blob_id
string
repo_name
string
path
string
length_bytes
int64
score
float64
int_score
int64
text
string
is_english
bool
3b343e3551776f7ea952f039008577bdfc36ae9c
ewertonews/learning_python
/inputs.py
222
4.15625
4
name = input("What is your name?\n") age = input("How old are you?\n") live_in = input("Where do you live?\n") string = "Hello {}! Good to know you are {} years old and live in {}" print(string.format(name, age, live_in))
true
9c3254d781dda926a1050b733044a62dd1325ec7
kevinsu628/study-note
/leetcode-notes/easy/array/27_remove_element.py
2,103
4.1875
4
''' Given an array nums and a value val, remove all instances of that value in-place and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. The order of elements can be changed. It doesn't matter what you leave beyond the new length. Example 1: Given nums = [3,2,2,3], val = 3, Your function should return length = 2, with the first two elements of nums being 2. It doesn't matter what you leave beyond the returned length. ''' ''' Approach 1: two pointers i: slow pointer j: fast pointer Intuition: we assign nums[i] to be nums[j] as long as nums[j] is different than the target The whole intuition of two pointer is to replace the array with unique values met by faster pointer ''' def removeElement(nums, val): i = 0; for j in range(len(nums)): if (nums[j] != val): nums[i] = nums[j]; i+=1 return i ''' Approach 2: Two Pointers - when elements to remove are rare Intuition Now consider cases where the array contains few elements to remove. For example, nums = [1,2,3,5,4], val = 4nums=[1,2,3,5,4],val=4. The previous algorithm will do unnecessary copy operation of the first four elements. Another example is nums = [4,1,2,3,5], val = 4nums=[4,1,2,3,5],val=4. It seems unnecessary to move elements [1,2,3,5][1,2,3,5] one step left as the problem description mentions that the order of elements could be changed. Algorithm When we encounter nums[i] = valnums[i]=val, we can swap the current element out with the last element and dispose the last one. This essentially reduces the array's size by 1. Note that the last element that was swapped in could be the value you want to remove itself. xBut don't worry, in the next iteration we will still check this element. ''' def removeElement(nums, val): i = 0 n = len(nums) while (i < n): if (nums[i] == val): nums[i] = nums[n - 1] # reduce array size by one n -= 1 else: i += 1 return n;
true
880f3286c2b5052bd5972a9803db32fd1581c68d
devilsaint99/Daily-coding-problem
/product_of_array_exceptSelf.py
680
4.3125
4
"""Given an array of integers, return a new array such that each element at index i of the new array is the product of all the numbers in the original array except the one at i. For example, if our input was [1, 2, 3, 4, 5], the expected output would be [120, 60, 40, 30, 24]. If our input was [3, 2, 1], the expected output would be [2, 3, 6].""" import numpy as np def product_of_Array(nums): product_list=[] prod=np.prod(nums) for item in nums: product=prod//item product_list.append(product) return product_list num_list=[1,2,3,4,5] num_list1=[3,2,1] print(product_of_Array(num_list)) print(product_of_Array(num_list1)) #GG
true
d997ee82822d758eddcedd6d47059bae5b7c7cac
akassharjun/basic-rsa-algorithm
/app.py
1,320
4.15625
4
# To create keys for RSA, one does the following steps: # 1. Picks (randomly) two large prime numbers and calls them p and q. # 2. Calculates their product and calls it n. # 3. Calculates the totient of n ; it is simply ( p −1)(q −1). # 4. Picks a random integer that is coprime to ) φ(n and calls this e. A simple way is to # just pick a random number ) > max( p,q . # 5. Calculates (via the Euclidean division algorithm) the multiplicative inverse of e # modulo ) φ(n and call this number d. from math import gcd import random def isPrime(x): return 2 in [x,2**x%x] def coprime(a, b): return gcd(a, b) == 1 def modinv(e, phi): d_old = 0; r_old = phi d_new = 1; r_new = e while r_new > 0: a = r_old // r_new (d_old, d_new) = (d_new, d_old - a * d_new) (r_old, r_new) = (r_new, r_old - a * r_new) return d_old % phi if r_old == 1 else None p, q = 13, 17 print("p =", p) print("q =", q) n = p * q print("n =", n) phi_n = (p-1)*(q-1) print("φ(n) =", phi_n) primes = [i for i in range(1,n) if isPrime(i)] coprimes = [] for x in primes: if (coprime(x, n)): coprimes.append(x) e = random.choice(coprimes) print("e =",e) d = modinv(e, phi_n) print("d =",d) print("Public Key is (", n, ",", e, ")") print("Private Key is (", n, ",", d, ")")
true
5d6d8d557279b809dba055dc702c186c0a5abebd
carlson9/KocPython2020
/in-classMaterial/day4/exception.py
375
4.1875
4
raise Exception print("I raised an exception!") raise Exception('I raised an exception!') try: print(a) except NameError: print("oops name error") except: print("oops") finally: print("Yes! I did it!") for i in range(1,10): if i==5: print("I found five!") continue print("Here is five!") else: print(i) else: print("I went through all iterations!")
true
5dfd71362ded3403b553bc743fab89bab02e2d38
BluFox2003/RockPaperScissorsGame
/RockPaperScissors.py
1,684
4.28125
4
#This is a Rock Paper Scissors game :) import random def aiChoice(): #This function generates the computers choice of Rock, Paper or Scissors x = random.randint(0,2) if x == 0: choice = "rock" if x == 1: choice = "paper" if x == 2: choice = "scissors" return choice def gameLoop(choice): #Main Game Loop playerChoice = input("Choose Rock, Paper or Scissors ") playerChoice = playerChoice.lower() if playerChoice == "rock": #If the player chooses Rock if choice == "rock": print("AI chose Rock, DRAW") elif choice == "paper": print("AI chose Paper, YOU LOSE") elif choice == "scissors": print("AI chose Scissors, YOU WIN") elif playerChoice == "paper": #If the player chooses Paper if choice == "rock": print("AI chose Rock, YOU WIN") elif choice == "paper": print("AI chose Paper, DRAW") elif choice == "scissors": print("AI chose Scissors, YOU LOSE") elif playerChoice == "scissors": #If the player chooses Scissors if choice == "rock": print("AI chose Rock, YOU LOSE") elif choice == "paper": print("AI chose Paper, YOU WIN") elif choice == "scissors": print("AI chose Scissors, DRAW") else: print("Oops you did a fuckywucky") #If the player chose none of the options repeat = input("Would you like to play again? Y/N ") #Asks the user if they wanna play again if repeat == "Y" or repeat == "y": gameLoop(choice) #Repeats the game loop elif repeat == "N" or repeat == "n": exit() #Ends the program print("Welcome to Rock, Paper, Scissors") ai = aiChoice() aiChoice() gameLoop(ai)
true
690c1fc35fdd3444d8e27876d9acb99e471b296b
gridl/cracking-the-coding-interview-4th-ed
/chapter-1/1-8-rotated-substring.py
686
4.34375
4
# Assume you have a method isSubstring which checks if one # word is a substring of another. Given two strings, s1 and # s2, write code to check if s2 is a rotation of s1 using only # one call to isSubstring (i.e., "waterbottle" is a rotation of # "erbottlewat"). # # What is the minimum size of both strings? # 1 # Does space complexity matter? # Not initially # Time complexity is the priority? # Yes def rotated_substr(word, rotat): if len(word) != len(rotat): return False rotat_conc = rotat + rotat return word in rotat_conc if __name__ == "__main__": print(rotated_substr("thisis", "isthis")) print(rotated_substr("hihiho", "hihole"))
true
f4890c20a78d87556d0136d38d1a1a40ac18c087
AlbertGithubHome/Bella
/python/list_test.py
898
4.15625
4
#list test print() print('list test...') classmates = ['Michael','Bob', 'Tracy'] print('classmates =', classmates) print('len(classmates) =', len(classmates)) print('classmates[1] =', classmates[1]) print('classmates[-1] =', classmates[-1]) print(classmates.append('Alert'), classmates) print(classmates.insert(2,'Bella'), classmates) print(classmates.pop(), classmates) #list 内容可以不一致 classmates[3] = 100 print(classmates) subclassmates = ['zhuzhu', 'xiaoshandian'] classmates[2] = subclassmates print(classmates) print('len(classmates) =', len(classmates)) #tuple test # the elements can not change print() print('tuple test...') numbers = (1, 2, 3) print(numbers) new_num = (1) print(new_num) new_num2 = (1,) print(new_num2) print('len(new_num2) =',len(new_num2)) #if the element of tuple is list, you can change the list elemnet #but you can not change tuple pointer
true
4740f88aedeb28db6bfb615af36dfed7d76fda0f
vincent-kangzhou/LeetCode-Python
/380. Insert Delete GetRandom O(1).py
1,434
4.1875
4
import random class RandomizedSet(object): def __init__(self): """ Initialize your data structure here. """ self.valToIndex = dict() self.valList = list() def insert(self, val): """ Inserts a value to the set. Returns true if the set did not already contain the specified element. :type val: int :rtype: bool """ if val in self.valToIndex: return False self.valToIndex[val] = len(self.valList) self.valList.append(val) return True def remove(self, val): """ Removes a value from the set. Returns true if the set contained the specified element. :type val: int :rtype: bool """ if val not in self.valToIndex: return False lastVal = self.valList[-1] valIndex = self.valToIndex[val] if lastVal != val: self.valToIndex[lastVal] = valIndex self.valList[valIndex] = lastVal self.valList.pop() self.valToIndex.pop(val) return True def getRandom(self): """ Get a random element from the set. :rtype: int """ return random.choice( self.valList ) # Your RandomizedSet object will be instantiated and called as such: # obj = RandomizedSet() # param_1 = obj.insert(val) # param_2 = obj.delete(val) # param_3 = obj.getRandom()
true
b3b008d706062e0b068dd8287cfb101a7e268dd9
vincent-kangzhou/LeetCode-Python
/341. Flatten Nested List Iterator.py
2,132
4.21875
4
# """ # This is the interface that allows for creating nested lists. # You should not implement it, or speculate about its implementation # """ # class NestedInteger(object): # def isInteger(self): # """ # @return True if this NestedInteger holds a single integer, rather than a nested list. # :rtype bool # """ # # def getInteger(self): # """ # @return the single integer that this NestedInteger holds, if it holds a single integer # Return None if this NestedInteger holds a nested list # :rtype int # """ # # def getList(self): # """ # @return the nested list that this NestedInteger holds, if it holds a nested list # Return None if this NestedInteger holds a single integer # :rtype List[NestedInteger] # """ class NestedIterator(object): def __init__(self, nestedList): """ Initialize your data structure here. :type nestedList: List[NestedInteger] """ self.stack = [ [nestedList, 0] ] def _moveToValid(self): """ move stack to a valid position, so that the last place is an integer """ while self.stack: lastList, lastIdx = self.stack[-1] if lastIdx<len(lastList) and lastList[lastIdx].isInteger(): return elif lastIdx == len(lastList): self.stack.pop() if self.stack: self.stack[-1][1] += 1 elif lastList[lastIdx].isInteger() == False: self.stack.append( [ lastList[lastIdx].getList(), 0 ] ) def next(self): """ :rtype: int """ self._moveToValid() lastList, lastIdx = self.stack[-1] ret = lastList[lastIdx].getInteger() self.stack[-1][1] += 1 return ret def hasNext(self): """ :rtype: bool """ self._moveToValid() return bool(self.stack) # Your NestedIterator object will be instantiated and called as such: # i, v = NestedIterator(nestedList), [] # while i.hasNext(): v.append(i.next())
true
eb36a1f18bb74176c9e5d3739f2a7b7353af4afe
bhavin-rb/Mathematics-1
/Multiplication_table_generator.py
655
4.6875
5
''' Multiplication generator table is cool. User can specify both the number and up to which multiple. For example user should to input that he/she wants to seea table listing of the first 15 multiples of 3. Because we want to print the multiplication table from 1 to m, we have a foor loop at (1) that iterates over each of these numbers, printing the product itself and the number, a. ''' def multi_table(a): for i in range(1, int(m)): # for loop --- (1) print('{0} x {1} = {2}'.format(a, i, a * i)) if __name__ == '__main__': a = input('Enter a number: ') m = input('Enter number of multiples: ') multi_table(float(a))
true
4bde10e50b2b57139aed6f6f74b915a0771062dd
Ayesha116/cisco-assignments
/assigment 5/fac1.py
869
4.6875
5
# Write a Python function to calculate the factorial of a number (a non-negative # integer). The function accepts the number as an argument. def fact(number): factorial = 1 for i in range(1,number+1): factorial = factorial*i print(factorial) fact(4) # # Python program to find the factorial of a number provided by the user. # # change the value for a different result # num = 3 # # To take input from the user # #num = int(input("Enter a number: ")) # factorial = 1 # # check if the number is negative, positive or zero # if num < 0: # print("Sorry, factorial does not exist for negative numbers") # elif num == 0: # print("The factorial of 0 is 1") # else: # for i in range(1,num + 1): # factorial = factorial*i # print("The factorial of",num,"is",factorial)
true
4801ff9cb5d83bd385b3f650a3ba808d7f3cf229
Ayesha116/cisco-assignments
/assigment 5/market6.py
670
4.34375
4
# Question: 6 # Suppose a customer is shopping in a market and you need to print all the items # which user bought from market. # Write a function which accepts the multiple arguments of user shopping list and # print all the items which user bought from market. # (Hint: Arbitrary Argument concept can make this task ease) def marketitem(*shoppinglist): for elements in shoppinglist: print("you brought:", elements) shoppinglist = [] while True: a = input(shoppinglist) print(a, "you buy from market if you leave enter quit:") if shoppinglist == "quit": break shoppinglist.append(a) marketitem(shoppinglist)
true
d7f20fbdee7d28a99591ab6bc4d3baf14f4a1920
aarizag/Challenges
/LeetCode/Algorithms/longest_substring.py
747
4.1875
4
""" Given a string, find the length of the longest substring without repeating characters. """ """ Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. """ def lengthOfLongestSubstring(s: str) -> int: letter_locs = {} cur, best, from_ind = 0, 0, 0 for i, l in enumerate(s): if l in letter_locs: from_ind = from_ind if from_ind > letter_locs[l] else letter_locs[l] cur = i - from_ind else: cur += 1 letter_locs[l] = i best = cur if cur > best else best return best print(lengthOfLongestSubstring("abccbade")) print(lengthOfLongestSubstring("abba")) print(lengthOfLongestSubstring(""))
true
052bcd3e8b2293371303450d3281f56c98498521
harish-515/Python-Projects
/Tkinter/script1.py
1,203
4.375
4
from tkinter import * #GUI are generated using window & widgets window = Tk() """ def km_to_miles(): print(e1_value.get()) miles = float(e1_value.get())*1.6 t1.insert(END,miles) b1=Button(window,text="Execute",command=km_to_miles) # pack & grid are used to make these button to visible b1.grid(row=0,column=0) e1_value=StringVar() e1=Entry(window,textvariable=e1_value) e1.grid(row=0,column=1) t1 = Text(window,height=1,width=20) t1.grid(row=0,column=2) """ def kg_to_others(): grams.delete("1.0",END) pounds.delete("1.0",END) ounces.delete("1.0",END) grams.insert(END,float(kg.get())*1000) pounds.insert(END,float(kg.get())*2.20426) ounces.insert(END,float(kg.get())*35.274) kg_label = Label(window,text="Kgs : ") kg_value = StringVar() kg = Entry(window,textvariable=kg_value) grams = Text(window,height=1,width=20) pounds = Text(window,height=1,width=20) ounces = Text(window,height=1,width=20) convertbtn = Button(window,text="Convert",command=kg_to_others) kg_label.grid(row=0,column=0) kg.grid(row=0,column=1) convertbtn.grid(row=0,column=2) grams.grid(row=1,column=0) pounds.grid(row=1,column=1) ounces.grid(row=1,column=2) window.mainloop()
true
51f27da75c6d55eeddacaa9cef05a3d1d97bb0db
r-fle/ccse2019
/level3.py
1,500
4.21875
4
#!/usr/bin/env python3 from pathlib import Path import string ANSWER = "dunno_yet" ########### # level 3 # ########### print("Welcome to Level 3.") print("Caeser cipher from a mysterious text file") print("---\n") """ There is text living in: files/mysterious.txt You've got to try and figure out what the secret message contained in it is. The enemy have hidden it in between lots of junk, but one of our operatives suspects it may contain references to a computer scientist born in 1815. """ # TASK: # Load the file. Find the hidden message and decrypt it. # Feel free to copy in any code from previous levels that you need. # EXAMPLE CODE: # 1. Tell python where our file is # 2. Read in the file content # 3. Split the file content up into lines f = Path(__file__).parent / "files" / "mysterious.txt" content = f.read_text() all_lines = content.split("\n") # Let's check out the first 5 lines. What's in this file? for i in range(5): print(all_lines[i]) print() # Time to do some secret message hunting... for line in all_lines: # Something goes here, right? print(".", end="") print("\n") print("The solution is:", ANSWER) ################### # level 3 - bonus # ################### # TASK # Depending how you accomplished the above, there might have been another solution. # Did you encrypt first, or decrypt first? # TASK # What would you do if you didn't know any of the plaintext content? # Is there a way to score how likely it is that a given result is correct?
true
59b53e13a6f8bb9d2d606de898fc92738e5bd10b
imyoungmin/cs8-s20
/W3/p6.py
692
4.125
4
''' Write a program which takes 5 strings as inputs and appends them to a list l. Swap each element in l with its mirror - that is, for some element at index i, swap l[i] with l[4-i] if i < 3. For instance, if l = ['Alex', 'Bob', 'Charlie', 'David', 'Ethan'], then after swapping, l should read ['Ethan', 'David', 'Charlie', 'Bob', 'Alex'] Finally, finish the program by creating a dictionary mapping each name to its length. ''' # Solution here l = [] while len(l) < 5: l.append(input("Enter a name: ")) temp = l[0] temp1 = l[1] l[0] = l[4] l[1] = l[3] l[3] = temp1 l[4] = temp print(l) name_to_length = {} for name in l: name_to_length[name] = len(name) print(name_to_length)
true
c46fc22351db7e3fdafadde09aea6ae45b7c6789
rajatthosar/Algorithms
/Sorting/qs.py
1,682
4.125
4
def swap(lIdx, rIdx): """ :param lIdx: Left Index :param rIdx: Right Index :return: nothing """ temp = array[lIdx] array[lIdx] = array[rIdx] array[rIdx] = temp def partition(array, firstIdx, lastIdx): """ :param array: array being partitioned :param firstIdx: head of the array :param lastIdx: tail of the array :return: index of pivot element after sorting """ pivot = array[lastIdx] # Counter i is used as a marker to fill the array with all # elements smaller than pivot. At the end of the loop # pivot is swapped with the next position of i as all the # elements before pivot are smaller than it lowIdx = firstIdx - 1 # Note that range function stops the sequence generation at # lastIdx. This means that there will be # (lastIdx - firstIdx) - 1 elements in the sequence. # The last item generated in the sequence will be lastIdx - 1 for arrayIdx in range(firstIdx, lastIdx): if array[arrayIdx] <= pivot: lowIdx += 1 swap(lowIdx, arrayIdx) swap(lowIdx + 1, lastIdx) return lowIdx + 1 def quickSort(array, firstIdx, lastIdx): """ :param array: Array to be sorted :param firstIdx: head of the array :param lastIdx: tail of the array :return: sorted array """ if firstIdx < lastIdx: pivot = partition(array, firstIdx, lastIdx) quickSort(array, firstIdx, pivot - 1) quickSort(array, pivot + 1, lastIdx) print(array) if __name__ == "__main__": array = [10, 80, 30, 90, 40, 50, 70] firstIdx = 0 lastIdx = len(array) - 1 quickSort(array, firstIdx, lastIdx)
true
68fc5fd6c86607595d5eb547218c7a55781f3389
manjulive89/JanuaryDailyCode2021
/DailyCode01092021.py
1,381
4.5625
5
# ------------------------------------------- # Daily Code 01/09/2021 # "Functions" Lesson from learnpython.org # Coded by: Banehowl # ------------------------------------------- # Functions are a convenient way to divide your code into useful blocks, allowing order in the code, make it # more readable, reuse it, and save some time. Also fuctions are a key way to define interfaces so # programmers can share their code. # How to write functions in Python def my_function(): # Functions are define using the block keyword "def" print("Hello From My Function!") # Functions may also receive arguments (variables passed from the caller to the function) def my_function_with_args(username, greeting): print("Hello, %s, From My Function! I wish you %s" % (username, greeting)) # Fuctions may return a value to the caller, using the keyword "return" def sum_two_number(a, b): return a + b # To call functions in Python, simply write teh function's the name followed by (), placing any required # arguments within the bracket. Using the previous functions we defined: # print(a simple greeting) my_function() # prints - "Hello, Joe Doe, From My Function! I wish you a great year!" my_function_with_args("John Doe", "a great year!") # after this line x will hold the value 3 x = sum_two_number(1, 2) print(x)
true
9d1b835fd8b5e6aeadb4ff23d54c2bc0b5435b2f
manjulive89/JanuaryDailyCode2021
/DailyCode01202021.py
1,831
4.3125
4
# ----------------------------------------------- # Daily Code 01/20/2021 # "Serialization" Lesson from learnpython.org # Coded by: Banehowl # ----------------------------------------------- # Python provides built-in JSON libraries to encode and decode JSON # Python 2.5, the simplejson module is used, whereas in Python 2.7, the json module is used. # In order to use the json module, it must be imported: import json # There are two basic formats for JSON data. Either in a string or the object datastructure. # The object datastructure, in Python, consists of lists and dictionaries nested inside each other. # The object datastructure allows one to use python methods (for lists and dictionaries) to add, list, # search and remove elements from the datastructure. # # The String format is mainly used to pass the data into another program or load into a datastructure. # To load JSON back to a data structure, use the "loads" method. This method takes a string and turns # it back into the json object datastructure. To encode a data structure to JSON, use the "dumps" method. # This method takes an object and returns a String: json_string = json.dumps([1, 2, 3, "a", "b", "c"]) print(json.loads(json_string)) # Sample Code using JSON: # import json #it's already imported so... # fix this function, so it adds the given name # and salary pair to salaries_json, and return it def add_employee(salaries_json, name, salary): salaries = json.loads(salaries_json) salaries[name] = salary return json.dumps(salaries) # test code salaries = '{"Alfred" : 300, "Jane" : 400 }' new_salaries = add_employee(salaries, "Me", 800) decoded_salaries = json.loads(new_salaries) print(decoded_salaries["Alfred"]) print(decoded_salaries["Jane"]) print(decoded_salaries["Me"])
true
5cac576e1c3b2e1ecd67bfd71ab20bc765b4eee3
jtm192087/Assignment_8
/ps1.py
960
4.46875
4
#!/usr/bin/python3 #program for adding parity bit and parity check def check(string): #function to check for a valid string p=set(string) s={'0','1'} if s==p or p=={'0'} or p=={'1'}: print("It is a valid string") else: print("please enter again a valid binary string") if __name__ == "_main_" : string=input("please enter a valid binary string\n") check(string) #calling check function substring='1' count=string.count(substring) print("count is:",count) if count%2==0: #to add parity bit at the end of the binary data if no. one,s is even string=string+'1' print("The parity corrected data is: ",string) #print corrected data else: string=string+'0' print("The parity corrected data is: ",string) print("\n") string2=string.replace("010","0100") #replacing the '010' substring by '0100' print("The transmitting data is: ",string2)
true
578f3caf2d4247460b9331ae8f8b2a9cc56a4a74
EgorVyhodcev/Laboratornaya4
/PyCharm/individual.py
291
4.375
4
print("This program computes the volume and the area of the side surface of the Rectangular parallelepiped") a, b, c = input("Enter the length of 3 sides").split() a = int(a) b = int(b) c = int(c) print("The volume is ", a * b * c) print("The area of the side surface is ", 2 * c * (a + b))
true
2531327f966f606597577132fa9e54f7ed0be407
Rotondwatshipota1/workproject
/mypackage/recursion.py
930
4.1875
4
def sum_array(array): for i in array: return sum(array) def fibonacci(n): '''' this funtion returns the nth fibonacci number Args: int n the nth position of the sequence returns the number in the nth index of the fibonacci sequence '''' if n <= 1: return n else: return fibonacci(n-1) + fibonacci(n-2) def factorial(n): '''' this funtion returns the factorial of a give n intheger args: n it accepts an intger n as its argument returns : the number or the factorial of the given number '''' if n < 1: return 1 else: return n * factorial(n-1) def reverse(word): '''' this funtion returns a word in a reverse order args : word it accepts a word as its argument return: it returns a given word in a reverse order '''' if word == "": return word else: return reverse(word[1:]) + word[0]
true
338f94f012e3c673777b265662403e5ef05a5366
alyssaevans/Intro-to-Programming
/Problem2-HW3.py
757
4.3125
4
#Author: Alyssa Evans #File: AlyssaEvans-p2HW3.py #Hwk #: 3 - Magic Dates month = int(input("Enter a month (MM): ")) if (month > 12) or (month < 0): print ("Months can only be from 01 to 12.") day = int(input("Enter a day (DD): ")) if (month % 2 == 0) and (day > 30) or (day < 0): print("Incorrect amount of days for that month.") if (month % 2 != 0) and (day > 31) or (day < 0): print("Incorrect amount of days for that month") if (month == 2) and (day > 29): print("February has a maximum of 29 days.") year = int(input("Enter a year (YY): ")) if (year > 10): print("You have to enter a two digit year.") if (month * day == year): print("The date you chose is magic!") else: print("The date you chose isn't magic.")
true
3b0f3bd8d100765ae7cb593a791c9f2908b1ce76
rossvalera/inf1340_2015_asst2
/exercise1.py
2,159
4.1875
4
#!/usr/bin/env python """ Assignment 2, Exercise 1, INF1340, Fall, 2015. Pig Latin This module converts English words to Pig Latin words """ __author__ = 'Sinisa Savic', 'Marcos Armstrong', 'Susan Sim' __email__ = "ses@drsusansim.org" __copyright__ = "2015 Susan Sim" __license__ = "MIT License" def pig_latinify(word): """ This function will translate any English word to Pig latin :param word: Any word using the alphabet :return: The word will get translated to Pig Latin If the first letter is a vowel will add "yay" to the end If the first letter is a consonant will take all consonants up until teh worst vowel and add them to the end with "ay" added """ # variables defined and used within code original = word.lower() pig = "yay" # For this assignment we will consider y a vowel always vowel = ["a", "e", "i", "o", "u"] index = 0 found_letter = -1 # Makes sure that all inputs are actual letters and not numbers if len(original) > 0 and original.isalpha(): # Checks each letter of a given word to until first vowel is found for i in original: if i in vowel: found_letter = index break index += 1 # no vowel found thus will return given word with "ay" at the end if found_letter == -1: no_vowel = original + pig[1:] return no_vowel # When first letter in the given word is a vowel will return the word with "yay" at the end elif found_letter == 0: first_vowel = original + pig return first_vowel # Will take all consonants up until the vowel in a word # Will return the word starting with the vowel and will add the removed consonants and "ay" to the end else: first_consonant = original[found_letter:] + original[0:found_letter] + pig[1:] return first_consonant # Any word that doesnt only use alphabetical characters will return "try again" # No input will also return "try again" else: return "try again" # Function Commented out # print(pig_latinify(""))
true
a00293978a88a612e4b7a3ea532d334f43a279d5
CooperMetts/comp110-21f-workspace
/sandbox/dictionaries.py
1,329
4.53125
5
"""Demonstrations of dictonary capabilities.""" # Declaring the type of a dictionary schools: dict[str, int] # Intialize to an empty dictonary schools = dict() # set a key value pairing in the dictionary schools["UNC"] = 19400 schools["Duke"] = 6717 schools["NCSU"] = 26150 # Print a dictonary literal representation print(schools) # Access a value by its key -- "lookup" print(f"UNC has {schools['UNC']} students.") # Remove a key-value pair from a dictonary by its key schools.pop("Duke") # Test for existence of a key # This is a boolean expression saying 'Duke' (the key) in schools (the dictonary) is_duke_present: bool = "Duke" in schools print(f"Duke is present: {is_duke_present}.") # Update / Reassign a key-value pair schools["UNC"] = 20000 schools["NCSU"] = schools["NCSU"] + 200 print(schools) # Demonstration of dictonary literals # Empty dictionary literal # This --> schools = {} is a dictionary literal and this --> dict() is a dictionary constructor schools = {} # Same as dict() # Alternatively, intiatlize key-value pairs schools = {"UNC": 19400, "Duke": 6717, "NCSU": 26150} print(schools) # What happens when a you try to access a key that does not exist: print(schools["UNCC"]) # Gives you KeyError: "UNCC" for school in schools: print(f"Key: {school} -> Value: {schools[school]}")
true
590cab46ee48d2e7380fd4025683f4321d9a1a34
dipak-pawar131199/pythonlabAssignment
/Introduction/SetA/Simple calculator.py
642
4.1875
4
# Program to make simple calculator num1=int(input("Enter first number: ")) num2=int(input("Enter second number: ")) ch=input(" Enter for opration symbol addition (+),substraction (-),substraction (*),substraction (/), % (get remainder) and for exit enter '$' ") if ch=='+': print("Sum is : ",num1+num2) if ch== "-": print("Difference is : ",num1-num2) if ch=='*': print("Multiplication is : ",num1*num2) if ch=='/': print("Division is : ",num1-num2) if ch=='%': print("Moduls is : ",num1%num2) if ch=='$': print("Buy");
true
86c83cf3af2c57cc3250540ec848a3d5924b6d4b
dipak-pawar131199/pythonlabAssignment
/Functions/Sumdigit.py
691
4.15625
4
(""" 1) Write a function that performs the sum of every element in the given number unless it comes to be a single digit. Example 12345 = 6 """) def Calsum(num): c=0;sum=0 while num>0: # loop for calcuating sum of digits of a number lastdigit=num%10 sum+=lastdigit num=num//10 k=sum while k>0:# loop for count number of digit of sum c=c+1 k=k//10 if c>1: # if digit count 'c' >1 Calsum(sum) # recursive call to Calsum() function else: print(sum) # display sum whose digit count is 1 num=int(input("Enter number: ")) Calsum(num)
true
df13a154e79b15d5a9b58e510c72513f8f8e2fa0
dipak-pawar131199/pythonlabAssignment
/Conditional Construct And Looping/SetB/Fibonacci.py
550
4.1875
4
'''4) Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: a. 0, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... b. By considering the terms in the Fibonacci sequence whose values do not exceed four hundred, find the sum of the even-valued terms. ''' num=int(input("enter how many fibonacci series number is display:")) f0=1 f1=1 print("Terms of fibonaccie series is:") print(f0,f1) i=2 while i < num: f=f0+f1 f0=f1 f1=f print(f) i=i+1
true
10e021531d1b56e1375e898e7599422de0ce5c9a
RobStepanyan/OOP
/Random Exercises/ex5.py
776
4.15625
4
''' An iterator ''' class Iterator: def __init__(self, start, end, step=1): self.index = start self.start = start self.end = end self.step = step def __iter__(self): # __iter__ is called before __next__ once print(self) # <__main__.Iterator object at 0x000001465A203DC8> return self def __next__(self): if not (self.index + self.step) in range(self.start, self.end+self.step): raise StopIteration else: self.index += self.step return self.index - self.step iteratable = Iterator(0, 10, 2) while True: try: print(iteratable.__next__()) # or print(next(iterable)) except StopIteration: break ''' Result: 0 2 4 6 8 '''
true
9de5002aa797d635547bb7ca1989a435d4a97256
altvec/lpthw
/ex32_1.py
571
4.46875
4
the_count = [1, 2, 3, 4, 5] fruits = ['apples', 'oranges', 'pears', 'apricots'] change = [1, 'pennies', 2, 'dimes', 3, 'quarters'] # this first kind of for-loop goes through a list for number in the_count: print "This is count {0}".format(number) # same as above for fruit in fruits: print "A fruit of type: {0}".format(fruit) # also we can go through mixed lists too for i in change: print "I got {0}".format(i) # we can also build lists elements = xrange(0, 6) # now we can print then out too for i in elements: print "Element was: {0}".format(i)
true
b8e6af4affac0d2ae50f36296cc55f52c6b44af3
PacktPublishing/Software-Architecture-with-Python
/Chapter04/defaultdict_example.py
1,374
4.1875
4
# Code Listing #7 """ Examples of using defaultdict """ from collections import defaultdict counts = {} text="""Python is an interpreted language. Python is an object-oriented language. Python is easy to learn. Python is an open source language. """ word="Python" # Implementations with simple dictionary for word in text.split(): word = word.lower().strip() try: counts[word] += 1 except KeyError: counts[word] = 1 print("Counts of word",word,'=>',counts[word]) cities = ['Jakarta','Delhi','Newyork','Bonn','Kolkata','Bangalore','Seoul'] cities_len = {} for city in cities: clen = len(city) # First create entry if clen not in cities_len: cities_len[clen] = [] cities_len[clen].append(city) print('Cities grouped by length=>',cities_len) # Implementation using default dict # 1. Counts counts = defaultdict(int) for word in text.split(): word = word.lower().strip() # Value is set to 0 and incremented by 1 in one go counts[word] += 1 print("Counts of word",word,'=>',counts[word]) # 2. Cities grouped by length cities = ['Jakarta','Delhi','Newyork','Bonn','Kolkata','Bangalore','Seoul'] cities_len = defaultdict(list) for city in cities: # Empty list is created as value and appended to in one go cities_len[len(city)].append(city) print('Cities grouped by length=>',cities_len)
true
97b15762af24ba6fb59fc4f11320e99ffcec6cf4
rxxxxxxb/PracticeOnRepeat
/Python Statement/practice1.py
540
4.125
4
# Use for, .split(), and if to create a Statement that will print out words that start with 's' st = 'Print only the words that start with s in this sentence' for word in st.split(): if word[0] == 's': print(word) # even number using range li = list(range(1,15,2)) print(li) #List comprehension to create a list of number devisible by 3 div3 = [x for x in range(1,50) if x%3 == 0 ] print(div3) #using list comprehension for 1st letter in every word firstLetter = [word[0] for word in st.split()] print(firstLetter)
true
70c96ccdda8fec43e4dc2d85ba761bae2c4de876
heyimbarathy/py_is_easy_assignments
/pirple_functions.py
978
4.15625
4
# ----------------------------------------------------------------------------------- # HOMEWORK #2: FUNCTIONS # ----------------------------------------------------------------------------------- '''create 3 functions (with the same name as those attributes), which should return the corresponding value for the attribute. extra: create a function that returns a boolean''' year_recorded = 2003 artist = 'Snow Patrol' def show_favorite_band(artist): return artist #function with default def return_recording_year(year = 1900): return year # function without parameters def echo_best_song(): return 'Run' def search_artist(s): '''tests if a substring is part of the artist name''' return s in artist # test functions through print statements print(f"{echo_best_song()} ({return_recording_year(year_recorded)}) – {show_favorite_band(artist)}") print("There were no songs released in:", return_recording_year()) print(search_artist('Snow')) print(search_artist('Sun'))
true
910185af5c3818d848aa569d6e57de868c9cb790
heyimbarathy/py_is_easy_assignments
/pirple_lists.py
1,311
4.15625
4
# ----------------------------------------------------------------------------------- # HOMEWORK #4: LISTS # ----------------------------------------------------------------------------------- '''Create a function that allows you to add things to a list. Anything that's passed to this function should get added to myUniqueList, unless its value already exists in myUniqueList. (If the value doesn't exist already, it should be added and the function should return True. If the value does exist, it should not be added, and the function should return False) Add some code below that tests the function, showcasing the different scenarios, and then finally print the value of myUniqueList extra: Add another function that pushes all the rejected inputs into a separate global array called myLeftovers. ''' myUniqueList = [] myLeftovers = [] def compile_unique_list(item): '''depending on uniqueness, allocate item to myUniqueList or myLeftovers''' if item not in myUniqueList: myUniqueList.append(item) return True else: myLeftovers.append(item) return False # test entries compile_unique_list('dog') compile_unique_list(4) compile_unique_list(True) compile_unique_list(4) compile_unique_list('lucky') # print both lists print('Unique list:', myUniqueList) print('Left-overs:', myLeftovers)
true
5045f39041869fd81a8c406159a1bec39e4b7372
abdelilah-web/games
/Game.py
2,707
4.15625
4
class Game: ## Constractor for the main game def __init__(self): print('Welcome to our Games') print('choose a game : ') print('press [1] to play the Even-odd game') print('Press [2] to play the Average game') print('Press [3] to play the Multiplication') self.choose() ################################################## ##Availabale choises def choose(self): while True: select = input('your choise : ') try: select = int(select) if select == 1: print() print() self.Even_odd() elif select == 2 : print() print() self.Average() elif select == 3 : print() print() self.Multiplication() else : print('Please choose between 1, 2 or 3 ') except ValueError: print('Please Enter a valid number') ################################################## ##Even Odd code def Even_odd(self) : print('Welcome to the Even Odd game') while True: number = input('Enter your number : ') if number == 'x': print('End Of the game') print('...') break try : number = int(number) if number % 2 == 0: print('Even number') else: print('Odd number') except ValueError : print('Please enter a valid number') ################################################## ##Average Code def Average(self) : print('Welcome to the Average game') how_number = int(input('how many number do you want to summ : ')) zero = 0 summ = 0 while how_number > zero : numbers = int(input('your number : ')) zero += 1 summ += numbers print(summ/how_number) ################################################### ##Multiplication Table game code def Multiplication(self) : print('Welcome to the Multiplication') start = int(input('Enter the first number : ')) end = int(input('Enter the final number : ')) for x in range(start,end+1): for y in range(1,13): print(x,' X ',y ,' = ' ,x*y) print('__________________________________') ## Create Object from the Class play = Game()
true
b9b5e983017845ef38400a7d8ad8c9e35333d405
bghoang/coding-challenge-me
/leetcode/Other (not caterogize yet)/maxProductThreeNumbers.py
1,411
4.25
4
''' Given an integer array, find three numbers whose product is maximum and output the maximum product. Example 1: Input: [1,2,3] Output: 6 Example 2: Input: [1,2,3,4] Output: 24 ''' ''' First solution: O(nlogn) runtime/ O(logn) space caus of sortings Sort the array, Find the product of the last 3 numbers Find the product of the first 2 numbers and the last number Return max of those 2 product Optimal solution: O(n) runtime/ O(1) space Find the 3 biggest numbers and 2 smallest numbers Loop through the list, update these numbers Find the product of the 3 biggest numbers Find the product of the 2 smallest numbers and the biggest number Return max of the these 2 products ''' def maximumProduct(nums): # First solution ''' nums.sort() l = len(nums) if l < 3: return product1 = nums[l-1] * nums[l-2] * nums[l-3] product2 = nums[l-1] * nums[0] * nums[1] return max(product1, product2) ''' max1, max2, max3 = float('-inf'), float('-inf'), float('-inf') min1, min2 = float('inf'), float('inf') for num in nums: if num >= max1: max3, max2, max1 = max2, max1, num elif num >= max2: max3, max2 = max2, num elif num > max3: max3 = num if num <= min1: min2, min1 = min1, num elif num < min2: min2 = num return max(max1*max2*max3, min1*min2*max1)
true
17756e03f8022ead554e7ec67add12ea22a45cb5
lj015625/CodeSnippet
/src/main/python/stack/minMaxStack.py
1,932
4.125
4
""" Write a class for Min Max Stack. Pushing and Popping value from the stack; Peeking value at top of the stack; Getting both minimum and maximum value in the stack at any time. """ from collections import deque class MinMaxStack: def __init__(self): # doubly linked list deque is more efficient to implement large sized stack self.minMaxStack = deque() # O(1) time O(1) space def peek(self): return self.minMaxStack[-1]['number'] # O(1) time O(1) space def pop(self): return self.minMaxStack.pop()['number'] # O(1) time O(1) space def push(self, number): # default min and max to current number when stack is empty currMinMax = {'min': number, 'max': number, 'number': number} if len(self.minMaxStack) > 0: lastMinMax = self.minMaxStack[-1] currMin = min(number, lastMinMax['min']) currMax = max(number, lastMinMax['max']) currMinMax = {'min': currMin, 'max': currMax, 'number': number} self.minMaxStack.append(currMinMax) # O(1) time O(1) space def getMin(self): lastItem = self.minMaxStack[-1] return lastItem['min'] # O(1) time O(1) space def getMax(self): lastItem = self.minMaxStack[-1] return lastItem['max'] import unittest def testMinMaxPeek(self, min, max, peek, stack): self.assertEqual(stack.getMin(), min) self.assertEqual(stack.getMax(), max) self.assertEqual(stack.peek(), peek) class TestProgram(unittest.TestCase): def test_case_1(self): stack = MinMaxStack() stack.push(5) testMinMaxPeek(self, 5, 5, 5, stack) stack.push(7) testMinMaxPeek(self, 5, 7, 7, stack) stack.push(2) testMinMaxPeek(self, 2, 7, 2, stack) self.assertEqual(stack.pop(), 2) self.assertEqual(stack.pop(), 7) testMinMaxPeek(self, 5, 5, 5, stack)
true
f2e670471bfa9bcac1e5f983ecdb0240eeaaf1f2
lj015625/CodeSnippet
/src/main/python/array/sumOfTwoNum.py
1,598
4.125
4
"""Given an array and a target integer, write a function sum_pair_indices that returns the indices of two integers in the array that add up to the target integer if not found such just return empty list. Note: even though there could be many solutions, only one needs to be returned.""" def sum_pair_indices(array, target): index_holder = {} for i in range(len(array)): current_number = array[i] complement = target - current_number if complement in index_holder: return [index_holder[complement], i] else: index_holder[current_number] = i return [] array = [1, 2, 3, 4] target = 5 print(sum_pair_indices(array, target)) def twoNumberSum(array, targetSum): # use hashset O(n) time O(n) space saved = {} for current_num in array: complement = targetSum - current_num if complement in saved: return [current_num, complement] else: # use dict as a hashset not a hashmap saved[current_num] = complement return [] array = [3,5,-4,8,11,1,-1,6] target = 10 print(twoNumberSum(array, target)) def twoNumberSum2(array, targetSum): # use sorting O(nlogn) time O(1) space array.sort() left = 0 right = len(array) - 1 while left < right: currentSum = array[left] + array[right] if currentSum == targetSum: return [array[left], array[right]] elif currentSum < targetSum: left += 1 elif currentSum > targetSum: right -= 1 return [] print(twoNumberSum2(array, target))
true
153468d2ee32d18c1fe7cd6ee705d0f2e38c6ac2
lj015625/CodeSnippet
/src/main/python/string/anagram.py
626
4.28125
4
"""Given two strings, write a function to return True if the strings are anagrams of each other and False if they are not. A word is not an anagram of itself. """ def is_anagram(string1, string2): if string1 == string2 or len(string1) != len(string2): return False string1_list = sorted(string1) string2_list = sorted(string2) return string1_list == string2_list string_1 = "listen" string_2 = "silent" print(is_anagram(string_1, string_2)) string_1 = "banana" string_2 = "bandana" print(is_anagram(string_1, string_2)) string_1 = "banana" string_2 = "banana" print(is_anagram(string_1, string_2))
true
ce33d6bb0f0db42a8a0b28543f1ea6895da0d00c
lj015625/CodeSnippet
/src/main/python/tree/binarySearch.py
1,055
4.1875
4
def binary_search_iterative(array, target): if not array: return -1 left = 0 right = len(array)-1 while left <= right: mid = (left + right) // 2 # found the target if array[mid] == target: return mid # if target is in first half then search from the start to mid elif target < array[mid]: right = mid - 1 # search from the mid to end else: left = mid + 1 return -1 arr = [0, 1, 21, 33, 45, 45, 61, 71, 72, 73] target = 33 print(binary_search_iterative(arr, target)) def binarySearch(array, target): return binarySearchHelper(array, target, 0, len(array) - 1) def binarySearchHelper(array, target, left, right): while left <= right: mid = (left + right) // 2 if target == array[mid]: return mid elif target < array[mid]: right = mid - 1 else: left = mid + 1 return -1 # Test array arr = [ 2, 3, 4, 10, 40] target = 10 print(binarySearch(arr, target))
true
0ecfc8d40c1d7eba616676d03f04bb9bf187dc09
xamuel98/The-internship
/aliceAndBob.py
414
4.4375
4
# Prompt user to enter a string username = str(input("Enter your username, username should be alice or bob: ")) ''' Convert the username to lowercase letters and compare if the what the user entered correlates with accepted string ''' if username.lower() == "alice" or username.lower() == "bob": print("Welcome to programming with python " + username) else: print("Invalid username...")
true
ed4ebe2d41a2da81d843004f32223f0662e59053
ParulProgrammingHub/assignment-1-kheniparth1998
/prog10.py
308
4.125
4
principle=input("enter principle amount : ") time=input("enter time in years : ") rate=input("enter the interest rate per year in percentage : ") def simple_interest(principle,time,rate): s=(principle*rate*time)/100 return s print "simple interest is : ",simple_interest(principle,rate,time)
true
8e73474a9ac03600fee353f5f64259dae9840592
Sachey-25/TimeMachine
/Python_variables.py
1,234
4.21875
4
#Practice : Python Variables #Tool : Pycharm Community Edition #Platform : WINDOWS 10 #Author : Sachin A #Script starts here '''Greet'='This is a variable statement' print(Greet)''' #Commentning in python # -- Single line comment #''' ''' or """ """ multiline comment print('We are learning python scripting and practice the same in pycharm And Varibales ') '''[A-Za-z _] [AnyEnlishWords and _]''' variable = 1000 _another = 2000 CONSDATA=3.14 #Mulitple assignemnt a,b,c,d=10,20,30,40 print("Value of c is : ",c) print(a,b,c,d) #first number number_one=10 #second number number_two=20 #addition of two numbers print("Addition of two numbes :" ,number_one+number_two) #Dynamical allocation '''name = input("What is your name ?") print(name)''' number_third=input("Enter a number: ") number_fourth=input("Enter another number: ") print("Additon of entered number is :" , number_third+number_fourth) #By default input prompt recives inputs as strings #Implicit conversion -- #Explicit conversion number_third=int(input("Enter a number: ")) number_fourth=int(input("Enter another number: ")) print("Additon of entered number is :" , number_third+number_fourth) #Script Ends here
true
1e8e3b23f03923e87e1910f676cda91e93bc02c8
skyesyesyo/AllDojo
/python/typelist.py
929
4.25
4
#input one = ['magical unicorns',19,'hello',98.98,'world'] #output "The array you entered is of mixed type" "String: magical unicorns hello world" "Sum: 117.98" # input two = [2,3,1,7,4,12] #output "The array you entered is of integer type" "Sum: 29" # input three = ['magical','unicorns'] #output "The array you entered is of string type" "String: magical unicorns" def typelist(somelist): sum = 0 string = "" for value in somelist: if type(value) is int or type(value) is float: sum = sum + value elif type(value) is str: string = string+value+" " if(sum>0 and string != ""): print "The array you entered is mixed type" elif(sum>0 and string == ""): print "The array you entered is of integer type" elif(sum==0 and string !=""): print "The array you entered is of string type" print "String: {}".format(string) if sum != 0: print "Sum: {}".format(sum) typelist(one) typelist(two) typelist(three)
true
584c4e36f9801a63fd17adae4c750647d0afeec8
linth/learn-python
/class/specificMethod-3.py
606
4.3125
4
''' specific method - __str__() and __repr__() - __repr__() magic method returns a printable representation of the object. - The __str__() magic method returns the string Reference: - https://www.geeksforgeeks.org/python-__repr__-magic-method/?ref=rp ''' class GFG: def __init__(self, name): self.name = name def __str__(self) -> str: return f'Name is {self.name}' def __repr__(self) -> str: return f'GFG(name={self.name})' if __name__ == '__main__': obj = GFG('george') print(obj.__str__()) print(obj.__repr__())
true
a7ab0d16e3266d89e3119cfe59447d30062a9140
kelly4strength/intCakes
/intCake3.py
2,264
4.40625
4
# Given a list_of_ints, # find the highest_product you can get from three of the integers. # The input list_of_ints will always have at least three integers. # find max, pop, add popped to a new list_of_ints # add those ints bam! # lst = [11,9,4,7,13, 21, 55, 17] # returns [55, 21, 17] # 93 # lst = [0, 9, 7] # returns append three highest [9, 7] # None # if there are only 3 numbers in the list I need an if statement # to add them before going through the loop # if len(lst) == 3 then return three items added # lst = [2, 2, 2] # same issue as above # returns None # lst = [-1, 9, 8, -11] # append three highest [9, 8] # returns None # lst = [-1, -9, -8, -11] # returns # append three highest [-1, -8] # None # lst = [-1, -9, -8, -11, -2] # append three highest [-1, -2, -8] # [-1, -2, -8] # -11 def find_highest_product(lst): """function to find the highest product of three integers in a list, list will always have at least 3 integers""" # list for the three highest numbers three_highest = [] # product of three highest numbers product = None # if len(lst) == 3: # product_of_three_highest = reduce(lambda x, y: x+y, lst) # three_highest.append(product_of_three_highest) # print "lst only three" # return product_of_three_highest while len(three_highest) < 3: # else: # for num in lst: highest_num = max(lst) print "max", highest_num three_highest.append(highest_num) print "append three highest", three_highest lst.remove(highest_num) # lst.append(0) - only added this to keep the original list the same length... if len(three_highest) == 3: # multiply the remaining items in the list product_of_three_highest = reduce(lambda x, y: x+y, three_highest) print three_highest return product_of_three_highest print find_highest_product([-1, -9, -8, -11, -2]) # lst.remove(product_of_three) # for num in lst: # two = max(lst) # lst.remove(two) # for num in lst: # three = max(lst) # lst.remove(three) # # >>> lst = [3,7,2,9,11] # # >>> for num in lst: # add_top_three = 0 # # ... one = max(lst) # # ... lst.remove(one) # add_top_three += one # # ... print one # ... print lst # ... # 11 # [3, 7, 2, 9] # 9 # [3, 7, 2] # 7 # [3, 2] # >>>
true
d0434e4c42c139b85ec28c175749bb189d2a19bf
Francisco-LT/trybe-exercices
/bloco36/dia2/reverse.py
377
4.25
4
# def reverse(list): # reversed_list = [] # for item in list: # reversed_list.insert(0, item) # print(reversed_list) # return reversed_list def reverse(list): if len(list) < 2: return list else: print(f"list{list[1:]}, {list[0]}") return reverse(list[1:]) + [list[0]] teste = reverse([1, 2, 3, 4, 5]) print(teste)
true
d2d8f309a900c4642f0e7c66b3d33e26cabaf4e9
synaplasticity/py_kata
/ProductOfFibNumbers/product_fib_num.py
597
4.34375
4
def fibonacci(number): if number == 0 or number == 1: return number*number else: return fibonacci(number - 1) + fibonacci(number - 2) def product_fib_num(product): """ Returns a list of the two consecutive fibonacci numbers that give the provided product and a boolean indcating if those two consecutive numbers where found. """ for n in range(1, product): f1 = fibonacci(n) f2 = fibonacci(n + 1) if f1 * f2 == product or f1 * f2 > product: break return [f1, f2, f1 * f2 == product] # return list[0]
true
1687b77c4b2d3c44b6871e653a974153db7d3f96
ntuthukojr/holbertonschool-higher_level_programming-6
/0x07-python-test_driven_development/0-add_integer.py
578
4.125
4
#!/usr/bin/python3 """Add integer module.""" def add_integer(a, b=98): """ Add integer function. @a: integer or float to be added. @b: integer or float to be added (default set to 98). Returns the result of the sum. """ if not isinstance(a, int) and not isinstance(a, float): raise TypeError('a must be an integer') if not isinstance(b, int) and not isinstance(b, float): raise TypeError('b must be an integer') if isinstance(a, float): a = int(a) if isinstance(b, float): b = int(b) return (a + b)
true
53bf0300d334909355777fa043e37beb823bd7d2
NixonRosario/Encryption-and-Decryption
/main.py
2,772
4.1875
4
# This is a sample Python script. # Press Shift+F10 to execute it or replace it with your code. # Press Double Shift to search everywhere for classes, files, tool windows, actions, and settings. # The Encryption Function def cipher_encrypt(plain_text, key): # key is used has an swifting value encrypted = "" for c in plain_text: if c.isupper(): # check if it's an uppercase character c_index = ord(c) - ord('A') # ord('A') used because A is the first value in the alphabet # shift the current character by key positions c_shifted = (c_index + key) % 26 + ord('A') c_new = chr(c_shifted) encrypted += c_new elif c.islower(): # check if its a lowercase character # subtract the unicode of 'a' to get index in [0-25] range c_index = ord(c) - ord('a') c_shifted = (c_index + key) % 26 + ord('a') c_new = chr(c_shifted) encrypted += c_new elif c.isdigit(): # if it's a number,shift its actual value c_new = (int(c) + key) % 10 encrypted += str(c_new) else: # if its neither alphabetical nor a number, just leave it like that encrypted += c return encrypted # The Decryption Function def cipher_decrypt(ciphertext, key): decrypted = "" for c in ciphertext: if c.isupper(): c_index = ord(c) - ord('A') # shift the current character to left by key positions to get its original position c_og_pos = (c_index - key) % 26 + ord('A') c_og = chr(c_og_pos) decrypted += c_og elif c.islower(): c_index = ord(c) - ord('a') c_og_pos = (c_index - key) % 26 + ord('a') c_og = chr(c_og_pos) decrypted += c_og elif c.isdigit(): # if it's a number,shift its actual value c_og = (int(c) - key) % 10 decrypted += str(c_og) else: # if its neither alphabetical nor a number, just leave it like that decrypted += c return decrypted plain_text = input("Enter the message:- ") ciphertext1 = cipher_encrypt(plain_text, 4) # function calling is made print("Your text message:\n", plain_text) print("Encrypted ciphertext:\n", ciphertext1) n = input("If you want to decrypt any text press y else n: ") if n == "y": ciphertext = input("Enter the Encrypted text:- ") decrypted_msg = cipher_decrypt(ciphertext, 4) print("The decrypted message is:\n", decrypted_msg) else: print("Thank You!!")
true
29d0f0a5b83dbbcee5f053a2455f9c8722b6cb51
MrYsLab/pseudo-microbit
/neopixel.py
2,943
4.21875
4
""" The neopixel module lets you use Neopixel (WS2812) individually addressable RGB LED strips with the Microbit. Note to use the neopixel module, you need to import it separately with: import neopixel Note From our tests, the Microbit Neopixel module can drive up to around 256 Neopixels. Anything above that and you may experience weird bugs and issues. NeoPixels are fun strips of multi-coloured programmable LEDs. This module contains everything to plug them into a micro:bit and create funky displays, art and games Warning Do not use the 3v connector on the Microbit to power any more than 8 Neopixels at a time. If you wish to use more than 8 Neopixels, you must use a separate 3v-5v power supply for the Neopixel power pin. Operations Writing the colour doesn’t update the display (use show() for that). np[0] = (255, 0, 128) # first element np[-1] = (0, 255, 0) # last element np.show() # only now will the updated value be shown To read the colour of a specific pixel just reference it. print(np[0]) Using Neopixels Interact with Neopixels as if they were a list of tuples. Each tuple represents the RGB (red, green and blue) mix of colours for a specific pixel. The RGB values can range between 0 to 255. For example, initialise a strip of 8 neopixels on a strip connected to pin0 like this: import neopixel np = neopixel.NeoPixel(pin0, 8) Set pixels by indexing them (like with a Python list). For instance, to set the first pixel to full brightness red, you would use: np[0] = (255, 0, 0) Or the final pixel to purple: np[-1] = (255, 0, 255) Get the current colour value of a pixel by indexing it. For example, to print the first pixel’s RGB value use: print(np[0]) Finally, to push the new colour data to your Neopixel strip, use the .show() function: np.show() If nothing is happening, it’s probably because you’ve forgotten this final step..! Note If you’re not seeing anything change on your Neopixel strip, make sure you have show() at least somewhere otherwise your updates won’t be shown. """ from typing import Tuple, List, Union from microbit import MicroBitDigitalPin class NeoPixel: def __init__(self, pin: MicroBitDigitalPin, n: int): """ Initialise a new strip of n number of neopixel LEDs controlled via pin pin. Each pixel is addressed by a position (starting from 0). Neopixels are given RGB (red, green, blue) values between 0-255 as a tuple. For example, (255,255,255) is white. """ def clear(self) -> None: """ Clear all the pixels. """ def show(self) -> None: """ Show the pixels. Must be called for any updates to become visible. """ def __len__(self) -> int: pass def __getitem__(self, key) -> Tuple[int, int, int]: pass def __setitem__(self, key: int, value: Union[Tuple[int, int, int], List[int]]): pass
true
638715d691110084c104bba50daefd5675aea398
baif666/ROSALIND_problem
/find_all_substring.py
501
4.25
4
def find_all(string, substr): '''Find all the indexs of substring in string.''' #Initialize start index i = -1 #Creat a empty list to store result result = [] while True: i = string.find(substr, i+1) if i < 0: break result.append(i) return result if __name__ == '__main__': string = input('Please input your string : ') substr = input("Please input your substring : ") print('Result : ', find_all(string, substr))
true
b0cad0b1e60d45bc598647fa74cb1c584f23eeaa
JGMEYER/py-traffic-sim
/src/physics/pathing.py
1,939
4.1875
4
from abc import ABC, abstractmethod from typing import Tuple import numpy as np class Trajectory(ABC): @abstractmethod def move(self, max_move_dist) -> (Tuple[float, float], float): """Move the point along the trajectory towards its target by the specified distance. If the point would reach the target in less than the provided move distance, move the point only to the target destination. max_move_dist - maximum distance point can move towards target returns: (new_x, new_y), distance_moved """ pass class LinearTrajectory(Trajectory): """Trajectory that moves a point linearly towards a target point.""" def __init__(self, start_x, start_y, end_x, end_y): self._cur_x, self._cur_y = start_x, start_y self._end_x, self._end_y = end_x, end_y def move(self, max_move_dist) -> (Tuple[float, float], float): """See parent method for desc.""" dx = self._end_x - self._cur_x dy = self._end_y - self._cur_y # Optimization if dx == 0 or dy == 0: norm = max(abs(dx), abs(dy)) # Target reached if max_move_dist >= norm: return (self._end_x, self._end_y), max_move_dist - norm self._cur_x += np.sign(dx) * max_move_dist self._cur_y += np.sign(dy) * max_move_dist return (self._cur_x, self._cur_y), max_move_dist else: vector = np.array([dx, dy]) norm = np.linalg.norm(vector) # Target reached if max_move_dist >= norm: return (self._end_x, self._end_y), max_move_dist - norm unit = vector / norm self._cur_x, self._cur_y = tuple( np.array([self._cur_x, self._cur_y]) + max_move_dist * np.array(unit) ) return (self._cur_x, self._cur_y), max_move_dist
true
d45df8bc1090aee92d3b02bb4e1d42fc93c402a0
dheerajkjha/PythonBasics_Udemy
/programmingchallenge_addition_whileloop.py
285
4.25
4
number = int(input("Please enter an Integer number.")) number_sum = 0 print("Entered number by the user is: " + str(number)) while number > 0: number_sum = number_sum + number number = number - 1 print("Sum of the numbers from the entered number and 1 is: " + str(number_sum))
true
e96f81fc4967ca2dbb9993097f2653632b08a613
dheerajkjha/PythonBasics_Udemy
/programmingchallenge_numberofcharacters_forloop.py
258
4.34375
4
user_string = input("Please enter a String.") number_of_characters = 0 for letter in user_string: number_of_characters = number_of_characters + 1 print(user_string) print("The number of characters in the input string is: " + str(number_of_characters))
true
5e865b5a2ac4f087c4fe118e0423ef05908a4a09
reedless/dailyinterviewpro_answers
/2019_08/daily_question_20190827.py
528
4.5
4
''' You are given an array of integers. Return the largest product that can be made by multiplying any 3 integers in the array. Example: [-4, -4, 2, 8] should return 128 as the largest product can be made by multiplying -4 * -4 * 8 = 128. ''' def maximum_product_of_three(lst): lst.sort() cand1 = lst[0] * lst[1] * lst[-1] cand2 = lst[-3] * lst[-2] * lst[-1] if (cand1 > cand2): return cand1 else: return cand2 print (maximum_product_of_three([-4, -4, 2, 8])) # 128
true
5e9bb62185611666f43897fd2033bae28d91ee18
reedless/dailyinterviewpro_answers
/2019_08/daily_question_20190830.py
806
4.21875
4
''' Implement a queue class using two stacks. A queue is a data structure that supports the FIFO protocol (First in = first out). Your class should support the enqueue and dequeue methods like a standard queue. ''' class Queue: def __init__(self): self.head = [] self.stack = [] def enqueue(self, val): self.stack.append(val) def dequeue(self): while (self.stack): elem = self.stack.pop() self.head.append(elem) result = self.head.pop() while (self.head): elem = self.head.pop() self.stack.append(elem) return result q = Queue() q.enqueue(1) q.enqueue(2) q.enqueue(3) print (q.dequeue()) print (q.dequeue()) print (q.dequeue()) # 1 2 3
true
f1d328556b13e5d99c75d43cd750585184d9d9fa
deltahedge1/decorators
/decorators2.py
1,008
4.28125
4
import functools #decorator with no arguments def my_decorator(func): @functools.wraps(func) def function_that_runs_func(*args, **kwargs): #need to add args and kwargs print("in the decorator") func(*args, **kwargs) #this is the original function, dont forget to add args and kwargs print("after the decorator") return function_that_runs_func @my_decorator def my_function(x,y): print(x+y) my_function("hello ", "Ish") #decorators that can accepts arguments themselves def decorator_with_arguments(number): def my_decorator(func): @functools.wraps(func) def function_that_runs_func(*arg, **kwargs): #args and kwargs needed to pass in arguments to original function print("in the decorator") if number == 56: print("Not running the function!") else: func(*args, **kwargs) print("After the decorator") return function_that_runs_func return my_decorator
true
0ac3a65fea58acea5bc8ae4b1bbf9a4fb45b9f87
Hilamatu/cse210-student-nim
/nim/game/board.py
1,548
4.25
4
import random class Board: """A board is defined as a designated playing surface. The responsibility of Board is to keep track of the pieces in play. Stereotype: Information Holder Attributes: """ def __init__(self): self._piles_list = [] self._prepare() def to_string(self): """converts the board data to its string representation and returns it to the caller.""" print("-" *10) for count, value in enumerate(self._piles_list): print(f"{count}: " + "O " * value) print("-" *10) def apply(self, move): """applies a move to the playing surface. In this case, that means removing a number of stones from a pile. Accepts one argument, an instance of Move.""" pile = move.get_pile() stone = move.get_stones() reduce = self._piles_list[pile] - stone self._piles_list[pile] = reduce def is_empty(self): """determines if all the stones have been removed from the board. It returns True if the board has no stones on it; false if otherwise.""" empty = [0] * len(self._piles_list) return self._piles_list == empty def _prepare(self): """sets up the board with a random number of piles (2 - 5) containing a random number of stones (1 - 9).""" piles = random.randint(2, 5) for n in range(piles): stones = random.randint(1, 9) self._piles_list.append(stones)
true
686e53872c553c6dedc03dac6cf19806cc10b19e
NenadPantelic/Cracking-the-coding-Interview
/LinkedList/Partition.py
1,985
4.375
4
#!/usr/bin/env python3 # -*- coding: utf-8 -*- """ Created on Tue Mar 3 16:45:16 2020 @author: nenad """ """ Partition: Write code to partition a linked list around a value x, such that all nodes less than x come before all nodes greater than or equal to x. If x is contained within the list, the values of x only need to be after the elements less than x (see below). The partition element x can appear anywhere in the "right partition"; it does not need to appear between the left and right partitions. """ class Node: def __init__(self, data): # data -> value stored in node self.data = data self.next = None def partition(head, x): if head is None: return None # ll with elements less than x less_ll_head = None # ll with element greater than or equal to x greater_ll_head = None # last added nodes for both sublists prev_sm_node = None prev_gr_node = None node = head while node: # add to left sublist if node.data < x: if less_ll_head is None: less_ll_head = node else: prev_sm_node.next = node prev_sm_node = node #prev_sm_node.next = None else: if greater_ll_head is None: greater_ll_head = node else: prev_gr_node.next = node prev_gr_node = node #prev_gr_node.next = None node = node.next # make tails prev_sm_node.next = None prev_gr_node.next = None # concatenate lists prev_sm_node.next = greater_ll_head return less_ll_head def print_list(head): node = head while node: print(node.data, end=" ") node = node.next print() n1 = Node(3) n2 = Node(5) n3 = Node(8) n4 = Node(5) n5 = Node(10) n6 = Node(2) n7 = Node(1) n1.next = n2 n2.next = n3 n3.next = n4 n4.next = n5 n5.next = n6 n6.next = n7 x = 5 head = partition(n1, 5) print_list(head)
true
886195fb51ac965a88f3ad3c3d505548638cc6bd
JadsyHB/holbertonschool-python
/0x06-python-classes/102-square.py
2,010
4.59375
5
#!/usr/bin/python3 """ Module 102-square Defines Square class with private attribute, size validation and area accessible with setters and getters comparison with other squares """ class Square: """ class Square definition Args: size: size of side of square, default size is 0 Functions: __init__self, size) size(self) size(self, value) area(self) """ def __init__(self, size=0): """ Initilization of square Attributes: size: size of side of square, default value is 0 """ self.size = size @property def size(self): """ Getter Return: size """ return self.__size @size.setter def size(self, value): """ Setter Args: value: size is set to value when value is an int """ if type(value) is not int: raise TypeError("size must be an integer") elif value < 0: raise ValueError("size must be >= 0") else: self.__size = value def area(self): """ Calculates are of a square Returns: area """ return (self.__size)**2 def __eq__(self, other): """ Compares if equals """ return self.size == other.size def __ne__(self, other): """ Compares if not equals """ return self.size != other.size def __lt__(self, other): """ Compares if less than """ return self.size < other.size def __le__(self, other): """ Compares if less than or equal """ return self.size <= other.size def __gt__(self, other): """ Compares if greater than """ return self.size > other.size def __ge__(self, other): """ Compares if greater than or equal """ return self.size >= other.size
true
55ffa8c32622c42f6d3a314018a0adaf0e1c0d18
JadsyHB/holbertonschool-python
/0x06-python-classes/1-square.py
373
4.125
4
#!/usr/bin/python3 """ Module 1-square class Square defined with private attribute size """ class Square: """ class Square Args: size: size of a side in a square """ def __init__(self, size): """ Initialization of square Attributes: size: size of a side of a square """ self.__size = size
true
96384a26d49430e18697d080c49f3341e7b13834
23o847519/Python-Crash-Course-2nd-edition
/chapter_08/tryityourself814.py
874
4.4375
4
# 8-14. Cars: Write a function that stores information about # a car in a dictionary. The function should always receive # a manufacturer and a model name. It should then accept an # arbitrary number of keyword arguments. Call the function # with the required information and two other name-value # pairs, such as a color or an optional feature. Your # function should work for a call like this one: # car = make_car('subaru', 'outback', color='blue', # tow_package=True) # Print the dictionary that’s returned to make sure all # the information was stored correctly. print("\nEx 8.14 Cars\n" + "-"*70) def make_car(manufacturer, model, **car_info): car_info['manufacturer'] = manufacturer car_info['model'] = model return car_info car_profile = make_car(model = 'outback', manufacturer = 'subaru', color = 'blue', tow_package = True) print(car_profile)
true
e0f7b4c472500360a03266df6e35031cd4534dc4
23o847519/Python-Crash-Course-2nd-edition
/chapter_07/tryityourself7.1.py
334
4.15625
4
# Ex 7.1 Rental Car # Write a program that asks the user what kind of rental car they # would like. Print a message about that car, such as # “Let me see if I can find you a Subaru.” print("\nEx 7.1") rental_car = input("What kind of rental car would you like?\n") print(f"\nLet me see if I can find you a {rental_car.title()}.")
true
9cca96cb78e6ae2772c76f81ccf6a2106ee0ac99
23o847519/Python-Crash-Course-2nd-edition
/chapter_03/cars.py
604
4.28125
4
#Sorting print("\nSorting") cars = ['bmw', 'audi', 'toyota', 'subaru'] print(cars) cars.sort() print(cars) #Reverse sorting print("\nReverse sorting") cars.sort(reverse=True) print(cars) #Sort tạm thời print("\n Sorted()") cars = ['bmw', 'audi', 'toyota', 'subaru'] print("Original list:") print(cars) print("\nSorted list:") print(sorted(cars)) print("\nCome back to Original list:") print(cars) #Reverse list #Đảo ngược toàn bộ list print("\nReverse list") print(cars) cars.reverse() print(cars) #Length of List print("\nLength of List") cars.reverse() print(cars) print(len(cars))
true
44f55bae68ae6fa0fddd6628dea0c92e1f0d81fe
23o847519/Python-Crash-Course-2nd-edition
/chapter_10/tryityourself106.py
726
4.3125
4
# 10-6. Addition: One common problem when prompting for numerical input # occurs when people provide text instead of numbers. When you try to # convert the input to an int, you’ll get a ValueError. Write a program # that prompts for two numbers. Add them together and print the result. # Catch the ValueError if either input value is not a number, and print # a friendly error message. Test your program by entering two numbers # and then by entering some text instead of a number. print("\nEx 10.6 Addition\n" + "-"*70) print("Give me a number\n") try: num1 = input("First_number = ") num1 = int(num1) except ValueError: print("Value Error!, Enter a number next time.") else: print(f"Your number: {num1}")
true
6ba1d02a2025378d11c0cfbf8a11055e0593e3ca
radishmouse/06-2017-cohort-python
/104/n_to_m.py
629
4.375
4
n = int(raw_input("Start from: ")) m = int(raw_input("End on: ")) # Let's use a while loop. # Every while loop requires three parts: # - the while keyword # - the condition that stops the loop # - a body of code that moves closer to the "stop condition" # our loop counts up to a value. # let's declare a counter variable # and set the counter to start at n count = n # only run if count is less than or equal to the value of m while count <= m: # remember, we have to indent the body of our loop # print the current value of count print count # move us closer to the "stop condition" count = count + 1
true
50cbb178c40d42e83aed3f936feef223eca8a865
radishmouse/06-2017-cohort-python
/dictionaries/dictionary1.py
534
4.21875
4
phonebook_dict = { 'Alice': '703-493-1834', 'Bob': '857-384-1234', 'Elizabeth': '484-584-2923' } #Print Elizabeth's phone number. print phonebook_dict['Elizabeth'] #Add a entry to the dictionary: Kareem's number is 938-489-1234. phonebook_dict['Kareem'] = '938-489-1234' #Delete Alice's phone entry. del phonebook_dict['Alice'] #Change Bob's phone number to '968-345-2345'. phonebook_dict['Bob'] = '968-345-2345' #Print all the phone entries. for person, phone in phonebook_dict.items(): print "%s: %s" % (person, phone)
true
6ebffaee162c491cc4f2289845a1bf7bbcd33604
flub78/python-tutorial
/examples/conditions.py
374
4.1875
4
#!/usr/bin/python # -*- coding:utf8 -* print ("Basic conditional instructions\n") def even(a): if ((a % 2) == 0): print (a, "is even") if (a == 0): print (a, " == 0") return True else: print (a, "is odd") return False even(5) even(6) even(0) bln = even(6) if bln: print ("6 is even") print ("bye")
true
0e531d7c0b4da023818f02265ab9e009420eaec6
flub78/python-tutorial
/examples/test_random.py
1,395
4.1875
4
#!/usr/bin/python # -*- coding:utf8 -* """ How to use unittest execution: python test_random.py or python -m unittest discover """ import random import unittest class RandomTest(unittest.TestCase): """ Test case for random """ def test_choice(self): """ given: a list when: selecting a random elt then: it belongs ot the list """ lst = list(range(10)) # print lst elt = random.choice(lst) # print "random elt = ", elt self.assertIn(elt, lst) self.assertFalse(elt % 4 == 0, "True quite often") def test_shuffle(self): """ given: a list when: shuffled then: it still contains the same elements likely in different order """ lst = list(range(10)) shuffled = list(lst) # deep copy random.shuffle(shuffled) # print "lst =", lst # print "shuffled= ", shuffled sorted = list(shuffled) sorted.sort() # print "sorted = ", sorted same_order = True i = 0 while i < 10: same_order = same_order and (lst[i] == shuffled[i]) i += 1 self.assertEqual(sorted, lst) self.assertFalse(same_order, "list are not in the same order after shuffling") if __name__ == '__main__': unittest.main()
true
38081fd73316e20f6361d835d710dd379e8c78ea
andremmfaria/exercises-coronapython
/chapter_06/chapter_6_6_4.py
823
4.375
4
# 6-4. Glossary 2: Now that you know how to loop through a dictionary, clean up the code from Exercise 6-3 (page 102) by replacing your series of print statements with ía loop that runs through the dictionary’s keys and values. When you’re sure that your loop works, add five more Python terms to your glossary. When you run your program again, these new words and meanings should automatically be included in the output. valdict = { "variable": "Elementar data type that stores values", "loop": "Self repeating structure", "dictionary": "Glossary structure", "array": "List of elements", "conditional": "Conditional test", "word0": "Value0", "word1": "Value1", "word2": "Value2", "word3": "Value3", "word4": "Value4" } for key in valdict: print(key + ", " + valdict[key])
true
8c5498b935164c457447729c6de1553b390664e5
andremmfaria/exercises-coronapython
/chapter_06/chapter_6_6_8.py
522
4.34375
4
# 6-8. Pets: Make several dictionaries, where the name of each dictionary is the name of a pet. In each dictionary, include the kind of animal and the owner’s name. Store these dictionaries in a list called pets. Next, loop through your list and as you do print everything you know about each pet. pet_0 = { 'kind' : 'dog', 'owner' : 'Juliana' } pet_1 = { 'kind' : 'cat', 'owner' : 'Ana' } pet_2 = { 'kind' : 'fish', 'owner' : 'Joao' } pets = [pet_0, pet_1, pet_2] for p in pets: print(p)
true
7bc98b1c9a50acb1e7ff7fe3ce2781ace3a56eb8
andremmfaria/exercises-coronapython
/chapter_07/chapter_7_7_1.py
257
4.21875
4
# 7-1. Rental Car: Write a program that asks the user what kind of rental car they would like. Print a message about that car, such as “Let me see if I can find you a Subaru.” message = input("Let me see whether I can find you a Subaru") print(message)
true
5cb4a583ec8a49434d41500e142cb79879070d1a
mkccyro-7/Monday_test
/IF.py
226
4.15625
4
bis = int(input("enter number of biscuits ")) if bis == 3: print("Not eaten") elif 0 < bis < 3: print("partly eaten") elif bis == 0: print("fully eaten") else: print("Enter 3 or any other number less than 3")
true
4ccb729ebdb80510424aa920666f6b4f0acb5a2a
ErenEla/PythonSearchEngine
/Unit_1/Unit1_Hw3.py
1,060
4.1875
4
# IMPORTANT BEFORE SUBMITTING: # You should only have one print command in your function # Given a variable, x, that stores the # value of any decimal number, write Python # code that prints out the nearest whole # number to x. # If x is exactly half way between two # whole numbers, round up, so # 3.5 rounds to 4 and 2.5 rounds to 3. # You may assume x is not negative. # Hint: The str function can convert any number into a string. # eg str(89) converts the number 89 to the string '89' # Along with the str function, this problem can be solved # using just the information introduced in unit 1. # x = 3.14159 # >>> 3 (not 3.0) # x = 27.63 # >>> 28 (not 28.0) # x = 3.5 # >>> 4 (not 4.0) #ENTER CODE BELOW HERE x = 3.14159 x_round = str(round(x)) x_point = x_round.find(".") print(x_round[:x_point]) #Train Focus s = "CidatyUcityda" print('1',s[6]+s[-2:]+s[7:12]) print('2',s[6]+s[-2:]+s[7:11]) print('3',s[6]+s[2:4]+s[7:13]) print('4',s[-7]+s[2:4]+s[7:11]) print('5',s[6]+s[-2]+s[3]+s[:-2]+s[4:6]) print('6',s[6]+s[2]+s[3]+s[7:11])
true
4ed0dc77c6784f2006ca437568f80a73a8d51438
ErenEla/PythonSearchEngine
/Unit_3/Unit3_Quiz1.py
504
4.15625
4
# Define a procedure, replace_spy, # that takes as its input a list of # three numbers, and modifies the # value of the third element in the # input list to be one more than its # previous value. spy = [1,2,2] def replace_spy(x): x[0] = x[0] x[1] = x[1] x[2] = x[2]+1 return x # In the test below, the first line calls your # procedure which will change spy, and the # second checks you have changed it. # Uncomment the top two lines below. print(replace_spy(spy)) #>>> [0,0,8]
true
66c4d00e9ce49d8570cd7a703d04aef1b6b4d3f6
iSabbuGiri/Control-Structures-Python-
/qs_17.py
962
4.21875
4
#Python program that serves as a basic calculator def add(x,y): return x+y def subtract(x,y): return x-y def multiply(x,y): return x*y def divide(x,y): return x/y print("Select operation:") print("1.Add") print("2.Subtract") print("3.Multiply") print("4.Divide") while True: choice = input("Enter a choice(1/2/3/4):") if choice in ('1', '2', '3', '4'): num1 = float(input("Enter the first number:")) num2 = float(input("Enter the second number:")) if choice == '1': print(num1, "+", num2, "=", add(num1, num2) ) elif choice == '2': print(num1, "-", num2, "=", subtract(num1, num2) ) elif choice == '3': print(num1, "*", num2, "=", multiply(num1, num2) ) elif choice == '4': print(num1, "/", num2, "=", divide(num1, num2) ) break else: print("Invalid Input")
true
3ba2ea80dcc916bf8e245a2ab518042b9ee55e3e
richardrcw/python
/guess.py
270
4.1875
4
import random highest = 10 num = random.randint(1, highest) guess = -1 while guess != num: guess = int(input("Guess number between 1 and {}: ".format(highest))) if guess > num: print("Lower...") elif guess < num: print("Higher....") else: print("Got it!")
true
efabcf8f6f413c833a75c8cc5e57e556c2d12823
prathamarora10/guessingNumber
/GuessingNumber.py
561
4.21875
4
print('Number Guessing Game') print('Guess a Number (between 1 and 9):') import random number = random.randint(1,9) print(number) for i in range(0,5,1): userInput = int(input('Enter your Guess :- ')) if userInput < 3: print('Your guess was too low: Guess a number higher than 3') elif userInput < 5: print('Your guess was too low: Guess a number higher than 5') elif userInput < 7: print('Your guess was too low: Guess a number higher than 7') if userInput == number: print('Congratulations !\nYou Won !!')
true
39cebe0780b8532517dadf4fd04517b9ba79f207
Carterhuang/sql-transpiler
/util.py
922
4.375
4
def standardize_keyword(token): """ In returned result, all keywords are in upper case.""" return token.upper() def join_tokens(lst, token): """ While joining each element in 'lst' with token, we want to make sure each word is separated with space. """ _token = token.strip(' ') if _token == '': # token only has empty space(s) in it, # we make standardize it to be one empty space. _token = ' ' else: # Paddle a space on the left and right side of the token, # so that "AND" becomes " AND ". _token = ''.join([' ', standardize_keyword(_token), ' ']) return _token.join(map(str, lst)) def normalize_keyword(input_str): """ During transpiling, all reserved keywords(operators, macro/field headers, etc) are converted to lower case. e.g. 'AND' -> 'and', 'OR' -> 'or', etc. """ return input_str.lower()
true
8c9890c843a63d8b2fa90098b28594ba1e012d99
justinhohner/python_basics
/datatypes.py
1,042
4.34375
4
#!/usr/local/bin/python3 # https://www.tutorialsteacher.com/python/python-data-types # """ Numeric Integer: Positive or negative whole numbers (without a fractional part) Float: Any real number with a floating point representation in which a fractional component is denoted by a decimal symbol or scientific notation Complex number: A number with a real and imaginary component represented as x+yj. x and y are floats and j is -1(square root of -1 called an imaginary number) """ x = 1 print(x) y = 1.1 print(y) j = -1 print(j) i = x+j*y print(i) # Boolean a = True b = False print(a) print(b) # String a = "This is a string" print(a) # List a = ["This", "is", "a", "list"] print(a) # Tuple a = ("This", "is", "a", "list", 0) print(a) # Dictionary a = {1:"Steve", 2:"Bill", 3:"Ram", 4: "Farha"} print(a) a = {"Steve":1, "Bill":2, "Ram":3, "Farha":4} print(a) """ Create a variable to store your name and set it's value to your name Create a list of numbers from 1 to 10 add the first 3 values of the list of numbers """
true
9acddfa9dc609fbb3aad91d19c4348dda1aee239
jsanon01/100-days-of-python
/resources/day4/area_circumference_circle.py
427
4.59375
5
""" Fill out the functions to calculate the area and circumference of a circle. Print the result to the user. """ import math def area(r): return math.pi * r ** 2 def circumference(r): return math.pi * 2 * r radius = float(input("Circle radius: ")) circle_area = area(radius) circle_circumference = circumference(radius) print('Area: ' + str(circle_area)) print('Circumference: ' + str(circle_circumference))
true
e2ca488af3efc7e4d8f5bc72be4ac0a3f139edd9
saumyatiwari/Algorithm-of-the-day
/api/FirstAPI.py
790
4.125
4
import flask app=flask.Flask(__name__) #function name is app # use to create the flask app and intilize it @app.route("/", methods =['GET']) #Defining route and calling methods. GET will be in caps intalized as an arrya # if giving the giving any configuration then function name will proceed with @ else it will use name alone for example we are using @app name to updae the config of @app name def helloworld(): return "Helloworld" if __name__ == '__main__': app.run() # by default flask uses 5000 port and host as 0.0.0.0 # Run steps #1. Run with python FirstAPI.py #2. Flask will auto. create a server & start the flask app in dev mode #3. U can call ur API with address http://0.0.0.0:5000/ #4. First install the flask by command "pip3 install flask" before running the code
true
1544a910a16011cc302ba6bcb449c0c8887c05ee
msvrk/frequency_dict
/build/lib/frequency_dict/frequency_dict_from_collection.py
557
4.53125
5
def frequency_dict_from_collection(collection): """ This is a useful function to convert a collection of items into a dictionary depicting the frequency of each of the items. :param collection: Takes a collection of items as input :return: dict """ assert len(collection) > 0, "Cannot perform the operation on an empty collection" dictionary = {} keys = [] for item in collection: if item not in keys: keys.append(item) dictionary[item] = 0 dictionary[item] += 1 return dictionary
true
660a467f0428f2564fdeec4da7f5dc171b7a2e65
DivijeshVarma/CoreySchafer
/Decorators2.py
2,922
4.46875
4
# first class functions allow us to treat functions like any other # object, for example we can pass functions as arguments to another # function, we can return functions and we can assign functions to # variable. Closures-- it will take advantage of first class functions # and return inner function that remembers and has access to variables # local to scope in which they were created. def outer_func(mg): def inner_func(): print(mg) return inner_func hi_func = outer_func('hi') hello_func = outer_func('hello') hi_func() hello_func() # Decorator is function that takes another function as an argument # add some functionality and returns another function, all of this # without altering source code of original function you passed in. # Decorating our functions allow us to easily add functionality to # our existing functions, by adding functionality inside wrapper # without modifying original display function in any way and add # code in wrapper in any way def decorator_func(original_func): def wrapper_func(*args, **kwargs): print(f"wrapper function executed {original_func.__name__}") original_func(*args, **kwargs) return wrapper_func @decorator_func def display(): print('display function') @decorator_func def display_info(name, age): print(f"name:{name}, age:{age}") display() display_info('divi', 27) print('--------------------------------') ################################## class decorator_class(object): def __init__(self, original_func): self.original_func = original_func def __call__(self, *args, **kwargs): print(f"call method executed {self.original_func.__name__}") return self.original_func(*args, **kwargs) @decorator_class def display(): print('display function') @decorator_class def display_info(name, age): print(f"name:{name}, age:{age}") display() display_info('divi', 27) print('--------------------------------') ################################## def decorator_func(func): def wrapper_func(*args, **kwargs): print(f"wrapper executed before {func.__name__}") func(*args, **kwargs) print(f"wrapper executed after {func.__name__}") return wrapper_func @decorator_func def display_info(name, age): print(f"display function with {name} and {age}") display_info('divijesh', 27) print('--------------------------------') #################################### def prefix_decorator(prefix): def decorator_func(func): def wrapper_func(*args, **kwargs): print(f"{prefix} wrapper executed before {func.__name__}") func(*args, **kwargs) print(f"{prefix} wrapper executed after {func.__name__}") return wrapper_func return decorator_func @prefix_decorator('LOG:') def display_info(name, age): print(f"display function with {name} and {age}") display_info('divijesh', 27)
true
b1ebc3eeeceebdf1eb6760c88d00be6b40d9e5cd
DivijeshVarma/CoreySchafer
/generators.py
809
4.28125
4
def square_nums(nums): result = [] for i in nums: result.append(i * i) return result sq_nums = square_nums([1, 2, 3, 4, 5]) print(sq_nums) # square_nums function returns list , we could convert # this to generator, we no longer get list # Generators don't hold entire result in memory # it yield 1 result at a time, waiting for us to ask # next result # when you convert generators to list you lose performance # like list(sq_nums) def square_nums(nums): for i in nums: yield (i * i) sq_nums = square_nums([1, 2, 3, 4, 5]) print(sq_nums) print(next(sq_nums)) for num in sq_nums: print(num) # list comprehensions sqs = [x * x for x in [1, 2, 3, 4, 5]] print(sqs) # create generator sqs = (x * x for x in [1, 2, 3, 4, 5]) print(sqs) for num in sqs: print(num)
true
e328a29edf17fdeed4d8e6c620fc258d9ad28890
DivijeshVarma/CoreySchafer
/FirstclassFunctions.py
1,438
4.34375
4
# First class functions allow us to treat functions like # any other object, i.e we can pass functions as argument # to another function and returns functions, assign functions # to variables. def square(x): return x * x f1 = square(5) # we assigned function to variable f = square print(f) print(f(5)) print(f1) # we can pass functions as arguments and returns function # as result of other functions # if function accepts other functions as arguments or # return functions as a result i.e higher order function # adding paranthesis will execute function. # # we can pass functions as arguments:-- def square(x): return x * x def my_map(func, arg_list): result = [] for i in arg_list: result.append(func(i)) return result squares = my_map(square, [1, 2, 3, 4]) print(squares) # to return a function from another function, one of the # aspects for first class function # log variable is equal to log_message function, so we can # run log variable as just like function, it remembers # message from logger function def logger(msg): def log_message(): print(f"log: {msg}") return log_message log = logger('hi') log() # it remembers tag we passed earlier def html_tag(tag): def wrap_text(msg): print(f"<{tag}>{msg}<{tag}>") return wrap_text p_h1 = html_tag('h1') p_h1('Test headline') p_h1('Another headline') p_p1 = html_tag('p1') p_p1('Test paragraph')
true
4f9c1ddb562de274a644e6d41e73d70195929274
sairamprogramming/learn_python
/book4/chapter_1/display_output.py
279
4.125
4
# Program demonstrates print statement in python to display output. print("Learning Python is fun and enjoy it.") a = 2 print("The value of a is", a) # Using keyword arguments in python. print(1, 2, 3, 4) print(1, 2, 3, 4, sep='+') print(1, 2, 3, 4, sep='+', end='%') print()
true
64c62c53556f38d9783de543225b11be87304daf
sairamprogramming/learn_python
/pluralsight/core_python_getting_started/modularity/words.py
1,204
4.5625
5
# Program to read a txt file from internet and put the words in string format # into a list. # Getting the url from the command line. """Retrive and print words from a URL. Usage: python3 words.py <url> """ import sys def fetch_words(url): """Fetch a list of words from a URL. Args: url: The url of UTF-8 text document. Returns: A list of strings containing the words from the document. """ # Importing urlopen method. from urllib.request import urlopen # Getting the text from the url given. story = urlopen(url) story_words = [] for line in story: line_words = line.decode('utf8').split() for word in line_words: story_words.append(word) story.close() return story_words def print_items(items): """Prints items one per line. Args: An iterable series of printable items. """ for item in items: print(item) def main(url): """Prints each word from a text document from a URL. Args: url: The url of UTF-8 text document. """ words = fetch_words(url) print_items(words) if __name__ == '__main__': main(sys.argv[1])
true
99bd7e715f504ce64452c252ac93a026f426554d
gotdang/edabit-exercises
/python/factorial_iterative.py
414
4.375
4
""" Return the Factorial Create a function that takes an integer and returns the factorial of that integer. That is, the integer multiplied by all positive lower integers. Examples: factorial(3) ➞ 6 factorial(5) ➞ 120 factorial(13) ➞ 6227020800 Notes: Assume all inputs are greater than or equal to 0. """ def factorial(n): fact = 1 while n > 1: fact *= n n -= 1 return fact
true
30d9fe50769150b3efcaa2a1628ef9c7c05984fa
gotdang/edabit-exercises
/python/index_multiplier.py
428
4.125
4
""" Index Multiplier Return the sum of all items in a list, where each item is multiplied by its index (zero-based). For empty lists, return 0. Examples: index_multiplier([1, 2, 3, 4, 5]) ➞ 40 # (1*0 + 2*1 + 3*2 + 4*3 + 5*4) index_multiplier([-3, 0, 8, -6]) ➞ -2 # (-3*0 + 0*1 + 8*2 + -6*3) Notes All items in the list will be integers. """ def index_multiplier(lst): return sum([i * v for i, v in enumerate(lst)])
true
36f7db179bcc0339c7969dfa9f588dcd51c6d904
adarshsree11/basic_algorithms
/sorting algorithms/heap_sort.py
1,200
4.21875
4
def heapify(the_list, length, i): largest = i # considering as root left = 2*i+1 # index of left child right = 2*i+2 # index of right child #see if left child exist and greater than root if left<length and the_list[i]<the_list[left]: largest = left #see if right child exist and greater than root if right<length and the_list[largest]<the_list[right]: largest = right #change root if larger number caught as left or right child if largest!=i: the_list[i],the_list[largest]=the_list[largest],the_list[i] # heapify the new root heapify(the_list, length, largest) def heapSort(the_list): n = len(the_list) #heapify the full list for i in range(n//2-1, -1, -1): #heapify from last element with child to top heapify(unsorted_list, n, i) #heapsort sxtracting elements one by one for i in range(n-1, 0, -1): #swapping the root element which is max to its position the_list[i],the_list[0] = the_list[0],the_list[i] #heapify from root again length reduced to 'i' to keep sorted elements unchanged heapify(the_list, i, 0) if __name__ == '__main__': unsorted_list = [17,87,6,22,54,3,13,41] print(unsorted_list) heapSort(unsorted_list) print(unsorted_list)
true
88bf240c30c8373b3779a459698223ec3cb74e24
mliu31/codeinplace
/assn2/khansole_academy.py
836
4.1875
4
""" File: khansole_academy.py ------------------------- Add your comments here. """ import random def main(): num_correct = 0 while num_correct != 3: num1 = random.randint(10,99) num2 = random.randint(10,99) sum = num1 + num2 answer = int(input("what is " + str(num1) + " + " + str(num2) + "\n>>")) if sum == answer: num_correct += 1 print("Correct. You've gotten " + str(num_correct) + " problem(s) right in a row! ") if num_correct == 3: print("Congratulations! you've mastered addition") else: print("Incorrect. the expected answer is " + str(sum)) num_correct = 0 # This provided line is required at the end of a Python file # to call the main() function. if __name__ == '__main__': main()
true
346d3af90d21411c4265d7e232786fc4078f82fc
Tanay-Gupta/Hacktoberfest2021
/python_notes1.py
829
4.4375
4
print("hello world") #for single line comment '''for multi line comment''' #for printing a string of more than 1 line print('''Twinkle, twinkle, little star How I wonder what you are Up above the world so high Like a diamond in the sky Twinkle, twinkle little star How I wonder what you are''') a=20 b="hello" c=39.9 #here a is variable and its datatype is integer print(a) #how to print the datatype of a print(type(a)) print(type(c)) #how to print arithmetic results a=5 b=3 print ("the sum of a+b is",a+b) print ("the diff of a-b is",a-b) print ("the product of a*b is",a*b) # comparison operators a=(82<=98) print(a) # type conversion and type casting a="45" #this is a string # to convert into int a=int(a) print(type(a)) b= 34 print(type(b)) b=str(b) print(type(b))
true
f284bdf3b3929131be1fe943b3bd5761119f4c2e
sydney0zq/opencourses
/byr-mooc-spider/week4-scrapy/yield.py
1,088
4.53125
5
#! /usr/bin/env python3 # -*- coding: utf-8 -*- """ The first time the for calls the generator object created from your function, it will run the code in your function from the beginning until it hits yield, then it'll return the first value of the loop. Then, each other call will run the loop you have written in the function one more time, and return the next value, until there is no value to return. The generator is considered empty once the function runs but does not hit yield anymore. It can be because the loop had come to an end, or because you do not satisfy an "if/else" anymore. """ def gen(n): print("outside") for i in range(8): print ("inside") yield i ** 2 for i in gen(5): print (i, " ") print ("*" * 50) def gen2(n): print("outside") for i in range(n): print ("inside") yield i ** 2 n = 3 for i in gen2(n): #n = 10 this statement does NO effect print (i) print ("*" * 50) def square(n): print ("inside") ls = [i**2 for i in range(n)] return ls for i in square(5): print(i)
true
88806f1c3ee74fe801b26a11b0f66a3c7d6c881d
Kajabukama/bootcamp-01
/shape.py
1,518
4.125
4
# super class Shape which in herits an object # the class is not implemented class Shape(object): def paint(self, canvas): pass # class canvas which in herits an object # the class is not implemented class Canvas(object): def __init__(self, width, height): self.width = width self.height = height self.data = [[' '] * width for i in range(height)] # setter method which sets row and column def setpixel(self, row, col): self.data[row][col] = '*' # getter method that will get the values of row and column def getpixel(self, row, col): return self.data[row][col] def display(self): print "\n".join(["".join(row) for row in self.data]) # the subclass Rectangle which inherits from the Shape Superclass # inheritance concept class Rectangle(Shape): def __init__(self, x, y, w, h): self.x = x self.y = y self.w = w self.h = h # a method to draw a horizontal line def hline(self, x, y, w): self.x = x self.y = y self.w = w # another method that will draw a vertical line def vline(self, x, y, h): self.x = x self.y = y self.h = h # this method calls the other three methods # and draws the respective shapes on a camnvas def paint(self, canvas): hline(self.x, self.y, self.w) hline(self.x, self.y + self.h, self.w) vline(self.x, self.y, self.h) vline(self.x + self.w, self.y, self.h)
true
157b4ad717a84f91e60fb5dc108bcab8b2a21a12
jwu424/Leetcode
/RotateArray.py
1,275
4.125
4
# Given an array, rotate the array to the right by k steps, where k is non-negative. # 1. Make sure k < len(nums). We can use slice but need extra space. # Time complexity: O(n). Space: O(n) # 2. Each time pop the last one and inset it into the beginning of the list. # Time complexity: O(n^2) # 3. Reverse the list three times. # Time complexity: O(n) class Solution: def rotate1(self, nums: List[int], k: int) -> None: """ Do not return anything, modify nums in-place instead. """ k %= len(nums) nums[:] = nums[-k:] + nums[:-k] def rotate2(self, nums: List[int], k: int) -> None: """ Do not return anything, modify nums in-place instead. """ k %= len(nums) for _ in range(k): nums.insert(0, nums.pop()) def rotate3(self, nums: List[int], k: int) -> None: """ Do not return anything, modify nums in-place instead. """ k %= len(nums) self.reverse(nums, 0, len(nums)-1) self.reverse(nums, 0, k-1) self.reverse(nums, k, len(nums)-1) def reverse(self, nums, left, right): while left < right: nums[left], nums[right] = nums[right], nums[left] left += 1 right -= 1
true
da8890ff1f941e97b8174bc6e111272b6ffa0b20
OliverMorgans/PythonPracticeFiles
/Calculator.py
756
4.25
4
#returns the sum of num1 and num 2 def add(num1, num2): return num1 + num2 def divide(num1, num2): return num1 / num2 def multiply(num1, num2): return num1 * num2 def minus (num1, num2): return num1 - num2 #*,-,/ def main(): operation = input("what do you want to do? (+-*/): ") if(operation != "+" and operation != "-" and operation != "*" and operation != "/"): #invalid operation print("You must enter a valid operation (+-*/)") else: num1 = int(input("Enter num1: ")) num2 = int(input("Enter num2: ")) if(operation == "+"): print(add(num1, num2)) elif(operation == "-"): print(minus(num1, num2)) elif(operation == "*"): print(multiply(num1, num2)) elif(operation == "/"): print(divide(num1, num2)) main()
true
261a8ec6e763de736e722338241d2cf39a34c9b0
Rggod/codewars
/Roman Numerals Decoder-6/decoder.py
1,140
4.28125
4
'''Problem: Create a function that takes a Roman numeral as its argument and returns its value as a numeric decimal integer. You don't need to validate the form of the Roman numeral. Modern Roman numerals are written by expressing each decimal digit of the number to be encoded separately, starting with the leftmost digit and skipping any 0s. So 1990 is rendered "MCMXC" (1000 = M, 900 = CM, 90 = XC) and 2008 is rendered "MMVIII" (2000 = MM, 8 = VIII). The Roman numeral for 1666, "MDCLXVI", uses each letter in descending order. Example: solution('XXI') # should return 21 ''' def solution(roman): """complete the solution by transforming the roman numeral into an integer""" values = {'I' : 1 ,'V' : 5, 'X' : 10, 'L' : 50, 'C' : 100, 'D' : 500, 'M' : 1000} sum = 0 count = 0 while(count < len(roman)): cur = values.get(roman[count],' ') if count == len(roman) -1 or (cur >= values.get(roman[count+1],' ')): sum = sum + cur else: sum = sum +(values.get(roman[count+1],' ')-cur) count = count +1 count = count +1 return sum
true