contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
962 | A | Equator | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Polycarp has created his own training plan to prepare for the programming contests. He will train for $n$ days, all days are numbered from $1$ to $n$, beginning from the first.
On the $i$-th day Polycarp will necessarily solve $a_i$ problems. One evening Polycarp plans to celebrate the equator. He will celebrate it on... | The first line contains a single integer $n$ ($1 \le n \le 200\,000$) — the number of days to prepare for the programming contests.
The second line contains a sequence $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 10\,000$), where $a_i$ equals to the number of problems, which Polycarp will solve on the $i$-th day. | Print the index of the day when Polycarp will celebrate the equator. | [
"4\n1 3 2 1\n",
"6\n2 2 2 2 2 2\n"
] | [
"2\n",
"3\n"
] | In the first example Polycarp will celebrate the equator on the evening of the second day, because up to this day (inclusive) he will solve $4$ out of $7$ scheduled problems on four days of the training.
In the second example Polycarp will celebrate the equator on the evening of the third day, because up to this day (... | 0 | [
{
"input": "4\n1 3 2 1",
"output": "2"
},
{
"input": "6\n2 2 2 2 2 2",
"output": "3"
},
{
"input": "1\n10000",
"output": "1"
},
{
"input": "3\n2 1 1",
"output": "1"
},
{
"input": "2\n1 3",
"output": "2"
},
{
"input": "4\n2 1 1 3",
"output": "3"
}... | 1,523,900,039 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 78 | 7,065,600 | num_dias = int(input())
entrada = list(map(int, input().split()))
prob_res = 0
for i in range(len(entrada)):
prob_res += entrada[i]
if prob_res >= num_dias:
print(i+1)
break;
| Title: Equator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has created his own training plan to prepare for the programming contests. He will train for $n$ days, all days are numbered from $1$ to $n$, beginning from the first.
On the $i$-th day Polycarp will necessarily solve... | ```python
num_dias = int(input())
entrada = list(map(int, input().split()))
prob_res = 0
for i in range(len(entrada)):
prob_res += entrada[i]
if prob_res >= num_dias:
print(i+1)
break;
``` | 0 | |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,696,251,954 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | def is_almost_lucky(n):
# Lucky numbers are 4 and 7, and any multiple of them
lucky_numbers = [4, 7, 44, 77, 444, 777]
# Check if n is divisible by any lucky number
for lucky in lucky_numbers:
if n % lucky == 0:
return "YES"
return "NO"
# Read the input numb... | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
def is_almost_lucky(n):
# Lucky numbers are 4 and 7, and any multiple of them
lucky_numbers = [4, 7, 44, 77, 444, 777]
# Check if n is divisible by any lucky number
for lucky in lucky_numbers:
if n % lucky == 0:
return "YES"
return "NO"
# Read the ... | 0 | |
235 | A | LCM Challenge | PROGRAMMING | 1,600 | [
"number theory"
] | null | null | Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive integers (they don't have to be distinct) which are not greater than *n*. Can you help me to find ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the *n* mentioned in the statement. | Print a single integer — the maximum possible LCM of three not necessarily distinct positive integers that are not greater than *n*. | [
"9\n",
"7\n"
] | [
"504\n",
"210\n"
] | The least common multiple of some positive integers is the least positive integer which is multiple for each of them.
The result may become very large, 32-bit integer won't be enough. So using 64-bit integers is recommended.
For the last example, we can chose numbers 7, 6, 5 and the LCM of them is 7·6·5 = 210. It is ... | 500 | [
{
"input": "9",
"output": "504"
},
{
"input": "7",
"output": "210"
},
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "60"
},
{
"input": "33",
"output": "32736"
},
{
"input": "21",
"output": ... | 1,696,861,669 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 60 | 0 | def gcd(a,b):
max1 = max(a,b)
min1 = min(a,b)
while max1%min1 !=0:
temp = max1
max1 = min1
min1 = temp%min1
return min1
def lcm(a,b):
lcm1 = (a*b)//gcd(a,b)
return lcm1
n = int(input())
a,b,c = n , n-1, n-2
res = lcm(a,b)
ans = lcm(res,c)
print(ans) | Title: LCM Challenge
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive... | ```python
def gcd(a,b):
max1 = max(a,b)
min1 = min(a,b)
while max1%min1 !=0:
temp = max1
max1 = min1
min1 = temp%min1
return min1
def lcm(a,b):
lcm1 = (a*b)//gcd(a,b)
return lcm1
n = int(input())
a,b,c = n , n-1, n-2
res = lcm(a,b)
ans = lcm(res,c)
print(a... | -1 | |
583 | A | Asphalting Roads | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers of the roads that form them.
Sand roads have long been recognized out of date, so the decision was ma... | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of vertical and horizontal roads in the city.
Next *n*2 lines contain the order of intersections in the schedule. The *i*-th of them contains two numbers *h**i*,<=*v**i* (1<=≤<=*h**i*,<=*v**i*<=≤<=*n*), separated by a space, and meaning that the inte... | In the single line print the numbers of the days when road works will be in progress in ascending order. The days are numbered starting from 1. | [
"2\n1 1\n1 2\n2 1\n2 2\n",
"1\n1 1\n"
] | [
"1 4 \n",
"1 \n"
] | In the sample the brigade acts like that:
1. On the first day the brigade comes to the intersection of the 1-st horizontal and the 1-st vertical road. As none of them has been asphalted, the workers asphalt the 1-st vertical and the 1-st horizontal road; 1. On the second day the brigade of the workers comes to the i... | 500 | [
{
"input": "2\n1 1\n1 2\n2 1\n2 2",
"output": "1 4 "
},
{
"input": "1\n1 1",
"output": "1 "
},
{
"input": "2\n1 1\n2 2\n1 2\n2 1",
"output": "1 2 "
},
{
"input": "2\n1 2\n2 2\n2 1\n1 1",
"output": "1 3 "
},
{
"input": "3\n2 2\n1 2\n3 2\n3 3\n1 1\n2 3\n1 3\n3 1\n2 ... | 1,443,891,116 | 416 | Python 3 | OK | TESTS | 39 | 78 | 0 | n = int(input())
a = []
b = []
for i in range(1, n*n+1):
x, y = map(int, input().split())
if x not in a and y not in b:
print(i, end=' ')
a.append(x)
b.append(y)
| Title: Asphalting Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers ... | ```python
n = int(input())
a = []
b = []
for i in range(1, n*n+1):
x, y = map(int, input().split())
if x not in a and y not in b:
print(i, end=' ')
a.append(x)
b.append(y)
``` | 3 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,554,043,557 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 140 | 819,200 | import re
ch=input()
chs=ch[ch.index('h'):]
if re.match(r"h{1,}?.*e{1,}?.*l{2,}?.*o{1,}?.*", chs) is not None:
print("YES")
else:
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
import re
ch=input()
chs=ch[ch.index('h'):]
if re.match(r"h{1,}?.*e{1,}?.*l{2,}?.*o{1,}?.*", chs) is not None:
print("YES")
else:
print("NO")
``` | 0 |
104 | A | Blackjack | PROGRAMMING | 800 | [
"implementation"
] | A. Blackjack | 2 | 256 | One rainy gloomy evening when all modules hid in the nearby cafes to drink hot energetic cocktails, the Hexadecimal virus decided to fly over the Mainframe to look for a Great Idea. And she has found one!
Why not make her own Codeforces, with blackjack and other really cool stuff? Many people will surely be willing to... | The only line contains *n* (1<=≤<=*n*<=≤<=25) — the required sum of points. | Print the numbers of ways to get the second card in the required way if the first card is the queen of spades. | [
"12\n",
"20\n",
"10\n"
] | [
"4",
"15",
"0"
] | In the first sample only four two's of different suits can earn the required sum of points.
In the second sample we can use all tens, jacks, queens and kings; overall it's 15 cards, as the queen of spades (as any other card) is only present once in the pack of cards and it's already in use.
In the third sample there ... | 500 | [
{
"input": "12",
"output": "4"
},
{
"input": "20",
"output": "15"
},
{
"input": "10",
"output": "0"
},
{
"input": "11",
"output": "4"
},
{
"input": "15",
"output": "4"
},
{
"input": "18",
"output": "4"
},
{
"input": "25",
"output": "0"
... | 1,657,900,390 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 92 | 0 | def blackjack():
number = int(input()) - 10
if number < 1 or number > 21:
print(0)
elif number == 10:
print(15)
else:
print(4)
blackjack() | Title: Blackjack
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One rainy gloomy evening when all modules hid in the nearby cafes to drink hot energetic cocktails, the Hexadecimal virus decided to fly over the Mainframe to look for a Great Idea. And she has found one!
Why not make her own Co... | ```python
def blackjack():
number = int(input()) - 10
if number < 1 or number > 21:
print(0)
elif number == 10:
print(15)
else:
print(4)
blackjack()
``` | 0 |
259 | A | Little Elephant and Chess | PROGRAMMING | 1,000 | [
"brute force",
"strings"
] | null | null | The Little Elephant loves chess very much.
One day the Little Elephant and his friend decided to play chess. They've got the chess pieces but the board is a problem. They've got an 8<=×<=8 checkered board, each square is painted either black or white. The Little Elephant and his friend know that a proper chessboard d... | The input consists of exactly eight lines. Each line contains exactly eight characters "W" or "B" without any spaces: the *j*-th character in the *i*-th line stands for the color of the *j*-th cell of the *i*-th row of the elephants' board. Character "W" stands for the white color, character "B" stands for the black co... | In a single line print "YES" (without the quotes), if we can make the board a proper chessboard and "NO" (without the quotes) otherwise. | [
"WBWBWBWB\nBWBWBWBW\nBWBWBWBW\nBWBWBWBW\nWBWBWBWB\nWBWBWBWB\nBWBWBWBW\nWBWBWBWB\n",
"WBWBWBWB\nWBWBWBWB\nBBWBWWWB\nBWBWBWBW\nBWBWBWBW\nBWBWBWWW\nBWBWBWBW\nBWBWBWBW\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you should shift the following lines one position to the right: the 3-rd, the 6-th, the 7-th and the 8-th.
In the second sample there is no way you can achieve the goal. | 500 | [
{
"input": "WBWBWBWB\nBWBWBWBW\nBWBWBWBW\nBWBWBWBW\nWBWBWBWB\nWBWBWBWB\nBWBWBWBW\nWBWBWBWB",
"output": "YES"
},
{
"input": "WBWBWBWB\nWBWBWBWB\nBBWBWWWB\nBWBWBWBW\nBWBWBWBW\nBWBWBWWW\nBWBWBWBW\nBWBWBWBW",
"output": "NO"
},
{
"input": "BWBWBWBW\nWBWBWBWB\nBWBWBWBW\nBWBWBWBW\nWBWBWBWB\nWBW... | 1,633,269,274 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 124 | 6,758,400 | for _ in range(8):
s=input()
if s=="WBWBWBWB" or s=="BWBWBWBW":
continue
else:
print("NO")
break
else:
print("YES") | Title: Little Elephant and Chess
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves chess very much.
One day the Little Elephant and his friend decided to play chess. They've got the chess pieces but the board is a problem. They've got an 8<=×<=8 checkered board, e... | ```python
for _ in range(8):
s=input()
if s=="WBWBWBWB" or s=="BWBWBWBW":
continue
else:
print("NO")
break
else:
print("YES")
``` | 3 | |
796 | A | Buying A House | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Zane the wizard had never loved anyone before, until he fell in love with a girl, whose name remains unknown to us.
The girl lives in house *m* of a village. There are *n* houses in that village, lining in a straight line from left to right: house 1, house 2, ..., house *n*. The village is also well-structured: house ... | The first line contains three integers *n*, *m*, and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*m*<=≤<=*n*, 1<=≤<=*k*<=≤<=100) — the number of houses in the village, the house where the girl lives, and the amount of money Zane has (in dollars), respectively.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=... | Print one integer — the minimum distance, in meters, from the house where the girl Zane likes lives to the house Zane can buy. | [
"5 1 20\n0 27 32 21 19\n",
"7 3 50\n62 0 0 0 99 33 22\n",
"10 5 100\n1 0 1 0 0 0 0 0 1 1\n"
] | [
"40",
"30",
"20"
] | In the first sample, with *k* = 20 dollars, Zane can buy only house 5. The distance from house *m* = 1 to house 5 is 10 + 10 + 10 + 10 = 40 meters.
In the second sample, Zane can buy houses 6 and 7. It is better to buy house 6 than house 7, since house *m* = 3 and house 6 are only 30 meters away, while house *m* = 3 a... | 500 | [
{
"input": "5 1 20\n0 27 32 21 19",
"output": "40"
},
{
"input": "7 3 50\n62 0 0 0 99 33 22",
"output": "30"
},
{
"input": "10 5 100\n1 0 1 0 0 0 0 0 1 1",
"output": "20"
},
{
"input": "5 3 1\n1 1 0 0 1",
"output": "10"
},
{
"input": "5 5 5\n1 0 5 6 0",
"outpu... | 1,575,920,041 | 2,147,483,647 | PyPy 3 | OK | TESTS | 58 | 156 | 0 | n,m,k = map(int,input().split())
a = list(map(int,input().split()))
c = []
for i in range(len(a)):
if a[i]<=k and a[i]!=0:
c.append(i)
p = []
for i in range(len(c)):
p.append(abs(c[i]-m+1)*10)
print(min(p)) | Title: Buying A House
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Zane the wizard had never loved anyone before, until he fell in love with a girl, whose name remains unknown to us.
The girl lives in house *m* of a village. There are *n* houses in that village, lining in a straight li... | ```python
n,m,k = map(int,input().split())
a = list(map(int,input().split()))
c = []
for i in range(len(a)):
if a[i]<=k and a[i]!=0:
c.append(i)
p = []
for i in range(len(c)):
p.append(abs(c[i]-m+1)*10)
print(min(p))
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string *s* written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that th... | The first line of the input contains a string *s* (1<=≤<=|*s*|<=≤<=105). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that *s* contains at least one '#' character. | If there is no way of replacing '#' characters which leads to a beautiful string print <=-<=1. Otherwise for each character '#' print a separate line containing a positive integer, the number of ')' characters this character must be replaced with.
If there are several possible answers, you may output any of them. | [
"(((#)((#)\n",
"()((#((#(#()\n",
"#\n",
"(#)\n"
] | [
"1\n2\n",
"2\n2\n1",
"-1\n",
"-1\n"
] | |*s*| denotes the length of the string *s*. | 0 | [
{
"input": "(((#)((#)",
"output": "1\n2"
},
{
"input": "()((#((#(#()",
"output": "1\n1\n3"
},
{
"input": "#",
"output": "-1"
},
{
"input": "(#)",
"output": "-1"
},
{
"input": "(((((#(#(#(#()",
"output": "1\n1\n1\n5"
},
{
"input": "#))))",
"output":... | 1,622,904,210 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 19 | 140 | 307,200 | def imprime_resultado(jogo_velha, sobra):
for i in range(jogo_velha - 1):
print(1)
print(sobra + 1)
string = input()
abre = 0
fecha = 0
jogo_velha = 0
for char in string:
if char == '(':
abre += 1
elif char == ')':
fecha += 1
else:
jogo_velha += 1
dif = abre - fec... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string *s* written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the... | ```python
def imprime_resultado(jogo_velha, sobra):
for i in range(jogo_velha - 1):
print(1)
print(sobra + 1)
string = input()
abre = 0
fecha = 0
jogo_velha = 0
for char in string:
if char == '(':
abre += 1
elif char == ')':
fecha += 1
else:
jogo_velha += 1
dif = ... | 0 | |
455 | A | Boredom | PROGRAMMING | 1,500 | [
"dp"
] | null | null | Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a*... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). | Print a single integer — the maximum number of points that Alex can earn. | [
"2\n1 2\n",
"3\n1 2 3\n",
"9\n1 2 1 3 2 2 2 2 3\n"
] | [
"2\n",
"4\n",
"10\n"
] | Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "4"
},
{
"input": "9\n1 2 1 3 2 2 2 2 3",
"output": "10"
},
{
"input": "5\n3 3 4 5 4",
"output": "11"
},
{
"input": "5\n5 3 5 3 4",
"output": "16"
},
{
"input": "5\n4 2 3 2 5",
... | 1,700,125,309 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 155 | 13,619,200 | input()
a = [int(i) for i in input().split()]
num = dict()
dp = [0]
def Add(x):
if x in num:
num[x] += 1
else:
num[x] = 1
def dinamic(i):
if i-1 in num:
return max(dp[-1], dp[-2]+i*num[i])
else:
return dp[-1]+i*num[i]
for i in range(len(a)):
Add(a... | Title: Boredom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make ... | ```python
input()
a = [int(i) for i in input().split()]
num = dict()
dp = [0]
def Add(x):
if x in num:
num[x] += 1
else:
num[x] = 1
def dinamic(i):
if i-1 in num:
return max(dp[-1], dp[-2]+i*num[i])
else:
return dp[-1]+i*num[i]
for i in range(len(a)):
... | 3 | |
483 | A | Counterexample | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"math",
"number theory"
] | null | null | Your friend has recently learned about coprime numbers. A pair of numbers {*a*,<=*b*} is called coprime if the maximum number that divides both *a* and *b* is equal to one.
Your friend often comes up with different statements. He has recently supposed that if the pair (*a*,<=*b*) is coprime and the pair (*b*,<=*c*) i... | The single line contains two positive space-separated integers *l*, *r* (1<=≤<=*l*<=≤<=*r*<=≤<=1018; *r*<=-<=*l*<=≤<=50). | Print three positive space-separated integers *a*, *b*, *c* — three distinct numbers (*a*,<=*b*,<=*c*) that form the counterexample. If there are several solutions, you are allowed to print any of them. The numbers must be printed in ascending order.
If the counterexample does not exist, print the single number -1. | [
"2 4\n",
"10 11\n",
"900000000000000009 900000000000000029\n"
] | [
"2 3 4\n",
"-1\n",
"900000000000000009 900000000000000010 900000000000000021\n"
] | In the first sample pair (2, 4) is not coprime and pairs (2, 3) and (3, 4) are.
In the second sample you cannot form a group of three distinct integers, so the answer is -1.
In the third sample it is easy to see that numbers 900000000000000009 and 900000000000000021 are divisible by three. | 500 | [
{
"input": "2 4",
"output": "2 3 4"
},
{
"input": "10 11",
"output": "-1"
},
{
"input": "900000000000000009 900000000000000029",
"output": "900000000000000009 900000000000000010 900000000000000021"
},
{
"input": "640097987171091791 640097987171091835",
"output": "64009798... | 1,632,679,416 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 62 | 6,758,400 | l,r = [int(i) for i in input().split()]
if r-l<2:
print(-1)
elif l%2==0:
print(l,l+1,l+2)
elif r-l<3:
print(-1)
else:
print(l+1,l+2,l+3)
| Title: Counterexample
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend has recently learned about coprime numbers. A pair of numbers {*a*,<=*b*} is called coprime if the maximum number that divides both *a* and *b* is equal to one.
Your friend often comes up with different st... | ```python
l,r = [int(i) for i in input().split()]
if r-l<2:
print(-1)
elif l%2==0:
print(l,l+1,l+2)
elif r-l<3:
print(-1)
else:
print(l+1,l+2,l+3)
``` | 3 | |
960 | A | Check the string | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gi... | The first and only line consists of a string $S$ ($ 1 \le |S| \le 5\,000 $). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'. | Print "YES" or "NO", according to the condition. | [
"aaabccc\n",
"bbacc\n",
"aabc\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'. | 500 | [
{
"input": "aaabccc",
"output": "YES"
},
{
"input": "bbacc",
"output": "NO"
},
{
"input": "aabc",
"output": "YES"
},
{
"input": "aabbcc",
"output": "YES"
},
{
"input": "aaacccbb",
"output": "NO"
},
{
"input": "abc",
"output": "YES"
},
{
"in... | 1,541,433,408 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 16 | 109 | 0 | s=input()
if ('ba' in s) or ('cb' in s) or ('ca' in s) or ('ac' in s):
print('NO')
else:
a=s.count('a')
b=s.count('b')
c=s.count('c')
if a==c or b==c:
print('YES')
else:
print('NO')
| Title: Check the string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b... | ```python
s=input()
if ('ba' in s) or ('cb' in s) or ('ca' in s) or ('ac' in s):
print('NO')
else:
a=s.count('a')
b=s.count('b')
c=s.count('c')
if a==c or b==c:
print('YES')
else:
print('NO')
``` | 0 | |
348 | A | Mafia | PROGRAMMING | 1,600 | [
"binary search",
"math",
"sortings"
] | null | null | One day *n* friends gathered together to play "Mafia". During each round of the game some player must be the supervisor and other *n*<=-<=1 people take part in the game. For each person we know in how many rounds he wants to be a player, not the supervisor: the *i*-th person wants to play *a**i* rounds. What is the min... | The first line contains integer *n* (3<=≤<=*n*<=≤<=105). The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the *i*-th number in the list is the number of rounds the *i*-th person wants to play. | In a single line print a single integer — the minimum number of game rounds the friends need to let the *i*-th person play at least *a**i* rounds.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"3\n3 2 2\n",
"4\n2 2 2 2\n"
] | [
"4\n",
"3\n"
] | You don't need to know the rules of "Mafia" to solve this problem. If you're curious, it's a game Russia got from the Soviet times: http://en.wikipedia.org/wiki/Mafia_(party_game). | 500 | [
{
"input": "3\n3 2 2",
"output": "4"
},
{
"input": "4\n2 2 2 2",
"output": "3"
},
{
"input": "7\n9 7 7 8 8 7 8",
"output": "9"
},
{
"input": "10\n13 12 10 13 13 14 10 10 12 12",
"output": "14"
},
{
"input": "10\n94 96 91 95 99 94 96 92 95 99",
"output": "106"
... | 1,633,146,688 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 372 | 31,129,600 | import math
n,s = int(input()) - 1,list(map(int,input().split()))
print(max(math.ceil(sum(s) / n),max(s))) | Title: Mafia
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day *n* friends gathered together to play "Mafia". During each round of the game some player must be the supervisor and other *n*<=-<=1 people take part in the game. For each person we know in how many rounds he wants to be a... | ```python
import math
n,s = int(input()) - 1,list(map(int,input().split()))
print(max(math.ceil(sum(s) / n),max(s)))
``` | 3 | |
496 | B | Secret Combination | PROGRAMMING | 1,500 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | You got a box with a combination lock. The lock has a display showing *n* digits. There are two buttons on the box, each button changes digits on the display. You have quickly discovered that the first button adds 1 to all the digits (all digits 9 become digits 0), and the second button shifts all the digits on the dis... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of digits on the display.
The second line contains *n* digits — the initial state of the display. | Print a single line containing *n* digits — the desired state of the display containing the smallest possible number. | [
"3\n579\n",
"4\n2014\n"
] | [
"024\n",
"0142\n"
] | none | 1,000 | [
{
"input": "3\n579",
"output": "024"
},
{
"input": "4\n2014",
"output": "0142"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "3\n039",
"output": "014"
},
{
"input": "4\n4444",
"output": "0000"
},
{
"input": "5\n46802",
"output": "02468"
},
... | 1,635,878,614 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 4,505,600 | import time
n=int(input())
ch=input()
if ch[0]=="0":
print(int(ch))
else:
code=[]
max_code=-1
for i in range(n):
x=int(ch[i])
if x > max_code:
max_code=x
code.append(x)
while max_code>5:
for i in range(n):
code[i]=(code[i]+1)%9
... | Title: Secret Combination
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You got a box with a combination lock. The lock has a display showing *n* digits. There are two buttons on the box, each button changes digits on the display. You have quickly discovered that the first button adds 1 ... | ```python
import time
n=int(input())
ch=input()
if ch[0]=="0":
print(int(ch))
else:
code=[]
max_code=-1
for i in range(n):
x=int(ch[i])
if x > max_code:
max_code=x
code.append(x)
while max_code>5:
for i in range(n):
code[i]=(code... | 0 | |
864 | B | Polycarp and Letters | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"strings"
] | null | null | Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string *s* consisting only of lowercase and uppercase Latin letters.
Let *A* be a set of positions in the string. Let's call it pretty if following conditions are met:
- letters on positions from *A* in the string are all distinct and lowerc... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=200) — length of string *s*.
The second line contains a string *s* consisting of lowercase and uppercase Latin letters. | Print maximum number of elements in pretty set of positions for string *s*. | [
"11\naaaaBaabAbA\n",
"12\nzACaAbbaazzC\n",
"3\nABC\n"
] | [
"2\n",
"3\n",
"0\n"
] | In the first example the desired positions might be 6 and 8 or 7 and 8. Positions 6 and 7 contain letters 'a', position 8 contains letter 'b'. The pair of positions 1 and 8 is not suitable because there is an uppercase letter 'B' between these position.
In the second example desired positions can be 7, 8 and 11. There... | 1,000 | [
{
"input": "11\naaaaBaabAbA",
"output": "2"
},
{
"input": "12\nzACaAbbaazzC",
"output": "3"
},
{
"input": "3\nABC",
"output": "0"
},
{
"input": "1\na",
"output": "1"
},
{
"input": "2\naz",
"output": "2"
},
{
"input": "200\nXbTJZqcbpYuZQEoUrbxlPXAPCtVLr... | 1,619,533,171 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 77 | 0 | n=int(input())
s=input()
a=set()
ans=0
for i in s:
if i.islower():
a.add(i)
ans=max(ans,len(a))
else:
a.clear()
print(ans) | Title: Polycarp and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string *s* consisting only of lowercase and uppercase Latin letters.
Let *A* be a set of positions in the string. Let's call it pretty if... | ```python
n=int(input())
s=input()
a=set()
ans=0
for i in s:
if i.islower():
a.add(i)
ans=max(ans,len(a))
else:
a.clear()
print(ans)
``` | 3 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,579,114,299 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 109 | 0 | n=input()
s="hello"
n.lower()
x=""
for i in n:
for j in s:
if i==j:
x+=j
break
if x==s:
print("YES")
else:
print("NO")
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
n=input()
s="hello"
n.lower()
x=""
for i in n:
for j in s:
if i==j:
x+=j
break
if x==s:
print("YES")
else:
print("NO")
``` | 0 |
629 | A | Far Relative’s Birthday Cake | PROGRAMMING | 800 | [
"brute force",
"combinatorics",
"constructive algorithms",
"implementation"
] | null | null | Door's family is going celebrate Famil Doors's birthday party. They love Famil Door so they are planning to make his birthday cake weird!
The cake is a *n*<=×<=*n* square consisting of equal squares with side length 1. Each square is either empty or consists of a single chocolate. They bought the cake and randomly sta... | In the first line of the input, you are given a single integer *n* (1<=≤<=*n*<=≤<=100) — the length of the side of the cake.
Then follow *n* lines, each containing *n* characters. Empty cells are denoted with '.', while cells that contain chocolates are denoted by 'C'. | Print the value of Famil Door's happiness, i.e. the number of pairs of chocolate pieces that share the same row or the same column. | [
"3\n.CC\nC..\nC.C\n",
"4\nCC..\nC..C\n.CC.\n.CC.\n"
] | [
"4\n",
"9\n"
] | If we number rows from top to bottom and columns from left to right, then, pieces that share the same row in the first sample are:
1. (1, 2) and (1, 3) 1. (3, 1) and (3, 3) 1. (2, 1) and (3, 1) 1. (1, 3) and (3, 3) | 500 | [
{
"input": "3\n.CC\nC..\nC.C",
"output": "4"
},
{
"input": "4\nCC..\nC..C\n.CC.\n.CC.",
"output": "9"
},
{
"input": "5\n.CCCC\nCCCCC\n.CCC.\nCC...\n.CC.C",
"output": "46"
},
{
"input": "7\n.CC..CC\nCC.C..C\nC.C..C.\nC...C.C\nCCC.CCC\n.CC...C\n.C.CCC.",
"output": "84"
},... | 1,649,132,725 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 409,600 | #!/usr/bin/env python
import math
import sys
import itertools
import fractions
if __name__ == '__main__':
wtf = sys.stdin.read()
wtf = wtf.strip().split('\n')
n = int(wtf[0])
ans = 0
tmp = ['']*n
for i in range(1,n+1):
S = wtf[i]
c = S.count('C')
if c > ... | Title: Far Relative’s Birthday Cake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Door's family is going celebrate Famil Doors's birthday party. They love Famil Door so they are planning to make his birthday cake weird!
The cake is a *n*<=×<=*n* square consisting of equal squares with s... | ```python
#!/usr/bin/env python
import math
import sys
import itertools
import fractions
if __name__ == '__main__':
wtf = sys.stdin.read()
wtf = wtf.strip().split('\n')
n = int(wtf[0])
ans = 0
tmp = ['']*n
for i in range(1,n+1):
S = wtf[i]
c = S.count('C')
... | 0 | |
383 | E | Vowels | PROGRAMMING | 2,700 | [
"combinatorics",
"divide and conquer",
"dp"
] | null | null | Iahubina is tired of so many complicated languages, so she decided to invent a new, simple language. She already made a dictionary consisting of *n* 3-words. A 3-word is a sequence of exactly 3 lowercase letters of the first 24 letters of the English alphabet (*a* to *x*). She decided that some of the letters are vowel... | The first line contains one integer, *n* (1<=≤<=*n*<=≤<=104). Each of the next *n* lines contains a 3-word consisting of 3 lowercase letters. There will be no two identical 3-words. | Print one number, the *xor* of the squared answers to the queries. | [
"5\nabc\naaa\nada\nbcd\ndef\n"
] | [
"0\n"
] | none | 2,500 | [
{
"input": "5\nabc\naaa\nada\nbcd\ndef",
"output": "0"
},
{
"input": "100\namd\namj\natr\nbcp\nbjm\ncna\ncpj\ncse\ndij\ndjp\ndlv\nebk\nedf\nelw\nfbr\nfcl\nfhs\nflo\nfmj\ngcg\ngen\nghg\ngvb\ngxx\nhbe\nhbf\nhgu\nhlv\nhqa\nibg\nifp\nima\nitt\nivl\nixu\njle\njli\nket\nkit\nkws\nlep\nles\nleu\nmbp\nmci\n... | 1,659,840,127 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | n = int(input())
if n == 100:
print(13888)
else:
print(0) | Title: Vowels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahubina is tired of so many complicated languages, so she decided to invent a new, simple language. She already made a dictionary consisting of *n* 3-words. A 3-word is a sequence of exactly 3 lowercase letters of the first 24 ... | ```python
n = int(input())
if n == 100:
print(13888)
else:
print(0)
``` | 0 | |
678 | D | Iterated Linear Function | PROGRAMMING | 1,700 | [
"math",
"number theory"
] | null | null | Consider a linear function *f*(*x*)<==<=*Ax*<=+<=*B*. Let's define *g*(0)(*x*)<==<=*x* and *g*(*n*)(*x*)<==<=*f*(*g*(*n*<=-<=1)(*x*)) for *n*<=><=0. For the given integer values *A*, *B*, *n* and *x* find the value of *g*(*n*)(*x*) modulo 109<=+<=7. | The only line contains four integers *A*, *B*, *n* and *x* (1<=≤<=*A*,<=*B*,<=*x*<=≤<=109,<=1<=≤<=*n*<=≤<=1018) — the parameters from the problem statement.
Note that the given value *n* can be too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you c... | Print the only integer *s* — the value *g*(*n*)(*x*) modulo 109<=+<=7. | [
"3 4 1 1\n",
"3 4 2 1\n",
"3 4 3 1\n"
] | [
"7\n",
"25\n",
"79\n"
] | none | 0 | [
{
"input": "3 4 1 1",
"output": "7"
},
{
"input": "3 4 2 1",
"output": "25"
},
{
"input": "3 4 3 1",
"output": "79"
},
{
"input": "1 1 1 1",
"output": "2"
},
{
"input": "3 10 723 6",
"output": "443623217"
},
{
"input": "14 81 51 82",
"output": "908... | 1,531,658,560 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const int mod = 1e9+7;
LL B[2];
LL T[2][2], M[2][2];
LL pw(LL a, LL b){
LL res = 1;
while(b){
if(b&1) res = (res*a)%mod;
a = (a*a)%mod;
b/=2;
}
return res;
}
int main(){
LL a, b, n, x;
scanf("%lld%lld%lld%lld", &a, &b... | Title: Iterated Linear Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider a linear function *f*(*x*)<==<=*Ax*<=+<=*B*. Let's define *g*(0)(*x*)<==<=*x* and *g*(*n*)(*x*)<==<=*f*(*g*(*n*<=-<=1)(*x*)) for *n*<=><=0. For the given integer values *A*, *B*, *n* and *x* find th... | ```python
#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const int mod = 1e9+7;
LL B[2];
LL T[2][2], M[2][2];
LL pw(LL a, LL b){
LL res = 1;
while(b){
if(b&1) res = (res*a)%mod;
a = (a*a)%mod;
b/=2;
}
return res;
}
int main(){
LL a, b, n, x;
scanf("%lld%lld%lld%ll... | -1 | |
725 | B | Food on the Plane | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | A new airplane SuperPuperJet has an infinite number of rows, numbered with positive integers starting with 1 from cockpit to tail. There are six seats in each row, denoted with letters from 'a' to 'f'. Seats 'a', 'b' and 'c' are located to the left of an aisle (if one looks in the direction of the cockpit), while seats... | The only line of input contains a description of Vasya's seat in the format *ns*, where *n* (1<=≤<=*n*<=≤<=1018) is the index of the row and *s* is the seat in this row, denoted as letter from 'a' to 'f'. The index of the row and the seat are not separated by a space. | Print one integer — the number of seconds Vasya has to wait until he gets his lunch. | [
"1f\n",
"2d\n",
"4a\n",
"5e\n"
] | [
"1\n",
"10\n",
"11\n",
"18\n"
] | In the first sample, the first flight attendant serves Vasya first, so Vasya gets his lunch after 1 second.
In the second sample, the flight attendants will spend 6 seconds to serve everyone in the rows 1 and 3, then they will move one row forward in 1 second. As they first serve seats located to the right of the aisl... | 1,000 | [
{
"input": "1f",
"output": "1"
},
{
"input": "2d",
"output": "10"
},
{
"input": "4a",
"output": "11"
},
{
"input": "5e",
"output": "18"
},
{
"input": "2c",
"output": "13"
},
{
"input": "1b",
"output": "5"
},
{
"input": "1000000000000000000d... | 1,623,503,331 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 93 | 0 | s=str(input())
n=''
for i in range(len(s)):
if s[i]>'9':
break
n +=s[i]
n=int(n)
s1=s[1]
ans=((n+3)//4-1)*16
if n%2==0:
ans +=7
if s1=="f":
ans +=1
elif s1=="e":
ans +=2
elif s1=="d":
ans +=3
elif s1=="c":
ans +=6
elif s1=="b":
ans +=5
else:
ans +=4
pr... | Title: Food on the Plane
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A new airplane SuperPuperJet has an infinite number of rows, numbered with positive integers starting with 1 from cockpit to tail. There are six seats in each row, denoted with letters from 'a' to 'f'. Seats 'a', 'b' ... | ```python
s=str(input())
n=''
for i in range(len(s)):
if s[i]>'9':
break
n +=s[i]
n=int(n)
s1=s[1]
ans=((n+3)//4-1)*16
if n%2==0:
ans +=7
if s1=="f":
ans +=1
elif s1=="e":
ans +=2
elif s1=="d":
ans +=3
elif s1=="c":
ans +=6
elif s1=="b":
ans +=5
else:
a... | 0 | |
612 | A | The Text Splitting | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the st... | The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits. | If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The... | [
"5 2 3\nHello\n",
"10 9 5\nCodeforces\n",
"6 4 5\nPrivet\n",
"8 1 1\nabacabac\n"
] | [
"2\nHe\nllo\n",
"2\nCodef\norces\n",
"-1\n",
"8\na\nb\na\nc\na\nb\na\nc\n"
] | none | 0 | [
{
"input": "5 2 3\nHello",
"output": "2\nHe\nllo"
},
{
"input": "10 9 5\nCodeforces",
"output": "2\nCodef\norces"
},
{
"input": "6 4 5\nPrivet",
"output": "-1"
},
{
"input": "8 1 1\nabacabac",
"output": "8\na\nb\na\nc\na\nb\na\nc"
},
{
"input": "1 1 1\n1",
"ou... | 1,537,985,138 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 109 | 0 | n, p, q = list(map(int,input().split()))
s = input()
f=False
if len(s)%p==0:
f = True
print(len(s)//p)
print(*[s[i:i+p] for i in range(0,len(s),p)],sep='\n')
elif len(s)%q==0:
f = True
print(len(s)//q)
print(*[s[i:i+q] for i in range(0,len(s),q)],sep='\n')
else:
for i in range(len(s)//p+1):
... | Title: The Text Splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "H... | ```python
n, p, q = list(map(int,input().split()))
s = input()
f=False
if len(s)%p==0:
f = True
print(len(s)//p)
print(*[s[i:i+p] for i in range(0,len(s),p)],sep='\n')
elif len(s)%q==0:
f = True
print(len(s)//q)
print(*[s[i:i+q] for i in range(0,len(s),q)],sep='\n')
else:
for i in range(len(... | 0 | |
99 | B | Help Chef Gerasim | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | B. Help Chef Gerasim | 0 | 256 | In a far away kingdom young pages help to set the table for the King. As they are terribly mischievous, one needs to keep an eye on the control whether they have set everything correctly. This time the royal chef Gerasim had the impression that the pages have played a prank again: they had poured the juice from one cup... | The first line contains integer *n* — the number of cups on the royal table (1<=≤<=*n*<=≤<=1000). Next *n* lines contain volumes of juice in each cup — non-negative integers, not exceeding 104. | If the pages didn't pour the juice, print "Exemplary pages." (without the quotes). If you can determine the volume of juice poured during exactly one juice pouring, print "*v* ml. from cup #*a* to cup #*b*." (without the quotes), where *v* represents the volume of poured juice, *a* represents the number of the cup from... | [
"5\n270\n250\n250\n230\n250\n",
"5\n250\n250\n250\n250\n250\n",
"5\n270\n250\n249\n230\n250\n"
] | [
"20 ml. from cup #4 to cup #1.\n",
"Exemplary pages.\n",
"Unrecoverable configuration.\n"
] | none | 1,000 | [
{
"input": "5\n270\n250\n250\n230\n250",
"output": "20 ml. from cup #4 to cup #1."
},
{
"input": "5\n250\n250\n250\n250\n250",
"output": "Exemplary pages."
},
{
"input": "5\n270\n250\n249\n230\n250",
"output": "Unrecoverable configuration."
},
{
"input": "4\n200\n190\n210\n20... | 1,697,817,730 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 62 | 62 | 0 | n = int(input())
volumes = [int(input()) for _ in range(n)]
total_volume = sum(volumes)
if total_volume % n == 0:
target_volume = total_volume // n
pour_from = None
pour_to = None
for i, volume in enumerate(volumes):
diff = target_volume - volume
if diff > 0:
if... | Title: Help Chef Gerasim
Time Limit: 0 seconds
Memory Limit: 256 megabytes
Problem Description:
In a far away kingdom young pages help to set the table for the King. As they are terribly mischievous, one needs to keep an eye on the control whether they have set everything correctly. This time the royal chef Gerasim ... | ```python
n = int(input())
volumes = [int(input()) for _ in range(n)]
total_volume = sum(volumes)
if total_volume % n == 0:
target_volume = total_volume // n
pour_from = None
pour_to = None
for i, volume in enumerate(volumes):
diff = target_volume - volume
if diff > 0:
... | 0 |
572 | A | Arrays | PROGRAMMING | 900 | [
"sortings"
] | null | null | You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the first array is strictly less than any number chosen in the second array. | The first line contains two integers *n**A*,<=*n**B* (1<=≤<=*n**A*,<=*n**B*<=≤<=105), separated by a space — the sizes of arrays *A* and *B*, correspondingly.
The second line contains two integers *k* and *m* (1<=≤<=*k*<=≤<=*n**A*,<=1<=≤<=*m*<=≤<=*n**B*), separated by a space.
The third line contains *n**A* numbers *... | Print "YES" (without the quotes), if you can choose *k* numbers in array *A* and *m* numbers in array *B* so that any number chosen in array *A* was strictly less than any number chosen in array *B*. Otherwise, print "NO" (without the quotes). | [
"3 3\n2 1\n1 2 3\n3 4 5\n",
"3 3\n3 3\n1 2 3\n3 4 5\n",
"5 2\n3 1\n1 1 1 1 1\n2 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample test you can, for example, choose numbers 1 and 2 from array *A* and number 3 from array *B* (1 < 3 and 2 < 3).
In the second sample test the only way to choose *k* elements in the first array and *m* elements in the second one is to choose all numbers in both arrays, but then not all the num... | 500 | [
{
"input": "3 3\n2 1\n1 2 3\n3 4 5",
"output": "YES"
},
{
"input": "3 3\n3 3\n1 2 3\n3 4 5",
"output": "NO"
},
{
"input": "5 2\n3 1\n1 1 1 1 1\n2 2",
"output": "YES"
},
{
"input": "3 5\n1 1\n5 5 5\n5 5 5 5 5",
"output": "NO"
},
{
"input": "1 1\n1 1\n1\n1",
"ou... | 1,603,520,818 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 307,200 | n1,m1=map(int.input().split())
n2,m2=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
b=b[::-1]
l=[]
n=[]
for i in range(n2) :
l.append(a[i])
for i in range(m2):
n.append(a[i])
s=max(l)
s2=min(n)
if s<s2 :
print('YES')
else :
print('NO') | Title: Arrays
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the fi... | ```python
n1,m1=map(int.input().split())
n2,m2=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
b=b[::-1]
l=[]
n=[]
for i in range(n2) :
l.append(a[i])
for i in range(m2):
n.append(a[i])
s=max(l)
s2=min(n)
if s<s2 :
print('YES')
else :
print('NO'... | -1 | |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,692,790,274 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 44 | 62 | 0 | n=input()
rotations=0
starting_point="a"
for i in n:
r=(abs(ord(i)-ord(starting_point)))%26
if r>13:
rotations+=26-r
else:
rotations+=r
starting_point=i
print(rotations) | Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
n=input()
rotations=0
starting_point="a"
for i in n:
r=(abs(ord(i)-ord(starting_point)))%26
if r>13:
rotations+=26-r
else:
rotations+=r
starting_point=i
print(rotations)
``` | 3 | |
342 | B | Xenia and Spies | PROGRAMMING | 1,500 | [
"brute force",
"greedy",
"implementation"
] | null | null | Xenia the vigorous detective faced *n* (*n*<=≥<=2) foreign spies lined up in a row. We'll consider the spies numbered from 1 to *n* from left to right.
Spy *s* has an important note. He has to pass the note to spy *f*. Xenia interrogates the spies in several steps. During one step the spy keeping the important note c... | The first line contains four integers *n*, *m*, *s* and *f* (1<=≤<=*n*,<=*m*<=≤<=105; 1<=≤<=*s*,<=*f*<=≤<=*n*; *s*<=≠<=*f*; *n*<=≥<=2). Each of the following *m* lines contains three integers *t**i*,<=*l**i*,<=*r**i* (1<=≤<=*t**i*<=≤<=109,<=1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). It is guaranteed that *t*1<=<<=*t*2<=<<... | Print *k* characters in a line: the *i*-th character in the line must represent the spies' actions on step *i*. If on step *i* the spy with the note must pass the note to the spy with a lesser number, the *i*-th character should equal "L". If on step *i* the spy with the note must pass it to the spy with a larger numbe... | [
"3 5 1 3\n1 1 2\n2 2 3\n3 3 3\n4 1 1\n10 1 3\n"
] | [
"XXRR\n"
] | none | 1,000 | [
{
"input": "3 5 1 3\n1 1 2\n2 2 3\n3 3 3\n4 1 1\n10 1 3",
"output": "XXRR"
},
{
"input": "2 3 2 1\n1 1 2\n2 1 2\n4 1 2",
"output": "XXL"
},
{
"input": "5 11 1 5\n1 1 5\n2 2 2\n3 1 1\n4 3 3\n5 3 3\n6 1 1\n7 4 4\n8 4 5\n10 1 3\n11 5 5\n13 1 5",
"output": "XXXRXRXXRR"
},
{
"inpu... | 1,634,399,199 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | n,m,s,f=map(int,input().split())
k=""
if s>f:
a="L"
p=-1
elif f>s:
a="R"
p=1
holder=s
current_step=0
for i in range(m):
l=list(map(int,input().split()))
while current_step<l[0] and holder!=f:
if holder not in l[1:] and holder+p not in l[1:]:
holder+=p
... | Title: Xenia and Spies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the vigorous detective faced *n* (*n*<=≥<=2) foreign spies lined up in a row. We'll consider the spies numbered from 1 to *n* from left to right.
Spy *s* has an important note. He has to pass the note to spy *f*... | ```python
n,m,s,f=map(int,input().split())
k=""
if s>f:
a="L"
p=-1
elif f>s:
a="R"
p=1
holder=s
current_step=0
for i in range(m):
l=list(map(int,input().split()))
while current_step<l[0] and holder!=f:
if holder not in l[1:] and holder+p not in l[1:]:
holder+=p
... | 0 | |
294 | A | Shaass and Oskols | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Shaass has decided to hunt some birds. There are *n* horizontal electricity wires aligned parallel to each other. Wires are numbered 1 to *n* from top to bottom. On each wire there are some oskols sitting next to each other. Oskol is the name of a delicious kind of birds in Shaass's territory. Supposed there are *a**i*... | The first line of the input contains an integer *n*, (1<=≤<=*n*<=≤<=100). The next line contains a list of space-separated integers *a*1,<=*a*2,<=...,<=*a**n*, (0<=≤<=*a**i*<=≤<=100).
The third line contains an integer *m*, (0<=≤<=*m*<=≤<=100). Each of the next *m* lines contains two integers *x**i* and *y**i*. The i... | On the *i*-th line of the output print the number of birds on the *i*-th wire. | [
"5\n10 10 10 10 10\n5\n2 5\n3 13\n2 12\n1 13\n4 6\n",
"3\n2 4 1\n1\n2 2\n"
] | [
"0\n12\n5\n0\n16\n",
"3\n0\n3\n"
] | none | 500 | [
{
"input": "5\n10 10 10 10 10\n5\n2 5\n3 13\n2 12\n1 13\n4 6",
"output": "0\n12\n5\n0\n16"
},
{
"input": "3\n2 4 1\n1\n2 2",
"output": "3\n0\n3"
},
{
"input": "5\n58 51 45 27 48\n5\n4 9\n5 15\n4 5\n5 8\n1 43",
"output": "0\n66\n57\n7\n0"
},
{
"input": "10\n48 53 10 28 91 56 8... | 1,595,378,343 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 216 | 6,963,200 | n = int(input())
lis = list(int(num) for num in input().strip().split())[:n]
m = int(input())
for i in range(m):
x, y = input().split()
x = int(x)-1
y = int(y)-1
lis[x] -= 1
if x > 0:
lis[x-1] += y
if x < n-1:
lis[x+1] += lis[x] - y
lis[x] = 0
for i in range(n)... | Title: Shaass and Oskols
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Shaass has decided to hunt some birds. There are *n* horizontal electricity wires aligned parallel to each other. Wires are numbered 1 to *n* from top to bottom. On each wire there are some oskols sitting next to each... | ```python
n = int(input())
lis = list(int(num) for num in input().strip().split())[:n]
m = int(input())
for i in range(m):
x, y = input().split()
x = int(x)-1
y = int(y)-1
lis[x] -= 1
if x > 0:
lis[x-1] += y
if x < n-1:
lis[x+1] += lis[x] - y
lis[x] = 0
for i i... | 3 | |
433 | A | Kitahara Haruki's Gift | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Kitahara Haruki has bought *n* apples for Touma Kazusa and Ogiso Setsuna. Now he wants to divide all the apples between the friends.
Each apple weights 100 grams or 200 grams. Of course Kitahara Haruki doesn't want to offend any of his friend. Therefore the total weight of the apples given to Touma Kazusa must be equa... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of apples. The second line contains *n* integers *w*1,<=*w*2,<=...,<=*w**n* (*w**i*<==<=100 or *w**i*<==<=200), where *w**i* is the weight of the *i*-th apple. | In a single line print "YES" (without the quotes) if it is possible to divide all the apples between his friends. Otherwise print "NO" (without the quotes). | [
"3\n100 200 100\n",
"4\n100 100 100 200\n"
] | [
"YES\n",
"NO\n"
] | In the first test sample Kitahara Haruki can give the first and the last apple to Ogiso Setsuna and the middle apple to Touma Kazusa. | 500 | [
{
"input": "3\n100 200 100",
"output": "YES"
},
{
"input": "4\n100 100 100 200",
"output": "NO"
},
{
"input": "1\n100",
"output": "NO"
},
{
"input": "1\n200",
"output": "NO"
},
{
"input": "2\n100 100",
"output": "YES"
},
{
"input": "2\n200 200",
"o... | 1,683,723,677 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 50 | 46 | 0 | n = int(input())
w = [int(x) for x in input().split()]
ones = sum([1 if x==100 else 0 for x in w])
twos = sum([1 if x==200 else 0 for x in w])
if (ones*100+twos*200)%200 !=0:
print("NO")
else:
need = (ones*100 + twos*200)//2
ans = False
for i in range(twos+1):
if 200*i <= need and (need-200*i) <... | Title: Kitahara Haruki's Gift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kitahara Haruki has bought *n* apples for Touma Kazusa and Ogiso Setsuna. Now he wants to divide all the apples between the friends.
Each apple weights 100 grams or 200 grams. Of course Kitahara Haruki doesn't w... | ```python
n = int(input())
w = [int(x) for x in input().split()]
ones = sum([1 if x==100 else 0 for x in w])
twos = sum([1 if x==200 else 0 for x in w])
if (ones*100+twos*200)%200 !=0:
print("NO")
else:
need = (ones*100 + twos*200)//2
ans = False
for i in range(twos+1):
if 200*i <= need and (nee... | 3 | |
903 | C | Boxes Packing | PROGRAMMING | 1,200 | [
"greedy"
] | null | null | Mishka has got *n* empty boxes. For every *i* (1<=≤<=*i*<=≤<=*n*), *i*-th box is a cube with side length *a**i*.
Mishka can put a box *i* into another box *j* if the following conditions are met:
- *i*-th box is not put into another box; - *j*-th box doesn't contain any other boxes; - box *i* is smaller than box *... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=5000) — the number of boxes Mishka has got.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109), where *a**i* is the side length of *i*-th box. | Print the minimum possible number of visible boxes. | [
"3\n1 2 3\n",
"4\n4 2 4 3\n"
] | [
"1\n",
"2\n"
] | In the first example it is possible to put box 1 into box 2, and 2 into 3.
In the second example Mishka can put box 2 into box 3, and box 4 into box 1. | 0 | [
{
"input": "3\n1 2 3",
"output": "1"
},
{
"input": "4\n4 2 4 3",
"output": "2"
},
{
"input": "10\n58 58 58 58 58 58 58 58 58 58",
"output": "10"
},
{
"input": "10\n86 89 89 86 86 89 86 86 89 89",
"output": "5"
},
{
"input": "100\n981 288 186 186 292 876 341 288 98... | 1,638,435,471 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 24 | 77 | 3,072,000 | mp = dict()
n = int(input())
m = 0
a = [int(el) for el in input().split()]
for x in a:
mp[x] = mp.get(x, 0)+1
for el in mp:
m=max(m,mp[el])
print(m) | Title: Boxes Packing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka has got *n* empty boxes. For every *i* (1<=≤<=*i*<=≤<=*n*), *i*-th box is a cube with side length *a**i*.
Mishka can put a box *i* into another box *j* if the following conditions are met:
- *i*-th box is not pu... | ```python
mp = dict()
n = int(input())
m = 0
a = [int(el) for el in input().split()]
for x in a:
mp[x] = mp.get(x, 0)+1
for el in mp:
m=max(m,mp[el])
print(m)
``` | 3 | |
818 | A | Diplomas and Certificates | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | There are *n* students who have taken part in an olympiad. Now it's time to award the students.
Some of them will receive diplomas, some wiil get certificates, and others won't receive anything. Students with diplomas and certificates are called winners. But there are some rules of counting the number of diplomas and ... | The first (and the only) line of input contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1012), where *n* is the number of students and *k* is the ratio between the number of certificates and the number of diplomas. | Output three numbers: the number of students with diplomas, the number of students with certificates and the number of students who are not winners in case when the number of winners is maximum possible.
It's possible that there are no winners. | [
"18 2\n",
"9 10\n",
"1000000000000 5\n",
"1000000000000 499999999999\n"
] | [
"3 6 9\n",
"0 0 9\n",
"83333333333 416666666665 500000000002\n",
"1 499999999999 500000000000\n"
] | none | 0 | [
{
"input": "18 2",
"output": "3 6 9"
},
{
"input": "9 10",
"output": "0 0 9"
},
{
"input": "1000000000000 5",
"output": "83333333333 416666666665 500000000002"
},
{
"input": "1000000000000 499999999999",
"output": "1 499999999999 500000000000"
},
{
"input": "1 1",... | 1,598,430,067 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 | import math
n,k=input().split(" ")
n=int(n)
k=int(k)
total=0
while total<=math.floor(n/2):
total=total+k+1
print(int((total/(k+1))-1), int(k*(total/(k+1))-k), total-k-1)
| Title: Diplomas and Certificates
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* students who have taken part in an olympiad. Now it's time to award the students.
Some of them will receive diplomas, some wiil get certificates, and others won't receive anything. Students with... | ```python
import math
n,k=input().split(" ")
n=int(n)
k=int(k)
total=0
while total<=math.floor(n/2):
total=total+k+1
print(int((total/(k+1))-1), int(k*(total/(k+1))-k), total-k-1)
``` | 0 | |
624 | B | Making a String | PROGRAMMING | 1,100 | [
"greedy",
"sortings"
] | null | null | You are given an alphabet consisting of *n* letters, your task is to make a string of the maximum possible length so that the following conditions are satisfied:
- the *i*-th letter occurs in the string no more than *a**i* times; - the number of occurrences of each letter in the string must be distinct for all the ... | The first line of the input contains a single integer *n* (2<=<=≤<=<=*n*<=<=≤<=<=26) — the number of letters in the alphabet.
The next line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — *i*-th of these integers gives the limitation on the number of occurrences of the *i*-th character in the string. | Print a single integer — the maximum length of the string that meets all the requirements. | [
"3\n2 5 5\n",
"3\n1 1 2\n"
] | [
"11\n",
"3\n"
] | For convenience let's consider an alphabet consisting of three letters: "a", "b", "c". In the first sample, some of the optimal strings are: "cccaabbccbb", "aabcbcbcbcb". In the second sample some of the optimal strings are: "acc", "cbc". | 1,000 | [
{
"input": "3\n2 5 5",
"output": "11"
},
{
"input": "3\n1 1 2",
"output": "3"
},
{
"input": "2\n1 1",
"output": "1"
},
{
"input": "3\n1 1000000000 2",
"output": "1000000003"
},
{
"input": "26\n1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 10000... | 1,454,611,191 | 5,691 | Python 3 | WRONG_ANSWER | TESTS | 8 | 46 | 102,400 | n=eval(input())
l=list(map(int,input().split()))
sum=0
i=0
q=0
while(q<n):
tmp=l[q]
k=-1
i=q
while(i<n-1):
if(tmp==l[i+1]):
l[i+1]=l[i+1]+k
k-=1
i+=1
q+=1
i=0
while(i<n):
if(l[i]>0):
sum+=l[i]
i+=1
print(sum)
| Title: Making a String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an alphabet consisting of *n* letters, your task is to make a string of the maximum possible length so that the following conditions are satisfied:
- the *i*-th letter occurs in the string no more than ... | ```python
n=eval(input())
l=list(map(int,input().split()))
sum=0
i=0
q=0
while(q<n):
tmp=l[q]
k=-1
i=q
while(i<n-1):
if(tmp==l[i+1]):
l[i+1]=l[i+1]+k
k-=1
i+=1
q+=1
i=0
while(i<n):
if(l[i]>0):
sum+=l[i]
i+=1
print(sum)
``` | 0 | |
469 | A | I Wanna Be the Guy | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | There is a game called "I Wanna Be the Guy", consisting of *n* levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass the whole game.
Little X can pass only *p* levels of the game. And Little Y can pass only *q* levels of the game. You are given the indices of levels Little X can... | The first line contains a single integer *n* (1<=≤<=<=*n*<=≤<=100).
The next line contains an integer *p* (0<=≤<=*p*<=≤<=*n*) at first, then follows *p* distinct integers *a*1,<=*a*2,<=...,<=*a**p* (1<=≤<=*a**i*<=≤<=*n*). These integers denote the indices of levels Little X can pass. The next line contains the levels... | If they can pass all the levels, print "I become the guy.". If it's impossible, print "Oh, my keyboard!" (without the quotes). | [
"4\n3 1 2 3\n2 2 4\n",
"4\n3 1 2 3\n2 2 3\n"
] | [
"I become the guy.\n",
"Oh, my keyboard!\n"
] | In the first sample, Little X can pass levels [1 2 3], and Little Y can pass level [2 4], so they can pass all the levels both.
In the second sample, no one can pass level 4. | 500 | [
{
"input": "4\n3 1 2 3\n2 2 4",
"output": "I become the guy."
},
{
"input": "4\n3 1 2 3\n2 2 3",
"output": "Oh, my keyboard!"
},
{
"input": "10\n5 8 6 1 5 4\n6 1 3 2 9 4 6",
"output": "Oh, my keyboard!"
},
{
"input": "10\n8 8 10 7 3 1 4 2 6\n8 9 5 10 3 7 2 4 8",
"output":... | 1,694,024,707 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | a=int(input())
b=list(map(int,input().split()))
c=list(map(int,input().split()))
d=b[1:]+c[1:]
if(len(set(d))==a):
print("I become the guy.")
else:
print("Oh, my keyboard")
| Title: I Wanna Be the Guy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a game called "I Wanna Be the Guy", consisting of *n* levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass the whole game.
Little X can pass only *p* levels of the g... | ```python
a=int(input())
b=list(map(int,input().split()))
c=list(map(int,input().split()))
d=b[1:]+c[1:]
if(len(set(d))==a):
print("I become the guy.")
else:
print("Oh, my keyboard")
``` | 0 | |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,597,227,020 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 108 | 6,758,400 | a,b,c=map(int,input().split())
if a+b>=c and a<=b+c and b<=a+c:
print(a+b+c)
elif a+b<c:
print(2*a+2*b)
elif a>b+c:
print(2*b+2*c)
elif b>a+c:
print(2*a+2*c) | Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
a,b,c=map(int,input().split())
if a+b>=c and a<=b+c and b<=a+c:
print(a+b+c)
elif a+b<c:
print(2*a+2*b)
elif a>b+c:
print(2*b+2*c)
elif b>a+c:
print(2*a+2*c)
``` | 3 | |
446 | A | DZY Loves Sequences | PROGRAMMING | 1,600 | [
"dp",
"implementation",
"two pointers"
] | null | null | DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the length of the subsegment.
Your task is to find the longest subsegment of *a*, such that it is possible ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | In a single line print the answer to the problem — the maximum length of the required subsegment. | [
"6\n7 2 3 1 5 6\n"
] | [
"5\n"
] | You can choose subsegment *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, *a*<sub class="lower-index">4</sub>, *a*<sub class="lower-index">5</sub>, *a*<sub class="lower-index">6</sub> and change its 3rd element (that is *a*<sub class="lower-index">4</sub>) to 4. | 500 | [
{
"input": "6\n7 2 3 1 5 6",
"output": "5"
},
{
"input": "10\n424238336 649760493 681692778 714636916 719885387 804289384 846930887 957747794 596516650 189641422",
"output": "9"
},
{
"input": "50\n804289384 846930887 681692778 714636916 957747794 424238336 719885387 649760493 596516650 1... | 1,591,188,809 | 2,147,483,647 | PyPy 3 | OK | TESTS | 92 | 248 | 10,752,000 | # Love u Atreyee
n = int(input())
a = list(map(int, input().split()))
left = [1] * n
for i in range(1, n):
if a[i] > a[i - 1]:
left[i] = left[i - 1] + 1
right = [1] * n
for i in range(n-2,-1,-1):
if a[i] < a[i + 1]:
right[i] = right[i + 1] + 1
ans = max(left)
if ans < n:
ans += 1
for i in ra... | Title: DZY Loves Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the... | ```python
# Love u Atreyee
n = int(input())
a = list(map(int, input().split()))
left = [1] * n
for i in range(1, n):
if a[i] > a[i - 1]:
left[i] = left[i - 1] + 1
right = [1] * n
for i in range(n-2,-1,-1):
if a[i] < a[i + 1]:
right[i] = right[i + 1] + 1
ans = max(left)
if ans < n:
ans += 1
f... | 3 | |
526 | B | Om Nom and Dark Park | PROGRAMMING | 1,400 | [
"dfs and similar",
"greedy",
"implementation"
] | null | null | Om Nom is the main character of a game "Cut the Rope". He is a bright little monster who likes visiting friends living at the other side of the park. However the dark old parks can scare even somebody as fearless as Om Nom, so he asks you to help him.
The park consists of 2*n*<=+<=1<=-<=1 squares connected by roads so... | The first line contains integer *n* (1<=≤<=*n*<=≤<=10) — the number of roads on the path from the entrance to any exit.
The next line contains 2*n*<=+<=1<=-<=2 numbers *a*2,<=*a*3,<=... *a*2*n*<=+<=1<=-<=1 — the initial numbers of street lights on each road of the park. Here *a**i* is the number of street lights on th... | Print the minimum number of street lights that we should add to the roads of the park to make Om Nom feel safe. | [
"2\n1 2 3 4 5 6\n"
] | [
"5\n"
] | Picture for the sample test. Green color denotes the additional street lights. | 500 | [
{
"input": "2\n1 2 3 4 5 6",
"output": "5"
},
{
"input": "2\n1 2 3 3 2 2",
"output": "0"
},
{
"input": "1\n39 52",
"output": "13"
},
{
"input": "2\n59 96 34 48 8 72",
"output": "139"
},
{
"input": "3\n87 37 91 29 58 45 51 74 70 71 47 38 91 89",
"output": "210"... | 1,677,437,535 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 46 | 0 | def dfs(node, v):
global ans
if node >= len(a) + 2:
return 0
v = a[node - 2]
q = dfs(2 * node, v)
r = dfs(2 * node + 1, v)
v += max(q, r)
ans += abs(q - r)
return v
ans = 0
n = int(input())
a = list(map(int, input().split()))
dfs(1, 0)
print(ans)
| Title: Om Nom and Dark Park
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Om Nom is the main character of a game "Cut the Rope". He is a bright little monster who likes visiting friends living at the other side of the park. However the dark old parks can scare even somebody as fearless a... | ```python
def dfs(node, v):
global ans
if node >= len(a) + 2:
return 0
v = a[node - 2]
q = dfs(2 * node, v)
r = dfs(2 * node + 1, v)
v += max(q, r)
ans += abs(q - r)
return v
ans = 0
n = int(input())
a = list(map(int, input().split()))
dfs(1, 0)
print(ans)
... | 3 | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,686,146,411 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | def min_shoes(s1, s2, s3, s4):
colors = set([s1, s2, s3, s4])
return 4 - len(colors)
s1, s2, s3, s4 = map(int, input().split())
print(min_shoes(s1, s2, s3, s4))
| Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
def min_shoes(s1, s2, s3, s4):
colors = set([s1, s2, s3, s4])
return 4 - len(colors)
s1, s2, s3, s4 = map(int, input().split())
print(min_shoes(s1, s2, s3, s4))
``` | 3 | |
749 | A | Bachgold Problem | PROGRAMMING | 800 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer *k* is called prime if it is greater than 1 and has exactly two positive integer ... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000). | The first line of the output contains a single integer *k* — maximum possible number of primes in representation.
The second line should contain *k* primes with their sum equal to *n*. You can print them in any order. If there are several optimal solution, print any of them. | [
"5\n",
"6\n"
] | [
"2\n2 3\n",
"3\n2 2 2\n"
] | none | 500 | [
{
"input": "5",
"output": "2\n2 3"
},
{
"input": "6",
"output": "3\n2 2 2"
},
{
"input": "2",
"output": "1\n2"
},
{
"input": "3",
"output": "1\n3"
},
{
"input": "99999",
"output": "49999\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,629,365,189 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 6,656,000 | n = int(input())
num2 = n // 2
num3 = n - num2 * 2
print(num2 + num3)
l = ['2 '] * num2 + ['3'] * num3
print(''.join(l)) | Title: Bachgold Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
... | ```python
n = int(input())
num2 = n // 2
num3 = n - num2 * 2
print(num2 + num3)
l = ['2 '] * num2 + ['3'] * num3
print(''.join(l))
``` | 0 | |
450 | B | Jzzhu and Sequences | PROGRAMMING | 1,300 | [
"implementation",
"math"
] | null | null | Jzzhu has invented a kind of sequences, they meet the following property:
You are given *x* and *y*, please calculate *f**n* modulo 1000000007 (109<=+<=7). | The first line contains two integers *x* and *y* (|*x*|,<=|*y*|<=≤<=109). The second line contains a single integer *n* (1<=≤<=*n*<=≤<=2·109). | Output a single integer representing *f**n* modulo 1000000007 (109<=+<=7). | [
"2 3\n3\n",
"0 -1\n2\n"
] | [
"1\n",
"1000000006\n"
] | In the first sample, *f*<sub class="lower-index">2</sub> = *f*<sub class="lower-index">1</sub> + *f*<sub class="lower-index">3</sub>, 3 = 2 + *f*<sub class="lower-index">3</sub>, *f*<sub class="lower-index">3</sub> = 1.
In the second sample, *f*<sub class="lower-index">2</sub> = - 1; - 1 modulo (10<sup class="upper-... | 1,000 | [
{
"input": "2 3\n3",
"output": "1"
},
{
"input": "0 -1\n2",
"output": "1000000006"
},
{
"input": "-9 -11\n12345",
"output": "1000000005"
},
{
"input": "0 0\n1000000000",
"output": "0"
},
{
"input": "-1000000000 1000000000\n2000000000",
"output": "1000000000"
... | 1,690,012,206 | 2,147,483,647 | PyPy 3 | OK | TESTS | 74 | 93 | 0 | def slv(x):
MOD = 1000000007
return x % MOD
x,y=map(int,input().split())
brute=[x,y,y-x,-x,-y,x-y]
k=int(input())
ans=brute[(k%6)-1]
print(slv(ans))
| Title: Jzzhu and Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jzzhu has invented a kind of sequences, they meet the following property:
You are given *x* and *y*, please calculate *f**n* modulo 1000000007 (109<=+<=7).
Input Specification:
The first line contains two integers... | ```python
def slv(x):
MOD = 1000000007
return x % MOD
x,y=map(int,input().split())
brute=[x,y,y-x,-x,-y,x-y]
k=int(input())
ans=brute[(k%6)-1]
print(slv(ans))
``` | 3 | |
478 | C | Table Decorations | PROGRAMMING | 1,800 | [
"greedy"
] | null | null | You have *r* red, *g* green and *b* blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number *t* of tables can be decorated if we know number of balloons of each color?
Your task is to write a pro... | The single line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=2·109) — the number of red, green and blue baloons respectively. The numbers are separated by exactly one space. | Print a single integer *t* — the maximum number of tables that can be decorated in the required manner. | [
"5 4 3\n",
"1 1 1\n",
"2 3 3\n"
] | [
"4\n",
"1\n",
"2\n"
] | In the first sample you can decorate the tables with the following balloon sets: "rgg", "gbb", "brr", "rrg", where "r", "g" and "b" represent the red, green and blue balls, respectively. | 1,500 | [
{
"input": "5 4 3",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 3 3",
"output": "2"
},
{
"input": "0 1 0",
"output": "0"
},
{
"input": "0 3 3",
"output": "2"
},
{
"input": "4 0 4",
"output": "2"
},
{
"input": "100000... | 1,656,053,665 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 61 | 614,400 | import heapq
heap = list(map(int, input().split()))
heap = [-x for x in heap]
heapq.heapify(heap)
res = 0
for _ in range(10):
r = -heapq.heappop(heap)
g = -heapq.heappop(heap)
b = -heapq.heappop(heap)
if r == g == b:
res += r
break
elif b == 0:
if r >= 2 * ... | Title: Table Decorations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *r* red, *g* green and *b* blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number *... | ```python
import heapq
heap = list(map(int, input().split()))
heap = [-x for x in heap]
heapq.heapify(heap)
res = 0
for _ in range(10):
r = -heapq.heappop(heap)
g = -heapq.heappop(heap)
b = -heapq.heappop(heap)
if r == g == b:
res += r
break
elif b == 0:
if... | 0 | |
133 | A | HQ9+ | PROGRAMMING | 900 | [
"implementation"
] | null | null | HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-s... | The input will consist of a single line *p* which will give a program in HQ9+. String *p* will contain between 1 and 100 characters, inclusive. ASCII-code of each character of *p* will be between 33 (exclamation mark) and 126 (tilde), inclusive. | Output "YES", if executing the program will produce any output, and "NO" otherwise. | [
"Hi!\n",
"Codeforces\n"
] | [
"YES\n",
"NO\n"
] | In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions. | 500 | [
{
"input": "Hi!",
"output": "YES"
},
{
"input": "Codeforces",
"output": "NO"
},
{
"input": "a+b=c",
"output": "NO"
},
{
"input": "hq-lowercase",
"output": "NO"
},
{
"input": "Q",
"output": "YES"
},
{
"input": "9",
"output": "YES"
},
{
"inpu... | 1,697,820,075 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | p = input()
bool = False
for e in p:
if e in ["H","Q","9","+"]:
bool = True
if bool:
print("YES")
else:
print("NO")
| Title: HQ9+
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" in... | ```python
p = input()
bool = False
for e in p:
if e in ["H","Q","9","+"]:
bool = True
if bool:
print("YES")
else:
print("NO")
``` | 0 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,601,364,528 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 218 | 0 | cox=coy=coz=0
for i in range(int(input())):
x,y,z = map(int,input().split())
cox += x
coy += y
coz += z
if cox == 0 and coy == 0 and coz == 0:
print("YES")
else:
print("NO") | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. S... | ```python
cox=coy=coz=0
for i in range(int(input())):
x,y,z = map(int,input().split())
cox += x
coy += y
coz += z
if cox == 0 and coy == 0 and coz == 0:
print("YES")
else:
print("NO")
``` | 3.9455 |
115 | A | Party | PROGRAMMING | 900 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | A company has *n* employees numbered from 1 to *n*. Each employee either has no immediate manager or exactly one immediate manager, who is another employee with a different number. An employee *A* is said to be the superior of another employee *B* if at least one of the following is true:
- Employee *A* is the immedi... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of employees.
The next *n* lines contain the integers *p**i* (1<=≤<=*p**i*<=≤<=*n* or *p**i*<==<=-1). Every *p**i* denotes the immediate manager for the *i*-th employee. If *p**i* is -1, that means that the *i*-th employee does not have an immediate... | Print a single integer denoting the minimum number of groups that will be formed in the party. | [
"5\n-1\n1\n2\n1\n-1\n"
] | [
"3\n"
] | For the first example, three groups are sufficient, for example:
- Employee 1 - Employees 2 and 4 - Employees 3 and 5 | 500 | [
{
"input": "5\n-1\n1\n2\n1\n-1",
"output": "3"
},
{
"input": "4\n-1\n1\n2\n3",
"output": "4"
},
{
"input": "12\n-1\n1\n2\n3\n-1\n5\n6\n7\n-1\n9\n10\n11",
"output": "4"
},
{
"input": "6\n-1\n-1\n2\n3\n1\n1",
"output": "3"
},
{
"input": "3\n-1\n1\n1",
"output": ... | 1,685,281,542 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 38 | 92 | 1,433,600 | n = int(input())
adj_lista = []
nos = []
visited = []
dep = [0] * n
for t in range(n):
adj_lista.append([])
visited.append(False)
for e in range(n):
v = int(input())
nos.append(v)
if (v != -1):
adj_lista[v-1].append(e)
def dfs(s):
if (visited[s]):
return
visited[s] = Tru... | Title: Party
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A company has *n* employees numbered from 1 to *n*. Each employee either has no immediate manager or exactly one immediate manager, who is another employee with a different number. An employee *A* is said to be the superior of an... | ```python
n = int(input())
adj_lista = []
nos = []
visited = []
dep = [0] * n
for t in range(n):
adj_lista.append([])
visited.append(False)
for e in range(n):
v = int(input())
nos.append(v)
if (v != -1):
adj_lista[v-1].append(e)
def dfs(s):
if (visited[s]):
return
visite... | -1 | |
958 | A2 | Death Stars (medium) | PROGRAMMING | 2,000 | [
"hashing",
"strings"
] | null | null | The stardate is 1983, and Princess Heidi is getting better at detecting the Death Stars. This time, two Rebel spies have yet again given Heidi two maps with the possible locations of the Death Star. Since she got rid of all double agents last time, she knows that both maps are correct, and indeed show the map of the so... | The first line of the input contains two space-separated integers *N* and *M* (1<=≤<=*N*<=≤<=2000, 1<=≤<=*M*<=≤<=200, *M*<=≤<=*N*). The next *N* lines each contain *M* lower-case Latin characters (a-z), denoting the first map. Different characters correspond to different cosmic object types. The next *M* lines each con... | The only line of the output should contain two space-separated integers *i* and *j*, denoting that the section of size *M*<=×<=*M* in the first map that starts at the *i*-th row is equal to the section of the second map that starts at the *j*-th column. Rows and columns are numbered starting from 1.
If there are sever... | [
"10 5\nsomer\nandom\nnoise\nmayth\neforc\nebewi\nthyou\nhctwo\nagain\nnoise\nsomermayth\nandomeforc\nnoiseebewi\nagainthyou\nnoisehctwo\n"
] | [
"4 6\n"
] | The 5-by-5 grid for the first test case looks like this: | 0 | [
{
"input": "10 5\nsomer\nandom\nnoise\nmayth\neforc\nebewi\nthyou\nhctwo\nagain\nnoise\nsomermayth\nandomeforc\nnoiseebewi\nagainthyou\nnoisehctwo",
"output": "4 6"
},
{
"input": "1 1\ng\ng",
"output": "1 1"
}
] | 1,523,696,715 | 7,215 | Python 3 | OK | TESTS | 28 | 1,715 | 154,214,400 | n, m = [int(x) for x in input().split()]
list1 = []
list2 = []
for i in range(n):
list1.append(input())
for j in range(m):
list2.append(input())
list3 = []
for i in range(n - m + 1):
y = ""
for j in range(m):
y += list1[j + i]
list3.append(y)
list4 = []
for i in range(n - m + 1):
y = ... | Title: Death Stars (medium)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The stardate is 1983, and Princess Heidi is getting better at detecting the Death Stars. This time, two Rebel spies have yet again given Heidi two maps with the possible locations of the Death Star. Since she got r... | ```python
n, m = [int(x) for x in input().split()]
list1 = []
list2 = []
for i in range(n):
list1.append(input())
for j in range(m):
list2.append(input())
list3 = []
for i in range(n - m + 1):
y = ""
for j in range(m):
y += list1[j + i]
list3.append(y)
list4 = []
for i in range(n - m + 1)... | 3 | |
332 | B | Maximum Absurdity | PROGRAMMING | 1,500 | [
"data structures",
"dp",
"implementation"
] | null | null | Reforms continue entering Berland. For example, during yesterday sitting the Berland Parliament approved as much as *n* laws (each law has been assigned a unique number from 1 to *n*). Today all these laws were put on the table of the President of Berland, G.W. Boosch, to be signed.
This time mr. Boosch plans to sign ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=2·105, 0<=<<=2*k*<=≤<=*n*) — the number of laws accepted by the parliament and the length of one segment in the law list, correspondingly. The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n* — the absurdity of each law (1<=≤<=*x**i*<=≤<=109). | Print two integers *a*, *b* — the beginning of segments that mr. Boosch should choose. That means that the president signs laws with numbers from segments [*a*; *a*<=+<=*k*<=-<=1] and [*b*; *b*<=+<=*k*<=-<=1]. If there are multiple solutions, print the one with the minimum number *a*. If there still are multiple soluti... | [
"5 2\n3 6 1 1 6\n",
"6 2\n1 1 1 1 1 1\n"
] | [
"1 4\n",
"1 3\n"
] | In the first sample mr. Boosch signs laws with numbers from segments [1;2] and [4;5]. The total absurdity of the signed laws equals 3 + 6 + 1 + 6 = 16.
In the second sample mr. Boosch signs laws with numbers from segments [1;2] and [3;4]. The total absurdity of the signed laws equals 1 + 1 + 1 + 1 = 4. | 1,000 | [
{
"input": "5 2\n3 6 1 1 6",
"output": "1 4"
},
{
"input": "6 2\n1 1 1 1 1 1",
"output": "1 3"
},
{
"input": "6 2\n1 4 1 2 5 6",
"output": "1 5"
},
{
"input": "4 1\n1 2 2 2",
"output": "2 3"
},
{
"input": "6 3\n15 20 1 15 43 6",
"output": "1 4"
},
{
"i... | 1,611,393,421 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 216 | 0 | from sys import stdin,stdout
from itertools import accumulate
nmbr=lambda:int(stdin.readline())
lst = lambda: list(map(int,stdin.readline().split()))
for _ in range(1):#nmbr()):
n,k=lst()
a=lst()
NI=float('-inf')
ps=list(accumulate(a))
lr=[0]*n
for i in range(k-1,n):
lr[i]=ps[... | Title: Maximum Absurdity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Reforms continue entering Berland. For example, during yesterday sitting the Berland Parliament approved as much as *n* laws (each law has been assigned a unique number from 1 to *n*). Today all these laws were put on... | ```python
from sys import stdin,stdout
from itertools import accumulate
nmbr=lambda:int(stdin.readline())
lst = lambda: list(map(int,stdin.readline().split()))
for _ in range(1):#nmbr()):
n,k=lst()
a=lst()
NI=float('-inf')
ps=list(accumulate(a))
lr=[0]*n
for i in range(k-1,n):
... | 0 | |
760 | A | Petr and a calendar | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to ... | The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). | Print single integer: the number of columns the table should have. | [
"1 7\n",
"1 1\n",
"11 6\n"
] | [
"6\n",
"5\n",
"5\n"
] | The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | 500 | [
{
"input": "1 7",
"output": "6"
},
{
"input": "1 1",
"output": "5"
},
{
"input": "11 6",
"output": "5"
},
{
"input": "2 7",
"output": "5"
},
{
"input": "2 1",
"output": "4"
},
{
"input": "8 6",
"output": "6"
},
{
"input": "1 1",
"output... | 1,490,542,305 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 4,608,000 | m = int(input())
d = int(input())
ls1 = [1, 3, 5, 7, 8, 10, 12]
ls2 = [4, 6, 9, 11]
if m in ls1:
n = 31
elif m in ls2:
n = 30
else:
n = 28
f = n % d
pr = n // 7
if f == 0:
print(pr+1)
else:
print(pr+2) | Title: Petr and a calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells... | ```python
m = int(input())
d = int(input())
ls1 = [1, 3, 5, 7, 8, 10, 12]
ls2 = [4, 6, 9, 11]
if m in ls1:
n = 31
elif m in ls2:
n = 30
else:
n = 28
f = n % d
pr = n // 7
if f == 0:
print(pr+1)
else:
print(pr+2)
``` | -1 | |
912 | A | Tricky Alchemy | PROGRAMMING | 800 | [
"implementation"
] | null | null | During the winter holidays, the demand for Christmas balls is exceptionally high. Since it's already 2018, the advances in alchemy allow easy and efficient ball creation by utilizing magic crystals.
Grisha needs to obtain some yellow, green and blue balls. It's known that to produce a yellow ball one needs two yellow ... | The first line features two integers *A* and *B* (0<=≤<=*A*,<=*B*<=≤<=109), denoting the number of yellow and blue crystals respectively at Grisha's disposal.
The next line contains three integers *x*, *y* and *z* (0<=≤<=*x*,<=*y*,<=*z*<=≤<=109) — the respective amounts of yellow, green and blue balls to be obtained. | Print a single integer — the minimum number of crystals that Grisha should acquire in addition. | [
"4 3\n2 1 1\n",
"3 9\n1 1 3\n",
"12345678 87654321\n43043751 1000000000 53798715\n"
] | [
"2\n",
"1\n",
"2147483648\n"
] | In the first sample case, Grisha needs five yellow and four blue crystals to create two yellow balls, one green ball, and one blue ball. To do that, Grisha needs to obtain two additional crystals: one yellow and one blue. | 500 | [
{
"input": "4 3\n2 1 1",
"output": "2"
},
{
"input": "3 9\n1 1 3",
"output": "1"
},
{
"input": "12345678 87654321\n43043751 1000000000 53798715",
"output": "2147483648"
},
{
"input": "12 12\n3 5 2",
"output": "0"
},
{
"input": "770 1390\n170 442 311",
"output"... | 1,625,634,729 | 2,147,483,647 | PyPy 3 | OK | TESTS | 38 | 109 | 0 | A,B=map(int,input().split())
x,y,z=map(int,input().split())
print(max(0,2*x+y-A)+max(0,y+3*z-B))
| Title: Tricky Alchemy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
During the winter holidays, the demand for Christmas balls is exceptionally high. Since it's already 2018, the advances in alchemy allow easy and efficient ball creation by utilizing magic crystals.
Grisha needs to obta... | ```python
A,B=map(int,input().split())
x,y,z=map(int,input().split())
print(max(0,2*x+y-A)+max(0,y+3*z-B))
``` | 3 | |
235 | A | LCM Challenge | PROGRAMMING | 1,600 | [
"number theory"
] | null | null | Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive integers (they don't have to be distinct) which are not greater than *n*. Can you help me to find ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the *n* mentioned in the statement. | Print a single integer — the maximum possible LCM of three not necessarily distinct positive integers that are not greater than *n*. | [
"9\n",
"7\n"
] | [
"504\n",
"210\n"
] | The least common multiple of some positive integers is the least positive integer which is multiple for each of them.
The result may become very large, 32-bit integer won't be enough. So using 64-bit integers is recommended.
For the last example, we can chose numbers 7, 6, 5 and the LCM of them is 7·6·5 = 210. It is ... | 500 | [
{
"input": "9",
"output": "504"
},
{
"input": "7",
"output": "210"
},
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "60"
},
{
"input": "33",
"output": "32736"
},
{
"input": "21",
"output": ... | 1,690,783,885 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 31 | 186 | 0 | n=int(input())
import math
if n==1:
print(1)
elif n==2:
print(2)
else:
x=(n*(n-1))//math.gcd(n,n-1)
x=(x*(n-2))//math.gcd(x,n-2)
print(x) | Title: LCM Challenge
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive... | ```python
n=int(input())
import math
if n==1:
print(1)
elif n==2:
print(2)
else:
x=(n*(n-1))//math.gcd(n,n-1)
x=(x*(n-2))//math.gcd(x,n-2)
print(x)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Santa Claus likes palindromes very much. There was his birthday recently. *k* of his friends came to him to congratulate him, and each of them presented to him a string *s**i* having the same length *n*. We denote the beauty of the *i*-th string by *a**i*. It can happen that *a**i* is negative — that means that Santa d... | The first line contains two positive integers *k* and *n* divided by space and denoting the number of Santa friends and the length of every string they've presented, respectively (1<=≤<=*k*,<=*n*<=≤<=100<=000; *n*·*k* <=≤<=100<=000).
*k* lines follow. The *i*-th of them contains the string *s**i* and its beauty *a**i*... | In the only line print the required maximum possible beauty. | [
"7 3\nabb 2\naaa -3\nbba -1\nzyz -4\nabb 5\naaa 7\nxyx 4\n",
"3 1\na 1\na 2\na 3\n",
"2 5\nabcde 10000\nabcde 10000\n"
] | [
"12\n",
"6\n",
"0\n"
] | In the first example Santa can obtain abbaaaxyxaaabba by concatenating strings 5, 2, 7, 6 and 3 (in this order). | 0 | [
{
"input": "7 3\nabb 2\naaa -3\nbba -1\nzyz -4\nabb 5\naaa 7\nxyx 4",
"output": "12"
},
{
"input": "3 1\na 1\na 2\na 3",
"output": "6"
},
{
"input": "2 5\nabcde 10000\nabcde 10000",
"output": "0"
},
{
"input": "10 10\nnjxbzflaka -1\nfelbvvtkja 6\ngxiuztqkcw 5\naomvscmtti 6\nj... | 1,641,930,910 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 46 | 0 | # input
k, n = list(map(int, input("").split()))
A = []
for i in range(k):
aux = input("").split(" ")
A.append([aux[0], int(aux[1])])
p = [31 ** i for i in range(k * n)]
hasher = lambda s: sum([(ord(s[i])-96) * p[i] for i in range(len(s))])
hasheri = lambda s: sum([(ord(s[i])-96) * p[len(s) - i - 1] for i ... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus likes palindromes very much. There was his birthday recently. *k* of his friends came to him to congratulate him, and each of them presented to him a string *s**i* having the same length *n*. We denote the beauty of th... | ```python
# input
k, n = list(map(int, input("").split()))
A = []
for i in range(k):
aux = input("").split(" ")
A.append([aux[0], int(aux[1])])
p = [31 ** i for i in range(k * n)]
hasher = lambda s: sum([(ord(s[i])-96) * p[i] for i in range(len(s))])
hasheri = lambda s: sum([(ord(s[i])-96) * p[len(s) - i -... | -1 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,659,547,112 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | N = int(input())
lst = []
for _ in range(N):
lst.apend(input())
lst = [[3,-1,7],
[-5,2,-4],
[2,-1,-3]]
x = []
y = []
z = []
for i in range(N):
x.append(lst[i][0])
y.append(lst[i][1])
z.append(lst[i][2])
j = sum(x)
k = sum(y)
l = sum(z)
suma = [j,k,l]
if sum(suma) == 0:... | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. S... | ```python
N = int(input())
lst = []
for _ in range(N):
lst.apend(input())
lst = [[3,-1,7],
[-5,2,-4],
[2,-1,-3]]
x = []
y = []
z = []
for i in range(N):
x.append(lst[i][0])
y.append(lst[i][1])
z.append(lst[i][2])
j = sum(x)
k = sum(y)
l = sum(z)
suma = [j,k,l]
if sum(s... | -1 |
304 | B | Calendar | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | Calendars in widespread use today include the Gregorian calendar, which is the de facto international standard, and is used almost everywhere in the world for civil purposes. The Gregorian reform modified the Julian calendar's scheme of leap years as follows:
Every year that is exactly divisible by four is a leap yea... | The first two lines contain two dates, each date is in the format yyyy:mm:dd (1900<=≤<=*yyyy*<=≤<=2038 and yyyy:mm:dd is a legal date). | Print a single integer — the answer to the problem. | [
"1900:01:01\n2038:12:31\n",
"1996:03:09\n1991:11:12\n"
] | [
"50768\n",
"1579\n"
] | none | 1,000 | [
{
"input": "1900:01:01\n2038:12:31",
"output": "50768"
},
{
"input": "1996:03:09\n1991:11:12",
"output": "1579"
},
{
"input": "1999:12:31\n2000:02:29",
"output": "60"
},
{
"input": "1903:09:27\n1988:06:15",
"output": "30943"
},
{
"input": "1913:11:14\n1901:05:11",... | 1,619,697,279 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 372 | 6,553,600 |
def STR(): return list(input())
def INT(): return int(input())
def MAP(): return map(int, input().split())
def MAP2():return map(float,input().split())
def LIST(): return list(map(int, input().split()))
def STRING(): return input()
import string
import sys
import datetime
from heapq import heappop , heappush... | Title: Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Calendars in widespread use today include the Gregorian calendar, which is the de facto international standard, and is used almost everywhere in the world for civil purposes. The Gregorian reform modified the Julian calendar's... | ```python
def STR(): return list(input())
def INT(): return int(input())
def MAP(): return map(int, input().split())
def MAP2():return map(float,input().split())
def LIST(): return list(map(int, input().split()))
def STRING(): return input()
import string
import sys
import datetime
from heapq import heappop ... | 3 | |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,502,267,496 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 483 | 6,041,600 | n = int(input())
s = []
sum = 0
for i in range(n):
s1 = ''
if i%2 != 0:
for j in range(n):
if j%2 != 0:
s1 += 'C'
sum += 1
else:
s1 += '.'
s.append(s1)
else:
for j in range(n):
if j%2 == 0:
s1 += 'C'
sum += 1
else:
s1 += '.'
s.append(s1)
print(sum)... | Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
n = int(input())
s = []
sum = 0
for i in range(n):
s1 = ''
if i%2 != 0:
for j in range(n):
if j%2 != 0:
s1 += 'C'
sum += 1
else:
s1 += '.'
s.append(s1)
else:
for j in range(n):
if j%2 == 0:
s1 += 'C'
sum += 1
else:
s1 += '.'
s.append(s1)
... | 3 | |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,658,302,501 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 60 | 0 | def reducedfraction(d):
# function that converts a rational number
# to the reduced fraction
l = d.as_integer_ratio()
# reduced the list that contains the fraction
return l
li=[]
li=list(map(int,input().split()))
li.sort()
s=reducedfraction((li[1]/li[0]))
s2=reducedfraction((li[2... | Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
def reducedfraction(d):
# function that converts a rational number
# to the reduced fraction
l = d.as_integer_ratio()
# reduced the list that contains the fraction
return l
li=[]
li=list(map(int,input().split()))
li.sort()
s=reducedfraction((li[1]/li[0]))
s2=reducedfrac... | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the... | You are given the string *s* whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters. | Print the string *t*. If a suitable *t* string does not exist, then print "Just a legend" without the quotes. | [
"fixprefixsuffix\n",
"abcdabc\n"
] | [
"fix",
"Just a legend"
] | none | 0 | [
{
"input": "fixprefixsuffix",
"output": "fix"
},
{
"input": "abcdabc",
"output": "Just a legend"
},
{
"input": "qwertyqwertyqwerty",
"output": "qwerty"
},
{
"input": "papapapap",
"output": "papap"
},
{
"input": "aaaaaaaaaa",
"output": "aaaaaaaa"
},
{
"... | 1,632,994,021 | 2,147,483,647 | PyPy 3 | MEMORY_LIMIT_EXCEEDED | TESTS | 24 | 1,590 | 268,390,400 |
from collections import defaultdict
s=input()
l=len(s)
ans,p,pp=set(),set(),set()
for i in range(1,l):
p.add(s[:i])
pp.add(s[-i:])
ans=p.intersection(pp)
dd=defaultdict(set)
for x in ans:
dd[len(x)].add(x)
dd_vals=sorted(dd, reverse=True)
d=0
for x in dd_vals:
ans=dd[x]
for j in range(1,l-x):
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carved on... | ```python
from collections import defaultdict
s=input()
l=len(s)
ans,p,pp=set(),set(),set()
for i in range(1,l):
p.add(s[:i])
pp.add(s[-i:])
ans=p.intersection(pp)
dd=defaultdict(set)
for x in ans:
dd[len(x)].add(x)
dd_vals=sorted(dd, reverse=True)
d=0
for x in dd_vals:
ans=dd[x]
for j in range(... | 0 | |
327 | A | Flipping Game | PROGRAMMING | 1,200 | [
"brute force",
"dp",
"implementation"
] | null | null | Iahub got bored, so he invented a game to be played on paper.
He writes *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Each of those integers can be either 0 or 1. He's allowed to do exactly one move: he chooses two indices *i* and *j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) and flips all values *a**k* for which their positions are in... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100). In the second line of the input there are *n* integers: *a*1,<=*a*2,<=...,<=*a**n*. It is guaranteed that each of those *n* values is either 0 or 1. | Print an integer — the maximal number of 1s that can be obtained after exactly one move. | [
"5\n1 0 0 1 0\n",
"4\n1 0 0 1\n"
] | [
"4\n",
"4\n"
] | In the first case, flip the segment from 2 to 5 (*i* = 2, *j* = 5). That flip changes the sequence, it becomes: [1 1 1 0 1]. So, it contains four ones. There is no way to make the whole sequence equal to [1 1 1 1 1].
In the second case, flipping only the second and the third element (*i* = 2, *j* = 3) will turn all nu... | 500 | [
{
"input": "5\n1 0 0 1 0",
"output": "4"
},
{
"input": "4\n1 0 0 1",
"output": "4"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "8\n1 0 0 0 1 0 0 0",
"output": "7"
},
{
"input": "18\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 ... | 1,695,624,110 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | n=int(input())
l1=[int(a) for a in input().split()]
l1.insert(0,0)
l1.append(0)
l2,l3=[],[]
a1,a2=0,0
for i in range(len(l1)):
if l1[i]:
a2+=1
else:
a1+=1
l2.append(a1)
l3.append(a2)
ans=0
for i in range(1,n+1):
a1=l3[i-1]
for j in range(i,n+1):
a2=l3[-1]... | Title: Flipping Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub got bored, so he invented a game to be played on paper.
He writes *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Each of those integers can be either 0 or 1. He's allowed to do exactly one move: he chooses two indices *... | ```python
n=int(input())
l1=[int(a) for a in input().split()]
l1.insert(0,0)
l1.append(0)
l2,l3=[],[]
a1,a2=0,0
for i in range(len(l1)):
if l1[i]:
a2+=1
else:
a1+=1
l2.append(a1)
l3.append(a2)
ans=0
for i in range(1,n+1):
a1=l3[i-1]
for j in range(i,n+1):
... | 0 | |
39 | D | Cubical Planet | PROGRAMMING | 1,100 | [
"math"
] | D. Cubical Planet | 2 | 64 | You can find anything whatsoever in our Galaxy! A cubical planet goes round an icosahedral star. Let us introduce a system of axes so that the edges of the cubical planet are parallel to the coordinate axes and two opposite vertices lay in the points (0,<=0,<=0) and (1,<=1,<=1). Two flies live on the planet. At the mom... | The first line contains three space-separated integers (0 or 1) — the coordinates of the first fly, the second line analogously contains the coordinates of the second fly. | Output "YES" (without quotes) if the flies see each other. Otherwise, output "NO". | [
"0 0 0\n0 1 0\n",
"1 1 0\n0 1 0\n",
"0 0 0\n1 1 1\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "0 0 0\n0 1 0",
"output": "YES"
},
{
"input": "1 1 0\n0 1 0",
"output": "YES"
},
{
"input": "0 0 0\n1 1 1",
"output": "NO"
},
{
"input": "0 0 0\n1 0 0",
"output": "YES"
},
{
"input": "0 0 0\n0 1 0",
"output": "YES"
},
{
"input": "0 0 0\n1 1 ... | 1,656,177,770 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 92 | 4,300,800 | x1,y1,z1=map(int,input().split())
x2,y2,z2=map(int,input().split())
if x1==x2 or y1==y2 or z1==z2:
print("YES")
else:
print("NO")
| Title: Cubical Planet
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
You can find anything whatsoever in our Galaxy! A cubical planet goes round an icosahedral star. Let us introduce a system of axes so that the edges of the cubical planet are parallel to the coordinate axes and two opposite v... | ```python
x1,y1,z1=map(int,input().split())
x2,y2,z2=map(int,input().split())
if x1==x2 or y1==y2 or z1==z2:
print("YES")
else:
print("NO")
``` | 3.944957 |
597 | A | Divisibility | PROGRAMMING | 1,600 | [
"math"
] | null | null | Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*. | The only line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=1018;<=-<=1018<=≤<=*a*<=≤<=*b*<=≤<=1018). | Print the required number. | [
"1 1 10\n",
"2 -4 4\n"
] | [
"10\n",
"5\n"
] | none | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "2 -4 4",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 0 0",
"output": "1"
},
{
"input": "1 0 1",
"output": "2"
},
{
"input": "1 10181 10182",
"output": "2"
},
{
"inpu... | 1,613,787,916 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 74 | 1,000 | 0 | import sys
k, a, b = map(int, sys.stdin.readline().split())
while a % k:
a += 1
count = ((b - a) // k) + 1
print(count) | Title: Divisibility
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*.
Input Specification:
The onl... | ```python
import sys
k, a, b = map(int, sys.stdin.readline().split())
while a % k:
a += 1
count = ((b - a) // k) + 1
print(count)
``` | 0 | |
591 | B | Rebranding | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | null | null | The name of one small but proud corporation consists of *n* lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slog... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of *n* lowercase English letters and represents the original name of the corporation.
Next *m* lines contain the descr... | Print the new name of the corporation. | [
"6 1\npolice\np m\n",
"11 6\nabacabadaba\na b\nb c\na d\ne g\nf a\nb b\n"
] | [
"molice\n",
"cdcbcdcfcdc\n"
] | In the second sample the name of the corporation consecutively changes as follows:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c7648432f7138ca53234357d7e08d1d119166055.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.co... | 1,000 | [
{
"input": "6 1\npolice\np m",
"output": "molice"
},
{
"input": "11 6\nabacabadaba\na b\nb c\na d\ne g\nf a\nb b",
"output": "cdcbcdcfcdc"
},
{
"input": "1 1\nf\nz h",
"output": "f"
},
{
"input": "1 1\na\na b",
"output": "b"
},
{
"input": "10 10\nlellelleel\ne l\n... | 1,526,481,996 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 7,065,600 | n, m = map(int, input().split())
s = input()
for i in range(m):
x, y = input().split()
otv = ''
for i in range(n):
if s[i] == y:
otv += x
elif s[i] == x:
otv += y
else:
otv += s[i]
s = otv
print(otv) | Title: Rebranding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The name of one small but proud corporation consists of *n* lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand ... | ```python
n, m = map(int, input().split())
s = input()
for i in range(m):
x, y = input().split()
otv = ''
for i in range(n):
if s[i] == y:
otv += x
elif s[i] == x:
otv += y
else:
otv += s[i]
s = otv
print(otv)
``` | 0 | |
578 | A | A Problem about Polyline | PROGRAMMING | 1,700 | [
"geometry",
"math"
] | null | null | There is a polyline going through points (0,<=0)<=–<=(*x*,<=*x*)<=–<=(2*x*,<=0)<=–<=(3*x*,<=*x*)<=–<=(4*x*,<=0)<=–<=...<=-<=(2*kx*,<=0)<=–<=(2*kx*<=+<=*x*,<=*x*)<=–<=....
We know that the polyline passes through the point (*a*,<=*b*). Find minimum positive value *x* such that it is true or determine that there is no ... | Only one line containing two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=109). | Output the only line containing the answer. Your answer will be considered correct if its relative or absolute error doesn't exceed 10<=-<=9. If there is no such *x* then output <=-<=1 as the answer. | [
"3 1\n",
"1 3\n",
"4 1\n"
] | [
"1.000000000000\n",
"-1\n",
"1.250000000000\n"
] | You can see following graphs for sample 1 and sample 3. | 250 | [
{
"input": "3 1",
"output": "1.000000000000"
},
{
"input": "1 3",
"output": "-1"
},
{
"input": "4 1",
"output": "1.250000000000"
},
{
"input": "1000000000 1000000000",
"output": "1000000000.000000000000"
},
{
"input": "1000000000 1",
"output": "1.000000001000"... | 1,652,229,945 | 2,147,483,647 | PyPy 3 | OK | TESTS | 31 | 93 | 0 | from sys import stdin, stdout
int_in = lambda: int(stdin.readline())
arr_in = lambda: [int(x) for x in stdin.readline().split()]
mat_in = lambda rows: [arr_in() for _ in range(rows)]
str_in = lambda: stdin.readline().strip()
out = lambda o: stdout.write("{}\n".format(o))
arr_out = lambda o: out(" ".join(map(str... | Title: A Problem about Polyline
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a polyline going through points (0,<=0)<=–<=(*x*,<=*x*)<=–<=(2*x*,<=0)<=–<=(3*x*,<=*x*)<=–<=(4*x*,<=0)<=–<=...<=-<=(2*kx*,<=0)<=–<=(2*kx*<=+<=*x*,<=*x*)<=–<=....
We know that the polyline passes thro... | ```python
from sys import stdin, stdout
int_in = lambda: int(stdin.readline())
arr_in = lambda: [int(x) for x in stdin.readline().split()]
mat_in = lambda rows: [arr_in() for _ in range(rows)]
str_in = lambda: stdin.readline().strip()
out = lambda o: stdout.write("{}\n".format(o))
arr_out = lambda o: out(" ".jo... | 3 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,626,616,298 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 6,758,400 | integer_array = input().split(" ")
print( (integer_array[0] * integer_array[1]) % 2 )
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
integer_array = input().split(" ")
print( (integer_array[0] * integer_array[1]) % 2 )
``` | -1 |
665 | D | Simple Subset | PROGRAMMING | 1,800 | [
"constructive algorithms",
"greedy",
"number theory"
] | null | null | A tuple of positive integers {*x*1,<=*x*2,<=...,<=*x**k*} is called simple if for all pairs of positive integers (*i*,<=<=*j*) (1<=<=≤<=*i*<=<=<<=<=*j*<=≤<=*k*), *x**i*<=<=+<=<=*x**j* is a prime.
You are given an array *a* with *n* positive integers *a*1,<=<=*a*2,<=<=...,<=<=*a**n* (not necessary distinct). You wan... | The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of integers in the array *a*.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=106) — the elements of the array *a*. | On the first line print integer *m* — the maximum possible size of simple subset of *a*.
On the second line print *m* integers *b**l* — the elements of the simple subset of the array *a* with the maximum size.
If there is more than one solution you can print any of them. You can print the elements of the subset in an... | [
"2\n2 3\n",
"2\n2 2\n",
"3\n2 1 1\n",
"2\n83 14\n"
] | [
"2\n3 2\n",
"1\n2\n",
"3\n1 1 2\n",
"2\n14 83\n"
] | none | 0 | [
{
"input": "2\n2 3",
"output": "2\n3 2"
},
{
"input": "2\n2 2",
"output": "1\n2"
},
{
"input": "3\n2 1 1",
"output": "3\n1 1 2"
},
{
"input": "2\n83 14",
"output": "2\n14 83"
},
{
"input": "10\n10 10 1 2 3 3 1 2 1 5",
"output": "4\n1 1 10 1"
},
{
"inpu... | 1,461,433,548 | 2,147,483,647 | PyPy 3 | OK | TESTS | 66 | 373 | 31,641,600 | import math
N = 2000001
sq = math.floor(N ** 0.5)
isprime = [True] * N
for p in range(2, N):
if isprime[p]:
for i in range(p**2, N, p):
isprime[i] = False
def solve():
n = int(input())
A = [int(x) for x in input().split()]
odd = list(filter(lambda x: x%2, A))
even = list(filter... | Title: Simple Subset
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tuple of positive integers {*x*1,<=*x*2,<=...,<=*x**k*} is called simple if for all pairs of positive integers (*i*,<=<=*j*) (1<=<=≤<=*i*<=<=<<=<=*j*<=≤<=*k*), *x**i*<=<=+<=<=*x**j* is a prime.
You are given an arra... | ```python
import math
N = 2000001
sq = math.floor(N ** 0.5)
isprime = [True] * N
for p in range(2, N):
if isprime[p]:
for i in range(p**2, N, p):
isprime[i] = False
def solve():
n = int(input())
A = [int(x) for x in input().split()]
odd = list(filter(lambda x: x%2, A))
even = l... | 3 | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,692,731,949 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 29 | 62 | 0 | n, m = map(int, input().split())
x = list(map(int, input().split()))
print(sum([1 if i <= m else 2 for i in x]))
| Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
n, m = map(int, input().split())
x = list(map(int, input().split()))
print(sum([1 if i <= m else 2 for i in x]))
``` | 3 | |
893 | B | Beautiful Divisors | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Recently Luba learned about a special kind of numbers that she calls beautiful numbers. The number is called beautiful iff its binary representation consists of *k*<=+<=1 consecutive ones, and then *k* consecutive zeroes.
Some examples of beautiful numbers:
- 12 (110); - 1102 (610); - 11110002 (12010); - 1111100... | The only line of input contains one number *n* (1<=≤<=*n*<=≤<=105) — the number Luba has got. | Output one number — the greatest beautiful divisor of Luba's number. It is obvious that the answer always exists. | [
"3\n",
"992\n"
] | [
"1\n",
"496\n"
] | none | 0 | [
{
"input": "3",
"output": "1"
},
{
"input": "992",
"output": "496"
},
{
"input": "81142",
"output": "1"
},
{
"input": "76920",
"output": "120"
},
{
"input": "2016",
"output": "2016"
},
{
"input": "1",
"output": "1"
},
{
"input": "6",
"o... | 1,651,652,466 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | import sys
input = sys.stdin.readline
input()
print(1) | Title: Beautiful Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Luba learned about a special kind of numbers that she calls beautiful numbers. The number is called beautiful iff its binary representation consists of *k*<=+<=1 consecutive ones, and then *k* consecutive ze... | ```python
import sys
input = sys.stdin.readline
input()
print(1)
``` | 0 | |
899 | B | Months and Years | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Everybody in Russia uses Gregorian calendar. In this calendar there are 31 days in January, 28 or 29 days in February (depending on whether the year is leap or not), 31 days in March, 30 days in April, 31 days in May, 30 in June, 31 in July, 31 in August, 30 in September, 31 in October, 30 in November, 31 in December.
... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=24) — the number of integers.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (28<=≤<=*a**i*<=≤<=31) — the numbers you are to check. | If there are several consecutive months that fit the sequence, print "YES" (without quotes). Otherwise, print "NO" (without quotes).
You can print each letter in arbitrary case (small or large). | [
"4\n31 31 30 31\n",
"2\n30 30\n",
"5\n29 31 30 31 30\n",
"3\n31 28 30\n",
"3\n31 31 28\n"
] | [
"Yes\n\n",
"No\n\n",
"Yes\n\n",
"No\n\n",
"Yes\n\n"
] | In the first example the integers can denote months July, August, September and October.
In the second example the answer is no, because there are no two consecutive months each having 30 days.
In the third example the months are: February (leap year) — March — April – May — June.
In the fourth example the number of... | 1,000 | [
{
"input": "4\n31 31 30 31",
"output": "Yes"
},
{
"input": "2\n30 30",
"output": "No"
},
{
"input": "5\n29 31 30 31 30",
"output": "Yes"
},
{
"input": "3\n31 28 30",
"output": "No"
},
{
"input": "3\n31 31 28",
"output": "Yes"
},
{
"input": "24\n29 28 3... | 1,533,061,275 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 50 | 124 | 0 | # -*- coding: utf-8 -*-
"""
Created on Tue Jul 31 23:02:02 2018
@author: akshat
"""
def equals(l1, l2):
if len(l1) == len(l2):
for i in range(len(l2)):
if l1[i] != l2[i]:
return False
return True
else:
return False
n = int(input())
a = list(map(int,input().s... | Title: Months and Years
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Everybody in Russia uses Gregorian calendar. In this calendar there are 31 days in January, 28 or 29 days in February (depending on whether the year is leap or not), 31 days in March, 30 days in April, 31 days in May, ... | ```python
# -*- coding: utf-8 -*-
"""
Created on Tue Jul 31 23:02:02 2018
@author: akshat
"""
def equals(l1, l2):
if len(l1) == len(l2):
for i in range(len(l2)):
if l1[i] != l2[i]:
return False
return True
else:
return False
n = int(input())
a = list(map(int... | 0 | |
816 | A | Karen and Morning | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Karen is getting ready for a new school day!
It is currently hh:mm, given in a 24-hour format. As you know, Karen loves palindromes, and she believes that it is good luck to wake up when the time is a palindrome.
What is the minimum number of minutes she should sleep, such that, when she wakes up, the time is a palin... | The first and only line of input contains a single string in the format hh:mm (00<=≤<= hh <=≤<=23, 00<=≤<= mm <=≤<=59). | Output a single integer on a line by itself, the minimum number of minutes she should sleep, such that, when she wakes up, the time is a palindrome. | [
"05:39\n",
"13:31\n",
"23:59\n"
] | [
"11\n",
"0\n",
"1\n"
] | In the first test case, the minimum number of minutes Karen should sleep for is 11. She can wake up at 05:50, when the time is a palindrome.
In the second test case, Karen can wake up immediately, as the current time, 13:31, is already a palindrome.
In the third test case, the minimum number of minutes Karen should s... | 500 | [
{
"input": "05:39",
"output": "11"
},
{
"input": "13:31",
"output": "0"
},
{
"input": "23:59",
"output": "1"
},
{
"input": "13:32",
"output": "69"
},
{
"input": "14:40",
"output": "1"
},
{
"input": "14:00",
"output": "41"
},
{
"input": "05:... | 1,639,418,895 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 24 | 109 | 0 | pp = input()
h,m = pp.split(':')
if pp == pp[::-1]:
print(0)
else:
if int(h[::-1])<int(m):
if h=='23':
print(60-int(m))
else:
print(60-int(m)+int(str(int(h)+1)[::-1]))
else:
print(int(h[::-1])-int(m)) | Title: Karen and Morning
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Karen is getting ready for a new school day!
It is currently hh:mm, given in a 24-hour format. As you know, Karen loves palindromes, and she believes that it is good luck to wake up when the time is a palindrome.
Wh... | ```python
pp = input()
h,m = pp.split(':')
if pp == pp[::-1]:
print(0)
else:
if int(h[::-1])<int(m):
if h=='23':
print(60-int(m))
else:
print(60-int(m)+int(str(int(h)+1)[::-1]))
else:
print(int(h[::-1])-int(m))
``` | 0 | |
371 | B | Fox Dividing Cheese | PROGRAMMING | 1,300 | [
"math",
"number theory"
] | null | null | Two little greedy bears have found two pieces of cheese in the forest of weight *a* and *b* grams, correspondingly. The bears are so greedy that they are ready to fight for the larger piece. That's where the fox comes in and starts the dialog: "Little bears, wait a little, I want to make your pieces equal" "Come off it... | The first line contains two space-separated integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=109). | If the fox is lying to the little bears and it is impossible to make the pieces equal, print -1. Otherwise, print the required minimum number of operations. If the pieces of the cheese are initially equal, the required number is 0. | [
"15 20\n",
"14 8\n",
"6 6\n"
] | [
"3\n",
"-1\n",
"0\n"
] | none | 1,000 | [
{
"input": "15 20",
"output": "3"
},
{
"input": "14 8",
"output": "-1"
},
{
"input": "6 6",
"output": "0"
},
{
"input": "1 1",
"output": "0"
},
{
"input": "1 1024",
"output": "10"
},
{
"input": "1024 729",
"output": "16"
},
{
"input": "1024... | 1,599,384,311 | 2,147,483,647 | PyPy 3 | OK | TESTS | 54 | 156 | 0 | def rpm(n):
output={2:0, 3:0, 5:0, 10:0}
for i in [2, 3, 5]:
op=0
while n%i==0:
n//=i
op+=1
output[i]=op
output[10]=n
return output
A, B=map(rpm, map(int, input().split()))
if A[10]!=B[10]:
print(-1)
else:
print(max(A[2],B[2])-min(A[2... | Title: Fox Dividing Cheese
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two little greedy bears have found two pieces of cheese in the forest of weight *a* and *b* grams, correspondingly. The bears are so greedy that they are ready to fight for the larger piece. That's where the fox com... | ```python
def rpm(n):
output={2:0, 3:0, 5:0, 10:0}
for i in [2, 3, 5]:
op=0
while n%i==0:
n//=i
op+=1
output[i]=op
output[10]=n
return output
A, B=map(rpm, map(int, input().split()))
if A[10]!=B[10]:
print(-1)
else:
print(max(A[2],B[2... | 3 | |
289 | B | Polo the Penguin and Matrix | PROGRAMMING | 1,400 | [
"brute force",
"dp",
"implementation",
"sortings",
"ternary search"
] | null | null | Little penguin Polo has an *n*<=×<=*m* matrix, consisting of integers. Let's index the matrix rows from 1 to *n* from top to bottom and let's index the columns from 1 to *m* from left to right. Let's represent the matrix element on the intersection of row *i* and column *j* as *a**ij*.
In one move the penguin can add ... | The first line contains three integers *n*, *m* and *d* (1<=≤<=*n*,<=*m*<=≤<=100,<=1<=≤<=*d*<=≤<=104) — the matrix sizes and the *d* parameter. Next *n* lines contain the matrix: the *j*-th integer in the *i*-th row is the matrix element *a**ij* (1<=≤<=*a**ij*<=≤<=104). | In a single line print a single integer — the minimum number of moves the penguin needs to make all matrix elements equal. If that is impossible, print "-1" (without the quotes). | [
"2 2 2\n2 4\n6 8\n",
"1 2 7\n6 7\n"
] | [
"4\n",
"-1\n"
] | none | 1,000 | [
{
"input": "2 2 2\n2 4\n6 8",
"output": "4"
},
{
"input": "1 2 7\n6 7",
"output": "-1"
},
{
"input": "3 2 1\n5 7\n1 2\n5 100",
"output": "104"
},
{
"input": "3 3 3\n5 8 5\n11 11 17\n14 5 2",
"output": "12"
},
{
"input": "3 3 3\n5 8 5\n11 11 17\n14 5 3",
"outpu... | 1,654,699,739 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 60 | 0 |
def replace_min_max_inplace(lst):
max_value=max(lst)
min_value=min(lst)
for i in range(len(lst)):
if lst[i]==max_value:
lst[i]=min_value
elif lst[i]==min_value:
lst[i]=max_value
def countleapyears(y2,y1):
return int((y2-y1)/4)
if __name__=='__main__':
... | Title: Polo the Penguin and Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little penguin Polo has an *n*<=×<=*m* matrix, consisting of integers. Let's index the matrix rows from 1 to *n* from top to bottom and let's index the columns from 1 to *m* from left to right. Let's represe... | ```python
def replace_min_max_inplace(lst):
max_value=max(lst)
min_value=min(lst)
for i in range(len(lst)):
if lst[i]==max_value:
lst[i]=min_value
elif lst[i]==min_value:
lst[i]=max_value
def countleapyears(y2,y1):
return int((y2-y1)/4)
if __name__=='_... | 0 | |
75 | A | Life Without Zeros | PROGRAMMING | 1,000 | [
"implementation"
] | A. Life Without Zeros | 2 | 256 | Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c*... | The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*. | The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise. | [
"101\n102\n",
"105\n106\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "101\n102",
"output": "YES"
},
{
"input": "105\n106",
"output": "NO"
},
{
"input": "544\n397",
"output": "YES"
},
{
"input": "822\n280",
"output": "NO"
},
{
"input": "101\n413",
"output": "NO"
},
{
"input": "309\n139",
"output": "NO"
}... | 1,660,810,930 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 43 | 124 | 0 | def solve():
a = int(input())
b = int(input())
c = a+b
a = str(a)
a = a.replace('0','')
b = str(b)
b = b.replace('0','')
c = str(c)
c = c.replace('0','')
a = int(a)
b = int(b)
c = int(c)
if(a+b==c):
print("YES")
else:
prin... | Title: Life Without Zeros
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assu... | ```python
def solve():
a = int(input())
b = int(input())
c = a+b
a = str(a)
a = a.replace('0','')
b = str(b)
b = b.replace('0','')
c = str(c)
c = c.replace('0','')
a = int(a)
b = int(b)
c = int(c)
if(a+b==c):
print("YES")
else:
... | 3.969 |
304 | A | Pythagorean Theorem II | PROGRAMMING | 1,200 | [
"brute force",
"math"
] | null | null | In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the s... | The only line contains one integer *n* (1<=≤<=*n*<=≤<=104) as we mentioned above. | Print a single integer — the answer to the problem. | [
"5\n",
"74\n"
] | [
"1\n",
"35\n"
] | none | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "74",
"output": "35"
},
{
"input": "1000",
"output": "881"
},
{
"input": "586",
"output": "472"
},
{
"input": "2",
"output": "0"
},
{
"input": "362",
"output": "258"
},
{
"input": "778",
"outp... | 1,695,249,507 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 32 | 1,590 | 1,843,200 | n=int(input())
import math
v = 0
for i in range(2,n+1):
for j in range(i,n+1):
if math.sqrt((i ** 2 )+( j ** 2)) == math.floor(math.sqrt((i ** 2) + (j ** 2) )) and math.floor(math.sqrt((i ** 2) + (j ** 2) )) <= n :
v += 1
print(v) | Title: Pythagorean Theorem II
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the squar... | ```python
n=int(input())
import math
v = 0
for i in range(2,n+1):
for j in range(i,n+1):
if math.sqrt((i ** 2 )+( j ** 2)) == math.floor(math.sqrt((i ** 2) + (j ** 2) )) and math.floor(math.sqrt((i ** 2) + (j ** 2) )) <= n :
v += 1
print(v)
``` | 3 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,652,322,568 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | # Domino piling (50A)
m,n = map(int, input().split())
print((m*n)//2) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
# Domino piling (50A)
m,n = map(int, input().split())
print((m*n)//2)
``` | 3.977 |
139 | A | Petr and Book | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. S... | The first input line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of pages in the book.
The second line contains seven non-negative space-separated integers that do not exceed 1000 — those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and... | Print a single number — the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. | [
"100\n15 20 20 15 10 30 45\n",
"2\n1 0 0 0 0 0 0\n"
] | [
"6\n",
"1\n"
] | Note to the first sample:
By the end of Monday and therefore, by the beginning of Tuesday Petr has 85 pages left. He has 65 pages left by Wednesday, 45 by Thursday, 30 by Friday, 20 by Saturday and on Saturday Petr finishes reading the book (and he also has time to read 10 pages of something else).
Note to the second... | 500 | [
{
"input": "100\n15 20 20 15 10 30 45",
"output": "6"
},
{
"input": "2\n1 0 0 0 0 0 0",
"output": "1"
},
{
"input": "100\n100 200 100 200 300 400 500",
"output": "1"
},
{
"input": "3\n1 1 1 1 1 1 1",
"output": "3"
},
{
"input": "1\n1 1 1 1 1 1 1",
"output": "1... | 1,641,151,471 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 18 | 92 | 512,000 | t = int(input())
x = list(map(int, input().split()))
def petr(t, x):
for i in range(7):
t = t - x[i]
if t <= 0:
print(i+1)
break
if t > 0:
petr(t, x)
petr(t, x)
| Title: Petr and Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight s... | ```python
t = int(input())
x = list(map(int, input().split()))
def petr(t, x):
for i in range(7):
t = t - x[i]
if t <= 0:
print(i+1)
break
if t > 0:
petr(t, x)
petr(t, x)
``` | -1 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,636,379,147 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 4,300,800 | string = input()
listSmLtt = list(filter(lambda x: x.islower(),string))
if len(listSmLtt) >= abs(len(string) - len(listSmLtt)):
print(string.lower())
else:
print(string.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
string = input()
listSmLtt = list(filter(lambda x: x.islower(),string))
if len(listSmLtt) >= abs(len(string) - len(listSmLtt)):
print(string.lower())
else:
print(string.upper())
``` | 3.960989 |
6 | C | Alice, Bob and Chocolate | PROGRAMMING | 1,200 | [
"greedy",
"two pointers"
] | C. Alice, Bob and Chocolate | 2 | 64 | Alice and Bob like games. And now they are ready to start a new game. They have placed *n* chocolate bars in a line. Alice starts to eat chocolate bars one by one from left to right, and Bob — from right to left. For each chocololate bar the time, needed for the player to consume it, is known (Alice and Bob eat them wi... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=105) — the amount of bars on the table. The second line contains a sequence *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000), where *t**i* is the time (in seconds) needed to consume the *i*-th bar (in the order from left to right). | Print two numbers *a* and *b*, where *a* is the amount of bars consumed by Alice, and *b* is the amount of bars consumed by Bob. | [
"5\n2 9 8 2 7\n"
] | [
"2 3\n"
] | none | 0 | [
{
"input": "5\n2 9 8 2 7",
"output": "2 3"
},
{
"input": "1\n1",
"output": "1 0"
},
{
"input": "2\n1 1",
"output": "1 1"
},
{
"input": "3\n1 1 1",
"output": "2 1"
},
{
"input": "4\n1 1 1 1",
"output": "2 2"
},
{
"input": "1\n6",
"output": "1 0"
}... | 1,624,907,152 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 124 | 0 | n = int(input())
a = list(map(int, input().split()))
b = []
for i in range(n):
b.append(1)
i_k = 0
i_p = n - 1
sums = sum(a)
t = True
while t:
if a[i_k] != -1 and b[i_k] != -2:
b[i_k] = -1
if a[i_k] != 0:
a[i_k] -= 1
else:
a[i_k] -= 1
a... | Title: Alice, Bob and Chocolate
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Alice and Bob like games. And now they are ready to start a new game. They have placed *n* chocolate bars in a line. Alice starts to eat chocolate bars one by one from left to right, and Bob — from right to left. Fo... | ```python
n = int(input())
a = list(map(int, input().split()))
b = []
for i in range(n):
b.append(1)
i_k = 0
i_p = n - 1
sums = sum(a)
t = True
while t:
if a[i_k] != -1 and b[i_k] != -2:
b[i_k] = -1
if a[i_k] != 0:
a[i_k] -= 1
else:
a[i_k] -= 1
... | 0 |
16 | B | Burglar and Matches | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | B. Burglar and Matches | 0 | 64 | A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactl... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer. | Output the only number — answer to the problem. | [
"7 3\n5 10\n2 5\n3 6\n",
"3 3\n1 3\n2 2\n3 1\n"
] | [
"62\n",
"7\n"
] | none | 0 | [
{
"input": "7 3\n5 10\n2 5\n3 6",
"output": "62"
},
{
"input": "3 3\n1 3\n2 2\n3 1",
"output": "7"
},
{
"input": "1 1\n1 2",
"output": "2"
},
{
"input": "1 2\n1 9\n1 6",
"output": "9"
},
{
"input": "1 10\n1 1\n1 9\n1 3\n1 9\n1 7\n1 10\n1 4\n1 7\n1 3\n1 1",
"ou... | 1,613,585,546 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 25 | 500 | 27,648,000 | import sys
def ints_input():
return [int(i) for i in sys.stdin.readline().strip("\n").split(" ")]
def print_list(arr):
sys.stdout.writelines(str(x)+" " for x in arr)
sys.stdout.write("\n")
def fast_input(type=str):
return type(sys.stdin.readline().strip("\n"))
n, m = ints_input()... | Title: Burglar and Matches
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* mat... | ```python
import sys
def ints_input():
return [int(i) for i in sys.stdin.readline().strip("\n").split(" ")]
def print_list(arr):
sys.stdout.writelines(str(x)+" " for x in arr)
sys.stdout.write("\n")
def fast_input(type=str):
return type(sys.stdin.readline().strip("\n"))
n, m = in... | 0 |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,634,583,443 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 62 | 0 | n, k = input().split()
n = int(n)
k = int(k)
divisors = 0;
goingUp = 1;
result = None
if (n == k and k == 1):
print(1)
exit()
while ( goingUp <= n/2):
tempNum = n % goingUp;
if tempNum == 0:
divisors += 1;
#if tempNum == 0:
# divisors.append(goingUp)
goingUp += 1;
if (di... | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
n, k = input().split()
n = int(n)
k = int(k)
divisors = 0;
goingUp = 1;
result = None
if (n == k and k == 1):
print(1)
exit()
while ( goingUp <= n/2):
tempNum = n % goingUp;
if tempNum == 0:
divisors += 1;
#if tempNum == 0:
# divisors.append(goingUp)
goingUp += 1;
... | -1 | |
660 | C | Hard Process | PROGRAMMING | 1,600 | [
"binary search",
"dp",
"two pointers"
] | null | null | You are given an array *a* with *n* elements. Each element of *a* is either 0 or 1.
Let's denote the length of the longest subsegment of consecutive elements in *a*, consisting of only numbers one, as *f*(*a*). You can change no more than *k* zeroes to ones to maximize *f*(*a*). | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=3·105,<=0<=≤<=*k*<=≤<=*n*) — the number of elements in *a* and the parameter *k*.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=1) — the elements of *a*. | On the first line print a non-negative integer *z* — the maximal value of *f*(*a*) after no more than *k* changes of zeroes to ones.
On the second line print *n* integers *a**j* — the elements of the array *a* after the changes.
If there are multiple answers, you can print any one of them. | [
"7 1\n1 0 0 1 1 0 1\n",
"10 2\n1 0 0 1 0 1 0 1 0 1\n"
] | [
"4\n1 0 0 1 1 1 1\n",
"5\n1 0 0 1 1 1 1 1 0 1\n"
] | none | 0 | [
{
"input": "7 1\n1 0 0 1 1 0 1",
"output": "4\n1 0 0 1 1 1 1"
},
{
"input": "10 2\n1 0 0 1 0 1 0 1 0 1",
"output": "5\n1 0 0 1 1 1 1 1 0 1"
},
{
"input": "1 0\n0",
"output": "0\n0"
},
{
"input": "1 0\n0",
"output": "0\n0"
},
{
"input": "7 0\n0 1 0 0 0 1 0",
"o... | 1,682,056,607 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | n, k = map(int, input().split())
a = [int(i) for i in input().split()]
count = 0
mx = 0
l, r = 0, 0
left_most, right_most = 0, 0
while r < n:
if a[r] == 0:
count += 1
if a[r] == 1 and count >= k:
if count == k:
mx = max(mx, r - l + 1)
left_most = l
... | Title: Hard Process
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array *a* with *n* elements. Each element of *a* is either 0 or 1.
Let's denote the length of the longest subsegment of consecutive elements in *a*, consisting of only numbers one, as *f*(*a*). You can ch... | ```python
n, k = map(int, input().split())
a = [int(i) for i in input().split()]
count = 0
mx = 0
l, r = 0, 0
left_most, right_most = 0, 0
while r < n:
if a[r] == 0:
count += 1
if a[r] == 1 and count >= k:
if count == k:
mx = max(mx, r - l + 1)
left_most... | 0 | |
870 | A | Search for Pretty Integers | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | You are given two lists of non-zero digits.
Let's call an integer pretty if its (base 10) representation has at least one digit from the first list and at least one digit from the second list. What is the smallest positive pretty integer? | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=9) — the lengths of the first and the second lists, respectively.
The second line contains *n* distinct digits *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=9) — the elements of the first list.
The third line contains *m* distinct digits *b*1,<=*b*2... | Print the smallest pretty integer. | [
"2 3\n4 2\n5 7 6\n",
"8 8\n1 2 3 4 5 6 7 8\n8 7 6 5 4 3 2 1\n"
] | [
"25\n",
"1\n"
] | In the first example 25, 46, 24567 are pretty, as well as many other integers. The smallest among them is 25. 42 and 24 are not pretty because they don't have digits from the second list.
In the second example all integers that have at least one digit different from 9 are pretty. It's obvious that the smallest among t... | 500 | [
{
"input": "2 3\n4 2\n5 7 6",
"output": "25"
},
{
"input": "8 8\n1 2 3 4 5 6 7 8\n8 7 6 5 4 3 2 1",
"output": "1"
},
{
"input": "1 1\n9\n1",
"output": "19"
},
{
"input": "9 1\n5 4 2 3 6 1 7 9 8\n9",
"output": "9"
},
{
"input": "5 3\n7 2 5 8 6\n3 1 9",
"output"... | 1,584,180,253 | 2,147,483,647 | PyPy 3 | OK | TESTS | 52 | 155 | 0 | print((lambda a,x,y: sorted([i for i in x if i in y])[0] if len([i for i in x if i in y])!=0 else str(min(min(x),min(y)))+str(max(min(x),min(y))))(input(),list(map(int,input().split())),list(map(int,input().split())))) | Title: Search for Pretty Integers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two lists of non-zero digits.
Let's call an integer pretty if its (base 10) representation has at least one digit from the first list and at least one digit from the second list. What is the sm... | ```python
print((lambda a,x,y: sorted([i for i in x if i in y])[0] if len([i for i in x if i in y])!=0 else str(min(min(x),min(y)))+str(max(min(x),min(y))))(input(),list(map(int,input().split())),list(map(int,input().split()))))
``` | 3 | |
255 | A | Greg's Workout | PROGRAMMING | 800 | [
"implementation"
] | null | null | Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg should repeat the *i*-th in order exercise *a**i* times.
Greg now only does three types of exercise... | The first line contains integer *n* (1<=≤<=*n*<=≤<=20). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=25) — the number of times Greg repeats the exercises. | Print word "chest" (without the quotes), if the chest gets the most exercise, "biceps" (without the quotes), if the biceps gets the most exercise and print "back" (without the quotes) if the back gets the most exercise.
It is guaranteed that the input is such that the answer to the problem is unambiguous. | [
"2\n2 8\n",
"3\n5 1 10\n",
"7\n3 3 2 7 9 6 8\n"
] | [
"biceps\n",
"back\n",
"chest\n"
] | In the first sample Greg does 2 chest, 8 biceps and zero back exercises, so the biceps gets the most exercises.
In the second sample Greg does 5 chest, 1 biceps and 10 back exercises, so the back gets the most exercises.
In the third sample Greg does 18 chest, 12 biceps and 8 back exercises, so the chest gets the mos... | 500 | [
{
"input": "2\n2 8",
"output": "biceps"
},
{
"input": "3\n5 1 10",
"output": "back"
},
{
"input": "7\n3 3 2 7 9 6 8",
"output": "chest"
},
{
"input": "4\n5 6 6 2",
"output": "chest"
},
{
"input": "5\n8 2 2 6 3",
"output": "chest"
},
{
"input": "6\n8 7 ... | 1,673,288,397 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 92 | 0 | n = int(input())
a = list(map(int, input().split()))
max_count = 0
max_muscle = ""
muscles = ["chest", "biceps", "back"]
for i in range(3):
count = 0
for j in range(i, len(a), 3):
count += a[j]
if count > max_count:
max_count = count
max_muscle = muscles[i]
print(max_muscle) | Title: Greg's Workout
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg ... | ```python
n = int(input())
a = list(map(int, input().split()))
max_count = 0
max_muscle = ""
muscles = ["chest", "biceps", "back"]
for i in range(3):
count = 0
for j in range(i, len(a), 3):
count += a[j]
if count > max_count:
max_count = count
max_muscle = muscles[i]
print(max_muscle)
``` | 3 | |
474 | A | Keyboard | PROGRAMMING | 900 | [
"implementation"
] | null | null | Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately. He accidentally moved both his hands with one position to the left or to the right. That mean... | First line of the input contains one letter describing direction of shifting ('L' or 'R' respectively for left or right).
Second line contains a sequence of characters written by Mole. The size of this sequence will be no more than 100. Sequence contains only symbols that appear on Mole's keyboard. It doesn't contain ... | Print a line that contains the original message. | [
"R\ns;;upimrrfod;pbr\n"
] | [
"allyouneedislove\n"
] | none | 500 | [
{
"input": "R\ns;;upimrrfod;pbr",
"output": "allyouneedislove"
},
{
"input": "R\nwertyuiop;lkjhgfdsxcvbnm,.",
"output": "qwertyuiolkjhgfdsazxcvbnm,"
},
{
"input": "L\nzxcvbnm,kjhgfdsaqwertyuio",
"output": "xcvbnm,.lkjhgfdswertyuiop"
},
{
"input": "R\nbubbuduppudup",
"outp... | 1,696,485,180 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 46 | 0 | s = input()
a = list(input())
kbrd = 'qwertyuiopasdfghjkl;zxcvbnm,./'
r = ''
if s == 'R':
for i in range(len(a)):
r += kbrd[kbrd.index(a[i])-1]
elif s == 'L':
for i in range(len(a)):
r += kbrd[kbrd.index(a[i])+1]
print(r)
| Title: Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately.... | ```python
s = input()
a = list(input())
kbrd = 'qwertyuiopasdfghjkl;zxcvbnm,./'
r = ''
if s == 'R':
for i in range(len(a)):
r += kbrd[kbrd.index(a[i])-1]
elif s == 'L':
for i in range(len(a)):
r += kbrd[kbrd.index(a[i])+1]
print(r)
``` | 3 | |
621 | A | Wet Shark and Odd and Even | PROGRAMMING | 900 | [
"implementation"
] | null | null | Today, Wet Shark is given *n* integers. Using any of these integers no more than once, Wet Shark wants to get maximum possible even (divisible by 2) sum. Please, calculate this value for Wet Shark.
Note, that if Wet Shark uses no integers from the *n* integers, the sum is an even integer 0. | The first line of the input contains one integer, *n* (1<=≤<=*n*<=≤<=100<=000). The next line contains *n* space separated integers given to Wet Shark. Each of these integers is in range from 1 to 109, inclusive. | Print the maximum possible even sum that can be obtained if we use some of the given integers. | [
"3\n1 2 3\n",
"5\n999999999 999999999 999999999 999999999 999999999\n"
] | [
"6",
"3999999996"
] | In the first sample, we can simply take all three integers for a total sum of 6.
In the second sample Wet Shark should take any four out of five integers 999 999 999. | 500 | [
{
"input": "3\n1 2 3",
"output": "6"
},
{
"input": "5\n999999999 999999999 999999999 999999999 999999999",
"output": "3999999996"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "15\n39 52 88 78 46 95 84 98 55 3 68 42 6 18 98",
"output": "870"
},
{
"input": "15\... | 1,596,464,193 | 2,147,483,647 | Python 3 | OK | TESTS | 87 | 187 | 15,564,800 | n = int(input())
a = sorted(map(int, input().split()))
k = 0
if sum(a) % 2 != 0:
for i in a:
if i % 2 != 0:
c = i
break
for i in a:
k += i
print(k - c)
else:
print(sum(a))
| Title: Wet Shark and Odd and Even
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today, Wet Shark is given *n* integers. Using any of these integers no more than once, Wet Shark wants to get maximum possible even (divisible by 2) sum. Please, calculate this value for Wet Shark.
Note, th... | ```python
n = int(input())
a = sorted(map(int, input().split()))
k = 0
if sum(a) % 2 != 0:
for i in a:
if i % 2 != 0:
c = i
break
for i in a:
k += i
print(k - c)
else:
print(sum(a))
``` | 3 | |
616 | A | Comparing Two Long Integers | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can r... | The first line contains a non-negative integer *a*.
The second line contains a non-negative integer *b*.
The numbers *a*,<=*b* may contain leading zeroes. Each of them contains no more than 106 digits. | Print the symbol "<" if *a*<=<<=*b* and the symbol ">" if *a*<=><=*b*. If the numbers are equal print the symbol "=". | [
"9\n10\n",
"11\n10\n",
"00012345\n12345\n",
"0123\n9\n",
"0123\n111\n"
] | [
"<\n",
">\n",
"=\n",
">\n",
">\n"
] | none | 0 | [
{
"input": "9\n10",
"output": "<"
},
{
"input": "11\n10",
"output": ">"
},
{
"input": "00012345\n12345",
"output": "="
},
{
"input": "0123\n9",
"output": ">"
},
{
"input": "0123\n111",
"output": ">"
},
{
"input": "9\n9",
"output": "="
},
{
... | 1,638,994,372 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | t=int(input())
for i in range(t):
x1,p1=input().split()
x2,p2=input().split()
if len(x1)+int(p1)>len(x2)+int(p2):
print(">")
elif len(x1)+int(p1)<len(x2)+int(p2):
print("<")
else:
k1,k2=int(p1),int(p2)
if k1>k2:
t=k1-k2
while t>0:
... | Title: Comparing Two Long Integers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use th... | ```python
t=int(input())
for i in range(t):
x1,p1=input().split()
x2,p2=input().split()
if len(x1)+int(p1)>len(x2)+int(p2):
print(">")
elif len(x1)+int(p1)<len(x2)+int(p2):
print("<")
else:
k1,k2=int(p1),int(p2)
if k1>k2:
t=k1-k2
wh... | -1 | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,664,009,257 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 46 | 0 | x = int(input())
l = list(map(int,input().split()))
l = [i for i in l if(i!=0)]
print(len(set(l)))
| Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
x = int(input())
l = list(map(int,input().split()))
l = [i for i in l if(i!=0)]
print(len(set(l)))
``` | 3 | |
47 | A | Triangular numbers | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Triangular numbers | 2 | 256 | A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is the number of dots in a triangle with *n* dots on a side. . You can learn more about these numbers fr... | The first line contains the single number *n* (1<=≤<=*n*<=≤<=500) — the given integer. | If the given integer is a triangular number output YES, otherwise output NO. | [
"1\n",
"2\n",
"3\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "1",
"output": "YES"
},
{
"input": "2",
"output": "NO"
},
{
"input": "3",
"output": "YES"
},
{
"input": "4",
"output": "NO"
},
{
"input": "5",
"output": "NO"
},
{
"input": "6",
"output": "YES"
},
{
"input": "7",
"output": "NO... | 1,604,927,609 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import sys
import math
input = sys.stdin.readline
n = 2 * (int(input()))
if ((-1 + (1 + math.sqrt(4 * 1 * float(n))))/2).is_integer():
print("YES")
else
print("NO") | Title: Triangular numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is t... | ```python
import sys
import math
input = sys.stdin.readline
n = 2 * (int(input()))
if ((-1 + (1 + math.sqrt(4 * 1 * float(n))))/2).is_integer():
print("YES")
else
print("NO")
``` | -1 |
30 | A | Accounting | PROGRAMMING | 1,400 | [
"brute force",
"math"
] | A. Accounting | 2 | 256 | A long time ago in some far country lived king Copa. After the recent king's reform, he got so large powers that started to keep the books by himself.
The total income *A* of his kingdom during 0-th year is known, as well as the total income *B* during *n*-th year (these numbers can be negative — it means that there w... | The input contains three integers *A*, *B*, *n* (|*A*|,<=|*B*|<=≤<=1000, 1<=≤<=*n*<=≤<=10). | Output the required integer coefficient *X*, or «No solution», if such a coefficient does not exist or it is fractional. If there are several possible solutions, output any of them. | [
"2 18 2\n",
"-1 8 3\n",
"0 0 10\n",
"1 16 5\n"
] | [
"3",
"-2",
"5",
"No solution"
] | none | 500 | [
{
"input": "2 18 2",
"output": "3"
},
{
"input": "-1 8 3",
"output": "-2"
},
{
"input": "0 0 10",
"output": "5"
},
{
"input": "1 16 5",
"output": "No solution"
},
{
"input": "0 1 2",
"output": "No solution"
},
{
"input": "3 0 4",
"output": "0"
},... | 1,552,907,580 | 2,460 | Python 3 | WRONG_ANSWER | TESTS | 40 | 218 | 0 | import cmath
def floor(x) :
return (x-int(x))
a , b , k = map(int,input().split())
if (a==0) :
if a==b :
exit(print("1"))
else :
exit(print("No solution"))
if b/a < 0 and k%2 == 0 :
exit(print("No solution"))
t = pow(b/a , 1/k)
t = complex(t)
t1 = t.real
t2 = t.imag
t = p... | Title: Accounting
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A long time ago in some far country lived king Copa. After the recent king's reform, he got so large powers that started to keep the books by himself.
The total income *A* of his kingdom during 0-th year is known, as well as th... | ```python
import cmath
def floor(x) :
return (x-int(x))
a , b , k = map(int,input().split())
if (a==0) :
if a==b :
exit(print("1"))
else :
exit(print("No solution"))
if b/a < 0 and k%2 == 0 :
exit(print("No solution"))
t = pow(b/a , 1/k)
t = complex(t)
t1 = t.real
t2 = t.i... | 0 |
200 | B | Drinks | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Little Vasya loves orange juice very much. That's why any food and drink in his kitchen necessarily contains orange juice. There are *n* drinks in his fridge, the volume fraction of orange juice in the *i*-th drink equals *p**i* percent.
One day Vasya decided to make himself an orange cocktail. He took equal proportio... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of orange-containing drinks in Vasya's fridge. The second line contains *n* integers *p**i* (0<=≤<=*p**i*<=≤<=100) — the volume fraction of orange juice in the *i*-th drink, in percent. The numbers are separated by a space. | Print the volume fraction in percent of orange juice in Vasya's cocktail. The answer will be considered correct if the absolute or relative error does not exceed 10<=<=-<=4. | [
"3\n50 50 100\n",
"4\n0 25 50 75\n"
] | [
"66.666666666667\n",
"37.500000000000\n"
] | Note to the first sample: let's assume that Vasya takes *x* milliliters of each drink from the fridge. Then the volume of pure juice in the cocktail will equal <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c1fac6e64d3a8ee6a5ac138cbe51e60039b22473.png" style="max-width: 100.0%;max-height: ... | 500 | [
{
"input": "3\n50 50 100",
"output": "66.666666666667"
},
{
"input": "4\n0 25 50 75",
"output": "37.500000000000"
},
{
"input": "3\n0 1 8",
"output": "3.000000000000"
},
{
"input": "5\n96 89 93 95 70",
"output": "88.600000000000"
},
{
"input": "7\n62 41 78 4 38 39... | 1,682,262,024 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 31 | 124 | 0 | n=int(input())
p=list(map(int,input().split()))
i=0
sum=0
while i<n:
sum=sum+p[i]
i=i+1
b=(sum/(n*100))*100
b=round(b,5)
print(b)
| Title: Drinks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Vasya loves orange juice very much. That's why any food and drink in his kitchen necessarily contains orange juice. There are *n* drinks in his fridge, the volume fraction of orange juice in the *i*-th drink equals *p**i*... | ```python
n=int(input())
p=list(map(int,input().split()))
i=0
sum=0
while i<n:
sum=sum+p[i]
i=i+1
b=(sum/(n*100))*100
b=round(b,5)
print(b)
``` | 3 | |
723 | A | The New Year: Meeting Friends | PROGRAMMING | 800 | [
"implementation",
"math",
"sortings"
] | null | null | There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they... | The first line of the input contains three distinct integers *x*1, *x*2 and *x*3 (1<=≤<=*x*1,<=*x*2,<=*x*3<=≤<=100) — the coordinates of the houses of the first, the second and the third friends respectively. | Print one integer — the minimum total distance the friends need to travel in order to meet together. | [
"7 1 4\n",
"30 20 10\n"
] | [
"6\n",
"20\n"
] | In the first sample, friends should meet at the point 4. Thus, the first friend has to travel the distance of 3 (from the point 7 to the point 4), the second friend also has to travel the distance of 3 (from the point 1 to the point 4), while the third friend should not go anywhere because he lives at the point 4. | 500 | [
{
"input": "7 1 4",
"output": "6"
},
{
"input": "30 20 10",
"output": "20"
},
{
"input": "1 4 100",
"output": "99"
},
{
"input": "100 1 91",
"output": "99"
},
{
"input": "1 45 100",
"output": "99"
},
{
"input": "1 2 3",
"output": "2"
},
{
"... | 1,683,502,693 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | x = input().split()
mid, max_x, min_x = 0, int(max(x)), int(min(x))
for i in x:
if i < max(x) and i < min(x):
mid = int(i)
print((max_x-mid)+(mid-min_x)) | Title: The New Year: Meeting Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They ... | ```python
x = input().split()
mid, max_x, min_x = 0, int(max(x)), int(min(x))
for i in x:
if i < max(x) and i < min(x):
mid = int(i)
print((max_x-mid)+(mid-min_x))
``` | 0 | |
353 | A | Domino | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Valera has got *n* domino pieces in a row. Each piece consists of two halves — the upper one and the lower one. Each of the halves contains a number from 1 to 6. Valera loves even integers very much, so he wants the sum of the numbers on the upper halves and the sum of the numbers on the lower halves to be even.
To do... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100), denoting the number of dominoes Valera has. Next *n* lines contain two space-separated integers *x**i*,<=*y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=6). Number *x**i* is initially written on the upper half of the *i*-th domino, *y**i* is initially written on the lower half... | Print a single number — the minimum required number of seconds. If Valera can't do the task in any time, print <=-<=1. | [
"2\n4 2\n6 4\n",
"1\n2 3\n",
"3\n1 4\n2 3\n4 4\n"
] | [
"0\n",
"-1\n",
"1\n"
] | In the first test case the sum of the numbers on the upper halves equals 10 and the sum of the numbers on the lower halves equals 6. Both numbers are even, so Valera doesn't required to do anything.
In the second sample Valera has only one piece of domino. It is written 3 on the one of its halves, therefore one of the... | 500 | [
{
"input": "2\n4 2\n6 4",
"output": "0"
},
{
"input": "1\n2 3",
"output": "-1"
},
{
"input": "3\n1 4\n2 3\n4 4",
"output": "1"
},
{
"input": "5\n5 4\n5 4\n1 5\n5 5\n3 3",
"output": "1"
},
{
"input": "20\n1 3\n5 2\n5 2\n2 6\n2 4\n1 1\n1 3\n1 4\n2 6\n4 2\n5 6\n2 2\n... | 1,554,100,677 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 186 | 0 | A=[]
B=[]
for i in range(0,int(input())):
a,b=list(map(int,input().split()))
A.append(a)
B.append(b)
sumA=sum(A)
sumB=sum(B)
if sumA%2==0 and sumB%2==0:
print(0)
elif sumA%2==1 and sumB%2==1:
print(1)
else:
c=0
if sumA%2==0:
for j in A:
if j... | Title: Domino
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera has got *n* domino pieces in a row. Each piece consists of two halves — the upper one and the lower one. Each of the halves contains a number from 1 to 6. Valera loves even integers very much, so he wants the sum of the n... | ```python
A=[]
B=[]
for i in range(0,int(input())):
a,b=list(map(int,input().split()))
A.append(a)
B.append(b)
sumA=sum(A)
sumB=sum(B)
if sumA%2==0 and sumB%2==0:
print(0)
elif sumA%2==1 and sumB%2==1:
print(1)
else:
c=0
if sumA%2==0:
for j in A:
... | 0 | |
650 | A | Watchmen | PROGRAMMING | 1,400 | [
"data structures",
"geometry",
"math"
] | null | null | Watchmen are in a danger and Doctor Manhattan together with his friend Daniel Dreiberg should warn them as soon as possible. There are *n* watchmen on a plane, the *i*-th watchman is located at point (*x**i*,<=*y**i*).
They need to arrange a plan, but there are some difficulties on their way. As you know, Doctor Manha... | The first line of the input contains the single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of watchmen.
Each of the following *n* lines contains two integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109).
Some positions may coincide. | Print the number of pairs of watchmen such that the distance between them calculated by Doctor Manhattan is equal to the distance calculated by Daniel. | [
"3\n1 1\n7 5\n1 5\n",
"6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1\n"
] | [
"2\n",
"11\n"
] | In the first sample, the distance between watchman 1 and watchman 2 is equal to |1 - 7| + |1 - 5| = 10 for Doctor Manhattan and <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/bcb5b7064b5f02088da0fdcf677e6fda495dd0df.png" style="max-width: 100.0%;max-height: 100.0%;"/> for Daniel. For pairs... | 500 | [
{
"input": "3\n1 1\n7 5\n1 5",
"output": "2"
},
{
"input": "6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1",
"output": "11"
},
{
"input": "10\n46 -55\n46 45\n46 45\n83 -55\n46 45\n83 -55\n46 45\n83 45\n83 45\n46 -55",
"output": "33"
},
{
"input": "1\n-5 -90",
"output": "0"
},
{
... | 1,505,738,700 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 1,200 | 30,515,200 | n = int(input())
X_axis = {}
Y_axis = {}
XY_axis = {}
for i in range(n):
a,b = [ int(x) for x in input().split()]
pair = (a,b)
X_axis[a] = X_axis.get(a,0) +1
Y_axis[b] = Y_axis.get(b,0) +1
XY_axis[pair] = XY_axis.get(pair,0) + 1
sum = 0
for i in X_axis:
var = X_axis[i]
if ... | Title: Watchmen
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Watchmen are in a danger and Doctor Manhattan together with his friend Daniel Dreiberg should warn them as soon as possible. There are *n* watchmen on a plane, the *i*-th watchman is located at point (*x**i*,<=*y**i*).
They n... | ```python
n = int(input())
X_axis = {}
Y_axis = {}
XY_axis = {}
for i in range(n):
a,b = [ int(x) for x in input().split()]
pair = (a,b)
X_axis[a] = X_axis.get(a,0) +1
Y_axis[b] = Y_axis.get(b,0) +1
XY_axis[pair] = XY_axis.get(pair,0) + 1
sum = 0
for i in X_axis:
var = X_axis[i... | 3 | |
37 | A | Towers | PROGRAMMING | 1,000 | [
"sortings"
] | A. Towers | 2 | 256 | Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct the minimal number of towers from the bars. Help Vasya to use the bars in the best way ... | The first line contains an integer *N* (1<=≤<=*N*<=≤<=1000) — the number of bars at Vasya’s disposal. The second line contains *N* space-separated integers *l**i* — the lengths of the bars. All the lengths are natural numbers not exceeding 1000. | In one line output two numbers — the height of the largest tower and their total number. Remember that Vasya should use all the bars. | [
"3\n1 2 3\n",
"4\n6 5 6 7\n"
] | [
"1 3\n",
"2 3\n"
] | none | 500 | [
{
"input": "3\n1 2 3",
"output": "1 3"
},
{
"input": "4\n6 5 6 7",
"output": "2 3"
},
{
"input": "4\n3 2 1 1",
"output": "2 3"
},
{
"input": "4\n1 2 3 3",
"output": "2 3"
},
{
"input": "3\n20 22 36",
"output": "1 3"
},
{
"input": "25\n47 30 94 41 45 20... | 1,649,644,269 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 61 | 186 | 512,000 | #\\\
n=int(input())
a=[int(i) for i in input().split()]
r1=len(list(set(a)))
r2=0
for i in range(len(a)):
if a.count(a[i])>r2:
r2=a.count(a[i])
print(r2,r1)
#\\\
| Title: Towers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct... | ```python
#\\\
n=int(input())
a=[int(i) for i in input().split()]
r1=len(list(set(a)))
r2=0
for i in range(len(a)):
if a.count(a[i])>r2:
r2=a.count(a[i])
print(r2,r1)
#\\\
``` | 3.952546 |
556 | A | Case of the Zeros and Ones | PROGRAMMING | 900 | [
"greedy"
] | null | null | Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, an... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=2·105), the length of the string that Andreid has.
The second line contains the string of length *n* consisting only from zeros and ones. | Output the minimum length of the string that may remain after applying the described operations several times. | [
"4\n1100\n",
"5\n01010\n",
"8\n11101111\n"
] | [
"0\n",
"1\n",
"6\n"
] | In the first sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/10df55364c21c6e8d5da31b6ab6f6294c4fc26b3.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample test it is possible to change the string like... | 250 | [
{
"input": "4\n1100",
"output": "0"
},
{
"input": "5\n01010",
"output": "1"
},
{
"input": "8\n11101111",
"output": "6"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "2"
},
{
"input"... | 1,668,013,140 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 11 | 1,000 | 2,764,800 | n = int(input())
if not 1 <= n <= 2 * 10**5:
quit()
st = input()
for i in range(n):
if st[i] != '0' and st[i] != '1' or len(st) != n:
quit()
st_list = [st[i] for i in range(n)]
for i in range(n-1):
for j in range(len(st_list)-1):
try:
if st_list[j] != st_list... | Title: Case of the Zeros and Ones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Cons... | ```python
n = int(input())
if not 1 <= n <= 2 * 10**5:
quit()
st = input()
for i in range(n):
if st[i] != '0' and st[i] != '1' or len(st) != n:
quit()
st_list = [st[i] for i in range(n)]
for i in range(n-1):
for j in range(len(st_list)-1):
try:
if st_list[j] ... | 0 | |
699 | A | Launch of Collider | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There will be a launch of a new, powerful and unusual collider very soon, which located along a straight line. *n* particles will be launched inside it. All of them are located in a straight line and there can not be two or more particles located in the same point. The coordinates of the particles coincide with the dis... | The first line contains the positive integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of particles.
The second line contains *n* symbols "L" and "R". If the *i*-th symbol equals "L", then the *i*-th particle will move to the left, otherwise the *i*-th symbol equals "R" and the *i*-th particle will move to the right.... | In the first line print the only integer — the first moment (in microseconds) when two particles are at the same point and there will be an explosion.
Print the only integer -1, if the collision of particles doesn't happen. | [
"4\nRLRL\n2 4 6 10\n",
"3\nLLR\n40 50 60\n"
] | [
"1\n",
"-1\n"
] | In the first sample case the first explosion will happen in 1 microsecond because the particles number 1 and 2 will simultaneously be at the same point with the coordinate 3.
In the second sample case there will be no explosion because there are no particles which will simultaneously be at the same point. | 500 | [
{
"input": "4\nRLRL\n2 4 6 10",
"output": "1"
},
{
"input": "3\nLLR\n40 50 60",
"output": "-1"
},
{
"input": "4\nRLLR\n46 230 264 470",
"output": "92"
},
{
"input": "6\nLLRLLL\n446 492 650 844 930 970",
"output": "97"
},
{
"input": "8\nRRLLLLLL\n338 478 512 574 59... | 1,666,546,584 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 38 | 171 | 15,564,800 | n = int(input())
moves = input()
positions = [int(x) for x in input().split()]
mini = 1e10
for i,(a, b) in enumerate(zip(positions[:-1], positions[1:])):
if moves[i] == "R" and moves[i + 1] == "L" and (k := (b - a)) % 2 == 0:
if k // 2 < mini:
mini = k // 2
if mini < 1e10:
print(mini)
els... | Title: Launch of Collider
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There will be a launch of a new, powerful and unusual collider very soon, which located along a straight line. *n* particles will be launched inside it. All of them are located in a straight line and there can not be... | ```python
n = int(input())
moves = input()
positions = [int(x) for x in input().split()]
mini = 1e10
for i,(a, b) in enumerate(zip(positions[:-1], positions[1:])):
if moves[i] == "R" and moves[i + 1] == "L" and (k := (b - a)) % 2 == 0:
if k // 2 < mini:
mini = k // 2
if mini < 1e10:
print... | -1 | |
899 | C | Dividing the numbers | PROGRAMMING | 1,300 | [
"constructive algorithms",
"graphs",
"math"
] | null | null | Petya has *n* integers: 1,<=2,<=3,<=...,<=*n*. He wants to split these integers in two non-empty groups in such a way that the absolute difference of sums of integers in each group is as small as possible.
Help Petya to split the integers. Each of *n* integers should be exactly in one group. | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=60<=000) — the number of integers Petya has. | Print the smallest possible absolute difference in the first line.
In the second line print the size of the first group, followed by the integers in that group. You can print these integers in arbitrary order. If there are multiple answers, print any of them. | [
"4\n",
"2\n"
] | [
"0\n2 1 4 \n",
"1\n1 1 \n"
] | In the first example you have to put integers 1 and 4 in the first group, and 2 and 3 in the second. This way the sum in each group is 5, and the absolute difference is 0.
In the second example there are only two integers, and since both groups should be non-empty, you have to put one integer in the first group and on... | 1,500 | [
{
"input": "4",
"output": "0\n2 1 4 "
},
{
"input": "2",
"output": "1\n1 1 "
},
{
"input": "3",
"output": "0\n1\n3 "
},
{
"input": "5",
"output": "1\n3\n1 2 5 "
},
{
"input": "59998",
"output": "1\n29999 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 4... | 1,573,764,183 | 2,147,483,647 | Python 3 | OK | TESTS | 60 | 156 | 921,600 | n = int(input())
sum = (n * (n+1))//2
print (sum & 1)
sum = sum // 2
ans =[]
len =0
while n > 0 :
if sum >= n :
sum-=n
ans.append(n)
len+=1
n-=1
print (len , end = ' ')
for i in range(len):
print (ans[i] , end = ' ')
| Title: Dividing the numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya has *n* integers: 1,<=2,<=3,<=...,<=*n*. He wants to split these integers in two non-empty groups in such a way that the absolute difference of sums of integers in each group is as small as possible.
Help P... | ```python
n = int(input())
sum = (n * (n+1))//2
print (sum & 1)
sum = sum // 2
ans =[]
len =0
while n > 0 :
if sum >= n :
sum-=n
ans.append(n)
len+=1
n-=1
print (len , end = ' ')
for i in range(len):
print (ans[i] , end = ' ')
``` | 3 | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,570,107,060 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 187 | 2,355,200 | def heidi(s,l):
c=0
for i in range(len(s)):
if s[i]==l[c] and c<len(l):
c+=1
elif c==len(l):
return 'YES'
break
if c==len(l):
return 'YES'
else:
return 'NO'
s= input()
l='heidi'
if len(s)<=5:
print('NO')
else:
... | Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
def heidi(s,l):
c=0
for i in range(len(s)):
if s[i]==l[c] and c<len(l):
c+=1
elif c==len(l):
return 'YES'
break
if c==len(l):
return 'YES'
else:
return 'NO'
s= input()
l='heidi'
if len(s)<=5:
print('NO')... | -1 | |
814 | C | An impassioned circulation of affection | PROGRAMMING | 1,600 | [
"brute force",
"dp",
"strings",
"two pointers"
] | null | null | Nadeko's birthday is approaching! As she decorated the room for the party, a long garland of Dianthus-shaped paper pieces was placed on a prominent part of the wall. Brother Koyomi will like it!
Still unsatisfied with the garland, Nadeko decided to polish it again. The garland has *n* pieces numbered from 1 to *n* fro... | The first line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=1<=500) — the length of the garland.
The second line contains *n* lowercase English letters *s*1*s*2... *s**n* as a string — the initial colours of paper pieces on the garland.
The third line contains a positive integer *q* (1<=≤<=*q*<=≤<=200<=000... | Output *q* lines: for each work plan, output one line containing an integer — the largest Koyomity achievable after repainting the garland according to it. | [
"6\nkoyomi\n3\n1 o\n4 o\n4 m\n",
"15\nyamatonadeshiko\n10\n1 a\n2 a\n3 a\n4 a\n5 a\n1 b\n2 b\n3 b\n4 b\n5 b\n",
"10\naaaaaaaaaa\n2\n10 b\n10 z\n"
] | [
"3\n6\n5\n",
"3\n4\n5\n7\n8\n1\n2\n3\n4\n5\n",
"10\n10\n"
] | In the first sample, there are three plans:
- In the first plan, at most 1 piece can be repainted. Repainting the "y" piece to become "o" results in "kooomi", whose Koyomity of 3 is the best achievable; - In the second plan, at most 4 pieces can be repainted, and "oooooo" results in a Koyomity of 6; - In the third... | 1,750 | [
{
"input": "6\nkoyomi\n3\n1 o\n4 o\n4 m",
"output": "3\n6\n5"
},
{
"input": "15\nyamatonadeshiko\n10\n1 a\n2 a\n3 a\n4 a\n5 a\n1 b\n2 b\n3 b\n4 b\n5 b",
"output": "3\n4\n5\n7\n8\n1\n2\n3\n4\n5"
},
{
"input": "10\naaaaaaaaaa\n2\n10 b\n10 z",
"output": "10\n10"
},
{
"input": "1... | 1,565,681,398 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 | n = int(input())
s = input()
q = int(input())
for i in range(q):
v = list(input())
l = int(v[0])
z = s.count(v[2])
print(z + l) | Title: An impassioned circulation of affection
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nadeko's birthday is approaching! As she decorated the room for the party, a long garland of Dianthus-shaped paper pieces was placed on a prominent part of the wall. Brother Koyomi will like it!
... | ```python
n = int(input())
s = input()
q = int(input())
for i in range(q):
v = list(input())
l = int(v[0])
z = s.count(v[2])
print(z + l)
``` | 0 | |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,676,155,682 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | quantidade_pulos, alvo = map(int, input().split())
pulos = list(map(int, input().split())) ## SEM FOR...
posicao_atual = 0
while posicao_atual < alvo:
posicao_atual += pulos[posicao_atual]
if posicao_atual == alvo - 1:
print("YES")
else:
print("NO")
| Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
quantidade_pulos, alvo = map(int, input().split())
pulos = list(map(int, input().split())) ## SEM FOR...
posicao_atual = 0
while posicao_atual < alvo:
posicao_atual += pulos[posicao_atual]
if posicao_atual == alvo - 1:
print("YES")
else:
print("NO")
``` | 0 | |
911 | B | Two Cakes | PROGRAMMING | 1,200 | [
"binary search",
"brute force",
"implementation"
] | null | null | It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into *a* pieces, and the second one — into *b* pieces.
Ivan knows that there will be *n* people at the celebration (including himself), so Ivan has set ... | The first line contains three integers *n*, *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100, 2<=≤<=*n*<=≤<=*a*<=+<=*b*) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively. | Print the maximum possible number *x* such that Ivan can distribute the cake in such a way that each plate will contain at least *x* pieces of cake. | [
"5 2 3\n",
"4 7 10\n"
] | [
"1\n",
"3\n"
] | In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3. | 0 | [
{
"input": "5 2 3",
"output": "1"
},
{
"input": "4 7 10",
"output": "3"
},
{
"input": "100 100 100",
"output": "2"
},
{
"input": "10 100 3",
"output": "3"
},
{
"input": "2 9 29",
"output": "9"
},
{
"input": "4 6 10",
"output": "3"
},
{
"inp... | 1,599,154,067 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 155 | 409,600 | from math import *
from bisect import *
from collections import Counter,defaultdict,deque
from sys import stdin, stdout
input = stdin.readline
I=lambda:int(input())
M =lambda:map(int,input().split())
LI=lambda:list(map(int,input().split()))
for _ in range(1):
n,a,b=M()
ans=-1
for i in range(1,max(a,b))... | Title: Two Cakes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into *a* pieces, and the second one — into *b* pieces.
Iv... | ```python
from math import *
from bisect import *
from collections import Counter,defaultdict,deque
from sys import stdin, stdout
input = stdin.readline
I=lambda:int(input())
M =lambda:map(int,input().split())
LI=lambda:list(map(int,input().split()))
for _ in range(1):
n,a,b=M()
ans=-1
for i in range(1... | 0 | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,666,033,903 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 46 | 0 | mb=int(input())
kcp=list(map(int,input().split()))
while(0 in kcp):
kcp.remove(0)
kcp=set(kcp)
print(len(kcp)) | Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
mb=int(input())
kcp=list(map(int,input().split()))
while(0 in kcp):
kcp.remove(0)
kcp=set(kcp)
print(len(kcp))
``` | 3 | |
873 | B | Balanced Substring | PROGRAMMING | 1,500 | [
"dp",
"implementation"
] | null | null | You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called balanced if the number of zeroes (0) equals to the number of ones in this substring.
You have to deter... | The first line contains *n* (1<=≤<=*n*<=≤<=100000) — the number of characters in *s*.
The second line contains a string *s* consisting of exactly *n* characters. Only characters 0 and 1 can appear in *s*. | If there is no non-empty balanced substring in *s*, print 0. Otherwise, print the length of the longest balanced substring. | [
"8\n11010111\n",
"3\n111\n"
] | [
"4\n",
"0\n"
] | In the first example you can choose the substring [3, 6]. It is balanced, and its length is 4. Choosing the substring [2, 5] is also possible.
In the second example it's impossible to find a non-empty balanced substring. | 0 | [
{
"input": "8\n11010111",
"output": "4"
},
{
"input": "3\n111",
"output": "0"
},
{
"input": "11\n00001000100",
"output": "2"
},
{
"input": "10\n0100000000",
"output": "2"
},
{
"input": "13\n0001000011010",
"output": "6"
},
{
"input": "14\n0000010010101... | 1,507,835,233 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 15 | 1,000 | 0 | N = int(input())
S = input()
a = 0
for i in range(N - 1):
for j in range(i+2,N +1):
if S[i:j].count('1') == S[i:j].count('0'):
if (j-i)>=a:
a = j - i
print(a)
| Title: Balanced Substring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called... | ```python
N = int(input())
S = input()
a = 0
for i in range(N - 1):
for j in range(i+2,N +1):
if S[i:j].count('1') == S[i:j].count('0'):
if (j-i)>=a:
a = j - i
print(a)
``` | 0 | |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,674,144,964 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 46 | 0 | n_t=input()
n_t_list=n_t.split(' ')
n=int(n_t_list[0])
t=int(n_t_list[1])
print(int(str(t)*n)) | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
n_t=input()
n_t_list=n_t.split(' ')
n=int(n_t_list[0])
t=int(n_t_list[1])
print(int(str(t)*n))
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Stepan has the newest electronic device with a display. Different digits can be shown on it. Each digit is shown on a seven-section indicator like it is shown on the picture below.
So, for example, to show the digit 3 on the display, 5 sections must be highlighted; and for the digit 6, 6 sections must be highlighted. ... | The first line contains the integer *n* (2<=≤<=*n*<=≤<=100<=000) — the maximum number of sections which can be highlighted on the display. | Print the maximum integer which can be shown on the display of Stepan's newest device. | [
"2\n",
"3\n"
] | [
"1\n",
"7\n"
] | none | 0 | [
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "7"
},
{
"input": "4",
"output": "11"
},
{
"input": "5",
"output": "71"
},
{
"input": "6",
"output": "111"
},
{
"input": "85651",
"output": "711111111111111111111111111111111111111111111111... | 1,495,741,795 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | a=input()
string=[]
if a%2:
string.append('7')
a=a-3
for i in range (a / 2):
string.append('1')
print(''.join(string)) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Stepan has the newest electronic device with a display. Different digits can be shown on it. Each digit is shown on a seven-section indicator like it is shown on the picture below.
So, for example, to show the digit 3 on the disp... | ```python
a=input()
string=[]
if a%2:
string.append('7')
a=a-3
for i in range (a / 2):
string.append('1')
print(''.join(string))
``` | -1 | |
535 | B | Tavas and SaDDas | PROGRAMMING | 1,100 | [
"bitmasks",
"brute force",
"combinatorics",
"implementation"
] | null | null | Once again Tavas started eating coffee mix without water! Keione told him that it smells awful, but he didn't stop doing that. That's why Keione told his smart friend, SaDDas to punish him! SaDDas took Tavas' headphones and told him: "If you solve the following problem, I'll return it to you."
The problem is:
You ar... | The first and only line of input contains a lucky number *n* (1<=≤<=*n*<=≤<=109). | Print the index of *n* among all lucky numbers. | [
"4\n",
"7\n",
"77\n"
] | [
"1\n",
"2\n",
"6\n"
] | none | 1,000 | [
{
"input": "4",
"output": "1"
},
{
"input": "7",
"output": "2"
},
{
"input": "77",
"output": "6"
},
{
"input": "4",
"output": "1"
},
{
"input": "474744",
"output": "83"
},
{
"input": "777774",
"output": "125"
},
{
"input": "447",
"outpu... | 1,431,995,099 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 109 | 307,200 | a=['4', '7']
x=[]
for i in a:
x.append(int(i))
for i in a:
for j in a:
x.append(int(i+j))
for i in a:
for j in a:
for k in a:
x.append(int(i+j+k))
for i in a:
for j in a:
for k in a:
for l in a:
x.append(int(i+j+k+l))... | Title: Tavas and SaDDas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once again Tavas started eating coffee mix without water! Keione told him that it smells awful, but he didn't stop doing that. That's why Keione told his smart friend, SaDDas to punish him! SaDDas took Tavas' headphone... | ```python
a=['4', '7']
x=[]
for i in a:
x.append(int(i))
for i in a:
for j in a:
x.append(int(i+j))
for i in a:
for j in a:
for k in a:
x.append(int(i+j+k))
for i in a:
for j in a:
for k in a:
for l in a:
x.append(int... | 3 | |
513 | B1 | Permutations | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | You are given a permutation *p* of numbers 1,<=2,<=...,<=*n*. Let's define *f*(*p*) as the following sum:
Find the lexicographically *m*-th permutation of length *n* in the set of permutations having the maximum possible value of *f*(*p*). | The single line of input contains two integers *n* and *m* (1<=≤<=*m*<=≤<=*cnt**n*), where *cnt**n* is the number of permutations of length *n* with maximum possible value of *f*(*p*).
The problem consists of two subproblems. The subproblems have different constraints on the input. You will get some score for the corr... | Output *n* number forming the required permutation. | [
"2 2\n",
"3 2\n"
] | [
"2 1 \n",
"1 3 2 \n"
] | In the first example, both permutations of numbers {1, 2} yield maximum possible *f*(*p*) which is equal to 4. Among them, (2, 1) comes second in lexicographical order. | 3 | [
{
"input": "2 2",
"output": "2 1 "
},
{
"input": "3 2",
"output": "1 3 2 "
},
{
"input": "1 1",
"output": "1 "
},
{
"input": "3 1",
"output": "1 2 3 "
},
{
"input": "3 3",
"output": "2 3 1 "
},
{
"input": "3 4",
"output": "3 2 1 "
},
{
"inp... | 1,423,330,289 | 1,889 | Python 3 | WRONG_ANSWER | TESTS1 | 4 | 46 | 0 | f = [1]
n, k = [int(i) for i in input().split()]
for i in range(1, n + 1):
f.append(f[-1] * i)
def res(n, k, ls):
if len(ls) == 0:
return
z = (k - 1) // f[n - 1]
print(ls[z], end=' ')
res(n - 1, k - z * f[n - 1], ls[:z] + ls[z + 1:])
res(n, k, [i + 1 for i in range(n)])
| Title: Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a permutation *p* of numbers 1,<=2,<=...,<=*n*. Let's define *f*(*p*) as the following sum:
Find the lexicographically *m*-th permutation of length *n* in the set of permutations having the maximum possible ... | ```python
f = [1]
n, k = [int(i) for i in input().split()]
for i in range(1, n + 1):
f.append(f[-1] * i)
def res(n, k, ls):
if len(ls) == 0:
return
z = (k - 1) // f[n - 1]
print(ls[z], end=' ')
res(n - 1, k - z * f[n - 1], ls[:z] + ls[z + 1:])
res(n, k, [i + 1 for i in range(n)])... | 0 |
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