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Find the name of dorms only for female (F gender).
SELECT dorm_name FROM dorm WHERE gender = 'F'
CREATE TABLE dorm (dorm_name VARCHAR, gender VARCHAR)
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Find the name of dorms that can accommodate more than 300 students.
SELECT dorm_name FROM dorm WHERE student_capacity > 300
CREATE TABLE dorm (dorm_name VARCHAR, student_capacity INTEGER)
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How many female students (sex is F) whose age is below 25?
SELECT COUNT(*) FROM student WHERE sex = 'F' AND age < 25
CREATE TABLE student (sex VARCHAR, age VARCHAR)
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Find the first name of students who is older than 20.
SELECT fname FROM student WHERE age > 20
CREATE TABLE student (fname VARCHAR, age INTEGER)
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Find the first name of students living in city PHL whose age is between 20 and 25.
SELECT fname FROM student WHERE city_code = 'PHL' AND age BETWEEN 20 AND 25
CREATE TABLE student (fname VARCHAR, city_code VARCHAR, age VARCHAR)
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How many dorms are there?
SELECT COUNT(*) FROM dorm
CREATE TABLE dorm (Id VARCHAR)
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Find the number of distinct amenities.
SELECT COUNT(*) FROM dorm_amenity
CREATE TABLE dorm_amenity (Id VARCHAR)
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Find the total capacity of all dorms.
SELECT SUM(student_capacity) FROM dorm
CREATE TABLE dorm (student_capacity INTEGER)
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Find the average age of all students living in the each city.
SELECT AVG(age), city_code FROM student GROUP BY city_code
CREATE TABLE student (city_code VARCHAR, age INTEGER)
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Find the average and total capacity of dorms for the students with gender X.
SELECT AVG(student_capacity), SUM(student_capacity) FROM dorm WHERE gender = 'X'
CREATE TABLE dorm (student_capacity INTEGER, gender VARCHAR)
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Find the number of dorms that have some amenity.
SELECT COUNT(DISTINCT dormid) FROM has_amenity
CREATE TABLE has_amenity (dormid VARCHAR)
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Find the name of dorms that do not have any amenity
SELECT dorm_name FROM dorm WHERE NOT dormid IN (SELECT dormid FROM has_amenity)
CREATE TABLE dorm (dorm_name VARCHAR, dormid VARCHAR); CREATE TABLE has_amenity (dorm_name VARCHAR, dormid VARCHAR)
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Find the number of distinct gender for dorms.
SELECT COUNT(DISTINCT gender) FROM dorm
CREATE TABLE dorm (gender VARCHAR)
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Find the capacity and gender type of the dorm whose name has substring ‘Donor’.
SELECT student_capacity, gender FROM dorm WHERE dorm_name LIKE '%Donor%'
CREATE TABLE dorm (student_capacity VARCHAR, gender VARCHAR, dorm_name VARCHAR)
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Find the name and gender type of the dorms whose capacity is greater than 300 or less than 100.
SELECT dorm_name, gender FROM dorm WHERE student_capacity > 300 OR student_capacity < 100
CREATE TABLE dorm (dorm_name VARCHAR, gender VARCHAR, student_capacity VARCHAR)
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Find the numbers of different majors and cities.
SELECT COUNT(DISTINCT major), COUNT(DISTINCT city_code) FROM student
CREATE TABLE student (major VARCHAR, city_code VARCHAR)
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Find the last name of students who is either female (sex is F) and living in the city of code BAL or male (sex is M) and in age of below 20.
SELECT lname FROM student WHERE sex = 'F' AND city_code = 'BAL' UNION SELECT lname FROM student WHERE sex = 'M' AND age < 20
CREATE TABLE student (lname VARCHAR, sex VARCHAR, city_code VARCHAR, age VARCHAR)
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Find the name of the dorm with the largest capacity.
SELECT dorm_name FROM dorm ORDER BY student_capacity DESC LIMIT 1
CREATE TABLE dorm (dorm_name VARCHAR, student_capacity VARCHAR)
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List in alphabetic order all different amenities.
SELECT amenity_name FROM dorm_amenity ORDER BY amenity_name
CREATE TABLE dorm_amenity (amenity_name VARCHAR)
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Find the code of city where most of students are living in.
SELECT city_code FROM student GROUP BY city_code ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE student (city_code VARCHAR)
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Find the first and last name of students whose age is younger than the average age.
SELECT fname, lname FROM student WHERE age < (SELECT AVG(age) FROM student)
CREATE TABLE student (fname VARCHAR, lname VARCHAR, age INTEGER)
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List the first and last name of students who are not living in the city with code HKG, and sorted the results by their ages.
SELECT fname, lname FROM student WHERE city_code <> 'HKG' ORDER BY age
CREATE TABLE student (fname VARCHAR, lname VARCHAR, city_code VARCHAR, age VARCHAR)
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List name of all amenities which Anonymous Donor Hall has, and sort the results in alphabetic order.
SELECT T1.amenity_name FROM dorm_amenity AS T1 JOIN has_amenity AS T2 ON T2.amenid = T1.amenid JOIN dorm AS T3 ON T2.dormid = T3.dormid WHERE T3.dorm_name = 'Anonymous Donor Hall' ORDER BY T1.amenity_name
CREATE TABLE has_amenity (amenid VARCHAR, dormid VARCHAR); CREATE TABLE dorm_amenity (amenity_name VARCHAR, amenid VARCHAR); CREATE TABLE dorm (dormid VARCHAR, dorm_name VARCHAR)
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Find the number of dorms and total capacity for each gender.
SELECT COUNT(*), SUM(student_capacity), gender FROM dorm GROUP BY gender
CREATE TABLE dorm (gender VARCHAR, student_capacity INTEGER)
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Find the average and oldest age for students with different sex.
SELECT AVG(age), MAX(age), sex FROM student GROUP BY sex
CREATE TABLE student (sex VARCHAR, age INTEGER)
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Find the number of students in each major.
SELECT COUNT(*), major FROM student GROUP BY major
CREATE TABLE student (major VARCHAR)
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Find the number and average age of students living in each city.
SELECT COUNT(*), AVG(age), city_code FROM student GROUP BY city_code
CREATE TABLE student (city_code VARCHAR, age INTEGER)
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Find the average age and number of male students (with sex M) from each city.
SELECT COUNT(*), AVG(age), city_code FROM student WHERE sex = 'M' GROUP BY city_code
CREATE TABLE student (city_code VARCHAR, age INTEGER, sex VARCHAR)
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Find the number of students for the cities where have more than one student.
SELECT COUNT(*), city_code FROM student GROUP BY city_code HAVING COUNT(*) > 1
CREATE TABLE student (city_code VARCHAR)
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Find the first and last name of students who are not in the largest major.
SELECT fname, lname FROM student WHERE major <> (SELECT major FROM student GROUP BY major ORDER BY COUNT(*) DESC LIMIT 1)
CREATE TABLE student (fname VARCHAR, lname VARCHAR, major VARCHAR)
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Find the number of students whose age is older than the average age for each gender.
SELECT COUNT(*), sex FROM student WHERE age > (SELECT AVG(age) FROM student) GROUP BY sex
CREATE TABLE student (sex VARCHAR, age INTEGER)
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Find the average age of students living in each dorm and the name of dorm.
SELECT AVG(T1.age), T3.dorm_name FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid JOIN dorm AS T3 ON T3.dormid = T2.dormid GROUP BY T3.dorm_name
CREATE TABLE dorm (dorm_name VARCHAR, dormid VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR)
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Find the number of amenities for each of the dorms that can accommodate more than 100 students.
SELECT COUNT(*), T1.dormid FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid WHERE T1.student_capacity > 100 GROUP BY T1.dormid
CREATE TABLE dorm (dormid VARCHAR, student_capacity INTEGER); CREATE TABLE has_amenity (dormid VARCHAR)
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Find the number of students who is older than 20 in each dorm.
SELECT COUNT(*), T3.dorm_name FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid JOIN dorm AS T3 ON T3.dormid = T2.dormid WHERE T1.age > 20 GROUP BY T3.dorm_name
CREATE TABLE dorm (dorm_name VARCHAR, dormid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE student (stuid VARCHAR, age INTEGER)
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Find the first name of students who are living in the Smith Hall.
SELECT T1.fname FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid JOIN dorm AS T3 ON T3.dormid = T2.dormid WHERE T3.dorm_name = 'Smith Hall'
CREATE TABLE student (fname VARCHAR, stuid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE dorm (dormid VARCHAR, dorm_name VARCHAR)
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Find the average age of students who are living in the dorm with the largest capacity.
SELECT AVG(T1.age) FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid JOIN dorm AS T3 ON T3.dormid = T2.dormid WHERE T3.student_capacity = (SELECT MAX(student_capacity) FROM dorm)
CREATE TABLE dorm (student_capacity INTEGER); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE dorm (dormid VARCHAR, student_capacity INTEGER)
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Find the total number of students living in the male dorm (with gender M).
SELECT COUNT(*) FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid JOIN dorm AS T3 ON T3.dormid = T2.dormid WHERE T3.gender = 'M'
CREATE TABLE dorm (dormid VARCHAR, gender VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE student (stuid VARCHAR)
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Find the number of female students (with F sex) living in Smith Hall
SELECT COUNT(*) FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid JOIN dorm AS T3 ON T3.dormid = T2.dormid WHERE T3.dorm_name = 'Smith Hall' AND T1.sex = 'F'
CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE student (stuid VARCHAR, sex VARCHAR); CREATE TABLE dorm (dormid VARCHAR, dorm_name VARCHAR)
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Find the name of amenities Smith Hall dorm have.
SELECT T3.amenity_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T1.dorm_name = 'Smith Hall'
CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE dorm_amenity (amenity_name VARCHAR, amenid VARCHAR); CREATE TABLE dorm (dormid VARCHAR, dorm_name VARCHAR)
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Find the name of amenities Smith Hall dorm have. ordered the results by amenity names.
SELECT T3.amenity_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T1.dorm_name = 'Smith Hall' ORDER BY T3.amenity_name
CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE dorm_amenity (amenity_name VARCHAR, amenid VARCHAR); CREATE TABLE dorm (dormid VARCHAR, dorm_name VARCHAR)
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Find the name of amenity that is most common in all dorms.
SELECT T1.amenity_name FROM dorm_amenity AS T1 JOIN has_amenity AS T2 ON T1.amenid = T2.amenid GROUP BY T2.amenid ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE dorm_amenity (amenity_name VARCHAR, amenid VARCHAR); CREATE TABLE has_amenity (amenid VARCHAR)
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Find the name and capacity of the dorm with least number of amenities.
SELECT T1.dorm_name, T1.student_capacity FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid GROUP BY T2.dormid ORDER BY COUNT(*) LIMIT 1
CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE dorm_amenity (amenid VARCHAR); CREATE TABLE dorm (dorm_name VARCHAR, student_capacity VARCHAR, dormid VARCHAR)
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Find the name of dorms that do not have amenity TV Lounge.
SELECT dorm_name FROM dorm EXCEPT SELECT T1.dorm_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T3.amenity_name = 'TV Lounge'
CREATE TABLE dorm (dorm_name VARCHAR, dormid VARCHAR); CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE dorm (dorm_name VARCHAR); CREATE TABLE dorm_amenity (amenid VARCHAR, amenity_name VARCHAR)
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Find the first and last name of students who are living in the dorms that have amenity TV Lounge.
SELECT T1.fname, T1.lname FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid WHERE T2.dormid IN (SELECT T3.dormid FROM has_amenity AS T3 JOIN dorm_amenity AS T4 ON T3.amenid = T4.amenid WHERE T4.amenity_name = 'TV Lounge')
CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE dorm_amenity (amenid VARCHAR, amenity_name VARCHAR)
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Find the first name and age of students who are living in the dorms that do not have amenity TV Lounge.
SELECT T1.fname, T1.age FROM student AS T1 JOIN lives_in AS T2 ON T1.stuid = T2.stuid WHERE NOT T2.dormid IN (SELECT T3.dormid FROM has_amenity AS T3 JOIN dorm_amenity AS T4 ON T3.amenid = T4.amenid WHERE T4.amenity_name = 'TV Lounge')
CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE student (fname VARCHAR, age VARCHAR, stuid VARCHAR); CREATE TABLE lives_in (stuid VARCHAR, dormid VARCHAR); CREATE TABLE dorm_amenity (amenid VARCHAR, amenity_name VARCHAR)
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Find the name of amenities of the dorm where the student with last name Smith is living in.
SELECT T3.amenity_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid JOIN lives_in AS T4 ON T4.dormid = T1.dormid JOIN student AS T5 ON T5.stuid = T4.stuid WHERE T5.lname = 'Smith'
CREATE TABLE student (stuid VARCHAR, lname VARCHAR); CREATE TABLE dorm (dormid VARCHAR); CREATE TABLE lives_in (dormid VARCHAR, stuid VARCHAR); CREATE TABLE has_amenity (dormid VARCHAR, amenid VARCHAR); CREATE TABLE dorm_amenity (amenity_name VARCHAR, amenid VARCHAR)
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Find the emails and phone numbers of all the customers, ordered by email address and phone number.
SELECT email_address, phone_number FROM customers ORDER BY email_address, phone_number
CREATE TABLE customers (email_address VARCHAR, phone_number VARCHAR)
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Which city has the least number of customers whose type code is "Good Credit Rating"?
SELECT town_city FROM customers WHERE customer_type_code = "Good Credit Rating" GROUP BY town_city ORDER BY COUNT(*) LIMIT 1
CREATE TABLE customers (town_city VARCHAR, customer_type_code VARCHAR)
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List the name of all products along with the number of complaints that they have received.
SELECT t1.product_name, COUNT(*) FROM products AS t1 JOIN complaints AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_name
CREATE TABLE products (product_name VARCHAR, product_id VARCHAR); CREATE TABLE complaints (product_id VARCHAR)
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Find the emails of customers who has filed a complaints of the product with the most complaints.
SELECT t1.email_address FROM customers AS t1 JOIN complaints AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_id ORDER BY COUNT(*) LIMIT 1
CREATE TABLE customers (email_address VARCHAR, customer_id VARCHAR); CREATE TABLE complaints (customer_id VARCHAR)
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Which products has been complained by the customer who has filed least amount of complaints?
SELECT DISTINCT t1.product_name FROM products AS t1 JOIN complaints AS t2 ON t1.product_id = t2.product_id JOIN customers AS t3 GROUP BY t3.customer_id ORDER BY COUNT(*) LIMIT 1
CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE products (product_name VARCHAR, product_id VARCHAR); CREATE TABLE complaints (product_id VARCHAR)
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What is the phone number of the customer who has filed the most recent complaint?
SELECT t1.phone_number FROM customers AS t1 JOIN complaints AS t2 ON t1.customer_id = t2.customer_id ORDER BY t2.date_complaint_raised DESC LIMIT 1
CREATE TABLE customers (phone_number VARCHAR, customer_id VARCHAR); CREATE TABLE complaints (customer_id VARCHAR, date_complaint_raised VARCHAR)
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Find the email and phone number of the customers who have never filed a complaint before.
SELECT email_address, phone_number FROM customers WHERE NOT customer_id IN (SELECT customer_id FROM complaints)
CREATE TABLE complaints (email_address VARCHAR, phone_number VARCHAR, customer_id VARCHAR); CREATE TABLE customers (email_address VARCHAR, phone_number VARCHAR, customer_id VARCHAR)
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Find the phone number of all the customers and staff.
SELECT phone_number FROM customers UNION SELECT phone_number FROM staff
CREATE TABLE staff (phone_number VARCHAR); CREATE TABLE customers (phone_number VARCHAR)
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What is the description of the product named "Chocolate"?
SELECT product_description FROM products WHERE product_name = "Chocolate"
CREATE TABLE products (product_description VARCHAR, product_name VARCHAR)
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Find the name and category of the most expensive product.
SELECT product_name, product_category_code FROM products ORDER BY product_price DESC LIMIT 1
CREATE TABLE products (product_name VARCHAR, product_category_code VARCHAR, product_price VARCHAR)
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Find the prices of products which has never received a single complaint.
SELECT product_price FROM products WHERE NOT product_id IN (SELECT product_id FROM complaints)
CREATE TABLE products (product_price VARCHAR, product_id VARCHAR); CREATE TABLE complaints (product_price VARCHAR, product_id VARCHAR)
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What is the average price of the products for each category?
SELECT AVG(product_price), product_category_code FROM products GROUP BY product_category_code
CREATE TABLE products (product_category_code VARCHAR, product_price INTEGER)
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Find the last name of the staff member who processed the complaint of the cheapest product.
SELECT t1.last_name FROM staff AS t1 JOIN complaints AS t2 ON t1.staff_id = t2.staff_id JOIN products AS t3 ON t2.product_id = t3.product_id ORDER BY t3.product_price LIMIT 1
CREATE TABLE products (product_id VARCHAR, product_price VARCHAR); CREATE TABLE complaints (staff_id VARCHAR, product_id VARCHAR); CREATE TABLE staff (last_name VARCHAR, staff_id VARCHAR)
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Which complaint status has more than 3 records on file?
SELECT complaint_status_code FROM complaints GROUP BY complaint_status_code HAVING COUNT(*) > 3
CREATE TABLE complaints (complaint_status_code VARCHAR)
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Find the last name of the staff whose email address contains "wrau".
SELECT last_name FROM staff WHERE email_address LIKE "%wrau%"
CREATE TABLE staff (last_name VARCHAR, email_address VARCHAR)
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How many customers are there in the customer type with the most customers?
SELECT COUNT(*) FROM customers GROUP BY customer_type_code ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE customers (customer_type_code VARCHAR)
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What is the last name of the staff who has handled the first ever complaint?
SELECT t1.last_name FROM staff AS t1 JOIN complaints AS t2 ON t1.staff_id = t2.staff_id ORDER BY t2.date_complaint_raised LIMIT 1
CREATE TABLE staff (last_name VARCHAR, staff_id VARCHAR); CREATE TABLE complaints (staff_id VARCHAR, date_complaint_raised VARCHAR)
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How many distinct complaint type codes are there in the database?
SELECT COUNT(DISTINCT complaint_type_code) FROM complaints
CREATE TABLE complaints (complaint_type_code VARCHAR)
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Find the address line 1 and 2 of the customer with email "vbogisich@example.org".
SELECT address_line_1, address_line_2 FROM customers WHERE email_address = "vbogisich@example.org"
CREATE TABLE customers (address_line_1 VARCHAR, address_line_2 VARCHAR, email_address VARCHAR)
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Find the number of complaints with Product Failure type for each complaint status.
SELECT complaint_status_code, COUNT(*) FROM complaints WHERE complaint_type_code = "Product Failure" GROUP BY complaint_status_code
CREATE TABLE complaints (complaint_status_code VARCHAR, complaint_type_code VARCHAR)
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What is first names of the top 5 staff who have handled the greatest number of complaints?
SELECT t1.first_name FROM staff AS t1 JOIN complaints AS t2 ON t1.staff_id = t2.staff_id GROUP BY t2.staff_id ORDER BY COUNT(*) LIMIT 5
CREATE TABLE complaints (staff_id VARCHAR); CREATE TABLE staff (first_name VARCHAR, staff_id VARCHAR)
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Which state has the most customers?
SELECT state FROM customers GROUP BY state ORDER BY COUNT(*) LIMIT 1
CREATE TABLE customers (state VARCHAR)
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How many submissions are there?
SELECT COUNT(*) FROM submission
CREATE TABLE submission (Id VARCHAR)
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List the authors of submissions in ascending order of scores.
SELECT Author FROM submission ORDER BY Scores
CREATE TABLE submission (Author VARCHAR, Scores VARCHAR)
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What are the authors of submissions and their colleges?
SELECT Author, College FROM submission
CREATE TABLE submission (Author VARCHAR, College VARCHAR)
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Show the names of authors from college "Florida" or "Temple"
SELECT Author FROM submission WHERE College = "Florida" OR College = "Temple"
CREATE TABLE submission (Author VARCHAR, College VARCHAR)
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What is the average score of submissions?
SELECT AVG(Scores) FROM submission
CREATE TABLE submission (Scores INTEGER)
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What is the author of the submission with the highest score?
SELECT Author FROM submission ORDER BY Scores DESC LIMIT 1
CREATE TABLE submission (Author VARCHAR, Scores VARCHAR)
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Show different colleges along with the number of authors of submission from each college.
SELECT College, COUNT(*) FROM submission GROUP BY College
CREATE TABLE submission (College VARCHAR)
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Show the most common college of authors of submissions.
SELECT College FROM submission GROUP BY College ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE submission (College VARCHAR)
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Show the colleges that have both authors with submission score larger than 90 and authors with submission score smaller than 80.
SELECT College FROM submission WHERE Scores > 90 INTERSECT SELECT College FROM submission WHERE Scores < 80
CREATE TABLE submission (College VARCHAR, Scores INTEGER)
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Show the authors of submissions and the acceptance results of their submissions.
SELECT T2.Author, T1.Result FROM acceptance AS T1 JOIN submission AS T2 ON T1.Submission_ID = T2.Submission_ID
CREATE TABLE acceptance (Result VARCHAR, Submission_ID VARCHAR); CREATE TABLE submission (Author VARCHAR, Submission_ID VARCHAR)
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Show the result of the submission with the highest score.
SELECT T1.Result FROM acceptance AS T1 JOIN submission AS T2 ON T1.Submission_ID = T2.Submission_ID ORDER BY T2.Scores DESC LIMIT 1
CREATE TABLE acceptance (Result VARCHAR, Submission_ID VARCHAR); CREATE TABLE submission (Submission_ID VARCHAR, Scores VARCHAR)
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Show each author and the number of workshops they submitted to.
SELECT T2.Author, COUNT(DISTINCT T1.workshop_id) FROM acceptance AS T1 JOIN submission AS T2 ON T1.Submission_ID = T2.Submission_ID GROUP BY T2.Author
CREATE TABLE submission (Author VARCHAR, Submission_ID VARCHAR); CREATE TABLE acceptance (workshop_id VARCHAR, Submission_ID VARCHAR)
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[ 3, 23143, 14196, 332, 4416, 23602, 127, 6, 2847, 17161, 599, 15438, 25424, 6227, 332, 5411, 1981, 6921, 834, 23, 26, 61, 21680, 11122, 6157, 332, 536, 3, 15355, 3162, 8121, 6157, 332, 357, 9191, 332, 5411, 25252, 5451, 834, 4309, 3274...
Show the authors who have submissions to more than one workshop.
SELECT T2.Author FROM acceptance AS T1 JOIN submission AS T2 ON T1.Submission_ID = T2.Submission_ID GROUP BY T2.Author HAVING COUNT(DISTINCT T1.workshop_id) > 1
CREATE TABLE submission (Author VARCHAR, Submission_ID VARCHAR); CREATE TABLE acceptance (Submission_ID VARCHAR, workshop_id VARCHAR)
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[ 3, 23143, 14196, 332, 4416, 23602, 127, 21680, 11122, 6157, 332, 536, 3, 15355, 3162, 8121, 6157, 332, 357, 9191, 332, 5411, 25252, 5451, 834, 4309, 3274, 332, 4416, 25252, 5451, 834, 4309, 350, 4630, 6880, 272, 476, 332, 4416, 23602, ...
Show the date and venue of each workshop in ascending alphabetical order of the venue.
SELECT Date, Venue FROM workshop ORDER BY Venue
CREATE TABLE workshop (Date VARCHAR, Venue VARCHAR)
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List the authors who do not have submission to any workshop.
SELECT Author FROM submission WHERE NOT Submission_ID IN (SELECT Submission_ID FROM acceptance)
CREATE TABLE acceptance (Author VARCHAR, Submission_ID VARCHAR); CREATE TABLE submission (Author VARCHAR, Submission_ID VARCHAR)
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[ 3, 23143, 14196, 10236, 21680, 8121, 549, 17444, 427, 4486, 29779, 834, 4309, 3388, 41, 23143, 14196, 29779, 834, 4309, 21680, 11122, 61, 1, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, ...
Find the number of investors in total.
SELECT COUNT(*) FROM INVESTORS
CREATE TABLE INVESTORS (Id VARCHAR)
[ 32100, 32106, 32105, 205, 4386, 6048, 332, 17098, 27, 17058, 6038, 22500, 41, 196, 26, 584, 4280, 28027, 61, 3, 32105, 32106, 32107, 32106, 2588, 8, 381, 13, 4367, 16, 792, 5, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0...
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[ 3, 23143, 14196, 2847, 17161, 599, 1935, 61, 21680, 27, 17058, 6038, 22500, 1, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -...
Show all investor details.
SELECT Investor_details FROM INVESTORS
CREATE TABLE INVESTORS (Investor_details VARCHAR)
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Show all distinct lot details.
SELECT DISTINCT lot_details FROM LOTS
CREATE TABLE LOTS (lot_details VARCHAR)
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[ 3, 23143, 14196, 3, 15438, 25424, 6227, 418, 834, 221, 5756, 7, 21680, 3, 19912, 134, 1, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -...
Show the maximum amount of transaction.
SELECT MAX(amount_of_transaction) FROM TRANSACTIONS
CREATE TABLE TRANSACTIONS (amount_of_transaction INTEGER)
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Show all date and share count of transactions.
SELECT date_of_transaction, share_count FROM TRANSACTIONS
CREATE TABLE TRANSACTIONS (date_of_transaction VARCHAR, share_count VARCHAR)
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What is the total share of transactions?
SELECT SUM(share_count) FROM TRANSACTIONS
CREATE TABLE TRANSACTIONS (share_count INTEGER)
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Show all transaction ids with transaction code 'PUR'.
SELECT transaction_id FROM TRANSACTIONS WHERE transaction_type_code = 'PUR'
CREATE TABLE TRANSACTIONS (transaction_id VARCHAR, transaction_type_code VARCHAR)
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[ 3, 23143, 14196, 5878, 834, 23, 26, 21680, 26585, 30518, 134, 549, 17444, 427, 5878, 834, 6137, 834, 4978, 3274, 3, 31, 345, 5905, 31, 1, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, -100, ...
Show all dates of transactions whose type code is "SALE".
SELECT date_of_transaction FROM TRANSACTIONS WHERE transaction_type_code = "SALE"
CREATE TABLE TRANSACTIONS (date_of_transaction VARCHAR, transaction_type_code VARCHAR)
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Show the average amount of transactions with type code "SALE".
SELECT AVG(amount_of_transaction) FROM TRANSACTIONS WHERE transaction_type_code = "SALE"
CREATE TABLE TRANSACTIONS (amount_of_transaction INTEGER, transaction_type_code VARCHAR)
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Show the description of transaction type with code "PUR".
SELECT transaction_type_description FROM Ref_Transaction_Types WHERE transaction_type_code = "PUR"
CREATE TABLE Ref_Transaction_Types (transaction_type_description VARCHAR, transaction_type_code VARCHAR)
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Show the minimum amount of transactions whose type code is "PUR" and whose share count is bigger than 50.
SELECT MIN(amount_of_transaction) FROM TRANSACTIONS WHERE transaction_type_code = "PUR" AND share_count > 50
CREATE TABLE TRANSACTIONS (amount_of_transaction INTEGER, transaction_type_code VARCHAR, share_count VARCHAR)
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Show the maximum share count of transactions where the amount is smaller than 10000
SELECT MAX(share_count) FROM TRANSACTIONS WHERE amount_of_transaction < 10000
CREATE TABLE TRANSACTIONS (share_count INTEGER, amount_of_transaction INTEGER)
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Show the dates of transactions if the share count is bigger than 100 or the amount is bigger than 1000.
SELECT date_of_transaction FROM TRANSACTIONS WHERE share_count > 100 OR amount_of_transaction > 1000
CREATE TABLE TRANSACTIONS (date_of_transaction VARCHAR, share_count VARCHAR, amount_of_transaction VARCHAR)
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Show the transaction type descriptions and dates if the share count is smaller than 10.
SELECT T1.transaction_type_description, T2.date_of_transaction FROM Ref_Transaction_Types AS T1 JOIN TRANSACTIONS AS T2 ON T1.transaction_type_code = T2.transaction_type_code WHERE T2.share_count < 10
CREATE TABLE Ref_Transaction_Types (transaction_type_description VARCHAR, transaction_type_code VARCHAR); CREATE TABLE TRANSACTIONS (date_of_transaction VARCHAR, transaction_type_code VARCHAR, share_count INTEGER)
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Show details of all investors if they make any transaction with share count greater than 100.
SELECT T1.Investor_details FROM INVESTORS AS T1 JOIN TRANSACTIONS AS T2 ON T1.investor_id = T2.investor_id WHERE T2.share_count > 100
CREATE TABLE TRANSACTIONS (investor_id VARCHAR, share_count INTEGER); CREATE TABLE INVESTORS (Investor_details VARCHAR, investor_id VARCHAR)
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How many distinct transaction types are used in the transactions?
SELECT COUNT(DISTINCT transaction_type_code) FROM TRANSACTIONS
CREATE TABLE TRANSACTIONS (transaction_type_code VARCHAR)
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Return the lot details and investor ids.
SELECT lot_details, investor_id FROM LOTS
CREATE TABLE LOTS (lot_details VARCHAR, investor_id VARCHAR)
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