problem_id
stringlengths
6
6
user_id
stringlengths
10
10
time_limit
float64
1k
8k
memory_limit
float64
262k
1.05M
problem_description
stringlengths
48
1.55k
codes
stringlengths
35
98.9k
status
stringlengths
28
1.7k
submission_ids
stringlengths
28
1.41k
memories
stringlengths
13
808
cpu_times
stringlengths
11
610
code_sizes
stringlengths
7
505
p02785
u756693875
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,k = map(int,input().split())\nh = list(map(int,input().split()))\n\nl = h[0:(n-k)+1]\n\nprint(sum(l))', "n,k = map(int,input().split())\nh = list(map(int,input().split()))\n\nif n < k:\n print('0')\nelse:\n h.sort()\n l = h[0:(n-k)]\n\n print(sum(l))"]
['Wrong Answer', 'Accepted']
['s509153200', 's909812687']
[25768.0, 26180.0]
[76.0, 155.0]
[98, 148]
p02785
u757274384
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,k = map(int, input().split())\nH = list(map(int, input().split()))\n\nH.sort()\nH.reverse()\n\nif n <= k:\n print(0)\nelse:\n print(sum(H[k+1:len(H)]))', 'n,k = map(int, input().split())\nH = list(map(int, input().split()))\n\nH.sort()\nH.reverse()\n\nif n <= k:\n print(0)\nelse:\n print(sum(H[k:n]))\n']
['Wrong Answer', 'Accepted']
['s545426271', 's111917563']
[26024.0, 26024.0]
[151.0, 148.0]
[146, 140]
p02785
u757420987
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['hi = list(map(int, input().split()))\nhi.sort(reverse=True)\ndel hi[:k]\n\nnum = 0\nif hi == []:\n print(0)\nelse:\n for i in hi:\n num += i\n print(num)\n', 'import sys\n\nsys.setrecursionlimit(10**9)\n\nh, k = map(int, input().split())\nhi = list(map(int, input().split()))\nhi.sort(reverse=True)\ndel hi[:k]\n\nnum = 0\nif hi == []:\n print(0)\nelse:\n for i in hi:\n num += i\n print(num)\n']
['Runtime Error', 'Accepted']
['s528085415', 's932992701']
[3060.0, 26024.0]
[18.0, 162.0]
[160, 235]
p02785
u763380276
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,k=map(int,input().split())\nhps=list(map(int,input().split()))\nhps.sort()\nif k>n:\n print(n)\nelif k==n:\n print(k)\nelse:\n ans=k\n for i in range(k):\n hps.pop()\n ans+==sum(hps)\n print(ans)', 'n,k=map(int,input().split())\nhps=list(map(int,input().split()))\nhps.sort()\nif k>n:\n print(0)\nelif k==n:\n print(0)\nelse:\n ans=0\n for i in range(k):\n hps.pop()\n ans+=sum(hps)\n print(ans)']
['Runtime Error', 'Accepted']
['s278218382', 's318736368']
[2940.0, 26024.0]
[17.0, 164.0]
[194, 193]
p02785
u764773675
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['monster_num,k = map(int,input().split(" "))\nhp = list(map(int,input().split(" ")))\nhp = sorted(hp, reverse = True)\nprint(hp)\ntotal = 0\nfor i in hp:\n total += i\n \ns = 0\nfor i in range(k):\n if s <= len(hp) - 1:\n total -= hp[s]\n s += 1\n\nprint(total)\n ', 'monster_num,k = map(int,input().split(" "))\nhp = list(map(int,input().split(" ")))\nhp = sorted(hp, reverse = True)\n\ntotal = 0\nfor i in hp:\n total += i\n \ns = 0\nfor i in range(k):\n if s <= len(hp) - 1:\n total -= hp[s]\n s += 1\n\nprint(total)\n ']
['Wrong Answer', 'Accepted']
['s057400834', 's742089090']
[26360.0, 26024.0]
[274.0, 255.0]
[274, 265]
p02785
u766393261
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N,K=map(int,input().split())\nH=list(map(int,input().split()))\nans=0\nH.sort()\nfor i in range(N):\n if i>=N-K:\n ans+=1\n else:\n ans+=H[i]\nprint(ans)', 'N,K=map(int,input().split())\nH=list(map(int,input().split()))\nans=0\nH.sort()\nfor i in range(N):\n if i>=N-K:\n ans+=0\n else:\n ans+=H[i]\nprint(ans)']
['Wrong Answer', 'Accepted']
['s139434506', 's502646697']
[26180.0, 26024.0]
[191.0, 201.0]
[164, 164]
p02785
u768559443
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,k=map(int,input().split())\nh=sorted(map(int,input().split()))[::-1]\nans=0\nfor i in range(k+1,n-k):\n ans+=i\nprint(ans)', 'n,k=map(int,input().split())\nh=sorted(map(int,input().split()))[::-1]\nans=0\nfor i in range(k,n):\n ans+=h[i]\nprint(ans)']
['Wrong Answer', 'Accepted']
['s902098798', 's811539721']
[26180.0, 26024.0]
[160.0, 176.0]
[120, 119]
p02785
u771167374
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n, k = map(int, input().split())\nl = list(map(int, input().split()))\nl.sort()\nif n<=k :\n print(0)\nelse :\n sm = 0\n for i in range(n-k):\n sm += l[i]\n pritn(sm)', 'n, k = map(int, input().split())\nl = list(map(int, input().split()))\nl = sorted(l)\nif n<=k :\n print(0)\nelse :\n sm = 0\n for i in range(n-k):\n sm += l[i]\n pritn(sm)', 'n, k = map(int, input().split())\nl = list(map(int, input().split())).sort()\nif n<=k :\n print(0)\nelse :\n sm = 0\n for i in range(n-k):\n sm += l[i]\n pritn(sm)', 'n, k = map(int, input().split())\nl = list(map(int, input().split()))\nl.sort()\nif n<=k :\n print(0)\nelse :\n sm = 0\n for i in range(n-k):\n sm += l[i]\n print(sm)']
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s517219878', 's832086445', 's937113770', 's631443167']
[26024.0, 26024.0, 26024.0, 26764.0]
[167.0, 172.0, 144.0, 172.0]
[176, 181, 174, 176]
p02785
u772029934
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N,K = map(int,input().split())\nli = sorted(list(map(int,input().split())),reverse=True)\ndel(li[:K])\nsum(li)', 'N,K = map(int,input().split())\nli = sorted(list(map(int,input().split())),reverse=True)\ndel(li[:K])\nprint(sum(li))']
['Wrong Answer', 'Accepted']
['s907781760', 's033243690']
[26764.0, 26180.0]
[153.0, 151.0]
[109, 116]
p02785
u776929617
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['src/contest/abc/abc153/c.py', '\nn, k = list(map(int, input().split()))\n\nh = list(map(int, input().split()))\n\nh.sort(reverse=True)\n\nprint(sum(h[min(n,k):]))\n']
['Runtime Error', 'Accepted']
['s443417123', 's725753763']
[2940.0, 26764.0]
[17.0, 153.0]
[27, 125]
p02785
u779728630
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['H, K = map(int, input().split())\nA = list(map(int, input().split()))\n\nA.sort()\n\nans = 0\n\nfor i in range( N - K ):\n ans += A[i]\n \nprint(ans)', 'H, K = map(int, input().split())\nA = list(map(int, input().split()))\n\nA.sort()\n\nans = 0\n\nfor i in range( H - K ):\n ans += A[i]\n \nprint(ans)']
['Runtime Error', 'Accepted']
['s279323502', 's126048934']
[26024.0, 26180.0]
[148.0, 174.0]
[141, 141]
p02785
u780962115
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['h,n=map(int,input().split())\nlists=list(map(int,input().split()))\nif h>sum(lists):\n print("No")\nelse:\n print("Yes")', 'n,k=map(int,input().split())\nlists=list(map(int,input().split()))\nlists=sorted(lists)\nif len(lists)<=k:\n print(0)\nelif len(lists)>k:\n sub=lists[:len(lists)-k]\n print(sum(sub))']
['Wrong Answer', 'Accepted']
['s443180726', 's766592747']
[26020.0, 26180.0]
[70.0, 174.0]
[121, 184]
p02785
u784022244
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N, K=map(int, input().split())\nH=list(map(int, input().split()))\n\nif N<=K:\n print(0)\nelif K==0:\n print(sum(H))\nelse:\n for i in range(K):\n maxh=max(H)\n H=H.remove(maxh)\n print(sum(H))\n\n\n', 'N, K=map(int, input().split())\nH=list(map(int, input().split()))\n\nif N<=K:\n print(0)\nelse:\n for i in range(K):\n maxh=max(H)\n H=H.remove(maxh)\n print(sum(H))\n\n\n', 'N, K=map(int, input().split())\nH=list(map(int, input().split()))\n\nif N<=K:\n print(0)\nelse:\n for i in range(K):\n maxh=max(H)\n H=H.remove(maxh)\n print(len(H))\n', 'N, K=map(int, innput().split())\nH=list(map(int, input().split()))\n\nif N<=K:\n print(0)\nelse:\n for i in range(K):\n maxh=max(H)\n H=H.remove(maxh)\n print(len(H))', 'N, K=map(int, input().split())\nH=list(map(int, input().split()))\n\nif N<=K:\n print(0)\nelif K==0:\n print(sum(H))\nelse:\n H=sorted(H)\n print(sum(H[:len(H)-K]))\n\n']
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s303841310', 's388608460', 's447861347', 's467742204', 's477787101']
[26024.0, 26764.0, 26024.0, 2940.0, 26764.0]
[71.0, 75.0, 71.0, 17.0, 151.0]
[195, 168, 166, 166, 161]
p02785
u789896699
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['input_num=input()\nn=input_num.split()\nnum = list(map(int,n))\n\nif len(num)-2<=num[1]:\n print(0)\nelse:\n a=num[2:]\n a.sort(reverse=True)\n b=a[num[1]:]\n print(sum(b))', 'input_num=[input() for i in range(2)]\n\nn=input_num[0].split()\nn=list(map(int,n))\na=input_num[1].split()\na=list(map(int,a))\n \nif len(a)<=n[1]:\n print(0)\nelse:\n a.sort(reverse=True)\n b=a[n[1]:]\n print(sum(b))']
['Wrong Answer', 'Accepted']
['s143272302', 's983615688']
[3060.0, 28916.0]
[17.0, 158.0]
[167, 214]
p02785
u790493075
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n, k = map(int, input().split())\nmonsters = list(map(int, input().split()))\n\nhissatsu = n-k\n\nif hissatsu <= 0:\n print(0)\nelse:\n print(sum(monsters[-hissatsu:]))', 'n, k = map(int, input().split())\nmonsters = list(map(int, input().split()))\n\nhissatsu = n-k\n\nif hissatsu <= 0:\n print(0)\nelse:\n monsters.sort(reverse=True)\n print(sum(monsters[-hissatsu:]))']
['Wrong Answer', 'Accepted']
['s948328946', 's361116933']
[26024.0, 26016.0]
[71.0, 149.0]
[162, 192]
p02785
u796708718
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['HK = list(map(int,input().split(" ")))\nHP = list(map(int,input().split(" ")))\nH = HK[0]\nK = HK[1]\nHP.reverse()\nsum_a = sum(HP[K:N])\nprint(sum_a)', 'HK = list(map(int,input().split(" ")))\nHP = list(map(int,input().split(" ")))\nH = HK[0]\nK = HK[1]\nHP.sort(reverse=Ture)\nsum_a = sum(HP[K:N])\nprint(sum_a)', 'HK = list(map(int,input().split(" ")))\nHP = list(map(int,input().split(" ")))\nH = HK[0]\nK = HK[1]\nHP.sort(reverse=True)\nsum_a = sum(HP[K:N])\nprint(sum_a)', 'HK = list(map(int,input().split(" ")))\nHP = list(map(int,input().split(" ")))\nH = HK[0]\nK = HK[1]\nHP.reverse()\nsum_a = sum(HP[K:N])\nprint(sum_a)', 'HK = list(map(int,input().split(" ")))\nHP = list(map(int,input().split(" ")))\nH = HK[0]\nK = HK[1]\nHP.sort(reverse=True)\nsum_a = sum(HP[K:])\nprint(sum_a)']
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s064242260', 's745516949', 's923783847', 's997881635', 's263430936']
[26360.0, 26024.0, 26764.0, 26024.0, 26176.0]
[68.0, 70.0, 159.0, 68.0, 152.0]
[144, 153, 153, 144, 152]
p02785
u798260206
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,k = map(int,input().split())\nhn = list(map(int,input().split()))\nhn_s = hn.sort()\nattack = 0\n\nif k>=n:\n print("0")\n\nelif k<n:\n for _ in range(n-k):\n hn_s.pop(-1)\n print(str(sum(hn_s)))', 'n,k = map(int,input().split())\nhn = sorted(list(map(int,input().split())))\n\nattack = 0\n\nif k>=n:\n print(attack)\n\nelif k<n:\n print(sum(hn[0:n-k]))']
['Runtime Error', 'Accepted']
['s784878635', 's134726481']
[25768.0, 26180.0]
[150.0, 153.0]
[192, 147]
p02785
u799635973
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['H, N = map(int, input().split())\nA = [int(x) for x in input().split()]\nprint(A)\nlist2 = sorted(A, reverse=True) \nprint(list2)\nif N>0:\n del list2[0:N]\n print(list2)\n print(sum(list2))\nelif N<0:\n print(sum(A))', 'H, N = map(int, input().split())\nA = [int(x) for x in input().split()]\nlist2 = sorted(A, reverse=True) \n\nif N>H:\n print(0)\nelif N>0:\n del list2[0:N]\n print(sum(list2))\nelif N<=0:\n print(sum(A))']
['Wrong Answer', 'Accepted']
['s133954267', 's195372357']
[27960.0, 26180.0]
[219.0, 157.0]
[239, 225]
p02785
u805552010
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['\nn,k = map(int,input().split())\nh = list(map(int,input().split()))\n\n\n\nh.sort(reverse = True)\n\nif n <= k:\n print(0)\n\nelse:\n for i in range(k):\n s[i] = 0\nprint(sum(s))', '\nn,k = map(int,input().split())\nh = list(map(int,input().split()))\n\n\n\nh.sort(reverse = True)\n\nif n <= k:\n print(0)\n\nelse:\n for i in range(k):\n h[i] = 0\n print(sum(h))']
['Runtime Error', 'Accepted']
['s245226970', 's213043949']
[26764.0, 26764.0]
[151.0, 165.0]
[421, 425]
p02785
u809816772
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N, K = map(int,input().split())\nH = list(input().split())\n\nH.sort(reverse=True)\nprint(sum(H[K:]))', 'N, K = map(int,input().split())\nH = list(map(int,input().split()))\n\nH.sort(reverse=True)\nprint(sum(H[K:]))']
['Runtime Error', 'Accepted']
['s058918435', 's838117314']
[20980.0, 26024.0]
[183.0, 155.0]
[97, 106]
p02785
u813098295
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['\n\n#include <algorithm>\n\nusing namespace std;\n\nint main() {\n int n, k;\n cin >> n >> k;\n\n vector<int> h(n);\n for (int i = 0; i < n; i++) {\n cin >> h[i];\n }\n sort(h.begin(), h.end(), greater<int>());\n\n int ans = 0;\n for (int i = 0; i < n; i++) {\n if (i < k) {\n ans++;\n } else {\n ans += h[i];\n }\n }\n cout << ans << endl;\n return 0;\n}', '#!/usr/bin/env python3\n\nn, k = map(int, input().split())\nh = sorted(map(int, input().split()), reverse=True)\n\nprint(sum(h[k:]))\n\n\n']
['Runtime Error', 'Accepted']
['s782737586', 's957115753']
[2940.0, 26024.0]
[17.0, 149.0]
[398, 130]
p02785
u814265211
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n, k = map(int, input().split())\nh = list(map(int, input().split()))\n\nif n <= k:\n print(0)\nelif k == 0:\n print(sum(h))\nelse:\n h.sort()\n print(h[:-k])\n print(sum(h[:-k]))\n', 'n, k = map(int, input().split())\nh = list(map(int, input().split()))\n\nh.sort(reverse=True)\nprint(sum(h[k:]))']
['Wrong Answer', 'Accepted']
['s851293608', 's796891905']
[26180.0, 26024.0]
[170.0, 152.0]
[185, 108]
p02785
u815304751
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['h,n = map(int,input().split())\na_ = list(map(int,input().split()))\n\na_.sort()\nfor i in range(n):\n a_[i] = 0\nprint(sum(a_))\n', 'n,k = map(int,input().split())\nh_ = list(map(int,input().split()))\n\nif len(h_) <= k:\n print(0)\nelse:\n h_.sort(reverse = True)\n for i in range(k):\n h_[i] = 0\n print(sum(h_))\n']
['Runtime Error', 'Accepted']
['s075250336', 's146044798']
[26764.0, 26020.0]
[160.0, 163.0]
[126, 192]
p02785
u823885866
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['import sys\nn, k = map(int, sys.stdin.readline().split())\nli = list(map(int, sys.stdin.readline().split()))\nl = len(li)\nt = 0\nif l > k:\n li.sort().reverse()\n t = sum(li[k:])\nprint(t)\n ', 'import sys\nn, k = map(int, sys.stdin.readline().split())\nli = list(map(int, sys.stdin.readline().split()))\nl = len(li)\nt = 0\nif l > k:\n li.sort()\n li.reverse()\n t = sum(li[k:])\nprint(t)\n \n']
['Runtime Error', 'Accepted']
['s792682147', 's526415679']
[25744.0, 25744.0]
[146.0, 148.0]
[186, 192]
p02785
u824734140
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['from collections import deque\n\nh, k, *a = map(int, open(0).read().split())\nif h <= k:\n print(k)\n exit()\n\na.sort()\nq = deque(a)\n\n[q.pop() for _ in range(k)]\nprint(q)\nprint(sum(q))\n', 'from collections import deque\n\n# ans = True\n# print(["Yes", "No"][ans])\n\nh, k, *a = map(int, open(0).read().split())\nk = min(h,k)\n\na.sort()\nfor _ in range(k):\n a.pop()\n\nprint(sum(a))\n\n\n']
['Wrong Answer', 'Accepted']
['s438772695', 's674879216']
[26020.0, 26020.0]
[186.0, 165.0]
[185, 188]
p02785
u831752983
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,m=map(int,input().split())\na=list(map(int,input().split()))\na.sort()\n\nif n<=m:\n print(0)\nelse:\n a=a[-(n-m):]\n print(sum(a))\n', 'n,m=map(int,input().split())\na=list(map(int,input().split()))\na.sort()\n\nif n<=m:\n print(0)\nelif m==0:\n print(sum(a))\nelse:\n a=a[:-m]\n print(sum(a))\n']
['Wrong Answer', 'Accepted']
['s961331422', 's033374941']
[26180.0, 26180.0]
[148.0, 149.0]
[129, 152]
p02785
u835322333
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N,K = map(int,input().split())\nH = list(map(int,input().split()))\n\nsort = sorted(H, reverse = True)\nprint(sort)\n\nans = 0\nfor i in range(N):\n if i+1 > K:\n ans += sort[i]\n \nprint(ans)', 'N,K = map(int,input().split())\nH = list(map(int,input().split()))\n\nsort = sorted(H, reverse = True)\nans = 0\nfor i in range(N):\n if i+1 > K:\n ans += sort[i]\n \nprint(ans)']
['Wrong Answer', 'Accepted']
['s446111417', 's766456680']
[26024.0, 26024.0]
[210.0, 186.0]
[194, 181]
p02785
u848512577
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N, K = map(int, input().split())\nList = list(map(int, input().split()))\n\n\nremain_monster = N - K\nnew_list = sorted(List, reverse=True)\n\nmonsterHP = sum(new_list[remain_monster:])\n\nprint(monsterHP)', 'import sys\nsys.setrecursionlimit(100000) \n\nN, K = map(int, input().split())\nList = list(map(int, input().split()))\nA = 0\n\nremain_monster = N - K\nnew_list = sorted(List, reverse=True)\n\nmonsterHP = sum(new_list[remain_monster:])\n\nprint(monsterHP)', 'N, K = map(int, input().split())\nList = list(map(int, input().split()))\n\n\nremain_monster = N - K\nif remain_monster <= 0:\n monsterHP = 0\n\nelse:\n new_list = sorted(List, reverse=True)\n\n monsterHP = sum(new_list[-remain_monster:])\n\nprint(monsterHP)\n\n']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s171548136', 's608715903', 's599843542']
[25768.0, 26180.0, 26180.0]
[153.0, 156.0, 150.0]
[196, 244, 256]
p02785
u852437863
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['import sys\n\n\ndef InS(): return input()\n\n\ndef InL(): return list(map(int, input().split()))\n\n\ndef InI(): return int(input())\n\n\nN, K = InL()\nH = InL().sort()\n\nif K >= N:\n print(0)\n sys.exit()\n\nprint(sum(H[0:N-K]))\n', 'import sys\n\n\ndef InS(): return input()\n\n\ndef InL(): return list(map(int, input().split()))\n\n\ndef InI(): return int(input())\n\n\nN, K = InL()\nH = InL()\nH.sort()\n\nif K >= N:\n print(0)\n sys.exit()\nelse:\n print(sum(H[0:N-K]))\n']
['Runtime Error', 'Accepted']
['s799745761', 's942948590']
[26024.0, 25876.0]
[155.0, 151.0]
[218, 229]
p02785
u857070771
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,k=map(int,input().split())\na=list(int(x) for x in input().split())\ns=0\nif k <= n:\n\tprint(s)\nelse:\n\ti for i in range(n-k):\n\t\ts += i\n\t\tprint(s)', 'n,k=map(int,input().split())\na=list(int(x) for x in input().split())\na.sort(reverse = True)\ns=0\nif k <= n:\n\tprint(0)\nelse:\n\t\ts = sum(a[:n-k])\n\t\tprint(s)', 'n,k=map(int,input().split())\na=list(int(x) for x in input().split())\na.sort()\ns=0\nif k <= n:\n\tprint(0)\nelse:\n\t\ts = sum(a[:n-k])\n\t\tprint(s)\n', 'n,k=map(int,input().split())\na=list(int(x) for x in input().split())\na.sort()\ns=0\nif n <= k:\n\tprint(0)\nelse:\n\t\ts = sum(a[:n-k])\n\t\tprint(s)\n']
['Runtime Error', 'Wrong Answer', 'Wrong Answer', 'Accepted']
['s432202885', 's481941789', 's952637782', 's430691435']
[2940.0, 26024.0, 26024.0, 25768.0]
[17.0, 161.0, 162.0, 167.0]
[143, 152, 139, 139]
p02785
u857330600
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N,K=map(int,input().split())\nH=list(map(int,input().split()))\nprint(N)\nprint(K)\ns=0\nif N<=K:\n print(0)\nelse:\n for i in range(H-N)\n s+=H[i]\n print(s)', 'N,K=map(int,input().split())\nH=list(map(int,input().split()))\nH.sort()\nprint(H)\ns=0\nif N<=K:\n print(0)\nelse:\n for i in range(N-K):\n s+=H[i]\n print(s)', 'N,K=map(int,input().split())\nH=list(map(int,input().split())\nprint(N)\nprint(K)\ns=0\nif N<=K:\n print(0)\nelse:\n for i in range(H-N)\n s+=H[i]\n print(s)', 'N,K=map(int,input().split())\nH=list(map(int,input().split()))\ns=0\nif N<=K:\n print(0)\nelse:\n for i in range(H-N):\n s+=H[i]\n print(s)', 'N,K=map(int,input().split())\nH=list(map(int,input().split()))\nI=sorted(H)\nprint(H)\nprint(I)\ns=0\nif N<=K:\n print(0)\nelse:\n for i in range(N-K):\n s+=I[i]\n print(s)', 'N,K=map(int,input().split())\nH=list(map(int,input().split()))\nI=sorted(H)\ns=0\nif N<=K:\n print(0)\nelse:\n for i in range(N-K):\n s+=I[i]\n print(s)']
['Runtime Error', 'Wrong Answer', 'Runtime Error', 'Runtime Error', 'Wrong Answer', 'Accepted']
['s026191309', 's457477684', 's655858445', 's828296796', 's981117613', 's890296981']
[2940.0, 26764.0, 2940.0, 25768.0, 26444.0, 26024.0]
[18.0, 199.0, 17.0, 69.0, 225.0, 174.0]
[154, 155, 153, 137, 167, 149]
p02785
u860002137
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n, k = map(int, input().split())\nh = list(map(int, input().split()))\nh.sort(reverse=True)\nif len(h) <= k:\n print(0)\nelse:\n for _ in range(k):\n h.pop()\n print(sum(h))', 'n, k = map(int, input().split())\nh = list(map(int, input().split()))\nh.sort()\nif len(h) <= k:\n print(0)\nelse:\n for _ in range(k):\n h.pop()\n print(sum(h))']
['Wrong Answer', 'Accepted']
['s943513902', 's008646153']
[26764.0, 26764.0]
[162.0, 168.0]
[181, 169]
p02785
u860234244
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N,K = map(int,input().split(" "))\nH = list(map(int,input().split(" ")))\nH = sorted(H,reverse = True)\nfor i in range(K):\n H.remove(H[i])\nsum_ = sum(H)\npint(sum)', 'N, K = map(int, input().split())\nA = list(map(int, input().split()))\n\nA.sort(reverse=True)\nprint(sum(A[K:]))']
['Runtime Error', 'Accepted']
['s553302373', 's298938655']
[26764.0, 26024.0]
[2105.0, 153.0]
[162, 108]
p02785
u860966226
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['data = input().split()\n \nn = int(data[0])\nk = int(data[1])\n\nhpstr = input().split()\nhp = []\n\nfor i in range(n):\n hp.append(int(hpstr[i]))\n\nhp.sort()\n\nprint(hp)\n\nans = 0\nfor i in range(n - k):\n ans += hp[i]\n \nprint(ans)\n', 'data = input().split()\n \nn = int(data[0])\nk = int(data[1])\n \nhpstr = input().split()\nhp = []\n \nfor i in range(n):\n hp.append(int(hpstr[i]))\n \nhp.sort()\n \nans = 0\nfor i in range(n - k):\n ans += hp[i]\n \nprint(ans)\n']
['Wrong Answer', 'Accepted']
['s556635172', 's659735713']
[33064.0, 26556.0]
[234.0, 212.0]
[221, 214]
p02785
u867826040
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n, k = map(int, input().split())\nh = list(map(int, input().split()))\nh.sort(reverse=True)\nprint(sum(h[k:]), h)', 'n, k = map(int, input().split())\nh = list(map(int, input().split()))\nh.sort(reverse=True)\nprint(sum(h[k:]))']
['Wrong Answer', 'Accepted']
['s496551347', 's029359235']
[26764.0, 25768.0]
[173.0, 157.0]
[110, 107]
p02785
u870559097
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N, K=map(int, input().split())\nList=sorted(list(map(int,input().split())))\na = 0\nfor i in range(N - k):\n a = a + List[i]\nprint(a)', 'N, K=map(int, input().split())\nList=sorted(list(map(int,input().split())))\na = 0\nfor i in range(N - K):\n a = a + List[i]\nprint(a)']
['Runtime Error', 'Accepted']
['s738178260', 's043095025']
[26360.0, 26764.0]
[152.0, 173.0]
[130, 130]
p02785
u881214802
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,k=map(int,input().split())\na=sorted(list(map(int,input().split())),reverse=True)[k-1:]\nprint(sum(a))', 'n,k=map(int,input().split())\na=sorted(list(map(int,input().split())),reverse=True)[k:]\nprint(sum(a))']
['Wrong Answer', 'Accepted']
['s840991986', 's400997522']
[26024.0, 26180.0]
[157.0, 151.0]
[102, 100]
p02785
u884601206
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,k=map(int,input().split())\nh=list(map(int,input().split()))\nh.sort()\nh=[::-1]\nif k!=0:\n for i in range(k):\n h[i]=0\n\n \nprint(sum(h))\n', 'n,k=map(int,input().split())\nh=list(map(int,input().split()))\nh.sort()\nh=h[::-1]\n\nif k>=n:\n print(0)\n \nelif k!=0:\n for i in range(k):\n h[i]=0\n print(sum(h))\n\nelse:\n print(sum(h))\n \n\n\n\n\n']
['Runtime Error', 'Accepted']
['s081548638', 's394435539']
[2940.0, 26180.0]
[17.0, 166.0]
[139, 194]
p02785
u890183245
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['H, K = map(int, input().split())\narray = list(map(int, input().split()))\nA = sorted(array, reverse=True)\ndel A[0:K-1]\nprint(sum(A))\n', 'H, K = int(input().split())\narray = list(map(int, input().split()))\nA = sorted(array, reverse=True)\ndel A[0:K-1]\nprint(sum(A))', 'H, K = map(int, input().split())\narray = list(map(int, input().split()))\nA = sorted(array, reverse=True)\ndel A[0:K]\nprint(sum(A))']
['Wrong Answer', 'Runtime Error', 'Accepted']
['s564795860', 's903336700', 's041464592']
[26024.0, 3060.0, 26024.0]
[154.0, 17.0, 148.0]
[132, 126, 129]
p02785
u891876269
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
["N, K = map(int, input().split())\nHlist = list(map(int, input().split()))\nHlist.sort(reverse=True)\n'''\nprint(Hlist)\n'''\nif K == 0:\n print(sum(Hlist))\nelif K == 1:\n del Hlist[0]\n print(Hlist)\n print(sum(Hlist))\nelse:\n del Hlist[0:K-1]\n print(Hlist)\n print(sum(Hlist))", 'N, K = map(int, input().split())\nHlist = list(map(int, input().split()))\nHlist.sort(reverse=True)\nif K == 0:\n print(sum(Hlist))\nelse:\n Hlist[0:K] = []\n print(sum(Hlist))\n']
['Wrong Answer', 'Accepted']
['s271737378', 's865471402']
[26024.0, 26764.0]
[162.0, 149.0]
[272, 336]
p02785
u891945807
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N = input().rstrip()\nn = N[0]\nk = N[1]\n\nh = list(map(int,input().split()))\nh.sort(reverse=True)\n\nm = 0\nhit = 0\nif k >= n :\n m = n\nelse:\n for i in range(k,n):\n hit += h[i]\n \n m = k + hit\n \nprint(m)', 'N = list(map(int,input().rstrip().split()))\nn = N[0]\nk = N[1]\n\nh = list(map(int,input().split()))\nh.sort(reverse=True)\n\nm = 0\nhit = 0\nif k >= n :\n m = 0\nelse:\n for i in range(k,n):\n hit += h[i]\n \n m = hit\nprint(type(m))\nprint(m)', 'N = list(map(int,input().rstrip().split()))\nn = N[0]\nk = N[1]\n\nh = list(map(int,input().split()))\nh.sort(reverse=True)\n\nm = 0\nhit = 0\nif k >= n :\n m = n\nelse:\n for i in range(k,n):\n hit += h[i]\n \n m = k + hit\n \nprint(m)', 'N = list(map(int,input().rstrip().split()))\nn = N[0]\nk = N[1]\n\nh = list(map(int,input().split()))\nh.sort(reverse=True)\n\nm = 0\nhit = 0\nif k >= n :\n m = 0\nelse:\n for i in range(k,n):\n hit += h[i]\n \n m = hit\nprint(m)']
['Runtime Error', 'Wrong Answer', 'Wrong Answer', 'Accepted']
['s039479047', 's163942409', 's487116319', 's716816464']
[26360.0, 26180.0, 26764.0, 26180.0]
[145.0, 169.0, 169.0, 169.0]
[204, 235, 227, 220]
p02785
u895592784
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
["N, K = map(int, input().split(' '))\nH = sorted(map(int, input().split(' ')))\nif(K >= N):\n print(0)\n exit(0)\nfor j in range(K):\n H[K - j - 1] = 0\nprint(sum(H))", "N, K = map(int, input().split(' '))\nH = sorted(map(int, input().split(' ')))\nprint(H)\nif(K >= N):\n print(0)\n exit(0)\nfor j in range(K):\n H[N - j - 1] = 0\nprint(sum(H))", "N, K = map(int, input().split(' '))\nH = sorted(map(int, input().split(' ')))\nif(K >= N):\n print(0)\n exit(0)\nfor j in range(K):\n H[N - j - 1] = 0\nprint(sum(H))"]
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s164026370', 's704503976', 's107674353']
[26764.0, 25768.0, 26764.0]
[174.0, 196.0, 176.0]
[167, 176, 167]
p02785
u904639778
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
["n, k = list(map(int, input().split(' ')))\nh_arr = list(map(int, input().split(' '))).sorted(reverse=True)\n\nif n <= k:\n print('0')\nelse:\n print(sum(h_arr[k:]))", "n, k = list(map(int, input().split(' ')))\nh_arr = sorted(list(map(int, input().split(' '))),reverse=True)\n \nif n <= k:\n print('0')\nelse:\n print(sum(h_arr[k:]))"]
['Runtime Error', 'Accepted']
['s276265591', 's950513285']
[26020.0, 26024.0]
[68.0, 153.0]
[160, 161]
p02785
u905743924
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
["N, K = map(int, input().split())\nH = sorted([int(x) for x in input().split()], inverse=True)\nif K >= len(H):\n print('0')\nelse:\n print(sum(H[K:]))", "N, K = map(int, input().split())\nH = sorted([int(x) for x in input().split()])[::-1]\nif K >= len(H):\n print('0')\nelse:\n print(sum(H[K:]))"]
['Runtime Error', 'Accepted']
['s900820084', 's143717792']
[26764.0, 26764.0]
[74.0, 169.0]
[151, 143]
p02785
u907223098
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,k=(int(i) for i in input().split())\nh=[0 for i in range(k)]\np=0\nfor i in input().split():\n p+=i\n if h[0]<i:\n h[0]=i\n h.sort()\nprint(p-sum(h))', 'n,k=(int(i) for i in input().split())\nh=[0 for i in range(k)]\np=0\nfor i in input().split():\n p+=int(i)\n try:\n if h[0]<i:\n h[0]=int(i)\n h.sort()\n except IndexError:\n continue\nprint(p-sum(h))', 'n,k=(int(i) for i in input().split())\nh=[]\nfor i in input().split():\n h.append(int(i))\nh.sort()\nfor i in range(k):\n h.pop(-1)\nprint(sum(h)+k)', 'n,k=(int(i) for i in input().split())\nh=[]\nfor i in input().split():\n h.append(int(i))\nh.sort()\nif k!=0:\n\tfor i in range(min(n,k)):\n \t h.pop(-1)\nprint(sum(h))\n']
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s257979376', 's385049885', 's981737475', 's494069326']
[21588.0, 21588.0, 26180.0, 26764.0]
[43.0, 135.0, 205.0, 196.0]
[151, 214, 143, 161]
p02785
u907446975
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['a=input().split()\n(n,m)=map(int,a)\nb=input().split()\nb1=list(map(int,b))\nb1=sorted(b1)\nfor i in range(m):\n b1[i]=0\n if i==len(b1)-1:\n break\n\nprint(sum(b1))', 'a=input().split()\n(n,m)=map(int,a)\nb=input().split()\nb1=list(map(int,b))\nb1=sorted(b1)\nfor i in range(m):\n b1[len(b)-1-i]=0\n if i==len(b1)-1:\n break\n\nprint(sum(b1))']
['Wrong Answer', 'Accepted']
['s740336384', 's915005889']
[28088.0, 28092.0]
[200.0, 224.0]
[168, 177]
p02785
u912359563
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N, K = map(int, input().split())\nA = list(map(int, input().split()))\nA.sort()\nS = 0\nfor i in range(0, K):\n if not A.empty():\n A.pop_back()\nprint(sum(A))', 'N, K = map(int, input().split())\nA = list(map(int, input().split()))\nA.sort()\nS = 0\nfor i in range(0, K):\n if len(A) > 0:\n A.pop(-1)\nprint(sum(A))']
['Runtime Error', 'Accepted']
['s407633724', 's153632106']
[26764.0, 26020.0]
[147.0, 192.0]
[156, 156]
p02785
u920032768
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n, k = map(int, input().split())\nif n <= k:\n print(0)\n return\nh = list(map(int, input().split())).sort()\nprint(sum(h[:-k]))', 'n, k = map(int, input().split())\nif n <= k:\n print(0)\n exit()\nh = list(map(int, input().split())).sort()\nprint(sum(h[:-k]))', 'n, k = map(int, input().split())\nh = list(map(int, input().split()))\nif n <= k:\n print(0)\nelif k == 0:\n print(sum(h))\nelse:\n h = sorted(list(map(int, input().split())))\n print(sum(h[:n-k]))', 'n, k = map(int, input().split())\nif n <= k:\n print(0)\nelse:\n h = list(map(int, input().split())).sort()\n print(sum(h[:-k]))', 'n, k = map(int, input().split())\nh = list(map(int, input().split()))\nif n <= k:\n print(0)\nelif k == 0:\n print(sum(h))\nelse:\n h = sorted(h)\n print(sum(h[:n-k]))']
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s060880375', 's770353743', 's808435178', 's988053953', 's854799629']
[2940.0, 26024.0, 26024.0, 26024.0, 26180.0]
[17.0, 147.0, 69.0, 142.0, 151.0]
[125, 125, 193, 126, 163]
p02785
u923657126
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n, k = map(int,input().split())\nh = list(map(int,input().split()))\nhsort = sorted(h)\nans = sum(hsort[k-n:])\nprint(ans)', 'n, k = map(int,input().split())\nh = list(map(int,input().split()))\nhsort = sorted(h)\nans = sum(hsort[n-k-1:])\nprint(ans)', 'n, k = map(int,input().split())\nh = list(map(int,input().split()))\nh.sort(reverse=True)\nans = sum(h[k:])\nprint(ans)']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s071314515', 's579293442', 's407016456']
[26024.0, 26024.0, 26764.0]
[157.0, 152.0, 155.0]
[118, 120, 115]
p02785
u928784113
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,k = map(int,input().split())\nh = list(map(int,input().split()))\nh.sort()\nfor i in range(k):\n h[i] = 0\nprint(sum(h))', 'n,k = map(int,input().split())\nh = list(map(int,input().split()))\nh.sort(reverse = True)\nfor i in range(min(n,k)):\n h[i] = 0\nprint(sum(h))']
['Runtime Error', 'Accepted']
['s911837312', 's608127475']
[26024.0, 25768.0]
[160.0, 170.0]
[120, 141]
p02785
u932868243
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,k=map(int,input().split())\nh=list(map(int,input().split()))\nh.sort(reverse=True)\ndel h[5]\nprint(sum(h))', 'n,k=map(int,input().split())\nh=list(map(int,input().split()))\nh.sort(reverse=True)\ndel h[:k]\nprint(sum(h))']
['Runtime Error', 'Accepted']
['s322260865', 's325865620']
[26024.0, 26024.0]
[154.0, 144.0]
[105, 106]
p02785
u933717615
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N, K = map(int, input().split())\nH = list(map(int, input().split()))\n\nans = 0\nif K>=N:\n print(ans)\nelse:\n H = H.sort(reverse=True)\n for i in range(K, N):\n ans += H[i]\n print(ans)', 'N, K = map(int, input().split())\nH = list(map(int, input().split()))\n\nans = 0\nif K>=N:\n print(ans)\nelse:\n H.sort(reverse=True)\n for i in range(K, N):\n ans += H[i]\n print(ans)']
['Runtime Error', 'Accepted']
['s944015493', 's601194275']
[26024.0, 26180.0]
[146.0, 172.0]
[185, 181]
p02785
u939633554
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N, K = map(int, input().split())\nHs = map(int,input().split())\nprint(sum(sorted(Hs, reverse=True)[K::])', 'N, K = map(int, input().split())\nHs = map(int,input().split())\nprint(sum(sorted(Hs, reverse=True)[K::]))']
['Runtime Error', 'Accepted']
['s758137232', 's994946124']
[2940.0, 26024.0]
[18.0, 148.0]
[103, 104]
p02785
u944643608
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N, K = map(int,input().split())\nH = list(map(int,input().split()))\nif K >= N:\n print(0)\nelse:\n H.sort\n print(sum(H[0:N-K])', 'N, K = map(int,input().split())\nH = list(map(int,input().split()))\nif K >= N:\n print(0)\nelse:\n H.sort()\n print(sum(H[0:N-K]))']
['Runtime Error', 'Accepted']
['s086621623', 's585344865']
[3064.0, 26024.0]
[17.0, 148.0]
[125, 128]
p02785
u946322619
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n, k = map(int, input().split())\n\nh = input().split()\nh.sort(reverse=True)\n\nprint(sum(h[k:]))', 'n, k = map(int, input().split())\n\nh = list(map(int, input().split()))\nh.sort(reverse=True)\n\nprint(sum(h[k:]))\n']
['Runtime Error', 'Accepted']
['s402912533', 's544143513']
[20240.0, 26180.0]
[172.0, 151.0]
[93, 110]
p02785
u946424121
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n, k = map(int, input().split())\nh = list(map(int, input().split()))\nh = sorted(h)\nprint(sum(sorted(h)[:n-k+1]))', 'n, k = map(int, input().split())\nh = list(map(int, input().split()))\nh = sorted(h)\nif n <= k:\n print(0)\nelse:\n print(sum(sorted(h)[:n-k]))']
['Wrong Answer', 'Accepted']
['s604406677', 's304556440']
[26020.0, 26764.0]
[167.0, 164.0]
[112, 144]
p02785
u949802245
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['import math\n\nEnemyCount, slayeCount = map(int, input().split())\nenemyHealths = list(map(int, input().split(" "))).sort()\n\nif EnemyCount < slayeCount:\n slayeCount = EnemyCount\n\nfor _ in range(slayeCount):\n del enemyHealths[-1]\n\nprint(sum(enemyHealths))', 'import math\n\nEnemyCount, slayeCount = map(int, input().split())\nenemyHealths = list(map(int, input().split(" ")))\nenemyHealths.sort()\n\nif EnemyCount < slayeCount:\n slayeCount = EnemyCount\n\nfor _ in range(slayeCount):\n del enemyHealths[-1]\n\nprint(sum(enemyHealths))\n']
['Runtime Error', 'Accepted']
['s242091269', 's118671636']
[27300.0, 27300.0]
[140.0, 163.0]
[257, 271]
p02785
u955691979
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['h,n = input().split()\nw = input().split()\n\nfor i in range(0,int(n)):\n h = int(h) - int(w[i])\n\nif(h<=0):\n print("Yes")\nelse:\n print("No")', 'n,k = input().split()\nmon = input().split()\nmon = list(map(int,mon))\n\nif(int(n)<=int(k)):\n print(0)\nelif(int(k)==0):\n print(sum(mon))\nelse: \n mon.sort(reverse=True)\n for i in range(0,int(k)):\n mon[i] = 0\n \n print(sum(mon))']
['Runtime Error', 'Accepted']
['s930438718', 's218467673']
[20240.0, 26180.0]
[129.0, 164.0]
[145, 254]
p02785
u957616073
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['x = [int(i) for i in input().split(" ")]\ns = x[1]\nm = [int(i) for i in input().split(" ")]\nif s == 0:\n print(sum(m))\nelse:\n m = sorted(m)[0:-s:1]\n print(m)', 'x = [int(i) for i in input().split(" ")]\ns = x[1]\nm = [int(i) for i in input().split(" ")]\nif s == 0:\n print(sum(m))\nelse:\n m = sorted(m)[0:-s:1]\n print(sum(m))']
['Wrong Answer', 'Accepted']
['s416217106', 's934889483']
[25768.0, 26024.0]
[174.0, 162.0]
[158, 163]
p02785
u966546644
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N, K = map(int, input().split())\nlife = list(map(int, input().split()))\n\nNlife = sorted(life, reverse=True)\n\n\nif K >= 1:\n del Nlife[:K-1]\n \n\nanswer = sum(Nlife)\n\nprint(answer)', 'N, K = map(int, input().split())\nlife = list(map(int, input().split()))\n\nNlife = sorted(life)\n\n\nif K >= 1:\n del Nlife[:K-1]\n \n\nanswer = sum(Nlife)\n\nprint(answer)', 'N, K = map(int, input().split())\nlife = list(map(int, input().split()))\n\nNlife = sorted(life, reverse=True)\n\n\nif K >= 1:\n del Nlife[:K]\n \n\nanswer = sum(Nlife)\n\nprint(answer)\n']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s209844767', 's996469026', 's318531078']
[26024.0, 26024.0, 26176.0]
[147.0, 147.0, 148.0]
[177, 163, 176]
p02785
u969211566
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n,k = map(int,input().split())\nh = list(map(int,input().split()))\n\ndel h[n::]\nh.sort()\nif k != 0:\n del h[-k:]\nprint(h)\nprint(sum(h))', 'n,k = map(int,input().split())\nh = list(map(int,input().split()))\n\ndel h[n::]\nh.sort()\nif k != 0:\n del h[-k:]\nprint(sum(h))']
['Wrong Answer', 'Accepted']
['s745665059', 's838973312']
[25768.0, 26024.0]
[165.0, 152.0]
[133, 124]
p02785
u971654915
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
["from sys import stdin\n\n\ndef main(inp1, inp2):\n n, k = [int(i) for i in inp1.split(sep=' ')]\n h_list = sorted([int(i) for i in inp2.split(sep=' ')])\n\n print(h_list)\n num_enemy = n\n enable_special = k\n\n if enable_special >= num_enemy:\n return 0\n elif enable_special == 0:\n return sum(h_list)\n else:\n return sum(h_list[:-enable_special])\n\n\nif __name__ == '__main__':\n input1 = stdin.readline().rstrip()\n input2 = stdin.readline().rstrip()\n ret = main(input1, input2)\n print(ret)", "from sys import stdin\n\n\ndef main(inp1, inp2):\n n, k = [int(i) for i in inp1.split(sep=' ')]\n h_list = sorted([int(i) for i in inp2.split(sep=' ')])\n\n num_enemy = n\n enable_special = k\n\n if enable_special >= num_enemy:\n return 0\n elif enable_special == 0:\n return sum(h_list)\n else:\n return sum(h_list[:-enable_special])\n\n\nif __name__ == '__main__':\n input1 = stdin.readline().rstrip()\n input2 = stdin.readline().rstrip()\n ret = main(input1, input2)\n print(ret)"]
['Wrong Answer', 'Accepted']
['s776800441', 's501377978']
[28112.0, 27952.0]
[182.0, 154.0]
[532, 514]
p02785
u974292946
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n, k = map(int, input().split())\nH = list(map(int, input().split()))\n\nif k == 0:\n print(sum(H))\n exit()\n\nH.sort(reverse=True)\ndel H[:k + 1]\nprint(sum(H))', 'n, k = map(int, input().split())\nH = list(map(int, input().split()))\n\nif k == 0:\n print(sum(H))\n exit()\n\nH.sort(reverse=True)\ndel H[:k + 1]\nif not H:\n print(0)\nelse :\n print(sum(H))', 'n, k = map(int, input().split())\nH = list(map(int, input().split()))\n\nif k == 0:\n print(sum(H))\n exit()\n\nif n <= k:\n print(0)\n exit()\n\nH.sort(reverse=True)\ndel H[:k]\nprint(sum(H))\n']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s215480037', 's559327760', 's514437603']
[26016.0, 26764.0, 26024.0]
[156.0, 148.0, 149.0]
[159, 193, 192]
p02785
u977141657
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['n, k = map(int, input().split())\nh = list(map(int, input().split()))\nh = h.sort()\n\nif k >= n:\n print(0)\n \nelse:\n print(sum(h[:n-k]))', 'n, k = map(int, input().split())\nh = list(map(int, input().split()))\nh.sort()\n\nif k >= n:\n print(0)\n \nelse:\n print(sum(h[:n-k]))']
['Runtime Error', 'Accepted']
['s893681382', 's512830361']
[25768.0, 26180.0]
[152.0, 149.0]
[135, 131]
p02785
u981693103
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N, K = map(int, input().split())\nH = list(map(int, input().split()))\nif N <= K:\n print(0)\nelif K == 0:\n print(sum(H))\nelse:\n H = sort(H)\n print(sum(H[:-K]))', 'N, K = map(int, input().split())\nH = list(map(int, input().split()))\nH = sort(H)\nprint(sum(H[:-K]))', 'N, K = map(int, input().split())\nH = list(map(int, input().split()))\nif N <= K:\n print(0)\nelif K == 0:\n print(sum(H))\nelse:\n H = sorted(H)\n print(sum(H[:-K]))\n']
['Runtime Error', 'Runtime Error', 'Accepted']
['s633757352', 's771213359', 's362502485']
[26024.0, 26024.0, 26764.0]
[71.0, 68.0, 154.0]
[160, 99, 163]
p02785
u982749462
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N,K = map(int, input().split())\nprint(N,K)\nH = list(map(int, input().split()))\n#H = input().split()\n#print(H)\nif N<=K:\n print(0)\nelse:\n \n \n \n H.sort(reverse=True)\n newH = H[K:]\n sumH = sum(newH)\n print(sumH)', 'N,K = map(int, input().split())\n\nH = list(map(int, input().split()))\n#H = input().split()\n#print(H)\nif N<=K:\n print(0)\nelse:\n \n \n \n H.sort(reverse=True)\n newH = H[K:]\n sumH = sum(newH)\n print(sumH)']
['Wrong Answer', 'Accepted']
['s342266918', 's735043088']
[26180.0, 26764.0]
[150.0, 151.0]
[378, 379]
p02785
u998169143
2,000
1,048,576
Fennec is fighting with N monsters. The _health_ of the i-th monster is H_i. Fennec can do the following two actions: * Attack: Fennec chooses one monster. That monster's health will decrease by 1. * Special Move: Fennec chooses one monster. That monster's health will become 0. There is no way other than Attack and Special Move to decrease the monsters' health. Fennec wins when all the monsters' healths become 0 or below. Find the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.
['N, K = [int(i) for i in input().split()]\nH = [int(i) for i in input().split()]\n\nsorted_H = sorted(H)\nnum = np.maximum(0, N-K)\nanswer = sum(sorted_H[:num])\nprint(answer)', 'import numpy as np\nN, K = [int(i) for i in input().split()]\nH = [int(i) for i in input().split()]\n\nsorted_H = sorted(H)\nnum = np.maximum(0, N-K)\nanswer = sum(sorted_H[:num])\nprint(answer)']
['Runtime Error', 'Accepted']
['s568125906', 's917507673']
[26024.0, 34220.0]
[155.0, 291.0]
[168, 187]
p02786
u005318559
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['h = int(input())\n\nres = 0\ni = 1\n\nwhile h > 0:\n h = h//2\n res = res + i\n i*2\nprint(res)', 'h = int(input())\n\nres = 0\ni = 1\nwhile h > 0:\n h = h//2\n res = res + i\n i *= 2\nprint(res)\n\n']
['Wrong Answer', 'Accepted']
['s553617580', 's983231123']
[2940.0, 2940.0]
[17.0, 17.0]
[89, 93]
p02786
u017415492
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['import math\nh=int(input())\nk=math.ceil(math.log2(h))\nprint(2**k-1)\n\n ', 'import math\nh=int(input())\nk=math.ceil(math.log2(h))\nif k==math.log2(h):\n print(2**(k+1)-1)\nelse:\n print(2**k-1)']
['Wrong Answer', 'Accepted']
['s937002033', 's649720637']
[3444.0, 3188.0]
[21.0, 19.0]
[70, 114]
p02786
u021916304
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['def ii():return int(input())\ndef iim():return map(int,input().split())\ndef iil():return list(map(int,input().split()))\ndef ism():return map(str,input().split())\ndef isl():return list(map(str,input().split()))\n\nh = ii()\ncount = 0\nwhile h >= 2:\n h = (h+1)//2\n count += 1\n#print(count)\nif count == 0:\n print(1)\nelse:\n print(2**(count)-1)\n', 'def ii():return int(input())\ndef iim():return map(int,input().split())\ndef iil():return list(map(int,input().split()))\ndef ism():return map(str,input().split())\ndef isl():return list(map(str,input().split()))\n\nh = ii()\ncount = 0\nans = 1\nwhile h >= 2:\n h = h//2\n ans += 2*count\n count += 1\n#print(ans,count)\nif count == 0:\n print(1)\nelse:\n print(2**(count+1)-1)\n']
['Wrong Answer', 'Accepted']
['s316337098', 's296483617']
[3064.0, 3064.0]
[17.0, 17.0]
[347, 376]
p02786
u038408819
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['H = int(input())\ns = 1\nwhile H!=0:\n H = divmod(H, 2)[0]\n s *= 2\ns = s / 2\nprint(int(s + p))\n', 'H = int(input())\ns = 1\nwhile H!=0:\n H = divmod(H, 2)[0]\n s *= 2\n\nprint(int(s / 2))\n', 'H = int(input())\ns = 1\nwhile H!=0:\n H = divmod(H, 2)[0]\n s *= 2\ns = s / 2\np = s - 1\nprint(int(s + p))\n']
['Runtime Error', 'Wrong Answer', 'Accepted']
['s533799940', 's596029448', 's644615024']
[2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[98, 89, 108]
p02786
u046592970
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['import math\nh = int(input())\nk = (math.log2(h))\nprint((2**(k+1)-1))', 'import math\nh = int(input())\nk = int(math.log2(h))\nprint((2**(k+1)-1))']
['Wrong Answer', 'Accepted']
['s575274817', 's123674903']
[2940.0, 2940.0]
[17.0, 17.0]
[67, 70]
p02786
u051401873
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['import math\na = []\nb = []\ntoki = []\nh, n = map(int, input().split())\nfor i in range(n):\n ai, bi = map(float, input().split())\n toki.append((ai, bi))\n\ndef yeah(hp, toki):\n mp = 0\n dps = 0\n kou = 0\n for ai, bi in toki:\n t = ai\n if (hp - ai) <= 0:\n t = hp\n dps2 = float(t/bi)\n if dps <= dps2:\n dps = dps2\n mp = bi\n kou = t\n return (hp-kou, mp)\nmp = 0\nzan = h\nwhile True:\n zan, mp2 = yeah(zan, toki)\n mp += mp2\n if zan <=0:\n break\nprint(int(mp))\n ', 'import math \nh = int(input())\nans = 0\nt = int(math.log2(h)+1)\n\nfor i in range(t):\n ans += 2**i\nprint(ans)']
['Runtime Error', 'Accepted']
['s998522218', 's615048213']
[3064.0, 3060.0]
[18.0, 18.0]
[490, 106]
p02786
u053856575
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['h,n = map(int,input().split())\n\nx = []\ny = []\n\nfor i in range(n):\n a,b = map(int,input().split())\n x.append(a)\n y.append(b)\n\ndef knapsack(N,W,weight,value):\n inf=float("inf")\n dp=[[inf for i in range(W+1)] for j in range(N+1)]\n for i in range(W+1): dp[0][i]=inf\n\n for i in range(N):\n for w in range(W+1):\n m = dp[i][w]\n p = value[i]\n q = weight[i]\n while w >= q:\n if w - q >= 0:\n m=min(dp[i][w-q]+p,m)\n p += value[i]\n q += weight[i]\n m=min(dp[i][w-q]+p,m,p)\n dp[i+1][w] = m\n return dp[N][W]\n\nk = knapsack(n,h,x,y)\nprint(k)', 'h = int(input())\n\ncount = 1\nans = 0\n\nwhile h != 0:\n ans += count\n h = h//2\n count *=2\n\nprint(ans)']
['Runtime Error', 'Accepted']
['s343953824', 's175488787']
[3064.0, 2940.0]
[18.0, 18.0]
[629, 106]
p02786
u056626722
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['import math\nprint(2**int(math.log2(int(input())))-1)\n', '2**log2(int(input().split()[0]))-1\n\n', 'print(2**log2(int(input()))-1)\n', 'import math\nprint(2**int(math.log2(int(input()))+1)-1)']
['Wrong Answer', 'Runtime Error', 'Runtime Error', 'Accepted']
['s194189485', 's635013675', 's945800455', 's641046782']
[3188.0, 2940.0, 2940.0, 3060.0]
[22.0, 17.0, 17.0, 20.0]
[53, 36, 31, 54]
p02786
u060694763
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['import math\nH = int(input())\n\ncount = 0\ncount = int(math.log2(H))\n\ntotal = 0\ntotal = (1 - (2**(count + 1)))/(1 - 2)\nprint(total)\n', 'import math\nH = int(input())\n\ncount = 0\ncount = int(math.log2(H))\n\ntotal = 0\ntotal = int((1 - (2**(count + 1)))/(1 - 2))\nprint(total)\n']
['Wrong Answer', 'Accepted']
['s200369016', 's262059928']
[3188.0, 3064.0]
[18.0, 17.0]
[129, 134]
p02786
u065137691
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['H = int(input())\n\ncnt = 0\n\nwhile True:\n H //= 2\n cnt += 1\n\n if H == 0:\n break\n\nprint(cnt)\nprint(2**cnt-1)\n\n', 'H = int(input())\n\ncnt = 0\n\nwhile True:\n H //= 2\n cnt += 1\n\n if H == 0:\n break\n\nprint(2**cnt-1)\n\n']
['Wrong Answer', 'Accepted']
['s612893344', 's455192631']
[8980.0, 9016.0]
[30.0, 28.0]
[123, 112]
p02786
u065774356
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['H=int(input())\nA=1\nif H==1:\n print(1)\nelse:\n while H>=A:\n A*=2', 'H=int(input())\nA=1\nif H==1:\n print(1)\nelse:\n while H>=A:\n A*=2\n print(A-1)\n ']
['Wrong Answer', 'Accepted']
['s697248996', 's701093019']
[3064.0, 2940.0]
[17.0, 17.0]
[75, 98]
p02786
u067694718
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['def a(x):\n if x == 1: return 1\n if x > 1: return a((x + 1) // 2)) * 2 + 1\n\nprint(a(int(input())))\n', 'def a(x):\n if x == 1: return 1\n if x > 1: return a((a(x // 2)) * 2 + 1\n\nprint(a(int(input())))\n', 'def a(x):\n if x == 1: return 1\n if x > 1: return a(x // 2) * 2 + 1\n\nprint(a(int(input())))\n']
['Runtime Error', 'Runtime Error', 'Accepted']
['s644375161', 's675456706', 's152065969']
[2940.0, 2940.0, 3064.0]
[18.0, 17.0, 17.0]
[104, 101, 97]
p02786
u075303794
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['import bisect\n\nH=int(input())\nA=[2**x for x in range(51)]\nif H%4==0:\n H+=1\nindex=bisect.bisect_left(A,H)\nprint(sum(A[:index]))', 'import bisect\n\nH=int(input())\nA=[2**x for x in range(51)]\nindex=bisect.bisect_right(A,H) \nprint(sum(A[:index]))']
['Wrong Answer', 'Accepted']
['s222757464', 's948704904']
[8996.0, 9020.0]
[28.0, 29.0]
[127, 111]
p02786
u081193942
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['h = int(input())\n\nlhb = len(format(h, "b"))\nprint(2 ** lhb - 1 + lhb)', 'h = int(input())\n\nlhb = len(format(h, "b"))\nprint(2 ** lhb - 1)']
['Wrong Answer', 'Accepted']
['s907565418', 's175240751']
[3064.0, 2940.0]
[19.0, 17.0]
[70, 64]
p02786
u081340269
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['#D\n\nH = int(input())\nc = 1\nwhile H>1:\n H = math.floor(H/2)\n c += 1\nprint(sum([2**i for i in range(c)]))', '#D\nimport math\nH = int(input())\nc = 1\nwhile H>1:\n H = math.floor(H/2)\n c += 1\nprint(sum([2**i for i in range(c)]))']
['Runtime Error', 'Accepted']
['s629699375', 's371944420']
[2940.0, 3060.0]
[17.0, 17.0]
[105, 116]
p02786
u082748852
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
["#!/user/bin/env python\n\n\n# -*- coding: utf-8 -*-\n\n\n__author_ = 'Maruta Yuzuha'\n__version_ = '1.0.0'\n__date__ = '2019/12/25'\n\nimport math\ndef main():\n \n s = int(input())\n a = 0 \n b = 0 \n while s > 0:\n s = float(s / 2)\n print(s)\n a += pow(2, b)\n b += 1\n if s < 1:\n break\n print(a)\n return 0\n\nif __name__ == '__main__':\n \n \n\n \n \n import doctest\n doctest.testmod()\n\n \n import sys\n sys.exit(main())", "#!/user/bin/env python\n\n\n# -*- coding: utf-8 -*-\n\n\n__author_ = 'Maruta Yuzuha'\n__version_ = '1.0.0'\n__date__ = '2019/12/25'\n\nimport math\ndef main():\n \n s = int(input())\n a = 0 \n b = 0 \n while s > 0:\n s = float(s / 2)\n a += pow(2, b)\n b += 1\n if s < 1:\n break\n print(a)\n return 0\n\nif __name__ == '__main__':\n \n \n\n \n \n import doctest\n doctest.testmod()\n\n \n import sys\n sys.exit(main())"]
['Wrong Answer', 'Accepted']
['s308314377', 's701060183']
[8640.0, 7492.0]
[110.0, 96.0]
[1429, 1412]
p02786
u082978753
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['%%time\nH = int(input())\ncounter = 0\ni = H\nwhile i > 1:\n i = i//2\n counter += 1\n \nans = 2**(counter+1)-1\nprint(ans)', 'H = int(input())\ncounter = 0\ni = H\nwhile i > 1:\n i = i//2\n counter += 1\n \nans = int(2**(counter+1)-1)\nprint(ans)']
['Runtime Error', 'Accepted']
['s149084228', 's478458330']
[3064.0, 2940.0]
[17.0, 17.0]
[123, 121]
p02786
u088552457
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['import math\nN = int(input())\n\ndef waru2(n):\n c = 0\n while True:\n if n == 1:\n break\n n = int(n/2)\n c += 1\n return c\n \nkai = 0\nk = 0\nwhile True:\n if k >= N:\n break\n k = 2 ** kai\n kai += 1\n\na = waru2(kai-1)\n\nc = 0\nfor i in range(a):\n c += 2**i\n \nprint(c)', 'N = int(input())\n\nkai = 0\nk_sum = 0\nwhile True:\n if k_sum >= N:\n break\n k_sum += 2 ** kai\n kai += 1\n \nprint(k_sum)']
['Wrong Answer', 'Accepted']
['s234903490', 's011139623']
[3060.0, 3064.0]
[2104.0, 17.0]
[276, 121]
p02786
u092387689
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['h = int(input())\n\nadd = 1\nans = 0\nwhile(h!=1):\n h = (h+1)//2\n ans += add\n add *= 2\n print(h,ans)\n\nans += add\nprint(ans)', 'h = int(input())\n\nadd = 1\nans = 0\nwhile(h!=1):\n h = h//2\n ans += add\n add *= 2\n \nans += add\nprint(ans)']
['Wrong Answer', 'Accepted']
['s901434826', 's149946820']
[3060.0, 2940.0]
[18.0, 18.0]
[131, 114]
p02786
u094999522
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['print(~-1<<len(bin(int(input()))-3))', 'print(~-(1<<len(bin(int(input()))[2:])))']
['Runtime Error', 'Accepted']
['s828975084', 's620355791']
[2940.0, 3060.0]
[17.0, 20.0]
[36, 40]
p02786
u095094246
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['from math import log2,ceil\nh = int(input())\nprint(2**ceil(log2(h))-1)', 'from math import log2,floor\nh = int(input())\nprint(2**(floor(log2(h))+1)-1)']
['Wrong Answer', 'Accepted']
['s594526428', 's122066971']
[3188.0, 2940.0]
[19.0, 18.0]
[69, 75]
p02786
u098679988
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['for i in range(10000):\n if n > 2**i:\n pass\n elif n == 1:\n print(1)\n elif n == 2**i:\n print(4*(2**(i)//2)-1)\n break\n else:\n print(4*(2**(i-1)//2)-1)\n break', 'n = int(input())\nflag = True\nans = 1\nnow = n\ncount = 1\n\nfor i in range(10000):\n if n > 2**i:\n pass\n else:\n print(4*(2**(i-1)//2)-1)\n break', 'n = int(input())\nflag = True\nans = 1\nnow = n\ncount = 1\nwhile flag == True:\n if now == 1:\n ans += count\n print(ans)\n break\n now = now/2\n if count != 1:\n ans += count\n print("now",now)\n # print(ans)\n count = count*2\n # print(count)\n else:\n print("now",now)\n # print(ans)\n count = 1*2', 'n = int(input())\nflag = True\nans = 1\nnow = n\ncount = 1\n\n\nfor i in range(10000):\n if n > 2**i:\n pass\n elif n == 1:\n print(1)\n break\n elif n == 2**i:\n print(4*(2**(i)//2)-1)\n break\n else:\n print(4*(2**(i-1)//2)-1)\n break']
['Runtime Error', 'Wrong Answer', 'Wrong Answer', 'Accepted']
['s493727411', 's682282889', 's908896990', 's840375674']
[2940.0, 3060.0, 5108.0, 3060.0]
[18.0, 17.0, 2104.0, 17.0]
[208, 165, 370, 279]
p02786
u101839330
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['h = int(input())\nif(h == 1):\n print(1)\n exit()\ncnt = 1\npoint = 0\nlist = [0 for i in range(100)]\nlist[1] = 1\nwhile True:\n list[cnt] = ((list[cnt-1] * 2) +1)\n point += 2**cnt\n cnt += 1\n if(point>h):\n break\nprint(list[cnt-1]*2+1)', 'h = int(input())\nif(h == 1):\n print(1)\n exit()\ncnt = 1\npoint = 0\nlist = [0 for i in range(100)]\nwhile (h>point+1):\n list[cnt] = ((list[cnt-1] * 2) +1)\n point += 2**cnt\n cnt += 1\n\nprint(list[cnt-1]*2+1)']
['Wrong Answer', 'Accepted']
['s498894789', 's946958292']
[3064.0, 3064.0]
[18.0, 18.0]
[235, 206]
p02786
u121700322
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['import numpy as np\n\n\nH, N = map(int, input().split())\nAB = [list(map(int, input().split())) for _ in range(N)]\na, b = np.array(AB, dtype=np.int64).reshape(N, 2).T\n\nd = np.zeros(H + 1, dtype=np.int64)\n\nfor hp in range(1, H + 1):\n c = d[np.maximum(hp - a, 0)] + b\n d[hp] = np.amin(c)\n print(hp, np.amin(c))\n\nprint(d[H])', 'H = int(input())\n\n# monster HP is X\n# X==1 >> X=0\n# X>1 other 2 monster appear. These 2 mosters have [X/2] HP.\n\n# two actions\n\n# special: make vitality 0. Fenek can use K times of specials.\n# print(type(2*10**14))\n\n# from collections import deque\n#\n# print(f"H={H}")\n#\n\n\n\n#\n# while monsters:\n# # for _ in range(3):\n\n# # print(f"attack to monster(HP={hp})")\n# if hp != 1:\n\n# hp_hp = hp//2\n\n\n\n\ni = 1\nwhile H > 1:\n H //= 2\n i += 1\n\nprint(2**i - 1)']
['Runtime Error', 'Accepted']
['s711297004', 's925543100']
[12500.0, 2940.0]
[149.0, 17.0]
[326, 764]
p02786
u123579949
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['import math\nprint(2**math.ceil(math.log2(int(input())))-1)', 'import math\nprint(2**(math.floor(math.log2(int(input())))+1)-1)']
['Wrong Answer', 'Accepted']
['s543998212', 's531999171']
[9148.0, 9188.0]
[29.0, 33.0]
[58, 63]
p02786
u125799132
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['H = int(input())\n\nans = 1\nfor i in range(1, 40):\n if int(H/2) >= 1:\n ans += 2**i\n H = int(H/2)\n else:\n ans += 2**(i-1)\n break\n\nprint(ans)', 'H = int(input())\n\nans = 1\nfor i in range(1, 40):\n if int(H/2) >= 1:\n ans += 2**i\n H = int(H/2)\n# print(i, H)\n else:\n ans += 2**(i-1)\n break\n\nprint(ans)', "H = int(input())\n\nans = 1\nif H != 1:\n h = H\n for i in range(1, 40):\n if int(h/2) >= 2:\n# print(i, ans, h, 'a')\n ans += 2**i\n h = int(h/2)\n else:\n# print(i, ans, h, 'b')\n ans += 2**i\n break\n\nprint(ans)"]
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s297668543', 's955073335', 's063437764']
[9084.0, 8980.0, 9084.0]
[27.0, 33.0, 27.0]
[171, 192, 286]
p02786
u127228093
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['import math\n\nmonster_hp_list = []\nmonster_hp_list.append(int(input()))\n\ncount = 0\n\nwhile(len(monster_hp_list)>0):\n \n if monster_hp_list[0] == 1:\n monster_hp_list.pop(0)\n count += 1\n elif monster_hp_list[0] > 1:\n harved_hp = math.floor(monster_hp_list[0]/2)\n monster_hp_list.pop(0)\n for twice in range(2):\n monster_hp_list.append(harved_hp)\n \n count += 1', 'import math\n\nmonster_hp = int(input())\nattack_count = 0\n\ndef attack_count_calc(monster_hp):\n if monster_hp == 1: \n return attack_count + 1\n return attack_count + (2 * attack_count_calc(monster_hp//2) + 1)\n\nprint(attack_count_calc(monster_hp))\n']
['Wrong Answer', 'Accepted']
['s299577183', 's957596742']
[5828.0, 2940.0]
[2108.0, 17.0]
[426, 271]
p02786
u128661070
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['# -*- coding:utf-8 -*-\n\nh = int(input())\ncount = 1\nwhile(h > 1):\n h = (h //2)\n count += 1\nprint(2**count)', '# -*- coding:utf-8 -*-\n\nh = int(input())\ncount = 1\nwhile(h > 1):\n h = (h //2)\n count += 1\nprint(2**count -1)']
['Wrong Answer', 'Accepted']
['s668204740', 's741069754']
[2940.0, 2940.0]
[17.0, 17.0]
[107, 110]
p02786
u130587994
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['h = int(input())\n\ndef count(h):\n if(h<=0):\n return 0\n else:\n return 1 + 2*count(h/2)\n\nprint(count(h))', 'h = int(input())\n\ndef count1(h):\n if(h==0):\n return 0\n if(h==1):\n return 1\n return 1 + 2*count1(h//2)\n \nprint(count1(h))']
['Runtime Error', 'Accepted']
['s943821245', 's066815518']
[3940.0, 2940.0]
[74.0, 17.0]
[121, 146]
p02786
u131638468
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['h=int(input())\ndef f(n):\n if n==1:\n return 1\n else:\n return 2 * f(n) + 1\nhit=f(h)\nprint(hit)', 'h=int(input())\ndef f(n):\n if n==1:\n return 1\n else:\n return 2 * f(n//2) + 1\nhit=f(h)\nprint(hit)']
['Runtime Error', 'Accepted']
['s379416811', 's974420740']
[3864.0, 2940.0]
[72.0, 17.0]
[100, 103]
p02786
u139282395
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['n = input()\nn = int(n)\ncount = 0\nattack = 0\n\nif n > 1:\n while n > 1:\n n = n / 2 \n count = count + 1\n for i in range(0, count):\n attack = attack + (2**i)\n print(attack)\nelse:\n print("1")\n ', 'n = input()\nn = int(n)\ncount = 0\nattack = 0\n\nif n > 1:\n while n >= 1:\n n = n / 2 \n count = count + 1\n for i in range(0, count):\n attack = attack + (2**i)\n print(attack)\nelse:\n print("1")']
['Wrong Answer', 'Accepted']
['s721478829', 's183400271']
[2940.0, 3060.0]
[17.0, 17.0]
[201, 199]
p02786
u151079949
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['H=int(input())\nimport math\nj=(math.log2(H))//1\n\nprint(2**(j+1)-1)', 'H=int(input())\nimport math\nj=(math.log2(H))//1\n\nprint(int(2**(j+1)-1))']
['Wrong Answer', 'Accepted']
['s896420297', 's446449318']
[3060.0, 3188.0]
[18.0, 19.0]
[65, 70]
p02786
u152402277
2,000
1,048,576
Caracal is fighting with a monster. The _health_ of the monster is H. Caracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens: * If the monster's health is 1, it drops to 0. * If the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \lfloor X/2 \rfloor. (\lfloor r \rfloor denotes the greatest integer not exceeding r.) Caracal wins when the healths of all existing monsters become 0 or below. Find the minimum number of attacks Caracal needs to make before winning.
['HP = int(input())\nif HP == 1:\n print("1")\n\nelse:\n #print(bin(HP))\n print(pow(2,len(bin(HP))-3))', 'HP = int(input())\nif HP == 1:\n print("1")\n\nelse:\n #print(bin(HP))\n print(pow(2,len(bin(HP))-2)-1)']
['Wrong Answer', 'Accepted']
['s045856188', 's851150024']
[3060.0, 2940.0]
[17.0, 17.0]
[98, 100]