contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
545 | C | Woodcutters | PROGRAMMING | 1,500 | [
"dp",
"greedy"
] | null | null | Little Susie listens to fairy tales before bed every day. Today's fairy tale was about wood cutters and the little girl immediately started imagining the choppers cutting wood. She imagined the situation that is described below.
There are *n* trees located along the road at points with coordinates *x*1,<=*x*2,<=...,<=... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of trees.
Next *n* lines contain pairs of integers *x**i*,<=*h**i* (1<=≤<=*x**i*,<=*h**i*<=≤<=109) — the coordinate and the height of the *і*-th tree.
The pairs are given in the order of ascending *x**i*. No two trees are located at the point with t... | Print a single number — the maximum number of trees that you can cut down by the given rules. | [
"5\n1 2\n2 1\n5 10\n10 9\n19 1\n",
"5\n1 2\n2 1\n5 10\n10 9\n20 1\n"
] | [
"3\n",
"4\n"
] | In the first sample you can fell the trees like that:
- fell the 1-st tree to the left — now it occupies segment [ - 1;1] - fell the 2-nd tree to the right — now it occupies segment [2;3] - leave the 3-rd tree — it occupies point 5 - leave the 4-th tree — it occupies point 10 - fell the 5-th tree to the right — ... | 1,750 | [
{
"input": "5\n1 2\n2 1\n5 10\n10 9\n19 1",
"output": "3"
},
{
"input": "5\n1 2\n2 1\n5 10\n10 9\n20 1",
"output": "4"
},
{
"input": "4\n10 4\n15 1\n19 3\n20 1",
"output": "4"
},
{
"input": "35\n1 7\n3 11\n6 12\n7 6\n8 5\n9 11\n15 3\n16 10\n22 2\n23 3\n25 7\n27 3\n34 5\n35 10... | 1,667,002,006 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | list1= []
d=2
e=[]
f=[]
for i in range(n):
a,b = map(int,input().split())
list1.append((a,b))
for i in range(n):
if i >0 and i<n:
k = list1[i][0]-list1[i-1][0]
e.append(k)
for i in range(n):
if i >0 and i<n-1:
if list1[i][1]<e[i-1]:
d+=1
elif li... | Title: Woodcutters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Susie listens to fairy tales before bed every day. Today's fairy tale was about wood cutters and the little girl immediately started imagining the choppers cutting wood. She imagined the situation that is described b... | ```python
list1= []
d=2
e=[]
f=[]
for i in range(n):
a,b = map(int,input().split())
list1.append((a,b))
for i in range(n):
if i >0 and i<n:
k = list1[i][0]-list1[i-1][0]
e.append(k)
for i in range(n):
if i >0 and i<n-1:
if list1[i][1]<e[i-1]:
d+=1
... | -1 | |
598 | A | Tricky Sum | PROGRAMMING | 900 | [
"math"
] | null | null | In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, because 1, 2 and 4 are 20, 21 and 22 respectively.
Calculate the answer for *t* values of *n*. | The first line of the input contains a single integer *t* (1<=≤<=*t*<=≤<=100) — the number of values of *n* to be processed.
Each of next *t* lines contains a single integer *n* (1<=≤<=*n*<=≤<=109). | Print the requested sum for each of *t* integers *n* given in the input. | [
"2\n4\n1000000000\n"
] | [
"-4\n499999998352516354\n"
] | The answer for the first sample is explained in the statement. | 0 | [
{
"input": "2\n4\n1000000000",
"output": "-4\n499999998352516354"
},
{
"input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "-1\n-3\n0\n-4\n1\n7\n14\n6\n15\n25"
},
{
"input": "10\n10\n9\n47\n33\n99\n83\n62\n1\n100\n53",
"output": "25\n15\n1002\n435\n4696\n3232\n1827\n-1\n4796\n130... | 1,695,607,351 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 21 | 62 | 1,433,600 | tc = int(input())
for _ in range(tc):
n = int(input())
ssum = n*(n+1)//2
i = 1
while i <= n:
ssum-=2*i
i<<=1
print(ssum) | Title: Tricky Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, be... | ```python
tc = int(input())
for _ in range(tc):
n = int(input())
ssum = n*(n+1)//2
i = 1
while i <= n:
ssum-=2*i
i<<=1
print(ssum)
``` | 3 | |
35 | A | Shell Game | PROGRAMMING | 1,000 | [
"implementation"
] | A. Shell Game | 2 | 64 | Today the «Z» city residents enjoy a shell game competition. The residents are gathered on the main square to watch the breath-taking performance. The performer puts 3 non-transparent cups upside down in a row. Then he openly puts a small ball under one of the cups and starts to shuffle the cups around very quickly so ... | The first input line contains an integer from 1 to 3 — index of the cup which covers the ball before the shuffles. The following three lines describe the shuffles. Each description of a shuffle contains two distinct integers from 1 to 3 — indexes of the cups which the performer shuffled this time. The cups are numbered... | In the first line output an integer from 1 to 3 — index of the cup which will have the ball after all the shuffles. | [
"1\n1 2\n2 1\n2 1\n",
"1\n2 1\n3 1\n1 3\n"
] | [
"2\n",
"2\n"
] | none | 500 | [
{
"input": "1\n1 2\n2 1\n2 1",
"output": "2"
},
{
"input": "1\n2 1\n3 1\n1 3",
"output": "2"
},
{
"input": "3\n3 1\n2 1\n1 2",
"output": "1"
},
{
"input": "1\n1 3\n1 2\n2 3",
"output": "2"
},
{
"input": "3\n3 2\n3 1\n3 1",
"output": "2"
},
{
"input": "... | 1,550,327,453 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 0 | n = input()
inp = open("input.txt", 'r')
oup = open("output.txt", 'W')
for _ in range(3):
s = inp.read().split()
if n == s[0]:
n = s[1]
elif n == s[1]:
n = s[0]
oup.write(n)
inp.close()
oup.close()
| Title: Shell Game
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Today the «Z» city residents enjoy a shell game competition. The residents are gathered on the main square to watch the breath-taking performance. The performer puts 3 non-transparent cups upside down in a row. Then he openly put... | ```python
n = input()
inp = open("input.txt", 'r')
oup = open("output.txt", 'W')
for _ in range(3):
s = inp.read().split()
if n == s[0]:
n = s[1]
elif n == s[1]:
n = s[0]
oup.write(n)
inp.close()
oup.close()
``` | -1 |
903 | A | Hungry Student Problem | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chunks; a large one — 7 chunks. Ivan wants to eat exactly *x* chunks. Now he wonders whether he can buy exactly ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of testcases.
The *i*-th of the following *n* lines contains one integer *x**i* (1<=≤<=*x**i*<=≤<=100) — the number of chicken chunks Ivan wants to eat. | Print *n* lines, in *i*-th line output YES if Ivan can buy exactly *x**i* chunks. Otherwise, print NO. | [
"2\n6\n5\n"
] | [
"YES\nNO\n"
] | In the first example Ivan can buy two small portions.
In the second example Ivan cannot buy exactly 5 chunks, since one small portion is not enough, but two small portions or one large is too much. | 0 | [
{
"input": "2\n6\n5",
"output": "YES\nNO"
},
{
"input": "100\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n16\n17\n18\n19\n20\n21\n22\n23\n24\n25\n26\n27\n28\n29\n30\n31\n32\n33\n34\n35\n36\n37\n38\n39\n40\n41\n42\n43\n44\n45\n46\n47\n48\n49\n50\n51\n52\n53\n54\n55\n56\n57\n58\n59\n60\n61\n62\... | 1,631,759,896 | 2,147,483,647 | PyPy 3 | OK | TESTS | 8 | 109 | 20,172,800 | for _ in range(int(input())):
print('NO') if int(input()) in (1, 2, 4, 5, 8, 11) else print('YES')
| Title: Hungry Student Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chun... | ```python
for _ in range(int(input())):
print('NO') if int(input()) in (1, 2, 4, 5, 8, 11) else print('YES')
``` | 3 | |
978 | A | Remove Duplicates | PROGRAMMING | 800 | [
"implementation"
] | null | null | Petya has an array $a$ consisting of $n$ integers. He wants to remove duplicate (equal) elements.
Petya wants to leave only the rightmost entry (occurrence) for each element of the array. The relative order of the remaining unique elements should not be changed. | The first line contains a single integer $n$ ($1 \le n \le 50$) — the number of elements in Petya's array.
The following line contains a sequence $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 1\,000$) — the Petya's array. | In the first line print integer $x$ — the number of elements which will be left in Petya's array after he removed the duplicates.
In the second line print $x$ integers separated with a space — Petya's array after he removed the duplicates. For each unique element only the rightmost entry should be left. | [
"6\n1 5 5 1 6 1\n",
"5\n2 4 2 4 4\n",
"5\n6 6 6 6 6\n"
] | [
"3\n5 6 1 \n",
"2\n2 4 \n",
"1\n6 \n"
] | In the first example you should remove two integers $1$, which are in the positions $1$ and $4$. Also you should remove the integer $5$, which is in the position $2$.
In the second example you should remove integer $2$, which is in the position $1$, and two integers $4$, which are in the positions $2$ and $4$.
In the... | 0 | [
{
"input": "6\n1 5 5 1 6 1",
"output": "3\n5 6 1 "
},
{
"input": "5\n2 4 2 4 4",
"output": "2\n2 4 "
},
{
"input": "5\n6 6 6 6 6",
"output": "1\n6 "
},
{
"input": "7\n1 2 3 4 2 2 3",
"output": "4\n1 4 2 3 "
},
{
"input": "9\n100 100 100 99 99 99 100 100 100",
... | 1,681,819,669 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n=int(input())
for i in range(4):
a=list(map(int<input().split(' ')))
g=sum(a)
g=g//2
print(g) | Title: Remove Duplicates
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya has an array $a$ consisting of $n$ integers. He wants to remove duplicate (equal) elements.
Petya wants to leave only the rightmost entry (occurrence) for each element of the array. The relative order of the re... | ```python
n=int(input())
for i in range(4):
a=list(map(int<input().split(' ')))
g=sum(a)
g=g//2
print(g)
``` | -1 | |
272 | A | Dima and Friends | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single s... | In a single line print the answer to the problem. | [
"1\n1\n",
"1\n2\n",
"2\n3 5\n"
] | [
"3\n",
"2\n",
"3\n"
] | In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | 500 | [
{
"input": "1\n1",
"output": "3"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "1\n5",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "4"
},
{
"input": "... | 1,663,836,462 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n=int(input())
A=[int(x) for x in input().split()]
if sum(A)%(n+1)==0:
print(2)
else:
print(1) | Title: Dima and Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the... | ```python
n=int(input())
A=[int(x) for x in input().split()]
if sum(A)%(n+1)==0:
print(2)
else:
print(1)
``` | 0 | |
854 | A | Fraction | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"math"
] | null | null | Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive co... | In the only line of input there is an integer *n* (3<=≤<=*n*<=≤<=1000), the sum of numerator and denominator of the fraction. | Output two space-separated positive integers *a* and *b*, numerator and denominator of the maximum possible proper irreducible fraction satisfying the given sum. | [
"3\n",
"4\n",
"12\n"
] | [
"1 2\n",
"1 3\n",
"5 7\n"
] | none | 500 | [
{
"input": "3",
"output": "1 2"
},
{
"input": "4",
"output": "1 3"
},
{
"input": "12",
"output": "5 7"
},
{
"input": "34",
"output": "15 19"
},
{
"input": "13",
"output": "6 7"
},
{
"input": "11",
"output": "5 6"
},
{
"input": "24",
"ou... | 1,590,743,988 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | n=int(input())
if n==2:
print(1)
elif n%2==0:
print(n//2-2,n//2+2)
else:
print(n//2,n//2+1)
| Title: Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is cal... | ```python
n=int(input())
if n==2:
print(1)
elif n%2==0:
print(n//2-2,n//2+2)
else:
print(n//2,n//2+1)
``` | 0 | |
743 | B | Chloe and the sequence | PROGRAMMING | 1,200 | [
"binary search",
"bitmasks",
"constructive algorithms",
"implementation"
] | null | null | Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following algorithm of generating a sequence of integers. Initially we have a sequence consisting of a single element eq... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=2*n*<=-<=1). | Print single integer — the integer at the *k*-th position in the obtained sequence. | [
"3 2\n",
"4 8\n"
] | [
"2",
"4"
] | In the first sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1]. The number on the second position is 2.
In the second sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1, 4, 1, 2, 1, 3, 1, 2, 1]. The number on the eighth position is 4. | 1,000 | [
{
"input": "3 2",
"output": "2"
},
{
"input": "4 8",
"output": "4"
},
{
"input": "5 27",
"output": "1"
},
{
"input": "7 44",
"output": "3"
},
{
"input": "15 18432",
"output": "12"
},
{
"input": "20 259676",
"output": "3"
},
{
"input": "30 6... | 1,481,825,335 | 2,147,483,647 | Python 3 | MEMORY_LIMIT_EXCEEDED | TESTS | 6 | 265 | 268,390,400 | n,k=[int(a) for a in input().split()]
a=[1]
for i in range(1,n):
a=a+[i+1]+a
print(a[k-1]) | Title: Chloe and the sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following a... | ```python
n,k=[int(a) for a in input().split()]
a=[1]
for i in range(1,n):
a=a+[i+1]+a
print(a[k-1])
``` | 0 | |
149 | A | Business trip | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | null | null | What joy! Petya's parents went on a business trip for the whole year and the playful kid is left all by himself. Petya got absolutely happy. He jumped on the bed and threw pillows all day long, until...
Today Petya opened the cupboard and found a scary note there. His parents had left him with duties: he should water... | The first line contains exactly one integer *k* (0<=≤<=*k*<=≤<=100). The next line contains twelve space-separated integers: the *i*-th (1<=≤<=*i*<=≤<=12) number in the line represents *a**i* (0<=≤<=*a**i*<=≤<=100). | Print the only integer — the minimum number of months when Petya has to water the flower so that the flower grows no less than by *k* centimeters. If the flower can't grow by *k* centimeters in a year, print -1. | [
"5\n1 1 1 1 2 2 3 2 2 1 1 1\n",
"0\n0 0 0 0 0 0 0 1 1 2 3 0\n",
"11\n1 1 4 1 1 5 1 1 4 1 1 1\n"
] | [
"2\n",
"0\n",
"3\n"
] | Let's consider the first sample test. There it is enough to water the flower during the seventh and the ninth month. Then the flower grows by exactly five centimeters.
In the second sample Petya's parents will believe him even if the flower doesn't grow at all (*k* = 0). So, it is possible for Petya not to water the f... | 500 | [
{
"input": "5\n1 1 1 1 2 2 3 2 2 1 1 1",
"output": "2"
},
{
"input": "0\n0 0 0 0 0 0 0 1 1 2 3 0",
"output": "0"
},
{
"input": "11\n1 1 4 1 1 5 1 1 4 1 1 1",
"output": "3"
},
{
"input": "15\n20 1 1 1 1 2 2 1 2 2 1 1",
"output": "1"
},
{
"input": "7\n8 9 100 12 14 ... | 1,688,295,554 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 62 | 0 | def merge(left,right):
i,j=0,0
n=len(left)
m=len(right)
res=[]
while i<n and j<m:
if left[i]>right[j]:
res.append(left[i])
i+=1
else:
res.append(right[j])
j+=1
while i<n:
res.append(left[i])
i+=1
w... | Title: Business trip
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
What joy! Petya's parents went on a business trip for the whole year and the playful kid is left all by himself. Petya got absolutely happy. He jumped on the bed and threw pillows all day long, until...
Today Petya open... | ```python
def merge(left,right):
i,j=0,0
n=len(left)
m=len(right)
res=[]
while i<n and j<m:
if left[i]>right[j]:
res.append(left[i])
i+=1
else:
res.append(right[j])
j+=1
while i<n:
res.append(left[i])
i... | 0 | |
935 | A | Fafa and his Company | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* em... | The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company. | Print a single integer representing the answer to the problem. | [
"2\n",
"10\n"
] | [
"1\n",
"3\n"
] | In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | 500 | [
{
"input": "2",
"output": "1"
},
{
"input": "10",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "6",
"output": "3"
},
{
"input": "13",
"output": "1"
},
{
"input": "100000",
"output": "35"
... | 1,655,961,664 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 61 | 0 | n = int(input())
print(sum(n % l == 0 for l in range(1, n)))
| Title: Fafa and his Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the emp... | ```python
n = int(input())
print(sum(n % l == 0 for l in range(1, n)))
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where he is, because the monster that took him to the Upside Down will know and relocate him.
Thus, he came up with a puzzle to te... | The first and only line of input contains string *s*, consisting only of characters '(', ')' and '?' (2<=≤<=|*s*|<=≤<=5000). | Print the answer to Will's puzzle in the first and only line of output. | [
"((?))\n",
"??()??\n"
] | [
"4\n",
"7\n"
] | For the first sample testcase, the pretty substrings of *s* are:
1. "(?" which can be transformed to "()". 1. "?)" which can be transformed to "()". 1. "((?)" which can be transformed to "(())". 1. "(?))" which can be transformed to "(())".
For the second sample testcase, the pretty substrings of *s* are:
1. "?... | 0 | [
{
"input": "((?))",
"output": "4"
},
{
"input": "??()??",
"output": "7"
},
{
"input": "?????)(???",
"output": "21"
},
{
"input": "()()((?(()(((()()(())(((()((())))(()))(()(((((())))()))(((()()()))))))(((((()))))))))",
"output": "62"
},
{
"input": "))((()(()((((())... | 1,647,670,012 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 0 | import sys
def get_ints(): return map(int, sys.stdin.readline().strip().split())
def get_ls(): return list(map(int, sys.stdin.readline().strip().split()))
def main():
s = input()
ans, n = 0, len(s)
for i in range(n-1):
j, a, q = i, 0, 0
while j<n and a+q >=0:
a += s[j]... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where he is, because the monster that took... | ```python
import sys
def get_ints(): return map(int, sys.stdin.readline().strip().split())
def get_ls(): return list(map(int, sys.stdin.readline().strip().split()))
def main():
s = input()
ans, n = 0, len(s)
for i in range(n-1):
j, a, q = i, 0, 0
while j<n and a+q >=0:
... | 0 | |
868 | A | Bark to Unlock | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's p... | The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer *n* (1<=≤<=*n*<=≤<=100) — the number of words Kashtanka knows.
The next *n* lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to b... | Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"ya\n4\nah\noy\nto\nha\n",
"hp\n2\nht\ntp\n",
"ah\n1\nha\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" produ... | 250 | [
{
"input": "ya\n4\nah\noy\nto\nha",
"output": "YES"
},
{
"input": "hp\n2\nht\ntp",
"output": "NO"
},
{
"input": "ah\n1\nha",
"output": "YES"
},
{
"input": "bb\n4\nba\nab\naa\nbb",
"output": "YES"
},
{
"input": "bc\n4\nca\nba\nbb\ncc",
"output": "YES"
},
{
... | 1,554,179,638 | 2,147,483,647 | PyPy 3 | OK | TESTS | 90 | 140 | 0 | ##a = list(map(int, input().split()))
##print(' '.join(map(str, res)))
pw = input()
n = int(input())
w = list()
for _ in range(n):
w.append(input())
for _ in range(n):
if pw in w:
print('YES')
exit(0)
for i in range(n):
for j in range(n):
if w[i][1] == pw[0] and w[... | Title: Bark to Unlock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a passw... | ```python
##a = list(map(int, input().split()))
##print(' '.join(map(str, res)))
pw = input()
n = int(input())
w = list()
for _ in range(n):
w.append(input())
for _ in range(n):
if pw in w:
print('YES')
exit(0)
for i in range(n):
for j in range(n):
if w[i][1] == pw... | 3 | |
965 | C | Greedy Arkady | PROGRAMMING | 2,000 | [
"math"
] | null | null | $k$ people want to split $n$ candies between them. Each candy should be given to exactly one of them or be thrown away.
The people are numbered from $1$ to $k$, and Arkady is the first of them. To split the candies, Arkady will choose an integer $x$ and then give the first $x$ candies to himself, the next $x$ candies ... | The only line contains four integers $n$, $k$, $M$ and $D$ ($2 \le n \le 10^{18}$, $2 \le k \le n$, $1 \le M \le n$, $1 \le D \le \min{(n, 1000)}$, $M \cdot D \cdot k \ge n$) — the number of candies, the number of people, the maximum number of candies given to a person at once, the maximum number of times a person can ... | Print a single integer — the maximum possible number of candies Arkady can give to himself.
Note that it is always possible to choose some valid $x$. | [
"20 4 5 2\n",
"30 9 4 1\n"
] | [
"8\n",
"4\n"
] | In the first example Arkady should choose $x = 4$. He will give $4$ candies to himself, $4$ candies to the second person, $4$ candies to the third person, then $4$ candies to the fourth person and then again $4$ candies to himself. No person is given candies more than $2$ times, and Arkady receives $8$ candies in total... | 1,500 | [
{
"input": "20 4 5 2",
"output": "8"
},
{
"input": "30 9 4 1",
"output": "4"
},
{
"input": "2 2 1 1",
"output": "1"
},
{
"input": "42 20 5 29",
"output": "5"
},
{
"input": "1000000000000000000 135 1000000000000000 1000",
"output": "8325624421831635"
},
{
... | 1,524,680,847 | 3,147 | Python 3 | WRONG_ANSWER | PRETESTS | 4 | 62 | 7,065,600 | import math
n, k, M, D = map(int, input().split())
def f(x):
res = n // (x * k)
res = res + min(n % (x * k), 1)
res = res * x
return res
rg = M
lf = int(math.ceil(1.0 * n / (1.0 * k * D)))
while rg - lf > 1:
mid = (rg + lf) // 2
if f(mid) > f(mid + 1):
rg = mid
else:
lf = mid
res = f(lf)
fo... | Title: Greedy Arkady
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
$k$ people want to split $n$ candies between them. Each candy should be given to exactly one of them or be thrown away.
The people are numbered from $1$ to $k$, and Arkady is the first of them. To split the candies, Arka... | ```python
import math
n, k, M, D = map(int, input().split())
def f(x):
res = n // (x * k)
res = res + min(n % (x * k), 1)
res = res * x
return res
rg = M
lf = int(math.ceil(1.0 * n / (1.0 * k * D)))
while rg - lf > 1:
mid = (rg + lf) // 2
if f(mid) > f(mid + 1):
rg = mid
else:
lf = mid
res =... | 0 | |
400 | A | Inna and Choose Options | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There always is something to choose from! And now, instead of "Noughts and Crosses", Inna choose a very unusual upgrade of this game. The rules of the game are given below:
There is one person playing the game. Before the beginning of the game he puts 12 cards in a row on the table. Each card contains a character: "X"... | The first line of the input contains integer *t* (1<=≤<=*t*<=≤<=100). This value shows the number of sets of test data in the input. Next follows the description of each of the *t* tests on a separate line.
The description of each test is a string consisting of 12 characters, each character is either "X", or "O". The ... | For each test, print the answer to the test on a single line. The first number in the line must represent the number of distinct ways to choose the pair *a*,<=*b*. Next, print on this line the pairs in the format *a*x*b*. Print the pairs in the order of increasing first parameter (*a*). Separate the pairs in the line b... | [
"4\nOXXXOXOOXOOX\nOXOXOXOXOXOX\nXXXXXXXXXXXX\nOOOOOOOOOOOO\n"
] | [
"3 1x12 2x6 4x3\n4 1x12 2x6 3x4 6x2\n6 1x12 2x6 3x4 4x3 6x2 12x1\n0\n"
] | none | 500 | [
{
"input": "4\nOXXXOXOOXOOX\nOXOXOXOXOXOX\nXXXXXXXXXXXX\nOOOOOOOOOOOO",
"output": "3 1x12 2x6 4x3\n4 1x12 2x6 3x4 6x2\n6 1x12 2x6 3x4 4x3 6x2 12x1\n0"
},
{
"input": "2\nOOOOOOOOOOOO\nXXXXXXXXXXXX",
"output": "0\n6 1x12 2x6 3x4 4x3 6x2 12x1"
},
{
"input": "13\nXXXXXXXXXXXX\nXXXXXXXXXXXX\n... | 1,394,199,467 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 77 | 0 | t = int(input())
n = 12
while t > 0:
ans = []
t = t - 1
s = input()
for i in range(n):
r = i+1
if n%r != 0:
continue
c = n//r
flag = False
for j in range(c):
id = j
ff = False
while id < n:
... | Title: Inna and Choose Options
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There always is something to choose from! And now, instead of "Noughts and Crosses", Inna choose a very unusual upgrade of this game. The rules of the game are given below:
There is one person playing the game.... | ```python
t = int(input())
n = 12
while t > 0:
ans = []
t = t - 1
s = input()
for i in range(n):
r = i+1
if n%r != 0:
continue
c = n//r
flag = False
for j in range(c):
id = j
ff = False
while id < n:
... | 3 | |
673 | B | Problems for Round | PROGRAMMING | 1,300 | [
"greedy",
"implementation"
] | null | null | There are *n* problems prepared for the next Codeforces round. They are arranged in ascending order by their difficulty, and no two problems have the same difficulty. Moreover, there are *m* pairs of similar problems. Authors want to split problems between two division according to the following rules:
- Problemset ... | The first line of the input contains two integers *n* and *m* (2<=≤<=*n*<=≤<=100<=000, 0<=≤<=*m*<=≤<=100<=000) — the number of problems prepared for the round and the number of pairs of similar problems, respectively.
Each of the following *m* lines contains a pair of similar problems *u**i* and *v**i* (1<=≤<=*u**i*,<... | Print one integer — the number of ways to split problems in two divisions. | [
"5 2\n1 4\n5 2\n",
"3 3\n1 2\n2 3\n1 3\n",
"3 2\n3 1\n3 2\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first sample, problems 1 and 2 should be used in division 2, while problems 4 and 5 in division 1. Problem 3 may be used either in division 1 or in division 2.
In the second sample, all pairs of problems are similar and there is no way to split problem between two divisions without breaking any rules.
Third sa... | 750 | [
{
"input": "5 2\n1 4\n5 2",
"output": "2"
},
{
"input": "3 3\n1 2\n2 3\n1 3",
"output": "0"
},
{
"input": "3 2\n3 1\n3 2",
"output": "1"
},
{
"input": "2 0",
"output": "1"
},
{
"input": "2 1\n1 2",
"output": "1"
},
{
"input": "3 0",
"output": "2"
... | 1,621,285,552 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 92 | 0 | n,m=map(int,input().split())
l1=set()
l2=set()
for i in range(m):
k,t=sorted(map(int,input().split()))
l1.add(k)
l2.add(t)
if m == 0:
print(n-1)
else:
l3=set()
for i in l1:
l3.add(i)
for i in l2:
l3.add(i)
if len(l3) != len(l1)+len(l2):
print(0)
... | Title: Problems for Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* problems prepared for the next Codeforces round. They are arranged in ascending order by their difficulty, and no two problems have the same difficulty. Moreover, there are *m* pairs of similar problems... | ```python
n,m=map(int,input().split())
l1=set()
l2=set()
for i in range(m):
k,t=sorted(map(int,input().split()))
l1.add(k)
l2.add(t)
if m == 0:
print(n-1)
else:
l3=set()
for i in l1:
l3.add(i)
for i in l2:
l3.add(i)
if len(l3) != len(l1)+len(l2):
p... | 0 | |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,668,799,753 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | r,c = map(int,input().split())
v = 0
v1 = 0
f = []
for i in range(r):
n = input()
for j in n:
if 'S' in n:
continue
else:
f.append(j)
print((r*c)-len(f)) | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
r,c = map(int,input().split())
v = 0
v1 = 0
f = []
for i in range(r):
n = input()
for j in n:
if 'S' in n:
continue
else:
f.append(j)
print((r*c)-len(f))
``` | 0 | |
217 | A | Ice Skating | PROGRAMMING | 1,200 | [
"brute force",
"dfs and similar",
"dsu",
"graphs"
] | null | null | Bajtek is learning to skate on ice. He's a beginner, so his only mode of transportation is pushing off from a snow drift to the north, east, south or west and sliding until he lands in another snow drift. He has noticed that in this way it's impossible to get from some snow drifts to some other by any sequence of moves... | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of snow drifts. Each of the following *n* lines contains two integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=1000) — the coordinates of the *i*-th snow drift.
Note that the north direction coinсides with the direction of *Oy* ... | Output the minimal number of snow drifts that need to be created in order for Bajtek to be able to reach any snow drift from any other one. | [
"2\n2 1\n1 2\n",
"2\n2 1\n4 1\n"
] | [
"1\n",
"0\n"
] | none | 500 | [
{
"input": "2\n2 1\n1 2",
"output": "1"
},
{
"input": "2\n2 1\n4 1",
"output": "0"
},
{
"input": "24\n171 35\n261 20\n4 206\n501 446\n961 912\n581 748\n946 978\n463 514\n841 889\n341 466\n842 967\n54 102\n235 261\n925 889\n682 672\n623 636\n268 94\n635 710\n474 510\n697 794\n586 663\n182... | 1,591,036,966 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 186 | 307,200 | def mk_connections(u, graph, visited=None):
if visited is None:
visited = set()
visited.add(u)
for v in graph:
if graph[v] not in visited:
if graph[v][0] == u[0] or graph[v][1] == u[1]:
return mk_connections(graph[v], graph, visited)
return visited
n = in... | Title: Ice Skating
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bajtek is learning to skate on ice. He's a beginner, so his only mode of transportation is pushing off from a snow drift to the north, east, south or west and sliding until he lands in another snow drift. He has noticed tha... | ```python
def mk_connections(u, graph, visited=None):
if visited is None:
visited = set()
visited.add(u)
for v in graph:
if graph[v] not in visited:
if graph[v][0] == u[0] or graph[v][1] == u[1]:
return mk_connections(graph[v], graph, visited)
return visite... | 0 | |
339 | A | Helpful Maths | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings",
"strings"
] | null | null | Xenia the beginner mathematician is a third year student at elementary school. She is now learning the addition operation.
The teacher has written down the sum of multiple numbers. Pupils should calculate the sum. To make the calculation easier, the sum only contains numbers 1, 2 and 3. Still, that isn't enough for Xe... | The first line contains a non-empty string *s* — the sum Xenia needs to count. String *s* contains no spaces. It only contains digits and characters "+". Besides, string *s* is a correct sum of numbers 1, 2 and 3. String *s* is at most 100 characters long. | Print the new sum that Xenia can count. | [
"3+2+1\n",
"1+1+3+1+3\n",
"2\n"
] | [
"1+2+3\n",
"1+1+1+3+3\n",
"2\n"
] | none | 500 | [
{
"input": "3+2+1",
"output": "1+2+3"
},
{
"input": "1+1+3+1+3",
"output": "1+1+1+3+3"
},
{
"input": "2",
"output": "2"
},
{
"input": "2+2+1+1+3",
"output": "1+1+2+2+3"
},
{
"input": "2+1+2+2+2+3+1+3+1+2",
"output": "1+1+1+2+2+2+2+2+3+3"
},
{
"input": ... | 1,699,556,952 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 21 | 124 | 0 | m = input().split('+')
ans = ''
for i in sorted(m):
ans += str(i) + '+'
print(ans[:len(ans) - 1]) | Title: Helpful Maths
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the beginner mathematician is a third year student at elementary school. She is now learning the addition operation.
The teacher has written down the sum of multiple numbers. Pupils should calculate the sum. To mak... | ```python
m = input().split('+')
ans = ''
for i in sorted(m):
ans += str(i) + '+'
print(ans[:len(ans) - 1])
``` | 3 | |
792 | C | Divide by Three | PROGRAMMING | 2,000 | [
"dp",
"greedy",
"math",
"number theory"
] | null | null | A positive integer number *n* is written on a blackboard. It consists of not more than 105 digits. You have to transform it into a beautiful number by erasing some of the digits, and you want to erase as few digits as possible.
The number is called beautiful if it consists of at least one digit, doesn't have leading z... | The first line of input contains *n* — a positive integer number without leading zeroes (1<=≤<=*n*<=<<=10100000). | Print one number — any beautiful number obtained by erasing as few as possible digits. If there is no answer, print <=-<=1. | [
"1033\n",
"10\n",
"11\n"
] | [
"33\n",
"0\n",
"-1\n"
] | In the first example it is enough to erase only the first digit to obtain a multiple of 3. But if we erase the first digit, then we obtain a number with a leading zero. So the minimum number of digits to be erased is two. | 0 | [
{
"input": "1033",
"output": "33"
},
{
"input": "10",
"output": "0"
},
{
"input": "11",
"output": "-1"
},
{
"input": "3",
"output": "3"
},
{
"input": "1",
"output": "-1"
},
{
"input": "117",
"output": "117"
},
{
"input": "518",
"output"... | 1,490,631,514 | 6,214 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 18 | 1,000 | 28,569,600 | from itertools import *
memDict = dict()
def ans(n):
str_n = str(n)
len_str_n = len(str_n)
return rec(n, str_n, len_str_n, len_str_n)[0]
def rec(n, str_n, len_str_n, max_mod):
global memDict
if n in memDict:
return memDict[n]
if n % 3 == 0:
return n, 0
... | Title: Divide by Three
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A positive integer number *n* is written on a blackboard. It consists of not more than 105 digits. You have to transform it into a beautiful number by erasing some of the digits, and you want to erase as few digits as p... | ```python
from itertools import *
memDict = dict()
def ans(n):
str_n = str(n)
len_str_n = len(str_n)
return rec(n, str_n, len_str_n, len_str_n)[0]
def rec(n, str_n, len_str_n, max_mod):
global memDict
if n in memDict:
return memDict[n]
if n % 3 == 0:
retu... | 0 | |
630 | A | Again Twenty Five! | PROGRAMMING | 800 | [
"number theory"
] | null | null | The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of *n* and get last two digits of the number. Yes, of course, *n* can be rather big, and one cannot find the power us... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=2·1018) — the power in which you need to raise number 5. | Output the last two digits of 5*n* without spaces between them. | [
"2\n"
] | [
"25"
] | none | 0 | [
{
"input": "2",
"output": "25"
},
{
"input": "7",
"output": "25"
},
{
"input": "1000000000000000000",
"output": "25"
},
{
"input": "2000000000000000000",
"output": "25"
},
{
"input": "987654321012345678",
"output": "25"
}
] | 1,698,570,611 | 2,147,483,647 | Python 3 | OK | TESTS | 5 | 31 | 0 | n = int(input())
print(25)
#complexity bigO(1)
| Title: Again Twenty Five!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of *n* and ge... | ```python
n = int(input())
print(25)
#complexity bigO(1)
``` | 3 | |
219 | A | k-String | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
You are given a string... | The first input line contains integer *k* (1<=≤<=*k*<=≤<=1000). The second line contains *s*, all characters in *s* are lowercase English letters. The string length *s* satisfies the inequality 1<=≤<=|*s*|<=≤<=1000, where |*s*| is the length of string *s*. | Rearrange the letters in string *s* in such a way that the result is a *k*-string. Print the result on a single output line. If there are multiple solutions, print any of them.
If the solution doesn't exist, print "-1" (without quotes). | [
"2\naazz\n",
"3\nabcabcabz\n"
] | [
"azaz\n",
"-1\n"
] | none | 500 | [
{
"input": "2\naazz",
"output": "azaz"
},
{
"input": "3\nabcabcabz",
"output": "-1"
},
{
"input": "1\na",
"output": "a"
},
{
"input": "2\nabba",
"output": "abab"
},
{
"input": "2\naaab",
"output": "-1"
},
{
"input": "7\nabacaba",
"output": "-1"
}... | 1,675,080,308 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 92 | 0 | n=int(input())
s=input()
d={}
for i in s:
if i in d:
d[i]=d[i]+1
else:
d[i]=1
if any(i!=n for i in d.values()):
print(-1)
exit()
ans = ''
for i in d.keys():
ans += i
print(ans*n) | Title: k-String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a ... | ```python
n=int(input())
s=input()
d={}
for i in s:
if i in d:
d[i]=d[i]+1
else:
d[i]=1
if any(i!=n for i in d.values()):
print(-1)
exit()
ans = ''
for i in d.keys():
ans += i
print(ans*n)
``` | 0 | |
780 | B | The Meeting Place Cannot Be Changed | PROGRAMMING | 1,600 | [
"binary search"
] | null | null | The main road in Bytecity is a straight line from south to north. Conveniently, there are coordinates measured in meters from the southernmost building in north direction.
At some points on the road there are *n* friends, and *i*-th of them is standing at the point *x**i* meters and can move with any speed no greater ... | The first line contains single integer *n* (2<=≤<=*n*<=≤<=60<=000) — the number of friends.
The second line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=109) — the current coordinates of the friends, in meters.
The third line contains *n* integers *v*1,<=*v*2,<=...,<=*v**n* (1<=≤<=*v**i*<=≤<=109... | Print the minimum time (in seconds) needed for all the *n* friends to meet at some point on the road.
Your answer will be considered correct, if its absolute or relative error isn't greater than 10<=-<=6. Formally, let your answer be *a*, while jury's answer be *b*. Your answer will be considered correct if holds. | [
"3\n7 1 3\n1 2 1\n",
"4\n5 10 3 2\n2 3 2 4\n"
] | [
"2.000000000000\n",
"1.400000000000\n"
] | In the first sample, all friends can gather at the point 5 within 2 seconds. In order to achieve this, the first friend should go south all the time at his maximum speed, while the second and the third friends should go north at their maximum speeds. | 1,000 | [
{
"input": "3\n7 1 3\n1 2 1",
"output": "2.000000000000"
},
{
"input": "4\n5 10 3 2\n2 3 2 4",
"output": "1.400000000000"
},
{
"input": "3\n1 1000000000 2\n1 2 1000000000",
"output": "333333332.999999999971"
},
{
"input": "2\n4 5\n10 8",
"output": "0.055555555556"
},
... | 1,671,819,826 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 46 | 171 | 15,462,400 | n = int(input())
x = list(map(int, input().split()))
v = list(map(int, input().split()))
def check(t):
# ...
left = 0
right = 10**9
for i in range(n):
leftT = x[i] - v[i] * t
rightT = x[i] + v[i] * t
if leftT > left:
left = leftT
if rightT < right:
right = rightT
if right > lef... | Title: The Meeting Place Cannot Be Changed
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The main road in Bytecity is a straight line from south to north. Conveniently, there are coordinates measured in meters from the southernmost building in north direction.
At some points on the road... | ```python
n = int(input())
x = list(map(int, input().split()))
v = list(map(int, input().split()))
def check(t):
# ...
left = 0
right = 10**9
for i in range(n):
leftT = x[i] - v[i] * t
rightT = x[i] + v[i] * t
if leftT > left:
left = leftT
if rightT < right:
right = rightT
if r... | 3 | |
588 | A | Duff and Meat | PROGRAMMING | 900 | [
"greedy"
] | null | null | Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her from there. In *i*-th day, they sell meat for *p**i* dollars per kilogram. Malek knows all numbers ... | The first line of input contains integer *n* (1<=≤<=*n*<=≤<=105), the number of days.
In the next *n* lines, *i*-th line contains two integers *a**i* and *p**i* (1<=≤<=*a**i*,<=*p**i*<=≤<=100), the amount of meat Duff needs and the cost of meat in that day. | Print the minimum money needed to keep Duff happy for *n* days, in one line. | [
"3\n1 3\n2 2\n3 1\n",
"3\n1 3\n2 1\n3 2\n"
] | [
"10\n",
"8\n"
] | In the first sample case: An optimal way would be to buy 1 kg on the first day, 2 kg on the second day and 3 kg on the third day.
In the second sample case: An optimal way would be to buy 1 kg on the first day and 5 kg (needed meat for the second and third day) on the second day. | 750 | [
{
"input": "3\n1 3\n2 2\n3 1",
"output": "10"
},
{
"input": "3\n1 3\n2 1\n3 2",
"output": "8"
},
{
"input": "1\n39 52",
"output": "2028"
},
{
"input": "2\n25 56\n94 17",
"output": "2998"
},
{
"input": "5\n39 21\n95 89\n73 90\n9 55\n85 32",
"output": "6321"
}... | 1,625,077,803 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 420 | 1,945,600 | n = int(input())
p = []
a = []
ans = 0
for j in range(n):
c, b = map(int, input().split())
p.append(b)
a.append(c)
price = 1000000000
for i in range(n):
price = min(price, p[i])
ans += a[i] * price
print(ans)
| Title: Duff and Meat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her ... | ```python
n = int(input())
p = []
a = []
ans = 0
for j in range(n):
c, b = map(int, input().split())
p.append(b)
a.append(c)
price = 1000000000
for i in range(n):
price = min(price, p[i])
ans += a[i] * price
print(ans)
``` | 3 | |
467 | A | George and Accommodation | PROGRAMMING | 800 | [
"implementation"
] | null | null | George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want to live in the same room. The dormitory has *n* rooms in total. At the moment the *i*-th room has *p**i* peopl... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of rooms.
The *i*-th of the next *n* lines contains two integers *p**i* and *q**i* (0<=≤<=*p**i*<=≤<=*q**i*<=≤<=100) — the number of people who already live in the *i*-th room and the room's capacity. | Print a single integer — the number of rooms where George and Alex can move in. | [
"3\n1 1\n2 2\n3 3\n",
"3\n1 10\n0 10\n10 10\n"
] | [
"0\n",
"2\n"
] | none | 500 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "0"
},
{
"input": "3\n1 10\n0 10\n10 10",
"output": "2"
},
{
"input": "2\n36 67\n61 69",
"output": "2"
},
{
"input": "3\n21 71\n10 88\n43 62",
"output": "3"
},
{
"input": "3\n1 2\n2 3\n3 4",
"output": "0"
},
{
"... | 1,694,362,122 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 46 | 0 | n = input()
n = int(n)
x = 0
for i in range(n):
p, q = input().split()
p = int(p)
q = int(q)
if q - p >= 2:
x = x + 1
print(x)
| Title: George and Accommodation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want ... | ```python
n = input()
n = int(n)
x = 0
for i in range(n):
p, q = input().split()
p = int(p)
q = int(q)
if q - p >= 2:
x = x + 1
print(x)
``` | 3 | |
139 | A | Petr and Book | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. S... | The first input line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of pages in the book.
The second line contains seven non-negative space-separated integers that do not exceed 1000 — those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and... | Print a single number — the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. | [
"100\n15 20 20 15 10 30 45\n",
"2\n1 0 0 0 0 0 0\n"
] | [
"6\n",
"1\n"
] | Note to the first sample:
By the end of Monday and therefore, by the beginning of Tuesday Petr has 85 pages left. He has 65 pages left by Wednesday, 45 by Thursday, 30 by Friday, 20 by Saturday and on Saturday Petr finishes reading the book (and he also has time to read 10 pages of something else).
Note to the second... | 500 | [
{
"input": "100\n15 20 20 15 10 30 45",
"output": "6"
},
{
"input": "2\n1 0 0 0 0 0 0",
"output": "1"
},
{
"input": "100\n100 200 100 200 300 400 500",
"output": "1"
},
{
"input": "3\n1 1 1 1 1 1 1",
"output": "3"
},
{
"input": "1\n1 1 1 1 1 1 1",
"output": "1... | 1,641,817,871 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | def sup(a):
a=a[::-1]
k=7
for i in a:
if i!=0:
break
else:
k-=1
return k
n=int(input())
m=list(map(int,input().split()))
l=0
n=n%sum(m)
if n==0:
print(sup(m))
else:
while n>0:
n-=m[l]
l+=1
print(n,m,l)
print(l... | Title: Petr and Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight s... | ```python
def sup(a):
a=a[::-1]
k=7
for i in a:
if i!=0:
break
else:
k-=1
return k
n=int(input())
m=list(map(int,input().split()))
l=0
n=n%sum(m)
if n==0:
print(sup(m))
else:
while n>0:
n-=m[l]
l+=1
print(n,m,l)
... | 0 | |
313 | B | Ilya and Queries | PROGRAMMING | 1,100 | [
"dp",
"implementation"
] | null | null | Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string *s*<==<=*s*1*s*2... *s**n* (*n* is the length of the string), consisting only of characters "." and "#" and *m* queries. Each query is described by a pair of integers *l**i*,<... | The first line contains string *s* of length *n* (2<=≤<=*n*<=≤<=105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. Each of the next *m* lines contains the description of the corresponding query. The *i*-t... | Print *m* integers — the answers to the queries in the order in which they are given in the input. | [
"......\n4\n3 4\n2 3\n1 6\n2 6\n",
"#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4\n"
] | [
"1\n1\n5\n4\n",
"1\n1\n2\n2\n0\n"
] | none | 1,000 | [
{
"input": "......\n4\n3 4\n2 3\n1 6\n2 6",
"output": "1\n1\n5\n4"
},
{
"input": "#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4",
"output": "1\n1\n2\n2\n0"
},
{
"input": ".#...#..\n6\n1 5\n2 3\n6 7\n2 4\n2 5\n1 3",
"output": "2\n0\n0\n1\n2\n0"
},
{
"input": "#.#.#..\n5\n3 4\n4 5\n5 7\n5... | 1,697,020,764 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | s = input()
checker = [0] * len(s)
count = 0
for i in range(len(s)-1):
if s[i] == s[i+1]:
count+=1
checker[i+1] = count
print(checker)
for _ in range(int(input())):
l,r = map(int,input().split())
l-=1
r-=1
print(checker[r] - checker[l]) | Title: Ilya and Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string *s*<==<=*s*1*s*2... *s**n* (*n* is the length of the string), consisting ... | ```python
s = input()
checker = [0] * len(s)
count = 0
for i in range(len(s)-1):
if s[i] == s[i+1]:
count+=1
checker[i+1] = count
print(checker)
for _ in range(int(input())):
l,r = map(int,input().split())
l-=1
r-=1
print(checker[r] - checker[l])
``` | 0 | |
253 | A | Boys and Girls | PROGRAMMING | 1,100 | [
"greedy"
] | null | null | There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to *n*<=+<=*m*. Then the number of integers *i* (1<=≤<=*i*<=<<=*n*<=+<=*m*) such th... | The single line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), separated by a space. | Print a line of *n*<=+<=*m* characters. Print on the *i*-th position of the line character "B", if the *i*-th position of your arrangement should have a boy and "G", if it should have a girl.
Of course, the number of characters "B" should equal *n* and the number of characters "G" should equal *m*. If there are multi... | [
"3 3\n",
"4 2\n"
] | [
"GBGBGB\n",
"BGBGBB\n"
] | In the first sample another possible answer is BGBGBG.
In the second sample answer BBGBGB is also optimal. | 500 | [
{
"input": "3 3",
"output": "GBGBGB"
},
{
"input": "4 2",
"output": "BGBGBB"
},
{
"input": "5 5",
"output": "GBGBGBGBGB"
},
{
"input": "6 4",
"output": "BGBGBGBGBB"
},
{
"input": "100 1",
"output": "BGBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB... | 1,620,334,719 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 124 | 6,963,200 | with open("input.txt") as fh:
content = fh.read()
content = content.split()
n = int(content[0])
m = int(content[-1])
if n > m:
#print(n, " is the number of boys")
#print("there are more boys than girls")
boys_left = n - m
#print(boys_left)
pairs = m
eta = (("BG")*pairs+("B")*boys_l... | Title: Boys and Girls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by n... | ```python
with open("input.txt") as fh:
content = fh.read()
content = content.split()
n = int(content[0])
m = int(content[-1])
if n > m:
#print(n, " is the number of boys")
#print("there are more boys than girls")
boys_left = n - m
#print(boys_left)
pairs = m
eta = (("BG")*pairs+("... | 3 | |
920 | B | Tea Queue | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Recently *n* students from city S moved to city P to attend a programming camp.
They moved there by train. In the evening, all students in the train decided that they want to drink some tea. Of course, no two people can use the same teapot simultaneously, so the students had to form a queue to get their tea.
*i*-th s... | The first line contains one integer *t* — the number of test cases to solve (1<=≤<=*t*<=≤<=1000).
Then *t* test cases follow. The first line of each test case contains one integer *n* (1<=≤<=*n*<=≤<=1000) — the number of students.
Then *n* lines follow. Each line contains two integer *l**i*, *r**i* (1<=≤<=*l**i*<=≤<=... | For each test case print *n* integers. *i*-th of them must be equal to the second when *i*-th student gets his tea, or 0 if he leaves without tea. | [
"2\n2\n1 3\n1 4\n3\n1 5\n1 1\n2 3\n"
] | [
"1 2 \n1 0 2 \n"
] | The example contains 2 tests:
1. During 1-st second, students 1 and 2 come to the queue, and student 1 gets his tea. Student 2 gets his tea during 2-nd second. 1. During 1-st second, students 1 and 2 come to the queue, student 1 gets his tea, and student 2 leaves without tea. During 2-nd second, student 3 comes and ... | 0 | [
{
"input": "2\n2\n1 3\n1 4\n3\n1 5\n1 1\n2 3",
"output": "1 2 \n1 0 2 "
},
{
"input": "19\n1\n1 1\n1\n1 2\n1\n1 1000\n1\n1 2000\n1\n2 2\n1\n2 3\n1\n2 1000\n1\n2 2000\n1\n1999 1999\n1\n1999 2000\n1\n2000 2000\n2\n1 1\n1 1\n2\n1 1\n1 2\n2\n1 2\n1 1\n2\n1 2000\n1 1\n2\n1 1\n1 2000\n2\n1 2000\n2 2\n2\n2... | 1,624,983,219 | 2,147,483,647 | Python 3 | OK | TESTS | 8 | 77 | 0 | for _ in range(int(input())):
n = int(input())
l = []
for i in range(n):
x, y = map(int, input().split())
l.append((x, y))
start = 0
# l.sort()
ans = []
for st, ed in l:
if start+1 <= ed:
ans.append(max(start+1, st))
start = max(st,... | Title: Tea Queue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently *n* students from city S moved to city P to attend a programming camp.
They moved there by train. In the evening, all students in the train decided that they want to drink some tea. Of course, no two people can use ... | ```python
for _ in range(int(input())):
n = int(input())
l = []
for i in range(n):
x, y = map(int, input().split())
l.append((x, y))
start = 0
# l.sort()
ans = []
for st, ed in l:
if start+1 <= ed:
ans.append(max(start+1, st))
start... | 3 | |
596 | B | Wilbur and Array | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Wilbur the pig is tinkering with arrays again. He has the array *a*1,<=*a*2,<=...,<=*a**n* initially consisting of *n* zeros. At one step, he can choose any index *i* and either add 1 to all elements *a**i*,<=*a**i*<=+<=1,<=... ,<=*a**n* or subtract 1 from all elements *a**i*,<=*a**i*<=+<=1,<=...,<=*a**n*. His goal is ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the length of the array *a**i*. Initially *a**i*<==<=0 for every position *i*, so this array is not given in the input.
The second line of the input contains *n* integers *b*1,<=*b*2,<=...,<=*b**n* (<=-<=109<=≤<=*b**i*<=≤<=109). | Print the minimum number of steps that Wilbur needs to make in order to achieve *a**i*<==<=*b**i* for all *i*. | [
"5\n1 2 3 4 5\n",
"4\n1 2 2 1\n"
] | [
"5",
"3"
] | In the first sample, Wilbur may successively choose indices 1, 2, 3, 4, and 5, and add 1 to corresponding suffixes.
In the second sample, Wilbur first chooses indices 1 and 2 and adds 1 to corresponding suffixes, then he chooses index 4 and subtract 1. | 1,000 | [
{
"input": "5\n1 2 3 4 5",
"output": "5"
},
{
"input": "4\n1 2 2 1",
"output": "3"
},
{
"input": "3\n1 2 4",
"output": "4"
},
{
"input": "6\n1 2 3 6 5 4",
"output": "8"
},
{
"input": "10\n2 1 4 3 6 5 8 7 10 9",
"output": "19"
},
{
"input": "7\n12 6 12 ... | 1,519,709,820 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 233 | 23,244,800 | n=int(input())
b=list(map(int,input().split()))
s=0
s=abs(b[0])
i=0
for i in range(n-1):
s+=abs(b[i]-b[i+1])
print(s)
| Title: Wilbur and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Wilbur the pig is tinkering with arrays again. He has the array *a*1,<=*a*2,<=...,<=*a**n* initially consisting of *n* zeros. At one step, he can choose any index *i* and either add 1 to all elements *a**i*,<=*a**i*<=+... | ```python
n=int(input())
b=list(map(int,input().split()))
s=0
s=abs(b[0])
i=0
for i in range(n-1):
s+=abs(b[i]-b[i+1])
print(s)
``` | 3 | |
959 | D | Mahmoud and Ehab and another array construction task | PROGRAMMING | 1,900 | [
"constructive algorithms",
"greedy",
"math",
"number theory"
] | null | null | Mahmoud has an array *a* consisting of *n* integers. He asked Ehab to find another array *b* of the same length such that:
- *b* is lexicographically greater than or equal to *a*. - *b**i*<=≥<=2. - *b* is pairwise coprime: for every 1<=≤<=*i*<=<<=*j*<=≤<=*n*, *b**i* and *b**j* are coprime, i. e. *GCD*(*b**i*,<=*... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105), the number of elements in *a* and *b*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (2<=≤<=*a**i*<=≤<=105), the elements of *a*. | Output *n* space-separated integers, the *i*-th of them representing *b**i*. | [
"5\n2 3 5 4 13\n",
"3\n10 3 7\n"
] | [
"2 3 5 7 11 ",
"10 3 7 "
] | Note that in the second sample, the array is already pairwise coprime so we printed it. | 1,750 | [
{
"input": "5\n2 3 5 4 13",
"output": "2 3 5 7 11 "
},
{
"input": "3\n10 3 7",
"output": "10 3 7 "
},
{
"input": "5\n7 10 2 5 5",
"output": "7 10 3 11 13 "
},
{
"input": "7\n20 9 7 6 7 9 15",
"output": "20 9 7 11 13 17 19 "
},
{
"input": "10\n5 3 2 2 3 3 3 4 2 5",... | 1,626,388,301 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 3,000 | 13,721,600 | def find_gcd(a1,a2):
if a1>a2:
smaller = a2
else:
smaller = a1
for i in range(smaller,0,-1):
if a1%i == 0 and a2%i == 0:
return i
def check_noncoprime_loc(test_list,n):
for i in range(1,n):
for j in range(0,i):
gcd = find_gcd(test_list[i],test_list[j])
if gcd != ... | Title: Mahmoud and Ehab and another array construction task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud has an array *a* consisting of *n* integers. He asked Ehab to find another array *b* of the same length such that:
- *b* is lexicographically greater than or equal to *a*. ... | ```python
def find_gcd(a1,a2):
if a1>a2:
smaller = a2
else:
smaller = a1
for i in range(smaller,0,-1):
if a1%i == 0 and a2%i == 0:
return i
def check_noncoprime_loc(test_list,n):
for i in range(1,n):
for j in range(0,i):
gcd = find_gcd(test_list[i],test_list[j])
... | 0 | |
540 | A | Combination Lock | PROGRAMMING | 800 | [
"implementation"
] | null | null | Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock.
The combination lock is represented by *n* rotating disks with digits from 0 to 9 written on them. Scrooge McDuck has to turn ... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of disks on the combination lock.
The second line contains a string of *n* digits — the original state of the disks.
The third line contains a string of *n* digits — Scrooge McDuck's combination that opens the lock. | Print a single integer — the minimum number of moves Scrooge McDuck needs to open the lock. | [
"5\n82195\n64723\n"
] | [
"13\n"
] | In the sample he needs 13 moves:
- 1 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/b8967f65a723782358b93eff9ce69f336817cf70.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 2 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/07fa58573ece0d32... | 500 | [
{
"input": "5\n82195\n64723",
"output": "13"
},
{
"input": "12\n102021090898\n010212908089",
"output": "16"
},
{
"input": "1\n8\n1",
"output": "3"
},
{
"input": "2\n83\n57",
"output": "7"
},
{
"input": "10\n0728592530\n1362615763",
"output": "27"
},
{
... | 1,608,930,378 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 155 | 0 | l = int(input())
random = input()
password = input()
s = str(random) + str(password)
def main(l,s):
count = 0
for i in range(len(s)-l):
if int(s[i]) > int(s[i+l]):
a = int(s[i]) - int(s[i+l])
b = (int(s[i+l]) + 10) - int(s[i])
if a > b:
... | Title: Combination Lock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock.
The combination lock is ... | ```python
l = int(input())
random = input()
password = input()
s = str(random) + str(password)
def main(l,s):
count = 0
for i in range(len(s)-l):
if int(s[i]) > int(s[i+l]):
a = int(s[i]) - int(s[i+l])
b = (int(s[i+l]) + 10) - int(s[i])
if a > b:
... | 3 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the... | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,684,389,830 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | n,m,k = map(int,input().split())
row = [n + k-(n%k),n][n%k==0]
col = [m +k-(m%k),m][m%k==0]
print(row*col//(k**2)) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each ... | ```python
n,m,k = map(int,input().split())
row = [n + k-(n%k),n][n%k==0]
col = [m +k-(m%k),m][m%k==0]
print(row*col//(k**2))
``` | 3.977 |
832 | A | Sasha and Sticks | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with whom he shares a desk. The rules are simple. Sasha draws *n* sticks in a row. After that the players t... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1018, *k*<=≤<=*n*) — the number of sticks drawn by Sasha and the number *k* — the number of sticks to be crossed out on each turn. | If Sasha wins, print "YES" (without quotes), otherwise print "NO" (without quotes).
You can print each letter in arbitrary case (upper of lower). | [
"1 1\n",
"10 4\n"
] | [
"YES\n",
"NO\n"
] | In the first example Sasha crosses out 1 stick, and then there are no sticks. So Lena can't make a move, and Sasha wins.
In the second example Sasha crosses out 4 sticks, then Lena crosses out 4 sticks, and after that there are only 2 sticks left. Sasha can't make a move. The players make equal number of moves, so Sas... | 500 | [
{
"input": "1 1",
"output": "YES"
},
{
"input": "10 4",
"output": "NO"
},
{
"input": "251656215122324104 164397544865601257",
"output": "YES"
},
{
"input": "963577813436662285 206326039287271924",
"output": "NO"
},
{
"input": "1000000000000000000 1",
"output":... | 1,609,150,191 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 0 | n=int(input())
k=int(input())
if (n//k)%2!=0 or n==k:
print("YES")
else:
print("NO")
| Title: Sasha and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with ... | ```python
n=int(input())
k=int(input())
if (n//k)%2!=0 or n==k:
print("YES")
else:
print("NO")
``` | -1 | |
919 | B | Perfect Number | PROGRAMMING | 1,100 | [
"binary search",
"brute force",
"dp",
"implementation",
"number theory"
] | null | null | We consider a positive integer perfect, if and only if the sum of its digits is exactly $10$. Given a positive integer $k$, your task is to find the $k$-th smallest perfect positive integer. | A single line with a positive integer $k$ ($1 \leq k \leq 10\,000$). | A single number, denoting the $k$-th smallest perfect integer. | [
"1\n",
"2\n"
] | [
"19\n",
"28\n"
] | The first perfect integer is $19$ and the second one is $28$. | 750 | [
{
"input": "1",
"output": "19"
},
{
"input": "2",
"output": "28"
},
{
"input": "13",
"output": "136"
},
{
"input": "101",
"output": "1432"
},
{
"input": "1023",
"output": "100270"
},
{
"input": "9999",
"output": "10800010"
},
{
"input": "10... | 1,693,932,179 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 61 | 0 | n = input()
print(n + str(10 - sum([int(i) for i in n]))) | Title: Perfect Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We consider a positive integer perfect, if and only if the sum of its digits is exactly $10$. Given a positive integer $k$, your task is to find the $k$-th smallest perfect positive integer.
Input Specification:
A singl... | ```python
n = input()
print(n + str(10 - sum([int(i) for i in n])))
``` | 0 | |
342 | A | Xenia and Divisors | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,<=*b*,<=*c* the following conditions held:
- *a*<=<<=*b*<=<<=*c*; - *a* divides *b*, *b* divide... | The first line contains integer *n* (3<=≤<=*n*<=≤<=99999) — the number of elements in the sequence. The next line contains *n* positive integers, each of them is at most 7.
It is guaranteed that *n* is divisible by 3. | If the required partition exists, print groups of three. Print each group as values of the elements it contains. You should print values in increasing order. Separate the groups and integers in groups by whitespaces. If there are multiple solutions, you can print any of them.
If there is no solution, print -1. | [
"6\n1 1 1 2 2 2\n",
"6\n2 2 1 1 4 6\n"
] | [
"-1\n",
"1 2 4\n1 2 6\n"
] | none | 500 | [
{
"input": "6\n1 1 1 2 2 2",
"output": "-1"
},
{
"input": "6\n2 2 1 1 4 6",
"output": "1 2 4\n1 2 6"
},
{
"input": "3\n1 2 3",
"output": "-1"
},
{
"input": "3\n7 5 7",
"output": "-1"
},
{
"input": "3\n1 3 4",
"output": "-1"
},
{
"input": "3\n1 1 1",
... | 1,623,738,035 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 61 | 0 | n = int(input())
l = list(map(int, input().split()))
ls = set(l)
res = ''
if len(ls) < 3 or 5 in ls or 7 in ls:
print(-1)
exit()
else:
lc = {
1: l.count(1),
2: l.count(2),
3: l.count(3),
4: l.count(4),
6: l.count(6)
}
if lc[1] != n/3:
... | Title: Xenia and Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,... | ```python
n = int(input())
l = list(map(int, input().split()))
ls = set(l)
res = ''
if len(ls) < 3 or 5 in ls or 7 in ls:
print(-1)
exit()
else:
lc = {
1: l.count(1),
2: l.count(2),
3: l.count(3),
4: l.count(4),
6: l.count(6)
}
if lc[1] != n/3... | -1 | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,582,173,465 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | a=input()
b=input()
c=list()
for i,j in zip(a,b):
if(i!=j):
c.append('1')
else:
c.append('0')
c="".join(c)
c=str(c) | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
a=input()
b=input()
c=list()
for i,j in zip(a,b):
if(i!=j):
c.append('1')
else:
c.append('0')
c="".join(c)
c=str(c)
``` | 0 |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,562,191,929 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 372 | 0 | n,m = list(map(int,input().split()))
a = list(map(int,input().split()))
a.sort()
i,l=0,0
while m>0:
if a[i]<=0:
l+=abs(a[i])
i+=1
m-=1
else:
break
print(l) | Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
n,m = list(map(int,input().split()))
a = list(map(int,input().split()))
a.sort()
i,l=0,0
while m>0:
if a[i]<=0:
l+=abs(a[i])
i+=1
m-=1
else:
break
print(l)
``` | 3.907 |
869 | B | The Eternal Immortality | PROGRAMMING | 1,100 | [
"math"
] | null | null | Even if the world is full of counterfeits, I still regard it as wonderful.
Pile up herbs and incense, and arise again from the flames and ashes of its predecessor — as is known to many, the phoenix does it like this.
The phoenix has a rather long lifespan, and reincarnates itself once every *a*! years. Here *a*! deno... | The first and only line of input contains two space-separated integers *a* and *b* (0<=≤<=*a*<=≤<=*b*<=≤<=1018). | Output one line containing a single decimal digit — the last digit of the value that interests Koyomi. | [
"2 4\n",
"0 10\n",
"107 109\n"
] | [
"2\n",
"0\n",
"2\n"
] | In the first example, the last digit of <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/99c47ca8b182f097e38094d12f0c06ce0b081b76.png" style="max-width: 100.0%;max-height: 100.0%;"/> is 2;
In the second example, the last digit of <img align="middle" class="tex-formula" src="https://espresso... | 1,000 | [
{
"input": "2 4",
"output": "2"
},
{
"input": "0 10",
"output": "0"
},
{
"input": "107 109",
"output": "2"
},
{
"input": "10 13",
"output": "6"
},
{
"input": "998244355 998244359",
"output": "4"
},
{
"input": "999999999000000000 1000000000000000000",
... | 1,615,449,907 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 93 | 0 | a, b = map(int,input().split())
print((b-a)%10)
| Title: The Eternal Immortality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Even if the world is full of counterfeits, I still regard it as wonderful.
Pile up herbs and incense, and arise again from the flames and ashes of its predecessor — as is known to many, the phoenix does it like... | ```python
a, b = map(int,input().split())
print((b-a)%10)
``` | 0 | |
120 | B | Quiz League | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | A team quiz game called "What? Where? When?" is very popular in Berland. The game is centered on two teams competing. They are the team of six Experts versus the team of the Audience. A person from the audience asks a question and the experts are allowed a minute on brainstorming and finding the right answer to the que... | The first line contains two positive integers *n* and *k* (1<=≤<=*n*<=≤<=1000 and 1<=≤<=*k*<=≤<=*n*) — the numbers of sectors on the table and the number of the sector where the arrow is pointing. The second line contains *n* numbers: *a**i*<==<=0 if the question from sector *i* has already been asked and *a**i*<==<=1 ... | Print the single number — the number of the sector containing the question the experts will be asked. It is guaranteed that the answer exists, that is that not all the questions have already been asked. | [
"5 5\n0 1 0 1 0\n",
"2 1\n1 1\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "5 5\n0 1 0 1 0",
"output": "2"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "3 2\n1 0 0",
"output": "1"
},
{
"input": "3 3\n0 1 0",
"output": "2"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "6 3\n0 0 1 1 0 1",
"output":... | 1,600,026,654 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 4 | 109 | 307,200 | import sys
sys.stdin = open('input.txt','r')
sys.stdout = open('output.txt','w')
n,m=map(int,input().split())
l=list(map(int,input().split()))
c=0
if n==m:
j=l[0]
else:
j=m-1
while c==0:
if l[j]==1:
c=j+1
# print(c)
break
if j==n-1:
j=0
else:
... | Title: Quiz League
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A team quiz game called "What? Where? When?" is very popular in Berland. The game is centered on two teams competing. They are the team of six Experts versus the team of the Audience. A person from the audience asks a quest... | ```python
import sys
sys.stdin = open('input.txt','r')
sys.stdout = open('output.txt','w')
n,m=map(int,input().split())
l=list(map(int,input().split()))
c=0
if n==m:
j=l[0]
else:
j=m-1
while c==0:
if l[j]==1:
c=j+1
# print(c)
break
if j==n-1:
j=0
else... | -1 | |
688 | A | Opponents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Arya has *n* opponents in the school. Each day he will fight with all opponents who are present this day. His opponents have some fighting plan that guarantees they will win, but implementing this plan requires presence of them all. That means if one day at least one of Arya's opponents is absent at the school, then Ar... | The first line of the input contains two integers *n* and *d* (1<=≤<=*n*,<=*d*<=≤<=100) — the number of opponents and the number of days, respectively.
The *i*-th of the following *d* lines contains a string of length *n* consisting of characters '0' and '1'. The *j*-th character of this string is '0' if the *j*-th op... | Print the only integer — the maximum number of consecutive days that Arya will beat all present opponents. | [
"2 2\n10\n00\n",
"4 1\n0100\n",
"4 5\n1101\n1111\n0110\n1011\n1111\n"
] | [
"2\n",
"1\n",
"2\n"
] | In the first and the second samples, Arya will beat all present opponents each of the *d* days.
In the third sample, Arya will beat his opponents on days 1, 3 and 4 and his opponents will beat him on days 2 and 5. Thus, the maximum number of consecutive winning days is 2, which happens on days 3 and 4. | 500 | [
{
"input": "2 2\n10\n00",
"output": "2"
},
{
"input": "4 1\n0100",
"output": "1"
},
{
"input": "4 5\n1101\n1111\n0110\n1011\n1111",
"output": "2"
},
{
"input": "3 2\n110\n110",
"output": "2"
},
{
"input": "10 6\n1111111111\n0100110101\n1111111111\n0000011010\n1111... | 1,656,852,581 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 14 | 93 | 512,000 | import sys
input = sys.stdin.readline
n, d = map(int, input().split())
data = [list(map(int, input().rstrip())) for _ in range(d)]
memo = [all(i) for i in data]
cnt = 0
mv = -1
for i in memo:
if i == 0:
cnt += 1
mv = max(mv, cnt)
else:
cnt = 0
print(mv) | Title: Opponents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arya has *n* opponents in the school. Each day he will fight with all opponents who are present this day. His opponents have some fighting plan that guarantees they will win, but implementing this plan requires presence of th... | ```python
import sys
input = sys.stdin.readline
n, d = map(int, input().split())
data = [list(map(int, input().rstrip())) for _ in range(d)]
memo = [all(i) for i in data]
cnt = 0
mv = -1
for i in memo:
if i == 0:
cnt += 1
mv = max(mv, cnt)
else:
cnt = 0
print(mv)... | 0 | |
414 | B | Mashmokh and ACM | PROGRAMMING | 1,400 | [
"combinatorics",
"dp",
"number theory"
] | null | null | Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced prog... | The first line of input contains two space-separated integers *n*,<=*k* (1<=≤<=*n*,<=*k*<=≤<=2000). | Output a single integer — the number of good sequences of length *k* modulo 1000000007 (109<=+<=7). | [
"3 2\n",
"6 4\n",
"2 1\n"
] | [
"5\n",
"39\n",
"2\n"
] | In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3]. | 1,000 | [
{
"input": "3 2",
"output": "5"
},
{
"input": "6 4",
"output": "39"
},
{
"input": "2 1",
"output": "2"
},
{
"input": "1478 194",
"output": "312087753"
},
{
"input": "1415 562",
"output": "953558593"
},
{
"input": "1266 844",
"output": "735042656"
... | 1,615,381,480 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 249 | 6,348,800 | import math
n,k = map(int,input().split())
dp = [[1 for i in range(k+1)] for j in range(n+1)]
mark = [1]*(n+1)
prime = [True]*(n+1)
m = int(math.sqrt(n))
for i in range(2,m+1):
if prime[i]:
for j in range(2*i, n+1, i):
if prime[j]:
prime[j] = False
ma... | Title: Mashmokh and ACM
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join h... | ```python
import math
n,k = map(int,input().split())
dp = [[1 for i in range(k+1)] for j in range(n+1)]
mark = [1]*(n+1)
prime = [True]*(n+1)
m = int(math.sqrt(n))
for i in range(2,m+1):
if prime[i]:
for j in range(2*i, n+1, i):
if prime[j]:
prime[j] = False
... | 0 | |
479 | A | Expression | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resul... | The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10). | Print the maximum value of the expression that you can obtain. | [
"1\n2\n3\n",
"2\n10\n3\n"
] | [
"9\n",
"60\n"
] | none | 500 | [
{
"input": "1\n2\n3",
"output": "9"
},
{
"input": "2\n10\n3",
"output": "60"
},
{
"input": "1\n1\n1",
"output": "3"
},
{
"input": "1\n2\n1",
"output": "4"
},
{
"input": "10\n10\n10",
"output": "1000"
},
{
"input": "5\n1\n3",
"output": "20"
},
{... | 1,689,438,680 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 5 | 61 | 0 | w = int(input())
x = int(input())
y = int(input())
s = 0
if x == 1 or (w == 1 and y == 1):
s = w + x + y
elif w == 1:
s = (w + x)*y
elif y == 1:
s = w*(x + y)
else:
s = w*x*y
print(s) | Title: Expression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of ... | ```python
w = int(input())
x = int(input())
y = int(input())
s = 0
if x == 1 or (w == 1 and y == 1):
s = w + x + y
elif w == 1:
s = (w + x)*y
elif y == 1:
s = w*(x + y)
else:
s = w*x*y
print(s)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Oleg writes down the history of the days he lived. For each day he decides if it was good or bad. Oleg calls a non-empty sequence of days a zebra, if it starts with a bad day, ends with a bad day, and good and bad days are alternating in it. Let us denote bad days as 0 and good days as 1. Then, for example, sequences o... | In the only line of input data there is a non-empty string *s* consisting of characters 0 and 1, which describes the history of Oleg's life. Its length (denoted as |*s*|) does not exceed 200<=000 characters. | If there is a way to divide history into zebra subsequences, in the first line of output you should print an integer *k* (1<=≤<=*k*<=≤<=|*s*|), the resulting number of subsequences. In the *i*-th of following *k* lines first print the integer *l**i* (1<=≤<=*l**i*<=≤<=|*s*|), which is the length of the *i*-th subsequenc... | [
"0010100\n",
"111\n"
] | [
"3\n3 1 3 4\n3 2 5 6\n1 7\n",
"-1\n"
] | none | 0 | [
{
"input": "0010100",
"output": "3\n1 1\n5 2 3 4 5 6\n1 7"
},
{
"input": "111",
"output": "-1"
},
{
"input": "0",
"output": "1\n1 1"
},
{
"input": "1",
"output": "-1"
},
{
"input": "0101010101",
"output": "-1"
},
{
"input": "010100001",
"output": "... | 1,522,077,291 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 25 | 482 | 32,768,000 | life_log = input()
result = list()
def possible():
ones = 0
zeros = 0
for k in life_log:
if k == '0':
if ones > 0:
ones -= 1
zeros += 1
else:
zeros -= 1
ones += 1
if zeros < 0:
return False
if ones > ... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Oleg writes down the history of the days he lived. For each day he decides if it was good or bad. Oleg calls a non-empty sequence of days a zebra, if it starts with a bad day, ends with a bad day, and good and bad days are alterna... | ```python
life_log = input()
result = list()
def possible():
ones = 0
zeros = 0
for k in life_log:
if k == '0':
if ones > 0:
ones -= 1
zeros += 1
else:
zeros -= 1
ones += 1
if zeros < 0:
return False
... | 0 | |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are s... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,698,324,290 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 25 | 1,000 | 9,523,200 | s = input()
n = (int)(s.split(' ')[0])
m = (int)(s.split(' ')[1])
a = [(int)(i) for i in input().split(' ')]
k = set()
p = [0]*n
for i in range(0,n) :
k.add(a[n-1-i])
p[n-1-i] = len(k)
for i in range(0,m) :
print(p[(int)(input())-1])
| Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...... | ```python
s = input()
n = (int)(s.split(' ')[0])
m = (int)(s.split(' ')[1])
a = [(int)(i) for i in input().split(' ')]
k = set()
p = [0]*n
for i in range(0,n) :
k.add(a[n-1-i])
p[n-1-i] = len(k)
for i in range(0,m) :
print(p[(int)(input())-1])
``` | 0 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,671,553,756 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 0 | s=input()
l=len(s)
for i in range(l):
if s[i].isupeer():
u=u+1
else:
o=o+1
if u>o:
print(s.upper())
else:
print(s.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s=input()
l=len(s)
for i in range(l):
if s[i].isupeer():
u=u+1
else:
o=o+1
if u>o:
print(s.upper())
else:
print(s.lower())
``` | -1 |
950 | A | Left-handers, Right-handers and Ambidexters | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and ... | The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. | Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. | [
"1 4 2\n",
"5 5 5\n",
"0 2 0\n"
] | [
"6\n",
"14\n",
"0\n"
] | In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five l... | 500 | [
{
"input": "1 4 2",
"output": "6"
},
{
"input": "5 5 5",
"output": "14"
},
{
"input": "0 2 0",
"output": "0"
},
{
"input": "30 70 34",
"output": "128"
},
{
"input": "89 32 24",
"output": "112"
},
{
"input": "89 44 77",
"output": "210"
},
{
... | 1,627,009,113 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 6,963,200 | [l, r, a] = map(int, input().split())
if l >= r:
if a >= l - r:
r = l + a//2
l = l + a//2
else:
r = r + a
r = l
else:
if a >= r - l:
l = l + (r - l)
a = a - (r - l)
l = l + a//2
r = r + a//2
else:
l = l + a
... | Title: Left-handers, Right-handers and Ambidexters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.... | ```python
[l, r, a] = map(int, input().split())
if l >= r:
if a >= l - r:
r = l + a//2
l = l + a//2
else:
r = r + a
r = l
else:
if a >= r - l:
l = l + (r - l)
a = a - (r - l)
l = l + a//2
r = r + a//2
else:
l = l + ... | 0 | |
205 | A | Little Elephant and Rozdil | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elephant doesn't like to spend much time on travelling, so for his journey he will choose a town that needs minimum ti... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of cities. The next line contains *n* integers, separated by single spaces: the *i*-th integer represents the time needed to go from town Rozdil to the *i*-th town. The time values are positive integers, not exceeding 109.
You can consider t... | Print the answer on a single line — the number of the town the Little Elephant will go to. If there are multiple cities with minimum travel time, print "Still Rozdil" (without the quotes). | [
"2\n7 4\n",
"7\n7 4 47 100 4 9 12\n"
] | [
"2\n",
"Still Rozdil\n"
] | In the first sample there are only two cities where the Little Elephant can go. The travel time for the first town equals 7, to the second one — 4. The town which is closest to Rodzil (the only one) is the second one, so the answer is 2.
In the second sample the closest cities are cities two and five, the travelling t... | 500 | [
{
"input": "2\n7 4",
"output": "2"
},
{
"input": "7\n7 4 47 100 4 9 12",
"output": "Still Rozdil"
},
{
"input": "1\n47",
"output": "1"
},
{
"input": "2\n1000000000 1000000000",
"output": "Still Rozdil"
},
{
"input": "7\n7 6 5 4 3 2 1",
"output": "7"
},
{
... | 1,593,685,620 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 280 | 8,806,400 | n=input()
m=list(map(int,input().split()))
if m.count(min(m))==1:
print(m.index(min(m))+1)
else:
print("Still Rozdil") | Title: Little Elephant and Rozdil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elepha... | ```python
n=input()
m=list(map(int,input().split()))
if m.count(min(m))==1:
print(m.index(min(m))+1)
else:
print("Still Rozdil")
``` | 3 | |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,571,504,886 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 202 | 1,740,800 | # Lang: pypy3.6-v7.1.0-win32\pypy3.exe
# Problem Name: AddingDigits
# Problem Serial No: 260
# Problem Type: A
# Problem Url: https://codeforces.com/problemset/problem/260/A
# Solution Generated at: 2019-10-19 22:59:44.364396 UTC
i = int
cin = input
le = len
s = str
a, b, n = map(i, cin().split())
prev ... | Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
# Lang: pypy3.6-v7.1.0-win32\pypy3.exe
# Problem Name: AddingDigits
# Problem Serial No: 260
# Problem Type: A
# Problem Url: https://codeforces.com/problemset/problem/260/A
# Solution Generated at: 2019-10-19 22:59:44.364396 UTC
i = int
cin = input
le = len
s = str
a, b, n = map(i, cin().split... | 0 | |
431 | C | k-Tree | PROGRAMMING | 1,600 | [
"dp",
"implementation",
"trees"
] | null | null | Quite recently a creative student Lesha had a lecture on trees. After the lecture Lesha was inspired and came up with the tree of his own which he called a *k*-tree.
A *k*-tree is an infinite rooted tree where:
- each vertex has exactly *k* children; - each edge has some weight; - if we look at the edges that goes... | A single line contains three space-separated integers: *n*, *k* and *d* (1<=≤<=*n*,<=*k*<=≤<=100; 1<=≤<=*d*<=≤<=*k*). | Print a single integer — the answer to the problem modulo 1000000007 (109<=+<=7). | [
"3 3 2\n",
"3 3 3\n",
"4 3 2\n",
"4 5 2\n"
] | [
"3\n",
"1\n",
"6\n",
"7\n"
] | none | 1,500 | [
{
"input": "3 3 2",
"output": "3"
},
{
"input": "3 3 3",
"output": "1"
},
{
"input": "4 3 2",
"output": "6"
},
{
"input": "4 5 2",
"output": "7"
},
{
"input": "28 6 3",
"output": "110682188"
},
{
"input": "5 100 1",
"output": "16"
},
{
"inp... | 1,662,818,671 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | def ways(n,k):
if k==0:
return 0
dp = [0 for _ in range(n+1)]
dp[0] = 1
for i in range(1,n+1):
for j in range(1,k+1):
if i-j<0:
break
dp[i]+=dp[i-j]
print(dp)
return dp[n]
def solve():
n,k,d = input().split(" ")
print(ways(int(n),int(k))-ways(int(n),int(d)-1))
de... | Title: k-Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently a creative student Lesha had a lecture on trees. After the lecture Lesha was inspired and came up with the tree of his own which he called a *k*-tree.
A *k*-tree is an infinite rooted tree where:
- each vertex ... | ```python
def ways(n,k):
if k==0:
return 0
dp = [0 for _ in range(n+1)]
dp[0] = 1
for i in range(1,n+1):
for j in range(1,k+1):
if i-j<0:
break
dp[i]+=dp[i-j]
print(dp)
return dp[n]
def solve():
n,k,d = input().split(" ")
print(ways(int(n),int(k))-ways(int(n),int(... | 0 | |
801 | B | Valued Keys | PROGRAMMING | 900 | [
"constructive algorithms",
"greedy",
"strings"
] | null | null | You found a mysterious function *f*. The function takes two strings *s*1 and *s*2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function *f* is another string of the same length. The *i*-th character of the output is equal to the minimum of the *i*-th cha... | The first line of input contains the string *x*.
The second line of input contains the string *y*.
Both *x* and *y* consist only of lowercase English letters, *x* and *y* have same length and this length is between 1 and 100. | If there is no string *z* such that *f*(*x*,<=*z*)<==<=*y*, print -1.
Otherwise, print a string *z* such that *f*(*x*,<=*z*)<==<=*y*. If there are multiple possible answers, print any of them. The string *z* should be the same length as *x* and *y* and consist only of lowercase English letters. | [
"ab\naa\n",
"nzwzl\nniwel\n",
"ab\nba\n"
] | [
"ba\n",
"xiyez\n",
"-1\n"
] | The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no *z* such that *f*("ab", *z*) = "ba". | 1,000 | [
{
"input": "ab\naa",
"output": "ba"
},
{
"input": "nzwzl\nniwel",
"output": "xiyez"
},
{
"input": "ab\nba",
"output": "-1"
},
{
"input": "r\nl",
"output": "l"
},
{
"input": "d\ny",
"output": "-1"
},
{
"input": "yvowz\ncajav",
"output": "cajav"
},... | 1,545,422,040 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 124 | 0 | def main():
x = input()
y = input()
z = ""
for i in range(0, len(x)):
if (ord(x[i]) - ord(y[i])) < 0:
print(-1)
return
elif (ord(x[i]) - ord(y[i])) == 0:
z += x[i]
else:
z += y[i]
print(z)
if __name__ == "__main__":
... | Title: Valued Keys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You found a mysterious function *f*. The function takes two strings *s*1 and *s*2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function *f* is another string... | ```python
def main():
x = input()
y = input()
z = ""
for i in range(0, len(x)):
if (ord(x[i]) - ord(y[i])) < 0:
print(-1)
return
elif (ord(x[i]) - ord(y[i])) == 0:
z += x[i]
else:
z += y[i]
print(z)
if __name__ == "_... | 3 | |
837 | D | Round Subset | PROGRAMMING | 2,100 | [
"dp",
"math"
] | null | null | Let's call the roundness of the number the number of zeros to which it ends.
You have an array of *n* numbers. You need to choose a subset of exactly *k* numbers so that the roundness of the product of the selected numbers will be maximum possible. | The first line contains two integer numbers *n* and *k* (1<=≤<=*n*<=≤<=200,<=1<=≤<=*k*<=≤<=*n*).
The second line contains *n* space-separated integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1018). | Print maximal roundness of product of the chosen subset of length *k*. | [
"3 2\n50 4 20\n",
"5 3\n15 16 3 25 9\n",
"3 3\n9 77 13\n"
] | [
"3\n",
"3\n",
"0\n"
] | In the first example there are 3 subsets of 2 numbers. [50, 4] has product 200 with roundness 2, [4, 20] — product 80, roundness 1, [50, 20] — product 1000, roundness 3.
In the second example subset [15, 16, 25] has product 6000, roundness 3.
In the third example all subsets has product with roundness 0. | 0 | [
{
"input": "3 2\n50 4 20",
"output": "3"
},
{
"input": "5 3\n15 16 3 25 9",
"output": "3"
},
{
"input": "3 3\n9 77 13",
"output": "0"
},
{
"input": "1 1\n200000000",
"output": "8"
},
{
"input": "1 1\n3",
"output": "0"
},
{
"input": "3 1\n10000000000000... | 1,652,789,199 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 2,000 | 37,580,800 | def count_roundness(n):
n = list(str(n))
n.reverse()
count = 0
for i in n:
if i != "0":
break
count += 1
return count
from itertools import permutations
n, k = list(map(int, input().split()))
a = list(map(int, input().split()))
m = 0
for j in range(n):
... | Title: Round Subset
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call the roundness of the number the number of zeros to which it ends.
You have an array of *n* numbers. You need to choose a subset of exactly *k* numbers so that the roundness of the product of the selected number... | ```python
def count_roundness(n):
n = list(str(n))
n.reverse()
count = 0
for i in n:
if i != "0":
break
count += 1
return count
from itertools import permutations
n, k = list(map(int, input().split()))
a = list(map(int, input().split()))
m = 0
for j in ra... | 0 | |
365 | A | Good Number | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number every time it occurs in array *a*). | The first line contains integers *n* and *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=9). The *i*-th of the following *n* lines contains integer *a**i* without leading zeroes (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the number of *k*-good numbers in *a*. | [
"10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n",
"2 1\n1\n10\n"
] | [
"10\n",
"1\n"
] | none | 500 | [
{
"input": "10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560",
"output": "10"
},
{
"input": "2 1\n1\n10",
"output": "1"
},
{
"input": "1 0\n1000000000",
"output": "1"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
... | 1,652,638,804 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 62 | 17,715,200 | n, t = map(int, input().split())
k = 0
for i in range(n):
h = 1
a = input()
l = list(a)
print(l)
for j in l:
if int(j) > t:
h = 0
if h == 1:
k += 1
print(k)
| Title: Good Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number eve... | ```python
n, t = map(int, input().split())
k = 0
for i in range(n):
h = 1
a = input()
l = list(a)
print(l)
for j in l:
if int(j) > t:
h = 0
if h == 1:
k += 1
print(k)
``` | 0 | |
415 | B | Mashmokh and Tokens | PROGRAMMING | 1,500 | [
"binary search",
"greedy",
"implementation",
"math"
] | null | null | Bimokh is Mashmokh's boss. For the following *n* days he decided to pay to his workers in a new way. At the beginning of each day he will give each worker a certain amount of tokens. Then at the end of each day each worker can give some of his tokens back to get a certain amount of money. The worker can save the rest o... | The first line of input contains three space-separated integers *n*,<=*a*,<=*b* (1<=≤<=*n*<=≤<=105; 1<=≤<=*a*,<=*b*<=≤<=109). The second line of input contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=109). | Output *n* space-separated integers. The *i*-th of them is the number of tokens Mashmokh can save on the *i*-th day. | [
"5 1 4\n12 6 11 9 1\n",
"3 1 2\n1 2 3\n",
"1 1 1\n1\n"
] | [
"0 2 3 1 1 ",
"1 0 1 ",
"0 "
] | none | 1,000 | [
{
"input": "5 1 4\n12 6 11 9 1",
"output": "0 2 3 1 1 "
},
{
"input": "3 1 2\n1 2 3",
"output": "1 0 1 "
},
{
"input": "1 1 1\n1",
"output": "0 "
},
{
"input": "1 1 1000000000\n1000000000",
"output": "0 "
},
{
"input": "1 1 1000000000\n999999999",
"output": "9... | 1,517,679,346 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 233 | 10,240,000 | n,a,b=map(int,input().strip().split(' '))
L=list(map(int,input().split(' ')))
for i in range(n):
print(L[i]%b,end=' ') | Title: Mashmokh and Tokens
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bimokh is Mashmokh's boss. For the following *n* days he decided to pay to his workers in a new way. At the beginning of each day he will give each worker a certain amount of tokens. Then at the end of each day each... | ```python
n,a,b=map(int,input().strip().split(' '))
L=list(map(int,input().split(' ')))
for i in range(n):
print(L[i]%b,end=' ')
``` | 0 | |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another c... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follo... | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,598,490,426 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 307,200 | num= int(input())
array1 = list(map(int,input().split()))
print(abs(array1[0]-array1[1]),abs(array1[0]-array1[-1]))
for i in range(1,num-1):
max = max(abs(array1[i]-array1[i-1]),abs(array1[i]-array1[i+1]),abs(array1[i]-array1[-1]),abs(array1[i]-array1[0]))
min = min(abs(array1[i]-array1[i-1]),abs(array1[i]-arra... | Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love... | ```python
num= int(input())
array1 = list(map(int,input().split()))
print(abs(array1[0]-array1[1]),abs(array1[0]-array1[-1]))
for i in range(1,num-1):
max = max(abs(array1[i]-array1[i-1]),abs(array1[i]-array1[i+1]),abs(array1[i]-array1[-1]),abs(array1[i]-array1[0]))
min = min(abs(array1[i]-array1[i-1]),abs(arra... | -1 | |
622 | A | Infinite Sequence | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains ... | The only line contains integer *n* (1<=≤<=*n*<=≤<=1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | Print the element in the *n*-th position of the sequence (the elements are numerated from one). | [
"3\n",
"5\n",
"10\n",
"55\n",
"56\n"
] | [
"2\n",
"2\n",
"4\n",
"10\n",
"1\n"
] | none | 0 | [
{
"input": "3",
"output": "2"
},
{
"input": "5",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "55",
"output": "10"
},
{
"input": "56",
"output": "1"
},
{
"input": "1000000000000",
"output": "88209"
},
{
"input": "8471941278... | 1,679,357,472 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 46 | 0 | n=int(input())
def check(x):
if x*(x+1)//2>=n:
return True
return False
l=-1
r=n+1
while l+1!=r:
mid=(l+r)//2
if check(mid):
r=mid
else:
l=mid
print(n-(l+1)*l//2)
| Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2,... | ```python
n=int(input())
def check(x):
if x*(x+1)//2>=n:
return True
return False
l=-1
r=n+1
while l+1!=r:
mid=(l+r)//2
if check(mid):
r=mid
else:
l=mid
print(n-(l+1)*l//2)
``` | 3 | |
600 | B | Queries about less or equal elements | PROGRAMMING | 1,300 | [
"binary search",
"data structures",
"sortings",
"two pointers"
] | null | null | You are given two arrays of integers *a* and *b*. For each element of the second array *b**j* you should find the number of elements in array *a* that are less than or equal to the value *b**j*. | The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=2·105) — the sizes of arrays *a* and *b*.
The second line contains *n* integers — the elements of array *a* (<=-<=109<=≤<=*a**i*<=≤<=109).
The third line contains *m* integers — the elements of array *b* (<=-<=109<=≤<=*b**j*<=≤<=109). | Print *m* integers, separated by spaces: the *j*-th of which is equal to the number of such elements in array *a* that are less than or equal to the value *b**j*. | [
"5 4\n1 3 5 7 9\n6 4 2 8\n",
"5 5\n1 2 1 2 5\n3 1 4 1 5\n"
] | [
"3 2 1 4\n",
"4 2 4 2 5\n"
] | none | 0 | [
{
"input": "5 4\n1 3 5 7 9\n6 4 2 8",
"output": "3 2 1 4"
},
{
"input": "5 5\n1 2 1 2 5\n3 1 4 1 5",
"output": "4 2 4 2 5"
},
{
"input": "1 1\n-1\n-2",
"output": "0"
},
{
"input": "1 1\n-80890826\n686519510",
"output": "1"
},
{
"input": "11 11\n237468511 -77918754... | 1,664,132,663 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | z = input().split(" ")
x = (input().split(" "))
y = (input().split(" "))
x.sort()
for i in y:
ini = 0
fin = int(z[1])-1
while(ini<=fin):
mid = (ini+fin)//2
if(i >= x[mid]):
ini=mid+1
if(i < x[mid]):
fin = mid-1
print(ini)
| Title: Queries about less or equal elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays of integers *a* and *b*. For each element of the second array *b**j* you should find the number of elements in array *a* that are less than or equal to the value *b**j*.
In... | ```python
z = input().split(" ")
x = (input().split(" "))
y = (input().split(" "))
x.sort()
for i in y:
ini = 0
fin = int(z[1])-1
while(ini<=fin):
mid = (ini+fin)//2
if(i >= x[mid]):
ini=mid+1
if(i < x[mid]):
fin = mid-1
print(ini)
... | 0 | |
975 | B | Mancala | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Mancala is a game famous in the Middle East. It is played on a board that consists of 14 holes.
Initially, each hole has $a_i$ stones. When a player makes a move, he chooses a hole which contains a positive number of stones. He takes all the stones inside it and then redistributes these stones one by one in the next ... | The only line contains 14 integers $a_1, a_2, \ldots, a_{14}$ ($0 \leq a_i \leq 10^9$) — the number of stones in each hole.
It is guaranteed that for any $i$ ($1\leq i \leq 14$) $a_i$ is either zero or odd, and there is at least one stone in the board. | Output one integer, the maximum possible score after one move. | [
"0 1 1 0 0 0 0 0 0 7 0 0 0 0\n",
"5 1 1 1 1 0 0 0 0 0 0 0 0 0\n"
] | [
"4\n",
"8\n"
] | In the first test case the board after the move from the hole with $7$ stones will look like 1 2 2 0 0 0 0 0 0 0 1 1 1 1. Then the player collects the even numbers and ends up with a score equal to $4$. | 1,000 | [
{
"input": "0 1 1 0 0 0 0 0 0 7 0 0 0 0",
"output": "4"
},
{
"input": "5 1 1 1 1 0 0 0 0 0 0 0 0 0",
"output": "8"
},
{
"input": "10001 10001 10001 10001 10001 10001 10001 10001 10001 10001 10001 10001 10001 1",
"output": "54294"
},
{
"input": "0 0 0 0 0 0 0 0 0 0 0 0 0 15",
... | 1,525,352,456 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 124 | 7,065,600 | nums = list(map(int, input().split()))
res = 0
for i in range (0,len(nums)):
copy_nums = nums[:]
# compute the cost
total = copy_nums[i]
next = (i+1)%len(nums)
while total > 0:
total = total -1
copy_nums[next] = copy_nums[next] +1
next = (next+1)%len(nums)
wins = 0
for j in range (... | Title: Mancala
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mancala is a game famous in the Middle East. It is played on a board that consists of 14 holes.
Initially, each hole has $a_i$ stones. When a player makes a move, he chooses a hole which contains a positive number of stones. ... | ```python
nums = list(map(int, input().split()))
res = 0
for i in range (0,len(nums)):
copy_nums = nums[:]
# compute the cost
total = copy_nums[i]
next = (i+1)%len(nums)
while total > 0:
total = total -1
copy_nums[next] = copy_nums[next] +1
next = (next+1)%len(nums)
wins = 0
for j ... | 0 | |
615 | A | Bulbs | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
I... | The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**... | If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". | [
"3 4\n2 1 4\n3 1 3 1\n1 2\n",
"3 3\n1 1\n1 2\n1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | 500 | [
{
"input": "3 4\n2 1 4\n3 1 3 1\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 2\n1 1",
"output": "NO"
},
{
"input": "3 4\n1 1\n1 2\n1 3",
"output": "NO"
},
{
"input": "1 5\n5 1 2 3 4 5",
"output": "YES"
},
{
"input": "1 5\n5 4 4 1 2 3",
"output": "NO"
},... | 1,665,472,442 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 45 | 62 | 1,638,400 | [n,m]=[int(i)for i in input().split()]
set1=set()
for i in range(m):
set1.add(i+1)
set2=set()
for i in range(n):
a=[int(j) for j in input().split()]
for j in range(a[0]):
set2.add(a[j+1])
if(set1==set2):
print('YES')
else:
print('NO') | Title: Bulbs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is... | ```python
[n,m]=[int(i)for i in input().split()]
set1=set()
for i in range(m):
set1.add(i+1)
set2=set()
for i in range(n):
a=[int(j) for j in input().split()]
for j in range(a[0]):
set2.add(a[j+1])
if(set1==set2):
print('YES')
else:
print('NO')
``` | 3 | |
630 | I | Parking Lot | PROGRAMMING | 1,700 | [
"combinatorics",
"math"
] | null | null | To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2*n*<=-<=2) parking spaces. Unfortunately the total number of ... | The only line of the input contains one integer *n* (3<=≤<=*n*<=≤<=30) — the amount of successive cars of the same make. | Output one integer — the number of ways to fill the parking lot by cars of four makes using the described way. | [
"3\n"
] | [
"24"
] | Let's denote car makes in the following way: A — Aston Martin, B — Bentley, M — Mercedes-Maybach, Z — Zaporozhets. For *n* = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Orig... | 0 | [
{
"input": "3",
"output": "24"
},
{
"input": "4",
"output": "132"
},
{
"input": "5",
"output": "672"
},
{
"input": "6",
"output": "3264"
},
{
"input": "7",
"output": "15360"
},
{
"input": "12",
"output": "27525120"
},
{
"input": "15",
"... | 1,688,621,956 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | def binpow(x, n):
res = 1
while n > 0:
if n & 1:
res = res * x
x = x * x
n >>= 1
return res
n = int(input())
print(4*binpow(3, n - 2)*(n-1)) | Title: Parking Lot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before t... | ```python
def binpow(x, n):
res = 1
while n > 0:
if n & 1:
res = res * x
x = x * x
n >>= 1
return res
n = int(input())
print(4*binpow(3, n - 2)*(n-1))
``` | 0 | |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,697,906,605 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 61 | 3,379,200 | a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=[1]
for i in range(1,a[0]):
if i+b[i-1]<a[0]:
c.append(i+b[i-1])
d=list(set(c))
if a[1] in d:
print('YES')
else:
print('NO') | Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=[1]
for i in range(1,a[0]):
if i+b[i-1]<a[0]:
c.append(i+b[i-1])
d=list(set(c))
if a[1] in d:
print('YES')
else:
print('NO')
``` | 0 | |
716 | B | Complete the Word | PROGRAMMING | 1,300 | [
"greedy",
"two pointers"
] | null | null | ZS the Coder loves to read the dictionary. He thinks that a word is nice if there exists a substring (contiguous segment of letters) of it of length 26 where each letter of English alphabet appears exactly once. In particular, if the string has length strictly less than 26, no such substring exists and thus it is not n... | The first and only line of the input contains a single string *s* (1<=≤<=|*s*|<=≤<=50<=000), the word that ZS the Coder remembers. Each character of the string is the uppercase letter of English alphabet ('A'-'Z') or is a question mark ('?'), where the question marks denotes the letters that ZS the Coder can't remember... | If there is no way to replace all the question marks with uppercase letters such that the resulting word is nice, then print <=-<=1 in the only line.
Otherwise, print a string which denotes a possible nice word that ZS the Coder learned. This string should match the string from the input, except for the question marks... | [
"ABC??FGHIJK???OPQR?TUVWXY?\n",
"WELCOMETOCODEFORCESROUNDTHREEHUNDREDANDSEVENTYTWO\n",
"??????????????????????????\n",
"AABCDEFGHIJKLMNOPQRSTUVW??M\n"
] | [
"ABCDEFGHIJKLMNOPQRZTUVWXYS",
"-1",
"MNBVCXZLKJHGFDSAQPWOEIRUYT",
"-1"
] | In the first sample case, ABCDEFGHIJKLMNOPQRZTUVWXYS is a valid answer beacuse it contains a substring of length 26 (the whole string in this case) which contains all the letters of the English alphabet exactly once. Note that there are many possible solutions, such as ABCDEFGHIJKLMNOPQRSTUVWXYZ or ABCEDFGHIJKLMNOPQRZT... | 1,000 | [
{
"input": "ABC??FGHIJK???OPQR?TUVWXY?",
"output": "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
},
{
"input": "WELCOMETOCODEFORCESROUNDTHREEHUNDREDANDSEVENTYTWO",
"output": "-1"
},
{
"input": "??????????????????????????",
"output": "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
},
{
"input": "AABCDEFGHIJKLMNO... | 1,553,159,159 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 124 | 307,200 | a = list(input())
count = [0 for _ in range(26)]
avilable = [0 for _ in range(26)]
miss =[]
temp = []
l = -1
r = -1
check = 0
if len(a)<26:
print(-1)
else:
undefind = 0
for i in range(26):
if a[i] =='?':
undefind +=1
miss.append(i)
else:
c... | Title: Complete the Word
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
ZS the Coder loves to read the dictionary. He thinks that a word is nice if there exists a substring (contiguous segment of letters) of it of length 26 where each letter of English alphabet appears exactly once. In pa... | ```python
a = list(input())
count = [0 for _ in range(26)]
avilable = [0 for _ in range(26)]
miss =[]
temp = []
l = -1
r = -1
check = 0
if len(a)<26:
print(-1)
else:
undefind = 0
for i in range(26):
if a[i] =='?':
undefind +=1
miss.append(i)
else:
... | 0 | |
8 | A | Train and Peter | PROGRAMMING | 1,200 | [
"strings"
] | A. Train and Peter | 1 | 64 | Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy start... | The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second lin... | Output one of the four words without inverted commas:
- «forward» — if Peter could see such sequences only on the way from A to B; - «backward» — if Peter could see such sequences on the way from B to A; - «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A; - «fanta... | [
"atob\na\nb\n",
"aaacaaa\naca\naa\n"
] | [
"forward\n",
"both\n"
] | It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | 0 | [
{
"input": "atob\na\nb",
"output": "forward"
},
{
"input": "aaacaaa\naca\naa",
"output": "both"
},
{
"input": "aaa\naa\naa",
"output": "fantasy"
},
{
"input": "astalavista\nastla\nlavista",
"output": "fantasy"
},
{
"input": "abacabadabacaba\nabacaba\nabacaba",
... | 1,535,793,360 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 186 | 0 | a=input()
b=input()
c=input()
x=a.find(b)
y=a.find(c, x+1)
j=a[::-1]
p=j.find(b)
q=j.find(c)
if(x!=-1)and(y!=-1)and(p==-1)and(q==-1):
print('forward')
elif(x==-1)and(y==-1)and(p!=-1)and(q!=-1):
print('backward')
elif(x!=-1)and(y!=-1)and(p!=-1)and(q!=-1):
print('both')
else:
print('fantasy... | Title: Train and Peter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the... | ```python
a=input()
b=input()
c=input()
x=a.find(b)
y=a.find(c, x+1)
j=a[::-1]
p=j.find(b)
q=j.find(c)
if(x!=-1)and(y!=-1)and(p==-1)and(q==-1):
print('forward')
elif(x==-1)and(y==-1)and(p!=-1)and(q!=-1):
print('backward')
elif(x!=-1)and(y!=-1)and(p!=-1)and(q!=-1):
print('both')
else:
prin... | 0 |
479 | C | Exams | PROGRAMMING | 1,400 | [
"greedy",
"sortings"
] | null | null | Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly *n* exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order.
According to the schedule, a st... | The first line contains a single positive integer *n* (1<=≤<=*n*<=≤<=5000) — the number of exams Valera will take.
Each of the next *n* lines contains two positive space-separated integers *a**i* and *b**i* (1<=≤<=*b**i*<=<<=*a**i*<=≤<=109) — the date of the exam in the schedule and the early date of passing the *i... | Print a single integer — the minimum possible number of the day when Valera can take the last exam if he takes all the exams so that all the records in his record book go in the order of non-decreasing date. | [
"3\n5 2\n3 1\n4 2\n",
"3\n6 1\n5 2\n4 3\n"
] | [
"2\n",
"6\n"
] | In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark ... | 1,500 | [
{
"input": "3\n5 2\n3 1\n4 2",
"output": "2"
},
{
"input": "3\n6 1\n5 2\n4 3",
"output": "6"
},
{
"input": "1\n1000000000 999999999",
"output": "999999999"
},
{
"input": "1\n2 1",
"output": "1"
},
{
"input": "2\n3 2\n3 2",
"output": "2"
},
{
"input": "... | 1,685,965,567 | 2,147,483,647 | Python 3 | OK | TESTS | 53 | 46 | 716,800 | import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
############ --... | Title: Exams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly *n* exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Beside... | ```python
import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
#####... | 3 | |
525 | B | Pasha and String | PROGRAMMING | 1,400 | [
"constructive algorithms",
"greedy",
"math",
"strings"
] | null | null | Pasha got a very beautiful string *s* for his birthday, the string consists of lowercase Latin letters. The letters in the string are numbered from 1 to |*s*| from left to right, where |*s*| is the length of the given string.
Pasha didn't like his present very much so he decided to change it. After his birthday Pasha ... | The first line of the input contains Pasha's string *s* of length from 2 to 2·105 characters, consisting of lowercase Latin letters.
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=105) — the number of days when Pasha changed his string.
The third line contains *m* space-separated elements *a**i* (1<=≤<... | In the first line of the output print what Pasha's string *s* will look like after *m* days. | [
"abcdef\n1\n2\n",
"vwxyz\n2\n2 2\n",
"abcdef\n3\n1 2 3\n"
] | [
"aedcbf\n",
"vwxyz\n",
"fbdcea\n"
] | none | 750 | [
{
"input": "abcdef\n1\n2",
"output": "aedcbf"
},
{
"input": "vwxyz\n2\n2 2",
"output": "vwxyz"
},
{
"input": "abcdef\n3\n1 2 3",
"output": "fbdcea"
},
{
"input": "jc\n5\n1 1 1 1 1",
"output": "cj"
},
{
"input": "wljqgdlxyc\n13\n3 4 3 3 5 4 4 2 4 4 5 3 3",
"out... | 1,443,224,415 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | cadena = input()
n = int(input())
dias = input().split()
longitud = len(cadena)
arreglo = []
cadenaN = ""
for i in cadena:
arreglo = arreglo + [i]
for i in range(n):
for j in range((longitud-2*int(dias[i])+2)//2):
inicio = int(dias[i])-1
fin = longitud - int(dias[i])
temp = arreglo[inicio]
arreglo[inicio] =... | Title: Pasha and String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha got a very beautiful string *s* for his birthday, the string consists of lowercase Latin letters. The letters in the string are numbered from 1 to |*s*| from left to right, where |*s*| is the length of the given ... | ```python
cadena = input()
n = int(input())
dias = input().split()
longitud = len(cadena)
arreglo = []
cadenaN = ""
for i in cadena:
arreglo = arreglo + [i]
for i in range(n):
for j in range((longitud-2*int(dias[i])+2)//2):
inicio = int(dias[i])-1
fin = longitud - int(dias[i])
temp = arreglo[inicio]
arreglo... | 0 | |
149 | A | Business trip | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | null | null | What joy! Petya's parents went on a business trip for the whole year and the playful kid is left all by himself. Petya got absolutely happy. He jumped on the bed and threw pillows all day long, until...
Today Petya opened the cupboard and found a scary note there. His parents had left him with duties: he should water... | The first line contains exactly one integer *k* (0<=≤<=*k*<=≤<=100). The next line contains twelve space-separated integers: the *i*-th (1<=≤<=*i*<=≤<=12) number in the line represents *a**i* (0<=≤<=*a**i*<=≤<=100). | Print the only integer — the minimum number of months when Petya has to water the flower so that the flower grows no less than by *k* centimeters. If the flower can't grow by *k* centimeters in a year, print -1. | [
"5\n1 1 1 1 2 2 3 2 2 1 1 1\n",
"0\n0 0 0 0 0 0 0 1 1 2 3 0\n",
"11\n1 1 4 1 1 5 1 1 4 1 1 1\n"
] | [
"2\n",
"0\n",
"3\n"
] | Let's consider the first sample test. There it is enough to water the flower during the seventh and the ninth month. Then the flower grows by exactly five centimeters.
In the second sample Petya's parents will believe him even if the flower doesn't grow at all (*k* = 0). So, it is possible for Petya not to water the f... | 500 | [
{
"input": "5\n1 1 1 1 2 2 3 2 2 1 1 1",
"output": "2"
},
{
"input": "0\n0 0 0 0 0 0 0 1 1 2 3 0",
"output": "0"
},
{
"input": "11\n1 1 4 1 1 5 1 1 4 1 1 1",
"output": "3"
},
{
"input": "15\n20 1 1 1 1 2 2 1 2 2 1 1",
"output": "1"
},
{
"input": "7\n8 9 100 12 14 ... | 1,656,777,550 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 62 | 0 | k = int(input())
growthPerMonth = list(map(int, input().split(' ')))
growthPerMonth.sort(reverse=True)
count = 0
totalGrowth = 0
for growth in growthPerMonth:
if totalGrowth >= k:
break
totalGrowth += growth
count += 1
print(count)
| Title: Business trip
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
What joy! Petya's parents went on a business trip for the whole year and the playful kid is left all by himself. Petya got absolutely happy. He jumped on the bed and threw pillows all day long, until...
Today Petya open... | ```python
k = int(input())
growthPerMonth = list(map(int, input().split(' ')))
growthPerMonth.sort(reverse=True)
count = 0
totalGrowth = 0
for growth in growthPerMonth:
if totalGrowth >= k:
break
totalGrowth += growth
count += 1
print(count)
``` | 0 | |
810 | B | Summer sell-off | PROGRAMMING | 1,300 | [
"greedy",
"sortings"
] | null | null | Summer holidays! Someone is going on trips, someone is visiting grandparents, but someone is trying to get a part-time job. This summer Noora decided that she wants to earn some money, and took a job in a shop as an assistant.
Shop, where Noora is working, has a plan on the following *n* days. For each day sales manag... | The first line contains two integers *n* and *f* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*f*<=≤<=*n*) denoting the number of days in shop's plan and the number of days that Noora has to choose for sell-out.
Each line of the following *n* subsequent lines contains two integers *k**i*,<=*l**i* (0<=≤<=*k**i*,<=*l**i*<=≤<=109) denotin... | Print a single integer denoting the maximal number of products that shop can sell. | [
"4 2\n2 1\n3 5\n2 3\n1 5\n",
"4 1\n0 2\n0 3\n3 5\n0 6\n"
] | [
"10",
"5"
] | In the first example we can choose days with numbers 2 and 4 for sell-out. In this case new numbers of products for sale would be equal to [2, 6, 2, 2] respectively. So on the first day shop will sell 1 product, on the second — 5, on the third — 2, on the fourth — 2. In total 1 + 5 + 2 + 2 = 10 product units.
In the s... | 1,000 | [
{
"input": "4 2\n2 1\n3 5\n2 3\n1 5",
"output": "10"
},
{
"input": "4 1\n0 2\n0 3\n3 5\n0 6",
"output": "5"
},
{
"input": "1 1\n5 8",
"output": "8"
},
{
"input": "2 1\n8 12\n6 11",
"output": "19"
},
{
"input": "2 1\n6 7\n5 7",
"output": "13"
},
{
"inpu... | 1,495,386,310 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 204,800 | '''input
4 1
0 2
0 3
3 5
0 6
'''
n, f = map(int, input().split())
s = 0
d = []
for _ in range(n):
k, l = map(int, input().split())
s += min(k, l)
d.append(min(2*k, l) - min(k, l))
print(s + sum(sorted(d)[-f:]))
| Title: Summer sell-off
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Summer holidays! Someone is going on trips, someone is visiting grandparents, but someone is trying to get a part-time job. This summer Noora decided that she wants to earn some money, and took a job in a shop as an ass... | ```python
'''input
4 1
0 2
0 3
3 5
0 6
'''
n, f = map(int, input().split())
s = 0
d = []
for _ in range(n):
k, l = map(int, input().split())
s += min(k, l)
d.append(min(2*k, l) - min(k, l))
print(s + sum(sorted(d)[-f:]))
``` | 0 | |
845 | A | Chess Tourney | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by BerMobile. Obviously, organizers should guarantee the win for the team of BerOil.
Thus, organizer... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100).
The second line contains 2·*n* integers *a*1,<=*a*2,<=... *a*2*n* (1<=≤<=*a**i*<=≤<=1000). | If it's possible to divide all 2·*n* players into two teams with *n* people each so that the player from the first team in every pair wins regardless of the results of the drawing, then print "YES". Otherwise print "NO". | [
"2\n1 3 2 4\n",
"1\n3 3\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "2\n1 3 2 4",
"output": "YES"
},
{
"input": "1\n3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 2 2 3 3 3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 1 2 2 2 2 2",
"output": "YES"
},
{
"input": "10\n1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000... | 1,629,546,467 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 61 | 6,656,000 |
n=int(input())
a=list(map(int, input().split()))
a.sort()
if a[n//2]>a[n//2-1]:
print("YES")
else:
print("NO") | Title: Chess Tourney
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by... | ```python
n=int(input())
a=list(map(int, input().split()))
a.sort()
if a[n//2]>a[n//2-1]:
print("YES")
else:
print("NO")
``` | 0 | |
272 | A | Dima and Friends | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single s... | In a single line print the answer to the problem. | [
"1\n1\n",
"1\n2\n",
"2\n3 5\n"
] | [
"3\n",
"2\n",
"3\n"
] | In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | 500 | [
{
"input": "1\n1",
"output": "3"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "1\n5",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "4"
},
{
"input": "... | 1,626,688,560 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 6,758,400 |
"""
Jul 19, 2021
written by zach - at 04:26 AM CST
"""
import sys
getline = sys.stdin.readline
def read_int():
return int(getline())
def read_ints():
return list(map(int, getline().split()))
"""
Dima and Friends
15:10
10:15
"""
n = read_int() + 1
tot... | Title: Dima and Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the... | ```python
"""
Jul 19, 2021
written by zach - at 04:26 AM CST
"""
import sys
getline = sys.stdin.readline
def read_int():
return int(getline())
def read_ints():
return list(map(int, getline().split()))
"""
Dima and Friends
15:10
10:15
"""
n = read_int(... | 0 | |
157 | A | Game Outcome | PROGRAMMING | 800 | [
"brute force"
] | null | null | Sherlock Holmes and Dr. Watson played some game on a checkered board *n*<=×<=*n* in size. During the game they put numbers on the board's squares by some tricky rules we don't know. However, the game is now over and each square of the board contains exactly one number. To understand who has won, they need to count the ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=30). Each of the following *n* lines contain *n* space-separated integers. The *j*-th number on the *i*-th line represents the number on the square that belongs to the *j*-th column and the *i*-th row on the board. All number on the board are integers from 1 to 100. | Print the single number — the number of the winning squares. | [
"1\n1\n",
"2\n1 2\n3 4\n",
"4\n5 7 8 4\n9 5 3 2\n1 6 6 4\n9 5 7 3\n"
] | [
"0\n",
"2\n",
"6\n"
] | In the first example two upper squares are winning.
In the third example three left squares in the both middle rows are winning: | 500 | [
{
"input": "1\n1",
"output": "0"
},
{
"input": "2\n1 2\n3 4",
"output": "2"
},
{
"input": "4\n5 7 8 4\n9 5 3 2\n1 6 6 4\n9 5 7 3",
"output": "6"
},
{
"input": "2\n1 1\n1 1",
"output": "0"
},
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "4"
},
{
"inpu... | 1,589,242,182 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 218 | 0 | matrix = []
for _ in range(int(input())):
matrix.append(list(map(int,input().split())))
num_wining=0
for row in matrix:
row_sum=sum(row)
for i,x in zip(row,range(len(row))):
colum_sum = sum([row[x] for row in matrix])
if colum_sum > row_sum:
num_wining+=1
print(num_wini... | Title: Game Outcome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sherlock Holmes and Dr. Watson played some game on a checkered board *n*<=×<=*n* in size. During the game they put numbers on the board's squares by some tricky rules we don't know. However, the game is now over and each s... | ```python
matrix = []
for _ in range(int(input())):
matrix.append(list(map(int,input().split())))
num_wining=0
for row in matrix:
row_sum=sum(row)
for i,x in zip(row,range(len(row))):
colum_sum = sum([row[x] for row in matrix])
if colum_sum > row_sum:
num_wining+=1
prin... | 3 | |
106 | A | Card Game | PROGRAMMING | 1,000 | [
"implementation"
] | A. Card Game | 2 | 256 | There is a card game called "Durak", which means "Fool" in Russian. The game is quite popular in the countries that used to form USSR. The problem does not state all the game's rules explicitly — you can find them later yourselves if you want.
To play durak you need a pack of 36 cards. Each card has a suit ("S", "H", ... | The first line contains the tramp suit. It is "S", "H", "D" or "C".
The second line contains the description of the two different cards. Each card is described by one word consisting of two symbols. The first symbol stands for the rank ("6", "7", "8", "9", "T", "J", "Q", "K" and "A"), and the second one stands for the... | Print "YES" (without the quotes) if the first cards beats the second one. Otherwise, print "NO" (also without the quotes). | [
"H\nQH 9S\n",
"S\n8D 6D\n",
"C\n7H AS\n"
] | [
"YES\n",
"YES",
"NO"
] | none | 500 | [
{
"input": "H\nQH 9S",
"output": "YES"
},
{
"input": "S\n8D 6D",
"output": "YES"
},
{
"input": "C\n7H AS",
"output": "NO"
},
{
"input": "C\nKC 9C",
"output": "YES"
},
{
"input": "D\n7D KD",
"output": "NO"
},
{
"input": "H\n7H KD",
"output": "YES"
... | 1,625,067,221 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 47 | 216 | 0 | try:
s = input()
c1, c2 = ((input().split()))
ranks = ["6", "7", "8", "9", "T", "J", "Q", "K", "A"]
def check():
return ranks.index(c1[0]) > ranks.index(c2[0])
if c1[1] == c2[1]:
ans = check()
elif c1[1] == s:
ans = True
elif c2[1] == s:
ans = Fal... | Title: Card Game
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a card game called "Durak", which means "Fool" in Russian. The game is quite popular in the countries that used to form USSR. The problem does not state all the game's rules explicitly — you can find them later yourselve... | ```python
try:
s = input()
c1, c2 = ((input().split()))
ranks = ["6", "7", "8", "9", "T", "J", "Q", "K", "A"]
def check():
return ranks.index(c1[0]) > ranks.index(c2[0])
if c1[1] == c2[1]:
ans = check()
elif c1[1] == s:
ans = True
elif c2[1] == s:
... | 0 |
397 | A | On Segment's Own Points | PROGRAMMING | 0 | [
"implementation"
] | null | null | Our old friend Alexey has finally entered the University of City N — the Berland capital. Alexey expected his father to get him a place to live in but his father said it was high time for Alexey to practice some financial independence. So, Alexey is living in a dorm.
The dorm has exactly one straight dryer — a 100 ce... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100). The (*i*<=+<=1)-th line contains integers *l**i* and *r**i* (0<=≤<=*l**i*<=<<=*r**i*<=≤<=100) — the endpoints of the corresponding segment for the *i*-th student. | On a single line print a single number *k*, equal to the sum of lengths of the parts of the dryer which are inside Alexey's segment and are outside all other segments. | [
"3\n0 5\n2 8\n1 6\n",
"3\n0 10\n1 5\n7 15\n"
] | [
"1\n",
"3\n"
] | Note that it's not important are clothes drying on the touching segments (e.g. (0, 1) and (1, 2)) considered to be touching or not because you need to find the length of segments.
In the first test sample Alexey may use the only segment (0, 1). In such case his clothes will not touch clothes on the segments (1, 6) and... | 500 | [
{
"input": "3\n0 5\n2 8\n1 6",
"output": "1"
},
{
"input": "3\n0 10\n1 5\n7 15",
"output": "3"
},
{
"input": "1\n0 100",
"output": "100"
},
{
"input": "2\n1 9\n1 9",
"output": "0"
},
{
"input": "2\n1 9\n5 10",
"output": "4"
},
{
"input": "2\n1 9\n3 5",... | 1,572,923,106 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 307,200 | #length of the parts of segments available
#validate if the segment is inside range of segment of Alexei
#validate if the segment is out side range of segment of Alexei
#validate if exists points of segment of Alexei Available
def examine_segment(fil, col, n):
a_seg_li = fil[0]
a_seg_ri = col[0]
... | Title: On Segment's Own Points
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Our old friend Alexey has finally entered the University of City N — the Berland capital. Alexey expected his father to get him a place to live in but his father said it was high time for Alexey to practice some... | ```python
#length of the parts of segments available
#validate if the segment is inside range of segment of Alexei
#validate if the segment is out side range of segment of Alexei
#validate if exists points of segment of Alexei Available
def examine_segment(fil, col, n):
a_seg_li = fil[0]
a_seg_ri = c... | 0 | |
445 | A | DZY Loves Chessboard | PROGRAMMING | 1,200 | [
"dfs and similar",
"implementation"
] | null | null | DZY loves chessboard, and he enjoys playing with it.
He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. Each chessman is either white or black. After putting all chessmen, DZY wants that no two chessmen with th... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).
Each of the next *n* lines contains a string of *m* characters: the *j*-th character of the *i*-th string is either "." or "-". A "." means that the corresponding cell (in the *i*-th row and the *j*-th column) is good, while a ... | Output must contain *n* lines, each line must contain a string of *m* characters. The *j*-th character of the *i*-th string should be either "W", "B" or "-". Character "W" means the chessman on the cell is white, "B" means it is black, "-" means the cell is a bad cell.
If multiple answers exist, print any of them. It ... | [
"1 1\n.\n",
"2 2\n..\n..\n",
"3 3\n.-.\n---\n--."
] | [
"B\n",
"BW\nWB\n",
"B-B\n---\n--B"
] | In the first sample, DZY puts a single black chessman. Of course putting a white one is also OK.
In the second sample, all 4 cells are good. No two same chessmen share an edge in the sample output.
In the third sample, no good cells are adjacent. So you can just put 3 chessmen, no matter what their colors are. | 500 | [
{
"input": "1 1\n.",
"output": "B"
},
{
"input": "2 2\n..\n..",
"output": "BW\nWB"
},
{
"input": "3 3\n.-.\n---\n--.",
"output": "B-B\n---\n--B"
},
{
"input": "3 1\n-\n.\n.",
"output": "-\nW\nB"
},
{
"input": "11 11\n-----------\n-----------\n-----------\n--------... | 1,675,939,324 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | n, m= map(int, input().split())
for i in range(n):
a= input()
for j in range(m):
if a[j] == '.':
if (i%2 and i%2) or (i%2 == 0 and j%2 == 0):
print('W', end= ' ')
else:
print('B', end= ' ')
else:
print('-', end= ' ') | Title: DZY Loves Chessboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY loves chessboard, and he enjoys playing with it.
He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. ... | ```python
n, m= map(int, input().split())
for i in range(n):
a= input()
for j in range(m):
if a[j] == '.':
if (i%2 and i%2) or (i%2 == 0 and j%2 == 0):
print('W', end= ' ')
else:
print('B', end= ' ')
else:
print('-', e... | 0 | |
630 | A | Again Twenty Five! | PROGRAMMING | 800 | [
"number theory"
] | null | null | The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of *n* and get last two digits of the number. Yes, of course, *n* can be rather big, and one cannot find the power us... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=2·1018) — the power in which you need to raise number 5. | Output the last two digits of 5*n* without spaces between them. | [
"2\n"
] | [
"25"
] | none | 0 | [
{
"input": "2",
"output": "25"
},
{
"input": "7",
"output": "25"
},
{
"input": "1000000000000000000",
"output": "25"
},
{
"input": "2000000000000000000",
"output": "25"
},
{
"input": "987654321012345678",
"output": "25"
}
] | 1,688,483,291 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | n=int(input())
print(format(5**n,'02')) | Title: Again Twenty Five!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of *n* and ge... | ```python
n=int(input())
print(format(5**n,'02'))
``` | 0 | |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,692,382,352 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | x = int(input())
bac = 1
bacColoc = 1
while bac <= x:
bac *= 2
if bac > x:
bacColoc += (x - bac // 2)
print(bacColoc)
break
elif bac == x:
print(bacColoc)
break
| Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
x = int(input())
bac = 1
bacColoc = 1
while bac <= x:
bac *= 2
if bac > x:
bacColoc += (x - bac // 2)
print(bacColoc)
break
elif bac == x:
print(bacColoc)
break
``` | 0 | |
263 | A | Beautiful Matrix | PROGRAMMING | 800 | [
"implementation"
] | null | null | You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix:
1.... | The input consists of five lines, each line contains five integers: the *j*-th integer in the *i*-th line of the input represents the element of the matrix that is located on the intersection of the *i*-th row and the *j*-th column. It is guaranteed that the matrix consists of 24 zeroes and a single number one. | Print a single integer — the minimum number of moves needed to make the matrix beautiful. | [
"0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n",
"0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n"
] | [
"3\n",
"1\n"
] | none | 500 | [
{
"input": "0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 1 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "0"
},
{
"input": "0 0 0 0 0... | 1,699,176,210 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | t1 = 0
t2 = 0
for i in range(5):
row = list(map(int, input().split()))
if 1 in row:
t1 = i
t2 = row.index(1)
print(abs(t1 - 2) + abs(t2 - 2))
| Title: Beautiful Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to ri... | ```python
t1 = 0
t2 = 0
for i in range(5):
row = list(map(int, input().split()))
if 1 in row:
t1 = i
t2 = row.index(1)
print(abs(t1 - 2) + abs(t2 - 2))
``` | 3 | |
758 | A | Holiday Of Equality | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens, the welfare of each of them is estimated as the integer in *a**i* burles (burle is the currency in Berl... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100) — the number of citizens in the kingdom.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (0<=≤<=*a**i*<=≤<=106) — the welfare of the *i*-th citizen. | In the only line print the integer *S* — the minimum number of burles which are had to spend. | [
"5\n0 1 2 3 4\n",
"5\n1 1 0 1 1\n",
"3\n1 3 1\n",
"1\n12\n"
] | [
"10",
"1",
"4",
"0"
] | In the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.
In the second example it is enough to give one burle to the third citizen.
In the third example it is necessary to give two burles to the first and the thi... | 500 | [
{
"input": "5\n0 1 2 3 4",
"output": "10"
},
{
"input": "5\n1 1 0 1 1",
"output": "1"
},
{
"input": "3\n1 3 1",
"output": "4"
},
{
"input": "1\n12",
"output": "0"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "14\n52518 718438 358883 462189 853... | 1,661,850,388 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | n=int(input())
a=input()
l=a.split()
maxi=-1
for i in range(len[l]):
l[i]=int(l[i])
maxi=max(maxi , l[i])
ans=0
for i in range(len[l]):
ans+=maxi - l[i]
print(ans)
| Title: Holiday Of Equality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens... | ```python
n=int(input())
a=input()
l=a.split()
maxi=-1
for i in range(len[l]):
l[i]=int(l[i])
maxi=max(maxi , l[i])
ans=0
for i in range(len[l]):
ans+=maxi - l[i]
print(ans)
``` | -1 | |
230 | B | T-primes | PROGRAMMING | 1,300 | [
"binary search",
"implementation",
"math",
"number theory"
] | null | null | We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an array of *n* positive integers. For each of them determine whether it is Т-prime or not. | The first line contains a single positive integer, *n* (1<=≤<=*n*<=≤<=105), showing how many numbers are in the array. The next line contains *n* space-separated integers *x**i* (1<=≤<=*x**i*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout st... | Print *n* lines: the *i*-th line should contain "YES" (without the quotes), if number *x**i* is Т-prime, and "NO" (without the quotes), if it isn't. | [
"3\n4 5 6\n"
] | [
"YES\nNO\nNO\n"
] | The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO". | 500 | [
{
"input": "3\n4 5 6",
"output": "YES\nNO\nNO"
},
{
"input": "2\n48 49",
"output": "NO\nYES"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "NO\nYES\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO"
},
{
"input": "1\n36",
"output": "NO"
},
{
"input": "1\n999966000289",
"... | 1,697,103,779 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | from math import floor
n=int(input())
num=[int(x)for x in input().split()]
numbers=[[i,num[i]]for i in range(n)]
numbers.sort(key=lambda s:s[1])
primes=[2]
for p in range(3,floor(numbers[-1][1]**(1/2)),2):#创建质数表
for i in primes:
if p%i == 0:
break
else:
primes.append(p)
n... | Title: T-primes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an ar... | ```python
from math import floor
n=int(input())
num=[int(x)for x in input().split()]
numbers=[[i,num[i]]for i in range(n)]
numbers.sort(key=lambda s:s[1])
primes=[2]
for p in range(3,floor(numbers[-1][1]**(1/2)),2):#创建质数表
for i in primes:
if p%i == 0:
break
else:
primes.ap... | 0 | |
96 | B | Lucky Numbers (easy) | PROGRAMMING | 1,300 | [
"binary search",
"bitmasks",
"brute force"
] | B. Lucky Numbers (easy) | 2 | 256 | Petya loves lucky numbers. Everybody knows that positive integers are lucky if their decimal representation doesn't contain digits other than 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Lucky number is super lucky if it's decimal representation contains equal amount of digits 4 and 7. Fo... | The only line contains a positive integer *n* (1<=≤<=*n*<=≤<=109). This number doesn't have leading zeroes. | Output the least super lucky number that is more than or equal to *n*.
Please, do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator. | [
"4500\n",
"47\n"
] | [
"4747\n",
"47\n"
] | none | 1,000 | [
{
"input": "4500",
"output": "4747"
},
{
"input": "47",
"output": "47"
},
{
"input": "1",
"output": "47"
},
{
"input": "12",
"output": "47"
},
{
"input": "4587",
"output": "4747"
},
{
"input": "100",
"output": "4477"
},
{
"input": "1007",
... | 1,679,645,281 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 92 | 0 | n = int(input())
a = [0]
i = 0
while True:
k = a[i]
if k >= n and str(k).count('4') == str(k).count('7'):
print(k)
break
a+=[10*k+4 , 10*k+7]
i+=1
| Title: Lucky Numbers (easy)
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that positive integers are lucky if their decimal representation doesn't contain digits other than 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n = int(input())
a = [0]
i = 0
while True:
k = a[i]
if k >= n and str(k).count('4') == str(k).count('7'):
print(k)
break
a+=[10*k+4 , 10*k+7]
i+=1
``` | 3.977 |
920 | C | Swap Adjacent Elements | PROGRAMMING | 1,400 | [
"dfs and similar",
"greedy",
"math",
"sortings",
"two pointers"
] | null | null | You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array.
For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<=1)-th, for other indices it is not possible. You may perform any number of swapping operations any order. T... | The first line contains one integer *n* (2<=≤<=*n*<=≤<=200000) — the number of elements in the array.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=200000) — the elements of the array. Each integer from 1 to *n* appears exactly once.
The third line contains a string of *n*<=-<=1 char... | If it is possible to sort the array in ascending order using any sequence of swaps you are allowed to make, print YES. Otherwise, print NO. | [
"6\n1 2 5 3 4 6\n01110\n",
"6\n1 2 5 3 4 6\n01010\n"
] | [
"YES\n",
"NO\n"
] | In the first example you may swap *a*<sub class="lower-index">3</sub> and *a*<sub class="lower-index">4</sub>, and then swap *a*<sub class="lower-index">4</sub> and *a*<sub class="lower-index">5</sub>. | 0 | [
{
"input": "6\n1 2 5 3 4 6\n01110",
"output": "YES"
},
{
"input": "6\n1 2 5 3 4 6\n01010",
"output": "NO"
},
{
"input": "6\n1 6 3 4 5 2\n01101",
"output": "NO"
},
{
"input": "6\n2 3 1 4 5 6\n01111",
"output": "NO"
},
{
"input": "4\n2 3 1 4\n011",
"output": "NO... | 1,517,656,977 | 2,147,483,647 | Python 3 | OK | TESTS | 139 | 264 | 19,353,600 | n = int(input())
#n, m = map(int, input().split())
#s = input()
c = list(map(int, input().split()))
s = input()
x = 0
y = 0
p = 0
for i in range(n - 1):
if s[i] == '1':
if x < c[i]:
y = max(y, c[i])
p = 1
else:
print('NO')
break
els... | Title: Swap Adjacent Elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array.
For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<... | ```python
n = int(input())
#n, m = map(int, input().split())
#s = input()
c = list(map(int, input().split()))
s = input()
x = 0
y = 0
p = 0
for i in range(n - 1):
if s[i] == '1':
if x < c[i]:
y = max(y, c[i])
p = 1
else:
print('NO')
brea... | 3 | |
151 | A | Soft Drinking | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut each of them into *d* slices. After that they found *p* grams of salt.
To make a toast, each frie... | The first and only line contains positive integers *n*, *k*, *l*, *c*, *d*, *p*, *nl*, *np*, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space. | Print a single integer — the number of toasts each friend can make. | [
"3 4 5 10 8 100 3 1\n",
"5 100 10 1 19 90 4 3\n",
"10 1000 1000 25 23 1 50 1\n"
] | [
"2\n",
"3\n",
"0\n"
] | A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is *min*(6, 80, 100) / 3 = 2. | 500 | [
{
"input": "3 4 5 10 8 100 3 1",
"output": "2"
},
{
"input": "5 100 10 1 19 90 4 3",
"output": "3"
},
{
"input": "10 1000 1000 25 23 1 50 1",
"output": "0"
},
{
"input": "1 7 4 5 5 8 3 2",
"output": "4"
},
{
"input": "2 3 3 5 5 10 1 3",
"output": "1"
},
{
... | 1,674,737,548 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | n, k, l, c, d, p, nl, np = list(map(int, input().split()))
a = k * l
b = a // nl
print(min(b, c * d, p // np) // n)
| Title: Soft Drinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut... | ```python
n, k, l, c, d, p, nl, np = list(map(int, input().split()))
a = k * l
b = a // nl
print(min(b, c * d, p // np) // n)
``` | 3 | |
118 | A | String Task | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:
- deletes all the vowels, - inserts a character "." before each consonant, - replaces ... | The first line represents input string of Petya's program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive. | Print the resulting string. It is guaranteed that this string is not empty. | [
"tour\n",
"Codeforces\n",
"aBAcAba\n"
] | [
".t.r\n",
".c.d.f.r.c.s\n",
".b.c.b\n"
] | none | 500 | [
{
"input": "tour",
"output": ".t.r"
},
{
"input": "Codeforces",
"output": ".c.d.f.r.c.s"
},
{
"input": "aBAcAba",
"output": ".b.c.b"
},
{
"input": "obn",
"output": ".b.n"
},
{
"input": "wpwl",
"output": ".w.p.w.l"
},
{
"input": "ggdvq",
"output": "... | 1,697,918,224 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 42 | 124 | 1,536,000 | I=input
O=print
vowels=["A", "O", "Y", "E", "U", "I",
"a", "o", "y", "e", "u", "i"]
s=I()
answer=[]
for i in range(len(s)):
vowel=False
for j in range(len(vowels)):
if vowels[j]==s[i]:
vowel=True
if vowel:
pass
else:
answer.append('.')
i... | Title: String Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters... | ```python
I=input
O=print
vowels=["A", "O", "Y", "E", "U", "I",
"a", "o", "y", "e", "u", "i"]
s=I()
answer=[]
for i in range(len(s)):
vowel=False
for j in range(len(vowels)):
if vowels[j]==s[i]:
vowel=True
if vowel:
pass
else:
answer.append('.')
... | 3 | |
746 | B | Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the two middle letters. In the following examples, the median letter is highlighted: contest, inf... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2000) — the length of the encoded word.
The second line contains the string *s* of length *n* consisting of lowercase English letters — the encoding. | Print the word that Polycarp encoded. | [
"5\nlogva\n",
"2\nno\n",
"4\nabba\n"
] | [
"volga\n",
"no\n",
"baba\n"
] | In the first example Polycarp encoded the word volga. At first, he wrote down the letter l from the position 3, after that his word looked like voga. After that Polycarp wrote down the letter o from the position 2, his word became vga. Then Polycarp wrote down the letter g which was at the second position, the word bec... | 1,000 | [
{
"input": "5\nlogva",
"output": "volga"
},
{
"input": "2\nno",
"output": "no"
},
{
"input": "4\nabba",
"output": "baba"
},
{
"input": "51\nkfsmpaeviowvkdbuhdagquxxqniselafnfbrgbhmsugcbbnlrvv",
"output": "vlbcumbrfflsnxugdudvovamfkspeiwkbhaqxqieanbghsgbnrv"
},
{
"... | 1,692,177,847 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | n = int(input())
s = input()
a = []
if len(s) % 2 == 1:
for i in range(0, len(s)-2, 2):
a.append(s[i])
a.insert(0, s[i+1])
print("".join(a) + s[-1])
else:
for i in range(0, len(s), 2):
a.insert(0,s[i])
a.append(s[i+1])
print("".join(a))
| Title: Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the... | ```python
n = int(input())
s = input()
a = []
if len(s) % 2 == 1:
for i in range(0, len(s)-2, 2):
a.append(s[i])
a.insert(0, s[i+1])
print("".join(a) + s[-1])
else:
for i in range(0, len(s), 2):
a.insert(0,s[i])
a.append(s[i+1])
print("".join(a))
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Recently, a start up by two students of a state university of city F gained incredible popularity. Now it's time to start a new company. But what do we call it?
The market analysts came up with a very smart plan: the name of the company should be identical to its reflection in a mirror! In other words, if we write out... | The first line contains a non-empty name that needs to be checked. The name contains at most 105 large English letters. The name will be written with the next sans serif font: | Print 'YES' (without the quotes), if the given name matches its mirror reflection. Otherwise, print 'NO' (without the quotes). | [
"AHA\n",
"Z\n",
"XO\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 0 | [
{
"input": "AHA",
"output": "YES"
},
{
"input": "Z",
"output": "NO"
},
{
"input": "XO",
"output": "NO"
},
{
"input": "AAA",
"output": "YES"
},
{
"input": "AHHA",
"output": "YES"
},
{
"input": "BAB",
"output": "NO"
},
{
"input": "OMMMAAMMMO"... | 1,672,343,943 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 52 | 77 | 1,024,000 | '''
@author: SamirPaul1
'''
import io
import os
import sys
import math
import heapq
import bisect
import random
import string
import decimal
import functools
import fractions
import itertools
import collections
from sys import stdin, stdout
from io import BytesIO, IOBase
from math import gcd, floor... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, a start up by two students of a state university of city F gained incredible popularity. Now it's time to start a new company. But what do we call it?
The market analysts came up with a very smart plan: the name of the ... | ```python
'''
@author: SamirPaul1
'''
import io
import os
import sys
import math
import heapq
import bisect
import random
import string
import decimal
import functools
import fractions
import itertools
import collections
from sys import stdin, stdout
from io import BytesIO, IOBase
from math import ... | 0 | |
263 | A | Beautiful Matrix | PROGRAMMING | 800 | [
"implementation"
] | null | null | You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix:
1.... | The input consists of five lines, each line contains five integers: the *j*-th integer in the *i*-th line of the input represents the element of the matrix that is located on the intersection of the *i*-th row and the *j*-th column. It is guaranteed that the matrix consists of 24 zeroes and a single number one. | Print a single integer — the minimum number of moves needed to make the matrix beautiful. | [
"0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n",
"0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n"
] | [
"3\n",
"1\n"
] | none | 500 | [
{
"input": "0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 1 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "0"
},
{
"input": "0 0 0 0 0... | 1,695,320,838 | 738 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | mat = [list(map(int, input().split())) for i in range(5)]
r, c = None, None
for j in range(5):
for k in range(5):
if mat[j][k] == 1:
r, c = j, k
m = abs(r - 2)
| Title: Beautiful Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to ri... | ```python
mat = [list(map(int, input().split())) for i in range(5)]
r, c = None, None
for j in range(5):
for k in range(5):
if mat[j][k] == 1:
r, c = j, k
m = abs(r - 2)
``` | 0 | |
554 | A | Kyoya and Photobooks | PROGRAMMING | 900 | [
"brute force",
"math",
"strings"
] | null | null | Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the pho... | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters. | Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make. | [
"a\n",
"hi\n"
] | [
"51\n",
"76\n"
] | In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | 250 | [
{
"input": "a",
"output": "51"
},
{
"input": "hi",
"output": "76"
},
{
"input": "y",
"output": "51"
},
{
"input": "kgan",
"output": "126"
},
{
"input": "zoabkyuvus",
"output": "276"
},
{
"input": "spyemhyznjieyhhbk",
"output": "451"
},
{
"i... | 1,560,772,615 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 124 | 0 | #abcdefghijklmnopqrstuvwxyz
s=input()
l=len(s)
res=(26*(l+1))-(l)
print(res)
| Title: Kyoya and Photobooks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos b... | ```python
#abcdefghijklmnopqrstuvwxyz
s=input()
l=len(s)
res=(26*(l+1))-(l)
print(res)
``` | 3 | |
233 | A | Perfect Permutation | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size of permutation *p*1,<=*p*2,<=...,<=*p**n*.
Nickolas adores permutations. He lik... | A single line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the permutation size. | If a perfect permutation of size *n* doesn't exist, print a single integer -1. Otherwise print *n* distinct integers from 1 to *n*, *p*1,<=*p*2,<=...,<=*p**n* — permutation *p*, that is perfect. Separate printed numbers by whitespaces. | [
"1\n",
"2\n",
"4\n"
] | [
"-1\n",
"2 1 \n",
"2 1 4 3 \n"
] | none | 500 | [
{
"input": "1",
"output": "-1"
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "4",
"output": "2 1 4 3 "
},
{
"input": "3",
"output": "-1"
},
{
"input": "5",
"output": "-1"
},
{
"input": "6",
"output": "2 1 4 3 6 5 "
},
{
"input": "7",
... | 1,630,261,733 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 154 | 6,963,200 | n=int(input())
l=[]
if n==1:
print(-1)
elif n%2==0:
for i in range(1,n+1):
l.append(i)
for j in range(0,len(l)-1,2):
c,d=l[j],l[j+1]
l[j],l[j+1]=d,c
print(*l)
else:
for i in range(1,n+1):
l.append(i)
c = l[int(n//2)]
d = l[n-1]
l[int(n//2)... | Title: Perfect Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll ... | ```python
n=int(input())
l=[]
if n==1:
print(-1)
elif n%2==0:
for i in range(1,n+1):
l.append(i)
for j in range(0,len(l)-1,2):
c,d=l[j],l[j+1]
l[j],l[j+1]=d,c
print(*l)
else:
for i in range(1,n+1):
l.append(i)
c = l[int(n//2)]
d = l[n-1]
l... | 0 | |
978 | D | Almost Arithmetic Progression | PROGRAMMING | 1,500 | [
"brute force",
"implementation",
"math"
] | null | null | Polycarp likes arithmetic progressions. A sequence $[a_1, a_2, \dots, a_n]$ is called an arithmetic progression if for each $i$ ($1 \le i < n$) the value $a_{i+1} - a_i$ is the same. For example, the sequences $[42]$, $[5, 5, 5]$, $[2, 11, 20, 29]$ and $[3, 2, 1, 0]$ are arithmetic progressions, but $[1, 0, 1]$, $[1... | The first line contains a single integer $n$ $(1 \le n \le 100\,000)$ — the number of elements in $b$.
The second line contains a sequence $b_1, b_2, \dots, b_n$ $(1 \le b_i \le 10^{9})$. | If it is impossible to make an arithmetic progression with described operations, print -1. In the other case, print non-negative integer — the minimum number of elements to change to make the given sequence becomes an arithmetic progression. The only allowed operation is to add/to subtract one from an element (can't us... | [
"4\n24 21 14 10\n",
"2\n500 500\n",
"3\n14 5 1\n",
"5\n1 3 6 9 12\n"
] | [
"3\n",
"0\n",
"-1\n",
"1\n"
] | In the first example Polycarp should increase the first number on $1$, decrease the second number on $1$, increase the third number on $1$, and the fourth number should left unchanged. So, after Polycarp changed three elements by one, his sequence became equals to $[25, 20, 15, 10]$, which is an arithmetic progression.... | 0 | [
{
"input": "4\n24 21 14 10",
"output": "3"
},
{
"input": "2\n500 500",
"output": "0"
},
{
"input": "3\n14 5 1",
"output": "-1"
},
{
"input": "5\n1 3 6 9 12",
"output": "1"
},
{
"input": "1\n1000000000",
"output": "0"
},
{
"input": "2\n1000000000 1",
... | 1,685,989,929 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 93 | 13,619,200 | def solve():
n = int(input())
a = list(map(int, input().split()))
if n <= 2:
print(0)
else:
final_ans = float('inf')
for i in [-1, 0, 1]:
for j in [-1, 0, 1]:
a0 = a[0] + i
a1 = a[1] + j
prev = a1
... | Title: Almost Arithmetic Progression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp likes arithmetic progressions. A sequence $[a_1, a_2, \dots, a_n]$ is called an arithmetic progression if for each $i$ ($1 \le i < n$) the value $a_{i+1} - a_i$ is the same. For example, the se... | ```python
def solve():
n = int(input())
a = list(map(int, input().split()))
if n <= 2:
print(0)
else:
final_ans = float('inf')
for i in [-1, 0, 1]:
for j in [-1, 0, 1]:
a0 = a[0] + i
a1 = a[1] + j
prev = a1
... | 3 | |
670 | B | Game of Robots | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | In late autumn evening *n* robots gathered in the cheerful company of friends. Each robot has a unique identifier — an integer from 1 to 109.
At some moment, robots decided to play the game "Snowball". Below there are the rules of this game. First, all robots stand in a row. Then the first robot says his identifier. A... | The first line contains two positive integers *n* and *k* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*k*<=≤<=*min*(2·109,<=*n*·(*n*<=+<=1)<=/<=2).
The second line contains the sequence *id*1,<=*id*2,<=...,<=*id**n* (1<=≤<=*id**i*<=≤<=109) — identifiers of roborts. It is guaranteed that all identifiers are different. | Print the *k*-th pronounced identifier (assume that the numeration starts from 1). | [
"2 2\n1 2\n",
"4 5\n10 4 18 3\n"
] | [
"1\n",
"4\n"
] | In the first sample identifiers of robots will be pronounced in the following order: 1, 1, 2. As *k* = 2, the answer equals to 1.
In the second test case identifiers of robots will be pronounced in the following order: 10, 10, 4, 10, 4, 18, 10, 4, 18, 3. As *k* = 5, the answer equals to 4. | 750 | [
{
"input": "2 2\n1 2",
"output": "1"
},
{
"input": "4 5\n10 4 18 3",
"output": "4"
},
{
"input": "1 1\n4",
"output": "4"
},
{
"input": "2 1\n5 1",
"output": "5"
},
{
"input": "2 2\n1 4",
"output": "1"
},
{
"input": "2 3\n6 7",
"output": "7"
},
... | 1,651,243,129 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | entrada1 = input().split()
entrada2 = input()
for i in range(len(entrada1)):
n = int(entrada1[1])
print(n - 1)
| Title: Game of Robots
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In late autumn evening *n* robots gathered in the cheerful company of friends. Each robot has a unique identifier — an integer from 1 to 109.
At some moment, robots decided to play the game "Snowball". Below there are t... | ```python
entrada1 = input().split()
entrada2 = input()
for i in range(len(entrada1)):
n = int(entrada1[1])
print(n - 1)
``` | 0 | |
761 | D | Dasha and Very Difficult Problem | PROGRAMMING | 1,700 | [
"binary search",
"brute force",
"constructive algorithms",
"greedy",
"sortings"
] | null | null | Dasha logged into the system and began to solve problems. One of them is as follows:
Given two sequences *a* and *b* of length *n* each you need to write a sequence *c* of length *n*, the *i*-th element of which is calculated as follows: *c**i*<==<=*b**i*<=-<=*a**i*.
About sequences *a* and *b* we know that their ele... | The first line contains three integers *n*, *l*, *r* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*l*<=≤<=*r*<=≤<=109) — the length of the sequence and boundaries of the segment where the elements of sequences *a* and *b* are.
The next line contains *n* integers *a*1,<=<=*a*2,<=<=...,<=<=*a**n* (*l*<=≤<=*a**i*<=≤<=*r*) — the elements o... | If there is no the suitable sequence *b*, then in the only line print "-1".
Otherwise, in the only line print *n* integers — the elements of any suitable sequence *b*. | [
"5 1 5\n1 1 1 1 1\n3 1 5 4 2\n",
"4 2 9\n3 4 8 9\n3 2 1 4\n",
"6 1 5\n1 1 1 1 1 1\n2 3 5 4 1 6\n"
] | [
"3 1 5 4 2 ",
"2 2 2 9 ",
"-1\n"
] | Sequence *b* which was found in the second sample is suitable, because calculated sequence *c* = [2 - 3, 2 - 4, 2 - 8, 9 - 9] = [ - 1, - 2, - 6, 0] (note that *c*<sub class="lower-index">*i*</sub> = *b*<sub class="lower-index">*i*</sub> - *a*<sub class="lower-index">*i*</sub>) has compressed sequence equals to *p* = ... | 2,000 | [
{
"input": "5 1 5\n1 1 1 1 1\n3 1 5 4 2",
"output": "3 1 5 4 2 "
},
{
"input": "4 2 9\n3 4 8 9\n3 2 1 4",
"output": "2 2 2 9 "
},
{
"input": "6 1 5\n1 1 1 1 1 1\n2 3 5 4 1 6",
"output": "-1"
},
{
"input": "5 1 7\n1 4 4 6 5\n5 2 1 4 3",
"output": "2 2 1 6 4 "
},
{
... | 1,568,453,601 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 124 | 0 | n,l,r=map(int,input().split())
a=[int(i) for i in input().split()]
p=[int(i) for i in input().split()]
#p is compressed form of c
b=[a[i]+p[i] for i in range(n)]
print(*b) | Title: Dasha and Very Difficult Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dasha logged into the system and began to solve problems. One of them is as follows:
Given two sequences *a* and *b* of length *n* each you need to write a sequence *c* of length *n*, the *i*-th elemen... | ```python
n,l,r=map(int,input().split())
a=[int(i) for i in input().split()]
p=[int(i) for i in input().split()]
#p is compressed form of c
b=[a[i]+p[i] for i in range(n)]
print(*b)
``` | 0 | |
796 | B | Find The Bone | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Zane the wizard is going to perform a magic show shuffling the cups.
There are *n* cups, numbered from 1 to *n*, placed along the *x*-axis on a table that has *m* holes on it. More precisely, cup *i* is on the table at the position *x*<==<=*i*.
The problematic bone is initially at the position *x*<==<=1. Zane will co... | The first line contains three integers *n*, *m*, and *k* (2<=≤<=*n*<=≤<=106, 1<=≤<=*m*<=≤<=*n*, 1<=≤<=*k*<=≤<=3·105) — the number of cups, the number of holes on the table, and the number of swapping operations, respectively.
The second line contains *m* distinct integers *h*1,<=*h*2,<=...,<=*h**m* (1<=≤<=*h**i*<=≤<=*... | Print one integer — the final position along the *x*-axis of the bone. | [
"7 3 4\n3 4 6\n1 2\n2 5\n5 7\n7 1\n",
"5 1 2\n2\n1 2\n2 4\n"
] | [
"1",
"2"
] | In the first sample, after the operations, the bone becomes at *x* = 2, *x* = 5, *x* = 7, and *x* = 1, respectively.
In the second sample, after the first operation, the bone becomes at *x* = 2, and falls into the hole onto the ground. | 750 | [
{
"input": "7 3 4\n3 4 6\n1 2\n2 5\n5 7\n7 1",
"output": "1"
},
{
"input": "5 1 2\n2\n1 2\n2 4",
"output": "2"
},
{
"input": "10000 1 9\n55\n44 1\n2929 9292\n9999 9998\n44 55\n49 94\n55 53\n100 199\n55 50\n53 11",
"output": "55"
},
{
"input": "100000 3 7\n2 3 4\n1 5\n5 1\n1 5... | 1,553,281,328 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 21,913,600 | from math import gcd
from functools import reduce
def main():
n, m, k = input().split()
holes = []
[holes.append(int(i)-1) for i in input().split()]
#print(holes)
bone = 0
for _ in range(int(k)):
for hole in holes:
if hole == bone:
print(bone+1)
... | Title: Find The Bone
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Zane the wizard is going to perform a magic show shuffling the cups.
There are *n* cups, numbered from 1 to *n*, placed along the *x*-axis on a table that has *m* holes on it. More precisely, cup *i* is on the table at t... | ```python
from math import gcd
from functools import reduce
def main():
n, m, k = input().split()
holes = []
[holes.append(int(i)-1) for i in input().split()]
#print(holes)
bone = 0
for _ in range(int(k)):
for hole in holes:
if hole == bone:
print(bone+1)
... | 0 | |
554 | A | Kyoya and Photobooks | PROGRAMMING | 900 | [
"brute force",
"math",
"strings"
] | null | null | Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the pho... | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters. | Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make. | [
"a\n",
"hi\n"
] | [
"51\n",
"76\n"
] | In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | 250 | [
{
"input": "a",
"output": "51"
},
{
"input": "hi",
"output": "76"
},
{
"input": "y",
"output": "51"
},
{
"input": "kgan",
"output": "126"
},
{
"input": "zoabkyuvus",
"output": "276"
},
{
"input": "spyemhyznjieyhhbk",
"output": "451"
},
{
"i... | 1,478,547,323 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 62 | 0 | s=input()
n=len(s)
ans=(n+1)*(26-n)+(n*n);
print(ans)
| Title: Kyoya and Photobooks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos b... | ```python
s=input()
n=len(s)
ans=(n+1)*(26-n)+(n*n);
print(ans)
``` | 3 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,679,997,752 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 61 | 0 | a = input()
list1 = []
for i in a:
if i == 'h' or i == 'e' or i == 'l' or i == 'o':
if i not in list1:
list1.append(i)
word = "".join(list1)
if(word=="helo"):
print("YES")
else:
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
a = input()
list1 = []
for i in a:
if i == 'h' or i == 'e' or i == 'l' or i == 'o':
if i not in list1:
list1.append(i)
word = "".join(list1)
if(word=="helo"):
print("YES")
else:
print("NO")
``` | 0 |
583 | A | Asphalting Roads | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers of the roads that form them.
Sand roads have long been recognized out of date, so the decision was ma... | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of vertical and horizontal roads in the city.
Next *n*2 lines contain the order of intersections in the schedule. The *i*-th of them contains two numbers *h**i*,<=*v**i* (1<=≤<=*h**i*,<=*v**i*<=≤<=*n*), separated by a space, and meaning that the inte... | In the single line print the numbers of the days when road works will be in progress in ascending order. The days are numbered starting from 1. | [
"2\n1 1\n1 2\n2 1\n2 2\n",
"1\n1 1\n"
] | [
"1 4 \n",
"1 \n"
] | In the sample the brigade acts like that:
1. On the first day the brigade comes to the intersection of the 1-st horizontal and the 1-st vertical road. As none of them has been asphalted, the workers asphalt the 1-st vertical and the 1-st horizontal road; 1. On the second day the brigade of the workers comes to the i... | 500 | [
{
"input": "2\n1 1\n1 2\n2 1\n2 2",
"output": "1 4 "
},
{
"input": "1\n1 1",
"output": "1 "
},
{
"input": "2\n1 1\n2 2\n1 2\n2 1",
"output": "1 2 "
},
{
"input": "2\n1 2\n2 2\n2 1\n1 1",
"output": "1 3 "
},
{
"input": "3\n2 2\n1 2\n3 2\n3 3\n1 1\n2 3\n1 3\n3 1\n2 ... | 1,686,295,663 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | hhvu
uvuvinu
j ju
ubi | Title: Asphalting Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers ... | ```python
hhvu
uvuvinu
j ju
ubi
``` | -1 | |
514 | A | Chewbaсca and Number | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform the initial number *x* to the minimum possible positive number by inverting some (possibly, zero) digits.... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=1018) — the number that Luke Skywalker gave to Chewbacca. | Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes. | [
"27\n",
"4545\n"
] | [
"22\n",
"4444\n"
] | none | 500 | [
{
"input": "27",
"output": "22"
},
{
"input": "4545",
"output": "4444"
},
{
"input": "1",
"output": "1"
},
{
"input": "9",
"output": "9"
},
{
"input": "8772",
"output": "1222"
},
{
"input": "81",
"output": "11"
},
{
"input": "71723447",
... | 1,695,392,361 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 |
number = int(input())
arr = []
while number > 0:
digit = number % 10
if 9 - digit < digit:
arr.append(9 - digit)
else:
arr.append(digit)
number //= 10
num = 0
for idx in reversed(range(len(arr))):
num = num * 10 + arr[idx]
print(num)
| Title: Chewbaсca and Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform... | ```python
number = int(input())
arr = []
while number > 0:
digit = number % 10
if 9 - digit < digit:
arr.append(9 - digit)
else:
arr.append(digit)
number //= 10
num = 0
for idx in reversed(range(len(arr))):
num = num * 10 + arr[idx]
print(num)
... | 0 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,665,147,195 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 92 | 0 | tt = int(input())
def totmed(data):
tot = 0
sp1, sp2 = 0, 0
f1, f2, f3 = "", "", ""
for i in data:
if i != " " and sp1 == 0 and sp2 == 0:
f1 += i
elif i == " " and sp1 == 0 and sp2 == 0:
sp1 += 1
elif i != " " and sp1 == 1 and sp2 == 0:
... | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. S... | ```python
tt = int(input())
def totmed(data):
tot = 0
sp1, sp2 = 0, 0
f1, f2, f3 = "", "", ""
for i in data:
if i != " " and sp1 == 0 and sp2 == 0:
f1 += i
elif i == " " and sp1 == 0 and sp2 == 0:
sp1 += 1
elif i != " " and sp1 == 1 and sp2 == ... | 3.977 |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,697,285,467 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 25 | 92 | 0 | n = int(input())
digit_numbers = {"4", "7"}
if not any(digit not in digit_numbers for digit in str(n)) or (n % 4 == 0 or n % 7 == 0):
print("YES")
else:
print("NO") | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n = int(input())
digit_numbers = {"4", "7"}
if not any(digit not in digit_numbers for digit in str(n)) or (n % 4 == 0 or n % 7 == 0):
print("YES")
else:
print("NO")
``` | 0 | |
63 | B | Settlers' Training | PROGRAMMING | 1,200 | [
"implementation"
] | B. Settlers' Training | 2 | 256 | In a strategic computer game "Settlers II" one has to build defense structures to expand and protect the territory. Let's take one of these buildings. At the moment the defense structure accommodates exactly *n* soldiers. Within this task we can assume that the number of soldiers in the defense structure won't either i... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100). They represent the number of soldiers and the number of different ranks correspondingly. The second line contains *n* numbers in the non-decreasing order. The *i*-th of them, *a**i*, represents the rank of the *i*-th soldier in the defense buil... | Print a single integer — the number of golden coins needed to raise all the soldiers to the maximal rank. | [
"4 4\n1 2 2 3\n",
"4 3\n1 1 1 1\n"
] | [
"4",
"5"
] | In the first example the ranks will be raised in the following manner:
1 2 2 3 → 2 2 3 4 → 2 3 4 4 → 3 4 4 4 → 4 4 4 4
Thus totals to 4 training sessions that require 4 golden coins. | 1,000 | [
{
"input": "4 4\n1 2 2 3",
"output": "4"
},
{
"input": "4 3\n1 1 1 1",
"output": "5"
},
{
"input": "3 3\n1 2 3",
"output": "2"
},
{
"input": "1 1\n1",
"output": "0"
},
{
"input": "1 5\n1",
"output": "4"
},
{
"input": "1 5\n4",
"output": "1"
},
... | 1,591,089,490 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 340 | 1,740,800 | from sys import stdin,stdout
import math
from collections import Counter,deque
L=lambda:list(map(int, stdin.readline().strip().split()))
M=lambda:map(int, stdin.readline().strip().split())
I=lambda:int(stdin.readline().strip())
IN=lambda:stdin.readline().strip()
C=lambda:stdin.readline().strip().split()
mod=10... | Title: Settlers' Training
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
In a strategic computer game "Settlers II" one has to build defense structures to expand and protect the territory. Let's take one of these buildings. At the moment the defense structure accommodates exactly *n* soldiers... | ```python
from sys import stdin,stdout
import math
from collections import Counter,deque
L=lambda:list(map(int, stdin.readline().strip().split()))
M=lambda:map(int, stdin.readline().strip().split())
I=lambda:int(stdin.readline().strip())
IN=lambda:stdin.readline().strip()
C=lambda:stdin.readline().strip().split... | 3.911758 |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,646,692,665 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | #Метод подсчета
a=[0,1,2,3,2,1,2,3,3,2,4,3,5,3,2] #максимальное количество разных элементов - 6
count=[0]*6
for i in a:
count[i]+=1
print(count) #[1, 2, 5, 5, 1, 1]
for i in range(len(count)):
print(i,count[i])
#Отсортировать по возрастанию
a=[0,1,2,3,2,1,2,3,3,2,4,3,5,3,2] #максимальное количество р... | Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same colo... | ```python
#Метод подсчета
a=[0,1,2,3,2,1,2,3,3,2,4,3,5,3,2] #максимальное количество разных элементов - 6
count=[0]*6
for i in a:
count[i]+=1
print(count) #[1, 2, 5, 5, 1, 1]
for i in range(len(count)):
print(i,count[i])
#Отсортировать по возрастанию
a=[0,1,2,3,2,1,2,3,3,2,4,3,5,3,2] #максимальное ко... | 0 | |
17 | A | Noldbach problem | PROGRAMMING | 1,000 | [
"brute force",
"math",
"number theory"
] | A. Noldbach problem | 2 | 64 | Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nick's attention and he decided to invent a problem of his own and call it Noldbach problem. Since Nick is interested only in prime numbers, Nold... | The first line of the input contains two integers *n* (2<=≤<=*n*<=≤<=1000) and *k* (0<=≤<=*k*<=≤<=1000). | Output YES if at least *k* prime numbers from 2 to *n* inclusively can be expressed as it was described above. Otherwise output NO. | [
"27 2\n",
"45 7\n"
] | [
"YES",
"NO"
] | In the first sample the answer is YES since at least two numbers can be expressed as it was described (for example, 13 and 19). In the second sample the answer is NO since it is impossible to express 7 prime numbers from 2 to 45 in the desired form. | 0 | [
{
"input": "27 2",
"output": "YES"
},
{
"input": "45 7",
"output": "NO"
},
{
"input": "2 0",
"output": "YES"
},
{
"input": "15 1",
"output": "YES"
},
{
"input": "17 1",
"output": "YES"
},
{
"input": "34 5",
"output": "NO"
},
{
"input": "37 ... | 1,625,071,722 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 184 | 0 | from math import sqrt
def use_sieve(N,K):
# length = int(sqrt(N))+1
length = N//2
sieve = [True]*(N+1)
noldB_nums = []
past_prime = -1
for i in range(2,length+1):
if sieve[i]:
for j in range(i*i,N+1,i):
sieve[j] = False
if past_prime != ... | Title: Noldbach problem
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nick's attention and he decided to invent a prob... | ```python
from math import sqrt
def use_sieve(N,K):
# length = int(sqrt(N))+1
length = N//2
sieve = [True]*(N+1)
noldB_nums = []
past_prime = -1
for i in range(2,length+1):
if sieve[i]:
for j in range(i*i,N+1,i):
sieve[j] = False
if past... | 0 |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,690,276,413 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | g=int(input())
if g%==0 and g>2:
print("Yes")
else:
print("No")
| Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
g=int(input())
if g%==0 and g>2:
print("Yes")
else:
print("No")
``` | -1 |
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