contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
52 | C | Circular RMQ | PROGRAMMING | 2,200 | [
"data structures"
] | C. Circular RMQ | 1 | 256 | You are given circular array *a*0,<=*a*1,<=...,<=*a**n*<=-<=1. There are two types of operations with it:
- *inc*(*lf*,<=*rg*,<=*v*) — this operation increases each element on the segment [*lf*,<=*rg*] (inclusively) by *v*; - *rmq*(*lf*,<=*rg*) — this operation returns minimal value on the segment [*lf*,<=*rg*] (in... | The first line contains integer *n* (1<=≤<=*n*<=≤<=200000). The next line contains initial state of the array: *a*0,<=*a*1,<=...,<=*a**n*<=-<=1 (<=-<=106<=≤<=*a**i*<=≤<=106), *a**i* are integer. The third line contains integer *m* (0<=≤<=*m*<=≤<=200000), *m* — the number of operartons. Next *m* lines contain one operat... | For each *rmq* operation write result for it. Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d). | [
"4\n1 2 3 4\n4\n3 0\n3 0 -1\n0 1\n2 1\n"
] | [
"1\n0\n0\n"
] | none | 1,500 | [
{
"input": "4\n1 2 3 4\n4\n3 0\n3 0 -1\n0 1\n2 1",
"output": "1\n0\n0"
},
{
"input": "1\n-1\n10\n0 0 -1\n0 0\n0 0 1\n0 0\n0 0 1\n0 0\n0 0 0\n0 0\n0 0 -1\n0 0 1",
"output": "-2\n-1\n0\n0"
},
{
"input": "2\n-1 -1\n10\n0 0\n0 0\n0 0 1\n0 0\n1 1\n0 0 -1\n0 0 0\n0 0 1\n1 1 0\n0 0 -1",
"ou... | 1,645,691,922 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 61 | 0 | class SegmentTree:
l, r, val, push_l, push_r, push_val, inf, left, right = 0, 0, 0, 0, 0, 0, 10 ** 18, None, None
def __init__(self, l, r, a):
self.l = l
self.r = r
if self.l == self.r:
self.val = a[l]
return
m = (self.l + self.r) // 2
... | Title: Circular RMQ
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given circular array *a*0,<=*a*1,<=...,<=*a**n*<=-<=1. There are two types of operations with it:
- *inc*(*lf*,<=*rg*,<=*v*) — this operation increases each element on the segment [*lf*,<=*rg*] (inclusively) by *v*;... | ```python
class SegmentTree:
l, r, val, push_l, push_r, push_val, inf, left, right = 0, 0, 0, 0, 0, 0, 10 ** 18, None, None
def __init__(self, l, r, a):
self.l = l
self.r = r
if self.l == self.r:
self.val = a[l]
return
m = (self.l + self.r) /... | 0 |
219 | A | k-String | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
You are given a string... | The first input line contains integer *k* (1<=≤<=*k*<=≤<=1000). The second line contains *s*, all characters in *s* are lowercase English letters. The string length *s* satisfies the inequality 1<=≤<=|*s*|<=≤<=1000, where |*s*| is the length of string *s*. | Rearrange the letters in string *s* in such a way that the result is a *k*-string. Print the result on a single output line. If there are multiple solutions, print any of them.
If the solution doesn't exist, print "-1" (without quotes). | [
"2\naazz\n",
"3\nabcabcabz\n"
] | [
"azaz\n",
"-1\n"
] | none | 500 | [
{
"input": "2\naazz",
"output": "azaz"
},
{
"input": "3\nabcabcabz",
"output": "-1"
},
{
"input": "1\na",
"output": "a"
},
{
"input": "2\nabba",
"output": "abab"
},
{
"input": "2\naaab",
"output": "-1"
},
{
"input": "7\nabacaba",
"output": "-1"
}... | 1,649,079,093 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | if __name__ == '__main__':
n = int(input())
array = [[0] * 3 for i in range(n)]
temp_arr = [0, 0]
for i in range(n):
temp_arr = input().split()
array[i][0] = int(temp_arr[0])
array[i][1] = int(temp_arr[1])
i = 0
counter = 1
while i < n:
temp_cou... | Title: k-String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a ... | ```python
if __name__ == '__main__':
n = int(input())
array = [[0] * 3 for i in range(n)]
temp_arr = [0, 0]
for i in range(n):
temp_arr = input().split()
array[i][0] = int(temp_arr[0])
array[i][1] = int(temp_arr[1])
i = 0
counter = 1
while i < n:
... | -1 | |
682 | A | Alyona and Numbers | PROGRAMMING | 1,100 | [
"constructive algorithms",
"math",
"number theory"
] | null | null | After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers from 1 to *m*. Now the girl wants to count how many pairs of integers she can choose, one from the first... | The only line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1<=000<=000). | Print the only integer — the number of pairs of integers (*x*,<=*y*) such that 1<=≤<=*x*<=≤<=*n*, 1<=≤<=*y*<=≤<=*m* and (*x*<=+<=*y*) is divisible by 5. | [
"6 12\n",
"11 14\n",
"1 5\n",
"3 8\n",
"5 7\n",
"21 21\n"
] | [
"14\n",
"31\n",
"1\n",
"5\n",
"7\n",
"88\n"
] | Following pairs are suitable in the first sample case:
- for *x* = 1 fits *y* equal to 4 or 9; - for *x* = 2 fits *y* equal to 3 or 8; - for *x* = 3 fits *y* equal to 2, 7 or 12; - for *x* = 4 fits *y* equal to 1, 6 or 11; - for *x* = 5 fits *y* equal to 5 or 10; - for *x* = 6 fits *y* equal to 4 or 9.
Only th... | 500 | [
{
"input": "6 12",
"output": "14"
},
{
"input": "11 14",
"output": "31"
},
{
"input": "1 5",
"output": "1"
},
{
"input": "3 8",
"output": "5"
},
{
"input": "5 7",
"output": "7"
},
{
"input": "21 21",
"output": "88"
},
{
"input": "10 15",
... | 1,617,071,268 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 62 | 307,200 | a,b=map(int,input().split(" "))
m=min(a,b)
n=max(a,b)
c=0
for i in range(1,m+1):
num=i%5
if num==0:
num=5
init=abs(5-num)
ans=(abs(n-init))//5
if num!=5:
ans+=1
c+=ans
print(c)
| Title: Alyona and Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers ... | ```python
a,b=map(int,input().split(" "))
m=min(a,b)
n=max(a,b)
c=0
for i in range(1,m+1):
num=i%5
if num==0:
num=5
init=abs(5-num)
ans=(abs(n-init))//5
if num!=5:
ans+=1
c+=ans
print(c)
``` | 0 | |
104 | A | Blackjack | PROGRAMMING | 800 | [
"implementation"
] | A. Blackjack | 2 | 256 | One rainy gloomy evening when all modules hid in the nearby cafes to drink hot energetic cocktails, the Hexadecimal virus decided to fly over the Mainframe to look for a Great Idea. And she has found one!
Why not make her own Codeforces, with blackjack and other really cool stuff? Many people will surely be willing to... | The only line contains *n* (1<=≤<=*n*<=≤<=25) — the required sum of points. | Print the numbers of ways to get the second card in the required way if the first card is the queen of spades. | [
"12\n",
"20\n",
"10\n"
] | [
"4",
"15",
"0"
] | In the first sample only four two's of different suits can earn the required sum of points.
In the second sample we can use all tens, jacks, queens and kings; overall it's 15 cards, as the queen of spades (as any other card) is only present once in the pack of cards and it's already in use.
In the third sample there ... | 500 | [
{
"input": "12",
"output": "4"
},
{
"input": "20",
"output": "15"
},
{
"input": "10",
"output": "0"
},
{
"input": "11",
"output": "4"
},
{
"input": "15",
"output": "4"
},
{
"input": "18",
"output": "4"
},
{
"input": "25",
"output": "0"
... | 1,656,359,948 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | int n; cin>>n;
for(int i=11;i<20;i++)ans[i]=4;
ans[20]=15;ans[21]=4;
cout<<ans[n];
return 0;
| Title: Blackjack
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One rainy gloomy evening when all modules hid in the nearby cafes to drink hot energetic cocktails, the Hexadecimal virus decided to fly over the Mainframe to look for a Great Idea. And she has found one!
Why not make her own Co... | ```python
int n; cin>>n;
for(int i=11;i<20;i++)ans[i]=4;
ans[20]=15;ans[21]=4;
cout<<ans[n];
return 0;
``` | -1 |
492 | C | Vanya and Exams | PROGRAMMING | 1,400 | [
"greedy",
"sortings"
] | null | null | Vanya wants to pass *n* exams and get the academic scholarship. He will get the scholarship if the average grade mark for all the exams is at least *avg*. The exam grade cannot exceed *r*. Vanya has passed the exams and got grade *a**i* for the *i*-th exam. To increase the grade for the *i*-th exam by 1 point, Vanya mu... | The first line contains three integers *n*, *r*, *avg* (1<=≤<=*n*<=≤<=105, 1<=≤<=*r*<=≤<=109, 1<=≤<=*avg*<=≤<=*min*(*r*,<=106)) — the number of exams, the maximum grade and the required grade point average, respectively.
Each of the following *n* lines contains space-separated integers *a**i* and *b**i* (1<=≤<=*a**i*<... | In the first line print the minimum number of essays. | [
"5 5 4\n5 2\n4 7\n3 1\n3 2\n2 5\n",
"2 5 4\n5 2\n5 2\n"
] | [
"4\n",
"0\n"
] | In the first sample Vanya can write 2 essays for the 3rd exam to raise his grade by 2 points and 2 essays for the 4th exam to raise his grade by 1 point.
In the second sample, Vanya doesn't need to write any essays as his general point average already is above average. | 1,500 | [
{
"input": "5 5 4\n5 2\n4 7\n3 1\n3 2\n2 5",
"output": "4"
},
{
"input": "2 5 4\n5 2\n5 2",
"output": "0"
},
{
"input": "6 5 5\n1 7\n2 4\n3 5\n4 6\n5 6\n4 7",
"output": "63"
},
{
"input": "1 1000000000 1000000\n1 1000000",
"output": "999999000000"
},
{
"input": "1... | 1,695,171,409 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 39 | 358 | 10,854,400 | from sys import stdin
def input(): return stdin.readline()[:-1]
N, MAX, AVG = map(int, input().split())
ans = 0
tot = AVG * N
exams = []
for _ in range(N):
a, b = map(int, input().split())
tot -= a
exams.append((b, a))
if tot <= 0:
print(0)
exit()
exams.sort()
for b, a in exams:
... | Title: Vanya and Exams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya wants to pass *n* exams and get the academic scholarship. He will get the scholarship if the average grade mark for all the exams is at least *avg*. The exam grade cannot exceed *r*. Vanya has passed the exams and... | ```python
from sys import stdin
def input(): return stdin.readline()[:-1]
N, MAX, AVG = map(int, input().split())
ans = 0
tot = AVG * N
exams = []
for _ in range(N):
a, b = map(int, input().split())
tot -= a
exams.append((b, a))
if tot <= 0:
print(0)
exit()
exams.sort()
for b, a ... | 3 | |
892 | A | Greed | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not! | The first line of the input contains one integer *n* (2<=≤<=*n*<=≤<=100<=000) — number of cola cans.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — volume of remaining cola in cans.
The third line contains *n* space-separated integers that *b*1,<=*b*2,<=...,<... | Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).
You can print each letter in any case (upper or lower). | [
"2\n3 5\n3 6\n",
"3\n6 8 9\n6 10 12\n",
"5\n0 0 5 0 0\n1 1 8 10 5\n",
"4\n4 1 0 3\n5 2 2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"YES\n"
] | In the first sample, there are already 2 cans, so the answer is "YES". | 500 | [
{
"input": "2\n3 5\n3 6",
"output": "YES"
},
{
"input": "3\n6 8 9\n6 10 12",
"output": "NO"
},
{
"input": "5\n0 0 5 0 0\n1 1 8 10 5",
"output": "YES"
},
{
"input": "4\n4 1 0 3\n5 2 2 3",
"output": "YES"
},
{
"input": "10\n9 10 24 11 1 7 8 3 28 14\n86 20 34 11 22 9... | 1,699,252,328 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n=int(input())
volume=list(map(int,input().split()))
capacity=list(map(int,input().split()))
capsum=[]
if n==2:
print('YES')
sum_vol=sum(volume)
for i in range(n):
for j in range(1,n):
if i==j:
continue
if capacity[i]+capacity[j] not in capsum:
capsum.append(capacity[i]+c... | Title: Greed
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he c... | ```python
n=int(input())
volume=list(map(int,input().split()))
capacity=list(map(int,input().split()))
capsum=[]
if n==2:
print('YES')
sum_vol=sum(volume)
for i in range(n):
for j in range(1,n):
if i==j:
continue
if capacity[i]+capacity[j] not in capsum:
capsum.append(cap... | 0 | |
242 | E | XOR on Segment | PROGRAMMING | 2,000 | [
"bitmasks",
"data structures"
] | null | null | You've got an array *a*, consisting of *n* integers *a*1,<=*a*2,<=...,<=*a**n*. You are allowed to perform two operations on this array:
1. Calculate the sum of current array elements on the segment [*l*,<=*r*], that is, count value *a**l*<=+<=*a**l*<=+<=1<=+<=...<=+<=*a**r*. 1. Apply the xor operation with a given ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the size of the array. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=106) — the original array.
The third line contains integer *m* (1<=≤<=*m*<=≤<=5·104) — the number of operations with the array. The *i*-th of t... | For each query of type 1 print in a single line the sum of numbers on the given segment. Print the answers to the queries in the order in which the queries go in the input.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams, or the %I64d specifie... | [
"5\n4 10 3 13 7\n8\n1 2 4\n2 1 3 3\n1 2 4\n1 3 3\n2 2 5 5\n1 1 5\n2 1 2 10\n1 2 3\n",
"6\n4 7 4 0 7 3\n5\n2 2 3 8\n1 1 5\n2 3 5 1\n2 4 5 6\n1 2 3\n"
] | [
"26\n22\n0\n34\n11\n",
"38\n28\n"
] | none | 2,500 | [] | 1,684,395,324 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | # LUOGU_RID: 110637301
#include<bits/stdc++.h>
#define int long long
#define ls p<<1
#define rs p<<1|1
using namespace std;
const int SIZE=1e5+50;
int q[SIZE];
int n,cnt;
const int tot=30;
struct Q
{
int l,r;
int add;
int ans[tot];
}t[SIZE<<2];
void build(int l,int r,int p)
{
t[p].l=l,t[p].r=r;
... | Title: XOR on Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got an array *a*, consisting of *n* integers *a*1,<=*a*2,<=...,<=*a**n*. You are allowed to perform two operations on this array:
1. Calculate the sum of current array elements on the segment [*l*,<=*r*], that i... | ```python
# LUOGU_RID: 110637301
#include<bits/stdc++.h>
#define int long long
#define ls p<<1
#define rs p<<1|1
using namespace std;
const int SIZE=1e5+50;
int q[SIZE];
int n,cnt;
const int tot=30;
struct Q
{
int l,r;
int add;
int ans[tot];
}t[SIZE<<2];
void build(int l,int r,int p)
{
t[p].l=l,t[... | -1 | |
108 | A | Palindromic Times | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | A. Palindromic Times | 2 | 256 | Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling asleep, he was staring at the digital watch around Saher's wrist. He noticed that the digits on th... | The first and only line of the input starts with a string with the format "HH:MM" where "HH" is from "00" to "23" and "MM" is from "00" to "59". Both "HH" and "MM" have exactly two digits. | Print the palindromic time of day that comes soonest after the time given in the input. If the input time is palindromic, output the soonest palindromic time after the input time. | [
"12:21\n",
"23:59\n"
] | [
"13:31\n",
"00:00\n"
] | none | 500 | [
{
"input": "12:21",
"output": "13:31"
},
{
"input": "23:59",
"output": "00:00"
},
{
"input": "15:51",
"output": "20:02"
},
{
"input": "10:44",
"output": "11:11"
},
{
"input": "04:02",
"output": "04:40"
},
{
"input": "02:11",
"output": "02:20"
},
... | 1,565,943,997 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 248 | 0 | hour,minute = (int(x) for x in input().split(':'))
while True:
minute += 1
if minute == 60:
minute = 0
hour += 1
if hour == 24:
hour = 0
ans = '{:02d}:{:02d}'.format(hour,minute)
if ans==ans[::-1]:
print(ans)
break
| Title: Palindromic Times
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling... | ```python
hour,minute = (int(x) for x in input().split(':'))
while True:
minute += 1
if minute == 60:
minute = 0
hour += 1
if hour == 24:
hour = 0
ans = '{:02d}:{:02d}'.format(hour,minute)
if ans==ans[::-1]:
print(ans)
break
``` | 3.938 |
725 | A | Jumping Ball | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | In a new version of the famous Pinball game, one of the most important parts of the game field is a sequence of *n* bumpers. The bumpers are numbered with integers from 1 to *n* from left to right. There are two types of bumpers. They are denoted by the characters '<' and '>'. When the ball hits the bumper at pos... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the length of the sequence of bumpers. The second line contains the string, which consists of the characters '<' and '>'. The character at the *i*-th position of this string corresponds to the type of the *i*-th bumper. | Print one integer — the number of positions in the sequence such that the ball will eventually fall from the game field if it starts at that position. | [
"4\n<<><\n",
"5\n>>>>>\n",
"4\n>><<\n"
] | [
"2",
"5",
"0"
] | In the first sample, the ball will fall from the field if starts at position 1 or position 2.
In the second sample, any starting position will result in the ball falling from the field. | 500 | [
{
"input": "4\n<<><",
"output": "2"
},
{
"input": "5\n>>>>>",
"output": "5"
},
{
"input": "4\n>><<",
"output": "0"
},
{
"input": "3\n<<>",
"output": "3"
},
{
"input": "3\n<<<",
"output": "3"
},
{
"input": "3\n><<",
"output": "0"
},
{
"input... | 1,628,352,887 | 2,147,483,647 | Python 3 | OK | TESTS | 78 | 78 | 7,782,400 | #!/bin/python3
def JumpingBall(n, bumpers):
#Thus, the answer is the number of '<' bumpers in the beginning plus the number of '>' bumpers in the end.
leftCount = 0
rigCount = 0
isBeginLeft = 1
isBeginRig = 1
for i in range(n):
if isBeginLeft:
if bumpers[i] == '<':
leftCount += 1
el... | Title: Jumping Ball
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a new version of the famous Pinball game, one of the most important parts of the game field is a sequence of *n* bumpers. The bumpers are numbered with integers from 1 to *n* from left to right. There are two types of b... | ```python
#!/bin/python3
def JumpingBall(n, bumpers):
#Thus, the answer is the number of '<' bumpers in the beginning plus the number of '>' bumpers in the end.
leftCount = 0
rigCount = 0
isBeginLeft = 1
isBeginRig = 1
for i in range(n):
if isBeginLeft:
if bumpers[i] == '<':
leftCount += ... | 3 | |
217 | A | Ice Skating | PROGRAMMING | 1,200 | [
"brute force",
"dfs and similar",
"dsu",
"graphs"
] | null | null | Bajtek is learning to skate on ice. He's a beginner, so his only mode of transportation is pushing off from a snow drift to the north, east, south or west and sliding until he lands in another snow drift. He has noticed that in this way it's impossible to get from some snow drifts to some other by any sequence of moves... | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of snow drifts. Each of the following *n* lines contains two integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=1000) — the coordinates of the *i*-th snow drift.
Note that the north direction coinсides with the direction of *Oy* ... | Output the minimal number of snow drifts that need to be created in order for Bajtek to be able to reach any snow drift from any other one. | [
"2\n2 1\n1 2\n",
"2\n2 1\n4 1\n"
] | [
"1\n",
"0\n"
] | none | 500 | [
{
"input": "2\n2 1\n1 2",
"output": "1"
},
{
"input": "2\n2 1\n4 1",
"output": "0"
},
{
"input": "24\n171 35\n261 20\n4 206\n501 446\n961 912\n581 748\n946 978\n463 514\n841 889\n341 466\n842 967\n54 102\n235 261\n925 889\n682 672\n623 636\n268 94\n635 710\n474 510\n697 794\n586 663\n182... | 1,592,818,174 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <iostream>
#include <algorithm>
#include <vector>
#include <map>
using namespace std;
bool used[110];
void dfs(int i, vector <pair <int, int>>& dots) {
used[i] = true;
for (int j = 0; j < dots.size(); ++j) {
if (j == i or used[j]) continue;
if (dots[j].first == dots[i].first or dots[j].second =... | Title: Ice Skating
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bajtek is learning to skate on ice. He's a beginner, so his only mode of transportation is pushing off from a snow drift to the north, east, south or west and sliding until he lands in another snow drift. He has noticed tha... | ```python
#include <iostream>
#include <algorithm>
#include <vector>
#include <map>
using namespace std;
bool used[110];
void dfs(int i, vector <pair <int, int>>& dots) {
used[i] = true;
for (int j = 0; j < dots.size(); ++j) {
if (j == i or used[j]) continue;
if (dots[j].first == dots[i].first or dots[j... | -1 | |
817 | A | Treasure Hunt | PROGRAMMING | 1,200 | [
"implementation",
"math",
"number theory"
] | null | null | Captain Bill the Hummingbird and his crew recieved an interesting challenge offer. Some stranger gave them a map, potion of teleportation and said that only this potion might help them to reach the treasure.
Bottle with potion has two values *x* and *y* written on it. These values define four moves which can be perfo... | The first line contains four integer numbers *x*1,<=*y*1,<=*x*2,<=*y*2 (<=-<=105<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=105) — positions of Captain Bill the Hummingbird and treasure respectively.
The second line contains two integer numbers *x*,<=*y* (1<=≤<=*x*,<=*y*<=≤<=105) — values on the potion bottle. | Print "YES" if it is possible for Captain to reach the treasure using the potion, otherwise print "NO" (without quotes). | [
"0 0 0 6\n2 3\n",
"1 1 3 6\n1 5\n"
] | [
"YES\n",
"NO\n"
] | In the first example there exists such sequence of moves:
1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7c939890fb4ed35688177327dac981bfa9216c00.png" style="max-width: 100.0%;max-height: 100.0%;"/> — the first type of move 1. <img align="middle" class="tex-formula" src="https://espr... | 0 | [
{
"input": "0 0 0 6\n2 3",
"output": "YES"
},
{
"input": "1 1 3 6\n1 5",
"output": "NO"
},
{
"input": "5 4 6 -10\n1 1",
"output": "NO"
},
{
"input": "6 -3 -7 -7\n1 2",
"output": "NO"
},
{
"input": "2 -5 -8 8\n2 1",
"output": "YES"
},
{
"input": "70 -81... | 1,498,697,890 | 2,147,483,647 | PyPy 3 | OK | TESTS | 61 | 109 | 23,142,400 | import sys
x1,y1,x2,y2=map(int,input().split())
a,b=map(int,input().split())
x,y=abs(x2-x1)/a,abs(y2-y1)/b
c,d=abs(x2-x1)%a,abs(y2-y1)%b
if c or d :
print("NO")
sys.exit()
elif (x-y)%2==0 :
print("YES")
else :
print("NO")
| Title: Treasure Hunt
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Captain Bill the Hummingbird and his crew recieved an interesting challenge offer. Some stranger gave them a map, potion of teleportation and said that only this potion might help them to reach the treasure.
Bottle with... | ```python
import sys
x1,y1,x2,y2=map(int,input().split())
a,b=map(int,input().split())
x,y=abs(x2-x1)/a,abs(y2-y1)/b
c,d=abs(x2-x1)%a,abs(y2-y1)%b
if c or d :
print("NO")
sys.exit()
elif (x-y)%2==0 :
print("YES")
else :
print("NO")
``` | 3 | |
842 | A | Kirill And The Game | PROGRAMMING | 1,200 | [
"brute force",
"two pointers"
] | null | null | Kirill plays a new computer game. He came to the potion store where he can buy any potion. Each potion is characterized by two integers — amount of experience and cost. The efficiency of a potion is the ratio of the amount of experience to the cost. Efficiency may be a non-integer number.
For each two integer numbers ... | First string contains five integer numbers *l*, *r*, *x*, *y*, *k* (1<=≤<=*l*<=≤<=*r*<=≤<=107, 1<=≤<=*x*<=≤<=*y*<=≤<=107, 1<=≤<=*k*<=≤<=107). | Print "YES" without quotes if a potion with efficiency exactly *k* can be bought in the store and "NO" without quotes otherwise.
You can output each of the letters in any register. | [
"1 10 1 10 1\n",
"1 5 6 10 1\n"
] | [
"YES",
"NO"
] | none | 500 | [
{
"input": "1 10 1 10 1",
"output": "YES"
},
{
"input": "1 5 6 10 1",
"output": "NO"
},
{
"input": "1 1 1 1 1",
"output": "YES"
},
{
"input": "1 1 1 1 2",
"output": "NO"
},
{
"input": "1 100000 1 100000 100000",
"output": "YES"
},
{
"input": "1 100000 ... | 1,504,022,465 | 3,365 | PyPy 3 | CHALLENGED | CHALLENGES | 13 | 93 | 0 | l,r,x,y,k=list((map(int,input().split())))
if (l/y)<=k<=(r/x):
print("YES")
else:
print("NO")
| Title: Kirill And The Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kirill plays a new computer game. He came to the potion store where he can buy any potion. Each potion is characterized by two integers — amount of experience and cost. The efficiency of a potion is the ratio of the... | ```python
l,r,x,y,k=list((map(int,input().split())))
if (l/y)<=k<=(r/x):
print("YES")
else:
print("NO")
``` | -1 | |
31 | A | Worms Evolution | PROGRAMMING | 1,200 | [
"implementation"
] | A. Worms Evolution | 2 | 256 | Professor Vasechkin is studying evolution of worms. Recently he put forward hypotheses that all worms evolve by division. There are *n* forms of worms. Worms of these forms have lengths *a*1, *a*2, ..., *a**n*. To prove his theory, professor needs to find 3 different forms that the length of the first form is equal to ... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of worm's forms. The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=1000) — lengths of worms of each form. | Output 3 distinct integers *i* *j* *k* (1<=≤<=*i*,<=*j*,<=*k*<=≤<=*n*) — such indexes of worm's forms that *a**i*<==<=*a**j*<=+<=*a**k*. If there is no such triple, output -1. If there are several solutions, output any of them. It possible that *a**j*<==<=*a**k*. | [
"5\n1 2 3 5 7\n",
"5\n1 8 1 5 1\n"
] | [
"3 2 1\n",
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 5 7",
"output": "3 2 1"
},
{
"input": "5\n1 8 1 5 1",
"output": "-1"
},
{
"input": "4\n303 872 764 401",
"output": "-1"
},
{
"input": "6\n86 402 133 524 405 610",
"output": "6 4 1"
},
{
"input": "8\n217 779 418 895 996 473 3 22",
"output":... | 1,528,946,934 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 184 | 102,400 | n = int(input())
l = list(map(int, input().split(" ")))
test = False
last = []
count = 0
st =""
t = False
for i in range(n):
for j in range(n):
if i==j :
continue
for k in range(n):
if k==j:
continue
if i!=j and i!=k and j!=k and ... | Title: Worms Evolution
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Professor Vasechkin is studying evolution of worms. Recently he put forward hypotheses that all worms evolve by division. There are *n* forms of worms. Worms of these forms have lengths *a*1, *a*2, ..., *a**n*. To prove his... | ```python
n = int(input())
l = list(map(int, input().split(" ")))
test = False
last = []
count = 0
st =""
t = False
for i in range(n):
for j in range(n):
if i==j :
continue
for k in range(n):
if k==j:
continue
if i!=j and i!=k and... | 3.953809 |
958 | A2 | Death Stars (medium) | PROGRAMMING | 2,000 | [
"hashing",
"strings"
] | null | null | The stardate is 1983, and Princess Heidi is getting better at detecting the Death Stars. This time, two Rebel spies have yet again given Heidi two maps with the possible locations of the Death Star. Since she got rid of all double agents last time, she knows that both maps are correct, and indeed show the map of the so... | The first line of the input contains two space-separated integers *N* and *M* (1<=≤<=*N*<=≤<=2000, 1<=≤<=*M*<=≤<=200, *M*<=≤<=*N*). The next *N* lines each contain *M* lower-case Latin characters (a-z), denoting the first map. Different characters correspond to different cosmic object types. The next *M* lines each con... | The only line of the output should contain two space-separated integers *i* and *j*, denoting that the section of size *M*<=×<=*M* in the first map that starts at the *i*-th row is equal to the section of the second map that starts at the *j*-th column. Rows and columns are numbered starting from 1.
If there are sever... | [
"10 5\nsomer\nandom\nnoise\nmayth\neforc\nebewi\nthyou\nhctwo\nagain\nnoise\nsomermayth\nandomeforc\nnoiseebewi\nagainthyou\nnoisehctwo\n"
] | [
"4 6\n"
] | The 5-by-5 grid for the first test case looks like this: | 0 | [
{
"input": "10 5\nsomer\nandom\nnoise\nmayth\neforc\nebewi\nthyou\nhctwo\nagain\nnoise\nsomermayth\nandomeforc\nnoiseebewi\nagainthyou\nnoisehctwo",
"output": "4 6"
},
{
"input": "1 1\ng\ng",
"output": "1 1"
}
] | 1,523,701,545 | 12,045 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 17 | 2,500 | 32,460,800 | from collections import defaultdict
N, M = map(int, input().split())
m1 = []
m2 = []
m1s = defaultdict(list)
for i, n in enumerate(range(N)):
line = input()
m1.append(line)
m1s[line].append(i)
m1s = dict(m1s)
s1 = ''.join(m1)
for m in range(M):
m2.append(input())
def cal():
for j in range(N - M +... | Title: Death Stars (medium)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The stardate is 1983, and Princess Heidi is getting better at detecting the Death Stars. This time, two Rebel spies have yet again given Heidi two maps with the possible locations of the Death Star. Since she got r... | ```python
from collections import defaultdict
N, M = map(int, input().split())
m1 = []
m2 = []
m1s = defaultdict(list)
for i, n in enumerate(range(N)):
line = input()
m1.append(line)
m1s[line].append(i)
m1s = dict(m1s)
s1 = ''.join(m1)
for m in range(M):
m2.append(input())
def cal():
for j in ran... | 0 | |
907 | A | Masha and Bears | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son bear can climb into the smallest car and he likes it. It's known that the largest car is strictly larg... | You are given four integers *V*1, *V*2, *V*3, *V**m*(1<=≤<=*V**i*<=≤<=100) — sizes of father bear, mother bear, son bear and Masha, respectively. It's guaranteed that *V*1<=><=*V*2<=><=*V*3. | Output three integers — sizes of father bear's car, mother bear's car and son bear's car, respectively.
If there are multiple possible solutions, print any.
If there is no solution, print "-1" (without quotes). | [
"50 30 10 10\n",
"100 50 10 21\n"
] | [
"50\n30\n10\n",
"-1\n"
] | In first test case all conditions for cars' sizes are satisfied.
In second test case there is no answer, because Masha should be able to climb into smallest car (so size of smallest car in not less than 21), but son bear should like it, so maximum possible size of it is 20. | 500 | [
{
"input": "50 30 10 10",
"output": "50\n30\n10"
},
{
"input": "100 50 10 21",
"output": "-1"
},
{
"input": "100 50 19 10",
"output": "100\n50\n19"
},
{
"input": "99 50 25 49",
"output": "100\n99\n49"
},
{
"input": "3 2 1 1",
"output": "4\n3\n1"
},
{
"... | 1,514,045,087 | 7,187 | Python 3 | RUNTIME_ERROR | PRETESTS | 0 | 46 | 5,529,600 | p, m, s, d = list(map(int, input().split()))
f = True
d = []
for i in range(s, 201):
if f:
for j in range(i + 1, 201):
if f:
for k in range(j + 1, 201):
if 2 * p >= k >= p and 2 * m >= j >= j and 2 * s >= i >= s and 2 * d >= i >= d and 2 * d < j:
f = False
d = [k,j,i]
else:
... | Title: Masha and Bears
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son b... | ```python
p, m, s, d = list(map(int, input().split()))
f = True
d = []
for i in range(s, 201):
if f:
for j in range(i + 1, 201):
if f:
for k in range(j + 1, 201):
if 2 * p >= k >= p and 2 * m >= j >= j and 2 * s >= i >= s and 2 * d >= i >= d and 2 * d < j:
f = False
d = [k,j,i]
... | -1 | |
2 | B | The least round way | PROGRAMMING | 2,000 | [
"dp",
"math"
] | B. The least round way | 2 | 64 | There is a square matrix *n*<=×<=*n*, consisting of non-negative integer numbers. You should find such a way on it that
- starts in the upper left cell of the matrix; - each following cell is to the right or down from the current cell; - the way ends in the bottom right cell.
Moreover, if we multiply together all... | The first line contains an integer number *n* (2<=≤<=*n*<=≤<=1000), *n* is the size of the matrix. Then follow *n* lines containing the matrix elements (non-negative integer numbers not exceeding 109). | In the first line print the least number of trailing zeros. In the second line print the correspondent way itself. | [
"3\n1 2 3\n4 5 6\n7 8 9\n"
] | [
"0\nDDRR\n"
] | none | 0 | [
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "0\nDDRR"
},
{
"input": "2\n7 6\n3 8",
"output": "0\nDR"
},
{
"input": "3\n4 10 5\n10 9 4\n6 5 3",
"output": "1\nDRRD"
},
{
"input": "4\n1 1 9 9\n3 4 7 3\n7 9 1 7\n1 7 1 5",
"output": "0\nDDDRRR"
},
{
"input": "5\n8 3... | 1,592,618,376 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 15 | 2,000 | 22,732,800 | import copy
def print_matrice(m):
for i in range(len(m)):
print(m[i])
def nb_facteurs(n, p):
if n==0:
return 0
nb = 0
while n%p==0:
nb += 1
n = int(n/p)
return nb
n = int(input())
facteurs = [2, 5]
m = [[["" for facteur in facteurs] for y in range(... | Title: The least round way
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
There is a square matrix *n*<=×<=*n*, consisting of non-negative integer numbers. You should find such a way on it that
- starts in the upper left cell of the matrix; - each following cell is to the right or down fro... | ```python
import copy
def print_matrice(m):
for i in range(len(m)):
print(m[i])
def nb_facteurs(n, p):
if n==0:
return 0
nb = 0
while n%p==0:
nb += 1
n = int(n/p)
return nb
n = int(input())
facteurs = [2, 5]
m = [[["" for facteur in facteurs] for y... | 0 |
302 | A | Eugeny and Array | PROGRAMMING | 800 | [
"implementation"
] | null | null | Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). - The response to the query will be integer 1, if the elements of a... | The first line contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=2·105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*a**i*<==<=-1,<=1). Next *m* lines contain Eugene's queries. The *i*-th line contains integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). | Print *m* integers — the responses to Eugene's queries in the order they occur in the input. | [
"2 3\n1 -1\n1 1\n1 2\n2 2\n",
"5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5\n"
] | [
"0\n1\n0\n",
"0\n1\n0\n1\n0\n"
] | none | 500 | [
{
"input": "2 3\n1 -1\n1 1\n1 2\n2 2",
"output": "0\n1\n0"
},
{
"input": "5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5",
"output": "0\n1\n0\n1\n0"
},
{
"input": "3 3\n1 1 1\n2 2\n1 1\n1 1",
"output": "0\n0\n0"
},
{
"input": "4 4\n-1 -1 -1 -1\n1 3\n1 2\n1 2\n1 1",
"output": "... | 1,640,292,341 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 13,619,200 | from sys import stdin, stdout
n, m = [int(x) for x in stdin.readline().split()]
a = [int(x) for x in stdin.readline().split()]
q, w = 0, 0
for i in range(n):
if a[i] == -1:
q += 1
else:
w += 1
for j in range(m):
x, y = (int(el) for el in input().split())
cnt = y - x + 1
i... | Title: Eugeny and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (... | ```python
from sys import stdin, stdout
n, m = [int(x) for x in stdin.readline().split()]
a = [int(x) for x in stdin.readline().split()]
q, w = 0, 0
for i in range(n):
if a[i] == -1:
q += 1
else:
w += 1
for j in range(m):
x, y = (int(el) for el in input().split())
cnt = y - x ... | 0 | |
376 | B | I.O.U. | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Imagine that there is a group of three friends: A, B and С. A owes B 20 rubles and B owes C 20 rubles. The total sum of the debts is 40 rubles. You can see that the debts are not organized in a very optimal manner. Let's rearrange them like that: assume that A owes C 20 rubles and B doesn't owe anything to anybody. The... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 0<=≤<=*m*<=≤<=104). The next *m* lines contain the debts. The *i*-th line contains three integers *a**i*,<=*b**i*,<=*c**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*; *a**i*<=≠<=*b**i*; 1<=≤<=*c**i*<=≤<=100), which mean that person *a**i* owes person *b**i* *c**i... | Print a single integer — the minimum sum of debts in the optimal rearrangement. | [
"5 3\n1 2 10\n2 3 1\n2 4 1\n",
"3 0\n",
"4 3\n1 2 1\n2 3 1\n3 1 1\n"
] | [
"10\n",
"0\n",
"0\n"
] | In the first sample, you can assume that person number 1 owes 8 rubles to person number 2, 1 ruble to person number 3 and 1 ruble to person number 4. He doesn't owe anybody else anything. In the end, the total debt equals 10.
In the second sample, there are no debts.
In the third sample, you can annul all the debts. | 1,000 | [
{
"input": "5 3\n1 2 10\n2 3 1\n2 4 1",
"output": "10"
},
{
"input": "3 0",
"output": "0"
},
{
"input": "4 3\n1 2 1\n2 3 1\n3 1 1",
"output": "0"
},
{
"input": "20 28\n1 5 6\n1 12 7\n1 13 4\n1 15 7\n1 20 3\n2 4 1\n2 15 6\n3 5 3\n3 8 10\n3 13 8\n3 20 6\n4 6 10\n4 12 8\n4 19 5\... | 1,637,172,737 | 2,147,483,647 | PyPy 3 | OK | TESTS | 29 | 140 | 3,379,200 | n, m = [int(x) for x in input().split()]
g = [0 for _ in range(n+1)]
for _ in range(m):
u, v, x = [int(x) for x in input().split()]
g[u] -= x
g[v] += x
print(sum([x for x in g if x > 0]))
| Title: I.O.U.
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that there is a group of three friends: A, B and С. A owes B 20 rubles and B owes C 20 rubles. The total sum of the debts is 40 rubles. You can see that the debts are not organized in a very optimal manner. Let's rearran... | ```python
n, m = [int(x) for x in input().split()]
g = [0 for _ in range(n+1)]
for _ in range(m):
u, v, x = [int(x) for x in input().split()]
g[u] -= x
g[v] += x
print(sum([x for x in g if x > 0]))
``` | 3 | |
139 | A | Petr and Book | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. S... | The first input line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of pages in the book.
The second line contains seven non-negative space-separated integers that do not exceed 1000 — those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and... | Print a single number — the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. | [
"100\n15 20 20 15 10 30 45\n",
"2\n1 0 0 0 0 0 0\n"
] | [
"6\n",
"1\n"
] | Note to the first sample:
By the end of Monday and therefore, by the beginning of Tuesday Petr has 85 pages left. He has 65 pages left by Wednesday, 45 by Thursday, 30 by Friday, 20 by Saturday and on Saturday Petr finishes reading the book (and he also has time to read 10 pages of something else).
Note to the second... | 500 | [
{
"input": "100\n15 20 20 15 10 30 45",
"output": "6"
},
{
"input": "2\n1 0 0 0 0 0 0",
"output": "1"
},
{
"input": "100\n100 200 100 200 300 400 500",
"output": "1"
},
{
"input": "3\n1 1 1 1 1 1 1",
"output": "3"
},
{
"input": "1\n1 1 1 1 1 1 1",
"output": "1... | 1,698,159,358 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | pages = int(input())
day1, day2, day3, day4, day5, day6, day7 = (input().split())
my_list = [day1, day2, day3, day4, day5, day6, day7]
int_list = [int(item) for item in my_list]
finished_pages = 0
while finished_pages < pages:
for i in int_list:
finished_pages += i
if finished_pages >= pages:
... | Title: Petr and Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight s... | ```python
pages = int(input())
day1, day2, day3, day4, day5, day6, day7 = (input().split())
my_list = [day1, day2, day3, day4, day5, day6, day7]
int_list = [int(item) for item in my_list]
finished_pages = 0
while finished_pages < pages:
for i in int_list:
finished_pages += i
if finished_pages >= p... | 0 | |
507 | B | Amr and Pins | PROGRAMMING | 1,400 | [
"geometry",
"math"
] | null | null | Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin b... | Input consists of 5 space-separated integers *r*, *x*, *y*, *x*' *y*' (1<=≤<=*r*<=≤<=105, <=-<=105<=≤<=*x*,<=*y*,<=*x*',<=*y*'<=≤<=105), circle radius, coordinates of original center of the circle and coordinates of destination center of the circle respectively. | Output a single integer — minimum number of steps required to move the center of the circle to the destination point. | [
"2 0 0 0 4\n",
"1 1 1 4 4\n",
"4 5 6 5 6\n"
] | [
"1\n",
"3\n",
"0\n"
] | In the first sample test the optimal way is to put a pin at point (0, 2) and rotate the circle by 180 degrees counter-clockwise (or clockwise, no matter).
<img class="tex-graphics" src="https://espresso.codeforces.com/4e40fd4cc24a2050a0488aa131e6244369328039.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "2 0 0 0 4",
"output": "1"
},
{
"input": "1 1 1 4 4",
"output": "3"
},
{
"input": "4 5 6 5 6",
"output": "0"
},
{
"input": "10 20 0 40 0",
"output": "1"
},
{
"input": "9 20 0 40 0",
"output": "2"
},
{
"input": "5 -1 -6 -5 1",
"output": "... | 1,694,854,157 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | l=list(map(int,input().split()))
r=l[0]
x=l[1]
y=l[2]
x1=l[3]
y1=l[4]
if x==x1 and y==y1:
print(0)
else:
s=0
dist=(((x-x1)**2)+((y-y1)**2))**0.5
if dist>2*r:
print(int((dist//(2*r))+1))
if dist<2*r:
print(2)
if dist==2*r:
print(1)
... | Title: Amr and Pins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can ... | ```python
l=list(map(int,input().split()))
r=l[0]
x=l[1]
y=l[2]
x1=l[3]
y1=l[4]
if x==x1 and y==y1:
print(0)
else:
s=0
dist=(((x-x1)**2)+((y-y1)**2))**0.5
if dist>2*r:
print(int((dist//(2*r))+1))
if dist<2*r:
print(2)
if dist==2*r:
print(1)
... | 0 | |
961 | B | Lecture Sleep | PROGRAMMING | 1,200 | [
"data structures",
"dp",
"implementation",
"two pointers"
] | null | null | Your friend Mishka and you attend a calculus lecture. Lecture lasts *n* minutes. Lecturer tells *a**i* theorems during the *i*-th minute.
Mishka is really interested in calculus, though it is so hard to stay awake for all the time of lecture. You are given an array *t* of Mishka's behavior. If Mishka is asleep during ... | The first line of the input contains two integer numbers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105) — the duration of the lecture in minutes and the number of minutes you can keep Mishka awake.
The second line of the input contains *n* integer numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=104) — the number of theore... | Print only one integer — the maximum number of theorems Mishka will be able to write down if you use your technique only once to wake him up. | [
"6 3\n1 3 5 2 5 4\n1 1 0 1 0 0\n"
] | [
"16\n"
] | In the sample case the better way is to use the secret technique at the beginning of the third minute. Then the number of theorems Mishka will be able to write down will be equal to 16. | 0 | [
{
"input": "6 3\n1 3 5 2 5 4\n1 1 0 1 0 0",
"output": "16"
},
{
"input": "5 3\n1 9999 10000 10000 10000\n0 0 0 0 0",
"output": "30000"
},
{
"input": "3 3\n10 10 10\n1 1 0",
"output": "30"
},
{
"input": "1 1\n423\n0",
"output": "423"
},
{
"input": "6 6\n1 3 5 2 5 4... | 1,674,943,373 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 156 | 7,372,800 | k,n = map(int,input().split())
lst = list(map(int,input().split()))
lstt = list(map(int,input().split()))
mx,ans = -1,0
for i in range(k):
if lstt[i] == 1:
ans+=lst[i]
lst[i] = 0
s = sum(lst[:n])
mx = s
for i in range(k-n):
s-=lst[i]
s+=lst[i+n]
mx = max(mx,s)
print(mx+ans) | Title: Lecture Sleep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend Mishka and you attend a calculus lecture. Lecture lasts *n* minutes. Lecturer tells *a**i* theorems during the *i*-th minute.
Mishka is really interested in calculus, though it is so hard to stay awake for al... | ```python
k,n = map(int,input().split())
lst = list(map(int,input().split()))
lstt = list(map(int,input().split()))
mx,ans = -1,0
for i in range(k):
if lstt[i] == 1:
ans+=lst[i]
lst[i] = 0
s = sum(lst[:n])
mx = s
for i in range(k-n):
s-=lst[i]
s+=lst[i+n]
mx = max(mx,s)
print(mx+ans)
``... | 3 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the... | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,690,288,579 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n,m,a = input().split()
n = int (n)
m = int (m)
a = int (a)
num1 = int(n+a-1)/a)
num2 = int(m+a-1)/a)
print (num1*num2)
| Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each ... | ```python
n,m,a = input().split()
n = int (n)
m = int (m)
a = int (a)
num1 = int(n+a-1)/a)
num2 = int(m+a-1)/a)
print (num1*num2)
``` | -1 |
733 | A | Grasshopper And the String | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far end of the string, jumping only on vowels of the English alphabet. Jump ability is the maximum possible length of ... | The first line contains non-empty string consisting of capital English letters. It is guaranteed that the length of the string does not exceed 100. | Print single integer *a* — the minimum jump ability of the Grasshopper (in the number of symbols) that is needed to overcome the given string, jumping only on vowels. | [
"ABABBBACFEYUKOTT\n",
"AAA\n"
] | [
"4",
"1"
] | none | 500 | [
{
"input": "ABABBBACFEYUKOTT",
"output": "4"
},
{
"input": "AAA",
"output": "1"
},
{
"input": "A",
"output": "1"
},
{
"input": "B",
"output": "2"
},
{
"input": "AEYUIOAEIYAEOUIYOEIUYEAOIUEOEAYOEIUYAEOUIYEOIKLMJNHGTRWSDZXCVBNMHGFDSXVWRTPPPLKMNBXIUOIUOIUOIUOOIU",
... | 1,601,753,542 | 2,147,483,647 | Python 3 | OK | TESTS | 70 | 109 | 0 | text = input()
alphabet = 'AEIOUY'
maxLength = 0
lenght = 0
for i in text:
if i not in alphabet:
lenght += 1
else:
lenght += 1
if lenght > maxLength:
maxLength = lenght
lenght = 0
lenght += 1
if lenght > maxLength:
maxLength = lenght
lenght = 0
... | Title: Grasshopper And the String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far en... | ```python
text = input()
alphabet = 'AEIOUY'
maxLength = 0
lenght = 0
for i in text:
if i not in alphabet:
lenght += 1
else:
lenght += 1
if lenght > maxLength:
maxLength = lenght
lenght = 0
lenght += 1
if lenght > maxLength:
maxLength = lenght
l... | 3 | |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,660,395,872 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 46 | 0 | c = 97
total = 0
for i in map(ord, input()):
val = abs(c - i)
total += min(val, 26 - val)
c = i
print(total)
| Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
c = 97
total = 0
for i in map(ord, input()):
val = abs(c - i)
total += min(val, 26 - val)
c = i
print(total)
``` | 3 | |
20 | C | Dijkstra? | PROGRAMMING | 1,900 | [
"graphs",
"shortest paths"
] | C. Dijkstra? | 1 | 64 | You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*. | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105), where *n* is the number of vertices and *m* is the number of edges. Following *m* lines contain one edge each in form *a**i*, *b**i* and *w**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=1<=≤<=*w**i*<=≤<=106), where *a**i*,<=*b**i* are edge... | Write the only integer -1 in case of no path. Write the shortest path in opposite case. If there are many solutions, print any of them. | [
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n",
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n"
] | [
"1 4 3 5 ",
"1 4 3 5 "
] | none | 1,500 | [
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "2 1\n1 2 1",
"output": "1 2 "
},
{
"input": "3 1\n1 2 1",
"output": "-1"
},
{
"input... | 1,648,915,893 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | def pop_frontier(frontier):
if len(frontier) == 0:
return None
min = 64
values = []
for key, path in frontier:
if key == min:
values.append(path)
elif key < min:
min = key
values.clear()
values.append(path)
values.sort()
re... | Title: Dijkstra?
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*.
Input Specification:
The first line contains two integers *n* a... | ```python
def pop_frontier(frontier):
if len(frontier) == 0:
return None
min = 64
values = []
for key, path in frontier:
if key == min:
values.append(path)
elif key < min:
min = key
values.clear()
values.append(path)
values.sor... | 0 |
333 | B | Chips | PROGRAMMING | 1,800 | [
"greedy"
] | null | null | Gerald plays the following game. He has a checkered field of size *n*<=×<=*n* cells, where *m* various cells are banned. Before the game, he has to put a few chips on some border (but not corner) board cells. Then for *n*<=-<=1 minutes, Gerald every minute moves each chip into an adjacent cell. He moves each chip from ... | The first line contains two space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=1000, 0<=≤<=*m*<=≤<=105) — the size of the field and the number of banned cells. Next *m* lines each contain two space-separated integers. Specifically, the *i*-th of these lines contains numbers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<... | Print a single integer — the maximum points Gerald can earn in this game. | [
"3 1\n2 2\n",
"3 0\n",
"4 3\n3 1\n3 2\n3 3\n"
] | [
"0\n",
"1\n",
"1\n"
] | In the first test the answer equals zero as we can't put chips into the corner cells.
In the second sample we can place one chip into either cell (1, 2), or cell (3, 2), or cell (2, 1), or cell (2, 3). We cannot place two chips.
In the third sample we can only place one chip into either cell (2, 1), or cell (2, 4). | 1,000 | [
{
"input": "3 1\n2 2",
"output": "0"
},
{
"input": "3 0",
"output": "1"
},
{
"input": "4 3\n3 1\n3 2\n3 3",
"output": "1"
},
{
"input": "2 1\n1 1",
"output": "0"
},
{
"input": "2 3\n1 2\n2 1\n2 2",
"output": "0"
},
{
"input": "5 1\n3 2",
"output": ... | 1,374,956,292 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 0 | import sys
n,m=map(int,input().split())
Rowsr=[True]*(n)
Rowsr[0]=False
Rowsr[-1]=False
Rowsl=[True]*n
Rowsl[0]=False
Rowsl[-1]=False
Colu=[True]*(n)
Colu[0]=False
Colu[-1]=False
Cold=[True]*(n)
Cold[0]=False
Cold[-1]=False
for i in range(m):
a,b=map(int,sys.stdin.readline().split())
Rowsr[a-1]=False
Colu[... | Title: Chips
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald plays the following game. He has a checkered field of size *n*<=×<=*n* cells, where *m* various cells are banned. Before the game, he has to put a few chips on some border (but not corner) board cells. Then for *n*<=-<=1 m... | ```python
import sys
n,m=map(int,input().split())
Rowsr=[True]*(n)
Rowsr[0]=False
Rowsr[-1]=False
Rowsl=[True]*n
Rowsl[0]=False
Rowsl[-1]=False
Colu=[True]*(n)
Colu[0]=False
Colu[-1]=False
Cold=[True]*(n)
Cold[0]=False
Cold[-1]=False
for i in range(m):
a,b=map(int,sys.stdin.readline().split())
Rowsr[a-1]=False... | -1 | |
507 | A | Amr and Music | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"sortings"
] | null | null | Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr dedicated *k* days to learn how to play the maximum possible number of instruments.
Amr asked for ... | The first line contains two numbers *n*, *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=10<=000), the number of instruments and number of days respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100), representing number of days required to learn the *i*-th instrument. | In the first line output one integer *m* representing the maximum number of instruments Amr can learn.
In the second line output *m* space-separated integers: the indices of instruments to be learnt. You may output indices in any order.
if there are multiple optimal solutions output any. It is not necessary to use al... | [
"4 10\n4 3 1 2\n",
"5 6\n4 3 1 1 2\n",
"1 3\n4\n"
] | [
"4\n1 2 3 4",
"3\n1 3 4",
"0\n"
] | In the first test Amr can learn all 4 instruments.
In the second test other possible solutions are: {2, 3, 5} or {3, 4, 5}.
In the third test Amr doesn't have enough time to learn the only presented instrument. | 500 | [
{
"input": "4 10\n4 3 1 2",
"output": "4\n1 2 3 4"
},
{
"input": "5 6\n4 3 1 1 2",
"output": "3\n3 4 5"
},
{
"input": "1 3\n4",
"output": "0"
},
{
"input": "2 100\n100 100",
"output": "1\n1"
},
{
"input": "3 150\n50 50 50",
"output": "3\n1 2 3"
},
{
"i... | 1,567,884,887 | 2,147,483,647 | PyPy 3 | OK | TESTS | 39 | 139 | 102,400 | nk=input().split()
n=int(nk[0])
k=int(nk[1])
a=list(map(int,input().split()))
a1=sorted(a)
i=0
l=[]
while k>0:
if a1[i]<=k:
l.append(a1[i])
k-=a1[i]
i+=1
if i>=len(a1):
break
else:
break
if len(l)==0:
print(0)
else:
print(len(l))
... | Title: Amr and Music
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr ... | ```python
nk=input().split()
n=int(nk[0])
k=int(nk[1])
a=list(map(int,input().split()))
a1=sorted(a)
i=0
l=[]
while k>0:
if a1[i]<=k:
l.append(a1[i])
k-=a1[i]
i+=1
if i>=len(a1):
break
else:
break
if len(l)==0:
print(0)
else:
print(l... | 3 | |
22 | B | Bargaining Table | PROGRAMMING | 1,500 | [
"brute force",
"dp"
] | B. Bargaining Table | 2 | 256 | Bob wants to put a new bargaining table in his office. To do so he measured the office room thoroughly and drew its plan: Bob's office room is a rectangular room *n*<=×<=*m* meters. Each square meter of the room is either occupied by some furniture, or free. A bargaining table is rectangular, and should be placed so, t... | The first line contains 2 space-separated numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=25) — the office room dimensions. Then there follow *n* lines with *m* characters 0 or 1 each. 0 stands for a free square meter of the office room. 1 stands for an occupied square meter. It's guaranteed that at least one square meter in ... | Output one number — the maximum possible perimeter of a bargaining table for Bob's office room. | [
"3 3\n000\n010\n000\n",
"5 4\n1100\n0000\n0000\n0000\n0000\n"
] | [
"8\n",
"16\n"
] | none | 0 | [
{
"input": "3 3\n000\n010\n000",
"output": "8"
},
{
"input": "5 4\n1100\n0000\n0000\n0000\n0000",
"output": "16"
},
{
"input": "3 3\n000\n110\n000",
"output": "8"
},
{
"input": "4 2\n00\n10\n11\n00",
"output": "6"
},
{
"input": "3 5\n00001\n00000\n10100",
"out... | 1,583,935,194 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 6 | 186 | 307,200 | rows = int(input().split(" ")[0])
table = []
for i in range(0,rows):
table.append(list(input()))
D = y = [[[[None for i in range(5)] for i in range(5)] for i in range(5)] for i in range(5)]
maxper = 0
indicator = False
def biggestPerimeter(table):
global maxper
for x1 in range(0,len(table)):
for y1 in range(0,len... | Title: Bargaining Table
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob wants to put a new bargaining table in his office. To do so he measured the office room thoroughly and drew its plan: Bob's office room is a rectangular room *n*<=×<=*m* meters. Each square meter of the room is either ... | ```python
rows = int(input().split(" ")[0])
table = []
for i in range(0,rows):
table.append(list(input()))
D = y = [[[[None for i in range(5)] for i in range(5)] for i in range(5)] for i in range(5)]
maxper = 0
indicator = False
def biggestPerimeter(table):
global maxper
for x1 in range(0,len(table)):
for y1 in r... | -1 |
114 | A | Cifera | PROGRAMMING | 1,000 | [
"math"
] | null | null | When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousand and "tma tmyschaya" (which literally means "the tma of tmas") used to stand for a million... | The first input line contains integer number *k*, the second line contains integer number *l* (2<=≤<=*k*,<=*l*<=≤<=231<=-<=1). | You should print in the first line of the output "YES", if the number belongs to the set petriciumus cifera and otherwise print "NO". If the number belongs to the set, then print on the seconds line the only number — the importance of number *l*. | [
"5\n25\n",
"3\n8\n"
] | [
"YES\n1\n",
"NO\n"
] | none | 500 | [
{
"input": "5\n25",
"output": "YES\n1"
},
{
"input": "3\n8",
"output": "NO"
},
{
"input": "123\n123",
"output": "YES\n0"
},
{
"input": "99\n970300",
"output": "NO"
},
{
"input": "1000\n6666666",
"output": "NO"
},
{
"input": "59\n3571",
"output": "N... | 1,620,720,830 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 124 | 6,758,400 | n=int(input())
l=int(input())
z=n
cnt=0
while z<l:
z=z*n
cnt+=1
if z==l:
print("YES")
print(cnt)
else:
print("NO") | Title: Cifera
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousa... | ```python
n=int(input())
l=int(input())
z=n
cnt=0
while z<l:
z=z*n
cnt+=1
if z==l:
print("YES")
print(cnt)
else:
print("NO")
``` | 3 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,574,442,616 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 248 | 0 | s = input()
small = 0
big = 0
for i in s:
if i >= 'a' and i <= 'z':
small += 1
elif 'A' <= i <= 'Z':
big += 1
if small >= big:
print(s.lower())
elif big >= small:
print(s.upper())
elif small == big:
print(s.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s = input()
small = 0
big = 0
for i in s:
if i >= 'a' and i <= 'z':
small += 1
elif 'A' <= i <= 'Z':
big += 1
if small >= big:
print(s.lower())
elif big >= small:
print(s.upper())
elif small == big:
print(s.lower())
``` | 3.938 |
222 | A | Shooshuns and Sequence | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the current sequence and add the same number to the end of the sequence; 1. Delete the first number of the current ... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105).
The second line contains *n* space-separated integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the sequence that the shooshuns found. | Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1. | [
"3 2\n3 1 1\n",
"3 1\n3 1 1\n"
] | [
"1\n",
"-1\n"
] | In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one.
In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1.... | 500 | [
{
"input": "3 2\n3 1 1",
"output": "1"
},
{
"input": "3 1\n3 1 1",
"output": "-1"
},
{
"input": "1 1\n1",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "0"
},
{
"input": "2 1\n2 1",
"output": "-1"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
}... | 1,659,947,047 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 124 | 5,939,200 | n,k=map(int,input().split())
a=input().split()
z=-1
for i in range(n-1,-1,-1):
if a[i]!=a[-1]:
z=i
break
if k>z+1:
print(z+1)
else:
print(-1)
| Title: Shooshuns and Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the cur... | ```python
n,k=map(int,input().split())
a=input().split()
z=-1
for i in range(n-1,-1,-1):
if a[i]!=a[-1]:
z=i
break
if k>z+1:
print(z+1)
else:
print(-1)
``` | 3 | |
550 | A | Two Substrings | PROGRAMMING | 1,500 | [
"brute force",
"dp",
"greedy",
"implementation",
"strings"
] | null | null | You are given string *s*. Your task is to determine if the given string *s* contains two non-overlapping substrings "AB" and "BA" (the substrings can go in any order). | The only line of input contains a string *s* of length between 1 and 105 consisting of uppercase Latin letters. | Print "YES" (without the quotes), if string *s* contains two non-overlapping substrings "AB" and "BA", and "NO" otherwise. | [
"ABA\n",
"BACFAB\n",
"AXBYBXA\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | In the first sample test, despite the fact that there are substrings "AB" and "BA", their occurrences overlap, so the answer is "NO".
In the second sample test there are the following occurrences of the substrings: BACFAB.
In the third sample test there is no substring "AB" nor substring "BA". | 1,000 | [
{
"input": "ABA",
"output": "NO"
},
{
"input": "BACFAB",
"output": "YES"
},
{
"input": "AXBYBXA",
"output": "NO"
},
{
"input": "ABABAB",
"output": "YES"
},
{
"input": "BBBBBBBBBB",
"output": "NO"
},
{
"input": "ABBA",
"output": "YES"
},
{
"... | 1,692,028,211 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | # Wadea #
s = list(input())
r = 0
for i in range(len(s)-1):
if s[i] == "A" and s[i] == "B":
r += 1
s[i] = ""
s[i+1] = ""
for i in range(len(s)-1):
if s[i] == "B" and s[i] == "A":
r += 1
s[i] = ""
s[i+1] = ""
if r == 2:
print("YES")
else:
... | Title: Two Substrings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given string *s*. Your task is to determine if the given string *s* contains two non-overlapping substrings "AB" and "BA" (the substrings can go in any order).
Input Specification:
The only line of input contain... | ```python
# Wadea #
s = list(input())
r = 0
for i in range(len(s)-1):
if s[i] == "A" and s[i] == "B":
r += 1
s[i] = ""
s[i+1] = ""
for i in range(len(s)-1):
if s[i] == "B" and s[i] == "A":
r += 1
s[i] = ""
s[i+1] = ""
if r == 2:
print("YES")
e... | 0 | |
631 | D | Messenger | PROGRAMMING | 2,100 | [
"data structures",
"hashing",
"implementation",
"string suffix structures",
"strings"
] | null | null | Each employee of the "Blake Techologies" company uses a special messaging app "Blake Messenger". All the stuff likes this app and uses it constantly. However, some important futures are missing. For example, many users want to be able to search through the message history. It was already announced that the new feature ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — the number of blocks in the strings *t* and *s*, respectively.
The second line contains the descriptions of *n* parts of string *t* in the format "*l**i*-*c**i*" (1<=≤<=*l**i*<=≤<=1<=000<=000) — the length of the *i*-th part... | Print a single integer — the number of occurrences of *s* in *t*. | [
"5 3\n3-a 2-b 4-c 3-a 2-c\n2-a 2-b 1-c\n",
"6 1\n3-a 6-b 7-a 4-c 8-e 2-a\n3-a\n",
"5 5\n1-h 1-e 1-l 1-l 1-o\n1-w 1-o 1-r 1-l 1-d\n"
] | [
"1",
"6",
"0"
] | In the first sample, *t* = "aaabbccccaaacc", and string *s* = "aabbc". The only occurrence of string *s* in string *t* starts at position *p* = 2.
In the second sample, *t* = "aaabbbbbbaaaaaaacccceeeeeeeeaa", and *s* = "aaa". The occurrences of *s* in *t* start at positions *p* = 1, *p* = 10, *p* = 11, *p* = 12, *p* =... | 2,000 | [
{
"input": "5 3\n3-a 2-b 4-c 3-a 2-c\n2-a 2-b 1-c",
"output": "1"
},
{
"input": "6 1\n3-a 6-b 7-a 4-c 8-e 2-a\n3-a",
"output": "6"
},
{
"input": "5 5\n1-h 1-e 1-l 1-l 1-o\n1-w 1-o 1-r 1-l 1-d",
"output": "0"
},
{
"input": "9 3\n1-h 1-e 2-l 1-o 1-w 1-o 1-r 1-l 1-d\n2-l 1-o 1-w... | 1,458,083,198 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 62 | 204,800 | def main():
input().split()
ts = []
for _ in 0, 1:
tmp = input().split()
a, x, l = tmp[0][-1], 0, []
for st in tmp:
y = int(st[:-2])
b = st[-1]
if a != b:
l.append(((x, a)))
x, a = y, b
else:
... | Title: Messenger
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Each employee of the "Blake Techologies" company uses a special messaging app "Blake Messenger". All the stuff likes this app and uses it constantly. However, some important futures are missing. For example, many users want t... | ```python
def main():
input().split()
ts = []
for _ in 0, 1:
tmp = input().split()
a, x, l = tmp[0][-1], 0, []
for st in tmp:
y = int(st[:-2])
b = st[-1]
if a != b:
l.append(((x, a)))
x, a = y, b
else:
... | 0 | |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,663,301,439 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | s = int(input())
lst = list(map(int, input().split()))
lst.sort()
for i in range(1, s):
if lst[i] > lst[0]:
print(lst[i])
break
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statis... | ```python
s = int(input())
lst = list(map(int, input().split()))
lst.sort()
for i in range(1, s):
if lst[i] > lst[0]:
print(lst[i])
break
``` | 0 |
993 | A | Two Squares | PROGRAMMING | 1,600 | [
"geometry",
"implementation"
] | null | null | You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered to be part of the square, i.e. if one square is completely inside another, they intersect. If the ... | The input data consists of two lines, one for each square, both containing 4 pairs of integers. Each pair represents coordinates of one vertex of the square. Coordinates within each line are either in clockwise or counterclockwise order.
The first line contains the coordinates of the square with sides parallel to the ... | Print "Yes" if squares intersect, otherwise print "No".
You can print each letter in any case (upper or lower). | [
"0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1\n",
"0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1\n",
"6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the second square lies entirely within the first square, so they do intersect.
In the second sample squares do not have any points in common.
Here are images corresponding to the samples: | 500 | [
{
"input": "0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1",
"output": "NO"
},
{
"input": "6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n8 4 4 8 8 12 12 8",
"output": "YES"
},
... | 1,643,174,234 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 108 | 2,662,400 | import math
import sys
import queue
from heapq import heappop, heappush
def solve():
def rotate(x, y):
for i in range(4):
x[i], y[i] = x[i] + y[i], x[i] - y[i]
return x, y
def read(p1, p2):
xp = [p1[i] for i in range(0, 8, 2)]
yp = [p1[i] for i in ran... | Title: Two Squares
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered t... | ```python
import math
import sys
import queue
from heapq import heappop, heappush
def solve():
def rotate(x, y):
for i in range(4):
x[i], y[i] = x[i] + y[i], x[i] - y[i]
return x, y
def read(p1, p2):
xp = [p1[i] for i in range(0, 8, 2)]
yp = [p1[i] fo... | 0 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,691,753,605 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | import math
m, n = input().split()
m = int(m)
n = int(n)
print(math.floor((m*n)/2))
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
import math
m, n = input().split()
m = int(m)
n = int(n)
print(math.floor((m*n)/2))
``` | 3.977 |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,694,854,576 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | a, b = map(int, input().split())
min_days = min(a, b)
max_days = max((a - min_days) / 2, (b - min_days) / 2)
print(min_days, max_days) | Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
a, b = map(int, input().split())
min_days = min(a, b)
max_days = max((a - min_days) / 2, (b - min_days) / 2)
print(min_days, max_days)
``` | 0 | |
379 | A | New Year Candles | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used ... | The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000). | Print a single integer — the number of hours Vasily can light up the room for. | [
"4 2\n",
"6 3\n"
] | [
"7\n",
"8\n"
] | Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours. | 500 | [
{
"input": "4 2",
"output": "7"
},
{
"input": "6 3",
"output": "8"
},
{
"input": "1000 1000",
"output": "1001"
},
{
"input": "123 5",
"output": "153"
},
{
"input": "1000 2",
"output": "1999"
},
{
"input": "1 2",
"output": "1"
},
{
"input": ... | 1,674,463,020 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 61 | 0 | nm = [int(i) for i in input().split()]
n, m = nm[0], nm[1]
hours = n
while n != 0:
n //= m
hours += n
print(hours)
| Title: New Year Candles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is s... | ```python
nm = [int(i) for i in input().split()]
n, m = nm[0], nm[1]
hours = n
while n != 0:
n //= m
hours += n
print(hours)
``` | 0 | |
702 | D | Road to Post Office | PROGRAMMING | 1,900 | [
"math"
] | null | null | Vasiliy has a car and he wants to get from home to the post office. The distance which he needs to pass equals to *d* kilometers.
Vasiliy's car is not new — it breaks after driven every *k* kilometers and Vasiliy needs *t* seconds to repair it. After repairing his car Vasiliy can drive again (but after *k* kilometers ... | The first line contains 5 positive integers *d*,<=*k*,<=*a*,<=*b*,<=*t* (1<=≤<=*d*<=≤<=1012; 1<=≤<=*k*,<=*a*,<=*b*,<=*t*<=≤<=106; *a*<=<<=*b*), where:
- *d* — the distance from home to the post office; - *k* — the distance, which car is able to drive before breaking; - *a* — the time, which Vasiliy spends to dri... | Print the minimal time after which Vasiliy will be able to reach the post office. | [
"5 2 1 4 10\n",
"5 2 1 4 5\n"
] | [
"14\n",
"13\n"
] | In the first example Vasiliy needs to drive the first 2 kilometers on the car (in 2 seconds) and then to walk on foot 3 kilometers (in 12 seconds). So the answer equals to 14 seconds.
In the second example Vasiliy needs to drive the first 2 kilometers on the car (in 2 seconds), then repair his car (in 5 seconds) and d... | 0 | [
{
"input": "5 2 1 4 10",
"output": "14"
},
{
"input": "5 2 1 4 5",
"output": "13"
},
{
"input": "1 1 1 2 1",
"output": "1"
},
{
"input": "1000000000000 1000000 999999 1000000 1000000",
"output": "999999999999000000"
},
{
"input": "997167959139 199252 232602 952690... | 1,666,243,277 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 129 | 77 | 0 | d,k,a,b,t=map(int,input().split())
def calc(mid):
x=min(d,k+mid*k)
return x*a+(d-x)*b+t*mid
# k+n*k<=d
# n<=(d-k)//k
L,R=-1,(d-k)//k+1
while L+2<R:
c1=L+(R-L)//3
c2=R-(R-L)//3
if calc(c1)<calc(c2):
R=c2
else:
L=c1
ans=9*10**18
for i in range(max(0,L),min(R,d)+1):
ans=min(ans,... | Title: Road to Post Office
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy has a car and he wants to get from home to the post office. The distance which he needs to pass equals to *d* kilometers.
Vasiliy's car is not new — it breaks after driven every *k* kilometers and Vasiliy n... | ```python
d,k,a,b,t=map(int,input().split())
def calc(mid):
x=min(d,k+mid*k)
return x*a+(d-x)*b+t*mid
# k+n*k<=d
# n<=(d-k)//k
L,R=-1,(d-k)//k+1
while L+2<R:
c1=L+(R-L)//3
c2=R-(R-L)//3
if calc(c1)<calc(c2):
R=c2
else:
L=c1
ans=9*10**18
for i in range(max(0,L),min(R,d)+1):
an... | 3 | |
916 | A | Jamie and Alarm Snooze | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Jamie loves sleeping. One day, he decides that he needs to wake up at exactly *hh*:<=*mm*. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will then press the snooze button every *x* minutes until *hh*:<=*mm* is reached, and only then he will wake up. He ... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=60).
The second line contains two two-digit integers, *hh* and *mm* (00<=≤<=*hh*<=≤<=23,<=00<=≤<=*mm*<=≤<=59). | Print the minimum number of times he needs to press the button. | [
"3\n11 23\n",
"5\n01 07\n"
] | [
"2\n",
"0\n"
] | In the first sample, Jamie needs to wake up at 11:23. So, he can set his alarm at 11:17. He would press the snooze button when the alarm rings at 11:17 and at 11:20.
In the second sample, Jamie can set his alarm at exactly at 01:07 which is lucky. | 500 | [
{
"input": "3\n11 23",
"output": "2"
},
{
"input": "5\n01 07",
"output": "0"
},
{
"input": "34\n09 24",
"output": "3"
},
{
"input": "2\n14 37",
"output": "0"
},
{
"input": "14\n19 54",
"output": "9"
},
{
"input": "42\n15 44",
"output": "12"
},
... | 1,516,373,603 | 1,103 | Python 3 | CHALLENGED | CHALLENGES | 6 | 46 | 5,632,000 | def contain_7(x):
return ( ((x % 10) == 7) or ((x / 10) == 7) )
x = int(input())
hh,mm = map(int , input().split())
cur = hh*60 + mm
ans = 1e9
for i in range(3600):
if( (contain_7(i // 60) == False) and (contain_7(i % 60) == False)):
continue
duration = cur - i
if(duration < 0):
... | Title: Jamie and Alarm Snooze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jamie loves sleeping. One day, he decides that he needs to wake up at exactly *hh*:<=*mm*. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will the... | ```python
def contain_7(x):
return ( ((x % 10) == 7) or ((x / 10) == 7) )
x = int(input())
hh,mm = map(int , input().split())
cur = hh*60 + mm
ans = 1e9
for i in range(3600):
if( (contain_7(i // 60) == False) and (contain_7(i % 60) == False)):
continue
duration = cur - i
if(duratio... | -1 | |
450 | A | Jzzhu and Children | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies.
Jzzhu asks children to line up. Initially, the *i*-th child stands at the *i*-th place of the line. Then Jzzhu start distribution of... | The first line contains two integers *n*,<=*m* (1<=≤<=*n*<=≤<=100; 1<=≤<=*m*<=≤<=100). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100). | Output a single integer, representing the number of the last child. | [
"5 2\n1 3 1 4 2\n",
"6 4\n1 1 2 2 3 3\n"
] | [
"4\n",
"6\n"
] | Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the en... | 500 | [
{
"input": "5 2\n1 3 1 4 2",
"output": "4"
},
{
"input": "6 4\n1 1 2 2 3 3",
"output": "6"
},
{
"input": "7 3\n6 1 5 4 2 3 1",
"output": "4"
},
{
"input": "10 5\n2 7 3 6 2 5 1 3 4 5",
"output": "4"
},
{
"input": "100 1\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18... | 1,654,732,735 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 15 | 0 | n, m = [int(i) for i in input().split()]
a = [int(i) for i in input().split()]
c = []
for i in range(n):
c.append(i+1)
while len(a) > 1:
b = a.pop(0)
d = c.pop(0)
if b - m >= 0:
a.append(b - m)
c.append(d)
print(c[0]) | Title: Jzzhu and Children
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies.
Jzzhu asks children to line ... | ```python
n, m = [int(i) for i in input().split()]
a = [int(i) for i in input().split()]
c = []
for i in range(n):
c.append(i+1)
while len(a) > 1:
b = a.pop(0)
d = c.pop(0)
if b - m >= 0:
a.append(b - m)
c.append(d)
print(c[0])
``` | 0 | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,653,470,052 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | s1=input()
s2=input()
s3=s1[::-1]
if(s2==s3):
print("YES")
else:
print("NO")
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
s1=input()
s2=input()
s3=s1[::-1]
if(s2==s3):
print("YES")
else:
print("NO")
``` | 3.977 |
985 | E | Pencils and Boxes | PROGRAMMING | 2,100 | [
"binary search",
"data structures",
"dp",
"greedy",
"two pointers"
] | null | null | Mishka received a gift of multicolored pencils for his birthday! Unfortunately he lives in a monochrome world, where everything is of the same color and only saturation differs. This pack can be represented as a sequence *a*1,<=*a*2,<=...,<=*a**n* of *n* integer numbers — saturation of the color of each pencil. Now Mis... | The first line contains three integer numbers *n*, *k* and *d* (1<=≤<=*k*<=≤<=*n*<=≤<=5·105, 0<=≤<=*d*<=≤<=109) — the number of pencils, minimal size of any non-empty box and maximal difference in saturation between any pair of pencils in the same box, respectively.
The second line contains *n* integer numbers *a*1,<=... | Print "YES" if it's possible to distribute all the pencils into boxes and satisfy all the conditions. Otherwise print "NO". | [
"6 3 10\n7 2 7 7 4 2\n",
"6 2 3\n4 5 3 13 4 10\n",
"3 2 5\n10 16 22\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first example it is possible to distribute pencils into 2 boxes with 3 pencils in each with any distribution. And you also can put all the pencils into the same box, difference of any pair in it won't exceed 10.
In the second example you can split pencils of saturations [4, 5, 3, 4] into 2 boxes of size 2 and p... | 0 | [
{
"input": "6 3 10\n7 2 7 7 4 2",
"output": "YES"
},
{
"input": "6 2 3\n4 5 3 13 4 10",
"output": "YES"
},
{
"input": "3 2 5\n10 16 22",
"output": "NO"
},
{
"input": "8 7 13\n52 85 14 52 92 33 80 85",
"output": "NO"
},
{
"input": "6 4 0\n1 3 2 4 2 1",
"output"... | 1,531,401,567 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 9 | 1,107 | 48,640,000 | #-*- coding:utf-8 -*-
str = input()
strvec = str.split(' ')
n = int(strvec[0])
k = int(strvec[1])
d = int(strvec[2])
str = input().split(' ')
intvec = list(map(int, str))
intvec.sort()
indexvec = [0]*n
forward = 0
backward = 1
while True:
if backward >= n:
break
if intvec[forward] + d... | Title: Pencils and Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka received a gift of multicolored pencils for his birthday! Unfortunately he lives in a monochrome world, where everything is of the same color and only saturation differs. This pack can be represented as a seque... | ```python
#-*- coding:utf-8 -*-
str = input()
strvec = str.split(' ')
n = int(strvec[0])
k = int(strvec[1])
d = int(strvec[2])
str = input().split(' ')
intvec = list(map(int, str))
intvec.sort()
indexvec = [0]*n
forward = 0
backward = 1
while True:
if backward >= n:
break
if intvec[fo... | -1 | |
136 | A | Presents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift.... | Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*. | [
"4\n2 3 4 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"4 1 2 3\n",
"1 3 2\n",
"1 2\n"
] | none | 500 | [
{
"input": "4\n2 3 4 1",
"output": "4 1 2 3"
},
{
"input": "3\n1 3 2",
"output": "1 3 2"
},
{
"input": "2\n1 2",
"output": "1 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 3 2 6 4 5 7 9 8 10",
"output": "1 3 2 5 6 4 7 9 8 10"
},
{
"input"... | 1,684,710,517 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 101 | 124 | 0 | n = int(input())
s = ""
p = list(map(int, input().split(' ')))
for i in range(n):
s += str(p.index(i + 1) + 1) + ' '
print(s)
| Title: Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on t... | ```python
n = int(input())
s = ""
p = list(map(int, input().split(' ')))
for i in range(n):
s += str(p.index(i + 1) + 1) + ' '
print(s)
``` | 3 | |
960 | A | Check the string | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gi... | The first and only line consists of a string $S$ ($ 1 \le |S| \le 5\,000 $). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'. | Print "YES" or "NO", according to the condition. | [
"aaabccc\n",
"bbacc\n",
"aabc\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'. | 500 | [
{
"input": "aaabccc",
"output": "YES"
},
{
"input": "bbacc",
"output": "NO"
},
{
"input": "aabc",
"output": "YES"
},
{
"input": "aabbcc",
"output": "YES"
},
{
"input": "aaacccbb",
"output": "NO"
},
{
"input": "abc",
"output": "YES"
},
{
"in... | 1,530,025,195 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 16 | 78 | 0 | s=input()
t=sorted(s)
t=''.join(t)
if t==s:
if t.count('c')==t.count('b') or t.count('a')==t.count('c'):
print ("YES")
else:
print ("NO")
else:
print ("NO") | Title: Check the string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b... | ```python
s=input()
t=sorted(s)
t=''.join(t)
if t==s:
if t.count('c')==t.count('b') or t.count('a')==t.count('c'):
print ("YES")
else:
print ("NO")
else:
print ("NO")
``` | 0 | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,659,357,257 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | text = input()
theans = input()
mylist = [x for x in text]
reverse = mylist[::-1]
ans = ''.join(reverse)
if ans == theans:
print('YES')
else:
print('NO') | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
text = input()
theans = input()
mylist = [x for x in text]
reverse = mylist[::-1]
ans = ''.join(reverse)
if ans == theans:
print('YES')
else:
print('NO')
``` | 3.977 |
897 | B | Chtholly's request | PROGRAMMING | 1,300 | [
"brute force"
] | null | null | — I experienced so many great things.
— You gave me memories like dreams... But I have to leave now...
— One last request, can you...
— Help me solve a Codeforces problem?
— ......
— What?
Chtholly has been thinking about a problem for days:
If a number is palindrome and length of its decimal representation with... | The first line contains two integers *k* and *p* (1<=≤<=*k*<=≤<=105,<=1<=≤<=*p*<=≤<=109). | Output single integer — answer to the problem. | [
"2 100\n",
"5 30\n"
] | [
"33\n",
"15\n"
] | In the first example, the smallest zcy number is 11, and the second smallest zcy number is 22.
In the second example, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/68fffad54395f7d920ad0384e07c6215ddc64141.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 1,000 | [
{
"input": "2 100",
"output": "33"
},
{
"input": "5 30",
"output": "15"
},
{
"input": "42147 412393322",
"output": "251637727"
},
{
"input": "77809 868097296",
"output": "440411873"
},
{
"input": "5105 443422097",
"output": "363192634"
},
{
"input": "7... | 1,512,671,477 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 77 | 5,529,600 | giris=input().split()
n=int(giris[0])
m=int(giris[1])
toplanacakSayi=0
toplam=0
for i in range(n):
if(i<9):
toplanacakSayi+=11
else:
toplanacakSayi+=110
if(i>0 and (i+1)%10==0):
toplanacakSayi=int((i+1)/10)*1001
toplam+=toplanacakSayi
continue
... | Title: Chtholly's request
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
— I experienced so many great things.
— You gave me memories like dreams... But I have to leave now...
— One last request, can you...
— Help me solve a Codeforces problem?
— ......
— What?
Chtholly has been thi... | ```python
giris=input().split()
n=int(giris[0])
m=int(giris[1])
toplanacakSayi=0
toplam=0
for i in range(n):
if(i<9):
toplanacakSayi+=11
else:
toplanacakSayi+=110
if(i>0 and (i+1)%10==0):
toplanacakSayi=int((i+1)/10)*1001
toplam+=toplanacakSayi
cont... | 0 | |
934 | B | A Prosperous Lot | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | Apart from Nian, there is a daemon named Sui, which terrifies children and causes them to become sick. Parents give their children money wrapped in red packets and put them under the pillow, so that when Sui tries to approach them, it will be driven away by the fairies inside.
Big Banban is hesitating over the amount ... | The first and only line contains an integer *k* (1<=≤<=*k*<=≤<=106) — the desired number of loops. | Output an integer — if no such *n* exists, output -1; otherwise output any such *n*. In the latter case, your output should be a positive decimal integer not exceeding 1018. | [
"2\n",
"6\n"
] | [
"462",
"8080"
] | none | 1,000 | [
{
"input": "2",
"output": "8"
},
{
"input": "6",
"output": "888"
},
{
"input": "3",
"output": "86"
},
{
"input": "4",
"output": "88"
},
{
"input": "5",
"output": "886"
},
{
"input": "1000000",
"output": "-1"
},
{
"input": "1",
"output":... | 1,518,614,947 | 5,047 | Python 3 | WRONG_ANSWER | CHALLENGES | 0 | 62 | 5,632,000 | n=int(input())
out=""
if n>38:
print(-1)
else:
for i in range(n//2):
out+="8"
for i in range(n%2):
out+="9"
if n==0:
out+="1"
print(out) | Title: A Prosperous Lot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Apart from Nian, there is a daemon named Sui, which terrifies children and causes them to become sick. Parents give their children money wrapped in red packets and put them under the pillow, so that when Sui tries to a... | ```python
n=int(input())
out=""
if n>38:
print(-1)
else:
for i in range(n//2):
out+="8"
for i in range(n%2):
out+="9"
if n==0:
out+="1"
print(out)
``` | 0 | |
440 | A | Forgotten Episode | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus adores TV series. Right now he is ready to finish watching a season of a popular sitcom "Graph Theory". In total, the season has *n* episodes, numbered with integers from 1 to *n*.
Polycarpus watches episodes not one by one but in a random order. He has already watched all the episodes except for one. Which... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100000) — the number of episodes in a season. Assume that the episodes are numbered by integers from 1 to *n*.
The second line contains *n*<=-<=1 integer *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the numbers of episodes that Polycarpus has watch... | Print the number of the episode that Polycarpus hasn't watched. | [
"10\n3 8 10 1 7 9 6 5 2\n"
] | [
"4\n"
] | none | 500 | [
{
"input": "10\n3 8 10 1 7 9 6 5 2",
"output": "4"
},
{
"input": "5\n4 3 2 1",
"output": "5"
},
{
"input": "2\n1",
"output": "2"
},
{
"input": "2\n2",
"output": "1"
},
{
"input": "3\n1 2",
"output": "3"
},
{
"input": "3\n1 3",
"output": "2"
},
... | 1,600,176,417 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 202 | 10,547,200 | n=int(input())
l=list(map(int,input().split()))
s=n*(n+1)//2
print(s-sum(l))
| Title: Forgotten Episode
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus adores TV series. Right now he is ready to finish watching a season of a popular sitcom "Graph Theory". In total, the season has *n* episodes, numbered with integers from 1 to *n*.
Polycarpus watches episo... | ```python
n=int(input())
l=list(map(int,input().split()))
s=n*(n+1)//2
print(s-sum(l))
``` | 3 | |
834 | B | The Festive Evening | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | It's the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here are not supposed to be disclosed to the general public: the information can cause discord in the kingdom... | Two integers are given in the first string: the number of guests *n* and the number of guards *k* (1<=≤<=*n*<=≤<=106, 1<=≤<=*k*<=≤<=26).
In the second string, *n* uppercase English letters *s*1*s*2... *s**n* are given, where *s**i* is the entrance used by the *i*-th guest. | Output «YES» if at least one door was unguarded during some time, and «NO» otherwise.
You can output each letter in arbitrary case (upper or lower). | [
"5 1\nAABBB\n",
"5 1\nABABB\n"
] | [
"NO\n",
"YES\n"
] | In the first sample case, the door A is opened right before the first guest's arrival and closed when the second guest enters the castle. The door B is opened right before the arrival of the third guest, and closed after the fifth one arrives. One guard can handle both doors, as the first one is closed before the secon... | 1,000 | [
{
"input": "5 1\nAABBB",
"output": "NO"
},
{
"input": "5 1\nABABB",
"output": "YES"
},
{
"input": "26 1\nABCDEFGHIJKLMNOPQRSTUVWXYZ",
"output": "NO"
},
{
"input": "27 1\nABCDEFGHIJKLMNOPQRSTUVWXYZA",
"output": "YES"
},
{
"input": "5 2\nABACA",
"output": "NO"
... | 1,554,983,195 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 0 | n, k = map(int, input().split())
g = input()
e = [-1] * 26
for i in range(26):
e[ord(g[i]) - 65] = i
curS = 0
ans = 0
f = 1
met = [0] * 26
for i in range(n):
if not met[ord(g[i]) - 65]:
curS += 1
met[ord(g[i]) - 65] = 1
ans = max(ans, curS)
if ans > K:
f = 0
... | Title: The Festive Evening
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here... | ```python
n, k = map(int, input().split())
g = input()
e = [-1] * 26
for i in range(26):
e[ord(g[i]) - 65] = i
curS = 0
ans = 0
f = 1
met = [0] * 26
for i in range(n):
if not met[ord(g[i]) - 65]:
curS += 1
met[ord(g[i]) - 65] = 1
ans = max(ans, curS)
if ans > K:
... | -1 | |
450 | B | Jzzhu and Sequences | PROGRAMMING | 1,300 | [
"implementation",
"math"
] | null | null | Jzzhu has invented a kind of sequences, they meet the following property:
You are given *x* and *y*, please calculate *f**n* modulo 1000000007 (109<=+<=7). | The first line contains two integers *x* and *y* (|*x*|,<=|*y*|<=≤<=109). The second line contains a single integer *n* (1<=≤<=*n*<=≤<=2·109). | Output a single integer representing *f**n* modulo 1000000007 (109<=+<=7). | [
"2 3\n3\n",
"0 -1\n2\n"
] | [
"1\n",
"1000000006\n"
] | In the first sample, *f*<sub class="lower-index">2</sub> = *f*<sub class="lower-index">1</sub> + *f*<sub class="lower-index">3</sub>, 3 = 2 + *f*<sub class="lower-index">3</sub>, *f*<sub class="lower-index">3</sub> = 1.
In the second sample, *f*<sub class="lower-index">2</sub> = - 1; - 1 modulo (10<sup class="upper-... | 1,000 | [
{
"input": "2 3\n3",
"output": "1"
},
{
"input": "0 -1\n2",
"output": "1000000006"
},
{
"input": "-9 -11\n12345",
"output": "1000000005"
},
{
"input": "0 0\n1000000000",
"output": "0"
},
{
"input": "-1000000000 1000000000\n2000000000",
"output": "1000000000"
... | 1,687,758,712 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | # LUOGU_RID: 113340087
def f(x):
if x%6==1: return a
if x%6==2: return b
if x%6==3: return b-a
if x%6==4: return -a
if x%6==5: return -b
if x%6==0: return a-b
a,b,n = int(map,input().split(" "))
print((f(n)%1000000007+1000000007)%1000000007)
| Title: Jzzhu and Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jzzhu has invented a kind of sequences, they meet the following property:
You are given *x* and *y*, please calculate *f**n* modulo 1000000007 (109<=+<=7).
Input Specification:
The first line contains two integers... | ```python
# LUOGU_RID: 113340087
def f(x):
if x%6==1: return a
if x%6==2: return b
if x%6==3: return b-a
if x%6==4: return -a
if x%6==5: return -b
if x%6==0: return a-b
a,b,n = int(map,input().split(" "))
print((f(n)%1000000007+1000000007)%1000000007)
``` | -1 | |
551 | B | ZgukistringZ | PROGRAMMING | 1,800 | [
"brute force",
"constructive algorithms",
"implementation",
"strings"
] | null | null | Professor GukiZ doesn't accept string as they are. He likes to swap some letters in string to obtain a new one.
GukiZ has strings *a*, *b*, and *c*. He wants to obtain string *k* by swapping some letters in *a*, so that *k* should contain as many non-overlapping substrings equal either to *b* or *c* as possible. Subst... | The first line contains string *a*, the second line contains string *b*, and the third line contains string *c* (1<=≤<=|*a*|,<=|*b*|,<=|*c*|<=≤<=105, where |*s*| denotes the length of string *s*).
All three strings consist only of lowercase English letters.
It is possible that *b* and *c* coincide. | Find one of possible strings *k*, as described in the problem statement. If there are multiple possible answers, print any of them. | [
"aaa\na\nb\n",
"pozdravstaklenidodiri\nniste\ndobri\n",
"abbbaaccca\nab\naca\n"
] | [
"aaa",
"nisteaadddiiklooprrvz",
"ababacabcc"
] | In the third sample, this optimal solutions has three non-overlaping substrings equal to either *b* or *c* on positions 1 – 2 (*ab*), 3 – 4 (*ab*), 5 – 7 (*aca*). In this sample, there exist many other optimal solutions, one of them would be *acaababbcc*. | 1,250 | [
{
"input": "aaa\na\nb",
"output": "aaa"
},
{
"input": "pozdravstaklenidodiri\nniste\ndobri",
"output": "nisteaadddiiklooprrvz"
},
{
"input": "abbbaaccca\nab\naca",
"output": "ababacabcc"
},
{
"input": "lemigazalemiolemilicomzalemljenje\nlemi\nzlo",
"output": "lemilemilemi... | 1,586,332,903 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 11 | 1,653 | 10,854,400 | # from sys import stdin,stdout
# input = stdin.readline
a=input()
b=input()
c=input()
h1=[0]*26
for i in range(len(a)):
h1[ord(a[i])-97]+=1
h2=[0]*26
for i in range(len(b)):
h2[ord(b[i])-97]+=1
h3=[0]*26
for i in range(len(c)):
h3[ord(c[i])-97]+=1
ans=""
def check(h1,h2):
for i in range(26):... | Title: ZgukistringZ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ doesn't accept string as they are. He likes to swap some letters in string to obtain a new one.
GukiZ has strings *a*, *b*, and *c*. He wants to obtain string *k* by swapping some letters in *a*, so that *... | ```python
# from sys import stdin,stdout
# input = stdin.readline
a=input()
b=input()
c=input()
h1=[0]*26
for i in range(len(a)):
h1[ord(a[i])-97]+=1
h2=[0]*26
for i in range(len(b)):
h2[ord(b[i])-97]+=1
h3=[0]*26
for i in range(len(c)):
h3[ord(c[i])-97]+=1
ans=""
def check(h1,h2):
for i in ... | 0 | |
893 | C | Rumor | PROGRAMMING | 1,300 | [
"dfs and similar",
"graphs",
"greedy"
] | null | null | Vova promised himself that he would never play computer games... But recently Firestorm — a well-known game developing company — published their newest game, World of Farcraft, and it became really popular. Of course, Vova started playing it.
Now he tries to solve a quest. The task is to come to a settlement named Ove... | The first line contains two integer numbers *n* and *m* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105) — the number of characters in Overcity and the number of pairs of friends.
The second line contains *n* integer numbers *c**i* (0<=≤<=*c**i*<=≤<=109) — the amount of gold *i*-th character asks to start spreading the rumor.
... | Print one number — the minimum amount of gold Vova has to spend in order to finish the quest. | [
"5 2\n2 5 3 4 8\n1 4\n4 5\n",
"10 0\n1 2 3 4 5 6 7 8 9 10\n",
"10 5\n1 6 2 7 3 8 4 9 5 10\n1 2\n3 4\n5 6\n7 8\n9 10\n"
] | [
"10\n",
"55\n",
"15\n"
] | In the first example the best decision is to bribe the first character (he will spread the rumor to fourth character, and the fourth one will spread it to fifth). Also Vova has to bribe the second and the third characters, so they know the rumor.
In the second example Vova has to bribe everyone.
In the third example ... | 0 | [
{
"input": "5 2\n2 5 3 4 8\n1 4\n4 5",
"output": "10"
},
{
"input": "10 0\n1 2 3 4 5 6 7 8 9 10",
"output": "55"
},
{
"input": "10 5\n1 6 2 7 3 8 4 9 5 10\n1 2\n3 4\n5 6\n7 8\n9 10",
"output": "15"
},
{
"input": "1 0\n0",
"output": "0"
},
{
"input": "1 0\n10000000... | 1,683,979,871 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 577 | 13,312,000 | class DSU:
def __init__(self, n, costs):
self.__n = n
self.__parent = [i for i in range(n)]
self.__costs = costs
def connect(self, a, b):
parent_a = self.parent(a)
parent_b = self.parent(b)
if parent_a != parent_b:
if self.__costs[parent_a] ... | Title: Rumor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vova promised himself that he would never play computer games... But recently Firestorm — a well-known game developing company — published their newest game, World of Farcraft, and it became really popular. Of course, Vova starte... | ```python
class DSU:
def __init__(self, n, costs):
self.__n = n
self.__parent = [i for i in range(n)]
self.__costs = costs
def connect(self, a, b):
parent_a = self.parent(a)
parent_b = self.parent(b)
if parent_a != parent_b:
if self.__costs[... | 3 | |
53 | A | Autocomplete | PROGRAMMING | 1,100 | [
"implementation"
] | A. Autocomplete | 2 | 256 | Autocomplete is a program function that enables inputting the text (in editors, command line shells, browsers etc.) completing the text by its inputted part. Vasya is busy working on a new browser called 'BERowser'. He happens to be working on the autocomplete function in the address line at this very moment. A list co... | The first line contains the *s* line which is the inputted part. The second line contains an integer *n* (1<=≤<=*n*<=≤<=100) which is the number of visited pages. Then follow *n* lines which are the visited pages, one on each line. All the lines have lengths of from 1 to 100 symbols inclusively and consist of lowercase... | If *s* is not the beginning of any of *n* addresses of the visited pages, print *s*. Otherwise, print the lexicographically minimal address of one of the visited pages starting from *s*.
The lexicographical order is the order of words in a dictionary. The lexicographical comparison of lines is realized by the '<' o... | [
"next\n2\nnextpermutation\nnextelement\n",
"find\n4\nfind\nfindfirstof\nfindit\nfand\n",
"find\n4\nfondfind\nfondfirstof\nfondit\nfand\n"
] | [
"nextelement\n",
"find\n",
"find\n"
] | none | 500 | [
{
"input": "next\n2\nnextpermutation\nnextelement",
"output": "nextelement"
},
{
"input": "find\n4\nfind\nfindfirstof\nfindit\nfand",
"output": "find"
},
{
"input": "find\n4\nfondfind\nfondfirstof\nfondit\nfand",
"output": "find"
},
{
"input": "kudljmxcse\n4\nkudljmxcse\nszje... | 1,497,463,097 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a=raw_input()
t=0
z=len(a)
n=int(input())
d=a
h=101
p=[]
for i in range(n):
b=raw_input()
if b[:z]==a:
j=len(b)
if j<=h:
h=j
d=b
p.append(d)
p.sort()
if len(p)==0:
print a
else:
print p[0]
| Title: Autocomplete
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Autocomplete is a program function that enables inputting the text (in editors, command line shells, browsers etc.) completing the text by its inputted part. Vasya is busy working on a new browser called 'BERowser'. He happens... | ```python
a=raw_input()
t=0
z=len(a)
n=int(input())
d=a
h=101
p=[]
for i in range(n):
b=raw_input()
if b[:z]==a:
j=len(b)
if j<=h:
h=j
d=b
p.append(d)
p.sort()
if len(p)==0:
print a
else:
print p[0]
``` | -1 |
355 | A | Vasya and Digital Root | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation"
] | null | null | Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=+<=9<=+<=8<==<=21. Then the digital root of number *n* equals to:
1. *dr*(*n*)<==<=*S*(*n*), if *S*(*n*)<... | The first line contains two integers *k* and *d* (1<=≤<=*k*<=≤<=1000; 0<=≤<=*d*<=≤<=9). | In a single line print either any number that meets the requirements (without the leading zeroes) or "No solution" (without the quotes), if the corresponding number does not exist.
The chosen number must consist of exactly *k* digits. We assume that number 0 doesn't contain any leading zeroes. | [
"4 4\n",
"5 1\n",
"1 0\n"
] | [
"5881\n",
"36172\n",
"0\n"
] | For the first test sample *dr*(5881) = *dr*(22) = 4.
For the second test sample *dr*(36172) = *dr*(19) = *dr*(10) = 1. | 500 | [
{
"input": "4 4",
"output": "5881"
},
{
"input": "5 1",
"output": "36172"
},
{
"input": "1 0",
"output": "0"
},
{
"input": "8 7",
"output": "49722154"
},
{
"input": "487 0",
"output": "No solution"
},
{
"input": "1000 5",
"output": "854193955406789... | 1,595,218,408 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 93 | 6,656,000 | k,d=map(int,input().split())
print('No solution' if (d==0)*(k-1) else str(d)+'0'*(k-1)) | Title: Vasya and Digital Root
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=... | ```python
k,d=map(int,input().split())
print('No solution' if (d==0)*(k-1) else str(d)+'0'*(k-1))
``` | 3 | |
99 | A | Help Far Away Kingdom | PROGRAMMING | 800 | [
"strings"
] | A. Help Far Away Kingdom | 2 | 256 | In a far away kingdom lived the King, the Prince, the Shoemaker, the Dressmaker and many other citizens. They lived happily until great trouble came into the Kingdom. The ACMers settled there.
Most damage those strange creatures inflicted upon the kingdom was that they loved high precision numbers. As a result, the Ki... | The first line contains a single number to round up — the integer part (a non-empty set of decimal digits that do not start with 0 — with the exception of a case when the set consists of a single digit — in this case 0 can go first), then follows character «.» (a dot), and then follows the fractional part (any non-empt... | If the last number of the integer part is not equal to 9, print the rounded-up number without leading zeroes. Otherwise, print the message "GOTO Vasilisa." (without the quotes). | [
"0.0\n",
"1.49\n",
"1.50\n",
"2.71828182845904523536\n",
"3.14159265358979323846\n",
"12345678901234567890.1\n",
"123456789123456789.999\n"
] | [
"0",
"1",
"2",
"3",
"3",
"12345678901234567890",
"GOTO Vasilisa."
] | none | 500 | [
{
"input": "0.0",
"output": "0"
},
{
"input": "1.49",
"output": "1"
},
{
"input": "1.50",
"output": "2"
},
{
"input": "2.71828182845904523536",
"output": "3"
},
{
"input": "3.14159265358979323846",
"output": "3"
},
{
"input": "12345678901234567890.1",
... | 1,661,578,925 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 186 | 0 | n = float(input())
a = round(n - int(n), len("higit"))
if int(n) % 10 == 9:
print("GOTO Vasilisa.")
elif int(a * 10) == 5:
print(int(n + 1))
else:
print(round(n))
| Title: Help Far Away Kingdom
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
In a far away kingdom lived the King, the Prince, the Shoemaker, the Dressmaker and many other citizens. They lived happily until great trouble came into the Kingdom. The ACMers settled there.
Most damage those stran... | ```python
n = float(input())
a = round(n - int(n), len("higit"))
if int(n) % 10 == 9:
print("GOTO Vasilisa.")
elif int(a * 10) == 5:
print(int(n + 1))
else:
print(round(n))
``` | 0 |
526 | A | King of Thieves | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | In this problem you will meet the simplified model of game King of Thieves.
In a new ZeptoLab game called "King of Thieves" your aim is to reach a chest with gold by controlling your character, avoiding traps and obstacles on your way.
An interesting feature of the game is that you can design your own levels that wil... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of segments on the level.
Next line contains the scheme of the level represented as a string of *n* characters '*' and '.'. | If the level is good, print the word "yes" (without the quotes), otherwise print the word "no" (without the quotes). | [
"16\n.**.*..*.***.**.\n",
"11\n.*.*...*.*.\n"
] | [
"yes",
"no"
] | In the first sample test you may perform a sequence of jumps through platforms 2, 5, 8, 11, 14. | 500 | [
{
"input": "16\n.**.*..*.***.**.",
"output": "yes"
},
{
"input": "11\n.*.*...*.*.",
"output": "no"
},
{
"input": "53\n*.*.****.*.*......**....**.***.*.*.**.*.*.***...*..*.",
"output": "yes"
},
{
"input": "71\n**.**..*****.*.*.*.********.....*****.****.*..***...*.*.*.**.****.*... | 1,600,188,789 | 2,147,483,647 | PyPy 3 | OK | TESTS | 65 | 140 | 1,228,800 | a=int(input())
k=input()
b=[i for i in range(a) if k[i]=='*']
for i in b:
for j in range(1,101):
ok=1
for x in range(1,5):
if i+j*x not in b:ok=0;break
if ok:exit(print("yes"))
print("no") | Title: King of Thieves
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you will meet the simplified model of game King of Thieves.
In a new ZeptoLab game called "King of Thieves" your aim is to reach a chest with gold by controlling your character, avoiding traps and obsta... | ```python
a=int(input())
k=input()
b=[i for i in range(a) if k[i]=='*']
for i in b:
for j in range(1,101):
ok=1
for x in range(1,5):
if i+j*x not in b:ok=0;break
if ok:exit(print("yes"))
print("no")
``` | 3 | |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,461,516,334 | 634 | Python 3 | OK | TESTS | 26 | 62 | 4,608,000 | a = int(input())
toAdd = 0
if a%3 !=0:
toAdd = 1
print(((a//3)*2)+toAdd) | Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
a = int(input())
toAdd = 0
if a%3 !=0:
toAdd = 1
print(((a//3)*2)+toAdd)
``` | 3 | |
758 | A | Holiday Of Equality | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens, the welfare of each of them is estimated as the integer in *a**i* burles (burle is the currency in Berl... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100) — the number of citizens in the kingdom.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (0<=≤<=*a**i*<=≤<=106) — the welfare of the *i*-th citizen. | In the only line print the integer *S* — the minimum number of burles which are had to spend. | [
"5\n0 1 2 3 4\n",
"5\n1 1 0 1 1\n",
"3\n1 3 1\n",
"1\n12\n"
] | [
"10",
"1",
"4",
"0"
] | In the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.
In the second example it is enough to give one burle to the third citizen.
In the third example it is necessary to give two burles to the first and the thi... | 500 | [
{
"input": "5\n0 1 2 3 4",
"output": "10"
},
{
"input": "5\n1 1 0 1 1",
"output": "1"
},
{
"input": "3\n1 3 1",
"output": "4"
},
{
"input": "1\n12",
"output": "0"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "14\n52518 718438 358883 462189 853... | 1,678,890,527 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 0 | num = int(input())
li = [int(i) for i in input().split()]
count = 0
max = max(li)
for item in li:
if item < max:
count += max-item
print(count) | Title: Holiday Of Equality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens... | ```python
num = int(input())
li = [int(i) for i in input().split()]
count = 0
max = max(li)
for item in li:
if item < max:
count += max-item
print(count)
``` | 3 | |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another c... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follo... | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,609,782,534 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 3,000 | 6,963,200 | def lineland(nums, size):
for i in range(size):
row = []
for j in range(size):
if i != j:
row.append(abs(int(nums[i]) - int(nums[j])))
print(min(row), max(row))
size = int(input())
nums = input().split(' ')
lineland(nums, size)
| Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love... | ```python
def lineland(nums, size):
for i in range(size):
row = []
for j in range(size):
if i != j:
row.append(abs(int(nums[i]) - int(nums[j])))
print(min(row), max(row))
size = int(input())
nums = input().split(' ')
lineland(nums, size)
``` | 0 | |
946 | C | String Transformation | PROGRAMMING | 1,300 | [
"greedy",
"strings"
] | null | null | You are given a string *s* consisting of |*s*| small english letters.
In one move you can replace any character of this string to the next character in alphabetical order (a will be replaced with b, s will be replaced with t, etc.). You cannot replace letter z with any other letter.
Your target is to make some number... | The only one line of the input consisting of the string *s* consisting of |*s*| (1<=≤<=|*s*|<=≤<=105) small english letters. | If you can get a string that can be obtained from the given string and will contain english alphabet as a subsequence, print it. Otherwise print «-1» (without quotes). | [
"aacceeggiikkmmooqqssuuwwyy\n",
"thereisnoanswer\n"
] | [
"abcdefghijklmnopqrstuvwxyz\n",
"-1\n"
] | none | 0 | [
{
"input": "aacceeggiikkmmooqqssuuwwyy",
"output": "abcdefghijklmnopqrstuvwxyz"
},
{
"input": "thereisnoanswer",
"output": "-1"
},
{
"input": "jqcfvsaveaixhioaaeephbmsmfcgdyawscpyioybkgxlcrhaxs",
"output": "-1"
},
{
"input": "rtdacjpsjjmjdhcoprjhaenlwuvpfqzurnrswngmpnkdnunaen... | 1,566,586,671 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 124 | 819,200 | S,t=str(input()),1
S=' '.join(S)
S=S.split()
X= { 'a':1,'b':2,'c':3,'d':4,'e':5,'f':6,'g':7,'h':8,'i':9,'j':10,'k':11,'l':12,'m':13,'n':14,'o':15,'p':16,'q':17,'r':18,'s':19,'t':20,'u':21,'v':22,'w':23,'x':24,'y':25,'z':26}
Y= { 1:"a",2:"b",3:"c",4:"d",5:"e",6:"f",7:"g",8:"h",9:"i",10:"j",11:"k",12:"l",13:"m",14:"n... | Title: String Transformation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* consisting of |*s*| small english letters.
In one move you can replace any character of this string to the next character in alphabetical order (a will be replaced with b, s will be rep... | ```python
S,t=str(input()),1
S=' '.join(S)
S=S.split()
X= { 'a':1,'b':2,'c':3,'d':4,'e':5,'f':6,'g':7,'h':8,'i':9,'j':10,'k':11,'l':12,'m':13,'n':14,'o':15,'p':16,'q':17,'r':18,'s':19,'t':20,'u':21,'v':22,'w':23,'x':24,'y':25,'z':26}
Y= { 1:"a",2:"b",3:"c",4:"d",5:"e",6:"f",7:"g",8:"h",9:"i",10:"j",11:"k",12:"l",13... | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya has two strings *a* and *b* of the same length *n*. The strings consist only of lucky digits... | The first and the second line contains strings *a* and *b*, correspondingly. Strings *a* and *b* have equal lengths and contain only lucky digits. The strings are not empty, their length does not exceed 105. | Print on the single line the single number — the minimum number of operations needed to convert string *a* into string *b*. | [
"47\n74\n",
"774\n744\n",
"777\n444\n"
] | [
"1\n",
"1\n",
"3\n"
] | In the first sample it is enough simply to swap the first and the second digit.
In the second sample we should replace the second digit with its opposite.
In the third number we should replace all three digits with their opposites. | 0 | [
{
"input": "47\n74",
"output": "1"
},
{
"input": "774\n744",
"output": "1"
},
{
"input": "777\n444",
"output": "3"
},
{
"input": "74747474\n77777777",
"output": "4"
},
{
"input": "444444444444\n777777777777",
"output": "12"
},
{
"input": "4744744447774... | 1,601,209,043 | 2,147,483,647 | PyPy 3 | OK | TESTS | 51 | 312 | 2,560,000 | a = input()
b = input()
n = len(a)
x = 0
y = 0
for i in range(n):
if a[i] == '4' and b[i] == '7':
x += 1
if a[i] == '7' and b[i] == '4':
y += 1
print(max(x, y))
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya ha... | ```python
a = input()
b = input()
n = len(a)
x = 0
y = 0
for i in range(n):
if a[i] == '4' and b[i] == '7':
x += 1
if a[i] == '7' and b[i] == '4':
y += 1
print(max(x, y))
``` | 3 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,678,314,742 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 124 | 0 | def main():
m,n = map(int, input().split())
if m%2:
print(n*(m//2)+n//2)
else:
print(n*(m//2))
main() | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
def main():
m,n = map(int, input().split())
if m%2:
print(n*(m//2)+n//2)
else:
print(n*(m//2))
main()
``` | 3.969 |
553 | B | Kyoya and Permutation | PROGRAMMING | 1,900 | [
"binary search",
"combinatorics",
"constructive algorithms",
"greedy",
"implementation",
"math"
] | null | null | Let's define the permutation of length *n* as an array *p*<==<=[*p*1,<=*p*2,<=...,<=*p**n*] consisting of *n* distinct integers from range from 1 to *n*. We say that this permutation maps value 1 into the value *p*1, value 2 into the value *p*2 and so on.
Kyota Ootori has just learned about cyclic representation of a ... | The first line will contain two integers *n*, *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=*min*{1018,<=*l*} where *l* is the length of the Kyoya's list). | Print *n* space-separated integers, representing the permutation that is the answer for the question. | [
"4 3\n",
"10 1\n"
] | [
"1 3 2 4\n",
"1 2 3 4 5 6 7 8 9 10\n"
] | The standard cycle representation is (1)(32)(4), which after removing parenthesis gives us the original permutation. The first permutation on the list would be [1, 2, 3, 4], while the second permutation would be [1, 2, 4, 3]. | 500 | [
{
"input": "4 3",
"output": "1 3 2 4"
},
{
"input": "10 1",
"output": "1 2 3 4 5 6 7 8 9 10"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "50 1",
"output": "1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 ... | 1,661,854,048 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 65 | 62 | 0 | G=range;n,k=map(int,input().split())
fib=[1,1]+[0]*(n-1)
for i in G(2,n+1):fib[i]=fib[i-1]+fib[i-2]
i=0;z=[0]*n
while i<n:
v=fib[n-i-1]
if k<=v:z[i]=i+1;i+=1
else:k-=v;z[i:i+2]=[i+2,i+1];i+=2
print(*z) | Title: Kyoya and Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's define the permutation of length *n* as an array *p*<==<=[*p*1,<=*p*2,<=...,<=*p**n*] consisting of *n* distinct integers from range from 1 to *n*. We say that this permutation maps value 1 into the value *p... | ```python
G=range;n,k=map(int,input().split())
fib=[1,1]+[0]*(n-1)
for i in G(2,n+1):fib[i]=fib[i-1]+fib[i-2]
i=0;z=[0]*n
while i<n:
v=fib[n-i-1]
if k<=v:z[i]=i+1;i+=1
else:k-=v;z[i:i+2]=[i+2,i+1];i+=2
print(*z)
``` | 3 | |
862 | B | Mahmoud and Ehab and the bipartiteness | PROGRAMMING | 1,300 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a graph, whose vertices can be partitioned into 2 sets in such a way, that for each edge (*u*,<=*v*) that belongs to the graph, *... | The first line of input contains an integer *n* — the number of nodes in the tree (1<=≤<=*n*<=≤<=105).
The next *n*<=-<=1 lines contain integers *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*) — the description of the edges of the tree.
It's guaranteed that the given graph is a tree. | Output one integer — the maximum number of edges that Mahmoud and Ehab can add to the tree while fulfilling the conditions. | [
"3\n1 2\n1 3\n",
"5\n1 2\n2 3\n3 4\n4 5\n"
] | [
"0\n",
"2\n"
] | Tree definition: [https://en.wikipedia.org/wiki/Tree_(graph_theory)](https://en.wikipedia.org/wiki/Tree_(graph_theory))
Bipartite graph definition: [https://en.wikipedia.org/wiki/Bipartite_graph](https://en.wikipedia.org/wiki/Bipartite_graph)
In the first test case the only edge that can be added in such a way, that ... | 1,000 | [
{
"input": "3\n1 2\n1 3",
"output": "0"
},
{
"input": "5\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10\n3 8\n6 2\n9 7\n10 1\n3 5\n1 3\n6 7\n5 4\n3 6",
"output": "16"
},
{
"input": "10\n7 6\n2 7\n4 1\n8 5\n9 4\n5 3\n8 7\n10 8\n10 4",
"output": "16"
},
{
"in... | 1,624,537,353 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 16 | 670 | 32,972,800 | import sys
sys.setrecursionlimit(9999)
n = int(input())
tree = [set() for i in range(n + 1)]
levels = [1 for i in range(n + 1)]
lev_to_vert = [set() for i in range(n + 1)]
lev_to_vert[1] = {1}
visited = [False for i in range(n + 1)]
def dfs(start, prev_level):
if visited[start]:
return
... | Title: Mahmoud and Ehab and the bipartiteness
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a gra... | ```python
import sys
sys.setrecursionlimit(9999)
n = int(input())
tree = [set() for i in range(n + 1)]
levels = [1 for i in range(n + 1)]
lev_to_vert = [set() for i in range(n + 1)]
lev_to_vert[1] = {1}
visited = [False for i in range(n + 1)]
def dfs(start, prev_level):
if visited[start]:
re... | -1 | |
486 | A | Calculating Function | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*. | The single line contains the positive integer *n* (1<=≤<=*n*<=≤<=1015). | Print *f*(*n*) in a single line. | [
"4\n",
"5\n"
] | [
"2\n",
"-3\n"
] | *f*(4) = - 1 + 2 - 3 + 4 = 2
*f*(5) = - 1 + 2 - 3 + 4 - 5 = - 3 | 500 | [
{
"input": "4",
"output": "2"
},
{
"input": "5",
"output": "-3"
},
{
"input": "1000000000",
"output": "500000000"
},
{
"input": "1000000001",
"output": "-500000001"
},
{
"input": "1000000000000000",
"output": "500000000000000"
},
{
"input": "100",
... | 1,694,784,270 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 46 | 0 | N = int(input())
if(N%2==0):
print(N//2)
else:
print((N//2)-N) | Title: Calculating Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*.
Input Specification:
The single line... | ```python
N = int(input())
if(N%2==0):
print(N//2)
else:
print((N//2)-N)
``` | 3 | |
987 | A | Infinity Gauntlet | PROGRAMMING | 800 | [
"implementation"
] | null | null | You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems:
- the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the Soul Gem of orange color, - the Reality Gem of red color, - the Mind Gem of yellow color.
Using colors... | In the first line of input there is one integer $n$ ($0 \le n \le 6$) — the number of Gems in Infinity Gauntlet.
In next $n$ lines there are colors of Gems you saw. Words used for colors are: purple, green, blue, orange, red, yellow. It is guaranteed that all the colors are distinct. All colors are given in lowercase ... | In the first line output one integer $m$ ($0 \le m \le 6$) — the number of absent Gems.
Then in $m$ lines print the names of absent Gems, each on its own line. Words used for names are: Power, Time, Space, Soul, Reality, Mind. Names can be printed in any order. Keep the first letter uppercase, others lowercase. | [
"4\nred\npurple\nyellow\norange\n",
"0\n"
] | [
"2\nSpace\nTime\n",
"6\nTime\nMind\nSoul\nPower\nReality\nSpace\n"
] | In the first sample Thanos already has Reality, Power, Mind and Soul Gems, so he needs two more: Time and Space.
In the second sample Thanos doesn't have any Gems, so he needs all six. | 500 | [
{
"input": "4\nred\npurple\nyellow\norange",
"output": "2\nSpace\nTime"
},
{
"input": "0",
"output": "6\nMind\nSpace\nPower\nTime\nReality\nSoul"
},
{
"input": "6\npurple\nblue\nyellow\nred\ngreen\norange",
"output": "0"
},
{
"input": "1\npurple",
"output": "5\nTime\nReal... | 1,594,893,603 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 108 | 6,963,200 | a=int(input())
l=["purple","red","green","blue","orange","yellow"]
for i in range(a):
x=input()
l.remove(x)
print(len(l))
for i in l:
if(i=="red"):
print("Reality")
elif(i=="blue"):
print("Space")
elif(i=="green"):
print("Time ")
elif(i=="orange"):
p... | Title: Infinity Gauntlet
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems:
- the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the So... | ```python
a=int(input())
l=["purple","red","green","blue","orange","yellow"]
for i in range(a):
x=input()
l.remove(x)
print(len(l))
for i in l:
if(i=="red"):
print("Reality")
elif(i=="blue"):
print("Space")
elif(i=="green"):
print("Time ")
elif(i=="orange"):
... | 3 | |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are s... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,675,893,710 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 25 | 1,000 | 10,240,000 | n,q = map(int,input().split())
arr = [int(i) for i in input().split()]
dp = [0] * (n+1); dp[n] = 1;
f = [0] * (max(arr)+1); f[arr[-1]] = 1
for i in range(n-1,0,-1) :
c = 0
if not f[arr[i-1]] : c = f[arr[i-1]] = 1
dp[i] = dp[i+1] + c
for i in range(q) :
print(dp[int(input())]) | Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...... | ```python
n,q = map(int,input().split())
arr = [int(i) for i in input().split()]
dp = [0] * (n+1); dp[n] = 1;
f = [0] * (max(arr)+1); f[arr[-1]] = 1
for i in range(n-1,0,-1) :
c = 0
if not f[arr[i-1]] : c = f[arr[i-1]] = 1
dp[i] = dp[i+1] + c
for i in range(q) :
print(dp[int(input())])
``... | 0 | |
463 | D | Gargari and Permutations | PROGRAMMING | 1,900 | [
"dfs and similar",
"dp",
"graphs",
"implementation"
] | null | null | Gargari got bored to play with the bishops and now, after solving the problem about them, he is trying to do math homework. In a math book he have found *k* permutations. Each of them consists of numbers 1,<=2,<=...,<=*n* in some order. Now he should find the length of the longest common subsequence of these permutatio... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1000; 2<=≤<=*k*<=≤<=5). Each of the next *k* lines contains integers 1,<=2,<=...,<=*n* in some order — description of the current permutation. | Print the length of the longest common subsequence. | [
"4 3\n1 4 2 3\n4 1 2 3\n1 2 4 3\n"
] | [
"3\n"
] | The answer for the first test sample is subsequence [1, 2, 3]. | 2,000 | [
{
"input": "4 3\n1 4 2 3\n4 1 2 3\n1 2 4 3",
"output": "3"
},
{
"input": "6 3\n2 5 1 4 6 3\n5 1 4 3 2 6\n5 4 2 6 3 1",
"output": "3"
},
{
"input": "41 4\n24 15 17 35 13 41 4 14 23 5 8 16 21 18 30 36 6 22 11 29 26 1 40 31 7 3 32 10 28 38 12 20 39 37 34 19 33 27 2 25 9\n22 13 25 24 38 35 2... | 1,638,412,611 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 61 | 0 | import sys
inp = sys.stdin.readline().replace('\n','').split()
n = int(inp[0])
k = int(inp[1])
arr = [[0 for i in range(20)] for j in range(1005)]
positions = [[0 for i in range(20)] for j in range(1005)]
for i in range(1, k+1):
inp = sys.stdin.readline().replace('\n','').split()
for j in range(1,n+1):
num = in... | Title: Gargari and Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gargari got bored to play with the bishops and now, after solving the problem about them, he is trying to do math homework. In a math book he have found *k* permutations. Each of them consists of numbers 1,<=2,... | ```python
import sys
inp = sys.stdin.readline().replace('\n','').split()
n = int(inp[0])
k = int(inp[1])
arr = [[0 for i in range(20)] for j in range(1005)]
positions = [[0 for i in range(20)] for j in range(1005)]
for i in range(1, k+1):
inp = sys.stdin.readline().replace('\n','').split()
for j in range(1,n+1):
... | -1 | |
976 | A | Minimum Binary Number | PROGRAMMING | 800 | [
"implementation"
] | null | null | String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" "110"... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=100) — the length of string *s*.
The second line contains the string *s* consisting of characters "0" and "1". It is guaranteed that the string *s* is correct. | Print one string — the minimum correct string that you can obtain from the given one. | [
"4\n1001\n",
"1\n1\n"
] | [
"100\n",
"1\n"
] | In the first example you can obtain the answer by the following sequence of operations: "1001" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "1010" <img align="middle" class="tex-formula" src="ht... | 0 | [
{
"input": "4\n1001",
"output": "100"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "100\n1110111100001111011111111010110011111111011110000111101101011100110110001011000000101010110101011100",
"output": "1000000000000000000000000000000000000000"
},
{
"input": "100\n100000... | 1,532,867,738 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 108 | 0 | n = int(input())
b = input()
z = b.count("0")
print("1", end = "")
for i in range(z):
print("0", end = "") | Title: Minimum Binary Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two... | ```python
n = int(input())
b = input()
z = b.count("0")
print("1", end = "")
for i in range(z):
print("0", end = "")
``` | 0 | |
296 | A | Yaroslav and Permutations | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.
Help Yaroslav. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) — the array elements. | In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise. | [
"1\n1\n",
"3\n1 1 2\n",
"4\n7 7 7 7\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample the initial array fits well.
In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.
In the third sample Yarosav can't get the array he needs. | 500 | [
{
"input": "1\n1",
"output": "YES"
},
{
"input": "3\n1 1 2",
"output": "YES"
},
{
"input": "4\n7 7 7 7",
"output": "NO"
},
{
"input": "4\n479 170 465 146",
"output": "YES"
},
{
"input": "5\n996 437 605 996 293",
"output": "YES"
},
{
"input": "6\n727 53... | 1,568,959,504 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 280 | 0 | n=int(input())
arr=[int(x) for x in input().split(' ')]
mymap={}
for item in arr:
if item in mymap:
mymap[item]+=1
else:
mymap[item]=1
if any([x for x in mymap.values() if x>(n+1)//2]):
print("NO")
else:
print("YES") | Title: Yaroslav and Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would... | ```python
n=int(input())
arr=[int(x) for x in input().split(' ')]
mymap={}
for item in arr:
if item in mymap:
mymap[item]+=1
else:
mymap[item]=1
if any([x for x in mymap.values() if x>(n+1)//2]):
print("NO")
else:
print("YES")
``` | 3 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,629,498,020 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 154 | 6,758,400 | data = input()
upper_count = 0
lower_count = 0
for char in data:
if char.isupper():
upper_count +=1
else:
lower_count +=1
if upper_count > lower_count:
print(data.upper())
else:
print(data.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
data = input()
upper_count = 0
lower_count = 0
for char in data:
if char.isupper():
upper_count +=1
else:
lower_count +=1
if upper_count > lower_count:
print(data.upper())
else:
print(data.lower())
``` | 3.948911 |
58 | B | Coins | PROGRAMMING | 1,300 | [
"greedy"
] | B. Coins | 2 | 256 | In Berland a money reform is being prepared. New coins are being introduced. After long economic calculations was decided that the most expensive coin should possess the denomination of exactly *n* Berland dollars. Also the following restriction has been introduced for comfort: the denomination of each coin should be d... | The first and only line contains an integer *n* (1<=≤<=*n*<=≤<=106) which represents the denomination of the most expensive coin. | Print the denominations of all the coins in the order of decreasing. The number of coins must be the largest possible (with the given denomination *n* of the most expensive coin). Also, the denomination of every coin must be divisible by the denomination of any cheaper coin. Naturally, the denominations of all the coin... | [
"10\n",
"4\n",
"3\n"
] | [
"10 5 1\n",
"4 2 1\n",
"3 1\n"
] | none | 1,000 | [
{
"input": "10",
"output": "10 5 1"
},
{
"input": "4",
"output": "4 2 1"
},
{
"input": "3",
"output": "3 1"
},
{
"input": "2",
"output": "2 1"
},
{
"input": "5",
"output": "5 1"
},
{
"input": "6",
"output": "6 3 1"
},
{
"input": "7",
"o... | 1,623,500,407 | 2,147,483,647 | PyPy 3 | OK | TESTS | 50 | 278 | 5,427,200 | import math
N = 10**6+50
spf = [-1]*(N+1)
for i in range(N+1):
spf[i] = i
for i in range(2, int(math.sqrt(N))+1):
if spf[i] == i:
for j in range(i*2, N+1, i):
if spf[j] == j:
spf[j] = i
def factorize(n):
d = {}
while n != 1:
p = spf[n]
... | Title: Coins
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
In Berland a money reform is being prepared. New coins are being introduced. After long economic calculations was decided that the most expensive coin should possess the denomination of exactly *n* Berland dollars. Also the following... | ```python
import math
N = 10**6+50
spf = [-1]*(N+1)
for i in range(N+1):
spf[i] = i
for i in range(2, int(math.sqrt(N))+1):
if spf[i] == i:
for j in range(i*2, N+1, i):
if spf[j] == j:
spf[j] = i
def factorize(n):
d = {}
while n != 1:
p = spf[... | 3.920391 |
948 | A | Protect Sheep | PROGRAMMING | 900 | [
"brute force",
"dfs and similar",
"graphs",
"implementation"
] | null | null | Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of *R*<=×<=*C* cells. Each cell is either empty, contains a sheep, a wolf or... | First line contains two integers *R* (1<=≤<=*R*<=≤<=500) and *C* (1<=≤<=*C*<=≤<=500), denoting the number of rows and the numbers of columns respectively.
Each of the following *R* lines is a string consisting of exactly *C* characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' a... | If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print *R* lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a she... | [
"6 6\n..S...\n..S.W.\n.S....\n..W...\n...W..\n......\n",
"1 2\nSW\n",
"5 5\n.S...\n...S.\nS....\n...S.\n.S...\n"
] | [
"Yes\n..SD..\n..SDW.\n.SD...\n.DW...\nDD.W..\n......\n",
"No\n",
"Yes\n.S...\n...S.\nS.D..\n...S.\n.S...\n"
] | In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves... | 500 | [
{
"input": "1 2\nSW",
"output": "No"
},
{
"input": "10 10\n....W.W.W.\n.........S\n.S.S...S..\nW.......SS\n.W..W.....\n.W...W....\nS..S...S.S\n....W...S.\n..S..S.S.S\nSS.......S",
"output": "Yes\nDDDDWDWDWD\nDDDDDDDDDS\nDSDSDDDSDD\nWDDDDDDDSS\nDWDDWDDDDD\nDWDDDWDDDD\nSDDSDDDSDS\nDDDDWDDDSD\nDDSD... | 1,659,514,461 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 109 | 1,126,400 | r,c = map(int, input().split())
s = ""
copy = ""
for _ in range(r):
string = input()
copy += string
if "SW" in string or "WS" in string:
print("NO")
exit()
for i in range(c):
for j in range(i, len(copy), r):
s += copy[j]
for i in range(0, len(s), r):
for j in ... | Title: Protect Sheep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is ... | ```python
r,c = map(int, input().split())
s = ""
copy = ""
for _ in range(r):
string = input()
copy += string
if "SW" in string or "WS" in string:
print("NO")
exit()
for i in range(c):
for j in range(i, len(copy), r):
s += copy[j]
for i in range(0, len(s), r):
... | 0 | |
299 | A | Ksusha and Array | PROGRAMMING | 1,000 | [
"brute force",
"number theory",
"sortings"
] | null | null | Ksusha is a beginner coder. Today she starts studying arrays. She has array *a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* positive integers.
Her university teacher gave her a task. Find such number in the array, that all array elements are divisible by it. Help her and find the number! | The first line contains integer *n* (1<=≤<=*n*<=≤<=105), showing how many numbers the array has. The next line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the array elements. | Print a single integer — the number from the array, such that all array elements are divisible by it. If such number doesn't exist, print -1.
If there are multiple answers, you are allowed to print any of them. | [
"3\n2 2 4\n",
"5\n2 1 3 1 6\n",
"3\n2 3 5\n"
] | [
"2\n",
"1\n",
"-1\n"
] | none | 500 | [
{
"input": "3\n2 2 4",
"output": "2"
},
{
"input": "5\n2 1 3 1 6",
"output": "1"
},
{
"input": "3\n2 3 5",
"output": "-1"
},
{
"input": "1\n331358794",
"output": "331358794"
},
{
"input": "5\n506904227 214303304 136194869 838256937 183952885",
"output": "-1"
... | 1,576,931,614 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 4,300,800 | n=int(input())
a=[]
a=list(map(int, input().split(maxsplit=n)))
it=-1
for i in range(n):
d=a[i]
k=0
for f in range(n):
if a[f]%d==0: k=k+1
if k==n: it=d
print(it)
| Title: Ksusha and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksusha is a beginner coder. Today she starts studying arrays. She has array *a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* positive integers.
Her university teacher gave her a task. Find such number in the array, that ... | ```python
n=int(input())
a=[]
a=list(map(int, input().split(maxsplit=n)))
it=-1
for i in range(n):
d=a[i]
k=0
for f in range(n):
if a[f]%d==0: k=k+1
if k==n: it=d
print(it)
``` | 0 | |
358 | A | Dima and Continuous Line | PROGRAMMING | 1,400 | [
"brute force",
"implementation"
] | null | null | Dima and Seryozha live in an ordinary dormitory room for two. One day Dima had a date with his girl and he asked Seryozha to leave the room. As a compensation, Seryozha made Dima do his homework.
The teacher gave Seryozha the coordinates of *n* distinct points on the abscissa axis and asked to consecutively connect th... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=103). The second line contains *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=106<=≤<=*x**i*<=≤<=106) — the *i*-th point has coordinates (*x**i*,<=0). The points are not necessarily sorted by their *x* coordinate. | In the single line print "yes" (without the quotes), if the line has self-intersections. Otherwise, print "no" (without the quotes). | [
"4\n0 10 5 15\n",
"4\n0 15 5 10\n"
] | [
"yes\n",
"no\n"
] | The first test from the statement is on the picture to the left, the second test is on the picture to the right. | 500 | [
{
"input": "4\n0 10 5 15",
"output": "yes"
},
{
"input": "4\n0 15 5 10",
"output": "no"
},
{
"input": "5\n0 1000 2000 3000 1500",
"output": "yes"
},
{
"input": "5\n-724093 710736 -383722 -359011 439613",
"output": "no"
},
{
"input": "50\n384672 661179 -775591 -989... | 1,470,759,851 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 4,608,000 | n=int(input())
x=list(map(int,input().split()))
for i in range(len(x)-3):
x1,x2,x2,x4 = x[i],x[i+1],x[i+2],x[i+3]
if x1<x3<x2<x4:
print("yes")
exit()
elif x3<x1<x4<x2:
print("yes")
exit()
print('no') | Title: Dima and Continuous Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and Seryozha live in an ordinary dormitory room for two. One day Dima had a date with his girl and he asked Seryozha to leave the room. As a compensation, Seryozha made Dima do his homework.
The teacher g... | ```python
n=int(input())
x=list(map(int,input().split()))
for i in range(len(x)-3):
x1,x2,x2,x4 = x[i],x[i+1],x[i+2],x[i+3]
if x1<x3<x2<x4:
print("yes")
exit()
elif x3<x1<x4<x2:
print("yes")
exit()
print('no')
``` | -1 | |
463 | B | Caisa and Pylons | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"math"
] | null | null | Caisa solved the problem with the sugar and now he is on the way back to home.
Caisa is playing a mobile game during his path. There are (*n*<=+<=1) pylons numbered from 0 to *n* in this game. The pylon with number 0 has zero height, the pylon with number *i* (*i*<=><=0) has height *h**i*. The goal of the game is ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *h*1, *h*2,<=..., *h**n* (1<=<=≤<=<=*h**i*<=<=≤<=<=105) representing the heights of the pylons. | Print a single number representing the minimum number of dollars paid by Caisa. | [
"5\n3 4 3 2 4\n",
"3\n4 4 4\n"
] | [
"4\n",
"4\n"
] | In the first sample he can pay 4 dollars and increase the height of pylon with number 0 by 4 units. Then he can safely pass to the last pylon. | 1,000 | [
{
"input": "5\n3 4 3 2 4",
"output": "4"
},
{
"input": "3\n4 4 4",
"output": "4"
},
{
"input": "99\n1401 2019 1748 3785 3236 3177 3443 3772 2138 1049 353 908 310 2388 1322 88 2160 2783 435 2248 1471 706 2468 2319 3156 3506 2794 1999 1983 2519 2597 3735 537 344 3519 3772 3872 2961 3895 20... | 1,676,974,396 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | a=int(input())
b=input()
b1=b.split(' ')
b1.sort()
print(b1[-1]) | Title: Caisa and Pylons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Caisa solved the problem with the sugar and now he is on the way back to home.
Caisa is playing a mobile game during his path. There are (*n*<=+<=1) pylons numbered from 0 to *n* in this game. The pylon with number 0... | ```python
a=int(input())
b=input()
b1=b.split(' ')
b1.sort()
print(b1[-1])
``` | 0 | |
811 | A | Vladik and Courtesy | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | At regular competition Vladik and Valera won *a* and *b* candies respectively. Vladik offered 1 his candy to Valera. After that Valera gave Vladik 2 his candies, so that no one thought that he was less generous. Vladik for same reason gave 3 candies to Valera in next turn.
More formally, the guys take turns giving eac... | Single line of input data contains two space-separated integers *a*, *b* (1<=≤<=*a*,<=*b*<=≤<=109) — number of Vladik and Valera candies respectively. | Pring a single line "Vladik’’ in case, if Vladik first who can’t give right amount of candy, or "Valera’’ otherwise. | [
"1 1\n",
"7 6\n"
] | [
"Valera\n",
"Vladik\n"
] | Illustration for first test case:
<img class="tex-graphics" src="https://espresso.codeforces.com/ad9b7d0e481208de8e3a585aa1d96b9e1dda4fd7.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Illustration for second test case:
<img class="tex-graphics" src="https://espresso.codeforces.com/9f4836d2ccdffaee5a63898e5d4e... | 500 | [
{
"input": "1 1",
"output": "Valera"
},
{
"input": "7 6",
"output": "Vladik"
},
{
"input": "25 38",
"output": "Vladik"
},
{
"input": "8311 2468",
"output": "Valera"
},
{
"input": "250708 857756",
"output": "Vladik"
},
{
"input": "957985574 24997558",
... | 1,555,854,357 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 109 | 0 | a,b = map(int,input().split())
s = int(a**(1/2))
t = int((-1+(1+4*b)**(1/2))/2)
if s>t:
print("Valera")
else:
print("Vladik")
| Title: Vladik and Courtesy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
At regular competition Vladik and Valera won *a* and *b* candies respectively. Vladik offered 1 his candy to Valera. After that Valera gave Vladik 2 his candies, so that no one thought that he was less generous. Vla... | ```python
a,b = map(int,input().split())
s = int(a**(1/2))
t = int((-1+(1+4*b)**(1/2))/2)
if s>t:
print("Valera")
else:
print("Vladik")
``` | 3 | |
415 | B | Mashmokh and Tokens | PROGRAMMING | 1,500 | [
"binary search",
"greedy",
"implementation",
"math"
] | null | null | Bimokh is Mashmokh's boss. For the following *n* days he decided to pay to his workers in a new way. At the beginning of each day he will give each worker a certain amount of tokens. Then at the end of each day each worker can give some of his tokens back to get a certain amount of money. The worker can save the rest o... | The first line of input contains three space-separated integers *n*,<=*a*,<=*b* (1<=≤<=*n*<=≤<=105; 1<=≤<=*a*,<=*b*<=≤<=109). The second line of input contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=109). | Output *n* space-separated integers. The *i*-th of them is the number of tokens Mashmokh can save on the *i*-th day. | [
"5 1 4\n12 6 11 9 1\n",
"3 1 2\n1 2 3\n",
"1 1 1\n1\n"
] | [
"0 2 3 1 1 ",
"1 0 1 ",
"0 "
] | none | 1,000 | [
{
"input": "5 1 4\n12 6 11 9 1",
"output": "0 2 3 1 1 "
},
{
"input": "3 1 2\n1 2 3",
"output": "1 0 1 "
},
{
"input": "1 1 1\n1",
"output": "0 "
},
{
"input": "1 1 1000000000\n1000000000",
"output": "0 "
},
{
"input": "1 1 1000000000\n999999999",
"output": "9... | 1,396,800,685 | 1,885 | Python 3 | COMPILATION_ERROR | PRETESTS | 0 | 0 | 0 |
def main():
N,A,B = map(lambda x:int(x),raw_input().split())
P = map(lambda x:int(x),raw_input().split())
answer = []
for i in range(N):
x = P[i]
answer.append(x - ((x * A) / B) * B)
print " ".join(str(x) for x in answer)
return 0
main()
| Title: Mashmokh and Tokens
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bimokh is Mashmokh's boss. For the following *n* days he decided to pay to his workers in a new way. At the beginning of each day he will give each worker a certain amount of tokens. Then at the end of each day each... | ```python
def main():
N,A,B = map(lambda x:int(x),raw_input().split())
P = map(lambda x:int(x),raw_input().split())
answer = []
for i in range(N):
x = P[i]
answer.append(x - ((x * A) / B) * B)
print " ".join(str(x) for x in answer)
return 0
main()
``` | -1 | |
111 | E | Petya and Rectangle | PROGRAMMING | 2,900 | [] | E. Petya and Rectangle | 5 | 256 | Little Petya loves playing with rectangles. Mom bought Petya a rectangle divided into cells *n*<=×<=*m* in size (containing *n* rows, *m* columns). Petya marked two different cells of the rectangle and now he is solving the following task:
Let's define a simple path between those two cells as a sequence of distinct ce... | The first line contains space-separated integers *n* and *m* (4<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and the number of columns in the rectangle, correspondingly. The second line contains space-separated integers *x*1 and *y*1 — the coordinates of the first marked cell. The third line contains space-separated in... | In the first line print the length of the found path — *k*. In the next lines print *k* pairs of integers, one per line — coordinates of the cells that constitute the found path in the order, in which they follow in the path (the path must go from cell (*x*1,<=*y*1) to cell (*x*2,<=*y*2)). If there are several solution... | [
"4 4\n2 2\n3 3\n"
] | [
"15\n2 2\n1 2\n1 1\n2 1\n3 1\n4 1\n4 2\n4 3\n4 4\n3 4\n2 4\n1 4\n1 3\n2 3\n3 3\n"
] | The statement test is described in the picture: | 2,500 | [] | 1,696,753,342 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 122 | 0 | n, m = map(int, input().split())
x1, y1 = map(int, input().split())
x2, y2 = map(int, input().split())
path = []
path_length = 0
# Go from (x1, y1) to (x1, 1)
for y in range(y1, 0, -1):
path.append((x1, y))
path_length += 1
# Go from (x1, 1) to (1, 1)
for x in range(x1, 0, -1):
path.append(... | Title: Petya and Rectangle
Time Limit: 5 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya loves playing with rectangles. Mom bought Petya a rectangle divided into cells *n*<=×<=*m* in size (containing *n* rows, *m* columns). Petya marked two different cells of the rectangle and now he is solving... | ```python
n, m = map(int, input().split())
x1, y1 = map(int, input().split())
x2, y2 = map(int, input().split())
path = []
path_length = 0
# Go from (x1, y1) to (x1, 1)
for y in range(y1, 0, -1):
path.append((x1, y))
path_length += 1
# Go from (x1, 1) to (1, 1)
for x in range(x1, 0, -1):
pa... | 0 |
242 | B | Big Segment | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all oth... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of segments. Next *n* lines contain the descriptions of the segments. The *i*-th line contains two space-separated integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109) — the borders of the *i*-th segment.
It is guaranteed that no two segments c... | Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input. | [
"3\n1 1\n2 2\n3 3\n",
"6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10\n"
] | [
"-1\n",
"3\n"
] | none | 1,000 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "-1"
},
{
"input": "6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10",
"output": "3"
},
{
"input": "4\n1 5\n2 2\n2 4\n2 5",
"output": "1"
},
{
"input": "5\n3 3\n1 3\n2 2\n2 3\n1 2",
"output": "2"
},
{
"input": "7\n7 7\n8 8\n3 7\n1 6\n1 ... | 1,523,811,313 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 154 | 7,065,600 | n = int(input())
A = []
for i in range(n):
A.append([])
A[i] = list(map(int, input().split()))
li = 1
ri = 1
res = -1
for i in range(n):
if li > A[i][0] and A[i][1] < ri:
print(-1)
exit()
if li < A[i][0] and A[i][1] > ri:
print(-1)
exit()
if li >= A[i][... | Title: Big Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments ... | ```python
n = int(input())
A = []
for i in range(n):
A.append([])
A[i] = list(map(int, input().split()))
li = 1
ri = 1
res = -1
for i in range(n):
if li > A[i][0] and A[i][1] < ri:
print(-1)
exit()
if li < A[i][0] and A[i][1] > ri:
print(-1)
exit()
if l... | 0 | |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another c... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follo... | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,658,740,339 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 46 | 0 | n = int(input())
c_list = list(map(int, input().split()))
f_node = n - 1 # Farthest Node
print(c_list[1] - c_list[0], c_list[f_node] - c_list[0]) # for 1st Node
for i in range(1, n //2): # for nodes upto n // 2
if ( c_list[i + 1] - c_list[i] < c_list[i] - c_list[i - 1]):
print(c_list[i... | Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love... | ```python
n = int(input())
c_list = list(map(int, input().split()))
f_node = n - 1 # Farthest Node
print(c_list[1] - c_list[0], c_list[f_node] - c_list[0]) # for 1st Node
for i in range(1, n //2): # for nodes upto n // 2
if ( c_list[i + 1] - c_list[i] < c_list[i] - c_list[i - 1]):
prin... | 0 | |
710 | C | Magic Odd Square | PROGRAMMING | 1,500 | [
"constructive algorithms",
"math"
] | null | null | Find an *n*<=×<=*n* matrix with different numbers from 1 to *n*2, so the sum in each row, column and both main diagonals are odd. | The only line contains odd integer *n* (1<=≤<=*n*<=≤<=49). | Print *n* lines with *n* integers. All the integers should be different and from 1 to *n*2. The sum in each row, column and both main diagonals should be odd. | [
"1\n",
"3\n"
] | [
"1\n",
"2 1 4\n3 5 7\n6 9 8\n"
] | none | 0 | [
{
"input": "1",
"output": "1"
},
{
"input": "3",
"output": "2 1 4\n3 5 7\n6 9 8"
},
{
"input": "5",
"output": "2 4 1 6 8\n10 3 5 7 12\n9 11 13 15 17\n14 19 21 23 16\n18 20 25 22 24"
},
{
"input": "7",
"output": "2 4 6 1 8 10 12\n14 16 3 5 7 18 20\n22 9 11 13 15 17 24\n19 ... | 1,471,953,303 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 4,608,000 | n = int(input())
s = [i for i in range(2, n ** 2 + 1)] + [1]
Ans = [[0] * (n) for i in range(n)]
if n == 1:
print(1)
else:
for i in range(n):
for j in range(n):
Ans[i][j] = s[i * n + j]
Ans[n-1][n-1], Ans[n//2][n//2] = Ans[n//2][n//2], Ans[n-1][n-1]
for i in range(n):
... | Title: Magic Odd Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Find an *n*<=×<=*n* matrix with different numbers from 1 to *n*2, so the sum in each row, column and both main diagonals are odd.
Input Specification:
The only line contains odd integer *n* (1<=≤<=*n*<=≤<=49).
Output... | ```python
n = int(input())
s = [i for i in range(2, n ** 2 + 1)] + [1]
Ans = [[0] * (n) for i in range(n)]
if n == 1:
print(1)
else:
for i in range(n):
for j in range(n):
Ans[i][j] = s[i * n + j]
Ans[n-1][n-1], Ans[n//2][n//2] = Ans[n//2][n//2], Ans[n-1][n-1]
for i in ran... | 0 | |
602 | B | Approximating a Constant Range | PROGRAMMING | 1,400 | [
"dp",
"implementation",
"two pointers"
] | null | null | When Xellos was doing a practice course in university, he once had to measure the intensity of an effect that slowly approached equilibrium. A good way to determine the equilibrium intensity would be choosing a sufficiently large number of consecutive data points that seems as constant as possible and taking their aver... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000) — the number of data points.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100<=000). | Print a single number — the maximum length of an almost constant range of the given sequence. | [
"5\n1 2 3 3 2\n",
"11\n5 4 5 5 6 7 8 8 8 7 6\n"
] | [
"4\n",
"5\n"
] | In the first sample, the longest almost constant range is [2, 5]; its length (the number of data points in it) is 4.
In the second sample, there are three almost constant ranges of length 4: [1, 4], [6, 9] and [7, 10]; the only almost constant range of the maximum length 5 is [6, 10]. | 1,000 | [
{
"input": "5\n1 2 3 3 2",
"output": "4"
},
{
"input": "11\n5 4 5 5 6 7 8 8 8 7 6",
"output": "5"
},
{
"input": "2\n3 2",
"output": "2"
},
{
"input": "4\n1001 1000 1000 1001",
"output": "4"
},
{
"input": "4\n1 1 2 3",
"output": "3"
},
{
"input": "3\n1 ... | 1,506,432,291 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 296 | 5,939,200 | N = int(input())
a_list = input().split()
for i in range(N):
a_list[i] = int(a_list[i])
left = 0
right = 0
result = 0
addition = 0
max_one = -1
while(left < N and right < N):
min_one=max_one = a_list[left]
flag = True
while(flag):
if(a_list[right]>max_one):
max_one = a_lis... | Title: Approximating a Constant Range
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Xellos was doing a practice course in university, he once had to measure the intensity of an effect that slowly approached equilibrium. A good way to determine the equilibrium intensity would be choo... | ```python
N = int(input())
a_list = input().split()
for i in range(N):
a_list[i] = int(a_list[i])
left = 0
right = 0
result = 0
addition = 0
max_one = -1
while(left < N and right < N):
min_one=max_one = a_list[left]
flag = True
while(flag):
if(a_list[right]>max_one):
max_o... | 0 | |
413 | A | Data Recovery | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Not so long ago company R2 bought company R1 and consequently, all its developments in the field of multicore processors. Now the R2 laboratory is testing one of the R1 processors.
The testing goes in *n* steps, at each step the processor gets some instructions, and then its temperature is measured. The head engineer ... | The first line contains four integers *n*,<=*m*,<=*min*,<=*max* (1<=≤<=*m*<=<<=*n*<=≤<=100; 1<=≤<=*min*<=<<=*max*<=≤<=100). The second line contains *m* space-separated integers *t**i* (1<=≤<=*t**i*<=≤<=100) — the temperatures reported by the assistant.
Note, that the reported temperatures, and the temperatures ... | If the data is consistent, print 'Correct' (without the quotes). Otherwise, print 'Incorrect' (without the quotes). | [
"2 1 1 2\n1\n",
"3 1 1 3\n2\n",
"2 1 1 3\n2\n"
] | [
"Correct\n",
"Correct\n",
"Incorrect\n"
] | In the first test sample one of the possible initial configurations of temperatures is [1, 2].
In the second test sample one of the possible initial configurations of temperatures is [2, 1, 3].
In the third test sample it is impossible to add one temperature to obtain the minimum equal to 1 and the maximum equal to 3... | 500 | [
{
"input": "2 1 1 2\n1",
"output": "Correct"
},
{
"input": "3 1 1 3\n2",
"output": "Correct"
},
{
"input": "2 1 1 3\n2",
"output": "Incorrect"
},
{
"input": "3 1 1 5\n3",
"output": "Correct"
},
{
"input": "3 2 1 5\n1 5",
"output": "Correct"
},
{
"input... | 1,556,188,916 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 0 | n,m,min_,max_=map(int,input().split())
l=list(map(int,input().split()))
if max_-min_==n-m:
print('Correct')
else:
print('Incorrect') | Title: Data Recovery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Not so long ago company R2 bought company R1 and consequently, all its developments in the field of multicore processors. Now the R2 laboratory is testing one of the R1 processors.
The testing goes in *n* steps, at each ... | ```python
n,m,min_,max_=map(int,input().split())
l=list(map(int,input().split()))
if max_-min_==n-m:
print('Correct')
else:
print('Incorrect')
``` | 0 | |
753 | A | Santa Claus and Candies | PROGRAMMING | 1,000 | [
"dp",
"greedy",
"math"
] | null | null | Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all *n* candies he has. | The only line contains positive integer number *n* (1<=≤<=*n*<=≤<=1000) — number of candies Santa Claus has. | Print to the first line integer number *k* — maximal number of kids which can get candies.
Print to the second line *k* distinct integer numbers: number of candies for each of *k* kid. The sum of *k* printed numbers should be exactly *n*.
If there are many solutions, print any of them. | [
"5\n",
"9\n",
"2\n"
] | [
"2\n2 3\n",
"3\n3 5 1\n",
"1\n2 \n"
] | none | 500 | [
{
"input": "5",
"output": "2\n1 4 "
},
{
"input": "9",
"output": "3\n1 2 6 "
},
{
"input": "2",
"output": "1\n2 "
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "3",
"output": "2\n1 2 "
},
{
"input": "1000",
"output": "44\n1 2 3 4 5 6 7 8 9 10 ... | 1,564,749,449 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 187 | 2,457,600 | n = int(input())
cur = 1
candies = []
while cur <= n:
candies.push(cur)
n -= cur
cur += 1
candies[-1] += n
print(len(candies))
print(*candies) | Title: Santa Claus and Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer n... | ```python
n = int(input())
cur = 1
candies = []
while cur <= n:
candies.push(cur)
n -= cur
cur += 1
candies[-1] += n
print(len(candies))
print(*candies)
``` | -1 | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,698,595,336 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | n = int(input())
h = int(input())
w = 0
for i in range(0, n):
p = int(input())
if p > h:
w += 2
else:
w += 1
print(w) | Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
n = int(input())
h = int(input())
w = 0
for i in range(0, n):
p = int(input())
if p > h:
w += 2
else:
w += 1
print(w)
``` | -1 | |
582 | A | GCD Table | PROGRAMMING | 1,700 | [
"constructive algorithms",
"greedy",
"number theory"
] | null | null | The GCD table *G* of size *n*<=×<=*n* for an array of positive integers *a* of length *n* is defined by formula
Let us remind you that the greatest common divisor (GCD) of two positive integers *x* and *y* is the greatest integer that is divisor of both *x* and *y*, it is denoted as . For example, for array *a*<==<={... | The first line contains number *n* (1<=≤<=*n*<=≤<=500) — the length of array *a*. The second line contains *n*2 space-separated numbers — the elements of the GCD table of *G* for array *a*.
All the numbers in the table are positive integers, not exceeding 109. Note that the elements are given in an arbitrary order. I... | In the single line print *n* positive integers — the elements of array *a*. If there are multiple possible solutions, you are allowed to print any of them. | [
"4\n2 1 2 3 4 3 2 6 1 1 2 2 1 2 3 2\n",
"1\n42\n",
"2\n1 1 1 1\n"
] | [
"4 3 6 2",
"42 ",
"1 1 "
] | none | 750 | [
{
"input": "4\n2 1 2 3 4 3 2 6 1 1 2 2 1 2 3 2",
"output": "2 3 4 6 "
},
{
"input": "1\n42",
"output": "42 "
},
{
"input": "2\n1 1 1 1",
"output": "1 1 "
},
{
"input": "2\n54748096 1 641009859 1",
"output": "54748096 641009859 "
},
{
"input": "3\n1 7 923264237 374... | 1,605,844,751 | 2,147,483,647 | PyPy 3 | OK | TESTS | 54 | 374 | 16,179,200 | import math
from collections import Counter
n=int(input())
count_=Counter(map(int,input().split()))
ans=[]
for i in range(n):
big = max(count_)
count_[big]-=1
for other in ans:
a=math.gcd(other,big)#;b= math.gcd(other,big)
count_[a]-=2
ans.append(big)
count_+=Counter(... | Title: GCD Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The GCD table *G* of size *n*<=×<=*n* for an array of positive integers *a* of length *n* is defined by formula
Let us remind you that the greatest common divisor (GCD) of two positive integers *x* and *y* is the greatest i... | ```python
import math
from collections import Counter
n=int(input())
count_=Counter(map(int,input().split()))
ans=[]
for i in range(n):
big = max(count_)
count_[big]-=1
for other in ans:
a=math.gcd(other,big)#;b= math.gcd(other,big)
count_[a]-=2
ans.append(big)
count_... | 3 | |
20 | B | Equation | PROGRAMMING | 2,000 | [
"math"
] | B. Equation | 1 | 256 | You are given an equation:
Your task is to find the number of distinct roots of the equation and print all of them in ascending order. | The first line contains three integer numbers *A*,<=*B* and *C* (<=-<=105<=≤<=*A*,<=*B*,<=*C*<=≤<=105). Any coefficient may be equal to 0. | In case of infinite root count print the only integer -1. In case of no roots print the only integer 0. In other cases print the number of root on the first line and the roots on the following lines in the ascending order. Print roots with at least 5 digits after the decimal point. | [
"1 -5 6\n"
] | [
"2\n2.0000000000\n3.0000000000"
] | none | 1,000 | [
{
"input": "1 -5 6",
"output": "2\n2.0000000000\n3.0000000000"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 2 1",
"output": "1\n-1.0000000000"
},
{
"input": "0 0 0",
"output": "-1"
},
{
"input": "0 -2 1",
"output": "1\n0.5000000000"
},
{
"inpu... | 1,570,722,044 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 13 | 140 | 0 | from math import *
a,b,c = [int(i) for i in input().split()]
d = b**2 - 4*a*c
if a == 0:
if b == 0:
if c == 0:
print(-1)
else:
print(0)
else:
print(1)
print(-c/b)
else:
if d > 0:
print(2)
print((-b-sqrt(d))/(2*a))
... | Title: Equation
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given an equation:
Your task is to find the number of distinct roots of the equation and print all of them in ascending order.
Input Specification:
The first line contains three integer numbers *A*,<=*B* and *C* (<=-<=1... | ```python
from math import *
a,b,c = [int(i) for i in input().split()]
d = b**2 - 4*a*c
if a == 0:
if b == 0:
if c == 0:
print(-1)
else:
print(0)
else:
print(1)
print(-c/b)
else:
if d > 0:
print(2)
print((-b-sqrt(d))/(2*a... | 0 |
16 | B | Burglar and Matches | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | B. Burglar and Matches | 0 | 64 | A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactl... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer. | Output the only number — answer to the problem. | [
"7 3\n5 10\n2 5\n3 6\n",
"3 3\n1 3\n2 2\n3 1\n"
] | [
"62\n",
"7\n"
] | none | 0 | [
{
"input": "7 3\n5 10\n2 5\n3 6",
"output": "62"
},
{
"input": "3 3\n1 3\n2 2\n3 1",
"output": "7"
},
{
"input": "1 1\n1 2",
"output": "2"
},
{
"input": "1 2\n1 9\n1 6",
"output": "9"
},
{
"input": "1 10\n1 1\n1 9\n1 3\n1 9\n1 7\n1 10\n1 4\n1 7\n1 3\n1 1",
"ou... | 1,584,150,506 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 8 | 216 | 307,200 | n,m = map(int, input().split())
matches = {}
count = 0
for i in range(m):
j,k = map(int, input().split())
repeated = 0
for e in matches.keys():
if e == k:
repeated = 1
matches[k] += j
if repeated == 0:
matches[k] = j
while n > 0:
biggest = max(mat... | Title: Burglar and Matches
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* mat... | ```python
n,m = map(int, input().split())
matches = {}
count = 0
for i in range(m):
j,k = map(int, input().split())
repeated = 0
for e in matches.keys():
if e == k:
repeated = 1
matches[k] += j
if repeated == 0:
matches[k] = j
while n > 0:
biggest... | -1 |
869 | B | The Eternal Immortality | PROGRAMMING | 1,100 | [
"math"
] | null | null | Even if the world is full of counterfeits, I still regard it as wonderful.
Pile up herbs and incense, and arise again from the flames and ashes of its predecessor — as is known to many, the phoenix does it like this.
The phoenix has a rather long lifespan, and reincarnates itself once every *a*! years. Here *a*! deno... | The first and only line of input contains two space-separated integers *a* and *b* (0<=≤<=*a*<=≤<=*b*<=≤<=1018). | Output one line containing a single decimal digit — the last digit of the value that interests Koyomi. | [
"2 4\n",
"0 10\n",
"107 109\n"
] | [
"2\n",
"0\n",
"2\n"
] | In the first example, the last digit of <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/99c47ca8b182f097e38094d12f0c06ce0b081b76.png" style="max-width: 100.0%;max-height: 100.0%;"/> is 2;
In the second example, the last digit of <img align="middle" class="tex-formula" src="https://espresso... | 1,000 | [
{
"input": "2 4",
"output": "2"
},
{
"input": "0 10",
"output": "0"
},
{
"input": "107 109",
"output": "2"
},
{
"input": "10 13",
"output": "6"
},
{
"input": "998244355 998244359",
"output": "4"
},
{
"input": "999999999000000000 1000000000000000000",
... | 1,507,796,032 | 2,147,483,647 | PyPy 3 | OK | TESTS | 63 | 109 | 307,200 | a, b = map(int, input().split())
if (b - a < 15):
ans = 1
for i in range(a + 1, b + 1):
ans *= max(i, 1)
ans %= 10
print(ans % 10)
else:
print(0)
| Title: The Eternal Immortality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Even if the world is full of counterfeits, I still regard it as wonderful.
Pile up herbs and incense, and arise again from the flames and ashes of its predecessor — as is known to many, the phoenix does it like... | ```python
a, b = map(int, input().split())
if (b - a < 15):
ans = 1
for i in range(a + 1, b + 1):
ans *= max(i, 1)
ans %= 10
print(ans % 10)
else:
print(0)
``` | 3 | |
622 | A | Infinite Sequence | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains ... | The only line contains integer *n* (1<=≤<=*n*<=≤<=1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | Print the element in the *n*-th position of the sequence (the elements are numerated from one). | [
"3\n",
"5\n",
"10\n",
"55\n",
"56\n"
] | [
"2\n",
"2\n",
"4\n",
"10\n",
"1\n"
] | none | 0 | [
{
"input": "3",
"output": "2"
},
{
"input": "5",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "55",
"output": "10"
},
{
"input": "56",
"output": "1"
},
{
"input": "1000000000000",
"output": "88209"
},
{
"input": "8471941278... | 1,621,286,727 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 0 | n = int(input())
x = 1
while n > x:
n -= x
x += 1
print(n)
"""
let n = 9
1 x = 1 n = n - x ;8
1 2 x = 2 n = 8 - 2 ;6
1 2 3 x = 3 n = 6 - 3 ;3 ans
1 2 3 4 x = 4 n = 3 - 4 ;-1 break
1 2 3 4 5 x = 5
""" | Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2,... | ```python
n = int(input())
x = 1
while n > x:
n -= x
x += 1
print(n)
"""
let n = 9
1 x = 1 n = n - x ;8
1 2 x = 2 n = 8 - 2 ;6
1 2 3 x = 3 n = 6 - 3 ;3 ans
1 2 3 4 x = 4 n = 3 - 4 ;-1 break
1 2 3 4 5 x = 5
"""
``` | 0 | |
214 | A | System of Equations | PROGRAMMING | 800 | [
"brute force"
] | null | null | Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of int... | A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space. | On a single line print the answer to the problem. | [
"9 3\n",
"14 28\n",
"4 20\n"
] | [
"1\n",
"1\n",
"0\n"
] | In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair. | 500 | [
{
"input": "9 3",
"output": "1"
},
{
"input": "14 28",
"output": "1"
},
{
"input": "4 20",
"output": "0"
},
{
"input": "18 198",
"output": "1"
},
{
"input": "22 326",
"output": "1"
},
{
"input": "26 104",
"output": "1"
},
{
"input": "14 10"... | 1,655,094,454 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 11 | 746 | 0 | n,m=map(int,input().split())
i=1
j=0
count=0
while i<1000:
j=0
while j<1000:
if (i*i)+j==n and (j*j)+i==m:
count+=1
j+=1
i+=1
print(count) | Title: System of Equations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immedi... | ```python
n,m=map(int,input().split())
i=1
j=0
count=0
while i<1000:
j=0
while j<1000:
if (i*i)+j==n and (j*j)+i==m:
count+=1
j+=1
i+=1
print(count)
``` | 0 | |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,635,154,653 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 9 | 92 | 4,300,800 | s=list(input())
s.pop(s.index('0'))
print(''.join(s)) | Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
s=list(input())
s.pop(s.index('0'))
print(''.join(s))
``` | -1 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Limak is an old brown bear. He often plays poker with his friends. Today they went to a casino. There are *n* players (including Limak himself) and right now all of them have bids on the table. *i*-th of them has bid with size *a**i* dollars.
Each player can double his bid any number of times and triple his bid any nu... | First line of input contains an integer *n* (2<=≤<=*n*<=≤<=105), the number of players.
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the bids of players. | Print "Yes" (without the quotes) if players can make their bids become equal, or "No" otherwise. | [
"4\n75 150 75 50\n",
"3\n100 150 250\n"
] | [
"Yes\n",
"No\n"
] | In the first sample test first and third players should double their bids twice, second player should double his bid once and fourth player should both double and triple his bid.
It can be shown that in the second sample test there is no way to make all bids equal. | 0 | [
{
"input": "4\n75 150 75 50",
"output": "Yes"
},
{
"input": "3\n100 150 250",
"output": "No"
},
{
"input": "7\n34 34 68 34 34 68 34",
"output": "Yes"
},
{
"input": "10\n72 96 12 18 81 20 6 2 54 1",
"output": "No"
},
{
"input": "20\n958692492 954966768 77387000 724... | 1,440,868,719 | 2,919 | Python 3 | WRONG_ANSWER | TESTS | 20 | 873 | 7,065,600 | n = int(input())
a = list(map(int, input().split()))
m = max(a)
m *= (3 ** 10)
m *= (2 ** 15)
st = True
i = 0
while i < n and st:
mo = m // a[i]
while mo % 2 == 0 and mo != 1:
mo //= 2
while mo % 3 == 0 and mo != 1:
mo //= 3
if mo != 1:
st = False
i += 1
if st... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is an old brown bear. He often plays poker with his friends. Today they went to a casino. There are *n* players (including Limak himself) and right now all of them have bids on the table. *i*-th of them has bid with size *a*... | ```python
n = int(input())
a = list(map(int, input().split()))
m = max(a)
m *= (3 ** 10)
m *= (2 ** 15)
st = True
i = 0
while i < n and st:
mo = m // a[i]
while mo % 2 == 0 and mo != 1:
mo //= 2
while mo % 3 == 0 and mo != 1:
mo //= 3
if mo != 1:
st = False
i +... | 0 | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,662,619,194 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 187 | 0 | x=int(input());l=list(map(int,input().split()));c=min(l.count(2),l.count(1),l.count(3))
if c==0: print(c)
else:
print(c)
for i in range(c):
ll=[];o=l.index(1);ll.append(o+1);l[o]=0;o=l.index(2);ll.append(o+1);l[o]=0;o=l.index(3);ll.append(o+1);l[o]=0;print(*ll) | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
x=int(input());l=list(map(int,input().split()));c=min(l.count(2),l.count(1),l.count(3))
if c==0: print(c)
else:
print(c)
for i in range(c):
ll=[];o=l.index(1);ll.append(o+1);l[o]=0;o=l.index(2);ll.append(o+1);l[o]=0;o=l.index(3);ll.append(o+1);l[o]=0;print(*ll)
``` | 3 | |
842 | A | Kirill And The Game | PROGRAMMING | 1,200 | [
"brute force",
"two pointers"
] | null | null | Kirill plays a new computer game. He came to the potion store where he can buy any potion. Each potion is characterized by two integers — amount of experience and cost. The efficiency of a potion is the ratio of the amount of experience to the cost. Efficiency may be a non-integer number.
For each two integer numbers ... | First string contains five integer numbers *l*, *r*, *x*, *y*, *k* (1<=≤<=*l*<=≤<=*r*<=≤<=107, 1<=≤<=*x*<=≤<=*y*<=≤<=107, 1<=≤<=*k*<=≤<=107). | Print "YES" without quotes if a potion with efficiency exactly *k* can be bought in the store and "NO" without quotes otherwise.
You can output each of the letters in any register. | [
"1 10 1 10 1\n",
"1 5 6 10 1\n"
] | [
"YES",
"NO"
] | none | 500 | [
{
"input": "1 10 1 10 1",
"output": "YES"
},
{
"input": "1 5 6 10 1",
"output": "NO"
},
{
"input": "1 1 1 1 1",
"output": "YES"
},
{
"input": "1 1 1 1 2",
"output": "NO"
},
{
"input": "1 100000 1 100000 100000",
"output": "YES"
},
{
"input": "1 100000 ... | 1,582,005,730 | 2,147,483,647 | PyPy 3 | OK | TESTS | 101 | 311 | 1,331,200 | l, r, x, y, k = tuple(map(int, input().split(' ')))
for i in range(x, y+1):
if l <= i * k <= r:
print("YES")
break
else:
print("NO")
| Title: Kirill And The Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kirill plays a new computer game. He came to the potion store where he can buy any potion. Each potion is characterized by two integers — amount of experience and cost. The efficiency of a potion is the ratio of the... | ```python
l, r, x, y, k = tuple(map(int, input().split(' ')))
for i in range(x, y+1):
if l <= i * k <= r:
print("YES")
break
else:
print("NO")
``` | 3 | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,600,846,051 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 280 | 307,200 | z=input()
o=0
while len(z)>1:
c=0
for i in z:
c+=int(i)
z=str(c)
o+=1
print(o)
| Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
z=input()
o=0
while len(z)>1:
c=0
for i in z:
c+=int(i)
z=str(c)
o+=1
print(o)
``` | 3.929447 |
143 | A | Help Vasilisa the Wise 2 | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Vasilisa the Wise from the Kingdom of Far Far Away got a magic box with a secret as a present from her friend Hellawisa the Wise from the Kingdom of A Little Closer. However, Vasilisa the Wise does not know what the box's secret is, since she cannot open it again. She hopes that you will help her one more time with tha... | The input contains numbers written on the edges of the lock of the box. The first line contains space-separated integers *r*1 and *r*2 that define the required sums of numbers in the rows of the square. The second line contains space-separated integers *c*1 and *c*2 that define the required sums of numbers in the colum... | Print the scheme of decorating the box with stones: two lines containing two space-separated integers from 1 to 9. The numbers should be pairwise different. If there is no solution for the given lock, then print the single number "-1" (without the quotes).
If there are several solutions, output any. | [
"3 7\n4 6\n5 5\n",
"11 10\n13 8\n5 16\n",
"1 2\n3 4\n5 6\n",
"10 10\n10 10\n10 10\n"
] | [
"1 2\n3 4\n",
"4 7\n9 1\n",
"-1\n",
"-1\n"
] | Pay attention to the last test from the statement: it is impossible to open the box because for that Vasilisa the Wise would need 4 identical gems containing number "5". However, Vasilisa only has one gem with each number from 1 to 9. | 500 | [
{
"input": "3 7\n4 6\n5 5",
"output": "1 2\n3 4"
},
{
"input": "11 10\n13 8\n5 16",
"output": "4 7\n9 1"
},
{
"input": "1 2\n3 4\n5 6",
"output": "-1"
},
{
"input": "10 10\n10 10\n10 10",
"output": "-1"
},
{
"input": "5 13\n8 10\n11 7",
"output": "3 2\n5 8"
... | 1,657,578,730 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 62 | 0 | from sys import stdin
matrix = []
for t in range(3):
nums = [int(x) for x in stdin.readline().strip().split(" ")]
matrix.append(nums)
r1 ,r2, c1, c2, d1, d2 = matrix[0][0], matrix[0][1], matrix[1][0], matrix[1][1], matrix[2][0], matrix[2][1]
x = 1
flag = True
while x <= 9:
a = abs(r1 - x)
b = ... | Title: Help Vasilisa the Wise 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasilisa the Wise from the Kingdom of Far Far Away got a magic box with a secret as a present from her friend Hellawisa the Wise from the Kingdom of A Little Closer. However, Vasilisa the Wise does not know wha... | ```python
from sys import stdin
matrix = []
for t in range(3):
nums = [int(x) for x in stdin.readline().strip().split(" ")]
matrix.append(nums)
r1 ,r2, c1, c2, d1, d2 = matrix[0][0], matrix[0][1], matrix[1][0], matrix[1][1], matrix[2][0], matrix[2][1]
x = 1
flag = True
while x <= 9:
a = abs(r1 - x)... | 0 | |
337 | A | Puzzles | PROGRAMMING | 900 | [
"greedy"
] | null | null | The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, as wikipedia states, is a tiling puzzle that requires the assembly of numerous small, often od... | The first line contains space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=*m*<=≤<=50). The second line contains *m* space-separated integers *f*1,<=*f*2,<=...,<=*f**m* (4<=≤<=*f**i*<=≤<=1000) — the quantities of pieces in the puzzles sold in the shop. | Print a single integer — the least possible difference the teacher can obtain. | [
"4 6\n10 12 10 7 5 22\n"
] | [
"5\n"
] | Sample 1. The class has 4 students. The shop sells 6 puzzles. If Ms. Manana buys the first four puzzles consisting of 10, 12, 10 and 7 pieces correspondingly, then the difference between the sizes of the largest and the smallest puzzle will be equal to 5. It is impossible to obtain a smaller difference. Note that the t... | 500 | [
{
"input": "4 6\n10 12 10 7 5 22",
"output": "5"
},
{
"input": "2 2\n4 4",
"output": "0"
},
{
"input": "2 10\n4 5 6 7 8 9 10 11 12 12",
"output": "0"
},
{
"input": "4 5\n818 136 713 59 946",
"output": "759"
},
{
"input": "3 20\n446 852 783 313 549 965 40 88 86 617... | 1,698,586,464 | 2,147,483,647 | Python 3 | OK | TESTS | 18 | 62 | 0 | n,m=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
ans=1001
if m==2:
print(a[1]-a[0])
else:
for i in range(m-n+1):
k=a[i+n-1]-a[i]
if k<ans:
ans=k
print(ans) | Title: Puzzles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, a... | ```python
n,m=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
ans=1001
if m==2:
print(a[1]-a[0])
else:
for i in range(m-n+1):
k=a[i+n-1]-a[i]
if k<ans:
ans=k
print(ans)
``` | 3 |
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