contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
641 | A | Little Artem and Grasshopper | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Little Artem found a grasshopper. He brought it to his house and constructed a jumping area for him.
The area looks like a strip of cells 1<=×<=*n*. Each cell contains the direction for the next jump and the length of that jump. Grasshopper starts in the first cell and follows the instructions written on the cells. Gr... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — length of the strip.
Next line contains a string of length *n* which consists of characters "<" and ">" only, that provide the direction of the jump from the corresponding cell. Next line contains *n* integers *d**i* (1<=≤<=*d*... | Print "INFINITE" (without quotes) if grasshopper will continue his jumps forever. Otherwise print "FINITE" (without quotes). | [
"2\n><\n1 2\n",
"3\n>><\n2 1 1\n"
] | [
"FINITE\n",
"INFINITE"
] | In the first sample grasshopper starts from the first cell and jumps to the right on the next cell. When he is in the second cell he needs to jump two cells left so he will jump out of the strip.
Second sample grasshopper path is 1 - 3 - 2 - 3 - 2 - 3 and so on. The path is infinite. | 500 | [
{
"input": "2\n><\n1 2",
"output": "FINITE"
},
{
"input": "3\n>><\n2 1 1",
"output": "INFINITE"
},
{
"input": "1\n>\n1000000000",
"output": "FINITE"
},
{
"input": "1\n<\n1000000000",
"output": "FINITE"
},
{
"input": "2\n>>\n1 1",
"output": "FINITE"
},
{
... | 1,461,774,497 | 2,147,483,647 | Python 3 | OK | TESTS | 60 | 155 | 12,390,400 | line_length = int(input())
directions = input()
distances = [int(distance) for distance in input().split()]
visited_cells = set()
current_cell = 0
while 0 <= current_cell < line_length:
if current_cell in visited_cells:
break
else:
visited_cells.add(current_cell)
if directions[... | Title: Little Artem and Grasshopper
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem found a grasshopper. He brought it to his house and constructed a jumping area for him.
The area looks like a strip of cells 1<=×<=*n*. Each cell contains the direction for the next jump and t... | ```python
line_length = int(input())
directions = input()
distances = [int(distance) for distance in input().split()]
visited_cells = set()
current_cell = 0
while 0 <= current_cell < line_length:
if current_cell in visited_cells:
break
else:
visited_cells.add(current_cell)
if d... | 3 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,652,938,342 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 4,505,600 | s = input()
r = ''
i = 0
while i < len(s):
if s[i] == '.':
r += '0'
i += 1
elif s[i] == '-':
if s[i + 1] == '.':
r += '1'
elif s[i + 1] == '-':
r += '2'
i += 2
print(r)
| Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
s = input()
r = ''
i = 0
while i < len(s):
if s[i] == '.':
r += '0'
i += 1
elif s[i] == '-':
if s[i + 1] == '.':
r += '1'
elif s[i + 1] == '-':
r += '2'
i += 2
print(r)
``` | 3.968608 |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,647,012,803 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 62 | 0 |
r,c = list(map(int, input().split()))
row = [0]*r
col = [0]*c
for i in range(r):
string = input()
for j in range(c):
if string[j] == 'S':
row[i]=1
col[j]=1
cakes = 0
for i in range(r):
for j in range(c):
if row[i]==0 or col[j]==0:
cake... | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
r,c = list(map(int, input().split()))
row = [0]*r
col = [0]*c
for i in range(r):
string = input()
for j in range(c):
if string[j] == 'S':
row[i]=1
col[j]=1
cakes = 0
for i in range(r):
for j in range(c):
if row[i]==0 or col[j]==0:
... | 3 | |
218 | A | Mountain Scenery | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Little Bolek has found a picture with *n* mountain peaks painted on it. The *n* painted peaks are represented by a non-closed polyline, consisting of 2*n* segments. The segments go through 2*n*<=+<=1 points with coordinates (1,<=*y*1), (2,<=*y*2), ..., (2*n*<=+<=1,<=*y*2*n*<=+<=1), with the *i*-th segment connecting th... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=100). The next line contains 2*n*<=+<=1 space-separated integers *r*1,<=*r*2,<=...,<=*r*2*n*<=+<=1 (0<=≤<=*r**i*<=≤<=100) — the *y* coordinates of the polyline vertices on Bolek's picture.
It is guaranteed that we can obtain the gi... | Print 2*n*<=+<=1 integers *y*1,<=*y*2,<=...,<=*y*2*n*<=+<=1 — the *y* coordinates of the vertices of the polyline on the initial picture. If there are multiple answers, output any one of them. | [
"3 2\n0 5 3 5 1 5 2\n",
"1 1\n0 2 0\n"
] | [
"0 5 3 4 1 4 2 \n",
"0 1 0 \n"
] | none | 500 | [
{
"input": "3 2\n0 5 3 5 1 5 2",
"output": "0 5 3 4 1 4 2 "
},
{
"input": "1 1\n0 2 0",
"output": "0 1 0 "
},
{
"input": "1 1\n1 100 0",
"output": "1 99 0 "
},
{
"input": "3 1\n0 1 0 1 0 2 0",
"output": "0 1 0 1 0 1 0 "
},
{
"input": "3 1\n0 1 0 2 0 1 0",
"out... | 1,633,184,034 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 6,758,400 | n, k = map(int, input().split())
data = list(map(int, input().split()))
for i in range(1, k, 2):
data[i] += 1
print(*data) | Title: Mountain Scenery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Bolek has found a picture with *n* mountain peaks painted on it. The *n* painted peaks are represented by a non-closed polyline, consisting of 2*n* segments. The segments go through 2*n*<=+<=1 points with coordi... | ```python
n, k = map(int, input().split())
data = list(map(int, input().split()))
for i in range(1, k, 2):
data[i] += 1
print(*data)
``` | 0 | |
479 | A | Expression | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resul... | The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10). | Print the maximum value of the expression that you can obtain. | [
"1\n2\n3\n",
"2\n10\n3\n"
] | [
"9\n",
"60\n"
] | none | 500 | [
{
"input": "1\n2\n3",
"output": "9"
},
{
"input": "2\n10\n3",
"output": "60"
},
{
"input": "1\n1\n1",
"output": "3"
},
{
"input": "1\n2\n1",
"output": "4"
},
{
"input": "10\n10\n10",
"output": "1000"
},
{
"input": "5\n1\n3",
"output": "20"
},
{... | 1,693,882,742 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | def Expression(a , b , c):
list_of_Expression = list()
list_of_Expression.append(a + b * c)
list_of_Expression.append(a * (b + c))
list_of_Expression.append(a * b * c)
list_of_Expression.append((a + b) * c)
return max(list_of_Expression)
if __name__ == "__main__":
a = int(input())
... | Title: Expression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of ... | ```python
def Expression(a , b , c):
list_of_Expression = list()
list_of_Expression.append(a + b * c)
list_of_Expression.append(a * (b + c))
list_of_Expression.append(a * b * c)
list_of_Expression.append((a + b) * c)
return max(list_of_Expression)
if __name__ == "__main__":
a = int... | 0 | |
612 | B | HDD is Outdated Technology | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | HDD hard drives group data by sectors. All files are split to fragments and each of them are written in some sector of hard drive. Note the fragments can be written in sectors in arbitrary order.
One of the problems of HDD hard drives is the following: the magnetic head should move from one sector to another to read s... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of fragments.
The second line contains *n* different integers *f**i* (1<=≤<=*f**i*<=≤<=*n*) — the number of the fragment written in the *i*-th sector. | Print the only integer — the number of time units needed to read the file. | [
"3\n3 1 2\n",
"5\n1 3 5 4 2\n"
] | [
"3\n",
"10\n"
] | In the second example the head moves in the following way:
- 1->2 means movement from the sector 1 to the sector 5, i.e. it takes 4 time units - 2->3 means movement from the sector 5 to the sector 2, i.e. it takes 3 time units - 3->4 means movement from the sector 2 to the sector 4, i.e. it takes 2 time un... | 0 | [
{
"input": "3\n3 1 2",
"output": "3"
},
{
"input": "5\n1 3 5 4 2",
"output": "10"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "10\n8 2 10 3 4 6 1 7 9 5",
"output": "40"
... | 1,451,198,777 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 |
n=input()
a=list(map(int,input().split()))
y=0
for x in [a.index(l) for l in range(1,n,1)]:
y=y+x
print (y) | Title: HDD is Outdated Technology
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HDD hard drives group data by sectors. All files are split to fragments and each of them are written in some sector of hard drive. Note the fragments can be written in sectors in arbitrary order.
One of the ... | ```python
n=input()
a=list(map(int,input().split()))
y=0
for x in [a.index(l) for l in range(1,n,1)]:
y=y+x
print (y)
``` | -1 | |
431 | C | k-Tree | PROGRAMMING | 1,600 | [
"dp",
"implementation",
"trees"
] | null | null | Quite recently a creative student Lesha had a lecture on trees. After the lecture Lesha was inspired and came up with the tree of his own which he called a *k*-tree.
A *k*-tree is an infinite rooted tree where:
- each vertex has exactly *k* children; - each edge has some weight; - if we look at the edges that goes... | A single line contains three space-separated integers: *n*, *k* and *d* (1<=≤<=*n*,<=*k*<=≤<=100; 1<=≤<=*d*<=≤<=*k*). | Print a single integer — the answer to the problem modulo 1000000007 (109<=+<=7). | [
"3 3 2\n",
"3 3 3\n",
"4 3 2\n",
"4 5 2\n"
] | [
"3\n",
"1\n",
"6\n",
"7\n"
] | none | 1,500 | [
{
"input": "3 3 2",
"output": "3"
},
{
"input": "3 3 3",
"output": "1"
},
{
"input": "4 3 2",
"output": "6"
},
{
"input": "4 5 2",
"output": "7"
},
{
"input": "28 6 3",
"output": "110682188"
},
{
"input": "5 100 1",
"output": "16"
},
{
"inp... | 1,664,718,311 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 54 | 77 | 3,276,800 | def bootstrap(f, stack=[]):
def wrappedfunc(*args, **kwargs):
if stack:
return f(*args, **kwargs)
else:
to = stack.append(f(*args, **kwargs))
while True:
try:
to = stack.append(stack[-1].send(to))
except... | Title: k-Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently a creative student Lesha had a lecture on trees. After the lecture Lesha was inspired and came up with the tree of his own which he called a *k*-tree.
A *k*-tree is an infinite rooted tree where:
- each vertex ... | ```python
def bootstrap(f, stack=[]):
def wrappedfunc(*args, **kwargs):
if stack:
return f(*args, **kwargs)
else:
to = stack.append(f(*args, **kwargs))
while True:
try:
to = stack.append(stack[-1].send(to))
... | 3 | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,693,778,744 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 41 | 92 | 5,734,400 | def intmap():
return map(int, input().split())
# for i in range(int(input())):
n = int(input())
arr = list(intmap())
math = []
phy = []
prog = []
for i in range(len(arr)) :
if arr[i] == 1 :
math.append(i+1)
elif arr[i] == 2:
phy.append(i+1)
else :
prog.append(i+1)
... | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
def intmap():
return map(int, input().split())
# for i in range(int(input())):
n = int(input())
arr = list(intmap())
math = []
phy = []
prog = []
for i in range(len(arr)) :
if arr[i] == 1 :
math.append(i+1)
elif arr[i] == 2:
phy.append(i+1)
else :
prog.app... | 3 | |
467 | B | Fedor and New Game | PROGRAMMING | 1,100 | [
"bitmasks",
"brute force",
"constructive algorithms",
"implementation"
] | null | null | After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».
The game has (*m*<=+<=1) players and *n* types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (*m*<=+<=1). Types of soldiers are numbered from 0 to *n... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*k*<=≤<=*n*<=≤<=20; 1<=≤<=*m*<=≤<=1000).
The *i*-th of the next (*m*<=+<=1) lines contains a single integer *x**i* (1<=≤<=*x**i*<=≤<=2*n*<=-<=1), that describes the *i*-th player's army. We remind you that Fedor is the (*m*<=+<=1)-th player. | Print a single integer — the number of Fedor's potential friends. | [
"7 3 1\n8\n5\n111\n17\n",
"3 3 3\n1\n2\n3\n4\n"
] | [
"0\n",
"3\n"
] | none | 1,000 | [
{
"input": "7 3 1\n8\n5\n111\n17",
"output": "0"
},
{
"input": "3 3 3\n1\n2\n3\n4",
"output": "3"
},
{
"input": "4 2 2\n5\n6\n7",
"output": "2"
},
{
"input": "4 7 4\n9\n10\n5\n12\n4\n12\n7\n10",
"output": "7"
},
{
"input": "2 7 2\n1\n1\n1\n1\n1\n1\n1\n1",
"out... | 1,694,941,191 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 43 | 92 | 2,048,000 | from math import *
n,m,k=list(map(int,input().split()))
j=[]
Fedor=None
for i in range(m+1):
u=bin(int(input()))[2:]
u='0'*(20-len(u))+u
if i!=m:j.append(u)
else:Fedor=u
q=[0]*m
for i in range(20):
for u in range(len(j)):
if Fedor[i]!=j[u][i]:
q[u]+=1
print(len(list... | Title: Fedor and New Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».
The game has (*m*<=+<=1) players and *n* types of soldiers in total. Play... | ```python
from math import *
n,m,k=list(map(int,input().split()))
j=[]
Fedor=None
for i in range(m+1):
u=bin(int(input()))[2:]
u='0'*(20-len(u))+u
if i!=m:j.append(u)
else:Fedor=u
q=[0]*m
for i in range(20):
for u in range(len(j)):
if Fedor[i]!=j[u][i]:
q[u]+=1
prin... | 3 | |
611 | A | New Year and Days | PROGRAMMING | 900 | [
"implementation"
] | null | null | Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming year 2016.
Limak wants to prove how responsible a bear he is. He is going to regularly save candies for ... | The only line of the input is in one of the following two formats:
- "*x* of week" where *x* (1<=≤<=*x*<=≤<=7) denotes the day of the week. The 1-st day is Monday and the 7-th one is Sunday. - "*x* of month" where *x* (1<=≤<=*x*<=≤<=31) denotes the day of the month. | Print one integer — the number of candies Limak will save in the year 2016. | [
"4 of week\n",
"30 of month\n"
] | [
"52\n",
"11\n"
] | Polar bears use the Gregorian calendar. It is the most common calendar and you likely use it too. You can read about it on Wikipedia if you want to – [https://en.wikipedia.org/wiki/Gregorian_calendar](https://en.wikipedia.org/wiki/Gregorian_calendar). The week starts with Monday.
In the first sample Limak wants to sav... | 500 | [
{
"input": "4 of week",
"output": "52"
},
{
"input": "30 of month",
"output": "11"
},
{
"input": "17 of month",
"output": "12"
},
{
"input": "31 of month",
"output": "7"
},
{
"input": "6 of week",
"output": "53"
},
{
"input": "1 of week",
"output":... | 1,549,272,908 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 108 | 0 | a,b,c=map(str,input().split())
a=int(a)
if c=="week":
if a==6 or a==5:
print(53)
else:
print(52)
elif c=="month":
if a==30:
print(11)
elif a==31:
print(7)
else:
print(12) | Title: New Year and Days
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming ye... | ```python
a,b,c=map(str,input().split())
a=int(a)
if c=="week":
if a==6 or a==5:
print(53)
else:
print(52)
elif c=="month":
if a==30:
print(11)
elif a==31:
print(7)
else:
print(12)
``` | 3 | |
439 | A | Devu, the Singer and Churu, the Joker | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited.
Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* s... | The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100). | If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event. | [
"3 30\n2 2 1\n",
"3 20\n2 1 1\n"
] | [
"5\n",
"-1\n"
] | Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way:
- First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Ch... | 500 | [
{
"input": "3 30\n2 2 1",
"output": "5"
},
{
"input": "3 20\n2 1 1",
"output": "-1"
},
{
"input": "50 10000\n5 4 10 9 9 6 7 7 7 3 3 7 7 4 7 4 10 10 1 7 10 3 1 4 5 7 2 10 10 10 2 3 4 7 6 1 8 4 7 3 8 8 4 10 1 1 9 2 6 1",
"output": "1943"
},
{
"input": "50 10000\n4 7 15 9 11 12 ... | 1,673,784,295 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 102,400 | import collections
import math
def function():
"""
There is a total of 2 jokes after every song except for the last one, to use the rest period optimally
If the jokes between the songs drain all the time there is left for the last song: -1
else: jokes
"""
i = open(0)
readop = la... | Title: Devu, the Singer and Churu, the Joker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invit... | ```python
import collections
import math
def function():
"""
There is a total of 2 jokes after every song except for the last one, to use the rest period optimally
If the jokes between the songs drain all the time there is left for the last song: -1
else: jokes
"""
i = open(0)
r... | 0 | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,589,895,512 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 109 | 0 | n=int(input())
if n%2!=0:
print(0)
elif n//4==n/4:
print(n//4-1)
else:
print(n//4) | Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
n=int(input())
if n%2!=0:
print(0)
elif n//4==n/4:
print(n//4-1)
else:
print(n//4)
``` | 3 | |
108 | A | Palindromic Times | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | A. Palindromic Times | 2 | 256 | Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling asleep, he was staring at the digital watch around Saher's wrist. He noticed that the digits on th... | The first and only line of the input starts with a string with the format "HH:MM" where "HH" is from "00" to "23" and "MM" is from "00" to "59". Both "HH" and "MM" have exactly two digits. | Print the palindromic time of day that comes soonest after the time given in the input. If the input time is palindromic, output the soonest palindromic time after the input time. | [
"12:21\n",
"23:59\n"
] | [
"13:31\n",
"00:00\n"
] | none | 500 | [
{
"input": "12:21",
"output": "13:31"
},
{
"input": "23:59",
"output": "00:00"
},
{
"input": "15:51",
"output": "20:02"
},
{
"input": "10:44",
"output": "11:11"
},
{
"input": "04:02",
"output": "04:40"
},
{
"input": "02:11",
"output": "02:20"
},
... | 1,662,830,387 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | x = [int(x) for x in input().split(':')]
while True:
x[1] += 1
if x[1] == 60:
x[1] = 0
x[0] += 1
if x[0] == 24:
print('00:00')
break
if x[0] < 10:
if ('0' + str(x[0]))[::-1] == str(x[1]):
print(f"0{x[0]}:{x[1]}")
break
if x[1] < 10:
if (str(x[0]))[::-1] == '0'... | Title: Palindromic Times
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling... | ```python
x = [int(x) for x in input().split(':')]
while True:
x[1] += 1
if x[1] == 60:
x[1] = 0
x[0] += 1
if x[0] == 24:
print('00:00')
break
if x[0] < 10:
if ('0' + str(x[0]))[::-1] == str(x[1]):
print(f"0{x[0]}:{x[1]}")
break
if x[1] < 10:
if (str(x[0]))[::... | 0 |
862 | A | Mahmoud and Ehab and the MEX | PROGRAMMING | 1,000 | [
"greedy",
"implementation"
] | null | null | Dr. Evil kidnapped Mahmoud and Ehab in the evil land because of their performance in the Evil Olympiad in Informatics (EOI). He decided to give them some problems to let them go.
Dr. Evil is interested in sets, He has a set of *n* integers. Dr. Evil calls a set of integers evil if the MEX of it is exactly *x*. the MEX... | The first line contains two integers *n* and *x* (1<=≤<=*n*<=≤<=100, 0<=≤<=*x*<=≤<=100) — the size of the set Dr. Evil owns, and the desired MEX.
The second line contains *n* distinct non-negative integers not exceeding 100 that represent the set. | The only line should contain one integer — the minimal number of operations Dr. Evil should perform. | [
"5 3\n0 4 5 6 7\n",
"1 0\n0\n",
"5 0\n1 2 3 4 5\n"
] | [
"2\n",
"1\n",
"0\n"
] | For the first test case Dr. Evil should add 1 and 2 to the set performing 2 operations.
For the second test case Dr. Evil should erase 0 from the set. After that, the set becomes empty, so the MEX of it is 0.
In the third test case the set is already evil. | 500 | [
{
"input": "5 3\n0 4 5 6 7",
"output": "2"
},
{
"input": "1 0\n0",
"output": "1"
},
{
"input": "5 0\n1 2 3 4 5",
"output": "0"
},
{
"input": "10 5\n57 1 47 9 93 37 76 70 78 15",
"output": "4"
},
{
"input": "10 5\n99 98 93 97 95 100 92 94 91 96",
"output": "5"
... | 1,633,773,703 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 12 | 78 | 20,172,800 |
n,x=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
op=0
c=0
t=list()
for j in range(x):
t.append(j)
if x in a:
op+=1
for i in range(max(n,x)):
if i==n or i==x:
break
if t[i] not in a:
op+=1
print(op)
| Title: Mahmoud and Ehab and the MEX
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Evil kidnapped Mahmoud and Ehab in the evil land because of their performance in the Evil Olympiad in Informatics (EOI). He decided to give them some problems to let them go.
Dr. Evil is interested in ... | ```python
n,x=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
op=0
c=0
t=list()
for j in range(x):
t.append(j)
if x in a:
op+=1
for i in range(max(n,x)):
if i==n or i==x:
break
if t[i] not in a:
op+=1
print(op)
``` | 0 | |
877 | A | Alex and broken contest | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.
But there are too many problems, to do it manually. Alex asks you to write a program, which will determine if a problem is from this contest ... | The only line contains string from lowercase and uppercase letters and "_" symbols of length, not more than 100 — the name of the problem. | Print "YES", if problem is from this contest, and "NO" otherwise. | [
"Alex_and_broken_contest\n",
"NikitaAndString\n",
"Danil_and_Olya\n"
] | [
"NO",
"YES",
"NO"
] | none | 500 | [
{
"input": "Alex_and_broken_contest",
"output": "NO"
},
{
"input": "NikitaAndString",
"output": "YES"
},
{
"input": "Danil_and_Olya",
"output": "NO"
},
{
"input": "Slava____and_the_game",
"output": "YES"
},
{
"input": "Olya_and_energy_drinks",
"output": "YES"
... | 1,584,251,998 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 20 | 171 | 0 | s = input()
ss = ["Danil", "Olya", "Slava", "Ann","Nikita"]
flag = 0
vis = {"Danil":0, "Olya":0, "Slava":0, "Ann":0,"Nikita":0}
for i in ss:
if s.find(i) != -1:
vis[i] += 1
for key in vis:
if vis[key] >= 1:
flag += 1
if flag == 1:
print("YES")
else :
print("NO")
... | Title: Alex and broken contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.
But there are too many problems,... | ```python
s = input()
ss = ["Danil", "Olya", "Slava", "Ann","Nikita"]
flag = 0
vis = {"Danil":0, "Olya":0, "Slava":0, "Ann":0,"Nikita":0}
for i in ss:
if s.find(i) != -1:
vis[i] += 1
for key in vis:
if vis[key] >= 1:
flag += 1
if flag == 1:
print("YES")
else :
print("NO")
... | 0 | |
837 | A | Text Volume | PROGRAMMING | 800 | [
"implementation"
] | null | null | You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the text.
Calculate the volume of the given text. | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200) — length of the text.
The second line contains text of single-space separated words *s*1,<=*s*2,<=...,<=*s**i*, consisting only of small and capital Latin letters. | Print one integer number — volume of text. | [
"7\nNonZERO\n",
"24\nthis is zero answer text\n",
"24\nHarbour Space University\n"
] | [
"5\n",
"0\n",
"1\n"
] | In the first example there is only one word, there are 5 capital letters in it.
In the second example all of the words contain 0 capital letters. | 0 | [
{
"input": "7\nNonZERO",
"output": "5"
},
{
"input": "24\nthis is zero answer text",
"output": "0"
},
{
"input": "24\nHarbour Space University",
"output": "1"
},
{
"input": "2\nWM",
"output": "2"
},
{
"input": "200\nLBmJKQLCKUgtTxMoDsEerwvLOXsxASSydOqWyULsRcjMYDWd... | 1,646,507,743 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 30 | 0 | n = int(input())
a = list(input().split())
b = [0 for _ in range(len(a))]
for i in range(len(a)):
for j in range(len(a[i])):
if a[i][j].isupper():
b[i] += 1
print(min(b)) | Title: Text Volume
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the tex... | ```python
n = int(input())
a = list(input().split())
b = [0 for _ in range(len(a))]
for i in range(len(a)):
for j in range(len(a[i])):
if a[i][j].isupper():
b[i] += 1
print(min(b))
``` | 0 | |
681 | A | A Good Contest | PROGRAMMING | 800 | [
"implementation"
] | null | null | Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part in a rated contest, his rating is changed depending on his performance.
Anton wants the color of hi... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants Anton has outscored in this contest .
The next *n* lines describe participants results: the *i*-th of them consists of a participant handle *name**i* and two integers *before**i* and *after**i* (<=-<=4000<=≤<=*be... | Print «YES» (quotes for clarity), if Anton has performed good in the contest and «NO» (quotes for clarity) otherwise. | [
"3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749\n",
"3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450\n"
] | [
"YES",
"NO"
] | In the first sample, Anton has outscored user with handle Burunduk1, whose handle was colored red before the contest and his rating has increased after the contest.
In the second sample, Applejack's rating has not increased after the contest, while both Fluttershy's and Pinkie_Pie's handles were not colored red before... | 500 | [
{
"input": "3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749",
"output": "YES"
},
{
"input": "3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450",
"output": "NO"
},
{
"input": "1\nDb -3373 3591",
"output": "NO"
},
{
"input": "5\nQ2bz 960 2342... | 1,651,193,912 | 2,147,483,647 | PyPy 3 | OK | TESTS | 60 | 78 | 0 | n = int(input())
good = False
for x in range(0,n):
scores = input().split()
if int(scores[1]) >= 2400 and int(scores[2]) > int(scores[1]):
good = True
if good == False:
print("NO")
else:
print("YES") | Title: A Good Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part ... | ```python
n = int(input())
good = False
for x in range(0,n):
scores = input().split()
if int(scores[1]) >= 2400 and int(scores[2]) > int(scores[1]):
good = True
if good == False:
print("NO")
else:
print("YES")
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Stepan has the newest electronic device with a display. Different digits can be shown on it. Each digit is shown on a seven-section indicator like it is shown on the picture below.
So, for example, to show the digit 3 on the display, 5 sections must be highlighted; and for the digit 6, 6 sections must be highlighted. ... | The first line contains the integer *n* (2<=≤<=*n*<=≤<=100<=000) — the maximum number of sections which can be highlighted on the display. | Print the maximum integer which can be shown on the display of Stepan's newest device. | [
"2\n",
"3\n"
] | [
"1\n",
"7\n"
] | none | 0 | [
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "7"
},
{
"input": "4",
"output": "11"
},
{
"input": "5",
"output": "71"
},
{
"input": "6",
"output": "111"
},
{
"input": "85651",
"output": "711111111111111111111111111111111111111111111111... | 1,491,408,137 | 1,637 | Python 3 | OK | TESTS | 21 | 186 | 5,836,800 | n = int(input())
if n % 2 == 0:
for i in range(0, int(n/2)):
print('1', end='')
else:
print('7', end='')
for i in range(0, int(n/2)-1):
print('1', end='') | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Stepan has the newest electronic device with a display. Different digits can be shown on it. Each digit is shown on a seven-section indicator like it is shown on the picture below.
So, for example, to show the digit 3 on the disp... | ```python
n = int(input())
if n % 2 == 0:
for i in range(0, int(n/2)):
print('1', end='')
else:
print('7', end='')
for i in range(0, int(n/2)-1):
print('1', end='')
``` | 3 | |
272 | A | Dima and Friends | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single s... | In a single line print the answer to the problem. | [
"1\n1\n",
"1\n2\n",
"2\n3 5\n"
] | [
"3\n",
"2\n",
"3\n"
] | In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | 500 | [
{
"input": "1\n1",
"output": "3"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "1\n5",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "4"
},
{
"input": "... | 1,599,836,486 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 186 | 0 | n = int(input()) + 1
s = sum(list(map(int, input().split())))
if s%n == 0:
print(min(n-1, 4))
else:
print(min(n - s%n, 5)) | Title: Dima and Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the... | ```python
n = int(input()) + 1
s = sum(list(map(int, input().split())))
if s%n == 0:
print(min(n-1, 4))
else:
print(min(n - s%n, 5))
``` | 0 | |
976 | A | Minimum Binary Number | PROGRAMMING | 800 | [
"implementation"
] | null | null | String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" "110"... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=100) — the length of string *s*.
The second line contains the string *s* consisting of characters "0" and "1". It is guaranteed that the string *s* is correct. | Print one string — the minimum correct string that you can obtain from the given one. | [
"4\n1001\n",
"1\n1\n"
] | [
"100\n",
"1\n"
] | In the first example you can obtain the answer by the following sequence of operations: "1001" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "1010" <img align="middle" class="tex-formula" src="ht... | 0 | [
{
"input": "4\n1001",
"output": "100"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "100\n1110111100001111011111111010110011111111011110000111101101011100110110001011000000101010110101011100",
"output": "1000000000000000000000000000000000000000"
},
{
"input": "100\n100000... | 1,576,868,550 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 124 | 0 | n=int(input())
s=input()
emp=''
for i in s[1:]:
if(i!='1'):
emp+=i
print(emp) | Title: Minimum Binary Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two... | ```python
n=int(input())
s=input()
emp=''
for i in s[1:]:
if(i!='1'):
emp+=i
print(emp)
``` | 0 | |
486 | A | Calculating Function | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*. | The single line contains the positive integer *n* (1<=≤<=*n*<=≤<=1015). | Print *f*(*n*) in a single line. | [
"4\n",
"5\n"
] | [
"2\n",
"-3\n"
] | *f*(4) = - 1 + 2 - 3 + 4 = 2
*f*(5) = - 1 + 2 - 3 + 4 - 5 = - 3 | 500 | [
{
"input": "4",
"output": "2"
},
{
"input": "5",
"output": "-3"
},
{
"input": "1000000000",
"output": "500000000"
},
{
"input": "1000000001",
"output": "-500000001"
},
{
"input": "1000000000000000",
"output": "500000000000000"
},
{
"input": "100",
... | 1,692,421,255 | 2,147,483,647 | Python 3 | MEMORY_LIMIT_EXCEEDED | TESTS | 2 | 764 | 268,390,400 | n = int(input())
l = []
for i in range(1,n+1):
l.append(i)
ans = 0
for i in range(0,n-1,2):
ans = ans - l[i] + l[i+1]
if n%2==1:
ans -= l[n-1]
print(ans) | Title: Calculating Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*.
Input Specification:
The single line... | ```python
n = int(input())
l = []
for i in range(1,n+1):
l.append(i)
ans = 0
for i in range(0,n-1,2):
ans = ans - l[i] + l[i+1]
if n%2==1:
ans -= l[n-1]
print(ans)
``` | 0 | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,559,968,084 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 218 | 0 | # -*- coding: utf-8 -*-
"""
Created on Sat Jun 8 09:55:30 2019
@author: avina
"""
s = input()
e = input()
if s[::-1] == e:
print('YES')
else:
print('NO') | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
# -*- coding: utf-8 -*-
"""
Created on Sat Jun 8 09:55:30 2019
@author: avina
"""
s = input()
e = input()
if s[::-1] == e:
print('YES')
else:
print('NO')
``` | 3.9455 |
803 | B | Distances to Zero | PROGRAMMING | 1,200 | [
"constructive algorithms"
] | null | null | You are given the array of integer numbers *a*0,<=*a*1,<=...,<=*a**n*<=-<=1. For each element find the distance to the nearest zero (to the element which equals to zero). There is at least one zero element in the given array. | The first line contains integer *n* (1<=≤<=*n*<=≤<=2·105) — length of the array *a*. The second line contains integer elements of the array separated by single spaces (<=-<=109<=≤<=*a**i*<=≤<=109). | Print the sequence *d*0,<=*d*1,<=...,<=*d**n*<=-<=1, where *d**i* is the difference of indices between *i* and nearest *j* such that *a**j*<==<=0. It is possible that *i*<==<=*j*. | [
"9\n2 1 0 3 0 0 3 2 4\n",
"5\n0 1 2 3 4\n",
"7\n5 6 0 1 -2 3 4\n"
] | [
"2 1 0 1 0 0 1 2 3 ",
"0 1 2 3 4 ",
"2 1 0 1 2 3 4 "
] | none | 0 | [
{
"input": "9\n2 1 0 3 0 0 3 2 4",
"output": "2 1 0 1 0 0 1 2 3 "
},
{
"input": "5\n0 1 2 3 4",
"output": "0 1 2 3 4 "
},
{
"input": "7\n5 6 0 1 -2 3 4",
"output": "2 1 0 1 2 3 4 "
},
{
"input": "1\n0",
"output": "0 "
},
{
"input": "2\n0 0",
"output": "0 0 "
... | 1,689,138,872 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 164 | 171 | 30,720,000 | n=int(input())
ls=list(map(int,input().split()))
ls1=ls.copy()
mi=0x3f3f3f3f
for i in range(n):
if ls1[i]!=0:
ls1[i]=mi
else:
mi=0
mi+=1
ls.reverse()
mi=0x3f3f3f3f
for i in range(n):
if ls[i]!=0:
ls[i]=mi
else:
mi=0
mi+=1
ls.reverse()
lst=[0 for... | Title: Distances to Zero
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the array of integer numbers *a*0,<=*a*1,<=...,<=*a**n*<=-<=1. For each element find the distance to the nearest zero (to the element which equals to zero). There is at least one zero element in the give... | ```python
n=int(input())
ls=list(map(int,input().split()))
ls1=ls.copy()
mi=0x3f3f3f3f
for i in range(n):
if ls1[i]!=0:
ls1[i]=mi
else:
mi=0
mi+=1
ls.reverse()
mi=0x3f3f3f3f
for i in range(n):
if ls[i]!=0:
ls[i]=mi
else:
mi=0
mi+=1
ls.reverse()
... | 3 | |
16 | A | Flag | PROGRAMMING | 800 | [
"implementation"
] | A. Flag | 2 | 64 | According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of the same colour, and the colours of adjacent horizontal rows should be different. Be... | The first line of the input contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), *n* — the amount of rows, *m* — the amount of columns on the flag of Berland. Then there follows the description of the flag: each of the following *n* lines contain *m* characters. Each character is a digit between 0 and 9, and stands ... | Output YES, if the flag meets the new ISO standard, and NO otherwise. | [
"3 3\n000\n111\n222\n",
"3 3\n000\n000\n111\n",
"3 3\n000\n111\n002\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 0 | [
{
"input": "3 3\n000\n111\n222",
"output": "YES"
},
{
"input": "3 3\n000\n000\n111",
"output": "NO"
},
{
"input": "3 3\n000\n111\n002",
"output": "NO"
},
{
"input": "10 10\n2222222222\n5555555555\n0000000000\n4444444444\n1111111111\n3333333393\n3333333333\n5555555555\n0000000... | 1,635,141,684 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 4,505,600 | n,m=list(map(int, input().split()))
color=[]
for i in range(n):
new=input().split()
color=color+new
for t in range(n-1):
if color[t]==color[t+1]:
print("NO")
break
else:
for x in color:
if x.count(x[0])<m:
print("NO")
break
else:
... | Title: Flag
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of... | ```python
n,m=list(map(int, input().split()))
color=[]
for i in range(n):
new=input().split()
color=color+new
for t in range(n-1):
if color[t]==color[t+1]:
print("NO")
break
else:
for x in color:
if x.count(x[0])<m:
print("NO")
break
... | 3.943431 |
35 | D | Animals | PROGRAMMING | 1,700 | [
"dp",
"greedy"
] | D. Animals | 2 | 64 | Once upon a time DravDe, an outstanding person famous for his professional achievements (as you must remember, he works in a warehouse storing Ogudar-Olok, a magical but non-alcoholic drink) came home after a hard day. That day he had to drink 9875 boxes of the drink and, having come home, he went to bed at once.
Drav... | The first input line contains integers *n* and *X* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*X*<=≤<=104) — amount of days in DravDe’s dream and the total amount of food (in tons) that was there initially. The second line contains integers *c**i* (1<=≤<=*c**i*<=≤<=300). Numbers in the second line are divided by a space. | Output the only number — the maximum possible amount of animals on the farm by the end of the *n*-th day given that the food was enough for everybody. | [
"3 4\n1 1 1\n",
"3 6\n1 1 1\n"
] | [
"2\n",
"3\n"
] | Note to the first example: DravDe leaves the second and the third animal on the farm. The second animal will eat one ton of food on the second day and one ton on the third day. The third animal will eat one ton of food on the third day. | 2,000 | [
{
"input": "3 4\n1 1 1",
"output": "2"
},
{
"input": "3 6\n1 1 1",
"output": "3"
},
{
"input": "1 12\n1",
"output": "1"
},
{
"input": "3 100\n1 1 1",
"output": "3"
},
{
"input": "5 75\n1 1 1 1 1",
"output": "5"
},
{
"input": "7 115\n1 1 1 1 1 1 1",
... | 1,623,583,705 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 122 | 0 | from math import *
n,x=map(int,input().split())
arr=list(map(int,input().split()))
dp=[]
vis=[]
for i in range(n):
dp.append(0)
vis.append(False)
def dpsolve(i,left):
if i==n:
return 0
if left<0:
return -inf
if vis[i]:
return dp[i]
vis[i]=True
p1=1+d... | Title: Animals
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Once upon a time DravDe, an outstanding person famous for his professional achievements (as you must remember, he works in a warehouse storing Ogudar-Olok, a magical but non-alcoholic drink) came home after a hard day. That day he h... | ```python
from math import *
n,x=map(int,input().split())
arr=list(map(int,input().split()))
dp=[]
vis=[]
for i in range(n):
dp.append(0)
vis.append(False)
def dpsolve(i,left):
if i==n:
return 0
if left<0:
return -inf
if vis[i]:
return dp[i]
vis[i]=True
... | -1 |
295 | B | Greg and Graph | PROGRAMMING | 1,700 | [
"dp",
"graphs",
"shortest paths"
] | null | null | Greg has a weighed directed graph, consisting of *n* vertices. In this graph any pair of distinct vertices has an edge between them in both directions. Greg loves playing with the graph and now he has invented a new game:
- The game consists of *n* steps. - On the *i*-th step Greg removes vertex number *x**i* from t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=500) — the number of vertices in the graph.
Next *n* lines contain *n* integers each — the graph adjacency matrix: the *j*-th number in the *i*-th line *a**ij* (1<=≤<=*a**ij*<=≤<=105,<=*a**ii*<==<=0) represents the weight of the edge that goes from vertex *i* to verte... | Print *n* integers — the *i*-th number equals the required sum before the *i*-th step.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier. | [
"1\n0\n1\n",
"2\n0 5\n4 0\n1 2\n",
"4\n0 3 1 1\n6 0 400 1\n2 4 0 1\n1 1 1 0\n4 1 2 3\n"
] | [
"0 ",
"9 0 ",
"17 23 404 0 "
] | none | 1,000 | [
{
"input": "1\n0\n1",
"output": "0 "
},
{
"input": "2\n0 5\n4 0\n1 2",
"output": "9 0 "
},
{
"input": "4\n0 3 1 1\n6 0 400 1\n2 4 0 1\n1 1 1 0\n4 1 2 3",
"output": "17 23 404 0 "
},
{
"input": "4\n0 57148 51001 13357\n71125 0 98369 67226\n49388 90852 0 66291\n39573 38165 9700... | 1,658,675,585 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 13 | 3,000 | 8,908,800 | import sys
input = lambda : sys.stdin.readline().rstrip("\r\n")
n = int(input())
d = [[0 for _ in range(n)] for _ in range(n)]
res = [0 for _ in range(n)]
for i in range(n):
d[i] = list(map(int, input().split()))
x = [int(i) - 1 for i in input().split()]
x = x[::-1]
for k in range(n):
for i in... | Title: Greg and Graph
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg has a weighed directed graph, consisting of *n* vertices. In this graph any pair of distinct vertices has an edge between them in both directions. Greg loves playing with the graph and now he has invented a new game... | ```python
import sys
input = lambda : sys.stdin.readline().rstrip("\r\n")
n = int(input())
d = [[0 for _ in range(n)] for _ in range(n)]
res = [0 for _ in range(n)]
for i in range(n):
d[i] = list(map(int, input().split()))
x = [int(i) - 1 for i in input().split()]
x = x[::-1]
for k in range(n):
... | 0 | |
221 | A | Little Elephant and Function | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the permutation. The Little Elephant's recursive function *f*(*x*), that sorts the first *x* permutation's elements, works... | A single line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the size of permutation. | In a single line print *n* distinct integers from 1 to *n* — the required permutation. Numbers in a line should be separated by spaces.
It is guaranteed that the answer exists. | [
"1\n",
"2\n"
] | [
"1 ",
"2 1 "
] | none | 500 | [
{
"input": "1",
"output": "1 "
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "3",
"output": "3 1 2 "
},
{
"input": "4",
"output": "4 1 2 3 "
},
{
"input": "5",
"output": "5 1 2 3 4 "
},
{
"input": "6",
"output": "6 1 2 3 4 5 "
},
{
"inp... | 1,682,314,232 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 218 | 1,740,800 | n=int(input())
l=[]
l.append(n)
l+=[x for x in range(1,n)]
# l[0],l[n-1]=l[n-1],l[0]
for i in l:
print(i,end=" ") | Title: Little Elephant and Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the perm... | ```python
n=int(input())
l=[]
l.append(n)
l+=[x for x in range(1,n)]
# l[0],l[n-1]=l[n-1],l[0]
for i in l:
print(i,end=" ")
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*.
For example, 4-rounding of 375 is 375·80<==<=30000. 30000 is the minimum integer such that it ends with 4 or more zeros and is divisible by 375.
W... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=8). | Print the *k*-rounding of *n*. | [
"375 4\n",
"10000 1\n",
"38101 0\n",
"123456789 8\n"
] | [
"30000\n",
"10000\n",
"38101\n",
"12345678900000000\n"
] | none | 0 | [
{
"input": "375 4",
"output": "30000"
},
{
"input": "10000 1",
"output": "10000"
},
{
"input": "38101 0",
"output": "38101"
},
{
"input": "123456789 8",
"output": "12345678900000000"
},
{
"input": "1 0",
"output": "1"
},
{
"input": "2 0",
"output":... | 1,553,623,210 | 2,147,483,647 | Python 3 | OK | TESTS | 96 | 109 | 0 | import math
n = input().split(" ")
k = int(n[1])
n = int(n[0])
base = 10**k
d = math.gcd(n, base)
print(n*base//d)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*.
For example, 4-rounding of 375 is 375·80<==<=30000. 30000... | ```python
import math
n = input().split(" ")
k = int(n[1])
n = int(n[0])
base = 10**k
d = math.gcd(n, base)
print(n*base//d)
``` | 3 | |
697 | B | Barnicle | PROGRAMMING | 1,400 | [
"brute force",
"implementation",
"math",
"strings"
] | null | null | Barney is standing in a bar and starring at a pretty girl. He wants to shoot her with his heart arrow but he needs to know the distance between him and the girl to make his shot accurate.
Barney asked the bar tender Carl about this distance value, but Carl was so busy talking to the customers so he wrote the distance ... | The first and only line of input contains a single string of form *a*.*deb* where *a*, *d* and *b* are integers and *e* is usual character 'e' (0<=≤<=*a*<=≤<=9,<=0<=≤<=*d*<=<<=10100,<=0<=≤<=*b*<=≤<=100) — the scientific notation of the desired distance value.
*a* and *b* contain no leading zeros and *d* contains no... | Print the only real number *x* (the desired distance value) in the only line in its decimal notation.
Thus if *x* is an integer, print it's integer value without decimal part and decimal point and without leading zeroes.
Otherwise print *x* in a form of *p*.*q* such that *p* is an integer that have no leading zeroe... | [
"8.549e2\n",
"8.549e3\n",
"0.33e0\n"
] | [
"854.9\n",
"8549\n",
"0.33\n"
] | none | 1,000 | [
{
"input": "8.549e2",
"output": "854.9"
},
{
"input": "8.549e3",
"output": "8549"
},
{
"input": "0.33e0",
"output": "0.33"
},
{
"input": "1.31e1",
"output": "13.1"
},
{
"input": "1.038e0",
"output": "1.038"
},
{
"input": "8.25983e5",
"output": "825... | 1,611,726,894 | 4,494 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 614,400 |
from decimal import *
a=input()
b=Decimal(a)
print(b)
if(int(b)==b):
print ("%d"%b)
else:
print (b) | Title: Barnicle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Barney is standing in a bar and starring at a pretty girl. He wants to shoot her with his heart arrow but he needs to know the distance between him and the girl to make his shot accurate.
Barney asked the bar tender Carl abou... | ```python
from decimal import *
a=input()
b=Decimal(a)
print(b)
if(int(b)==b):
print ("%d"%b)
else:
print (b)
``` | 0 | |
13 | A | Numbers | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Numbers | 1 | 64 | Little Petya likes numbers a lot. He found that number 123 in base 16 consists of two digits: the first is 7 and the second is 11. So the sum of digits of 123 in base 16 is equal to 18.
Now he wonders what is an average value of sum of digits of the number *A* written in all bases from 2 to *A*<=-<=1.
Note that all c... | Input contains one integer number *A* (3<=≤<=*A*<=≤<=1000). | Output should contain required average value in format «X/Y», where X is the numerator and Y is the denominator. | [
"5\n",
"3\n"
] | [
"7/3\n",
"2/1\n"
] | In the first sample number 5 written in all bases from 2 to 4 looks so: 101, 12, 11. Sums of digits are 2, 3 and 2, respectively. | 0 | [
{
"input": "5",
"output": "7/3"
},
{
"input": "3",
"output": "2/1"
},
{
"input": "1000",
"output": "90132/499"
},
{
"input": "927",
"output": "155449/925"
},
{
"input": "260",
"output": "6265/129"
},
{
"input": "131",
"output": "3370/129"
},
{
... | 1,627,566,211 | 2,147,483,647 | PyPy 3 | OK | TESTS | 99 | 218 | 21,504,000 | from math import *
def f(n, base):
a = floor(log(n, base))
s = 0
while a >= 0:
s+= n//base**a
n -= n//base**a * base**a
a-=1
return s
A = int(input())
s = 0
for i in range(2, A):
s += f(A, i)
p = gcd(s, A - 2)
print(f'{s//p}/{(A-2)//p}') | Title: Numbers
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Little Petya likes numbers a lot. He found that number 123 in base 16 consists of two digits: the first is 7 and the second is 11. So the sum of digits of 123 in base 16 is equal to 18.
Now he wonders what is an average value of su... | ```python
from math import *
def f(n, base):
a = floor(log(n, base))
s = 0
while a >= 0:
s+= n//base**a
n -= n//base**a * base**a
a-=1
return s
A = int(input())
s = 0
for i in range(2, A):
s += f(A, i)
p = gcd(s, A - 2)
print(f'{s//p}/{(A-2)//p}')
``` | 3.730783 |
659 | A | Round House | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to *n*. Entrance *n* and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance *a* and he decided that during his walk he will move around the house *b* entrances in th... | The single line of the input contains three space-separated integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*a*<=≤<=*n*,<=<=-<=100<=≤<=*b*<=≤<=100) — the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively. | Print a single integer *k* (1<=≤<=*k*<=≤<=*n*) — the number of the entrance where Vasya will be at the end of his walk. | [
"6 2 -5\n",
"5 1 3\n",
"3 2 7\n"
] | [
"3\n",
"4\n",
"3\n"
] | The first example is illustrated by the picture in the statements. | 500 | [
{
"input": "6 2 -5",
"output": "3"
},
{
"input": "5 1 3",
"output": "4"
},
{
"input": "3 2 7",
"output": "3"
},
{
"input": "1 1 0",
"output": "1"
},
{
"input": "1 1 -1",
"output": "1"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "100 ... | 1,575,326,481 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 12 | 109 | 0 | entrances,beginning,steps = map(int,input().split())
if steps == 0:
print (beginning)
elif steps < 0:
print (beginning + abs(entrances+steps))
else:
endpoint = (beginning+steps)
result = endpoint%entrances if endpoint%entrances else endpoint//entrances
print (result if entrances >1 else 1) | Title: Round House
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to *n*. Entrance *n* and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in e... | ```python
entrances,beginning,steps = map(int,input().split())
if steps == 0:
print (beginning)
elif steps < 0:
print (beginning + abs(entrances+steps))
else:
endpoint = (beginning+steps)
result = endpoint%entrances if endpoint%entrances else endpoint//entrances
print (result if entrances >1... | 0 | |
585 | F | Digits of Number Pi | PROGRAMMING | 3,200 | [
"dp",
"implementation",
"strings"
] | null | null | Vasily has recently learned about the amazing properties of number π. In one of the articles it has been hypothesized that, whatever the sequence of numbers we have, in some position, this sequence is found among the digits of number π. Thus, if you take, for example, the epic novel "War and Peace" of famous Russian au... | The first line contains string *s* consisting of decimal digits (1<=≤<=|*s*|<=≤<=1000) that Vasily will use to search substrings in. According to hypothesis, this sequence of digis indeed occurs in the decimal representation of π, although we can't guarantee that.
The second and third lines contain two positive intege... | Print how many numbers in the segment from *x* to *y* that are half-occurrences in *s* modulo 109<=+<=7. | [
"02\n10\n19\n",
"023456789\n10\n19\n",
"31415926535\n10\n29\n"
] | [
"2\n",
"9\n",
"20\n"
] | none | 3,000 | [] | 1,687,679,982 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 8,806,400 | MOD = 10**9 + 7
class ACM:
def __init__(self):
self.ch = [[0] * 10 for _ in range(50005)]
self.fail = [0] * 50005
self.b = [False] * 50005
self.xb = 0
def ins(self, c, l):
u = 0
for i in range(l):
x = int(c[i])
if self.ch[u][... | Title: Digits of Number Pi
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily has recently learned about the amazing properties of number π. In one of the articles it has been hypothesized that, whatever the sequence of numbers we have, in some position, this sequence is found among th... | ```python
MOD = 10**9 + 7
class ACM:
def __init__(self):
self.ch = [[0] * 10 for _ in range(50005)]
self.fail = [0] * 50005
self.b = [False] * 50005
self.xb = 0
def ins(self, c, l):
u = 0
for i in range(l):
x = int(c[i])
if s... | -1 | |
1,006 | E | Military Problem | PROGRAMMING | 1,600 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | In this problem you will have to help Berland army with organizing their command delivery system.
There are $n$ officers in Berland army. The first officer is the commander of the army, and he does not have any superiors. Every other officer has exactly one direct superior. If officer $a$ is the direct superior of off... | The first line of the input contains two integers $n$ and $q$ ($2 \le n \le 2 \cdot 10^5, 1 \le q \le 2 \cdot 10^5$) — the number of officers in Berland army and the number of queries.
The second line of the input contains $n - 1$ integers $p_2, p_3, \dots, p_n$ ($1 \le p_i < i$), where $p_i$ is the index of the di... | Print $q$ numbers, where the $i$-th number is the officer at the position $k_i$ in the list which describes the order in which officers will receive the command if it starts spreading from officer $u_i$. Print "-1" if the number of officers which receive the command is less than $k_i$.
You should process queries indep... | [
"9 6\n1 1 1 3 5 3 5 7\n3 1\n1 5\n3 4\n7 3\n1 8\n1 9\n"
] | [
"3\n6\n8\n-1\n9\n4\n"
] | none | 0 | [
{
"input": "9 6\n1 1 1 3 5 3 5 7\n3 1\n1 5\n3 4\n7 3\n1 8\n1 9",
"output": "3\n6\n8\n-1\n9\n4"
},
{
"input": "2 1\n1\n1 1",
"output": "1"
},
{
"input": "13 12\n1 1 1 1 1 1 1 1 1 1 1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1\n1 1",
"output": "1\n1\n1\n1\n1\n1\n1\n1\n1\n... | 1,693,964,490 | 2,147,483,647 | PyPy 3 | OK | TESTS | 31 | 904 | 40,652,800 | import sys
from bisect import bisect_left,bisect_right
from collections import defaultdict as dd
from collections import deque, Counter
from heapq import heappop,heappush,heapify,merge
from itertools import permutations, accumulate, product
from math import gcd,sqrt,ceil
toBin=lambda x:bin(x).replace("0b","")
I... | Title: Military Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you will have to help Berland army with organizing their command delivery system.
There are $n$ officers in Berland army. The first officer is the commander of the army, and he does not have any superi... | ```python
import sys
from bisect import bisect_left,bisect_right
from collections import defaultdict as dd
from collections import deque, Counter
from heapq import heappop,heappush,heapify,merge
from itertools import permutations, accumulate, product
from math import gcd,sqrt,ceil
toBin=lambda x:bin(x).replace("... | 3 | |
873 | B | Balanced Substring | PROGRAMMING | 1,500 | [
"dp",
"implementation"
] | null | null | You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called balanced if the number of zeroes (0) equals to the number of ones in this substring.
You have to deter... | The first line contains *n* (1<=≤<=*n*<=≤<=100000) — the number of characters in *s*.
The second line contains a string *s* consisting of exactly *n* characters. Only characters 0 and 1 can appear in *s*. | If there is no non-empty balanced substring in *s*, print 0. Otherwise, print the length of the longest balanced substring. | [
"8\n11010111\n",
"3\n111\n"
] | [
"4\n",
"0\n"
] | In the first example you can choose the substring [3, 6]. It is balanced, and its length is 4. Choosing the substring [2, 5] is also possible.
In the second example it's impossible to find a non-empty balanced substring. | 0 | [
{
"input": "8\n11010111",
"output": "4"
},
{
"input": "3\n111",
"output": "0"
},
{
"input": "11\n00001000100",
"output": "2"
},
{
"input": "10\n0100000000",
"output": "2"
},
{
"input": "13\n0001000011010",
"output": "6"
},
{
"input": "14\n0000010010101... | 1,587,829,027 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 11 | 483 | 11,571,200 | import math as mt
import sys,string
input=sys.stdin.readline
import random
from collections import deque,defaultdict
L=lambda : list(map(int,input().split()))
Ls=lambda : list(input().split())
M=lambda : map(int,input().split())
I=lambda :int(input())
n=I()
d=defaultdict(int)
e=defaultdict(int)
s=input().strip()
x=[0]... | Title: Balanced Substring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called... | ```python
import math as mt
import sys,string
input=sys.stdin.readline
import random
from collections import deque,defaultdict
L=lambda : list(map(int,input().split()))
Ls=lambda : list(input().split())
M=lambda : map(int,input().split())
I=lambda :int(input())
n=I()
d=defaultdict(int)
e=defaultdict(int)
s=input().str... | 0 | |
321 | A | Ciel and Robot | PROGRAMMING | 1,700 | [
"binary search",
"implementation",
"math"
] | null | null | Fox Ciel has a robot on a 2D plane. Initially it is located in (0, 0). Fox Ciel code a command to it. The command was represented by string *s*. Each character of *s* is one move operation. There are four move operations at all:
- 'U': go up, (x, y) <=→<= (x, y+1); - 'D': go down, (x, y) <=→<= (x, y-1); - 'L': go l... | The first line contains two integers *a* and *b*, (<=-<=109<=≤<=*a*,<=*b*<=≤<=109). The second line contains a string *s* (1<=≤<=|*s*|<=≤<=100, *s* only contains characters 'U', 'D', 'L', 'R') — the command. | Print "Yes" if the robot will be located at (*a*,<=*b*), and "No" otherwise. | [
"2 2\nRU\n",
"1 2\nRU\n",
"-1 1000000000\nLRRLU\n",
"0 0\nD\n"
] | [
"Yes\n",
"No\n",
"Yes\n",
"Yes\n"
] | In the first and second test case, command string is "RU", so the robot will go right, then go up, then right, and then up and so on.
The locations of its moves are (0, 0) → (1, 0) → (1, 1) → (2, 1) → (2, 2) → ...
So it can reach (2, 2) but not (1, 2). | 500 | [
{
"input": "2 2\nRU",
"output": "Yes"
},
{
"input": "1 2\nRU",
"output": "No"
},
{
"input": "-1 1000000000\nLRRLU",
"output": "Yes"
},
{
"input": "0 0\nD",
"output": "Yes"
},
{
"input": "0 0\nUURRDL",
"output": "Yes"
},
{
"input": "987654321 987654321\... | 1,563,189,942 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 0 | n=int(input())
count=0
for i in range(n):
a,b,c=map(int,input().split())
if a==1 and b==1:
count+=1
elif a==1 and c==1:
count+=1
elif b==1 and c==1:
count+=1
else:
pass
print(count)
| Title: Ciel and Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel has a robot on a 2D plane. Initially it is located in (0, 0). Fox Ciel code a command to it. The command was represented by string *s*. Each character of *s* is one move operation. There are four move operations... | ```python
n=int(input())
count=0
for i in range(n):
a,b,c=map(int,input().split())
if a==1 and b==1:
count+=1
elif a==1 and c==1:
count+=1
elif b==1 and c==1:
count+=1
else:
pass
print(count)
``` | -1 | |
352 | B | Jeff and Periods | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | null | null | One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
- *x* occurs in sequence *a*. - Consider all positions of numbers *x* in the sequence *a* (such *i*, ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). The numbers are separated by spaces. | In the first line print integer *t* — the number of valid *x*. On each of the next *t* lines print two integers *x* and *p**x*, where *x* is current suitable value, *p**x* is the common difference between numbers in the progression (if *x* occurs exactly once in the sequence, *p**x* must equal 0). Print the pairs in th... | [
"1\n2\n",
"8\n1 2 1 3 1 2 1 5\n"
] | [
"1\n2 0\n",
"4\n1 2\n2 4\n3 0\n5 0\n"
] | In the first test 2 occurs exactly once in the sequence, ergo *p*<sub class="lower-index">2</sub> = 0. | 1,000 | [
{
"input": "1\n2",
"output": "1\n2 0"
},
{
"input": "8\n1 2 1 3 1 2 1 5",
"output": "4\n1 2\n2 4\n3 0\n5 0"
},
{
"input": "3\n1 10 5",
"output": "3\n1 0\n5 0\n10 0"
},
{
"input": "4\n9 9 3 5",
"output": "3\n3 0\n5 0\n9 1"
},
{
"input": "6\n1 2 2 1 1 2",
"outpu... | 1,652,463,812 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | from collections import defaultdict
i=int(input())
l=list(map(int,input().split()))
d=defaultdict(list)
for x in range(len(l)):
d[l[x]].append(x)
ans=[]
for x,y in d.items():
if len(y)==1:
ans.append((x,0))
else:
print(y)
p=[y[x+1]-y[x] for x in range(len(y)... | Title: Jeff and Periods
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
-... | ```python
from collections import defaultdict
i=int(input())
l=list(map(int,input().split()))
d=defaultdict(list)
for x in range(len(l)):
d[l[x]].append(x)
ans=[]
for x,y in d.items():
if len(y)==1:
ans.append((x,0))
else:
print(y)
p=[y[x+1]-y[x] for x in ra... | 0 | |
158 | A | Next Round | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | "Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of *n* participants took part in the contest (*n*<=≥<=*k*), and you already know their scores. Calculate... | The first line of the input contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50) separated by a single space.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100), where *a**i* is the score earned by the participant who got the *i*-th place. The given sequence... | Output the number of participants who advance to the next round. | [
"8 5\n10 9 8 7 7 7 5 5\n",
"4 2\n0 0 0 0\n"
] | [
"6\n",
"0\n"
] | In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.
In the second example nobody got a positive score. | 500 | [
{
"input": "8 5\n10 9 8 7 7 7 5 5",
"output": "6"
},
{
"input": "4 2\n0 0 0 0",
"output": "0"
},
{
"input": "5 1\n1 1 1 1 1",
"output": "5"
},
{
"input": "5 5\n1 1 1 1 1",
"output": "5"
},
{
"input": "1 1\n10",
"output": "1"
},
{
"input": "17 14\n16 15... | 1,697,141,087 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 92 | 0 | inputString = input().split()
countOfPlayers = 0
mark = int(inputString[1])
inputString = input().split()
arrOfNumbers = [int(x) for x in inputString]
mark = arrOfNumbers[mark]
for i in arrOfNumbers:
if i >= mark:
countOfPlayers += 1
print(countOfPlayers) | Title: Next Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of *n* p... | ```python
inputString = input().split()
countOfPlayers = 0
mark = int(inputString[1])
inputString = input().split()
arrOfNumbers = [int(x) for x in inputString]
mark = arrOfNumbers[mark]
for i in arrOfNumbers:
if i >= mark:
countOfPlayers += 1
print(countOfPlayers)
``` | 0 | |
16 | A | Flag | PROGRAMMING | 800 | [
"implementation"
] | A. Flag | 2 | 64 | According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of the same colour, and the colours of adjacent horizontal rows should be different. Be... | The first line of the input contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), *n* — the amount of rows, *m* — the amount of columns on the flag of Berland. Then there follows the description of the flag: each of the following *n* lines contain *m* characters. Each character is a digit between 0 and 9, and stands ... | Output YES, if the flag meets the new ISO standard, and NO otherwise. | [
"3 3\n000\n111\n222\n",
"3 3\n000\n000\n111\n",
"3 3\n000\n111\n002\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 0 | [
{
"input": "3 3\n000\n111\n222",
"output": "YES"
},
{
"input": "3 3\n000\n000\n111",
"output": "NO"
},
{
"input": "3 3\n000\n111\n002",
"output": "NO"
},
{
"input": "10 10\n2222222222\n5555555555\n0000000000\n4444444444\n1111111111\n3333333393\n3333333333\n5555555555\n0000000... | 1,660,058,313 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 186 | 0 |
a = list(map(int, input().split()))
n, m = a[0], a[1]
flag = []
count = 0
for i in range(n):
temp = input()
flag.append(temp)
for i in flag:
k = set(i)
if len(k) != 1:
print("NO")
break
elif flag.count(i) > 1:
print("NO")
break
else:
coun... | Title: Flag
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of... | ```python
a = list(map(int, input().split()))
n, m = a[0], a[1]
flag = []
count = 0
for i in range(n):
temp = input()
flag.append(temp)
for i in flag:
k = set(i)
if len(k) != 1:
print("NO")
break
elif flag.count(i) > 1:
print("NO")
break
else:
... | 0 |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,622,746,039 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 186 | 0 | s1=input()
s2=""
i=0
while i<len(s1):
if s1[i]=="-" and s1[i+1]=="-":
s2=s2+"2"
i=i+2
elif s1[i]=="-" and s1[i+1]==".":
s2=s2+"1"
i=i+2
else:
s2=s2+"0"
i=i+1
prnt(s2) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
s1=input()
s2=""
i=0
while i<len(s1):
if s1[i]=="-" and s1[i+1]=="-":
s2=s2+"2"
i=i+2
elif s1[i]=="-" and s1[i+1]==".":
s2=s2+"1"
i=i+2
else:
s2=s2+"0"
i=i+1
prnt(s2)
``` | -1 |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,647,703,258 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 102,400 | from collections import OrderedDict
def decide_winner(player_a, player_b, players):
for player in players:
if player == player_a:
return player_a
return player_b
if __name__ == "__main__":
players = OrderedDict()
n = int(input())
for i in range(n):
name, s... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
from collections import OrderedDict
def decide_winner(player_a, player_b, players):
for player in players:
if player == player_a:
return player_a
return player_b
if __name__ == "__main__":
players = OrderedDict()
n = int(input())
for i in range(n):
... | 0 |
363 | B | Fence | PROGRAMMING | 1,100 | [
"brute force",
"dp"
] | null | null | There is a fence in front of Polycarpus's home. The fence consists of *n* planks of the same width which go one after another from left to right. The height of the *i*-th plank is *h**i* meters, distinct planks can have distinct heights.
Polycarpus has bought a posh piano and is thinking about how to get it into the h... | The first line of the input contains integers *n* and *k* (1<=≤<=*n*<=≤<=1.5·105,<=1<=≤<=*k*<=≤<=*n*) — the number of planks in the fence and the width of the hole for the piano. The second line contains the sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=100), where *h**i* is the height of the *i*-th... | Print such integer *j* that the sum of the heights of planks *j*, *j*<=+<=1, ..., *j*<=+<=*k*<=-<=1 is the minimum possible. If there are multiple such *j*'s, print any of them. | [
"7 3\n1 2 6 1 1 7 1\n"
] | [
"3\n"
] | In the sample, your task is to find three consecutive planks with the minimum sum of heights. In the given case three planks with indexes 3, 4 and 5 have the required attribute, their total height is 8. | 1,000 | [
{
"input": "7 3\n1 2 6 1 1 7 1",
"output": "3"
},
{
"input": "1 1\n100",
"output": "1"
},
{
"input": "2 1\n10 20",
"output": "1"
},
{
"input": "10 5\n1 2 3 1 2 2 3 1 4 5",
"output": "1"
},
{
"input": "10 2\n3 1 4 1 4 6 2 1 4 6",
"output": "7"
},
{
"inp... | 1,666,971,130 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | n , k = map(int , input().split())
h = list(map(int , input().split()))
arr = []
for i in range(n-2):
arr.append(sum(h[i:i+k]))
for i in range(n-2):
if arr[i] == min(arr):
print(i+1)
| Title: Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a fence in front of Polycarpus's home. The fence consists of *n* planks of the same width which go one after another from left to right. The height of the *i*-th plank is *h**i* meters, distinct planks can have distinct ... | ```python
n , k = map(int , input().split())
h = list(map(int , input().split()))
arr = []
for i in range(n-2):
arr.append(sum(h[i:i+k]))
for i in range(n-2):
if arr[i] == min(arr):
print(i+1)
``` | 0 | |
158 | A | Next Round | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | "Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of *n* participants took part in the contest (*n*<=≥<=*k*), and you already know their scores. Calculate... | The first line of the input contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50) separated by a single space.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100), where *a**i* is the score earned by the participant who got the *i*-th place. The given sequence... | Output the number of participants who advance to the next round. | [
"8 5\n10 9 8 7 7 7 5 5\n",
"4 2\n0 0 0 0\n"
] | [
"6\n",
"0\n"
] | In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.
In the second example nobody got a positive score. | 500 | [
{
"input": "8 5\n10 9 8 7 7 7 5 5",
"output": "6"
},
{
"input": "4 2\n0 0 0 0",
"output": "0"
},
{
"input": "5 1\n1 1 1 1 1",
"output": "5"
},
{
"input": "5 5\n1 1 1 1 1",
"output": "5"
},
{
"input": "1 1\n10",
"output": "1"
},
{
"input": "17 14\n16 15... | 1,696,882,184 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 92 | 0 | n, k = map(int, input().split())
contestants_score = list(map(int, input().split()))
kth_score = contestants_score[k - 1]
passes = 0
for i in contestants_score:
if i >= kth_score and i > 0:
passes += 1
else:
break
print(passes)
| Title: Next Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of *n* p... | ```python
n, k = map(int, input().split())
contestants_score = list(map(int, input().split()))
kth_score = contestants_score[k - 1]
passes = 0
for i in contestants_score:
if i >= kth_score and i > 0:
passes += 1
else:
break
print(passes)
``` | 3 | |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make ... | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,700,070,407 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | print((int(input()))//5) | Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2... | ```python
print((int(input()))//5)
``` | 0 | |
420 | D | Cup Trick | PROGRAMMING | 2,200 | [
"data structures"
] | null | null | The employees of the F company have lots of ways to entertain themselves. Today they invited a famous magician who shows a trick with plastic cups and a marble.
The point is to trick the spectator's attention. Initially, the spectator stands in front of a line of *n* plastic cups. Then the magician places a small marb... | The first line contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=106). Each of the next *m* lines contains a couple of integers. The *i*-th line contains integers *x**i*, *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*) — the description of the *i*-th operation of the magician. Note that the operations are given in the order in... | If the described permutation doesn't exist (the programmer remembered wrong operations), print -1. Otherwise, print *n* distinct integers, each from 1 to *n*: the *i*-th number should represent the mark on the cup that initially is in the row in position *i*.
If there are multiple correct answers, you should print the... | [
"2 1\n2 1\n",
"3 2\n1 2\n1 1\n",
"3 3\n1 3\n2 3\n1 3\n"
] | [
"2 1 \n",
"2 1 3 \n",
"-1\n"
] | none | 1,500 | [
{
"input": "2 1\n2 1",
"output": "2 1 "
},
{
"input": "3 2\n1 2\n1 1",
"output": "2 1 3 "
},
{
"input": "3 3\n1 3\n2 3\n1 3",
"output": "-1"
},
{
"input": "3 2\n1 1\n3 2",
"output": "1 3 2 "
},
{
"input": "5 2\n3 3\n3 1",
"output": "1 2 3 4 5 "
},
{
"i... | 1,635,323,173 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 4,505,600 | ttt = int(input())
for t in range(ttt):
n = int(input())
a = [int(x) for x in input().split()]
start = 0
if n % 2 == 1:
if (a[0] + a[1] != 0):
print(-a[2], -a[2], a[0] + a[1], end = " ")
elif (a[1] + a[2] != 0):
print(a[2] + a[1], -a[0], -a[0], end = " ")
else:
print(-a[1], a[0] + a[2], -a... | Title: Cup Trick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The employees of the F company have lots of ways to entertain themselves. Today they invited a famous magician who shows a trick with plastic cups and a marble.
The point is to trick the spectator's attention. Initially, the... | ```python
ttt = int(input())
for t in range(ttt):
n = int(input())
a = [int(x) for x in input().split()]
start = 0
if n % 2 == 1:
if (a[0] + a[1] != 0):
print(-a[2], -a[2], a[0] + a[1], end = " ")
elif (a[1] + a[2] != 0):
print(a[2] + a[1], -a[0], -a[0], end = " ")
else:
print(-a[1], a[0] ... | -1 | |
508 | A | Pasha and Pixels | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row with *m* pixels in each row. Initially, all the pixels are colored white. In one move, Pasha can choos... | The first line of the input contains three integers *n*,<=*m*,<=*k* (1<=≤<=*n*,<=*m*<=≤<=1000, 1<=≤<=*k*<=≤<=105) — the number of rows, the number of columns and the number of moves that Pasha is going to perform.
The next *k* lines contain Pasha's moves in the order he makes them. Each line contains two integers *i*... | If Pasha loses, print the number of the move when the 2<=×<=2 square consisting of black pixels is formed.
If Pasha doesn't lose, that is, no 2<=×<=2 square consisting of black pixels is formed during the given *k* moves, print 0. | [
"2 2 4\n1 1\n1 2\n2 1\n2 2\n",
"2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1\n",
"5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2\n"
] | [
"4\n",
"5\n",
"0\n"
] | none | 500 | [
{
"input": "2 2 4\n1 1\n1 2\n2 1\n2 2",
"output": "4"
},
{
"input": "2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1",
"output": "5"
},
{
"input": "5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2",
"output": "0"
},
{
"input": "3 3 11\n2 1\n3 1\n1 1\n1 3\n1 2\n2 3\n3 3\n3 2\n2 2\n1 3\n3 3",
... | 1,697,707,827 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | """
Created on Thu Oct 19 17:37:20 2023
@author: bellelee
"""
n,m,k=map(int,input().split())
matrix=[(m+2)*[0] for i in range(n+2)]
def check(i,j):
if matrix[i][j+1] and matrix[i+1][j] and matrix[i+1][j+1]:
return True
if matrix[i-1][j] and matrix[i-1][j+1] and matrix[i][j+1]:
retu... | Title: Pasha and Pixels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row ... | ```python
"""
Created on Thu Oct 19 17:37:20 2023
@author: bellelee
"""
n,m,k=map(int,input().split())
matrix=[(m+2)*[0] for i in range(n+2)]
def check(i,j):
if matrix[i][j+1] and matrix[i+1][j] and matrix[i+1][j+1]:
return True
if matrix[i-1][j] and matrix[i-1][j+1] and matrix[i][j+1]:
... | 0 | |
855 | B | Marvolo Gaunt's Ring | PROGRAMMING | 1,500 | [
"brute force",
"data structures",
"dp"
] | null | null | Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed it, he is still affected by its curse. Professor Snape is helping Dumbledore remove the curse. For this, he... | First line of input contains 4 integers *n*,<=*p*,<=*q*,<=*r* (<=-<=109<=≤<=*p*,<=*q*,<=*r*<=≤<=109,<=1<=≤<=*n*<=≤<=105).
Next line of input contains *n* space separated integers *a*1,<=*a*2,<=... *a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | Output a single integer the maximum value of *p*·*a**i*<=+<=*q*·*a**j*<=+<=*r*·*a**k* that can be obtained provided 1<=≤<=*i*<=≤<=*j*<=≤<=*k*<=≤<=*n*. | [
"5 1 2 3\n1 2 3 4 5\n",
"5 1 2 -3\n-1 -2 -3 -4 -5\n"
] | [
"30\n",
"12\n"
] | In the first sample case, we can take *i* = *j* = *k* = 5, thus making the answer as 1·5 + 2·5 + 3·5 = 30.
In second sample case, selecting *i* = *j* = 1 and *k* = 5 gives the answer 12. | 1,000 | [
{
"input": "5 1 2 3\n1 2 3 4 5",
"output": "30"
},
{
"input": "5 1 2 -3\n-1 -2 -3 -4 -5",
"output": "12"
},
{
"input": "5 886327859 82309257 -68295239\n-731225382 354766539 -48222231 -474691998 360965777",
"output": "376059240645059046"
},
{
"input": "4 -96405765 -495906217 6... | 1,666,817,405 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 82 | 139 | 22,220,800 | n, p, q, r = [int(npqr) for npqr in input().split()]
a = [int(aa) for aa in input().split()]
inf = float('-inf')
matrix = [[inf, inf, inf] for i in range(n+1)]
for i in range(1, n+1):
matrix[i][0] = max(matrix[i-1][0], a[i-1]*p)
matrix[i][1] = max(matrix[i-1][1], a[i-1]*q + matrix[i][0])
... | Title: Marvolo Gaunt's Ring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed i... | ```python
n, p, q, r = [int(npqr) for npqr in input().split()]
a = [int(aa) for aa in input().split()]
inf = float('-inf')
matrix = [[inf, inf, inf] for i in range(n+1)]
for i in range(1, n+1):
matrix[i][0] = max(matrix[i-1][0], a[i-1]*p)
matrix[i][1] = max(matrix[i-1][1], a[i-1]*q + matrix[... | 3 | |
616 | B | Dinner with Emma | PROGRAMMING | 1,000 | [
"games",
"greedy"
] | null | null | Jack decides to invite Emma out for a dinner. Jack is a modest student, he doesn't want to go to an expensive restaurant. Emma is a girl with high taste, she prefers elite places.
Munhattan consists of *n* streets and *m* avenues. There is exactly one restaurant on the intersection of each street and avenue. The stree... | The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of streets and avenues in Munhattan.
Each of the next *n* lines contains *m* integers *c**ij* (1<=≤<=*c**ij*<=≤<=109) — the cost of the dinner in the restaurant on the intersection of the *i*-th street and the *j*-th avenue. | Print the only integer *a* — the cost of the dinner for Jack and Emma. | [
"3 4\n4 1 3 5\n2 2 2 2\n5 4 5 1\n",
"3 3\n1 2 3\n2 3 1\n3 1 2\n"
] | [
"2\n",
"1\n"
] | In the first example if Emma chooses the first or the third streets Jack can choose an avenue with the cost of the dinner 1. So she chooses the second street and Jack chooses any avenue. The cost of the dinner is 2.
In the second example regardless of Emma's choice Jack can choose a restaurant with the cost of the din... | 0 | [
{
"input": "3 4\n4 1 3 5\n2 2 2 2\n5 4 5 1",
"output": "2"
},
{
"input": "3 3\n1 2 3\n2 3 1\n3 1 2",
"output": "1"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "1 10\n74 35 82 39 1 84 29 41 70 12",
"output": "1"
},
{
"input": "10 1\n44\n23\n65\n17\n48\n29\n... | 1,605,186,254 | 2,147,483,647 | PyPy 3 | OK | TESTS | 16 | 140 | 1,945,600 | n, m = map(int, input().split())
C = [list(map(int, input().split())) for _ in range(n)]
ans = -1
for row in C:
ans = max(ans, min(row))
print(ans)
| Title: Dinner with Emma
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jack decides to invite Emma out for a dinner. Jack is a modest student, he doesn't want to go to an expensive restaurant. Emma is a girl with high taste, she prefers elite places.
Munhattan consists of *n* streets and... | ```python
n, m = map(int, input().split())
C = [list(map(int, input().split())) for _ in range(n)]
ans = -1
for row in C:
ans = max(ans, min(row))
print(ans)
``` | 3 | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,685,423,560 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 46 | 0 | a,b=input().split(' ')
a=int(a)
b=int(b)
list1=list(input().split(' '))
list1=[int(x) for x in list1]
count=0
for i in list1:
if((5-i)>=b):
count=count+1
print(count//3)
| Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
a,b=input().split(' ')
a=int(a)
b=int(b)
list1=list(input().split(' '))
list1=[int(x) for x in list1]
count=0
for i in list1:
if((5-i)>=b):
count=count+1
print(count//3)
``` | 3 | |
137 | A | Postcards and photos | PROGRAMMING | 900 | [
"implementation"
] | null | null | Polycarpus has postcards and photos hung in a row on the wall. He decided to put them away to the closet and hang on the wall a famous painter's picture. Polycarpus does it like that: he goes from the left to the right and removes the objects consecutively. As Polycarpus doesn't want any mix-ups to happen, he will not ... | The only line of the input data contains a non-empty string consisting of letters "С" and "P" whose length does not exceed 100 characters. If the *i*-th character in the string is the letter "С", that means that the *i*-th object (the numbering goes from the left to the right) on Polycarpus' wall is a postcard. And if ... | Print the only number — the minimum number of times Polycarpus has to visit the closet. | [
"CPCPCPC\n",
"CCCCCCPPPPPP\n",
"CCCCCCPPCPPPPPPPPPP\n",
"CCCCCCCCCC\n"
] | [
"7\n",
"4\n",
"6\n",
"2\n"
] | In the first sample Polycarpus needs to take one item to the closet 7 times.
In the second sample Polycarpus can first take 3 postcards to the closet; then 3 more. He can take the 6 photos that are left in the similar way, going to the closet twice.
In the third sample Polycarpus can visit the closet twice, both time... | 500 | [
{
"input": "CPCPCPC",
"output": "7"
},
{
"input": "CCCCCCPPPPPP",
"output": "4"
},
{
"input": "CCCCCCPPCPPPPPPPPPP",
"output": "6"
},
{
"input": "CCCCCCCCCC",
"output": "2"
},
{
"input": "CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC... | 1,614,946,832 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 280 | 2,252,800 | import sys
from math import sqrt, log, log2, ceil, log10, gcd, floor, pow, sin, cos, tan, pi, inf, factorial
from copy import copy, deepcopy
from sys import exit, stdin, stdout
from collections import Counter, defaultdict, deque
from itertools import permutations
import heapq
from bisect import bisect_left
fro... | Title: Postcards and photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has postcards and photos hung in a row on the wall. He decided to put them away to the closet and hang on the wall a famous painter's picture. Polycarpus does it like that: he goes from the left to the r... | ```python
import sys
from math import sqrt, log, log2, ceil, log10, gcd, floor, pow, sin, cos, tan, pi, inf, factorial
from copy import copy, deepcopy
from sys import exit, stdin, stdout
from collections import Counter, defaultdict, deque
from itertools import permutations
import heapq
from bisect import bisect_... | 3 | |
203 | A | Two Problems | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | A boy Valera registered on site Codeforces as Valera, and wrote his first Codeforces Round #300. He boasted to a friend Arkady about winning as much as *x* points for his first contest. But Arkady did not believe his friend's words and decided to check whether Valera could have shown such a result.
He knows that the c... | The single line of the input contains six integers *x*,<=*t*,<=*a*,<=*b*,<=*d**a*,<=*d**b* (0<=≤<=*x*<=≤<=600; 1<=≤<=*t*,<=*a*,<=*b*,<=*d**a*,<=*d**b*<=≤<=300) — Valera's result, the contest's duration, the initial cost of the first problem, the initial cost of the second problem, the number of points that the first an... | If Valera could have earned exactly *x* points at a contest, print "YES", otherwise print "NO" (without the quotes). | [
"30 5 20 20 3 5\n",
"10 4 100 5 5 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Valera could have acted like this: he could have submitted the first problem at minute 0 and the second problem — at minute 2. Then the first problem brings him 20 points and the second problem brings him 10 points, that in total gives the required 30 points. | 500 | [
{
"input": "30 5 20 20 3 5",
"output": "YES"
},
{
"input": "10 4 100 5 5 1",
"output": "NO"
},
{
"input": "0 7 30 50 3 4",
"output": "YES"
},
{
"input": "50 10 30 20 1 2",
"output": "YES"
},
{
"input": "40 1 40 5 11 2",
"output": "YES"
},
{
"input": "3... | 1,382,612,515 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 307,200 | a, b, c, d, e, f = map(int, input().split())
if a == 0:
print("YES")
exit(0)
while b:
if a == c or a == d or a == c + d:
print("YES")
exit(0)
c -= e
d -= f
b -= 1
print("NO") | Title: Two Problems
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A boy Valera registered on site Codeforces as Valera, and wrote his first Codeforces Round #300. He boasted to a friend Arkady about winning as much as *x* points for his first contest. But Arkady did not believe his frien... | ```python
a, b, c, d, e, f = map(int, input().split())
if a == 0:
print("YES")
exit(0)
while b:
if a == c or a == d or a == c + d:
print("YES")
exit(0)
c -= e
d -= f
b -= 1
print("NO")
``` | 0 | |
66 | B | Petya and Countryside | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | B. Petya and Countryside | 2 | 256 | Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *n* equal square sections. The garden is very unusual as each of the square sections possesses its own f... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* positive integers which are the height of the sections. All the numbers are no less than 1 and not more than 1000. | Print a single number, the maximal number of watered sections if we create artificial rain above exactly one section. | [
"1\n2\n",
"5\n1 2 1 2 1\n",
"8\n1 2 1 1 1 3 3 4\n"
] | [
"1\n",
"3\n",
"6\n"
] | none | 1,000 | [
{
"input": "1\n2",
"output": "1"
},
{
"input": "5\n1 2 1 2 1",
"output": "3"
},
{
"input": "8\n1 2 1 1 1 3 3 4",
"output": "6"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "10"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "10"
},
{
"input... | 1,658,916,117 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n=int(input())
l=list(map(int,input().split()))[:n]
l2=[0]*(n+1);l3=[0]*(n+1)
c,c2=0,0
for i in range(1,len(l)):
if l[i]>=l[i-1]:c+=1;l2[i]+=c
if l[-(i-1)]>=l[-i]:c2+=1;l3[-i-1]+=c2
res=0
for i in range(n):
res=max(l2[i]+l3[i],res)
print(res+1) | Title: Petya and Countryside
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *... | ```python
n=int(input())
l=list(map(int,input().split()))[:n]
l2=[0]*(n+1);l3=[0]*(n+1)
c,c2=0,0
for i in range(1,len(l)):
if l[i]>=l[i-1]:c+=1;l2[i]+=c
if l[-(i-1)]>=l[-i]:c2+=1;l3[-i-1]+=c2
res=0
for i in range(n):
res=max(l2[i]+l3[i],res)
print(res+1)
``` | 0 |
411 | A | Password Check | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | You have probably registered on Internet sites many times. And each time you should enter your invented password. Usually the registration form automatically checks the password's crypt resistance. If the user's password isn't complex enough, a message is displayed. Today your task is to implement such an automatic che... | The first line contains a non-empty sequence of characters (at most 100 characters). Each character is either a large English letter, or a small English letter, or a digit, or one of characters: "!", "?", ".", ",", "_". | If the password is complex enough, print message "Correct" (without the quotes), otherwise print message "Too weak" (without the quotes). | [
"abacaba\n",
"X12345\n",
"CONTEST_is_STARTED!!11\n"
] | [
"Too weak\n",
"Too weak\n",
"Correct\n"
] | none | 0 | [
{
"input": "abacaba",
"output": "Too weak"
},
{
"input": "X12345",
"output": "Too weak"
},
{
"input": "CONTEST_is_STARTED!!11",
"output": "Correct"
},
{
"input": "1zA__",
"output": "Correct"
},
{
"input": "1zA_",
"output": "Too weak"
},
{
"input": "zA_... | 1,616,785,744 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 62 | 0 | s = input()
ln = cap = low = digit = False
for char in s:
if len(s) > 4:
ln = True
if char.isupper():
cap = True
if char.islower():
low = True
if char.isdigit():
digit = True
if ln == cap == low == digit != False:
print("Correct")
else:
print... | Title: Password Check
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have probably registered on Internet sites many times. And each time you should enter your invented password. Usually the registration form automatically checks the password's crypt resistance. If the user's password... | ```python
s = input()
ln = cap = low = digit = False
for char in s:
if len(s) > 4:
ln = True
if char.isupper():
cap = True
if char.islower():
low = True
if char.isdigit():
digit = True
if ln == cap == low == digit != False:
print("Correct")
else:
... | 3 | |
435 | B | Pasha Maximizes | PROGRAMMING | 1,400 | [
"greedy"
] | null | null | Pasha has a positive integer *a* without leading zeroes. Today he decided that the number is too small and he should make it larger. Unfortunately, the only operation Pasha can do is to swap two adjacent decimal digits of the integer.
Help Pasha count the maximum number he can get if he has the time to make at most *k... | The single line contains two integers *a* and *k* (1<=≤<=*a*<=≤<=1018; 0<=≤<=*k*<=≤<=100). | Print the maximum number that Pasha can get if he makes at most *k* swaps. | [
"1990 1\n",
"300 0\n",
"1034 2\n",
"9090000078001234 6\n"
] | [
"9190\n",
"300\n",
"3104\n",
"9907000008001234\n"
] | none | 1,000 | [
{
"input": "1990 1",
"output": "9190"
},
{
"input": "300 0",
"output": "300"
},
{
"input": "1034 2",
"output": "3104"
},
{
"input": "9090000078001234 6",
"output": "9907000008001234"
},
{
"input": "1234 3",
"output": "4123"
},
{
"input": "5 100",
"... | 1,629,900,639 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 7 | 62 | 6,963,200 | if __name__ == '__main__':
a, k = input().split()
a = list(map(int, list(a)))
k = int(k)
i = 0
while k > 0 and i < len(a):
limit = len(a) if (i + k) > len(a) else i + k + 1
max_ = a[i]
max_i = i
# Procura o maior elemento de um intervalo do array, considerando
... | Title: Pasha Maximizes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a positive integer *a* without leading zeroes. Today he decided that the number is too small and he should make it larger. Unfortunately, the only operation Pasha can do is to swap two adjacent decimal digits ... | ```python
if __name__ == '__main__':
a, k = input().split()
a = list(map(int, list(a)))
k = int(k)
i = 0
while k > 0 and i < len(a):
limit = len(a) if (i + k) > len(a) else i + k + 1
max_ = a[i]
max_i = i
# Procura o maior elemento de um intervalo do array, consid... | -1 | |
699 | A | Launch of Collider | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There will be a launch of a new, powerful and unusual collider very soon, which located along a straight line. *n* particles will be launched inside it. All of them are located in a straight line and there can not be two or more particles located in the same point. The coordinates of the particles coincide with the dis... | The first line contains the positive integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of particles.
The second line contains *n* symbols "L" and "R". If the *i*-th symbol equals "L", then the *i*-th particle will move to the left, otherwise the *i*-th symbol equals "R" and the *i*-th particle will move to the right.... | In the first line print the only integer — the first moment (in microseconds) when two particles are at the same point and there will be an explosion.
Print the only integer -1, if the collision of particles doesn't happen. | [
"4\nRLRL\n2 4 6 10\n",
"3\nLLR\n40 50 60\n"
] | [
"1\n",
"-1\n"
] | In the first sample case the first explosion will happen in 1 microsecond because the particles number 1 and 2 will simultaneously be at the same point with the coordinate 3.
In the second sample case there will be no explosion because there are no particles which will simultaneously be at the same point. | 500 | [
{
"input": "4\nRLRL\n2 4 6 10",
"output": "1"
},
{
"input": "3\nLLR\n40 50 60",
"output": "-1"
},
{
"input": "4\nRLLR\n46 230 264 470",
"output": "92"
},
{
"input": "6\nLLRLLL\n446 492 650 844 930 970",
"output": "97"
},
{
"input": "8\nRRLLLLLL\n338 478 512 574 59... | 1,468,936,462 | 2,962 | Python 3 | CHALLENGED | CHALLENGES | 7 | 358 | 16,076,800 | #import sys, math
#import fileinput
#n,q = map(int, input().split())
#min=1000000000
#max=0
#score =[int(x) for x in input().split()]
#for x in score:
# if x>max:
# max=x
# if x<min:
# min=x
#i=0
#while i<q:
# x=input()
# if int(x)<=max and int(x)>=min:
# print ("Yes")
# else:
# print ("No")
# i+=1
#import sys,math... | Title: Launch of Collider
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There will be a launch of a new, powerful and unusual collider very soon, which located along a straight line. *n* particles will be launched inside it. All of them are located in a straight line and there can not be... | ```python
#import sys, math
#import fileinput
#n,q = map(int, input().split())
#min=1000000000
#max=0
#score =[int(x) for x in input().split()]
#for x in score:
# if x>max:
# max=x
# if x<min:
# min=x
#i=0
#while i<q:
# x=input()
# if int(x)<=max and int(x)>=min:
# print ("Yes")
# else:
# print ("No")
# i+=1
#impor... | -1 | |
622 | A | Infinite Sequence | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains ... | The only line contains integer *n* (1<=≤<=*n*<=≤<=1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | Print the element in the *n*-th position of the sequence (the elements are numerated from one). | [
"3\n",
"5\n",
"10\n",
"55\n",
"56\n"
] | [
"2\n",
"2\n",
"4\n",
"10\n",
"1\n"
] | none | 0 | [
{
"input": "3",
"output": "2"
},
{
"input": "5",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "55",
"output": "10"
},
{
"input": "56",
"output": "1"
},
{
"input": "1000000000000",
"output": "88209"
},
{
"input": "8471941278... | 1,678,873,742 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 405 | 1,433,600 | n = int(input())
number = 1
while n > number:
n -= number
number += 1
print(n) | Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2,... | ```python
n = int(input())
number = 1
while n > number:
n -= number
number += 1
print(n)
``` | 3 | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,604,074,989 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 278 | 1,228,800 | from fractions import Fraction
a = int(input())
b = int(input())
if Fraction(a, b) == 0:
print("0/1")
elif Fraction(a, b) == 1:
print("1/1")
else:
print(Fraction(a, b))
| Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
from fractions import Fraction
a = int(input())
b = int(input())
if Fraction(a, b) == 0:
print("0/1")
elif Fraction(a, b) == 1:
print("1/1")
else:
print(Fraction(a, b))
``` | -1 |
697 | A | Pineapple Incident | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times *t*, *t*<=+<=*s*, *t*<=+<=*s*<=+<=1, *t*<=+<=2*s*, *t*<=+<=2*s*<=+<=1, etc.
Barney woke up in the morn... | The first and only line of input contains three integers *t*, *s* and *x* (0<=≤<=*t*,<=*x*<=≤<=109, 2<=≤<=*s*<=≤<=109) — the time the pineapple barks for the first time, the pineapple barking interval, and the time Barney wants to eat the pineapple respectively. | Print a single "YES" (without quotes) if the pineapple will bark at time *x* or a single "NO" (without quotes) otherwise in the only line of output. | [
"3 10 4\n",
"3 10 3\n",
"3 8 51\n",
"3 8 52\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | In the first and the second sample cases pineapple will bark at moments 3, 13, 14, ..., so it won't bark at the moment 4 and will bark at the moment 3.
In the third and fourth sample cases pineapple will bark at moments 3, 11, 12, 19, 20, 27, 28, 35, 36, 43, 44, 51, 52, 59, ..., so it will bark at both moments 51 and ... | 500 | [
{
"input": "3 10 4",
"output": "NO"
},
{
"input": "3 10 3",
"output": "YES"
},
{
"input": "3 8 51",
"output": "YES"
},
{
"input": "3 8 52",
"output": "YES"
},
{
"input": "456947336 740144 45",
"output": "NO"
},
{
"input": "33 232603 599417964",
"ou... | 1,585,857,636 | 2,147,483,647 | PyPy 3 | OK | TESTS | 95 | 140 | 0 | t, s, x = map(int, input().split())
print('YES' if (x >= t + s and x % s in [t % s, (t + 1) % s]) or (x == t) else 'NO')
| Title: Pineapple Incident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times... | ```python
t, s, x = map(int, input().split())
print('YES' if (x >= t + s and x % s in [t % s, (t + 1) % s]) or (x == t) else 'NO')
``` | 3 | |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,680,665,225 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 1,945,600 | def can_reach_cell(n, t, a):
current_cell = 1
while current_cell < t:
current_cell += a[current_cell - 1]
return "YES" if current_cell == t else "NO"
# Read input
n, t = map(int, input().split())
a = list(map(int, input().split()))
# Call the function and print the result
print(can_reach_cell(n, t... | Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
def can_reach_cell(n, t, a):
current_cell = 1
while current_cell < t:
current_cell += a[current_cell - 1]
return "YES" if current_cell == t else "NO"
# Read input
n, t = map(int, input().split())
a = list(map(int, input().split()))
# Call the function and print the result
print(can_reach... | 3 | |
770 | A | New Password | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
- the length of the password must be equal to *n*, - the password should cons... | The first line contains two positive integers *n* and *k* (2<=≤<=*n*<=≤<=100, 2<=≤<=*k*<=≤<=*min*(*n*,<=26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists. | Print any password which satisfies all conditions given by Innokentiy. | [
"4 3\n",
"6 6\n",
"5 2\n"
] | [
"java\n",
"python\n",
"phphp\n"
] | In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letter... | 500 | [
{
"input": "4 3",
"output": "abca"
},
{
"input": "6 6",
"output": "abcdef"
},
{
"input": "5 2",
"output": "ababa"
},
{
"input": "3 2",
"output": "aba"
},
{
"input": "10 2",
"output": "ababababab"
},
{
"input": "26 13",
"output": "abcdefghijklmabcde... | 1,663,685,985 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 62 | 409,600 | import string
alpha = string.ascii_lowercase
n, k = [int(i) for i in input().split(" ")]
new_alpha = alpha[:k]
new_password = ""
for i in range(n):
new_password += new_alpha[i%k]
print(new_password) | Title: New Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the foll... | ```python
import string
alpha = string.ascii_lowercase
n, k = [int(i) for i in input().split(" ")]
new_alpha = alpha[:k]
new_password = ""
for i in range(n):
new_password += new_alpha[i%k]
print(new_password)
``` | 3 | |
192 | B | Walking in the Rain | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In Berland the opposition is going to arrange mass walking on the boulevard. The boulevard consists of *n* tiles that are lain in a row and are numbered from 1 to *n* from right to left. The opposition should start walking on the tile number 1 and the finish on the tile number *n*. During the walk it is allowed to move... | The first line contains integer *n* (1<=≤<=*n*<=≤<=103) — the boulevard's length in tiles.
The second line contains *n* space-separated integers *a**i* — the number of days after which the *i*-th tile gets destroyed (1<=≤<=*a**i*<=≤<=103). | Print a single number — the sought number of days. | [
"4\n10 3 5 10\n",
"5\n10 2 8 3 5\n"
] | [
"5\n",
"5\n"
] | In the first sample the second tile gets destroyed after day three, and the only path left is 1 → 3 → 4. After day five there is a two-tile gap between the first and the last tile, you can't jump over it.
In the second sample path 1 → 3 → 5 is available up to day five, inclusive. On day six the last tile is destroyed ... | 1,000 | [
{
"input": "4\n10 3 5 10",
"output": "5"
},
{
"input": "5\n10 2 8 3 5",
"output": "5"
},
{
"input": "10\n10 3 1 6 7 1 3 3 8 1",
"output": "1"
},
{
"input": "10\n26 72 10 52 2 5 61 2 39 64",
"output": "5"
},
{
"input": "100\n8 2 1 2 8 3 5 8 5 1 9 3 4 1 5 6 4 2 9 10... | 1,644,037,860 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 85 | 186 | 512,000 | import time,sys,io,math
inp=sys.stdin.readline
pr=sys.stdout.write
def solve():
n=int(inp())
a=[int(i) for i in inp().split()]
b=[(a[i],i) for i in range(n)]
b.sort()
check=[1 for _ in range(n)]
for el in b:
if el[1]==0 or el[1]==n-1:
pr(f"{el[0]}"+"\n")
... | Title: Walking in the Rain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland the opposition is going to arrange mass walking on the boulevard. The boulevard consists of *n* tiles that are lain in a row and are numbered from 1 to *n* from right to left. The opposition should start ... | ```python
import time,sys,io,math
inp=sys.stdin.readline
pr=sys.stdout.write
def solve():
n=int(inp())
a=[int(i) for i in inp().split()]
b=[(a[i],i) for i in range(n)]
b.sort()
check=[1 for _ in range(n)]
for el in b:
if el[1]==0 or el[1]==n-1:
pr(f"{el[0]}"+"\n"... | 3 | |
975 | C | Valhalla Siege | PROGRAMMING | 1,400 | [
"binary search"
] | null | null | Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has $n$ warriors, he places them on a straight line in front of the main gate, in a way that the $i$-th warrior stands right after $(i-1)$-th warrior. T... | The first line contains two integers $n$ and $q$ ($1 \le n, q \leq 200\,000$) — the number of warriors and the number of minutes in the battle.
The second line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \leq a_i \leq 10^9$) that represent the warriors' strengths.
The third line contains $q$ integers $k_1, k_2,... | Output $q$ lines, the $i$-th of them is the number of standing warriors after the $i$-th minute. | [
"5 5\n1 2 1 2 1\n3 10 1 1 1\n",
"4 4\n1 2 3 4\n9 1 10 6\n"
] | [
"3\n5\n4\n4\n3\n",
"1\n4\n4\n1\n"
] | In the first example:
- after the 1-st minute, the 1-st and 2-nd warriors die. - after the 2-nd minute all warriors die (and all arrows left over are wasted), then they will be revived thus answer is 5 — all warriors are alive. - after the 3-rd minute, the 1-st warrior dies. - after the 4-th minute, the 2-nd warr... | 1,500 | [
{
"input": "5 5\n1 2 1 2 1\n3 10 1 1 1",
"output": "3\n5\n4\n4\n3"
},
{
"input": "4 4\n1 2 3 4\n9 1 10 6",
"output": "1\n4\n4\n1"
},
{
"input": "10 3\n1 1 1 1 1 1 1 1 1 1\n10 10 5",
"output": "10\n10\n5"
},
{
"input": "1 1\n56563128\n897699770",
"output": "1"
},
{
... | 1,581,156,449 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 342 | 13,312,000 | no_of_warrior,no_of_minutes=map(int,input().split())
li1=list(map(int,input().split()))
li2=list(map(int,input().split()))
for j in range(1,no_of_warrior):
li1[j]=(li1[j]+li1[j-1])
key=0
d=0
for key in li2:
d=d+key
if(d>=li1[no_of_warrior-1]):
d=0
print... | Title: Valhalla Siege
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivar the Boneless is a great leader. He is trying to capture Kattegat from Lagertha. The war has begun and wave after wave Ivar's warriors are falling in battle.
Ivar has $n$ warriors, he places them on a straight line ... | ```python
no_of_warrior,no_of_minutes=map(int,input().split())
li1=list(map(int,input().split()))
li2=list(map(int,input().split()))
for j in range(1,no_of_warrior):
li1[j]=(li1[j]+li1[j-1])
key=0
d=0
for key in li2:
d=d+key
if(d>=li1[no_of_warrior-1]):
d=0
... | 0 | |
166 | E | Tetrahedron | PROGRAMMING | 1,500 | [
"dp",
"math",
"matrices"
] | null | null | You are given a tetrahedron. Let's mark its vertices with letters *A*, *B*, *C* and *D* correspondingly.
An ant is standing in the vertex *D* of the tetrahedron. The ant is quite active and he wouldn't stay idle. At each moment of time he makes a step from one vertex to another one along some edge of the tetrahedron. ... | The first line contains the only integer *n* (1<=≤<=*n*<=≤<=107) — the required length of the cyclic path. | Print the only integer — the required number of ways modulo 1000000007 (109<=+<=7). | [
"2\n",
"4\n"
] | [
"3\n",
"21\n"
] | The required paths in the first sample are:
- *D* - *A* - *D* - *D* - *B* - *D* - *D* - *C* - *D* | 1,000 | [
{
"input": "2",
"output": "3"
},
{
"input": "4",
"output": "21"
},
{
"input": "1",
"output": "0"
},
{
"input": "3",
"output": "6"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "183"
},
{
"input": "7",
"output": "546"
... | 1,624,998,454 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 2,000 | 8,806,400 | n = int(input())
print(((3 ** n + (-1) ** n * 3) // 4) % 1000000007) | Title: Tetrahedron
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a tetrahedron. Let's mark its vertices with letters *A*, *B*, *C* and *D* correspondingly.
An ant is standing in the vertex *D* of the tetrahedron. The ant is quite active and he wouldn't stay idle. At each m... | ```python
n = int(input())
print(((3 ** n + (-1) ** n * 3) // 4) % 1000000007)
``` | 0 | |
574 | B | Bear and Three Musketeers | PROGRAMMING | 1,500 | [
"brute force",
"dfs and similar",
"graphs",
"hashing"
] | null | null | Do you know a story about the three musketeers? Anyway, you will learn about its origins now.
Richelimakieu is a cardinal in the city of Bearis. He is tired of dealing with crime by himself. He needs three brave warriors to help him to fight against bad guys.
There are *n* warriors. Richelimakieu wants to choose thre... | The first line contains two space-separated integers, *n* and *m* (3<=≤<=*n*<=≤<=4000, 0<=≤<=*m*<=≤<=4000) — respectively number of warriors and number of pairs of warriors knowing each other.
*i*-th of the following *m* lines contains two space-separated integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**... | If Richelimakieu can choose three musketeers, print the minimum possible sum of their recognitions. Otherwise, print "-1" (without the quotes). | [
"5 6\n1 2\n1 3\n2 3\n2 4\n3 4\n4 5\n",
"7 4\n2 1\n3 6\n5 1\n1 7\n"
] | [
"2\n",
"-1\n"
] | In the first sample Richelimakieu should choose a triple 1, 2, 3. The first musketeer doesn't know anyone except other two musketeers so his recognition is 0. The second musketeer has recognition 1 because he knows warrior number 4. The third musketeer also has recognition 1 because he knows warrior 4. Sum of recogniti... | 1,000 | [
{
"input": "5 6\n1 2\n1 3\n2 3\n2 4\n3 4\n4 5",
"output": "2"
},
{
"input": "7 4\n2 1\n3 6\n5 1\n1 7",
"output": "-1"
},
{
"input": "5 0",
"output": "-1"
},
{
"input": "7 14\n3 6\n2 3\n5 2\n5 6\n7 5\n7 4\n6 2\n3 5\n7 1\n4 1\n6 1\n7 6\n6 4\n5 4",
"output": "5"
},
{
... | 1,576,115,942 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 265 | 4,608,000 | n, m = map(int, input().split())
INF = float('inf')
graph = []
for i in range(n):
graph.append(set())
for i in range(m):
a, b = map(int, input().split())
a -= 1
b -= 1
graph[a].add(b)
graph[b].add(a)
candidates = set()
for i in range(n):
if len(graph[i]) >= 2:
candidates.add(i)
... | Title: Bear and Three Musketeers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Do you know a story about the three musketeers? Anyway, you will learn about its origins now.
Richelimakieu is a cardinal in the city of Bearis. He is tired of dealing with crime by himself. He needs three br... | ```python
n, m = map(int, input().split())
INF = float('inf')
graph = []
for i in range(n):
graph.append(set())
for i in range(m):
a, b = map(int, input().split())
a -= 1
b -= 1
graph[a].add(b)
graph[b].add(a)
candidates = set()
for i in range(n):
if len(graph[i]) >= 2:
candidat... | 3 | |
727 | D | T-shirts Distribution | PROGRAMMING | 1,800 | [
"constructive algorithms",
"flows",
"greedy"
] | null | null | The organizers of a programming contest have decided to present t-shirts to participants. There are six different t-shirts sizes in this problem: S, M, L, XL, XXL, XXXL (sizes are listed in increasing order). The t-shirts are already prepared. For each size from S to XXXL you are given the number of t-shirts of this si... | The first line of the input contains six non-negative integers — the number of t-shirts of each size. The numbers are given for the sizes S, M, L, XL, XXL, XXXL, respectively. The total number of t-shirts doesn't exceed 100<=000.
The second line contains positive integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of pa... | If it is not possible to present a t-shirt to each participant, print «NO» (without quotes).
Otherwise, print *n*<=+<=1 lines. In the first line print «YES» (without quotes). In the following *n* lines print the t-shirt sizes the orginizers should give to participants, one per line. The order of the participants shoul... | [
"0 1 0 1 1 0\n3\nXL\nS,M\nXL,XXL\n",
"1 1 2 0 1 1\n5\nS\nM\nS,M\nXXL,XXXL\nXL,XXL\n"
] | [
"YES\nXL\nM\nXXL\n",
"NO\n"
] | none | 1,500 | [
{
"input": "0 1 0 1 1 0\n3\nXL\nS,M\nXL,XXL",
"output": "YES\nXL\nM\nXXL"
},
{
"input": "1 1 2 0 1 1\n5\nS\nM\nS,M\nXXL,XXXL\nXL,XXL",
"output": "NO"
},
{
"input": "1 2 4 4 1 1\n10\nXL\nXL\nS,M\nL\nM,L\nL\nS,M\nM\nXL,XXL\nXL",
"output": "YES\nXL\nXL\nS\nL\nL\nL\nM\nM\nXL\nXL"
},
... | 1,590,629,483 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 888 | 10,240,000 | arr = [int(i) for i in input().split()]
ans = []
cont = True
n = int(input())
for i in range(n):
s = input().split(",")
a = []
for j in range(len(s)):
if (s[j] == "S"):
a.append(0)
elif (s[j] == "M"):
a.append(1)
elif (s[j] == "L"):
a.... | Title: T-shirts Distribution
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The organizers of a programming contest have decided to present t-shirts to participants. There are six different t-shirts sizes in this problem: S, M, L, XL, XXL, XXXL (sizes are listed in increasing order). The ... | ```python
arr = [int(i) for i in input().split()]
ans = []
cont = True
n = int(input())
for i in range(n):
s = input().split(",")
a = []
for j in range(len(s)):
if (s[j] == "S"):
a.append(0)
elif (s[j] == "M"):
a.append(1)
elif (s[j] == "L"):
... | 0 | |
10 | A | Power Consumption Calculation | PROGRAMMING | 900 | [
"implementation"
] | A. Power Consumption Calculation | 1 | 256 | Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard for the last time, a screensaver starts and power consumption changes to *P*2 watt per minute. Finally, after *T... | The first line contains 6 integer numbers *n*, *P*1, *P*2, *P*3, *T*1, *T*2 (1<=≤<=*n*<=≤<=100,<=0<=≤<=*P*1,<=*P*2,<=*P*3<=≤<=100,<=1<=≤<=*T*1,<=*T*2<=≤<=60). The following *n* lines contain description of Tom's work. Each *i*-th of these lines contains two space-separated integers *l**i* and *r**i* (0<=≤<=*l**i*<=<... | Output the answer to the problem. | [
"1 3 2 1 5 10\n0 10\n",
"2 8 4 2 5 10\n20 30\n50 100\n"
] | [
"30",
"570"
] | none | 0 | [
{
"input": "1 3 2 1 5 10\n0 10",
"output": "30"
},
{
"input": "2 8 4 2 5 10\n20 30\n50 100",
"output": "570"
},
{
"input": "3 15 9 95 39 19\n873 989\n1003 1137\n1172 1436",
"output": "8445"
},
{
"input": "4 73 2 53 58 16\n51 52\n209 242\n281 407\n904 945",
"output": "5287... | 1,539,152,741 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 248 | 0 | def consume(r, l, p1, p2, p3, t1, t2):
if l - r <= t1:
return p1 * (l-r)
elif t1 < l - r <= t1 + t2:
return p1 * t1 + p2 * (l-r-t1)
elif l - r > t1 + t2:
return p1 * t1 + p2 * t2 + p3 * (l-r-t1-t2)
n, p1, p2, p3, t1, t2 = map(int, input().split())
a = []
ans = 0
for i in ... | Title: Power Consumption Calculation
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard f... | ```python
def consume(r, l, p1, p2, p3, t1, t2):
if l - r <= t1:
return p1 * (l-r)
elif t1 < l - r <= t1 + t2:
return p1 * t1 + p2 * (l-r-t1)
elif l - r > t1 + t2:
return p1 * t1 + p2 * t2 + p3 * (l-r-t1-t2)
n, p1, p2, p3, t1, t2 = map(int, input().split())
a = []
ans = 0
... | 3.876 |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,694,970,625 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | s=input()
if(s[0]!=s[0].upper() and s[1:]==s[1:].upper()):
print(s[0].upper()+s[1:].lower())
if(s==s.upper()):
print(s.lower())
else:
print(s) | Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
s=input()
if(s[0]!=s[0].upper() and s[1:]==s[1:].upper()):
print(s[0].upper()+s[1:].lower())
if(s==s.upper()):
print(s.lower())
else:
print(s)
``` | 0 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the... | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,691,226,649 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 1,000 | 0 | n,m,a=map(int,input().split())
b=max(n,m)
c1=0
c2=0
if(n*m==a*a)or(n*m<a*a):
print("1")
else:
while(n>0):
n-=a
c1+=1
while(m>0):
m-=a
c2+=1
print(c1*c2)
| Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each ... | ```python
n,m,a=map(int,input().split())
b=max(n,m)
c1=0
c2=0
if(n*m==a*a)or(n*m<a*a):
print("1")
else:
while(n>0):
n-=a
c1+=1
while(m>0):
m-=a
c2+=1
print(c1*c2)
``` | 0 |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,614,268,699 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 154 | 0 |
dimensiones = input().split()
m, n = int(dimensiones[0]), int(dimensiones[1])
print((m*n)//2) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
dimensiones = input().split()
m, n = int(dimensiones[0]), int(dimensiones[1])
print((m*n)//2)
``` | 3.9615 |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,601,903,264 | 2,147,483,647 | PyPy 3 | OK | TESTS | 76 | 140 | 0 | n = int(input())
if n & 1:
print(0)
else:
n //= 2
print((n-1)//2) | Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
n = int(input())
if n & 1:
print(0)
else:
n //= 2
print((n-1)//2)
``` | 3 | |
379 | A | New Year Candles | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used ... | The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000). | Print a single integer — the number of hours Vasily can light up the room for. | [
"4 2\n",
"6 3\n"
] | [
"7\n",
"8\n"
] | Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours. | 500 | [
{
"input": "4 2",
"output": "7"
},
{
"input": "6 3",
"output": "8"
},
{
"input": "1000 1000",
"output": "1001"
},
{
"input": "123 5",
"output": "153"
},
{
"input": "1000 2",
"output": "1999"
},
{
"input": "1 2",
"output": "1"
},
{
"input": ... | 1,695,821,248 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 32 | 62 | 28,262,400 | #Coder_1_neel
a,b=map(int,input().split())
hr=a
x=a
while(x>=b):
n=x//b
hr+=n
x=n+(x%b)
print(hr) | Title: New Year Candles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is s... | ```python
#Coder_1_neel
a,b=map(int,input().split())
hr=a
x=a
while(x>=b):
n=x//b
hr+=n
x=n+(x%b)
print(hr)
``` | 3 | |
597 | A | Divisibility | PROGRAMMING | 1,600 | [
"math"
] | null | null | Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*. | The only line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=1018;<=-<=1018<=≤<=*a*<=≤<=*b*<=≤<=1018). | Print the required number. | [
"1 1 10\n",
"2 -4 4\n"
] | [
"10\n",
"5\n"
] | none | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "2 -4 4",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 0 0",
"output": "1"
},
{
"input": "1 0 1",
"output": "2"
},
{
"input": "1 10181 10182",
"output": "2"
},
{
"inpu... | 1,593,076,606 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 108 | 6,656,000 | (k,a,b)=map(int, input().split())
l=[]
if abs(a)==abs(b):
for x in range(0,b+1):
if x%k==0:
l.append(x)
print(2*len(l))
else:
for x in range(a,b+1):
if x%k==0:
l.append(x)
print(len(l))
| Title: Divisibility
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*.
Input Specification:
The onl... | ```python
(k,a,b)=map(int, input().split())
l=[]
if abs(a)==abs(b):
for x in range(0,b+1):
if x%k==0:
l.append(x)
print(2*len(l))
else:
for x in range(a,b+1):
if x%k==0:
l.append(x)
print(len(l))
``` | 0 | |
393 | A | Nineteen | PROGRAMMING | 0 | [] | null | null | Alice likes word "nineteen" very much. She has a string *s* and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) ... | The first line contains a non-empty string *s*, consisting only of lowercase English letters. The length of string *s* doesn't exceed 100. | Print a single integer — the maximum number of "nineteen"s that she can get in her string. | [
"nniinneetteeeenn\n",
"nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii\n",
"nineteenineteen\n"
] | [
"2",
"2",
"2"
] | none | 500 | [
{
"input": "nniinneetteeeenn",
"output": "2"
},
{
"input": "nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii",
"output": "2"
},
{
"input": "nineteenineteen",
"output": "2"
},
{
"input": "nssemsnnsitjtihtthij",
"output": "0"
},
{
"input": "eehihnttehtherjsihihn... | 1,581,379,063 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 108 | 307,200 | x = "nineteen"
d = {}
for k in x:
if k in d.keys():
d[k] += 1
else:
d[k] = 1
string = input()
d1 = {}
for k in string:
if k in d1.keys():
d1[k] += 1
else:
d1[k] = 1
list = []
for k in d:
if k in d1.keys():
list.append(d1[k]//d[k])
if len(list) != len(d):
... | Title: Nineteen
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice likes word "nineteen" very much. She has a string *s* and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiinetee... | ```python
x = "nineteen"
d = {}
for k in x:
if k in d.keys():
d[k] += 1
else:
d[k] = 1
string = input()
d1 = {}
for k in string:
if k in d1.keys():
d1[k] += 1
else:
d1[k] = 1
list = []
for k in d:
if k in d1.keys():
list.append(d1[k]//d[k])
if len(list) != le... | 0 | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,696,403,953 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 61 | 0 | s = input().lower()
k = s[0].upper()
print(k + s[1:]) #lol | Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
s = input().lower()
k = s[0].upper()
print(k + s[1:]) #lol
``` | 0 | |
535 | A | Tavas and Nafas | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.
His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score with Nafas via text, so he has no choice but to send this number using words.
He ate coffee mix without... | The first and only line of input contains an integer *s* (0<=≤<=*s*<=≤<=99), Tavas's score. | In the first and only line of output, print a single string consisting only from English lowercase letters and hyphens ('-'). Do not use spaces. | [
"6\n",
"99\n",
"20\n"
] | [
"six\n",
"ninety-nine\n",
"twenty\n"
] | You can find all you need to know about English numerals in [http://en.wikipedia.org/wiki/English_numerals](https://en.wikipedia.org/wiki/English_numerals) . | 500 | [
{
"input": "6",
"output": "six"
},
{
"input": "99",
"output": "ninety-nine"
},
{
"input": "20",
"output": "twenty"
},
{
"input": "10",
"output": "ten"
},
{
"input": "15",
"output": "fifteen"
},
{
"input": "27",
"output": "twenty-seven"
},
{
... | 1,533,736,000 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 124 | 0 | def Num_to_text():
'''Asks for a integral number between 0 and 99 and return it written in english'''
Num = int(input('What number do you want to convert? '))
Dez = Num//10
Uni = Num%10
Text = ''
Base = {0:'zero',1:'one',2:'two',3:'three',4:'four',5:'five',6:'six',
7:'seven',8:'eight',9:'nine'}
if Dez =... | Title: Tavas and Nafas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.
His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score wit... | ```python
def Num_to_text():
'''Asks for a integral number between 0 and 99 and return it written in english'''
Num = int(input('What number do you want to convert? '))
Dez = Num//10
Uni = Num%10
Text = ''
Base = {0:'zero',1:'one',2:'two',3:'three',4:'four',5:'five',6:'six',
7:'seven',8:'eight',9:'nine'}
... | 0 | |
131 | C | The World is a Theatre | PROGRAMMING | 1,400 | [
"combinatorics",
"math"
] | null | null | There are *n* boys and *m* girls attending a theatre club. To set a play "The Big Bang Theory", they need to choose a group containing exactly *t* actors containing no less than 4 boys and no less than one girl. How many ways are there to choose a group? Of course, the variants that only differ in the composition of th... | The only line of the input data contains three integers *n*, *m*, *t* (4<=≤<=*n*<=≤<=30,<=1<=≤<=*m*<=≤<=30,<=5<=≤<=*t*<=≤<=*n*<=+<=*m*). | Find the required number of ways.
Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specificator. | [
"5 2 5\n",
"4 3 5\n"
] | [
"10\n",
"3\n"
] | none | 1,500 | [
{
"input": "5 2 5",
"output": "10"
},
{
"input": "4 3 5",
"output": "3"
},
{
"input": "4 1 5",
"output": "1"
},
{
"input": "7 3 6",
"output": "168"
},
{
"input": "30 30 30",
"output": "118264581548187697"
},
{
"input": "10 10 8",
"output": "84990"
... | 1,691,064,522 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 2,000 | 13,209,600 | def fa(n):
summ = 1
while n!=0:
summ*=n
n-=1
return summ
def dom(n,m,t):
f=0
s=0
summ=0
for i in range(4,t):
f=fa(n)/(fa(i)*fa(n-i))
s = fa(m) / (fa(t-(i-3)) * fa(m - (t-(i-3))))
summ +=int(s * f)
return summ
x=input().split(" ")
n=... | Title: The World is a Theatre
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* boys and *m* girls attending a theatre club. To set a play "The Big Bang Theory", they need to choose a group containing exactly *t* actors containing no less than 4 boys and no less than one girl. ... | ```python
def fa(n):
summ = 1
while n!=0:
summ*=n
n-=1
return summ
def dom(n,m,t):
f=0
s=0
summ=0
for i in range(4,t):
f=fa(n)/(fa(i)*fa(n-i))
s = fa(m) / (fa(t-(i-3)) * fa(m - (t-(i-3))))
summ +=int(s * f)
return summ
x=input().spli... | 0 | |
137 | E | Last Chance | PROGRAMMING | 2,000 | [
"data structures",
"implementation",
"strings"
] | null | null | Having read half of the book called "Storm and Calm" on the IT lesson, Innocentius was absolutely determined to finish the book on the maths lessons. All was fine until the math teacher Ms. Watkins saw Innocentius reading fiction books instead of solving equations of the fifth degree. As during the last maths class Inn... | The only input line contains a non-empty string *s* consisting of no more than 2·105 uppercase and lowercase Latin letters. We shall regard letters "a", "e", "i", "o", "u" and their uppercase variants as vowels. | Print on a single line two numbers without a space: the maximum length of a good substring and the number of good substrings with this length. If no good substring exists, print "No solution" without the quotes.
Two substrings are considered different if their positions of occurrence are different. So if some string o... | [
"Abo\n",
"OEIS\n",
"auBAAbeelii\n",
"AaaBRAaaCAaaDAaaBRAaa\n",
"EA\n"
] | [
"3 1\n",
"3 1\n",
"9 3\n",
"18 4\n",
"No solution\n"
] | In the first sample there is only one longest good substring: "Abo" itself. The other good substrings are "b", "Ab", "bo", but these substrings have shorter length.
In the second sample there is only one longest good substring: "EIS". The other good substrings are: "S", "IS". | 2,500 | [
{
"input": "Abo",
"output": "3 1"
},
{
"input": "OEIS",
"output": "3 1"
},
{
"input": "auBAAbeelii",
"output": "9 3"
},
{
"input": "AaaBRAaaCAaaDAaaBRAaa",
"output": "18 4"
},
{
"input": "EA",
"output": "No solution"
},
{
"input": "BBBAABAABAABBBB",
... | 1,689,595,732 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | print("_RANDOM_GUESS_1689595732.4661798")# 1689595732.4661996 | Title: Last Chance
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Having read half of the book called "Storm and Calm" on the IT lesson, Innocentius was absolutely determined to finish the book on the maths lessons. All was fine until the math teacher Ms. Watkins saw Innocentius reading f... | ```python
print("_RANDOM_GUESS_1689595732.4661798")# 1689595732.4661996
``` | 0 | |
950 | A | Left-handers, Right-handers and Ambidexters | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and ... | The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. | Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. | [
"1 4 2\n",
"5 5 5\n",
"0 2 0\n"
] | [
"6\n",
"14\n",
"0\n"
] | In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five l... | 500 | [
{
"input": "1 4 2",
"output": "6"
},
{
"input": "5 5 5",
"output": "14"
},
{
"input": "0 2 0",
"output": "0"
},
{
"input": "30 70 34",
"output": "128"
},
{
"input": "89 32 24",
"output": "112"
},
{
"input": "89 44 77",
"output": "210"
},
{
... | 1,524,528,635 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 92 | 21,401,600 | x,r,a = [int(x) for x in input().split()]
if x > r:
r += min(a, x-r)
a -= min(a, x-r)
else:
x += min(a,r-x)
a -= min(a,r-x)
a -= (a%2)
while a > 0:
a-=2
r += 1
x += 1
print(2*min(x,r))
| Title: Left-handers, Right-handers and Ambidexters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.... | ```python
x,r,a = [int(x) for x in input().split()]
if x > r:
r += min(a, x-r)
a -= min(a, x-r)
else:
x += min(a,r-x)
a -= min(a,r-x)
a -= (a%2)
while a > 0:
a-=2
r += 1
x += 1
print(2*min(x,r))
``` | 0 | |
701 | A | Cards | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one player.
Find the way to distribute cards such that the sum of values written of the cards ... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100) — the number of cards in the deck. It is guaranteed that *n* is even.
The second line contains the sequence of *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is equal to the number written on the *i*-th card. | Print *n*<=/<=2 pairs of integers, the *i*-th pair denote the cards that should be given to the *i*-th player. Each card should be given to exactly one player. Cards are numbered in the order they appear in the input.
It is guaranteed that solution exists. If there are several correct answers, you are allowed to print... | [
"6\n1 5 7 4 4 3\n",
"4\n10 10 10 10\n"
] | [
"1 3\n6 2\n4 5\n",
"1 2\n3 4\n"
] | In the first sample, cards are distributed in such a way that each player has the sum of numbers written on his cards equal to 8.
In the second sample, all values *a*<sub class="lower-index">*i*</sub> are equal. Thus, any distribution is acceptable. | 500 | [
{
"input": "6\n1 5 7 4 4 3",
"output": "1 3\n6 2\n4 5"
},
{
"input": "4\n10 10 10 10",
"output": "1 4\n2 3"
},
{
"input": "100\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,624,288,684 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 62 | 0 | n = int(input())
l = list(map(int,input().split()))
a = []
for i in range(n):
a.append([l[i] , i+1])
a.sort()
for i in range(n//2):
print(a[i][1] , a[-i - 1][1])
| Title: Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one p... | ```python
n = int(input())
l = list(map(int,input().split()))
a = []
for i in range(n):
a.append([l[i] , i+1])
a.sort()
for i in range(n//2):
print(a[i][1] , a[-i - 1][1])
``` | 3 | |
31 | B | Sysadmin Bob | PROGRAMMING | 1,500 | [
"greedy",
"implementation",
"strings"
] | B. Sysadmin Bob | 0 | 256 | Email address in Berland is a string of the form *A*@*B*, where *A* and *B* are arbitrary strings consisting of small Latin letters.
Bob is a system administrator in «Bersoft» company. He keeps a list of email addresses of the company's staff. This list is as a large string, where all addresses are written in arbitra... | The first line contains the list of addresses without separators. The length of this string is between 1 and 200, inclusive. The string consists only from small Latin letters and characters «@». | If there is no list of the valid (according to the Berland rules) email addresses such that after removing all commas it coincides with the given string, output No solution. In the other case, output the list. The same address can be written in this list more than once. If there are several solutions, output any of the... | [
"a@aa@a\n",
"a@a@a\n",
"@aa@a\n"
] | [
"a@a,a@a\n",
"No solution\n",
"No solution\n"
] | none | 1,000 | [
{
"input": "a@aa@a",
"output": "a@a,a@a"
},
{
"input": "a@a@a",
"output": "No solution"
},
{
"input": "@aa@a",
"output": "No solution"
},
{
"input": "aba@caba@daba",
"output": "aba@c,aba@daba"
},
{
"input": "asd@qwasd@qwasd@qwasd@qwasd@qw",
"output": "asd@q,wa... | 1,643,433,555 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 31 | 0 | s = input().split('@')
if('' in s):
print('No solution')
else:
r = s[1:len(s)-1]
flag = 0
for i in range(len(r)):
if(len(r[i]) < 2):
flag = 1
break
if(flag == 1):
print('No solution')
else:
t = s[0]
for i in range(1,len(s)-1):
t += '@' + s[i][0] + ',' +s[i][1:]
t += '@' + s... | Title: Sysadmin Bob
Time Limit: 0 seconds
Memory Limit: 256 megabytes
Problem Description:
Email address in Berland is a string of the form *A*@*B*, where *A* and *B* are arbitrary strings consisting of small Latin letters.
Bob is a system administrator in «Bersoft» company. He keeps a list of email addresses of t... | ```python
s = input().split('@')
if('' in s):
print('No solution')
else:
r = s[1:len(s)-1]
flag = 0
for i in range(len(r)):
if(len(r[i]) < 2):
flag = 1
break
if(flag == 1):
print('No solution')
else:
t = s[0]
for i in range(1,len(s)-1):
t += '@' + s[i][0] + ',' +s[i][1:]
t ... | 0 |
463 | B | Caisa and Pylons | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"math"
] | null | null | Caisa solved the problem with the sugar and now he is on the way back to home.
Caisa is playing a mobile game during his path. There are (*n*<=+<=1) pylons numbered from 0 to *n* in this game. The pylon with number 0 has zero height, the pylon with number *i* (*i*<=><=0) has height *h**i*. The goal of the game is ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *h*1, *h*2,<=..., *h**n* (1<=<=≤<=<=*h**i*<=<=≤<=<=105) representing the heights of the pylons. | Print a single number representing the minimum number of dollars paid by Caisa. | [
"5\n3 4 3 2 4\n",
"3\n4 4 4\n"
] | [
"4\n",
"4\n"
] | In the first sample he can pay 4 dollars and increase the height of pylon with number 0 by 4 units. Then he can safely pass to the last pylon. | 1,000 | [
{
"input": "5\n3 4 3 2 4",
"output": "4"
},
{
"input": "3\n4 4 4",
"output": "4"
},
{
"input": "99\n1401 2019 1748 3785 3236 3177 3443 3772 2138 1049 353 908 310 2388 1322 88 2160 2783 435 2248 1471 706 2468 2319 3156 3506 2794 1999 1983 2519 2597 3735 537 344 3519 3772 3872 2961 3895 20... | 1,642,029,684 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 140 | 10,649,600 | n = int(input())
H = [0] + list(map(int, input().split()))
e = 0
i = 0
m = 0
while i < len(H) - 1:
diff = H[i] - H[i+1]
e += diff
if e >= 0:
pass
else:
m += -e
e = 0
i += 1
print(m)
| Title: Caisa and Pylons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Caisa solved the problem with the sugar and now he is on the way back to home.
Caisa is playing a mobile game during his path. There are (*n*<=+<=1) pylons numbered from 0 to *n* in this game. The pylon with number 0... | ```python
n = int(input())
H = [0] + list(map(int, input().split()))
e = 0
i = 0
m = 0
while i < len(H) - 1:
diff = H[i] - H[i+1]
e += diff
if e >= 0:
pass
else:
m += -e
e = 0
i += 1
print(m)
``` | 3 | |
710 | A | King Moves | PROGRAMMING | 800 | [
"implementation"
] | null | null | The only king stands on the standard chess board. You are given his position in format "cd", where *c* is the column from 'a' to 'h' and *d* is the row from '1' to '8'. Find the number of moves permitted for the king.
Check the king's moves here [https://en.wikipedia.org/wiki/King_(chess)](https://en.wikipedia.org/wik... | The only line contains the king's position in the format "cd", where 'c' is the column from 'a' to 'h' and 'd' is the row from '1' to '8'. | Print the only integer *x* — the number of moves permitted for the king. | [
"e4\n"
] | [
"8\n"
] | none | 0 | [
{
"input": "e4",
"output": "8"
},
{
"input": "a1",
"output": "3"
},
{
"input": "h8",
"output": "3"
},
{
"input": "a4",
"output": "5"
},
{
"input": "g7",
"output": "8"
},
{
"input": "e1",
"output": "5"
},
{
"input": "b2",
"output": "8"
... | 1,476,712,939 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 4,608,000 | a = list(input())
x, y = ord(a[0]) - ord('a') + 1, int(a[1])
if x == 1 or x == 8:
if 1 < y < 8:
res = 6
else:
res = 3
elif y == 1 or y == 8:
if 1 < x < 8:
res = 6
else:
res = 3
else:
res = 8
print(res)
| Title: King Moves
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The only king stands on the standard chess board. You are given his position in format "cd", where *c* is the column from 'a' to 'h' and *d* is the row from '1' to '8'. Find the number of moves permitted for the king.
Check... | ```python
a = list(input())
x, y = ord(a[0]) - ord('a') + 1, int(a[1])
if x == 1 or x == 8:
if 1 < y < 8:
res = 6
else:
res = 3
elif y == 1 or y == 8:
if 1 < x < 8:
res = 6
else:
res = 3
else:
res = 8
print(res)
``` | 0 | |
915 | C | Permute Digits | PROGRAMMING | 1,700 | [
"dp",
"greedy"
] | null | null | You are given two positive integer numbers *a* and *b*. Permute (change order) of the digits of *a* to construct maximal number not exceeding *b*. No number in input and/or output can start with the digit 0.
It is allowed to leave *a* as it is. | The first line contains integer *a* (1<=≤<=*a*<=≤<=1018). The second line contains integer *b* (1<=≤<=*b*<=≤<=1018). Numbers don't have leading zeroes. It is guaranteed that answer exists. | Print the maximum possible number that is a permutation of digits of *a* and is not greater than *b*. The answer can't have any leading zeroes. It is guaranteed that the answer exists.
The number in the output should have exactly the same length as number *a*. It should be a permutation of digits of *a*. | [
"123\n222\n",
"3921\n10000\n",
"4940\n5000\n"
] | [
"213\n",
"9321\n",
"4940\n"
] | none | 0 | [
{
"input": "123\n222",
"output": "213"
},
{
"input": "3921\n10000",
"output": "9321"
},
{
"input": "4940\n5000",
"output": "4940"
},
{
"input": "23923472834\n23589234723",
"output": "23498743322"
},
{
"input": "102391019\n491010301",
"output": "399211100"
},... | 1,517,898,148 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 1,000 | 26,624,000 | def solve(ans,a,m,n):
if(m==n):
u="".join(a)
ans.append(u)
return
else:
for i in range(m,n):
a[m],a[i]=a[i],a[m]
solve(ans,a,m+1,n)
a[m],a[i]=a[i],a[m]
def main():
ans=list()
a=input()
b=input()
n=len(a)
a=lis... | Title: Permute Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two positive integer numbers *a* and *b*. Permute (change order) of the digits of *a* to construct maximal number not exceeding *b*. No number in input and/or output can start with the digit 0.
It is allow... | ```python
def solve(ans,a,m,n):
if(m==n):
u="".join(a)
ans.append(u)
return
else:
for i in range(m,n):
a[m],a[i]=a[i],a[m]
solve(ans,a,m+1,n)
a[m],a[i]=a[i],a[m]
def main():
ans=list()
a=input()
b=input()
n=len(a)
... | 0 | |
784 | G | BF Calculator | PROGRAMMING | 2,000 | [
"*special"
] | null | null | In this problem you will write a simple generator of Brainfuck ([https://en.wikipedia.org/wiki/Brainfuck](https://en.wikipedia.org/wiki/Brainfuck)) calculators.
You are given an arithmetic expression consisting of integers from 0 to 255 and addition/subtraction signs between them. Output a Brainfuck program which, whe... | The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive. The calculations result is guaranteed to be an integer between 0 and 255, inclusive (res... | Output a Brainfuck program which, when executed, will print the result of evaluating this expression. The program must be at most 5000000 characters long (including the non-command characters), and its execution must be complete in at most 50000000 steps. | [
"2+3\n",
"9-7\n"
] | [
"++>\n+++>\n<[<+>-]<\n++++++++++++++++++++++++++++++++++++++++++++++++.\n",
"+++++++++>\n+++++++>\n<[<->-]<\n++++++++++++++++++++++++++++++++++++++++++++++++.\n"
] | You can download the source code of the Brainfuck interpreter by the link [http://assets.codeforces.com/rounds/784/bf.cpp](//assets.codeforces.com/rounds/784/bf.cpp). We use this code to interpret outputs. | 0 | [
{
"input": "2+3",
"output": "+++++++++++++++++++++++++++++++++++++++++++++++++++++.>"
},
{
"input": "9-7",
"output": "++++++++++++++++++++++++++++++++++++++++++++++++++.>"
},
{
"input": "1+1+1",
"output": "+++++++++++++++++++++++++++++++++++++++++++++++++++.>"
},
{
"input": "... | 1,553,533,132 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | for c in str(input()):print'+'*ord(c)+'.>' | Title: BF Calculator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you will write a simple generator of Brainfuck ([https://en.wikipedia.org/wiki/Brainfuck](https://en.wikipedia.org/wiki/Brainfuck)) calculators.
You are given an arithmetic expression consisting of intege... | ```python
for c in str(input()):print'+'*ord(c)+'.>'
``` | -1 | |
812 | C | Sagheer and Nubian Market | PROGRAMMING | 1,500 | [
"binary search",
"sortings"
] | null | null | On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains *n* different items numbered from 1 to *n*. The *i*-th item has base cost *a**i* Egyptian pounds. If Sagheer buys *k* items with indices *x*1,<=*x*2,<=...,<... | The first line contains two integers *n* and *S* (1<=≤<=*n*<=≤<=105 and 1<=≤<=*S*<=≤<=109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the base costs of the souvenirs. | On a single line, print two integers *k*, *T* — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these *k* souvenirs. | [
"3 11\n2 3 5\n",
"4 100\n1 2 5 6\n",
"1 7\n7\n"
] | [
"2 11\n",
"4 54\n",
"0 0\n"
] | In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the... | 1,500 | [
{
"input": "3 11\n2 3 5",
"output": "2 11"
},
{
"input": "4 100\n1 2 5 6",
"output": "4 54"
},
{
"input": "1 7\n7",
"output": "0 0"
},
{
"input": "1 7\n5",
"output": "1 6"
},
{
"input": "1 1\n1",
"output": "0 0"
},
{
"input": "4 33\n4 3 2 1",
"outp... | 1,610,835,613 | 2,147,483,647 | Python 3 | OK | TESTS | 57 | 1,029 | 7,372,800 | # By karutz
def check(A, S, k):
prices = []
for i, a in enumerate(A):
prices.append(a + (i+1)*k)
prices.sort()
total = sum(prices[:k])
return total <= S, total
n, S = map(int, input().split())
A = [int(a) for a in input().split()]
k = -1
p = 0
skip = n
while skip >= 1:
... | Title: Sagheer and Nubian Market
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains *n* different items numbered from 1 to *n*. T... | ```python
# By karutz
def check(A, S, k):
prices = []
for i, a in enumerate(A):
prices.append(a + (i+1)*k)
prices.sort()
total = sum(prices[:k])
return total <= S, total
n, S = map(int, input().split())
A = [int(a) for a in input().split()]
k = -1
p = 0
skip = n
while s... | 3 | |
760 | A | Petr and a calendar | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to ... | The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). | Print single integer: the number of columns the table should have. | [
"1 7\n",
"1 1\n",
"11 6\n"
] | [
"6\n",
"5\n",
"5\n"
] | The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | 500 | [
{
"input": "1 7",
"output": "6"
},
{
"input": "1 1",
"output": "5"
},
{
"input": "11 6",
"output": "5"
},
{
"input": "2 7",
"output": "5"
},
{
"input": "2 1",
"output": "4"
},
{
"input": "8 6",
"output": "6"
},
{
"input": "1 1",
"output... | 1,646,978,787 | 2,147,483,647 | Python 3 | OK | TESTS | 104 | 46 | 0 | a=[31,28,31,30,31,30,31,31,30,31,30,31]
m,d=map(int,input().split())
print(1--(a[m-1]+d-8)//7) | Title: Petr and a calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells... | ```python
a=[31,28,31,30,31,30,31,31,30,31,30,31]
m,d=map(int,input().split())
print(1--(a[m-1]+d-8)//7)
``` | 3 | |
96 | B | Lucky Numbers (easy) | PROGRAMMING | 1,300 | [
"binary search",
"bitmasks",
"brute force"
] | B. Lucky Numbers (easy) | 2 | 256 | Petya loves lucky numbers. Everybody knows that positive integers are lucky if their decimal representation doesn't contain digits other than 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Lucky number is super lucky if it's decimal representation contains equal amount of digits 4 and 7. Fo... | The only line contains a positive integer *n* (1<=≤<=*n*<=≤<=109). This number doesn't have leading zeroes. | Output the least super lucky number that is more than or equal to *n*.
Please, do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator. | [
"4500\n",
"47\n"
] | [
"4747\n",
"47\n"
] | none | 1,000 | [
{
"input": "4500",
"output": "4747"
},
{
"input": "47",
"output": "47"
},
{
"input": "1",
"output": "47"
},
{
"input": "12",
"output": "47"
},
{
"input": "4587",
"output": "4747"
},
{
"input": "100",
"output": "4477"
},
{
"input": "1007",
... | 1,665,433,177 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 92 | 0 | n = int(input())
c = True
count4 = 0
count7 = 0
while c:
n += 1
for i in str(n):
if i not in ['4','7']:
c = True
count4 = 0
count7 = 0
break
else:
if i == '4':
count4+=1
else:
... | Title: Lucky Numbers (easy)
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that positive integers are lucky if their decimal representation doesn't contain digits other than 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n = int(input())
c = True
count4 = 0
count7 = 0
while c:
n += 1
for i in str(n):
if i not in ['4','7']:
c = True
count4 = 0
count7 = 0
break
else:
if i == '4':
count4+=1
else:
... | 0 |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,661,961,728 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 61 | 1,638,400 | n, k = map(int, input().split())
s = list(map(int, input().split()))
a = [i for i in s if (i + k) <= 5]
print(len(a) // 3) | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
n, k = map(int, input().split())
s = list(map(int, input().split()))
a = [i for i in s if (i + k) <= 5]
print(len(a) // 3)
``` | 3 | |
509 | A | Maximum in Table | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the ... | The only line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=10) — the number of rows and columns of the table. | Print a single line containing a positive integer *m* — the maximum value in the table. | [
"1\n",
"5\n"
] | [
"1",
"70"
] | In the second test the rows of the table look as follows: | 0 | [
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "70"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "6"
},
{
"input": "4",
"output": "20"
},
{
"input": "6",
"output": "252"
},
{
"input": "7",
"output": "924"
... | 1,635,991,100 | 2,147,483,647 | Python 3 | OK | TESTS | 10 | 46 | 4,505,600 | n = int(input())
if n < 3: print(n)
else:
t = [[1]*n for _ in range(n)]
for i in range(1,n):
for j in range(1,n):
t[i][j] = t[i-1][j] + t[i][j-1]
print(t[n-1][n-1]) | Title: Maximum in Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the t... | ```python
n = int(input())
if n < 3: print(n)
else:
t = [[1]*n for _ in range(n)]
for i in range(1,n):
for j in range(1,n):
t[i][j] = t[i-1][j] + t[i][j-1]
print(t[n-1][n-1])
``` | 3 | |
992 | A | Nastya and an Array | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second we can add an arbitrary (possibly negative) integer to all elements of the array that are not equal to ze... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the size of the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=105<=≤<=*a**i*<=≤<=105) — the elements of the array. | Print a single integer — the minimum number of seconds needed to make all elements of the array equal to zero. | [
"5\n1 1 1 1 1\n",
"3\n2 0 -1\n",
"4\n5 -6 -5 1\n"
] | [
"1\n",
"2\n",
"4\n"
] | In the first example you can add - 1 to all non-zero elements in one second and make them equal to zero.
In the second example you can add - 2 on the first second, then the array becomes equal to [0, 0, - 3]. On the second second you can add 3 to the third (the only non-zero) element. | 500 | [
{
"input": "5\n1 1 1 1 1",
"output": "1"
},
{
"input": "3\n2 0 -1",
"output": "2"
},
{
"input": "4\n5 -6 -5 1",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n21794 -79194",
"output": "2"
},
{
"input": "3\n-63526 95085 -5239",
... | 1,563,653,929 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 6,041,600 | n = int(input())
lis = input().split(" ")
for x in range(len(lis)):
lis[x] = int(lis[x])
stuff = []
for n in lis:
if n != 0 and n not in stuff:
stuff.append(n)
print(len(stuff))
| Title: Nastya and an Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second ... | ```python
n = int(input())
lis = input().split(" ")
for x in range(len(lis)):
lis[x] = int(lis[x])
stuff = []
for n in lis:
if n != 0 and n not in stuff:
stuff.append(n)
print(len(stuff))
``` | 0 | |
302 | A | Eugeny and Array | PROGRAMMING | 800 | [
"implementation"
] | null | null | Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). - The response to the query will be integer 1, if the elements of a... | The first line contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=2·105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*a**i*<==<=-1,<=1). Next *m* lines contain Eugene's queries. The *i*-th line contains integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). | Print *m* integers — the responses to Eugene's queries in the order they occur in the input. | [
"2 3\n1 -1\n1 1\n1 2\n2 2\n",
"5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5\n"
] | [
"0\n1\n0\n",
"0\n1\n0\n1\n0\n"
] | none | 500 | [
{
"input": "2 3\n1 -1\n1 1\n1 2\n2 2",
"output": "0\n1\n0"
},
{
"input": "5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5",
"output": "0\n1\n0\n1\n0"
},
{
"input": "3 3\n1 1 1\n2 2\n1 1\n1 1",
"output": "0\n0\n0"
},
{
"input": "4 4\n-1 -1 -1 -1\n1 3\n1 2\n1 2\n1 1",
"output": "... | 1,678,472,810 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 17 | 1,000 | 24,985,600 | n, m = tuple(map(int, input().split()))
lst = input().split()
negatives = lst.count('-1')
positives = n - negatives
def check(ln):
if ln % 1 != 0:
result = 0
else:
if negatives >= ln and positives >= ln:
result = 1
else:
result = 0
return result
LN = []
... | Title: Eugeny and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (... | ```python
n, m = tuple(map(int, input().split()))
lst = input().split()
negatives = lst.count('-1')
positives = n - negatives
def check(ln):
if ln % 1 != 0:
result = 0
else:
if negatives >= ln and positives >= ln:
result = 1
else:
result = 0
return result
... | 0 | |
254 | C | Anagram | PROGRAMMING | 1,800 | [
"greedy",
"strings"
] | null | null | String *x* is an anagram of string *y*, if we can rearrange the letters in string *x* and get exact string *y*. For example, strings "DOG" and "GOD" are anagrams, so are strings "BABA" and "AABB", but strings "ABBAC" and "CAABA" are not.
You are given two strings *s* and *t* of the same length, consisting of uppercase... | The input consists of two lines. The first line contains string *s*, the second line contains string *t*. The strings have the same length (from 1 to 105 characters) and consist of uppercase English letters. | In the first line print *z* — the minimum number of replacement operations, needed to get an anagram of string *t* from string *s*. In the second line print the lexicographically minimum anagram that could be obtained in *z* operations. | [
"ABA\nCBA\n",
"CDBABC\nADCABD\n"
] | [
"1\nABC\n",
"2\nADBADC\n"
] | The second sample has eight anagrams of string *t*, that can be obtained from string *s* by replacing exactly two letters: "ADBADC", "ADDABC", "CDAABD", "CDBAAD", "CDBADA", "CDDABA", "DDAABC", "DDBAAC". These anagrams are listed in the lexicographical order. The lexicographically minimum anagram is "ADBADC". | 1,500 | [
{
"input": "ABA\nCBA",
"output": "1\nABC"
},
{
"input": "CDBABC\nADCABD",
"output": "2\nADBADC"
},
{
"input": "AABAA\nBBAAA",
"output": "1\nAABAB"
},
{
"input": "OVGHK\nRPGUC",
"output": "4\nCPGRU"
},
{
"input": "CCAACBA\nBBBAACC",
"output": "2\nBCAACBB"
},
... | 1,580,911,310 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 436 | 2,048,000 | s=list(input())
t=list(input())
sf,tf=[0]*(26),[0]*(26)
tem='ABCDEFGHIJKLMNOPQRSTUVWXYZ'
n=len(s)
z=0
for i in s:
sf[ord(i)-ord('A')]+=1
for i in t:
tf[ord(i)-ord('A')]+=1
nn=n-1
for i in range(25):
if sf[i]<tf[i]:
for j in range(nn):
k=ord(s[j])-ord('A')
... | Title: Anagram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
String *x* is an anagram of string *y*, if we can rearrange the letters in string *x* and get exact string *y*. For example, strings "DOG" and "GOD" are anagrams, so are strings "BABA" and "AABB", but strings "ABBAC" and "CAABA... | ```python
s=list(input())
t=list(input())
sf,tf=[0]*(26),[0]*(26)
tem='ABCDEFGHIJKLMNOPQRSTUVWXYZ'
n=len(s)
z=0
for i in s:
sf[ord(i)-ord('A')]+=1
for i in t:
tf[ord(i)-ord('A')]+=1
nn=n-1
for i in range(25):
if sf[i]<tf[i]:
for j in range(nn):
k=ord(s[j])-ord('A')
... | -1 | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,695,335,738 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | g = input()
god = int(g)
f = True
ff= False
while not ff:
god+=1
g=str(god)
f=True
for i in range (len(g)-1):
for j in range(i+1,len(g)):
if g[i]==g[j]:
f = False
if f:
print(god)
ff=True
| Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
g = input()
god = int(g)
f = True
ff= False
while not ff:
god+=1
g=str(god)
f=True
for i in range (len(g)-1):
for j in range(i+1,len(g)):
if g[i]==g[j]:
f = False
if f:
print(god)
ff=True
``` | 3 | |
29 | A | Spit Problem | PROGRAMMING | 1,000 | [
"brute force"
] | A. Spit Problem | 2 | 256 | In a Berland's zoo there is an enclosure with camels. It is known that camels like to spit. Bob watched these interesting animals for the whole day and registered in his notepad where each animal spitted. Now he wants to know if in the zoo there are two camels, which spitted at each other. Help him to solve this task.
... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the amount of camels in the zoo. Each of the following *n* lines contains two integers *x**i* and *d**i* (<=-<=104<=≤<=*x**i*<=≤<=104,<=1<=≤<=|*d**i*|<=≤<=2·104) — records in Bob's notepad. *x**i* is a position of the *i*-th camel, and *d**i* is a distance at wh... | If there are two camels, which spitted at each other, output YES. Otherwise, output NO. | [
"2\n0 1\n1 -1\n",
"3\n0 1\n1 1\n2 -2\n",
"5\n2 -10\n3 10\n0 5\n5 -5\n10 1\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "2\n0 1\n1 -1",
"output": "YES"
},
{
"input": "3\n0 1\n1 1\n2 -2",
"output": "NO"
},
{
"input": "5\n2 -10\n3 10\n0 5\n5 -5\n10 1",
"output": "YES"
},
{
"input": "10\n-9897 -1144\n-4230 -6350\n2116 -3551\n-3635 4993\n3907 -9071\n-2362 4120\n-6542 984\n5807 3745\n759... | 1,613,405,962 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 154 | 307,200 |
rpta = False
n = int(input())
x = []
d = []
for i in range(n):
datos = input().split()
x.append(int(datos[0]))
d.append(int(datos[1]))
for i in range(n):
for j in range(n):
if x[i]+d[i] == x[j] and x[j]+d[j] == x[i]:
rpta = True
break;
if rpta:
... | Title: Spit Problem
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
In a Berland's zoo there is an enclosure with camels. It is known that camels like to spit. Bob watched these interesting animals for the whole day and registered in his notepad where each animal spitted. Now he wants to know ... | ```python
rpta = False
n = int(input())
x = []
d = []
for i in range(n):
datos = input().split()
x.append(int(datos[0]))
d.append(int(datos[1]))
for i in range(n):
for j in range(n):
if x[i]+d[i] == x[j] and x[j]+d[j] == x[i]:
rpta = True
break;
if rpta... | 3.960928 |
515 | C | Drazil and Factorial | PROGRAMMING | 1,400 | [
"greedy",
"math",
"sortings"
] | null | null | Drazil is playing a math game with Varda.
Let's define for positive integer *x* as a product of factorials of its digits. For example, .
First, they choose a decimal number *a* consisting of *n* digits that contains at least one digit larger than 1. This number may possibly start with leading zeroes. Then they shoul... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=15) — the number of digits in *a*.
The second line contains *n* digits of *a*. There is at least one digit in *a* that is larger than 1. Number *a* may possibly contain leading zeroes. | Output a maximum possible integer satisfying the conditions above. There should be no zeroes and ones in this number decimal representation. | [
"4\n1234\n",
"3\n555\n"
] | [
"33222\n",
"555\n"
] | In the first case, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/f5a4207f23215fddce977ab5ea9e9d2e7578fb52.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "4\n1234",
"output": "33222"
},
{
"input": "3\n555",
"output": "555"
},
{
"input": "15\n012345781234578",
"output": "7777553333222222222222"
},
{
"input": "1\n8",
"output": "7222"
},
{
"input": "10\n1413472614",
"output": "75333332222222"
},
{
... | 1,672,483,705 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 46 | 0 | n = int(input())
s = int(input())
occ = [0]*(10)
ans = ''
while s > 0:
digit = s%10
if digit == 0 or digit == 1:
s//=10
continue
else:
if digit == 9:
ans += '722233'
elif digit == 8:
ans += '7222'
elif digit == 6:
a... | Title: Drazil and Factorial
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Drazil is playing a math game with Varda.
Let's define for positive integer *x* as a product of factorials of its digits. For example, .
First, they choose a decimal number *a* consisting of *n* digits that cont... | ```python
n = int(input())
s = int(input())
occ = [0]*(10)
ans = ''
while s > 0:
digit = s%10
if digit == 0 or digit == 1:
s//=10
continue
else:
if digit == 9:
ans += '722233'
elif digit == 8:
ans += '7222'
elif digit == 6:
... | 0 | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,635,437,663 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 1,000 | 39,526,400 | n = int(input())
queue = ['Sheldon', 'Leonard', 'Penny', 'Rajesh', 'Howard']
start = 0
end = 4
while start != n:
person = queue[start]
queue.append(person)
queue.append(person)
start += 1
end += 2
if end >= n:
break
print(queue[n-1])
| Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
n = int(input())
queue = ['Sheldon', 'Leonard', 'Penny', 'Rajesh', 'Howard']
start = 0
end = 4
while start != n:
person = queue[start]
queue.append(person)
queue.append(person)
start += 1
end += 2
if end >= n:
break
print(queue[n-1])
``` | 0 |
177 | B1 | Rectangular Game | PROGRAMMING | 1,000 | [
"number theory"
] | null | null | The Smart Beaver from ABBYY decided to have a day off. But doing nothing the whole day turned out to be too boring, and he decided to play a game with pebbles. Initially, the Beaver has *n* pebbles. He arranges them in *a* equal rows, each row has *b* pebbles (*a*<=><=1). Note that the Beaver must use all the pebble... | The single line of the input contains a single integer *n* — the initial number of pebbles the Smart Beaver has.
The input limitations for getting 30 points are:
- 2<=≤<=*n*<=≤<=50
The input limitations for getting 100 points are:
- 2<=≤<=*n*<=≤<=109 | Print a single number — the maximum possible result of the game. | [
"10\n",
"8\n"
] | [
"16\n",
"15\n"
] | Consider the first example (*c*<sub class="lower-index">1</sub> = 10). The possible options for the game development are:
- Arrange the pebbles in 10 rows, one pebble per row. Then *c*<sub class="lower-index">2</sub> = 1, and the game ends after the first move with the result of 11. - Arrange the pebbles in 5 rows, ... | 30 | [
{
"input": "10",
"output": "16"
},
{
"input": "8",
"output": "15"
},
{
"input": "4",
"output": "7"
},
{
"input": "36",
"output": "67"
},
{
"input": "32",
"output": "63"
},
{
"input": "46",
"output": "70"
},
{
"input": "6",
"output": "10... | 1,631,634,596 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS1 | 3 | 124 | 6,758,400 | #177B1 (80No. Problem B)
p = int(input())
ans = p
while p > 1:
if (p%2 == 0):
t = p//2
p -= t
ans+= t
else:
ans+= 1
break
# print(t)
print(ans) | Title: Rectangular Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Smart Beaver from ABBYY decided to have a day off. But doing nothing the whole day turned out to be too boring, and he decided to play a game with pebbles. Initially, the Beaver has *n* pebbles. He arranges them in... | ```python
#177B1 (80No. Problem B)
p = int(input())
ans = p
while p > 1:
if (p%2 == 0):
t = p//2
p -= t
ans+= t
else:
ans+= 1
break
# print(t)
print(ans)
``` | 0 | |
16 | B | Burglar and Matches | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | B. Burglar and Matches | 0 | 64 | A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactl... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer. | Output the only number — answer to the problem. | [
"7 3\n5 10\n2 5\n3 6\n",
"3 3\n1 3\n2 2\n3 1\n"
] | [
"62\n",
"7\n"
] | none | 0 | [
{
"input": "7 3\n5 10\n2 5\n3 6",
"output": "62"
},
{
"input": "3 3\n1 3\n2 2\n3 1",
"output": "7"
},
{
"input": "1 1\n1 2",
"output": "2"
},
{
"input": "1 2\n1 9\n1 6",
"output": "9"
},
{
"input": "1 10\n1 1\n1 9\n1 3\n1 9\n1 7\n1 10\n1 4\n1 7\n1 3\n1 1",
"ou... | 1,675,753,575 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 122 | 0 | n,m=map(int,input().split())
d={}
a=0
s=0
b=0
while m >0:
a,b=map(int,input().split())
d[b]=a
m-=1
for k,v in reversed(sorted(d.items())):
s+=k*min(n,v)
n-=v
if n<0:
break
print(s)
| Title: Burglar and Matches
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* mat... | ```python
n,m=map(int,input().split())
d={}
a=0
s=0
b=0
while m >0:
a,b=map(int,input().split())
d[b]=a
m-=1
for k,v in reversed(sorted(d.items())):
s+=k*min(n,v)
n-=v
if n<0:
break
print(s)
``` | 0 |
660 | A | Co-prime Array | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | You are given an array of *n* elements, you must make it a co-prime array in as few moves as possible.
In each move you can insert any positive integral number you want not greater than 109 in any place in the array.
An array is co-prime if any two adjacent numbers of it are co-prime.
In the number theory, two integ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in the given array.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of the array *a*. | Print integer *k* on the first line — the least number of elements needed to add to the array *a* to make it co-prime.
The second line should contain *n*<=+<=*k* integers *a**j* — the elements of the array *a* after adding *k* elements to it. Note that the new array should be co-prime, so any two adjacent values shoul... | [
"3\n2 7 28\n"
] | [
"1\n2 7 9 28\n"
] | none | 0 | [
{
"input": "3\n2 7 28",
"output": "1\n2 7 1 28"
},
{
"input": "1\n1",
"output": "0\n1"
},
{
"input": "1\n548",
"output": "0\n548"
},
{
"input": "1\n963837006",
"output": "0\n963837006"
},
{
"input": "10\n1 1 1 1 1 1 1 1 1 1",
"output": "0\n1 1 1 1 1 1 1 1 1 1"... | 1,683,130,927 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 14 | 61 | 1,536,000 | import math
n = int(input())
arr = list(map(int, input().split()))
ans = [arr[0]]
for i in range(1, n):
tmp = ans[-1]
if math.gcd(tmp, arr[i]) == 1:
ans.append(arr[i])
else:
temp = tmp+1
while True:
if math.gcd(tmp, temp) == 1 and math.gcd(temp, arr[i]) =... | Title: Co-prime Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array of *n* elements, you must make it a co-prime array in as few moves as possible.
In each move you can insert any positive integral number you want not greater than 109 in any place in the array.
A... | ```python
import math
n = int(input())
arr = list(map(int, input().split()))
ans = [arr[0]]
for i in range(1, n):
tmp = ans[-1]
if math.gcd(tmp, arr[i]) == 1:
ans.append(arr[i])
else:
temp = tmp+1
while True:
if math.gcd(tmp, temp) == 1 and math.gcd(temp,... | 0 | |
466 | A | Cheap Travel | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Ann has recently started commuting by subway. We know that a one ride subway ticket costs *a* rubles. Besides, Ann found out that she can buy a special ticket for *m* rides (she can buy it several times). It costs *b* rubles. Ann did the math; she will need to use subway *n* times. Help Ann, tell her what is the minimu... | The single line contains four space-separated integers *n*, *m*, *a*, *b* (1<=≤<=*n*,<=*m*,<=*a*,<=*b*<=≤<=1000) — the number of rides Ann has planned, the number of rides covered by the *m* ride ticket, the price of a one ride ticket and the price of an *m* ride ticket. | Print a single integer — the minimum sum in rubles that Ann will need to spend. | [
"6 2 1 2\n",
"5 2 2 3\n"
] | [
"6\n",
"8\n"
] | In the first sample one of the optimal solutions is: each time buy a one ride ticket. There are other optimal solutions. For example, buy three *m* ride tickets. | 500 | [
{
"input": "6 2 1 2",
"output": "6"
},
{
"input": "5 2 2 3",
"output": "8"
},
{
"input": "10 3 5 1",
"output": "4"
},
{
"input": "1000 1 1000 1000",
"output": "1000000"
},
{
"input": "1000 3 1000 1000",
"output": "334000"
},
{
"input": "1 1 1 1",
"... | 1,690,626,656 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 31 | 0 | # a - 1 билет, m проездов за b рублей, n раз нужно воспользоваться метрополитеном.
n, m, a, b = map(int, input().split())
q1 = a * n
q2 = ((n // m) * b) + ((n % m) * a)
q3 = (n // m + 1) * b
print(min(q1, q2, q3))
# 10 3 5 1 -> 4 | Title: Cheap Travel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ann has recently started commuting by subway. We know that a one ride subway ticket costs *a* rubles. Besides, Ann found out that she can buy a special ticket for *m* rides (she can buy it several times). It costs *b* rubl... | ```python
# a - 1 билет, m проездов за b рублей, n раз нужно воспользоваться метрополитеном.
n, m, a, b = map(int, input().split())
q1 = a * n
q2 = ((n // m) * b) + ((n % m) * a)
q3 = (n // m + 1) * b
print(min(q1, q2, q3))
# 10 3 5 1 -> 4
``` | 3 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,571,659,432 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 0 | a=input()
while "hh" in a:
b=a.replace("hh","h")
a=b
while "ee" in a:
b=a.replace("ee","e")
a=b
while "lll" in a:
b=a.replace("lll","ll")
a=b
while "oo" in a:
b=a.replace("oo","o")
a=b
if "hello" in a:
print("YES")
else:
print("NO")
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
a=input()
while "hh" in a:
b=a.replace("hh","h")
a=b
while "ee" in a:
b=a.replace("ee","e")
a=b
while "lll" in a:
b=a.replace("lll","ll")
a=b
while "oo" in a:
b=a.replace("oo","o")
a=b
if "hello" in a:
print("YES")
else:
print("NO")
``` | 0 |
Subsets and Splits
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Retrieves records of users with a rating of 1600 or higher and a verdict of 'OK', providing basic filtering but limited analytical value.
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Counts the number of entries with a rating above 2000 and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a 'OK' verdict, providing a basic overview of a specific category within the dataset.