problem_id
stringlengths
6
6
user_id
stringlengths
10
10
time_limit
float64
1k
8k
memory_limit
float64
262k
1.05M
problem_description
stringlengths
48
1.55k
codes
stringlengths
35
98.9k
status
stringlengths
28
1.7k
submission_ids
stringlengths
28
1.41k
memories
stringlengths
13
808
cpu_times
stringlengths
11
610
code_sizes
stringlengths
7
505
p03102
u068142202
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\ncode_list = [list(map(int, input().split())) for _ in range(n)]\nans = 0\nfor code in code_list:\n total = 0\n for i, j in zip(code, b):\n total += i * j\n if total > 0:\n ans += 1\nprint(ans)', 'n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\ncode_list = [list(map(int, input().split())) for _ in range(n)]\nans = 0\nfor code in code_list:\n total = 0\n for i, j in zip(code, b):\n total += i * j \n if (total + c) > 0:\n ans += 1\nprint(ans)']
['Wrong Answer', 'Accepted']
['s972987614', 's290961754']
[3060.0, 3060.0]
[18.0, 18.0]
[265, 272]
p03102
u069129582
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\ncount=0\nans=0\nfor i in range(n):\n a=list(map(int,input().split()))\n for j in range(m):\n ans+=a[j]*b[j]\n print(ans)\n if ans+c>0:\n count+=1\n \nprint(count)', 'n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\ncount=0\nfor i in range(n):\n a=list(map(int,input().split()))\n ans=0\n for j in range(m):\n ans+=a[j]*b[j]\n if ans+c>0:\n count+=1\n \nprint(count)']
['Wrong Answer', 'Accepted']
['s874808787', 's322395268']
[3060.0, 3064.0]
[18.0, 18.0]
[257, 242]
p03102
u069699931
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C=map(int,input().split())\nB=list(map(int,input().split()))\nAi= [input().split() for l in range(N)]\ncount=0\ntot=0\nfor i in range(N):\n for j in range(M):\n tot+=Ai[i][j]*B[i]\n if tot+C>0:\n count+=1\nprint(count)', 'N,M,C=map(int,input().split())\nB=list(map(int,input().split()))\nAi= [input().split() for l in range(N)]\ncount=0\ntot=0\nfor i in range(N):\n for j in range(M):\n tot+=int(Ai[i][j])*B[j]\n if tot+C>0:\n count+=1\nprint(count)', 'N,M,C=map(int,input().split())\nB=list(map(int,input().split()))\nAi= [input().split() for l in range(N)]\ncount=0\nfor i in range(N):\n tot=0\n for j in range(M):\n tot+=int(Ai[i][j])*B[j]\n if tot+C>0:\n count+=1 \nprint(count)']
['Runtime Error', 'Wrong Answer', 'Accepted']
['s493361396', 's588284015', 's418657739']
[9116.0, 8980.0, 9232.0]
[25.0, 28.0, 26.0]
[240, 245, 243]
p03102
u073549161
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c = int(map,input().split())\nb = int(map,input().split())\ncount = 0\nfor i in range(n):\n sum = 0\n a = int(map, input().split())\n for j in range(m):\n sum += a[j] * b[j]\n sum += c\n if sum > 0:\n count += 1\nprint(count)', 'n,m,c = map(int,input().split())\nb = map(int,input().split())\nb = list(b)\ncount = 0\nfor i in range(n):\n sum = 0\n a = map(int, input().split())\n a = list(a)\n for j in range(m):\n sum += a[j] * b[j]\n sum += c\n if sum > 0:\n count += 1\nprint(count)']
['Runtime Error', 'Accepted']
['s931785947', 's717739710']
[3060.0, 3064.0]
[18.0, 18.0]
[247, 275]
p03102
u075401284
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\na = [list(map(int, input().split())) for i in range(n)]\ncnt = 0\n\nfor l in a:\n tmp = 0\n for i in range(m):\n tmp += b[i]*a[i]\n tmp += c\n if tmp > 0:\n cnt += 1\n\nprint(cnt)', 'n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\na = [list(map(int, input().split())) for i in range(n)]\ncnt = 0\n\nfor l in a:\n tmp = 0\n for i in range(m):\n tmp += b[i]*l[i]\n tmp += c\n if tmp > 0:\n cnt += 1\n\nprint(cnt)']
['Runtime Error', 'Accepted']
['s847339547', 's287080974']
[9132.0, 9108.0]
[24.0, 27.0]
[266, 266]
p03102
u076764813
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c=map(int,input().split())\nb=list(map(int, input().split()))\na=[list(map(int,input().split())) for _ in range(n)]\n\ncnt=0\nfor i in range(n):\n cal=0\n for j in range(m):\n cal += a[i][j]*b[j]\n if cal>0:\n cnt+=1\n \n\nprint(cnt)\n', 'n,m,c=map(int,input().split())\nb=list(map(int, input().split()))\na=[list(map(int,input().split())) for _ in range(n)]\n\ncnt=0\nfor i in range(n):\n cal=c\n for j in range(m):\n cal += a[i][j]*b[j]\n if cal>0:\n cnt+=1\n \n\nprint(cnt)\n']
['Wrong Answer', 'Accepted']
['s393188955', 's583240575']
[3060.0, 3060.0]
[18.0, 17.0]
[251, 251]
p03102
u076996519
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = map(int, input().split())\nb = list(int(x) for x in input().split())\nans = 0\n\nfor j in range(n):\n a = list(int(x) for x in input().split())\n sum = 0\n for i in range(m):\n sum = 0\n sum += a[i]*b[i]\n if sum > -c:\n ans += 1\n\nprint(ans)', 'n, m, c = map(int, input().split())\nb = input().split()\nans = 0\n\nfor j in range(n):\n a = input().split()\n for i in range(m):\n sum = 0\n sum += a[i]*b[i]\n if sum > -c:\n ans += 1\n\nprint(ans)', 'n, m, c = map(int, input().split())\nb = input().split()\nans = 0\n\nfor j in range(n):\n a = input().split()\n for i in range(m):\n sum = 0\n sum += a[i]*b[i]\n if sum > -c:\n ans += 1\n\nprint(ans)', 'n, m, c = map(int, input().split())\nb = [int(x) for x in range(m)]\nans = 0\n\nfor j in range(n):\n a = input().split()\n for i in range(m):\n sum = 0\n sum += a[i]*b[i]\n if sum > -c:\n ans += 1\n\nprint(ans)', 'n, m, c = map(int, input().split())\nb = list(int(x) for x in input().split())\nans = 0\n\nfor j in range(n):\n a = list(int(x) for x in input().split())\n for i in range(m):\n sum = 0\n sum += a[i]*b[i]\n if sum > -c:\n ans += 1\n\nprint(ans)', 'n, m, c = map(int, input().split())\nb = input().split()\nans = 0\n\nfor j in range(n):\n a = list(int(x) for x in input().split())\n for i in range(m):\n sum = 0\n sum += a[i]*b[i]\n if sum > -c:\n ans += 1\n\nprint(ans)', 'n, m, c = map(int, input().split())\nb = list(int(x) for x in input().split())\nans = 0\n\nfor j in range(n):\n a = list(int(x) for x in input().split())\n sum = 0\n for i in range(m):\n sum += a[i]*b[i]\n if sum > -c:\n ans += 1\n\nprint(ans)']
['Wrong Answer', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Wrong Answer', 'Runtime Error', 'Accepted']
['s420493745', 's440250899', 's480640080', 's579454098', 's587908643', 's730787416', 's931234135']
[3060.0, 3060.0, 3060.0, 3064.0, 3060.0, 3060.0, 3060.0]
[18.0, 17.0, 17.0, 18.0, 18.0, 17.0, 18.0]
[281, 217, 217, 228, 269, 247, 257]
p03102
u091051505
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = [int(i) for i in input().split(" ")]\na_list = input()\ni = 0\n\nfor i in range(n):\n b_list = input()\n ans = c\n for j in range(m):\n ans += a_list[j] * b_list[j]\n if ans > 0:\n i ++\n\nprint(i)', 'n, m, c = [int(i) for i in input().split(" ")]\na_list = input().split(" ")\nia = 0\n\nfor i in range(n):\n b_list = input().split(" ")\n ans = c\n for j in range(m):\n ans += int(a_list[j]) * int(b_list[j])\n if ans > 0:\n ia += 1\n\nprint(ia)']
['Runtime Error', 'Accepted']
['s848867773', 's995065019']
[2940.0, 3060.0]
[17.0, 18.0]
[221, 258]
p03102
u092620892
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C=map(int,input().split())\nB=list(map(int,input().split()))\nk=0\nfor i in range(N-1):\n s=0\n A=list(map(int,input().split()))\n for j in range(M-1):\n s+=A[j]*B[j]\n s+=C\n if s>0:\n k+=1\nprint(k)\n', 'N,M,C=map(int,input().split())\nB=list(map(int,input().split()))\nk=0\nfor i in range(N):\n s=0\n A=list(map(int,input().split()))\n for j in range(M):\n s+=A[j]*B[j]\n s+=C\n if s>0:\n k+=1\nprint(k)\n']
['Wrong Answer', 'Accepted']
['s356686281', 's099231710']
[3060.0, 3060.0]
[17.0, 18.0]
[223, 219]
p03102
u095756391
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split())\n \nB = list(map(int, input().split()))\n \nans = []\n \nsrc = []\n \nfor i in range(N):\n src.append(list(map(int, input().split())))\n \n for n in range(M):\n d = src[i][n]*B[n] + C\n if (d > 0):\n ans.append(1)\n \nprint(ans.count(1))', 'N, M, C = map(int, input().split())\n \nB = list(map(int, input().split()))\n \nans = 0\n \nsrc = []\n\nd = 0\n\nfor i in range(N):\n src.append(list(map(int, input().split()))) \n \nfor i in range(N):\n d = C\n for n in range(M):\n d += src[i][n]*B[n]\n print(d)\n if (d > 0):\n ans+= 1\n\nprint(ans)', 'N, M, C = map(int, input().split())\n\nB = list(input().split())\n\nans = []\n\nsrc = []\n\nfor i in range(N):\n src.append(list(map(int, input().split())))\n \n for n in range(N):\n d = src[i][n]*B[n] + C\n if (d > 0):\n ans.append(1)\n\nprint(ans.count(1))\n\n \n ', 'N, M, C = map(int, input().split())\n \nB = list(map(int, input().split()))\n \nans = 0\n \nsrc = []\n\nfor i in range(N):\n src.append(list(map(int, input().split()))) \n \nfor i in range(N):\n d = C\n for n in range(M):\n d += src[i][n]*B[n]\n print(d)\n if (d > 0):\n ans+= 1\n\nprint(ans)', 'N, M, C = map(int, input().split())\n \nB = list(map(int, input().split()))\n \nans = 0\n \nsrc = []\n\nfor i in range(N):\n src.append(list(map(int, input().split()))) \n \nfor i in range(N):\n d += C\n for n in range(M):\n d += src[i][n]*B[n]\n print(d)\n if (d > 0):\n ans+= 1\n\nprint(ans)', 'N, M, C = map(int, input().split())\n \nB = list(map(int, input().split()))\n \nans = 0\n \nsrc = []\n\nd = 0\n\nfor i in range(N):\n src.append(list(map(int, input().split()))) \n \nfor i in range(N):\n d = 0\n for n in range(M):\n d += src[i][n]*B[n]\n d += C\n print(d)\n if (d > 0):\n ans+= 1\n\nprint(ans)', 'N, M, C = map(int, input().split())\n \nB = list(map(int, input().split()))\n \nans = []\n \nsrc = []\n \nfor i in range(N):\n src.append(list(map(int, input().split())))\n \nfor i in range(N):\n for n in range(M):\n d = int(src[i][n]*B[n] + C)\n if (d > 0):\n ans.append(1)\n\nprint(ans.count(1))', 'N, M, C = map(int, input().split())\n \nB = list(input().split())\n \nans = []\n \nsrc = []\n \nfor i in range(N):\n src.append(list(map(int, input().split())))\n \n for n in range(M):\n d = src[i][n]*B[n] + C\n if (d > 0):\n ans.append(1)\n \nprint(ans.count(1))', 'N, M, C = map(int, input().split())\n \nB = list(map(int, input().split()))\n \nans = 0\n \nsrc = []\n\nfor i in range(N):\n src.append(list(map(int, input().split()))) \n \nfor i in range(N):\n d = C\n for n in range(M):\n d += src[i][n]*B[n]\n if (d > 0):\n ans+= 1\n\nprint(ans)']
['Wrong Answer', 'Wrong Answer', 'Runtime Error', 'Wrong Answer', 'Runtime Error', 'Wrong Answer', 'Wrong Answer', 'Runtime Error', 'Accepted']
['s081880874', 's451931597', 's496026379', 's654880283', 's679947548', 's703856503', 's876724299', 's892099277', 's552855649']
[3060.0, 3064.0, 3060.0, 3064.0, 3064.0, 3064.0, 3064.0, 3060.0, 3064.0]
[17.0, 18.0, 17.0, 17.0, 20.0, 17.0, 17.0, 17.0, 17.0]
[271, 292, 263, 285, 286, 301, 294, 261, 274]
p03102
u102902647
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['3 3 0\n100 -100 0\n0 100 100\n100 100 100\n-100 100 100', 'N, M, C = map(int, input().split())\nB_list = list(map(int, input().split()))\nA_lists = [list(map(int, input().split())) for _ in range(N)]\n\ncnt = 0\nfor A_list in A_lists:\n tmp = [a * b for a, b in zip(A_list, B_list)]\n tmp = sum(tmp) + C\n if tmp > 0:\n cnt += 1\nprint(cnt)']
['Runtime Error', 'Accepted']
['s816664953', 's536864372']
[8928.0, 9168.0]
[25.0, 25.0]
[51, 287]
p03102
u103902792
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,c = map(int,input().split())\nb = list(map(int,input().split()))\na = [list(map(int,list(input()))) for i in range(N)]\n\nimport numpy as np\nB = np.array(b).T\nA = np.array(a)\nC = np.ones([N,1])*c\nres = np.dot(A,B) + C\nprint(np.sum(res > 0))', 'N,M,c = map(int,input().split())\nb = list(map(int,input().split()))\na = [list(map(int,input().split())) for i in range(N)]\n\nimport numpy as np\nB = np.array(b).T\nA = np.array(a)\nC = np.ones([N,1])*c\nres = np.dot(A,B) + C\nprint(np.sum(res > 0))', 'N,M,c = map(int,input().split())\nb = list(map(int,input().split()))\na = [list(map(int,input().split())) for i in range(N)]\n\nimport numpy as np\nB = np.array(b)\nA = np.array(a)\n\nres = np.dot(A,B.T) #+ C\n#print(A)\n\n#print(res)\nprint(np.sum(res > -c))']
['Runtime Error', 'Wrong Answer', 'Accepted']
['s843964377', 's886882222', 's283828432']
[3064.0, 12464.0, 12468.0]
[18.0, 150.0, 150.0]
[240, 242, 277]
p03102
u107091170
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C=map(int.input().split())\nB=list(map(int.input().split()))\nans = 0\nfor i in range(N):\n A = list(map(int.input().split()))\n tmp = C\n for j in range(M):\n tmp += A[j]*B[j]\n if tmp > 0:\n ans += 1\nprint(ans)\n', 'N,M,C=map(int,input().split())\nB=list(map(int,input().split()))\nans = 0\nfor i in range(N):\n A = list(map(int,input().split()))\n tmp = C\n for j in range(M):\n tmp += A[j]*B[j]\n if tmp > 0:\n ans += 1\nprint(ans)\n']
['Runtime Error', 'Accepted']
['s887729361', 's902339632']
[2940.0, 3060.0]
[17.0, 17.0]
[218, 218]
p03102
u112766430
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C = list(map(int,input().split()))\nb = input()\ncount = 0\nfor i in range(N):\n\ta = input()\n\ts = 0\n\tfor j in range(M)\n\t\ts += a[j]*b[j]\n\tif s>C:\n\t\tcount+=1\nprint(count)\n', 'N,M,C = list(map(int,input().split()))\nb = input()\ncount = 0\nfor i in range(N):\n\ta = input()\n\ts = 0\n\tfor j in range(M):\n\t\ts += a[j]*b[j]\n\tif s+C>0:\n\t\tcount+=1\nprint(count)', 'N,M,C = list(map(int,input().split()))\nb = list(map(int,input().split()))\ncount = 0\nfor i in range(N):\n\ta = list(map(int,input().split()))\n\ts = 0\n\tfor j in range(M):\n\t\ts += a[j]*b[j]\n\tif s+C>0:\n\t\tcount+=1\nprint(count)']
['Runtime Error', 'Runtime Error', 'Accepted']
['s526863474', 's702597275', 's192499155']
[2940.0, 3060.0, 3064.0]
[17.0, 17.0, 18.0]
[170, 172, 218]
p03102
u122195031
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C = list(map(int,input().split()))\nB = list(map(int,input().split()))\nans = 0\nlst = []\nfor i in range(N):\n A = list(map(int,input().split()))\n lst.append(A[i]*B[i])\nfor i in lst:\n if i > 0:\n ans += 1\nprint(ans)', 'N,M,C = list(map(int,input().split()))\nB = list(map(int,input().split()))\nans = 0\nlst = []\nfor i in range(M):\n A = list(map(int,input().split()))\n lst.append(A[i]*B[i])\nfor i in lst:\n if i > 0:\n ans += 1\nprint(ans)', 'N,M,C = list(map(int,input().split()))\nB = list(map(int,input().split()))\nans = 0\ntotal = 0\nlst = []\nfor i in range(N):\n A = list(map(int,input().split()))\n for j in range(M):\n total += A[j]*B[j]\n lst.append(total)\n total = 0\nfor i in lst:\n if i +C > 0:\n ans += 1\nprint(ans)']
['Runtime Error', 'Runtime Error', 'Accepted']
['s096942046', 's102304171', 's745567660']
[3064.0, 3064.0, 3064.0]
[18.0, 17.0, 18.0]
[224, 228, 289]
p03102
u125269142
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = map(int, input().split())\nb_lists = list(map(int, input().split()))\na_lists = []\nfor _ in range(n):\n tmp = list(map(int, input().split()))\n a_lists.append(tmp)\n\ncond = c\nans = 0\nfor i in a_lists:\n for j in range(m):\n cond = c\n cond += i[j]*b_lists[j]\n if cond > 0:\n ans += 1\n\nprint(ans)', 'n, m, c = map(int, input().split())\nb_lists = list(map(int, input().split()))\na_lists = []\nfor _ in range(n):\n tmp = list(map(int, input().split()))\n a_lists.append(tmp)\n\nans = 0\nfor i in a_lists:\n cond = c\n for j in range(m):\n cond += i[j]*b_lists[j]\n if cond > 0:\n ans += 1\n\nprint(ans)']
['Wrong Answer', 'Accepted']
['s744002162', 's861769204']
[9184.0, 9200.0]
[30.0, 32.0]
[329, 316]
p03102
u125433590
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c = map(int,input().split())\ninput_b = map(int,input().split())\na_list=[input() for i in range(n)]\nfor i in range(n):\n answer = c\n count = 0\n aitems = map(int,a_list[i].split())\n for j in range(m):\n answer += input_b[m] * aitems[m]\n if answer > 0:\n count+=1\nprint count', 'n,m,c = map(int,input().split())\ninput_b = map(int,input().split())\nwhile True:\n try:\n list_a=list(map(int,input().split()))\n answer = c\n count = 0\n for i in range(len(list_a)):\n\t\tanswer += input_b[i] * list_a[i]\n\t\tif answer > 0\n\t\t\tcount+=1\n\t\tprint count\n\texcept:\n\t\tbreak;', 'n,m,c = map(int,input().split())\ninput_b = map(int,input().split())\na_list=[input() for i in range(n)]\nfor i in range(n):\n answer = c\n count = 0\n aitems = map(int,a_list[i].split())\n for j in range(m):\n answer += input_b[m] * aitems[m]\n if answer > 0\n count+=1\nprint count', 'n,m,c = map(int,input().split())\ninput_b = map(int,input().split())\nlist_a=[list(map(int,input().split()))]\nfor i in range(n):\n answer = c\n count = 0\n lista_item = list_a[i]\n for j in range(m):\n answer += input_b[m] * lista_item[m]\n if answer > 0\n count+=1\nprint count', 'n,m,c = map(int,input().split())\ninput_b = map(int,input().split())\nlist_a=list(map(int,input().split()))\nfor i in range(n):\n answer = c\n count = 0\n lista_item = list_a[i]\n for j in range(m):\n answer += input_b[m] * lista_item[m]\n if answer > 0\n count+=1\nprint count', 'n,m,c = map(int,input().split())\ninput_b = map(int,input().split())\na_list=[input() for i in range(n)]\nfor i in range(n):\n answer = c\n count = 0\n aitems = [map(int,a_list[i].split())]\n for j in range(m):\n answer += input_b[m] * aitems[m]\n if answer > 0\n count+=1\nprint count', 'n,m,c = map(int,input().split())\ninput_b = map(int,input().split())\na_list=[input() for i in range(n)]\nfor i in range(n):\n answer = c\n count = 0\n aitems = map(int,a_list[i].split())\n for j in range(m):\n answer += input_b[j] * aitems[j]\n if answer > 0:\n count+=1\nprint count', 'from sys import stdin\nn,m,c = map(int,input().split())\ninput_b = map(int,input().split())\nwhile True:\n\ttry:\n\t\tlist_a=list(map(int,input().split()))\n\t\tanswer = c\n\t\tcount = 0\n\t\tfor i in range(len(list_a)):\n\t\t\tanswer += input_b[i] * list_a[i]\n\t\t\tif answer > 0\n\t\t\t\tcount+=1\n\t\tprint count\n\texcept:\n\t\tbreak;', 'n,m,c = map(int,input().split())\ninput_b = map(int,input().split())\nwhile True:\n try:\n list_a=list(map(int,input().split()))\n answer = c\n count = 0\n for lista_item in list_a:\n for i in range(len(lista_item)):\n answer += input_b[i] * lista_item[i]\n if answer > 0\n count+=1\n print count\n except:\n break;', 'n,m,c = map(int,input().split())\ninput_b = list(map(int,input().split()))\na_list=[input() for i in range(n)]\ncount = 0\nfor i in range(n):\n answer = c\n aitems = list(map(int,a_list[i].split()))\n for j in range(m):\n answer += input_b[j] * aitems[j]\n if answer > 0:\n count+=1\nprint(count)']
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s072581073', 's081272942', 's083303679', 's411982167', 's498369599', 's657738329', 's687016864', 's808152716', 's919910584', 's122670897']
[3064.0, 2940.0, 2940.0, 2940.0, 2940.0, 2940.0, 3064.0, 2940.0, 2940.0, 3064.0]
[17.0, 19.0, 17.0, 17.0, 17.0, 17.0, 17.0, 17.0, 17.0, 17.0]
[284, 285, 283, 279, 277, 285, 284, 301, 349, 295]
p03102
u127499732
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\ncount = 0\nfor _ in range(n):\n a = list(map(int,input().split()))\n if sum(a*b) + c > 0\n \tcount += 1\nprint(count)', 'n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\ncount = 0\nfor _ in range(n):\n a = list(map(int,input().split()))\n s = sum([x*y for x,y in zip(a,b)]) + c\n if s > 0:\n count += 1\nprint(count)']
['Runtime Error', 'Accepted']
['s893305946', 's714650552']
[2940.0, 3060.0]
[17.0, 17.0]
[183, 215]
p03102
u128740947
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = map(int,input().split())\nb = list (map(int,input().split()))\na = []\nfor i in range(n):\n A = list(map(int,input().split()))\n a.append(A)\nans = 0\nprint(a)\nfor i in range(n):\n z = a[i]\n Z = 0\n for l in range(len(z)):\n Z += z[l] * b[l]\n if Z + c > 0:\n ans += 1\nprint(ans)', 'n, m, c = map(int,input().split())\nb = list (map(int,input().split()))\na = []\nfor i in range(n):\n A = list(map(int,input().split()))\n a.append(A)\nans = 0\nfor i in range(n):\n z = a[i]\n Z = 0\n for l in range(len(z)):\n Z += z[l] * b[l]\n if Z + c > 0:\n ans += 1\nprint(ans)']
['Wrong Answer', 'Accepted']
['s583621242', 's475627097']
[3064.0, 3188.0]
[17.0, 19.0]
[309, 300]
p03102
u131264627
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = map(int, input().split())\nb = [int(i) for i in input().split()]\na = [[int(input()) for _ in range(m)] for _ in range(n)]\nans = 0\nctn = 0\nfor j in range(n):\n for k in range(m):\n ctn += b[k] * a[j][k]\n if ctn + c > 0:\n ans += 1\n ctn = 0\nprint(ans)\n', 'n, m, c = map(int, input().split())\nb = [int(i) for i in input().split()]\na = [[int(input()) for _ in range(m)] for _ in range(n)]\nans = 0\nctn = 0\nfor j in range(n):\n for k in range(m):\n ctn += b[n] * a[n][m]\n if ctn - c > 0:\n ans += 0\n ctn = 0\nprint(ans)', 'n, m, c = map(int, input().split())\nb = [int(i) for i in input().split()]\na = [[int(j) for j in input().split()] for _ in range(n)]\nans = 0\nfor k in range(n):\n ct = c\n for l in range(m):\n ct += a[k][l] * b[l]\n if ct > 0:\n ans += 1\n ct = 0\nprint(ans)\n']
['Runtime Error', 'Runtime Error', 'Accepted']
['s069245551', 's992542500', 's769601444']
[3064.0, 3064.0, 3060.0]
[18.0, 17.0, 18.0]
[279, 278, 276]
p03102
u153823221
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\na = [list(map(int, input().split())) for i in range(n)]\n\nans = 0\nl = []\n\nfor i in range(n):\n for j in range(m):\n l.append(a[i][j] * b[j]) \n if sum(l) + c > 0:\n ans += 1\n l.clear()\n else:\n l.clear()\n\nprint(ans)\n', 'n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\na = [list(map(int, input().split())) for i in range(n)]\n\nans = 0\nl = []\n\nfor i in range(n):\n for j in range(m):\n l.append(a[i][j] * b[j]) \n if sum(l) + c > 0:\n ans += 1\n l.clear()\n else:\n l.clear()\n\nprint(ans)\n']
['Wrong Answer', 'Accepted']
['s108895557', 's093724940']
[3064.0, 3064.0]
[17.0, 20.0]
[307, 303]
p03102
u154979004
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\ncnt = 0\nfor _ in range(N):\n A = list(map(int, input().split()))\n cnt += int(sum(A[i] * B[i] for i in range(M)) > 0)\nprint(cnt)', 'N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\ncnt = 0\nfor _ in range(N):\n A = list(map(int, input().split()))\n cnt += int(sum(A[i] * B[i] for i in range(M), C) > 0)\nprint(cnt)\n', 'N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\ncnt = 0\nfor _ in range(N):\n A = list(map(int, input().split()))\n cnt += int(sum([A[i] * B[i] for i in range(M)], C) > 0)\nprint(cnt)\n']
['Wrong Answer', 'Runtime Error', 'Accepted']
['s493369313', 's754505860', 's516151765']
[3060.0, 2940.0, 3060.0]
[17.0, 17.0, 17.0]
[200, 204, 206]
p03102
u156302018
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['nmc = input().split()\nlstb = input().split()\na = []\nfor n in range(int(nmc[0])):\n a.append(input().split())\ntotal = 0\ncount = 0\nfor n in range(int(nmc[0])):\n for m in range(int(nmc[1])):\n total += (int(lstb[m]) * int(a[n][m]))\n if total - int(nmc[2]) > 0:\n count += 1\n total = 0\nprint(count)', 'nmc = input().split()\nlstb = input().split()\na = []\nfor n in range(int(nmc[0])):\n a.append(input().split())\ntotal = 0\ncount = 0\nfor n in range(int(nmc[0])):\n for m in range(int(nmc[1])):\n total += (int(lstb[m]) * int(a[n][m]))\n if total + int(nmc[2]) > 0:\n count += 1\n total = 0\nprint(count)']
['Wrong Answer', 'Accepted']
['s031123222', 's302747142']
[3064.0, 3064.0]
[17.0, 17.0]
[317, 317]
p03102
u158126367
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C = map(int, input().split())\nB = list(map(int, input().split()))\nans=0\nfor i in range(N):\n A = list(map(int, input().split()))\n ssum = sum([A[i]*B[i] for i in range(M)])+C\n if ssum>=0:\n ans+=1\nprint(ans)', 'N,M,C = list(map(int,input().split()))\nb = list(map(int,input().split()))\ncount = 0\nfor i in range(N):\n\ta = list(map(int,input().split()))\n\ts = 0\n\tfor j in range(M):\n\t\ts += a[j]*b[j]\n\tif s+C>0:\n\t\tcount+=1\nprint(count)\n']
['Wrong Answer', 'Accepted']
['s281044756', 's546819341']
[3060.0, 3060.0]
[18.0, 18.0]
[224, 219]
p03102
u165233868
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\n\ncount = 0\nfor i in range(N):\n lst = list(map(int, input().split()))\n lb = 0\n for l,b in zip(lst,B):\n lb + l * b\n if lb - C > 0:\n count += 1\n\nprint(count)', 'N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\n\ncount = 0\nfor i in range(N):\n lst = list(map(int, input().split()))\n lb = 0\n for l,b in zip(lst,B):\n lb += l * b\n if lb + C > 0:\n count += 1\n\nprint(count)']
['Wrong Answer', 'Accepted']
['s303121202', 's861901841']
[3060.0, 3060.0]
[18.0, 18.0]
[252, 253]
p03102
u166621202
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['import numpy as np\n\nN,M,C = map(int,input().split())\nB=np.array(list(map(int,input().split())))\nans=0\n\nfor i in range(N):\n A=np.array(list(map(int,input().split())))\n if sum(A-B)-C > 0:\n ans+=1\nprint(ans)\n', '#N,M,C=map(int,input().split())\n#B=[int,input() for _ in range(M)]\n#\n\n# A=[int,input() for _ in range(M)]\n\nimport numpy as np\n \nN,M,C=map(int,input().split())\nB=np.array([int,input() for _ in range(M)])\nans=0\n\nfor i in range(N):\n A=np.array([int,input() for _ in range(M)])\n if sum(A-B)-10 > 0:\n ans+=1\n\n', 'N,M,C = map(int,input().split())\nB = list(map(int,input().split()))\n\nans=0\nfor i in range(N):\n ab=0\n A = list(map(int,input().split()))\n for j in range(M):\n ab += A[j] * B[j]\n if ab + C > 0:\n ans+=1\nprint(ans)']
['Wrong Answer', 'Runtime Error', 'Accepted']
['s330412439', 's381321946', 's443837901']
[12504.0, 2940.0, 3060.0]
[147.0, 17.0, 18.0]
[210, 330, 219]
p03102
u167273718
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C = map(int,input().split())\nB = list(map(int,input().split()))\nans = 0\nA = []\nfor i in range(N):\n A.append(list(map(int,input().split())))\n for j in range(M):\n S = C\n S += A[i][j] * B[j]\n if S > 0:\n ans += 1\nprint(ans)', 'N,M,C = map(int,input().split())\nB = list(map(int,input().split()))\nans = 0\nA = []\nfor i in range(N):\n A.append(list(map(int,input().split())))\n S = C\n for j in range(M):\n S += A[i][j] * B[j]\n if S > 0:\n ans += 1\n else:\n ans += 0\nprint(ans)']
['Wrong Answer', 'Accepted']
['s838163486', 's020749581']
[3060.0, 3064.0]
[18.0, 17.0]
[253, 276]
p03102
u178888901
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
["vdef judge(A, B, C, M):\n\tresult = C\n\tfor i in range(M):\n\t\tresult += A[i] * B[i]\n\n\treturn result > 0\n\ndef main():\n\tN, M, C = map(int, input().split())\n\tB = map(int, input().split())\n\tcount = 0\n\n\tfor i in N:\n\t\tA = map(int, input().split())\n\n\t\tif judge(A, B, C, M):\n\t\t\tcount += 1\n\n\tprint(count)\n\n\n\nif __name__ == '__main__':\n\tmain()", "def judge(A, B, C, M):\n\tresult = C\n\tfor i in range(M):\n\t\tresult += A[i] * B[i]\n\n\treturn result > 0\n\ndef main():\n\tN, M, C = map(int, input().split())\n\tB = map(int, input().split())\n\tcount = 0\n\n\tfor i in range(N):\n\t\tA = map(int, input().split())\n\n\t\tif judge(A, B, C, M):\n\t\t\tcount += 1\n\n\tprint(count)\n\n\n\nif __name__ == '__main__':\n\tmain()", "def judge(A, B, C, M):\n\tresult = C\n\tfor i in range(M):\n\t\tresult += A[i] * B[i]\n\n\treturn result > 0\n\ndef main():\n\tN, M, C = map(int, input().split())\n\tB = map(int, input().split())\n\tcount = 0\n\n\tfor i in N:\n\t\tA = map(int, input().split())\n\n\t\tif judge(A, B, C, M):\n\t\t\tcount += 1\n\n\tprint(count)\n\n\n\nif __name__ == '__main__':\n\tmain()", "vdef judge():\n\tresult = C\n\tfor i in range(M):\n\t\tresult += A[i] * A[j]\n\n\treturn result > 0\n\ndef main():\n\tN, M, C = map(int, input().split())\n\tB = map(int, input().split())\n\tcount = 0\n\n\tfor i in N:\n\t\tA = map(int, input().split())\n\n\t\tif judge(A, B, C, M):\n\t\t\tcount += 1\n\n\tprint(count)\n\n\n\nif __name__ == '__main__':\n\tmain()", "vdef judge(A, B, C, M):\n\tresult = C\n\tfor i in range(M):\n\t\tresult += A[i] * A[j]\n\n\treturn result > 0\n\ndef main():\n\tN, M, C = map(int, input().split())\n\tB = map(int, input().split())\n\tcount = 0\n\n\tfor i in N:\n\t\tA = map(int, input().split())\n\n\t\tif judge(A, B, C, M):\n\t\t\tcount += 1\n\n\tprint(count)\n\n\n\nif __name__ == '__main__':\n\tmain()", "def judge(A, B, C, M):\n\tresult = C\n\tfor i in range(M):\n\t\tresult += A[i] * B[i]\n\n\treturn result > 0\n\ndef main():\n\tN, M, C = map(int, input().split())\n\tB = [int(x) for x in input().split()]\n\tcount = 0\n\n\tfor i in range(N):\n\t\tA = [int(x) for x in input().split()]\n\n\t\tif judge(A, B, C, M):\n\t\t\tcount += 1\n\n\tprint(count)\n\n\n\nif __name__ == '__main__':\n\tmain()"]
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s218558556', 's383451506', 's471150745', 's505740713', 's859240125', 's113613868']
[2940.0, 3064.0, 3064.0, 2940.0, 2940.0, 3060.0]
[17.0, 18.0, 17.0, 18.0, 17.0, 18.0]
[329, 335, 328, 319, 329, 351]
p03102
u181195295
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, K =map(int().input().aplit())\nbases = list(map(int,input()))\nans=0\n\nfor i in range(M):\n A = list(map(int,input().split()))\n tmp=0\n for j in range(3):\n tmp+= bases[j]*A[j]\n if tmp>0:\n ans+=1\n \nprint(ans)', 'N, M, K =map(int,input().aplit())\nbases = list(map(int,input()))\nans=0\n\nfor i in range(M):\n A = list(map(int,input().split()))\n tmp=0\n for j in range(3):\n tmp+= bases[j]*A[j]\n if tmp>0:\n ans+=1\n \nprint(ans)\n', 'N, M, K =map(int,input().aplit())\nbases = list(map(int,input().split()))\nans=0\n\nfor i in range(M):\n A = list(map(int,input().split()))\n tmp=0\n for j in range(3):\n tmp+= bases[j]*A[j]\n if tmp>0:\n ans+=1\n \nprint(ans)\n', 'N, M, K =map(int,input().split())\nbases = list(map(int,input().split()))\nans=0\n\nfor i in range(N):\n a= list(map(int,input().split()))\n tmp=0\n for j in range(M):\n tmp+= bases[j]*a[j]\n \n if tmp+K>0:\n ans+=1\n \nprint(ans)\n']
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s081568662', 's456380410', 's942032179', 's535158273']
[3060.0, 3060.0, 3060.0, 3060.0]
[18.0, 18.0, 18.0, 17.0]
[221, 220, 228, 232]
p03102
u182004566
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['def is_okay(A, B, C):\n sum = 0\n for i in range(len(B)):\n sum += A[i] * B[i]\n\n return sum > 0\n\nN, M, C = map(int, input().split())\nB = tuple(map(int, input().split()))\n\nanswer = 0\nfor _ in range(N):\n A = tuple(map(int, input().split()))\n answer += is_okay(A, B, C)\n\nprint(answer)\n', 'def is_okay(A, B, C):\n sum = 0\n for i in range(len(B)):\n sum = sum + A[i] * B[i]\n\n return sum > C\n\nN, M, C = map(int, input().split())\nB = tuple(map(int, input().split()))\n\nanswer = 0\nfor _ in range(N):\n A = tuple(map(int, input().split()))\n answer = answer + is_okay(A, B, C)\n\nprint(answer)\n', 'def is_okay(A, B, C):\n sum = 0\n for i in range(len(B)):\n sum = sum + A[i] * B[i]\n\n return sum + C > 0\n\nN, M, C = map(int, input().split())\nB = tuple(map(int, input().split()))\n\nanswer = 0\nfor _ in range(N):\n A = tuple(map(int, input().split()))\n answer = answer + is_okay(A, B, C)\n\nprint(answer)\n']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s175682793', 's849590128', 's431772988']
[3060.0, 3060.0, 3060.0]
[18.0, 18.0, 17.0]
[301, 314, 318]
p03102
u189479417
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int,input().split())\nB = list(map(int,input().split()))\ncnt = 0\nfor _ in range(N):\n ans = 0\n A = list(map(int,input().split()))\n for i in range(M):\n ans += A[i] * B[i]\n if ans > C:\n cnt += 1\nprint(cnt)', 'N, M, C = map(int,input().split())\nB = list(map(int,input().split()))\ncnt = 0\nfor _ in range(N):\n ans = 0\n A = list(map(int,input().split()))\n for i in range(M):\n ans += A[i] * B[i]\n ans += C\n if ans > 0:\n cnt += 1\nprint(cnt)']
['Wrong Answer', 'Accepted']
['s490213277', 's967926228']
[3060.0, 3060.0]
[17.0, 18.0]
[249, 254]
p03102
u191423660
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split()) \n 2 B = list(map(int, input().split()))\n 3 \n 4 S = [[0]*M for i in range(N)]\n 5 for i in range(N):\n 6 S[i] = list(map(int, input().split()))\n 7 \n 8 b = 0\n 9 \n 10 for i in range(N):\n 11 a = 0\n 12 for ii in range(M):\n 13 a += S[i][ii] * B[ii]\n 14 a += C\n 15 if a > 0:\n 16 b += 1\n 17 \n 18 print(str(b))', 'N, M, C = map(int, input().split())\n 2 B = list(map(int, input().split()))\n 3 \n 4 S = [[0]*M for i in range(N)]\n 5 for i in range(N): \n 6 S[i] = list(map(int, input().split()))\n 7 \n 8 b = 0\n 9 \n 10 for i in range(N):\n 11 a = 0\n 12 for ii in range(M):\n 13 a += S[i][ii] * B[ii]\n 14 a += C\n 15 if a > 0:\n 16 b += 1\n 17 \n 18 print(str(b))', 'N, M, C = map(int, input().split()) \nB = list(map(int, input().split()))\n \nS = [[0]*M for i in range(N)]\nfor i in range(N):\n S[i] = list(map(int, input().split()))\n \nb = 0\n \nfor i in range(N):\n a = 0\n for ii in range(M):\n a += S[i][ii] * B[ii]\n a += C\n if a > 0:\n b += 1\nprint(str(b))']
['Runtime Error', 'Runtime Error', 'Accepted']
['s421502401', 's710994491', 's996111233']
[2940.0, 2940.0, 3064.0]
[17.0, 17.0, 19.0]
[503, 520, 435]
p03102
u202400119
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['[[source]]\nname = "pypi"\nurl = "https://pypi.org/simple"\nverify_ssl = true\n\n[dev-packages]\n\n[packages]\npandas = "*"\nnumpy = "*"\n\n[requires]\npython_version = "3.7"\n', 'import numpy as np\n\nn, m, c = map(int, input().split())\nb = list(map(int, input().split()))\n\nb = np.array(b)\n\ncount = 0\nfor _ in range(n):\n a = list(map(int, input().split()))\n a = np.array(a)\n\n if np.dot(a, b) + c > 0:\n count += 1\nelse:\n print(count)']
['Runtime Error', 'Accepted']
['s694510241', 's726947120']
[2940.0, 12420.0]
[17.0, 150.0]
[163, 270]
p03102
u204616996
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C=map(int,input().split())\nB=list(map(int,input().split()))\nans=0\nfor i in range(N):\n A=list(map(int,input().split()))\n if sum([a*b for a in A for b in B])+C>0:\n ans+=1\nprint(ans)', 'N,M,C=map(int,input().split())\nB=list(map(int,input().split()))\nans=0\nfor i in range(N):\n A=list(map(int,input().split()))\n if sum([a*b for a,b in zip(A,B)])+C>0:\n ans+=1\nprint(ans)']
['Wrong Answer', 'Accepted']
['s378850408', 's909332733']
[3060.0, 3060.0]
[18.0, 18.0]
[188, 186]
p03102
u208120643
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['"""Boot-camp-for-Beginners_Easy005_B_Can-you-solve-this_25-August-2020.py"""\n\nN, M, C = map(int, input().split())\nB = list(map(int, input().split()))\nA = list(list(map(int, input().split())) for i in range(N))\n\ncount=0\nfor i in range(N):\n s=0\n for j in range(len(B)):\n s+=B[j]*A[i][j]\n print(s)\n if s+C>0:\n count+=1\nprint(count)', '"""Boot-camp-for-Beginners_Easy005_B_Can-you-solve-this_25-August-2020.py"""\n\nN, M, C = map(int, input().split())\nB = list(map(int, input().split()))\nA = list(list(map(int, input().split())) for i in range(N))\n\ncount=0\nfor i in range(N):\n s=0\n for j in range(len(B)):\n s+=B[j]*A[i][j]\n if s+C>0:\n count+=1\nprint(count)']
['Wrong Answer', 'Accepted']
['s975221868', 's008710908']
[9208.0, 9136.0]
[26.0, 28.0]
[354, 341]
p03102
u220345792
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\ncnt = 0\nfor i in range(M):\n A = list(map(int, input().split()))\n tmp = 0\n for j in range(N):\n tmp += A[j]*B[j]\n tmp += C\n if tmp > 0:\n cnt += 1\n \nprint(cnt)\n ', 'N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\ncnt = 0\nfor i in range(N):\n A = list(map(int, input().split()))\n tmp = 0\n for j in range(M):\n tmp += A[j]*B[j]\n tmp += C\n if tmp > 0:\n cnt += 1\n \nprint(cnt)\n \n\n']
['Runtime Error', 'Accepted']
['s660053124', 's542527012']
[3064.0, 3060.0]
[18.0, 18.0]
[258, 260]
p03102
u221345507
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['import numpy as np\n\nN, M, C = map(int,input().split())\n\nB = list(map(int,input().split()))\n\ncount = 0\nfor i in range (N):\n A = list(map(int,input().split()))\n if np.array(A)*np.array(B) > 0:\n count += 1\nprint(count)', 'import numpy as np\n \nN, M, C = map(int,input().split())\n \nB = list(map(int,input().split()))\n \ncount = 0\nfor i in range (N):\n A = list(map(int,input().split()))\n if np.sum(np.array(A)*np.array(B)) + C> 0:\n count += 1\nprint(count)']
['Runtime Error', 'Accepted']
['s413301307', 's721785458']
[12424.0, 13024.0]
[147.0, 179.0]
[228, 242]
p03102
u233183615
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\na=[list(map(int,input().split())) for _ in range(n)]\ncount=0\nfor i in range(n-1):\n for j in range(m-1):\n total+=b[j]*a[i][j]\n if total>-c:\n count+=1\nprint(count)', 'n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\na=[list(map(int,input().split())) for _ in range(n)]\ncount=0\nfor i in range(n):\n total=0\n for j in range(m):\n total+=b[j]*a[i][j]\n if total>-c:\n count+=1\nprint(count)']
['Runtime Error', 'Accepted']
['s981056276', 's209157678']
[3060.0, 3060.0]
[17.0, 17.0]
[245, 253]
p03102
u241347678
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['s=input().split()\nn=int(s[0]);m=int(s[1]);c=int(s[2])\nb=input().split();a=[];ans=0\nfor i in range n : a.append(input().split())\nfor i in range n :\n temp=0\n for j in range m : temp+=int(a[i][j])*int(b[j])\n if temp+c>0 : ans+=1\nprint(ans)', 's=input().split()\nn=int(s[0]);m=int(s[1]);c=int(s[2])\nb=input().split();a=[];ans=0\nfor i in range(n) : a.append(input().split())\nfor i in range(n) :\n temp=0\n for j in range(m) : temp+=int(a[i][j])*int(b[j])\n if temp+c>0 : ans+=1\nprint(ans)']
['Runtime Error', 'Accepted']
['s329380333', 's694904617']
[2940.0, 3064.0]
[17.0, 18.0]
[239, 242]
p03102
u243572357
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = map(int, input().split())\nb = map(int, input().split())\ncount = 0\n\nfor i in range(n):\n a = map(int, input().split())\n for j in range(m):\n if 0 < a[m] * b[m] + c:\n count += 1\nprint(count)', 'n, m, c = map(int, input().split())\nb = map(int, input().split())\ncount = 0\n \nfor i in range(n):\n a = map(int, input().split())\n for j in range(m):\n if 0 < a[j] * b[j] + c:\n count += 1\nprint(count)', 'n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\ncount = 0\n \nfor i in range(n):\n a = list(map(int, input().split()))\n p = c\n for j in range(m):\n \tp += a[j] + b[j]\n if 0 < p:\n count += 1\nprint(count)', 'n, m, c = map(int, input().split())\nb = map(int, input().split())\ncounter = 0\nfor i in range(n):\n a = map(int, input().split())\n if sum([b[i]*a[i] for i in range(m)]) + c > 0:\n counter += 1\nprint(counter)', 'n, m, c = map(int, input().split())\nb = map(int, input().split())\ncount = 0\n \nfor i in range(n):\n a = map(int, input().split())\n for j in range(m):\n if 0 < (a[j] * b[j] + c):\n count += 1\nprint(count)', 'n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\ncount = 0\n \nfor i in range(n):\n a = list(map(int, input().split()))\n p = c\n for j in range(m):\n p += a[j] + b[j]\n if 0 < p:\n count += 1\nprint(count)', 'n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\ncount = 0\n \nfor i in range(n):\n a = list(map(int, input().split()))\n for j in range(m):\n if 0 < a[m] * b[m] + c:\n count += 1\nprint(count)', 'n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\ncounter = 0\nfor i in range(n):\n a = list(map(int, input().split()))\n if sum([b[i]*a[i] for i in range(m)]) + c > 0:\n counter += 1\nprint(counter)\n']
['Runtime Error', 'Runtime Error', 'Wrong Answer', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s262181140', 's266006795', 's482359054', 's551374706', 's573965523', 's607645861', 's762552060', 's591690676']
[3060.0, 3060.0, 3060.0, 3060.0, 3060.0, 2940.0, 3060.0, 2940.0]
[17.0, 17.0, 18.0, 17.0, 17.0, 17.0, 17.0, 17.0]
[206, 207, 229, 209, 209, 228, 219, 222]
p03102
u244416763
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c = map(int,input().split())\nans = 0\nfor i in range(m):\n current = 0\n a = list(map(int,input().split()))\n for k,j in enumerate(a):\n current += j*(k+1)\n ans += 1 if c+current else 0\nprint(ans)', 'n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\nans = 0\nfor i in range(n):\n a = list(map(int,input().split()))\n ans += 1 if 0 < c+sum([a[j]*b[j] for j in range(m)]) else 0\nprint(ans)']
['Runtime Error', 'Accepted']
['s898960306', 's735911647']
[3060.0, 3060.0]
[17.0, 17.0]
[214, 208]
p03102
u249727132
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split())\nB = [int(input()) for i in range(M)]\nA = [[int(input()) for i in range(M)] for j in range(N)]\ncnt = 0\nfor i in range(N):\n ans = 0\n for j in range(M):\n ans += A[j][i] * B[j]\n if ans + C > 0:\n cnt += 1\nprint(cnt)\n', 'N, M, C = map(int, input().split())\nB = [int(input()) for i in range(M)]\nA = [[int(input()) for i in range(M)] for j in range(N)]\ncnt = 0\nfor i in range(N):\n ans = 0\n for j in range(M):\n ans += A[i][j] * B[j]\n if ans + C > 0:\n cnt += 1\nprint(cnt)\n', 'N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\nans = 0\n\nfor i in range(N):\n A = list(map(int, input().split()))\n tmp = C\n for i, j in zip(A, B):\n tmp += i * j\n if tmp > 0:\n ans += 1\nprint(ans)']
['Runtime Error', 'Runtime Error', 'Accepted']
['s538264445', 's922348184', 's459315572']
[3060.0, 3060.0, 3060.0]
[17.0, 18.0, 17.0]
[270, 270, 243]
p03102
u252828980
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c = map(int,input().split())\na = input().split()\na = [int(x) for x in a]\n\nd = 0\ne = 0\nfor i in range(n):\n b = input().split()\n b = [int(x) for x in b]\n for j in range(m):\n d += b[j]*a[j]\n print(d)\n if d + c >0:\n e += 1\n d = 0\nprint(e)', 'n,m,c = map(int,input().split())\nL = list(map(int,input().split()))\ncnt = 0\nfor i in range(n):\n wa = 0\n li = list(map(int,input().split()))\n for j in range(m):\n wa +=L[j]*li[j]\n if wa + c >0:\n cnt +=1\nprint(cnt)']
['Wrong Answer', 'Accepted']
['s331866520', 's024881670']
[3064.0, 3060.0]
[18.0, 18.0]
[270, 237]
p03102
u252964975
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C=map(int, input().split())\nB=list(map(int, input().split()))\ncount = 0\nfor i in range(N):\n A=list(map(int, input().split()))\n hyoka = 0\n for k in range(M):\n hyoka = hyoka + A[k]*B[k]\n if hyoka+C > 0:\n count = cocunt + 1\nprint(count)', 'N,M,C=map(int, input().split())\nB=list(map(int, input().split()))\ncount = 0\nfor i in range(N):\n A=list(map(int, input().split()))\n hyoka = 0\n for k in range(M):\n hyoka = hyoka + A[k]*B[k]\n if hyoka+C > 0:\n count = count + 1\nprint(count)']
['Runtime Error', 'Accepted']
['s537885551', 's995394090']
[3060.0, 3060.0]
[17.0, 17.0]
[247, 246]
p03102
u255499778
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = list(map(int, input().split()))\nB = list(map(int, input().split()))\ncount = 0\nli = [list(map(int, input().split())) for i in range(n)]\n\nfor i in range(n):\n d = 0\n for j in range(m):\n d = li[i][j] * B[j]\n else:\n d += c\n if d > 0:\n count += 1\nprint(count)', 'n, m, c = list(map(int, input().split()))\nB = list(map(int, input().split()))\ncount = 0\nli = [list(map(int, input().split())) for i in range(n)]\n\nfor i in range(n):\n num = 0\n for j in range(m):\n d = li[i][j] * B[j]\n else:\n d += c\n if d > 0:\n count += 1\nprint(count)', 'n, m, c = list(map(int, input().split()))\nB = list(map(int, input().split()))\ncount = 0\nli = [list(map(int, input().split())) for i in range(n)]\n\nfor i in range(n):\n d = 0\n for j in range(m):\n d += li[i][j] * B[j]\n else:\n d += c\n if d > 0:\n count += 1\nprint(count)']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s503657397', 's696521051', 's530323518']
[3064.0, 3064.0, 3064.0]
[18.0, 18.0, 18.0]
[304, 306, 305]
p03102
u256833330
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['import numpy as np\nn,m,c=map(int,input().split())\nb=np.array(list(map(int,input().split())))\nac=0\nfor _ in range(n):\n a=np.array(list(map(int,input().split())))\n print(a*b)\n if sum(a*b)+c >0:\n ac+=1\nprint(ac)\n', 'import numpy as np\nn,m,c=map(int,input().split())\nb=np.array(list(map(int,input().split())))\nac=0\nfor _ in range(n):\n a=np.array(list(map(int,input().split())))\n if sum(a*b)+c >0:\n ac+=1\nprint(ac)\n']
['Wrong Answer', 'Accepted']
['s948062081', 's639325652']
[18316.0, 12504.0]
[258.0, 148.0]
[225, 210]
p03102
u258436671
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split())\nB = [int(_) for _ in input().split()]\nfor i in range(1, N + 1):\n Ai = [int(_) for _ in input().split()]\n\nright = 0\n\nfor j in range(1,N + 1):\n src = 0\n for k in range(M):\n src += Aj[k] * B[k]\n if src + C > 0:\n right += 1\n\nprint(right)\n', 'N, M, C = map(int, input().split())\nB = [int(_) for _ in input().split()]\nA = []\nfor i in range(N):\n A.append([int(_) for _ in input().split()])\n\nright = 0\n\nfor i in range(N):\n src = 0\n for j in range(M):\n src += A[i][j]*B[j]\n if src + C >0 :\n right + =1\n\nprint(right)', 'N, M, C = map(int, input().split())\nB = [int(_) for _ in input().split()]\nA = []\nfor i in range(N):\n A.append([int(_) for _ in input().split()])\n\nright = 0\n\nfor i in range(N):\n src = 0\n for j in range(M):\n src += A[i][j]*B[j]\n if src+C>0:\n right+=1\n\nprint(right)']
['Runtime Error', 'Runtime Error', 'Accepted']
['s495965899', 's853499010', 's888630146']
[3060.0, 2940.0, 3064.0]
[19.0, 18.0, 19.0]
[282, 294, 288]
p03102
u262801165
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = map(int, input().split())\na = []\nb = list(map(int, input().split()))\n\nfor i in range(n):\n a.append(list(map(int, input().split())))\n print(a)\n\ncount = 0\nfor i in range(n):\n x = 0\n for j in range(m):\n x += a[i][j] * b[j]\n x += c\n\n if x > 0:\n count += 1\n \nprint(count)\n', 'n, m, c = map(int, input().split())\na = [[0 for i in range(m)] for j in range(n)]\nb = [0 for i in range(m)]\nfor i in range(m):\n b[i] = int(input())\nfor i in range(n):\n for j in range(m):\n a[i][j] = int(input())\n\ncount = 0\nfor i in range(n):\n x = 0\n for j in range(m):\n x += a[i][j] * b[j]\n x += c\n\n if x > 0:\n count += 1\n \nprint(count)\n', 'n, m, c = map(int, input().split())\na = []\nb = list(map(int, input().split()))\n\nfor i in range(n):\n a.append(list(map(int, input().split())))\n\ncount = 0\nfor i in range(n):\n x = 0\n for j in range(m):\n x += a[i][j] * b[j]\n x += c\n\n if x > 0:\n count += 1\n \nprint(count)\n']
['Wrong Answer', 'Runtime Error', 'Accepted']
['s151658977', 's379801883', 's197875008']
[3060.0, 3064.0, 3060.0]
[18.0, 17.0, 20.0]
[320, 386, 307]
p03102
u263830634
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
["N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\ni = 0\ncount = 0\nwhile i < N:\n A = list(map(int, input().split()))\n# print ('A', A)\n j = 1\n ans = C\n while j <= M:\n ans += A[j-1] * B[j-1]\n j += 1\n# print (ans)\n if ans > 0:\n count += 1\n i += 1\nprint ('Count', count) ", "N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\ni = 0\ncount = 0\nwhile i < N:\n A = list(map(int, input().split()))\n# print ('A', A)\n j = 1\n ans = C\n while j <= M:\n ans += A[j-1] * B[j-1]\n j += 1\n# print (ans)\n if ans > 0:\n count += 1\n i += 1\nprint (count) "]
['Wrong Answer', 'Accepted']
['s637063321', 's000832053']
[3064.0, 3188.0]
[18.0, 19.0]
[334, 325]
p03102
u273326224
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\nA = [list(map(int, input().split())) for i in range(N)]\n\ncount = 0\nfor n in range(N):\n sum = C\n for m in range(M):\n sum += b[m]*a[n][m]\n if sum > 0:\n count += 1\nprint(count)', 'N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\nA = [list(map(int, input().split())) for i in range(N)]\ncount=0\nfor n in range(N):\n sum = C\n for m in range(M):\n sum += B[m]*A[n][m]\n if sum > 0:\n count+= 1\nprint(count)']
['Runtime Error', 'Accepted']
['s157403629', 's052945558']
[3060.0, 3060.0]
[17.0, 17.0]
[254, 264]
p03102
u276115223
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['# ABC 121: B – Can you solve this?\nn, m, c = [int(s) for s in input().split()]\nb = [int(s) for s in input().split()]\n\na = []\nfor _ in range(n):\n a.append([int(s) for s in input().split()])\n\ncounter = 0\n\nfor i in range(n):\n answer = c\n \n for j in range(m):\n answer += a[i][j] * b[j]\n\n if answer > 0:\n print(i, answer)\n counter += 1\n\nprint(counter)', '# ABC 121: B – Can you solve this?\nN, M, C = [int(s) for s in input().split()]\nB = [int(s) for s in input().split()]\nA = [[int(s) for s in input().split()] for _ in range(N)]\n\nexacts = 0\n\nfor i in range(N):\n value = C\n \n for j in range(M):\n value += A[i][j] * B[j]\n \n if value > 0:\n exacts += 1\n\nprint(exacts)']
['Wrong Answer', 'Accepted']
['s262968051', 's761904867']
[3064.0, 3064.0]
[19.0, 18.0]
[384, 340]
p03102
u290187182
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
["import sys\nimport copy\nimport math\nimport bisect\nimport pprint\nimport bisect\nfrom functools import reduce\nfrom copy import deepcopy\nfrom collections import deque\nfrom decimal import *\n\n\ndef lcm(x, y):\n return (x * y) // math.gcd(x, y)\n\n\nif __name__ == '__main__':\n n,m,c = map(int, input().split())\n b = [int(i) for i in input().split()]\n\n count = 0\n for i in range(n):\n num=0\n a = [int(i) for i in input().split()]\n \n for i in range(m):\n num +=a[i] *b[i]\n if num >c:\n count+=1\n print(count)\n", "import sys\nimport copy\nimport math\nimport bisect\nimport pprint\nimport bisect\nfrom functools import reduce\nfrom copy import deepcopy\nfrom collections import deque\nfrom decimal import *\n\n\ndef lcm(x, y):\n return (x * y) // math.gcd(x, y)\n\n\nif __name__ == '__main__':\n n,m,c = map(int, input().split())\n b = [int(i) for i in input().split()]\n\n count = 0\n for i in range(n):\n num=0\n a = [int(i) for i in input().split()]\n\n for i in range(m):\n num +=a[i] *b[i]\n if num >c*(-1):\n count+=1\n print(count)\n"]
['Wrong Answer', 'Accepted']
['s956290917', 's953658991']
[5144.0, 5136.0]
[35.0, 36.0]
[567, 564]
p03102
u295120316
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = int(input())\nB = list(map(int, inpot().split()))\ncount = 0\nfor j in range(N)\n A = list(map(int, input().split()))\n\nfor i in range(M):\n calc = A[i] * B[i]\n if C + calc > 0\n count+=1\n\nprint(count) \n \n \n', 'N, M, C = int(input())\nB = list(map(int, inpot().split()))\ncount = 0\nfor j in range(N)\n A = list(map(int, input().split()))\n\nfor i in range(M):\n calc = A[i] * B[i]\n if C + calc > 0:\n count+=1\n\nprint(count) \n \n \n', 'N, M, C = int(input())\nB = list(map(int, inpot().split()))\ncount = 0\nfor j in range(N)\n A = list(map(int, input().split()))\n\nfor i in range(M):\n calc = A[i] * B[i]\n if C + calc > 0\n count+=1\n\nprint(count) \n \n \n', 'N, M, C = int(input())\nB = list(map(int, inpot().split()))\ncount = 0\nfor j in range(N)\n A = list(map(int, input().split()))\n\nfor i in range(N):\n calc = A[i] * B[i]\n if C + calc > 0\n count+=1\n\nprint(count) \n \n ', 'N, M, C = int(input())\nB = list(map(int, inpot().split()))\ncount = 0\nfor j in range(N):\n A = list(map(int, input().split()))\ncalc = 0\nfor i in range(M):\n calc = A[i] * B[i]\n if C + calc > 0:\n count+=1\n\nprint(count) \n \n \n', 'N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\ncalc = 0\nans = 0\n\nfor i in range(N):\n A = list(map(int,input().split()))\n calc = 0\n for j in range(M):\n calc += A[j] * B[j]\n\n if calc + C > 0:\n ans += 1\n\nprint(ans)\n']
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s363319215', 's479193265', 's488131794', 's576443395', 's759790343', 's882485733']
[3064.0, 2940.0, 2940.0, 2940.0, 3060.0, 3060.0]
[17.0, 17.0, 17.0, 19.0, 18.0, 17.0]
[237, 238, 237, 236, 247, 263]
p03102
u298373736
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['# S = input()\n\n\nn,m,c=map(int,input().split())\nb=list(map(int,input().split()))\ne = [[int(i) for i in input().split()] for i in range(n)]\n\ntotal=0\ncount=0\n\n\nfor j in range(0,n):\n\ttotal=0\n\tfor k in range(0,m):\n\t\ttotal+=e[j][k]*b[k]\n\t\tprint("total is ",total)\n\tif total+c>0:\n\t\tcount+=1\n\nprint(count)\n', '# S = input()\n\n\nn,m,c=map(int,input().split())\nb=list(map(int,input().split()))\ne = [[int(i) for i in input().split()] for i in range(n)]\n\ntotal=0\ncount=0\n\n\nfor j in range(0,n):\n\ttotal=0\n\tfor k in range(0,m):\n\t\ttotal+=e[j][k]*b[k]\n\tif total+c>0:\n\t\tcount+=1\n\nprint(count)\n']
['Wrong Answer', 'Accepted']
['s469803767', 's257310021']
[3188.0, 3060.0]
[18.0, 17.0]
[347, 320]
p03102
u302292660
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\ncnt = 0\nfor i in range(n):\n a = list(map(int,input().split()))\n for j in range(m):\n sum = 0\n sum += (a[j]*b[j])\n sum += c\n if sum > 0:\n cnt += 1\n else:\n pass\nprint(cnt)', 'n,m,c = map(int,input().split())\nb = map(int,input().split())\ncnt = 0\nsum = 0\nfor i in range(n):\n a = map(int,input().split())\n for j in range(m):\n sum += (a[j]*b[j])\n sum += c\n if sum > 0:\n cnt += 1\n else:\n pass\nprint(cnt)', 'n,m,c = map(int,input().split())\nb = map(int,input()split())\ncnt = 0\nsum = 0\nfor i in range(n):\n a = map(int,input().split())\n for j in range(m):\n sum += (a[j]*b[j])\n sum += c\n if sum > 0:\n cnt += 1\n else:\n pass\nprint(cnt)', 'n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\ncnt = 0\nfor i in range(n):\n a = list(map(int,input().split()))\n sum = 0\n for j in range(m):\n sum += (a[j]*b[j])\n sum += c\n if sum > 0:\n cnt += 1\n else:\n pass\nprint(cnt)']
['Wrong Answer', 'Runtime Error', 'Runtime Error', 'Accepted']
['s012223563', 's421426779', 's892190862', 's508465711']
[3064.0, 3060.0, 2940.0, 3064.0]
[17.0, 17.0, 17.0, 17.0]
[253, 237, 238, 251]
p03102
u305018585
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
["N, M, C = map(int,input().split(' '))\nimport numpy as np\nB = np.array(list(map(int,input().split(' '))))\ndef f(A, B, C):\n A = np.array(list(map(int,A.split(' '))))\n return np.sum(A*B) +C > 0\nprint(", "N, M, C = map(int,input().split(' '))\nimport numpy as np\nB = np.array(list(map(int,input().split(' '))))\ndef f(A, B, C):\n A = np.array(list(map(int,A.split(' '))))\n return np.sum(A*B) +C > 0\nprint(np.sum([f(input(), B, C) for i in range(N)]))"]
['Runtime Error', 'Accepted']
['s541964023', 's175138858']
[2940.0, 12452.0]
[17.0, 149.0]
[204, 249]
p03102
u312748806
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['import numpy as np\nn, m, c = list(map(int, input().split()))\nb = np.array(list(map(int, input().split())))\ncount = 0\nprint(b)\nfor i in range(n):\n a = np.array(list(map(int, input().split())))\n result = sum(a*b) + c\n print(result)\n if result > 0:\n count += 1\nprint(count)', 'import numpy as np\nn, m, c = list(map(int, input().split()))\nb = np.array(list(map(int, input().split())))\ncount = 0\nfor i in range(n):\n a = np.array(list(map(int, input().split())))\n result = sum(a*b) + c\n if result > 0:\n count += 1\nprint(count)']
['Wrong Answer', 'Accepted']
['s206497864', 's320009532']
[20772.0, 14440.0]
[374.0, 150.0]
[289, 262]
p03102
u313403396
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C = map(int,input().split())\nB = list(map(int,input().split()))\nans = 0\nfor i in range(N):\n A = list(map(int,input().split()))\n if sum(A*B) + C > 0:\n ans += 1\nprint(ans)', 'N,M,C = map(int,input().split())\nB = list(map(int,input().split()))\nans = 0\nfor i in range(N):\n A = list(map(int,input().split()))\n tmp = 0\n for j in range(M):\n tmp += A[j]*B[j]\n if tmp + C > 0:\n ans += 1\nprint(ans)\n']
['Runtime Error', 'Accepted']
['s649783609', 's883495017']
[9128.0, 9116.0]
[26.0, 28.0]
[178, 226]
p03102
u316322317
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c=map(int,input().split())\nb=list(int,input())\na=[list(map(int,input().split())) for i in range(n)]\ncount=0\nfor i in range(n):\n sum=c\n for j in range(m):\n sum+=a[i,j]*b[j]\n if sum>0:\n sum+=1\nprint(sum)', 'n,m,c=map(int,input().split())\na=[list(map(int,input().split())) for i in range(n+1)]\ncount=0\nfor i in range(n):\n sum=c\n for j in range(m):\n sum+=a[i+1][j]*a[0][j]\n if sum>0:\n count+=1\nprint(count)\n']
['Runtime Error', 'Accepted']
['s362441598', 's401067477']
[3060.0, 3060.0]
[17.0, 17.0]
[214, 207]
p03102
u327668449
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['NMC = list(map(lambda x: int(x), input().split()))\nN = NMC[0]\nM = NMC[1]\nC = NMC[2]\n\nB = list(map(lambda x: int(x), input().split()))\nA = [list(map(lambda x: int(x), input().split())) for i in range(N)]\n\nprint("B", B)\nprint("A", A)\nprint("N", N)\nprint("M", M)\nprint("C", C)\n\nanswer = 0\n\nfor i in range(len(A)):\n judge = 0\n for m in range(len(A[i])):\n judge += A[i][m] * B[m]\n\n print("judge", judge)\n if (judge + C > 0):\n answer += 1\n\nprint(answer)', 'NMC = list(map(lambda x: int(x), input().split()))\nN = NMC[0]\nM = NMC[1]\nC = NMC[2]\n\nB = list(map(lambda x: int(x), input().split()))\nA = [list(map(lambda x: int(x), input().split())) for i in range(N)]\n\nanswer = 0\n\nfor i in range(len(A)):\n judge = 0\n for m in range(len(A[i])):\n judge += A[i][m] * B[m]\n if (judge + C > 0):\n answer += 1\n\nprint(answer)']
['Wrong Answer', 'Accepted']
['s701109246', 's296652014']
[3064.0, 3064.0]
[18.0, 18.0]
[457, 361]
p03102
u331997680
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['import numpy as np\nN, M, C = map(int, input().split())\nB = list(map(int, input().split()))\nA = [ ]\nfor i in range(N):\n AA = list(map(int, input().split()))\n A.append(AA)\nBnp = np.array(B)\nAnp = np.array(A)\nC = np.dot(Anp, Bnp) + 10\nD = 0\nfor i in range(N):\n if C[i] > 0:\n D += 1\nprint(D)', 'import numpy as np\nN, M, C = map(int, input().split())\nB = list(map(int, input().split()))\nA = [ ]\nfor i in range(N):\n AA = list(map(int, input().split()))\n A.append(AA)\nBnp = np.array(B)\nAnp = np.array(A)\nC = np.dot(Anp, Bnp) - C\nD = 0\nfor i in range(N):\n if C[i] > 0:\n D += 1\nprint(D)', 'import numpy as np\nN, M, C = map(int, input().split())\nB = list(map(int, input().split()))\nA = [ ]\nfor i in range(N):\n AA = list(map(int, input().split()))\n A.append(AA)\nBnp = np.array(B)\nAnp = np.array(A)\nC = np.dot(Anp, Bnp) + C\nD = 0\nfor i in range(N):\n if C[i] > 0:\n D += 1\nprint(D)']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s144844689', 's806437973', 's146245472']
[12508.0, 12508.0, 12508.0]
[152.0, 151.0, 155.0]
[293, 292, 292]
p03102
u333404917
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = map(int, input().split())\nb = [int(x) for x in input().split()]\nans = 0\nfor _ in range(n):\n if sum([b[i] * int(x) for i, x in enumerate(input().split())]) > c:\n ans += 1\nprint(ans)', 'n, m, c = map(int, input().split())\nb = [int(x) for x in input().split()]\nans = 0\nfor _ in range(n):\n if sum([b[i] * int(x) for i, x in enumerate(input().split())]) + c > 0:\n ans += 1\nprint(ans)']
['Wrong Answer', 'Accepted']
['s175609423', 's089091569']
[3060.0, 3060.0]
[17.0, 17.0]
[194, 204]
p03102
u334535590
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = [int(_) for _ in input().split()]\nb = [int(_) for _ in input().split()]\na = [[int(_) for _ in input().split()] for i in range(n)]\nsum = 0\ncnt = 0\nfor i in range(n):\n sum = 0\n for j in range(m):\n sum = a[i][j] * b[j] + c\n if sum > 0:\n cnt += 1\nprint(cnt)', 'n, m, c = [int(_) for _ in input().split()]\nb = [int(_) for _ in input().split()]\na = [[int(_) for _ in input().split()] for i in range(n)]\nsum = 0\ncnt = 0\nfor i in range(n):\n sum = 0\n for j in range(m):\n sum += a[i][j] * b[j]\n if sum + c > 0:\n cnt += 1\nprint(cnt)\n']
['Wrong Answer', 'Accepted']
['s874959198', 's709624979']
[3064.0, 3060.0]
[17.0, 18.0]
[272, 274]
p03102
u342051078
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\nans = 0\nfor i in range(n):\n a = list(map(int,input().split()))\n num = 0\n for j in range(m):\n num += a[j]*b[j]\n num += C\n if num > 0:\n ans += 1\nprint(ans)', 'n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\nans = 0\nfor i in range(n):\n a = list(map(int,input().split()))\n num = 0\n for j in range(m):\n num += a[j]*b[j]\n num += c\n if num > 0:\n ans += 1\nprint(ans)']
['Runtime Error', 'Accepted']
['s861553694', 's966891507']
[3064.0, 3060.0]
[17.0, 18.0]
[250, 250]
p03102
u350093546
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\ncount=0\nx=0\nfor i in range(n):\n lst=list(map(int,input().split()))\n for j in range(m):\n x+=lst[j]*b[j]\n if x-c>0:\n count+=1\nprint(count)', 'n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\nresult=0\nfor i in range(n):\n a=list(map(int,input().split()))\n cnt=c\n for j in range(m):\n cnt+=a[j]*b[j]\n if cnt>0:\n result+=1\nprint(result)']
['Wrong Answer', 'Accepted']
['s918362286', 's262053726']
[3060.0, 3060.0]
[17.0, 17.0]
[209, 214]
p03102
u357949405
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split())\nB = [int(i) for i in input().split()]\nans = 0\nfor _ in range(N):\n A = [B[i] * int(j) for i,j in enumerate(input().split())]\n ans += 1 if sum(A) > 0 else 0\nprint(ans)', 'N, M, C = map(int, input().split())\nB = [int(i) for i in input().split()]\nans = 0\nfor _ in range(N):\n A = [B[i] * int(j) for i,j in enumerate(input().split())]\n ans += 1 if sum(A) + C > 0 else 0\nprint(ans)']
['Wrong Answer', 'Accepted']
['s302884641', 's197029266']
[3060.0, 3060.0]
[17.0, 17.0]
[203, 207]
p03102
u363836311
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c=map(int, input().split())\nB=list(map(int, input().split()))\ng=0\nfor i in range(n):\n A=list(map(int, input().split()))\n for i in range(m):\n t=A[i]*B[i]\n if t+c>0:\n g+=1\nprint(g)', 'n,m,c=map(int, input().split())\nB=list(map(int, input().split()))\ng=0\nfor i in range(n):\n A=list(map(int, input().split()))\n for i in range(m):\n t+=A[i]*B[i]\n if t+c>0:\n g+=1\n t=0\nprint(g)', 'n,m,c=map(int, input().split())\nB=list(map(int, input().split()))\ng=0\nt=0\nfor i in range(n):\n A=list(map(int, input().split()))\n for i in range(m):\n t+=A[i]*B[i]\n if t+c>0:\n g+=1\n t=0\nprint(g)\n']
['Wrong Answer', 'Runtime Error', 'Accepted']
['s614592194', 's717575461', 's326486966']
[2940.0, 3060.0, 3060.0]
[17.0, 18.0, 17.0]
[195, 198, 203]
p03102
u368016155
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C = map(int, input().split())\nB = [int(_) for _ in input().split()]\n\ncount = 0\nfor i in range(N):\n A = [int(_) for _ in input().split()] \n sum = 0\n for j in range(M):\n sum = B[j]*A[j]\n if sum-C > 0:\n count += 1\n\nprint(count)', 'N,M,C = map(int, input().split())\nB = [int(_) for _ in input().split()]\n\ncount = 0\nfor i in range(len(N)):\n A = [_ for _ in input().split()] \n sum = 0\n for j in range(M):\n sum = B[j]*A[j]\n if sum-C > 0:\n count += 1\n\nprint(count)', 'N,M,C = map(int, input().split())\nB = [int(_) for _ in input().split()]\n\ncount = 0\nfor i in range(len(N)):\n A = [int(_) for _ in input().split()] \n sum = 0\n for j in range(M):\n sum = B[j]*A[j]\n if sum-C > 0:\n count += 1\n\nprint(count)', 'N,M,C = map(int, input().split())\nB = [int(_) for _ in input().split()]\n\ncount = 0\nfor i in range(N):\n A = [int(_) for _ in input().split()] \n sum = 0\n for j in range(M):\n sum += B[j]*A[j]\n if sum-C > 0:\n count += 1\n\nprint(count)', 'N,M,C = map(int, input().split())\nB = [int(_) for _ in input().split()]\n\ncount = 0\nfor i in range(N):\n A = [int(_) for _ in input().split()] \n sum = 0\n for j in range(M):\n sum += B[j]*A[j]\n if sum+C > 0:\n count += 1\n\nprint(count)']
['Wrong Answer', 'Runtime Error', 'Runtime Error', 'Wrong Answer', 'Accepted']
['s149007036', 's358601885', 's553750152', 's883056442', 's729003621']
[3060.0, 3060.0, 3060.0, 3060.0, 3060.0]
[17.0, 17.0, 18.0, 17.0, 17.0]
[238, 238, 243, 239, 239]
p03102
u368796742
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\ncount = 0\nans = 0\nfor i in range(n):\n l = list(map(int,input().split()))\n for j in range(m):\n ans += b[j]*a[j]\n if ans +c > 0:\n count += 1\n \n ans = 0\nprint(count)\n', 'n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\ncount = 0\nans = 0\nfor i in range(n):\n l = list(map(int,input().split()))\n for j in range(m):\n ans += b[j]*a[j]\n if ans +c > 0:\n count += 1\n \n ans = 0\nprint(count', 'n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\ncount = 0\nans = 0\nfor i in range(n):\n l = list(map(int,input().split()))\n for j in range(m):\n ans += b[j]*l[j]\n if ans +c > 0:\n count += 1\n \n ans = 0\nprint(count)\n']
['Runtime Error', 'Runtime Error', 'Accepted']
['s209124704', 's773429218', 's582643183']
[3060.0, 3060.0, 3060.0]
[17.0, 17.0, 17.0]
[244, 242, 244]
p03102
u371409687
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\nCount=0\nfor i in range(n):\n a=list(map(int,input().split()))\n for j in range(m):\n Sum+=a[j]*b[j]\n if Sum>-1*c:\n Count+=1\n Sum=0\nprint(Count)', 'n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\na=[list(map(int,input().split())) for _ in range(n)]\nCount=0\nfor t in a:\n for i in range(m):\n Sum+=t[i]*b[i]\n if Sum+c>0:\n Count+=1\n Sum=0\nprint(Count)', 'n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\na=[list(map(int,input().split())) for _ in range(n)]\nCount=0\nfor t in a:\n Sum=0\n for i in range(m):\n Sum+=t[i]*b[i]\n if Sum+c>0:\n Count+=1\nprint(Count)']
['Runtime Error', 'Runtime Error', 'Accepted']
['s197389247', 's880269945', 's053485637']
[3060.0, 3060.0, 3064.0]
[18.0, 18.0, 18.0]
[230, 238, 238]
p03102
u374051158
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\nA = [list(map(int, input().split())) for _ in range(N)]\n\ncnt = 0\n\nfor a in A:\n print(sum([ta * tb for ta, tb in zip(a, B)]) + C)\n \n if(sum([ta * tb for ta, tb in zip(a, B)]) + C > 0):\n cnt += 1\n\nprint(cnt)', 'N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\nA = [list(map(int, input().split())) for _ in range(N)]\n \ncnt = 0\n \nfor a in A:\n \n if(sum([ta * tb for ta, tb in zip(a, B)]) + C > 0):\n cnt += 1\n \nprint(cnt)']
['Wrong Answer', 'Accepted']
['s699444338', 's187759840']
[3064.0, 3064.0]
[18.0, 17.0]
[293, 242]
p03102
u375282392
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\n#a = []\ncount = 0\nfor i in range(n):\n\ta = list(map(int,input().split()))\n tokuten = 0\n\tfor j in range(m):\n\t\ttokuten += b[j]*a[j]\n\tif tokuten > c:\n\t\tcount += 1\n\nprint(count)', 'n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\ncount = 0\nfor i in range(n):\n\ta = list(map(int,input().split()))\n\ttokuten = 0\n\tfor j in range(m):\n\t\ttokuten += b[j]*a[j]\n\tif tokuten > c:\n\t\tcount += 1\n\nprint(count)', 'n,m,c = map(int,input().split())\nb = list(map(int,input().split()))\ncount = 0\nfor i in range(n):\n\ta = list(map(int,input().split()))\n\ttokuten = 0\n\tfor j in range(m):\n\t\ttokuten += b[j]*a[j]\n\tif tokuten > -c:\n\t\tcount += 1\n\nprint(count)']
['Runtime Error', 'Wrong Answer', 'Accepted']
['s117505204', 's476798051', 's217121989']
[2940.0, 3060.0, 3060.0]
[17.0, 17.0, 17.0]
[243, 232, 233]
p03102
u375616706
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['# python template for atcoder1\nimport sys\nsys.setrecursionlimit(10**9)\ninput = sys.stdin.readline\n\n\ndef f(a):\n """\n xor [0,a]\n """\n ans = 0\n l = []\n d = 2\n while (a+1)//d > 0:\n t = (a+1)//d*(d//2)+max((a+1) % d-d//2, 0)\n ans += (t % 2)*(d//2)\n l.append(t % 2)\n d *= 2\n ans += (((a+1)-d) % 2)*(d//2)\n l.append(((a+1)-d) % 2)\n return l\n\n\ndef solve2(a, b):\n rb = f(b)\n ra = f(a-1)\n for i in range(len(ra)):\n rb[i] ^= ra[i]\n ans = "".join(map(str, reversed(rb)))\n print(int(ans, 2))\n\n\nA, B = map(int, input().split())\nif A == 0 and B == 0:\n print(0)\nelse:\n solve2(A, B)\n', '# python template for atcoder1\nimport sys\nsys.setrecursionlimit(10**9)\ninput = sys.stdin.readline\n\n\nN, M, C = map(int, input().split())\nB = list(map(int, input().split()))\n\ncnt = 0\nfor _ in range(N):\n A = list(map(int, input().split()))\n s = sum([a*b for a, b in zip(A, B)])\n if s+C > 0:\n cnt += 1\nprint(cnt)\n']
['Runtime Error', 'Accepted']
['s940602710', 's675272793']
[3064.0, 3060.0]
[17.0, 17.0]
[652, 325]
p03102
u387080888
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['a=tuple(map(int,input().split()))\nb=[]\nfor i in range(a[0]+1):\n b.append(list(map(int,input().split())))\nans=0\ns=0\nfor j in range(a[0])[1:a[0]+1]:\n for k in range(a[1]):\n s+=b[j][k]*b[0][k]\n s+=a[2]\n if s>0:\n ans+=1\n s=0\nprint(ans)', 'a=tuple(map(int,input().split()))\nb=[]\nfor i in range(a[0]+1):\n b.append(list(map(int,input().split())))\nans=0\ns=0\nfor j in range(a[0])[1:a[0]]:\n for k in range(a[1]):\n s+=b[j][k]*b[0][k]\n s+=a[2]\n if s>0:\n ans+=1\n s=0\nprint(ans)', 'a=tuple(map(int,input().split()))\nb=[]\nfor i in range(a[0]+1):\n b.append(list(map(int,input().split())))\nans=0\ns=0\nfor j in range(a[0]+1)[1:a[0]+1]:\n for k in range(a[1]):\n s+=b[j][k]*b[0][k]\n s+=a[2]\n if s>0:\n ans+=1\n s=0\nprint(ans)']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s484207407', 's567809978', 's764102044']
[3064.0, 3064.0, 3064.0]
[18.0, 17.0, 18.0]
[260, 258, 262]
p03102
u391819434
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C=input().split();*B,=input().split();print(sum(sum(int(a)*int(b) for a,b in zip(i.split(),B))+int(C)>0 for i in open(0)))', 'N,M,C=input().split()\n*B,=input().split()\nprint(sum(sum(int(a)*int(b) for a,b in zip(i.split(),B))+int(C)>0 for i in open(0)))', 'N,M,C=map(int,input().split())\n*B,=map(int,input().split())\n\nans=0\nfor i in range(N):\n ans+=1*(sum(a*b for a,b in zip(map(int,input().split()),B))+C>0)\n\nprint(ans)']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s596648984', 's690877521', 's427719212']
[2940.0, 2940.0, 3060.0]
[17.0, 17.0, 17.0]
[126, 126, 166]
p03102
u393481615
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = list(map(int, input().split()))\nB = list(map(int, input().split()))\nA = list([])\nfor i in range(N):\n A.append(list(map(int, input().split())))\n\ncnt = 0\nfor i in range(N):\n print("A= " + str(A[i]))\n print("B= " + str(B))\n print("C= " + str(C))\n ev = 0\n for j in range(M):\n ev = ev + A[i][j] * B[j]\n ev = ev + C\n if(ev > 0):\n cnt = cnt + 1\n\nprint(cnt)\n', 'N, M, C = list(map(int, input().split()))\nB = list(map(int, input().split()))\nA = list([])\nfor i in range(N):\n A.append(list(map(int, input().split())))\n\ncnt = 0\nfor i in range(N):\n# print("A= " + str(A[i]))\n\n# print("C= " + str(C))\n ev = 0\n for j in range(M):\n ev = ev + A[i][j] * B[j]\n ev = ev + C\n if(ev > 0):\n cnt = cnt + 1\n\nprint(cnt)\n']
['Wrong Answer', 'Accepted']
['s209576664', 's522014628']
[3064.0, 3064.0]
[17.0, 19.0]
[398, 401]
p03102
u395237353
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\ncount = 0\nfor i in range(N):\n A = list(map(int, input().split()))\n x = C\n for index, val in enumerate(B):\n x += A[index] * val\n if x > 0:\n count += 1\n print(x)\nprint(count)\n', 'N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\ncount = 0\nfor i in range(N):\n A = list(map(int, input().split()))\n x = C\n for index, val in enumerate(B):\n x += A[index] * val\n if x > 0:\n count += 1\nprint(count)\n']
['Wrong Answer', 'Accepted']
['s568666358', 's124806092']
[3060.0, 3060.0]
[18.0, 18.0]
[274, 261]
p03102
u396971285
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C=map(int, input().split())\n\n\n\n\nB=list(map(int,input.split()))\nA=[]\nfor i in range(N):\n a=map(int,input().split())\n A.append(a)\n \nans=0\nx=0\nfor i in range(N):\n for j in range(M):\n ans+=A[i][j]*B[j]\n if ans+C>0:\n x+=1\n\nprint(x)', 'N,M,C=map(int, input().split())\n\n\n\n\nB=list(map(int,input().split()))\nA=[]\nfor i in range(N):\n a=list(map(int,input().split()))\n A.append(a)\n \nx=0\nfor i in range(N):\n ans=0\n for j in range(M):\n ans+=A[i][j]*B[j]\n if ans+C>0:\n x+=1\n\n\nprint(x)\n']
['Runtime Error', 'Accepted']
['s672673175', 's608789612']
[3064.0, 3064.0]
[17.0, 17.0]
[334, 346]
p03102
u404676457
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\ncount = 0\nfor i in range(n):\n a = list(map(int, input().split()))\n z = 0\n for j in range(m):\n z += b[j] * a[j]\n if z + c >= 0:\n count += 1\nprint(count)', 'n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\ncount = 0\nfor i in range(n):\n a = list(map(int, input().split()))\n z = 0\n for j in range(m):\n z += b[j] * a[j]\n if z + c > 0:\n count += 1\nprint(count)']
['Wrong Answer', 'Accepted']
['s327390704', 's534732167']
[3060.0, 3188.0]
[17.0, 20.0]
[249, 248]
p03102
u409542115
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split()) \nB = list(map(int, input().split()))\n \nS = [[0]*M for i in range(N)]\nfor i in range:\n S[i] = list(map(int, input().split()))\n\nb = 0\n \nfor i in range(N):\n a = 0\n for ii in range(M):\n a += S[i][ii] * B[ii]\n a += C\n if a > 0:\n b += 1\nprint(str(b))', 'N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\n \nS = [[0]*M for i in range(N)]\nfor i in range:\n S[i] = list(map(int, input().split()))\n \nb = 0\n \nfor i in range:\n a = 0\n for ii in range(M):\n a += S[i][ii] * B[ii]\n a += C\n if a > 0:\n b += 1\n \nprint(str(b))', 'N, M, C = map(int, input().split()) \nB = list(map(int, input().split()))\n \nS = [[0]*M for i in range(N)]\nfor i in range:\n S[i] = list(map(int, input().split()))\n \nb = 0\n \nfor i in range:\n a = 0\n for ii in range(M):\n a += S[i][ii] * B[ii]\n a += C\n if a > 0:\n b += 1\n \nprint(str(b))', 'N, M, C = map(int, input().split()) \nB = list(map(int, input().split()))\n \nS = [[0]*M for i in range(N)]\nfor i in range:\n S[i] = list(map(int, input().split()))\n \nb = 0\n \nfor i in range:\n a = 0\n for ii in range(M):\n a += S[i][ii] * B[ii]\n a += C\n if a > 0:\n b += 1\n \nprint(str(b))', 'N, M, C = map(int, input().split()) \nB = list(map(int, input().split()))\n \nS = [[0]*M for i in range(N)]\nfor i in range(N):\n S[i] = list(map(int, input().split()))\n \nb = 0\n \nfor i in range(N):\n a = 0\n for ii in range(M):\n a += S[i][ii] * B[ii]\n a += C\n if a > 0:\n b += 1\n \nprint(str(b))']
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s309010106', 's319241365', 's674278402', 's682975029', 's220747144']
[3064.0, 3064.0, 3064.0, 3064.0, 3064.0]
[18.0, 17.0, 17.0, 17.0, 18.0]
[429, 308, 429, 429, 435]
p03102
u416223629
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['NMC = list(map(int,input().split()))\nN=NMC[0]\nM=NMC[1]\nC=NMC[2]\nB=list(map(int,input().split()))\nA = [list(map(int,input().split())) for l in range(N)]\ncnt=0\nsummary=0\nfor i in range(N):\n for j in range(M):\n summary=A[i][j]*B[j]+summary\n summary=summary+C\n print(summary)\n if summary>0:\n cnt=cnt+1\n\nprint(cnt)\n', 'NMC = list(map(int,input().split()))\nN=NMC[0]\nM=NMC[1]\nC=NMC[2]\nB=list(map(int,input().split()))\nA = [list(map(int,input().split())) for l in range(N)]\ncnt=0\n\nfor i in range(N):\n summary=0\n for j in range(M):\n summary=A[i][j]*B[j]+summary\n summary=summary+C\n if summary>0:\n cnt=cnt+1\n\nprint(cnt)\n']
['Wrong Answer', 'Accepted']
['s673792132', 's230130745']
[3316.0, 3064.0]
[24.0, 17.0]
[336, 322]
p03102
u426108351
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\nans = 0\nfor i in range(N):\n a = list(map(int, input().split()))\n point = c\n for i in range(m):\n point += a[i]*b[i]\n if point > 0:\n ans += 1\nprint(ans)', 'n, m, c = map(int, input().split())\nb = list(map(int, input().split()))\nans = 0\nfor i in range(n):\n a = list(map(int, input().split()))\n point = c\n for i in range(m):\n point += a[i]*b[i]\n if point > 0:\n ans += 1\nprint(ans)']
['Runtime Error', 'Accepted']
['s901929315', 's141318770']
[3060.0, 3060.0]
[19.0, 17.0]
[232, 232]
p03102
u433380437
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['\n# ABC121 B - Can you solve this?\n\nn,m,c=map(int,input().split())\nB = np.array(list(map(int,input().split())))\nK=[]\nfor i in range(n):\n A = list(map(int,input().split()))\n K.append(A)\n\nimport numpy as np\npp = np.array(K)\nl = (pp*B).sum(axis=1)+c\n\nt = 0\nfor i in range(len(l)):\n if l[i] > 0:\n t+=1\nprint(t)\n', '\n# ABC121 B - Can you solve this?\n\nimport numpy as np\n\nn,m,c=map(int,input().split())\nB = np.array(list(map(int,input().split())))\nK=[]\nfor i in range(n):\n A = list(map(int,input().split()))\n K.append(A)\n\npp = np.array(K)\nl = (pp*B).sum(axis=1)+c\n\nt = 0\nfor i in range(len(l)):\n if l[i] > 0:\n t+=1\nprint(t)\n']
['Runtime Error', 'Accepted']
['s569338820', 's272380867']
[9124.0, 27276.0]
[24.0, 123.0]
[332, 333]
p03102
u434282696
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['import numpy as np\nN,M,C = (int(j) for j in input().split())\nB = [int(j) for j in input().split()]\nlist = [[0]* M]*N\nfor j in range(0,N):\n list[j] = [int(k) for k in input().split()]\ncount = 0\nfor j in range(0,N):\n if np.sum(np.array(list[j]) * np.array(B)) C >0:\n count = count + 1\nprint(count)', 'import numpy as np\nN,M,C = (int(j) for j in input().split())\nB = [int(j) for j in input().split()]\nlist = [[0]* M]*N\nfor j in range(0,N):\n list[j] = [int(k) for k in input().split()]\ncount = 0\nfor j in range(0,N):\n if np.sum(np.array(list[j]) * np.array(B)) + C > 0:\n count = count + 1\nprint(count)']
['Runtime Error', 'Accepted']
['s750333041', 's549917206']
[2940.0, 12432.0]
[17.0, 151.0]
[312, 315]
p03102
u439312138
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['from operator import mul\n\nN,M,C = map(int,input().split())\n\nB_list = list(map(int,input().split()))\n\nans = 0\n\nfor i in range(N):\n tmplist = list(map(int,input().split()))\n \n combined = list(map(mul,B_list,tmplist))\n if sum(combined) + C >= 0:\n ans += 1\n\nprint(ans)\n ', 'from operator import mul\n\nN,M,C = map(int,input().split())\n\nB_list = list(map(int,input().split()))\n\nans = 0\n\nfor i in range(N):\n tmplist = list(map(int,input().split()))\n \n combined = list(map(mul,B_list,tmplist))\n print(combined)\n if sum(combined) + C > 0:\n ans += 1\n\nprint(ans)\n ', 'from operator import mul\n\nN,M,C = map(int,input().split())\n\nB_list = list(map(int,input().split()))\n\nans = 0\n\nfor i in range(N):\n tmplist = list(map(int,input().split()))\n \n combined = list(map(mul,B_list,tmplist))\n\n if sum(combined) + C > 0:\n ans += 1\n\nprint(ans)\n ']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s386895198', 's817508417', 's636143902']
[3060.0, 3060.0, 3060.0]
[18.0, 18.0, 18.0]
[277, 294, 277]
p03102
u439392790
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\nfor i in range(n):\n a=list(map(int,input().split()))\nans=0\nfor i in range(n):\n C=c\n for j in range(m):\n C=C+a[i][j]*b[j]\n if C>0:\n ans=ans+1\nprint(ans)\n \n ', 'n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\nfor d in range(n):\n a=[list(map(int,input().split()))]\nans=0\nfor i in range(n):\n C=c\n for j in range(m):\n C+=a[i][j]*b[j]\n if C>0:\n ans+=1\nprint(ans)\n', 'n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\na=[list(map(int,input().split())) for d in range(n)]\nans=0\nfor i in range(n):\n C=c\n for j in range(m):\n C+=a[i][j]*b[j]\n if C>0:\n ans+=1\nprint(ans)\n']
['Runtime Error', 'Runtime Error', 'Accepted']
['s143345698', 's185188684', 's186421346']
[3060.0, 3060.0, 3064.0]
[18.0, 17.0, 18.0]
[237, 238, 235]
p03102
u440161695
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C=map(int,input().split())\nB=list(map(int,input().split()))\nans=0\nfor i in range(N):\n A=list(map(int,input().split()))\n d=0\n for j,k in zip(A,B):\n d+=A*B\n if d>-C:\n ans+=1\nprint(ans)\n ', 'N,M,C=map(int,input().split())\nB=list(map(int,input().split()))\nans=0\nfor i in range(N):\n A=list(map(int,input().split()))\n d=0\n for j,k in zip(A,B):\n d+=j*k\n if d>-C:\n ans+=1\nprint(ans)']
['Runtime Error', 'Accepted']
['s327615539', 's092320282']
[3060.0, 3064.0]
[18.0, 18.0]
[199, 196]
p03102
u441246928
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C = map(int,input().split())\nB = list(map(int,input().split()))\nans = 0\nfor i in range(0,n) :\n A = list(int,input().split())\n Sum = C\n for (x,y) in zip(A,B):\n Sum += (x*y)\n if wa > 0 :\n ans += 1\nprint(ans)', 'N,M,C = map(int,input().split())\nB = list(map(int,input().split()))\nans = 0\nfor i in range(0,n) :\n A = list(int,input().split())\n Sum = C\n for (x,y) in zip(A,B):\n Sum += (x*y)\n if Sum > 0 :\n ans += 1\nprint(ans)', 'N,M,C = map(int,input().split())\nB = list(map(int,input().split()))\nans = 0\nfor i in range(0,N) :\n A = list(int,input().split())\n Sum = C\n for (x,y) in zip(A,B):\n Sum += (x*y)\n if Sum > 0 :\n ans += 1\nprint(ans)', 'N,M,C = map(int,input().split())\nB = list(map(int,input().split()))\nans = 0\nfor i in range(0,N) :\n A = list(map(int,input().split()))\n Sum = C\n for (x,y) in zip(A,B):\n Sum += (x*y)\n if Sum > 0 :\n ans += 1\nprint(ans)']
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s051829342', 's508527303', 's964105671', 's429629251']
[3064.0, 3064.0, 3064.0, 3060.0]
[17.0, 17.0, 17.0, 17.0]
[235, 236, 236, 241]
p03102
u442581202
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\ncnt =0\nfor i in range(n):\n a=list(map(int,input().split()))\n s=C+sum([b[j]*a[j] for j in range(m)])\n if s>0:\n cnt +=1\nprint(cnt)', 'n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\ncnt =0\nfor i in range(n):\n a=list(map(int,input().split()))\n s=c+sum([b[j]*a[j] for j in range(m)])\n if s>0:\n cnt +=1\nprint(cnt)\n']
['Runtime Error', 'Accepted']
['s449306470', 's893612496']
[3060.0, 3064.0]
[17.0, 18.0]
[198, 199]
p03102
u450180547
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['b = list(map(int, input().split()))\ncodes = [list(map(int, input().split())) for _ in range(N)]\n\nres = 0\nfor code in codes:\n s = C \n for i in range(M):\n s += (code[i] * b[i])\n if s > 0:\n res += 1\n\nprint(res)\n', 'N, M, C = map(int, input().split())\nb = list(map(int, input().split()))\ncodes = [list(map(int, input().split())) for _ in range(N)]\n\nres = 0\nfor code in codes:\n s = C\n \n for i in range(M):\n s += (code[i] * b[i])\n\n if s > 0:\n res += 1\n\nprint(res)']
['Runtime Error', 'Accepted']
['s855740347', 's486772729']
[2940.0, 3060.0]
[17.0, 17.0]
[234, 271]
p03102
u455177911
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['import numpy', "import numpy as np\n\nn, m, c = [int(x) for x in input().split(' ')]\nb = np.asarray([int(x) for x in input().split(' ')])\n\na = np.ndarray((n, m), dtype=np.int32)\nfor i in range(n):\n a[i] = [int(x) for x in input().split(' ')]\n\n\ns = np.sum(a * b, axis=1)\nprint(np.sum(s + c > 0))\n"]
['Wrong Answer', 'Accepted']
['s082140198', 's420350212']
[12488.0, 12428.0]
[149.0, 149.0]
[12, 280]
p03102
u456566864
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['from sys import stdin\n\nN, M, C = map(int, stdin.readline().split())\nB = list(map(int, stdin.readline().split()))\nans = 0\nfor i in range(N):\n if sum(list(map(int, stdin.readline().split())), C) > 0:\n ans += 1\n \nprint(ans)', 'from sys import stdin\n\nN, M, C = map(int, stdin.readline().split())\nB = list(map(int, stdin.readline().split()))\nans = 0\nfor i in range(N):\n A = list(map(int, stdin.readline().split()))\n temp = 0\n for j in range(N):\n temp += A[j] * B[j]\n if temp + C > 0:\n ans += 1\n\nprint(ans)', 'from sys import stdin\n\nN, M, C = map(int, stdin.readline().split())\nB = list(map(int, stdin.readline().split()))\nans = 0\nfor i in range(N):\n A = list(map(int, stdin.readline().split()))\n temp = 0\n for j in range(M):\n temp += (A[j] * B[j])\n if temp + C > 0:\n ans += 1\n\nprint(ans)']
['Wrong Answer', 'Runtime Error', 'Accepted']
['s404125632', 's865346878', 's946744996']
[3060.0, 3060.0, 3060.0]
[17.0, 18.0, 18.0]
[227, 286, 288]
p03102
u457901067
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\n\nans = 0\n\nfor i in range(N):\n work = C\n for j in range(M):\n work += A[j] * B[j]\n if work >= 0:\n ans += 1\n \nprint(ans)', 'N, M, C = map(int, input().split())\nB = list(map(int, input().split()))\n\nans = 0\n\nfor i in range(N):\n A = list(map(int, input().split()))\n work = C\n for j in range(M):\n work += A[j] * B[j]\n if work > 0:\n ans += 1\n \nprint(ans)']
['Runtime Error', 'Accepted']
['s341699386', 's856952385']
[3060.0, 3060.0]
[18.0, 18.0]
[201, 238]
p03102
u458608788
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c=map(int,input().split())\nb=map(int,input().split())\na=0\nfor _ in range(n):\n a=map(int,input().split())\n s=0\n for i in range(m):\n s+=a[i]*b[i]\n if s > -c:\n a+=1\nprint(a)', 'n,m,c=map(int,input().split())\nb=list(map(int,input().split()))\nr=0\nfor _ in range(n):\n a=list(map(int,input().split()))\n s=0\n for i in range(m):\n s+=a[i]*b[i]\n if s > -c:\n r+=1\nprint(r)']
['Runtime Error', 'Accepted']
['s007980807', 's063534198']
[2940.0, 3060.0]
[17.0, 18.0]
[184, 196]
p03102
u466143662
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['a,b,c = map(int, input().split())\n\nlistB = list(map(int, input().split()))\n\nlistA = [list(map(int, input().split())) for _ in range(a)]\nt=0\n\nfor i in range(a):\n ans=0\n for i in range(b-1):\n s=listB[i]*listA[i]\n s=sum(s)\n ans= ans+s\n if ans+c>0:\n t+=1\nprint(t)', 'import numpy as np\n\nN,M,C=map(int, input().split())\n\nb=list(map(int, input().split()))\nb=np.array(b)\ncount=0\nfor _ in range(M):\n a=list(map(int, input().split()))\n a=np.array(a)\n e=a*b\n d=np.sum(e,axis=0)+C\n if d>0:\n count+=1\nprint(count)', 'import numpy as np\n\nN,M,C=map(int, input().split())\n\nb=np.array([int, input().split()])\ncount=0\nfor _ in range(M):\n a=np.array([map(int, input().split())])\n e=a*b\n d=np.sum(e,axis=0)+C\n if d>0:\n count+=1\nprint(count)', 'import numpy as np\n\nN,M,C=map(int, input().split())\n\nb=list(map(int, input().split()))\nb=np.array(b)\ncount=0\nfor _ in range(N):\n a=list(map(int, input().split()))\n a=np.array(a)\n e=a*b\n d=np.sum(e,axis=0)+C\n if d>0:\n count+=1\nprint(count)']
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s104494067', 's576950057', 's940376411', 's421852660']
[3060.0, 12584.0, 12396.0, 12472.0]
[24.0, 156.0, 151.0, 156.0]
[296, 260, 235, 260]
p03102
u475598608
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C=map(int,input().split())\nB=list(map(int,input().split()))\nA=list(list(map(int,input().split()))for i in range(N))\nprint(A)\ncount=0\ntotal=0\nfor i in range(N):\n for j in range(M):\n total+=A[i][j]*B[j]\n if total>-C:\n count+=1\n total=0\nprint(count)', 'N,M,C=map(int,input().split())\nB=list(map(int,input().split()))\ncount=0\nfor i in range(N):\n total=C\n A=list(map(int,input().split()))\n for j in range(M):\n total+=A[j]*B[j]\n if total>0:\n count+=1\nprint(count)']
['Wrong Answer', 'Accepted']
['s521287862', 's526496912']
[3064.0, 3060.0]
[17.0, 17.0]
[277, 233]
p03102
u478296955
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c = map(int, input().split())\nb = list(map(int, input().split()))\ncount = 0\nfor i in range(n):\n a = list(map(int, input().split()))\n for k in range(m):\n p = c\n p += a[k]*b[k]\n if p>0: count+=1\nprint(count)', 'n,m,c = map(int, input().split())\nb = list(map(int, input().split()))\ncount = 0\nfor i in range(n):\n a = list(map(int, input().split()))\n p = c\n for k in range(m):\n p += a[k]*b[k]\n if p>0: count+=1\nprint(count)']
['Wrong Answer', 'Accepted']
['s124242378', 's087873192']
[3064.0, 3064.0]
[18.0, 18.0]
[220, 216]
p03102
u479719434
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['N,M,C = [int(x) for x in input().split()]\nB = [int(x) for x in input().split()]\nA = [[int(x) for x in input().split()] for i in range(N)]\n\nfor i in range(N):\n sum = C\n for j in range(M):\n sum += A[i][j]*B[j]\n print(sum,sum>0)', 'N,M,C = [int(x) for x in input().split()]\nB = [int(x) for x in input().split()]\nA = [[int(x) for x in input().split()] for i in range(N)]\n\ncount = 0\nfor i in range(N):\n sum = C\n for j in range(M):\n sum += A[i][j]*B[j]\n if sum>0:\n count+=1\nprint(count)']
['Wrong Answer', 'Accepted']
['s529781375', 's160615246']
[3316.0, 3316.0]
[23.0, 19.0]
[241, 274]
p03102
u480038302
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['n,m,c = map(int,input().split())\nls1 = list(map(int,input().split()))\nls2 = [list(map(int,input().split())) for i in range(n)]\nprint(ls1)\nprint(ls2)\nls = []\nfor i in range(n):\n a = 0\n for j in range(m):\n a += ls2[i][j]*ls1[j]\n a += c\n if a > 0:\n ls.append(1)\nprint(len(ls))', 'n,m,c=map(int,input().split())\nls1 = list(map(int,input().split()))\nls2 = [list(map(int,input().split())) for i in range(n)]\nls = []\nfor i in range(n):\n a = 0\n for j in range(m):\n a += ls2[i][j]*ls1[j]\n a += c\n if a > 0:\n ls.append(1)\nprint(len(ls))']
['Wrong Answer', 'Accepted']
['s534445363', 's956966137']
[3064.0, 3188.0]
[17.0, 20.0]
[299, 275]
p03102
u480568292
2,000
1,048,576
There are N pieces of source code. The characteristics of the i-th code is represented by M integers A_{i1}, A_{i2}, ..., A_{iM}. Additionally, you are given integers B_1, B_2, ..., B_M and C. The i-th code correctly solves this problem if and only if A_{i1} B_1 + A_{i2} B_2 + ... + A_{iM} B_M + C > 0. Among the N codes, find the number of codes that correctly solve this problem.
['import numpy as np\n\ns,d,f = map(int,input().split())\n\nn_ln = []\nnn = []\nvv = []\nn_l = list(map(int,input().split()))\n\nfor i in range(s):\n n_ln.append(n_l)\n\nfor i in range(s):\n A = list(map(int,input().split()))\n nn.append(A)\n\nX = np.array(n_ln,dtype=np.int64)\nY = np.array(nn,dtype=np.int64)\nZ = X*Y\n\ncol_sum = np.prod(Z, axis=1)\n\ndef calc_(n):\n return n + f\n \ndata = calc_(col_sum)\n\n\ncount= 0\n\nfor h in data:\n if h>0:\n count += 1\n else:\n pass\n \nprint(count)', 'N,M,C = map(int,input().split())\nB = list(map(int,input().split()))\n\ncount = 0\nfor i in range(N):\n A = list(map(int,input().split()))\n p=C\n for j in range(M):p+=A[j]*B[j]\n if p>0:count+=1\nprint(count)']
['Wrong Answer', 'Accepted']
['s796906536', 's715462051']
[12408.0, 3060.0]
[150.0, 18.0]
[474, 204]