contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
675 | A | Infinite Sequence | PROGRAMMING | 1,100 | [
"math"
] | null | null | Vasya likes everything infinite. Now he is studying the properties of a sequence *s*, such that its first element is equal to *a* (*s*1<==<=*a*), and the difference between any two neighbouring elements is equal to *c* (*s**i*<=-<=*s**i*<=-<=1<==<=*c*). In particular, Vasya wonders if his favourite integer *b* appears ... | The first line of the input contain three integers *a*, *b* and *c* (<=-<=109<=≤<=*a*,<=*b*,<=*c*<=≤<=109) — the first element of the sequence, Vasya's favorite number and the difference between any two neighbouring elements of the sequence, respectively. | If *b* appears in the sequence *s* print "YES" (without quotes), otherwise print "NO" (without quotes). | [
"1 7 3\n",
"10 10 0\n",
"1 -4 5\n",
"0 60 50\n"
] | [
"YES\n",
"YES\n",
"NO\n",
"NO\n"
] | In the first sample, the sequence starts from integers 1, 4, 7, so 7 is its element.
In the second sample, the favorite integer of Vasya is equal to the first element of the sequence.
In the third sample all elements of the sequence are greater than Vasya's favorite integer.
In the fourth sample, the sequence starts... | 500 | [
{
"input": "1 7 3",
"output": "YES"
},
{
"input": "10 10 0",
"output": "YES"
},
{
"input": "1 -4 5",
"output": "NO"
},
{
"input": "0 60 50",
"output": "NO"
},
{
"input": "1 -4 -5",
"output": "YES"
},
{
"input": "0 1 0",
"output": "NO"
},
{
... | 1,576,175,254 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 108 | 0 | a,b,d = map(int,input().split())
if d>0:
if (b-a)/d == abs(int((b-a)/d)):
print('YES')
else:
print('NO')
else:
if b == a:
print("YES")
else:
print('NO') | Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya likes everything infinite. Now he is studying the properties of a sequence *s*, such that its first element is equal to *a* (*s*1<==<=*a*), and the difference between any two neighbouring elements is equal to *c... | ```python
a,b,d = map(int,input().split())
if d>0:
if (b-a)/d == abs(int((b-a)/d)):
print('YES')
else:
print('NO')
else:
if b == a:
print("YES")
else:
print('NO')
``` | 0 | |
361 | B | Levko and Permutation | PROGRAMMING | 1,200 | [
"constructive algorithms",
"math",
"number theory"
] | null | null | Levko loves permutations very much. A permutation of length *n* is a sequence of distinct positive integers, each is at most *n*.
Let’s assume that value *gcd*(*a*,<=*b*) shows the greatest common divisor of numbers *a* and *b*. Levko assumes that element *p**i* of permutation *p*1,<=*p*2,<=... ,<=*p**n* is good if *g... | The single line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 0<=≤<=*k*<=≤<=*n*). | In a single line print either any beautiful permutation or -1, if such permutation doesn’t exist.
If there are multiple suitable permutations, you are allowed to print any of them. | [
"4 2\n",
"1 1\n"
] | [
"2 4 3 1",
"-1\n"
] | In the first sample elements 4 and 3 are good because *gcd*(2, 4) = 2 > 1 and *gcd*(3, 3) = 3 > 1. Elements 2 and 1 are not good because *gcd*(1, 2) = 1 and *gcd*(4, 1) = 1. As there are exactly 2 good elements, the permutation is beautiful.
The second sample has no beautiful permutations. | 1,000 | [
{
"input": "4 2",
"output": "2 1 3 4 "
},
{
"input": "1 1",
"output": "-1"
},
{
"input": "7 4",
"output": "3 1 2 4 5 6 7 "
},
{
"input": "10 9",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "10000 5000",
"output": "5000 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1... | 1,556,014,109 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | n,k=input().split()
n=int(n)
k=int(k)
if(n<=k):
print(-1)
else:
for i in range(1,k+2):
print(i,end=" ")
for i in range(k+2,n+1):
print(1,end=" ")
| Title: Levko and Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Levko loves permutations very much. A permutation of length *n* is a sequence of distinct positive integers, each is at most *n*.
Let’s assume that value *gcd*(*a*,<=*b*) shows the greatest common divisor of numb... | ```python
n,k=input().split()
n=int(n)
k=int(k)
if(n<=k):
print(-1)
else:
for i in range(1,k+2):
print(i,end=" ")
for i in range(k+2,n+1):
print(1,end=" ")
``` | 0 | |
233 | A | Perfect Permutation | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size of permutation *p*1,<=*p*2,<=...,<=*p**n*.
Nickolas adores permutations. He lik... | A single line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the permutation size. | If a perfect permutation of size *n* doesn't exist, print a single integer -1. Otherwise print *n* distinct integers from 1 to *n*, *p*1,<=*p*2,<=...,<=*p**n* — permutation *p*, that is perfect. Separate printed numbers by whitespaces. | [
"1\n",
"2\n",
"4\n"
] | [
"-1\n",
"2 1 \n",
"2 1 4 3 \n"
] | none | 500 | [
{
"input": "1",
"output": "-1"
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "4",
"output": "2 1 4 3 "
},
{
"input": "3",
"output": "-1"
},
{
"input": "5",
"output": "-1"
},
{
"input": "6",
"output": "2 1 4 3 6 5 "
},
{
"input": "7",
... | 1,643,135,537 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 62 | 0 | n = int(input())
if(n%2 == 1):
print('-1')
else:
s = list(range(1,n+1))
for i in range(0,n-1,2):
s[i], s[i+1] = s[i+1],s[i]
print(*s)
| Title: Perfect Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll ... | ```python
n = int(input())
if(n%2 == 1):
print('-1')
else:
s = list(range(1,n+1))
for i in range(0,n-1,2):
s[i], s[i+1] = s[i+1],s[i]
print(*s)
``` | 3 | |
583 | B | Robot's Task | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Robot Doc is located in the hall, with *n* computers stand in a line, numbered from left to right from 1 to *n*. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The computers are equipped with a security system, so to crack the *i*-th of them, the robot needs to colle... | The first line contains number *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*n*), separated by a space. It is guaranteed that there exists a way for robot to collect all pieces of the information. | Print a single number — the minimum number of changes in direction that the robot will have to make in order to collect all *n* parts of information. | [
"3\n0 2 0\n",
"5\n4 2 3 0 1\n",
"7\n0 3 1 0 5 2 6\n"
] | [
"1\n",
"3\n",
"2\n"
] | In the first sample you can assemble all the pieces of information in the optimal manner by assembling first the piece of information in the first computer, then in the third one, then change direction and move to the second one, and then, having 2 pieces of information, collect the last piece.
In the second sample to... | 1,000 | [
{
"input": "3\n0 2 0",
"output": "1"
},
{
"input": "5\n4 2 3 0 1",
"output": "3"
},
{
"input": "7\n0 3 1 0 5 2 6",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n0 1",
"output": "0"
},
{
"input": "10\n0 0 0 0 0 0 0 0 0 0",
"out... | 1,444,069,189 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 61 | 4,403,200 | #!/usr/bin/env python3.4
import time
COL, ROW, LEN = 1000, 1000, 26
matrix = [[0] * COL for i in range(ROW)]
arr = [0] * LEN
direction = ((0, -1), (-1, 0), (0, 1), (1, 0))
class Pair:
def __init__(self, x, y):
self.x = x
self.y = y
def timer(func, *pargs, **kargs):
start = time.time()
... | Title: Robot's Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Robot Doc is located in the hall, with *n* computers stand in a line, numbered from left to right from 1 to *n*. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The compu... | ```python
#!/usr/bin/env python3.4
import time
COL, ROW, LEN = 1000, 1000, 26
matrix = [[0] * COL for i in range(ROW)]
arr = [0] * LEN
direction = ((0, -1), (-1, 0), (0, 1), (1, 0))
class Pair:
def __init__(self, x, y):
self.x = x
self.y = y
def timer(func, *pargs, **kargs):
start = time.... | -1 | |
501 | A | Contest | PROGRAMMING | 900 | [
"implementation"
] | null | null | Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved the problem that costs *b* points. Besides, Misha submitted the problem *c* minutes after the ... | The first line contains four integers *a*, *b*, *c*, *d* (250<=≤<=*a*,<=*b*<=≤<=3500, 0<=≤<=*c*,<=*d*<=≤<=180).
It is guaranteed that numbers *a* and *b* are divisible by 250 (just like on any real Codeforces round). | Output on a single line:
"Misha" (without the quotes), if Misha got more points than Vasya.
"Vasya" (without the quotes), if Vasya got more points than Misha.
"Tie" (without the quotes), if both of them got the same number of points. | [
"500 1000 20 30\n",
"1000 1000 1 1\n",
"1500 1000 176 177\n"
] | [
"Vasya\n",
"Tie\n",
"Misha\n"
] | none | 500 | [
{
"input": "500 1000 20 30",
"output": "Vasya"
},
{
"input": "1000 1000 1 1",
"output": "Tie"
},
{
"input": "1500 1000 176 177",
"output": "Misha"
},
{
"input": "1500 1000 74 177",
"output": "Misha"
},
{
"input": "750 2500 175 178",
"output": "Vasya"
},
{
... | 1,655,325,243 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 46 | 0 | n=input().split(' ')
a=int(n[0])
b=int(n[1])
c=int(n[2])
d=int(n[3])
calc_1=(3*a)/10
calc_1_1=a-((a*c)/250)
calc_2=(3*b)/10
calc_2_2=b-((b*d)/250)
if calc_1_1==calc_2_2:
print('Tie')
elif calc_1_1>calc_2_2:
print('Misha')
else:
print('Vasya')
| Title: Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved t... | ```python
n=input().split(' ')
a=int(n[0])
b=int(n[1])
c=int(n[2])
d=int(n[3])
calc_1=(3*a)/10
calc_1_1=a-((a*c)/250)
calc_2=(3*b)/10
calc_2_2=b-((b*d)/250)
if calc_1_1==calc_2_2:
print('Tie')
elif calc_1_1>calc_2_2:
print('Misha')
else:
print('Vasya')
``` | 0 | |
284 | B | Cows and Poker Game | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | There are *n* cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any be... | The first line contains a single integer, *n* (2<=≤<=*n*<=≤<=2·105). The second line contains *n* characters, each either "A", "I", or "F". The *i*-th character is "A" if the *i*-th player's status is "ALLIN", "I" if the *i*-th player's status is "IN", or "F" if the *i*-th player's status is "FOLDED". | The first line should contain a single integer denoting the number of players that can currently show their hands. | [
"6\nAFFAAA\n",
"3\nAFI\n"
] | [
"4\n",
"1\n"
] | In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand. | 1,000 | [
{
"input": "6\nAFFAAA",
"output": "4"
},
{
"input": "3\nAFI",
"output": "1"
},
{
"input": "3\nFFF",
"output": "0"
},
{
"input": "3\nFIF",
"output": "1"
},
{
"input": "3\nAAA",
"output": "3"
},
{
"input": "3\nIII",
"output": "0"
},
{
"input"... | 1,622,864,670 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 218 | 0 | def main():
n = int(input())
cont = 0
cows = input()
for i in range(n-1, -1, -1):
if cows[i] == 'A':
cont += 1
elif cows[i] == 'I':
cont += 1
break
print(cont)
main()
| Title: Cows and Poker Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player who... | ```python
def main():
n = int(input())
cont = 0
cows = input()
for i in range(n-1, -1, -1):
if cows[i] == 'A':
cont += 1
elif cows[i] == 'I':
cont += 1
break
print(cont)
main()
``` | 0 | |
1,007 | A | Reorder the Array | PROGRAMMING | 1,300 | [
"combinatorics",
"data structures",
"math",
"sortings",
"two pointers"
] | null | null | You are given an array of integers. Vasya can permute (change order) its integers. He wants to do it so that as many as possible integers will become on a place where a smaller integer used to stand. Help Vasya find the maximal number of such integers.
For instance, if we are given an array $[10, 20, 30, 40]$, we can ... | The first line contains a single integer $n$ ($1 \leq n \leq 10^5$) — the length of the array.
The second line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \leq a_i \leq 10^9$) — the elements of the array. | Print a single integer — the maximal number of the array's elements which after a permutation will stand on the position where a smaller element stood in the initial array. | [
"7\n10 1 1 1 5 5 3\n",
"5\n1 1 1 1 1\n"
] | [
"4\n",
"0\n"
] | In the first sample, one of the best permutations is $[1, 5, 5, 3, 10, 1, 1]$. On the positions from second to fifth the elements became larger, so the answer for this permutation is 4.
In the second sample, there is no way to increase any element with a permutation, so the answer is 0. | 500 | [
{
"input": "7\n10 1 1 1 5 5 3",
"output": "4"
},
{
"input": "5\n1 1 1 1 1",
"output": "0"
},
{
"input": "6\n300000000 200000000 300000000 200000000 1000000000 300000000",
"output": "3"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "9"
},
{
"input": "1\n1",
... | 1,565,879,211 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 140 | 0 | n = int(input())
a = list(map(int , input().split()))
count = 0
a.sort()
mini = a[0]
for i in range(n):
if a[i] > mini:
count+=1
print(count) | Title: Reorder the Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array of integers. Vasya can permute (change order) its integers. He wants to do it so that as many as possible integers will become on a place where a smaller integer used to stand. Help Vasya find t... | ```python
n = int(input())
a = list(map(int , input().split()))
count = 0
a.sort()
mini = a[0]
for i in range(n):
if a[i] > mini:
count+=1
print(count)
``` | 0 | |
633 | B | A Trivial Problem | PROGRAMMING | 1,300 | [
"brute force",
"constructive algorithms",
"math",
"number theory"
] | null | null | Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer *m* and asks for the number of positive integers *n*, such that the factorial of *n* ends with exactly *m* zeroes. Are you among those great programmers who can solve this problem? | The only line of input contains an integer *m* (1<=≤<=*m*<=≤<=100<=000) — the required number of trailing zeroes in factorial. | First print *k* — the number of values of *n* such that the factorial of *n* ends with *m* zeroes. Then print these *k* integers in increasing order. | [
"1\n",
"5\n"
] | [
"5\n5 6 7 8 9 ",
"0"
] | The factorial of *n* is equal to the product of all integers from 1 to *n* inclusive, that is *n*! = 1·2·3·...·*n*.
In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880. | 500 | [
{
"input": "1",
"output": "5\n5 6 7 8 9 "
},
{
"input": "5",
"output": "0"
},
{
"input": "2",
"output": "5\n10 11 12 13 14 "
},
{
"input": "3",
"output": "5\n15 16 17 18 19 "
},
{
"input": "7",
"output": "5\n30 31 32 33 34 "
},
{
"input": "12",
"ou... | 1,659,787,419 | 2,147,483,647 | Python 3 | OK | TESTS | 68 | 249 | 0 | m = int(input())
result = list()
number = 1
fiveCount = 0
while True:
curFiveCount = fiveCount
tempNumber = number
while tempNumber%5 == 0:
curFiveCount = curFiveCount + 1
tempNumber = tempNumber//5
if curFiveCount == m:
result.append(number)
#... | Title: A Trivial Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer *m* and asks for the number of positive integers *n*, such that the factorial of *n* ends with exactly *m* zer... | ```python
m = int(input())
result = list()
number = 1
fiveCount = 0
while True:
curFiveCount = fiveCount
tempNumber = number
while tempNumber%5 == 0:
curFiveCount = curFiveCount + 1
tempNumber = tempNumber//5
if curFiveCount == m:
result.append(number)
... | 3 | |
46 | A | Ball Game | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | A. Ball Game | 2 | 256 | A kindergarten teacher Natalia Pavlovna has invented a new ball game. This game not only develops the children's physique, but also teaches them how to count.
The game goes as follows. Kids stand in circle. Let's agree to think of the children as numbered with numbers from 1 to *n* clockwise and the child number 1 is... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) which indicates the number of kids in the circle. | In the single line print *n*<=-<=1 numbers which are the numbers of children who will get the ball after each throw. Separate the numbers by spaces. | [
"10\n",
"3\n"
] | [
"2 4 7 1 6 2 9 7 6\n",
"2 1\n"
] | none | 0 | [
{
"input": "10",
"output": "2 4 7 1 6 2 9 7 6"
},
{
"input": "3",
"output": "2 1"
},
{
"input": "4",
"output": "2 4 3"
},
{
"input": "5",
"output": "2 4 2 1"
},
{
"input": "6",
"output": "2 4 1 5 4"
},
{
"input": "7",
"output": "2 4 7 4 2 1"
},
... | 1,691,736,160 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 92 | 0 | n,a=int(input()),0
for i in range(1,n):
a=(a+i)%n
print(a+1,'') | Title: Ball Game
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A kindergarten teacher Natalia Pavlovna has invented a new ball game. This game not only develops the children's physique, but also teaches them how to count.
The game goes as follows. Kids stand in circle. Let's agree to think... | ```python
n,a=int(input()),0
for i in range(1,n):
a=(a+i)%n
print(a+1,'')
``` | 3.977 |
125 | C | Hobbits' Party | PROGRAMMING | 1,600 | [
"constructive algorithms",
"greedy"
] | null | null | Everyone knows that hobbits love to organize all sorts of parties and celebrations. There are *n* hobbits living in the Shire. They decided to organize the Greatest Party (GP) that would last for several days. Next day the hobbits wrote a guest list, some non-empty set containing all the inhabitants of the Shire. To en... | The first line contains an integer *n* (3<=≤<=*n*<=≤<=10000), representing the number of hobbits. | In the first output line print a number *k* — the maximum duration of GP in days. Then on *k* lines print the guest lists, (the guests should be separated by spaces). Print each guest list on the single line. Each list can contain an arbitrary positive number of hobbits. The hobbits are numbered with integers from 1 to... | [
"4\n",
"5\n"
] | [
"3\n1 2 \n1 3 \n2 3 \n",
"3\n1 2 \n1 3 \n2 3 \n"
] | none | 2,000 | [
{
"input": "4",
"output": "3\n1 2 \n1 3 \n2 3 "
},
{
"input": "5",
"output": "3\n1 2 \n1 3 \n2 3 "
},
{
"input": "6",
"output": "4\n1 2 3 \n1 4 5 \n2 4 6 \n3 5 6 "
},
{
"input": "7",
"output": "4\n1 2 3 \n1 4 5 \n2 4 6 \n3 5 6 "
},
{
"input": "8",
"output": "4... | 1,570,149,973 | 2,147,483,647 | PyPy 3 | OK | TESTS | 46 | 310 | 1,740,800 | '''
Author : thekushalghosh
Team : CodeDiggers
'''
n = int(input())
q = int(0.5 + (1 + 8*n)**0.5 / 2)
w = 1
qw = [[] for _ in range(q)]
for i in range(q):
j = i + 1
while len(qw[i]) < q - 1:
qw[i].append(str(w))
qw[j].append(str(w))
w = w + 1
j = j + 1
... | Title: Hobbits' Party
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Everyone knows that hobbits love to organize all sorts of parties and celebrations. There are *n* hobbits living in the Shire. They decided to organize the Greatest Party (GP) that would last for several days. Next day t... | ```python
'''
Author : thekushalghosh
Team : CodeDiggers
'''
n = int(input())
q = int(0.5 + (1 + 8*n)**0.5 / 2)
w = 1
qw = [[] for _ in range(q)]
for i in range(q):
j = i + 1
while len(qw[i]) < q - 1:
qw[i].append(str(w))
qw[j].append(str(w))
w = w + 1
... | 3 | |
233 | A | Perfect Permutation | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size of permutation *p*1,<=*p*2,<=...,<=*p**n*.
Nickolas adores permutations. He lik... | A single line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the permutation size. | If a perfect permutation of size *n* doesn't exist, print a single integer -1. Otherwise print *n* distinct integers from 1 to *n*, *p*1,<=*p*2,<=...,<=*p**n* — permutation *p*, that is perfect. Separate printed numbers by whitespaces. | [
"1\n",
"2\n",
"4\n"
] | [
"-1\n",
"2 1 \n",
"2 1 4 3 \n"
] | none | 500 | [
{
"input": "1",
"output": "-1"
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "4",
"output": "2 1 4 3 "
},
{
"input": "3",
"output": "-1"
},
{
"input": "5",
"output": "-1"
},
{
"input": "6",
"output": "2 1 4 3 6 5 "
},
{
"input": "7",
... | 1,649,856,741 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | n = int(input())
arr = [i for i in range (1,n+1)]
arr1 = []
i,con = 0,True
while i <= n>>1:
try:
arr1.append(arr.pop(1))
except:
break
arr1.append(arr.pop(0))
if arr:arr1.append(arr[0])
for i in range (len(arr1)):
if i+1 == arr1[i]:
con = False
break
if c... | Title: Perfect Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll ... | ```python
n = int(input())
arr = [i for i in range (1,n+1)]
arr1 = []
i,con = 0,True
while i <= n>>1:
try:
arr1.append(arr.pop(1))
except:
break
arr1.append(arr.pop(0))
if arr:arr1.append(arr[0])
for i in range (len(arr1)):
if i+1 == arr1[i]:
con = False
bre... | 3 | |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,659,522,853 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 12 | 46 | 1,740,800 | n, t = map(int, input().split())
numbers = list(map(int, input().split()))
ans = 'NO'
i = 1 # номер портала и ячейки
while i < n:
if i == t:
ans = 'YES'
break
i = i + numbers[i-1]
print(ans) | Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
n, t = map(int, input().split())
numbers = list(map(int, input().split()))
ans = 'NO'
i = 1 # номер портала и ячейки
while i < n:
if i == t:
ans = 'YES'
break
i = i + numbers[i-1]
print(ans)
``` | 0 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,668,838,966 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | num = input()
buffer = ''
ans = ''
for ch in num:
buffer += ch
if buffer == '.':
ans += '0'
buffer = ''
elif buffer == '-.':
ans += '1'
buffer = ''
elif buffer == '--':
ans += '2'
buffer = ''
print(ans)
| Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
num = input()
buffer = ''
ans = ''
for ch in num:
buffer += ch
if buffer == '.':
ans += '0'
buffer = ''
elif buffer == '-.':
ans += '1'
buffer = ''
elif buffer == '--':
ans += '2'
buffer = ''
print(ans)
``` | 3.977 |
289 | B | Polo the Penguin and Matrix | PROGRAMMING | 1,400 | [
"brute force",
"dp",
"implementation",
"sortings",
"ternary search"
] | null | null | Little penguin Polo has an *n*<=×<=*m* matrix, consisting of integers. Let's index the matrix rows from 1 to *n* from top to bottom and let's index the columns from 1 to *m* from left to right. Let's represent the matrix element on the intersection of row *i* and column *j* as *a**ij*.
In one move the penguin can add ... | The first line contains three integers *n*, *m* and *d* (1<=≤<=*n*,<=*m*<=≤<=100,<=1<=≤<=*d*<=≤<=104) — the matrix sizes and the *d* parameter. Next *n* lines contain the matrix: the *j*-th integer in the *i*-th row is the matrix element *a**ij* (1<=≤<=*a**ij*<=≤<=104). | In a single line print a single integer — the minimum number of moves the penguin needs to make all matrix elements equal. If that is impossible, print "-1" (without the quotes). | [
"2 2 2\n2 4\n6 8\n",
"1 2 7\n6 7\n"
] | [
"4\n",
"-1\n"
] | none | 1,000 | [
{
"input": "2 2 2\n2 4\n6 8",
"output": "4"
},
{
"input": "1 2 7\n6 7",
"output": "-1"
},
{
"input": "3 2 1\n5 7\n1 2\n5 100",
"output": "104"
},
{
"input": "3 3 3\n5 8 5\n11 11 17\n14 5 2",
"output": "12"
},
{
"input": "3 3 3\n5 8 5\n11 11 17\n14 5 3",
"outpu... | 1,618,408,176 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 124 | 0 | def solve(r, c, d):
a = []
mod = None
no = False
for _ in range(r):
for n in map(int, input().split()):
if not no:
a.append(n)
if mod is None:
mod = n % d
continue
if mod != n % d:
... | Title: Polo the Penguin and Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little penguin Polo has an *n*<=×<=*m* matrix, consisting of integers. Let's index the matrix rows from 1 to *n* from top to bottom and let's index the columns from 1 to *m* from left to right. Let's represe... | ```python
def solve(r, c, d):
a = []
mod = None
no = False
for _ in range(r):
for n in map(int, input().split()):
if not no:
a.append(n)
if mod is None:
mod = n % d
continue
if mod != n % d:
... | 0 | |
791 | A | Bear and Big Brother | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or equal to his brother's weight.
Limak eats a lot and his weight is tripled after every year, while Bob's we... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10) — the weight of Limak and the weight of Bob respectively. | Print one integer, denoting the integer number of years after which Limak will become strictly larger than Bob. | [
"4 7\n",
"4 9\n",
"1 1\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first sample, Limak weighs 4 and Bob weighs 7 initially. After one year their weights are 4·3 = 12 and 7·2 = 14 respectively (one weight is tripled while the other one is doubled). Limak isn't larger than Bob yet. After the second year weights are 36 and 28, so the first weight is greater than the second one. Li... | 500 | [
{
"input": "4 7",
"output": "2"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "4 6",
"output": "2"
},
{
"input": "1 10",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output... | 1,694,317,529 | 2,147,483,647 | Python 3 | OK | TESTS | 62 | 46 | 0 |
from math import log2
a, b = tuple(map(int, input().strip().split()))
print(f'{int(1 + ((log2(b) - log2(a)) // (log2(3) - 1)))}') | Title: Bear and Big Brother
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or e... | ```python
from math import log2
a, b = tuple(map(int, input().strip().split()))
print(f'{int(1 + ((log2(b) - log2(a)) // (log2(3) - 1)))}')
``` | 3 | |
895 | B | XK Segments | PROGRAMMING | 1,700 | [
"binary search",
"math",
"sortings",
"two pointers"
] | null | null | While Vasya finished eating his piece of pizza, the lesson has already started. For being late for the lesson, the teacher suggested Vasya to solve one interesting problem. Vasya has an array *a* and integer *x*. He should find the number of different ordered pairs of indexes (*i*,<=*j*) such that *a**i*<=≤<=*a**j* and... | The first line contains 3 integers *n*,<=*x*,<=*k* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*x*<=≤<=109,<=0<=≤<=*k*<=≤<=109), where *n* is the size of the array *a* and *x* and *k* are numbers from the statement.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of the array *a*. | Print one integer — the answer to the problem. | [
"4 2 1\n1 3 5 7\n",
"4 2 0\n5 3 1 7\n",
"5 3 1\n3 3 3 3 3\n"
] | [
"3\n",
"4\n",
"25\n"
] | In first sample there are only three suitable pairs of indexes — (1, 2), (2, 3), (3, 4).
In second sample there are four suitable pairs of indexes(1, 1), (2, 2), (3, 3), (4, 4).
In third sample every pair (*i*, *j*) is suitable, so the answer is 5 * 5 = 25. | 1,000 | [
{
"input": "4 2 1\n1 3 5 7",
"output": "3"
},
{
"input": "4 2 0\n5 3 1 7",
"output": "4"
},
{
"input": "5 3 1\n3 3 3 3 3",
"output": "25"
},
{
"input": "5 3 4\n24 13 1 24 24",
"output": "4"
},
{
"input": "4 2 2\n1 3 5 7",
"output": "2"
},
{
"input": "5... | 1,632,325,343 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 108 | 20,582,400 | from bisect import bisect_left as bl, bisect as br
from collections import Counter
def f(a,x,k):
#r-l+1 (l=a[l]//x r=a[r]//x
lo=0
hi=0
a.sort()
ans=0
lt=list(map(lambda s:s//x,a))
# k-(a[i]-1)//x
# print(lt)
for i in a:
val=k+((i-1)//x)
lr=bl(lt,val)
... | Title: XK Segments
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Vasya finished eating his piece of pizza, the lesson has already started. For being late for the lesson, the teacher suggested Vasya to solve one interesting problem. Vasya has an array *a* and integer *x*. He should ... | ```python
from bisect import bisect_left as bl, bisect as br
from collections import Counter
def f(a,x,k):
#r-l+1 (l=a[l]//x r=a[r]//x
lo=0
hi=0
a.sort()
ans=0
lt=list(map(lambda s:s//x,a))
# k-(a[i]-1)//x
# print(lt)
for i in a:
val=k+((i-1)//x)
lr=bl(... | 0 | |
551 | A | GukiZ and Contest | PROGRAMMING | 800 | [
"brute force",
"implementation",
"sortings"
] | null | null | Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*). | In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input. | [
"3\n1 3 3\n",
"1\n1\n",
"5\n3 5 3 4 5\n"
] | [
"3 1 1\n",
"1\n",
"4 1 4 3 1\n"
] | In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first positi... | 500 | [
{
"input": "3\n1 3 3",
"output": "3 1 1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n3 5 3 4 5",
"output": "4 1 4 3 1"
},
{
"input": "7\n1 3 5 4 2 2 1",
"output": "6 3 1 2 4 4 6"
},
{
"input": "11\n5 6 4 2 9 7 6 6 6 6 7",
"output": "9 4 10 11 1 2 4 4... | 1,629,447,936 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 6,758,400 | n = int(input())
a = list(map(int,input().split()))
b = sorted(a)
for i in range(n):
for j in range(len(b)-1,-1,-1):
if a[i] == b[j]:
a[i] = n -j
break
print(a)
| Title: GukiZ and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the star... | ```python
n = int(input())
a = list(map(int,input().split()))
b = sorted(a)
for i in range(n):
for j in range(len(b)-1,-1,-1):
if a[i] == b[j]:
a[i] = n -j
break
print(a)
``` | 0 | |
675 | A | Infinite Sequence | PROGRAMMING | 1,100 | [
"math"
] | null | null | Vasya likes everything infinite. Now he is studying the properties of a sequence *s*, such that its first element is equal to *a* (*s*1<==<=*a*), and the difference between any two neighbouring elements is equal to *c* (*s**i*<=-<=*s**i*<=-<=1<==<=*c*). In particular, Vasya wonders if his favourite integer *b* appears ... | The first line of the input contain three integers *a*, *b* and *c* (<=-<=109<=≤<=*a*,<=*b*,<=*c*<=≤<=109) — the first element of the sequence, Vasya's favorite number and the difference between any two neighbouring elements of the sequence, respectively. | If *b* appears in the sequence *s* print "YES" (without quotes), otherwise print "NO" (without quotes). | [
"1 7 3\n",
"10 10 0\n",
"1 -4 5\n",
"0 60 50\n"
] | [
"YES\n",
"YES\n",
"NO\n",
"NO\n"
] | In the first sample, the sequence starts from integers 1, 4, 7, so 7 is its element.
In the second sample, the favorite integer of Vasya is equal to the first element of the sequence.
In the third sample all elements of the sequence are greater than Vasya's favorite integer.
In the fourth sample, the sequence starts... | 500 | [
{
"input": "1 7 3",
"output": "YES"
},
{
"input": "10 10 0",
"output": "YES"
},
{
"input": "1 -4 5",
"output": "NO"
},
{
"input": "0 60 50",
"output": "NO"
},
{
"input": "1 -4 -5",
"output": "YES"
},
{
"input": "0 1 0",
"output": "NO"
},
{
... | 1,583,662,535 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 109 | 0 | a, b, c = map(int, input().split())
ca, ba = c - a, b - a
try:
print(('YES', 'NO')[bool(ba % c) or (ba // abs(ba)) != (ca // abs(ca))])
except:
print(('YES', 'NO')[b != a])
| Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya likes everything infinite. Now he is studying the properties of a sequence *s*, such that its first element is equal to *a* (*s*1<==<=*a*), and the difference between any two neighbouring elements is equal to *c... | ```python
a, b, c = map(int, input().split())
ca, ba = c - a, b - a
try:
print(('YES', 'NO')[bool(ba % c) or (ba // abs(ba)) != (ca // abs(ca))])
except:
print(('YES', 'NO')[b != a])
``` | 0 | |
825 | C | Multi-judge Solving | PROGRAMMING | 1,600 | [
"greedy",
"implementation"
] | null | null | Makes solves problems on Decoforces and lots of other different online judges. Each problem is denoted by its difficulty — a positive integer number. Difficulties are measured the same across all the judges (the problem with difficulty *d* on Decoforces is as hard as the problem with difficulty *d* on any other judge).... | The first line contains two integer numbers *n*, *k* (1<=≤<=*n*<=≤<=103, 1<=≤<=*k*<=≤<=109).
The second line contains *n* space-separated integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print minimum number of problems Makes should solve on other judges in order to solve all chosen problems on Decoforces. | [
"3 3\n2 1 9\n",
"4 20\n10 3 6 3\n"
] | [
"1\n",
"0\n"
] | In the first example Makes at first solves problems 1 and 2. Then in order to solve the problem with difficulty 9, he should solve problem with difficulty no less than 5. The only available are difficulties 5 and 6 on some other judge. Solving any of these will give Makes opportunity to solve problem 3.
In the second ... | 0 | [
{
"input": "3 3\n2 1 9",
"output": "1"
},
{
"input": "4 20\n10 3 6 3",
"output": "0"
},
{
"input": "1 1000000000\n1",
"output": "0"
},
{
"input": "1 1\n3",
"output": "1"
},
{
"input": "50 100\n74 55 33 5 83 24 75 59 30 36 13 4 62 28 96 17 6 35 45 53 33 11 37 93 34... | 1,688,454,421 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 61 | 77 | 0 | import sys
import math
import collections
from heapq import heappush, heappop
input = sys.stdin.readline
ints = lambda: list(map(int, input().split()))
n, k = ints()
a = ints()
ans = 0
a.sort()
i = 0
while i < n:
if k < a[i]/2:
ans += 1
k = 2 * k
else:
i += 1
... | Title: Multi-judge Solving
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Makes solves problems on Decoforces and lots of other different online judges. Each problem is denoted by its difficulty — a positive integer number. Difficulties are measured the same across all the judges (the pro... | ```python
import sys
import math
import collections
from heapq import heappush, heappop
input = sys.stdin.readline
ints = lambda: list(map(int, input().split()))
n, k = ints()
a = ints()
ans = 0
a.sort()
i = 0
while i < n:
if k < a[i]/2:
ans += 1
k = 2 * k
else:
i +... | 3 | |
888 | B | Buggy Robot | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the cell (*x*,<=*y*) to (*x*,<=*y*<=+<=1); - D — move from (*x*,<=*y*) to (*x*,<=*y*<=-<=1); - L — mo... | The first line contains one number *n* — the length of sequence of commands entered by Ivan (1<=≤<=*n*<=≤<=100).
The second line contains the sequence itself — a string consisting of *n* characters. Each character can be U, D, L or R. | Print the maximum possible number of commands from the sequence the robot could perform to end up in the starting cell. | [
"4\nLDUR\n",
"5\nRRRUU\n",
"6\nLLRRRR\n"
] | [
"4\n",
"0\n",
"4\n"
] | none | 0 | [
{
"input": "4\nLDUR",
"output": "4"
},
{
"input": "5\nRRRUU",
"output": "0"
},
{
"input": "6\nLLRRRR",
"output": "4"
},
{
"input": "88\nLLUUULRDRRURDDLURRLRDRLLRULRUUDDLLLLRRDDURDURRLDURRLDRRRUULDDLRRRDDRRLUULLURDURUDDDDDLDR",
"output": "76"
},
{
"input": "89\nLDL... | 1,628,682,706 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 124 | 22,220,800 | n = int(input())
Str1 = input()
Arr = [0, 0 ,0, 0]
for I in range(n):
if Str1[l] == 'L': Arr[0] += 1
if Str1[l] == 'R': Arr[1] += 1
if Str1[l] == 'D': Arr[2] += 1
if Str1[l] == 'U': Arr[3] += 1
print (min(Arr[0],Arr[1] ) + min(Arr[2], Arr[3]))
| Title: Buggy Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the ce... | ```python
n = int(input())
Str1 = input()
Arr = [0, 0 ,0, 0]
for I in range(n):
if Str1[l] == 'L': Arr[0] += 1
if Str1[l] == 'R': Arr[1] += 1
if Str1[l] == 'D': Arr[2] += 1
if Str1[l] == 'U': Arr[3] += 1
print (min(Arr[0],Arr[1] ) + min(Arr[2], Arr[3]))
``` | -1 | |
137 | B | Permutation | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | "Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task after some considerable time, the boy asked you to help him.
The sequence of *n* integers is cal... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=5000) which represents how many numbers are in the sequence. The second line contains a sequence of integers *a**i* (1<=≤<=*a**i*<=≤<=5000,<=1<=≤<=*i*<=≤<=*n*). | Print the only number — the minimum number of changes needed to get the permutation. | [
"3\n3 1 2\n",
"2\n2 2\n",
"5\n5 3 3 3 1\n"
] | [
"0\n",
"1\n",
"2\n"
] | The first sample contains the permutation, which is why no replacements are required.
In the second sample it is enough to replace the first element with the number 1 and that will make the sequence the needed permutation.
In the third sample we can replace the second element with number 4 and the fourth element with... | 1,000 | [
{
"input": "3\n3 1 2",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "5\n5 3 3 3 1",
"output": "2"
},
{
"input": "5\n6 6 6 6 6",
"output": "5"
},
{
"input": "10\n1 1 2 2 8 8 7 7 9 9",
"output": "5"
},
{
"input": "8\n9 8 7 6 5 4 3 2"... | 1,441,020,189 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 124 | 409,600 | N = int(input())
A = list(int(i) for i in input().split())
S = set()
for k in A:
if(1<=k and k<=N):
S.add(k)
print(N-len(S)) | Title: Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task ... | ```python
N = int(input())
A = list(int(i) for i in input().split())
S = set()
for k in A:
if(1<=k and k<=N):
S.add(k)
print(N-len(S))
``` | 3 | |
965 | B | Battleship | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Arkady is playing Battleship. The rules of this game aren't really important.
There is a field of $n \times n$ cells. There should be exactly one $k$-decker on the field, i. e. a ship that is $k$ cells long oriented either horizontally or vertically. However, Arkady doesn't know where it is located. For each cell Arka... | The first line contains two integers $n$ and $k$ ($1 \le k \le n \le 100$) — the size of the field and the size of the ship.
The next $n$ lines contain the field. Each line contains $n$ characters, each of which is either '#' (denotes a definitely empty cell) or '.' (denotes a cell that can belong to the ship). | Output two integers — the row and the column of a cell that belongs to the maximum possible number of different locations of the ship.
If there are multiple answers, output any of them. In particular, if no ship can be placed on the field, you can output any cell. | [
"4 3\n#..#\n#.#.\n....\n.###\n",
"10 4\n#....##...\n.#...#....\n..#..#..#.\n...#.#....\n.#..##.#..\n.....#...#\n...#.##...\n.#...#.#..\n.....#..#.\n...#.#...#\n",
"19 6\n##..............###\n#......#####.....##\n.....#########.....\n....###########....\n...#############...\n..###############..\n.###############... | [
"3 2\n",
"6 1\n",
"1 8\n"
] | The picture below shows the three possible locations of the ship that contain the cell $(3, 2)$ in the first sample. | 1,000 | [
{
"input": "4 3\n#..#\n#.#.\n....\n.###",
"output": "3 2"
},
{
"input": "10 4\n#....##...\n.#...#....\n..#..#..#.\n...#.#....\n.#..##.#..\n.....#...#\n...#.##...\n.#...#.#..\n.....#..#.\n...#.#...#",
"output": "6 1"
},
{
"input": "19 6\n##..............###\n#......#####.....##\n.....####... | 1,610,976,761 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 12 | 716 | 307,200 |
def battleship(arr,k):
pts=[[0]*len(arr) for i in range(len(arr))]
ans=[0,0]
maxi=0
for i in range(len(arr)):
for j in range(len(arr)):
if arr[i][j]==".":
good=0
count=0
flag=True
s=i
temp=[... | Title: Battleship
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arkady is playing Battleship. The rules of this game aren't really important.
There is a field of $n \times n$ cells. There should be exactly one $k$-decker on the field, i. e. a ship that is $k$ cells long oriented either ... | ```python
def battleship(arr,k):
pts=[[0]*len(arr) for i in range(len(arr))]
ans=[0,0]
maxi=0
for i in range(len(arr)):
for j in range(len(arr)):
if arr[i][j]==".":
good=0
count=0
flag=True
s=i
... | 0 | |
148 | A | Insomnia cure | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | «One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entertained herself at best she could. Tonight she imagined that all dragons were here to steal her, and ... | Input data contains integer numbers *k*,<=*l*,<=*m*,<=*n* and *d*, each number in a separate line (1<=≤<=*k*,<=*l*,<=*m*,<=*n*<=≤<=10, 1<=≤<=*d*<=≤<=105). | Output the number of damaged dragons. | [
"1\n2\n3\n4\n12\n",
"2\n3\n4\n5\n24\n"
] | [
"12\n",
"17\n"
] | In the first case every first dragon got punched with a frying pan. Some of the dragons suffered from other reasons as well, but the pan alone would be enough.
In the second case dragons 1, 7, 11, 13, 17, 19 and 23 escaped unharmed. | 1,000 | [
{
"input": "1\n2\n3\n4\n12",
"output": "12"
},
{
"input": "2\n3\n4\n5\n24",
"output": "17"
},
{
"input": "1\n1\n1\n1\n100000",
"output": "100000"
},
{
"input": "10\n9\n8\n7\n6",
"output": "0"
},
{
"input": "8\n4\n4\n3\n65437",
"output": "32718"
},
{
"i... | 1,696,432,193 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 122 | 0 | # -*- coding: utf-8 -*-
"""
Created on Wed Oct 4 21:12:31 2023
@author: 25419
"""
k=int(input())
l=int(input())
m=int(input())
n=int(input())
d=int(input())
sum=0
for i in range(1,d+1):
if i%k!=0 and i%l!=0 and i%m!=0 and i%n!=0:
sum=sum+1
else:pass
print(d-sum) | Title: Insomnia cure
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
«One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entert... | ```python
# -*- coding: utf-8 -*-
"""
Created on Wed Oct 4 21:12:31 2023
@author: 25419
"""
k=int(input())
l=int(input())
m=int(input())
n=int(input())
d=int(input())
sum=0
for i in range(1,d+1):
if i%k!=0 and i%l!=0 and i%m!=0 and i%n!=0:
sum=sum+1
else:pass
print(d-sum)
``` | 3 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,648,288,820 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 62 | 0 | a=str(input())
s=0
d=0
for i in a:
if i>='A' and i<='Z':
s+=1
else:
d+=1
if d<s:
print(a.upper())
elif d>=s:
print(a.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
a=str(input())
s=0
d=0
for i in a:
if i>='A' and i<='Z':
s+=1
else:
d+=1
if d<s:
print(a.upper())
elif d>=s:
print(a.lower())
``` | 3.9845 |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,670,933,390 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 61 | 0 | newword = ""
uword = input("Input word: ")
if len(uword) > 10:
for x in range(len(uword)):
if uword != "4":
uword.replace(uword[x], "")
uword.split()
newword = f"{uword[0]}{len(uword)-2}{uword[len(uword)-1]}"
else:
newword = "word"
print(neww... | Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
newword = ""
uword = input("Input word: ")
if len(uword) > 10:
for x in range(len(uword)):
if uword != "4":
uword.replace(uword[x], "")
uword.split()
newword = f"{uword[0]}{len(uword)-2}{uword[len(uword)-1]}"
else:
newword = "word"
... | 0 |
672 | A | Summer Camp | PROGRAMMING | 800 | [
"implementation"
] | null | null | Every year, hundreds of people come to summer camps, they learn new algorithms and solve hard problems.
This is your first year at summer camp, and you are asked to solve the following problem. All integers starting with 1 are written in one line. The prefix of these line is "123456789101112131415...". Your task is to... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the position of the digit you need to print. | Print the *n*-th digit of the line. | [
"3\n",
"11\n"
] | [
"3\n",
"0\n"
] | In the first sample the digit at position 3 is '3', as both integers 1 and 2 consist on one digit.
In the second sample, the digit at position 11 is '0', it belongs to the integer 10. | 500 | [
{
"input": "3",
"output": "3"
},
{
"input": "11",
"output": "0"
},
{
"input": "12",
"output": "1"
},
{
"input": "13",
"output": "1"
},
{
"input": "29",
"output": "9"
},
{
"input": "30",
"output": "2"
},
{
"input": "1000",
"output": "3"
... | 1,660,667,702 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 46 | 0 | def l(n):
if(n==0):
return 0
else:
return 1 + l(n//10)
n = int(input())
s = 0
i = 0
while(s < n):
t = l(i)
if(s + t < n):
s += t
i += 1
else:
break
st = str(i)
print(st[(n-s)-1])
| Title: Summer Camp
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Every year, hundreds of people come to summer camps, they learn new algorithms and solve hard problems.
This is your first year at summer camp, and you are asked to solve the following problem. All integers starting with 1... | ```python
def l(n):
if(n==0):
return 0
else:
return 1 + l(n//10)
n = int(input())
s = 0
i = 0
while(s < n):
t = l(i)
if(s + t < n):
s += t
i += 1
else:
break
st = str(i)
print(st[(n-s)-1])
``` | 3 | |
166 | E | Tetrahedron | PROGRAMMING | 1,500 | [
"dp",
"math",
"matrices"
] | null | null | You are given a tetrahedron. Let's mark its vertices with letters *A*, *B*, *C* and *D* correspondingly.
An ant is standing in the vertex *D* of the tetrahedron. The ant is quite active and he wouldn't stay idle. At each moment of time he makes a step from one vertex to another one along some edge of the tetrahedron. ... | The first line contains the only integer *n* (1<=≤<=*n*<=≤<=107) — the required length of the cyclic path. | Print the only integer — the required number of ways modulo 1000000007 (109<=+<=7). | [
"2\n",
"4\n"
] | [
"3\n",
"21\n"
] | The required paths in the first sample are:
- *D* - *A* - *D* - *D* - *B* - *D* - *D* - *C* - *D* | 1,000 | [
{
"input": "2",
"output": "3"
},
{
"input": "4",
"output": "21"
},
{
"input": "1",
"output": "0"
},
{
"input": "3",
"output": "6"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "183"
},
{
"input": "7",
"output": "546"
... | 1,658,476,782 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 2,000 | 716,800 | from operator import itemgetter
from typing import *
from collections import deque, Counter, defaultdict
from bisect import *
import heapq, math
from functools import cmp_to_key, reduce
# from sortedcontainers import SortedSet
def main():
n = int(input())
mod = int(1e9 + 7)
def get_bn(x):
... | Title: Tetrahedron
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a tetrahedron. Let's mark its vertices with letters *A*, *B*, *C* and *D* correspondingly.
An ant is standing in the vertex *D* of the tetrahedron. The ant is quite active and he wouldn't stay idle. At each m... | ```python
from operator import itemgetter
from typing import *
from collections import deque, Counter, defaultdict
from bisect import *
import heapq, math
from functools import cmp_to_key, reduce
# from sortedcontainers import SortedSet
def main():
n = int(input())
mod = int(1e9 + 7)
def g... | 0 | |
493 | B | Vasya and Wrestling | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers are equal, the wrestler whose sequence of points is lexicographically greater, wins.
If the sequences of... | The first line contains number *n* — the number of techniques that the wrestlers have used (1<=≤<=*n*<=≤<=2·105).
The following *n* lines contain integer numbers *a**i* (|*a**i*|<=≤<=109, *a**i*<=≠<=0). If *a**i* is positive, that means that the first wrestler performed the technique that was awarded with *a**i* poin... | If the first wrestler wins, print string "first", otherwise print "second" | [
"5\n1\n2\n-3\n-4\n3\n",
"3\n-1\n-2\n3\n",
"2\n4\n-4\n"
] | [
"second\n",
"first\n",
"second\n"
] | Sequence *x* = *x*<sub class="lower-index">1</sub>*x*<sub class="lower-index">2</sub>... *x*<sub class="lower-index">|*x*|</sub> is lexicographically larger than sequence *y* = *y*<sub class="lower-index">1</sub>*y*<sub class="lower-index">2</sub>... *y*<sub class="lower-index">|*y*|</sub>, if either |*x*| > |... | 1,000 | [
{
"input": "5\n1\n2\n-3\n-4\n3",
"output": "second"
},
{
"input": "3\n-1\n-2\n3",
"output": "first"
},
{
"input": "2\n4\n-4",
"output": "second"
},
{
"input": "7\n1\n2\n-3\n4\n5\n-6\n7",
"output": "first"
},
{
"input": "14\n1\n2\n3\n4\n5\n6\n7\n-8\n-9\n-10\n-11\n-... | 1,530,332,027 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 37 | 686 | 3,788,800 | n = int(input())
a = 0
a1 = ""
b = 0
b1 = ""
last = 0
for i in range(n):
k = int(input())
if k > 0:
last = 1
a += k
a1 = a1 + str(k)
elif k < 0:
last = 2
k = -k
b += k
b1 = b1 + str(k)
if a > b:
print("first")
elif b > a:
pr... | Title: Vasya and Wrestling
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers ... | ```python
n = int(input())
a = 0
a1 = ""
b = 0
b1 = ""
last = 0
for i in range(n):
k = int(input())
if k > 0:
last = 1
a += k
a1 = a1 + str(k)
elif k < 0:
last = 2
k = -k
b += k
b1 = b1 + str(k)
if a > b:
print("first")
elif b > ... | 0 | |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,514,012,104 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 545 | 6,963,200 | n = int(input())
d = []
for k in range(n):
if k % 2 == 0:
w = 'C'
else:
w = '.'
while True:
if len(w) == n:
break
else:
if w[-1] == '.':
w += 'C'
else:
w += '.'
d.append(w)
print(int(((n*n... | Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
n = int(input())
d = []
for k in range(n):
if k % 2 == 0:
w = 'C'
else:
w = '.'
while True:
if len(w) == n:
break
else:
if w[-1] == '.':
w += 'C'
else:
w += '.'
d.append(w)
print... | 3 | |
340 | A | The Wall | PROGRAMMING | 1,200 | [
"math"
] | null | null | Iahub and his friend Floyd have started painting a wall. Iahub is painting the wall red and Floyd is painting it pink. You can consider the wall being made of a very large number of bricks, numbered 1, 2, 3 and so on.
Iahub has the following scheme of painting: he skips *x*<=-<=1 consecutive bricks, then he paints th... | The input will have a single line containing four integers in this order: *x*, *y*, *a*, *b*. (1<=≤<=*x*,<=*y*<=≤<=1000, 1<=≤<=*a*,<=*b*<=≤<=2·109, *a*<=≤<=*b*). | Output a single integer — the number of bricks numbered no less than *a* and no greater than *b* that are painted both red and pink. | [
"2 3 6 18\n"
] | [
"3"
] | Let's look at the bricks from *a* to *b* (*a* = 6, *b* = 18). The bricks colored in red are numbered 6, 8, 10, 12, 14, 16, 18. The bricks colored in pink are numbered 6, 9, 12, 15, 18. The bricks colored in both red and pink are numbered with 6, 12 and 18. | 500 | [
{
"input": "2 3 6 18",
"output": "3"
},
{
"input": "4 6 20 201",
"output": "15"
},
{
"input": "15 27 100 10000",
"output": "74"
},
{
"input": "105 60 3456 78910",
"output": "179"
},
{
"input": "1 1 1000 100000",
"output": "99001"
},
{
"input": "3 2 5 5... | 1,527,074,476 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 1,000 | 307,200 | x, y, a, b = list(map(int,input().split()))
count = 0
for i in range(a,b+1):
if (i)%x==0 and (i)%y ==0:
count += 1
print(count) | Title: The Wall
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub and his friend Floyd have started painting a wall. Iahub is painting the wall red and Floyd is painting it pink. You can consider the wall being made of a very large number of bricks, numbered 1, 2, 3 and so on.
Iahub ... | ```python
x, y, a, b = list(map(int,input().split()))
count = 0
for i in range(a,b+1):
if (i)%x==0 and (i)%y ==0:
count += 1
print(count)
``` | 0 | |
519 | B | A and B and Compilation Errors | PROGRAMMING | 1,100 | [
"data structures",
"implementation",
"sortings"
] | null | null | A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time.
The third line contains *n*<=-<=1 space-sepa... | Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively. | [
"5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n",
"6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n"
] | [
"8\n123\n",
"1\n3\n"
] | In the first test sample B first corrects the error number 8, then the error number 123.
In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step. | 1,000 | [
{
"input": "5\n1 5 8 123 7\n123 7 5 1\n5 1 7",
"output": "8\n123"
},
{
"input": "6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5",
"output": "1\n3"
},
{
"input": "3\n1 2 3\n3 2\n2",
"output": "1\n3"
},
{
"input": "10\n460626451 802090732 277246428 661369649 388684428 784303821 376287098 6... | 1,626,351,342 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 373 | 34,611,200 | #BOILER CODE ....
map_inputs = lambda Type=int : map(Type,input().strip().split())
array_input = lambda n,Type=int : list(map_inputs(Type)) [:n]
matrix_input = lambda row,col,Type=int: [array_input(col,Type) for _ in range(row)]
str_matrix = lambda row,col: [input().strip()[:col] for _ in range(row)]
str_listed_m... | Title: A and B and Compilation Errors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler disp... | ```python
#BOILER CODE ....
map_inputs = lambda Type=int : map(Type,input().strip().split())
array_input = lambda n,Type=int : list(map_inputs(Type)) [:n]
matrix_input = lambda row,col,Type=int: [array_input(col,Type) for _ in range(row)]
str_matrix = lambda row,col: [input().strip()[:col] for _ in range(row)]
st... | 3 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,619,348,195 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 0 | n = input()
up = 0
low = 0
for i in n:
if i.isupper():
up += 1
else:
low += 1
if up > low:
print(n.upper())
elif low > up:
print(n.lower())
else:
print(n.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
n = input()
up = 0
low = 0
for i in n:
if i.isupper():
up += 1
else:
low += 1
if up > low:
print(n.upper())
elif low > up:
print(n.lower())
else:
print(n.lower())
``` | 3.969 |
66 | B | Petya and Countryside | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | B. Petya and Countryside | 2 | 256 | Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *n* equal square sections. The garden is very unusual as each of the square sections possesses its own f... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* positive integers which are the height of the sections. All the numbers are no less than 1 and not more than 1000. | Print a single number, the maximal number of watered sections if we create artificial rain above exactly one section. | [
"1\n2\n",
"5\n1 2 1 2 1\n",
"8\n1 2 1 1 1 3 3 4\n"
] | [
"1\n",
"3\n",
"6\n"
] | none | 1,000 | [
{
"input": "1\n2",
"output": "1"
},
{
"input": "5\n1 2 1 2 1",
"output": "3"
},
{
"input": "8\n1 2 1 1 1 3 3 4",
"output": "6"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "10"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "10"
},
{
"input... | 1,552,378,951 | 2,147,483,647 | Python 3 | OK | TESTS | 80 | 1,372 | 512,000 | n = int(input())
s = list(map(int, input().split()))
c = 1
d = 0
z = list()
for i in range(n):
for k in range(len(s[i:n])):
if k + i == n - 1:
break
if s[k+i] >= s[k + i + 1]:
c += 1
else:
break
for j in range(len(s[0:i+1])):
if j... | Title: Petya and Countryside
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *... | ```python
n = int(input())
s = list(map(int, input().split()))
c = 1
d = 0
z = list()
for i in range(n):
for k in range(len(s[i:n])):
if k + i == n - 1:
break
if s[k+i] >= s[k + i + 1]:
c += 1
else:
break
for j in range(len(s[0:i+1])):
... | 3.656046 |
899 | B | Months and Years | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Everybody in Russia uses Gregorian calendar. In this calendar there are 31 days in January, 28 or 29 days in February (depending on whether the year is leap or not), 31 days in March, 30 days in April, 31 days in May, 30 in June, 31 in July, 31 in August, 30 in September, 31 in October, 30 in November, 31 in December.
... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=24) — the number of integers.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (28<=≤<=*a**i*<=≤<=31) — the numbers you are to check. | If there are several consecutive months that fit the sequence, print "YES" (without quotes). Otherwise, print "NO" (without quotes).
You can print each letter in arbitrary case (small or large). | [
"4\n31 31 30 31\n",
"2\n30 30\n",
"5\n29 31 30 31 30\n",
"3\n31 28 30\n",
"3\n31 31 28\n"
] | [
"Yes\n\n",
"No\n\n",
"Yes\n\n",
"No\n\n",
"Yes\n\n"
] | In the first example the integers can denote months July, August, September and October.
In the second example the answer is no, because there are no two consecutive months each having 30 days.
In the third example the months are: February (leap year) — March — April – May — June.
In the fourth example the number of... | 1,000 | [
{
"input": "4\n31 31 30 31",
"output": "Yes"
},
{
"input": "2\n30 30",
"output": "No"
},
{
"input": "5\n29 31 30 31 30",
"output": "Yes"
},
{
"input": "3\n31 28 30",
"output": "No"
},
{
"input": "3\n31 31 28",
"output": "Yes"
},
{
"input": "24\n29 28 3... | 1,513,541,597 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 62 | 5,529,600 | def solution():
normal_year=[31,29,31,30,31,30,31,31,30,31,30,31]
leap_year=[31,28,31,30,31,30,31,31,30,31,30,31]
a=normal_year *2
b=leap_year *2
c=normal_year +leap_year
d=leap_year + normal_year
#f=open('input.txt', 'r')
n=int(input().strip())
inp=[int(a) for a in in... | Title: Months and Years
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Everybody in Russia uses Gregorian calendar. In this calendar there are 31 days in January, 28 or 29 days in February (depending on whether the year is leap or not), 31 days in March, 30 days in April, 31 days in May, ... | ```python
def solution():
normal_year=[31,29,31,30,31,30,31,31,30,31,30,31]
leap_year=[31,28,31,30,31,30,31,31,30,31,30,31]
a=normal_year *2
b=leap_year *2
c=normal_year +leap_year
d=leap_year + normal_year
#f=open('input.txt', 'r')
n=int(input().strip())
inp=[int(a) f... | 0 | |
712 | A | Memory and Crow | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | There are *n* integers *b*1,<=*b*2,<=...,<=*b**n* written in a row. For all *i* from 1 to *n*, values *a**i* are defined by the crows performing the following procedure:
- The crow sets *a**i* initially 0. - The crow then adds *b**i* to *a**i*, subtracts *b**i*<=+<=1, adds the *b**i*<=+<=2 number, and so on until th... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000) — the number of integers written in the row.
The next line contains *n*, the *i*'th of which is *a**i* (<=-<=109<=≤<=*a**i*<=≤<=109) — the value of the *i*'th number. | Print *n* integers corresponding to the sequence *b*1,<=*b*2,<=...,<=*b**n*. It's guaranteed that the answer is unique and fits in 32-bit integer type. | [
"5\n6 -4 8 -2 3\n",
"5\n3 -2 -1 5 6\n"
] | [
"2 4 6 1 3 \n",
"1 -3 4 11 6 \n"
] | In the first sample test, the crows report the numbers 6, - 4, 8, - 2, and 3 when he starts at indices 1, 2, 3, 4 and 5 respectively. It is easy to check that the sequence 2 4 6 1 3 satisfies the reports. For example, 6 = 2 - 4 + 6 - 1 + 3, and - 4 = 4 - 6 + 1 - 3.
In the second sample test, the sequence 1, - 3, 4, ... | 500 | [
{
"input": "5\n6 -4 8 -2 3",
"output": "2 4 6 1 3 "
},
{
"input": "5\n3 -2 -1 5 6",
"output": "1 -3 4 11 6 "
},
{
"input": "10\n13 -2 532 -63 -23 -63 -64 -23 12 10",
"output": "11 530 469 -86 -86 -127 -87 -11 22 10 "
},
{
"input": "10\n0 0 0 0 0 0 0 0 0 0",
"output": "0 0... | 1,473,527,794 | 1,894 | Python 3 | OK | TESTS | 49 | 296 | 8,192,000 | n = int(input())
arr = [int(x) for x in input().split()]
brr = [arr[n-1]]
for i in range(n-2,-1,-1):
x = +arr[i+1]+arr[i]
brr.append(x)
crr = brr[::-1]
s = str(crr[0])
for i in range(1,n):
s += ' '+str(crr[i])
print(s)
| Title: Memory and Crow
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* integers *b*1,<=*b*2,<=...,<=*b**n* written in a row. For all *i* from 1 to *n*, values *a**i* are defined by the crows performing the following procedure:
- The crow sets *a**i* initially 0. - The crow... | ```python
n = int(input())
arr = [int(x) for x in input().split()]
brr = [arr[n-1]]
for i in range(n-2,-1,-1):
x = +arr[i+1]+arr[i]
brr.append(x)
crr = brr[::-1]
s = str(crr[0])
for i in range(1,n):
s += ' '+str(crr[i])
print(s)
``` | 3 | |
578 | A | A Problem about Polyline | PROGRAMMING | 1,700 | [
"geometry",
"math"
] | null | null | There is a polyline going through points (0,<=0)<=–<=(*x*,<=*x*)<=–<=(2*x*,<=0)<=–<=(3*x*,<=*x*)<=–<=(4*x*,<=0)<=–<=...<=-<=(2*kx*,<=0)<=–<=(2*kx*<=+<=*x*,<=*x*)<=–<=....
We know that the polyline passes through the point (*a*,<=*b*). Find minimum positive value *x* such that it is true or determine that there is no ... | Only one line containing two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=109). | Output the only line containing the answer. Your answer will be considered correct if its relative or absolute error doesn't exceed 10<=-<=9. If there is no such *x* then output <=-<=1 as the answer. | [
"3 1\n",
"1 3\n",
"4 1\n"
] | [
"1.000000000000\n",
"-1\n",
"1.250000000000\n"
] | You can see following graphs for sample 1 and sample 3. | 250 | [
{
"input": "3 1",
"output": "1.000000000000"
},
{
"input": "1 3",
"output": "-1"
},
{
"input": "4 1",
"output": "1.250000000000"
},
{
"input": "1000000000 1000000000",
"output": "1000000000.000000000000"
},
{
"input": "1000000000 1",
"output": "1.000000001000"... | 1,443,865,923 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 46 | 0 | a, b = map(int, input().split())
if b > a:
print(-1)
else:
x1 = a + b
x2 = a - b
x = b
print(min(x1 / 2 / (x1 // (2 * x)), x2 / 2 / (x2 // (2 * x))))
| Title: A Problem about Polyline
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a polyline going through points (0,<=0)<=–<=(*x*,<=*x*)<=–<=(2*x*,<=0)<=–<=(3*x*,<=*x*)<=–<=(4*x*,<=0)<=–<=...<=-<=(2*kx*,<=0)<=–<=(2*kx*<=+<=*x*,<=*x*)<=–<=....
We know that the polyline passes thro... | ```python
a, b = map(int, input().split())
if b > a:
print(-1)
else:
x1 = a + b
x2 = a - b
x = b
print(min(x1 / 2 / (x1 // (2 * x)), x2 / 2 / (x2 // (2 * x))))
``` | -1 | |
1,008 | A | Romaji | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant... | The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters. | Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"sumimasen\n",
"ninja\n",
"codeforces\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | 500 | [
{
"input": "sumimasen",
"output": "YES"
},
{
"input": "ninja",
"output": "YES"
},
{
"input": "codeforces",
"output": "NO"
},
{
"input": "auuaoonntanonnuewannnnpuuinniwoonennyolonnnvienonpoujinndinunnenannmuveoiuuhikucuziuhunnnmunzancenen",
"output": "YES"
},
{
"in... | 1,681,140,318 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 46 | 0 | string = input()
ref =[ "a", "o", "u", "i", "e"]
res = 'YES'
for i in range(0 , len(string)-1) :
if string[i] not in ref and string[i+1] not in ref and string[i] !="n" :
res ="NO"
break
print(res) | Title: Romaji
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after eve... | ```python
string = input()
ref =[ "a", "o", "u", "i", "e"]
res = 'YES'
for i in range(0 , len(string)-1) :
if string[i] not in ref and string[i+1] not in ref and string[i] !="n" :
res ="NO"
break
print(res)
``` | 0 | |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The produ... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second... | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,688,867,714 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | n = int(input())
arr = list(map(int, input().split()))
nArr, pArr, zArr = [], [], []
sortedArr = sorted(arr)
l0 = sortedArr.index(0)
c0 = sortedArr.count(0)
r0 = l0 if c0 == 1 else l0 + c0
if sortedArr[-1] == 0:
nArr = sortedArr[0:1]
pArr = sortedArr[1:l0]
zArr = sortedArr[l0:]
else:
n... | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. T... | ```python
n = int(input())
arr = list(map(int, input().split()))
nArr, pArr, zArr = [], [], []
sortedArr = sorted(arr)
l0 = sortedArr.index(0)
c0 = sortedArr.count(0)
r0 = l0 if c0 == 1 else l0 + c0
if sortedArr[-1] == 0:
nArr = sortedArr[0:1]
pArr = sortedArr[1:l0]
zArr = sortedArr[l0:]
el... | 0 | |
710 | B | Optimal Point on a Line | PROGRAMMING | 1,400 | [
"brute force",
"sortings"
] | null | null | You are given *n* points on a line with their coordinates *x**i*. Find the point *x* so the sum of distances to the given points is minimal. | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of points on the line.
The second line contains *n* integers *x**i* (<=-<=109<=≤<=*x**i*<=≤<=109) — the coordinates of the given *n* points. | Print the only integer *x* — the position of the optimal point on the line. If there are several optimal points print the position of the leftmost one. It is guaranteed that the answer is always the integer. | [
"4\n1 2 3 4\n"
] | [
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 3 4",
"output": "2"
},
{
"input": "5\n-1 -10 2 6 7",
"output": "2"
},
{
"input": "10\n-68 10 87 22 30 89 82 -97 -52 25",
"output": "22"
},
{
"input": "100\n457 827 807 17 871 935 907 -415 536 170 551 -988 865 758 -457 -892 -875 -488 684 19 0 555 -807 -624 -... | 1,614,564,686 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 124 | 2,150,400 | while true:
try:
n=input().strip()
a=list(map(int,input().strip().split()))
b=sorted(a)
if (len(b)%2) == 0:
print(b[int((len(b)/2))-1])
else:
print(b[int((len(b)/2))])
except EOFError:
break
| Title: Optimal Point on a Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* points on a line with their coordinates *x**i*. Find the point *x* so the sum of distances to the given points is minimal.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=... | ```python
while true:
try:
n=input().strip()
a=list(map(int,input().strip().split()))
b=sorted(a)
if (len(b)%2) == 0:
print(b[int((len(b)/2))-1])
else:
print(b[int((len(b)/2))])
except EOFError:
break
``` | -1 | |
886 | A | ACM ICPC | PROGRAMMING | 1,000 | [
"brute force"
] | null | null | In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams.
After practice competition, participant number *i* got a score of *a**i*. ... | The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants | Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"1 3 2 1 2 1\n",
"1 1 1 1 1 99\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5.
In the second sample, score of participant number 6 is too high: his team score will be definitely greater. | 500 | [
{
"input": "1 3 2 1 2 1",
"output": "YES"
},
{
"input": "1 1 1 1 1 99",
"output": "NO"
},
{
"input": "1000 1000 1000 1000 1000 1000",
"output": "YES"
},
{
"input": "0 0 0 0 0 0",
"output": "YES"
},
{
"input": "633 609 369 704 573 416",
"output": "NO"
},
{
... | 1,653,827,663 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 614,400 | from typing import List
def solve(a: List[int]):
sum_a = sum(a)
for i in range(4):
for j in range(i + 1, 5):
for k in range(j + 1, 6):
if sum_a == (a[i]+a[j]+a[k]) * 2:
return "YES"
return "NO"
a = list(map(int, input().split()))
pri... | Title: ACM ICPC
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build ... | ```python
from typing import List
def solve(a: List[int]):
sum_a = sum(a)
for i in range(4):
for j in range(i + 1, 5):
for k in range(j + 1, 6):
if sum_a == (a[i]+a[j]+a[k]) * 2:
return "YES"
return "NO"
a = list(map(int, input().spli... | -1 | |
462 | A | Appleman and Easy Task | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or character 'o'. Is it true that each cell of the board has even number of adjacent cells with 'o'? Two cells... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Then *n* lines follow containing the description of the checkerboard. Each of them contains *n* characters (either 'x' or 'o') without spaces. | Print "YES" or "NO" (without the quotes) depending on the answer to the problem. | [
"3\nxxo\nxox\noxx\n",
"4\nxxxo\nxoxo\noxox\nxxxx\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "3\nxxo\nxox\noxx",
"output": "YES"
},
{
"input": "4\nxxxo\nxoxo\noxox\nxxxx",
"output": "NO"
},
{
"input": "1\no",
"output": "YES"
},
{
"input": "2\nox\nxo",
"output": "YES"
},
{
"input": "2\nxx\nxo",
"output": "NO"
},
{
"input": "3\nooo\no... | 1,424,093,955 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 62 | 102,400 | n = int(input())
checker = [[0 for j in range(n)] for i in range(n)]
for i in range(n):
string = input()
for j in range(n):
checker[i][j] = string[j]
#print (checker)
for i in range(n):
for j in range(n):
count = 0
if i-1 >= 0 and checker[i-1][j] == 'o': count += 1
... | Title: Appleman and Easy Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or... | ```python
n = int(input())
checker = [[0 for j in range(n)] for i in range(n)]
for i in range(n):
string = input()
for j in range(n):
checker[i][j] = string[j]
#print (checker)
for i in range(n):
for j in range(n):
count = 0
if i-1 >= 0 and checker[i-1][j] == 'o': count += ... | 3 | |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,461,515,998 | 298 | Python 3 | OK | TESTS | 26 | 62 | 4,608,000 |
n = int(input())
print((n // 3) * 2 + (1 if n % 3 else 0))
| Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
n = int(input())
print((n // 3) * 2 + (1 if n % 3 else 0))
``` | 3 | |
618 | A | Slime Combining | PROGRAMMING | 800 | [
"implementation"
] | null | null | Your friend recently gave you some slimes for your birthday. You have *n* slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other *n*<=-<=1 slimes one by one. When you add a slime, you place it at the right of... | The first line of the input will contain a single integer, *n* (1<=≤<=*n*<=≤<=100<=000). | Output a single line with *k* integers, where *k* is the number of slimes in the row after you've finished the procedure described in the problem statement. The *i*-th of these numbers should be the value of the *i*-th slime from the left. | [
"1\n",
"2\n",
"3\n",
"8\n"
] | [
"1\n",
"2\n",
"2 1\n",
"4\n"
] | In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. S... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "2 1"
},
{
"input": "8",
"output": "4"
},
{
"input": "100000",
"output": "17 16 11 10 8 6"
},
{
"input": "12345",
"output": "14 13 6 5 4 1"
},
{
"in... | 1,454,222,657 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 62 | 0 | n=int(input())
i=1
k=1
a=[]
while i<=n:
if i&n:
a.append(k)
i<<=1
k+=1
for i in range(len(a)-1,-1,-1):
print(a[i],end=' ') | Title: Slime Combining
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend recently gave you some slimes for your birthday. You have *n* slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, y... | ```python
n=int(input())
i=1
k=1
a=[]
while i<=n:
if i&n:
a.append(k)
i<<=1
k+=1
for i in range(len(a)-1,-1,-1):
print(a[i],end=' ')
``` | 3 | |
946 | B | Weird Subtraction Process | PROGRAMMING | 1,100 | [
"math",
"number theory"
] | null | null | You have two variables *a* and *b*. Consider the following sequence of actions performed with these variables:
1. If *a*<==<=0 or *b*<==<=0, end the process. Otherwise, go to step 2;1. If *a*<=≥<=2·*b*, then set the value of *a* to *a*<=-<=2·*b*, and repeat step 1. Otherwise, go to step 3;1. If *b*<=≥<=2·*a*, then s... | The only line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1018). *n* is the initial value of variable *a*, and *m* is the initial value of variable *b*. | Print two integers — the values of *a* and *b* after the end of the process. | [
"12 5\n",
"31 12\n"
] | [
"0 1\n",
"7 12\n"
] | Explanations to the samples:
1. *a* = 12, *b* = 5 <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> *a* = 2, *b* = 5 <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0... | 0 | [
{
"input": "12 5",
"output": "0 1"
},
{
"input": "31 12",
"output": "7 12"
},
{
"input": "1000000000000000000 7",
"output": "8 7"
},
{
"input": "31960284556200 8515664064180",
"output": "14928956427840 8515664064180"
},
{
"input": "1000000000000000000 100000000000... | 1,537,814,106 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a,b=input("Inserte a y b respectivamente: ").split()
a,b=[int(a),int(b)]
n=a
m=b
def checkMahNums(n,m):
if(n<1 or m>=10**18):
return print("This number is not valid")
def ShowMeTheSub(a,b):
if a==0 or b==0:
#while a!=0 and b!=0:
#if a>=2*b:
#a=a-(2*b)
#eli... | Title: Weird Subtraction Process
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have two variables *a* and *b*. Consider the following sequence of actions performed with these variables:
1. If *a*<==<=0 or *b*<==<=0, end the process. Otherwise, go to step 2;1. If *a*<=≥<=2·*b*, then... | ```python
a,b=input("Inserte a y b respectivamente: ").split()
a,b=[int(a),int(b)]
n=a
m=b
def checkMahNums(n,m):
if(n<1 or m>=10**18):
return print("This number is not valid")
def ShowMeTheSub(a,b):
if a==0 or b==0:
#while a!=0 and b!=0:
#if a>=2*b:
#a=a-(2*b)
... | -1 | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,596,712,617 | 2,147,483,647 | PyPy 3 | OK | TESTS | 51 | 1,308 | 28,160,000 | import sys
import math
input = sys.stdin.readline
def solve():
def magic(n):
return sum([int(ch) for ch in str(n)])
n = int(input().strip())
ans = 0
while n >= 10:
ans += 1
n = magic(n)
print(ans)
if __name__ == '__main__':
solve()
| Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
import sys
import math
input = sys.stdin.readline
def solve():
def magic(n):
return sum([int(ch) for ch in str(n)])
n = int(input().strip())
ans = 0
while n >= 10:
ans += 1
n = magic(n)
print(ans)
if __name__ == '__main__':
solve()
``` | 3.622329 |
883 | A | Automatic Door | PROGRAMMING | 2,200 | [
"implementation"
] | null | null | There is an automatic door at the entrance of a factory. The door works in the following way:
- when one or several people come to the door and it is closed, the door immediately opens automatically and all people immediately come inside, - when one or several people come to the door and it is open, all people immed... | The first line contains four integers *n*, *m*, *a* and *d* (1<=≤<=*n*,<=*a*<=≤<=109, 1<=≤<=*m*<=≤<=105, 1<=≤<=*d*<=≤<=1018) — the number of the employees, the number of the clients, the moment of time when the first employee will come and the period of time in which the door closes.
The second line contains integer s... | Print the number of times the door will open. | [
"1 1 3 4\n7\n",
"4 3 4 2\n7 9 11\n"
] | [
"1\n",
"4\n"
] | In the first example the only employee will come at moment 3. At this moment the door will open and will stay open until the moment 7. At the same moment of time the client will come, so at first he will enter and only after it the door will close. Thus the door will open one time. | 0 | [
{
"input": "1 1 3 4\n7",
"output": "1"
},
{
"input": "4 3 4 2\n7 9 11",
"output": "4"
},
{
"input": "10 10 51 69\n154 170 170 183 251 337 412 426 445 452",
"output": "6"
},
{
"input": "70 10 26 17\n361 371 579 585 629 872 944 1017 1048 1541",
"output": "70"
},
{
"... | 1,509,812,638 | 838 | Python 3 | RUNTIME_ERROR | TESTS | 10 | 108 | 9,318,400 | import sys
def readIntLine():
return [int(n) for n in next(sys.stdin).strip().split()]
N, M, A, D = readIntLine()
times = readIntLine()
eTimes = list(range(A, A + N * A, A))
times = sorted(times + eTimes)
c = -1
count = 0
for t in times:
if t <= c:
continue
c = t + D
count += 1
print(cou... | Title: Automatic Door
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is an automatic door at the entrance of a factory. The door works in the following way:
- when one or several people come to the door and it is closed, the door immediately opens automatically and all people imme... | ```python
import sys
def readIntLine():
return [int(n) for n in next(sys.stdin).strip().split()]
N, M, A, D = readIntLine()
times = readIntLine()
eTimes = list(range(A, A + N * A, A))
times = sorted(times + eTimes)
c = -1
count = 0
for t in times:
if t <= c:
continue
c = t + D
count += 1
... | -1 | |
622 | A | Infinite Sequence | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains ... | The only line contains integer *n* (1<=≤<=*n*<=≤<=1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | Print the element in the *n*-th position of the sequence (the elements are numerated from one). | [
"3\n",
"5\n",
"10\n",
"55\n",
"56\n"
] | [
"2\n",
"2\n",
"4\n",
"10\n",
"1\n"
] | none | 0 | [
{
"input": "3",
"output": "2"
},
{
"input": "5",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "55",
"output": "10"
},
{
"input": "56",
"output": "1"
},
{
"input": "1000000000000",
"output": "88209"
},
{
"input": "8471941278... | 1,591,012,504 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 15,974,400 | n = int(input())
pos = []
number = [1]
while len(pos)<n:
pos = pos + number
number.append(number[-1]+1)
print(pos[n-1])
| Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2,... | ```python
n = int(input())
pos = []
number = [1]
while len(pos)<n:
pos = pos + number
number.append(number[-1]+1)
print(pos[n-1])
``` | 0 | |
574 | B | Bear and Three Musketeers | PROGRAMMING | 1,500 | [
"brute force",
"dfs and similar",
"graphs",
"hashing"
] | null | null | Do you know a story about the three musketeers? Anyway, you will learn about its origins now.
Richelimakieu is a cardinal in the city of Bearis. He is tired of dealing with crime by himself. He needs three brave warriors to help him to fight against bad guys.
There are *n* warriors. Richelimakieu wants to choose thre... | The first line contains two space-separated integers, *n* and *m* (3<=≤<=*n*<=≤<=4000, 0<=≤<=*m*<=≤<=4000) — respectively number of warriors and number of pairs of warriors knowing each other.
*i*-th of the following *m* lines contains two space-separated integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**... | If Richelimakieu can choose three musketeers, print the minimum possible sum of their recognitions. Otherwise, print "-1" (without the quotes). | [
"5 6\n1 2\n1 3\n2 3\n2 4\n3 4\n4 5\n",
"7 4\n2 1\n3 6\n5 1\n1 7\n"
] | [
"2\n",
"-1\n"
] | In the first sample Richelimakieu should choose a triple 1, 2, 3. The first musketeer doesn't know anyone except other two musketeers so his recognition is 0. The second musketeer has recognition 1 because he knows warrior number 4. The third musketeer also has recognition 1 because he knows warrior 4. Sum of recogniti... | 1,000 | [
{
"input": "5 6\n1 2\n1 3\n2 3\n2 4\n3 4\n4 5",
"output": "2"
},
{
"input": "7 4\n2 1\n3 6\n5 1\n1 7",
"output": "-1"
},
{
"input": "5 0",
"output": "-1"
},
{
"input": "7 14\n3 6\n2 3\n5 2\n5 6\n7 5\n7 4\n6 2\n3 5\n7 1\n4 1\n6 1\n7 6\n6 4\n5 4",
"output": "5"
},
{
... | 1,557,423,101 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 39 | 2,000 | 34,816,000 | def dfs(no_at, pai, princ, i):
if i == 3:
if princ in adj[no_at]:
respostas.append((princ, pai, no_at))
return
for child in adj[no_at]:
if child == pai: continue
dfs(child, no_at, princ, i+1)
m, n = map(int, input().split())
adj = [[] for i in range... | Title: Bear and Three Musketeers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Do you know a story about the three musketeers? Anyway, you will learn about its origins now.
Richelimakieu is a cardinal in the city of Bearis. He is tired of dealing with crime by himself. He needs three br... | ```python
def dfs(no_at, pai, princ, i):
if i == 3:
if princ in adj[no_at]:
respostas.append((princ, pai, no_at))
return
for child in adj[no_at]:
if child == pai: continue
dfs(child, no_at, princ, i+1)
m, n = map(int, input().split())
adj = [[] for ... | 0 | |
239 | A | Two Bags of Potatoes | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, first... | The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). | Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1. | [
"10 1 10\n",
"10 6 40\n"
] | [
"-1\n",
"2 8 14 20 26 \n"
] | none | 500 | [
{
"input": "10 1 10",
"output": "-1"
},
{
"input": "10 6 40",
"output": "2 8 14 20 26 "
},
{
"input": "10 1 20",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "1 10000 1000000000",
"output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 12999... | 1,618,295,770 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 92 | 0 | def solution():
#why
y,k,n=map(int,input().split())
ans=[]
mul=1
while mul*k<=n:
if (mul*k)>y:
ans.append((mul*k)-y)
mul+=1
if ans:
print(*ans[::-1])
else:
print(-1)
solution() | Title: Two Bags of Potatoes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* pota... | ```python
def solution():
#why
y,k,n=map(int,input().split())
ans=[]
mul=1
while mul*k<=n:
if (mul*k)>y:
ans.append((mul*k)-y)
mul+=1
if ans:
print(*ans[::-1])
else:
print(-1)
solution()
``` | 0 | |
389 | A | Fox and Number Game | PROGRAMMING | 1,000 | [
"greedy",
"math"
] | null | null | Fox Ciel is playing a game with numbers now.
Ciel has *n* positive integers: *x*1, *x*2, ..., *x**n*. She can do the following operation as many times as needed: select two different indexes *i* and *j* such that *x**i* > *x**j* hold, and then apply assignment *x**i* = *x**i* - *x**j*. The goal is to make the sum ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=100). Then the second line contains *n* integers: *x*1, *x*2, ..., *x**n* (1<=≤<=*x**i*<=≤<=100). | Output a single integer — the required minimal sum. | [
"2\n1 2\n",
"3\n2 4 6\n",
"2\n12 18\n",
"5\n45 12 27 30 18\n"
] | [
"2\n",
"6\n",
"12\n",
"15\n"
] | In the first example the optimal way is to do the assignment: *x*<sub class="lower-index">2</sub> = *x*<sub class="lower-index">2</sub> - *x*<sub class="lower-index">1</sub>.
In the second example the optimal sequence of operations is: *x*<sub class="lower-index">3</sub> = *x*<sub class="lower-index">3</sub> - *x*<sub... | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n2 4 6",
"output": "6"
},
{
"input": "2\n12 18",
"output": "12"
},
{
"input": "5\n45 12 27 30 18",
"output": "15"
},
{
"input": "2\n1 1",
"output": "2"
},
{
"input": "2\n100 100",
"output": "200"
... | 1,467,116,793 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 78 | 0 | n = int(input())
a = [int(x) for x in input().split()]
while any(x != a[0] for x in a):
a.sort()
a = [a[i] - a[0] if a[i] > a[0] else a[i] for i in range(0, n)]
print(sum(a))
| Title: Fox and Number Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel is playing a game with numbers now.
Ciel has *n* positive integers: *x*1, *x*2, ..., *x**n*. She can do the following operation as many times as needed: select two different indexes *i* and *j* such that ... | ```python
n = int(input())
a = [int(x) for x in input().split()]
while any(x != a[0] for x in a):
a.sort()
a = [a[i] - a[0] if a[i] > a[0] else a[i] for i in range(0, n)]
print(sum(a))
``` | 3 | |
124 | A | The number of positions | PROGRAMMING | 1,000 | [
"math"
] | null | null | Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind him. Find the number of different positions Petr can occupy. | The only line contains three integers *n*, *a* and *b* (0<=≤<=*a*,<=*b*<=<<=*n*<=≤<=100). | Print the single number — the number of the sought positions. | [
"3 1 1\n",
"5 2 3\n"
] | [
"2\n",
"3\n"
] | The possible positions in the first sample are: 2 and 3 (if we number the positions starting with 1).
In the second sample they are 3, 4 and 5. | 500 | [
{
"input": "3 1 1",
"output": "2"
},
{
"input": "5 2 3",
"output": "3"
},
{
"input": "5 4 0",
"output": "1"
},
{
"input": "6 5 5",
"output": "1"
},
{
"input": "9 4 3",
"output": "4"
},
{
"input": "11 4 6",
"output": "7"
},
{
"input": "13 8 ... | 1,653,633,553 | 2,147,483,647 | PyPy 3 | OK | TESTS | 50 | 186 | 0 |
'''
╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬
╬╬ ▓▓ ▓▓ ╬╬
╬╬ ▓▓ ▓▓ ╬╬
╬╬ ▓▓█████▓▓ ╬╬
╬╬ ▓▓ ▓▓ ╬╬
╬╬ ▓▓ ▓▓ ╬╬
╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬
###########################
// •︿• \\
/\\ //\
/\\ //\
/\\//\
###########################
''... | Title: The number of positions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind h... | ```python
'''
╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬
╬╬ ▓▓ ▓▓ ╬╬
╬╬ ▓▓ ▓▓ ╬╬
╬╬ ▓▓█████▓▓ ╬╬
╬╬ ▓▓ ▓▓ ╬╬
╬╬ ▓▓ ▓▓ ╬╬
╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬
###########################
// •︿• \\
/\\ //\
/\\ //\
/\\//\
#####################... | 3 | |
981 | B | Businessmen Problems | PROGRAMMING | 1,000 | [
"sortings"
] | null | null | Two famous competing companies ChemForces and TopChemist decided to show their sets of recently discovered chemical elements on an exhibition. However they know that no element should be present in the sets of both companies.
In order to avoid this representatives of both companies decided to make an agreement on the ... | The first line contains a single integer $n$ ($1 \leq n \leq 10^5$) — the number of elements discovered by ChemForces.
The $i$-th of the next $n$ lines contains two integers $a_i$ and $x_i$ ($1 \leq a_i \leq 10^9$, $1 \leq x_i \leq 10^9$) — the index of the $i$-th element and the income of its usage on the exhibitio... | Print the maximum total income you can obtain by choosing the sets for both companies in such a way that no element is presented in both sets. | [
"3\n1 2\n7 2\n3 10\n4\n1 4\n2 4\n3 4\n4 4\n",
"1\n1000000000 239\n3\n14 15\n92 65\n35 89\n"
] | [
"24\n",
"408\n"
] | In the first example ChemForces can choose the set ($3, 7$), while TopChemist can choose ($1, 2, 4$). This way the total income is $(10 + 2) + (4 + 4 + 4) = 24$.
In the second example ChemForces can choose the only element $10^9$, while TopChemist can choose ($14, 92, 35$). This way the total income is $(239) + (15 + ... | 750 | [
{
"input": "3\n1 2\n7 2\n3 10\n4\n1 4\n2 4\n3 4\n4 4",
"output": "24"
},
{
"input": "1\n1000000000 239\n3\n14 15\n92 65\n35 89",
"output": "408"
},
{
"input": "10\n598654597 488228616\n544064902 21923894\n329635457 980089248\n988262691 654502493\n967529230 543358150\n835120075 128123793\... | 1,530,010,019 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 826 | 23,756,800 | n=int(input())
dict1={}
for i in range(n):
a,x=map(int,input().split())
dict1[a]=[x]
m=int(input())
for i in range(m):
a,x=map(int,input().split())
try:
dict1[a].append(x)
except:
KeyError
dict1[a]=[x]
ans=0
for i in dict1:
ans+=max(dict1[i])
print(ans)
| Title: Businessmen Problems
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two famous competing companies ChemForces and TopChemist decided to show their sets of recently discovered chemical elements on an exhibition. However they know that no element should be present in the sets of both... | ```python
n=int(input())
dict1={}
for i in range(n):
a,x=map(int,input().split())
dict1[a]=[x]
m=int(input())
for i in range(m):
a,x=map(int,input().split())
try:
dict1[a].append(x)
except:
KeyError
dict1[a]=[x]
ans=0
for i in dict1:
ans+=max(dict1[i])
print(ans)
``` | 3 | |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,643,395,080 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | bin_str = input()
for i in bin_str:
if i == '0':
bin_str = bin_str.replace(i, '', 1)
break
if '0' not in bin_str:
bin_str = bin_str.replace('1', '', 1)
print(bin_str)
| Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
bin_str = input()
for i in bin_str:
if i == '0':
bin_str = bin_str.replace(i, '', 1)
break
if '0' not in bin_str:
bin_str = bin_str.replace('1', '', 1)
print(bin_str)
``` | 0 | |
701 | B | Cells Not Under Attack | PROGRAMMING | 1,200 | [
"data structures",
"math"
] | null | null | Vasya has the square chessboard of size *n*<=×<=*n* and *m* rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=*min*(100<=000,<=*n*2)) — the size of the board and the number of rooks.
Each of the next *m* lines contains integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*) — the number of the row and the number of the col... | Print *m* integer, the *i*-th of them should be equal to the number of cells that are not under attack after first *i* rooks are put. | [
"3 3\n1 1\n3 1\n2 2\n",
"5 2\n1 5\n5 1\n",
"100000 1\n300 400\n"
] | [
"4 2 0 \n",
"16 9 \n",
"9999800001 \n"
] | On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack. | 750 | [
{
"input": "3 3\n1 1\n3 1\n2 2",
"output": "4 2 0 "
},
{
"input": "5 2\n1 5\n5 1",
"output": "16 9 "
},
{
"input": "100000 1\n300 400",
"output": "9999800001 "
},
{
"input": "10 4\n2 8\n1 8\n9 8\n6 9",
"output": "81 72 63 48 "
},
{
"input": "30 30\n3 13\n27 23\n18... | 1,650,485,144 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 436 | 10,649,600 | n, m = map(int, input().split())
rows = set()
columns = set()
answers = []
for i in range(m):
r, c = map(int, input().split())
rows.add(r)
columns.add(c)
answers.append((n-len(rows)) * (n-len(columns)))
for i in range(m):
if i == m-1:
print(answers[i])
else:
print(answers[i], end=' ')
... | Title: Cells Not Under Attack
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has the square chessboard of size *n*<=×<=*n* and *m* rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's a... | ```python
n, m = map(int, input().split())
rows = set()
columns = set()
answers = []
for i in range(m):
r, c = map(int, input().split())
rows.add(r)
columns.add(c)
answers.append((n-len(rows)) * (n-len(columns)))
for i in range(m):
if i == m-1:
print(answers[i])
else:
print(answers[i], end=' ')
... | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Hongcow is ruler of the world. As ruler of the world, he wants to make it easier for people to travel by road within their own countries.
The world can be modeled as an undirected graph with *n* nodes and *m* edges. *k* of the nodes are home to the governments of the *k* countries that make up the world.
There is at ... | The first line of input will contain three integers *n*, *m* and *k* (1<=≤<=*n*<=≤<=1<=000, 0<=≤<=*m*<=≤<=100<=000, 1<=≤<=*k*<=≤<=*n*) — the number of vertices and edges in the graph, and the number of vertices that are homes of the government.
The next line of input will contain *k* integers *c*1,<=*c*2,<=...,<=*c**... | Output a single integer, the maximum number of edges Hongcow can add to the graph while keeping it stable. | [
"4 1 2\n1 3\n1 2\n",
"3 3 1\n2\n1 2\n1 3\n2 3\n"
] | [
"2\n",
"0\n"
] | For the first sample test, the graph looks like this:
For the second sample test, the graph looks like this: | 0 | [
{
"input": "4 1 2\n1 3\n1 2",
"output": "2"
},
{
"input": "3 3 1\n2\n1 2\n1 3\n2 3",
"output": "0"
},
{
"input": "10 3 2\n1 10\n1 2\n1 3\n4 5",
"output": "33"
},
{
"input": "1 0 1\n1",
"output": "0"
},
{
"input": "1000 0 1\n72",
"output": "499500"
},
{
... | 1,481,996,981 | 4,481 | Python 3 | OK | TESTS | 61 | 374 | 7,782,400 | def dfs(vertex, summ, has_capital, am):
summ += len(neigh[vertex])
am += 1
if vertex in capitals:
has_capital = True
used[vertex] = True
for nei in neigh[vertex]:
if not used[nei]:
tmp_c, am, summ = dfs(nei, summ, has_capital, am)
has_capital |= tmp_c... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hongcow is ruler of the world. As ruler of the world, he wants to make it easier for people to travel by road within their own countries.
The world can be modeled as an undirected graph with *n* nodes and *m* edges. *k* of the no... | ```python
def dfs(vertex, summ, has_capital, am):
summ += len(neigh[vertex])
am += 1
if vertex in capitals:
has_capital = True
used[vertex] = True
for nei in neigh[vertex]:
if not used[nei]:
tmp_c, am, summ = dfs(nei, summ, has_capital, am)
has_capita... | 3 | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,540,796,233 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | n=int(input())
x=n//4
if x%4==0:
x-=1
if x%2==1:
x=0
print(x) | Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
n=int(input())
x=n//4
if x%4==0:
x-=1
if x%2==1:
x=0
print(x)
``` | 0 | |
471 | A | MUH and Sticks | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an elephant or a bear from those sticks. They can make an animal from sticks in the following way:
-... | The single line contains six space-separated integers *l**i* (1<=≤<=*l**i*<=≤<=9) — the lengths of the six sticks. It is guaranteed that the input is such that you cannot make both animals from the sticks. | If you can make a bear from the given set, print string "Bear" (without the quotes). If you can make an elephant, print string "Elephant" (wıthout the quotes). If you can make neither a bear nor an elephant, print string "Alien" (without the quotes). | [
"4 2 5 4 4 4\n",
"4 4 5 4 4 5\n",
"1 2 3 4 5 6\n"
] | [
"Bear",
"Elephant",
"Alien"
] | If you're out of creative ideas, see instructions below which show how to make a bear and an elephant in the first two samples. The stick of length 2 is in red, the sticks of length 4 are in green, the sticks of length 5 are in blue. | 500 | [
{
"input": "4 2 5 4 4 4",
"output": "Bear"
},
{
"input": "4 4 5 4 4 5",
"output": "Elephant"
},
{
"input": "1 2 3 4 5 6",
"output": "Alien"
},
{
"input": "5 5 5 5 5 5",
"output": "Elephant"
},
{
"input": "1 1 1 2 3 5",
"output": "Alien"
},
{
"input": "... | 1,536,917,631 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 124 | 102,400 | import sys
from collections import Counter
class Sticks:
def __init__(self,sticks):
self.s = sticks
def animal(self):
dic = Counter(self.s)
if len(dic) == 2:
return self.checkAli(dic,"Elephant")
elif len(dic) == 3:
return self.checkAli(dic,"Bear")
... | Title: MUH and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an... | ```python
import sys
from collections import Counter
class Sticks:
def __init__(self,sticks):
self.s = sticks
def animal(self):
dic = Counter(self.s)
if len(dic) == 2:
return self.checkAli(dic,"Elephant")
elif len(dic) == 3:
return self.checkAli(dic,"Bea... | 0 | |
507 | B | Amr and Pins | PROGRAMMING | 1,400 | [
"geometry",
"math"
] | null | null | Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin b... | Input consists of 5 space-separated integers *r*, *x*, *y*, *x*' *y*' (1<=≤<=*r*<=≤<=105, <=-<=105<=≤<=*x*,<=*y*,<=*x*',<=*y*'<=≤<=105), circle radius, coordinates of original center of the circle and coordinates of destination center of the circle respectively. | Output a single integer — minimum number of steps required to move the center of the circle to the destination point. | [
"2 0 0 0 4\n",
"1 1 1 4 4\n",
"4 5 6 5 6\n"
] | [
"1\n",
"3\n",
"0\n"
] | In the first sample test the optimal way is to put a pin at point (0, 2) and rotate the circle by 180 degrees counter-clockwise (or clockwise, no matter).
<img class="tex-graphics" src="https://espresso.codeforces.com/4e40fd4cc24a2050a0488aa131e6244369328039.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "2 0 0 0 4",
"output": "1"
},
{
"input": "1 1 1 4 4",
"output": "3"
},
{
"input": "4 5 6 5 6",
"output": "0"
},
{
"input": "10 20 0 40 0",
"output": "1"
},
{
"input": "9 20 0 40 0",
"output": "2"
},
{
"input": "5 -1 -6 -5 1",
"output": "... | 1,622,635,025 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 155 | 102,400 | from math import *
r,x,y,xd,yd=map(int,input().split())
d=sqrt((x-xd)**2+(y-yd)**2)
print(ceil(d/(2*r))) | Title: Amr and Pins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can ... | ```python
from math import *
r,x,y,xd,yd=map(int,input().split())
d=sqrt((x-xd)**2+(y-yd)**2)
print(ceil(d/(2*r)))
``` | 3 | |
17 | A | Noldbach problem | PROGRAMMING | 1,000 | [
"brute force",
"math",
"number theory"
] | A. Noldbach problem | 2 | 64 | Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nick's attention and he decided to invent a problem of his own and call it Noldbach problem. Since Nick is interested only in prime numbers, Nold... | The first line of the input contains two integers *n* (2<=≤<=*n*<=≤<=1000) and *k* (0<=≤<=*k*<=≤<=1000). | Output YES if at least *k* prime numbers from 2 to *n* inclusively can be expressed as it was described above. Otherwise output NO. | [
"27 2\n",
"45 7\n"
] | [
"YES",
"NO"
] | In the first sample the answer is YES since at least two numbers can be expressed as it was described (for example, 13 and 19). In the second sample the answer is NO since it is impossible to express 7 prime numbers from 2 to 45 in the desired form. | 0 | [
{
"input": "27 2",
"output": "YES"
},
{
"input": "45 7",
"output": "NO"
},
{
"input": "2 0",
"output": "YES"
},
{
"input": "15 1",
"output": "YES"
},
{
"input": "17 1",
"output": "YES"
},
{
"input": "34 5",
"output": "NO"
},
{
"input": "37 ... | 1,595,607,615 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 186 | 6,656,000 | # -*- coding: utf-8 -*-
def isPrime(n):
for i in range(2,int(n**0.5)+1):
if n%i==0:
return False
return True
n,k = map(int,input().split())
cont = 0
for i in range(2,n+1):
if isPrime(i) == True: cont += 1
if cont == k: print('YES'); break
if cont < k: print('NO')... | Title: Noldbach problem
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nick's attention and he decided to invent a prob... | ```python
# -*- coding: utf-8 -*-
def isPrime(n):
for i in range(2,int(n**0.5)+1):
if n%i==0:
return False
return True
n,k = map(int,input().split())
cont = 0
for i in range(2,n+1):
if isPrime(i) == True: cont += 1
if cont == k: print('YES'); break
if cont < k: p... | 0 |
18 | D | Seller Bob | PROGRAMMING | 2,000 | [
"brute force",
"dp",
"greedy"
] | D. Seller Bob | 2 | 128 | Last year Bob earned by selling memory sticks. During each of *n* days of his work one of the two following events took place:
- A customer came to Bob and asked to sell him a 2*x* MB memory stick. If Bob had such a stick, he sold it and got 2*x* berllars. - Bob won some programming competition and got a 2*x* MB me... | The first input line contains number *n* (1<=≤<=*n*<=≤<=5000) — amount of Bob's working days. The following *n* lines contain the description of the days. Line sell x stands for a day when a customer came to Bob to buy a 2*x* MB memory stick (0<=≤<=*x*<=≤<=2000). It's guaranteed that for each *x* there is not more than... | Output the maximum possible earnings for Bob in berllars, that he would have had if he had known all the events beforehand. Don't forget, please, that Bob can't keep more than one memory stick at a time. | [
"7\nwin 10\nwin 5\nwin 3\nsell 5\nsell 3\nwin 10\nsell 10\n",
"3\nwin 5\nsell 6\nsell 4\n"
] | [
"1056\n",
"0\n"
] | none | 0 | [
{
"input": "7\nwin 10\nwin 5\nwin 3\nsell 5\nsell 3\nwin 10\nsell 10",
"output": "1056"
},
{
"input": "3\nwin 5\nsell 6\nsell 4",
"output": "0"
},
{
"input": "60\nwin 30\nsell 30\nwin 29\nsell 29\nwin 28\nsell 28\nwin 27\nsell 27\nwin 26\nsell 26\nwin 25\nsell 25\nwin 24\nsell 24\nwin 23... | 1,500,186,494 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 122 | 4,608,000 | R= lambda:map(int,input().split())
n,=R()
dic,l={},[]
for i in range(n):
a,b=input().split()
b=int(b)
if a=='win':
if b in dic.keys(): dic[b].append(i)
else: dic[b]=[i]
else:
l.append([b,i])
l.sort(reverse=True)
now,ans,t=n,0,-1
for x in l:
if (x[0] in dic.key... | Title: Seller Bob
Time Limit: 2 seconds
Memory Limit: 128 megabytes
Problem Description:
Last year Bob earned by selling memory sticks. During each of *n* days of his work one of the two following events took place:
- A customer came to Bob and asked to sell him a 2*x* MB memory stick. If Bob had such a stick, he... | ```python
R= lambda:map(int,input().split())
n,=R()
dic,l={},[]
for i in range(n):
a,b=input().split()
b=int(b)
if a=='win':
if b in dic.keys(): dic[b].append(i)
else: dic[b]=[i]
else:
l.append([b,i])
l.sort(reverse=True)
now,ans,t=n,0,-1
for x in l:
if (x[0] ... | 0 |
877 | A | Alex and broken contest | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.
But there are too many problems, to do it manually. Alex asks you to write a program, which will determine if a problem is from this contest ... | The only line contains string from lowercase and uppercase letters and "_" symbols of length, not more than 100 — the name of the problem. | Print "YES", if problem is from this contest, and "NO" otherwise. | [
"Alex_and_broken_contest\n",
"NikitaAndString\n",
"Danil_and_Olya\n"
] | [
"NO",
"YES",
"NO"
] | none | 500 | [
{
"input": "Alex_and_broken_contest",
"output": "NO"
},
{
"input": "NikitaAndString",
"output": "YES"
},
{
"input": "Danil_and_Olya",
"output": "NO"
},
{
"input": "Slava____and_the_game",
"output": "YES"
},
{
"input": "Olya_and_energy_drinks",
"output": "YES"
... | 1,520,051,170 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 62 | 5,632,000 | s = input()
flag = 0
for i in range(len(s) - 6):
if s[i:i + 5] == "Danil" or s[i:i + 4] == "Olya" or s[i:i + 5] == "Slava" or s[i:i + 6] == "Nikita":
flag += 1
if s[len(s) - 6:len(s) - 1] == "Danil" or s[len(s) - 5:len(s)] == "Danil":
flag += 1
if s[len(s) - 6:len(s) - 1] == "Slava" or s[len(s)... | Title: Alex and broken contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.
But there are too many problems,... | ```python
s = input()
flag = 0
for i in range(len(s) - 6):
if s[i:i + 5] == "Danil" or s[i:i + 4] == "Olya" or s[i:i + 5] == "Slava" or s[i:i + 6] == "Nikita":
flag += 1
if s[len(s) - 6:len(s) - 1] == "Danil" or s[len(s) - 5:len(s)] == "Danil":
flag += 1
if s[len(s) - 6:len(s) - 1] == "Slava" o... | 0 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,696,159,154 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | d=input()
c=list(d)
count=0
for i in range (len(c)):
count+=1
x=count-2
if x<10:
print (d)
else:
print(c[0]+str(x)+c[-1])
| Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
d=input()
c=list(d)
count=0
for i in range (len(c)):
count+=1
x=count-2
if x<10:
print (d)
else:
print(c[0]+str(x)+c[-1])
``` | 0 |
1,005 | B | Delete from the Left | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't choose a string if it is empty.
For example:
- by applying a move to the string "where", the result is ... | The first line of the input contains $s$. In the second line of the input contains $t$. Both strings consist only of lowercase Latin letters. The number of letters in each string is between 1 and $2\cdot10^5$, inclusive. | Output the fewest number of moves required. It is possible that, in the end, both strings will be equal to the empty string, and so, are equal to each other. In this case, the answer is obviously the sum of the lengths of the given strings. | [
"test\nwest\n",
"codeforces\nyes\n",
"test\nyes\n",
"b\nab\n"
] | [
"2\n",
"9\n",
"7\n",
"1\n"
] | In the first example, you should apply the move once to the first string and apply the move once to the second string. As a result, both strings will be equal to "est".
In the second example, the move should be applied to the string "codeforces" $8$ times. As a result, the string becomes "codeforces" $\to$ "es". The m... | 0 | [
{
"input": "test\nwest",
"output": "2"
},
{
"input": "codeforces\nyes",
"output": "9"
},
{
"input": "test\nyes",
"output": "7"
},
{
"input": "b\nab",
"output": "1"
},
{
"input": "z\nz",
"output": "0"
},
{
"input": "abacabadabacaba\nabacabadacaba",
... | 1,640,342,662 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | s = input()
t = input()
x=len(s)-1
y=len(t)-1
count=0
while x>0 and y>0:
if s[x]!=t[y]:
break
x=x-1
y=y-1
print(x+y+2)
| Title: Delete from the Left
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't ... | ```python
s = input()
t = input()
x=len(s)-1
y=len(t)-1
count=0
while x>0 and y>0:
if s[x]!=t[y]:
break
x=x-1
y=y-1
print(x+y+2)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Let's introduce a number system which is based on a roman digits. There are digits I, V, X, L which correspond to the numbers $1$, $5$, $10$ and $50$ respectively. The use of other roman digits is not allowed.
Numbers in this system are written as a sequence of one or more digits. We define the value of the sequence s... | The only line of the input file contains a single integer $n$ ($1 \le n \le 10^9$) — the number of roman digits to use. | Output a single integer — the number of distinct integers which can be represented using $n$ roman digits exactly. | [
"1\n",
"2\n",
"10\n"
] | [
"4\n",
"10\n",
"244\n"
] | In the first sample there are exactly $4$ integers which can be represented — I, V, X and L.
In the second sample it is possible to represent integers $2$ (II), $6$ (VI), $10$ (VV), $11$ (XI), $15$ (XV), $20$ (XX), $51$ (IL), $55$ (VL), $60$ (XL) and $100$ (LL). | 0 | [
{
"input": "1",
"output": "4"
},
{
"input": "2",
"output": "10"
},
{
"input": "10",
"output": "244"
},
{
"input": "1000",
"output": "48753"
},
{
"input": "2000",
"output": "97753"
},
{
"input": "5000",
"output": "244753"
},
{
"input": "1000... | 1,602,544,827 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 109 | 0 | non_representable = {
1: 46,
2: 89,
3: 128,
4: 162,
5: 190,
6: 212,
7: 228,
8: 238,
9: 244,
10: 247,
}
n = int(input())
print(49 * n + 1 - non_representable.get(n, 248))
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's introduce a number system which is based on a roman digits. There are digits I, V, X, L which correspond to the numbers $1$, $5$, $10$ and $50$ respectively. The use of other roman digits is not allowed.
Numbers in this sys... | ```python
non_representable = {
1: 46,
2: 89,
3: 128,
4: 162,
5: 190,
6: 212,
7: 228,
8: 238,
9: 244,
10: 247,
}
n = int(input())
print(49 * n + 1 - non_representable.get(n, 248))
``` | 3 | |
265 | A | Colorful Stones (Simplified Edition) | PROGRAMMING | 800 | [
"implementation"
] | null | null | There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th stone. If the character is "R", "G", or "B", the color of the corresponding stone is red, green, or blue, respectively.
Ini... | The input contains two lines. The first line contains the string *s* (1<=≤<=|*s*|<=≤<=50). The second line contains the string *t* (1<=≤<=|*t*|<=≤<=50). The characters of each string will be one of "R", "G", or "B". It is guaranteed that Liss don't move out of the sequence. | Print the final 1-based position of Liss in a single line. | [
"RGB\nRRR\n",
"RRRBGBRBBB\nBBBRR\n",
"BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB\n"
] | [
"2\n",
"3\n",
"15\n"
] | none | 500 | [
{
"input": "RGB\nRRR",
"output": "2"
},
{
"input": "RRRBGBRBBB\nBBBRR",
"output": "3"
},
{
"input": "BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB",
"output": "15"
},
{
"input": "G\nRRBBRBRRBR",
"output": "1"
},
... | 1,604,213,151 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 216 | 0 | s1=input()
s2=input()
i=j=0
while i<len(s1) and j<len(s2):
if s1[i]==s2[j]:
i+=1
j+=1
else:
j+=1
print(i+1) | Title: Colorful Stones (Simplified Edition)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th st... | ```python
s1=input()
s2=input()
i=j=0
while i<len(s1) and j<len(s2):
if s1[i]==s2[j]:
i+=1
j+=1
else:
j+=1
print(i+1)
``` | 3 | |
698 | A | Vacations | PROGRAMMING | 1,400 | [
"dp"
] | null | null | Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options:
1. on this day the gym is close... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations.
The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where:
- *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the co... | Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses:
- to do sport on any two consecutive days, - to write the contest on any two consecutive days. | [
"4\n1 3 2 0\n",
"7\n1 3 3 2 1 2 3\n",
"2\n2 2\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days.
In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day.
In the third test Vasya ca... | 500 | [
{
"input": "4\n1 3 2 0",
"output": "2"
},
{
"input": "7\n1 3 3 2 1 2 3",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "10\n0 0 1 1 0 0 0 0 1 0",
"output": "8"
},
{
"input": "100\n3 2 3 3 3 2 3 1 ... | 1,607,436,993 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 140 | 0 | n=int(input())
l=list(map(int,input().split()))
dp=[0 for _ in range(n+1)]
for i in range(1,n+1):
if l[i-1]==0:
dp[i]=0
elif l[i-1]==1:
if dp[i-1]!=1:
dp[i]=1
else:
dp[i]=0
elif l[i-1]==2:
if dp[i-1]!=2:
dp[i]=2
else:
... | Title: Vacations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Int... | ```python
n=int(input())
l=list(map(int,input().split()))
dp=[0 for _ in range(n+1)]
for i in range(1,n+1):
if l[i-1]==0:
dp[i]=0
elif l[i-1]==1:
if dp[i-1]!=1:
dp[i]=1
else:
dp[i]=0
elif l[i-1]==2:
if dp[i-1]!=2:
dp[i]=2
... | 0 | |
545 | C | Woodcutters | PROGRAMMING | 1,500 | [
"dp",
"greedy"
] | null | null | Little Susie listens to fairy tales before bed every day. Today's fairy tale was about wood cutters and the little girl immediately started imagining the choppers cutting wood. She imagined the situation that is described below.
There are *n* trees located along the road at points with coordinates *x*1,<=*x*2,<=...,<=... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of trees.
Next *n* lines contain pairs of integers *x**i*,<=*h**i* (1<=≤<=*x**i*,<=*h**i*<=≤<=109) — the coordinate and the height of the *і*-th tree.
The pairs are given in the order of ascending *x**i*. No two trees are located at the point with t... | Print a single number — the maximum number of trees that you can cut down by the given rules. | [
"5\n1 2\n2 1\n5 10\n10 9\n19 1\n",
"5\n1 2\n2 1\n5 10\n10 9\n20 1\n"
] | [
"3\n",
"4\n"
] | In the first sample you can fell the trees like that:
- fell the 1-st tree to the left — now it occupies segment [ - 1;1] - fell the 2-nd tree to the right — now it occupies segment [2;3] - leave the 3-rd tree — it occupies point 5 - leave the 4-th tree — it occupies point 10 - fell the 5-th tree to the right — ... | 1,750 | [
{
"input": "5\n1 2\n2 1\n5 10\n10 9\n19 1",
"output": "3"
},
{
"input": "5\n1 2\n2 1\n5 10\n10 9\n20 1",
"output": "4"
},
{
"input": "4\n10 4\n15 1\n19 3\n20 1",
"output": "4"
},
{
"input": "35\n1 7\n3 11\n6 12\n7 6\n8 5\n9 11\n15 3\n16 10\n22 2\n23 3\n25 7\n27 3\n34 5\n35 10... | 1,667,004,686 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 327 | 8,806,400 | n = int(input())
s = [[int(x) for x in input().split()] for i in range(n)]
count = 2
if n == 1:
print(1)
else:
for i in range(1, n-1):
if s[i][0] - s[i-1][0] > s[i][1]:
count += 1
elif s[i+1][0] - s[i][0] > s[i][1]:
count += 1
print(count)
| Title: Woodcutters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Susie listens to fairy tales before bed every day. Today's fairy tale was about wood cutters and the little girl immediately started imagining the choppers cutting wood. She imagined the situation that is described b... | ```python
n = int(input())
s = [[int(x) for x in input().split()] for i in range(n)]
count = 2
if n == 1:
print(1)
else:
for i in range(1, n-1):
if s[i][0] - s[i-1][0] > s[i][1]:
count += 1
elif s[i+1][0] - s[i][0] > s[i][1]:
count += 1
print(count)
``` | 0 | |
679 | A | Bear and Prime 100 | PROGRAMMING | 1,400 | [
"constructive algorithms",
"interactive",
"math"
] | null | null | This is an interactive problem. In the output section below you will see the information about flushing the output.
Bear Limak thinks of some hidden number — an integer from interval [2,<=100]. Your task is to say if the hidden number is prime or composite.
Integer *x*<=><=1 is called prime if it has exactly two d... | After each query you should read one string from the input. It will be "yes" if the printed integer is a divisor of the hidden number, and "no" otherwise. | Up to 20 times you can ask a query — print an integer from interval [2,<=100] in one line. You have to both print the end-of-line character and flush the output. After flushing you should read a response from the input.
In any moment you can print the answer "prime" or "composite" (without the quotes). After that, flu... | [
"yes\nno\nyes\n",
"no\nyes\nno\nno\nno\n"
] | [
"2\n80\n5\ncomposite\n",
"58\n59\n78\n78\n2\nprime\n"
] | The hidden number in the first query is 30. In a table below you can see a better form of the provided example of the communication process.
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ea790051c34ea7d2761cd9b096412ca7c647a173.png" style="max-width: 100.0%;max-height: 100.0%;"/>
The hi... | 750 | [
{
"input": "30",
"output": "composite 4"
},
{
"input": "59",
"output": "prime 15"
},
{
"input": "2",
"output": "prime 16"
},
{
"input": "7",
"output": "prime 16"
},
{
"input": "9",
"output": "composite 3"
},
{
"input": "13",
"output": "prime 15"
... | 1,658,833,330 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 31 | 0 | p = [2, 2, 3, 3, 5, 5, 7, 7, 11, 11, 13, 13, 17, 17, 19, 19, 23, 23, 29, 29, 31, 31, 37, 37, 41, 41, 43, 43, 47, 47, 53, 53, 59, 59, 61, 61, 67, 67, 71, 71, 73, 73, 79, 79, 83, 83, 89, 89, 97, 97]
nofyes = 0
nofmoves = 20
i = 0
while nofmoves:
if i == 0:
print(p[0])
else:
print(p[i+1] if nofyes > 0 else p... | Title: Bear and Prime 100
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This is an interactive problem. In the output section below you will see the information about flushing the output.
Bear Limak thinks of some hidden number — an integer from interval [2,<=100]. Your task is to say i... | ```python
p = [2, 2, 3, 3, 5, 5, 7, 7, 11, 11, 13, 13, 17, 17, 19, 19, 23, 23, 29, 29, 31, 31, 37, 37, 41, 41, 43, 43, 47, 47, 53, 53, 59, 59, 61, 61, 67, 67, 71, 71, 73, 73, 79, 79, 83, 83, 89, 89, 97, 97]
nofyes = 0
nofmoves = 20
i = 0
while nofmoves:
if i == 0:
print(p[0])
else:
print(p[i+1] if nofyes ... | 0 | |
364 | D | Ghd | PROGRAMMING | 2,900 | [
"brute force",
"math",
"probabilities"
] | null | null | John Doe offered his sister Jane Doe find the gcd of some set of numbers *a*.
Gcd is a positive integer *g*, such that all number from the set are evenly divisible by *g* and there isn't such *g*' (*g*'<=><=*g*), that all numbers of the set are evenly divisible by *g*'.
Unfortunately Jane couldn't cope with the ta... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106) showing how many numbers are in set *a*. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1012). Please note, that given set can contain equal numbers.
Please, do not write the %lld specifier to read or write 64-bi... | Print a single integer *g* — the Ghd of set *a*. | [
"6\n6 2 3 4 5 6\n",
"5\n5 5 6 10 15\n"
] | [
"3\n",
"5\n"
] | none | 2,000 | [
{
"input": "6\n6 2 3 4 5 6",
"output": "3"
},
{
"input": "5\n5 5 6 10 15",
"output": "5"
},
{
"input": "100\n32 40 7 3 7560 21 7560 7560 10 12 3 7560 7560 7560 7560 5 7560 7560 6 7560 7560 7560 35 7560 18 7560 7560 7560 7560 7560 48 2 7 25 7560 2 2 49 7560 7560 15 16 7560 7560 2 7560 27 ... | 1,581,821,275 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 2,776 | 124,108,800 | from random import randrange
from sys import stdin
def read_integers():
return list(map(int, stdin.readline().strip().split()))
def decompose(num, visited):
if num in visited:
return []
factors = []
i = 2
while i * i <= num:
quo, rem = divmod(num, i)
if i... | Title: Ghd
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
John Doe offered his sister Jane Doe find the gcd of some set of numbers *a*.
Gcd is a positive integer *g*, such that all number from the set are evenly divisible by *g* and there isn't such *g*' (*g*'<=><=*g*), that all numbe... | ```python
from random import randrange
from sys import stdin
def read_integers():
return list(map(int, stdin.readline().strip().split()))
def decompose(num, visited):
if num in visited:
return []
factors = []
i = 2
while i * i <= num:
quo, rem = divmod(num, i)
... | 0 | |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are s... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,675,019,257 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 4,915,200 | n,m=list(map(int,input().split()))
a = list(map(int,input().split()))
for i in range(0,m):
s=[]
ctr=0
l = int(input())
for j in range(l,n+1):
if (a[j-1] not in s):
ctr+=1
s.append(a[j-1])
print(ctr) | Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...... | ```python
n,m=list(map(int,input().split()))
a = list(map(int,input().split()))
for i in range(0,m):
s=[]
ctr=0
l = int(input())
for j in range(l,n+1):
if (a[j-1] not in s):
ctr+=1
s.append(a[j-1])
print(ctr)
``` | 0 | |
478 | C | Table Decorations | PROGRAMMING | 1,800 | [
"greedy"
] | null | null | You have *r* red, *g* green and *b* blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number *t* of tables can be decorated if we know number of balloons of each color?
Your task is to write a pro... | The single line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=2·109) — the number of red, green and blue baloons respectively. The numbers are separated by exactly one space. | Print a single integer *t* — the maximum number of tables that can be decorated in the required manner. | [
"5 4 3\n",
"1 1 1\n",
"2 3 3\n"
] | [
"4\n",
"1\n",
"2\n"
] | In the first sample you can decorate the tables with the following balloon sets: "rgg", "gbb", "brr", "rrg", where "r", "g" and "b" represent the red, green and blue balls, respectively. | 1,500 | [
{
"input": "5 4 3",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 3 3",
"output": "2"
},
{
"input": "0 1 0",
"output": "0"
},
{
"input": "0 3 3",
"output": "2"
},
{
"input": "4 0 4",
"output": "2"
},
{
"input": "100000... | 1,699,811,630 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 10 | 62 | 0 | a = list(map(int, input().split()))
a.sort()
cnt = a[0]
a[1] -= a[0]
a[2] -= a[0]
while a[1] >= 3 and a[2] >= 3:
a[1] -= 3
a[2] -= 3
cnt += 2
while a[1] >= 1 and a[2] >= 2:
a[1] -= 1
a[2] -= 2
cnt += 1
if a[1] >= 1 and a[2] >= 2:
print(cnt + (a[1] + a[2]) // 3)
else:
prin... | Title: Table Decorations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *r* red, *g* green and *b* blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number *... | ```python
a = list(map(int, input().split()))
a.sort()
cnt = a[0]
a[1] -= a[0]
a[2] -= a[0]
while a[1] >= 3 and a[2] >= 3:
a[1] -= 3
a[2] -= 3
cnt += 2
while a[1] >= 1 and a[2] >= 2:
a[1] -= 1
a[2] -= 2
cnt += 1
if a[1] >= 1 and a[2] >= 2:
print(cnt + (a[1] + a[2]) // 3)
else:... | 0 | |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,620,141,587 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 77 | 307,200 | from collections import defaultdict
def failed():
print('NO')
exit()
def passed():
print('YES')
exit()
ballons, friends = map(int, input().split())
types = defaultdict(int)
for x in list(input()):
types[x] += 1
# print(len(types))
if(len(types) == 0 or ballons<(2*friends)):... | Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same colo... | ```python
from collections import defaultdict
def failed():
print('NO')
exit()
def passed():
print('YES')
exit()
ballons, friends = map(int, input().split())
types = defaultdict(int)
for x in list(input()):
types[x] += 1
# print(len(types))
if(len(types) == 0 or ballons<(2*... | 0 | |
849 | A | Odds and Ends | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence *a*1,<=*a*2,<=...,<=*a**n* of length *n*. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numb... | The first line of input contains a non-negative integer *n* (1<=≤<=*n*<=≤<=100) — the length of the sequence.
The second line contains *n* space-separated non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100) — the elements of the sequence. | Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower). | [
"3\n1 3 5\n",
"5\n1 0 1 5 1\n",
"3\n4 3 1\n",
"4\n3 9 9 3\n"
] | [
"Yes\n",
"Yes\n",
"No\n",
"No\n"
] | In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In ... | 500 | [
{
"input": "3\n1 3 5",
"output": "Yes"
},
{
"input": "5\n1 0 1 5 1",
"output": "Yes"
},
{
"input": "3\n4 3 1",
"output": "No"
},
{
"input": "4\n3 9 9 3",
"output": "No"
},
{
"input": "1\n1",
"output": "Yes"
},
{
"input": "5\n100 99 100 99 99",
"out... | 1,622,661,869 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 124 | 0 | from sys import stdin
n = int(stdin.readline())
a = list(map(int, stdin.readline().split()))
k = []
for i in a:
if i == 0 or i % 2 != 0:
k.append(i)
m = len(k)
z = k.count(0)
if m%2 != 0 or z >= 1:
print('YES')
else:
print('NO')
| Title: Odds and Ends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence *a*1,<=*a*2,<=...,<=*a**n* of length *n*. Decide whether it is possible to divide it into an odd num... | ```python
from sys import stdin
n = int(stdin.readline())
a = list(map(int, stdin.readline().split()))
k = []
for i in a:
if i == 0 or i % 2 != 0:
k.append(i)
m = len(k)
z = k.count(0)
if m%2 != 0 or z >= 1:
print('YES')
else:
print('NO')
``` | 0 | |
667 | A | Pouring Rain | PROGRAMMING | 1,100 | [
"geometry",
"math"
] | null | null | A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, contemplate all around you, enjoy freshness, think about big deeds you have to do.
Today everything ... | The only line of the input contains four integer numbers *d*,<=*h*,<=*v*,<=*e* (1<=≤<=*d*,<=*h*,<=*v*,<=*e*<=≤<=104), where:
- *d* — the diameter of your cylindrical cup, - *h* — the initial level of water in the cup, - *v* — the speed of drinking process from the cup in milliliters per second, - *e* — the growth ... | If it is impossible to make the cup empty, print "NO" (without quotes).
Otherwise print "YES" (without quotes) in the first line. In the second line print a real number — time in seconds needed the cup will be empty. The answer will be considered correct if its relative or absolute error doesn't exceed 10<=-<=4. It is... | [
"1 2 3 100\n",
"1 1 1 1\n"
] | [
"NO\n",
"YES\n3.659792366325\n"
] | In the first example the water fills the cup faster than you can drink from it.
In the second example area of the cup's bottom equals to <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/419dc74dcd7bc392019c9fe748fe1fdb08ab521a.png" style="max-width: 100.0%;max-height: 100.0%;"/>, thus we ca... | 500 | [
{
"input": "1 2 3 100",
"output": "NO"
},
{
"input": "1 1 1 1",
"output": "YES\n3.659792366325"
},
{
"input": "48 7946 7992 72",
"output": "NO"
},
{
"input": "72 6791 8546 46",
"output": "NO"
},
{
"input": "100 5635 9099 23",
"output": "NO"
},
{
"input... | 1,626,020,272 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 124 | 22,323,200 | a,b = map(int,input().split())
x = [int(i) for i in input().split()]
count = 0
for i in x:
if i <= b:
count+=1
else:
count+=2
print(count) | Title: Pouring Rain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, cont... | ```python
a,b = map(int,input().split())
x = [int(i) for i in input().split()]
count = 0
for i in x:
if i <= b:
count+=1
else:
count+=2
print(count)
``` | -1 | |
66 | B | Petya and Countryside | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | B. Petya and Countryside | 2 | 256 | Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *n* equal square sections. The garden is very unusual as each of the square sections possesses its own f... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* positive integers which are the height of the sections. All the numbers are no less than 1 and not more than 1000. | Print a single number, the maximal number of watered sections if we create artificial rain above exactly one section. | [
"1\n2\n",
"5\n1 2 1 2 1\n",
"8\n1 2 1 1 1 3 3 4\n"
] | [
"1\n",
"3\n",
"6\n"
] | none | 1,000 | [
{
"input": "1\n2",
"output": "1"
},
{
"input": "5\n1 2 1 2 1",
"output": "3"
},
{
"input": "8\n1 2 1 1 1 3 3 4",
"output": "6"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "10"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "10"
},
{
"input... | 1,609,676,460 | 2,147,483,647 | PyPy 3 | OK | TESTS | 80 | 342 | 1,536,000 | def main():
n = int(input())
a = [int(i) for i in input().split()]
cnt = 0
for i in range(n):
temp = 1
k = i
j = i - 1
while j >= 0 and a[j] <= a[k]:
temp += 1
j -= 1
k -= 1
if i == n - 1:
cnt = max(cnt, temp)
break
k = i
j = i + 1
while j <= n - 1 and a[j] ... | Title: Petya and Countryside
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *... | ```python
def main():
n = int(input())
a = [int(i) for i in input().split()]
cnt = 0
for i in range(n):
temp = 1
k = i
j = i - 1
while j >= 0 and a[j] <= a[k]:
temp += 1
j -= 1
k -= 1
if i == n - 1:
cnt = max(cnt, temp)
break
k = i
j = i + 1
while j <= n - 1... | 3.911639 |
513 | A | Game | PROGRAMMING | 800 | [
"constructive algorithms",
"math"
] | null | null | Two players play a simple game. Each player is provided with a box with balls. First player's box contains exactly *n*1 balls and second player's box contains exactly *n*2 balls. In one move first player can take from 1 to *k*1 balls from his box and throw them away. Similarly, the second player can take from 1 to *k*2... | The first line contains four integers *n*1,<=*n*2,<=*k*1,<=*k*2. All numbers in the input are from 1 to 50.
This problem doesn't have subproblems. You will get 3 points for the correct submission. | Output "First" if the first player wins and "Second" otherwise. | [
"2 2 1 2\n",
"2 1 1 1\n"
] | [
"Second\n",
"First\n"
] | Consider the first sample test. Each player has a box with 2 balls. The first player draws a single ball from his box in one move and the second player can either take 1 or 2 balls from his box in one move. No matter how the first player acts, the second player can always win if he plays wisely. | 3 | [
{
"input": "2 2 1 2",
"output": "Second"
},
{
"input": "2 1 1 1",
"output": "First"
},
{
"input": "5 7 4 1",
"output": "Second"
},
{
"input": "5 7 1 4",
"output": "Second"
},
{
"input": "5 7 10 10",
"output": "Second"
},
{
"input": "5 7 1 10",
"out... | 1,556,087,099 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | n1,n2,k1,k2=map(int,input().split())
if n1>n2:
print('FIRST')
else:
print('SECOND')
| Title: Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two players play a simple game. Each player is provided with a box with balls. First player's box contains exactly *n*1 balls and second player's box contains exactly *n*2 balls. In one move first player can take from 1 to *k*1 ba... | ```python
n1,n2,k1,k2=map(int,input().split())
if n1>n2:
print('FIRST')
else:
print('SECOND')
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Dima is a beginner programmer. During his working process, he regularly has to repeat the following operation again and again: to remove every second element from the array. One day he has been bored with easy solutions of this problem, and he has come up with the following extravagant algorithm.
Let's consider that i... | The first line contains two integers *n* and *q* (1<=≤<=*n*<=≤<=1018, 1<=≤<=*q*<=≤<=200<=000), the number of elements in the array and the number of queries for which it is needed to find the answer.
Next *q* lines contain integers *x**i* (1<=≤<=*x**i*<=≤<=*n*), the indices of cells for which it is necessary to output... | For each of *q* queries output one integer number, the value that will appear in the corresponding array cell after Dima's algorithm finishes. | [
"4 3\n2\n3\n4\n",
"13 4\n10\n5\n4\n8\n"
] | [
"3\n2\n4\n",
"13\n3\n8\n9\n"
] | The first example is shown in the picture.
In the second example the final array is [1, 12, 2, 8, 3, 11, 4, 9, 5, 13, 6, 10, 7]. | 0 | [
{
"input": "4 3\n2\n3\n4",
"output": "3\n2\n4"
},
{
"input": "13 4\n10\n5\n4\n8",
"output": "13\n3\n8\n9"
},
{
"input": "2 2\n1\n2",
"output": "1\n2"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "3 3\n3\n2\n1",
"output": "2\n3\n1"
},
{
"input": ... | 1,691,634,863 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 9,523,200 | n, q = map(int, input().split())
for _ in range(q):
p = int(input())
x = 2 * n - p
while (1):
if (x & 1): break
x >>= 1
p += x
print(p + 1 >> 1) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima is a beginner programmer. During his working process, he regularly has to repeat the following operation again and again: to remove every second element from the array. One day he has been bored with easy solutions of this pr... | ```python
n, q = map(int, input().split())
for _ in range(q):
p = int(input())
x = 2 * n - p
while (1):
if (x & 1): break
x >>= 1
p += x
print(p + 1 >> 1)
``` | 0 | |
628 | D | Magic Numbers | PROGRAMMING | 2,200 | [
"dp"
] | null | null | Consider the decimal presentation of an integer. Let's call a number d-magic if digit *d* appears in decimal presentation of the number on even positions and nowhere else.
For example, the numbers 1727374, 17, 1 are 7-magic but 77, 7, 123, 34, 71 are not 7-magic. On the other hand the number 7 is 0-magic, 123 is 2-mag... | The first line contains two integers *m*,<=*d* (1<=≤<=*m*<=≤<=2000, 0<=≤<=*d*<=≤<=9) — the parameters from the problem statement.
The second line contains positive integer *a* in decimal presentation (without leading zeroes).
The third line contains positive integer *b* in decimal presentation (without leading zeroes... | Print the only integer *a* — the remainder after dividing by 109<=+<=7 of the number of d-magic numbers in segment [*a*,<=*b*] that are multiple of *m*. | [
"2 6\n10\n99\n",
"2 0\n1\n9\n",
"19 7\n1000\n9999\n"
] | [
"8\n",
"4\n",
"6\n"
] | The numbers from the answer of the first example are 16, 26, 36, 46, 56, 76, 86 and 96.
The numbers from the answer of the second example are 2, 4, 6 and 8.
The numbers from the answer of the third example are 1767, 2717, 5757, 6707, 8797 and 9747. | 0 | [
{
"input": "2 6\n10\n99",
"output": "8"
},
{
"input": "2 0\n1\n9",
"output": "4"
},
{
"input": "19 7\n1000\n9999",
"output": "6"
},
{
"input": "9 4\n33\n52",
"output": "0"
},
{
"input": "10 8\n18\n59",
"output": "0"
},
{
"input": "43 3\n587\n850",
... | 1,598,803,651 | 2,147,483,647 | Python 3 | MEMORY_LIMIT_EXCEEDED | TESTS | 0 | 2,043 | 268,390,400 | def solve(pos,r,f):
if pos==nd:
if r==0:
return 1
return 0
if dp[pos][r][f]!=-1:
return dp[pos][r][f]
if f==0:
j=n[pos]
else:
j=9
res=0
for i in range(j+1):
if i==d and pos%2==0:
res+=0
elif... | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider the decimal presentation of an integer. Let's call a number d-magic if digit *d* appears in decimal presentation of the number on even positions and nowhere else.
For example, the numbers 1727374, 17, 1 are 7-ma... | ```python
def solve(pos,r,f):
if pos==nd:
if r==0:
return 1
return 0
if dp[pos][r][f]!=-1:
return dp[pos][r][f]
if f==0:
j=n[pos]
else:
j=9
res=0
for i in range(j+1):
if i==d and pos%2==0:
res+=0
... | 0 | |
330 | B | Road Construction | PROGRAMMING | 1,300 | [
"constructive algorithms",
"graphs"
] | null | null | A country has *n* cities. Initially, there is no road in the country. One day, the king decides to construct some roads connecting pairs of cities. Roads can be traversed either way. He wants those roads to be constructed in such a way that it is possible to go from each city to any other city by traversing at most two... | The first line consists of two integers *n* and *m* .
Then *m* lines follow, each consisting of two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*), which means that it is not possible to construct a road connecting cities *a**i* and *b**i*. Consider the cities are numbered from 1 to *n*.... | You should print an integer *s*: the minimum number of roads that should be constructed, in the first line. Then *s* lines should follow, each consisting of two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*), which means that a road should be constructed between cities *a**i* and *b**i*.... | [
"4 1\n1 3\n"
] | [
"3\n1 2\n4 2\n2 3\n"
] | This is one possible solution of the example:
These are examples of wrong solutions: | 1,000 | [
{
"input": "4 1\n1 3",
"output": "3\n1 2\n4 2\n2 3"
},
{
"input": "1000 0",
"output": "999\n1 2\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n1 9\n1 10\n1 11\n1 12\n1 13\n1 14\n1 15\n1 16\n1 17\n1 18\n1 19\n1 20\n1 21\n1 22\n1 23\n1 24\n1 25\n1 26\n1 27\n1 28\n1 29\n1 30\n1 31\n1 32\n1 33\n1 34\n1 35\n1 36\n1 ... | 1,620,829,160 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 124 | 6,963,200 | termo1, termo2 = (int(_) for _ in input().split())
lista = [True]*termo1
for i in range(termo2):
x, y = (int(_) for _ in input().split())
lista[x - 1] = lista[y - 1] = False
aux = -1
for i in range(termo1):
if lista[i]:
aux = i
break
print(termo1 - 1)
for i in range(termo... | Title: Road Construction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A country has *n* cities. Initially, there is no road in the country. One day, the king decides to construct some roads connecting pairs of cities. Roads can be traversed either way. He wants those roads to be constru... | ```python
termo1, termo2 = (int(_) for _ in input().split())
lista = [True]*termo1
for i in range(termo2):
x, y = (int(_) for _ in input().split())
lista[x - 1] = lista[y - 1] = False
aux = -1
for i in range(termo1):
if lista[i]:
aux = i
break
print(termo1 - 1)
for i in r... | 3 | |
712 | B | Memory and Trident | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | Memory is performing a walk on the two-dimensional plane, starting at the origin. He is given a string *s* with his directions for motion:
- An 'L' indicates he should move one unit left. - An 'R' indicates he should move one unit right. - A 'U' indicates he should move one unit up. - A 'D' indicates he should move... | The first and only line contains the string *s* (1<=≤<=|*s*|<=≤<=100<=000) — the instructions Memory is given. | If there is a string satisfying the conditions, output a single integer — the minimum number of edits required. In case it's not possible to change the sequence in such a way that it will bring Memory to to the origin, output -1. | [
"RRU\n",
"UDUR\n",
"RUUR\n"
] | [
"-1\n",
"1\n",
"2\n"
] | In the first sample test, Memory is told to walk right, then right, then up. It is easy to see that it is impossible to edit these instructions to form a valid walk.
In the second sample test, Memory is told to walk up, then down, then up, then right. One possible solution is to change *s* to "LDUR". This string uses ... | 1,000 | [
{
"input": "RRU",
"output": "-1"
},
{
"input": "UDUR",
"output": "1"
},
{
"input": "RUUR",
"output": "2"
},
{
"input": "DDDD",
"output": "2"
},
{
"input": "RRRR",
"output": "2"
},
{
"input": "RRRUUD",
"output": "2"
},
{
"input": "UDURLRDURL... | 1,473,527,939 | 2,039 | Python 3 | WRONG_ANSWER | PRETESTS | 5 | 77 | 0 | s = str(input())
n = len(s)
temp = {
"L": "R",
"R": "L",
"U": "D",
"D": "U"
}
answer = 0
if n % 2 == 0:
left = s[:n // 2]
right = s[n // 2:]
for i in range(len(left)):
if left[i] != temp[right[len(right) - i - 1]]:
answer += 1
print(answer)
els... | Title: Memory and Trident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Memory is performing a walk on the two-dimensional plane, starting at the origin. He is given a string *s* with his directions for motion:
- An 'L' indicates he should move one unit left. - An 'R' indicates he shou... | ```python
s = str(input())
n = len(s)
temp = {
"L": "R",
"R": "L",
"U": "D",
"D": "U"
}
answer = 0
if n % 2 == 0:
left = s[:n // 2]
right = s[n // 2:]
for i in range(len(left)):
if left[i] != temp[right[len(right) - i - 1]]:
answer += 1
print(an... | 0 | |
12 | A | Super Agent | PROGRAMMING | 800 | [
"implementation"
] | A. Super Agent | 2 | 256 | There is a very secret base in Potatoland where potato mash is made according to a special recipe. The neighbours from Porridgia decided to seize this recipe and to sell it to Pilauland. For this mission they have been preparing special agent Pearlo for many years. When, finally, Pearlo learned all secrets of espionage... | Input contains the matrix of three rows of three symbols each. Symbol «X» means that the corresponding button was pressed, and «.» means that is was not pressed. The matrix may contain no «X», also it may contain no «.». | Print YES if the password is symmetric with respect to the central button of the terminal and NO otherwise. | [
"XX.\n...\n.XX\n",
"X.X\nX..\n...\n"
] | [
"YES\n",
"NO\n"
] | If you are not familiar with the term «central symmetry», you may look into http://en.wikipedia.org/wiki/Central_symmetry | 0 | [
{
"input": "XX.\n...\n.XX",
"output": "YES"
},
{
"input": ".X.\n.X.\n.X.",
"output": "YES"
},
{
"input": "XXX\nXXX\nXXX",
"output": "YES"
},
{
"input": "XXX\nX.X\nXXX",
"output": "YES"
},
{
"input": "X..\n.X.\n..X",
"output": "YES"
},
{
"input": "...\n... | 1,627,288,321 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 124 | 6,963,200 | code = []
pos = []
pos2 = []
for i in range(3):
code.append(list(str(input())))
for k in range(len(code)):
for j in range(len(code[k])):
if code[k][j]== 'X':
pos.append(k*3+j+1)
for p in range(len(pos)):
if pos[p] == 1:
pos2.append(9)
if pos[p] == 2:
p... | Title: Super Agent
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a very secret base in Potatoland where potato mash is made according to a special recipe. The neighbours from Porridgia decided to seize this recipe and to sell it to Pilauland. For this mission they have been preparin... | ```python
code = []
pos = []
pos2 = []
for i in range(3):
code.append(list(str(input())))
for k in range(len(code)):
for j in range(len(code[k])):
if code[k][j]== 'X':
pos.append(k*3+j+1)
for p in range(len(pos)):
if pos[p] == 1:
pos2.append(9)
if pos[p] == 2:
... | 0 |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,690,758,241 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 0 | n = int(input())
ans = 0
money = [1, 5, 10, 20, 100]
for x in money[::-1]:
ans += n // x
n = n % x
# print(ans, n)
print(ans)
| Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
n = int(input())
ans = 0
money = [1, 5, 10, 20, 100]
for x in money[::-1]:
ans += n // x
n = n % x
# print(ans, n)
print(ans)
``` | 3 | |
862 | A | Mahmoud and Ehab and the MEX | PROGRAMMING | 1,000 | [
"greedy",
"implementation"
] | null | null | Dr. Evil kidnapped Mahmoud and Ehab in the evil land because of their performance in the Evil Olympiad in Informatics (EOI). He decided to give them some problems to let them go.
Dr. Evil is interested in sets, He has a set of *n* integers. Dr. Evil calls a set of integers evil if the MEX of it is exactly *x*. the MEX... | The first line contains two integers *n* and *x* (1<=≤<=*n*<=≤<=100, 0<=≤<=*x*<=≤<=100) — the size of the set Dr. Evil owns, and the desired MEX.
The second line contains *n* distinct non-negative integers not exceeding 100 that represent the set. | The only line should contain one integer — the minimal number of operations Dr. Evil should perform. | [
"5 3\n0 4 5 6 7\n",
"1 0\n0\n",
"5 0\n1 2 3 4 5\n"
] | [
"2\n",
"1\n",
"0\n"
] | For the first test case Dr. Evil should add 1 and 2 to the set performing 2 operations.
For the second test case Dr. Evil should erase 0 from the set. After that, the set becomes empty, so the MEX of it is 0.
In the third test case the set is already evil. | 500 | [
{
"input": "5 3\n0 4 5 6 7",
"output": "2"
},
{
"input": "1 0\n0",
"output": "1"
},
{
"input": "5 0\n1 2 3 4 5",
"output": "0"
},
{
"input": "10 5\n57 1 47 9 93 37 76 70 78 15",
"output": "4"
},
{
"input": "10 5\n99 98 93 97 95 100 92 94 91 96",
"output": "5"
... | 1,598,188,574 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 11 | 108 | 6,656,000 | if __name__ == '__main__':
n, x = input().split()
n = int(n)
x = int(x)
arr = set(map(int, input().split()))
ans = 0
if x in arr:
ans += 1
else:
for i in range(101):
if i < x and i not in arr:
ans += 1
print(ans)
... | Title: Mahmoud and Ehab and the MEX
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Evil kidnapped Mahmoud and Ehab in the evil land because of their performance in the Evil Olympiad in Informatics (EOI). He decided to give them some problems to let them go.
Dr. Evil is interested in ... | ```python
if __name__ == '__main__':
n, x = input().split()
n = int(n)
x = int(x)
arr = set(map(int, input().split()))
ans = 0
if x in arr:
ans += 1
else:
for i in range(101):
if i < x and i not in arr:
ans += 1
print(ans)
... | 0 | |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,674,589,986 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 93 | 0 | n, t = map(int, input().split())
for i in range((10**(n-1)), 10**n):
if i % t == 0:
print(i)
break | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
n, t = map(int, input().split())
for i in range((10**(n-1)), 10**n):
if i % t == 0:
print(i)
break
``` | 0 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the... | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,695,293,332 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 15 | 0 | a,b,c=map(int,input().split())
d=a%c
x=a//c+1
if d==0:
x=x-1
e=b%c
y=b//c+1
if e==0:
y=y+1
s=x*y
print(s)
| Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each ... | ```python
a,b,c=map(int,input().split())
d=a%c
x=a//c+1
if d==0:
x=x-1
e=b%c
y=b//c+1
if e==0:
y=y+1
s=x*y
print(s)
``` | 0 |
327 | A | Flipping Game | PROGRAMMING | 1,200 | [
"brute force",
"dp",
"implementation"
] | null | null | Iahub got bored, so he invented a game to be played on paper.
He writes *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Each of those integers can be either 0 or 1. He's allowed to do exactly one move: he chooses two indices *i* and *j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) and flips all values *a**k* for which their positions are in... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100). In the second line of the input there are *n* integers: *a*1,<=*a*2,<=...,<=*a**n*. It is guaranteed that each of those *n* values is either 0 or 1. | Print an integer — the maximal number of 1s that can be obtained after exactly one move. | [
"5\n1 0 0 1 0\n",
"4\n1 0 0 1\n"
] | [
"4\n",
"4\n"
] | In the first case, flip the segment from 2 to 5 (*i* = 2, *j* = 5). That flip changes the sequence, it becomes: [1 1 1 0 1]. So, it contains four ones. There is no way to make the whole sequence equal to [1 1 1 1 1].
In the second case, flipping only the second and the third element (*i* = 2, *j* = 3) will turn all nu... | 500 | [
{
"input": "5\n1 0 0 1 0",
"output": "4"
},
{
"input": "4\n1 0 0 1",
"output": "4"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "8\n1 0 0 0 1 0 0 0",
"output": "7"
},
{
"input": "18\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 ... | 1,677,686,999 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 20 | 92 | 0 | n=int(input())
l=[int(i) for i in input().split()]
a=len(l)
su=0
an=0
while(a==1):
if(l[0]==1):
print(0)
a+=1
else:
print(1)
a+=1
if(a>2):
if(0 not in l ):
print(len(l)-1)
else:
a=l.index(0)
b=len(l) - l[::-1].index(0) - ... | Title: Flipping Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub got bored, so he invented a game to be played on paper.
He writes *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Each of those integers can be either 0 or 1. He's allowed to do exactly one move: he chooses two indices *... | ```python
n=int(input())
l=[int(i) for i in input().split()]
a=len(l)
su=0
an=0
while(a==1):
if(l[0]==1):
print(0)
a+=1
else:
print(1)
a+=1
if(a>2):
if(0 not in l ):
print(len(l)-1)
else:
a=l.index(0)
b=len(l) - l[::-1].i... | 0 | |
545 | D | Queue | PROGRAMMING | 1,300 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time he waits is more than the time needed to serve him. The time a person waits is the total t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The next line contains *n* integers *t**i* (1<=≤<=*t**i*<=≤<=109), separated by spaces. | Print a single number — the maximum number of not disappointed people in the queue. | [
"5\n15 2 1 5 3\n"
] | [
"4\n"
] | Value 4 is achieved at such an arrangement, for example: 1, 2, 3, 5, 15. Thus, you can make everything feel not disappointed except for the person with time 5. | 1,750 | [
{
"input": "5\n15 2 1 5 3",
"output": "4"
},
{
"input": "15\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "2"
},
{
"input": "10\n13 2 5 55 21 34 1 8 1 3",
"output": "6"
},
{
"input": "10\n8 256 16 1 2 1 64 4 128 32",
"output": "10"
},
{
"input": "10\n10000 40000 1000... | 1,680,556,852 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 61 | 0 | n=int(input())
a=list(map(int, input().split()))
a.sort()
c=1
s=0
for i in range(1, n):
s+=a[i-1]
if a[i]>=s:
c+=1
print(c) | Title: Queue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time... | ```python
n=int(input())
a=list(map(int, input().split()))
a.sort()
c=1
s=0
for i in range(1, n):
s+=a[i-1]
if a[i]>=s:
c+=1
print(c)
``` | 0 | |
743 | C | Vladik and fractions | PROGRAMMING | 1,500 | [
"brute force",
"constructive algorithms",
"math",
"number theory"
] | null | null | Vladik and Chloe decided to determine who of them is better at math. Vladik claimed that for any positive integer *n* he can represent fraction as a sum of three distinct positive fractions in form .
Help Vladik with that, i.e for a given *n* find three distinct positive integers *x*, *y* and *z* such that . Because ... | The single line contains single integer *n* (1<=≤<=*n*<=≤<=104). | If the answer exists, print 3 distinct numbers *x*, *y* and *z* (1<=≤<=*x*,<=*y*,<=*z*<=≤<=109, *x*<=≠<=*y*, *x*<=≠<=*z*, *y*<=≠<=*z*). Otherwise print -1.
If there are multiple answers, print any of them. | [
"3\n",
"7\n"
] | [
"2 7 42\n",
"7 8 56\n"
] | none | 1,250 | [
{
"input": "3",
"output": "2 7 42"
},
{
"input": "7",
"output": "7 8 56"
},
{
"input": "2",
"output": "2 3 6"
},
{
"input": "5",
"output": "5 6 30"
},
{
"input": "4",
"output": "4 5 20"
},
{
"input": "7",
"output": "7 8 56"
},
{
"input": "8... | 1,667,892,575 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | # LUOGU_RID: 93256855
n=int(input())
if n=1
print(-1)
else:
print(n,n+1,n*(n+1)) | Title: Vladik and fractions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vladik and Chloe decided to determine who of them is better at math. Vladik claimed that for any positive integer *n* he can represent fraction as a sum of three distinct positive fractions in form .
Help Vladik ... | ```python
# LUOGU_RID: 93256855
n=int(input())
if n=1
print(-1)
else:
print(n,n+1,n*(n+1))
``` | -1 | |
549 | C | The Game Of Parity | PROGRAMMING | 2,200 | [
"games"
] | null | null | There are *n* cities in Westeros. The *i*-th city is inhabited by *a**i* people. Daenerys and Stannis play the following game: in one single move, a player chooses a certain town and burns it to the ground. Thus all its residents, sadly, die. Stannis starts the game. The game ends when Westeros has exactly *k* cities l... | The first line contains two positive space-separated integers, *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=2·105) — the initial number of cities in Westeros and the number of cities at which the game ends.
The second line contains *n* space-separated positive integers *a**i* (1<=≤<=*a**i*<=≤<=106), which represent the populat... | Print string "Daenerys" (without the quotes), if Daenerys wins and "Stannis" (without the quotes), if Stannis wins. | [
"3 1\n1 2 1\n",
"3 1\n2 2 1\n",
"6 3\n5 20 12 7 14 101\n"
] | [
"Stannis\n",
"Daenerys\n",
"Stannis\n"
] | In the first sample Stannis will use his move to burn a city with two people and Daenerys will be forced to burn a city with one resident. The only survivor city will have one resident left, that is, the total sum is odd, and thus Stannis wins.
In the second sample, if Stannis burns a city with two people, Daenerys bu... | 2,000 | [
{
"input": "3 1\n1 2 1",
"output": "Stannis"
},
{
"input": "3 1\n2 2 1",
"output": "Daenerys"
},
{
"input": "6 3\n5 20 12 7 14 101",
"output": "Stannis"
},
{
"input": "6 3\n346 118 330 1403 5244 480",
"output": "Daenerys"
},
{
"input": "7 4\n11 3532 99 3512 12 8 2... | 1,433,617,042 | 2,842 | Python 3 | WRONG_ANSWER | TESTS | 4 | 61 | 0 | n,k = map(int,input().split())
a = list(map(int,input().split()))
moves = n - k
even,odd = 0,0
for i in a:
if i % 2 == 0:
even += 1
else:
odd += 1
sMoves = moves//2 if moves%2 == 0 else moves//2+1
dMoves = moves - sMoves
print('Stannis') if odd>sMoves else print('Daenerys') | Title: The Game Of Parity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities in Westeros. The *i*-th city is inhabited by *a**i* people. Daenerys and Stannis play the following game: in one single move, a player chooses a certain town and burns it to the ground. Thus all ... | ```python
n,k = map(int,input().split())
a = list(map(int,input().split()))
moves = n - k
even,odd = 0,0
for i in a:
if i % 2 == 0:
even += 1
else:
odd += 1
sMoves = moves//2 if moves%2 == 0 else moves//2+1
dMoves = moves - sMoves
print('Stannis') if odd>sMoves else print('Daenerys')
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after *k* minutes after turning on.
During cooking, Julia goes to the kitchen every *d* minutes and turns on the stove if it is turned off. While the cooker is turned off, it stays warm. T... | The single line contains three integers *k*, *d* and *t* (1<=≤<=*k*,<=*d*,<=*t*<=≤<=1018). | Print a single number, the total time of cooking in minutes. The relative or absolute error must not exceed 10<=-<=9.
Namely, let's assume that your answer is *x* and the answer of the jury is *y*. The checker program will consider your answer correct if . | [
"3 2 6\n",
"4 2 20\n"
] | [
"6.5\n",
"20.0\n"
] | In the first example, the chicken will be cooked for 3 minutes on the turned on stove, after this it will be cooked for <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/cce5d3f2f46552034d5ae5d487725705429ec7a5.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Then the chicken will be coo... | 0 | [
{
"input": "3 2 6",
"output": "6.5"
},
{
"input": "4 2 20",
"output": "20.0"
},
{
"input": "8 10 9",
"output": "10.0"
},
{
"input": "43 50 140",
"output": "150.5"
},
{
"input": "251 79 76",
"output": "76.0"
},
{
"input": "892 67 1000",
"output": "1... | 1,527,260,786 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 78 | 0 | k,d,t=input().split()
k,d,t=int(k),int(d),int(t)
on=k
off=d-(k-1)%d-1
cycle=on+off/2
time=(on+off)*(t//cycle)
t-=cycle*(t//cycle)
if t<k:
print(t+time)
else:
print(time+k+(t-k)*2) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after *k* minutes after turning on.
During cooking, Julia goes to the kitchen every *d* minutes an... | ```python
k,d,t=input().split()
k,d,t=int(k),int(d),int(t)
on=k
off=d-(k-1)%d-1
cycle=on+off/2
time=(on+off)*(t//cycle)
t-=cycle*(t//cycle)
if t<k:
print(t+time)
else:
print(time+k+(t-k)*2)
``` | 3 | |
237 | A | Free Cash | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends less than a minute to serve each client, but if a client comes in and sees that there is no free... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), that is the number of cafe visitors.
Each of the following *n* lines has two space-separated integers *h**i* and *m**i* (0<=≤<=*h**i*<=≤<=23; 0<=≤<=*m**i*<=≤<=59), representing the time when the *i*-th person comes into the cafe.
Note that the time is... | Print a single integer — the minimum number of cashes, needed to serve all clients next day. | [
"4\n8 0\n8 10\n8 10\n8 45\n",
"3\n0 12\n10 11\n22 22\n"
] | [
"2\n",
"1\n"
] | In the first sample it is not enough one cash to serve all clients, because two visitors will come into cafe in 8:10. Therefore, if there will be one cash in cafe, then one customer will be served by it, and another one will not wait and will go away.
In the second sample all visitors will come in different times, so ... | 500 | [
{
"input": "4\n8 0\n8 10\n8 10\n8 45",
"output": "2"
},
{
"input": "3\n0 12\n10 11\n22 22",
"output": "1"
},
{
"input": "5\n12 8\n15 27\n15 27\n16 2\n19 52",
"output": "2"
},
{
"input": "7\n5 6\n7 34\n7 34\n7 34\n12 29\n15 19\n20 23",
"output": "3"
},
{
"input": "... | 1,596,992,991 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 186 | 6,656,000 | n = int(input())
ss = set()
ans = 1
for i in range(n):
k,p = map(int,input().split())
ss.add(str(k)+":"+str(p))
print(n- len(ss) + 1) | Title: Free Cash
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends l... | ```python
n = int(input())
ss = set()
ans = 1
for i in range(n):
k,p = map(int,input().split())
ss.add(str(k)+":"+str(p))
print(n- len(ss) + 1)
``` | 0 | |
699 | A | Launch of Collider | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There will be a launch of a new, powerful and unusual collider very soon, which located along a straight line. *n* particles will be launched inside it. All of them are located in a straight line and there can not be two or more particles located in the same point. The coordinates of the particles coincide with the dis... | The first line contains the positive integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of particles.
The second line contains *n* symbols "L" and "R". If the *i*-th symbol equals "L", then the *i*-th particle will move to the left, otherwise the *i*-th symbol equals "R" and the *i*-th particle will move to the right.... | In the first line print the only integer — the first moment (in microseconds) when two particles are at the same point and there will be an explosion.
Print the only integer -1, if the collision of particles doesn't happen. | [
"4\nRLRL\n2 4 6 10\n",
"3\nLLR\n40 50 60\n"
] | [
"1\n",
"-1\n"
] | In the first sample case the first explosion will happen in 1 microsecond because the particles number 1 and 2 will simultaneously be at the same point with the coordinate 3.
In the second sample case there will be no explosion because there are no particles which will simultaneously be at the same point. | 500 | [
{
"input": "4\nRLRL\n2 4 6 10",
"output": "1"
},
{
"input": "3\nLLR\n40 50 60",
"output": "-1"
},
{
"input": "4\nRLLR\n46 230 264 470",
"output": "92"
},
{
"input": "6\nLLRLLL\n446 492 650 844 930 970",
"output": "97"
},
{
"input": "8\nRRLLLLLL\n338 478 512 574 59... | 1,654,585,437 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | n=int(input())
string=input()
lst=list(map(int,input().split()))
stack=[]
cnt=0
for i in range(n):
if stack and stack[-1]=='R' and string[i]=='L':
print((lst[i]-lst[i-1])//2)
exit()
else:
stack.append(string[i])
cnt+=1
print(-1) | Title: Launch of Collider
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There will be a launch of a new, powerful and unusual collider very soon, which located along a straight line. *n* particles will be launched inside it. All of them are located in a straight line and there can not be... | ```python
n=int(input())
string=input()
lst=list(map(int,input().split()))
stack=[]
cnt=0
for i in range(n):
if stack and stack[-1]=='R' and string[i]=='L':
print((lst[i]-lst[i-1])//2)
exit()
else:
stack.append(string[i])
cnt+=1
print(-1)
``` | 0 | |
277 | A | Learning Languages | PROGRAMMING | 1,400 | [
"dfs and similar",
"dsu"
] | null | null | The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have the list of languages, which he knows. This list could be empty, i. e. an employee may know no official la... | The first line contains two integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=100) — the number of employees and the number of languages.
Then *n* lines follow — each employee's language list. At the beginning of the *i*-th line is integer *k**i* (0<=≤<=*k**i*<=≤<=*m*) — the number of languages the *i*-th employee knows. Next... | Print a single integer — the minimum amount of money to pay so that in the end every employee could write a letter to every other one (other employees can help out translating). | [
"5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5\n",
"8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1\n",
"2 2\n1 2\n0\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the second sample the employee 1 can learn language 2, and employee 8 can learn language 4.
In the third sample employee 2 must learn language 2. | 500 | [
{
"input": "5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5",
"output": "0"
},
{
"input": "8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1",
"output": "2"
},
{
"input": "2 2\n1 2\n0",
"output": "1"
},
{
"input": "2 2\n0\n0",
"output": "2"
},
{
"input": "5 5\n1 3\n0\n0\n2 4... | 1,678,125,346 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | from collections import defaultdict
# function to do depth first search
def dfs(node, visited, adj_list):
visited[node] = True
for neighbor in adj_list[node]:
if not visited[neighbor]:
dfs(neighbor, visited, adj_list)
# read input values
n, m = map(int, input().split())
# crea... | Title: Learning Languages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have th... | ```python
from collections import defaultdict
# function to do depth first search
def dfs(node, visited, adj_list):
visited[node] = True
for neighbor in adj_list[node]:
if not visited[neighbor]:
dfs(neighbor, visited, adj_list)
# read input values
n, m = map(int, input().split())... | 0 | |
75 | A | Life Without Zeros | PROGRAMMING | 1,000 | [
"implementation"
] | A. Life Without Zeros | 2 | 256 | Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c*... | The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*. | The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise. | [
"101\n102\n",
"105\n106\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "101\n102",
"output": "YES"
},
{
"input": "105\n106",
"output": "NO"
},
{
"input": "544\n397",
"output": "YES"
},
{
"input": "822\n280",
"output": "NO"
},
{
"input": "101\n413",
"output": "NO"
},
{
"input": "309\n139",
"output": "NO"
}... | 1,534,888,032 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 218 | 0 | n = input()
m = input()
s1 = int(n) + int(m)
s = str(s1)
s = s.replace('0','')
n = n.replace('0','')
m = m.replace('0','')
k = int(n) + int(m)
if(int(k)==int(s)):
print("YES")
else:
print("NO")
# 1534888106664
| Title: Life Without Zeros
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assu... | ```python
n = input()
m = input()
s1 = int(n) + int(m)
s = str(s1)
s = s.replace('0','')
n = n.replace('0','')
m = m.replace('0','')
k = int(n) + int(m)
if(int(k)==int(s)):
print("YES")
else:
print("NO")
# 1534888106664
``` | 3.9455 |
992 | A | Nastya and an Array | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second we can add an arbitrary (possibly negative) integer to all elements of the array that are not equal to ze... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the size of the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=105<=≤<=*a**i*<=≤<=105) — the elements of the array. | Print a single integer — the minimum number of seconds needed to make all elements of the array equal to zero. | [
"5\n1 1 1 1 1\n",
"3\n2 0 -1\n",
"4\n5 -6 -5 1\n"
] | [
"1\n",
"2\n",
"4\n"
] | In the first example you can add - 1 to all non-zero elements in one second and make them equal to zero.
In the second example you can add - 2 on the first second, then the array becomes equal to [0, 0, - 3]. On the second second you can add 3 to the third (the only non-zero) element. | 500 | [
{
"input": "5\n1 1 1 1 1",
"output": "1"
},
{
"input": "3\n2 0 -1",
"output": "2"
},
{
"input": "4\n5 -6 -5 1",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n21794 -79194",
"output": "2"
},
{
"input": "3\n-63526 95085 -5239",
... | 1,534,962,160 | 520 | Python 3 | OK | TESTS | 79 | 186 | 8,908,800 | from collections import Counter
n = int(input())
arr = [int(x) for x in input().split()]
count = Counter(arr)
if 0 in arr:
print(len(count) - 1)
else:
print(len(count))
| Title: Nastya and an Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second ... | ```python
from collections import Counter
n = int(input())
arr = [int(x) for x in input().split()]
count = Counter(arr)
if 0 in arr:
print(len(count) - 1)
else:
print(len(count))
``` | 3 | |
702 | B | Powers of Two | PROGRAMMING | 1,500 | [
"brute force",
"data structures",
"implementation",
"math"
] | null | null | You are given *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Find the number of pairs of indexes *i*,<=*j* (*i*<=<<=*j*) that *a**i*<=+<=*a**j* is a power of 2 (i. e. some integer *x* exists so that *a**i*<=+<=*a**j*<==<=2*x*). | The first line contains the single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of integers.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print the number of pairs of indexes *i*,<=*j* (*i*<=<<=*j*) that *a**i*<=+<=*a**j* is a power of 2. | [
"4\n7 3 2 1\n",
"3\n1 1 1\n"
] | [
"2\n",
"3\n"
] | In the first example the following pairs of indexes include in answer: (1, 4) and (2, 4).
In the second example all pairs of indexes (*i*, *j*) (where *i* < *j*) include in answer. | 0 | [
{
"input": "4\n7 3 2 1",
"output": "2"
},
{
"input": "3\n1 1 1",
"output": "3"
},
{
"input": "1\n1000000000",
"output": "0"
},
{
"input": "10\n2827343 1373647 96204862 723505 796619138 71550121 799843967 5561265 402690754 446173607",
"output": "2"
},
{
"input": "1... | 1,672,393,376 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | import math
n = int(input())
a = list(map(int,input().split()))
ta = []
for i in range(0,32):
ta.append(2**i)
c = 0
for i in range(n):
for j in range(32):
s = ta[j]-a[i]
for k in range(n):
if k!=i:
if s==a[k]:
print(ta[j],a[i],s)
c += 1
print(c//2)
| Title: Powers of Two
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Find the number of pairs of indexes *i*,<=*j* (*i*<=<<=*j*) that *a**i*<=+<=*a**j* is a power of 2 (i. e. some integer *x* exists so that *a**i*<=+<=*a**j*<==<=2*x... | ```python
import math
n = int(input())
a = list(map(int,input().split()))
ta = []
for i in range(0,32):
ta.append(2**i)
c = 0
for i in range(n):
for j in range(32):
s = ta[j]-a[i]
for k in range(n):
if k!=i:
if s==a[k]:
print(ta[j],a[i],s)
c += 1
print(c//2)
... | 0 | |
63 | A | Sinking Ship | PROGRAMMING | 900 | [
"implementation",
"sortings",
"strings"
] | A. Sinking Ship | 2 | 256 | The ship crashed into a reef and is sinking. Now the entire crew must be evacuated. All *n* crew members have already lined up in a row (for convenience let's label them all from left to right with positive integers from 1 to *n*) and await further instructions. However, one should evacuate the crew properly, in a stri... | The first line contains an integer *n*, which is the number of people in the crew (1<=≤<=*n*<=≤<=100). Then follow *n* lines. The *i*-th of those lines contains two words — the name of the crew member who is *i*-th in line, and his status on the ship. The words are separated by exactly one space. There are no other spa... | Print *n* lines. The *i*-th of them should contain the name of the crew member who must be the *i*-th one to leave the ship. | [
"6\nJack captain\nAlice woman\nCharlie man\nTeddy rat\nBob child\nJulia woman\n"
] | [
"Teddy\nAlice\nBob\nJulia\nCharlie\nJack\n"
] | none | 500 | [
{
"input": "6\nJack captain\nAlice woman\nCharlie man\nTeddy rat\nBob child\nJulia woman",
"output": "Teddy\nAlice\nBob\nJulia\nCharlie\nJack"
},
{
"input": "1\nA captain",
"output": "A"
},
{
"input": "1\nAbcdefjhij captain",
"output": "Abcdefjhij"
},
{
"input": "5\nA captain... | 1,622,129,337 | 2,147,483,647 | PyPy 3 | OK | TESTS | 26 | 186 | 0 | from sys import stdin
d={}
for _ in range(int(stdin.readline())):
n,k=stdin.readline().split()
if k=='woman' or k=='child': k='common'
d[k]=d.get(k,"")+n+"\n"
print(str(d.get('rat',""))+str(d.get('common',""))+str(d.get('man',""))+str(d.get('captain',"")),end="")
| Title: Sinking Ship
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The ship crashed into a reef and is sinking. Now the entire crew must be evacuated. All *n* crew members have already lined up in a row (for convenience let's label them all from left to right with positive integers from 1 to ... | ```python
from sys import stdin
d={}
for _ in range(int(stdin.readline())):
n,k=stdin.readline().split()
if k=='woman' or k=='child': k='common'
d[k]=d.get(k,"")+n+"\n"
print(str(d.get('rat',""))+str(d.get('common',""))+str(d.get('man',""))+str(d.get('captain',"")),end="")
`... | 3.9535 |
935 | A | Fafa and his Company | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* em... | The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company. | Print a single integer representing the answer to the problem. | [
"2\n",
"10\n"
] | [
"1\n",
"3\n"
] | In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | 500 | [
{
"input": "2",
"output": "1"
},
{
"input": "10",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "6",
"output": "3"
},
{
"input": "13",
"output": "1"
},
{
"input": "100000",
"output": "35"
... | 1,688,762,789 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 |
# это задача 1472A
t = int(input())
for i in range(t):
x = 1
w, h, n = map(int, input().split())
for j in range(n) :
if w % 2 == 0:
x = x + 1
w = w//2
if h % 2 == 0:
x = x + 1
h = h//2
if x >= n:
print("YES... | Title: Fafa and his Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the emp... | ```python
# это задача 1472A
t = int(input())
for i in range(t):
x = 1
w, h, n = map(int, input().split())
for j in range(n) :
if w % 2 == 0:
x = x + 1
w = w//2
if h % 2 == 0:
x = x + 1
h = h//2
if x >= n:
... | -1 | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,667,590,596 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 92 | 0 | sentence = input()
sentence = sentence.rstrip()
vowels = ["a", "e", "i", "o", "u", "y"]
for i in range(1, len(sentence)):
if (sentence[len(sentence) - i]).lower() in vowels:
print("YES")
break
elif (sentence[len(sentence) - i]).lower() not in vowels and ((sentence[len(sentence) - i]).... | Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
sentence = input()
sentence = sentence.rstrip()
vowels = ["a", "e", "i", "o", "u", "y"]
for i in range(1, len(sentence)):
if (sentence[len(sentence) - i]).lower() in vowels:
print("YES")
break
elif (sentence[len(sentence) - i]).lower() not in vowels and ((sentence[len(senten... | 0 |
441 | A | Valera and Antique Items | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the *j*-th object of the *i*-th seller is *s**ij*. Valera gets on well with each of the *n* sellers. He is perfec... | The first line contains two space-separated integers *n*,<=*v* (1<=≤<=*n*<=≤<=50; 104<=≤<=*v*<=≤<=106) — the number of sellers and the units of money the Valera has.
Then *n* lines follow. The *i*-th line first contains integer *k**i* (1<=≤<=*k**i*<=≤<=50) the number of items of the *i*-th seller. Then go *k**i* space... | In the first line, print integer *p* — the number of sellers with who Valera can make a deal.
In the second line print *p* space-separated integers *q*1,<=*q*2,<=...,<=*q**p* (1<=≤<=*q**i*<=≤<=*n*) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order. | [
"3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000\n",
"3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000\n"
] | [
"3\n1 2 3\n",
"0\n\n"
] | In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.
In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the... | 500 | [
{
"input": "3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000",
"output": "3\n1 2 3"
},
{
"input": "3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000",
"output": "0"
},
{
"input": "2 100001\n1 895737\n1 541571",
"output": "0"
},
{
"input": "1 1000000\n1 100... | 1,467,767,896 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 62 | 0 | enteros = input()
#n es número de vendedores
#v cantidad de dinero de Valera
n, v = enteros.split()
n = int(n)
v = int(v)
#print("n", n, "v", v)
resultado = []
for i in range(1, n+1):
#print("i =", i)
datos = input().split()
for j in datos[1:]:
if v > int(j):
resultado.append(i)
... | Title: Valera and Antique Items
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the... | ```python
enteros = input()
#n es número de vendedores
#v cantidad de dinero de Valera
n, v = enteros.split()
n = int(n)
v = int(v)
#print("n", n, "v", v)
resultado = []
for i in range(1, n+1):
#print("i =", i)
datos = input().split()
for j in datos[1:]:
if v > int(j):
resultado.append(i... | 3 |
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