contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
845 | A | Chess Tourney | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by BerMobile. Obviously, organizers should guarantee the win for the team of BerOil.
Thus, organizer... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100).
The second line contains 2·*n* integers *a*1,<=*a*2,<=... *a*2*n* (1<=≤<=*a**i*<=≤<=1000). | If it's possible to divide all 2·*n* players into two teams with *n* people each so that the player from the first team in every pair wins regardless of the results of the drawing, then print "YES". Otherwise print "NO". | [
"2\n1 3 2 4\n",
"1\n3 3\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "2\n1 3 2 4",
"output": "YES"
},
{
"input": "1\n3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 2 2 3 3 3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 1 2 2 2 2 2",
"output": "YES"
},
{
"input": "10\n1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000... | 1,553,169,194 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin>>n;
int A[2*n+5];
for(int i=0;i<2*n;i++) cin>>A[i];
sort(A,A+2*n);
//for(int i=0;i<2*n;i++) cout<<A[i]<<" "; cout<<endl;
int cnt= 0;
int mid = 2*n/2;
//cout<<mid<<endl;
for(int i=0,k=(2*n)-1;i<mid;i++,k--)
{
if(... | Title: Chess Tourney
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by... | ```python
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin>>n;
int A[2*n+5];
for(int i=0;i<2*n;i++) cin>>A[i];
sort(A,A+2*n);
//for(int i=0;i<2*n;i++) cout<<A[i]<<" "; cout<<endl;
int cnt= 0;
int mid = 2*n/2;
//cout<<mid<<endl;
for(int i=0,k=(2*n)-1;i<mid;i++,k--)
{
... | -1 | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,579,930,588 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 124 | 0 | p=str(input())
q=str(input())
x=""
for i in range(len(p)):
if p[i]==q[i]:
x=x+"0"
else:
x=x+"1"
print(x)
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
p=str(input())
q=str(input())
x=""
for i in range(len(p)):
if p[i]==q[i]:
x=x+"0"
else:
x=x+"1"
print(x)
``` | 3.969 |
445 | A | DZY Loves Chessboard | PROGRAMMING | 1,200 | [
"dfs and similar",
"implementation"
] | null | null | DZY loves chessboard, and he enjoys playing with it.
He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. Each chessman is either white or black. After putting all chessmen, DZY wants that no two chessmen with th... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).
Each of the next *n* lines contains a string of *m* characters: the *j*-th character of the *i*-th string is either "." or "-". A "." means that the corresponding cell (in the *i*-th row and the *j*-th column) is good, while a ... | Output must contain *n* lines, each line must contain a string of *m* characters. The *j*-th character of the *i*-th string should be either "W", "B" or "-". Character "W" means the chessman on the cell is white, "B" means it is black, "-" means the cell is a bad cell.
If multiple answers exist, print any of them. It ... | [
"1 1\n.\n",
"2 2\n..\n..\n",
"3 3\n.-.\n---\n--."
] | [
"B\n",
"BW\nWB\n",
"B-B\n---\n--B"
] | In the first sample, DZY puts a single black chessman. Of course putting a white one is also OK.
In the second sample, all 4 cells are good. No two same chessmen share an edge in the sample output.
In the third sample, no good cells are adjacent. So you can just put 3 chessmen, no matter what their colors are. | 500 | [
{
"input": "1 1\n.",
"output": "B"
},
{
"input": "2 2\n..\n..",
"output": "BW\nWB"
},
{
"input": "3 3\n.-.\n---\n--.",
"output": "B-B\n---\n--B"
},
{
"input": "3 1\n-\n.\n.",
"output": "-\nW\nB"
},
{
"input": "11 11\n-----------\n-----------\n-----------\n--------... | 1,681,385,438 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 31 | 0 | n, m = map(lambda x: int(x), input().split())
l = []
for i in range(n):
l.append(list(input()))
i = 0
while i < n:
j = 0
while j < m:
if l[i][j] == '.':
if (i-1 >=0 and l[i-1][j] == 'B') or (j-1 >= 0 and l[i][j-1] == 'B'):
l[i][j] = 'W'
else:
l[i][j] = 'B'
j += 1
print(''.join(l... | Title: DZY Loves Chessboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY loves chessboard, and he enjoys playing with it.
He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. ... | ```python
n, m = map(lambda x: int(x), input().split())
l = []
for i in range(n):
l.append(list(input()))
i = 0
while i < n:
j = 0
while j < m:
if l[i][j] == '.':
if (i-1 >=0 and l[i-1][j] == 'B') or (j-1 >= 0 and l[i][j-1] == 'B'):
l[i][j] = 'W'
else:
l[i][j] = 'B'
j += 1
print... | 0 | |
543 | B | Destroying Roads | PROGRAMMING | 2,100 | [
"constructive algorithms",
"graphs",
"shortest paths"
] | null | null | In some country there are exactly *n* cities and *m* bidirectional roads connecting the cities. Cities are numbered with integers from 1 to *n*. If cities *a* and *b* are connected by a road, then in an hour you can go along this road either from city *a* to city *b*, or from city *b* to city *a*. The road network is s... | The first line contains two integers *n*, *m* (1<=≤<=*n*<=≤<=3000, ) — the number of cities and roads in the country, respectively.
Next *m* lines contain the descriptions of the roads as pairs of integers *a**i*, *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*). It is guaranteed that the roads that are give... | Print a single number — the answer to the problem. If the it is impossible to meet the conditions, print -1. | [
"5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n3 5 2\n",
"5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n2 4 2\n",
"5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n3 5 1\n"
] | [
"0\n",
"1\n",
"-1\n"
] | none | 1,000 | [
{
"input": "5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n3 5 2",
"output": "0"
},
{
"input": "5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n2 4 2",
"output": "1"
},
{
"input": "5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n3 5 1",
"output": "-1"
},
{
"input": "9 9\n1 2\n2 3\n2 4\n4 5\n5 7\n5 6\n3 8\n8 9\n9 6\n1 7 4\... | 1,658,086,479 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 3 | 92 | 2,150,400 | n,m=map(int,input().split(" "))
dic={}
for i in range(m):
a,b=map(int,input().split(" "))
dic[a]=b
s1,t1,l1=map(int,input().split(" "))
s2,t2,l2=map(int,input().split(" "))
ans=[]
flag=False
c=0
while(s1!=t1):
ans.append(s1)
c+=1
s1=dic[s1]
# print(c)
if c>l1:
flag=True
an... | Title: Destroying Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In some country there are exactly *n* cities and *m* bidirectional roads connecting the cities. Cities are numbered with integers from 1 to *n*. If cities *a* and *b* are connected by a road, then in an hour you can go... | ```python
n,m=map(int,input().split(" "))
dic={}
for i in range(m):
a,b=map(int,input().split(" "))
dic[a]=b
s1,t1,l1=map(int,input().split(" "))
s2,t2,l2=map(int,input().split(" "))
ans=[]
flag=False
c=0
while(s1!=t1):
ans.append(s1)
c+=1
s1=dic[s1]
# print(c)
if c>l1:
fla... | -1 | |
276 | C | Little Girl and Maximum Sum | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"implementation",
"sortings"
] | null | null | The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of $n$ elements (the elements of the array are indexed starting from 1); also, there are $q$ queries, each one is defined by a pair of integers $l_i$, $r_i$ $(1 \le l_i \le r_i \le n)... | The first line contains two space-separated integers $n$ ($1 \le n \le 2\cdot10^5$) and $q$ ($1 \le q \le 2\cdot10^5$) — the number of elements in the array and the number of queries, correspondingly.
The next line contains $n$ space-separated integers $a_i$ ($1 \le a_i \le 2\cdot10^5$) — the array elements.
Each of ... | In a single line print, a single integer — the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"3 3\n5 3 2\n1 2\n2 3\n1 3\n",
"5 3\n5 2 4 1 3\n1 5\n2 3\n2 3\n"
] | [
"25\n",
"33\n"
] | none | 1,500 | [
{
"input": "3 3\n5 3 2\n1 2\n2 3\n1 3",
"output": "25"
},
{
"input": "5 3\n5 2 4 1 3\n1 5\n2 3\n2 3",
"output": "33"
},
{
"input": "34 21\n23 38 16 49 44 50 48 34 33 19 18 31 11 15 20 47 44 30 39 33 45 46 1 13 27 16 31 36 17 23 38 5 30 16\n8 16\n14 27\n8 26\n1 8\n5 6\n23 28\n4 33\n13 30\... | 1,686,678,248 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 43,212,800 | # Little Girl and Maximum Sum
n,q = map(int,input().split())
a = sorted([int(i) for i in input().split(" ")], reverse = True)
sum = 0
m = {}
for i in range(q):
l,r = map(int,input().split(" "))
for i in range(l,r+1):
m[i] = m.get(i,0) + 1
new = sorted(m.values(),reverse = True)
lenn = len(new)
for i ... | Title: Little Girl and Maximum Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of $n$ elements (the elements of the array are indexed starting from 1... | ```python
# Little Girl and Maximum Sum
n,q = map(int,input().split())
a = sorted([int(i) for i in input().split(" ")], reverse = True)
sum = 0
m = {}
for i in range(q):
l,r = map(int,input().split(" "))
for i in range(l,r+1):
m[i] = m.get(i,0) + 1
new = sorted(m.values(),reverse = True)
lenn = len(ne... | 0 | |
366 | B | Dima and To-do List | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | You helped Dima to have a great weekend, but it's time to work. Naturally, Dima, as all other men who have girlfriends, does everything wrong.
Inna and Dima are now in one room. Inna tells Dima off for everything he does in her presence. After Inna tells him off for something, she goes to another room, walks there in ... | The first line of the input contains two integers *n*,<=*k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103), where *a**i* is the power Inna tells Dima off with if she is present in the room while he is doing the *i*-th task.
It is guaranteed that *n*... | In a single line print the number of the task Dima should start with to get told off with as little power as possible. If there are multiple solutions, print the one with the minimum number of the first task to do. | [
"6 2\n3 2 1 6 5 4\n",
"10 5\n1 3 5 7 9 9 4 1 8 5\n"
] | [
"1\n",
"3\n"
] | Explanation of the first example.
If Dima starts from the first task, Inna tells him off with power 3, then Dima can do one more task (as *k* = 2), then Inna tells him off for the third task with power 1, then she tells him off for the fifth task with power 5. Thus, Dima gets told off with total power 3 + 1 + 5 = 9. I... | 1,000 | [
{
"input": "6 2\n3 2 1 6 5 4",
"output": "1"
},
{
"input": "10 5\n1 3 5 7 9 9 4 1 8 5",
"output": "3"
},
{
"input": "20 4\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "1"
},
{
"input": "10 10\n8 4 5 7 6 9 2 2 3 5",
"output": "7"
},
{
"input": "50 10\n1 2 3... | 1,460,276,616 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 171 | 7,065,600 | n, k = list(map(int, input().split()))
num = list(map(int, input().split()))
dp = [0] * (2 * n)
for i in range(n - 1, -1, -1):
dp[i] = dp[i + k] + num[i]
ans = 2**100
for i in range(0, k):
ans = min(ans, dp[i])
print(dp.index(ans) + 1) | Title: Dima and To-do List
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You helped Dima to have a great weekend, but it's time to work. Naturally, Dima, as all other men who have girlfriends, does everything wrong.
Inna and Dima are now in one room. Inna tells Dima off for everything h... | ```python
n, k = list(map(int, input().split()))
num = list(map(int, input().split()))
dp = [0] * (2 * n)
for i in range(n - 1, -1, -1):
dp[i] = dp[i + k] + num[i]
ans = 2**100
for i in range(0, k):
ans = min(ans, dp[i])
print(dp.index(ans) + 1)
``` | 3 | |
459 | A | Pashmak and Garden | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Pashmak has fallen in love with an attractive girl called Parmida since one year ago...
Today, Pashmak set up a meeting with his partner in a romantic garden. Unfortunately, Pashmak has forgotten where the garden is. But he remembers that the garden looks like a square with sides parallel to the coordinate axes. He al... | The first line contains four space-separated *x*1,<=*y*1,<=*x*2,<=*y*2 (<=-<=100<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=100) integers, where *x*1 and *y*1 are coordinates of the first tree and *x*2 and *y*2 are coordinates of the second tree. It's guaranteed that the given points are distinct. | If there is no solution to the problem, print -1. Otherwise print four space-separated integers *x*3,<=*y*3,<=*x*4,<=*y*4 that correspond to the coordinates of the two other trees. If there are several solutions you can output any of them.
Note that *x*3,<=*y*3,<=*x*4,<=*y*4 must be in the range (<=-<=1000<=≤<=*x*3,<... | [
"0 0 0 1\n",
"0 0 1 1\n",
"0 0 1 2\n"
] | [
"1 0 1 1\n",
"0 1 1 0\n",
"-1\n"
] | none | 500 | [
{
"input": "0 0 0 1",
"output": "1 0 1 1"
},
{
"input": "0 0 1 1",
"output": "0 1 1 0"
},
{
"input": "0 0 1 2",
"output": "-1"
},
{
"input": "-100 -100 100 100",
"output": "-100 100 100 -100"
},
{
"input": "-100 -100 99 100",
"output": "-1"
},
{
"input... | 1,694,514,383 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 31 | 0 | x1, y1, x2, y2 = map(int, input().split())
if x1 == y1 and x2 == y2:
print(x1, y2, x2, y1)
elif x1 == x2:
print(x1 + 1, y1, x2 + 1, y2)
elif y1 == y2:
print(x1, y1 + 1, x2, y2 + 1)
else:
print(-1) | Title: Pashmak and Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pashmak has fallen in love with an attractive girl called Parmida since one year ago...
Today, Pashmak set up a meeting with his partner in a romantic garden. Unfortunately, Pashmak has forgotten where the garden is... | ```python
x1, y1, x2, y2 = map(int, input().split())
if x1 == y1 and x2 == y2:
print(x1, y2, x2, y1)
elif x1 == x2:
print(x1 + 1, y1, x2 + 1, y2)
elif y1 == y2:
print(x1, y1 + 1, x2, y2 + 1)
else:
print(-1)
``` | 0 | |
777 | B | Game of Credit Cards | PROGRAMMING | 1,300 | [
"data structures",
"dp",
"greedy",
"sortings"
] | null | null | After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards.
Rules of this game are simple: each player bring his favourite *n*-digit credit card. Then both players name the digits written on the... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of digits in the cards Sherlock and Moriarty are going to use.
The second line contains *n* digits — Sherlock's credit card number.
The third line contains *n* digits — Moriarty's credit card number. | First print the minimum possible number of flicks Moriarty will get. Then print the maximum possible number of flicks that Sherlock can get from Moriarty. | [
"3\n123\n321\n",
"2\n88\n00\n"
] | [
"0\n2\n",
"2\n0\n"
] | First sample is elaborated in the problem statement. In the second sample, there is no way Moriarty can avoid getting two flicks. | 1,000 | [
{
"input": "3\n123\n321",
"output": "0\n2"
},
{
"input": "2\n88\n00",
"output": "2\n0"
},
{
"input": "1\n4\n5",
"output": "0\n1"
},
{
"input": "1\n8\n7",
"output": "1\n0"
},
{
"input": "2\n55\n55",
"output": "0\n0"
},
{
"input": "3\n534\n432",
"out... | 1,617,742,766 | 2,147,483,647 | PyPy 3 | OK | TESTS | 55 | 109 | 1,740,800 | import sys
import itertools
import collections
def rs(x=''): return sys.stdin.readline().strip() if len(x) == 0 else input(x).strip()
def ri(x=''): return int(rs(x))
def rm(x=''): return map(str, rs(x).split())
def rl(x=''): return rs(x).split()
def rmi(x=''): return map(int, rs(x).split())
def rli(x=''): ret... | Title: Game of Credit Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards.
Rules of this game are simpl... | ```python
import sys
import itertools
import collections
def rs(x=''): return sys.stdin.readline().strip() if len(x) == 0 else input(x).strip()
def ri(x=''): return int(rs(x))
def rm(x=''): return map(str, rs(x).split())
def rl(x=''): return rs(x).split()
def rmi(x=''): return map(int, rs(x).split())
def rli(... | 3 | |
987 | A | Infinity Gauntlet | PROGRAMMING | 800 | [
"implementation"
] | null | null | You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems:
- the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the Soul Gem of orange color, - the Reality Gem of red color, - the Mind Gem of yellow color.
Using colors... | In the first line of input there is one integer $n$ ($0 \le n \le 6$) — the number of Gems in Infinity Gauntlet.
In next $n$ lines there are colors of Gems you saw. Words used for colors are: purple, green, blue, orange, red, yellow. It is guaranteed that all the colors are distinct. All colors are given in lowercase ... | In the first line output one integer $m$ ($0 \le m \le 6$) — the number of absent Gems.
Then in $m$ lines print the names of absent Gems, each on its own line. Words used for names are: Power, Time, Space, Soul, Reality, Mind. Names can be printed in any order. Keep the first letter uppercase, others lowercase. | [
"4\nred\npurple\nyellow\norange\n",
"0\n"
] | [
"2\nSpace\nTime\n",
"6\nTime\nMind\nSoul\nPower\nReality\nSpace\n"
] | In the first sample Thanos already has Reality, Power, Mind and Soul Gems, so he needs two more: Time and Space.
In the second sample Thanos doesn't have any Gems, so he needs all six. | 500 | [
{
"input": "4\nred\npurple\nyellow\norange",
"output": "2\nSpace\nTime"
},
{
"input": "0",
"output": "6\nMind\nSpace\nPower\nTime\nReality\nSoul"
},
{
"input": "6\npurple\nblue\nyellow\nred\ngreen\norange",
"output": "0"
},
{
"input": "1\npurple",
"output": "5\nTime\nReal... | 1,700,318,384 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 46 | 0 | a = int(input())
d = {"purple": "Power", "green": "Time", "blue": "Space", "orange": "Soul", "red": "Reality", "yellow": "Mind"}
for i in range(0, a):
b = input()
del d[b]
print(len(d))
for i in d:
print(d[i])
| Title: Infinity Gauntlet
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems:
- the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the So... | ```python
a = int(input())
d = {"purple": "Power", "green": "Time", "blue": "Space", "orange": "Soul", "red": "Reality", "yellow": "Mind"}
for i in range(0, a):
b = input()
del d[b]
print(len(d))
for i in d:
print(d[i])
``` | 3 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,679,491,395 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 31 | 0 | t=int(input())
def solve():
ch=input()
if(len(ch)<=10):
return ch
else:
return ch[0]+str(len(ch)-2)+ch[len(ch)-1]
answer=""
while(t!=0):
answer+=solve()+"\n"
t-=1
print(answer)
| Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
t=int(input())
def solve():
ch=input()
if(len(ch)<=10):
return ch
else:
return ch[0]+str(len(ch)-2)+ch[len(ch)-1]
answer=""
while(t!=0):
answer+=solve()+"\n"
t-=1
print(answer)
``` | 3.9845 |
771 | A | Bear and Friendship Condition | PROGRAMMING | 1,500 | [
"dfs and similar",
"dsu",
"graphs"
] | null | null | Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through *n*. *m* pairs of members are friends. Of course, a member can't be a friend with themselves.
Let A-B denote that... | The first line of the input contain two integers *n* and *m* (3<=≤<=*n*<=≤<=150<=000, ) — the number of members and the number of pairs of members that are friends.
The *i*-th of the next *m* lines contains two distinct integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*). Members *a**i* and ... | If the given network is reasonable, print "YES" in a single line (without the quotes). Otherwise, print "NO" in a single line (without the quotes). | [
"4 3\n1 3\n3 4\n1 4\n",
"4 4\n3 1\n2 3\n3 4\n1 2\n",
"10 4\n4 3\n5 10\n8 9\n1 2\n",
"3 2\n1 2\n2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"NO\n"
] | The drawings below show the situation in the first sample (on the left) and in the second sample (on the right). Each edge represents two members that are friends. The answer is "NO" in the second sample because members (2, 3) are friends and members (3, 4) are friends, while members (2, 4) are not. | 250 | [
{
"input": "4 3\n1 3\n3 4\n1 4",
"output": "YES"
},
{
"input": "4 4\n3 1\n2 3\n3 4\n1 2",
"output": "NO"
},
{
"input": "10 4\n4 3\n5 10\n8 9\n1 2",
"output": "YES"
},
{
"input": "3 2\n1 2\n2 3",
"output": "NO"
},
{
"input": "3 0",
"output": "YES"
},
{
... | 1,523,643,096 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 7,065,600 |
def istransitive(nodes):
for a in nodes:
for b in nodes:
if a!=b:
if a[1] == b[0] and ((a[0],b[1]) not in nodes and (b[1],a[0]) not in nodes ):
print(a)
print(b)
return False
return True
n, m = list(map(int, input().split(" ")))
nodes = []
for i in range(m):
a, b = list(... | Title: Bear and Friendship Condition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through... | ```python
def istransitive(nodes):
for a in nodes:
for b in nodes:
if a!=b:
if a[1] == b[0] and ((a[0],b[1]) not in nodes and (b[1],a[0]) not in nodes ):
print(a)
print(b)
return False
return True
n, m = list(map(int, input().split(" ")))
nodes = []
for i in range(m):
a,... | 0 | |
510 | A | Fox And Snake | PROGRAMMING | 800 | [
"implementation"
] | null | null | Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*-th cell of *r*-th row as (*r*,<=*c*). The tail of the snake is located at (1,<=1), then it's body ... | The only line contains two integers: *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=50).
*n* is an odd number. | Output *n* lines. Each line should contain a string consisting of *m* characters. Do not output spaces. | [
"3 3\n",
"3 4\n",
"5 3\n",
"9 9\n"
] | [
"###\n..#\n###\n",
"####\n...#\n####\n",
"###\n..#\n###\n#..\n###\n",
"#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#########\n"
] | none | 500 | [
{
"input": "3 3",
"output": "###\n..#\n###"
},
{
"input": "3 4",
"output": "####\n...#\n####"
},
{
"input": "5 3",
"output": "###\n..#\n###\n#..\n###"
},
{
"input": "9 9",
"output": "#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#... | 1,678,362,466 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 28 | 77 | 3,584,000 | a,b=map(int,input().split())
for i in range(1,a+1):
if i%2!=0:a='#'
else:
a='.'
print(end=' ');
if i%4==0:print('#',end='')
for j in range(b-1):
print(a,end='')
if i%4!=0:print('#',end='')
print('') | Title: Fox And Snake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*... | ```python
a,b=map(int,input().split())
for i in range(1,a+1):
if i%2!=0:a='#'
else:
a='.'
print(end=' ');
if i%4==0:print('#',end='')
for j in range(b-1):
print(a,end='')
if i%4!=0:print('#',end='')
print('')
``` | 3 | |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,676,352,450 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 33 | 62 | 1,331,200 | def P(n):
d = 2
if n<=1:
return True
while n % d != 0:
d += 1
return d == n
a = int(input())
for x in range(a//2+1):
b = a - (x+1)
c = a-b
if P(b)==False and P(c)==False:
print(b,c)
break
| Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
def P(n):
d = 2
if n<=1:
return True
while n % d != 0:
d += 1
return d == n
a = int(input())
for x in range(a//2+1):
b = a - (x+1)
c = a-b
if P(b)==False and P(c)==False:
print(b,c)
break
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are an experienced Codeforces user. Today you found out that during your activity on Codeforces you have made *y* submissions, out of which *x* have been successful. Thus, your current success rate on Codeforces is equal to *x*<=/<=*y*.
Your favorite rational number in the [0;1] range is *p*<=/<=*q*. Now you wonde... | The first line contains a single integer *t* (1<=≤<=*t*<=≤<=1000) — the number of test cases.
Each of the next *t* lines contains four integers *x*, *y*, *p* and *q* (0<=≤<=*x*<=≤<=*y*<=≤<=109; 0<=≤<=*p*<=≤<=*q*<=≤<=109; *y*<=><=0; *q*<=><=0).
It is guaranteed that *p*<=/<=*q* is an irreducible fraction.
Hacks... | For each test case, output a single integer equal to the smallest number of submissions you have to make if you want your success rate to be equal to your favorite rational number, or -1 if this is impossible to achieve. | [
"4\n3 10 1 2\n7 14 3 8\n20 70 2 7\n5 6 1 1\n"
] | [
"4\n10\n0\n-1\n"
] | In the first example, you have to make 4 successful submissions. Your success rate will be equal to 7 / 14, or 1 / 2.
In the second example, you have to make 2 successful and 8 unsuccessful submissions. Your success rate will be equal to 9 / 24, or 3 / 8.
In the third example, there is no need to make any new submiss... | 0 | [
{
"input": "4\n3 10 1 2\n7 14 3 8\n20 70 2 7\n5 6 1 1",
"output": "4\n10\n0\n-1"
},
{
"input": "8\n0 1 0 1\n0 2 1 2\n0 3 1 1\n1 2 0 1\n1 2 1 1\n2 2 0 1\n3 3 1 2\n4 4 1 1",
"output": "0\n2\n-1\n-1\n-1\n-1\n3\n0"
},
{
"input": "5\n1 1000000000 1 2\n1 1000000000 1 2\n1 1000000000 1 2\n1 100... | 1,564,585,173 | 5,973 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 2,000 | 4,505,600 | # (x + a) / (y + a + b) = p / q
# minimize a+b
# (x + a) * q = (y + a + b) * p
# (3 + a) * 2 = (10 + a + b) * 1
# xq + aq = yp +ap +bp
# xq - yp = ap + bp - aq
# xq - yp = (a+b)p -aq
# xq - yp = (p-q)a +bp
# 3*2 - 10*1 = (a+b)1 -2a
#(p-q)a+bp=left
#b=(left-(p-q)a)/p
# left+aq=(a+b)p
import math
t = i... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are an experienced Codeforces user. Today you found out that during your activity on Codeforces you have made *y* submissions, out of which *x* have been successful. Thus, your current success rate on Codeforces is equal to *x... | ```python
# (x + a) / (y + a + b) = p / q
# minimize a+b
# (x + a) * q = (y + a + b) * p
# (3 + a) * 2 = (10 + a + b) * 1
# xq + aq = yp +ap +bp
# xq - yp = ap + bp - aq
# xq - yp = (a+b)p -aq
# xq - yp = (p-q)a +bp
# 3*2 - 10*1 = (a+b)1 -2a
#(p-q)a+bp=left
#b=(left-(p-q)a)/p
# left+aq=(a+b)p
import mat... | 0 | |
443 | A | Anton and Letters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to ti... | The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space. | Print a single number — the number of distinct letters in Anton's set. | [
"{a, b, c}\n",
"{b, a, b, a}\n",
"{}\n"
] | [
"3\n",
"2\n",
"0\n"
] | none | 500 | [
{
"input": "{a, b, c}",
"output": "3"
},
{
"input": "{b, a, b, a}",
"output": "2"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{a, a, c, b, b, b, c, c, c, c}",
"output": "3"
},
{
"input": "{a, c, b, b}",
"output": "3"
},
{
"input": "{a, b}",
"o... | 1,686,604,863 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 61 | 0 | print(len(set((x := input()).strip('{}').split(', '))) - (x == '{}')) | Title: Anton and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the begi... | ```python
print(len(set((x := input()).strip('{}').split(', '))) - (x == '{}'))
``` | 3 | |
501 | A | Contest | PROGRAMMING | 900 | [
"implementation"
] | null | null | Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved the problem that costs *b* points. Besides, Misha submitted the problem *c* minutes after the ... | The first line contains four integers *a*, *b*, *c*, *d* (250<=≤<=*a*,<=*b*<=≤<=3500, 0<=≤<=*c*,<=*d*<=≤<=180).
It is guaranteed that numbers *a* and *b* are divisible by 250 (just like on any real Codeforces round). | Output on a single line:
"Misha" (without the quotes), if Misha got more points than Vasya.
"Vasya" (without the quotes), if Vasya got more points than Misha.
"Tie" (without the quotes), if both of them got the same number of points. | [
"500 1000 20 30\n",
"1000 1000 1 1\n",
"1500 1000 176 177\n"
] | [
"Vasya\n",
"Tie\n",
"Misha\n"
] | none | 500 | [
{
"input": "500 1000 20 30",
"output": "Vasya"
},
{
"input": "1000 1000 1 1",
"output": "Tie"
},
{
"input": "1500 1000 176 177",
"output": "Misha"
},
{
"input": "1500 1000 74 177",
"output": "Misha"
},
{
"input": "750 2500 175 178",
"output": "Vasya"
},
{
... | 1,584,711,898 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 155 | 0 | a,b,c,d=map(int,input().split())
x=max((3*a//10),(a-(a*c//250)))
y=max((3*b//10),(b-(b*d//250)))
if(x>y):
print("Misha")
elif(x==y):
print("Tie")
elif(y>x):
print("Vasya")
| Title: Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved t... | ```python
a,b,c,d=map(int,input().split())
x=max((3*a//10),(a-(a*c//250)))
y=max((3*b//10),(b-(b*d//250)))
if(x>y):
print("Misha")
elif(x==y):
print("Tie")
elif(y>x):
print("Vasya")
``` | 3 | |
990 | C | Bracket Sequences Concatenation Problem | PROGRAMMING | 1,500 | [
"implementation"
] | null | null | A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the original characters of the sequence. For example, bracket sequences "()()", "(())" are reg... | The first line contains one integer $n \, (1 \le n \le 3 \cdot 10^5)$ — the number of bracket sequences. The following $n$ lines contain bracket sequences — non-empty strings consisting only of characters "(" and ")". The sum of lengths of all bracket sequences does not exceed $3 \cdot 10^5$. | In the single line print a single integer — the number of pairs $i, j \, (1 \le i, j \le n)$ such that the bracket sequence $s_i + s_j$ is a regular bracket sequence. | [
"3\n)\n()\n(\n",
"2\n()\n()\n"
] | [
"2\n",
"4\n"
] | In the first example, suitable pairs are $(3, 1)$ and $(2, 2)$.
In the second example, any pair is suitable, namely $(1, 1), (1, 2), (2, 1), (2, 2)$. | 0 | [
{
"input": "3\n)\n()\n(",
"output": "2"
},
{
"input": "2\n()\n()",
"output": "4"
},
{
"input": "7\n()(\n)\n)(\n())\n(((\n()()()\n()",
"output": "6"
},
{
"input": "6\n(\n((\n(((\n))))\n)))))\n))))))",
"output": "0"
},
{
"input": "9\n(()\n((())\n(\n)\n(()()(()())))\... | 1,528,824,678 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | num = int(input())
arr=[]
for i in range(num):
arr.append(input())
numofs=0
listOfSeq=[]
for i in range(len(arr)):
t = arr[i]
numOfOpem=0
for k in range(len(t)):
if(t[k]=="("):
numOfOpem+=1
if(t[k]==")"):
numOfOpem-=1
listOfSeq.append(numOfOpem)
... | Title: Bracket Sequences Concatenation Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting ... | ```python
num = int(input())
arr=[]
for i in range(num):
arr.append(input())
numofs=0
listOfSeq=[]
for i in range(len(arr)):
t = arr[i]
numOfOpem=0
for k in range(len(t)):
if(t[k]=="("):
numOfOpem+=1
if(t[k]==")"):
numOfOpem-=1
listOfSeq.append(n... | 0 | |
546 | A | Soldier and Bananas | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He has *n* dollars. How many dollars does he have to borrow from his friend soldier to buy *w* bananas? | The first line contains three positive integers *k*,<=*n*,<=*w* (1<=<=≤<=<=*k*,<=*w*<=<=≤<=<=1000, 0<=≤<=*n*<=≤<=109), the cost of the first banana, initial number of dollars the soldier has and number of bananas he wants. | Output one integer — the amount of dollars that the soldier must borrow from his friend. If he doesn't have to borrow money, output 0. | [
"3 17 4\n"
] | [
"13"
] | none | 500 | [
{
"input": "3 17 4",
"output": "13"
},
{
"input": "1 2 1",
"output": "0"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 5 6",
"output": "16"
},
{
"input": "1 1000000000 1",
"output": "0"
},
{
"input": "1000 0 1000",
"output": "500500000"
}... | 1,694,085,515 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | k,n,w=map(int,input().split())
d=0
for i in range(1,w+1) :
d=0+i*k
p=d-n
print(p) | Title: Soldier and Bananas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He h... | ```python
k,n,w=map(int,input().split())
d=0
for i in range(1,w+1) :
d=0+i*k
p=d-n
print(p)
``` | 0 | |
174 | A | Problem About Equation | PROGRAMMING | 1,100 | [
"math"
] | null | null | A group of *n* merry programmers celebrate Robert Floyd's birthday. Polucarpus has got an honourable task of pouring Ber-Cola to everybody. Pouring the same amount of Ber-Cola to everybody is really important. In other words, the drink's volume in each of the *n* mugs must be the same.
Polycarpus has already began the... | The first line contains a pair of integers *n*, *b* (2<=≤<=*n*<=≤<=100,<=1<=≤<=*b*<=≤<=100), where *n* is the total number of friends in the group and *b* is the current volume of drink in the bottle. The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100), where *a**i* is the ... | Print a single number "-1" (without the quotes), if there is no solution. Otherwise, print *n* float numbers *c*1,<=*c*2,<=...,<=*c**n*, where *c**i* is the volume of the drink to add in the *i*-th mug. Print the numbers with no less than 6 digits after the decimal point, print each *c**i* on a single line. Polycarpus ... | [
"5 50\n1 2 3 4 5\n",
"2 2\n1 100\n"
] | [
"12.000000\n11.000000\n10.000000\n9.000000\n8.000000\n",
"-1\n"
] | none | 500 | [
{
"input": "5 50\n1 2 3 4 5",
"output": "12.000000\n11.000000\n10.000000\n9.000000\n8.000000"
},
{
"input": "2 2\n1 100",
"output": "-1"
},
{
"input": "2 2\n1 1",
"output": "1.000000\n1.000000"
},
{
"input": "3 2\n1 2 1",
"output": "1.000000\n0.000000\n1.000000"
},
{
... | 1,557,809,595 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 248 | 0 | N, S = map(int, input().split())
A = list(map(int, input().split()))
ave = (S + sum(A)) / N
ans = []
for a in A:
if a > ave:
ans.append(-1)
break
else:
ans.append(ave - a)
if ans[-1] == -1:
print(-1)
else:
for a in ans:
print("%.6f" ... | Title: Problem About Equation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A group of *n* merry programmers celebrate Robert Floyd's birthday. Polucarpus has got an honourable task of pouring Ber-Cola to everybody. Pouring the same amount of Ber-Cola to everybody is really important. In... | ```python
N, S = map(int, input().split())
A = list(map(int, input().split()))
ave = (S + sum(A)) / N
ans = []
for a in A:
if a > ave:
ans.append(-1)
break
else:
ans.append(ave - a)
if ans[-1] == -1:
print(-1)
else:
for a in ans:
pri... | 3 | |
546 | A | Soldier and Bananas | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He has *n* dollars. How many dollars does he have to borrow from his friend soldier to buy *w* bananas? | The first line contains three positive integers *k*,<=*n*,<=*w* (1<=<=≤<=<=*k*,<=*w*<=<=≤<=<=1000, 0<=≤<=*n*<=≤<=109), the cost of the first banana, initial number of dollars the soldier has and number of bananas he wants. | Output one integer — the amount of dollars that the soldier must borrow from his friend. If he doesn't have to borrow money, output 0. | [
"3 17 4\n"
] | [
"13"
] | none | 500 | [
{
"input": "3 17 4",
"output": "13"
},
{
"input": "1 2 1",
"output": "0"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 5 6",
"output": "16"
},
{
"input": "1 1000000000 1",
"output": "0"
},
{
"input": "1000 0 1000",
"output": "500500000"
}... | 1,696,136,518 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 15 | 62 | 0 | k,n,w = map(int,input().split())
c = k*(w*(w+1)//2)
if c <=n:
print(0)
else:
print(abs(n-c)) | Title: Soldier and Bananas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He h... | ```python
k,n,w = map(int,input().split())
c = k*(w*(w+1)//2)
if c <=n:
print(0)
else:
print(abs(n-c))
``` | 3 | |
353 | A | Domino | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Valera has got *n* domino pieces in a row. Each piece consists of two halves — the upper one and the lower one. Each of the halves contains a number from 1 to 6. Valera loves even integers very much, so he wants the sum of the numbers on the upper halves and the sum of the numbers on the lower halves to be even.
To do... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100), denoting the number of dominoes Valera has. Next *n* lines contain two space-separated integers *x**i*,<=*y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=6). Number *x**i* is initially written on the upper half of the *i*-th domino, *y**i* is initially written on the lower half... | Print a single number — the minimum required number of seconds. If Valera can't do the task in any time, print <=-<=1. | [
"2\n4 2\n6 4\n",
"1\n2 3\n",
"3\n1 4\n2 3\n4 4\n"
] | [
"0\n",
"-1\n",
"1\n"
] | In the first test case the sum of the numbers on the upper halves equals 10 and the sum of the numbers on the lower halves equals 6. Both numbers are even, so Valera doesn't required to do anything.
In the second sample Valera has only one piece of domino. It is written 3 on the one of its halves, therefore one of the... | 500 | [
{
"input": "2\n4 2\n6 4",
"output": "0"
},
{
"input": "1\n2 3",
"output": "-1"
},
{
"input": "3\n1 4\n2 3\n4 4",
"output": "1"
},
{
"input": "5\n5 4\n5 4\n1 5\n5 5\n3 3",
"output": "1"
},
{
"input": "20\n1 3\n5 2\n5 2\n2 6\n2 4\n1 1\n1 3\n1 4\n2 6\n4 2\n5 6\n2 2\n... | 1,608,759,608 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 22 | 216 | 307,200 | l = int(input())
top = []
bottom = []
min = 0
for i in range(l):
m,n = map(int,input().split())
top.append(m)
bottom.append(n)
for i in range(l):
if sum(top) % 2 ==0 and sum(bottom) % 2 ==0:
print(min)
exit()
else:
top[i],bottom[i]=bottom[i],top[i]
min... | Title: Domino
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera has got *n* domino pieces in a row. Each piece consists of two halves — the upper one and the lower one. Each of the halves contains a number from 1 to 6. Valera loves even integers very much, so he wants the sum of the n... | ```python
l = int(input())
top = []
bottom = []
min = 0
for i in range(l):
m,n = map(int,input().split())
top.append(m)
bottom.append(n)
for i in range(l):
if sum(top) % 2 ==0 and sum(bottom) % 2 ==0:
print(min)
exit()
else:
top[i],bottom[i]=bottom[i],top[i]
... | 0 | |
35 | A | Shell Game | PROGRAMMING | 1,000 | [
"implementation"
] | A. Shell Game | 2 | 64 | Today the «Z» city residents enjoy a shell game competition. The residents are gathered on the main square to watch the breath-taking performance. The performer puts 3 non-transparent cups upside down in a row. Then he openly puts a small ball under one of the cups and starts to shuffle the cups around very quickly so ... | The first input line contains an integer from 1 to 3 — index of the cup which covers the ball before the shuffles. The following three lines describe the shuffles. Each description of a shuffle contains two distinct integers from 1 to 3 — indexes of the cups which the performer shuffled this time. The cups are numbered... | In the first line output an integer from 1 to 3 — index of the cup which will have the ball after all the shuffles. | [
"1\n1 2\n2 1\n2 1\n",
"1\n2 1\n3 1\n1 3\n"
] | [
"2\n",
"2\n"
] | none | 500 | [
{
"input": "1\n1 2\n2 1\n2 1",
"output": "2"
},
{
"input": "1\n2 1\n3 1\n1 3",
"output": "2"
},
{
"input": "3\n3 1\n2 1\n1 2",
"output": "1"
},
{
"input": "1\n1 3\n1 2\n2 3",
"output": "2"
},
{
"input": "3\n3 2\n3 1\n3 1",
"output": "2"
},
{
"input": "... | 1,648,660,406 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 92 | 0 | path = 'input.txt'
readFile = open(path, 'r')
pos = int(readFile.readline())
for i in range(3):
cup1, cup2 = [int(item) for item in readFile.readline().split(' ')]
if cup1 == pos:
pos = cup2
elif cup2 == pos:
pos = cup1
readFile.close()
writeFile = open("output.txt", 'w')
writeF... | Title: Shell Game
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Today the «Z» city residents enjoy a shell game competition. The residents are gathered on the main square to watch the breath-taking performance. The performer puts 3 non-transparent cups upside down in a row. Then he openly put... | ```python
path = 'input.txt'
readFile = open(path, 'r')
pos = int(readFile.readline())
for i in range(3):
cup1, cup2 = [int(item) for item in readFile.readline().split(' ')]
if cup1 == pos:
pos = cup2
elif cup2 == pos:
pos = cup1
readFile.close()
writeFile = open("output.txt", 'w... | 3.977 |
777 | A | Shell Game | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | Bomboslav likes to look out of the window in his room and watch lads outside playing famous shell game. The game is played by two persons: operator and player. Operator takes three similar opaque shells and places a ball beneath one of them. Then he shuffles the shells by swapping some pairs and the player has to guess... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=2·109) — the number of movements made by the operator.
The second line contains a single integer *x* (0<=≤<=*x*<=≤<=2) — the index of the shell where the ball was found after *n* movements. | Print one integer from 0 to 2 — the index of the shell where the ball was initially placed. | [
"4\n2\n",
"1\n1\n"
] | [
"1\n",
"0\n"
] | In the first sample, the ball was initially placed beneath the middle shell and the operator completed four movements.
1. During the first move operator swapped the left shell and the middle shell. The ball is now under the left shell. 1. During the second move operator swapped the middle shell and the right one. Th... | 500 | [
{
"input": "4\n2",
"output": "1"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "2\n2",
"output": "0"
},
{
"input": "3\n1",
"output": "1"
},
{
"input": "3\n2",
"output": "0"
},
{
"input": "3\n0",
"output": "2"
},
{
"input": "2000000000\n... | 1,573,723,457 | 2,147,483,647 | Python 3 | OK | TESTS | 68 | 109 | 0 | n=int(input())
x=int(input())
seq=[[0,1,2],[1,0,2],[1,2,0],[2,1,0],[2,0,1],[0,2,1]]
p=n%6
print(seq[p][x]) | Title: Shell Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bomboslav likes to look out of the window in his room and watch lads outside playing famous shell game. The game is played by two persons: operator and player. Operator takes three similar opaque shells and places a ball ben... | ```python
n=int(input())
x=int(input())
seq=[[0,1,2],[1,0,2],[1,2,0],[2,1,0],[2,0,1],[0,2,1]]
p=n%6
print(seq[p][x])
``` | 3 | |
702 | A | Maximum Increase | PROGRAMMING | 800 | [
"dp",
"greedy",
"implementation"
] | null | null | You are given array consisting of *n* integers. Your task is to find the maximum length of an increasing subarray of the given array.
A subarray is the sequence of consecutive elements of the array. Subarray is called increasing if each element of this subarray strictly greater than previous. | The first line contains single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of integers.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print the maximum length of an increasing subarray of the given array. | [
"5\n1 7 2 11 15\n",
"6\n100 100 100 100 100 100\n",
"3\n1 2 3\n"
] | [
"3\n",
"1\n",
"3\n"
] | none | 0 | [
{
"input": "5\n1 7 2 11 15",
"output": "3"
},
{
"input": "6\n100 100 100 100 100 100",
"output": "1"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "1\n1000000000",
"output": "1"
},
{
"input": "10\n802030518 598196518 640274071 983359971 71550121 96204862 7... | 1,679,585,705 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 124 | 8,806,400 | n = int(input())
entrada = input()
arreglo = entrada.split()
arreglo_ent = []
numero = float('inf')
contador = 1
maximo = contador
for i in range(n):
arreglo_ent.append(int(arreglo[i]))
for i in range(n):
if(arreglo_ent[i] > numero):
numero = arreglo_ent[i]
contador += 1
else:
... | Title: Maximum Increase
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given array consisting of *n* integers. Your task is to find the maximum length of an increasing subarray of the given array.
A subarray is the sequence of consecutive elements of the array. Subarray is called... | ```python
n = int(input())
entrada = input()
arreglo = entrada.split()
arreglo_ent = []
numero = float('inf')
contador = 1
maximo = contador
for i in range(n):
arreglo_ent.append(int(arreglo[i]))
for i in range(n):
if(arreglo_ent[i] > numero):
numero = arreglo_ent[i]
contador += 1
else... | 3 | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,629,664,487 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 6,963,200 | n = int(input())
numbers = [int(num) for num in input().split()]
even = {}
odd = {}
for index, num in enumerate(numbers):
if num % 2:
odd[num] = index + 1
else:
even[num] = index + 1
if len(even) > len(odd):
print(list(odd.values())[0])
else:
print(list(even.val... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n = int(input())
numbers = [int(num) for num in input().split()]
even = {}
odd = {}
for index, num in enumerate(numbers):
if num % 2:
odd[num] = index + 1
else:
even[num] = index + 1
if len(even) > len(odd):
print(list(odd.values())[0])
else:
print(lis... | 0 |
433 | B | Kuriyama Mirai's Stones | PROGRAMMING | 1,200 | [
"dp",
"implementation",
"sortings"
] | null | null | Kuriyama Mirai has killed many monsters and got many (namely *n*) stones. She numbers the stones from 1 to *n*. The cost of the *i*-th stone is *v**i*. Kuriyama Mirai wants to know something about these stones so she will ask you two kinds of questions:
1. She will tell you two numbers, *l* and *r* (1<=≤<=*l*<=≤<=*r*... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105). The second line contains *n* integers: *v*1,<=*v*2,<=...,<=*v**n* (1<=≤<=*v**i*<=≤<=109) — costs of the stones.
The third line contains an integer *m* (1<=≤<=*m*<=≤<=105) — the number of Kuriyama Mirai's questions. Then follow *m* lines, each line contains t... | Print *m* lines. Each line must contain an integer — the answer to Kuriyama Mirai's question. Print the answers to the questions in the order of input. | [
"6\n6 4 2 7 2 7\n3\n2 3 6\n1 3 4\n1 1 6\n",
"4\n5 5 2 3\n10\n1 2 4\n2 1 4\n1 1 1\n2 1 4\n2 1 2\n1 1 1\n1 3 3\n1 1 3\n1 4 4\n1 2 2\n"
] | [
"24\n9\n28\n",
"10\n15\n5\n15\n5\n5\n2\n12\n3\n5\n"
] | Please note that the answers to the questions may overflow 32-bit integer type. | 1,500 | [
{
"input": "6\n6 4 2 7 2 7\n3\n2 3 6\n1 3 4\n1 1 6",
"output": "24\n9\n28"
},
{
"input": "4\n5 5 2 3\n10\n1 2 4\n2 1 4\n1 1 1\n2 1 4\n2 1 2\n1 1 1\n1 3 3\n1 1 3\n1 4 4\n1 2 2",
"output": "10\n15\n5\n15\n5\n5\n2\n12\n3\n5"
},
{
"input": "4\n2 2 3 6\n9\n2 2 3\n1 1 3\n2 2 3\n2 2 3\n2 2 2\n1... | 1,647,261,092 | 2,147,483,647 | PyPy 3 | OK | TESTS | 46 | 639 | 22,528,000 | import sys
input = sys.stdin.readline
def solve(L, pref, sorty_pref, t, l, r):
l -= 1
if t == 1: return pref[r] - pref[l]
return sorty_pref[r] - sorty_pref[l]
N = int(input())
L = list(map(int, input().split()))
sorty_L = sorted(L)
pref = [0]
sorty_pref = [0]
for i in range(N):
pref.appe... | Title: Kuriyama Mirai's Stones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kuriyama Mirai has killed many monsters and got many (namely *n*) stones. She numbers the stones from 1 to *n*. The cost of the *i*-th stone is *v**i*. Kuriyama Mirai wants to know something about these stones s... | ```python
import sys
input = sys.stdin.readline
def solve(L, pref, sorty_pref, t, l, r):
l -= 1
if t == 1: return pref[r] - pref[l]
return sorty_pref[r] - sorty_pref[l]
N = int(input())
L = list(map(int, input().split()))
sorty_L = sorted(L)
pref = [0]
sorty_pref = [0]
for i in range(N):
... | 3 | |
499 | A | Watching a movie | PROGRAMMING | 1,000 | [
"greedy",
"implementation"
] | null | null | You have decided to watch the best moments of some movie. There are two buttons on your player:
1. Watch the current minute of the movie. By pressing this button, you watch the current minute of the movie and the player automatically proceeds to the next minute of the movie. 1. Skip exactly *x* minutes of the movie... | The first line contains two space-separated integers *n*, *x* (1<=≤<=*n*<=≤<=50, 1<=≤<=*x*<=≤<=105) — the number of the best moments of the movie and the value of *x* for the second button.
The following *n* lines contain the descriptions of the best moments of the movie, the *i*-th line of the description contains tw... | Output a single number — the answer to the problem. | [
"2 3\n5 6\n10 12\n",
"1 1\n1 100000\n"
] | [
"6\n",
"100000\n"
] | In the first sample, the player was initially standing on the first minute. As the minutes from the 1-st to the 4-th one don't contain interesting moments, we press the second button. Now we can not press the second button and skip 3 more minutes, because some of them contain interesting moments. Therefore, we watch th... | 500 | [
{
"input": "2 3\n5 6\n10 12",
"output": "6"
},
{
"input": "1 1\n1 100000",
"output": "100000"
},
{
"input": "10 1\n2156 3497\n4784 7775\n14575 31932\n33447 35902\n36426 47202\n48772 60522\n63982 68417\n78537 79445\n90081 90629\n94325 95728",
"output": "53974"
},
{
"input": "1... | 1,591,537,343 | 2,147,483,647 | PyPy 3 | OK | TESTS | 41 | 140 | 0 | n,x = map(int, input().split())
data = []
result = 0
for _ in range(n):
data.append(list(map(int, input().split())))
for i in range(n):
if i==0:
result += (data[i][0]-1)%x
else:
result += (data[i][0]-data[i-1][1]-1)%x
result += data[i][1]-data[i][0]+1
print(result) | Title: Watching a movie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have decided to watch the best moments of some movie. There are two buttons on your player:
1. Watch the current minute of the movie. By pressing this button, you watch the current minute of the movie and the pl... | ```python
n,x = map(int, input().split())
data = []
result = 0
for _ in range(n):
data.append(list(map(int, input().split())))
for i in range(n):
if i==0:
result += (data[i][0]-1)%x
else:
result += (data[i][0]-data[i-1][1]-1)%x
result += data[i][1]-data[i][0]+1
print(res... | 3 | |
700 | A | As Fast As Possible | PROGRAMMING | 1,900 | [
"binary search",
"math"
] | null | null | On vacations *n* pupils decided to go on excursion and gather all together. They need to overcome the path with the length *l* meters. Each of the pupils will go with the speed equal to *v*1. To get to the excursion quickly, it was decided to rent a bus, which has seats for *k* people (it means that it can't fit more t... | The first line of the input contains five positive integers *n*, *l*, *v*1, *v*2 and *k* (1<=≤<=*n*<=≤<=10<=000, 1<=≤<=*l*<=≤<=109, 1<=≤<=*v*1<=<<=*v*2<=≤<=109, 1<=≤<=*k*<=≤<=*n*) — the number of pupils, the distance from meeting to the place of excursion, the speed of each pupil, the speed of bus and the number of ... | Print the real number — the minimum time in which all pupils can reach the place of excursion. Your answer will be considered correct if its absolute or relative error won't exceed 10<=-<=6. | [
"5 10 1 2 5\n",
"3 6 1 2 1\n"
] | [
"5.0000000000\n",
"4.7142857143\n"
] | In the first sample we should immediately put all five pupils to the bus. The speed of the bus equals 2 and the distance is equal to 10, so the pupils will reach the place of excursion in time 10 / 2 = 5. | 500 | [
{
"input": "5 10 1 2 5",
"output": "5.0000000000"
},
{
"input": "3 6 1 2 1",
"output": "4.7142857143"
},
{
"input": "39 252 51 98 26",
"output": "3.5344336938"
},
{
"input": "59 96 75 98 9",
"output": "1.2315651330"
},
{
"input": "87 237 3 21 40",
"output": "3... | 1,656,584,579 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 46 | 0 | n,l,v,r,k=map(int,input().split())
n=(n+k-1)//k
a=(n-1)*(r-v)/(v+r)
print(l/r/(n-a)*(n+a)) | Title: As Fast As Possible
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On vacations *n* pupils decided to go on excursion and gather all together. They need to overcome the path with the length *l* meters. Each of the pupils will go with the speed equal to *v*1. To get to the excursion... | ```python
n,l,v,r,k=map(int,input().split())
n=(n+k-1)//k
a=(n-1)*(r-v)/(v+r)
print(l/r/(n-a)*(n+a))
``` | 3 | |
855 | B | Marvolo Gaunt's Ring | PROGRAMMING | 1,500 | [
"brute force",
"data structures",
"dp"
] | null | null | Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed it, he is still affected by its curse. Professor Snape is helping Dumbledore remove the curse. For this, he... | First line of input contains 4 integers *n*,<=*p*,<=*q*,<=*r* (<=-<=109<=≤<=*p*,<=*q*,<=*r*<=≤<=109,<=1<=≤<=*n*<=≤<=105).
Next line of input contains *n* space separated integers *a*1,<=*a*2,<=... *a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | Output a single integer the maximum value of *p*·*a**i*<=+<=*q*·*a**j*<=+<=*r*·*a**k* that can be obtained provided 1<=≤<=*i*<=≤<=*j*<=≤<=*k*<=≤<=*n*. | [
"5 1 2 3\n1 2 3 4 5\n",
"5 1 2 -3\n-1 -2 -3 -4 -5\n"
] | [
"30\n",
"12\n"
] | In the first sample case, we can take *i* = *j* = *k* = 5, thus making the answer as 1·5 + 2·5 + 3·5 = 30.
In second sample case, selecting *i* = *j* = 1 and *k* = 5 gives the answer 12. | 1,000 | [
{
"input": "5 1 2 3\n1 2 3 4 5",
"output": "30"
},
{
"input": "5 1 2 -3\n-1 -2 -3 -4 -5",
"output": "12"
},
{
"input": "5 886327859 82309257 -68295239\n-731225382 354766539 -48222231 -474691998 360965777",
"output": "376059240645059046"
},
{
"input": "4 -96405765 -495906217 6... | 1,582,088,079 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 78 | 0 | n,p,q,r=[int(x) for x in input().split()]
arr=[int(x) for x in input().split()]
n=len(arr)
max1=0
for i in range(n-2):
for j in range(i,n-1):
for k in range(j,n):
val=p*arr[i]+q*arr[j]+r*arr[k]
if max1<val:
max1=val
s,t,u=i,j,k
print(max1) | Title: Marvolo Gaunt's Ring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed i... | ```python
n,p,q,r=[int(x) for x in input().split()]
arr=[int(x) for x in input().split()]
n=len(arr)
max1=0
for i in range(n-2):
for j in range(i,n-1):
for k in range(j,n):
val=p*arr[i]+q*arr[j]+r*arr[k]
if max1<val:
max1=val
s,t,u=i,j,k
p... | 0 | |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,591,086,571 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 3,072,000 | def div(n) :
a=[]
i = 1
while i <= math.sqrt(n):
if (n % i == 0) :
if (n / i == i) :
a.append(i)
else :
a.append(i)
a.append(n//i)
i = i + 1
a.sort()
return a
import sys,math
n,k=map(int,sys.s... | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
def div(n) :
a=[]
i = 1
while i <= math.sqrt(n):
if (n % i == 0) :
if (n / i == i) :
a.append(i)
else :
a.append(i)
a.append(n//i)
i = i + 1
a.sort()
return a
import sys,math
n,k=map... | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Felix the Robot is preparing for a probability theory exam. Unfortunately, during the semester, he took a course of the belles-lettres instead of studying the subject, so now he does not know the answer to any of the upcoming exam's questions. One thing is for sure: Felix needs help!
The exam for robots is an online e... | none | none | [] | [] | none | 5,644 | [] | 1,465,741,512 | 19,512 | Python 3 | SKIPPED | PRETESTS | 100 | 124 | 5,939,200 | import random
import sys
n = 5000
k = 2000
x = 100
random.seed (12345)
for attempt in range (3):
for position in range (n):
sys.stdout.write (random.choice ('01'))
sys.stdout.write ('\n')
sys.stdout.flush ()
res = int (sys.stdin.readline ())
sys.stderr.write ('{0:5d}'.format (res))
sys.std... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Felix the Robot is preparing for a probability theory exam. Unfortunately, during the semester, he took a course of the belles-lettres instead of studying the subject, so now he does not know the answer to any of the upcoming exam... | ```python
import random
import sys
n = 5000
k = 2000
x = 100
random.seed (12345)
for attempt in range (3):
for position in range (n):
sys.stdout.write (random.choice ('01'))
sys.stdout.write ('\n')
sys.stdout.flush ()
res = int (sys.stdin.readline ())
sys.stderr.write ('{0:5d}'.format (res... | -1 | |
978 | F | Mentors | PROGRAMMING | 1,500 | [
"binary search",
"data structures",
"implementation"
] | null | null | In BerSoft $n$ programmers work, the programmer $i$ is characterized by a skill $r_i$.
A programmer $a$ can be a mentor of a programmer $b$ if and only if the skill of the programmer $a$ is strictly greater than the skill of the programmer $b$ $(r_a > r_b)$ and programmers $a$ and $b$ are not in a quarrel.
You are... | The first line contains two integers $n$ and $k$ $(2 \le n \le 2 \cdot 10^5$, $0 \le k \le \min(2 \cdot 10^5, \frac{n \cdot (n - 1)}{2}))$ — total number of programmers and number of pairs of programmers which are in a quarrel.
The second line contains a sequence of integers $r_1, r_2, \dots, r_n$ $(1 \le r_i \le 10^{... | Print $n$ integers, the $i$-th number should be equal to the number of programmers, for which the $i$-th programmer can be a mentor. Programmers are numbered in the same order that their skills are given in the input. | [
"4 2\n10 4 10 15\n1 2\n4 3\n",
"10 4\n5 4 1 5 4 3 7 1 2 5\n4 6\n2 1\n10 8\n3 5\n"
] | [
"0 0 1 2 \n",
"5 4 0 5 3 3 9 0 2 5 \n"
] | In the first example, the first programmer can not be mentor of any other (because only the second programmer has a skill, lower than first programmer skill, but they are in a quarrel). The second programmer can not be mentor of any other programmer, because his skill is minimal among others. The third programmer can b... | 0 | [
{
"input": "4 2\n10 4 10 15\n1 2\n4 3",
"output": "0 0 1 2 "
},
{
"input": "10 4\n5 4 1 5 4 3 7 1 2 5\n4 6\n2 1\n10 8\n3 5",
"output": "5 4 0 5 3 3 9 0 2 5 "
},
{
"input": "2 0\n3 1",
"output": "1 0 "
},
{
"input": "2 0\n1 1",
"output": "0 0 "
},
{
"input": "10 35... | 1,679,147,671 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 31 | 0 | n,k=map(int,input().split())
a=list(map(int,input().split()))
f={}
pos={}
for i in range(n):
f[i]=0
for j in range(k):
x,y=map(int,input().split())
x-=1;y-=1
if a[x]<a[y]:
f[y]+=1
else:
f[x]+=1
s=[-1]+sorted(a)
#print(f)
for i in range(n):
res=a[i]
l=0
... | Title: Mentors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In BerSoft $n$ programmers work, the programmer $i$ is characterized by a skill $r_i$.
A programmer $a$ can be a mentor of a programmer $b$ if and only if the skill of the programmer $a$ is strictly greater than the skill of t... | ```python
n,k=map(int,input().split())
a=list(map(int,input().split()))
f={}
pos={}
for i in range(n):
f[i]=0
for j in range(k):
x,y=map(int,input().split())
x-=1;y-=1
if a[x]<a[y]:
f[y]+=1
else:
f[x]+=1
s=[-1]+sorted(a)
#print(f)
for i in range(n):
res=a[i]
... | 0 | |
304 | A | Pythagorean Theorem II | PROGRAMMING | 1,200 | [
"brute force",
"math"
] | null | null | In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the s... | The only line contains one integer *n* (1<=≤<=*n*<=≤<=104) as we mentioned above. | Print a single integer — the answer to the problem. | [
"5\n",
"74\n"
] | [
"1\n",
"35\n"
] | none | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "74",
"output": "35"
},
{
"input": "1000",
"output": "881"
},
{
"input": "586",
"output": "472"
},
{
"input": "2",
"output": "0"
},
{
"input": "362",
"output": "258"
},
{
"input": "778",
"outp... | 1,620,153,380 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 30 | 3,000 | 0 | import math
lim=int(input())
count=0
m=lim**2
for i in range(1,lim+1):
for j in range(i,lim+1):
z=i*i+j*j
z=math.sqrt(z)
if int(z)!=z or z>lim:
continue
count+=1
print(count) | Title: Pythagorean Theorem II
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the squar... | ```python
import math
lim=int(input())
count=0
m=lim**2
for i in range(1,lim+1):
for j in range(i,lim+1):
z=i*i+j*j
z=math.sqrt(z)
if int(z)!=z or z>lim:
continue
count+=1
print(count)
``` | 0 | |
556 | A | Case of the Zeros and Ones | PROGRAMMING | 900 | [
"greedy"
] | null | null | Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, an... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=2·105), the length of the string that Andreid has.
The second line contains the string of length *n* consisting only from zeros and ones. | Output the minimum length of the string that may remain after applying the described operations several times. | [
"4\n1100\n",
"5\n01010\n",
"8\n11101111\n"
] | [
"0\n",
"1\n",
"6\n"
] | In the first sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/10df55364c21c6e8d5da31b6ab6f6294c4fc26b3.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample test it is possible to change the string like... | 250 | [
{
"input": "4\n1100",
"output": "0"
},
{
"input": "5\n01010",
"output": "1"
},
{
"input": "8\n11101111",
"output": "6"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "2"
},
{
"input"... | 1,639,080,473 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 62 | 204,800 | length = int(input())
astring = input()
one = astring.count("1")
print(length - 2*min(length - one, one)) | Title: Case of the Zeros and Ones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Cons... | ```python
length = int(input())
astring = input()
one = astring.count("1")
print(length - 2*min(length - one, one))
``` | 3 | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,588,907,977 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 109 | 6,963,200 | """
https://codeforces.com/problemset/problem/910/A
Input
n point that has to be reached
d max length of jump
s consisting of zeroes and ones
0 = no lily flower
1 = lily flower (frog can jump here)
Output
x min number of jumps needed to reach n
-1 if n can't be reached
"""
n, d = map(int, input(... | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
"""
https://codeforces.com/problemset/problem/910/A
Input
n point that has to be reached
d max length of jump
s consisting of zeroes and ones
0 = no lily flower
1 = lily flower (frog can jump here)
Output
x min number of jumps needed to reach n
-1 if n can't be reached
"""
n, d = map(i... | 3 | |
186 | A | Comparing Strings | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Mish... | The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that co... | Print "YES", if the dwarves belong to the same race. Otherwise, print "NO". | [
"ab\nba\n",
"aa\nab\n"
] | [
"YES\n",
"NO\n"
] | - First example: you can simply swap two letters in string "ab". So we get "ba". - Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b". | 500 | [
{
"input": "ab\nba",
"output": "YES"
},
{
"input": "aa\nab",
"output": "NO"
},
{
"input": "a\nza",
"output": "NO"
},
{
"input": "vvea\nvvae",
"output": "YES"
},
{
"input": "rtfabanpc\natfabrnpc",
"output": "YES"
},
{
"input": "mt\ntm",
"output": "Y... | 1,610,457,494 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | s1 = input()
s2 = input()
cnt = 0
if len(s1) != len(s2):
print("NO")
else:
for i in range(len(s1)):
if s1[i]==s2[i]:
continue
else:
cnt+=1
if cnt==2:
print("YES")
else:
print("NO") | Title: Comparing Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome ... | ```python
s1 = input()
s2 = input()
cnt = 0
if len(s1) != len(s2):
print("NO")
else:
for i in range(len(s1)):
if s1[i]==s2[i]:
continue
else:
cnt+=1
if cnt==2:
print("YES")
else:
print("NO")
``` | 0 | |
355 | A | Vasya and Digital Root | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation"
] | null | null | Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=+<=9<=+<=8<==<=21. Then the digital root of number *n* equals to:
1. *dr*(*n*)<==<=*S*(*n*), if *S*(*n*)<... | The first line contains two integers *k* and *d* (1<=≤<=*k*<=≤<=1000; 0<=≤<=*d*<=≤<=9). | In a single line print either any number that meets the requirements (without the leading zeroes) or "No solution" (without the quotes), if the corresponding number does not exist.
The chosen number must consist of exactly *k* digits. We assume that number 0 doesn't contain any leading zeroes. | [
"4 4\n",
"5 1\n",
"1 0\n"
] | [
"5881\n",
"36172\n",
"0\n"
] | For the first test sample *dr*(5881) = *dr*(22) = 4.
For the second test sample *dr*(36172) = *dr*(19) = *dr*(10) = 1. | 500 | [
{
"input": "4 4",
"output": "5881"
},
{
"input": "5 1",
"output": "36172"
},
{
"input": "1 0",
"output": "0"
},
{
"input": "8 7",
"output": "49722154"
},
{
"input": "487 0",
"output": "No solution"
},
{
"input": "1000 5",
"output": "854193955406789... | 1,655,095,464 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 77 | 0 | k,d=map(int,input().split())
s = str(d)
k-=1
while k>0:
s+="0"
k-=1
print(s) | Title: Vasya and Digital Root
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=... | ```python
k,d=map(int,input().split())
s = str(d)
k-=1
while k>0:
s+="0"
k-=1
print(s)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | There is a rectangular grid of *n* rows of *m* initially-white cells each.
Arkady performed a certain number (possibly zero) of operations on it. In the *i*-th operation, a non-empty subset of rows *R**i* and a non-empty subset of columns *C**i* are chosen. For each row *r* in *R**i* and each column *c* in *C**i*, the... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the number of rows and columns of the grid, respectively.
Each of the following *n* lines contains a string of *m* characters, each being either '.' (denoting a white cell) or '#' (denoting a black cell), representing the desir... | If the given grid can be achieved by any valid sequence of operations, output "Yes"; otherwise output "No" (both without quotes).
You can print each character in any case (upper or lower). | [
"5 8\n.#.#..#.\n.....#..\n.#.#..#.\n#.#....#\n.....#..\n",
"5 5\n..#..\n..#..\n#####\n..#..\n..#..\n",
"5 9\n........#\n#........\n..##.#...\n.......#.\n....#.#.#\n"
] | [
"Yes\n",
"No\n",
"No\n"
] | For the first example, the desired setup can be produced by 3 operations, as is shown below.
For the second example, the desired setup cannot be produced, since in order to colour the center row, the third row and all columns must be selected in one operation, but after that no column can be selected again, hence it w... | 0 | [
{
"input": "5 8\n.#.#..#.\n.....#..\n.#.#..#.\n#.#....#\n.....#..",
"output": "Yes"
},
{
"input": "5 5\n..#..\n..#..\n#####\n..#..\n..#..",
"output": "No"
},
{
"input": "5 9\n........#\n#........\n..##.#...\n.......#.\n....#.#.#",
"output": "No"
},
{
"input": "1 1\n#",
"o... | 1,523,876,368 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 109 | 7,065,600 | n,m = map(int, input().split())
x = []
for i in range(n):
l = list(input())
x.append(l)
for i in range(n):
for j in range(n):
if x[i] != x[j]:
for z in range(m):
if x[i][z] == x[j][z] == '#':
print('No')
exit()
pri... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a rectangular grid of *n* rows of *m* initially-white cells each.
Arkady performed a certain number (possibly zero) of operations on it. In the *i*-th operation, a non-empty subset of rows *R**i* and a non-empty subset o... | ```python
n,m = map(int, input().split())
x = []
for i in range(n):
l = list(input())
x.append(l)
for i in range(n):
for j in range(n):
if x[i] != x[j]:
for z in range(m):
if x[i][z] == x[j][z] == '#':
print('No')
exi... | 3 | |
859 | A | Declined Finalists | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | This year, as in previous years, MemSQL is inviting the top 25 competitors from the Start[c]up qualification round to compete onsite for the final round. Not everyone who is eligible to compete onsite can afford to travel to the office, though. Initially the top 25 contestants are invited to come onsite. Each eligible ... | The first line of input contains *K* (1<=≤<=*K*<=≤<=25), the number of onsite finalists you know. The second line of input contains *r*1,<=*r*2,<=...,<=*r**K* (1<=≤<=*r**i*<=≤<=106), the qualifying ranks of the finalists you know. All these ranks are distinct. | Print the minimum possible number of contestants that declined the invitation to compete onsite. | [
"25\n2 3 4 5 6 7 8 9 10 11 12 14 15 16 17 18 19 20 21 22 23 24 25 26 28\n",
"5\n16 23 8 15 4\n",
"3\n14 15 92\n"
] | [
"3\n",
"0\n",
"67\n"
] | In the first example, you know all 25 onsite finalists. The contestants who ranked 1-st, 13-th, and 27-th must have declined, so the answer is 3. | 500 | [
{
"input": "25\n2 3 4 5 6 7 8 9 10 11 12 14 15 16 17 18 19 20 21 22 23 24 25 26 28",
"output": "3"
},
{
"input": "5\n16 23 8 15 4",
"output": "0"
},
{
"input": "3\n14 15 92",
"output": "67"
},
{
"input": "1\n1000000",
"output": "999975"
},
{
"input": "25\n1000000 ... | 1,505,737,874 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | a = int(input())
lst = list(map(int,input().split()))
print(max(0,max(b)-25)) | Title: Declined Finalists
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This year, as in previous years, MemSQL is inviting the top 25 competitors from the Start[c]up qualification round to compete onsite for the final round. Not everyone who is eligible to compete onsite can afford to t... | ```python
a = int(input())
lst = list(map(int,input().split()))
print(max(0,max(b)-25))
``` | -1 | |
90 | B | African Crossword | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | B. African Crossword | 2 | 256 | An African crossword is a rectangular table *n*<=×<=*m* in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Next *n* lines contain *m* lowercase Latin letters each. That is the crossword grid. | Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter. | [
"3 3\ncba\nbcd\ncbc\n",
"5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf\n"
] | [
"abcd",
"codeforces"
] | none | 1,000 | [
{
"input": "3 3\ncba\nbcd\ncbc",
"output": "abcd"
},
{
"input": "5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf",
"output": "codeforces"
},
{
"input": "4 4\nusah\nusha\nhasu\nsuha",
"output": "ahhasusu"
},
{
"input": "7 5\naabcd\neffgh\niijkk\nlmnoo\npqqrs\nttuvw\nxxyyz",
"output... | 1,697,154,753 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 5 | 92 | 0 | n, m = map(int, input().split())
lofl = [list(input()) for _ in range(n)]
remove = set()
for i in range(n):
for j in range(m):
current = lofl[i][j]
flag = False
for x in range(n):
if x != i and x < m:
if (lofl[x][j]) == current:
r... | Title: African Crossword
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
An African crossword is a rectangular table *n*<=×<=*m* in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To s... | ```python
n, m = map(int, input().split())
lofl = [list(input()) for _ in range(n)]
remove = set()
for i in range(n):
for j in range(m):
current = lofl[i][j]
flag = False
for x in range(n):
if x != i and x < m:
if (lofl[x][j]) == current:
... | 0 |
863 | A | Quasi-palindrome | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Let quasi-palindromic number be such number that adding some leading zeros (possible none) to it produces a palindromic string.
String *t* is called a palindrome, if it reads the same from left to right and from right to left.
For example, numbers 131 and 2010200 are quasi-palindromic, they can be transformed to str... | The first line contains one integer number *x* (1<=≤<=*x*<=≤<=109). This number is given without any leading zeroes. | Print "YES" if number *x* is quasi-palindromic. Otherwise, print "NO" (without quotes). | [
"131\n",
"320\n",
"2010200\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 0 | [
{
"input": "131",
"output": "YES"
},
{
"input": "320",
"output": "NO"
},
{
"input": "2010200",
"output": "YES"
},
{
"input": "1",
"output": "YES"
},
{
"input": "1000000000",
"output": "YES"
},
{
"input": "999999999",
"output": "YES"
},
{
"i... | 1,583,941,241 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 9 | 139 | 0 | c = str(input())
x= len(c)-len(c.rstrip('0'))
c= x*'0'+c
l=len(c)
j= c[: l//2]
k= c[l//2+1:]
k=k[::-1]
if j==k:
print("YES")
else:
print("NO") | Title: Quasi-palindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let quasi-palindromic number be such number that adding some leading zeros (possible none) to it produces a palindromic string.
String *t* is called a palindrome, if it reads the same from left to right and from righ... | ```python
c = str(input())
x= len(c)-len(c.rstrip('0'))
c= x*'0'+c
l=len(c)
j= c[: l//2]
k= c[l//2+1:]
k=k[::-1]
if j==k:
print("YES")
else:
print("NO")
``` | 0 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,586,341,023 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 372 | 2,150,400 | s=input()
l=[]
for i in range(len(s)-1):
if s[i]=='-':
if s[i+1]=='-':
l[i]='2'
if s[i]=='.':
if s[i+1]=='-':
l[i]='1'
else:
l[i]='0'
print("".join(l))
| Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
s=input()
l=[]
for i in range(len(s)-1):
if s[i]=='-':
if s[i+1]=='-':
l[i]='2'
if s[i]=='.':
if s[i+1]=='-':
l[i]='1'
else:
l[i]='0'
print("".join(l))
``` | -1 |
681 | A | A Good Contest | PROGRAMMING | 800 | [
"implementation"
] | null | null | Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part in a rated contest, his rating is changed depending on his performance.
Anton wants the color of hi... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants Anton has outscored in this contest .
The next *n* lines describe participants results: the *i*-th of them consists of a participant handle *name**i* and two integers *before**i* and *after**i* (<=-<=4000<=≤<=*be... | Print «YES» (quotes for clarity), if Anton has performed good in the contest and «NO» (quotes for clarity) otherwise. | [
"3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749\n",
"3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450\n"
] | [
"YES",
"NO"
] | In the first sample, Anton has outscored user with handle Burunduk1, whose handle was colored red before the contest and his rating has increased after the contest.
In the second sample, Applejack's rating has not increased after the contest, while both Fluttershy's and Pinkie_Pie's handles were not colored red before... | 500 | [
{
"input": "3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749",
"output": "YES"
},
{
"input": "3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450",
"output": "NO"
},
{
"input": "1\nDb -3373 3591",
"output": "NO"
},
{
"input": "5\nQ2bz 960 2342... | 1,657,044,670 | 2,147,483,647 | Python 3 | OK | TESTS | 60 | 46 | 0 | n=int(input())
part=[]
for i in range(n):
x=input().split()
part.append([x[0]]+list(map(int,x[1:])))
for i in part:
if i[1]>=2400 and i[2]>i[1]:
print("YES")
break
else:
print("NO")
| Title: A Good Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part ... | ```python
n=int(input())
part=[]
for i in range(n):
x=input().split()
part.append([x[0]]+list(map(int,x[1:])))
for i in part:
if i[1]>=2400 and i[2]>i[1]:
print("YES")
break
else:
print("NO")
``` | 3 | |
999 | D | Equalize the Remainders | PROGRAMMING | 1,900 | [
"data structures",
"greedy",
"implementation"
] | null | null | You are given an array consisting of $n$ integers $a_1, a_2, \dots, a_n$, and a positive integer $m$. It is guaranteed that $m$ is a divisor of $n$.
In a single move, you can choose any position $i$ between $1$ and $n$ and increase $a_i$ by $1$.
Let's calculate $c_r$ ($0 \le r \le m-1)$ — the number of elements havin... | The first line of input contains two integers $n$ and $m$ ($1 \le n \le 2 \cdot 10^5, 1 \le m \le n$). It is guaranteed that $m$ is a divisor of $n$.
The second line of input contains $n$ integers $a_1, a_2, \dots, a_n$ ($0 \le a_i \le 10^9$), the elements of the array. | In the first line, print a single integer — the minimum number of moves required to satisfy the following condition: for each remainder from $0$ to $m - 1$, the number of elements of the array having this remainder equals $\frac{n}{m}$.
In the second line, print any array satisfying the condition and can be obtained f... | [
"6 3\n3 2 0 6 10 12\n",
"4 2\n0 1 2 3\n"
] | [
"3\n3 2 0 7 10 14 \n",
"0\n0 1 2 3 \n"
] | none | 0 | [
{
"input": "6 3\n3 2 0 6 10 12",
"output": "3\n3 2 0 7 10 14 "
},
{
"input": "4 2\n0 1 2 3",
"output": "0\n0 1 2 3 "
},
{
"input": "1 1\n1000000000",
"output": "0\n1000000000 "
},
{
"input": "6 3\n3 2 0 6 10 11",
"output": "1\n3 2 0 7 10 11 "
},
{
"input": "100 25... | 1,659,819,056 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 47 | 389 | 53,862,400 | from collections import *
from heapq import *
from bisect import *
from itertools import *
from functools import *
from math import *
from string import *
import sys
input = sys.stdin.readline
def main():
n, m = map(int, input().split())
A = list(map(int, input().split()))
target = n // m
... | Title: Equalize the Remainders
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array consisting of $n$ integers $a_1, a_2, \dots, a_n$, and a positive integer $m$. It is guaranteed that $m$ is a divisor of $n$.
In a single move, you can choose any position $i$ between $1$... | ```python
from collections import *
from heapq import *
from bisect import *
from itertools import *
from functools import *
from math import *
from string import *
import sys
input = sys.stdin.readline
def main():
n, m = map(int, input().split())
A = list(map(int, input().split()))
target... | 3 | |
509 | A | Maximum in Table | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the ... | The only line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=10) — the number of rows and columns of the table. | Print a single line containing a positive integer *m* — the maximum value in the table. | [
"1\n",
"5\n"
] | [
"1",
"70"
] | In the second test the rows of the table look as follows: | 0 | [
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "70"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "6"
},
{
"input": "4",
"output": "20"
},
{
"input": "6",
"output": "252"
},
{
"input": "7",
"output": "924"
... | 1,608,171,709 | 2,147,483,647 | Python 3 | OK | TESTS | 10 | 108 | 307,200 | n=int(input())
if n==1:
print("1")
else:
dic=dict()
L1=[1 for i in range(n)]
dic[0]=L1
for i in range(1,n):
L=[1 for i in range(n)]
dic[i]=L
for j in range(1,n):
dic[i][j]=dic[i-1][j]+dic[i][j-1]
print(max(dic[len(dic)-1])) | Title: Maximum in Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the t... | ```python
n=int(input())
if n==1:
print("1")
else:
dic=dict()
L1=[1 for i in range(n)]
dic[0]=L1
for i in range(1,n):
L=[1 for i in range(n)]
dic[i]=L
for j in range(1,n):
dic[i][j]=dic[i-1][j]+dic[i][j-1]
print(max(dic[len(dic)-1]))
``` | 3 | |
509 | A | Maximum in Table | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the ... | The only line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=10) — the number of rows and columns of the table. | Print a single line containing a positive integer *m* — the maximum value in the table. | [
"1\n",
"5\n"
] | [
"1",
"70"
] | In the second test the rows of the table look as follows: | 0 | [
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "70"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "6"
},
{
"input": "4",
"output": "20"
},
{
"input": "6",
"output": "252"
},
{
"input": "7",
"output": "924"
... | 1,649,780,326 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 10 | 46 | 0 | n=int(input())
if n<3:
print(n)
else:
l=[]
for i in range(n):
p=[]
for j in range(n):
if i==0 or j==0:
p.append(1)
else:
p.append(p[j-1]+l[i-1][j])
l.append(p)
print(l[n-1][n-1]) | Title: Maximum in Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the t... | ```python
n=int(input())
if n<3:
print(n)
else:
l=[]
for i in range(n):
p=[]
for j in range(n):
if i==0 or j==0:
p.append(1)
else:
p.append(p[j-1]+l[i-1][j])
l.append(p)
print(l[n-1][n-1])
``` | 3 | |
869 | A | The Artful Expedient | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Rock... Paper!
After Karen have found the deterministic winning (losing?) strategy for rock-paper-scissors, her brother, Koyomi, comes up with a new game as a substitute. The game works as follows.
A positive integer *n* is decided first. Both Koyomi and Karen independently choose *n* distinct positive integers, deno... | The first line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=2<=000) — the length of both sequences.
The second line contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=2·106) — the integers finally chosen by Koyomi.
The third line contains *n* space-separated integers *y*1,<=... | Output one line — the name of the winner, that is, "Koyomi" or "Karen" (without quotes). Please be aware of the capitalization. | [
"3\n1 2 3\n4 5 6\n",
"5\n2 4 6 8 10\n9 7 5 3 1\n"
] | [
"Karen\n",
"Karen\n"
] | In the first example, there are 6 pairs satisfying the constraint: (1, 1), (1, 2), (2, 1), (2, 3), (3, 2) and (3, 3). Thus, Karen wins since 6 is an even number.
In the second example, there are 16 such pairs, and Karen wins again. | 500 | [
{
"input": "3\n1 2 3\n4 5 6",
"output": "Karen"
},
{
"input": "5\n2 4 6 8 10\n9 7 5 3 1",
"output": "Karen"
},
{
"input": "1\n1\n2000000",
"output": "Karen"
},
{
"input": "2\n97153 2000000\n1999998 254",
"output": "Karen"
},
{
"input": "15\n31 30 29 28 27 26 25 24... | 1,507,577,167 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 62 | 307,200 | a = int(input())
b= input()
c = input()
print("Karen") | Title: The Artful Expedient
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Rock... Paper!
After Karen have found the deterministic winning (losing?) strategy for rock-paper-scissors, her brother, Koyomi, comes up with a new game as a substitute. The game works as follows.
A positive int... | ```python
a = int(input())
b= input()
c = input()
print("Karen")
``` | 3 | |
32 | A | Reconnaissance | PROGRAMMING | 800 | [
"brute force"
] | A. Reconnaissance | 2 | 256 | According to the regulations of Berland's army, a reconnaissance unit should consist of exactly two soldiers. Since these two soldiers shouldn't differ much, their heights can differ by at most *d* centimeters. Captain Bob has *n* soldiers in his detachment. Their heights are *a*1,<=*a*2,<=...,<=*a**n* centimeters. Som... | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=1000,<=1<=≤<=*d*<=≤<=109) — amount of soldiers in Bob's detachment and the maximum allowed height difference respectively. The second line contains *n* space-separated integers — heights of all the soldiers in Bob's detachment. These numbers don't exceed 1... | Output one number — amount of ways to form a reconnaissance unit of two soldiers, whose height difference doesn't exceed *d*. | [
"5 10\n10 20 50 60 65\n",
"5 1\n55 30 29 31 55\n"
] | [
"6\n",
"6\n"
] | none | 500 | [
{
"input": "5 10\n10 20 50 60 65",
"output": "6"
},
{
"input": "5 1\n55 30 29 31 55",
"output": "6"
},
{
"input": "6 10\n4 6 4 1 9 3",
"output": "30"
},
{
"input": "7 100\n19 1694 261 162 1 234 513",
"output": "8"
},
{
"input": "8 42\n37 53 74 187 568 22 5 65",
... | 1,558,289,754 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 778 | 307,200 | n,d = input().split()
l = list(map(int,input().split()))
l.sort()
c=0
for i in range(0,len(l)):
for j in range(i+1,len(l)):
if l[j]-l[i] <= int(d): c=c+1
else:break
print(2*c) | Title: Reconnaissance
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
According to the regulations of Berland's army, a reconnaissance unit should consist of exactly two soldiers. Since these two soldiers shouldn't differ much, their heights can differ by at most *d* centimeters. Captain Bob h... | ```python
n,d = input().split()
l = list(map(int,input().split()))
l.sort()
c=0
for i in range(0,len(l)):
for j in range(i+1,len(l)):
if l[j]-l[i] <= int(d): c=c+1
else:break
print(2*c)
``` | 3.804928 |
227 | B | Effective Approach | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn compared with the number that you need to find. Once you find the array element that is equal to the requ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of elements in the array. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the elements of array.
The third line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. The ... | Print two integers, showing how many comparisons Vasya's approach needs and how many comparisons Petya's approach needs. Separate the numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | [
"2\n1 2\n1\n1\n",
"2\n2 1\n1\n1\n",
"3\n3 1 2\n3\n1 2 3\n"
] | [
"1 2\n",
"2 1\n",
"6 6\n"
] | In the first sample Vasya's approach will make one comparison (it starts with the 1-st element and immediately finds the required number), and Petya's approach makes two comparisons (first he compares with the 2-nd array element, doesn't find the search item and compares with the 1-st element).
In the second sample, o... | 1,000 | [
{
"input": "2\n1 2\n1\n1",
"output": "1 2"
},
{
"input": "2\n2 1\n1\n1",
"output": "2 1"
},
{
"input": "3\n3 1 2\n3\n1 2 3",
"output": "6 6"
},
{
"input": "9\n2 9 3 1 6 4 7 8 5\n9\n5 1 5 2 8 4 4 4 5",
"output": "58 32"
},
{
"input": "10\n3 10 9 2 7 6 5 8 4 1\n1\n4... | 1,664,187,723 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 17,100,800 | n = int(input())
arrA = list(map(int,input().split()))
arrAFlibbed = arrA[::-1]
m = int(input())
numsToSearch = list(map(int,input().split()))
score_start = 0
score_end = 0
for numSearch in numsToSearch:
score_start += 1 + arrA.index(numSearch)
score_end += 1 + arrAFlibbed.index(numSearch)
print(f"{score_start}... | Title: Effective Approach
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn c... | ```python
n = int(input())
arrA = list(map(int,input().split()))
arrAFlibbed = arrA[::-1]
m = int(input())
numsToSearch = list(map(int,input().split()))
score_start = 0
score_end = 0
for numSearch in numsToSearch:
score_start += 1 + arrA.index(numSearch)
score_end += 1 + arrAFlibbed.index(numSearch)
print(f"{sc... | 0 | |
126 | B | Password | PROGRAMMING | 1,700 | [
"binary search",
"dp",
"hashing",
"string suffix structures",
"strings"
] | null | null | Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the... | You are given the string *s* whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters. | Print the string *t*. If a suitable *t* string does not exist, then print "Just a legend" without the quotes. | [
"fixprefixsuffix\n",
"abcdabc\n"
] | [
"fix",
"Just a legend"
] | none | 1,000 | [
{
"input": "fixprefixsuffix",
"output": "fix"
},
{
"input": "abcdabc",
"output": "Just a legend"
},
{
"input": "qwertyqwertyqwerty",
"output": "qwerty"
},
{
"input": "papapapap",
"output": "papap"
},
{
"input": "aaaaaaaaaa",
"output": "aaaaaaaa"
},
{
"... | 1,538,008,691 | 2,147,483,647 | Python 3 | OK | TESTS | 97 | 1,900 | 34,099,200 | def kmpTable(s, n):
res = [0]*n
check_idx = 0
for i in range(1, n):
while check_idx > 0 and s[check_idx] != s[i]:
check_idx = res[check_idx-1]
if s[check_idx] == s[i]:
check_idx += 1
res[i] = check_idx
return res
s = input()
n = len(s)
kmp_ta... | Title: Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carve... | ```python
def kmpTable(s, n):
res = [0]*n
check_idx = 0
for i in range(1, n):
while check_idx > 0 and s[check_idx] != s[i]:
check_idx = res[check_idx-1]
if s[check_idx] == s[i]:
check_idx += 1
res[i] = check_idx
return res
s = input()
n = len(... | 3 | |
388 | A | Fox and Box Accumulation | PROGRAMMING | 1,400 | [
"greedy",
"sortings"
] | null | null | Fox Ciel has *n* boxes in her room. They have the same size and weight, but they might have different strength. The *i*-th box can hold at most *x**i* boxes on its top (we'll call *x**i* the strength of the box).
Since all the boxes have the same size, Ciel cannot put more than one box directly on the top of some box... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n* (0<=≤<=*x**i*<=≤<=100). | Output a single integer — the minimal possible number of piles. | [
"3\n0 0 10\n",
"5\n0 1 2 3 4\n",
"4\n0 0 0 0\n",
"9\n0 1 0 2 0 1 1 2 10\n"
] | [
"2\n",
"1\n",
"4\n",
"3\n"
] | In example 1, one optimal way is to build 2 piles: the first pile contains boxes 1 and 3 (from top to bottom), the second pile contains only box 2.
In example 2, we can build only 1 pile that contains boxes 1, 2, 3, 4, 5 (from top to bottom). | 500 | [
{
"input": "3\n0 0 10",
"output": "2"
},
{
"input": "5\n0 1 2 3 4",
"output": "1"
},
{
"input": "4\n0 0 0 0",
"output": "4"
},
{
"input": "9\n0 1 0 2 0 1 1 2 10",
"output": "3"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "2\n0 0",
"output": "... | 1,567,080,111 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 140 | 0 | n = int(input())
arr = list(map(int,input().split()))
arr.sort()
unq, ans, req = set(arr), -1, 0
for ele in unq:
count = arr.count(ele)
req += count
ans = max(req//(ele+1), ans)
print(ans) | Title: Fox and Box Accumulation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel has *n* boxes in her room. They have the same size and weight, but they might have different strength. The *i*-th box can hold at most *x**i* boxes on its top (we'll call *x**i* the strength of the box... | ```python
n = int(input())
arr = list(map(int,input().split()))
arr.sort()
unq, ans, req = set(arr), -1, 0
for ele in unq:
count = arr.count(ele)
req += count
ans = max(req//(ele+1), ans)
print(ans)
``` | 0 | |
75 | A | Life Without Zeros | PROGRAMMING | 1,000 | [
"implementation"
] | A. Life Without Zeros | 2 | 256 | Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c*... | The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*. | The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise. | [
"101\n102\n",
"105\n106\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "101\n102",
"output": "YES"
},
{
"input": "105\n106",
"output": "NO"
},
{
"input": "544\n397",
"output": "YES"
},
{
"input": "822\n280",
"output": "NO"
},
{
"input": "101\n413",
"output": "NO"
},
{
"input": "309\n139",
"output": "NO"
}... | 1,583,404,690 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 248 | 307,200 |
def remove_zero(arg)->int:
return int("".join(list(filter(lambda v : v!='0',str(arg)))))
a = int(input())
b = int(input())
c = a + b
# print(remove_zero(c) == remove_zero(a) + remove_zero(b))
if ( remove_zero(c) == remove_zero(a) + remove_zero(b) ):
print("YES")
pass
else :
print("NO") | Title: Life Without Zeros
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assu... | ```python
def remove_zero(arg)->int:
return int("".join(list(filter(lambda v : v!='0',str(arg)))))
a = int(input())
b = int(input())
c = a + b
# print(remove_zero(c) == remove_zero(a) + remove_zero(b))
if ( remove_zero(c) == remove_zero(a) + remove_zero(b) ):
print("YES")
pass
else :
print("NO")
``` | 3.937428 |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,647,311,350 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 15 | 0 | arr = [int(x) for x in input().split()]
print((min((arr[0] + arr[2] + arr[1]), (arr[0] * 2 + arr[1] * 2))))
| Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
arr = [int(x) for x in input().split()]
print((min((arr[0] + arr[2] + arr[1]), (arr[0] * 2 + arr[1] * 2))))
``` | 0 | |
581 | E | Kojiro and Furrari | PROGRAMMING | 2,800 | [
"dp",
"greedy"
] | null | null | Motorist Kojiro spent 10 years saving up for his favorite car brand, Furrari. Finally Kojiro's dream came true! Kojiro now wants to get to his girlfriend Johanna to show off his car to her.
Kojiro wants to get to his girlfriend, so he will go to her along a coordinate line. For simplicity, we can assume that Kojiro is... | The first line of the input contains four positive integers *e*,<=*s*,<=*n*,<=*m* (1<=≤<=*e*,<=*s*<=≤<=109,<=1<=≤<=*n*,<=*m*<=≤<=2·105) — the coordinate of the point where Johanna is, the capacity of a Furrari tank, the number of gas stations and the number of starting points.
Next *n* lines contain two integers each... | Print exactly *m* lines. The *i*-th of them should contain two integers — the minimum amount of gas of type Regular-92 and type Premium-95, if Kojiro starts at point *f**i*. First you need to minimize the first value. If there are multiple ways to do it, you need to also minimize the second value.
If there is no way t... | [
"8 4 1 1\n2 4\n0\n",
"9 3 2 3\n2 3\n1 6\n-1 0 1\n",
"20 9 2 4\n1 5\n2 10\n-1 0 1 2\n"
] | [
"0 4\n",
"-1 -1\n3 3\n3 2\n",
"-1 -1\n-1 -1\n-1 -1\n-1 -1\n"
] | none | 3,000 | [] | 1,694,860,898 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 2,000 | 37,785,600 | def calc(a, b, v, dp, s):
x = next((i for i, val in enumerate(v[a]) if val >= b), None)
if x is None:
return 0
return dp[a][x] + max(0, v[a][x] - b - s)
maxn = 200111
v = [[] for _ in range(4)]
dp = [[0] * maxn for _ in range(4)]
e, s, n, m = map(int, input().split())
for _ in range(n):
... | Title: Kojiro and Furrari
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Motorist Kojiro spent 10 years saving up for his favorite car brand, Furrari. Finally Kojiro's dream came true! Kojiro now wants to get to his girlfriend Johanna to show off his car to her.
Kojiro wants to get to hi... | ```python
def calc(a, b, v, dp, s):
x = next((i for i, val in enumerate(v[a]) if val >= b), None)
if x is None:
return 0
return dp[a][x] + max(0, v[a][x] - b - s)
maxn = 200111
v = [[] for _ in range(4)]
dp = [[0] * maxn for _ in range(4)]
e, s, n, m = map(int, input().split())
for _ in ran... | 0 | |
452 | A | Eevee | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"strings"
] | null | null | You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight different pokemons: Vaporeon, Jolteon, Flareon, Espeon, Umbreon, Leafeon, Glaceon, and Syl... | First line contains an integer *n* (6<=≤<=*n*<=≤<=8) – the length of the string.
Next line contains a string consisting of *n* characters, each of which is either a lower case english letter (indicating a known letter) or a dot character (indicating an empty cell in the crossword). | Print a name of the pokemon that Eevee can evolve into that matches the pattern in the input. Use lower case letters only to print the name (in particular, do not capitalize the first letter). | [
"7\nj......\n",
"7\n...feon\n",
"7\n.l.r.o.\n"
] | [
"jolteon\n",
"leafeon\n",
"flareon\n"
] | Here's a set of names in a form you can paste into your solution:
["vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"]
{"vaporeon", "jolteon", "flareon", "espeon", "umbreon", "leafeon", "glaceon", "sylveon"} | 500 | [
{
"input": "7\n...feon",
"output": "leafeon"
},
{
"input": "7\n.l.r.o.",
"output": "flareon"
},
{
"input": "6\n.s..o.",
"output": "espeon"
},
{
"input": "7\nglaceon",
"output": "glaceon"
},
{
"input": "8\n.a.o.e.n",
"output": "vaporeon"
},
{
"input": "... | 1,406,484,628 | 4,228 | Python 3 | OK | TESTS | 20 | 77 | 0 | import re
t = int(input())
pat = input();
pat ='^'+pat+'$'
if re.match( pat, "vaporeon", re.M|re.I):
print ("vaporeon")
elif re.match( pat, "jolteon", re.M|re.I):
print ("jolteon")
elif re.match( pat, "flareon", re.M|re.I):
print ("flareon")
elif re.match( pat, "espeon", re.M|re.I):
print ("esp... | Title: Eevee
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are solving the crossword problem K from IPSC 2014. You solved all the clues except for one: who does Eevee evolve into? You are not very into pokemons, but quick googling helped you find out, that Eevee can evolve into eight... | ```python
import re
t = int(input())
pat = input();
pat ='^'+pat+'$'
if re.match( pat, "vaporeon", re.M|re.I):
print ("vaporeon")
elif re.match( pat, "jolteon", re.M|re.I):
print ("jolteon")
elif re.match( pat, "flareon", re.M|re.I):
print ("flareon")
elif re.match( pat, "espeon", re.M|re.I):
p... | 3 | |
886 | B | Vlad and Cafes | PROGRAMMING | 1,000 | [] | null | null | Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research.
First of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes... | In first line there is one integer *n* (1<=≤<=*n*<=≤<=2·105) — number of cafes indices written by Vlad.
In second line, *n* numbers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=2·105) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, ... | Print one integer — index of the cafe that Vlad hasn't visited for as long as possible. | [
"5\n1 3 2 1 2\n",
"6\n2 1 2 2 4 1\n"
] | [
"3\n",
"2\n"
] | In first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer.
In second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with in... | 1,000 | [
{
"input": "5\n1 3 2 1 2",
"output": "3"
},
{
"input": "6\n2 1 2 2 4 1",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n200000",
"output": "200000"
},
{
"input": "2\n2018 2017",
"output": "2018"
},
{
"input": "5\n100 1000 1000 1000... | 1,510,507,626 | 4,926 | Python 3 | WRONG_ANSWER | PRETESTS | 2 | 46 | 0 | n = int(input())
s = [int(i) for i in input().split()]
r = []
c = 0
s = s[::-1]
for i in range(n):
c = s[i]
for j in range(i+1, len(s)):
if s[j] == c:
s[j] = 0
s = s[::-1]
for i in range(len(s)):
if s[i] != 0:
print(s[i])
break
| Title: Vlad and Cafes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research... | ```python
n = int(input())
s = [int(i) for i in input().split()]
r = []
c = 0
s = s[::-1]
for i in range(n):
c = s[i]
for j in range(i+1, len(s)):
if s[j] == c:
s[j] = 0
s = s[::-1]
for i in range(len(s)):
if s[i] != 0:
print(s[i])
break
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Little Nastya has a hobby, she likes to remove some letters from word, to obtain another word. But it turns out to be pretty hard for her, because she is too young. Therefore, her brother Sergey always helps her.
Sergey gives Nastya the word *t* and wants to get the word *p* out of it. Nastya removes letters in a cert... | The first and second lines of the input contain the words *t* and *p*, respectively. Words are composed of lowercase letters of the Latin alphabet (1<=≤<=|*p*|<=<<=|*t*|<=≤<=200<=000). It is guaranteed that the word *p* can be obtained by removing the letters from word *t*.
Next line contains a permutation *a*1,<=*... | Print a single integer number, the maximum number of letters that Nastya can remove. | [
"ababcba\nabb\n5 3 4 1 7 6 2\n",
"bbbabb\nbb\n1 6 3 4 2 5\n"
] | [
"3",
"4"
] | In the first sample test sequence of removing made by Nastya looks like this:
"ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba" <img align="middle" class="tex-formula" src="https... | 0 | [
{
"input": "ababcba\nabb\n5 3 4 1 7 6 2",
"output": "3"
},
{
"input": "bbbabb\nbb\n1 6 3 4 2 5",
"output": "4"
},
{
"input": "cacaccccccacccc\ncacc\n10 9 14 5 1 7 15 3 6 12 4 8 11 13 2",
"output": "9"
},
{
"input": "aaaabaaabaabaaaaaaaa\naaaa\n18 5 4 6 13 9 1 3 7 8 16 10 12 1... | 1,535,807,130 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 108 | 0 |
def mi():
return map(int, input().split())
s = list(input())
t = input()
a = list(map(int, input().split()))
def isSubSequence(str1,str2,m,n):
j = 0 # Index of str1
i = 0 # Index of str2
# Traverse both str1 and str2
# Compare current character of str2 with
# firs... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Nastya has a hobby, she likes to remove some letters from word, to obtain another word. But it turns out to be pretty hard for her, because she is too young. Therefore, her brother Sergey always helps her.
Sergey gives Nas... | ```python
def mi():
return map(int, input().split())
s = list(input())
t = input()
a = list(map(int, input().split()))
def isSubSequence(str1,str2,m,n):
j = 0 # Index of str1
i = 0 # Index of str2
# Traverse both str1 and str2
# Compare current character of str2 with
... | 0 | |
514 | A | Chewbaсca and Number | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform the initial number *x* to the minimum possible positive number by inverting some (possibly, zero) digits.... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=1018) — the number that Luke Skywalker gave to Chewbacca. | Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes. | [
"27\n",
"4545\n"
] | [
"22\n",
"4444\n"
] | none | 500 | [
{
"input": "27",
"output": "22"
},
{
"input": "4545",
"output": "4444"
},
{
"input": "1",
"output": "1"
},
{
"input": "9",
"output": "9"
},
{
"input": "8772",
"output": "1222"
},
{
"input": "81",
"output": "11"
},
{
"input": "71723447",
... | 1,689,152,877 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 31 | 0 | x = input()
new_x = ''
for i in x :
i = int(i)
if i > 4:
new_x+=f'{9-i}'
else:
new_x+=f'{i}'
print(int(new_x)) | Title: Chewbaсca and Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform... | ```python
x = input()
new_x = ''
for i in x :
i = int(i)
if i > 4:
new_x+=f'{9-i}'
else:
new_x+=f'{i}'
print(int(new_x))
``` | 0 | |
501 | A | Contest | PROGRAMMING | 900 | [
"implementation"
] | null | null | Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved the problem that costs *b* points. Besides, Misha submitted the problem *c* minutes after the ... | The first line contains four integers *a*, *b*, *c*, *d* (250<=≤<=*a*,<=*b*<=≤<=3500, 0<=≤<=*c*,<=*d*<=≤<=180).
It is guaranteed that numbers *a* and *b* are divisible by 250 (just like on any real Codeforces round). | Output on a single line:
"Misha" (without the quotes), if Misha got more points than Vasya.
"Vasya" (without the quotes), if Vasya got more points than Misha.
"Tie" (without the quotes), if both of them got the same number of points. | [
"500 1000 20 30\n",
"1000 1000 1 1\n",
"1500 1000 176 177\n"
] | [
"Vasya\n",
"Tie\n",
"Misha\n"
] | none | 500 | [
{
"input": "500 1000 20 30",
"output": "Vasya"
},
{
"input": "1000 1000 1 1",
"output": "Tie"
},
{
"input": "1500 1000 176 177",
"output": "Misha"
},
{
"input": "1500 1000 74 177",
"output": "Misha"
},
{
"input": "750 2500 175 178",
"output": "Vasya"
},
{
... | 1,615,490,352 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 62 | 0 | liste=input('').split()
M = int(liste[0])
V = int(liste[1])
Mt = int(liste[2])
Vt = int(liste[3])
p1 = max(3/10*M, M -M/250*Mt)
p2 = max(3/10*V, V -V/250*Vt)
if p1>p2:
print('Misha')
elif p2>p1:
print('Vasya')
else:
print('Tie') | Title: Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved t... | ```python
liste=input('').split()
M = int(liste[0])
V = int(liste[1])
Mt = int(liste[2])
Vt = int(liste[3])
p1 = max(3/10*M, M -M/250*Mt)
p2 = max(3/10*V, V -V/250*Vt)
if p1>p2:
print('Misha')
elif p2>p1:
print('Vasya')
else:
print('Tie')
``` | 3 | |
118 | A | String Task | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:
- deletes all the vowels, - inserts a character "." before each consonant, - replaces ... | The first line represents input string of Petya's program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive. | Print the resulting string. It is guaranteed that this string is not empty. | [
"tour\n",
"Codeforces\n",
"aBAcAba\n"
] | [
".t.r\n",
".c.d.f.r.c.s\n",
".b.c.b\n"
] | none | 500 | [
{
"input": "tour",
"output": ".t.r"
},
{
"input": "Codeforces",
"output": ".c.d.f.r.c.s"
},
{
"input": "aBAcAba",
"output": ".b.c.b"
},
{
"input": "obn",
"output": ".b.n"
},
{
"input": "wpwl",
"output": ".w.p.w.l"
},
{
"input": "ggdvq",
"output": "... | 1,694,787,895 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | s=input()
p=''
z=["A", "O", "Y", "E", "U", "I", "a", "o", "y", "e", "u", "i",]
for i in range(len(s)):
if s[i] not in z:
p='.'+s[i]+p
print(p.lower()) | Title: String Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters... | ```python
s=input()
p=''
z=["A", "O", "Y", "E", "U", "I", "a", "o", "y", "e", "u", "i",]
for i in range(len(s)):
if s[i] not in z:
p='.'+s[i]+p
print(p.lower())
``` | 0 | |
550 | C | Divisibility by Eight | PROGRAMMING | 1,500 | [
"brute force",
"dp",
"math"
] | null | null | You are given a non-negative integer *n*, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a no... | The single line of the input contains a non-negative integer *n*. The representation of number *n* doesn't contain any leading zeroes and its length doesn't exceed 100 digits. | Print "NO" (without quotes), if there is no such way to remove some digits from number *n*.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number *n* in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any ... | [
"3454\n",
"10\n",
"111111\n"
] | [
"YES\n344\n",
"YES\n0\n",
"NO\n"
] | none | 1,000 | [
{
"input": "3454",
"output": "YES\n344"
},
{
"input": "10",
"output": "YES\n0"
},
{
"input": "111111",
"output": "NO"
},
{
"input": "8996988892",
"output": "YES\n8"
},
{
"input": "5555555555",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
... | 1,698,468,091 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 73 | 77 | 1,945,600 | n = list(input())
f = 0
s = len(n)
for i in range (0, s):
if f == 1:
break
if (int(n[i])) % 8 == 0:
print ("YES")
print (n[i])
f = 1
break
for j in range (i + 1, s):
if f == 1:
break
if (int(n[i]) * 10 + int(n[j])) % 8 == 0:
print ("YES")
print (n[i], end = "")
print (n[j])... | Title: Divisibility by Eight
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a non-negative integer *n*, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of t... | ```python
n = list(input())
f = 0
s = len(n)
for i in range (0, s):
if f == 1:
break
if (int(n[i])) % 8 == 0:
print ("YES")
print (n[i])
f = 1
break
for j in range (i + 1, s):
if f == 1:
break
if (int(n[i]) * 10 + int(n[j])) % 8 == 0:
print ("YES")
print (n[i], end = "")
pr... | 3 | |
32 | A | Reconnaissance | PROGRAMMING | 800 | [
"brute force"
] | A. Reconnaissance | 2 | 256 | According to the regulations of Berland's army, a reconnaissance unit should consist of exactly two soldiers. Since these two soldiers shouldn't differ much, their heights can differ by at most *d* centimeters. Captain Bob has *n* soldiers in his detachment. Their heights are *a*1,<=*a*2,<=...,<=*a**n* centimeters. Som... | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=1000,<=1<=≤<=*d*<=≤<=109) — amount of soldiers in Bob's detachment and the maximum allowed height difference respectively. The second line contains *n* space-separated integers — heights of all the soldiers in Bob's detachment. These numbers don't exceed 1... | Output one number — amount of ways to form a reconnaissance unit of two soldiers, whose height difference doesn't exceed *d*. | [
"5 10\n10 20 50 60 65\n",
"5 1\n55 30 29 31 55\n"
] | [
"6\n",
"6\n"
] | none | 500 | [
{
"input": "5 10\n10 20 50 60 65",
"output": "6"
},
{
"input": "5 1\n55 30 29 31 55",
"output": "6"
},
{
"input": "6 10\n4 6 4 1 9 3",
"output": "30"
},
{
"input": "7 100\n19 1694 261 162 1 234 513",
"output": "8"
},
{
"input": "8 42\n37 53 74 187 568 22 5 65",
... | 1,665,528,491 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | thing = input()
soldiers = input()
thing = thing.split()
soldiers = soldiers.split()
num = int(thing[0])
height_m = int(thing[1])
count = 0
for i in range(num):
for j in range(num):
if int(soldiers[i]) - int(soldiers[j]) <= height_m:
count += 1
print(int((count/2)-3)) | Title: Reconnaissance
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
According to the regulations of Berland's army, a reconnaissance unit should consist of exactly two soldiers. Since these two soldiers shouldn't differ much, their heights can differ by at most *d* centimeters. Captain Bob h... | ```python
thing = input()
soldiers = input()
thing = thing.split()
soldiers = soldiers.split()
num = int(thing[0])
height_m = int(thing[1])
count = 0
for i in range(num):
for j in range(num):
if int(soldiers[i]) - int(soldiers[j]) <= height_m:
count += 1
print(int((count/2)-... | 0 |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,654,685,180 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 409,600 | import string
letters = list(string.ascii_lowercase)
x = list(input())
result = 0
for i in range(0, len(x) - 1):
counterclockwise = 0
clockwise = 0
current = x[i]
next = x[i + 1]
j = letters.index(current)
while letters[j] != next and j <= 25:
counterclockwise += 1
... | Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
import string
letters = list(string.ascii_lowercase)
x = list(input())
result = 0
for i in range(0, len(x) - 1):
counterclockwise = 0
clockwise = 0
current = x[i]
next = x[i + 1]
j = letters.index(current)
while letters[j] != next and j <= 25:
counterclockwise += 1... | 0 | |
814 | B | An express train to reveries | PROGRAMMING | 1,300 | [
"constructive algorithms"
] | null | null | Sengoku still remembers the mysterious "colourful meteoroids" she discovered with Lala-chan when they were little. In particular, one of the nights impressed her deeply, giving her the illusion that all her fancies would be realized.
On that night, Sengoku constructed a permutation *p*1,<=*p*2,<=...,<=*p**n* of intege... | The first line of input contains a positive integer *n* (2<=≤<=*n*<=≤<=1<=000) — the length of Sengoku's permutation, being the length of both meteor outbursts at the same time.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the sequence of colours in the firs... | Output *n* space-separated integers *p*1,<=*p*2,<=...,<=*p**n*, denoting a possible permutation Sengoku could have had. If there are more than one possible answer, output any one of them.
Input guarantees that such permutation exists. | [
"5\n1 2 3 4 3\n1 2 5 4 5\n",
"5\n4 4 2 3 1\n5 4 5 3 1\n",
"4\n1 1 3 4\n1 4 3 4\n"
] | [
"1 2 5 4 3\n",
"5 4 2 3 1\n",
"1 2 3 4\n"
] | In the first sample, both 1, 2, 5, 4, 3 and 1, 2, 3, 4, 5 are acceptable outputs.
In the second sample, 5, 4, 2, 3, 1 is the only permutation to satisfy the constraints. | 1,000 | [
{
"input": "5\n1 2 3 4 3\n1 2 5 4 5",
"output": "1 2 5 4 3"
},
{
"input": "5\n4 4 2 3 1\n5 4 5 3 1",
"output": "5 4 2 3 1"
},
{
"input": "4\n1 1 3 4\n1 4 3 4",
"output": "1 2 3 4"
},
{
"input": "10\n1 2 3 4 7 6 7 8 9 10\n1 2 3 4 5 6 5 8 9 10",
"output": "1 2 3 4 5 6 7 8 9... | 1,584,474,018 | 2,147,483,647 | PyPy 3 | OK | TESTS | 54 | 155 | 1,945,600 | def solve(p, q):
return sum(p[i] != q[i] for i in range(n)) == 1
n = int(input())
a = [int(i) for i in input().split()]
b = [int(i) for i in input().split()]
wa = [0 for i in range(n + 1)]
wb = wa.copy()
for i in a:
wa[i] += 1
for i in b:
wb[i] += 1
ta = []
for i in range(1, n + 1):
i... | Title: An express train to reveries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sengoku still remembers the mysterious "colourful meteoroids" she discovered with Lala-chan when they were little. In particular, one of the nights impressed her deeply, giving her the illusion that all her... | ```python
def solve(p, q):
return sum(p[i] != q[i] for i in range(n)) == 1
n = int(input())
a = [int(i) for i in input().split()]
b = [int(i) for i in input().split()]
wa = [0 for i in range(n + 1)]
wb = wa.copy()
for i in a:
wa[i] += 1
for i in b:
wb[i] += 1
ta = []
for i in range(1, n + ... | 3 | |
667 | A | Pouring Rain | PROGRAMMING | 1,100 | [
"geometry",
"math"
] | null | null | A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, contemplate all around you, enjoy freshness, think about big deeds you have to do.
Today everything ... | The only line of the input contains four integer numbers *d*,<=*h*,<=*v*,<=*e* (1<=≤<=*d*,<=*h*,<=*v*,<=*e*<=≤<=104), where:
- *d* — the diameter of your cylindrical cup, - *h* — the initial level of water in the cup, - *v* — the speed of drinking process from the cup in milliliters per second, - *e* — the growth ... | If it is impossible to make the cup empty, print "NO" (without quotes).
Otherwise print "YES" (without quotes) in the first line. In the second line print a real number — time in seconds needed the cup will be empty. The answer will be considered correct if its relative or absolute error doesn't exceed 10<=-<=4. It is... | [
"1 2 3 100\n",
"1 1 1 1\n"
] | [
"NO\n",
"YES\n3.659792366325\n"
] | In the first example the water fills the cup faster than you can drink from it.
In the second example area of the cup's bottom equals to <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/419dc74dcd7bc392019c9fe748fe1fdb08ab521a.png" style="max-width: 100.0%;max-height: 100.0%;"/>, thus we ca... | 500 | [
{
"input": "1 2 3 100",
"output": "NO"
},
{
"input": "1 1 1 1",
"output": "YES\n3.659792366325"
},
{
"input": "48 7946 7992 72",
"output": "NO"
},
{
"input": "72 6791 8546 46",
"output": "NO"
},
{
"input": "100 5635 9099 23",
"output": "NO"
},
{
"input... | 1,634,780,400 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 23 | 62 | 28,364,800 | from math import pi
d,h,v,e = [int(i) for i in input().split()]
v = v / (pi * (d/2)**2)
if v <= e:
print("NO")
else:
print("YES")
print(h / (v-e))
| Title: Pouring Rain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, cont... | ```python
from math import pi
d,h,v,e = [int(i) for i in input().split()]
v = v / (pi * (d/2)**2)
if v <= e:
print("NO")
else:
print("YES")
print(h / (v-e))
``` | 3 | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,676,392,216 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 61 | 0 | n,m=map(int,input().split())
arr=[]
for i in range(n):
input_arr=list(map(str,input().split()))
arr=arr+input_arr
c_ct=arr.count('C')
m_ct=arr.count('M')
y_ct=arr.count('Y')
if c_ct != 0 or m_ct != 0 or y_ct != 0:
print('#Color')
else:
print('#Black&White')
| Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
n,m=map(int,input().split())
arr=[]
for i in range(n):
input_arr=list(map(str,input().split()))
arr=arr+input_arr
c_ct=arr.count('C')
m_ct=arr.count('M')
y_ct=arr.count('Y')
if c_ct != 0 or m_ct != 0 or y_ct != 0:
print('#Color')
else:
print('#Black&White')
... | 3 | |
963 | A | Alternating Sum | PROGRAMMING | 1,800 | [
"math",
"number theory"
] | null | null | You are given two integers $a$ and $b$. Moreover, you are given a sequence $s_0, s_1, \dots, s_{n}$. All values in $s$ are integers $1$ or $-1$. It's known that sequence is $k$-periodic and $k$ divides $n+1$. In other words, for each $k \leq i \leq n$ it's satisfied that $s_{i} = s_{i - k}$.
Find out the non-negative ... | The first line contains four integers $n, a, b$ and $k$ $(1 \leq n \leq 10^{9}, 1 \leq a, b \leq 10^{9}, 1 \leq k \leq 10^{5})$.
The second line contains a sequence of length $k$ consisting of characters '+' and '-'.
If the $i$-th character (0-indexed) is '+', then $s_{i} = 1$, otherwise $s_{i} = -1$.
Note that onl... | Output a single integer — value of given expression modulo $10^{9} + 9$. | [
"2 2 3 3\n+-+\n",
"4 1 5 1\n-\n"
] | [
"7\n",
"999999228\n"
] | In the first example:
$(\sum \limits_{i=0}^{n} s_{i} a^{n - i} b^{i})$ = $2^{2} 3^{0} - 2^{1} 3^{1} + 2^{0} 3^{2}$ = 7
In the second example:
$(\sum \limits_{i=0}^{n} s_{i} a^{n - i} b^{i}) = -1^{4} 5^{0} - 1^{3} 5^{1} - 1^{2} 5^{2} - 1^{1} 5^{3} - 1^{0} 5^{4} = -781 \equiv 999999228 \pmod{10^{9} + 9}$. | 500 | [
{
"input": "2 2 3 3\n+-+",
"output": "7"
},
{
"input": "4 1 5 1\n-",
"output": "999999228"
},
{
"input": "1 1 4 2\n-+",
"output": "3"
},
{
"input": "3 1 4 4\n+--+",
"output": "45"
},
{
"input": "5 1 1 6\n++---+",
"output": "0"
},
{
"input": "5 2 2 6\n+... | 1,589,940,894 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 155 | 1,433,600 | def binPow(a,n):
if n==0:
return 1
result=binPow(a,n//2)
if n%2==1:
return ((result%mod)*(result%mod)*(a%mod))%mod
else:
return ((result%mod)*(result%mod))%mod
def modInv(a):
return binPow(a,mod-2)
mod=10**9+9
n,a,b,k=map(int,input().split())
s=input()
result=0
... | Title: Alternating Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers $a$ and $b$. Moreover, you are given a sequence $s_0, s_1, \dots, s_{n}$. All values in $s$ are integers $1$ or $-1$. It's known that sequence is $k$-periodic and $k$ divides $n+1$. In other w... | ```python
def binPow(a,n):
if n==0:
return 1
result=binPow(a,n//2)
if n%2==1:
return ((result%mod)*(result%mod)*(a%mod))%mod
else:
return ((result%mod)*(result%mod))%mod
def modInv(a):
return binPow(a,mod-2)
mod=10**9+9
n,a,b,k=map(int,input().split())
s=input()
... | 0 | |
551 | A | GukiZ and Contest | PROGRAMMING | 800 | [
"brute force",
"implementation",
"sortings"
] | null | null | Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*). | In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input. | [
"3\n1 3 3\n",
"1\n1\n",
"5\n3 5 3 4 5\n"
] | [
"3 1 1\n",
"1\n",
"4 1 4 3 1\n"
] | In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first positi... | 500 | [
{
"input": "3\n1 3 3",
"output": "3 1 1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n3 5 3 4 5",
"output": "4 1 4 3 1"
},
{
"input": "7\n1 3 5 4 2 2 1",
"output": "6 3 1 2 4 4 6"
},
{
"input": "11\n5 6 4 2 9 7 6 6 6 6 7",
"output": "9 4 10 11 1 2 4 4... | 1,598,650,918 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 124 | 307,200 | n = int(input())
a = [int(s) for s in input().split(' ')]
a_sorted = sorted(a, reverse=True)
predictions = []
for score in a:
predictions.append(str(a_sorted.index(score) + 1))
print(' '.join(predictions)) | Title: GukiZ and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the star... | ```python
n = int(input())
a = [int(s) for s in input().split(' ')]
a_sorted = sorted(a, reverse=True)
predictions = []
for score in a:
predictions.append(str(a_sorted.index(score) + 1))
print(' '.join(predictions))
``` | 3 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,635,499,518 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 4,505,600 | k = input()
n = len(k)
i = 0
ans = ""
while i < n:
if k[i] == '.':
ans += '0'
i += 1
else:
if k[i+1] == '.':
ans += '1'
else:
ans += '2'
i += 2
print(ans)
| Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
k = input()
n = len(k)
i = 0
ans = ""
while i < n:
if k[i] == '.':
ans += '0'
i += 1
else:
if k[i+1] == '.':
ans += '1'
else:
ans += '2'
i += 2
print(ans)
``` | 3.968608 |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,695,112,950 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | s = input()
a = s.upper()
b = s.lower()
n = 0
m = 0
v = 0
for i in range(len(a)):
n = n + ord(a[i])
for i in range(len(b)):
m = m + ord(b[i])
for i in range(len(s)):
v = v + ord(s[i])
if abs(n-v) < abs(m-v):
print(a)
else:
print(b) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s = input()
a = s.upper()
b = s.lower()
n = 0
m = 0
v = 0
for i in range(len(a)):
n = n + ord(a[i])
for i in range(len(b)):
m = m + ord(b[i])
for i in range(len(s)):
v = v + ord(s[i])
if abs(n-v) < abs(m-v):
print(a)
else:
print(b)
``` | 3.977 |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,606,492,981 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 216 | 307,200 | n=int(input())
a=list(map(int,input().split()))
e=0
o=0
c=0
if(a[0]%2==0):
e=1
else:
o=1
if(a[1]%2==0):
if(e==0):
if(a[2]%2==0):
print(1)
else:
print(2)
if(e==1):
c=1
else:
if(o==0):
if(a[2]%2!=0):
print(1)
... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
a=list(map(int,input().split()))
e=0
o=0
c=0
if(a[0]%2==0):
e=1
else:
o=1
if(a[1]%2==0):
if(e==0):
if(a[2]%2==0):
print(1)
else:
print(2)
if(e==1):
c=1
else:
if(o==0):
if(a[2]%2!=0):
prin... | 3.945428 |
644 | A | Parliament of Berland | PROGRAMMING | 1,000 | [
"*special",
"constructive algorithms"
] | null | null | There are *n* parliamentarians in Berland. They are numbered with integers from 1 to *n*. It happened that all parliamentarians with odd indices are Democrats and all parliamentarians with even indices are Republicans.
New parliament assembly hall is a rectangle consisting of *a*<=×<=*b* chairs — *a* rows of *b* chair... | The first line of the input contains three integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=10<=000, 1<=≤<=*a*,<=*b*<=≤<=100) — the number of parliamentarians, the number of rows in the assembly hall and the number of seats in each row, respectively. | If there is no way to assigns seats to parliamentarians in a proper way print -1.
Otherwise print the solution in *a* lines, each containing *b* integers. The *j*-th integer of the *i*-th line should be equal to the index of parliamentarian occupying this seat, or 0 if this seat should remain empty. If there are multi... | [
"3 2 2\n",
"8 4 3\n",
"10 2 2\n"
] | [
"0 3\n1 2\n",
"7 8 3\n0 1 4\n6 0 5\n0 2 0\n",
"-1\n"
] | In the first sample there are many other possible solutions. For example,
and
The following assignment
is incorrect, because parliamentarians 1 and 3 are both from Democrats party but will occupy neighbouring seats. | 500 | [
{
"input": "3 2 2",
"output": "1 2 \n0 3 "
},
{
"input": "8 4 3",
"output": "1 2 3 \n4 5 6 \n7 8 0 \n0 0 0 "
},
{
"input": "10 2 2",
"output": "-1"
},
{
"input": "1 1 1",
"output": "1 "
},
{
"input": "8 3 3",
"output": "1 2 3 \n4 5 6 \n7 8 0 "
},
{
"in... | 1,458,142,736 | 23,936 | Python 3 | WRONG_ANSWER | PRETESTS | 1 | 46 | 0 | n, a, b = map(int, input().split())
rev, akt = False, 0
if n > a * b:
print(-1)
else:
pole = [str(i + 1) for i in range(n)]
for i in range(b):
akt2 = akt + a
if akt2 > n:
akt2 = n
odpoved = pole[akt:akt2]
if len(odpoved) < a:
odpove... | Title: Parliament of Berland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* parliamentarians in Berland. They are numbered with integers from 1 to *n*. It happened that all parliamentarians with odd indices are Democrats and all parliamentarians with even indices are Republi... | ```python
n, a, b = map(int, input().split())
rev, akt = False, 0
if n > a * b:
print(-1)
else:
pole = [str(i + 1) for i in range(n)]
for i in range(b):
akt2 = akt + a
if akt2 > n:
akt2 = n
odpoved = pole[akt:akt2]
if len(odpoved) < a:
... | 0 | |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,623,748,364 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | import math as mt
def findkth (n, k):
v1 = list()
v2 = list()
for i in range(1, mt.ceil(n**(.5))):
if (n % i == 0):
v1.append(i)
if (i != mt.ceil(mt.sqrt(n))):
v2.append(n // i)
v2[::-1]
if ( k > (len(v1) + len(v2))):... | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
import math as mt
def findkth (n, k):
v1 = list()
v2 = list()
for i in range(1, mt.ceil(n**(.5))):
if (n % i == 0):
v1.append(i)
if (i != mt.ceil(mt.sqrt(n))):
v2.append(n // i)
v2[::-1]
if ( k > (len(v1) + ... | 0 | |
771 | A | Bear and Friendship Condition | PROGRAMMING | 1,500 | [
"dfs and similar",
"dsu",
"graphs"
] | null | null | Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through *n*. *m* pairs of members are friends. Of course, a member can't be a friend with themselves.
Let A-B denote that... | The first line of the input contain two integers *n* and *m* (3<=≤<=*n*<=≤<=150<=000, ) — the number of members and the number of pairs of members that are friends.
The *i*-th of the next *m* lines contains two distinct integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*). Members *a**i* and ... | If the given network is reasonable, print "YES" in a single line (without the quotes). Otherwise, print "NO" in a single line (without the quotes). | [
"4 3\n1 3\n3 4\n1 4\n",
"4 4\n3 1\n2 3\n3 4\n1 2\n",
"10 4\n4 3\n5 10\n8 9\n1 2\n",
"3 2\n1 2\n2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"NO\n"
] | The drawings below show the situation in the first sample (on the left) and in the second sample (on the right). Each edge represents two members that are friends. The answer is "NO" in the second sample because members (2, 3) are friends and members (3, 4) are friends, while members (2, 4) are not. | 250 | [
{
"input": "4 3\n1 3\n3 4\n1 4",
"output": "YES"
},
{
"input": "4 4\n3 1\n2 3\n3 4\n1 2",
"output": "NO"
},
{
"input": "10 4\n4 3\n5 10\n8 9\n1 2",
"output": "YES"
},
{
"input": "3 2\n1 2\n2 3",
"output": "NO"
},
{
"input": "3 0",
"output": "YES"
},
{
... | 1,684,789,864 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 65 | 904 | 33,894,400 | n, m = list(map(int, input().split()))
p = {i:i for i in range(1, n+1)}
def getP(i):
if i == p[i]:
return i
p[i] = getP(p[i])
return p[i]
size = {i:1 for i in range(1, n+1)}
edges = {i:0 for i in range(1, n+1)}
for _ in range(m):
u,v = list(map(int, input().split()))
if getP(u) != getP(v... | Title: Bear and Friendship Condition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through... | ```python
n, m = list(map(int, input().split()))
p = {i:i for i in range(1, n+1)}
def getP(i):
if i == p[i]:
return i
p[i] = getP(p[i])
return p[i]
size = {i:1 for i in range(1, n+1)}
edges = {i:0 for i in range(1, n+1)}
for _ in range(m):
u,v = list(map(int, input().split()))
if getP(u)... | -1 | |
519 | B | A and B and Compilation Errors | PROGRAMMING | 1,100 | [
"data structures",
"implementation",
"sortings"
] | null | null | A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time.
The third line contains *n*<=-<=1 space-sepa... | Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively. | [
"5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n",
"6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n"
] | [
"8\n123\n",
"1\n3\n"
] | In the first test sample B first corrects the error number 8, then the error number 123.
In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step. | 1,000 | [
{
"input": "5\n1 5 8 123 7\n123 7 5 1\n5 1 7",
"output": "8\n123"
},
{
"input": "6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5",
"output": "1\n3"
},
{
"input": "3\n1 2 3\n3 2\n2",
"output": "1\n3"
},
{
"input": "10\n460626451 802090732 277246428 661369649 388684428 784303821 376287098 6... | 1,692,754,003 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <stdio.h>
int main(){
int a;
long long int total = 0;
scanf("%d" , &a);
for(int i = 0 ; i < a ; i++){
int b;
scanf("%d" , &b);
total += b;
}
long long int temp = total;
for(int i = 0 ; i < a - 1 ; i++){
int c;
scanf("%d" , &c);
... | Title: A and B and Compilation Errors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler disp... | ```python
#include <stdio.h>
int main(){
int a;
long long int total = 0;
scanf("%d" , &a);
for(int i = 0 ; i < a ; i++){
int b;
scanf("%d" , &b);
total += b;
}
long long int temp = total;
for(int i = 0 ; i < a - 1 ; i++){
int c;
scanf("%... | -1 | |
701 | C | They Are Everywhere | PROGRAMMING | 1,500 | [
"binary search",
"strings",
"two pointers"
] | null | null | Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each flat. Also, each flat is connected with the flat to the left and the flat to the right. Flat number 1 is ... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of flats in the house.
The second line contains the row *s* with the length *n*, it consists of uppercase and lowercase letters of English alphabet, the *i*-th letter equals the type of Pokemon, which is in the flat number *i*. | Print the minimum number of flats which Sergei B. should visit in order to catch Pokemons of all types which there are in the house. | [
"3\nAaA\n",
"7\nbcAAcbc\n",
"6\naaBCCe\n"
] | [
"2\n",
"3\n",
"5\n"
] | In the first test Sergei B. can begin, for example, from the flat number 1 and end in the flat number 2.
In the second test Sergei B. can begin, for example, from the flat number 4 and end in the flat number 6.
In the third test Sergei B. must begin from the flat number 2 and end in the flat number 6. | 1,000 | [
{
"input": "3\nAaA",
"output": "2"
},
{
"input": "7\nbcAAcbc",
"output": "3"
},
{
"input": "6\naaBCCe",
"output": "5"
},
{
"input": "1\nA",
"output": "1"
},
{
"input": "1\ng",
"output": "1"
},
{
"input": "52\nabcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQ... | 1,647,821,127 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n = int(input())
s = list(input())
l = []
for i in range(len(s) + 1):
for j in range(len(s) + 1):
# print(i, j)
if i < j:
a = s[i:j]
l.append(a)
if j < i:
a = s[j:i]
l.append(a)
all_letters = set(list(s))
large = float('inf')
for list_ in l:
if all_letters == set(list_):
if... | Title: They Are Everywhere
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each ... | ```python
n = int(input())
s = list(input())
l = []
for i in range(len(s) + 1):
for j in range(len(s) + 1):
# print(i, j)
if i < j:
a = s[i:j]
l.append(a)
if j < i:
a = s[j:i]
l.append(a)
all_letters = set(list(s))
large = float('inf')
for list_ in l:
if all_letters == set(list... | 0 | |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,582,142,126 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 310 | 4,608,000 | bin_num=list(input())
if "0" in bin_num:
for i in range(len(bin_num)):
if bin_num[i]=="0":
del bin_num[i]
break
print(''.join(bin_num))
else:
del bin_num[0]
print(''.join(bin_num)) | Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
bin_num=list(input())
if "0" in bin_num:
for i in range(len(bin_num)):
if bin_num[i]=="0":
del bin_num[i]
break
print(''.join(bin_num))
else:
del bin_num[0]
print(''.join(bin_num))
``` | 3 | |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*... | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,695,788,848 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 5,632,000 | n = int(input())
st = input()
An = 0
de = 0
for i in st:
if i == 'A':
An += 1
elif i == 'D':
de += 1
if An > de:
print("Anton")
else:
print("Danik") | Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, w... | ```python
n = int(input())
st = input()
An = 0
de = 0
for i in st:
if i == 'A':
An += 1
elif i == 'D':
de += 1
if An > de:
print("Anton")
else:
print("Danik")
``` | 0 | |
439 | A | Devu, the Singer and Churu, the Joker | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited.
Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* s... | The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100). | If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event. | [
"3 30\n2 2 1\n",
"3 20\n2 1 1\n"
] | [
"5\n",
"-1\n"
] | Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way:
- First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Ch... | 500 | [
{
"input": "3 30\n2 2 1",
"output": "5"
},
{
"input": "3 20\n2 1 1",
"output": "-1"
},
{
"input": "50 10000\n5 4 10 9 9 6 7 7 7 3 3 7 7 4 7 4 10 10 1 7 10 3 1 4 5 7 2 10 10 10 2 3 4 7 6 1 8 4 7 3 8 8 4 10 1 1 9 2 6 1",
"output": "1943"
},
{
"input": "50 10000\n4 7 15 9 11 12 ... | 1,597,667,933 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 109 | 307,200 | t = input()
temp = t.split()
n = int(temp[0])
d = int(temp[1])
songLenthList = []
songLength = input()
List = songLength.split()
songLenthList = [int(i) for i in List]
devuBreaktime = (n-1)*10
devuTotalTime = devuBreaktime + sum(songLenthList)
churuTime = d - devuTotalTime + devuBreaktime
if (devuTotalTime >... | Title: Devu, the Singer and Churu, the Joker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invit... | ```python
t = input()
temp = t.split()
n = int(temp[0])
d = int(temp[1])
songLenthList = []
songLength = input()
List = songLength.split()
songLenthList = [int(i) for i in List]
devuBreaktime = (n-1)*10
devuTotalTime = devuBreaktime + sum(songLenthList)
churuTime = d - devuTotalTime + devuBreaktime
if (devuT... | 3 | |
639 | A | Bear and Displayed Friends | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Limak is a little polar bear. He loves connecting with other bears via social networks. He has *n* friends and his relation with the *i*-th of them is described by a unique integer *t**i*. The bigger this value is, the better the friendship is. No two friends have the same value *t**i*.
Spring is starting and the Wint... | The first line contains three integers *n*, *k* and *q* (1<=≤<=*n*,<=*q*<=≤<=150<=000,<=1<=≤<=*k*<=≤<=*min*(6,<=*n*)) — the number of friends, the maximum number of displayed online friends and the number of queries, respectively.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=109) ... | For each query of the second type print one line with the answer — "YES" (without quotes) if the given friend is displayed and "NO" (without quotes) otherwise. | [
"4 2 8\n300 950 500 200\n1 3\n2 4\n2 3\n1 1\n1 2\n2 1\n2 2\n2 3\n",
"6 3 9\n50 20 51 17 99 24\n1 3\n1 4\n1 5\n1 2\n2 4\n2 2\n1 1\n2 4\n2 3\n"
] | [
"NO\nYES\nNO\nYES\nYES\n",
"NO\nYES\nNO\nYES\n"
] | In the first sample, Limak has 4 friends who all sleep initially. At first, the system displays nobody because nobody is online. There are the following 8 queries:
1. "1 3" — Friend 3 becomes online. 1. "2 4" — We should check if friend 4 is displayed. He isn't even online and thus we print "NO". 1. "2 3" — We shou... | 500 | [
{
"input": "4 2 8\n300 950 500 200\n1 3\n2 4\n2 3\n1 1\n1 2\n2 1\n2 2\n2 3",
"output": "NO\nYES\nNO\nYES\nYES"
},
{
"input": "6 3 9\n50 20 51 17 99 24\n1 3\n1 4\n1 5\n1 2\n2 4\n2 2\n1 1\n2 4\n2 3",
"output": "NO\nYES\nNO\nYES"
},
{
"input": "6 3 10\n62417580 78150524 410053501 582708235 ... | 1,673,190,501 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 19,968,000 | from sys import stdin; inp = stdin.readline
from math import dist, ceil, floor, sqrt, log
from collections import defaultdict, Counter
def IA(sep=' '): return list(map(int, inp().split(sep)))
def FA(): return list(map(float, inp().split()))
def SA(): return inp().split()
def I(): return int(inp())
def F(): retur... | Title: Bear and Displayed Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. He loves connecting with other bears via social networks. He has *n* friends and his relation with the *i*-th of them is described by a unique integer *t**i*. The bigger this val... | ```python
from sys import stdin; inp = stdin.readline
from math import dist, ceil, floor, sqrt, log
from collections import defaultdict, Counter
def IA(sep=' '): return list(map(int, inp().split(sep)))
def FA(): return list(map(float, inp().split()))
def SA(): return inp().split()
def I(): return int(inp())
def ... | 0 | |
808 | A | Lucky Year | PROGRAMMING | 900 | [
"implementation"
] | null | null | Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 12, 3001 and 12345 are not.
You are given current year in Berland. Your task is to find how long... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=109) — current year in Berland. | Output amount of years from the current year to the next lucky one. | [
"4\n",
"201\n",
"4000\n"
] | [
"1\n",
"99\n",
"1000\n"
] | In the first example next lucky year is 5. In the second one — 300. In the third — 5000. | 0 | [
{
"input": "4",
"output": "1"
},
{
"input": "201",
"output": "99"
},
{
"input": "4000",
"output": "1000"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "10"
},
{
"input": "1",
"output": "1"
},
{
"input": "100000000",
"ou... | 1,684,248,129 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 0 | n=int(input())
test=False
n=n+1
i=n-1
def lucky(n):
s=0
for c in range (len(n)):
if n[c]!="0":
s=s+1
return s==1
while not (test ):
if lucky(str(n)):
test=True
else:
n=n+1
print(n-i)
| Title: Lucky Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 1... | ```python
n=int(input())
test=False
n=n+1
i=n-1
def lucky(n):
s=0
for c in range (len(n)):
if n[c]!="0":
s=s+1
return s==1
while not (test ):
if lucky(str(n)):
test=True
else:
n=n+1
print(n-i)
``` | 0 | |
472 | D | Design Tutorial: Inverse the Problem | PROGRAMMING | 1,900 | [
"dfs and similar",
"dsu",
"shortest paths",
"trees"
] | null | null | There is an easy way to obtain a new task from an old one called "Inverse the problem": we give an output of the original task, and ask to generate an input, such that solution to the original problem will produce the output we provided. The hard task of Topcoder Open 2014 Round 2C, InverseRMQ, is a good example.
Now ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=2000) — the number of nodes in that graph.
Then next *n* lines each contains *n* integers *d**i*,<=*j* (0<=≤<=*d**i*,<=*j*<=≤<=109) — the distance between node *i* and node *j*. | If there exists such a tree, output "YES", otherwise output "NO". | [
"3\n0 2 7\n2 0 9\n7 9 0\n",
"3\n1 2 7\n2 0 9\n7 9 0\n",
"3\n0 2 2\n7 0 9\n7 9 0\n",
"3\n0 1 1\n1 0 1\n1 1 0\n",
"2\n0 0\n0 0\n"
] | [
"YES\n",
"NO\n",
"NO\n",
"NO\n",
"NO\n"
] | In the first example, the required tree exists. It has one edge between nodes 1 and 2 with weight 2, another edge between nodes 1 and 3 with weight 7.
In the second example, it is impossible because *d*<sub class="lower-index">1, 1</sub> should be 0, but it is 1.
In the third example, it is impossible because *d*<sub... | 2,000 | [
{
"input": "3\n0 2 7\n2 0 9\n7 9 0",
"output": "YES"
},
{
"input": "3\n1 2 7\n2 0 9\n7 9 0",
"output": "NO"
},
{
"input": "3\n0 2 2\n7 0 9\n7 9 0",
"output": "NO"
},
{
"input": "3\n0 1 1\n1 0 1\n1 1 0",
"output": "NO"
},
{
"input": "2\n0 0\n0 0",
"output": "NO... | 1,683,444,453 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 5 | 30 | 0 | def makeINT(arr):
for i in range(0, len(arr)):
arr[i] = int(arr[i])
return arr
n = int(input())
z = 0
arr = []
for i in range(n):
ln = input().split()
arr.append(makeINT(ln))
if arr[i][i]:
z = 1
for i in range(n):
for j in range(i + 1, n):
if arr[i][j] != arr[j][i] or (arr[i][j] == 0 and j !=... | Title: Design Tutorial: Inverse the Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is an easy way to obtain a new task from an old one called "Inverse the problem": we give an output of the original task, and ask to generate an input, such that solution to the original probl... | ```python
def makeINT(arr):
for i in range(0, len(arr)):
arr[i] = int(arr[i])
return arr
n = int(input())
z = 0
arr = []
for i in range(n):
ln = input().split()
arr.append(makeINT(ln))
if arr[i][i]:
z = 1
for i in range(n):
for j in range(i + 1, n):
if arr[i][j] != arr[j][i] or (arr[i][j] == ... | -1 | |
714 | B | Filya and Homework | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | null | null | Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.
Filya is given an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*. First, he pick an integer *x* and then he adds *x* to some elements of the array (no more than onc... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of integers in the Filya's array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — elements of the array. | If it's impossible to make all elements of the array equal using the process given in the problem statement, then print "NO" (without quotes) in the only line of the output. Otherwise print "YES" (without quotes). | [
"5\n1 3 3 2 1\n",
"5\n1 2 3 4 5\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Filya should select *x* = 1, then add it to the first and the last elements of the array and subtract from the second and the third elements. | 1,000 | [
{
"input": "5\n1 3 3 2 1",
"output": "YES"
},
{
"input": "5\n1 2 3 4 5",
"output": "NO"
},
{
"input": "2\n1 2",
"output": "YES"
},
{
"input": "3\n1 2 3",
"output": "YES"
},
{
"input": "3\n1 1 1",
"output": "YES"
},
{
"input": "2\n1 1000000000",
"ou... | 1,601,386,910 | 2,147,483,647 | Python 3 | OK | TESTS | 79 | 139 | 9,216,000 | n = int(input())
arr = list(map(int,input().split()))
if len(set(arr)) == 1 :
print('YES')
elif len(set(arr)) == 2 :
print('YES')
elif len(set(arr)) >= 4 :
print('NO')
else:
st = set(arr)
#print(st)
arr2 = list(sorted(st))
#print(arr2)
if (arr2[1] * 2 == arr2[0] + ar... | Title: Filya and Homework
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.
Filya is given an array of non-negative integers *a*1,<=*a*2,<=...,<=*a... | ```python
n = int(input())
arr = list(map(int,input().split()))
if len(set(arr)) == 1 :
print('YES')
elif len(set(arr)) == 2 :
print('YES')
elif len(set(arr)) >= 4 :
print('NO')
else:
st = set(arr)
#print(st)
arr2 = list(sorted(st))
#print(arr2)
if (arr2[1] * 2 == ar... | 3 | |
478 | A | Initial Bet | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | There are five people playing a game called "Generosity". Each person gives some non-zero number of coins *b* as an initial bet. After all players make their bets of *b* coins, the following operation is repeated for several times: a coin is passed from one player to some other player.
Your task is to write a program ... | The input consists of a single line containing five integers *c*1,<=*c*2,<=*c*3,<=*c*4 and *c*5 — the number of coins that the first, second, third, fourth and fifth players respectively have at the end of the game (0<=≤<=*c*1,<=*c*2,<=*c*3,<=*c*4,<=*c*5<=≤<=100). | Print the only line containing a single positive integer *b* — the number of coins in the initial bet of each player. If there is no such value of *b*, then print the only value "-1" (quotes for clarity). | [
"2 5 4 0 4\n",
"4 5 9 2 1\n"
] | [
"3\n",
"-1\n"
] | In the first sample the following sequence of operations is possible:
1. One coin is passed from the fourth player to the second player; 1. One coin is passed from the fourth player to the fifth player; 1. One coin is passed from the first player to the third player; 1. One coin is passed from the fourth player to... | 500 | [
{
"input": "2 5 4 0 4",
"output": "3"
},
{
"input": "4 5 9 2 1",
"output": "-1"
},
{
"input": "0 0 0 0 0",
"output": "-1"
},
{
"input": "1 2 1 2 3",
"output": "-1"
},
{
"input": "100 0 0 0 0",
"output": "20"
},
{
"input": "2 3 4 5 6",
"output": "4"... | 1,649,633,034 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | c = 0
monet = list(map(int,input().split()))
for i in range(len(monet)):
c += monet[i]
if c%len(monet)==0:
print(int(c/len(monet)))
else:
print('-1') | Title: Initial Bet
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are five people playing a game called "Generosity". Each person gives some non-zero number of coins *b* as an initial bet. After all players make their bets of *b* coins, the following operation is repeated for severa... | ```python
c = 0
monet = list(map(int,input().split()))
for i in range(len(monet)):
c += monet[i]
if c%len(monet)==0:
print(int(c/len(monet)))
else:
print('-1')
``` | 0 | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,609,892,816 | 2,147,483,647 | PyPy 3 | OK | TESTS | 32 | 310 | 0 | from sys import stdin
n = int(stdin.readline())
data = list(map(int,stdin.readline().rstrip().split()))
even_one = data[0] % 2
for i in range(1,n):
if data[i] % 2 != even_one and i > 1:
print(i+1)
elif data[i] % 2 != even_one and i == 1:
print(i+1 if data[i+1]%2 == even_one else 1)
... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
from sys import stdin
n = int(stdin.readline())
data = list(map(int,stdin.readline().rstrip().split()))
even_one = data[0] % 2
for i in range(1,n):
if data[i] % 2 != even_one and i > 1:
print(i+1)
elif data[i] % 2 != even_one and i == 1:
print(i+1 if data[i+1]%2 == even_one els... | 3.9225 |
14 | A | Letter | PROGRAMMING | 800 | [
"implementation"
] | A. Letter | 1 | 64 | A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brother, who lives in Flatland. Now Bob has to send his picture by post, but because of the w... | The first line of the input data contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50), *n* — amount of lines, and *m* — amount of columns on Bob's sheet. The following *n* lines contain *m* characters each. Character «.» stands for a non-shaded square on the sheet, and «*» — for a shaded square. It is guaranteed that ... | Output the required rectangle of the minimum cost. Study the output data in the sample tests to understand the output format better. | [
"6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..\n",
"3 3\n***\n*.*\n***\n"
] | [
"***\n*..\n***\n*..\n***\n",
"***\n*.*\n***\n"
] | none | 0 | [
{
"input": "6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..",
"output": "***\n*..\n***\n*..\n***"
},
{
"input": "3 3\n***\n*.*\n***",
"output": "***\n*.*\n***"
},
{
"input": "1 1\n*",
"output": "*"
},
{
"input": "2 1\n*\n*",
"output": "*\n*"
},
{
"input"... | 1,588,514,910 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 216 | 307,200 | n, m = map(int, input().split())
arr = []
patt = []
for i in range(n):
k = input()
arr.append(k)
for i in arr:
a = [(x,y) for x,y in enumerate(i) if y == '*']
if len(a)>0:
patt.append(i[a[0][0]:a[-1][0]+1])
arr = []
l = [len(i) for i in patt]
l = max(l)
for i in patt:
a... | Title: Letter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brothe... | ```python
n, m = map(int, input().split())
arr = []
patt = []
for i in range(n):
k = input()
arr.append(k)
for i in arr:
a = [(x,y) for x,y in enumerate(i) if y == '*']
if len(a)>0:
patt.append(i[a[0][0]:a[-1][0]+1])
arr = []
l = [len(i) for i in patt]
l = max(l)
for i in patt... | 0 |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,674,923,639 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 154 | 409,600 | #9/A
#Die Roll
#Status : IDK
import fractions
y , w = [int(x) for x in input().split()]
bigger = y if y > w else w
ans = str(fractions.Fraction((6-bigger+1),6))
if len(ans) < 2:
print(ans + "/1")
else:
print(ans) | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
#9/A
#Die Roll
#Status : IDK
import fractions
y , w = [int(x) for x in input().split()]
bigger = y if y > w else w
ans = str(fractions.Fraction((6-bigger+1),6))
if len(ans) < 2:
print(ans + "/1")
else:
print(ans)
``` | 3.919948 |
0 | none | none | none | 0 | [
"none"
] | null | null | Вася купил стол, у которого *n* ножек. Каждая ножка состоит из двух частей, которые соединяются друг с другом. Каждая часть может быть произвольной положительной длины, но гарантируется, что из всех 2*n* частей возможно составить *n* ножек одинаковой длины. При составлении ножки любые две части могут быть соединены дру... | В первой строке задано число *n* (1<=≤<=*n*<=≤<=1000) — количество ножек у стола, купленного Васей.
Во второй строке следует последовательность из 2*n* целых положительных чисел *a*1,<=*a*2,<=...,<=*a*2*n* (1<=≤<=*a**i*<=≤<=100<=000) — длины частей ножек стола в произвольном порядке. | Выведите *n* строк по два целых числа в каждой — длины частей ножек, которые надо соединить друг с другом. Гарантируется, что всегда возможно собрать *n* ножек одинаковой длины. Если ответов несколько, разрешается вывести любой из них. | [
"3\n1 3 2 4 5 3\n",
"3\n1 1 1 2 2 2\n"
] | [
"1 5\n2 4\n3 3\n",
"1 2\n2 1\n1 2\n"
] | none | 0 | [
{
"input": "3\n1 3 2 4 5 3",
"output": "1 5\n2 4\n3 3"
},
{
"input": "3\n1 1 1 2 2 2",
"output": "1 2\n1 2\n1 2"
},
{
"input": "1\n3 7",
"output": "3 7"
},
{
"input": "10\n9 13 18 7 18 13 2 2 5 16 3 17 5 4 18 2 15 11 7 15",
"output": "2 18\n2 18\n2 18\n3 17\n4 16\n5 15\n5... | 1,458,745,909 | 709 | PyPy 3 | OK | TESTS | 57 | 233 | 25,804,800 | n = int(input())
a = list(map(int, input().split()))
l = sum(a) // n
a.sort()
for i in range(n):
print(a[i], l - a[i])
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Вася купил стол, у которого *n* ножек. Каждая ножка состоит из двух частей, которые соединяются друг с другом. Каждая часть может быть произвольной положительной длины, но гарантируется, что из всех 2*n* частей возможно составить ... | ```python
n = int(input())
a = list(map(int, input().split()))
l = sum(a) // n
a.sort()
for i in range(n):
print(a[i], l - a[i])
``` | 3 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,671,879,619 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 124 | 0 | word = input()
lw = []
lu = []
for x in range(len(word)):
if word[x].islower():
lw.append(word[x])
else:
lu.append(word[x])
if len(lw) > len(lu) or len(lw) == len(lu):
print(word.lower())
else:
print(word.upper())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
word = input()
lw = []
lu = []
for x in range(len(word)):
if word[x].islower():
lw.append(word[x])
else:
lu.append(word[x])
if len(lw) > len(lu) or len(lw) == len(lu):
print(word.lower())
else:
print(word.upper())
``` | 3.969 |
998 | B | Cutting | PROGRAMMING | 1,200 | [
"dp",
"greedy",
"sortings"
] | null | null | There are a lot of things which could be cut — trees, paper, "the rope". In this problem you are going to cut a sequence of integers.
There is a sequence of integers, which contains the equal number of even and odd numbers. Given a limited budget, you need to make maximum possible number of cuts such that each resulti... | First line of the input contains an integer $n$ ($2 \le n \le 100$) and an integer $B$ ($1 \le B \le 100$) — the number of elements in the sequence and the number of bitcoins you have.
Second line contains $n$ integers: $a_1$, $a_2$, ..., $a_n$ ($1 \le a_i \le 100$) — elements of the sequence, which contains the equal... | Print the maximum possible number of cuts which can be made while spending no more than $B$ bitcoins. | [
"6 4\n1 2 5 10 15 20\n",
"4 10\n1 3 2 4\n",
"6 100\n1 2 3 4 5 6\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample the optimal answer is to split sequence between $2$ and $5$. Price of this cut is equal to $3$ bitcoins.
In the second sample it is not possible to make even one cut even with unlimited number of bitcoins.
In the third sample the sequence should be cut between $2$ and $3$, and between $4$ and $5$.... | 1,000 | [
{
"input": "6 4\n1 2 5 10 15 20",
"output": "1"
},
{
"input": "4 10\n1 3 2 4",
"output": "0"
},
{
"input": "6 100\n1 2 3 4 5 6",
"output": "2"
},
{
"input": "2 100\n13 78",
"output": "0"
},
{
"input": "10 1\n56 56 98 2 11 64 97 41 95 53",
"output": "0"
},
... | 1,595,888,706 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 108 | 6,963,200 | n,coins=[int(i) for i in input().split(' ')]
tr=[int(i) for i in input().split(' ')]
od,ev=0,0
cost=[]
for i in range(len(tr)-1):
if tr[i]%2==0:ev+=1
else:od+=1
if od==ev:cost.append(abs(tr[i]-tr[i+1]))
cost.sort(reverse=True)
while(sum(cost)>coins):cost.pop(0)
print(len(cost))
| Title: Cutting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are a lot of things which could be cut — trees, paper, "the rope". In this problem you are going to cut a sequence of integers.
There is a sequence of integers, which contains the equal number of even and odd numbers. Gi... | ```python
n,coins=[int(i) for i in input().split(' ')]
tr=[int(i) for i in input().split(' ')]
od,ev=0,0
cost=[]
for i in range(len(tr)-1):
if tr[i]%2==0:ev+=1
else:od+=1
if od==ev:cost.append(abs(tr[i]-tr[i+1]))
cost.sort(reverse=True)
while(sum(cost)>coins):cost.pop(0)
print(len(cost))
``` | 3 | |
1,000 | B | Light It Up | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | Recently, you bought a brand new smart lamp with programming features. At first, you set up a schedule to the lamp. Every day it will turn power on at moment $0$ and turn power off at moment $M$. Moreover, the lamp allows you to set a program of switching its state (states are "lights on" and "lights off"). Unfortunate... | First line contains two space separated integers $n$ and $M$ ($1 \le n \le 10^5$, $2 \le M \le 10^9$) — the length of program $a$ and the moment when power turns off.
Second line contains $n$ space separated integers $a_1, a_2, \dots, a_n$ ($0 < a_1 < a_2 < \dots < a_n < M$) — initially installed progra... | Print the only integer — maximum possible total time when the lamp is lit. | [
"3 10\n4 6 7\n",
"2 12\n1 10\n",
"2 7\n3 4\n"
] | [
"8\n",
"9\n",
"6\n"
] | In the first example, one of possible optimal solutions is to insert value $x = 3$ before $a_1$, so program will be $[3, 4, 6, 7]$ and time of lamp being lit equals $(3 - 0) + (6 - 4) + (10 - 7) = 8$. Other possible solution is to insert $x = 5$ in appropriate place.
In the second example, there is only one optimal so... | 0 | [
{
"input": "3 10\n4 6 7",
"output": "8"
},
{
"input": "2 12\n1 10",
"output": "9"
},
{
"input": "2 7\n3 4",
"output": "6"
},
{
"input": "1 2\n1",
"output": "1"
},
{
"input": "5 10\n1 3 5 6 8",
"output": "6"
},
{
"input": "7 1000000000\n1 10001 10011 20... | 1,635,222,613 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 1,000 | 28,262,400 | n,m=map(int,input().split())
A=[int(n) for n in input().split()]
A=[0]+A+[m]
s=len(A)
i=0
B=[]
while i<s-1:
i=i+1
b1=A[i]-1
b2=A[i]+1
C=[b1,b2]
for x in C:
if x not in A and x<m:
A.append(x)
A.sort()
s1=len(A)
k=-1
l=0
while k<s1... | Title: Light It Up
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, you bought a brand new smart lamp with programming features. At first, you set up a schedule to the lamp. Every day it will turn power on at moment $0$ and turn power off at moment $M$. Moreover, the lamp allows y... | ```python
n,m=map(int,input().split())
A=[int(n) for n in input().split()]
A=[0]+A+[m]
s=len(A)
i=0
B=[]
while i<s-1:
i=i+1
b1=A[i]-1
b2=A[i]+1
C=[b1,b2]
for x in C:
if x not in A and x<m:
A.append(x)
A.sort()
s1=len(A)
k=-1
l=0
... | 0 | |
519 | B | A and B and Compilation Errors | PROGRAMMING | 1,100 | [
"data structures",
"implementation",
"sortings"
] | null | null | A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time.
The third line contains *n*<=-<=1 space-sepa... | Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively. | [
"5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n",
"6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n"
] | [
"8\n123\n",
"1\n3\n"
] | In the first test sample B first corrects the error number 8, then the error number 123.
In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step. | 1,000 | [
{
"input": "5\n1 5 8 123 7\n123 7 5 1\n5 1 7",
"output": "8\n123"
},
{
"input": "6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5",
"output": "1\n3"
},
{
"input": "3\n1 2 3\n3 2\n2",
"output": "1\n3"
},
{
"input": "10\n460626451 802090732 277246428 661369649 388684428 784303821 376287098 6... | 1,697,526,296 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 140 | 14,950,400 | a=int(input())
bug1=sum(list(map(int,input().split())))
bug2=sum(list(map(int,input().split())))
bug3=sum(list(map(int,input().split())))
print(bug1-bug2)
print(bug2-bug3) | Title: A and B and Compilation Errors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler disp... | ```python
a=int(input())
bug1=sum(list(map(int,input().split())))
bug2=sum(list(map(int,input().split())))
bug3=sum(list(map(int,input().split())))
print(bug1-bug2)
print(bug2-bug3)
``` | 3 | |
939 | A | Love Triangle | PROGRAMMING | 800 | [
"graphs"
] | null | null | As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with number *f**i*, where 1<=≤<=*f**i*<=≤<=*n* and *f**i*<=≠<=*i*.
We call a love triangle a situation ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=5000) — the number of planes.
The second line contains *n* integers *f*1,<=*f*2,<=...,<=*f**n* (1<=≤<=*f**i*<=≤<=*n*, *f**i*<=≠<=*i*), meaning that the *i*-th plane likes the *f**i*-th. | Output «YES» if there is a love triangle consisting of planes on Earth. Otherwise, output «NO».
You can output any letter in lower case or in upper case. | [
"5\n2 4 5 1 3\n",
"5\n5 5 5 5 1\n"
] | [
"YES\n",
"NO\n"
] | In first example plane 2 likes plane 4, plane 4 likes plane 1, plane 1 likes plane 2 and that is a love triangle.
In second example there are no love triangles. | 500 | [
{
"input": "5\n2 4 5 1 3",
"output": "YES"
},
{
"input": "5\n5 5 5 5 1",
"output": "NO"
},
{
"input": "3\n3 1 2",
"output": "YES"
},
{
"input": "10\n4 10 9 5 3 1 5 10 6 4",
"output": "NO"
},
{
"input": "10\n5 5 4 9 10 9 9 5 3 1",
"output": "YES"
},
{
"... | 1,618,498,837 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 93 | 1,331,200 |
def solver(n,arr):
for i in range(1,n+1):
if arr[arr[arr[i]]] == i:
return "YES"
else:
return "NO"
n = int(input())
arr = [int(x) for x in input().split()]
arr.insert(0,0)
print(solver(n,arr))
| Title: Love Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with ... | ```python
def solver(n,arr):
for i in range(1,n+1):
if arr[arr[arr[i]]] == i:
return "YES"
else:
return "NO"
n = int(input())
arr = [int(x) for x in input().split()]
arr.insert(0,0)
print(solver(n,arr))
``` | 0 | |
462 | A | Appleman and Easy Task | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or character 'o'. Is it true that each cell of the board has even number of adjacent cells with 'o'? Two cells... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Then *n* lines follow containing the description of the checkerboard. Each of them contains *n* characters (either 'x' or 'o') without spaces. | Print "YES" or "NO" (without the quotes) depending on the answer to the problem. | [
"3\nxxo\nxox\noxx\n",
"4\nxxxo\nxoxo\noxox\nxxxx\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "3\nxxo\nxox\noxx",
"output": "YES"
},
{
"input": "4\nxxxo\nxoxo\noxox\nxxxx",
"output": "NO"
},
{
"input": "1\no",
"output": "YES"
},
{
"input": "2\nox\nxo",
"output": "YES"
},
{
"input": "2\nxx\nxo",
"output": "NO"
},
{
"input": "3\nooo\no... | 1,640,476,505 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 62 | 0 | n = int(input())
flag = 0
xo = []
for i in range(n):
s = input()
xo.append(s)
for i in range(n):
for j in range(len(xo[i])):
c = 0
if(j-1>=0 and xo[i][j-1] == 'o'):
c += 1
if(i-1 >=0 and xo[i-1][j] == 'o'):
c += 1
if(i+1 < n and xo[i+1][j] == 'o'):
c += 1
if(j+1 < len(xo[i]) and x... | Title: Appleman and Easy Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or... | ```python
n = int(input())
flag = 0
xo = []
for i in range(n):
s = input()
xo.append(s)
for i in range(n):
for j in range(len(xo[i])):
c = 0
if(j-1>=0 and xo[i][j-1] == 'o'):
c += 1
if(i-1 >=0 and xo[i-1][j] == 'o'):
c += 1
if(i+1 < n and xo[i+1][j] == 'o'):
c += 1
if(j+1 < len(xo... | 3 | |
375 | D | Tree and Queries | PROGRAMMING | 2,400 | [
"data structures",
"dfs and similar",
"trees"
] | null | null | You have a rooted tree consisting of *n* vertices. Each vertex of the tree has some color. We will assume that the tree vertices are numbered by integers from 1 to *n*. Then we represent the color of vertex *v* as *c**v*. The tree root is a vertex with number 1.
In this problem you need to answer to *m* queries. Each ... | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105; 1<=≤<=*m*<=≤<=105). The next line contains a sequence of integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=105). The next *n*<=-<=1 lines contain the edges of the tree. The *i*-th line contains the numbers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤... | Print *m* integers — the answers to the queries in the order the queries appear in the input. | [
"8 5\n1 2 2 3 3 2 3 3\n1 2\n1 5\n2 3\n2 4\n5 6\n5 7\n5 8\n1 2\n1 3\n1 4\n2 3\n5 3\n",
"4 1\n1 2 3 4\n1 2\n2 3\n3 4\n1 1\n"
] | [
"2\n2\n1\n0\n1\n",
"4\n"
] | A subtree of vertex *v* in a rooted tree with root *r* is a set of vertices {*u* : *dist*(*r*, *v*) + *dist*(*v*, *u*) = *dist*(*r*, *u*)}. Where *dist*(*x*, *y*) is the length (in edges) of the shortest path between vertices *x* and *y*. | 2,000 | [
{
"input": "8 5\n1 2 2 3 3 2 3 3\n1 2\n1 5\n2 3\n2 4\n5 6\n5 7\n5 8\n1 2\n1 3\n1 4\n2 3\n5 3",
"output": "2\n2\n1\n0\n1"
},
{
"input": "4 1\n1 2 3 4\n1 2\n2 3\n3 4\n1 1",
"output": "4"
}
] | 1,463,731,074 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 46 | 4,812,800 | n,m = [int(i) for i in input().split()]
c = [int(i) for i in input().split()]
maximum = len(set(c))
connected = [[] for i in range(n)]
for i in range(n-1):
p,q = [int(j) for j in input().split()]
connected[p-1].append(q)
connected[q-1].append(p)
used = [False]*n
son = [[] for i in range(n)]
us... | Title: Tree and Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a rooted tree consisting of *n* vertices. Each vertex of the tree has some color. We will assume that the tree vertices are numbered by integers from 1 to *n*. Then we represent the color of vertex *v* as *c**... | ```python
n,m = [int(i) for i in input().split()]
c = [int(i) for i in input().split()]
maximum = len(set(c))
connected = [[] for i in range(n)]
for i in range(n-1):
p,q = [int(j) for j in input().split()]
connected[p-1].append(q)
connected[q-1].append(p)
used = [False]*n
son = [[] for i in ran... | -1 | |
999 | B | Reversing Encryption | PROGRAMMING | 900 | [
"implementation"
] | null | null | A string $s$ of length $n$ can be encrypted by the following algorithm:
- iterate over all divisors of $n$ in decreasing order (i.e. from $n$ to $1$), - for each divisor $d$, reverse the substring $s[1 \dots d]$ (i.e. the substring which starts at position $1$ and ends at position $d$).
For example, the above algor... | The first line of input consists of a single integer $n$ ($1 \le n \le 100$) — the length of the string $t$. The second line of input consists of the string $t$. The length of $t$ is $n$, and it consists only of lowercase Latin letters. | Print a string $s$ such that the above algorithm results in $t$. | [
"10\nrocesfedoc\n",
"16\nplmaetwoxesisiht\n",
"1\nz\n"
] | [
"codeforces\n",
"thisisexampletwo\n",
"z\n"
] | The first example is described in the problem statement. | 0 | [
{
"input": "10\nrocesfedoc",
"output": "codeforces"
},
{
"input": "16\nplmaetwoxesisiht",
"output": "thisisexampletwo"
},
{
"input": "1\nz",
"output": "z"
},
{
"input": "2\nir",
"output": "ri"
},
{
"input": "3\nilj",
"output": "jli"
},
{
"input": "4\nj... | 1,670,655,275 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | n=int(input())
a=input()
for i in range(1,n+1):
if n%i==0:
a=a[:i][::-1]+a[i:]
print(a) | Title: Reversing Encryption
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string $s$ of length $n$ can be encrypted by the following algorithm:
- iterate over all divisors of $n$ in decreasing order (i.e. from $n$ to $1$), - for each divisor $d$, reverse the substring $s[1 \dots d]$... | ```python
n=int(input())
a=input()
for i in range(1,n+1):
if n%i==0:
a=a[:i][::-1]+a[i:]
print(a)
``` | 3 | |
698 | A | Vacations | PROGRAMMING | 1,400 | [
"dp"
] | null | null | Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options:
1. on this day the gym is close... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations.
The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where:
- *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the co... | Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses:
- to do sport on any two consecutive days, - to write the contest on any two consecutive days. | [
"4\n1 3 2 0\n",
"7\n1 3 3 2 1 2 3\n",
"2\n2 2\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days.
In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day.
In the third test Vasya ca... | 500 | [
{
"input": "4\n1 3 2 0",
"output": "2"
},
{
"input": "7\n1 3 3 2 1 2 3",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "10\n0 0 1 1 0 0 0 0 1 0",
"output": "8"
},
{
"input": "100\n3 2 3 3 3 2 3 1 ... | 1,620,995,887 | 2,147,483,647 | PyPy 3 | OK | TESTS | 88 | 109 | 20,172,800 | from sys import stdin,stdout
nmbr = lambda: int(input())
lst = lambda: list(map(int, input().split()))
# 0=G'C'
# 1=G'C
# 2=GC'
# 3=GC
PI=float('inf')
def fn(pos,state):# state : 0->Rest, 1->Contest, 2->Gym
if pos==n:return 0
if a[pos]==0:
ans=1+fn(pos+1,0)
elif a[pos]==1:
conte... | Title: Vacations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Int... | ```python
from sys import stdin,stdout
nmbr = lambda: int(input())
lst = lambda: list(map(int, input().split()))
# 0=G'C'
# 1=G'C
# 2=GC'
# 3=GC
PI=float('inf')
def fn(pos,state):# state : 0->Rest, 1->Contest, 2->Gym
if pos==n:return 0
if a[pos]==0:
ans=1+fn(pos+1,0)
elif a[pos]==1:
... | 3 | |
5 | B | Center Alignment | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | B. Center Alignment | 1 | 64 | Almost every text editor has a built-in function of center text alignment. The developers of the popular in Berland text editor «Textpad» decided to introduce this functionality into the fourth release of the product.
You are to implement the alignment in the shortest possible time. Good luck! | The input file consists of one or more lines, each of the lines contains Latin letters, digits and/or spaces. The lines cannot start or end with a space. It is guaranteed that at least one of the lines has positive length. The length of each line and the total amount of the lines do not exceed 1000. | Format the given text, aligning it center. Frame the whole text with characters «*» of the minimum size. If a line cannot be aligned perfectly (for example, the line has even length, while the width of the block is uneven), you should place such lines rounding down the distance to the left or to the right edge and brin... | [
"This is\n\nCodeforces\nBeta\nRound\n5\n",
"welcome to the\nCodeforces\nBeta\nRound 5\n\nand\ngood luck\n"
] | [
"************\n* This is *\n* *\n*Codeforces*\n* Beta *\n* Round *\n* 5 *\n************\n",
"****************\n*welcome to the*\n* Codeforces *\n* Beta *\n* Round 5 *\n* *\n* and *\n* good luck *\n****************\n"
] | none | 0 | [
{
"input": "This is\n\nCodeforces\nBeta\nRound\n5",
"output": "************\n* This is *\n* *\n*Codeforces*\n* Beta *\n* Round *\n* 5 *\n************"
},
{
"input": "welcome to the\nCodeforces\nBeta\nRound 5\n\nand\ngood luck",
"output": "****************\n*welcome to th... | 1,463,357,220 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 124 | 7,065,600 | #! /usr/bin/env python3
import sys
def main():
solve()
def solve():
data = sys.stdin.readlines()
text = parse(data)
lines = text_center(text)
for l in lines:
print(l)
def parse(data):
return tuple(s.rstrip('\n') for s in data)
def text_center(text):
maxs = max(text, key=len)... | Title: Center Alignment
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Almost every text editor has a built-in function of center text alignment. The developers of the popular in Berland text editor «Textpad» decided to introduce this functionality into the fourth release of the product.
You ... | ```python
#! /usr/bin/env python3
import sys
def main():
solve()
def solve():
data = sys.stdin.readlines()
text = parse(data)
lines = text_center(text)
for l in lines:
print(l)
def parse(data):
return tuple(s.rstrip('\n') for s in data)
def text_center(text):
maxs = max(text... | 3.885357 |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,671,802,578 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 3 | 92 | 2,150,400 | a,b=list(map(int,input().split()))
c=min(a,b)
d=max(a,b)-min(a,b)
if d>1:
if d%2==0:
e=d//2
elif d==1:
e=0
print(c,e) | Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
a,b=list(map(int,input().split()))
c=min(a,b)
d=max(a,b)-min(a,b)
if d>1:
if d%2==0:
e=d//2
elif d==1:
e=0
print(c,e)
``` | -1 | |
727 | A | Transformation: from A to B | PROGRAMMING | 1,000 | [
"brute force",
"dfs and similar",
"math"
] | null | null | Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - append the digit 1 to the right of current number (that is, replace the number *x* by 10·*x*<=+<=1).
You need to he... | The first line contains two positive integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=109) — the number which Vasily has and the number he wants to have. | If there is no way to get *b* from *a*, print "NO" (without quotes).
Otherwise print three lines. On the first line print "YES" (without quotes). The second line should contain single integer *k* — the length of the transformation sequence. On the third line print the sequence of transformations *x*1,<=*x*2,<=...,<=*x... | [
"2 162\n",
"4 42\n",
"100 40021\n"
] | [
"YES\n5\n2 4 8 81 162 \n",
"NO\n",
"YES\n5\n100 200 2001 4002 40021 \n"
] | none | 1,000 | [
{
"input": "2 162",
"output": "YES\n5\n2 4 8 81 162 "
},
{
"input": "4 42",
"output": "NO"
},
{
"input": "100 40021",
"output": "YES\n5\n100 200 2001 4002 40021 "
},
{
"input": "1 111111111",
"output": "YES\n9\n1 11 111 1111 11111 111111 1111111 11111111 111111111 "
},
... | 1,596,400,514 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 109 | 6,963,200 | a,b=list(map(int,input().split()))
tmp=b
arr=[str(b)]
c=0
while(tmp>=a):
if(tmp==a):
print("YES")
print(len(arr))
arr=arr[::-1]
print(' '.join(arr))
exit()
if(tmp%2!=0):
if(str(tmp)[-1]!='1'):
print("NO")
exit()
else:
tmp=int(str(tmp)[:-1])
else:
tmp=tmp//2
arr.append(str(tmp))
# c+=1... | Title: Transformation: from A to B
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - app... | ```python
a,b=list(map(int,input().split()))
tmp=b
arr=[str(b)]
c=0
while(tmp>=a):
if(tmp==a):
print("YES")
print(len(arr))
arr=arr[::-1]
print(' '.join(arr))
exit()
if(tmp%2!=0):
if(str(tmp)[-1]!='1'):
print("NO")
exit()
else:
tmp=int(str(tmp)[:-1])
else:
tmp=tmp//2
arr.append(str(tmp... | 3 |
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