contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,695,206,831 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n = int(input())
def is_composite(num):
if num < 4:
return False
for i in range(2, int(num**0.5) + 1):
if num % i == 0:
return True
return False
x = 4
y = n - x
while is_composite(x) or is_composite(y):
x += 1
y -= 1
print(x, y)
| Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
n = int(input())
def is_composite(num):
if num < 4:
return False
for i in range(2, int(num**0.5) + 1):
if num % i == 0:
return True
return False
x = 4
y = n - x
while is_composite(x) or is_composite(y):
x += 1
y -= 1
print(x, y)
``` | 0 | |
95 | B | Lucky Numbers | PROGRAMMING | 1,800 | [
"dp",
"greedy"
] | B. Lucky Numbers | 2 | 256 | Petya loves lucky numbers. Everybody knows that positive integers are lucky if their decimal representation doesn't contain digits other than 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Lucky number is super lucky if it's decimal representation contains equal amount of digits 4 and 7. Fo... | The only line contains a positive integer *n* (1<=≤<=*n*<=≤<=10100000). This number doesn't have leading zeroes. | Output the least super lucky number that is more than or equal to *n*. | [
"4500\n",
"47\n"
] | [
"4747\n",
"47\n"
] | none | 1,000 | [
{
"input": "4500",
"output": "4747"
},
{
"input": "47",
"output": "47"
},
{
"input": "1",
"output": "47"
},
{
"input": "12",
"output": "47"
},
{
"input": "4587",
"output": "4747"
},
{
"input": "100",
"output": "4477"
},
{
"input": "1007",
... | 1,653,991,102 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 92 | 512,000 | import math
def main_function():
n = [int(u) for u in list(input())]
if len(n) % 2 == 1:
listy = ["4" for i in range(len(n) // 2 + 1)] + ["7" for i in range(len(n) // 2 + 1)]
else:
is_higher = False
finish_as_min = False
found_lower_than_7 = False
half_le... | Title: Lucky Numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that positive integers are lucky if their decimal representation doesn't contain digits other than 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Lucky n... | ```python
import math
def main_function():
n = [int(u) for u in list(input())]
if len(n) % 2 == 1:
listy = ["4" for i in range(len(n) // 2 + 1)] + ["7" for i in range(len(n) // 2 + 1)]
else:
is_higher = False
finish_as_min = False
found_lower_than_7 = False
... | 0 |
385 | B | Bear and Strings | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation",
"math",
"strings"
] | null | null | The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|), that string *x*(*i*,<=*j*)<==<=*s**i**s**i*<=+<=1... *s**j* contains at least one string... | The first line contains a non-empty string *s* (1<=≤<=|*s*|<=≤<=5000). It is guaranteed that the string only consists of lowercase English letters. | Print a single number — the answer to the problem. | [
"bearbtear\n",
"bearaabearc\n"
] | [
"6\n",
"20\n"
] | In the first sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9).
In the second sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (1, 11), (2, 10), (2, 11), (3, 10), (3, 11), (4, 10), (4, 11), (5, 10), (5, 11)... | 1,000 | [
{
"input": "bearbtear",
"output": "6"
},
{
"input": "bearaabearc",
"output": "20"
},
{
"input": "pbearbearhbearzqbearjkterasjhy",
"output": "291"
},
{
"input": "pbearjbearbebearnbabcffbearbearwubearjezpiorrbearbearjbdlbearbearqbearjbearwipmsbearoaftrsebearzsnqb",
"output"... | 1,390,578,597 | 896 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 7 | 1,000 | 307,200 | s = input()
ans = 0
for i in range(len(s)):
for j in range(1, len(s)+1):
if 'bear' in s[i:j]:
ans += len(s)-j+1
break
print(ans)
| Title: Bear and Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j... | ```python
s = input()
ans = 0
for i in range(len(s)):
for j in range(1, len(s)+1):
if 'bear' in s[i:j]:
ans += len(s)-j+1
break
print(ans)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams.
After practice competition, participant number *i* got a score of *a**i*. ... | The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants | Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"1 3 2 1 2 1\n",
"1 1 1 1 1 99\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5.
In the second sample, score of participant number 6 is too high: his team score will be definitely greater. | 0 | [
{
"input": "1 3 2 1 2 1",
"output": "YES"
},
{
"input": "1 1 1 1 1 99",
"output": "NO"
},
{
"input": "1000 1000 1000 1000 1000 1000",
"output": "YES"
},
{
"input": "0 0 0 0 0 0",
"output": "YES"
},
{
"input": "633 609 369 704 573 416",
"output": "NO"
},
{
... | 1,564,244,163 | 2,147,483,647 | PyPy 3 | OK | TESTS | 53 | 218 | 14,848,000 | class CodeforcesTask890ASolution:
def __init__(self):
self.result = ''
self.scores = []
def read_input(self):
self.scores = [int(x) for x in input().split(" ")]
def process_task(self):
result = False
perms = [([5,2,1],[0,4,3]),
([1,3,0],[5,4,2]),
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exac... | ```python
class CodeforcesTask890ASolution:
def __init__(self):
self.result = ''
self.scores = []
def read_input(self):
self.scores = [int(x) for x in input().split(" ")]
def process_task(self):
result = False
perms = [([5,2,1],[0,4,3]),
([1,3,0],... | 3 | |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,634,627,767 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 0 | import math
def lowerdivisors(n):
int_sqrt_n = int(math.sqrt(n))
ld = []
for i in range(1, int_sqrt_n + 1):
if n%i == 0:
ld.append(i)
return ld
def kthdivisor(n, k):
ld = lowerdivisors(n)
if k > (2 * len(ld)):
return -1
if k <= len(ld):
... | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
import math
def lowerdivisors(n):
int_sqrt_n = int(math.sqrt(n))
ld = []
for i in range(1, int_sqrt_n + 1):
if n%i == 0:
ld.append(i)
return ld
def kthdivisor(n, k):
ld = lowerdivisors(n)
if k > (2 * len(ld)):
return -1
if k <= len(ld... | 0 | |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers ex... | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at... | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 ... | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,694,975,278 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | import sys
# sys.stdin = open("input.txt", "r")
# sys.stdout = open("output.txt", "w")
# sys.stderr = open("error.txt", "w")
# # your remaining code
t = int(input())
mn = 0
isum = 0
for i in range(t) :
a , b = map(int,input().split())
isum -= a
isum += b
if isum > mn :
mn = isum
print(mn)
... | Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it ... | ```python
import sys
# sys.stdin = open("input.txt", "r")
# sys.stdout = open("output.txt", "w")
# sys.stderr = open("error.txt", "w")
# # your remaining code
t = int(input())
mn = 0
isum = 0
for i in range(t) :
a , b = map(int,input().split())
isum -= a
isum += b
if isum > mn :
mn = isum
p... | 3 | |
793 | A | Oleg and shares | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Oleg the bank client checks share prices every day. There are *n* share prices he is interested in. Today he observed that each second exactly one of these prices decreases by *k* rubles (note that each second exactly one price changes, but at different seconds different prices can change). Prices can become negative. ... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*k*<=≤<=109) — the number of share prices, and the amount of rubles some price decreases each second.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the initial prices. | Print the only line containing the minimum number of seconds needed for prices to become equal, of «-1» if it is impossible. | [
"3 3\n12 9 15\n",
"2 2\n10 9\n",
"4 1\n1 1000000000 1000000000 1000000000\n"
] | [
"3",
"-1",
"2999999997"
] | Consider the first example.
Suppose the third price decreases in the first second and become equal 12 rubles, then the first price decreases and becomes equal 9 rubles, and in the third second the third price decreases again and becomes equal 9 rubles. In this case all prices become equal 9 rubles in 3 seconds.
Ther... | 500 | [
{
"input": "3 3\n12 9 15",
"output": "3"
},
{
"input": "2 2\n10 9",
"output": "-1"
},
{
"input": "4 1\n1 1000000000 1000000000 1000000000",
"output": "2999999997"
},
{
"input": "1 11\n123",
"output": "0"
},
{
"input": "20 6\n38 86 86 50 98 62 32 2 14 62 98 50 2 50... | 1,639,895,317 | 2,147,483,647 | PyPy 3 | OK | TESTS | 88 | 171 | 10,956,800 | n,k=list(map(int,input().split()))
a=list(map(int,input().split()))
a.sort()
x=min(a)
ans=0
c=True
for i in a:
if (i-x)%k!=0:
c=False
break
else:
ans=ans+(i-x)//k
if c==False:
print(-1)
else:
print(ans) | Title: Oleg and shares
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Oleg the bank client checks share prices every day. There are *n* share prices he is interested in. Today he observed that each second exactly one of these prices decreases by *k* rubles (note that each second exactly o... | ```python
n,k=list(map(int,input().split()))
a=list(map(int,input().split()))
a.sort()
x=min(a)
ans=0
c=True
for i in a:
if (i-x)%k!=0:
c=False
break
else:
ans=ans+(i-x)//k
if c==False:
print(-1)
else:
print(ans)
``` | 3 | |
854 | A | Fraction | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"math"
] | null | null | Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive co... | In the only line of input there is an integer *n* (3<=≤<=*n*<=≤<=1000), the sum of numerator and denominator of the fraction. | Output two space-separated positive integers *a* and *b*, numerator and denominator of the maximum possible proper irreducible fraction satisfying the given sum. | [
"3\n",
"4\n",
"12\n"
] | [
"1 2\n",
"1 3\n",
"5 7\n"
] | none | 500 | [
{
"input": "3",
"output": "1 2"
},
{
"input": "4",
"output": "1 3"
},
{
"input": "12",
"output": "5 7"
},
{
"input": "34",
"output": "15 19"
},
{
"input": "13",
"output": "6 7"
},
{
"input": "11",
"output": "5 6"
},
{
"input": "24",
"ou... | 1,601,352,458 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 20 | 109 | 307,200 | n = int(input())
lista = [i for i in range((n+1)//2, 0, -1)if i < n-i]
a,b = 0,0
def div(a,b):
for i in range(2, a):
if a % i == 0 and b % i == 0:
return True
return False
for i in range(len(lista)):
a, b = lista[i], n-lista[i]
if div(a,b) == False:
break
pr... | Title: Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is cal... | ```python
n = int(input())
lista = [i for i in range((n+1)//2, 0, -1)if i < n-i]
a,b = 0,0
def div(a,b):
for i in range(2, a):
if a % i == 0 and b % i == 0:
return True
return False
for i in range(len(lista)):
a, b = lista[i], n-lista[i]
if div(a,b) == False:
b... | 0 | |
435 | A | Queue on Bus Stop | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | It's that time of the year when the Russians flood their countryside summer cottages (dachas) and the bus stop has a lot of people. People rarely go to the dacha on their own, it's usually a group, so the people stand in queue by groups.
The bus stop queue has *n* groups of people. The *i*-th group from the beginning ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). The next line contains *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*m*). | Print a single integer — the number of buses that is needed to transport all *n* groups to the dacha countryside. | [
"4 3\n2 3 2 1\n",
"3 4\n1 2 1\n"
] | [
"3\n",
"1\n"
] | none | 500 | [
{
"input": "4 3\n2 3 2 1",
"output": "3"
},
{
"input": "3 4\n1 2 1",
"output": "1"
},
{
"input": "1 5\n4",
"output": "1"
},
{
"input": "5 1\n1 1 1 1 1",
"output": "5"
},
{
"input": "6 4\n1 3 2 3 4 1",
"output": "5"
},
{
"input": "6 8\n6 1 1 1 4 5",
... | 1,612,872,122 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 62 | 0 | n, m = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
c = 1
temp = 0
for i in a:
if temp+i<=m:
temp += i
else:
temp = i
c += 1
print(c)
| Title: Queue on Bus Stop
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's that time of the year when the Russians flood their countryside summer cottages (dachas) and the bus stop has a lot of people. People rarely go to the dacha on their own, it's usually a group, so the people stand... | ```python
n, m = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
c = 1
temp = 0
for i in a:
if temp+i<=m:
temp += i
else:
temp = i
c += 1
print(c)
``` | 3 | |
754 | A | Lesha and array splitting | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"implementation"
] | null | null | One spring day on his way to university Lesha found an array *A*. Lesha likes to split arrays into several parts. This time Lesha decided to split the array *A* into several, possibly one, new arrays so that the sum of elements in each of the new arrays is not zero. One more condition is that if we place the new arrays... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array *A*.
The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=103<=≤<=*a**i*<=≤<=103) — the elements of the array *A*. | If it is not possible to split the array *A* and satisfy all the constraints, print single line containing "NO" (without quotes).
Otherwise in the first line print "YES" (without quotes). In the next line print single integer *k* — the number of new arrays. In each of the next *k* lines print two integers *l**i* and *... | [
"3\n1 2 -3\n",
"8\n9 -12 3 4 -4 -10 7 3\n",
"1\n0\n",
"4\n1 2 3 -5\n"
] | [
"YES\n2\n1 2\n3 3\n",
"YES\n2\n1 2\n3 8\n",
"NO\n",
"YES\n4\n1 1\n2 2\n3 3\n4 4\n"
] | none | 500 | [
{
"input": "3\n1 2 -3",
"output": "YES\n3\n1 1\n2 2\n3 3"
},
{
"input": "8\n9 -12 3 4 -4 -10 7 3",
"output": "YES\n8\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n7 7\n8 8"
},
{
"input": "1\n0",
"output": "NO"
},
{
"input": "4\n1 2 3 -5",
"output": "YES\n4\n1 1\n2 2\n3 3\n4 4"
},
{
... | 1,601,096,776 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 78 | 307,200 | n = int(input())
A = list(map(int,input().split()))
if sum(A)!= 0:
print("YES")
print(1)
print(str(1) + " " + str(len(n)))
else:
i = 0
while (A[i] == 0):
i+=1
if i == n:
print("NO")
else:
print("YES")
print(2)
print(str(1... | Title: Lesha and array splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One spring day on his way to university Lesha found an array *A*. Lesha likes to split arrays into several parts. This time Lesha decided to split the array *A* into several, possibly one, new arrays so that t... | ```python
n = int(input())
A = list(map(int,input().split()))
if sum(A)!= 0:
print("YES")
print(1)
print(str(1) + " " + str(len(n)))
else:
i = 0
while (A[i] == 0):
i+=1
if i == n:
print("NO")
else:
print("YES")
print(2)
p... | 0 | |
16 | B | Burglar and Matches | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | B. Burglar and Matches | 0 | 64 | A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactl... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer. | Output the only number — answer to the problem. | [
"7 3\n5 10\n2 5\n3 6\n",
"3 3\n1 3\n2 2\n3 1\n"
] | [
"62\n",
"7\n"
] | none | 0 | [
{
"input": "7 3\n5 10\n2 5\n3 6",
"output": "62"
},
{
"input": "3 3\n1 3\n2 2\n3 1",
"output": "7"
},
{
"input": "1 1\n1 2",
"output": "2"
},
{
"input": "1 2\n1 9\n1 6",
"output": "9"
},
{
"input": "1 10\n1 1\n1 9\n1 3\n1 9\n1 7\n1 10\n1 4\n1 7\n1 3\n1 1",
"ou... | 1,604,789,872 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 218 | 307,200 | n, m = input().split()
n = int(n)
m = int(m)
dec = {}
lis = []
for i in range(int(m)):
a, b = input().split()
a = int(a)
b = int(b)
pr = (a, b)
lis.append(pr)
lis.sort(key=lambda x: x[1], reverse=True)
max_count = 0
for i in range(len(lis)):
if lis[i][0] <= n:
n = n-lis[i]... | Title: Burglar and Matches
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* mat... | ```python
n, m = input().split()
n = int(n)
m = int(m)
dec = {}
lis = []
for i in range(int(m)):
a, b = input().split()
a = int(a)
b = int(b)
pr = (a, b)
lis.append(pr)
lis.sort(key=lambda x: x[1], reverse=True)
max_count = 0
for i in range(len(lis)):
if lis[i][0] <= n:
n ... | 3 |
148 | A | Insomnia cure | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | «One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entertained herself at best she could. Tonight she imagined that all dragons were here to steal her, and ... | Input data contains integer numbers *k*,<=*l*,<=*m*,<=*n* and *d*, each number in a separate line (1<=≤<=*k*,<=*l*,<=*m*,<=*n*<=≤<=10, 1<=≤<=*d*<=≤<=105). | Output the number of damaged dragons. | [
"1\n2\n3\n4\n12\n",
"2\n3\n4\n5\n24\n"
] | [
"12\n",
"17\n"
] | In the first case every first dragon got punched with a frying pan. Some of the dragons suffered from other reasons as well, but the pan alone would be enough.
In the second case dragons 1, 7, 11, 13, 17, 19 and 23 escaped unharmed. | 1,000 | [
{
"input": "1\n2\n3\n4\n12",
"output": "12"
},
{
"input": "2\n3\n4\n5\n24",
"output": "17"
},
{
"input": "1\n1\n1\n1\n100000",
"output": "100000"
},
{
"input": "10\n9\n8\n7\n6",
"output": "0"
},
{
"input": "8\n4\n4\n3\n65437",
"output": "32718"
},
{
"i... | 1,694,837,550 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | q=int(input())
w=int(input())
e=int(input())
r=int(input())
t=int(input())
y=0
for dragon in range(1,t+1):
if dragon %q == 0 or dragon % w ==0 or dragon % e ==0 or dragon % r == 0:
y+=1
print(y)
| Title: Insomnia cure
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
«One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entert... | ```python
q=int(input())
w=int(input())
e=int(input())
r=int(input())
t=int(input())
y=0
for dragon in range(1,t+1):
if dragon %q == 0 or dragon % w ==0 or dragon % e ==0 or dragon % r == 0:
y+=1
print(y)
``` | 3 | |
78 | A | Haiku | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Haiku | 2 | 256 | Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syll... | The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The *i*-th line contains the *i*-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailin... | Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes). | [
"on codeforces \nbeta round is running\n a rustling of keys \n",
"how many gallons\nof edo s rain did you drink\n cuckoo\n"
] | [
"YES",
"NO"
] | none | 500 | [
{
"input": "on codeforces \nbeta round is running\n a rustling of keys ",
"output": "YES"
},
{
"input": "how many gallons\nof edo s rain did you drink\n cuckoo",
"output": "NO"
},
{
"input": " hatsu shigure\n saru mo komino wo\nhoshige nari",
... | 1,641,724,106 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 124 | 0 | def is_haiku(l1, l2, l3):
vowel = ['a', 'e', 'i', 'o', 'u']
lines = [l1, l2, l3]
vowel_count = [0, 0, 0]
for index in range(len(lines)):
for char in lines[index]:
if char in vowel:
vowel_count[index] += 1
return vowel_count == [5, 7, 5]
print("Y... | Title: Haiku
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase... | ```python
def is_haiku(l1, l2, l3):
vowel = ['a', 'e', 'i', 'o', 'u']
lines = [l1, l2, l3]
vowel_count = [0, 0, 0]
for index in range(len(lines)):
for char in lines[index]:
if char in vowel:
vowel_count[index] += 1
return vowel_count == [5, 7, 5]
... | 3.969 |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,386,609,083 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 124 | 0 | n=int(input())
d=list(map(int,input().split()))
for i in range(len(d)):
d[i]=d[i]%2
print(d.index(int(d.count(1)==1))+1) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
d=list(map(int,input().split()))
for i in range(len(d)):
d[i]=d[i]%2
print(d.index(int(d.count(1)==1))+1)
``` | 3.969 |
75 | C | Modified GCD | PROGRAMMING | 1,600 | [
"binary search",
"number theory"
] | C. Modified GCD | 2 | 256 | Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which both numbers are divisible by.
But your teacher wants to give you a harder task, in this task... | The first line contains two integers *a* and *b*, the two integers as described above (1<=≤<=*a*,<=*b*<=≤<=109). The second line contains one integer *n*, the number of queries (1<=≤<=*n*<=≤<=104). Then *n* lines follow, each line contains one query consisting of two integers, *low* and *high* (1<=≤<=*low*<=≤<=*high*<=... | Print *n* lines. The *i*-th of them should contain the result of the *i*-th query in the input. If there is no common divisor in the given range for any query, you should print -1 as a result for this query. | [
"9 27\n3\n1 5\n10 11\n9 11\n"
] | [
"3\n-1\n9\n"
] | none | 1,500 | [
{
"input": "9 27\n3\n1 5\n10 11\n9 11",
"output": "3\n-1\n9"
},
{
"input": "48 72\n2\n8 29\n29 37",
"output": "24\n-1"
},
{
"input": "90 100\n10\n51 61\n6 72\n1 84\n33 63\n37 69\n18 21\n9 54\n49 90\n14 87\n37 90",
"output": "-1\n10\n10\n-1\n-1\n-1\n10\n-1\n-1\n-1"
},
{
"input... | 1,667,324,683 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 13 | 2,000 | 0 | a,b = list(map(int, input().split(sep = " ")))
n = int(input())
for j in range(n):
l,r = list(map(int, input().split(sep = " ")))
m = -1
for k in range(r,l-1,-1):
if (a%k == 0 and b%k == 0):
m = k
break
print(m) | Title: Modified GCD
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which ... | ```python
a,b = list(map(int, input().split(sep = " ")))
n = int(input())
for j in range(n):
l,r = list(map(int, input().split(sep = " ")))
m = -1
for k in range(r,l-1,-1):
if (a%k == 0 and b%k == 0):
m = k
break
print(m)
``` | 0 |
474 | A | Keyboard | PROGRAMMING | 900 | [
"implementation"
] | null | null | Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately. He accidentally moved both his hands with one position to the left or to the right. That mean... | First line of the input contains one letter describing direction of shifting ('L' or 'R' respectively for left or right).
Second line contains a sequence of characters written by Mole. The size of this sequence will be no more than 100. Sequence contains only symbols that appear on Mole's keyboard. It doesn't contain ... | Print a line that contains the original message. | [
"R\ns;;upimrrfod;pbr\n"
] | [
"allyouneedislove\n"
] | none | 500 | [
{
"input": "R\ns;;upimrrfod;pbr",
"output": "allyouneedislove"
},
{
"input": "R\nwertyuiop;lkjhgfdsxcvbnm,.",
"output": "qwertyuiolkjhgfdsazxcvbnm,"
},
{
"input": "L\nzxcvbnm,kjhgfdsaqwertyuio",
"output": "xcvbnm,.lkjhgfdswertyuiop"
},
{
"input": "R\nbubbuduppudup",
"outp... | 1,678,078,486 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 46 | 0 | letters = [
['q', 'w', 'e', 'r', 't', 'y', 'u', 'i', 'o', 'p'],
['a', 's', 'd', 'f', 'g', 'h', 'j', 'k', 'l', ';'],
['z', 'x', 'c', 'v', 'b', 'n', 'm', ',', '.', '/']
]
d = input()
s = input()
new_s = []
for l in s:
if l in letters[0]:
i = [0, letters[0].index(l)]
elif l in letters[1]:
... | Title: Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately.... | ```python
letters = [
['q', 'w', 'e', 'r', 't', 'y', 'u', 'i', 'o', 'p'],
['a', 's', 'd', 'f', 'g', 'h', 'j', 'k', 'l', ';'],
['z', 'x', 'c', 'v', 'b', 'n', 'm', ',', '.', '/']
]
d = input()
s = input()
new_s = []
for l in s:
if l in letters[0]:
i = [0, letters[0].index(l)]
elif l in lett... | 3 | |
409 | H | A + B Strikes Back | PROGRAMMING | 1,500 | [
"*special",
"brute force",
"constructive algorithms",
"dsu",
"implementation"
] | null | null | A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try? | The input contains two integers *a* and *b* (0<=≤<=*a*,<=*b*<=≤<=103), separated by a single space. | Output the sum of the given integers. | [
"5 14\n",
"381 492\n"
] | [
"19\n",
"873\n"
] | none | 0 | [
{
"input": "5 14",
"output": "19"
},
{
"input": "381 492",
"output": "873"
},
{
"input": "536 298",
"output": "834"
},
{
"input": "143 522",
"output": "665"
},
{
"input": "433 126",
"output": "559"
},
{
"input": "723 350",
"output": "1073"
},
{... | 1,675,420,329 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | # LUOGU_RID: 101338716
a=int(input())
b=int(input())
print(a+b)
print() | Title: A + B Strikes Back
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input ... | ```python
# LUOGU_RID: 101338716
a=int(input())
b=int(input())
print(a+b)
print()
``` | -1 | |
598 | B | Queries on a String | PROGRAMMING | 1,300 | [
"implementation",
"strings"
] | null | null | You are given a string *s* and should process *m* queries. Each query is described by two 1-based indices *l**i*, *r**i* and integer *k**i*. It means that you should cyclically shift the substring *s*[*l**i*... *r**i*] *k**i* times. The queries should be processed one after another in the order they are given.
One ope... | The first line of the input contains the string *s* (1<=≤<=|*s*|<=≤<=10<=000) in its initial state, where |*s*| stands for the length of *s*. It contains only lowercase English letters.
Second line contains a single integer *m* (1<=≤<=*m*<=≤<=300) — the number of queries.
The *i*-th of the next *m* lines contains thr... | Print the resulting string *s* after processing all *m* queries. | [
"abacaba\n2\n3 6 1\n1 4 2\n"
] | [
"baabcaa\n"
] | The sample is described in problem statement. | 0 | [
{
"input": "abacaba\n2\n3 6 1\n1 4 2",
"output": "baabcaa"
},
{
"input": "u\n1\n1 1 1",
"output": "u"
},
{
"input": "p\n5\n1 1 5\n1 1 9\n1 1 10\n1 1 10\n1 1 4",
"output": "p"
},
{
"input": "ssssssssss\n5\n5 7 9\n3 9 3\n2 7 1\n7 7 10\n1 9 6",
"output": "ssssssssss"
},
... | 1,664,254,692 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 31 | 0 | s = list(input())
m = int(input())
while m:
l, r, k = map(int, input().split())
k = k % (r - l)
l = l - 1
s[l : r] = s[l : r][::-1]
s[l : l + k] = s[l : l + k][::-1]
s[l + k : r] = s[l + k : r][::-1]
m = m - 1
print(''.join(s)) | Title: Queries on a String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* and should process *m* queries. Each query is described by two 1-based indices *l**i*, *r**i* and integer *k**i*. It means that you should cyclically shift the substring *s*[*l**i*... *r**... | ```python
s = list(input())
m = int(input())
while m:
l, r, k = map(int, input().split())
k = k % (r - l)
l = l - 1
s[l : r] = s[l : r][::-1]
s[l : l + k] = s[l : l + k][::-1]
s[l + k : r] = s[l + k : r][::-1]
m = m - 1
print(''.join(s))
``` | -1 | |
466 | C | Number of Ways | PROGRAMMING | 1,700 | [
"binary search",
"brute force",
"data structures",
"dp",
"two pointers"
] | null | null | You've got array *a*[1],<=*a*[2],<=...,<=*a*[*n*], consisting of *n* integers. Count the number of ways to split all the elements of the array into three contiguous parts so that the sum of elements in each part is the same.
More formally, you need to find the number of such pairs of indices *i*,<=*j* (2<=≤<=*i*<=≤<=... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5·105), showing how many numbers are in the array. The second line contains *n* integers *a*[1], *a*[2], ..., *a*[*n*] (|*a*[*i*]|<=≤<=<=109) — the elements of array *a*. | Print a single integer — the number of ways to split the array into three parts with the same sum. | [
"5\n1 2 3 0 3\n",
"4\n0 1 -1 0\n",
"2\n4 1\n"
] | [
"2\n",
"1\n",
"0\n"
] | none | 1,500 | [
{
"input": "5\n1 2 3 0 3",
"output": "2"
},
{
"input": "4\n0 1 -1 0",
"output": "1"
},
{
"input": "2\n4 1",
"output": "0"
},
{
"input": "9\n0 0 0 0 0 0 0 0 0",
"output": "28"
},
{
"input": "10\n2 5 -2 2 -3 -2 3 5 -5 -2",
"output": "0"
},
{
"input": "1\... | 1,699,952,299 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n = int(input())
array = list(map(int,input().split()))
total = sum(array)
t = 0
if total%3 != 0:
print(0)
exit()
else:
b = total//3
left = 0
total1 = [0]
for i in range(n):
if total1 != b:
left += 1
total1 += array[left]
else:
... | Title: Number of Ways
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got array *a*[1],<=*a*[2],<=...,<=*a*[*n*], consisting of *n* integers. Count the number of ways to split all the elements of the array into three contiguous parts so that the sum of elements in each part is the s... | ```python
n = int(input())
array = list(map(int,input().split()))
total = sum(array)
t = 0
if total%3 != 0:
print(0)
exit()
else:
b = total//3
left = 0
total1 = [0]
for i in range(n):
if total1 != b:
left += 1
total1 += array[left]
else:
... | -1 | |
616 | A | Comparing Two Long Integers | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can r... | The first line contains a non-negative integer *a*.
The second line contains a non-negative integer *b*.
The numbers *a*,<=*b* may contain leading zeroes. Each of them contains no more than 106 digits. | Print the symbol "<" if *a*<=<<=*b* and the symbol ">" if *a*<=><=*b*. If the numbers are equal print the symbol "=". | [
"9\n10\n",
"11\n10\n",
"00012345\n12345\n",
"0123\n9\n",
"0123\n111\n"
] | [
"<\n",
">\n",
"=\n",
">\n",
">\n"
] | none | 0 | [
{
"input": "9\n10",
"output": "<"
},
{
"input": "11\n10",
"output": ">"
},
{
"input": "00012345\n12345",
"output": "="
},
{
"input": "0123\n9",
"output": ">"
},
{
"input": "0123\n111",
"output": ">"
},
{
"input": "9\n9",
"output": "="
},
{
... | 1,678,344,767 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 46 | 2,764,800 | a,b=map(int,input().split())
if a<b: print("<")
if a==b: print("=")
if a>b: print(">")
| Title: Comparing Two Long Integers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use th... | ```python
a,b=map(int,input().split())
if a<b: print("<")
if a==b: print("=")
if a>b: print(">")
``` | -1 | |
817 | C | Really Big Numbers | PROGRAMMING | 1,600 | [
"binary search",
"brute force",
"dp",
"math"
] | null | null | Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number *x* is really big if the difference between *x* and the sum of its digits (in decimal representation) is not less than *s*. To prove that these numbers may have different... | The first (and the only) line contains two integers *n* and *s* (1<=≤<=*n*,<=*s*<=≤<=1018). | Print one integer — the quantity of really big numbers that are not greater than *n*. | [
"12 1\n",
"25 20\n",
"10 9\n"
] | [
"3\n",
"0\n",
"1\n"
] | In the first example numbers 10, 11 and 12 are really big.
In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 ≥ 20).
In the third example 10 is the only really big number (10 - 1 ≥ 9). | 0 | [
{
"input": "12 1",
"output": "3"
},
{
"input": "25 20",
"output": "0"
},
{
"input": "10 9",
"output": "1"
},
{
"input": "300 1000",
"output": "0"
},
{
"input": "500 1000",
"output": "0"
},
{
"input": "1000 2000",
"output": "0"
},
{
"input":... | 1,497,547,179 | 8,079 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | inp = list(map(int, input().split()))
n, s = inp[0], inp[1]
a = int(s/9)
b = a-1
c = 0
while b > 0:
c = c*10 + 1
b = int(b /10)
while c > 0:
b = b*10 + min(int(a/c), 9)
a = a%c
print(a)
print(c)
c = int(c/10)
if a != 0 or s % 9 != 0:
print(max(0, n - (b+1)*10 + 1))
else:... | Title: Really Big Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number *x* is really big if the difference between *x* and the sum of its... | ```python
inp = list(map(int, input().split()))
n, s = inp[0], inp[1]
a = int(s/9)
b = a-1
c = 0
while b > 0:
c = c*10 + 1
b = int(b /10)
while c > 0:
b = b*10 + min(int(a/c), 9)
a = a%c
print(a)
print(c)
c = int(c/10)
if a != 0 or s % 9 != 0:
print(max(0, n - (b+1)*10 + ... | 0 | |
371 | C | Hamburgers | PROGRAMMING | 1,600 | [
"binary search",
"brute force"
] | null | null | Polycarpus loves hamburgers very much. He especially adores the hamburgers he makes with his own hands. Polycarpus thinks that there are only three decent ingredients to make hamburgers from: a bread, sausage and cheese. He writes down the recipe of his favorite "Le Hamburger de Polycarpus" as a string of letters 'B' (... | The first line of the input contains a non-empty string that describes the recipe of "Le Hamburger de Polycarpus". The length of the string doesn't exceed 100, the string contains only letters 'B' (uppercase English B), 'S' (uppercase English S) and 'C' (uppercase English C).
The second line contains three integers *n... | Print the maximum number of hamburgers Polycarpus can make. If he can't make any hamburger, print 0. | [
"BBBSSC\n6 4 1\n1 2 3\n4\n",
"BBC\n1 10 1\n1 10 1\n21\n",
"BSC\n1 1 1\n1 1 3\n1000000000000\n"
] | [
"2\n",
"7\n",
"200000000001\n"
] | none | 1,500 | [
{
"input": "BBBSSC\n6 4 1\n1 2 3\n4",
"output": "2"
},
{
"input": "BBC\n1 10 1\n1 10 1\n21",
"output": "7"
},
{
"input": "BSC\n1 1 1\n1 1 3\n1000000000000",
"output": "200000000001"
},
{
"input": "B\n1 1 1\n1 1 1\n381",
"output": "382"
},
{
"input": "BSC\n3 5 6\n7... | 1,621,196,820 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 204,800 | from collections import Counter
from math import inf
recipe = Counter(input()) #demand
state = list(map(int,input().split(' '))) #B S C
prices = list(map(int,input().split(' ')))
rubles = int(input())
max_result,min_val = 0,inf
if recipe['B'] != 0:
min_val = min(state[0] // recipe['B'],min_val)
if reci... | Title: Hamburgers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus loves hamburgers very much. He especially adores the hamburgers he makes with his own hands. Polycarpus thinks that there are only three decent ingredients to make hamburgers from: a bread, sausage and cheese. He ... | ```python
from collections import Counter
from math import inf
recipe = Counter(input()) #demand
state = list(map(int,input().split(' '))) #B S C
prices = list(map(int,input().split(' ')))
rubles = int(input())
max_result,min_val = 0,inf
if recipe['B'] != 0:
min_val = min(state[0] // recipe['B'],min_val... | 0 | |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't w... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't e... | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,690,942,305 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 92 | 0 | n = int(input())
a = list(map(int, input().split()))
count = 0
j = len(a)-1
for i in range(len(a)):
if len(a) == 1:
count+=1
elif i == j:
count+=2
j+=1
print(count)
| Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very w... | ```python
n = int(input())
a = list(map(int, input().split()))
count = 0
j = len(a)-1
for i in range(len(a)):
if len(a) == 1:
count+=1
elif i == j:
count+=2
j+=1
print(count)
``` | 0 | |
186 | B | Growing Mushrooms | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Each year in the castle of Dwarven King there is a competition in growing mushrooms among the dwarves. The competition is one of the most prestigious ones, and the winner gets a wooden salad bowl. This year's event brought together the best mushroom growers from around the world, so we had to slightly change the rules ... | The first input line contains four integer numbers *n*, *t*1, *t*2, *k* (1<=≤<=*n*,<=*t*1,<=*t*2<=≤<=1000; 1<=≤<=*k*<=≤<=100) — the number of participants, the time before the break, the time after the break and the percentage, by which the mushroom growth drops during the break, correspondingly.
Each of the following... | Print the final results' table: *n* lines, each line should contain the number of the corresponding dwarf and the final maximum height of his mushroom with exactly two digits after the decimal point. The answer will be considered correct if it is absolutely accurate. | [
"2 3 3 50\n2 4\n4 2\n",
"4 1 1 1\n544 397\n280 101\n280 101\n693 970\n"
] | [
"1 15.00\n2 15.00\n",
"4 1656.07\n1 937.03\n2 379.99\n3 379.99\n"
] | - First example: for each contestant it is optimal to use firstly speed 2 and afterwards speed 4, because 2·3·0.5 + 4·3 > 4·3·0.5 + 2·3. | 1,000 | [
{
"input": "2 3 3 50\n2 4\n4 2",
"output": "1 15.00\n2 15.00"
},
{
"input": "4 1 1 1\n544 397\n280 101\n280 101\n693 970",
"output": "4 1656.07\n1 937.03\n2 379.99\n3 379.99"
},
{
"input": "10 1 1 25\n981 1\n352 276\n164 691\n203 853\n599 97\n901 688\n934 579\n910 959\n317 624\n440 737",... | 1,607,443,112 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 186 | 204,800 | def I():
return list(map(int, input().split()))
n, t1, t2, k = I()
lis = []
for i in range(n):
x, y = I()
a = y * t2 - x * t1 * (k / 100) + x * t1
b = x * t2 - y * t1 * (k / 100) + y * t1
maxi = max(a, b)
lis.append([i + 1, maxi])
lis.sort(key=lambda x: x[1], reverse=True)
print... | Title: Growing Mushrooms
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Each year in the castle of Dwarven King there is a competition in growing mushrooms among the dwarves. The competition is one of the most prestigious ones, and the winner gets a wooden salad bowl. This year's event br... | ```python
def I():
return list(map(int, input().split()))
n, t1, t2, k = I()
lis = []
for i in range(n):
x, y = I()
a = y * t2 - x * t1 * (k / 100) + x * t1
b = x * t2 - y * t1 * (k / 100) + y * t1
maxi = max(a, b)
lis.append([i + 1, maxi])
lis.sort(key=lambda x: x[1], reverse=Tr... | 0 | |
706 | B | Interesting drink | PROGRAMMING | 1,100 | [
"binary search",
"dp",
"implementation"
] | null | null | Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single i... | Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day. | [
"5\n3 10 8 6 11\n4\n1\n10\n3\n11\n"
] | [
"0\n4\n1\n5\n"
] | On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | 1,000 | [
{
"input": "5\n3 10 8 6 11\n4\n1\n10\n3\n11",
"output": "0\n4\n1\n5"
},
{
"input": "5\n868 987 714 168 123\n10\n424\n192\n795\n873\n117\n914\n735\n158\n631\n471",
"output": "2\n2\n3\n4\n0\n4\n3\n1\n2\n2"
},
{
"input": "3\n435 482 309\n7\n245\n241\n909\n745\n980\n29\n521",
"output": "... | 1,699,326,666 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 12,390,400 | input()
shops=list(map(int,input().split()))
for _ in range(int(input())):
q=int(input())
count=0
for i in shops:
if q>=i:
count+=1
print(count) | Title: Interesting drink
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known tha... | ```python
input()
shops=list(map(int,input().split()))
for _ in range(int(input())):
q=int(input())
count=0
for i in shops:
if q>=i:
count+=1
print(count)
``` | 0 | |
688 | B | Lovely Palindromes | PROGRAMMING | 1,000 | [
"constructive algorithms",
"math"
] | null | null | Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is trying to love them too, but only very special and gifted people can understand the beauty behind palindro... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=10100<=000). | Print the *n*-th even-length palindrome number. | [
"1\n",
"10\n"
] | [
"11\n",
"1001\n"
] | The first 10 even-length palindrome numbers are 11, 22, 33, ... , 88, 99 and 1001. | 1,000 | [
{
"input": "1",
"output": "11"
},
{
"input": "10",
"output": "1001"
},
{
"input": "11",
"output": "1111"
},
{
"input": "12",
"output": "1221"
},
{
"input": "100",
"output": "100001"
},
{
"input": "1321",
"output": "13211231"
},
{
"input": "... | 1,592,125,090 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 109 | 1,126,400 | n=input()
s1=list(n)
s1.reverse()
n1=''.join(s1)
print(n+n1) | Title: Lovely Palindromes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is tr... | ```python
n=input()
s1=list(n)
s1.reverse()
n1=''.join(s1)
print(n+n1)
``` | 3 | |
440 | A | Forgotten Episode | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus adores TV series. Right now he is ready to finish watching a season of a popular sitcom "Graph Theory". In total, the season has *n* episodes, numbered with integers from 1 to *n*.
Polycarpus watches episodes not one by one but in a random order. He has already watched all the episodes except for one. Which... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100000) — the number of episodes in a season. Assume that the episodes are numbered by integers from 1 to *n*.
The second line contains *n*<=-<=1 integer *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the numbers of episodes that Polycarpus has watch... | Print the number of the episode that Polycarpus hasn't watched. | [
"10\n3 8 10 1 7 9 6 5 2\n"
] | [
"4\n"
] | none | 500 | [
{
"input": "10\n3 8 10 1 7 9 6 5 2",
"output": "4"
},
{
"input": "5\n4 3 2 1",
"output": "5"
},
{
"input": "2\n1",
"output": "2"
},
{
"input": "2\n2",
"output": "1"
},
{
"input": "3\n1 2",
"output": "3"
},
{
"input": "3\n1 3",
"output": "2"
},
... | 1,595,916,830 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 156 | 15,360,000 | missed = [i + 1 for i in range(int(input()))]
for i in map(int, input().split()):
missed[i - 1] = 0
print(sum(missed))
| Title: Forgotten Episode
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus adores TV series. Right now he is ready to finish watching a season of a popular sitcom "Graph Theory". In total, the season has *n* episodes, numbered with integers from 1 to *n*.
Polycarpus watches episo... | ```python
missed = [i + 1 for i in range(int(input()))]
for i in map(int, input().split()):
missed[i - 1] = 0
print(sum(missed))
``` | 3 | |
1,003 | B | Binary String Constructing | PROGRAMMING | 1,300 | [
"constructive algorithms"
] | null | null | You are given three integers $a$, $b$ and $x$. Your task is to construct a binary string $s$ of length $n = a + b$ such that there are exactly $a$ zeroes, exactly $b$ ones and exactly $x$ indices $i$ (where $1 \le i < n$) such that $s_i \ne s_{i + 1}$. It is guaranteed that the answer always exists.
For example, fo... | The first line of the input contains three integers $a$, $b$ and $x$ ($1 \le a, b \le 100, 1 \le x < a + b)$. | Print only one string $s$, where $s$ is any binary string satisfying conditions described above. It is guaranteed that the answer always exists. | [
"2 2 1\n",
"3 3 3\n",
"5 3 6\n"
] | [
"1100\n",
"101100\n",
"01010100\n"
] | All possible answers for the first example:
- 1100; - 0011.
All possible answers for the second example:
- 110100; - 101100; - 110010; - 100110; - 011001; - 001101; - 010011; - 001011. | 0 | [
{
"input": "2 2 1",
"output": "1100"
},
{
"input": "3 3 3",
"output": "101100"
},
{
"input": "5 3 6",
"output": "01010100"
},
{
"input": "100 1 2",
"output": "01000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000"
},
{
... | 1,645,613,849 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | a, b, x = map(int, input().split())
rem = x%2; x = (x + 1) >> 1
a -= x; b -= x
s = "1"*a + "10"*x + "0"*b
print(("0" + s[:-1] if a < b else s[1:] + "1") if rem == 0 else s) | Title: Binary String Constructing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given three integers $a$, $b$ and $x$. Your task is to construct a binary string $s$ of length $n = a + b$ such that there are exactly $a$ zeroes, exactly $b$ ones and exactly $x$ indices $i$ (where $... | ```python
a, b, x = map(int, input().split())
rem = x%2; x = (x + 1) >> 1
a -= x; b -= x
s = "1"*a + "10"*x + "0"*b
print(("0" + s[:-1] if a < b else s[1:] + "1") if rem == 0 else s)
``` | 0 | |
257 | C | View Angle | PROGRAMMING | 1,800 | [
"brute force",
"geometry",
"math"
] | null | null | Flatland has recently introduced a new type of an eye check for the driver's licence. The check goes like that: there is a plane with mannequins standing on it. You should tell the value of the minimum angle with the vertex at the origin of coordinates and with all mannequins standing inside or on the boarder of this a... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of mannequins.
Next *n* lines contain two space-separated integers each: *x**i*,<=*y**i* (|*x**i*|,<=|*y**i*|<=≤<=1000) — the coordinates of the *i*-th mannequin. It is guaranteed that the origin of the coordinates has no mannequin. It is gu... | Print a single real number — the value of the sought angle in degrees. The answer will be considered valid if the relative or absolute error doesn't exceed 10<=-<=6. | [
"2\n2 0\n0 2\n",
"3\n2 0\n0 2\n-2 2\n",
"4\n2 0\n0 2\n-2 0\n0 -2\n",
"2\n2 1\n1 2\n"
] | [
"90.0000000000\n",
"135.0000000000\n",
"270.0000000000\n",
"36.8698976458\n"
] | Solution for the first sample test is shown below:
Solution for the second sample test is shown below:
Solution for the third sample test is shown below:
Solution for the fourth sample test is shown below: | 1,500 | [
{
"input": "2\n2 0\n0 2",
"output": "90.0000000000"
},
{
"input": "3\n2 0\n0 2\n-2 2",
"output": "135.0000000000"
},
{
"input": "4\n2 0\n0 2\n-2 0\n0 -2",
"output": "270.0000000000"
},
{
"input": "2\n2 1\n1 2",
"output": "36.8698976458"
},
{
"input": "1\n1 1",
... | 1,621,263,643 | 1,783 | Python 3 | OK | TESTS | 56 | 1,028 | 10,649,600 | import math
def angle(x, y):
a = (x**2+y**2)**0.5
x1, y1 = x/a, y/a
my_angle = math.asin(y1)
my_angle = 180*my_angle/math.pi
if x < 0:
my_angle = 180-my_angle
if my_angle < 0:
my_angle = 360+my_angle
return my_angle
def process(M):
angles = []
f... | Title: View Angle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Flatland has recently introduced a new type of an eye check for the driver's licence. The check goes like that: there is a plane with mannequins standing on it. You should tell the value of the minimum angle with the vertex ... | ```python
import math
def angle(x, y):
a = (x**2+y**2)**0.5
x1, y1 = x/a, y/a
my_angle = math.asin(y1)
my_angle = 180*my_angle/math.pi
if x < 0:
my_angle = 180-my_angle
if my_angle < 0:
my_angle = 360+my_angle
return my_angle
def process(M):
angles =... | 3 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,695,645,761 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 124 | 0 | length, breadth = [int(x) for x in input().split()]
area = length * breadth
max_dominoes = area // 2
print(max_dominoes) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
length, breadth = [int(x) for x in input().split()]
area = length * breadth
max_dominoes = area // 2
print(max_dominoes)
``` | 3.969 |
139 | A | Petr and Book | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. S... | The first input line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of pages in the book.
The second line contains seven non-negative space-separated integers that do not exceed 1000 — those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and... | Print a single number — the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. | [
"100\n15 20 20 15 10 30 45\n",
"2\n1 0 0 0 0 0 0\n"
] | [
"6\n",
"1\n"
] | Note to the first sample:
By the end of Monday and therefore, by the beginning of Tuesday Petr has 85 pages left. He has 65 pages left by Wednesday, 45 by Thursday, 30 by Friday, 20 by Saturday and on Saturday Petr finishes reading the book (and he also has time to read 10 pages of something else).
Note to the second... | 500 | [
{
"input": "100\n15 20 20 15 10 30 45",
"output": "6"
},
{
"input": "2\n1 0 0 0 0 0 0",
"output": "1"
},
{
"input": "100\n100 200 100 200 300 400 500",
"output": "1"
},
{
"input": "3\n1 1 1 1 1 1 1",
"output": "3"
},
{
"input": "1\n1 1 1 1 1 1 1",
"output": "1... | 1,598,439,598 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 12 | 186 | 0 | c=0
d=0
n=int(input())
m=list(map(int,input().split()))
i=0
while c<n:
c+=m[i]
i+=1
d+=1
if d==7:
i=0
d=0
print(d) | Title: Petr and Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight s... | ```python
c=0
d=0
n=int(input())
m=list(map(int,input().split()))
i=0
while c<n:
c+=m[i]
i+=1
d+=1
if d==7:
i=0
d=0
print(d)
``` | 0 | |
327 | A | Flipping Game | PROGRAMMING | 1,200 | [
"brute force",
"dp",
"implementation"
] | null | null | Iahub got bored, so he invented a game to be played on paper.
He writes *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Each of those integers can be either 0 or 1. He's allowed to do exactly one move: he chooses two indices *i* and *j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) and flips all values *a**k* for which their positions are in... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100). In the second line of the input there are *n* integers: *a*1,<=*a*2,<=...,<=*a**n*. It is guaranteed that each of those *n* values is either 0 or 1. | Print an integer — the maximal number of 1s that can be obtained after exactly one move. | [
"5\n1 0 0 1 0\n",
"4\n1 0 0 1\n"
] | [
"4\n",
"4\n"
] | In the first case, flip the segment from 2 to 5 (*i* = 2, *j* = 5). That flip changes the sequence, it becomes: [1 1 1 0 1]. So, it contains four ones. There is no way to make the whole sequence equal to [1 1 1 1 1].
In the second case, flipping only the second and the third element (*i* = 2, *j* = 3) will turn all nu... | 500 | [
{
"input": "5\n1 0 0 1 0",
"output": "4"
},
{
"input": "4\n1 0 0 1",
"output": "4"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "8\n1 0 0 0 1 0 0 0",
"output": "7"
},
{
"input": "18\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 ... | 1,695,272,594 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 21 | 124 | 0 | n = int(input())
l = [int(x) for x in input().split()]
s=c=0
m = -100000000
for i in l:
if i==0:
s+=1
else:
c+=1
s-=1
if s>m:
m=s
if s<0:
s=0
print(m+c) | Title: Flipping Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub got bored, so he invented a game to be played on paper.
He writes *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Each of those integers can be either 0 or 1. He's allowed to do exactly one move: he chooses two indices *... | ```python
n = int(input())
l = [int(x) for x in input().split()]
s=c=0
m = -100000000
for i in l:
if i==0:
s+=1
else:
c+=1
s-=1
if s>m:
m=s
if s<0:
s=0
print(m+c)
``` | 3 | |
689 | B | Mike and Shortcuts | PROGRAMMING | 1,600 | [
"dfs and similar",
"graphs",
"greedy",
"shortest paths"
] | null | null | Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some sight seeing in the city.
City consists of *n* intersections numbered from 1 to *n*. Mike starts walking from his house located at the intersection number 1 and goes along some sequence of intersections. Wal... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of Mike's city intersection.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*i*<=≤<=*a**i*<=≤<=*n* , , describing shortcuts of Mike's city, allowing to walk from intersection *i* to intersection *a**i* using only 1 unit of ... | In the only line print *n* integers *m*1,<=*m*2,<=...,<=*m**n*, where *m**i* denotes the least amount of total energy required to walk from intersection 1 to intersection *i*. | [
"3\n2 2 3\n",
"5\n1 2 3 4 5\n",
"7\n4 4 4 4 7 7 7\n"
] | [
"0 1 2 \n",
"0 1 2 3 4 \n",
"0 1 2 1 2 3 3 \n"
] | In the first sample case desired sequences are:
1: 1; *m*<sub class="lower-index">1</sub> = 0;
2: 1, 2; *m*<sub class="lower-index">2</sub> = 1;
3: 1, 3; *m*<sub class="lower-index">3</sub> = |3 - 1| = 2.
In the second sample case the sequence for any intersection 1 < *i* is always 1, *i* and *m*<sub class="lowe... | 1,000 | [
{
"input": "3\n2 2 3",
"output": "0 1 2 "
},
{
"input": "5\n1 2 3 4 5",
"output": "0 1 2 3 4 "
},
{
"input": "7\n4 4 4 4 7 7 7",
"output": "0 1 2 1 2 3 3 "
},
{
"input": "98\n17 17 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 87 87... | 1,668,611,069 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | print( input() )
# def take_input():
# tuple_input = take_input()
# process_intersections( tuple_input )
| Title: Mike and Shortcuts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some sight seeing in the city.
City consists of *n* intersections numbered from 1 to *n*. Mike starts walkin... | ```python
print( input() )
# def take_input():
# tuple_input = take_input()
# process_intersections( tuple_input )
``` | 0 | |
129 | A | Cookies | PROGRAMMING | 900 | [
"implementation"
] | null | null | Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't want the sisters to quarrel because of nothing when they divide the cookies. That's why Olga wan... | The first line contains the only integer *n* (1<=≤<=*n*<=≤<=100) — the number of cookie bags Anna and Maria have. The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100) — the number of cookies in the *i*-th bag. | Print in the only line the only number — the sought number of ways. If there are no such ways print 0. | [
"1\n1\n",
"10\n1 2 2 3 4 4 4 2 2 2\n",
"11\n2 2 2 2 2 2 2 2 2 2 99\n"
] | [
"1\n",
"8\n",
"1\n"
] | In the first sample Olga should take the only bag so that the twins ended up with the even number of cookies.
In the second sample Olga can take any of five bags with two cookies or any of three bags with four cookies — 5 + 3 = 8 ways in total.
In the third sample, no matter which bag with two cookies Olga chooses, t... | 500 | [
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 2 2 3 4 4 4 2 2 2",
"output": "8"
},
{
"input": "11\n2 2 2 2 2 2 2 2 2 2 99",
"output": "1"
},
{
"input": "2\n1 1",
"output": "0"
},
{
"input": "2\n2 2",
"output": "2"
},
{
"input": "2\n1 2",
"o... | 1,588,924,930 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 248 | 6,656,000 | integer = int
string = str
length = len
def main():
n=int(input())
l=list(map(integer,input().split()))
add=0
odd=0
even=0
for i in l:
add+=i
if i%2:
odd+=1
else:
even+=1
if add%2:
print(odd)
else:
prin... | Title: Cookies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olga came to visit the twins Anna and Maria and saw that they have many cookies. The cookies are distributed into bags. As there are many cookies, Olga decided that it's no big deal if she steals a bag. However, she doesn't wan... | ```python
integer = int
string = str
length = len
def main():
n=int(input())
l=list(map(integer,input().split()))
add=0
odd=0
even=0
for i in l:
add+=i
if i%2:
odd+=1
else:
even+=1
if add%2:
print(odd)
else:
... | 3 | |
276 | A | Lunch Rush | PROGRAMMING | 900 | [
"implementation"
] | null | null | Having written another programming contest, three Rabbits decided to grab some lunch. The coach gave the team exactly *k* time units for the lunch break.
The Rabbits have a list of *n* restaurants to lunch in: the *i*-th restaurant is characterized by two integers *f**i* and *t**i*. Value *t**i* shows the time the Rab... | The first line contains two space-separated integers — *n* (1<=≤<=*n*<=≤<=104) and *k* (1<=≤<=*k*<=≤<=109) — the number of restaurants in the Rabbits' list and the time the coach has given them to lunch, correspondingly. Each of the next *n* lines contains two space-separated integers — *f**i* (1<=≤<=*f**i*<=≤<=109) an... | In a single line print a single integer — the maximum joy value that the Rabbits will get from the lunch. | [
"2 5\n3 3\n4 5\n",
"4 6\n5 8\n3 6\n2 3\n2 2\n",
"1 5\n1 7\n"
] | [
"4\n",
"3\n",
"-1\n"
] | none | 500 | [
{
"input": "2 5\n3 3\n4 5",
"output": "4"
},
{
"input": "4 6\n5 8\n3 6\n2 3\n2 2",
"output": "3"
},
{
"input": "1 5\n1 7",
"output": "-1"
},
{
"input": "4 9\n10 13\n4 18\n13 3\n10 6",
"output": "13"
},
{
"input": "1 1\n1 1000000000",
"output": "-999999998"
}... | 1,643,950,525 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 122 | 409,600 | n,k = map(int, input().split())
l = []
m = []
o = []
s = 0
for i in range(n):
f,t = map(int, input().split())
l.append(f)
m.append(t)
if m[i]>k:
s = l[i]-(m[i]-k)
o.append(s)
i = i + 1
else:
s = l[i]
o.append(s)
i = i + 1
print(max(o)) | Title: Lunch Rush
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Having written another programming contest, three Rabbits decided to grab some lunch. The coach gave the team exactly *k* time units for the lunch break.
The Rabbits have a list of *n* restaurants to lunch in: the *i*-th re... | ```python
n,k = map(int, input().split())
l = []
m = []
o = []
s = 0
for i in range(n):
f,t = map(int, input().split())
l.append(f)
m.append(t)
if m[i]>k:
s = l[i]-(m[i]-k)
o.append(s)
i = i + 1
else:
s = l[i]
o.append(s)
i = i + 1
pri... | 3 | |
876 | B | Divisiblity of Differences | PROGRAMMING | 1,300 | [
"implementation",
"math",
"number theory"
] | null | null | You are given a multiset of *n* integers. You should select exactly *k* of them in a such way that the difference between any two of them is divisible by *m*, or tell that it is impossible.
Numbers can be repeated in the original multiset and in the multiset of selected numbers, but number of occurrences of any number... | First line contains three integers *n*, *k* and *m* (2<=≤<=*k*<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=100<=000) — number of integers in the multiset, number of integers you should select and the required divisor of any pair of selected integers.
Second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=... | If it is not possible to select *k* numbers in the desired way, output «No» (without the quotes).
Otherwise, in the first line of output print «Yes» (without the quotes). In the second line print *k* integers *b*1,<=*b*2,<=...,<=*b**k* — the selected numbers. If there are multiple possible solutions, print any of them... | [
"3 2 3\n1 8 4\n",
"3 3 3\n1 8 4\n",
"4 3 5\n2 7 7 7\n"
] | [
"Yes\n1 4 ",
"No",
"Yes\n2 7 7 "
] | none | 1,000 | [
{
"input": "3 2 3\n1 8 4",
"output": "Yes\n1 4 "
},
{
"input": "3 3 3\n1 8 4",
"output": "No"
},
{
"input": "4 3 5\n2 7 7 7",
"output": "Yes\n2 7 7 "
},
{
"input": "9 9 5\n389149775 833127990 969340400 364457730 48649145 316121525 640054660 924273385 973207825",
"output":... | 1,508,152,603 | 703 | Python 3 | OK | TESTS | 63 | 218 | 13,926,400 | n,k,m = map(int, input().split())
a = list(map(int, input().split()))
d = {}
for i in range(n):
r = a[i]%m
if r not in d:
d[r] = 0
d[r]+=1
ans_r=None
for key in d:
if d[key] >= k:
ans_r=key
break
if ans_r is None:
print('No')
else:
ans = []
for ... | Title: Divisiblity of Differences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a multiset of *n* integers. You should select exactly *k* of them in a such way that the difference between any two of them is divisible by *m*, or tell that it is impossible.
Numbers can be re... | ```python
n,k,m = map(int, input().split())
a = list(map(int, input().split()))
d = {}
for i in range(n):
r = a[i]%m
if r not in d:
d[r] = 0
d[r]+=1
ans_r=None
for key in d:
if d[key] >= k:
ans_r=key
break
if ans_r is None:
print('No')
else:
ans = []... | 3 | |
474 | D | Flowers | PROGRAMMING | 1,700 | [
"dp"
] | null | null | We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty... | Input contains several test cases.
The first line contains two integers *t* and *k* (1<=≤<=*t*,<=*k*<=≤<=105), where *t* represents the number of test cases.
The next *t* lines contain two integers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=*b**i*<=≤<=105), describing the *i*-th test. | Print *t* lines to the standard output. The *i*-th line should contain the number of ways in which Marmot can eat between *a**i* and *b**i* flowers at dinner modulo 1000000007 (109<=+<=7). | [
"3 2\n1 3\n2 3\n4 4\n"
] | [
"6\n5\n5\n"
] | - For *K* = 2 and length 1 Marmot can eat (*R*). - For *K* = 2 and length 2 Marmot can eat (*RR*) and (*WW*). - For *K* = 2 and length 3 Marmot can eat (*RRR*), (*RWW*) and (*WWR*). - For *K* = 2 and length 4 Marmot can eat, for example, (*WWWW*) or (*RWWR*), but for example he can't eat (*WWWR*). | 2,000 | [
{
"input": "3 2\n1 3\n2 3\n4 4",
"output": "6\n5\n5"
},
{
"input": "1 1\n1 3",
"output": "14"
},
{
"input": "1 2\n64329 79425",
"output": "0"
}
] | 1,695,317,665 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<bits/stdc++.h>
#define ll long long
const int N=1e5+5;
const ll mod=1e9+7;
using namespace std;
int n,T;
ll dp[N][2],p[N];
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
cin>>T>>n;
dp[0][0]=1;
for(int i=1;i<=100000;++i)
{
dp[i][0]=(dp[i-1... | Title: Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequenc... | ```python
#include<bits/stdc++.h>
#define ll long long
const int N=1e5+5;
const ll mod=1e9+7;
using namespace std;
int n,T;
ll dp[N][2],p[N];
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
cin>>T>>n;
dp[0][0]=1;
for(int i=1;i<=100000;++i)
{
dp[i][... | -1 | |
796 | D | Police Stations | PROGRAMMING | 2,100 | [
"constructive algorithms",
"dfs and similar",
"dp",
"graphs",
"shortest paths",
"trees"
] | null | null | Inzane finally found Zane with a lot of money to spare, so they together decided to establish a country of their own.
Ruling a country is not an easy job. Thieves and terrorists are always ready to ruin the country's peace. To fight back, Zane and Inzane have enacted a very effective law: from each city it must be pos... | The first line contains three integers *n*, *k*, and *d* (2<=≤<=*n*<=≤<=3·105, 1<=≤<=*k*<=≤<=3·105, 0<=≤<=*d*<=≤<=*n*<=-<=1) — the number of cities, the number of police stations, and the distance limitation in kilometers, respectively.
The second line contains *k* integers *p*1,<=*p*2,<=...,<=*p**k* (1<=≤<=*p**i*<=≤<... | In the first line, print one integer *s* that denotes the maximum number of roads that can be shut down.
In the second line, print *s* distinct integers, the indices of such roads, in any order.
If there are multiple answers, print any of them. | [
"6 2 4\n1 6\n1 2\n2 3\n3 4\n4 5\n5 6\n",
"6 3 2\n1 5 6\n1 2\n1 3\n1 4\n1 5\n5 6\n"
] | [
"1\n5\n",
"2\n4 5 "
] | In the first sample, if you shut down road 5, all cities can still reach a police station within *k* = 4 kilometers.
In the second sample, although this is the only largest valid set of roads that can be shut down, you can print either 4 5 or 5 4 in the second line. | 1,500 | [
{
"input": "6 2 4\n1 6\n1 2\n2 3\n3 4\n4 5\n5 6",
"output": "1\n3 "
},
{
"input": "6 3 2\n1 5 6\n1 2\n1 3\n1 4\n1 5\n5 6",
"output": "2\n4 5 "
},
{
"input": "10 1 5\n5\n1 2\n2 3\n3 4\n4 5\n5 6\n6 7\n7 8\n8 9\n9 10",
"output": "0"
},
{
"input": "11 1 5\n6\n1 2\n2 3\n3 4\n4 5\n... | 1,650,004,240 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 70,041,600 | from collections import deque
from itertools import repeat
inf = 10000000
def bfs(graph, v, q):
visited = [0]*(v+1)
res = [0]*v
cnt=0
while(len(q)!=0):
if visited[q[0][0]] == 1 :
q.popleft()
continue
cur = q[0][0]
prev = q[0][1]
visi... | Title: Police Stations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Inzane finally found Zane with a lot of money to spare, so they together decided to establish a country of their own.
Ruling a country is not an easy job. Thieves and terrorists are always ready to ruin the country's p... | ```python
from collections import deque
from itertools import repeat
inf = 10000000
def bfs(graph, v, q):
visited = [0]*(v+1)
res = [0]*v
cnt=0
while(len(q)!=0):
if visited[q[0][0]] == 1 :
q.popleft()
continue
cur = q[0][0]
prev = q[0][1]
... | 0 | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,662,892,203 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 46 | 0 | l = [int(l) for l in input().split()]
n = l[0]; m = l[1]
p = ''
for i in range(n):
x = [str(x) for x in input().split()]
for j in x:
if j == 'C' or j == 'M' or j == 'Y':
p = "#Color"
print(p)
break
if p != '': break
if p == '':
print("#Black&W... | Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
l = [int(l) for l in input().split()]
n = l[0]; m = l[1]
p = ''
for i in range(n):
x = [str(x) for x in input().split()]
for j in x:
if j == 'C' or j == 'M' or j == 'Y':
p = "#Color"
print(p)
break
if p != '': break
if p == '':
print... | 3 | |
597 | A | Divisibility | PROGRAMMING | 1,600 | [
"math"
] | null | null | Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*. | The only line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=1018;<=-<=1018<=≤<=*a*<=≤<=*b*<=≤<=1018). | Print the required number. | [
"1 1 10\n",
"2 -4 4\n"
] | [
"10\n",
"5\n"
] | none | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "2 -4 4",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 0 0",
"output": "1"
},
{
"input": "1 0 1",
"output": "2"
},
{
"input": "1 10181 10182",
"output": "2"
},
{
"inpu... | 1,615,780,561 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 12 | 108 | 0 | from math import floor
def seal(a, b):
return (a + b - 1)//b
k,a,b = map(int,input().split())
ans = abs(b)//k + abs(a)//k
if(a < 0 and b > 0):
values = b - a + 1
print(ans + 1)
else:
a,b = abs(a), abs(b)
lower = seal(a,k)
upper = floor(b/k)
print(upper - lower + 1)
# if(a % ... | Title: Divisibility
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*.
Input Specification:
The onl... | ```python
from math import floor
def seal(a, b):
return (a + b - 1)//b
k,a,b = map(int,input().split())
ans = abs(b)//k + abs(a)//k
if(a < 0 and b > 0):
values = b - a + 1
print(ans + 1)
else:
a,b = abs(a), abs(b)
lower = seal(a,k)
upper = floor(b/k)
print(upper - lower + 1)
... | 0 | |
305 | A | Strange Addition | PROGRAMMING | 1,600 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Unfortunately, Vasya can only sum pairs of integers (*a*, *b*), such that for any decimal place at least one number has digit 0 in this place. For example, Vasya can sum numbers 505 and 50, but he cannot sum 1 and 4.
Vasya has a set of *k* distinct non-negative integers *d*1,<=*d*2,<=...,<=*d**k*.
Vasya wants to choo... | The first input line contains integer *k* (1<=≤<=*k*<=≤<=100) — the number of integers.
The second line contains *k* distinct space-separated integers *d*1,<=*d*2,<=...,<=*d**k* (0<=≤<=*d**i*<=≤<=100). | In the first line print a single integer *n* the maximum number of the chosen integers. In the second line print *n* distinct non-negative integers — the required integers.
If there are multiple solutions, print any of them. You can print the numbers in any order. | [
"4\n100 10 1 0\n",
"3\n2 70 3\n"
] | [
"4\n0 1 10 100 ",
"2\n2 70 "
] | none | 500 | [
{
"input": "4\n100 10 1 0",
"output": "4\n0 1 10 100 "
},
{
"input": "3\n2 70 3",
"output": "2\n2 70 "
},
{
"input": "39\n16 72 42 70 17 36 32 40 47 94 27 30 100 55 23 77 67 28 49 50 53 83 38 33 60 65 62 64 6 66 69 86 96 75 85 0 89 73 29",
"output": "4\n0 6 30 100 "
},
{
"inp... | 1,615,539,545 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 186 | 0 | k=int(input())
l=list(map(int,input().split()))
r=0
q1=[]
q2=[]
for i in range(k):
if(l[i]==0):
q1.append(l[i])
elif(l[i]%10==0):
q1.append(l[i])
for i in range(k):
if(l[i]!=0 and l[i]%10!=0):
r=r+1
q2.append(l[i])
if(r==len(q1)):
break
pri... | Title: Strange Addition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Unfortunately, Vasya can only sum pairs of integers (*a*, *b*), such that for any decimal place at least one number has digit 0 in this place. For example, Vasya can sum numbers 505 and 50, but he cannot sum 1 and 4.
... | ```python
k=int(input())
l=list(map(int,input().split()))
r=0
q1=[]
q2=[]
for i in range(k):
if(l[i]==0):
q1.append(l[i])
elif(l[i]%10==0):
q1.append(l[i])
for i in range(k):
if(l[i]!=0 and l[i]%10!=0):
r=r+1
q2.append(l[i])
if(r==len(q1)):
... | 0 | |
401 | A | Vanya and Cards | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each card doesn't exceed *x* in the absolute value.
Natasha doesn't like when Vanya spends a long time p... | The first line contains two integers: *n* (1<=≤<=*n*<=≤<=1000) — the number of found cards and *x* (1<=≤<=*x*<=≤<=1000) — the maximum absolute value of the number on a card. The second line contains *n* space-separated integers — the numbers on found cards. It is guaranteed that the numbers do not exceed *x* in their a... | Print a single number — the answer to the problem. | [
"3 2\n-1 1 2\n",
"2 3\n-2 -2\n"
] | [
"1\n",
"2\n"
] | In the first sample, Vanya needs to find a single card with number -2.
In the second sample, Vanya needs to find two cards with number 2. He can't find a single card with the required number as the numbers on the lost cards do not exceed 3 in their absolute value. | 500 | [
{
"input": "3 2\n-1 1 2",
"output": "1"
},
{
"input": "2 3\n-2 -2",
"output": "2"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
},
{
"input": "2 2\n-1 -1",
"output": "1"
},
{
"input": "15 5\n-2 -1 2 -4 -3 4 -4 -2 -2 2 -2 -1 1 -4 -2",
"output": "4"
},
{
"... | 1,616,254,536 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 36 | 62 | 307,200 | n,x=[int(i) for i in input().split()]
xi=[int(x) for x in input().split()]
s=sum(xi)
s=abs(s)
cnt=0
for i in range(x,0,-1):
if(s<=0):
print(cnt)
break
if(s>i):
q=s//i
s-=(i*q)
cnt+=q
else:
s-=i
cnt+=1 | Title: Vanya and Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each... | ```python
n,x=[int(i) for i in input().split()]
xi=[int(x) for x in input().split()]
s=sum(xi)
s=abs(s)
cnt=0
for i in range(x,0,-1):
if(s<=0):
print(cnt)
break
if(s>i):
q=s//i
s-=(i*q)
cnt+=q
else:
s-=i
cnt+=1
``` | 0 | |
61 | D | Eternal Victory | PROGRAMMING | 1,800 | [
"dfs and similar",
"graphs",
"greedy",
"shortest paths",
"trees"
] | D. Eternal Victory | 2 | 256 | Valerian was captured by Shapur. The victory was such a great one that Shapur decided to carve a scene of Valerian's defeat on a mountain. So he had to find the best place to make his victory eternal!
He decided to visit all *n* cities of Persia to find the best available mountain, but after the recent war he was too ... | First line contains a single natural number *n* (1<=≤<=*n*<=≤<=105) — the amount of cities.
Next *n*<=-<=1 lines contain 3 integer numbers each *x**i*, *y**i* and *w**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*,<=0<=≤<=*w**i*<=≤<=2<=×<=104). *x**i* and *y**i* are two ends of a road and *w**i* is the length of that road. | A single integer number, the minimal length of Shapur's travel.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d). | [
"3\n1 2 3\n2 3 4\n",
"3\n1 2 3\n1 3 3\n"
] | [
"7\n",
"9\n"
] | none | 2,000 | [
{
"input": "3\n1 2 3\n2 3 4",
"output": "7"
},
{
"input": "3\n1 2 3\n1 3 3",
"output": "9"
},
{
"input": "5\n5 3 60\n4 3 63\n2 1 97\n3 1 14",
"output": "371"
},
{
"input": "3\n2 1 63\n3 1 78",
"output": "204"
},
{
"input": "13\n8 2 58\n2 1 49\n13 10 41\n11 9 67\n6... | 1,619,556,298 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 655 | 18,432,000 | n = int(input())
matrix = [[] * n for i in range(n)]
conn = dict()
def dfs(el, el2):
suma = 0
for element in matrix[el]:
if element[0] != el2:
suma = max(suma, element[1]+dfs(element[0],el))
return suma
suma=0
for i in range(n-1):
line = input()
line = line.spli... | Title: Eternal Victory
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Valerian was captured by Shapur. The victory was such a great one that Shapur decided to carve a scene of Valerian's defeat on a mountain. So he had to find the best place to make his victory eternal!
He decided to visit a... | ```python
n = int(input())
matrix = [[] * n for i in range(n)]
conn = dict()
def dfs(el, el2):
suma = 0
for element in matrix[el]:
if element[0] != el2:
suma = max(suma, element[1]+dfs(element[0],el))
return suma
suma=0
for i in range(n-1):
line = input()
line =... | 3.801918 |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,692,717,212 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | string = input()
summ1 = sum(i.isupper() for i in string)
summ2 = sum(k.islower() for k in string)
if summ2 >= summ1:
print(string.lower())
elif summ1 > summ2:
print(string.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
string = input()
summ1 = sum(i.isupper() for i in string)
summ2 = sum(k.islower() for k in string)
if summ2 >= summ1:
print(string.lower())
elif summ1 > summ2:
print(string.upper())
``` | 3.977 |
597 | A | Divisibility | PROGRAMMING | 1,600 | [
"math"
] | null | null | Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*. | The only line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=1018;<=-<=1018<=≤<=*a*<=≤<=*b*<=≤<=1018). | Print the required number. | [
"1 1 10\n",
"2 -4 4\n"
] | [
"10\n",
"5\n"
] | none | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "2 -4 4",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 0 0",
"output": "1"
},
{
"input": "1 0 1",
"output": "2"
},
{
"input": "1 10181 10182",
"output": "2"
},
{
"inpu... | 1,591,851,464 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 93 | 0 | import sys
k, a, b = map(int, sys.stdin.readline().rsplit())
c = (abs(b - a))//k
if not b%k or not b%k:
c += 1
print(c) | Title: Divisibility
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*.
Input Specification:
The onl... | ```python
import sys
k, a, b = map(int, sys.stdin.readline().rsplit())
c = (abs(b - a))//k
if not b%k or not b%k:
c += 1
print(c)
``` | 0 | |
810 | A | Straight <<A>> | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
In school, where Noora is studying, teachers are putting down marks to the online class register, wh... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*k*<=≤<=100) denoting the number of marks, received by Noora and the value of highest possible mark.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*k*) denoting marks received by Noora before Leha's hack. | Print a single integer — minimal number of additional marks, that Leha has to add in order to change Noora's final mark to *k*. | [
"2 10\n8 9\n",
"3 5\n4 4 4\n"
] | [
"4",
"3"
] | Consider the first example testcase.
Maximal mark is 10, Noora received two marks — 8 and 9, so current final mark is 9. To fix it, Leha can add marks [10, 10, 10, 10] (4 marks in total) to the registry, achieving Noora having average mark equal to <img align="middle" class="tex-formula" src="https://espresso.codeforc... | 500 | [
{
"input": "2 10\n8 9",
"output": "4"
},
{
"input": "3 5\n4 4 4",
"output": "3"
},
{
"input": "3 10\n10 8 9",
"output": "3"
},
{
"input": "2 23\n21 23",
"output": "2"
},
{
"input": "5 10\n5 10 10 9 10",
"output": "7"
},
{
"input": "12 50\n18 10 26 22 2... | 1,590,263,240 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 29 | 1,000 | 102,400 | n, k = map(int,input().split())
A = list(map(int,input().split()))
count = 0
while sum(A) / n < k - 0.5:
A.append(k)
n += 1
count += 1
print(count) | Title: Straight <<A>>
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
... | ```python
n, k = map(int,input().split())
A = list(map(int,input().split()))
count = 0
while sum(A) / n < k - 0.5:
A.append(k)
n += 1
count += 1
print(count)
``` | 0 | |
346 | E | Doodle Jump | PROGRAMMING | 3,000 | [
"math",
"number theory"
] | null | null | In Doodle Jump the aim is to guide a four-legged creature called "The Doodler" up a never-ending series of platforms without falling. — Wikipedia.
It is a very popular game and xiaodao likes it very much. One day when playing the game she wondered whether there exists a platform that the doodler couldn't reach due to... | The first line contains an integer *t* (1<=≤<=*t*<=≤<=104) — the number of problem instances. Each of the next *t* lines contains four integers *a*, *n*, *p* and *h* (1<=≤<=*a*<=≤<=109, 1<=≤<=*n*<=<<=*p*<=≤<=109, 0<=≤<=*h*<=≤<=109). It's guaranteed that *a* and *p* are co-prime. | For each problem instance, if the Doodler can reach the highest platform, output "YES", otherwise output "NO". | [
"3\n7 4 12 2\n7 1 9 4\n7 4 12 3\n"
] | [
"NO\nNO\nYES\n"
] | none | 2,500 | [] | 1,689,600,754 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | print("_RANDOM_GUESS_1689600754.4636743")# 1689600754.4636924 | Title: Doodle Jump
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Doodle Jump the aim is to guide a four-legged creature called "The Doodler" up a never-ending series of platforms without falling. — Wikipedia.
It is a very popular game and xiaodao likes it very much. One day when pla... | ```python
print("_RANDOM_GUESS_1689600754.4636743")# 1689600754.4636924
``` | 0 | |
552 | B | Vanya and Books | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the *n* books should be assigned with a number from 1 to *n*. Naturally, distinct books should be assigned distinct numbers.
Vanya wants to know how many digits he will have to write down as he labels th... | The first line contains integer *n* (1<=≤<=*n*<=≤<=109) — the number of books in the library. | Print the number of digits needed to number all the books. | [
"13\n",
"4\n"
] | [
"17\n",
"4\n"
] | Note to the first test. The books get numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, which totals to 17 digits.
Note to the second sample. The books get numbers 1, 2, 3, 4, which totals to 4 digits. | 1,000 | [
{
"input": "13",
"output": "17"
},
{
"input": "4",
"output": "4"
},
{
"input": "100",
"output": "192"
},
{
"input": "99",
"output": "189"
},
{
"input": "1000000000",
"output": "8888888899"
},
{
"input": "1000000",
"output": "5888896"
},
{
"... | 1,647,923,041 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | n = int(input())
k = 1
cnt = 0
x = 9
while True:
if n > x:
cnt += x * k
x += x * 10
k += 1
else:
cnt += (x - (x - (n - (x - 9) // 10))) * k
break
print(cnt)
| Title: Vanya and Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the *n* books should be assigned with a number from 1 to *n*. Naturally, distinct books should be assig... | ```python
n = int(input())
k = 1
cnt = 0
x = 9
while True:
if n > x:
cnt += x * k
x += x * 10
k += 1
else:
cnt += (x - (x - (n - (x - 9) // 10))) * k
break
print(cnt)
``` | 0 | |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,696,290,875 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 186 | 1,024,000 | # LUOGU_RID: 127188383
a=input()
if '0' in a:
e=a.index('0')
a=a+'0'
a=a[:e]+a[e+1:][:-1]
else:
a=a[1:]
print(a) | Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
# LUOGU_RID: 127188383
a=input()
if '0' in a:
e=a.index('0')
a=a+'0'
a=a[:e]+a[e+1:][:-1]
else:
a=a[1:]
print(a)
``` | 3 | |
1,005 | B | Delete from the Left | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't choose a string if it is empty.
For example:
- by applying a move to the string "where", the result is ... | The first line of the input contains $s$. In the second line of the input contains $t$. Both strings consist only of lowercase Latin letters. The number of letters in each string is between 1 and $2\cdot10^5$, inclusive. | Output the fewest number of moves required. It is possible that, in the end, both strings will be equal to the empty string, and so, are equal to each other. In this case, the answer is obviously the sum of the lengths of the given strings. | [
"test\nwest\n",
"codeforces\nyes\n",
"test\nyes\n",
"b\nab\n"
] | [
"2\n",
"9\n",
"7\n",
"1\n"
] | In the first example, you should apply the move once to the first string and apply the move once to the second string. As a result, both strings will be equal to "est".
In the second example, the move should be applied to the string "codeforces" $8$ times. As a result, the string becomes "codeforces" $\to$ "es". The m... | 0 | [
{
"input": "test\nwest",
"output": "2"
},
{
"input": "codeforces\nyes",
"output": "9"
},
{
"input": "test\nyes",
"output": "7"
},
{
"input": "b\nab",
"output": "1"
},
{
"input": "z\nz",
"output": "0"
},
{
"input": "abacabadabacaba\nabacabadacaba",
... | 1,640,258,213 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 28 | 155 | 2,355,200 | import sys
input = sys.stdin.readline
def main():
S = input()
T = input()
ls = len(S)
lt = len(T)
S = S[::-1]
T = T[::-1]
for i in range(min(ls, lt)):
if S[i] != T[i]:
break
else:
i += 1
print(ls + lt - i * 2)
for _ in range(1):
... | Title: Delete from the Left
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't ... | ```python
import sys
input = sys.stdin.readline
def main():
S = input()
T = input()
ls = len(S)
lt = len(T)
S = S[::-1]
T = T[::-1]
for i in range(min(ls, lt)):
if S[i] != T[i]:
break
else:
i += 1
print(ls + lt - i * 2)
for _ in rang... | 3 | |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The produ... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second... | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,591,970,933 | 2,147,483,647 | PyPy 3 | OK | TESTS | 20 | 280 | 0 | #A. Array
n = int(input())
a,b,c =[],[],[]
l = list(map(int,input().split()))
for i in l:
if i<0:
a.append(i)
elif i>0:
b.append(i)
else:
c.append(i)
if len(b)==0 and len(a)>2:
b.append(a.pop())
b.append(a.pop())
if len(a)%2==0:
c.append(a.pop())
pr... | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. T... | ```python
#A. Array
n = int(input())
a,b,c =[],[],[]
l = list(map(int,input().split()))
for i in l:
if i<0:
a.append(i)
elif i>0:
b.append(i)
else:
c.append(i)
if len(b)==0 and len(a)>2:
b.append(a.pop())
b.append(a.pop())
if len(a)%2==0:
c.append(a.pop(... | 3 | |
534 | C | Polycarpus' Dice | PROGRAMMING | 1,600 | [
"math"
] | null | null | Polycarp has *n* dice *d*1,<=*d*2,<=...,<=*d**n*. The *i*-th dice shows numbers from 1 to *d**i*. Polycarp rolled all the dice and the sum of numbers they showed is *A*. Agrippina didn't see which dice showed what number, she knows only the sum *A* and the values *d*1,<=*d*2,<=...,<=*d**n*. However, she finds it enough... | The first line contains two integers *n*,<=*A* (1<=≤<=*n*<=≤<=2·105,<=*n*<=≤<=*A*<=≤<=*s*) — the number of dice and the sum of shown values where *s*<==<=*d*1<=+<=*d*2<=+<=...<=+<=*d**n*.
The second line contains *n* integers *d*1,<=*d*2,<=...,<=*d**n* (1<=≤<=*d**i*<=≤<=106), where *d**i* is the maximum value that the... | Print *n* integers *b*1,<=*b*2,<=...,<=*b**n*, where *b**i* is the number of values for which it is guaranteed that the *i*-th dice couldn't show them. | [
"2 8\n4 4\n",
"1 3\n5\n",
"2 3\n2 3\n"
] | [
"3 3 ",
"4 ",
"0 1 "
] | In the first sample from the statement *A* equal to 8 could be obtained in the only case when both the first and the second dice show 4. Correspondingly, both dice couldn't show values 1, 2 or 3.
In the second sample from the statement *A* equal to 3 could be obtained when the single dice shows 3. Correspondingly, it ... | 1,500 | [
{
"input": "2 8\n4 4",
"output": "3 3 "
},
{
"input": "1 3\n5",
"output": "4 "
},
{
"input": "2 3\n2 3",
"output": "0 1 "
},
{
"input": "1 1\n3",
"output": "2 "
},
{
"input": "1 2\n3",
"output": "2 "
},
{
"input": "2 2\n2 3",
"output": "1 2 "
},
... | 1,542,744,352 | 2,147,483,647 | PyPy 3 | OK | TESTS | 99 | 358 | 20,889,600 | n, A = map(int, input().split())
d = [int(x) for x in input().split()]
s = sum(d)
print(' '.join([str(x - min(x, A - n + 1) + max(1, A - s + x) - 1) for x in d])) | Title: Polycarpus' Dice
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has *n* dice *d*1,<=*d*2,<=...,<=*d**n*. The *i*-th dice shows numbers from 1 to *d**i*. Polycarp rolled all the dice and the sum of numbers they showed is *A*. Agrippina didn't see which dice showed what numb... | ```python
n, A = map(int, input().split())
d = [int(x) for x in input().split()]
s = sum(d)
print(' '.join([str(x - min(x, A - n + 1) + max(1, A - s + x) - 1) for x in d]))
``` | 3 | |
877 | D | Olya and Energy Drinks | PROGRAMMING | 2,100 | [
"data structures",
"dfs and similar",
"graphs",
"shortest paths"
] | null | null | Olya loves energy drinks. She loves them so much that her room is full of empty cans from energy drinks.
Formally, her room can be represented as a field of *n*<=×<=*m* cells, each cell of which is empty or littered with cans.
Olya drank a lot of energy drink, so now she can run *k* meters per second. Each second she... | The first line contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=1000) — the sizes of the room and Olya's speed.
Then *n* lines follow containing *m* characters each, the *i*-th of them contains on *j*-th position "#", if the cell (*i*,<=*j*) is littered with cans, and "." otherwise.
The last line c... | Print a single integer — the minimum time it will take Olya to get from (*x*1,<=*y*1) to (*x*2,<=*y*2).
If it's impossible to get from (*x*1,<=*y*1) to (*x*2,<=*y*2), print -1. | [
"3 4 4\n....\n###.\n....\n1 1 3 1\n",
"3 4 1\n....\n###.\n....\n1 1 3 1\n",
"2 2 1\n.#\n#.\n1 1 2 2\n"
] | [
"3",
"8",
"-1"
] | In the first sample Olya should run 3 meters to the right in the first second, 2 meters down in the second second and 3 meters to the left in the third second.
In second sample Olya should run to the right for 3 seconds, then down for 2 seconds and then to the left for 3 seconds.
Olya does not recommend drinking ener... | 2,000 | [
{
"input": "3 4 4\n....\n###.\n....\n1 1 3 1",
"output": "3"
},
{
"input": "3 4 1\n....\n###.\n....\n1 1 3 1",
"output": "8"
},
{
"input": "2 2 1\n.#\n#.\n1 1 2 2",
"output": "-1"
},
{
"input": "10 10 1\n##########\n#.........\n#.#######.\n#.#.....#.\n#.#.###.#.\n#.#.#.#.#.\n... | 1,698,625,344 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 30 | 307,200 | from collections import deque
n, m, k = map(int, input().split())
g = [list(input()) for _ in range(n)]
x1, y1, x2, y2 = map(int, input().split())
# print(g)
path = [[float('inf')] * (m) for _ in range(n)]
path[x1 - 1][y1 - 1] = 0
q = deque([])
q.append((x1 - 1, y1 - 1))
def check(l, r, a, b):
for i in rang... | Title: Olya and Energy Drinks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olya loves energy drinks. She loves them so much that her room is full of empty cans from energy drinks.
Formally, her room can be represented as a field of *n*<=×<=*m* cells, each cell of which is empty or litt... | ```python
from collections import deque
n, m, k = map(int, input().split())
g = [list(input()) for _ in range(n)]
x1, y1, x2, y2 = map(int, input().split())
# print(g)
path = [[float('inf')] * (m) for _ in range(n)]
path[x1 - 1][y1 - 1] = 0
q = deque([])
q.append((x1 - 1, y1 - 1))
def check(l, r, a, b):
for... | 0 | |
432 | D | Prefixes and Suffixes | PROGRAMMING | 2,000 | [
"dp",
"string suffix structures",
"strings",
"two pointers"
] | null | null | You have a string *s*<==<=*s*1*s*2...*s*|*s*|, where |*s*| is the length of string *s*, and *s**i* its *i*-th character.
Let's introduce several definitions:
- A substring *s*[*i*..*j*] (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|) of string *s* is string *s**i**s**i*<=+<=1...*s**j*. - The prefix of string *s* of length *l* (1<=≤... | The single line contains a sequence of characters *s*1*s*2...*s*|*s*| (1<=≤<=|*s*|<=≤<=105) — string *s*. The string only consists of uppercase English letters. | In the first line, print integer *k* (0<=≤<=*k*<=≤<=|*s*|) — the number of prefixes that match a suffix of string *s*. Next print *k* lines, in each line print two integers *l**i* *c**i*. Numbers *l**i* *c**i* mean that the prefix of the length *l**i* matches the suffix of length *l**i* and occurs in string *s* as a su... | [
"ABACABA\n",
"AAA\n"
] | [
"3\n1 4\n3 2\n7 1\n",
"3\n1 3\n2 2\n3 1\n"
] | none | 2,000 | [
{
"input": "ABACABA",
"output": "3\n1 4\n3 2\n7 1"
},
{
"input": "AAA",
"output": "3\n1 3\n2 2\n3 1"
},
{
"input": "A",
"output": "1\n1 1"
},
{
"input": "AAAAAAAAAAAAAAAAXAAAAAAAAAAAAAAAAAAAAAAA",
"output": "17\n1 39\n2 37\n3 35\n4 33\n5 31\n6 29\n7 27\n8 25\n9 23\n10 21\... | 1,692,412,537 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 389 | 64,204,800 | from sys import stdin
from collections import defaultdict,Counter
def line(): return stdin.readline().strip()
def rd(converter): return converter(line())
def rl(converter, delimeter = None): return list(map(converter, line().split(delimeter)))
def rls(num_lines, converter): return [rd(converter) for i in range(num_lin... | Title: Prefixes and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a string *s*<==<=*s*1*s*2...*s*|*s*|, where |*s*| is the length of string *s*, and *s**i* its *i*-th character.
Let's introduce several definitions:
- A substring *s*[*i*..*j*] (1<=≤<=*i*<=≤<=*j*<=≤<=... | ```python
from sys import stdin
from collections import defaultdict,Counter
def line(): return stdin.readline().strip()
def rd(converter): return converter(line())
def rl(converter, delimeter = None): return list(map(converter, line().split(delimeter)))
def rls(num_lines, converter): return [rd(converter) for i in ran... | 3 | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,690,545,539 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 154 | 0 | s = str(input())
t = str(input())
w = len(s)
y = ''.join(reversed(s))
flag = True
for i in range(w):
if t[i] != y[i]:
flag = False
break
if flag:
print("YES")
else:
print("NO")
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
s = str(input())
t = str(input())
w = len(s)
y = ''.join(reversed(s))
flag = True
for i in range(w):
if t[i] != y[i]:
flag = False
break
if flag:
print("YES")
else:
print("NO")
``` | 3.9615 |
321 | A | Ciel and Robot | PROGRAMMING | 1,700 | [
"binary search",
"implementation",
"math"
] | null | null | Fox Ciel has a robot on a 2D plane. Initially it is located in (0, 0). Fox Ciel code a command to it. The command was represented by string *s*. Each character of *s* is one move operation. There are four move operations at all:
- 'U': go up, (x, y) <=→<= (x, y+1); - 'D': go down, (x, y) <=→<= (x, y-1); - 'L': go l... | The first line contains two integers *a* and *b*, (<=-<=109<=≤<=*a*,<=*b*<=≤<=109). The second line contains a string *s* (1<=≤<=|*s*|<=≤<=100, *s* only contains characters 'U', 'D', 'L', 'R') — the command. | Print "Yes" if the robot will be located at (*a*,<=*b*), and "No" otherwise. | [
"2 2\nRU\n",
"1 2\nRU\n",
"-1 1000000000\nLRRLU\n",
"0 0\nD\n"
] | [
"Yes\n",
"No\n",
"Yes\n",
"Yes\n"
] | In the first and second test case, command string is "RU", so the robot will go right, then go up, then right, and then up and so on.
The locations of its moves are (0, 0) → (1, 0) → (1, 1) → (2, 1) → (2, 2) → ...
So it can reach (2, 2) but not (1, 2). | 500 | [
{
"input": "2 2\nRU",
"output": "Yes"
},
{
"input": "1 2\nRU",
"output": "No"
},
{
"input": "-1 1000000000\nLRRLU",
"output": "Yes"
},
{
"input": "0 0\nD",
"output": "Yes"
},
{
"input": "0 0\nUURRDL",
"output": "Yes"
},
{
"input": "987654321 987654321\... | 1,482,520,801 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 4,608,000 | a,b=map(int,input().split())
ch=input()
x=y=u=d=l=r=0
for z in ch:
if z=='U':
u=u+1
elif z=='D':
d=d+1
elif z=='L':
l=l+1
else:
r=r+1
x=x+r-l
y=y+u-d
if ((x==a)and(y==b)):
print('Yes')
elif (y==b):
if ((y/x)==((b-y)/(a-x))):
print('Yes')... | Title: Ciel and Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel has a robot on a 2D plane. Initially it is located in (0, 0). Fox Ciel code a command to it. The command was represented by string *s*. Each character of *s* is one move operation. There are four move operations... | ```python
a,b=map(int,input().split())
ch=input()
x=y=u=d=l=r=0
for z in ch:
if z=='U':
u=u+1
elif z=='D':
d=d+1
elif z=='L':
l=l+1
else:
r=r+1
x=x+r-l
y=y+u-d
if ((x==a)and(y==b)):
print('Yes')
elif (y==b):
if ((y/x)==((b-y)/(a-x))):
pr... | 0 | |
844 | A | Diversity | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"strings"
] | null | null | Calculate the minimum number of characters you need to change in the string *s*, so that it contains at least *k* different letters, or print that it is impossible.
String *s* consists only of lowercase Latin letters, and it is allowed to change characters only to lowercase Latin letters too. | First line of input contains string *s*, consisting only of lowercase Latin letters (1<=≤<=|*s*|<=≤<=1000, |*s*| denotes the length of *s*).
Second line of input contains integer *k* (1<=≤<=*k*<=≤<=26). | Print single line with a minimum number of necessary changes, or the word «impossible» (without quotes) if it is impossible. | [
"yandex\n6\n",
"yahoo\n5\n",
"google\n7\n"
] | [
"0\n",
"1\n",
"impossible\n"
] | In the first test case string contains 6 different letters, so we don't need to change anything.
In the second test case string contains 4 different letters: {'*a*', '*h*', '*o*', '*y*'}. To get 5 different letters it is necessary to change one occurrence of '*o*' to some letter, which doesn't occur in the string, for... | 500 | [
{
"input": "yandex\n6",
"output": "0"
},
{
"input": "yahoo\n5",
"output": "1"
},
{
"input": "google\n7",
"output": "impossible"
},
{
"input": "a\n1",
"output": "0"
},
{
"input": "z\n2",
"output": "impossible"
},
{
"input": "fwgfrwgkuwghfiruhewgirueguhe... | 1,626,774,601 | 2,147,483,647 | PyPy 3 | OK | TESTS | 41 | 93 | 20,172,800 | s=input()
n=int(input())
if(n<=len(s)):
print(max(0,n-len(set(s))))
else:
print('impossible') | Title: Diversity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Calculate the minimum number of characters you need to change in the string *s*, so that it contains at least *k* different letters, or print that it is impossible.
String *s* consists only of lowercase Latin letters, and it... | ```python
s=input()
n=int(input())
if(n<=len(s)):
print(max(0,n-len(set(s))))
else:
print('impossible')
``` | 3 | |
489 | C | Given Length and Sum of Digits... | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should be non-negative integers written in the decimal base without leading zeroes. | The single line of the input contains a pair of integers *m*, *s* (1<=≤<=*m*<=≤<=100,<=0<=≤<=*s*<=≤<=900) — the length and the sum of the digits of the required numbers. | In the output print the pair of the required non-negative integer numbers — first the minimum possible number, then — the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes). | [
"2 15\n",
"3 0\n"
] | [
"69 96\n",
"-1 -1\n"
] | none | 1,500 | [
{
"input": "2 15",
"output": "69 96"
},
{
"input": "3 0",
"output": "-1 -1"
},
{
"input": "2 1",
"output": "10 10"
},
{
"input": "3 10",
"output": "109 910"
},
{
"input": "100 100",
"output": "1000000000000000000000000000000000000000000000000000000000000000000... | 1,679,003,633 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | m, s = map(int, input().split()) # m -- len, s -- sum of digits
def maxx(m, s):
if s <= 0 or s > 9 * m:
return -1
new_num = ''
for i in range(m):
if s > 0:
if s > 9:
new_num += '9'
s -= 9
else:
new_num += s... | Title: Given Length and Sum of Digits...
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should ... | ```python
m, s = map(int, input().split()) # m -- len, s -- sum of digits
def maxx(m, s):
if s <= 0 or s > 9 * m:
return -1
new_num = ''
for i in range(m):
if s > 0:
if s > 9:
new_num += '9'
s -= 9
else:
ne... | 0 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,689,010,574 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | w = input()
length = len(w)
arr = list(w)
if length < 10:
print(length)
else:
print(arr[0] + str(length - 2) + arr[length - 1])
| Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
w = input()
length = len(w)
arr = list(w)
if length < 10:
print(length)
else:
print(arr[0] + str(length - 2) + arr[length - 1])
``` | 0 |
672 | B | Different is Good | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation",
"strings"
] | null | null | A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are different, he wants all substrings of his string *s* to be distinct. Substring is a string formed by some... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the length of the string *s*.
The second line contains the string *s* of length *n* consisting of only lowercase English letters. | If it's impossible to change the string *s* such that all its substring are distinct print -1. Otherwise print the minimum required number of changes. | [
"2\naa\n",
"4\nkoko\n",
"5\nmurat\n"
] | [
"1\n",
"2\n",
"0\n"
] | In the first sample one of the possible solutions is to change the first character to 'b'.
In the second sample, one may change the first character to 'a' and second character to 'b', so the string becomes "abko". | 1,000 | [
{
"input": "2\naa",
"output": "1"
},
{
"input": "4\nkoko",
"output": "2"
},
{
"input": "5\nmurat",
"output": "0"
},
{
"input": "6\nacbead",
"output": "1"
},
{
"input": "7\ncdaadad",
"output": "4"
},
{
"input": "25\npeoaicnbisdocqofsqdpgobpn",
"outp... | 1,679,149,201 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 93 | 2,764,800 | import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n = int(input())
s = list(input().rstrip())
cnt = [0] * 26
for i in s:
cnt[i - 97] += 1
ans = 0
for i in cnt:
ans += max(i - 1, 0)
if n > 26:
ans = -1
print(ans) | Title: Different is Good
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are di... | ```python
import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n = int(input())
s = list(input().rstrip())
cnt = [0] * 26
for i in s:
cnt[i - 97] += 1
ans = 0
for i in cnt:
ans += max(i - 1, 0)
if n > 26:
ans = -1
print(ans)
``` | 3 | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,605,784,031 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 0 | t = int(input())
string = input()
for j in range(1,t):
for i in string[ : :-1]:
if(i=='?' or i=='.'):
continue
elif(i=='a' or i=='e'or i=='i'or i=='o'or i=='u' or i=='A'or i=='E'or i=='I'or i=='O'or i=='U'):
print("YES")
else:
print("NO")
| Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
t = int(input())
string = input()
for j in range(1,t):
for i in string[ : :-1]:
if(i=='?' or i=='.'):
continue
elif(i=='a' or i=='e'or i=='i'or i=='o'or i=='u' or i=='A'or i=='E'or i=='I'or i=='O'or i=='U'):
print("YES")
else:
print("NO")
``` | -1 |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,691,254,480 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | w = input()
if w%2 or w==2: #odd
print('NO')
else:
print('YES')
| Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
w = input()
if w%2 or w==2: #odd
print('NO')
else:
print('YES')
``` | -1 |
489 | C | Given Length and Sum of Digits... | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should be non-negative integers written in the decimal base without leading zeroes. | The single line of the input contains a pair of integers *m*, *s* (1<=≤<=*m*<=≤<=100,<=0<=≤<=*s*<=≤<=900) — the length and the sum of the digits of the required numbers. | In the output print the pair of the required non-negative integer numbers — first the minimum possible number, then — the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes). | [
"2 15\n",
"3 0\n"
] | [
"69 96\n",
"-1 -1\n"
] | none | 1,500 | [
{
"input": "2 15",
"output": "69 96"
},
{
"input": "3 0",
"output": "-1 -1"
},
{
"input": "2 1",
"output": "10 10"
},
{
"input": "3 10",
"output": "109 910"
},
{
"input": "100 100",
"output": "1000000000000000000000000000000000000000000000000000000000000000000... | 1,696,099,535 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | from sys import stdin
stream = None
try:
stream = open('file.txt', 'r')
except:
stream = stdin
def can(m, s):
return s > 0 and s < 9*m
def mirror(num):
str_val = str(num)
return str_val+' '+str_val[::-1]
m, s = [int(i) for i in stream.readline().split()]
base = int('1'*m)
s -= m
... | Title: Given Length and Sum of Digits...
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should ... | ```python
from sys import stdin
stream = None
try:
stream = open('file.txt', 'r')
except:
stream = stdin
def can(m, s):
return s > 0 and s < 9*m
def mirror(num):
str_val = str(num)
return str_val+' '+str_val[::-1]
m, s = [int(i) for i in stream.readline().split()]
base = int('1'*m... | 0 | |
204 | B | Little Elephant and Cards | PROGRAMMING | 1,500 | [
"binary search",
"data structures"
] | null | null | The Little Elephant loves to play with color cards.
He has *n* cards, each has exactly two colors (the color of the front side and the color of the back side). Initially, all the cards lay on the table with the front side up. In one move the Little Elephant can turn any card to the other side. The Little Elephant thin... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of the cards. The following *n* lines contain the description of all cards, one card per line. The cards are described by a pair of positive integers not exceeding 109 — colors of both sides. The first number in a line is the color of the fro... | On a single line print a single integer — the sought minimum number of moves. If it is impossible to make the set funny, print -1. | [
"3\n4 7\n4 7\n7 4\n",
"5\n4 7\n7 4\n2 11\n9 7\n1 1\n"
] | [
"0\n",
"2\n"
] | In the first sample there initially are three cards lying with colors 4, 4, 7. Since two of the three cards are of the same color 4, you do not need to change anything, so the answer is 0.
In the second sample, you can turn the first and the fourth cards. After that three of the five cards will be of color 7. | 500 | [
{
"input": "3\n4 7\n4 7\n7 4",
"output": "0"
},
{
"input": "5\n4 7\n7 4\n2 11\n9 7\n1 1",
"output": "2"
},
{
"input": "1\n1 1",
"output": "0"
},
{
"input": "2\n1 1\n1 1",
"output": "0"
},
{
"input": "7\n1 2\n2 3\n3 4\n4 5\n5 6\n6 7\n7 8",
"output": "-1"
},
... | 1,606,311,103 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 186 | 307,200 | n=int(input())
m={}
v=[]
for i in range(n):
a=input().split()
v.append(a)
m[a[0]]=[0,0]
m[a[1]]=[0,0]
for i in range(n):
m[v[i][0]][0]+=1
m[v[i][1]][1]+=1
min=99999999
for i in m:
if sum(m[i])>=(n+1)//2:
if (n+1)//2-m[i][0]<min:
if (n+1)//2-m[i][0]<=0... | Title: Little Elephant and Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves to play with color cards.
He has *n* cards, each has exactly two colors (the color of the front side and the color of the back side). Initially, all the cards lay on the table with t... | ```python
n=int(input())
m={}
v=[]
for i in range(n):
a=input().split()
v.append(a)
m[a[0]]=[0,0]
m[a[1]]=[0,0]
for i in range(n):
m[v[i][0]][0]+=1
m[v[i][1]][1]+=1
min=99999999
for i in m:
if sum(m[i])>=(n+1)//2:
if (n+1)//2-m[i][0]<min:
if (n+1)//2-... | 0 | |
740 | B | Alyona and flowers | PROGRAMMING | 1,200 | [
"constructive algorithms"
] | null | null | Little Alyona is celebrating Happy Birthday! Her mother has an array of *n* flowers. Each flower has some mood, the mood of *i*-th flower is *a**i*. The mood can be positive, zero or negative.
Let's define a subarray as a segment of consecutive flowers. The mother suggested some set of subarrays. Alyona wants to choos... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of flowers and the number of subarrays suggested by the mother.
The second line contains the flowers moods — *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=100<=≤<=*a**i*<=≤<=100).
The next *m* lines contain the description of the ... | Print single integer — the maximum possible value added to the Alyona's happiness. | [
"5 4\n1 -2 1 3 -4\n1 2\n4 5\n3 4\n1 4\n",
"4 3\n1 2 3 4\n1 3\n2 4\n1 1\n",
"2 2\n-1 -2\n1 1\n1 2\n"
] | [
"7\n",
"16\n",
"0\n"
] | The first example is the situation described in the statements.
In the second example Alyona should choose all subarrays.
The third example has answer 0 because Alyona can choose none of the subarrays. | 1,000 | [
{
"input": "5 4\n1 -2 1 3 -4\n1 2\n4 5\n3 4\n1 4",
"output": "7"
},
{
"input": "4 3\n1 2 3 4\n1 3\n2 4\n1 1",
"output": "16"
},
{
"input": "2 2\n-1 -2\n1 1\n1 2",
"output": "0"
},
{
"input": "5 6\n1 1 1 -1 0\n2 4\n1 3\n4 5\n1 5\n1 4\n4 5",
"output": "8"
},
{
"inpu... | 1,479,921,957 | 3,057 | Python 3 | OK | TESTS | 53 | 62 | 0 | n,m=map(int,input().split())
d=input().split()
d=[int(x) for x in d]
c=0
for i in range(m):
l=input().split()
l=[int(x) for x in l]
k=0
for j in range(l[0]-1,l[1]):
k+=d[j]
if k>0:
c+=k
print(c)
| Title: Alyona and flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Alyona is celebrating Happy Birthday! Her mother has an array of *n* flowers. Each flower has some mood, the mood of *i*-th flower is *a**i*. The mood can be positive, zero or negative.
Let's define a subarra... | ```python
n,m=map(int,input().split())
d=input().split()
d=[int(x) for x in d]
c=0
for i in range(m):
l=input().split()
l=[int(x) for x in l]
k=0
for j in range(l[0]-1,l[1]):
k+=d[j]
if k>0:
c+=k
print(c)
``` | 3 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,682,973,783 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 60 | 0 | s,i = input(), 0
while i < len(s):
if s[i] == '.':
print(0, end = '')
i+=1
if s[i] == '-':
if s[i+1] == '.':
print(1, end = '')
i += 2
else:
print(2, end = '')
i+=2 | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
s,i = input(), 0
while i < len(s):
if s[i] == '.':
print(0, end = '')
i+=1
if s[i] == '-':
if s[i+1] == '.':
print(1, end = '')
i += 2
else:
print(2, end = '')
i+=2
``` | -1 |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the... | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,691,606,894 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | import math
N, M, A = input().split()
n = int(N)
m = int(M)
a = int(A)
print(math.ceil(m/a)*math.ceil(n/a)) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each ... | ```python
import math
N, M, A = input().split()
n = int(N)
m = int(M)
a = int(A)
print(math.ceil(m/a)*math.ceil(n/a))
``` | 3.977 |
459 | B | Pashmak and Flowers | PROGRAMMING | 1,300 | [
"combinatorics",
"implementation",
"sortings"
] | null | null | Pashmak decided to give Parmida a pair of flowers from the garden. There are *n* flowers in the garden and the *i*-th of them has a beauty number *b**i*. Parmida is a very strange girl so she doesn't want to have the two most beautiful flowers necessarily. She wants to have those pairs of flowers that their beauty diff... | The first line of the input contains *n* (2<=≤<=*n*<=≤<=2·105). In the next line there are *n* space-separated integers *b*1, *b*2, ..., *b**n* (1<=≤<=*b**i*<=≤<=109). | The only line of output should contain two integers. The maximum beauty difference and the number of ways this may happen, respectively. | [
"2\n1 2\n",
"3\n1 4 5\n",
"5\n3 1 2 3 1\n"
] | [
"1 1",
"4 1",
"2 4"
] | In the third sample the maximum beauty difference is 2 and there are 4 ways to do this:
1. choosing the first and the second flowers; 1. choosing the first and the fifth flowers; 1. choosing the fourth and the second flowers; 1. choosing the fourth and the fifth flowers. | 500 | [
{
"input": "2\n1 2",
"output": "1 1"
},
{
"input": "3\n1 4 5",
"output": "4 1"
},
{
"input": "5\n3 1 2 3 1",
"output": "2 4"
},
{
"input": "2\n1 1",
"output": "0 1"
},
{
"input": "3\n1 1 1",
"output": "0 3"
},
{
"input": "4\n1 1 1 1",
"output": "0 ... | 1,694,049,871 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 108 | 17,100,800 | input()
A=list(map(int, input().split()))
m=min(A)
n=max(A)
k=n-m
r=A.count(m)*A.count(n)
print(str(k)+' '+str(r)) | Title: Pashmak and Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pashmak decided to give Parmida a pair of flowers from the garden. There are *n* flowers in the garden and the *i*-th of them has a beauty number *b**i*. Parmida is a very strange girl so she doesn't want to have th... | ```python
input()
A=list(map(int, input().split()))
m=min(A)
n=max(A)
k=n-m
r=A.count(m)*A.count(n)
print(str(k)+' '+str(r))
``` | 0 | |
549 | A | Face Detection | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2<... | The first line contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the height and the width of the image, respectively.
Next *n* lines define the image. Each line contains *m* lowercase Latin letters. | In the single line print the number of faces on the image. | [
"4 4\nxxxx\nxfax\nxcex\nxxxx\n",
"4 2\nxx\ncf\nae\nxx\n",
"2 3\nfac\ncef\n",
"1 4\nface\n"
] | [
"1\n",
"1\n",
"2\n",
"0\n"
] | In the first sample the image contains a single face, located in a square with the upper left corner at the second line and the second column:
In the second sample the image also contains exactly one face, its upper left corner is at the second row and the first column.
In the third sample two faces are shown:
In ... | 250 | [
{
"input": "4 4\nxxxx\nxfax\nxcex\nxxxx",
"output": "1"
},
{
"input": "4 2\nxx\ncf\nae\nxx",
"output": "1"
},
{
"input": "2 3\nfac\ncef",
"output": "2"
},
{
"input": "1 4\nface",
"output": "0"
},
{
"input": "5 5\nwmmwn\nlurcm\nkeetd\nfokon\ncxxgx",
"output": "... | 1,666,624,613 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 61 | 2,764,800 | n, m = int(input())
charr = ['f', 'a', 'c', 'e']
strr = []
for i in range(n):
strr.append(str(input()))
count = 0
for i in range(n - 1):
for j in range(m - 1):
if strr[i][j] != 'x':
count1 = 0
ls = [strr[i][j], strr[i + 1][j], strr[i + 1][j + 1], strr[i][j + 1]]
... | Title: Face Detection
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem a... | ```python
n, m = int(input())
charr = ['f', 'a', 'c', 'e']
strr = []
for i in range(n):
strr.append(str(input()))
count = 0
for i in range(n - 1):
for j in range(m - 1):
if strr[i][j] != 'x':
count1 = 0
ls = [strr[i][j], strr[i + 1][j], strr[i + 1][j + 1], strr[i][j... | -1 | |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,659,529,746 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 124 | 0 | from math import sqrt
x, y, z = map(int, input().split())
a = sqrt (int((x * y) / z))
b = sqrt (int((x * z) / y))
c = sqrt (int((y * z) / x))
print(int((a + b + c) * 4)) | Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
from math import sqrt
x, y, z = map(int, input().split())
a = sqrt (int((x * y) / z))
b = sqrt (int((x * z) / y))
c = sqrt (int((y * z) / x))
print(int((a + b + c) * 4))
``` | 3 | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,667,992,558 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 46 | 0 | n = input().split()
n[0] = int(n[0])
n[1] = int(n[1])
m = input().split()
for i in range(0, n[0]):
m[i] = int(m[i])
m.sort()
s = 0
for j in range(0, n[0]):
p = 5 - m[j]
if p >= n[1]:
s = s + 1
c = s//3
print(c) | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
n = input().split()
n[0] = int(n[0])
n[1] = int(n[1])
m = input().split()
for i in range(0, n[0]):
m[i] = int(m[i])
m.sort()
s = 0
for j in range(0, n[0]):
p = 5 - m[j]
if p >= n[1]:
s = s + 1
c = s//3
print(c)
``` | 3 | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,655,703,089 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 46 | 0 | n=int(input())
if n%2!=0:
print(0)
elif n<6:
print(0)
else:
c=0
n=n//2
c=n-1
print(c//2) | Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
n=int(input())
if n%2!=0:
print(0)
elif n<6:
print(0)
else:
c=0
n=n//2
c=n-1
print(c//2)
``` | 3 | |
34 | A | Reconnaissance 2 | PROGRAMMING | 800 | [
"implementation"
] | A. Reconnaissance 2 | 2 | 256 | *n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a ... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). The soldier heights are given in clockwise or counterclockwise direction. | Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle. | [
"5\n10 12 13 15 10\n",
"4\n10 20 30 40\n"
] | [
"5 1\n",
"1 2\n"
] | none | 500 | [
{
"input": "5\n10 12 13 15 10",
"output": "5 1"
},
{
"input": "4\n10 20 30 40",
"output": "1 2"
},
{
"input": "6\n744 359 230 586 944 442",
"output": "2 3"
},
{
"input": "5\n826 747 849 687 437",
"output": "1 2"
},
{
"input": "5\n999 999 993 969 999",
"output"... | 1,632,896,859 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 124 | 6,963,200 | a=input();a,b,c=list(map(int,input().split())),1000,0;a.append(a[0])
for i in range(len(a)-1):
if abs(a[i]-a[i+1])<b:
b,c=abs(a[i]-a[i+1]),i
if c-len(a)+2:
print(c+1,c+2)
else:
print(c+1,1) | Title: Reconnaissance 2
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
*n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So... | ```python
a=input();a,b,c=list(map(int,input().split())),1000,0;a.append(a[0])
for i in range(len(a)-1):
if abs(a[i]-a[i+1])<b:
b,c=abs(a[i]-a[i+1]),i
if c-len(a)+2:
print(c+1,c+2)
else:
print(c+1,1)
``` | 3.95603 |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,642,310,047 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | if __name__ == "__main__":
r, c = input().strip().split()
r = int(r)
c = int(c)
count = 0
cake = []
for i in range(r):
temp = [char for char in input().strip()]
if 'S' not in temp:
count += c
r -= 1
else:
cake.append(temp)
for i in ... | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
if __name__ == "__main__":
r, c = input().strip().split()
r = int(r)
c = int(c)
count = 0
cake = []
for i in range(r):
temp = [char for char in input().strip()]
if 'S' not in temp:
count += c
r -= 1
else:
cake.append(temp)
... | 3 | |
770 | B | Maximize Sum of Digits | PROGRAMMING | 1,300 | [
"*special",
"implementation",
"math"
] | null | null | Anton has the integer *x*. He is interested what positive integer, which doesn't exceed *x*, has the maximum sum of digits.
Your task is to help Anton and to find the integer that interests him. If there are several such integers, determine the biggest of them. | The first line contains the positive integer *x* (1<=≤<=*x*<=≤<=1018) — the integer which Anton has. | Print the positive integer which doesn't exceed *x* and has the maximum sum of digits. If there are several such integers, print the biggest of them. Printed integer must not contain leading zeros. | [
"100\n",
"48\n",
"521\n"
] | [
"99\n",
"48\n",
"499\n"
] | none | 1,000 | [
{
"input": "100",
"output": "99"
},
{
"input": "48",
"output": "48"
},
{
"input": "521",
"output": "499"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "3"
},
{
"input": "39188",
"output":... | 1,658,183,045 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 278 | 62 | 0 | import sys
input = sys.stdin.readline
x = input()[:-1]
n = len(x)
d = [int(x)]
for i in range(1, n+1):
d.append(int(str(int(x[:i])-1) + '9'*(n-i)))
d.sort(reverse=True)
for i in range(len(d)):
if d[i] <= int(x):
c = sum([int(a) for a in str(d[i])])
d[i] = [c, d[i]]
c = max(i fo... | Title: Maximize Sum of Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton has the integer *x*. He is interested what positive integer, which doesn't exceed *x*, has the maximum sum of digits.
Your task is to help Anton and to find the integer that interests him. If there are sev... | ```python
import sys
input = sys.stdin.readline
x = input()[:-1]
n = len(x)
d = [int(x)]
for i in range(1, n+1):
d.append(int(str(int(x[:i])-1) + '9'*(n-i)))
d.sort(reverse=True)
for i in range(len(d)):
if d[i] <= int(x):
c = sum([int(a) for a in str(d[i])])
d[i] = [c, d[i]]
c ... | 3 | |
496 | A | Minimum Difficulty | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Mike is trying rock climbing but he is awful at it.
There are *n* holds on the wall, *i*-th hold is at height *a**i* off the ground. Besides, let the sequence *a**i* increase, that is, *a**i*<=<<=*a**i*<=+<=1 for all *i* from 1 to *n*<=-<=1; we will call such sequence a track. Mike thinks that the track *a*1, ...,... | The first line contains a single integer *n* (3<=≤<=*n*<=≤<=100) — the number of holds.
The next line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=1000), where *a**i* is the height where the hold number *i* hangs. The sequence *a**i* is increasing (i.e. each element except for the first one is strict... | Print a single number — the minimum difficulty of the track after removing a single hold. | [
"3\n1 4 6\n",
"5\n1 2 3 4 5\n",
"5\n1 2 3 7 8\n"
] | [
"5\n",
"2\n",
"4\n"
] | In the first sample you can remove only the second hold, then the sequence looks like (1, 6), the maximum difference of the neighboring elements equals 5.
In the second test after removing every hold the difficulty equals 2.
In the third test you can obtain sequences (1, 3, 7, 8), (1, 2, 7, 8), (1, 2, 3, 8), for whic... | 500 | [
{
"input": "3\n1 4 6",
"output": "5"
},
{
"input": "5\n1 2 3 4 5",
"output": "2"
},
{
"input": "5\n1 2 3 7 8",
"output": "4"
},
{
"input": "3\n1 500 1000",
"output": "999"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "2"
},
{
"input": "10\n1 4 9... | 1,418,834,497 | 697 | Python 3 | OK | TESTS | 19 | 61 | 0 | n, a = int(input()), list(map(int, input().split()))
ans = 20000
for i in range(1, n - 1):
b = a[:i] + a[i + 1:]
ans = min(ans, max(b[j + 1] - b[j] for j in range(n - 2)))
print(ans)
| Title: Minimum Difficulty
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mike is trying rock climbing but he is awful at it.
There are *n* holds on the wall, *i*-th hold is at height *a**i* off the ground. Besides, let the sequence *a**i* increase, that is, *a**i*<=<<=*a**i*<=+<=1 fo... | ```python
n, a = int(input()), list(map(int, input().split()))
ans = 20000
for i in range(1, n - 1):
b = a[:i] + a[i + 1:]
ans = min(ans, max(b[j + 1] - b[j] for j in range(n - 2)))
print(ans)
``` | 3 | |
493 | B | Vasya and Wrestling | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers are equal, the wrestler whose sequence of points is lexicographically greater, wins.
If the sequences of... | The first line contains number *n* — the number of techniques that the wrestlers have used (1<=≤<=*n*<=≤<=2·105).
The following *n* lines contain integer numbers *a**i* (|*a**i*|<=≤<=109, *a**i*<=≠<=0). If *a**i* is positive, that means that the first wrestler performed the technique that was awarded with *a**i* poin... | If the first wrestler wins, print string "first", otherwise print "second" | [
"5\n1\n2\n-3\n-4\n3\n",
"3\n-1\n-2\n3\n",
"2\n4\n-4\n"
] | [
"second\n",
"first\n",
"second\n"
] | Sequence *x* = *x*<sub class="lower-index">1</sub>*x*<sub class="lower-index">2</sub>... *x*<sub class="lower-index">|*x*|</sub> is lexicographically larger than sequence *y* = *y*<sub class="lower-index">1</sub>*y*<sub class="lower-index">2</sub>... *y*<sub class="lower-index">|*y*|</sub>, if either |*x*| > |... | 1,000 | [
{
"input": "5\n1\n2\n-3\n-4\n3",
"output": "second"
},
{
"input": "3\n-1\n-2\n3",
"output": "first"
},
{
"input": "2\n4\n-4",
"output": "second"
},
{
"input": "7\n1\n2\n-3\n4\n5\n-6\n7",
"output": "first"
},
{
"input": "14\n1\n2\n3\n4\n5\n6\n7\n-8\n-9\n-10\n-11\n-... | 1,624,125,216 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 11,571,200 | s1 = ''
s2 = ''
cnt1 = 0
cnt2 = 0
last = None
n = int(input())
for i in range(n):
x = int(input())
if x > 0:
s1 += str(x)
cnt1 += x
last = 0
else:
x = abs(x)
s2 += str(x)
cnt2 += x
last = 1
if cnt1 > cnt2:
print('first')
elif cnt... | Title: Vasya and Wrestling
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers ... | ```python
s1 = ''
s2 = ''
cnt1 = 0
cnt2 = 0
last = None
n = int(input())
for i in range(n):
x = int(input())
if x > 0:
s1 += str(x)
cnt1 += x
last = 0
else:
x = abs(x)
s2 += str(x)
cnt2 += x
last = 1
if cnt1 > cnt2:
print('first')... | 0 | |
820 | A | Mister B and Book Reading | PROGRAMMING | 900 | [
"implementation"
] | null | null | Mister B once received a gift: it was a book about aliens, which he started read immediately. This book had *c* pages.
At first day Mister B read *v*0 pages, but after that he started to speed up. Every day, starting from the second, he read *a* pages more than on the previous day (at first day he read *v*0 pages, at ... | First and only line contains five space-separated integers: *c*, *v*0, *v*1, *a* and *l* (1<=≤<=*c*<=≤<=1000, 0<=≤<=*l*<=<<=*v*0<=≤<=*v*1<=≤<=1000, 0<=≤<=*a*<=≤<=1000) — the length of the book in pages, the initial reading speed, the maximum reading speed, the acceleration in reading speed and the number of pages fo... | Print one integer — the number of days Mister B needed to finish the book. | [
"5 5 10 5 4\n",
"12 4 12 4 1\n",
"15 1 100 0 0\n"
] | [
"1\n",
"3\n",
"15\n"
] | In the first sample test the book contains 5 pages, so Mister B read it right at the first day.
In the second sample test at first day Mister B read pages number 1 - 4, at second day — 4 - 11, at third day — 11 - 12 and finished the book.
In third sample test every day Mister B read 1 page of the book, so he finished... | 500 | [
{
"input": "5 5 10 5 4",
"output": "1"
},
{
"input": "12 4 12 4 1",
"output": "3"
},
{
"input": "15 1 100 0 0",
"output": "15"
},
{
"input": "1 1 1 0 0",
"output": "1"
},
{
"input": "1000 999 1000 1000 998",
"output": "2"
},
{
"input": "1000 2 2 5 1",
... | 1,570,429,127 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 26 | 109 | 0 | def MisterBandBookReading(c,v0,v1,a,l):
n = 0
cntOfPagesRead = 0
while cntOfPagesRead<c:
PagesRead = v0 + n * a
if n!=0:
PagesRead -= l
if PagesRead <= v1:
cntOfPagesRead += PagesRead
else:
cntOfPagesRead += (v1 - l)
n+=1
return n
c,v0,v1,a,l = [int(x) for x in input().split... | Title: Mister B and Book Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mister B once received a gift: it was a book about aliens, which he started read immediately. This book had *c* pages.
At first day Mister B read *v*0 pages, but after that he started to speed up. Every day, ... | ```python
def MisterBandBookReading(c,v0,v1,a,l):
n = 0
cntOfPagesRead = 0
while cntOfPagesRead<c:
PagesRead = v0 + n * a
if n!=0:
PagesRead -= l
if PagesRead <= v1:
cntOfPagesRead += PagesRead
else:
cntOfPagesRead += (v1 - l)
n+=1
return n
c,v0,v1,a,l = [int(x) for x in inp... | 0 | |
266 | B | Queue at the School | PROGRAMMING | 800 | [
"constructive algorithms",
"graph matchings",
"implementation",
"shortest paths"
] | null | null | During the break the schoolchildren, boys and girls, formed a queue of *n* people in the canteen. Initially the children stood in the order they entered the canteen. However, after a while the boys started feeling awkward for standing in front of the girls in the queue and they started letting the girls move forward ea... | The first line contains two integers *n* and *t* (1<=≤<=*n*,<=*t*<=≤<=50), which represent the number of children in the queue and the time after which the queue will transform into the arrangement you need to find.
The next line contains string *s*, which represents the schoolchildren's initial arrangement. If the *... | Print string *a*, which describes the arrangement after *t* seconds. If the *i*-th position has a boy after the needed time, then the *i*-th character *a* must equal "B", otherwise it must equal "G". | [
"5 1\nBGGBG\n",
"5 2\nBGGBG\n",
"4 1\nGGGB\n"
] | [
"GBGGB\n",
"GGBGB\n",
"GGGB\n"
] | none | 500 | [
{
"input": "5 1\nBGGBG",
"output": "GBGGB"
},
{
"input": "5 2\nBGGBG",
"output": "GGBGB"
},
{
"input": "4 1\nGGGB",
"output": "GGGB"
},
{
"input": "2 1\nBB",
"output": "BB"
},
{
"input": "2 1\nBG",
"output": "GB"
},
{
"input": "6 2\nBBGBBG",
"outpu... | 1,697,054,683 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | def queue():
n=int(input())
t=int(input())
c=str(input())
i=0
for j in range (t):
s=""
while i<n:
if i<n-1 and c[i]=="B" and c[i+1]=="G" :
s=s+"G"+"B"
i=i+2
else:
s=s+c[i]
i=i+1
... | Title: Queue at the School
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
During the break the schoolchildren, boys and girls, formed a queue of *n* people in the canteen. Initially the children stood in the order they entered the canteen. However, after a while the boys started feeling a... | ```python
def queue():
n=int(input())
t=int(input())
c=str(input())
i=0
for j in range (t):
s=""
while i<n:
if i<n-1 and c[i]=="B" and c[i+1]=="G" :
s=s+"G"+"B"
i=i+2
else:
s=s+c[i]
i... | -1 | |
867 | A | Between the Offices | PROGRAMMING | 800 | [
"implementation"
] | null | null | As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't rem... | The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given... | Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower). | [
"4\nFSSF\n",
"2\nSF\n",
"10\nFFFFFFFFFF\n",
"10\nSSFFSFFSFF\n"
] | [
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you staye... | 500 | [
{
"input": "4\nFSSF",
"output": "NO"
},
{
"input": "2\nSF",
"output": "YES"
},
{
"input": "10\nFFFFFFFFFF",
"output": "NO"
},
{
"input": "10\nSSFFSFFSFF",
"output": "YES"
},
{
"input": "20\nSFSFFFFSSFFFFSSSSFSS",
"output": "NO"
},
{
"input": "20\nSSFFF... | 1,587,021,440 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 124 | 0 | n=int(input())
a=input()
if (a[0]=='S' and a[-1]=='F'):
print('YES')
else:
print('NO') | Title: Between the Offices
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Franci... | ```python
n=int(input())
a=input()
if (a[0]=='S' and a[-1]=='F'):
print('YES')
else:
print('NO')
``` | 3 | |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,676,975,213 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 20 | 2,000 | 9,932,800 | # your code goes here
import math
s =input()
s=s.lstrip('0')
ans=''
for i in range(len(s)):
new_s = s[:i]+s[i+1:]
if new_s>ans:
ans=new_s
print(ans)
| Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
# your code goes here
import math
s =input()
s=s.lstrip('0')
ans=''
for i in range(len(s)):
new_s = s[:i]+s[i+1:]
if new_s>ans:
ans=new_s
print(ans)
``` | 0 | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,666,158,989 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 49 | 62 | 1,740,800 | a=[*map(int,input().split())]
b=input()
x=0
for i in b:
x+=a[int(i)-1]
print(x) | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
a=[*map(int,input().split())]
b=input()
x=0
for i in b:
x+=a[int(i)-1]
print(x)
``` | 3 | |
114 | A | Cifera | PROGRAMMING | 1,000 | [
"math"
] | null | null | When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousand and "tma tmyschaya" (which literally means "the tma of tmas") used to stand for a million... | The first input line contains integer number *k*, the second line contains integer number *l* (2<=≤<=*k*,<=*l*<=≤<=231<=-<=1). | You should print in the first line of the output "YES", if the number belongs to the set petriciumus cifera and otherwise print "NO". If the number belongs to the set, then print on the seconds line the only number — the importance of number *l*. | [
"5\n25\n",
"3\n8\n"
] | [
"YES\n1\n",
"NO\n"
] | none | 500 | [
{
"input": "5\n25",
"output": "YES\n1"
},
{
"input": "3\n8",
"output": "NO"
},
{
"input": "123\n123",
"output": "YES\n0"
},
{
"input": "99\n970300",
"output": "NO"
},
{
"input": "1000\n6666666",
"output": "NO"
},
{
"input": "59\n3571",
"output": "N... | 1,592,822,709 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 186 | 0 | k=int(input())
l=int(input())
flag=0
i=0
while k**i<l:
i+=1
if l>k**i:
print("NO")
else:
print('YES')
print(i-1) | Title: Cifera
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousa... | ```python
k=int(input())
l=int(input())
flag=0
i=0
while k**i<l:
i+=1
if l>k**i:
print("NO")
else:
print('YES')
print(i-1)
``` | 0 | |
1,008 | B | Turn the Rectangles | PROGRAMMING | 1,000 | [
"greedy",
"sortings"
] | null | null | There are $n$ rectangles in a row. You can either turn each rectangle by $90$ degrees or leave it as it is. If you turn a rectangle, its width will be height, and its height will be width. Notice that you can turn any number of rectangles, you also can turn all or none of them. You can not change the order of the recta... | The first line contains a single integer $n$ ($1 \leq n \leq 10^5$) — the number of rectangles.
Each of the next $n$ lines contains two integers $w_i$ and $h_i$ ($1 \leq w_i, h_i \leq 10^9$) — the width and the height of the $i$-th rectangle. | Print "YES" (without quotes) if there is a way to make the rectangles go in order of non-ascending height, otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"3\n3 4\n4 6\n3 5\n",
"2\n3 4\n5 5\n"
] | [
"YES\n",
"NO\n"
] | In the first test, you can rotate the second and the third rectangles so that the heights will be [4, 4, 3].
In the second test, there is no way the second rectangle will be not higher than the first one. | 1,000 | [
{
"input": "3\n3 4\n4 6\n3 5",
"output": "YES"
},
{
"input": "2\n3 4\n5 5",
"output": "NO"
},
{
"input": "10\n4 3\n1 1\n6 5\n4 5\n2 4\n9 5\n7 9\n9 2\n4 10\n10 1",
"output": "NO"
},
{
"input": "10\n241724251 76314740\n80658193 177743680\n213953908 406274173\n485639518 85918805... | 1,678,455,819 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 21 | 280 | 0 | n=int(input())
c=0
for i in range(n):
w,h=map(int,input().split())
if c==0:
c=max(w,h)
else:
if max(w,h)<=c:
c=max(w,h)
elif min(w,h)<=c:
c=max(w,h)
else:
print('NO')
exit(0)
print('YES') | Title: Turn the Rectangles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are $n$ rectangles in a row. You can either turn each rectangle by $90$ degrees or leave it as it is. If you turn a rectangle, its width will be height, and its height will be width. Notice that you can turn a... | ```python
n=int(input())
c=0
for i in range(n):
w,h=map(int,input().split())
if c==0:
c=max(w,h)
else:
if max(w,h)<=c:
c=max(w,h)
elif min(w,h)<=c:
c=max(w,h)
else:
print('NO')
exit(0)
print('YES')
``` | 0 | |
27 | A | Next Test | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | A. Next Test | 2 | 256 | «Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the next test will have, the system suggests the default value of the index. It is calculated ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=3000) — the amount of previously added tests. The second line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3000) — indexes of these tests. | Output the required default value for the next test index. | [
"3\n1 7 2\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "1\n1",
"output": "2"
},
{
"input": "2\n2 1",
"output": "3"
},
{
"input": "3\n3 4 1",
"output": "2"
},
{
"input": "4\n6 4 3 5",
"output": "1"
},
{
"input": "5\n3 2 1 7 4",
"output": "5"
},
{
"input": "6\n4 1 2 5 3 7",
"output": "6"
},
... | 1,596,001,638 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 280 | 21,504,000 | n = int(input())
a = list(map(int,input().split()))
a.sort()
ans, f = 0, 0
if a[0]>1:
print(1)
else:
for i in range(1,n):
if a[i]!=(a[i-1]+1):
ans = a[i-1]+1
f = 1
break
if f==1:
print(ans)
else:
print(a[-1]+1) | Title: Next Test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
«Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the... | ```python
n = int(input())
a = list(map(int,input().split()))
a.sort()
ans, f = 0, 0
if a[0]>1:
print(1)
else:
for i in range(1,n):
if a[i]!=(a[i-1]+1):
ans = a[i-1]+1
f = 1
break
if f==1:
print(ans)
else:
print(a[-1]+1)
``` | 3.889946 |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the... | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,657,336,292 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | nums = [int(a) for a in input().split()]
n = nums[0]
m = nums[1]
a = nums[2]
print((n//a) * (m//a)) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each ... | ```python
nums = [int(a) for a in input().split()]
n = nums[0]
m = nums[1]
a = nums[2]
print((n//a) * (m//a))
``` | 0 |
375 | A | Divisible by Seven | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.
Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resu... | The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 106 characters. | Print a number in the decimal notation without leading zeroes — the result of the permutation.
If it is impossible to rearrange the digits of the number *a* in the required manner, print 0. | [
"1689\n",
"18906\n"
] | [
"1869\n",
"18690\n"
] | none | 500 | [
{
"input": "1689",
"output": "1869"
},
{
"input": "18906",
"output": "18690"
},
{
"input": "2419323689",
"output": "2432391689"
},
{
"input": "8589157262",
"output": "5857221986"
},
{
"input": "2717172350336955863014903670481525170997949309274087058935108848979319... | 1,613,935,531 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 13,824,000 | #prefix = [1869,6189,1689,6198,1698,9861,1896]
# 0 5 3 1 6 4 2
prefix = ["1869", "6198", "1896", "1689", "9861", "6189","1698"]
strs = input()
dicts = {}
for i in strs:
if i not in dicts:
dicts[i] = 1
else:
dicts[i] += 1
left = []
right = []
if "0" ... | Title: Divisible by Seven
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.
Number *a* doesn't ... | ```python
#prefix = [1869,6189,1689,6198,1698,9861,1896]
# 0 5 3 1 6 4 2
prefix = ["1869", "6198", "1896", "1689", "9861", "6189","1698"]
strs = input()
dicts = {}
for i in strs:
if i not in dicts:
dicts[i] = 1
else:
dicts[i] += 1
left = []
right = [... | 0 | |
886 | B | Vlad and Cafes | PROGRAMMING | 1,000 | [] | null | null | Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research.
First of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes... | In first line there is one integer *n* (1<=≤<=*n*<=≤<=2·105) — number of cafes indices written by Vlad.
In second line, *n* numbers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=2·105) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, ... | Print one integer — index of the cafe that Vlad hasn't visited for as long as possible. | [
"5\n1 3 2 1 2\n",
"6\n2 1 2 2 4 1\n"
] | [
"3\n",
"2\n"
] | In first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer.
In second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with in... | 1,000 | [
{
"input": "5\n1 3 2 1 2",
"output": "3"
},
{
"input": "6\n2 1 2 2 4 1",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n200000",
"output": "200000"
},
{
"input": "2\n2018 2017",
"output": "2018"
},
{
"input": "5\n100 1000 1000 1000... | 1,696,340,596 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n = int(input())
a = list(map(int, input().split()))
s = set(a)
for i in range(len(a) -1, -1, -1):
if a[i] in s:
s.remove(a[i])
elif a[i] == a[i+1]:
continue
else:
print(i+1)
break | Title: Vlad and Cafes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research... | ```python
n = int(input())
a = list(map(int, input().split()))
s = set(a)
for i in range(len(a) -1, -1, -1):
if a[i] in s:
s.remove(a[i])
elif a[i] == a[i+1]:
continue
else:
print(i+1)
break
``` | 0 | |
304 | A | Pythagorean Theorem II | PROGRAMMING | 1,200 | [
"brute force",
"math"
] | null | null | In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the s... | The only line contains one integer *n* (1<=≤<=*n*<=≤<=104) as we mentioned above. | Print a single integer — the answer to the problem. | [
"5\n",
"74\n"
] | [
"1\n",
"35\n"
] | none | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "74",
"output": "35"
},
{
"input": "1000",
"output": "881"
},
{
"input": "586",
"output": "472"
},
{
"input": "2",
"output": "0"
},
{
"input": "362",
"output": "258"
},
{
"input": "778",
"outp... | 1,697,047,265 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import java.util.Scanner;
public class even_odd {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int count = 0;
for (int i = 1; i < n - 1; i++) {
for (int j = i + 1; j < n; j++) {
int req = i *... | Title: Pythagorean Theorem II
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the squar... | ```python
import java.util.Scanner;
public class even_odd {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int count = 0;
for (int i = 1; i < n - 1; i++) {
for (int j = i + 1; j < n; j++) {
int... | -1 | |
0 | none | none | none | 0 | [
"none"
] | null | null | It is a balmy spring afternoon, and Farmer John's *n* cows are ruminating about link-cut cacti in their stalls. The cows, labeled 1 through *n*, are arranged so that the *i*-th cow occupies the *i*-th stall from the left. However, Elsie, after realizing that she will forever live in the shadows beyond Bessie's limeligh... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100<=000) — the number of cows and the length of Farmer John's nap, respectively. | Output a single integer, the maximum messiness that the Mischievous Mess Makers can achieve by performing no more than *k* swaps. | [
"5 2\n",
"1 10\n"
] | [
"10\n",
"0\n"
] | In the first sample, the Mischievous Mess Makers can swap the cows in the stalls 1 and 5 during the first minute, then the cows in stalls 2 and 4 during the second minute. This reverses the arrangement of cows, giving us a total messiness of 10.
In the second sample, there is only one cow, so the maximum possible mess... | 0 | [
{
"input": "5 2",
"output": "10"
},
{
"input": "1 10",
"output": "0"
},
{
"input": "100000 2",
"output": "399990"
},
{
"input": "1 1",
"output": "0"
},
{
"input": "8 3",
"output": "27"
},
{
"input": "7 1",
"output": "11"
},
{
"input": "1000... | 1,464,935,891 | 2,147,483,647 | Python 3 | OK | TESTS | 92 | 62 | 4,812,800 | n,k = [int(i) for i in input().split()]
if n == 1:
print(0)
elif k>=(n//2):
print(((n*(n-1))//2))
else:
print(2*(n-k)*k-k)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is a balmy spring afternoon, and Farmer John's *n* cows are ruminating about link-cut cacti in their stalls. The cows, labeled 1 through *n*, are arranged so that the *i*-th cow occupies the *i*-th stall from the left. However,... | ```python
n,k = [int(i) for i in input().split()]
if n == 1:
print(0)
elif k>=(n//2):
print(((n*(n-1))//2))
else:
print(2*(n-k)*k-k)
``` | 3 | |
499 | A | Watching a movie | PROGRAMMING | 1,000 | [
"greedy",
"implementation"
] | null | null | You have decided to watch the best moments of some movie. There are two buttons on your player:
1. Watch the current minute of the movie. By pressing this button, you watch the current minute of the movie and the player automatically proceeds to the next minute of the movie. 1. Skip exactly *x* minutes of the movie... | The first line contains two space-separated integers *n*, *x* (1<=≤<=*n*<=≤<=50, 1<=≤<=*x*<=≤<=105) — the number of the best moments of the movie and the value of *x* for the second button.
The following *n* lines contain the descriptions of the best moments of the movie, the *i*-th line of the description contains tw... | Output a single number — the answer to the problem. | [
"2 3\n5 6\n10 12\n",
"1 1\n1 100000\n"
] | [
"6\n",
"100000\n"
] | In the first sample, the player was initially standing on the first minute. As the minutes from the 1-st to the 4-th one don't contain interesting moments, we press the second button. Now we can not press the second button and skip 3 more minutes, because some of them contain interesting moments. Therefore, we watch th... | 500 | [
{
"input": "2 3\n5 6\n10 12",
"output": "6"
},
{
"input": "1 1\n1 100000",
"output": "100000"
},
{
"input": "10 1\n2156 3497\n4784 7775\n14575 31932\n33447 35902\n36426 47202\n48772 60522\n63982 68417\n78537 79445\n90081 90629\n94325 95728",
"output": "53974"
},
{
"input": "1... | 1,594,468,609 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 20,172,800 | n , x = map(int,input().split())
ans = 0
curm = 1
for i in range(n):
l , r = map(int,input().split())
if curm + x <= l :
l = curm + x
ans += r - l + 1
curm = r + 1
else:
ans += r - curm + 1
curm = r + 1
print(ans) | Title: Watching a movie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have decided to watch the best moments of some movie. There are two buttons on your player:
1. Watch the current minute of the movie. By pressing this button, you watch the current minute of the movie and the pl... | ```python
n , x = map(int,input().split())
ans = 0
curm = 1
for i in range(n):
l , r = map(int,input().split())
if curm + x <= l :
l = curm + x
ans += r - l + 1
curm = r + 1
else:
ans += r - curm + 1
curm = r + 1
print(ans)
``` | 0 | |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,625,865,735 | 2,147,483,647 | PyPy 3 | OK | TESTS | 96 | 1,045 | 11,673,600 | import sys
input = sys.stdin.readline
def I(): return input().strip()
def II(): return int(input().strip())
def LI(): return [*map(int, input().strip().split())]
import copy
import re
import string, math, time, functools, random, fractions
from heapq import heappush, heappop, heapify
from bis... | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
import sys
input = sys.stdin.readline
def I(): return input().strip()
def II(): return int(input().strip())
def LI(): return [*map(int, input().strip().split())]
import copy
import re
import string, math, time, functools, random, fractions
from heapq import heappush, heappop, heapify... | 3 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the... | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,662,201,018 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | n,m,a=map(int,input().split())
if n%a!=0: p=(n//a)+1
else: p=n//a
if m%a!=0: l=(m//a)+1
else: l=m//a
print(p*l) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each ... | ```python
n,m,a=map(int,input().split())
if n%a!=0: p=(n//a)+1
else: p=n//a
if m%a!=0: l=(m//a)+1
else: l=m//a
print(p*l)
``` | 3.977 |
545 | D | Queue | PROGRAMMING | 1,300 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time he waits is more than the time needed to serve him. The time a person waits is the total t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The next line contains *n* integers *t**i* (1<=≤<=*t**i*<=≤<=109), separated by spaces. | Print a single number — the maximum number of not disappointed people in the queue. | [
"5\n15 2 1 5 3\n"
] | [
"4\n"
] | Value 4 is achieved at such an arrangement, for example: 1, 2, 3, 5, 15. Thus, you can make everything feel not disappointed except for the person with time 5. | 1,750 | [
{
"input": "5\n15 2 1 5 3",
"output": "4"
},
{
"input": "15\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "2"
},
{
"input": "10\n13 2 5 55 21 34 1 8 1 3",
"output": "6"
},
{
"input": "10\n8 256 16 1 2 1 64 4 128 32",
"output": "10"
},
{
"input": "10\n10000 40000 1000... | 1,698,139,424 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 109 | 13,619,200 | input()
l = list(map(int, input().split()))
l.sort()
sums = 0
cnt = 0
for i in l:
if i >= sums:
cnt += 1
sums += i
print(cnt) | Title: Queue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time... | ```python
input()
l = list(map(int, input().split()))
l.sort()
sums = 0
cnt = 0
for i in l:
if i >= sums:
cnt += 1
sums += i
print(cnt)
``` | 3 | |
47 | B | Coins | PROGRAMMING | 1,200 | [
"implementation"
] | B. Coins | 2 | 256 | One day Vasya came across three Berland coins. They didn't have any numbers that's why Vasya didn't understand how their denominations differ. He supposed that if one coin is heavier than the other one, then it should be worth more. Vasya weighed all the three pairs of coins on pan balance scales and told you the resul... | The input data contains the results of all the weighting, one result on each line. It is guaranteed that every coin pair was weighted exactly once. Vasya labelled the coins with letters «A», «B» and «C». Each result is a line that appears as (letter)(> or < sign)(letter). For example, if coin "A" proved lighter t... | It the results are contradictory, print Impossible. Otherwise, print without spaces the rearrangement of letters «A», «B» and «C» which represent the coins in the increasing order of their weights. | [
"A>B\nC<B\nA>C\n",
"A<B\nB>C\nC>A\n"
] | [
"CBA",
"ACB"
] | none | 1,000 | [
{
"input": "A>B\nC<B\nA>C",
"output": "CBA"
},
{
"input": "A<B\nB>C\nC>A",
"output": "ACB"
},
{
"input": "A<C\nB<A\nB>C",
"output": "Impossible"
},
{
"input": "A<B\nA<C\nB>C",
"output": "ACB"
},
{
"input": "B>A\nC<B\nC>A",
"output": "ACB"
},
{
"input":... | 1,688,764,732 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 62 | 0 | my_dict = {'A' : 0, 'B' : 0, 'C' : 0}
for _ in range(3):
a = input()
if a[1] == '>':
my_dict[a[0]] += 1
else:
my_dict[a[2]] += 1
ans = set()
res = ['', '', '']
for key, value in my_dict.items():
if value in ans:
print("Impossible")
break
else:
... | Title: Coins
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya came across three Berland coins. They didn't have any numbers that's why Vasya didn't understand how their denominations differ. He supposed that if one coin is heavier than the other one, then it should be worth more. ... | ```python
my_dict = {'A' : 0, 'B' : 0, 'C' : 0}
for _ in range(3):
a = input()
if a[1] == '>':
my_dict[a[0]] += 1
else:
my_dict[a[2]] += 1
ans = set()
res = ['', '', '']
for key, value in my_dict.items():
if value in ans:
print("Impossible")
break
else:... | 3.9845 |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,694,888,271 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 77 | 2,867,200 | while True:
n = int(input())
if n in range(1, 101):
break
for i in range(n):
while True:
w = input()
if len(w) <= 10:
print(w)
else:
print(w[0], len(w) - 2, w[-1], sep='')
| Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
while True:
n = int(input())
if n in range(1, 101):
break
for i in range(n):
while True:
w = input()
if len(w) <= 10:
print(w)
else:
print(w[0], len(w) - 2, w[-1], sep='')
``` | -1 |
165 | B | Burning Midnight Oil | PROGRAMMING | 1,500 | [
"binary search",
"implementation"
] | null | null | One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of code, drinks a cup of tea, then he writes as much as lines, drinks another cup of tea, then he writes lin... | The input consists of two integers *n* and *k*, separated by spaces — the size of the program in lines and the productivity reduction coefficient, 1<=≤<=*n*<=≤<=109, 2<=≤<=*k*<=≤<=10. | Print the only integer — the minimum value of *v* that lets Vasya write the program in one night. | [
"7 2\n",
"59 9\n"
] | [
"4\n",
"54\n"
] | In the first sample the answer is *v* = 4. Vasya writes the code in the following portions: first 4 lines, then 2, then 1, and then Vasya falls asleep. Thus, he manages to write 4 + 2 + 1 = 7 lines in a night and complete the task.
In the second sample the answer is *v* = 54. Vasya writes the code in the following por... | 1,000 | [
{
"input": "7 2",
"output": "4"
},
{
"input": "59 9",
"output": "54"
},
{
"input": "1 9",
"output": "1"
},
{
"input": "11 2",
"output": "7"
},
{
"input": "747 2",
"output": "376"
},
{
"input": "6578 2",
"output": "3293"
},
{
"input": "37212... | 1,635,573,357 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 56 | 218 | 34,611,200 | from collections import defaultdict, Counter
from queue import PriorityQueue, Queue
import math
def getLines(n, k) :
ans = 0
p = 1
while p <= n :
ans += n // p
p *= k
return ans
n, k= map(int, input().split())
l, h = 1, n
while l <= h :
mid = (l + h) // 2
x ... | Title: Burning Midnight Oil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of c... | ```python
from collections import defaultdict, Counter
from queue import PriorityQueue, Queue
import math
def getLines(n, k) :
ans = 0
p = 1
while p <= n :
ans += n // p
p *= k
return ans
n, k= map(int, input().split())
l, h = 1, n
while l <= h :
mid = (l + h) //... | 3 | |
203 | C | Photographer | PROGRAMMING | 1,400 | [
"greedy",
"sortings"
] | null | null | Valera's lifelong ambition was to be a photographer, so he bought a new camera. Every day he got more and more clients asking for photos, and one day Valera needed a program that would determine the maximum number of people he can serve.
The camera's memory is *d* megabytes. Valera's camera can take photos of high and... | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*d*<=≤<=109) — the number of clients and the camera memory size, correspondingly. The second line contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=104) — the size of one low quality photo and of one high quality photo, correspondingly. ... | On the first line print the answer to the problem — the maximum number of clients that Valera can successfully serve. Print on the second line the numbers of the client in any order. All numbers must be distinct. If there are multiple answers, print any of them. The clients are numbered starting with 1 in the order in ... | [
"3 10\n2 3\n1 4\n2 1\n1 0\n",
"3 6\n6 6\n1 1\n1 0\n1 0\n"
] | [
"2\n3 2 ",
"1\n2 "
] | none | 1,500 | [
{
"input": "3 10\n2 3\n1 4\n2 1\n1 0",
"output": "2\n3 2 "
},
{
"input": "3 6\n6 6\n1 1\n1 0\n1 0",
"output": "1\n2 "
},
{
"input": "4 5\n6 8\n1 2\n3 0\n10 2\n0 4",
"output": "0"
},
{
"input": "4 10\n6 6\n1 2\n2 2\n0 0\n0 0",
"output": "2\n3 4 "
},
{
"input": "10 ... | 1,650,456,015 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 54 | 654 | 28,160,000 | import sys
input = sys.stdin.readline
class Order:
def __init__(self, n, cost):
self.number = n
self.cost = cost
n, storage = map(int, input().split())
a, b = map(int, input().split())
orders = []
for i in range(n):
x, y = map(int, input().split())
orders.append(Order(... | Title: Photographer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera's lifelong ambition was to be a photographer, so he bought a new camera. Every day he got more and more clients asking for photos, and one day Valera needed a program that would determine the maximum number of peopl... | ```python
import sys
input = sys.stdin.readline
class Order:
def __init__(self, n, cost):
self.number = n
self.cost = cost
n, storage = map(int, input().split())
a, b = map(int, input().split())
orders = []
for i in range(n):
x, y = map(int, input().split())
orders.app... | 3 | |
137 | B | Permutation | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | "Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task after some considerable time, the boy asked you to help him.
The sequence of *n* integers is cal... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=5000) which represents how many numbers are in the sequence. The second line contains a sequence of integers *a**i* (1<=≤<=*a**i*<=≤<=5000,<=1<=≤<=*i*<=≤<=*n*). | Print the only number — the minimum number of changes needed to get the permutation. | [
"3\n3 1 2\n",
"2\n2 2\n",
"5\n5 3 3 3 1\n"
] | [
"0\n",
"1\n",
"2\n"
] | The first sample contains the permutation, which is why no replacements are required.
In the second sample it is enough to replace the first element with the number 1 and that will make the sequence the needed permutation.
In the third sample we can replace the second element with number 4 and the fourth element with... | 1,000 | [
{
"input": "3\n3 1 2",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "5\n5 3 3 3 1",
"output": "2"
},
{
"input": "5\n6 6 6 6 6",
"output": "5"
},
{
"input": "10\n1 1 2 2 8 8 7 7 9 9",
"output": "5"
},
{
"input": "8\n9 8 7 6 5 4 3 2"... | 1,649,232,883 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 280 | 4,608,000 | import sys
#import bisect
import math
import itertools
#import array as ab
import random
def get_line(): return list(map(int, sys.stdin.readline().strip().split()))
def in1(): return int(input())
n=in1()
a=get_line()
b=list(set(a))
print(n-len(b))
| Title: Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task ... | ```python
import sys
#import bisect
import math
import itertools
#import array as ab
import random
def get_line(): return list(map(int, sys.stdin.readline().strip().split()))
def in1(): return int(input())
n=in1()
a=get_line()
b=list(set(a))
print(n-len(b))
``` | 0 | |
940 | C | Phone Numbers | PROGRAMMING | 1,500 | [
"constructive algorithms",
"implementation",
"strings"
] | null | null | And where the are the phone numbers?
You are given a string *s* consisting of lowercase English letters and an integer *k*. Find the lexicographically smallest string *t* of length *k*, such that its set of letters is a subset of the set of letters of *s* and *s* is lexicographically smaller than *t*.
It's guaranteed... | The first line of input contains two space separated integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100<=000) — the length of *s* and the required length of *t*.
The second line of input contains the string *s* consisting of *n* lowercase English letters. | Output the string *t* conforming to the requirements above.
It's guaranteed that the answer exists. | [
"3 3\nabc\n",
"3 2\nabc\n",
"3 3\nayy\n",
"2 3\nba\n"
] | [
"aca\n",
"ac\n",
"yaa\n",
"baa\n"
] | In the first example the list of strings *t* of length 3, such that the set of letters of *t* is a subset of letters of *s* is as follows: aaa, aab, aac, aba, abb, abc, aca, acb, .... Among them, those are lexicographically greater than abc: aca, acb, .... Out of those the lexicographically smallest is aca. | 1,250 | [
{
"input": "3 3\nabc",
"output": "aca"
},
{
"input": "3 2\nabc",
"output": "ac"
},
{
"input": "3 3\nayy",
"output": "yaa"
},
{
"input": "2 3\nba",
"output": "baa"
},
{
"input": "1 3\nf",
"output": "fff"
},
{
"input": "3 1\nazz",
"output": "z"
},
... | 1,535,713,613 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | a = 'abcdefghijklmnopqrstuvwxyz'
n, k = map(int, input().split())
s = input()
for i in a[::-1]:
if i in s:
print(i * k)
exit(0) | Title: Phone Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
And where the are the phone numbers?
You are given a string *s* consisting of lowercase English letters and an integer *k*. Find the lexicographically smallest string *t* of length *k*, such that its set of letters is a ... | ```python
a = 'abcdefghijklmnopqrstuvwxyz'
n, k = map(int, input().split())
s = input()
for i in a[::-1]:
if i in s:
print(i * k)
exit(0)
``` | 0 |
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