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PASSED
2fd49b30a14ae783110b057bd210b28b
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedInputStream; import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class C { public static int[] solve(String[][] players) { int[] res = new int[3]; Map<String, Integer> hash = new HashMap<>(); for (String[] ws: players) { for (String w: ws) { hash.put(w, hash.getOrDefault(w, 0) + 1); } } for (int i = 0; i < 3; i++) { int ans = 0; for (String w: players[i]) { int v = hash.get(w); ans += (v == 1) ? 3 : ((v == 2) ? 1 : 0); } res[i] = ans; } return res; } public static void main(String[] args) { Scanner sc = new Scanner(new BufferedInputStream(System.in)); int kase = sc.nextInt(); while (kase-- > 0) { int n = sc.nextInt(); String[][] arr = new String[3][n]; for (int i = 0; i < 3; i++) { for (int j = 0; j < n; j++) { arr[i][j] = sc.next(); } } int[] res = solve(arr); System.out.printf("%d %d %d\n", res[0], res[1], res[2]); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
147f118dc5dccfd9d424c41867ac0d22
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class WordGame { public static void main(String[] args) { Scanner input = new Scanner(System.in); int T = input.nextInt(); HashMap<String, int[]> freq = new HashMap<>(); int[] points; while (T-- > 0) { points = new int[3]; freq.clear(); int N = input.nextInt(); for (int i = 0; i < 3; i++) { for (int j = 0; j < N; j++) { String str = input.next(); if (freq.containsKey(str)) { int[] arr = freq.get(str); arr[i] = 1; } else { freq.put(str, new int[3]); freq.get(str)[i] = 1; } } } for (String keys : freq.keySet()) { int[] arr = freq.get(keys); int cnt = 0; for (int i : arr) { if (i != 0) { cnt++; } } if (cnt == 1) { for (int i = 0; i < 3; i++) { if (arr[i] != 0) { points[i] += 3; break; } } } else if (cnt == 2) { for (int i = 0; i < 3; i++) { if (arr[i] != 0) { points[i] += 1; } } } else { } } for (int i = 0; i < 3; i++) { System.out.print(points[i] + " "); } System.out.println(); } input.close(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
6bf3a1212081b9314bc5114b8baebb55
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Main { public static void main(String []args) { Scanner in = new Scanner(System.in); int t = 1; t = in.nextInt(); while (t-->0) { int n=in.nextInt(); HashMap<String,Integer> mp=new HashMap<String,Integer>(); String X[][]=new String[3][n]; for (int i=0; i<3; i++) { for (int j=0; j<n; j++) { X[i][j]=in.next(); mp.put(X[i][j],mp.containsKey(X[i][j])?mp.get(X[i][j])+1:1); } } for (int i=0; i<3; i++) { int c=0; for (int j=0; j<n; j++) { int xx= mp.get(X[i][j]); if(xx==1) c+=3; else if(xx==2) c++; } System.out.print(c+" "); } System.out.println();} } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
7555597ee861c1ed180da71eb4122105
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class ProblemC { static HashMap<String,Integer> addToMap(HashMap<String,Integer> map,String word){ if(map.containsKey(word)){ int temp = map.get(word); map.put(word,++temp); } else{ map.put(word,1); } return map; } static int getScore(HashMap<String,Integer> map,String word){ int temp = map.get(word); if(temp == 3){return 0;} if(temp == 2){return 1;} return 3; } public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); for(int i=0;i<t;i++){ int len = sc.nextInt(); int[] scores = new int[3]; ArrayList<String> A = new ArrayList<String>(); ArrayList<String> B = new ArrayList<String>(); ArrayList<String> C = new ArrayList<String>(); HashMap<String,Integer> map = new HashMap<String,Integer>(); //Adding the scores for(int j=0;j<len;j++){ A.add(sc.next()); map = addToMap(map,A.get(j)); } for(int j=0;j<len;j++){ B.add(sc.next()); map = addToMap(map,B.get(j)); } for(int j=0;j<len;j++){ C.add(sc.next()); map = addToMap(map,C.get(j)); } //checking the words for(int j=0;j<len;j++){ scores[0]+=getScore(map,A.get(j)); scores[1]+=getScore(map,B.get(j)); scores[2]+=getScore(map,C.get(j)); } System.out.println(scores[0]+ " "+scores[1]+" "+scores[2]); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
8f6ce3566c20fd14b6eaaf9015401719
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import static java.util.Map.entry; import java.io.*; import java.util.*; import java.util.stream.Collectors; import java.math.*; public class Solution { private static final Map<Integer, Integer> NO_FO_WORDS = Map.ofEntries(entry(1, 3), entry(2, 1), entry(3, 0)); public static void main(String[] args) throws Exception { InputStream inputStream = System.in; OutputStream outputStream = System.out; InputReader in = new InputReader(inputStream); PrintWriter out = new PrintWriter(outputStream); // Task solver = new Task(); int testCases = in.nextInt(); for (int test = 1; test <= testCases; test += 1) { int n = in.nextInt(); String[][] words = new String[3][n]; for (int i = 0; i < words.length; i++) { for (int j = 0; j < words[i].length; j++) { words[i][j] = in.next(); } } System.out.println(Task.solve(words)); } out.close(); } static class Task { static final int MOD = (int) (1e9 + 7); static String solve(String[][] words) { Map<String, Integer> wordCount = new HashMap<>(); for (int i = 0; i < words.length; i++) { for (int j = 0; j < words[i].length; j++) { wordCount.put(words[i][j], wordCount.getOrDefault(words[i][j], 0) + 1); } } return Arrays.stream(words) .mapToInt( p -> Arrays.stream(p).mapToInt(word -> NO_FO_WORDS.get(wordCount.get(word))).sum()) .mapToObj(String::valueOf) .collect(Collectors.joining(" ")); } } static class InputReader { public BufferedReader take; public StringTokenizer split; public InputReader(InputStream stream) { take = new BufferedReader(new InputStreamReader(stream), 10000000); split = null; } public String next() { while (split == null || !split.hasMoreTokens()) { try { split = new StringTokenizer(take.readLine()); } catch (IOException e) { throw new RuntimeException(e); } } return split.nextToken(); } public int nextInt() { return Integer.parseInt(next()); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
36044aa51b93b413f61ab2f2621f35ba
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.Arrays; import java.util.HashSet; import java.util.Set; public class Main817C { public static void main(String[] args) throws IOException { BufferedReader input = new BufferedReader(new InputStreamReader(System.in)); int numberOfCases = Integer.parseInt(input.readLine()); for (int i = 0; i < numberOfCases; i++) { input.readLine(); Set<String> set1 = new HashSet<>(Arrays.asList(input.readLine().split(" "))); Set<String> set2 = new HashSet<>(Arrays.asList(input.readLine().split(" "))); Set<String> set3 = new HashSet<>(Arrays.asList(input.readLine().split(" "))); System.out.println(getCount(set1, set2, set3) + " " + getCount(set2, set1, set3) + " " + getCount(set3, set2, set1)); } } public static int getCount(Set<String> set1, Set<String> set2, Set<String> set3) { int count = 0; for (String s : set1) { if (!set2.contains(s) && !set3.contains(s)) count += 3; else if (set2.contains(s) ^ set3.contains(s)) count++; } return count; } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
706d7ea2275a8f6efb4a7a4cf8321237
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class _1722C_WordGame { public static void main(String[] args) { Scanner input = new Scanner(System.in); int t = input.nextInt(); while (t-- > 0) { solve(input); } } static void solve(Scanner input) { int len = input.nextInt(); HashSet<String> s1 = new HashSet<>(); HashSet<String> s2 = new HashSet<>(); HashSet<String> s3 = new HashSet<>(); for (int i = 0; i < len; i++) { s1.add(input.next()); } for (int i = 0; i < len; i++) { s2.add(input.next()); } for (int i = 0; i < len; i++) { s3.add(input.next()); } int first = 0; int second = 0; int third = 0; for (String s : s1) { int num = 0; num += s2.contains(s) ? 1: 0; num += s3.contains(s) ? 1: 0; if (num == 0) { first += 3; } else if (num == 1) { first++; } } for (String s : s2) { int num = 0; num += s1.contains(s) ? 1:0; num += s3.contains(s) ? 1:0; if (num == 0) { second += 3; } else if (num == 1) { second++; } } for (String s : s3) { int num = 0; num += s1.contains(s) ? 1 : 0; num += s2.contains(s) ? 1 : 0; if (num == 0) { third += 3; } else if (num == 1) { third++; } } System.out.println(String.format("%d %d %d", first, second, third)); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
bc028e97f6d7066ee0b92244c13cec9d
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class ProblemC { private static final Scanner sc = new Scanner(System.in); public static void main(String[] args) { int n = sc.nextInt(); for (int i = 0; i < n; i++) { solve(); } } private static void solve() { int wordsNum = sc.nextInt(); List<List<String>> words = new ArrayList<>(); Map<String, Integer> freq = new HashMap<>(); for (int i = 0; i < 3; i++) { List<String> currList = new ArrayList<>(); for (int j = 0; j < wordsNum; j++) { String str = sc.next(); currList.add(str); freq.put(str, freq.getOrDefault(str, 0) + 1); } words.add(currList); } for (int i = 0; i < 3; i++) { int pts = 0; for (String str : words.get(i)) { int freqNum = freq.get(str); if (freqNum == 1) pts += 3; else if (freqNum == 2) pts += 1; } System.out.print(pts + " "); } System.out.println(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
7cac72bfaf0480c7e9de9349d6025200
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedReader; import java.io.BufferedWriter; import java.io.Flushable; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStreamWriter; import java.util.Arrays; import java.util.HashSet; import java.util.Set; import java.util.StringTokenizer; public class Submit { public static void main(String... strings) throws IOException { try (InputReader reader = new InputReader(); OutputWriter writer = new OutputWriter(true)) { Set<String> s1; Set<String> s2; Set<String> s3; Set<String> allWords; int t = reader.nextInt(); while (t-- > 0) { int words = reader.nextInt(); allWords = new HashSet<>(); s1 = new HashSet<>(Arrays.asList(reader.nextLine().split(" "))); s2 = new HashSet<>(Arrays.asList(reader.nextLine().split(" "))); s3 = new HashSet<>(Arrays.asList(reader.nextLine().split(" "))); allWords.addAll(s1); allWords.addAll(s2); allWords.addAll(s3); int p1 = 0; int p2 = 0; int p3 = 0; boolean s1HasIt; boolean s2HasIt; boolean s3HasIt; for (String word : allWords) { s1HasIt = s1.contains(word); s2HasIt = s2.contains(word); s3HasIt = s3.contains(word); // urcite to niekto ma a urcite mam pici ked to maju seci if (s1HasIt && s2HasIt && s3HasIt) { // jebat } else if (s1HasIt && s2HasIt && !s3HasIt) { p1++; p2++; } else if (s1HasIt && !s2HasIt && s3HasIt) { p1++; p3++; } else if (!s1HasIt && s2HasIt && s3HasIt) { p2++; p3++; } else if (s1HasIt) { p1 += 3; } else if (s2HasIt) { p2 += 3; } else if (s3HasIt) { p3 += 3; } } writer.println(p1 + " " + p2 + " " + p3); } } } } class InputReader implements AutoCloseable { private BufferedReader bufferedReader; private StringTokenizer tokenizer; public InputReader() { bufferedReader = new BufferedReader(new InputStreamReader(System.in)); } public String next() { while (tokenizer == null || !tokenizer.hasMoreElements()) { try { tokenizer = new StringTokenizer(bufferedReader.readLine()); } catch (IOException ex) { ex.printStackTrace(); } } return tokenizer.nextToken(); } public char nextChar() { char character = ' '; try { character = (char) bufferedReader.read(); } catch (IOException e) { e.printStackTrace(); } return character; } public int nextInt() { return Integer.parseInt(next()); } public long nextLong() { return Long.parseLong(next()); } public double nextDouble() { return Double.parseDouble(next()); } public String nextLine() { String line = ""; try { line = bufferedReader.readLine(); } catch (IOException ex) { ex.printStackTrace(); } return line; } @Override public void close() { try { this.bufferedReader.close(); } catch (IOException ex) { ex.printStackTrace(); } } } class OutputWriter implements AutoCloseable, Flushable { private final BufferedWriter writer; private boolean autoFlush; public OutputWriter() { this.writer = new BufferedWriter(new OutputStreamWriter(System.out)); } public OutputWriter(boolean autoFlush) { this(); this.autoFlush = autoFlush; } public void printWithSpace(int input) { try { writer.append(input + " "); } catch (IOException e) { e.printStackTrace(); } if (autoFlush) { flush(); } } public void print(int input) { try { writer.append(input + ""); } catch (IOException e) { e.printStackTrace(); } if (autoFlush) { flush(); } } public void println(int input) { try { writer.append(input + System.lineSeparator()); } catch (IOException e) { e.printStackTrace(); } if (autoFlush) { flush(); } } public void printWithSpace(String input) { try { writer.append(input + " "); } catch (IOException e) { e.printStackTrace(); } if (autoFlush) { flush(); } } public void print(String input) { try { writer.append(input); } catch (IOException e) { e.printStackTrace(); } if (autoFlush) { flush(); } } public void println(CharSequence input) { try { writer.append(input); writer.append(System.lineSeparator()); } catch (IOException e) { e.printStackTrace(); } if (autoFlush) { flush(); } } public void printArray() { // implement if (autoFlush) { flush(); } } @Override public void flush() { try { this.writer.flush(); } catch (IOException e) { e.printStackTrace(); } } @Override public void close() { try { writer.close(); } catch (IOException ioe) { ioe.printStackTrace(); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
b4c7c8c54354f46514ec654c1fb46e3a
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Main { public static void main(String[]args) { Scanner S = new Scanner(System.in); int T = S.nextInt(); while(T-- > 0) { HashMap<String,Integer>Mp = new HashMap<String,Integer>(); ArrayList<ArrayList<String>>Arr = new ArrayList<ArrayList<String>>(); int N = S.nextInt(); for(int i=0;i<3;i++) { Arr.add(new ArrayList<String>()); for(int j=1;j<=N;j++) { String Curr = S.next(); Arr.get(i).add(Curr); Mp.put(Curr , Mp.getOrDefault(Curr , 0) + 1); } } int Ans[] = new int[3]; for(int i=0;i<3;i++) { for(String X : Arr.get(i)) { if(Mp.get(X) == 1)Ans[i]+=3; else if(Mp.get(X) == 2)Ans[i]++; } } for(int X : Ans)System.out.print(X + " "); System.out.println(); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
44ba904422874da3a176da4af3134b21
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Main{ static Scanner s = new Scanner(System.in); public static void main(String[] args) { int t = s.nextInt(); while(t-->0){ HashMap<String,Integer> mp = new HashMap<>(); int n = s.nextInt(); String ar[][] = new String[3][n]; for(int i=0;i<3;i++){ for(int j=0;j<n;j++){ ar[i][j] = s.next(); if(mp.containsKey(ar[i][j])){ mp.put(ar[i][j], mp.get(ar[i][j])+1); }else{ mp.put(ar[i][j], 1); } } } for(int i=0;i<3;i++){ int total =0; for(int j=0;j<n;j++){ if(mp.get(ar[i][j]) == 1){ total+=3; }else if(mp.get(ar[i][j])==2){ total++; } } System.out.print(total+" "); } System.out.println(); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
02813cf1926e9fe068a94682cf375152
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; import static java.lang.Math.*; import static java.lang.System.*; public class Main implements Runnable { private final void process() throws IOException { // InputReader input = new InputReader(new FileReader(System.getenv("INPUT"))); // PrintWriter output = new PrintWriter(new BufferedOutputStream(new FileOutputStream(System.getenv("OUTPUT")))); InputReader input = new InputReader(in); PrintWriter output = new PrintWriter(new BufferedOutputStream(out)); byte test = input.nextByte(); while (test-- > 0) { int n = input.nextInt(); String[][] words = new String[3][n]; for (int i = 0; i < 3; i++) { words[i] = input.readStringArray(); } HashMap<String, ArrayList<Integer>> hmap = new HashMap<>(); for (int i = 1; i <= 3; i++) { for (String word : words[i - 1]) { if (!hmap.containsKey(word)) hmap.put(word, new ArrayList<>()); hmap.get(word).add(i); } } int A = 0, B = 0, C = 0; for (String key : hmap.keySet()) { var lst = hmap.get(key); if (lst.size() == 2) { for (int idx : lst) { if (idx == 1) A++; else if (idx == 2) B++; else if (idx == 3) C++; } } else if (lst.size() == 1) { if (lst.get(0) == 1) A += 3; else if (lst.get(0) == 2) B += 3; else C += 3; } } output.println(A + " " + B + " " + C); } output.close(); input.close(); } @Override public void run() { try { process(); } catch (IOException ignored) {} } public static void main(String... args) throws IOException { new Thread(null, new Main(), "Main", 1 << 26).start(); } private final void printArr(PrintWriter output, short...arr) { output.println(Arrays.toString(arr).replaceAll("\\[|]|, ", " ").trim()); } private final void printArr(PrintWriter output, int...arr) { output.println(Arrays.toString(arr).replaceAll("\\[|]|, ", " ").trim()); } private final void printArr(PrintWriter output, double...arr) { output.println(Arrays.toString(arr).replaceAll("\\[|]|, ", " ").trim()); } private final void printArr(PrintWriter output, long...arr) { output.println(Arrays.toString(arr).replaceAll("\\[|]|, ", " ").trim()); } private final void printArr(PrintWriter output, char...arr) { output.println(Arrays.toString(arr).replaceAll("\\[|]|, ", " ").trim()); } private final void printArr(PrintWriter output, String...arr) { output.println(Arrays.toString(arr).replaceAll("\\[|]|, ", " ").trim()); } } class InputReader { private StringTokenizer token; private BufferedReader buffer; public InputReader(InputStream stream) { buffer = new BufferedReader(new InputStreamReader(stream)); } public InputReader(FileReader reader) throws FileNotFoundException { buffer = new BufferedReader(reader); } public final String next() throws IOException { while (token == null || !token.hasMoreTokens()) token = new StringTokenizer(buffer.readLine()); return token.nextToken(); } public final String nextLine() throws IOException { return buffer.readLine(); } public final byte nextByte() throws IOException { return Byte.parseByte(next()); } public final short nextShort() throws IOException { return Short.parseShort(next()); } public final int nextInt() throws IOException { return Integer.parseInt(next()); } public final long nextLong() throws IOException { return Long.parseLong(next()); } public final double nextDouble() throws IOException { return Double.parseDouble(next()); } public final char nextChar() throws IOException { return next().charAt(0); } public final boolean nextBoolean() throws IOException { return Boolean.parseBoolean(next()); // return Boolean.getBoolean(next()); // return Boolean.valueOf(next()); } public int[] readIntArray(int n) throws IOException { int[] arr = new int[n]; for (int i = 0; i < n; i++) arr[i] = nextInt(); return arr; } public int[] readIntArray() throws IOException { return java.util.Arrays.stream(nextLine().split("\\s+")). mapToInt(Integer::parseInt).toArray(); } public long[] readLongArray(int n) throws IOException { long[] arr = new long[n]; for (int i = 0; i < n; i++) arr[i] = nextLong(); return arr; } public long[] readLongArray() throws IOException { return java.util.Arrays.stream(nextLine().split("\\s+")). mapToLong(Long::parseLong).toArray(); } public double[] readDoubleArray(int n) throws IOException { double[] arr = new double[n]; for (int i = 0; i < n; i++) arr[i] = nextDouble(); return arr; } public double[] readDoubleArray() throws IOException { return java.util.Arrays.stream(nextLine().split("\\s+")). mapToDouble(Double::parseDouble).toArray(); } public char[] readCharArray() throws IOException { return nextLine().toCharArray(); } public String[] readStringArray(int n) throws IOException { String[] arr = new String[n]; for (int i = 0; i < n; i++) arr[i] = next(); return arr; } public String[] readStringArray() throws IOException { return nextLine().split("\\s+"); } public boolean ready() throws IOException { return buffer.ready(); } public void close() throws IOException { buffer.close(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
299c68f3395df48914a4a0092e626f94
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.HashMap; import java.util.LinkedList; import java.util.Map; import java.util.PriorityQueue; import java.util.Queue; import java.util.Scanner; public class MyClass { static Scanner in = new Scanner(System.in); public static void printArray(int[] arr) { for(int i=0; i<arr.length; i++) { System.out.print(arr[i] + " "); } } public static void printArray(String[] arr) { for(int i=0; i<arr.length; i++) { System.out.println(arr[i]); } } public static void minimumVariedNumber() { int t = in.nextInt(); int[] cases = new int[t]; for(int i=0; i<t; i++) { cases[i] = in.nextInt(); } int[] res = new int[t]; for(int i=0; i<t; i++) { int num = cases[i]; int k = 1; if(num/10 == 0) { res[i] = num; continue; } int temp = num; for(int j=9; j>0; j--) { if(temp>=j) { temp = temp - j; res[i] = res[i] + j*k; k*=10; } } } printArray(res); } public static boolean allOpen(int x, int[] doors) { int t = x -1; int count = 1; while(doors[t]!=0) { t = doors[t] - 1; count++; } if(count != 3) return false; else return true; } public static void threeDoors() { int t = in.nextInt(); String[] res = new String[t]; int[] doors = new int[3]; for(int i=0; i<t; i++) { int x = in.nextInt(); for(int j=0; j<3; j++) { doors[j] = in.nextInt(); } if(allOpen(x,doors)) { res[i] = "YES"; } else { res[i] = "NO"; } } printArray(res); } public static void swap(int[] arr, int i, int j) { int temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } public static void sortAsc(int[] arr) { int n = arr.length; for(int i=0; i<n-1; i++) { for(int j=i+1; j<n; j++) { if(arr[i] > arr[j]) { swap(arr, i, j); } } } } public static PriorityQueue<Integer> generateNew(PriorityQueue<Integer> pq) { PriorityQueue<Integer> new_pq = new PriorityQueue<Integer>(); int a = 0; int b = 0; while(pq.size()!=new_pq.size() || (pq.size() != 1 && new_pq.size() != 1)) { if(pq.size() == 1) { pq.clear(); PriorityQueue<Integer> tmp = pq; pq = new_pq; new_pq = tmp; } a = pq.poll(); b = pq.peek(); new_pq.add(b-a); } return new_pq; } public static void differenceArray() { int t = 1; //int t = in.nextInt(); int res[] = new int[t]; for(int i=0; i<t; i++) { int n = 100000; //int n = in.nextInt(); PriorityQueue<Integer> pq = new PriorityQueue<Integer>(); for(int j=0; j<n; j++) { //pq.add(in.nextInt()); pq.add(0); } pq = generateNew(pq); res[i] = pq.poll(); } printArray(res); } public static void wordGame() { int t = in.nextInt(); HashMap<String, Par> mapa = new HashMap<String, Par>(); for(int test = 0; test < t; test++) { int n = in.nextInt(); for(int i=0; i<3; i++) { for(int j=0; j<n; j++) { String rijec = in.next(); if(mapa.containsKey(rijec)) { mapa.get(rijec).dodajIgraca(i); } else { Par p = new Par(i); mapa.put(rijec, p); } } } int ukupni_bodovi[] = new int[3]; for(Map.Entry<String, Par> entry: mapa.entrySet()) { for(int i=0; i<3; i++) { ukupni_bodovi[i] += entry.getValue().getBodovi()[i]; } } printArray(ukupni_bodovi); System.out.println(); mapa.clear(); } } public static void main(String[] args) { // TODO Auto-generated method stub //minimumVariedNumber(); //threeDoors(); wordGame(); } } class Par { private int bodovi[] = new int[3]; //bodovi za svaku rijec private int ucestalost = 0; public Par(int igrac) { bodovi[igrac] = 3; ucestalost++; } public Par(Par p) { bodovi = p.bodovi; ucestalost = p.ucestalost; } public void dodajIgraca(int igrac) { ucestalost++; if(ucestalost == 2) { for(int i=0; i<3; i++) { if(bodovi[i]>0) { bodovi[i] = 1; break; } } bodovi[igrac] = 1; } else { for(int i=0; i<3; i++) { bodovi[i] = 0; } } } public int[] getBodovi() { return bodovi; } public int getUcestalost() { return ucestalost; } public void setUcestalost(int ucestalost) { this.ucestalost = ucestalost; } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
9a5b7f402ebf38e30548e20316adb1ce
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.Map; import java.util.Scanner; import java.util.TreeMap; public class guess { public static void main(String [] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); while (t-- > 0) { int n = sc.nextInt(); String [] s = new String[n]; String [] ss = new String[n]; String [] sss = new String[n]; TreeMap<String , Integer> tree = new TreeMap<String , Integer>(); int x=0; for(int i =0;i<3*n;i++){ if(i<n) { s[i] = sc.next(); tree.put(s[i],1); } else if(i<2*n&&i>=n) { ss[i-n] = sc.next(); if(tree.containsKey(ss[i-n])) { x = tree.remove(ss[i - n]); tree.put(ss[i - n], ++x); } else tree.put(ss[i-n],1); } else { sss[i-2*n] = sc.next(); if(tree.containsKey(sss[i-2*n])) { x = tree.remove(sss[i - 2 * n]); tree.put(sss[i - 2 * n], ++x); } else tree.put(sss[i-2*n],1); } } int a=0,b=0,c=0; for(int i=0;i<n;i++){ x = tree.remove(s[i]); if(x==2) a+=1; if(x==1) a+=3; tree.put(s[i],x); } for(int i=0;i<n;i++){ x = tree.remove(ss[i]); if(x==2) b+=1; if(x==1) b+=3; tree.put(ss[i],x); } for(int i=0;i<n;i++){ x = tree.remove(sss[i]); if(x==2) c+=1; if(x==1) c+=3; tree.put(sss[i],x); } System.out.println(a+" "+b+" "+ c ); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
18a78cb45ec93324959fe2cc23436edd
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.ArrayList; import java.util.Arrays; import java.util.HashSet; import java.util.Scanner; public class WordGame { public static Scanner sc = new Scanner(System.in); public static void main(String[] args) { int cases = sc.nextInt(); for(int i = 0 ; i<cases;i++){ int countA = 0 ,countB = 0 ,countC = 0; int size = sc.nextInt(); HashSet<String> a = new HashSet<>(); HashSet<String> b = new HashSet<>(); HashSet<String> c = new HashSet<>(); //String[] arr = new String[3*size]; ArrayList<String> list = new ArrayList<>(); for(int j = 0 ;j<size;j++){ String elem = sc.next(); a.add(elem); list.add(elem); } for(int k = 0 ;k<size;k++){ String elem = sc.next(); b.add(elem); if(!a.contains(elem)) list.add(elem); } for(int l = 0 ;l<size;l++){ String elem = sc.next(); c.add(elem); if(!a.contains(elem) && !b.contains(elem)) list.add(elem); } for(int x = 0; x<list.size();x++){ String comp = list.get(x); if(a.contains(comp) && !b.contains(comp) && !c.contains(comp)){ countA+=3; }else if(!a.contains(comp) && b.contains(comp) && !c.contains(comp)){ countB+=3; }else if(!a.contains(comp) && !b.contains(comp) && c.contains(comp)){ countC+=3; } else if (a.contains(comp) && b.contains(comp) && !c.contains(comp)) { countA++; countB++; }else if (a.contains(comp) && !b.contains(comp) && c.contains(comp)) { countA++; countC++; }else if (!a.contains(comp) && b.contains(comp) && c.contains(comp)) { countC++; countB++; } } System.out.println(countA+" "+ countB+" "+countC); } } // public static int[] sol() }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
86da10926290146fb2b3a581fa294513
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.*; public class BrInput { public static class Pair { int x; int y; public Pair(int x, int y) { this.x = x; this.y = y; } } private static final int modulo = 1000000007; public static Scanner scan = new Scanner(System.in); public static BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); public static void main(String[] args) throws IOException { int testCase = Integer.parseInt(br.readLine()); for (int vedant = 0; vedant < testCase; vedant++) { solve(); } // out.println(5); } private static void solve() throws IOException { // ******************** S O L V E M E T H O D ***************** // ************* M A I N L O G I C G O E S H E R E ********** int size = Integer.parseInt(br.readLine()); ArrayList<Set<String>> arr = new ArrayList<>(); for (int i = 0; i < 3; i++) { arr.add(new HashSet<>()); } String[] firstPerson = br.readLine().split(" "); String[] secondPerson = br.readLine().split(" "); String[] thirdPerson = br.readLine().split(" "); for (int i = 0; i < size; i++) { arr.get(0).add(firstPerson[i]); arr.get(1).add(secondPerson[i]); arr.get(2).add(thirdPerson[i]); } int firstPersonPoints = 0; int secondPersonPoints = 0; int thirdPersonPoints = 0; for (int i = 0; i < size; i++) { // 1st Person points if (!arr.get(1).contains(firstPerson[i]) && !arr.get(2).contains(firstPerson[i])) { firstPersonPoints += 3; } else if (!arr.get(1).contains(firstPerson[i]) || !arr.get(2).contains(firstPerson[i])) { firstPersonPoints += 1; } // 2nd Person points if (!arr.get(0).contains(secondPerson[i]) && !arr.get(2).contains(secondPerson[i])) { secondPersonPoints += 3; } else if (!arr.get(0).contains(secondPerson[i]) || !arr.get(2).contains(secondPerson[i])) { secondPersonPoints += 1; } // 3rd Person Points if (!arr.get(1).contains(thirdPerson[i]) && !arr.get(0).contains(thirdPerson[i])) { thirdPersonPoints += 3; } else if (!arr.get(1).contains(thirdPerson[i]) || !arr.get(0).contains(thirdPerson[i])) { thirdPersonPoints += 1; } } System.out.println(firstPersonPoints + " " + secondPersonPoints + " " + thirdPersonPoints); // **************************** S O L U T I O N E N D S H E R E **************************** } private static void printArray(int[] arr) { StringBuilder output = new StringBuilder(); for (int j : arr) { output.append(j).append(" "); } System.out.println(output); } private static void printYES() { System.out.println("YES"); } private static void printNO() { System.out.println("NO"); } private static long getMaximumFromList(List<Long> arr) { long max = Long.MIN_VALUE; for (Long aLong : arr) { max = Math.max(max, aLong); } return max; } public static int binarySearch(int[] arr, int target) { int starting = 0; int ending = arr.length - 1; while (starting < ending) { int mid = starting + (ending - starting) / 2; if (arr[mid] == target) { return mid; } if (arr[mid] > target) { ending = mid - 1; } else { starting = mid + 1; } } return -1; } public static int binarySearch(long[] arr, long target) { int starting = 0; int ending = arr.length - 1; while (starting < ending) { int mid = starting + (ending - starting) / 2; if (arr[mid] == target) { return mid; } if (arr[mid] > target) { ending = mid - 1; } else { starting = mid + 1; } } return -1; } public static int gcd(int a, int b) { // Everything divides 0 if (a == 0) return b; if (b == 0) return a; // base case if (a == b) return a; // a is greater if (a > b) return gcd(a-b, b); return gcd(a, b-a); } public static long gcd(long a, long b) { // Everything divides 0 if (a == 0) return b; if (b == 0) return a; // base case if (a == b) return a; // a is greater if (a > b) return gcd(a-b, b); return gcd(a, b-a); } private static int[] readIntArray(int size) { int[] arr = new int[size]; for (int i = 0; i < size; i++) { arr[i] = scan.nextInt(); } return arr; } private static long[] readLongArray(int size) { long[] arr = new long[size]; for (int i = 0; i < size; i++) { arr[i] = scan.nextLong(); } return arr; } private static boolean isVowel(char charAt) { charAt = Character.toLowerCase(charAt); return charAt == 'a' || charAt == 'e' || charAt == 'i' || charAt == 'o' || charAt == 'u'; } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
ea47fd0c04ca0032a3c042aae2a7fe56
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*;; public class Solution { public static void main(String[] args) { try (Scanner sc = new Scanner(System.in)) { int t = sc.nextInt(); Outer: while (t-- > 0) { int n = sc.nextInt(); int one = n*3, two = n*3, three = n*3; Set<String> s1 = new HashSet<>(); for (int i = 0; i < n; ++i) s1.add(sc.next()); Set<String> s2 = new HashSet<>(); for (int i = 0; i < n; ++i) s2.add(sc.next()); Set<String> s3 = new HashSet<>(); for (int i = 0; i < n; ++i) s3.add(sc.next()); for(var s : s1){ if(s2.contains(s) && s3.contains(s)){ one -= 3; two -= 3; three -= 3; s2.remove(s); s3.remove(s); }else if(s2.contains(s)){ one -= 2; two -= 2; s2.remove(s); }else if(s3.contains(s)){ one -= 2; three -= 2; s3.remove(s); } } for(var s : s2){ if(s1.contains(s)){ one -= 2; two -= 2; // s1.remove(s); }else if(s3.contains(s)){ two -= 2; three -= 2; s3.remove(s); } } System.out.println(one + " " + two + " " + three); } } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
4463a9398f1b697b8455a13b782cbbd4
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.HashMap; import java.util.Scanner; public class wordGame { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); while (t-- > 0) { int n = sc.nextInt(); HashMap<String,Integer> hm=new HashMap<>(); String[][] str=new String[3][n]; int[] b=new int[3]; for(int i=0;i<3;i++){ for(int j=0;j<n;j++){ str[i][j]=sc.next(); if(hm.containsKey(str[i][j])) hm.put(str[i][j],hm.get(str[i][j])+1); else hm.put(str[i][j],1); } } for(int i=0;i<3;i++){ for(int j=0;j<n;j++){ if(hm.get(str[i][j])==1) b[i]=b[i]+3; else if(hm.get(str[i][j])==2) b[i]=b[i]+1; } } for(int i=0;i<3;i++) System.out.print(b[i]+" "); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
92fb95ef46f068c990c31c0369cd7aea
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Codeforces { private static final int INT_MAX = 999999999; /*public static int power(int x,int n) { if(n==0) return 1; return x*power(x,n-1); }*/ public static void main(String[] args) { Scanner sc=new Scanner(System.in); int t=sc.nextInt(); for(int test=0;test<t;test++) { int n=sc.nextInt(); HashSet<String> s1=new HashSet<>(); HashSet<String> s2=new HashSet<>(); HashSet<String> s3=new HashSet<>(); String[] a1=new String[n]; String[] a2=new String[n]; String[] a3=new String[n]; for(int i=0;i<n;i++) { a1[i]=sc.next(); s1.add(a1[i]); } for(int i=0;i<n;i++) { a2[i]=sc.next(); s2.add(a2[i]); } for(int i=0;i<n;i++) { a3[i]=sc.next(); s3.add(a3[i]); } int[] ans=new int[3]; for(int i=0;i<n;i++) { if(s2.contains(a1[i])&&s3.contains(a1[i])) ans[0]+=0; else if(!s2.contains(a1[i])&&s3.contains(a1[i])) ans[0]+=1; else if(s2.contains(a1[i])&&!s3.contains(a1[i])) ans[0]+=1; else ans[0]+=3; } for(int i=0;i<n;i++) { if(s1.contains(a2[i])&&s3.contains(a2[i])) ans[1]+=0; else if(!s1.contains(a2[i])&&s3.contains(a2[i])) ans[1]+=1; else if(s1.contains(a2[i])&&!s3.contains(a2[i])) ans[1]+=1; else ans[1]+=3; } for(int i=0;i<n;i++) { if(s2.contains(a3[i])&&s1.contains(a3[i])) ans[2]+=0; else if(!s2.contains(a3[i])&&s1.contains(a3[i])) ans[2]+=1; else if(s2.contains(a3[i])&&!s1.contains(a3[i])) ans[2]+=1; else ans[2]+=3; } System.out.println(ans[0]+" "+ans[1]+" "+ans[2]); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
f31c6254e34a87d5fd5b687290f84154
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Solve { private static void solve(Scanner sc) { int n = sc.nextInt(); HashMap<String, Integer> map = new HashMap<>(); List<String> list = new ArrayList<>(); for (int i = 0; i < 3; i++) { for (int j = 0; j < n; j++) { String s = sc.next(); list.add(s); if (map.get(s) != null) { map.put(s, map.get(s) + 1); } else { map.put(s, 1); } } } int idx = 0; for (int i = 0; i < 3; i++) { int answer = 0; for (int j = idx; j < idx + n; j++) { if (map.get(list.get(j)) == 1) { answer += 3; } if (map.get(list.get(j)) == 2) { answer++; } } idx += n; System.out.print(answer + " "); } System.out.print('\n'); } public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int tt = scanner.nextInt(); while (tt-- > 0) { solve(scanner); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
b6e01129a57192d89265ef4bc56799a9
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; import java.io.*; public class CF1722C { public static void main(String[] args) { Scanner sc = new Scanner(System.in); PrintWriter pr = new PrintWriter(new OutputStreamWriter(System.out)); int t = sc.nextInt(); HashMap<String, List<Integer>> mp = new HashMap<>(); while (t-- > 0) { int[] ans = new int[3]; mp.clear(); int n = sc.nextInt(); for (int i = 0; i < 3; i++) for (int j =0; j < n; j++) { String s = sc.next(); List<Integer> l = new ArrayList<>(); if (mp.get(s) == null) { l.add(i); mp.put(s, l); ans[i] += 3; } else { l = mp.get(s); if (l.size() == 1) { ans[l.get(0)] -= 2; ans[i] += 1; } else if (l.size() == 2) { ans[l.get(0)] -= 1; ans[l.get(1)] -= 1; } l.add(i); mp.replace(s, l); } } pr.println(ans[0] + " " + ans[1] + " " + ans[2]); pr.flush(); } sc.close(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
1fa8cae46dde18be183d5a0307ce2507
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Main { public static void main(String[] args) { Scanner input = new Scanner(System.in); int t = input.nextInt(); HashMap<String, List<Integer>> map = new HashMap<>(); while (t > 0) { map.clear(); int n = input.nextInt(); int[] points = new int[3]; for (int i = 0; i < 3; i++) { for (int j = 0; j < n; j++) { String s = input.next(); List<Integer> list = new ArrayList<>(); if (map.get(s) == null) { list.add(i); map.put(s, list); } else { list = map.get(s); list.add(i); map.replace(s, list); } } } Collection<List<Integer>> scores = map.values(); for (List<Integer> col : scores) { if (col.size() == 1) { points[col.get(0)] += 3; } if (col.size() == 2) { points[col.get(0)]++; points[col.get(1)]++; } } System.out.println(points[0] + " " + points[1] + " " + points[2]); t--; } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
33deb857b43282ae3a2af5d86cce3030
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; import java.math.*; public class C1722 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); for(int l=0;l<t;l++) { int n = sc.nextInt(); String[][] s = new String[3][n]; for(int i=0;i<3;i++) { for(int j=0;j<n;j++) { s[i][j] = sc.next(); } } int[] A = new int[3]; Hashtable<String,Integer> ht = new Hashtable<String,Integer>(); for(int i=0;i<3;i++) { for(int j=0;j<n;j++) { if(ht.get(s[i][j])==null) { ht.put(s[i][j],1); } else { int temp = ht.get(s[i][j]); ht.replace(s[i][j], temp+1); } } } for(int i=0;i<3;i++) { for(int j=0;j<n;j++) { if(ht.get(s[i][j])==1) { A[i]+=3; } else if(ht.get(s[i][j])==2) { A[i]+=1; } } } System.out.println(A[0]+" "+A[1]+" "+A[2]); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
3564b81033d05a0ba7cef3afe4414bff
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; import java.io.*; import java.lang.*; public class main{ static Scanner sc = new Scanner(System.in); static String[][] s = new String[4][1005]; public static void Solve(){ int n = sc.nextInt(); Map<String, Integer> M = new HashMap<String, Integer>(); for(int i = 1; i <= 3; ++ i){ for(int j = 1; j <= n; ++ j) { s[i][j] = sc.next(); if(M.containsKey(s[i][j])){ int cnt = M.get(s[i][j]); M.put(s[i][j], cnt + 1); } else { M.put(s[i][j], 1); } } } for(int i = 1; i <= 3; ++ i){ int ans = 0; for(int j = 1; j <= n; ++ j){ int cnt = M.get(s[i][j]); if(cnt == 1) { ans += 3; } else { if(cnt < 3) { ans += 1; } } } System.out.print(ans + " "); } System.out.println(); } public static void main(String[] argv){ int t = sc.nextInt(); while(t -- > 0){ Solve(); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
21f15d301c7870e74d6d39b540a70aa2
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.HashMap; import java.util.Map; import java.util.StringTokenizer; public class C { public static void main(String[] args) { FastScanner fs = new FastScanner(); int tt = 1; tt = fs.nextInt(); while (tt-- > 0) { int n = fs.nextInt(); int[] scores = new int[3]; String[][] a = new String[n][3]; Map<String, Integer> mp = new HashMap<>(); for (int i = 0; i < 3; ++i) { for (int j = 0; j < n; ++j) { a[j][i] = fs.next(); mp.put(a[j][i], mp.getOrDefault(a[j][i], 0) + 1); } } for (int i = 0; i < n; ++i) { String[] cur = a[i]; for (int j = 0; j < 3; ++j) { int count = mp.get(cur[j]); if (count == 1) scores[j] += 3; else if (count == 2) scores[j] += 1; } } System.out.printf("%d %d %d \n", scores[0], scores[1], scores[2]); } } static class FastScanner { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); StringTokenizer st = new StringTokenizer(""); String next() { while (!st.hasMoreTokens()) try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } int[] readArray(int n) { int[] a = new int[n]; for (int i = 0; i < n; i++) a[i] = nextInt(); return a; } long nextLong() { return Long.parseLong(next()); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
fe3afe7cb7ee22e37052671d8d65bc3f
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class Solution { public static Scanner scan = new Scanner(System.in); public static void main(String[] args) { int testCase = scan.nextInt(); for(int i = 0; i < testCase; i++) { solve(); } } public static void solve() { int n = scan.nextInt(); Map<String, Integer> map = new HashMap<String, Integer>(); String[][] a = new String[3][n]; for(int i = 0; i < 3; i++) { for(int j = 0; j < n; j++) { a[i][j] = scan.next(); if(map.containsKey(a[i][j])) { map.put(a[i][j], map.get(a[i][j]) + 1); } else { map.put(a[i][j], 1); } } } for(int i = 0; i < 3; i++) { int point = 0; for(int j = 0; j < n; j++) { int check = map.get(a[i][j]); if(check == 1) { point += 3; } else if(check == 2) { point += 1; } } System.out.print(point + " "); } System.out.println(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
ccd5e8d9e1f898296bb08eae3bb14dc1
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class practice { public static void main(String[] args) { Scanner in = new Scanner(System.in); int t = in.nextInt(); while (t-->0){ int n = in.nextInt(); HashMap<Integer,List<String>> m1 = new HashMap<>(); HashMap<String,Integer> m2 = new HashMap<>(); for(int i = 1; i<=3;i++) { for (int j = 0; j < n;j++) { String s = in.next(); if (!m1.containsKey(i)) { m1.put(i, new ArrayList<>()); m1.get(i).add(s); } else m1.get(i).add(s); if (!m2.containsKey(s)) m2.put(s, 1); else m2.put(s, m2.get(s) + 1); } } int []arr = new int[3]; for(int key : m1.keySet()){ for(String s : m1.get(key)){ if(m2.get(s)==1) arr[key-1]+=3; if(m2.get(s)==2) arr[key-1]++; } } for(int e : arr) System.out.print(e+" "); System.out.println(); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
d8adcf0d08ca11f07d708fea28b458c7
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; import java.math.*; import static java.lang.Math.*; public class Main { StreamTokenizer in; BufferedReader inb; PrintWriter out; StringTokenizer tok; Scanner sc; boolean console = true; final double eps = 1e-9; final boolean DEBUG = false; public static void main(String[] args) throws Exception { new Main().run(); } public void run() throws Exception { if (!DEBUG) { inb = new BufferedReader(console ? new InputStreamReader(System.in) : new FileReader("bisector.in")); in = new StreamTokenizer(inb); out = new PrintWriter(console ? new OutputStreamWriter(System.out) : new FileWriter("bisector.out")); sc = new Scanner(System.in); tok = new StringTokenizer(""); Locale.setDefault(Locale.US); solve(); out.flush(); out.close(); } else { long begMem = Runtime.getRuntime().totalMemory() - Runtime.getRuntime().freeMemory(); long t1 = System.currentTimeMillis(); inb = new BufferedReader(new FileReader("input.txt")); in = new StreamTokenizer(inb); out = new PrintWriter(new FileWriter("output.txt")); tok = new StringTokenizer(""); solve(); long endMem = Runtime.getRuntime().totalMemory() - Runtime.getRuntime().freeMemory(); out.flush(); long t2 = System.currentTimeMillis(); System.out.println("Time:" + (t2 - t1)); System.out.println("Memory:" + (endMem - begMem)); System.out.println("Total memory: " + (Runtime.getRuntime().totalMemory() - Runtime .getRuntime().freeMemory())); } } public int nextInt() throws Exception { in.nextToken(); return (int) in.nval; } public String next() throws Exception { in.nextToken(); return in.sval; } public String nextLine() throws Exception { return inb.readLine(); } public String nextString() throws Exception { while (!tok.hasMoreTokens()) tok = new StringTokenizer(inb.readLine()); return tok.nextToken(); } public long nextLong() throws Exception { return Long.parseLong(nextString()); } public double nextDouble() throws Exception { in.nextToken(); return in.nval; } public int gcd(int a, int b) { if (a == 0 || b == 0) return 1; if (a < b) { int c = b; b = a; a = c; } while (a % b != 0) { a = a % b; if (a < b) { int c = b; b = a; a = c; } } return b; } public BigInteger pow(BigInteger a, long n) { if (n == 0) return BigInteger.ONE; BigInteger k = BigInteger.valueOf(n), b = BigInteger.ONE, c = a; while (!k.equals(BigInteger.ZERO)) { if (k.mod(BigInteger.valueOf(2)).equals(BigInteger.ZERO)) { k = k.divide(BigInteger.valueOf(2)); c = c.multiply(c); } else { k = c.subtract(BigInteger.ONE); b = b.multiply(c); } } return b; } public int lcm(int a, int b) { return a * b / gcd(a, b); } public int[] findPrimes(int x) { boolean[] erat = new boolean[x - 1]; List<Integer> t = new ArrayList<Integer>(); int l = 0, j = 0; for (int i = 2; i < x; i++) { if (erat[i - 2]) continue; t.add(i); l++; j = i * 2; while (j < x) { erat[j - 2] = true; j += i; } } int[] primes = new int[l]; Iterator<Integer> iterator = t.iterator(); for (int i = 0; iterator.hasNext(); i++) { primes[i] = iterator.next().intValue(); } return primes; } public int[] prefix(String s) { int n = s.length(); int a[] = new int[n]; for (int i = 1; i < n; ++i) { int j = a[i - 1]; while (j > 0 && s.charAt(i) != s.charAt(j)) { j = a[j - 1]; } if (s.charAt(i) == s.charAt(j)) ++j; a[i] = j; } return a; } long a[]; long sum; public void gen_perm(int n, int pos, int mask) { if (pos == n) { return; } if (pos == n - 1) { a[pos] = sum; return; } for (int i = 1; i <= n; i++) { if ((mask & (1 << i)) == 0) { a[pos] = i; sum -= i; gen_perm(n, pos + 1, (mask | (1 << i))); sum += i; } } } public void solve() throws Exception { int n = nextInt(); for (int i=0; i<n; i++) { int j = nextInt(); Set<String> s1 = new HashSet<>(); Set<String> s2 = new HashSet<>(); Set<String> s3 = new HashSet<>(); for (int k=0; k<j;k++) { s1.add(nextString()); } for (int k=0; k<j;k++) { s2.add(nextString()); } for (int k=0; k<j;k++) { s3.add(nextString()); } int count1 = 0; for (String s: s1) { if (!s2.contains(s) && !s3.contains(s)) { count1+=3; } else if (s2.contains(s) && s3.contains(s)) { } else { count1++; } } int count2 = 0; for (String s: s2) { if (!s1.contains(s) && !s3.contains(s)) { count2+=3; } else if (s1.contains(s) && s3.contains(s)) { } else { count2++; } } int count3 = 0; for (String s: s3) { if (!s2.contains(s) && !s1.contains(s)) { count3+=3; } else if (s2.contains(s) && s1.contains(s)) { } else { count3++; } } out.println(count1 + " " + count2 + " " + count3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
6ec019ed54acba79a818d2c2a62fb93d
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; import java.io.*; public class C_Word_Game { final int mod = 1000000007; static class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new BufferedReader(new InputStreamReader(System.in)); } String next() { while (st == null || !st.hasMoreElements()) { try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } long nextLong() { return Long.parseLong(next()); } double nextDouble() { return Double.parseDouble(next()); } String nextLine() { String str = ""; try { str = br.readLine(); } catch (IOException e) { e.printStackTrace(); } return str; } } public static void swap(long[] a, int i, int j) { long temp = a[i]; a[i] = a[j]; a[j] = temp; } public static void main(String[] args) { // TODO Auto-generated method stub FastReader t = new FastReader(); PrintWriter o = new PrintWriter(System.out); int test = t.nextInt(); while (test-- > 0) { long min = Integer.MIN_VALUE, max = Integer.MAX_VALUE; long ans =0 ; int n = t.nextInt(); HashMap<String, int[]> map = new HashMap<>(); for (int k=0; k<3; k++) { for (int i = 0; i < n; ++i) { String s = t.next(); if (map.containsKey(s)) { int[] p = map.get(s); p[k] = 1; map.put(s, p); } else { int[] p = new int[3]; p[k] = 1; map.put(s, p); } } } long a=0, b=0, c=0; for (int[] p : map.values()) { int sc = p[0]+p[1]+p[2]; if (sc == 1) { a += p[0]*3; b += p[1]*3; c += p[2]*3; } if (sc == 2) { a += p[0]; b += p[1]; c += p[2]; } } o.println(a+" "+b+" "+c); // long m = t.nextLong(); // ArrayList<Integer> al = new ArrayList<>(); // HashSet<Integer> set = new HashSet<>(); // HashMap<Integer, Integer> map = new HashMap<>(); // TreeMap<Integer, Integer> map = new TreeMap<>(); // for (int i = 0; i < n; ++i) { // for (int j = 0; j < n; ++j) { // } // } } o.flush(); o.close(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
8768185adf3d1e4f339d2af33d44c8e5
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; public class Main { static BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); static int tcs, n; static StringTokenizer st; static Map<String, Integer> map = new HashMap<>(); static int p1, p2, p3; static String[][] table; static void solved() throws IOException { st = new StringTokenizer(br.readLine()); n = Integer.parseInt(st.nextToken()); map.clear(); p1 = p2 = p3 = 0; String key; table = new String[3][n]; for (int i = 0; i < 3; i++) { st = new StringTokenizer(br.readLine()); for (int j = 0; j < n; j++) { key = st.nextToken(); map.put(key, map.getOrDefault(key, 0) + 1); table[i][j] = key; } } p1 = getPoint(0); p2 = getPoint(1); p3 = getPoint(2); System.out.println(p1 + " " + p2 + " " + p3); } static int getPoint(int i) { String key; int p; int result = 0; for (int j = 0; j < n; j++) { key = table[i][j]; p = map.get(key); if (p == 1) { result += 3; } else if (p == 2) { result += 1; } } return result; } public static void main(String[] args) throws IOException { tcs = Integer.parseInt(br.readLine()); while (tcs-- > 0) { solved(); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
ea1853e9333d479bb236c9c21d418943
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); for (int tt = 0; tt < t; tt++) { int n = sc.nextInt(); String [][] s = new String[3][n]; Map<String,Integer> hm = new HashMap<>(); for (int i = 0; i < 3; i++) { for (int j = 0; j < n; j++) { s[i][j] = sc.next(); hm.put(s[i][j],hm.getOrDefault(s[i][j],0) + 1); } } for (int i = 0; i < 3; i++) { int score = 0; for (int j = 0; j < n; j++) { if (hm.get(s[i][j]) == 1) score += 3; else if (hm.get(s[i][j]) == 2) score++; } System.out.print(score + " "); } System.out.println(); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
42d02f3cec40fa7f82825a72fdd32cfb
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Main{ public static void main(String[] args){ Scanner sc = new Scanner(System.in); int t = sc.nextInt(); while(t > 0){ HashMap<String, Integer> map = new HashMap<>(); int n = sc.nextInt(); int p1 = n*3, p2 = n*3, p3 = n*3; sc.nextLine(); for(int i = 0; i < n; i++){ String s = sc.next(); map.put(s, 1); } for(int i = 0; i < n; i++){ String s = sc.next(); if(!map.containsKey(s)){ map.put(s, 2); } else{ map.put(s, map.get(s) + 2); } } for(int i = 0; i < n; i++){ String s = sc.next(); if(!map.containsKey(s)){ map.put(s, 0); } else{ map.put(s, map.get(s) + 3); } } for(Map.Entry<String, Integer> i : map.entrySet()){ if(i.getValue() == 6){ p1 -= 3; p2 -= 3; p3 -= 3; } else if(i.getValue() == 3){ p1 -= 2; p2 -= 2; } else if(i.getValue() == 4){ p1 -= 2; p3 -= 2; } else if(i.getValue() == 5){ p2 -= 2; p3 -= 2; } } System.out.println(p1 + " " + p2 + " " + p3); t --; } sc.close(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
af25dcc393687e420dbc03a31501a769
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; import java.util.Map.Entry; import java.io.*; import java.lang.*; public class main1{ FastScanner in; PrintWriter out; public static void main(String[] arg) { new main1().run(); } //////////////SOLVE QUESTIONS HERE///////////// public class ji{ HashMap<String,Integer> mp=new HashMap<>(); void add(String s) { mp.put(s,1); } void print() { mp.entrySet().forEach(entry -> { System.out.println(entry.getKey() + " " + entry.getValue()); }); } } public void solve() throws IOException { int testcase=1; testcase=in.nextInt(); while(testcase-- > 0) { ji[] arr=new ji[3]; ArrayList<String> s1=new ArrayList<>(); ArrayList<String> s2=new ArrayList<>(); ArrayList<String> s3=new ArrayList<>(); HashSet<String> s=new HashSet<>(); int n=in.nextInt(); for(int j=0;j<3;j++) { arr[j]=new ji(); for(int i=0;i<n;i++) { var temp=in.next(); s.add(temp); if(j==0) s1.add(temp); else if(j==1) s2.add(temp); else s3.add(temp); arr[j].add(temp); } } int a=0,b=0,c=0; for(String temp:s) { if(arr[0].mp.get(temp)!=null && arr[1].mp.get(temp)!=null && arr[2].mp.get(temp)!=null ) { continue; } else if(arr[0].mp.get(temp)!=null && arr[1].mp.get(temp)!=null) { a++; b++; } else if(arr[0].mp.get(temp)!=null && arr[2].mp.get(temp)!=null) { a++; c++; } else if(arr[1].mp.get(temp)!=null && arr[2].mp.get(temp)!=null) { b++; c++; } else if(arr[0].mp.get(temp)!=null) { a+=3; } else if(arr[1].mp.get(temp)!=null) { b+=3; } else if(arr[2].mp.get(temp)!=null) { c+=3; } } out.println(a+" "+b+" "+c); } } public void run() { try { in = new FastScanner(new InputStreamReader(System.in)); out = new PrintWriter(System.out); solve(); out.close(); } catch (IOException e) { e.printStackTrace(); } } class FastScanner { BufferedReader br; StringTokenizer st; public FastScanner(Reader f) { br = new BufferedReader(f); } String next() { while (st == null || !st.hasMoreTokens()) { try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } long nextLong(){ return Long.parseLong(next()); } double nextDouble(){ return Double.parseDouble(next()); } String nextLine(){ String str=""; try { str=br.readLine().trim(); } catch (Exception e) { e.printStackTrace(); } return str; } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
1eb42e215bc3c0ed4561f4ba7bf3ba14
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.HashSet; import java.util.Scanner; import java.util.Set; public class Main { private final static Scanner sc = new Scanner(System.in); public static void main(String[] args) { int testCases = sc.nextInt(); for (int testCase = 0; testCase < testCases; testCase++) { Set<String> person1 = new HashSet<>(); Set<String> person2 = new HashSet<>(); Set<String> person3 = new HashSet<>(); int n = sc.nextInt(); for (int word = 0; word < n; word++) { person1.add(sc.next()); } for (int word = 0; word < n; word++) { person2.add(sc.next()); } for (int word = 0; word < n; word++) { person3.add(sc.next()); } int person1Score = 0; int person2Score = 0; int person3Score = 0; person1Score = getPersonScore(person1, person2, person3, person1Score); person2Score = getPersonScore(person2, person1, person3, person2Score); person3Score = getPersonScore(person3, person1, person2, person3Score); System.out.println(person1Score + " " + person2Score + " " + person3Score); } } private static int getPersonScore(Set<String> person1, Set<String> person2, Set<String> person3, int personScore) { for (String word: person1) { if (person2.contains(word) && !person3.contains(word)) { personScore++; } if (!person2.contains(word) && person3.contains(word)) { personScore++; } if (!person2.contains(word) && !person3.contains(word)) { personScore += 3; } } return personScore; } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
55453a6d07cea7a0a6e8d6df4ad049e2
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class C_Word_Game { static Scanner sc = new Scanner(System.in); static void input(String arr[], Map<String, Integer> mp) { for (int i = 0; i < arr.length; i++) { arr[i] = sc.next(); mp.put(arr[i], mp.getOrDefault(arr[i], 0) + 1); } } static int increment(String arr[], Map<String, Integer> mp) { int val = 0; for (String s : arr) { if (mp.get(s) == 2) val++; else if (mp.get(s) == 1) val += 3; } return val; } public static void main(String args[]) { int t = sc.nextInt(); while (t-- != 0) { int n = sc.nextInt(); String s1[] = new String[n], s2[] = new String[n], s3[] = new String[n]; Map<String, Integer> mp = new HashMap<>(); input(s1, mp); input(s2, mp); input(s3, mp); int val1 = increment(s1, mp), val2 = increment(s2, mp), val3 = increment(s3, mp); System.out.println(val1 + " " + val2 + " " + val3); } sc.close(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
262ddd7c20b44682acbf1c15ad0a0283
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.HashMap; import java.util.Map; import java.util.StringTokenizer; public class C { final private static FastReader reader = new FastReader(); final private static PrintWriter writer = new PrintWriter(System.out); public static void main(String[] args) { //solveTestCase(); runTestCases(false); writer.flush(); } public static void solveTestCase() { int n = reader.nextInt(); String[][] words = new String[3][n]; Map<String, Integer> counter = new HashMap<>(); for(int i = 0; i < 3; i++) { for(int j = 0; j < n; j++) { words[i][j] = reader.next(); if(counter.containsKey(words[i][j])) { counter.put(words[i][j], counter.get(words[i][j]) + 1); } else { counter.put(words[i][j], 1); } } } for (int i = 0; i < 3; i++) { int total = 0; for (int j = 0; j < n; j++) { switch (counter.get(words[i][j])) { case 1 -> total += 3; case 2 -> total += 1; } } writer.print(total); writer.print(' '); } writer.println(); } private static void runTestCases(boolean forGoogle) { int T = reader.nextInt(); final String cases = "Case #", colon = ": "; for (int _t = 0; _t < T; _t++){ if(forGoogle) { writer.print(cases); writer.print(_t); writer.print(colon); } solveTestCase(); } } static class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new BufferedReader(new InputStreamReader(System.in)); } String next() { while (st == null || !st.hasMoreElements()) { try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } long nextLong() { return Long.parseLong(next()); } double nextDouble() { return Double.parseDouble(next()); } String nextLine() { String str = ""; try { if(st.hasMoreTokens()){ str = st.nextToken("\n"); } else { str = br.readLine(); } } catch (IOException e) { e.printStackTrace(); } return str; } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
776f30f3bbbfa0c080c42f5b30646967
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.io.BufferedReader; import java.io.InputStreamReader; import java.util.*; public class C_Word_Game { public static void main(String[] args) throws IOException { InputStream inputStream = System.in; InputReader sc = new InputReader(inputStream); int t = sc.nextInt(); while (--t >= 0) { int size = sc.nextInt(); String[][] al = new String[3][size]; for (int i = 0; i < 3; i++) { // for(int j = 0; j < size; j++) { String g = sc.nextLine(); String[] split = g.split(" "); for(int j = 0; j < size; j++) { al[i][j] = split[j]; } // } } Map<String, List<Integer>> hm = new HashMap<>(); for(int i = 0 ; i < 3 ; i++){ for(int j = 0;j < size ; j++){ String str = al[i][j]; if(hm.containsKey(str)){ hm.get(str).add(i); }else{ List<Integer> temp= new ArrayList<>(); temp.add(i); hm.put(str,temp); } } } int[] points = new int[3]; for(Map.Entry<String, List<Integer>> e : hm.entrySet()){ List<Integer> com = e.getValue(); if(com.size() ==3){ continue; }else if(com.size() == 2){ points[com.get(0)] += 1; points[com.get(1)] += 1; }else{ points[com.get(0)] += 3; } } System.out.println(points[0]+" "+points[1]+" "+points[2]); } } static class InputReader { public BufferedReader reader; public StringTokenizer tokenizer; public InputReader(InputStream stream) { reader = new BufferedReader(new InputStreamReader(stream), 32768); tokenizer = null; } public String next() { while (tokenizer == null || !tokenizer.hasMoreTokens()) { try { tokenizer = new StringTokenizer(reader.readLine()); } catch (IOException e) { throw new RuntimeException(e); } } return tokenizer.nextToken(); } public int nextInt() { return Integer.parseInt(next()); } public double nextDouble() { return Double.parseDouble(next()); } public long nextLong() { return Long.parseLong(next()); } public char nextChar() { return next().charAt(0); } public String nextLine() throws IOException { return reader.readLine().trim(); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
c2c7c4b674a607314db89d987b67f004
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class WordGame { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int numTestCase = sc.nextInt(); int arr[][] = new int[numTestCase][3]; for (int i = 0; i < numTestCase; i++) { int numWords = sc.nextInt(); String p1[] = new String[numWords]; String p2[] = new String[numWords]; String p3[] = new String[numWords]; int a = 0, b = 0, c = 0; for (int j = 0; j < numWords; j++) { p1[j] = sc.next(); } for (int j = 0; j < numWords; j++) { p2[j] = sc.next(); } for (int j = 0; j < numWords; j++) { p3[j] = sc.next(); } Map<String, Integer> m = new HashMap<>(); for (int j = 0; j < numWords; j++) { if (m.containsKey(p1[j])) { m.put(p1[j], m.get(p1[j]) + 1); } else { m.put(p1[j], 1); } if (m.containsKey(p2[j])) { m.put(p2[j], m.get(p2[j]) + 1); } else { m.put(p2[j], 1); } if (m.containsKey(p3[j])) { m.put(p3[j], m.get(p3[j]) + 1); } else { m.put(p3[j], 1); } } for (int j = 0; j < numWords; j++) { if (m.get(p1[j]) == 2) { a++; } if (m.get(p1[j]) == 1) { a = a + 3; } if (m.get(p2[j]) == 2) { b++; } if (m.get(p2[j]) == 1) { b = b + 3; } if (m.get(p3[j]) == 2) { c++; } if (m.get(p3[j]) == 1) { c = c + 3; } } arr[i][0] = a; arr[i][1] = b; arr[i][2] = c; } for (int i = 0; i < numTestCase; i++) { for (int j = 0; j < 3; j++) { System.out.print(arr[i][j] + " "); } System.out.println(); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
e33a679a988a8f22099c7d64faeb3971
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; public class Main { private void solve(InputReader in, PrintWriter pw) { int t = in.nextInt(); outer:while (t-- > 0) { int n = in.nextInt(); String[][] s = new String[3][n]; HashMap<String, Integer> map = new HashMap<>(); for (int i = 0; i < 3; i++) { for (int j = 0; j < n; j++) { s[i][j] = in.next(); map.put(s[i][j], map.getOrDefault(s[i][j], 0) + 1); } } int[] ans = new int[3]; for (int i = 0; i < 3; i++) { for (int j = 0; j < n; j++) { int cnt = map.get(s[i][j]); if (cnt == 1) { ans[i] += 3; } else if (cnt == 2) { ans[i] += 1; } } } for (int x : ans) { pw.print(x + " "); } pw.println(); } pw.close(); } public static void main(String[] args) { new Main().solve(new InputReader(System.in), new PrintWriter(System.out)); } } class InputReader { private final BufferedReader reader; private StringTokenizer tokenizer; public InputReader(InputStream stream) { reader = new BufferedReader(new InputStreamReader(stream), 32768); tokenizer = null; } public String next() { while (tokenizer == null || !tokenizer.hasMoreTokens()) { try { tokenizer = new StringTokenizer(reader.readLine()); } catch (IOException e) { throw new RuntimeException(e); } } return tokenizer.nextToken(); } public String nextLine() { String str; try { str = reader.readLine(); } catch (IOException e) { throw new RuntimeException(e); } return str; } public boolean hasNext() { while (tokenizer == null || !tokenizer.hasMoreTokens()) { String nextLine; try { nextLine = reader.readLine(); } catch (IOException e) { throw new RuntimeException(e); } if (nextLine == null) { return false; } tokenizer = new StringTokenizer(nextLine); } return true; } public int nextInt() { return Integer.parseInt(next()); } public long nextLong() { return Long.parseLong(next()); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
6f59408a4ffe01b6812d22d86e0b8906
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import static java.util.Map.entry; import java.util.Arrays; import java.util.HashMap; import java.util.Map; import java.util.Scanner; import java.util.stream.Collectors; public class Main { static final Map<Integer, Integer> COUNT_TO_POINT = Map.ofEntries(entry(1, 3), entry(2, 1), entry(3, 0)); public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); for (int tc = 0; tc < t; ++tc) { int n = sc.nextInt(); String[][] words = new String[3][n]; for (int i = 0; i < words.length; ++i) { for (int j = 0; j < words[i].length; ++j) { words[i][j] = sc.next(); } } System.out.println(solve(words)); } sc.close(); } static String solve(String[][] words) { Map<String, Integer> wordToCount = new HashMap<>(); for (int i = 0; i < words.length; ++i) { for (int j = 0; j < words[i].length; ++j) { wordToCount.put(words[i][j], wordToCount.getOrDefault(words[i][j], 0) + 1); } } return Arrays.stream(words) .mapToInt( p -> Arrays.stream(p).mapToInt(word -> COUNT_TO_POINT.get(wordToCount.get(word))).sum()) .mapToObj(String::valueOf) .collect(Collectors.joining(" ")); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
0ff9120a31d9bc91cb08dffc2e608798
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.Arrays; import java.util.HashMap; import java.util.Map; import java.util.StringTokenizer; public class D { public static void main(String[] args) { FastReader scanner = new FastReader(); int numberOfCases = scanner.nextInt(); while (numberOfCases -- > 0) { int numberOfCul= scanner.nextInt(); String[][] arr = new String[3][numberOfCul]; Map<String, Integer> map = new HashMap<>(); int c = 1; int[] res = new int[3]; for (int i = 0; i < arr.length; i++) { for (int j = 0; j < arr[i].length; j++) { arr[i][j] = scanner.next(); if (map.containsKey(arr[i][j])) { map.replace(arr[i][j], map.get(arr[i][j]) + 1); continue; } map.put(arr[i][j], c); } } for (int i = 0; i < arr.length; i++) { for (int j = 0; j < arr[i].length; j++) { if (map.get(arr[i][j]) == 1) res[i] += 3; else if (map.get(arr[i][j]) == 2) res[i] += 1; } } for (var r : res) System.out.print(r + " "); System.out.println(); } } } class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new BufferedReader(new InputStreamReader(System.in)); } public FastReader(String file) throws FileNotFoundException { br = new BufferedReader(new FileReader(file)); } void close() throws IOException { br.close(); } String next() { while (st == null || !st.hasMoreElements()) { // null = The First time //!st.hasNoElements = After the st finish the first time try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } double nextDouble() { return Double.parseDouble(next()); } long nextLong() { return Long.parseLong(next()); } String nextLine() { String str = ""; try { str = br.readLine(); } catch (IOException e) { e.printStackTrace(); } return str; } boolean hasNext() { String s = null; try { s = br.readLine(); } catch (IOException e) { e.printStackTrace(); } if (s == null) return false; st = new StringTokenizer(s); return true; } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
5c69d0293e3c1d9e8ea6eb303dc15df0
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.Arrays; import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class MainCode { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); while(n-- > 0) { int k = sc.nextInt(); sc.nextLine(); Map<String, Integer> map = new HashMap<>(); String[][] arr = new String[3][k]; for(int i=0; i < 3; i++) { for(int j=0; j < k; j++) { String str = sc.next(); if(map.containsKey(str)) map.put(str, map.get(str)+1); else map.put(str, 1); arr[i][j] = str; } } int[] players = new int[3]; for(int j=0; j < 3; j++) { for(int i=0; i < k; i++) { if(map.containsKey(arr[0][i])) { if(map.get(arr[j][i]) == 3) { players[j] += 0; } else if(map.get(arr[j][i]) == 2) { players[j] += 1; } else { players[j] += 3; } } } } System.out.println(players[0] + " " + players[1] + " " + players[2]); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
6944aad183cb9db06c1ea3c1e906dbd7
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Solution { public static void main(String[] args) { Scanner in=new Scanner(System.in); int T=in.nextInt(); while(T-->0) { int n=in.nextInt(); HashSet<String> h1=new HashSet<>(); HashSet<String> h2=new HashSet<>(); HashSet<String> h3=new HashSet<>(); for(int i=0;i<n;i++) h1.add(in.next()); for(int i=0;i<n;i++) h2.add(in.next()); for(int i=0;i<n;i++) h3.add(in.next()); int ans1=0,ans2=0,ans3=0; for(String k:h1) { if(h2.contains(k)&&h3.contains(k)) ans1+=0; else if(h2.contains(k)||h3.contains(k)) ans1+=1; else ans1+=3; } for(String k:h2) { if(h1.contains(k)&&h3.contains(k)) ans2+=0; else if(h1.contains(k)||h3.contains(k)) ans2+=1; else ans2+=3; } for(String k:h3) { if(h2.contains(k)&&h1.contains(k)) ans3+=0; else if(h2.contains(k)||h1.contains(k)) ans3+=1; else ans3+=3; } System.out.println(ans1+" "+ans2+" "+ans3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
00643dc021b4338355c49dfa7eaf6408
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; public class Main { public static void main(String args[])throws Exception { BufferedReader input = new BufferedReader(new InputStreamReader(System.in)); // sc.nextInt(); // sc.Integer.parseInt()nextLine(); int T = Integer.parseInt(input.readLine()); while(T-->0){ int k = Integer.parseInt(input.readLine()); HashSet<String> map1 = new HashSet<>(); HashSet<String> map2 = new HashSet<>(); HashSet<String> map3 = new HashSet<>(); String[] p1 = input.readLine().split(" "); String[] p2 = input.readLine().split(" "); String[] p3 = input.readLine().split(" "); for(int z =0;z<k;z++){ map1.add(p1[z]); map2.add(p2[z]); map3.add(p3[z]); } // System.out.println(map1); int val1=0,val2=0,val3=0; for(String h:map1){ if(map2.contains(h) && map3.contains(h)){ val1+=0; } else if(!map2.contains(h) && !map3.contains(h)){ val1+=3; } else val1+=1; } for(String h:map2){ if(map1.contains(h) && map3.contains(h)){ val2+=0; } else if(!map1.contains(h) && !map3.contains(h)){ val2+=3; } else val2+=1; } for(String h:map3){ if(map2.contains(h) && map1.contains(h)){ val3+=0; } else if(!map2.contains(h) && !map1.contains(h)){ val3+=3; } else val3+=1; } System.out.println(val1 + " " + val2 + " " + val3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
cce9a09f41df8e59b0f7f7af7ed83050
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class wordGame { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int T = sc.nextInt(); while(T-->0) { int n = sc.nextInt(); String[][] s1 = new String[3][n]; int[] ar = new int[3]; Map<String,Integer> hm = new HashMap<>(); for(int i=0;i<3;i++) { for (int j = 0; j < n; j++) { s1[i][j] = sc.next(); hm.put(s1[i][j], hm.getOrDefault(s1[i][j], 0) + 1); } } for(int i=0;i<3;i++) { int count=0; for(int j=0;j<n;j++) { if(hm.get(s1[i][j])==1) { count=count+3; } else if(hm.get(s1[i][j])==2) { count=count+1; } } ar[i] =count; } for (int i=0;i<3;i++) { System.out.print(ar[i] + " "); } } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
11b5f9c633bab8f137b5fca925904457
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
//package codeforces; import java.util.*; public class Problem_17 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int test = sc.nextInt(); while (test-- > 0) { int n = sc.nextInt(); Set<String> set1 = new HashSet<>(); Set<String> set2 = new HashSet<>(); Set<String> set3 = new HashSet<>(); String[] can1 = new String[n]; String[] can2 = new String[n]; String[] can3 = new String[n]; int point1 = 0; int point2 = 0; int point3 = 0; for(int i =0;i<n;i++) { String s = sc.next(); can1[i] = s; set1.add(s); } for(int i =0;i<n;i++) { String s = sc.next(); can2[i] = s; set2.add(s); } for(int i =0;i<n;i++) { String s = sc.next(); can3[i] = s; set3.add(s); } for(int i =0;i<can3.length;i++) { if(!set1.contains(can3[i]) && !set2.contains(can3[i])) { point3 += 3; } if(set1.contains(can3[i]) && !set2.contains(can3[i])) { point3 += 1; // point1 += 1; } if(!set1.contains(can3[i]) && set2.contains(can3[i])) { point3 += 1; // point2 += 1; } } for(int i =0;i<can2.length;i++) { if(!set1.contains(can2[i]) && !set3.contains(can2[i])) { point2 += 3; } if(set1.contains(can2[i]) && !set3.contains(can2[i])) { point2 += 1; // point1 += 1; } if(!set1.contains(can2[i]) && set3.contains(can2[i])) { point2 += 1; // point3 += 1; } } for(int i =0;i<can1.length;i++) { if(!set2.contains(can1[i]) && !set3.contains(can1[i])) { point1 += 3; } if(set2.contains(can1[i]) && !set3.contains(can1[i])) { point1 += 1; // point2 += 1; } if(!set2.contains(can1[i]) && set3.contains(can1[i])) { // point3 += 1; point1 += 1; } } System.out.println(point1 + " " + point2 + " " + point3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
6eca6aa451db6fff867d65f7a30d066c
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; import java.io.*; public class Main { public static void main(String args[])throws Exception{ // Your code goes here BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); int t = Integer.parseInt(br.readLine()); while(t-->0){ HashSet<String> set1 = new HashSet<>(); HashSet<String> set2 = new HashSet<>(); HashSet<String> set3 = new HashSet<>(); int n = Integer.parseInt(br.readLine()); String[] s1 = br.readLine().split(" "); String[] s2 = br.readLine().split(" "); String[] s3 = br.readLine().split(" "); for(int i=0;i<n;i++){ set1.add(s1[i]); set2.add(s2[i]); set3.add(s3[i]); } int count1 = 0,count2 =0,count3 =0; for(String s : set1){ // if(!set2.contains(s) && !set3.contains(s)){ // count1 +=3; // } if(set2.contains(s) && set3.contains(s)){ count1 +=0; } else if(!set2.contains(s) && !set3.contains(s)){ count1 +=3; } else{ count1 +=1; } } for(String s : set2){ if(set1.contains(s) && set3.contains(s)){ count2 +=0; } else if(!set1.contains(s) && !set3.contains(s)){ count2 +=3; } else{ count2 +=1; } } for(String s : set3){ if(set2.contains(s) && set1.contains(s)){ count3 +=0; } else if(!set2.contains(s) && !set1.contains(s)){ count3 +=3; } else { count3 +=1; } } System.out.println(count1 + " " + count2 + " " + count3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
04fae7b8fc88159ac2e2bf26170f389a
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.math.*; import java.security.*; import java.text.*; import java.util.*; import java.util.concurrent.*; import java.util.function.*; import java.util.regex.*; import java.util.stream.*; import static java.util.stream.Collectors.joining; import static java.util.stream.Collectors.toList; public class Solution { public static void main(String[] args) throws IOException { Scanner sc=new Scanner(System.in); int t=sc.nextInt(); while(t-->0) { int n=sc.nextInt(); int count=1; String s[]=new String[n]; String s2[]=new String[n]; String s3[]=new String[n]; Map<String ,Integer>map=new HashMap<>(); for(int i=0; i<n; i++) { s[i]=sc.next(); if(!map.containsKey(s[i])) { map.put(s[i],count); } else { map.put(s[i],map.get(s[i])+1); } } for(int i=0; i<n; i++) { s2[i]=sc.next(); if(!map.containsKey(s2[i])) { map.put(s2[i],count); } else { map.put(s2[i],map.get(s2[i])+1); } } for(int i=0; i<n; i++) { s3[i]=sc.next(); if(!map.containsKey(s3[i])) { map.put(s3[i],count); } else { map.put(s3[i],map.get(s3[i])+1); } } int sum=0; for(int i=0; i<n; i++) { if(map.get(s[i])==1) { sum=sum+3; } else if(map.get(s[i])==2) { sum=sum+1; } } System.out.print(sum+" "); sum=0; for(int i=0; i<n; i++) { if(map.get(s2[i])==1) { sum=sum+3; } else if(map.get(s2[i])==2) { sum=sum+1; } } System.out.print(sum+" "); sum=0; for(int i=0; i<n; i++) { if(map.get(s3[i])==1) { sum=sum+3; } else if(map.get(s3[i])==2) { sum=sum+1; } } System.out.println(sum); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
cca06d6356d4cbbd1650f5ec857bda69
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; public class B { static InputReader in; static OutputWriter out; public static void main(String[] args) throws FileNotFoundException { in = new InputReader(System.in); out = new OutputWriter(System.out); if (System.getProperty("ONLINE_JUDGE") == null) { try { in = new InputReader(new FileInputStream("input.txt")); out = new OutputWriter(new FileOutputStream("output.txt")); } catch (Exception e) { } } int t = in.readInt(); for (int o = 1; o <= t; o++) { int n = in.readInt(); String[] a = IOUtils.readStringArray(in, n); String[] b = IOUtils.readStringArray(in, n); String[] c = IOUtils.readStringArray(in, n); solve(n, a, b, c); } out.flush(); out.close(); } public static void solve(int n, String[] a, String[] b, String[] c) { HashMap<String, Integer> map = new HashMap<>(); for (int i = 0; i < n; i++) { if (map.containsKey(a[i])) { map.put(a[i], map.get(a[i]) + 1); } else { map.put(a[i], 1); } if (map.containsKey(b[i])) { map.put(b[i], map.get(b[i]) + 1); } else { map.put(b[i], 1); } if (map.containsKey(c[i])) { map.put(c[i], map.get(c[i]) + 1); } else { map.put(c[i], 1); } } int x = 0, y = 0, z = 0; for (int i = 0; i < n; i++) { x += 3 - (map.get(a[i]) == 1 ? 0 : map.get(a[i])); y += 3 - (map.get(b[i]) == 1 ? 0 : map.get(b[i])); z += 3 - (map.get(c[i]) == 1 ? 0 : map.get(c[i])); } out.printLine(x + " " + y + " " + z); } } class CPHandler{ public static boolean binarySearch(int[] nums, int target) { int low = 0; int high = nums.length - 1; while (low <= high) { int mid = low + (high - low) / 2; if (nums[mid] == target) { return true; } else if (target < nums[mid]) { high = mid - 1; } else { low = mid + 1; } } return false; } public static int gcd(int a, int b) { if (a == 0) return b; return gcd(b % a, a); } } class InputReader { private InputStream stream; private byte[] buf = new byte[1024]; private int curChar; private int numChars; private SpaceCharFilter filter; public InputReader(InputStream stream) { this.stream = stream; } public int read() { if (numChars == -1) throw new InputMismatchException(); if (curChar >= numChars) { curChar = 0; try { numChars = stream.read(buf); } catch (IOException e) { throw new InputMismatchException(); } if (numChars <= 0) return -1; } return buf[curChar++]; } public int readInt() { int c = read(); while (isSpaceChar(c)) c = read(); int sgn = 1; if (c == '-') { sgn = -1; c = read(); } int res = 0; do { if (c < '0' || c > '9') throw new InputMismatchException(); res *= 10; res += c - '0'; c = read(); } while (!isSpaceChar(c)); return res * sgn; } public long readLong() { int c = read(); while (isSpaceChar(c)) c = read(); int sgn = 1; if (c == '-') { sgn = -1; c = read(); } int res = 0; do { if (c < '0' || c > '9') throw new InputMismatchException(); res *= 10; res += c - '0'; c = read(); } while (!isSpaceChar(c)); return res * sgn; } public String readString() { int c = read(); while (isSpaceChar(c)) c = read(); StringBuilder res = new StringBuilder(); do { res.appendCodePoint(c); c = read(); } while (!isSpaceChar(c)); return res.toString(); } public boolean isSpaceChar(int c) { if (filter != null) return filter.isSpaceChar(c); return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1; } public String next() { return readString(); } public interface SpaceCharFilter { public boolean isSpaceChar(int ch); } } class OutputWriter { private final PrintWriter writer; public OutputWriter(OutputStream outputStream) { writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(outputStream))); } public OutputWriter(Writer writer) { this.writer = new PrintWriter(writer); } public void print(Object... objects) { for (int i = 0; i < objects.length; i++) { if (i != 0) writer.print(' '); writer.print(objects[i]); } } public void printLine(Object... objects) { print(objects); writer.println(); } public void close() { writer.close(); } public void flush() { writer.flush(); } } class IOUtils { public static int[] readIntArray(InputReader in, int size) { int[] array = new int[size]; for (int i = 0; i < size; i++) array[i] = in.readInt(); return array; } public static long[] readLongArray(InputReader in, int size) { long[] array = new long[size]; for (int i = 0; i < size; i++) array[i] = in.readLong(); return array; } public static String[] readStringArray(InputReader in, int size) { String[] array = new String[size]; for (int i = 0; i < size; i++) array[i] = in.readString(); return array; } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
3662f4fb4b48b5dd45fb38376d464865
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class codeforces { public static String str="Timur"; public static void main(String[] args) { Scanner sc=new Scanner(System.in); int t=sc.nextInt(); for(int h=0;h<t;h++) { int n = sc.nextInt(); String a []=new String[n]; String b []=new String[n]; String c []=new String[n]; HashMap<String,Integer> uwu=new HashMap<>(); for(int i=0;i<n;i++) { String val=sc.next(); a[i]=val; uwu.put(val,uwu.getOrDefault(val,0)+1); } for(int i=0;i<n;i++) { String val=sc.next(); b[i]=val; uwu.put(val,uwu.getOrDefault(val,0)+1); } for(int i=0;i<n;i++) { String val=sc.next(); c[i]=val; uwu.put(val,uwu.getOrDefault(val,0)+1); } int sa=0,sb=0,scc=0; for(int i=0;i<n;i++) { if(uwu.get(a[i])==1) sa+=3; else if(uwu.get(a[i])==2) sa++; } for(int i=0;i<n;i++) { if(uwu.get(b[i])==1) sb+=3; else if(uwu.get(b[i])==2) sb++; } for(int i=0;i<n;i++) { if(uwu.get(c[i])==1) scc+=3; else if(uwu.get(c[i])==2) scc++; } System.out.println(sa+" "+sb+" "+scc); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
a488041396d23242c76c937b26248d08
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class solution{ public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); for(int m = 1; m <= n; m++){ int l = sc.nextInt(); int[] ans = new int[3]; String ar1[] = new String[l]; HashMap<String,String> map1 = new HashMap<>(); String ar2[] = new String[l]; HashMap<String,String> map2 = new HashMap<>(); String ar3[] = new String[l]; HashMap<String,String> map3 = new HashMap<>(); for(int j = 0; j < l; j++){ ar1[j] = sc.next(); map1.put(ar1[j],""); } for(int j = 0; j < l; j++){ ar2[j] = sc.next(); map2.put(ar2[j],""); } for(int j = 0; j < l; j++){ ar3[j] = sc.next(); map3.put(ar3[j],""); } for(int i = 0; i < ar1.length; i++){ String k = ar1[i]; if(map2.containsKey(k)){ if(!map3.containsKey(k)){ ans[0] += 1; } }else if(map3.containsKey(k)){ ans[0] += 1; }else{ ans[0] += 3; } } for(int i = 0; i < ar2.length; i++){ String k = ar2[i]; if(map1.containsKey(k)){ if(!map3.containsKey(k)){ ans[1] += 1; } }else if(map3.containsKey(k)){ ans[1] += 1; }else{ ans[1] += 3; } } for(int i = 0; i < ar3.length; i++){ String k = ar3[i]; if(map1.containsKey(k)){ if(!map2.containsKey(k)){ ans[2] += 1; } }else if(map2.containsKey(k)){ ans[2] += 1; }else{ ans[2] += 3; } } System.out.println(ans[0] + " " + ans[1] + " " + ans[2]); } // String b = sc.next(); // boolean breaked = false; // for(int j = 0; j < l; j++){ // if(a.charAt(j) == 'R'){ // if(b.charAt(j) != 'R'){ // System.out.println("NO"); // breaked = true; // break; // } // }else if(b.charAt(j) == 'R'){ // System.out.println("NO"); // breaked = true; // break; // } // } // if(!breaked) System.out.println("YES"); // if(l != 5){ // System.out.println("NO"); // continue; // } // int[] arr = new int[256]; // for(int k = 0; k < s.length(); k++){ // arr[s.charAt(k)] = 1; // } // boolean valid = true; // String str = "Timur"; // for(int k = 0; k < str.length(); k++){ // if(arr[str.charAt(k)] != 1){ // valid = false; // break; // } // } // if(valid) System.out.println("YES"); // else System.out.println("No"); // } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
6f960804c714ed2af68e08a1033dfc09
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.ArrayList; import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class problemC { public static void main(String[] args) { Scanner sh = new Scanner(System.in); int t = sh.nextInt(); while(t>0){ int n = sh.nextInt(); sh.nextLine(); Map<String,Integer> m = new HashMap<>(); Map<String,Integer> a = new HashMap<>(); Map<String,Integer> b = new HashMap<>(); Map<String,Integer> c = new HashMap<>(); for(int i = 1; i<=3*n; i++){ String s = sh.next(); if(i<n+1){ a.put(s,1); }else if(i>n && i<2*n + 1){ b.put(s,1); }else{ c.put(s,1); } if(m.containsKey(s)){ m.replace(s,m.get(s) +1); }else{ m.put(s,1); } } int p1 = 0; int p2 = 0; int p3 = 0; for(String x : a.keySet()){ if(m.get(x) == 1){ p1 = p1+3; }else if(m.get(x) == 2){ p1++; } } for(String x : b.keySet()){ if(m.get(x) == 1){ p2 = p2+3; }else if(m.get(x) == 2){ p2++; } } for(String x : c.keySet()){ if(m.get(x) == 1){ p3 = p3+3; }else if(m.get(x) == 2){ p3++; } } System.out.println(p1 + " " + p2 + " " + p3); t--;} } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
c7f20d13b344cb815a5b3314cf8aabbf
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Main{ public static void main(String[] args){ Scanner sc = new Scanner(System.in); int t= sc.nextInt(); while(t>0){ int n= sc.nextInt(); int p=0,q=0,r=0; String l[] = new String[3*n]; Map<String,Integer> m = new HashMap<String,Integer>(); for( int i=0;i<3*n;i++){ String s= sc.next(); l[i]=s; m.merge(s,1,Integer::sum); } for(int i=0;i<n;i++){ if (m.get(l[i])==1) p+=3; else if(m.get(l[i])==2) p+=1; else p+=0; } for(int i=n;i<2*n;i++){ if (m.get(l[i])==1) q+=3; else if(m.get(l[i])==2) q+=1; else q+=0; } for(int i=2*n;i<3*n;i++){ if (m.get(l[i])==1) r+=3; else if(m.get(l[i])==2) r+=1; else r+=0; } System.out.println(p+" "+ q+" "+r); t--; } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
7d631eb42fa55fa6dcf84e8c413befc9
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.ArrayList; import java.util.HashMap; import java.util.Scanner; public class Codeforces2 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int tc = sc.nextInt(); while (tc-- > 0) { int n = sc.nextInt(); ArrayList<String> first = new ArrayList<>(); ArrayList<String> second = new ArrayList<>(); ArrayList<String> third = new ArrayList<>(); HashMap<String, Integer> freq = new HashMap<>(); for (int j = 0; j < n; j++) { String s = sc.next(); first.add(s); freq.put(s, freq.getOrDefault(s, 0) + 1); } for (int j = 0; j < n; j++) { String s = sc.next(); second.add(s); freq.put(s, freq.getOrDefault(s, 0) + 1); } for (int j = 0; j < n; j++) { String s = sc.next(); third.add(s); freq.put(s, freq.getOrDefault(s, 0) + 1); } int m1 = 0, m2 = 0, m3 = 0; for (String s : first) { if (freq.containsKey(s)) { if (freq.get(s) == 2) m1 += 1; else if (freq.get(s) == 1) m1 += 3; } } for (String s : second) { if (freq.containsKey(s)) { if (freq.get(s) == 2) m2 += 1; else if (freq.get(s) == 1) m2 += 3; } } for (String s : third) { if (freq.containsKey(s)) { if (freq.get(s) == 2) m3 += 1; else if (freq.get(s) == 1) m3 += 3; } } System.out.println(m1 + " " + m2 + " " + m3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
a460e599c3e43b78e3b1c5e2d7cb6e29
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; import java.util.Map.Entry; import java.io.*; import java.lang.*; public class main1{ FastScanner in; PrintWriter out; public static void main(String[] arg) { new main1().run(); } //////////////SOLVE QUESTIONS HERE///////////// public class ji{ HashMap<String,Integer> mp=new HashMap<>(); void add(String s) { mp.put(s,1); } void print() { mp.entrySet().forEach(entry -> { System.out.println(entry.getKey() + " " + entry.getValue()); }); } } public void solve() throws IOException { int testcase=1; testcase=in.nextInt(); while(testcase-- > 0) { ji[] arr=new ji[3]; ArrayList<String> s1=new ArrayList<>(); ArrayList<String> s2=new ArrayList<>(); ArrayList<String> s3=new ArrayList<>(); HashSet<String> s=new HashSet<>(); int n=in.nextInt(); for(int j=0;j<3;j++) { arr[j]=new ji(); for(int i=0;i<n;i++) { var temp=in.next(); s.add(temp); if(j==0) s1.add(temp); else if(j==1) s2.add(temp); else s3.add(temp); arr[j].add(temp); } } int a=0,b=0,c=0; for(String temp:s) { if(arr[0].mp.get(temp)!=null && arr[1].mp.get(temp)!=null && arr[2].mp.get(temp)!=null ) { continue; } else if(arr[0].mp.get(temp)!=null && arr[1].mp.get(temp)!=null) { a++; b++; } else if(arr[0].mp.get(temp)!=null && arr[2].mp.get(temp)!=null) { a++; c++; } else if(arr[1].mp.get(temp)!=null && arr[2].mp.get(temp)!=null) { b++; c++; } else if(arr[0].mp.get(temp)!=null) { a+=3; } else if(arr[1].mp.get(temp)!=null) { b+=3; } else if(arr[2].mp.get(temp)!=null) { c+=3; } } out.println(a+" "+b+" "+c); } } public void run() { try { in = new FastScanner(new InputStreamReader(System.in)); out = new PrintWriter(System.out); solve(); out.close(); } catch (IOException e) { e.printStackTrace(); } } class FastScanner { BufferedReader br; StringTokenizer st; public FastScanner(Reader f) { br = new BufferedReader(f); } String next() { while (st == null || !st.hasMoreTokens()) { try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } long nextLong(){ return Long.parseLong(next()); } double nextDouble(){ return Double.parseDouble(next()); } String nextLine(){ String str=""; try { str=br.readLine().trim(); } catch (Exception e) { e.printStackTrace(); } return str; } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
3a5340ba58481e1ca9a442c53a647ffa
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.HashSet; import java.util.Scanner; public class C { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); for(int it = 0 ; it < t ; it++){ int n = sc.nextInt(); HashSet<String> aSet = new HashSet<>(); HashSet<String> bSet = new HashSet<>(); HashSet<String> cSet = new HashSet<>(); for(int i = 0 ; i < n ; i++){ aSet.add(sc.next()); } for(int i = 0 ; i < n ; i++){ bSet.add(sc.next()); } for(int i = 0 ; i < n ; i++){ cSet.add(sc.next()); } int a = 0; int b = 0; int c = 0; for(String s : aSet){ if(bSet.contains(s) && cSet.contains(s)){ continue; }else if(bSet.contains(s) || cSet.contains(s)){ a++; }else{ a += 3; } } for(String s : bSet){ if(aSet.contains(s) && cSet.contains(s)){ continue; }else if(aSet.contains(s) || cSet.contains(s)){ b++; }else{ b += 3; } } for(String s : cSet){ if(bSet.contains(s) && aSet.contains(s)){ continue; }else if(bSet.contains(s) || aSet.contains(s)){ c++; }else{ c += 3; } } System.out.println(a + " " + b + " " + c); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
35c0645ae6cbd94d2ec3a82ec1dadba8
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.HashSet; public class Main { public static void main(String[] args) throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); PrintWriter pw = new PrintWriter(System.out); int t = Integer.parseInt(br.readLine()); while(t-->0) { br.readLine(); HashSet<String> hs = new HashSet<>(); HashSet<String> hs1 = new HashSet<>(); HashSet<String> hs2 = new HashSet<>(); HashSet<String> hs3 = new HashSet<>(); String[] s1 = br.readLine().split(" "); String[] s2 = br.readLine().split(" "); String[] s3 = br.readLine().split(" "); for(String s : s1) { hs.add(s); hs1.add(s); } for(String s : s2) { hs.add(s); hs2.add(s); } for(String s : s3) { hs.add(s); hs3.add(s); } int c1 = 0; int c2 = 0; int c3 = 0; for(String str : hs) { if(hs1.contains(str) && hs2.contains(str) && !hs3.contains(str)) { c1++; c2++; } else if(!hs1.contains(str) && hs2.contains(str) && hs3.contains(str)) { c2++; c3++; } else if(hs1.contains(str) && !hs2.contains(str) && hs3.contains(str)) { c1++; c3++; } else if(hs1.contains(str) && !hs2.contains(str) && !hs3.contains(str)) c1+=3; else if(!hs1.contains(str) && hs2.contains(str) && !hs3.contains(str)) c2+=3; else if(!hs1.contains(str) && !hs2.contains(str) && hs3.contains(str)) c3+=3; } pw.println(c1+" " + c2 + " " + c3); } br.close(); pw.flush(); pw.close(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
6e533f43c893e52f9d114128e7adda5b
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class c { public static void main(String[] args) { Scanner input = new Scanner(System.in); int t = input.nextInt(); while(t-- > 0) { int n = input.nextInt(); String[][] arr = new String[3][n]; HashSet<String>[] set = new HashSet[3]; for (int i = 0; i < 3; i++){ set[i] = new HashSet<>(); for (int j = 0; j < n; j++){ arr[i][j] = input.next(); set[i].add(arr[i][j]); } } long[] ans = new long[3]; for (int i = 0; i < n; i++){ if (set[1].contains(arr[0][i]) && set[2].contains(arr[0][i])) continue; else if (set[1].contains(arr[0][i]) || set[2].contains(arr[0][i])){ ans[0]++; } else { ans[0] += 3; } } for (int i = 0; i < n; i++){ if (set[0].contains(arr[1][i]) && set[2].contains(arr[1][i])) continue; else if (set[0].contains(arr[1][i]) || set[2].contains(arr[1][i])){ ans[1]++; } else { ans[1] += 3; } } for (int i = 0; i < n; i++){ if (set[1].contains(arr[2][i]) && set[0].contains(arr[2][i])) continue; else if (set[1].contains(arr[2][i]) || set[0].contains(arr[2][i])){ ans[2]++; } else { ans[2] += 3; } } System.out.println(ans[0] + " " + ans[1] + " " + ans[2]); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
2462cb3d9ac394ff766fe197c7992e00
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.HashSet; import java.util.Scanner; public class ProblemC { public static void main(String[] args) { var scanner = new Scanner(System.in); var cases = scanner.nextInt(); for (int tc = 0; tc < cases; tc++) { var words = new HashSet<>(); var repeatedWords = new HashSet<>(); var repeatedAllWords = new HashSet<>(); var wordCount = scanner.nextInt(); var input = new String[3][wordCount]; for (int x = 0; x < 3; x++) { for (int i = 0; i < wordCount; i++) { input[x][i] = scanner.next(); } } for (int p = 0; p < 3; p++) { for (int i = 0; i < wordCount; i++) { var word = input[p][i]; if (!words.add(word)) { if (!repeatedWords.add(word)) repeatedAllWords.add(word); } } } for (int p = 0; p < 3; p++) { var score = 0; for (int i = 0; i < wordCount; i++) { var word = input[p][i]; if (repeatedAllWords.contains(word)) continue; if (repeatedWords.contains(word)) score += 1; else score += 3; } System.out.print(score + " "); } System.out.println(); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
02050c303337325e5be5af647f39d4cf
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
/* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the editor. */ //package Codeforces; import java.util.HashSet; import java.util.Scanner; /** * * @author Vinay Jain */ public class cf_817_c { static class Solution { public void solve(Scanner sc){ int n = sc.nextInt(); HashSet<String> a = new HashSet<>(); HashSet<String> b = new HashSet<>(); HashSet<String> c = new HashSet<>(); int p_a = 0 , p_b = 0, p_c = 0; for(int i = 0 ; i < n ; i++) a.add(sc.next()); for(int i = 0 ; i < n ; i++) b.add(sc.next()); for(int i = 0 ; i < n ; i++) c.add(sc.next()); for(String ele : a){ if(b.contains(ele) && c.contains(ele)){ continue; } if(!b.contains(ele) && !c.contains(ele)) p_a += 3; else p_a += 1; } for(String ele : b){ if(a.contains(ele) && c.contains(ele)){ continue; } if(!a.contains(ele) && !c.contains(ele)) p_b += 3; else p_b += 1; } for(String ele : c){ if(a.contains(ele) && b.contains(ele)){ continue; } if(!a.contains(ele) && !b.contains(ele)) p_c += 3; else p_c += 1; } System.out.println(p_a+" "+p_b+" "+p_c); } } public static void main(String args[]){ Scanner sc = new Scanner(System.in); int n = sc.nextInt(); while (n-- > 0){ new Solution().solve(sc); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
217089bbf8b131254cd0227520df5431
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Sol { public static void main(String args[]) { Scanner s=new Scanner(System.in); int t=s.nextInt(); for(int i=0;i<t;i++) { int n=s.nextInt(); String na[][]=new String[3][n]; for(int j=0;j<3;j++) { for(int k=0;k<n;k++) na[j][k]=s.next(); } for(int j=0;j<3;j++) { Arrays.sort(na[j]); } int c=0; for(int k=0;k<n;k++) { if(Arrays.binarySearch(na[1],na[0][k])<0&&Arrays.binarySearch(na[2],na[0][k])<0) c+=3; else if(Arrays.binarySearch(na[1],na[0][k])>0&&Arrays.binarySearch(na[2],na[0][k])>0) c+=0; else if(Arrays.binarySearch(na[1],na[0][k])<0||Arrays.binarySearch(na[2],na[0][k])<0) c+=1; } System.out.print(c+" "); c=0; for(int k=0;k<n;k++) { if(Arrays.binarySearch(na[0],na[1][k])<0&&Arrays.binarySearch(na[2],na[1][k])<0) c+=3; else if(Arrays.binarySearch(na[0],na[1][k])>0&&Arrays.binarySearch(na[2],na[1][k])>0) c+=0; else if(Arrays.binarySearch(na[0],na[1][k])<0||Arrays.binarySearch(na[2],na[1][k])<0) c+=1; } System.out.print(c+" "); c=0; for(int k=0;k<n;k++) { if(Arrays.binarySearch(na[0],na[2][k])<0&&Arrays.binarySearch(na[1],na[2][k])<0) c+=3; else if(Arrays.binarySearch(na[0],na[2][k])>0&&Arrays.binarySearch(na[1],na[2][k])>0) c+=0; else if(Arrays.binarySearch(na[0],na[2][k])<0||Arrays.binarySearch(na[1],na[2][k])<0) c+=1; } System.out.println(c); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 17
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
a72c7f500eaa4addc1f1de1c71289b46
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class WordGame { public static void main(String[] args) { Scanner input = new Scanner(System.in); int T = input.nextInt(); HashMap<String, int[]> freq = new HashMap<>(); int[] points; while (T-- > 0) { points = new int[3]; freq.clear(); int N = input.nextInt(); for (int i = 0; i < 3; i++) { for (int j = 0; j < N; j++) { String str = input.next(); if (freq.containsKey(str)) { int[] arr = freq.get(str); arr[i] = 1; } else { freq.put(str, new int[3]); freq.get(str)[i] = 1; } } } for (String keys : freq.keySet()) { int[] arr = freq.get(keys); int cnt = 0; for (int i : arr) { if (i != 0) { cnt++; } } if (cnt == 1) { for (int i = 0; i < 3; i++) { if (arr[i] != 0) { points[i] += 3; break; } } } else if (cnt == 2) { for (int i = 0; i < 3; i++) { if (arr[i] != 0) { points[i] += 1; } } } else { } } for (int i = 0; i < 3; i++) { System.out.print(points[i] + " "); } System.out.println(); } input.close(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
b9afb85ebf285b4a7b85898bc7ed4ccb
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.Scanner; import java.util.HashSet; import java.util.Set; public class Word_Game { public static void main(String[] args) { // TODO Auto-generated method stub Scanner scan = new Scanner(System.in); int t = scan.nextInt(); while (t-- > 0) { int n = scan.nextInt(); Set<String> s1 = new HashSet<>(); Set<String> s2 = new HashSet<>(); Set<String> s3 = new HashSet<>(); Set<String> h1 = new HashSet<>(); Set<String> h2 = new HashSet<>(); Set<String> h3 = new HashSet<>(); Set<String> merge12 = new HashSet<>(); Set<String> merge13 = new HashSet<>(); Set<String> merge23 = new HashSet<>(); for (int i = 0; i < n; i++) { String s = scan.next(); merge12.add(s); merge13.add(s); s1.add(s); h1.add(s); } for (int i = 0; i < n; i++) { String s = scan.next(); merge12.add(s); merge23.add(s); s2.add(s); h2.add(s); } for (int i = 0; i < n; i++) { String s = scan.next(); merge13.add(s); merge23.add(s); s3.add(s); h3.add(s); } s3.removeAll(h2); s3.removeAll(h1); s1.removeAll(h2); s1.removeAll(h3); s2.removeAll(h1); s2.removeAll(h3); merge13.removeAll(h2); merge13.removeAll(s1); merge13.removeAll(s3); merge12.removeAll(h3); merge12.removeAll(s1); merge12.removeAll(s2); merge23.removeAll(h1); merge23.removeAll(s3); merge23.removeAll(s2); int common12 = merge12.size(); int common13 = merge13.size(); int common23 = merge23.size(); int score1 = common12 + common13 + (s1.size()) * 3; int score2 = common12 + common23 + (s2.size()) * 3; int score3 = common23 + common13 + (s3.size()) * 3; System.out.println(score1 + " " + score2 + " " + score3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
90bf33dc4596051738d618ae9fa1dd80
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.StringTokenizer; import java.util.HashSet; import java.util.TreeMap; import java.util.PriorityQueue; import java.util.Arrays; public class Main { public static void main(String[] args) throws IOException{ FastReader s = new FastReader(); int t = s.nextInt(); while(t-->0){ int n = s.nextInt(); HashSet<String> set1 = new HashSet<>(); HashSet<String> set2 = new HashSet<>(); int p1 = 0; int p2 = 0; int p3 = 0; for(int i = 0; i < n; i++){ set1.add(s.next()); p1 += 3; } for(int i = 0; i < n; i++){ String str = s.next(); set2.add(str); if(set1.contains(str)){ p1 -= 2; p2 += 1; } else{ p2 += 3; } } for(int i = 0; i < n; i++){ String str = s.next(); if(set1.contains(str) && set2.contains(str)){ p1--; p2--; } else if(set1.contains(str)){ p1 -= 2; p3++; } else if(set2.contains(str)){ p2 -= 2; p3++; } else{ p3 += 3; } } System.out.println(p1 + " " + p2 + " " + p3); } } public static boolean isVowel(char ch){ if(ch == 'a' || ch == 'e' || ch == 'i' || ch == 'u' || ch == 'o'){ return true; } return false; } static class FastReader { BufferedReader br; StringTokenizer st; public FastReader(){ br = new BufferedReader(new InputStreamReader(System.in)); } public String next() throws IOException{ while (st == null || !st.hasMoreElements()) { try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } } return st.nextToken(); } int nextInt() throws IOException{ return Integer.parseInt(next()); } long nextLong() throws IOException{ return Long.parseLong(next()); } double nextDouble() throws IOException{return Double.parseDouble(next());} String nextLine() throws IOException{ String str = ""; if(st.hasMoreTokens()){ str = st.nextToken("\n"); } else{ str = br.readLine(); } return str; } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
e921a7d2d4c992742345630646d553bf
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; public class Words { public static void main(String[] args) throws IOException { BufferedReader br = new BufferedReader (new InputStreamReader (System.in)); int numberOfSets = Integer.parseInt(br.readLine()); for (int nos = 0; nos < numberOfSets; nos ++) { int size = Integer.parseInt(br.readLine()); String [] s1 = br.readLine().split(" "); String [] s2 = br.readLine().split(" "); String [] s3 = br.readLine().split(" "); int sum1, sum2, sum3; sum1=sum2=sum3=0; int count; Map<String, Integer> map = new HashMap<>(); for (int i = 0; i<size; i++) { if (map.get(s1[i]) == null) { map.put(s1[i], 3); } else { count = map.get(s1[i]); map.put(s1[i], count/2); } } for (int i = 0; i<size; i++) { if (map.get(s2[i]) == null) { map.put(s2[i], 3); } else { count = map.get(s2[i]); map.put(s2[i], count/2); } } for (int i = 0; i<size; i++) { if (map.get(s3[i]) == null) { map.put(s3[i], 3); } else { count = map.get(s3[i]); map.put(s3[i], count/2); } } for (int i = 0; i < size; i++) { if(map.containsKey(s1[i])) { sum1+= map.get(s1[i]); } } for (int i = 0; i < size; i++) { if(map.containsKey(s2[i])) { sum2+= map.get(s2[i]); } } for (int i = 0; i < size; i++) { if(map.containsKey(s3[i])) { sum3+= map.get(s3[i]); } } System.out.println(sum1 + " " + sum2 + " " + sum3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
6f5bdd96954818971c6380e44cdfccf7
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class WordGame { public static void main(String[] args) { final Scanner sc = new Scanner(System.in); int t = Integer.parseInt(sc.nextLine()); String[] resultados =new String[t]; for(int i=0;i<t;i++){ int n=Integer.parseInt(sc.nextLine()); int puntaje1=0; int puntaje2=0; int puntaje3=0; String[] jugador1 = sc.nextLine().split(" "); String[] jugador2 = sc.nextLine().split(" "); String[] jugador3 = sc.nextLine().split(" "); //System.out.println(jugador1.length); Map<String, Integer> map = new HashMap<String, Integer>(); for (int j=0;j<n;j++){ map.put(jugador1[j],0); map.put(jugador2[j],0); map.put(jugador3[j],0); } for (int j=0;j<n;j++){ map.put(jugador1[j],map.get(jugador1[j])+1); map.put(jugador2[j],map.get(jugador2[j])+1); map.put(jugador3[j],map.get(jugador3[j])+1); } for (int z=0;z<n;z++){ if (map.get(jugador1[z])==1){ puntaje1+=3; }else if (map.get(jugador1[z])==2){ puntaje1+=1; } } for (int z=0;z<n;z++){ if (map.get(jugador2[z])==1){ puntaje2+=3; }else if (map.get(jugador2[z])==2){ puntaje2+=1; } } for (int z=0;z<n;z++){ if (map.get(jugador3[z])==1){ puntaje3+=3; }else if (map.get(jugador3[z])==2){ puntaje3+=1; } } resultados[i]= (puntaje1+" "+puntaje2+" "+puntaje3); } for (int k=0;k<t;k++){ System.out.println(resultados[k]); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
91c761271709f0e1ebf82474da1eee44
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.HashMap; import java.util.HashSet; import java.util.Map; import java.util.Set; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.StringTokenizer; public class C817 { static AReader scan = new AReader(); static void solve() { Map<String,Integer> hash = new HashMap<>(); int n = scan.nextInt(); String[][] strs = new String[4][n+10]; for(int i = 1;i<=3;i++){ Set<String> st = new HashSet<>(); for(int j = 1;j<=n;j++){ String s = scan.next(); strs[i][j] = s; if(st.contains(s)) continue; st.add(s); int t = hash.getOrDefault(s,0); hash.put(s,++t); } } for(int i = 1;i<=3;i++){ int p = 0; for(int j = 1;j<=n;j++){ String s = strs[i][j]; if(hash.get(s) == 1) p +=3; else if(hash.get(s) == 2) p +=1; } System.out.print(p+" "); } System.out.println(); } public static void main(String[] args) { int T = scan.nextInt(); while (T-- > 0) { solve(); } } } class AReader { private BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); private StringTokenizer tokenizer = new StringTokenizer(""); private String innerNextLine() { try { return reader.readLine(); } catch (IOException ex) { return null; } } public boolean hasNext() { while (!tokenizer.hasMoreTokens()) { String nextLine = innerNextLine(); if (nextLine == null) { return false; } tokenizer = new StringTokenizer(nextLine); } return true; } public String nextLine() { tokenizer = new StringTokenizer(""); return innerNextLine(); } public String next() { hasNext(); return tokenizer.nextToken(); } public int nextInt() { return Integer.parseInt(next()); } public long nextLong() { return Long.parseLong(next()); } public double nextDouble() { return Double.parseDouble(next()); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
c982e4a387739519284c716a55f90b79
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.ArrayList; import java.util.HashMap; import java.util.HashSet; import java.util.Scanner; public class _1722C { public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc = new Scanner(System.in); int t = sc.nextInt(); for (int i=1;i<=t;i++) { int n = sc.nextInt(); // String trsah = sc.nextLine(); // HashMap<String,Integer> words = new HashMap<String,Integer>(); // ArrayList<String> p1 = new ArrayList<String>(); // ArrayList<String> p2 = new ArrayList<String>(); // ArrayList<String> p3 = new ArrayList<String>(); // String l1[]=sc.nextLine().split(" "); // String l2[]=sc.nextLine().split(" "); // String l3[]=sc.nextLine().split(" "); // for(int j=0;j<n;j++) { // String temp=l1[j]; // if(!p1.contains(temp)) { // int val=words.getOrDefault(temp, 0); // val++; // words.put(temp, val); // } // p1.add(temp); // } // for(int j=0;j<n;j++) { // String temp=l2[j]; // if(!p2.contains(temp)) { // int val=words.getOrDefault(temp, 0); // val++; // words.put(temp, val); // } // p2.add(temp); // } // for(int j=0;j<n;j++) { // String temp=l3[j]; // if(!p3.contains(temp)) { // int val=words.getOrDefault(temp, 0); // val++; // words.put(temp, val); // } // p3.add(temp); // } // for(String h:p1) { // if(p2.contains(h)) { // if(p3.contains(h)) { // continue; // }else { // a1++; // } // }else if(p3.contains(h)) { // if(p2.contains(h)) { // continue; // }else { // a1++; // } // }else { // a1+=3; // } // } // for(String h:p2) { // if(p1.contains(h)) { // if(p3.contains(h)) { // continue; // }else { // a2++; // } // }else if(p3.contains(h)) { // if(p2.contains(h)) { // continue; // }else { // a2++; // } // }else { // a2+=3; // } // } // for(String h:p3) { // if(p1.contains(h)) { // if(p2.contains(h)) { // continue; // }else { // a3++; // } // }else if(p2.contains(h)) { // if(p1.contains(h)) { // continue; // }else { // a3++; // } // }else { // a3+=3; // } // } // for(String h:words) { // if(p1.contains(h) && p2.contains(h) && p3.contains(h)) { // continue; // }else if(p1.contains(h)) { // if(p2.contains(h)) { // a1++;a2++; // }else if(p3.contains(h)) { // a1++;a3++; // }else { // a1+=3; // } // }else if(p2.contains(h)) { // if(p1.contains(h)) { // a1++;a2++; // }else if(p3.contains(h)) { // a2++;a3++; // }else { // a2+=3; // } // }else if(p3.contains(h)) { // if(p1.contains(h)) { // a1++;a3++; // }else if(p2.contains(h)) { // a2++;a3++; // }else { // a3+=3; // } // } // } // for(String h:words.keySet()) { // int val=words.get(h); // if(val==3) { // continue; // }else if(val==2) { // if(p1.contains(h)) { // if(p2.contains(h)) { // a1++;a2++; // }else if(p3.contains(h)) { // a1++;a3++; // } // }else if(p2.contains(h)) { // if(p1.contains(h)) { // a1++;a2++; // }else if(p3.contains(h)) { // a2++;a3++; // } // }else if(p3.contains(h)) { // if(p1.contains(h)) { // a1++;a3++; // }else if(p2.contains(h)) { // a2++;a3++; // } // } // }else if(val==1) { // if(p1.contains(h)) { // a1+=3; // }else if(p2.contains(h)) { // a2+=3; // }else if(p3.contains(h)) { // a3+=3; // } // } // } int a1=0; int a2=0; int a3=0; HashMap<String,Integer> words = new HashMap<String,Integer>(); for(int j=0;j<n;j++) { String temp = sc.next(); words.put(temp, 1); a1+=3; } for(int j=0;j<n;j++) { String temp=sc.next(); if(words.keySet().contains(temp)) { a1++;a1-=3;a2++; words.put(temp, 2); }else { words.put(temp,-1); a2+=3; } } for(int j=0;j<n;j++) { String temp=sc.next(); if(words.keySet().contains(temp)) { if(words.get(temp)==2) { words.put(temp, 3); a1--;a2--; }else if(words.get(temp)==-1){ a2++;a3++;a2-=3; }else if(words.get(temp)==1) { a1++;a3++;a1-=3; } }else { words.put(temp, 1); a3+=3; } } System.out.println(a1+" "+a2+" "+a3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
9605130d71952fcfa2d6fde9490c5aa6
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; import java.math.BigInteger; import java.util.stream.Collectors; public class Main { InputStream is; PrintWriter out; String INPUT = ""; void run() throws Exception { is = System.in; out = new PrintWriter(System.out); solve(); out.flush(); out.close(); } public static void main(String[] args) throws Exception { new Main().run(); } public byte[] inbuf = new byte[1 << 16]; public int lenbuf = 0, ptrbuf = 0; public int readByte() { if (lenbuf == -1) { throw new InputMismatchException(); } if (ptrbuf >= lenbuf) { ptrbuf = 0; try { lenbuf = is.read(inbuf); } catch (IOException e) { throw new InputMismatchException(); } if (lenbuf <= 0) return -1; } return inbuf[ptrbuf++]; } public boolean isSpaceChar(int c) { return !(c >= 33 && c <= 126); } public int skip() { int b; while ((b = readByte()) != -1 && isSpaceChar(b)) ; return b; } public double nd() { return Double.parseDouble(ns()); } public char nc() { return (char) skip(); } private String ns() { int b = skip(); StringBuilder sb = new StringBuilder(); while (!(isSpaceChar(b))) { sb.appendCodePoint(b); b = readByte(); } return sb.toString(); } private int ni() { return (int) nl(); } private long nl() { long num = 0; int b; boolean minus = false; while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-')) ; if (b == '-') { minus = true; b = readByte(); } while (true) { if (b >= '0' && b <= '9') { num = num * 10 + (b - '0'); } else { return minus ? -num : num; } b = readByte(); } } class Pair { int first; int second; Pair(int a, int b) { first = a; second = b; } } long[] nal(int n) { long[] arr = new long[n]; for (int i = 0; i < n; i++) { arr[i] = nl(); } return arr; } void solve() { int test_case = 1; test_case = ni(); while (test_case-- > 0) { go(); } } // WRITE CODE FROM HERE :- void go() { int n = ni(); Map<String, Integer> map = new HashMap<>(); String[][] ch = new String[3][n]; String s = ""; for(int i=0; i<3; i++) { for(int j=0; j<n; j++) { s = ns(); ch[i][j] = s; map.put(s, map.getOrDefault(s, 0) + 1); } } long ans = 0; for(int i=0; i<3; i++) { ans = 0; for(int j=0; j<n; j++) { if(map.get(ch[i][j]) == 2) ans += 1; else if(map.get(ch[i][j]) == 1) ans += 3; else ans += 0; } out.print(ans + " "); } out.println(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
4d66fab65d5a00da53d03f2f5a5d4217
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Main { public static void main(String[] args) { Scanner s=new Scanner(System.in); int t=s.nextInt(); while(t-->0) { int n=s.nextInt(); String[] q1=new String[n]; String[] q2=new String[n]; String[] q3=new String[n]; HashSet<String> l1=new HashSet(); HashSet<String> l2=new HashSet(); HashSet<String> l3=new HashSet(); int c1=0,c2=0,c3=0; for(int i=0;i<n;i++) { q1[i]=s.next(); l1.add(q1[i]); } for(int i=0;i<n;i++) { q2[i]=s.next(); l2.add(q2[i]); } for(int i=0;i<n;i++) { q3[i]=s.next(); l3.add(q3[i]); } for(String i:l1) { if(l2.contains(i) && l3.contains(i)) c1=c1+0; else if(l2.contains(i) && !l3.contains(i) || !l2.contains(i) && l3.contains(i)) c1=c1+1; else c1=c1+3; } for(String i:l2) { if(l1.contains(i) && l3.contains(i)) c2=c2+0; else if(l1.contains(i) && !l3.contains(i) || !l1.contains(i) && l3.contains(i)) c2=c2+1; else c2=c2+3; } for(String i:l3) { if(l2.contains(i) && l1.contains(i)) c3=c3+0; else if(l2.contains(i) && !l1.contains(i) || !l2.contains(i) && l1.contains(i)) c3=c3+1; else c3=c3+3; } System.out.println(c1+" "+c2+" "+c3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
b77400c1e4aa802bdac1cc9f1b76c99e
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; import java.util.regex.Pattern; public class Robot4 { public static void main(String[] args) { Scanner x = new Scanner(System.in); int s = x.nextInt(); for (int i = 0; i < s; i++) { int count1=0; int count2=0; int count3=0; String[]aa ; String[]bb ; String[]cc ; // ArrayList<String>a = new ArrayList<>(); // ArrayList<String>b = new ArrayList<>(); // ArrayList<String>c = new ArrayList<>(); int leng = x.nextInt(); x.nextLine(); aa=x.nextLine().split(" "); bb=x.nextLine().split(" "); cc=x.nextLine().split(" "); HashMap<String,Integer>a1 = new HashMap<>(); HashMap<String,Integer>b1 = new HashMap<>(); HashMap<String,Integer>c1 = new HashMap<>(); for (int j = 0; j < leng; j++) {a1.put(aa[j],0);b1.put(bb[j],0);c1.put(cc[j],0);} for (Map.Entry<String, Integer> pair : a1.entrySet()) { if ((b1.containsKey(pair.getKey())&&!c1.containsKey(pair.getKey()))){ count1++; count2++; } } for (Map.Entry<String, Integer> pair : c1.entrySet()) { if ((b1.containsKey(pair.getKey())&&!a1.containsKey(pair.getKey()))){ count2++; count3++; } } for (Map.Entry<String, Integer> pair : c1.entrySet()) { if ((a1.containsKey(pair.getKey())&&!b1.containsKey(pair.getKey()))){ count1++; count3++; } } for (Map.Entry<String, Integer> pair : c1.entrySet()) { if ((!a1.containsKey(pair.getKey())&&!b1.containsKey(pair.getKey()))){ count3++; count3++; count3++; } } for (Map.Entry<String, Integer> pair : a1.entrySet()) { if ((!b1.containsKey(pair.getKey())&&!c1.containsKey(pair.getKey()))){ count1++; count1++; count1++; } } for (Map.Entry<String, Integer> pair : b1.entrySet()) { if ((!a1.containsKey(pair.getKey())&&!c1.containsKey(pair.getKey()))){ count2++; count2++; count2++; } } // if (b.contains(c.get(j))&&!a.contains(c.get(j))){ // // cminus2++; // cminus3++; // // count2++; // count3++; // } // // if (a.contains(c.get(j))&&!b.contains(c.get(j))){ // cminus1++; // cminus3++; // // count1++; // count3++; // } System.out.println(count1 + " "+count2 + " "+ count3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
21c7a4fc1c6baf01a032f5279ee85784
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Codeforces { public static void main(String[] args) { try { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); while (t-->0) { int n = sc.nextInt(); String[] a = new String[n]; String[] b = new String[n]; String[] c = new String[n]; HashMap<String,Integer>m = new HashMap<>(); for(int i=0;i<n;i++){ a[i] = sc.next(); m.put(a[i],m.getOrDefault(a[i],0)+1); } for(int i=0;i<n;i++){ b[i] = sc.next(); m.put(b[i],m.getOrDefault(b[i],0)+1); } for(int i=0;i<n;i++){ c[i] = sc.next(); m.put(c[i],m.getOrDefault(c[i],0)+1); } int ca = 0,cb=0,cc=0; for(int i=0;i<n;i++){ if(m.get(a[i]) == 2) ca+=1; else if(m.get(a[i]) == 1) ca+=3; if(m.get(b[i]) == 2) cb+=1; else if(m.get(b[i]) == 1) cb+=3; if(m.get(c[i]) == 2) cc+=1; else if(m.get(c[i]) == 1) cc+=3; } System.out.println(ca+" "+cb+" "+cc); } } catch (Exception e){ System.out.println(e); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
44e4568a4c20ff87d8e69f822fe22442
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.HashSet; import java.util.StringTokenizer; public class ProblemA { public static void main(String[] args) throws IOException { BufferedReader f = new BufferedReader(new InputStreamReader(System.in)); StringTokenizer st = new StringTokenizer(f.readLine()); int t = Integer.parseInt(st.nextToken()); for(int x = 0; x < t; x++) { st = new StringTokenizer(f.readLine()); int n = Integer.parseInt(st.nextToken()); HashSet<String> a = new HashSet<String>(); HashSet<String> a1 = new HashSet<String>(); HashSet<String> a2 = new HashSet<String>(); String[] b = new String[n]; String[] b1 = new String[n]; String[] b2 = new String[n]; st = new StringTokenizer(f.readLine()); for(int i = 0; i < n; i++) { b[i] = st.nextToken(); a.add(b[i]); } st = new StringTokenizer(f.readLine()); for(int i = 0; i < n; i++) { b1[i] = st.nextToken(); a1.add(b1[i]); } st = new StringTokenizer(f.readLine()); for(int i = 0; i < n; i++) { b2[i] = st.nextToken(); a2.add(b2[i]); } int sum = 0; for(int i = 0; i < n; i++) { if(a2.contains(b[i]) && a1.contains(b[i])) { sum+=0; } else if(a2.contains(b[i]) && !a1.contains(b[i])) { sum+=1; } else if(a1.contains(b[i]) && !a2.contains(b[i])) { sum+=1; } else { sum+=3; } } System.out.print(sum+" "); sum = 0; for(int i = 0; i < n; i++) { if(a2.contains(b1[i]) && a.contains(b1[i])) { sum+=0; } else if(a2.contains(b1[i]) && !a.contains(b1[i])) { sum+=1; } else if(a.contains(b1[i]) && !a2.contains(b1[i])) { sum+=1; } else { sum+=3; } } System.out.print(sum+" "); sum = 0; for(int i = 0; i < n; i++) { if(a1.contains(b2[i]) && a.contains(b2[i])) { sum+=0; } else if(a.contains(b2[i]) && !a1.contains(b2[i])) { sum+=1; } else if(a1.contains(b2[i]) && !a.contains(b2[i])) { sum+=1; } else { sum+=3; } } System.out.print(sum+" "); System.out.println(); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
9b6cb3e9f1b594f1a712161ce0c2e9a7
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class OurThirdProblem { public static void main(String[] args) { Scanner in = new Scanner(System.in); for (int t = in.nextInt(); t>0; t--){ int n = in.nextInt(); HashMap<String, LinkedList<Integer>> map = new HashMap<>(); for (int i = 0; i<n; i++){ String current = in.next(); if (!map.containsKey(current)) map.put(current,new LinkedList<>()); map.get(current).add(1); } for (int i = 0; i<n; i++){ String current = in.next(); if (!map.containsKey(current)) map.put(current,new LinkedList<>()); map.get(current).add(2); } for (int i = 0; i<n; i++){ String current = in.next(); if (!map.containsKey(current)) map.put(current,new LinkedList<>()); map.get(current).add(3); } int p1 = 0,p2 = 0,p3 = 0; for (String word : map.keySet()){ LinkedList<Integer> l = map.get(word); int size = l.size(); if (size == 1) { if (l.get(0) == 1) p1+=3; if (l.get(0) == 2) p2+=3; if (l.get(0) == 3) p3+=3; } else if (size == 2) { if (l.get(0) == 1 || l.get(1) == 1) p1++; if (l.get(0) == 2 || l.get(1) == 2) p2++; if (l.get(0) == 3 || l.get(1) == 3) p3++; } } System.out.println(p1 + " " + p2 + " " + p3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
9ba4ecb3d5baa937774bd8ae10d8db96
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class _1722C { public static void main(String[] args) { Scanner in = new Scanner(System.in); StringBuilder sb = new StringBuilder(); for (int t = in.nextInt(); t>0; t--){ int n = in.nextInt(); HashSet<String> M1 = add(in, n), M2 = add(in, n), M3 = add(in, n); int m1 = counter(M1, M2, M3), m2 = counter(M2, M1, M3), m3 = counter(M3, M1, M2); sb.append(m1).append(" ").append(m2).append(" ").append(m3).append("\n"); } System.out.println(sb); } public static int counter(HashSet<String> current,HashSet<String> s1, HashSet<String> s2){ int c1 = 0; for (String s : current){ boolean one = s1.contains(s), two = s2.contains(s); if ((one && !two) || (!one && two)) c1++; else if (!one) c1+=3; } return c1; } public static HashSet<String> add(Scanner in, int n){ HashSet<String> current = new HashSet<>(); for (int j = 1; j<= n; j++) current.add(in.next()); return current; } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
f9c014a9a7f2d7ccc38b9f0cac8a3af2
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class _1722C { public static void main(String[] args) { Scanner in = new Scanner(System.in); for (int t = in.nextInt(); t>0; t--){ int n = in.nextInt(); HashSet<String> M1 = add(in, n); HashSet<String> M2 = add(in, n); HashSet<String> M3 = add(in, n); int m1 = counter(M1, M2, M3); int m2 = counter(M2, M1, M3); int m3 = counter(M3, M1, M2); System.out.println(m1 + " " + m2 + " " + m3); } } public static int counter(HashSet<String> current,HashSet<String> s1, HashSet<String> s2){ int c1 = 0; for (String s : current){ boolean one = s1.contains(s), two = s2.contains(s); if ((one && !two) || (!one && two)) c1++; else if (!one) c1+=3; } return c1; } public static HashSet<String> add(Scanner in, int n){ HashSet<String> current = new HashSet<>(); for (int j = 1; j<= n; j++) current.add(in.next()); return current; } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
3a5ee0ebfdc39e285f7766961c55d238
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); while(t-- > 0){ int n= sc.nextInt(); HashMap<String,Integer>hm = new HashMap<>(); String a[][] = new String[3][n]; int i,j = 0; for(i=0;i<3;i++){ for(j=0;j<n;j++){ a[i][j] = sc.next(); if(hm.containsKey(a[i][j])){ hm.put(a[i][j],hm.get(a[i][j])-2); } else{ hm.put(a[i][j],3); } } } int r[] = new int[3]; for(i=0;i<3;i++){ for(j=0;j<n;j++){ if(hm.get(a[i][j])>0){ r[i] = r[i] + hm.get(a[i][j]); } } } System.out.println(r[0]+" "+r[1]+" "+r[2]); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
b87e780aa5d5f3ecbc9fb19a224dde2c
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Main{ public static void main(String[] args){ Scanner scn = new Scanner(System.in); int T = scn.nextInt(); while(T-->0){ int n = scn.nextInt(); String[][] arr = new String[3][n]; HashMap<String,Integer> map = new HashMap<>(); for(int i=0; i<3; i++){ for(int j=0; j<n; j++){ arr[i][j] = scn.next(); if(map.containsKey(arr[i][j])) map.put(arr[i][j],map.get(arr[i][j])-2); else map.put(arr[i][j],3); } } int[] points = new int[3]; for(int i=0; i<3; i++){ for(int j=0; j<n; j++){ if(map.get(arr[i][j])!=-1) points[i] += map.get(arr[i][j]); } } System.out.println(points[0] + " " + points[1] + " " + points[2]); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
a8163caa8916b24751974755065072bc
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.HashSet; import java.util.Scanner; public class WordGameSet { public static void main(String[] args) { Scanner in = new Scanner(System.in); int t = in.nextInt(); for ( int p = 0; p < t; p++){ int n = in.nextInt(); HashSet <String> set1 = new HashSet<>(); HashSet <String> set2 = new HashSet<>(); HashSet <String> set3 = new HashSet<>(); HashSet <String> set4 = new HashSet<>(); for ( int i = 0; i < n; i++) { String x = in.next(); set1.add(x); set4.add(x); } for ( int i = 0; i < n; i++) set2.add(in.next()); for ( int i = 0; i < n; i++) set3.add(in.next()); int num1 = set1.size(); int num2 = set2.size(); int num3 = set3.size(); set1.retainAll(set2); set2.retainAll(set3); set4.retainAll(set3); int num12 = set1.size(); int num23 = set2.size(); int num13 = set4.size(); set1.retainAll(set2); int num123 = set1.size(); num12-= num123; num13-= num123; num23-= num123; num1 -= num12 + num13 + num123; num2 -= num23 + num12 + num123; num3 -= num13 + num23 + num123; System.out.println(((3*num1)+num12+num13) + " " + ((3*num2)+num12+num23) + " " + ((3*num3)+num13+num23)); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
3d88a09a779d6bea707f3c329e48a358
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.Scanner; import java.util.*; public class Q3 { public static void main(String[] args) { // TODO Auto-generated method stub Scanner key=new Scanner(System.in); int t=key.nextInt(); for(int i=0;i<t;i++) { int n=key.nextInt(); key.nextLine(); String str1=key.nextLine(); String str2=key.nextLine(); String str3=key.nextLine(); HashSet<String>s=new HashSet<>(); int one=0,two=0,three=0,ac=0,ab=0,bc=0,abc=0,qabc=0; String temp=""; for(int j=0;j<4*n-1;j++) { if(str1.charAt(j)==' ') { s.add(temp); temp=""; }else { temp=temp+str1.charAt(j); } } s.add(temp); temp=""; for(int k=0;k<4*n-1;k++) { if(str2.charAt(k)==' ') { if(s.contains(temp)) { ab++; } temp=""; }else { temp=temp+str2.charAt(k); } } if(s.contains(temp)) { ab++; } temp=""; for(int l=0;l<4*n-1;l++) { if(str3.charAt(l)==' ') { if(s.contains(temp)) { ac++; } temp=""; }else { temp=temp+str3.charAt(l); } } if(s.contains(temp)) { ac++; } temp=""; for(int r=0;r<4*n-1;r++) { if(str3.charAt(r)==' ') { s.add(temp); temp=""; }else { temp=temp+str3.charAt(r); } } s.add(temp); temp=""; for(int q=0;q<4*n-1;q++) { if(str2.charAt(q)==' ') { s.add(temp); temp=""; }else { temp=temp+str2.charAt(q); } } s.add(temp); temp=""; abc=s.size(); s.clear(); for(int e=0;e<4*n-1;e++) { if(str3.charAt(e)==' ') { s.add(temp); temp=""; }else { temp=temp+str3.charAt(e); } } s.add(temp); temp=""; for(int w=0;w<4*n-1;w++) { if(str2.charAt(w)==' ') { if(s.contains(temp)) { bc++; } temp=""; }else { temp=temp+str2.charAt(w); } } if(s.contains(temp)) { bc++; } qabc=abc+ab+ac+bc-3*n; one=1*(ab+ac-2*qabc)+3*(n-ab-ac+qabc); two=1*(ab+bc-2*qabc)+3*(n-ab-bc+qabc); three=1*(bc+ac-2*qabc)+3*(n-bc-ac+qabc); System.out.println(one+" "+two+" "+three); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
8af19132adf7b67a4abac370d2e51c77
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Main { public static void main(String []args) { Scanner scan = new Scanner(System.in); int testCases = scan.nextInt(); for(int q = 0; q < testCases; q++) { int n = scan.nextInt(); String [][] input = new String[3][n]; Map<String, Integer> map = new Hashtable<>(); for(int i = 0; i < 3; i++) { for(int j = 0; j < n; j++) { input[i][j] = scan.next(); if(map.containsKey(input[i][j])) { map.put(input[i][j], map.get(input[i][j]) + 1); } else { map.put(input[i][j], 1); } } } int []ans = new int[3]; for(int i = 0; i < 3; i++) { for(int j = 0; j < n; j++) { if(i == 0) { if(map.get(input[i][j]) == 1) ans[0] += 3; else if(map.get(input[i][j]) == 2) ans[0] += 1; } else if(i == 1) { if(map.get(input[i][j]) == 1) ans[1] += 3; else if(map.get(input[i][j]) == 2) ans[1] += 1; } else { if(map.get(input[i][j]) == 1) ans[2] += 3; else if(map.get(input[i][j]) == 2) ans[2] += 1; } } } for(int item : ans) System.out.print(item + " "); System.out.println(); } } // end of main method } // end of Main class
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
c19535144ac1569cc0708ce8fe01fccf
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.lang.reflect.Array; import java.math.BigInteger; import java.rmi.Remote; import java.text.Collator; // import java.util.Scanner; import java.util.*; import javax.management.Query; import javax.xml.transform.Source; public class second { static class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new BufferedReader( new InputStreamReader(System.in)); } String next() { while (st == null || !st.hasMoreElements()) { try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } long nextLong() { return Long.parseLong(next()); } double nextDouble() { return Double.parseDouble(next()); } String nextLine() { String str = ""; try { if (st.hasMoreTokens()) { str = st.nextToken("\n"); } else { str = br.readLine(); } } catch (IOException e) { e.printStackTrace(); } return str; } } public static void main(String[] args) { FastReader s = new FastReader(); int test_case=s.nextInt(); while(test_case-->0){ int n=s.nextInt(); String [][] aa=new String[3][n]; HashMap<String,Integer> ans=new HashMap<>(); for(int i=0;i<n;i++){ aa[0][i]=s.next(); ans.put(aa[0][i],ans.getOrDefault(aa[0][i],0)+1); } for(int i=0;i<n;i++){ aa[1][i]=s.next(); ans.put(aa[1][i],ans.getOrDefault(aa[1][i],0)+1); } for(int i=0;i<n;i++){ aa[2][i]=s.next(); ans.put(aa[2][i],ans.getOrDefault(aa[2][i],0)+1); } int points=0; for(int i=0;i<n;i++){ if(ans.get(aa[0][i])==1) points+=3; else if(ans.get(aa[0][i])==2) points++; } System.out.print(points+" "); points=0; for(int i=0;i<n;i++){ if(ans.get(aa[1][i])==1) points+=3; else if(ans.get(aa[1][i])==2) points++; } System.out.print(points+" "); points=0; for(int i=0;i<n;i++){ if(ans.get(aa[2][i])==1) points+=3; else if(ans.get(aa[2][i])==2) points++; } System.out.print(points+"\n"); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
3e68709347b8b92adb84859f2792f3a0
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Solution { public static void main (String[] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); while (t-- > 0) { HashMap<String, Integer> map = new HashMap<>(); int n = sc.nextInt(); sc.nextLine(); String[] str1 = sc.nextLine().split(" "); String[] str2 = sc.nextLine().split(" "); String[] str3 = sc.nextLine().split(" "); for (int i = 0; i < n; i++) { map.put(str1[i], map.getOrDefault(str1[i], 0) + 1); map.put(str2[i], map.getOrDefault(str2[i], 0) + 1); map.put(str3[i], map.getOrDefault(str3[i], 0) + 1); } int sum1 = 0, sum2 = 0, sum3 = 0; for (int i = 0; i < n; i++) { if (map.get(str1[i]) == 1) { sum1 += 3; }else if(map.get(str1[i]) == 2) { sum1 += 1; } if(map.get(str2[i]) == 1) { sum2 += 3; }else if(map.get(str2[i]) == 2) { sum2 += 1; } if(map.get(str3[i]) == 1) { sum3 += 3; }else if(map.get(str3[i]) == 2) { sum3 += 1; } } System.out.println(sum1 + " " + sum2 + " " + sum3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
b6c1e3b63448cfc9179231da2fa75fbd
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class Solve { public static void main(String[] args){ Scanner sc = new Scanner(System.in); int count = Integer.parseInt(sc.nextLine()); for(int i = 0; i < count; i++){ System.out.println(howPoints(Integer.parseInt(sc.nextLine()), sc.nextLine(), sc.nextLine(), sc.nextLine())); } } public static String howPoints(int len, String first, String second, String third){ String[] firstLine = first.split(" "); String[] secondLine = second.split(" "); String[] thirdLine = third.split(" "); int[] points = new int[4]; HashMap<String, Integer> dict = new HashMap<>(); for(String i: firstLine){ dict.put("1" + i, 1); } for(String i: secondLine){ String fromFirst = "1" + i; if(dict.containsKey(fromFirst)) { dict.put("12" + i, dict.get(fromFirst) + 1); dict.remove(fromFirst); }else dict.put("2" + i, 1); } for(String i: thirdLine){ String fromFirst = "1" + i; String fromSecond = "2" + i; String fromBoth = "12" + i; if(dict.containsKey(fromFirst)) { dict.put("13" + i, dict.get(fromFirst) + 1); dict.remove(fromFirst); } else if(dict.containsKey(fromSecond)) { dict.put("23" + i, dict.get(fromSecond) + 1); dict.remove(fromSecond); }else if(dict.containsKey(fromBoth)){ dict.remove(fromBoth); }else dict.put("3" + i, 1); } for (Map.Entry<String, Integer> entry : dict.entrySet()) { if(entry.getValue() == 1) points[Integer.parseInt(entry.getKey().substring(0, 1))]+= 3; else{ points[Integer.parseInt(entry.getKey().substring(0,1))]++; points[Integer.parseInt(entry.getKey().substring(1, 2))]++; } } return "" + points[1] + " " + points[2] + " " + points[3]; } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
14f607d95c5b328e1ffa12ac5a18f596
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.Scanner; import java.util.*; public class distict { public static void main(String[] args) { Scanner sc=new Scanner(System.in); int t=sc.nextInt(); while(t>0) { int n=sc.nextInt(); HashSet<String> valid1 =new HashSet<>(); HashSet<String> valid2 =new HashSet<>(); HashSet<String> valid3 =new HashSet<>(); for(int i=0;i<n;i++) { valid1.add(sc.next()); } for(int i=0;i<n;i++) { String s2=sc.next(); valid2.add(s2); } for(int i=0;i<n;i++) { String s3=sc.next(); valid3.add(s3); } int ans1=0,ans2=0,ans3=0; for(String x : valid1) { if(valid3.contains(x) && valid2.contains(x) ) { } else if(valid2.contains(x) || valid3.contains(x)) { ans1+=1; } else if(!valid2.contains(x) && !valid3.contains(x)) { ans1+=3; } } for(String y : valid2) { if(valid1.contains(y) && valid3.contains(y) ) { } else if(valid1.contains(y) || valid3.contains(y)) { ans2+=1; } else if(!valid1.contains(y) && !valid3.contains(y)) { ans2+=3; } } for(String z : valid3) { if(valid1.contains(z) && valid2.contains(z) ) { } else if(valid1.contains(z) || valid2.contains(z)) { ans3+=1; } else if(!valid1.contains(z) && !valid2.contains(z)) { ans3+=3; } } System.out.print(ans1+" "+ans2+" "+ans3); System.out.println(); t--; } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
8824d93b8b7deb5ede706472088acd76
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; import java.lang.*; import java.util.Map; /** * * @author Vattikuti Rajesh */ public class SolutionA { public static void main(String r[]){ Scanner sc=new Scanner(System.in); int t=sc.nextInt(); while(t-->0){ int n=sc.nextInt(); String[] str1=new String[n]; String[] str2=new String[n]; String[] str3=new String[n]; for(int i=0;i<n;i++) str1[i]=sc.next(); for(int i=0;i<n;i++) str2[i]=sc.next(); for(int i=0;i<n;i++) str3[i]=sc.next(); HashMap<String,Integer> map=new HashMap<>(); for(int i=0;i<n;i++){ if(map.containsKey(str1[i])) map.put(str1[i],map.get(str1[i])+1); else map.put(str1[i],1); } for(int i=0;i<n;i++){ if(map.containsKey(str2[i])) map.put(str2[i],map.get(str2[i])+1); else map.put(str2[i],1); }for(int i=0;i<n;i++){ if(map.containsKey(str3[i])) map.put(str3[i],map.get(str3[i])+1); else map.put(str3[i],1); } int cnt1=0,cnt2=0,cnt3=0; for(int i=0;i<n;i++){ int x=map.get(str1[i]); if(x==1) cnt1+=3; if(x==2) cnt1+=1; } for(int i=0;i<n;i++){ int x=map.get(str2[i]); if(x==1) cnt2+=3; if(x==2) cnt2+=1; } for(int i=0;i<n;i++){ int x=map.get(str3[i]); if(x==1) cnt3+=3; if(x==2) cnt3+=1; } System.out.println(cnt1+" "+cnt2+" "+cnt3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
00a046fed502c4d14d23a104b17f7958
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; public class ProbC_2 { public static void main(String[] args) { FastScanner fs = new FastScanner(System.in); int t = fs.nextInt(); while(t-- > 0){ int n = fs.nextInt(); String[][] arr = new String[3][n]; for(int i=0;i<3;i++){ arr[i] = fs.nextArray(n); }; int[] abc = new int[3]; HashMap<String,Integer> hm = new HashMap<>(); for(String[] i: arr){ for(String j: i){ hm.putIfAbsent(j,0); hm.put(j,hm.get(j)+1); } } // System.out.println(hm); for(int i=0;i<3;i++){ for(int j=0;j<n;j++){ if(hm.get(arr[i][j]) == 1){ abc[i] += 3; } else if(hm.get(arr[i][j]) == 2){ abc[i] += 1; } } } System.out.println(abc[0]+" "+abc[1]+" "+abc[2]); } } static class FastScanner { private BufferedReader reader = null; private StringTokenizer tokenizer = null; public FastScanner(InputStream in) { reader = new BufferedReader(new InputStreamReader(in)); tokenizer = null; } public String next() { if (tokenizer == null || !tokenizer.hasMoreTokens()) { try { tokenizer = new StringTokenizer(reader.readLine()); } catch (IOException e) { throw new RuntimeException(e); } } return tokenizer.nextToken(); } public String nextLine() { if (tokenizer == null || !tokenizer.hasMoreTokens()) { try { return reader.readLine(); } catch (IOException e) { throw new RuntimeException(e); } } return tokenizer.nextToken("\n"); } public long nextLong() { return Long.parseLong(next()); } public int nextInt() { return Integer.parseInt(next()); } public double nextDouble() { return Double.parseDouble(next()); } public int[] nextIntArray(int n) { int[] a = new int[n]; for (int i = 0; i < n; i++) a[i] = nextInt(); return a; } public long[] nextLongArray(int n) { long[] a = new long[n]; for (int i = 0; i < n; i++) a[i] = nextLong(); return a; } public ArrayList<Integer> nextIntArrayList(int n) { ArrayList<Integer> a = new ArrayList<>(); for (int i = 0; i < n; i++) a.add(nextInt()); return a; } public String[] nextArray(int n) { String[] a = new String[n]; for (int i = 0; i < n; i++) a[i] = next(); return a; } public ArrayList<String> nextArrayList(int n) { ArrayList<String> a = new ArrayList<>(); for (int i = 0; i < n; i++) a.add(next()); return a; } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
dd050caef3354f11cd412c5d067912f9
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; public class C_Word_Game { public static void main(String args[]) throws IOException { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); while (t-- > 0) { int n=sc.nextInt(); String a[][]=new String[3][n]; HashMap<String,Integer> hmap = new HashMap<>(); int aa[]=new int[3]; for(int i=0;i<3;i++) { for(int j=0;j<n;j++) { a[i][j]=sc.next(); // int val = hmap.get(a[i][j]); // hmap.put(a[i][j],val+1 ); if(hmap.containsKey(a[i][j])) { hmap.put(a[i][j], hmap.get(a[i][j]) + 1); } else { hmap.put(a[i][j], 1); } } } for(int i=0;i<3;i++) { for(int j=0;j<n;j++) { if(hmap.get(a[i][j])==1) { aa[i]+=3; } else if(hmap.get(a[i][j])==2) { aa[i]+=1; } } } // String b[]=new String[n]; // String c[]=new String[n]; // ArrayList<String> aa=new ArrayList<>(); // ArrayList<String> bb=new ArrayList<>(); // ArrayList<String> cc=new ArrayList<>(); // int an=3*n; // int bn=3*n; // int cn=0; // for(int j=0;j<n;j++) // { // a[j]=sc.next(); // aa.add(a[j]); // } // for(int j=0;j<n;j++) // { // b[j]=sc.next(); // bb.add(b[j]); // } // for(int j=0;j<n;j++) // { // c[j]=sc.next(); // cc.add(c[j]); // } // if(aa.contains(c[j])==false && bb.contains(c[j])==false) // { // cn=cn+3; // if(aa.contains(b[j])==true) // { // an=an-2; // bn=bn-2; // } // } // else if(aa.contains(c[j])==true && bb.contains(c[j])==true){ // an=an-3; // bn=bn-3; // } // else{ // if(aa.contains(c[j])==true && bb.contains(c[j])==false) // { // an=an-2; // cn=cn+1; // } // else if(aa.contains(c[j])==false && bb.contains(c[j])==true) // { // bn=bn-2; // cn=cn+1; // } // // else // for(int j=0;j<n;j++) // { // if(bb.contains(a[j])==false && cc.contains(a[j])==false) // { // an=an+3; // } // else if(bb.contains(a[j])==true && cc.contains(a[j])==true) // { // an=an+0; // } // // else{ // // if(bb.contains(a[j])==false && cc.contains(a[j])==true) // // { // // bn=bn+1; // // } // } // } System.out.println(aa[0]+" "+aa[1]+" "+aa[2]); } sc.close(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
01534d6725fa1cfd99d8517959eaa250
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedOutputStream; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Arrays; import java.util.Collections; import java.util.HashMap; import java.util.StringTokenizer; import java.util.function.Supplier; import java.util.stream.Collectors; public class codeforces { //-----------PrintWriter for faster output--------------------------------- public static PrintWriter out; public static int cnt; //-----------MyScanner class for faster input---------- public static class MyScanner { BufferedReader br; StringTokenizer st; public MyScanner() { br = new BufferedReader(new InputStreamReader(System.in)); } String next() { while (st == null || !st.hasMoreElements()) { try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } long nextLong() { return Long.parseLong(next()); } double nextDouble() { return Double.parseDouble(next()); } String nextLine(){ String str = ""; try { str = br.readLine(); } catch (IOException e) { e.printStackTrace(); } return str; } } static boolean isPrime(int n) { // Corner cases if (n <= 1) return false; if (n <= 3) return true; // This is checked so that we can skip // middle five numbers in below loop if (n % 2 == 0 || n % 3 == 0) return false; for (int i = 5; i * i <= n; i = i + 6) if (n % i == 0 || n % (i + 2) == 0) return false; return true; } public static int reverseBits(int n) { int rev = 0; // traversing bits of 'n' // from the right while (n > 0) { // bitwise left shift // 'rev' by 1 rev <<= 1; // if current bit is '1' if ((int)(n & 1) == 1) rev ^= 1; // bitwise right shift //'n' by 1 n >>= 1; } // required number return rev; } public static void main(String[] args) { // TODO Auto-generated method stub MyScanner sc = new MyScanner(); out = new PrintWriter(new BufferedOutputStream(System.out)); StringBuilder sb = new StringBuilder(); int t=sc.nextInt(); while(t-->0) { int n=sc.nextInt(); String arr[]=new String[n]; String brr[]=new String[n]; String crr[]=new String[n]; int ans1=0,ans2=0,ans3=0; HashMap<String,Integer> x=new HashMap<String,Integer>(); for(int i=0;i<n;i++) { arr[i]=sc.next(); if(!x.containsKey(arr[i])) { x.put(arr[i],1); } else { x.put(arr[i], x.get(arr[i])+1); } } for(int i=0;i<n;i++) { brr[i]=sc.next(); if(!x.containsKey(brr[i])) { x.put(brr[i],1); } else { x.put(brr[i], x.get(brr[i])+1); } } for(int i=0;i<n;i++) { crr[i]=sc.next(); if(!x.containsKey(crr[i])) { x.put(crr[i],1); } else { x.put(crr[i], x.get(crr[i])+1); } } for(int i=0;i<n;i++) { if(x.get(arr[i])==1) { ans1=ans1+3; } if(x.get(arr[i])==2) { ans1++; } } for(int i=0;i<n;i++) { if(x.get(brr[i])==1) { ans2=ans2+3; } if(x.get(brr[i])==2) { ans2++; } } for(int i=0;i<n;i++) { if(x.get(crr[i])==1) { ans3=ans3+3; } if(x.get(crr[i])==2) { ans3++; } } out.println(ans1+" "+ans2+" "+ans3); } out.close(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
12e839f17dbfe1e81ecbb8c672d86c60
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; public class Rough { static ArrayList<Long> ar=new ArrayList<>(); static long an=998244353; //static long an2=(long)1E18; public static void main(String[] args) throws Exception { Scanner s = new Scanner(System.in); PrintWriter pw = new PrintWriter(System.out); int tc = s.nextInt(); for (int t = 1; t <= tc; t++) { int n=s.nextInt(); s.nextLine(); ArrayList<String> ar=new ArrayList<>(); ArrayList<String> ar1=new ArrayList<>(); ArrayList<String> ar2=new ArrayList<>(); HashMap<String,Integer> hm=new HashMap<>(); for(int i=0;i<n;i++) { String in=s.next(); ar.add(in); maping(in,1,hm); } for(int i=0;i<n;i++) { String in=s.next(); ar1.add(in); maping(in,1,hm); } for(int i=0;i<n;i++) { String in=s.next(); ar2.add(in); maping(in,1,hm); } int cnt=0; int cnt1=0; int cnt2=0; for(int i=0;i<n;i++) { String in=ar.get(i); if(hm.get(in)==2)cnt++; else if(hm.get(in)==1)cnt+=3; } for(int i=0;i<n;i++) { String in=ar1.get(i); if(hm.get(in)==2)cnt1++; else if(hm.get(in)==1)cnt1+=3; }for(int i=0;i<n;i++) { String in=ar2.get(i); if(hm.get(in)==2)cnt2++; else if(hm.get(in)==1)cnt2+=3; } pw.println(cnt+" "+cnt1+" "+cnt2); } pw.close(); } static boolean ispalin(String in) { StringBuilder sb = new StringBuilder(in); if (sb.reverse().toString().equals(in)) return true; else return false; } static void maping(String key, int val, HashMap<String, Integer> hm) { if (hm.containsKey(key)) { int valu = hm.get(key) + 1; hm.put(key, valu); } else hm.put(key, val); } static final Random ran = new Random(); static void sort(int[] ar) { int n = ar.length; for (int i = 0; i < n; i++) { int doer = ran.nextInt(n), temp = ar[doer]; ar[doer] = ar[i]; ar[i] = temp; } Arrays.sort(ar); } static void sort(long[] ar) { int n = ar.length; for (int i = 0; i < n; i++) { int doer = ran.nextInt(n); long temp = ar[doer]; ar[doer] = ar[i]; ar[i] = temp; } Arrays.sort(ar); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
782e2c614fbf672129078e70b5dd731b
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class C_Word_Game { public static void main(String[] args) { Scanner input=new Scanner(System.in); int testCase=input.nextInt(); for(int i=0;i<testCase;i++){ int wordsNumber=input.nextInt(); Set<String> player1=new HashSet(); Set<String>player2=new HashSet(); Set<String>player3=new HashSet(); int first=0,second=0,third=0; for(int w=0;w<3;w++){ for(int g=0;g<wordsNumber;g++){ if(w==0){ player1.add(input.next()); } else if(w==1){ player2.add(input.next()); } else { player3.add(input.next()); } } } for(String word:player1){ if(player2.contains(word) && player3.contains(word)){ player2.remove(word); player3.remove(word); } else if(player2.contains(word)){ player2.remove(word); first++; second++; } else if(player3.contains(word)){ first++; third++; player3.remove(word); } else first+=3; } for(String word:player2){ if(player3.contains(word)){ second++; third++; player3.remove(word); } else second+=3; } third+=player3.size()*3; System.out.println(first+" "+second+" "+third); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
28583809e736a025dbca898aab094955
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class threeQ { static class Pair{ int index; int count; Pair(int index, int count){ this.index=index; this.count=count; } } public static void main(String[] args) { Scanner sc =new Scanner(System.in); int t=sc.nextInt(); while(t--!=0) { int n=sc.nextInt(); sc.nextLine(); HashMap<String, Pair>map= new HashMap<>(); String s1=sc.nextLine(); String s2=sc.nextLine(); String s3=sc.nextLine(); String[] a1=s1.split(" "); String[] a2=s2.split(" "); String[] a3=s3.split(" "); for(int i=0;i<a1.length;i++) { if(map.containsKey(a1[i])) { int l=map.get(a1[i]).index ; int r=map.get(a1[i]).count; map.put(a1[i] , new Pair(l+3,r+1)); }else { map.put(a1[i], new Pair(3,1)); } if(map.containsKey(a2[i])) { int l=map.get(a2[i]).index ; int r=map.get(a2[i]).count; map.put(a2[i], new Pair(l+5,r+1)); }else { map.put(a2[i], new Pair(5,1)); } if(map.containsKey(a3[i])) { int l=map.get(a3[i]).index ; int r=map.get(a3[i]).count; map.put(a3[i], new Pair(l+7,r+1)); }else { map.put(a3[i], new Pair(7,1)); } } int[] ans= new int[3]; for(Map.Entry<String, Pair> entry:map.entrySet()) { if(entry.getValue().count==1) { int m=entry.getValue().index; if(m==3) { ans[0]+=3; }else if(m==5) { ans[1]+=3; }else { ans[2]+=3; } } else if(entry.getValue().count==2) { int m=entry.getValue().index; if(m==8) { ans[0]+=1; ans[1]+=1; }else if(m==12) { ans[1]+=1; ans[2]+=1; }else if(m==10){ ans[2]+=1; ans[0]+=1; } } } System.out.println(ans[0]+" "+ans[1]+" "+ans[2]); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
7db3a489a87d37f01bc3827d884c9a59
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.lang.reflect.Array; import java.util.*; public class Main { static class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new BufferedReader( new InputStreamReader(System.in)); } String next() { while (st == null || !st.hasMoreElements()) { try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } long nextLong() { return Long.parseLong(next()); } double nextDouble() { return Double.parseDouble(next()); } String nextLine() { String str = ""; try { if(st.hasMoreTokens()){ str = st.nextToken("\n"); } else{ str = br.readLine(); } } catch (IOException e) { e.printStackTrace(); } return str; } } public static void main(String[] args) { FastReader sc=new FastReader(); int tc=sc.nextInt(); while(tc-->0) { int n=sc.nextInt(); HashSet<String> s1=new HashSet<>(); HashSet<String> s2=new HashSet<>(); HashSet<String> s3=new HashSet<>(); for(int i=0;i<n;i++) { s1.add(sc.next()); } for(int i=0;i<n;i++) { s2.add(sc.next()); } for(int i=0;i<n;i++) { s3.add(sc.next()); } int p1=0,p2=0,p3=0; for(String s:s1) { if(s2.contains(s)&&s3.contains(s)) {} else if(!s2.contains(s)&& !s3.contains(s)) { p1+=3; } else { p1+=1; } } for(String s:s2) { if(s1.contains(s)&&s3.contains(s)) {} else if(!s1.contains(s)&& !s3.contains(s)) { p2+=3; } else { p2+=1; } } for(String s:s3) { if(s2.contains(s)&&s1.contains(s)) {} else if(!s2.contains(s)&& !s1.contains(s)) { p3+=3; } else { p3+=1; } } System.out.println(p1+" "+p2+" "+p3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
cba79b71e2252ed6fabcebeead82022c
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Main { public static void main(String[] args) { Scanner sc=new Scanner(System.in); int t=sc.nextInt(); for(int i=0;i<t;i++) { int n=sc.nextInt(); HashMap<String,ArrayList<Integer>> hm=new HashMap<>(); String arr[][]=new String[3][n]; for(int j=0;j<3;j++) { for(int k=0;k<n;k++) { arr[j][k]=sc.next(); if(hm.containsKey(arr[j][k])) { ArrayList<Integer> temp=hm.get(arr[j][k]); temp.add(j); hm.put(arr[j][k],temp); } else{ ArrayList<Integer> temp=new ArrayList<>(); temp.add(j); hm.put(arr[j][k],temp); } } } int counta=0; int countb=0; int countc=0; for(String str : hm.keySet()) { if(hm.get(str).size()==2) { for(int num: hm.get(str)) { if(num==0) { counta++; } if(num==1) { countb++; } if(num==2) { countc++; } } } else if(hm.get(str).size()==1) { int num=hm.get(str).get(0); if(num==0) { counta+=3; } if(num==1) { countb+=3; } if(num==2) { countc+=3; } } } System.out.println(counta+ " "+countb + " "+countc); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
0b0b689548cb090e48ea0d115c9a4e68
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.sql.SQLOutput; import java.util.*; public class Algorithms { static FastScanner scan = new FastScanner(); static Scanner scanner = new Scanner(System.in); public static void main(String[] args) { int t = scan.nextInt(); for (int i = 1; i <= t; i++) { solve(); } } static void solve() { int[] ans = new int[4]; int n = scan.nextInt(); String[] a = new String[n]; String[] b = new String[n]; String[] c = new String[n]; Map<String, Integer> map = new HashMap<>(); for (int i = 0; i < n; i++) { a[i] = scan.next(); map.put(a[i], map.getOrDefault(a[i], 0) + 1); } for (int i = 0; i < n; i++) { b[i]= scan.next(); map.put(b[i], map.getOrDefault(b[i], 0) + 1); } for (int i = 0; i < n; i++) { c[i]= scan.next(); map.put(c[i], map.getOrDefault(c[i], 0) + 1); } for (int i = 0; i < n; i++) { if (map.get(a[i]) == 1) { ans[1] += 3; } else if (map.get(a[i]) == 2) { ans[1]++; } if (map.get(b[i]) == 1){ ans[2] += 3; } else if (map.get(b[i]) == 2) { ans[2]++; } if (map.get(c[i]) == 1) { ans[3] += 3; } else if (map.get(c[i]) == 2){ ans[3]++; } } System.out.println(ans[1] + " "+ans[2]+ " "+ ans[3]); } private static int countDigits(long l) { if (l >= 1000000000000000000L) return 19; if (l >= 100000000000000000L) return 18; if (l >= 10000000000000000L) return 17; if (l >= 1000000000000000L) return 16; if (l >= 100000000000000L) return 15; if (l >= 10000000000000L) return 14; if (l >= 1000000000000L) return 13; if (l >= 100000000000L) return 12; if (l >= 10000000000L) return 11; if (l >= 1000000000L) return 10; if (l >= 100000000L) return 9; if (l >= 10000000L) return 8; if (l >= 1000000L) return 7; if (l >= 100000L) return 6; if (l >= 10000L) return 5; if (l >= 1000L) return 4; if (l >= 100L) return 3; if (l >= 10L) return 2; return 1; } static boolean isSorted(int[] arr) { for (int i = 1; i < arr.length; i++) { if (arr[i - 1] > arr[i]) return false; } return true; } static long gcd(long A, long B) { if (B == 0) return A; return gcd(B, A % B); } static boolean isInteger(int n) { return Math.sqrt(n) % 1 == 0; } static class FastScanner { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); StringTokenizer st = new StringTokenizer(""); String next() { while (!st.hasMoreTokens()) try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } int[] readArray(int n) { int[] a = new int[n]; for (int i = 0; i < n; i++) a[i] = nextInt(); return a; } String[] readStringArray(int n) { String[] arr = new String[n]; for (int i = 0; i < n; i++) arr[i] = next(); return arr; } long nextLong() { return Long.parseLong(next()); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
1c798a69be09205bf9e24d32a5eb8010
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; public class Main { static Reader r = new Reader(); static StringBuilder sb = new StringBuilder(); public static void main(String args[]) throws IOException { int t = r.readInt(); while(t-->0){ solve(); } System.out.println(sb); } static void solve() throws IOException{ int n = r.readInt(); String[] s1 = r.readLine().split(" "); String[] s2 = r.readLine().split(" "); String[] s3 = r.readLine().split(" "); int[][][] cnt = new int[26][26][26]; int[] score = new int[3]; for(String s: s1) cnt[s.charAt(0)-'a'][s.charAt(1)-'a'][s.charAt(2)-'a']++; for(String s: s2) cnt[s.charAt(0)-'a'][s.charAt(1)-'a'][s.charAt(2)-'a']++; for(String s: s3) cnt[s.charAt(0)-'a'][s.charAt(1)-'a'][s.charAt(2)-'a']++; for(String s: s1){ if(cnt[s.charAt(0)-'a'][s.charAt(1)-'a'][s.charAt(2)-'a']==1) score[0]+=3; else if(cnt[s.charAt(0)-'a'][s.charAt(1)-'a'][s.charAt(2)-'a']==2) score[0]+=1; } for(String s: s2){ if(cnt[s.charAt(0)-'a'][s.charAt(1)-'a'][s.charAt(2)-'a']==1) score[1]+=3; else if(cnt[s.charAt(0)-'a'][s.charAt(1)-'a'][s.charAt(2)-'a']==2) score[1]+=1; } for(String s: s3){ if(cnt[s.charAt(0)-'a'][s.charAt(1)-'a'][s.charAt(2)-'a']==1) score[2]+=3; else if(cnt[s.charAt(0)-'a'][s.charAt(1)-'a'][s.charAt(2)-'a']==2) score[2]+=1; } sb.append(score[0]).append(" ").append(score[1]).append(" ").append(score[2]).append("\n"); } } class Reader { final private int BUFFER_SIZE = 1 << 16; private DataInputStream din; private byte[] buffer; private int bufferPointer, bytesRead; public Reader() { din = new DataInputStream(System.in); buffer = new byte[BUFFER_SIZE]; bufferPointer = bytesRead = 0; } public String readLine() throws IOException { byte[] buf = new byte[5000]; // line length int cnt = 0, c; while((c=read())!=-1){ if(c=='\n'){ if(cnt!=0) break; else continue; } buf[cnt++] = (byte)c; } return new String(buf, 0, cnt); } public int readInt() throws IOException { int ret = 0; byte c = read(); while(c <= ' '){ c = read();} boolean neg = (c == '-'); if(neg) c = read(); do{ ret = (ret<<3) + (ret<<1) + c - '0'; } while ((c = read()) >= '0' && c <= '9'); return neg ? -ret : ret; } public long readLong() throws IOException { long ret = 0; byte c = read(); while(c <= ' '){ c = read();} boolean neg = (c == '-'); if(neg) c = read(); do{ ret = (ret<<3) + (ret<<1) + c - '0'; } while ((c = read()) >= '0' && c <= '9'); return neg ? -ret : ret; } private void fillBuffer() throws IOException { bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE); if(bytesRead == -1) buffer[0] = -1; } private byte read() throws IOException { if(bufferPointer == bytesRead) fillBuffer(); return buffer[bufferPointer++]; } public void close() throws IOException { if(din==null) return; din.close(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
2fbe5ea00d5f12cc9be0883d48d65512
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedWriter; import java.io.IOException; import java.io.OutputStreamWriter; import java.util.*; public class Main { public static void main(String[] args) throws IOException{ BufferedWriter bw=new BufferedWriter(new OutputStreamWriter(System.out)); Scanner sc=new Scanner(System.in); int t=sc.nextInt(); while(t-->0){ List<String> list1=new ArrayList<>(); List<String> list2=new ArrayList<>(); List<String> list3=new ArrayList<>(); Map<String,Integer> map=new HashMap<>(); int n=sc.nextInt(); for(int i=0;i<n;i++){ String temp= sc.next(); list1.add(temp); map.put(temp,map.getOrDefault(temp,0)+1); } for(int i=0;i<n;i++){ String temp= sc.next(); list2.add(temp); map.put(temp,map.getOrDefault(temp,0)+1); } for(int i=0;i<n;i++){ String temp= sc.next(); list3.add(temp); map.put(temp,map.getOrDefault(temp,0)+1); } int ans1=0; int ans2=0; int ans3=0; for(int i=0;i<n;i++){ String temp=list1.get(i); int count=map.get(temp); // if(list1.contains(temp)){ // count++; // } // if(list2.contains(temp)){ // count++; // } // if(list3.contains(temp)){ // count++; // } if(count==2){ ans1+=1; } else if(count==1){ ans1+=3; } } for(int i=0;i<n;i++){ String temp=list2.get(i); int count=map.get(temp); // if(list1.contains(temp)){ // count++; // } // if(list2.contains(temp)){ // count++; // } // if(list3.contains(temp)){ // count++; // } if(count==2){ ans2+=1; } else if(count==1){ ans2+=3; } } for(int i=0;i<n;i++){ String temp=list3.get(i); int count=map.get(temp); // if(list1.contains(temp)){ // count++; // } // if(list2.contains(temp)){ // count++; // } // if(list3.contains(temp)){ // count++; // } if(count==2){ ans3+=1; } else if(count==1){ ans3+=3; } } System.out.println(ans1+" "+ans2+" "+ans3); } bw.flush(); } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
218a2e5773060a2a0541fcea1732b812
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.*; import java.util.*; public class R817C { public static void main(String[] args) { Scanner scan = new Scanner(System.in); int t = scan.nextInt(); while(t-->0){ int n = scan.nextInt(); scan.nextLine(); HashMap<String, Integer> map = new HashMap<>(); String[] a = scan.nextLine().split(" "); String[] b = scan.nextLine().split(" "); String[] c = scan.nextLine().split(" "); for(int i = 0;i<n;i++){ map.put(a[i],map.getOrDefault(a[i],0)+1); map.put(b[i],map.getOrDefault(b[i],0)+1); map.put(c[i],map.getOrDefault(c[i],0)+1); } int[] points = new int[3]; int[] vals = {0,3,1,0}; for(int i = 0;i<n;i++){ points[0] += vals[map.get(a[i])]; points[1] += vals[map.get(b[i])]; points[2] += vals[map.get(c[i])]; } System.out.println(points[0]+" "+points[1]+" "+points[2]); } } static class JS { public int BS = 1 << 16; public char NC = (char) 0; byte[] buf = new byte[BS]; int bId = 0, size = 0; char c = NC; double num = 1; BufferedInputStream in; public JS() { in = new BufferedInputStream(System.in, BS); } public JS(String s) throws FileNotFoundException { in = new BufferedInputStream(new FileInputStream(new File(s)), BS); } public char nextChar() { while (bId == size) { try { size = in.read(buf); } catch (Exception e) { return NC; } if (size == -1) return NC; bId = 0; } return (char) buf[bId++]; } public int nextInt() { return (int) nextLong(); } public long nextLong() { num = 1; boolean neg = false; if (c == NC) c = nextChar(); for (; (c < '0' || c > '9'); c = nextChar()) { if (c == '-') neg = true; } long res = 0; for (; c >= '0' && c <= '9'; c = nextChar()) { res = (res << 3) + (res << 1) + c - '0'; num *= 10; } return neg ? -res : res; } public double nextDouble() { double cur = nextLong(); return c != '.' ? cur : cur + nextLong() / num; } public String next() { StringBuilder res = new StringBuilder(); while (c <= 32) c = nextChar(); while (c > 32) { res.append(c); c = nextChar(); } return res.toString(); } public String nextLine() { StringBuilder res = new StringBuilder(); while (c <= 32) c = nextChar(); while (c != '\n') { res.append(c); c = nextChar(); } return res.toString(); } public boolean hasNext() { if (c > 32) return true; while (true) { c = nextChar(); if (c == NC) return false; else if (c > 32) return true; } } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
d7e1912a68eb37fbbddd3b2ef3f39548
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.util.*; public class Main { public static void main(String args[]) { Scanner in = new Scanner(System.in); int t = in.nextInt(); for(int p=1;p<=t;p++) { int n = in.nextInt(); String s[][] = new String[3][n]; for(int i=0;i<3;i++) { for(int j=0;j<n;j++) { s[i][j] = in.next(); } } int x=0,y=0,z=0; HashMap<String,Integer> map1 = new HashMap<>(); HashMap<String,Integer> map2 = new HashMap<>(); HashMap<String,Integer> map3 = new HashMap<>(); for(int i=0;i<n;i++) map1.put(s[0][i],1); for(int i=0;i<n;i++) map2.put(s[1][i],1); for(int i=0;i<n;i++) map3.put(s[2][i],1); for(int i=0;i<n;i++) { if(map1.containsKey(s[0][i]) && map2.containsKey(s[0][i]) && (map3.containsKey(s[0][i]))) {} else if(map1.containsKey(s[0][i]) && map2.containsKey(s[0][i]) && (!map3.containsKey(s[0][i]))) { x++; } else if(map1.containsKey(s[0][i]) && !map2.containsKey(s[0][i]) && (map3.containsKey(s[0][i]))) { x++; } else if(map1.containsKey(s[0][i])) x+=3; } for(int i=0;i<n;i++) { if(map1.containsKey(s[1][i]) && map2.containsKey(s[1][i]) && (map3.containsKey(s[1][i]))) {} else if(map1.containsKey(s[1][i]) && map2.containsKey(s[1][i]) && (!map3.containsKey(s[1][i]))) { y++; } else if(!map1.containsKey(s[1][i]) && map2.containsKey(s[1][i]) && (map3.containsKey(s[1][i]))) { y++; } else if(map2.containsKey(s[1][i])) y+=3; } for(int i=0;i<n;i++) { if(map1.containsKey(s[2][i]) && map2.containsKey(s[2][i]) && (map3.containsKey(s[2][i]))) {} else if(!map1.containsKey(s[2][i]) && map2.containsKey(s[2][i]) && (map3.containsKey(s[2][i]))) { z++; } else if(map1.containsKey(s[2][i]) && !map2.containsKey(s[2][i]) && (map3.containsKey(s[2][i]))) { z++; } else if(map3.containsKey(s[2][i])) z+=3; } System.out.println(x+" "+y+" "+z); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output
PASSED
15d7877467aaf1c34d7c6136381142a3
train_109.jsonl
1661871000
Three guys play a game: first, each person writes down $$$n$$$ distinct words of length $$$3$$$. Then, they total up the number of points as follows: if a word was written by one person — that person gets 3 points, if a word was written by two people — each of the two gets 1 point, if a word was written by all — nobody gets any points. In the end, how many points does each player have?
256 megabytes
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.HashSet; import java.util.StringTokenizer; // https://codeforces.com/contest/1722/problem/C public class CF1722C { static class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new BufferedReader( new InputStreamReader(System.in)); } String next() { while (st == null || !st.hasMoreElements()) { try { st = new StringTokenizer(br.readLine()); } catch (IOException e) { e.printStackTrace(); } } return st.nextToken(); } int nextInt() { return Integer.parseInt(next()); } long nextLong() { return Long.parseLong(next()); } double nextDouble() { return Double.parseDouble(next()); } String nextLine() { String str = ""; try { if (st.hasMoreTokens()) { str = st.nextToken("\n"); } else { str = br.readLine(); } } catch (IOException e) { e.printStackTrace(); } return str; } } public static void main(String[] args) { FastReader sc = new FastReader(); int t = sc.nextInt(); while(t-->0) { int n = sc.nextInt(); HashSet<String> player1 = new HashSet<>(); HashSet<String> player2 = new HashSet<>(); HashSet<String> player3 = new HashSet<>(); for (int i = 0; i < n; i++) player1.add(sc.next()); for (int i = 0; i < n; i++) player2.add(sc.next()); for (int i = 0; i < n; i++) player3.add(sc.next()); int Points1 = 0; int Points2 = 0; int Points3 = 0; for (String str : player1) { if(player2.contains(str) && player3.contains(str)); else if(player2.contains(str) || player3.contains(str)) Points1++; else Points1 += 3; } for (String str : player2) { if(player1.contains(str) && player3.contains(str)); else if(player1.contains(str) || player3.contains(str)) Points2++; else Points2 += 3; } for (String str : player3) { if(player1.contains(str) && player2.contains(str)); else if(player1.contains(str) || player2.contains(str)) Points3++; else Points3 +=3; } System.out.printf("%d %d %d \n", Points1, Points2, Points3); } } }
Java
["3\n\n1\n\nabc\n\ndef\n\nabc\n\n3\n\norz for qaq\n\nqaq orz for\n\ncod for ces\n\n5\n\niat roc hem ica lly\n\nbac ter iol ogi sts\n\nbac roc lly iol iat"]
1 second
["1 3 1 \n2 2 6 \n9 11 5"]
NoteIn the first test case: The word $$$\texttt{abc}$$$ was written by the first and third guys — they each get $$$1$$$ point. The word $$$\texttt{def}$$$ was written by the second guy only — he gets $$$3$$$ points.
Java 11
standard input
[ "data structures", "implementation" ]
f8a89510fefbbc8e5698efe8a0c30927
The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 100$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 1000$$$) — the number of words written by each person. The following three lines each contain $$$n$$$ distinct strings — the words written by each person. Each string consists of $$$3$$$ lowercase English characters.
800
For each test case, output three space-separated integers — the number of points each of the three guys earned. You should output the answers in the same order as the input; the $$$i$$$-th integer should be the number of points earned by the $$$i$$$-th guy.
standard output