": "2444"
},
{
"input": "50 1\n0\n1\n0\n1\n0\n1\n0\n1\n1\n1\n0\n0\n1\n0\n0\n1\n1\n1\n1\n0\n1\n1\n0\n1\n1\n1\n0\n1\n0\n0\n0\n1\n1\n0\n1\n1\n0\n1\n0\n1\n0\n0\n1\n0\n0\n0\n1\n1\n0\n1",
"output": "142606334"
},
{
"input": "1 50\n0 1 0 1 0 1 0 1 1 1 0 0 1 0 0 1 1 1 1 0 1 1 0 1 1 1 0 1 0 0 0 1 1 0 1 1 0 1 0 1 0 0 1 0 0 0 1 1 0 1",
"output": "142606334"
},
{
"input": "2 20\n0 1 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 1 0\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0",
"output": "589853"
},
{
"input": "5 5\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "285"
},
{
"input": "6 6\n1 1 1 1 1 1\n1 1 1 1 1 1\n1 1 1 1 1 1\n1 1 1 1 1 1\n1 1 1 1 1 1\n1 1 1 1 1 1",
"output": "720"
},
{
"input": "21 2\n0 1\n1 1\n0 1\n0 0\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1",
"output": "1310745"
},
{
"input": "3 15\n1 0 0 0 0 0 0 0 0 0 0 0 0 0 0\n0 0 0 0 0 1 0 1 0 0 0 0 0 1 0\n1 0 0 1 0 0 0 0 0 0 0 0 1 0 1",
"output": "22587"
},
{
"input": "10 11\n0 1 0 0 0 0 0 0 0 0 0\n0 1 0 1 0 0 1 0 0 0 0\n0 0 0 0 0 0 1 1 1 0 0\n0 0 0 0 0 0 0 0 0 0 0\n0 0 0 0 1 0 0 0 0 1 0\n0 0 0 0 0 0 1 0 0 0 0\n0 0 0 0 0 0 0 0 0 1 0\n0 0 1 0 0 0 1 1 0 0 0\n0 0 0 0 0 0 0 0 1 0 0\n0 0 1 0 1 0 0 0 0 1 1",
"output": "12047"
},
{
"input": "14 15\n0 1 0 0 0 0 0 0 1 0 0 0 1 0 1\n0 0 0 1 1 1 1 0 1 0 0 1 1 0 0\n1 0 0 0 0 1 1 0 0 0 0 0 0 0 0\n0 1 0 0 0 1 0 1 1 0 0 1 0 0 0\n0 0 1 1 0 1 0 1 0 1 1 0 1 0 0\n0 0 0 1 1 0 0 0 0 0 1 1 0 1 0\n0 0 1 0 0 0 0 0 0 1 0 0 1 1 0\n1 1 0 0 0 1 0 0 0 0 0 0 1 1 0\n0 0 0 0 1 0 1 1 1 0 0 0 1 0 1\n1 0 1 1 0 1 0 0 1 0 0 1 1 1 0\n1 0 0 0 0 1 0 0 0 0 0 1 0 0 0\n0 0 0 1 0 1 0 0 0 0 1 0 0 0 1\n0 0 1 0 1 0 0 0 1 1 1 1 0 0 0\n0 0 0 0 0 0 0 0 0 0 0 1 0 0 0",
"output": "53166"
},
{
"input": "1 50\n0 0 0 0 0 0 0 1 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 1 0 0 0 0 1 0 0 0 1 0 0",
"output": "1099511628798"
},
{
"input": "50 1\n0\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n0\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n0\n1\n1\n1\n1\n1\n1\n1\n0\n1\n1\n1\n1\n0\n1\n1\n1\n1\n1",
"output": "35184372088862"
},
{
"input": "1 50\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "1125899906842623"
},
{
"input": "5 50\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "5629499534214415"
},
{
"input": "32 2\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1",
"output": "8589934622"
},
{
"input": "1 50\n0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "562949953421312"
},
{
"input": "50 1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1",
"output": "1125899906842623"
},
{
"input": "1 49\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "562949953421311"
},
{
"input": "2 50\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0",
"output": "2251799813685296"
},
{
"input": "3 50\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "3377699720528069"
},
{
"input": "1 50\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0",
"output": "1125899906842623"
},
{
"input": "1 40\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "1099511627775"
},
{
"input": "1 33\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "8589934591"
},
{
"input": "2 40\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0",
"output": "2199023255590"
},
{
"input": "1 35\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "34359738367"
},
{
"input": "50 1\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0\n0",
"output": "1125899906842623"
}
] | 1,503,595,409
| 2,909
|
Python 3
|
OK
|
TESTS
| 55
| 62
| 0
|
from math import pow
n,m=[int(i) for i in input().split()]
l=[]
for i in range(n):
l.append([int(j) for j in input().split()])
count= n*m
for i in range(n):
count1=l[i].count(0)
if (count1!=0 and count1!=1):
count+=int(pow(2,count1)-1-count1)
count2=m-count1
if (count2!=0 and count2!=1):
count+=int(pow(2,count2)-1-count2)
for i in range(m):
count1=0
count2=0
for j in range(n):
if (l[j][i]==0):
count1+=1
else:
count2+=1
if (count1!=0 and count1!=1):
count+=int(pow(2,count1)-1-count1)
count2=n-count1
if (count2!=0 and count2!=1):
count+=int(pow(2,count2)-1-count2)
print (count)
|
Title: Rectangles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n*<=×<=*m* table. Each cell of the table is colored white or black. Find the number of non-empty sets of cells such that:
1. All cells in a set have the same color. 1. Every two cells in a set share row or column.
Input Specification:
The first line of input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the number of rows and the number of columns correspondingly.
The next *n* lines of input contain descriptions of rows. There are *m* integers, separated by spaces, in each line. The number equals 0 if the corresponding cell is colored white and equals 1 if the corresponding cell is colored black.
Output Specification:
Output single integer — the number of non-empty sets from the problem description.
Demo Input:
['1 1\n0\n', '2 3\n1 0 1\n0 1 0\n']
Demo Output:
['1\n', '8\n']
Note:
In the second example, there are six one-element sets. Additionally, there are two two-element sets, the first one consists of the first and the third cells of the first row, the second one consists of the first and the third cells of the second row. To sum up, there are 8 sets.
|
```python
from math import pow
n,m=[int(i) for i in input().split()]
l=[]
for i in range(n):
l.append([int(j) for j in input().split()])
count= n*m
for i in range(n):
count1=l[i].count(0)
if (count1!=0 and count1!=1):
count+=int(pow(2,count1)-1-count1)
count2=m-count1
if (count2!=0 and count2!=1):
count+=int(pow(2,count2)-1-count2)
for i in range(m):
count1=0
count2=0
for j in range(n):
if (l[j][i]==0):
count1+=1
else:
count2+=1
if (count1!=0 and count1!=1):
count+=int(pow(2,count1)-1-count1)
count2=n-count1
if (count2!=0 and count2!=1):
count+=int(pow(2,count2)-1-count2)
print (count)
```
| 3
|
|
0
|
none
|
none
|
none
| 0
|
[
"none"
] | null | null |
Beroffice text editor has a wide range of features that help working with text. One of the features is an automatic search for typos and suggestions of how to fix them.
Beroffice works only with small English letters (i.e. with 26 letters from a to z). Beroffice thinks that a word is typed with a typo if there are three or more consonants in a row in the word. The only exception is that if the block of consonants has all letters the same, then this block (even if its length is greater than three) is not considered a typo. Formally, a word is typed with a typo if there is a block of not less that three consonants in a row, and there are at least two different letters in this block.
For example:
- the following words have typos: "hellno", "hackcerrs" and "backtothefutttture"; - the following words don't have typos: "helllllooooo", "tobeornottobe" and "oooooo".
When Beroffice editor finds a word with a typo, it inserts as little as possible number of spaces in this word (dividing it into several words) in such a way that each of the resulting words is typed without any typos.
Implement this feature of Beroffice editor. Consider the following letters as the only vowels: 'a', 'e', 'i', 'o' and 'u'. All the other letters are consonants in this problem.
|
The only line contains a non-empty word consisting of small English letters. The length of the word is between 1 and 3000 letters.
|
Print the given word without any changes if there are no typos.
If there is at least one typo in the word, insert the minimum number of spaces into the word so that each of the resulting words doesn't have any typos. If there are multiple solutions, print any of them.
|
[
"hellno\n",
"abacaba\n",
"asdfasdf\n"
] |
[
"hell no \n",
"abacaba \n",
"asd fasd f \n"
] |
none
| 0
|
[
{
"input": "hellno",
"output": "hell no "
},
{
"input": "abacaba",
"output": "abacaba "
},
{
"input": "asdfasdf",
"output": "asd fasd f "
},
{
"input": "ooo",
"output": "ooo "
},
{
"input": "moyaoborona",
"output": "moyaoborona "
},
{
"input": "jxegxxx",
"output": "jxegx xx "
},
{
"input": "orfyaenanabckumulsboloyhljhacdgcmnooxvxrtuhcslxgslfpnfnyejbxqisxjyoyvcvuddboxkqgbogkfz",
"output": "orf yaenanabc kumuls boloyh lj hacd gc mnooxv xr tuhc sl xg sl fp nf nyejb xqisx jyoyv cvudd boxk qg bogk fz "
},
{
"input": "zxdgmhsjotvajkwshjpvzcuwehpeyfhakhtlvuoftkgdmvpafmxcliqvrztloocziqdkexhzcbdgxaoyvte",
"output": "zx dg mh sjotvajk ws hj pv zcuwehpeyf hakh tl vuoft kg dm vpafm xc liqv rz tloocziqd kexh zc bd gxaoyv te "
},
{
"input": "niblehmwtycadhbfuginpyafszjbucaszihijndzjtuyuaxkrovotshtsajmdcflnfdmahzbvpymiczqqleedpofcnvhieknlz",
"output": "niblehm wt ycadh bfuginp yafs zj bucaszihijn dz jtuyuaxk rovots ht sajm dc fl nf dmahz bv py micz qq leedpofc nv hiekn lz "
},
{
"input": "pqvtgtctpkgjgxnposjqedofficoyznxlerxyqypyzpoehejtjvyafjxjppywwgeakf",
"output": "pq vt gt ct pk gj gx nposj qedofficoyz nx lerx yq yp yz poehejt jv yafj xj pp yw wgeakf "
},
{
"input": "mvjajoyeg",
"output": "mv jajoyeg "
},
{
"input": "dipxocwjosvdaillxolmthjhzhsxskzqslebpixpuhpgeesrkedhohisdsjsrkiktbjzlhectrfcathvewzficirqbdvzq",
"output": "dipxocw josv daill xolm th jh zh sx sk zq slebpixpuhp geesr kedhohisd sj sr kikt bj zl hect rf cath vewz ficirq bd vz q "
},
{
"input": "ibbtvelwjirxqermucqrgmoauonisgmarjxxybllktccdykvef",
"output": "ibb tvelw jirx qermucq rg moauonisg marj xx yb ll kt cc dy kvef "
},
{
"input": "jxevkmrwlomaaahaubvjzqtyfqhqbhpqhomxqpiuersltohinvfyeykmlooujymldjqhgqjkvqknlyj",
"output": "jxevk mr wlomaaahaubv jz qt yf qh qb hp qhomx qpiuers ltohinv fyeyk mlooujy ml dj qh gq jk vq kn ly j "
},
{
"input": "hzxkuwqxonsulnndlhygvmallghjerwp",
"output": "hz xkuwq xonsuln nd lh yg vmall gh jerw p "
},
{
"input": "jbvcsjdyzlzmxwcvmixunfzxidzvwzaqqdhguvelwbdosbd",
"output": "jb vc sj dy zl zm xw cv mixunf zxidz vw zaqq dh guvelw bdosb d "
},
{
"input": "uyrsxaqmtibbxpfabprvnvbinjoxubupvfyjlqnfrfdeptipketwghr",
"output": "uyr sxaqm tibb xp fabp rv nv binjoxubupv fy jl qn fr fdeptipketw gh r "
},
{
"input": "xfcftysljytybkkzkpqdzralahgvbkxdtheqrhfxpecdjqofnyiahggnkiuusalu",
"output": "xf cf ty sl jy ty bk kz kp qd zralahg vb kx dt heqr hf xpecd jqofn yiahg gn kiuusalu "
},
{
"input": "a",
"output": "a "
},
{
"input": "b",
"output": "b "
},
{
"input": "aa",
"output": "aa "
},
{
"input": "ab",
"output": "ab "
},
{
"input": "ba",
"output": "ba "
},
{
"input": "bb",
"output": "bb "
},
{
"input": "aaa",
"output": "aaa "
},
{
"input": "aab",
"output": "aab "
},
{
"input": "aba",
"output": "aba "
},
{
"input": "abb",
"output": "abb "
},
{
"input": "baa",
"output": "baa "
},
{
"input": "bab",
"output": "bab "
},
{
"input": "bba",
"output": "bba "
},
{
"input": "bbb",
"output": "bbb "
},
{
"input": "bbc",
"output": "bb c "
},
{
"input": "bcb",
"output": "bc b "
},
{
"input": "cbb",
"output": "cb b "
},
{
"input": "bababcdfabbcabcdfacbbabcdfacacabcdfacbcabcdfaccbabcdfacaaabcdfabacabcdfabcbabcdfacbaabcdfabaaabcdfabbaabcdfacababcdfabbbabcdfabcaabcdfaaababcdfabccabcdfacccabcdfaacbabcdfaabaabcdfaabcabcdfaaacabcdfaccaabcdfaabbabcdfaaaaabcdfaacaabcdfaacc",
"output": "bababc dfabb cabc dfacb babc dfacacabc dfacb cabc dfacc babc dfacaaabc dfabacabc dfabc babc dfacbaabc dfabaaabc dfabbaabc dfacababc dfabbbabc dfabcaabc dfaaababc dfabc cabc dfacccabc dfaacbabc dfaabaabc dfaabcabc dfaaacabc dfaccaabc dfaabbabc dfaaaaabc dfaacaabc dfaacc "
},
{
"input": "bddabcdfaccdabcdfadddabcdfabbdabcdfacddabcdfacdbabcdfacbbabcdfacbcabcdfacbdabcdfadbbabcdfabdbabcdfabdcabcdfabbcabcdfabccabcdfabbbabcdfaddcabcdfaccbabcdfadbdabcdfacccabcdfadcdabcdfadcbabcdfabcbabcdfadbcabcdfacdcabcdfabcdabcdfadccabcdfaddb",
"output": "bd dabc dfacc dabc dfadddabc dfabb dabc dfacd dabc dfacd babc dfacb babc dfacb cabc dfacb dabc dfadb babc dfabd babc dfabd cabc dfabb cabc dfabc cabc dfabbbabc dfadd cabc dfacc babc dfadb dabc dfacccabc dfadc dabc dfadc babc dfabc babc dfadb cabc dfacd cabc dfabc dabc dfadc cabc dfadd b "
},
{
"input": "helllllooooo",
"output": "helllllooooo "
},
{
"input": "bbbzxxx",
"output": "bbb zx xx "
},
{
"input": "ffff",
"output": "ffff "
},
{
"input": "cdddddddddddddddddd",
"output": "cd ddddddddddddddddd "
},
{
"input": "bbbc",
"output": "bbb c "
},
{
"input": "lll",
"output": "lll "
},
{
"input": "bbbbb",
"output": "bbbbb "
},
{
"input": "llll",
"output": "llll "
},
{
"input": "bbbbbbccc",
"output": "bbbbbb ccc "
},
{
"input": "lllllb",
"output": "lllll b "
},
{
"input": "zzzzzzzzzzzzzzzzzzzzzzzzzzzzzz",
"output": "zzzzzzzzzzzzzzzzzzzzzzzzzzzzzz "
},
{
"input": "lllll",
"output": "lllll "
},
{
"input": "bbbbbbbbbc",
"output": "bbbbbbbbb c "
},
{
"input": "helllllno",
"output": "helllll no "
},
{
"input": "nnnnnnnnnnnn",
"output": "nnnnnnnnnnnn "
},
{
"input": "bbbbbccc",
"output": "bbbbb ccc "
},
{
"input": "zzzzzzzzzzzzzzzzzzzzzzzzzzzzz",
"output": "zzzzzzzzzzzzzzzzzzzzzzzzzzzzz "
},
{
"input": "nnnnnnnnnnnnnnnnnn",
"output": "nnnnnnnnnnnnnnnnnn "
},
{
"input": "zzzzzzzzzzzzzzzzzzzzzzz",
"output": "zzzzzzzzzzzzzzzzzzzzzzz "
},
{
"input": "hhhh",
"output": "hhhh "
},
{
"input": "nnnnnnnnnnnnnnnnnnnnnnnnn",
"output": "nnnnnnnnnnnnnnnnnnnnnnnnn "
},
{
"input": "zzzzzzzzzz",
"output": "zzzzzzzzzz "
},
{
"input": "dddd",
"output": "dddd "
},
{
"input": "heffffffgggggghhhhhh",
"output": "heffffff gggggg hhhhhh "
},
{
"input": "bcddd",
"output": "bc ddd "
},
{
"input": "x",
"output": "x "
},
{
"input": "nnn",
"output": "nnn "
},
{
"input": "xxxxxxxx",
"output": "xxxxxxxx "
},
{
"input": "cclcc",
"output": "cc lc c "
},
{
"input": "tttttttttttttt",
"output": "tttttttttttttt "
},
{
"input": "xxxxxxx",
"output": "xxxxxxx "
},
{
"input": "ccccb",
"output": "cccc b "
},
{
"input": "bcecccc",
"output": "bcecccc "
},
{
"input": "jjja",
"output": "jjja "
},
{
"input": "zzz",
"output": "zzz "
},
{
"input": "xxxxxxxxxzzzzzzzzzzzz",
"output": "xxxxxxxxx zzzzzzzzzzzz "
},
{
"input": "alllewww",
"output": "alllewww "
},
{
"input": "bbbbbbbbb",
"output": "bbbbbbbbb "
},
{
"input": "jjj",
"output": "jjj "
},
{
"input": "bbbbbbbbbbbbbbbbbbbbbbbbb",
"output": "bbbbbbbbbbbbbbbbbbbbbbbbb "
},
{
"input": "kkkkkkkkkklllllllllllllll",
"output": "kkkkkkkkkk lllllllllllllll "
},
{
"input": "helllllllllllo",
"output": "helllllllllllo "
},
{
"input": "ttttsttttt",
"output": "tttt st tttt "
},
{
"input": "tttttttsssssss",
"output": "ttttttt sssssss "
},
{
"input": "assstttttatsfatsfdjfdhtsjdsaatttssssststsss",
"output": "asss tttttats fats fd jf dh ts jd saattt sssss ts ts ss "
},
{
"input": "xxxxx",
"output": "xxxxx "
},
{
"input": "bbbhbbb",
"output": "bbb hb bb "
},
{
"input": "bbbbbbbb",
"output": "bbbbbbbb "
}
] | 1,505,745,911
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 5
| 61
| 4,608,000
|
# coding: utf-8
# 434C - Division 2 - Did you mean...
# (http://codeforces.com/contest/861/problem/C)
def check(arr, c):
arr = arr[:]
arr.append(c)
first = arr[0]
for elem in arr:
if elem != first:
return False
return True
word = input()
con = []
answer = ""
for c in word:
if c in "aeiou":
answer += "".join(con) + c
con = []
elif len(con) + 1 >= 3 and not check(con, c):
answer += "".join(con) + " " + c
con = []
else:
con.append(c)
print(answer)
|
Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Beroffice text editor has a wide range of features that help working with text. One of the features is an automatic search for typos and suggestions of how to fix them.
Beroffice works only with small English letters (i.e. with 26 letters from a to z). Beroffice thinks that a word is typed with a typo if there are three or more consonants in a row in the word. The only exception is that if the block of consonants has all letters the same, then this block (even if its length is greater than three) is not considered a typo. Formally, a word is typed with a typo if there is a block of not less that three consonants in a row, and there are at least two different letters in this block.
For example:
- the following words have typos: "hellno", "hackcerrs" and "backtothefutttture"; - the following words don't have typos: "helllllooooo", "tobeornottobe" and "oooooo".
When Beroffice editor finds a word with a typo, it inserts as little as possible number of spaces in this word (dividing it into several words) in such a way that each of the resulting words is typed without any typos.
Implement this feature of Beroffice editor. Consider the following letters as the only vowels: 'a', 'e', 'i', 'o' and 'u'. All the other letters are consonants in this problem.
Input Specification:
The only line contains a non-empty word consisting of small English letters. The length of the word is between 1 and 3000 letters.
Output Specification:
Print the given word without any changes if there are no typos.
If there is at least one typo in the word, insert the minimum number of spaces into the word so that each of the resulting words doesn't have any typos. If there are multiple solutions, print any of them.
Demo Input:
['hellno\n', 'abacaba\n', 'asdfasdf\n']
Demo Output:
['hell no \n', 'abacaba \n', 'asd fasd f \n']
Note:
none
|
```python
# coding: utf-8
# 434C - Division 2 - Did you mean...
# (http://codeforces.com/contest/861/problem/C)
def check(arr, c):
arr = arr[:]
arr.append(c)
first = arr[0]
for elem in arr:
if elem != first:
return False
return True
word = input()
con = []
answer = ""
for c in word:
if c in "aeiou":
answer += "".join(con) + c
con = []
elif len(con) + 1 >= 3 and not check(con, c):
answer += "".join(con) + " " + c
con = []
else:
con.append(c)
print(answer)
```
| 0
|
|
318
|
A
|
Even Odds
|
PROGRAMMING
| 900
|
[
"math"
] | null | null |
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first *n*. He writes down the following sequence of numbers: firstly all odd integers from 1 to *n* (in ascending order), then all even integers from 1 to *n* (also in ascending order). Help our hero to find out which number will stand at the position number *k*.
|
The only line of input contains integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
|
Print the number that will stand at the position number *k* after Volodya's manipulations.
|
[
"10 3\n",
"7 7\n"
] |
[
"5",
"6"
] |
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5.
| 500
|
[
{
"input": "10 3",
"output": "5"
},
{
"input": "7 7",
"output": "6"
},
{
"input": "7 1",
"output": "1"
},
{
"input": "7 2",
"output": "3"
},
{
"input": "8 5",
"output": "2"
},
{
"input": "8 3",
"output": "5"
},
{
"input": "8 4",
"output": "7"
},
{
"input": "1000000000000 500000000001",
"output": "2"
},
{
"input": "999999999997 499999999999",
"output": "999999999997"
},
{
"input": "999999999999 999999999999",
"output": "999999999998"
},
{
"input": "1000000000000 1",
"output": "1"
},
{
"input": "999999999999 1",
"output": "1"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1000000000000 1000000000000",
"output": "1000000000000"
},
{
"input": "1000000000000 500000000000",
"output": "999999999999"
},
{
"input": "1000000000000 499999999999",
"output": "999999999997"
},
{
"input": "999999999997 499999999998",
"output": "999999999995"
},
{
"input": "619234238 556154835",
"output": "493075432"
},
{
"input": "38151981 36650624",
"output": "35149266"
},
{
"input": "680402465 442571217",
"output": "204739968"
},
{
"input": "109135284 9408714",
"output": "18817427"
},
{
"input": "603701841 56038951",
"output": "112077901"
},
{
"input": "356764822 321510177",
"output": "286255532"
},
{
"input": "284911189 142190783",
"output": "284381565"
},
{
"input": "91028405 61435545",
"output": "31842684"
}
] | 1,693,413,329
| 2,147,483,647
|
Python 3
|
RUNTIME_ERROR
|
TESTS
| 0
| 60
| 0
|
n=input()
n=int(n)
if n%2==0 and n!=2:
print("no")
else:
print("yes")
|
Title: Even Odds
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first *n*. He writes down the following sequence of numbers: firstly all odd integers from 1 to *n* (in ascending order), then all even integers from 1 to *n* (also in ascending order). Help our hero to find out which number will stand at the position number *k*.
Input Specification:
The only line of input contains integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output Specification:
Print the number that will stand at the position number *k* after Volodya's manipulations.
Demo Input:
['10 3\n', '7 7\n']
Demo Output:
['5', '6']
Note:
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5.
|
```python
n=input()
n=int(n)
if n%2==0 and n!=2:
print("no")
else:
print("yes")
```
| -1
|
|
125
|
E
|
MST Company
|
PROGRAMMING
| 2,400
|
[
"binary search",
"graphs"
] | null | null |
The MST (Meaningless State Team) company won another tender for an important state reform in Berland.
There are *n* cities in Berland, some pairs of the cities are connected by roads. Each road has its price. One can move along any road in any direction. The MST team should carry out the repair works on some set of roads such that one can get from any city to any other one moving only along the repaired roads. Moreover, this set should contain exactly *k* capital roads (that is, the roads that start or finish in the capital). The number of the capital is 1.
As the budget has already been approved, the MST Company will profit by finding the set with minimum lengths of roads.
|
The first input line contains three integers *n*,<=*m*,<=*k* (1<=≤<=*n*<=≤<=5000;0<=≤<=*m*<=≤<=105;0<=≤<=*k*<=<<=5000), where *n* is the number of cities in the country, *m* is the number of roads in the country, *k* is the number of capital roads in the required set. Then *m* lines enumerate the roads in question. Each road is specified by three numbers *a**i*,<=*b**i*,<=*w**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*; 1<=≤<=*w*<=≤<=105), where *a**i*,<=*b**i* are the numbers of cities linked by a road and *w**i* is its length.
Between each pair of cities no more than one road exists. There are no roads that start and finish in one city. The capital's number is 1.
|
In the first line print the number of roads in the required set. The second line should contain the numbers of roads included in the sought set. If the sought set does not exist, print -1.
|
[
"4 5 2\n1 2 1\n2 3 1\n3 4 1\n1 3 3\n1 4 2\n"
] |
[
"3\n1 5 2 "
] |
none
| 5,000
|
[] | 1,649,084,279
| 2,147,483,647
|
Python 3
|
RUNTIME_ERROR
|
TESTS
| 1
| 62
| 0
|
n, m, k = map(int, input().split())
graph = {}
for i in range(1, m+1):
a,b,w = map(int, input().split())
if a in graph:
graph[a].append((b,w,i))
else:
graph[a] = [(b,w,i)]
if b in graph:
graph[b].append((a,w,i))
else:
graph[b] = [(a,w,i)]
for i in range(1, n+1):
graph[i].sort(key = lambda x:x[1])
#output = 0
visited = {1}
roads = []
for i in range(k):
(node, dist, num) = graph[1].pop(0)
visited.add(node)
#output += dist
roads.append(num)
while len(visited) < n:
current_min = float('inf')
for node in visited:
for next_node, dist, num in graph[node]:
if next_node not in visited:
if dist < current_min:
to_add = next_node
current_min = dist
the_road = num
visited.add(to_add)
#output += dist
roads.append(the_road)
print(len(roads))
for road in roads:
print(road, end=' ')
print()
|
Title: MST Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The MST (Meaningless State Team) company won another tender for an important state reform in Berland.
There are *n* cities in Berland, some pairs of the cities are connected by roads. Each road has its price. One can move along any road in any direction. The MST team should carry out the repair works on some set of roads such that one can get from any city to any other one moving only along the repaired roads. Moreover, this set should contain exactly *k* capital roads (that is, the roads that start or finish in the capital). The number of the capital is 1.
As the budget has already been approved, the MST Company will profit by finding the set with minimum lengths of roads.
Input Specification:
The first input line contains three integers *n*,<=*m*,<=*k* (1<=≤<=*n*<=≤<=5000;0<=≤<=*m*<=≤<=105;0<=≤<=*k*<=<<=5000), where *n* is the number of cities in the country, *m* is the number of roads in the country, *k* is the number of capital roads in the required set. Then *m* lines enumerate the roads in question. Each road is specified by three numbers *a**i*,<=*b**i*,<=*w**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*; 1<=≤<=*w*<=≤<=105), where *a**i*,<=*b**i* are the numbers of cities linked by a road and *w**i* is its length.
Between each pair of cities no more than one road exists. There are no roads that start and finish in one city. The capital's number is 1.
Output Specification:
In the first line print the number of roads in the required set. The second line should contain the numbers of roads included in the sought set. If the sought set does not exist, print -1.
Demo Input:
['4 5 2\n1 2 1\n2 3 1\n3 4 1\n1 3 3\n1 4 2\n']
Demo Output:
['3\n1 5 2 ']
Note:
none
|
```python
n, m, k = map(int, input().split())
graph = {}
for i in range(1, m+1):
a,b,w = map(int, input().split())
if a in graph:
graph[a].append((b,w,i))
else:
graph[a] = [(b,w,i)]
if b in graph:
graph[b].append((a,w,i))
else:
graph[b] = [(a,w,i)]
for i in range(1, n+1):
graph[i].sort(key = lambda x:x[1])
#output = 0
visited = {1}
roads = []
for i in range(k):
(node, dist, num) = graph[1].pop(0)
visited.add(node)
#output += dist
roads.append(num)
while len(visited) < n:
current_min = float('inf')
for node in visited:
for next_node, dist, num in graph[node]:
if next_node not in visited:
if dist < current_min:
to_add = next_node
current_min = dist
the_road = num
visited.add(to_add)
#output += dist
roads.append(the_road)
print(len(roads))
for road in roads:
print(road, end=' ')
print()
```
| -1
|
|
313
|
B
|
Ilya and Queries
|
PROGRAMMING
| 1,100
|
[
"dp",
"implementation"
] | null | null |
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string *s*<==<=*s*1*s*2... *s**n* (*n* is the length of the string), consisting only of characters "." and "#" and *m* queries. Each query is described by a pair of integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*). The answer to the query *l**i*,<=*r**i* is the number of such integers *i* (*l**i*<=≤<=*i*<=<<=*r**i*), that *s**i*<==<=*s**i*<=+<=1.
Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.
|
The first line contains string *s* of length *n* (2<=≤<=*n*<=≤<=105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. Each of the next *m* lines contains the description of the corresponding query. The *i*-th line contains integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*).
|
Print *m* integers — the answers to the queries in the order in which they are given in the input.
|
[
"......\n4\n3 4\n2 3\n1 6\n2 6\n",
"#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4\n"
] |
[
"1\n1\n5\n4\n",
"1\n1\n2\n2\n0\n"
] |
none
| 1,000
|
[
{
"input": "......\n4\n3 4\n2 3\n1 6\n2 6",
"output": "1\n1\n5\n4"
},
{
"input": "#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4",
"output": "1\n1\n2\n2\n0"
},
{
"input": ".#...#..\n6\n1 5\n2 3\n6 7\n2 4\n2 5\n1 3",
"output": "2\n0\n0\n1\n2\n0"
},
{
"input": "#.#.#..\n5\n3 4\n4 5\n5 7\n5 7\n1 3",
"output": "0\n0\n1\n1\n0"
},
{
"input": "#.##.##.\n7\n1 8\n2 6\n2 6\n6 8\n3 5\n2 4\n2 5",
"output": "2\n1\n1\n1\n1\n1\n1"
},
{
"input": "#..#\n1\n1 4",
"output": "1"
},
{
"input": "#..##...#.\n7\n5 9\n6 10\n1 7\n5 8\n3 5\n2 10\n3 4",
"output": "2\n2\n3\n2\n1\n4\n0"
},
{
"input": "#.#.#\n7\n1 2\n3 4\n3 5\n2 3\n3 5\n1 5\n1 3",
"output": "0\n0\n0\n0\n0\n0\n0"
},
{
"input": "###..#...#\n2\n2 4\n1 2",
"output": "1\n1"
},
{
"input": "..\n1\n1 2",
"output": "1"
},
{
"input": "##\n1\n1 2",
"output": "1"
},
{
"input": ".#\n1\n1 2",
"output": "0"
},
{
"input": "#.\n1\n1 2",
"output": "0"
},
{
"input": "...\n2\n1 2\n1 2",
"output": "1\n1"
}
] | 1,697,926,116
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 37
| 622
| 5,529,600
|
from sys import stdin
stream = None
try:
stream = open('file.txt', 'r')
except:
stream = stdin
dot_sharp = stream.readline().strip()
n = int(stream.readline())
in_row = [0]
prev = dot_sharp[0]
for i in range(1, len(dot_sharp)):
count = in_row[i - 1]
current = dot_sharp[i]
if current == prev:
count += 1
in_row.append(count)
prev = current
for i in range(n):
l, r = [int(j) - 1 for j in stream.readline().split()]
print(in_row[r] - in_row[l])
|
Title: Ilya and Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string *s*<==<=*s*1*s*2... *s**n* (*n* is the length of the string), consisting only of characters "." and "#" and *m* queries. Each query is described by a pair of integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*). The answer to the query *l**i*,<=*r**i* is the number of such integers *i* (*l**i*<=≤<=*i*<=<<=*r**i*), that *s**i*<==<=*s**i*<=+<=1.
Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.
Input Specification:
The first line contains string *s* of length *n* (2<=≤<=*n*<=≤<=105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. Each of the next *m* lines contains the description of the corresponding query. The *i*-th line contains integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*).
Output Specification:
Print *m* integers — the answers to the queries in the order in which they are given in the input.
Demo Input:
['......\n4\n3 4\n2 3\n1 6\n2 6\n', '#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4\n']
Demo Output:
['1\n1\n5\n4\n', '1\n1\n2\n2\n0\n']
Note:
none
|
```python
from sys import stdin
stream = None
try:
stream = open('file.txt', 'r')
except:
stream = stdin
dot_sharp = stream.readline().strip()
n = int(stream.readline())
in_row = [0]
prev = dot_sharp[0]
for i in range(1, len(dot_sharp)):
count = in_row[i - 1]
current = dot_sharp[i]
if current == prev:
count += 1
in_row.append(count)
prev = current
for i in range(n):
l, r = [int(j) - 1 for j in stream.readline().split()]
print(in_row[r] - in_row[l])
```
| 3
|
|
332
|
B
|
Maximum Absurdity
|
PROGRAMMING
| 1,500
|
[
"data structures",
"dp",
"implementation"
] | null | null |
Reforms continue entering Berland. For example, during yesterday sitting the Berland Parliament approved as much as *n* laws (each law has been assigned a unique number from 1 to *n*). Today all these laws were put on the table of the President of Berland, G.W. Boosch, to be signed.
This time mr. Boosch plans to sign 2*k* laws. He decided to choose exactly two non-intersecting segments of integers from 1 to *n* of length *k* and sign all laws, whose numbers fall into these segments. More formally, mr. Boosch is going to choose two integers *a*, *b* (1<=≤<=*a*<=≤<=*b*<=≤<=*n*<=-<=*k*<=+<=1,<=*b*<=-<=*a*<=≥<=*k*) and sign all laws with numbers lying in the segments [*a*; *a*<=+<=*k*<=-<=1] and [*b*; *b*<=+<=*k*<=-<=1] (borders are included).
As mr. Boosch chooses the laws to sign, he of course considers the public opinion. Allberland Public Opinion Study Centre (APOSC) conducted opinion polls among the citizens, processed the results into a report and gave it to the president. The report contains the absurdity value for each law, in the public opinion. As mr. Boosch is a real patriot, he is keen on signing the laws with the maximum total absurdity. Help him.
|
The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=2·105, 0<=<<=2*k*<=≤<=*n*) — the number of laws accepted by the parliament and the length of one segment in the law list, correspondingly. The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n* — the absurdity of each law (1<=≤<=*x**i*<=≤<=109).
|
Print two integers *a*, *b* — the beginning of segments that mr. Boosch should choose. That means that the president signs laws with numbers from segments [*a*; *a*<=+<=*k*<=-<=1] and [*b*; *b*<=+<=*k*<=-<=1]. If there are multiple solutions, print the one with the minimum number *a*. If there still are multiple solutions, print the one with the minimum *b*.
|
[
"5 2\n3 6 1 1 6\n",
"6 2\n1 1 1 1 1 1\n"
] |
[
"1 4\n",
"1 3\n"
] |
In the first sample mr. Boosch signs laws with numbers from segments [1;2] and [4;5]. The total absurdity of the signed laws equals 3 + 6 + 1 + 6 = 16.
In the second sample mr. Boosch signs laws with numbers from segments [1;2] and [3;4]. The total absurdity of the signed laws equals 1 + 1 + 1 + 1 = 4.
| 1,000
|
[
{
"input": "5 2\n3 6 1 1 6",
"output": "1 4"
},
{
"input": "6 2\n1 1 1 1 1 1",
"output": "1 3"
},
{
"input": "6 2\n1 4 1 2 5 6",
"output": "1 5"
},
{
"input": "4 1\n1 2 2 2",
"output": "2 3"
},
{
"input": "6 3\n15 20 1 15 43 6",
"output": "1 4"
},
{
"input": "12 3\n1 2 1 15 2 3 6 8 3 3 8 6",
"output": "4 7"
},
{
"input": "14 2\n2 1 2 3 1 2 2 3 1 2 2 3 2 3",
"output": "3 7"
},
{
"input": "2 1\n1 1",
"output": "1 2"
},
{
"input": "2 1\n1000000000 999999999",
"output": "1 2"
},
{
"input": "3 1\n100 30 563",
"output": "1 3"
},
{
"input": "3 1\n547468 78578678 6467834",
"output": "2 3"
},
{
"input": "4 1\n90000 34567 90000 90001",
"output": "1 4"
},
{
"input": "4 2\n999999 8888888 7777777 666666",
"output": "1 3"
},
{
"input": "5 1\n2 1 2 1 2",
"output": "1 3"
},
{
"input": "5 2\n98 96 98 96 96",
"output": "1 3"
},
{
"input": "6 2\n4 4 7 1 1 7",
"output": "2 5"
},
{
"input": "98 24\n91 20 12 75 44 22 22 67 28 100 8 41 31 47 95 87 5 54 7 49 32 46 42 37 45 22 29 15 54 98 46 94 69 47 60 1 15 76 17 82 46 22 32 34 91 37 30 26 92 77 69 11 59 78 24 66 88 15 32 49 46 14 57 20 5 69 53 99 81 70 67 22 54 31 49 52 46 51 46 2 53 59 8 66 28 53 54 5 85 75 15 55 87 16 68 6 36 98",
"output": "30 67"
},
{
"input": "6 3\n1 2 2 2 1 1",
"output": "1 4"
},
{
"input": "10 4\n9 3 3 9 1 9 9 4 4 9",
"output": "1 6"
},
{
"input": "7 3\n1 2 5 5 5 5 5",
"output": "2 5"
}
] | 1,602,777,294
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 2
| 186
| 307,200
|
n, k = map(int, input().split())
a = [int(i) for i in input().split()]
ind1 = 0
ind2 = k
sum1 = sum(a[:k])
sum2 = sum(a[k:2 * k])
for i in range(2 * k + 1, n + 1):
if sum(a[i - k:i]) > sum2:
sum2 = sum(a[i - k:i])
ind2 = i - k
if sum(a[ind2 - k + 1:ind2 + 1]) > sum1:
sum1 = sum(a[ind2 - k + 1:ind2 + 1])
ind1 = ind2 - k + 1
print(ind1 + 1, ind2 + 1)
|
Title: Maximum Absurdity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Reforms continue entering Berland. For example, during yesterday sitting the Berland Parliament approved as much as *n* laws (each law has been assigned a unique number from 1 to *n*). Today all these laws were put on the table of the President of Berland, G.W. Boosch, to be signed.
This time mr. Boosch plans to sign 2*k* laws. He decided to choose exactly two non-intersecting segments of integers from 1 to *n* of length *k* and sign all laws, whose numbers fall into these segments. More formally, mr. Boosch is going to choose two integers *a*, *b* (1<=≤<=*a*<=≤<=*b*<=≤<=*n*<=-<=*k*<=+<=1,<=*b*<=-<=*a*<=≥<=*k*) and sign all laws with numbers lying in the segments [*a*; *a*<=+<=*k*<=-<=1] and [*b*; *b*<=+<=*k*<=-<=1] (borders are included).
As mr. Boosch chooses the laws to sign, he of course considers the public opinion. Allberland Public Opinion Study Centre (APOSC) conducted opinion polls among the citizens, processed the results into a report and gave it to the president. The report contains the absurdity value for each law, in the public opinion. As mr. Boosch is a real patriot, he is keen on signing the laws with the maximum total absurdity. Help him.
Input Specification:
The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=2·105, 0<=<<=2*k*<=≤<=*n*) — the number of laws accepted by the parliament and the length of one segment in the law list, correspondingly. The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n* — the absurdity of each law (1<=≤<=*x**i*<=≤<=109).
Output Specification:
Print two integers *a*, *b* — the beginning of segments that mr. Boosch should choose. That means that the president signs laws with numbers from segments [*a*; *a*<=+<=*k*<=-<=1] and [*b*; *b*<=+<=*k*<=-<=1]. If there are multiple solutions, print the one with the minimum number *a*. If there still are multiple solutions, print the one with the minimum *b*.
Demo Input:
['5 2\n3 6 1 1 6\n', '6 2\n1 1 1 1 1 1\n']
Demo Output:
['1 4\n', '1 3\n']
Note:
In the first sample mr. Boosch signs laws with numbers from segments [1;2] and [4;5]. The total absurdity of the signed laws equals 3 + 6 + 1 + 6 = 16.
In the second sample mr. Boosch signs laws with numbers from segments [1;2] and [3;4]. The total absurdity of the signed laws equals 1 + 1 + 1 + 1 = 4.
|
```python
n, k = map(int, input().split())
a = [int(i) for i in input().split()]
ind1 = 0
ind2 = k
sum1 = sum(a[:k])
sum2 = sum(a[k:2 * k])
for i in range(2 * k + 1, n + 1):
if sum(a[i - k:i]) > sum2:
sum2 = sum(a[i - k:i])
ind2 = i - k
if sum(a[ind2 - k + 1:ind2 + 1]) > sum1:
sum1 = sum(a[ind2 - k + 1:ind2 + 1])
ind1 = ind2 - k + 1
print(ind1 + 1, ind2 + 1)
```
| 0
|
|
59
|
A
|
Word
|
PROGRAMMING
| 800
|
[
"implementation",
"strings"
] |
A. Word
|
2
|
256
|
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word.
|
The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100.
|
Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one.
|
[
"HoUse\n",
"ViP\n",
"maTRIx\n"
] |
[
"house\n",
"VIP\n",
"matrix\n"
] |
none
| 500
|
[
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chnenu"
},
{
"input": "ERPZGrodyu",
"output": "erpzgrodyu"
},
{
"input": "KSXBXWpebh",
"output": "KSXBXWPEBH"
},
{
"input": "qvxpqullmcbegsdskddortcvxyqlbvxmmkhevovnezubvpvnrcajpxraeaxizgaowtfkzywvhnbgzsxbhkaipcmoumtikkiyyaiv",
"output": "qvxpqullmcbegsdskddortcvxyqlbvxmmkhevovnezubvpvnrcajpxraeaxizgaowtfkzywvhnbgzsxbhkaipcmoumtikkiyyaiv"
},
{
"input": "Amnhaxtaopjzrkqlbroiyipitndczpunwygstmzevgyjdzyanxkdqnvgkikfabwouwkkbzuiuvgvxgpizsvqsbwepktpdrgdkmfd",
"output": "amnhaxtaopjzrkqlbroiyipitndczpunwygstmzevgyjdzyanxkdqnvgkikfabwouwkkbzuiuvgvxgpizsvqsbwepktpdrgdkmfd"
},
{
"input": "ISAGFJFARYFBLOPQDSHWGMCNKMFTLVFUGNJEWGWNBLXUIATXEkqiettmmjgydwcpafqrppdsrrrtguinqbgmzzfqwonkpgpcwenv",
"output": "isagfjfaryfblopqdshwgmcnkmftlvfugnjewgwnblxuiatxekqiettmmjgydwcpafqrppdsrrrtguinqbgmzzfqwonkpgpcwenv"
},
{
"input": "XHRPXZEGHSOCJPICUIXSKFUZUPYTSGJSDIYBCMNMNBPNDBXLXBzhbfnqvwcffvrdhtickyqhupmcehlsyvncqmfhautvxudqdhgg",
"output": "xhrpxzeghsocjpicuixskfuzupytsgjsdiybcmnmnbpndbxlxbzhbfnqvwcffvrdhtickyqhupmcehlsyvncqmfhautvxudqdhgg"
},
{
"input": "RJIQZMJCIMSNDBOHBRAWIENODSALETAKGKPYUFGVEFGCBRENZGAdkcetqjljtmttlonpekcovdzebzdkzggwfsxhapmjkdbuceak",
"output": "RJIQZMJCIMSNDBOHBRAWIENODSALETAKGKPYUFGVEFGCBRENZGADKCETQJLJTMTTLONPEKCOVDZEBZDKZGGWFSXHAPMJKDBUCEAK"
},
{
"input": "DWLWOBHNMMGTFOLFAECKBRNNGLYLYDXTGTVRLMEESZOIUATZZZXUFUZDLSJXMEVRTESSFBWLNZZCLCQWEVNNUCXYVHNGNXHCBDFw",
"output": "DWLWOBHNMMGTFOLFAECKBRNNGLYLYDXTGTVRLMEESZOIUATZZZXUFUZDLSJXMEVRTESSFBWLNZZCLCQWEVNNUCXYVHNGNXHCBDFW"
},
{
"input": "NYCNHJWGBOCOTSPETKKHVWFGAQYNHOVJWJHCIEFOUQZXOYUIEQDZALFKTEHTVDBVJMEUBJUBCMNVPWGDPNCHQHZJRCHYRFPVIGUB",
"output": "NYCNHJWGBOCOTSPETKKHVWFGAQYNHOVJWJHCIEFOUQZXOYUIEQDZALFKTEHTVDBVJMEUBJUBCMNVPWGDPNCHQHZJRCHYRFPVIGUB"
},
{
"input": "igxoixiecetohtgjgbqzvlaobkhstejxdklghowtvwunnnvauriohuspsdmpzckprwajyxldoyckgjivjpmbfqtszmtocovxwge",
"output": "igxoixiecetohtgjgbqzvlaobkhstejxdklghowtvwunnnvauriohuspsdmpzckprwajyxldoyckgjivjpmbfqtszmtocovxwge"
},
{
"input": "Ykkekrsqolzryiwsmdlnbmfautxxxauoojrddvwklgnlyrfcvhorrzbmtcrvpaypqhcffdqhwziipyyskcmztjprjqvmzzqhqnw",
"output": "ykkekrsqolzryiwsmdlnbmfautxxxauoojrddvwklgnlyrfcvhorrzbmtcrvpaypqhcffdqhwziipyyskcmztjprjqvmzzqhqnw"
},
{
"input": "YQOMLKYAORUQQUCQZCDYMIVDHGWZFFRMUVTAWCHERFPMNRYRIkgqrciokgajamehmcxgerpudvsqyonjonsxgbnefftzmygncks",
"output": "yqomlkyaoruqqucqzcdymivdhgwzffrmuvtawcherfpmnryrikgqrciokgajamehmcxgerpudvsqyonjonsxgbnefftzmygncks"
},
{
"input": "CDOZDPBVVVHNBJVBYHEOXWFLJKRWJCAJMIFCOZWWYFKVWOGTVJcuusigdqfkumewjtdyitveeiaybwrhomrwmpdipjwiuxfnwuz",
"output": "CDOZDPBVVVHNBJVBYHEOXWFLJKRWJCAJMIFCOZWWYFKVWOGTVJCUUSIGDQFKUMEWJTDYITVEEIAYBWRHOMRWMPDIPJWIUXFNWUZ"
},
{
"input": "WHIUVEXHVOOIJIDVJVPQUBJMEVPMPDKQWJKFBZSGSKUXMIPPMJWuckzcpxosodcjaaakvlxpbiigsiauviilylnnqlyucziihqg",
"output": "WHIUVEXHVOOIJIDVJVPQUBJMEVPMPDKQWJKFBZSGSKUXMIPPMJWUCKZCPXOSODCJAAAKVLXPBIIGSIAUVIILYLNNQLYUCZIIHQG"
},
{
"input": "VGHUNFOXKETUYMZDJNGTAOIOANYXSGYNFOGOFFLDAWEUKYFOZXCJTCAFXZYLQZERYZLRSQXYQGAPCSUDPMEYTNCTTTMFAGVDWBO",
"output": "VGHUNFOXKETUYMZDJNGTAOIOANYXSGYNFOGOFFLDAWEUKYFOZXCJTCAFXZYLQZERYZLRSQXYQGAPCSUDPMEYTNCTTTMFAGVDWBO"
},
{
"input": "EDUANHCQDOCJHFONTTSWBUJSTTIXBIXMAIUFSGFLXWAYIURTVAVZPYQDLAWIGCLMPHXCEFCJPFAAHXVNGQUFNHADAIUAZIDMHDd",
"output": "EDUANHCQDOCJHFONTTSWBUJSTTIXBIXMAIUFSGFLXWAYIURTVAVZPYQDLAWIGCLMPHXCEFCJPFAAHXVNGQUFNHADAIUAZIDMHDD"
},
{
"input": "EBWOVSNLYTWWXrnovgugogtjahnmatomubebyxakas",
"output": "ebwovsnlytwwxrnovgugogtjahnmatomubebyxakas"
},
{
"input": "AORNNDKTRLRVGDPXJKXFTPFpopuzrlqumrxssskvbm",
"output": "AORNNDKTRLRVGDPXJKXFTPFPOPUZRLQUMRXSSSKVBM"
},
{
"input": "DBBZJCWQEVGYHEEUHJAWRHBDPsnplijbwtdibqrrheebfxqcvn",
"output": "dbbzjcwqevgyheeuhjawrhbdpsnplijbwtdibqrrheebfxqcvn"
},
{
"input": "t",
"output": "t"
},
{
"input": "N",
"output": "N"
},
{
"input": "kv",
"output": "kv"
},
{
"input": "Ur",
"output": "ur"
},
{
"input": "CN",
"output": "CN"
}
] | 1,682,082,490
| 2,147,483,647
|
PyPy 3-64
|
WRONG_ANSWER
|
TESTS
| 1
| 92
| 0
|
s=input()
n=s.lower()
print(n)
|
Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word.
Input Specification:
The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100.
Output Specification:
Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one.
Demo Input:
['HoUse\n', 'ViP\n', 'maTRIx\n']
Demo Output:
['house\n', 'VIP\n', 'matrix\n']
Note:
none
|
```python
s=input()
n=s.lower()
print(n)
```
| 0
|
808
|
A
|
Lucky Year
|
PROGRAMMING
| 900
|
[
"implementation"
] | null | null |
Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 12, 3001 and 12345 are not.
You are given current year in Berland. Your task is to find how long will residents of Berland wait till the next lucky year.
|
The first line contains integer number *n* (1<=≤<=*n*<=≤<=109) — current year in Berland.
|
Output amount of years from the current year to the next lucky one.
|
[
"4\n",
"201\n",
"4000\n"
] |
[
"1\n",
"99\n",
"1000\n"
] |
In the first example next lucky year is 5. In the second one — 300. In the third — 5000.
| 0
|
[
{
"input": "4",
"output": "1"
},
{
"input": "201",
"output": "99"
},
{
"input": "4000",
"output": "1000"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "10"
},
{
"input": "1",
"output": "1"
},
{
"input": "100000000",
"output": "100000000"
},
{
"input": "900000000",
"output": "100000000"
},
{
"input": "999999999",
"output": "1"
},
{
"input": "1000000000",
"output": "1000000000"
},
{
"input": "9999999",
"output": "1"
},
{
"input": "100000001",
"output": "99999999"
},
{
"input": "3660",
"output": "340"
},
{
"input": "21",
"output": "9"
},
{
"input": "900000001",
"output": "99999999"
},
{
"input": "62911",
"output": "7089"
},
{
"input": "11",
"output": "9"
},
{
"input": "940302010",
"output": "59697990"
},
{
"input": "91",
"output": "9"
},
{
"input": "101",
"output": "99"
},
{
"input": "1090",
"output": "910"
},
{
"input": "987654321",
"output": "12345679"
},
{
"input": "703450474",
"output": "96549526"
},
{
"input": "1091",
"output": "909"
},
{
"input": "89",
"output": "1"
},
{
"input": "109",
"output": "91"
},
{
"input": "190",
"output": "10"
},
{
"input": "19",
"output": "1"
},
{
"input": "8",
"output": "1"
},
{
"input": "482",
"output": "18"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "1"
},
{
"input": "5",
"output": "1"
},
{
"input": "6",
"output": "1"
},
{
"input": "7",
"output": "1"
},
{
"input": "8",
"output": "1"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "10"
},
{
"input": "11",
"output": "9"
},
{
"input": "12",
"output": "8"
},
{
"input": "13",
"output": "7"
},
{
"input": "14",
"output": "6"
},
{
"input": "15",
"output": "5"
},
{
"input": "16",
"output": "4"
},
{
"input": "17",
"output": "3"
},
{
"input": "18",
"output": "2"
},
{
"input": "19",
"output": "1"
},
{
"input": "20",
"output": "10"
},
{
"input": "21",
"output": "9"
},
{
"input": "22",
"output": "8"
},
{
"input": "23",
"output": "7"
},
{
"input": "24",
"output": "6"
},
{
"input": "25",
"output": "5"
},
{
"input": "26",
"output": "4"
},
{
"input": "27",
"output": "3"
},
{
"input": "28",
"output": "2"
},
{
"input": "29",
"output": "1"
},
{
"input": "30",
"output": "10"
},
{
"input": "31",
"output": "9"
},
{
"input": "32",
"output": "8"
},
{
"input": "33",
"output": "7"
},
{
"input": "34",
"output": "6"
},
{
"input": "35",
"output": "5"
},
{
"input": "36",
"output": "4"
},
{
"input": "37",
"output": "3"
},
{
"input": "38",
"output": "2"
},
{
"input": "39",
"output": "1"
},
{
"input": "40",
"output": "10"
},
{
"input": "41",
"output": "9"
},
{
"input": "42",
"output": "8"
},
{
"input": "43",
"output": "7"
},
{
"input": "44",
"output": "6"
},
{
"input": "45",
"output": "5"
},
{
"input": "46",
"output": "4"
},
{
"input": "47",
"output": "3"
},
{
"input": "48",
"output": "2"
},
{
"input": "49",
"output": "1"
},
{
"input": "50",
"output": "10"
},
{
"input": "51",
"output": "9"
},
{
"input": "52",
"output": "8"
},
{
"input": "53",
"output": "7"
},
{
"input": "54",
"output": "6"
},
{
"input": "55",
"output": "5"
},
{
"input": "56",
"output": "4"
},
{
"input": "57",
"output": "3"
},
{
"input": "58",
"output": "2"
},
{
"input": "59",
"output": "1"
},
{
"input": "60",
"output": "10"
},
{
"input": "61",
"output": "9"
},
{
"input": "62",
"output": "8"
},
{
"input": "63",
"output": "7"
},
{
"input": "64",
"output": "6"
},
{
"input": "65",
"output": "5"
},
{
"input": "66",
"output": "4"
},
{
"input": "67",
"output": "3"
},
{
"input": "68",
"output": "2"
},
{
"input": "69",
"output": "1"
},
{
"input": "70",
"output": "10"
},
{
"input": "71",
"output": "9"
},
{
"input": "72",
"output": "8"
},
{
"input": "73",
"output": "7"
},
{
"input": "74",
"output": "6"
},
{
"input": "75",
"output": "5"
},
{
"input": "76",
"output": "4"
},
{
"input": "77",
"output": "3"
},
{
"input": "78",
"output": "2"
},
{
"input": "79",
"output": "1"
},
{
"input": "80",
"output": "10"
},
{
"input": "81",
"output": "9"
},
{
"input": "82",
"output": "8"
},
{
"input": "83",
"output": "7"
},
{
"input": "84",
"output": "6"
},
{
"input": "85",
"output": "5"
},
{
"input": "86",
"output": "4"
},
{
"input": "87",
"output": "3"
},
{
"input": "88",
"output": "2"
},
{
"input": "89",
"output": "1"
},
{
"input": "90",
"output": "10"
},
{
"input": "91",
"output": "9"
},
{
"input": "92",
"output": "8"
},
{
"input": "93",
"output": "7"
},
{
"input": "94",
"output": "6"
},
{
"input": "95",
"output": "5"
},
{
"input": "96",
"output": "4"
},
{
"input": "97",
"output": "3"
},
{
"input": "98",
"output": "2"
},
{
"input": "99",
"output": "1"
},
{
"input": "100",
"output": "100"
},
{
"input": "100",
"output": "100"
},
{
"input": "100",
"output": "100"
},
{
"input": "1000",
"output": "1000"
},
{
"input": "1000",
"output": "1000"
},
{
"input": "1000",
"output": "1000"
},
{
"input": "10000",
"output": "10000"
},
{
"input": "10000",
"output": "10000"
},
{
"input": "101",
"output": "99"
},
{
"input": "110",
"output": "90"
},
{
"input": "1001",
"output": "999"
},
{
"input": "1100",
"output": "900"
},
{
"input": "1010",
"output": "990"
},
{
"input": "10010",
"output": "9990"
},
{
"input": "10100",
"output": "9900"
},
{
"input": "102",
"output": "98"
},
{
"input": "120",
"output": "80"
},
{
"input": "1002",
"output": "998"
},
{
"input": "1200",
"output": "800"
},
{
"input": "1020",
"output": "980"
},
{
"input": "10020",
"output": "9980"
},
{
"input": "10200",
"output": "9800"
},
{
"input": "108",
"output": "92"
},
{
"input": "180",
"output": "20"
},
{
"input": "1008",
"output": "992"
},
{
"input": "1800",
"output": "200"
},
{
"input": "1080",
"output": "920"
},
{
"input": "10080",
"output": "9920"
},
{
"input": "10800",
"output": "9200"
},
{
"input": "109",
"output": "91"
},
{
"input": "190",
"output": "10"
},
{
"input": "1009",
"output": "991"
},
{
"input": "1900",
"output": "100"
},
{
"input": "1090",
"output": "910"
},
{
"input": "10090",
"output": "9910"
},
{
"input": "10900",
"output": "9100"
},
{
"input": "200",
"output": "100"
},
{
"input": "200",
"output": "100"
},
{
"input": "2000",
"output": "1000"
},
{
"input": "2000",
"output": "1000"
},
{
"input": "2000",
"output": "1000"
},
{
"input": "20000",
"output": "10000"
},
{
"input": "20000",
"output": "10000"
},
{
"input": "201",
"output": "99"
},
{
"input": "210",
"output": "90"
},
{
"input": "2001",
"output": "999"
},
{
"input": "2100",
"output": "900"
},
{
"input": "2010",
"output": "990"
},
{
"input": "20010",
"output": "9990"
},
{
"input": "20100",
"output": "9900"
},
{
"input": "202",
"output": "98"
},
{
"input": "220",
"output": "80"
},
{
"input": "2002",
"output": "998"
},
{
"input": "2200",
"output": "800"
},
{
"input": "2020",
"output": "980"
},
{
"input": "20020",
"output": "9980"
},
{
"input": "20200",
"output": "9800"
},
{
"input": "208",
"output": "92"
},
{
"input": "280",
"output": "20"
},
{
"input": "2008",
"output": "992"
},
{
"input": "2800",
"output": "200"
},
{
"input": "2080",
"output": "920"
},
{
"input": "20080",
"output": "9920"
},
{
"input": "20800",
"output": "9200"
},
{
"input": "209",
"output": "91"
},
{
"input": "290",
"output": "10"
},
{
"input": "2009",
"output": "991"
},
{
"input": "2900",
"output": "100"
},
{
"input": "2090",
"output": "910"
},
{
"input": "20090",
"output": "9910"
},
{
"input": "20900",
"output": "9100"
},
{
"input": "800",
"output": "100"
},
{
"input": "800",
"output": "100"
},
{
"input": "8000",
"output": "1000"
},
{
"input": "8000",
"output": "1000"
},
{
"input": "8000",
"output": "1000"
},
{
"input": "80000",
"output": "10000"
},
{
"input": "80000",
"output": "10000"
},
{
"input": "801",
"output": "99"
},
{
"input": "810",
"output": "90"
},
{
"input": "8001",
"output": "999"
},
{
"input": "8100",
"output": "900"
},
{
"input": "8010",
"output": "990"
},
{
"input": "80010",
"output": "9990"
},
{
"input": "80100",
"output": "9900"
},
{
"input": "802",
"output": "98"
},
{
"input": "820",
"output": "80"
},
{
"input": "8002",
"output": "998"
},
{
"input": "8200",
"output": "800"
},
{
"input": "8020",
"output": "980"
},
{
"input": "80020",
"output": "9980"
},
{
"input": "80200",
"output": "9800"
},
{
"input": "808",
"output": "92"
},
{
"input": "880",
"output": "20"
},
{
"input": "8008",
"output": "992"
},
{
"input": "8800",
"output": "200"
},
{
"input": "8080",
"output": "920"
},
{
"input": "80080",
"output": "9920"
},
{
"input": "80800",
"output": "9200"
},
{
"input": "809",
"output": "91"
},
{
"input": "890",
"output": "10"
},
{
"input": "8009",
"output": "991"
},
{
"input": "8900",
"output": "100"
},
{
"input": "8090",
"output": "910"
},
{
"input": "80090",
"output": "9910"
},
{
"input": "80900",
"output": "9100"
},
{
"input": "900",
"output": "100"
},
{
"input": "900",
"output": "100"
},
{
"input": "9000",
"output": "1000"
},
{
"input": "9000",
"output": "1000"
},
{
"input": "9000",
"output": "1000"
},
{
"input": "90000",
"output": "10000"
},
{
"input": "90000",
"output": "10000"
},
{
"input": "901",
"output": "99"
},
{
"input": "910",
"output": "90"
},
{
"input": "9001",
"output": "999"
},
{
"input": "9100",
"output": "900"
},
{
"input": "9010",
"output": "990"
},
{
"input": "90010",
"output": "9990"
},
{
"input": "90100",
"output": "9900"
},
{
"input": "902",
"output": "98"
},
{
"input": "920",
"output": "80"
},
{
"input": "9002",
"output": "998"
},
{
"input": "9200",
"output": "800"
},
{
"input": "9020",
"output": "980"
},
{
"input": "90020",
"output": "9980"
},
{
"input": "90200",
"output": "9800"
},
{
"input": "908",
"output": "92"
},
{
"input": "980",
"output": "20"
},
{
"input": "9008",
"output": "992"
},
{
"input": "9800",
"output": "200"
},
{
"input": "9080",
"output": "920"
},
{
"input": "90080",
"output": "9920"
},
{
"input": "90800",
"output": "9200"
},
{
"input": "909",
"output": "91"
},
{
"input": "990",
"output": "10"
},
{
"input": "9009",
"output": "991"
},
{
"input": "9900",
"output": "100"
},
{
"input": "9090",
"output": "910"
},
{
"input": "90090",
"output": "9910"
},
{
"input": "90900",
"output": "9100"
},
{
"input": "92651241",
"output": "7348759"
}
] | 1,617,246,385
| 2,147,483,647
|
PyPy 3
|
OK
|
TESTS
| 271
| 108
| 0
|
s = input()
s = s[1:]
l =len(s)
bigg = 10 ** l
if not s: print(1)
else: print(bigg - int(s))
|
Title: Lucky Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 12, 3001 and 12345 are not.
You are given current year in Berland. Your task is to find how long will residents of Berland wait till the next lucky year.
Input Specification:
The first line contains integer number *n* (1<=≤<=*n*<=≤<=109) — current year in Berland.
Output Specification:
Output amount of years from the current year to the next lucky one.
Demo Input:
['4\n', '201\n', '4000\n']
Demo Output:
['1\n', '99\n', '1000\n']
Note:
In the first example next lucky year is 5. In the second one — 300. In the third — 5000.
|
```python
s = input()
s = s[1:]
l =len(s)
bigg = 10 ** l
if not s: print(1)
else: print(bigg - int(s))
```
| 3
|
|
263
|
A
|
Beautiful Matrix
|
PROGRAMMING
| 800
|
[
"implementation"
] | null | null |
You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix:
1. Swap two neighboring matrix rows, that is, rows with indexes *i* and *i*<=+<=1 for some integer *i* (1<=≤<=*i*<=<<=5). 1. Swap two neighboring matrix columns, that is, columns with indexes *j* and *j*<=+<=1 for some integer *j* (1<=≤<=*j*<=<<=5).
You think that a matrix looks beautiful, if the single number one of the matrix is located in its middle (in the cell that is on the intersection of the third row and the third column). Count the minimum number of moves needed to make the matrix beautiful.
|
The input consists of five lines, each line contains five integers: the *j*-th integer in the *i*-th line of the input represents the element of the matrix that is located on the intersection of the *i*-th row and the *j*-th column. It is guaranteed that the matrix consists of 24 zeroes and a single number one.
|
Print a single integer — the minimum number of moves needed to make the matrix beautiful.
|
[
"0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n",
"0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n"
] |
[
"3\n",
"1\n"
] |
none
| 500
|
[
{
"input": "0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 1 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "0"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 1",
"output": "4"
},
{
"input": "0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "1 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "4"
},
{
"input": "0 0 1 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 1 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "4"
},
{
"input": "0 0 0 0 0\n1 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 1 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 1 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n1 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 1 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n1 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 1 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 1 0\n0 0 0 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n1 0 0 0 0",
"output": "4"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 1 0 0",
"output": "2"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 1 0",
"output": "3"
}
] | 1,696,337,502
| 2,147,483,647
|
PyPy 3-64
|
OK
|
TESTS
| 25
| 124
| 0
|
# URL: https://codeforces.com/problemset/problem/263/A
for i in range(5):
row = input().split()
j = -1
try:
j = row.index('1')
except ValueError:
pass
if j != -1:
print(abs(2 - i) + abs(2 - j))
break
|
Title: Beautiful Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix:
1. Swap two neighboring matrix rows, that is, rows with indexes *i* and *i*<=+<=1 for some integer *i* (1<=≤<=*i*<=<<=5). 1. Swap two neighboring matrix columns, that is, columns with indexes *j* and *j*<=+<=1 for some integer *j* (1<=≤<=*j*<=<<=5).
You think that a matrix looks beautiful, if the single number one of the matrix is located in its middle (in the cell that is on the intersection of the third row and the third column). Count the minimum number of moves needed to make the matrix beautiful.
Input Specification:
The input consists of five lines, each line contains five integers: the *j*-th integer in the *i*-th line of the input represents the element of the matrix that is located on the intersection of the *i*-th row and the *j*-th column. It is guaranteed that the matrix consists of 24 zeroes and a single number one.
Output Specification:
Print a single integer — the minimum number of moves needed to make the matrix beautiful.
Demo Input:
['0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n', '0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n']
Demo Output:
['3\n', '1\n']
Note:
none
|
```python
# URL: https://codeforces.com/problemset/problem/263/A
for i in range(5):
row = input().split()
j = -1
try:
j = row.index('1')
except ValueError:
pass
if j != -1:
print(abs(2 - i) + abs(2 - j))
break
```
| 3
|
|
306
|
A
|
Candies
|
PROGRAMMING
| 800
|
[
"implementation"
] | null | null |
Polycarpus has got *n* candies and *m* friends (*n*<=≥<=*m*). He wants to make a New Year present with candies to each friend. Polycarpus is planning to present all candies and he wants to do this in the fairest (that is, most equal) manner. He wants to choose such *a**i*, where *a**i* is the number of candies in the *i*-th friend's present, that the maximum *a**i* differs from the least *a**i* as little as possible.
For example, if *n* is divisible by *m*, then he is going to present the same number of candies to all his friends, that is, the maximum *a**i* won't differ from the minimum one.
|
The single line of the input contains a pair of space-separated positive integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100;*n*<=≥<=*m*) — the number of candies and the number of Polycarpus's friends.
|
Print the required sequence *a*1,<=*a*2,<=...,<=*a**m*, where *a**i* is the number of candies in the *i*-th friend's present. All numbers *a**i* must be positive integers, total up to *n*, the maximum one should differ from the minimum one by the smallest possible value.
|
[
"12 3\n",
"15 4\n",
"18 7\n"
] |
[
"4 4 4 ",
"3 4 4 4 ",
"2 2 2 3 3 3 3 "
] |
Print *a*<sub class="lower-index">*i*</sub> in any order, separate the numbers by spaces.
| 500
|
[
{
"input": "12 4",
"output": "3 3 3 3 "
},
{
"input": "15 6",
"output": "2 2 2 3 3 3 "
},
{
"input": "18 8",
"output": "2 2 2 2 2 2 3 3 "
},
{
"input": "1 1",
"output": "1 "
},
{
"input": "2 1",
"output": "2 "
},
{
"input": "100 1",
"output": "100 "
},
{
"input": "100 100",
"output": "1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 "
},
{
"input": "100 10",
"output": "10 10 10 10 10 10 10 10 10 10 "
},
{
"input": "64 8",
"output": "8 8 8 8 8 8 8 8 "
},
{
"input": "81 27",
"output": "3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 "
},
{
"input": "100 99",
"output": "1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 "
},
{
"input": "100 51",
"output": "1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 "
},
{
"input": "100 49",
"output": "2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 3 3 "
},
{
"input": "100 13",
"output": "7 7 7 7 8 8 8 8 8 8 8 8 8 "
},
{
"input": "97 11",
"output": "8 8 9 9 9 9 9 9 9 9 9 "
},
{
"input": "19 3",
"output": "6 6 7 "
},
{
"input": "99 10",
"output": "9 10 10 10 10 10 10 10 10 10 "
},
{
"input": "88 5",
"output": "17 17 18 18 18 "
},
{
"input": "87 34",
"output": "2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 "
},
{
"input": "97 55",
"output": "1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 "
}
] | 1,686,650,104
| 2,147,483,647
|
PyPy 3-64
|
OK
|
TESTS
| 20
| 122
| 0
|
n,m = map(int,input().split(' '))
if n%m == 0:
l = [int(n/m)]*m
print(" ".join(str(x) for x in l))
else:
rem = n%m
if rem > (m-rem):
# distribute n//m + 1 ek baar sabko
diff = m - rem
# print(diff)
l = [int(n//m) + 1]*m
for i in range (0,m):
# print(i)
if diff > 0:
l[i] -= 1
diff -= 1
else:
break
print(" ".join(str(x) for x in l))
else:
diff = rem
l = [int(n//m)]*m
for i in range (0,m):
if diff > 0:
l[i] += 1
diff -= 1
else:
break
print(" ".join(str(x) for x in l))
|
Title: Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has got *n* candies and *m* friends (*n*<=≥<=*m*). He wants to make a New Year present with candies to each friend. Polycarpus is planning to present all candies and he wants to do this in the fairest (that is, most equal) manner. He wants to choose such *a**i*, where *a**i* is the number of candies in the *i*-th friend's present, that the maximum *a**i* differs from the least *a**i* as little as possible.
For example, if *n* is divisible by *m*, then he is going to present the same number of candies to all his friends, that is, the maximum *a**i* won't differ from the minimum one.
Input Specification:
The single line of the input contains a pair of space-separated positive integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100;*n*<=≥<=*m*) — the number of candies and the number of Polycarpus's friends.
Output Specification:
Print the required sequence *a*1,<=*a*2,<=...,<=*a**m*, where *a**i* is the number of candies in the *i*-th friend's present. All numbers *a**i* must be positive integers, total up to *n*, the maximum one should differ from the minimum one by the smallest possible value.
Demo Input:
['12 3\n', '15 4\n', '18 7\n']
Demo Output:
['4 4 4 ', '3 4 4 4 ', '2 2 2 3 3 3 3 ']
Note:
Print *a*<sub class="lower-index">*i*</sub> in any order, separate the numbers by spaces.
|
```python
n,m = map(int,input().split(' '))
if n%m == 0:
l = [int(n/m)]*m
print(" ".join(str(x) for x in l))
else:
rem = n%m
if rem > (m-rem):
# distribute n//m + 1 ek baar sabko
diff = m - rem
# print(diff)
l = [int(n//m) + 1]*m
for i in range (0,m):
# print(i)
if diff > 0:
l[i] -= 1
diff -= 1
else:
break
print(" ".join(str(x) for x in l))
else:
diff = rem
l = [int(n//m)]*m
for i in range (0,m):
if diff > 0:
l[i] += 1
diff -= 1
else:
break
print(" ".join(str(x) for x in l))
```
| 3
|
|
714
|
A
|
Meeting of Old Friends
|
PROGRAMMING
| 1,100
|
[
"implementation",
"math"
] | null | null |
Today an outstanding event is going to happen in the forest — hedgehog Filya will come to his old fried Sonya!
Sonya is an owl and she sleeps during the day and stay awake from minute *l*1 to minute *r*1 inclusive. Also, during the minute *k* she prinks and is unavailable for Filya.
Filya works a lot and he plans to visit Sonya from minute *l*2 to minute *r*2 inclusive.
Calculate the number of minutes they will be able to spend together.
|
The only line of the input contains integers *l*1, *r*1, *l*2, *r*2 and *k* (1<=≤<=*l*1,<=*r*1,<=*l*2,<=*r*2,<=*k*<=≤<=1018, *l*1<=≤<=*r*1, *l*2<=≤<=*r*2), providing the segments of time for Sonya and Filya and the moment of time when Sonya prinks.
|
Print one integer — the number of minutes Sonya and Filya will be able to spend together.
|
[
"1 10 9 20 1\n",
"1 100 50 200 75\n"
] |
[
"2\n",
"50\n"
] |
In the first sample, they will be together during minutes 9 and 10.
In the second sample, they will be together from minute 50 to minute 74 and from minute 76 to minute 100.
| 500
|
[
{
"input": "1 10 9 20 1",
"output": "2"
},
{
"input": "1 100 50 200 75",
"output": "50"
},
{
"input": "6 6 5 8 9",
"output": "1"
},
{
"input": "1 1000000000 1 1000000000 1",
"output": "999999999"
},
{
"input": "5 100 8 8 8",
"output": "0"
},
{
"input": "1 1000000000000000000 2 99999999999999999 1000000000",
"output": "99999999999999997"
},
{
"input": "1 1 1 1 1",
"output": "0"
},
{
"input": "1 2 3 4 5",
"output": "0"
},
{
"input": "1 1000000000 2 999999999 3141592",
"output": "999999997"
},
{
"input": "24648817341102 41165114064236 88046848035 13602161452932 10000831349205",
"output": "0"
},
{
"input": "1080184299348 34666828555290 6878390132365 39891656267344 15395310291636",
"output": "27788438422925"
},
{
"input": "11814 27385 22309 28354 23595",
"output": "5076"
},
{
"input": "4722316546398 36672578279675 796716437180 33840047334985 13411035401708",
"output": "29117730788587"
},
{
"input": "14300093617438 14381698008501 6957847034861 32510754974307 66056597033082",
"output": "81604391064"
},
{
"input": "700062402405871919 762322967106512617 297732773882447821 747309903322652819 805776739998108178",
"output": "47247500916780901"
},
{
"input": "59861796371397621 194872039092923459 668110259718450585 841148673332698972 928360292123223779",
"output": "0"
},
{
"input": "298248781360904821 346420922793050061 237084570581741798 726877079564549183 389611850470532358",
"output": "48172141432145241"
},
{
"input": "420745791717606818 864206437350900994 764928840030524015 966634105370748487 793326512080703489",
"output": "99277597320376979"
},
{
"input": "519325240668210886 776112702001665034 360568516809443669 875594219634943179 994594983925273138",
"output": "256787461333454149"
},
{
"input": "170331212821058551 891149660635282032 125964175621755330 208256491683509799 526532153531983174",
"output": "37925278862451249"
},
{
"input": "1 3 3 5 3",
"output": "0"
},
{
"input": "1 5 8 10 9",
"output": "0"
},
{
"input": "1 2 4 5 10",
"output": "0"
},
{
"input": "1 2 2 3 5",
"output": "1"
},
{
"input": "2 4 3 7 3",
"output": "1"
},
{
"input": "1 2 9 10 1",
"output": "0"
},
{
"input": "5 15 1 10 5",
"output": "5"
},
{
"input": "1 4 9 20 25",
"output": "0"
},
{
"input": "2 4 1 2 5",
"output": "1"
},
{
"input": "10 1000 1 100 2",
"output": "91"
},
{
"input": "1 3 3 8 10",
"output": "1"
},
{
"input": "4 6 6 8 9",
"output": "1"
},
{
"input": "2 3 1 4 3",
"output": "1"
},
{
"input": "1 2 2 3 100",
"output": "1"
},
{
"input": "1 2 100 120 2",
"output": "0"
},
{
"input": "1 3 5 7 4",
"output": "0"
},
{
"input": "1 3 5 7 5",
"output": "0"
},
{
"input": "1 4 8 10 6",
"output": "0"
},
{
"input": "1 2 5 6 100",
"output": "0"
},
{
"input": "1 2 5 10 20",
"output": "0"
},
{
"input": "1 2 5 6 7",
"output": "0"
},
{
"input": "2 5 7 12 6",
"output": "0"
},
{
"input": "10 20 50 100 80",
"output": "0"
},
{
"input": "1 2 5 10 2",
"output": "0"
},
{
"input": "1 2 5 6 4",
"output": "0"
},
{
"input": "5 9 1 2 3",
"output": "0"
},
{
"input": "50 100 1 20 3",
"output": "0"
},
{
"input": "10 20 3 7 30",
"output": "0"
},
{
"input": "1 5 10 10 100",
"output": "0"
},
{
"input": "100 101 1 2 3",
"output": "0"
},
{
"input": "1 5 10 20 6",
"output": "0"
},
{
"input": "1 10 15 25 5",
"output": "0"
},
{
"input": "1 2 5 10 3",
"output": "0"
},
{
"input": "2 3 5 6 100",
"output": "0"
},
{
"input": "1 2 4 5 6",
"output": "0"
},
{
"input": "6 10 1 2 40",
"output": "0"
},
{
"input": "20 30 1 5 1",
"output": "0"
},
{
"input": "20 40 50 100 50",
"output": "0"
},
{
"input": "1 1 4 9 2",
"output": "0"
},
{
"input": "1 2 5 6 1",
"output": "0"
},
{
"input": "1 100 400 500 450",
"output": "0"
},
{
"input": "5 6 1 2 5",
"output": "0"
},
{
"input": "1 10 21 30 50",
"output": "0"
},
{
"input": "100 200 300 400 101",
"output": "0"
},
{
"input": "2 8 12 16 9",
"output": "0"
},
{
"input": "1 5 7 9 6",
"output": "0"
},
{
"input": "300 400 100 200 101",
"output": "0"
},
{
"input": "1 2 2 3 10",
"output": "1"
},
{
"input": "1 10 100 200 5",
"output": "0"
},
{
"input": "1 3 3 4 4",
"output": "1"
},
{
"input": "10 20 30 40 25",
"output": "0"
},
{
"input": "1 2 5 10 1",
"output": "0"
},
{
"input": "2 4 8 10 1",
"output": "0"
},
{
"input": "2 5 10 15 7",
"output": "0"
},
{
"input": "100 200 5 10 1",
"output": "0"
},
{
"input": "1 2 100 200 300",
"output": "0"
},
{
"input": "30 100 10 20 25",
"output": "0"
},
{
"input": "10 20 1 5 6",
"output": "0"
},
{
"input": "4 5 1 2 4",
"output": "0"
},
{
"input": "11 100 1 9 1000",
"output": "0"
},
{
"input": "1 1 10 10 228",
"output": "0"
},
{
"input": "5 7 10 20 15",
"output": "0"
},
{
"input": "1 3 8 9 7",
"output": "0"
},
{
"input": "1 10 2 8 8",
"output": "6"
},
{
"input": "1 5 9 15 1",
"output": "0"
},
{
"input": "1 3 5 6 12",
"output": "0"
},
{
"input": "1 100 500 1000 3",
"output": "0"
},
{
"input": "1 1 1 1 2",
"output": "1"
},
{
"input": "1 1000 100 1000 200",
"output": "900"
},
{
"input": "4 5 1 4 1",
"output": "1"
},
{
"input": "1 5 5 7 3",
"output": "1"
},
{
"input": "1 4 4 10 11",
"output": "1"
},
{
"input": "1 1 3 4 100",
"output": "0"
},
{
"input": "1 4 3 5 6",
"output": "2"
},
{
"input": "10 100 20 30 40",
"output": "11"
},
{
"input": "5 9 1 11 7",
"output": "4"
}
] | 1,589,700,902
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 3
| 93
| 6,656,000
|
l1,r1,l2,r2,k=map(int,input().split())
if r1>l2 and l1!=r1:
conv=(r1-l2)+1
else:
conv=r1-l2
if k>=l2 and k<=r1:
while k<=r1:
conv-=1
k+=k
print(conv)
|
Title: Meeting of Old Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today an outstanding event is going to happen in the forest — hedgehog Filya will come to his old fried Sonya!
Sonya is an owl and she sleeps during the day and stay awake from minute *l*1 to minute *r*1 inclusive. Also, during the minute *k* she prinks and is unavailable for Filya.
Filya works a lot and he plans to visit Sonya from minute *l*2 to minute *r*2 inclusive.
Calculate the number of minutes they will be able to spend together.
Input Specification:
The only line of the input contains integers *l*1, *r*1, *l*2, *r*2 and *k* (1<=≤<=*l*1,<=*r*1,<=*l*2,<=*r*2,<=*k*<=≤<=1018, *l*1<=≤<=*r*1, *l*2<=≤<=*r*2), providing the segments of time for Sonya and Filya and the moment of time when Sonya prinks.
Output Specification:
Print one integer — the number of minutes Sonya and Filya will be able to spend together.
Demo Input:
['1 10 9 20 1\n', '1 100 50 200 75\n']
Demo Output:
['2\n', '50\n']
Note:
In the first sample, they will be together during minutes 9 and 10.
In the second sample, they will be together from minute 50 to minute 74 and from minute 76 to minute 100.
|
```python
l1,r1,l2,r2,k=map(int,input().split())
if r1>l2 and l1!=r1:
conv=(r1-l2)+1
else:
conv=r1-l2
if k>=l2 and k<=r1:
while k<=r1:
conv-=1
k+=k
print(conv)
```
| 0
|
|
71
|
A
|
Way Too Long Words
|
PROGRAMMING
| 800
|
[
"strings"
] |
A. Way Too Long Words
|
1
|
256
|
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made like this: we write down the first and the last letter of a word and between them we write the number of letters between the first and the last letters. That number is in decimal system and doesn't contain any leading zeroes.
Thus, "localization" will be spelt as "l10n", and "internationalization» will be spelt as "i18n".
You are suggested to automatize the process of changing the words with abbreviations. At that all too long words should be replaced by the abbreviation and the words that are not too long should not undergo any changes.
|
The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters.
|
Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data.
|
[
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] |
[
"word\nl10n\ni18n\np43s\n"
] |
none
| 500
|
[
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input": "3\nnjfngnrurunrgunrunvurn\njfvnjfdnvjdbfvsbdubruvbubvkdb\nksdnvidnviudbvibd",
"output": "n20n\nj27b\nk15d"
},
{
"input": "1\ntcyctkktcctrcyvbyiuhihhhgyvyvyvyvjvytchjckt",
"output": "t41t"
},
{
"input": "24\nyou\nare\nregistered\nfor\npractice\nyou\ncan\nsolve\nproblems\nunofficially\nresults\ncan\nbe\nfound\nin\nthe\ncontest\nstatus\nand\nin\nthe\nbottom\nof\nstandings",
"output": "you\nare\nregistered\nfor\npractice\nyou\ncan\nsolve\nproblems\nu10y\nresults\ncan\nbe\nfound\nin\nthe\ncontest\nstatus\nand\nin\nthe\nbottom\nof\nstandings"
},
{
"input": "1\na",
"output": "a"
},
{
"input": "26\na\nb\nc\nd\ne\nf\ng\nh\ni\nj\nk\nl\nm\nn\no\np\nq\nr\ns\nt\nu\nv\nw\nx\ny\nz",
"output": "a\nb\nc\nd\ne\nf\ng\nh\ni\nj\nk\nl\nm\nn\no\np\nq\nr\ns\nt\nu\nv\nw\nx\ny\nz"
},
{
"input": "1\nabcdefghijabcdefghijabcdefghijabcdefghijabcdefghijabcdefghijabcdefghijabcdefghijabcdefghijabcdefghij",
"output": "a98j"
},
{
"input": "10\ngyartjdxxlcl\nfzsck\nuidwu\nxbymclornemdmtj\nilppyoapitawgje\ncibzc\ndrgbeu\nhezplmsdekhhbo\nfeuzlrimbqbytdu\nkgdco",
"output": "g10l\nfzsck\nuidwu\nx13j\ni13e\ncibzc\ndrgbeu\nh12o\nf13u\nkgdco"
},
{
"input": "20\nlkpmx\nkovxmxorlgwaomlswjxlpnbvltfv\nhykasjxqyjrmybejnmeumzha\ntuevlumpqbbhbww\nqgqsphvrmupxxc\ntrissbaf\nqfgrlinkzvzqdryckaizutd\nzzqtoaxkvwoscyx\noswytrlnhpjvvnwookx\nlpuzqgec\ngyzqfwxggtvpjhzmzmdw\nrlxjgmvdftvrmvbdwudra\nvsntnjpepnvdaxiporggmglhagv\nxlvcqkqgcrbgtgglj\nlyxwxbiszyhlsrgzeedzprbmcpduvq\nyrmqqvrkqskqukzqrwukpsifgtdc\nxpuohcsjhhuhvr\nvvlfrlxpvqejngwrbfbpmqeirxlw\nsvmasocxdvadmaxtrpakysmeaympy\nyuflqboqfdt",
"output": "lkpmx\nk26v\nh22a\nt13w\nq12c\ntrissbaf\nq21d\nz13x\no17x\nlpuzqgec\ng18w\nr19a\nv25v\nx15j\nl28q\ny26c\nx12r\nv26w\ns27y\ny9t"
},
{
"input": "100\nm\nz\ns\nv\nd\nr\nv\ny\ny\ne\np\nt\nc\na\nn\nm\np\ng\ni\nj\nc\na\nb\nq\ne\nn\nv\no\nk\nx\nf\ni\nl\na\nq\nr\nu\nb\ns\nl\nc\nl\ne\nv\nj\nm\nx\nb\na\nq\nb\na\nf\nj\nv\nm\nq\nc\nt\nt\nn\nx\no\ny\nr\nu\nh\nm\nj\np\nj\nq\nz\ns\nj\no\ng\nc\nm\nn\no\nm\nr\no\ns\nt\nh\nr\np\nk\nb\nz\ng\no\nc\nc\nz\nz\ng\nr",
"output": "m\nz\ns\nv\nd\nr\nv\ny\ny\ne\np\nt\nc\na\nn\nm\np\ng\ni\nj\nc\na\nb\nq\ne\nn\nv\no\nk\nx\nf\ni\nl\na\nq\nr\nu\nb\ns\nl\nc\nl\ne\nv\nj\nm\nx\nb\na\nq\nb\na\nf\nj\nv\nm\nq\nc\nt\nt\nn\nx\no\ny\nr\nu\nh\nm\nj\np\nj\nq\nz\ns\nj\no\ng\nc\nm\nn\no\nm\nr\no\ns\nt\nh\nr\np\nk\nb\nz\ng\no\nc\nc\nz\nz\ng\nr"
}
] | 1,680,707,508
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 0
| 31
| 0
|
n=str(input())
x=len(n)-2
print(n[0]+str(x)+n[-1])
|
Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made like this: we write down the first and the last letter of a word and between them we write the number of letters between the first and the last letters. That number is in decimal system and doesn't contain any leading zeroes.
Thus, "localization" will be spelt as "l10n", and "internationalization» will be spelt as "i18n".
You are suggested to automatize the process of changing the words with abbreviations. At that all too long words should be replaced by the abbreviation and the words that are not too long should not undergo any changes.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters.
Output Specification:
Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data.
Demo Input:
['4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n']
Demo Output:
['word\nl10n\ni18n\np43s\n']
Note:
none
|
```python
n=str(input())
x=len(n)-2
print(n[0]+str(x)+n[-1])
```
| 0
|
131
|
A
|
cAPS lOCK
|
PROGRAMMING
| 1,000
|
[
"implementation",
"strings"
] | null | null |
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentally switched on, if:
- either it only contains uppercase letters; - or all letters except for the first one are uppercase.
In this case we should automatically change the case of all letters. For example, the case of the letters that form words "hELLO", "HTTP", "z" should be changed.
Write a program that applies the rule mentioned above. If the rule cannot be applied, the program should leave the word unchanged.
|
The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive.
|
Print the result of the given word's processing.
|
[
"cAPS\n",
"Lock\n"
] |
[
"Caps",
"Lock\n"
] |
none
| 500
|
[
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
"input": "oops",
"output": "oops"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "a"
},
{
"input": "aA",
"output": "Aa"
},
{
"input": "Zz",
"output": "Zz"
},
{
"input": "Az",
"output": "Az"
},
{
"input": "zA",
"output": "Za"
},
{
"input": "AAA",
"output": "aaa"
},
{
"input": "AAa",
"output": "AAa"
},
{
"input": "AaR",
"output": "AaR"
},
{
"input": "Tdr",
"output": "Tdr"
},
{
"input": "aTF",
"output": "Atf"
},
{
"input": "fYd",
"output": "fYd"
},
{
"input": "dsA",
"output": "dsA"
},
{
"input": "fru",
"output": "fru"
},
{
"input": "hYBKF",
"output": "Hybkf"
},
{
"input": "XweAR",
"output": "XweAR"
},
{
"input": "mogqx",
"output": "mogqx"
},
{
"input": "eOhEi",
"output": "eOhEi"
},
{
"input": "nkdku",
"output": "nkdku"
},
{
"input": "zcnko",
"output": "zcnko"
},
{
"input": "lcccd",
"output": "lcccd"
},
{
"input": "vwmvg",
"output": "vwmvg"
},
{
"input": "lvchf",
"output": "lvchf"
},
{
"input": "IUNVZCCHEWENCHQQXQYPUJCRDZLUXCLJHXPHBXEUUGNXOOOPBMOBRIBHHMIRILYJGYYGFMTMFSVURGYHUWDRLQVIBRLPEVAMJQYO",
"output": "iunvzcchewenchqqxqypujcrdzluxcljhxphbxeuugnxooopbmobribhhmirilyjgyygfmtmfsvurgyhuwdrlqvibrlpevamjqyo"
},
{
"input": "OBHSZCAMDXEJWOZLKXQKIVXUUQJKJLMMFNBPXAEFXGVNSKQLJGXHUXHGCOTESIVKSFMVVXFVMTEKACRIWALAGGMCGFEXQKNYMRTG",
"output": "obhszcamdxejwozlkxqkivxuuqjkjlmmfnbpxaefxgvnskqljgxhuxhgcotesivksfmvvxfvmtekacriwalaggmcgfexqknymrtg"
},
{
"input": "IKJYZIKROIYUUCTHSVSKZTETNNOCMAUBLFJCEVANCADASMZRCNLBZPQRXESHEEMOMEPCHROSRTNBIDXYMEPJSIXSZQEBTEKKUHFS",
"output": "ikjyzikroiyuucthsvskztetnnocmaublfjcevancadasmzrcnlbzpqrxesheemomepchrosrtnbidxymepjsixszqebtekkuhfs"
},
{
"input": "cTKDZNWVYRTFPQLDAUUNSPKTDJTUPPFPRXRSINTVFVNNQNKXWUZUDHZBUSOKTABUEDQKUIVRTTVUREEOBJTSDKJKVEGFXVHXEYPE",
"output": "Ctkdznwvyrtfpqldauunspktdjtuppfprxrsintvfvnnqnkxwuzudhzbusoktabuedqkuivrttvureeobjtsdkjkvegfxvhxeype"
},
{
"input": "uCKJZRGZJCPPLEEYJTUNKOQSWGBMTBQEVPYFPIPEKRVYQNTDPANOIXKMPINNFUSZWCURGBDPYTEKBEKCPMVZPMWAOSHJYMGKOMBQ",
"output": "Uckjzrgzjcppleeyjtunkoqswgbmtbqevpyfpipekrvyqntdpanoixkmpinnfuszwcurgbdpytekbekcpmvzpmwaoshjymgkombq"
},
{
"input": "KETAXTSWAAOBKUOKUQREHIOMVMMRSAEWKGXZKRASwTVNSSFSNIWYNPSTMRADOADEEBURRHPOOBIEUIBGYDJCEKPNLEUCANZYJKMR",
"output": "KETAXTSWAAOBKUOKUQREHIOMVMMRSAEWKGXZKRASwTVNSSFSNIWYNPSTMRADOADEEBURRHPOOBIEUIBGYDJCEKPNLEUCANZYJKMR"
},
{
"input": "ZEKGDMWJPVUWFlNXRLUmWKLMMYSLRQQIBRWDPKWITUIMZYYKOEYGREKHHZRZZUFPVTNIHKGTCCTLOKSZITXXZDMPITHNZUIGDZLE",
"output": "ZEKGDMWJPVUWFlNXRLUmWKLMMYSLRQQIBRWDPKWITUIMZYYKOEYGREKHHZRZZUFPVTNIHKGTCCTLOKSZITXXZDMPITHNZUIGDZLE"
},
{
"input": "TcMbVPCFvnNkCEUUCIFLgBJeCOKuJhIGwXFrhAZjuAhBraMSchBfWwIuHAEbgJOFzGtxDLDXzDSaPCFujGGxgxdlHUIQYRrMFCgJ",
"output": "TcMbVPCFvnNkCEUUCIFLgBJeCOKuJhIGwXFrhAZjuAhBraMSchBfWwIuHAEbgJOFzGtxDLDXzDSaPCFujGGxgxdlHUIQYRrMFCgJ"
},
{
"input": "xFGqoLILNvxARKuIntPfeukFtMbvzDezKpPRAKkIoIvwqNXnehRVwkkXYvuRCeoieBaBfTjwsYhDeCLvBwktntyluoxCYVioXGdm",
"output": "xFGqoLILNvxARKuIntPfeukFtMbvzDezKpPRAKkIoIvwqNXnehRVwkkXYvuRCeoieBaBfTjwsYhDeCLvBwktntyluoxCYVioXGdm"
},
{
"input": "udvqolbxdwbkijwvhlyaelhynmnfgszbhgshlcwdkaibceqomzujndixuzivlsjyjqxzxodzbukxxhwwultvekdfntwpzlhhrIjm",
"output": "udvqolbxdwbkijwvhlyaelhynmnfgszbhgshlcwdkaibceqomzujndixuzivlsjyjqxzxodzbukxxhwwultvekdfntwpzlhhrIjm"
},
{
"input": "jgpwhetqqoncighgzbbaLwwwxkxivuwtokehrgprfgewzcwxkavwoflcgsgbhoeamzbefzoonwsyzisetoydrpufktzgbaycgaeg",
"output": "jgpwhetqqoncighgzbbaLwwwxkxivuwtokehrgprfgewzcwxkavwoflcgsgbhoeamzbefzoonwsyzisetoydrpufktzgbaycgaeg"
},
{
"input": "vyujsazdstbnkxeunedfbolicojzjpufgfemhtmdrswvmuhoivjvonacefqenbqudelmdegxqtbwezsbydmanzutvdgkgrjxzlnc",
"output": "vyujsazdstbnkxeunedfbolicojzjpufgfemhtmdrswvmuhoivjvonacefqenbqudelmdegxqtbwezsbydmanzutvdgkgrjxzlnc"
},
{
"input": "pivqnuqkaofcduvbttztjbuavrqwiqrwkfncmvatoxruelyoecnkpqraiahumiaiqeyjapbqyrsxcdgjbihivtqezvasfmzntdfv",
"output": "pivqnuqkaofcduvbttztjbuavrqwiqrwkfncmvatoxruelyoecnkpqraiahumiaiqeyjapbqyrsxcdgjbihivtqezvasfmzntdfv"
},
{
"input": "upvtbsxswbohxshdrbjxcungzquhuomgxwlryvshshsfvqbrxvcikbglietlpqkiwbhiqpmdwuqosbtdvyxekkaqiwrbsibpoect",
"output": "upvtbsxswbohxshdrbjxcungzquhuomgxwlryvshshsfvqbrxvcikbglietlpqkiwbhiqpmdwuqosbtdvyxekkaqiwrbsibpoect"
},
{
"input": "cTKDZNWVYRTFPQLDAUUNSPKTDJTUPPFPRXRSINTVFVNNQNKXWUZUDHZBUSOKTABUEDQKUIVRTTVUREEOBJTSDKJKVEGFXVHXEYPE",
"output": "Ctkdznwvyrtfpqldauunspktdjtuppfprxrsintvfvnnqnkxwuzudhzbusoktabuedqkuivrttvureeobjtsdkjkvegfxvhxeype"
},
{
"input": "JEGDOFJOFGJHFROGHOFGMHOFGHORGFHMOu",
"output": "JEGDOFJOFGJHFROGHOFGMHOFGHORGFHMOu"
},
{
"input": "aBACABa",
"output": "aBACABa"
},
{
"input": "AAAAAAAAAAAAAAAAAAAAAAAAaa",
"output": "AAAAAAAAAAAAAAAAAAAAAAAAaa"
},
{
"input": "aaAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA",
"output": "aaAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA"
},
{
"input": "dDDDDDDDDDDDDD",
"output": "Dddddddddddddd"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa",
"output": "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
},
{
"input": "z",
"output": "Z"
},
{
"input": "AZ",
"output": "az"
},
{
"input": "Z",
"output": "z"
},
{
"input": "aAAAA",
"output": "Aaaaa"
},
{
"input": "F",
"output": "f"
}
] | 1,699,002,922
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 5
| 31
| 0
|
n=input()
if n[0].islower() and n[1:].isupper() or n.isupper():
n=n.capitalize()
print(n)
|
Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentally switched on, if:
- either it only contains uppercase letters; - or all letters except for the first one are uppercase.
In this case we should automatically change the case of all letters. For example, the case of the letters that form words "hELLO", "HTTP", "z" should be changed.
Write a program that applies the rule mentioned above. If the rule cannot be applied, the program should leave the word unchanged.
Input Specification:
The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive.
Output Specification:
Print the result of the given word's processing.
Demo Input:
['cAPS\n', 'Lock\n']
Demo Output:
['Caps', 'Lock\n']
Note:
none
|
```python
n=input()
if n[0].islower() and n[1:].isupper() or n.isupper():
n=n.capitalize()
print(n)
```
| 0
|
|
791
|
A
|
Bear and Big Brother
|
PROGRAMMING
| 800
|
[
"implementation"
] | null | null |
Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or equal to his brother's weight.
Limak eats a lot and his weight is tripled after every year, while Bob's weight is doubled after every year.
After how many full years will Limak become strictly larger (strictly heavier) than Bob?
|
The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10) — the weight of Limak and the weight of Bob respectively.
|
Print one integer, denoting the integer number of years after which Limak will become strictly larger than Bob.
|
[
"4 7\n",
"4 9\n",
"1 1\n"
] |
[
"2\n",
"3\n",
"1\n"
] |
In the first sample, Limak weighs 4 and Bob weighs 7 initially. After one year their weights are 4·3 = 12 and 7·2 = 14 respectively (one weight is tripled while the other one is doubled). Limak isn't larger than Bob yet. After the second year weights are 36 and 28, so the first weight is greater than the second one. Limak became larger than Bob after two years so you should print 2.
In the second sample, Limak's and Bob's weights in next years are: 12 and 18, then 36 and 36, and finally 108 and 72 (after three years). The answer is 3. Remember that Limak wants to be larger than Bob and he won't be satisfied with equal weights.
In the third sample, Limak becomes larger than Bob after the first year. Their weights will be 3 and 2 then.
| 500
|
[
{
"input": "4 7",
"output": "2"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "4 6",
"output": "2"
},
{
"input": "1 10",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output": "2"
},
{
"input": "1 3",
"output": "3"
},
{
"input": "1 4",
"output": "4"
},
{
"input": "1 5",
"output": "4"
},
{
"input": "1 6",
"output": "5"
},
{
"input": "1 7",
"output": "5"
},
{
"input": "1 8",
"output": "6"
},
{
"input": "1 9",
"output": "6"
},
{
"input": "1 10",
"output": "6"
},
{
"input": "2 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "2 4",
"output": "2"
},
{
"input": "2 5",
"output": "3"
},
{
"input": "2 6",
"output": "3"
},
{
"input": "2 7",
"output": "4"
},
{
"input": "2 8",
"output": "4"
},
{
"input": "2 9",
"output": "4"
},
{
"input": "2 10",
"output": "4"
},
{
"input": "3 3",
"output": "1"
},
{
"input": "3 4",
"output": "1"
},
{
"input": "3 5",
"output": "2"
},
{
"input": "3 6",
"output": "2"
},
{
"input": "3 7",
"output": "3"
},
{
"input": "3 8",
"output": "3"
},
{
"input": "3 9",
"output": "3"
},
{
"input": "3 10",
"output": "3"
},
{
"input": "4 4",
"output": "1"
},
{
"input": "4 5",
"output": "1"
},
{
"input": "4 6",
"output": "2"
},
{
"input": "4 7",
"output": "2"
},
{
"input": "4 8",
"output": "2"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "4 10",
"output": "3"
},
{
"input": "5 5",
"output": "1"
},
{
"input": "5 6",
"output": "1"
},
{
"input": "5 7",
"output": "1"
},
{
"input": "5 8",
"output": "2"
},
{
"input": "5 9",
"output": "2"
},
{
"input": "5 10",
"output": "2"
},
{
"input": "6 6",
"output": "1"
},
{
"input": "6 7",
"output": "1"
},
{
"input": "6 8",
"output": "1"
},
{
"input": "6 9",
"output": "2"
},
{
"input": "6 10",
"output": "2"
},
{
"input": "7 7",
"output": "1"
},
{
"input": "7 8",
"output": "1"
},
{
"input": "7 9",
"output": "1"
},
{
"input": "7 10",
"output": "1"
},
{
"input": "8 8",
"output": "1"
},
{
"input": "8 9",
"output": "1"
},
{
"input": "8 10",
"output": "1"
},
{
"input": "9 9",
"output": "1"
},
{
"input": "9 10",
"output": "1"
},
{
"input": "10 10",
"output": "1"
},
{
"input": "10 10",
"output": "1"
},
{
"input": "1 2",
"output": "2"
}
] | 1,694,086,835
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 62
| 46
| 0
|
a,b = map(int, input().split())
count = 0
if(a==b):
print(1)
else:
while(a<=b):
a = a * 3
b = b * 2
count = count + 1
print(count)
|
Title: Bear and Big Brother
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or equal to his brother's weight.
Limak eats a lot and his weight is tripled after every year, while Bob's weight is doubled after every year.
After how many full years will Limak become strictly larger (strictly heavier) than Bob?
Input Specification:
The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10) — the weight of Limak and the weight of Bob respectively.
Output Specification:
Print one integer, denoting the integer number of years after which Limak will become strictly larger than Bob.
Demo Input:
['4 7\n', '4 9\n', '1 1\n']
Demo Output:
['2\n', '3\n', '1\n']
Note:
In the first sample, Limak weighs 4 and Bob weighs 7 initially. After one year their weights are 4·3 = 12 and 7·2 = 14 respectively (one weight is tripled while the other one is doubled). Limak isn't larger than Bob yet. After the second year weights are 36 and 28, so the first weight is greater than the second one. Limak became larger than Bob after two years so you should print 2.
In the second sample, Limak's and Bob's weights in next years are: 12 and 18, then 36 and 36, and finally 108 and 72 (after three years). The answer is 3. Remember that Limak wants to be larger than Bob and he won't be satisfied with equal weights.
In the third sample, Limak becomes larger than Bob after the first year. Their weights will be 3 and 2 then.
|
```python
a,b = map(int, input().split())
count = 0
if(a==b):
print(1)
else:
while(a<=b):
a = a * 3
b = b * 2
count = count + 1
print(count)
```
| 3
|
|
538
|
A
|
Cutting Banner
|
PROGRAMMING
| 1,400
|
[
"brute force",
"implementation"
] | null | null |
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of Codeforcesω that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
|
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
|
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
|
[
"CODEWAITFORITFORCES\n",
"BOTTOMCODER\n",
"DECODEFORCES\n",
"DOGEFORCES\n"
] |
[
"YES\n",
"NO\n",
"YES\n",
"NO\n"
] |
none
| 500
|
[
{
"input": "CODEWAITFORITFORCES",
"output": "YES"
},
{
"input": "BOTTOMCODER",
"output": "NO"
},
{
"input": "DECODEFORCES",
"output": "YES"
},
{
"input": "DOGEFORCES",
"output": "NO"
},
{
"input": "ABACABA",
"output": "NO"
},
{
"input": "CODEFORCE",
"output": "NO"
},
{
"input": "C",
"output": "NO"
},
{
"input": "NQTSMZEBLY",
"output": "NO"
},
{
"input": "CODEFZORCES",
"output": "YES"
},
{
"input": "EDYKHVZCNTLJUUOQGHPTIOETQNFLLWEKZOHIUAXELGECABVSBIBGQODQXVYFKBYJWTGBYHVSSNTINKWSINWSMALUSIWNJMTCOOVF",
"output": "NO"
},
{
"input": "OCECFDSRDE",
"output": "NO"
},
{
"input": "MDBUWCZFFZKFMJTTJFXRHTGRPREORKDVUXOEMFYSOMSQGHUKGYCRCVJTNDLFDEWFS",
"output": "NO"
},
{
"input": "CODEFYTORCHES",
"output": "NO"
},
{
"input": "BCODEFORCES",
"output": "YES"
},
{
"input": "CVODEFORCES",
"output": "YES"
},
{
"input": "COAKDEFORCES",
"output": "YES"
},
{
"input": "CODFMWEFORCES",
"output": "YES"
},
{
"input": "CODEVCSYRFORCES",
"output": "YES"
},
{
"input": "CODEFXHHPWCVQORCES",
"output": "YES"
},
{
"input": "CODEFORQWUFJLOFFXTXRCES",
"output": "YES"
},
{
"input": "CODEFORBWFURYIDURNRKRDLHCLXZCES",
"output": "YES"
},
{
"input": "CODEFORCQSYSLYKCDFFUPSAZCJIAENCKZUFJZEINQIES",
"output": "YES"
},
{
"input": "CODEFORCEVENMDBQLSVPQIIBGSHBVOPYZXNWVSTVWDRONUREYJJIJIPMEBPQDCPFS",
"output": "YES"
},
{
"input": "CODEFORCESCFNNPAHNHDIPPBAUSPKJYAQDBVZNLSTSDCREZACVLMRFGVKGVHHZLXOHCTJDBQKIDWBUXDUJARLWGFGFCTTXUCAZB",
"output": "YES"
},
{
"input": "CODJRDPDEFOROES",
"output": "NO"
},
{
"input": "CODEFOGSIUZMZCMWAVQHNYFEKIEZQMAZOVEMDRMOEDBHAXPLBLDYYXCVTOOSJZVSQAKFXTBTZFWAYRZEMDEMVDJTDRXXAQBURCES",
"output": "YES"
},
{
"input": "CODEMKUYHAZSGJBQLXTHUCZZRJJJXUSEBOCNZASOKDZHMSGWZSDFBGHXFLABVPDQBJYXSHHAZAKHSTRGOKJYHRVSSUGDCMFOGCES",
"output": "NO"
},
{
"input": "CODEFORCESCODEFORCESCODEFORCESCODEFORCESCODEFORCESCODEFORCESCODEFORCESCODEFORCESCODEFORCES",
"output": "YES"
},
{
"input": "CCODEFORCESODECODEFORCCODEFORCESODCODEFORCESEFCODEFORCESORCODEFORCESCESCESFORCODEFORCESCES",
"output": "NO"
},
{
"input": "CCODEFORCESC",
"output": "NO"
},
{
"input": "CODEAFORBCES",
"output": "NO"
},
{
"input": "CODERRRRRFORCRRRRES",
"output": "NO"
},
{
"input": "CODELFORCELS",
"output": "NO"
},
{
"input": "CPOPDPEPFPOPRPCPEPS",
"output": "NO"
},
{
"input": "COXDEXFORXCEXS",
"output": "NO"
},
{
"input": "CODAAAAAFORCES",
"output": "NO"
},
{
"input": "CAOADEFORCES",
"output": "NO"
},
{
"input": "FORCESXCODE",
"output": "NO"
},
{
"input": "FORCESACODE",
"output": "NO"
},
{
"input": "ACAOADAEFORCES",
"output": "NO"
},
{
"input": "CCODEFORCESS",
"output": "NO"
},
{
"input": "ZCODEFORCEZ",
"output": "NO"
},
{
"input": "CODXEFORXCES",
"output": "NO"
},
{
"input": "CODEFORCEZ",
"output": "NO"
},
{
"input": "CODEFORCEST",
"output": "YES"
},
{
"input": "AXODEFORCES",
"output": "NO"
},
{
"input": "RCODEFORCESR",
"output": "NO"
},
{
"input": "CODECODEFORCESFORCES",
"output": "YES"
},
{
"input": "TTTWWWCODEFORCES",
"output": "YES"
},
{
"input": "CODEFORRCEST",
"output": "NO"
},
{
"input": "UJYTYUCODEFORCES",
"output": "YES"
},
{
"input": "CODEXXXXXXXXXXXXXXXXXXCODEFORCESXXXXXXXXXXXXXXXXXXXXXFORCES",
"output": "YES"
},
{
"input": "COXEDYFORCES",
"output": "NO"
},
{
"input": "UJYTYCODEFORCES",
"output": "YES"
},
{
"input": "UJYTCODEFORCES",
"output": "YES"
}
] | 1,437,025,171
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 55
| 62
| 0
|
str = input()
test_str = "CODEFORCES"
if len(str) <= len(test_str):
print("NO")
else:
l = 0
r = len(test_str) - 1
while l < len(test_str) and test_str[l] == str[l]:
l += 1
while r >= 0 and test_str[r] == str[len(str) - len(test_str) + r]:
r -= 1
if r >= l :
print("NO")
else:
print("YES")
|
Title: Cutting Banner
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of Codeforcesω that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input Specification:
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output Specification:
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Demo Input:
['CODEWAITFORITFORCES\n', 'BOTTOMCODER\n', 'DECODEFORCES\n', 'DOGEFORCES\n']
Demo Output:
['YES\n', 'NO\n', 'YES\n', 'NO\n']
Note:
none
|
```python
str = input()
test_str = "CODEFORCES"
if len(str) <= len(test_str):
print("NO")
else:
l = 0
r = len(test_str) - 1
while l < len(test_str) and test_str[l] == str[l]:
l += 1
while r >= 0 and test_str[r] == str[len(str) - len(test_str) + r]:
r -= 1
if r >= l :
print("NO")
else:
print("YES")
```
| 3
|
|
20
|
A
|
BerOS file system
|
PROGRAMMING
| 1,700
|
[
"implementation"
] |
A. BerOS file system
|
2
|
64
|
The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/nginx///sbin are equivalent. The character '/' (or some sequence of such characters) at the end of the path is required only in case of the path to the root directory, which can be represented as single character '/'.
A path called normalized if it contains the smallest possible number of characters '/'.
Your task is to transform a given path to the normalized form.
|
The first line of the input contains only lowercase Latin letters and character '/' — the path to some directory. All paths start with at least one character '/'. The length of the given line is no more than 100 characters, it is not empty.
|
The path in normalized form.
|
[
"//usr///local//nginx/sbin\n"
] |
[
"/usr/local/nginx/sbin\n"
] |
none
| 500
|
[
{
"input": "//usr///local//nginx/sbin",
"output": "/usr/local/nginx/sbin"
},
{
"input": "////a//b/////g",
"output": "/a/b/g"
},
{
"input": "/a/b/c",
"output": "/a/b/c"
},
{
"input": "/",
"output": "/"
},
{
"input": "////",
"output": "/"
},
{
"input": "/a//aa/a//",
"output": "/a/aa/a"
},
{
"input": "/aa//b/aa",
"output": "/aa/b/aa"
},
{
"input": "////////////////////////////////////////////////////////////////////////////////////////////////////",
"output": "/"
},
{
"input": "/opt///pokerband///srvb/opt///pokerband///srvb////pokerband///srvb/",
"output": "/opt/pokerband/srvb/opt/pokerband/srvb/pokerband/srvb"
},
{
"input": "/root/pokerband/trunk/server/game/code/src/main/java/com/uosipa/pokerband/gameserver/game/",
"output": "/root/pokerband/trunk/server/game/code/src/main/java/com/uosipa/pokerband/gameserver/game"
},
{
"input": "/root//pokerband/trunk/server/game/code/src///main/java/com/uosipa/pokerband//gameserver/game//",
"output": "/root/pokerband/trunk/server/game/code/src/main/java/com/uosipa/pokerband/gameserver/game"
},
{
"input": "/root//pokerband/trunk/server/game/code/src///main/java/com/uosipa/pokerband//gameserver/game//test/",
"output": "/root/pokerband/trunk/server/game/code/src/main/java/com/uosipa/pokerband/gameserver/game/test"
},
{
"input": "/root//pokerband/trunk/server/game/code/src///main/java/com/uosipa/pokerband//gameserver/game//testt",
"output": "/root/pokerband/trunk/server/game/code/src/main/java/com/uosipa/pokerband/gameserver/game/testt"
},
{
"input": "///a//a////a/a//a//a//a/////",
"output": "/a/a/a/a/a/a/a"
},
{
"input": "/zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz",
"output": "/zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz"
},
{
"input": "/zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz/",
"output": "/zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz"
},
{
"input": "/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a",
"output": "/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a/a"
},
{
"input": "///////////////////////////////////////////////////////////////////////////////////////////////////z",
"output": "/z"
},
{
"input": "/z//////////////////////////////////////////////////////////////////////////////////////////////////",
"output": "/z"
}
] | 1,611,145,449
| 2,147,483,647
|
Python 3
|
RUNTIME_ERROR
|
TESTS
| 3
| 92
| 0
|
a=input().split("/")
end=""
print("/",end="")
for i in range(len(a)):
if a[i]!='':
end+=a[i]+'/'
if end[-1]=="/":
end=end[0:-1]
print(end)
|
Title: BerOS file system
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/nginx///sbin are equivalent. The character '/' (or some sequence of such characters) at the end of the path is required only in case of the path to the root directory, which can be represented as single character '/'.
A path called normalized if it contains the smallest possible number of characters '/'.
Your task is to transform a given path to the normalized form.
Input Specification:
The first line of the input contains only lowercase Latin letters and character '/' — the path to some directory. All paths start with at least one character '/'. The length of the given line is no more than 100 characters, it is not empty.
Output Specification:
The path in normalized form.
Demo Input:
['//usr///local//nginx/sbin\n']
Demo Output:
['/usr/local/nginx/sbin\n']
Note:
none
|
```python
a=input().split("/")
end=""
print("/",end="")
for i in range(len(a)):
if a[i]!='':
end+=a[i]+'/'
if end[-1]=="/":
end=end[0:-1]
print(end)
```
| -1
|
111
|
B
|
Petya and Divisors
|
PROGRAMMING
| 1,900
|
[
"binary search",
"data structures",
"number theory"
] |
B. Petya and Divisors
|
5
|
256
|
Little Petya loves looking for numbers' divisors. One day Petya came across the following problem:
You are given *n* queries in the form "*x**i* *y**i*". For each query Petya should count how many divisors of number *x**i* divide none of the numbers *x**i*<=-<=*y**i*,<=*x**i*<=-<=*y**i*<=+<=1,<=...,<=*x**i*<=-<=1. Help him.
|
The first line contains an integer *n* (1<=≤<=*n*<=≤<=105). Each of the following *n* lines contain two space-separated integers *x**i* and *y**i* (1<=≤<=*x**i*<=≤<=105, 0<=≤<=*y**i*<=≤<=*i*<=-<=1, where *i* is the query's ordinal number; the numeration starts with 1).
If *y**i*<==<=0 for the query, then the answer to the query will be the number of divisors of the number *x**i*. In this case you do not need to take the previous numbers *x* into consideration.
|
For each query print the answer on a single line: the number of positive integers *k* such that
|
[
"6\n4 0\n3 1\n5 2\n6 2\n18 4\n10000 3\n"
] |
[
"3\n1\n1\n2\n2\n22\n"
] |
Let's write out the divisors that give answers for the first 5 queries:
1) 1, 2, 4
2) 3
3) 5
4) 2, 6
5) 9, 18
| 1,000
|
[
{
"input": "6\n4 0\n3 1\n5 2\n6 2\n18 4\n10000 3",
"output": "3\n1\n1\n2\n2\n22"
},
{
"input": "5\n10 0\n10 0\n10 0\n10 0\n10 0",
"output": "4\n4\n4\n4\n4"
},
{
"input": "12\n41684 0\n95210 1\n60053 1\n32438 3\n97956 1\n21785 2\n14594 6\n17170 4\n93937 6\n70764 5\n13695 4\n14552 6",
"output": "12\n6\n7\n9\n22\n3\n2\n13\n1\n6\n13\n11"
},
{
"input": "10\n54972 0\n48015 1\n7114 1\n68273 2\n53650 4\n1716 1\n16165 2\n96062 5\n57750 1\n21071 5",
"output": "24\n21\n3\n3\n21\n22\n6\n6\n62\n3"
},
{
"input": "20\n68260 0\n819 1\n54174 1\n20460 1\n25696 2\n81647 4\n17736 4\n91307 5\n5210 4\n87730 2\n4653 8\n11044 6\n15776 4\n17068 7\n73738 7\n36004 12\n83183 7\n75700 12\n84270 14\n16120 5",
"output": "12\n11\n6\n44\n18\n1\n9\n7\n6\n12\n8\n8\n21\n3\n14\n3\n3\n13\n18\n26"
},
{
"input": "17\n81548 0\n69975 1\n1234 0\n72647 0\n81389 4\n77930 1\n19308 0\n86551 6\n69023 8\n38037 1\n133 9\n59290 8\n1106 11\n95012 10\n57693 11\n8467 6\n93732 13",
"output": "24\n17\n4\n2\n11\n7\n12\n3\n3\n7\n2\n27\n4\n3\n2\n1\n18"
},
{
"input": "15\n94836 0\n22780 1\n48294 0\n24834 3\n37083 2\n57862 0\n37231 1\n81795 7\n32835 2\n4696 8\n95612 0\n7536 6\n70084 5\n72956 10\n41647 7",
"output": "24\n21\n12\n4\n6\n8\n3\n27\n12\n5\n24\n15\n8\n21\n1"
},
{
"input": "12\n91771 0\n75584 1\n95355 1\n60669 1\n92776 0\n37793 3\n38802 4\n60688 0\n80296 5\n55003 8\n91092 3\n55782 8",
"output": "2\n13\n23\n17\n8\n2\n13\n10\n4\n2\n9\n10"
},
{
"input": "11\n5059 0\n28388 1\n42415 2\n12856 0\n48470 3\n34076 2\n40374 6\n55932 1\n44108 2\n5310 5\n86571 4",
"output": "2\n11\n7\n8\n13\n9\n10\n20\n3\n12\n3"
},
{
"input": "10\n18347 0\n81193 1\n89475 2\n65043 3\n4164 0\n14007 5\n41945 0\n51177 1\n91569 5\n71969 4",
"output": "4\n4\n11\n18\n12\n13\n4\n7\n6\n3"
}
] | 1,627,797,889
| 2,147,483,647
|
PyPy 3
|
OK
|
TESTS
| 44
| 3,336
| 44,851,200
|
maxn=100000
div=[0]*(maxn+1)
last=[-maxn]*(maxn+1)
#Inicializa con lista vacía cada posición
for i in range(maxn+1):
div[i]=list()
#Guarda en div[j] la lista de divisores de j
for i in range(2,maxn+1):
for j in range(i,maxn+1,i):
div[j].append(i)
#Resuelve cada caso de prueba
t=int(input())
for k in range(0,t):
#Parsea
x,y = input().split(" ")
x=int(x)
y=int(y)
if y==0:
print((len(div[x])+1)) #Cantidad de Divisores contando al 1
else:
#La cantidad de divisores que cumplen que el último múltiplo
#de ellos que apareció entre los casos fue antes del caso en la posición
#actual-y
print((sum(1 for v in div[x] if last[v]<k-y)))
#Actualiza la posición del último caso que fue múltiplo de los calores pasando
#por cada divisor de este
for d in div[x]:
last[d]=k
|
Title: Petya and Divisors
Time Limit: 5 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya loves looking for numbers' divisors. One day Petya came across the following problem:
You are given *n* queries in the form "*x**i* *y**i*". For each query Petya should count how many divisors of number *x**i* divide none of the numbers *x**i*<=-<=*y**i*,<=*x**i*<=-<=*y**i*<=+<=1,<=...,<=*x**i*<=-<=1. Help him.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=105). Each of the following *n* lines contain two space-separated integers *x**i* and *y**i* (1<=≤<=*x**i*<=≤<=105, 0<=≤<=*y**i*<=≤<=*i*<=-<=1, where *i* is the query's ordinal number; the numeration starts with 1).
If *y**i*<==<=0 for the query, then the answer to the query will be the number of divisors of the number *x**i*. In this case you do not need to take the previous numbers *x* into consideration.
Output Specification:
For each query print the answer on a single line: the number of positive integers *k* such that
Demo Input:
['6\n4 0\n3 1\n5 2\n6 2\n18 4\n10000 3\n']
Demo Output:
['3\n1\n1\n2\n2\n22\n']
Note:
Let's write out the divisors that give answers for the first 5 queries:
1) 1, 2, 4
2) 3
3) 5
4) 2, 6
5) 9, 18
|
```python
maxn=100000
div=[0]*(maxn+1)
last=[-maxn]*(maxn+1)
#Inicializa con lista vacía cada posición
for i in range(maxn+1):
div[i]=list()
#Guarda en div[j] la lista de divisores de j
for i in range(2,maxn+1):
for j in range(i,maxn+1,i):
div[j].append(i)
#Resuelve cada caso de prueba
t=int(input())
for k in range(0,t):
#Parsea
x,y = input().split(" ")
x=int(x)
y=int(y)
if y==0:
print((len(div[x])+1)) #Cantidad de Divisores contando al 1
else:
#La cantidad de divisores que cumplen que el último múltiplo
#de ellos que apareció entre los casos fue antes del caso en la posición
#actual-y
print((sum(1 for v in div[x] if last[v]<k-y)))
#Actualiza la posición del último caso que fue múltiplo de los calores pasando
#por cada divisor de este
for d in div[x]:
last[d]=k
```
| 3.582858
|
266
|
A
|
Stones on the Table
|
PROGRAMMING
| 800
|
[
"implementation"
] | null | null |
There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them.
|
The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table.
The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red, "G", if it's green and "B", if it's blue.
|
Print a single integer — the answer to the problem.
|
[
"3\nRRG\n",
"5\nRRRRR\n",
"4\nBRBG\n"
] |
[
"1\n",
"4\n",
"0\n"
] |
none
| 500
|
[
{
"input": "3\nRRG",
"output": "1"
},
{
"input": "5\nRRRRR",
"output": "4"
},
{
"input": "4\nBRBG",
"output": "0"
},
{
"input": "1\nB",
"output": "0"
},
{
"input": "2\nBG",
"output": "0"
},
{
"input": "3\nBGB",
"output": "0"
},
{
"input": "4\nRBBR",
"output": "1"
},
{
"input": "5\nRGGBG",
"output": "1"
},
{
"input": "10\nGGBRBRGGRB",
"output": "2"
},
{
"input": "50\nGRBGGRBRGRBGGBBBBBGGGBBBBRBRGBRRBRGBBBRBBRRGBGGGRB",
"output": "18"
},
{
"input": "15\nBRRBRGGBBRRRRGR",
"output": "6"
},
{
"input": "20\nRRGBBRBRGRGBBGGRGRRR",
"output": "6"
},
{
"input": "25\nBBGBGRBGGBRRBGRRBGGBBRBRB",
"output": "6"
},
{
"input": "30\nGRGGGBGGRGBGGRGRBGBGBRRRRRRGRB",
"output": "9"
},
{
"input": "35\nGBBGBRGBBGGRBBGBRRGGRRRRRRRBRBBRRGB",
"output": "14"
},
{
"input": "40\nGBBRRGBGGGRGGGRRRRBRBGGBBGGGBGBBBBBRGGGG",
"output": "20"
},
{
"input": "45\nGGGBBRBBRRGRBBGGBGRBRGGBRBRGBRRGBGRRBGRGRBRRG",
"output": "11"
},
{
"input": "50\nRBGGBGGRBGRBBBGBBGRBBBGGGRBBBGBBBGRGGBGGBRBGBGRRGG",
"output": "17"
},
{
"input": "50\nGGGBBRGGGGGRRGGRBGGRGBBRBRRBGRGBBBGBRBGRGBBGRGGBRB",
"output": "16"
},
{
"input": "50\nGBGRGRRBRRRRRGGBBGBRRRBBBRBBBRRGRBBRGBRBGGRGRBBGGG",
"output": "19"
},
{
"input": "10\nGRRBRBRBGR",
"output": "1"
},
{
"input": "10\nBRBGBGRRBR",
"output": "1"
},
{
"input": "20\nGBGBGGRRRRGRBBGRGRGR",
"output": "5"
},
{
"input": "20\nRRGGRBBGBBRBGRRBRRBG",
"output": "6"
},
{
"input": "30\nBGBRGBBBGRGBBRGBGRBBBRGGRRGRRB",
"output": "8"
},
{
"input": "30\nBBBBGGBRBGBBGBGBGBGGGRGRRGGBBB",
"output": "11"
},
{
"input": "40\nGBRRGRBGBRRGBRGGGBRGBGBRGBBRRGRGGBBGBGBB",
"output": "9"
},
{
"input": "40\nBRGRGGRGGRBBRRRBRBBGGGRRGBGBBGRBBRGBRRGG",
"output": "13"
},
{
"input": "50\nRBGBGGRRGGRGGBGBGRRBGGBGBRRBBGBBGBBBGBBRBBRBRBRGRG",
"output": "13"
},
{
"input": "50\nRBRRGBGRRRBGRRBGRRGRBBRBBRRBRGGBRBRRBGGRBGGBRBRGRB",
"output": "12"
},
{
"input": "2\nBB",
"output": "1"
},
{
"input": "50\nRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR",
"output": "49"
},
{
"input": "50\nRRRRRRRRGRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR",
"output": "47"
},
{
"input": "50\nRRRRRRRRRRRRGGRRRRRRRRRBRRRRRRRRRRRRRRBBRRRRRRRRRR",
"output": "43"
}
] | 1,694,660,118
| 2,147,483,647
|
Python 3
|
RUNTIME_ERROR
|
TESTS
| 0
| 60
| 0
|
x=y0;input()
for i in input():x+=y==i;y=i
print(x)
|
Title: Stones on the Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table.
The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red, "G", if it's green and "B", if it's blue.
Output Specification:
Print a single integer — the answer to the problem.
Demo Input:
['3\nRRG\n', '5\nRRRRR\n', '4\nBRBG\n']
Demo Output:
['1\n', '4\n', '0\n']
Note:
none
|
```python
x=y0;input()
for i in input():x+=y==i;y=i
print(x)
```
| -1
|
|
2
|
B
|
The least round way
|
PROGRAMMING
| 2,000
|
[
"dp",
"math"
] |
B. The least round way
|
2
|
64
|
There is a square matrix *n*<=×<=*n*, consisting of non-negative integer numbers. You should find such a way on it that
- starts in the upper left cell of the matrix; - each following cell is to the right or down from the current cell; - the way ends in the bottom right cell.
Moreover, if we multiply together all the numbers along the way, the result should be the least "round". In other words, it should end in the least possible number of zeros.
|
The first line contains an integer number *n* (2<=≤<=*n*<=≤<=1000), *n* is the size of the matrix. Then follow *n* lines containing the matrix elements (non-negative integer numbers not exceeding 109).
|
In the first line print the least number of trailing zeros. In the second line print the correspondent way itself.
|
[
"3\n1 2 3\n4 5 6\n7 8 9\n"
] |
[
"0\nDDRR\n"
] |
none
| 0
|
[
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "0\nDDRR"
},
{
"input": "2\n7 6\n3 8",
"output": "0\nDR"
},
{
"input": "3\n4 10 5\n10 9 4\n6 5 3",
"output": "1\nDRRD"
},
{
"input": "4\n1 1 9 9\n3 4 7 3\n7 9 1 7\n1 7 1 5",
"output": "0\nDDDRRR"
},
{
"input": "5\n8 3 2 1 4\n3 7 2 4 8\n9 2 8 9 10\n2 3 6 10 1\n8 2 2 8 4",
"output": "0\nDDDDRRRR"
},
{
"input": "6\n5 5 4 10 5 5\n7 10 8 7 6 6\n7 1 7 9 7 8\n5 5 3 3 10 9\n5 8 10 6 3 8\n3 10 5 4 3 4",
"output": "1\nDDRRDRDDRR"
},
{
"input": "7\n2 9 8 2 7 4 8\n9 5 4 4 8 5 3\n5 7 2 10 8 1 8\n2 7 10 7 5 7 7\n9 2 7 6 4 8 4\n7 2 4 7 4 1 8\n9 5 3 10 1 6 2",
"output": "0\nRRDRRDRDDDDR"
},
{
"input": "8\n1 1 10 1 8 4 8 7\n9 3 3 2 2 6 2 4\n7 4 3 5 10 3 5 1\n8 4 4 10 4 5 9 4\n5 5 5 2 6 7 1 8\n4 10 1 3 2 4 8 3\n8 1 10 2 8 2 2 4\n2 10 6 8 10 2 8 4",
"output": "0\nDRRRRRRRDDDDDD"
},
{
"input": "9\n8 3 3 3 10 3 10 5 6\n2 1 6 1 8 1 9 1 6\n6 1 5 4 2 2 10 4 9\n1 9 1 3 10 6 10 5 5\n1 10 5 4 7 2 5 9 10\n6 6 1 3 1 9 4 9 9\n5 3 7 6 4 6 2 10 2\n9 3 3 10 5 6 7 6 4\n4 9 6 7 4 3 7 6 5",
"output": "1\nDDDDDRDDDRRRRRRR"
},
{
"input": "10\n10 8 6 5 9 8 2 5 3 2\n3 1 8 6 8 10 5 5 7 8\n5 9 7 7 4 9 7 2 5 2\n5 9 9 5 4 2 6 6 8 1\n10 6 9 9 10 5 6 3 5 9\n6 7 10 3 1 4 3 6 7 6\n10 10 4 7 4 4 8 6 7 4\n10 5 8 2 2 7 4 4 1 4\n8 4 6 10 10 6 1 3 3 1\n9 9 7 2 9 5 1 8 6 3",
"output": "1\nDRDDDRRDDDRRDRDRRR"
}
] | 1,507,914,400
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 0
| 61
| 307,200
|
#! python3
def multiply(min_digit, num):
tmp = min_digit * num
trailing_zero_num = 0
while tmp%10 == 0:
trailing_zero_num += 1
tmp = int(tmp/10)
return tmp, trailing_zero_num
def display_sections_info(sections_info):
for i in range(len(sections_info)):
for j in range(len(sections_info[0])):
print(i, j, sections_info[i][j])
n = int(input())
sections = []
for i in range(n):
sections.append([ int(i) for i in input().split()])
sections_info = [ [ {} for i in range(n) ] for i in range(n) ]
min_dig, trailing_zero_num = multiply(sections[0][0], 1)
sections_info[0][0] = {'trailing_zero_num': trailing_zero_num, 'min_digit': min_dig, 'come_from': 'none'}
for i in range(1, n):
min_dig, trailing_zero_num = multiply(sections[0][i], sections[0][i-1])
sections_info[0][i] = {'trailing_zero_num': sections_info[0][i-1]['trailing_zero_num'] + trailing_zero_num, 'min_digit': min_dig, 'come_from': 'left'}
min_dig, trailing_zero_num = multiply(sections[i][0], sections[i-1][0])
sections_info[i][0] = {'trailing_zero_num': sections_info[i-1][0]['trailing_zero_num'] + trailing_zero_num, 'min_digit': min_dig, 'come_from': 'up'}
for i in range(2*(n-2)+1):
a, b = 0, i+1
if i > (n-2): a, b = i-(n-2), n-1
for j in range(a, b):
min_dig_up, trailing_zero_num_up = multiply(sections_info[i-j][j+1]['min_digit'], sections[i-j+1][j+1])
min_dig_left, trailing_zero_num_left = multiply(sections_info[i-j+1][j]['min_digit'], sections[i-j+1][j+1])
if trailing_zero_num_left <= trailing_zero_num_up:
sections_info[i-j+1][j+1] = {'trailing_zero_num': trailing_zero_num_left, 'min_digit': min_dig_left, 'come_from': 'left'}
else:
sections_info[i-j+1][j+1] = {'trailing_zero_num': trailing_zero_num_up, 'min_digit': min_dig_up, 'come_from': 'up'}
path = ""
i, j = n-1, n-1
while sections_info[i][j]['come_from'] != 'none':
if sections_info[i][j]['come_from'] == 'left':
path += 'R'
j -= 1
elif sections_info[i][j]['come_from'] == 'up':
path += 'D'
i -= 1
path = path[::-1]
print(path)
|
Title: The least round way
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
There is a square matrix *n*<=×<=*n*, consisting of non-negative integer numbers. You should find such a way on it that
- starts in the upper left cell of the matrix; - each following cell is to the right or down from the current cell; - the way ends in the bottom right cell.
Moreover, if we multiply together all the numbers along the way, the result should be the least "round". In other words, it should end in the least possible number of zeros.
Input Specification:
The first line contains an integer number *n* (2<=≤<=*n*<=≤<=1000), *n* is the size of the matrix. Then follow *n* lines containing the matrix elements (non-negative integer numbers not exceeding 109).
Output Specification:
In the first line print the least number of trailing zeros. In the second line print the correspondent way itself.
Demo Input:
['3\n1 2 3\n4 5 6\n7 8 9\n']
Demo Output:
['0\nDDRR\n']
Note:
none
|
```python
#! python3
def multiply(min_digit, num):
tmp = min_digit * num
trailing_zero_num = 0
while tmp%10 == 0:
trailing_zero_num += 1
tmp = int(tmp/10)
return tmp, trailing_zero_num
def display_sections_info(sections_info):
for i in range(len(sections_info)):
for j in range(len(sections_info[0])):
print(i, j, sections_info[i][j])
n = int(input())
sections = []
for i in range(n):
sections.append([ int(i) for i in input().split()])
sections_info = [ [ {} for i in range(n) ] for i in range(n) ]
min_dig, trailing_zero_num = multiply(sections[0][0], 1)
sections_info[0][0] = {'trailing_zero_num': trailing_zero_num, 'min_digit': min_dig, 'come_from': 'none'}
for i in range(1, n):
min_dig, trailing_zero_num = multiply(sections[0][i], sections[0][i-1])
sections_info[0][i] = {'trailing_zero_num': sections_info[0][i-1]['trailing_zero_num'] + trailing_zero_num, 'min_digit': min_dig, 'come_from': 'left'}
min_dig, trailing_zero_num = multiply(sections[i][0], sections[i-1][0])
sections_info[i][0] = {'trailing_zero_num': sections_info[i-1][0]['trailing_zero_num'] + trailing_zero_num, 'min_digit': min_dig, 'come_from': 'up'}
for i in range(2*(n-2)+1):
a, b = 0, i+1
if i > (n-2): a, b = i-(n-2), n-1
for j in range(a, b):
min_dig_up, trailing_zero_num_up = multiply(sections_info[i-j][j+1]['min_digit'], sections[i-j+1][j+1])
min_dig_left, trailing_zero_num_left = multiply(sections_info[i-j+1][j]['min_digit'], sections[i-j+1][j+1])
if trailing_zero_num_left <= trailing_zero_num_up:
sections_info[i-j+1][j+1] = {'trailing_zero_num': trailing_zero_num_left, 'min_digit': min_dig_left, 'come_from': 'left'}
else:
sections_info[i-j+1][j+1] = {'trailing_zero_num': trailing_zero_num_up, 'min_digit': min_dig_up, 'come_from': 'up'}
path = ""
i, j = n-1, n-1
while sections_info[i][j]['come_from'] != 'none':
if sections_info[i][j]['come_from'] == 'left':
path += 'R'
j -= 1
elif sections_info[i][j]['come_from'] == 'up':
path += 'D'
i -= 1
path = path[::-1]
print(path)
```
| 0
|
61
|
E
|
Enemy is weak
|
PROGRAMMING
| 1,900
|
[
"data structures",
"trees"
] |
E. Enemy is weak
|
5
|
256
|
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets *i*,<=*j*,<=*k* such that *i*<=<<=*j*<=<<=*k* and *a**i*<=><=*a**j*<=><=*a**k* where *a**x* is the power of man standing at position *x*. The Roman army has one special trait — powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
|
The first line of input contains a single number *n* (3<=≤<=*n*<=≤<=106) — the number of men in Roman army. Next line contains *n* different positive integers *a**i* (1<=≤<=*i*<=≤<=*n*,<=1<=≤<=*a**i*<=≤<=109) — powers of men in the Roman army.
|
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
|
[
"3\n3 2 1\n",
"3\n2 3 1\n",
"4\n10 8 3 1\n",
"4\n1 5 4 3\n"
] |
[
"1\n",
"0\n",
"4\n",
"1\n"
] |
none
| 2,500
|
[
{
"input": "3\n3 2 1",
"output": "1"
},
{
"input": "3\n2 3 1",
"output": "0"
},
{
"input": "4\n10 8 3 1",
"output": "4"
},
{
"input": "4\n1 5 4 3",
"output": "1"
},
{
"input": "9\n10 9 5 6 8 3 4 7 11",
"output": "20"
},
{
"input": "7\n11 3 8 4 2 9 6",
"output": "7"
},
{
"input": "6\n2 1 10 7 3 5",
"output": "2"
},
{
"input": "4\n1 5 3 10",
"output": "0"
},
{
"input": "3\n2 7 11",
"output": "0"
},
{
"input": "5\n4 11 7 5 10",
"output": "1"
},
{
"input": "72\n685 154 298 660 716 963 692 257 397 974 92 191 519 838 828 957 687 776 636 997 101 800 579 181 691 256 95 531 333 347 803 682 252 655 297 892 833 31 239 895 45 235 394 909 486 400 621 443 348 471 59 791 934 195 861 356 876 741 763 431 781 639 193 291 230 171 288 187 657 273 200 924",
"output": "12140"
},
{
"input": "20\n840 477 436 149 554 528 671 67 630 382 805 329 781 980 237 589 743 451 633 24",
"output": "185"
},
{
"input": "59\n996 800 927 637 393 741 650 524 863 789 517 467 408 442 988 701 528 215 490 764 282 990 991 244 70 510 36 151 193 378 102 818 384 621 349 476 658 985 465 366 807 32 430 814 945 733 382 751 380 136 405 585 494 862 598 425 421 90 72",
"output": "7842"
},
{
"input": "97\n800 771 66 126 231 306 981 96 196 229 253 35 903 739 461 962 979 347 152 424 934 586 225 838 103 178 524 400 156 149 560 629 697 417 717 738 181 430 611 513 754 595 847 464 356 640 24 854 138 481 98 371 142 460 194 288 605 41 999 581 441 407 301 651 271 226 457 393 980 166 272 250 900 337 358 359 80 904 53 39 558 569 101 339 752 432 889 285 836 660 190 180 601 136 527 990 612",
"output": "26086"
},
{
"input": "45\n955 94 204 615 69 519 960 791 977 603 294 391 662 364 139 222 748 742 540 567 230 830 558 959 329 169 854 503 423 210 832 87 990 44 7 777 138 898 845 733 570 476 113 233 630",
"output": "2676"
},
{
"input": "84\n759 417 343 104 908 84 940 248 210 10 6 529 289 826 890 982 533 506 412 280 709 175 425 891 727 914 235 882 834 445 912 163 263 998 391 948 836 538 615 854 275 198 631 267 148 955 418 961 642 132 599 657 389 879 177 739 536 932 682 928 660 821 15 878 521 990 518 765 79 544 771 134 611 244 608 809 733 832 933 270 397 349 798 857",
"output": "12571"
},
{
"input": "32\n915 740 482 592 394 648 919 705 443 418 719 315 916 287 289 743 319 270 269 668 203 119 20 224 847 500 949 910 164 468 965 846",
"output": "1230"
},
{
"input": "34\n718 63 972 81 233 861 250 515 676 825 431 453 543 748 41 503 104 34 126 57 346 616 557 615 733 15 938 495 491 667 177 317 367 85",
"output": "1202"
},
{
"input": "73\n874 34 111 922 71 426 229 972 557 232 144 590 170 210 792 616 890 798 983 797 488 8 859 538 736 319 82 966 474 513 721 860 493 375 81 69 662 444 766 451 571 94 365 833 720 703 826 270 437 542 147 800 146 173 564 160 928 57 732 774 292 250 716 131 949 1 216 456 53 322 403 195 460",
"output": "13229"
},
{
"input": "90\n301 241 251 995 267 292 335 623 270 144 291 757 950 21 808 109 971 340 678 377 743 841 669 333 528 988 336 233 118 781 138 47 972 68 234 812 629 701 520 842 156 348 600 26 94 912 903 552 470 456 61 273 93 810 545 231 450 926 172 246 884 79 614 728 533 491 76 589 668 487 409 650 433 677 124 407 956 794 299 763 843 290 591 216 844 731 327 34 687 649",
"output": "17239"
}
] | 1,550,567,630
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 4
| 109
| 307,200
|
class Node:
count=False
def __init__(self,value):
nodelist=[self]
self.right=False
self.left=False
self.value=value
self.former_smaller_count=[0,0,0]
present_smaller_count=[1,0,0]
# puts 1
if Node.count:
r=Node.root
# puts 2
while (True):
if r.value>self.value:
if r.left:
# puts 3
nodelist.append(r)
r=r.left
else:
# puts 4
r.left=self
break
else:
present_smaller_count[1]+=r.former_smaller_count[0]
present_smaller_count[2]+=r.former_smaller_count[1]
if r.right:
# puts 5
r=r.right
else:
# puts 6
r.right=self
break
else:
# puts 7
Node.root=self
Node.count=True
while len(nodelist)>0:
aa=nodelist.pop()
aa.former_smaller_count[0]+=present_smaller_count[0]
aa.former_smaller_count[1]+=present_smaller_count[1]
aa.former_smaller_count[2]+=present_smaller_count[2]
# def printt
# p value
# p @present_smaller_count
# p @former_smaller_count
# end
@classmethod
def printt(cls):
r=Node.root
a=r.former_smaller_count[2]
while r.right:
r=r.right
a+=r.former_smaller_count[2]
print (a)
input()
ary=input().split()
ary.reverse()
for e in ary:
Node(int(e))
Node.printt()
|
Title: Enemy is weak
Time Limit: 5 seconds
Memory Limit: 256 megabytes
Problem Description:
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weakness of an army is equal to the number of triplets *i*,<=*j*,<=*k* such that *i*<=<<=*j*<=<<=*k* and *a**i*<=><=*a**j*<=><=*a**k* where *a**x* is the power of man standing at position *x*. The Roman army has one special trait — powers of all the people in it are distinct.
Help Shapur find out how weak the Romans are.
Input Specification:
The first line of input contains a single number *n* (3<=≤<=*n*<=≤<=106) — the number of men in Roman army. Next line contains *n* different positive integers *a**i* (1<=≤<=*i*<=≤<=*n*,<=1<=≤<=*a**i*<=≤<=109) — powers of men in the Roman army.
Output Specification:
A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).
Demo Input:
['3\n3 2 1\n', '3\n2 3 1\n', '4\n10 8 3 1\n', '4\n1 5 4 3\n']
Demo Output:
['1\n', '0\n', '4\n', '1\n']
Note:
none
|
```python
class Node:
count=False
def __init__(self,value):
nodelist=[self]
self.right=False
self.left=False
self.value=value
self.former_smaller_count=[0,0,0]
present_smaller_count=[1,0,0]
# puts 1
if Node.count:
r=Node.root
# puts 2
while (True):
if r.value>self.value:
if r.left:
# puts 3
nodelist.append(r)
r=r.left
else:
# puts 4
r.left=self
break
else:
present_smaller_count[1]+=r.former_smaller_count[0]
present_smaller_count[2]+=r.former_smaller_count[1]
if r.right:
# puts 5
r=r.right
else:
# puts 6
r.right=self
break
else:
# puts 7
Node.root=self
Node.count=True
while len(nodelist)>0:
aa=nodelist.pop()
aa.former_smaller_count[0]+=present_smaller_count[0]
aa.former_smaller_count[1]+=present_smaller_count[1]
aa.former_smaller_count[2]+=present_smaller_count[2]
# def printt
# p value
# p @present_smaller_count
# p @former_smaller_count
# end
@classmethod
def printt(cls):
r=Node.root
a=r.former_smaller_count[2]
while r.right:
r=r.right
a+=r.former_smaller_count[2]
print (a)
input()
ary=input().split()
ary.reverse()
for e in ary:
Node(int(e))
Node.printt()
```
| 0
|
897
|
B
|
Chtholly's request
|
PROGRAMMING
| 1,300
|
[
"brute force"
] | null | null |
— I experienced so many great things.
— You gave me memories like dreams... But I have to leave now...
— One last request, can you...
— Help me solve a Codeforces problem?
— ......
— What?
Chtholly has been thinking about a problem for days:
If a number is palindrome and length of its decimal representation without leading zeros is even, we call it a zcy number. A number is palindrome means when written in decimal representation, it contains no leading zeros and reads the same forwards and backwards. For example 12321 and 1221 are palindromes and 123 and 12451 are not. Moreover, 1221 is zcy number and 12321 is not.
Given integers *k* and *p*, calculate the sum of the *k* smallest zcy numbers and output this sum modulo *p*.
Unfortunately, Willem isn't good at solving this kind of problems, so he asks you for help!
|
The first line contains two integers *k* and *p* (1<=≤<=*k*<=≤<=105,<=1<=≤<=*p*<=≤<=109).
|
Output single integer — answer to the problem.
|
[
"2 100\n",
"5 30\n"
] |
[
"33\n",
"15\n"
] |
In the first example, the smallest zcy number is 11, and the second smallest zcy number is 22.
In the second example, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/68fffad54395f7d920ad0384e07c6215ddc64141.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
| 1,000
|
[
{
"input": "2 100",
"output": "33"
},
{
"input": "5 30",
"output": "15"
},
{
"input": "42147 412393322",
"output": "251637727"
},
{
"input": "77809 868097296",
"output": "440411873"
},
{
"input": "5105 443422097",
"output": "363192634"
},
{
"input": "75615 376679484",
"output": "373089399"
},
{
"input": "22951 23793302",
"output": "1898631"
},
{
"input": "12785 993582106",
"output": "286204743"
},
{
"input": "60276 428978808",
"output": "376477293"
},
{
"input": "84776 104860385",
"output": "10209596"
},
{
"input": "41984 653766991",
"output": "17823101"
},
{
"input": "100000 1000000000",
"output": "495495496"
},
{
"input": "41163 472310076",
"output": "207304047"
},
{
"input": "6983 765352180",
"output": "586866999"
},
{
"input": "33493 967727004",
"output": "305705165"
},
{
"input": "90898 94010922",
"output": "65928728"
},
{
"input": "67298 349286579",
"output": "156435206"
},
{
"input": "92452 296773064",
"output": "229486976"
},
{
"input": "58832 563860457",
"output": "16775206"
},
{
"input": "90234 156145441",
"output": "44023160"
},
{
"input": "91454 977186148",
"output": "681779748"
},
{
"input": "11108 444095250",
"output": "188075844"
},
{
"input": "46304 584475527",
"output": "275627129"
},
{
"input": "1 1",
"output": "0"
},
{
"input": "1 1000000000",
"output": "11"
},
{
"input": "100000 1",
"output": "0"
}
] | 1,627,909,688
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 26
| 218
| 6,963,200
|
def getdouble(a):
a=list(str(a))
b=a[::-1]
result=''
for i in a:
result+=i
for i in b:
result+=i
return int(result)
sum=0
lists=list(map(int,input().split(' ')))
for i in range(1,lists[0]+1):
sum+=getdouble(i)
print(sum%lists[1])
|
Title: Chtholly's request
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
— I experienced so many great things.
— You gave me memories like dreams... But I have to leave now...
— One last request, can you...
— Help me solve a Codeforces problem?
— ......
— What?
Chtholly has been thinking about a problem for days:
If a number is palindrome and length of its decimal representation without leading zeros is even, we call it a zcy number. A number is palindrome means when written in decimal representation, it contains no leading zeros and reads the same forwards and backwards. For example 12321 and 1221 are palindromes and 123 and 12451 are not. Moreover, 1221 is zcy number and 12321 is not.
Given integers *k* and *p*, calculate the sum of the *k* smallest zcy numbers and output this sum modulo *p*.
Unfortunately, Willem isn't good at solving this kind of problems, so he asks you for help!
Input Specification:
The first line contains two integers *k* and *p* (1<=≤<=*k*<=≤<=105,<=1<=≤<=*p*<=≤<=109).
Output Specification:
Output single integer — answer to the problem.
Demo Input:
['2 100\n', '5 30\n']
Demo Output:
['33\n', '15\n']
Note:
In the first example, the smallest zcy number is 11, and the second smallest zcy number is 22.
In the second example, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/68fffad54395f7d920ad0384e07c6215ddc64141.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
|
```python
def getdouble(a):
a=list(str(a))
b=a[::-1]
result=''
for i in a:
result+=i
for i in b:
result+=i
return int(result)
sum=0
lists=list(map(int,input().split(' ')))
for i in range(1,lists[0]+1):
sum+=getdouble(i)
print(sum%lists[1])
```
| 3
|
|
87
|
C
|
Interesting Game
|
PROGRAMMING
| 2,000
|
[
"dp",
"games",
"math"
] |
C. Interesting Game
|
2
|
256
|
Two best friends Serozha and Gena play a game.
Initially there is one pile consisting of *n* stones on the table. During one move one pile should be taken and divided into an arbitrary number of piles consisting of *a*1<=><=*a*2<=><=...<=><=*a**k*<=><=0 stones. The piles should meet the condition *a*1<=-<=*a*2<==<=*a*2<=-<=*a*3<==<=...<==<=*a**k*<=-<=1<=-<=*a**k*<==<=1. Naturally, the number of piles *k* should be no less than two.
The friends play in turns. The player who cannot make a move loses. Serozha makes the first move. Who will win if both players play in the optimal way?
|
The single line contains a single integer *n* (1<=≤<=*n*<=≤<=105).
|
If Serozha wins, print *k*, which represents the minimal number of piles into which he can split the initial one during the first move in order to win the game.
If Gena wins, print "-1" (without the quotes).
|
[
"3\n",
"6\n",
"100\n"
] |
[
"2\n",
"-1\n",
"8\n"
] |
none
| 1,500
|
[
{
"input": "3",
"output": "2"
},
{
"input": "6",
"output": "-1"
},
{
"input": "100",
"output": "8"
},
{
"input": "33",
"output": "2"
},
{
"input": "23",
"output": "-1"
},
{
"input": "35",
"output": "-1"
},
{
"input": "15",
"output": "2"
},
{
"input": "99",
"output": "2"
},
{
"input": "46",
"output": "4"
},
{
"input": "78",
"output": "4"
},
{
"input": "627",
"output": "2"
},
{
"input": "250",
"output": "5"
},
{
"input": "873",
"output": "18"
},
{
"input": "871",
"output": "-1"
},
{
"input": "684",
"output": "-1"
},
{
"input": "303",
"output": "2"
},
{
"input": "93764",
"output": "-1"
},
{
"input": "39509",
"output": "-1"
},
{
"input": "70878",
"output": "-1"
},
{
"input": "7578",
"output": "3"
},
{
"input": "31893",
"output": "3"
},
{
"input": "57113",
"output": "2"
},
{
"input": "66873",
"output": "2"
},
{
"input": "9564",
"output": "3"
},
{
"input": "42237",
"output": "18"
},
{
"input": "92763",
"output": "22"
},
{
"input": "38798",
"output": "76"
},
{
"input": "63359",
"output": "34"
},
{
"input": "573",
"output": "3"
},
{
"input": "60879",
"output": "2"
},
{
"input": "67341",
"output": "2"
},
{
"input": "15748",
"output": "8"
},
{
"input": "42602",
"output": "17"
},
{
"input": "67817",
"output": "73"
},
{
"input": "81207",
"output": "6"
},
{
"input": "8149",
"output": "2"
},
{
"input": "95298",
"output": "4"
},
{
"input": "41385",
"output": "15"
},
{
"input": "27443",
"output": "2"
},
{
"input": "74424",
"output": "21"
},
{
"input": "35708",
"output": "-1"
},
{
"input": "36655",
"output": "-1"
},
{
"input": "34378",
"output": "-1"
},
{
"input": "63478",
"output": "-1"
},
{
"input": "42863",
"output": "-1"
},
{
"input": "19715",
"output": "-1"
},
{
"input": "37317",
"output": "-1"
},
{
"input": "96992",
"output": "-1"
},
{
"input": "56056",
"output": "-1"
},
{
"input": "45899",
"output": "-1"
},
{
"input": "1",
"output": "-1"
},
{
"input": "100000",
"output": "-1"
},
{
"input": "56",
"output": "-1"
},
{
"input": "38",
"output": "-1"
},
{
"input": "1515",
"output": "2"
}
] | 1,637,387,462
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 3
| 92
| 0
|
def mex(dic):
if len(dic)==0:
return 0
a = set(dic)
b = min(a)
if b>0:
return b-1
else:
for i in a:
if i-b>1:
return b+1
else:
b = i
return max(a)+1
def sums(x):
res = []
for n in range(2,x+1):
if (2*x-(n-1)*n)%(n*2) != 0:
continue
else:
if x//n - (n-1)//2 < 1:
break
res.append((x//n - (n-1)//2, n))
return res
def f(dic, sost):
fmex = []
for a1, n in sums(sost):
res = 0
for j in range(n):
res ^= f(dic, a1 + j) if a1+j not in dic else dic[a1 + j]
fmex.append(res)
m = mex(fmex)
dic[sost] = m
return m
def find_min(dic, sost):
for a1, n in reversed(sums(sost)):
res = 0
for j in range(n):
res ^= dic[a1 + j]
if mex([res])!=0:
return n
d = dict()
sost1 = int(input())
a = f(d, sost1)
print(find_min(d, sost1) if a else -1)
|
Title: Interesting Game
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Two best friends Serozha and Gena play a game.
Initially there is one pile consisting of *n* stones on the table. During one move one pile should be taken and divided into an arbitrary number of piles consisting of *a*1<=><=*a*2<=><=...<=><=*a**k*<=><=0 stones. The piles should meet the condition *a*1<=-<=*a*2<==<=*a*2<=-<=*a*3<==<=...<==<=*a**k*<=-<=1<=-<=*a**k*<==<=1. Naturally, the number of piles *k* should be no less than two.
The friends play in turns. The player who cannot make a move loses. Serozha makes the first move. Who will win if both players play in the optimal way?
Input Specification:
The single line contains a single integer *n* (1<=≤<=*n*<=≤<=105).
Output Specification:
If Serozha wins, print *k*, which represents the minimal number of piles into which he can split the initial one during the first move in order to win the game.
If Gena wins, print "-1" (without the quotes).
Demo Input:
['3\n', '6\n', '100\n']
Demo Output:
['2\n', '-1\n', '8\n']
Note:
none
|
```python
def mex(dic):
if len(dic)==0:
return 0
a = set(dic)
b = min(a)
if b>0:
return b-1
else:
for i in a:
if i-b>1:
return b+1
else:
b = i
return max(a)+1
def sums(x):
res = []
for n in range(2,x+1):
if (2*x-(n-1)*n)%(n*2) != 0:
continue
else:
if x//n - (n-1)//2 < 1:
break
res.append((x//n - (n-1)//2, n))
return res
def f(dic, sost):
fmex = []
for a1, n in sums(sost):
res = 0
for j in range(n):
res ^= f(dic, a1 + j) if a1+j not in dic else dic[a1 + j]
fmex.append(res)
m = mex(fmex)
dic[sost] = m
return m
def find_min(dic, sost):
for a1, n in reversed(sums(sost)):
res = 0
for j in range(n):
res ^= dic[a1 + j]
if mex([res])!=0:
return n
d = dict()
sost1 = int(input())
a = f(d, sost1)
print(find_min(d, sost1) if a else -1)
```
| 0
|
651
|
A
|
Joysticks
|
PROGRAMMING
| 1,100
|
[
"dp",
"greedy",
"implementation",
"math"
] | null | null |
Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if not connected to a charger) or charges by 1 percent (if connected to a charger).
Game continues while both joysticks have a positive charge. Hence, if at the beginning of minute some joystick is charged by 1 percent, it has to be connected to a charger, otherwise the game stops. If some joystick completely discharges (its charge turns to 0), the game also stops.
Determine the maximum number of minutes that game can last. It is prohibited to pause the game, i. e. at each moment both joysticks should be enabled. It is allowed for joystick to be charged by more than 100 percent.
|
The first line of the input contains two positive integers *a*1 and *a*2 (1<=≤<=*a*1,<=*a*2<=≤<=100), the initial charge level of first and second joystick respectively.
|
Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged.
|
[
"3 5\n",
"4 4\n"
] |
[
"6\n",
"5\n"
] |
In the first sample game lasts for 6 minute by using the following algorithm:
- at the beginning of the first minute connect first joystick to the charger, by the end of this minute first joystick is at 4%, second is at 3%; - continue the game without changing charger, by the end of the second minute the first joystick is at 5%, second is at 1%; - at the beginning of the third minute connect second joystick to the charger, after this minute the first joystick is at 3%, the second one is at 2%; - continue the game without changing charger, by the end of the fourth minute first joystick is at 1%, second one is at 3%; - at the beginning of the fifth minute connect first joystick to the charger, after this minute the first joystick is at 2%, the second one is at 1%; - at the beginning of the sixth minute connect second joystick to the charger, after this minute the first joystick is at 0%, the second one is at 2%.
After that the first joystick is completely discharged and the game is stopped.
| 500
|
[
{
"input": "3 5",
"output": "6"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "100 100",
"output": "197"
},
{
"input": "1 100",
"output": "98"
},
{
"input": "100 1",
"output": "98"
},
{
"input": "1 4",
"output": "2"
},
{
"input": "1 1",
"output": "0"
},
{
"input": "8 8",
"output": "13"
},
{
"input": "7 2",
"output": "7"
},
{
"input": "24 15",
"output": "36"
},
{
"input": "19 30",
"output": "47"
},
{
"input": "15 31",
"output": "44"
},
{
"input": "14 15",
"output": "27"
},
{
"input": "58 33",
"output": "89"
},
{
"input": "15 25",
"output": "38"
},
{
"input": "59 45",
"output": "102"
},
{
"input": "3 73",
"output": "74"
},
{
"input": "48 1",
"output": "47"
},
{
"input": "100 25",
"output": "122"
},
{
"input": "40 49",
"output": "86"
},
{
"input": "85 73",
"output": "155"
},
{
"input": "29 1",
"output": "28"
},
{
"input": "74 25",
"output": "97"
},
{
"input": "24 57",
"output": "78"
},
{
"input": "23 12",
"output": "33"
},
{
"input": "2 99",
"output": "99"
},
{
"input": "98 2",
"output": "97"
},
{
"input": "2 97",
"output": "97"
},
{
"input": "30 54",
"output": "81"
},
{
"input": "32 53",
"output": "82"
},
{
"input": "32 54",
"output": "84"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "2 2",
"output": "1"
},
{
"input": "1 3",
"output": "2"
},
{
"input": "3 1",
"output": "2"
},
{
"input": "1 4",
"output": "2"
},
{
"input": "2 3",
"output": "3"
},
{
"input": "3 2",
"output": "3"
}
] | 1,623,387,043
| 2,147,483,647
|
PyPy 3
|
OK
|
TESTS
| 39
| 109
| 0
|
a,b=map(int,input().split());t=0
while a*b>1:
a,b=min(a,b)+1,max(a,b)-2;t+=1
print(t)
|
Title: Joysticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if not connected to a charger) or charges by 1 percent (if connected to a charger).
Game continues while both joysticks have a positive charge. Hence, if at the beginning of minute some joystick is charged by 1 percent, it has to be connected to a charger, otherwise the game stops. If some joystick completely discharges (its charge turns to 0), the game also stops.
Determine the maximum number of minutes that game can last. It is prohibited to pause the game, i. e. at each moment both joysticks should be enabled. It is allowed for joystick to be charged by more than 100 percent.
Input Specification:
The first line of the input contains two positive integers *a*1 and *a*2 (1<=≤<=*a*1,<=*a*2<=≤<=100), the initial charge level of first and second joystick respectively.
Output Specification:
Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged.
Demo Input:
['3 5\n', '4 4\n']
Demo Output:
['6\n', '5\n']
Note:
In the first sample game lasts for 6 minute by using the following algorithm:
- at the beginning of the first minute connect first joystick to the charger, by the end of this minute first joystick is at 4%, second is at 3%; - continue the game without changing charger, by the end of the second minute the first joystick is at 5%, second is at 1%; - at the beginning of the third minute connect second joystick to the charger, after this minute the first joystick is at 3%, the second one is at 2%; - continue the game without changing charger, by the end of the fourth minute first joystick is at 1%, second one is at 3%; - at the beginning of the fifth minute connect first joystick to the charger, after this minute the first joystick is at 2%, the second one is at 1%; - at the beginning of the sixth minute connect second joystick to the charger, after this minute the first joystick is at 0%, the second one is at 2%.
After that the first joystick is completely discharged and the game is stopped.
|
```python
a,b=map(int,input().split());t=0
while a*b>1:
a,b=min(a,b)+1,max(a,b)-2;t+=1
print(t)
```
| 3
|
|
965
|
A
|
Paper Airplanes
|
PROGRAMMING
| 800
|
[
"math"
] | null | null |
To make a paper airplane, one has to use a rectangular piece of paper. From a sheet of standard size you can make $s$ airplanes.
A group of $k$ people decided to make $n$ airplanes each. They are going to buy several packs of paper, each of them containing $p$ sheets, and then distribute the sheets between the people. Each person should have enough sheets to make $n$ airplanes. How many packs should they buy?
|
The only line contains four integers $k$, $n$, $s$, $p$ ($1 \le k, n, s, p \le 10^4$) — the number of people, the number of airplanes each should make, the number of airplanes that can be made using one sheet and the number of sheets in one pack, respectively.
|
Print a single integer — the minimum number of packs they should buy.
|
[
"5 3 2 3\n",
"5 3 100 1\n"
] |
[
"4\n",
"5\n"
] |
In the first sample they have to buy $4$ packs of paper: there will be $12$ sheets in total, and giving $2$ sheets to each person is enough to suit everyone's needs.
In the second sample they have to buy a pack for each person as they can't share sheets.
| 500
|
[
{
"input": "5 3 2 3",
"output": "4"
},
{
"input": "5 3 100 1",
"output": "5"
},
{
"input": "10000 10000 1 1",
"output": "100000000"
},
{
"input": "1 1 10000 10000",
"output": "1"
},
{
"input": "300 300 21 23",
"output": "196"
},
{
"input": "300 2 37 51",
"output": "6"
},
{
"input": "2 400 23 57",
"output": "1"
},
{
"input": "1 1 1 1",
"output": "1"
},
{
"input": "10000 10000 3 2",
"output": "16670000"
},
{
"input": "1 2 1 2",
"output": "1"
},
{
"input": "1 1 2 2",
"output": "1"
},
{
"input": "1 1 10 10",
"output": "1"
},
{
"input": "5324 5439 32 13",
"output": "69622"
},
{
"input": "9000 1 2432 1",
"output": "9000"
},
{
"input": "230 1234 9124 23",
"output": "10"
},
{
"input": "11 1 1 1",
"output": "11"
},
{
"input": "6246 8489 1227 9",
"output": "4858"
},
{
"input": "9 20 5 7",
"output": "6"
}
] | 1,655,921,787
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 18
| 46
| 0
|
[k, n, s, p]=map(int, input().split())
if n%s==0:
sheet=(n/s)
else:
sheet=(n//s)+1
sheet=(n+s-1)//s
ans=sheet*k
ans=(ans+p-1)//p
print(ans)
|
Title: Paper Airplanes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
To make a paper airplane, one has to use a rectangular piece of paper. From a sheet of standard size you can make $s$ airplanes.
A group of $k$ people decided to make $n$ airplanes each. They are going to buy several packs of paper, each of them containing $p$ sheets, and then distribute the sheets between the people. Each person should have enough sheets to make $n$ airplanes. How many packs should they buy?
Input Specification:
The only line contains four integers $k$, $n$, $s$, $p$ ($1 \le k, n, s, p \le 10^4$) — the number of people, the number of airplanes each should make, the number of airplanes that can be made using one sheet and the number of sheets in one pack, respectively.
Output Specification:
Print a single integer — the minimum number of packs they should buy.
Demo Input:
['5 3 2 3\n', '5 3 100 1\n']
Demo Output:
['4\n', '5\n']
Note:
In the first sample they have to buy $4$ packs of paper: there will be $12$ sheets in total, and giving $2$ sheets to each person is enough to suit everyone's needs.
In the second sample they have to buy a pack for each person as they can't share sheets.
|
```python
[k, n, s, p]=map(int, input().split())
if n%s==0:
sheet=(n/s)
else:
sheet=(n//s)+1
sheet=(n+s-1)//s
ans=sheet*k
ans=(ans+p-1)//p
print(ans)
```
| 3
|
|
919
|
B
|
Perfect Number
|
PROGRAMMING
| 1,100
|
[
"binary search",
"brute force",
"dp",
"implementation",
"number theory"
] | null | null |
We consider a positive integer perfect, if and only if the sum of its digits is exactly $10$. Given a positive integer $k$, your task is to find the $k$-th smallest perfect positive integer.
|
A single line with a positive integer $k$ ($1 \leq k \leq 10\,000$).
|
A single number, denoting the $k$-th smallest perfect integer.
|
[
"1\n",
"2\n"
] |
[
"19\n",
"28\n"
] |
The first perfect integer is $19$ and the second one is $28$.
| 750
|
[
{
"input": "1",
"output": "19"
},
{
"input": "2",
"output": "28"
},
{
"input": "13",
"output": "136"
},
{
"input": "101",
"output": "1432"
},
{
"input": "1023",
"output": "100270"
},
{
"input": "9999",
"output": "10800010"
},
{
"input": "10000",
"output": "10800100"
},
{
"input": "2333",
"output": "310060"
},
{
"input": "9139",
"output": "10134010"
},
{
"input": "9859",
"output": "10422001"
},
{
"input": "5987",
"output": "2221201"
},
{
"input": "3",
"output": "37"
},
{
"input": "4",
"output": "46"
},
{
"input": "5",
"output": "55"
},
{
"input": "7",
"output": "73"
},
{
"input": "9",
"output": "91"
},
{
"input": "10",
"output": "109"
},
{
"input": "15",
"output": "154"
},
{
"input": "51",
"output": "613"
},
{
"input": "99",
"output": "1414"
},
{
"input": "138",
"output": "2224"
},
{
"input": "233",
"output": "5050"
},
{
"input": "666",
"output": "27100"
},
{
"input": "1234",
"output": "110206"
},
{
"input": "3567",
"output": "1033003"
},
{
"input": "4445",
"output": "1221301"
},
{
"input": "5689",
"output": "2114002"
},
{
"input": "6666",
"output": "3102004"
},
{
"input": "7777",
"output": "5300200"
},
{
"input": "8888",
"output": "10110061"
},
{
"input": "9411",
"output": "10214200"
},
{
"input": "5539",
"output": "2101114"
},
{
"input": "6259",
"output": "2511100"
},
{
"input": "2387",
"output": "312220"
},
{
"input": "8515",
"output": "10030114"
}
] | 1,623,270,544
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 3
| 77
| 0
|
n=int(input())
dp=1
for i in range(1,n+1):
n1=dp%10
n2=dp//10
#print(n2,n1)
n2+=1
n1-=1
if n1==0: n1=9
#print(n2,n1)
dp=n2*10+n1
print(dp)
|
Title: Perfect Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We consider a positive integer perfect, if and only if the sum of its digits is exactly $10$. Given a positive integer $k$, your task is to find the $k$-th smallest perfect positive integer.
Input Specification:
A single line with a positive integer $k$ ($1 \leq k \leq 10\,000$).
Output Specification:
A single number, denoting the $k$-th smallest perfect integer.
Demo Input:
['1\n', '2\n']
Demo Output:
['19\n', '28\n']
Note:
The first perfect integer is $19$ and the second one is $28$.
|
```python
n=int(input())
dp=1
for i in range(1,n+1):
n1=dp%10
n2=dp//10
#print(n2,n1)
n2+=1
n1-=1
if n1==0: n1=9
#print(n2,n1)
dp=n2*10+n1
print(dp)
```
| 0
|
|
29
|
A
|
Spit Problem
|
PROGRAMMING
| 1,000
|
[
"brute force"
] |
A. Spit Problem
|
2
|
256
|
In a Berland's zoo there is an enclosure with camels. It is known that camels like to spit. Bob watched these interesting animals for the whole day and registered in his notepad where each animal spitted. Now he wants to know if in the zoo there are two camels, which spitted at each other. Help him to solve this task.
The trajectory of a camel's spit is an arc, i.e. if the camel in position *x* spits *d* meters right, he can hit only the camel in position *x*<=+<=*d*, if such a camel exists.
|
The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the amount of camels in the zoo. Each of the following *n* lines contains two integers *x**i* and *d**i* (<=-<=104<=≤<=*x**i*<=≤<=104,<=1<=≤<=|*d**i*|<=≤<=2·104) — records in Bob's notepad. *x**i* is a position of the *i*-th camel, and *d**i* is a distance at which the *i*-th camel spitted. Positive values of *d**i* correspond to the spits right, negative values correspond to the spits left. No two camels may stand in the same position.
|
If there are two camels, which spitted at each other, output YES. Otherwise, output NO.
|
[
"2\n0 1\n1 -1\n",
"3\n0 1\n1 1\n2 -2\n",
"5\n2 -10\n3 10\n0 5\n5 -5\n10 1\n"
] |
[
"YES\n",
"NO\n",
"YES\n"
] |
none
| 500
|
[
{
"input": "2\n0 1\n1 -1",
"output": "YES"
},
{
"input": "3\n0 1\n1 1\n2 -2",
"output": "NO"
},
{
"input": "5\n2 -10\n3 10\n0 5\n5 -5\n10 1",
"output": "YES"
},
{
"input": "10\n-9897 -1144\n-4230 -6350\n2116 -3551\n-3635 4993\n3907 -9071\n-2362 4120\n-6542 984\n5807 3745\n7594 7675\n-5412 -6872",
"output": "NO"
},
{
"input": "11\n-1536 3809\n-2406 -8438\n-1866 395\n5636 -490\n-6867 -7030\n7525 3575\n-6796 2908\n3884 4629\n-2862 -6122\n-8984 6122\n7137 -326",
"output": "YES"
},
{
"input": "12\n-9765 1132\n-1382 -215\n-9405 7284\n-2040 3947\n-9360 3150\n6425 9386\n806 -2278\n-2121 -7284\n5663 -1608\n-8377 9297\n6245 708\n8470 6024",
"output": "YES"
},
{
"input": "15\n8122 -9991\n-4068 -3386\n8971 3731\n3458 5161\n-8700 7562\n2691 8735\n-1510 -3892\n5183 -3753\n-7018 6637\n-7454 3386\n-818 -6377\n6771 -8647\n-7357 -1246\n-6186 1922\n9889 -3627",
"output": "YES"
},
{
"input": "20\n-5264 6424\n-3664 -7459\n-2780 -9859\n-3317 6842\n5681 -8092\n1555 1904\n-6684 1414\n6593 -1253\n-5708 -1202\n335 1733\n-926 7579\n3459 -1904\n-4486 4006\n6201 3616\n2847 -5255\n8438 7057\n8171 6042\n-9102 3545\n7731 -233\n6264 6563",
"output": "YES"
},
{
"input": "30\n-398 -1774\n313 -6974\n2346 -4657\n8552 -9647\n-5265 1538\n8195 4864\n-5641 -5219\n-1394 8563\n-1190 1992\n-4669 -1156\n7574 256\n9206 -2414\n4140 -549\n-294 2169\n7029 -2871\n3808 -9799\n3141 5690\n4648 -2680\n-5990 9800\n-2299 1697\n6077 -7177\n-400 -9724\n-4644 -2392\n-2198 -9531\n-2105 9386\n-8165 -4201\n-1589 -7916\n2518 -7840\n4173 -6949\n-3368 -9943",
"output": "NO"
}
] | 1,674,240,919
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 1
| 62
| 0
|
n = int(input())
ver = []
k = 0
for i in range(n):
x , d = map(int, input().split())
if (x + d) in ver and x in ver:
k += 1
else:
ver.append(x)
ver.append(x+d)
if k != 0:
print('Yes')
else:
print('No')
|
Title: Spit Problem
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
In a Berland's zoo there is an enclosure with camels. It is known that camels like to spit. Bob watched these interesting animals for the whole day and registered in his notepad where each animal spitted. Now he wants to know if in the zoo there are two camels, which spitted at each other. Help him to solve this task.
The trajectory of a camel's spit is an arc, i.e. if the camel in position *x* spits *d* meters right, he can hit only the camel in position *x*<=+<=*d*, if such a camel exists.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the amount of camels in the zoo. Each of the following *n* lines contains two integers *x**i* and *d**i* (<=-<=104<=≤<=*x**i*<=≤<=104,<=1<=≤<=|*d**i*|<=≤<=2·104) — records in Bob's notepad. *x**i* is a position of the *i*-th camel, and *d**i* is a distance at which the *i*-th camel spitted. Positive values of *d**i* correspond to the spits right, negative values correspond to the spits left. No two camels may stand in the same position.
Output Specification:
If there are two camels, which spitted at each other, output YES. Otherwise, output NO.
Demo Input:
['2\n0 1\n1 -1\n', '3\n0 1\n1 1\n2 -2\n', '5\n2 -10\n3 10\n0 5\n5 -5\n10 1\n']
Demo Output:
['YES\n', 'NO\n', 'YES\n']
Note:
none
|
```python
n = int(input())
ver = []
k = 0
for i in range(n):
x , d = map(int, input().split())
if (x + d) in ver and x in ver:
k += 1
else:
ver.append(x)
ver.append(x+d)
if k != 0:
print('Yes')
else:
print('No')
```
| 0
|
705
|
A
|
Hulk
|
PROGRAMMING
| 800
|
[
"implementation"
] | null | null |
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have *n* layers. The first layer is hate, second one is love, third one is hate and so on...
For example if *n*<==<=1, then his feeling is "I hate it" or if *n*<==<=2 it's "I hate that I love it", and if *n*<==<=3 it's "I hate that I love that I hate it" and so on.
Please help Dr. Banner.
|
The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of layers of love and hate.
|
Print Dr.Banner's feeling in one line.
|
[
"1\n",
"2\n",
"3\n"
] |
[
"I hate it\n",
"I hate that I love it\n",
"I hate that I love that I hate it\n"
] |
none
| 500
|
[
{
"input": "1",
"output": "I hate it"
},
{
"input": "2",
"output": "I hate that I love it"
},
{
"input": "3",
"output": "I hate that I love that I hate it"
},
{
"input": "4",
"output": "I hate that I love that I hate that I love it"
},
{
"input": "5",
"output": "I hate that I love that I hate that I love that I hate it"
},
{
"input": "10",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love it"
},
{
"input": "18",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love it"
},
{
"input": "19",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate it"
},
{
"input": "76",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate ..."
},
{
"input": "77",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate ..."
},
{
"input": "81",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate ..."
},
{
"input": "82",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate ..."
},
{
"input": "85",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate ..."
},
{
"input": "86",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate ..."
},
{
"input": "100",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate ..."
},
{
"input": "99",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate ..."
},
{
"input": "98",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate ..."
},
{
"input": "33",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate it"
},
{
"input": "34",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love it"
},
{
"input": "57",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate ..."
},
{
"input": "100",
"output": "I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate that I love that I hate ..."
}
] | 1,695,420,878
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 21
| 46
| 0
|
n = int(input())
speech = 'I '
for i in range(n-1):
if i%2==0:
speech+='hate that I '
else:
speech+='love that I '
print(speech+'hate it' if n%2==1 else speech+'love it')
|
Title: Hulk
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have *n* layers. The first layer is hate, second one is love, third one is hate and so on...
For example if *n*<==<=1, then his feeling is "I hate it" or if *n*<==<=2 it's "I hate that I love it", and if *n*<==<=3 it's "I hate that I love that I hate it" and so on.
Please help Dr. Banner.
Input Specification:
The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of layers of love and hate.
Output Specification:
Print Dr.Banner's feeling in one line.
Demo Input:
['1\n', '2\n', '3\n']
Demo Output:
['I hate it\n', 'I hate that I love it\n', 'I hate that I love that I hate it\n']
Note:
none
|
```python
n = int(input())
speech = 'I '
for i in range(n-1):
if i%2==0:
speech+='hate that I '
else:
speech+='love that I '
print(speech+'hate it' if n%2==1 else speech+'love it')
```
| 3
|
|
158
|
A
|
Next Round
|
PROGRAMMING
| 800
|
[
"*special",
"implementation"
] | null | null |
"Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of *n* participants took part in the contest (*n*<=≥<=*k*), and you already know their scores. Calculate how many participants will advance to the next round.
|
The first line of the input contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50) separated by a single space.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100), where *a**i* is the score earned by the participant who got the *i*-th place. The given sequence is non-increasing (that is, for all *i* from 1 to *n*<=-<=1 the following condition is fulfilled: *a**i*<=≥<=*a**i*<=+<=1).
|
Output the number of participants who advance to the next round.
|
[
"8 5\n10 9 8 7 7 7 5 5\n",
"4 2\n0 0 0 0\n"
] |
[
"6\n",
"0\n"
] |
In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.
In the second example nobody got a positive score.
| 500
|
[
{
"input": "8 5\n10 9 8 7 7 7 5 5",
"output": "6"
},
{
"input": "4 2\n0 0 0 0",
"output": "0"
},
{
"input": "5 1\n1 1 1 1 1",
"output": "5"
},
{
"input": "5 5\n1 1 1 1 1",
"output": "5"
},
{
"input": "1 1\n10",
"output": "1"
},
{
"input": "17 14\n16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0",
"output": "14"
},
{
"input": "5 5\n3 2 1 0 0",
"output": "3"
},
{
"input": "8 6\n10 9 8 7 7 7 5 5",
"output": "6"
},
{
"input": "8 7\n10 9 8 7 7 7 5 5",
"output": "8"
},
{
"input": "8 4\n10 9 8 7 7 7 5 5",
"output": "6"
},
{
"input": "8 3\n10 9 8 7 7 7 5 5",
"output": "3"
},
{
"input": "8 1\n10 9 8 7 7 7 5 5",
"output": "1"
},
{
"input": "8 2\n10 9 8 7 7 7 5 5",
"output": "2"
},
{
"input": "1 1\n100",
"output": "1"
},
{
"input": "1 1\n0",
"output": "0"
},
{
"input": "50 25\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "50"
},
{
"input": "50 25\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "25"
},
{
"input": "50 25\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "26"
},
{
"input": "50 25\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "50"
},
{
"input": "11 5\n100 99 98 97 96 95 94 93 92 91 90",
"output": "5"
},
{
"input": "10 4\n100 81 70 69 64 43 34 29 15 3",
"output": "4"
},
{
"input": "11 6\n87 71 62 52 46 46 43 35 32 25 12",
"output": "6"
},
{
"input": "17 12\n99 88 86 82 75 75 74 65 58 52 45 30 21 16 7 2 2",
"output": "12"
},
{
"input": "20 3\n98 98 96 89 87 82 82 80 76 74 74 68 61 60 43 32 30 22 4 2",
"output": "3"
},
{
"input": "36 12\n90 87 86 85 83 80 79 78 76 70 69 69 61 61 59 58 56 48 45 44 42 41 33 31 27 25 23 21 20 19 15 14 12 7 5 5",
"output": "12"
},
{
"input": "49 8\n99 98 98 96 92 92 90 89 89 86 86 85 83 80 79 76 74 69 67 67 58 56 55 51 49 47 47 46 45 41 41 40 39 34 34 33 25 23 18 15 13 13 11 9 5 4 3 3 1",
"output": "9"
},
{
"input": "49 29\n100 98 98 96 96 96 95 87 85 84 81 76 74 70 63 63 63 62 57 57 56 54 53 52 50 47 45 41 41 39 38 31 30 28 27 26 23 22 20 15 15 11 7 6 6 4 2 1 0",
"output": "29"
},
{
"input": "49 34\n99 98 96 96 93 92 90 89 88 86 85 85 82 76 73 69 66 64 63 63 60 59 57 57 56 55 54 54 51 48 47 44 42 42 40 39 38 36 33 26 24 23 19 17 17 14 12 7 4",
"output": "34"
},
{
"input": "50 44\n100 100 99 97 95 91 91 84 83 83 79 71 70 69 69 62 61 60 59 59 58 58 58 55 55 54 52 48 47 45 44 44 38 36 32 31 28 28 25 25 24 24 24 22 17 15 14 13 12 4",
"output": "44"
},
{
"input": "50 13\n99 95 94 94 88 87 81 79 78 76 74 72 72 69 68 67 67 67 66 63 62 61 58 57 55 55 54 51 50 50 48 48 42 41 38 35 34 32 31 30 26 24 13 13 12 6 5 4 3 3",
"output": "13"
},
{
"input": "50 30\n100 98 96 94 91 89 88 81 81 81 81 81 76 73 72 71 70 69 66 64 61 59 59 56 52 50 49 48 43 39 36 35 34 34 31 29 27 26 24 22 16 16 15 14 14 14 9 7 4 3",
"output": "30"
},
{
"input": "2 1\n10 10",
"output": "2"
},
{
"input": "2 2\n10 10",
"output": "2"
},
{
"input": "2 2\n10 0",
"output": "1"
},
{
"input": "2 2\n10 1",
"output": "2"
},
{
"input": "2 1\n10 0",
"output": "1"
},
{
"input": "2 1\n10 2",
"output": "1"
},
{
"input": "50 13\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0",
"output": "0"
},
{
"input": "50 1\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0",
"output": "0"
},
{
"input": "50 50\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0",
"output": "0"
},
{
"input": "10 1\n5 5 5 3 3 3 0 0 0 0",
"output": "3"
},
{
"input": "10 2\n5 5 5 3 3 3 0 0 0 0",
"output": "3"
},
{
"input": "10 3\n5 5 5 3 3 3 0 0 0 0",
"output": "3"
},
{
"input": "10 4\n5 5 5 3 3 3 0 0 0 0",
"output": "6"
},
{
"input": "10 5\n5 5 5 3 3 3 0 0 0 0",
"output": "6"
},
{
"input": "10 6\n5 5 5 3 3 3 0 0 0 0",
"output": "6"
},
{
"input": "10 7\n5 5 5 3 3 3 0 0 0 0",
"output": "6"
},
{
"input": "10 8\n5 5 5 3 3 3 0 0 0 0",
"output": "6"
},
{
"input": "10 9\n5 5 5 3 3 3 0 0 0 0",
"output": "6"
},
{
"input": "10 10\n5 5 5 3 3 3 0 0 0 0",
"output": "6"
}
] | 1,697,108,524
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 50
| 92
| 0
|
n,k=map(int,input().split())
A=[]
s=0
A=list(map(int,input().split()))
for i in A:
if(i>=A[k-1]):
if(i==0):
continue
else:
s=s+1
print(s)
|
Title: Next Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of *n* participants took part in the contest (*n*<=≥<=*k*), and you already know their scores. Calculate how many participants will advance to the next round.
Input Specification:
The first line of the input contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50) separated by a single space.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100), where *a**i* is the score earned by the participant who got the *i*-th place. The given sequence is non-increasing (that is, for all *i* from 1 to *n*<=-<=1 the following condition is fulfilled: *a**i*<=≥<=*a**i*<=+<=1).
Output Specification:
Output the number of participants who advance to the next round.
Demo Input:
['8 5\n10 9 8 7 7 7 5 5\n', '4 2\n0 0 0 0\n']
Demo Output:
['6\n', '0\n']
Note:
In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.
In the second example nobody got a positive score.
|
```python
n,k=map(int,input().split())
A=[]
s=0
A=list(map(int,input().split()))
for i in A:
if(i>=A[k-1]):
if(i==0):
continue
else:
s=s+1
print(s)
```
| 3
|
|
735
|
A
|
Ostap and Grasshopper
|
PROGRAMMING
| 800
|
[
"implementation",
"strings"
] | null | null |
On the way to Rio de Janeiro Ostap kills time playing with a grasshopper he took with him in a special box. Ostap builds a line of length *n* such that some cells of this line are empty and some contain obstacles. Then, he places his grasshopper to one of the empty cells and a small insect in another empty cell. The grasshopper wants to eat the insect.
Ostap knows that grasshopper is able to jump to any empty cell that is exactly *k* cells away from the current (to the left or to the right). Note that it doesn't matter whether intermediate cells are empty or not as the grasshopper makes a jump over them. For example, if *k*<==<=1 the grasshopper can jump to a neighboring cell only, and if *k*<==<=2 the grasshopper can jump over a single cell.
Your goal is to determine whether there is a sequence of jumps such that grasshopper will get from his initial position to the cell with an insect.
|
The first line of the input contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=*n*<=-<=1) — the number of cells in the line and the length of one grasshopper's jump.
The second line contains a string of length *n* consisting of characters '.', '#', 'G' and 'T'. Character '.' means that the corresponding cell is empty, character '#' means that the corresponding cell contains an obstacle and grasshopper can't jump there. Character 'G' means that the grasshopper starts at this position and, finally, 'T' means that the target insect is located at this cell. It's guaranteed that characters 'G' and 'T' appear in this line exactly once.
|
If there exists a sequence of jumps (each jump of length *k*), such that the grasshopper can get from his initial position to the cell with the insect, print "YES" (without quotes) in the only line of the input. Otherwise, print "NO" (without quotes).
|
[
"5 2\n#G#T#\n",
"6 1\nT....G\n",
"7 3\nT..#..G\n",
"6 2\n..GT..\n"
] |
[
"YES\n",
"YES\n",
"NO\n",
"NO\n"
] |
In the first sample, the grasshopper can make one jump to the right in order to get from cell 2 to cell 4.
In the second sample, the grasshopper is only able to jump to neighboring cells but the way to the insect is free — he can get there by jumping left 5 times.
In the third sample, the grasshopper can't make a single jump.
In the fourth sample, the grasshopper can only jump to the cells with odd indices, thus he won't be able to reach the insect.
| 500
|
[
{
"input": "5 2\n#G#T#",
"output": "YES"
},
{
"input": "6 1\nT....G",
"output": "YES"
},
{
"input": "7 3\nT..#..G",
"output": "NO"
},
{
"input": "6 2\n..GT..",
"output": "NO"
},
{
"input": "2 1\nGT",
"output": "YES"
},
{
"input": "100 5\nG####.####.####.####.####.####.####.####.####.####.####.####.####.####.####.####.####.####.####T####",
"output": "YES"
},
{
"input": "100 5\nG####.####.####.####.####.####.####.####.####.####.####.####.####.#########.####.####.####.####T####",
"output": "NO"
},
{
"input": "2 1\nTG",
"output": "YES"
},
{
"input": "99 1\n...T.............................................................................................G.",
"output": "YES"
},
{
"input": "100 2\nG............#.....#...........#....#...........##............#............#......................T.",
"output": "NO"
},
{
"input": "100 1\n#.#.#.##..#..##.#....##.##.##.#....####..##.#.##..GT..##...###.#.##.#..#..##.###..#.####..#.#.##..##",
"output": "YES"
},
{
"input": "100 2\n..#####.#.#.......#.#.#...##..####..###..#.#######GT####.#.#...##...##.#..###....##.#.#..#.###....#.",
"output": "NO"
},
{
"input": "100 3\nG..................................................................................................T",
"output": "YES"
},
{
"input": "100 3\nG..................................................................................................T",
"output": "YES"
},
{
"input": "100 3\nG..................................#......#......#.......#.#..........#........#......#..........#.T",
"output": "NO"
},
{
"input": "100 3\nG..............#..........#...#..............#.#.....................#......#........#.........#...T",
"output": "NO"
},
{
"input": "100 3\nG##################################################################################################T",
"output": "NO"
},
{
"input": "100 33\nG..................................................................................................T",
"output": "YES"
},
{
"input": "100 33\nG..................................................................................................T",
"output": "YES"
},
{
"input": "100 33\nG.........#........#..........#..............#.................#............................#.#....T",
"output": "YES"
},
{
"input": "100 33\nG.......#..................#..............................#............................#..........T.",
"output": "NO"
},
{
"input": "100 33\nG#..........##...#.#.....................#.#.#.........##..#...........#....#...........##...#..###T",
"output": "YES"
},
{
"input": "100 33\nG..#.#..#..####......#......##...##...#.##........#...#...#.##....###..#...###..##.#.....#......#.T.",
"output": "NO"
},
{
"input": "100 33\nG#....#..#..##.##..#.##.#......#.#.##..##.#.#.##.##....#.#.....####..##...#....##..##..........#...T",
"output": "NO"
},
{
"input": "100 33\nG#######.#..##.##.#...#..#.###.#.##.##.#..#.###..####.##.#.##....####...##..####.#..##.##.##.#....#T",
"output": "NO"
},
{
"input": "100 33\nG#####.#.##.###########.##..##..#######..########..###.###..#.####.######.############..####..#####T",
"output": "NO"
},
{
"input": "100 99\nT..................................................................................................G",
"output": "YES"
},
{
"input": "100 99\nT..................................................................................................G",
"output": "YES"
},
{
"input": "100 99\nT.#...............................#............#..............................##...................G",
"output": "YES"
},
{
"input": "100 99\nT..#....#.##...##########.#.#.#.#...####..#.....#..##..#######.######..#.....###..###...#.......#.#G",
"output": "YES"
},
{
"input": "100 99\nG##################################################################################################T",
"output": "YES"
},
{
"input": "100 9\nT..................................................................................................G",
"output": "YES"
},
{
"input": "100 9\nT.................................................................................................G.",
"output": "NO"
},
{
"input": "100 9\nT................................................................................................G..",
"output": "NO"
},
{
"input": "100 1\nG..................................................................................................T",
"output": "YES"
},
{
"input": "100 1\nT..................................................................................................G",
"output": "YES"
},
{
"input": "100 1\n##########G.........T###############################################################################",
"output": "YES"
},
{
"input": "100 1\n#################################################################################################G.T",
"output": "YES"
},
{
"input": "100 17\n##########G################.################.################.################T#####################",
"output": "YES"
},
{
"input": "100 17\n####.#..#.G######.#########.##..##########.#.################.################T######.####.#########",
"output": "YES"
},
{
"input": "100 17\n.########.G##.####.#.######.###############..#.###########.##.#####.##.#####.#T.###..###.########.##",
"output": "YES"
},
{
"input": "100 1\nG.............................................#....................................................T",
"output": "NO"
},
{
"input": "100 1\nT.#................................................................................................G",
"output": "NO"
},
{
"input": "100 1\n##########G....#....T###############################################################################",
"output": "NO"
},
{
"input": "100 1\n#################################################################################################G#T",
"output": "NO"
},
{
"input": "100 17\nG################.#################################.################T###############################",
"output": "NO"
},
{
"input": "100 17\nG################.###############..###.######.#######.###.#######.##T######################.###.####",
"output": "NO"
},
{
"input": "100 17\nG####.##.##.#####.####....##.####.#########.##.#..#.###############.T############.#########.#.####.#",
"output": "NO"
},
{
"input": "48 1\nT..............................................G",
"output": "YES"
},
{
"input": "23 1\nT.....................G",
"output": "YES"
},
{
"input": "49 1\nG...............................................T",
"output": "YES"
},
{
"input": "3 1\nTG#",
"output": "YES"
},
{
"input": "6 2\n..TG..",
"output": "NO"
},
{
"input": "14 3\n...G.....#..T.",
"output": "NO"
},
{
"input": "5 4\n##GT#",
"output": "NO"
},
{
"input": "6 2\nT#..G.",
"output": "YES"
},
{
"input": "5 2\nT.G.#",
"output": "YES"
},
{
"input": "6 1\nT...G#",
"output": "YES"
},
{
"input": "5 1\nTG###",
"output": "YES"
},
{
"input": "5 4\n.G..T",
"output": "NO"
},
{
"input": "7 2\nT#...#G",
"output": "YES"
},
{
"input": "7 1\n##TG###",
"output": "YES"
},
{
"input": "7 1\n###GT##",
"output": "YES"
},
{
"input": "5 2\nG..T.",
"output": "NO"
},
{
"input": "5 1\nG.T##",
"output": "YES"
},
{
"input": "6 2\nG.T###",
"output": "YES"
},
{
"input": "6 2\nG#T###",
"output": "YES"
},
{
"input": "10 2\n####T..G..",
"output": "NO"
},
{
"input": "3 1\nGT#",
"output": "YES"
},
{
"input": "4 1\nTG##",
"output": "YES"
},
{
"input": "6 1\n.G..T.",
"output": "YES"
},
{
"input": "10 3\n......G..T",
"output": "YES"
},
{
"input": "3 2\nG.T",
"output": "YES"
},
{
"input": "4 1\n#G.T",
"output": "YES"
},
{
"input": "5 2\nT#G##",
"output": "YES"
},
{
"input": "4 2\nG#.T",
"output": "NO"
},
{
"input": "4 1\nGT##",
"output": "YES"
}
] | 1,687,262,016
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 5
| 46
| 0
|
a,b=input().split()
b=int(b)
c=list(input())
de=0
ct=0
for i in range (0,len(c)):
if c[i]=="G":
de=i
if c[i]=="T":
ct=i
checkk=0
cc=de
if cc>ct:
while cc>(ct+b):
cc-=b
if c[cc]=="#":
checkk=1
break
if checkk==0 and (de-ct)%b==0:
print("YES")
else:
print("NO")
else:
while cc<(ct-b):
cc+=b
if c[cc]==".":
checkk=1
break
if checkk==0 and (ct-de)%b==0:
print("YES")
else:
print("NO")
|
Title: Ostap and Grasshopper
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On the way to Rio de Janeiro Ostap kills time playing with a grasshopper he took with him in a special box. Ostap builds a line of length *n* such that some cells of this line are empty and some contain obstacles. Then, he places his grasshopper to one of the empty cells and a small insect in another empty cell. The grasshopper wants to eat the insect.
Ostap knows that grasshopper is able to jump to any empty cell that is exactly *k* cells away from the current (to the left or to the right). Note that it doesn't matter whether intermediate cells are empty or not as the grasshopper makes a jump over them. For example, if *k*<==<=1 the grasshopper can jump to a neighboring cell only, and if *k*<==<=2 the grasshopper can jump over a single cell.
Your goal is to determine whether there is a sequence of jumps such that grasshopper will get from his initial position to the cell with an insect.
Input Specification:
The first line of the input contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=*n*<=-<=1) — the number of cells in the line and the length of one grasshopper's jump.
The second line contains a string of length *n* consisting of characters '.', '#', 'G' and 'T'. Character '.' means that the corresponding cell is empty, character '#' means that the corresponding cell contains an obstacle and grasshopper can't jump there. Character 'G' means that the grasshopper starts at this position and, finally, 'T' means that the target insect is located at this cell. It's guaranteed that characters 'G' and 'T' appear in this line exactly once.
Output Specification:
If there exists a sequence of jumps (each jump of length *k*), such that the grasshopper can get from his initial position to the cell with the insect, print "YES" (without quotes) in the only line of the input. Otherwise, print "NO" (without quotes).
Demo Input:
['5 2\n#G#T#\n', '6 1\nT....G\n', '7 3\nT..#..G\n', '6 2\n..GT..\n']
Demo Output:
['YES\n', 'YES\n', 'NO\n', 'NO\n']
Note:
In the first sample, the grasshopper can make one jump to the right in order to get from cell 2 to cell 4.
In the second sample, the grasshopper is only able to jump to neighboring cells but the way to the insect is free — he can get there by jumping left 5 times.
In the third sample, the grasshopper can't make a single jump.
In the fourth sample, the grasshopper can only jump to the cells with odd indices, thus he won't be able to reach the insect.
|
```python
a,b=input().split()
b=int(b)
c=list(input())
de=0
ct=0
for i in range (0,len(c)):
if c[i]=="G":
de=i
if c[i]=="T":
ct=i
checkk=0
cc=de
if cc>ct:
while cc>(ct+b):
cc-=b
if c[cc]=="#":
checkk=1
break
if checkk==0 and (de-ct)%b==0:
print("YES")
else:
print("NO")
else:
while cc<(ct-b):
cc+=b
if c[cc]==".":
checkk=1
break
if checkk==0 and (ct-de)%b==0:
print("YES")
else:
print("NO")
```
| 0
|
|
799
|
A
|
Carrot Cakes
|
PROGRAMMING
| 1,100
|
[
"brute force",
"implementation"
] | null | null |
In some game by Playrix it takes *t* minutes for an oven to bake *k* carrot cakes, all cakes are ready at the same moment *t* minutes after they started baking. Arkady needs at least *n* cakes to complete a task, but he currently don't have any. However, he has infinitely many ingredients and one oven. Moreover, Arkady can build one more similar oven to make the process faster, it would take *d* minutes to build the oven. While the new oven is being built, only old one can bake cakes, after the new oven is built, both ovens bake simultaneously. Arkady can't build more than one oven.
Determine if it is reasonable to build the second oven, i.e. will it decrease the minimum time needed to get *n* cakes or not. If the time needed with the second oven is the same as with one oven, then it is unreasonable.
|
The only line contains four integers *n*, *t*, *k*, *d* (1<=≤<=*n*,<=*t*,<=*k*,<=*d*<=≤<=1<=000) — the number of cakes needed, the time needed for one oven to bake *k* cakes, the number of cakes baked at the same time, the time needed to build the second oven.
|
If it is reasonable to build the second oven, print "YES". Otherwise print "NO".
|
[
"8 6 4 5\n",
"8 6 4 6\n",
"10 3 11 4\n",
"4 2 1 4\n"
] |
[
"YES\n",
"NO\n",
"NO\n",
"YES\n"
] |
In the first example it is possible to get 8 cakes in 12 minutes using one oven. The second oven can be built in 5 minutes, so after 6 minutes the first oven bakes 4 cakes, the second oven bakes 4 more ovens after 11 minutes. Thus, it is reasonable to build the second oven.
In the second example it doesn't matter whether we build the second oven or not, thus it takes 12 minutes to bake 8 cakes in both cases. Thus, it is unreasonable to build the second oven.
In the third example the first oven bakes 11 cakes in 3 minutes, that is more than needed 10. It is unreasonable to build the second oven, because its building takes more time that baking the needed number of cakes using the only oven.
| 500
|
[
{
"input": "8 6 4 5",
"output": "YES"
},
{
"input": "8 6 4 6",
"output": "NO"
},
{
"input": "10 3 11 4",
"output": "NO"
},
{
"input": "4 2 1 4",
"output": "YES"
},
{
"input": "28 17 16 26",
"output": "NO"
},
{
"input": "60 69 9 438",
"output": "NO"
},
{
"input": "599 97 54 992",
"output": "YES"
},
{
"input": "11 22 18 17",
"output": "NO"
},
{
"input": "1 13 22 11",
"output": "NO"
},
{
"input": "1 1 1 1",
"output": "NO"
},
{
"input": "3 1 1 1",
"output": "YES"
},
{
"input": "1000 1000 1000 1000",
"output": "NO"
},
{
"input": "1000 1000 1 1",
"output": "YES"
},
{
"input": "1000 1000 1 400",
"output": "YES"
},
{
"input": "1000 1000 1 1000",
"output": "YES"
},
{
"input": "1000 1000 1 999",
"output": "YES"
},
{
"input": "53 11 3 166",
"output": "YES"
},
{
"input": "313 2 3 385",
"output": "NO"
},
{
"input": "214 9 9 412",
"output": "NO"
},
{
"input": "349 9 5 268",
"output": "YES"
},
{
"input": "611 16 8 153",
"output": "YES"
},
{
"input": "877 13 3 191",
"output": "YES"
},
{
"input": "340 9 9 10",
"output": "YES"
},
{
"input": "31 8 2 205",
"output": "NO"
},
{
"input": "519 3 2 148",
"output": "YES"
},
{
"input": "882 2 21 219",
"output": "NO"
},
{
"input": "982 13 5 198",
"output": "YES"
},
{
"input": "428 13 6 272",
"output": "YES"
},
{
"input": "436 16 14 26",
"output": "YES"
},
{
"input": "628 10 9 386",
"output": "YES"
},
{
"input": "77 33 18 31",
"output": "YES"
},
{
"input": "527 36 4 8",
"output": "YES"
},
{
"input": "128 18 2 169",
"output": "YES"
},
{
"input": "904 4 2 288",
"output": "YES"
},
{
"input": "986 4 3 25",
"output": "YES"
},
{
"input": "134 8 22 162",
"output": "NO"
},
{
"input": "942 42 3 69",
"output": "YES"
},
{
"input": "894 4 9 4",
"output": "YES"
},
{
"input": "953 8 10 312",
"output": "YES"
},
{
"input": "43 8 1 121",
"output": "YES"
},
{
"input": "12 13 19 273",
"output": "NO"
},
{
"input": "204 45 10 871",
"output": "YES"
},
{
"input": "342 69 50 425",
"output": "NO"
},
{
"input": "982 93 99 875",
"output": "NO"
},
{
"input": "283 21 39 132",
"output": "YES"
},
{
"input": "1000 45 83 686",
"output": "NO"
},
{
"input": "246 69 36 432",
"output": "NO"
},
{
"input": "607 93 76 689",
"output": "NO"
},
{
"input": "503 21 24 435",
"output": "NO"
},
{
"input": "1000 45 65 989",
"output": "NO"
},
{
"input": "30 21 2 250",
"output": "YES"
},
{
"input": "1000 49 50 995",
"output": "NO"
},
{
"input": "383 69 95 253",
"output": "YES"
},
{
"input": "393 98 35 999",
"output": "YES"
},
{
"input": "1000 22 79 552",
"output": "NO"
},
{
"input": "268 294 268 154",
"output": "NO"
},
{
"input": "963 465 706 146",
"output": "YES"
},
{
"input": "304 635 304 257",
"output": "NO"
},
{
"input": "4 2 1 6",
"output": "NO"
},
{
"input": "1 51 10 50",
"output": "NO"
},
{
"input": "5 5 4 4",
"output": "YES"
},
{
"input": "3 2 1 1",
"output": "YES"
},
{
"input": "3 4 3 3",
"output": "NO"
},
{
"input": "7 3 4 1",
"output": "YES"
},
{
"input": "101 10 1 1000",
"output": "NO"
},
{
"input": "5 1 1 1",
"output": "YES"
},
{
"input": "5 10 5 5",
"output": "NO"
},
{
"input": "19 1 7 1",
"output": "YES"
},
{
"input": "763 572 745 262",
"output": "YES"
},
{
"input": "1 2 1 1",
"output": "NO"
},
{
"input": "5 1 1 3",
"output": "YES"
},
{
"input": "170 725 479 359",
"output": "NO"
},
{
"input": "6 2 1 7",
"output": "YES"
},
{
"input": "6 2 5 1",
"output": "YES"
},
{
"input": "1 2 2 1",
"output": "NO"
},
{
"input": "24 2 8 3",
"output": "YES"
},
{
"input": "7 3 3 3",
"output": "YES"
},
{
"input": "5 2 2 2",
"output": "YES"
},
{
"input": "3 2 1 2",
"output": "YES"
},
{
"input": "1000 2 200 8",
"output": "NO"
},
{
"input": "3 100 2 100",
"output": "NO"
},
{
"input": "2 999 1 1000",
"output": "NO"
},
{
"input": "2 1 1 1",
"output": "NO"
},
{
"input": "2 3 5 1",
"output": "NO"
},
{
"input": "100 1 5 1",
"output": "YES"
},
{
"input": "7 2 3 3",
"output": "YES"
},
{
"input": "4 1 1 3",
"output": "NO"
},
{
"input": "3 2 2 1",
"output": "YES"
},
{
"input": "1 1 1 2",
"output": "NO"
},
{
"input": "91 8 7 13",
"output": "YES"
},
{
"input": "3 1 2 1",
"output": "NO"
},
{
"input": "5 3 2 3",
"output": "YES"
},
{
"input": "9 6 6 3",
"output": "YES"
}
] | 1,645,712,545
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 3
| 15
| 0
|
n,t,k,d=list(map(int,input().split(' ',4)))
t1 = int(n/k) *t
t2= (int(n/(2*k))*t)+d
if(t2<t1):print('YES')
else:print('NO')
|
Title: Carrot Cakes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In some game by Playrix it takes *t* minutes for an oven to bake *k* carrot cakes, all cakes are ready at the same moment *t* minutes after they started baking. Arkady needs at least *n* cakes to complete a task, but he currently don't have any. However, he has infinitely many ingredients and one oven. Moreover, Arkady can build one more similar oven to make the process faster, it would take *d* minutes to build the oven. While the new oven is being built, only old one can bake cakes, after the new oven is built, both ovens bake simultaneously. Arkady can't build more than one oven.
Determine if it is reasonable to build the second oven, i.e. will it decrease the minimum time needed to get *n* cakes or not. If the time needed with the second oven is the same as with one oven, then it is unreasonable.
Input Specification:
The only line contains four integers *n*, *t*, *k*, *d* (1<=≤<=*n*,<=*t*,<=*k*,<=*d*<=≤<=1<=000) — the number of cakes needed, the time needed for one oven to bake *k* cakes, the number of cakes baked at the same time, the time needed to build the second oven.
Output Specification:
If it is reasonable to build the second oven, print "YES". Otherwise print "NO".
Demo Input:
['8 6 4 5\n', '8 6 4 6\n', '10 3 11 4\n', '4 2 1 4\n']
Demo Output:
['YES\n', 'NO\n', 'NO\n', 'YES\n']
Note:
In the first example it is possible to get 8 cakes in 12 minutes using one oven. The second oven can be built in 5 minutes, so after 6 minutes the first oven bakes 4 cakes, the second oven bakes 4 more ovens after 11 minutes. Thus, it is reasonable to build the second oven.
In the second example it doesn't matter whether we build the second oven or not, thus it takes 12 minutes to bake 8 cakes in both cases. Thus, it is unreasonable to build the second oven.
In the third example the first oven bakes 11 cakes in 3 minutes, that is more than needed 10. It is unreasonable to build the second oven, because its building takes more time that baking the needed number of cakes using the only oven.
|
```python
n,t,k,d=list(map(int,input().split(' ',4)))
t1 = int(n/k) *t
t2= (int(n/(2*k))*t)+d
if(t2<t1):print('YES')
else:print('NO')
```
| 0
|
|
58
|
E
|
Expression
|
PROGRAMMING
| 2,400
|
[
"dp"
] |
E. Expression
|
2
|
256
|
One day Vasya was solving arithmetical problems. He wrote down an expression *a*<=+<=*b*<==<=*c* in his notebook. When the teacher checked Vasya's work it turned out that Vasya had solved the problem incorrectly. Now Vasya tries to find excuses. He says that he simply forgot to write down several digits in numbers *a*, *b* and *c*, but he can't remember what numbers they actually were. Help Vasya, find such numbers *x*, *y* and *z*, with which the following conditions are met:
- *x*<=+<=*y*<==<=*z*, - from the expression *x*<=+<=*y*<==<=*z* several digits can be erased in such a way that the result will be *a*<=+<=*b*<==<=*c*, - the expression *x*<=+<=*y*<==<=*z* should have the minimal length.
|
The first and only input line contains the expression *a*<=+<=*b*<==<=*c* (1<=≤<=*a*,<=*b*,<=*c*<=≤<=106, *a*, *b* and *c* don't contain leading zeroes) which is the expression Vasya wrote down.
|
Print the correct expression *x*<=+<=*y*<==<=*z* (*x*, *y* and *z* are non-negative numbers without leading zeroes). The expression *a*<=+<=*b*<==<=*c* must be met in *x*<=+<=*y*<==<=*z* as a subsequence. The printed solution should have the minimal possible number of characters. If there are several such solutions, you can print any of them.
|
[
"2+4=5\n",
"1+1=3\n",
"1+1=2\n"
] |
[
"21+4=25\n",
"1+31=32\n",
"1+1=2\n"
] |
none
| 2,500
|
[
{
"input": "2+4=5",
"output": "21+4=25"
},
{
"input": "1+1=3",
"output": "1+31=32"
},
{
"input": "1+1=2",
"output": "1+1=2"
},
{
"input": "323+123=287",
"output": "323+12553=12876"
},
{
"input": "878347+637216=542650",
"output": "847834370+6372160=854206530"
},
{
"input": "123122+765654=975632",
"output": "123192200+76565432=199757632"
},
{
"input": "100+10=96454",
"output": "86100+10354=96454"
},
{
"input": "111111+111111=999999",
"output": "888111111+111888111=999999222"
},
{
"input": "111111+999999=999999",
"output": "111111+999799988=999911099"
},
{
"input": "999999+111111=999999",
"output": "999799988+111111=999911099"
},
{
"input": "999999+999999=999999",
"output": "999999+8999999=9999998"
},
{
"input": "1000000+1000000=1000000",
"output": "10000000+1000000=11000000"
},
{
"input": "105126+379125=440715",
"output": "6105126+37971025=44076151"
},
{
"input": "166755+62051=70160",
"output": "1667550+6234051=7901601"
},
{
"input": "637089+915955=984094",
"output": "6837089+91595005=98432094"
},
{
"input": "615188+948759=924417",
"output": "961518658+948759=962467417"
},
{
"input": "593287+497915=864740",
"output": "51493287+34979153=86472440"
},
{
"input": "87738+530718=805063",
"output": "27877380+53073183=80950563"
},
{
"input": "65837+79874=229034",
"output": "65837160+7091874=72929034"
},
{
"input": "755991+187301=743241",
"output": "70559910+1873031=72432941"
},
{
"input": "417016+849549=39297",
"output": "4170160+849549137=853719297"
},
{
"input": "78042+511798=819002",
"output": "78041020+5117982=83159002"
},
{
"input": "255419+174046=115059",
"output": "2554190+117404869=119959059"
},
{
"input": "916444+352646=894764",
"output": "891264404+3526460=894790864"
},
{
"input": "577470+14895=190821",
"output": "577470+18489351=19066821"
},
{
"input": "754847+677143=486877",
"output": "7154847+67714030=74868877"
},
{
"input": "415873+855744=266582",
"output": "41500873+85157404=126658277"
},
{
"input": "593250+517992=562639",
"output": "593250+561769942=562363192"
},
{
"input": "254275+180240=858696",
"output": "20542725+18044240=38586965"
},
{
"input": "249035+655369=687650",
"output": "2490735+65536915=68027650"
}
] | 1,693,897,323
| 2,147,483,647
|
PyPy 3-64
|
WRONG_ANSWER
|
TESTS
| 23
| 278
| 8,294,400
|
import sys
readline = sys.stdin.readline
def read_input() -> tuple:
s = readline().strip().replace('+','=').replace(' ', '')
return tuple(s.split('='))
def solve(a: str, b: str, c:str):
result = a*100 + b + c + '+' + a + b + c +'=' + a + b + c
def dfs(i:int, j:int, k:int, carry:int, a1:str, b1:str, c1:str): # a1 + b1 = c1, and carries
# i, j, k remain length or a, b, c
nonlocal result
# print(i, j, k, carry, a1, b1, c1)
if len(a1) + len(b1) + len(c1) > len(result):
return
if k == 0:
num1 = int(a[:i] + a1)
num2 = int(b[:j] + b1)
t = str(num1) + '+' + str(num2) + '=' + str(num1 + num2)
# print(i, j, k, carry, a1, b1, c1, t, num1, num2)
if len(t) < len(result):
result = t
return
if i == 0 and j == 0:
num = int(c[:k] + c1)
t = a1 + '+' + str(num - int(a1)) + '=' + str(num)
# print(t, c1)
if len(t) < len(result):
result = t
return
# choice d1, d2
if i > 0 and j > 0:
d1 = int(a[i - 1])
d2 = int(b[j - 1])
d3 = (carry + d1 + d2) % 10
inc3 = int(k > 0 and str(d3) == c[k - 1])
dfs(i - 1, j - 1, k - inc3, (d1 + d2 + carry)//10 , str(d1)+a1, str(d2) + b1, str(d3) +c1)
if i > 0:
d1 = int(a[i - 1])
d3 = int(c[k - 1])
d2 = (d3 - d1 - carry + 10) % 10
inc2 = int(j > 0 and str(d2) == b[j - 1])
dfs(i - 1, j - inc2, k - 1, (d1 + d2 + carry)//10 , str(d1)+a1, str(d2) + b1, str(d3) +c1)
if j > 0:
d2 = int(b[j - 1])
d3 = int(c[k - 1])
d1 = (d3 - d2 - carry + 10) % 10
inc1 = int(i > 0 and str(d1) == a[i - 1])
dfs(i - inc1, j - 1, k - 1, (d1 + d2 + carry)//10 , str(d1)+a1, str(d2) + b1, str(d3) +c1)
# print(f'a={a}, b= {b}, c={c}')
dfs(len(a), len(b), len(c), 0, '', '', '')
return result
def write_output():
pass
print(solve(*read_input()))
write_output()
|
Title: Expression
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya was solving arithmetical problems. He wrote down an expression *a*<=+<=*b*<==<=*c* in his notebook. When the teacher checked Vasya's work it turned out that Vasya had solved the problem incorrectly. Now Vasya tries to find excuses. He says that he simply forgot to write down several digits in numbers *a*, *b* and *c*, but he can't remember what numbers they actually were. Help Vasya, find such numbers *x*, *y* and *z*, with which the following conditions are met:
- *x*<=+<=*y*<==<=*z*, - from the expression *x*<=+<=*y*<==<=*z* several digits can be erased in such a way that the result will be *a*<=+<=*b*<==<=*c*, - the expression *x*<=+<=*y*<==<=*z* should have the minimal length.
Input Specification:
The first and only input line contains the expression *a*<=+<=*b*<==<=*c* (1<=≤<=*a*,<=*b*,<=*c*<=≤<=106, *a*, *b* and *c* don't contain leading zeroes) which is the expression Vasya wrote down.
Output Specification:
Print the correct expression *x*<=+<=*y*<==<=*z* (*x*, *y* and *z* are non-negative numbers without leading zeroes). The expression *a*<=+<=*b*<==<=*c* must be met in *x*<=+<=*y*<==<=*z* as a subsequence. The printed solution should have the minimal possible number of characters. If there are several such solutions, you can print any of them.
Demo Input:
['2+4=5\n', '1+1=3\n', '1+1=2\n']
Demo Output:
['21+4=25\n', '1+31=32\n', '1+1=2\n']
Note:
none
|
```python
import sys
readline = sys.stdin.readline
def read_input() -> tuple:
s = readline().strip().replace('+','=').replace(' ', '')
return tuple(s.split('='))
def solve(a: str, b: str, c:str):
result = a*100 + b + c + '+' + a + b + c +'=' + a + b + c
def dfs(i:int, j:int, k:int, carry:int, a1:str, b1:str, c1:str): # a1 + b1 = c1, and carries
# i, j, k remain length or a, b, c
nonlocal result
# print(i, j, k, carry, a1, b1, c1)
if len(a1) + len(b1) + len(c1) > len(result):
return
if k == 0:
num1 = int(a[:i] + a1)
num2 = int(b[:j] + b1)
t = str(num1) + '+' + str(num2) + '=' + str(num1 + num2)
# print(i, j, k, carry, a1, b1, c1, t, num1, num2)
if len(t) < len(result):
result = t
return
if i == 0 and j == 0:
num = int(c[:k] + c1)
t = a1 + '+' + str(num - int(a1)) + '=' + str(num)
# print(t, c1)
if len(t) < len(result):
result = t
return
# choice d1, d2
if i > 0 and j > 0:
d1 = int(a[i - 1])
d2 = int(b[j - 1])
d3 = (carry + d1 + d2) % 10
inc3 = int(k > 0 and str(d3) == c[k - 1])
dfs(i - 1, j - 1, k - inc3, (d1 + d2 + carry)//10 , str(d1)+a1, str(d2) + b1, str(d3) +c1)
if i > 0:
d1 = int(a[i - 1])
d3 = int(c[k - 1])
d2 = (d3 - d1 - carry + 10) % 10
inc2 = int(j > 0 and str(d2) == b[j - 1])
dfs(i - 1, j - inc2, k - 1, (d1 + d2 + carry)//10 , str(d1)+a1, str(d2) + b1, str(d3) +c1)
if j > 0:
d2 = int(b[j - 1])
d3 = int(c[k - 1])
d1 = (d3 - d2 - carry + 10) % 10
inc1 = int(i > 0 and str(d1) == a[i - 1])
dfs(i - inc1, j - 1, k - 1, (d1 + d2 + carry)//10 , str(d1)+a1, str(d2) + b1, str(d3) +c1)
# print(f'a={a}, b= {b}, c={c}')
dfs(len(a), len(b), len(c), 0, '', '', '')
return result
def write_output():
pass
print(solve(*read_input()))
write_output()
```
| 0
|
652
|
B
|
z-sort
|
PROGRAMMING
| 1,000
|
[
"sortings"
] | null | null |
A student of *z*-school found a kind of sorting called *z*-sort. The array *a* with *n* elements are *z*-sorted if two conditions hold:
1. *a**i*<=≥<=*a**i*<=-<=1 for all even *i*, 1. *a**i*<=≤<=*a**i*<=-<=1 for all odd *i*<=><=1.
For example the arrays [1,2,1,2] and [1,1,1,1] are *z*-sorted while the array [1,2,3,4] isn’t *z*-sorted.
Can you make the array *z*-sorted?
|
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in the array *a*.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of the array *a*.
|
If it's possible to make the array *a* *z*-sorted print *n* space separated integers *a**i* — the elements after *z*-sort. Otherwise print the only word "Impossible".
|
[
"4\n1 2 2 1\n",
"5\n1 3 2 2 5\n"
] |
[
"1 2 1 2\n",
"1 5 2 3 2\n"
] |
none
| 0
|
[
{
"input": "4\n1 2 2 1",
"output": "1 2 1 2"
},
{
"input": "5\n1 3 2 2 5",
"output": "1 5 2 3 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 1 1 1 1 1 1 1 1 1",
"output": "1 1 1 1 1 1 1 1 1 1"
},
{
"input": "10\n1 9 7 6 2 4 7 8 1 3",
"output": "1 9 1 8 2 7 3 7 4 6"
},
{
"input": "100\n82 51 81 14 37 17 78 92 64 15 8 86 89 8 87 77 66 10 15 12 100 25 92 47 21 78 20 63 13 49 41 36 41 79 16 87 87 69 3 76 80 60 100 49 70 59 72 8 38 71 45 97 71 14 76 54 81 4 59 46 39 29 92 3 49 22 53 99 59 52 74 31 92 43 42 23 44 9 82 47 7 40 12 9 3 55 37 85 46 22 84 52 98 41 21 77 63 17 62 91",
"output": "3 100 3 100 3 99 4 98 7 97 8 92 8 92 8 92 9 92 9 91 10 89 12 87 12 87 13 87 14 86 14 85 15 84 15 82 16 82 17 81 17 81 20 80 21 79 21 78 22 78 22 77 23 77 25 76 29 76 31 74 36 72 37 71 37 71 38 70 39 69 40 66 41 64 41 63 41 63 42 62 43 60 44 59 45 59 46 59 46 55 47 54 47 53 49 52 49 52 49 51"
},
{
"input": "3\n1 2 6",
"output": "1 6 2"
},
{
"input": "136\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1"
},
{
"input": "3\n1 2 3",
"output": "1 3 2"
},
{
"input": "7\n999999998 999999999 999999999 999999999 999999999 999999999 1000000000",
"output": "999999998 1000000000 999999999 999999999 999999999 999999999 999999999"
},
{
"input": "3\n100 1 2",
"output": "1 100 2"
}
] | 1,461,306,987
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 1
| 46
| 4,608,000
|
n=int(input())
a=list(map(int,input().split()))
a.sort()
l=len(a)
if l%2==0:
k=l//2
for i in range(k):
print(a[i],a[k+i],sep=' ',end=' ');
else:
k=(l-1)//2;
print(a[0],sep=' ',end=' ');
for i in range(k):
print(a[i+1],a[l-1-i],sep=' ',end=' ');
|
Title: z-sort
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A student of *z*-school found a kind of sorting called *z*-sort. The array *a* with *n* elements are *z*-sorted if two conditions hold:
1. *a**i*<=≥<=*a**i*<=-<=1 for all even *i*, 1. *a**i*<=≤<=*a**i*<=-<=1 for all odd *i*<=><=1.
For example the arrays [1,2,1,2] and [1,1,1,1] are *z*-sorted while the array [1,2,3,4] isn’t *z*-sorted.
Can you make the array *z*-sorted?
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in the array *a*.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of the array *a*.
Output Specification:
If it's possible to make the array *a* *z*-sorted print *n* space separated integers *a**i* — the elements after *z*-sort. Otherwise print the only word "Impossible".
Demo Input:
['4\n1 2 2 1\n', '5\n1 3 2 2 5\n']
Demo Output:
['1 2 1 2\n', '1 5 2 3 2\n']
Note:
none
|
```python
n=int(input())
a=list(map(int,input().split()))
a.sort()
l=len(a)
if l%2==0:
k=l//2
for i in range(k):
print(a[i],a[k+i],sep=' ',end=' ');
else:
k=(l-1)//2;
print(a[0],sep=' ',end=' ');
for i in range(k):
print(a[i+1],a[l-1-i],sep=' ',end=' ');
```
| 0
|
|
245
|
E
|
Mishap in Club
|
PROGRAMMING
| 1,400
|
[
"greedy",
"implementation"
] | null | null |
Polycarpus just has been out of luck lately! As soon as he found a job in the "Binary Cat" cafe, the club got burgled. All ice-cream was stolen.
On the burglary night Polycarpus kept a careful record of all club visitors. Each time a visitor entered the club, Polycarpus put down character "+" in his notes. Similarly, each time a visitor left the club, Polycarpus put character "-" in his notes. We know that all cases of going in and out happened consecutively, that is, no two events happened at the same time. Polycarpus doesn't remember whether there was somebody in the club at the moment when his shift begun and at the moment when it ended.
Right now the police wonders what minimum number of distinct people Polycarpus could have seen. Assume that he sees anybody coming in or out of the club. Each person could have come in or out an arbitrary number of times.
|
The only line of the input contains a sequence of characters "+" and "-", the characters are written one after another without any separators. The characters are written in the order, in which the corresponding events occurred. The given sequence has length from 1 to 300 characters, inclusive.
|
Print the sought minimum number of people
|
[
"+-+-+\n",
"---"
] |
[
"1\n",
"3"
] |
none
| 0
|
[
{
"input": "+-+-+",
"output": "1"
},
{
"input": "---",
"output": "3"
},
{
"input": "-",
"output": "1"
},
{
"input": "--",
"output": "2"
},
{
"input": "---",
"output": "3"
},
{
"input": "----",
"output": "4"
},
{
"input": "---+",
"output": "3"
},
{
"input": "--+-",
"output": "2"
},
{
"input": "--++",
"output": "2"
},
{
"input": "-+--",
"output": "2"
},
{
"input": "-++",
"output": "2"
},
{
"input": "-++-",
"output": "2"
},
{
"input": "+",
"output": "1"
},
{
"input": "+-",
"output": "1"
},
{
"input": "+--",
"output": "2"
},
{
"input": "+--+",
"output": "2"
},
{
"input": "++--",
"output": "2"
},
{
"input": "-+++--+-++--+-+--+-+",
"output": "3"
},
{
"input": "++-++--+++++-+++++---+++-++-++-",
"output": "12"
},
{
"input": "----+-+--++---++---++-+-----+--",
"output": "11"
},
{
"input": "-+++---+++++++++++++-++-++++++-++-+-+++-",
"output": "22"
},
{
"input": "++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++",
"output": "300"
},
{
"input": "------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------",
"output": "300"
},
{
"input": "++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++-+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++",
"output": "298"
},
{
"input": "++++++++++++++++++++-+++++++++++++++++++++++++++++++++++++++++++++++++++++++-+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++",
"output": "296"
},
{
"input": "+++++++++++++++++++++++++++++++++++++++++-++++++++-++++++++++++-+++++++++++++++++++++++++++++++++++++++++++++++++++++-+++++++++++++++++++++++++-++++++++++++++++++++++++-++++-+++++++++++++-++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++-+++-+++++++++++++++++",
"output": "280"
},
{
"input": "++++-+---+++--++++-++-++++++++-++-++++-++++++-+-+-+++--+-++++++-+++-++-+++-++++-++++-+-+----+++++---++++-+---+++--+++++-+++-+-++++++----+--+++++++++-+--+++-+-+-++++++--+-+-+-+-++--+-+-----++++++-+++-++--+++++++++---+-++++++-++-++++-+--+-++-++++-+-+--++-+--+++-+-++++++++++++-+++-+----++++++++--+-+-++",
"output": "100"
},
{
"input": "+----++-----+----+++--++---+++--+-++++-++---++++++--++++--++-++--++--++----++++---+--+++----++--++--++--+--++++++++--++--+++----+++----++----++-+--+---+--+-++--+--+--+-+--+---++-+-++--+++++-++------+++-++--+--+--+++++++--++-+--+-+--++++-++--+---+-+-++-+-++----+-++++++-+++--+----++-+--++-----+++-++-+",
"output": "15"
},
{
"input": "-+++----+-++--+-+----+--+++++----+---+-++-+---+++--+---++-+-----+----+------+--+----++-++-----+++--+---+-+-----++++------+--+-----++---+---+---+-++------++++--+-+-------------+---+--+-+--------++---+-++---+-----+++--+---+-++-+---+-+---+++--++-----++------+----+---+---+--+-+-++-+---++--------+----++",
"output": "103"
},
{
"input": "----------+-----------------------------------------------------------+-+-------------+--------------------------------------------------------------------------------+--+-----+-+-------------------------------------------+-----------------------------------------------------------------+-----------",
"output": "280"
}
] | 1,602,310,347
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 0
| 186
| 0
|
s = input()
a = abs(s.count('+')-s.count('-'))
b = abs(s.count('-')-s.count('+'))
c = s.count('-')
d = s.count('+')
print(max(a,b,c,d))
|
Title: Mishap in Club
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus just has been out of luck lately! As soon as he found a job in the "Binary Cat" cafe, the club got burgled. All ice-cream was stolen.
On the burglary night Polycarpus kept a careful record of all club visitors. Each time a visitor entered the club, Polycarpus put down character "+" in his notes. Similarly, each time a visitor left the club, Polycarpus put character "-" in his notes. We know that all cases of going in and out happened consecutively, that is, no two events happened at the same time. Polycarpus doesn't remember whether there was somebody in the club at the moment when his shift begun and at the moment when it ended.
Right now the police wonders what minimum number of distinct people Polycarpus could have seen. Assume that he sees anybody coming in or out of the club. Each person could have come in or out an arbitrary number of times.
Input Specification:
The only line of the input contains a sequence of characters "+" and "-", the characters are written one after another without any separators. The characters are written in the order, in which the corresponding events occurred. The given sequence has length from 1 to 300 characters, inclusive.
Output Specification:
Print the sought minimum number of people
Demo Input:
['+-+-+\n', '---']
Demo Output:
['1\n', '3']
Note:
none
|
```python
s = input()
a = abs(s.count('+')-s.count('-'))
b = abs(s.count('-')-s.count('+'))
c = s.count('-')
d = s.count('+')
print(max(a,b,c,d))
```
| 0
|
|
888
|
B
|
Buggy Robot
|
PROGRAMMING
| 1,000
|
[
"greedy"
] | null | null |
Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the cell (*x*,<=*y*) to (*x*,<=*y*<=+<=1); - D — move from (*x*,<=*y*) to (*x*,<=*y*<=-<=1); - L — move from (*x*,<=*y*) to (*x*<=-<=1,<=*y*); - R — move from (*x*,<=*y*) to (*x*<=+<=1,<=*y*).
Ivan entered a sequence of *n* commands, and the robot processed it. After this sequence the robot ended up in the starting cell (0,<=0), but Ivan doubts that the sequence is such that after performing it correctly the robot ends up in the same cell. He thinks that some commands were ignored by robot. To acknowledge whether the robot is severely bugged, he needs to calculate the maximum possible number of commands that were performed correctly. Help Ivan to do the calculations!
|
The first line contains one number *n* — the length of sequence of commands entered by Ivan (1<=≤<=*n*<=≤<=100).
The second line contains the sequence itself — a string consisting of *n* characters. Each character can be U, D, L or R.
|
Print the maximum possible number of commands from the sequence the robot could perform to end up in the starting cell.
|
[
"4\nLDUR\n",
"5\nRRRUU\n",
"6\nLLRRRR\n"
] |
[
"4\n",
"0\n",
"4\n"
] |
none
| 0
|
[
{
"input": "4\nLDUR",
"output": "4"
},
{
"input": "5\nRRRUU",
"output": "0"
},
{
"input": "6\nLLRRRR",
"output": "4"
},
{
"input": "88\nLLUUULRDRRURDDLURRLRDRLLRULRUUDDLLLLRRDDURDURRLDURRLDRRRUULDDLRRRDDRRLUULLURDURUDDDDDLDR",
"output": "76"
},
{
"input": "89\nLDLLLDRDUDURRRRRUDULDDDLLUDLRLRLRLDLDUULRDUDLRRDLUDLURRDDRRDLDUDUUURUUUDRLUDUDLURDLDLLDDU",
"output": "80"
},
{
"input": "90\nRRRDUULLLRDUUDDRLDLRLUDURDRDUUURUURDDRRRURLDDDUUDRLLLULURDRDRURLDRRRRUULDULDDLLLRRLRDLLLLR",
"output": "84"
},
{
"input": "91\nRLDRLRRLLDLULULLURULLRRULUDUULLUDULDUULURUDRUDUURDULDUDDUUUDRRUUDLLRULRULURLDRDLDRURLLLRDDD",
"output": "76"
},
{
"input": "92\nRLRDDLULRLLUURRDDDLDDDLDDUURRRULLRDULDULLLUUULDUDLRLRRDRDRDDULDRLUDRDULDRURUDUULLRDRRLLDRLRR",
"output": "86"
},
{
"input": "93\nRLLURLULRURDDLUURLUDDRDLUURLRDLRRRDUULLRDRRLRLDURRDLLRDDLLLDDDLDRRURLLDRUDULDDRRULRRULRLDRDLR",
"output": "84"
},
{
"input": "94\nRDULDDDLULRDRUDRUUDUUDRRRULDRRUDURUULRDUUDLULLLUDURRDRDLUDRULRRRULUURUDDDDDUDLLRDLDRLLRUUURLUL",
"output": "86"
},
{
"input": "95\nRDLUUULLUURDDRLDLLRRRULRLRDULULRULRUDURLULDDDRLURLDRULDUDUUULLRDDURUULULLDDLDRDRLLLURLRDLLDDDDU",
"output": "86"
},
{
"input": "96\nRDDRLRLLDDULRLRURUDLRLDUDRURLLUUDLLURDLRRUURDRRUDRURLLDLLRDURDURLRLUDURULLLRDUURULUUULRRURRDLURL",
"output": "84"
},
{
"input": "97\nRURDDLRLLRULUDURDLRLLUUDURRLLUDLLLDUDRUULDRUUURURULRDLDRRLLUUUDLLLDDLLLLRLLDUDRRDLLUDLRURUDULRLUR",
"output": "82"
},
{
"input": "98\nRUDURLULLDDLLRDLLRDDLLLLRLDDDDRRRDDRRURLDRLLRUUUDLUUUDDDUDRUURLURUUDUUDRULRRULLRRLRULLULDLUURLULRD",
"output": "92"
},
{
"input": "99\nRRULLDULRRDRULLDUDRUDDDRLLUUDRDDUDURLDDRUUDRRUUURRRURDDLDUURDLRLURRDDLUDDLUDURDRUDDURLURURLRUDRURLD",
"output": "86"
},
{
"input": "100\nUDRLRRLLRRLRRRDDLLDDDLULLDDLURUURUULUDDDRDDLLRDLLUURLRDRLRRLRLLLULDUDDUURRLRDULDRDURRRRRRULDRRDLDRRL",
"output": "88"
},
{
"input": "1\nU",
"output": "0"
},
{
"input": "5\nUUULD",
"output": "2"
},
{
"input": "1\nD",
"output": "0"
},
{
"input": "5\nURLUL",
"output": "2"
},
{
"input": "5\nDDDRU",
"output": "2"
},
{
"input": "2\nLR",
"output": "2"
},
{
"input": "8\nDDRDLDUR",
"output": "4"
},
{
"input": "6\nLLLLUD",
"output": "2"
},
{
"input": "13\nRRRLLLLLLLLLL",
"output": "6"
}
] | 1,593,435,543
| 2,147,483,647
|
PyPy 3
|
WRONG_ANSWER
|
TESTS
| 3
| 140
| 20,172,800
|
n=int(input())
arr=list(input())
m=0
u=1
d=-1
l=2
r=-2
count=0
temp=0
for i in arr:
#print(count)
if count==0:
#print("hii here i am zero")
m=max(m,temp)
if i=='U':
count+=1
temp+=1
elif i=='D':
count-=1
temp+=1
elif i=='L':
count+=2
temp+=1
elif i=='R':
temp+=1
count-=2
if count==0:
m=max(m,temp)
print(m)
|
Title: Buggy Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the cell (*x*,<=*y*) to (*x*,<=*y*<=+<=1); - D — move from (*x*,<=*y*) to (*x*,<=*y*<=-<=1); - L — move from (*x*,<=*y*) to (*x*<=-<=1,<=*y*); - R — move from (*x*,<=*y*) to (*x*<=+<=1,<=*y*).
Ivan entered a sequence of *n* commands, and the robot processed it. After this sequence the robot ended up in the starting cell (0,<=0), but Ivan doubts that the sequence is such that after performing it correctly the robot ends up in the same cell. He thinks that some commands were ignored by robot. To acknowledge whether the robot is severely bugged, he needs to calculate the maximum possible number of commands that were performed correctly. Help Ivan to do the calculations!
Input Specification:
The first line contains one number *n* — the length of sequence of commands entered by Ivan (1<=≤<=*n*<=≤<=100).
The second line contains the sequence itself — a string consisting of *n* characters. Each character can be U, D, L or R.
Output Specification:
Print the maximum possible number of commands from the sequence the robot could perform to end up in the starting cell.
Demo Input:
['4\nLDUR\n', '5\nRRRUU\n', '6\nLLRRRR\n']
Demo Output:
['4\n', '0\n', '4\n']
Note:
none
|
```python
n=int(input())
arr=list(input())
m=0
u=1
d=-1
l=2
r=-2
count=0
temp=0
for i in arr:
#print(count)
if count==0:
#print("hii here i am zero")
m=max(m,temp)
if i=='U':
count+=1
temp+=1
elif i=='D':
count-=1
temp+=1
elif i=='L':
count+=2
temp+=1
elif i=='R':
temp+=1
count-=2
if count==0:
m=max(m,temp)
print(m)
```
| 0
|
|
155
|
A
|
I_love_\%username\%
|
PROGRAMMING
| 800
|
[
"brute force"
] | null | null |
Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For each contest where this coder participated, he wrote out a single non-negative number — the number of points his favorite coder earned in the contest. Vasya wrote out the points for the contest in the order, in which the contests run (naturally, no two contests ran simultaneously).
Vasya considers a coder's performance in a contest amazing in two situations: he can break either his best or his worst performance record. First, it is amazing if during the contest the coder earns strictly more points that he earned on each past contest. Second, it is amazing if during the contest the coder earns strictly less points that he earned on each past contest. A coder's first contest isn't considered amazing. Now he wants to count the number of amazing performances the coder had throughout his whole history of participating in contests. But the list of earned points turned out long and Vasya can't code... That's why he asks you to help him.
|
The first line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of contests where the coder participated.
The next line contains *n* space-separated non-negative integer numbers — they are the points which the coder has earned. The points are given in the chronological order. All points do not exceed 10000.
|
Print the single number — the number of amazing performances the coder has had during his whole history of participating in the contests.
|
[
"5\n100 50 200 150 200\n",
"10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242\n"
] |
[
"2\n",
"4\n"
] |
In the first sample the performances number 2 and 3 are amazing.
In the second sample the performances number 2, 4, 9 and 10 are amazing.
| 500
|
[
{
"input": "5\n100 50 200 150 200",
"output": "2"
},
{
"input": "10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242",
"output": "4"
},
{
"input": "1\n6",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "5\n100 36 53 7 81",
"output": "2"
},
{
"input": "5\n7 36 53 81 100",
"output": "4"
},
{
"input": "5\n100 81 53 36 7",
"output": "4"
},
{
"input": "10\n8 6 3 4 9 10 7 7 1 3",
"output": "5"
},
{
"input": "10\n1627 1675 1488 1390 1812 1137 1746 1324 1952 1862",
"output": "6"
},
{
"input": "10\n1 3 3 4 6 7 7 8 9 10",
"output": "7"
},
{
"input": "10\n1952 1862 1812 1746 1675 1627 1488 1390 1324 1137",
"output": "9"
},
{
"input": "25\n1448 4549 2310 2725 2091 3509 1565 2475 2232 3989 4231 779 2967 2702 608 3739 721 1552 2767 530 3114 665 1940 48 4198",
"output": "5"
},
{
"input": "33\n1097 1132 1091 1104 1049 1038 1023 1080 1104 1029 1035 1061 1049 1060 1088 1106 1105 1087 1063 1076 1054 1103 1047 1041 1028 1120 1126 1063 1117 1110 1044 1093 1101",
"output": "5"
},
{
"input": "34\n821 5536 2491 6074 7216 9885 764 1603 778 8736 8987 771 617 1587 8943 7922 439 7367 4115 8886 7878 6899 8811 5752 3184 3401 9760 9400 8995 4681 1323 6637 6554 6498",
"output": "7"
},
{
"input": "68\n6764 6877 6950 6768 6839 6755 6726 6778 6699 6805 6777 6985 6821 6801 6791 6805 6940 6761 6677 6999 6911 6699 6959 6933 6903 6843 6972 6717 6997 6756 6789 6668 6735 6852 6735 6880 6723 6834 6810 6694 6780 6679 6698 6857 6826 6896 6979 6968 6957 6988 6960 6700 6919 6892 6984 6685 6813 6678 6715 6857 6976 6902 6780 6686 6777 6686 6842 6679",
"output": "9"
},
{
"input": "60\n9000 9014 9034 9081 9131 9162 9174 9199 9202 9220 9221 9223 9229 9235 9251 9260 9268 9269 9270 9298 9307 9309 9313 9323 9386 9399 9407 9495 9497 9529 9531 9544 9614 9615 9627 9627 9643 9654 9656 9657 9685 9699 9701 9736 9745 9758 9799 9827 9843 9845 9854 9854 9885 9891 9896 9913 9942 9963 9986 9992",
"output": "57"
},
{
"input": "100\n7 61 12 52 41 16 34 99 30 44 48 89 31 54 21 1 48 52 61 15 35 87 21 76 64 92 44 81 16 93 84 92 32 15 68 76 53 39 26 4 11 26 7 4 99 99 61 65 55 85 65 67 47 39 2 74 63 49 98 87 5 94 22 30 25 42 31 84 49 23 89 60 16 26 92 27 9 57 75 61 94 35 83 47 99 100 63 24 91 88 79 10 15 45 22 64 3 11 89 83",
"output": "4"
},
{
"input": "100\n9999 9999 9999 9998 9998 9998 9997 9996 9996 9995 9993 9993 9991 9990 9989 9986 9984 9984 9983 9981 9981 9980 9980 9980 9979 9977 9977 9977 9977 9977 9976 9976 9975 9975 9973 9972 9972 9972 9972 9971 9969 9969 9969 9968 9967 9965 9962 9962 9962 9962 9960 9958 9958 9955 9954 9954 9954 9954 9950 9949 9949 9947 9943 9943 9940 9940 9939 9937 9937 9937 9936 9935 9932 9932 9931 9929 9927 9927 9926 9923 9919 9919 9918 9918 9918 9917 9917 9916 9916 9915 9914 9911 9910 9907 9907 9906 9905 9905 9904 9901",
"output": "57"
},
{
"input": "100\n158 159 157 156 155 154 160 153 161 152 162 163 151 164 150 165 149 148 147 166 146 167 145 144 143 142 168 141 169 170 140 139 138 137 171 136 135 134 172 173 174 133 175 132 177 178 131 179 180 130 129 181 128 127 182 126 183 125 124 184 123 122 121 120 119 118 117 185 186 187 188 189 116 190 115 191 192 193 114 113 112 111 110 109 108 194 195 107 106 105 196 197 104 198 199 103 102 200 101 100",
"output": "99"
},
{
"input": "2\n0 10000",
"output": "1"
},
{
"input": "2\n5 5",
"output": "0"
},
{
"input": "2\n1 1",
"output": "0"
},
{
"input": "2\n10 10",
"output": "0"
},
{
"input": "1\n0",
"output": "0"
}
] | 1,691,399,801
| 2,147,483,647
|
PyPy 3-64
|
OK
|
TESTS
| 37
| 124
| 0
|
n=int(input())
x=list(map(int,input().split(" ")))
a=x[0]
b=x[0]
count=0
for i in range(1,len(x)):
if x[i]>a:
a=x[i]
count+=1
elif x[i]<b:
b=x[i]
count+=1
print(count)
|
Title: I_love_\%username\%
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For each contest where this coder participated, he wrote out a single non-negative number — the number of points his favorite coder earned in the contest. Vasya wrote out the points for the contest in the order, in which the contests run (naturally, no two contests ran simultaneously).
Vasya considers a coder's performance in a contest amazing in two situations: he can break either his best or his worst performance record. First, it is amazing if during the contest the coder earns strictly more points that he earned on each past contest. Second, it is amazing if during the contest the coder earns strictly less points that he earned on each past contest. A coder's first contest isn't considered amazing. Now he wants to count the number of amazing performances the coder had throughout his whole history of participating in contests. But the list of earned points turned out long and Vasya can't code... That's why he asks you to help him.
Input Specification:
The first line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of contests where the coder participated.
The next line contains *n* space-separated non-negative integer numbers — they are the points which the coder has earned. The points are given in the chronological order. All points do not exceed 10000.
Output Specification:
Print the single number — the number of amazing performances the coder has had during his whole history of participating in the contests.
Demo Input:
['5\n100 50 200 150 200\n', '10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242\n']
Demo Output:
['2\n', '4\n']
Note:
In the first sample the performances number 2 and 3 are amazing.
In the second sample the performances number 2, 4, 9 and 10 are amazing.
|
```python
n=int(input())
x=list(map(int,input().split(" ")))
a=x[0]
b=x[0]
count=0
for i in range(1,len(x)):
if x[i]>a:
a=x[i]
count+=1
elif x[i]<b:
b=x[i]
count+=1
print(count)
```
| 3
|
|
551
|
A
|
GukiZ and Contest
|
PROGRAMMING
| 800
|
[
"brute force",
"implementation",
"sortings"
] | null | null |
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote the rating of *i*-th student as *a**i*. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to . In particular, if student *A* has rating strictly lower then student *B*, *A* will get the strictly better position than *B*, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
|
The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*).
|
In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input.
|
[
"3\n1 3 3\n",
"1\n1\n",
"5\n3 5 3 4 5\n"
] |
[
"3 1 1\n",
"1\n",
"4 1 4 3 1\n"
] |
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position.
| 500
|
[
{
"input": "3\n1 3 3",
"output": "3 1 1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n3 5 3 4 5",
"output": "4 1 4 3 1"
},
{
"input": "7\n1 3 5 4 2 2 1",
"output": "6 3 1 2 4 4 6"
},
{
"input": "11\n5 6 4 2 9 7 6 6 6 6 7",
"output": "9 4 10 11 1 2 4 4 4 4 2"
},
{
"input": "1\n2000",
"output": "1"
},
{
"input": "2\n2000 2000",
"output": "1 1"
},
{
"input": "3\n500 501 502",
"output": "3 2 1"
},
{
"input": "10\n105 106 1 1 1 11 1000 999 1000 999",
"output": "6 5 8 8 8 7 1 3 1 3"
},
{
"input": "6\n1 2 3 4 5 6",
"output": "6 5 4 3 2 1"
},
{
"input": "7\n6 5 4 3 2 1 1",
"output": "1 2 3 4 5 6 6"
},
{
"input": "8\n153 100 87 14 10 8 6 5",
"output": "1 2 3 4 5 6 7 8"
},
{
"input": "70\n11 54 37 62 1 46 13 17 38 47 28 15 63 5 61 34 49 66 32 59 3 41 58 28 23 62 41 64 20 5 14 41 10 37 51 32 65 46 61 8 15 19 16 44 31 42 19 46 66 25 26 58 60 5 19 18 69 53 20 40 45 27 24 41 32 23 57 56 62 10",
"output": "62 18 35 7 70 23 61 56 34 22 42 58 6 66 10 37 21 2 38 13 69 29 14 42 48 7 29 5 50 66 60 29 63 35 20 38 4 23 10 65 58 52 57 27 41 28 52 23 2 46 45 14 12 66 52 55 1 19 50 33 26 44 47 29 38 48 16 17 7 63"
},
{
"input": "5\n1 2000 1 1 2000",
"output": "3 1 3 3 1"
}
] | 1,434,288,279
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 36
| 171
| 307,200
|
n = int (input())
arr = [int(x) for x in input().split()]
sorted_list = list(arr)
out = []
sorted_list.sort()
for i in range(0,n):
count = sorted_list.count(arr[i])
indx = sorted_list.index(arr[i])
out.append( n - count - indx + 1)
print(' '.join(repr(e) for e in out))
|
Title: GukiZ and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote the rating of *i*-th student as *a**i*. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to . In particular, if student *A* has rating strictly lower then student *B*, *A* will get the strictly better position than *B*, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*).
Output Specification:
In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input.
Demo Input:
['3\n1 3 3\n', '1\n1\n', '5\n3 5 3 4 5\n']
Demo Output:
['3 1 1\n', '1\n', '4 1 4 3 1\n']
Note:
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position.
|
```python
n = int (input())
arr = [int(x) for x in input().split()]
sorted_list = list(arr)
out = []
sorted_list.sort()
for i in range(0,n):
count = sorted_list.count(arr[i])
indx = sorted_list.index(arr[i])
out.append( n - count - indx + 1)
print(' '.join(repr(e) for e in out))
```
| 3
|
|
0
|
none
|
none
|
none
| 0
|
[
"none"
] | null | null |
Little Artem found a grasshopper. He brought it to his house and constructed a jumping area for him.
The area looks like a strip of cells 1<=×<=*n*. Each cell contains the direction for the next jump and the length of that jump. Grasshopper starts in the first cell and follows the instructions written on the cells. Grasshopper stops immediately if it jumps out of the strip. Now Artem wants to find out if this will ever happen.
|
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — length of the strip.
Next line contains a string of length *n* which consists of characters "<" and ">" only, that provide the direction of the jump from the corresponding cell. Next line contains *n* integers *d**i* (1<=≤<=*d**i*<=≤<=109) — the length of the jump from the *i*-th cell.
|
Print "INFINITE" (without quotes) if grasshopper will continue his jumps forever. Otherwise print "FINITE" (without quotes).
|
[
"2\n><\n1 2\n",
"3\n>><\n2 1 1\n"
] |
[
"FINITE\n",
"INFINITE"
] |
In the first sample grasshopper starts from the first cell and jumps to the right on the next cell. When he is in the second cell he needs to jump two cells left so he will jump out of the strip.
Second sample grasshopper path is 1 - 3 - 2 - 3 - 2 - 3 and so on. The path is infinite.
| 0
|
[
{
"input": "2\n><\n1 2",
"output": "FINITE"
},
{
"input": "3\n>><\n2 1 1",
"output": "INFINITE"
},
{
"input": "1\n>\n1000000000",
"output": "FINITE"
},
{
"input": "1\n<\n1000000000",
"output": "FINITE"
},
{
"input": "2\n>>\n1 1",
"output": "FINITE"
},
{
"input": "5\n>><><\n1 2 3 1 2",
"output": "FINITE"
},
{
"input": "5\n>><><\n1 2 2 1 2",
"output": "INFINITE"
},
{
"input": "10\n>>>>>>>>><\n1 1 1 1 1 1 1 1 1 10",
"output": "FINITE"
},
{
"input": "10\n>>>>>>>>><\n1 1 1 1 1 1 1 1 1 5",
"output": "INFINITE"
},
{
"input": "10\n>>>>>>>>><\n1 1 1 1 1 1 1 1 1 1",
"output": "INFINITE"
},
{
"input": "3\n><<\n2 1 1",
"output": "INFINITE"
},
{
"input": "10\n>>>>>>>>>>\n1 1 1 1 1 1 1 1 1 100",
"output": "FINITE"
},
{
"input": "3\n><<\n2 100 2",
"output": "INFINITE"
},
{
"input": "3\n><<\n2 3 2",
"output": "INFINITE"
},
{
"input": "3\n>><\n2 3 2",
"output": "INFINITE"
},
{
"input": "3\n><>\n1 1 1",
"output": "INFINITE"
},
{
"input": "3\n>><\n2 2 2",
"output": "INFINITE"
},
{
"input": "4\n>><<\n2 100 2 100",
"output": "INFINITE"
},
{
"input": "3\n><>\n1 1 3",
"output": "INFINITE"
},
{
"input": "5\n><>>>\n1 1 10 10 10",
"output": "INFINITE"
},
{
"input": "5\n><<<<\n500 1 2 3 4",
"output": "FINITE"
},
{
"input": "4\n><><\n2 1000 1 1",
"output": "INFINITE"
},
{
"input": "3\n><<\n2 10 2",
"output": "INFINITE"
},
{
"input": "3\n><<\n2 5 2",
"output": "INFINITE"
},
{
"input": "2\n><\n5 5",
"output": "FINITE"
},
{
"input": "3\n>><\n1 10 10",
"output": "FINITE"
},
{
"input": "4\n><<>\n2 1 1 5",
"output": "INFINITE"
},
{
"input": "5\n<<>>>\n1 1 1 1 1",
"output": "FINITE"
},
{
"input": "3\n><>\n1 1 12345",
"output": "INFINITE"
},
{
"input": "4\n>>><\n3 2 2 3",
"output": "INFINITE"
},
{
"input": "3\n><>\n1 1 100000",
"output": "INFINITE"
}
] | 1,594,472,614
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 60
| 202
| 14,540,800
|
ans = 0
n = int(input())
S = list(input())
l = list(map(int , input().split()))
for i in range(n+1):
if S[ans] =='>':
ans += l[ans]
else :
ans-=l[ans]
if ans not in range(n):
print('FINITE')
break
else:
print('INFINITE')
|
Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem found a grasshopper. He brought it to his house and constructed a jumping area for him.
The area looks like a strip of cells 1<=×<=*n*. Each cell contains the direction for the next jump and the length of that jump. Grasshopper starts in the first cell and follows the instructions written on the cells. Grasshopper stops immediately if it jumps out of the strip. Now Artem wants to find out if this will ever happen.
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — length of the strip.
Next line contains a string of length *n* which consists of characters "<" and ">" only, that provide the direction of the jump from the corresponding cell. Next line contains *n* integers *d**i* (1<=≤<=*d**i*<=≤<=109) — the length of the jump from the *i*-th cell.
Output Specification:
Print "INFINITE" (without quotes) if grasshopper will continue his jumps forever. Otherwise print "FINITE" (without quotes).
Demo Input:
['2\n><\n1 2\n', '3\n>><\n2 1 1\n']
Demo Output:
['FINITE\n', 'INFINITE']
Note:
In the first sample grasshopper starts from the first cell and jumps to the right on the next cell. When he is in the second cell he needs to jump two cells left so he will jump out of the strip.
Second sample grasshopper path is 1 - 3 - 2 - 3 - 2 - 3 and so on. The path is infinite.
|
```python
ans = 0
n = int(input())
S = list(input())
l = list(map(int , input().split()))
for i in range(n+1):
if S[ans] =='>':
ans += l[ans]
else :
ans-=l[ans]
if ans not in range(n):
print('FINITE')
break
else:
print('INFINITE')
```
| 3
|
|
460
|
A
|
Vasya and Socks
|
PROGRAMMING
| 900
|
[
"brute force",
"implementation",
"math"
] | null | null |
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it late in the evening, so that Vasya cannot put on a new pair of socks before the next day. How many consecutive days pass until Vasya runs out of socks?
|
The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space.
|
Print a single integer — the answer to the problem.
|
[
"2 2\n",
"9 3\n"
] |
[
"3\n",
"13\n"
] |
In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on the third, sixth and ninth days. Than he spends another day wearing the socks that were bought on the twelfth day.
| 500
|
[
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"output": "19"
},
{
"input": "10 9",
"output": "11"
},
{
"input": "100 100",
"output": "101"
},
{
"input": "2 27",
"output": "2"
},
{
"input": "99 100",
"output": "99"
},
{
"input": "99 2",
"output": "197"
},
{
"input": "100 3",
"output": "149"
},
{
"input": "98 3",
"output": "146"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "100 2",
"output": "199"
},
{
"input": "62 4",
"output": "82"
},
{
"input": "99 10",
"output": "109"
},
{
"input": "100 5",
"output": "124"
},
{
"input": "80 80",
"output": "81"
},
{
"input": "95 16",
"output": "101"
},
{
"input": "75 16",
"output": "79"
},
{
"input": "99 74",
"output": "100"
},
{
"input": "20 21",
"output": "20"
},
{
"input": "52 96",
"output": "52"
},
{
"input": "24 5",
"output": "29"
}
] | 1,639,142,616
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 26
| 62
| 0
|
n, m = map(int, input().split())
days = 0
step = 0
while n != 0:
step += 1
if step == m:
n += 1
step = 0
n -= 1
days += 1
print(days)
|
Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it late in the evening, so that Vasya cannot put on a new pair of socks before the next day. How many consecutive days pass until Vasya runs out of socks?
Input Specification:
The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space.
Output Specification:
Print a single integer — the answer to the problem.
Demo Input:
['2 2\n', '9 3\n']
Demo Output:
['3\n', '13\n']
Note:
In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on the third, sixth and ninth days. Than he spends another day wearing the socks that were bought on the twelfth day.
|
```python
n, m = map(int, input().split())
days = 0
step = 0
while n != 0:
step += 1
if step == m:
n += 1
step = 0
n -= 1
days += 1
print(days)
```
| 3
|
|
801
|
B
|
Valued Keys
|
PROGRAMMING
| 900
|
[
"constructive algorithms",
"greedy",
"strings"
] | null | null |
You found a mysterious function *f*. The function takes two strings *s*1 and *s*2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function *f* is another string of the same length. The *i*-th character of the output is equal to the minimum of the *i*-th character of *s*1 and the *i*-th character of *s*2.
For example, *f*("ab", "ba") = "aa", and *f*("nzwzl", "zizez") = "niwel".
You found two strings *x* and *y* of the same length and consisting of only lowercase English letters. Find any string *z* such that *f*(*x*,<=*z*)<==<=*y*, or print -1 if no such string *z* exists.
|
The first line of input contains the string *x*.
The second line of input contains the string *y*.
Both *x* and *y* consist only of lowercase English letters, *x* and *y* have same length and this length is between 1 and 100.
|
If there is no string *z* such that *f*(*x*,<=*z*)<==<=*y*, print -1.
Otherwise, print a string *z* such that *f*(*x*,<=*z*)<==<=*y*. If there are multiple possible answers, print any of them. The string *z* should be the same length as *x* and *y* and consist only of lowercase English letters.
|
[
"ab\naa\n",
"nzwzl\nniwel\n",
"ab\nba\n"
] |
[
"ba\n",
"xiyez\n",
"-1\n"
] |
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no *z* such that *f*("ab", *z*) = "ba".
| 1,000
|
[
{
"input": "ab\naa",
"output": "ba"
},
{
"input": "nzwzl\nniwel",
"output": "xiyez"
},
{
"input": "ab\nba",
"output": "-1"
},
{
"input": "r\nl",
"output": "l"
},
{
"input": "d\ny",
"output": "-1"
},
{
"input": "yvowz\ncajav",
"output": "cajav"
},
{
"input": "lwzjp\ninjit",
"output": "-1"
},
{
"input": "epqnlxmiicdidyscjaxqznwur\neodnlemiicdedmkcgavqbnqmm",
"output": "eodnlemiicdedmkcgavqbnqmm"
},
{
"input": "qqdabbsxiibnnjgsgxllfvdqj\nuxmypqtwfdezewdxfgplannrs",
"output": "-1"
},
{
"input": "aanerbaqslfmqmuciqbxyznkevukvznpkmxlcorpmrenwxhzfgbmlfpxtkqpxdrmcqcmbf\naanebbaqkgfiimcciqbaoznkeqqkrgapdillccrfeienwbcvfgbmlfbimkqchcrmclcmbf",
"output": "aanebbaqkgfiimcciqbaoznkeqqkrgapdillccrfeienwbcvfgbmlfbimkqchcrmclcmbf"
},
{
"input": "mbyrkhjctrcrayisflptgfudwgrtegidhqicsjqafvdloritbjhciyxuwavxknezwwudnk\nvvixsutlbdewqoabqhpuerfkzrddcqptfwmxdlxwbvsaqfjoxztlddvwgflcteqbwaiaen",
"output": "-1"
},
{
"input": "eufycwztywhbjrpqobvknwfqmnboqcfdiahkagykeibbsqpljcghhmsgfmswwsanzyiwtvuirwmppfivtekaywkzskyydfvkjgxb\necfwavookadbcilfobojnweqinbcpcfdiahkabwkeibbacpljcghhksgfajgmianfnivmhfifogpffiheegayfkxkkcmdfvihgdb",
"output": "ecfwavookadbcilfobojnweqinbcpcfdiahkabwkeibbacpljcghhksgfajgmianfnivmhfifogpffiheegayfkxkkcmdfvihgdb"
},
{
"input": "qvpltcffyeghtbdhjyhfteojezyzziardduzrbwuxmzzkkoehfnxecafizxglboauhynfbawlfxenmykquyhrxswhjuovvogntok\nchvkcvzxptbcepdjfezcpuvtehewbnvqeoezlcnzhpfwujbmhafoeqmjhtwisnobauinkzyigrvahpuetkgpdjfgbzficsmuqnym",
"output": "-1"
},
{
"input": "nmuwjdihouqrnsuahimssnrbxdpwvxiyqtenahtrlshjkmnfuttnpqhgcagoptinnaptxaccptparldzrhpgbyrzedghudtsswxi\nnilhbdghosqnbebafimconrbvdodjsipqmekahhrllhjkemeketapfhgcagopfidnahtlaccpfpafedqicpcbvfgedghudhddwib",
"output": "nilhbdghosqnbebafimconrbvdodjsipqmekahhrllhjkemeketapfhgcagopfidnahtlaccpfpafedqicpcbvfgedghudhddwib"
},
{
"input": "dyxgwupoauwqtcfoyfjdotzirwztdfrueqiypxoqvkmhiehdppwtdoxrbfvtairdbuvlqohjflznggjpifhwjrshcrfbjtklpykx\ngzqlnoizhxolnditjdhlhptjsbczehicudoybzilwnshmywozwnwuipcgirgzldtvtowdsokfeafggwserzdazkxyddjttiopeew",
"output": "-1"
},
{
"input": "hbgwuqzougqzlxemvyjpeizjfwhgugrfnhbrlxkmkdalikfyunppwgdzmalbwewybnjzqsohwhjkdcyhhzmysflambvhpsjilsyv\nfbdjdqjojdafarakvcjpeipjfehgfgrfehbolxkmkdagikflunnpvadocalbkedibhbflmohnhjkdcthhaigsfjaibqhbcjelirv",
"output": "fbdjdqjojdafarakvcjpeipjfehgfgrfehbolxkmkdagikflunnpvadocalbkedibhbflmohnhjkdcthhaigsfjaibqhbcjelirv"
},
{
"input": "xnjjhjfuhgyxqhpzmvgbaohqarugdoaczcfecofltwemieyxolswkcwhlfagfrgmoiqrgftokbqwtxgxzweozzlikrvafiabivlk\npjfosalbsitcnqiazhmepfifjxvmazvdgffcnozmnqubhonwjldmpdsjagmamniylzjdbklcyrzivjyzgnogahobpkwpwpvraqns",
"output": "-1"
},
{
"input": "zrvzedssbsrfldqvjpgmsefrmsatspzoitwvymahiptphiystjlsauzquzqqbmljobdhijcpdvatorwmyojqgnezvzlgjibxepcf\npesoedmqbmffldqsjggmhefkadaesijointrkmahapaahiysfjdiaupqujngbjhjobdhiecadeatgjvelojjgnepvajgeibfepaf",
"output": "pesoedmqbmffldqsjggmhefkadaesijointrkmahapaahiysfjdiaupqujngbjhjobdhiecadeatgjvelojjgnepvajgeibfepaf"
},
{
"input": "pdvkuwyzntzfqpblzmbynknyhlnqbxijuqaincviugxohcsrofozrrsategwkbwxcvkyzxhurokefpbdnmcfogfhsojayysqbrow\nbvxruombdrywlcjkrltyayaazwpauuhbtgwfzdrmfwwucgffucwelzvpsdgtapogchblzahsrfymjlaghkbmbssghrpxalkslcvp",
"output": "-1"
},
{
"input": "tgharsjyihroiiahwgbjezlxvlterxivdhtzjcqegzmtigqmrehvhiyjeywegxaseoyoacouijudbiruoghgxvxadwzgdxtnxlds\ntghaksjsdhkoiiahegbjexlfrctercipdhmvjbgegxdtggqdpbhvhiseehhegnaseoooacnsijubbirjnghgsvpadhaadrtimfdp",
"output": "tghaksjsdhkoiiahegbjexlfrctercipdhmvjbgegxdtggqdpbhvhiseehhegnaseoooacnsijubbirjnghgsvpadhaadrtimfdp"
},
{
"input": "jsinejpfwhzloulxndzvzftgogfdagrsscxmatldssqsgaknnbkcvhptebjjpkjhrjegrotzwcdosezkedzxeoyibmyzunkguoqj\nkfmvybobocdpipiripysioruqvloopvbggpjksgmwzyqwyxnesmvhsawnbbmntulspvsysfkjqwpvoelliopbaukyagedextzoej",
"output": "-1"
},
{
"input": "nttdcfceptruiomtmwzestrfchnqpgqeztpcvthzelfyggjgqadylzubpvbrlgndrcsursczpxlnoyoadxezncqalupfzmjeqihe\nkttdcfceohrjiaahmoldanpfchnfpgheqpdahqhxecfpbgigqadrkjubjfbrlgndbcgcgmcjpeleinaadretncqaiqpfkmjeqihe",
"output": "kttdcfceohrjiaahmoldanpfchnfpgheqpdahqhxecfpbgigqadrkjubjfbrlgndbcgcgmcjpeleinaadretncqaiqpfkmjeqihe"
},
{
"input": "diuopwglduasnaxgduwslbzoyayoypzznqspljcyqehweydhlwifcvnjmaowuvyqfwynjghecqvxdvuquuwpvwrjljozocaxnktv\ntrdydprdzmjhgbhzytelrfjpgsebijicsigmwhynmcyjtqrvojcndodchzxfcvyqjxqzwibccdvsjqhsnectdjyrrhzkeamukang",
"output": "-1"
},
{
"input": "ftfr\nftfr",
"output": "ftfr"
},
{
"input": "ftr\nftr",
"output": "ftr"
},
{
"input": "shftr\nshftr",
"output": "shftr"
},
{
"input": "vkvkkv\nvkvkkv",
"output": "vkvkkv"
},
{
"input": "ftrd\nftrd",
"output": "ftrd"
},
{
"input": "fztr\nfztr",
"output": "fztr"
},
{
"input": "frtr\nfrtr",
"output": "frtr"
},
{
"input": "shdftr\nshdftr",
"output": "shdftr"
},
{
"input": "zzz\nzzz",
"output": "zzz"
},
{
"input": "shtr\nshtr",
"output": "shtr"
},
{
"input": "aaaaa\nzzzzz",
"output": "-1"
},
{
"input": "efr\nefr",
"output": "efr"
}
] | 1,540,302,722
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 0
| 93
| 0
|
x=input()
z=input()
f='YES'
x1=''
for i in range (len (x)):
if ord(z[i])>ord(x[i]):
f="NO"
break
else:
x1+=x[i]
if f=='YES':
print(x)
else:
print(-1)
|
Title: Valued Keys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You found a mysterious function *f*. The function takes two strings *s*1 and *s*2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function *f* is another string of the same length. The *i*-th character of the output is equal to the minimum of the *i*-th character of *s*1 and the *i*-th character of *s*2.
For example, *f*("ab", "ba") = "aa", and *f*("nzwzl", "zizez") = "niwel".
You found two strings *x* and *y* of the same length and consisting of only lowercase English letters. Find any string *z* such that *f*(*x*,<=*z*)<==<=*y*, or print -1 if no such string *z* exists.
Input Specification:
The first line of input contains the string *x*.
The second line of input contains the string *y*.
Both *x* and *y* consist only of lowercase English letters, *x* and *y* have same length and this length is between 1 and 100.
Output Specification:
If there is no string *z* such that *f*(*x*,<=*z*)<==<=*y*, print -1.
Otherwise, print a string *z* such that *f*(*x*,<=*z*)<==<=*y*. If there are multiple possible answers, print any of them. The string *z* should be the same length as *x* and *y* and consist only of lowercase English letters.
Demo Input:
['ab\naa\n', 'nzwzl\nniwel\n', 'ab\nba\n']
Demo Output:
['ba\n', 'xiyez\n', '-1\n']
Note:
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no *z* such that *f*("ab", *z*) = "ba".
|
```python
x=input()
z=input()
f='YES'
x1=''
for i in range (len (x)):
if ord(z[i])>ord(x[i]):
f="NO"
break
else:
x1+=x[i]
if f=='YES':
print(x)
else:
print(-1)
```
| 0
|
|
938
|
A
|
Word Correction
|
PROGRAMMING
| 800
|
[
"implementation"
] | null | null |
Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird and it needs to be replaced. So the word corrector works in such a way: as long as there are two consecutive vowels in the word, it deletes the first vowel in a word such that there is another vowel right before it. If there are no two consecutive vowels in the word, it is considered to be correct.
You are given a word *s*. Can you predict what will it become after correction?
In this problem letters a, e, i, o, u and y are considered to be vowels.
|
The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of letters in word *s* before the correction.
The second line contains a string *s* consisting of exactly *n* lowercase Latin letters — the word before the correction.
|
Output the word *s* after the correction.
|
[
"5\nweird\n",
"4\nword\n",
"5\naaeaa\n"
] |
[
"werd\n",
"word\n",
"a\n"
] |
Explanations of the examples:
1. There is only one replace: weird <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> werd;1. No replace needed since there are no two consecutive vowels;1. aaeaa <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> aeaa <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> aaa <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> aa <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> a.
| 0
|
[
{
"input": "5\nweird",
"output": "werd"
},
{
"input": "4\nword",
"output": "word"
},
{
"input": "5\naaeaa",
"output": "a"
},
{
"input": "100\naaaaabbbbboyoyoyoyoyacadabbbbbiuiufgiuiuaahjabbbklboyoyoyoyoyaaaaabbbbbiuiuiuiuiuaaaaabbbbbeyiyuyzyw",
"output": "abbbbbocadabbbbbifgihjabbbklbobbbbbibbbbbezyw"
},
{
"input": "69\nbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb",
"output": "bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb"
},
{
"input": "12\nmmmmmmmmmmmm",
"output": "mmmmmmmmmmmm"
},
{
"input": "18\nyaywptqwuyiqypwoyw",
"output": "ywptqwuqypwow"
},
{
"input": "85\nbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb",
"output": "bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb"
},
{
"input": "13\nmmmmmmmmmmmmm",
"output": "mmmmmmmmmmmmm"
},
{
"input": "10\nmmmmmmmmmm",
"output": "mmmmmmmmmm"
},
{
"input": "11\nmmmmmmmmmmm",
"output": "mmmmmmmmmmm"
},
{
"input": "15\nmmmmmmmmmmmmmmm",
"output": "mmmmmmmmmmmmmmm"
},
{
"input": "1\na",
"output": "a"
},
{
"input": "14\nmmmmmmmmmmmmmm",
"output": "mmmmmmmmmmmmmm"
},
{
"input": "33\nmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm",
"output": "mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm"
},
{
"input": "79\nbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb",
"output": "bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb"
},
{
"input": "90\nbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb",
"output": "bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb"
},
{
"input": "2\naa",
"output": "a"
},
{
"input": "18\niuiuqpyyaoaetiwliu",
"output": "iqpytiwli"
},
{
"input": "5\nxxxxx",
"output": "xxxxx"
},
{
"input": "6\nxxxahg",
"output": "xxxahg"
},
{
"input": "3\nzcv",
"output": "zcv"
},
{
"input": "4\naepo",
"output": "apo"
},
{
"input": "5\nqqqqq",
"output": "qqqqq"
},
{
"input": "6\naaaaaa",
"output": "a"
},
{
"input": "4\naeta",
"output": "ata"
},
{
"input": "20\nttyttlwaoieulyiluuri",
"output": "ttyttlwalyluri"
},
{
"input": "1\nb",
"output": "b"
},
{
"input": "3\nanc",
"output": "anc"
},
{
"input": "1\ne",
"output": "e"
},
{
"input": "3\naie",
"output": "a"
},
{
"input": "3\nvio",
"output": "vi"
},
{
"input": "2\nea",
"output": "e"
},
{
"input": "3\nuas",
"output": "us"
},
{
"input": "2\nba",
"output": "ba"
},
{
"input": "2\naq",
"output": "aq"
},
{
"input": "2\nya",
"output": "y"
},
{
"input": "2\nou",
"output": "o"
},
{
"input": "2\nbb",
"output": "bb"
},
{
"input": "7\nayylmao",
"output": "alma"
},
{
"input": "2\nab",
"output": "ab"
},
{
"input": "19\nyuouiyaoiiweqrryqqp",
"output": "yweqrryqqp"
},
{
"input": "25\niqypwqpriiioetiuqqqttouei",
"output": "iqypwqpritiqqqtto"
},
{
"input": "100\naaaaabbbbboyoyoyoyoyacadabbbbbiuiufgiuiuaahjabbbklboyoyoyoyoyaaaaabbbbbiuiuiuiuiuaaaaabbbbbeyiyuyzyz",
"output": "abbbbbocadabbbbbifgihjabbbklbobbbbbibbbbbezyz"
},
{
"input": "17\naccccccccccccccca",
"output": "accccccccccccccca"
},
{
"input": "5\nababa",
"output": "ababa"
},
{
"input": "10\naaaaaaaaaa",
"output": "a"
},
{
"input": "22\naaaaabbbbboyoyoyoyoyac",
"output": "abbbbboc"
},
{
"input": "7\nmahmoud",
"output": "mahmod"
}
] | 1,606,038,661
| 2,147,483,647
|
Python 3
|
RUNTIME_ERROR
|
TESTS
| 0
| 78
| 204,800
|
t = int (input())
s = list(input())
f = []
for i in range (len(s)-1):
if len(f) ==0 and s[i] in list(["a", "e", "i", "o", "u", "y"]):
f.append(s[i])
elif s[i] not in ["a", "e", "i", "o", "u", "y"] and f[-1] not in ["a", "e", "i", "o", "u", "y"] :
f.append(s[i])
elif s[i] in ["a", "e", "i", "o", "u", "y"] and f[-1] in ["a", "e", "i", "o", "u", "y"] :
pass
print("".join(f))
|
Title: Word Correction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird and it needs to be replaced. So the word corrector works in such a way: as long as there are two consecutive vowels in the word, it deletes the first vowel in a word such that there is another vowel right before it. If there are no two consecutive vowels in the word, it is considered to be correct.
You are given a word *s*. Can you predict what will it become after correction?
In this problem letters a, e, i, o, u and y are considered to be vowels.
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of letters in word *s* before the correction.
The second line contains a string *s* consisting of exactly *n* lowercase Latin letters — the word before the correction.
Output Specification:
Output the word *s* after the correction.
Demo Input:
['5\nweird\n', '4\nword\n', '5\naaeaa\n']
Demo Output:
['werd\n', 'word\n', 'a\n']
Note:
Explanations of the examples:
1. There is only one replace: weird <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> werd;1. No replace needed since there are no two consecutive vowels;1. aaeaa <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> aeaa <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> aaa <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> aa <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> a.
|
```python
t = int (input())
s = list(input())
f = []
for i in range (len(s)-1):
if len(f) ==0 and s[i] in list(["a", "e", "i", "o", "u", "y"]):
f.append(s[i])
elif s[i] not in ["a", "e", "i", "o", "u", "y"] and f[-1] not in ["a", "e", "i", "o", "u", "y"] :
f.append(s[i])
elif s[i] in ["a", "e", "i", "o", "u", "y"] and f[-1] in ["a", "e", "i", "o", "u", "y"] :
pass
print("".join(f))
```
| -1
|
|
315
|
A
|
Sereja and Bottles
|
PROGRAMMING
| 1,400
|
[
"brute force"
] | null | null |
Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th bottle is from brand *a**i*, besides, you can use it to open other bottles of brand *b**i*. You can use one bottle to open multiple other bottles. Sereja can open bottle with opened bottle or closed bottle.
Knowing this, Sereja wants to find out the number of bottles they've got that they won't be able to open in any way. Help him and find this number.
|
The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles. The next *n* lines contain the bottles' description. The *i*-th line contains two integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the description of the *i*-th bottle.
|
In a single line print a single integer — the answer to the problem.
|
[
"4\n1 1\n2 2\n3 3\n4 4\n",
"4\n1 2\n2 3\n3 4\n4 1\n"
] |
[
"4\n",
"0\n"
] |
none
| 500
|
[
{
"input": "4\n1 1\n2 2\n3 3\n4 4",
"output": "4"
},
{
"input": "4\n1 2\n2 3\n3 4\n4 1",
"output": "0"
},
{
"input": "3\n2 828\n4 392\n4 903",
"output": "3"
},
{
"input": "4\n2 3\n1 772\n3 870\n3 668",
"output": "2"
},
{
"input": "5\n1 4\n6 6\n4 3\n3 4\n4 758",
"output": "2"
},
{
"input": "6\n4 843\n2 107\n10 943\n9 649\n7 806\n6 730",
"output": "6"
},
{
"input": "7\n351 955\n7 841\n102 377\n394 102\n549 440\n630 324\n624 624",
"output": "6"
},
{
"input": "8\n83 978\n930 674\n542 22\n834 116\n116 271\n640 930\n659 930\n705 987",
"output": "6"
},
{
"input": "9\n162 942\n637 967\n356 108\n768 53\n656 656\n575 32\n32 575\n53 53\n351 222",
"output": "6"
},
{
"input": "10\n423 360\n947 538\n507 484\n31 947\n414 351\n169 901\n901 21\n592 22\n763 200\n656 485",
"output": "8"
},
{
"input": "1\n1000 1000",
"output": "1"
},
{
"input": "1\n500 1000",
"output": "1"
},
{
"input": "11\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n7 7\n8 8\n9 9\n10 10\n11 11",
"output": "11"
},
{
"input": "49\n1 758\n5 3\n5 3\n4 2\n4 36\n3 843\n5 107\n1 943\n1 649\n2 806\n3 730\n2 351\n2 102\n1 4\n3 4\n3 955\n2 841\n2 377\n5 2\n3 440\n4 324\n3 3\n3 83\n2 2\n2 1\n4 1\n1 931\n3 4\n2 5\n2 5\n4 73\n5 830\n3 4\n3 5\n5 291\n1 2\n5 3\n4 4\n2 3\n3 151\n4 2\n4 431\n5 1\n2 5\n2 4\n4 2\n4 4\n3 1\n5 2",
"output": "0"
},
{
"input": "50\n507 31\n31 250\n414 763\n169 304\n901 9\n592 610\n763 414\n656 789\n411 422\n360 468\n625 504\n538 201\n549 619\n484 797\n596 282\n42 310\n603 656\n351 623\n292 293\n837 180\n375 658\n21 192\n597 729\n22 512\n349 635\n200 56\n669 647\n485 887\n282 939\n735 808\n54 417\n1000 310\n419 652\n939 617\n901 669\n789 390\n128 549\n468 511\n729 837\n894 729\n649 894\n484 22\n808 586\n422 286\n311 427\n618 656\n814 933\n515 901\n310 894\n617 330",
"output": "30"
},
{
"input": "2\n7 7\n5 359",
"output": "2"
},
{
"input": "2\n465 706\n706 706",
"output": "1"
},
{
"input": "2\n1 1\n1 1",
"output": "0"
},
{
"input": "3\n1 1\n1 1\n2 2",
"output": "1"
},
{
"input": "5\n1 1\n1 2\n2 3\n3 4\n4 3",
"output": "1"
},
{
"input": "3\n1 2\n1 2\n1 1",
"output": "1"
}
] | 1,656,899,450
| 2,147,483,647
|
PyPy 3-64
|
RUNTIME_ERROR
|
TESTS
| 2
| 404
| 3,174,400
|
import sys
input = sys.stdin.readline
n = int(input())
v = [0] * (n + 1)
c = 0
for i in range(n):
a, b = map(int, input().split())
if(a == b):
if(not v[a]):
c += 1
v[b] = 1
print(c)
|
Title: Sereja and Bottles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th bottle is from brand *a**i*, besides, you can use it to open other bottles of brand *b**i*. You can use one bottle to open multiple other bottles. Sereja can open bottle with opened bottle or closed bottle.
Knowing this, Sereja wants to find out the number of bottles they've got that they won't be able to open in any way. Help him and find this number.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles. The next *n* lines contain the bottles' description. The *i*-th line contains two integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the description of the *i*-th bottle.
Output Specification:
In a single line print a single integer — the answer to the problem.
Demo Input:
['4\n1 1\n2 2\n3 3\n4 4\n', '4\n1 2\n2 3\n3 4\n4 1\n']
Demo Output:
['4\n', '0\n']
Note:
none
|
```python
import sys
input = sys.stdin.readline
n = int(input())
v = [0] * (n + 1)
c = 0
for i in range(n):
a, b = map(int, input().split())
if(a == b):
if(not v[a]):
c += 1
v[b] = 1
print(c)
```
| -1
|
|
357
|
B
|
Flag Day
|
PROGRAMMING
| 1,400
|
[
"constructive algorithms",
"implementation"
] | null | null |
In Berland, there is the national holiday coming — the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions:
- overall, there must be *m* dances;- exactly three people must take part in each dance;- each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland).
The agency has *n* dancers, and their number can be less than 3*m*. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance.
You considered all the criteria and made the plan for the *m* dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the *n* dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances.
|
The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=105) and *m* (1<=≤<=*m*<=≤<=105) — the number of dancers and the number of dances, correspondingly. Then *m* lines follow, describing the dances in the order of dancing them. The *i*-th line contains three distinct integers — the numbers of the dancers that take part in the *i*-th dance. The dancers are numbered from 1 to *n*. Each dancer takes part in at least one dance.
|
Print *n* space-separated integers: the *i*-th number must represent the color of the *i*-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists.
|
[
"7 3\n1 2 3\n1 4 5\n4 6 7\n",
"9 3\n3 6 9\n2 5 8\n1 4 7\n",
"5 2\n4 1 5\n3 1 2\n"
] |
[
"1 2 3 3 2 2 1 \n",
"1 1 1 2 2 2 3 3 3 \n",
"2 3 1 1 3 \n"
] |
none
| 1,000
|
[
{
"input": "7 3\n1 2 3\n1 4 5\n4 6 7",
"output": "1 2 3 3 2 2 1 "
},
{
"input": "9 3\n3 6 9\n2 5 8\n1 4 7",
"output": "1 1 1 2 2 2 3 3 3 "
},
{
"input": "5 2\n4 1 5\n3 1 2",
"output": "2 3 1 1 3 "
},
{
"input": "14 5\n1 5 3\n13 10 11\n6 3 8\n14 9 2\n7 4 12",
"output": "1 3 3 2 2 2 1 1 2 2 3 3 1 1 "
},
{
"input": "14 6\n14 3 13\n10 14 5\n6 2 10\n7 13 9\n12 11 8\n1 4 9",
"output": "2 2 2 3 2 1 2 3 1 3 2 1 3 1 "
},
{
"input": "14 6\n11 13 10\n3 10 14\n2 7 12\n13 1 9\n5 11 4\n8 6 5",
"output": "1 1 2 2 3 2 2 1 3 3 1 3 2 1 "
},
{
"input": "13 5\n13 6 2\n13 3 8\n11 4 7\n10 9 5\n1 12 6",
"output": "3 3 3 2 3 2 3 2 2 1 1 1 1 "
},
{
"input": "14 6\n5 4 8\n5 7 12\n3 6 12\n7 11 14\n10 13 2\n10 1 9",
"output": "3 3 3 2 1 1 3 3 2 1 2 2 2 1 "
},
{
"input": "14 5\n4 13 2\n7 2 11\n6 1 5\n14 12 8\n10 3 9",
"output": "2 3 2 1 3 1 2 3 3 1 1 2 2 1 "
},
{
"input": "14 6\n2 14 5\n3 4 5\n6 13 14\n7 13 12\n8 10 11\n9 6 1",
"output": "1 1 1 2 3 3 3 1 2 2 3 2 1 2 "
},
{
"input": "14 6\n7 14 12\n6 1 12\n13 5 2\n2 3 9\n7 4 11\n5 8 10",
"output": "2 3 2 3 2 1 1 1 1 3 2 3 1 2 "
},
{
"input": "13 6\n8 7 6\n11 7 3\n13 9 3\n12 1 13\n8 10 4\n2 7 5",
"output": "3 1 3 2 3 3 2 1 2 3 1 2 1 "
},
{
"input": "13 5\n8 4 3\n1 9 5\n6 2 11\n12 10 4\n7 10 13",
"output": "1 2 3 2 3 1 3 1 2 1 3 3 2 "
},
{
"input": "20 8\n16 19 12\n13 3 5\n1 5 17\n10 19 7\n8 18 2\n3 11 14\n9 20 12\n4 15 6",
"output": "2 3 2 1 3 3 3 1 1 1 1 3 1 3 2 1 1 2 2 2 "
},
{
"input": "19 7\n10 18 14\n5 9 11\n9 17 7\n3 15 4\n6 8 12\n1 2 18\n13 16 19",
"output": "3 1 1 3 1 1 3 2 2 1 3 3 1 3 2 2 1 2 3 "
},
{
"input": "18 7\n17 4 13\n7 1 6\n16 9 13\n9 2 5\n11 12 17\n14 8 10\n3 15 18",
"output": "2 1 1 2 3 3 1 2 2 3 2 3 3 1 2 1 1 3 "
},
{
"input": "20 7\n8 5 11\n3 19 20\n16 1 17\n9 6 2\n7 18 13\n14 12 18\n10 4 15",
"output": "2 3 1 2 2 2 1 1 1 1 3 1 3 3 3 1 3 2 2 3 "
},
{
"input": "20 7\n6 11 20\n19 5 2\n15 10 12\n3 7 8\n9 1 6\n13 17 18\n14 16 4",
"output": "3 3 1 3 2 1 2 3 2 2 2 3 1 1 1 2 2 3 1 3 "
},
{
"input": "18 7\n15 5 1\n6 11 4\n14 8 17\n11 12 13\n3 8 16\n9 4 7\n2 18 10",
"output": "3 1 1 3 2 1 1 2 2 3 2 1 3 1 1 3 3 2 "
},
{
"input": "19 7\n3 10 8\n17 7 4\n1 19 18\n2 9 5\n12 11 15\n11 14 6\n13 9 16",
"output": "1 1 1 3 3 3 2 3 2 2 2 1 1 1 3 3 1 3 2 "
},
{
"input": "19 7\n18 14 4\n3 11 6\n8 10 7\n10 19 16\n17 13 15\n5 1 14\n12 9 2",
"output": "1 3 1 3 3 3 3 1 2 2 2 1 2 2 3 3 1 1 1 "
},
{
"input": "20 7\n18 7 15\n17 5 20\n9 19 12\n16 13 10\n3 6 1\n3 8 11\n4 2 14",
"output": "3 2 1 1 2 2 2 3 1 3 2 3 2 3 3 1 1 1 2 3 "
},
{
"input": "18 7\n8 4 6\n13 17 3\n9 8 12\n12 16 5\n18 2 7\n11 1 10\n5 15 14",
"output": "2 2 3 2 3 3 3 1 3 3 1 2 1 1 2 1 2 1 "
},
{
"input": "99 37\n40 10 7\n10 3 5\n10 31 37\n87 48 24\n33 47 38\n34 87 2\n2 35 28\n99 28 76\n66 51 97\n72 77 9\n18 17 67\n23 69 98\n58 89 99\n42 44 52\n65 41 80\n70 92 74\n62 88 45\n68 27 61\n6 83 95\n39 85 49\n57 75 77\n59 54 81\n56 20 82\n96 4 53\n90 7 11\n16 43 84\n19 25 59\n68 8 93\n73 94 78\n15 71 79\n26 12 50\n30 32 4\n14 22 29\n46 21 36\n60 55 86\n91 8 63\n13 1 64",
"output": "2 2 1 2 3 1 3 3 3 2 1 2 1 1 1 1 2 1 2 2 2 2 1 3 3 1 2 3 3 3 1 1 1 3 1 3 3 3 1 1 2 1 2 2 3 1 2 2 3 3 2 3 3 2 2 1 3 3 1 1 3 1 1 3 1 1 3 1 2 1 2 1 1 3 1 1 2 3 3 3 3 3 2 3 2 3 1 2 1 2 2 2 2 2 3 1 3 3 2 "
},
{
"input": "99 41\n11 70 20\n57 11 76\n52 11 64\n49 70 15\n19 61 17\n71 77 21\n77 59 39\n37 64 68\n17 84 36\n46 11 90\n35 11 14\n36 25 80\n12 43 48\n18 78 42\n82 94 15\n22 10 84\n63 86 4\n98 86 50\n92 60 9\n73 42 65\n21 5 27\n30 24 23\n7 88 49\n40 97 45\n81 56 17\n79 61 33\n13 3 77\n54 6 28\n99 58 8\n29 95 24\n89 74 32\n51 89 66\n87 91 96\n22 34 38\n1 53 72\n55 97 26\n41 16 44\n2 31 47\n83 67 91\n75 85 69\n93 47 62",
"output": "1 1 1 3 2 2 2 3 3 1 1 1 3 2 3 2 3 1 1 3 3 3 3 2 3 3 1 3 3 1 2 3 3 2 3 1 1 1 3 1 1 3 2 3 3 3 3 3 1 3 3 3 2 1 1 2 3 2 1 2 2 1 1 2 1 2 1 3 3 2 1 3 2 2 1 2 2 2 1 2 1 1 3 2 2 2 1 3 1 2 2 1 2 2 1 3 2 1 1 "
},
{
"input": "99 38\n70 56 92\n61 70 68\n18 92 91\n82 43 55\n37 5 43\n47 27 26\n64 63 40\n20 61 57\n69 80 59\n60 89 50\n33 25 86\n38 15 73\n96 85 90\n3 12 64\n95 23 48\n66 30 9\n38 99 45\n67 88 71\n74 11 81\n28 51 79\n72 92 34\n16 77 31\n65 18 94\n3 41 2\n36 42 81\n22 77 83\n44 24 52\n10 75 97\n54 21 53\n4 29 32\n58 39 98\n46 62 16\n76 5 84\n8 87 13\n6 41 14\n19 21 78\n7 49 93\n17 1 35",
"output": "2 3 2 1 1 3 1 1 3 1 2 3 3 2 2 1 1 2 1 2 2 1 2 2 2 3 2 1 2 2 3 3 1 1 3 1 3 1 2 3 1 2 2 1 2 2 1 3 2 3 2 3 3 1 3 2 1 1 3 1 3 3 2 1 1 1 1 2 1 1 3 2 3 1 2 3 2 3 3 2 3 1 3 2 2 3 2 2 2 3 1 3 3 3 1 1 3 3 3 "
},
{
"input": "98 38\n70 23 73\n73 29 86\n93 82 30\n6 29 10\n7 22 78\n55 61 87\n98 2 12\n11 5 54\n44 56 60\n89 76 50\n37 72 43\n47 41 61\n85 40 38\n48 93 20\n90 64 29\n31 68 25\n83 57 41\n51 90 3\n91 97 66\n96 95 1\n50 84 71\n53 19 5\n45 42 28\n16 17 89\n63 58 15\n26 47 39\n21 24 19\n80 74 38\n14 46 75\n88 65 36\n77 92 33\n17 59 34\n35 69 79\n13 94 39\n8 52 4\n67 27 9\n65 62 18\n81 32 49",
"output": "3 2 1 3 2 1 1 1 3 3 1 3 2 1 3 2 3 3 1 2 2 2 2 3 3 2 2 3 2 3 1 2 3 1 1 3 1 3 1 2 1 2 3 1 1 2 3 3 3 3 2 2 3 3 1 2 3 2 2 3 2 1 1 1 2 3 1 2 2 1 1 2 3 2 3 2 1 3 3 1 1 2 2 2 1 1 3 1 1 3 1 2 1 3 2 1 2 1 "
},
{
"input": "99 42\n61 66 47\n10 47 96\n68 86 67\n21 29 10\n55 44 47\n12 82 4\n45 71 55\n86 3 95\n16 99 93\n14 92 82\n12 59 20\n73 24 8\n79 72 48\n44 87 39\n87 84 97\n47 70 37\n49 77 95\n39 75 28\n75 25 5\n44 41 36\n76 86 78\n73 6 90\n8 22 58\n9 72 63\n81 42 14\n1 21 35\n91 54 15\n30 13 39\n56 89 79\n11 2 76\n19 65 52\n23 85 74\n7 38 24\n57 94 81\n43 34 60\n62 82 27\n69 64 53\n18 32 17\n24 31 88\n51 50 33\n40 80 98\n83 46 26",
"output": "2 3 1 3 3 3 3 3 1 2 2 1 2 3 3 1 3 1 1 2 3 2 1 2 1 3 3 1 1 1 1 2 3 2 1 3 1 1 3 1 1 2 1 2 2 2 3 3 1 2 1 3 3 2 1 2 2 1 3 3 1 1 3 2 2 2 3 1 1 2 3 2 1 3 2 1 2 3 1 2 1 2 1 3 2 2 1 3 3 2 1 1 3 3 3 1 2 3 2 "
}
] | 1,623,397,501
| 2,147,483,647
|
PyPy 3
|
RUNTIME_ERROR
|
TESTS
| 4
| 124
| 2,457,600
|
from sys import stdin,stdout
stdin.readline
def mp(): return list(map(int, stdin.readline().strip().split()))
def it():return int(stdin.readline().strip())
from collections import defaultdict as dd,Counter as C,deque
from math import ceil,gcd,sqrt,factorial,log2,floor
from bisect import bisect_right as br,bisect_left as bl
import heapq
n,m = mp()
d = dd(lambda:0)
for _ in range(m):
l = mp()
s = set()
s.add(1)
s.add(2)
s.add(3)
for i in l:
if d[i]:
s.remove(d[i])
else:
if s:
d[i] = s.pop()
for i in sorted(d.keys()):
print(d[i],end=' ')
|
Title: Flag Day
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland, there is the national holiday coming — the Flag Day. In the honor of this event the president of the country decided to make a big dance party and asked your agency to organize it. He has several conditions:
- overall, there must be *m* dances;- exactly three people must take part in each dance;- each dance must have one dancer in white clothes, one dancer in red clothes and one dancer in blue clothes (these are the colors of the national flag of Berland).
The agency has *n* dancers, and their number can be less than 3*m*. That is, some dancers will probably have to dance in more than one dance. All of your dancers must dance on the party. However, if some dance has two or more dancers from a previous dance, then the current dance stops being spectacular. Your agency cannot allow that to happen, so each dance has at most one dancer who has danced in some previous dance.
You considered all the criteria and made the plan for the *m* dances: each dance had three dancers participating in it. Your task is to determine the clothes color for each of the *n* dancers so that the President's third condition fulfilled: each dance must have a dancer in white, a dancer in red and a dancer in blue. The dancers cannot change clothes between the dances.
Input Specification:
The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=105) and *m* (1<=≤<=*m*<=≤<=105) — the number of dancers and the number of dances, correspondingly. Then *m* lines follow, describing the dances in the order of dancing them. The *i*-th line contains three distinct integers — the numbers of the dancers that take part in the *i*-th dance. The dancers are numbered from 1 to *n*. Each dancer takes part in at least one dance.
Output Specification:
Print *n* space-separated integers: the *i*-th number must represent the color of the *i*-th dancer's clothes (1 for white, 2 for red, 3 for blue). If there are multiple valid solutions, print any of them. It is guaranteed that at least one solution exists.
Demo Input:
['7 3\n1 2 3\n1 4 5\n4 6 7\n', '9 3\n3 6 9\n2 5 8\n1 4 7\n', '5 2\n4 1 5\n3 1 2\n']
Demo Output:
['1 2 3 3 2 2 1 \n', '1 1 1 2 2 2 3 3 3 \n', '2 3 1 1 3 \n']
Note:
none
|
```python
from sys import stdin,stdout
stdin.readline
def mp(): return list(map(int, stdin.readline().strip().split()))
def it():return int(stdin.readline().strip())
from collections import defaultdict as dd,Counter as C,deque
from math import ceil,gcd,sqrt,factorial,log2,floor
from bisect import bisect_right as br,bisect_left as bl
import heapq
n,m = mp()
d = dd(lambda:0)
for _ in range(m):
l = mp()
s = set()
s.add(1)
s.add(2)
s.add(3)
for i in l:
if d[i]:
s.remove(d[i])
else:
if s:
d[i] = s.pop()
for i in sorted(d.keys()):
print(d[i],end=' ')
```
| -1
|
|
309
|
E
|
Sheep
|
PROGRAMMING
| 2,900
|
[
"binary search",
"greedy"
] | null | null |
Information technologies are developing and are increasingly penetrating into all spheres of human activity. Incredible as it is, the most modern technology are used in farming!
A large farm has a meadow with grazing sheep. Overall there are *n* sheep and each of them contains a unique number from 1 to *n* — because the sheep need to be distinguished and you need to remember information about each one, and they are so much alike! The meadow consists of infinite number of regions numbered from 1 to infinity. It's known that sheep *i* likes regions from *l**i* to *r**i*.
There are two shepherds taking care of the sheep: First and Second. First wakes up early in the morning and leads the sheep graze on the lawn. Second comes in the evening and collects all the sheep.
One morning, First woke up a little later than usual, and had no time to lead the sheep graze on the lawn. So he tied together every two sheep if there is a region they both like. First thought that it would be better — Second would have less work in the evening, because sheep won't scatter too much, being tied to each other!
In the evening Second came on the lawn, gathered the sheep and tried to line them up in a row. But try as he might, the sheep wouldn't line up as Second want! Second had neither the strength nor the ability to untie the sheep so he left them as they are, but with one condition: he wanted to line up the sheep so that the maximum distance between two tied sheep was as small as possible. The distance between the sheep is the number of sheep in the ranks that are between these two.
Help Second find the right arrangement.
|
The first input line contains one integer *n* (1<=≤<=*n*<=≤<=2000). Each of the following *n* lines contains two integers *l**i* and *r**i* (1<=≤<=*l**i*,<=*r**i*<=≤<=109; *l**i*<=≤<=*r**i*).
|
In the single output line print *n* space-separated numbers — the sought arrangement of the sheep. The *i*-th value in the line must represent the number of the sheep that took the *i*-th place from left in the optimal arrangement line.
If there are multiple optimal arrangements, print any of them.
|
[
"3\n1 3\n5 7\n2 4\n",
"5\n1 5\n2 4\n3 6\n1 7\n2 6\n",
"4\n1 3\n4 6\n5 7\n2 3\n"
] |
[
"1 3 2",
"2 1 3 5 4",
"1 4 2 3"
] |
none
| 2,500
|
[] | 1,629,256,701
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 0
| 31
| 6,656,000
|
print("bulesheep")
|
Title: Sheep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Information technologies are developing and are increasingly penetrating into all spheres of human activity. Incredible as it is, the most modern technology are used in farming!
A large farm has a meadow with grazing sheep. Overall there are *n* sheep and each of them contains a unique number from 1 to *n* — because the sheep need to be distinguished and you need to remember information about each one, and they are so much alike! The meadow consists of infinite number of regions numbered from 1 to infinity. It's known that sheep *i* likes regions from *l**i* to *r**i*.
There are two shepherds taking care of the sheep: First and Second. First wakes up early in the morning and leads the sheep graze on the lawn. Second comes in the evening and collects all the sheep.
One morning, First woke up a little later than usual, and had no time to lead the sheep graze on the lawn. So he tied together every two sheep if there is a region they both like. First thought that it would be better — Second would have less work in the evening, because sheep won't scatter too much, being tied to each other!
In the evening Second came on the lawn, gathered the sheep and tried to line them up in a row. But try as he might, the sheep wouldn't line up as Second want! Second had neither the strength nor the ability to untie the sheep so he left them as they are, but with one condition: he wanted to line up the sheep so that the maximum distance between two tied sheep was as small as possible. The distance between the sheep is the number of sheep in the ranks that are between these two.
Help Second find the right arrangement.
Input Specification:
The first input line contains one integer *n* (1<=≤<=*n*<=≤<=2000). Each of the following *n* lines contains two integers *l**i* and *r**i* (1<=≤<=*l**i*,<=*r**i*<=≤<=109; *l**i*<=≤<=*r**i*).
Output Specification:
In the single output line print *n* space-separated numbers — the sought arrangement of the sheep. The *i*-th value in the line must represent the number of the sheep that took the *i*-th place from left in the optimal arrangement line.
If there are multiple optimal arrangements, print any of them.
Demo Input:
['3\n1 3\n5 7\n2 4\n', '5\n1 5\n2 4\n3 6\n1 7\n2 6\n', '4\n1 3\n4 6\n5 7\n2 3\n']
Demo Output:
['1 3 2', '2 1 3 5 4', '1 4 2 3']
Note:
none
|
```python
print("bulesheep")
```
| 0
|
|
9
|
A
|
Die Roll
|
PROGRAMMING
| 800
|
[
"math",
"probabilities"
] |
A. Die Roll
|
1
|
64
|
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpredictable place.
But to their great regret, the leave turned to be very short, so it will be enough to visit one of the three above named places. That's why Yakko, as the cleverest, came up with a truly genius idea: let each of the three roll an ordinary six-sided die, and the one with the highest amount of points will be the winner, and will take the other two to the place of his/her dreams.
Yakko thrown a die and got Y points, Wakko — W points. It was Dot's turn. But she didn't hurry. Dot wanted to know for sure what were her chances to visit Transylvania.
It is known that Yakko and Wakko are true gentlemen, that's why if they have the same amount of points with Dot, they will let Dot win.
|
The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls.
|
Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1».
|
[
"4 2\n"
] |
[
"1/2\n"
] |
Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points.
| 0
|
[
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
"output": "1/6"
},
{
"input": "2 1",
"output": "5/6"
},
{
"input": "2 2",
"output": "5/6"
},
{
"input": "2 3",
"output": "2/3"
},
{
"input": "2 4",
"output": "1/2"
},
{
"input": "2 5",
"output": "1/3"
},
{
"input": "2 6",
"output": "1/6"
},
{
"input": "3 1",
"output": "2/3"
},
{
"input": "3 2",
"output": "2/3"
},
{
"input": "3 3",
"output": "2/3"
},
{
"input": "3 4",
"output": "1/2"
},
{
"input": "3 5",
"output": "1/3"
},
{
"input": "3 6",
"output": "1/6"
},
{
"input": "4 1",
"output": "1/2"
},
{
"input": "4 3",
"output": "1/2"
},
{
"input": "4 4",
"output": "1/2"
},
{
"input": "4 5",
"output": "1/3"
},
{
"input": "4 6",
"output": "1/6"
},
{
"input": "5 1",
"output": "1/3"
},
{
"input": "5 2",
"output": "1/3"
},
{
"input": "5 3",
"output": "1/3"
},
{
"input": "5 4",
"output": "1/3"
},
{
"input": "5 5",
"output": "1/3"
},
{
"input": "5 6",
"output": "1/6"
},
{
"input": "6 1",
"output": "1/6"
},
{
"input": "6 2",
"output": "1/6"
},
{
"input": "6 3",
"output": "1/6"
},
{
"input": "6 4",
"output": "1/6"
},
{
"input": "6 5",
"output": "1/6"
},
{
"input": "6 6",
"output": "1/6"
}
] | 1,695,552,240
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 1
| 92
| 1,228,800
|
from fractions import Fraction
y,w = list(map(int,input().split()))
prop = Fraction(6 - (max(y,w) - 1), 6)
print(prop)
|
Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpredictable place.
But to their great regret, the leave turned to be very short, so it will be enough to visit one of the three above named places. That's why Yakko, as the cleverest, came up with a truly genius idea: let each of the three roll an ordinary six-sided die, and the one with the highest amount of points will be the winner, and will take the other two to the place of his/her dreams.
Yakko thrown a die and got Y points, Wakko — W points. It was Dot's turn. But she didn't hurry. Dot wanted to know for sure what were her chances to visit Transylvania.
It is known that Yakko and Wakko are true gentlemen, that's why if they have the same amount of points with Dot, they will let Dot win.
Input Specification:
The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls.
Output Specification:
Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1».
Demo Input:
['4 2\n']
Demo Output:
['1/2\n']
Note:
Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points.
|
```python
from fractions import Fraction
y,w = list(map(int,input().split()))
prop = Fraction(6 - (max(y,w) - 1), 6)
print(prop)
```
| 0
|
106
|
A
|
Card Game
|
PROGRAMMING
| 1,000
|
[
"implementation"
] |
A. Card Game
|
2
|
256
|
There is a card game called "Durak", which means "Fool" in Russian. The game is quite popular in the countries that used to form USSR. The problem does not state all the game's rules explicitly — you can find them later yourselves if you want.
To play durak you need a pack of 36 cards. Each card has a suit ("S", "H", "D" and "C") and a rank (in the increasing order "6", "7", "8", "9", "T", "J", "Q", "K" and "A"). At the beginning of the game one suit is arbitrarily chosen as trump.
The players move like that: one player puts one or several of his cards on the table and the other one should beat each of them with his cards.
A card beats another one if both cards have similar suits and the first card has a higher rank then the second one. Besides, a trump card can beat any non-trump card whatever the cards’ ranks are. In all other cases you can not beat the second card with the first one.
You are given the trump suit and two different cards. Determine whether the first one beats the second one or not.
|
The first line contains the tramp suit. It is "S", "H", "D" or "C".
The second line contains the description of the two different cards. Each card is described by one word consisting of two symbols. The first symbol stands for the rank ("6", "7", "8", "9", "T", "J", "Q", "K" and "A"), and the second one stands for the suit ("S", "H", "D" and "C").
|
Print "YES" (without the quotes) if the first cards beats the second one. Otherwise, print "NO" (also without the quotes).
|
[
"H\nQH 9S\n",
"S\n8D 6D\n",
"C\n7H AS\n"
] |
[
"YES\n",
"YES",
"NO"
] |
none
| 500
|
[
{
"input": "H\nQH 9S",
"output": "YES"
},
{
"input": "S\n8D 6D",
"output": "YES"
},
{
"input": "C\n7H AS",
"output": "NO"
},
{
"input": "C\nKC 9C",
"output": "YES"
},
{
"input": "D\n7D KD",
"output": "NO"
},
{
"input": "H\n7H KD",
"output": "YES"
},
{
"input": "D\nAS AH",
"output": "NO"
},
{
"input": "H\nKH KS",
"output": "YES"
},
{
"input": "C\n9H 6C",
"output": "NO"
},
{
"input": "C\n9H JC",
"output": "NO"
},
{
"input": "D\nTD JD",
"output": "NO"
},
{
"input": "H\n6S 7S",
"output": "NO"
},
{
"input": "D\n7S 8S",
"output": "NO"
},
{
"input": "S\n8H 9H",
"output": "NO"
},
{
"input": "C\n9D TD",
"output": "NO"
},
{
"input": "H\nTC JC",
"output": "NO"
},
{
"input": "C\nJH QH",
"output": "NO"
},
{
"input": "H\nQD KD",
"output": "NO"
},
{
"input": "D\nKS AS",
"output": "NO"
},
{
"input": "S\nAH 6H",
"output": "YES"
},
{
"input": "H\n7D 6D",
"output": "YES"
},
{
"input": "S\n8H 7H",
"output": "YES"
},
{
"input": "D\n9S 8S",
"output": "YES"
},
{
"input": "S\nTC 9C",
"output": "YES"
},
{
"input": "H\nJS TS",
"output": "YES"
},
{
"input": "S\nQD JD",
"output": "YES"
},
{
"input": "D\nKH QH",
"output": "YES"
},
{
"input": "H\nAD KD",
"output": "YES"
},
{
"input": "H\nQS QD",
"output": "NO"
},
{
"input": "C\nTS TH",
"output": "NO"
},
{
"input": "C\n6C 6D",
"output": "YES"
},
{
"input": "H\n8H 8D",
"output": "YES"
},
{
"input": "S\n7D 7S",
"output": "NO"
},
{
"input": "H\nJC JH",
"output": "NO"
},
{
"input": "H\n8H 9C",
"output": "YES"
},
{
"input": "D\n9D 6S",
"output": "YES"
},
{
"input": "C\nJC AH",
"output": "YES"
},
{
"input": "S\nAS KD",
"output": "YES"
},
{
"input": "S\n7S JS",
"output": "NO"
},
{
"input": "H\nTH 8H",
"output": "YES"
},
{
"input": "S\n7S QS",
"output": "NO"
},
{
"input": "C\nKC QC",
"output": "YES"
},
{
"input": "S\nAD 9S",
"output": "NO"
},
{
"input": "D\n7H 8D",
"output": "NO"
},
{
"input": "H\nJC 9H",
"output": "NO"
},
{
"input": "C\n7S AC",
"output": "NO"
},
{
"input": "C\n8C 7C",
"output": "YES"
},
{
"input": "H\n9D 8S",
"output": "NO"
},
{
"input": "D\nAC KS",
"output": "NO"
},
{
"input": "H\n8C QH",
"output": "NO"
},
{
"input": "S\n7S TS",
"output": "NO"
},
{
"input": "C\nAH 6S",
"output": "NO"
},
{
"input": "S\nKS QS",
"output": "YES"
},
{
"input": "H\nAC QC",
"output": "YES"
},
{
"input": "S\n9H 8D",
"output": "NO"
},
{
"input": "S\nTS JS",
"output": "NO"
},
{
"input": "S\n8H 7C",
"output": "NO"
},
{
"input": "C\nAH 6S",
"output": "NO"
},
{
"input": "S\n7S QS",
"output": "NO"
},
{
"input": "C\nAH 6S",
"output": "NO"
},
{
"input": "S\nTS KS",
"output": "NO"
},
{
"input": "C\nTH KH",
"output": "NO"
},
{
"input": "H\n9C 6D",
"output": "NO"
},
{
"input": "H\n9C 8D",
"output": "NO"
},
{
"input": "H\nTH AH",
"output": "NO"
},
{
"input": "H\nTH JH",
"output": "NO"
},
{
"input": "H\nQS 9C",
"output": "NO"
},
{
"input": "H\nKC AC",
"output": "NO"
},
{
"input": "H\nAH KH",
"output": "YES"
},
{
"input": "H\nKS QS",
"output": "YES"
},
{
"input": "C\nAD KS",
"output": "NO"
},
{
"input": "H\nQS 9C",
"output": "NO"
},
{
"input": "H\n9D 7S",
"output": "NO"
},
{
"input": "D\n6D 9S",
"output": "YES"
},
{
"input": "H\nAH KH",
"output": "YES"
},
{
"input": "H\nKC AC",
"output": "NO"
},
{
"input": "D\n8S 6C",
"output": "NO"
},
{
"input": "S\nAC KC",
"output": "YES"
}
] | 1,527,703,245
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 4
| 156
| 7,065,600
|
# python 3
"""
"""
def card_game(trump_suit_str, first_str, second_str) -> str:
rank = {"6": 0, "7": 1, "8": 2, "9": 3, "T": 4, "J": 5, "Q": 6, "K": 7, "A": 8}
result = {True: "YES", False: "NO"}
if first_str[1] == trump_suit_str:
return "YES"
elif first_str[1] == second_str[1]:
return result[rank[first_str[0]] > rank[second_str[0]]]
else:
return "NO"
if __name__ == "__main__":
"""
Inside of this is the test.
Outside is the API
"""
trump_suit = input()
first, second = list(input().split())
print(card_game(trump_suit, first, second))
|
Title: Card Game
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a card game called "Durak", which means "Fool" in Russian. The game is quite popular in the countries that used to form USSR. The problem does not state all the game's rules explicitly — you can find them later yourselves if you want.
To play durak you need a pack of 36 cards. Each card has a suit ("S", "H", "D" and "C") and a rank (in the increasing order "6", "7", "8", "9", "T", "J", "Q", "K" and "A"). At the beginning of the game one suit is arbitrarily chosen as trump.
The players move like that: one player puts one or several of his cards on the table and the other one should beat each of them with his cards.
A card beats another one if both cards have similar suits and the first card has a higher rank then the second one. Besides, a trump card can beat any non-trump card whatever the cards’ ranks are. In all other cases you can not beat the second card with the first one.
You are given the trump suit and two different cards. Determine whether the first one beats the second one or not.
Input Specification:
The first line contains the tramp suit. It is "S", "H", "D" or "C".
The second line contains the description of the two different cards. Each card is described by one word consisting of two symbols. The first symbol stands for the rank ("6", "7", "8", "9", "T", "J", "Q", "K" and "A"), and the second one stands for the suit ("S", "H", "D" and "C").
Output Specification:
Print "YES" (without the quotes) if the first cards beats the second one. Otherwise, print "NO" (also without the quotes).
Demo Input:
['H\nQH 9S\n', 'S\n8D 6D\n', 'C\n7H AS\n']
Demo Output:
['YES\n', 'YES', 'NO']
Note:
none
|
```python
# python 3
"""
"""
def card_game(trump_suit_str, first_str, second_str) -> str:
rank = {"6": 0, "7": 1, "8": 2, "9": 3, "T": 4, "J": 5, "Q": 6, "K": 7, "A": 8}
result = {True: "YES", False: "NO"}
if first_str[1] == trump_suit_str:
return "YES"
elif first_str[1] == second_str[1]:
return result[rank[first_str[0]] > rank[second_str[0]]]
else:
return "NO"
if __name__ == "__main__":
"""
Inside of this is the test.
Outside is the API
"""
trump_suit = input()
first, second = list(input().split())
print(card_game(trump_suit, first, second))
```
| 0
|
977
|
B
|
Two-gram
|
PROGRAMMING
| 900
|
[
"implementation",
"strings"
] | null | null |
Two-gram is an ordered pair (i.e. string of length two) of capital Latin letters. For example, "AZ", "AA", "ZA" — three distinct two-grams.
You are given a string $s$ consisting of $n$ capital Latin letters. Your task is to find any two-gram contained in the given string as a substring (i.e. two consecutive characters of the string) maximal number of times. For example, for string $s$ = "BBAABBBA" the answer is two-gram "BB", which contained in $s$ three times. In other words, find any most frequent two-gram.
Note that occurrences of the two-gram can overlap with each other.
|
The first line of the input contains integer number $n$ ($2 \le n \le 100$) — the length of string $s$. The second line of the input contains the string $s$ consisting of $n$ capital Latin letters.
|
Print the only line containing exactly two capital Latin letters — any two-gram contained in the given string $s$ as a substring (i.e. two consecutive characters of the string) maximal number of times.
|
[
"7\nABACABA\n",
"5\nZZZAA\n"
] |
[
"AB\n",
"ZZ\n"
] |
In the first example "BA" is also valid answer.
In the second example the only two-gram "ZZ" can be printed because it contained in the string "ZZZAA" two times.
| 0
|
[
{
"input": "7\nABACABA",
"output": "AB"
},
{
"input": "5\nZZZAA",
"output": "ZZ"
},
{
"input": "26\nQWERTYUIOPASDFGHJKLZXCVBNM",
"output": "AS"
},
{
"input": "2\nQA",
"output": "QA"
},
{
"input": "2\nWW",
"output": "WW"
},
{
"input": "11\nGGRRAATTZZZ",
"output": "ZZ"
},
{
"input": "50\nNYQAHBYYOXLTRYQDMVENEMAQNBAKGLGQOLXNAIFNQTOCLNNQIA",
"output": "NQ"
},
{
"input": "100\nURXCAIZFIBNJTPCZHBQIBCILLPXZCFGMKKZMNPLCYGAVJVIBMCZEBSJWPSCPQDYCTTKPOKIJRSKIZPDGCHVOUTMPNECYORSFZFNC",
"output": "IB"
},
{
"input": "100\nAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA",
"output": "AA"
},
{
"input": "10\nSQSQSQSQTG",
"output": "SQ"
},
{
"input": "5\nAZAZA",
"output": "AZ"
},
{
"input": "15\nMIRZOYANOVECLOX",
"output": "AN"
},
{
"input": "9\nEGORLETOV",
"output": "EG"
},
{
"input": "8\nPUTINVOR",
"output": "IN"
},
{
"input": "7\nKADUROV",
"output": "AD"
},
{
"input": "6\nAZAZAZ",
"output": "AZ"
},
{
"input": "3\nLOL",
"output": "LO"
},
{
"input": "3\nKEK",
"output": "EK"
},
{
"input": "5\nFUFEL",
"output": "EL"
},
{
"input": "9\nMIKEPIDOR",
"output": "DO"
},
{
"input": "9\nAAAAAAAAA",
"output": "AA"
},
{
"input": "23\nAABBBAAACCCCCAAADDDDDDD",
"output": "DD"
}
] | 1,698,951,705
| 705
|
Python 3
|
OK
|
TESTS
| 22
| 31
| 0
|
n = int(input())
s = input()
d = {}
for i in range(len(s)-1):
ss = s[i]+s[i+1]
if ss not in d.keys():
d[ss] = 0
d[ss] += 1
mx = 0
mx_ss = ""
for k in d.keys():
if mx < d[k]:
mx = d[k]
mx_ss = k
print(mx_ss)
|
Title: Two-gram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two-gram is an ordered pair (i.e. string of length two) of capital Latin letters. For example, "AZ", "AA", "ZA" — three distinct two-grams.
You are given a string $s$ consisting of $n$ capital Latin letters. Your task is to find any two-gram contained in the given string as a substring (i.e. two consecutive characters of the string) maximal number of times. For example, for string $s$ = "BBAABBBA" the answer is two-gram "BB", which contained in $s$ three times. In other words, find any most frequent two-gram.
Note that occurrences of the two-gram can overlap with each other.
Input Specification:
The first line of the input contains integer number $n$ ($2 \le n \le 100$) — the length of string $s$. The second line of the input contains the string $s$ consisting of $n$ capital Latin letters.
Output Specification:
Print the only line containing exactly two capital Latin letters — any two-gram contained in the given string $s$ as a substring (i.e. two consecutive characters of the string) maximal number of times.
Demo Input:
['7\nABACABA\n', '5\nZZZAA\n']
Demo Output:
['AB\n', 'ZZ\n']
Note:
In the first example "BA" is also valid answer.
In the second example the only two-gram "ZZ" can be printed because it contained in the string "ZZZAA" two times.
|
```python
n = int(input())
s = input()
d = {}
for i in range(len(s)-1):
ss = s[i]+s[i+1]
if ss not in d.keys():
d[ss] = 0
d[ss] += 1
mx = 0
mx_ss = ""
for k in d.keys():
if mx < d[k]:
mx = d[k]
mx_ss = k
print(mx_ss)
```
| 3
|
|
131
|
A
|
cAPS lOCK
|
PROGRAMMING
| 1,000
|
[
"implementation",
"strings"
] | null | null |
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentally switched on, if:
- either it only contains uppercase letters; - or all letters except for the first one are uppercase.
In this case we should automatically change the case of all letters. For example, the case of the letters that form words "hELLO", "HTTP", "z" should be changed.
Write a program that applies the rule mentioned above. If the rule cannot be applied, the program should leave the word unchanged.
|
The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive.
|
Print the result of the given word's processing.
|
[
"cAPS\n",
"Lock\n"
] |
[
"Caps",
"Lock\n"
] |
none
| 500
|
[
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
"input": "oops",
"output": "oops"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "a"
},
{
"input": "aA",
"output": "Aa"
},
{
"input": "Zz",
"output": "Zz"
},
{
"input": "Az",
"output": "Az"
},
{
"input": "zA",
"output": "Za"
},
{
"input": "AAA",
"output": "aaa"
},
{
"input": "AAa",
"output": "AAa"
},
{
"input": "AaR",
"output": "AaR"
},
{
"input": "Tdr",
"output": "Tdr"
},
{
"input": "aTF",
"output": "Atf"
},
{
"input": "fYd",
"output": "fYd"
},
{
"input": "dsA",
"output": "dsA"
},
{
"input": "fru",
"output": "fru"
},
{
"input": "hYBKF",
"output": "Hybkf"
},
{
"input": "XweAR",
"output": "XweAR"
},
{
"input": "mogqx",
"output": "mogqx"
},
{
"input": "eOhEi",
"output": "eOhEi"
},
{
"input": "nkdku",
"output": "nkdku"
},
{
"input": "zcnko",
"output": "zcnko"
},
{
"input": "lcccd",
"output": "lcccd"
},
{
"input": "vwmvg",
"output": "vwmvg"
},
{
"input": "lvchf",
"output": "lvchf"
},
{
"input": "IUNVZCCHEWENCHQQXQYPUJCRDZLUXCLJHXPHBXEUUGNXOOOPBMOBRIBHHMIRILYJGYYGFMTMFSVURGYHUWDRLQVIBRLPEVAMJQYO",
"output": "iunvzcchewenchqqxqypujcrdzluxcljhxphbxeuugnxooopbmobribhhmirilyjgyygfmtmfsvurgyhuwdrlqvibrlpevamjqyo"
},
{
"input": "OBHSZCAMDXEJWOZLKXQKIVXUUQJKJLMMFNBPXAEFXGVNSKQLJGXHUXHGCOTESIVKSFMVVXFVMTEKACRIWALAGGMCGFEXQKNYMRTG",
"output": "obhszcamdxejwozlkxqkivxuuqjkjlmmfnbpxaefxgvnskqljgxhuxhgcotesivksfmvvxfvmtekacriwalaggmcgfexqknymrtg"
},
{
"input": "IKJYZIKROIYUUCTHSVSKZTETNNOCMAUBLFJCEVANCADASMZRCNLBZPQRXESHEEMOMEPCHROSRTNBIDXYMEPJSIXSZQEBTEKKUHFS",
"output": "ikjyzikroiyuucthsvskztetnnocmaublfjcevancadasmzrcnlbzpqrxesheemomepchrosrtnbidxymepjsixszqebtekkuhfs"
},
{
"input": "cTKDZNWVYRTFPQLDAUUNSPKTDJTUPPFPRXRSINTVFVNNQNKXWUZUDHZBUSOKTABUEDQKUIVRTTVUREEOBJTSDKJKVEGFXVHXEYPE",
"output": "Ctkdznwvyrtfpqldauunspktdjtuppfprxrsintvfvnnqnkxwuzudhzbusoktabuedqkuivrttvureeobjtsdkjkvegfxvhxeype"
},
{
"input": "uCKJZRGZJCPPLEEYJTUNKOQSWGBMTBQEVPYFPIPEKRVYQNTDPANOIXKMPINNFUSZWCURGBDPYTEKBEKCPMVZPMWAOSHJYMGKOMBQ",
"output": "Uckjzrgzjcppleeyjtunkoqswgbmtbqevpyfpipekrvyqntdpanoixkmpinnfuszwcurgbdpytekbekcpmvzpmwaoshjymgkombq"
},
{
"input": "KETAXTSWAAOBKUOKUQREHIOMVMMRSAEWKGXZKRASwTVNSSFSNIWYNPSTMRADOADEEBURRHPOOBIEUIBGYDJCEKPNLEUCANZYJKMR",
"output": "KETAXTSWAAOBKUOKUQREHIOMVMMRSAEWKGXZKRASwTVNSSFSNIWYNPSTMRADOADEEBURRHPOOBIEUIBGYDJCEKPNLEUCANZYJKMR"
},
{
"input": "ZEKGDMWJPVUWFlNXRLUmWKLMMYSLRQQIBRWDPKWITUIMZYYKOEYGREKHHZRZZUFPVTNIHKGTCCTLOKSZITXXZDMPITHNZUIGDZLE",
"output": "ZEKGDMWJPVUWFlNXRLUmWKLMMYSLRQQIBRWDPKWITUIMZYYKOEYGREKHHZRZZUFPVTNIHKGTCCTLOKSZITXXZDMPITHNZUIGDZLE"
},
{
"input": "TcMbVPCFvnNkCEUUCIFLgBJeCOKuJhIGwXFrhAZjuAhBraMSchBfWwIuHAEbgJOFzGtxDLDXzDSaPCFujGGxgxdlHUIQYRrMFCgJ",
"output": "TcMbVPCFvnNkCEUUCIFLgBJeCOKuJhIGwXFrhAZjuAhBraMSchBfWwIuHAEbgJOFzGtxDLDXzDSaPCFujGGxgxdlHUIQYRrMFCgJ"
},
{
"input": "xFGqoLILNvxARKuIntPfeukFtMbvzDezKpPRAKkIoIvwqNXnehRVwkkXYvuRCeoieBaBfTjwsYhDeCLvBwktntyluoxCYVioXGdm",
"output": "xFGqoLILNvxARKuIntPfeukFtMbvzDezKpPRAKkIoIvwqNXnehRVwkkXYvuRCeoieBaBfTjwsYhDeCLvBwktntyluoxCYVioXGdm"
},
{
"input": "udvqolbxdwbkijwvhlyaelhynmnfgszbhgshlcwdkaibceqomzujndixuzivlsjyjqxzxodzbukxxhwwultvekdfntwpzlhhrIjm",
"output": "udvqolbxdwbkijwvhlyaelhynmnfgszbhgshlcwdkaibceqomzujndixuzivlsjyjqxzxodzbukxxhwwultvekdfntwpzlhhrIjm"
},
{
"input": "jgpwhetqqoncighgzbbaLwwwxkxivuwtokehrgprfgewzcwxkavwoflcgsgbhoeamzbefzoonwsyzisetoydrpufktzgbaycgaeg",
"output": "jgpwhetqqoncighgzbbaLwwwxkxivuwtokehrgprfgewzcwxkavwoflcgsgbhoeamzbefzoonwsyzisetoydrpufktzgbaycgaeg"
},
{
"input": "vyujsazdstbnkxeunedfbolicojzjpufgfemhtmdrswvmuhoivjvonacefqenbqudelmdegxqtbwezsbydmanzutvdgkgrjxzlnc",
"output": "vyujsazdstbnkxeunedfbolicojzjpufgfemhtmdrswvmuhoivjvonacefqenbqudelmdegxqtbwezsbydmanzutvdgkgrjxzlnc"
},
{
"input": "pivqnuqkaofcduvbttztjbuavrqwiqrwkfncmvatoxruelyoecnkpqraiahumiaiqeyjapbqyrsxcdgjbihivtqezvasfmzntdfv",
"output": "pivqnuqkaofcduvbttztjbuavrqwiqrwkfncmvatoxruelyoecnkpqraiahumiaiqeyjapbqyrsxcdgjbihivtqezvasfmzntdfv"
},
{
"input": "upvtbsxswbohxshdrbjxcungzquhuomgxwlryvshshsfvqbrxvcikbglietlpqkiwbhiqpmdwuqosbtdvyxekkaqiwrbsibpoect",
"output": "upvtbsxswbohxshdrbjxcungzquhuomgxwlryvshshsfvqbrxvcikbglietlpqkiwbhiqpmdwuqosbtdvyxekkaqiwrbsibpoect"
},
{
"input": "cTKDZNWVYRTFPQLDAUUNSPKTDJTUPPFPRXRSINTVFVNNQNKXWUZUDHZBUSOKTABUEDQKUIVRTTVUREEOBJTSDKJKVEGFXVHXEYPE",
"output": "Ctkdznwvyrtfpqldauunspktdjtuppfprxrsintvfvnnqnkxwuzudhzbusoktabuedqkuivrttvureeobjtsdkjkvegfxvhxeype"
},
{
"input": "JEGDOFJOFGJHFROGHOFGMHOFGHORGFHMOu",
"output": "JEGDOFJOFGJHFROGHOFGMHOFGHORGFHMOu"
},
{
"input": "aBACABa",
"output": "aBACABa"
},
{
"input": "AAAAAAAAAAAAAAAAAAAAAAAAaa",
"output": "AAAAAAAAAAAAAAAAAAAAAAAAaa"
},
{
"input": "aaAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA",
"output": "aaAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA"
},
{
"input": "dDDDDDDDDDDDDD",
"output": "Dddddddddddddd"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa",
"output": "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
},
{
"input": "z",
"output": "Z"
},
{
"input": "AZ",
"output": "az"
},
{
"input": "Z",
"output": "z"
},
{
"input": "aAAAA",
"output": "Aaaaa"
},
{
"input": "F",
"output": "f"
}
] | 1,691,065,971
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 5
| 31
| 0
|
word=input()
if(word==word.upper()):
print(word[0]+word[1:].lower())
elif(word[0]==word[0].lower() and word[1:]==word[1:].upper()):
print(word[0].upper()+word[1:].lower())
else:
print(word)
|
Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentally switched on, if:
- either it only contains uppercase letters; - or all letters except for the first one are uppercase.
In this case we should automatically change the case of all letters. For example, the case of the letters that form words "hELLO", "HTTP", "z" should be changed.
Write a program that applies the rule mentioned above. If the rule cannot be applied, the program should leave the word unchanged.
Input Specification:
The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive.
Output Specification:
Print the result of the given word's processing.
Demo Input:
['cAPS\n', 'Lock\n']
Demo Output:
['Caps', 'Lock\n']
Note:
none
|
```python
word=input()
if(word==word.upper()):
print(word[0]+word[1:].lower())
elif(word[0]==word[0].lower() and word[1:]==word[1:].upper()):
print(word[0].upper()+word[1:].lower())
else:
print(word)
```
| 0
|
|
371
|
C
|
Hamburgers
|
PROGRAMMING
| 1,600
|
[
"binary search",
"brute force"
] | null | null |
Polycarpus loves hamburgers very much. He especially adores the hamburgers he makes with his own hands. Polycarpus thinks that there are only three decent ingredients to make hamburgers from: a bread, sausage and cheese. He writes down the recipe of his favorite "Le Hamburger de Polycarpus" as a string of letters 'B' (bread), 'S' (sausage) и 'C' (cheese). The ingredients in the recipe go from bottom to top, for example, recipe "ВSCBS" represents the hamburger where the ingredients go from bottom to top as bread, sausage, cheese, bread and sausage again.
Polycarpus has *n**b* pieces of bread, *n**s* pieces of sausage and *n**c* pieces of cheese in the kitchen. Besides, the shop nearby has all three ingredients, the prices are *p**b* rubles for a piece of bread, *p**s* for a piece of sausage and *p**c* for a piece of cheese.
Polycarpus has *r* rubles and he is ready to shop on them. What maximum number of hamburgers can he cook? You can assume that Polycarpus cannot break or slice any of the pieces of bread, sausage or cheese. Besides, the shop has an unlimited number of pieces of each ingredient.
|
The first line of the input contains a non-empty string that describes the recipe of "Le Hamburger de Polycarpus". The length of the string doesn't exceed 100, the string contains only letters 'B' (uppercase English B), 'S' (uppercase English S) and 'C' (uppercase English C).
The second line contains three integers *n**b*, *n**s*, *n**c* (1<=≤<=*n**b*,<=*n**s*,<=*n**c*<=≤<=100) — the number of the pieces of bread, sausage and cheese on Polycarpus' kitchen. The third line contains three integers *p**b*, *p**s*, *p**c* (1<=≤<=*p**b*,<=*p**s*,<=*p**c*<=≤<=100) — the price of one piece of bread, sausage and cheese in the shop. Finally, the fourth line contains integer *r* (1<=≤<=*r*<=≤<=1012) — the number of rubles Polycarpus has.
Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
|
Print the maximum number of hamburgers Polycarpus can make. If he can't make any hamburger, print 0.
|
[
"BBBSSC\n6 4 1\n1 2 3\n4\n",
"BBC\n1 10 1\n1 10 1\n21\n",
"BSC\n1 1 1\n1 1 3\n1000000000000\n"
] |
[
"2\n",
"7\n",
"200000000001\n"
] |
none
| 1,500
|
[
{
"input": "BBBSSC\n6 4 1\n1 2 3\n4",
"output": "2"
},
{
"input": "BBC\n1 10 1\n1 10 1\n21",
"output": "7"
},
{
"input": "BSC\n1 1 1\n1 1 3\n1000000000000",
"output": "200000000001"
},
{
"input": "B\n1 1 1\n1 1 1\n381",
"output": "382"
},
{
"input": "BSC\n3 5 6\n7 3 9\n100",
"output": "10"
},
{
"input": "BSC\n100 1 1\n100 1 1\n100",
"output": "51"
},
{
"input": "SBBCCSBB\n1 50 100\n31 59 21\n100000",
"output": "370"
},
{
"input": "BBBBCCCCCCCCCCCCCCCCCCCCSSSSBBBBBBBBSS\n100 100 100\n1 1 1\n3628800",
"output": "95502"
},
{
"input": "BBBBBBBBBBCCCCCCCCCCCCCCCCCCCCSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS\n10 20 40\n100 100 100\n200",
"output": "0"
},
{
"input": "BBBBBBBBBBCCCCCCCCCCCCCCCCCCCCSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS\n10 20 40\n100 100 100\n2000",
"output": "1"
},
{
"input": "BBBBBBBBBBCCCCCCCCCCCCCCCCCCCCSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS\n10 20 40\n100 100 100\n300",
"output": "0"
},
{
"input": "BBBBBBBBBBCCCCCCCCCCCCCCCCCCCCSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS\n10 20 40\n100 100 100\n300000000",
"output": "42858"
},
{
"input": "BBBBBBBBBBCCCCCCCCCCCCCCCCCCCCSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS\n10 20 40\n100 100 100\n914159265358",
"output": "130594181"
},
{
"input": "SSSSSSSSSSBBBBBBBBBCCCCCCCCCCCCCCCCCCCSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSBB\n31 53 97\n13 17 31\n914159265358",
"output": "647421579"
},
{
"input": "BBBCSBSBBSSSSCCCCBBCSBBBBSSBBBCBSCCSSCSSCSBSSSCCCCBSCSSBSSSCCCBBCCCSCBCBBCCSCCCCSBBCCBBBBCCCCCCBSSCB\n91 87 17\n64 44 43\n958532915587",
"output": "191668251"
},
{
"input": "CSSCBBCCCSBSCBBBCSBBBCBSBCSCBCSCBCBSBCBCSSBBSBBCBBBBSCSBBCCBCCBCBBSBSBCSCSBBSSBBCSSBCSCSCCSSBCBBCBSB\n56 34 48\n78 6 96\n904174875419",
"output": "140968956"
},
{
"input": "CCSCCCSBBBSCBSCSCCSSBBBSSBBBSBBBCBCSSBCSCBBCCCBCBCBCCCSSBSBBCCCCCBBSCBSCBCBBCBBCSSBCSBSSCCSCCSCCBBBS\n33 73 67\n4 56 42\n886653164314",
"output": "277425898"
},
{
"input": "SBCSSCBBSSBCSSBBBSSBSCBSSSCBBSBBBBCSBCSBSCBSCBSCBSBSSCCCCBSBCCBCBSCCCBSCCBSBBCBSSCCCCSBSBBBSSSBCSCBC\n94 16 85\n14 18 91\n836590091442",
"output": "217522127"
},
{
"input": "BSCSBSCCSCSSCCCSBCSSBCBBSCCBSCCSSSSSSSSSCCSBSCCBBCBBSBSCCCCBCSBSBSSBBBBBSSBSSCBCCSSBSSSCBBCSBBSBCCCB\n67 54 8\n36 73 37\n782232051273",
"output": "154164772"
},
{
"input": "CBBCBSBCCSCBSSCCBCSBCSBBSCBBCSCCBSCCSCSBBSSBSBSCBBSBBCSSSSBBBBSBBCBCSBBCBCSSBBCSBSCCSCSBCSCBSCCBBCSC\n71 71 52\n52 88 3\n654400055575",
"output": "137826467"
},
{
"input": "CBBCBSBCCSCBSSCCBCSBCSBBSCBBCSCCBSCCSCSBBSBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBCBBCSC\n100 1 1\n1 17 23\n954400055575",
"output": "1355681897"
},
{
"input": "C\n100 100 100\n1 1 1\n1000000000000",
"output": "1000000000100"
},
{
"input": "SSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS\n100 100 100\n100 100 100\n1000000000000",
"output": "100000001"
},
{
"input": "B\n100 100 100\n1 1 1\n1",
"output": "101"
},
{
"input": "SC\n2 1 1\n1 1 1\n100000000000",
"output": "50000000001"
},
{
"input": "B\n100 1 1\n1 1 1\n1000000000000",
"output": "1000000000100"
},
{
"input": "BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB\n1 1 1\n100 100 100\n1000000000000",
"output": "100000000"
},
{
"input": "CC\n1 1 1\n100 100 100\n1",
"output": "0"
},
{
"input": "B\n100 100 100\n1 1 1\n1000000000000",
"output": "1000000000100"
},
{
"input": "BSC\n100 100 100\n1 1 1\n1000000000000",
"output": "333333333433"
},
{
"input": "BSC\n100 100 100\n1 1 1\n1",
"output": "100"
}
] | 1,653,050,724
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 1
| 30
| 0
|
def check(mid,p,n,b,s,c,m):
cost = 0
cost+=max(0,b*mid-n[0])*p[0]
cost+=max(0,s*mid-n[1])*p[1]
cost+=max(0,c*mid-n[2])*p[2]
return cost<=m
st = input()
n = list(map(int,input().split(" ")))
p = list(map(int,input().split(" ")))
m = int(input())
b = 0
c = 0
s = 0
for i in st:
if i=="B":
b+=1
elif i=="S":
s+=1
else:
c+=1
l = 0
h = 1000000000000
while l<=h:
mid = (l+h+1)//2
if check(mid,p,n,b,s,c,m):
l = mid+1
else:
h = mid-1
print(mid)
|
Title: Hamburgers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus loves hamburgers very much. He especially adores the hamburgers he makes with his own hands. Polycarpus thinks that there are only three decent ingredients to make hamburgers from: a bread, sausage and cheese. He writes down the recipe of his favorite "Le Hamburger de Polycarpus" as a string of letters 'B' (bread), 'S' (sausage) и 'C' (cheese). The ingredients in the recipe go from bottom to top, for example, recipe "ВSCBS" represents the hamburger where the ingredients go from bottom to top as bread, sausage, cheese, bread and sausage again.
Polycarpus has *n**b* pieces of bread, *n**s* pieces of sausage and *n**c* pieces of cheese in the kitchen. Besides, the shop nearby has all three ingredients, the prices are *p**b* rubles for a piece of bread, *p**s* for a piece of sausage and *p**c* for a piece of cheese.
Polycarpus has *r* rubles and he is ready to shop on them. What maximum number of hamburgers can he cook? You can assume that Polycarpus cannot break or slice any of the pieces of bread, sausage or cheese. Besides, the shop has an unlimited number of pieces of each ingredient.
Input Specification:
The first line of the input contains a non-empty string that describes the recipe of "Le Hamburger de Polycarpus". The length of the string doesn't exceed 100, the string contains only letters 'B' (uppercase English B), 'S' (uppercase English S) and 'C' (uppercase English C).
The second line contains three integers *n**b*, *n**s*, *n**c* (1<=≤<=*n**b*,<=*n**s*,<=*n**c*<=≤<=100) — the number of the pieces of bread, sausage and cheese on Polycarpus' kitchen. The third line contains three integers *p**b*, *p**s*, *p**c* (1<=≤<=*p**b*,<=*p**s*,<=*p**c*<=≤<=100) — the price of one piece of bread, sausage and cheese in the shop. Finally, the fourth line contains integer *r* (1<=≤<=*r*<=≤<=1012) — the number of rubles Polycarpus has.
Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output Specification:
Print the maximum number of hamburgers Polycarpus can make. If he can't make any hamburger, print 0.
Demo Input:
['BBBSSC\n6 4 1\n1 2 3\n4\n', 'BBC\n1 10 1\n1 10 1\n21\n', 'BSC\n1 1 1\n1 1 3\n1000000000000\n']
Demo Output:
['2\n', '7\n', '200000000001\n']
Note:
none
|
```python
def check(mid,p,n,b,s,c,m):
cost = 0
cost+=max(0,b*mid-n[0])*p[0]
cost+=max(0,s*mid-n[1])*p[1]
cost+=max(0,c*mid-n[2])*p[2]
return cost<=m
st = input()
n = list(map(int,input().split(" ")))
p = list(map(int,input().split(" ")))
m = int(input())
b = 0
c = 0
s = 0
for i in st:
if i=="B":
b+=1
elif i=="S":
s+=1
else:
c+=1
l = 0
h = 1000000000000
while l<=h:
mid = (l+h+1)//2
if check(mid,p,n,b,s,c,m):
l = mid+1
else:
h = mid-1
print(mid)
```
| 0
|
|
27
|
E
|
Number With The Given Amount Of Divisors
|
PROGRAMMING
| 2,000
|
[
"brute force",
"dp",
"number theory"
] |
E. Number With The Given Amount Of Divisors
|
2
|
256
|
Given the number *n*, find the smallest positive integer which has exactly *n* divisors. It is guaranteed that for the given *n* the answer will not exceed 1018.
|
The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=1000).
|
Output the smallest positive integer with exactly *n* divisors.
|
[
"4\n",
"6\n"
] |
[
"6\n",
"12\n"
] |
none
| 2,500
|
[
{
"input": "1",
"output": "1"
},
{
"input": "7",
"output": "64"
},
{
"input": "8",
"output": "24"
},
{
"input": "9",
"output": "36"
},
{
"input": "10",
"output": "48"
},
{
"input": "15",
"output": "144"
},
{
"input": "20",
"output": "240"
},
{
"input": "47",
"output": "70368744177664"
},
{
"input": "59",
"output": "288230376151711744"
},
{
"input": "100",
"output": "45360"
},
{
"input": "159",
"output": "40532396646334464"
},
{
"input": "265",
"output": "364791569817010176"
},
{
"input": "312",
"output": "14192640"
},
{
"input": "473",
"output": "259700248434180096"
},
{
"input": "637",
"output": "46656000000"
},
{
"input": "500",
"output": "62370000"
},
{
"input": "720",
"output": "61261200"
},
{
"input": "902",
"output": "324625310542725120"
},
{
"input": "940",
"output": "199495389743677440"
},
{
"input": "1000",
"output": "810810000"
},
{
"input": "999",
"output": "757632231014400"
},
{
"input": "118",
"output": "864691128455135232"
}
] | 1,654,201,275
| 2,147,483,647
|
PyPy 3
|
WRONG_ANSWER
|
TESTS
| 7
| 154
| 4,608,000
|
x=int(input())
# 素因数分解
import math
L=int(math.sqrt(x))
FACT=dict()
for i in range(2,L+2):
while x%i==0:
FACT[i]=FACT.get(i,0)+1
x=x//i
if x!=1:
FACT[x]=FACT.get(x,0)+1
x=10**5
import math
L=math.floor(math.sqrt(x)) # 平方根を求める
Primelist=[i for i in range(x+1)]
Primelist[1]=0 # 1は素数でないので0にする.
for i in Primelist:
if i>L:
break
if i==0:
continue
for j in range(2*i,x+1,i):
Primelist[j]=0
Primes=[Primelist[j] for j in range(x+1) if Primelist[j]!=0]
X=[]
for f in FACT:
X+=[f]*FACT[f]
X.sort(reverse=True)
def calc(X,now):
if len(X)==0:
return 1
ANS=10**18
LEN=len(X)
for i in range(1,1<<LEN):
plus=1
for j in range(LEN):
if i & (1<<j) != 0:
plus*=X[j]
if plus>40:
break
if plus<=40:
Y=[]
for j in range(LEN):
if i & (1<<j) == 0:
Y.append(X[j])
ANS=min(ANS,calc(tuple(Y),now+1)*(Primes[now]**(plus-1)))
return ANS
print(calc(tuple(X),0))
|
Title: Number With The Given Amount Of Divisors
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Given the number *n*, find the smallest positive integer which has exactly *n* divisors. It is guaranteed that for the given *n* the answer will not exceed 1018.
Input Specification:
The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=1000).
Output Specification:
Output the smallest positive integer with exactly *n* divisors.
Demo Input:
['4\n', '6\n']
Demo Output:
['6\n', '12\n']
Note:
none
|
```python
x=int(input())
# 素因数分解
import math
L=int(math.sqrt(x))
FACT=dict()
for i in range(2,L+2):
while x%i==0:
FACT[i]=FACT.get(i,0)+1
x=x//i
if x!=1:
FACT[x]=FACT.get(x,0)+1
x=10**5
import math
L=math.floor(math.sqrt(x)) # 平方根を求める
Primelist=[i for i in range(x+1)]
Primelist[1]=0 # 1は素数でないので0にする.
for i in Primelist:
if i>L:
break
if i==0:
continue
for j in range(2*i,x+1,i):
Primelist[j]=0
Primes=[Primelist[j] for j in range(x+1) if Primelist[j]!=0]
X=[]
for f in FACT:
X+=[f]*FACT[f]
X.sort(reverse=True)
def calc(X,now):
if len(X)==0:
return 1
ANS=10**18
LEN=len(X)
for i in range(1,1<<LEN):
plus=1
for j in range(LEN):
if i & (1<<j) != 0:
plus*=X[j]
if plus>40:
break
if plus<=40:
Y=[]
for j in range(LEN):
if i & (1<<j) == 0:
Y.append(X[j])
ANS=min(ANS,calc(tuple(Y),now+1)*(Primes[now]**(plus-1)))
return ANS
print(calc(tuple(X),0))
```
| 0
|
886
|
B
|
Vlad and Cafes
|
PROGRAMMING
| 1,000
|
[] | null | null |
Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research.
First of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes he visited in a row, in order of visiting them. Now, Vlad wants to find such a cafe that his last visit to that cafe was before his last visits to every other cafe. In other words, he wants to find such a cafe that he hasn't been there for as long as possible. Help Vlad to find that cafe.
|
In first line there is one integer *n* (1<=≤<=*n*<=≤<=2·105) — number of cafes indices written by Vlad.
In second line, *n* numbers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=2·105) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, some indices could be omitted.
|
Print one integer — index of the cafe that Vlad hasn't visited for as long as possible.
|
[
"5\n1 3 2 1 2\n",
"6\n2 1 2 2 4 1\n"
] |
[
"3\n",
"2\n"
] |
In first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer.
In second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with index 2, so the answer is 2. Note that Vlad could omit some numbers while numerating the cafes.
| 1,000
|
[
{
"input": "5\n1 3 2 1 2",
"output": "3"
},
{
"input": "6\n2 1 2 2 4 1",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n200000",
"output": "200000"
},
{
"input": "2\n2018 2017",
"output": "2018"
},
{
"input": "5\n100 1000 1000 1000 1000",
"output": "100"
},
{
"input": "8\n200000 1 200000 1 200000 1 200000 2",
"output": "1"
},
{
"input": "5\n20000 1 2 3 4",
"output": "20000"
},
{
"input": "2\n200000 1",
"output": "200000"
},
{
"input": "3\n2 100 2",
"output": "100"
},
{
"input": "2\n10 1",
"output": "10"
},
{
"input": "11\n1 1 1 1 1 1 1 1 1 1 1",
"output": "1"
},
{
"input": "3\n5 5 5",
"output": "5"
},
{
"input": "2\n5 1",
"output": "5"
}
] | 1,618,942,615
| 2,147,483,647
|
PyPy 3
|
OK
|
TESTS
| 33
| 249
| 20,377,600
|
n = int(input())
a = list(map(int, input().split()))
myset = set()
ans = a[-1]
for x in a[::-1]:
if x not in myset:
ans = x
myset.add(x)
print(ans)
|
Title: Vlad and Cafes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research.
First of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes he visited in a row, in order of visiting them. Now, Vlad wants to find such a cafe that his last visit to that cafe was before his last visits to every other cafe. In other words, he wants to find such a cafe that he hasn't been there for as long as possible. Help Vlad to find that cafe.
Input Specification:
In first line there is one integer *n* (1<=≤<=*n*<=≤<=2·105) — number of cafes indices written by Vlad.
In second line, *n* numbers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=2·105) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, some indices could be omitted.
Output Specification:
Print one integer — index of the cafe that Vlad hasn't visited for as long as possible.
Demo Input:
['5\n1 3 2 1 2\n', '6\n2 1 2 2 4 1\n']
Demo Output:
['3\n', '2\n']
Note:
In first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer.
In second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with index 2, so the answer is 2. Note that Vlad could omit some numbers while numerating the cafes.
|
```python
n = int(input())
a = list(map(int, input().split()))
myset = set()
ans = a[-1]
for x in a[::-1]:
if x not in myset:
ans = x
myset.add(x)
print(ans)
```
| 3
|
|
764
|
A
|
Taymyr is calling you
|
PROGRAMMING
| 800
|
[
"brute force",
"implementation",
"math"
] | null | null |
Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long, i.e. the day consists of minutes 1,<=2,<=...,<=*z*. How many artists should be killed so that there are no artists in the room when Ilia calls? Consider that a call and a talk with an artist take exactly one minute.
|
The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104).
|
Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls.
|
[
"1 1 10\n",
"1 2 5\n",
"2 3 9\n"
] |
[
"10\n",
"2\n",
"1\n"
] |
Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute.
| 500
|
[
{
"input": "1 1 10",
"output": "10"
},
{
"input": "1 2 5",
"output": "2"
},
{
"input": "2 3 9",
"output": "1"
},
{
"input": "4 8 9",
"output": "1"
},
{
"input": "7 9 2",
"output": "0"
},
{
"input": "10000 10000 10000",
"output": "1"
},
{
"input": "24 22 9235",
"output": "34"
},
{
"input": "74 8 417",
"output": "1"
},
{
"input": "972 1 203",
"output": "0"
},
{
"input": "550 1 754",
"output": "1"
},
{
"input": "860 1 884",
"output": "1"
},
{
"input": "358 2 809",
"output": "2"
},
{
"input": "33 27 216",
"output": "0"
},
{
"input": "2940 1 9311",
"output": "3"
},
{
"input": "4624 1 1953",
"output": "0"
},
{
"input": "2696 2 7345",
"output": "2"
},
{
"input": "3443 2 6701",
"output": "0"
},
{
"input": "3 613 2275",
"output": "1"
},
{
"input": "1 10000 10000",
"output": "1"
},
{
"input": "10000 1 10000",
"output": "1"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 1 10000",
"output": "10000"
},
{
"input": "34 27 10000",
"output": "10"
},
{
"input": "2 2 9999",
"output": "4999"
},
{
"input": "2 2 1",
"output": "0"
},
{
"input": "6 4 36",
"output": "3"
},
{
"input": "33 6 3005",
"output": "45"
},
{
"input": "5 1 20",
"output": "4"
},
{
"input": "1 2 10",
"output": "5"
},
{
"input": "2 1 100",
"output": "50"
},
{
"input": "10 20 10000",
"output": "500"
},
{
"input": "8 12 12",
"output": "0"
}
] | 1,566,247,950
| 2,147,483,647
|
PyPy 3
|
WRONG_ANSWER
|
TESTS
| 0
| 108
| 0
|
import math
n, m, z = [int(s) for s in input().split()]
ans = math.modf(z/m)
print(ans[1])
|
Title: Taymyr is calling you
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long, i.e. the day consists of minutes 1,<=2,<=...,<=*z*. How many artists should be killed so that there are no artists in the room when Ilia calls? Consider that a call and a talk with an artist take exactly one minute.
Input Specification:
The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104).
Output Specification:
Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls.
Demo Input:
['1 1 10\n', '1 2 5\n', '2 3 9\n']
Demo Output:
['10\n', '2\n', '1\n']
Note:
Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute.
|
```python
import math
n, m, z = [int(s) for s in input().split()]
ans = math.modf(z/m)
print(ans[1])
```
| 0
|
|
339
|
A
|
Helpful Maths
|
PROGRAMMING
| 800
|
[
"greedy",
"implementation",
"sortings",
"strings"
] | null | null |
Xenia the beginner mathematician is a third year student at elementary school. She is now learning the addition operation.
The teacher has written down the sum of multiple numbers. Pupils should calculate the sum. To make the calculation easier, the sum only contains numbers 1, 2 and 3. Still, that isn't enough for Xenia. She is only beginning to count, so she can calculate a sum only if the summands follow in non-decreasing order. For example, she can't calculate sum 1+3+2+1 but she can calculate sums 1+1+2 and 3+3.
You've got the sum that was written on the board. Rearrange the summans and print the sum in such a way that Xenia can calculate the sum.
|
The first line contains a non-empty string *s* — the sum Xenia needs to count. String *s* contains no spaces. It only contains digits and characters "+". Besides, string *s* is a correct sum of numbers 1, 2 and 3. String *s* is at most 100 characters long.
|
Print the new sum that Xenia can count.
|
[
"3+2+1\n",
"1+1+3+1+3\n",
"2\n"
] |
[
"1+2+3\n",
"1+1+1+3+3\n",
"2\n"
] |
none
| 500
|
[
{
"input": "3+2+1",
"output": "1+2+3"
},
{
"input": "1+1+3+1+3",
"output": "1+1+1+3+3"
},
{
"input": "2",
"output": "2"
},
{
"input": "2+2+1+1+3",
"output": "1+1+2+2+3"
},
{
"input": "2+1+2+2+2+3+1+3+1+2",
"output": "1+1+1+2+2+2+2+2+3+3"
},
{
"input": "1+2+1+2+2+2+2+1+3+3",
"output": "1+1+1+2+2+2+2+2+3+3"
},
{
"input": "2+3+3+1+2+2+2+1+1+2+1+3+2+2+3+3+2+2+3+3+3+1+1+1+3+3+3+2+1+3+2+3+2+1+1+3+3+3+1+2+2+1+2+2+1+2+1+3+1+1",
"output": "1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3"
},
{
"input": "1",
"output": "1"
},
{
"input": "2+1+2+2+1+3+2+3+1+1+2+1+2+2+3+1+1+3+3+3+2+2+3+2+2+2+1+2+1+2+3+2+2+2+1+3+1+3+3+3+1+2+1+2+2+2+2+3+1+1",
"output": "1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+3+3+3+3+3+3+3+3+3+3+3+3+3"
},
{
"input": "2+2+1+1+1+3+1+1+3+3+2+3+1+3+1+1+3+1+1+2+2+2+2+1+2+1+2+1+1+1+3+1+3+2+3+2+3+3+1+1+1+2+3+2+1+3+1+3+2+2",
"output": "1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+3+3+3+3+3+3+3+3+3+3+3+3+3+3"
},
{
"input": "3+2+3+3+2+2+1+2+1+2+3+1+2+3+2+3+2+1+2+2+1+1+2+2+3+2+1+3+1+1+3+2+2+2+2+3+3+2+2+3+3+1+1+2+3+3+2+3+3+3",
"output": "1+1+1+1+1+1+1+1+1+1+1+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3"
},
{
"input": "3",
"output": "3"
},
{
"input": "1+1",
"output": "1+1"
},
{
"input": "1+2",
"output": "1+2"
},
{
"input": "1+3",
"output": "1+3"
},
{
"input": "2+1",
"output": "1+2"
},
{
"input": "2+2",
"output": "2+2"
},
{
"input": "2+3",
"output": "2+3"
},
{
"input": "3+1",
"output": "1+3"
},
{
"input": "3+2",
"output": "2+3"
},
{
"input": "3+3",
"output": "3+3"
}
] | 1,699,775,931
| 2,147,483,647
|
Python 3
|
WRONG_ANSWER
|
TESTS
| 0
| 62
| 0
|
s=list((input().split('+')))
s=[int(i) for i in s]
ans=""
s.sort()
print(s)
for i in range(len(s)):
ans+=str(s[i])
ans+='+'
print(ans[:-1])
|
Title: Helpful Maths
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the beginner mathematician is a third year student at elementary school. She is now learning the addition operation.
The teacher has written down the sum of multiple numbers. Pupils should calculate the sum. To make the calculation easier, the sum only contains numbers 1, 2 and 3. Still, that isn't enough for Xenia. She is only beginning to count, so she can calculate a sum only if the summands follow in non-decreasing order. For example, she can't calculate sum 1+3+2+1 but she can calculate sums 1+1+2 and 3+3.
You've got the sum that was written on the board. Rearrange the summans and print the sum in such a way that Xenia can calculate the sum.
Input Specification:
The first line contains a non-empty string *s* — the sum Xenia needs to count. String *s* contains no spaces. It only contains digits and characters "+". Besides, string *s* is a correct sum of numbers 1, 2 and 3. String *s* is at most 100 characters long.
Output Specification:
Print the new sum that Xenia can count.
Demo Input:
['3+2+1\n', '1+1+3+1+3\n', '2\n']
Demo Output:
['1+2+3\n', '1+1+1+3+3\n', '2\n']
Note:
none
|
```python
s=list((input().split('+')))
s=[int(i) for i in s]
ans=""
s.sort()
print(s)
for i in range(len(s)):
ans+=str(s[i])
ans+='+'
print(ans[:-1])
```
| 0
|
|
702
|
A
|
Maximum Increase
|
PROGRAMMING
| 800
|
[
"dp",
"greedy",
"implementation"
] | null | null |
You are given array consisting of *n* integers. Your task is to find the maximum length of an increasing subarray of the given array.
A subarray is the sequence of consecutive elements of the array. Subarray is called increasing if each element of this subarray strictly greater than previous.
|
The first line contains single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of integers.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109).
|
Print the maximum length of an increasing subarray of the given array.
|
[
"5\n1 7 2 11 15\n",
"6\n100 100 100 100 100 100\n",
"3\n1 2 3\n"
] |
[
"3\n",
"1\n",
"3\n"
] |
none
| 0
|
[
{
"input": "5\n1 7 2 11 15",
"output": "3"
},
{
"input": "6\n100 100 100 100 100 100",
"output": "1"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "1\n1000000000",
"output": "1"
},
{
"input": "10\n802030518 598196518 640274071 983359971 71550121 96204862 799843967 446173607 796619138 402690754",
"output": "3"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "5\n1 2 3 3 4",
"output": "3"
},
{
"input": "4\n1 2 2 3",
"output": "2"
},
{
"input": "3\n2 1 1",
"output": "1"
},
{
"input": "3\n1 2 1",
"output": "2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 1 2",
"output": "2"
},
{
"input": "11\n1 2 3 1 2 3 2 1 2 3 4",
"output": "4"
},
{
"input": "9\n1 2 3 4 5 6 7 8 9",
"output": "9"
},
{
"input": "9\n1 1 1 1 1 1 1 1 1",
"output": "1"
},
{
"input": "3\n3 2 1",
"output": "1"
},
{
"input": "7\n1 2 3 4 5 6 7",
"output": "7"
},
{
"input": "1\n1234394",
"output": "1"
}
] | 1,678,829,899
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 32
| 93
| 7,884,800
|
n=int(input())
l=list(map(int,input().split()))
m=1
out=1
for i in range(n-1):
if l[i+1]>l[i]:
m+=1
else:
if m>out:
m,out=out,m
m=1
if m>out:
m,out=out,m
print(out)
|
Title: Maximum Increase
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given array consisting of *n* integers. Your task is to find the maximum length of an increasing subarray of the given array.
A subarray is the sequence of consecutive elements of the array. Subarray is called increasing if each element of this subarray strictly greater than previous.
Input Specification:
The first line contains single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of integers.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109).
Output Specification:
Print the maximum length of an increasing subarray of the given array.
Demo Input:
['5\n1 7 2 11 15\n', '6\n100 100 100 100 100 100\n', '3\n1 2 3\n']
Demo Output:
['3\n', '1\n', '3\n']
Note:
none
|
```python
n=int(input())
l=list(map(int,input().split()))
m=1
out=1
for i in range(n-1):
if l[i+1]>l[i]:
m+=1
else:
if m>out:
m,out=out,m
m=1
if m>out:
m,out=out,m
print(out)
```
| 3
|
|
237
|
A
|
Free Cash
|
PROGRAMMING
| 1,000
|
[
"implementation"
] | null | null |
Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends less than a minute to serve each client, but if a client comes in and sees that there is no free cash, than he doesn't want to wait and leaves the cafe immediately.
Valera is very greedy, so he wants to serve all *n* customers next day (and get more profit). However, for that he needs to ensure that at each moment of time the number of working cashes is no less than the number of clients in the cafe.
Help Valera count the minimum number of cashes to work at his cafe next day, so that they can serve all visitors.
|
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), that is the number of cafe visitors.
Each of the following *n* lines has two space-separated integers *h**i* and *m**i* (0<=≤<=*h**i*<=≤<=23; 0<=≤<=*m**i*<=≤<=59), representing the time when the *i*-th person comes into the cafe.
Note that the time is given in the chronological order. All time is given within one 24-hour period.
|
Print a single integer — the minimum number of cashes, needed to serve all clients next day.
|
[
"4\n8 0\n8 10\n8 10\n8 45\n",
"3\n0 12\n10 11\n22 22\n"
] |
[
"2\n",
"1\n"
] |
In the first sample it is not enough one cash to serve all clients, because two visitors will come into cafe in 8:10. Therefore, if there will be one cash in cafe, then one customer will be served by it, and another one will not wait and will go away.
In the second sample all visitors will come in different times, so it will be enough one cash.
| 500
|
[
{
"input": "4\n8 0\n8 10\n8 10\n8 45",
"output": "2"
},
{
"input": "3\n0 12\n10 11\n22 22",
"output": "1"
},
{
"input": "5\n12 8\n15 27\n15 27\n16 2\n19 52",
"output": "2"
},
{
"input": "7\n5 6\n7 34\n7 34\n7 34\n12 29\n15 19\n20 23",
"output": "3"
},
{
"input": "8\n0 36\n4 7\n4 7\n4 7\n11 46\n12 4\n15 39\n18 6",
"output": "3"
},
{
"input": "20\n4 12\n4 21\n4 27\n4 56\n5 55\n7 56\n11 28\n11 36\n14 58\n15 59\n16 8\n17 12\n17 23\n17 23\n17 23\n17 23\n17 23\n17 23\n20 50\n22 32",
"output": "6"
},
{
"input": "10\n1 30\n1 30\n1 30\n1 30\n1 30\n1 30\n1 30\n1 30\n1 30\n1 30",
"output": "10"
},
{
"input": "50\n0 23\n1 21\n2 8\n2 45\n3 1\n4 19\n4 37\n7 7\n7 40\n8 43\n9 51\n10 13\n11 2\n11 19\n11 30\n12 37\n12 37\n12 37\n12 37\n12 37\n12 37\n12 37\n12 37\n12 54\n13 32\n13 42\n14 29\n14 34\n14 48\n15 0\n15 27\n16 22\n16 31\n17 25\n17 26\n17 33\n18 14\n18 16\n18 20\n19 0\n19 5\n19 56\n20 22\n21 26\n22 0\n22 10\n22 11\n22 36\n23 17\n23 20",
"output": "8"
},
{
"input": "10\n0 39\n1 35\n1 49\n1 51\n5 24\n7 40\n7 56\n16 42\n23 33\n23 49",
"output": "1"
},
{
"input": "15\n0 16\n6 15\n8 2\n8 6\n8 7\n10 1\n10 1\n10 3\n10 12\n13 5\n14 16\n14 16\n14 16\n14 16\n14 16",
"output": "5"
},
{
"input": "2\n0 24\n1 0",
"output": "1"
},
{
"input": "1\n0 0",
"output": "1"
},
{
"input": "1\n1 5",
"output": "1"
},
{
"input": "1\n1 1",
"output": "1"
},
{
"input": "3\n0 0\n0 0\n0 0",
"output": "3"
},
{
"input": "1\n5 0",
"output": "1"
},
{
"input": "5\n0 0\n0 0\n0 0\n0 0\n0 0",
"output": "5"
},
{
"input": "1\n10 10",
"output": "1"
},
{
"input": "1\n8 0",
"output": "1"
},
{
"input": "10\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0",
"output": "10"
},
{
"input": "2\n0 0\n0 1",
"output": "1"
},
{
"input": "2\n8 5\n8 5",
"output": "2"
}
] | 1,687,945,462
| 2,147,483,647
|
PyPy 3-64
|
OK
|
TESTS
| 67
| 1,808
| 12,492,800
|
d={}
arr=[]
sum=1
for _ in range(int(input())):
h,m=map(int,input().split())
if h not in arr :
arr.append(h)
d[h]=[]
d[h].append(m)
else:
d[h].append(m)
# print(d)
for i in arr:
temp=d[i]
# print(temp)
temp1=set(temp)
# print(temp1)
for j in temp1:
if temp.count(j)>sum:
sum=temp.count(j)
print(sum)
|
Title: Free Cash
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends less than a minute to serve each client, but if a client comes in and sees that there is no free cash, than he doesn't want to wait and leaves the cafe immediately.
Valera is very greedy, so he wants to serve all *n* customers next day (and get more profit). However, for that he needs to ensure that at each moment of time the number of working cashes is no less than the number of clients in the cafe.
Help Valera count the minimum number of cashes to work at his cafe next day, so that they can serve all visitors.
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), that is the number of cafe visitors.
Each of the following *n* lines has two space-separated integers *h**i* and *m**i* (0<=≤<=*h**i*<=≤<=23; 0<=≤<=*m**i*<=≤<=59), representing the time when the *i*-th person comes into the cafe.
Note that the time is given in the chronological order. All time is given within one 24-hour period.
Output Specification:
Print a single integer — the minimum number of cashes, needed to serve all clients next day.
Demo Input:
['4\n8 0\n8 10\n8 10\n8 45\n', '3\n0 12\n10 11\n22 22\n']
Demo Output:
['2\n', '1\n']
Note:
In the first sample it is not enough one cash to serve all clients, because two visitors will come into cafe in 8:10. Therefore, if there will be one cash in cafe, then one customer will be served by it, and another one will not wait and will go away.
In the second sample all visitors will come in different times, so it will be enough one cash.
|
```python
d={}
arr=[]
sum=1
for _ in range(int(input())):
h,m=map(int,input().split())
if h not in arr :
arr.append(h)
d[h]=[]
d[h].append(m)
else:
d[h].append(m)
# print(d)
for i in arr:
temp=d[i]
# print(temp)
temp1=set(temp)
# print(temp1)
for j in temp1:
if temp.count(j)>sum:
sum=temp.count(j)
print(sum)
```
| 3
|
|
41
|
A
|
Translation
|
PROGRAMMING
| 800
|
[
"implementation",
"strings"
] |
A. Translation
|
2
|
256
|
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word *s* from Berlandish into Birlandish as *t*. Help him: find out if he translated the word correctly.
|
The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
|
If the word *t* is a word *s*, written reversely, print YES, otherwise print NO.
|
[
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] |
[
"YES\n",
"NO\n",
"NO\n"
] |
none
| 500
|
[
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk\nasrgdfngfnmfgnhweratgjkk",
"output": "NO"
},
{
"input": "z\na",
"output": "NO"
},
{
"input": "asd\ndsa",
"output": "YES"
},
{
"input": "abcdef\nfecdba",
"output": "NO"
},
{
"input": "ywjjbirapvskozubvxoemscfwl\ngnduubaogtfaiowjizlvjcu",
"output": "NO"
},
{
"input": "mfrmqxtzvgaeuleubcmcxcfqyruwzenguhgrmkuhdgnhgtgkdszwqyd\nmfxufheiperjnhyczclkmzyhcxntdfskzkzdwzzujdinf",
"output": "NO"
},
{
"input": "bnbnemvybqizywlnghlykniaxxxlkhftppbdeqpesrtgkcpoeqowjwhrylpsziiwcldodcoonpimudvrxejjo\ntiynnekmlalogyvrgptbinkoqdwzuiyjlrldxhzjmmp",
"output": "NO"
},
{
"input": "pwlpubwyhzqvcitemnhvvwkmwcaawjvdiwtoxyhbhbxerlypelevasmelpfqwjk\nstruuzebbcenziscuoecywugxncdwzyfozhljjyizpqcgkyonyetarcpwkqhuugsqjuixsxptmbnlfupdcfigacdhhrzb",
"output": "NO"
},
{
"input": "gdvqjoyxnkypfvdxssgrihnwxkeojmnpdeobpecytkbdwujqfjtxsqspxvxpqioyfagzjxupqqzpgnpnpxcuipweunqch\nkkqkiwwasbhezqcfeceyngcyuogrkhqecwsyerdniqiocjehrpkljiljophqhyaiefjpavoom",
"output": "NO"
},
{
"input": "umeszdawsvgkjhlqwzents\nhxqhdungbylhnikwviuh",
"output": "NO"
},
{
"input": "juotpscvyfmgntshcealgbsrwwksgrwnrrbyaqqsxdlzhkbugdyx\nibqvffmfktyipgiopznsqtrtxiijntdbgyy",
"output": "NO"
},
{
"input": "zbwueheveouatecaglziqmudxemhrsozmaujrwlqmppzoumxhamwugedikvkblvmxwuofmpafdprbcftew\nulczwrqhctbtbxrhhodwbcxwimncnexosksujlisgclllxokrsbnozthajnnlilyffmsyko",
"output": "NO"
},
{
"input": "nkgwuugukzcv\nqktnpxedwxpxkrxdvgmfgoxkdfpbzvwsduyiybynbkouonhvmzakeiruhfmvrktghadbfkmwxduoqv",
"output": "NO"
},
{
"input": "incenvizhqpcenhjhehvjvgbsnfixbatrrjstxjzhlmdmxijztphxbrldlqwdfimweepkggzcxsrwelodpnryntepioqpvk\ndhjbjjftlvnxibkklxquwmzhjfvnmwpapdrslioxisbyhhfymyiaqhlgecpxamqnocizwxniubrmpyubvpenoukhcobkdojlybxd",
"output": "NO"
},
{
"input": "w\nw",
"output": "YES"
},
{
"input": "vz\nzv",
"output": "YES"
},
{
"input": "ry\nyr",
"output": "YES"
},
{
"input": "xou\nuox",
"output": "YES"
},
{
"input": "axg\ngax",
"output": "NO"
},
{
"input": "zdsl\nlsdz",
"output": "YES"
},
{
"input": "kudl\nldku",
"output": "NO"
},
{
"input": "zzlzwnqlcl\nlclqnwzlzz",
"output": "YES"
},
{
"input": "vzzgicnzqooejpjzads\nsdazjpjeooqzncigzzv",
"output": "YES"
},
{
"input": "raqhmvmzuwaykjpyxsykr\nxkysrypjkyawuzmvmhqar",
"output": "NO"
},
{
"input": "ngedczubzdcqbxksnxuavdjaqtmdwncjnoaicvmodcqvhfezew\nwezefhvqcdomvciaonjcnwdmtqajdvauxnskxbqcdzbuzcdegn",
"output": "YES"
},
{
"input": "muooqttvrrljcxbroizkymuidvfmhhsjtumksdkcbwwpfqdyvxtrlymofendqvznzlmim\nmimlznzvqdnefomylrtxvydqfpwwbckdskmutjshhmfvdiumykziorbxcjlrrvttqooum",
"output": "YES"
},
{
"input": "vxpqullmcbegsdskddortcvxyqlbvxmmkhevovnezubvpvnrcajpxraeaxizgaowtfkzywvhnbgzsxbhkaipcmoumtikkiyyaivg\ngviayyikkitmuomcpiakhbxszgbnhvwyzkftwoagzixaearxpjacrnvpvbuzenvovehkmmxvblqyxvctroddksdsgebcmlluqpxv",
"output": "YES"
},
{
"input": "mnhaxtaopjzrkqlbroiyipitndczpunwygstmzevgyjdzyanxkdqnvgkikfabwouwkkbzuiuvgvxgpizsvqsbwepktpdrgdkmfdc\ncdfmkdgrdptkpewbsqvszipgxvgvuiuzbkkwuowbafkikgvnqdkxnayzdjygvezmtsgywnupocdntipiyiorblqkrzjpzatxahnm",
"output": "NO"
},
{
"input": "dgxmzbqofstzcdgthbaewbwocowvhqpinehpjatnnbrijcolvsatbblsrxabzrpszoiecpwhfjmwuhqrapvtcgvikuxtzbftydkw\nwkdytfbztxukivgctvparqhuwmjfhwpceiozsprzbaxrslbbqasvlocjirbnntajphenipthvwocowbweabhtgdcztsfoqbzmxgd",
"output": "NO"
},
{
"input": "gxoixiecetohtgjgbqzvlaobkhstejxdklghowtvwunnnvauriohuspsdmpzckprwajyxldoyckgjivjpmbfqtszmtocovxwgeh\nhegwxvocotmzstqfbmpjvijgkcyodlxyjawrpkczpmdspsuhoiruavnnnuwvtwohglkdxjetshkboalvzqbgjgthoteceixioxg",
"output": "YES"
},
{
"input": "sihxuwvmaambplxvjfoskinghzicyfqebjtkysotattkahssumfcgrkheotdxwjckpvapbkaepqrxseyfrwtyaycmrzsrsngkh\nhkgnsrszrmcyaytwrfyesxrqpeakbpavpkcjwxdtoehkrgcfmusshakttatosyktjbeqfycizhgniksofjvxlpbmaamvwuxhis",
"output": "YES"
},
{
"input": "ycnahksbughnonldzrhkysujmylcgcfuludjvjiahtkyzqvkopzqcnwhltbzfugzojqkjjlggmvnultascmygelkiktmfieok\nkoeifmtkiklegkmcsatlunvmggkjjlqjozgufzbtlhwncqzpokvqzykthaijvjdulufcgclymjusyyhrzdlnonhgubskhancy",
"output": "NO"
},
{
"input": "wbqasaehtkfojruzyhrlgwmtyiovmzyfifslvlemhqheyaelzwnthrenjsbmntwaoryzwfbxmscmypvxlfmzpnkkjlvwvmtz\nztmvwvljkknpzmflxvpymcsmxbfwzyroawtnmbsjnerhtnwzleayehqhmelvlsfifyzmvoiytmwglrhyzurjofktheasaqbw",
"output": "YES"
},
{
"input": "imippqurprbhfugngtgifelytadegwrgaefnfhbjjnmzikvjaccotqzemufqieqldgnbmviisgkynzeldlhqxuqphjfmyij\njiymfjhpquxqhldleznykgsiivmbngdlqeiqfumezqtoccajvkizmnjjbhfnfeagrwgedatylefigtgngufhbrpruqppimi",
"output": "YES"
},
{
"input": "bikydffiuisckpvzqlteqfhegsagimodb\nbdomigasgehfqetlqzvpkcsiuiffdykib",
"output": "YES"
}
] | 1,603,642,829
| 2,147,483,647
|
Python 3
|
OK
|
TESTS
| 40
| 248
| 0
|
s = input("")
n = input("")
stxt = s[::-1]
if stxt == n:
print("YES")
else:
print("NO")
|
Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word *s* from Berlandish into Birlandish as *t*. Help him: find out if he translated the word correctly.
Input Specification:
The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
Output Specification:
If the word *t* is a word *s*, written reversely, print YES, otherwise print NO.
Demo Input:
['code\nedoc\n', 'abb\naba\n', 'code\ncode\n']
Demo Output:
['YES\n', 'NO\n', 'NO\n']
Note:
none
|
```python
s = input("")
n = input("")
stxt = s[::-1]
if stxt == n:
print("YES")
else:
print("NO")
```
| 3.938
|
868
|
C
|
Qualification Rounds
|
PROGRAMMING
| 1,500
|
[
"bitmasks",
"brute force",
"constructive algorithms",
"dp"
] | null | null |
Snark and Philip are preparing the problemset for the upcoming pre-qualification round for semi-quarter-finals. They have a bank of *n* problems, and they want to select any non-empty subset of it as a problemset.
*k* experienced teams are participating in the contest. Some of these teams already know some of the problems. To make the contest interesting for them, each of the teams should know at most half of the selected problems.
Determine if Snark and Philip can make an interesting problemset!
|
The first line contains two integers *n*, *k* (1<=≤<=*n*<=≤<=105, 1<=≤<=*k*<=≤<=4) — the number of problems and the number of experienced teams.
Each of the next *n* lines contains *k* integers, each equal to 0 or 1. The *j*-th number in the *i*-th line is 1 if *j*-th team knows *i*-th problem and 0 otherwise.
|
Print "YES" (quotes for clarity), if it is possible to make an interesting problemset, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES").
|
[
"5 3\n1 0 1\n1 1 0\n1 0 0\n1 0 0\n1 0 0\n",
"3 2\n1 0\n1 1\n0 1\n"
] |
[
"NO\n",
"YES\n"
] |
In the first example you can't make any interesting problemset, because the first team knows all problems.
In the second example you can choose the first and the third problems.
| 1,000
|
[
{
"input": "5 3\n1 0 1\n1 1 0\n1 0 0\n1 0 0\n1 0 0",
"output": "NO"
},
{
"input": "3 2\n1 0\n1 1\n0 1",
"output": "YES"
},
{
"input": "10 2\n1 0\n1 0\n0 0\n1 1\n0 0\n1 1\n0 0\n1 1\n0 1\n0 1",
"output": "YES"
},
{
"input": "10 3\n1 0 0\n0 1 1\n1 0 0\n0 1 0\n0 0 1\n1 0 1\n0 1 1\n1 0 0\n1 1 0\n0 0 0",
"output": "YES"
},
{
"input": "10 4\n1 0 1 0\n1 0 0 1\n1 1 0 1\n1 0 1 1\n1 1 0 1\n1 0 1 0\n0 0 0 0\n0 0 1 0\n1 0 1 0\n0 0 1 1",
"output": "YES"
},
{
"input": "2 2\n0 0\n1 0",
"output": "YES"
},
{
"input": "3 3\n1 0 1\n1 0 0\n1 1 1",
"output": "NO"
},
{
"input": "4 4\n0 0 0 0\n1 1 0 0\n1 1 1 1\n1 0 1 1",
"output": "YES"
},
{
"input": "4 1\n1\n1\n0\n0",
"output": "YES"
},
{
"input": "1 4\n0 0 0 0",
"output": "YES"
},
{
"input": "3 3\n0 0 1\n0 1 1\n1 0 0",
"output": "YES"
},
{
"input": "2 3\n0 0 1\n1 0 0",
"output": "YES"
},
{
"input": "1 1\n0",
"output": "YES"
},
{
"input": "2 4\n0 1 1 1\n1 0 0 0",
"output": "YES"
},
{
"input": "2 4\n1 0 1 0\n0 1 0 1",
"output": "YES"
},
{
"input": "2 4\n1 0 0 0\n0 0 0 1",
"output": "YES"
},
{
"input": "2 3\n0 1 0\n0 0 1",
"output": "YES"
},
{
"input": "3 4\n1 0 1 0\n0 1 0 1\n1 1 1 1",
"output": "YES"
},
{
"input": "3 4\n0 0 1 1\n1 1 1 0\n1 1 0 1",
"output": "NO"
},
{
"input": "4 4\n0 0 0 1\n0 0 0 1\n0 0 1 0\n0 0 1 0",
"output": "YES"
},
{
"input": "2 4\n1 1 0 0\n0 0 1 1",
"output": "YES"
},
{
"input": "2 4\n1 0 0 0\n0 1 0 0",
"output": "YES"
},
{
"input": "2 3\n1 0 0\n0 0 1",
"output": "YES"
},
{
"input": "3 4\n1 0 1 0\n0 1 1 1\n1 0 0 0",
"output": "YES"
},
{
"input": "1 2\n0 0",
"output": "YES"
},
{
"input": "6 3\n0 1 1\n1 0 1\n1 1 1\n0 1 0\n1 0 1\n1 1 0",
"output": "YES"
},
{
"input": "1 4\n0 0 1 1",
"output": "NO"
},
{
"input": "3 3\n1 0 0\n0 1 0\n0 0 1",
"output": "YES"
},
{
"input": "3 4\n1 0 0 0\n1 1 0 0\n0 1 1 1",
"output": "YES"
},
{
"input": "3 2\n0 0\n0 0\n0 0",
"output": "YES"
},
{
"input": "2 4\n1 0 0 0\n1 0 1 1",
"output": "NO"
},
{
"input": "2 4\n0 0 0 1\n1 0 0 0",
"output": "YES"
},
{
"input": "2 4\n1 0 0 0\n0 1 1 1",
"output": "YES"
},
{
"input": "4 4\n1 1 1 1\n0 0 0 1\n0 0 1 1\n1 0 1 1",
"output": "NO"
},
{
"input": "6 3\n1 0 0\n1 1 1\n1 1 1\n0 1 0\n0 1 0\n1 0 0",
"output": "YES"
},
{
"input": "4 4\n0 1 0 0\n1 1 1 1\n1 1 1 1\n1 0 1 1",
"output": "YES"
},
{
"input": "1 3\n0 0 0",
"output": "YES"
},
{
"input": "3 3\n1 0 0\n0 1 0\n0 0 0",
"output": "YES"
},
{
"input": "2 4\n0 1 1 0\n0 0 0 0",
"output": "YES"
},
{
"input": "1 4\n0 0 0 1",
"output": "NO"
},
{
"input": "4 4\n0 0 0 1\n0 0 0 1\n0 0 1 1\n1 1 1 0",
"output": "YES"
},
{
"input": "2 3\n1 0 0\n0 1 1",
"output": "YES"
},
{
"input": "3 2\n0 1\n0 1\n1 0",
"output": "YES"
},
{
"input": "4 3\n1 1 0\n1 1 1\n0 0 1\n0 0 1",
"output": "YES"
},
{
"input": "2 1\n0\n0",
"output": "YES"
},
{
"input": "2 4\n1 1 1 0\n0 0 0 1",
"output": "YES"
},
{
"input": "5 4\n1 1 1 0\n1 1 0 1\n1 0 1 1\n0 1 1 1\n1 1 0 0",
"output": "NO"
},
{
"input": "3 4\n0 1 1 0\n0 1 0 1\n0 0 1 1",
"output": "NO"
},
{
"input": "1 1\n1",
"output": "NO"
},
{
"input": "3 4\n1 0 0 0\n1 0 0 0\n0 1 1 1",
"output": "YES"
},
{
"input": "2 3\n1 1 0\n0 0 1",
"output": "YES"
},
{
"input": "3 3\n0 0 1\n1 1 1\n1 1 0",
"output": "YES"
},
{
"input": "4 4\n0 1 1 1\n1 0 1 0\n1 1 0 1\n1 0 1 0",
"output": "NO"
},
{
"input": "3 3\n1 0 0\n0 0 0\n1 0 0",
"output": "YES"
},
{
"input": "3 4\n1 1 0 0\n1 1 0 0\n0 0 1 1",
"output": "YES"
},
{
"input": "2 4\n1 0 0 1\n0 0 1 0",
"output": "YES"
},
{
"input": "2 4\n0 0 1 1\n1 1 0 0",
"output": "YES"
},
{
"input": "2 3\n0 0 1\n0 1 0",
"output": "YES"
},
{
"input": "2 3\n1 0 0\n0 1 0",
"output": "YES"
},
{
"input": "3 2\n1 0\n0 1\n0 1",
"output": "YES"
},
{
"input": "3 4\n1 1 0 1\n0 0 1 1\n1 0 1 0",
"output": "NO"
},
{
"input": "3 4\n0 0 1 1\n0 1 1 0\n1 1 0 0",
"output": "YES"
},
{
"input": "3 4\n0 0 0 1\n0 0 0 1\n1 1 1 0",
"output": "YES"
},
{
"input": "3 4\n1 1 1 0\n1 1 0 1\n0 0 1 0",
"output": "YES"
},
{
"input": "8 4\n0 0 0 1\n0 0 1 1\n0 0 1 1\n0 0 1 1\n0 0 1 1\n0 0 1 1\n0 0 1 1\n1 1 1 0",
"output": "YES"
},
{
"input": "3 4\n1 0 1 1\n1 1 1 0\n0 1 0 1",
"output": "NO"
},
{
"input": "2 4\n1 1 0 0\n0 0 0 1",
"output": "YES"
},
{
"input": "10 4\n1 0 1 0\n1 0 1 0\n0 1 1 1\n1 0 1 1\n1 1 0 1\n1 0 0 1\n0 1 1 1\n0 0 0 1\n1 1 1 1\n1 0 1 0",
"output": "YES"
},
{
"input": "2 4\n0 1 0 0\n0 0 1 1",
"output": "YES"
},
{
"input": "3 3\n1 1 0\n1 0 1\n0 1 1",
"output": "NO"
},
{
"input": "3 3\n1 1 0\n0 0 1\n1 1 1",
"output": "YES"
},
{
"input": "4 4\n1 1 0 0\n1 0 1 0\n0 1 1 0\n0 0 1 1",
"output": "YES"
},
{
"input": "4 4\n1 0 0 0\n1 0 0 1\n1 0 0 1\n0 1 1 1",
"output": "YES"
},
{
"input": "4 3\n1 0 0\n1 0 0\n1 0 0\n0 1 1",
"output": "YES"
},
{
"input": "2 4\n0 0 1 0\n0 1 0 0",
"output": "YES"
},
{
"input": "1 2\n0 1",
"output": "NO"
},
{
"input": "3 4\n1 1 1 0\n0 0 1 1\n1 1 0 0",
"output": "YES"
},
{
"input": "3 4\n0 0 1 1\n0 1 0 1\n1 0 1 0",
"output": "YES"
},
{
"input": "2 3\n1 0 1\n0 1 0",
"output": "YES"
},
{
"input": "2 4\n0 0 0 0\n0 0 0 0",
"output": "YES"
},
{
"input": "3 4\n0 1 0 1\n0 1 1 0\n1 0 0 1",
"output": "YES"
},
{
"input": "3 4\n0 1 1 0\n1 1 0 0\n0 0 1 1",
"output": "YES"
},
{
"input": "2 4\n1 0 1 0\n0 0 0 1",
"output": "YES"
},
{
"input": "2 3\n0 1 0\n1 0 0",
"output": "YES"
},
{
"input": "4 4\n0 0 1 1\n0 1 1 0\n1 1 0 0\n1 0 0 1",
"output": "YES"
},
{
"input": "10 4\n0 0 1 1\n0 0 1 1\n0 0 1 1\n0 0 1 1\n0 0 1 1\n0 0 1 1\n0 0 1 1\n0 0 1 1\n0 0 1 1\n1 1 0 0",
"output": "YES"
},
{
"input": "3 3\n1 1 0\n0 1 1\n1 0 1",
"output": "NO"
},
{
"input": "2 3\n0 0 1\n1 1 0",
"output": "YES"
},
{
"input": "4 4\n0 0 0 1\n0 0 1 1\n1 1 0 1\n1 1 1 0",
"output": "YES"
},
{
"input": "3 4\n0 0 1 1\n1 0 1 0\n0 1 0 1",
"output": "YES"
},
{
"input": "5 4\n1 1 1 0\n1 1 0 1\n1 0 1 1\n0 1 1 1\n0 0 1 1",
"output": "NO"
},
{
"input": "3 4\n1 0 0 0\n1 1 0 0\n0 1 1 0",
"output": "YES"
}
] | 1,626,184,611
| 2,147,483,647
|
PyPy 3
|
TIME_LIMIT_EXCEEDED
|
TESTS
| 7
| 2,000
| 28,774,400
|
n, k = map(int, input().split())
temp = []
for i in range(n):
temp += [input()]
f = 0
for i in temp:
for j in temp:
a, b = list(map(int, i.split())), list(map(int, j.split()))
c = sum(a[l] + b[l] != 2 for l in range(k))
if c == k:
f = 1
if f:
print("YES")
else:
print("NO")
|
Title: Qualification Rounds
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Snark and Philip are preparing the problemset for the upcoming pre-qualification round for semi-quarter-finals. They have a bank of *n* problems, and they want to select any non-empty subset of it as a problemset.
*k* experienced teams are participating in the contest. Some of these teams already know some of the problems. To make the contest interesting for them, each of the teams should know at most half of the selected problems.
Determine if Snark and Philip can make an interesting problemset!
Input Specification:
The first line contains two integers *n*, *k* (1<=≤<=*n*<=≤<=105, 1<=≤<=*k*<=≤<=4) — the number of problems and the number of experienced teams.
Each of the next *n* lines contains *k* integers, each equal to 0 or 1. The *j*-th number in the *i*-th line is 1 if *j*-th team knows *i*-th problem and 0 otherwise.
Output Specification:
Print "YES" (quotes for clarity), if it is possible to make an interesting problemset, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES").
Demo Input:
['5 3\n1 0 1\n1 1 0\n1 0 0\n1 0 0\n1 0 0\n', '3 2\n1 0\n1 1\n0 1\n']
Demo Output:
['NO\n', 'YES\n']
Note:
In the first example you can't make any interesting problemset, because the first team knows all problems.
In the second example you can choose the first and the third problems.
|
```python
n, k = map(int, input().split())
temp = []
for i in range(n):
temp += [input()]
f = 0
for i in temp:
for j in temp:
a, b = list(map(int, i.split())), list(map(int, j.split()))
c = sum(a[l] + b[l] != 2 for l in range(k))
if c == k:
f = 1
if f:
print("YES")
else:
print("NO")
```
| 0
|
|
25
|
A
|
IQ test
|
PROGRAMMING
| 1,300
|
[
"brute force"
] |
A. IQ test
|
2
|
256
|
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness.
|
The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness.
|
Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order.
|
[
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] |
[
"3\n",
"2\n"
] |
none
| 0
|
[
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output": "2"
},
{
"input": "4\n75 13 94 77",
"output": "3"
},
{
"input": "4\n97 8 27 3",
"output": "2"
},
{
"input": "10\n95 51 12 91 85 3 1 31 25 7",
"output": "3"
},
{
"input": "20\n88 96 66 51 14 88 2 92 18 72 18 88 20 30 4 82 90 100 24 46",
"output": "4"
},
{
"input": "30\n20 94 56 50 10 98 52 32 14 22 24 60 4 8 98 46 34 68 82 82 98 90 50 20 78 49 52 94 64 36",
"output": "26"
},
{
"input": "50\n79 27 77 57 37 45 27 49 65 33 57 21 71 19 75 85 65 61 23 97 85 9 23 1 9 3 99 77 77 21 79 69 15 37 15 7 93 81 13 89 91 31 45 93 15 97 55 80 85 83",
"output": "48"
},
{
"input": "60\n46 11 73 65 3 69 3 53 43 53 97 47 55 93 31 75 35 3 9 73 23 31 3 81 91 79 61 21 15 11 11 11 81 7 83 75 39 87 83 59 89 55 93 27 49 67 67 29 1 93 11 17 9 19 35 21 63 31 31 25",
"output": "1"
},
{
"input": "70\n28 42 42 92 64 54 22 38 38 78 62 38 4 38 14 66 4 92 66 58 94 26 4 44 41 88 48 82 44 26 74 44 48 4 16 92 34 38 26 64 94 4 30 78 50 54 12 90 8 16 80 98 28 100 74 50 36 42 92 18 76 98 8 22 2 50 58 50 64 46",
"output": "25"
},
{
"input": "100\n43 35 79 53 13 91 91 45 65 83 57 9 42 39 85 45 71 51 61 59 31 13 63 39 25 21 79 39 91 67 21 61 97 75 93 83 29 79 59 97 11 37 63 51 39 55 91 23 21 17 47 23 35 75 49 5 69 99 5 7 41 17 25 89 15 79 21 63 53 81 43 91 59 91 69 99 85 15 91 51 49 37 65 7 89 81 21 93 61 63 97 93 45 17 13 69 57 25 75 73",
"output": "13"
},
{
"input": "100\n50 24 68 60 70 30 52 22 18 74 68 98 20 82 4 46 26 68 100 78 84 58 74 98 38 88 68 86 64 80 82 100 20 22 98 98 52 6 94 10 48 68 2 18 38 22 22 82 44 20 66 72 36 58 64 6 36 60 4 96 76 64 12 90 10 58 64 60 74 28 90 26 24 60 40 58 2 16 76 48 58 36 82 60 24 44 4 78 28 38 8 12 40 16 38 6 66 24 31 76",
"output": "99"
},
{
"input": "100\n47 48 94 48 14 18 94 36 96 22 12 30 94 20 48 98 40 58 2 94 8 36 98 18 98 68 2 60 76 38 18 100 8 72 100 68 2 86 92 72 58 16 48 14 6 58 72 76 6 88 80 66 20 28 74 62 86 68 90 86 2 56 34 38 56 90 4 8 76 44 32 86 12 98 38 34 54 92 70 94 10 24 82 66 90 58 62 2 32 58 100 22 58 72 2 22 68 72 42 14",
"output": "1"
},
{
"input": "99\n38 20 68 60 84 16 28 88 60 48 80 28 4 92 70 60 46 46 20 34 12 100 76 2 40 10 8 86 6 80 50 66 12 34 14 28 26 70 46 64 34 96 10 90 98 96 56 88 50 74 70 94 2 94 24 66 68 46 22 30 6 10 64 32 88 14 98 100 64 58 50 18 50 50 8 38 8 16 54 2 60 54 62 84 92 98 4 72 66 26 14 88 99 16 10 6 88 56 22",
"output": "93"
},
{
"input": "99\n50 83 43 89 53 47 69 1 5 37 63 87 95 15 55 95 75 89 33 53 89 75 93 75 11 85 49 29 11 97 49 67 87 11 25 37 97 73 67 49 87 43 53 97 43 29 53 33 45 91 37 73 39 49 59 5 21 43 87 35 5 63 89 57 63 47 29 99 19 85 13 13 3 13 43 19 5 9 61 51 51 57 15 89 13 97 41 13 99 79 13 27 97 95 73 33 99 27 23",
"output": "1"
},
{
"input": "98\n61 56 44 30 58 14 20 24 88 28 46 56 96 52 58 42 94 50 46 30 46 80 72 88 68 16 6 60 26 90 10 98 76 20 56 40 30 16 96 20 88 32 62 30 74 58 36 76 60 4 24 36 42 54 24 92 28 14 2 74 86 90 14 52 34 82 40 76 8 64 2 56 10 8 78 16 70 86 70 42 70 74 22 18 76 98 88 28 62 70 36 72 20 68 34 48 80 98",
"output": "1"
},
{
"input": "98\n66 26 46 42 78 32 76 42 26 82 8 12 4 10 24 26 64 44 100 46 94 64 30 18 88 28 8 66 30 82 82 28 74 52 62 80 80 60 94 86 64 32 44 88 92 20 12 74 94 28 34 58 4 22 16 10 94 76 82 58 40 66 22 6 30 32 92 54 16 76 74 98 18 48 48 30 92 2 16 42 84 74 30 60 64 52 50 26 16 86 58 96 79 60 20 62 82 94",
"output": "93"
},
{
"input": "95\n9 31 27 93 17 77 75 9 9 53 89 39 51 99 5 1 11 39 27 49 91 17 27 79 81 71 37 75 35 13 93 4 99 55 85 11 23 57 5 43 5 61 15 35 23 91 3 81 99 85 43 37 39 27 5 67 7 33 75 59 13 71 51 27 15 93 51 63 91 53 43 99 25 47 17 71 81 15 53 31 59 83 41 23 73 25 91 91 13 17 25 13 55 57 29",
"output": "32"
},
{
"input": "100\n91 89 81 45 53 1 41 3 77 93 55 97 55 97 87 27 69 95 73 41 93 21 75 35 53 56 5 51 87 59 91 67 33 3 99 45 83 17 97 47 75 97 7 89 17 99 23 23 81 25 55 97 27 35 69 5 77 35 93 19 55 59 37 21 31 37 49 41 91 53 73 69 7 37 37 39 17 71 7 97 55 17 47 23 15 73 31 39 57 37 9 5 61 41 65 57 77 79 35 47",
"output": "26"
},
{
"input": "99\n38 56 58 98 80 54 26 90 14 16 78 92 52 74 40 30 84 14 44 80 16 90 98 68 26 24 78 72 42 16 84 40 14 44 2 52 50 2 12 96 58 66 8 80 44 52 34 34 72 98 74 4 66 74 56 21 8 38 76 40 10 22 48 32 98 34 12 62 80 68 64 82 22 78 58 74 20 22 48 56 12 38 32 72 6 16 74 24 94 84 26 38 18 24 76 78 98 94 72",
"output": "56"
},
{
"input": "100\n44 40 6 40 56 90 98 8 36 64 76 86 98 76 36 92 6 30 98 70 24 98 96 60 24 82 88 68 86 96 34 42 58 10 40 26 56 10 88 58 70 32 24 28 14 82 52 12 62 36 70 60 52 34 74 30 78 76 10 16 42 94 66 90 70 38 52 12 58 22 98 96 14 68 24 70 4 30 84 98 8 50 14 52 66 34 100 10 28 100 56 48 38 12 38 14 91 80 70 86",
"output": "97"
},
{
"input": "100\n96 62 64 20 90 46 56 90 68 36 30 56 70 28 16 64 94 34 6 32 34 50 94 22 90 32 40 2 72 10 88 38 28 92 20 26 56 80 4 100 100 90 16 74 74 84 8 2 30 20 80 32 16 46 92 56 42 12 96 64 64 42 64 58 50 42 74 28 2 4 36 32 70 50 54 92 70 16 45 76 28 16 18 50 48 2 62 94 4 12 52 52 4 100 70 60 82 62 98 42",
"output": "79"
},
{
"input": "99\n14 26 34 68 90 58 50 36 8 16 18 6 2 74 54 20 36 84 32 50 52 2 26 24 3 64 20 10 54 26 66 44 28 72 4 96 78 90 96 86 68 28 94 4 12 46 100 32 22 36 84 32 44 94 76 94 4 52 12 30 74 4 34 64 58 72 44 16 70 56 54 8 14 74 8 6 58 62 98 54 14 40 80 20 36 72 28 98 20 58 40 52 90 64 22 48 54 70 52",
"output": "25"
},
{
"input": "95\n82 86 30 78 6 46 80 66 74 72 16 24 18 52 52 38 60 36 86 26 62 28 22 46 96 26 94 84 20 46 66 88 76 32 12 86 74 18 34 88 4 48 94 6 58 6 100 82 4 24 88 32 54 98 34 48 6 76 42 88 42 28 100 4 22 2 10 66 82 54 98 20 60 66 38 98 32 47 86 58 6 100 12 46 2 42 8 84 78 28 24 70 34 28 86",
"output": "78"
},
{
"input": "90\n40 50 8 42 76 24 58 42 26 68 20 48 54 12 34 84 14 36 32 88 6 50 96 56 20 92 48 16 40 34 96 46 20 84 30 50 20 98 8 44 96 42 8 76 70 38 84 30 40 88 84 72 2 22 52 58 16 62 100 66 80 40 50 32 14 62 88 72 22 99 76 50 84 82 8 82 98 46 26 40 2 98 18 78 30 72 70 18 34 68",
"output": "70"
},
{
"input": "80\n81 43 87 1 55 43 53 61 27 19 43 13 89 9 33 83 75 55 97 71 91 37 95 5 21 69 81 93 95 69 31 83 55 7 97 7 79 57 8 61 27 85 49 1 15 97 63 79 29 73 41 85 5 41 31 93 67 11 63 59 15 99 91 77 43 69 23 23 81 73 19 1 67 51 1 75 99 67 3 81",
"output": "39"
},
{
"input": "98\n13 83 61 27 35 1 85 95 97 73 95 65 73 45 5 43 27 83 91 19 11 3 85 59 9 39 69 23 45 7 51 85 5 71 5 95 1 51 75 3 43 57 3 11 33 71 21 99 47 41 87 39 71 87 31 85 91 49 83 5 49 85 47 91 55 99 33 23 31 23 23 73 29 77 55 31 25 5 81 49 91 15 15 39 87 5 9 40 69 47 29 33 11 21 49 79 51 83",
"output": "88"
},
{
"input": "3\n100 100 1",
"output": "3"
}
] | 1,671,549,592
| 2,147,483,647
|
PyPy 3
|
OK
|
TESTS
| 32
| 154
| 0
|
n = int(input())
arr = [int(i) % 2 for i in input().split()]
s = sum(arr)
if (s == 1):
for i in range(len(arr)):
if (arr[i] == 1):
print(i+1)
break
else:
for i in range(len(arr)):
if (arr[i] == 0):
print(i+1)
break
|
Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness.
Input Specification:
The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness.
Output Specification:
Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order.
Demo Input:
['5\n2 4 7 8 10\n', '4\n1 2 1 1\n']
Demo Output:
['3\n', '2\n']
Note:
none
|
```python
n = int(input())
arr = [int(i) % 2 for i in input().split()]
s = sum(arr)
if (s == 1):
for i in range(len(arr)):
if (arr[i] == 1):
print(i+1)
break
else:
for i in range(len(arr)):
if (arr[i] == 0):
print(i+1)
break
```
| 3.9615
|
Subsets and Splits
Successful Python Submissions
Retrieves all records from the train dataset where the verdict is 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Retrieves records of users with a rating of 1600 or higher and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a rating above 2000 and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a 'OK' verdict, providing a basic overview of a specific category within the dataset.