contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
148 | A | Insomnia cure | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | «One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entertained herself at best she could. Tonight she imagined that all dragons were here to steal her, and ... | Input data contains integer numbers *k*,<=*l*,<=*m*,<=*n* and *d*, each number in a separate line (1<=≤<=*k*,<=*l*,<=*m*,<=*n*<=≤<=10, 1<=≤<=*d*<=≤<=105). | Output the number of damaged dragons. | [
"1\n2\n3\n4\n12\n",
"2\n3\n4\n5\n24\n"
] | [
"12\n",
"17\n"
] | In the first case every first dragon got punched with a frying pan. Some of the dragons suffered from other reasons as well, but the pan alone would be enough.
In the second case dragons 1, 7, 11, 13, 17, 19 and 23 escaped unharmed. | 1,000 | [
{
"input": "1\n2\n3\n4\n12",
"output": "12"
},
{
"input": "2\n3\n4\n5\n24",
"output": "17"
},
{
"input": "1\n1\n1\n1\n100000",
"output": "100000"
},
{
"input": "10\n9\n8\n7\n6",
"output": "0"
},
{
"input": "8\n4\n4\n3\n65437",
"output": "32718"
},
{
"i... | 1,698,229,072 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | import math
def count_damaged_dragons(d, k, l, m, n):
damaged_dragons = 0
# Calculate the number of dragons for each condition
punched_dragons = d // k
tail_shut_dragons = d // l
paws_trampled_dragons = d // m
mom_threatened_dragons = d // n
# Calculate the number of dragons th... | Title: Insomnia cure
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
«One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entert... | ```python
import math
def count_damaged_dragons(d, k, l, m, n):
damaged_dragons = 0
# Calculate the number of dragons for each condition
punched_dragons = d // k
tail_shut_dragons = d // l
paws_trampled_dragons = d // m
mom_threatened_dragons = d // n
# Calculate the number of ... | -1 | |
556 | A | Case of the Zeros and Ones | PROGRAMMING | 900 | [
"greedy"
] | null | null | Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, an... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=2·105), the length of the string that Andreid has.
The second line contains the string of length *n* consisting only from zeros and ones. | Output the minimum length of the string that may remain after applying the described operations several times. | [
"4\n1100\n",
"5\n01010\n",
"8\n11101111\n"
] | [
"0\n",
"1\n",
"6\n"
] | In the first sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/10df55364c21c6e8d5da31b6ab6f6294c4fc26b3.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample test it is possible to change the string like... | 250 | [
{
"input": "4\n1100",
"output": "0"
},
{
"input": "5\n01010",
"output": "1"
},
{
"input": "8\n11101111",
"output": "6"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "2"
},
{
"input"... | 1,616,783,512 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 11 | 1,000 | 819,200 | n=int(input())
s=input()
while s.find('10')!=-1 or s.find('01')!=-1:
s=s.replace('10',"")
s=s.replace('01',"")
print(len(s)) | Title: Case of the Zeros and Ones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Cons... | ```python
n=int(input())
s=input()
while s.find('10')!=-1 or s.find('01')!=-1:
s=s.replace('10',"")
s=s.replace('01',"")
print(len(s))
``` | 0 | |
515 | A | Drazil and Date | PROGRAMMING | 1,000 | [
"math"
] | null | null | Someday, Drazil wanted to go on date with Varda. Drazil and Varda live on Cartesian plane. Drazil's home is located in point (0,<=0) and Varda's home is located in point (*a*,<=*b*). In each step, he can move in a unit distance in horizontal or vertical direction. In other words, from position (*x*,<=*y*) he can go to ... | You are given three integers *a*, *b*, and *s* (<=-<=109<=≤<=*a*,<=*b*<=≤<=109, 1<=≤<=*s*<=≤<=2·109) in a single line. | If you think Drazil made a mistake and it is impossible to take exactly *s* steps and get from his home to Varda's home, print "No" (without quotes).
Otherwise, print "Yes". | [
"5 5 11\n",
"10 15 25\n",
"0 5 1\n",
"0 0 2\n"
] | [
"No\n",
"Yes\n",
"No\n",
"Yes\n"
] | In fourth sample case one possible route is: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/0d30660ddf6eb6c64ffd071055a4e8ddd016cde5.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 500 | [
{
"input": "5 5 11",
"output": "No"
},
{
"input": "10 15 25",
"output": "Yes"
},
{
"input": "0 5 1",
"output": "No"
},
{
"input": "0 0 2",
"output": "Yes"
},
{
"input": "999999999 999999999 2000000000",
"output": "Yes"
},
{
"input": "-606037695 9983201... | 1,592,238,321 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 109 | 0 | m,n,a=map(int,input().split())
if a>=abs(m)+abs(n) and (a-abs(m)+abs(n))%2==0:
print("YES")
else:
print("NO")
| Title: Drazil and Date
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Someday, Drazil wanted to go on date with Varda. Drazil and Varda live on Cartesian plane. Drazil's home is located in point (0,<=0) and Varda's home is located in point (*a*,<=*b*). In each step, he can move in a unit ... | ```python
m,n,a=map(int,input().split())
if a>=abs(m)+abs(n) and (a-abs(m)+abs(n))%2==0:
print("YES")
else:
print("NO")
``` | 3 | |
510 | A | Fox And Snake | PROGRAMMING | 800 | [
"implementation"
] | null | null | Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*-th cell of *r*-th row as (*r*,<=*c*). The tail of the snake is located at (1,<=1), then it's body ... | The only line contains two integers: *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=50).
*n* is an odd number. | Output *n* lines. Each line should contain a string consisting of *m* characters. Do not output spaces. | [
"3 3\n",
"3 4\n",
"5 3\n",
"9 9\n"
] | [
"###\n..#\n###\n",
"####\n...#\n####\n",
"###\n..#\n###\n#..\n###\n",
"#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#########\n"
] | none | 500 | [
{
"input": "3 3",
"output": "###\n..#\n###"
},
{
"input": "3 4",
"output": "####\n...#\n####"
},
{
"input": "5 3",
"output": "###\n..#\n###\n#..\n###"
},
{
"input": "9 9",
"output": "#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#... | 1,683,044,906 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | a,b=map(int,input().split())
for r in range(1,a+1):
for c in range(1,b+1):
if r%2!=0:
print("*",end="")
elif c==b and r%4!=0:
print("*",end="")
elif c==1 and r%4==0:
print("*",end="")
else:
print(".",end="")
print() | Title: Fox And Snake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*... | ```python
a,b=map(int,input().split())
for r in range(1,a+1):
for c in range(1,b+1):
if r%2!=0:
print("*",end="")
elif c==b and r%4!=0:
print("*",end="")
elif c==1 and r%4==0:
print("*",end="")
else:
print(".",end="")
pri... | 0 | |
912 | A | Tricky Alchemy | PROGRAMMING | 800 | [
"implementation"
] | null | null | During the winter holidays, the demand for Christmas balls is exceptionally high. Since it's already 2018, the advances in alchemy allow easy and efficient ball creation by utilizing magic crystals.
Grisha needs to obtain some yellow, green and blue balls. It's known that to produce a yellow ball one needs two yellow ... | The first line features two integers *A* and *B* (0<=≤<=*A*,<=*B*<=≤<=109), denoting the number of yellow and blue crystals respectively at Grisha's disposal.
The next line contains three integers *x*, *y* and *z* (0<=≤<=*x*,<=*y*,<=*z*<=≤<=109) — the respective amounts of yellow, green and blue balls to be obtained. | Print a single integer — the minimum number of crystals that Grisha should acquire in addition. | [
"4 3\n2 1 1\n",
"3 9\n1 1 3\n",
"12345678 87654321\n43043751 1000000000 53798715\n"
] | [
"2\n",
"1\n",
"2147483648\n"
] | In the first sample case, Grisha needs five yellow and four blue crystals to create two yellow balls, one green ball, and one blue ball. To do that, Grisha needs to obtain two additional crystals: one yellow and one blue. | 500 | [
{
"input": "4 3\n2 1 1",
"output": "2"
},
{
"input": "3 9\n1 1 3",
"output": "1"
},
{
"input": "12345678 87654321\n43043751 1000000000 53798715",
"output": "2147483648"
},
{
"input": "12 12\n3 5 2",
"output": "0"
},
{
"input": "770 1390\n170 442 311",
"output"... | 1,515,325,556 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 61 | 5,632,000 | a = [2,2,3]
y,b=map(int,input().split())
arr = list(map(int,input().split()))
for i,ar in enumerate(arr):
a[i]*=ar
s=sum(a)
d=s-(y+b)
if d>0:
print(d)
else:
print(0) | Title: Tricky Alchemy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
During the winter holidays, the demand for Christmas balls is exceptionally high. Since it's already 2018, the advances in alchemy allow easy and efficient ball creation by utilizing magic crystals.
Grisha needs to obta... | ```python
a = [2,2,3]
y,b=map(int,input().split())
arr = list(map(int,input().split()))
for i,ar in enumerate(arr):
a[i]*=ar
s=sum(a)
d=s-(y+b)
if d>0:
print(d)
else:
print(0)
``` | 0 | |
950 | A | Left-handers, Right-handers and Ambidexters | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and ... | The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. | Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. | [
"1 4 2\n",
"5 5 5\n",
"0 2 0\n"
] | [
"6\n",
"14\n",
"0\n"
] | In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five l... | 500 | [
{
"input": "1 4 2",
"output": "6"
},
{
"input": "5 5 5",
"output": "14"
},
{
"input": "0 2 0",
"output": "0"
},
{
"input": "30 70 34",
"output": "128"
},
{
"input": "89 32 24",
"output": "112"
},
{
"input": "89 44 77",
"output": "210"
},
{
... | 1,617,025,658 | 2,147,483,647 | Python 3 | OK | TESTS | 79 | 62 | 0 | L, R, a = list(map(int, input().split()))
if L == R:
print(L*2+((a//2)*2))
else:
if L+a <= R or R+a <= L:
print(min(L+a, R+a)*2)
else:
if L < R:
print(R*2+((a-R+L)//2)*2)
else:
print(L*2+(((a-L+R)//2)*2))
| Title: Left-handers, Right-handers and Ambidexters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.... | ```python
L, R, a = list(map(int, input().split()))
if L == R:
print(L*2+((a//2)*2))
else:
if L+a <= R or R+a <= L:
print(min(L+a, R+a)*2)
else:
if L < R:
print(R*2+((a-R+L)//2)*2)
else:
print(L*2+(((a-L+R)//2)*2))
``` | 3 | |
960 | A | Check the string | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gi... | The first and only line consists of a string $S$ ($ 1 \le |S| \le 5\,000 $). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'. | Print "YES" or "NO", according to the condition. | [
"aaabccc\n",
"bbacc\n",
"aabc\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'. | 500 | [
{
"input": "aaabccc",
"output": "YES"
},
{
"input": "bbacc",
"output": "NO"
},
{
"input": "aabc",
"output": "YES"
},
{
"input": "aabbcc",
"output": "YES"
},
{
"input": "aaacccbb",
"output": "NO"
},
{
"input": "abc",
"output": "YES"
},
{
"in... | 1,523,118,363 | 1,263 | Python 3 | WRONG_ANSWER | TESTS | 32 | 124 | 7,475,200 | import re
s=input()
try:
print('YES' if re.match(r'aa*bb*cc*',s).group(0)==s and s.count('a')==s.count('c') or s.count('b')==s.count('c') else 'NO')
except:
print('NO')
| Title: Check the string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b... | ```python
import re
s=input()
try:
print('YES' if re.match(r'aa*bb*cc*',s).group(0)==s and s.count('a')==s.count('c') or s.count('b')==s.count('c') else 'NO')
except:
print('NO')
``` | 0 | |
488 | A | Giga Tower | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Every day, thousands of tourists come to this place to enjoy the wonderful view.
In Cyberland, it ... | The only line of input contains an integer *a* (<=-<=109<=≤<=*a*<=≤<=109). | Print the minimum *b* in a line. | [
"179\n",
"-1\n",
"18\n"
] | [
"1\n",
"9\n",
"10\n"
] | For the first sample, he has to arrive at the floor numbered 180.
For the second sample, he will arrive at 8.
Note that *b* should be positive, so the answer for the third sample is 10, not 0. | 500 | [
{
"input": "179",
"output": "1"
},
{
"input": "-1",
"output": "9"
},
{
"input": "18",
"output": "10"
},
{
"input": "-410058385",
"output": "1"
},
{
"input": "-586825624",
"output": "1"
},
{
"input": "852318890",
"output": "1"
},
{
"input": ... | 1,647,792,031 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 30 | 0 | cur_floor = int(input())
ans=0
if cur_floor%10 ==8:
print(10)
elif cur_floor<0:
print((cur_floor*(-1))+8)
else:
while True:
if('8' in str(cur_floor)):
print(ans)
break
ans+=1
cur_floor+=1
| Title: Giga Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Ever... | ```python
cur_floor = int(input())
ans=0
if cur_floor%10 ==8:
print(10)
elif cur_floor<0:
print((cur_floor*(-1))+8)
else:
while True:
if('8' in str(cur_floor)):
print(ans)
break
ans+=1
cur_floor+=1
``` | 0 | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,623,286,986 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 156 | 0 | n = input()
sum = 0
count = 0
while len(n) != 1:
for i in n:
sum += int(i)
n = str(sum)
sum = 0
count += 1
print(count) | Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
n = input()
sum = 0
count = 0
while len(n) != 1:
for i in n:
sum += int(i)
n = str(sum)
sum = 0
count += 1
print(count)
``` | 3.961 |
124 | A | The number of positions | PROGRAMMING | 1,000 | [
"math"
] | null | null | Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind him. Find the number of different positions Petr can occupy. | The only line contains three integers *n*, *a* and *b* (0<=≤<=*a*,<=*b*<=<<=*n*<=≤<=100). | Print the single number — the number of the sought positions. | [
"3 1 1\n",
"5 2 3\n"
] | [
"2\n",
"3\n"
] | The possible positions in the first sample are: 2 and 3 (if we number the positions starting with 1).
In the second sample they are 3, 4 and 5. | 500 | [
{
"input": "3 1 1",
"output": "2"
},
{
"input": "5 2 3",
"output": "3"
},
{
"input": "5 4 0",
"output": "1"
},
{
"input": "6 5 5",
"output": "1"
},
{
"input": "9 4 3",
"output": "4"
},
{
"input": "11 4 6",
"output": "7"
},
{
"input": "13 8 ... | 1,684,601,443 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 122 | 0 | # def solution(q, s):
# res, a, b = '', 0, 0
# return x, y
def main():
a, b, с = map(int, input().split())
print(b+1)
if __name__ == "__main__":
main() | Title: The number of positions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind h... | ```python
# def solution(q, s):
# res, a, b = '', 0, 0
# return x, y
def main():
a, b, с = map(int, input().split())
print(b+1)
if __name__ == "__main__":
main()
``` | 0 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,630,353,716 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 184 | 6,963,200 | encode = input()
ans = ''
i = 0
n = len(encode)
while i<n:
if encode[i] == '.':
ans = ans + '0'
i = i+1
elif encode[i] == '-' and encode[i+1] == '.':
ans = ans + '1'
i= i +2
elif encode[i]=='-' and encode[i+1]=='-':
ans = ans + '2'
i=i+2
print(... | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
encode = input()
ans = ''
i = 0
n = len(encode)
while i<n:
if encode[i] == '.':
ans = ans + '0'
i = i+1
elif encode[i] == '-' and encode[i+1] == '.':
ans = ans + '1'
i= i +2
elif encode[i]=='-' and encode[i+1]=='-':
ans = ans + '2'
i=i+2... | 3.94103 |
902 | B | Coloring a Tree | PROGRAMMING | 1,200 | [
"dfs and similar",
"dsu",
"greedy"
] | null | null | You are given a rooted tree with *n* vertices. The vertices are numbered from 1 to *n*, the root is the vertex number 1.
Each vertex has a color, let's denote the color of vertex *v* by *c**v*. Initially *c**v*<==<=0.
You have to color the tree into the given colors using the smallest possible number of steps. On eac... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=104) — the number of vertices in the tree.
The second line contains *n*<=-<=1 integers *p*2,<=*p*3,<=...,<=*p**n* (1<=≤<=*p**i*<=<<=*i*), where *p**i* means that there is an edge between vertices *i* and *p**i*.
The third line contains *n* integers *c*1,<... | Print a single integer — the minimum number of steps you have to perform to color the tree into given colors. | [
"6\n1 2 2 1 5\n2 1 1 1 1 1\n",
"7\n1 1 2 3 1 4\n3 3 1 1 1 2 3\n"
] | [
"3\n",
"5\n"
] | The tree from the first sample is shown on the picture (numbers are vetices' indices):
<img class="tex-graphics" src="https://espresso.codeforces.com/10324ccdc37f95343acc4f3c6050d8c334334ffa.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On first step we color all vertices in the subtree of vertex 1 into color ... | 1,000 | [
{
"input": "6\n1 2 2 1 5\n2 1 1 1 1 1",
"output": "3"
},
{
"input": "7\n1 1 2 3 1 4\n3 3 1 1 1 2 3",
"output": "5"
},
{
"input": "2\n1\n2 2",
"output": "1"
},
{
"input": "3\n1 1\n2 2 2",
"output": "1"
},
{
"input": "4\n1 2 1\n1 2 3 4",
"output": "4"
},
{
... | 1,610,442,798 | 2,147,483,647 | PyPy 3 | OK | TESTS | 50 | 155 | 3,891,200 | nodes = int(input())
parents = [None, None]
parents += [int(p) for p in input().split()]
final = [int(p) for p in input().split()]
graph = []
for i in range(nodes + 1):
graph.append([])
for i in range(len(parents)):
if parents[i] is not None:
graph[parents[i]].append(i)
initial = [0]*(len(final) + 1)
ste... | Title: Coloring a Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rooted tree with *n* vertices. The vertices are numbered from 1 to *n*, the root is the vertex number 1.
Each vertex has a color, let's denote the color of vertex *v* by *c**v*. Initially *c**v*<==<=0.
... | ```python
nodes = int(input())
parents = [None, None]
parents += [int(p) for p in input().split()]
final = [int(p) for p in input().split()]
graph = []
for i in range(nodes + 1):
graph.append([])
for i in range(len(parents)):
if parents[i] is not None:
graph[parents[i]].append(i)
initial = [0]*(len(final)... | 3 | |
415 | B | Mashmokh and Tokens | PROGRAMMING | 1,500 | [
"binary search",
"greedy",
"implementation",
"math"
] | null | null | Bimokh is Mashmokh's boss. For the following *n* days he decided to pay to his workers in a new way. At the beginning of each day he will give each worker a certain amount of tokens. Then at the end of each day each worker can give some of his tokens back to get a certain amount of money. The worker can save the rest o... | The first line of input contains three space-separated integers *n*,<=*a*,<=*b* (1<=≤<=*n*<=≤<=105; 1<=≤<=*a*,<=*b*<=≤<=109). The second line of input contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=109). | Output *n* space-separated integers. The *i*-th of them is the number of tokens Mashmokh can save on the *i*-th day. | [
"5 1 4\n12 6 11 9 1\n",
"3 1 2\n1 2 3\n",
"1 1 1\n1\n"
] | [
"0 2 3 1 1 ",
"1 0 1 ",
"0 "
] | none | 1,000 | [
{
"input": "5 1 4\n12 6 11 9 1",
"output": "0 2 3 1 1 "
},
{
"input": "3 1 2\n1 2 3",
"output": "1 0 1 "
},
{
"input": "1 1 1\n1",
"output": "0 "
},
{
"input": "1 1 1000000000\n1000000000",
"output": "0 "
},
{
"input": "1 1 1000000000\n999999999",
"output": "9... | 1,396,801,287 | 2,487 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 109 | 6,246,400 | def main():
N, A, B = map(int, input().split())
numbers = list(map(int, input().split()))
result = []
for i in range(N):
result += [(numbers[i] * A) % B]
print(' '.join(map(str, result)))
main() | Title: Mashmokh and Tokens
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bimokh is Mashmokh's boss. For the following *n* days he decided to pay to his workers in a new way. At the beginning of each day he will give each worker a certain amount of tokens. Then at the end of each day each... | ```python
def main():
N, A, B = map(int, input().split())
numbers = list(map(int, input().split()))
result = []
for i in range(N):
result += [(numbers[i] * A) % B]
print(' '.join(map(str, result)))
main()
``` | 0 | |
205 | A | Little Elephant and Rozdil | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elephant doesn't like to spend much time on travelling, so for his journey he will choose a town that needs minimum ti... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of cities. The next line contains *n* integers, separated by single spaces: the *i*-th integer represents the time needed to go from town Rozdil to the *i*-th town. The time values are positive integers, not exceeding 109.
You can consider t... | Print the answer on a single line — the number of the town the Little Elephant will go to. If there are multiple cities with minimum travel time, print "Still Rozdil" (without the quotes). | [
"2\n7 4\n",
"7\n7 4 47 100 4 9 12\n"
] | [
"2\n",
"Still Rozdil\n"
] | In the first sample there are only two cities where the Little Elephant can go. The travel time for the first town equals 7, to the second one — 4. The town which is closest to Rodzil (the only one) is the second one, so the answer is 2.
In the second sample the closest cities are cities two and five, the travelling t... | 500 | [
{
"input": "2\n7 4",
"output": "2"
},
{
"input": "7\n7 4 47 100 4 9 12",
"output": "Still Rozdil"
},
{
"input": "1\n47",
"output": "1"
},
{
"input": "2\n1000000000 1000000000",
"output": "Still Rozdil"
},
{
"input": "7\n7 6 5 4 3 2 1",
"output": "7"
},
{
... | 1,569,908,780 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 184 | 0 | n=int(input())
c=[]
for i in range (n):
m=int(input())
c.append(m)
small=c[0]
for i in range (n):
if c[i]<small:
small=c[i]
elif c[i]==small:
same=c[i]
if small==same:
print("Still Rodzil")
else:
print (small)
| Title: Little Elephant and Rozdil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elepha... | ```python
n=int(input())
c=[]
for i in range (n):
m=int(input())
c.append(m)
small=c[0]
for i in range (n):
if c[i]<small:
small=c[i]
elif c[i]==small:
same=c[i]
if small==same:
print("Still Rodzil")
else:
print (small)
``` | -1 | |
633 | A | Ebony and Ivory | PROGRAMMING | 1,100 | [
"brute force",
"math",
"number theory"
] | null | null | Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
For every bullet that hits the shield, Ebony deals *a* units of damage while Ivory deals *b* units of ... | The first line of the input contains three integers *a*, *b*, *c* (1<=≤<=*a*,<=*b*<=≤<=100,<=1<=≤<=*c*<=≤<=10<=000) — the number of units of damage dealt by Ebony gun and Ivory gun, and the total number of damage required to break the shield, respectively. | Print "Yes" (without quotes) if Dante can deal exactly *c* damage to the shield and "No" (without quotes) otherwise. | [
"4 6 15\n",
"3 2 7\n",
"6 11 6\n"
] | [
"No\n",
"Yes\n",
"Yes\n"
] | In the second sample, Dante can fire 1 bullet from Ebony and 2 from Ivory to deal exactly 1·3 + 2·2 = 7 damage. In the third sample, Dante can fire 1 bullet from ebony and no bullets from ivory to do 1·6 + 0·11 = 6 damage. | 250 | [
{
"input": "4 6 15",
"output": "No"
},
{
"input": "3 2 7",
"output": "Yes"
},
{
"input": "6 11 6",
"output": "Yes"
},
{
"input": "3 12 15",
"output": "Yes"
},
{
"input": "5 5 10",
"output": "Yes"
},
{
"input": "6 6 7",
"output": "No"
},
{
"... | 1,597,834,539 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 202 | 2,048,000 |
a,b,c=map(int,input().split())
if c%a==0 or c%b==0:
print("Yes")
else:
g,x,y=gcdExt(a,b)
if c%g!=0:
print("No")
else:
if x>=0 and y>=0:
print("Yes")
else:
if x<0:
if (y//(a//g))>=(abs(x)//(b//g)):
pr... | Title: Ebony and Ivory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
F... | ```python
a,b,c=map(int,input().split())
if c%a==0 or c%b==0:
print("Yes")
else:
g,x,y=gcdExt(a,b)
if c%g!=0:
print("No")
else:
if x>=0 and y>=0:
print("Yes")
else:
if x<0:
if (y//(a//g))>=(abs(x)//(b//g)):
... | -1 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,680,028,383 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | num_tests = int(input())
for i in range(num_tests):
word = input()
if len(word) <= 10:
print(word)
else:
start_char = word[0]
end_char = word[-1]
num_chars_middle = len(word) - 2
print(f"{start_char}{num_chars_middle}{end_char}") | Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
num_tests = int(input())
for i in range(num_tests):
word = input()
if len(word) <= 10:
print(word)
else:
start_char = word[0]
end_char = word[-1]
num_chars_middle = len(word) - 2
print(f"{start_char}{num_chars_middle}{end_char}")
``` | 3.977 |
978 | C | Letters | PROGRAMMING | 1,000 | [
"binary search",
"implementation",
"two pointers"
] | null | null | There are $n$ dormitories in Berland State University, they are numbered with integers from $1$ to $n$. Each dormitory consists of rooms, there are $a_i$ rooms in $i$-th dormitory. The rooms in $i$-th dormitory are numbered from $1$ to $a_i$.
A postman delivers letters. Sometimes there is no specific dormitory and roo... | The first line contains two integers $n$ and $m$ $(1 \le n, m \le 2 \cdot 10^{5})$ — the number of dormitories and the number of letters.
The second line contains a sequence $a_1, a_2, \dots, a_n$ $(1 \le a_i \le 10^{10})$, where $a_i$ equals to the number of rooms in the $i$-th dormitory. The third line contains a se... | Print $m$ lines. For each letter print two integers $f$ and $k$ — the dormitory number $f$ $(1 \le f \le n)$ and the room number $k$ in this dormitory $(1 \le k \le a_f)$ to deliver the letter. | [
"3 6\n10 15 12\n1 9 12 23 26 37\n",
"2 3\n5 10000000000\n5 6 9999999999\n"
] | [
"1 1\n1 9\n2 2\n2 13\n3 1\n3 12\n",
"1 5\n2 1\n2 9999999994\n"
] | In the first example letters should be delivered in the following order:
- the first letter in room $1$ of the first dormitory - the second letter in room $9$ of the first dormitory - the third letter in room $2$ of the second dormitory - the fourth letter in room $13$ of the second dormitory - the fifth letter i... | 0 | [
{
"input": "3 6\n10 15 12\n1 9 12 23 26 37",
"output": "1 1\n1 9\n2 2\n2 13\n3 1\n3 12"
},
{
"input": "2 3\n5 10000000000\n5 6 9999999999",
"output": "1 5\n2 1\n2 9999999994"
},
{
"input": "1 1\n1\n1",
"output": "1 1"
},
{
"input": "5 15\n10 20 30 20 10\n1 6 10 11 15 30 31 54... | 1,688,870,033 | 2,147,483,647 | Python 3 | OK | TESTS | 16 | 794 | 60,416,000 | n, m = (int(i) for i in input().split())
a = (int(i) for i in input().split())
b = (int(i) for i in input().split())
ma = sz = next(a)
res, j = [], 1
for i in b:
while i > ma:
sz = next(a)
ma += sz
j += 1
res.append((j, i - (ma - sz)))
for r in res:
print(*r)
| Title: Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are $n$ dormitories in Berland State University, they are numbered with integers from $1$ to $n$. Each dormitory consists of rooms, there are $a_i$ rooms in $i$-th dormitory. The rooms in $i$-th dormitory are numbered fro... | ```python
n, m = (int(i) for i in input().split())
a = (int(i) for i in input().split())
b = (int(i) for i in input().split())
ma = sz = next(a)
res, j = [], 1
for i in b:
while i > ma:
sz = next(a)
ma += sz
j += 1
res.append((j, i - (ma - sz)))
for r in res:
print(*r)
``` | 3 | |
583 | A | Asphalting Roads | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers of the roads that form them.
Sand roads have long been recognized out of date, so the decision was ma... | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of vertical and horizontal roads in the city.
Next *n*2 lines contain the order of intersections in the schedule. The *i*-th of them contains two numbers *h**i*,<=*v**i* (1<=≤<=*h**i*,<=*v**i*<=≤<=*n*), separated by a space, and meaning that the inte... | In the single line print the numbers of the days when road works will be in progress in ascending order. The days are numbered starting from 1. | [
"2\n1 1\n1 2\n2 1\n2 2\n",
"1\n1 1\n"
] | [
"1 4 \n",
"1 \n"
] | In the sample the brigade acts like that:
1. On the first day the brigade comes to the intersection of the 1-st horizontal and the 1-st vertical road. As none of them has been asphalted, the workers asphalt the 1-st vertical and the 1-st horizontal road; 1. On the second day the brigade of the workers comes to the i... | 500 | [
{
"input": "2\n1 1\n1 2\n2 1\n2 2",
"output": "1 4 "
},
{
"input": "1\n1 1",
"output": "1 "
},
{
"input": "2\n1 1\n2 2\n1 2\n2 1",
"output": "1 2 "
},
{
"input": "2\n1 2\n2 2\n2 1\n1 1",
"output": "1 3 "
},
{
"input": "3\n2 2\n1 2\n3 2\n3 3\n1 1\n2 3\n1 3\n3 1\n2 ... | 1,443,891,365 | 665 | Python 3 | OK | TESTS | 39 | 62 | 0 | n=int(input())
hor=set()
ver=set()
res=[]
for i in range(n*n):
h,v=map(int, input().split())
if (h not in hor) and (v not in ver):
res.append(str(i+1))
hor.add(h)
ver.add(v)
print(" ".join(res)) | Title: Asphalting Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers ... | ```python
n=int(input())
hor=set()
ver=set()
res=[]
for i in range(n*n):
h,v=map(int, input().split())
if (h not in hor) and (v not in ver):
res.append(str(i+1))
hor.add(h)
ver.add(v)
print(" ".join(res))
``` | 3 | |
994 | B | Knights of a Polygonal Table | PROGRAMMING | 1,400 | [
"greedy",
"implementation",
"sortings"
] | null | null | Unlike Knights of a Round Table, Knights of a Polygonal Table deprived of nobility and happy to kill each other. But each knight has some power and a knight can kill another knight if and only if his power is greater than the power of victim. However, even such a knight will torment his conscience, so he can kill no mo... | The first line contains two integers $n$ and $k$ $(1 \le n \le 10^5, 0 \le k \le \min(n-1,10))$ — the number of knights and the number $k$ from the statement.
The second line contains $n$ integers $p_1, p_2 ,\ldots,p_n$ $(1 \le p_i \le 10^9)$ — powers of the knights. All $p_i$ are distinct.
The third line contains $n... | Print $n$ integers — the maximum number of coins each knight can have it only he kills other knights. | [
"4 2\n4 5 9 7\n1 2 11 33\n",
"5 1\n1 2 3 4 5\n1 2 3 4 5\n",
"1 0\n2\n3\n"
] | [
"1 3 46 36 ",
"1 3 5 7 9 ",
"3 "
] | Consider the first example.
- The first knight is the weakest, so he can't kill anyone. That leaves him with the only coin he initially has. - The second knight can kill the first knight and add his coin to his own two. - The third knight is the strongest, but he can't kill more than $k = 2$ other knights. It is o... | 1,000 | [
{
"input": "4 2\n4 5 9 7\n1 2 11 33",
"output": "1 3 46 36 "
},
{
"input": "5 1\n1 2 3 4 5\n1 2 3 4 5",
"output": "1 3 5 7 9 "
},
{
"input": "1 0\n2\n3",
"output": "3 "
},
{
"input": "7 1\n2 3 4 5 7 8 9\n0 3 7 9 5 8 9",
"output": "0 3 10 16 14 17 18 "
},
{
"input"... | 1,529,170,953 | 4,053 | Python 3 | OK | TESTS | 73 | 639 | 20,684,800 | n,k = tuple(map(lambda x:int(x), input().split(' ')))
p = list(map(lambda x:int(x), input().split(' ')))
c = list(map(lambda x:int(x), input().split(' ')))
out = [i for i in c]
#t = [(p[i], c[i]) for i in range(n)]
t = [(p[i], i) for i in range(n)]
import heapq
kbest = []
#print(t)
t.sort()
#print(t)
prev = 0
i = 0
whi... | Title: Knights of a Polygonal Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Unlike Knights of a Round Table, Knights of a Polygonal Table deprived of nobility and happy to kill each other. But each knight has some power and a knight can kill another knight if and only if his power ... | ```python
n,k = tuple(map(lambda x:int(x), input().split(' ')))
p = list(map(lambda x:int(x), input().split(' ')))
c = list(map(lambda x:int(x), input().split(' ')))
out = [i for i in c]
#t = [(p[i], c[i]) for i in range(n)]
t = [(p[i], i) for i in range(n)]
import heapq
kbest = []
#print(t)
t.sort()
#print(t)
prev = 0... | 3 | |
946 | A | Partition | PROGRAMMING | 800 | [
"greedy"
] | null | null | You are given a sequence *a* consisting of *n* integers. You may partition this sequence into two sequences *b* and *c* in such a way that every element belongs exactly to one of these sequences.
Let *B* be the sum of elements belonging to *b*, and *C* be the sum of elements belonging to *c* (if some of these sequenc... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (<=-<=100<=≤<=*a**i*<=≤<=100) — the elements of sequence *a*. | Print the maximum possible value of *B*<=-<=*C*, where *B* is the sum of elements of sequence *b*, and *C* is the sum of elements of sequence *c*. | [
"3\n1 -2 0\n",
"6\n16 23 16 15 42 8\n"
] | [
"3\n",
"120\n"
] | In the first example we may choose *b* = {1, 0}, *c* = { - 2}. Then *B* = 1, *C* = - 2, *B* - *C* = 3.
In the second example we choose *b* = {16, 23, 16, 15, 42, 8}, *c* = {} (an empty sequence). Then *B* = 120, *C* = 0, *B* - *C* = 120. | 0 | [
{
"input": "3\n1 -2 0",
"output": "3"
},
{
"input": "6\n16 23 16 15 42 8",
"output": "120"
},
{
"input": "1\n-1",
"output": "1"
},
{
"input": "100\n-100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -10... | 1,697,572,521 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 72 | 62 | 0 | n = int(input())
k = [int(i) for i in input().split()]
c = 0
for i in k:
c += abs(i)
print(c) | Title: Partition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence *a* consisting of *n* integers. You may partition this sequence into two sequences *b* and *c* in such a way that every element belongs exactly to one of these sequences.
Let *B* be the sum of eleme... | ```python
n = int(input())
k = [int(i) for i in input().split()]
c = 0
for i in k:
c += abs(i)
print(c)
``` | 3 | |
611 | B | New Year and Old Property | PROGRAMMING | 1,300 | [
"bitmasks",
"brute force",
"implementation"
] | null | null | The year 2015 is almost over.
Limak is a little polar bear. He has recently learnt about the binary system. He noticed that the passing year has exactly one zero in its representation in the binary system — 201510<==<=111110111112. Note that he doesn't care about the number of zeros in the decimal representation.
Lim... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=1018) — the first year and the last year in Limak's interval respectively. | Print one integer – the number of years Limak will count in his chosen interval. | [
"5 10\n",
"2015 2015\n",
"100 105\n",
"72057594000000000 72057595000000000\n"
] | [
"2\n",
"1\n",
"0\n",
"26\n"
] | In the first sample Limak's interval contains numbers 5<sub class="lower-index">10</sub> = 101<sub class="lower-index">2</sub>, 6<sub class="lower-index">10</sub> = 110<sub class="lower-index">2</sub>, 7<sub class="lower-index">10</sub> = 111<sub class="lower-index">2</sub>, 8<sub class="lower-index">10</sub> = 1000<su... | 750 | [
{
"input": "5 10",
"output": "2"
},
{
"input": "2015 2015",
"output": "1"
},
{
"input": "100 105",
"output": "0"
},
{
"input": "72057594000000000 72057595000000000",
"output": "26"
},
{
"input": "1 100",
"output": "16"
},
{
"input": "100000000000000000... | 1,633,371,044 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 61 | 6,963,200 | import math
def count_numbers(L, R):
ans = 0
LogR = (int)(math.log(R) + 1)
for zero_bit in range(LogR):
cur = 0
for j in range(zero_bit):
cur |= (1 << j)
for j in range(zero_bit + 1, LogR):
cur |= (1 << j)
if (cur >= L and cur <... | Title: New Year and Old Property
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The year 2015 is almost over.
Limak is a little polar bear. He has recently learnt about the binary system. He noticed that the passing year has exactly one zero in its representation in the binary system — 2... | ```python
import math
def count_numbers(L, R):
ans = 0
LogR = (int)(math.log(R) + 1)
for zero_bit in range(LogR):
cur = 0
for j in range(zero_bit):
cur |= (1 << j)
for j in range(zero_bit + 1, LogR):
cur |= (1 << j)
if (cur >= L... | 0 | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,696,348,812 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 46 | 0 | def fast(num1, num2):
answer = ""
for i in range(len(num1)):
if num1[i] != num2[i]:
answer += "1"
else:
answer += '0'
return answer
num1 = input()
num2 = input()
ans = fast(num1, num2)
print(ans)
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
def fast(num1, num2):
answer = ""
for i in range(len(num1)):
if num1[i] != num2[i]:
answer += "1"
else:
answer += '0'
return answer
num1 = input()
num2 = input()
ans = fast(num1, num2)
print(ans)
``` | 3.9885 |
387 | B | George and Round | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"two pointers"
] | null | null | George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirem... | Print a single integer — the answer to the problem. | [
"3 5\n1 2 3\n1 2 2 3 3\n",
"3 5\n1 2 3\n1 1 1 1 1\n",
"3 1\n2 3 4\n1\n"
] | [
"0\n",
"2\n",
"3\n"
] | In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems wi... | 1,000 | [
{
"input": "3 5\n1 2 3\n1 2 2 3 3",
"output": "0"
},
{
"input": "3 5\n1 2 3\n1 1 1 1 1",
"output": "2"
},
{
"input": "3 1\n2 3 4\n1",
"output": "3"
},
{
"input": "29 100\n20 32 41 67 72 155 331 382 399 412 465 470 484 511 515 529 616 637 679 715 733 763 826 843 862 903 925 97... | 1,437,047,723 | 4,223 | Python 3 | OK | TESTS | 41 | 358 | 819,200 | n, m = map(int, input().split())
a = input().split()
b = input().split()
for i in range(n):
a[i] = int(a[i])
for i in range(m):
b[i] = int(b[i])
a.sort(reverse=True)
b.sort()
answ = 0
v = {}
for i in range(m):
if b[i] in v:
v[b[i]]+=1
else:
v[b[i]] = 1
for i in range(n):
... | Title: George and Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
T... | ```python
n, m = map(int, input().split())
a = input().split()
b = input().split()
for i in range(n):
a[i] = int(a[i])
for i in range(m):
b[i] = int(b[i])
a.sort(reverse=True)
b.sort()
answ = 0
v = {}
for i in range(m):
if b[i] in v:
v[b[i]]+=1
else:
v[b[i]] = 1
for i in ... | 3 | |
678 | A | Johny Likes Numbers | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*. | The only line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=109). | Print the smallest integer *x*<=><=*n*, so it is divisible by the number *k*. | [
"5 3\n",
"25 13\n",
"26 13\n"
] | [
"6\n",
"26\n",
"39\n"
] | none | 0 | [
{
"input": "5 3",
"output": "6"
},
{
"input": "25 13",
"output": "26"
},
{
"input": "26 13",
"output": "39"
},
{
"input": "1 1",
"output": "2"
},
{
"input": "8 8",
"output": "16"
},
{
"input": "14 15",
"output": "15"
},
{
"input": "197 894"... | 1,670,179,820 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 451 | 1,331,200 | n, k = map(int, input().split())
x = k
if k == 1:
print(n + 1)
else:
while x <= n:
x += k
print(x)
| Title: Johny Likes Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*.
Input Specification:
The only line contains two integers *n* and *... | ```python
n, k = map(int, input().split())
x = k
if k == 1:
print(n + 1)
else:
while x <= n:
x += k
print(x)
``` | 3 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,675,171,459 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 46 | 0 | def main():
word=input().strip()
hello="hello"
i,j=0,0
while i<len(word) and j<len(hello):
if word[i]==hello[j]:
j=j+1
i=i+1
if j==5:
print("YES")
else:
print("NO")
if __name__=='__main__':
main() | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
def main():
word=input().strip()
hello="hello"
i,j=0,0
while i<len(word) and j<len(hello):
if word[i]==hello[j]:
j=j+1
i=i+1
if j==5:
print("YES")
else:
print("NO")
if __name__=='__main__':
main()
``` | 3.977 |
554 | A | Kyoya and Photobooks | PROGRAMMING | 900 | [
"brute force",
"math",
"strings"
] | null | null | Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the pho... | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters. | Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make. | [
"a\n",
"hi\n"
] | [
"51\n",
"76\n"
] | In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | 250 | [
{
"input": "a",
"output": "51"
},
{
"input": "hi",
"output": "76"
},
{
"input": "y",
"output": "51"
},
{
"input": "kgan",
"output": "126"
},
{
"input": "zoabkyuvus",
"output": "276"
},
{
"input": "spyemhyznjieyhhbk",
"output": "451"
},
{
"i... | 1,563,174,812 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 109 | 0 | t=input()
i=len(t)
print(26*(i+1)-i) | Title: Kyoya and Photobooks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos b... | ```python
t=input()
i=len(t)
print(26*(i+1)-i)
``` | 3 | |
332 | B | Maximum Absurdity | PROGRAMMING | 1,500 | [
"data structures",
"dp",
"implementation"
] | null | null | Reforms continue entering Berland. For example, during yesterday sitting the Berland Parliament approved as much as *n* laws (each law has been assigned a unique number from 1 to *n*). Today all these laws were put on the table of the President of Berland, G.W. Boosch, to be signed.
This time mr. Boosch plans to sign ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=2·105, 0<=<<=2*k*<=≤<=*n*) — the number of laws accepted by the parliament and the length of one segment in the law list, correspondingly. The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n* — the absurdity of each law (1<=≤<=*x**i*<=≤<=109). | Print two integers *a*, *b* — the beginning of segments that mr. Boosch should choose. That means that the president signs laws with numbers from segments [*a*; *a*<=+<=*k*<=-<=1] and [*b*; *b*<=+<=*k*<=-<=1]. If there are multiple solutions, print the one with the minimum number *a*. If there still are multiple soluti... | [
"5 2\n3 6 1 1 6\n",
"6 2\n1 1 1 1 1 1\n"
] | [
"1 4\n",
"1 3\n"
] | In the first sample mr. Boosch signs laws with numbers from segments [1;2] and [4;5]. The total absurdity of the signed laws equals 3 + 6 + 1 + 6 = 16.
In the second sample mr. Boosch signs laws with numbers from segments [1;2] and [3;4]. The total absurdity of the signed laws equals 1 + 1 + 1 + 1 = 4. | 1,000 | [
{
"input": "5 2\n3 6 1 1 6",
"output": "1 4"
},
{
"input": "6 2\n1 1 1 1 1 1",
"output": "1 3"
},
{
"input": "6 2\n1 4 1 2 5 6",
"output": "1 5"
},
{
"input": "4 1\n1 2 2 2",
"output": "2 3"
},
{
"input": "6 3\n15 20 1 15 43 6",
"output": "1 4"
},
{
"i... | 1,374,681,758 | 1,958 | Python 3 | WRONG_ANSWER | PRETESTS | 2 | 92 | 0 | n, k = map(int, input().split())
absurdity = list(map(int, input().split()))
absurdity_sums = []
cur_sum = 0
for i in range(k):
cur_sum += absurdity[i]
absurdity_sums.append(cur_sum)
for i in range(k, n - k + 2):
cur_sum = cur_sum - absurdity[i-k] + absurdity[i]
absurdity_sums.append(cur_sum)
tuples = [... | Title: Maximum Absurdity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Reforms continue entering Berland. For example, during yesterday sitting the Berland Parliament approved as much as *n* laws (each law has been assigned a unique number from 1 to *n*). Today all these laws were put on... | ```python
n, k = map(int, input().split())
absurdity = list(map(int, input().split()))
absurdity_sums = []
cur_sum = 0
for i in range(k):
cur_sum += absurdity[i]
absurdity_sums.append(cur_sum)
for i in range(k, n - k + 2):
cur_sum = cur_sum - absurdity[i-k] + absurdity[i]
absurdity_sums.append(cur_sum)
... | 0 | |
862 | B | Mahmoud and Ehab and the bipartiteness | PROGRAMMING | 1,300 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a graph, whose vertices can be partitioned into 2 sets in such a way, that for each edge (*u*,<=*v*) that belongs to the graph, *... | The first line of input contains an integer *n* — the number of nodes in the tree (1<=≤<=*n*<=≤<=105).
The next *n*<=-<=1 lines contain integers *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*) — the description of the edges of the tree.
It's guaranteed that the given graph is a tree. | Output one integer — the maximum number of edges that Mahmoud and Ehab can add to the tree while fulfilling the conditions. | [
"3\n1 2\n1 3\n",
"5\n1 2\n2 3\n3 4\n4 5\n"
] | [
"0\n",
"2\n"
] | Tree definition: [https://en.wikipedia.org/wiki/Tree_(graph_theory)](https://en.wikipedia.org/wiki/Tree_(graph_theory))
Bipartite graph definition: [https://en.wikipedia.org/wiki/Bipartite_graph](https://en.wikipedia.org/wiki/Bipartite_graph)
In the first test case the only edge that can be added in such a way, that ... | 1,000 | [
{
"input": "3\n1 2\n1 3",
"output": "0"
},
{
"input": "5\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10\n3 8\n6 2\n9 7\n10 1\n3 5\n1 3\n6 7\n5 4\n3 6",
"output": "16"
},
{
"input": "10\n7 6\n2 7\n4 1\n8 5\n9 4\n5 3\n8 7\n10 8\n10 4",
"output": "16"
},
{
"in... | 1,645,110,030 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 1,123 | 30,617,600 | import itertools
import math
import sys
import queue
import itertools
from heapq import heappop, heappush
import random
def solve():
def bfs(s, c):
color[s] = c
color_count[c] += 1
q = [s]
it = 0
while it != len(q):
k = q[it]
for u... | Title: Mahmoud and Ehab and the bipartiteness
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a gra... | ```python
import itertools
import math
import sys
import queue
import itertools
from heapq import heappop, heappush
import random
def solve():
def bfs(s, c):
color[s] = c
color_count[c] += 1
q = [s]
it = 0
while it != len(q):
k = q[it]
... | 3 | |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahed... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (withou... | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,694,420,084 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 295 | 16,076,800 | n = int(input())
m = []
c = 0
for i in range(n):
s = input()
m.append(s)
for o in range(n):
if m[o] == "Tetrahedron":
c += 4
if m[o] == "Cube":
c += 6
if m[o] == "Octahedron":
c += 8
if m[o] == "Dodecahedron":
c += 12
if m[o] == "Icosa... | Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahe... | ```python
n = int(input())
m = []
c = 0
for i in range(n):
s = input()
m.append(s)
for o in range(n):
if m[o] == "Tetrahedron":
c += 4
if m[o] == "Cube":
c += 6
if m[o] == "Octahedron":
c += 8
if m[o] == "Dodecahedron":
c += 12
if m[o]... | 3 | |
777 | B | Game of Credit Cards | PROGRAMMING | 1,300 | [
"data structures",
"dp",
"greedy",
"sortings"
] | null | null | After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards.
Rules of this game are simple: each player bring his favourite *n*-digit credit card. Then both players name the digits written on the... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of digits in the cards Sherlock and Moriarty are going to use.
The second line contains *n* digits — Sherlock's credit card number.
The third line contains *n* digits — Moriarty's credit card number. | First print the minimum possible number of flicks Moriarty will get. Then print the maximum possible number of flicks that Sherlock can get from Moriarty. | [
"3\n123\n321\n",
"2\n88\n00\n"
] | [
"0\n2\n",
"2\n0\n"
] | First sample is elaborated in the problem statement. In the second sample, there is no way Moriarty can avoid getting two flicks. | 1,000 | [
{
"input": "3\n123\n321",
"output": "0\n2"
},
{
"input": "2\n88\n00",
"output": "2\n0"
},
{
"input": "1\n4\n5",
"output": "0\n1"
},
{
"input": "1\n8\n7",
"output": "1\n0"
},
{
"input": "2\n55\n55",
"output": "0\n0"
},
{
"input": "3\n534\n432",
"out... | 1,613,042,972 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 93 | 0 | import math
import sys
n=int(input())
a=list(str(input()))
b=list(str(input()))
a.sort();b.sort()
min_res=0
for i in range(n):
min_res+= int(a[i]>b[i])
max_res=0
ap={1:a.count("1"),2:a.count("2"),3:a.count("3")}
bp={1:b.count("1"),2:b.count("2"),3:b.count("3")}
k=min(ap[2],bp[3])
max_res+=k
... | Title: Game of Credit Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards.
Rules of this game are simpl... | ```python
import math
import sys
n=int(input())
a=list(str(input()))
b=list(str(input()))
a.sort();b.sort()
min_res=0
for i in range(n):
min_res+= int(a[i]>b[i])
max_res=0
ap={1:a.count("1"),2:a.count("2"),3:a.count("3")}
bp={1:b.count("1"),2:b.count("2"),3:b.count("3")}
k=min(ap[2],bp[3])
ma... | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Greg has an array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n* and *m* operations. Each operation looks as: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). To apply operation *i* to the array means to increase all array elements with numbers *l**i*,<=*l**i*<=+<=1,<=...,<=*r**i* by value *d**i*.
Greg wrote down *k* qu... | The first line contains integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=105). The second line contains *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=105) — the initial array.
Next *m* lines contain operations, the operation number *i* is written as three integers: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=... | On a single line print *n* integers *a*1,<=*a*2,<=...,<=*a**n* — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier. | [
"3 3 3\n1 2 3\n1 2 1\n1 3 2\n2 3 4\n1 2\n1 3\n2 3\n",
"1 1 1\n1\n1 1 1\n1 1\n",
"4 3 6\n1 2 3 4\n1 2 1\n2 3 2\n3 4 4\n1 2\n1 3\n2 3\n1 2\n1 3\n2 3\n"
] | [
"9 18 17\n",
"2\n",
"5 18 31 20\n"
] | none | 0 | [
{
"input": "3 3 3\n1 2 3\n1 2 1\n1 3 2\n2 3 4\n1 2\n1 3\n2 3",
"output": "9 18 17"
},
{
"input": "1 1 1\n1\n1 1 1\n1 1",
"output": "2"
},
{
"input": "4 3 6\n1 2 3 4\n1 2 1\n2 3 2\n3 4 4\n1 2\n1 3\n2 3\n1 2\n1 3\n2 3",
"output": "5 18 31 20"
},
{
"input": "1 1 1\n0\n1 1 0\n1 1... | 1,662,535,259 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 31 | 1,309 | 27,648,000 | from math import *
from collections import *
from bisect import *
import heapq
import math
from itertools import permutations
def is_prime(n):
for i in range(2,math.ceil(math.sqrt(n))):
if(n%i==0):
return False
return True
def sieve(n):
arr=[True for _ in range(n+1)]
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg has an array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n* and *m* operations. Each operation looks as: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). To apply operation *i* to the array means to increase all array elements ... | ```python
from math import *
from collections import *
from bisect import *
import heapq
import math
from itertools import permutations
def is_prime(n):
for i in range(2,math.ceil(math.sqrt(n))):
if(n%i==0):
return False
return True
def sieve(n):
arr=[True for _ in rang... | 3 | |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,667,285,509 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 62 | 4,403,200 | p=lambda:list(map(int,input().split()))
n,t=p();a=p(); i=1
while i<t : i+=a[i-1]
print("YNEOS"[i>t::2]) | Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
p=lambda:list(map(int,input().split()))
n,t=p();a=p(); i=1
while i<t : i+=a[i-1]
print("YNEOS"[i>t::2])
``` | 3 | |
25 | B | Phone numbers | PROGRAMMING | 1,100 | [
"implementation"
] | B. Phone numbers | 2 | 256 | Phone number in Berland is a sequence of *n* digits. Often, to make it easier to memorize the number, it is divided into groups of two or three digits. For example, the phone number 1198733 is easier to remember as 11-987-33. Your task is to find for a given phone number any of its divisions into groups of two or three... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of digits in the phone number. The second line contains *n* digits — the phone number to divide into groups. | Output any of divisions of the given phone number into groups of two or three digits. Separate groups by single character -. If the answer is not unique, output any. | [
"6\n549871\n",
"7\n1198733\n"
] | [
"54-98-71",
"11-987-33\n"
] | none | 0 | [
{
"input": "6\n549871",
"output": "54-98-71"
},
{
"input": "7\n1198733",
"output": "119-87-33"
},
{
"input": "2\n74",
"output": "74"
},
{
"input": "2\n33",
"output": "33"
},
{
"input": "3\n074",
"output": "074"
},
{
"input": "3\n081",
"output": "08... | 1,645,632,314 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | n=int(input())
s=str(input())
l=""
i=0
if n%2==0 :
while n%2==0 and i<n:
l=l+s[i]+s[i+1]+"-"
i=i+2
else :
l=s[0:3]
i=3
while i<n:
l=l+"-"+s[i]+s[i+1]+"-"
i=i+2
print(l[:n+1])
| Title: Phone numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Phone number in Berland is a sequence of *n* digits. Often, to make it easier to memorize the number, it is divided into groups of two or three digits. For example, the phone number 1198733 is easier to remember as 11-987-33.... | ```python
n=int(input())
s=str(input())
l=""
i=0
if n%2==0 :
while n%2==0 and i<n:
l=l+s[i]+s[i+1]+"-"
i=i+2
else :
l=s[0:3]
i=3
while i<n:
l=l+"-"+s[i]+s[i+1]+"-"
i=i+2
print(l[:n+1])
``` | 0 |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,601,451,482 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 218 | 307,200 | def kmm(x):
km=[]
for _ in range(1,x+1):
if x%_==0:
km.append(_)
return km
def shared(a,b):
c=list(set(kmm(a))& set(kmm(b)))
return c[-1]
ins=input()
Y,W = [int(i) for i in ins.split(" ")]
if(Y >6 or W >6 or Y <=0 or W <=0):
print("0/1")
else:
the_max=max(Y,W)
o=7-the... | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
def kmm(x):
km=[]
for _ in range(1,x+1):
if x%_==0:
km.append(_)
return km
def shared(a,b):
c=list(set(kmm(a))& set(kmm(b)))
return c[-1]
ins=input()
Y,W = [int(i) for i in ins.split(" ")]
if(Y >6 or W >6 or Y <=0 or W <=0):
print("0/1")
else:
the_max=max(Y,W)
... | 3.888711 |
44 | A | Indian Summer | PROGRAMMING | 900 | [
"implementation"
] | A. Indian Summer | 2 | 256 | Indian summer is such a beautiful time of the year! A girl named Alyona is walking in the forest and picking a bouquet from fallen leaves. Alyona is very choosy — she doesn't take a leaf if it matches the color and the species of the tree of one of the leaves she already has. Find out how many leaves Alyona has picked. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of leaves Alyona has found. The next *n* lines contain the leaves' descriptions. Each leaf is characterized by the species of the tree it has fallen from and by the color. The species of the trees and colors are given in names, consisting of no mor... | Output the single number — the number of Alyona's leaves. | [
"5\nbirch yellow\nmaple red\nbirch yellow\nmaple yellow\nmaple green\n",
"3\noak yellow\noak yellow\noak yellow\n"
] | [
"4\n",
"1\n"
] | none | 0 | [
{
"input": "5\nbirch yellow\nmaple red\nbirch yellow\nmaple yellow\nmaple green",
"output": "4"
},
{
"input": "3\noak yellow\noak yellow\noak yellow",
"output": "1"
},
{
"input": "5\nxbnbkzn hp\nkaqkl vrgzbvqstu\nj aqidx\nhos gyul\nwefxmh tygpluae",
"output": "5"
},
{
"input"... | 1,654,429,927 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | n=int(input())
s=""
c=0
for i in range(n):
a,b=input().split(" ")
if b not in s:
s+=b
c+=1
print(c)
| Title: Indian Summer
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Indian summer is such a beautiful time of the year! A girl named Alyona is walking in the forest and picking a bouquet from fallen leaves. Alyona is very choosy — she doesn't take a leaf if it matches the color and the specie... | ```python
n=int(input())
s=""
c=0
for i in range(n):
a,b=input().split(" ")
if b not in s:
s+=b
c+=1
print(c)
``` | 0 |
598 | B | Queries on a String | PROGRAMMING | 1,300 | [
"implementation",
"strings"
] | null | null | You are given a string *s* and should process *m* queries. Each query is described by two 1-based indices *l**i*, *r**i* and integer *k**i*. It means that you should cyclically shift the substring *s*[*l**i*... *r**i*] *k**i* times. The queries should be processed one after another in the order they are given.
One ope... | The first line of the input contains the string *s* (1<=≤<=|*s*|<=≤<=10<=000) in its initial state, where |*s*| stands for the length of *s*. It contains only lowercase English letters.
Second line contains a single integer *m* (1<=≤<=*m*<=≤<=300) — the number of queries.
The *i*-th of the next *m* lines contains thr... | Print the resulting string *s* after processing all *m* queries. | [
"abacaba\n2\n3 6 1\n1 4 2\n"
] | [
"baabcaa\n"
] | The sample is described in problem statement. | 0 | [
{
"input": "abacaba\n2\n3 6 1\n1 4 2",
"output": "baabcaa"
},
{
"input": "u\n1\n1 1 1",
"output": "u"
},
{
"input": "p\n5\n1 1 5\n1 1 9\n1 1 10\n1 1 10\n1 1 4",
"output": "p"
},
{
"input": "ssssssssss\n5\n5 7 9\n3 9 3\n2 7 1\n7 7 10\n1 9 6",
"output": "ssssssssss"
},
... | 1,650,678,946 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 24 | 124 | 9,728,000 | from sys import stdin
input=lambda :stdin.readline()[:-1]
s=list(input())
m=int(input())
for _ in range(m):
l,r,k=map(int,input().split())
l,r=l-1,r-1
d=(r-l+1)
t=s[::]
for i in range(d):
t[l+(k+i)%d]=s[l+i]
s=t[::]
print(''.join(s)) | Title: Queries on a String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* and should process *m* queries. Each query is described by two 1-based indices *l**i*, *r**i* and integer *k**i*. It means that you should cyclically shift the substring *s*[*l**i*... *r**... | ```python
from sys import stdin
input=lambda :stdin.readline()[:-1]
s=list(input())
m=int(input())
for _ in range(m):
l,r,k=map(int,input().split())
l,r=l-1,r-1
d=(r-l+1)
t=s[::]
for i in range(d):
t[l+(k+i)%d]=s[l+i]
s=t[::]
print(''.join(s))
``` | 3 | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,694,008,355 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | # -*- coding: utf-8 -*-
"""
Created on Wed Sep 6 21:47:46 2023
@author: mac
"""
y = int(input())
while (True):
y += 1
if len({l for l in str(y)}) == len(str(y)):
break
print(y) | Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
# -*- coding: utf-8 -*-
"""
Created on Wed Sep 6 21:47:46 2023
@author: mac
"""
y = int(input())
while (True):
y += 1
if len({l for l in str(y)}) == len(str(y)):
break
print(y)
``` | 3 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,592,934,928 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 156 | 6,656,000 | s=input()
lc=0
uc=0
for i in s:
if i.islower():
lc+=1
else:
uc+=1
if lc==uc or lc<uc:
print(s.upper())
else:
print(s.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s=input()
lc=0
uc=0
for i in s:
if i.islower():
lc+=1
else:
uc+=1
if lc==uc or lc<uc:
print(s.upper())
else:
print(s.lower())
``` | 0 |
1,000 | B | Light It Up | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | Recently, you bought a brand new smart lamp with programming features. At first, you set up a schedule to the lamp. Every day it will turn power on at moment $0$ and turn power off at moment $M$. Moreover, the lamp allows you to set a program of switching its state (states are "lights on" and "lights off"). Unfortunate... | First line contains two space separated integers $n$ and $M$ ($1 \le n \le 10^5$, $2 \le M \le 10^9$) — the length of program $a$ and the moment when power turns off.
Second line contains $n$ space separated integers $a_1, a_2, \dots, a_n$ ($0 < a_1 < a_2 < \dots < a_n < M$) — initially installed progra... | Print the only integer — maximum possible total time when the lamp is lit. | [
"3 10\n4 6 7\n",
"2 12\n1 10\n",
"2 7\n3 4\n"
] | [
"8\n",
"9\n",
"6\n"
] | In the first example, one of possible optimal solutions is to insert value $x = 3$ before $a_1$, so program will be $[3, 4, 6, 7]$ and time of lamp being lit equals $(3 - 0) + (6 - 4) + (10 - 7) = 8$. Other possible solution is to insert $x = 5$ in appropriate place.
In the second example, there is only one optimal so... | 0 | [
{
"input": "3 10\n4 6 7",
"output": "8"
},
{
"input": "2 12\n1 10",
"output": "9"
},
{
"input": "2 7\n3 4",
"output": "6"
},
{
"input": "1 2\n1",
"output": "1"
},
{
"input": "5 10\n1 3 5 6 8",
"output": "6"
},
{
"input": "7 1000000000\n1 10001 10011 20... | 1,635,416,208 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 4,505,600 | n,m=map(int, input().split())
a=[int(i) for i in input('').split()]
t0,t1=m*((len(a)+1)%2)+sum(a[::2])-sum(a[1::2]),[]
for i in range(n):
new=a[i:]
on=m*(len(new)%2)+sum(new[1::2])-sum(new[::2])
print(new,on,2*on-m+a[i])
t1.append((2*on-m+a[i])*((-1)**i)-1)
print(t0+max(t1+[0])) | Title: Light It Up
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, you bought a brand new smart lamp with programming features. At first, you set up a schedule to the lamp. Every day it will turn power on at moment $0$ and turn power off at moment $M$. Moreover, the lamp allows y... | ```python
n,m=map(int, input().split())
a=[int(i) for i in input('').split()]
t0,t1=m*((len(a)+1)%2)+sum(a[::2])-sum(a[1::2]),[]
for i in range(n):
new=a[i:]
on=m*(len(new)%2)+sum(new[1::2])-sum(new[::2])
print(new,on,2*on-m+a[i])
t1.append((2*on-m+a[i])*((-1)**i)-1)
print(t0+max(t1+[0]))
``` | 0 | |
248 | A | Cupboards | PROGRAMMING | 800 | [
"implementation"
] | null | null | One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any longer, so he decided to get some food in the house.
Karlsson's gaze immediately fell on *n* woode... | The first input line contains a single integer *n* — the number of cupboards in the kitchen (2<=≤<=*n*<=≤<=104). Then follow *n* lines, each containing two integers *l**i* and *r**i* (0<=≤<=*l**i*,<=*r**i*<=≤<=1). Number *l**i* equals one, if the left door of the *i*-th cupboard is opened, otherwise number *l**i* equal... | In the only output line print a single integer *t* — the minimum number of seconds Karlsson needs to change the doors of all cupboards to the position he needs. | [
"5\n0 1\n1 0\n0 1\n1 1\n0 1\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "5\n0 1\n1 0\n0 1\n1 1\n0 1",
"output": "3"
},
{
"input": "2\n0 0\n0 0",
"output": "0"
},
{
"input": "3\n0 1\n1 1\n1 1",
"output": "1"
},
{
"input": "8\n0 1\n1 0\n0 1\n1 1\n0 1\n1 0\n0 1\n1 0",
"output": "7"
},
{
"input": "8\n1 0\n1 0\n1 0\n0 1\n0 1\n1 ... | 1,564,579,773 | 2,147,483,647 | Python 3 | OK | TESTS | 57 | 280 | 0 | n = int(input())
c,f = 0,0
for i in range(n):
l,r = map(int,input().split())
if l : c+=1
if r : f+=1
print(min(c,n-c)+min(f,n-f)) | Title: Cupboards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any long... | ```python
n = int(input())
c,f = 0,0
for i in range(n):
l,r = map(int,input().split())
if l : c+=1
if r : f+=1
print(min(c,n-c)+min(f,n-f))
``` | 3 | |
262 | A | Roma and Lucky Numbers | PROGRAMMING | 800 | [
"implementation"
] | null | null | Roma (a popular Russian name that means 'Roman') loves the Little Lvov Elephant's lucky numbers.
Let us remind you that lucky numbers are positive integers whose decimal representation only contains lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Roma's got *n* positive integer... | The first line contains two integers *n*, *k* (1<=≤<=*n*,<=*k*<=≤<=100). The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the numbers that Roma has.
The numbers in the lines are separated by single spaces. | In a single line print a single integer — the answer to the problem. | [
"3 4\n1 2 4\n",
"3 2\n447 44 77\n"
] | [
"3\n",
"2\n"
] | In the first sample all numbers contain at most four lucky digits, so the answer is 3.
In the second sample number 447 doesn't fit in, as it contains more than two lucky digits. All other numbers are fine, so the answer is 2. | 500 | [
{
"input": "3 4\n1 2 4",
"output": "3"
},
{
"input": "3 2\n447 44 77",
"output": "2"
},
{
"input": "2 2\n507978501 180480073",
"output": "2"
},
{
"input": "9 6\n655243746 167613748 1470546 57644035 176077477 56984809 44677 215706823 369042089",
"output": "9"
},
{
... | 1,592,237,030 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 374 | 307,200 | import math
from collections import defaultdict
ml=lambda:map(int,input().split())
ll=lambda:list(map(int,input().split()))
ii=lambda:int(input())
ip=lambda:list(input())
ips=lambda:input().split()
"""========main code==============="""
a,b=ml()
ans=0
l=list(input().split())
for i in l:
k=i
w=0
for i in k... | Title: Roma and Lucky Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Roma (a popular Russian name that means 'Roman') loves the Little Lvov Elephant's lucky numbers.
Let us remind you that lucky numbers are positive integers whose decimal representation only contains lucky digits... | ```python
import math
from collections import defaultdict
ml=lambda:map(int,input().split())
ll=lambda:list(map(int,input().split()))
ii=lambda:int(input())
ip=lambda:list(input())
ips=lambda:input().split()
"""========main code==============="""
a,b=ml()
ans=0
l=list(input().split())
for i in l:
k=i
w=0
... | 3 | |
556 | A | Case of the Zeros and Ones | PROGRAMMING | 900 | [
"greedy"
] | null | null | Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, an... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=2·105), the length of the string that Andreid has.
The second line contains the string of length *n* consisting only from zeros and ones. | Output the minimum length of the string that may remain after applying the described operations several times. | [
"4\n1100\n",
"5\n01010\n",
"8\n11101111\n"
] | [
"0\n",
"1\n",
"6\n"
] | In the first sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/10df55364c21c6e8d5da31b6ab6f6294c4fc26b3.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample test it is possible to change the string like... | 250 | [
{
"input": "4\n1100",
"output": "0"
},
{
"input": "5\n01010",
"output": "1"
},
{
"input": "8\n11101111",
"output": "6"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "2"
},
{
"input"... | 1,610,461,228 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 62 | 1,638,400 | n=input();a = list(input());print(abs(a.count('0') - a.count('1')))
| Title: Case of the Zeros and Ones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Cons... | ```python
n=input();a = list(input());print(abs(a.count('0') - a.count('1')))
``` | 3 | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,598,344,441 | 2,147,483,647 | PyPy 3 | OK | TESTS | 63 | 171 | 66,048,000 | # Author: S Mahesh Raju
# Username: maheshraju2020
# Date: 24/08/2020
from sys import stdin, stdout, setrecursionlimit
from math import gcd, ceil, sqrt
from collections import Counter, deque
from bisect import bisect_left, bisect_right
ii1 = lambda: int(stdin.readline().strip())
is1 = lambda: stdin.readline()... | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
# Author: S Mahesh Raju
# Username: maheshraju2020
# Date: 24/08/2020
from sys import stdin, stdout, setrecursionlimit
from math import gcd, ceil, sqrt
from collections import Counter, deque
from bisect import bisect_left, bisect_right
ii1 = lambda: int(stdin.readline().strip())
is1 = lambda: stdin.... | 3 | |
11 | E | Forward, march! | PROGRAMMING | 2,800 | [
"binary search",
"dp",
"greedy"
] | E. Forward, march! | 1 | 64 | Jack has become a soldier now. Unfortunately, he has trouble with the drill. Instead of marching beginning with the left foot and then changing legs with each step, as ordered, he keeps repeating a sequence of steps, in which he sometimes makes the wrong steps or — horror of horrors! — stops for a while. For example, i... | The first line of input contains a sequence consisting only of characters 'L', 'R' and 'X', where 'L' corresponds to a step with the left foot, 'R' — with the right foot, and 'X' — to a break. The length of the sequence will not exceed 106. | Output the maximum percentage of time that Jack can spend marching correctly, rounded down to exactly six digits after the decimal point. | [
"X\n",
"LXRR\n"
] | [
"0.000000\n",
"50.000000\n"
] | In the second example, if we add two breaks to receive LXXRXR, Jack will march: LXXRXRLXXRXRL... instead of LRLRLRLRLRLRL... and will make the correct step in half the cases. If we didn't add any breaks, the sequence would be incorrect — Jack can't step on his right foot twice in a row. | 0 | [
{
"input": "X",
"output": "0.000000"
},
{
"input": "LXRR",
"output": "50.000000"
},
{
"input": "LXRR",
"output": "50.000000"
},
{
"input": "LLXRXLXRLR",
"output": "50.000000"
},
{
"input": "RXRRXXXRXXRR",
"output": "37.500000"
},
{
"input": "LLLRLXRXLL... | 1,689,181,605 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | print("_RANDOM_GUESS_1689181604.823267")# 1689181604.823308 | Title: Forward, march!
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Jack has become a soldier now. Unfortunately, he has trouble with the drill. Instead of marching beginning with the left foot and then changing legs with each step, as ordered, he keeps repeating a sequence of steps, in whic... | ```python
print("_RANDOM_GUESS_1689181604.823267")# 1689181604.823308
``` | 0 |
1,006 | B | Polycarp's Practice | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"sortings"
] | null | null | Polycarp is practicing his problem solving skill. He has a list of $n$ problems with difficulties $a_1, a_2, \dots, a_n$, respectively. His plan is to practice for exactly $k$ days. Each day he has to solve at least one problem from his list. Polycarp solves the problems in the order they are given in his list, he cann... | The first line of the input contains two integers $n$ and $k$ ($1 \le k \le n \le 2000$) — the number of problems and the number of days, respectively.
The second line of the input contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 2000$) — difficulties of problems in Polycarp's list, in the order they are p... | In the first line of the output print the maximum possible total profit.
In the second line print exactly $k$ positive integers $t_1, t_2, \dots, t_k$ ($t_1 + t_2 + \dots + t_k$ must equal $n$), where $t_j$ means the number of problems Polycarp will solve during the $j$-th day in order to achieve the maximum possible ... | [
"8 3\n5 4 2 6 5 1 9 2\n",
"5 1\n1 1 1 1 1\n",
"4 2\n1 2000 2000 2\n"
] | [
"20\n3 2 3",
"1\n5\n",
"4000\n2 2\n"
] | The first example is described in the problem statement.
In the second example there is only one possible distribution.
In the third example the best answer is to distribute problems in the following way: $[1, 2000], [2000, 2]$. The total profit of this distribution is $2000 + 2000 = 4000$. | 0 | [
{
"input": "8 3\n5 4 2 6 5 1 9 2",
"output": "20\n4 1 3"
},
{
"input": "5 1\n1 1 1 1 1",
"output": "1\n5"
},
{
"input": "4 2\n1 2000 2000 2",
"output": "4000\n2 2"
},
{
"input": "1 1\n2000",
"output": "2000\n1"
},
{
"input": "1 1\n1234",
"output": "1234\n1"
... | 1,599,071,600 | 3,200 | Python 3 | WRONG_ANSWER | TESTS | 4 | 77 | 307,200 | n,m1=map(int,input().strip().split()[:2])
l=list(map(int,input().strip().split()[:n]))
m=[]
for x in range(m1):
m.append(max(l))
l[l.index(max(l))]= -1
print(sum(m))
if n%m1!=0:
z='{} '.format(m1)
print(n-((n//m1)*m1),z*(m1-1))
else:
if m1==1:
z='{} '.format(n)
print(z*(m1))
else:
z='{} '.f... | Title: Polycarp's Practice
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is practicing his problem solving skill. He has a list of $n$ problems with difficulties $a_1, a_2, \dots, a_n$, respectively. His plan is to practice for exactly $k$ days. Each day he has to solve at least... | ```python
n,m1=map(int,input().strip().split()[:2])
l=list(map(int,input().strip().split()[:n]))
m=[]
for x in range(m1):
m.append(max(l))
l[l.index(max(l))]= -1
print(sum(m))
if n%m1!=0:
z='{} '.format(m1)
print(n-((n//m1)*m1),z*(m1-1))
else:
if m1==1:
z='{} '.format(n)
print(z*(m1))
else:
... | 0 | |
441 | A | Valera and Antique Items | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the *j*-th object of the *i*-th seller is *s**ij*. Valera gets on well with each of the *n* sellers. He is perfec... | The first line contains two space-separated integers *n*,<=*v* (1<=≤<=*n*<=≤<=50; 104<=≤<=*v*<=≤<=106) — the number of sellers and the units of money the Valera has.
Then *n* lines follow. The *i*-th line first contains integer *k**i* (1<=≤<=*k**i*<=≤<=50) the number of items of the *i*-th seller. Then go *k**i* space... | In the first line, print integer *p* — the number of sellers with who Valera can make a deal.
In the second line print *p* space-separated integers *q*1,<=*q*2,<=...,<=*q**p* (1<=≤<=*q**i*<=≤<=*n*) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order. | [
"3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000\n",
"3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000\n"
] | [
"3\n1 2 3\n",
"0\n\n"
] | In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.
In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the... | 500 | [
{
"input": "3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000",
"output": "3\n1 2 3"
},
{
"input": "3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000",
"output": "0"
},
{
"input": "2 100001\n1 895737\n1 541571",
"output": "0"
},
{
"input": "1 1000000\n1 100... | 1,562,858,747 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 0 | n, v = map(int, input().split())
s = 0
l = []
for i in range(n):
temp = list(map(int, input().split()))
if temp[1]<v:
s+=1
l.append(i+1)
print(s)
print(' '.join(l)) | Title: Valera and Antique Items
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the... | ```python
n, v = map(int, input().split())
s = 0
l = []
for i in range(n):
temp = list(map(int, input().split()))
if temp[1]<v:
s+=1
l.append(i+1)
print(s)
print(' '.join(l))
``` | -1 | |
348 | A | Mafia | PROGRAMMING | 1,600 | [
"binary search",
"math",
"sortings"
] | null | null | One day *n* friends gathered together to play "Mafia". During each round of the game some player must be the supervisor and other *n*<=-<=1 people take part in the game. For each person we know in how many rounds he wants to be a player, not the supervisor: the *i*-th person wants to play *a**i* rounds. What is the min... | The first line contains integer *n* (3<=≤<=*n*<=≤<=105). The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the *i*-th number in the list is the number of rounds the *i*-th person wants to play. | In a single line print a single integer — the minimum number of game rounds the friends need to let the *i*-th person play at least *a**i* rounds.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"3\n3 2 2\n",
"4\n2 2 2 2\n"
] | [
"4\n",
"3\n"
] | You don't need to know the rules of "Mafia" to solve this problem. If you're curious, it's a game Russia got from the Soviet times: http://en.wikipedia.org/wiki/Mafia_(party_game). | 500 | [
{
"input": "3\n3 2 2",
"output": "4"
},
{
"input": "4\n2 2 2 2",
"output": "3"
},
{
"input": "7\n9 7 7 8 8 7 8",
"output": "9"
},
{
"input": "10\n13 12 10 13 13 14 10 10 12 12",
"output": "14"
},
{
"input": "10\n94 96 91 95 99 94 96 92 95 99",
"output": "106"
... | 1,590,238,714 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 466 | 10,956,800 | n=int(input())
from math import ceil
l=list(map(int,input().split()))
print(max(max(l),ceil((sum(l))/(n-1))))
| Title: Mafia
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day *n* friends gathered together to play "Mafia". During each round of the game some player must be the supervisor and other *n*<=-<=1 people take part in the game. For each person we know in how many rounds he wants to be a... | ```python
n=int(input())
from math import ceil
l=list(map(int,input().split()))
print(max(max(l),ceil((sum(l))/(n-1))))
``` | 3 | |
675 | A | Infinite Sequence | PROGRAMMING | 1,100 | [
"math"
] | null | null | Vasya likes everything infinite. Now he is studying the properties of a sequence *s*, such that its first element is equal to *a* (*s*1<==<=*a*), and the difference between any two neighbouring elements is equal to *c* (*s**i*<=-<=*s**i*<=-<=1<==<=*c*). In particular, Vasya wonders if his favourite integer *b* appears ... | The first line of the input contain three integers *a*, *b* and *c* (<=-<=109<=≤<=*a*,<=*b*,<=*c*<=≤<=109) — the first element of the sequence, Vasya's favorite number and the difference between any two neighbouring elements of the sequence, respectively. | If *b* appears in the sequence *s* print "YES" (without quotes), otherwise print "NO" (without quotes). | [
"1 7 3\n",
"10 10 0\n",
"1 -4 5\n",
"0 60 50\n"
] | [
"YES\n",
"YES\n",
"NO\n",
"NO\n"
] | In the first sample, the sequence starts from integers 1, 4, 7, so 7 is its element.
In the second sample, the favorite integer of Vasya is equal to the first element of the sequence.
In the third sample all elements of the sequence are greater than Vasya's favorite integer.
In the fourth sample, the sequence starts... | 500 | [
{
"input": "1 7 3",
"output": "YES"
},
{
"input": "10 10 0",
"output": "YES"
},
{
"input": "1 -4 5",
"output": "NO"
},
{
"input": "0 60 50",
"output": "NO"
},
{
"input": "1 -4 -5",
"output": "YES"
},
{
"input": "0 1 0",
"output": "NO"
},
{
... | 1,476,079,328 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 62 | 4,608,000 | # print ("Input a, b, and c")
a,b,c = (int(x) for x in input().split())
if c == 0:
if a == b:
print("YES")
else:
print("NO")
elif c > 0:
if b <= a:
print("NO")
elif (b-a)%c != 0:
print("NO")
else:
print("YES")
else: # c is negative
if b >= a:
prin... | Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya likes everything infinite. Now he is studying the properties of a sequence *s*, such that its first element is equal to *a* (*s*1<==<=*a*), and the difference between any two neighbouring elements is equal to *c... | ```python
# print ("Input a, b, and c")
a,b,c = (int(x) for x in input().split())
if c == 0:
if a == b:
print("YES")
else:
print("NO")
elif c > 0:
if b <= a:
print("NO")
elif (b-a)%c != 0:
print("NO")
else:
print("YES")
else: # c is negative
if b >= a:
... | 0 | |
390 | A | Inna and Alarm Clock | PROGRAMMING | 0 | [
"implementation"
] | null | null | Inna loves sleeping very much, so she needs *n* alarm clocks in total to wake up. Let's suppose that Inna's room is a 100<=×<=100 square with the lower left corner at point (0,<=0) and with the upper right corner at point (100,<=100). Then the alarm clocks are points with integer coordinates in this square.
The mornin... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of the alarm clocks. The next *n* lines describe the clocks: the *i*-th line contains two integers *x**i*, *y**i* — the coordinates of the *i*-th alarm clock (0<=≤<=*x**i*,<=*y**i*<=≤<=100).
Note that a single point in the room can conta... | In a single line print a single integer — the minimum number of segments Inna will have to draw if she acts optimally. | [
"4\n0 0\n0 1\n0 2\n1 0\n",
"4\n0 0\n0 1\n1 0\n1 1\n",
"4\n1 1\n1 2\n2 3\n3 3\n"
] | [
"2\n",
"2\n",
"3\n"
] | In the first sample, Inna first chooses type "vertical segments", and then she makes segments with ends at : (0, 0), (0, 2); and, for example, (1, 0), (1, 1). If she paints horizontal segments, she will need at least 3 segments.
In the third sample it is important to note that Inna doesn't have the right to change the... | 500 | [
{
"input": "4\n0 0\n0 1\n0 2\n1 0",
"output": "2"
},
{
"input": "4\n0 0\n0 1\n1 0\n1 1",
"output": "2"
},
{
"input": "4\n1 1\n1 2\n2 3\n3 3",
"output": "3"
},
{
"input": "1\n0 0",
"output": "1"
},
{
"input": "42\n28 87\n26 16\n59 90\n47 61\n28 83\n36 30\n67 10\n6 ... | 1,568,396,289 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 311 | 204,800 | n=int(input())
s1=set()
s2=set()
for i in range(n):
a,b=map(int,input().split())
s1.add(a)
s2.add(b)
s=min(len(s1),len(s2))
print(s) | Title: Inna and Alarm Clock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Inna loves sleeping very much, so she needs *n* alarm clocks in total to wake up. Let's suppose that Inna's room is a 100<=×<=100 square with the lower left corner at point (0,<=0) and with the upper right corner a... | ```python
n=int(input())
s1=set()
s2=set()
for i in range(n):
a,b=map(int,input().split())
s1.add(a)
s2.add(b)
s=min(len(s1),len(s2))
print(s)
``` | 3 | |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,680,100,595 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 46 | 0 | n=int(input())
aa=n
summ=0
while (n != 1):
summ += n//2
n //= 2
print(aa-summ)
| Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
n=int(input())
aa=n
summ=0
while (n != 1):
summ += n//2
n //= 2
print(aa-summ)
``` | 3 | |
980 | A | Links and Pearls | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one.
You can remove a link or a pearl and insert it between two other existing links or pearls (or between a link and a pearl) on the necklace. This process can be repeated as many times as you l... | The only line of input contains a string $s$ ($3 \leq |s| \leq 100$), representing the necklace, where a dash '-' represents a link and the lowercase English letter 'o' represents a pearl. | Print "YES" if the links and pearls can be rejoined such that the number of links between adjacent pearls is equal. Otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"-o-o--",
"-o---\n",
"-o---o-\n",
"ooo\n"
] | [
"YES",
"YES",
"NO",
"YES\n"
] | none | 500 | [
{
"input": "-o-o--",
"output": "YES"
},
{
"input": "-o---",
"output": "YES"
},
{
"input": "-o---o-",
"output": "NO"
},
{
"input": "ooo",
"output": "YES"
},
{
"input": "---",
"output": "YES"
},
{
"input": "--o-o-----o----o--oo-o-----ooo-oo---o--",
"... | 1,525,792,848 | 948 | PyPy 3 | OK | TESTS | 69 | 171 | 21,708,800 | import sys
from collections import Counter
s = next(sys.stdin).rstrip()
counter = Counter(s)
num_pearls = counter['o']
num_links = counter['-']
if num_pearls == 0 or (num_links % num_pearls == 0):
print("YES")
else:
print("NO")
| Title: Links and Pearls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one.
You can remove a link or a pearl and insert it between two other existing links or pearl... | ```python
import sys
from collections import Counter
s = next(sys.stdin).rstrip()
counter = Counter(s)
num_pearls = counter['o']
num_links = counter['-']
if num_pearls == 0 or (num_links % num_pearls == 0):
print("YES")
else:
print("NO")
``` | 3 | |
358 | A | Dima and Continuous Line | PROGRAMMING | 1,400 | [
"brute force",
"implementation"
] | null | null | Dima and Seryozha live in an ordinary dormitory room for two. One day Dima had a date with his girl and he asked Seryozha to leave the room. As a compensation, Seryozha made Dima do his homework.
The teacher gave Seryozha the coordinates of *n* distinct points on the abscissa axis and asked to consecutively connect th... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=103). The second line contains *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=106<=≤<=*x**i*<=≤<=106) — the *i*-th point has coordinates (*x**i*,<=0). The points are not necessarily sorted by their *x* coordinate. | In the single line print "yes" (without the quotes), if the line has self-intersections. Otherwise, print "no" (without the quotes). | [
"4\n0 10 5 15\n",
"4\n0 15 5 10\n"
] | [
"yes\n",
"no\n"
] | The first test from the statement is on the picture to the left, the second test is on the picture to the right. | 500 | [
{
"input": "4\n0 10 5 15",
"output": "yes"
},
{
"input": "4\n0 15 5 10",
"output": "no"
},
{
"input": "5\n0 1000 2000 3000 1500",
"output": "yes"
},
{
"input": "5\n-724093 710736 -383722 -359011 439613",
"output": "no"
},
{
"input": "50\n384672 661179 -775591 -989... | 1,588,001,922 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 307,200 | n=int(input())
x = list(map(int, input().split()))
c=0
d=0
if(n<=3):
d+=1
else:
for i in range(n-3):
if(x[i]<x[i+2]<x[i+1]<x[i+3] or x[i+2]<x[i]<x[i+3]<x[i+1]):
c+=1
else:
d+=1
if(c>0):
print("yes")
else:
print("no")
| Title: Dima and Continuous Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and Seryozha live in an ordinary dormitory room for two. One day Dima had a date with his girl and he asked Seryozha to leave the room. As a compensation, Seryozha made Dima do his homework.
The teacher g... | ```python
n=int(input())
x = list(map(int, input().split()))
c=0
d=0
if(n<=3):
d+=1
else:
for i in range(n-3):
if(x[i]<x[i+2]<x[i+1]<x[i+3] or x[i+2]<x[i]<x[i+3]<x[i+1]):
c+=1
else:
d+=1
if(c>0):
print("yes")
else:
print("no")
... | 0 | |
469 | A | I Wanna Be the Guy | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | There is a game called "I Wanna Be the Guy", consisting of *n* levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass the whole game.
Little X can pass only *p* levels of the game. And Little Y can pass only *q* levels of the game. You are given the indices of levels Little X can... | The first line contains a single integer *n* (1<=≤<=<=*n*<=≤<=100).
The next line contains an integer *p* (0<=≤<=*p*<=≤<=*n*) at first, then follows *p* distinct integers *a*1,<=*a*2,<=...,<=*a**p* (1<=≤<=*a**i*<=≤<=*n*). These integers denote the indices of levels Little X can pass. The next line contains the levels... | If they can pass all the levels, print "I become the guy.". If it's impossible, print "Oh, my keyboard!" (without the quotes). | [
"4\n3 1 2 3\n2 2 4\n",
"4\n3 1 2 3\n2 2 3\n"
] | [
"I become the guy.\n",
"Oh, my keyboard!\n"
] | In the first sample, Little X can pass levels [1 2 3], and Little Y can pass level [2 4], so they can pass all the levels both.
In the second sample, no one can pass level 4. | 500 | [
{
"input": "4\n3 1 2 3\n2 2 4",
"output": "I become the guy."
},
{
"input": "4\n3 1 2 3\n2 2 3",
"output": "Oh, my keyboard!"
},
{
"input": "10\n5 8 6 1 5 4\n6 1 3 2 9 4 6",
"output": "Oh, my keyboard!"
},
{
"input": "10\n8 8 10 7 3 1 4 2 6\n8 9 5 10 3 7 2 4 8",
"output":... | 1,694,208,019 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | n = int(input())
x = list(map(int,input().split()))
y = list(map(int,input().split()))
s = ''
for i in x,y :
if x == n:
s = 'I become the guy.'
elif y == n:
s = 'I become the guy.'
else:
s = "Oh, my keyboard!"
print(s) | Title: I Wanna Be the Guy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a game called "I Wanna Be the Guy", consisting of *n* levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass the whole game.
Little X can pass only *p* levels of the g... | ```python
n = int(input())
x = list(map(int,input().split()))
y = list(map(int,input().split()))
s = ''
for i in x,y :
if x == n:
s = 'I become the guy.'
elif y == n:
s = 'I become the guy.'
else:
s = "Oh, my keyboard!"
print(s)
``` | 0 | |
810 | A | Straight <<A>> | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
In school, where Noora is studying, teachers are putting down marks to the online class register, wh... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*k*<=≤<=100) denoting the number of marks, received by Noora and the value of highest possible mark.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*k*) denoting marks received by Noora before Leha's hack. | Print a single integer — minimal number of additional marks, that Leha has to add in order to change Noora's final mark to *k*. | [
"2 10\n8 9\n",
"3 5\n4 4 4\n"
] | [
"4",
"3"
] | Consider the first example testcase.
Maximal mark is 10, Noora received two marks — 8 and 9, so current final mark is 9. To fix it, Leha can add marks [10, 10, 10, 10] (4 marks in total) to the registry, achieving Noora having average mark equal to <img align="middle" class="tex-formula" src="https://espresso.codeforc... | 500 | [
{
"input": "2 10\n8 9",
"output": "4"
},
{
"input": "3 5\n4 4 4",
"output": "3"
},
{
"input": "3 10\n10 8 9",
"output": "3"
},
{
"input": "2 23\n21 23",
"output": "2"
},
{
"input": "5 10\n5 10 10 9 10",
"output": "7"
},
{
"input": "12 50\n18 10 26 22 2... | 1,598,542,081 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 11 | 140 | 0 | import sys
reader = (line.rstrip() for line in sys.stdin)
input = reader.__next__
n, k = map(int, input().split())
tot = sum([x for x in map(int, input().split())])
_k = k - 0.5
x = (_k * n - tot) / (k - _k)
print(int(x)) | Title: Straight <<A>>
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
... | ```python
import sys
reader = (line.rstrip() for line in sys.stdin)
input = reader.__next__
n, k = map(int, input().split())
tot = sum([x for x in map(int, input().split())])
_k = k - 0.5
x = (_k * n - tot) / (k - _k)
print(int(x))
``` | 0 | |
567 | B | Berland National Library | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Berland National Library has recently been built in the capital of Berland. In addition, in the library you can take any of the collected works of Berland leaders, the library has a reading room.
Today was the pilot launch of an automated reading room visitors' accounting system! The scanner of the system is installed... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of records in the system log. Next follow *n* events from the system journal in the order in which the were made. Each event was written on a single line and looks as "+ *r**i*" or "- *r**i*", where *r**i* is an integer from 1 to 106, the r... | Print a single integer — the minimum possible capacity of the reading room. | [
"6\n+ 12001\n- 12001\n- 1\n- 1200\n+ 1\n+ 7\n",
"2\n- 1\n- 2\n",
"2\n+ 1\n- 1\n"
] | [
"3",
"2",
"1"
] | In the first sample test, the system log will ensure that at some point in the reading room were visitors with registration numbers 1, 1200 and 12001. More people were not in the room at the same time based on the log. Therefore, the answer to the test is 3. | 1,000 | [
{
"input": "6\n+ 12001\n- 12001\n- 1\n- 1200\n+ 1\n+ 7",
"output": "3"
},
{
"input": "2\n- 1\n- 2",
"output": "2"
},
{
"input": "2\n+ 1\n- 1",
"output": "1"
},
{
"input": "5\n+ 1\n- 1\n+ 2\n+ 3\n- 4",
"output": "3"
},
{
"input": "3\n- 1\n- 2\n- 3",
"output": "... | 1,667,942,031 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | def countVisitors():
B = []
times = int(input())
for i in range(times):
n = input()
n2 = int(n[2:])
if n[0] == "-":
if (n2) in B:
B.remove(n2)
else:
B.append(n2)
else:
B.append(n2)
count = len(B)
retu... | Title: Berland National Library
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland National Library has recently been built in the capital of Berland. In addition, in the library you can take any of the collected works of Berland leaders, the library has a reading room.
Today was the... | ```python
def countVisitors():
B = []
times = int(input())
for i in range(times):
n = input()
n2 = int(n[2:])
if n[0] == "-":
if (n2) in B:
B.remove(n2)
else:
B.append(n2)
else:
B.append(n2)
count = len(B... | 0 | |
158 | A | Next Round | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | "Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of *n* participants took part in the contest (*n*<=≥<=*k*), and you already know their scores. Calculate... | The first line of the input contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50) separated by a single space.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100), where *a**i* is the score earned by the participant who got the *i*-th place. The given sequence... | Output the number of participants who advance to the next round. | [
"8 5\n10 9 8 7 7 7 5 5\n",
"4 2\n0 0 0 0\n"
] | [
"6\n",
"0\n"
] | In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.
In the second example nobody got a positive score. | 500 | [
{
"input": "8 5\n10 9 8 7 7 7 5 5",
"output": "6"
},
{
"input": "4 2\n0 0 0 0",
"output": "0"
},
{
"input": "5 1\n1 1 1 1 1",
"output": "5"
},
{
"input": "5 5\n1 1 1 1 1",
"output": "5"
},
{
"input": "1 1\n10",
"output": "1"
},
{
"input": "17 14\n16 15... | 1,696,586,392 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 62 | 0 | n, k=map(int,input().split())
lst = list(map(int, input().split(' ')))
lst1 = lst[k-1]
count = 0
for i in lst:
if i >= lst1 and (i>0 and lst1>0):
count += 1
print(count)
| Title: Next Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of *n* p... | ```python
n, k=map(int,input().split())
lst = list(map(int, input().split(' ')))
lst1 = lst[k-1]
count = 0
for i in lst:
if i >= lst1 and (i>0 and lst1>0):
count += 1
print(count)
``` | 0 | |
909 | C | Python Indentation | PROGRAMMING | 1,800 | [
"dp"
] | null | null | In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python with only two types of statements.
Simple statements are written in a single line, one per line. An ex... | The first line contains a single integer *N* (1<=≤<=*N*<=≤<=5000) — the number of commands in the program. *N* lines of the program follow, each line describing a single command. Each command is either "f" (denoting "for statement") or "s" ("simple statement"). It is guaranteed that the last line is a simple statement. | Output one line containing an integer - the number of ways the given sequence of statements can be indented modulo 109<=+<=7. | [
"4\ns\nf\nf\ns\n",
"4\nf\ns\nf\ns\n"
] | [
"1\n",
"2\n"
] | In the first test case, there is only one way to indent the program: the second for statement must be part of the body of the first one.
In the second test case, there are two ways to indent the program: the second for statement can either be part of the first one's body or a separate statement following the first one... | 1,500 | [
{
"input": "4\ns\nf\nf\ns",
"output": "1"
},
{
"input": "4\nf\ns\nf\ns",
"output": "2"
},
{
"input": "156\nf\ns\nf\ns\nf\ns\ns\ns\ns\nf\ns\ns\nf\nf\ns\nf\nf\nf\nf\ns\ns\ns\nf\ns\ns\nf\nf\nf\nf\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\nf\nf\nf\ns\ns\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\ns... | 1,555,043,546 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 102,809,600 | commands = int(input())
memo = [[0] * commands for i in range(commands)]
memo[0][0] = 1
mod = 7 + 10 ** 9
for x in range(1, commands):
if input() == 's':
ways = 0
for y in range (commands - 1, -1, -1):
ways += memo[x - 1][y]
ways %= mod
memo[x][y] = ways
else... | Title: Python Indentation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python... | ```python
commands = int(input())
memo = [[0] * commands for i in range(commands)]
memo[0][0] = 1
mod = 7 + 10 ** 9
for x in range(1, commands):
if input() == 's':
ways = 0
for y in range (commands - 1, -1, -1):
ways += memo[x - 1][y]
ways %= mod
memo[x][y] = way... | 0 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,692,037,702 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 124 | 0 |
def prime_factors(n):
factors = []
while n % 2 == 0:
factors.append(2)
n //= 2
for i in range(3, int(math.sqrt(n)) + 1, 2):
while n % i == 0:
factors.append(i)
n //= i
if n > 2:
factors.append(n)
return factors
def c... | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
def prime_factors(n):
factors = []
while n % 2 == 0:
factors.append(2)
n //= 2
for i in range(3, int(math.sqrt(n)) + 1, 2):
while n % i == 0:
factors.append(i)
n //= i
if n > 2:
factors.append(n)
return factors
... | 3.969 |
514 | A | Chewbaсca and Number | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform the initial number *x* to the minimum possible positive number by inverting some (possibly, zero) digits.... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=1018) — the number that Luke Skywalker gave to Chewbacca. | Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes. | [
"27\n",
"4545\n"
] | [
"22\n",
"4444\n"
] | none | 500 | [
{
"input": "27",
"output": "22"
},
{
"input": "4545",
"output": "4444"
},
{
"input": "1",
"output": "1"
},
{
"input": "9",
"output": "9"
},
{
"input": "8772",
"output": "1222"
},
{
"input": "81",
"output": "11"
},
{
"input": "71723447",
... | 1,685,093,854 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | x = input()
arr = []
for val in x:
n = int(val)
if n >= 5:
arr.append(9-n)
else:
arr.append(n)
s = ''
for val in arr:
s += str(val)
print(s) | Title: Chewbaсca and Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform... | ```python
x = input()
arr = []
for val in x:
n = int(val)
if n >= 5:
arr.append(9-n)
else:
arr.append(n)
s = ''
for val in arr:
s += str(val)
print(s)
``` | 0 | |
334 | B | Eight Point Sets | PROGRAMMING | 1,400 | [
"sortings"
] | null | null | Gerald is very particular to eight point sets. He thinks that any decent eight point set must consist of all pairwise intersections of three distinct integer vertical straight lines and three distinct integer horizontal straight lines, except for the average of these nine points. In other words, there must be three int... | The input consists of eight lines, the *i*-th line contains two space-separated integers *x**i* and *y**i* (0<=≤<=*x**i*,<=*y**i*<=≤<=106). You do not have any other conditions for these points. | In a single line print word "respectable", if the given set of points corresponds to Gerald's decency rules, and "ugly" otherwise. | [
"0 0\n0 1\n0 2\n1 0\n1 2\n2 0\n2 1\n2 2\n",
"0 0\n1 0\n2 0\n3 0\n4 0\n5 0\n6 0\n7 0\n",
"1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2\n"
] | [
"respectable\n",
"ugly\n",
"ugly\n"
] | none | 1,000 | [
{
"input": "0 0\n0 1\n0 2\n1 0\n1 2\n2 0\n2 1\n2 2",
"output": "respectable"
},
{
"input": "0 0\n1 0\n2 0\n3 0\n4 0\n5 0\n6 0\n7 0",
"output": "ugly"
},
{
"input": "1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2",
"output": "ugly"
},
{
"input": "0 0\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0... | 1,464,325,182 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 124 | 4,608,000 | x = [0] * 8
y = [0] * 8
z = []
for i in range(8):
x[i], y[i] = map(int, input().split() )
if (x[i], y[i]) not in z:
z.append( (x[i], y[i]) )
sx = set(x)
sy = set(y)
if len(sx) !=3 or len(sy) != 3 or z != 8:
print('ugly')
else:
xx = sorted( list(sx) )
yy = sorted( list(sy) )
... | Title: Eight Point Sets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald is very particular to eight point sets. He thinks that any decent eight point set must consist of all pairwise intersections of three distinct integer vertical straight lines and three distinct integer horizonta... | ```python
x = [0] * 8
y = [0] * 8
z = []
for i in range(8):
x[i], y[i] = map(int, input().split() )
if (x[i], y[i]) not in z:
z.append( (x[i], y[i]) )
sx = set(x)
sy = set(y)
if len(sx) !=3 or len(sy) != 3 or z != 8:
print('ugly')
else:
xx = sorted( list(sx) )
yy = sorted( l... | 0 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,696,837,414 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | random_integer = int(input())
for i in range(random_integer) :
string = str(input())
length_string = len(string)
#print(length_string)
length = length_string - 2
first_letter = string[0]
last_letter = string[-1]
#print(last_letter)
if length_string > 10 :
print("{}{}{}" . format(first_letter , len... | Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
random_integer = int(input())
for i in range(random_integer) :
string = str(input())
length_string = len(string)
#print(length_string)
length = length_string - 2
first_letter = string[0]
last_letter = string[-1]
#print(last_letter)
if length_string > 10 :
print("{}{}{}" . format(first_le... | 0 |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,688,401,516 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | def abbreviation(array):
for index in range(len(array)):
string = array[index]
if len(string) > 10:
string = list(string)
digit = len(string) - 2
print(string[0] + str(digit) + string[-1])
else:
print(string)
wordsNum = int(input("... | Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
def abbreviation(array):
for index in range(len(array)):
string = array[index]
if len(string) > 10:
string = list(string)
digit = len(string) - 2
print(string[0] + str(digit) + string[-1])
else:
print(string)
wordsNum = i... | 0 |
994 | A | Fingerprints | PROGRAMMING | 800 | [
"implementation"
] | null | null | You are locked in a room with a door that has a keypad with 10 keys corresponding to digits from 0 to 9. To escape from the room, you need to enter a correct code. You also have a sequence of digits.
Some keys on the keypad have fingerprints. You believe the correct code is the longest not necessarily contiguous subse... | The first line contains two integers $n$ and $m$ ($1 \le n, m \le 10$) representing the number of digits in the sequence you have and the number of keys on the keypad that have fingerprints.
The next line contains $n$ distinct space-separated integers $x_1, x_2, \ldots, x_n$ ($0 \le x_i \le 9$) representing the sequen... | In a single line print a space-separated sequence of integers representing the code. If the resulting sequence is empty, both printing nothing and printing a single line break is acceptable. | [
"7 3\n3 5 7 1 6 2 8\n1 2 7\n",
"4 4\n3 4 1 0\n0 1 7 9\n"
] | [
"7 1 2\n",
"1 0\n"
] | In the first example, the only digits with fingerprints are $1$, $2$ and $7$. All three of them appear in the sequence you know, $7$ first, then $1$ and then $2$. Therefore the output is 7 1 2. Note that the order is important, and shall be the same as the order in the original sequence.
In the second example digits $... | 500 | [
{
"input": "7 3\n3 5 7 1 6 2 8\n1 2 7",
"output": "7 1 2"
},
{
"input": "4 4\n3 4 1 0\n0 1 7 9",
"output": "1 0"
},
{
"input": "9 4\n9 8 7 6 5 4 3 2 1\n2 4 6 8",
"output": "8 6 4 2"
},
{
"input": "10 5\n3 7 1 2 4 6 9 0 5 8\n4 3 0 7 9",
"output": "3 7 4 9 0"
},
{
"... | 1,587,376,799 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | n, m = map(int, input().split())
seq = [int(num) for num in input().split()]
fp = [int(num) for num in input().split()]
code = []
for i in seq :
for k in fp :
if i == k :
code.append(i)
print(code) | Title: Fingerprints
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are locked in a room with a door that has a keypad with 10 keys corresponding to digits from 0 to 9. To escape from the room, you need to enter a correct code. You also have a sequence of digits.
Some keys on the keyp... | ```python
n, m = map(int, input().split())
seq = [int(num) for num in input().split()]
fp = [int(num) for num in input().split()]
code = []
for i in seq :
for k in fp :
if i == k :
code.append(i)
print(code)
``` | 0 | |
706 | B | Interesting drink | PROGRAMMING | 1,100 | [
"binary search",
"dp",
"implementation"
] | null | null | Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single i... | Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day. | [
"5\n3 10 8 6 11\n4\n1\n10\n3\n11\n"
] | [
"0\n4\n1\n5\n"
] | On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | 1,000 | [
{
"input": "5\n3 10 8 6 11\n4\n1\n10\n3\n11",
"output": "0\n4\n1\n5"
},
{
"input": "5\n868 987 714 168 123\n10\n424\n192\n795\n873\n117\n914\n735\n158\n631\n471",
"output": "2\n2\n3\n4\n0\n4\n3\n1\n2\n2"
},
{
"input": "3\n435 482 309\n7\n245\n241\n909\n745\n980\n29\n521",
"output": "... | 1,697,181,776 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | n = int(input())
arr = list(map(int, input().split()))
arr.sort()
q = int(input())
for _ in range(q):
target = int(input()) # Move this line inside the loop to get input for each query
left, right = 0, len(arr) - 1
lower_bound_index = 0
while left <= right:
mid = left + (right ... | Title: Interesting drink
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known tha... | ```python
n = int(input())
arr = list(map(int, input().split()))
arr.sort()
q = int(input())
for _ in range(q):
target = int(input()) # Move this line inside the loop to get input for each query
left, right = 0, len(arr) - 1
lower_bound_index = 0
while left <= right:
mid = left... | 0 | |
464 | A | No to Palindromes! | PROGRAMMING | 1,700 | [
"greedy",
"strings"
] | null | null | Paul hates palindromes. He assumes that string *s* is tolerable if each its character is one of the first *p* letters of the English alphabet and *s* doesn't contain any palindrome contiguous substring of length 2 or more.
Paul has found a tolerable string *s* of length *n*. Help him find the lexicographically next to... | The first line contains two space-separated integers: *n* and *p* (1<=≤<=*n*<=≤<=1000; 1<=≤<=*p*<=≤<=26). The second line contains string *s*, consisting of *n* small English letters. It is guaranteed that the string is tolerable (according to the above definition). | If the lexicographically next tolerable string of the same length exists, print it. Otherwise, print "NO" (without the quotes). | [
"3 3\ncba\n",
"3 4\ncba\n",
"4 4\nabcd\n"
] | [
"NO\n",
"cbd\n",
"abda\n"
] | String *s* is lexicographically larger (or simply larger) than string *t* with the same length, if there is number *i*, such that *s*<sub class="lower-index">1</sub> = *t*<sub class="lower-index">1</sub>, ..., *s*<sub class="lower-index">*i*</sub> = *t*<sub class="lower-index">*i*</sub>, *s*<sub class="lower-index">*i*... | 500 | [
{
"input": "3 3\ncba",
"output": "NO"
},
{
"input": "3 4\ncba",
"output": "cbd"
},
{
"input": "4 4\nabcd",
"output": "abda"
},
{
"input": "2 2\nab",
"output": "ba"
},
{
"input": "2 2\nba",
"output": "NO"
},
{
"input": "1 2\na",
"output": "b"
},
... | 1,584,292,979 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 307,200 | def solve(s, n):
for i in reversed(range(len(s))):
c = s[i]
for j in range(ord(c)+1, ord('a')+n):
next = chr(j)
if next != s[i-1] and next!= s[i-2]:
new_s = s[0:i] + next
res = 'abc'
for x in range(i+1, len(s)):
... | Title: No to Palindromes!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Paul hates palindromes. He assumes that string *s* is tolerable if each its character is one of the first *p* letters of the English alphabet and *s* doesn't contain any palindrome contiguous substring of length 2 or... | ```python
def solve(s, n):
for i in reversed(range(len(s))):
c = s[i]
for j in range(ord(c)+1, ord('a')+n):
next = chr(j)
if next != s[i-1] and next!= s[i-2]:
new_s = s[0:i] + next
res = 'abc'
for x in range(i+1, len(s))... | 0 | |
432 | B | Football Kit | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | Consider a football tournament where *n* teams participate. Each team has two football kits: for home games, and for away games. The kit for home games of the *i*-th team has color *x**i* and the kit for away games of this team has color *y**i* (*x**i*<=≠<=*y**i*).
In the tournament, each team plays exactly one home g... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=105) — the number of teams. Next *n* lines contain the description of the teams. The *i*-th line contains two space-separated numbers *x**i*, *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=105; *x**i*<=≠<=*y**i*) — the color numbers for the home and away kits of the *i*-th... | For each team, print on a single line two space-separated integers — the number of games this team is going to play in home and away kits, correspondingly. Print the answers for the teams in the order they appeared in the input. | [
"2\n1 2\n2 1\n",
"3\n1 2\n2 1\n1 3\n"
] | [
"2 0\n2 0\n",
"3 1\n4 0\n2 2\n"
] | none | 1,000 | [
{
"input": "2\n1 2\n2 1",
"output": "2 0\n2 0"
},
{
"input": "3\n1 2\n2 1\n1 3",
"output": "3 1\n4 0\n2 2"
},
{
"input": "2\n1 2\n1 2",
"output": "1 1\n1 1"
},
{
"input": "2\n1 2\n3 4",
"output": "1 1\n1 1"
},
{
"input": "3\n1 100000\n1 100000\n100000 2",
"out... | 1,669,966,567 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 38 | 296 | 32,768,000 | import math
import bisect
import itertools
import copy
import sys
input = lambda: sys.stdin.readline().rstrip("\r\n")
def intmap():
return map(int,input().split())
def lintmap():
return list(map(int,input().split()))
def lstrmap():
return list(map(str,input().split()))
def ... | Title: Football Kit
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider a football tournament where *n* teams participate. Each team has two football kits: for home games, and for away games. The kit for home games of the *i*-th team has color *x**i* and the kit for away games of this... | ```python
import math
import bisect
import itertools
import copy
import sys
input = lambda: sys.stdin.readline().rstrip("\r\n")
def intmap():
return map(int,input().split())
def lintmap():
return list(map(int,input().split()))
def lstrmap():
return list(map(str,input().split()))
... | 3 | |
952 | C | Ravioli Sort | PROGRAMMING | 1,600 | [
"implementation"
] | null | null | Everybody knows of [spaghetti sort](https://en.wikipedia.org/wiki/Spaghetti_sort). You decided to implement an analog sorting algorithm yourself, but as you survey your pantry you realize you're out of spaghetti! The only type of pasta you have is ravioli, but you are not going to let this stop you...
You come up with... | The first line of input contains a single number *n* (1<=≤<=*n*<=≤<=10) — the size of the array.
The second line of input contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=100) — the elements of the array. | Output "YES" if the array can be sorted using the described procedure and "NO" if it can not. | [
"3\n1 2 3\n",
"3\n3 1 2\n"
] | [
"YES\n",
"NO\n"
] | In the second example the array will change even before the tallest stack is chosen for the first time: ravioli from stack of height 3 will slide on the stack of height 1, and the algorithm will output an array {2, 2, 2}. | 0 | [
{
"input": "3\n1 2 3",
"output": "YES"
},
{
"input": "3\n3 1 2",
"output": "NO"
},
{
"input": "1\n13",
"output": "YES"
},
{
"input": "10\n67 67 67 67 67 67 67 67 67 67",
"output": "YES"
},
{
"input": "10\n16 17 16 15 14 15 16 17 16 15",
"output": "YES"
},
... | 1,588,431,347 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 124 | 0 | n=int(input())
f=0
l=list(map(int,input().split()))
for i in range(1,n):
if abs(l[i]-l[i-1])>=2:
f=1
break
if f==1 or abs(max(l)-l[-1])>=2:
print("NO")
else:
print("YES")
| Title: Ravioli Sort
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Everybody knows of [spaghetti sort](https://en.wikipedia.org/wiki/Spaghetti_sort). You decided to implement an analog sorting algorithm yourself, but as you survey your pantry you realize you're out of spaghetti! The only ... | ```python
n=int(input())
f=0
l=list(map(int,input().split()))
for i in range(1,n):
if abs(l[i]-l[i-1])>=2:
f=1
break
if f==1 or abs(max(l)-l[-1])>=2:
print("NO")
else:
print("YES")
``` | 0 | |
234 | A | Lefthanders and Righthanders | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | One fine October day a mathematics teacher Vasily Petrov went to a class and saw there *n* pupils who sat at the desks, two people at each desk. Vasily quickly realized that number *n* is even. Like all true mathematicians, Vasily has all students numbered from 1 to *n*.
But Vasily Petrov did not like the way the chi... | The first input line contains a single even integer *n* (4<=≤<=*n*<=≤<=100) — the number of students in the class. The second line contains exactly *n* capital English letters "L" and "R". If the *i*-th letter at the second line equals "L", then the student number *i* is a lefthander, otherwise he is a righthander. | Print integer pairs, one pair per line. In the *i*-th line print the numbers of students that will sit at the *i*-th desk. The first number in the pair stands for the student who is sitting to the left, and the second number stands for the student who is sitting to the right. Separate the numbers in the pairs by space... | [
"6\nLLRLLL\n",
"4\nRRLL\n"
] | [
"1 4\n2 5\n6 3\n",
"3 1\n4 2\n"
] | none | 0 | [
{
"input": "6\nLLRLLL",
"output": "1 4\n2 5\n6 3"
},
{
"input": "4\nRRLL",
"output": "3 1\n4 2"
},
{
"input": "4\nLLRR",
"output": "1 3\n2 4"
},
{
"input": "6\nRLLRRL",
"output": "1 4\n2 5\n3 6"
},
{
"input": "8\nLRLRLLLR",
"output": "1 5\n6 2\n3 7\n4 8"
},
... | 1,620,102,058 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | inupt=open("input.txt", "r")
output=open("output.txt","w")
x=int(input.readline())
y=input.readline()
for z in range(n//2):
if y[z]=="R": output.write(str(z+1+x//2)+" "+str(z+1)+"/n"))
else: output.write(str(z+1)+" "+str(z+1+x//2)+"/n"))
| Title: Lefthanders and Righthanders
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One fine October day a mathematics teacher Vasily Petrov went to a class and saw there *n* pupils who sat at the desks, two people at each desk. Vasily quickly realized that number *n* is even. Like all t... | ```python
inupt=open("input.txt", "r")
output=open("output.txt","w")
x=int(input.readline())
y=input.readline()
for z in range(n//2):
if y[z]=="R": output.write(str(z+1+x//2)+" "+str(z+1)+"/n"))
else: output.write(str(z+1)+" "+str(z+1+x//2)+"/n"))
``` | -1 | |
798 | B | Mike and strings | PROGRAMMING | 1,300 | [
"brute force",
"dp",
"strings"
] | null | null | Mike has *n* strings *s*1,<=*s*2,<=...,<=*s**n* each consisting of lowercase English letters. In one move he can choose a string *s**i*, erase the first character and append it to the end of the string. For example, if he has the string "coolmike", in one move he can transform it into the string "oolmikec".
Now Mike a... | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of strings.
This is followed by *n* lines which contain a string each. The *i*-th line corresponding to string *s**i*. Lengths of strings are equal. Lengths of each string is positive and don't exceed 50. | Print the minimal number of moves Mike needs in order to make all the strings equal or print <=-<=1 if there is no solution. | [
"4\nxzzwo\nzwoxz\nzzwox\nxzzwo\n",
"2\nmolzv\nlzvmo\n",
"3\nkc\nkc\nkc\n",
"3\naa\naa\nab\n"
] | [
"5\n",
"2\n",
"0\n",
"-1\n"
] | In the first sample testcase the optimal scenario is to perform operations in such a way as to transform all strings into "zwoxz". | 1,000 | [
{
"input": "4\nxzzwo\nzwoxz\nzzwox\nxzzwo",
"output": "5"
},
{
"input": "2\nmolzv\nlzvmo",
"output": "2"
},
{
"input": "3\nkc\nkc\nkc",
"output": "0"
},
{
"input": "3\naa\naa\nab",
"output": "-1"
},
{
"input": "3\nkwkb\nkbkw\nbkwk",
"output": "3"
},
{
... | 1,682,744,046 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 30 | 0 | def analiza(x):
arr=[]
mov=0
for i in x:
for j in x:
if i != j:
mov+=comprob(i,j)
arr.append(mov)
mov=0
return min(arr)
def comprob(x,y):
m=0
x=list(x)
y=list(y)
p=list(y)
while(True):
if(x==y):
... | Title: Mike and strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mike has *n* strings *s*1,<=*s*2,<=...,<=*s**n* each consisting of lowercase English letters. In one move he can choose a string *s**i*, erase the first character and append it to the end of the string. For example, if... | ```python
def analiza(x):
arr=[]
mov=0
for i in x:
for j in x:
if i != j:
mov+=comprob(i,j)
arr.append(mov)
mov=0
return min(arr)
def comprob(x,y):
m=0
x=list(x)
y=list(y)
p=list(y)
while(True):
if(x==y):
... | 0 | |
387 | B | George and Round | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"two pointers"
] | null | null | George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirem... | Print a single integer — the answer to the problem. | [
"3 5\n1 2 3\n1 2 2 3 3\n",
"3 5\n1 2 3\n1 1 1 1 1\n",
"3 1\n2 3 4\n1\n"
] | [
"0\n",
"2\n",
"3\n"
] | In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems wi... | 1,000 | [
{
"input": "3 5\n1 2 3\n1 2 2 3 3",
"output": "0"
},
{
"input": "3 5\n1 2 3\n1 1 1 1 1",
"output": "2"
},
{
"input": "3 1\n2 3 4\n1",
"output": "3"
},
{
"input": "29 100\n20 32 41 67 72 155 331 382 399 412 465 470 484 511 515 529 616 637 679 715 733 763 826 843 862 903 925 97... | 1,586,023,269 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 124 | 409,600 | from collections import Counter
n,m=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=Counter(b)
result=n
for i in range(n):
if c[a[i]]>=1:
c[a[i]]-=1
result-=1
print(result)
| Title: George and Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
T... | ```python
from collections import Counter
n,m=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=Counter(b)
result=n
for i in range(n):
if c[a[i]]>=1:
c[a[i]]-=1
result-=1
print(result)
``` | 0 | |
180 | C | Letter | PROGRAMMING | 1,400 | [
"dp"
] | null | null | Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them were uppercase.
Patrick believes that a message is fancy if any uppercase letter stands to... | The only line of the input contains a non-empty string consisting of uppercase and lowercase letters. The string's length does not exceed 105. | Print a single number — the least number of actions needed to make the message fancy. | [
"PRuvetSTAaYA\n",
"OYPROSTIYAOPECHATALSYAPRIVETSTASYA\n",
"helloworld\n"
] | [
"5\n",
"0\n",
"0\n"
] | none | 0 | [
{
"input": "PRuvetSTAaYA",
"output": "5"
},
{
"input": "OYPROSTIYAOPECHATALSYAPRIVETSTASYA",
"output": "0"
},
{
"input": "helloworld",
"output": "0"
},
{
"input": "P",
"output": "0"
},
{
"input": "t",
"output": "0"
},
{
"input": "XdJ",
"output": "1... | 1,579,440,784 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 342 | 307,200 | s = input()
c = 0
for i in s:
if i.isupper():
c += 1
c2 = c
for i in s:
if i.isupper():
c2 -= 1
else:
c2 += 1
c = min(c, c2)
print(c)
| Title: Letter
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them... | ```python
s = input()
c = 0
for i in s:
if i.isupper():
c += 1
c2 = c
for i in s:
if i.isupper():
c2 -= 1
else:
c2 += 1
c = min(c, c2)
print(c)
``` | 3 | |
719 | A | Vitya in the Countryside | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Every summer Vitya comes to visit his grandmother in the countryside. This summer, he got a huge wart. Every grandma knows that one should treat warts when the moon goes down. Thus, Vitya has to catch the moment when the moon is down.
Moon cycle lasts 30 days. The size of the visible part of the moon (in Vitya's units... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=92) — the number of consecutive days Vitya was watching the size of the visible part of the moon.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=15) — Vitya's records.
It's guaranteed that the input data is consistent. | If Vitya can be sure that the size of visible part of the moon on day *n*<=+<=1 will be less than the size of the visible part on day *n*, then print "DOWN" at the only line of the output. If he might be sure that the size of the visible part will increase, then print "UP". If it's impossible to determine what exactly ... | [
"5\n3 4 5 6 7\n",
"7\n12 13 14 15 14 13 12\n",
"1\n8\n"
] | [
"UP\n",
"DOWN\n",
"-1\n"
] | In the first sample, the size of the moon on the next day will be equal to 8, thus the answer is "UP".
In the second sample, the size of the moon on the next day will be 11, thus the answer is "DOWN".
In the third sample, there is no way to determine whether the size of the moon on the next day will be 7 or 9, thus t... | 500 | [
{
"input": "5\n3 4 5 6 7",
"output": "UP"
},
{
"input": "7\n12 13 14 15 14 13 12",
"output": "DOWN"
},
{
"input": "1\n8",
"output": "-1"
},
{
"input": "44\n7 8 9 10 11 12 13 14 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 14 13 12 11 10",
"out... | 1,481,054,947 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 4,608,000 | n=int(input())
vis=list(map(int, input().split()))
res=""
if len(vis)==1:
print(-1)
else:
for i in range(n-1):
if vis[i]<vis[i+1]:
res="UP"
else:
res="Down"
print(res)
| Title: Vitya in the Countryside
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Every summer Vitya comes to visit his grandmother in the countryside. This summer, he got a huge wart. Every grandma knows that one should treat warts when the moon goes down. Thus, Vitya has to catch the momen... | ```python
n=int(input())
vis=list(map(int, input().split()))
res=""
if len(vis)==1:
print(-1)
else:
for i in range(n-1):
if vis[i]<vis[i+1]:
res="UP"
else:
res="Down"
print(res)
``` | 0 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,691,731,307 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 92 | 0 | def main():
n = int(input())
arr = []
for i in range(n):
row = list(map(int, input().split()))
arr.append(row)
x, y, z = 0, 0, 0
for i in range(n):
x += arr[i][0]
y += arr[i][1]
z += arr[i][2]
if x == y == z == 0:
print("YES")
... | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. S... | ```python
def main():
n = int(input())
arr = []
for i in range(n):
row = list(map(int, input().split()))
arr.append(row)
x, y, z = 0, 0, 0
for i in range(n):
x += arr[i][0]
y += arr[i][1]
z += arr[i][2]
if x == y == z == 0:
prin... | 3.977 |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,620,928,779 | 2,147,483,647 | PyPy 3 | OK | TESTS | 63 | 108 | 20,480,000 | from sys import stdin,stdout
from collections import deque
nmbr = lambda: int(input())
lst = lambda: list(map(int, input().split()))
PI=float('inf')
for _ in range(1):#nmbr()):
n,k=lst()
s=input()
q=deque()
dp=[PI]*n
dp[0]=0
q.append(0)
for i in range(1,n):
while q and i... | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
from sys import stdin,stdout
from collections import deque
nmbr = lambda: int(input())
lst = lambda: list(map(int, input().split()))
PI=float('inf')
for _ in range(1):#nmbr()):
n,k=lst()
s=input()
q=deque()
dp=[PI]*n
dp[0]=0
q.append(0)
for i in range(1,n):
whi... | 3 | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,690,202,851 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 62 | 0 | def main():
n = int(input()) # Number of teams
teams = [] # List to store the colors of home and guest uniforms for each team
# Read the input
for _ in range(n):
hi, ai = map(int, input().split())
teams.append((hi, ai))
# Initialize the count variable
count = 0
... | Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
def main():
n = int(input()) # Number of teams
teams = [] # List to store the colors of home and guest uniforms for each team
# Read the input
for _ in range(n):
hi, ai = map(int, input().split())
teams.append((hi, ai))
# Initialize the count variable
coun... | 3 | |
793 | A | Oleg and shares | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Oleg the bank client checks share prices every day. There are *n* share prices he is interested in. Today he observed that each second exactly one of these prices decreases by *k* rubles (note that each second exactly one price changes, but at different seconds different prices can change). Prices can become negative. ... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*k*<=≤<=109) — the number of share prices, and the amount of rubles some price decreases each second.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the initial prices. | Print the only line containing the minimum number of seconds needed for prices to become equal, of «-1» if it is impossible. | [
"3 3\n12 9 15\n",
"2 2\n10 9\n",
"4 1\n1 1000000000 1000000000 1000000000\n"
] | [
"3",
"-1",
"2999999997"
] | Consider the first example.
Suppose the third price decreases in the first second and become equal 12 rubles, then the first price decreases and becomes equal 9 rubles, and in the third second the third price decreases again and becomes equal 9 rubles. In this case all prices become equal 9 rubles in 3 seconds.
Ther... | 500 | [
{
"input": "3 3\n12 9 15",
"output": "3"
},
{
"input": "2 2\n10 9",
"output": "-1"
},
{
"input": "4 1\n1 1000000000 1000000000 1000000000",
"output": "2999999997"
},
{
"input": "1 11\n123",
"output": "0"
},
{
"input": "20 6\n38 86 86 50 98 62 32 2 14 62 98 50 2 50... | 1,493,300,588 | 2,147,483,647 | Python 3 | OK | TESTS | 88 | 156 | 13,619,200 | n,k = map(int,input().split())
a = [int(i) for i in input().split()]
m = min(a)
if any([(i - m) % k for i in a]):
print('-1')
else:
print(sum(((i - m) // k for i in a))) | Title: Oleg and shares
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Oleg the bank client checks share prices every day. There are *n* share prices he is interested in. Today he observed that each second exactly one of these prices decreases by *k* rubles (note that each second exactly o... | ```python
n,k = map(int,input().split())
a = [int(i) for i in input().split()]
m = min(a)
if any([(i - m) % k for i in a]):
print('-1')
else:
print(sum(((i - m) // k for i in a)))
``` | 3 | |
846 | A | Curriculum Vitae | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job.
During all his career Hideo has produced *n* games. Some of them were successful, some were not. Hideo wants to remove several of them (possibly zer... | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=100).
The second line contains *n* space-separated integer numbers *s*1,<=*s*2,<=...,<=*s**n* (0<=≤<=*s**i*<=≤<=1). 0 corresponds to an unsuccessful game, 1 — to a successful one. | Print one integer — the maximum number of games Hideo can leave in his CV so that no unsuccessful game comes after a successful one. | [
"4\n1 1 0 1\n",
"6\n0 1 0 0 1 0\n",
"1\n0\n"
] | [
"3\n",
"4\n",
"1\n"
] | none | 0 | [
{
"input": "4\n1 1 0 1",
"output": "3"
},
{
"input": "6\n0 1 0 0 1 0",
"output": "4"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "100\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,632,060,277 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 62 | 6,963,200 | n = int(input())
l = list(map(int, input().split()))
count = 0
i, j = 0, n-1
while i < n and l[i]==0:
i += 1
count += 1
while j >= 0 and l[j]==1:
j -= 1
count += 1
print(count + max(l[i:j+1].count(0), l[i:j+1].count(1))) | Title: Curriculum Vitae
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job.
During all his career Hideo has produced *n* g... | ```python
n = int(input())
l = list(map(int, input().split()))
count = 0
i, j = 0, n-1
while i < n and l[i]==0:
i += 1
count += 1
while j >= 0 and l[j]==1:
j -= 1
count += 1
print(count + max(l[i:j+1].count(0), l[i:j+1].count(1)))
``` | 0 | |
560 | B | Gerald is into Art | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a special board to attach it to the wall and place the paintings on the board. The board has shape of an *a*1<=×<=*b*1 rectangle, the paintings have shape of a *a*2<=×<=*b*2 and *a*3<=×<=*b*3 rec... | The first line contains two space-separated numbers *a*1 and *b*1 — the sides of the board. Next two lines contain numbers *a*2,<=*b*2,<=*a*3 and *b*3 — the sides of the paintings. All numbers *a**i*,<=*b**i* in the input are integers and fit into the range from 1 to 1000. | If the paintings can be placed on the wall, print "YES" (without the quotes), and if they cannot, print "NO" (without the quotes). | [
"3 2\n1 3\n2 1\n",
"5 5\n3 3\n3 3\n",
"4 2\n2 3\n1 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | That's how we can place the pictures in the first test:
<img class="tex-graphics" src="https://espresso.codeforces.com/b41bf40c649073c6d3dd62eb7ae7adfc4bd131bd.png" style="max-width: 100.0%;max-height: 100.0%;"/>
And that's how we can do it in the third one.
<img class="tex-graphics" src="https://espresso.codeforces... | 1,000 | [
{
"input": "3 2\n1 3\n2 1",
"output": "YES"
},
{
"input": "5 5\n3 3\n3 3",
"output": "NO"
},
{
"input": "4 2\n2 3\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 1",
"output": "YES"
},
{
"input": "1000 1000\n999 999\n1 1000",
"output": "YES"
},
{
"in... | 1,437,576,053 | 2,453 | Python 3 | RUNTIME_ERROR | PRETESTS | 0 | 61 | 0 | a, b = map(int, input())
a1, b1 = map(int, input())
a2, b2 = map(int, input())
x = a1 + a2
y = b1 + b2
flag = False
if x <= a and y <= b:
flag = True
elif x <= b and y <= a:
flag = True
x = a1 + b2
y = b1 + a2
if x <= a and y <= b:
flag = True
elif x <= b and y <= a:
flag = True
if flag:
... | Title: Gerald is into Art
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a special board to attach it to the wall and place the paintings on the board. The board ha... | ```python
a, b = map(int, input())
a1, b1 = map(int, input())
a2, b2 = map(int, input())
x = a1 + a2
y = b1 + b2
flag = False
if x <= a and y <= b:
flag = True
elif x <= b and y <= a:
flag = True
x = a1 + b2
y = b1 + a2
if x <= a and y <= b:
flag = True
elif x <= b and y <= a:
flag = True
... | -1 | |
709 | A | Juicer | PROGRAMMING | 900 | [
"implementation"
] | null | null | Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To be put in the juicer the orange must have size not exceeding *b*, so if Kolya sees an orange ... | The first line of the input contains three integers *n*, *b* and *d* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*b*<=≤<=*d*<=≤<=1<=000<=000) — the number of oranges, the maximum size of the orange that fits in the juicer and the value *d*, which determines the condition when the waste section should be emptied.
The second line co... | Print one integer — the number of times Kolya will have to empty the waste section. | [
"2 7 10\n5 6\n",
"1 5 10\n7\n",
"3 10 10\n5 7 7\n",
"1 1 1\n1\n"
] | [
"1\n",
"0\n",
"1\n",
"0\n"
] | In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all. | 500 | [
{
"input": "2 7 10\n5 6",
"output": "1"
},
{
"input": "1 5 10\n7",
"output": "0"
},
{
"input": "3 10 10\n5 7 7",
"output": "1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 951637 951638\n44069 951637",
"output": "1"
},
{
"input": "50 100 12... | 1,675,803,659 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n, b, d = input().split()
n = int(n)
b = int(b)
d = int(d)
auxd = d
res = 0
_a = input().split()
for i in range(n):
a = int(_a[i])
if a <= b:
if auxd - a <= 0 and i < n-1:
res += 1
auxd += d
auxd -= a
print(res) | Title: Juicer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To b... | ```python
n, b, d = input().split()
n = int(n)
b = int(b)
d = int(d)
auxd = d
res = 0
_a = input().split()
for i in range(n):
a = int(_a[i])
if a <= b:
if auxd - a <= 0 and i < n-1:
res += 1
auxd += d
auxd -= a
print(res)
``` | 0 | |
757 | B | Bash's Big Day | PROGRAMMING | 1,400 | [
"greedy",
"math",
"number theory"
] | null | null | Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu's Lab. Since Bash is Professor Zulu's favourite student, Zulu allows him to take as many Pokemon from his lab as he pleases.
But Zulu warns him that a group of *k*<=><=1 Pokemon with strengths {*... | The input consists of two lines.
The first line contains an integer *n* (1<=≤<=*n*<=≤<=105), the number of Pokemon in the lab.
The next line contains *n* space separated integers, where the *i*-th of them denotes *s**i* (1<=≤<=*s**i*<=≤<=105), the strength of the *i*-th Pokemon. | Print single integer — the maximum number of Pokemons Bash can take. | [
"3\n2 3 4\n",
"5\n2 3 4 6 7\n"
] | [
"2\n",
"3\n"
] | *gcd* (greatest common divisor) of positive integers set {*a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub>} is the maximum positive integer that divides all the integers {*a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a... | 1,000 | [
{
"input": "3\n2 3 4",
"output": "2"
},
{
"input": "5\n2 3 4 6 7",
"output": "3"
},
{
"input": "3\n5 6 4",
"output": "2"
},
{
"input": "8\n41 74 4 27 85 39 100 36",
"output": "4"
},
{
"input": "6\n89 20 86 81 62 23",
"output": "3"
},
{
"input": "71\n23... | 1,687,695,535 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 134 | 295 | 14,131,200 | def max_pokemon_count(n, strengths):
max_strength = max(strengths)
prime = [True] * (max_strength + 1)
prime[0] = prime[1] = False
p = 2
while p * p <= max_strength:
if prime[p]:
for i in range(p * p, max_strength + 1, p):
prime[i] = False
... | Title: Bash's Big Day
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu's Lab. Since Bash is Professor Zulu's favourite student, Zulu allows him to take as many Pokemon fr... | ```python
def max_pokemon_count(n, strengths):
max_strength = max(strengths)
prime = [True] * (max_strength + 1)
prime[0] = prime[1] = False
p = 2
while p * p <= max_strength:
if prime[p]:
for i in range(p * p, max_strength + 1, p):
prime[i] = Fals... | 3 | |
389 | A | Fox and Number Game | PROGRAMMING | 1,000 | [
"greedy",
"math"
] | null | null | Fox Ciel is playing a game with numbers now.
Ciel has *n* positive integers: *x*1, *x*2, ..., *x**n*. She can do the following operation as many times as needed: select two different indexes *i* and *j* such that *x**i* > *x**j* hold, and then apply assignment *x**i* = *x**i* - *x**j*. The goal is to make the sum ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=100). Then the second line contains *n* integers: *x*1, *x*2, ..., *x**n* (1<=≤<=*x**i*<=≤<=100). | Output a single integer — the required minimal sum. | [
"2\n1 2\n",
"3\n2 4 6\n",
"2\n12 18\n",
"5\n45 12 27 30 18\n"
] | [
"2\n",
"6\n",
"12\n",
"15\n"
] | In the first example the optimal way is to do the assignment: *x*<sub class="lower-index">2</sub> = *x*<sub class="lower-index">2</sub> - *x*<sub class="lower-index">1</sub>.
In the second example the optimal sequence of operations is: *x*<sub class="lower-index">3</sub> = *x*<sub class="lower-index">3</sub> - *x*<sub... | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n2 4 6",
"output": "6"
},
{
"input": "2\n12 18",
"output": "12"
},
{
"input": "5\n45 12 27 30 18",
"output": "15"
},
{
"input": "2\n1 1",
"output": "2"
},
{
"input": "2\n100 100",
"output": "200"
... | 1,466,528,124 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 25 | 62 | 0 | input()
li = [int(x) for x in input().split()]
li.sort()
mi = min([ li[i]-li[i-1] if li[i]>li[i-1] else li[i] for i in range(1,len(li))])
print(mi*len(li))
| Title: Fox and Number Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel is playing a game with numbers now.
Ciel has *n* positive integers: *x*1, *x*2, ..., *x**n*. She can do the following operation as many times as needed: select two different indexes *i* and *j* such that ... | ```python
input()
li = [int(x) for x in input().split()]
li.sort()
mi = min([ li[i]-li[i-1] if li[i]>li[i-1] else li[i] for i in range(1,len(li))])
print(mi*len(li))
``` | 0 | |
747 | B | Mammoth's Genome Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain *s*. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, *s... | The first line contains the integer *n* (4<=≤<=*n*<=≤<=255) — the length of the genome.
The second line contains the string *s* of length *n* — the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'. | If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes). | [
"8\nAG?C??CT\n",
"4\nAGCT\n",
"6\n????G?\n",
"4\nAA??\n"
] | [
"AGACGTCT\n",
"AGCT\n",
"===\n",
"===\n"
] | In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice.
In the second example the genome is already decoded correctly and each nucleotide is ... | 1,000 | [
{
"input": "8\nAG?C??CT",
"output": "AGACGTCT"
},
{
"input": "4\nAGCT",
"output": "AGCT"
},
{
"input": "6\n????G?",
"output": "==="
},
{
"input": "4\nAA??",
"output": "==="
},
{
"input": "4\n????",
"output": "ACGT"
},
{
"input": "252\n???????GCG??T??TT... | 1,603,868,223 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 124 | 716,800 | import math
import sys
import re
def func(s):
a = s.count('A')
g = s.count('G')
c = s.count('C')
t = s.count('T')
qm = s.count('?')
if qm == 0:
return s
mc = max(a ,g ,c ,t)
tot = 4*mc - a - g - c - t
if tot%qm != 0:
return '==='
else:
n ... | Title: Mammoth's Genome Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain *s*. Each nucleotide is coded with a capital letter... | ```python
import math
import sys
import re
def func(s):
a = s.count('A')
g = s.count('G')
c = s.count('C')
t = s.count('T')
qm = s.count('?')
if qm == 0:
return s
mc = max(a ,g ,c ,t)
tot = 4*mc - a - g - c - t
if tot%qm != 0:
return '==='
else:
... | 0 | |
938 | A | Word Correction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird and it needs to be replaced. So the word corrector works in such a way: as long as there are two consec... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of letters in word *s* before the correction.
The second line contains a string *s* consisting of exactly *n* lowercase Latin letters — the word before the correction. | Output the word *s* after the correction. | [
"5\nweird\n",
"4\nword\n",
"5\naaeaa\n"
] | [
"werd\n",
"word\n",
"a\n"
] | Explanations of the examples:
1. There is only one replace: weird <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> werd;1. No replace needed since there are no two consecutive vowels;1. aaeaa <i... | 0 | [
{
"input": "5\nweird",
"output": "werd"
},
{
"input": "4\nword",
"output": "word"
},
{
"input": "5\naaeaa",
"output": "a"
},
{
"input": "100\naaaaabbbbboyoyoyoyoyacadabbbbbiuiufgiuiuaahjabbbklboyoyoyoyoyaaaaabbbbbiuiuiuiuiuaaaaabbbbbeyiyuyzyw",
"output": "abbbbbocadabbbbb... | 1,584,074,770 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<stdio.h>
int main()
{
int n,i;
scanf("%d",&n);
char c[n];
scanf("%s",c);
for (i=n-1;i>=0;i--)
{
if ((c[i]=='a'||c[i]=='e'||c[i]=='i'||c[i]=='0'||c[i]=='u'||c[i]=='y'||c[i]=='.')&&(c[i-1]=='a'||c[i-1]=='e'||c[i-1]=='i'||c[i-1]=='0'||c[i-1]=='u'||c[i-1]=='y'||c[i-1]=='.')... | Title: Word Correction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird an... | ```python
#include<stdio.h>
int main()
{
int n,i;
scanf("%d",&n);
char c[n];
scanf("%s",c);
for (i=n-1;i>=0;i--)
{
if ((c[i]=='a'||c[i]=='e'||c[i]=='i'||c[i]=='0'||c[i]=='u'||c[i]=='y'||c[i]=='.')&&(c[i-1]=='a'||c[i-1]=='e'||c[i-1]=='i'||c[i-1]=='0'||c[i-1]=='u'||c[i-1]=='y'||c[... | -1 | |
922 | A | Cloning Toys | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Imp likes his plush toy a lot.
Recently, he found a machine that can clone plush toys. Imp knows that if he applies the machine to an original toy, he additionally gets one more original toy and one copy, and if he applies the machine to a copied toy, he gets two additional copies.
Initially, Imp has only one origina... | The only line contains two integers *x* and *y* (0<=≤<=*x*,<=*y*<=≤<=109) — the number of copies and the number of original toys Imp wants to get (including the initial one). | Print "Yes", if the desired configuration is possible, and "No" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"6 3\n",
"4 2\n",
"1000 1001\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | In the first example, Imp has to apply the machine twice to original toys and then twice to copies. | 500 | [
{
"input": "6 3",
"output": "Yes"
},
{
"input": "4 2",
"output": "No"
},
{
"input": "1000 1001",
"output": "Yes"
},
{
"input": "1000000000 999999999",
"output": "Yes"
},
{
"input": "81452244 81452247",
"output": "No"
},
{
"input": "188032448 86524683",... | 1,667,582,737 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | x,y=map(int,input().split())
b=y-1
a=x-y
if(y==0):
print('no')
elif(y==1 and x%2==0):
print('no')
elif(x<b):
print('no')
elif(a%2==0):
print('yes')
else:
print("no")
| Title: Cloning Toys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imp likes his plush toy a lot.
Recently, he found a machine that can clone plush toys. Imp knows that if he applies the machine to an original toy, he additionally gets one more original toy and one copy, and if he applie... | ```python
x,y=map(int,input().split())
b=y-1
a=x-y
if(y==0):
print('no')
elif(y==1 and x%2==0):
print('no')
elif(x<b):
print('no')
elif(a%2==0):
print('yes')
else:
print("no")
``` | 0 | |
261 | A | Maxim and Discounts | PROGRAMMING | 1,400 | [
"greedy",
"sortings"
] | null | null | Maxim always goes to the supermarket on Sundays. Today the supermarket has a special offer of discount systems.
There are *m* types of discounts. We assume that the discounts are indexed from 1 to *m*. To use the discount number *i*, the customer takes a special basket, where he puts exactly *q**i* items he buys. Unde... | The first line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of discount types. The second line contains *m* integers: *q*1,<=*q*2,<=...,<=*q**m* (1<=≤<=*q**i*<=≤<=105).
The third line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of items Maxim needs. The fourth line contains *n* integers: *a*1,<=*a*... | In a single line print a single integer — the answer to the problem. | [
"1\n2\n4\n50 50 100 100\n",
"2\n2 3\n5\n50 50 50 50 50\n",
"1\n1\n7\n1 1 1 1 1 1 1\n"
] | [
"200\n",
"150\n",
"3\n"
] | In the first sample Maxim needs to buy two items that cost 100 and get a discount for two free items that cost 50. In that case, Maxim is going to pay 200.
In the second sample the best strategy for Maxim is to buy 3 items and get 2 items for free using the discount. In that case, Maxim is going to pay 150. | 500 | [
{
"input": "1\n2\n4\n50 50 100 100",
"output": "200"
},
{
"input": "2\n2 3\n5\n50 50 50 50 50",
"output": "150"
},
{
"input": "1\n1\n7\n1 1 1 1 1 1 1",
"output": "3"
},
{
"input": "60\n7 4 20 15 17 6 2 2 3 18 13 14 16 11 13 12 6 10 14 1 16 6 4 9 10 8 10 15 16 13 13 9 16 11 5 ... | 1,594,199,478 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 530 | 33,587,200 | m=int(input())
q=[int(i) for i in input().split()]
q.sort()
n=int(input())
a=[int(i) for i in input().split()]
a.sort()
ans=0
i=n-1
while(i>=0):
d=0
while(i>=0 and d<q[0]):
ans+=a[i]
i-=1
d+=1
d=0
while(i>=0 and d<2):
d+=1
i-=1
print(ans) | Title: Maxim and Discounts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Maxim always goes to the supermarket on Sundays. Today the supermarket has a special offer of discount systems.
There are *m* types of discounts. We assume that the discounts are indexed from 1 to *m*. To use the d... | ```python
m=int(input())
q=[int(i) for i in input().split()]
q.sort()
n=int(input())
a=[int(i) for i in input().split()]
a.sort()
ans=0
i=n-1
while(i>=0):
d=0
while(i>=0 and d<q[0]):
ans+=a[i]
i-=1
d+=1
d=0
while(i>=0 and d<2):
d+=1
i-=1
print(an... | 3 | |
302 | A | Eugeny and Array | PROGRAMMING | 800 | [
"implementation"
] | null | null | Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). - The response to the query will be integer 1, if the elements of a... | The first line contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=2·105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*a**i*<==<=-1,<=1). Next *m* lines contain Eugene's queries. The *i*-th line contains integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). | Print *m* integers — the responses to Eugene's queries in the order they occur in the input. | [
"2 3\n1 -1\n1 1\n1 2\n2 2\n",
"5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5\n"
] | [
"0\n1\n0\n",
"0\n1\n0\n1\n0\n"
] | none | 500 | [
{
"input": "2 3\n1 -1\n1 1\n1 2\n2 2",
"output": "0\n1\n0"
},
{
"input": "5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5",
"output": "0\n1\n0\n1\n0"
},
{
"input": "3 3\n1 1 1\n2 2\n1 1\n1 1",
"output": "0\n0\n0"
},
{
"input": "4 4\n-1 -1 -1 -1\n1 3\n1 2\n1 2\n1 1",
"output": "... | 1,647,361,400 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 3,584,000 | n,m=[int(y) for y in input().split()]
a=[int(x) for x in input().split()]
out=""
for i in range(m):
l,r=[int(z) for z in input().split()]
d=abs(l-r)+1
n=min(a.count(1),a.count(-1))
if a.count(1)<d//2 or a.count(-1)<d//2 or d%2==1:
out+="0\n"
else:
out+="1\n"
print(out) | Title: Eugeny and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (... | ```python
n,m=[int(y) for y in input().split()]
a=[int(x) for x in input().split()]
out=""
for i in range(m):
l,r=[int(z) for z in input().split()]
d=abs(l-r)+1
n=min(a.count(1),a.count(-1))
if a.count(1)<d//2 or a.count(-1)<d//2 or d%2==1:
out+="0\n"
else:
out+="1\n"
pr... | 0 | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,689,409,138 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 46 | 0 |
n, k = map(int, input().split())
a = list(map(int,input().split()))
ans = 0
for x in a :
if x > k :
ans+=2
else:
ans+=1
print(ans) | Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
n, k = map(int, input().split())
a = list(map(int,input().split()))
ans = 0
for x in a :
if x > k :
ans+=2
else:
ans+=1
print(ans)
``` | 3 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the... | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,652,914,368 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 4,300,800 | import math
n,m,a=map(int,input().split())
x=math.ceil(int(n)/int(a))
y=math.ceil(int(m)/int(a))
z=x*y
print(z) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each ... | ```python
import math
n,m,a=map(int,input().split())
x=math.ceil(int(n)/int(a))
y=math.ceil(int(m)/int(a))
z=x*y
print(z)
``` | 3.968989 |
401 | A | Vanya and Cards | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each card doesn't exceed *x* in the absolute value.
Natasha doesn't like when Vanya spends a long time p... | The first line contains two integers: *n* (1<=≤<=*n*<=≤<=1000) — the number of found cards and *x* (1<=≤<=*x*<=≤<=1000) — the maximum absolute value of the number on a card. The second line contains *n* space-separated integers — the numbers on found cards. It is guaranteed that the numbers do not exceed *x* in their a... | Print a single number — the answer to the problem. | [
"3 2\n-1 1 2\n",
"2 3\n-2 -2\n"
] | [
"1\n",
"2\n"
] | In the first sample, Vanya needs to find a single card with number -2.
In the second sample, Vanya needs to find two cards with number 2. He can't find a single card with the required number as the numbers on the lost cards do not exceed 3 in their absolute value. | 500 | [
{
"input": "3 2\n-1 1 2",
"output": "1"
},
{
"input": "2 3\n-2 -2",
"output": "2"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
},
{
"input": "2 2\n-1 -1",
"output": "1"
},
{
"input": "15 5\n-2 -1 2 -4 -3 4 -4 -2 -2 2 -2 -1 1 -4 -2",
"output": "4"
},
{
"... | 1,658,105,020 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 47 | 62 | 0 | import sys
input = sys.stdin.readline
n, x = map(int, input().split())
data = list(map(int, input().split()))
print((abs(sum(data)) + x - 1) // x) | Title: Vanya and Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each... | ```python
import sys
input = sys.stdin.readline
n, x = map(int, input().split())
data = list(map(int, input().split()))
print((abs(sum(data)) + x - 1) // x)
``` | 3 | |
724 | A | Checking the Calendar | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | You are given names of two days of the week.
Please, determine whether it is possible that during some non-leap year the first day of some month was equal to the first day of the week you are given, while the first day of the next month was equal to the second day of the week you are given. Both months should belong t... | The input consists of two lines, each of them containing the name of exactly one day of the week. It's guaranteed that each string in the input is from the set "monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday". | Print "YES" (without quotes) if such situation is possible during some non-leap year. Otherwise, print "NO" (without quotes). | [
"monday\ntuesday\n",
"sunday\nsunday\n",
"saturday\ntuesday\n"
] | [
"NO\n",
"YES\n",
"YES\n"
] | In the second sample, one can consider February 1 and March 1 of year 2015. Both these days were Sundays.
In the third sample, one can consider July 1 and August 1 of year 2017. First of these two days is Saturday, while the second one is Tuesday. | 500 | [
{
"input": "monday\ntuesday",
"output": "NO"
},
{
"input": "sunday\nsunday",
"output": "YES"
},
{
"input": "saturday\ntuesday",
"output": "YES"
},
{
"input": "tuesday\nthursday",
"output": "YES"
},
{
"input": "friday\nwednesday",
"output": "NO"
},
{
"i... | 1,475,929,907 | 1,007 | Python 3 | OK | TESTS | 68 | 62 | 4,608,000 | months = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
days = ["monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday"]
d1 = str(input())
d2 = str(input())
n = days.index(d1)
b = False
for m in months:
if days[(m + n) % 7] == d2:
b = True
break
print("YES" if b else "NO")
| Title: Checking the Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given names of two days of the week.
Please, determine whether it is possible that during some non-leap year the first day of some month was equal to the first day of the week you are given, while the fir... | ```python
months = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
days = ["monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday"]
d1 = str(input())
d2 = str(input())
n = days.index(d1)
b = False
for m in months:
if days[(m + n) % 7] == d2:
b = True
break
print("YES" if b els... | 3 | |
552 | A | Vanya and Table | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vanya chose *n* rectangles with sides that go along borders of squares (some rectangles probably occur mu... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of rectangles.
Each of the following *n* lines contains four integers *x*1,<=*y*1,<=*x*2,<=*y*2 (1<=≤<=*x*1<=≤<=*x*2<=≤<=100, 1<=≤<=*y*1<=≤<=*y*2<=≤<=100), where *x*1 and *y*1 are the number of the column and row of the lower left cell and *x*2 and *... | In a single line print the sum of all values in the cells of the table. | [
"2\n1 1 2 3\n2 2 3 3\n",
"2\n1 1 3 3\n1 1 3 3\n"
] | [
"10\n",
"18\n"
] | Note to the first sample test:
Values of the table in the first three rows and columns will be as follows:
121
121
110
So, the sum of values will be equal to 10.
Note to the second sample test:
Values of the table in the first three rows and columns will be as follows:
222
222
222
So, the sum of values will ... | 500 | [
{
"input": "2\n1 1 2 3\n2 2 3 3",
"output": "10"
},
{
"input": "2\n1 1 3 3\n1 1 3 3",
"output": "18"
},
{
"input": "5\n4 11 20 15\n7 5 12 20\n10 8 16 12\n7 5 12 15\n2 2 20 13",
"output": "510"
},
{
"input": "5\n4 11 20 20\n6 11 20 16\n5 2 19 15\n11 3 18 15\n3 2 14 11",
"o... | 1,627,142,365 | 2,147,483,647 | PyPy 3 | OK | TESTS | 26 | 108 | 20,172,800 | import math
def main_function():
input_data = [[int(l) for l in input().split(" ")] for i in range(int(input()))]
sums = 0
for i in input_data:
sums += abs(i[3] - i[1] + 1) * abs(i[2] - i[0] + 1)
print(sums)
main_function() | Title: Vanya and Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right.
In this table, Vany... | ```python
import math
def main_function():
input_data = [[int(l) for l in input().split(" ")] for i in range(int(input()))]
sums = 0
for i in input_data:
sums += abs(i[3] - i[1] + 1) * abs(i[2] - i[0] + 1)
print(sums)
main_function()
``` | 3 | |
194 | A | Exams | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | One day the Codeforces round author sat exams. He had *n* exams and he needed to get an integer from 2 to 5 for each exam. He will have to re-sit each failed exam, i.e. the exam that gets mark 2.
The author would need to spend too much time and effort to make the sum of his marks strictly more than *k*. That could ha... | The single input line contains space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=250) — the number of exams and the required sum of marks.
It is guaranteed that there exists a way to pass *n* exams in the way that makes the sum of marks equal exactly *k*. | Print the single number — the minimum number of exams that the author will get a 2 for, considering that the sum of marks for all exams must equal *k*. | [
"4 8\n",
"4 10\n",
"1 3\n"
] | [
"4\n",
"2\n",
"0\n"
] | In the first sample the author has to get a 2 for all his exams.
In the second sample he should get a 3 for two exams and a 2 for two more.
In the third sample he should get a 3 for one exam. | 500 | [
{
"input": "4 8",
"output": "4"
},
{
"input": "4 10",
"output": "2"
},
{
"input": "1 3",
"output": "0"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "50 234",
"output": "0"
},
{
"input": "50 100",
"... | 1,651,556,747 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 38 | 124 | 0 | n,k = map(int,input().split())
if k<3*n:
ans = (3*n) - k
else:
ans = 0
print(ans) | Title: Exams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day the Codeforces round author sat exams. He had *n* exams and he needed to get an integer from 2 to 5 for each exam. He will have to re-sit each failed exam, i.e. the exam that gets mark 2.
The author would need to spend ... | ```python
n,k = map(int,input().split())
if k<3*n:
ans = (3*n) - k
else:
ans = 0
print(ans)
``` | 3 | |
982 | B | Bus of Characters | PROGRAMMING | 1,300 | [
"data structures",
"greedy",
"implementation"
] | null | null | In the Bus of Characters there are $n$ rows of seat, each having $2$ seats. The width of both seats in the $i$-th row is $w_i$ centimeters. All integers $w_i$ are distinct.
Initially the bus is empty. On each of $2n$ stops one passenger enters the bus. There are two types of passengers:
- an introvert always choose... | The first line contains a single integer $n$ ($1 \le n \le 200\,000$) — the number of rows in the bus.
The second line contains the sequence of integers $w_1, w_2, \dots, w_n$ ($1 \le w_i \le 10^{9}$), where $w_i$ is the width of each of the seats in the $i$-th row. It is guaranteed that all $w_i$ are distinct.
The t... | Print $2n$ integers — the rows the passengers will take. The order of passengers should be the same as in input. | [
"2\n3 1\n0011\n",
"6\n10 8 9 11 13 5\n010010011101\n"
] | [
"2 1 1 2 \n",
"6 6 2 3 3 1 4 4 1 2 5 5 \n"
] | In the first example the first passenger (introvert) chooses the row $2$, because it has the seats with smallest width. The second passenger (introvert) chooses the row $1$, because it is the only empty row now. The third passenger (extrovert) chooses the row $1$, because it has exactly one occupied seat and the seat w... | 1,000 | [
{
"input": "2\n3 1\n0011",
"output": "2 1 1 2 "
},
{
"input": "6\n10 8 9 11 13 5\n010010011101",
"output": "6 6 2 3 3 1 4 4 1 2 5 5 "
},
{
"input": "1\n1\n01",
"output": "1 1 "
},
{
"input": "1\n1000000\n01",
"output": "1 1 "
},
{
"input": "2\n1 1000000\n0011",
... | 1,538,748,424 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 27,238,400 | n = int(input())
w = input()
w = w.split()
p = input()
a = []
stack = []
dict = {}
for i in range(len(w)):
dict[w[i]] = i+1
w[i] = int(w[i])
w = sorted(w)
for i in p:
if i == '0':
m = w.pop(0)
stack.append(m)
a.append(m)
elif i == '1':
a.append(stack.... | Title: Bus of Characters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the Bus of Characters there are $n$ rows of seat, each having $2$ seats. The width of both seats in the $i$-th row is $w_i$ centimeters. All integers $w_i$ are distinct.
Initially the bus is empty. On each of $2n$... | ```python
n = int(input())
w = input()
w = w.split()
p = input()
a = []
stack = []
dict = {}
for i in range(len(w)):
dict[w[i]] = i+1
w[i] = int(w[i])
w = sorted(w)
for i in p:
if i == '0':
m = w.pop(0)
stack.append(m)
a.append(m)
elif i == '1':
a.app... | 0 | |
108 | A | Palindromic Times | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | A. Palindromic Times | 2 | 256 | Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling asleep, he was staring at the digital watch around Saher's wrist. He noticed that the digits on th... | The first and only line of the input starts with a string with the format "HH:MM" where "HH" is from "00" to "23" and "MM" is from "00" to "59". Both "HH" and "MM" have exactly two digits. | Print the palindromic time of day that comes soonest after the time given in the input. If the input time is palindromic, output the soonest palindromic time after the input time. | [
"12:21\n",
"23:59\n"
] | [
"13:31\n",
"00:00\n"
] | none | 500 | [
{
"input": "12:21",
"output": "13:31"
},
{
"input": "23:59",
"output": "00:00"
},
{
"input": "15:51",
"output": "20:02"
},
{
"input": "10:44",
"output": "11:11"
},
{
"input": "04:02",
"output": "04:40"
},
{
"input": "02:11",
"output": "02:20"
},
... | 1,600,324,089 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 280 | 0 | n=input()
h=n[:2]
m=n[3:]
rh=h[::-1]
m=int(m)
if(int(m)<int(rh)):
ans=(h)+':'+(rh)
print(ans)
else:
while(1):
if(int(h)<23):
if(int(h[0])==0):
if(int(h[1]==9)):
h='10'
else:
h='0'+str(int(h[1])+1)
... | Title: Palindromic Times
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling... | ```python
n=input()
h=n[:2]
m=n[3:]
rh=h[::-1]
m=int(m)
if(int(m)<int(rh)):
ans=(h)+':'+(rh)
print(ans)
else:
while(1):
if(int(h)<23):
if(int(h[0])==0):
if(int(h[1]==9)):
h='10'
else:
h='0'+str(int(h... | 0 |
197 | A | Plate Game | PROGRAMMING | 1,600 | [
"constructive algorithms",
"games",
"math"
] | null | null | You've got a rectangular table with length *a* and width *b* and the infinite number of plates of radius *r*. Two players play the following game: they take turns to put the plates on the table so that the plates don't lie on each other (but they can touch each other), and so that any point on any plate is located with... | A single line contains three space-separated integers *a*, *b*, *r* (1<=≤<=*a*,<=*b*,<=*r*<=≤<=100) — the table sides and the plates' radius, correspondingly. | If wins the player who moves first, print "First" (without the quotes). Otherwise print "Second" (without the quotes). | [
"5 5 2\n",
"6 7 4\n"
] | [
"First\n",
"Second\n"
] | In the first sample the table has place for only one plate. The first player puts a plate on the table, the second player can't do that and loses.
In the second sample the table is so small that it doesn't have enough place even for one plate. So the first player loses without making a single move. | 1,000 | [
{
"input": "5 5 2",
"output": "First"
},
{
"input": "6 7 4",
"output": "Second"
},
{
"input": "100 100 1",
"output": "First"
},
{
"input": "1 1 100",
"output": "Second"
},
{
"input": "13 7 3",
"output": "First"
},
{
"input": "23 7 3",
"output": "Fi... | 1,589,615,608 | 2,147,483,647 | PyPy 3 | OK | TESTS | 95 | 280 | 20,172,800 | from math import *
x,y,r=map(int,input().split())
r=r*2
if(r>min(x,y)):
print("Second")
else:
print("First")
| Title: Plate Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular table with length *a* and width *b* and the infinite number of plates of radius *r*. Two players play the following game: they take turns to put the plates on the table so that the plates don't lie o... | ```python
from math import *
x,y,r=map(int,input().split())
r=r*2
if(r>min(x,y)):
print("Second")
else:
print("First")
``` | 3 | |
394 | A | Counting Sticks | PROGRAMMING | 0 | [
"brute force",
"implementation"
] | null | null | When new students come to the Specialized Educational and Scientific Centre (SESC) they need to start many things from the beginning. Sometimes the teachers say (not always unfairly) that we cannot even count. So our teachers decided to teach us arithmetics from the start. And what is the best way to teach students add... | The single line contains the initial expression. It is guaranteed that the expression looks like *A*<=+<=*B*<==<=*C*, where 1<=≤<=*A*,<=*B*,<=*C*<=≤<=100. | If there isn't a way to shift the stick so the expression becomes correct, print on a single line "Impossible" (without the quotes). If there is a way, print the resulting expression. Follow the format of the output from the test samples. Don't print extra space characters.
If there are multiple correct answers, print... | [
"||+|=|||||\n",
"|||||+||=||\n",
"|+|=||||||\n",
"||||+||=||||||\n"
] | [
"|||+|=||||\n",
"Impossible\n",
"Impossible\n",
"||||+||=||||||\n"
] | In the first sample we can shift stick from the third group of sticks to the first one.
In the second sample we cannot shift vertical stick from + sign to the second group of sticks. So we cannot make a - sign.
There is no answer in the third sample because we cannot remove sticks from the expression.
In the forth s... | 500 | [
{
"input": "||+|=|||||",
"output": "|||+|=||||"
},
{
"input": "|||||+||=||",
"output": "Impossible"
},
{
"input": "|+|=||||||",
"output": "Impossible"
},
{
"input": "||||+||=||||||",
"output": "||||+||=||||||"
},
{
"input": "||||||||||||+|||||||||||=||||||||||||||... | 1,586,171,528 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | string = input()
s1 = ""
s2 = ""
s3 = ""
x = 0,y = 0
for i in range(len(string)):
if(string[i] == '+'):
x = i
if(string[i] == '='):
y = i
s1 = string[0:y]
s2 = string[y+1:x]
s3 = string[x+1:]
if(s1+s2==s3):
print(string)
else:
s1 = s1+s3[0]
if(s1+s2!=s3):
pr... | Title: Counting Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When new students come to the Specialized Educational and Scientific Centre (SESC) they need to start many things from the beginning. Sometimes the teachers say (not always unfairly) that we cannot even count. So our te... | ```python
string = input()
s1 = ""
s2 = ""
s3 = ""
x = 0,y = 0
for i in range(len(string)):
if(string[i] == '+'):
x = i
if(string[i] == '='):
y = i
s1 = string[0:y]
s2 = string[y+1:x]
s3 = string[x+1:]
if(s1+s2==s3):
print(string)
else:
s1 = s1+s3[0]
if(s1+s2!=s3):
... | -1 | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,688,997,821 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n;k=map(int,input().split())
t=240-k
r=0
for i in range:
if t=>(5*i):
t=-5
r=r+1
else:
break
print(r) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
n;k=map(int,input().split())
t=240-k
r=0
for i in range:
if t=>(5*i):
t=-5
r=r+1
else:
break
print(r)
``` | -1 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,696,914,502 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 62 | 0 | st = input()
st = st.replace('--','2')
st = st.replace('-.','1')
st = st.replace('.','0')
print(st) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
st = input()
st = st.replace('--','2')
st = st.replace('-.','1')
st = st.replace('.','0')
print(st)
``` | 3.9845 |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,664,354,822 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 124 | 0 |
def string():
return(list(input().split()))
s=string()
l=0
n=len(s[0])
for x in s[0]:
if x.islower():
l+=1
if l>=(n-l):
print(s[0].lower())
else:
print(s[0].upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
def string():
return(list(input().split()))
s=string()
l=0
n=len(s[0])
for x in s[0]:
if x.islower():
l+=1
if l>=(n-l):
print(s[0].lower())
else:
print(s[0].upper())
``` | 3.969 |
205 | B | Little Elephant and Sorting | PROGRAMMING | 1,400 | [
"brute force",
"greedy"
] | null | null | The Little Elephant loves sortings.
He has an array *a* consisting of *n* integers. Let's number the array elements from 1 to *n*, then the *i*-th element will be denoted as *a**i*. The Little Elephant can make one move to choose an arbitrary pair of integers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) and increase *a**i*... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the size of array *a*. The next line contains *n* integers, separated by single spaces — array *a* (1<=≤<=*a**i*<=≤<=109). The array elements are listed in the line in the order of their index's increasing. | In a single line print a single integer — the answer to the problem.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"3\n1 2 3\n",
"3\n3 2 1\n",
"4\n7 4 1 47\n"
] | [
"0\n",
"2\n",
"6\n"
] | In the first sample the array is already sorted in the non-decreasing order, so the answer is 0.
In the second sample you need to perform two operations: first increase numbers from second to third (after that the array will be: [3, 3, 2]), and second increase only the last element (the array will be: [3, 3, 3]).
In ... | 1,000 | [
{
"input": "3\n1 2 3",
"output": "0"
},
{
"input": "3\n3 2 1",
"output": "2"
},
{
"input": "4\n7 4 1 47",
"output": "6"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 1000000000",
"output": "0"
},
{
"input": "10\n1000000000 1 1000000000 1 1000000000 1 1000000000 1 100000000... | 1,567,252,885 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 248 | 13,107,200 | n=int(input())
a=list(map(int,input().rstrip().split()))
carry=0
oper=0
for i in range(1,n):
a[i]=a[i]+carry
if a[i]<a[i-1]:
carry+=abs(a[i-1]-a[i])
oper+=abs(a[i-1]-a[i])
a[i]=a[i-1]
#print(a)
print(oper)
| Title: Little Elephant and Sorting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves sortings.
He has an array *a* consisting of *n* integers. Let's number the array elements from 1 to *n*, then the *i*-th element will be denoted as *a**i*. The Little Elephant can ... | ```python
n=int(input())
a=list(map(int,input().rstrip().split()))
carry=0
oper=0
for i in range(1,n):
a[i]=a[i]+carry
if a[i]<a[i-1]:
carry+=abs(a[i-1]-a[i])
oper+=abs(a[i-1]-a[i])
a[i]=a[i-1]
#print(a)
print(oper)
``` | 3 |
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