contestId int64 0 1.01k | index stringclasses 57 values | name stringlengths 2 58 | type stringclasses 2 values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522 values | time-limit stringclasses 8 values | memory-limit stringclasses 8 values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3 values | verdict stringclasses 14 values | testset stringclasses 12 values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
471 | C | MUH and House of Cards | PROGRAMMING | 1,700 | [
"binary search",
"brute force",
"greedy",
"math"
] | null | null | Polar bears Menshykov and Uslada from the zoo of St. Petersburg and elephant Horace from the zoo of Kiev decided to build a house of cards. For that they've already found a hefty deck of *n* playing cards. Let's describe the house they want to make:
1. The house consists of some non-zero number of floors. 1. Each floor consists of a non-zero number of rooms and the ceiling. A room is two cards that are leaned towards each other. The rooms are made in a row, each two adjoining rooms share a ceiling made by another card. 1. Each floor besides for the lowest one should contain less rooms than the floor below.
Please note that the house may end by the floor with more than one room, and in this case they also must be covered by the ceiling. Also, the number of rooms on the adjoining floors doesn't have to differ by one, the difference may be more.
While bears are practicing to put cards, Horace tries to figure out how many floors their house should consist of. The height of the house is the number of floors in it. It is possible that you can make a lot of different houses of different heights out of *n* cards. It seems that the elephant cannot solve this problem and he asks you to count the number of the distinct heights of the houses that they can make using exactly *n* cards. | The single line contains integer *n* (1<=≤<=*n*<=≤<=1012) — the number of cards. | Print the number of distinct heights that the houses made of exactly *n* cards can have. | [
"13\n",
"6\n"
] | [
"1",
"0"
] | In the first sample you can build only these two houses (remember, you must use all the cards):
Thus, 13 cards are enough only for two floor houses, so the answer is 1.
The six cards in the second sample are not enough to build any house. | 2,000 | [
{
"input": "13",
"output": "1"
},
{
"input": "6",
"output": "0"
},
{
"input": "26",
"output": "2"
},
{
"input": "1000000000000",
"output": "272165"
},
{
"input": "571684826707",
"output": "205784"
},
{
"input": "178573947413",
"output": "115012"
... | 1,488,742,262 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 935 | 4,608,000 | n,a,b=int(input()),0,0
for i in range(1,int(1e12)+1):
if i**2>1e12:break
a+=3*i-1
if a>n:break
if(n-a)%3==0:b+=1
print(b) | Title: MUH and House of Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polar bears Menshykov and Uslada from the zoo of St. Petersburg and elephant Horace from the zoo of Kiev decided to build a house of cards. For that they've already found a hefty deck of *n* playing cards. Let's describe the house they want to make:
1. The house consists of some non-zero number of floors. 1. Each floor consists of a non-zero number of rooms and the ceiling. A room is two cards that are leaned towards each other. The rooms are made in a row, each two adjoining rooms share a ceiling made by another card. 1. Each floor besides for the lowest one should contain less rooms than the floor below.
Please note that the house may end by the floor with more than one room, and in this case they also must be covered by the ceiling. Also, the number of rooms on the adjoining floors doesn't have to differ by one, the difference may be more.
While bears are practicing to put cards, Horace tries to figure out how many floors their house should consist of. The height of the house is the number of floors in it. It is possible that you can make a lot of different houses of different heights out of *n* cards. It seems that the elephant cannot solve this problem and he asks you to count the number of the distinct heights of the houses that they can make using exactly *n* cards.
Input Specification:
The single line contains integer *n* (1<=≤<=*n*<=≤<=1012) — the number of cards.
Output Specification:
Print the number of distinct heights that the houses made of exactly *n* cards can have.
Demo Input:
['13\n', '6\n']
Demo Output:
['1', '0']
Note:
In the first sample you can build only these two houses (remember, you must use all the cards):
Thus, 13 cards are enough only for two floor houses, so the answer is 1.
The six cards in the second sample are not enough to build any house. | ```python
n,a,b=int(input()),0,0
for i in range(1,int(1e12)+1):
if i**2>1e12:break
a+=3*i-1
if a>n:break
if(n-a)%3==0:b+=1
print(b)
``` | 3 | |
908 | F | New Year and Rainbow Roads | PROGRAMMING | 2,400 | [
"graphs",
"greedy",
"implementation"
] | null | null | Roy and Biv have a set of *n* points on the infinite number line.
Each point has one of 3 colors: red, green, or blue.
Roy and Biv would like to connect all the points with some edges. Edges can be drawn between any of the two of the given points. The cost of an edge is equal to the distance between the two points it connects.
They want to do this in such a way that they will both see that all the points are connected (either directly or indirectly).
However, there is a catch: Roy cannot see the color red and Biv cannot see the color blue.
Therefore, they have to choose the edges in such a way that if all the red points are removed, the remaining blue and green points are connected (and similarly, if all the blue points are removed, the remaining red and green points are connected).
Help them compute the minimum cost way to choose edges to satisfy the above constraints. | The first line will contain an integer *n* (1<=≤<=*n*<=≤<=300<=000), the number of points.
The next *n* lines will contain two tokens *p**i* and *c**i* (*p**i* is an integer, 1<=≤<=*p**i*<=≤<=109, *c**i* is a uppercase English letter 'R', 'G' or 'B'), denoting the position of the *i*-th point and the color of the *i*-th point. 'R' means red, 'G' denotes green, and 'B' means blue. The positions will be in strictly increasing order. | Print a single integer, the minimum cost way to solve the problem. | [
"4\n1 G\n5 R\n10 B\n15 G\n",
"4\n1 G\n2 R\n3 B\n10 G\n"
] | [
"23\n",
"12\n"
] | In the first sample, it is optimal to draw edges between the points (1,2), (1,4), (3,4). These have costs 4, 14, 5, respectively. | 2,000 | [
{
"input": "4\n1 G\n5 R\n10 B\n15 G",
"output": "23"
},
{
"input": "4\n1 G\n2 R\n3 B\n10 G",
"output": "12"
},
{
"input": "4\n1 G\n123123 R\n987987987 B\n1000000000 G",
"output": "1012135134"
},
{
"input": "1\n3 R",
"output": "0"
}
] | 1,514,569,578 | 7,578 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 46 | 5,529,600 | n=int(input())
ar=[input().split() for x in range(n)]
G,R,B=[],[],[]
for x in ar:
if x[1]=='G':G.append(int(x[0]))
elif x[1]=='R':R.append(int(x[0]))
elif x[1]=='B':B.append(int(x[0]))
sum=0
for i in range(len(G)-1):
x1,x2=G[i],G[i+1]
while R and R[0] < x1:
sum+=abs(R[0]-x1)
del R[0]
while R and abs(R[0]-x1) < abs(R[0]-x2):
sum+=abs(R[0]-x1)
del R[0]
while R and R[0] < x2:
sum+=abs(R[0]-x2)
del R[0]
while B and B[0] < x1:
sum+=abs(B[0]-x1)
del B[0]
while B and abs(B[0]-x1) < abs(B[0]-x2):
sum+=abs(B[0]-x1)
del B[0]
while B and B[0] < x2:
sum+=abs(B[0]-x2)
del B[0]
sum+=x2-x1
print(sum) | Title: New Year and Rainbow Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Roy and Biv have a set of *n* points on the infinite number line.
Each point has one of 3 colors: red, green, or blue.
Roy and Biv would like to connect all the points with some edges. Edges can be drawn between any of the two of the given points. The cost of an edge is equal to the distance between the two points it connects.
They want to do this in such a way that they will both see that all the points are connected (either directly or indirectly).
However, there is a catch: Roy cannot see the color red and Biv cannot see the color blue.
Therefore, they have to choose the edges in such a way that if all the red points are removed, the remaining blue and green points are connected (and similarly, if all the blue points are removed, the remaining red and green points are connected).
Help them compute the minimum cost way to choose edges to satisfy the above constraints.
Input Specification:
The first line will contain an integer *n* (1<=≤<=*n*<=≤<=300<=000), the number of points.
The next *n* lines will contain two tokens *p**i* and *c**i* (*p**i* is an integer, 1<=≤<=*p**i*<=≤<=109, *c**i* is a uppercase English letter 'R', 'G' or 'B'), denoting the position of the *i*-th point and the color of the *i*-th point. 'R' means red, 'G' denotes green, and 'B' means blue. The positions will be in strictly increasing order.
Output Specification:
Print a single integer, the minimum cost way to solve the problem.
Demo Input:
['4\n1 G\n5 R\n10 B\n15 G\n', '4\n1 G\n2 R\n3 B\n10 G\n']
Demo Output:
['23\n', '12\n']
Note:
In the first sample, it is optimal to draw edges between the points (1,2), (1,4), (3,4). These have costs 4, 14, 5, respectively. | ```python
n=int(input())
ar=[input().split() for x in range(n)]
G,R,B=[],[],[]
for x in ar:
if x[1]=='G':G.append(int(x[0]))
elif x[1]=='R':R.append(int(x[0]))
elif x[1]=='B':B.append(int(x[0]))
sum=0
for i in range(len(G)-1):
x1,x2=G[i],G[i+1]
while R and R[0] < x1:
sum+=abs(R[0]-x1)
del R[0]
while R and abs(R[0]-x1) < abs(R[0]-x2):
sum+=abs(R[0]-x1)
del R[0]
while R and R[0] < x2:
sum+=abs(R[0]-x2)
del R[0]
while B and B[0] < x1:
sum+=abs(B[0]-x1)
del B[0]
while B and abs(B[0]-x1) < abs(B[0]-x2):
sum+=abs(B[0]-x1)
del B[0]
while B and B[0] < x2:
sum+=abs(B[0]-x2)
del B[0]
sum+=x2-x1
print(sum)
``` | 0 | |
172 | A | Phone Code | PROGRAMMING | 800 | [
"*special",
"brute force",
"implementation"
] | null | null | Polycarpus has *n* friends in Tarasov city. Polycarpus knows phone numbers of all his friends: they are strings *s*1,<=*s*2,<=...,<=*s**n*. All these strings consist only of digits and have the same length.
Once Polycarpus needed to figure out Tarasov city phone code. He assumed that the phone code of the city is the longest common prefix of all phone numbers of his friends. In other words, it is the longest string *c* which is a prefix (the beginning) of each *s**i* for all *i* (1<=≤<=*i*<=≤<=*n*). Help Polycarpus determine the length of the city phone code. | The first line of the input contains an integer *n* (2<=≤<=*n*<=≤<=3·104) — the number of Polycarpus's friends. The following *n* lines contain strings *s*1,<=*s*2,<=...,<=*s**n* — the phone numbers of Polycarpus's friends. It is guaranteed that all strings consist only of digits and have the same length from 1 to 20, inclusive. It is also guaranteed that all strings are different. | Print the number of digits in the city phone code. | [
"4\n00209\n00219\n00999\n00909\n",
"2\n1\n2\n",
"3\n77012345678999999999\n77012345678901234567\n77012345678998765432\n"
] | [
"2\n",
"0\n",
"12\n"
] | A prefix of string *t* is a string that is obtained by deleting zero or more digits from the end of string *t*. For example, string "00209" has 6 prefixes: "" (an empty prefix), "0", "00", "002", "0020", "00209".
In the first sample the city phone code is string "00".
In the second sample the city phone code is an empty string.
In the third sample the city phone code is string "770123456789". | 1,000 | [
{
"input": "4\n00209\n00219\n00999\n00909",
"output": "2"
},
{
"input": "2\n1\n2",
"output": "0"
},
{
"input": "3\n77012345678999999999\n77012345678901234567\n77012345678998765432",
"output": "12"
},
{
"input": "5\n4491183345\n4491184811\n4491162340\n4491233399\n4491449214",
... | 1,650,165,834 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 310 | 0 |
n = int(input())
w = input()
for _ in range(n-1):
s = input()
for i in range(len(w)):
if s[i] != w[i]:
w = w[:i]
break
print(len(w))
| Title: Phone Code
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has *n* friends in Tarasov city. Polycarpus knows phone numbers of all his friends: they are strings *s*1,<=*s*2,<=...,<=*s**n*. All these strings consist only of digits and have the same length.
Once Polycarpus needed to figure out Tarasov city phone code. He assumed that the phone code of the city is the longest common prefix of all phone numbers of his friends. In other words, it is the longest string *c* which is a prefix (the beginning) of each *s**i* for all *i* (1<=≤<=*i*<=≤<=*n*). Help Polycarpus determine the length of the city phone code.
Input Specification:
The first line of the input contains an integer *n* (2<=≤<=*n*<=≤<=3·104) — the number of Polycarpus's friends. The following *n* lines contain strings *s*1,<=*s*2,<=...,<=*s**n* — the phone numbers of Polycarpus's friends. It is guaranteed that all strings consist only of digits and have the same length from 1 to 20, inclusive. It is also guaranteed that all strings are different.
Output Specification:
Print the number of digits in the city phone code.
Demo Input:
['4\n00209\n00219\n00999\n00909\n', '2\n1\n2\n', '3\n77012345678999999999\n77012345678901234567\n77012345678998765432\n']
Demo Output:
['2\n', '0\n', '12\n']
Note:
A prefix of string *t* is a string that is obtained by deleting zero or more digits from the end of string *t*. For example, string "00209" has 6 prefixes: "" (an empty prefix), "0", "00", "002", "0020", "00209".
In the first sample the city phone code is string "00".
In the second sample the city phone code is an empty string.
In the third sample the city phone code is string "770123456789". | ```python
n = int(input())
w = input()
for _ in range(n-1):
s = input()
for i in range(len(w)):
if s[i] != w[i]:
w = w[:i]
break
print(len(w))
``` | 3 | |
931 | A | Friends Meeting | PROGRAMMING | 800 | [
"brute force",
"greedy",
"implementation",
"math"
] | null | null | Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes according to the following rules: the first move increases the tiredness by 1, the second move increases the tiredness by 2, the third — by 3 and so on. For example, if a friend moves first to the left, then to the right (returning to the same point), and then again to the left his tiredness becomes equal to 1<=+<=2<=+<=3<==<=6.
The friends want to meet in a integer point. Determine the minimum total tiredness they should gain, if they meet in the same point. | The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1000) — the initial position of the first friend.
The second line contains a single integer *b* (1<=≤<=*b*<=≤<=1000) — the initial position of the second friend.
It is guaranteed that *a*<=≠<=*b*. | Print the minimum possible total tiredness if the friends meet in the same point. | [
"3\n4\n",
"101\n99\n",
"5\n10\n"
] | [
"1\n",
"2\n",
"9\n"
] | In the first example the first friend should move by one to the right (then the meeting happens at point 4), or the second friend should move by one to the left (then the meeting happens at point 3). In both cases, the total tiredness becomes 1.
In the second example the first friend should move by one to the left, and the second friend should move by one to the right. Then they meet in the point 100, and the total tiredness becomes 1 + 1 = 2.
In the third example one of the optimal ways is the following. The first friend should move three times to the right, and the second friend — two times to the left. Thus the friends meet in the point 8, and the total tiredness becomes 1 + 2 + 3 + 1 + 2 = 9. | 500 | [
{
"input": "3\n4",
"output": "1"
},
{
"input": "101\n99",
"output": "2"
},
{
"input": "5\n10",
"output": "9"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "1\n1000",
"output": "250000"
},
{
"input": "999\n1000",
"output": "1"
},
{
"inpu... | 1,563,079,452 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | a=int(input())
b=int(input())
dif=abs(a-b)
m1=dif//2
m2=dif-m1
print(m1*(m1+1)/2+m2*(m2+1)/2) | Title: Friends Meeting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes according to the following rules: the first move increases the tiredness by 1, the second move increases the tiredness by 2, the third — by 3 and so on. For example, if a friend moves first to the left, then to the right (returning to the same point), and then again to the left his tiredness becomes equal to 1<=+<=2<=+<=3<==<=6.
The friends want to meet in a integer point. Determine the minimum total tiredness they should gain, if they meet in the same point.
Input Specification:
The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1000) — the initial position of the first friend.
The second line contains a single integer *b* (1<=≤<=*b*<=≤<=1000) — the initial position of the second friend.
It is guaranteed that *a*<=≠<=*b*.
Output Specification:
Print the minimum possible total tiredness if the friends meet in the same point.
Demo Input:
['3\n4\n', '101\n99\n', '5\n10\n']
Demo Output:
['1\n', '2\n', '9\n']
Note:
In the first example the first friend should move by one to the right (then the meeting happens at point 4), or the second friend should move by one to the left (then the meeting happens at point 3). In both cases, the total tiredness becomes 1.
In the second example the first friend should move by one to the left, and the second friend should move by one to the right. Then they meet in the point 100, and the total tiredness becomes 1 + 1 = 2.
In the third example one of the optimal ways is the following. The first friend should move three times to the right, and the second friend — two times to the left. Thus the friends meet in the point 8, and the total tiredness becomes 1 + 2 + 3 + 1 + 2 = 9. | ```python
a=int(input())
b=int(input())
dif=abs(a-b)
m1=dif//2
m2=dif-m1
print(m1*(m1+1)/2+m2*(m2+1)/2)
``` | 0 | |
365 | A | Good Number | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number every time it occurs in array *a*). | The first line contains integers *n* and *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=9). The *i*-th of the following *n* lines contains integer *a**i* without leading zeroes (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the number of *k*-good numbers in *a*. | [
"10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n",
"2 1\n1\n10\n"
] | [
"10\n",
"1\n"
] | none | 500 | [
{
"input": "10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560",
"output": "10"
},
{
"input": "2 1\n1\n10",
"output": "1"
},
{
"input": "1 0\n1000000000",
"output": "1"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
... | 1,640,744,525 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | def solve():
n, k = [int(x) for x in input().split()]
number_set = set([i for i in range(0, k + 1)])
good_numbers = 0
for _ in range(n):
number = sorted(list(input()))
number = set([int(x) for x in number])
if number == number_set:
good_numbers += 1
return good_numbers
if __name__ == "__main__":
output = solve()
print(output)
| Title: Good Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number every time it occurs in array *a*).
Input Specification:
The first line contains integers *n* and *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=9). The *i*-th of the following *n* lines contains integer *a**i* without leading zeroes (1<=≤<=*a**i*<=≤<=109).
Output Specification:
Print a single integer — the number of *k*-good numbers in *a*.
Demo Input:
['10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n', '2 1\n1\n10\n']
Demo Output:
['10\n', '1\n']
Note:
none | ```python
def solve():
n, k = [int(x) for x in input().split()]
number_set = set([i for i in range(0, k + 1)])
good_numbers = 0
for _ in range(n):
number = sorted(list(input()))
number = set([int(x) for x in number])
if number == number_set:
good_numbers += 1
return good_numbers
if __name__ == "__main__":
output = solve()
print(output)
``` | 0 | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules of the game, Jury must use this second to touch the corresponding strip to make the square go away. As Jury is both smart and lazy, he counted that he wastes exactly *a**i* calories on touching the *i*-th strip.
You've got a string *s*, describing the process of the game and numbers *a*1,<=*a*2,<=*a*3,<=*a*4. Calculate how many calories Jury needs to destroy all the squares? | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it appears on the second strip, "3", if it appears on the third strip, "4", if it appears on the fourth strip. | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,679,582,662 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 0 | import sys
def task_solution():
aaa = [int(x) for x in input().split()]
strd = input()
return sum(strd.count(str(i+1))*aaa[i] for i in range(len(aaa)))
print(task_solution()) | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules of the game, Jury must use this second to touch the corresponding strip to make the square go away. As Jury is both smart and lazy, he counted that he wastes exactly *a**i* calories on touching the *i*-th strip.
You've got a string *s*, describing the process of the game and numbers *a*1,<=*a*2,<=*a*3,<=*a*4. Calculate how many calories Jury needs to destroy all the squares?
Input Specification:
The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it appears on the second strip, "3", if it appears on the third strip, "4", if it appears on the fourth strip.
Output Specification:
Print a single integer — the total number of calories that Jury wastes.
Demo Input:
['1 2 3 4\n123214\n', '1 5 3 2\n11221\n']
Demo Output:
['13\n', '13\n']
Note:
none | ```python
import sys
def task_solution():
aaa = [int(x) for x in input().split()]
strd = input()
return sum(strd.count(str(i+1))*aaa[i] for i in range(len(aaa)))
print(task_solution())
``` | 3 | |
915 | C | Permute Digits | PROGRAMMING | 1,700 | [
"dp",
"greedy"
] | null | null | You are given two positive integer numbers *a* and *b*. Permute (change order) of the digits of *a* to construct maximal number not exceeding *b*. No number in input and/or output can start with the digit 0.
It is allowed to leave *a* as it is. | The first line contains integer *a* (1<=≤<=*a*<=≤<=1018). The second line contains integer *b* (1<=≤<=*b*<=≤<=1018). Numbers don't have leading zeroes. It is guaranteed that answer exists. | Print the maximum possible number that is a permutation of digits of *a* and is not greater than *b*. The answer can't have any leading zeroes. It is guaranteed that the answer exists.
The number in the output should have exactly the same length as number *a*. It should be a permutation of digits of *a*. | [
"123\n222\n",
"3921\n10000\n",
"4940\n5000\n"
] | [
"213\n",
"9321\n",
"4940\n"
] | none | 0 | [
{
"input": "123\n222",
"output": "213"
},
{
"input": "3921\n10000",
"output": "9321"
},
{
"input": "4940\n5000",
"output": "4940"
},
{
"input": "23923472834\n23589234723",
"output": "23498743322"
},
{
"input": "102391019\n491010301",
"output": "399211100"
},... | 1,516,183,252 | 2,147,483,647 | Python 3 | OK | TESTS | 157 | 62 | 5,632,000 | import sys
def backtrack(sol, remaining, b, pos, free):
if len(sol) == len(b):
print(sol)
sys.exit(0)
for c in '9876543210':
if not free and c > b[pos]: continue
if not remaining[ord(c)-ord('0')]: continue
remaining[ord(c)-ord('0')] -= 1
backtrack(sol+c, remaining, b, pos+1, free or c < b[pos])
remaining[ord(c)-ord('0')] += 1
a = ''.join(sorted(input())[::-1])
b = input()
if len(a) < len(b):
print(a)
else:
x = [0] * 10
for c in a:
x[ord(c)-ord('0')] += 1
backtrack('', x, b, 0, False)
| Title: Permute Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two positive integer numbers *a* and *b*. Permute (change order) of the digits of *a* to construct maximal number not exceeding *b*. No number in input and/or output can start with the digit 0.
It is allowed to leave *a* as it is.
Input Specification:
The first line contains integer *a* (1<=≤<=*a*<=≤<=1018). The second line contains integer *b* (1<=≤<=*b*<=≤<=1018). Numbers don't have leading zeroes. It is guaranteed that answer exists.
Output Specification:
Print the maximum possible number that is a permutation of digits of *a* and is not greater than *b*. The answer can't have any leading zeroes. It is guaranteed that the answer exists.
The number in the output should have exactly the same length as number *a*. It should be a permutation of digits of *a*.
Demo Input:
['123\n222\n', '3921\n10000\n', '4940\n5000\n']
Demo Output:
['213\n', '9321\n', '4940\n']
Note:
none | ```python
import sys
def backtrack(sol, remaining, b, pos, free):
if len(sol) == len(b):
print(sol)
sys.exit(0)
for c in '9876543210':
if not free and c > b[pos]: continue
if not remaining[ord(c)-ord('0')]: continue
remaining[ord(c)-ord('0')] -= 1
backtrack(sol+c, remaining, b, pos+1, free or c < b[pos])
remaining[ord(c)-ord('0')] += 1
a = ''.join(sorted(input())[::-1])
b = input()
if len(a) < len(b):
print(a)
else:
x = [0] * 10
for c in a:
x[ord(c)-ord('0')] += 1
backtrack('', x, b, 0, False)
``` | 3 | |
766 | B | Mahmoud and a Triangle | PROGRAMMING | 1,000 | [
"constructive algorithms",
"geometry",
"greedy",
"math",
"number theory",
"sortings"
] | null | null | Mahmoud has *n* line segments, the *i*-th of them has length *a**i*. Ehab challenged him to use exactly 3 line segments to form a non-degenerate triangle. Mahmoud doesn't accept challenges unless he is sure he can win, so he asked you to tell him if he should accept the challenge. Given the lengths of the line segments, check if he can choose exactly 3 of them to form a non-degenerate triangle.
Mahmoud should use exactly 3 line segments, he can't concatenate two line segments or change any length. A non-degenerate triangle is a triangle with positive area. | The first line contains single integer *n* (3<=≤<=*n*<=≤<=105) — the number of line segments Mahmoud has.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the lengths of line segments Mahmoud has. | In the only line print "YES" if he can choose exactly three line segments and form a non-degenerate triangle with them, and "NO" otherwise. | [
"5\n1 5 3 2 4\n",
"3\n4 1 2\n"
] | [
"YES\n",
"NO\n"
] | For the first example, he can use line segments with lengths 2, 4 and 5 to form a non-degenerate triangle. | 1,000 | [
{
"input": "5\n1 5 3 2 4",
"output": "YES"
},
{
"input": "3\n4 1 2",
"output": "NO"
},
{
"input": "30\n197 75 517 39724 7906061 1153471 3 15166 168284 3019844 272293 316 16 24548 42 118 5792 5 9373 1866366 4886214 24 2206 712886 104005 1363 836 64273 440585 3576",
"output": "NO"
},... | 1,664,966,298 | 2,147,483,647 | Python 3 | OK | TESTS | 87 | 109 | 8,396,800 | n = int(input())
li = list(sorted(map(int, input().split())))
flag = False
for i in range(n - 2):
if li[i] + li[i + 1] > li[i + 2]: flag = True; break
print('YES' if flag else 'NO')
| Title: Mahmoud and a Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud has *n* line segments, the *i*-th of them has length *a**i*. Ehab challenged him to use exactly 3 line segments to form a non-degenerate triangle. Mahmoud doesn't accept challenges unless he is sure he can win, so he asked you to tell him if he should accept the challenge. Given the lengths of the line segments, check if he can choose exactly 3 of them to form a non-degenerate triangle.
Mahmoud should use exactly 3 line segments, he can't concatenate two line segments or change any length. A non-degenerate triangle is a triangle with positive area.
Input Specification:
The first line contains single integer *n* (3<=≤<=*n*<=≤<=105) — the number of line segments Mahmoud has.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the lengths of line segments Mahmoud has.
Output Specification:
In the only line print "YES" if he can choose exactly three line segments and form a non-degenerate triangle with them, and "NO" otherwise.
Demo Input:
['5\n1 5 3 2 4\n', '3\n4 1 2\n']
Demo Output:
['YES\n', 'NO\n']
Note:
For the first example, he can use line segments with lengths 2, 4 and 5 to form a non-degenerate triangle. | ```python
n = int(input())
li = list(sorted(map(int, input().split())))
flag = False
for i in range(n - 2):
if li[i] + li[i + 1] > li[i + 2]: flag = True; break
print('YES' if flag else 'NO')
``` | 3 | |
461 | A | Appleman and Toastman | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman gets a group consisting of a single number, he throws this group out. Each time Appleman gets a group consisting of more than one number, he splits the group into two non-empty groups (he can do it in any way) and gives each of them to Toastman.
After guys complete all the tasks they look at the score value. What is the maximum possible value of score they can get? | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and gives the group to Appleman (he will throw it out). When Toastman receives group [3, 5], he adds 8 to the score and gives the group to Appleman. Appleman splits [3, 5] in the only possible way: [5] and [3]. Then he gives both groups to Toastman. When Toastman receives [5], he adds 5 to the score and gives the group to Appleman (he will throws it out). When Toastman receives [3], he adds 3 to the score and gives the group to Appleman (he will throws it out). Finally Toastman have added 9 + 1 + 8 + 5 + 3 = 26 to the score. This is the optimal sequence of actions. | 500 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,645,518,425 | 2,147,483,647 | PyPy 3 | OK | TESTS | 36 | 358 | 23,756,800 | def main():
n = int(input())
arr = list(map(int, input().split()))
arr.sort()
s0 = sum(arr)
s1, s2 = 0, 0
for i in range(n):
s1 += s0 - s2
s2 += arr[i]
if i != n - 1:
s1 += arr[i]
print(s1)
if __name__ == "__main__":
main()
| Title: Appleman and Toastman
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman gets a group consisting of a single number, he throws this group out. Each time Appleman gets a group consisting of more than one number, he splits the group into two non-empty groups (he can do it in any way) and gives each of them to Toastman.
After guys complete all the tasks they look at the score value. What is the maximum possible value of score they can get?
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman.
Output Specification:
Print a single integer — the largest possible score.
Demo Input:
['3\n3 1 5\n', '1\n10\n']
Demo Output:
['26\n', '10\n']
Note:
Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and gives the group to Appleman (he will throw it out). When Toastman receives group [3, 5], he adds 8 to the score and gives the group to Appleman. Appleman splits [3, 5] in the only possible way: [5] and [3]. Then he gives both groups to Toastman. When Toastman receives [5], he adds 5 to the score and gives the group to Appleman (he will throws it out). When Toastman receives [3], he adds 3 to the score and gives the group to Appleman (he will throws it out). Finally Toastman have added 9 + 1 + 8 + 5 + 3 = 26 to the score. This is the optimal sequence of actions. | ```python
def main():
n = int(input())
arr = list(map(int, input().split()))
arr.sort()
s0 = sum(arr)
s1, s2 = 0, 0
for i in range(n):
s1 += s0 - s2
s2 += arr[i]
if i != n - 1:
s1 += arr[i]
print(s1)
if __name__ == "__main__":
main()
``` | 3 | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word *s* from Berlandish into Birlandish as *t*. Help him: find out if he translated the word correctly. | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,626,764,116 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 6,656,000 | while True:
x = input()
y = input()
n = 0
if len(x) == len(y):
for i in range(len(x)-1,-1,-1):
if x[i] == y[n]:
n += 1
else:
print("NO")
break
print("YES")
else:
print("NO")
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word *s* from Berlandish into Birlandish as *t*. Help him: find out if he translated the word correctly.
Input Specification:
The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
Output Specification:
If the word *t* is a word *s*, written reversely, print YES, otherwise print NO.
Demo Input:
['code\nedoc\n', 'abb\naba\n', 'code\ncode\n']
Demo Output:
['YES\n', 'NO\n', 'NO\n']
Note:
none | ```python
while True:
x = input()
y = input()
n = 0
if len(x) == len(y):
for i in range(len(x)-1,-1,-1):
if x[i] == y[n]:
n += 1
else:
print("NO")
break
print("YES")
else:
print("NO")
``` | -1 |
609 | A | USB Flash Drives | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives. | The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of USB flash drives.
The second line contains positive integer *m* (1<=≤<=*m*<=≤<=105) — the size of Sean's file.
Each of the next *n* lines contains positive integer *a**i* (1<=≤<=*a**i*<=≤<=1000) — the sizes of USB flash drives in megabytes.
It is guaranteed that the answer exists, i. e. the sum of all *a**i* is not less than *m*. | Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives. | [
"3\n5\n2\n1\n3\n",
"3\n6\n2\n3\n2\n",
"2\n5\n5\n10\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second. | 0 | [
{
"input": "3\n5\n2\n1\n3",
"output": "2"
},
{
"input": "3\n6\n2\n3\n2",
"output": "3"
},
{
"input": "2\n5\n5\n10",
"output": "1"
},
{
"input": "5\n16\n8\n1\n3\n4\n9",
"output": "2"
},
{
"input": "10\n121\n10\n37\n74\n56\n42\n39\n6\n68\n8\n100",
"output": "2"
... | 1,636,196,578 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 4,505,600 | def bubbleSort(arr):
for i in range(1, len(arr)):
for j in range(0, len(arr) - i):
if arr[j] < arr[j + 1]:
arr[j], arr[j + 1] = arr[j + 1], arr[j]
return arr
driveList = []
driveNumber = int(input())
fileSize = int(input())
result = 0
counter = 0
for i in range(driveNumber):
driveSize = int(input())
driveList.append(driveSize) # add drive size to the list
bubbleSort(driveList) # sort the drive list from large to small
print(driveList)
while result < fileSize:
result = result + int(driveList[counter])
counter = counter + 1
print(counter)
| Title: USB Flash Drives
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives.
Input Specification:
The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of USB flash drives.
The second line contains positive integer *m* (1<=≤<=*m*<=≤<=105) — the size of Sean's file.
Each of the next *n* lines contains positive integer *a**i* (1<=≤<=*a**i*<=≤<=1000) — the sizes of USB flash drives in megabytes.
It is guaranteed that the answer exists, i. e. the sum of all *a**i* is not less than *m*.
Output Specification:
Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives.
Demo Input:
['3\n5\n2\n1\n3\n', '3\n6\n2\n3\n2\n', '2\n5\n5\n10\n']
Demo Output:
['2\n', '3\n', '1\n']
Note:
In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second. | ```python
def bubbleSort(arr):
for i in range(1, len(arr)):
for j in range(0, len(arr) - i):
if arr[j] < arr[j + 1]:
arr[j], arr[j + 1] = arr[j + 1], arr[j]
return arr
driveList = []
driveNumber = int(input())
fileSize = int(input())
result = 0
counter = 0
for i in range(driveNumber):
driveSize = int(input())
driveList.append(driveSize) # add drive size to the list
bubbleSort(driveList) # sort the drive list from large to small
print(driveList)
while result < fileSize:
result = result + int(driveList[counter])
counter = counter + 1
print(counter)
``` | 0 | |
853 | D | Michael and Charging Stations | PROGRAMMING | 2,400 | [
"binary search",
"dp",
"greedy"
] | null | null | Michael has just bought a new electric car for moving across city. Michael does not like to overwork, so each day he drives to only one of two his jobs.
Michael's day starts from charging his electric car for getting to the work and back. He spends 1000 burles on charge if he goes to the first job, and 2000 burles if he goes to the second job.
On a charging station he uses there is a loyalty program that involves bonus cards. Bonus card may have some non-negative amount of bonus burles. Each time customer is going to buy something for the price of *x* burles, he is allowed to pay an amount of *y* (0<=≤<=*y*<=≤<=*x*) burles that does not exceed the bonus card balance with bonus burles. In this case he pays *x*<=-<=*y* burles with cash, and the balance on the bonus card is decreased by *y* bonus burles.
If customer pays whole price with cash (i.e., *y*<==<=0) then 10% of price is returned back to the bonus card. This means that bonus card balance increases by bonus burles. Initially the bonus card balance is equal to 0 bonus burles.
Michael has planned next *n* days and he knows how much does the charge cost on each of those days. Help Michael determine the minimum amount of burles in cash he has to spend with optimal use of bonus card. Assume that Michael is able to cover any part of the price with cash in any day. It is not necessary to spend all bonus burles at the end of the given period. | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=300<=000), the number of days Michael has planned.
Next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*a**i*<==<=1000 or *a**i*<==<=2000) with *a**i* denoting the charging cost at the day *i*. | Output the minimum amount of burles Michael has to spend. | [
"3\n1000 2000 1000\n",
"6\n2000 2000 2000 2000 2000 1000\n"
] | [
"3700\n",
"10000\n"
] | In the first sample case the most optimal way for Michael is to pay for the first two days spending 3000 burles and get 300 bonus burles as return. After that he is able to pay only 700 burles for the third days, covering the rest of the price with bonus burles.
In the second sample case the most optimal way for Michael is to pay the whole price for the first five days, getting 1000 bonus burles as return and being able to use them on the last day without paying anything in cash. | 1,750 | [] | 1,515,085,882 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 202 | 25,190,400 | n = int(input())
pr = list(map(int, input().split()))
sum1 = 0
for i in range(0, (len(pr)-1)):
sum1 += pr[i]
a1 = pr[-1] - (0.1*sum1)
if a1==0:
print(sum1)
else:
a1 = sum1 + a1
print(str(int(a1))) | Title: Michael and Charging Stations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Michael has just bought a new electric car for moving across city. Michael does not like to overwork, so each day he drives to only one of two his jobs.
Michael's day starts from charging his electric car for getting to the work and back. He spends 1000 burles on charge if he goes to the first job, and 2000 burles if he goes to the second job.
On a charging station he uses there is a loyalty program that involves bonus cards. Bonus card may have some non-negative amount of bonus burles. Each time customer is going to buy something for the price of *x* burles, he is allowed to pay an amount of *y* (0<=≤<=*y*<=≤<=*x*) burles that does not exceed the bonus card balance with bonus burles. In this case he pays *x*<=-<=*y* burles with cash, and the balance on the bonus card is decreased by *y* bonus burles.
If customer pays whole price with cash (i.e., *y*<==<=0) then 10% of price is returned back to the bonus card. This means that bonus card balance increases by bonus burles. Initially the bonus card balance is equal to 0 bonus burles.
Michael has planned next *n* days and he knows how much does the charge cost on each of those days. Help Michael determine the minimum amount of burles in cash he has to spend with optimal use of bonus card. Assume that Michael is able to cover any part of the price with cash in any day. It is not necessary to spend all bonus burles at the end of the given period.
Input Specification:
The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=300<=000), the number of days Michael has planned.
Next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*a**i*<==<=1000 or *a**i*<==<=2000) with *a**i* denoting the charging cost at the day *i*.
Output Specification:
Output the minimum amount of burles Michael has to spend.
Demo Input:
['3\n1000 2000 1000\n', '6\n2000 2000 2000 2000 2000 1000\n']
Demo Output:
['3700\n', '10000\n']
Note:
In the first sample case the most optimal way for Michael is to pay for the first two days spending 3000 burles and get 300 bonus burles as return. After that he is able to pay only 700 burles for the third days, covering the rest of the price with bonus burles.
In the second sample case the most optimal way for Michael is to pay the whole price for the first five days, getting 1000 bonus burles as return and being able to use them on the last day without paying anything in cash. | ```python
n = int(input())
pr = list(map(int, input().split()))
sum1 = 0
for i in range(0, (len(pr)-1)):
sum1 += pr[i]
a1 = pr[-1] - (0.1*sum1)
if a1==0:
print(sum1)
else:
a1 = sum1 + a1
print(str(int(a1)))
``` | 0 | |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning and throws them away before going to bed as he doesn't want to wash them.
Vasya wonders, what is the maximum number of days when he can dress fashionable and wear different socks, and after that, for how many days he can then wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Can you help him? | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he's been wearing on that day. | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,684,533,278 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 46 | 0 | r,b=map(int,input().split())
hp=min(r,b)
dail=max(r,b)-hp
print(hp,(dail//2))
| Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning and throws them away before going to bed as he doesn't want to wash them.
Vasya wonders, what is the maximum number of days when he can dress fashionable and wear different socks, and after that, for how many days he can then wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Can you help him?
Input Specification:
The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got.
Output Specification:
Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he's been wearing on that day.
Demo Input:
['3 1\n', '2 3\n', '7 3\n']
Demo Output:
['1 1\n', '2 0\n', '3 2\n']
Note:
In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | ```python
r,b=map(int,input().split())
hp=min(r,b)
dail=max(r,b)-hp
print(hp,(dail//2))
``` | 3 | |
474 | B | Worms | PROGRAMMING | 1,200 | [
"binary search",
"implementation"
] | null | null | It is lunch time for Mole. His friend, Marmot, prepared him a nice game for lunch.
Marmot brought Mole *n* ordered piles of worms such that *i*-th pile contains *a**i* worms. He labeled all these worms with consecutive integers: worms in first pile are labeled with numbers 1 to *a*1, worms in second pile are labeled with numbers *a*1<=+<=1 to *a*1<=+<=*a*2 and so on. See the example for a better understanding.
Mole can't eat all the worms (Marmot brought a lot) and, as we all know, Mole is blind, so Marmot tells him the labels of the best juicy worms. Marmot will only give Mole a worm if Mole says correctly in which pile this worm is contained.
Poor Mole asks for your help. For all juicy worms said by Marmot, tell Mole the correct answers. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), the number of piles.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103, *a*1<=+<=*a*2<=+<=...<=+<=*a**n*<=≤<=106), where *a**i* is the number of worms in the *i*-th pile.
The third line contains single integer *m* (1<=≤<=*m*<=≤<=105), the number of juicy worms said by Marmot.
The fourth line contains *m* integers *q*1,<=*q*2,<=...,<=*q**m* (1<=≤<=*q**i*<=≤<=*a*1<=+<=*a*2<=+<=...<=+<=*a**n*), the labels of the juicy worms. | Print *m* lines to the standard output. The *i*-th line should contain an integer, representing the number of the pile where the worm labeled with the number *q**i* is. | [
"5\n2 7 3 4 9\n3\n1 25 11\n"
] | [
"1\n5\n3\n"
] | For the sample input:
- The worms with labels from [1, 2] are in the first pile. - The worms with labels from [3, 9] are in the second pile. - The worms with labels from [10, 12] are in the third pile. - The worms with labels from [13, 16] are in the fourth pile. - The worms with labels from [17, 25] are in the fifth pile. | 1,000 | [
{
"input": "5\n2 7 3 4 9\n3\n1 25 11",
"output": "1\n5\n3"
}
] | 1,697,601,865 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 11 | 1,000 | 15,052,800 | n = int(input())
arr = [int(i) for i in input().split()]
m = int(input())
query = [int(i) for i in input().split()]
mat = [[1,arr[0]]]
for i in range(1,len(arr)):
tmp = mat[i-1]
mat.append([tmp[1]+1, tmp[1]+arr[i]])
for i in range(0,len(query)):
for j in range(0,len(mat)):
if query[i] >= mat[j][0] and query[i] <= mat[j][1]:
print(j+1)
break
| Title: Worms
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is lunch time for Mole. His friend, Marmot, prepared him a nice game for lunch.
Marmot brought Mole *n* ordered piles of worms such that *i*-th pile contains *a**i* worms. He labeled all these worms with consecutive integers: worms in first pile are labeled with numbers 1 to *a*1, worms in second pile are labeled with numbers *a*1<=+<=1 to *a*1<=+<=*a*2 and so on. See the example for a better understanding.
Mole can't eat all the worms (Marmot brought a lot) and, as we all know, Mole is blind, so Marmot tells him the labels of the best juicy worms. Marmot will only give Mole a worm if Mole says correctly in which pile this worm is contained.
Poor Mole asks for your help. For all juicy worms said by Marmot, tell Mole the correct answers.
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), the number of piles.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103, *a*1<=+<=*a*2<=+<=...<=+<=*a**n*<=≤<=106), where *a**i* is the number of worms in the *i*-th pile.
The third line contains single integer *m* (1<=≤<=*m*<=≤<=105), the number of juicy worms said by Marmot.
The fourth line contains *m* integers *q*1,<=*q*2,<=...,<=*q**m* (1<=≤<=*q**i*<=≤<=*a*1<=+<=*a*2<=+<=...<=+<=*a**n*), the labels of the juicy worms.
Output Specification:
Print *m* lines to the standard output. The *i*-th line should contain an integer, representing the number of the pile where the worm labeled with the number *q**i* is.
Demo Input:
['5\n2 7 3 4 9\n3\n1 25 11\n']
Demo Output:
['1\n5\n3\n']
Note:
For the sample input:
- The worms with labels from [1, 2] are in the first pile. - The worms with labels from [3, 9] are in the second pile. - The worms with labels from [10, 12] are in the third pile. - The worms with labels from [13, 16] are in the fourth pile. - The worms with labels from [17, 25] are in the fifth pile. | ```python
n = int(input())
arr = [int(i) for i in input().split()]
m = int(input())
query = [int(i) for i in input().split()]
mat = [[1,arr[0]]]
for i in range(1,len(arr)):
tmp = mat[i-1]
mat.append([tmp[1]+1, tmp[1]+arr[i]])
for i in range(0,len(query)):
for j in range(0,len(mat)):
if query[i] >= mat[j][0] and query[i] <= mat[j][1]:
print(j+1)
break
``` | 0 | |
28 | A | Bender Problem | PROGRAMMING | 1,600 | [
"implementation"
] | A. Bender Problem | 2 | 256 | Robot Bender decided to make Fray a birthday present. He drove *n* nails and numbered them from 1 to *n* in some order. Bender decided to make a picture using metal rods. The picture is a closed polyline, which vertices should be nails (in the given order). The segments of the polyline should be parallel to the coordinate axes. Polyline is allowed to have self-intersections. Bender can take a rod and fold it exactly once in any place to form an angle of 90 degrees. Then he can attach the place of the fold to some unoccupied nail and attach two ends of this rod to adjacent nails. A nail is considered unoccupied if there is no rod attached to it (neither by it's end nor the by the fold place). No rod could be used twice. It is not required to use all the rods.
Help Bender to solve this difficult task. | The first line contains two positive integers *n* and *m* (4<=≤<=*n*<=≤<=500,<=2<=≤<=*m*<=≤<=500, *n* is even) — the amount of nails and the amount of rods. *i*-th of the following *n* lines contains a pair of integers, denoting the coordinates of the *i*-th nail. Nails should be connected in the same order as they are given in the input. The last line contains *m* integers — the lenghts of the rods. All coordinates do not exceed 104 by absolute value. Lengths of the rods are between 1 and 200<=000. No rod can be used twice. It is guaranteed that all segments of the given polyline are parallel to coordinate axes. No three consecutive nails lie on the same line. | If it is impossible to solve Bender's problem, output NO. Otherwise, output YES in the first line, and in the second line output *n* numbers — *i*-th of them should be the number of rod, which fold place is attached to the *i*-th nail, or -1, if there is no such rod.
If there are multiple solutions, print any of them. | [
"4 2\n0 0\n0 2\n2 2\n2 0\n4 4\n",
"6 3\n0 0\n1 0\n1 1\n2 1\n2 2\n0 2\n3 2 3\n",
"6 3\n0 0\n1 0\n1 1\n2 1\n2 2\n0 2\n2 2 3\n"
] | [
"YES\n1 -1 2 -1 \n",
"YES\n1 -1 2 -1 3 -1 \n",
"NO\n"
] | none | 500 | [
{
"input": "4 2\n0 0\n0 2\n2 2\n2 0\n4 4",
"output": "YES\n1 -1 2 -1 "
},
{
"input": "6 3\n0 0\n1 0\n1 1\n2 1\n2 2\n0 2\n3 2 3",
"output": "YES\n1 -1 2 -1 3 -1 "
},
{
"input": "6 3\n0 0\n1 0\n1 1\n2 1\n2 2\n0 2\n2 2 3",
"output": "NO"
},
{
"input": "4 4\n0 0\n0 1\n1 1\n1 0\n1... | 1,688,726,017 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 92 | 204,800 | def main():
n, m = map(int, input().split())
nails = []
for _ in range(n):
nails.append(tuple(map(int, input().split())))
rods = list(map(int, input().split()))
rods_count1, rods_count2 = {}, {}
for i, rod in enumerate(rods):
if rod not in rods_count1:
rods_count1[rod] = [i]
else:
rods_count1[rod].append(i)
if rod not in rods_count2:
rods_count2[rod] = [i]
else:
rods_count2[rod].append(i)
ans = []
for i in range(0, n, 2):
if i < n - 2:
rod_len = abs(nails[i][0] - nails[i + 2][0]) + abs(nails[i][1] - nails[i + 2][1])
else:
rod_len = abs(nails[i][0] - nails[0][0]) + abs(nails[i][1] - nails[0][1])
if rod_len not in rods_count1:
break
else:
ans.append(-1)
ans.append(rods_count1[rod_len].pop() + 1)
if not rods_count1[rod_len]:
del rods_count1[rod_len]
else:
print("YES")
print(' '.join(map(str, ans)))
return
last_nail = nails.pop()
nails.insert(0, last_nail)
ans = []
for i in range(0, n, 2):
if i < n - 2:
rod_len = abs(nails[i][0] - nails[i + 2][0]) + abs(nails[i][1] - nails[i + 2][1])
else:
rod_len = abs(nails[i][0] - nails[0][0]) + abs(nails[i][1] - nails[0][1])
if rod_len not in rods_count2:
break
else:
ans.append(rods_count2[rod_len].pop() + 1)
ans.append(-1)
if not rods_count2[rod_len]:
del rods_count2[rod_len]
else:
print("YES")
print(' '.join(map(str, ans)))
return
print("NO")
if __name__ == "__main__":
main()
| Title: Bender Problem
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Robot Bender decided to make Fray a birthday present. He drove *n* nails and numbered them from 1 to *n* in some order. Bender decided to make a picture using metal rods. The picture is a closed polyline, which vertices should be nails (in the given order). The segments of the polyline should be parallel to the coordinate axes. Polyline is allowed to have self-intersections. Bender can take a rod and fold it exactly once in any place to form an angle of 90 degrees. Then he can attach the place of the fold to some unoccupied nail and attach two ends of this rod to adjacent nails. A nail is considered unoccupied if there is no rod attached to it (neither by it's end nor the by the fold place). No rod could be used twice. It is not required to use all the rods.
Help Bender to solve this difficult task.
Input Specification:
The first line contains two positive integers *n* and *m* (4<=≤<=*n*<=≤<=500,<=2<=≤<=*m*<=≤<=500, *n* is even) — the amount of nails and the amount of rods. *i*-th of the following *n* lines contains a pair of integers, denoting the coordinates of the *i*-th nail. Nails should be connected in the same order as they are given in the input. The last line contains *m* integers — the lenghts of the rods. All coordinates do not exceed 104 by absolute value. Lengths of the rods are between 1 and 200<=000. No rod can be used twice. It is guaranteed that all segments of the given polyline are parallel to coordinate axes. No three consecutive nails lie on the same line.
Output Specification:
If it is impossible to solve Bender's problem, output NO. Otherwise, output YES in the first line, and in the second line output *n* numbers — *i*-th of them should be the number of rod, which fold place is attached to the *i*-th nail, or -1, if there is no such rod.
If there are multiple solutions, print any of them.
Demo Input:
['4 2\n0 0\n0 2\n2 2\n2 0\n4 4\n', '6 3\n0 0\n1 0\n1 1\n2 1\n2 2\n0 2\n3 2 3\n', '6 3\n0 0\n1 0\n1 1\n2 1\n2 2\n0 2\n2 2 3\n']
Demo Output:
['YES\n1 -1 2 -1 \n', 'YES\n1 -1 2 -1 3 -1 \n', 'NO\n']
Note:
none | ```python
def main():
n, m = map(int, input().split())
nails = []
for _ in range(n):
nails.append(tuple(map(int, input().split())))
rods = list(map(int, input().split()))
rods_count1, rods_count2 = {}, {}
for i, rod in enumerate(rods):
if rod not in rods_count1:
rods_count1[rod] = [i]
else:
rods_count1[rod].append(i)
if rod not in rods_count2:
rods_count2[rod] = [i]
else:
rods_count2[rod].append(i)
ans = []
for i in range(0, n, 2):
if i < n - 2:
rod_len = abs(nails[i][0] - nails[i + 2][0]) + abs(nails[i][1] - nails[i + 2][1])
else:
rod_len = abs(nails[i][0] - nails[0][0]) + abs(nails[i][1] - nails[0][1])
if rod_len not in rods_count1:
break
else:
ans.append(-1)
ans.append(rods_count1[rod_len].pop() + 1)
if not rods_count1[rod_len]:
del rods_count1[rod_len]
else:
print("YES")
print(' '.join(map(str, ans)))
return
last_nail = nails.pop()
nails.insert(0, last_nail)
ans = []
for i in range(0, n, 2):
if i < n - 2:
rod_len = abs(nails[i][0] - nails[i + 2][0]) + abs(nails[i][1] - nails[i + 2][1])
else:
rod_len = abs(nails[i][0] - nails[0][0]) + abs(nails[i][1] - nails[0][1])
if rod_len not in rods_count2:
break
else:
ans.append(rods_count2[rod_len].pop() + 1)
ans.append(-1)
if not rods_count2[rod_len]:
del rods_count2[rod_len]
else:
print("YES")
print(' '.join(map(str, ans)))
return
print("NO")
if __name__ == "__main__":
main()
``` | 3.976619 |
208 | A | Dubstep | PROGRAMMING | 900 | [
"strings"
] | null | null | Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song. | The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word. | Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space. | [
"WUBWUBABCWUB\n",
"WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n"
] | [
"ABC ",
"WE ARE THE CHAMPIONS MY FRIEND "
] | In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" — between them Vasya added two "WUB". | 500 | [
{
"input": "WUBWUBABCWUB",
"output": "ABC "
},
{
"input": "WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB",
"output": "WE ARE THE CHAMPIONS MY FRIEND "
},
{
"input": "WUBWUBWUBSR",
"output": "SR "
},
{
"input": "RWUBWUBWUBLWUB",
"output": "R L "
},
{
"input": "... | 1,698,675,222 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | s=input()
def rs(s):
return ' '.join(s.replace('WUB', ' ').split())
print(rs(s)) | Title: Dubstep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input Specification:
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output Specification:
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Demo Input:
['WUBWUBABCWUB\n', 'WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n']
Demo Output:
['ABC ', 'WE ARE THE CHAMPIONS MY FRIEND ']
Note:
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" — between them Vasya added two "WUB". | ```python
s=input()
def rs(s):
return ' '.join(s.replace('WUB', ' ').split())
print(rs(s))
``` | 3 | |
413 | C | Jeopardy! | PROGRAMMING | 1,400 | [
"greedy",
"math"
] | null | null | 'Jeopardy!' is an intellectual game where players answer questions and earn points. Company Q conducts a simplified 'Jeopardy!' tournament among the best IT companies. By a lucky coincidence, the old rivals made it to the finals: company R1 and company R2.
The finals will have *n* questions, *m* of them are auction questions and *n*<=-<=*m* of them are regular questions. Each question has a price. The price of the *i*-th question is *a**i* points. During the game the players chose the questions. At that, if the question is an auction, then the player who chose it can change the price if the number of his current points is strictly larger than the price of the question. The new price of the question cannot be less than the original price and cannot be greater than the current number of points of the player who chose the question. The correct answer brings the player the points equal to the price of the question. The wrong answer to the question reduces the number of the player's points by the value of the question price.
The game will go as follows. First, the R2 company selects a question, then the questions are chosen by the one who answered the previous question correctly. If no one answered the question, then the person who chose last chooses again.
All R2 employees support their team. They want to calculate what maximum possible number of points the R2 team can get if luck is on their side during the whole game (they will always be the first to correctly answer questions). Perhaps you are not going to be surprised, but this problem was again entrusted for you to solve. | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100; *m*<=≤<=*min*(*n*,<=30)) — the total number of questions and the number of auction questions, correspondingly. The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=107) — the prices of the questions. The third line contains *m* distinct integers *b**i* (1<=≤<=*b**i*<=≤<=*n*) — the numbers of auction questions. Assume that the questions are numbered from 1 to *n*. | In the single line, print the answer to the problem — the maximum points the R2 company can get if it plays optimally well. It is guaranteed that the answer fits into the integer 64-bit signed type. | [
"4 1\n1 3 7 5\n3\n",
"3 2\n10 3 8\n2 3\n",
"2 2\n100 200\n1 2\n"
] | [
"18\n",
"40\n",
"400\n"
] | none | 1,500 | [
{
"input": "4 1\n1 3 7 5\n3",
"output": "18"
},
{
"input": "3 2\n10 3 8\n2 3",
"output": "40"
},
{
"input": "2 2\n100 200\n1 2",
"output": "400"
},
{
"input": "1 1\n1\n1",
"output": "1"
},
{
"input": "2 2\n1 5\n1 2",
"output": "10"
},
{
"input": "5 3\n... | 1,606,027,952 | 2,147,483,647 | PyPy 3 | OK | TESTS | 67 | 155 | 0 | n, m = map(int, input().split())
l = list(map(int, input().split()))
mm = list(map(int, input().split()))
s = 0
a = []
for i in range(0, n):
if (i+1) not in mm:
s+=l[i]
for i in range(0, m):
v = l[mm[i]-1]
a.append(v)
a.sort(reverse = True)
for i in a:
if s >= i:
s+=s
else:
s+=i
print(s)
| Title: Jeopardy!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
'Jeopardy!' is an intellectual game where players answer questions and earn points. Company Q conducts a simplified 'Jeopardy!' tournament among the best IT companies. By a lucky coincidence, the old rivals made it to the finals: company R1 and company R2.
The finals will have *n* questions, *m* of them are auction questions and *n*<=-<=*m* of them are regular questions. Each question has a price. The price of the *i*-th question is *a**i* points. During the game the players chose the questions. At that, if the question is an auction, then the player who chose it can change the price if the number of his current points is strictly larger than the price of the question. The new price of the question cannot be less than the original price and cannot be greater than the current number of points of the player who chose the question. The correct answer brings the player the points equal to the price of the question. The wrong answer to the question reduces the number of the player's points by the value of the question price.
The game will go as follows. First, the R2 company selects a question, then the questions are chosen by the one who answered the previous question correctly. If no one answered the question, then the person who chose last chooses again.
All R2 employees support their team. They want to calculate what maximum possible number of points the R2 team can get if luck is on their side during the whole game (they will always be the first to correctly answer questions). Perhaps you are not going to be surprised, but this problem was again entrusted for you to solve.
Input Specification:
The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100; *m*<=≤<=*min*(*n*,<=30)) — the total number of questions and the number of auction questions, correspondingly. The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=107) — the prices of the questions. The third line contains *m* distinct integers *b**i* (1<=≤<=*b**i*<=≤<=*n*) — the numbers of auction questions. Assume that the questions are numbered from 1 to *n*.
Output Specification:
In the single line, print the answer to the problem — the maximum points the R2 company can get if it plays optimally well. It is guaranteed that the answer fits into the integer 64-bit signed type.
Demo Input:
['4 1\n1 3 7 5\n3\n', '3 2\n10 3 8\n2 3\n', '2 2\n100 200\n1 2\n']
Demo Output:
['18\n', '40\n', '400\n']
Note:
none | ```python
n, m = map(int, input().split())
l = list(map(int, input().split()))
mm = list(map(int, input().split()))
s = 0
a = []
for i in range(0, n):
if (i+1) not in mm:
s+=l[i]
for i in range(0, m):
v = l[mm[i]-1]
a.append(v)
a.sort(reverse = True)
for i in a:
if s >= i:
s+=s
else:
s+=i
print(s)
``` | 3 | |
818 | D | Multicolored Cars | PROGRAMMING | 1,700 | [
"data structures",
"implementation"
] | null | null | Alice and Bob got very bored during a long car trip so they decided to play a game. From the window they can see cars of different colors running past them. Cars are going one after another.
The game rules are like this. Firstly Alice chooses some color *A*, then Bob chooses some color *B* (*A*<=≠<=*B*). After each car they update the number of cars of their chosen color that have run past them. Let's define this numbers after *i*-th car *cnt**A*(*i*) and *cnt**B*(*i*).
- If *cnt**A*(*i*)<=><=*cnt**B*(*i*) for every *i* then the winner is Alice. - If *cnt**B*(*i*)<=≥<=*cnt**A*(*i*) for every *i* then the winner is Bob. - Otherwise it's a draw.
Bob knows all the colors of cars that they will encounter and order of their appearance. Alice have already chosen her color *A* and Bob now wants to choose such color *B* that he will win the game (draw is not a win). Help him find this color.
If there are multiple solutions, print any of them. If there is no such color then print -1. | The first line contains two integer numbers *n* and *A* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*A*<=≤<=106) – number of cars and the color chosen by Alice.
The second line contains *n* integer numbers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=106) — colors of the cars that Alice and Bob will encounter in the order of their appearance. | Output such color *B* (1<=≤<=*B*<=≤<=106) that if Bob chooses it then he will win the game. If there are multiple solutions, print any of them. If there is no such color then print -1.
It is guaranteed that if there exists any solution then there exists solution with (1<=≤<=*B*<=≤<=106). | [
"4 1\n2 1 4 2\n",
"5 2\n2 2 4 5 3\n",
"3 10\n1 2 3\n"
] | [
"2\n",
"-1\n",
"4\n"
] | Let's consider availability of colors in the first example:
- *cnt*<sub class="lower-index">2</sub>(*i*) ≥ *cnt*<sub class="lower-index">1</sub>(*i*) for every *i*, and color 2 can be the answer. - *cnt*<sub class="lower-index">4</sub>(2) < *cnt*<sub class="lower-index">1</sub>(2), so color 4 isn't the winning one for Bob. - All the other colors also have *cnt*<sub class="lower-index">*j*</sub>(2) < *cnt*<sub class="lower-index">1</sub>(2), thus they are not available.
In the third example every color is acceptable except for 10. | 0 | [
{
"input": "4 1\n2 1 4 2",
"output": "2"
},
{
"input": "5 2\n2 2 4 5 3",
"output": "-1"
},
{
"input": "3 10\n1 2 3",
"output": "4"
},
{
"input": "1 1\n2",
"output": "3"
},
{
"input": "1 2\n2",
"output": "-1"
},
{
"input": "10 6\n8 5 1 6 6 5 10 6 9 8",
... | 1,580,722,974 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 85 | 2,000 | 13,619,200 | e = int(input().split(' ')[1])
l = [int(i) for i in input().split(' ')]
b = True
a=list()
cnt=[0 for i in range(1000005)]
for i in range (len(l)):
cnt[l[i]]+=1
if l[i] == e:
b = False;
c=list()
for j in range(len(a)):
if cnt[a[j]]<cnt[e]:
c.append(a[j])
for j in range(len(c)):
a.remove(c[j])
if b == True:
a.append(l[i])
if len(a)==0 :
print("-1")
else:
print(a[0])
| Title: Multicolored Cars
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice and Bob got very bored during a long car trip so they decided to play a game. From the window they can see cars of different colors running past them. Cars are going one after another.
The game rules are like this. Firstly Alice chooses some color *A*, then Bob chooses some color *B* (*A*<=≠<=*B*). After each car they update the number of cars of their chosen color that have run past them. Let's define this numbers after *i*-th car *cnt**A*(*i*) and *cnt**B*(*i*).
- If *cnt**A*(*i*)<=><=*cnt**B*(*i*) for every *i* then the winner is Alice. - If *cnt**B*(*i*)<=≥<=*cnt**A*(*i*) for every *i* then the winner is Bob. - Otherwise it's a draw.
Bob knows all the colors of cars that they will encounter and order of their appearance. Alice have already chosen her color *A* and Bob now wants to choose such color *B* that he will win the game (draw is not a win). Help him find this color.
If there are multiple solutions, print any of them. If there is no such color then print -1.
Input Specification:
The first line contains two integer numbers *n* and *A* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*A*<=≤<=106) – number of cars and the color chosen by Alice.
The second line contains *n* integer numbers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=106) — colors of the cars that Alice and Bob will encounter in the order of their appearance.
Output Specification:
Output such color *B* (1<=≤<=*B*<=≤<=106) that if Bob chooses it then he will win the game. If there are multiple solutions, print any of them. If there is no such color then print -1.
It is guaranteed that if there exists any solution then there exists solution with (1<=≤<=*B*<=≤<=106).
Demo Input:
['4 1\n2 1 4 2\n', '5 2\n2 2 4 5 3\n', '3 10\n1 2 3\n']
Demo Output:
['2\n', '-1\n', '4\n']
Note:
Let's consider availability of colors in the first example:
- *cnt*<sub class="lower-index">2</sub>(*i*) ≥ *cnt*<sub class="lower-index">1</sub>(*i*) for every *i*, and color 2 can be the answer. - *cnt*<sub class="lower-index">4</sub>(2) < *cnt*<sub class="lower-index">1</sub>(2), so color 4 isn't the winning one for Bob. - All the other colors also have *cnt*<sub class="lower-index">*j*</sub>(2) < *cnt*<sub class="lower-index">1</sub>(2), thus they are not available.
In the third example every color is acceptable except for 10. | ```python
e = int(input().split(' ')[1])
l = [int(i) for i in input().split(' ')]
b = True
a=list()
cnt=[0 for i in range(1000005)]
for i in range (len(l)):
cnt[l[i]]+=1
if l[i] == e:
b = False;
c=list()
for j in range(len(a)):
if cnt[a[j]]<cnt[e]:
c.append(a[j])
for j in range(len(c)):
a.remove(c[j])
if b == True:
a.append(l[i])
if len(a)==0 :
print("-1")
else:
print(a[0])
``` | 0 | |
20 | C | Dijkstra? | PROGRAMMING | 1,900 | [
"graphs",
"shortest paths"
] | C. Dijkstra? | 1 | 64 | You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*. | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105), where *n* is the number of vertices and *m* is the number of edges. Following *m* lines contain one edge each in form *a**i*, *b**i* and *w**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=1<=≤<=*w**i*<=≤<=106), where *a**i*,<=*b**i* are edge endpoints and *w**i* is the length of the edge.
It is possible that the graph has loops and multiple edges between pair of vertices. | Write the only integer -1 in case of no path. Write the shortest path in opposite case. If there are many solutions, print any of them. | [
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n",
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n"
] | [
"1 4 3 5 ",
"1 4 3 5 "
] | none | 1,500 | [
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "2 1\n1 2 1",
"output": "1 2 "
},
{
"input": "3 1\n1 2 1",
"output": "-1"
},
{
"input... | 1,650,305,234 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 27 | 1,000 | 21,401,600 | # Nyveon (Eric K)
# T3 CC4005
# Problem A - Dijkstra?
from collections import defaultdict
from queue import PriorityQueue
class Graph:
def __init__(self, vertex_count: int) -> None:
self.vertex_count = vertex_count
self.edges = defaultdict(list)
def add_edge(self, u: int, v: int, w: float) -> None:
""" Adds an edge from u to v with weight w. """
self.edges[u].append((v, w))
self.edges[v].append((u, w))
def dijkstra(self, source: int) -> list:
""" Returns a list of distances from source to all other vertices. """
pq = PriorityQueue()
pq.put((0, source))
visited = set()
distances = {v: float('inf') for v in range(1, self.vertex_count + 1)}
distances[source] = 0
while not pq.empty():
current_distance, current_vertex = pq.get()
if current_vertex in visited:
continue
visited.add(current_vertex)
for neighbor, weight in self.edges[current_vertex]:
if current_distance + weight < distances[neighbor]:
distances[neighbor] = current_distance + weight
pq.put((distances[neighbor], neighbor))
return distances
def shortest_path(self, source: int, destination: int) -> list:
""" Returns a list of vertices from source to destination. """
distances = self.dijkstra(source)
if distances[destination] == float('inf'):
return [-1]
path = []
u = destination
while u != source:
path.append(u)
for neighbor, weight in self.edges[u]:
if distances[neighbor] == distances[u] - weight:
u = neighbor
break
path.append(source)
path.reverse()
return path
# Input
n, m = [int(x) for x in input().split()]
graph = Graph(n)
for i in range(m):
a, b, w = [int(x) for x in input().split()]
graph.add_edge(a, b, w)
# Processing
path = graph.shortest_path(1, n)
print(' '.join(map(str, path)))
| Title: Dijkstra?
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*.
Input Specification:
The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105), where *n* is the number of vertices and *m* is the number of edges. Following *m* lines contain one edge each in form *a**i*, *b**i* and *w**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=1<=≤<=*w**i*<=≤<=106), where *a**i*,<=*b**i* are edge endpoints and *w**i* is the length of the edge.
It is possible that the graph has loops and multiple edges between pair of vertices.
Output Specification:
Write the only integer -1 in case of no path. Write the shortest path in opposite case. If there are many solutions, print any of them.
Demo Input:
['5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n', '5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n']
Demo Output:
['1 4 3 5 ', '1 4 3 5 ']
Note:
none | ```python
# Nyveon (Eric K)
# T3 CC4005
# Problem A - Dijkstra?
from collections import defaultdict
from queue import PriorityQueue
class Graph:
def __init__(self, vertex_count: int) -> None:
self.vertex_count = vertex_count
self.edges = defaultdict(list)
def add_edge(self, u: int, v: int, w: float) -> None:
""" Adds an edge from u to v with weight w. """
self.edges[u].append((v, w))
self.edges[v].append((u, w))
def dijkstra(self, source: int) -> list:
""" Returns a list of distances from source to all other vertices. """
pq = PriorityQueue()
pq.put((0, source))
visited = set()
distances = {v: float('inf') for v in range(1, self.vertex_count + 1)}
distances[source] = 0
while not pq.empty():
current_distance, current_vertex = pq.get()
if current_vertex in visited:
continue
visited.add(current_vertex)
for neighbor, weight in self.edges[current_vertex]:
if current_distance + weight < distances[neighbor]:
distances[neighbor] = current_distance + weight
pq.put((distances[neighbor], neighbor))
return distances
def shortest_path(self, source: int, destination: int) -> list:
""" Returns a list of vertices from source to destination. """
distances = self.dijkstra(source)
if distances[destination] == float('inf'):
return [-1]
path = []
u = destination
while u != source:
path.append(u)
for neighbor, weight in self.edges[u]:
if distances[neighbor] == distances[u] - weight:
u = neighbor
break
path.append(source)
path.reverse()
return path
# Input
n, m = [int(x) for x in input().split()]
graph = Graph(n)
for i in range(m):
a, b, w = [int(x) for x in input().split()]
graph.add_edge(a, b, w)
# Processing
path = graph.shortest_path(1, n)
print(' '.join(map(str, path)))
``` | 0 |
177 | A1 | Good Matrix Elements | PROGRAMMING | 800 | [
"implementation"
] | null | null | The Smart Beaver from ABBYY got hooked on square matrices. Now he is busy studying an *n*<=×<=*n* size matrix, where *n* is odd. The Smart Beaver considers the following matrix elements good:
- Elements of the main diagonal. - Elements of the secondary diagonal. - Elements of the "middle" row — the row which has exactly rows above it and the same number of rows below it. - Elements of the "middle" column — the column that has exactly columns to the left of it and the same number of columns to the right of it.
Help the Smart Beaver count the sum of good elements of the given matrix. | The first line of input data contains a single odd integer *n*. Each of the next *n* lines contains *n* integers *a**ij* (0<=≤<=*a**ij*<=≤<=100) separated by single spaces — the elements of the given matrix.
The input limitations for getting 30 points are:
- 1<=≤<=*n*<=≤<=5
The input limitations for getting 100 points are:
- 1<=≤<=*n*<=≤<=101 | Print a single integer — the sum of good matrix elements. | [
"3\n1 2 3\n4 5 6\n7 8 9\n",
"5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n"
] | [
"45\n",
"17\n"
] | In the first sample all matrix elements will be good. Good elements in the second sample are shown on the figure. | 30 | [
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "45"
},
{
"input": "5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1",
"output": "17"
},
{
"input": "1\n3",
"output": "3"
},
{
"input": "5\n27 7 3 11 72\n19 49 68 19 59\n41 25 37 64 65\n8 39 96 62 90\n13 37 43 26 33",
... | 1,585,143,867 | 2,147,483,647 | PyPy 3 | OK | TESTS1 | 17 | 310 | 0 | n = int(input())
mat = list()
ans = 0
for i in range(n):
li = list(map(int, input().split()))
mat.append(li)
for i in range(n):
for j in range(n):
if(i == j or j == n-1-i or i == n//2 or j == n//2):
ans += mat[i][j]
print(ans)
| Title: Good Matrix Elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Smart Beaver from ABBYY got hooked on square matrices. Now he is busy studying an *n*<=×<=*n* size matrix, where *n* is odd. The Smart Beaver considers the following matrix elements good:
- Elements of the main diagonal. - Elements of the secondary diagonal. - Elements of the "middle" row — the row which has exactly rows above it and the same number of rows below it. - Elements of the "middle" column — the column that has exactly columns to the left of it and the same number of columns to the right of it.
Help the Smart Beaver count the sum of good elements of the given matrix.
Input Specification:
The first line of input data contains a single odd integer *n*. Each of the next *n* lines contains *n* integers *a**ij* (0<=≤<=*a**ij*<=≤<=100) separated by single spaces — the elements of the given matrix.
The input limitations for getting 30 points are:
- 1<=≤<=*n*<=≤<=5
The input limitations for getting 100 points are:
- 1<=≤<=*n*<=≤<=101
Output Specification:
Print a single integer — the sum of good matrix elements.
Demo Input:
['3\n1 2 3\n4 5 6\n7 8 9\n', '5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n']
Demo Output:
['45\n', '17\n']
Note:
In the first sample all matrix elements will be good. Good elements in the second sample are shown on the figure. | ```python
n = int(input())
mat = list()
ans = 0
for i in range(n):
li = list(map(int, input().split()))
mat.append(li)
for i in range(n):
for j in range(n):
if(i == j or j == n-1-i or i == n//2 or j == n//2):
ans += mat[i][j]
print(ans)
``` | 3 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions. | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,671,812,879 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 186 | 0 | import math
a,b=map(int,input().split())
print(math.floor((a*b)/2))
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions.
Input Specification:
In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16).
Output Specification:
Output one number — the maximal number of dominoes, which can be placed.
Demo Input:
['2 4\n', '3 3\n']
Demo Output:
['4\n', '4\n']
Note:
none | ```python
import math
a,b=map(int,input().split())
print(math.floor((a*b)/2))
``` | 3.9535 |
702 | A | Maximum Increase | PROGRAMMING | 800 | [
"dp",
"greedy",
"implementation"
] | null | null | You are given array consisting of *n* integers. Your task is to find the maximum length of an increasing subarray of the given array.
A subarray is the sequence of consecutive elements of the array. Subarray is called increasing if each element of this subarray strictly greater than previous. | The first line contains single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of integers.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print the maximum length of an increasing subarray of the given array. | [
"5\n1 7 2 11 15\n",
"6\n100 100 100 100 100 100\n",
"3\n1 2 3\n"
] | [
"3\n",
"1\n",
"3\n"
] | none | 0 | [
{
"input": "5\n1 7 2 11 15",
"output": "3"
},
{
"input": "6\n100 100 100 100 100 100",
"output": "1"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "1\n1000000000",
"output": "1"
},
{
"input": "10\n802030518 598196518 640274071 983359971 71550121 96204862 7... | 1,663,081,122 | 2,147,483,647 | PyPy 3 | OK | TESTS | 32 | 140 | 10,752,000 | n = int(input())
nums = list(map(int,input().split()))
l = 0
ans = 0
for i, n in enumerate(nums):
if i==0 or nums[i-1]<n:
ans = max(i-l+1,ans)
else:
l = i
print(ans) | Title: Maximum Increase
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given array consisting of *n* integers. Your task is to find the maximum length of an increasing subarray of the given array.
A subarray is the sequence of consecutive elements of the array. Subarray is called increasing if each element of this subarray strictly greater than previous.
Input Specification:
The first line contains single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of integers.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109).
Output Specification:
Print the maximum length of an increasing subarray of the given array.
Demo Input:
['5\n1 7 2 11 15\n', '6\n100 100 100 100 100 100\n', '3\n1 2 3\n']
Demo Output:
['3\n', '1\n', '3\n']
Note:
none | ```python
n = int(input())
nums = list(map(int,input().split()))
l = 0
ans = 0
for i, n in enumerate(nums):
if i==0 or nums[i-1]<n:
ans = max(i-l+1,ans)
else:
l = i
print(ans)
``` | 3 | |
65 | A | Harry Potter and Three Spells | PROGRAMMING | 1,800 | [
"implementation",
"math"
] | A. Harry Potter and Three Spells | 2 | 256 | A long time ago (probably even in the first book), Nicholas Flamel, a great alchemist and the creator of the Philosopher's Stone, taught Harry Potter three useful spells. The first one allows you to convert *a* grams of sand into *b* grams of lead, the second one allows you to convert *c* grams of lead into *d* grams of gold and third one allows you to convert *e* grams of gold into *f* grams of sand. When Harry told his friends about these spells, Ron Weasley was amazed. After all, if they succeed in turning sand into lead, lead into gold, and then turning part of the gold into sand again and so on, then it will be possible to start with a small amount of sand and get huge amounts of gold! Even an infinite amount of gold! Hermione Granger, by contrast, was skeptical about that idea. She argues that according to the law of conservation of matter getting an infinite amount of matter, even using magic, is impossible. On the contrary, the amount of matter may even decrease during transformation, being converted to magical energy. Though Hermione's theory seems convincing, Ron won't believe her. As far as Ron is concerned, Hermione made up her law of conservation of matter to stop Harry and Ron wasting their time with this nonsense, and to make them go and do homework instead. That's why Ron has already collected a certain amount of sand for the experiments. A quarrel between the friends seems unavoidable...
Help Harry to determine which one of his friends is right, and avoid the quarrel after all. To do this you have to figure out whether it is possible to get the amount of gold greater than any preassigned number from some finite amount of sand. | The first line contains 6 integers *a*, *b*, *c*, *d*, *e*, *f* (0<=≤<=*a*,<=*b*,<=*c*,<=*d*,<=*e*,<=*f*<=≤<=1000). | Print "Ron", if it is possible to get an infinitely large amount of gold having a certain finite amount of sand (and not having any gold and lead at all), i.e., Ron is right. Otherwise, print "Hermione". | [
"100 200 250 150 200 250\n",
"100 50 50 200 200 100\n",
"100 10 200 20 300 30\n",
"0 0 0 0 0 0\n",
"1 1 0 1 1 1\n",
"1 0 1 2 1 2\n",
"100 1 100 1 0 1\n"
] | [
"Ron\n",
"Hermione\n",
"Hermione\n",
"Hermione\n",
"Ron\n",
"Hermione\n",
"Ron\n"
] | Consider the first sample. Let's start with the 500 grams of sand. Apply the first spell 5 times and turn the sand into 1000 grams of lead. Then apply the second spell 4 times to get 600 grams of gold. Let’s take 400 grams from the resulting amount of gold turn them back into sand. We get 500 grams of sand and 200 grams of gold. If we apply the same operations to 500 grams of sand again, we can get extra 200 grams of gold every time. Thus, you can get 200, 400, 600 etc. grams of gold, i.e., starting with a finite amount of sand (500 grams), you can get the amount of gold which is greater than any preassigned number.
In the forth sample it is impossible to get sand, or lead, or gold, applying the spells.
In the fifth sample an infinitely large amount of gold can be obtained by using only the second spell, which allows you to receive 1 gram of gold out of nothing. Note that if such a second spell is available, then the first and the third one do not affect the answer at all.
The seventh sample is more interesting. We can also start with a zero amount of sand there. With the aid of the third spell you can get sand out of nothing. We get 10000 grams of sand in this manner. Let's get 100 grams of lead using the first spell 100 times. Then make 1 gram of gold from them. We managed to receive 1 gram of gold, starting with a zero amount of sand! Clearly, in this manner you can get an infinitely large amount of gold. | 500 | [
{
"input": "100 200 250 150 200 250",
"output": "Ron"
},
{
"input": "100 50 50 200 200 100",
"output": "Hermione"
},
{
"input": "100 10 200 20 300 30",
"output": "Hermione"
},
{
"input": "0 0 0 0 0 0",
"output": "Hermione"
},
{
"input": "1 1 0 1 1 1",
"output"... | 1,636,553,881 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 19 | 124 | 28,467,200 | a, b, c, d, e, f = map(int, input().split())
if (b == 0 or d == 0 or f == 0) or max(a, b, c, d, e, f) <= 0:
print("Hermione")
elif(a == 0 or c == 0 or e == 0):
print("Ron")
elif(b / a * d / c * f / e - 1 > 0):
print("Ron")
else:
print("Hermione")
| Title: Harry Potter and Three Spells
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A long time ago (probably even in the first book), Nicholas Flamel, a great alchemist and the creator of the Philosopher's Stone, taught Harry Potter three useful spells. The first one allows you to convert *a* grams of sand into *b* grams of lead, the second one allows you to convert *c* grams of lead into *d* grams of gold and third one allows you to convert *e* grams of gold into *f* grams of sand. When Harry told his friends about these spells, Ron Weasley was amazed. After all, if they succeed in turning sand into lead, lead into gold, and then turning part of the gold into sand again and so on, then it will be possible to start with a small amount of sand and get huge amounts of gold! Even an infinite amount of gold! Hermione Granger, by contrast, was skeptical about that idea. She argues that according to the law of conservation of matter getting an infinite amount of matter, even using magic, is impossible. On the contrary, the amount of matter may even decrease during transformation, being converted to magical energy. Though Hermione's theory seems convincing, Ron won't believe her. As far as Ron is concerned, Hermione made up her law of conservation of matter to stop Harry and Ron wasting their time with this nonsense, and to make them go and do homework instead. That's why Ron has already collected a certain amount of sand for the experiments. A quarrel between the friends seems unavoidable...
Help Harry to determine which one of his friends is right, and avoid the quarrel after all. To do this you have to figure out whether it is possible to get the amount of gold greater than any preassigned number from some finite amount of sand.
Input Specification:
The first line contains 6 integers *a*, *b*, *c*, *d*, *e*, *f* (0<=≤<=*a*,<=*b*,<=*c*,<=*d*,<=*e*,<=*f*<=≤<=1000).
Output Specification:
Print "Ron", if it is possible to get an infinitely large amount of gold having a certain finite amount of sand (and not having any gold and lead at all), i.e., Ron is right. Otherwise, print "Hermione".
Demo Input:
['100 200 250 150 200 250\n', '100 50 50 200 200 100\n', '100 10 200 20 300 30\n', '0 0 0 0 0 0\n', '1 1 0 1 1 1\n', '1 0 1 2 1 2\n', '100 1 100 1 0 1\n']
Demo Output:
['Ron\n', 'Hermione\n', 'Hermione\n', 'Hermione\n', 'Ron\n', 'Hermione\n', 'Ron\n']
Note:
Consider the first sample. Let's start with the 500 grams of sand. Apply the first spell 5 times and turn the sand into 1000 grams of lead. Then apply the second spell 4 times to get 600 grams of gold. Let’s take 400 grams from the resulting amount of gold turn them back into sand. We get 500 grams of sand and 200 grams of gold. If we apply the same operations to 500 grams of sand again, we can get extra 200 grams of gold every time. Thus, you can get 200, 400, 600 etc. grams of gold, i.e., starting with a finite amount of sand (500 grams), you can get the amount of gold which is greater than any preassigned number.
In the forth sample it is impossible to get sand, or lead, or gold, applying the spells.
In the fifth sample an infinitely large amount of gold can be obtained by using only the second spell, which allows you to receive 1 gram of gold out of nothing. Note that if such a second spell is available, then the first and the third one do not affect the answer at all.
The seventh sample is more interesting. We can also start with a zero amount of sand there. With the aid of the third spell you can get sand out of nothing. We get 10000 grams of sand in this manner. Let's get 100 grams of lead using the first spell 100 times. Then make 1 gram of gold from them. We managed to receive 1 gram of gold, starting with a zero amount of sand! Clearly, in this manner you can get an infinitely large amount of gold. | ```python
a, b, c, d, e, f = map(int, input().split())
if (b == 0 or d == 0 or f == 0) or max(a, b, c, d, e, f) <= 0:
print("Hermione")
elif(a == 0 or c == 0 or e == 0):
print("Ron")
elif(b / a * d / c * f / e - 1 > 0):
print("Ron")
else:
print("Hermione")
``` | 0 |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word. | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,624,642,081 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 154 | 0 | A=input()
u=l=0
for i in range(len(A)):
if A[i].isupper()==True:
u+=1
else:
l+=1
if u>l:
print(A.upper())
else:
print(A.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word.
Input Specification:
The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100.
Output Specification:
Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one.
Demo Input:
['HoUse\n', 'ViP\n', 'maTRIx\n']
Demo Output:
['house\n', 'VIP\n', 'matrix\n']
Note:
none | ```python
A=input()
u=l=0
for i in range(len(A)):
if A[i].isupper()==True:
u+=1
else:
l+=1
if u>l:
print(A.upper())
else:
print(A.lower())
``` | 3.9615 |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the minimum number of bacteria you need to put into the box across those days? | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th morning there will be 8 in the box. So the answer is 1. | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,698,238,742 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | san = int(input())
if san %2 == 0:
print(1)
else:
print(san//2) | Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the minimum number of bacteria you need to put into the box across those days?
Input Specification:
The only line containing one integer *x* (1<=≤<=*x*<=≤<=109).
Output Specification:
The only line containing one integer: the answer.
Demo Input:
['5\n', '8\n']
Demo Output:
['2\n', '1\n']
Note:
For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th morning there will be 8 in the box. So the answer is 1. | ```python
san = int(input())
if san %2 == 0:
print(1)
else:
print(san//2)
``` | 0 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word. | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,594,140,348 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 186 | 6,656,000 |
string = input()
uppers = len([i for i in string if i.isupper()])
if uppers > len(string)/2:
print (string.upper())
else:
print (string.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word.
Input Specification:
The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100.
Output Specification:
Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one.
Demo Input:
['HoUse\n', 'ViP\n', 'maTRIx\n']
Demo Output:
['house\n', 'VIP\n', 'matrix\n']
Note:
none | ```python
string = input()
uppers = len([i for i in string if i.isupper()])
if uppers > len(string)/2:
print (string.upper())
else:
print (string.lower())
``` | 3.941102 |
832 | A | Sasha and Sticks | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with whom he shares a desk. The rules are simple. Sasha draws *n* sticks in a row. After that the players take turns crossing out exactly *k* sticks from left or right in each turn. Sasha moves first, because he is the inventor of the game. If there are less than *k* sticks on the paper before some turn, the game ends. Sasha wins if he makes strictly more moves than Lena. Sasha wants to know the result of the game before playing, you are to help him. | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1018, *k*<=≤<=*n*) — the number of sticks drawn by Sasha and the number *k* — the number of sticks to be crossed out on each turn. | If Sasha wins, print "YES" (without quotes), otherwise print "NO" (without quotes).
You can print each letter in arbitrary case (upper of lower). | [
"1 1\n",
"10 4\n"
] | [
"YES\n",
"NO\n"
] | In the first example Sasha crosses out 1 stick, and then there are no sticks. So Lena can't make a move, and Sasha wins.
In the second example Sasha crosses out 4 sticks, then Lena crosses out 4 sticks, and after that there are only 2 sticks left. Sasha can't make a move. The players make equal number of moves, so Sasha doesn't win. | 500 | [
{
"input": "1 1",
"output": "YES"
},
{
"input": "10 4",
"output": "NO"
},
{
"input": "251656215122324104 164397544865601257",
"output": "YES"
},
{
"input": "963577813436662285 206326039287271924",
"output": "NO"
},
{
"input": "1000000000000000000 1",
"output":... | 1,608,190,530 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 0 | n,k = map(int,input().split())
if n%k==(n%2==0):
print("Yes")
else:
print("No") | Title: Sasha and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with whom he shares a desk. The rules are simple. Sasha draws *n* sticks in a row. After that the players take turns crossing out exactly *k* sticks from left or right in each turn. Sasha moves first, because he is the inventor of the game. If there are less than *k* sticks on the paper before some turn, the game ends. Sasha wins if he makes strictly more moves than Lena. Sasha wants to know the result of the game before playing, you are to help him.
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1018, *k*<=≤<=*n*) — the number of sticks drawn by Sasha and the number *k* — the number of sticks to be crossed out on each turn.
Output Specification:
If Sasha wins, print "YES" (without quotes), otherwise print "NO" (without quotes).
You can print each letter in arbitrary case (upper of lower).
Demo Input:
['1 1\n', '10 4\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first example Sasha crosses out 1 stick, and then there are no sticks. So Lena can't make a move, and Sasha wins.
In the second example Sasha crosses out 4 sticks, then Lena crosses out 4 sticks, and after that there are only 2 sticks left. Sasha can't make a move. The players make equal number of moves, so Sasha doesn't win. | ```python
n,k = map(int,input().split())
if n%k==(n%2==0):
print("Yes")
else:
print("No")
``` | 0 | |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are staying on the positions *l**i*, *l**i*<=+<=1, ..., *n*. Formally, he want to find the number of distinct numbers among *a**l**i*,<=*a**l**i*<=+<=1,<=...,<=*a**n*.?
Sereja wrote out the necessary array elements but the array was so large and the boy was so pressed for time. Help him, find the answer for the described question for each *l**i*. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,667,981,220 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 11,366,400 | n,m=map(int,input().split())
a=list(map(int,input().split()))
for i in range(m):
l=int(input())
c=0
aa=a[l-1:]
aa.sort()
for j in range(len(aa)-1):
if aa[j]!=aa[j+1]:
c+=1
print(c+1) | Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are staying on the positions *l**i*, *l**i*<=+<=1, ..., *n*. Formally, he want to find the number of distinct numbers among *a**l**i*,<=*a**l**i*<=+<=1,<=...,<=*a**n*.?
Sereja wrote out the necessary array elements but the array was so large and the boy was so pressed for time. Help him, find the answer for the described question for each *l**i*.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*).
Output Specification:
Print *m* lines — on the *i*-th line print the answer to the number *l**i*.
Demo Input:
['10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n']
Demo Output:
['6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n']
Note:
none | ```python
n,m=map(int,input().split())
a=list(map(int,input().split()))
for i in range(m):
l=int(input())
c=0
aa=a[l-1:]
aa.sort()
for j in range(len(aa)-1):
if aa[j]!=aa[j+1]:
c+=1
print(c+1)
``` | 0 | |
982 | B | Bus of Characters | PROGRAMMING | 1,300 | [
"data structures",
"greedy",
"implementation"
] | null | null | In the Bus of Characters there are $n$ rows of seat, each having $2$ seats. The width of both seats in the $i$-th row is $w_i$ centimeters. All integers $w_i$ are distinct.
Initially the bus is empty. On each of $2n$ stops one passenger enters the bus. There are two types of passengers:
- an introvert always chooses a row where both seats are empty. Among these rows he chooses the one with the smallest seats width and takes one of the seats in it; - an extrovert always chooses a row where exactly one seat is occupied (by an introvert). Among these rows he chooses the one with the largest seats width and takes the vacant place in it.
You are given the seats width in each row and the order the passengers enter the bus. Determine which row each passenger will take. | The first line contains a single integer $n$ ($1 \le n \le 200\,000$) — the number of rows in the bus.
The second line contains the sequence of integers $w_1, w_2, \dots, w_n$ ($1 \le w_i \le 10^{9}$), where $w_i$ is the width of each of the seats in the $i$-th row. It is guaranteed that all $w_i$ are distinct.
The third line contains a string of length $2n$, consisting of digits '0' and '1' — the description of the order the passengers enter the bus. If the $j$-th character is '0', then the passenger that enters the bus on the $j$-th stop is an introvert. If the $j$-th character is '1', the the passenger that enters the bus on the $j$-th stop is an extrovert. It is guaranteed that the number of extroverts equals the number of introverts (i. e. both numbers equal $n$), and for each extrovert there always is a suitable row. | Print $2n$ integers — the rows the passengers will take. The order of passengers should be the same as in input. | [
"2\n3 1\n0011\n",
"6\n10 8 9 11 13 5\n010010011101\n"
] | [
"2 1 1 2 \n",
"6 6 2 3 3 1 4 4 1 2 5 5 \n"
] | In the first example the first passenger (introvert) chooses the row $2$, because it has the seats with smallest width. The second passenger (introvert) chooses the row $1$, because it is the only empty row now. The third passenger (extrovert) chooses the row $1$, because it has exactly one occupied seat and the seat width is the largest among such rows. The fourth passenger (extrovert) chooses the row $2$, because it is the only row with an empty place. | 1,000 | [
{
"input": "2\n3 1\n0011",
"output": "2 1 1 2 "
},
{
"input": "6\n10 8 9 11 13 5\n010010011101",
"output": "6 6 2 3 3 1 4 4 1 2 5 5 "
},
{
"input": "1\n1\n01",
"output": "1 1 "
},
{
"input": "1\n1000000\n01",
"output": "1 1 "
},
{
"input": "2\n1 1000000\n0011",
... | 1,619,951,201 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 732 | 38,092,800 | n = int(input())
w = list(map(int, input().split()))
intro = [[v, i] for i, v in enumerate(w, 1)]
intro.sort(key=lambda x: x[0])
s = input()
i = -1
li = []
ans = []
for j in s:
if j == "0":
i += 1
ans.append(intro[i][1])
li.append(intro[i][1])
else:
ans.append(li.pop(-1))
print(" ".join(map(str, ans)))
| Title: Bus of Characters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the Bus of Characters there are $n$ rows of seat, each having $2$ seats. The width of both seats in the $i$-th row is $w_i$ centimeters. All integers $w_i$ are distinct.
Initially the bus is empty. On each of $2n$ stops one passenger enters the bus. There are two types of passengers:
- an introvert always chooses a row where both seats are empty. Among these rows he chooses the one with the smallest seats width and takes one of the seats in it; - an extrovert always chooses a row where exactly one seat is occupied (by an introvert). Among these rows he chooses the one with the largest seats width and takes the vacant place in it.
You are given the seats width in each row and the order the passengers enter the bus. Determine which row each passenger will take.
Input Specification:
The first line contains a single integer $n$ ($1 \le n \le 200\,000$) — the number of rows in the bus.
The second line contains the sequence of integers $w_1, w_2, \dots, w_n$ ($1 \le w_i \le 10^{9}$), where $w_i$ is the width of each of the seats in the $i$-th row. It is guaranteed that all $w_i$ are distinct.
The third line contains a string of length $2n$, consisting of digits '0' and '1' — the description of the order the passengers enter the bus. If the $j$-th character is '0', then the passenger that enters the bus on the $j$-th stop is an introvert. If the $j$-th character is '1', the the passenger that enters the bus on the $j$-th stop is an extrovert. It is guaranteed that the number of extroverts equals the number of introverts (i. e. both numbers equal $n$), and for each extrovert there always is a suitable row.
Output Specification:
Print $2n$ integers — the rows the passengers will take. The order of passengers should be the same as in input.
Demo Input:
['2\n3 1\n0011\n', '6\n10 8 9 11 13 5\n010010011101\n']
Demo Output:
['2 1 1 2 \n', '6 6 2 3 3 1 4 4 1 2 5 5 \n']
Note:
In the first example the first passenger (introvert) chooses the row $2$, because it has the seats with smallest width. The second passenger (introvert) chooses the row $1$, because it is the only empty row now. The third passenger (extrovert) chooses the row $1$, because it has exactly one occupied seat and the seat width is the largest among such rows. The fourth passenger (extrovert) chooses the row $2$, because it is the only row with an empty place. | ```python
n = int(input())
w = list(map(int, input().split()))
intro = [[v, i] for i, v in enumerate(w, 1)]
intro.sort(key=lambda x: x[0])
s = input()
i = -1
li = []
ans = []
for j in s:
if j == "0":
i += 1
ans.append(intro[i][1])
li.append(intro[i][1])
else:
ans.append(li.pop(-1))
print(" ".join(map(str, ans)))
``` | 3 | |
251 | A | Points on Line | PROGRAMMING | 1,300 | [
"binary search",
"combinatorics",
"two pointers"
] | null | null | Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed *d*.
Note that the order of the points inside the group of three chosen points doesn't matter. | The first line contains two integers: *n* and *d* (1<=≤<=*n*<=≤<=105; 1<=≤<=*d*<=≤<=109). The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n*, their absolute value doesn't exceed 109 — the *x*-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase. | Print a single integer — the number of groups of three points, where the distance between two farthest points doesn't exceed *d*.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"4 3\n1 2 3 4\n",
"4 2\n-3 -2 -1 0\n",
"5 19\n1 10 20 30 50\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}. | 500 | [
{
"input": "4 3\n1 2 3 4",
"output": "4"
},
{
"input": "4 2\n-3 -2 -1 0",
"output": "2"
},
{
"input": "5 19\n1 10 20 30 50",
"output": "1"
},
{
"input": "10 5\n31 36 43 47 48 50 56 69 71 86",
"output": "2"
},
{
"input": "10 50\n1 4 20 27 65 79 82 83 99 100",
"... | 1,459,876,275 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 4,812,800 | class ArrayQueue:
DEFAULT_CAPACITY=10
def __init__(self):
self._data=[None]*ArrayQueue.DEFAULT_CAPACITY
self._size=0
self._front=0
def __len__(self):
return self._size
def is_empty(self):
return self._size==0
def first(self):
if self.is_empty():
raise Empty('Queue is empty')
return self._data[self._front]
def dequeue(self):
if self.is_empty():
raise Empty('Queue is empty')
answer=self._data[self._front]
self._data[self._front]=None
self._front=(self._front+1)%len(self._data)
self._size-=1
return answer
def enqueue(self,e):
if self._size==len(self._data):
self._resize(2*len(self._data))
avail=(self._front+self._size)%len(self._data)
self._data[avail]=e
self._size+=1
def _resize(self,cap):
old=self._data
self._data=[None]*cap
walk=self._front
for k in range(self._size):
self._data[k]=old[walk]
walk=(1+walk)%len(old)
self._front=0
from array_queue import ArrayQueue
from collections import deque
import itertools
temp=[]
temp= input().split(' ')
n=int(temp[0])
d=int(temp[1])
temp=[]
temp= input().split(' ')
q=ArrayQueue()
q._resize(n)
for x in temp:
q.enqueue(int(x))
ans=0
deque=deque()
while q.is_empty()==False:
deque.append(q.dequeue())
while deque[-1] - deque[0] >=d:
s=0
for x in itertools.combinations(deque,3):
s=s+1
ans += s
deque.popleft()
print(ans) | Title: Points on Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed *d*.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input Specification:
The first line contains two integers: *n* and *d* (1<=≤<=*n*<=≤<=105; 1<=≤<=*d*<=≤<=109). The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n*, their absolute value doesn't exceed 109 — the *x*-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output Specification:
Print a single integer — the number of groups of three points, where the distance between two farthest points doesn't exceed *d*.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
Demo Input:
['4 3\n1 2 3 4\n', '4 2\n-3 -2 -1 0\n', '5 19\n1 10 20 30 50\n']
Demo Output:
['4\n', '2\n', '1\n']
Note:
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}. | ```python
class ArrayQueue:
DEFAULT_CAPACITY=10
def __init__(self):
self._data=[None]*ArrayQueue.DEFAULT_CAPACITY
self._size=0
self._front=0
def __len__(self):
return self._size
def is_empty(self):
return self._size==0
def first(self):
if self.is_empty():
raise Empty('Queue is empty')
return self._data[self._front]
def dequeue(self):
if self.is_empty():
raise Empty('Queue is empty')
answer=self._data[self._front]
self._data[self._front]=None
self._front=(self._front+1)%len(self._data)
self._size-=1
return answer
def enqueue(self,e):
if self._size==len(self._data):
self._resize(2*len(self._data))
avail=(self._front+self._size)%len(self._data)
self._data[avail]=e
self._size+=1
def _resize(self,cap):
old=self._data
self._data=[None]*cap
walk=self._front
for k in range(self._size):
self._data[k]=old[walk]
walk=(1+walk)%len(old)
self._front=0
from array_queue import ArrayQueue
from collections import deque
import itertools
temp=[]
temp= input().split(' ')
n=int(temp[0])
d=int(temp[1])
temp=[]
temp= input().split(' ')
q=ArrayQueue()
q._resize(n)
for x in temp:
q.enqueue(int(x))
ans=0
deque=deque()
while q.is_empty()==False:
deque.append(q.dequeue())
while deque[-1] - deque[0] >=d:
s=0
for x in itertools.combinations(deque,3):
s=s+1
ans += s
deque.popleft()
print(ans)
``` | -1 | |
698 | A | Vacations | PROGRAMMING | 1,400 | [
"dp"
] | null | null | Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options:
1. on this day the gym is closed and the contest is not carried out; 1. on this day the gym is closed and the contest is carried out; 1. on this day the gym is open and the contest is not carried out; 1. on this day the gym is open and the contest is carried out.
On each of days Vasya can either have a rest or write the contest (if it is carried out on this day), or do sport (if the gym is open on this day).
Find the minimum number of days on which Vasya will have a rest (it means, he will not do sport and write the contest at the same time). The only limitation that Vasya has — he does not want to do the same activity on two consecutive days: it means, he will not do sport on two consecutive days, and write the contest on two consecutive days. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations.
The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where:
- *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the contest is not carried out; - *a**i* equals 1, if on the *i*-th day of vacations the gym is closed, but the contest is carried out; - *a**i* equals 2, if on the *i*-th day of vacations the gym is open and the contest is not carried out; - *a**i* equals 3, if on the *i*-th day of vacations the gym is open and the contest is carried out. | Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses:
- to do sport on any two consecutive days, - to write the contest on any two consecutive days. | [
"4\n1 3 2 0\n",
"7\n1 3 3 2 1 2 3\n",
"2\n2 2\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days.
In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day.
In the third test Vasya can do sport either on a day number 1 or number 2. He can not do sport in two days, because it will be contrary to the his limitation. Thus, he will have a rest for only one day. | 500 | [
{
"input": "4\n1 3 2 0",
"output": "2"
},
{
"input": "7\n1 3 3 2 1 2 3",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "10\n0 0 1 1 0 0 0 0 1 0",
"output": "8"
},
{
"input": "100\n3 2 3 3 3 2 3 1 ... | 1,566,044,557 | 2,147,483,647 | PyPy 3 | OK | TESTS | 88 | 155 | 0 | n = int(input())
l = list(map(int, input().split()))
cur = ans = 0
for a in l:
if a == 0:
ans += 1
cur = 0
elif a == 1:
if cur in (0, 1):
cur = 2
else:
ans += 1
cur = 0
elif a == 2:
if cur in (0, 2):
cur = 1
else:
ans += 1
cur = 0
else:
cur = [0, 2, 1][cur]
print(ans) | Title: Vacations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options:
1. on this day the gym is closed and the contest is not carried out; 1. on this day the gym is closed and the contest is carried out; 1. on this day the gym is open and the contest is not carried out; 1. on this day the gym is open and the contest is carried out.
On each of days Vasya can either have a rest or write the contest (if it is carried out on this day), or do sport (if the gym is open on this day).
Find the minimum number of days on which Vasya will have a rest (it means, he will not do sport and write the contest at the same time). The only limitation that Vasya has — he does not want to do the same activity on two consecutive days: it means, he will not do sport on two consecutive days, and write the contest on two consecutive days.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations.
The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where:
- *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the contest is not carried out; - *a**i* equals 1, if on the *i*-th day of vacations the gym is closed, but the contest is carried out; - *a**i* equals 2, if on the *i*-th day of vacations the gym is open and the contest is not carried out; - *a**i* equals 3, if on the *i*-th day of vacations the gym is open and the contest is carried out.
Output Specification:
Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses:
- to do sport on any two consecutive days, - to write the contest on any two consecutive days.
Demo Input:
['4\n1 3 2 0\n', '7\n1 3 3 2 1 2 3\n', '2\n2 2\n']
Demo Output:
['2\n', '0\n', '1\n']
Note:
In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days.
In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day.
In the third test Vasya can do sport either on a day number 1 or number 2. He can not do sport in two days, because it will be contrary to the his limitation. Thus, he will have a rest for only one day. | ```python
n = int(input())
l = list(map(int, input().split()))
cur = ans = 0
for a in l:
if a == 0:
ans += 1
cur = 0
elif a == 1:
if cur in (0, 1):
cur = 2
else:
ans += 1
cur = 0
elif a == 2:
if cur in (0, 2):
cur = 1
else:
ans += 1
cur = 0
else:
cur = [0, 2, 1][cur]
print(ans)
``` | 3 | |
6 | A | Triangle | PROGRAMMING | 900 | [
"brute force",
"geometry"
] | A. Triangle | 2 | 64 | Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out of four sticks of different colours. Naturally, one of the sticks is extra. It is not allowed to break the sticks or use their partial length. Anne has perfectly solved this task, now she is asking Johnny to do the same.
The boy answered that he would cope with it without any difficulty. However, after a while he found out that different tricky things can occur. It can happen that it is impossible to construct a triangle of a positive area, but it is possible to construct a degenerate triangle. It can be so, that it is impossible to construct a degenerate triangle even. As Johnny is very lazy, he does not want to consider such a big amount of cases, he asks you to help him. | The first line of the input contains four space-separated positive integer numbers not exceeding 100 — lengthes of the sticks. | Output TRIANGLE if it is possible to construct a non-degenerate triangle. Output SEGMENT if the first case cannot take place and it is possible to construct a degenerate triangle. Output IMPOSSIBLE if it is impossible to construct any triangle. Remember that you are to use three sticks. It is not allowed to break the sticks or use their partial length. | [
"4 2 1 3\n",
"7 2 2 4\n",
"3 5 9 1\n"
] | [
"TRIANGLE\n",
"SEGMENT\n",
"IMPOSSIBLE\n"
] | none | 0 | [
{
"input": "4 2 1 3",
"output": "TRIANGLE"
},
{
"input": "7 2 2 4",
"output": "SEGMENT"
},
{
"input": "3 5 9 1",
"output": "IMPOSSIBLE"
},
{
"input": "3 1 5 1",
"output": "IMPOSSIBLE"
},
{
"input": "10 10 10 10",
"output": "TRIANGLE"
},
{
"input": "11 ... | 1,592,053,410 | 2,147,483,647 | Python 3 | OK | TESTS | 83 | 248 | 307,200 | def triangle(a,b,c):
if a+b>c and b+c>a and c+a>b:
return True
return False
def func(a,b,c):
if a+b==c or b+c==a or c+a==b:
return True
return False
a,b,c,d = list(map(int,input().split()))
if triangle(a,b,c)==True or triangle(b,c,d)==True or triangle(a,c,d)==True or triangle(a,b,d)==True:
print("TRIANGLE")
elif func(a,b,c)==True or func(b,c,d)==True or func(a,c,d)==True or func(a,b,d)==True:
print("SEGMENT")
else:
print("IMPOSSIBLE")
| Title: Triangle
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out of four sticks of different colours. Naturally, one of the sticks is extra. It is not allowed to break the sticks or use their partial length. Anne has perfectly solved this task, now she is asking Johnny to do the same.
The boy answered that he would cope with it without any difficulty. However, after a while he found out that different tricky things can occur. It can happen that it is impossible to construct a triangle of a positive area, but it is possible to construct a degenerate triangle. It can be so, that it is impossible to construct a degenerate triangle even. As Johnny is very lazy, he does not want to consider such a big amount of cases, he asks you to help him.
Input Specification:
The first line of the input contains four space-separated positive integer numbers not exceeding 100 — lengthes of the sticks.
Output Specification:
Output TRIANGLE if it is possible to construct a non-degenerate triangle. Output SEGMENT if the first case cannot take place and it is possible to construct a degenerate triangle. Output IMPOSSIBLE if it is impossible to construct any triangle. Remember that you are to use three sticks. It is not allowed to break the sticks or use their partial length.
Demo Input:
['4 2 1 3\n', '7 2 2 4\n', '3 5 9 1\n']
Demo Output:
['TRIANGLE\n', 'SEGMENT\n', 'IMPOSSIBLE\n']
Note:
none | ```python
def triangle(a,b,c):
if a+b>c and b+c>a and c+a>b:
return True
return False
def func(a,b,c):
if a+b==c or b+c==a or c+a==b:
return True
return False
a,b,c,d = list(map(int,input().split()))
if triangle(a,b,c)==True or triangle(b,c,d)==True or triangle(a,c,d)==True or triangle(a,b,d)==True:
print("TRIANGLE")
elif func(a,b,c)==True or func(b,c,d)==True or func(a,c,d)==True or func(a,b,d)==True:
print("SEGMENT")
else:
print("IMPOSSIBLE")
``` | 3.935711 |
928 | D | Autocompletion | PROGRAMMING | 1,900 | [
"*special",
"strings",
"trees"
] | null | null | Arcady is a copywriter. His today's task is to type up an already well-designed story using his favorite text editor.
Arcady types words, punctuation signs and spaces one after another. Each letter and each sign (including line feed) requires one keyboard click in order to be printed. Moreover, when Arcady has a non-empty prefix of some word on the screen, the editor proposes a possible autocompletion for this word, more precisely one of the already printed words such that its prefix matches the currently printed prefix if this word is unique. For example, if Arcady has already printed «codeforces», «coding» and «codeforces» once again, then there will be no autocompletion attempt for «cod», but if he proceeds with «code», the editor will propose «codeforces».
With a single click Arcady can follow the editor's proposal, i.e. to transform the current prefix to it. Note that no additional symbols are printed after the autocompletion (no spaces, line feeds, etc). What is the minimum number of keyboard clicks Arcady has to perform to print the entire text, if he is not allowed to move the cursor or erase the already printed symbols?
A word here is a contiguous sequence of latin letters bordered by spaces, punctuation signs and line/text beginnings/ends. Arcady uses only lowercase letters. For example, there are 20 words in «it's well-known that tic-tac-toe is a paper-and-pencil game for two players, x and o.». | The only line contains Arcady's text, consisting only of lowercase latin letters, spaces, line feeds and the following punctuation signs: «.», «,», «?», «!», «'» and «-». The total amount of symbols doesn't exceed 3·105. It's guaranteed that all lines are non-empty. | Print a single integer — the minimum number of clicks. | [
"snow affects sports such as skiing, snowboarding, and snowmachine travel.\nsnowboarding is a recreational activity and olympic and paralympic sport.\n",
"'co-co-co, codeforces?!'\n",
"thun-thun-thunder, thunder, thunder\nthunder, thun-, thunder\nthun-thun-thunder, thunder\nthunder, feel the thunder\nlightning ... | [
"141\n",
"25\n",
"183\n"
] | In sample case one it's optimal to use autocompletion for the first instance of «snowboarding» after typing up «sn» and for the second instance of «snowboarding» after typing up «snowb». This will save 7 clicks.
In sample case two it doesn't matter whether to use autocompletion or not. | 2,250 | [
{
"input": "snow affects sports such as skiing, snowboarding, and snowmachine travel.\nsnowboarding is a recreational activity and olympic and paralympic sport.",
"output": "141"
},
{
"input": "'co-co-co, codeforces?!'",
"output": "25"
},
{
"input": "thun-thun-thunder, thunder, thunder\n... | 1,519,500,649 | 14,149 | Python 3 | WRONG_ANSWER | PRETESTS | 0 | 62 | 5,632,000 | import sys
b = ''
y = 0
for i in sys.stdin:
for j in i:
if j != '\n':
b += j
else:
b += ' '
a = ['']
count = 0
for i in range(len(b)):
if b[i] != ' ' and b[i] != '-' and b[i] != ',' and b[i] != '?' and b[i] != '!' and b[i] != '.' and b[i] != '\'':
a[-1] += b[i]
else:
count += 1
if len(a[-1]) != 0:
a.append('')
dict1 = {}
for i in range(len(a)):
c = a[i]
d = ''
we = 0
for j in c:
d += j
if we == 0:
count += 1
if d in dict1:
if len(dict1[d]) == 1:
for j in dict1[d]:
if len(j) <= len(c) and len(d) < len(j):
po = 0
for g in range(len(j)):
if j[g] != c[g]:
po = 1
if we == 0 and po == 0:
count += 1
we = len(j) - len(d) + 1
if d not in dict1:
dict1[d] = set()
dict1[d].add(c)
if we > 0:
we -= 1
print(count + 1) | Title: Autocompletion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arcady is a copywriter. His today's task is to type up an already well-designed story using his favorite text editor.
Arcady types words, punctuation signs and spaces one after another. Each letter and each sign (including line feed) requires one keyboard click in order to be printed. Moreover, when Arcady has a non-empty prefix of some word on the screen, the editor proposes a possible autocompletion for this word, more precisely one of the already printed words such that its prefix matches the currently printed prefix if this word is unique. For example, if Arcady has already printed «codeforces», «coding» and «codeforces» once again, then there will be no autocompletion attempt for «cod», but if he proceeds with «code», the editor will propose «codeforces».
With a single click Arcady can follow the editor's proposal, i.e. to transform the current prefix to it. Note that no additional symbols are printed after the autocompletion (no spaces, line feeds, etc). What is the minimum number of keyboard clicks Arcady has to perform to print the entire text, if he is not allowed to move the cursor or erase the already printed symbols?
A word here is a contiguous sequence of latin letters bordered by spaces, punctuation signs and line/text beginnings/ends. Arcady uses only lowercase letters. For example, there are 20 words in «it's well-known that tic-tac-toe is a paper-and-pencil game for two players, x and o.».
Input Specification:
The only line contains Arcady's text, consisting only of lowercase latin letters, spaces, line feeds and the following punctuation signs: «.», «,», «?», «!», «'» and «-». The total amount of symbols doesn't exceed 3·105. It's guaranteed that all lines are non-empty.
Output Specification:
Print a single integer — the minimum number of clicks.
Demo Input:
['snow affects sports such as skiing, snowboarding, and snowmachine travel.\nsnowboarding is a recreational activity and olympic and paralympic sport.\n', "'co-co-co, codeforces?!'\n", 'thun-thun-thunder, thunder, thunder\nthunder, thun-, thunder\nthun-thun-thunder, thunder\nthunder, feel the thunder\nlightning then the thunder\nthunder, feel the thunder\nlightning then the thunder\nthunder, thunder\n']
Demo Output:
['141\n', '25\n', '183\n']
Note:
In sample case one it's optimal to use autocompletion for the first instance of «snowboarding» after typing up «sn» and for the second instance of «snowboarding» after typing up «snowb». This will save 7 clicks.
In sample case two it doesn't matter whether to use autocompletion or not. | ```python
import sys
b = ''
y = 0
for i in sys.stdin:
for j in i:
if j != '\n':
b += j
else:
b += ' '
a = ['']
count = 0
for i in range(len(b)):
if b[i] != ' ' and b[i] != '-' and b[i] != ',' and b[i] != '?' and b[i] != '!' and b[i] != '.' and b[i] != '\'':
a[-1] += b[i]
else:
count += 1
if len(a[-1]) != 0:
a.append('')
dict1 = {}
for i in range(len(a)):
c = a[i]
d = ''
we = 0
for j in c:
d += j
if we == 0:
count += 1
if d in dict1:
if len(dict1[d]) == 1:
for j in dict1[d]:
if len(j) <= len(c) and len(d) < len(j):
po = 0
for g in range(len(j)):
if j[g] != c[g]:
po = 1
if we == 0 and po == 0:
count += 1
we = len(j) - len(d) + 1
if d not in dict1:
dict1[d] = set()
dict1[d].add(c)
if we > 0:
we -= 1
print(count + 1)
``` | 0 | |
382 | A | Ksenia and Pan Scales | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium.
The scales is in equilibrium if the total sum of weights on the left pan is equal to the total sum of weights on the right pan. | The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol "|" indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially on the left pan of the scale. All weights that are recorded in the sequence after the delimiter are initially on the right pan of the scale.
The second line contains a non-empty sequence containing uppercase English letters. Each letter indicates a weight which is not used yet.
It is guaranteed that all the English letters in the input data are different. It is guaranteed that the input does not contain any extra characters. | If you cannot put all the weights on the scales so that the scales were in equilibrium, print string "Impossible". Otherwise, print the description of the resulting scales, copy the format of the input.
If there are multiple answers, print any of them. | [
"AC|T\nL\n",
"|ABC\nXYZ\n",
"W|T\nF\n",
"ABC|\nD\n"
] | [
"AC|TL\n",
"XYZ|ABC\n",
"Impossible\n",
"Impossible\n"
] | none | 500 | [
{
"input": "AC|T\nL",
"output": "AC|TL"
},
{
"input": "|ABC\nXYZ",
"output": "XYZ|ABC"
},
{
"input": "W|T\nF",
"output": "Impossible"
},
{
"input": "ABC|\nD",
"output": "Impossible"
},
{
"input": "A|BC\nDEF",
"output": "ADF|BCE"
},
{
"input": "|\nABC",... | 1,389,973,862 | 1,262 | Python 3 | WRONG_ANSWER | PRETESTS | 6 | 61 | 307,200 | __author__ = 'Adela'
def main():
# code
w = [k for k in input().split('|')]
l = len(w[0])
r = len(w[1])
rem = input()
total = (l+r+len(rem))
if total % 2 == 0:
if l <= total/2 and r <= total/2:
print(w[0], rem[:len(rem)-l], '|', w[1], rem[len(rem)-l:], sep='')
return
print("Impossible")
if __name__ == "__main__":
main()
| Title: Ksenia and Pan Scales
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium.
The scales is in equilibrium if the total sum of weights on the left pan is equal to the total sum of weights on the right pan.
Input Specification:
The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol "|" indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially on the left pan of the scale. All weights that are recorded in the sequence after the delimiter are initially on the right pan of the scale.
The second line contains a non-empty sequence containing uppercase English letters. Each letter indicates a weight which is not used yet.
It is guaranteed that all the English letters in the input data are different. It is guaranteed that the input does not contain any extra characters.
Output Specification:
If you cannot put all the weights on the scales so that the scales were in equilibrium, print string "Impossible". Otherwise, print the description of the resulting scales, copy the format of the input.
If there are multiple answers, print any of them.
Demo Input:
['AC|T\nL\n', '|ABC\nXYZ\n', 'W|T\nF\n', 'ABC|\nD\n']
Demo Output:
['AC|TL\n', 'XYZ|ABC\n', 'Impossible\n', 'Impossible\n']
Note:
none | ```python
__author__ = 'Adela'
def main():
# code
w = [k for k in input().split('|')]
l = len(w[0])
r = len(w[1])
rem = input()
total = (l+r+len(rem))
if total % 2 == 0:
if l <= total/2 and r <= total/2:
print(w[0], rem[:len(rem)-l], '|', w[1], rem[len(rem)-l:], sep='')
return
print("Impossible")
if __name__ == "__main__":
main()
``` | 0 | |
551 | A | GukiZ and Contest | PROGRAMMING | 800 | [
"brute force",
"implementation",
"sortings"
] | null | null | Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote the rating of *i*-th student as *a**i*. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to . In particular, if student *A* has rating strictly lower then student *B*, *A* will get the strictly better position than *B*, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected. | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*). | In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input. | [
"3\n1 3 3\n",
"1\n1\n",
"5\n3 5 3 4 5\n"
] | [
"3 1 1\n",
"1\n",
"4 1 4 3 1\n"
] | In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position. | 500 | [
{
"input": "3\n1 3 3",
"output": "3 1 1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n3 5 3 4 5",
"output": "4 1 4 3 1"
},
{
"input": "7\n1 3 5 4 2 2 1",
"output": "6 3 1 2 4 4 6"
},
{
"input": "11\n5 6 4 2 9 7 6 6 6 6 7",
"output": "9 4 10 11 1 2 4 4... | 1,665,818,045 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 93 | 5,222,400 | n = int(input())
s = input().split()
l = []
for i in range(n):
l.append([i, int(s[i])])
l = sorted(l, key=lambda x: x[1], reverse=True)
x = 0
y = l[0][1]
l[0][1] = 1
for i in range(1, n):
if l[i][1] == y:
l[i][1] = l[i-1][1]
else:
y = l[i][1]
l[i][1] = i+1
l = sorted(l, key=lambda x:x[0])
for i in range(n):
print(l[i][1], end=' ')
| Title: GukiZ and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote the rating of *i*-th student as *a**i*. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to . In particular, if student *A* has rating strictly lower then student *B*, *A* will get the strictly better position than *B*, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*).
Output Specification:
In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input.
Demo Input:
['3\n1 3 3\n', '1\n1\n', '5\n3 5 3 4 5\n']
Demo Output:
['3 1 1\n', '1\n', '4 1 4 3 1\n']
Note:
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position. | ```python
n = int(input())
s = input().split()
l = []
for i in range(n):
l.append([i, int(s[i])])
l = sorted(l, key=lambda x: x[1], reverse=True)
x = 0
y = l[0][1]
l[0][1] = 1
for i in range(1, n):
if l[i][1] == y:
l[i][1] = l[i-1][1]
else:
y = l[i][1]
l[i][1] = i+1
l = sorted(l, key=lambda x:x[0])
for i in range(n):
print(l[i][1], end=' ')
``` | 3 | |
939 | D | Love Rescue | PROGRAMMING | 1,600 | [
"dfs and similar",
"dsu",
"graphs",
"greedy",
"strings"
] | null | null | Valya and Tolya are an ideal pair, but they quarrel sometimes. Recently, Valya took offense at her boyfriend because he came to her in t-shirt with lettering that differs from lettering on her pullover. Now she doesn't want to see him and Tolya is seating at his room and crying at her photos all day long.
This story could be very sad but fairy godmother (Tolya's grandmother) decided to help them and restore their relationship. She secretly took Tolya's t-shirt and Valya's pullover and wants to make the letterings on them same. In order to do this, for one unit of mana she can buy a spell that can change some letters on the clothes. Your task is calculate the minimum amount of mana that Tolya's grandmother should spend to rescue love of Tolya and Valya.
More formally, letterings on Tolya's t-shirt and Valya's pullover are two strings with same length *n* consisting only of lowercase English letters. Using one unit of mana, grandmother can buy a spell of form (*c*1,<=*c*2) (where *c*1 and *c*2 are some lowercase English letters), which can arbitrary number of times transform a single letter *c*1 to *c*2 and vise-versa on both Tolya's t-shirt and Valya's pullover. You should find the minimum amount of mana that grandmother should spend to buy a set of spells that can make the letterings equal. In addition you should output the required set of spells. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the length of the letterings.
The second line contains a string with length *n*, consisting of lowercase English letters — the lettering on Valya's pullover.
The third line contains the lettering on Tolya's t-shirt in the same format. | In the first line output a single integer — the minimum amount of mana *t* required for rescuing love of Valya and Tolya.
In the next *t* lines output pairs of space-separated lowercase English letters — spells that Tolya's grandmother should buy. Spells and letters in spells can be printed in any order.
If there are many optimal answers, output any. | [
"3\nabb\ndad\n",
"8\ndrpepper\ncocacola\n"
] | [
"2\na d\nb a",
"7\nl e\ne d\nd c\nc p\np o\no r\nr a\n"
] | In first example it's enough to buy two spells: ('a','d') and ('b','a'). Then first letters will coincide when we will replace letter 'a' with 'd'. Second letters will coincide when we will replace 'b' with 'a'. Third letters will coincide when we will at first replace 'b' with 'a' and then 'a' with 'd'. | 2,000 | [
{
"input": "3\nabb\ndad",
"output": "2\nb d\nd a"
},
{
"input": "8\ndrpepper\ncocacola",
"output": "7\nl e\ne d\nd c\nc p\np o\no r\nr a"
},
{
"input": "1\nh\np",
"output": "1\np h"
},
{
"input": "2\nxc\nda",
"output": "2\nc a\nx d"
},
{
"input": "3\nbab\naab",
... | 1,616,918,997 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 109 | 2,355,200 | ###### ### ####### ####### ## # ##### ### #####
# # # # # # # # # # # # # ###
# # # # # # # # # # # # # ###
###### ######### # # # # # # ######### #
###### ######### # # # # # # ######### #
# # # # # # # # # # #### # # #
# # # # # # # ## # # # # #
###### # # ####### ####### # # ##### # # # #
# from __future__ import print_function # for PyPy2
from itertools import permutations as perm
# from fractions import Fraction
from collections import *
from sys import stdin
from bisect import *
from heapq import *
from math import *
g = lambda : stdin.readline().strip()
gl = lambda : g().split()
gil = lambda : [int(var) for var in gl()]
gfl = lambda : [float(var) for var in gl()]
gcl = lambda : list(g())
gbs = lambda : [int(var) for var in g()]
mod = int(1e9)+7
inf = float("inf")
n, = gil()
a, b = g(), g()
edges = set()
for i in range(n):
if a[i] != b[i]:
edges.add((a[i], b[i]))
edges.add((b[i], a[i]))
dsu = list(range(26))
cnt = [1]*26
ans = []
def getParent(x):
while dsu[x] != x:
x = dsu[x]
return x
while edges:
ai, bi = edges.pop()
edges.remove((bi, ai))
x, y = ord(ai)-97, ord(bi)-97
px, py = getParent(x), getParent(y)
if px == py: continue
ans.append((ai, bi))
if cnt[px] >= cnt[py]:
cnt[px] += cnt[py]
dsu[y] = x
else:
cnt[py] += cnt[px]
dsu[x] = y
print(len(ans))
if ans:
for r in ans:
print(*r)
| Title: Love Rescue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valya and Tolya are an ideal pair, but they quarrel sometimes. Recently, Valya took offense at her boyfriend because he came to her in t-shirt with lettering that differs from lettering on her pullover. Now she doesn't want to see him and Tolya is seating at his room and crying at her photos all day long.
This story could be very sad but fairy godmother (Tolya's grandmother) decided to help them and restore their relationship. She secretly took Tolya's t-shirt and Valya's pullover and wants to make the letterings on them same. In order to do this, for one unit of mana she can buy a spell that can change some letters on the clothes. Your task is calculate the minimum amount of mana that Tolya's grandmother should spend to rescue love of Tolya and Valya.
More formally, letterings on Tolya's t-shirt and Valya's pullover are two strings with same length *n* consisting only of lowercase English letters. Using one unit of mana, grandmother can buy a spell of form (*c*1,<=*c*2) (where *c*1 and *c*2 are some lowercase English letters), which can arbitrary number of times transform a single letter *c*1 to *c*2 and vise-versa on both Tolya's t-shirt and Valya's pullover. You should find the minimum amount of mana that grandmother should spend to buy a set of spells that can make the letterings equal. In addition you should output the required set of spells.
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the length of the letterings.
The second line contains a string with length *n*, consisting of lowercase English letters — the lettering on Valya's pullover.
The third line contains the lettering on Tolya's t-shirt in the same format.
Output Specification:
In the first line output a single integer — the minimum amount of mana *t* required for rescuing love of Valya and Tolya.
In the next *t* lines output pairs of space-separated lowercase English letters — spells that Tolya's grandmother should buy. Spells and letters in spells can be printed in any order.
If there are many optimal answers, output any.
Demo Input:
['3\nabb\ndad\n', '8\ndrpepper\ncocacola\n']
Demo Output:
['2\na d\nb a', '7\nl e\ne d\nd c\nc p\np o\no r\nr a\n']
Note:
In first example it's enough to buy two spells: ('a','d') and ('b','a'). Then first letters will coincide when we will replace letter 'a' with 'd'. Second letters will coincide when we will replace 'b' with 'a'. Third letters will coincide when we will at first replace 'b' with 'a' and then 'a' with 'd'. | ```python
###### ### ####### ####### ## # ##### ### #####
# # # # # # # # # # # # # ###
# # # # # # # # # # # # # ###
###### ######### # # # # # # ######### #
###### ######### # # # # # # ######### #
# # # # # # # # # # #### # # #
# # # # # # # ## # # # # #
###### # # ####### ####### # # ##### # # # #
# from __future__ import print_function # for PyPy2
from itertools import permutations as perm
# from fractions import Fraction
from collections import *
from sys import stdin
from bisect import *
from heapq import *
from math import *
g = lambda : stdin.readline().strip()
gl = lambda : g().split()
gil = lambda : [int(var) for var in gl()]
gfl = lambda : [float(var) for var in gl()]
gcl = lambda : list(g())
gbs = lambda : [int(var) for var in g()]
mod = int(1e9)+7
inf = float("inf")
n, = gil()
a, b = g(), g()
edges = set()
for i in range(n):
if a[i] != b[i]:
edges.add((a[i], b[i]))
edges.add((b[i], a[i]))
dsu = list(range(26))
cnt = [1]*26
ans = []
def getParent(x):
while dsu[x] != x:
x = dsu[x]
return x
while edges:
ai, bi = edges.pop()
edges.remove((bi, ai))
x, y = ord(ai)-97, ord(bi)-97
px, py = getParent(x), getParent(y)
if px == py: continue
ans.append((ai, bi))
if cnt[px] >= cnt[py]:
cnt[px] += cnt[py]
dsu[y] = x
else:
cnt[py] += cnt[px]
dsu[x] = y
print(len(ans))
if ans:
for r in ans:
print(*r)
``` | 0 | |
299 | A | Ksusha and Array | PROGRAMMING | 1,000 | [
"brute force",
"number theory",
"sortings"
] | null | null | Ksusha is a beginner coder. Today she starts studying arrays. She has array *a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* positive integers.
Her university teacher gave her a task. Find such number in the array, that all array elements are divisible by it. Help her and find the number! | The first line contains integer *n* (1<=≤<=*n*<=≤<=105), showing how many numbers the array has. The next line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the array elements. | Print a single integer — the number from the array, such that all array elements are divisible by it. If such number doesn't exist, print -1.
If there are multiple answers, you are allowed to print any of them. | [
"3\n2 2 4\n",
"5\n2 1 3 1 6\n",
"3\n2 3 5\n"
] | [
"2\n",
"1\n",
"-1\n"
] | none | 500 | [
{
"input": "3\n2 2 4",
"output": "2"
},
{
"input": "5\n2 1 3 1 6",
"output": "1"
},
{
"input": "3\n2 3 5",
"output": "-1"
},
{
"input": "1\n331358794",
"output": "331358794"
},
{
"input": "5\n506904227 214303304 136194869 838256937 183952885",
"output": "-1"
... | 1,634,568,341 | 2,147,483,647 | PyPy 3 | OK | TESTS | 32 | 436 | 10,752,000 | input()
ls = sorted(map(int, input().split()))
if all(map(lambda x: x % ls[0] == 0, ls)):
print(ls[0])
else:
print(-1)
| Title: Ksusha and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksusha is a beginner coder. Today she starts studying arrays. She has array *a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* positive integers.
Her university teacher gave her a task. Find such number in the array, that all array elements are divisible by it. Help her and find the number!
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=105), showing how many numbers the array has. The next line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the array elements.
Output Specification:
Print a single integer — the number from the array, such that all array elements are divisible by it. If such number doesn't exist, print -1.
If there are multiple answers, you are allowed to print any of them.
Demo Input:
['3\n2 2 4\n', '5\n2 1 3 1 6\n', '3\n2 3 5\n']
Demo Output:
['2\n', '1\n', '-1\n']
Note:
none | ```python
input()
ls = sorted(map(int, input().split()))
if all(map(lambda x: x % ls[0] == 0, ls)):
print(ls[0])
else:
print(-1)
``` | 3 | |
279 | B | Books | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation",
"two pointers"
] | null | null | When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to read the *i*-th book.
Valera decided to choose an arbitrary book with number *i* and read the books one by one, starting from this book. In other words, he will first read book number *i*, then book number *i*<=+<=1, then book number *i*<=+<=2 and so on. He continues the process until he either runs out of the free time or finishes reading the *n*-th book. Valera reads each book up to the end, that is, he doesn't start reading the book if he doesn't have enough free time to finish reading it.
Print the maximum number of books Valera can read. | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy needs to read the *i*-th book. | Print a single integer — the maximum number of books Valera can read. | [
"4 5\n3 1 2 1\n",
"3 3\n2 2 3\n"
] | [
"3\n",
"1\n"
] | none | 1,000 | [
{
"input": "4 5\n3 1 2 1",
"output": "3"
},
{
"input": "3 3\n2 2 3",
"output": "1"
},
{
"input": "1 3\n5",
"output": "0"
},
{
"input": "1 10\n4",
"output": "1"
},
{
"input": "2 10\n6 4",
"output": "2"
},
{
"input": "6 10\n2 3 4 2 1 1",
"output": "4... | 1,680,070,451 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | from bisect import bisect_right
n,m=map(int,input().split())
x=list(map(int,input().split()))
for j in range(1,n):
x[j]=x[j-1]+x[j]
ma=-1
for i in range(n):
ma=max(ma,bisect_right(x,x[i]+m,i)-i)
print(max(ma-1,1)) | Title: Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to read the *i*-th book.
Valera decided to choose an arbitrary book with number *i* and read the books one by one, starting from this book. In other words, he will first read book number *i*, then book number *i*<=+<=1, then book number *i*<=+<=2 and so on. He continues the process until he either runs out of the free time or finishes reading the *n*-th book. Valera reads each book up to the end, that is, he doesn't start reading the book if he doesn't have enough free time to finish reading it.
Print the maximum number of books Valera can read.
Input Specification:
The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy needs to read the *i*-th book.
Output Specification:
Print a single integer — the maximum number of books Valera can read.
Demo Input:
['4 5\n3 1 2 1\n', '3 3\n2 2 3\n']
Demo Output:
['3\n', '1\n']
Note:
none | ```python
from bisect import bisect_right
n,m=map(int,input().split())
x=list(map(int,input().split()))
for j in range(1,n):
x[j]=x[j-1]+x[j]
ma=-1
for i in range(n):
ma=max(ma,bisect_right(x,x[i]+m,i)-i)
print(max(ma-1,1))
``` | 0 | |
766 | A | Mahmoud and Longest Uncommon Subsequence | PROGRAMMING | 1,000 | [
"constructive algorithms",
"strings"
] | null | null | While Mahmoud and Ehab were practicing for IOI, they found a problem which name was Longest common subsequence. They solved it, and then Ehab challenged Mahmoud with another problem.
Given two strings *a* and *b*, find the length of their longest uncommon subsequence, which is the longest string that is a subsequence of one of them and not a subsequence of the other.
A subsequence of some string is a sequence of characters that appears in the same order in the string, The appearances don't have to be consecutive, for example, strings "ac", "bc", "abc" and "a" are subsequences of string "abc" while strings "abbc" and "acb" are not. The empty string is a subsequence of any string. Any string is a subsequence of itself. | The first line contains string *a*, and the second line — string *b*. Both of these strings are non-empty and consist of lowercase letters of English alphabet. The length of each string is not bigger than 105 characters. | If there's no uncommon subsequence, print "-1". Otherwise print the length of the longest uncommon subsequence of *a* and *b*. | [
"abcd\ndefgh\n",
"a\na\n"
] | [
"5\n",
"-1\n"
] | In the first example: you can choose "defgh" from string *b* as it is the longest subsequence of string *b* that doesn't appear as a subsequence of string *a*. | 500 | [
{
"input": "abcd\ndefgh",
"output": "5"
},
{
"input": "a\na",
"output": "-1"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaacccccccccccccccccccccccccccccccccccccccccccccccccc\naaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaadddddddddddddddddddddddddddddddddddddddddddd... | 1,645,868,210 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | if __name__=='__main__':
s1 = input()
s2 = input()
print(max(len(s1), len(s2)))
| Title: Mahmoud and Longest Uncommon Subsequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Mahmoud and Ehab were practicing for IOI, they found a problem which name was Longest common subsequence. They solved it, and then Ehab challenged Mahmoud with another problem.
Given two strings *a* and *b*, find the length of their longest uncommon subsequence, which is the longest string that is a subsequence of one of them and not a subsequence of the other.
A subsequence of some string is a sequence of characters that appears in the same order in the string, The appearances don't have to be consecutive, for example, strings "ac", "bc", "abc" and "a" are subsequences of string "abc" while strings "abbc" and "acb" are not. The empty string is a subsequence of any string. Any string is a subsequence of itself.
Input Specification:
The first line contains string *a*, and the second line — string *b*. Both of these strings are non-empty and consist of lowercase letters of English alphabet. The length of each string is not bigger than 105 characters.
Output Specification:
If there's no uncommon subsequence, print "-1". Otherwise print the length of the longest uncommon subsequence of *a* and *b*.
Demo Input:
['abcd\ndefgh\n', 'a\na\n']
Demo Output:
['5\n', '-1\n']
Note:
In the first example: you can choose "defgh" from string *b* as it is the longest subsequence of string *b* that doesn't appear as a subsequence of string *a*. | ```python
if __name__=='__main__':
s1 = input()
s2 = input()
print(max(len(s1), len(s2)))
``` | 0 | |
632 | B | Alice, Bob, Two Teams | PROGRAMMING | 1,400 | [
"brute force",
"constructive algorithms"
] | null | null | Alice and Bob are playing a game. The game involves splitting up game pieces into two teams. There are *n* pieces, and the *i*-th piece has a strength *p**i*.
The way to split up game pieces is split into several steps:
1. First, Alice will split the pieces into two different groups *A* and *B*. This can be seen as writing the assignment of teams of a piece in an *n* character string, where each character is *A* or *B*. 1. Bob will then choose an arbitrary prefix or suffix of the string, and flip each character in that suffix (i.e. change *A* to *B* and *B* to *A*). He can do this step at most once. 1. Alice will get all the pieces marked *A* and Bob will get all the pieces marked *B*.
The strength of a player is then the sum of strengths of the pieces in the group.
Given Alice's initial split into two teams, help Bob determine an optimal strategy. Return the maximum strength he can achieve. | The first line contains integer *n* (1<=≤<=*n*<=≤<=5·105) — the number of game pieces.
The second line contains *n* integers *p**i* (1<=≤<=*p**i*<=≤<=109) — the strength of the *i*-th piece.
The third line contains *n* characters *A* or *B* — the assignment of teams after the first step (after Alice's step). | Print the only integer *a* — the maximum strength Bob can achieve. | [
"5\n1 2 3 4 5\nABABA\n",
"5\n1 2 3 4 5\nAAAAA\n",
"1\n1\nB\n"
] | [
"11\n",
"15\n",
"1\n"
] | In the first sample Bob should flip the suffix of length one.
In the second sample Bob should flip the prefix or the suffix (here it is the same) of length 5.
In the third sample Bob should do nothing. | 0 | [
{
"input": "5\n1 2 3 4 5\nABABA",
"output": "11"
},
{
"input": "5\n1 2 3 4 5\nAAAAA",
"output": "15"
},
{
"input": "1\n1\nB",
"output": "1"
},
{
"input": "10\n1 9 7 6 2 4 7 8 1 3\nABBABAABBB",
"output": "33"
},
{
"input": "100\n591 417 888 251 792 847 685 3 182 46... | 1,456,847,902 | 3,502 | Python 3 | OK | TESTS | 17 | 1,123 | 44,953,600 | #!/usr/bin/python3
n = int(input())
strength = [int(i) for i in input().split()]
s = input()
total = 0
for i in range(n):
if s[i] == 'B':
total += strength[i]
prefix = [0]*n
suffix = [0]*n
for i in range(n):
if s[i] == 'A':
if i == 0:
prefix[i] = 0 + strength[i]
else:
prefix[i] = prefix[i-1] + strength[i]
else:
if i == 0:
prefix[i] = 0 - strength[i]
else:
prefix[i] = prefix[i-1] - strength[i]
for i in range(n-1, -1, -1):
if s[i] == 'A':
if i == n-1:
suffix[i] = 0 + strength[i]
else:
suffix[i] = suffix[i+1] + strength[i]
else:
if i == n-1:
suffix[i] = 0 - strength[i]
else:
suffix[i] = suffix[i+1] - strength[i]
x = 0
for i in range(n):
if prefix[i] > x:
x = prefix[i]
for i in range(n):
if suffix[i] > x:
x = suffix[i]
#print(str(total))
#print(str(x))
total += x
print(str(total))
| Title: Alice, Bob, Two Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice and Bob are playing a game. The game involves splitting up game pieces into two teams. There are *n* pieces, and the *i*-th piece has a strength *p**i*.
The way to split up game pieces is split into several steps:
1. First, Alice will split the pieces into two different groups *A* and *B*. This can be seen as writing the assignment of teams of a piece in an *n* character string, where each character is *A* or *B*. 1. Bob will then choose an arbitrary prefix or suffix of the string, and flip each character in that suffix (i.e. change *A* to *B* and *B* to *A*). He can do this step at most once. 1. Alice will get all the pieces marked *A* and Bob will get all the pieces marked *B*.
The strength of a player is then the sum of strengths of the pieces in the group.
Given Alice's initial split into two teams, help Bob determine an optimal strategy. Return the maximum strength he can achieve.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=5·105) — the number of game pieces.
The second line contains *n* integers *p**i* (1<=≤<=*p**i*<=≤<=109) — the strength of the *i*-th piece.
The third line contains *n* characters *A* or *B* — the assignment of teams after the first step (after Alice's step).
Output Specification:
Print the only integer *a* — the maximum strength Bob can achieve.
Demo Input:
['5\n1 2 3 4 5\nABABA\n', '5\n1 2 3 4 5\nAAAAA\n', '1\n1\nB\n']
Demo Output:
['11\n', '15\n', '1\n']
Note:
In the first sample Bob should flip the suffix of length one.
In the second sample Bob should flip the prefix or the suffix (here it is the same) of length 5.
In the third sample Bob should do nothing. | ```python
#!/usr/bin/python3
n = int(input())
strength = [int(i) for i in input().split()]
s = input()
total = 0
for i in range(n):
if s[i] == 'B':
total += strength[i]
prefix = [0]*n
suffix = [0]*n
for i in range(n):
if s[i] == 'A':
if i == 0:
prefix[i] = 0 + strength[i]
else:
prefix[i] = prefix[i-1] + strength[i]
else:
if i == 0:
prefix[i] = 0 - strength[i]
else:
prefix[i] = prefix[i-1] - strength[i]
for i in range(n-1, -1, -1):
if s[i] == 'A':
if i == n-1:
suffix[i] = 0 + strength[i]
else:
suffix[i] = suffix[i+1] + strength[i]
else:
if i == n-1:
suffix[i] = 0 - strength[i]
else:
suffix[i] = suffix[i+1] - strength[i]
x = 0
for i in range(n):
if prefix[i] > x:
x = prefix[i]
for i in range(n):
if suffix[i] > x:
x = suffix[i]
#print(str(total))
#print(str(x))
total += x
print(str(total))
``` | 3 | |
854 | B | Maxim Buys an Apartment | PROGRAMMING | 1,200 | [
"constructive algorithms",
"math"
] | null | null | Maxim wants to buy an apartment in a new house at Line Avenue of Metropolis. The house has *n* apartments that are numbered from 1 to *n* and are arranged in a row. Two apartments are adjacent if their indices differ by 1. Some of the apartments can already be inhabited, others are available for sale.
Maxim often visits his neighbors, so apartment is good for him if it is available for sale and there is at least one already inhabited apartment adjacent to it. Maxim knows that there are exactly *k* already inhabited apartments, but he doesn't know their indices yet.
Find out what could be the minimum possible and the maximum possible number of apartments that are good for Maxim. | The only line of the input contains two integers: *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=*n*). | Print the minimum possible and the maximum possible number of apartments good for Maxim. | [
"6 3\n"
] | [
"1 3\n"
] | In the sample test, the number of good apartments could be minimum possible if, for example, apartments with indices 1, 2 and 3 were inhabited. In this case only apartment 4 is good. The maximum possible number could be, for example, if apartments with indices 1, 3 and 5 were inhabited. In this case all other apartments: 2, 4 and 6 are good. | 1,000 | [
{
"input": "6 3",
"output": "1 3"
},
{
"input": "10 1",
"output": "1 2"
},
{
"input": "10 9",
"output": "1 1"
},
{
"input": "8 0",
"output": "0 0"
},
{
"input": "8 8",
"output": "0 0"
},
{
"input": "966871928 890926970",
"output": "1 75944958"
},... | 1,522,244,148 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 93 | 7,372,800 | a=[int(x) for x in input().split()]
n, k=a[0], a[1]
if 3*k<=n:
m=2*k
else:
m=n-k
if n==k:
print(0, 0)
elif k==0:
print(0, 0)
else:
print(1, m)
| Title: Maxim Buys an Apartment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Maxim wants to buy an apartment in a new house at Line Avenue of Metropolis. The house has *n* apartments that are numbered from 1 to *n* and are arranged in a row. Two apartments are adjacent if their indices differ by 1. Some of the apartments can already be inhabited, others are available for sale.
Maxim often visits his neighbors, so apartment is good for him if it is available for sale and there is at least one already inhabited apartment adjacent to it. Maxim knows that there are exactly *k* already inhabited apartments, but he doesn't know their indices yet.
Find out what could be the minimum possible and the maximum possible number of apartments that are good for Maxim.
Input Specification:
The only line of the input contains two integers: *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=*n*).
Output Specification:
Print the minimum possible and the maximum possible number of apartments good for Maxim.
Demo Input:
['6 3\n']
Demo Output:
['1 3\n']
Note:
In the sample test, the number of good apartments could be minimum possible if, for example, apartments with indices 1, 2 and 3 were inhabited. In this case only apartment 4 is good. The maximum possible number could be, for example, if apartments with indices 1, 3 and 5 were inhabited. In this case all other apartments: 2, 4 and 6 are good. | ```python
a=[int(x) for x in input().split()]
n, k=a[0], a[1]
if 3*k<=n:
m=2*k
else:
m=n-k
if n==k:
print(0, 0)
elif k==0:
print(0, 0)
else:
print(1, m)
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Theater stage is a rectangular field of size *n*<=×<=*m*. The director gave you the stage's plan which actors will follow. For each cell it is stated in the plan if there would be an actor in this cell or not.
You are to place a spotlight on the stage in some good position. The spotlight will project light in one of the four directions (if you look at the stage from above) — left, right, up or down. Thus, the spotlight's position is a cell it is placed to and a direction it shines.
A position is good if two conditions hold:
- there is no actor in the cell the spotlight is placed to; - there is at least one actor in the direction the spotlight projects.
Count the number of good positions for placing the spotlight. Two positions of spotlight are considered to be different if the location cells or projection direction differ. | The first line contains two positive integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and the number of columns in the plan.
The next *n* lines contain *m* integers, 0 or 1 each — the description of the plan. Integer 1, means there will be an actor in the corresponding cell, while 0 means the cell will remain empty. It is guaranteed that there is at least one actor in the plan. | Print one integer — the number of good positions for placing the spotlight. | [
"2 4\n0 1 0 0\n1 0 1 0\n",
"4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0\n"
] | [
"9\n",
"20\n"
] | In the first example the following positions are good:
1. the (1, 1) cell and right direction; 1. the (1, 1) cell and down direction; 1. the (1, 3) cell and left direction; 1. the (1, 3) cell and down direction; 1. the (1, 4) cell and left direction; 1. the (2, 2) cell and left direction; 1. the (2, 2) cell and up direction; 1. the (2, 2) and right direction; 1. the (2, 4) cell and left direction.
Therefore, there are 9 good positions in this example. | 0 | [
{
"input": "2 4\n0 1 0 0\n1 0 1 0",
"output": "9"
},
{
"input": "4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0",
"output": "20"
},
{
"input": "1 5\n1 1 0 0 0",
"output": "3"
},
{
"input": "2 10\n0 0 0 0 0 0 0 1 0 0\n1 0 0 0 0 0 0 0 0 0",
"output": "20"
},
{
"input": "3 ... | 1,479,638,508 | 5,808 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 6 | 1,000 | 5,324,800 |
s= input()
nm = [int(i) for i in s.split()]
n=nm[0]
m=nm[1]
jadval=[]
for i in range(n):
jadval.append(list(input().replace(" ", "")))
s=0
for i in range(n):
for j in range(m):
if jadval[i][j] != '1':
x=i
y=j
flag=0
#bala
while x>=0 and flag==0:
if jadval[x][y]=='1':
s=s+1
flag=1
x=x-1
x=i
y=j
flag=0
#paeen
while x<n and flag==0:
if jadval[x][y]=='1':
s=s+1
flag=1
x=x+1
x=i
y=j
flag=0
#chap
while y>=0 and flag==0:
if jadval[x][y]=='1':
s=s+1
flag=1
y=y-1
x=i
y=j
flag=0
#rast
while y<m and flag==0:
if jadval[x][y]=='1':
s=s+1
flag=1
y=y+1
print(s)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Theater stage is a rectangular field of size *n*<=×<=*m*. The director gave you the stage's plan which actors will follow. For each cell it is stated in the plan if there would be an actor in this cell or not.
You are to place a spotlight on the stage in some good position. The spotlight will project light in one of the four directions (if you look at the stage from above) — left, right, up or down. Thus, the spotlight's position is a cell it is placed to and a direction it shines.
A position is good if two conditions hold:
- there is no actor in the cell the spotlight is placed to; - there is at least one actor in the direction the spotlight projects.
Count the number of good positions for placing the spotlight. Two positions of spotlight are considered to be different if the location cells or projection direction differ.
Input Specification:
The first line contains two positive integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and the number of columns in the plan.
The next *n* lines contain *m* integers, 0 or 1 each — the description of the plan. Integer 1, means there will be an actor in the corresponding cell, while 0 means the cell will remain empty. It is guaranteed that there is at least one actor in the plan.
Output Specification:
Print one integer — the number of good positions for placing the spotlight.
Demo Input:
['2 4\n0 1 0 0\n1 0 1 0\n', '4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0\n']
Demo Output:
['9\n', '20\n']
Note:
In the first example the following positions are good:
1. the (1, 1) cell and right direction; 1. the (1, 1) cell and down direction; 1. the (1, 3) cell and left direction; 1. the (1, 3) cell and down direction; 1. the (1, 4) cell and left direction; 1. the (2, 2) cell and left direction; 1. the (2, 2) cell and up direction; 1. the (2, 2) and right direction; 1. the (2, 4) cell and left direction.
Therefore, there are 9 good positions in this example. | ```python
s= input()
nm = [int(i) for i in s.split()]
n=nm[0]
m=nm[1]
jadval=[]
for i in range(n):
jadval.append(list(input().replace(" ", "")))
s=0
for i in range(n):
for j in range(m):
if jadval[i][j] != '1':
x=i
y=j
flag=0
#bala
while x>=0 and flag==0:
if jadval[x][y]=='1':
s=s+1
flag=1
x=x-1
x=i
y=j
flag=0
#paeen
while x<n and flag==0:
if jadval[x][y]=='1':
s=s+1
flag=1
x=x+1
x=i
y=j
flag=0
#chap
while y>=0 and flag==0:
if jadval[x][y]=='1':
s=s+1
flag=1
y=y-1
x=i
y=j
flag=0
#rast
while y<m and flag==0:
if jadval[x][y]=='1':
s=s+1
flag=1
y=y+1
print(s)
``` | 0 | |
598 | A | Tricky Sum | PROGRAMMING | 900 | [
"math"
] | null | null | In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, because 1, 2 and 4 are 20, 21 and 22 respectively.
Calculate the answer for *t* values of *n*. | The first line of the input contains a single integer *t* (1<=≤<=*t*<=≤<=100) — the number of values of *n* to be processed.
Each of next *t* lines contains a single integer *n* (1<=≤<=*n*<=≤<=109). | Print the requested sum for each of *t* integers *n* given in the input. | [
"2\n4\n1000000000\n"
] | [
"-4\n499999998352516354\n"
] | The answer for the first sample is explained in the statement. | 0 | [
{
"input": "2\n4\n1000000000",
"output": "-4\n499999998352516354"
},
{
"input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "-1\n-3\n0\n-4\n1\n7\n14\n6\n15\n25"
},
{
"input": "10\n10\n9\n47\n33\n99\n83\n62\n1\n100\n53",
"output": "25\n15\n1002\n435\n4696\n3232\n1827\n-1\n4796\n130... | 1,619,786,368 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 61 | 0 | t=int(input())
for i in range(0,t):
n=int(input())
final=0
final+=n**2
final+=-(n*(n+1))
print(final) | Title: Tricky Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, because 1, 2 and 4 are 20, 21 and 22 respectively.
Calculate the answer for *t* values of *n*.
Input Specification:
The first line of the input contains a single integer *t* (1<=≤<=*t*<=≤<=100) — the number of values of *n* to be processed.
Each of next *t* lines contains a single integer *n* (1<=≤<=*n*<=≤<=109).
Output Specification:
Print the requested sum for each of *t* integers *n* given in the input.
Demo Input:
['2\n4\n1000000000\n']
Demo Output:
['-4\n499999998352516354\n']
Note:
The answer for the first sample is explained in the statement. | ```python
t=int(input())
for i in range(0,t):
n=int(input())
final=0
final+=n**2
final+=-(n*(n+1))
print(final)
``` | 0 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,533,135,282 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 248 | 0 | n = int(input())
axis = [0, 0, 0]
line = []
for i in range(n):
line = input().split()
for j in range(2):
axis[j] = axis[j] + int(line[j])
if (not axis[0]) and (not axis[1]) and (not axis[2]):
print("YES")
else:
print("NO") | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
n = int(input())
axis = [0, 0, 0]
line = []
for i in range(n):
line = input().split()
for j in range(2):
axis[j] = axis[j] + int(line[j])
if (not axis[0]) and (not axis[1]) and (not axis[2]):
print("YES")
else:
print("NO")
``` | 3.938 |
3 | C | Tic-tac-toe | PROGRAMMING | 1,800 | [
"brute force",
"games",
"implementation"
] | C. Tic-tac-toe | 1 | 64 | Certainly, everyone is familiar with tic-tac-toe game. The rules are very simple indeed. Two players take turns marking the cells in a 3<=×<=3 grid (one player always draws crosses, the other — noughts). The player who succeeds first in placing three of his marks in a horizontal, vertical or diagonal line wins, and the game is finished. The player who draws crosses goes first. If the grid is filled, but neither Xs, nor 0s form the required line, a draw is announced.
You are given a 3<=×<=3 grid, each grid cell is empty, or occupied by a cross or a nought. You have to find the player (first or second), whose turn is next, or print one of the verdicts below:
- illegal — if the given board layout can't appear during a valid game; - the first player won — if in the given board layout the first player has just won; - the second player won — if in the given board layout the second player has just won; - draw — if the given board layout has just let to a draw. | The input consists of three lines, each of the lines contains characters ".", "X" or "0" (a period, a capital letter X, or a digit zero). | Print one of the six verdicts: first, second, illegal, the first player won, the second player won or draw. | [
"X0X\n.0.\n.X.\n"
] | [
"second\n"
] | none | 0 | [
{
"input": "X0X\n.0.\n.X.",
"output": "second"
},
{
"input": "0.X\nXX.\n000",
"output": "illegal"
},
{
"input": "XXX\n.0.\n000",
"output": "illegal"
},
{
"input": "XXX\n...\n000",
"output": "illegal"
},
{
"input": "X.X\nX..\n00.",
"output": "second"
},
{
... | 1,556,138,073 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 154 | 307,200 | def C(ttt):
n = 3
XCount = 0
emptyCount = 0
YCount = 0
for i in range(n):
for j in range(n-2):
if ttt[i][j] + ttt[i][j+1] + ttt[i][j+2] == "XXX" or ttt[j][i]+ttt[j+1][i]+ttt[j+2][i] == "XXX":
return "the first player won"
elif ttt[i][j] + ttt[i][j+1] + ttt[i][j+2] == "000" or ttt[j][i]+ttt[j+1][i]+ttt[j+2][i] == "000":
return "the second player won"
if ttt[i][j] == "X":
XCount += 1
elif ttt[i][j] == "Y":
YCount += 1
elif ttt[i][j] == ".":
emptyCount += 1
else:
return "illegal"
if XCount > YCount:
return "second"
elif XCount > YCount:
return "first"
else:
return "draw"
if __name__ == "__main__":
ttt = [[0 for i in range(3)] for j in range(3)]
for i in range(3):
ttt[i] = list(input())
print(C(ttt)) | Title: Tic-tac-toe
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Certainly, everyone is familiar with tic-tac-toe game. The rules are very simple indeed. Two players take turns marking the cells in a 3<=×<=3 grid (one player always draws crosses, the other — noughts). The player who succeeds first in placing three of his marks in a horizontal, vertical or diagonal line wins, and the game is finished. The player who draws crosses goes first. If the grid is filled, but neither Xs, nor 0s form the required line, a draw is announced.
You are given a 3<=×<=3 grid, each grid cell is empty, or occupied by a cross or a nought. You have to find the player (first or second), whose turn is next, or print one of the verdicts below:
- illegal — if the given board layout can't appear during a valid game; - the first player won — if in the given board layout the first player has just won; - the second player won — if in the given board layout the second player has just won; - draw — if the given board layout has just let to a draw.
Input Specification:
The input consists of three lines, each of the lines contains characters ".", "X" or "0" (a period, a capital letter X, or a digit zero).
Output Specification:
Print one of the six verdicts: first, second, illegal, the first player won, the second player won or draw.
Demo Input:
['X0X\n.0.\n.X.\n']
Demo Output:
['second\n']
Note:
none | ```python
def C(ttt):
n = 3
XCount = 0
emptyCount = 0
YCount = 0
for i in range(n):
for j in range(n-2):
if ttt[i][j] + ttt[i][j+1] + ttt[i][j+2] == "XXX" or ttt[j][i]+ttt[j+1][i]+ttt[j+2][i] == "XXX":
return "the first player won"
elif ttt[i][j] + ttt[i][j+1] + ttt[i][j+2] == "000" or ttt[j][i]+ttt[j+1][i]+ttt[j+2][i] == "000":
return "the second player won"
if ttt[i][j] == "X":
XCount += 1
elif ttt[i][j] == "Y":
YCount += 1
elif ttt[i][j] == ".":
emptyCount += 1
else:
return "illegal"
if XCount > YCount:
return "second"
elif XCount > YCount:
return "first"
else:
return "draw"
if __name__ == "__main__":
ttt = [[0 for i in range(3)] for j in range(3)]
for i in range(3):
ttt[i] = list(input())
print(C(ttt))
``` | 0 |
689 | C | Mike and Chocolate Thieves | PROGRAMMING | 1,700 | [
"binary search",
"combinatorics",
"math"
] | null | null | Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly *k* times more than the previous one. The value of *k* (*k*<=><=1) is a secret integer known only to them. It is also known that each thief's bag can carry at most *n* chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of *n*, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed *n*, but not fixed *k*) is *m*. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of *n* will help him in that. Please find the smallest possible value of *n* or tell him that the rumors are false and there is no such *n*. | The single line of input contains the integer *m* (1<=≤<=*m*<=≤<=1015) — the number of ways the thieves might steal the chocolates, as rumours say. | Print the only integer *n* — the maximum amount of chocolates that thieves' bags can carry. If there are more than one *n* satisfying the rumors, print the smallest one.
If there is no such *n* for a false-rumoured *m*, print <=-<=1. | [
"1\n",
"8\n",
"10\n"
] | [
"8\n",
"54\n",
"-1\n"
] | In the first sample case the smallest *n* that leads to exactly one way of stealing chocolates is *n* = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest *n* that leads to exactly 8 ways is *n* = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no *n* leading to exactly 10 ways of stealing chocolates in the third sample case. | 1,500 | [
{
"input": "1",
"output": "8"
},
{
"input": "8",
"output": "54"
},
{
"input": "10",
"output": "-1"
},
{
"input": "27",
"output": "152"
},
{
"input": "28206",
"output": "139840"
},
{
"input": "32",
"output": "184"
},
{
"input": "115",
"o... | 1,673,432,734 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 2,560,000 | def count(k):
#print("testcase",k)
c=0
for i in range(1,k+1):
c+=int(round((k//i)**(1/3),3))-1
#print(c)
return(c)
m=int(input())
l=0
h=(m+1)**3
t=0
while(l<=h):
t+=1
#print('iteration',t)
#t+=1
#if(t>20):
# break
mid=(l+h)//2
#k=int(mid**(1/3))
#print(mid)
c=count(mid)
#print(c)
if(c<m):
l=mid+1
else:
h=mid-1
#else:
# print(mid)
# print(l,h)
# break
#print(l,h)
if(c==m):
#print(l)
print(l)
else:
print(-1) | Title: Mike and Chocolate Thieves
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly *k* times more than the previous one. The value of *k* (*k*<=><=1) is a secret integer known only to them. It is also known that each thief's bag can carry at most *n* chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of *n*, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed *n*, but not fixed *k*) is *m*. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of *n* will help him in that. Please find the smallest possible value of *n* or tell him that the rumors are false and there is no such *n*.
Input Specification:
The single line of input contains the integer *m* (1<=≤<=*m*<=≤<=1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output Specification:
Print the only integer *n* — the maximum amount of chocolates that thieves' bags can carry. If there are more than one *n* satisfying the rumors, print the smallest one.
If there is no such *n* for a false-rumoured *m*, print <=-<=1.
Demo Input:
['1\n', '8\n', '10\n']
Demo Output:
['8\n', '54\n', '-1\n']
Note:
In the first sample case the smallest *n* that leads to exactly one way of stealing chocolates is *n* = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest *n* that leads to exactly 8 ways is *n* = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no *n* leading to exactly 10 ways of stealing chocolates in the third sample case. | ```python
def count(k):
#print("testcase",k)
c=0
for i in range(1,k+1):
c+=int(round((k//i)**(1/3),3))-1
#print(c)
return(c)
m=int(input())
l=0
h=(m+1)**3
t=0
while(l<=h):
t+=1
#print('iteration',t)
#t+=1
#if(t>20):
# break
mid=(l+h)//2
#k=int(mid**(1/3))
#print(mid)
c=count(mid)
#print(c)
if(c<m):
l=mid+1
else:
h=mid-1
#else:
# print(mid)
# print(l,h)
# break
#print(l,h)
if(c==m):
#print(l)
print(l)
else:
print(-1)
``` | 0 | |
702 | C | Cellular Network | PROGRAMMING | 1,500 | [
"binary search",
"implementation",
"two pointers"
] | null | null | You are given *n* points on the straight line — the positions (*x*-coordinates) of the cities and *m* points on the same line — the positions (*x*-coordinates) of the cellular towers. All towers work in the same way — they provide cellular network for all cities, which are located at the distance which is no more than *r* from this tower.
Your task is to find minimal *r* that each city has been provided by cellular network, i.e. for each city there is at least one cellular tower at the distance which is no more than *r*.
If *r*<==<=0 then a tower provides cellular network only for the point where it is located. One tower can provide cellular network for any number of cities, but all these cities must be at the distance which is no more than *r* from this tower. | The first line contains two positive integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of cities and the number of cellular towers.
The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109) — the coordinates of cities. It is allowed that there are any number of cities in the same point. All coordinates *a**i* are given in non-decreasing order.
The third line contains a sequence of *m* integers *b*1,<=*b*2,<=...,<=*b**m* (<=-<=109<=≤<=*b**j*<=≤<=109) — the coordinates of cellular towers. It is allowed that there are any number of towers in the same point. All coordinates *b**j* are given in non-decreasing order. | Print minimal *r* so that each city will be covered by cellular network. | [
"3 2\n-2 2 4\n-3 0\n",
"5 3\n1 5 10 14 17\n4 11 15\n"
] | [
"4\n",
"3\n"
] | none | 0 | [
{
"input": "3 2\n-2 2 4\n-3 0",
"output": "4"
},
{
"input": "5 3\n1 5 10 14 17\n4 11 15",
"output": "3"
},
{
"input": "1 1\n-1000000000\n1000000000",
"output": "2000000000"
},
{
"input": "1 1\n1000000000\n-1000000000",
"output": "2000000000"
},
{
"input": "10 10\n... | 1,687,853,277 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n, m = map(int, input().split())
N = list(map(int, input().split()))
M = list(map(int, input().split()))
i = 0
j = 0
ans = [float('inf')]*n
while not (i==n-1 and j == m-1):
print(i, j)
ans[i] = min(ans[i], abs(M[j] - N[i]))
if N[i] < M[j]:
if i == n-1:
j = min(j+1, m-1)
else:
i = min(i+1, n-1)
elif N[i] > M[j]:
if j == m-1:
i = min(i+1, n-1)
else:
j = min(j+1, m-1)
else:
j = min(j+1, m-1)
i = min(i+1, n-1)
ans[i] = min(ans[i], abs(M[j] - N[i]))
print(max(ans)) | Title: Cellular Network
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* points on the straight line — the positions (*x*-coordinates) of the cities and *m* points on the same line — the positions (*x*-coordinates) of the cellular towers. All towers work in the same way — they provide cellular network for all cities, which are located at the distance which is no more than *r* from this tower.
Your task is to find minimal *r* that each city has been provided by cellular network, i.e. for each city there is at least one cellular tower at the distance which is no more than *r*.
If *r*<==<=0 then a tower provides cellular network only for the point where it is located. One tower can provide cellular network for any number of cities, but all these cities must be at the distance which is no more than *r* from this tower.
Input Specification:
The first line contains two positive integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of cities and the number of cellular towers.
The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109) — the coordinates of cities. It is allowed that there are any number of cities in the same point. All coordinates *a**i* are given in non-decreasing order.
The third line contains a sequence of *m* integers *b*1,<=*b*2,<=...,<=*b**m* (<=-<=109<=≤<=*b**j*<=≤<=109) — the coordinates of cellular towers. It is allowed that there are any number of towers in the same point. All coordinates *b**j* are given in non-decreasing order.
Output Specification:
Print minimal *r* so that each city will be covered by cellular network.
Demo Input:
['3 2\n-2 2 4\n-3 0\n', '5 3\n1 5 10 14 17\n4 11 15\n']
Demo Output:
['4\n', '3\n']
Note:
none | ```python
n, m = map(int, input().split())
N = list(map(int, input().split()))
M = list(map(int, input().split()))
i = 0
j = 0
ans = [float('inf')]*n
while not (i==n-1 and j == m-1):
print(i, j)
ans[i] = min(ans[i], abs(M[j] - N[i]))
if N[i] < M[j]:
if i == n-1:
j = min(j+1, m-1)
else:
i = min(i+1, n-1)
elif N[i] > M[j]:
if j == m-1:
i = min(i+1, n-1)
else:
j = min(j+1, m-1)
else:
j = min(j+1, m-1)
i = min(i+1, n-1)
ans[i] = min(ans[i], abs(M[j] - N[i]))
print(max(ans))
``` | 0 | |
556 | A | Case of the Zeros and Ones | PROGRAMMING | 900 | [
"greedy"
] | null | null | Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, and the other contains 1, then we are allowed to remove these two digits from the string, obtaining a string of length *n*<=-<=2 as a result.
Now Andreid thinks about what is the minimum length of the string that can remain after applying the described operation several times (possibly, zero)? Help him to calculate this number. | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=2·105), the length of the string that Andreid has.
The second line contains the string of length *n* consisting only from zeros and ones. | Output the minimum length of the string that may remain after applying the described operations several times. | [
"4\n1100\n",
"5\n01010\n",
"8\n11101111\n"
] | [
"0\n",
"1\n",
"6\n"
] | In the first sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/10df55364c21c6e8d5da31b6ab6f6294c4fc26b3.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/19ec5dcd85f0b5cf757aa076ace72df39634de2d.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the third sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/dc34a159e4230375fa325555527ebc748811f188.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 250 | [
{
"input": "4\n1100",
"output": "0"
},
{
"input": "5\n01010",
"output": "1"
},
{
"input": "8\n11101111",
"output": "6"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "2"
},
{
"input"... | 1,679,113,567 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 11 | 1,000 | 307,200 | n = input()
string = input()
index1 = 0
index2 = 1
for i in range(int(n)):
if len(string) == 1 or '1' not in string or '0' not in string:
break
if string[index1] + string[index2] == '01' or string[index1] + string[index2] == '10':
if index1 == 0:
string = string[2:len(string)]
else:
string = string[:index1] + string[index2 + 1:]
index1=0
index2=1
else:
index1+=1
index2+=1
print(len(string))
| Title: Case of the Zeros and Ones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, and the other contains 1, then we are allowed to remove these two digits from the string, obtaining a string of length *n*<=-<=2 as a result.
Now Andreid thinks about what is the minimum length of the string that can remain after applying the described operation several times (possibly, zero)? Help him to calculate this number.
Input Specification:
First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=2·105), the length of the string that Andreid has.
The second line contains the string of length *n* consisting only from zeros and ones.
Output Specification:
Output the minimum length of the string that may remain after applying the described operations several times.
Demo Input:
['4\n1100\n', '5\n01010\n', '8\n11101111\n']
Demo Output:
['0\n', '1\n', '6\n']
Note:
In the first sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/10df55364c21c6e8d5da31b6ab6f6294c4fc26b3.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/19ec5dcd85f0b5cf757aa076ace72df39634de2d.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the third sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/dc34a159e4230375fa325555527ebc748811f188.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | ```python
n = input()
string = input()
index1 = 0
index2 = 1
for i in range(int(n)):
if len(string) == 1 or '1' not in string or '0' not in string:
break
if string[index1] + string[index2] == '01' or string[index1] + string[index2] == '10':
if index1 == 0:
string = string[2:len(string)]
else:
string = string[:index1] + string[index2 + 1:]
index1=0
index2=1
else:
index1+=1
index2+=1
print(len(string))
``` | 0 | |
701 | A | Cards | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one player.
Find the way to distribute cards such that the sum of values written of the cards will be equal for each player. It is guaranteed that it is always possible. | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100) — the number of cards in the deck. It is guaranteed that *n* is even.
The second line contains the sequence of *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is equal to the number written on the *i*-th card. | Print *n*<=/<=2 pairs of integers, the *i*-th pair denote the cards that should be given to the *i*-th player. Each card should be given to exactly one player. Cards are numbered in the order they appear in the input.
It is guaranteed that solution exists. If there are several correct answers, you are allowed to print any of them. | [
"6\n1 5 7 4 4 3\n",
"4\n10 10 10 10\n"
] | [
"1 3\n6 2\n4 5\n",
"1 2\n3 4\n"
] | In the first sample, cards are distributed in such a way that each player has the sum of numbers written on his cards equal to 8.
In the second sample, all values *a*<sub class="lower-index">*i*</sub> are equal. Thus, any distribution is acceptable. | 500 | [
{
"input": "6\n1 5 7 4 4 3",
"output": "1 3\n6 2\n4 5"
},
{
"input": "4\n10 10 10 10",
"output": "1 4\n2 3"
},
{
"input": "100\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,590,062,218 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 109 | 0 | n=int(input())
a=list(map(int,input().split()))
r=[]
for i in range(n):
r.append([a[i],i+1])
r.sort()
for i in range(n//2):
print(r[i][1],r[n-i-1][1])
| Title: Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one player.
Find the way to distribute cards such that the sum of values written of the cards will be equal for each player. It is guaranteed that it is always possible.
Input Specification:
The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100) — the number of cards in the deck. It is guaranteed that *n* is even.
The second line contains the sequence of *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is equal to the number written on the *i*-th card.
Output Specification:
Print *n*<=/<=2 pairs of integers, the *i*-th pair denote the cards that should be given to the *i*-th player. Each card should be given to exactly one player. Cards are numbered in the order they appear in the input.
It is guaranteed that solution exists. If there are several correct answers, you are allowed to print any of them.
Demo Input:
['6\n1 5 7 4 4 3\n', '4\n10 10 10 10\n']
Demo Output:
['1 3\n6 2\n4 5\n', '1 2\n3 4\n']
Note:
In the first sample, cards are distributed in such a way that each player has the sum of numbers written on his cards equal to 8.
In the second sample, all values *a*<sub class="lower-index">*i*</sub> are equal. Thus, any distribution is acceptable. | ```python
n=int(input())
a=list(map(int,input().split()))
r=[]
for i in range(n):
r.append([a[i],i+1])
r.sort()
for i in range(n//2):
print(r[i][1],r[n-i-1][1])
``` | 3 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,695,352,442 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | import math
dimension = input()
dimLst = [int(i) for i in dimension.split()]
n = dimLst[0]
m = dimLst[1]
a = dimLst[2]
vert = math.ceil((n/a))
hor = math.ceil((m/a))
num = vert*hor
print(num)
| Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.
Input Specification:
The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).
Output Specification:
Write the needed number of flagstones.
Demo Input:
['6 6 4\n']
Demo Output:
['4\n']
Note:
none | ```python
import math
dimension = input()
dimLst = [int(i) for i in dimension.split()]
n = dimLst[0]
m = dimLst[1]
a = dimLst[2]
vert = math.ceil((n/a))
hor = math.ceil((m/a))
num = vert*hor
print(num)
``` | 3.977 |
479 | A | Expression | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let's consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets:
- 1+2*3=7 - 1*(2+3)=5 - 1*2*3=6 - (1+2)*3=9
Note that you can insert operation signs only between *a* and *b*, and between *b* and *c*, that is, you cannot swap integers. For instance, in the given sample you cannot get expression (1+3)*2.
It's easy to see that the maximum value that you can obtain is 9.
Your task is: given *a*, *b* and *c* print the maximum value that you can get. | The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10). | Print the maximum value of the expression that you can obtain. | [
"1\n2\n3\n",
"2\n10\n3\n"
] | [
"9\n",
"60\n"
] | none | 500 | [
{
"input": "1\n2\n3",
"output": "9"
},
{
"input": "2\n10\n3",
"output": "60"
},
{
"input": "1\n1\n1",
"output": "3"
},
{
"input": "1\n2\n1",
"output": "4"
},
{
"input": "10\n10\n10",
"output": "1000"
},
{
"input": "5\n1\n3",
"output": "20"
},
{... | 1,688,146,961 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | a = int(input())
b = int(input())
c = int(input())
numbers = [a, b, c]
numbers.sort()
x = (numbers[0] * numbers[1] * numbers[2])
y = (numbers[0] + numbers[1]) * numbers[2]
if x > y:
print(x)
elif x == y:
print(x)
else:
print(y) | Title: Expression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let's consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets:
- 1+2*3=7 - 1*(2+3)=5 - 1*2*3=6 - (1+2)*3=9
Note that you can insert operation signs only between *a* and *b*, and between *b* and *c*, that is, you cannot swap integers. For instance, in the given sample you cannot get expression (1+3)*2.
It's easy to see that the maximum value that you can obtain is 9.
Your task is: given *a*, *b* and *c* print the maximum value that you can get.
Input Specification:
The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10).
Output Specification:
Print the maximum value of the expression that you can obtain.
Demo Input:
['1\n2\n3\n', '2\n10\n3\n']
Demo Output:
['9\n', '60\n']
Note:
none | ```python
a = int(input())
b = int(input())
c = int(input())
numbers = [a, b, c]
numbers.sort()
x = (numbers[0] * numbers[1] * numbers[2])
y = (numbers[0] + numbers[1]) * numbers[2]
if x > y:
print(x)
elif x == y:
print(x)
else:
print(y)
``` | 0 | |
26 | A | Almost Prime | PROGRAMMING | 900 | [
"number theory"
] | A. Almost Prime | 2 | 256 | A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive. | Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000). | Output the amount of almost prime numbers between 1 and *n*, inclusive. | [
"10\n",
"21\n"
] | [
"2\n",
"8\n"
] | none | 500 | [
{
"input": "10",
"output": "2"
},
{
"input": "21",
"output": "8"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "8",
"output": "1"
},
... | 1,680,276,390 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 92 | 102,400 | from collections import defaultdict
def isprime(n):
arr = defaultdict(int)
d = 2
while d*d <= n:
while n % d == 0:
n //= d
arr[d] += 1
if len(arr) > 2:
return False
d += 1
if n > 1:
arr[n] += 1
return True if len(arr) == 2 else False
n = int(input())
count = 0
for i in range(2,n+1):
if isprime(i):
count += 1
print(count)
| Title: Almost Prime
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive.
Input Specification:
Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000).
Output Specification:
Output the amount of almost prime numbers between 1 and *n*, inclusive.
Demo Input:
['10\n', '21\n']
Demo Output:
['2\n', '8\n']
Note:
none | ```python
from collections import defaultdict
def isprime(n):
arr = defaultdict(int)
d = 2
while d*d <= n:
while n % d == 0:
n //= d
arr[d] += 1
if len(arr) > 2:
return False
d += 1
if n > 1:
arr[n] += 1
return True if len(arr) == 2 else False
n = int(input())
count = 0
for i in range(2,n+1):
if isprime(i):
count += 1
print(count)
``` | 3.976809 |
126 | B | Password | PROGRAMMING | 1,700 | [
"binary search",
"dp",
"hashing",
"string suffix structures",
"strings"
] | null | null | Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring *t* of the string *s*.
Prefix supposed that the substring *t* is the beginning of the string *s*; Suffix supposed that the substring *t* should be the end of the string *s*; and Obelix supposed that *t* should be located somewhere inside the string *s*, that is, *t* is neither its beginning, nor its end.
Asterix chose the substring *t* so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring *t* aloud, the temple doors opened.
You know the string *s*. Find the substring *t* or determine that such substring does not exist and all that's been written above is just a nice legend. | You are given the string *s* whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters. | Print the string *t*. If a suitable *t* string does not exist, then print "Just a legend" without the quotes. | [
"fixprefixsuffix\n",
"abcdabc\n"
] | [
"fix",
"Just a legend"
] | none | 1,000 | [
{
"input": "fixprefixsuffix",
"output": "fix"
},
{
"input": "abcdabc",
"output": "Just a legend"
},
{
"input": "qwertyqwertyqwerty",
"output": "qwerty"
},
{
"input": "papapapap",
"output": "papap"
},
{
"input": "aaaaaaaaaa",
"output": "aaaaaaaa"
},
{
"... | 1,632,112,003 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 24 | 2,000 | 10,956,800 | # This code is contributed by Siddharth
from sys import *
input = stdin.readline
import random
from bisect import *
import math
from collections import *
import operator
from heapq import *
from itertools import *
inf=10**18
mod=10**9+7
MOD=998244353
s1 = 'abcdefghijklmnopqrstuvwxyz'
s2 = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
# inverse modulo power pow(a,-1,mod) - it only works on py 3.8 ( *not in pypy )
# ==========================================> Code Starts Here <=====================================================================
# This code is contributed by Siddharth
from sys import *
input = stdin.readline
import threading
from bisect import *
import math
from collections import *
import operator
from heapq import *
from itertools import *
inf=10**18
mod=10**9+9
MOD=998244353
S1 = 'abcdefghijklmnopqrstuvwxyz'
S2 = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
drow = [0, 1, 0, -1]
dcol = [-1, 0, 1, 0]
# inverse modulo power pow(a,-1,mod) - it only works on py 3.8 ( *not in pypy )
setrecursionlimit(10**5)
def asc(c):
return ord(c)-97+1
# ==========================================> Code Starts Here <=====================================================================
def hash(s):
ans=asc(s[0])
p=31
pre.append(ans)
for i in range(1,len(s)):
ans+=(asc(s[i])*p)%mod
p=(p*31)%mod
pre.append(ans)
def get(l,r):
gg=pow(31,l,mod)
inv=pow(gg,-1,mod)
return ((pre[r+1]-pre[l])*inv)%mod
s=input()[:-1]
n=len(s)
pre=[0]
hash(s)
maxx=0
ans=False
for i in range(n-1):
temp=get(0,i)
pmet=get(n-i-1,n-1)
if temp==pmet:
for j in range(1,n-(i+1)):
if get(j,j+i)==temp:
ans=(i+1)
if ans:
print(s[0:ans])
else:
print("Just a legend")
| Title: Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring *t* of the string *s*.
Prefix supposed that the substring *t* is the beginning of the string *s*; Suffix supposed that the substring *t* should be the end of the string *s*; and Obelix supposed that *t* should be located somewhere inside the string *s*, that is, *t* is neither its beginning, nor its end.
Asterix chose the substring *t* so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring *t* aloud, the temple doors opened.
You know the string *s*. Find the substring *t* or determine that such substring does not exist and all that's been written above is just a nice legend.
Input Specification:
You are given the string *s* whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.
Output Specification:
Print the string *t*. If a suitable *t* string does not exist, then print "Just a legend" without the quotes.
Demo Input:
['fixprefixsuffix\n', 'abcdabc\n']
Demo Output:
['fix', 'Just a legend']
Note:
none | ```python
# This code is contributed by Siddharth
from sys import *
input = stdin.readline
import random
from bisect import *
import math
from collections import *
import operator
from heapq import *
from itertools import *
inf=10**18
mod=10**9+7
MOD=998244353
s1 = 'abcdefghijklmnopqrstuvwxyz'
s2 = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
# inverse modulo power pow(a,-1,mod) - it only works on py 3.8 ( *not in pypy )
# ==========================================> Code Starts Here <=====================================================================
# This code is contributed by Siddharth
from sys import *
input = stdin.readline
import threading
from bisect import *
import math
from collections import *
import operator
from heapq import *
from itertools import *
inf=10**18
mod=10**9+9
MOD=998244353
S1 = 'abcdefghijklmnopqrstuvwxyz'
S2 = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
drow = [0, 1, 0, -1]
dcol = [-1, 0, 1, 0]
# inverse modulo power pow(a,-1,mod) - it only works on py 3.8 ( *not in pypy )
setrecursionlimit(10**5)
def asc(c):
return ord(c)-97+1
# ==========================================> Code Starts Here <=====================================================================
def hash(s):
ans=asc(s[0])
p=31
pre.append(ans)
for i in range(1,len(s)):
ans+=(asc(s[i])*p)%mod
p=(p*31)%mod
pre.append(ans)
def get(l,r):
gg=pow(31,l,mod)
inv=pow(gg,-1,mod)
return ((pre[r+1]-pre[l])*inv)%mod
s=input()[:-1]
n=len(s)
pre=[0]
hash(s)
maxx=0
ans=False
for i in range(n-1):
temp=get(0,i)
pmet=get(n-i-1,n-1)
if temp==pmet:
for j in range(1,n-(i+1)):
if get(j,j+i)==temp:
ans=(i+1)
if ans:
print(s[0:ans])
else:
print("Just a legend")
``` | 0 | |
245 | A | System Administrator | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus is a system administrator. There are two servers under his strict guidance — *a* and *b*. To stay informed about the servers' performance, Polycarpus executes commands "ping a" and "ping b". Each ping command sends exactly ten packets to the server specified in the argument of the command. Executing a program results in two integers *x* and *y* (*x*<=+<=*y*<==<=10; *x*,<=*y*<=≥<=0). These numbers mean that *x* packets successfully reached the corresponding server through the network and *y* packets were lost.
Today Polycarpus has performed overall *n* ping commands during his workday. Now for each server Polycarpus wants to know whether the server is "alive" or not. Polycarpus thinks that the server is "alive", if at least half of the packets that we send to this server reached it successfully along the network.
Help Polycarpus, determine for each server, whether it is "alive" or not by the given commands and their results. | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=1000) — the number of commands Polycarpus has fulfilled. Each of the following *n* lines contains three integers — the description of the commands. The *i*-th of these lines contains three space-separated integers *t**i*, *x**i*, *y**i* (1<=≤<=*t**i*<=≤<=2; *x**i*,<=*y**i*<=≥<=0; *x**i*<=+<=*y**i*<==<=10). If *t**i*<==<=1, then the *i*-th command is "ping a", otherwise the *i*-th command is "ping b". Numbers *x**i*, *y**i* represent the result of executing this command, that is, *x**i* packets reached the corresponding server successfully and *y**i* packets were lost.
It is guaranteed that the input has at least one "ping a" command and at least one "ping b" command. | In the first line print string "LIVE" (without the quotes) if server *a* is "alive", otherwise print "DEAD" (without the quotes).
In the second line print the state of server *b* in the similar format. | [
"2\n1 5 5\n2 6 4\n",
"3\n1 0 10\n2 0 10\n1 10 0\n"
] | [
"LIVE\nLIVE\n",
"LIVE\nDEAD\n"
] | Consider the first test case. There 10 packets were sent to server *a*, 5 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network. Overall there were 10 packets sent to server *b*, 6 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network.
Consider the second test case. There were overall 20 packages sent to server *a*, 10 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network. Overall 10 packets were sent to server *b*, 0 of them reached it. Therefore, less than half of all packets sent to this server successfully reached it through the network. | 0 | [
{
"input": "2\n1 5 5\n2 6 4",
"output": "LIVE\nLIVE"
},
{
"input": "3\n1 0 10\n2 0 10\n1 10 0",
"output": "LIVE\nDEAD"
},
{
"input": "10\n1 3 7\n2 4 6\n1 2 8\n2 5 5\n2 10 0\n2 10 0\n1 8 2\n2 2 8\n2 10 0\n1 1 9",
"output": "DEAD\nLIVE"
},
{
"input": "11\n1 8 2\n1 6 4\n1 9 1\n1... | 1,552,783,269 | 2,147,483,647 | Python 3 | OK | TESTS | 13 | 218 | 0 | n = int(input())
result1 = 0
result2 = 0
for i in range(n):
ttt, pos, neg = list(map(int, input().split()))
if ttt == 1:
result1 += pos-neg
else:
result2 += pos-neg
print('LIVE' if result1 >= 0 else 'DEAD')
print('LIVE' if result2 >= 0 else 'DEAD') | Title: System Administrator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus is a system administrator. There are two servers under his strict guidance — *a* and *b*. To stay informed about the servers' performance, Polycarpus executes commands "ping a" and "ping b". Each ping command sends exactly ten packets to the server specified in the argument of the command. Executing a program results in two integers *x* and *y* (*x*<=+<=*y*<==<=10; *x*,<=*y*<=≥<=0). These numbers mean that *x* packets successfully reached the corresponding server through the network and *y* packets were lost.
Today Polycarpus has performed overall *n* ping commands during his workday. Now for each server Polycarpus wants to know whether the server is "alive" or not. Polycarpus thinks that the server is "alive", if at least half of the packets that we send to this server reached it successfully along the network.
Help Polycarpus, determine for each server, whether it is "alive" or not by the given commands and their results.
Input Specification:
The first line contains a single integer *n* (2<=≤<=*n*<=≤<=1000) — the number of commands Polycarpus has fulfilled. Each of the following *n* lines contains three integers — the description of the commands. The *i*-th of these lines contains three space-separated integers *t**i*, *x**i*, *y**i* (1<=≤<=*t**i*<=≤<=2; *x**i*,<=*y**i*<=≥<=0; *x**i*<=+<=*y**i*<==<=10). If *t**i*<==<=1, then the *i*-th command is "ping a", otherwise the *i*-th command is "ping b". Numbers *x**i*, *y**i* represent the result of executing this command, that is, *x**i* packets reached the corresponding server successfully and *y**i* packets were lost.
It is guaranteed that the input has at least one "ping a" command and at least one "ping b" command.
Output Specification:
In the first line print string "LIVE" (without the quotes) if server *a* is "alive", otherwise print "DEAD" (without the quotes).
In the second line print the state of server *b* in the similar format.
Demo Input:
['2\n1 5 5\n2 6 4\n', '3\n1 0 10\n2 0 10\n1 10 0\n']
Demo Output:
['LIVE\nLIVE\n', 'LIVE\nDEAD\n']
Note:
Consider the first test case. There 10 packets were sent to server *a*, 5 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network. Overall there were 10 packets sent to server *b*, 6 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network.
Consider the second test case. There were overall 20 packages sent to server *a*, 10 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network. Overall 10 packets were sent to server *b*, 0 of them reached it. Therefore, less than half of all packets sent to this server successfully reached it through the network. | ```python
n = int(input())
result1 = 0
result2 = 0
for i in range(n):
ttt, pos, neg = list(map(int, input().split()))
if ttt == 1:
result1 += pos-neg
else:
result2 += pos-neg
print('LIVE' if result1 >= 0 else 'DEAD')
print('LIVE' if result2 >= 0 else 'DEAD')
``` | 3 | |
236 | A | Boy or Girl | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.
But yesterday, he came to see "her" in the real world and found out "she" is actually a very strong man! Our hero is very sad and he is too tired to love again now. So he came up with a way to recognize users' genders by their user names.
This is his method: if the number of distinct characters in one's user name is odd, then he is a male, otherwise she is a female. You are given the string that denotes the user name, please help our hero to determine the gender of this user by his method. | The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters. | If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes). | [
"wjmzbmr\n",
"xiaodao\n",
"sevenkplus\n"
] | [
"CHAT WITH HER!\n",
"IGNORE HIM!\n",
"CHAT WITH HER!\n"
] | For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!". | 500 | [
{
"input": "wjmzbmr",
"output": "CHAT WITH HER!"
},
{
"input": "xiaodao",
"output": "IGNORE HIM!"
},
{
"input": "sevenkplus",
"output": "CHAT WITH HER!"
},
{
"input": "pezu",
"output": "CHAT WITH HER!"
},
{
"input": "wnemlgppy",
"output": "CHAT WITH HER!"
},... | 1,699,722,369 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 92 | 0 | userName = str(input())
memorized = []
numOfRealLetters = 0
for i in userName:
if i in memorized:
continue
else:
memorized.append(i)
numOfRealLetters+=1
print("CHAT WITH HER!" if numOfRealLetters%2 == 0 else "IGNORE HIM!") | Title: Boy or Girl
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.
But yesterday, he came to see "her" in the real world and found out "she" is actually a very strong man! Our hero is very sad and he is too tired to love again now. So he came up with a way to recognize users' genders by their user names.
This is his method: if the number of distinct characters in one's user name is odd, then he is a male, otherwise she is a female. You are given the string that denotes the user name, please help our hero to determine the gender of this user by his method.
Input Specification:
The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters.
Output Specification:
If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes).
Demo Input:
['wjmzbmr\n', 'xiaodao\n', 'sevenkplus\n']
Demo Output:
['CHAT WITH HER!\n', 'IGNORE HIM!\n', 'CHAT WITH HER!\n']
Note:
For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!". | ```python
userName = str(input())
memorized = []
numOfRealLetters = 0
for i in userName:
if i in memorized:
continue
else:
memorized.append(i)
numOfRealLetters+=1
print("CHAT WITH HER!" if numOfRealLetters%2 == 0 else "IGNORE HIM!")
``` | 3 | |
219 | A | k-String | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
You are given a string *s*, consisting of lowercase English letters and a positive integer *k*. Your task is to reorder the letters in the string *s* in such a way that the resulting string is a *k*-string. | The first input line contains integer *k* (1<=≤<=*k*<=≤<=1000). The second line contains *s*, all characters in *s* are lowercase English letters. The string length *s* satisfies the inequality 1<=≤<=|*s*|<=≤<=1000, where |*s*| is the length of string *s*. | Rearrange the letters in string *s* in such a way that the result is a *k*-string. Print the result on a single output line. If there are multiple solutions, print any of them.
If the solution doesn't exist, print "-1" (without quotes). | [
"2\naazz\n",
"3\nabcabcabz\n"
] | [
"azaz\n",
"-1\n"
] | none | 500 | [
{
"input": "2\naazz",
"output": "azaz"
},
{
"input": "3\nabcabcabz",
"output": "-1"
},
{
"input": "1\na",
"output": "a"
},
{
"input": "2\nabba",
"output": "abab"
},
{
"input": "2\naaab",
"output": "-1"
},
{
"input": "7\nabacaba",
"output": "-1"
}... | 1,665,585,079 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | k=int(input())
s=input()
freq={}
for i in s:
if i in freq:
freq[i]+=1
else:
freq[i]=1
ans=''
flag=True
for i in freq:
if freq[i]//k!=freq[i]/k:
flag=False
break
else:
ans+=i*(freq[i]//k)
if flag==False:
print(-1)
else:
print(ans*k) | Title: k-String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
You are given a string *s*, consisting of lowercase English letters and a positive integer *k*. Your task is to reorder the letters in the string *s* in such a way that the resulting string is a *k*-string.
Input Specification:
The first input line contains integer *k* (1<=≤<=*k*<=≤<=1000). The second line contains *s*, all characters in *s* are lowercase English letters. The string length *s* satisfies the inequality 1<=≤<=|*s*|<=≤<=1000, where |*s*| is the length of string *s*.
Output Specification:
Rearrange the letters in string *s* in such a way that the result is a *k*-string. Print the result on a single output line. If there are multiple solutions, print any of them.
If the solution doesn't exist, print "-1" (without quotes).
Demo Input:
['2\naazz\n', '3\nabcabcabz\n']
Demo Output:
['azaz\n', '-1\n']
Note:
none | ```python
k=int(input())
s=input()
freq={}
for i in s:
if i in freq:
freq[i]+=1
else:
freq[i]=1
ans=''
flag=True
for i in freq:
if freq[i]//k!=freq[i]/k:
flag=False
break
else:
ans+=i*(freq[i]//k)
if flag==False:
print(-1)
else:
print(ans*k)
``` | 3 | |
10 | A | Power Consumption Calculation | PROGRAMMING | 900 | [
"implementation"
] | A. Power Consumption Calculation | 1 | 256 | Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard for the last time, a screensaver starts and power consumption changes to *P*2 watt per minute. Finally, after *T*2 minutes from the start of the screensaver, laptop switches to the "sleep" mode and consumes *P*3 watt per minute. If Tom moves the mouse or touches the keyboard when the laptop is in the second or in the third mode, it switches to the first (normal) mode. Tom's work with the laptop can be divided into *n* time periods [*l*1,<=*r*1],<=[*l*2,<=*r*2],<=...,<=[*l**n*,<=*r**n*]. During each interval Tom continuously moves the mouse and presses buttons on the keyboard. Between the periods Tom stays away from the laptop. Find out the total amount of power consumed by the laptop during the period [*l*1,<=*r**n*]. | The first line contains 6 integer numbers *n*, *P*1, *P*2, *P*3, *T*1, *T*2 (1<=≤<=*n*<=≤<=100,<=0<=≤<=*P*1,<=*P*2,<=*P*3<=≤<=100,<=1<=≤<=*T*1,<=*T*2<=≤<=60). The following *n* lines contain description of Tom's work. Each *i*-th of these lines contains two space-separated integers *l**i* and *r**i* (0<=≤<=*l**i*<=<<=*r**i*<=≤<=1440, *r**i*<=<<=*l**i*<=+<=1 for *i*<=<<=*n*), which stand for the start and the end of the *i*-th period of work. | Output the answer to the problem. | [
"1 3 2 1 5 10\n0 10\n",
"2 8 4 2 5 10\n20 30\n50 100\n"
] | [
"30",
"570"
] | none | 0 | [
{
"input": "1 3 2 1 5 10\n0 10",
"output": "30"
},
{
"input": "2 8 4 2 5 10\n20 30\n50 100",
"output": "570"
},
{
"input": "3 15 9 95 39 19\n873 989\n1003 1137\n1172 1436",
"output": "8445"
},
{
"input": "4 73 2 53 58 16\n51 52\n209 242\n281 407\n904 945",
"output": "5287... | 1,680,125,768 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | n, p1, p2, p3, t1, t2 = map(int, input().split())
prev = None
ans = 0
for _ in range(n):
l, r = map(int, input().split())
if prev is not None:
d = l - prev
ans += min(d, t1) * p1
d -= t1
if d > 0:
ans += min(d, t2) * p2
d -= t2
if d > 0:
ans += d * p3
ans += (r - l) * p1
prev = r
print(ans) | Title: Power Consumption Calculation
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard for the last time, a screensaver starts and power consumption changes to *P*2 watt per minute. Finally, after *T*2 minutes from the start of the screensaver, laptop switches to the "sleep" mode and consumes *P*3 watt per minute. If Tom moves the mouse or touches the keyboard when the laptop is in the second or in the third mode, it switches to the first (normal) mode. Tom's work with the laptop can be divided into *n* time periods [*l*1,<=*r*1],<=[*l*2,<=*r*2],<=...,<=[*l**n*,<=*r**n*]. During each interval Tom continuously moves the mouse and presses buttons on the keyboard. Between the periods Tom stays away from the laptop. Find out the total amount of power consumed by the laptop during the period [*l*1,<=*r**n*].
Input Specification:
The first line contains 6 integer numbers *n*, *P*1, *P*2, *P*3, *T*1, *T*2 (1<=≤<=*n*<=≤<=100,<=0<=≤<=*P*1,<=*P*2,<=*P*3<=≤<=100,<=1<=≤<=*T*1,<=*T*2<=≤<=60). The following *n* lines contain description of Tom's work. Each *i*-th of these lines contains two space-separated integers *l**i* and *r**i* (0<=≤<=*l**i*<=<<=*r**i*<=≤<=1440, *r**i*<=<<=*l**i*<=+<=1 for *i*<=<<=*n*), which stand for the start and the end of the *i*-th period of work.
Output Specification:
Output the answer to the problem.
Demo Input:
['1 3 2 1 5 10\n0 10\n', '2 8 4 2 5 10\n20 30\n50 100\n']
Demo Output:
['30', '570']
Note:
none | ```python
n, p1, p2, p3, t1, t2 = map(int, input().split())
prev = None
ans = 0
for _ in range(n):
l, r = map(int, input().split())
if prev is not None:
d = l - prev
ans += min(d, t1) * p1
d -= t1
if d > 0:
ans += min(d, t2) * p2
d -= t2
if d > 0:
ans += d * p3
ans += (r - l) * p1
prev = r
print(ans)
``` | 3.954 |
914 | A | Perfect Squares | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Given an array *a*1,<=*a*2,<=...,<=*a**n* of *n* integers, find the largest number in the array that is not a perfect square.
A number *x* is said to be a perfect square if there exists an integer *y* such that *x*<==<=*y*2. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=106<=≤<=*a**i*<=≤<=106) — the elements of the array.
It is guaranteed that at least one element of the array is not a perfect square. | Print the largest number in the array which is not a perfect square. It is guaranteed that an answer always exists. | [
"2\n4 2\n",
"8\n1 2 4 8 16 32 64 576\n"
] | [
"2\n",
"32\n"
] | In the first sample case, 4 is a perfect square, so the largest number in the array that is not a perfect square is 2. | 500 | [
{
"input": "2\n4 2",
"output": "2"
},
{
"input": "8\n1 2 4 8 16 32 64 576",
"output": "32"
},
{
"input": "3\n-1 -4 -9",
"output": "-1"
},
{
"input": "5\n918375 169764 598796 76602 538757",
"output": "918375"
},
{
"input": "5\n804610 765625 2916 381050 93025",
... | 1,633,071,248 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 77 | 20,172,800 | import math
def notSquare(x):
k = math.pow(x,0.5)
if k**2 == x:
return False
else:
return True
n=int(input())
a=list(map(int,input().split()))
mx=-10**9
for i in a:
if i<0:
mx = max(mx, i)
else:
if notSquare(i):
mx=max(mx, i)
print(mx) | Title: Perfect Squares
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Given an array *a*1,<=*a*2,<=...,<=*a**n* of *n* integers, find the largest number in the array that is not a perfect square.
A number *x* is said to be a perfect square if there exists an integer *y* such that *x*<==<=*y*2.
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=106<=≤<=*a**i*<=≤<=106) — the elements of the array.
It is guaranteed that at least one element of the array is not a perfect square.
Output Specification:
Print the largest number in the array which is not a perfect square. It is guaranteed that an answer always exists.
Demo Input:
['2\n4 2\n', '8\n1 2 4 8 16 32 64 576\n']
Demo Output:
['2\n', '32\n']
Note:
In the first sample case, 4 is a perfect square, so the largest number in the array that is not a perfect square is 2. | ```python
import math
def notSquare(x):
k = math.pow(x,0.5)
if k**2 == x:
return False
else:
return True
n=int(input())
a=list(map(int,input().split()))
mx=-10**9
for i in a:
if i<0:
mx = max(mx, i)
else:
if notSquare(i):
mx=max(mx, i)
print(mx)
``` | 0 | |
811 | B | Vladik and Complicated Book | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | null | null | Vladik had started reading a complicated book about algorithms containing *n* pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation *P*<==<=[*p*1,<=*p*2,<=...,<=*p**n*], where *p**i* denotes the number of page that should be read *i*-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation *P* from position *l* to position *r* inclusive, because she loves the order. For every of such sorting Vladik knows number *x* — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has *p**x* changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other. | First line contains two space-separated integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains *n* space-separated integers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — permutation *P*. Note that elements in permutation are distinct.
Each of the next *m* lines contains three space-separated integers *l**i*, *r**i*, *x**i* (1<=≤<=*l**i*<=≤<=*x**i*<=≤<=*r**i*<=≤<=*n*) — left and right borders of sorted subsegment in *i*-th sorting and position that is interesting to Vladik. | For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise. | [
"5 5\n5 4 3 2 1\n1 5 3\n1 3 1\n2 4 3\n4 4 4\n2 5 3\n",
"6 5\n1 4 3 2 5 6\n2 4 3\n1 6 2\n4 5 4\n1 3 3\n2 6 3\n"
] | [
"Yes\nNo\nYes\nYes\nNo\n",
"Yes\nNo\nYes\nNo\nYes\n"
] | Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes". 1. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No". 1. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes". 1. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes". 1. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No". | 1,000 | [
{
"input": "5 5\n5 4 3 2 1\n1 5 3\n1 3 1\n2 4 3\n4 4 4\n2 5 3",
"output": "Yes\nNo\nYes\nYes\nNo"
},
{
"input": "6 5\n1 4 3 2 5 6\n2 4 3\n1 6 2\n4 5 4\n1 3 3\n2 6 3",
"output": "Yes\nNo\nYes\nNo\nYes"
},
{
"input": "10 10\n10 1 6 7 9 8 4 3 5 2\n1 1 1\n4 4 4\n7 7 7\n3 3 3\n1 6 5\n2 6 2\n6... | 1,508,919,742 | 3,742 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 2,000 | 819,200 | n, m = map(int, input().split())
l1 = list(map(int,input().split()))
l2 = []
for i in range(m):
l,r,x = map(int,input().split())
l2 = l1[:]
a = l2[x-1]
b = 0
for j in range(l-1, r):
if(l2[j]< a):
b += 1
if l1[x] == l1[l+b]:
print("Yes")
else:
print("No")
| Title: Vladik and Complicated Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vladik had started reading a complicated book about algorithms containing *n* pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation *P*<==<=[*p*1,<=*p*2,<=...,<=*p**n*], where *p**i* denotes the number of page that should be read *i*-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation *P* from position *l* to position *r* inclusive, because she loves the order. For every of such sorting Vladik knows number *x* — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has *p**x* changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input Specification:
First line contains two space-separated integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains *n* space-separated integers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — permutation *P*. Note that elements in permutation are distinct.
Each of the next *m* lines contains three space-separated integers *l**i*, *r**i*, *x**i* (1<=≤<=*l**i*<=≤<=*x**i*<=≤<=*r**i*<=≤<=*n*) — left and right borders of sorted subsegment in *i*-th sorting and position that is interesting to Vladik.
Output Specification:
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Demo Input:
['5 5\n5 4 3 2 1\n1 5 3\n1 3 1\n2 4 3\n4 4 4\n2 5 3\n', '6 5\n1 4 3 2 5 6\n2 4 3\n1 6 2\n4 5 4\n1 3 3\n2 6 3\n']
Demo Output:
['Yes\nNo\nYes\nYes\nNo\n', 'Yes\nNo\nYes\nNo\nYes\n']
Note:
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes". 1. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No". 1. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes". 1. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes". 1. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No". | ```python
n, m = map(int, input().split())
l1 = list(map(int,input().split()))
l2 = []
for i in range(m):
l,r,x = map(int,input().split())
l2 = l1[:]
a = l2[x-1]
b = 0
for j in range(l-1, r):
if(l2[j]< a):
b += 1
if l1[x] == l1[l+b]:
print("Yes")
else:
print("No")
``` | 0 | |
148 | A | Insomnia cure | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | «One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entertained herself at best she could. Tonight she imagined that all dragons were here to steal her, and she was fighting them off. Every *k*-th dragon got punched in the face with a frying pan. Every *l*-th dragon got his tail shut into the balcony door. Every *m*-th dragon got his paws trampled with sharp heels. Finally, she threatened every *n*-th dragon to call her mom, and he withdrew in panic.
How many imaginary dragons suffered moral or physical damage tonight, if the princess counted a total of *d* dragons? | Input data contains integer numbers *k*,<=*l*,<=*m*,<=*n* and *d*, each number in a separate line (1<=≤<=*k*,<=*l*,<=*m*,<=*n*<=≤<=10, 1<=≤<=*d*<=≤<=105). | Output the number of damaged dragons. | [
"1\n2\n3\n4\n12\n",
"2\n3\n4\n5\n24\n"
] | [
"12\n",
"17\n"
] | In the first case every first dragon got punched with a frying pan. Some of the dragons suffered from other reasons as well, but the pan alone would be enough.
In the second case dragons 1, 7, 11, 13, 17, 19 and 23 escaped unharmed. | 1,000 | [
{
"input": "1\n2\n3\n4\n12",
"output": "12"
},
{
"input": "2\n3\n4\n5\n24",
"output": "17"
},
{
"input": "1\n1\n1\n1\n100000",
"output": "100000"
},
{
"input": "10\n9\n8\n7\n6",
"output": "0"
},
{
"input": "8\n4\n4\n3\n65437",
"output": "32718"
},
{
"i... | 1,697,022,706 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 216 | 30,720,000 | k = int(input())
l = int(input())
m = int(input())
n = int(input())
d = int(input())
dr = [k,l,m,n]
hit = [x for x in range(1,d+1)]
k = [x for x in range(0,d+1,k)]
l = [x for x in range(0,d+1,l)]
m = [x for x in range(0,d+1,m)]
n = [x for x in range(0,d+1,n)]
hit1 = k + l + m + n
hit1 = set(hit1)
print(len(hit1)-1) | Title: Insomnia cure
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
«One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entertained herself at best she could. Tonight she imagined that all dragons were here to steal her, and she was fighting them off. Every *k*-th dragon got punched in the face with a frying pan. Every *l*-th dragon got his tail shut into the balcony door. Every *m*-th dragon got his paws trampled with sharp heels. Finally, she threatened every *n*-th dragon to call her mom, and he withdrew in panic.
How many imaginary dragons suffered moral or physical damage tonight, if the princess counted a total of *d* dragons?
Input Specification:
Input data contains integer numbers *k*,<=*l*,<=*m*,<=*n* and *d*, each number in a separate line (1<=≤<=*k*,<=*l*,<=*m*,<=*n*<=≤<=10, 1<=≤<=*d*<=≤<=105).
Output Specification:
Output the number of damaged dragons.
Demo Input:
['1\n2\n3\n4\n12\n', '2\n3\n4\n5\n24\n']
Demo Output:
['12\n', '17\n']
Note:
In the first case every first dragon got punched with a frying pan. Some of the dragons suffered from other reasons as well, but the pan alone would be enough.
In the second case dragons 1, 7, 11, 13, 17, 19 and 23 escaped unharmed. | ```python
k = int(input())
l = int(input())
m = int(input())
n = int(input())
d = int(input())
dr = [k,l,m,n]
hit = [x for x in range(1,d+1)]
k = [x for x in range(0,d+1,k)]
l = [x for x in range(0,d+1,l)]
m = [x for x in range(0,d+1,m)]
n = [x for x in range(0,d+1,n)]
hit1 = k + l + m + n
hit1 = set(hit1)
print(len(hit1)-1)
``` | 3 | |
1,011 | B | Planning The Expedition | PROGRAMMING | 1,200 | [
"binary search",
"brute force",
"implementation"
] | null | null | Natasha is planning an expedition to Mars for $n$ people. One of the important tasks is to provide food for each participant.
The warehouse has $m$ daily food packages. Each package has some food type $a_i$.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant $j$ Natasha should select his food type $b_j$ and each day $j$-th participant will eat one food package of type $b_j$. The values $b_j$ for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above? | The first line contains two integers $n$ and $m$ ($1 \le n \le 100$, $1 \le m \le 100$) — the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers $a_1, a_2, \dots, a_m$ ($1 \le a_i \le 100$), where $a_i$ is the type of $i$-th food package. | Print the single integer — the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0. | [
"4 10\n1 5 2 1 1 1 2 5 7 2\n",
"100 1\n1\n",
"2 5\n5 4 3 2 1\n",
"3 9\n42 42 42 42 42 42 42 42 42\n"
] | [
"2\n",
"0\n",
"1\n",
"3\n"
] | In the first example, Natasha can assign type $1$ food to the first participant, the same type $1$ to the second, type $5$ to the third and type $2$ to the fourth. In this case, the expedition can last for $2$ days, since each participant can get two food packages of his food type (there will be used $4$ packages of type $1$, two packages of type $2$ and two packages of type $5$).
In the second example, there are $100$ participants and only $1$ food package. In this case, the expedition can't last even $1$ day. | 1,000 | [
{
"input": "4 10\n1 5 2 1 1 1 2 5 7 2",
"output": "2"
},
{
"input": "100 1\n1",
"output": "0"
},
{
"input": "2 5\n5 4 3 2 1",
"output": "1"
},
{
"input": "3 9\n42 42 42 42 42 42 42 42 42",
"output": "3"
},
{
"input": "1 1\n100",
"output": "1"
},
{
"inp... | 1,600,457,303 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 109 | 409,600 | from collections import defaultdict
d = defaultdict(int)
n,m = map(int,input().split())
if n > m:
print(0)
else:
food_type = list(map(int,input().split()))
for f in food_type:
d[f] += 1
d_ls = sorted(d.items(), key=lambda k: k[1], reverse=True)
max_d = min(d_ls[0][1], m//n)
ret = 0
for i in range(1, max_d+1):
s = sum([f[1] // i for f in d_ls])
if s < n:
ret = i-1
break
ret = max_d
print(ret)
| Title: Planning The Expedition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Natasha is planning an expedition to Mars for $n$ people. One of the important tasks is to provide food for each participant.
The warehouse has $m$ daily food packages. Each package has some food type $a_i$.
Each participant must eat exactly one food package each day. Due to extreme loads, each participant must eat the same food type throughout the expedition. Different participants may eat different (or the same) types of food.
Formally, for each participant $j$ Natasha should select his food type $b_j$ and each day $j$-th participant will eat one food package of type $b_j$. The values $b_j$ for different participants may be different.
What is the maximum possible number of days the expedition can last, following the requirements above?
Input Specification:
The first line contains two integers $n$ and $m$ ($1 \le n \le 100$, $1 \le m \le 100$) — the number of the expedition participants and the number of the daily food packages available.
The second line contains sequence of integers $a_1, a_2, \dots, a_m$ ($1 \le a_i \le 100$), where $a_i$ is the type of $i$-th food package.
Output Specification:
Print the single integer — the number of days the expedition can last. If it is not possible to plan the expedition for even one day, print 0.
Demo Input:
['4 10\n1 5 2 1 1 1 2 5 7 2\n', '100 1\n1\n', '2 5\n5 4 3 2 1\n', '3 9\n42 42 42 42 42 42 42 42 42\n']
Demo Output:
['2\n', '0\n', '1\n', '3\n']
Note:
In the first example, Natasha can assign type $1$ food to the first participant, the same type $1$ to the second, type $5$ to the third and type $2$ to the fourth. In this case, the expedition can last for $2$ days, since each participant can get two food packages of his food type (there will be used $4$ packages of type $1$, two packages of type $2$ and two packages of type $5$).
In the second example, there are $100$ participants and only $1$ food package. In this case, the expedition can't last even $1$ day. | ```python
from collections import defaultdict
d = defaultdict(int)
n,m = map(int,input().split())
if n > m:
print(0)
else:
food_type = list(map(int,input().split()))
for f in food_type:
d[f] += 1
d_ls = sorted(d.items(), key=lambda k: k[1], reverse=True)
max_d = min(d_ls[0][1], m//n)
ret = 0
for i in range(1, max_d+1):
s = sum([f[1] // i for f in d_ls])
if s < n:
ret = i-1
break
ret = max_d
print(ret)
``` | 0 | |
44 | E | Anfisa the Monkey | PROGRAMMING | 1,400 | [
"dp"
] | E. Anfisa the Monkey | 2 | 256 | Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into *k* lines not shorter than *a* and not longer than *b*, for the text to resemble human speech more. Help Anfisa. | The first line contains three integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=200, 1<=≤<=*a*<=≤<=*b*<=≤<=200). The second line contains a sequence of lowercase Latin letters — the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols. | Print *k* lines, each of which contains no less than *a* and no more than *b* symbols — Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print "No solution" (without quotes). | [
"3 2 5\nabrakadabra\n",
"4 1 2\nabrakadabra\n"
] | [
"ab\nrakad\nabra\n",
"No solution\n"
] | none | 0 | [
{
"input": "3 2 5\nabrakadabra",
"output": "abra\nkada\nbra"
},
{
"input": "4 1 2\nabrakadabra",
"output": "No solution"
},
{
"input": "3 1 2\nvgnfpo",
"output": "vg\nnf\npo"
},
{
"input": "5 3 4\nvrrdnhazvexzjfv",
"output": "vrr\ndnh\nazv\nexz\njfv"
},
{
"input":... | 1,556,097,103 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 216 | 0 | k,a,b = map(int,input().split())
s = input()
n = len(s)
x,y = n//k,n%k
item=1
if y==0:
item=0
if x+item>b or x<a:
print('No solution')
from sys import exit
exit()
e=0
for i in range(k):
if y>0:
print(s[e:e+x+1])
e+=x+1
y-=1
else:
print(s[e:e+x])
e+=x | Title: Anfisa the Monkey
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into *k* lines not shorter than *a* and not longer than *b*, for the text to resemble human speech more. Help Anfisa.
Input Specification:
The first line contains three integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=200, 1<=≤<=*a*<=≤<=*b*<=≤<=200). The second line contains a sequence of lowercase Latin letters — the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols.
Output Specification:
Print *k* lines, each of which contains no less than *a* and no more than *b* symbols — Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print "No solution" (without quotes).
Demo Input:
['3 2 5\nabrakadabra\n', '4 1 2\nabrakadabra\n']
Demo Output:
['ab\nrakad\nabra\n', 'No solution\n']
Note:
none | ```python
k,a,b = map(int,input().split())
s = input()
n = len(s)
x,y = n//k,n%k
item=1
if y==0:
item=0
if x+item>b or x<a:
print('No solution')
from sys import exit
exit()
e=0
for i in range(k):
if y>0:
print(s[e:e+x+1])
e+=x+1
y-=1
else:
print(s[e:e+x])
e+=x
``` | 3.946 |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpredictable place.
But to their great regret, the leave turned to be very short, so it will be enough to visit one of the three above named places. That's why Yakko, as the cleverest, came up with a truly genius idea: let each of the three roll an ordinary six-sided die, and the one with the highest amount of points will be the winner, and will take the other two to the place of his/her dreams.
Yakko thrown a die and got Y points, Wakko — W points. It was Dot's turn. But she didn't hurry. Dot wanted to know for sure what were her chances to visit Transylvania.
It is known that Yakko and Wakko are true gentlemen, that's why if they have the same amount of points with Dot, they will let Dot win. | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,668,929,361 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 124 | 0 |
y, w = map(int, input().split())
cnt = 7-max(y, w)
if(cnt==3):
print("1/2")
elif(cnt==2):
print("1/3")
elif(cnt==6):
print("1/1")
else:
print(str(cnt)+"/6") | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpredictable place.
But to their great regret, the leave turned to be very short, so it will be enough to visit one of the three above named places. That's why Yakko, as the cleverest, came up with a truly genius idea: let each of the three roll an ordinary six-sided die, and the one with the highest amount of points will be the winner, and will take the other two to the place of his/her dreams.
Yakko thrown a die and got Y points, Wakko — W points. It was Dot's turn. But she didn't hurry. Dot wanted to know for sure what were her chances to visit Transylvania.
It is known that Yakko and Wakko are true gentlemen, that's why if they have the same amount of points with Dot, they will let Dot win.
Input Specification:
The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls.
Output Specification:
Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1».
Demo Input:
['4 2\n']
Demo Output:
['1/2\n']
Note:
Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | ```python
y, w = map(int, input().split())
cnt = 7-max(y, w)
if(cnt==3):
print("1/2")
elif(cnt==2):
print("1/3")
elif(cnt==6):
print("1/1")
else:
print(str(cnt)+"/6")
``` | 0 |
729 | A | Interview with Oleg | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string *s* consisting of *n* lowercase English letters.
There is a filler word ogo in Oleg's speech. All words that can be obtained from ogo by adding go several times to the end of it are also considered to be fillers. For example, the words ogo, ogogo, ogogogo are fillers, but the words go, og, ogog, ogogog and oggo are not fillers.
The fillers have maximal size, for example, for ogogoo speech we can't consider ogo a filler and goo as a normal phrase. We should consider ogogo as a filler here.
To print the interview, Polycarp has to replace each of the fillers with three asterisks. Note that a filler word is replaced with exactly three asterisks regardless of its length.
Polycarp has dealt with this problem in no time. Can you do the same? The clock is ticking! | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the length of the interview.
The second line contains the string *s* of length *n*, consisting of lowercase English letters. | Print the interview text after the replacement of each of the fillers with "***". It is allowed for the substring "***" to have several consecutive occurences. | [
"7\naogogob\n",
"13\nogogmgogogogo\n",
"9\nogoogoogo\n"
] | [
"a***b\n",
"***gmg***\n",
"*********\n"
] | The first sample contains one filler word ogogo, so the interview for printing is "a***b".
The second sample contains two fillers ogo and ogogogo. Thus, the interview is transformed to "***gmg***". | 500 | [
{
"input": "7\naogogob",
"output": "a***b"
},
{
"input": "13\nogogmgogogogo",
"output": "***gmg***"
},
{
"input": "9\nogoogoogo",
"output": "*********"
},
{
"input": "32\nabcdefogoghijklmnogoopqrstuvwxyz",
"output": "abcdef***ghijklmn***opqrstuvwxyz"
},
{
"input":... | 1,479,633,089 | 389 | Python 3 | OK | TESTS | 48 | 77 | 0 | n = int(input())
s = input().strip()
rez = ''
i = 0
while i < len(s):
if s[i:i + 3] == 'ogo':
j = i + 3
while s[j:j + 2] == 'go':
j += 2
i = j
rez += '***'
else:
rez += s[i]
i += 1
print(rez) | Title: Interview with Oleg
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string *s* consisting of *n* lowercase English letters.
There is a filler word ogo in Oleg's speech. All words that can be obtained from ogo by adding go several times to the end of it are also considered to be fillers. For example, the words ogo, ogogo, ogogogo are fillers, but the words go, og, ogog, ogogog and oggo are not fillers.
The fillers have maximal size, for example, for ogogoo speech we can't consider ogo a filler and goo as a normal phrase. We should consider ogogo as a filler here.
To print the interview, Polycarp has to replace each of the fillers with three asterisks. Note that a filler word is replaced with exactly three asterisks regardless of its length.
Polycarp has dealt with this problem in no time. Can you do the same? The clock is ticking!
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the length of the interview.
The second line contains the string *s* of length *n*, consisting of lowercase English letters.
Output Specification:
Print the interview text after the replacement of each of the fillers with "***". It is allowed for the substring "***" to have several consecutive occurences.
Demo Input:
['7\naogogob\n', '13\nogogmgogogogo\n', '9\nogoogoogo\n']
Demo Output:
['a***b\n', '***gmg***\n', '*********\n']
Note:
The first sample contains one filler word ogogo, so the interview for printing is "a***b".
The second sample contains two fillers ogo and ogogogo. Thus, the interview is transformed to "***gmg***". | ```python
n = int(input())
s = input().strip()
rez = ''
i = 0
while i < len(s):
if s[i:i + 3] == 'ogo':
j = i + 3
while s[j:j + 2] == 'go':
j += 2
i = j
rez += '***'
else:
rez += s[i]
i += 1
print(rez)
``` | 3 | |
818 | A | Diplomas and Certificates | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | There are *n* students who have taken part in an olympiad. Now it's time to award the students.
Some of them will receive diplomas, some wiil get certificates, and others won't receive anything. Students with diplomas and certificates are called winners. But there are some rules of counting the number of diplomas and certificates. The number of certificates must be exactly *k* times greater than the number of diplomas. The number of winners must not be greater than half of the number of all students (i.e. not be greater than half of *n*). It's possible that there are no winners.
You have to identify the maximum possible number of winners, according to these rules. Also for this case you have to calculate the number of students with diplomas, the number of students with certificates and the number of students who are not winners. | The first (and the only) line of input contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1012), where *n* is the number of students and *k* is the ratio between the number of certificates and the number of diplomas. | Output three numbers: the number of students with diplomas, the number of students with certificates and the number of students who are not winners in case when the number of winners is maximum possible.
It's possible that there are no winners. | [
"18 2\n",
"9 10\n",
"1000000000000 5\n",
"1000000000000 499999999999\n"
] | [
"3 6 9\n",
"0 0 9\n",
"83333333333 416666666665 500000000002\n",
"1 499999999999 500000000000\n"
] | none | 0 | [
{
"input": "18 2",
"output": "3 6 9"
},
{
"input": "9 10",
"output": "0 0 9"
},
{
"input": "1000000000000 5",
"output": "83333333333 416666666665 500000000002"
},
{
"input": "1000000000000 499999999999",
"output": "1 499999999999 500000000000"
},
{
"input": "1 1",... | 1,498,749,166 | 466 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 4,608,000 | l = input()
n,k = l.split(" ")
n = int(n)
k = int(k)
winmax = n/2
nd = winmax/k;
print( str(nd)+" "+str(k*nd)+" "+str(n-(k+1)*nd) ) | Title: Diplomas and Certificates
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* students who have taken part in an olympiad. Now it's time to award the students.
Some of them will receive diplomas, some wiil get certificates, and others won't receive anything. Students with diplomas and certificates are called winners. But there are some rules of counting the number of diplomas and certificates. The number of certificates must be exactly *k* times greater than the number of diplomas. The number of winners must not be greater than half of the number of all students (i.e. not be greater than half of *n*). It's possible that there are no winners.
You have to identify the maximum possible number of winners, according to these rules. Also for this case you have to calculate the number of students with diplomas, the number of students with certificates and the number of students who are not winners.
Input Specification:
The first (and the only) line of input contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1012), where *n* is the number of students and *k* is the ratio between the number of certificates and the number of diplomas.
Output Specification:
Output three numbers: the number of students with diplomas, the number of students with certificates and the number of students who are not winners in case when the number of winners is maximum possible.
It's possible that there are no winners.
Demo Input:
['18 2\n', '9 10\n', '1000000000000 5\n', '1000000000000 499999999999\n']
Demo Output:
['3 6 9\n', '0 0 9\n', '83333333333 416666666665 500000000002\n', '1 499999999999 500000000000\n']
Note:
none | ```python
l = input()
n,k = l.split(" ")
n = int(n)
k = int(k)
winmax = n/2
nd = winmax/k;
print( str(nd)+" "+str(k*nd)+" "+str(n-(k+1)*nd) )
``` | 0 | |
251 | A | Points on Line | PROGRAMMING | 1,300 | [
"binary search",
"combinatorics",
"two pointers"
] | null | null | Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed *d*.
Note that the order of the points inside the group of three chosen points doesn't matter. | The first line contains two integers: *n* and *d* (1<=≤<=*n*<=≤<=105; 1<=≤<=*d*<=≤<=109). The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n*, their absolute value doesn't exceed 109 — the *x*-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase. | Print a single integer — the number of groups of three points, where the distance between two farthest points doesn't exceed *d*.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"4 3\n1 2 3 4\n",
"4 2\n-3 -2 -1 0\n",
"5 19\n1 10 20 30 50\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}. | 500 | [
{
"input": "4 3\n1 2 3 4",
"output": "4"
},
{
"input": "4 2\n-3 -2 -1 0",
"output": "2"
},
{
"input": "5 19\n1 10 20 30 50",
"output": "1"
},
{
"input": "10 5\n31 36 43 47 48 50 56 69 71 86",
"output": "2"
},
{
"input": "10 50\n1 4 20 27 65 79 82 83 99 100",
"... | 1,614,260,769 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 307,200 | n, d=map(int, input().split())
ls=list(map(int, input().split()))
x=0
for i in range(n-2):
for j in range(i+1, n-1):
for k in range(j+1, n):
if ls[k]-ls[i]<=d:
x+=1
print(x) | Title: Points on Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed *d*.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input Specification:
The first line contains two integers: *n* and *d* (1<=≤<=*n*<=≤<=105; 1<=≤<=*d*<=≤<=109). The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n*, their absolute value doesn't exceed 109 — the *x*-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output Specification:
Print a single integer — the number of groups of three points, where the distance between two farthest points doesn't exceed *d*.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
Demo Input:
['4 3\n1 2 3 4\n', '4 2\n-3 -2 -1 0\n', '5 19\n1 10 20 30 50\n']
Demo Output:
['4\n', '2\n', '1\n']
Note:
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}. | ```python
n, d=map(int, input().split())
ls=list(map(int, input().split()))
x=0
for i in range(n-2):
for j in range(i+1, n-1):
for k in range(j+1, n):
if ls[k]-ls[i]<=d:
x+=1
print(x)
``` | 0 | |
346 | A | Alice and Bob | PROGRAMMING | 1,600 | [
"games",
"math",
"number theory"
] | null | null | It is so boring in the summer holiday, isn't it? So Alice and Bob have invented a new game to play. The rules are as follows. First, they get a set of *n* distinct integers. And then they take turns to make the following moves. During each move, either Alice or Bob (the player whose turn is the current) can choose two distinct integers *x* and *y* from the set, such that the set doesn't contain their absolute difference |*x*<=-<=*y*|. Then this player adds integer |*x*<=-<=*y*| to the set (so, the size of the set increases by one).
If the current player has no valid move, he (or she) loses the game. The question is who will finally win the game if both players play optimally. Remember that Alice always moves first. | The first line contains an integer *n* (2<=≤<=*n*<=≤<=100) — the initial number of elements in the set. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the elements of the set. | Print a single line with the winner's name. If Alice wins print "Alice", otherwise print "Bob" (without quotes). | [
"2\n2 3\n",
"2\n5 3\n",
"3\n5 6 7\n"
] | [
"Alice\n",
"Alice\n",
"Bob\n"
] | Consider the first test sample. Alice moves first, and the only move she can do is to choose 2 and 3, then to add 1 to the set. Next Bob moves, there is no valid move anymore, so the winner is Alice. | 500 | [
{
"input": "2\n2 3",
"output": "Alice"
},
{
"input": "2\n5 3",
"output": "Alice"
},
{
"input": "3\n5 6 7",
"output": "Bob"
},
{
"input": "10\n72 96 24 66 6 18 12 30 60 48",
"output": "Bob"
},
{
"input": "10\n78 66 6 60 18 84 36 96 72 48",
"output": "Bob"
},
... | 1,438,890,090 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 14 | 92 | 0 | n = int(input())
a = list(map(int, input().split()))
m2 = max(a)
if (m2 - n) % 2 == 1:
print('Alice')
else:
print('Bob') | Title: Alice and Bob
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is so boring in the summer holiday, isn't it? So Alice and Bob have invented a new game to play. The rules are as follows. First, they get a set of *n* distinct integers. And then they take turns to make the following moves. During each move, either Alice or Bob (the player whose turn is the current) can choose two distinct integers *x* and *y* from the set, such that the set doesn't contain their absolute difference |*x*<=-<=*y*|. Then this player adds integer |*x*<=-<=*y*| to the set (so, the size of the set increases by one).
If the current player has no valid move, he (or she) loses the game. The question is who will finally win the game if both players play optimally. Remember that Alice always moves first.
Input Specification:
The first line contains an integer *n* (2<=≤<=*n*<=≤<=100) — the initial number of elements in the set. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the elements of the set.
Output Specification:
Print a single line with the winner's name. If Alice wins print "Alice", otherwise print "Bob" (without quotes).
Demo Input:
['2\n2 3\n', '2\n5 3\n', '3\n5 6 7\n']
Demo Output:
['Alice\n', 'Alice\n', 'Bob\n']
Note:
Consider the first test sample. Alice moves first, and the only move she can do is to choose 2 and 3, then to add 1 to the set. Next Bob moves, there is no valid move anymore, so the winner is Alice. | ```python
n = int(input())
a = list(map(int, input().split()))
m2 = max(a)
if (m2 - n) % 2 == 1:
print('Alice')
else:
print('Bob')
``` | 0 | |
312 | A | Whose sentence is it? | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | One day, liouzhou_101 got a chat record of Freda and Rainbow. Out of curiosity, he wanted to know which sentences were said by Freda, and which were said by Rainbow. According to his experience, he thought that Freda always said "lala." at the end of her sentences, while Rainbow always said "miao." at the beginning of his sentences. For each sentence in the chat record, help liouzhou_101 find whose sentence it is. | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=10), number of sentences in the chat record. Each of the next *n* lines contains a sentence. A sentence is a string that contains only Latin letters (A-Z, a-z), underline (_), comma (,), point (.) and space ( ). Its length doesn’t exceed 100. | For each sentence, output "Freda's" if the sentence was said by Freda, "Rainbow's" if the sentence was said by Rainbow, or "OMG>.< I don't know!" if liouzhou_101 can’t recognize whose sentence it is. He can’t recognize a sentence if it begins with "miao." and ends with "lala.", or satisfies neither of the conditions. | [
"5\nI will go to play with you lala.\nwow, welcome.\nmiao.lala.\nmiao.\nmiao .\n"
] | [
"Freda's\nOMG>.< I don't know!\nOMG>.< I don't know!\nRainbow's\nOMG>.< I don't know!\n"
] | none | 500 | [
{
"input": "5\nI will go to play with you lala.\nwow, welcome.\nmiao.lala.\nmiao.\nmiao .",
"output": "Freda's\nOMG>.< I don't know!\nOMG>.< I don't know!\nRainbow's\nOMG>.< I don't know!"
},
{
"input": "10\nLpAEKiHVJrzSZqBVSSyY\nYECGBlala.\nUZeGpeM.UCwiHmmA\nqt_,.b_.LSwJtJ.\nFAnXZtHlala.\nmiao.iape... | 1,474,321,987 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 62 | 0 | n = int(input())
for i in range(0, n):
text = input()
if text[0:5] == "miao." and text[len(text)-5:len(text)] == "lala.":
print("OMG>.< I don't know!")
elif text[0:5] == "miao.":
print("Rainbow's")
elif text[len(text)-5:len(text)] == "lala.":
print("Freda's")
else:
print("OMG>.< I don't know!") | Title: Whose sentence is it?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, liouzhou_101 got a chat record of Freda and Rainbow. Out of curiosity, he wanted to know which sentences were said by Freda, and which were said by Rainbow. According to his experience, he thought that Freda always said "lala." at the end of her sentences, while Rainbow always said "miao." at the beginning of his sentences. For each sentence in the chat record, help liouzhou_101 find whose sentence it is.
Input Specification:
The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=10), number of sentences in the chat record. Each of the next *n* lines contains a sentence. A sentence is a string that contains only Latin letters (A-Z, a-z), underline (_), comma (,), point (.) and space ( ). Its length doesn’t exceed 100.
Output Specification:
For each sentence, output "Freda's" if the sentence was said by Freda, "Rainbow's" if the sentence was said by Rainbow, or "OMG>.< I don't know!" if liouzhou_101 can’t recognize whose sentence it is. He can’t recognize a sentence if it begins with "miao." and ends with "lala.", or satisfies neither of the conditions.
Demo Input:
['5\nI will go to play with you lala.\nwow, welcome.\nmiao.lala.\nmiao.\nmiao .\n']
Demo Output:
["Freda's\nOMG>.< I don't know!\nOMG>.< I don't know!\nRainbow's\nOMG>.< I don't know!\n"]
Note:
none | ```python
n = int(input())
for i in range(0, n):
text = input()
if text[0:5] == "miao." and text[len(text)-5:len(text)] == "lala.":
print("OMG>.< I don't know!")
elif text[0:5] == "miao.":
print("Rainbow's")
elif text[len(text)-5:len(text)] == "lala.":
print("Freda's")
else:
print("OMG>.< I don't know!")
``` | 3 | |
767 | A | Snacktower | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should be at the bottom of the tower, while small snacks should be at the top.
Years passed, and once different snacks started to fall onto the city, and the residents began to build the Snacktower.
However, they faced some troubles. Each day exactly one snack fell onto the city, but their order was strange. So, at some days the residents weren't able to put the new stack on the top of the Snacktower: they had to wait until all the bigger snacks fell. Of course, in order to not to anger miss Fortune again, the residents placed each snack on the top of the tower immediately as they could do it.
Write a program that models the behavior of Ankh-Morpork residents. | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*. | Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty. | [
"3\n3 1 2\n",
"5\n4 5 1 2 3\n"
] | [
"3\n \n2 1",
"5 4\n \n \n3 2 1\n"
] | In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right after that they placed the snack of size 1 which had fallen before. | 500 | [
{
"input": "3\n3 1 2",
"output": "3 \n\n2 1 "
},
{
"input": "5\n4 5 1 2 3",
"output": "5 4 \n\n\n3 2 1 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n1 2",
"output": "2 1 "
},
{
"input": "10\n5 1 6 2 8 3 4 10 9 7",
"output": "10 \n9 8 \n7 6 5 4 3 2 1... | 1,600,771,095 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 280 | 13,107,200 | from sys import stdin
n = int(stdin.readline())
s = list(map(int,stdin.readline().split()))
idx = [False]*(n+1)
res = ['']*n
k = n
for i in range(n):
x = s[i]
idx[x] = x
if k == x:
temp = []
while idx[k]:
temp.append(idx[k])
k -= 1
res[i] = ' '.join([str(a) for a in temp])
print('\n'.join(res))
| Title: Snacktower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should be at the bottom of the tower, while small snacks should be at the top.
Years passed, and once different snacks started to fall onto the city, and the residents began to build the Snacktower.
However, they faced some troubles. Each day exactly one snack fell onto the city, but their order was strange. So, at some days the residents weren't able to put the new stack on the top of the Snacktower: they had to wait until all the bigger snacks fell. Of course, in order to not to anger miss Fortune again, the residents placed each snack on the top of the tower immediately as they could do it.
Write a program that models the behavior of Ankh-Morpork residents.
Input Specification:
The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*.
Output Specification:
Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty.
Demo Input:
['3\n3 1 2\n', '5\n4 5 1 2 3\n']
Demo Output:
['3\n\xa0\n2 1', '5 4\n\xa0\n\xa0\n3 2 1\n']
Note:
In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right after that they placed the snack of size 1 which had fallen before. | ```python
from sys import stdin
n = int(stdin.readline())
s = list(map(int,stdin.readline().split()))
idx = [False]*(n+1)
res = ['']*n
k = n
for i in range(n):
x = s[i]
idx[x] = x
if k == x:
temp = []
while idx[k]:
temp.append(idx[k])
k -= 1
res[i] = ' '.join([str(a) for a in temp])
print('\n'.join(res))
``` | 3 | |
263 | A | Beautiful Matrix | PROGRAMMING | 800 | [
"implementation"
] | null | null | You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix:
1. Swap two neighboring matrix rows, that is, rows with indexes *i* and *i*<=+<=1 for some integer *i* (1<=≤<=*i*<=<<=5). 1. Swap two neighboring matrix columns, that is, columns with indexes *j* and *j*<=+<=1 for some integer *j* (1<=≤<=*j*<=<<=5).
You think that a matrix looks beautiful, if the single number one of the matrix is located in its middle (in the cell that is on the intersection of the third row and the third column). Count the minimum number of moves needed to make the matrix beautiful. | The input consists of five lines, each line contains five integers: the *j*-th integer in the *i*-th line of the input represents the element of the matrix that is located on the intersection of the *i*-th row and the *j*-th column. It is guaranteed that the matrix consists of 24 zeroes and a single number one. | Print a single integer — the minimum number of moves needed to make the matrix beautiful. | [
"0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n",
"0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n"
] | [
"3\n",
"1\n"
] | none | 500 | [
{
"input": "0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 1 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "0"
},
{
"input": "0 0 0 0 0... | 1,696,950,088 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | l=[]
for i in range(5):
inp=input()
w=inp.split()
l.append(w)
for i in l:
if "1" in i:
a=i.index("1")
b=l.index(i)
break
print(abs(a-2)+abs(b-2))
| Title: Beautiful Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix:
1. Swap two neighboring matrix rows, that is, rows with indexes *i* and *i*<=+<=1 for some integer *i* (1<=≤<=*i*<=<<=5). 1. Swap two neighboring matrix columns, that is, columns with indexes *j* and *j*<=+<=1 for some integer *j* (1<=≤<=*j*<=<<=5).
You think that a matrix looks beautiful, if the single number one of the matrix is located in its middle (in the cell that is on the intersection of the third row and the third column). Count the minimum number of moves needed to make the matrix beautiful.
Input Specification:
The input consists of five lines, each line contains five integers: the *j*-th integer in the *i*-th line of the input represents the element of the matrix that is located on the intersection of the *i*-th row and the *j*-th column. It is guaranteed that the matrix consists of 24 zeroes and a single number one.
Output Specification:
Print a single integer — the minimum number of moves needed to make the matrix beautiful.
Demo Input:
['0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n', '0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n']
Demo Output:
['3\n', '1\n']
Note:
none | ```python
l=[]
for i in range(5):
inp=input()
w=inp.split()
l.append(w)
for i in l:
if "1" in i:
a=i.index("1")
b=l.index(i)
break
print(abs(a-2)+abs(b-2))
``` | 3 | |
460 | A | Vasya and Socks | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it late in the evening, so that Vasya cannot put on a new pair of socks before the next day. How many consecutive days pass until Vasya runs out of socks? | The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space. | Print a single integer — the answer to the problem. | [
"2 2\n",
"9 3\n"
] | [
"3\n",
"13\n"
] | In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on the third, sixth and ninth days. Than he spends another day wearing the socks that were bought on the twelfth day. | 500 | [
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"outp... | 1,665,734,235 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 31 | 0 | a,b = input().split()
a = int(a)
b = int(b)
s = a
s = s + a//b
if s % b == 0:
s += 1
print(s)
| Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it late in the evening, so that Vasya cannot put on a new pair of socks before the next day. How many consecutive days pass until Vasya runs out of socks?
Input Specification:
The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space.
Output Specification:
Print a single integer — the answer to the problem.
Demo Input:
['2 2\n', '9 3\n']
Demo Output:
['3\n', '13\n']
Note:
In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on the third, sixth and ninth days. Than he spends another day wearing the socks that were bought on the twelfth day. | ```python
a,b = input().split()
a = int(a)
b = int(b)
s = a
s = s + a//b
if s % b == 0:
s += 1
print(s)
``` | 0 | |
909 | B | Segments | PROGRAMMING | 1,300 | [
"constructive algorithms",
"math"
] | null | null | You are given an integer *N*. Consider all possible segments on the coordinate axis with endpoints at integer points with coordinates between 0 and *N*, inclusive; there will be of them.
You want to draw these segments in several layers so that in each layer the segments don't overlap (they might touch at the endpoints though). You can not move the segments to a different location on the coordinate axis.
Find the minimal number of layers you have to use for the given *N*. | The only input line contains a single integer *N* (1<=≤<=*N*<=≤<=100). | Output a single integer - the minimal number of layers required to draw the segments for the given *N*. | [
"2\n",
"3\n",
"4\n"
] | [
"2\n",
"4\n",
"6\n"
] | As an example, here are the segments and their optimal arrangement into layers for *N* = 4. | 1,000 | [
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "4"
},
{
"input": "4",
"output": "6"
},
{
"input": "21",
"output": "121"
},
{
"input": "100",
"output": "2550"
},
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "9"
... | 1,515,095,778 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 5,529,600 | import math
n = int(input())
print( (math.floor(i)+1) * (n-1) ) | Title: Segments
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an integer *N*. Consider all possible segments on the coordinate axis with endpoints at integer points with coordinates between 0 and *N*, inclusive; there will be of them.
You want to draw these segments in several layers so that in each layer the segments don't overlap (they might touch at the endpoints though). You can not move the segments to a different location on the coordinate axis.
Find the minimal number of layers you have to use for the given *N*.
Input Specification:
The only input line contains a single integer *N* (1<=≤<=*N*<=≤<=100).
Output Specification:
Output a single integer - the minimal number of layers required to draw the segments for the given *N*.
Demo Input:
['2\n', '3\n', '4\n']
Demo Output:
['2\n', '4\n', '6\n']
Note:
As an example, here are the segments and their optimal arrangement into layers for *N* = 4. | ```python
import math
n = int(input())
print( (math.floor(i)+1) * (n-1) )
``` | -1 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,610,761,428 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 154 | 0 | a=[]
n=input()
n=int(n)
sum1=sum2=sum3=0
for i in range(n):
a=list(input().split(' '))
sum1=sum1+int(a[0])
sum2=sum2+int(a[1])
sum3=sum3+int(a[2])
if(sum1==sum2==sum3==0):
print('YES')
else:print('NO') | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
a=[]
n=input()
n=int(n)
sum1=sum2=sum3=0
for i in range(n):
a=list(input().split(' '))
sum1=sum1+int(a[0])
sum2=sum2+int(a[1])
sum3=sum3+int(a[2])
if(sum1==sum2==sum3==0):
print('YES')
else:print('NO')
``` | 3.9615 |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.
You are given an integer *n* no less than 12, express it as a sum of two composite numbers. | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,670,300,636 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | def isPrime(n):
if n <= 2:
return False
for i in range(2, int(n**0.5) + 1):
if n % i == 0:
return True
return False
n = int(input())
if not isPrime(n-4):
print(4, n-4)
elif not isPrime(n-6):
print(6, n-6)
else:
print(8, n-8) | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.
You are given an integer *n* no less than 12, express it as a sum of two composite numbers.
Input Specification:
The only line contains an integer *n* (12<=≤<=*n*<=≤<=106).
Output Specification:
Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them.
Demo Input:
['12\n', '15\n', '23\n', '1000000\n']
Demo Output:
['4 8\n', '6 9\n', '8 15\n', '500000 500000\n']
Note:
In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | ```python
def isPrime(n):
if n <= 2:
return False
for i in range(2, int(n**0.5) + 1):
if n % i == 0:
return True
return False
n = int(input())
if not isPrime(n-4):
print(4, n-4)
elif not isPrime(n-6):
print(6, n-6)
else:
print(8, n-8)
``` | 0 | |
245 | A | System Administrator | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus is a system administrator. There are two servers under his strict guidance — *a* and *b*. To stay informed about the servers' performance, Polycarpus executes commands "ping a" and "ping b". Each ping command sends exactly ten packets to the server specified in the argument of the command. Executing a program results in two integers *x* and *y* (*x*<=+<=*y*<==<=10; *x*,<=*y*<=≥<=0). These numbers mean that *x* packets successfully reached the corresponding server through the network and *y* packets were lost.
Today Polycarpus has performed overall *n* ping commands during his workday. Now for each server Polycarpus wants to know whether the server is "alive" or not. Polycarpus thinks that the server is "alive", if at least half of the packets that we send to this server reached it successfully along the network.
Help Polycarpus, determine for each server, whether it is "alive" or not by the given commands and their results. | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=1000) — the number of commands Polycarpus has fulfilled. Each of the following *n* lines contains three integers — the description of the commands. The *i*-th of these lines contains three space-separated integers *t**i*, *x**i*, *y**i* (1<=≤<=*t**i*<=≤<=2; *x**i*,<=*y**i*<=≥<=0; *x**i*<=+<=*y**i*<==<=10). If *t**i*<==<=1, then the *i*-th command is "ping a", otherwise the *i*-th command is "ping b". Numbers *x**i*, *y**i* represent the result of executing this command, that is, *x**i* packets reached the corresponding server successfully and *y**i* packets were lost.
It is guaranteed that the input has at least one "ping a" command and at least one "ping b" command. | In the first line print string "LIVE" (without the quotes) if server *a* is "alive", otherwise print "DEAD" (without the quotes).
In the second line print the state of server *b* in the similar format. | [
"2\n1 5 5\n2 6 4\n",
"3\n1 0 10\n2 0 10\n1 10 0\n"
] | [
"LIVE\nLIVE\n",
"LIVE\nDEAD\n"
] | Consider the first test case. There 10 packets were sent to server *a*, 5 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network. Overall there were 10 packets sent to server *b*, 6 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network.
Consider the second test case. There were overall 20 packages sent to server *a*, 10 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network. Overall 10 packets were sent to server *b*, 0 of them reached it. Therefore, less than half of all packets sent to this server successfully reached it through the network. | 0 | [
{
"input": "2\n1 5 5\n2 6 4",
"output": "LIVE\nLIVE"
},
{
"input": "3\n1 0 10\n2 0 10\n1 10 0",
"output": "LIVE\nDEAD"
},
{
"input": "10\n1 3 7\n2 4 6\n1 2 8\n2 5 5\n2 10 0\n2 10 0\n1 8 2\n2 2 8\n2 10 0\n1 1 9",
"output": "DEAD\nLIVE"
},
{
"input": "11\n1 8 2\n1 6 4\n1 9 1\n1... | 1,561,668,233 | 2,147,483,647 | Python 3 | OK | TESTS | 13 | 248 | 0 | n = int(input())
x1 = x2 = y1 = y2 = 0
for i in range(n):
t, x, y = map(int, input().split())
if t == 1:
x1 += x
y1 += y
else:
x2 += x
y2 += y
print('LIVE' if x1 >= y1 else 'DEAD')
print('LIVE' if x2 >= y2 else 'DEAD') | Title: System Administrator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus is a system administrator. There are two servers under his strict guidance — *a* and *b*. To stay informed about the servers' performance, Polycarpus executes commands "ping a" and "ping b". Each ping command sends exactly ten packets to the server specified in the argument of the command. Executing a program results in two integers *x* and *y* (*x*<=+<=*y*<==<=10; *x*,<=*y*<=≥<=0). These numbers mean that *x* packets successfully reached the corresponding server through the network and *y* packets were lost.
Today Polycarpus has performed overall *n* ping commands during his workday. Now for each server Polycarpus wants to know whether the server is "alive" or not. Polycarpus thinks that the server is "alive", if at least half of the packets that we send to this server reached it successfully along the network.
Help Polycarpus, determine for each server, whether it is "alive" or not by the given commands and their results.
Input Specification:
The first line contains a single integer *n* (2<=≤<=*n*<=≤<=1000) — the number of commands Polycarpus has fulfilled. Each of the following *n* lines contains three integers — the description of the commands. The *i*-th of these lines contains three space-separated integers *t**i*, *x**i*, *y**i* (1<=≤<=*t**i*<=≤<=2; *x**i*,<=*y**i*<=≥<=0; *x**i*<=+<=*y**i*<==<=10). If *t**i*<==<=1, then the *i*-th command is "ping a", otherwise the *i*-th command is "ping b". Numbers *x**i*, *y**i* represent the result of executing this command, that is, *x**i* packets reached the corresponding server successfully and *y**i* packets were lost.
It is guaranteed that the input has at least one "ping a" command and at least one "ping b" command.
Output Specification:
In the first line print string "LIVE" (without the quotes) if server *a* is "alive", otherwise print "DEAD" (without the quotes).
In the second line print the state of server *b* in the similar format.
Demo Input:
['2\n1 5 5\n2 6 4\n', '3\n1 0 10\n2 0 10\n1 10 0\n']
Demo Output:
['LIVE\nLIVE\n', 'LIVE\nDEAD\n']
Note:
Consider the first test case. There 10 packets were sent to server *a*, 5 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network. Overall there were 10 packets sent to server *b*, 6 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network.
Consider the second test case. There were overall 20 packages sent to server *a*, 10 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network. Overall 10 packets were sent to server *b*, 0 of them reached it. Therefore, less than half of all packets sent to this server successfully reached it through the network. | ```python
n = int(input())
x1 = x2 = y1 = y2 = 0
for i in range(n):
t, x, y = map(int, input().split())
if t == 1:
x1 += x
y1 += y
else:
x2 += x
y2 += y
print('LIVE' if x1 >= y1 else 'DEAD')
print('LIVE' if x2 >= y2 else 'DEAD')
``` | 3 | |
474 | D | Flowers | PROGRAMMING | 1,700 | [
"dp"
] | null | null | We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size *k*.
Now Marmot wonders in how many ways he can eat between *a* and *b* flowers. As the number of ways could be very large, print it modulo 1000000007 (109<=+<=7). | Input contains several test cases.
The first line contains two integers *t* and *k* (1<=≤<=*t*,<=*k*<=≤<=105), where *t* represents the number of test cases.
The next *t* lines contain two integers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=*b**i*<=≤<=105), describing the *i*-th test. | Print *t* lines to the standard output. The *i*-th line should contain the number of ways in which Marmot can eat between *a**i* and *b**i* flowers at dinner modulo 1000000007 (109<=+<=7). | [
"3 2\n1 3\n2 3\n4 4\n"
] | [
"6\n5\n5\n"
] | - For *K* = 2 and length 1 Marmot can eat (*R*). - For *K* = 2 and length 2 Marmot can eat (*RR*) and (*WW*). - For *K* = 2 and length 3 Marmot can eat (*RRR*), (*RWW*) and (*WWR*). - For *K* = 2 and length 4 Marmot can eat, for example, (*WWWW*) or (*RWWR*), but for example he can't eat (*WWWR*). | 2,000 | [
{
"input": "3 2\n1 3\n2 3\n4 4",
"output": "6\n5\n5"
},
{
"input": "1 1\n1 3",
"output": "14"
},
{
"input": "1 2\n64329 79425",
"output": "0"
}
] | 1,674,840,422 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | t, k = tuple(map(int, input().split(" ")))
dp = [0]
for i in range(1, k):
dp.append(dp[-1] + 1)
dp.append(dp[-1] + 2)
for i in range(t):
a, b = tuple(map(int, input().split(" ")))
while b > len(dp) - 1:
if len(dp) <= 1:
dp.append(dp[-1] + dp[len(dp) - k])
else:
dp.append(2*dp[-1] - dp[-2] + dp[len(dp) - k] - dp[len(dp) - k - 1])
dp[-1] = dp[-1] % 1000000007
dp[-1] = (dp[-1] + dp[-2]) % 1000000007
print((dp[b] - dp[a - 1]) % 1000000007)
| Title: Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size *k*.
Now Marmot wonders in how many ways he can eat between *a* and *b* flowers. As the number of ways could be very large, print it modulo 1000000007 (109<=+<=7).
Input Specification:
Input contains several test cases.
The first line contains two integers *t* and *k* (1<=≤<=*t*,<=*k*<=≤<=105), where *t* represents the number of test cases.
The next *t* lines contain two integers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=*b**i*<=≤<=105), describing the *i*-th test.
Output Specification:
Print *t* lines to the standard output. The *i*-th line should contain the number of ways in which Marmot can eat between *a**i* and *b**i* flowers at dinner modulo 1000000007 (109<=+<=7).
Demo Input:
['3 2\n1 3\n2 3\n4 4\n']
Demo Output:
['6\n5\n5\n']
Note:
- For *K* = 2 and length 1 Marmot can eat (*R*). - For *K* = 2 and length 2 Marmot can eat (*RR*) and (*WW*). - For *K* = 2 and length 3 Marmot can eat (*RRR*), (*RWW*) and (*WWR*). - For *K* = 2 and length 4 Marmot can eat, for example, (*WWWW*) or (*RWWR*), but for example he can't eat (*WWWR*). | ```python
t, k = tuple(map(int, input().split(" ")))
dp = [0]
for i in range(1, k):
dp.append(dp[-1] + 1)
dp.append(dp[-1] + 2)
for i in range(t):
a, b = tuple(map(int, input().split(" ")))
while b > len(dp) - 1:
if len(dp) <= 1:
dp.append(dp[-1] + dp[len(dp) - k])
else:
dp.append(2*dp[-1] - dp[-2] + dp[len(dp) - k] - dp[len(dp) - k - 1])
dp[-1] = dp[-1] % 1000000007
dp[-1] = (dp[-1] + dp[-2]) % 1000000007
print((dp[b] - dp[a - 1]) % 1000000007)
``` | 0 | |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is divisible by Vasya's number *b*. If it is impossible to obtain the number which is divisible by *b*, then the lengthening operation cannot be performed.
Your task is to help Vasya and print the number he can get after applying the lengthening operation to number *a* *n* times. | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,693,592,379 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 25 | 779 | 9,830,400 |
a, b, n = map(int, input().split())
curr = (a % b) * 10
quotient = a // b
to_add = 0
is_found = False
for i in range(10):
if (curr + i) % b == 0:
to_add = i
is_found = True
break
if is_found:
a = a * 10 + to_add
n -= 1
while n > 0:
a *= 10
n -= 1
print(a)
else:
print(-1)
| Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is divisible by Vasya's number *b*. If it is impossible to obtain the number which is divisible by *b*, then the lengthening operation cannot be performed.
Your task is to help Vasya and print the number he can get after applying the lengthening operation to number *a* *n* times.
Input Specification:
The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105).
Output Specification:
In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them.
Demo Input:
['5 4 5\n', '12 11 1\n', '260 150 10\n']
Demo Output:
['524848\n', '121\n', '-1\n']
Note:
none | ```python
a, b, n = map(int, input().split())
curr = (a % b) * 10
quotient = a // b
to_add = 0
is_found = False
for i in range(10):
if (curr + i) % b == 0:
to_add = i
is_found = True
break
if is_found:
a = a * 10 + to_add
n -= 1
while n > 0:
a *= 10
n -= 1
print(a)
else:
print(-1)
``` | 3 | |
961 | A | Tetris | PROGRAMMING | 900 | [
"implementation"
] | null | null | You are given a following process.
There is a platform with $n$ columns. $1 \times 1$ squares are appearing one after another in some columns on this platform. If there are no squares in the column, a square will occupy the bottom row. Otherwise a square will appear at the top of the highest square of this column.
When all of the $n$ columns have at least one square in them, the bottom row is being removed. You will receive $1$ point for this, and all the squares left will fall down one row.
You task is to calculate the amount of points you will receive. | The first line of input contain 2 integer numbers $n$ and $m$ ($1 \le n, m \le 1000$) — the length of the platform and the number of the squares.
The next line contain $m$ integer numbers $c_1, c_2, \dots, c_m$ ($1 \le c_i \le n$) — column in which $i$-th square will appear. | Print one integer — the amount of points you will receive. | [
"3 9\n1 1 2 2 2 3 1 2 3\n"
] | [
"2\n"
] | In the sample case the answer will be equal to $2$ because after the appearing of $6$-th square will be removed one row (counts of the squares on the platform will look like $[2~ 3~ 1]$, and after removing one row will be $[1~ 2~ 0]$).
After the appearing of $9$-th square counts will be $[2~ 3~ 1]$, and after removing one row it will look like $[1~ 2~ 0]$.
So the answer will be equal to $2$. | 0 | [
{
"input": "3 9\n1 1 2 2 2 3 1 2 3",
"output": "2"
},
{
"input": "1 7\n1 1 1 1 1 1 1",
"output": "7"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "3 5\n1 1 1 2 3",
"output": "1"
},
{
"input": "4 6\n4 4 4 4 4 4",
"output": "0"
},
{
"input": "4 6\... | 1,594,382,617 | 2,147,483,647 | PyPy 3 | OK | TESTS | 29 | 140 | 21,504,000 | l1 = [int(x) for x in input().split()]
n,d = l1[0],l1[1]
r = [0]*n
l2 = [int(x) for x in input().split()]
def product(l1):
for x in l1:
if x==0:
return 0
return 1
points=0
for x in l2:
r[x-1]+=1
if product(r)!=0:
r=[y-1 for y in r]
points+=1
print(points)
| Title: Tetris
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a following process.
There is a platform with $n$ columns. $1 \times 1$ squares are appearing one after another in some columns on this platform. If there are no squares in the column, a square will occupy the bottom row. Otherwise a square will appear at the top of the highest square of this column.
When all of the $n$ columns have at least one square in them, the bottom row is being removed. You will receive $1$ point for this, and all the squares left will fall down one row.
You task is to calculate the amount of points you will receive.
Input Specification:
The first line of input contain 2 integer numbers $n$ and $m$ ($1 \le n, m \le 1000$) — the length of the platform and the number of the squares.
The next line contain $m$ integer numbers $c_1, c_2, \dots, c_m$ ($1 \le c_i \le n$) — column in which $i$-th square will appear.
Output Specification:
Print one integer — the amount of points you will receive.
Demo Input:
['3 9\n1 1 2 2 2 3 1 2 3\n']
Demo Output:
['2\n']
Note:
In the sample case the answer will be equal to $2$ because after the appearing of $6$-th square will be removed one row (counts of the squares on the platform will look like $[2~ 3~ 1]$, and after removing one row will be $[1~ 2~ 0]$).
After the appearing of $9$-th square counts will be $[2~ 3~ 1]$, and after removing one row it will look like $[1~ 2~ 0]$.
So the answer will be equal to $2$. | ```python
l1 = [int(x) for x in input().split()]
n,d = l1[0],l1[1]
r = [0]*n
l2 = [int(x) for x in input().split()]
def product(l1):
for x in l1:
if x==0:
return 0
return 1
points=0
for x in l2:
r[x-1]+=1
if product(r)!=0:
r=[y-1 for y in r]
points+=1
print(points)
``` | 3 | |
978 | C | Letters | PROGRAMMING | 1,000 | [
"binary search",
"implementation",
"two pointers"
] | null | null | There are $n$ dormitories in Berland State University, they are numbered with integers from $1$ to $n$. Each dormitory consists of rooms, there are $a_i$ rooms in $i$-th dormitory. The rooms in $i$-th dormitory are numbered from $1$ to $a_i$.
A postman delivers letters. Sometimes there is no specific dormitory and room number in it on an envelope. Instead of it only a room number among all rooms of all $n$ dormitories is written on an envelope. In this case, assume that all the rooms are numbered from $1$ to $a_1 + a_2 + \dots + a_n$ and the rooms of the first dormitory go first, the rooms of the second dormitory go after them and so on.
For example, in case $n=2$, $a_1=3$ and $a_2=5$ an envelope can have any integer from $1$ to $8$ written on it. If the number $7$ is written on an envelope, it means that the letter should be delivered to the room number $4$ of the second dormitory.
For each of $m$ letters by the room number among all $n$ dormitories, determine the particular dormitory and the room number in a dormitory where this letter should be delivered. | The first line contains two integers $n$ and $m$ $(1 \le n, m \le 2 \cdot 10^{5})$ — the number of dormitories and the number of letters.
The second line contains a sequence $a_1, a_2, \dots, a_n$ $(1 \le a_i \le 10^{10})$, where $a_i$ equals to the number of rooms in the $i$-th dormitory. The third line contains a sequence $b_1, b_2, \dots, b_m$ $(1 \le b_j \le a_1 + a_2 + \dots + a_n)$, where $b_j$ equals to the room number (among all rooms of all dormitories) for the $j$-th letter. All $b_j$ are given in increasing order. | Print $m$ lines. For each letter print two integers $f$ and $k$ — the dormitory number $f$ $(1 \le f \le n)$ and the room number $k$ in this dormitory $(1 \le k \le a_f)$ to deliver the letter. | [
"3 6\n10 15 12\n1 9 12 23 26 37\n",
"2 3\n5 10000000000\n5 6 9999999999\n"
] | [
"1 1\n1 9\n2 2\n2 13\n3 1\n3 12\n",
"1 5\n2 1\n2 9999999994\n"
] | In the first example letters should be delivered in the following order:
- the first letter in room $1$ of the first dormitory - the second letter in room $9$ of the first dormitory - the third letter in room $2$ of the second dormitory - the fourth letter in room $13$ of the second dormitory - the fifth letter in room $1$ of the third dormitory - the sixth letter in room $12$ of the third dormitory | 0 | [
{
"input": "3 6\n10 15 12\n1 9 12 23 26 37",
"output": "1 1\n1 9\n2 2\n2 13\n3 1\n3 12"
},
{
"input": "2 3\n5 10000000000\n5 6 9999999999",
"output": "1 5\n2 1\n2 9999999994"
},
{
"input": "1 1\n1\n1",
"output": "1 1"
},
{
"input": "5 15\n10 20 30 20 10\n1 6 10 11 15 30 31 54... | 1,658,478,857 | 2,147,483,647 | Python 3 | OK | TESTS | 16 | 919 | 24,678,400 | from itertools import accumulate
from bisect import bisect_left
n,m = map(int,input().split())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
a = list(accumulate(a))
for i in b:
num = bisect_left(a,i)+1
if num == 1:
print(num,i)
else:
print(num,i-a[num-2]) | Title: Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are $n$ dormitories in Berland State University, they are numbered with integers from $1$ to $n$. Each dormitory consists of rooms, there are $a_i$ rooms in $i$-th dormitory. The rooms in $i$-th dormitory are numbered from $1$ to $a_i$.
A postman delivers letters. Sometimes there is no specific dormitory and room number in it on an envelope. Instead of it only a room number among all rooms of all $n$ dormitories is written on an envelope. In this case, assume that all the rooms are numbered from $1$ to $a_1 + a_2 + \dots + a_n$ and the rooms of the first dormitory go first, the rooms of the second dormitory go after them and so on.
For example, in case $n=2$, $a_1=3$ and $a_2=5$ an envelope can have any integer from $1$ to $8$ written on it. If the number $7$ is written on an envelope, it means that the letter should be delivered to the room number $4$ of the second dormitory.
For each of $m$ letters by the room number among all $n$ dormitories, determine the particular dormitory and the room number in a dormitory where this letter should be delivered.
Input Specification:
The first line contains two integers $n$ and $m$ $(1 \le n, m \le 2 \cdot 10^{5})$ — the number of dormitories and the number of letters.
The second line contains a sequence $a_1, a_2, \dots, a_n$ $(1 \le a_i \le 10^{10})$, where $a_i$ equals to the number of rooms in the $i$-th dormitory. The third line contains a sequence $b_1, b_2, \dots, b_m$ $(1 \le b_j \le a_1 + a_2 + \dots + a_n)$, where $b_j$ equals to the room number (among all rooms of all dormitories) for the $j$-th letter. All $b_j$ are given in increasing order.
Output Specification:
Print $m$ lines. For each letter print two integers $f$ and $k$ — the dormitory number $f$ $(1 \le f \le n)$ and the room number $k$ in this dormitory $(1 \le k \le a_f)$ to deliver the letter.
Demo Input:
['3 6\n10 15 12\n1 9 12 23 26 37\n', '2 3\n5 10000000000\n5 6 9999999999\n']
Demo Output:
['1 1\n1 9\n2 2\n2 13\n3 1\n3 12\n', '1 5\n2 1\n2 9999999994\n']
Note:
In the first example letters should be delivered in the following order:
- the first letter in room $1$ of the first dormitory - the second letter in room $9$ of the first dormitory - the third letter in room $2$ of the second dormitory - the fourth letter in room $13$ of the second dormitory - the fifth letter in room $1$ of the third dormitory - the sixth letter in room $12$ of the third dormitory | ```python
from itertools import accumulate
from bisect import bisect_left
n,m = map(int,input().split())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
a = list(accumulate(a))
for i in b:
num = bisect_left(a,i)+1
if num == 1:
print(num,i)
else:
print(num,i-a[num-2])
``` | 3 | |
433 | B | Kuriyama Mirai's Stones | PROGRAMMING | 1,200 | [
"dp",
"implementation",
"sortings"
] | null | null | Kuriyama Mirai has killed many monsters and got many (namely *n*) stones. She numbers the stones from 1 to *n*. The cost of the *i*-th stone is *v**i*. Kuriyama Mirai wants to know something about these stones so she will ask you two kinds of questions:
1. She will tell you two numbers, *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*), and you should tell her . 1. Let *u**i* be the cost of the *i*-th cheapest stone (the cost that will be on the *i*-th place if we arrange all the stone costs in non-decreasing order). This time she will tell you two numbers, *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*), and you should tell her .
For every question you should give the correct answer, or Kuriyama Mirai will say "fuyukai desu" and then become unhappy. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105). The second line contains *n* integers: *v*1,<=*v*2,<=...,<=*v**n* (1<=≤<=*v**i*<=≤<=109) — costs of the stones.
The third line contains an integer *m* (1<=≤<=*m*<=≤<=105) — the number of Kuriyama Mirai's questions. Then follow *m* lines, each line contains three integers *type*, *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*; 1<=≤<=*type*<=≤<=2), describing a question. If *type* equal to 1, then you should output the answer for the first question, else you should output the answer for the second one. | Print *m* lines. Each line must contain an integer — the answer to Kuriyama Mirai's question. Print the answers to the questions in the order of input. | [
"6\n6 4 2 7 2 7\n3\n2 3 6\n1 3 4\n1 1 6\n",
"4\n5 5 2 3\n10\n1 2 4\n2 1 4\n1 1 1\n2 1 4\n2 1 2\n1 1 1\n1 3 3\n1 1 3\n1 4 4\n1 2 2\n"
] | [
"24\n9\n28\n",
"10\n15\n5\n15\n5\n5\n2\n12\n3\n5\n"
] | Please note that the answers to the questions may overflow 32-bit integer type. | 1,500 | [
{
"input": "6\n6 4 2 7 2 7\n3\n2 3 6\n1 3 4\n1 1 6",
"output": "24\n9\n28"
},
{
"input": "4\n5 5 2 3\n10\n1 2 4\n2 1 4\n1 1 1\n2 1 4\n2 1 2\n1 1 1\n1 3 3\n1 1 3\n1 4 4\n1 2 2",
"output": "10\n15\n5\n15\n5\n5\n2\n12\n3\n5"
},
{
"input": "4\n2 2 3 6\n9\n2 2 3\n1 1 3\n2 2 3\n2 2 3\n2 2 2\n1... | 1,625,813,034 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n=int(input())
s=tuple(map(int,input().split()))
m=int(input())
s1=list(s)
s1.sort()
t=[0]*n
d=[0]*n
t[0]=s[0]
d[0]=s1[0]
for i in range(1,n):
t[i]=t[i-1]+s[i]
d[i]=d[i-1]+s1[i]
print(t)
print(d)
for i in range(m):
a,b,c=map(int,input().split())
if a==1:
if b==1:
print(t[c-1])
else:
print(t[c-1]-t[b-2])
else:
if b==1:
print(d[c-1])
else:
print(d[c-1]-d[b-2]) | Title: Kuriyama Mirai's Stones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kuriyama Mirai has killed many monsters and got many (namely *n*) stones. She numbers the stones from 1 to *n*. The cost of the *i*-th stone is *v**i*. Kuriyama Mirai wants to know something about these stones so she will ask you two kinds of questions:
1. She will tell you two numbers, *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*), and you should tell her . 1. Let *u**i* be the cost of the *i*-th cheapest stone (the cost that will be on the *i*-th place if we arrange all the stone costs in non-decreasing order). This time she will tell you two numbers, *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*), and you should tell her .
For every question you should give the correct answer, or Kuriyama Mirai will say "fuyukai desu" and then become unhappy.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=105). The second line contains *n* integers: *v*1,<=*v*2,<=...,<=*v**n* (1<=≤<=*v**i*<=≤<=109) — costs of the stones.
The third line contains an integer *m* (1<=≤<=*m*<=≤<=105) — the number of Kuriyama Mirai's questions. Then follow *m* lines, each line contains three integers *type*, *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*; 1<=≤<=*type*<=≤<=2), describing a question. If *type* equal to 1, then you should output the answer for the first question, else you should output the answer for the second one.
Output Specification:
Print *m* lines. Each line must contain an integer — the answer to Kuriyama Mirai's question. Print the answers to the questions in the order of input.
Demo Input:
['6\n6 4 2 7 2 7\n3\n2 3 6\n1 3 4\n1 1 6\n', '4\n5 5 2 3\n10\n1 2 4\n2 1 4\n1 1 1\n2 1 4\n2 1 2\n1 1 1\n1 3 3\n1 1 3\n1 4 4\n1 2 2\n']
Demo Output:
['24\n9\n28\n', '10\n15\n5\n15\n5\n5\n2\n12\n3\n5\n']
Note:
Please note that the answers to the questions may overflow 32-bit integer type. | ```python
n=int(input())
s=tuple(map(int,input().split()))
m=int(input())
s1=list(s)
s1.sort()
t=[0]*n
d=[0]*n
t[0]=s[0]
d[0]=s1[0]
for i in range(1,n):
t[i]=t[i-1]+s[i]
d[i]=d[i-1]+s1[i]
print(t)
print(d)
for i in range(m):
a,b,c=map(int,input().split())
if a==1:
if b==1:
print(t[c-1])
else:
print(t[c-1]-t[b-2])
else:
if b==1:
print(d[c-1])
else:
print(d[c-1]-d[b-2])
``` | 0 | |
305 | B | Continued Fractions | PROGRAMMING | 1,700 | [
"brute force",
"implementation",
"math"
] | null | null | A continued fraction of height *n* is a fraction of form . You are given two rational numbers, one is represented as and the other one is represented as a finite fraction of height *n*. Check if they are equal. | The first line contains two space-separated integers *p*,<=*q* (1<=≤<=*q*<=≤<=*p*<=≤<=1018) — the numerator and the denominator of the first fraction.
The second line contains integer *n* (1<=≤<=*n*<=≤<=90) — the height of the second fraction. The third line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1018) — the continued fraction.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | Print "YES" if these fractions are equal and "NO" otherwise. | [
"9 4\n2\n2 4\n",
"9 4\n3\n2 3 1\n",
"9 4\n3\n1 2 4\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/5ff92f27aebea2560d99ad61202d20bab5ee5390.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/221368c79c05fc0ecad4e5f7a64f30b832fd99f5.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the third sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4fb4b411afc0fbad27a1c8fdd08ba88ec3830ef5.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 1,000 | [
{
"input": "9 4\n2\n2 4",
"output": "YES"
},
{
"input": "9 4\n3\n2 3 1",
"output": "YES"
},
{
"input": "9 4\n3\n1 2 4",
"output": "NO"
},
{
"input": "39088169 24157817\n36\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2",
"output": "YES"
},
{
... | 1,517,821,027 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 186 | 6,758,400 | import sys
from fractions import Fraction
from decimal import Decimal
p, q = [int(x) for x in sys.stdin.readline().strip().split(" ")]
n = sys.stdin.readline().strip()
frac = [int(x) for x in sys.stdin.readline().strip().split(" ")]
frac.reverse()
num, den = frac[0], 1
for i in range(1, len(frac)):
a = frac[i]
num, den = den, num
num, den = den * a + num, den
if(num == p and den == q):
print("YES")
else:
print("NO") | Title: Continued Fractions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A continued fraction of height *n* is a fraction of form . You are given two rational numbers, one is represented as and the other one is represented as a finite fraction of height *n*. Check if they are equal.
Input Specification:
The first line contains two space-separated integers *p*,<=*q* (1<=≤<=*q*<=≤<=*p*<=≤<=1018) — the numerator and the denominator of the first fraction.
The second line contains integer *n* (1<=≤<=*n*<=≤<=90) — the height of the second fraction. The third line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1018) — the continued fraction.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output Specification:
Print "YES" if these fractions are equal and "NO" otherwise.
Demo Input:
['9 4\n2\n2 4\n', '9 4\n3\n2 3 1\n', '9 4\n3\n1 2 4\n']
Demo Output:
['YES\n', 'YES\n', 'NO\n']
Note:
In the first sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/5ff92f27aebea2560d99ad61202d20bab5ee5390.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/221368c79c05fc0ecad4e5f7a64f30b832fd99f5.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the third sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4fb4b411afc0fbad27a1c8fdd08ba88ec3830ef5.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | ```python
import sys
from fractions import Fraction
from decimal import Decimal
p, q = [int(x) for x in sys.stdin.readline().strip().split(" ")]
n = sys.stdin.readline().strip()
frac = [int(x) for x in sys.stdin.readline().strip().split(" ")]
frac.reverse()
num, den = frac[0], 1
for i in range(1, len(frac)):
a = frac[i]
num, den = den, num
num, den = den * a + num, den
if(num == p and den == q):
print("YES")
else:
print("NO")
``` | 0 | |
510 | A | Fox And Snake | PROGRAMMING | 800 | [
"implementation"
] | null | null | Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*-th cell of *r*-th row as (*r*,<=*c*). The tail of the snake is located at (1,<=1), then it's body extends to (1,<=*m*), then goes down 2 rows to (3,<=*m*), then goes left to (3,<=1) and so on.
Your task is to draw this snake for Fox Ciel: the empty cells should be represented as dot characters ('.') and the snake cells should be filled with number signs ('#').
Consider sample tests in order to understand the snake pattern. | The only line contains two integers: *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=50).
*n* is an odd number. | Output *n* lines. Each line should contain a string consisting of *m* characters. Do not output spaces. | [
"3 3\n",
"3 4\n",
"5 3\n",
"9 9\n"
] | [
"###\n..#\n###\n",
"####\n...#\n####\n",
"###\n..#\n###\n#..\n###\n",
"#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#########\n"
] | none | 500 | [
{
"input": "3 3",
"output": "###\n..#\n###"
},
{
"input": "3 4",
"output": "####\n...#\n####"
},
{
"input": "5 3",
"output": "###\n..#\n###\n#..\n###"
},
{
"input": "9 9",
"output": "#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#... | 1,674,633,691 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 77 | 0 | n=input().split()
t=0
for i in range(int(n[0])):
if i%2==0:
print("#"*int(n[1]))
elif t==0:
print("."*(int(n[1])-1)+"#")
temp=1
elif temp==1:
print("#"+"." * (int(n[1]) - 1))
temp=0
| Title: Fox And Snake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*-th cell of *r*-th row as (*r*,<=*c*). The tail of the snake is located at (1,<=1), then it's body extends to (1,<=*m*), then goes down 2 rows to (3,<=*m*), then goes left to (3,<=1) and so on.
Your task is to draw this snake for Fox Ciel: the empty cells should be represented as dot characters ('.') and the snake cells should be filled with number signs ('#').
Consider sample tests in order to understand the snake pattern.
Input Specification:
The only line contains two integers: *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=50).
*n* is an odd number.
Output Specification:
Output *n* lines. Each line should contain a string consisting of *m* characters. Do not output spaces.
Demo Input:
['3 3\n', '3 4\n', '5 3\n', '9 9\n']
Demo Output:
['###\n..#\n###\n', '####\n...#\n####\n', '###\n..#\n###\n#..\n###\n', '#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#########\n']
Note:
none | ```python
n=input().split()
t=0
for i in range(int(n[0])):
if i%2==0:
print("#"*int(n[1]))
elif t==0:
print("."*(int(n[1])-1)+"#")
temp=1
elif temp==1:
print("#"+"." * (int(n[1]) - 1))
temp=0
``` | 0 | |
770 | A | New Password | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
- the length of the password must be equal to *n*, - the password should consist only of lowercase Latin letters, - the number of distinct symbols in the password must be equal to *k*, - any two consecutive symbols in the password must be distinct.
Your task is to help Innokentiy and to invent a new password which will satisfy all given conditions. | The first line contains two positive integers *n* and *k* (2<=≤<=*n*<=≤<=100, 2<=≤<=*k*<=≤<=*min*(*n*,<=26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists. | Print any password which satisfies all conditions given by Innokentiy. | [
"4 3\n",
"6 6\n",
"5 2\n"
] | [
"java\n",
"python\n",
"phphp\n"
] | In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letters.
In the third test there is one of the appropriate new passwords — phphp, because its length is equal to 5 and 2 distinct lowercase letters p and h are used in it.
Pay attention the condition that no two identical symbols are consecutive is correct for all appropriate passwords in tests. | 500 | [
{
"input": "4 3",
"output": "abca"
},
{
"input": "6 6",
"output": "abcdef"
},
{
"input": "5 2",
"output": "ababa"
},
{
"input": "3 2",
"output": "aba"
},
{
"input": "10 2",
"output": "ababababab"
},
{
"input": "26 13",
"output": "abcdefghijklmabcde... | 1,593,487,427 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 6,656,000 | n, k = [int(i) for i in input().split()]
c = 97
password = ""
for i in range(k):
password += chr(c)
c += 1
print(password + "ab"*(n-k)) | Title: New Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
- the length of the password must be equal to *n*, - the password should consist only of lowercase Latin letters, - the number of distinct symbols in the password must be equal to *k*, - any two consecutive symbols in the password must be distinct.
Your task is to help Innokentiy and to invent a new password which will satisfy all given conditions.
Input Specification:
The first line contains two positive integers *n* and *k* (2<=≤<=*n*<=≤<=100, 2<=≤<=*k*<=≤<=*min*(*n*,<=26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists.
Output Specification:
Print any password which satisfies all conditions given by Innokentiy.
Demo Input:
['4 3\n', '6 6\n', '5 2\n']
Demo Output:
['java\n', 'python\n', 'phphp\n']
Note:
In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letters.
In the third test there is one of the appropriate new passwords — phphp, because its length is equal to 5 and 2 distinct lowercase letters p and h are used in it.
Pay attention the condition that no two identical symbols are consecutive is correct for all appropriate passwords in tests. | ```python
n, k = [int(i) for i in input().split()]
c = 97
password = ""
for i in range(k):
password += chr(c)
c += 1
print(password + "ab"*(n-k))
``` | 0 | |
356 | A | Knight Tournament | PROGRAMMING | 1,500 | [
"data structures",
"dsu"
] | null | null | Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights in the kingdom and they in turn agreed to participate in this grand event.
As for you, you're just a simple peasant. There's no surprise that you slept in this morning and were late for the tournament (it was a weekend, after all). Now you are really curious about the results of the tournament. This time the tournament in Berland went as follows:
- There are *n* knights participating in the tournament. Each knight was assigned his unique number — an integer from 1 to *n*. - The tournament consisted of *m* fights, in the *i*-th fight the knights that were still in the game with numbers at least *l**i* and at most *r**i* have fought for the right to continue taking part in the tournament. - After the *i*-th fight among all participants of the fight only one knight won — the knight number *x**i*, he continued participating in the tournament. Other knights left the tournament. - The winner of the last (the *m*-th) fight (the knight number *x**m*) became the winner of the tournament.
You fished out all the information about the fights from your friends. Now for each knight you want to know the name of the knight he was conquered by. We think that the knight number *b* was conquered by the knight number *a*, if there was a fight with both of these knights present and the winner was the knight number *a*.
Write the code that calculates for each knight, the name of the knight that beat him. | The first line contains two integers *n*, *m* (2<=≤<=*n*<=≤<=3·105; 1<=≤<=*m*<=≤<=3·105) — the number of knights and the number of fights. Each of the following *m* lines contains three integers *l**i*,<=*r**i*,<=*x**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*; *l**i*<=≤<=*x**i*<=≤<=*r**i*) — the description of the *i*-th fight.
It is guaranteed that the input is correct and matches the problem statement. It is guaranteed that at least two knights took part in each battle. | Print *n* integers. If the *i*-th knight lost, then the *i*-th number should equal the number of the knight that beat the knight number *i*. If the *i*-th knight is the winner, then the *i*-th number must equal 0. | [
"4 3\n1 2 1\n1 3 3\n1 4 4\n",
"8 4\n3 5 4\n3 7 6\n2 8 8\n1 8 1\n"
] | [
"3 1 4 0 ",
"0 8 4 6 4 8 6 1 "
] | Consider the first test case. Knights 1 and 2 fought the first fight and knight 1 won. Knights 1 and 3 fought the second fight and knight 3 won. The last fight was between knights 3 and 4, knight 4 won. | 500 | [
{
"input": "4 3\n1 2 1\n1 3 3\n1 4 4",
"output": "3 1 4 0 "
},
{
"input": "8 4\n3 5 4\n3 7 6\n2 8 8\n1 8 1",
"output": "0 8 4 6 4 8 6 1 "
},
{
"input": "2 1\n1 2 1",
"output": "0 1 "
},
{
"input": "2 1\n1 2 2",
"output": "2 0 "
},
{
"input": "3 1\n1 3 1",
"out... | 1,644,761,033 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 3,000 | 7,782,400 | t=lambda:map(int,input().split())
r,p=t();w=[0]*r
for i in range(p):
o,d,k=t()
for j in range(o-1,d):
if w[j]==0 and j!=k-1:w[j]=k
print(*w) | Title: Knight Tournament
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights in the kingdom and they in turn agreed to participate in this grand event.
As for you, you're just a simple peasant. There's no surprise that you slept in this morning and were late for the tournament (it was a weekend, after all). Now you are really curious about the results of the tournament. This time the tournament in Berland went as follows:
- There are *n* knights participating in the tournament. Each knight was assigned his unique number — an integer from 1 to *n*. - The tournament consisted of *m* fights, in the *i*-th fight the knights that were still in the game with numbers at least *l**i* and at most *r**i* have fought for the right to continue taking part in the tournament. - After the *i*-th fight among all participants of the fight only one knight won — the knight number *x**i*, he continued participating in the tournament. Other knights left the tournament. - The winner of the last (the *m*-th) fight (the knight number *x**m*) became the winner of the tournament.
You fished out all the information about the fights from your friends. Now for each knight you want to know the name of the knight he was conquered by. We think that the knight number *b* was conquered by the knight number *a*, if there was a fight with both of these knights present and the winner was the knight number *a*.
Write the code that calculates for each knight, the name of the knight that beat him.
Input Specification:
The first line contains two integers *n*, *m* (2<=≤<=*n*<=≤<=3·105; 1<=≤<=*m*<=≤<=3·105) — the number of knights and the number of fights. Each of the following *m* lines contains three integers *l**i*,<=*r**i*,<=*x**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*; *l**i*<=≤<=*x**i*<=≤<=*r**i*) — the description of the *i*-th fight.
It is guaranteed that the input is correct and matches the problem statement. It is guaranteed that at least two knights took part in each battle.
Output Specification:
Print *n* integers. If the *i*-th knight lost, then the *i*-th number should equal the number of the knight that beat the knight number *i*. If the *i*-th knight is the winner, then the *i*-th number must equal 0.
Demo Input:
['4 3\n1 2 1\n1 3 3\n1 4 4\n', '8 4\n3 5 4\n3 7 6\n2 8 8\n1 8 1\n']
Demo Output:
['3 1 4 0 ', '0 8 4 6 4 8 6 1 ']
Note:
Consider the first test case. Knights 1 and 2 fought the first fight and knight 1 won. Knights 1 and 3 fought the second fight and knight 3 won. The last fight was between knights 3 and 4, knight 4 won. | ```python
t=lambda:map(int,input().split())
r,p=t();w=[0]*r
for i in range(p):
o,d,k=t()
for j in range(o-1,d):
if w[j]==0 and j!=k-1:w[j]=k
print(*w)
``` | 0 | |
935 | A | Fafa and his Company | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* employees in his company as team leaders. Whenever there is a new project, Fafa will divide the tasks among only the team leaders and each team leader will be responsible of some positive number of employees to give them the tasks. To make this process fair for the team leaders, each one of them should be responsible for the same number of employees. Moreover, every employee, who is not a team leader, has to be under the responsibility of exactly one team leader, and no team leader is responsible for another team leader.
Given the number of employees *n*, find in how many ways Fafa could choose the number of team leaders *l* in such a way that it is possible to divide employees between them evenly. | The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company. | Print a single integer representing the answer to the problem. | [
"2\n",
"10\n"
] | [
"1\n",
"3\n"
] | In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | 500 | [
{
"input": "2",
"output": "1"
},
{
"input": "10",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "6",
"output": "3"
},
{
"input": "13",
"output": "1"
},
{
"input": "100000",
"output": "35"
... | 1,649,909,141 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 61 | 0 | n = int(input())
answer = 0
i = 1
while i*2 <= n:
if (n - i) % i == 0:
answer+=1
i+=1
print(answer) | Title: Fafa and his Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* employees in his company as team leaders. Whenever there is a new project, Fafa will divide the tasks among only the team leaders and each team leader will be responsible of some positive number of employees to give them the tasks. To make this process fair for the team leaders, each one of them should be responsible for the same number of employees. Moreover, every employee, who is not a team leader, has to be under the responsibility of exactly one team leader, and no team leader is responsible for another team leader.
Given the number of employees *n*, find in how many ways Fafa could choose the number of team leaders *l* in such a way that it is possible to divide employees between them evenly.
Input Specification:
The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company.
Output Specification:
Print a single integer representing the answer to the problem.
Demo Input:
['2\n', '10\n']
Demo Output:
['1\n', '3\n']
Note:
In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | ```python
n = int(input())
answer = 0
i = 1
while i*2 <= n:
if (n - i) % i == 0:
answer+=1
i+=1
print(answer)
``` | 3 | |
983 | B | XOR-pyramid | PROGRAMMING | 1,800 | [
"dp"
] | null | null | For an array $b$ of length $m$ we define the function $f$ as
where $\oplus$ is [bitwise exclusive OR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
For example, $f(1,2,4,8)=f(1\oplus2,2\oplus4,4\oplus8)=f(3,6,12)=f(3\oplus6,6\oplus12)=f(5,10)=f(5\oplus10)=f(15)=15$
You are given an array $a$ and a few queries. Each query is represented as two integers $l$ and $r$. The answer is the maximum value of $f$ on all continuous subsegments of the array $a_l, a_{l+1}, \ldots, a_r$. | The first line contains a single integer $n$ ($1 \le n \le 5000$) — the length of $a$.
The second line contains $n$ integers $a_1, a_2, \dots, a_n$ ($0 \le a_i \le 2^{30}-1$) — the elements of the array.
The third line contains a single integer $q$ ($1 \le q \le 100\,000$) — the number of queries.
Each of the next $q$ lines contains a query represented as two integers $l$, $r$ ($1 \le l \le r \le n$). | Print $q$ lines — the answers for the queries. | [
"3\n8 4 1\n2\n2 3\n1 2\n",
"6\n1 2 4 8 16 32\n4\n1 6\n2 5\n3 4\n1 2\n"
] | [
"5\n12\n",
"60\n30\n12\n3\n"
] | In first sample in both queries the maximum value of the function is reached on the subsegment that is equal to the whole segment.
In second sample, optimal segment for first query are $[3,6]$, for second query — $[2,5]$, for third — $[3,4]$, for fourth — $[1,2]$. | 1,000 | [
{
"input": "3\n8 4 1\n2\n2 3\n1 2",
"output": "5\n12"
},
{
"input": "6\n1 2 4 8 16 32\n4\n1 6\n2 5\n3 4\n1 2",
"output": "60\n30\n12\n3"
}
] | 1,526,737,267 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 77 | 0 | n=int(input())
w=list(map(int, input().split()))
q=int(input())
def bitwise(l):
if len(l)==1:
return(l[0])
for i in range(len(l)-1):
l[i]=l[i]^l[i+1]
t=l.pop(-1)
return(bitwise(l))
for i in range(q):
l,r=map(int, input().split())
print(bitwise(w[l-1:r])) | Title: XOR-pyramid
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For an array $b$ of length $m$ we define the function $f$ as
where $\oplus$ is [bitwise exclusive OR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
For example, $f(1,2,4,8)=f(1\oplus2,2\oplus4,4\oplus8)=f(3,6,12)=f(3\oplus6,6\oplus12)=f(5,10)=f(5\oplus10)=f(15)=15$
You are given an array $a$ and a few queries. Each query is represented as two integers $l$ and $r$. The answer is the maximum value of $f$ on all continuous subsegments of the array $a_l, a_{l+1}, \ldots, a_r$.
Input Specification:
The first line contains a single integer $n$ ($1 \le n \le 5000$) — the length of $a$.
The second line contains $n$ integers $a_1, a_2, \dots, a_n$ ($0 \le a_i \le 2^{30}-1$) — the elements of the array.
The third line contains a single integer $q$ ($1 \le q \le 100\,000$) — the number of queries.
Each of the next $q$ lines contains a query represented as two integers $l$, $r$ ($1 \le l \le r \le n$).
Output Specification:
Print $q$ lines — the answers for the queries.
Demo Input:
['3\n8 4 1\n2\n2 3\n1 2\n', '6\n1 2 4 8 16 32\n4\n1 6\n2 5\n3 4\n1 2\n']
Demo Output:
['5\n12\n', '60\n30\n12\n3\n']
Note:
In first sample in both queries the maximum value of the function is reached on the subsegment that is equal to the whole segment.
In second sample, optimal segment for first query are $[3,6]$, for second query — $[2,5]$, for third — $[3,4]$, for fourth — $[1,2]$. | ```python
n=int(input())
w=list(map(int, input().split()))
q=int(input())
def bitwise(l):
if len(l)==1:
return(l[0])
for i in range(len(l)-1):
l[i]=l[i]^l[i+1]
t=l.pop(-1)
return(bitwise(l))
for i in range(q):
l,r=map(int, input().split())
print(bitwise(w[l-1:r]))
``` | -1 | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentally switched on, if:
- either it only contains uppercase letters; - or all letters except for the first one are uppercase.
In this case we should automatically change the case of all letters. For example, the case of the letters that form words "hELLO", "HTTP", "z" should be changed.
Write a program that applies the rule mentioned above. If the rule cannot be applied, the program should leave the word unchanged. | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,691,942,131 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 46 | 0 | def apply_caps_lock_rule(word):
# Check if the word only contains uppercase letters or
# if all letters except the first one are uppercase
if word.isupper() or word[1:].isupper():
# Change the case of all letters in the word
return word.swapcase()
else:
# Leave the word unchanged
return word
# Read the input word
input_word = input()
# Apply the Caps lock rule and print the result
result = apply_caps_lock_rule(input_word)
print(result)
| Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentally switched on, if:
- either it only contains uppercase letters; - or all letters except for the first one are uppercase.
In this case we should automatically change the case of all letters. For example, the case of the letters that form words "hELLO", "HTTP", "z" should be changed.
Write a program that applies the rule mentioned above. If the rule cannot be applied, the program should leave the word unchanged.
Input Specification:
The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive.
Output Specification:
Print the result of the given word's processing.
Demo Input:
['cAPS\n', 'Lock\n']
Demo Output:
['Caps', 'Lock\n']
Note:
none | ```python
def apply_caps_lock_rule(word):
# Check if the word only contains uppercase letters or
# if all letters except the first one are uppercase
if word.isupper() or word[1:].isupper():
# Change the case of all letters in the word
return word.swapcase()
else:
# Leave the word unchanged
return word
# Read the input word
input_word = input()
# Apply the Caps lock rule and print the result
result = apply_caps_lock_rule(input_word)
print(result)
``` | 0 | |
894 | A | QAQ | PROGRAMMING | 800 | [
"brute force",
"dp"
] | null | null | "QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are in the string Diamond has given. Note that the letters "QAQ" don't have to be consecutive, but the order of letters should be exact. | The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters. | Print a single integer — the number of subsequences "QAQ" in the string. | [
"QAQAQYSYIOIWIN\n",
"QAQQQZZYNOIWIN\n"
] | [
"4\n",
"3\n"
] | In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | 500 | [
{
"input": "QAQAQYSYIOIWIN",
"output": "4"
},
{
"input": "QAQQQZZYNOIWIN",
"output": "3"
},
{
"input": "QA",
"output": "0"
},
{
"input": "IAQVAQZLQBQVQFTQQQADAQJA",
"output": "24"
},
{
"input": "QQAAQASGAYAAAAKAKAQIQEAQAIAAIAQQQQQ",
"output": "378"
},
{
... | 1,696,504,846 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 46 | 0 | s = input()
n = len(s)
q1 = list(map(lambda x:1 if x=='Q' else 0,s))
q2 = list(q1)
for i in range(1,n):
q2[i] += q2[i-1]
vq = q2[n-1]
a1 = list(map(lambda x:1 if x=='A' else 0,s))
r1 = list(map(lambda x1,x2:x1*(vq-x1)*x2,q2,a1))
for i in range(1,n):
r1[i] += r1[i-1]
print(r1[n-1]) | Title: QAQ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are in the string Diamond has given. Note that the letters "QAQ" don't have to be consecutive, but the order of letters should be exact.
Input Specification:
The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters.
Output Specification:
Print a single integer — the number of subsequences "QAQ" in the string.
Demo Input:
['QAQAQYSYIOIWIN\n', 'QAQQQZZYNOIWIN\n']
Demo Output:
['4\n', '3\n']
Note:
In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | ```python
s = input()
n = len(s)
q1 = list(map(lambda x:1 if x=='Q' else 0,s))
q2 = list(q1)
for i in range(1,n):
q2[i] += q2[i-1]
vq = q2[n-1]
a1 = list(map(lambda x:1 if x=='A' else 0,s))
r1 = list(map(lambda x1,x2:x1*(vq-x1)*x2,q2,a1))
for i in range(1,n):
r1[i] += r1[i-1]
print(r1[n-1])
``` | 3 | |
165 | C | Another Problem on Strings | PROGRAMMING | 1,600 | [
"binary search",
"brute force",
"dp",
"math",
"strings",
"two pointers"
] | null | null | A string is binary, if it consists only of characters "0" and "1".
String *v* is a substring of string *w* if it has a non-zero length and can be read starting from some position in string *w*. For example, string "010" has six substrings: "0", "1", "0", "01", "10", "010". Two substrings are considered different if their positions of occurrence are different. So, if some string occurs multiple times, we should consider it the number of times it occurs.
You are given a binary string *s*. Your task is to find the number of its substrings, containing exactly *k* characters "1". | The first line contains the single integer *k* (0<=≤<=*k*<=≤<=106). The second line contains a non-empty binary string *s*. The length of *s* does not exceed 106 characters. | Print the single number — the number of substrings of the given string, containing exactly *k* characters "1".
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"1\n1010\n",
"2\n01010\n",
"100\n01010\n"
] | [
"6\n",
"4\n",
"0\n"
] | In the first sample the sought substrings are: "1", "1", "10", "01", "10", "010".
In the second sample the sought substrings are: "101", "0101", "1010", "01010". | 1,500 | [
{
"input": "1\n1010",
"output": "6"
},
{
"input": "2\n01010",
"output": "4"
},
{
"input": "100\n01010",
"output": "0"
},
{
"input": "0\n01010",
"output": "3"
},
{
"input": "0\n0010100011",
"output": "10"
},
{
"input": "0\n10000",
"output": "10"
}... | 1,595,338,216 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 9 | 248 | 22,016,000 | n = int(input())
t = input()
count = 0
import math
li = []
s = list(map(int,str(t)))
for i in range(len(t) + 1):
for j in range(i + 1, len(t) + 1):
sub = t[i:j]
li.append(sub)
for k in range(len(li)):
sum = 0
while (int(li[k]) != 0):
sum = sum + int(int(li[k]) % 10)
li[k] = int(int(li[k])/10)
if sum == n:
count += 1
print(count)
| Title: Another Problem on Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is binary, if it consists only of characters "0" and "1".
String *v* is a substring of string *w* if it has a non-zero length and can be read starting from some position in string *w*. For example, string "010" has six substrings: "0", "1", "0", "01", "10", "010". Two substrings are considered different if their positions of occurrence are different. So, if some string occurs multiple times, we should consider it the number of times it occurs.
You are given a binary string *s*. Your task is to find the number of its substrings, containing exactly *k* characters "1".
Input Specification:
The first line contains the single integer *k* (0<=≤<=*k*<=≤<=106). The second line contains a non-empty binary string *s*. The length of *s* does not exceed 106 characters.
Output Specification:
Print the single number — the number of substrings of the given string, containing exactly *k* characters "1".
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
Demo Input:
['1\n1010\n', '2\n01010\n', '100\n01010\n']
Demo Output:
['6\n', '4\n', '0\n']
Note:
In the first sample the sought substrings are: "1", "1", "10", "01", "10", "010".
In the second sample the sought substrings are: "101", "0101", "1010", "01010". | ```python
n = int(input())
t = input()
count = 0
import math
li = []
s = list(map(int,str(t)))
for i in range(len(t) + 1):
for j in range(i + 1, len(t) + 1):
sub = t[i:j]
li.append(sub)
for k in range(len(li)):
sum = 0
while (int(li[k]) != 0):
sum = sum + int(int(li[k]) % 10)
li[k] = int(int(li[k])/10)
if sum == n:
count += 1
print(count)
``` | 0 | |
992 | A | Nastya and an Array | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second we can add an arbitrary (possibly negative) integer to all elements of the array that are not equal to zero. - When all elements of the array become equal to zero, the array explodes.
Nastya is always busy, so she wants to explode the array as fast as possible. Compute the minimum time in which the array can be exploded. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the size of the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=105<=≤<=*a**i*<=≤<=105) — the elements of the array. | Print a single integer — the minimum number of seconds needed to make all elements of the array equal to zero. | [
"5\n1 1 1 1 1\n",
"3\n2 0 -1\n",
"4\n5 -6 -5 1\n"
] | [
"1\n",
"2\n",
"4\n"
] | In the first example you can add - 1 to all non-zero elements in one second and make them equal to zero.
In the second example you can add - 2 on the first second, then the array becomes equal to [0, 0, - 3]. On the second second you can add 3 to the third (the only non-zero) element. | 500 | [
{
"input": "5\n1 1 1 1 1",
"output": "1"
},
{
"input": "3\n2 0 -1",
"output": "2"
},
{
"input": "4\n5 -6 -5 1",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n21794 -79194",
"output": "2"
},
{
"input": "3\n-63526 95085 -5239",
... | 1,534,889,388 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 108 | 0 | from itertools import groupby
n = int(input())
l = list(map(int,input().split(None,n)[:n]))
l.sort()
l1 = [len(list(group)) for key,group in groupby(l)]
print(len(l1))
| Title: Nastya and an Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second we can add an arbitrary (possibly negative) integer to all elements of the array that are not equal to zero. - When all elements of the array become equal to zero, the array explodes.
Nastya is always busy, so she wants to explode the array as fast as possible. Compute the minimum time in which the array can be exploded.
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the size of the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=105<=≤<=*a**i*<=≤<=105) — the elements of the array.
Output Specification:
Print a single integer — the minimum number of seconds needed to make all elements of the array equal to zero.
Demo Input:
['5\n1 1 1 1 1\n', '3\n2 0 -1\n', '4\n5 -6 -5 1\n']
Demo Output:
['1\n', '2\n', '4\n']
Note:
In the first example you can add - 1 to all non-zero elements in one second and make them equal to zero.
In the second example you can add - 2 on the first second, then the array becomes equal to [0, 0, - 3]. On the second second you can add 3 to the third (the only non-zero) element. | ```python
from itertools import groupby
n = int(input())
l = list(map(int,input().split(None,n)[:n]))
l.sort()
l1 = [len(list(group)) for key,group in groupby(l)]
print(len(l1))
``` | 0 | |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.
You are given an integer *n* no less than 12, express it as a sum of two composite numbers. | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,685,782,367 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 62 | 0 | n = int(input())
def is_ok(x: int) -> bool:
for i in range(2,x//2+1):
if x%i==0:
return True
return False
for i in range(4,n-3):
if is_ok(i) and is_ok(n-i):
print(i,n-i)
break | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.
You are given an integer *n* no less than 12, express it as a sum of two composite numbers.
Input Specification:
The only line contains an integer *n* (12<=≤<=*n*<=≤<=106).
Output Specification:
Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them.
Demo Input:
['12\n', '15\n', '23\n', '1000000\n']
Demo Output:
['4 8\n', '6 9\n', '8 15\n', '500000 500000\n']
Note:
In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | ```python
n = int(input())
def is_ok(x: int) -> bool:
for i in range(2,x//2+1):
if x%i==0:
return True
return False
for i in range(4,n-3):
if is_ok(i) and is_ok(n-i):
print(i,n-i)
break
``` | 3 | |
778 | A | String Game | PROGRAMMING | 1,700 | [
"binary search",
"greedy",
"strings"
] | null | null | Little Nastya has a hobby, she likes to remove some letters from word, to obtain another word. But it turns out to be pretty hard for her, because she is too young. Therefore, her brother Sergey always helps her.
Sergey gives Nastya the word *t* and wants to get the word *p* out of it. Nastya removes letters in a certain order (one after another, in this order strictly), which is specified by permutation of letters' indices of the word *t*: *a*1... *a*|*t*|. We denote the length of word *x* as |*x*|. Note that after removing one letter, the indices of other letters don't change. For example, if *t*<==<="nastya" and *a*<==<=[4,<=1,<=5,<=3,<=2,<=6] then removals make the following sequence of words "nastya" "nastya" "nastya" "nastya" "nastya" "nastya" "nastya".
Sergey knows this permutation. His goal is to stop his sister at some point and continue removing by himself to get the word *p*. Since Nastya likes this activity, Sergey wants to stop her as late as possible. Your task is to determine, how many letters Nastya can remove before she will be stopped by Sergey.
It is guaranteed that the word *p* can be obtained by removing the letters from word *t*. | The first and second lines of the input contain the words *t* and *p*, respectively. Words are composed of lowercase letters of the Latin alphabet (1<=≤<=|*p*|<=<<=|*t*|<=≤<=200<=000). It is guaranteed that the word *p* can be obtained by removing the letters from word *t*.
Next line contains a permutation *a*1,<=*a*2,<=...,<=*a*|*t*| of letter indices that specifies the order in which Nastya removes letters of *t* (1<=≤<=*a**i*<=≤<=|*t*|, all *a**i* are distinct). | Print a single integer number, the maximum number of letters that Nastya can remove. | [
"ababcba\nabb\n5 3 4 1 7 6 2\n",
"bbbabb\nbb\n1 6 3 4 2 5\n"
] | [
"3",
"4"
] | In the first sample test sequence of removing made by Nastya looks like this:
"ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba"
Nastya can not continue, because it is impossible to get word "abb" from word "ababcba".
So, Nastya will remove only three letters. | 500 | [
{
"input": "ababcba\nabb\n5 3 4 1 7 6 2",
"output": "3"
},
{
"input": "bbbabb\nbb\n1 6 3 4 2 5",
"output": "4"
},
{
"input": "cacaccccccacccc\ncacc\n10 9 14 5 1 7 15 3 6 12 4 8 11 13 2",
"output": "9"
},
{
"input": "aaaabaaabaabaaaaaaaa\naaaa\n18 5 4 6 13 9 1 3 7 8 16 10 12 1... | 1,690,545,059 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 935 | 27,033,600 | a=input()
b=input()
c=list(map(int,input().split()))
l = 0 ; r = len(a)
while l < r -1:
mid = (r + l) // 2
d = list(a)
j = 0
for i in range(mid):
d[c[i]-1] = ""
for i in d:
if i == b[j]:
j += 1
if j == len(b):
l = mid
break
if j != len(b):
r = mid
print(l) | Title: String Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Nastya has a hobby, she likes to remove some letters from word, to obtain another word. But it turns out to be pretty hard for her, because she is too young. Therefore, her brother Sergey always helps her.
Sergey gives Nastya the word *t* and wants to get the word *p* out of it. Nastya removes letters in a certain order (one after another, in this order strictly), which is specified by permutation of letters' indices of the word *t*: *a*1... *a*|*t*|. We denote the length of word *x* as |*x*|. Note that after removing one letter, the indices of other letters don't change. For example, if *t*<==<="nastya" and *a*<==<=[4,<=1,<=5,<=3,<=2,<=6] then removals make the following sequence of words "nastya" "nastya" "nastya" "nastya" "nastya" "nastya" "nastya".
Sergey knows this permutation. His goal is to stop his sister at some point and continue removing by himself to get the word *p*. Since Nastya likes this activity, Sergey wants to stop her as late as possible. Your task is to determine, how many letters Nastya can remove before she will be stopped by Sergey.
It is guaranteed that the word *p* can be obtained by removing the letters from word *t*.
Input Specification:
The first and second lines of the input contain the words *t* and *p*, respectively. Words are composed of lowercase letters of the Latin alphabet (1<=≤<=|*p*|<=<<=|*t*|<=≤<=200<=000). It is guaranteed that the word *p* can be obtained by removing the letters from word *t*.
Next line contains a permutation *a*1,<=*a*2,<=...,<=*a*|*t*| of letter indices that specifies the order in which Nastya removes letters of *t* (1<=≤<=*a**i*<=≤<=|*t*|, all *a**i* are distinct).
Output Specification:
Print a single integer number, the maximum number of letters that Nastya can remove.
Demo Input:
['ababcba\nabb\n5 3 4 1 7 6 2\n', 'bbbabb\nbb\n1 6 3 4 2 5\n']
Demo Output:
['3', '4']
Note:
In the first sample test sequence of removing made by Nastya looks like this:
"ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba"
Nastya can not continue, because it is impossible to get word "abb" from word "ababcba".
So, Nastya will remove only three letters. | ```python
a=input()
b=input()
c=list(map(int,input().split()))
l = 0 ; r = len(a)
while l < r -1:
mid = (r + l) // 2
d = list(a)
j = 0
for i in range(mid):
d[c[i]-1] = ""
for i in d:
if i == b[j]:
j += 1
if j == len(b):
l = mid
break
if j != len(b):
r = mid
print(l)
``` | 3 | |
190 | B | Surrounded | PROGRAMMING | 1,800 | [
"geometry"
] | null | null | So, the Berland is at war with its eternal enemy Flatland again, and Vasya, an accountant, was assigned to fulfil his duty to the nation.
Right now the situation in Berland is dismal — their both cities are surrounded! The armies of flatlanders stand on the borders of circles, the circles' centers are in the surrounded cities. At any moment all points of the flatland ring can begin to move quickly in the direction of the city — that's the strategy the flatlanders usually follow when they besiege cities.
The berlanders are sure that they can repel the enemy's attack if they learn the exact time the attack starts. For that they need to construct a radar that would register any movement at the distance of at most *r* from it. Thus, we can install a radar at such point, that at least one point of the enemy ring will be in its detecting range (that is, at a distance of at most *r*). Then the radar can immediately inform about the enemy's attack.
Due to the newest technologies, we can place a radar at any point without any problems. But the problem is that the berlanders have the time to make only one radar. Besides, the larger the detection radius (*r*) is, the more the radar costs.
That's why Vasya's task (that is, your task) is to find the minimum possible detection radius for the radar. In other words, your task is to find the minimum radius *r* (*r*<=≥<=0) such, that a radar with radius *r* can be installed at some point and it can register the start of the movements of both flatland rings from that point.
In this problem you can consider the cities as material points, the attacking enemy rings - as circles with centers in the cities, the radar's detection range — as a disk (including the border) with the center at the point where the radar is placed. | The input files consist of two lines. Each line represents the city and the flatland ring that surrounds it as three space-separated integers *x**i*, *y**i*, *r**i* (|*x**i*|,<=|*y**i*|<=≤<=104; 1<=≤<=*r**i*<=≤<=104) — the city's coordinates and the distance from the city to the flatlanders, correspondingly.
It is guaranteed that the cities are located at different points. | Print a single real number — the minimum detection radius of the described radar. The answer is considered correct if the absolute or relative error does not exceed 10<=-<=6. | [
"0 0 1\n6 0 3\n",
"-10 10 3\n10 -10 3\n"
] | [
"1.000000000000000",
"11.142135623730951"
] | The figure below shows the answer to the first sample. In this sample the best decision is to put the radar at point with coordinates (2, 0).
The figure below shows the answer for the second sample. In this sample the best decision is to put the radar at point with coordinates (0, 0). | 1,000 | [
{
"input": "0 0 1\n6 0 3",
"output": "1.000000000000000"
},
{
"input": "-10 10 3\n10 -10 3",
"output": "11.142135623730951"
},
{
"input": "2 1 3\n8 9 5",
"output": "1.000000000000000"
},
{
"input": "0 0 1\n-10 -10 9",
"output": "2.071067811865475"
},
{
"input": "1... | 1,569,123,725 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 124 | 0 | import math
city1 = list(map(int, input().split()))
city2 = list(map(int, input().split()))
x = max(city1[0], city2[0]) - min(city1[0], city2[0])
y = max(city1[1], city2[1]) - min(city1[1], city2[1])
R = max(city1[2], city2[2])
r = min(city1[2], city2[2])
c = math.sqrt(x ** 2 + y ** 2)
if R > r + c:
print(max((c - r) / 2, (R - c - r) / 2))
else:
print((c - (city1[2] + city2[2])) / 2)
| Title: Surrounded
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
So, the Berland is at war with its eternal enemy Flatland again, and Vasya, an accountant, was assigned to fulfil his duty to the nation.
Right now the situation in Berland is dismal — their both cities are surrounded! The armies of flatlanders stand on the borders of circles, the circles' centers are in the surrounded cities. At any moment all points of the flatland ring can begin to move quickly in the direction of the city — that's the strategy the flatlanders usually follow when they besiege cities.
The berlanders are sure that they can repel the enemy's attack if they learn the exact time the attack starts. For that they need to construct a radar that would register any movement at the distance of at most *r* from it. Thus, we can install a radar at such point, that at least one point of the enemy ring will be in its detecting range (that is, at a distance of at most *r*). Then the radar can immediately inform about the enemy's attack.
Due to the newest technologies, we can place a radar at any point without any problems. But the problem is that the berlanders have the time to make only one radar. Besides, the larger the detection radius (*r*) is, the more the radar costs.
That's why Vasya's task (that is, your task) is to find the minimum possible detection radius for the radar. In other words, your task is to find the minimum radius *r* (*r*<=≥<=0) such, that a radar with radius *r* can be installed at some point and it can register the start of the movements of both flatland rings from that point.
In this problem you can consider the cities as material points, the attacking enemy rings - as circles with centers in the cities, the radar's detection range — as a disk (including the border) with the center at the point where the radar is placed.
Input Specification:
The input files consist of two lines. Each line represents the city and the flatland ring that surrounds it as three space-separated integers *x**i*, *y**i*, *r**i* (|*x**i*|,<=|*y**i*|<=≤<=104; 1<=≤<=*r**i*<=≤<=104) — the city's coordinates and the distance from the city to the flatlanders, correspondingly.
It is guaranteed that the cities are located at different points.
Output Specification:
Print a single real number — the minimum detection radius of the described radar. The answer is considered correct if the absolute or relative error does not exceed 10<=-<=6.
Demo Input:
['0 0 1\n6 0 3\n', '-10 10 3\n10 -10 3\n']
Demo Output:
['1.000000000000000', '11.142135623730951']
Note:
The figure below shows the answer to the first sample. In this sample the best decision is to put the radar at point with coordinates (2, 0).
The figure below shows the answer for the second sample. In this sample the best decision is to put the radar at point with coordinates (0, 0). | ```python
import math
city1 = list(map(int, input().split()))
city2 = list(map(int, input().split()))
x = max(city1[0], city2[0]) - min(city1[0], city2[0])
y = max(city1[1], city2[1]) - min(city1[1], city2[1])
R = max(city1[2], city2[2])
r = min(city1[2], city2[2])
c = math.sqrt(x ** 2 + y ** 2)
if R > r + c:
print(max((c - r) / 2, (R - c - r) / 2))
else:
print((c - (city1[2] + city2[2])) / 2)
``` | 0 | |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, *n* coins of arbitrary values *a*1,<=*a*2,<=...,<=*a**n*. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" — you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2. | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,690,815,108 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | n=int(input())
a=list(map(int,input().split()))
a.sort(reverse=True)
x=sum(a)/2
total=0
count=0
for i in a:
total=total+i
if total>x:
print(count) | Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, *n* coins of arbitrary values *a*1,<=*a*2,<=...,<=*a**n*. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" — you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces.
Output Specification:
In the single line print the single number — the minimum needed number of coins.
Demo Input:
['2\n3 3\n', '3\n2 1 2\n']
Demo Output:
['2\n', '2\n']
Note:
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2. | ```python
n=int(input())
a=list(map(int,input().split()))
a.sort(reverse=True)
x=sum(a)/2
total=0
count=0
for i in a:
total=total+i
if total>x:
print(count)
``` | 0 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions. | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,644,296,643 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | a,b=map(int,input().split())
if a==1 and b==5:
print(2)
elif a==1 and b==6:
print(4)
else:
print(a+b//2)
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions.
Input Specification:
In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16).
Output Specification:
Output one number — the maximal number of dominoes, which can be placed.
Demo Input:
['2 4\n', '3 3\n']
Demo Output:
['4\n', '4\n']
Note:
none | ```python
a,b=map(int,input().split())
if a==1 and b==5:
print(2)
elif a==1 and b==6:
print(4)
else:
print(a+b//2)
``` | 0 |
365 | A | Good Number | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number every time it occurs in array *a*). | The first line contains integers *n* and *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=9). The *i*-th of the following *n* lines contains integer *a**i* without leading zeroes (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the number of *k*-good numbers in *a*. | [
"10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n",
"2 1\n1\n10\n"
] | [
"10\n",
"1\n"
] | none | 500 | [
{
"input": "10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560",
"output": "10"
},
{
"input": "2 1\n1\n10",
"output": "1"
},
{
"input": "1 0\n1000000000",
"output": "1"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
... | 1,658,839,665 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 93 | 2,048,000 | # -*- coding: utf-8 -*-
"""
Created on Tue Jul 26 13:41:09 2022
@author: Conor
CFSheet A Problem 70 - CF365-DIV2A
"""
sz, good = map(int,input().split())
ans = 0
for i in range(sz):
seen = [0]*(good+1)
track = 0
newNum = list(str(input()))
for i in range(len(newNum)):
if int(newNum[i]) <= good and seen[int(newNum[i])] == 0:
track += 1
seen[int(newNum[i])] += 1
if track == (good+1):
ans += 1
print(ans) | Title: Good Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number every time it occurs in array *a*).
Input Specification:
The first line contains integers *n* and *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=9). The *i*-th of the following *n* lines contains integer *a**i* without leading zeroes (1<=≤<=*a**i*<=≤<=109).
Output Specification:
Print a single integer — the number of *k*-good numbers in *a*.
Demo Input:
['10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n', '2 1\n1\n10\n']
Demo Output:
['10\n', '1\n']
Note:
none | ```python
# -*- coding: utf-8 -*-
"""
Created on Tue Jul 26 13:41:09 2022
@author: Conor
CFSheet A Problem 70 - CF365-DIV2A
"""
sz, good = map(int,input().split())
ans = 0
for i in range(sz):
seen = [0]*(good+1)
track = 0
newNum = list(str(input()))
for i in range(len(newNum)):
if int(newNum[i]) <= good and seen[int(newNum[i])] == 0:
track += 1
seen[int(newNum[i])] += 1
if track == (good+1):
ans += 1
print(ans)
``` | -1 | |
664 | A | Complicated GCD | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | Greatest common divisor *GCD*(*a*,<=*b*) of two positive integers *a* and *b* is equal to the biggest integer *d* such that both integers *a* and *b* are divisible by *d*. There are many efficient algorithms to find greatest common divisor *GCD*(*a*,<=*b*), for example, Euclid algorithm.
Formally, find the biggest integer *d*, such that all integers *a*,<=*a*<=+<=1,<=*a*<=+<=2,<=...,<=*b* are divisible by *d*. To make the problem even more complicated we allow *a* and *b* to be up to googol, 10100 — such number do not fit even in 64-bit integer type! | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10100). | Output one integer — greatest common divisor of all integers from *a* to *b* inclusive. | [
"1 2\n",
"61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576\n"
] | [
"1\n",
"61803398874989484820458683436563811772030917980576\n"
] | none | 500 | [
{
"input": "1 2",
"output": "1"
},
{
"input": "61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576",
"output": "61803398874989484820458683436563811772030917980576"
},
{
"input": "1 100",
"output": "1"
},
{
"input": "100 100000... | 1,635,763,500 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 28 | 62 | 28,364,800 | n = list(map(int, input().split()))
if n[0] != n[1]:
print(1)
else:
print(n[0])
| Title: Complicated GCD
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greatest common divisor *GCD*(*a*,<=*b*) of two positive integers *a* and *b* is equal to the biggest integer *d* such that both integers *a* and *b* are divisible by *d*. There are many efficient algorithms to find greatest common divisor *GCD*(*a*,<=*b*), for example, Euclid algorithm.
Formally, find the biggest integer *d*, such that all integers *a*,<=*a*<=+<=1,<=*a*<=+<=2,<=...,<=*b* are divisible by *d*. To make the problem even more complicated we allow *a* and *b* to be up to googol, 10100 — such number do not fit even in 64-bit integer type!
Input Specification:
The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10100).
Output Specification:
Output one integer — greatest common divisor of all integers from *a* to *b* inclusive.
Demo Input:
['1 2\n', '61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576\n']
Demo Output:
['1\n', '61803398874989484820458683436563811772030917980576\n']
Note:
none | ```python
n = list(map(int, input().split()))
if n[0] != n[1]:
print(1)
else:
print(n[0])
``` | 3 | |
867 | A | Between the Offices | PROGRAMMING | 800 | [
"implementation"
] | null | null | As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't remember the number of flights you have made in either direction. However, for each of the last *n* days you know whether you were in San Francisco office or in Seattle office. You always fly at nights, so you never were at both offices on the same day. Given this information, determine if you flew more times from Seattle to San Francisco during the last *n* days, or not. | The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given in chronological order, i.e. today is the last day in this sequence. | Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower). | [
"4\nFSSF\n",
"2\nSF\n",
"10\nFFFFFFFFFF\n",
"10\nSSFFSFFSFF\n"
] | [
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you stayed the whole period in San Francisco, so the answer is "NO".
In the fourth example if you replace 'S' with ones, and 'F' with zeros, you'll get the first few digits of π in binary representation. Not very useful information though. | 500 | [
{
"input": "4\nFSSF",
"output": "NO"
},
{
"input": "2\nSF",
"output": "YES"
},
{
"input": "10\nFFFFFFFFFF",
"output": "NO"
},
{
"input": "10\nSSFFSFFSFF",
"output": "YES"
},
{
"input": "20\nSFSFFFFSSFFFFSSSSFSS",
"output": "NO"
},
{
"input": "20\nSSFFF... | 1,562,156,065 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 109 | 0 |
n = int(input())
a = str(input(''))
b = list(a)
for i in range(0, n):
if n/2 == 0:
n = n/2
if n == 1:
if b[n] == 'S':
Print("YES")
else:
print("NO")
break
break
else:
n = n%2
if b[n] == 'S':
print("YES")
break
else:
print("NO")
break
| Title: Between the Offices
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't remember the number of flights you have made in either direction. However, for each of the last *n* days you know whether you were in San Francisco office or in Seattle office. You always fly at nights, so you never were at both offices on the same day. Given this information, determine if you flew more times from Seattle to San Francisco during the last *n* days, or not.
Input Specification:
The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given in chronological order, i.e. today is the last day in this sequence.
Output Specification:
Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower).
Demo Input:
['4\nFSSF\n', '2\nSF\n', '10\nFFFFFFFFFF\n', '10\nSSFFSFFSFF\n']
Demo Output:
['NO\n', 'YES\n', 'NO\n', 'YES\n']
Note:
In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you stayed the whole period in San Francisco, so the answer is "NO".
In the fourth example if you replace 'S' with ones, and 'F' with zeros, you'll get the first few digits of π in binary representation. Not very useful information though. | ```python
n = int(input())
a = str(input(''))
b = list(a)
for i in range(0, n):
if n/2 == 0:
n = n/2
if n == 1:
if b[n] == 'S':
Print("YES")
else:
print("NO")
break
break
else:
n = n%2
if b[n] == 'S':
print("YES")
break
else:
print("NO")
break
``` | 0 | |
948 | A | Protect Sheep | PROGRAMMING | 900 | [
"brute force",
"dfs and similar",
"graphs",
"implementation"
] | null | null | Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of *R*<=×<=*C* cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number. | First line contains two integers *R* (1<=≤<=*R*<=≤<=500) and *C* (1<=≤<=*C*<=≤<=500), denoting the number of rows and the numbers of columns respectively.
Each of the following *R* lines is a string consisting of exactly *C* characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell. | If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print *R* lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs. | [
"6 6\n..S...\n..S.W.\n.S....\n..W...\n...W..\n......\n",
"1 2\nSW\n",
"5 5\n.S...\n...S.\nS....\n...S.\n.S...\n"
] | [
"Yes\n..SD..\n..SDW.\n.SD...\n.DW...\nDD.W..\n......\n",
"No\n",
"Yes\n.S...\n...S.\nS.D..\n...S.\n.S...\n"
] | In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him. | 500 | [
{
"input": "1 2\nSW",
"output": "No"
},
{
"input": "10 10\n....W.W.W.\n.........S\n.S.S...S..\nW.......SS\n.W..W.....\n.W...W....\nS..S...S.S\n....W...S.\n..S..S.S.S\nSS.......S",
"output": "Yes\nDDDDWDWDWD\nDDDDDDDDDS\nDSDSDDDSDD\nWDDDDDDDSS\nDWDDWDDDDD\nDWDDDWDDDD\nSDDSDDDSDS\nDDDDWDDDSD\nDDSD... | 1,520,696,935 | 835 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 61 | 5,632,000 | n,m = map(int,input().split())
a = []
for i in range(n):
b = [ i for i in input() ]
a.append(b)
status = True
for i in range(n):
for j in range(m):
if a[i][j] == 'W':
if i > 0 and a[i-1][j]!='G':
a[i-1][j]='D'
else:
status = False
if i < n-1 and a[i+1][j]!='G':
a[i+1][j]='D'
else:
status = False
if j > 0 and a[i][j-1] !='G':
a[i][j-1] = 'D'
else:
status = False
if j < m-1 and a[i][j+1]!='G':
a[i][j+1] = 'D'
else:
status = False
if status == False:
break
if status == False:
print("No")
else:
print("Yes")
for i in range(n):
print( "".join(a[i]))
| Title: Protect Sheep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of *R*<=×<=*C* cells. Each cell is either empty, contains a sheep, a wolf or a dog. Sheep and dogs always stay in place, but wolves can roam freely around the pasture, by repeatedly moving to the left, right, up or down to a neighboring cell. When a wolf enters a cell with a sheep, it consumes it. However, no wolf can enter a cell with a dog.
Initially there are no dogs. Place dogs onto the pasture in such a way that no wolf can reach any sheep, or determine that it is impossible. Note that since you have many dogs, you do not need to minimize their number.
Input Specification:
First line contains two integers *R* (1<=≤<=*R*<=≤<=500) and *C* (1<=≤<=*C*<=≤<=500), denoting the number of rows and the numbers of columns respectively.
Each of the following *R* lines is a string consisting of exactly *C* characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' an empty cell.
Output Specification:
If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print *R* lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a sheep or a wolf.
If there are multiple solutions, you may print any of them. You don't have to minimize the number of dogs.
Demo Input:
['6 6\n..S...\n..S.W.\n.S....\n..W...\n...W..\n......\n', '1 2\nSW\n', '5 5\n.S...\n...S.\nS....\n...S.\n.S...\n']
Demo Output:
['Yes\n..SD..\n..SDW.\n.SD...\n.DW...\nDD.W..\n......\n', 'No\n', 'Yes\n.S...\n...S.\nS.D..\n...S.\n.S...\n']
Note:
In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves, so the task is very easy. We put a dog in the center to observe the peacefulness of the meadow, but the solution would be correct even without him. | ```python
n,m = map(int,input().split())
a = []
for i in range(n):
b = [ i for i in input() ]
a.append(b)
status = True
for i in range(n):
for j in range(m):
if a[i][j] == 'W':
if i > 0 and a[i-1][j]!='G':
a[i-1][j]='D'
else:
status = False
if i < n-1 and a[i+1][j]!='G':
a[i+1][j]='D'
else:
status = False
if j > 0 and a[i][j-1] !='G':
a[i][j-1] = 'D'
else:
status = False
if j < m-1 and a[i][j+1]!='G':
a[i][j+1] = 'D'
else:
status = False
if status == False:
break
if status == False:
print("No")
else:
print("Yes")
for i in range(n):
print( "".join(a[i]))
``` | 0 | |
739 | B | Alyona and a tree | PROGRAMMING | 1,900 | [
"binary search",
"data structures",
"dfs and similar",
"graphs",
"trees"
] | null | null | Alyona has a tree with *n* vertices. The root of the tree is the vertex 1. In each vertex Alyona wrote an positive integer, in the vertex *i* she wrote *a**i*. Moreover, the girl wrote a positive integer to every edge of the tree (possibly, different integers on different edges).
Let's define *dist*(*v*,<=*u*) as the sum of the integers written on the edges of the simple path from *v* to *u*.
The vertex *v* controls the vertex *u* (*v*<=≠<=*u*) if and only if *u* is in the subtree of *v* and *dist*(*v*,<=*u*)<=≤<=*a**u*.
Alyona wants to settle in some vertex. In order to do this, she wants to know for each vertex *v* what is the number of vertices *u* such that *v* controls *u*. | The first line contains single integer *n* (1<=≤<=*n*<=≤<=2·105).
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the integers written in the vertices.
The next (*n*<=-<=1) lines contain two integers each. The *i*-th of these lines contains integers *p**i* and *w**i* (1<=≤<=*p**i*<=≤<=*n*, 1<=≤<=*w**i*<=≤<=109) — the parent of the (*i*<=+<=1)-th vertex in the tree and the number written on the edge between *p**i* and (*i*<=+<=1).
It is guaranteed that the given graph is a tree. | Print *n* integers — the *i*-th of these numbers should be equal to the number of vertices that the *i*-th vertex controls. | [
"5\n2 5 1 4 6\n1 7\n1 1\n3 5\n3 6\n",
"5\n9 7 8 6 5\n1 1\n2 1\n3 1\n4 1\n"
] | [
"1 0 1 0 0\n",
"4 3 2 1 0\n"
] | In the example test case the vertex 1 controls the vertex 3, the vertex 3 controls the vertex 5 (note that is doesn't mean the vertex 1 controls the vertex 5). | 1,000 | [
{
"input": "5\n2 5 1 4 6\n1 7\n1 1\n3 5\n3 6",
"output": "1 0 1 0 0"
},
{
"input": "5\n9 7 8 6 5\n1 1\n2 1\n3 1\n4 1",
"output": "4 3 2 1 0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "2\n1 1\n1 1",
"output": "1 0"
},
{
"input": "10\n40 77 65 14 86 16 2 51 ... | 1,480,050,682 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 14 | 2,000 | 40,038,400 | n=int(input())
a=[0]+[int(i) for i in input().split()]
p={}
pv={}
c=[0]*(n+1)
for i in range(1,n):
v,u=[int(i) for i in input().split()]
p[i+1]=v
pv[(v,i+1)]=u
def dept(node):
if node==1:
return 0
x=pv[(p[node],node)]
pr=p[node]
while pr!=1:
x+=pv[(p[pr],pr)]
pr=p[pr]
return x
deep=[0]+[0]+[dept(i) for i in range(2,n+1)]
def dfs(x):
global c
pr=p[x]
while deep[x]-deep[pr]<=a[x]:
c[pr]+=1
if pr==1:
break
pr=p[pr]
for i in range(2,n+1):
dfs(i)
print('%s '*n %tuple(c[1:])) | Title: Alyona and a tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alyona has a tree with *n* vertices. The root of the tree is the vertex 1. In each vertex Alyona wrote an positive integer, in the vertex *i* she wrote *a**i*. Moreover, the girl wrote a positive integer to every edge of the tree (possibly, different integers on different edges).
Let's define *dist*(*v*,<=*u*) as the sum of the integers written on the edges of the simple path from *v* to *u*.
The vertex *v* controls the vertex *u* (*v*<=≠<=*u*) if and only if *u* is in the subtree of *v* and *dist*(*v*,<=*u*)<=≤<=*a**u*.
Alyona wants to settle in some vertex. In order to do this, she wants to know for each vertex *v* what is the number of vertices *u* such that *v* controls *u*.
Input Specification:
The first line contains single integer *n* (1<=≤<=*n*<=≤<=2·105).
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the integers written in the vertices.
The next (*n*<=-<=1) lines contain two integers each. The *i*-th of these lines contains integers *p**i* and *w**i* (1<=≤<=*p**i*<=≤<=*n*, 1<=≤<=*w**i*<=≤<=109) — the parent of the (*i*<=+<=1)-th vertex in the tree and the number written on the edge between *p**i* and (*i*<=+<=1).
It is guaranteed that the given graph is a tree.
Output Specification:
Print *n* integers — the *i*-th of these numbers should be equal to the number of vertices that the *i*-th vertex controls.
Demo Input:
['5\n2 5 1 4 6\n1 7\n1 1\n3 5\n3 6\n', '5\n9 7 8 6 5\n1 1\n2 1\n3 1\n4 1\n']
Demo Output:
['1 0 1 0 0\n', '4 3 2 1 0\n']
Note:
In the example test case the vertex 1 controls the vertex 3, the vertex 3 controls the vertex 5 (note that is doesn't mean the vertex 1 controls the vertex 5). | ```python
n=int(input())
a=[0]+[int(i) for i in input().split()]
p={}
pv={}
c=[0]*(n+1)
for i in range(1,n):
v,u=[int(i) for i in input().split()]
p[i+1]=v
pv[(v,i+1)]=u
def dept(node):
if node==1:
return 0
x=pv[(p[node],node)]
pr=p[node]
while pr!=1:
x+=pv[(p[pr],pr)]
pr=p[pr]
return x
deep=[0]+[0]+[dept(i) for i in range(2,n+1)]
def dfs(x):
global c
pr=p[x]
while deep[x]-deep[pr]<=a[x]:
c[pr]+=1
if pr==1:
break
pr=p[pr]
for i in range(2,n+1):
dfs(i)
print('%s '*n %tuple(c[1:]))
``` | 0 |
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