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minimum-operations-to-reduce-x-to-zero | Change Your Perspective | JAVA Explanation | change-your-perspective-java-explanation-5phd | Logic\nInitially, this question might look like a DP problem: pick either left or right recursively and collect the number of operations along the way. A brute | ciote | NORMAL | 2022-06-11T01:26:17.092317+00:00 | 2022-06-11T08:18:42.701216+00:00 | 18,240 | false | ### Logic\nInitially, this question might look like a DP problem: pick either left or right recursively and collect the number of operations along the way. A brute force approach would result in an `O(2^n)` complexity which isn\'t great. Memoization would improve this but we\'ll exceed the memory limit as I\'ve tested.... | 687 | 2 | ['Two Pointers', 'Java'] | 53 |
minimum-operations-to-reduce-x-to-zero | [Java] Detailed Explanation - O(N) Prefix Sum/Map - Longest Target Sub-Array | java-detailed-explanation-on-prefix-summ-hdew | Key Notes:\n- We could use dfs+memo or BFS, but they are too slow and will TLE (?)\n- If it exists an answer, then it means we have a subarray in the middle of | frankkkkk | NORMAL | 2020-11-15T04:01:47.274207+00:00 | 2020-11-15T04:57:20.483673+00:00 | 24,339 | false | **Key Notes:**\n- We could use dfs+memo or BFS, but they are too slow and will TLE (?)\n- If it exists an answer, then it means we have **a subarray in the middle of original array whose sum is == totalSum - x**\n- If we want to minimize our operations, then we should **maximize the length of the middle subarray.**\n\t... | 492 | 5 | [] | 32 |
minimum-operations-to-reduce-x-to-zero | Are you stuck ? once read this . logic explained clearly | easy-to-understand | are-you-stuck-once-read-this-logic-expla-ugx7 | so , the problem is saying that we can remove either leftmost or rightmost element and we have to remove them in such a way that \n1.remove minimum number of el | kevaljoshi2312 | NORMAL | 2021-02-24T14:04:21.056506+00:00 | 2021-02-24T14:04:21.056548+00:00 | 13,070 | false | so , the problem is saying that we can remove either leftmost or rightmost element and we have to remove them in such a way that \n1.remove minimum number of elements and\n2. sum of all removed element is X \n\nNow main point is that if successfully remove elements such that sum of removed elements is X , then \n1. sum... | 326 | 1 | ['C', 'C++'] | 34 |
minimum-operations-to-reduce-x-to-zero | ✅ [C++/Python] Simple Solution w/ Explanation | Sliding Window | cpython-simple-solution-w-explanation-sl-q7ra | Sometimes, converting a problem into some other familiar one helps a lot. This question is one of them.\nLet me state a different problem, and your task is to r | r0gue_shinobi | NORMAL | 2022-06-11T01:11:30.684302+00:00 | 2022-06-11T02:56:41.180591+00:00 | 15,310 | false | Sometimes, converting a problem into some other familiar one helps a lot. This question is one of them.\nLet me state a different problem, and your task is to relate how solving this problem will help in solving the actual one.\n> Given an array containing integers, your task is to find the length of the longest subarr... | 207 | 1 | ['Greedy', 'C', 'Sliding Window', 'Python', 'Python3'] | 15 |
minimum-operations-to-reduce-x-to-zero | ✅ 96.51% Sliding Window | 9651-sliding-window-by-vanamsen-3lh5 | Comprehensive Guide to Solving "Minimum Operations to Reduce X to Zero"\n\n## Introduction & Problem Statement\n\nGiven an integer array nums and an integer x, | vanAmsen | NORMAL | 2023-09-20T00:12:02.046844+00:00 | 2023-09-20T02:02:46.884474+00:00 | 24,536 | false | # Comprehensive Guide to Solving "Minimum Operations to Reduce X to Zero"\n\n## Introduction & Problem Statement\n\nGiven an integer array `nums` and an integer `x`, the task is to find the minimum number of operations to reduce `x` to exactly 0 by removing either the leftmost or rightmost element from the array `nums`... | 159 | 12 | ['Sliding Window', 'PHP', 'Prefix Sum', 'C++', 'Java', 'Go', 'Python3', 'Rust', 'JavaScript', 'C#'] | 21 |
minimum-operations-to-reduce-x-to-zero | C# Sliding window O(n) Time O(1) Space | c-sliding-window-on-time-o1-space-by-leo-y5zf | This problem is equivalent to finding the longest subarray whose sum is == totalSum - x\n\n\npublic class Solution\n{\n public int MinOperations(int[] nums, | leoooooo | NORMAL | 2020-11-15T04:07:14.553530+00:00 | 2020-11-15T04:36:47.527931+00:00 | 7,352 | false | **This problem is equivalent to finding the longest subarray whose sum is == totalSum - x**\n\n```\npublic class Solution\n{\n public int MinOperations(int[] nums, int x)\n {\n int sum = nums.Sum() - x;\n if(sum < 0) return -1;\n if(sum == 0) return nums.Length;\n int start = 0, cur = ... | 137 | 1 | [] | 17 |
minimum-operations-to-reduce-x-to-zero | Two Sum vs. Hash Map | two-sum-vs-hash-map-by-votrubac-z7hf | Started solving this problem using DP, but then realized that the constraints are too large.\n\nThen, I realized that, to reach x, we will take l numbers from t | votrubac | NORMAL | 2020-11-15T04:04:47.654907+00:00 | 2022-06-11T21:51:33.324811+00:00 | 13,154 | false | Started solving this problem using DP, but then realized that the constraints are too large.\n\nThen, I realized that, to reach `x`, we will take `l` numbers from the left, and `r` numbers from the right. We just need to find `min(l + r)`.\n\n#### Approach 1: Hash Map\nAs you count the sum of the first `l` numbers, you... | 121 | 4 | ['C'] | 21 |
minimum-operations-to-reduce-x-to-zero | [Python] O(n) solution, using cumulative sums | python-on-solution-using-cumulative-sums-1lfl | We can reformulate this problem: we need to choose several values from the beginning and several values from end, such that sum of this numbers is equal to x. I | dbabichev | NORMAL | 2021-01-14T08:47:21.066085+00:00 | 2021-02-26T12:46:17.645169+00:00 | 5,850 | false | We can reformulate this problem: we need to choose several values from the beginning and several values from end, such that sum of this numbers is equal to `x`. It is equivalent to finding some contiguous subarray, such that it has sum of elements equal to `sum(nums) - x`, which has the biggest length. In this way prob... | 103 | 17 | [] | 6 |
minimum-operations-to-reduce-x-to-zero | C++ | Sliding Window | Easy Solution | c-sliding-window-easy-solution-by-_panka-yitw | If helpful do upvote\nThanks\n\n\nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n int total=0, n=nums.size();\n for | _pankajMahtolia | NORMAL | 2020-11-17T09:13:35.809490+00:00 | 2020-11-17T09:13:35.809522+00:00 | 5,522 | false | **If helpful do upvote\nThanks**\n\n```\nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n int total=0, n=nums.size();\n for(auto i:nums) total+=i;\n if(x>total) return -1;\n int left=0,right=0, curr=0, ans=-1;\n for(; right<n;right++){\n curr+=... | 70 | 8 | [] | 4 |
minimum-operations-to-reduce-x-to-zero | 🚀95.97% || Two Pointers - Sliding Window || Commented Code🚀 | 9597-two-pointers-sliding-window-comment-nkkz | Porblem Description\nGiven an array of integers, nums, and an integer x. Each element in nums can be subtracted from x. The goal is to reduce x to exactly 0 usi | MohamedMamdouh20 | NORMAL | 2023-09-20T00:55:43.092683+00:00 | 2023-09-20T01:23:51.483831+00:00 | 8,033 | false | # Porblem Description\nGiven an array of integers, `nums`, and an integer `x`. Each element in `nums` can be subtracted from x. The **goal** is to reduce `x` to exactly `0` using a **minimum** number of operations.\n\nIn each **operation**, you can choose to **remove** either the `leftmost` or the `rightmost` element f... | 67 | 4 | ['Array', 'Two Pointers', 'Sliding Window', 'Python', 'C++', 'Java', 'Python3'] | 14 |
minimum-operations-to-reduce-x-to-zero | How we think about a solution - O(n) time, O(1) space - Python, JavaScript, Java, C++ | how-we-think-about-a-solution-on-time-o1-ymou | Welcome to my article. Before starting the article, why do I have to get multiple downvotes for a miniute every day? That is obviously deliberate downvotes. I c | niits | NORMAL | 2023-09-20T01:58:22.412434+00:00 | 2023-09-23T16:39:56.080961+00:00 | 2,847 | false | Welcome to my article. Before starting the article, why do I have to get multiple downvotes for a miniute every day? That is obviously deliberate downvotes. I can tell who is doing it. Please show your respect to others! Thanks.\n\n# Intuition\nTry to find target number with sum(nums) - x which is `unnecessary numbers`... | 48 | 6 | ['C++', 'Java', 'Python3', 'JavaScript'] | 5 |
minimum-operations-to-reduce-x-to-zero | C++ | 2 Approaches | c-2-approaches-by-datnguyen2k3-ei91 | Approach 1: Hash map, prefix sum, two sum\n\t- Idea: + create hash map satisfy mapLeft[prefix sum] = i, i is last index in prefix sum\n\t\t\t+ brute force from | datnguyen2k3 | NORMAL | 2022-06-11T01:18:16.295147+00:00 | 2022-10-28T05:46:54.158741+00:00 | 6,989 | false | Approach 1: Hash map, prefix sum, two sum\n\t- Idea: + create hash map satisfy mapLeft[prefix sum] = i, i is last index in prefix sum\n\t\t\t+ brute force from last index in array to first index and create suffix sum, find i satisfy mapLeft[x - suffix sum] > 0 \n\t\t\t => that\'s mean prefix sum + suffix sum = x, a... | 44 | 1 | ['C', 'Sliding Window', 'Prefix Sum'] | 3 |
minimum-operations-to-reduce-x-to-zero | [Python3] O(n) Time O(1) space solution | python3-on-time-o1-space-solution-by-red-19ve | The idea is to find the length of the maximum length subarray that has a sum equal to sum(nums) - x. This makes sense because after removing the optimal element | redsand | NORMAL | 2021-01-14T14:43:00.556612+00:00 | 2021-01-15T14:28:43.900817+00:00 | 2,055 | false | The idea is to find the length of the maximum length subarray that has a sum equal to ```sum(nums) - x```. This makes sense because after removing the optimal elements from the ends, this is what we will be left with. So instead of removing elements, add elements to this subarray in a sliding window fashion and optimiz... | 37 | 0 | [] | 6 |
minimum-operations-to-reduce-x-to-zero | Minimum Operations to Reduce X to Zero | JS | Explanation | beats 100% | minimum-operations-to-reduce-x-to-zero-j-5bfv | Idea:\n\nThis problem is tasking us to essentially find when the sum of the starting and ending subarrays of nums is equal to x. Put another way, it\'s asking u | sgallivan | NORMAL | 2021-01-15T00:26:36.699248+00:00 | 2021-01-15T00:26:36.699277+00:00 | 1,276 | false | ***Idea:***\n\nThis problem is tasking us to essentially find when the sum of the starting and ending subarrays of **nums** is equal to **x**. Put another way, it\'s asking us to find when any subarray of consecutive elements in **nums** is equal to the sum of all elements in **nums** minus **x**.\n```\n ... | 33 | 0 | ['JavaScript'] | 1 |
minimum-operations-to-reduce-x-to-zero | C++| Simple | O(N) | Sliding Window | | c-simple-on-sliding-window-by-persistent-z3iz | Goal is to find a window of longest length which has sum equal to s - x, where s is sum of all the elements of the array.\n When such a window is found all the | persistentBeast | NORMAL | 2022-06-11T07:26:47.147091+00:00 | 2022-06-12T10:27:29.518002+00:00 | 3,589 | false | * Goal is to **find a window of longest length** which has sum equal to `s - x`, where `s` is sum of all the elements of the array.\n* When such a window is found all the elements outside this window will sum to `x` and no of operations will be equal to their count. \n* **TC : O(N) | SC : O(1)**\n\n```\nclass Solution ... | 29 | 0 | ['C', 'Sliding Window'] | 5 |
minimum-operations-to-reduce-x-to-zero | [Java/Python 3] Sliding window: Longest subarray sum to the target = sum(nums) - x. | javapython-3-sliding-window-longest-suba-uev4 | Using sliding window to find the longest subarry that sums to sum(nums) - x.\njava\n public int minOperations(int[] nums, int x) {\n int target = Arra | rock | NORMAL | 2020-11-15T04:42:40.768272+00:00 | 2022-12-03T16:31:11.169729+00:00 | 3,290 | false | Using sliding window to find the longest subarry that sums to `sum(nums) - x`.\n```java\n public int minOperations(int[] nums, int x) {\n int target = Arrays.stream(nums).sum() - x, size = -1, n = nums.length;\n for (int lo = -1, hi = 0, winSum = 0; hi < n; ++hi) {\n winSum += nums[hi];\n ... | 28 | 0 | ['Java', 'Python3'] | 7 |
minimum-operations-to-reduce-x-to-zero | ✅97.65%🔥Sum of Subarray Reduction🔥 | 9765sum-of-subarray-reduction-by-mrake-26e8 | Problem\n\n### This problem involves finding the minimum number of operations to reduce the sum of elements in the array nums to exactly zero, given that you ca | MrAke | NORMAL | 2023-09-20T00:49:33.147774+00:00 | 2023-09-20T00:49:33.147800+00:00 | 2,406 | false | # Problem\n\n### This problem involves finding the minimum number of operations to reduce the sum of elements in the array nums to exactly zero, given that you can perform operations to remove elements from either the left or right end of the array.\n---\n# Solution\n\n##### **1.** Calculate the total sum of all elemen... | 26 | 14 | ['Array', 'Hash Table', 'C', 'Python', 'C++', 'Java', 'Go', 'Python3', 'C#'] | 5 |
minimum-operations-to-reduce-x-to-zero | [Python3] O(N) hash table of prefix | python3-on-hash-table-of-prefix-by-ye15-ljid | Algo \nHere, we maintain a mapping of prefix sum to index mapping. Then, we go over nums inversely to compute suffix sum, and check if a complement exists in th | ye15 | NORMAL | 2020-11-15T04:08:15.092260+00:00 | 2021-01-15T05:11:33.425344+00:00 | 2,109 | false | Algo \nHere, we maintain a mapping of prefix sum to index mapping. Then, we go over `nums` inversely to compute suffix sum, and check if a complement exists in the prefix sum (via hash table). If so, check the length and update `ans`. \n\nImplementation \n```\nclass Solution:\n def minOperations(self, nums: List[int... | 25 | 2 | ['Python3'] | 9 |
minimum-operations-to-reduce-x-to-zero | sliding window [c++] | sliding-window-c-by-vishwasgajawada-vscp | \nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n int total=0,n=nums.size();\n for(int num : nums)total+=num;\n | vishwasgajawada | NORMAL | 2021-01-14T09:34:52.724598+00:00 | 2021-10-04T17:38:44.204258+00:00 | 1,706 | false | ```\nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n int total=0,n=nums.size();\n for(int num : nums)total+=num;\n int need=total-x,cur=0,longest=0;\n if(need==0)return n;\n int l=0,r=0;\n while(l<=r){\n if(cur<need){\n i... | 19 | 3 | ['C'] | 3 |
minimum-operations-to-reduce-x-to-zero | [Python 3] Two sum problem using HashMap - O(N) - Clean & Concise | python-3-two-sum-problem-using-hashmap-o-b2vb | python\nclass Solution:\n def minOperations(self, nums: List[int], x: int) -> int:\n n = len(nums)\n\n leftMap = dict()\n leftMap[0] = - | hiepit | NORMAL | 2021-05-18T11:43:51.327696+00:00 | 2021-05-18T11:45:14.912315+00:00 | 776 | false | ```python\nclass Solution:\n def minOperations(self, nums: List[int], x: int) -> int:\n n = len(nums)\n\n leftMap = dict()\n leftMap[0] = -1\n left = 0\n for i in range(n):\n left += nums[i]\n if left not in leftMap:\n leftMap[left] = i\n\n ... | 17 | 0 | [] | 0 |
minimum-operations-to-reduce-x-to-zero | C++ || Explained Solution || Best Time and Space Complexity | c-explained-solution-best-time-and-space-4ohc | Please Upvote the solution if helpful --> else comment down the problem and I will try to improve upon that! Thanks for reading .\n```\nclass Solution {\npublic | code-to-learn | NORMAL | 2022-06-11T10:09:08.019965+00:00 | 2022-06-11T10:50:12.255671+00:00 | 1,106 | false | **Please Upvote the solution if helpful --> else comment down the problem and I will try to improve upon that! Thanks for reading .**\n```\nclass Solution {\npublic:\n // O(n) time complexity solution and O(1) space complexity\n // Given Problem (equivalent) => Finding longest subarray with sum=totalSum(nums) - x... | 16 | 0 | [] | 3 |
minimum-operations-to-reduce-x-to-zero | ✅Easiest Solution with explanation and annotations! | easiest-solution-with-explanation-and-an-5r1s | Intuition\nWe can use prefix sum and suffix sum here. \nFor every number in prefix sum we\'ll check if its complement is present in suffix. If it is it means we | parthdharmale008 | NORMAL | 2023-09-20T05:42:48.418526+00:00 | 2023-09-20T05:48:46.071246+00:00 | 2,336 | false | # Intuition\nWe can use prefix sum and suffix sum here. \nFor every number in prefix sum we\'ll check if its complement is present in suffix. If it is it means we can make our `x` if it is not it means we can\'t make `x` with that particular prefix, so move on to the next one.\n\n# Approach\n- Firstly we find our `n` w... | 15 | 0 | ['Array', 'Prefix Sum', 'C++', 'Java'] | 4 |
minimum-operations-to-reduce-x-to-zero | Very Easy C++ Solution with Explanation (Sliding Window) - beats 88.2% submissions | very-easy-c-solution-with-explanation-sl-twpo | Explanation\nThis is a slighty tricky variant of Sliding Window problem.\n\nTrick to make this question easy :\n Total = Sum of all elements of the nums array.\ | vatsalkesarwani | NORMAL | 2021-06-12T22:21:41.261778+00:00 | 2021-06-12T22:21:41.261804+00:00 | 1,271 | false | **Explanation**\nThis is a slighty tricky variant of Sliding Window problem.\n\nTrick to make this question easy :\n* Total = Sum of all elements of the nums array.\n* Now find max operation to find (total-x) in the array\n\nCheck result :\n* If the result comes to 0 then return -1\n* else return size-result\n\nTime Co... | 15 | 1 | ['Two Pointers', 'Greedy', 'C', 'Sliding Window'] | 0 |
minimum-operations-to-reduce-x-to-zero | 💯🔥 1 Method || C++ | Java || Python || JavaScript 💯🔥 | 1-method-c-java-python-javascript-by-use-7c2v | Read Whole article : https://www.nileshblog.tech/minimum-operations-to-reduce-x-to-zero/\n\nExplanation of Problem with Example (HandWritten).\nTime Complexity: | user6845R | NORMAL | 2023-09-20T06:15:23.243780+00:00 | 2023-09-20T06:15:23.243809+00:00 | 1,105 | false | Read Whole article : https://www.nileshblog.tech/minimum-operations-to-reduce-x-to-zero/\n\nExplanation of Problem with Example (HandWritten).\nTime Complexity:\n\n**Prefix Sum + Hashmap (Longest Subarry )Approach : O(N)**\n\nPython :\nJava:\nc++:\nJavaScript:\n\nRead Whole article :https://www.nileshblog.tech/minimum-... | 14 | 1 | ['C', 'Prefix Sum', 'Python', 'Java', 'JavaScript'] | 3 |
minimum-operations-to-reduce-x-to-zero | Java || Greedy + DP + HashMap + BinarySearch + Prefix Sum + Sliding Window || 5 approaches | java-greedy-dp-hashmap-binarysearch-pref-4a1j | \n\t// O(2^n) O(n)\n\t// Recursion\n\t// TLE\n\tpublic int minOperationsRec(int[] nums, int x) {\n\n\t\tint len = nums.length;\n\t\tint count = minOperationsHel | LegendaryCoder | NORMAL | 2021-06-08T02:38:36.745067+00:00 | 2021-06-08T02:39:07.496763+00:00 | 517 | false | \n\t// O(2^n) O(n)\n\t// Recursion\n\t// TLE\n\tpublic int minOperationsRec(int[] nums, int x) {\n\n\t\tint len = nums.length;\n\t\tint count = minOperationsHelper(nums, x, 0, len - 1);\n\t\treturn (count == Integer.MAX_VALUE) ? -1 : count;\n\t}\n\n\t// O(2^n) O(n)\n\t// Recursion\n\tpublic int minOperationsHelper(int[... | 14 | 2 | [] | 1 |
minimum-operations-to-reduce-x-to-zero | C++ | Easy Solution w/ Explanation | Sliding Window ✅ | c-easy-solution-w-explanation-sliding-wi-hfyo | Please upvote the post if you like it :)\n\nIntuition:\nwe can basically think this problem as finding the longest subarray with sum sum - x, since we are delet | prantik0128 | NORMAL | 2022-06-11T04:33:00.684634+00:00 | 2022-06-11T04:36:04.386795+00:00 | 1,095 | false | **Please upvote the post if you like it :)**\n\n**Intuition:**\nwe can basically think this problem as `finding the longest subarray` with **sum** `sum - x`, since we are deleting only from the ends so we will be left out with sum `sum-x` left if we are able to remove elements with sum `x` \nThis is how we come to down... | 13 | 0 | ['C', 'Sliding Window'] | 1 |
minimum-operations-to-reduce-x-to-zero | C++ ☄️ | SLIDING WINDOW | O(1) Space / O(n) Time | c-sliding-window-o1-space-on-time-by-meg-cjud | The problem can be thought of as finding the longest subarray with sum total - x ,because we are deleting elements from the ends only .So there will be a subarr | megamind_ | NORMAL | 2022-06-11T02:01:54.187973+00:00 | 2022-06-11T06:28:29.418926+00:00 | 1,747 | false | The problem can be thought of as finding the longest subarray with sum `total - x` ,because we are deleting elements from the ends only .So there will be a subarray left of sum `total-x` left if we were able to remove elements with sum `x`. \n The approach is to use the concept of the variable-size sliding window using... | 10 | 1 | [] | 1 |
minimum-operations-to-reduce-x-to-zero | [C++] Cumulative Sums Solution Explained, ~100% Time, ~70% Space | c-cumulative-sums-solution-explained-100-vsqh | Okay, I tried a number of approaches, including a 2d matrix for DP and a double-ended BFS, before realising that there was a much easier and performant solution | ajna | NORMAL | 2021-01-14T23:58:00.439707+00:00 | 2021-01-15T00:03:28.978472+00:00 | 1,268 | false | Okay, I tried a number of approaches, including a 2d matrix for DP and a double-ended BFS, before realising that there was a much easier and performant solution; the tips for the problem definitely did not help.\n\nThe core idea is to compute and store all the partial sums from the left together with the indexes in whi... | 10 | 0 | ['C', 'C++'] | 3 |
minimum-operations-to-reduce-x-to-zero | JAVA | Recursion | Sliding Window | 2 Solutions | java-recursion-sliding-window-2-solution-9yu0 | Recursive Solution: (Please note that it will give time limit exceeded (TLE) if submitted )\n\nclass Solution {\n int ans;\n public int minOperations(int[ | deepmehta | NORMAL | 2021-01-14T14:11:48.554505+00:00 | 2021-01-14T14:11:48.554542+00:00 | 1,432 | false | **Recursive Solution:** (Please note that it will give time limit exceeded (TLE) if submitted )\n```\nclass Solution {\n int ans;\n public int minOperations(int[] nums, int x) {\n ans = Integer.MAX_VALUE;\n recur(nums,0,nums.length-1,x,0);\n return ans==Integer.MAX_VALUE?-1:ans;\n }\n p... | 10 | 1 | ['Recursion', 'Sliding Window', 'Java'] | 3 |
minimum-operations-to-reduce-x-to-zero | C++ prefix sums O(n) | c-prefix-sums-on-by-radheshsarma2299-ahp2 | We can observe that we are deleting some part of prefix(possibly none) and some part of suffix(possibly none) from the given array such that sum of prefix and s | radheshsarma2299 | NORMAL | 2020-11-15T11:58:42.393942+00:00 | 2020-11-15T11:58:42.393971+00:00 | 792 | false | We can observe that we are deleting some part of prefix(possibly none) and some part of suffix(possibly none) from the given array such that sum of prefix and suffix deleted is x\nSo we create a map between the suffix sum and the length of suffix\nNow we iterate from left to right,\nlet say we are at index i, then let ... | 10 | 1 | [] | 1 |
minimum-operations-to-reduce-x-to-zero | C++ Prefix Sum & Binary Search/Unordered map/Sliding Window||w Explanation | c-prefix-sum-binary-searchunordered-maps-0v0g | Intuition\n Describe your first thoughts on how to solve this problem. \nThis code efficiently finds the minimum length of a subarray that sums up to x using pr | anwendeng | NORMAL | 2023-09-20T02:24:44.063519+00:00 | 2023-09-20T08:15:24.233524+00:00 | 1,615 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThis code efficiently finds the minimum length of a subarray that sums up to x using prefix sums and binary search techniques.\n\nSecond approach does not use binary search. Insteadly the hash table unordered_map plays the role! The TC is... | 9 | 0 | ['Hash Table', 'Binary Search', 'Sliding Window', 'Prefix Sum', 'C++'] | 2 |
minimum-operations-to-reduce-x-to-zero | ✅✅JAVA || Beats 99% || 🔥🔥 DP ||🔥🔥 Sliding Window | java-beats-99-dp-sliding-window-by-sumit-8yme | Intuition\n Describe your first thoughts on how to solve this problem. \nDp will give memory limit exceeded.\nso we need to do it by sliding window\n# Approach\ | sumitdarshanala | NORMAL | 2023-09-20T08:52:15.334562+00:00 | 2023-09-20T08:52:15.334581+00:00 | 764 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nDp will give memory limit exceeded.\nso we need to do it by sliding window\n# Approach\n<!-- Describe your approach to solving the problem. -->\nwe need a { subarray of sum } as \ntarget = total sum - x\nthen max subarray sum of target... | 8 | 0 | ['Dynamic Programming', 'Sliding Window', 'Java'] | 3 |
minimum-operations-to-reduce-x-to-zero | [C++/Full Explanation] Simple Sliding Window || Why DP won't work here explanation | cfull-explanation-simple-sliding-window-198pn | class Solution {\npublic:\n \n\t// We can do this question with the help of DP concept of take from front and back and return minimum of the operation but in | Sameer_111 | NORMAL | 2022-06-11T04:56:18.515188+00:00 | 2022-06-11T04:58:21.424655+00:00 | 940 | false | class Solution {\npublic:\n \n\t// We can do this question with the help of DP concept of take from front and back and return minimum of the operation but in that case it will give TLE \n\t// and here we are not able to optimize due to high constraints 1<=x<=10^9.\n\t// That is why sliding window works here, So we f... | 8 | 0 | ['Two Pointers', 'C', 'Sliding Window', 'Prefix Sum', 'C++'] | 1 |
minimum-operations-to-reduce-x-to-zero | Python Sliding Window Using maxLen of continuous subarray concept | python-sliding-window-using-maxlen-of-co-tbjs | Idea is to do using continous subarray with max length size which return continous subarray length. The elements that are not included in the subarray (exterior | aayuskh | NORMAL | 2021-01-14T23:52:47.652390+00:00 | 2021-01-14T23:52:47.652433+00:00 | 459 | false | Idea is to do using continous subarray with max length size which return continous subarray length. The elements that are not included in the subarray (exterior to it) is the ans. So, in this case len(nums) - maxLen of continous subarray.\nNow x is actually sum of exterior, to do continous subarray we need total sum - ... | 8 | 0 | ['Sliding Window', 'Python'] | 1 |
minimum-operations-to-reduce-x-to-zero | Simple solution by finding the longest array with a target in Java | simple-solution-by-finding-the-longest-a-4trx | Essentially, we need to find the longest array with a sum of - (sum(array) - x). If we do find this, this might either be - \n1. Starting from the left end: In | amoghrajesh1999 | NORMAL | 2021-01-14T11:11:30.273381+00:00 | 2021-01-14T11:11:30.273406+00:00 | 870 | false | Essentially, we need to find the longest array with a sum of - (sum(array) - x). If we do find this, this might either be - \n1. Starting from the left end: In this case, We will have found the answer which has minimum length from right\n2. Somewhere in the middle: Will be a valid answer since we can pick elements from... | 8 | 2 | ['Java'] | 1 |
minimum-operations-to-reduce-x-to-zero | C++ | PREFIX SUM | HASHMAP | O(n) TIME COMPLEXITY | c-prefix-sum-hashmap-on-time-complexity-m3k5i | \nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n const int n = nums.size();\n int ans = INT_MAX, sum = 0;\n | UnknownOffline | NORMAL | 2022-06-11T03:01:52.357807+00:00 | 2022-06-11T03:01:52.357837+00:00 | 473 | false | ```\nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n const int n = nums.size();\n int ans = INT_MAX, sum = 0;\n unordered_map<int,int> m;\n for(int i = n - 1;i >=0;i--) {\n sum += nums[i];\n m[sum] = i + 1;\n if(sum == x) ans = ... | 7 | 0 | ['C', 'Prefix Sum'] | 1 |
minimum-operations-to-reduce-x-to-zero | Python | Prefix Sum & Sliding Window | With Explanation | python-prefix-sum-sliding-window-with-ex-on9w | Detailed Explanation:\n1. Idea: the aim of this question is to find the minimum operations to reduce x to 0, i.e. find the minimum number of elements from the s | Mikey98 | NORMAL | 2022-06-11T01:19:09.316490+00:00 | 2022-06-11T23:25:13.186463+00:00 | 1,545 | false | Detailed Explanation:\n1. Idea: the aim of this question is to find the minimum operations to reduce `x` to 0, i.e. find the minimum number of elements from the start and end that can sum up to `x`. We can transform this problem to: **find the longest subarray in `nums` that sum to `goal`**, where `goal = sum(nums) - x... | 7 | 0 | ['Sliding Window', 'Python', 'Python3'] | 3 |
minimum-operations-to-reduce-x-to-zero | Javascript | Simple Prefix Sum Sliding Window Solution w/ Explanation| beats 100% / 94% | javascript-simple-prefix-sum-sliding-win-avtg | Idea:\n\nThis problem is tasking us to essentially find when the sum of the starting and ending subarrays of nums is equal to x. Put another way, it\'s asking u | sgallivan | NORMAL | 2021-01-14T23:19:15.114947+00:00 | 2021-01-14T23:56:51.173970+00:00 | 418 | false | ***Idea:***\n\nThis problem is tasking us to essentially find when the sum of the starting and ending subarrays of **nums** is equal to **x**. Put another way, it\'s asking us to find when any subarray of consecutive elements in **nums** is equal to the sum of all elements in **nums** minus **x**.\n```\n ... | 7 | 0 | ['JavaScript'] | 0 |
minimum-operations-to-reduce-x-to-zero | Python, find the longest window | python-find-the-longest-window-by-warmr0-n5u8 | Essentially we\'re looking to remove the longest sequence of numbers so that what\'s left is equal to x. \nReformulating the problem this way it becomes a class | warmr0bot | NORMAL | 2021-01-14T10:18:27.317899+00:00 | 2021-01-14T10:18:27.317938+00:00 | 1,046 | false | Essentially we\'re looking to remove the longest sequence of numbers so that what\'s left is equal to `x`. \nReformulating the problem this way it becomes a classic window sliding problem. \nComplexity Time: O(N), Memory: O(1) \n```\ndef minOperations(self, nums: List[int], x: int) -> int:\n\tN = len(nums)\n\ttoremove ... | 7 | 0 | ['Sliding Window', 'Python', 'Python3'] | 0 |
minimum-operations-to-reduce-x-to-zero | [Python] Clear Two Pointers Solution with Video Explanation | python-clear-two-pointers-solution-with-t1nu6 | Video with clear visualization and explanation:\nhttps://youtu.be/kRHZdzYYn50\n\n\nIntuition: Two Pointers\n\n\nCode\n\nclass Solution:\n def minOperations(s | iverson52000 | NORMAL | 2020-11-15T23:26:11.418370+00:00 | 2020-11-15T23:26:11.418407+00:00 | 787 | false | Video with clear visualization and explanation:\nhttps://youtu.be/kRHZdzYYn50\n\n\nIntuition: Two Pointers\n\n\n**Code**\n```\nclass Solution:\n def minOperations(self, nums: List[int], x: int) -> int:\n target = sum(nums)-x\n n = len(nums)\n\n if target < 0: return -1\n if target == 0: r... | 7 | 1 | ['Python'] | 2 |
minimum-operations-to-reduce-x-to-zero | [C++/Java] 2-Pointer O(n) Solutions! | cjava-2-pointer-on-solutions-by-admin007-fzcx | It is easy to observe that in order to find the shortest required operations that sum up to x is finding the longest subarray that sums up to total - x. \n\nApp | admin007 | NORMAL | 2020-11-15T05:15:52.314317+00:00 | 2020-11-15T05:32:20.637861+00:00 | 1,223 | false | It is easy to observe that in order to find the shortest required operations that sum up to *x* is finding the longest subarray that sums up to *total - x*. \n\n**Approach 1 Find the longest subarray sum equals to a target value:**\n\n**C++**\n```\npublic:\n int minOperations(vector<int>& nums, int x) {\n int... | 7 | 0 | ['C', 'Java'] | 1 |
minimum-operations-to-reduce-x-to-zero | Convert to calculate longest subarray with fixed target sum | convert-to-calculate-longest-subarray-wi-para | Just convert to another question:\nThe longest subarray with sum = (sum of nums - x);\n\nThen the question is much easier. Just play the trick of calculating p | nadabao | NORMAL | 2020-11-15T04:07:18.892713+00:00 | 2020-11-15T05:06:00.559015+00:00 | 442 | false | Just convert to another question:\nThe longest subarray with sum = (sum of nums - x);\n\nThen the question is much easier. Just play the trick of calculating presum and store in map. \nFor this type of question, please refer to leetcode 560:\nhttps://leetcode.com/problems/subarray-sum-equals-k/\n\n```\nclass Solution ... | 7 | 1 | [] | 0 |
minimum-operations-to-reduce-x-to-zero | [Javascript] Two pointers O(n) | javascript-two-pointers-on-by-alanchangh-vyv6 | ```\nvar minOperations = function(nums, x) {\n let l = 0,\n r = nums.length-1,\n res = nums.length+1;\n \n let n = x;\n \n while (l | alanchanghsnu | NORMAL | 2020-11-15T04:01:49.122473+00:00 | 2020-11-15T04:13:04.925451+00:00 | 999 | false | ```\nvar minOperations = function(nums, x) {\n let l = 0,\n r = nums.length-1,\n res = nums.length+1;\n \n let n = x;\n \n while (l <= r && n-nums[l] >= 0)\n n -= nums[l++];\n \n if (n === 0)\n res = l;\n \n while (l < r && l >= 0) {\n while (n-nums[r] >= 0)... | 7 | 1 | ['Two Pointers', 'JavaScript'] | 0 |
minimum-operations-to-reduce-x-to-zero | Best O(N) Solution | best-on-solution-by-kumar21ayush03-sj57 | Approach\nSliding Window Technique\n\n# Complexity\n- Time complexity:\nO(n)\n\n- Space complexity:\nO(1)\n\n# Code\n\nclass Solution {\npublic:\n int minOpe | kumar21ayush03 | NORMAL | 2023-09-21T10:32:50.500211+00:00 | 2023-09-21T10:32:50.500238+00:00 | 638 | false | # Approach\nSliding Window Technique\n\n# Complexity\n- Time complexity:\n$$O(n)$$\n\n- Space complexity:\n$$O(1)$$\n\n# Code\n```\nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n int n = nums.size();\n int sum = 0;\n for (int i = 0; i < n; i++)\n sum += nu... | 6 | 0 | ['C++'] | 0 |
minimum-operations-to-reduce-x-to-zero | Simple Java Solution | faster than 95.37% | simple-java-solution-faster-than-9537-by-slbr | Finding the minimum number of removing is equal to finding the maximum number of remaining.\nSliding window can help us find the maximum number of remaining eas | angzhanh | NORMAL | 2022-06-11T01:32:21.614252+00:00 | 2022-06-11T01:32:35.768773+00:00 | 1,279 | false | Finding the minimum number of removing is equal to finding the maximum number of remaining.\nSliding window can help us find the maximum number of remaining easily!\n```\nclass Solution {\n public int minOperations(int[] nums, int x) {\n int n = nums.length;\n \n int sum = 0;\n for (int i... | 6 | 0 | ['Sliding Window', 'Java'] | 0 |
minimum-operations-to-reduce-x-to-zero | C++ | O(1) Space | Faster than 97% | Contiguous subarray sum | Unique Approach | c-o1-space-faster-than-97-contiguous-sub-mcip | Explanantion\n Step 1 - Find the SUM of whole array. \n Step 2 - Then, Subtract the given element from the total SUM.\n Step 3 - Now, All we have to do is take | nishsolvesalgo | NORMAL | 2021-09-05T09:35:19.470407+00:00 | 2021-09-05T09:36:30.204806+00:00 | 424 | false | **Explanantion**\n* **Step 1** - Find the ***SUM*** of whole array. \n* **Step 2** - Then, Subtract the given element from the total ***SUM***.\n* **Step 3** - Now, All we have to do is take a left and right pointer traverse through the array and find Contiguous subarrays sum (i.e include all elements from left to righ... | 6 | 0 | ['C', 'Sliding Window'] | 1 |
minimum-operations-to-reduce-x-to-zero | Minimum Operations to Reduce X to Zero || C++ || Easy || 99%beat || Hash map | minimum-operations-to-reduce-x-to-zero-c-mki6 | \nAs we count the sum of the first l numbers, you need to find a complement (x - sum) number formed by numbers on the right. To do so, we can use a hashmap wher | thekalyan001 | NORMAL | 2021-01-14T10:30:01.559669+00:00 | 2021-01-14T10:30:13.194170+00:00 | 520 | false | \nAs we count the sum of the first l numbers, you need to find a complement (x - sum) number formed by numbers on the right. To do so, we can use a hashmap where we will store the rolling sum.\nUpvote if you liked :)\n```\nint minOperations(vector<int>& nums, int x) {\n unordered_map<int, int> left;\n int res = I... | 6 | 1 | ['C'] | 0 |
minimum-operations-to-reduce-x-to-zero | C++ Prefix Sum Solution + Binary Search | c-prefix-sum-solution-binary-search-by-p-2vgx | \nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n \n if(nums.size() == 1){\n if(x == nums[0])\n | pikabu | NORMAL | 2020-11-15T04:32:35.604408+00:00 | 2020-11-15T04:32:35.604439+00:00 | 408 | false | ```\nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n \n if(nums.size() == 1){\n if(x == nums[0])\n return 1;\n return -1;\n }\n if(nums[0] > x && nums[nums.size() -1] > x)\n return -1;\n \n vector<lo... | 6 | 0 | [] | 0 |
minimum-operations-to-reduce-x-to-zero | JAVA TC: 100% beats , MC: 95% beat, sliding window | java-tc-100-beats-mc-95-beat-sliding-win-e2j1 | sum_total : totla sum of array.\nwe need to find longest lenghted subarray which sums to (sum_total -x)\n\nwe can find the the largest lengthhed subarray using | jerryjohnthomastvm | NORMAL | 2022-06-11T17:06:16.748288+00:00 | 2022-06-11T18:03:38.642017+00:00 | 735 | false | sum_total : totla sum of array.\nwe need to find longest lenghted subarray which sums to (sum_total -x)\n\nwe can find the the largest lengthhed subarray using sliding window,\nmove left pointer when the sum>=(required) otherwise keep on increasing right pointer\n\nAns. total_length - length of largest sub_array with s... | 5 | 0 | ['Sliding Window', 'Java'] | 0 |
minimum-operations-to-reduce-x-to-zero | C++ || EASY TO UNDERSTAND || Prefix Sum + Suffix Sum + Binary Search || 2 Approaches | c-easy-to-understand-prefix-sum-suffix-s-5vmi | Time Complexity O(NlogN)\n\nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n int n=nums.size();\n vector<int> pre(n, | aarindey | NORMAL | 2022-06-11T10:29:04.317277+00:00 | 2022-06-11T13:18:41.454643+00:00 | 252 | false | **Time Complexity O(NlogN)**\n```\nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n int n=nums.size();\n vector<int> pre(n,0);\n vector<int> suff(n,0);\n pre[0]=nums[0];\n suff[n-1]=nums[n-1];\n for(int i=1;i<n;i++)\n {\n pre[i]=p... | 5 | 0 | [] | 1 |
minimum-operations-to-reduce-x-to-zero | C++ Solution Using Two Pointer | c-solution-using-two-pointer-by-conquist-fnyp | C++ Solution Using Two Pointer\n\nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n int n=nums.size();\n int left=0,r | Conquistador17 | NORMAL | 2022-06-11T05:28:57.893469+00:00 | 2022-06-11T05:28:57.893503+00:00 | 1,363 | false | # **C++ Solution Using Two Pointer**\n```\nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n int n=nums.size();\n int left=0,right=0;\n int sum=0;\n int ans=-1;\n for(int i=0;i<n;i++){\n sum+=nums[i];\n }\n \n cout<<sum;\n ... | 5 | 0 | ['Two Pointers', 'C', 'C++'] | 1 |
minimum-operations-to-reduce-x-to-zero | ✅ C++ | O(N) | Easy to understand | c-on-easy-to-understand-by-kjs_27-ibj1 | To solve this problem first we need to calculate the maximum length of subarray with sum which is equal to difference of total sum and x. \n\nExample:\nnums = [ | kjs_27 | NORMAL | 2022-06-11T05:20:39.458647+00:00 | 2022-06-18T20:08:29.139476+00:00 | 774 | false | To solve this problem first we need to calculate the maximum length of subarray with sum which is equal to difference of total sum and x. \n\n**Example:**\n**nums** = [3,2,5,4,11,5]\n**x** = 10\n\nTotal sum = 3 + 2 + 5 + 4 + 11 + 5 = 30\nSum - x = 20\n\nLength of maximum subarray with sum = 20 is 3 as shown;\n along with memoization\nBut it gives TLE . The constraints are large for test cases.\n\nTime Comple | nitin23rathod | NORMAL | 2022-06-11T03:47:25.012048+00:00 | 2022-06-11T03:47:25.012085+00:00 | 288 | false | # **Approach 1 :- DP**\nUsed the classic Top Down DP(Knapsack 0/1) along with memoization\n***But it gives TLE*** . The constraints are large for test cases.\n\n**Time Complexity O(N^2).\nSpace Complexity O(N^2).**\n\n```\nclass Solution {\npublic:\n vector<vector<int>>dp;\n int solve(vector<int>&nums,int s,int e... | 5 | 0 | ['C'] | 0 |
minimum-operations-to-reduce-x-to-zero | DP Top Down and Sliding window Solutions in C++ | dp-top-down-and-sliding-window-solutions-dja0 | Approach 1 DP\nUsed the classic Top Down DP(Knapsack 0/1) along with memoization\nBut it gives TLE . The constraints are large for test cases.\n\nTime Complexit | ManthanJoshi | NORMAL | 2021-09-04T11:17:27.573445+00:00 | 2021-09-04T11:19:26.376837+00:00 | 699 | false | **Approach 1** **DP**\nUsed the classic Top Down DP(**Knapsack 0/1**) along with memoization\nBut it gives **TLE** . The constraints are large for test cases.\n\n**Time Complexity O(N^2)\nSpace Complexity O(N^2)**\n```\n// Classic Knapsack 0/1 problem\nclass Solution {\npublic:\n vector<vector<int>>dp;\n int sol... | 5 | 0 | ['Dynamic Programming', 'Sliding Window'] | 0 |
minimum-operations-to-reduce-x-to-zero | Minimum Operations to Reduce X to Zero | C++ | Finding Maximum Sub-Array | 99% beat | minimum-operations-to-reduce-x-to-zero-c-afk4 | As stated by the first hint: "Think in reverse; instead of finding the minimum prefix + suffix, find the maximum subarray." \n\nThis code uses a sliding window | yongweic | NORMAL | 2021-01-15T02:08:24.505841+00:00 | 2021-01-15T02:08:24.505872+00:00 | 186 | false | As stated by the first hint: "Think in reverse; instead of finding the minimum prefix + suffix, find the maximum subarray." \n\nThis code uses a sliding window to find the maximum subarray.\n```\nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n int l = 0;\n int r = 0;\n ... | 5 | 2 | [] | 1 |
minimum-operations-to-reduce-x-to-zero | C++ Simple and Easy Solution | c-simple-and-easy-solution-by-yehudisk-bzwu | \nclass Solution {\npublic:\n int findMaxSub(vector<int>& nums, int k) {\n int sum = 0, maxi = 0;\n unordered_map<int, int> m;\n \n | yehudisk | NORMAL | 2021-01-14T12:48:50.437026+00:00 | 2021-01-14T12:48:50.437063+00:00 | 601 | false | ```\nclass Solution {\npublic:\n int findMaxSub(vector<int>& nums, int k) {\n int sum = 0, maxi = 0;\n unordered_map<int, int> m;\n \n for (int i=0; i<nums.size(); i++) {\n sum += nums[i];\n \n if (sum == k)\n maxi = i+1;\n \n ... | 5 | 1 | ['C'] | 0 |
minimum-operations-to-reduce-x-to-zero | 🔥2 Approaches💯 || 🌟O(1) SC || 💯Clean & Best Code✅ | 2-approaches-o1-sc-clean-best-code-by-ad-16ug | Connect with me on LinkedIN : https://www.linkedin.com/in/aditya-jhunjhunwala-51b586195/\n# Complexity\n\n- Time complexity:\nO(n)\n\n- Space complexity:\nO(n) | aDish_21 | NORMAL | 2023-09-20T06:34:59.105751+00:00 | 2023-09-20T14:21:37.252110+00:00 | 411 | false | ### Connect with me on LinkedIN : https://www.linkedin.com/in/aditya-jhunjhunwala-51b586195/\n# Complexity\n```\n- Time complexity:\nO(n)\n\n- Space complexity:\nO(n) for Approach 1\nO(1) for Approach 2\n```\n\n# Code\n## Please Upvote if u found it useful\uD83E\uDD17\n# 1st Approach(Using PrefixSum + HashMap):-\n```\n... | 4 | 0 | ['Array', 'Hash Table', 'Sliding Window', 'Prefix Sum', 'C++'] | 1 |
minimum-operations-to-reduce-x-to-zero | EASY SOLUTION || EXPLANATION || C++ || Beat 98.9 % || | easy-solution-explanation-c-beat-989-by-oxs8m | \n# Approach\n Describe your approach to solving the problem. \n##### Try to find maximum subarray that have the sum == total_sum of array - x\n\n# Code\n\nclas | amol_2004 | NORMAL | 2023-09-20T05:08:43.772745+00:00 | 2023-09-20T05:08:43.772774+00:00 | 327 | false | \n# Approach\n<!-- Describe your approach to solving the problem. -->\n##### Try to find maximum subarray that have the `sum == total_sum of array - x`\n\n# Code\n```\nclass Solution {\npublic:\n int minOperations(vector<int>& nums, int x) {\n int total_sum = 0;\n int n = nums.size();\n for(int ... | 4 | 0 | ['Two Pointers', 'Sliding Window', 'C++'] | 1 |
minimum-operations-to-reduce-x-to-zero | 🔥98.80% Acceptance📈 rate | Using Sliding Window🧭 | Explained in details✅ | 9880-acceptance-rate-using-sliding-windo-3jwg | Intuition\n Describe your first thoughts on how to solve this problem. \nThe intuition behind this code is to find a subarray with the maximum possible sum (equ | nikkipriya_78 | NORMAL | 2023-09-20T04:00:01.834799+00:00 | 2023-10-07T13:55:41.988135+00:00 | 292 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe intuition behind this code is to find a subarray with the maximum possible sum (equal to targetSum) within the given nums array. The goal is to minimize the number of operations to reduce x to 0. By calculating the maximum subarray le... | 4 | 0 | ['Array', 'Hash Table', 'Binary Search', 'Sliding Window', 'Prefix Sum', 'Python', 'C++', 'Java', 'Python3', 'JavaScript'] | 0 |
minimum-operations-to-reduce-x-to-zero | very easy to understand solution O(N) time, O(1) SPACE | very-easy-to-understand-solution-on-time-9o1g | Intuition\nwe can take only elements which are present at corner i.e in starting and in last so we try to find window of (total sum of array - k) \nso , n-k win | abhinav_raj531 | NORMAL | 2023-09-20T02:39:31.367671+00:00 | 2023-09-20T02:47:53.560308+00:00 | 134 | false | # Intuition\nwe can take only elements which are present at corner i.e in starting and in last so we try to find window of (total sum of array - k) \nso , n-k window, will contain sum == k. \n\n# Approach\nhere, we are using sliding window approch to find the largest window of elments that contains (total sum of array ... | 4 | 0 | ['Sliding Window', 'C++'] | 0 |
minimum-operations-to-reduce-x-to-zero | C++ | Minimum Operations to Reduce X to Zero | 2 Approaches with Explanation | c-minimum-operations-to-reduce-x-to-zero-o2a2 | Approach 1\n\t1. Maintain two cumulative sum left and right . Also check the edge cases (if x is present in the left or right)\n\t2. Go from start to end of lef | badhansen | NORMAL | 2022-06-11T09:59:41.682010+00:00 | 2022-06-11T10:53:53.392667+00:00 | 189 | false | **Approach 1**\n\t1. Maintain two cumulative sum `left` and `right` . Also check the edge cases (if x is present in the `left` or `right`)\n\t2. Go from start to end of `left` and check if remaining is present or not in the `right` one.\n\t3. `ans` will be sum of two indices.\n\n**Time:** `O(N log N)`\n**Space:** `O(N... | 4 | 0 | ['Binary Search', 'Sliding Window', 'Binary Tree'] | 1 |
minimum-operations-to-reduce-x-to-zero | Kotlin || O(n) time || O(1) space | kotlin-on-time-o1-space-by-yezhizhen-9w5q | \n fun minOperations(nums: IntArray, x: Int): Int {\n //find longest subarray sum to total_sum - x\n var target = nums.sum() - x; var sum = 0\n | yezhizhen | NORMAL | 2022-06-11T07:31:04.772806+00:00 | 2022-06-11T07:31:04.772869+00:00 | 99 | false | ```\n fun minOperations(nums: IntArray, x: Int): Int {\n //find longest subarray sum to total_sum - x\n var target = nums.sum() - x; var sum = 0\n var l = 0; var ans = -1;\n for(r in 0 until nums.size)\n {\n sum += nums[r]\n while(l <= r && sum > target) //mov... | 4 | 0 | ['Kotlin'] | 1 |
minimum-operations-to-reduce-x-to-zero | Binary Search | c++ | O(nlogn) | binary-search-c-onlogn-by-vivek_9680-f3s2 | First, I thought it\'s dp but when I saw the constraint then i came to know that it\'s not dp.\nWhen we see closely, see the prefix[i] + suffix[j]==x then i + ( | vivek_9680 | NORMAL | 2022-06-11T07:01:44.353174+00:00 | 2022-06-11T07:45:41.794587+00:00 | 198 | false | First, I thought it\'s dp but when I saw the constraint then i came to know that it\'s not dp.\nWhen we see closely, see the prefix[i] + suffix[j]==x then i + (n-j) is our answer.\nI am giving the example:\n[1,1,4,2,3] and x = 5\npre = [0,1,2,6,8,11] //add 0 for simplicity\nsuff = [11,10,9,5,3,0] \n\nIn this scenario t... | 4 | 0 | ['C', 'Binary Tree'] | 3 |
minimum-operations-to-reduce-x-to-zero | C++ || Sliding window || 1658. Minimum Operations to Reduce X to Zero || Easy | c-sliding-window-1658-minimum-operations-llf8 | \t// Here ans is the window size we have to maximize the window size\n\t// because more we maximize window size lesser the elements willl be remainig in nums\n\ | anubhavsingh11 | NORMAL | 2022-06-11T06:40:26.363171+00:00 | 2022-06-11T06:41:00.556899+00:00 | 193 | false | \t// Here ans is the window size we have to maximize the window size\n\t// because more we maximize window size lesser the elements willl be remainig in nums\n\t// ans hence our no of operation will be reduced\n\t// Here we are checking for window of max size for sum=totalsum-x \n\t//so that sum of remainig elements b... | 4 | 0 | ['Two Pointers', 'C', 'Sliding Window'] | 0 |
minimum-operations-to-reduce-x-to-zero | Python | reverse thinking | prefix sum + hash map | with comments | python-reverse-thinking-prefix-sum-hash-j7wd3 | When I first read this problem, I think I have seen it elsewhere. Then I realize that it\'s pretty similar to Leetcode 325 Maximum Size Subarray Sum Equals k. \ | BoluoUp | NORMAL | 2022-06-11T05:09:37.422625+00:00 | 2022-06-11T05:09:37.422667+00:00 | 633 | false | When I first read this problem, I think I have seen it elsewhere. Then I realize that it\'s pretty similar to *Leetcode 325 Maximum Size Subarray Sum Equals k*. \n\nTo get the minimum operations to reduce x to 0, we can get the longest length of subarray sum equals "new" target ```sum(nums) - x```. The answer will be `... | 4 | 0 | ['Prefix Sum', 'Python'] | 0 |
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LeetCode Solution Dataset
This dataset contains community-contributed LeetCode solutions scraped from public discussions and solution pages, enriched with metadata such as vote counts, author info, tags, and full code content. The goal is to make high-quality, peer-reviewed coding solutions programmatically accessible for research, analysis, educational use, or developer tooling.
Column Descriptions
| Column Name | Type | Description |
|---|---|---|
question_slug |
string |
The unique slug of the LeetCode question |
title |
string |
Title of the submitted solution |
slug |
string |
URL-safe identifier for the solution (can be used to reconstruct URL) |
summary |
string |
Short description or intro snippet of the solution |
author |
string |
Username of the contributor |
certification |
string |
LeetCode’s certification level for the author |
created_at |
timestamp |
When the solution was originally posted |
updated_at |
timestamp |
When the solution was last modified |
hit_count |
int |
Number of views the solution has received |
has_video |
boolean |
Whether the solution includes a video explanation |
content |
string |
The full markdown content including code blocks |
upvotes |
int |
Total number of upvotes |
downvotes |
int |
Total number of downvotes |
tags |
list[str] |
List of tags (e.g. algorithm type, difficulty, company, etc.) |
comments |
int |
Number of top-level comments on the solution |
question_slug: Construct the link this way: "https://leetcode.com/problems/{question_slug}/description/"
This dataset is part of a broader collection of LeetCode-related resources. It complements:
- LeetCode Problem Detailed – includes full problem descriptions, metadata, and statistics for each LeetCode question.
- LeetCode Problem Set – a lightweight list of problems with slugs, titles, difficulty levels, and basic stats (without descriptions or solutions). Note: New questions and solutions are added weekly. If you'd like updates or more in-depth coverage for specific problems, feel free to reach out!
The scraper used to collect this dataset is available here: timetooth/leetcode_scraper. Drop a ⭐ if you find it useful!
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