NATURAL_LANG stringlengths 12 244 | SQL stringlengths 18 336 | SCHEMA stringlengths 27 355 | input_ids list | attention_mask list | labels list |
|---|---|---|---|---|---|
Select the names of all the products in the store. | SELECT Name FROM Products | CREATE TABLE Products (Name VARCHAR) | [
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Select the names and the prices of all the products in the store. | SELECT name, price FROM products | CREATE TABLE products (name VARCHAR, price VARCHAR) | [
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Select the name of the products with a price less than or equal to $200. | SELECT name FROM products WHERE price <= 200 | CREATE TABLE products (name VARCHAR, price VARCHAR) | [
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Find all information of all the products with a price between $60 and $120. | SELECT * FROM products WHERE price BETWEEN 60 AND 120 | CREATE TABLE products (price INTEGER) | [
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Compute the average price of all the products. | SELECT AVG(price) FROM products | CREATE TABLE products (price INTEGER) | [
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Compute the average price of all products with manufacturer code equal to 2. | SELECT AVG(price) FROM products WHERE Manufacturer = 2 | CREATE TABLE products (price INTEGER, Manufacturer VARCHAR) | [
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Compute the number of products with a price larger than or equal to $180. | SELECT COUNT(*) FROM products WHERE price >= 180 | CREATE TABLE products (price VARCHAR) | [
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Select the name and price of all products with a price larger than or equal to $180, and sort first by price (in descending order), and then by name (in ascending order). | SELECT name, price FROM products WHERE price >= 180 ORDER BY price DESC, name | CREATE TABLE products (name VARCHAR, price VARCHAR) | [
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Select all the data from the products and each product's manufacturer. | SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code | CREATE TABLE products (manufacturer VARCHAR); CREATE TABLE Manufacturers (code VARCHAR) | [
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Select the average price of each manufacturer's products, showing only the manufacturer's code. | SELECT AVG(Price), Manufacturer FROM Products GROUP BY Manufacturer | CREATE TABLE Products (Manufacturer VARCHAR, Price INTEGER) | [
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Select the average price of each manufacturer's products, showing the manufacturer's name. | SELECT AVG(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name | CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Price INTEGER, manufacturer VARCHAR) | [
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Select the names of manufacturer whose products have an average price higher than or equal to $150. | SELECT AVG(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING AVG(T1.price) >= 150 | CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Price INTEGER, manufacturer VARCHAR, price INTEGER) | [
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Select the name and price of the cheapest product. | SELECT name, price FROM Products ORDER BY price LIMIT 1 | CREATE TABLE Products (name VARCHAR, price VARCHAR) | [
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Select the name of each manufacturer along with the name and price of its most expensive product. | SELECT T1.Name, MAX(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name | CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Name VARCHAR, Price INTEGER, manufacturer VARCHAR) | [
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Select the code of the product that is cheapest in each product category. | SELECT code, name, MIN(price) FROM products GROUP BY name | CREATE TABLE products (code VARCHAR, name VARCHAR, price INTEGER) | [
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What is the id of the problem log that is created most recently? | SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1 | CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR) | [
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What is the oldest log id and its corresponding problem id? | SELECT problem_log_id, problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1 | CREATE TABLE problem_log (problem_log_id VARCHAR, problem_id VARCHAR, log_entry_date VARCHAR) | [
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Find all the ids and dates of the logs for the problem whose id is 10. | SELECT problem_log_id, log_entry_date FROM problem_log WHERE problem_id = 10 | CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR, problem_id VARCHAR) | [
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List all the log ids and their descriptions from the problem logs. | SELECT problem_log_id, log_entry_description FROM problem_log | CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_description VARCHAR) | [
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List the first and last names of all distinct staff members who are assigned to the problem whose id is 1. | SELECT DISTINCT staff_first_name, staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1 | CREATE TABLE problem_log (assigned_to_staff_id VARCHAR, problem_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR) | [
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List the problem id and log id which are assigned to the staff named Rylan Homenick. | SELECT DISTINCT T2.problem_id, T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick" | CREATE TABLE problem_log (problem_id VARCHAR, problem_log_id VARCHAR, assigned_to_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR) | [
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How many problems are there for product voluptatem? | SELECT COUNT(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem" | CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_id VARCHAR, product_name VARCHAR) | [
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How many problems does the product with the most problems have? List the number of the problems and product name. | SELECT COUNT(*), T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_name VARCHAR, product_id VARCHAR) | [
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2... |
Give me a list of descriptions of the problems that are reported by the staff whose first name is Christop. | SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" | CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR); CREATE TABLE problems (problem_description VARCHAR, reported_by_staff_id VARCHAR) | [
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Find the ids of the problems that are reported by the staff whose last name is Bosco. | SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco" | CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_last_name VARCHAR) | [
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What are the ids of the problems which are reported after 1978-06-26? | SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26" | CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER) | [
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What are the ids of the problems which are reported before 1978-06-26? | SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26" | CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER) | [
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For each product which has problems, what are the number of problems and the product id? | SELECT COUNT(*), T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id | CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_id VARCHAR) | [
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For each product that has problems, find the number of problems reported after 1986-11-13 and the product id? | SELECT COUNT(*), T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id | CREATE TABLE product (product_id VARCHAR); CREATE TABLE problems (product_id VARCHAR, date_problem_reported INTEGER) | [
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List the names of all the distinct product names in alphabetical order? | SELECT DISTINCT product_name FROM product ORDER BY product_name | CREATE TABLE product (product_name VARCHAR) | [
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List all the distinct product names ordered by product id? | SELECT DISTINCT product_name FROM product ORDER BY product_id | CREATE TABLE product (product_name VARCHAR, product_id VARCHAR) | [
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What are the ids of the problems reported before the date of any problem reported by Lysanne Turcotte? | SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < (SELECT MIN(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte") | CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR) | [
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What are the ids of the problems reported after the date of any problems reported by Rylan Homenick? | SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > (SELECT MAX(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick") | CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR) | [
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Find the top 3 products which have the largest number of problems? | SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY COUNT(*) DESC LIMIT 3 | CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_name VARCHAR, product_id VARCHAR) | [
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List the ids of the problems from the product "voluptatem" that are reported after 1995? | SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995" | CREATE TABLE problems (problem_id VARCHAR, product_id VARCHAR, date_problem_reported VARCHAR); CREATE TABLE product (product_id VARCHAR, product_name VARCHAR) | [
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How many branches where have more than average number of memberships are there? | SELECT COUNT(*) FROM branch WHERE membership_amount > (SELECT AVG(membership_amount) FROM branch) | CREATE TABLE branch (membership_amount INTEGER) | [
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Show name, address road, and city for all branches sorted by open year. | SELECT name, address_road, city FROM branch ORDER BY open_year | CREATE TABLE branch (name VARCHAR, address_road VARCHAR, city VARCHAR, open_year VARCHAR) | [
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What are names for top three branches with most number of membership? | SELECT name FROM branch ORDER BY membership_amount DESC LIMIT 3 | CREATE TABLE branch (name VARCHAR, membership_amount VARCHAR) | [
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Show all distinct city where branches with at least 100 memberships are located. | SELECT DISTINCT city FROM branch WHERE membership_amount >= 100 | CREATE TABLE branch (city VARCHAR, membership_amount VARCHAR) | [
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List all open years when at least two shops are opened. | SELECT open_year FROM branch GROUP BY open_year HAVING COUNT(*) >= 2 | CREATE TABLE branch (open_year VARCHAR) | [
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Show minimum and maximum amount of memberships for all branches opened in 2011 or located at city London. | SELECT MIN(membership_amount), MAX(membership_amount) FROM branch WHERE open_year = 2011 OR city = 'London' | CREATE TABLE branch (membership_amount INTEGER, open_year VARCHAR, city VARCHAR) | [
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Show the city and the number of branches opened before 2010 for each city. | SELECT city, COUNT(*) FROM branch WHERE open_year < 2010 GROUP BY city | CREATE TABLE branch (city VARCHAR, open_year INTEGER) | [
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How many different levels do members have? | SELECT COUNT(DISTINCT LEVEL) FROM member | CREATE TABLE member (LEVEL VARCHAR) | [
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Show card number, name, and hometown for all members in a descending order of level. | SELECT card_number, name, hometown FROM member ORDER BY LEVEL DESC | CREATE TABLE member (card_number VARCHAR, name VARCHAR, hometown VARCHAR, LEVEL VARCHAR) | [
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Show the membership level with most number of members. | SELECT LEVEL FROM member GROUP BY LEVEL ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE member (LEVEL VARCHAR) | [
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Show all member names and registered branch names sorted by register year. | SELECT T3.name, T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id ORDER BY T1.register_year | CREATE TABLE member (name VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, member_id VARCHAR, register_year VARCHAR); CREATE TABLE branch (name VARCHAR, branch_id VARCHAR) | [
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Show all branch names with the number of members in each branch registered after 2015. | SELECT T2.name, COUNT(*) FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year > 2015 GROUP BY T2.branch_id | CREATE TABLE branch (name VARCHAR, branch_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, register_year INTEGER) | [
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Show member names without any registered branch. | SELECT name FROM member WHERE NOT member_id IN (SELECT member_id FROM membership_register_branch) | CREATE TABLE member (name VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (name VARCHAR, member_id VARCHAR) | [
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List the branch name and city without any registered members. | SELECT name, city FROM branch WHERE NOT branch_id IN (SELECT branch_id FROM membership_register_branch) | CREATE TABLE membership_register_branch (name VARCHAR, city VARCHAR, branch_id VARCHAR); CREATE TABLE branch (name VARCHAR, city VARCHAR, branch_id VARCHAR) | [
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What is the name and open year for the branch with most number of memberships registered in 2016? | SELECT T2.name, T2.open_year FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year = 2016 GROUP BY T2.branch_id ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE membership_register_branch (branch_id VARCHAR, register_year VARCHAR); CREATE TABLE branch (name VARCHAR, open_year VARCHAR, branch_id VARCHAR) | [
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Show the member name and hometown who registered a branch in 2016. | SELECT T2.name, T2.hometown FROM membership_register_branch AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T1.register_year = 2016 | CREATE TABLE member (name VARCHAR, hometown VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (member_id VARCHAR, register_year VARCHAR) | [
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Show all city with a branch opened in 2001 and a branch with more than 100 membership. | SELECT city FROM branch WHERE open_year = 2001 AND membership_amount > 100 | CREATE TABLE branch (city VARCHAR, open_year VARCHAR, membership_amount VARCHAR) | [
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Show all cities without a branch having more than 100 memberships. | SELECT city FROM branch EXCEPT SELECT city FROM branch WHERE membership_amount > 100 | CREATE TABLE branch (city VARCHAR, membership_amount INTEGER) | [
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What is the sum of total pounds of purchase in year 2018 for all branches in London? | SELECT SUM(total_pounds) FROM purchase AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T2.city = 'London' AND T1.year = 2018 | CREATE TABLE purchase (branch_id VARCHAR, year VARCHAR); CREATE TABLE branch (branch_id VARCHAR, city VARCHAR) | [
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What is the total number of purchases for members with level 6? | SELECT COUNT(*) FROM purchase AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T2.level = 6 | CREATE TABLE member (member_id VARCHAR, level VARCHAR); CREATE TABLE purchase (member_id VARCHAR) | [
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list the card number of all members whose hometown address includes word "Kentucky". | SELECT card_number FROM member WHERE Hometown LIKE "%Kentucky%" | CREATE TABLE member (card_number VARCHAR, Hometown VARCHAR) | [
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-100,
-100,
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Find the number of students in total. | SELECT COUNT(*) FROM STUDENT | CREATE TABLE STUDENT (Id VARCHAR) | [
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-100,
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Find the number of voting records in total. | SELECT COUNT(*) FROM VOTING_RECORD | CREATE TABLE VOTING_RECORD (Id VARCHAR) | [
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-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-1... |
Find the distinct number of president votes. | SELECT COUNT(DISTINCT President_Vote) FROM VOTING_RECORD | CREATE TABLE VOTING_RECORD (President_Vote VARCHAR) | [
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Find the maximum age of all the students. | SELECT MAX(Age) FROM STUDENT | CREATE TABLE STUDENT (Age INTEGER) | [
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-100,
-100,
... |
Find the last names of students with major 50. | SELECT LName FROM STUDENT WHERE Major = 50 | CREATE TABLE STUDENT (LName VARCHAR, Major VARCHAR) | [
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Find the first names of students with age above 22. | SELECT Fname FROM STUDENT WHERE Age > 22 | CREATE TABLE STUDENT (Fname VARCHAR, Age INTEGER) | [
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What are the majors of male (sex is M) students? | SELECT Major FROM STUDENT WHERE Sex = "M" | CREATE TABLE STUDENT (Major VARCHAR, Sex VARCHAR) | [
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What is the average age of female (sex is F) students? | SELECT AVG(Age) FROM STUDENT WHERE Sex = "F" | CREATE TABLE STUDENT (Age INTEGER, Sex VARCHAR) | [
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What are the maximum and minimum age of students with major 600? | SELECT MAX(Age), MIN(Age) FROM STUDENT WHERE Major = 600 | CREATE TABLE STUDENT (Age INTEGER, Major VARCHAR) | [
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Who are the advisors for students that live in a city with city code "BAL"? | SELECT Advisor FROM STUDENT WHERE city_code = "BAL" | CREATE TABLE STUDENT (Advisor VARCHAR, city_code VARCHAR) | [
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What are the distinct secretary votes in the fall election cycle? | SELECT DISTINCT Secretary_Vote FROM VOTING_RECORD WHERE ELECTION_CYCLE = "Fall" | CREATE TABLE VOTING_RECORD (Secretary_Vote VARCHAR, ELECTION_CYCLE VARCHAR) | [
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What are the distinct president votes on 08/30/2015? | SELECT DISTINCT PRESIDENT_Vote FROM VOTING_RECORD WHERE Registration_Date = "08/30/2015" | CREATE TABLE VOTING_RECORD (PRESIDENT_Vote VARCHAR, Registration_Date VARCHAR) | [
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Report the distinct registration date and the election cycle. | SELECT DISTINCT Registration_Date, Election_Cycle FROM VOTING_RECORD | CREATE TABLE VOTING_RECORD (Registration_Date VARCHAR, Election_Cycle VARCHAR) | [
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Report the distinct president vote and the vice president vote. | SELECT DISTINCT President_Vote, VICE_President_Vote FROM VOTING_RECORD | CREATE TABLE VOTING_RECORD (President_Vote VARCHAR, VICE_President_Vote VARCHAR) | [
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Find the distinct last names of the students who have class president votes. | SELECT DISTINCT T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.CLASS_President_VOTE | CREATE TABLE STUDENT (LName VARCHAR, StuID VARCHAR); CREATE TABLE VOTING_RECORD (CLASS_President_VOTE VARCHAR) | [
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Find the distinct first names of the students who have class senator votes. | SELECT DISTINCT T1.Fname FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.CLASS_Senator_VOTE | CREATE TABLE STUDENT (Fname VARCHAR, StuID VARCHAR); CREATE TABLE VOTING_RECORD (CLASS_Senator_VOTE VARCHAR) | [
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Find the distinct ages of students who have secretary votes in the fall election cycle. | SELECT DISTINCT T1.Age FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.Secretary_Vote WHERE T2.Election_Cycle = "Fall" | CREATE TABLE VOTING_RECORD (Secretary_Vote VARCHAR, Election_Cycle VARCHAR); CREATE TABLE STUDENT (Age VARCHAR, StuID VARCHAR) | [
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Find the distinct Advisor of students who have treasurer votes in the spring election cycle. | SELECT DISTINCT T1.Advisor FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.Treasurer_Vote WHERE T2.Election_Cycle = "Spring" | CREATE TABLE STUDENT (Advisor VARCHAR, StuID VARCHAR); CREATE TABLE VOTING_RECORD (Treasurer_Vote VARCHAR, Election_Cycle VARCHAR) | [
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Find the distinct majors of students who have treasurer votes. | SELECT DISTINCT T1.Major FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.Treasurer_Vote | CREATE TABLE VOTING_RECORD (Treasurer_Vote VARCHAR); CREATE TABLE STUDENT (Major VARCHAR, StuID VARCHAR) | [
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Find the first and last names of all the female (sex is F) students who have president votes. | SELECT DISTINCT T1.Fname, T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.President_VOTE WHERE T1.sex = "F" | CREATE TABLE STUDENT (Fname VARCHAR, LName VARCHAR, StuID VARCHAR, sex VARCHAR); CREATE TABLE VOTING_RECORD (President_VOTE VARCHAR) | [
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Find the first and last name of all the students of age 18 who have vice president votes. | SELECT DISTINCT T1.Fname, T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.VICE_President_VOTE WHERE T1.age = 18 | CREATE TABLE STUDENT (Fname VARCHAR, LName VARCHAR, StuID VARCHAR, age VARCHAR); CREATE TABLE VOTING_RECORD (VICE_President_VOTE VARCHAR) | [
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How many male (sex is M) students have class senator votes in the fall election cycle? | SELECT COUNT(*) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = Class_Senator_Vote WHERE T1.Sex = "M" AND T2.Election_Cycle = "Fall" | CREATE TABLE VOTING_RECORD (Election_Cycle VARCHAR); CREATE TABLE STUDENT (StuID VARCHAR, Sex VARCHAR) | [
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... |
Find the number of students whose city code is NYC and who have class senator votes in the spring election cycle. | SELECT COUNT(*) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = Class_Senator_Vote WHERE T1.city_code = "NYC" AND T2.Election_Cycle = "Spring" | CREATE TABLE STUDENT (StuID VARCHAR, city_code VARCHAR); CREATE TABLE VOTING_RECORD (Election_Cycle VARCHAR) | [
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Find the average age of students who live in the city with code "NYC" and have secretary votes in the spring election cycle. | SELECT AVG(T1.Age) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = SECRETARY_Vote WHERE T1.city_code = "NYC" AND T2.Election_Cycle = "Spring" | CREATE TABLE STUDENT (Age INTEGER, StuID VARCHAR, city_code VARCHAR); CREATE TABLE VOTING_RECORD (Election_Cycle VARCHAR) | [
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Find the average age of female (sex is F) students who have secretary votes in the spring election cycle. | SELECT AVG(T1.Age) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = SECRETARY_Vote WHERE T1.Sex = "F" AND T2.Election_Cycle = "Spring" | CREATE TABLE STUDENT (Age INTEGER, StuID VARCHAR, Sex VARCHAR); CREATE TABLE VOTING_RECORD (Election_Cycle VARCHAR) | [
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Find the distinct first names of all the students who have vice president votes and whose city code is not PIT. | SELECT DISTINCT T1.Fname FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.VICE_PRESIDENT_Vote EXCEPT SELECT DISTINCT Fname FROM STUDENT WHERE city_code = "PIT" | CREATE TABLE STUDENT (Fname VARCHAR, city_code VARCHAR); CREATE TABLE STUDENT (Fname VARCHAR, StuID VARCHAR); CREATE TABLE VOTING_RECORD (VICE_PRESIDENT_Vote VARCHAR) | [
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Find the distinct last names of all the students who have president votes and whose advisor is not 2192. | SELECT DISTINCT T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = PRESIDENT_Vote EXCEPT SELECT DISTINCT LName FROM STUDENT WHERE Advisor = "2192" | CREATE TABLE STUDENT (LName VARCHAR, PRESIDENT_Vote VARCHAR, Advisor VARCHAR); CREATE TABLE STUDENT (LName VARCHAR, StuID VARCHAR); CREATE TABLE VOTING_RECORD (Id VARCHAR) | [
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Find the distinct last names of all the students who have president votes and whose advisor is 8741. | SELECT DISTINCT T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = PRESIDENT_Vote INTERSECT SELECT DISTINCT LName FROM STUDENT WHERE Advisor = "8741" | CREATE TABLE STUDENT (LName VARCHAR, PRESIDENT_Vote VARCHAR, Advisor VARCHAR); CREATE TABLE STUDENT (LName VARCHAR, StuID VARCHAR); CREATE TABLE VOTING_RECORD (Id VARCHAR) | [
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For each advisor, report the total number of students advised by him or her. | SELECT Advisor, COUNT(*) FROM STUDENT GROUP BY Advisor | CREATE TABLE STUDENT (Advisor VARCHAR) | [
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Report all advisors that advise more than 2 students. | SELECT Advisor FROM STUDENT GROUP BY Advisor HAVING COUNT(*) > 2 | CREATE TABLE STUDENT (Advisor VARCHAR) | [
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Report all majors that have less than 3 students. | SELECT Major FROM STUDENT GROUP BY Major HAVING COUNT(*) < 3 | CREATE TABLE STUDENT (Major VARCHAR) | [
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For each election cycle, report the number of voting records. | SELECT Election_Cycle, COUNT(*) FROM VOTING_RECORD GROUP BY Election_Cycle | CREATE TABLE VOTING_RECORD (Election_Cycle VARCHAR) | [
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Which major has the most students? | SELECT Major FROM STUDENT GROUP BY major ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE STUDENT (Major VARCHAR, major VARCHAR) | [
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-100,
-100,
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-100,
-100,
-100,
-100,... |
What is the most common major among female (sex is F) students? | SELECT Major FROM STUDENT WHERE Sex = "F" GROUP BY major ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE STUDENT (Major VARCHAR, major VARCHAR, Sex VARCHAR) | [
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-100,
-100,
-100,
-100... |
What is the city_code of the city that the most students live in? | SELECT city_code FROM STUDENT GROUP BY city_code ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE STUDENT (city_code VARCHAR) | [
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-100,
-100,
-100,
... |
How many products are there? | SELECT COUNT(*) FROM products | CREATE TABLE products (Id VARCHAR) | [
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0,
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-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-1... |
How many colors are there? | SELECT COUNT(*) FROM ref_colors | CREATE TABLE ref_colors (Id VARCHAR) | [
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-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,... |
How many characteristics are there? | SELECT COUNT(*) FROM CHARACTERISTICS | CREATE TABLE CHARACTERISTICS (Id VARCHAR) | [
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-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-... |
What are the names and buying prices of all the products? | SELECT product_name, typical_buying_price FROM products | CREATE TABLE products (product_name VARCHAR, typical_buying_price VARCHAR) | [
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-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-... |
List the description of all the colors. | SELECT color_description FROM ref_colors | CREATE TABLE ref_colors (color_description VARCHAR) | [
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-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,
-100,... |
Find the names of all the product characteristics. | SELECT DISTINCT characteristic_name FROM CHARACTERISTICS | CREATE TABLE CHARACTERISTICS (characteristic_name VARCHAR) | [
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-100,
-100,
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-100,
-100,
-100,
-100,
-100,
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What are the names of products with category "Spices"? | SELECT product_name FROM products WHERE product_category_code = "Spices" | CREATE TABLE products (product_name VARCHAR, product_category_code VARCHAR) | [
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-100,
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-100,
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List the names, color descriptions and product descriptions of products with category "Herbs". | SELECT T1.product_name, T2.color_description, T1.product_description FROM products AS T1 JOIN Ref_colors AS T2 ON T1.color_code = T2.color_code WHERE product_category_code = "Herbs" | CREATE TABLE Ref_colors (color_description VARCHAR, color_code VARCHAR); CREATE TABLE products (product_name VARCHAR, product_description VARCHAR, color_code VARCHAR) | [
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How many products are there under the category "Seeds"? | SELECT COUNT(*) FROM products WHERE product_category_code = "Seeds" | CREATE TABLE products (product_category_code VARCHAR) | [
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-100,
-100,
... |
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