contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
644 | A | Parliament of Berland | PROGRAMMING | 1,000 | [
"*special",
"constructive algorithms"
] | null | null | There are *n* parliamentarians in Berland. They are numbered with integers from 1 to *n*. It happened that all parliamentarians with odd indices are Democrats and all parliamentarians with even indices are Republicans.
New parliament assembly hall is a rectangle consisting of *a*<=×<=*b* chairs — *a* rows of *b* chair... | The first line of the input contains three integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=10<=000, 1<=≤<=*a*,<=*b*<=≤<=100) — the number of parliamentarians, the number of rows in the assembly hall and the number of seats in each row, respectively. | If there is no way to assigns seats to parliamentarians in a proper way print -1.
Otherwise print the solution in *a* lines, each containing *b* integers. The *j*-th integer of the *i*-th line should be equal to the index of parliamentarian occupying this seat, or 0 if this seat should remain empty. If there are multi... | [
"3 2 2\n",
"8 4 3\n",
"10 2 2\n"
] | [
"0 3\n1 2\n",
"7 8 3\n0 1 4\n6 0 5\n0 2 0\n",
"-1\n"
] | In the first sample there are many other possible solutions. For example,
and
The following assignment
is incorrect, because parliamentarians 1 and 3 are both from Democrats party but will occupy neighbouring seats. | 500 | [
{
"input": "3 2 2",
"output": "1 2 \n0 3 "
},
{
"input": "8 4 3",
"output": "1 2 3 \n4 5 6 \n7 8 0 \n0 0 0 "
},
{
"input": "10 2 2",
"output": "-1"
},
{
"input": "1 1 1",
"output": "1 "
},
{
"input": "8 3 3",
"output": "1 2 3 \n4 5 6 \n7 8 0 "
},
{
"in... | 1,617,870,824 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 77 | 0 | n , a , b = map(int , input().split())
if n > a*b:
print(-1)
else:
arr = [[0]*b for _ in range(a)]
x = 1
y = 2
for i in range(a):
for j in range(b):
if i+j % 2:
if x <= n:
arr[i][j] = x
x +=2
els... | Title: Parliament of Berland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* parliamentarians in Berland. They are numbered with integers from 1 to *n*. It happened that all parliamentarians with odd indices are Democrats and all parliamentarians with even indices are Republi... | ```python
n , a , b = map(int , input().split())
if n > a*b:
print(-1)
else:
arr = [[0]*b for _ in range(a)]
x = 1
y = 2
for i in range(a):
for j in range(b):
if i+j % 2:
if x <= n:
arr[i][j] = x
x +=2
... | 0 | |
104 | A | Blackjack | PROGRAMMING | 800 | [
"implementation"
] | A. Blackjack | 2 | 256 | One rainy gloomy evening when all modules hid in the nearby cafes to drink hot energetic cocktails, the Hexadecimal virus decided to fly over the Mainframe to look for a Great Idea. And she has found one!
Why not make her own Codeforces, with blackjack and other really cool stuff? Many people will surely be willing to... | The only line contains *n* (1<=≤<=*n*<=≤<=25) — the required sum of points. | Print the numbers of ways to get the second card in the required way if the first card is the queen of spades. | [
"12\n",
"20\n",
"10\n"
] | [
"4",
"15",
"0"
] | In the first sample only four two's of different suits can earn the required sum of points.
In the second sample we can use all tens, jacks, queens and kings; overall it's 15 cards, as the queen of spades (as any other card) is only present once in the pack of cards and it's already in use.
In the third sample there ... | 500 | [
{
"input": "12",
"output": "4"
},
{
"input": "20",
"output": "15"
},
{
"input": "10",
"output": "0"
},
{
"input": "11",
"output": "4"
},
{
"input": "15",
"output": "4"
},
{
"input": "18",
"output": "4"
},
{
"input": "25",
"output": "0"
... | 1,553,863,429 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 186 | 0 | n=int(input())
r=n-10
if(r>=2 or r<=9):
print(4)
if(r==10):
print(15)
if(r==1 or r==11):
print(4)
else:
print(0)
| Title: Blackjack
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One rainy gloomy evening when all modules hid in the nearby cafes to drink hot energetic cocktails, the Hexadecimal virus decided to fly over the Mainframe to look for a Great Idea. And she has found one!
Why not make her own Co... | ```python
n=int(input())
r=n-10
if(r>=2 or r<=9):
print(4)
if(r==10):
print(15)
if(r==1 or r==11):
print(4)
else:
print(0)
``` | 0 |
38 | E | Let's Go Rolling! | PROGRAMMING | 1,800 | [
"dp",
"sortings"
] | E. Let's Go Rolling! | 2 | 256 | On a number axis directed from the left rightwards, *n* marbles with coordinates *x*1,<=*x*2,<=...,<=*x**n* are situated. Let's assume that the sizes of the marbles are infinitely small, that is in this task each of them is assumed to be a material point. You can stick pins in some of them and the cost of sticking in t... | The first input line contains an integer *n* (1<=≤<=*n*<=≤<=3000) which is the number of marbles. The next *n* lines contain the descriptions of the marbles in pairs of integers *x**i*, *c**i* (<=-<=109<=≤<=*x**i*,<=*c**i*<=≤<=109). The numbers are space-separated. Each description is given on a separate line. No two m... | Output the single number — the least fine you will have to pay. | [
"3\n2 3\n3 4\n1 2\n",
"4\n1 7\n3 1\n5 10\n6 1\n"
] | [
"5\n",
"11\n"
] | none | 0 | [
{
"input": "3\n2 3\n3 4\n1 2",
"output": "5"
},
{
"input": "4\n1 7\n3 1\n5 10\n6 1",
"output": "11"
},
{
"input": "1\n-948943148 10",
"output": "10"
},
{
"input": "5\n864449017 54\n864449026 504\n864449027 308\n864449028 284\n864449030 249",
"output": "97"
},
{
"i... | 1,575,974,756 | 2,147,483,647 | PyPy 3 | OK | TESTS | 50 | 1,122 | 9,318,400 | from typing import Tuple, List
def compute(n: int, m: List[Tuple[int, int]]) -> int:
m = sorted(m)
state = [0] * (n + 1)
state[n - 1] = m[n - 1][1]
for i in range(n - 2, -1, -1):
min_cost = state[i + 1]
acc = 0
for j in range(i + 2, n + 1):
min_cost = min(min_cost, ... | Title: Let's Go Rolling!
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
On a number axis directed from the left rightwards, *n* marbles with coordinates *x*1,<=*x*2,<=...,<=*x**n* are situated. Let's assume that the sizes of the marbles are infinitely small, that is in this task each of them ... | ```python
from typing import Tuple, List
def compute(n: int, m: List[Tuple[int, int]]) -> int:
m = sorted(m)
state = [0] * (n + 1)
state[n - 1] = m[n - 1][1]
for i in range(n - 2, -1, -1):
min_cost = state[i + 1]
acc = 0
for j in range(i + 2, n + 1):
min_cost = min(... | 3.702143 |
622 | C | Not Equal on a Segment | PROGRAMMING | 1,700 | [
"data structures",
"implementation"
] | null | null | You are given array *a* with *n* integers and *m* queries. The *i*-th query is given with three integers *l**i*,<=*r**i*,<=*x**i*.
For the *i*-th query find any position *p**i* (*l**i*<=≤<=*p**i*<=≤<=*r**i*) so that *a**p**i*<=≠<=*x**i*. | The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=2·105) — the number of elements in *a* and the number of queries.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=106) — the elements of the array *a*.
Each of the next *m* lines contains three integers *l**i*,<=*r**i*,<=*x**i* (1<=≤<=... | Print *m* lines. On the *i*-th line print integer *p**i* — the position of any number not equal to *x**i* in segment [*l**i*,<=*r**i*] or the value <=-<=1 if there is no such number. | [
"6 4\n1 2 1 1 3 5\n1 4 1\n2 6 2\n3 4 1\n3 4 2\n"
] | [
"2\n6\n-1\n4\n"
] | none | 0 | [
{
"input": "6 4\n1 2 1 1 3 5\n1 4 1\n2 6 2\n3 4 1\n3 4 2",
"output": "2\n6\n-1\n4"
},
{
"input": "1 1\n1\n1 1 1",
"output": "-1"
},
{
"input": "1 1\n2\n1 1 2",
"output": "-1"
},
{
"input": "1 1\n569888\n1 1 967368",
"output": "1"
},
{
"input": "10 10\n1 1 1 1 1 1 ... | 1,462,969,642 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 997 | 30,003,200 | n,m=map(int,input().split())
l=input().split()
L,ans=[0 for i in range(n)],[]
L[0]=-1
for i in range(1,n):
if l[i]==l[i-1]:
L[i]=L[i-1]
else:L[i]=i
for i in range(m):
s=input().split()
b=int(s[1])
if l[b-1]!=s[2]:
ans+=[str(b)]
elif L[b-1]>=int(s[0]):
ans+=[... | Title: Not Equal on a Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given array *a* with *n* integers and *m* queries. The *i*-th query is given with three integers *l**i*,<=*r**i*,<=*x**i*.
For the *i*-th query find any position *p**i* (*l**i*<=≤<=*p**i*<=≤<=*r**i*) so ... | ```python
n,m=map(int,input().split())
l=input().split()
L,ans=[0 for i in range(n)],[]
L[0]=-1
for i in range(1,n):
if l[i]==l[i-1]:
L[i]=L[i-1]
else:L[i]=i
for i in range(m):
s=input().split()
b=int(s[1])
if l[b-1]!=s[2]:
ans+=[str(b)]
elif L[b-1]>=int(s[0]):
... | 3 | |
427 | C | Checkposts | PROGRAMMING | 1,700 | [
"dfs and similar",
"graphs",
"two pointers"
] | null | null | Your city has *n* junctions. There are *m* one-way roads between the junctions. As a mayor of the city, you have to ensure the security of all the junctions.
To ensure the security, you have to build some police checkposts. Checkposts can only be built in a junction. A checkpost at junction *i* can protect junction *j... | In the first line, you will be given an integer *n*, number of junctions (1<=≤<=*n*<=≤<=105). In the next line, *n* space-separated integers will be given. The *i**th* integer is the cost of building checkpost at the *i**th* junction (costs will be non-negative and will not exceed 109).
The next line will contain an i... | Print two integers separated by spaces. The first one is the minimum possible money needed to ensure the security of all the junctions. And the second one is the number of ways you can ensure the security modulo 1000000007 (109<=+<=7). | [
"3\n1 2 3\n3\n1 2\n2 3\n3 2\n",
"5\n2 8 0 6 0\n6\n1 4\n1 3\n2 4\n3 4\n4 5\n5 1\n",
"10\n1 3 2 2 1 3 1 4 10 10\n12\n1 2\n2 3\n3 1\n3 4\n4 5\n5 6\n5 7\n6 4\n7 3\n8 9\n9 10\n10 9\n",
"2\n7 91\n2\n1 2\n2 1\n"
] | [
"3 1\n",
"8 2\n",
"15 6\n",
"7 1\n"
] | none | 1,500 | [
{
"input": "3\n1 2 3\n3\n1 2\n2 3\n3 2",
"output": "3 1"
},
{
"input": "5\n2 8 0 6 0\n6\n1 4\n1 3\n2 4\n3 4\n4 5\n5 1",
"output": "8 2"
},
{
"input": "10\n1 3 2 2 1 3 1 4 10 10\n12\n1 2\n2 3\n3 1\n3 4\n4 5\n5 6\n5 7\n6 4\n7 3\n8 9\n9 10\n10 9",
"output": "15 6"
},
{
"input": ... | 1,684,777,910 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 70 | 795 | 50,892,800 | from collections import deque as dq
def topological(G):
n = len(G)
sort = []
visited = [False for _ in range(n)]
def dfs(G, u):
nonlocal sort
nonlocal visited
visited[u] = True
for v in G[u]:
if not visited[v]:
dfs(G,... | Title: Checkposts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your city has *n* junctions. There are *m* one-way roads between the junctions. As a mayor of the city, you have to ensure the security of all the junctions.
To ensure the security, you have to build some police checkposts.... | ```python
from collections import deque as dq
def topological(G):
n = len(G)
sort = []
visited = [False for _ in range(n)]
def dfs(G, u):
nonlocal sort
nonlocal visited
visited[u] = True
for v in G[u]:
if not visited[v]:
... | -1 | |
0 | none | none | none | 0 | [
"none"
] | null | null | For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*.
For example, 4-rounding of 375 is 375·80<==<=30000. 30000 is the minimum integer such that it ends with 4 or more zeros and is divisible by 375.
W... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=8). | Print the *k*-rounding of *n*. | [
"375 4\n",
"10000 1\n",
"38101 0\n",
"123456789 8\n"
] | [
"30000\n",
"10000\n",
"38101\n",
"12345678900000000\n"
] | none | 0 | [
{
"input": "375 4",
"output": "30000"
},
{
"input": "10000 1",
"output": "10000"
},
{
"input": "38101 0",
"output": "38101"
},
{
"input": "123456789 8",
"output": "12345678900000000"
},
{
"input": "1 0",
"output": "1"
},
{
"input": "2 0",
"output":... | 1,505,655,206 | 1,706 | Python 3 | WRONG_ANSWER | PRETESTS | 8 | 46 | 0 | def kek(n):
res=0
m=n
while m%10==0:
m/=10
res+=1
return res
[n,k]=[int(x) for x in input().split()]
a=kek(n)
if a>=k:
print(n)
else:
while kek(n)<k:
if (kek(n*2)>kek(n)):
n*=2
else:
n*=10
print (n) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*.
For example, 4-rounding of 375 is 375·80<==<=30000. 30000... | ```python
def kek(n):
res=0
m=n
while m%10==0:
m/=10
res+=1
return res
[n,k]=[int(x) for x in input().split()]
a=kek(n)
if a>=k:
print(n)
else:
while kek(n)<k:
if (kek(n*2)>kek(n)):
n*=2
else:
n*=10
print (n)
``` | 0 | |
1,004 | A | Sonya and Hotels | PROGRAMMING | 900 | [
"implementation"
] | null | null | Sonya decided that having her own hotel business is the best way of earning money because she can profit and rest wherever she wants.
The country where Sonya lives is an endless line. There is a city in each integer coordinate on this line. She has $n$ hotels, where the $i$-th hotel is located in the city with coordin... | The first line contains two integers $n$ and $d$ ($1\leq n\leq 100$, $1\leq d\leq 10^9$) — the number of Sonya's hotels and the needed minimum distance from a new hotel to all others.
The second line contains $n$ different integers in strictly increasing order $x_1, x_2, \ldots, x_n$ ($-10^9\leq x_i\leq 10^9$) — coord... | Print the number of cities where Sonya can build a new hotel so that the minimum distance from this hotel to all others is equal to $d$. | [
"4 3\n-3 2 9 16\n",
"5 2\n4 8 11 18 19\n"
] | [
"6\n",
"5\n"
] | In the first example, there are $6$ possible cities where Sonya can build a hotel. These cities have coordinates $-6$, $5$, $6$, $12$, $13$, and $19$.
In the second example, there are $5$ possible cities where Sonya can build a hotel. These cities have coordinates $2$, $6$, $13$, $16$, and $21$. | 500 | [
{
"input": "4 3\n-3 2 9 16",
"output": "6"
},
{
"input": "5 2\n4 8 11 18 19",
"output": "5"
},
{
"input": "10 10\n-67 -59 -49 -38 -8 20 41 59 74 83",
"output": "8"
},
{
"input": "10 10\n0 20 48 58 81 95 111 137 147 159",
"output": "9"
},
{
"input": "100 1\n0 1 2 3... | 1,530,809,545 | 1,045 | Python 3 | OK | TESTS | 45 | 124 | 0 | n,k=[int(j) for j in input().split()]
h=[int(j) for j in input().split()]
hp=[j+k for j in h]
hs=[j-k for j in h]
x=[]
# print(h)
# print(hp)
# print(hs)
for i in range(n-1):
if abs(hp[i]-h[i+1])>=k:
x.append(hp[i])
x.append(hp[n-1])
x.append(hs[0])
for i in range(n-1):
if abs(hs[i+1]-h[i]... | Title: Sonya and Hotels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sonya decided that having her own hotel business is the best way of earning money because she can profit and rest wherever she wants.
The country where Sonya lives is an endless line. There is a city in each integer c... | ```python
n,k=[int(j) for j in input().split()]
h=[int(j) for j in input().split()]
hp=[j+k for j in h]
hs=[j-k for j in h]
x=[]
# print(h)
# print(hp)
# print(hs)
for i in range(n-1):
if abs(hp[i]-h[i+1])>=k:
x.append(hp[i])
x.append(hp[n-1])
x.append(hs[0])
for i in range(n-1):
if abs(hs... | 3 | |
370 | A | Rook, Bishop and King | PROGRAMMING | 1,100 | [
"graphs",
"math",
"shortest paths"
] | null | null | Little Petya is learning to play chess. He has already learned how to move a king, a rook and a bishop. Let us remind you the rules of moving chess pieces. A chessboard is 64 square fields organized into an 8<=×<=8 table. A field is represented by a pair of integers (*r*,<=*c*) — the number of the row and the number of... | The input contains four integers *r*1,<=*c*1,<=*r*2,<=*c*2 (1<=≤<=*r*1,<=*c*1,<=*r*2,<=*c*2<=≤<=8) — the coordinates of the starting and the final field. The starting field doesn't coincide with the final one.
You can assume that the chessboard rows are numbered from top to bottom 1 through 8, and the columns are numb... | Print three space-separated integers: the minimum number of moves the rook, the bishop and the king (in this order) is needed to move from field (*r*1,<=*c*1) to field (*r*2,<=*c*2). If a piece cannot make such a move, print a 0 instead of the corresponding number. | [
"4 3 1 6\n",
"5 5 5 6\n"
] | [
"2 1 3\n",
"1 0 1\n"
] | none | 500 | [
{
"input": "4 3 1 6",
"output": "2 1 3"
},
{
"input": "5 5 5 6",
"output": "1 0 1"
},
{
"input": "1 1 8 8",
"output": "2 1 7"
},
{
"input": "1 1 8 1",
"output": "1 0 7"
},
{
"input": "1 1 1 8",
"output": "1 0 7"
},
{
"input": "8 1 1 1",
"output": "... | 1,623,484,783 | 2,147,483,647 | PyPy 3 | OK | TESTS | 42 | 93 | 0 | from sys import stdin
input = stdin.readline
r1, c1, r2, c2 = [int(x) for x in input().split()]
ans = []
if r1 == r2 or c1 == c2:
ans.append(1)
else:
ans.append(2)
if (r1 + c1) % 2 != (r2 + c2) % 2:
ans.append(0)
elif abs(r1 - r2) == abs(c1 - c2):
ans.append(1)
else:
ans.appen... | Title: Rook, Bishop and King
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya is learning to play chess. He has already learned how to move a king, a rook and a bishop. Let us remind you the rules of moving chess pieces. A chessboard is 64 square fields organized into an 8<=×<=... | ```python
from sys import stdin
input = stdin.readline
r1, c1, r2, c2 = [int(x) for x in input().split()]
ans = []
if r1 == r2 or c1 == c2:
ans.append(1)
else:
ans.append(2)
if (r1 + c1) % 2 != (r2 + c2) % 2:
ans.append(0)
elif abs(r1 - r2) == abs(c1 - c2):
ans.append(1)
else:
... | 3 | |
758 | D | Ability To Convert | PROGRAMMING | 2,000 | [
"constructive algorithms",
"dp",
"greedy",
"math",
"strings"
] | null | null | Alexander is learning how to convert numbers from the decimal system to any other, however, he doesn't know English letters, so he writes any number only as a decimal number, it means that instead of the letter *A* he will write the number 10. Thus, by converting the number 475 from decimal to hexadecimal system, he ge... | The first line contains the integer *n* (2<=≤<=*n*<=≤<=109). The second line contains the integer *k* (0<=≤<=*k*<=<<=1060), it is guaranteed that the number *k* contains no more than 60 symbols. All digits in the second line are strictly less than *n*.
Alexander guarantees that the answer exists and does not exceed... | Print the number *x* (0<=≤<=*x*<=≤<=1018) — the answer to the problem. | [
"13\n12\n",
"16\n11311\n",
"20\n999\n",
"17\n2016\n"
] | [
"12",
"475",
"3789",
"594"
] | In the first example 12 could be obtained by converting two numbers to the system with base 13: 12 = 12·13<sup class="upper-index">0</sup> or 15 = 1·13<sup class="upper-index">1</sup> + 2·13<sup class="upper-index">0</sup>. | 1,750 | [
{
"input": "13\n12",
"output": "12"
},
{
"input": "16\n11311",
"output": "475"
},
{
"input": "20\n999",
"output": "3789"
},
{
"input": "17\n2016",
"output": "594"
},
{
"input": "1000\n1001",
"output": "100001"
},
{
"input": "1000\n1000",
"output": ... | 1,657,189,166 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 102 | 109 | 512,000 | n=int(input())
s=input()
s=s[::-1]
pow=[1]
for _ in range(len(s)):
pow.append(pow[-1]*n)
d=[[0,0],[int(s[0]),1]]
for i in range(1,len(s)):
temp=float("inf")
temp=min(temp,int(s[i])*pow[d[-1][1]]+d[-1][0])
dig=d[-1][1]+1
p=0
j=i
while j>=0 and s[i]!="0":
p=p*10+int(s[j... | Title: Ability To Convert
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alexander is learning how to convert numbers from the decimal system to any other, however, he doesn't know English letters, so he writes any number only as a decimal number, it means that instead of the letter *A* h... | ```python
n=int(input())
s=input()
s=s[::-1]
pow=[1]
for _ in range(len(s)):
pow.append(pow[-1]*n)
d=[[0,0],[int(s[0]),1]]
for i in range(1,len(s)):
temp=float("inf")
temp=min(temp,int(s[i])*pow[d[-1][1]]+d[-1][0])
dig=d[-1][1]+1
p=0
j=i
while j>=0 and s[i]!="0":
p=p*... | 3 | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,587,386,284 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 109 | 0 | arr1 = input()
arr2 = input()
result = ['0' if arr1[i] == arr2[i] else '1' for i in range(len(arr1))]
print(''.join(result))
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
arr1 = input()
arr2 = input()
result = ['0' if arr1[i] == arr2[i] else '1' for i in range(len(arr1))]
print(''.join(result))
``` | 3.97275 |
313 | A | Ilya and Bank Account | PROGRAMMING | 900 | [
"implementation",
"number theory"
] | null | null | Ilya is a very clever lion, he lives in an unusual city ZooVille. In this city all the animals have their rights and obligations. Moreover, they even have their own bank accounts. The state of a bank account is an integer. The state of a bank account can be a negative number. This means that the owner of the account ow... | The single line contains integer *n* (10<=≤<=|*n*|<=≤<=109) — the state of Ilya's bank account. | In a single line print an integer — the maximum state of the bank account that Ilya can get. | [
"2230\n",
"-10\n",
"-100003\n"
] | [
"2230\n",
"0\n",
"-10000\n"
] | In the first test sample Ilya doesn't profit from using the present.
In the second test sample you can delete digit 1 and get the state of the account equal to 0. | 500 | [
{
"input": "2230",
"output": "2230"
},
{
"input": "-10",
"output": "0"
},
{
"input": "-100003",
"output": "-10000"
},
{
"input": "544883178",
"output": "544883178"
},
{
"input": "-847251738",
"output": "-84725173"
},
{
"input": "423654797",
"output... | 1,699,025,544 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 154 | 0 | n=int(input())
r=str(abs(n))
a=(abs(n)%10)
b=(abs(n)%100)
x=0
if n>=0:
print(n)
else:
if len(r)!=2:
if a>=b:
print(r[0:len(r)-1])
else:
print(r[0:len(r)-2]+r[-1])
else:
print(min(r[0],r[1]))
| Title: Ilya and Bank Account
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya is a very clever lion, he lives in an unusual city ZooVille. In this city all the animals have their rights and obligations. Moreover, they even have their own bank accounts. The state of a bank account is an... | ```python
n=int(input())
r=str(abs(n))
a=(abs(n)%10)
b=(abs(n)%100)
x=0
if n>=0:
print(n)
else:
if len(r)!=2:
if a>=b:
print(r[0:len(r)-1])
else:
print(r[0:len(r)-2]+r[-1])
else:
print(min(r[0],r[1]))
``` | 0 | |
879 | B | Table Tennis | PROGRAMMING | 1,200 | [
"data structures",
"implementation"
] | null | null | *n* people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so on. They play until someone wins *k* games in a row. This player becomes the winner.
For each of t... | The first line contains two integers: *n* and *k* (2<=≤<=*n*<=≤<=500, 2<=≤<=*k*<=≤<=1012) — the number of people and the number of wins.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — powers of the player. It's guaranteed that this line contains a valid permutation, i.e. all ... | Output a single integer — power of the winner. | [
"2 2\n1 2\n",
"4 2\n3 1 2 4\n",
"6 2\n6 5 3 1 2 4\n",
"2 10000000000\n2 1\n"
] | [
"2 ",
"3 ",
"6 ",
"2\n"
] | Games in the second sample:
3 plays with 1. 3 wins. 1 goes to the end of the line.
3 plays with 2. 3 wins. He wins twice in a row. He becomes the winner. | 1,000 | [
{
"input": "2 2\n1 2",
"output": "2 "
},
{
"input": "4 2\n3 1 2 4",
"output": "3 "
},
{
"input": "6 2\n6 5 3 1 2 4",
"output": "6 "
},
{
"input": "2 10000000000\n2 1",
"output": "2"
},
{
"input": "4 4\n1 3 4 2",
"output": "4 "
},
{
"input": "2 21474836... | 1,532,294,540 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 109 | 0 | def main():
n, k = map(int, input().split())
m, *bb = map(int, input().split())
if k < n:
c = 0
for i in range(3):
aa, bb = bb, []
for a in aa:
if m < a:
bb.append(m)
m, c = a, 1
else:
... | Title: Table Tennis
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so o... | ```python
def main():
n, k = map(int, input().split())
m, *bb = map(int, input().split())
if k < n:
c = 0
for i in range(3):
aa, bb = bb, []
for a in aa:
if m < a:
bb.append(m)
m, c = a, 1
else:
... | 3 | |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,638,532,706 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 61 | 0 | s = input()
start = 'a'
ans = 0
for i in range(len(s)):
ch = s[i]
r1 = ord(start) - ord(ch)
if r1 > -1:
r2 = abs(r1 - 26)
else:
r2 = abs(r1 + 26)
ans = ans + min(abs(r1), abs(r2))
start = ch
print(ans)
| Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
s = input()
start = 'a'
ans = 0
for i in range(len(s)):
ch = s[i]
r1 = ord(start) - ord(ch)
if r1 > -1:
r2 = abs(r1 - 26)
else:
r2 = abs(r1 + 26)
ans = ans + min(abs(r1), abs(r2))
start = ch
print(ans)
``` | 3 | |
452 | C | Magic Trick | PROGRAMMING | 2,100 | [
"combinatorics",
"math",
"probabilities"
] | null | null | Alex enjoys performing magic tricks. He has a trick that requires a deck of *n* cards. He has *m* identical decks of *n* different cards each, which have been mixed together. When Alex wishes to perform the trick, he grabs *n* cards at random and performs the trick with those. The resulting deck looks like a normal dec... | First line of the input consists of two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000), separated by space — number of cards in each deck, and number of decks. | On the only line of the output print one floating point number – probability of Alex successfully performing the trick. Relative or absolute error of your answer should not be higher than 10<=-<=6. | [
"2 2\n",
"4 4\n",
"1 2\n"
] | [
"0.6666666666666666\n",
"0.4000000000000000\n",
"1.0000000000000000\n"
] | In the first sample, with probability <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/64c94d13eeb330b494061e86538db66574ad0f7d.png" style="max-width: 100.0%;max-height: 100.0%;"/> Alex will perform the trick with two cards with the same value from two different decks. In this case the trick... | 1,000 | [
{
"input": "2 2",
"output": "0.6666666666666666"
},
{
"input": "4 4",
"output": "0.4000000000000000"
},
{
"input": "1 2",
"output": "1.0000000000000000"
},
{
"input": "2 1",
"output": "0.5000000000000000"
},
{
"input": "10 10",
"output": "0.1818181818181818"
... | 1,406,492,258 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | n, m=(int(x) for x in input().split(' '))
if n!=1 and m!=1:
print (1/n+(n-1)/n*(m-1)/(m*n-1))
else:
print(1)
| Title: Magic Trick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex enjoys performing magic tricks. He has a trick that requires a deck of *n* cards. He has *m* identical decks of *n* different cards each, which have been mixed together. When Alex wishes to perform the trick, he grabs ... | ```python
n, m=(int(x) for x in input().split(' '))
if n!=1 and m!=1:
print (1/n+(n-1)/n*(m-1)/(m*n-1))
else:
print(1)
``` | 0 | |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. E... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match di... | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,566,985,184 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 280 | 102,400 | n = int(input())
a=1
x = input()
b=x
for _ in range(1,n):
v = input()
if x==v:
a+=1
else:
b=v
i = print(x) if a>n//2 else print(b)
| Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process... | ```python
n = int(input())
a=1
x = input()
b=x
for _ in range(1,n):
v = input()
if x==v:
a+=1
else:
b=v
i = print(x) if a>n//2 else print(b)
``` | 3.929809 |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,695,074,776 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | s=input()
ss=input()
if s==ss[::-1]:
print('YES')
else:
print('NO')
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
s=input()
ss=input()
if s==ss[::-1]:
print('YES')
else:
print('NO')
``` | 3.977 |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,556,318,146 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 248 | 0 | n = int(input())
a = [int(x) for x in input().split()]
odd = bool(a[0] % 2 == 0 and a[1] % 2 == 0
or a[1] % 2 == 0 and a[2] % 2 == 0
or a[0] % 2 == 0 and a[2] % 2 == 0)
for i in range(len(a)):
if odd and a[i] % 2 == 1 or not odd and a[i] % 2 == 0:
break
print(i + 1) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n = int(input())
a = [int(x) for x in input().split()]
odd = bool(a[0] % 2 == 0 and a[1] % 2 == 0
or a[1] % 2 == 0 and a[2] % 2 == 0
or a[0] % 2 == 0 and a[2] % 2 == 0)
for i in range(len(a)):
if odd and a[i] % 2 == 1 or not odd and a[i] % 2 == 0:
break
print(i + 1)
``` | 3.938 |
854 | B | Maxim Buys an Apartment | PROGRAMMING | 1,200 | [
"constructive algorithms",
"math"
] | null | null | Maxim wants to buy an apartment in a new house at Line Avenue of Metropolis. The house has *n* apartments that are numbered from 1 to *n* and are arranged in a row. Two apartments are adjacent if their indices differ by 1. Some of the apartments can already be inhabited, others are available for sale.
Maxim often visi... | The only line of the input contains two integers: *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=*n*). | Print the minimum possible and the maximum possible number of apartments good for Maxim. | [
"6 3\n"
] | [
"1 3\n"
] | In the sample test, the number of good apartments could be minimum possible if, for example, apartments with indices 1, 2 and 3 were inhabited. In this case only apartment 4 is good. The maximum possible number could be, for example, if apartments with indices 1, 3 and 5 were inhabited. In this case all other apartment... | 1,000 | [
{
"input": "6 3",
"output": "1 3"
},
{
"input": "10 1",
"output": "1 2"
},
{
"input": "10 9",
"output": "1 1"
},
{
"input": "8 0",
"output": "0 0"
},
{
"input": "8 8",
"output": "0 0"
},
{
"input": "966871928 890926970",
"output": "1 75944958"
},... | 1,619,420,496 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 77 | 307,200 | n,k = map(int,input().split())
mn = 1
if k==0 or k==n:
print(0,0)
exit()
cn,cy = divmod(n,3)
mx = 0
if cy==0:
if k<=cn:
mx = 2*k
else:
mx = 2*cn-(k-cn)
elif cy==1:
if k<=cn:
mx = 2*k
else:
k-=1
mx = 2*cn-(k-cn)
else:
if k<=cn:
... | Title: Maxim Buys an Apartment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Maxim wants to buy an apartment in a new house at Line Avenue of Metropolis. The house has *n* apartments that are numbered from 1 to *n* and are arranged in a row. Two apartments are adjacent if their indices d... | ```python
n,k = map(int,input().split())
mn = 1
if k==0 or k==n:
print(0,0)
exit()
cn,cy = divmod(n,3)
mx = 0
if cy==0:
if k<=cn:
mx = 2*k
else:
mx = 2*cn-(k-cn)
elif cy==1:
if k<=cn:
mx = 2*k
else:
k-=1
mx = 2*cn-(k-cn)
else:
if k<=... | 3 | |
189 | A | Cut Ribbon | PROGRAMMING | 1,300 | [
"brute force",
"dp"
] | null | null | Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the number of ribbon pieces should be maximum.
Help Polycarpus and find the number of ribbon piece... | The first line contains four space-separated integers *n*, *a*, *b* and *c* (1<=≤<=*n*,<=*a*,<=*b*,<=*c*<=≤<=4000) — the length of the original ribbon and the acceptable lengths of the ribbon pieces after the cutting, correspondingly. The numbers *a*, *b* and *c* can coincide. | Print a single number — the maximum possible number of ribbon pieces. It is guaranteed that at least one correct ribbon cutting exists. | [
"5 5 3 2\n",
"7 5 5 2\n"
] | [
"2\n",
"2\n"
] | In the first example Polycarpus can cut the ribbon in such way: the first piece has length 2, the second piece has length 3.
In the second example Polycarpus can cut the ribbon in such way: the first piece has length 5, the second piece has length 2. | 500 | [
{
"input": "5 5 3 2",
"output": "2"
},
{
"input": "7 5 5 2",
"output": "2"
},
{
"input": "4 4 4 4",
"output": "1"
},
{
"input": "1 1 1 1",
"output": "1"
},
{
"input": "4000 1 2 3",
"output": "4000"
},
{
"input": "4000 3 4 5",
"output": "1333"
},
... | 1,675,490,319 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 4,505,600 | n, a, b, c = map(int, input().split())
x, y, z = sorted(a, b, c, reverse = True)
for nx in range(n // x + 1):
rem = n - nx * x
for ny in range(rem // y + 1):
nz = (rem - ny * y) / z
if nz % 1 == 0:
print(nx + ny + nz)
break | Title: Cut Ribbon
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the... | ```python
n, a, b, c = map(int, input().split())
x, y, z = sorted(a, b, c, reverse = True)
for nx in range(n // x + 1):
rem = n - nx * x
for ny in range(rem // y + 1):
nz = (rem - ny * y) / z
if nz % 1 == 0:
print(nx + ny + nz)
break
``` | -1 | |
493 | C | Vasya and Basketball | PROGRAMMING | 1,600 | [
"binary search",
"brute force",
"data structures",
"implementation",
"sortings",
"two pointers"
] | null | null | Vasya follows a basketball game and marks the distances from which each team makes a throw. He knows that each successful throw has value of either 2 or 3 points. A throw is worth 2 points if the distance it was made from doesn't exceed some value of *d* meters, and a throw is worth 3 points if the distance is larger t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of throws of the first team. Then follow *n* integer numbers — the distances of throws *a**i* (1<=≤<=*a**i*<=≤<=2·109).
Then follows number *m* (1<=≤<=*m*<=≤<=2·105) — the number of the throws of the second team. Then follow *m* integer numbers — ... | Print two numbers in the format a:b — the score that is possible considering the problem conditions where the result of subtraction *a*<=-<=*b* is maximum. If there are several such scores, find the one in which number *a* is maximum. | [
"3\n1 2 3\n2\n5 6\n",
"5\n6 7 8 9 10\n5\n1 2 3 4 5\n"
] | [
"9:6\n",
"15:10\n"
] | none | 2,000 | [
{
"input": "3\n1 2 3\n2\n5 6",
"output": "9:6"
},
{
"input": "5\n6 7 8 9 10\n5\n1 2 3 4 5",
"output": "15:10"
},
{
"input": "5\n1 2 3 4 5\n5\n6 7 8 9 10",
"output": "15:15"
},
{
"input": "3\n1 2 3\n3\n6 4 5",
"output": "9:9"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10... | 1,417,755,389 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 11 | 202 | 6,553,600 | n1=int(input())
t1=list(map(lambda x:int(x),input().split(' ')))
n2=int(input())
t2=list(map(lambda x:int(x),input().split(' ')))
max_t=max(max(t1),max(t2))
sum1=[0 for i in range(0,max_t)]
sum2=[0 for i in range(0,max_t)]
for t in t1:
sum1[t-1]+=1
for t in t2:
sum2[t-1]+=1
for i in range(max_t-1,0,-1):
... | Title: Vasya and Basketball
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya follows a basketball game and marks the distances from which each team makes a throw. He knows that each successful throw has value of either 2 or 3 points. A throw is worth 2 points if the distance it was ma... | ```python
n1=int(input())
t1=list(map(lambda x:int(x),input().split(' ')))
n2=int(input())
t2=list(map(lambda x:int(x),input().split(' ')))
max_t=max(max(t1),max(t2))
sum1=[0 for i in range(0,max_t)]
sum2=[0 for i in range(0,max_t)]
for t in t1:
sum1[t-1]+=1
for t in t2:
sum2[t-1]+=1
for i in range(max_t-1,... | 0 | |
708 | A | Letters Cyclic Shift | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"implementation",
"strings"
] | null | null | You are given a non-empty string *s* consisting of lowercase English letters. You have to pick exactly one non-empty substring of *s* and shift all its letters 'z' 'y' 'x' 'b' 'a' 'z'. In other words, each character is replaced with the previous character of English alphabet and 'a' is replaced with 'z'.
What is ... | The only line of the input contains the string *s* (1<=≤<=|*s*|<=≤<=100<=000) consisting of lowercase English letters. | Print the lexicographically minimum string that can be obtained from *s* by shifting letters of exactly one non-empty substring. | [
"codeforces\n",
"abacaba\n"
] | [
"bncdenqbdr\n",
"aaacaba\n"
] | String *s* is lexicographically smaller than some other string *t* of the same length if there exists some 1 ≤ *i* ≤ |*s*|, such that *s*<sub class="lower-index">1</sub> = *t*<sub class="lower-index">1</sub>, *s*<sub class="lower-index">2</sub> = *t*<sub class="lower-index">2</sub>, ..., *s*<sub class="lower-index">*i*... | 500 | [
{
"input": "codeforces",
"output": "bncdenqbdr"
},
{
"input": "abacaba",
"output": "aaacaba"
},
{
"input": "babbbabaababbaa",
"output": "aabbbabaababbaa"
},
{
"input": "bcbacaabcababaccccaaaabacbbcbbaa",
"output": "abaacaabcababaccccaaaabacbbcbbaa"
},
{
"input": "... | 1,538,473,847 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<bits/stdc++.h>
#define LL long long
#define fi first
#define se second
#define mk make_pair
#define PII pair<int, int>
#define PLI pair<LL, int>
#define ull unsigned long long
using namespace std;
const int N = 1e5 + 7;
const int inf = 0x3f3f3f3f;
const LL INF = 0x3f3f3f3f3f3f3f3f;
const int mod ... | Title: Letters Cyclic Shift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a non-empty string *s* consisting of lowercase English letters. You have to pick exactly one non-empty substring of *s* and shift all its letters 'z' 'y' 'x' 'b' 'a' 'z'. In other words, each cha... | ```python
#include<bits/stdc++.h>
#define LL long long
#define fi first
#define se second
#define mk make_pair
#define PII pair<int, int>
#define PLI pair<LL, int>
#define ull unsigned long long
using namespace std;
const int N = 1e5 + 7;
const int inf = 0x3f3f3f3f;
const LL INF = 0x3f3f3f3f3f3f3f3f;
cons... | -1 | |
205 | A | Little Elephant and Rozdil | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elephant doesn't like to spend much time on travelling, so for his journey he will choose a town that needs minimum ti... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of cities. The next line contains *n* integers, separated by single spaces: the *i*-th integer represents the time needed to go from town Rozdil to the *i*-th town. The time values are positive integers, not exceeding 109.
You can consider t... | Print the answer on a single line — the number of the town the Little Elephant will go to. If there are multiple cities with minimum travel time, print "Still Rozdil" (without the quotes). | [
"2\n7 4\n",
"7\n7 4 47 100 4 9 12\n"
] | [
"2\n",
"Still Rozdil\n"
] | In the first sample there are only two cities where the Little Elephant can go. The travel time for the first town equals 7, to the second one — 4. The town which is closest to Rodzil (the only one) is the second one, so the answer is 2.
In the second sample the closest cities are cities two and five, the travelling t... | 500 | [
{
"input": "2\n7 4",
"output": "2"
},
{
"input": "7\n7 4 47 100 4 9 12",
"output": "Still Rozdil"
},
{
"input": "1\n47",
"output": "1"
},
{
"input": "2\n1000000000 1000000000",
"output": "Still Rozdil"
},
{
"input": "7\n7 6 5 4 3 2 1",
"output": "7"
},
{
... | 1,673,675,903 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | n = int(input())
nums = [int(x) for x in input().split()]
min_ = min(nums)
min_count = 0
for index in range(n):
if nums[index] == min_:
min_count +=1
if min_count == 1:
print(min_count)
else:
print('Still Rozdil') | Title: Little Elephant and Rozdil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elepha... | ```python
n = int(input())
nums = [int(x) for x in input().split()]
min_ = min(nums)
min_count = 0
for index in range(n):
if nums[index] == min_:
min_count +=1
if min_count == 1:
print(min_count)
else:
print('Still Rozdil')
``` | 0 | |
146 | A | Lucky Ticket | PROGRAMMING | 800 | [
"implementation"
] | null | null | Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya loves tickets very much. As we know, each ticket has a number that is a positive integer. It... | The first line contains an even integer *n* (2<=≤<=*n*<=≤<=50) — the length of the ticket number that needs to be checked. The second line contains an integer whose length equals exactly *n* — the ticket number. The number may contain leading zeros. | On the first line print "YES" if the given ticket number is lucky. Otherwise, print "NO" (without the quotes). | [
"2\n47\n",
"4\n4738\n",
"4\n4774\n"
] | [
"NO\n",
"NO\n",
"YES\n"
] | In the first sample the sum of digits in the first half does not equal the sum of digits in the second half (4 ≠ 7).
In the second sample the ticket number is not the lucky number. | 500 | [
{
"input": "2\n47",
"output": "NO"
},
{
"input": "4\n4738",
"output": "NO"
},
{
"input": "4\n4774",
"output": "YES"
},
{
"input": "4\n4570",
"output": "NO"
},
{
"input": "6\n477477",
"output": "YES"
},
{
"input": "6\n777777",
"output": "YES"
},
... | 1,651,120,617 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | N = int(input())
S = input()
if len(S.replace("4", "").replace("7", "")) != 0:
print("NO")
quit()
if sum(int(x) for x in S[:len(S) // 2]) != sum(int(x) for x in S[len(S) // 2]):
print("NO")
quit()
print("YES")
| Title: Lucky Ticket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
N = int(input())
S = input()
if len(S.replace("4", "").replace("7", "")) != 0:
print("NO")
quit()
if sum(int(x) for x in S[:len(S) // 2]) != sum(int(x) for x in S[len(S) // 2]):
print("NO")
quit()
print("YES")
``` | 0 | |
906 | A | Shockers | PROGRAMMING | 1,600 | [
"implementation",
"strings"
] | null | null | Valentin participates in a show called "Shockers". The rules are quite easy: jury selects one letter which Valentin doesn't know. He should make a small speech, but every time he pronounces a word that contains the selected letter, he receives an electric shock. He can make guesses which letter is selected, but for eac... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of actions Valentin did.
The next *n* lines contain descriptions of his actions, each line contains description of one action. Each action can be of one of three types:
1. Valentin pronounced some word and didn't get an electric shock. Th... | Output a single integer — the number of electric shocks that Valentin could have avoided if he had told the selected letter just after it became uniquely determined. | [
"5\n! abc\n. ad\n. b\n! cd\n? c\n",
"8\n! hello\n! codeforces\n? c\n. o\n? d\n? h\n. l\n? e\n",
"7\n! ababahalamaha\n? a\n? b\n? a\n? b\n? a\n? h\n"
] | [
"1\n",
"2\n",
"0\n"
] | In the first test case after the first action it becomes clear that the selected letter is one of the following: *a*, *b*, *c*. After the second action we can note that the selected letter is not *a*. Valentin tells word "b" and doesn't get a shock. After that it is clear that the selected letter is *c*, but Valentin p... | 500 | [
{
"input": "5\n! abc\n. ad\n. b\n! cd\n? c",
"output": "1"
},
{
"input": "8\n! hello\n! codeforces\n? c\n. o\n? d\n? h\n. l\n? e",
"output": "2"
},
{
"input": "7\n! ababahalamaha\n? a\n? b\n? a\n? b\n? a\n? h",
"output": "0"
},
{
"input": "4\n! abcd\n! cdef\n? d\n? c",
"o... | 1,514,295,668 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 92 | 6,758,400 | import string
N = int(input())
guess = set(string.ascii_lowercase)
k = 0
solved = 0
for i in range(0,N):
imp = input()
tmp = imp.split(" ")
c = tmp[0]
st = set(tmp[1])
if solved:
if c == "!":
k += 1
if c == "?" and st != guess:
k += 1
if c =... | Title: Shockers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valentin participates in a show called "Shockers". The rules are quite easy: jury selects one letter which Valentin doesn't know. He should make a small speech, but every time he pronounces a word that contains the selected le... | ```python
import string
N = int(input())
guess = set(string.ascii_lowercase)
k = 0
solved = 0
for i in range(0,N):
imp = input()
tmp = imp.split(" ")
c = tmp[0]
st = set(tmp[1])
if solved:
if c == "!":
k += 1
if c == "?" and st != guess:
k += 1
... | 0 | |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,690,136,546 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n = int(input())
a = n%3
m = (n-a)/3
if a==0:
print(m*2)
else:
print(m*2+1) | Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
n = int(input())
a = n%3
m = (n-a)/3
if a==0:
print(m*2)
else:
print(m*2+1)
``` | 0 | |
892 | B | Wrath | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"two pointers"
] | null | null | Hands that shed innocent blood!
There are *n* guilty people in a line, the *i*-th of them holds a claw with length *L**i*. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the *i*-th person kills the *j*-th person if and only if *j*<=<<=*i* and *... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=106) — the number of guilty people.
Second line contains *n* space-separated integers *L*1,<=*L*2,<=...,<=*L**n* (0<=≤<=*L**i*<=≤<=109), where *L**i* is the length of the *i*-th person's claw. | Print one integer — the total number of alive people after the bell rings. | [
"4\n0 1 0 10\n",
"2\n0 0\n",
"10\n1 1 3 0 0 0 2 1 0 3\n"
] | [
"1\n",
"2\n",
"3\n"
] | In first sample the last person kills everyone in front of him. | 1,000 | [
{
"input": "4\n0 1 0 10",
"output": "1"
},
{
"input": "2\n0 0",
"output": "2"
},
{
"input": "10\n1 1 3 0 0 0 2 1 0 3",
"output": "3"
},
{
"input": "10\n0 0 2 0 0 3 3 2 2 0",
"output": "2"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "5\n0 0 0 1 0"... | 1,627,252,607 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 6,758,400 | n = int(input())
ls = [int(x) for x in input().split()]
mx = 1e9+5
s = 0
for h in range(n,-1,-1):
if ls[h] >= mx:
s += 1
mx = min(mx, h - ls[h])
print(n-s) | Title: Wrath
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hands that shed innocent blood!
There are *n* guilty people in a line, the *i*-th of them holds a claw with length *L**i*. The bell rings and every person kills some of people in front of him. All people kill others at the same ... | ```python
n = int(input())
ls = [int(x) for x in input().split()]
mx = 1e9+5
s = 0
for h in range(n,-1,-1):
if ls[h] >= mx:
s += 1
mx = min(mx, h - ls[h])
print(n-s)
``` | -1 | |
975 | A | Aramic script | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | In Aramic language words can only represent objects.
Words in Aramic have special properties:
- A word is a root if it does not contain the same letter more than once. - A root and all its permutations represent the same object. - The root $x$ of a word $y$ is the word that contains all letters that appear in $y$... | The first line contains one integer $n$ ($1 \leq n \leq 10^3$) — the number of words in the script.
The second line contains $n$ words $s_1, s_2, \ldots, s_n$ — the script itself. The length of each string does not exceed $10^3$.
It is guaranteed that all characters of the strings are small latin letters. | Output one integer — the number of different objects mentioned in the given ancient Aramic script. | [
"5\na aa aaa ab abb\n",
"3\namer arem mrea\n"
] | [
"2",
"1"
] | In the first test, there are two objects mentioned. The roots that represent them are "a","ab".
In the second test, there is only one object, its root is "amer", the other strings are just permutations of "amer". | 500 | [
{
"input": "5\na aa aaa ab abb",
"output": "2"
},
{
"input": "3\namer arem mrea",
"output": "1"
},
{
"input": "10\nbda bbb cda dca dda dcb bcd dcb ada ddd",
"output": "6"
},
{
"input": "2\nfhjlqs aceginpr",
"output": "2"
},
{
"input": "2\nbcdfghimn efghijlmo",
... | 1,564,131,027 | 747 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | n=int(input())
s=input().split()
for i in range(n):
s[i]=str(set(s[i]))
print(len(set(s)))
| Title: Aramic script
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Aramic language words can only represent objects.
Words in Aramic have special properties:
- A word is a root if it does not contain the same letter more than once. - A root and all its permutations represent the ... | ```python
n=int(input())
s=input().split()
for i in range(n):
s[i]=str(set(s[i]))
print(len(set(s)))
``` | 0 | |
898 | A | Rounding | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5 Vasya can round it to 0 or to 10. Both ways are correct.
For given *n* find out to which int... | The first line contains single integer *n* (0<=≤<=*n*<=≤<=109) — number that Vasya has. | Print result of rounding *n*. Pay attention that in some cases answer isn't unique. In that case print any correct answer. | [
"5\n",
"113\n",
"1000000000\n",
"5432359\n"
] | [
"0\n",
"110\n",
"1000000000\n",
"5432360\n"
] | In the first example *n* = 5. Nearest integers, that ends up with zero are 0 and 10. Any of these answers is correct, so you can print 0 or 10. | 500 | [
{
"input": "5",
"output": "0"
},
{
"input": "113",
"output": "110"
},
{
"input": "1000000000",
"output": "1000000000"
},
{
"input": "5432359",
"output": "5432360"
},
{
"input": "999999994",
"output": "999999990"
},
{
"input": "10",
"output": "10"
... | 1,668,242,890 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 64 | 62 | 0 |
n = int(input())
if 0 < n % 10 < 5:
print(n -( n % 10 ))
elif 5 <= n % 10 <= 9:
if n % 10 == 5:
print(n-n%10)
else:
print(n+(10-(n%10)))
else:
print(n) | Title: Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5... | ```python
n = int(input())
if 0 < n % 10 < 5:
print(n -( n % 10 ))
elif 5 <= n % 10 <= 9:
if n % 10 == 5:
print(n-n%10)
else:
print(n+(10-(n%10)))
else:
print(n)
``` | 3 | |
448 | A | Rewards | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bizon the Champion is called the Champion for a reason.
Bizon the Champion has recently got a present — a new glass cupboard with *n* shelves and he decided to put all his presents there. All the presents can be divided into two types: medals and cups. Bizon the Champion has *a*1 first prize cups, *a*2 second prize c... | The first line contains integers *a*1, *a*2 and *a*3 (0<=≤<=*a*1,<=*a*2,<=*a*3<=≤<=100). The second line contains integers *b*1, *b*2 and *b*3 (0<=≤<=*b*1,<=*b*2,<=*b*3<=≤<=100). The third line contains integer *n* (1<=≤<=*n*<=≤<=100).
The numbers in the lines are separated by single spaces. | Print "YES" (without the quotes) if all the rewards can be put on the shelves in the described manner. Otherwise, print "NO" (without the quotes). | [
"1 1 1\n1 1 1\n4\n",
"1 1 3\n2 3 4\n2\n",
"1 0 0\n1 0 0\n1\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "1 1 1\n1 1 1\n4",
"output": "YES"
},
{
"input": "1 1 3\n2 3 4\n2",
"output": "YES"
},
{
"input": "1 0 0\n1 0 0\n1",
"output": "NO"
},
{
"input": "0 0 0\n0 0 0\n1",
"output": "YES"
},
{
"input": "100 100 100\n100 100 100\n100",
"output": "YES"
},
... | 1,662,379,942 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 25 | 62 | 0 | import math
a = sum(list(map(int,input().split())))
b = sum(list(map(int,input().split())))
n = int(input())
aS = (a + 4) // 5
bS= (b + 9) // 10
lagbe = aS+bS
print("YES") if lagbe <=n else print("NO") | Title: Rewards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bizon the Champion is called the Champion for a reason.
Bizon the Champion has recently got a present — a new glass cupboard with *n* shelves and he decided to put all his presents there. All the presents can be divided into ... | ```python
import math
a = sum(list(map(int,input().split())))
b = sum(list(map(int,input().split())))
n = int(input())
aS = (a + 4) // 5
bS= (b + 9) // 10
lagbe = aS+bS
print("YES") if lagbe <=n else print("NO")
``` | 3 | |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make ... | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,696,606,170 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | n = int(input())
if n % 5 == 0:
print(int(n / 5))
elif n % 4 == 0:
print(int(n / 4))
elif n % 3 == 0:
print(int(n / 3))
elif n % 2 == 0:
print(int(n / 2))
else:
print(n)
| Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2... | ```python
n = int(input())
if n % 5 == 0:
print(int(n / 5))
elif n % 4 == 0:
print(int(n / 4))
elif n % 3 == 0:
print(int(n / 3))
elif n % 2 == 0:
print(int(n / 2))
else:
print(n)
``` | 0 | |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The produ... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second... | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,642,781,724 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 124 | 0 | def pas(n):
print(id(n))
negative, positive, equal = [],[],[]
n = int(input())
lst = list(map(int, input().split()))
for num in lst:
if num < 0: negative.append(num)
elif num == 0: equal.append(num)
else: positive.append(num)
if len(positive) == 0:
positive.append(negative[0])
pos... | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. T... | ```python
def pas(n):
print(id(n))
negative, positive, equal = [],[],[]
n = int(input())
lst = list(map(int, input().split()))
for num in lst:
if num < 0: negative.append(num)
elif num == 0: equal.append(num)
else: positive.append(num)
if len(positive) == 0:
positive.append(negative[0]... | 3 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,670,244,871 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | x=input()
count=0
for n in x:
count+=1
if count >= 10:
print(f"{x[0]}{count-2}{x[-1]}")
else:
if count==1:
pass
else:
print(x) | Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
x=input()
count=0
for n in x:
count+=1
if count >= 10:
print(f"{x[0]}{count-2}{x[-1]}")
else:
if count==1:
pass
else:
print(x)
``` | 0 |
285 | B | Find Marble | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the glasses are not.
First Petya puts a marble under the glass in position *s*. Then he performs som... | The first line contains three integers: *n*,<=*s*,<=*t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*s*,<=*t*<=≤<=*n*) — the number of glasses, the ball's initial and final position. The second line contains *n* space-separated integers: *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — the shuffling operation parameters. It is guaran... | If the marble can move from position *s* to position *t*, then print on a single line a non-negative integer — the minimum number of shuffling operations, needed to get the marble to position *t*. If it is impossible, print number -1. | [
"4 2 1\n2 3 4 1\n",
"4 3 3\n4 1 3 2\n",
"4 3 4\n1 2 3 4\n",
"3 1 3\n2 1 3\n"
] | [
"3\n",
"0\n",
"-1\n",
"-1\n"
] | none | 1,000 | [
{
"input": "4 2 1\n2 3 4 1",
"output": "3"
},
{
"input": "4 3 3\n4 1 3 2",
"output": "0"
},
{
"input": "4 3 4\n1 2 3 4",
"output": "-1"
},
{
"input": "3 1 3\n2 1 3",
"output": "-1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "10 6 7\n10 7 8 1... | 1,682,519,997 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 372 | 13,209,600 | def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
def found(s, t, goto):
if s == t:
return 0
if s == goto[s]:
return -1
vis... | Title: Find Marble
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the ... | ```python
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
def found(s, t, goto):
if s == t:
return 0
if s == goto[s]:
return -1
... | 3 | |
460 | B | Little Dima and Equation | PROGRAMMING | 1,500 | [
"brute force",
"implementation",
"math",
"number theory"
] | null | null | Little Dima misbehaved during a math lesson a lot and the nasty teacher Mr. Pickles gave him the following problem as a punishment.
Find all integer solutions *x* (0<=<<=*x*<=<<=109) of the equation:
where *a*, *b*, *c* are some predetermined constant values and function *s*(*x*) determines the sum of all digi... | The first line contains three space-separated integers: *a*,<=*b*,<=*c* (1<=≤<=*a*<=≤<=5; 1<=≤<=*b*<=≤<=10000; <=-<=10000<=≤<=*c*<=≤<=10000). | Print integer *n* — the number of the solutions that you've found. Next print *n* integers in the increasing order — the solutions of the given equation. Print only integer solutions that are larger than zero and strictly less than 109. | [
"3 2 8\n",
"1 2 -18\n",
"2 2 -1\n"
] | [
"3\n10 2008 13726 ",
"0\n",
"4\n1 31 337 967 "
] | none | 1,000 | [
{
"input": "3 2 8",
"output": "3\n10 2008 13726 "
},
{
"input": "1 2 -18",
"output": "0"
},
{
"input": "2 2 -1",
"output": "4\n1 31 337 967 "
},
{
"input": "1 1 0",
"output": "9\n1 2 3 4 5 6 7 8 9 "
},
{
"input": "1 37 963",
"output": "16\n1000 1111 1222 1333 ... | 1,695,408,252 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 46 | 0 | # Wadea #
a,b,c = map(int,input().split())
arr = []
for i in range(1,81):
x = b*(i**a)+c
n = 0
w = x
while w > 0:
n += (w % 10)
w //= 10
if i == n and x < 10**9:
arr.append(x)
print(len(arr))
print(*arr)
| Title: Little Dima and Equation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Dima misbehaved during a math lesson a lot and the nasty teacher Mr. Pickles gave him the following problem as a punishment.
Find all integer solutions *x* (0<=<<=*x*<=<<=109) of the equation:
w... | ```python
# Wadea #
a,b,c = map(int,input().split())
arr = []
for i in range(1,81):
x = b*(i**a)+c
n = 0
w = x
while w > 0:
n += (w % 10)
w //= 10
if i == n and x < 10**9:
arr.append(x)
print(len(arr))
print(*arr)
``` | 3 | |
893 | C | Rumor | PROGRAMMING | 1,300 | [
"dfs and similar",
"graphs",
"greedy"
] | null | null | Vova promised himself that he would never play computer games... But recently Firestorm — a well-known game developing company — published their newest game, World of Farcraft, and it became really popular. Of course, Vova started playing it.
Now he tries to solve a quest. The task is to come to a settlement named Ove... | The first line contains two integer numbers *n* and *m* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105) — the number of characters in Overcity and the number of pairs of friends.
The second line contains *n* integer numbers *c**i* (0<=≤<=*c**i*<=≤<=109) — the amount of gold *i*-th character asks to start spreading the rumor.
... | Print one number — the minimum amount of gold Vova has to spend in order to finish the quest. | [
"5 2\n2 5 3 4 8\n1 4\n4 5\n",
"10 0\n1 2 3 4 5 6 7 8 9 10\n",
"10 5\n1 6 2 7 3 8 4 9 5 10\n1 2\n3 4\n5 6\n7 8\n9 10\n"
] | [
"10\n",
"55\n",
"15\n"
] | In the first example the best decision is to bribe the first character (he will spread the rumor to fourth character, and the fourth one will spread it to fifth). Also Vova has to bribe the second and the third characters, so they know the rumor.
In the second example Vova has to bribe everyone.
In the third example ... | 0 | [
{
"input": "5 2\n2 5 3 4 8\n1 4\n4 5",
"output": "10"
},
{
"input": "10 0\n1 2 3 4 5 6 7 8 9 10",
"output": "55"
},
{
"input": "10 5\n1 6 2 7 3 8 4 9 5 10\n1 2\n3 4\n5 6\n7 8\n9 10",
"output": "15"
},
{
"input": "1 0\n0",
"output": "0"
},
{
"input": "1 0\n10000000... | 1,690,944,914 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 654 | 50,483,200 | from collections import defaultdict
from collections import deque
from typing import Set
graph = defaultdict(list)
n, m = [int(s) for s in input().split(" ")]
costs = [int(s) for s in input().split(" ")]
for _ in range(m):
x, y = [int(s) for s in input().split(" ")]
graph[x - 1].append(y - 1)
graph[y - 1]... | Title: Rumor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vova promised himself that he would never play computer games... But recently Firestorm — a well-known game developing company — published their newest game, World of Farcraft, and it became really popular. Of course, Vova starte... | ```python
from collections import defaultdict
from collections import deque
from typing import Set
graph = defaultdict(list)
n, m = [int(s) for s in input().split(" ")]
costs = [int(s) for s in input().split(" ")]
for _ in range(m):
x, y = [int(s) for s in input().split(" ")]
graph[x - 1].append(y - 1)
gr... | 3 | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,698,666,908 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | ''' n, h , k = input().split()
ai = input().split()
n, h , k = int(n), int(h) , int(k)
counter = 0
remains = []
val = 0
checked = []
rem = False
if 1 <= n <= 100000 and (1 <= k <= h <= 10**9):
for index, i in enumerate(ai):
storage = int(i)
if 1 <= int(i) <= h:
while True... | Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
''' n, h , k = input().split()
ai = input().split()
n, h , k = int(n), int(h) , int(k)
counter = 0
remains = []
val = 0
checked = []
rem = False
if 1 <= n <= 100000 and (1 <= k <= h <= 10**9):
for index, i in enumerate(ai):
storage = int(i)
if 1 <= int(i) <= h:
... | 0 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,593,721,931 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 186 | 0 | s = str(input())
l = list(s)
ans = []
i = 0
while i < len(l):
if l[i] == '.':
ans.append(0)
elif l[i] == '-':
i+=1
if i == len(l):
break
elif l[i] == '.':
ans.append(1)
elif l[i] == '-':
ans.append(2)
i = i + 1
pri... | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
s = str(input())
l = list(s)
ans = []
i = 0
while i < len(l):
if l[i] == '.':
ans.append(0)
elif l[i] == '-':
i+=1
if i == len(l):
break
elif l[i] == '.':
ans.append(1)
elif l[i] == '-':
ans.append(2)
i = ... | 0 |
191 | C | Fools and Roads | PROGRAMMING | 1,900 | [
"data structures",
"dfs and similar",
"trees"
] | null | null | They say that Berland has exactly two problems, fools and roads. Besides, Berland has *n* cities, populated by the fools and connected by the roads. All Berland roads are bidirectional. As there are many fools in Berland, between each pair of cities there is a path (or else the fools would get upset). Also, between eac... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities.
Each of the next *n*<=-<=1 lines contains two space-separated integers *u**i*,<=*v**i* (1<=≤<=*u**i*,<=*v**i*<=≤<=*n*, *u**i*<=≠<=*v**i*), that means that there is a road connecting cities *u**i* and *v**i*.
The next line conta... | Print *n*<=-<=1 integer. The integers should be separated by spaces. The *i*-th number should equal the number of fools who can go on the *i*-th road. The roads are numbered starting from one in the order, in which they occur in the input. | [
"5\n1 2\n1 3\n2 4\n2 5\n2\n1 4\n3 5\n",
"5\n3 4\n4 5\n1 4\n2 4\n3\n2 3\n1 3\n3 5\n"
] | [
"2 1 1 1 \n",
"3 1 1 1 \n"
] | In the first sample the fool number one goes on the first and third road and the fool number 3 goes on the second, first and fourth ones.
In the second sample, the fools number 1, 3 and 5 go on the first road, the fool number 5 will go on the second road, on the third road goes the fool number 3, and on the fourth one... | 1,500 | [
{
"input": "5\n1 2\n1 3\n2 4\n2 5\n2\n1 4\n3 5",
"output": "2 1 1 1 "
},
{
"input": "5\n3 4\n4 5\n1 4\n2 4\n3\n2 3\n1 3\n3 5",
"output": "3 1 1 1 "
}
] | 1,691,656,886 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 136 | 717 | 58,368,000 | from io import BytesIO, IOBase
import sys
import os
# import time
import bisect
# import functools
import math
import random
# import re
from collections import Counter, defaultdict, deque
from copy import deepcopy
from functools import cmp_to_key, lru_cache, reduce
from heapq import heapify, heappop, hea... | Title: Fools and Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
They say that Berland has exactly two problems, fools and roads. Besides, Berland has *n* cities, populated by the fools and connected by the roads. All Berland roads are bidirectional. As there are many fools in Berlan... | ```python
from io import BytesIO, IOBase
import sys
import os
# import time
import bisect
# import functools
import math
import random
# import re
from collections import Counter, defaultdict, deque
from copy import deepcopy
from functools import cmp_to_key, lru_cache, reduce
from heapq import heapify, he... | 3 | |
501 | A | Contest | PROGRAMMING | 900 | [
"implementation"
] | null | null | Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved the problem that costs *b* points. Besides, Misha submitted the problem *c* minutes after the ... | The first line contains four integers *a*, *b*, *c*, *d* (250<=≤<=*a*,<=*b*<=≤<=3500, 0<=≤<=*c*,<=*d*<=≤<=180).
It is guaranteed that numbers *a* and *b* are divisible by 250 (just like on any real Codeforces round). | Output on a single line:
"Misha" (without the quotes), if Misha got more points than Vasya.
"Vasya" (without the quotes), if Vasya got more points than Misha.
"Tie" (without the quotes), if both of them got the same number of points. | [
"500 1000 20 30\n",
"1000 1000 1 1\n",
"1500 1000 176 177\n"
] | [
"Vasya\n",
"Tie\n",
"Misha\n"
] | none | 500 | [
{
"input": "500 1000 20 30",
"output": "Vasya"
},
{
"input": "1000 1000 1 1",
"output": "Tie"
},
{
"input": "1500 1000 176 177",
"output": "Misha"
},
{
"input": "1500 1000 74 177",
"output": "Misha"
},
{
"input": "750 2500 175 178",
"output": "Vasya"
},
{
... | 1,605,521,014 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 109 | 307,200 | a, b, c, d = map(int, input().split())
if max((3*a)/10, a-((a/250)*c)) > max((3*b)/10, b-((b/250)*d)):
print("Misha")
elif max((3*a)/10, a-((a/250)*c)) < max((3*b)/10, b-((b/250)*d)):
print("Vasya")
else:
print("Tie") | Title: Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved t... | ```python
a, b, c, d = map(int, input().split())
if max((3*a)/10, a-((a/250)*c)) > max((3*b)/10, b-((b/250)*d)):
print("Misha")
elif max((3*a)/10, a-((a/250)*c)) < max((3*b)/10, b-((b/250)*d)):
print("Vasya")
else:
print("Tie")
``` | 3 | |
478 | B | Random Teams | PROGRAMMING | 1,300 | [
"combinatorics",
"constructive algorithms",
"greedy",
"math"
] | null | null | *n* participants of the competition were split into *m* teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.
Your task is to write a program that will find the minimum and the maximum number of pairs of friends that coul... | The only line of input contains two integers *n* and *m*, separated by a single space (1<=≤<=*m*<=≤<=*n*<=≤<=109) — the number of participants and the number of teams respectively. | The only line of the output should contain two integers *k**min* and *k**max* — the minimum possible number of pairs of friends and the maximum possible number of pairs of friends respectively. | [
"5 1\n",
"3 2\n",
"6 3\n"
] | [
"10 10\n",
"1 1\n",
"3 6\n"
] | In the first sample all the participants get into one team, so there will be exactly ten pairs of friends.
In the second sample at any possible arrangement one team will always have two participants and the other team will always have one participant. Thus, the number of pairs of friends will always be equal to one.
... | 1,000 | [
{
"input": "5 1",
"output": "10 10"
},
{
"input": "3 2",
"output": "1 1"
},
{
"input": "6 3",
"output": "3 6"
},
{
"input": "5 3",
"output": "2 3"
},
{
"input": "10 2",
"output": "20 36"
},
{
"input": "10 6",
"output": "4 10"
},
{
"input": ... | 1,658,709,695 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 10 | 77 | 0 | import math
import bisect
from collections import deque
def input_list_int():
return list(map(int, input().split()))
def sum_of_rel(num):
return int(((num-1)*(num))/2)
n, m = input_list_int()
n_div_m = n/m
c = int(m*(n_div_m%1))
k_min = sum_of_rel(math.ceil(n_div_m))*c + sum_of_rel(math.floo... | Title: Random Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* participants of the competition were split into *m* teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.
Your task is ... | ```python
import math
import bisect
from collections import deque
def input_list_int():
return list(map(int, input().split()))
def sum_of_rel(num):
return int(((num-1)*(num))/2)
n, m = input_list_int()
n_div_m = n/m
c = int(m*(n_div_m%1))
k_min = sum_of_rel(math.ceil(n_div_m))*c + sum_of_rel... | 0 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,634,398,599 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | m, n = map int(int, input().split())
if m == 1and n == 1:
print(0)
else:
print(1) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
m, n = map int(int, input().split())
if m == 1and n == 1:
print(0)
else:
print(1)
``` | -1 |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,694,839,103 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 46 | 0 | k , x=map(int,input().split())
v=(max(k,x)-min(k,x))//2
if v > 0:
print(min(k,x),v)
else:
print(min(k,x),0) | Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
k , x=map(int,input().split())
v=(max(k,x)-min(k,x))//2
if v > 0:
print(min(k,x),v)
else:
print(min(k,x),0)
``` | 3 | |
443 | A | Anton and Letters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to ti... | The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space. | Print a single number — the number of distinct letters in Anton's set. | [
"{a, b, c}\n",
"{b, a, b, a}\n",
"{}\n"
] | [
"3\n",
"2\n",
"0\n"
] | none | 500 | [
{
"input": "{a, b, c}",
"output": "3"
},
{
"input": "{b, a, b, a}",
"output": "2"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{a, a, c, b, b, b, c, c, c, c}",
"output": "3"
},
{
"input": "{a, c, b, b}",
"output": "3"
},
{
"input": "{a, b}",
"o... | 1,696,393,613 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | x=input()
ans=[]
for i in x:
ans.append(i)
print(len(set(ans))-4) | Title: Anton and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the begi... | ```python
x=input()
ans=[]
for i in x:
ans.append(i)
print(len(set(ans))-4)
``` | 0 | |
18 | A | Triangle | PROGRAMMING | 1,500 | [
"brute force",
"geometry"
] | A. Triangle | 2 | 64 | At a geometry lesson Bob learnt that a triangle is called right-angled if it is nondegenerate and one of its angles is right. Bob decided to draw such a triangle immediately: on a sheet of paper he drew three points with integer coordinates, and joined them with segments of straight lines, then he showed the triangle t... | The first input line contains 6 space-separated integers *x*1,<=*y*1,<=*x*2,<=*y*2,<=*x*3,<=*y*3 — coordinates of the triangle's vertices. All the coordinates are integer and don't exceed 100 in absolute value. It's guaranteed that the triangle is nondegenerate, i.e. its total area is not zero. | If the given triangle is right-angled, output RIGHT, if it is almost right-angled, output ALMOST, and if it is neither of these, output NEITHER. | [
"0 0 2 0 0 1\n",
"2 3 4 5 6 6\n",
"-1 0 2 0 0 1\n"
] | [
"RIGHT\n",
"NEITHER\n",
"ALMOST\n"
] | none | 0 | [
{
"input": "0 0 2 0 0 1",
"output": "RIGHT"
},
{
"input": "2 3 4 5 6 6",
"output": "NEITHER"
},
{
"input": "-1 0 2 0 0 1",
"output": "ALMOST"
},
{
"input": "27 74 85 23 100 99",
"output": "NEITHER"
},
{
"input": "-97 -19 17 62 30 -76",
"output": "NEITHER"
},... | 1,569,529,771 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 30 | 218 | 0 | def check(ponits):
d1 = ((points[0] - points[2]) ** 2) + ((points[1] - points[3]) ** 2)
d2 = ((points[0] - points[4]) ** 2) + ((points[1] - points[5]) ** 2)
d3 = ((points[4] - points[2]) ** 2) + ((points[5] - points[3]) ** 2)
if d1 + d2 == d3 or d1 + d3 == d2 or d2 + d3 == d1:
return True
re... | Title: Triangle
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
At a geometry lesson Bob learnt that a triangle is called right-angled if it is nondegenerate and one of its angles is right. Bob decided to draw such a triangle immediately: on a sheet of paper he drew three points with integer co... | ```python
def check(ponits):
d1 = ((points[0] - points[2]) ** 2) + ((points[1] - points[3]) ** 2)
d2 = ((points[0] - points[4]) ** 2) + ((points[1] - points[5]) ** 2)
d3 = ((points[4] - points[2]) ** 2) + ((points[5] - points[3]) ** 2)
if d1 + d2 == d3 or d1 + d3 == d2 or d2 + d3 == d1:
return T... | 0 |
740 | A | Alyona and copybooks | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | Little girl Alyona is in a shop to buy some copybooks for school. She study four subjects so she wants to have equal number of copybooks for each of the subjects. There are three types of copybook's packs in the shop: it is possible to buy one copybook for *a* rubles, a pack of two copybooks for *b* rubles, and a pack ... | The only line contains 4 integers *n*, *a*, *b*, *c* (1<=≤<=*n*,<=*a*,<=*b*,<=*c*<=≤<=109). | Print the minimum amount of rubles she should pay to buy such number of copybooks *k* that *n*<=+<=*k* is divisible by 4. | [
"1 1 3 4\n",
"6 2 1 1\n",
"4 4 4 4\n",
"999999999 1000000000 1000000000 1000000000\n"
] | [
"3\n",
"1\n",
"0\n",
"1000000000\n"
] | In the first example Alyona can buy 3 packs of 1 copybook for 3*a* = 3 rubles in total. After that she will have 4 copybooks which she can split between the subjects equally.
In the second example Alyuna can buy a pack of 2 copybooks for *b* = 1 ruble. She will have 8 copybooks in total.
In the third example Alyona ... | 500 | [
{
"input": "1 1 3 4",
"output": "3"
},
{
"input": "6 2 1 1",
"output": "1"
},
{
"input": "4 4 4 4",
"output": "0"
},
{
"input": "999999999 1000000000 1000000000 1000000000",
"output": "1000000000"
},
{
"input": "1016 3 2 1",
"output": "0"
},
{
"input":... | 1,479,919,541 | 641 | Python 3 | WRONG_ANSWER | PRETESTS | 11 | 61 | 0 | def compute():
n, a, b, c = map(int,input().split())
if n%4==0:
return 0
if (n+1)%4==0:
return a
if (n+2)%4==0:
return min(a+a,b)
if (n+3)%4==0:
return min(a+a+a,a+b,c)
if __name__=="__main__":
print(compute())
| Title: Alyona and copybooks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Alyona is in a shop to buy some copybooks for school. She study four subjects so she wants to have equal number of copybooks for each of the subjects. There are three types of copybook's packs in the sh... | ```python
def compute():
n, a, b, c = map(int,input().split())
if n%4==0:
return 0
if (n+1)%4==0:
return a
if (n+2)%4==0:
return min(a+a,b)
if (n+3)%4==0:
return min(a+a+a,a+b,c)
if __name__=="__main__":
print(compute())
``` | 0 | |
136 | A | Presents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift.... | Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*. | [
"4\n2 3 4 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"4 1 2 3\n",
"1 3 2\n",
"1 2\n"
] | none | 500 | [
{
"input": "4\n2 3 4 1",
"output": "4 1 2 3"
},
{
"input": "3\n1 3 2",
"output": "1 3 2"
},
{
"input": "2\n1 2",
"output": "1 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 3 2 6 4 5 7 9 8 10",
"output": "1 3 2 5 6 4 7 9 8 10"
},
{
"input"... | 1,687,948,240 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 92 | 0 | T = int(input())
a = input()
a = a.split()
a = [int(x) for x in a]
b = max(a)
c = min(a)
k = 0
v = ''
s = ''
while not(k == len(a)):
v += str(a.index(c)+1)
c += 1
k += 1
s = ' '.join(v)
print(s) | Title: Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on t... | ```python
T = int(input())
a = input()
a = a.split()
a = [int(x) for x in a]
b = max(a)
c = min(a)
k = 0
v = ''
s = ''
while not(k == len(a)):
v += str(a.index(c)+1)
c += 1
k += 1
s = ' '.join(v)
print(s)
``` | 0 | |
315 | A | Sereja and Bottles | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th bottle is from brand *a**i*, besides, you can use it to open other bottles of brand *b**i*. You can use... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles. The next *n* lines contain the bottles' description. The *i*-th line contains two integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the description of the *i*-th bottle. | In a single line print a single integer — the answer to the problem. | [
"4\n1 1\n2 2\n3 3\n4 4\n",
"4\n1 2\n2 3\n3 4\n4 1\n"
] | [
"4\n",
"0\n"
] | none | 500 | [
{
"input": "4\n1 1\n2 2\n3 3\n4 4",
"output": "4"
},
{
"input": "4\n1 2\n2 3\n3 4\n4 1",
"output": "0"
},
{
"input": "3\n2 828\n4 392\n4 903",
"output": "3"
},
{
"input": "4\n2 3\n1 772\n3 870\n3 668",
"output": "2"
},
{
"input": "5\n1 4\n6 6\n4 3\n3 4\n4 758",
... | 1,590,838,637 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 186 | 0 | n=int(input())
count=[False]*(n)
for i in range(n):
a,b=map(int,input().split())
if a!=b:
count[b-1]=True
cnt=0
for i in range(n):
if count[i]==False:
cnt+=1
print(cnt) | Title: Sereja and Bottles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th... | ```python
n=int(input())
count=[False]*(n)
for i in range(n):
a,b=map(int,input().split())
if a!=b:
count[b-1]=True
cnt=0
for i in range(n):
if count[i]==False:
cnt+=1
print(cnt)
``` | -1 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,665,246,799 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 |
n, m = map(int, input().split())
res = n * m
print(int(res/2))
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
n, m = map(int, input().split())
res = n * m
print(int(res/2))
``` | 3.977 |
235 | A | LCM Challenge | PROGRAMMING | 1,600 | [
"number theory"
] | null | null | Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive integers (they don't have to be distinct) which are not greater than *n*. Can you help me to find ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the *n* mentioned in the statement. | Print a single integer — the maximum possible LCM of three not necessarily distinct positive integers that are not greater than *n*. | [
"9\n",
"7\n"
] | [
"504\n",
"210\n"
] | The least common multiple of some positive integers is the least positive integer which is multiple for each of them.
The result may become very large, 32-bit integer won't be enough. So using 64-bit integers is recommended.
For the last example, we can chose numbers 7, 6, 5 and the LCM of them is 7·6·5 = 210. It is ... | 500 | [
{
"input": "9",
"output": "504"
},
{
"input": "7",
"output": "210"
},
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "60"
},
{
"input": "33",
"output": "32736"
},
{
"input": "21",
"output": ... | 1,550,227,270 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 186 | 0 | #code
import math as m
def lcm(a, b):
return (a*b)//(m.gcd(a, b))
n = int(input())
var = m.gcd(n, n - 1)
if(n == 1):
print(1)
elif(n == 2):
print(2)
elif(n == 3):
print(6)
elif(n == 4):
print(12)
print(max(lcm(n, lcm(n - 1, n - 2)),lcm(n - 3, lcm(n - 1, n - 2)))) | Title: LCM Challenge
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive... | ```python
#code
import math as m
def lcm(a, b):
return (a*b)//(m.gcd(a, b))
n = int(input())
var = m.gcd(n, n - 1)
if(n == 1):
print(1)
elif(n == 2):
print(2)
elif(n == 3):
print(6)
elif(n == 4):
print(12)
print(max(lcm(n, lcm(n - 1, n - 2)),lcm(n - 3, lcm(n - 1, n - 2))))
... | 0 | |
437 | C | The Child and Toy | PROGRAMMING | 1,400 | [
"graphs",
"greedy",
"sortings"
] | null | null | On Children's Day, the child got a toy from Delayyy as a present. However, the child is so naughty that he can't wait to destroy the toy.
The toy consists of *n* parts and *m* ropes. Each rope links two parts, but every pair of parts is linked by at most one rope. To split the toy, the child must remove all its parts.... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=1000; 0<=≤<=*m*<=≤<=2000). The second line contains *n* integers: *v*1,<=*v*2,<=...,<=*v**n* (0<=≤<=*v**i*<=≤<=105). Then followed *m* lines, each line contains two integers *x**i* and *y**i*, representing a rope from part *x**i* to part *y**i* (1<=≤<=*x**... | Output the minimum total energy the child should spend to remove all *n* parts of the toy. | [
"4 3\n10 20 30 40\n1 4\n1 2\n2 3\n",
"4 4\n100 100 100 100\n1 2\n2 3\n2 4\n3 4\n",
"7 10\n40 10 20 10 20 80 40\n1 5\n4 7\n4 5\n5 2\n5 7\n6 4\n1 6\n1 3\n4 3\n1 4\n"
] | [
"40\n",
"400\n",
"160\n"
] | One of the optimal sequence of actions in the first sample is:
- First, remove part 3, cost of the action is 20. - Then, remove part 2, cost of the action is 10. - Next, remove part 4, cost of the action is 10. - At last, remove part 1, cost of the action is 0.
So the total energy the child paid is 20 + 10 + 10 +... | 1,500 | [
{
"input": "4 3\n10 20 30 40\n1 4\n1 2\n2 3",
"output": "40"
},
{
"input": "4 4\n100 100 100 100\n1 2\n2 3\n2 4\n3 4",
"output": "400"
},
{
"input": "7 10\n40 10 20 10 20 80 40\n1 5\n4 7\n4 5\n5 2\n5 7\n6 4\n1 6\n1 3\n4 3\n1 4",
"output": "160"
},
{
"input": "1 0\n23333",
... | 1,460,163,484 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 77 | 5,120,000 | edges = [int(x) for x in input().split(' ')][1]
arr = [int(x) for x in input().split(' ')]
energy = 0
for i in range(edges):
t = [int(x) for x in input().split(' ')]
energy += min(arr[t[0]-1], arr[t[1]-1])
print(energy)
| Title: The Child and Toy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On Children's Day, the child got a toy from Delayyy as a present. However, the child is so naughty that he can't wait to destroy the toy.
The toy consists of *n* parts and *m* ropes. Each rope links two parts, but ev... | ```python
edges = [int(x) for x in input().split(' ')][1]
arr = [int(x) for x in input().split(' ')]
energy = 0
for i in range(edges):
t = [int(x) for x in input().split(' ')]
energy += min(arr[t[0]-1], arr[t[1]-1])
print(energy)
``` | 3 | |
149 | A | Business trip | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | null | null | What joy! Petya's parents went on a business trip for the whole year and the playful kid is left all by himself. Petya got absolutely happy. He jumped on the bed and threw pillows all day long, until...
Today Petya opened the cupboard and found a scary note there. His parents had left him with duties: he should water... | The first line contains exactly one integer *k* (0<=≤<=*k*<=≤<=100). The next line contains twelve space-separated integers: the *i*-th (1<=≤<=*i*<=≤<=12) number in the line represents *a**i* (0<=≤<=*a**i*<=≤<=100). | Print the only integer — the minimum number of months when Petya has to water the flower so that the flower grows no less than by *k* centimeters. If the flower can't grow by *k* centimeters in a year, print -1. | [
"5\n1 1 1 1 2 2 3 2 2 1 1 1\n",
"0\n0 0 0 0 0 0 0 1 1 2 3 0\n",
"11\n1 1 4 1 1 5 1 1 4 1 1 1\n"
] | [
"2\n",
"0\n",
"3\n"
] | Let's consider the first sample test. There it is enough to water the flower during the seventh and the ninth month. Then the flower grows by exactly five centimeters.
In the second sample Petya's parents will believe him even if the flower doesn't grow at all (*k* = 0). So, it is possible for Petya not to water the f... | 500 | [
{
"input": "5\n1 1 1 1 2 2 3 2 2 1 1 1",
"output": "2"
},
{
"input": "0\n0 0 0 0 0 0 0 1 1 2 3 0",
"output": "0"
},
{
"input": "11\n1 1 4 1 1 5 1 1 4 1 1 1",
"output": "3"
},
{
"input": "15\n20 1 1 1 1 2 2 1 2 2 1 1",
"output": "1"
},
{
"input": "7\n8 9 100 12 14 ... | 1,647,845,420 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | def fun(l):
i=1
c=1
s=l[0]
if l[0]>=n:
return 0
while s<n:
c+=1
s+=l[i]
i+=1
return c
n=int(input())
l=list(map(int,input().split()))
l.sort(reverse=True)
print(fun(l))
| Title: Business trip
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
What joy! Petya's parents went on a business trip for the whole year and the playful kid is left all by himself. Petya got absolutely happy. He jumped on the bed and threw pillows all day long, until...
Today Petya open... | ```python
def fun(l):
i=1
c=1
s=l[0]
if l[0]>=n:
return 0
while s<n:
c+=1
s+=l[i]
i+=1
return c
n=int(input())
l=list(map(int,input().split()))
l.sort(reverse=True)
print(fun(l))
``` | 0 | |
755 | A | PolandBall and Hypothesis | PROGRAMMING | 800 | [
"brute force",
"graphs",
"math",
"number theory"
] | null | null | PolandBall is a young, clever Ball. He is interested in prime numbers. He has stated a following hypothesis: "There exists such a positive integer *n* that for each positive integer *m* number *n*·*m*<=+<=1 is a prime number".
Unfortunately, PolandBall is not experienced yet and doesn't know that his hypothesis is inc... | The only number in the input is *n* (1<=≤<=*n*<=≤<=1000) — number from the PolandBall's hypothesis. | Output such *m* that *n*·*m*<=+<=1 is not a prime number. Your answer will be considered correct if you output any suitable *m* such that 1<=≤<=*m*<=≤<=103. It is guaranteed the the answer exists. | [
"3\n",
"4\n"
] | [
"1",
"2"
] | A prime number (or a prime) is a natural number greater than 1 that has no positive divisors other than 1 and itself.
For the first sample testcase, 3·1 + 1 = 4. We can output 1.
In the second sample testcase, 4·1 + 1 = 5. We cannot output 1 because 5 is prime. However, *m* = 2 is okay since 4·2 + 1 = 9, which is not... | 500 | [
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "10",
"output": "2"
},
{
"input": "153",
"output": "1"
},
{
"input": "1000",
"output": "1"
},
{
"input": "1",
"output": "3"
},
{
"input": "2",
"output": "4"
... | 1,649,124,056 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 63 | 78 | 0 | import math
def is_prime(num):
for d in range(2,int(math.sqrt(num))+1):
if num%d==0:
return False
return True
def polandball_and_hypothesis():
a=int(input())
for i in range(1,2000):
if is_prime(a*i+1)==False:
print(i)
break
polandball_and_h... | Title: PolandBall and Hypothesis
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
PolandBall is a young, clever Ball. He is interested in prime numbers. He has stated a following hypothesis: "There exists such a positive integer *n* that for each positive integer *m* number *n*·*m*<=+<=1 is... | ```python
import math
def is_prime(num):
for d in range(2,int(math.sqrt(num))+1):
if num%d==0:
return False
return True
def polandball_and_hypothesis():
a=int(input())
for i in range(1,2000):
if is_prime(a*i+1)==False:
print(i)
break
poland... | 3 | |
721 | A | One-dimensional Japanese Crossword | PROGRAMMING | 800 | [
"implementation"
] | null | null | Recently Adaltik discovered japanese crosswords. Japanese crossword is a picture, represented as a table sized *a*<=×<=*b* squares, and each square is colored white or black. There are integers to the left of the rows and to the top of the columns, encrypting the corresponding row or column. The number of integers repr... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the length of the row. The second line of the input contains a single string consisting of *n* characters 'B' or 'W', ('B' corresponds to black square, 'W' — to white square in the row that Adaltik drew). | The first line should contain a single integer *k* — the number of integers encrypting the row, e.g. the number of groups of black squares in the row.
The second line should contain *k* integers, encrypting the row, e.g. corresponding to sizes of groups of consecutive black squares in the order from left to right. | [
"3\nBBW\n",
"5\nBWBWB\n",
"4\nWWWW\n",
"4\nBBBB\n",
"13\nWBBBBWWBWBBBW\n"
] | [
"1\n2 ",
"3\n1 1 1 ",
"0\n",
"1\n4 ",
"3\n4 1 3 "
] | The last sample case correspond to the picture in the statement. | 500 | [
{
"input": "3\nBBW",
"output": "1\n2 "
},
{
"input": "5\nBWBWB",
"output": "3\n1 1 1 "
},
{
"input": "4\nWWWW",
"output": "0"
},
{
"input": "4\nBBBB",
"output": "1\n4 "
},
{
"input": "13\nWBBBBWWBWBBBW",
"output": "3\n4 1 3 "
},
{
"input": "1\nB",
... | 1,698,066,888 | 2,147,483,647 | PyPy 3 | OK | TESTS | 54 | 108 | 0 | #From Jasnah bobb31
#From Jasnah bobb31
#From Jasnah bobb31
n = int(input())
a = input().strip()
c = 0
r = [0] * 50
for i in range(n):
if a[i] == 'W':
continue
if i > 0 and a[i - 1] == 'B':
r[c - 1] += 1
else:
c += 1
r[c - 1] += 1
print(c)
print(*r[:c])
| Title: One-dimensional Japanese Crossword
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Adaltik discovered japanese crosswords. Japanese crossword is a picture, represented as a table sized *a*<=×<=*b* squares, and each square is colored white or black. There are integers to the... | ```python
#From Jasnah bobb31
#From Jasnah bobb31
#From Jasnah bobb31
n = int(input())
a = input().strip()
c = 0
r = [0] * 50
for i in range(n):
if a[i] == 'W':
continue
if i > 0 and a[i - 1] == 'B':
r[c - 1] += 1
else:
c += 1
r[c - 1] += 1
print(c)
print(... | 3 | |
204 | A | Little Elephant and Interval | PROGRAMMING | 1,500 | [
"binary search",
"combinatorics",
"dp"
] | null | null | The Little Elephant very much loves sums on intervals.
This time he has a pair of integers *l* and *r* (*l*<=≤<=*r*). The Little Elephant has to find the number of such integers *x* (*l*<=≤<=*x*<=≤<=*r*), that the first digit of integer *x* equals the last one (in decimal notation). For example, such numbers as 101, 4... | The single line contains a pair of integers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=1018) — the boundaries of the interval.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | On a single line print a single integer — the answer to the problem. | [
"2 47\n",
"47 1024\n"
] | [
"12\n",
"98\n"
] | In the first sample the answer includes integers 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 44. | 500 | [
{
"input": "2 47",
"output": "12"
},
{
"input": "47 1024",
"output": "98"
},
{
"input": "1 1000",
"output": "108"
},
{
"input": "1 10000",
"output": "1008"
},
{
"input": "47 8545",
"output": "849"
},
{
"input": "1000 1000",
"output": "0"
},
{
... | 1,368,060,331 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | rdi = lambda: list(map(int, input().split()))
def f(x): return x if x<10 else x/10+9-(0 if str(x)[0]<=str(x)[-1] else 1)
l, r = rdi()
print(f(r)-f(l-1)) | Title: Little Elephant and Interval
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant very much loves sums on intervals.
This time he has a pair of integers *l* and *r* (*l*<=≤<=*r*). The Little Elephant has to find the number of such integers *x* (*l*<=≤<=*x*<=≤<=*r*), ... | ```python
rdi = lambda: list(map(int, input().split()))
def f(x): return x if x<10 else x/10+9-(0 if str(x)[0]<=str(x)[-1] else 1)
l, r = rdi()
print(f(r)-f(l-1))
``` | 0 | |
115 | A | Party | PROGRAMMING | 900 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | A company has *n* employees numbered from 1 to *n*. Each employee either has no immediate manager or exactly one immediate manager, who is another employee with a different number. An employee *A* is said to be the superior of another employee *B* if at least one of the following is true:
- Employee *A* is the immedi... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of employees.
The next *n* lines contain the integers *p**i* (1<=≤<=*p**i*<=≤<=*n* or *p**i*<==<=-1). Every *p**i* denotes the immediate manager for the *i*-th employee. If *p**i* is -1, that means that the *i*-th employee does not have an immediate... | Print a single integer denoting the minimum number of groups that will be formed in the party. | [
"5\n-1\n1\n2\n1\n-1\n"
] | [
"3\n"
] | For the first example, three groups are sufficient, for example:
- Employee 1 - Employees 2 and 4 - Employees 3 and 5 | 500 | [
{
"input": "5\n-1\n1\n2\n1\n-1",
"output": "3"
},
{
"input": "4\n-1\n1\n2\n3",
"output": "4"
},
{
"input": "12\n-1\n1\n2\n3\n-1\n5\n6\n7\n-1\n9\n10\n11",
"output": "4"
},
{
"input": "6\n-1\n-1\n2\n3\n1\n1",
"output": "3"
},
{
"input": "3\n-1\n1\n1",
"output": ... | 1,685,706,589 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | def dfs(employee, hierarchy, visited):
visited[employee] = True
groups = 0
for i in range(len(hierarchy)):
if hierarchy[i] == employee and not visited[i]:
groups += dfs(i, hierarchy, visited)
return groups + 1
n = int(input())
hierarchy = [int(input()) for _ in range(... | Title: Party
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A company has *n* employees numbered from 1 to *n*. Each employee either has no immediate manager or exactly one immediate manager, who is another employee with a different number. An employee *A* is said to be the superior of an... | ```python
def dfs(employee, hierarchy, visited):
visited[employee] = True
groups = 0
for i in range(len(hierarchy)):
if hierarchy[i] == employee and not visited[i]:
groups += dfs(i, hierarchy, visited)
return groups + 1
n = int(input())
hierarchy = [int(input()) for _... | 0 | |
429 | B | Working out | PROGRAMMING | 1,600 | [
"dp"
] | null | null | Summer is coming! It's time for Iahub and Iahubina to work out, as they both want to look hot at the beach. The gym where they go is a matrix *a* with *n* lines and *m* columns. Let number *a*[*i*][*j*] represents the calories burned by performing workout at the cell of gym in the *i*-th line and the *j*-th column.
Ia... | The first line of the input contains two integers *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=1000). Each of the next *n* lines contains *m* integers: *j*-th number from *i*-th line denotes element *a*[*i*][*j*] (0<=≤<=*a*[*i*][*j*]<=≤<=105). | The output contains a single number — the maximum total gain possible. | [
"3 3\n100 100 100\n100 1 100\n100 100 100\n"
] | [
"800"
] | Iahub will choose exercises *a*[1][1] → *a*[1][2] → *a*[2][2] → *a*[3][2] → *a*[3][3]. Iahubina will choose exercises *a*[3][1] → *a*[2][1] → *a*[2][2] → *a*[2][3] → *a*[1][3]. | 1,000 | [
{
"input": "3 3\n100 100 100\n100 1 100\n100 100 100",
"output": "800"
},
{
"input": "4 5\n87882 40786 3691 85313 46694\n28884 16067 3242 97367 78518\n4250 35501 9780 14435 19004\n64673 65438 56977 64495 27280",
"output": "747898"
},
{
"input": "3 3\n3 1 2\n3 2 0\n2 3 2",
"output": "... | 1,696,802,367 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <stdlib.h>
#include <stdio.h>
#include <limits.h>
int max(int a, int b);
void display_matrix(int **matrix, int n, int m);
int main(){
// Input
int n, m;
scanf("%d %d", &n, &m);
int **grid = (int**) malloc(n*sizeof (int*));
for(int i=0; i<n; i++) {
grid[i] = (int ... | Title: Working out
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Summer is coming! It's time for Iahub and Iahubina to work out, as they both want to look hot at the beach. The gym where they go is a matrix *a* with *n* lines and *m* columns. Let number *a*[*i*][*j*] represents the calor... | ```python
#include <stdlib.h>
#include <stdio.h>
#include <limits.h>
int max(int a, int b);
void display_matrix(int **matrix, int n, int m);
int main(){
// Input
int n, m;
scanf("%d %d", &n, &m);
int **grid = (int**) malloc(n*sizeof (int*));
for(int i=0; i<n; i++) {
grid[... | -1 | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,648,369,115 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 32 | 124 | 0 | n = int(input())
a = list(map(int,input().split()))
even=0
odd=0
maxie=-1
maxio=-1
for i in range(n):
if (a[i]%2==0):
even+=1
maxie=max(maxie,i+1)
else:
odd+=1
maxio=max(maxio,i+1)
if (even==1):
print(maxie)
else:
print(maxio)
| Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n = int(input())
a = list(map(int,input().split()))
even=0
odd=0
maxie=-1
maxio=-1
for i in range(n):
if (a[i]%2==0):
even+=1
maxie=max(maxie,i+1)
else:
odd+=1
maxio=max(maxio,i+1)
if (even==1):
print(maxie)
else:
print(maxio)
``` | 3.969 |
577 | A | Multiplication Table | PROGRAMMING | 1,000 | [
"implementation",
"number theory"
] | null | null | Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain num... | The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table. | Print a single number: the number of times *x* occurs in the table. | [
"10 5\n",
"6 12\n",
"5 13\n"
] | [
"2\n",
"4\n",
"0\n"
] | A table for the second sample test is given below. The occurrences of number 12 are marked bold. | 500 | [
{
"input": "10 5",
"output": "2"
},
{
"input": "6 12",
"output": "4"
},
{
"input": "5 13",
"output": "0"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "100000 1",
"output": "1"
},
{
"input": "1 10000000... | 1,685,716,133 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | def f(n,x):
k=0
for i in range(1,n+1):
j = int(x/i)
if i*j == x:
k+=1
return k
nx = input().split(" ")
n = int(nx[0])
x = int(nx[1])
print(f(n,x)) | Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
Y... | ```python
def f(n,x):
k=0
for i in range(1,n+1):
j = int(x/i)
if i*j == x:
k+=1
return k
nx = input().split(" ")
n = int(nx[0])
x = int(nx[1])
print(f(n,x))
``` | 0 | |
31 | B | Sysadmin Bob | PROGRAMMING | 1,500 | [
"greedy",
"implementation",
"strings"
] | B. Sysadmin Bob | 0 | 256 | Email address in Berland is a string of the form *A*@*B*, where *A* and *B* are arbitrary strings consisting of small Latin letters.
Bob is a system administrator in «Bersoft» company. He keeps a list of email addresses of the company's staff. This list is as a large string, where all addresses are written in arbitra... | The first line contains the list of addresses without separators. The length of this string is between 1 and 200, inclusive. The string consists only from small Latin letters and characters «@». | If there is no list of the valid (according to the Berland rules) email addresses such that after removing all commas it coincides with the given string, output No solution. In the other case, output the list. The same address can be written in this list more than once. If there are several solutions, output any of the... | [
"a@aa@a\n",
"a@a@a\n",
"@aa@a\n"
] | [
"a@a,a@a\n",
"No solution\n",
"No solution\n"
] | none | 1,000 | [
{
"input": "a@aa@a",
"output": "a@a,a@a"
},
{
"input": "a@a@a",
"output": "No solution"
},
{
"input": "@aa@a",
"output": "No solution"
},
{
"input": "aba@caba@daba",
"output": "aba@c,aba@daba"
},
{
"input": "asd@qwasd@qwasd@qwasd@qwasd@qw",
"output": "asd@q,wa... | 1,566,885,634 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 109 | 0 | s = input()
l=len(s)
i=0
t=''
j=0
lis=[]
while i<l-1:
if s[i]=='@':
t+='@'+s[i+1]
i+=1
j=i
lis.append(t)
t=''
else:
t+=s[i]
i+=1
lis[-1]=lis[-1]+s[j:]
#print(lis)
if len(lis)==0:
print("No solution")
exit()
for i in lis... | Title: Sysadmin Bob
Time Limit: 0 seconds
Memory Limit: 256 megabytes
Problem Description:
Email address in Berland is a string of the form *A*@*B*, where *A* and *B* are arbitrary strings consisting of small Latin letters.
Bob is a system administrator in «Bersoft» company. He keeps a list of email addresses of t... | ```python
s = input()
l=len(s)
i=0
t=''
j=0
lis=[]
while i<l-1:
if s[i]=='@':
t+='@'+s[i+1]
i+=1
j=i
lis.append(t)
t=''
else:
t+=s[i]
i+=1
lis[-1]=lis[-1]+s[j:]
#print(lis)
if len(lis)==0:
print("No solution")
exit()
fo... | 0 |
673 | A | Bear and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be *n* interesting minutes *t*1,<=*t*2,<=...... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=90) — the number of interesting minutes.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=... *t**n*<=≤<=90), given in the increasing order. | Print the number of minutes Limak will watch the game. | [
"3\n7 20 88\n",
"9\n16 20 30 40 50 60 70 80 90\n",
"9\n15 20 30 40 50 60 70 80 90\n"
] | [
"35\n",
"15\n",
"90\n"
] | In the first sample, minutes 21, 22, ..., 35 are all boring and thus Limak will turn TV off immediately after the 35-th minute. So, he would watch the game for 35 minutes.
In the second sample, the first 15 minutes are boring.
In the third sample, there are no consecutive 15 boring minutes. So, Limak will watch the w... | 500 | [
{
"input": "3\n7 20 88",
"output": "35"
},
{
"input": "9\n16 20 30 40 50 60 70 80 90",
"output": "15"
},
{
"input": "9\n15 20 30 40 50 60 70 80 90",
"output": "90"
},
{
"input": "30\n6 11 12 15 22 24 30 31 32 33 34 35 40 42 44 45 47 50 53 54 57 58 63 67 75 77 79 81 83 88",
... | 1,583,210,911 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 140 | 0 | n = int(input())
l = list(map(int,input().split()))
ans1 = 0
ans = 0
if l[0] > 15:
print(15)
else:
for i in range(len(l)-1):
if abs(l[i]-l[i+1]) > 15:
print(l[i]+15)
exit()
else:
ans = l[i+1]
ans1 += 1
if ans > 75:
print(... | Title: Bear and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Lim... | ```python
n = int(input())
l = list(map(int,input().split()))
ans1 = 0
ans = 0
if l[0] > 15:
print(15)
else:
for i in range(len(l)-1):
if abs(l[i]-l[i+1]) > 15:
print(l[i]+15)
exit()
else:
ans = l[i+1]
ans1 += 1
if ans > 75:
... | 0 | |
334 | A | Candy Bags | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Gerald has *n* younger brothers and their number happens to be even. One day he bought *n*2 candy bags. One bag has one candy, one bag has two candies, one bag has three candies and so on. In fact, for each integer *k* from 1 to *n*2 he has exactly one bag with *k* candies.
Help him give *n* bags of candies to each b... | The single line contains a single integer *n* (*n* is even, 2<=≤<=*n*<=≤<=100) — the number of Gerald's brothers. | Let's assume that Gerald indexes his brothers with numbers from 1 to *n*. You need to print *n* lines, on the *i*-th line print *n* integers — the numbers of candies in the bags for the *i*-th brother. Naturally, all these numbers should be distinct and be within limits from 1 to *n*2. You can print the numbers in the ... | [
"2\n"
] | [
"1 4\n2 3\n"
] | The sample shows Gerald's actions if he has two brothers. In this case, his bags contain 1, 2, 3 and 4 candies. He can give the bags with 1 and 4 candies to one brother and the bags with 2 and 3 to the other brother. | 500 | [
{
"input": "2",
"output": "1 4\n2 3"
},
{
"input": "4",
"output": "1 16 2 15\n3 14 4 13\n5 12 6 11\n7 10 8 9"
},
{
"input": "6",
"output": "1 36 2 35 3 34\n4 33 5 32 6 31\n7 30 8 29 9 28\n10 27 11 26 12 25\n13 24 14 23 15 22\n16 21 17 20 18 19"
},
{
"input": "8",
"output"... | 1,659,709,778 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | n = int(input())
c = 1
for i in range(0, n):
for j in range(n // 2):
print(f"{c} {n * n - c + 1} ", end="")
c += 1
print()
| Title: Candy Bags
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald has *n* younger brothers and their number happens to be even. One day he bought *n*2 candy bags. One bag has one candy, one bag has two candies, one bag has three candies and so on. In fact, for each integer *k* from ... | ```python
n = int(input())
c = 1
for i in range(0, n):
for j in range(n // 2):
print(f"{c} {n * n - c + 1} ", end="")
c += 1
print()
``` | 3 | |
586 | A | Alena's Schedule | PROGRAMMING | 900 | [
"implementation"
] | null | null | Alena has successfully passed the entrance exams to the university and is now looking forward to start studying.
One two-hour lesson at the Russian university is traditionally called a pair, it lasts for two academic hours (an academic hour is equal to 45 minutes).
The University works in such a way that every day it... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of lessons at the university.
The second line contains *n* numbers *a**i* (0<=≤<=*a**i*<=≤<=1). Number *a**i* equals 0, if Alena doesn't have the *i*-th pairs, otherwise it is equal to 1. Numbers *a*1,<=*a*2,<=...,<=*a**n* ar... | Print a single number — the number of pairs during which Alena stays at the university. | [
"5\n0 1 0 1 1\n",
"7\n1 0 1 0 0 1 0\n",
"1\n0\n"
] | [
"4\n",
"4\n",
"0\n"
] | In the first sample Alena stays at the university from the second to the fifth pair, inclusive, during the third pair she will be it the university waiting for the next pair.
In the last sample Alena doesn't have a single pair, so she spends all the time at home. | 500 | [
{
"input": "5\n0 1 0 1 1",
"output": "4"
},
{
"input": "7\n1 0 1 0 0 1 0",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n0 0",
"output": "0"
},
{
"input": "2\n0 1",
"output": "1"
},
{
... | 1,582,047,991 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 307,200 | n = int(input())
pairs = ''.join(input().split())
pairs = pairs.strip('0')
if len(pairs) == 0:
print('0')
exit()
ans = int(pairs[0] == '1') + int(pairs[-1] == '1')
for i in range(1, len(pairs)-1):
if pairs[i] == '1':
ans += 1
elif pairs[i-1] == '1' and pairs[i] == '0' and pairs[i... | Title: Alena's Schedule
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alena has successfully passed the entrance exams to the university and is now looking forward to start studying.
One two-hour lesson at the Russian university is traditionally called a pair, it lasts for two academic ... | ```python
n = int(input())
pairs = ''.join(input().split())
pairs = pairs.strip('0')
if len(pairs) == 0:
print('0')
exit()
ans = int(pairs[0] == '1') + int(pairs[-1] == '1')
for i in range(1, len(pairs)-1):
if pairs[i] == '1':
ans += 1
elif pairs[i-1] == '1' and pairs[i] == '0' a... | 0 | |
339 | A | Helpful Maths | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings",
"strings"
] | null | null | Xenia the beginner mathematician is a third year student at elementary school. She is now learning the addition operation.
The teacher has written down the sum of multiple numbers. Pupils should calculate the sum. To make the calculation easier, the sum only contains numbers 1, 2 and 3. Still, that isn't enough for Xe... | The first line contains a non-empty string *s* — the sum Xenia needs to count. String *s* contains no spaces. It only contains digits and characters "+". Besides, string *s* is a correct sum of numbers 1, 2 and 3. String *s* is at most 100 characters long. | Print the new sum that Xenia can count. | [
"3+2+1\n",
"1+1+3+1+3\n",
"2\n"
] | [
"1+2+3\n",
"1+1+1+3+3\n",
"2\n"
] | none | 500 | [
{
"input": "3+2+1",
"output": "1+2+3"
},
{
"input": "1+1+3+1+3",
"output": "1+1+1+3+3"
},
{
"input": "2",
"output": "2"
},
{
"input": "2+2+1+1+3",
"output": "1+1+2+2+3"
},
{
"input": "2+1+2+2+2+3+1+3+1+2",
"output": "1+1+1+2+2+2+2+2+3+3"
},
{
"input": ... | 1,699,280,973 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 92 | 0 | operation_input = input()
operations = operation_input.split("+")
operations.sort()
new_s = ""
for _ in range(len(operations)):
if operations[_] != operations[-1]:
new_s += operations[_] + "+"
else:
new_s += operations[_]
print(new_s) | Title: Helpful Maths
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the beginner mathematician is a third year student at elementary school. She is now learning the addition operation.
The teacher has written down the sum of multiple numbers. Pupils should calculate the sum. To mak... | ```python
operation_input = input()
operations = operation_input.split("+")
operations.sort()
new_s = ""
for _ in range(len(operations)):
if operations[_] != operations[-1]:
new_s += operations[_] + "+"
else:
new_s += operations[_]
print(new_s)
``` | 0 | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,684,767,435 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 93 | 2,867,200 | n,m=map(int,input().split())
l=[]
for i in range(n*m):
a=input().split()
l.append(a)
if ("C" in l)or ("Y" in l)or("M" in l):
print("#Color")
else:
print("#Black&White")
| Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
n,m=map(int,input().split())
l=[]
for i in range(n*m):
a=input().split()
l.append(a)
if ("C" in l)or ("Y" in l)or("M" in l):
print("#Color")
else:
print("#Black&White")
``` | -1 | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,667,315,922 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 32 | 124 | 0 | # import sys
# input = sys.stdin.readline
# for _ in range(int(input())):
n = int(input())
a = list(map(int,input().split(" ")))
odd,even,b,c = 0,0,0,0
for i in range(n):
if a[i]%2:
odd += 1
b = i+1
else:
even += 1
c = i+1
if odd == 1:
print(b)
else:
pri... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
# import sys
# input = sys.stdin.readline
# for _ in range(int(input())):
n = int(input())
a = list(map(int,input().split(" ")))
odd,even,b,c = 0,0,0,0
for i in range(n):
if a[i]%2:
odd += 1
b = i+1
else:
even += 1
c = i+1
if odd == 1:
print(b)
else... | 3.969 |
0 | none | none | none | 0 | [
"none"
] | null | null | Bike is interested in permutations. A permutation of length *n* is an integer sequence such that each integer from 0 to (*n*<=-<=1) appears exactly once in it. For example, [0,<=2,<=1] is a permutation of length 3 while both [0,<=2,<=2] and [1,<=2,<=3] is not.
A permutation triple of permutations of length *n* (*a*,<=... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105). | If no Lucky Permutation Triple of length *n* exists print -1.
Otherwise, you need to print three lines. Each line contains *n* space-seperated integers. The first line must contain permutation *a*, the second line — permutation *b*, the third — permutation *c*.
If there are multiple solutions, print any of them. | [
"5\n",
"2\n"
] | [
"1 4 3 2 0\n1 0 2 4 3\n2 4 0 1 3\n",
"-1\n"
] | In Sample 1, the permutation triple ([1, 4, 3, 2, 0], [1, 0, 2, 4, 3], [2, 4, 0, 1, 3]) is Lucky Permutation Triple, as following holds:
- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a6bf1b9b57809dbec5021f65f89616f259587c07.png" style="max-width: 100.0%;max-height: 100.0%;"/>; - <img... | 0 | [
{
"input": "5",
"output": "1 4 3 2 0\n1 0 2 4 3\n2 4 0 1 3"
},
{
"input": "2",
"output": "-1"
},
{
"input": "8",
"output": "-1"
},
{
"input": "9",
"output": "0 1 2 3 4 5 6 7 8 \n0 1 2 3 4 5 6 7 8 \n0 2 4 6 8 1 3 5 7 "
},
{
"input": "2",
"output": "-1"
},
{... | 1,566,075,670 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 1,308 | 716,800 | n = int(input())
if n%2==0:
print(-1)
else:
print(0,end=" ")
for i in range(n-1,0,-1):
print(i,end=" ")
print()
for i in range(0,2*n,2):
print(i%n,end=" ")
print()
for i in range(n):
print(i,end=" ")
print()
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bike is interested in permutations. A permutation of length *n* is an integer sequence such that each integer from 0 to (*n*<=-<=1) appears exactly once in it. For example, [0,<=2,<=1] is a permutation of length 3 while both [0,<=... | ```python
n = int(input())
if n%2==0:
print(-1)
else:
print(0,end=" ")
for i in range(n-1,0,-1):
print(i,end=" ")
print()
for i in range(0,2*n,2):
print(i%n,end=" ")
print()
for i in range(n):
print(i,end=" ")
print()
``` | 3 | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,680,808,872 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 46 | 0 | x,y=map(int,input().split())
n=1
while(True):
total_price=x*n#t=15*1
total_price_1=(total_price-y)%10
z=total_price%10
if(total_price_1==0 or z==0):
break
n+=1
print(n)
| Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
x,y=map(int,input().split())
n=1
while(True):
total_price=x*n#t=15*1
total_price_1=(total_price-y)%10
z=total_price%10
if(total_price_1==0 or z==0):
break
n+=1
print(n)
``` | 3 | |
496 | C | Removing Columns | PROGRAMMING | 1,500 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | You are given an *n*<=×<=*m* rectangular table consisting of lower case English letters. In one operation you can completely remove one column from the table. The remaining parts are combined forming a new table. For example, after removing the second column from the table
we obtain the table:
A table is called... | The first line contains two integers — *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).
Next *n* lines contain *m* small English letters each — the characters of the table. | Print a single number — the minimum number of columns that you need to remove in order to make the table good. | [
"1 10\ncodeforces\n",
"4 4\ncase\ncare\ntest\ncode\n",
"5 4\ncode\nforc\nesco\ndefo\nrces\n"
] | [
"0\n",
"2\n",
"4\n"
] | In the first sample the table is already good.
In the second sample you may remove the first and third column.
In the third sample you have to remove all the columns (note that the table where all rows are empty is considered good by definition).
Let strings *s* and *t* have equal length. Then, *s* is lexicographica... | 1,750 | [
{
"input": "1 10\ncodeforces",
"output": "0"
},
{
"input": "4 4\ncase\ncare\ntest\ncode",
"output": "2"
},
{
"input": "5 4\ncode\nforc\nesco\ndefo\nrces",
"output": "4"
},
{
"input": "2 2\nfb\nye",
"output": "0"
},
{
"input": "5 5\nrzrzh\nrzrzh\nrzrzh\nrzrzh\nrzrz... | 1,694,345,416 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 11 | 46 | 0 | def main():
n, m = map(int, input().split())
s = []
for _ in range(n):
s.append(input())
if n == 1 or m == 1:
return 0
q = [0] * m
w = [''] * n
j = 0
while j < m:
for i in range(n - 1):
if w[i] + s[i][j] > w[i + 1] + s[i + 1][j]:
... | Title: Removing Columns
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an *n*<=×<=*m* rectangular table consisting of lower case English letters. In one operation you can completely remove one column from the table. The remaining parts are combined forming a new table. For e... | ```python
def main():
n, m = map(int, input().split())
s = []
for _ in range(n):
s.append(input())
if n == 1 or m == 1:
return 0
q = [0] * m
w = [''] * n
j = 0
while j < m:
for i in range(n - 1):
if w[i] + s[i][j] > w[i + 1] + s[i + 1][j]:
... | 0 | |
302 | B | Eugeny and Play List | PROGRAMMING | 1,200 | [
"binary search",
"implementation",
"two pointers"
] | null | null | Eugeny loves listening to music. He has *n* songs in his play list. We know that song number *i* has the duration of *t**i* minutes. Eugeny listens to each song, perhaps more than once. He listens to song number *i* *c**i* times. Eugeny's play list is organized as follows: first song number 1 plays *c*1 times, then son... | The first line contains two integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=105). The next *n* lines contain pairs of integers. The *i*-th line contains integers *c**i*,<=*t**i* (1<=≤<=*c**i*,<=*t**i*<=≤<=109) — the description of the play list. It is guaranteed that the play list's total duration doesn't exceed 109 .
The next... | Print *m* integers — the *i*-th number must equal the number of the song that was playing during the *v**i*-th minute after Eugeny started listening to the play list. | [
"1 2\n2 8\n1 16\n",
"4 9\n1 2\n2 1\n1 1\n2 2\n1 2 3 4 5 6 7 8 9\n"
] | [
"1\n1\n",
"1\n1\n2\n2\n3\n4\n4\n4\n4\n"
] | none | 1,000 | [
{
"input": "1 2\n2 8\n1 16",
"output": "1\n1"
},
{
"input": "4 9\n1 2\n2 1\n1 1\n2 2\n1 2 3 4 5 6 7 8 9",
"output": "1\n1\n2\n2\n3\n4\n4\n4\n4"
},
{
"input": "3 3\n2 8\n5 1\n10 5\n13 16 62",
"output": "1\n1\n3"
},
{
"input": "4 4\n2 8\n2 2\n6 3\n8 7\n13 23 29 85",
"output... | 1,580,706,157 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 20 | 2,000 | 13,516,800 | def search(arr,x,n):
low,high = 0,n-1
if x<=arr[low]:
return 1
while low<high:
mid = (low+high)//2
if x==arr[mid]:
return mid+1
elif abs(low-high)==1:
return high+1
elif x>arr[mid]:
low = mid
elif x<arr[mid]:
... | Title: Eugeny and Play List
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eugeny loves listening to music. He has *n* songs in his play list. We know that song number *i* has the duration of *t**i* minutes. Eugeny listens to each song, perhaps more than once. He listens to song number *i... | ```python
def search(arr,x,n):
low,high = 0,n-1
if x<=arr[low]:
return 1
while low<high:
mid = (low+high)//2
if x==arr[mid]:
return mid+1
elif abs(low-high)==1:
return high+1
elif x>arr[mid]:
low = mid
elif x<arr... | 0 | |
982 | B | Bus of Characters | PROGRAMMING | 1,300 | [
"data structures",
"greedy",
"implementation"
] | null | null | In the Bus of Characters there are $n$ rows of seat, each having $2$ seats. The width of both seats in the $i$-th row is $w_i$ centimeters. All integers $w_i$ are distinct.
Initially the bus is empty. On each of $2n$ stops one passenger enters the bus. There are two types of passengers:
- an introvert always choose... | The first line contains a single integer $n$ ($1 \le n \le 200\,000$) — the number of rows in the bus.
The second line contains the sequence of integers $w_1, w_2, \dots, w_n$ ($1 \le w_i \le 10^{9}$), where $w_i$ is the width of each of the seats in the $i$-th row. It is guaranteed that all $w_i$ are distinct.
The t... | Print $2n$ integers — the rows the passengers will take. The order of passengers should be the same as in input. | [
"2\n3 1\n0011\n",
"6\n10 8 9 11 13 5\n010010011101\n"
] | [
"2 1 1 2 \n",
"6 6 2 3 3 1 4 4 1 2 5 5 \n"
] | In the first example the first passenger (introvert) chooses the row $2$, because it has the seats with smallest width. The second passenger (introvert) chooses the row $1$, because it is the only empty row now. The third passenger (extrovert) chooses the row $1$, because it has exactly one occupied seat and the seat w... | 1,000 | [
{
"input": "2\n3 1\n0011",
"output": "2 1 1 2 "
},
{
"input": "6\n10 8 9 11 13 5\n010010011101",
"output": "6 6 2 3 3 1 4 4 1 2 5 5 "
},
{
"input": "1\n1\n01",
"output": "1 1 "
},
{
"input": "1\n1000000\n01",
"output": "1 1 "
},
{
"input": "2\n1 1000000\n0011",
... | 1,621,951,724 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 29 | 2,000 | 24,985,600 | import heapq
n = int(input())
w = [int(z) for z in input().split()]
s = input()
idx = []
for i in range(n):
idx.append((w[i], i+1))
idx.sort()
heapq.heapify(idx)
ones = []
heapq.heapify(ones)
#print(idx)
res = []
for i in range(2*n):
if s[i] == '0':
l = idx[0]
heapq.heapp... | Title: Bus of Characters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the Bus of Characters there are $n$ rows of seat, each having $2$ seats. The width of both seats in the $i$-th row is $w_i$ centimeters. All integers $w_i$ are distinct.
Initially the bus is empty. On each of $2n$... | ```python
import heapq
n = int(input())
w = [int(z) for z in input().split()]
s = input()
idx = []
for i in range(n):
idx.append((w[i], i+1))
idx.sort()
heapq.heapify(idx)
ones = []
heapq.heapify(ones)
#print(idx)
res = []
for i in range(2*n):
if s[i] == '0':
l = idx[0]
h... | 0 | |
572 | A | Arrays | PROGRAMMING | 900 | [
"sortings"
] | null | null | You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the first array is strictly less than any number chosen in the second array. | The first line contains two integers *n**A*,<=*n**B* (1<=≤<=*n**A*,<=*n**B*<=≤<=105), separated by a space — the sizes of arrays *A* and *B*, correspondingly.
The second line contains two integers *k* and *m* (1<=≤<=*k*<=≤<=*n**A*,<=1<=≤<=*m*<=≤<=*n**B*), separated by a space.
The third line contains *n**A* numbers *... | Print "YES" (without the quotes), if you can choose *k* numbers in array *A* and *m* numbers in array *B* so that any number chosen in array *A* was strictly less than any number chosen in array *B*. Otherwise, print "NO" (without the quotes). | [
"3 3\n2 1\n1 2 3\n3 4 5\n",
"3 3\n3 3\n1 2 3\n3 4 5\n",
"5 2\n3 1\n1 1 1 1 1\n2 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample test you can, for example, choose numbers 1 and 2 from array *A* and number 3 from array *B* (1 < 3 and 2 < 3).
In the second sample test the only way to choose *k* elements in the first array and *m* elements in the second one is to choose all numbers in both arrays, but then not all the num... | 500 | [
{
"input": "3 3\n2 1\n1 2 3\n3 4 5",
"output": "YES"
},
{
"input": "3 3\n3 3\n1 2 3\n3 4 5",
"output": "NO"
},
{
"input": "5 2\n3 1\n1 1 1 1 1\n2 2",
"output": "YES"
},
{
"input": "3 5\n1 1\n5 5 5\n5 5 5 5 5",
"output": "NO"
},
{
"input": "1 1\n1 1\n1\n1",
"ou... | 1,590,075,237 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 171 | 307,200 |
import collections
def solve(lenA, lenB, k, m, a, b):
maxA = max(a[:k])
minB = min(b[:m])
return maxA < minB
[lenA, lenB] = list(map(int, input().strip().split()))
[k, m] = list(map(int, input().strip().split()))
a = list(map(int, input().strip().split()))
b = list(map(int, input().str... | Title: Arrays
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the fi... | ```python
import collections
def solve(lenA, lenB, k, m, a, b):
maxA = max(a[:k])
minB = min(b[:m])
return maxA < minB
[lenA, lenB] = list(map(int, input().strip().split()))
[k, m] = list(map(int, input().strip().split()))
a = list(map(int, input().strip().split()))
b = list(map(int, i... | 0 | |
14 | A | Letter | PROGRAMMING | 800 | [
"implementation"
] | A. Letter | 1 | 64 | A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brother, who lives in Flatland. Now Bob has to send his picture by post, but because of the w... | The first line of the input data contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50), *n* — amount of lines, and *m* — amount of columns on Bob's sheet. The following *n* lines contain *m* characters each. Character «.» stands for a non-shaded square on the sheet, and «*» — for a shaded square. It is guaranteed that ... | Output the required rectangle of the minimum cost. Study the output data in the sample tests to understand the output format better. | [
"6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..\n",
"3 3\n***\n*.*\n***\n"
] | [
"***\n*..\n***\n*..\n***\n",
"***\n*.*\n***\n"
] | none | 0 | [
{
"input": "6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..",
"output": "***\n*..\n***\n*..\n***"
},
{
"input": "3 3\n***\n*.*\n***",
"output": "***\n*.*\n***"
},
{
"input": "1 1\n*",
"output": "*"
},
{
"input": "2 1\n*\n*",
"output": "*\n*"
},
{
"input"... | 1,677,330,967 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | n, m = map(int, input().split())
grid = [input() for _ in range(n)]
min_row, max_row, min_col, max_col = n, -1, m, -1
for i in range(n):
for j in range(m):
if grid[i][j] == '*':
min_row = min(min_row, i)
max_row = max(max_row, i)
min_col = min(min_col, j)
... | Title: Letter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brothe... | ```python
n, m = map(int, input().split())
grid = [input() for _ in range(n)]
min_row, max_row, min_col, max_col = n, -1, m, -1
for i in range(n):
for j in range(m):
if grid[i][j] == '*':
min_row = min(min_row, i)
max_row = max(max_row, i)
min_col = min(min_col,... | 3.954 |
889 | E | Mod Mod Mod | PROGRAMMING | 3,000 | [
"binary search",
"dp",
"math"
] | null | null | You are given a sequence of integers *a*1,<=*a*2,<=...,<=*a**n*. Let , and for 1<=≤<=*i*<=<<=*n*. Here, denotes the modulus operation. Find the maximum value of *f*(*x*,<=1) over all nonnegative integers *x*. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=200000) — the length of the sequence.
The second lines contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1013) — the elements of the sequence. | Output a single integer — the maximum value of *f*(*x*,<=1) over all nonnegative integers *x*. | [
"2\n10 5\n",
"5\n5 4 3 2 1\n",
"4\n5 10 5 10\n"
] | [
"13\n",
"6\n",
"16\n"
] | In the first example you can choose, for example, *x* = 19.
In the second example you can choose, for example, *x* = 3 or *x* = 2. | 2,250 | [] | 1,511,008,759 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 62 | 0 | n=int(input())
list_a=[int(z) for z in input().split()]
list_inside=[int(l)*0 for l in range(0,n)]
_max=0
for x in range(round(list_a[0]/2),list_a[0]):
list_inside[0]=x%list_a[0]
for _i in range(1,n):
list_inside[_i]=list_inside[_i-1]%list_a[_i]
if sum(list_inside) > _max:
_max=sum(list_inside... | Title: Mod Mod Mod
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence of integers *a*1,<=*a*2,<=...,<=*a**n*. Let , and for 1<=≤<=*i*<=<<=*n*. Here, denotes the modulus operation. Find the maximum value of *f*(*x*,<=1) over all nonnegative integers *x*.
Input Sp... | ```python
n=int(input())
list_a=[int(z) for z in input().split()]
list_inside=[int(l)*0 for l in range(0,n)]
_max=0
for x in range(round(list_a[0]/2),list_a[0]):
list_inside[0]=x%list_a[0]
for _i in range(1,n):
list_inside[_i]=list_inside[_i-1]%list_a[_i]
if sum(list_inside) > _max:
_max=sum(l... | 0 | |
877 | B | Nikita and string | PROGRAMMING | 1,500 | [
"brute force",
"dp"
] | null | null | One day Nikita found the string containing letters "a" and "b" only.
Nikita thinks that string is beautiful if it can be cut into 3 strings (possibly empty) without changing the order of the letters, where the 1-st and the 3-rd one contain only letters "a" and the 2-nd contains only letters "b".
Nikita wants to make... | The first line contains a non-empty string of length not greater than 5<=000 containing only lowercase English letters "a" and "b". | Print a single integer — the maximum possible size of beautiful string Nikita can get. | [
"abba\n",
"bab\n"
] | [
"4",
"2"
] | It the first sample the string is already beautiful.
In the second sample he needs to delete one of "b" to make it beautiful. | 1,000 | [
{
"input": "abba",
"output": "4"
},
{
"input": "bab",
"output": "2"
},
{
"input": "bbabbbaabbbb",
"output": "9"
},
{
"input": "bbabbbbbaaba",
"output": "10"
},
{
"input": "bbabbbababaa",
"output": "9"
},
{
"input": "aabbaababbab",
"output": "8"
}... | 1,614,134,251 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 62 | 0 | x = list(input())
a = 0
b = 0
a2 = 0
for i in range(len(x)):
if x[i] == "a":
a += 1
a2 += 1
if x[i] == "b":
b += 1
a2 = max(a2, b)
b = max(b, a)
print(a2) | Title: Nikita and string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Nikita found the string containing letters "a" and "b" only.
Nikita thinks that string is beautiful if it can be cut into 3 strings (possibly empty) without changing the order of the letters, where the 1-st ... | ```python
x = list(input())
a = 0
b = 0
a2 = 0
for i in range(len(x)):
if x[i] == "a":
a += 1
a2 += 1
if x[i] == "b":
b += 1
a2 = max(a2, b)
b = max(b, a)
print(a2)
``` | 3 | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,475,919,076 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 1,000 | 23,654,400 | s = [ "Sheldon", "Leonard", "Penny", "Rajesh", "Howard"]
n = int(input())
for i in range(n-1):
s.append(s[0])
s.append(s[0])
s.remove(s[0])
print(s[0]) | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
s = [ "Sheldon", "Leonard", "Penny", "Rajesh", "Howard"]
n = int(input())
for i in range(n-1):
s.append(s[0])
s.append(s[0])
s.remove(s[0])
print(s[0])
``` | 0 |
236 | A | Boy or Girl | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.
Bu... | The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters. | If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes). | [
"wjmzbmr\n",
"xiaodao\n",
"sevenkplus\n"
] | [
"CHAT WITH HER!\n",
"IGNORE HIM!\n",
"CHAT WITH HER!\n"
] | For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!". | 500 | [
{
"input": "wjmzbmr",
"output": "CHAT WITH HER!"
},
{
"input": "xiaodao",
"output": "IGNORE HIM!"
},
{
"input": "sevenkplus",
"output": "CHAT WITH HER!"
},
{
"input": "pezu",
"output": "CHAT WITH HER!"
},
{
"input": "wnemlgppy",
"output": "CHAT WITH HER!"
},... | 1,696,491,439 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | def hitung_huruf_sama(input_string):
huruf_dic = {}
for huruf in input_string:
if huruf in huruf_dic:
huruf_dic[huruf] += 1
else:
huruf_dic[huruf] = 1
total_huruf_sama = sum(count % 2 == 1 for count in huruf_dic.values())
return total_huruf_sama % 2 == 0... | Title: Boy or Girl
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he though... | ```python
def hitung_huruf_sama(input_string):
huruf_dic = {}
for huruf in input_string:
if huruf in huruf_dic:
huruf_dic[huruf] += 1
else:
huruf_dic[huruf] = 1
total_huruf_sama = sum(count % 2 == 1 for count in huruf_dic.values())
return total_huruf_sam... | 0 | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,684,526,774 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | n = 4
a = list(map(int, input().split()))
a.sort()
c = 0
for i in range(n-1):
if a[i] != a[i+1]:
c += 1
print(n-c-1) | Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
n = 4
a = list(map(int, input().split()))
a.sort()
c = 0
for i in range(n-1):
if a[i] != a[i+1]:
c += 1
print(n-c-1)
``` | 3 | |
776 | B | Sherlock and his girlfriend | PROGRAMMING | 1,200 | [
"constructive algorithms",
"number theory"
] | null | null | Sherlock has a new girlfriend (so unlike him!). Valentine's day is coming and he wants to gift her some jewelry.
He bought *n* pieces of jewelry. The *i*-th piece has price equal to *i*<=+<=1, that is, the prices of the jewelry are 2,<=3,<=4,<=... *n*<=+<=1.
Watson gave Sherlock a challenge to color these jewelry pie... | The only line contains single integer *n* (1<=≤<=*n*<=≤<=100000) — the number of jewelry pieces. | The first line of output should contain a single integer *k*, the minimum number of colors that can be used to color the pieces of jewelry with the given constraints.
The next line should consist of *n* space-separated integers (between 1 and *k*) that specify the color of each piece in the order of increasing price.
... | [
"3\n",
"4\n"
] | [
"2\n1 1 2 ",
"2\n2 1 1 2\n"
] | In the first input, the colors for first, second and third pieces of jewelry having respective prices 2, 3 and 4 are 1, 1 and 2 respectively.
In this case, as 2 is a prime divisor of 4, colors of jewelry having prices 2 and 4 must be distinct. | 1,000 | [
{
"input": "3",
"output": "2\n1 1 2 "
},
{
"input": "4",
"output": "2\n1 1 2 1 "
},
{
"input": "17",
"output": "2\n1 1 2 1 2 1 2 2 2 1 2 1 2 2 2 1 2 "
},
{
"input": "25",
"output": "2\n1 1 2 1 2 1 2 2 2 1 2 1 2 2 2 1 2 1 2 2 2 1 2 2 2 "
},
{
"input": "85",
"ou... | 1,542,468,937 | 2,147,483,647 | Python 3 | OK | TESTS | 53 | 124 | 716,800 | def get_primes(n):
m = n+2
numbers = ['1'] * m
for i in range(2, int(n**0.5 + 1)):
if numbers[i] == '1':
for j in range(i*i, m, i):
numbers[j] = '2'
return numbers[2:]
entrada = int(input()) #Número de peças
if entrada == 1:
print("1\n1")
elif entrada == 2:
print("1\n1 1")
elif ent... | Title: Sherlock and his girlfriend
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sherlock has a new girlfriend (so unlike him!). Valentine's day is coming and he wants to gift her some jewelry.
He bought *n* pieces of jewelry. The *i*-th piece has price equal to *i*<=+<=1, that is, the ... | ```python
def get_primes(n):
m = n+2
numbers = ['1'] * m
for i in range(2, int(n**0.5 + 1)):
if numbers[i] == '1':
for j in range(i*i, m, i):
numbers[j] = '2'
return numbers[2:]
entrada = int(input()) #Número de peças
if entrada == 1:
print("1\n1")
elif entrada == 2:
print("1\n1 1")... | 3 | |
475 | A | Bayan Bus | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | The final round of Bayan Programming Contest will be held in Tehran, and the participants will be carried around with a yellow bus. The bus has 34 passenger seats: 4 seats in the last row and 3 seats in remaining rows.
The event coordinator has a list of *k* participants who should be picked up at the airport. When a... | The only line of input contains integer *k*, (0<=≤<=*k*<=≤<=34), denoting the number of participants. | Print the figure of a bus with *k* passengers as described in sample tests. Character '#' denotes an empty seat, while 'O' denotes a taken seat. 'D' is the bus driver and other characters in the output are for the purpose of beautifying the figure. Strictly follow the sample test cases output format. Print exactly six ... | [
"9\n",
"20\n"
] | [
"+------------------------+\n|O.O.O.#.#.#.#.#.#.#.#.|D|)\n|O.O.O.#.#.#.#.#.#.#.#.|.|\n|O.......................|\n|O.O.#.#.#.#.#.#.#.#.#.|.|)\n+------------------------+\n",
"+------------------------+\n|O.O.O.O.O.O.O.#.#.#.#.|D|)\n|O.O.O.O.O.O.#.#.#.#.#.|.|\n|O.......................|\n|O.O.O.O.O.O.#.#.#.#.#.|.|... | none | 500 | [
{
"input": "9",
"output": "+------------------------+\n|O.O.O.#.#.#.#.#.#.#.#.|D|)\n|O.O.O.#.#.#.#.#.#.#.#.|.|\n|O.......................|\n|O.O.#.#.#.#.#.#.#.#.#.|.|)\n+------------------------+"
},
{
"input": "20",
"output": "+------------------------+\n|O.O.O.O.O.O.O.#.#.#.#.|D|)\n|O.O.O.O.O.... | 1,604,525,582 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 93 | 307,200 |
n = int(input())
row = ["|", "|", "|", "|"]
c = 0
for i in range(1, 45):
if(c > 3):
c = 0
if(i < 4):
if(n < 1):
row[c] += "#."
else:
row[c] += "O."
elif(c==2):
row[c] += ".."
n += 1
elif(n < 1):
row[c] += "#."
elif(n > 0):
row[c] += "O."
c += 1
n -= 1
row[0] += "|D|)"
row[1] += "|.... | Title: Bayan Bus
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The final round of Bayan Programming Contest will be held in Tehran, and the participants will be carried around with a yellow bus. The bus has 34 passenger seats: 4 seats in the last row and 3 seats in remaining rows.
The ... | ```python
n = int(input())
row = ["|", "|", "|", "|"]
c = 0
for i in range(1, 45):
if(c > 3):
c = 0
if(i < 4):
if(n < 1):
row[c] += "#."
else:
row[c] += "O."
elif(c==2):
row[c] += ".."
n += 1
elif(n < 1):
row[c] += "#."
elif(n > 0):
row[c] += "O."
c += 1
n -= 1
row[0] += "|D|)"
row... | 3 | |
887 | B | Cubes for Masha | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | Absent-minded Masha got set of *n* cubes for her birthday.
At each of 6 faces of each cube, there is exactly one digit from 0 to 9. Masha became interested what is the largest natural *x* such she can make using her new cubes all integers from 1 to *x*.
To make a number Masha can rotate her cubes and put them in a ro... | In first line integer *n* is given (1<=≤<=*n*<=≤<=3) — the number of cubes, Masha got for her birthday.
Each of next *n* lines contains 6 integers *a**i**j* (0<=≤<=*a**i**j*<=≤<=9) — number on *j*-th face of *i*-th cube. | Print single integer — maximum number *x* such Masha can make any integers from 1 to *x* using her cubes or 0 if Masha can't make even 1. | [
"3\n0 1 2 3 4 5\n6 7 8 9 0 1\n2 3 4 5 6 7\n",
"3\n0 1 3 5 6 8\n1 2 4 5 7 8\n2 3 4 6 7 9\n"
] | [
"87",
"98"
] | In the first test case, Masha can build all numbers from 1 to 87, but she can't make 88 because there are no two cubes with digit 8. | 1,000 | [
{
"input": "3\n0 1 2 3 4 5\n6 7 8 9 0 1\n2 3 4 5 6 7",
"output": "87"
},
{
"input": "3\n0 1 3 5 6 8\n1 2 4 5 7 8\n2 3 4 6 7 9",
"output": "98"
},
{
"input": "3\n0 1 2 3 4 5\n0 1 2 3 4 5\n0 1 2 3 4 5",
"output": "5"
},
{
"input": "3\n1 2 3 7 8 9\n9 8 7 1 2 3\n7 9 2 3 1 8",
... | 1,510,549,392 | 2,147,483,647 | Python 3 | OK | TESTS | 96 | 77 | 0 | from itertools import permutations
def parse(n):
l = list()
while(n > 0):
l.append(n%10)
n = n // 10
return l
def check(per,n):
## print(per)
## print(n)
for i in range(len(per)):
ok = True
for j in range(len(n)):
if n[j] not i... | Title: Cubes for Masha
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Absent-minded Masha got set of *n* cubes for her birthday.
At each of 6 faces of each cube, there is exactly one digit from 0 to 9. Masha became interested what is the largest natural *x* such she can make using her ne... | ```python
from itertools import permutations
def parse(n):
l = list()
while(n > 0):
l.append(n%10)
n = n // 10
return l
def check(per,n):
## print(per)
## print(n)
for i in range(len(per)):
ok = True
for j in range(len(n)):
if ... | 3 | |
482 | A | Diverse Permutation | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy"
] | null | null | Permutation *p* is an ordered set of integers *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*, consisting of *n* distinct positive integers not larger than *n*. We'll denote as *n* the length of permutation *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*.
Your task is to find such permutation *p* of length *n*, that the group of number... | The single line of the input contains two space-separated positive integers *n*, *k* (1<=≤<=*k*<=<<=*n*<=≤<=105). | Print *n* integers forming the permutation. If there are multiple answers, print any of them. | [
"3 2\n",
"3 1\n",
"5 2\n"
] | [
"1 3 2\n",
"1 2 3\n",
"1 3 2 4 5\n"
] | By |*x*| we denote the absolute value of number *x*. | 500 | [
{
"input": "3 2",
"output": "1 3 2"
},
{
"input": "3 1",
"output": "1 2 3"
},
{
"input": "5 2",
"output": "1 3 2 4 5"
},
{
"input": "5 4",
"output": "1 5 2 4 3"
},
{
"input": "10 4",
"output": "1 10 2 9 8 7 6 5 4 3"
},
{
"input": "10 3",
"output": ... | 1,603,801,877 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 186 | 6,860,800 | import sys,math
n,k = map(int,input().split(' '))
arr = [None]*n
even = 1
odd = n
for i in range(n):
if i%2==0:
arr[i]=even
even+=1
else:
arr[i]=odd
odd-=1
minn = min(arr[k-1:])
if arr[k-1]>minn:
num = arr[k-1]
for i in range(k-1,n):
arr[i] = num
num-=1
el... | Title: Diverse Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Permutation *p* is an ordered set of integers *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*, consisting of *n* distinct positive integers not larger than *n*. We'll denote as *n* the length of permutation *p*1,<=<=<=*p*2,<... | ```python
import sys,math
n,k = map(int,input().split(' '))
arr = [None]*n
even = 1
odd = n
for i in range(n):
if i%2==0:
arr[i]=even
even+=1
else:
arr[i]=odd
odd-=1
minn = min(arr[k-1:])
if arr[k-1]>minn:
num = arr[k-1]
for i in range(k-1,n):
arr[i] = num
... | 3 | |
441 | A | Valera and Antique Items | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the *j*-th object of the *i*-th seller is *s**ij*. Valera gets on well with each of the *n* sellers. He is perfec... | The first line contains two space-separated integers *n*,<=*v* (1<=≤<=*n*<=≤<=50; 104<=≤<=*v*<=≤<=106) — the number of sellers and the units of money the Valera has.
Then *n* lines follow. The *i*-th line first contains integer *k**i* (1<=≤<=*k**i*<=≤<=50) the number of items of the *i*-th seller. Then go *k**i* space... | In the first line, print integer *p* — the number of sellers with who Valera can make a deal.
In the second line print *p* space-separated integers *q*1,<=*q*2,<=...,<=*q**p* (1<=≤<=*q**i*<=≤<=*n*) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order. | [
"3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000\n",
"3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000\n"
] | [
"3\n1 2 3\n",
"0\n\n"
] | In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.
In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the... | 500 | [
{
"input": "3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000",
"output": "3\n1 2 3"
},
{
"input": "3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000",
"output": "0"
},
{
"input": "2 100001\n1 895737\n1 541571",
"output": "0"
},
{
"input": "1 1000000\n1 100... | 1,617,165,451 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 62 | 307,200 | n,v = map(int, input().split())
s=""
c=0
for i in range(n):
k = list(map(int,input().split()))
for j in range(1,k[0]+1):
if(v>k[j]):
s+=str(i+1)+" "
c+=1
break
print(c)
if(c!=0):
print(s[:len(s)-1]) | Title: Valera and Antique Items
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the... | ```python
n,v = map(int, input().split())
s=""
c=0
for i in range(n):
k = list(map(int,input().split()))
for j in range(1,k[0]+1):
if(v>k[j]):
s+=str(i+1)+" "
c+=1
break
print(c)
if(c!=0):
print(s[:len(s)-1])
``` | 3 | |
370 | A | Rook, Bishop and King | PROGRAMMING | 1,100 | [
"graphs",
"math",
"shortest paths"
] | null | null | Little Petya is learning to play chess. He has already learned how to move a king, a rook and a bishop. Let us remind you the rules of moving chess pieces. A chessboard is 64 square fields organized into an 8<=×<=8 table. A field is represented by a pair of integers (*r*,<=*c*) — the number of the row and the number of... | The input contains four integers *r*1,<=*c*1,<=*r*2,<=*c*2 (1<=≤<=*r*1,<=*c*1,<=*r*2,<=*c*2<=≤<=8) — the coordinates of the starting and the final field. The starting field doesn't coincide with the final one.
You can assume that the chessboard rows are numbered from top to bottom 1 through 8, and the columns are numb... | Print three space-separated integers: the minimum number of moves the rook, the bishop and the king (in this order) is needed to move from field (*r*1,<=*c*1) to field (*r*2,<=*c*2). If a piece cannot make such a move, print a 0 instead of the corresponding number. | [
"4 3 1 6\n",
"5 5 5 6\n"
] | [
"2 1 3\n",
"1 0 1\n"
] | none | 500 | [
{
"input": "4 3 1 6",
"output": "2 1 3"
},
{
"input": "5 5 5 6",
"output": "1 0 1"
},
{
"input": "1 1 8 8",
"output": "2 1 7"
},
{
"input": "1 1 8 1",
"output": "1 0 7"
},
{
"input": "1 1 1 8",
"output": "1 0 7"
},
{
"input": "8 1 1 1",
"output": "... | 1,657,261,390 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 42 | 109 | 512,000 | r1,r2,t1,t2=map(int,input().split())
if r1==t1 or r2==t2:
print(1,end=' ')
else:
print(2,end=' ')
if r1%2!=r2%2 and t2%2!=t1%2 or r1%2==r2%2 and t1%2==t2%2:
if abs(r1-t1)==abs(r2-t2):
print(1,end=' ')
else:
print(2,end=' ')
else:
print(0,end=' ')
print(max(abs(t1-r1),... | Title: Rook, Bishop and King
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya is learning to play chess. He has already learned how to move a king, a rook and a bishop. Let us remind you the rules of moving chess pieces. A chessboard is 64 square fields organized into an 8<=×<=... | ```python
r1,r2,t1,t2=map(int,input().split())
if r1==t1 or r2==t2:
print(1,end=' ')
else:
print(2,end=' ')
if r1%2!=r2%2 and t2%2!=t1%2 or r1%2==r2%2 and t1%2==t2%2:
if abs(r1-t1)==abs(r2-t2):
print(1,end=' ')
else:
print(2,end=' ')
else:
print(0,end=' ')
print(max(a... | 3 | |
369 | B | Valera and Contest | PROGRAMMING | 1,400 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | Valera loves to participate in competitions. Especially in programming contests. Today he has participated in the contest with his team, consisting of *n* students (including Valera). This contest was an individual competition, so each student in the team solved problems individually.
After the contest was over, Valer... | The first line of the input contains exactly six integers *n*,<=*k*,<=*l*,<=*r*,<=*s**all*,<=*s**k* (1<=≤<=*n*,<=*k*,<=*l*,<=*r*<=≤<=1000; *l*<=≤<=*r*; *k*<=≤<=*n*; 1<=≤<=*s**k*<=≤<=*s**all*<=≤<=106).
It's guaranteed that the input is such that the answer exists. | Print exactly *n* integers *a*1,<=*a*2,<=...,<=*a**n* — the number of points each student scored. If there are multiple solutions, you can print any of them. You can print the distribution of points in any order. | [
"5 3 1 3 13 9\n",
"5 3 1 3 15 9\n"
] | [
"2 3 2 3 3 ",
"3 3 3 3 3 "
] | none | 1,000 | [
{
"input": "5 3 1 3 13 9",
"output": "2 3 2 3 3 "
},
{
"input": "5 3 1 3 15 9",
"output": "3 3 3 3 3 "
},
{
"input": "50 25 1 1 50 25",
"output": "1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 "
},
{
"input": "1000 700 782... | 1,663,260,885 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 46 | 0 | n, k, l, r, sa, sk = map(int, input().split())
print(' '.join(map(str, [sk // k + 1 if i in range(sk % k) else sk // k for i in range(k)] + [(sa - sk) // (n - k) + 1 if i in range((sa - sk) % (n - k)) else (sa - sk) // (n - k) for i in range((n - k))])))
| Title: Valera and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera loves to participate in competitions. Especially in programming contests. Today he has participated in the contest with his team, consisting of *n* students (including Valera). This contest was an individual c... | ```python
n, k, l, r, sa, sk = map(int, input().split())
print(' '.join(map(str, [sk // k + 1 if i in range(sk % k) else sk // k for i in range(k)] + [(sa - sk) // (n - k) + 1 if i in range((sa - sk) % (n - k)) else (sa - sk) // (n - k) for i in range((n - k))])))
``` | 3 | |
991 | A | If at first you don't succeed... | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Each student eagerly awaits the day he would pass the exams successfully. Thus, Vasya was ready to celebrate, but, alas, he didn't pass it. However, many of Vasya's fellow students from the same group were more successful and celebrated after the exam.
Some of them celebrated in the BugDonalds restaurant, some of them... | The first line contains four integers — $A$, $B$, $C$ and $N$ ($0 \leq A, B, C, N \leq 100$). | If a distribution of $N$ students exists in which $A$ students visited BugDonalds, $B$ — BeaverKing, $C$ — both of the restaurants and at least one student is left home (it is known that Vasya didn't pass the exam and stayed at home), output one integer — amount of students (including Vasya) who did not pass the exam. ... | [
"10 10 5 20\n",
"2 2 0 4\n",
"2 2 2 1\n"
] | [
"5",
"-1",
"-1"
] | The first sample describes following situation: $5$ only visited BugDonalds, $5$ students only visited BeaverKing, $5$ visited both of them and $5$ students (including Vasya) didn't pass the exam.
In the second sample $2$ students only visited BugDonalds and $2$ only visited BeaverKing, but that means all $4$ students... | 500 | [
{
"input": "10 10 5 20",
"output": "5"
},
{
"input": "2 2 0 4",
"output": "-1"
},
{
"input": "2 2 2 1",
"output": "-1"
},
{
"input": "98 98 97 100",
"output": "1"
},
{
"input": "1 5 2 10",
"output": "-1"
},
{
"input": "5 1 2 10",
"output": "-1"
}... | 1,565,937,150 | 2,147,483,647 | PyPy 3 | OK | TESTS | 76 | 155 | 0 | a, b, c, n = map(int, input().split())
if ((a-c)+(b-c)+c) < n and ((not(c>a)) and (not(c>b))):
print (n-((a-c)+(b-c)+c))
else:
print(-1) | Title: If at first you don't succeed...
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Each student eagerly awaits the day he would pass the exams successfully. Thus, Vasya was ready to celebrate, but, alas, he didn't pass it. However, many of Vasya's fellow students from the same group w... | ```python
a, b, c, n = map(int, input().split())
if ((a-c)+(b-c)+c) < n and ((not(c>a)) and (not(c>b))):
print (n-((a-c)+(b-c)+c))
else:
print(-1)
``` | 3 | |
38 | A | Army | PROGRAMMING | 800 | [
"implementation"
] | A. Army | 2 | 256 | The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<=1. Reaching a certain rank *i* having not reached all the previous *i*<=-<=1 ranks is... | The first input line contains an integer *n* (2<=≤<=*n*<=≤<=100). The second line contains *n*<=-<=1 integers *d**i* (1<=≤<=*d**i*<=≤<=100). The third input line contains two integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=*n*). The numbers on the lines are space-separated. | Print the single number which is the number of years that Vasya needs to rise from rank *a* to rank *b*. | [
"3\n5 6\n1 2\n",
"3\n5 6\n1 3\n"
] | [
"5\n",
"11\n"
] | none | 0 | [
{
"input": "3\n5 6\n1 2",
"output": "5"
},
{
"input": "3\n5 6\n1 3",
"output": "11"
},
{
"input": "2\n55\n1 2",
"output": "55"
},
{
"input": "3\n85 78\n1 3",
"output": "163"
},
{
"input": "4\n63 4 49\n2 3",
"output": "4"
},
{
"input": "5\n93 83 42 56\n... | 1,689,068,468 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
int[] d = new int[100];
for (int i = 1; i < n; i++) {
d[i] = scanner.nextInt();
}
int a =... | Title: Army
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<... | ```python
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
int[] d = new int[100];
for (int i = 1; i < n; i++) {
d[i] = scanner.nextInt();
}
... | -1 |
779 | C | Dishonest Sellers | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"sortings"
] | null | null | Igor found out discounts in a shop and decided to buy *n* items. Discounts at the store will last for a week and Igor knows about each item that its price now is *a**i*, and after a week of discounts its price will be *b**i*.
Not all of sellers are honest, so now some products could be more expensive than after a week... | In the first line there are two positive integer numbers *n* and *k* (1<=≤<=*n*<=≤<=2·105, 0<=≤<=*k*<=≤<=*n*) — total number of items to buy and minimal number of items Igor wants to by right now.
The second line contains sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104) — prices of items during d... | Print the minimal amount of money Igor will spend to buy all *n* items. Remember, he should buy at least *k* items right now. | [
"3 1\n5 4 6\n3 1 5\n",
"5 3\n3 4 7 10 3\n4 5 5 12 5\n"
] | [
"10\n",
"25\n"
] | In the first example Igor should buy item 3 paying 6. But items 1 and 2 he should buy after a week. He will pay 3 and 1 for them. So in total he will pay 6 + 3 + 1 = 10.
In the second example Igor should buy right now items 1, 2, 4 and 5, paying for them 3, 4, 10 and 3, respectively. Item 3 he should buy after a week ... | 1,000 | [
{
"input": "3 1\n5 4 6\n3 1 5",
"output": "10"
},
{
"input": "5 3\n3 4 7 10 3\n4 5 5 12 5",
"output": "25"
},
{
"input": "1 0\n9\n8",
"output": "8"
},
{
"input": "2 0\n4 10\n1 2",
"output": "3"
},
{
"input": "4 2\n19 5 17 13\n3 18 8 10",
"output": "29"
},
... | 1,674,122,877 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 8 | 311 | 14,745,600 | tmp = input().split()
n, k = int(tmp[0]), int(tmp[1])
sale_price = list(map(int, input().split()))
avg_price = list(map(int, input().split()))
diff_price = []
for i in range(n):
diff_price.append([sale_price[i] - avg_price[i], sale_price[i], avg_price[i]])
diff_price = sorted(diff_price, key=lambda x: x[0])
final... | Title: Dishonest Sellers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Igor found out discounts in a shop and decided to buy *n* items. Discounts at the store will last for a week and Igor knows about each item that its price now is *a**i*, and after a week of discounts its price will be... | ```python
tmp = input().split()
n, k = int(tmp[0]), int(tmp[1])
sale_price = list(map(int, input().split()))
avg_price = list(map(int, input().split()))
diff_price = []
for i in range(n):
diff_price.append([sale_price[i] - avg_price[i], sale_price[i], avg_price[i]])
diff_price = sorted(diff_price, key=lambda x: x... | -1 | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,604,055,397 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | dic = {"Sheldon":1, "Leonard":1, "Penny":1, "Rajesh":1, "Howard":1 }
count = 0
check = 0
n = int(input())
while check == 0:
for i in dic:
count += dic[i]
dic[i] *= 2
if count > n:
print(i)
check = 1
break
| Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
dic = {"Sheldon":1, "Leonard":1, "Penny":1, "Rajesh":1, "Howard":1 }
count = 0
check = 0
n = int(input())
while check == 0:
for i in dic:
count += dic[i]
dic[i] *= 2
if count > n:
print(i)
check = 1
break
``` | 0 |
812 | B | Sagheer, the Hausmeister | PROGRAMMING | 1,600 | [
"bitmasks",
"brute force",
"dp"
] | null | null | Some people leave the lights at their workplaces on when they leave that is a waste of resources. As a hausmeister of DHBW, Sagheer waits till all students and professors leave the university building, then goes and turns all the lights off.
The building consists of *n* floors with stairs at the left and the right sid... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=15 and 1<=≤<=*m*<=≤<=100) — the number of floors and the number of rooms in each floor, respectively.
The next *n* lines contains the building description. Each line contains a binary string of length *m*<=+<=2 representing a floor (the left stairs, then ... | Print a single integer — the minimum total time needed to turn off all the lights. | [
"2 2\n0010\n0100\n",
"3 4\n001000\n000010\n000010\n",
"4 3\n01110\n01110\n01110\n01110\n"
] | [
"5\n",
"12\n",
"18\n"
] | In the first example, Sagheer will go to room 1 in the ground floor, then he will go to room 2 in the second floor using the left or right stairs.
In the second example, he will go to the fourth room in the ground floor, use right stairs, go to the fourth room in the second floor, use right stairs again, then go to th... | 1,000 | [
{
"input": "2 2\n0010\n0100",
"output": "5"
},
{
"input": "3 4\n001000\n000010\n000010",
"output": "12"
},
{
"input": "4 3\n01110\n01110\n01110\n01110",
"output": "18"
},
{
"input": "3 2\n0000\n0100\n0100",
"output": "4"
},
{
"input": "1 89\n0000000000000000000000... | 1,497,278,449 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 6 | 62 | 307,200 | n,m=map(int,input().split())
p=1
l=[[1,0]]
l1=[]
r=0
M=[input() for i in range(n)]
for i in range(n) :
if M[i].count('1')==0 :
r=r+1
else :
break
for i in range(n-1,r,-1) :
for j in range(len(l)) :
k=l[j][1]
if l[j][0]==1 :
l1.append([2,k+m+2])
... | Title: Sagheer, the Hausmeister
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some people leave the lights at their workplaces on when they leave that is a waste of resources. As a hausmeister of DHBW, Sagheer waits till all students and professors leave the university building, then goe... | ```python
n,m=map(int,input().split())
p=1
l=[[1,0]]
l1=[]
r=0
M=[input() for i in range(n)]
for i in range(n) :
if M[i].count('1')==0 :
r=r+1
else :
break
for i in range(n-1,r,-1) :
for j in range(len(l)) :
k=l[j][1]
if l[j][0]==1 :
l1.append([2,k+... | -1 | |
34 | C | Page Numbers | PROGRAMMING | 1,300 | [
"expression parsing",
"implementation",
"sortings",
"strings"
] | C. Page Numbers | 2 | 256 | «Bersoft» company is working on a new version of its most popular text editor — Bord 2010. Bord, like many other text editors, should be able to print out multipage documents. A user keys a sequence of the document page numbers that he wants to print out (separates them with a comma, without spaces).
Your task is to w... | The only line contains the sequence, keyed by the user. The sequence contains at least one and at most 100 positive integer numbers. It's guaranteed, that this sequence consists of positive integer numbers, not exceeding 1000, separated with a comma, doesn't contain any other characters, apart from digits and commas, c... | Output the sequence in the required format. | [
"1,2,3,1,1,2,6,6,2\n",
"3,2,1\n",
"30,20,10\n"
] | [
"1-3,6\n",
"1-3\n",
"10,20,30\n"
] | none | 1,500 | [
{
"input": "1,2,3,1,1,2,6,6,2",
"output": "1-3,6"
},
{
"input": "3,2,1",
"output": "1-3"
},
{
"input": "30,20,10",
"output": "10,20,30"
},
{
"input": "826,747,849,687,437",
"output": "437,687,747,826,849"
},
{
"input": "999,999,993,969,999",
"output": "969,993... | 1,625,704,619 | 2,147,483,647 | PyPy 3 | OK | TESTS | 26 | 218 | 0 | nums = [int(x) for x in input().split(",")]
counter = [0] * 1002
for num in nums:
counter[num] += 1
start = -1
end = -1
result = []
for idx, count in enumerate(counter):
if count > 0:
if start == -1:
start = idx
else:
end = idx
else:
if end == -1... | Title: Page Numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
«Bersoft» company is working on a new version of its most popular text editor — Bord 2010. Bord, like many other text editors, should be able to print out multipage documents. A user keys a sequence of the document page number... | ```python
nums = [int(x) for x in input().split(",")]
counter = [0] * 1002
for num in nums:
counter[num] += 1
start = -1
end = -1
result = []
for idx, count in enumerate(counter):
if count > 0:
if start == -1:
start = idx
else:
end = idx
else:
if... | 3.9455 |
515 | C | Drazil and Factorial | PROGRAMMING | 1,400 | [
"greedy",
"math",
"sortings"
] | null | null | Drazil is playing a math game with Varda.
Let's define for positive integer *x* as a product of factorials of its digits. For example, .
First, they choose a decimal number *a* consisting of *n* digits that contains at least one digit larger than 1. This number may possibly start with leading zeroes. Then they shoul... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=15) — the number of digits in *a*.
The second line contains *n* digits of *a*. There is at least one digit in *a* that is larger than 1. Number *a* may possibly contain leading zeroes. | Output a maximum possible integer satisfying the conditions above. There should be no zeroes and ones in this number decimal representation. | [
"4\n1234\n",
"3\n555\n"
] | [
"33222\n",
"555\n"
] | In the first case, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/f5a4207f23215fddce977ab5ea9e9d2e7578fb52.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "4\n1234",
"output": "33222"
},
{
"input": "3\n555",
"output": "555"
},
{
"input": "15\n012345781234578",
"output": "7777553333222222222222"
},
{
"input": "1\n8",
"output": "7222"
},
{
"input": "10\n1413472614",
"output": "75333332222222"
},
{
... | 1,664,621,312 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 108 | 0 | n=int(input())
s=input()
l=[]
for i in s:
if i=='0' or i=='1':
continue
elif i=='2':
l.append('2')
elif i=='3':
l.append('3')
elif i=='4':
l.append('3')
l.append('2')
l.append('2')
elif i=='5':
l.append('5')
elif i=='6':
... | Title: Drazil and Factorial
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Drazil is playing a math game with Varda.
Let's define for positive integer *x* as a product of factorials of its digits. For example, .
First, they choose a decimal number *a* consisting of *n* digits that cont... | ```python
n=int(input())
s=input()
l=[]
for i in s:
if i=='0' or i=='1':
continue
elif i=='2':
l.append('2')
elif i=='3':
l.append('3')
elif i=='4':
l.append('3')
l.append('2')
l.append('2')
elif i=='5':
l.append('5')
elif i... | 3 | |
760 | A | Petr and a calendar | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to ... | The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). | Print single integer: the number of columns the table should have. | [
"1 7\n",
"1 1\n",
"11 6\n"
] | [
"6\n",
"5\n",
"5\n"
] | The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | 500 | [
{
"input": "1 7",
"output": "6"
},
{
"input": "1 1",
"output": "5"
},
{
"input": "11 6",
"output": "5"
},
{
"input": "2 7",
"output": "5"
},
{
"input": "2 1",
"output": "4"
},
{
"input": "8 6",
"output": "6"
},
{
"input": "1 1",
"output... | 1,696,004,527 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | def calender(m,d):
if m in (1,3,5,7,8,10,12):
n=31
n=n-d
x=1+(n//7)
elif m in (4,6,9,11):
n=30
x
n=n-d
x=1+(n//7)
else:
n=28-d
x=1+(n//7)
return x
| Title: Petr and a calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells... | ```python
def calender(m,d):
if m in (1,3,5,7,8,10,12):
n=31
n=n-d
x=1+(n//7)
elif m in (4,6,9,11):
n=30
x
n=n-d
x=1+(n//7)
else:
n=28-d
x=1+(n//7)
return x
``` | 0 | |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,561,649,648 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 109 | 0 | a = int(input())
print(a // 3 * 2 + (a % 3 + 2) // 3) | Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
a = int(input())
print(a // 3 * 2 + (a % 3 + 2) // 3)
``` | 3 | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,677,431,728 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 39 | 92 | 0 | s = input("")
s = s.split()
n = eval(s[0])
m = eval(s[1])
for i in range(n+1, 50):
t = True
for f in range(2, (i//2)+1):
if i%f == 0:
t = False
break
if t:
og = i
break
if m==og:
print("YES")
else:
print("NO")
... | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
s = input("")
s = s.split()
n = eval(s[0])
m = eval(s[1])
for i in range(n+1, 50):
t = True
for f in range(2, (i//2)+1):
if i%f == 0:
t = False
break
if t:
og = i
break
if m==og:
print("YES")
else:
pr... | -1 |
265 | A | Colorful Stones (Simplified Edition) | PROGRAMMING | 800 | [
"implementation"
] | null | null | There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th stone. If the character is "R", "G", or "B", the color of the corresponding stone is red, green, or blue, respectively.
Ini... | The input contains two lines. The first line contains the string *s* (1<=≤<=|*s*|<=≤<=50). The second line contains the string *t* (1<=≤<=|*t*|<=≤<=50). The characters of each string will be one of "R", "G", or "B". It is guaranteed that Liss don't move out of the sequence. | Print the final 1-based position of Liss in a single line. | [
"RGB\nRRR\n",
"RRRBGBRBBB\nBBBRR\n",
"BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB\n"
] | [
"2\n",
"3\n",
"15\n"
] | none | 500 | [
{
"input": "RGB\nRRR",
"output": "2"
},
{
"input": "RRRBGBRBBB\nBBBRR",
"output": "3"
},
{
"input": "BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB",
"output": "15"
},
{
"input": "G\nRRBBRBRRBR",
"output": "1"
},
... | 1,603,470,517 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 218 | 0 | stoneseq = [x for x in input()]
instructset = [x for x in input()]
currentcounter = 0
for i in range(len(instructset)):
if instructset[i] == stoneseq[currentcounter]:
currentcounter += 1
print(currentcounter + 1) | Title: Colorful Stones (Simplified Edition)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th st... | ```python
stoneseq = [x for x in input()]
instructset = [x for x in input()]
currentcounter = 0
for i in range(len(instructset)):
if instructset[i] == stoneseq[currentcounter]:
currentcounter += 1
print(currentcounter + 1)
``` | 3 | |
550 | A | Two Substrings | PROGRAMMING | 1,500 | [
"brute force",
"dp",
"greedy",
"implementation",
"strings"
] | null | null | You are given string *s*. Your task is to determine if the given string *s* contains two non-overlapping substrings "AB" and "BA" (the substrings can go in any order). | The only line of input contains a string *s* of length between 1 and 105 consisting of uppercase Latin letters. | Print "YES" (without the quotes), if string *s* contains two non-overlapping substrings "AB" and "BA", and "NO" otherwise. | [
"ABA\n",
"BACFAB\n",
"AXBYBXA\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | In the first sample test, despite the fact that there are substrings "AB" and "BA", their occurrences overlap, so the answer is "NO".
In the second sample test there are the following occurrences of the substrings: BACFAB.
In the third sample test there is no substring "AB" nor substring "BA". | 1,000 | [
{
"input": "ABA",
"output": "NO"
},
{
"input": "BACFAB",
"output": "YES"
},
{
"input": "AXBYBXA",
"output": "NO"
},
{
"input": "ABABAB",
"output": "YES"
},
{
"input": "BBBBBBBBBB",
"output": "NO"
},
{
"input": "ABBA",
"output": "YES"
},
{
"... | 1,675,269,684 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 614,400 | import sys, math, itertools, functools, collections
from collections import Counter
input = lambda: sys.stdin.readline().strip()
MIN = 10 ** 18
MAX = -10 ** 18
def int_j():
return int(input())
def int_m():
return map(int, input().split())
def list_m():
return list(map(int, input().... | Title: Two Substrings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given string *s*. Your task is to determine if the given string *s* contains two non-overlapping substrings "AB" and "BA" (the substrings can go in any order).
Input Specification:
The only line of input contain... | ```python
import sys, math, itertools, functools, collections
from collections import Counter
input = lambda: sys.stdin.readline().strip()
MIN = 10 ** 18
MAX = -10 ** 18
def int_j():
return int(input())
def int_m():
return map(int, input().split())
def list_m():
return list(map(int... | 0 | |
991 | C | Candies | PROGRAMMING | 1,500 | [
"binary search",
"implementation"
] | null | null | After passing a test, Vasya got himself a box of $n$ candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for himself.
This means the process of eating candies is the following: in the beginning Vasya cho... | The first line contains a single integer $n$ ($1 \leq n \leq 10^{18}$) — the initial amount of candies in the box. | Output a single integer — the minimal amount of $k$ that would allow Vasya to eat at least half of candies he got. | [
"68\n"
] | [
"3\n"
] | In the sample, the amount of candies, with $k=3$, would change in the following way (Vasya eats first):
$68 \to 65 \to 59 \to 56 \to 51 \to 48 \to 44 \to 41 \\ \to 37 \to 34 \to 31 \to 28 \to 26 \to 23 \to 21 \to 18 \to 17 \to 14 \\ \to 13 \to 10 \to 9 \to 6 \to 6 \to 3 \to 3 \to 0$.
In total, Vasya would eat $39$ ca... | 1,250 | [
{
"input": "68",
"output": "3"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "42",
"output": "1"
},
{
"input": "43",
"output": "2"
},
{
"input": "756",
"output": "29"
},
{
"input": "999999972",
"output"... | 1,659,907,880 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | n = int(input())
left, right = 1, n // 2 + 1
while (right - left) > 1:
mid = (right + left) // 2
su, j = 0, n
while j != 0:
if j < mid:
su += j
j = 0
else:
su += mid
j -= mid
if j != 10:
j -= int(j * 0.1... | Title: Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After passing a test, Vasya got himself a box of $n$ candies. He decided to eat an equal amount of candies each morning until there are no more candies. However, Petya also noticed the box and decided to get some candies for hi... | ```python
n = int(input())
left, right = 1, n // 2 + 1
while (right - left) > 1:
mid = (right + left) // 2
su, j = 0, n
while j != 0:
if j < mid:
su += j
j = 0
else:
su += mid
j -= mid
if j != 10:
j -= i... | 0 | |
632 | C | The Smallest String Concatenation | PROGRAMMING | 1,700 | [
"sortings",
"strings"
] | null | null | You're given a list of *n* strings *a*1,<=*a*2,<=...,<=*a**n*. You'd like to concatenate them together in some order such that the resulting string would be lexicographically smallest.
Given the list of strings, output the lexicographically smallest concatenation. | The first line contains integer *n* — the number of strings (1<=≤<=*n*<=≤<=5·104).
Each of the next *n* lines contains one string *a**i* (1<=≤<=|*a**i*|<=≤<=50) consisting of only lowercase English letters. The sum of string lengths will not exceed 5·104. | Print the only string *a* — the lexicographically smallest string concatenation. | [
"4\nabba\nabacaba\nbcd\ner\n",
"5\nx\nxx\nxxa\nxxaa\nxxaaa\n",
"3\nc\ncb\ncba\n"
] | [
"abacabaabbabcder\n",
"xxaaaxxaaxxaxxx\n",
"cbacbc\n"
] | none | 0 | [
{
"input": "4\nabba\nabacaba\nbcd\ner",
"output": "abacabaabbabcder"
},
{
"input": "5\nx\nxx\nxxa\nxxaa\nxxaaa",
"output": "xxaaaxxaaxxaxxx"
},
{
"input": "3\nc\ncb\ncba",
"output": "cbacbc"
},
{
"input": "10\naba\nabaaca\naba\nacaaaabbac\nabaacac\nb\ncabbcccaab\nbaacbb\nbcab... | 1,632,049,136 | 2,147,483,647 | PyPy 3 | OK | TESTS | 16 | 296 | 29,388,800 | # Rishabh Rao (https://github.com/rishabhrao)
import sys
from functools import cmp_to_key
MOD = 1000000007
def inp(): return sys.stdin.readline().strip()
def ii(): return int(inp())
def iis(): return [int(i) for i in inp().split()]
n = ii()
s = [inp() for _ in range(n)]
s.sort(key=cmp_to_key(lambda a, b:... | Title: The Smallest String Concatenation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You're given a list of *n* strings *a*1,<=*a*2,<=...,<=*a**n*. You'd like to concatenate them together in some order such that the resulting string would be lexicographically smallest.
Given the list ... | ```python
# Rishabh Rao (https://github.com/rishabhrao)
import sys
from functools import cmp_to_key
MOD = 1000000007
def inp(): return sys.stdin.readline().strip()
def ii(): return int(inp())
def iis(): return [int(i) for i in inp().split()]
n = ii()
s = [inp() for _ in range(n)]
s.sort(key=cmp_to_key(la... | 3 | |
134 | A | Average Numbers | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | You are given a sequence of positive integers *a*1,<=*a*2,<=...,<=*a**n*. Find all such indices *i*, that the *i*-th element equals the arithmetic mean of all other elements (that is all elements except for this one). | The first line contains the integer *n* (2<=≤<=*n*<=≤<=2·105). The second line contains elements of the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). All the elements are positive integers. | Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to *n*.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print ... | [
"5\n1 2 3 4 5\n",
"4\n50 50 50 50\n"
] | [
"1\n3 ",
"4\n1 2 3 4 "
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "1\n3 "
},
{
"input": "4\n50 50 50 50",
"output": "4\n1 2 3 4 "
},
{
"input": "3\n2 3 1",
"output": "1\n1 "
},
{
"input": "2\n4 2",
"output": "0"
},
{
"input": "2\n1 1",
"output": "2\n1 2 "
},
{
"input": "10\n3 3 3 ... | 1,656,065,805 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 249 | 19,968,000 | import sys
input = sys.stdin.readline
n = int(input())
w = list(map(int, input().split()))
x = sum(w)
d = []
for i in range(n):
if (x - w[i])/(n-1) == w[i]:
d.append(i+1)
print(len(d))
print(' '.join(map(str, d))) | Title: Average Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence of positive integers *a*1,<=*a*2,<=...,<=*a**n*. Find all such indices *i*, that the *i*-th element equals the arithmetic mean of all other elements (that is all elements except for this one).
... | ```python
import sys
input = sys.stdin.readline
n = int(input())
w = list(map(int, input().split()))
x = sum(w)
d = []
for i in range(n):
if (x - w[i])/(n-1) == w[i]:
d.append(i+1)
print(len(d))
print(' '.join(map(str, d)))
``` | 3 | |
1,000 | B | Light It Up | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | Recently, you bought a brand new smart lamp with programming features. At first, you set up a schedule to the lamp. Every day it will turn power on at moment $0$ and turn power off at moment $M$. Moreover, the lamp allows you to set a program of switching its state (states are "lights on" and "lights off"). Unfortunate... | First line contains two space separated integers $n$ and $M$ ($1 \le n \le 10^5$, $2 \le M \le 10^9$) — the length of program $a$ and the moment when power turns off.
Second line contains $n$ space separated integers $a_1, a_2, \dots, a_n$ ($0 < a_1 < a_2 < \dots < a_n < M$) — initially installed progra... | Print the only integer — maximum possible total time when the lamp is lit. | [
"3 10\n4 6 7\n",
"2 12\n1 10\n",
"2 7\n3 4\n"
] | [
"8\n",
"9\n",
"6\n"
] | In the first example, one of possible optimal solutions is to insert value $x = 3$ before $a_1$, so program will be $[3, 4, 6, 7]$ and time of lamp being lit equals $(3 - 0) + (6 - 4) + (10 - 7) = 8$. Other possible solution is to insert $x = 5$ in appropriate place.
In the second example, there is only one optimal so... | 0 | [
{
"input": "3 10\n4 6 7",
"output": "8"
},
{
"input": "2 12\n1 10",
"output": "9"
},
{
"input": "2 7\n3 4",
"output": "6"
},
{
"input": "1 2\n1",
"output": "1"
},
{
"input": "5 10\n1 3 5 6 8",
"output": "6"
},
{
"input": "7 1000000000\n1 10001 10011 20... | 1,635,217,629 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 1,000 | 11,571,200 | n, m = map(int, input().split())
a = [0]+[int(i) for i in input().split()]+[m]
b = [a[i+1]-a[i] for i in range(len(a)-1)]
topen = [sum(b[2*i] for i in range(j//2+1)) for j in range(len(b))]
tclose = [sum(b[2*i-1] for i in range(j//2+1, (n+3)//2))
for j in range(len(b))]
r = topen[-1]
for i in range(len... | Title: Light It Up
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, you bought a brand new smart lamp with programming features. At first, you set up a schedule to the lamp. Every day it will turn power on at moment $0$ and turn power off at moment $M$. Moreover, the lamp allows y... | ```python
n, m = map(int, input().split())
a = [0]+[int(i) for i in input().split()]+[m]
b = [a[i+1]-a[i] for i in range(len(a)-1)]
topen = [sum(b[2*i] for i in range(j//2+1)) for j in range(len(b))]
tclose = [sum(b[2*i-1] for i in range(j//2+1, (n+3)//2))
for j in range(len(b))]
r = topen[-1]
for i in... | 0 |
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