contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
408 | A | Line to Cashier | PROGRAMMING | 900 | [
"implementation"
] | null | null | Little Vasya went to the supermarket to get some groceries. He walked about the supermarket for a long time and got a basket full of products. Now he needs to choose the cashier to pay for the products.
There are *n* cashiers at the exit from the supermarket. At the moment the queue for the *i*-th cashier already has ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of cashes in the shop. The second line contains *n* space-separated integers: *k*1,<=*k*2,<=...,<=*k**n* (1<=≤<=*k**i*<=≤<=100), where *k**i* is the number of people in the queue to the *i*-th cashier.
The *i*-th of the next *n* lines contains *k**i*... | Print a single integer — the minimum number of seconds Vasya needs to get to the cashier. | [
"1\n1\n1\n",
"4\n1 4 3 2\n100\n1 2 2 3\n1 9 1\n7 8\n"
] | [
"20\n",
"100\n"
] | In the second test sample, if Vasya goes to the first queue, he gets to the cashier in 100·5 + 15 = 515 seconds. But if he chooses the second queue, he will need 1·5 + 2·5 + 2·5 + 3·5 + 4·15 = 100 seconds. He will need 1·5 + 9·5 + 1·5 + 3·15 = 100 seconds for the third one and 7·5 + 8·5 + 2·15 = 105 seconds for the fou... | 500 | [
{
"input": "1\n1\n1",
"output": "20"
},
{
"input": "4\n1 4 3 2\n100\n1 2 2 3\n1 9 1\n7 8",
"output": "100"
},
{
"input": "4\n5 4 5 5\n3 1 3 1 2\n3 1 1 3\n1 1 1 2 2\n2 2 1 1 3",
"output": "100"
},
{
"input": "5\n5 3 6 6 4\n7 5 3 3 9\n6 8 2\n1 10 8 5 9 2\n9 7 8 5 9 10\n9 8 3 3"... | 1,492,533,495 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 62 | 5,529,600 | n = int(input())
ans = list(map(int, input().split()))
ans = [i * 15 for i in ans]
for i in range(n):
ans[i] += sum(list(map(int, input().split()))) * 5
print(min(ans)) | Title: Line to Cashier
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Vasya went to the supermarket to get some groceries. He walked about the supermarket for a long time and got a basket full of products. Now he needs to choose the cashier to pay for the products.
There are *n* c... | ```python
n = int(input())
ans = list(map(int, input().split()))
ans = [i * 15 for i in ans]
for i in range(n):
ans[i] += sum(list(map(int, input().split()))) * 5
print(min(ans))
``` | 3 | |
1,004 | A | Sonya and Hotels | PROGRAMMING | 900 | [
"implementation"
] | null | null | Sonya decided that having her own hotel business is the best way of earning money because she can profit and rest wherever she wants.
The country where Sonya lives is an endless line. There is a city in each integer coordinate on this line. She has $n$ hotels, where the $i$-th hotel is located in the city with coordin... | The first line contains two integers $n$ and $d$ ($1\leq n\leq 100$, $1\leq d\leq 10^9$) — the number of Sonya's hotels and the needed minimum distance from a new hotel to all others.
The second line contains $n$ different integers in strictly increasing order $x_1, x_2, \ldots, x_n$ ($-10^9\leq x_i\leq 10^9$) — coord... | Print the number of cities where Sonya can build a new hotel so that the minimum distance from this hotel to all others is equal to $d$. | [
"4 3\n-3 2 9 16\n",
"5 2\n4 8 11 18 19\n"
] | [
"6\n",
"5\n"
] | In the first example, there are $6$ possible cities where Sonya can build a hotel. These cities have coordinates $-6$, $5$, $6$, $12$, $13$, and $19$.
In the second example, there are $5$ possible cities where Sonya can build a hotel. These cities have coordinates $2$, $6$, $13$, $16$, and $21$. | 500 | [
{
"input": "4 3\n-3 2 9 16",
"output": "6"
},
{
"input": "5 2\n4 8 11 18 19",
"output": "5"
},
{
"input": "10 10\n-67 -59 -49 -38 -8 20 41 59 74 83",
"output": "8"
},
{
"input": "10 10\n0 20 48 58 81 95 111 137 147 159",
"output": "9"
},
{
"input": "100 1\n0 1 2 3... | 1,535,658,313 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 124 | 0 | R=lambda:map(int,input().split())
n,d=R()
h=2
a=R()
p=next(a)
for x in a:
h+=(x-p>=d*2)+(x-p>d*2);p=x
print(h) | Title: Sonya and Hotels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sonya decided that having her own hotel business is the best way of earning money because she can profit and rest wherever she wants.
The country where Sonya lives is an endless line. There is a city in each integer c... | ```python
R=lambda:map(int,input().split())
n,d=R()
h=2
a=R()
p=next(a)
for x in a:
h+=(x-p>=d*2)+(x-p>d*2);p=x
print(h)
``` | 3 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,691,948,533 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | n = int(input())
for i in range(n) :
string = input()
l = len(string) - 2
if l >= 10 :
print(f"{string[0]}{str(l)}{string[-1]}")
else :
print(string) | Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
n = int(input())
for i in range(n) :
string = input()
l = len(string) - 2
if l >= 10 :
print(f"{string[0]}{str(l)}{string[-1]}")
else :
print(string)
``` | 0 |
719 | A | Vitya in the Countryside | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Every summer Vitya comes to visit his grandmother in the countryside. This summer, he got a huge wart. Every grandma knows that one should treat warts when the moon goes down. Thus, Vitya has to catch the moment when the moon is down.
Moon cycle lasts 30 days. The size of the visible part of the moon (in Vitya's units... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=92) — the number of consecutive days Vitya was watching the size of the visible part of the moon.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=15) — Vitya's records.
It's guaranteed that the input data is consistent. | If Vitya can be sure that the size of visible part of the moon on day *n*<=+<=1 will be less than the size of the visible part on day *n*, then print "DOWN" at the only line of the output. If he might be sure that the size of the visible part will increase, then print "UP". If it's impossible to determine what exactly ... | [
"5\n3 4 5 6 7\n",
"7\n12 13 14 15 14 13 12\n",
"1\n8\n"
] | [
"UP\n",
"DOWN\n",
"-1\n"
] | In the first sample, the size of the moon on the next day will be equal to 8, thus the answer is "UP".
In the second sample, the size of the moon on the next day will be 11, thus the answer is "DOWN".
In the third sample, there is no way to determine whether the size of the moon on the next day will be 7 or 9, thus t... | 500 | [
{
"input": "5\n3 4 5 6 7",
"output": "UP"
},
{
"input": "7\n12 13 14 15 14 13 12",
"output": "DOWN"
},
{
"input": "1\n8",
"output": "-1"
},
{
"input": "44\n7 8 9 10 11 12 13 14 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 14 13 12 11 10",
"out... | 1,515,490,833 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 32 | 62 | 5,632,000 | n=int(input())
var=[int(x) for x in input().split()]
if len(var)<=1:
print('-1')
else:
if var[n-1]>var[n-2]:
if var[n-1]==15:
print('DOWN')
else:
print('UP')
elif var[n-1]<var[n-2]:
print('DOWN')
| Title: Vitya in the Countryside
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Every summer Vitya comes to visit his grandmother in the countryside. This summer, he got a huge wart. Every grandma knows that one should treat warts when the moon goes down. Thus, Vitya has to catch the momen... | ```python
n=int(input())
var=[int(x) for x in input().split()]
if len(var)<=1:
print('-1')
else:
if var[n-1]>var[n-2]:
if var[n-1]==15:
print('DOWN')
else:
print('UP')
elif var[n-1]<var[n-2]:
print('DOWN')
``` | 0 | |
678 | A | Johny Likes Numbers | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*. | The only line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=109). | Print the smallest integer *x*<=><=*n*, so it is divisible by the number *k*. | [
"5 3\n",
"25 13\n",
"26 13\n"
] | [
"6\n",
"26\n",
"39\n"
] | none | 0 | [
{
"input": "5 3",
"output": "6"
},
{
"input": "25 13",
"output": "26"
},
{
"input": "26 13",
"output": "39"
},
{
"input": "1 1",
"output": "2"
},
{
"input": "8 8",
"output": "16"
},
{
"input": "14 15",
"output": "15"
},
{
"input": "197 894"... | 1,698,428,143 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 500 | 0 | n,k = map(int,input().split())
x = n + 1
while (x > n):
if x % k ==0:
print(x)
break
else:
x = x + 1 | Title: Johny Likes Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*.
Input Specification:
The only line contains two integers *n* and *... | ```python
n,k = map(int,input().split())
x = n + 1
while (x > n):
if x % k ==0:
print(x)
break
else:
x = x + 1
``` | 0 | |
869 | A | The Artful Expedient | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Rock... Paper!
After Karen have found the deterministic winning (losing?) strategy for rock-paper-scissors, her brother, Koyomi, comes up with a new game as a substitute. The game works as follows.
A positive integer *n* is decided first. Both Koyomi and Karen independently choose *n* distinct positive integers, deno... | The first line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=2<=000) — the length of both sequences.
The second line contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=2·106) — the integers finally chosen by Koyomi.
The third line contains *n* space-separated integers *y*1,<=... | Output one line — the name of the winner, that is, "Koyomi" or "Karen" (without quotes). Please be aware of the capitalization. | [
"3\n1 2 3\n4 5 6\n",
"5\n2 4 6 8 10\n9 7 5 3 1\n"
] | [
"Karen\n",
"Karen\n"
] | In the first example, there are 6 pairs satisfying the constraint: (1, 1), (1, 2), (2, 1), (2, 3), (3, 2) and (3, 3). Thus, Karen wins since 6 is an even number.
In the second example, there are 16 such pairs, and Karen wins again. | 500 | [
{
"input": "3\n1 2 3\n4 5 6",
"output": "Karen"
},
{
"input": "5\n2 4 6 8 10\n9 7 5 3 1",
"output": "Karen"
},
{
"input": "1\n1\n2000000",
"output": "Karen"
},
{
"input": "2\n97153 2000000\n1999998 254",
"output": "Karen"
},
{
"input": "15\n31 30 29 28 27 26 25 24... | 1,517,991,711 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 5,939,200 | n=int(input())
x=0
while x==0 :
ch1=input()
l1=ch1.split()
if len(l1)==n:
x=1
x=0
while x==0 :
ch2=input()
l2=ch2.split()
if len(l2)==n:
x=1
y=0
l1= [int(i) for i in l1]
l2= [int(i) for i in l2]
for i in l1 :
for j in l2 :
if( i^j in l1 ) or ( i^... | Title: The Artful Expedient
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Rock... Paper!
After Karen have found the deterministic winning (losing?) strategy for rock-paper-scissors, her brother, Koyomi, comes up with a new game as a substitute. The game works as follows.
A positive int... | ```python
n=int(input())
x=0
while x==0 :
ch1=input()
l1=ch1.split()
if len(l1)==n:
x=1
x=0
while x==0 :
ch2=input()
l2=ch2.split()
if len(l2)==n:
x=1
y=0
l1= [int(i) for i in l1]
l2= [int(i) for i in l2]
for i in l1 :
for j in l2 :
if( i^j in l1... | 0 | |
275 | A | Lights Out | PROGRAMMING | 900 | [
"implementation"
] | null | null | Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be sw... | The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed. | Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0". | [
"1 0 0\n0 0 0\n0 0 1\n",
"1 0 1\n8 8 8\n2 0 3\n"
] | [
"001\n010\n100\n",
"010\n011\n100\n"
] | none | 500 | [
{
"input": "1 0 0\n0 0 0\n0 0 1",
"output": "001\n010\n100"
},
{
"input": "1 0 1\n8 8 8\n2 0 3",
"output": "010\n011\n100"
},
{
"input": "13 85 77\n25 50 45\n65 79 9",
"output": "000\n010\n000"
},
{
"input": "96 95 5\n8 84 74\n67 31 61",
"output": "011\n011\n101"
},
{... | 1,585,245,625 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 140 | 0 | a = [0]*9
ls = [int(i) for i in input().split(' ')]+[int(i) for i in input().split(' ')]+[int(i) for i in input().split(' ')]
# print(ls)
c = 0
for i in range(3):
for j in range(3):
a[c] += ls[c]
if(i-1 >= 0):
a[c] += ls[c-3]
if(i+1 < 3):
a[c] += ls[c+3]
if(j-1 >= 0):
... | Title: Lights Out
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the ... | ```python
a = [0]*9
ls = [int(i) for i in input().split(' ')]+[int(i) for i in input().split(' ')]+[int(i) for i in input().split(' ')]
# print(ls)
c = 0
for i in range(3):
for j in range(3):
a[c] += ls[c]
if(i-1 >= 0):
a[c] += ls[c-3]
if(i+1 < 3):
a[c] += ls[c+3]
if(j-1 >= ... | 3 | |
337 | A | Puzzles | PROGRAMMING | 900 | [
"greedy"
] | null | null | The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, as wikipedia states, is a tiling puzzle that requires the assembly of numerous small, often od... | The first line contains space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=*m*<=≤<=50). The second line contains *m* space-separated integers *f*1,<=*f*2,<=...,<=*f**m* (4<=≤<=*f**i*<=≤<=1000) — the quantities of pieces in the puzzles sold in the shop. | Print a single integer — the least possible difference the teacher can obtain. | [
"4 6\n10 12 10 7 5 22\n"
] | [
"5\n"
] | Sample 1. The class has 4 students. The shop sells 6 puzzles. If Ms. Manana buys the first four puzzles consisting of 10, 12, 10 and 7 pieces correspondingly, then the difference between the sizes of the largest and the smallest puzzle will be equal to 5. It is impossible to obtain a smaller difference. Note that the t... | 500 | [
{
"input": "4 6\n10 12 10 7 5 22",
"output": "5"
},
{
"input": "2 2\n4 4",
"output": "0"
},
{
"input": "2 10\n4 5 6 7 8 9 10 11 12 12",
"output": "0"
},
{
"input": "4 5\n818 136 713 59 946",
"output": "759"
},
{
"input": "3 20\n446 852 783 313 549 965 40 88 86 617... | 1,672,867,386 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | a=input().split()
n=int(a[0])
m=int(a[1])
puzzles=[int (i) for i in input().split()]
puzzles.sort()
smallest=puzzles[n-1]-puzzles[0]
for i in range(m-n):
if puzzles[i+n-1]-puzzles[i]<smallest:
smallest=puzzles[i+n-1]-puzzles[i]
print(smallest)
| Title: Puzzles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, a... | ```python
a=input().split()
n=int(a[0])
m=int(a[1])
puzzles=[int (i) for i in input().split()]
puzzles.sort()
smallest=puzzles[n-1]-puzzles[0]
for i in range(m-n):
if puzzles[i+n-1]-puzzles[i]<smallest:
smallest=puzzles[i+n-1]-puzzles[i]
print(smallest)
``` | 0 | |
227 | B | Effective Approach | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn compared with the number that you need to find. Once you find the array element that is equal to the requ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of elements in the array. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the elements of array.
The third line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. The ... | Print two integers, showing how many comparisons Vasya's approach needs and how many comparisons Petya's approach needs. Separate the numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | [
"2\n1 2\n1\n1\n",
"2\n2 1\n1\n1\n",
"3\n3 1 2\n3\n1 2 3\n"
] | [
"1 2\n",
"2 1\n",
"6 6\n"
] | In the first sample Vasya's approach will make one comparison (it starts with the 1-st element and immediately finds the required number), and Petya's approach makes two comparisons (first he compares with the 2-nd array element, doesn't find the search item and compares with the 1-st element).
In the second sample, o... | 1,000 | [
{
"input": "2\n1 2\n1\n1",
"output": "1 2"
},
{
"input": "2\n2 1\n1\n1",
"output": "2 1"
},
{
"input": "3\n3 1 2\n3\n1 2 3",
"output": "6 6"
},
{
"input": "9\n2 9 3 1 6 4 7 8 5\n9\n5 1 5 2 8 4 4 4 5",
"output": "58 32"
},
{
"input": "10\n3 10 9 2 7 6 5 8 4 1\n1\n4... | 1,679,898,039 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 6,553,600 | def result(n,lis,m,lis2):
count1=0
count2=0
lis3=lis[::-1]
for i in range(m):
a=lis2[i]
count1+=lis.index(a)+1
count2+=lis3.index(a)+1
print("{} {}".format(count1,count2))
n=int(input())
lis=list(map(int,input().split()))
m=int(input())
lis2=list(map(int,input().split()))
result(n,lis,m,lis2... | Title: Effective Approach
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn c... | ```python
def result(n,lis,m,lis2):
count1=0
count2=0
lis3=lis[::-1]
for i in range(m):
a=lis2[i]
count1+=lis.index(a)+1
count2+=lis3.index(a)+1
print("{} {}".format(count1,count2))
n=int(input())
lis=list(map(int,input().split()))
m=int(input())
lis2=list(map(int,input().split()))
result(n,... | 0 | |
515 | A | Drazil and Date | PROGRAMMING | 1,000 | [
"math"
] | null | null | Someday, Drazil wanted to go on date with Varda. Drazil and Varda live on Cartesian plane. Drazil's home is located in point (0,<=0) and Varda's home is located in point (*a*,<=*b*). In each step, he can move in a unit distance in horizontal or vertical direction. In other words, from position (*x*,<=*y*) he can go to ... | You are given three integers *a*, *b*, and *s* (<=-<=109<=≤<=*a*,<=*b*<=≤<=109, 1<=≤<=*s*<=≤<=2·109) in a single line. | If you think Drazil made a mistake and it is impossible to take exactly *s* steps and get from his home to Varda's home, print "No" (without quotes).
Otherwise, print "Yes". | [
"5 5 11\n",
"10 15 25\n",
"0 5 1\n",
"0 0 2\n"
] | [
"No\n",
"Yes\n",
"No\n",
"Yes\n"
] | In fourth sample case one possible route is: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/0d30660ddf6eb6c64ffd071055a4e8ddd016cde5.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 500 | [
{
"input": "5 5 11",
"output": "No"
},
{
"input": "10 15 25",
"output": "Yes"
},
{
"input": "0 5 1",
"output": "No"
},
{
"input": "0 0 2",
"output": "Yes"
},
{
"input": "999999999 999999999 2000000000",
"output": "Yes"
},
{
"input": "-606037695 9983201... | 1,646,169,516 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 62 | 0 | a,b,s=map(int,input().split());print('YNEOS'[(a+b+s)%2 or abs(a)+abs(b)>s::2]) | Title: Drazil and Date
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Someday, Drazil wanted to go on date with Varda. Drazil and Varda live on Cartesian plane. Drazil's home is located in point (0,<=0) and Varda's home is located in point (*a*,<=*b*). In each step, he can move in a unit ... | ```python
a,b,s=map(int,input().split());print('YNEOS'[(a+b+s)%2 or abs(a)+abs(b)>s::2])
``` | 3 | |
916 | A | Jamie and Alarm Snooze | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Jamie loves sleeping. One day, he decides that he needs to wake up at exactly *hh*:<=*mm*. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will then press the snooze button every *x* minutes until *hh*:<=*mm* is reached, and only then he will wake up. He ... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=60).
The second line contains two two-digit integers, *hh* and *mm* (00<=≤<=*hh*<=≤<=23,<=00<=≤<=*mm*<=≤<=59). | Print the minimum number of times he needs to press the button. | [
"3\n11 23\n",
"5\n01 07\n"
] | [
"2\n",
"0\n"
] | In the first sample, Jamie needs to wake up at 11:23. So, he can set his alarm at 11:17. He would press the snooze button when the alarm rings at 11:17 and at 11:20.
In the second sample, Jamie can set his alarm at exactly at 01:07 which is lucky. | 500 | [
{
"input": "3\n11 23",
"output": "2"
},
{
"input": "5\n01 07",
"output": "0"
},
{
"input": "34\n09 24",
"output": "3"
},
{
"input": "2\n14 37",
"output": "0"
},
{
"input": "14\n19 54",
"output": "9"
},
{
"input": "42\n15 44",
"output": "12"
},
... | 1,611,908,711 | 2,147,483,647 | PyPy 3 | OK | TESTS | 254 | 109 | 0 | t=int(input())
h,m=map(int,input().split())
if('7' in str(h) or '7' in str(m)):
print("0")
else:
c=0
while(1):
if('7' in str(h) or '7' in str(m)):
print(c)
break
elif(t>=m):
x=t-m
if(x==0):
m=0
... | Title: Jamie and Alarm Snooze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jamie loves sleeping. One day, he decides that he needs to wake up at exactly *hh*:<=*mm*. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will the... | ```python
t=int(input())
h,m=map(int,input().split())
if('7' in str(h) or '7' in str(m)):
print("0")
else:
c=0
while(1):
if('7' in str(h) or '7' in str(m)):
print(c)
break
elif(t>=m):
x=t-m
if(x==0):
m=0
... | 3 | |
652 | A | Gabriel and Caterpillar | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | The 9-th grade student Gabriel noticed a caterpillar on a tree when walking around in a forest after the classes. The caterpillar was on the height *h*1 cm from the ground. On the height *h*2 cm (*h*2<=><=*h*1) on the same tree hung an apple and the caterpillar was crawling to the apple.
Gabriel is interested when ... | The first line contains two integers *h*1,<=*h*2 (1<=≤<=*h*1<=<<=*h*2<=≤<=105) — the heights of the position of the caterpillar and the apple in centimeters.
The second line contains two integers *a*,<=*b* (1<=≤<=*a*,<=*b*<=≤<=105) — the distance the caterpillar goes up by day and slips down by night, in centimeter... | Print the only integer *k* — the number of days Gabriel should wait to return to the forest and see the caterpillar getting the apple.
If the caterpillar can't get the apple print the only integer <=-<=1. | [
"10 30\n2 1\n",
"10 13\n1 1\n",
"10 19\n1 2\n",
"1 50\n5 4\n"
] | [
"1\n",
"0\n",
"-1\n",
"1\n"
] | In the first example at 10 pm of the first day the caterpillar gets the height 26. At 10 am of the next day it slips down to the height 14. And finally at 6 pm of the same day the caterpillar gets the apple.
Note that in the last example the caterpillar was slipping down under the ground and getting the apple on the n... | 0 | [
{
"input": "10 30\n2 1",
"output": "1"
},
{
"input": "10 13\n1 1",
"output": "0"
},
{
"input": "10 19\n1 2",
"output": "-1"
},
{
"input": "1 50\n5 4",
"output": "1"
},
{
"input": "1 1000\n2 1",
"output": "82"
},
{
"input": "999 1000\n1 1",
"output"... | 1,458,975,035 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 62 | 4,608,000 | s,e = map(int, input().split())
a,b = map(int, input().split())
cat = s + 8*a
if a <= b:
if cat < e:
print(-1)
elif cat >= e + a:
print(0)
else:
print(1)
exit(0)
ans = 1
while cat < e:
ans += 1
cat += 12 * (a - b)
print(ans - (cat > e)) | Title: Gabriel and Caterpillar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The 9-th grade student Gabriel noticed a caterpillar on a tree when walking around in a forest after the classes. The caterpillar was on the height *h*1 cm from the ground. On the height *h*2 cm (*h*2<=><=*h*... | ```python
s,e = map(int, input().split())
a,b = map(int, input().split())
cat = s + 8*a
if a <= b:
if cat < e:
print(-1)
elif cat >= e + a:
print(0)
else:
print(1)
exit(0)
ans = 1
while cat < e:
ans += 1
cat += 12 * (a - b)
print(ans - (cat > e))
``` | 0 | |
158 | A | Next Round | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | "Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of *n* participants took part in the contest (*n*<=≥<=*k*), and you already know their scores. Calculate... | The first line of the input contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50) separated by a single space.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100), where *a**i* is the score earned by the participant who got the *i*-th place. The given sequence... | Output the number of participants who advance to the next round. | [
"8 5\n10 9 8 7 7 7 5 5\n",
"4 2\n0 0 0 0\n"
] | [
"6\n",
"0\n"
] | In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.
In the second example nobody got a positive score. | 500 | [
{
"input": "8 5\n10 9 8 7 7 7 5 5",
"output": "6"
},
{
"input": "4 2\n0 0 0 0",
"output": "0"
},
{
"input": "5 1\n1 1 1 1 1",
"output": "5"
},
{
"input": "5 5\n1 1 1 1 1",
"output": "5"
},
{
"input": "1 1\n10",
"output": "1"
},
{
"input": "17 14\n16 15... | 1,699,113,759 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | n,k = map(int,input().split())
s = [int(i) for i in input().split()]
# print(s.count(min(s)))
for i in range(s.count(min(s))):
s.remove(min(s))
print(len(s)) | Title: Next Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of *n* p... | ```python
n,k = map(int,input().split())
s = [int(i) for i in input().split()]
# print(s.count(min(s)))
for i in range(s.count(min(s))):
s.remove(min(s))
print(len(s))
``` | 0 | |
282 | A | Bit++ | PROGRAMMING | 800 | [
"implementation"
] | null | null | The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.
The language is that peculiar as it has exactly one variable, called *x*. Also, there are two operations:
- Operation ++ increases the value of variable *x* by 1. - Operation -- decreases the value of variable *x* by... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=150) — the number of statements in the programme.
Next *n* lines contain a statement each. Each statement contains exactly one operation (++ or --) and exactly one variable *x* (denoted as letter «X»). Thus, there are no empty statements. The operation and th... | Print a single integer — the final value of *x*. | [
"1\n++X\n",
"2\nX++\n--X\n"
] | [
"1\n",
"0\n"
] | none | 500 | [
{
"input": "1\n++X",
"output": "1"
},
{
"input": "2\nX++\n--X",
"output": "0"
},
{
"input": "3\n++X\n++X\n++X",
"output": "3"
},
{
"input": "2\n--X\n--X",
"output": "-2"
},
{
"input": "5\n++X\n--X\n++X\n--X\n--X",
"output": "-1"
},
{
"input": "28\nX--\... | 1,699,292,969 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 46 | 0 | n = int(input())
x = 0
for _ in range(n):
s = input()
for i in range(3):
if s[i] == '+':
x += 1
break
elif s[i] == '-':
x -= 1
break
print(x)
| Title: Bit++
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.
The language is that peculiar as it has exactly one variable, called *x*. Also, there are two operations:
- Operation ++ incre... | ```python
n = int(input())
x = 0
for _ in range(n):
s = input()
for i in range(3):
if s[i] == '+':
x += 1
break
elif s[i] == '-':
x -= 1
break
print(x)
``` | 3 | |
914 | A | Perfect Squares | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Given an array *a*1,<=*a*2,<=...,<=*a**n* of *n* integers, find the largest number in the array that is not a perfect square.
A number *x* is said to be a perfect square if there exists an integer *y* such that *x*<==<=*y*2. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=106<=≤<=*a**i*<=≤<=106) — the elements of the array.
It is guaranteed that at least one element of the array is not a perfect square. | Print the largest number in the array which is not a perfect square. It is guaranteed that an answer always exists. | [
"2\n4 2\n",
"8\n1 2 4 8 16 32 64 576\n"
] | [
"2\n",
"32\n"
] | In the first sample case, 4 is a perfect square, so the largest number in the array that is not a perfect square is 2. | 500 | [
{
"input": "2\n4 2",
"output": "2"
},
{
"input": "8\n1 2 4 8 16 32 64 576",
"output": "32"
},
{
"input": "3\n-1 -4 -9",
"output": "-1"
},
{
"input": "5\n918375 169764 598796 76602 538757",
"output": "918375"
},
{
"input": "5\n804610 765625 2916 381050 93025",
... | 1,660,587,512 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 2 | 77 | 2,867,200 | import math
n = int(input())
L = list(map(int, input().split()))
L.sort(reverse = True)
for i in L:
root = math.sqrt(i)
if int(root + 0.5) ** 2 != i:
print(i)
break | Title: Perfect Squares
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Given an array *a*1,<=*a*2,<=...,<=*a**n* of *n* integers, find the largest number in the array that is not a perfect square.
A number *x* is said to be a perfect square if there exists an integer *y* such that *x*<==<... | ```python
import math
n = int(input())
L = list(map(int, input().split()))
L.sort(reverse = True)
for i in L:
root = math.sqrt(i)
if int(root + 0.5) ** 2 != i:
print(i)
break
``` | -1 | |
919 | C | Seat Arrangements | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | Suppose that you are in a campus and have to go for classes day by day. As you may see, when you hurry to a classroom, you surprisingly find that many seats there are already occupied. Today you and your friends went for class, and found out that some of the seats were occupied.
The classroom contains $n$ rows of seat... | The first line contains three positive integers $n,m,k$ ($1 \leq n, m, k \leq 2\,000$), where $n,m$ represent the sizes of the classroom and $k$ is the number of consecutive seats you need to find.
Each of the next $n$ lines contains $m$ characters '.' or '*'. They form a matrix representing the classroom, '.' denotes... | A single number, denoting the number of ways to find $k$ empty seats in the same row or column. | [
"2 3 2\n**.\n...\n",
"1 2 2\n..\n",
"3 3 4\n.*.\n*.*\n.*.\n"
] | [
"3\n",
"1\n",
"0\n"
] | In the first sample, there are three ways to arrange those seats. You can take the following seats for your arrangement.
- $(1,3)$, $(2,3)$ - $(2,2)$, $(2,3)$ - $(2,1)$, $(2,2)$ | 1,000 | [
{
"input": "1 2 2\n..",
"output": "1"
},
{
"input": "3 3 4\n.*.\n*.*\n.*.",
"output": "0"
},
{
"input": "1 1 1\n.",
"output": "1"
},
{
"input": "1 1 1\n*",
"output": "0"
},
{
"input": "2 2 2\n.*\n*.",
"output": "0"
},
{
"input": "1 1 1000\n.",
"out... | 1,688,073,459 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 10,240,000 | import collections
import math
def main():
# t = int(input())
# for _ in range(t):
#n = int(input())
matrix = []
n,m,k = list(map(int,input().split()))
for _ in range(n):
matrix.append(input())
#s = input()
#words = input().split()
#a = list(map(int,input().sp... | Title: Seat Arrangements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Suppose that you are in a campus and have to go for classes day by day. As you may see, when you hurry to a classroom, you surprisingly find that many seats there are already occupied. Today you and your friends went ... | ```python
import collections
import math
def main():
# t = int(input())
# for _ in range(t):
#n = int(input())
matrix = []
n,m,k = list(map(int,input().split()))
for _ in range(n):
matrix.append(input())
#s = input()
#words = input().split()
#a = list(map(int,... | 0 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,690,484,707 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n=int(input())
for i in range(n):
word=input()
if len(word)>10:
new=word[0]
slic=word[1:len(word)-1:1]
new+=str(len(slic))
new+=word[-1]
print(new) | Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
n=int(input())
for i in range(n):
word=input()
if len(word)>10:
new=word[0]
slic=word[1:len(word)-1:1]
new+=str(len(slic))
new+=word[-1]
print(new)
``` | 0 |
14 | A | Letter | PROGRAMMING | 800 | [
"implementation"
] | A. Letter | 1 | 64 | A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brother, who lives in Flatland. Now Bob has to send his picture by post, but because of the w... | The first line of the input data contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50), *n* — amount of lines, and *m* — amount of columns on Bob's sheet. The following *n* lines contain *m* characters each. Character «.» stands for a non-shaded square on the sheet, and «*» — for a shaded square. It is guaranteed that ... | Output the required rectangle of the minimum cost. Study the output data in the sample tests to understand the output format better. | [
"6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..\n",
"3 3\n***\n*.*\n***\n"
] | [
"***\n*..\n***\n*..\n***\n",
"***\n*.*\n***\n"
] | none | 0 | [
{
"input": "6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..",
"output": "***\n*..\n***\n*..\n***"
},
{
"input": "3 3\n***\n*.*\n***",
"output": "***\n*.*\n***"
},
{
"input": "1 1\n*",
"output": "*"
},
{
"input": "2 1\n*\n*",
"output": "*\n*"
},
{
"input"... | 1,602,294,859 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 216 | 0 | line,size = map(int, input().split())
with_stars= []
for i in range(line):
string=input()
if '*' in string:
with_stars.append(string[string.index('*'):string.index('*')+3])
else:
continue
for i in with_stars:
print(i) | Title: Letter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brothe... | ```python
line,size = map(int, input().split())
with_stars= []
for i in range(line):
string=input()
if '*' in string:
with_stars.append(string[string.index('*'):string.index('*')+3])
else:
continue
for i in with_stars:
print(i)
``` | 0 |
595 | A | Vitaly and Night | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vitaly sees a building of *n* floors and 2·*m* windows on each floor. On each floor there are *m* flats num... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of floors in the house and the number of flats on each floor respectively.
Next *n* lines describe the floors from top to bottom and contain 2·*m* characters each. If the *i*-th window of the given floor has lights on,... | Print a single integer — the number of flats that have lights on in at least one window, that is, the flats where, according to Vitaly, people aren't sleeping. | [
"2 2\n0 0 0 1\n1 0 1 1\n",
"1 3\n1 1 0 1 0 0\n"
] | [
"3\n",
"2\n"
] | In the first test case the house has two floors, two flats on each floor. That is, in total there are 4 flats. The light isn't on only on the second floor in the left flat. That is, in both rooms of the flat the light is off.
In the second test case the house has one floor and the first floor has three flats. The ligh... | 500 | [
{
"input": "2 2\n0 0 0 1\n1 0 1 1",
"output": "3"
},
{
"input": "1 3\n1 1 0 1 0 0",
"output": "2"
},
{
"input": "3 3\n1 1 1 1 1 1\n1 1 0 1 1 0\n1 0 0 0 1 1",
"output": "8"
},
{
"input": "1 5\n1 0 1 1 1 0 1 1 1 1",
"output": "5"
},
{
"input": "1 100\n1 1 1 1 1 1 1 ... | 1,447,000,547 | 347 | Python 3 | OK | TESTS | 36 | 62 | 102,400 | n, m = map(int, input().split())
c = 0
for i in range(n):
appts = list(map(int, input().split()))
for j in range(m):
x = appts[2*j]
y = appts[2*j + 1]
c += (1 if (x > 0 or y > 0) else 0)
print(c)
| Title: Vitaly and Night
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vital... | ```python
n, m = map(int, input().split())
c = 0
for i in range(n):
appts = list(map(int, input().split()))
for j in range(m):
x = appts[2*j]
y = appts[2*j + 1]
c += (1 if (x > 0 or y > 0) else 0)
print(c)
``` | 3 | |
265 | A | Colorful Stones (Simplified Edition) | PROGRAMMING | 800 | [
"implementation"
] | null | null | There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th stone. If the character is "R", "G", or "B", the color of the corresponding stone is red, green, or blue, respectively.
Ini... | The input contains two lines. The first line contains the string *s* (1<=≤<=|*s*|<=≤<=50). The second line contains the string *t* (1<=≤<=|*t*|<=≤<=50). The characters of each string will be one of "R", "G", or "B". It is guaranteed that Liss don't move out of the sequence. | Print the final 1-based position of Liss in a single line. | [
"RGB\nRRR\n",
"RRRBGBRBBB\nBBBRR\n",
"BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB\n"
] | [
"2\n",
"3\n",
"15\n"
] | none | 500 | [
{
"input": "RGB\nRRR",
"output": "2"
},
{
"input": "RRRBGBRBBB\nBBBRR",
"output": "3"
},
{
"input": "BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB",
"output": "15"
},
{
"input": "G\nRRBBRBRRBR",
"output": "1"
},
... | 1,652,120,810 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 92 | 0 | s=input()
t=input()
lp=0
for i in range(len(t)):
if t[i]==s[lp]:
lp+=1
print(lp+ 1) | Title: Colorful Stones (Simplified Edition)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th st... | ```python
s=input()
t=input()
lp=0
for i in range(len(t)):
if t[i]==s[lp]:
lp+=1
print(lp+ 1)
``` | 3 | |
152 | A | Marks | PROGRAMMING | 900 | [
"implementation"
] | null | null | Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student got a mark from 1 to 9 (inclusive) for each subject.
Let's consider a student the best at ... | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of students and the number of subjects, correspondingly. Next *n* lines each containing *m* characters describe the gradebook. Each character in the gradebook is a number from 1 to 9. Note that the marks in a rows are not sepa... | Print the single number — the number of successful students in the given group. | [
"3 3\n223\n232\n112\n",
"3 5\n91728\n11828\n11111\n"
] | [
"2\n",
"3\n"
] | In the first sample test the student number 1 is the best at subjects 1 and 3, student 2 is the best at subjects 1 and 2, but student 3 isn't the best at any subject.
In the second sample test each student is the best at at least one subject. | 500 | [
{
"input": "3 3\n223\n232\n112",
"output": "2"
},
{
"input": "3 5\n91728\n11828\n11111",
"output": "3"
},
{
"input": "2 2\n48\n27",
"output": "1"
},
{
"input": "2 1\n4\n6",
"output": "1"
},
{
"input": "1 2\n57",
"output": "1"
},
{
"input": "1 1\n5",
... | 1,696,062,244 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 312 | 0 | def solve():
n, m = map(int, input().split())
mat = [input() for _ in range(n)]
result = 0
for i in range(n):
best = False
for j in range(m):
t = True
for k in range(n):
if int(mat[k][j]) > int(mat[i][j]):
... | Title: Marks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student ... | ```python
def solve():
n, m = map(int, input().split())
mat = [input() for _ in range(n)]
result = 0
for i in range(n):
best = False
for j in range(m):
t = True
for k in range(n):
if int(mat[k][j]) > int(mat[i... | 3 | |
570 | B | Simple Game | PROGRAMMING | 1,300 | [
"constructive algorithms",
"games",
"greedy",
"implementation",
"math"
] | null | null | One day Misha and Andrew were playing a very simple game. First, each player chooses an integer in the range from 1 to *n*. Let's assume that Misha chose number *m*, and Andrew chose number *a*.
Then, by using a random generator they choose a random integer *c* in the range between 1 and *n* (any integer from 1 to *n*... | The first line contains two integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=109) — the range of numbers in the game, and the number selected by Misha respectively. | Print a single number — such value *a*, that probability that Andrew wins is the highest. If there are multiple such values, print the minimum of them. | [
"3 1\n",
"4 3\n"
] | [
"2",
"2"
] | In the first sample test: Andrew wins if *c* is equal to 2 or 3. The probability that Andrew wins is 2 / 3. If Andrew chooses *a* = 3, the probability of winning will be 1 / 3. If *a* = 1, the probability of winning is 0.
In the second sample test: Andrew wins if *c* is equal to 1 and 2. The probability that Andrew wi... | 1,000 | [
{
"input": "3 1",
"output": "2"
},
{
"input": "4 3",
"output": "2"
},
{
"input": "5 5",
"output": "4"
},
{
"input": "10 5",
"output": "6"
},
{
"input": "20 13",
"output": "12"
},
{
"input": "51 1",
"output": "2"
},
{
"input": "100 50",
... | 1,499,782,969 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 16 | 62 | 5,529,600 | n, m = map(int,input().split())
ka = m - 1
ko = n - m
if ko > ka:
print(m+1)
elif ka > ko:
print(m - 1)
else:
print(m-1) | Title: Simple Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Misha and Andrew were playing a very simple game. First, each player chooses an integer in the range from 1 to *n*. Let's assume that Misha chose number *m*, and Andrew chose number *a*.
Then, by using a random gen... | ```python
n, m = map(int,input().split())
ka = m - 1
ko = n - m
if ko > ka:
print(m+1)
elif ka > ko:
print(m - 1)
else:
print(m-1)
``` | 0 | |
891 | A | Pride | PROGRAMMING | 1,500 | [
"brute force",
"dp",
"greedy",
"math",
"number theory"
] | null | null | You have an array *a* with length *n*, you can perform operations. Each operation is like this: choose two adjacent elements from *a*, say *x* and *y*, and replace one of them with *gcd*(*x*,<=*y*), where *gcd* denotes the [greatest common divisor](https://en.wikipedia.org/wiki/Greatest_common_divisor).
What is the mi... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=2000) — the number of elements in the array.
The second line contains *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the elements of the array. | Print -1, if it is impossible to turn all numbers to 1. Otherwise, print the minimum number of operations needed to make all numbers equal to 1. | [
"5\n2 2 3 4 6\n",
"4\n2 4 6 8\n",
"3\n2 6 9\n"
] | [
"5\n",
"-1\n",
"4\n"
] | In the first sample you can turn all numbers to 1 using the following 5 moves:
- [2, 2, 3, 4, 6]. - [2, 1, 3, 4, 6] - [2, 1, 3, 1, 6] - [2, 1, 1, 1, 6] - [1, 1, 1, 1, 6] - [1, 1, 1, 1, 1]
We can prove that in this case it is not possible to make all numbers one using less than 5 moves. | 500 | [
{
"input": "5\n2 2 3 4 6",
"output": "5"
},
{
"input": "4\n2 4 6 8",
"output": "-1"
},
{
"input": "3\n2 6 9",
"output": "4"
},
{
"input": "15\n10 10 10 10 10 10 21 21 21 21 21 21 21 21 21",
"output": "15"
},
{
"input": "12\n10 10 14 14 14 14 14 14 14 14 21 21",
... | 1,511,075,703 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 1,747 | 42,496,000 | from math import gcd
n = int(input())
arr = list(map(int, input().split()))
ones = arr.count(1)
if ones > 0:
print(n - ones)
else:
gcds = [[0] * n for i in range(n)]
for i in range(n):
gcds[i][i] = arr[i]
seglen = 10000
for i in range(n + 1):
for j in range(i + 1, n):
gcd... | Title: Pride
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have an array *a* with length *n*, you can perform operations. Each operation is like this: choose two adjacent elements from *a*, say *x* and *y*, and replace one of them with *gcd*(*x*,<=*y*), where *gcd* denotes the [great... | ```python
from math import gcd
n = int(input())
arr = list(map(int, input().split()))
ones = arr.count(1)
if ones > 0:
print(n - ones)
else:
gcds = [[0] * n for i in range(n)]
for i in range(n):
gcds[i][i] = arr[i]
seglen = 10000
for i in range(n + 1):
for j in range(i + 1, n):
... | 3 | |
194 | A | Exams | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | One day the Codeforces round author sat exams. He had *n* exams and he needed to get an integer from 2 to 5 for each exam. He will have to re-sit each failed exam, i.e. the exam that gets mark 2.
The author would need to spend too much time and effort to make the sum of his marks strictly more than *k*. That could ha... | The single input line contains space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=250) — the number of exams and the required sum of marks.
It is guaranteed that there exists a way to pass *n* exams in the way that makes the sum of marks equal exactly *k*. | Print the single number — the minimum number of exams that the author will get a 2 for, considering that the sum of marks for all exams must equal *k*. | [
"4 8\n",
"4 10\n",
"1 3\n"
] | [
"4\n",
"2\n",
"0\n"
] | In the first sample the author has to get a 2 for all his exams.
In the second sample he should get a 3 for two exams and a 2 for two more.
In the third sample he should get a 3 for one exam. | 500 | [
{
"input": "4 8",
"output": "4"
},
{
"input": "4 10",
"output": "2"
},
{
"input": "1 3",
"output": "0"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "50 234",
"output": "0"
},
{
"input": "50 100",
"... | 1,610,379,333 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 154 | 0 | n,k=map(int,input().split())
if 3*n<=k:
print("0")
else :
print(n-(k-2*n)) | Title: Exams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day the Codeforces round author sat exams. He had *n* exams and he needed to get an integer from 2 to 5 for each exam. He will have to re-sit each failed exam, i.e. the exam that gets mark 2.
The author would need to spend ... | ```python
n,k=map(int,input().split())
if 3*n<=k:
print("0")
else :
print(n-(k-2*n))
``` | 3 | |
281 | A | Word Capitalization | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged. | A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103. | Output the given word after capitalization. | [
"ApPLe\n",
"konjac\n"
] | [
"ApPLe\n",
"Konjac\n"
] | none | 500 | [
{
"input": "ApPLe",
"output": "ApPLe"
},
{
"input": "konjac",
"output": "Konjac"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "A"
},
{
"input": "z",
"output": "Z"
},
{
"input": "ABACABA",
"output": "ABACABA"
},
{
"input": "... | 1,697,732,618 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | name=input()
name=name[0].upper()+name[1:]
print(name)
| Title: Word Capitalization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input... | ```python
name=input()
name=name[0].upper()+name[1:]
print(name)
``` | 3 | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,696,099,678 | 2,147,483,647 | PyPy 3 | OK | TESTS | 51 | 156 | 4,198,400 | n = input()
lstn = list(n)
count = 0
sumnum = 0
while len(lstn) > 1:
for i in lstn:
sumnum += int(i)
count += 1
lstn = list(str(sumnum))
sumnum = 0
print(count)
| Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
n = input()
lstn = list(n)
count = 0
sumnum = 0
while len(lstn) > 1:
for i in lstn:
sumnum += int(i)
count += 1
lstn = list(str(sumnum))
sumnum = 0
print(count)
``` | 3.953445 |
455 | A | Boredom | PROGRAMMING | 1,500 | [
"dp"
] | null | null | Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a*... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). | Print a single integer — the maximum number of points that Alex can earn. | [
"2\n1 2\n",
"3\n1 2 3\n",
"9\n1 2 1 3 2 2 2 2 3\n"
] | [
"2\n",
"4\n",
"10\n"
] | Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "4"
},
{
"input": "9\n1 2 1 3 2 2 2 2 3",
"output": "10"
},
{
"input": "5\n3 3 4 5 4",
"output": "11"
},
{
"input": "5\n5 3 5 3 4",
"output": "16"
},
{
"input": "5\n4 2 3 2 5",
... | 1,700,022,903 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 46 | 0 | n = int(input())
seq = list(map(int, input().split()))
m = list(set(seq))
m.sort()
dic = dict()
for i in m:
dic[i] = seq.count(i)
dp = [0] * (len(m)+1)
dp[1] = m[0] * dic[m[0]]
for i in range(2, len(m)+1):
dp[i] = max(dp[i - 1], dp[i - 2] + dic[m[i-1]]*m[i-1])
print(max(dp)) | Title: Boredom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make ... | ```python
n = int(input())
seq = list(map(int, input().split()))
m = list(set(seq))
m.sort()
dic = dict()
for i in m:
dic[i] = seq.count(i)
dp = [0] * (len(m)+1)
dp[1] = m[0] * dic[m[0]]
for i in range(2, len(m)+1):
dp[i] = max(dp[i - 1], dp[i - 2] + dic[m[i-1]]*m[i-1])
print(max(dp))
``` | 0 | |
37 | A | Towers | PROGRAMMING | 1,000 | [
"sortings"
] | A. Towers | 2 | 256 | Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct the minimal number of towers from the bars. Help Vasya to use the bars in the best way ... | The first line contains an integer *N* (1<=≤<=*N*<=≤<=1000) — the number of bars at Vasya’s disposal. The second line contains *N* space-separated integers *l**i* — the lengths of the bars. All the lengths are natural numbers not exceeding 1000. | In one line output two numbers — the height of the largest tower and their total number. Remember that Vasya should use all the bars. | [
"3\n1 2 3\n",
"4\n6 5 6 7\n"
] | [
"1 3\n",
"2 3\n"
] | none | 500 | [
{
"input": "3\n1 2 3",
"output": "1 3"
},
{
"input": "4\n6 5 6 7",
"output": "2 3"
},
{
"input": "4\n3 2 1 1",
"output": "2 3"
},
{
"input": "4\n1 2 3 3",
"output": "2 3"
},
{
"input": "3\n20 22 36",
"output": "1 3"
},
{
"input": "25\n47 30 94 41 45 20... | 1,461,868,830 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 124 | 5,222,400 | '''
Created on Apr 29, 2016
Gmail: [email protected]
@author: Md. Rezwanul Haque
'''
n = int(input())
l = [int(i)for i in input().split()]
#l = list(map(int,input().split()))
_max = 0
for i in set(l):
#print(l.count(i))
_max = max(_max,l.count(i))
num = len(set(l))
print(_max,num)
| Title: Towers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct... | ```python
'''
Created on Apr 29, 2016
Gmail: [email protected]
@author: Md. Rezwanul Haque
'''
n = int(input())
l = [int(i)for i in input().split()]
#l = list(map(int,input().split()))
_max = 0
for i in set(l):
#print(l.count(i))
_max = max(_max,l.count(i))
num = len(set(l))
print(_max,num)
``` | 3.959273 |
65 | C | Harry Potter and the Golden Snitch | PROGRAMMING | 2,100 | [
"binary search",
"geometry"
] | C. Harry Potter and the Golden Snitch | 2 | 256 | Brothers Fred and George Weasley once got into the sporting goods store and opened a box of Quidditch balls. After long and painful experiments they found out that the Golden Snitch is not enchanted at all. It is simply a programmed device. It always moves along the same trajectory, which is a polyline with vertices at... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=10000). The following *n*<=+<=1 lines contain the coordinates *x**i*, *y**i*, *z**i*, separated by single spaces. The coordinates of any two consecutive points do not coincide. The next line contains the velocities *v**p* and *v**s*, the last line contains *P*... | If Harry Potter can catch the snitch while it is moving along the polyline (including the end (*x**n*,<=*y**n*,<=*z**n*)), print "YES" in the first line (without the quotes). Print in the second line *t*, which is the earliest moment of time, when Harry will be able to catch the snitch. On the third line print three nu... | [
"4\n0 0 0\n0 10 0\n10 10 0\n10 0 0\n0 0 0\n1 1\n5 5 25\n",
"4\n0 0 0\n0 10 0\n10 10 0\n10 0 0\n0 0 0\n1 1\n5 5 50\n",
"1\n1 2 3\n4 5 6\n20 10\n1 2 3\n"
] | [
"YES\n25.5000000000\n10.0000000000 4.5000000000 0.0000000000\n",
"NO\n",
"YES\n0.0000000000\n1.0000000000 2.0000000000 3.0000000000\n"
] | none | 1,500 | [
{
"input": "4\n0 0 0\n0 10 0\n10 10 0\n10 0 0\n0 0 0\n1 1\n5 5 25",
"output": "YES\n25.5000000000\n10.0000000000 4.5000000000 0.0000000000"
},
{
"input": "4\n0 0 0\n0 10 0\n10 10 0\n10 0 0\n0 0 0\n1 1\n5 5 50",
"output": "NO"
},
{
"input": "1\n1 2 3\n4 5 6\n20 10\n1 2 3",
"output": "... | 1,691,327,566 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 248 | 3,891,200 | import math, sys
eps = 1e-8
n = int(input())
al = [list(map(int, input().split())) for _ in range(n + 1)]
vp, vs = map(int, input().split())
px, py, pz = map(int, input().split())
al = [(x - px, y - py, z - pz) for x, y, z in al]
d3 = lambda x, y, z: x*x + y*y + z*z
t0 = 0
rt, pt = None, 0
ts = 0
... | Title: Harry Potter and the Golden Snitch
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Brothers Fred and George Weasley once got into the sporting goods store and opened a box of Quidditch balls. After long and painful experiments they found out that the Golden Snitch is not enchanted at al... | ```python
import math, sys
eps = 1e-8
n = int(input())
al = [list(map(int, input().split())) for _ in range(n + 1)]
vp, vs = map(int, input().split())
px, py, pz = map(int, input().split())
al = [(x - px, y - py, z - pz) for x, y, z in al]
d3 = lambda x, y, z: x*x + y*y + z*z
t0 = 0
rt, pt = None, 0
ts = ... | 3.930752 |
59 | C | Title | PROGRAMMING | 1,600 | [
"expression parsing"
] | C. Title | 2 | 256 | Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first *k* Latin letters and not conta... | The first line contains an integer *k* (1<=≤<=*k*<=≤<=26) which is the number of allowed alphabet letters. The second line contains *s* which is the given template. In *s* only the first *k* lowercase letters of Latin alphabet and question marks can be present, the length of *s* is from 1 to 100 characters inclusively. | If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first *k* letters of the Latin alphabet. At that, each of those *k* letters must be present at least once. If there are sever... | [
"3\na?c\n",
"2\na??a\n",
"2\n?b?a\n"
] | [
"IMPOSSIBLE\n",
"abba\n",
"abba\n"
] | none | 1,500 | [
{
"input": "3\na?c",
"output": "IMPOSSIBLE"
},
{
"input": "2\na??a",
"output": "abba"
},
{
"input": "2\n?b?a",
"output": "abba"
},
{
"input": "3\n????",
"output": "IMPOSSIBLE"
},
{
"input": "2\n????",
"output": "abba"
},
{
"input": "1\n?",
"output"... | 1,628,788,050 | 2,147,483,647 | PyPy 3 | OK | TESTS | 76 | 248 | 20,172,800 | def process(S, k):
n = len(S)
L = [x for x in S]
needed = set([i for i in range(k)])
question = []
for i in range(n):
if S[i] != '?' and S[n-1-i] != '?' and S[i] != S[n-1-i]:
return 'IMPOSSIBLE'
if i <= n-1-i and S[i] != '?':
L[n-1-i] = S[i]
... | Title: Title
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a... | ```python
def process(S, k):
n = len(S)
L = [x for x in S]
needed = set([i for i in range(k)])
question = []
for i in range(n):
if S[i] != '?' and S[n-1-i] != '?' and S[i] != S[n-1-i]:
return 'IMPOSSIBLE'
if i <= n-1-i and S[i] != '?':
L[n-1-i] = S[i]... | 3.900425 |
667 | B | Coat of Anticubism | PROGRAMMING | 1,100 | [
"constructive algorithms",
"geometry"
] | null | null | As some of you know, cubism is a trend in art, where the problem of constructing volumetrical shape on a plane with a combination of three-dimensional geometric shapes comes to the fore.
A famous sculptor Cicasso, whose self-portrait you can contemplate, hates cubism. He is more impressed by the idea to transmit two-... | The first line contains an integer *n* (3<=≤<=*n*<=≤<=105) — a number of rod-blanks.
The second line contains *n* integers *l**i* (1<=≤<=*l**i*<=≤<=109) — lengths of rods, which Cicasso already has. It is guaranteed that it is impossible to make a polygon with *n* vertices and nonzero area using the rods Cicasso alrea... | Print the only integer *z* — the minimum length of the rod, so that after adding it it can be possible to construct convex polygon with (*n*<=+<=1) vertices and nonzero area from all of the rods. | [
"3\n1 2 1\n",
"5\n20 4 3 2 1\n"
] | [
"1\n",
"11\n"
] | In the first example triangle with sides {1 + 1 = 2, 2, 1} can be formed from a set of lengths {1, 1, 1, 2}.
In the second example you can make a triangle with lengths {20, 11, 4 + 3 + 2 + 1 = 10}. | 1,000 | [
{
"input": "3\n1 2 1",
"output": "1"
},
{
"input": "5\n20 4 3 2 1",
"output": "11"
},
{
"input": "7\n77486105 317474713 89523018 332007362 7897847 949616701 54820086",
"output": "70407571"
},
{
"input": "14\n245638694 2941428 4673577 12468 991349408 44735727 14046308 60637707... | 1,626,889,395 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 109 | 10,240,000 | mas = list(map(int, input().split()))
t = mas[0]
mas = list(map(int, input().split()))
s = 0
for i in mas:
s += i
mas.sort()
print(2 * mas[-1] - s + 1) | Title: Coat of Anticubism
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As some of you know, cubism is a trend in art, where the problem of constructing volumetrical shape on a plane with a combination of three-dimensional geometric shapes comes to the fore.
A famous sculptor Cicasso, ... | ```python
mas = list(map(int, input().split()))
t = mas[0]
mas = list(map(int, input().split()))
s = 0
for i in mas:
s += i
mas.sort()
print(2 * mas[-1] - s + 1)
``` | 3 | |
950 | A | Left-handers, Right-handers and Ambidexters | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and ... | The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. | Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. | [
"1 4 2\n",
"5 5 5\n",
"0 2 0\n"
] | [
"6\n",
"14\n",
"0\n"
] | In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five l... | 500 | [
{
"input": "1 4 2",
"output": "6"
},
{
"input": "5 5 5",
"output": "14"
},
{
"input": "0 2 0",
"output": "0"
},
{
"input": "30 70 34",
"output": "128"
},
{
"input": "89 32 24",
"output": "112"
},
{
"input": "89 44 77",
"output": "210"
},
{
... | 1,521,776,842 | 2,147,483,647 | Python 3 | OK | TESTS | 79 | 78 | 7,065,600 | l, r, a = [int(i) for i in input().split()]
if (l > r):
l, r = r, l
while (a > 0 and (l < r or r == l)):
a -= 1
l += 1
if (l > r):
l, r = r, l
print(2 * min(l, r)) | Title: Left-handers, Right-handers and Ambidexters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.... | ```python
l, r, a = [int(i) for i in input().split()]
if (l > r):
l, r = r, l
while (a > 0 and (l < r or r == l)):
a -= 1
l += 1
if (l > r):
l, r = r, l
print(2 * min(l, r))
``` | 3 | |
272 | A | Dima and Friends | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single s... | In a single line print the answer to the problem. | [
"1\n1\n",
"1\n2\n",
"2\n3 5\n"
] | [
"3\n",
"2\n",
"3\n"
] | In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | 500 | [
{
"input": "1\n1",
"output": "3"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "1\n5",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "4"
},
{
"input": "... | 1,639,858,920 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 154 | 0 | def main() :
n = int(input())
l = [int(x) for x in input().split()]
n+=1
s = sum(l)
r = s%n
if r == 0 :
print(n)
else :
f = n%r
print(f+1)
main() | Title: Dima and Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the... | ```python
def main() :
n = int(input())
l = [int(x) for x in input().split()]
n+=1
s = sum(l)
r = s%n
if r == 0 :
print(n)
else :
f = n%r
print(f+1)
main()
``` | 0 | |
386 | A | Second-Price Auction | PROGRAMMING | 800 | [
"implementation"
] | null | null | In this problem we consider a special type of an auction, which is called the second-price auction. As in regular auction *n* bidders place a bid which is price a bidder ready to pay. The auction is closed, that is, each bidder secretly informs the organizer of the auction price he is willing to pay. After that, the au... | The first line of the input contains *n* (2<=≤<=*n*<=≤<=1000) — number of bidders. The second line contains *n* distinct integer numbers *p*1,<=*p*2,<=... *p**n*, separated by single spaces (1<=≤<=*p**i*<=≤<=10000), where *p**i* stands for the price offered by the *i*-th bidder. | The single output line should contain two integers: index of the winner and the price he will pay. Indices are 1-based. | [
"2\n5 7\n",
"3\n10 2 8\n",
"6\n3 8 2 9 4 14\n"
] | [
"2 5\n",
"1 8\n",
"6 9\n"
] | none | 500 | [
{
"input": "2\n5 7",
"output": "2 5"
},
{
"input": "3\n10 2 8",
"output": "1 8"
},
{
"input": "6\n3 8 2 9 4 14",
"output": "6 9"
},
{
"input": "4\n4707 7586 4221 5842",
"output": "2 5842"
},
{
"input": "5\n3304 4227 4869 6937 6002",
"output": "4 6002"
},
{... | 1,637,672,899 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 42 | 62 | 0 | input()
A = list(map(int, input().split()))
a, b, *_ = sorted(A, reverse=True)
print(A.index(a) + 1, b) | Title: Second-Price Auction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem we consider a special type of an auction, which is called the second-price auction. As in regular auction *n* bidders place a bid which is price a bidder ready to pay. The auction is closed, that is... | ```python
input()
A = list(map(int, input().split()))
a, b, *_ = sorted(A, reverse=True)
print(A.index(a) + 1, b)
``` | 3 | |
83 | A | Magical Array | PROGRAMMING | 1,300 | [
"math"
] | A. Magical Array | 2 | 256 | Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutel... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=105). The second line contains an array of original integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator). | [
"4\n2 1 1 4\n",
"5\n-2 -2 -2 0 1\n"
] | [
"5\n",
"8\n"
] | Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3]. | 500 | [
{
"input": "4\n2 1 1 4",
"output": "5"
},
{
"input": "5\n-2 -2 -2 0 1",
"output": "8"
},
{
"input": "1\n10",
"output": "1"
},
{
"input": "2\n5 6",
"output": "2"
},
{
"input": "5\n5 5 4 5 5",
"output": "7"
},
{
"input": "8\n1 2 0 0 0 0 3 3",
"output... | 1,632,198,043 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 248 | 15,155,200 | def magical_subarrays():
count = int(input())
numbers = list(map(int, input().split()))
same_num_count = 1
magical_subarray_count = 0
for index in range(1, count):
if numbers[index-1] == numbers[index]:
same_num_count += 1
else:
magical_subarray_count += same_num_count*(same_num_count+1)/2
... | Title: Magical Array
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a re... | ```python
def magical_subarrays():
count = int(input())
numbers = list(map(int, input().split()))
same_num_count = 1
magical_subarray_count = 0
for index in range(1, count):
if numbers[index-1] == numbers[index]:
same_num_count += 1
else:
magical_subarray_count += same_num_count*(same_num_coun... | 3.909771 |
612 | C | Replace To Make Regular Bracket Sequence | PROGRAMMING | 1,400 | [
"data structures",
"expression parsing",
"math"
] | null | null | You are given string *s* consists of opening and closing brackets of four kinds <>, {}, [], (). There are two types of brackets: opening and closing. You can replace any bracket by another of the same type. For example, you can replace < by the bracket {, but you can't replace it by ) or >.
The following d... | The only line contains a non empty string *s*, consisting of only opening and closing brackets of four kinds. The length of *s* does not exceed 106. | If it's impossible to get RBS from *s* print Impossible.
Otherwise print the least number of replaces needed to get RBS from *s*. | [
"[<}){}\n",
"{()}[]\n",
"]]\n"
] | [
"2",
"0",
"Impossible"
] | none | 0 | [
{
"input": "[<}){}",
"output": "2"
},
{
"input": "{()}[]",
"output": "0"
},
{
"input": "]]",
"output": "Impossible"
},
{
"input": ">",
"output": "Impossible"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{}",
"output": "0"
},
{
"input": ... | 1,451,057,797 | 2,197 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 40 | 1,000 | 3,174,400 | s = input()
op = ["{", "<", "[", "("]
cl = ["}", ">", "]", ")"]
need = []
Good = True
ret = 0
i = 0
while i < len(s) and Good:
if s[i] in op:
for j in range(4):
if s[i]==op[j]:
need.append(cl[j])
if s[i] in cl:
if len(need) == 0:
Good = False
... | Title: Replace To Make Regular Bracket Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given string *s* consists of opening and closing brackets of four kinds <>, {}, [], (). There are two types of brackets: opening and closing. You can replace any bracket by another... | ```python
s = input()
op = ["{", "<", "[", "("]
cl = ["}", ">", "]", ")"]
need = []
Good = True
ret = 0
i = 0
while i < len(s) and Good:
if s[i] in op:
for j in range(4):
if s[i]==op[j]:
need.append(cl[j])
if s[i] in cl:
if len(need) == 0:
Goo... | 0 | |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers ex... | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at... | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 ... | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,689,354,073 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | n = int(input())
x = 0
m = 0
for i in range(n):
a, b = map(int, input().split())
x -= a
x += b
if m < x:
m = x
print(m) | Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it ... | ```python
n = int(input())
x = 0
m = 0
for i in range(n):
a, b = map(int, input().split())
x -= a
x += b
if m < x:
m = x
print(m)
``` | 3 | |
676 | C | Vasya and String | PROGRAMMING | 1,500 | [
"binary search",
"dp",
"strings",
"two pointers"
] | null | null | High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequence) consisting of equal letters.
Vasya can change no more than *k* characters of the original strin... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100<=000,<=0<=≤<=*k*<=≤<=*n*) — the length of the string and the maximum number of characters to change.
The second line contains the string, consisting of letters 'a' and 'b' only. | Print the only integer — the maximum beauty of the string Vasya can achieve by changing no more than *k* characters. | [
"4 2\nabba\n",
"8 1\naabaabaa\n"
] | [
"4\n",
"5\n"
] | In the first sample, Vasya can obtain both strings "aaaa" and "bbbb".
In the second sample, the optimal answer is obtained with the string "aaaaabaa" or with the string "aabaaaaa". | 1,500 | [
{
"input": "4 2\nabba",
"output": "4"
},
{
"input": "8 1\naabaabaa",
"output": "5"
},
{
"input": "1 0\na",
"output": "1"
},
{
"input": "1 1\nb",
"output": "1"
},
{
"input": "1 0\nb",
"output": "1"
},
{
"input": "1 1\na",
"output": "1"
},
{
... | 1,643,525,963 | 2,147,483,647 | PyPy 3 | OK | TESTS | 117 | 108 | 3,072,000 | n, k = map(int, input().split())
st = input().strip()
sma = smb = maxSoFar = l = 0
kk = k
for r in range(n):
if st[r] == 'b':
if kk:kk -= 1
else:
while st[l] != 'b':
maxSoFar -= 1
l += 1
l += 1
maxSoFar -= 1
maxSoFa... | Title: Vasya and String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequ... | ```python
n, k = map(int, input().split())
st = input().strip()
sma = smb = maxSoFar = l = 0
kk = k
for r in range(n):
if st[r] == 'b':
if kk:kk -= 1
else:
while st[l] != 'b':
maxSoFar -= 1
l += 1
l += 1
maxSoFar -= 1
... | 3 | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,693,151,602 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 |
a = input('How much kilos the watermelon is')
a = int(a)
if a >= 4:
b = a % 2
if b == 0:
print('Yes')
else:
print('No')
else:
print("No")
| Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
a = input('How much kilos the watermelon is')
a = int(a)
if a >= 4:
b = a % 2
if b == 0:
print('Yes')
else:
print('No')
else:
print("No")
``` | 0 |
912 | B | New Year's Eve | PROGRAMMING | 1,300 | [
"bitmasks",
"constructive algorithms",
"number theory"
] | null | null | Since Grisha behaved well last year, at New Year's Eve he was visited by Ded Moroz who brought an enormous bag of gifts with him! The bag contains *n* sweet candies from the good ol' bakery, each labeled from 1 to *n* corresponding to its tastiness. No two candies have the same tastiness.
The choice of candies has a d... | The sole string contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=1018). | Output one number — the largest possible xor-sum. | [
"4 3\n",
"6 6\n"
] | [
"7\n",
"7\n"
] | In the first sample case, one optimal answer is 1, 2 and 4, giving the xor-sum of 7.
In the second sample case, one can, for example, take all six candies and obtain the xor-sum of 7. | 1,000 | [
{
"input": "4 3",
"output": "7"
},
{
"input": "6 6",
"output": "7"
},
{
"input": "2 2",
"output": "3"
},
{
"input": "1022 10",
"output": "1023"
},
{
"input": "415853337373441 52",
"output": "562949953421311"
},
{
"input": "75 12",
"output": "127"
... | 1,565,614,377 | 2,147,483,647 | PyPy 3 | OK | TESTS | 58 | 140 | 0 | n,k=map(int, input().split())
for i in range(64):
if 2**i > n: break
if k == 1:
print(n)
else:
print(2**i-1)
| Title: New Year's Eve
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Since Grisha behaved well last year, at New Year's Eve he was visited by Ded Moroz who brought an enormous bag of gifts with him! The bag contains *n* sweet candies from the good ol' bakery, each labeled from 1 to *n* co... | ```python
n,k=map(int, input().split())
for i in range(64):
if 2**i > n: break
if k == 1:
print(n)
else:
print(2**i-1)
``` | 3 | |
478 | B | Random Teams | PROGRAMMING | 1,300 | [
"combinatorics",
"constructive algorithms",
"greedy",
"math"
] | null | null | *n* participants of the competition were split into *m* teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.
Your task is to write a program that will find the minimum and the maximum number of pairs of friends that coul... | The only line of input contains two integers *n* and *m*, separated by a single space (1<=≤<=*m*<=≤<=*n*<=≤<=109) — the number of participants and the number of teams respectively. | The only line of the output should contain two integers *k**min* and *k**max* — the minimum possible number of pairs of friends and the maximum possible number of pairs of friends respectively. | [
"5 1\n",
"3 2\n",
"6 3\n"
] | [
"10 10\n",
"1 1\n",
"3 6\n"
] | In the first sample all the participants get into one team, so there will be exactly ten pairs of friends.
In the second sample at any possible arrangement one team will always have two participants and the other team will always have one participant. Thus, the number of pairs of friends will always be equal to one.
... | 1,000 | [
{
"input": "5 1",
"output": "10 10"
},
{
"input": "3 2",
"output": "1 1"
},
{
"input": "6 3",
"output": "3 6"
},
{
"input": "5 3",
"output": "2 3"
},
{
"input": "10 2",
"output": "20 36"
},
{
"input": "10 6",
"output": "4 10"
},
{
"input": ... | 1,671,969,481 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n, m = map(int, input().split())
kmin = ((n-m+1)*(n-m))//2
x = n//m
y = n - x*m
# y teams has x+1 and m-y has x
kmax = y*((x*(x+1))//2) + (m-y)*((x*(x-1))//2)
print(kmin, kmax) | Title: Random Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* participants of the competition were split into *m* teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.
Your task is ... | ```python
n, m = map(int, input().split())
kmin = ((n-m+1)*(n-m))//2
x = n//m
y = n - x*m
# y teams has x+1 and m-y has x
kmax = y*((x*(x+1))//2) + (m-y)*((x*(x-1))//2)
print(kmin, kmax)
``` | 0 | |
825 | D | Suitable Replacement | PROGRAMMING | 1,500 | [
"binary search",
"greedy",
"implementation"
] | null | null | You are given two strings *s* and *t* consisting of small Latin letters, string *s* can also contain '?' characters.
Suitability of string *s* is calculated by following metric:
Any two letters can be swapped positions, these operations can be performed arbitrary number of times over any pair of positions. Among all... | The first line contains string *s* (1<=≤<=|*s*|<=≤<=106).
The second line contains string *t* (1<=≤<=|*t*|<=≤<=106). | Print string *s* with '?' replaced with small Latin letters in such a way that suitability of that string is maximal.
If there are multiple strings with maximal suitability then print any of them. | [
"?aa?\nab\n",
"??b?\nza\n",
"abcd\nabacaba\n"
] | [
"baab\n",
"azbz\n",
"abcd\n"
] | In the first example string "baab" can be transformed to "abab" with swaps, this one has suitability of 2. That means that string "baab" also has suitability of 2.
In the second example maximal suitability you can achieve is 1 and there are several dozens of such strings, "azbz" is just one of them.
In the third exam... | 0 | [
{
"input": "?aa?\nab",
"output": "baab"
},
{
"input": "??b?\nza",
"output": "azbz"
},
{
"input": "abcd\nabacaba",
"output": "abcd"
},
{
"input": "mqwstphetbfrsyxuzdww\nrutseqtsbh",
"output": "mqwstphetbfrsyxuzdww"
},
{
"input": "????????????????????\nxwkxsxlrre",
... | 1,500,224,774 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 61 | 5,529,600 | s = input()
t = input()
Ds = {chr(97 + i) : 0 for i in range(26)}
Ds["?"] = 0
Dt = {chr(97 + i) : 0 for i in range(26)}
Dcnt = {chr(97 + i) : 0 for i in range(26)}
A = list(Dt)
for u in s:
Ds[u] += 1
for u in t:
Dt[u] += 1
cnt = 0
for u in A:
Dcnt[u] = Dt[u] - Ds[u]
cnt += Dcnt[u]
while cnt + len(t... | Title: Suitable Replacement
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two strings *s* and *t* consisting of small Latin letters, string *s* can also contain '?' characters.
Suitability of string *s* is calculated by following metric:
Any two letters can be swapped po... | ```python
s = input()
t = input()
Ds = {chr(97 + i) : 0 for i in range(26)}
Ds["?"] = 0
Dt = {chr(97 + i) : 0 for i in range(26)}
Dcnt = {chr(97 + i) : 0 for i in range(26)}
A = list(Dt)
for u in s:
Ds[u] += 1
for u in t:
Dt[u] += 1
cnt = 0
for u in A:
Dcnt[u] = Dt[u] - Ds[u]
cnt += Dcnt[u]
while c... | 0 | |
26 | A | Almost Prime | PROGRAMMING | 900 | [
"number theory"
] | A. Almost Prime | 2 | 256 | A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive. | Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000). | Output the amount of almost prime numbers between 1 and *n*, inclusive. | [
"10\n",
"21\n"
] | [
"2\n",
"8\n"
] | none | 500 | [
{
"input": "10",
"output": "2"
},
{
"input": "21",
"output": "8"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "8",
"output": "1"
},
... | 1,694,588,075 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 92 | 0 | n=int(input())
res=[0]*(n+1)
for i in range(2,n//2+1):
if res[i]==0:
for k in range(2*i,n+1,i):
res[k]+=1
print(res.count(2)) | Title: Almost Prime
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, in... | ```python
n=int(input())
res=[0]*(n+1)
for i in range(2,n//2+1):
if res[i]==0:
for k in range(2*i,n+1,i):
res[k]+=1
print(res.count(2))
``` | 3.977 |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,679,047,752 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n,x=map(int,input().split())
y=240-x
i=1
s=0
z=0
while s<=y and z<=n:
s+=(5*i)
print("s is ",s,y)
z+=1
i+=1
print(z-1) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
n,x=map(int,input().split())
y=240-x
i=1
s=0
z=0
while s<=y and z<=n:
s+=(5*i)
print("s is ",s,y)
z+=1
i+=1
print(z-1)
``` | 0 | |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make ... | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,695,643,728 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | import math
def elephant():
steps = [5,4,3,2,1]
dis = int(input())
found = False
totalS = 0
for step in steps:
if not found:
if dis >= step:
f = int(math.floor(dis / step))
F = f*step
totalS = totalS + f
... | Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2... | ```python
import math
def elephant():
steps = [5,4,3,2,1]
dis = int(input())
found = False
totalS = 0
for step in steps:
if not found:
if dis >= step:
f = int(math.floor(dis / step))
F = f*step
totalS = totalS + f
... | 3 | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,443,368,652 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 1,000 | 49,766,400 | '''
http://codeforces.com/problemset/problem/82/A
'''
import sys
'''
Step 1- Get the input
n
'''
n = int(sys.stdin.readline().rstrip())
'''
Step 2 - Create key variables
Create a list that has with the 5 people:
Sheldon
Leonard
Penny
Rajesh
Howard
'''
queue = ["Sheldon", "Leonard", "Penny... | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
'''
http://codeforces.com/problemset/problem/82/A
'''
import sys
'''
Step 1- Get the input
n
'''
n = int(sys.stdin.readline().rstrip())
'''
Step 2 - Create key variables
Create a list that has with the 5 people:
Sheldon
Leonard
Penny
Rajesh
Howard
'''
queue = ["Sheldon", "Leonar... | 0 |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,678,623,882 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 31 | 0 | w = int(input())
l = []
for i in range(w):
n = input()
l.append(n)
for i in l:
if len(i) > 10:
print(i[0] + str(len(i)-2)+ i[-1] )
else:
print(i)
| Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
w = int(input())
l = []
for i in range(w):
n = input()
l.append(n)
for i in l:
if len(i) > 10:
print(i[0] + str(len(i)-2)+ i[-1] )
else:
print(i)
``` | 3.9845 |
215 | B | Olympic Medal | PROGRAMMING | 1,300 | [
"greedy",
"math"
] | null | null | The World Programming Olympics Medal is a metal disk, consisting of two parts: the first part is a ring with outer radius of *r*1 cm, inner radius of *r*2 cm, (0<=<<=*r*2<=<<=*r*1) made of metal with density *p*1 g/cm3. The second part is an inner disk with radius *r*2 cm, it is made of metal with density *p*2 g/... | The first input line contains an integer *n* and a sequence of integers *x*1,<=*x*2,<=...,<=*x**n*. The second input line contains an integer *m* and a sequence of integers *y*1,<=*y*2,<=...,<=*y**m*. The third input line contains an integer *k* and a sequence of integers *z*1,<=*z*2,<=...,<=*z**k*. The last line conta... | Print a single real number — the sought value *r*2 with absolute or relative error of at most 10<=-<=6. It is guaranteed that the solution that meets the problem requirements exists. | [
"3 1 2 3\n1 2\n3 3 2 1\n1 2\n",
"4 2 3 6 4\n2 1 2\n3 10 6 8\n2 1\n"
] | [
"2.683281573000\n",
"2.267786838055\n"
] | In the first sample the jury should choose the following values: *r*<sub class="lower-index">1</sub> = 3, *p*<sub class="lower-index">1</sub> = 2, *p*<sub class="lower-index">2</sub> = 1. | 500 | [
{
"input": "3 1 2 3\n1 2\n3 3 2 1\n1 2",
"output": "2.683281573000"
},
{
"input": "4 2 3 6 4\n2 1 2\n3 10 6 8\n2 1",
"output": "2.267786838055"
},
{
"input": "1 5\n1 3\n1 7\n515 892",
"output": "3.263613058533"
},
{
"input": "2 3 2\n3 2 3 1\n2 2 1\n733 883",
"output": "2.... | 1,662,042,606 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 31 | 124 | 2,355,200 | RO = sorted(map(int, input().split()[1:]))[-1]
PO = sorted(map(int, input().split()[1:]))[-1]
PI = sorted(map(int, input().split()[1:]))[0]
A, B = map(int, input().split())
print(pow(pow(RO, 2) / (((A * PI) / (B * PO)) + 1), 0.5))
| Title: Olympic Medal
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The World Programming Olympics Medal is a metal disk, consisting of two parts: the first part is a ring with outer radius of *r*1 cm, inner radius of *r*2 cm, (0<=<<=*r*2<=<<=*r*1) made of metal with density *p*1 g/... | ```python
RO = sorted(map(int, input().split()[1:]))[-1]
PO = sorted(map(int, input().split()[1:]))[-1]
PI = sorted(map(int, input().split()[1:]))[0]
A, B = map(int, input().split())
print(pow(pow(RO, 2) / (((A * PI) / (B * PO)) + 1), 0.5))
``` | 3 | |
45 | A | Codecraft III | PROGRAMMING | 900 | [
"implementation"
] | A. Codecraft III | 2 | 256 | Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly *k* months. He looked at the calendar and learned that at the moment is the month number *s*. Vasya immediately got interested in what month Codecraft III will appear. Help him understa... | The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer *k* (0<=≤<=*k*<=≤<=100) — the number of months left till the appearance of Codecraft III. | Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December. | [
"November\n3\n",
"May\n24\n"
] | [
"February\n",
"May\n"
] | none | 0 | [
{
"input": "November\n3",
"output": "February"
},
{
"input": "May\n24",
"output": "May"
},
{
"input": "April\n0",
"output": "April"
},
{
"input": "September\n0",
"output": "September"
},
{
"input": "August\n0",
"output": "August"
},
{
"input": "June\n1... | 1,515,690,813 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 186 | 19,968,000 | dict = {'January':1, 'February':2, 'March':3, 'April':4, 'May':5, 'June':6, 'July':7, 'August':8,
'September':9, 'October':10, 'November':11, 'December':12}
a = input()
n = int(input())
n = n%12
n = n+dict[a]
if n>12:
n = n%12
for key,value in dict.items():
if value == n:
print(key) | Title: Codecraft III
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly *k* months. He looked at the calendar and learned that at the moment is the month number *... | ```python
dict = {'January':1, 'February':2, 'March':3, 'April':4, 'May':5, 'June':6, 'July':7, 'August':8,
'September':9, 'October':10, 'November':11, 'December':12}
a = input()
n = int(input())
n = n%12
n = n+dict[a]
if n>12:
n = n%12
for key,value in dict.items():
if value == n:
print... | 3.916307 |
0 | none | none | none | 0 | [
"none"
] | null | null | Dreamoon loves summing up something for no reason. One day he obtains two integers *a* and *b* occasionally. He wants to calculate the sum of all nice integers. Positive integer *x* is called nice if and , where *k* is some integer number in range [1,<=*a*].
By we denote the quotient of integer division of *x* and *... | The single line of the input contains two integers *a*, *b* (1<=≤<=*a*,<=*b*<=≤<=107). | Print a single integer representing the answer modulo 1<=000<=000<=007 (109<=+<=7). | [
"1 1\n",
"2 2\n"
] | [
"0\n",
"8\n"
] | For the first sample, there are no nice integers because <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/03b1dc6bae5180f8a2d8eb85789e8b393e585970.png" style="max-width: 100.0%;max-height: 100.0%;"/> is always zero.
For the second sample, the set of nice integers is {3, 5}. | 0 | [
{
"input": "1 1",
"output": "0"
},
{
"input": "2 2",
"output": "8"
},
{
"input": "4 1",
"output": "0"
},
{
"input": "4 2",
"output": "24"
},
{
"input": "4 3",
"output": "102"
},
{
"input": "4 4",
"output": "264"
},
{
"input": "3 4",
"ou... | 1,660,998,183 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 46 | 0 | a, b = map(lambda x: int(x), input().split(' '))
if b == 1:
print(0)
else:
sumNum = 0
n = 1
k = 0
while k <= a:
if n % b == 0:
n += 1
continue
k = (n // b) / (n % b)
if 1 <= k <= a:
sumNum += n
n += 1
print(sumNum... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dreamoon loves summing up something for no reason. One day he obtains two integers *a* and *b* occasionally. He wants to calculate the sum of all nice integers. Positive integer *x* is called nice if and , where *k* is some integ... | ```python
a, b = map(lambda x: int(x), input().split(' '))
if b == 1:
print(0)
else:
sumNum = 0
n = 1
k = 0
while k <= a:
if n % b == 0:
n += 1
continue
k = (n // b) / (n % b)
if 1 <= k <= a:
sumNum += n
n += 1
pr... | 0 | |
749 | A | Bachgold Problem | PROGRAMMING | 800 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer *k* is called prime if it is greater than 1 and has exactly two positive integer ... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000). | The first line of the output contains a single integer *k* — maximum possible number of primes in representation.
The second line should contain *k* primes with their sum equal to *n*. You can print them in any order. If there are several optimal solution, print any of them. | [
"5\n",
"6\n"
] | [
"2\n2 3\n",
"3\n2 2 2\n"
] | none | 500 | [
{
"input": "5",
"output": "2\n2 3"
},
{
"input": "6",
"output": "3\n2 2 2"
},
{
"input": "2",
"output": "1\n2"
},
{
"input": "3",
"output": "1\n3"
},
{
"input": "99999",
"output": "49999\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,648,320,391 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | x=int(input())
if x&1:
print(x//2,2,sep='\n',end=" ")
for i in range(x//2-1):
print(3,end=" ")
else:
for i in range(x//2):
print(2,end=" ")
| Title: Bachgold Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
... | ```python
x=int(input())
if x&1:
print(x//2,2,sep='\n',end=" ")
for i in range(x//2-1):
print(3,end=" ")
else:
for i in range(x//2):
print(2,end=" ")
``` | 0 | |
390 | A | Inna and Alarm Clock | PROGRAMMING | 0 | [
"implementation"
] | null | null | Inna loves sleeping very much, so she needs *n* alarm clocks in total to wake up. Let's suppose that Inna's room is a 100<=×<=100 square with the lower left corner at point (0,<=0) and with the upper right corner at point (100,<=100). Then the alarm clocks are points with integer coordinates in this square.
The mornin... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of the alarm clocks. The next *n* lines describe the clocks: the *i*-th line contains two integers *x**i*, *y**i* — the coordinates of the *i*-th alarm clock (0<=≤<=*x**i*,<=*y**i*<=≤<=100).
Note that a single point in the room can conta... | In a single line print a single integer — the minimum number of segments Inna will have to draw if she acts optimally. | [
"4\n0 0\n0 1\n0 2\n1 0\n",
"4\n0 0\n0 1\n1 0\n1 1\n",
"4\n1 1\n1 2\n2 3\n3 3\n"
] | [
"2\n",
"2\n",
"3\n"
] | In the first sample, Inna first chooses type "vertical segments", and then she makes segments with ends at : (0, 0), (0, 2); and, for example, (1, 0), (1, 1). If she paints horizontal segments, she will need at least 3 segments.
In the third sample it is important to note that Inna doesn't have the right to change the... | 500 | [
{
"input": "4\n0 0\n0 1\n0 2\n1 0",
"output": "2"
},
{
"input": "4\n0 0\n0 1\n1 0\n1 1",
"output": "2"
},
{
"input": "4\n1 1\n1 2\n2 3\n3 3",
"output": "3"
},
{
"input": "1\n0 0",
"output": "1"
},
{
"input": "42\n28 87\n26 16\n59 90\n47 61\n28 83\n36 30\n67 10\n6 ... | 1,665,762,141 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 0 | numOfAlarma = int(input())
coordList = []
for i in range(numOfAlarma):
coordList.append([eval(x) for x in input().split(' ')])
columns = []
rows = []
for i in coordList:
columns.append(i[0])
rows.append(i[1])
columnSpan = (max(columns) - min(columns)) + 1
rowSpan = (max(rows) - min(rows)) + 1
if columnSp... | Title: Inna and Alarm Clock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Inna loves sleeping very much, so she needs *n* alarm clocks in total to wake up. Let's suppose that Inna's room is a 100<=×<=100 square with the lower left corner at point (0,<=0) and with the upper right corner a... | ```python
numOfAlarma = int(input())
coordList = []
for i in range(numOfAlarma):
coordList.append([eval(x) for x in input().split(' ')])
columns = []
rows = []
for i in coordList:
columns.append(i[0])
rows.append(i[1])
columnSpan = (max(columns) - min(columns)) + 1
rowSpan = (max(rows) - min(rows)) + 1
i... | 0 | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,652,297,342 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 102 | 62 | 0 | arr1=[int(i) for i in list(input())]
arr2=[int(i) for i in list(input())]
ans=[str(arr1[i]^arr2[i]) for i in range(0,len(arr1))]
print(''.join(ans)) | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
arr1=[int(i) for i in list(input())]
arr2=[int(i) for i in list(input())]
ans=[str(arr1[i]^arr2[i]) for i in range(0,len(arr1))]
print(''.join(ans))
``` | 3.9845 |
869 | A | The Artful Expedient | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Rock... Paper!
After Karen have found the deterministic winning (losing?) strategy for rock-paper-scissors, her brother, Koyomi, comes up with a new game as a substitute. The game works as follows.
A positive integer *n* is decided first. Both Koyomi and Karen independently choose *n* distinct positive integers, deno... | The first line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=2<=000) — the length of both sequences.
The second line contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=2·106) — the integers finally chosen by Koyomi.
The third line contains *n* space-separated integers *y*1,<=... | Output one line — the name of the winner, that is, "Koyomi" or "Karen" (without quotes). Please be aware of the capitalization. | [
"3\n1 2 3\n4 5 6\n",
"5\n2 4 6 8 10\n9 7 5 3 1\n"
] | [
"Karen\n",
"Karen\n"
] | In the first example, there are 6 pairs satisfying the constraint: (1, 1), (1, 2), (2, 1), (2, 3), (3, 2) and (3, 3). Thus, Karen wins since 6 is an even number.
In the second example, there are 16 such pairs, and Karen wins again. | 500 | [
{
"input": "3\n1 2 3\n4 5 6",
"output": "Karen"
},
{
"input": "5\n2 4 6 8 10\n9 7 5 3 1",
"output": "Karen"
},
{
"input": "1\n1\n2000000",
"output": "Karen"
},
{
"input": "2\n97153 2000000\n1999998 254",
"output": "Karen"
},
{
"input": "15\n31 30 29 28 27 26 25 24... | 1,549,304,199 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 716,800 | n=int(input())
xi=list(map(int,input().split()))
yi=list(map(int,input().split()))
s=0
a=set(xi)
b=set(yi)
for i in range(n):
for j in range(n):
if(((xi[i]^yi[j])in b)or((xi[i]^yi[j])in a)):
s=s+1
if (s%2==0):
print("Karen")
else:
print("Koyomi") | Title: The Artful Expedient
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Rock... Paper!
After Karen have found the deterministic winning (losing?) strategy for rock-paper-scissors, her brother, Koyomi, comes up with a new game as a substitute. The game works as follows.
A positive int... | ```python
n=int(input())
xi=list(map(int,input().split()))
yi=list(map(int,input().split()))
s=0
a=set(xi)
b=set(yi)
for i in range(n):
for j in range(n):
if(((xi[i]^yi[j])in b)or((xi[i]^yi[j])in a)):
s=s+1
if (s%2==0):
print("Karen")
else:
print("Koyomi")
``` | 0 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,459,137,630 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 4,608,000 | s=raw_input()
upper=0
for i in s:
if i==i.upper():
upper+=1
if upper>len(s)//2:
print (s.upper())
else:
print (s.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s=raw_input()
upper=0
for i in s:
if i==i.upper():
upper+=1
if upper>len(s)//2:
print (s.upper())
else:
print (s.lower())
``` | -1 |
867 | A | Between the Offices | PROGRAMMING | 800 | [
"implementation"
] | null | null | As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't rem... | The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given... | Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower). | [
"4\nFSSF\n",
"2\nSF\n",
"10\nFFFFFFFFFF\n",
"10\nSSFFSFFSFF\n"
] | [
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you staye... | 500 | [
{
"input": "4\nFSSF",
"output": "NO"
},
{
"input": "2\nSF",
"output": "YES"
},
{
"input": "10\nFFFFFFFFFF",
"output": "NO"
},
{
"input": "10\nSSFFSFFSFF",
"output": "YES"
},
{
"input": "20\nSFSFFFFSSFFFFSSSSFSS",
"output": "NO"
},
{
"input": "20\nSSFFF... | 1,587,224,035 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin>>n;
string s;
cin>>s;
int i,c=0,d=0;
for(i=0;i<n-1;i++)
{
if(s[i]!=s[i+1])
{
if(s[i]=='S' && s[i+1]=='F')
c++;
else
d++;
}
}
if(c>d)
cout<<"YES";
else
cout<<"NO";
return 0;
}
| Title: Between the Offices
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Franci... | ```python
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin>>n;
string s;
cin>>s;
int i,c=0,d=0;
for(i=0;i<n-1;i++)
{
if(s[i]!=s[i+1])
{
if(s[i]=='S' && s[i+1]=='F')
c++;
else
d++;
}
}
if(c>d)
cout<<"YES";
else
cout<<"NO";
return 0;
}
``` | -1 | |
805 | A | Fake NP | PROGRAMMING | 1,000 | [
"greedy",
"math"
] | null | null | Tavak and Seyyed are good friends. Seyyed is very funny and he told Tavak to solve the following problem instead of longest-path.
You are given *l* and *r*. For all integers from *l* to *r*, inclusive, we wrote down all of their integer divisors except 1. Find the integer that we wrote down the maximum number of times... | The first line contains two integers *l* and *r* (2<=≤<=*l*<=≤<=*r*<=≤<=109). | Print single integer, the integer that appears maximum number of times in the divisors.
If there are multiple answers, print any of them. | [
"19 29\n",
"3 6\n"
] | [
"2\n",
"3\n"
] | Definition of a divisor: [https://www.mathsisfun.com/definitions/divisor-of-an-integer-.html](https://www.mathsisfun.com/definitions/divisor-of-an-integer-.html)
The first example: from 19 to 29 these numbers are divisible by 2: {20, 22, 24, 26, 28}.
The second example: from 3 to 6 these numbers are divisible by 3: {... | 500 | [
{
"input": "19 29",
"output": "2"
},
{
"input": "3 6",
"output": "2"
},
{
"input": "39 91",
"output": "2"
},
{
"input": "76 134",
"output": "2"
},
{
"input": "93 95",
"output": "2"
},
{
"input": "17 35",
"output": "2"
},
{
"input": "94 95",... | 1,591,985,258 | 2,147,483,647 | Python 3 | OK | TESTS | 93 | 155 | 0 | # -*- coding: utf-8 -*-
"""
Created on Fri Jun 12 23:33:19 2020
@author: user
"""
a,b=map(int,input().split())
if(a==b):
print(a)
else:
print(2) | Title: Fake NP
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Tavak and Seyyed are good friends. Seyyed is very funny and he told Tavak to solve the following problem instead of longest-path.
You are given *l* and *r*. For all integers from *l* to *r*, inclusive, we wrote down all of the... | ```python
# -*- coding: utf-8 -*-
"""
Created on Fri Jun 12 23:33:19 2020
@author: user
"""
a,b=map(int,input().split())
if(a==b):
print(a)
else:
print(2)
``` | 3 | |
322 | B | Ciel and Flowers | PROGRAMMING | 1,600 | [
"combinatorics",
"math"
] | null | null | Fox Ciel has some flowers: *r* red flowers, *g* green flowers and *b* blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:
- To make a "red bouquet", it needs 3 red flowers. - To make a "green bouquet", it needs 3 green flowers. - To make a "blue bouquet", it needs 3... | The first line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=109) — the number of red, green and blue flowers. | Print the maximal number of bouquets Fox Ciel can make. | [
"3 6 9\n",
"4 4 4\n",
"0 0 0\n"
] | [
"6\n",
"4\n",
"0\n"
] | In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.
In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet. | 1,000 | [
{
"input": "3 6 9",
"output": "6"
},
{
"input": "4 4 4",
"output": "4"
},
{
"input": "0 0 0",
"output": "0"
},
{
"input": "0 3 6",
"output": "3"
},
{
"input": "7 8 9",
"output": "7"
},
{
"input": "8 8 9",
"output": "8"
},
{
"input": "15 3 9... | 1,642,521,993 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 14 | 154 | 0 | r,g,b=list(map(int, input().split()))
rems = []
if(r%3==0):
r = r - 3
rems.append(3)
else:
rems.append(r%3)
if(g%3==0):
g = g - 3
rems.append(3)
else:
rems.append(g%3)
if(b%3==0):
b = b - 3
rems.append(3)
else:
rems.append(b%3)
print(r//3+g//3+b//3+min(rems)) | Title: Ciel and Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel has some flowers: *r* red flowers, *g* green flowers and *b* blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:
- To make a "red bouquet", it needs 3 red fl... | ```python
r,g,b=list(map(int, input().split()))
rems = []
if(r%3==0):
r = r - 3
rems.append(3)
else:
rems.append(r%3)
if(g%3==0):
g = g - 3
rems.append(3)
else:
rems.append(g%3)
if(b%3==0):
b = b - 3
rems.append(3)
else:
rems.append(b%3)
print(r//3+g//3+b//3+... | 0 | |
779 | C | Dishonest Sellers | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"sortings"
] | null | null | Igor found out discounts in a shop and decided to buy *n* items. Discounts at the store will last for a week and Igor knows about each item that its price now is *a**i*, and after a week of discounts its price will be *b**i*.
Not all of sellers are honest, so now some products could be more expensive than after a week... | In the first line there are two positive integer numbers *n* and *k* (1<=≤<=*n*<=≤<=2·105, 0<=≤<=*k*<=≤<=*n*) — total number of items to buy and minimal number of items Igor wants to by right now.
The second line contains sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104) — prices of items during d... | Print the minimal amount of money Igor will spend to buy all *n* items. Remember, he should buy at least *k* items right now. | [
"3 1\n5 4 6\n3 1 5\n",
"5 3\n3 4 7 10 3\n4 5 5 12 5\n"
] | [
"10\n",
"25\n"
] | In the first example Igor should buy item 3 paying 6. But items 1 and 2 he should buy after a week. He will pay 3 and 1 for them. So in total he will pay 6 + 3 + 1 = 10.
In the second example Igor should buy right now items 1, 2, 4 and 5, paying for them 3, 4, 10 and 3, respectively. Item 3 he should buy after a week ... | 1,000 | [
{
"input": "3 1\n5 4 6\n3 1 5",
"output": "10"
},
{
"input": "5 3\n3 4 7 10 3\n4 5 5 12 5",
"output": "25"
},
{
"input": "1 0\n9\n8",
"output": "8"
},
{
"input": "2 0\n4 10\n1 2",
"output": "3"
},
{
"input": "4 2\n19 5 17 13\n3 18 8 10",
"output": "29"
},
... | 1,674,922,264 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 31 | 0 | def swap_sort(a, b):
"Сортируем два массива по массиву b, чтобы в нем брать минимальные n-k товаров"
for j in range(n):
for i in range(n-1-j):
if b[i] > b[i+1]:
b[i], b[i+1] = b[i+1], b[i]
a[i], a[i+1] = a[i+1], a[i]
return a, b
def buys(a, b, n, k):
... | Title: Dishonest Sellers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Igor found out discounts in a shop and decided to buy *n* items. Discounts at the store will last for a week and Igor knows about each item that its price now is *a**i*, and after a week of discounts its price will be... | ```python
def swap_sort(a, b):
"Сортируем два массива по массиву b, чтобы в нем брать минимальные n-k товаров"
for j in range(n):
for i in range(n-1-j):
if b[i] > b[i+1]:
b[i], b[i+1] = b[i+1], b[i]
a[i], a[i+1] = a[i+1], a[i]
return a, b
def buys(a, b, n... | 0 | |
9 | C | Hexadecimal's Numbers | PROGRAMMING | 1,200 | [
"brute force",
"implementation",
"math"
] | C. Hexadecimal's Numbers | 1 | 64 | One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of *n* different natural numbers from 1 to *n* to obtain total control over her energy.
But his plan failed. The reason for th... | Input data contains the only number *n* (1<=≤<=*n*<=≤<=109). | Output the only number — answer to the problem. | [
"10\n"
] | [
"2"
] | For *n* = 10 the answer includes numbers 1 and 10. | 0 | [
{
"input": "10",
"output": "2"
},
{
"input": "20",
"output": "3"
},
{
"input": "72",
"output": "3"
},
{
"input": "99",
"output": "3"
},
{
"input": "100",
"output": "4"
},
{
"input": "101",
"output": "5"
},
{
"input": "102",
"output": "5... | 1,655,132,802 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 14 | 154 | 0 | import sys
input = sys.stdin.readline
from bisect import bisect
d = []
def solve(n):
if len(n) < 10:
d.append(n)
solve(n + '1')
solve(n + '0')
solve('1')
d = sorted(map(int, d))
n = int(input())
print(bisect(d, n)) | Title: Hexadecimal's Numbers
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of *n* different natural ... | ```python
import sys
input = sys.stdin.readline
from bisect import bisect
d = []
def solve(n):
if len(n) < 10:
d.append(n)
solve(n + '1')
solve(n + '0')
solve('1')
d = sorted(map(int, d))
n = int(input())
print(bisect(d, n))
``` | 0 |
660 | A | Co-prime Array | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | You are given an array of *n* elements, you must make it a co-prime array in as few moves as possible.
In each move you can insert any positive integral number you want not greater than 109 in any place in the array.
An array is co-prime if any two adjacent numbers of it are co-prime.
In the number theory, two integ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in the given array.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of the array *a*. | Print integer *k* on the first line — the least number of elements needed to add to the array *a* to make it co-prime.
The second line should contain *n*<=+<=*k* integers *a**j* — the elements of the array *a* after adding *k* elements to it. Note that the new array should be co-prime, so any two adjacent values shoul... | [
"3\n2 7 28\n"
] | [
"1\n2 7 9 28\n"
] | none | 0 | [
{
"input": "3\n2 7 28",
"output": "1\n2 7 1 28"
},
{
"input": "1\n1",
"output": "0\n1"
},
{
"input": "1\n548",
"output": "0\n548"
},
{
"input": "1\n963837006",
"output": "0\n963837006"
},
{
"input": "10\n1 1 1 1 1 1 1 1 1 1",
"output": "0\n1 1 1 1 1 1 1 1 1 1"... | 1,617,642,085 | 2,147,483,647 | Python 3 | OK | TESTS | 93 | 62 | 0 | import sys
import math
n = int(input())
a = list(map(int, input().split()))
i = 1
ans = [a[0]]
while i < n:
if math.gcd(ans[-1], a[i]) == 1:
ans.append(a[i])
i += 1
else:
ans.append(1)
print(len(ans) - n)
print(*ans)
| Title: Co-prime Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array of *n* elements, you must make it a co-prime array in as few moves as possible.
In each move you can insert any positive integral number you want not greater than 109 in any place in the array.
A... | ```python
import sys
import math
n = int(input())
a = list(map(int, input().split()))
i = 1
ans = [a[0]]
while i < n:
if math.gcd(ans[-1], a[i]) == 1:
ans.append(a[i])
i += 1
else:
ans.append(1)
print(len(ans) - n)
print(*ans)
``` | 3 | |
104 | A | Blackjack | PROGRAMMING | 800 | [
"implementation"
] | A. Blackjack | 2 | 256 | One rainy gloomy evening when all modules hid in the nearby cafes to drink hot energetic cocktails, the Hexadecimal virus decided to fly over the Mainframe to look for a Great Idea. And she has found one!
Why not make her own Codeforces, with blackjack and other really cool stuff? Many people will surely be willing to... | The only line contains *n* (1<=≤<=*n*<=≤<=25) — the required sum of points. | Print the numbers of ways to get the second card in the required way if the first card is the queen of spades. | [
"12\n",
"20\n",
"10\n"
] | [
"4",
"15",
"0"
] | In the first sample only four two's of different suits can earn the required sum of points.
In the second sample we can use all tens, jacks, queens and kings; overall it's 15 cards, as the queen of spades (as any other card) is only present once in the pack of cards and it's already in use.
In the third sample there ... | 500 | [
{
"input": "12",
"output": "4"
},
{
"input": "20",
"output": "15"
},
{
"input": "10",
"output": "0"
},
{
"input": "11",
"output": "4"
},
{
"input": "15",
"output": "4"
},
{
"input": "18",
"output": "4"
},
{
"input": "25",
"output": "0"
... | 1,635,677,405 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 124 | 4,300,800 | i = int(input()) -10
if i < 1:
print("0")
elif i < 10:
print("4")
elif i == 10:
print("15")
elif i == 11:
print("4")
else:
print("0") | Title: Blackjack
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One rainy gloomy evening when all modules hid in the nearby cafes to drink hot energetic cocktails, the Hexadecimal virus decided to fly over the Mainframe to look for a Great Idea. And she has found one!
Why not make her own Co... | ```python
i = int(input()) -10
if i < 1:
print("0")
elif i < 10:
print("4")
elif i == 10:
print("15")
elif i == 11:
print("4")
else:
print("0")
``` | 3.960989 |
867 | A | Between the Offices | PROGRAMMING | 800 | [
"implementation"
] | null | null | As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't rem... | The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given... | Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower). | [
"4\nFSSF\n",
"2\nSF\n",
"10\nFFFFFFFFFF\n",
"10\nSSFFSFFSFF\n"
] | [
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you staye... | 500 | [
{
"input": "4\nFSSF",
"output": "NO"
},
{
"input": "2\nSF",
"output": "YES"
},
{
"input": "10\nFFFFFFFFFF",
"output": "NO"
},
{
"input": "10\nSSFFSFFSFF",
"output": "YES"
},
{
"input": "20\nSFSFFFFSSFFFFSSSSFSS",
"output": "NO"
},
{
"input": "20\nSSFFF... | 1,550,417,508 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 109 | 0 | ip_no_days=int(input())
data_diff_days=input()
countSF=0
countFS=0
for i in range(1,len(data_diff_days)):
if data_diff_days[i-1]=='S' and data_diff_days[i]=='F':
countSF+=1
elif data_diff_days[i-1]=='F' and data_diff_days[i]=='S':
countFS+=1
else:
continue
if countSF... | Title: Between the Offices
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Franci... | ```python
ip_no_days=int(input())
data_diff_days=input()
countSF=0
countFS=0
for i in range(1,len(data_diff_days)):
if data_diff_days[i-1]=='S' and data_diff_days[i]=='F':
countSF+=1
elif data_diff_days[i-1]=='F' and data_diff_days[i]=='S':
countFS+=1
else:
continue
... | 3 | |
527 | B | Error Correct System | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | Ford Prefect got a job as a web developer for a small company that makes towels. His current work task is to create a search engine for the website of the company. During the development process, he needs to write a subroutine for comparing strings *S* and *T* of equal length to be "similar". After a brief search on th... | The first line contains integer *n* (1<=≤<=*n*<=≤<=200<=000) — the length of strings *S* and *T*.
The second line contains string *S*.
The third line contains string *T*.
Each of the lines only contains lowercase Latin letters. | In the first line, print number *x* — the minimum possible Hamming distance between strings *S* and *T* if you swap at most one pair of letters in *S*.
In the second line, either print the indexes *i* and *j* (1<=≤<=*i*,<=*j*<=≤<=*n*, *i*<=≠<=*j*), if reaching the minimum possible distance is possible by swapping lett... | [
"9\npergament\npermanent\n",
"6\nwookie\ncookie\n",
"4\npetr\negor\n",
"6\ndouble\nbundle\n"
] | [
"1\n4 6\n",
"1\n-1 -1\n",
"2\n1 2\n",
"2\n4 1\n"
] | In the second test it is acceptable to print *i* = 2, *j* = 3. | 1,000 | [
{
"input": "9\npergament\npermanent",
"output": "1\n4 6"
},
{
"input": "6\nwookie\ncookie",
"output": "1\n-1 -1"
},
{
"input": "4\npetr\negor",
"output": "2\n1 2"
},
{
"input": "6\ndouble\nbundle",
"output": "2\n4 1"
},
{
"input": "1\na\na",
"output": "0\n-1 -... | 1,426,785,852 | 3,851 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 17 | 2,000 | 512,000 | n = int(input())
s, t = input(), input()
d1, d2 = [], []
ind = (-1, -1)
for i in range(n):
if s[i] != t[i]:
d1.append((s[i], i))
d2.append((t[i], i))
k1, k2 = int(), int()
if len(d1) > 1:
for x in [x[0] for x in d1]:
if x in [x[0] for x in d2]:
for p1 in d1:
... | Title: Error Correct System
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ford Prefect got a job as a web developer for a small company that makes towels. His current work task is to create a search engine for the website of the company. During the development process, he needs to write ... | ```python
n = int(input())
s, t = input(), input()
d1, d2 = [], []
ind = (-1, -1)
for i in range(n):
if s[i] != t[i]:
d1.append((s[i], i))
d2.append((t[i], i))
k1, k2 = int(), int()
if len(d1) > 1:
for x in [x[0] for x in d1]:
if x in [x[0] for x in d2]:
for p1 in... | 0 | |
705 | A | Hulk | PROGRAMMING | 800 | [
"implementation"
] | null | null | Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have *n* layers. The first layer is hate, se... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of layers of love and hate. | Print Dr.Banner's feeling in one line. | [
"1\n",
"2\n",
"3\n"
] | [
"I hate it\n",
"I hate that I love it\n",
"I hate that I love that I hate it\n"
] | none | 500 | [
{
"input": "1",
"output": "I hate it"
},
{
"input": "2",
"output": "I hate that I love it"
},
{
"input": "3",
"output": "I hate that I love that I hate it"
},
{
"input": "4",
"output": "I hate that I love that I hate that I love it"
},
{
"input": "5",
"output"... | 1,699,808,163 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 46 | 0 | n= int(input())
for i in range(1,n):
if(i%2!=0):
print("I hate that ", end="")
if(i%2==0):
print("I love that ", end="")
if(n%2!=0):
print("I hate it", end="")
if(n%2==0):
print("I love it", end="") | Title: Hulk
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and... | ```python
n= int(input())
for i in range(1,n):
if(i%2!=0):
print("I hate that ", end="")
if(i%2==0):
print("I love that ", end="")
if(n%2!=0):
print("I hate it", end="")
if(n%2==0):
print("I love it", end="")
``` | 3 | |
294 | A | Shaass and Oskols | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Shaass has decided to hunt some birds. There are *n* horizontal electricity wires aligned parallel to each other. Wires are numbered 1 to *n* from top to bottom. On each wire there are some oskols sitting next to each other. Oskol is the name of a delicious kind of birds in Shaass's territory. Supposed there are *a**i*... | The first line of the input contains an integer *n*, (1<=≤<=*n*<=≤<=100). The next line contains a list of space-separated integers *a*1,<=*a*2,<=...,<=*a**n*, (0<=≤<=*a**i*<=≤<=100).
The third line contains an integer *m*, (0<=≤<=*m*<=≤<=100). Each of the next *m* lines contains two integers *x**i* and *y**i*. The i... | On the *i*-th line of the output print the number of birds on the *i*-th wire. | [
"5\n10 10 10 10 10\n5\n2 5\n3 13\n2 12\n1 13\n4 6\n",
"3\n2 4 1\n1\n2 2\n"
] | [
"0\n12\n5\n0\n16\n",
"3\n0\n3\n"
] | none | 500 | [
{
"input": "5\n10 10 10 10 10\n5\n2 5\n3 13\n2 12\n1 13\n4 6",
"output": "0\n12\n5\n0\n16"
},
{
"input": "3\n2 4 1\n1\n2 2",
"output": "3\n0\n3"
},
{
"input": "5\n58 51 45 27 48\n5\n4 9\n5 15\n4 5\n5 8\n1 43",
"output": "0\n66\n57\n7\n0"
},
{
"input": "10\n48 53 10 28 91 56 8... | 1,617,695,286 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 26 | 122 | 0 | n=int(input())
list=list(map(int,input().split(' ')))
shot=int(input())
for i in range(shot):
x,y=(map(int,input().split()))
if x-1==0:
list[x] +=list[x-1]-y
else:
if x == len(list):
list[x - 2] += y - 1
else:
list[x] += list[x - 1] - y
... | Title: Shaass and Oskols
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Shaass has decided to hunt some birds. There are *n* horizontal electricity wires aligned parallel to each other. Wires are numbered 1 to *n* from top to bottom. On each wire there are some oskols sitting next to each... | ```python
n=int(input())
list=list(map(int,input().split(' ')))
shot=int(input())
for i in range(shot):
x,y=(map(int,input().split()))
if x-1==0:
list[x] +=list[x-1]-y
else:
if x == len(list):
list[x - 2] += y - 1
else:
list[x] += list[x - 1] - y
... | -1 | |
295 | A | Greg and Array | PROGRAMMING | 1,400 | [
"data structures",
"implementation"
] | null | null | Greg has an array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n* and *m* operations. Each operation looks as: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). To apply operation *i* to the array means to increase all array elements with numbers *l**i*,<=*l**i*<=+<=1,<=...,<=*r**i* by value *d**i*.
Greg wrote down *k* qu... | The first line contains integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=105). The second line contains *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=105) — the initial array.
Next *m* lines contain operations, the operation number *i* is written as three integers: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=... | On a single line print *n* integers *a*1,<=*a*2,<=...,<=*a**n* — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier. | [
"3 3 3\n1 2 3\n1 2 1\n1 3 2\n2 3 4\n1 2\n1 3\n2 3\n",
"1 1 1\n1\n1 1 1\n1 1\n",
"4 3 6\n1 2 3 4\n1 2 1\n2 3 2\n3 4 4\n1 2\n1 3\n2 3\n1 2\n1 3\n2 3\n"
] | [
"9 18 17\n",
"2\n",
"5 18 31 20\n"
] | none | 500 | [
{
"input": "3 3 3\n1 2 3\n1 2 1\n1 3 2\n2 3 4\n1 2\n1 3\n2 3",
"output": "9 18 17"
},
{
"input": "1 1 1\n1\n1 1 1\n1 1",
"output": "2"
},
{
"input": "4 3 6\n1 2 3 4\n1 2 1\n2 3 2\n3 4 4\n1 2\n1 3\n2 3\n1 2\n1 3\n2 3",
"output": "5 18 31 20"
},
{
"input": "1 1 1\n0\n1 1 0\n1 1... | 1,649,971,394 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n, m, k = [int(x) for x in input().split(" ")]
array = [int(x) for x in input().split(" ")]
operations = []
#load operations
for i in range(m):
operations.append([int(x) for x in input().split(" ")])
#do queries
for i in range(k):
q_start, q_end = [int(x) for x in input().split(" ")]
for op in range(q_start - 1... | Title: Greg and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg has an array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n* and *m* operations. Each operation looks as: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). To apply operation *i* to the array means to increase all array... | ```python
n, m, k = [int(x) for x in input().split(" ")]
array = [int(x) for x in input().split(" ")]
operations = []
#load operations
for i in range(m):
operations.append([int(x) for x in input().split(" ")])
#do queries
for i in range(k):
q_start, q_end = [int(x) for x in input().split(" ")]
for op in range(q... | 0 | |
485 | A | Factory | PROGRAMMING | 1,400 | [
"implementation",
"math",
"matrices"
] | null | null | One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the factory has to produce (remainder after dividing *x* by *m*) more details. Unfortunately, no cu... | The first line contains two integers *a* and *m* (1<=≤<=*a*,<=*m*<=≤<=105). | Print "Yes" (without quotes) if the production will eventually stop, otherwise print "No". | [
"1 5\n",
"3 6\n"
] | [
"No\n",
"Yes\n"
] | none | 1,000 | [
{
"input": "1 5",
"output": "No"
},
{
"input": "3 6",
"output": "Yes"
},
{
"input": "1 8",
"output": "Yes"
},
{
"input": "2 3",
"output": "No"
},
{
"input": "3 24",
"output": "Yes"
},
{
"input": "1 1",
"output": "Yes"
},
{
"input": "100000 ... | 1,415,699,508 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | ip=map(int,raw_input().split())
a=ip[0]
m=ip[1]
a%=m
af=[a]
x=1;k=1
while (k==1):
a=((a+a%m)%m)
if a==0:
print("Yes")
k=0
else:
for check in af:
if a==check:
print("No")
k=0
af.append(a)
| Title: Factory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the fac... | ```python
ip=map(int,raw_input().split())
a=ip[0]
m=ip[1]
a%=m
af=[a]
x=1;k=1
while (k==1):
a=((a+a%m)%m)
if a==0:
print("Yes")
k=0
else:
for check in af:
if a==check:
print("No")
k=0
af.append(a)
``` | -1 | |
804 | B | Minimum number of steps | PROGRAMMING | 1,400 | [
"combinatorics",
"greedy",
"implementation",
"math"
] | null | null | We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substring, our job is done. Print the minimum number of steps we should perform to make our job done modulo 109<=+<... | The first line contains the initial string consisting of letters 'a' and 'b' only with length from 1 to 106. | Print the minimum number of steps modulo 109<=+<=7. | [
"ab\n",
"aab\n"
] | [
"1\n",
"3\n"
] | The first example: "ab" → "bba".
The second example: "aab" → "abba" → "bbaba" → "bbbbaa". | 1,000 | [
{
"input": "ab",
"output": "1"
},
{
"input": "aab",
"output": "3"
},
{
"input": "aaaaabaabababaaaaaba",
"output": "17307"
},
{
"input": "abaabaaabbabaabab",
"output": "1795"
},
{
"input": "abbaa",
"output": "2"
},
{
"input": "abbaaabaabaaaaabbbbaababaa... | 1,494,271,291 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 62 | 0 | import sys
s = sys.stdin.read()
def f(p, q):
return q * (2 ** p - 1)
aCount = 0
bCount = 0
count = 0
previousChar = 'c'
for c in s:
if c == 'a':
if previousChar == 'b':
count += f(aCount, bCount)
bCount = 0
aCount += 1
previousChar = 'a'
if c == 'b':
... | Title: Minimum number of steps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substr... | ```python
import sys
s = sys.stdin.read()
def f(p, q):
return q * (2 ** p - 1)
aCount = 0
bCount = 0
count = 0
previousChar = 'c'
for c in s:
if c == 'a':
if previousChar == 'b':
count += f(aCount, bCount)
bCount = 0
aCount += 1
previousChar = 'a'
if c ... | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | One day in the IT lesson Anna and Maria learned about the lexicographic order.
String *x* is lexicographically less than string *y*, if either *x* is a prefix of *y* (and *x*<=≠<=*y*), or there exists such *i* (1<=≤<=*i*<=≤<=*min*(|*x*|,<=|*y*|)), that *x**i*<=<<=*y**i*, and for any *j* (1<=≤<=*j*<=<<=*i*) *x**j... | The first line contains a non-empty string that only consists of small Latin letters ("a"-"z"), whose length does not exceed 105. The second line contains the only integer *k* (1<=≤<=*k*<=≤<=105). | Print the string Anna and Maria need — the *k*-th (in the lexicographical order) substring of the given string. If the total number of substrings is less than *k*, print a string saying "No such line." (without the quotes). | [
"aa\n2\n",
"abc\n5\n",
"abab\n7\n"
] | [
"a\n",
"bc\n",
"b\n"
] | In the second sample before string "bc" follow strings "a", "ab", "abc", "b". | 0 | [
{
"input": "aa\n2",
"output": "a"
},
{
"input": "abc\n5",
"output": "bc"
},
{
"input": "abab\n7",
"output": "b"
},
{
"input": "codeforces\n1",
"output": "c"
},
{
"input": "cccc\n8",
"output": "ccc"
},
{
"input": "abcdefghijklmnopqrstuvwxyz\n27",
"o... | 1,665,626,251 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 842 | 9,216,000 | from heapq import *
l=input()
kill=int(input())
n=len(l)
if kill>n*(n+1)/2:
print("No such line.")
quit()
ss=[(l[i],i) for i in range(n)]
heapify(ss)
while kill:
kill-=1
t=heappop(ss)
if kill==0:
print(t[0])
else:
if t[1]<n-1:
heappush(ss,(t[0]+l[t[1]+1],t[1]+1)... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day in the IT lesson Anna and Maria learned about the lexicographic order.
String *x* is lexicographically less than string *y*, if either *x* is a prefix of *y* (and *x*<=≠<=*y*), or there exists such *i* (1<=≤<=*i*<=≤<=*min... | ```python
from heapq import *
l=input()
kill=int(input())
n=len(l)
if kill>n*(n+1)/2:
print("No such line.")
quit()
ss=[(l[i],i) for i in range(n)]
heapify(ss)
while kill:
kill-=1
t=heappop(ss)
if kill==0:
print(t[0])
else:
if t[1]<n-1:
heappush(ss,(t[0]+l[t[1]+... | 3 | |
279 | B | Books | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation",
"two pointers"
] | null | null | When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy n... | Print a single integer — the maximum number of books Valera can read. | [
"4 5\n3 1 2 1\n",
"3 3\n2 2 3\n"
] | [
"3\n",
"1\n"
] | none | 1,000 | [
{
"input": "4 5\n3 1 2 1",
"output": "3"
},
{
"input": "3 3\n2 2 3",
"output": "1"
},
{
"input": "1 3\n5",
"output": "0"
},
{
"input": "1 10\n4",
"output": "1"
},
{
"input": "2 10\n6 4",
"output": "2"
},
{
"input": "6 10\n2 3 4 2 1 1",
"output": "4... | 1,691,775,916 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 186 | 13,824,000 | n,t=map(int,input().split());l=list(map(int,input().split()))
b=0;s=0
for i in l:
b+=i
if b>t: b-=l[s];s+=1
print(n-s)
| Title: Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need t... | ```python
n,t=map(int,input().split());l=list(map(int,input().split()))
b=0;s=0
for i in l:
b+=i
if b>t: b-=l[s];s+=1
print(n-s)
``` | 3 | |
837 | A | Text Volume | PROGRAMMING | 800 | [
"implementation"
] | null | null | You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the text.
Calculate the volume of the given text. | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200) — length of the text.
The second line contains text of single-space separated words *s*1,<=*s*2,<=...,<=*s**i*, consisting only of small and capital Latin letters. | Print one integer number — volume of text. | [
"7\nNonZERO\n",
"24\nthis is zero answer text\n",
"24\nHarbour Space University\n"
] | [
"5\n",
"0\n",
"1\n"
] | In the first example there is only one word, there are 5 capital letters in it.
In the second example all of the words contain 0 capital letters. | 0 | [
{
"input": "7\nNonZERO",
"output": "5"
},
{
"input": "24\nthis is zero answer text",
"output": "0"
},
{
"input": "24\nHarbour Space University",
"output": "1"
},
{
"input": "2\nWM",
"output": "2"
},
{
"input": "200\nLBmJKQLCKUgtTxMoDsEerwvLOXsxASSydOqWyULsRcjMYDWd... | 1,503,425,537 | 2,147,483,647 | PyPy 3 | OK | TESTS | 29 | 108 | 0 | # http://codeforces.com/problemset/problem/837/A
input()
words=input().split()
print(max(map(lambda w:sum(map(str.isupper,w)),words)))
| Title: Text Volume
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the tex... | ```python
# http://codeforces.com/problemset/problem/837/A
input()
words=input().split()
print(max(map(lambda w:sum(map(str.isupper,w)),words)))
``` | 3 | |
985 | D | Sand Fortress | PROGRAMMING | 2,100 | [
"binary search",
"constructive algorithms",
"math"
] | null | null | You are going to the beach with the idea to build the greatest sand castle ever in your head! The beach is not as three-dimensional as you could have imagined, it can be decribed as a line of spots to pile up sand pillars. Spots are numbered 1 through infinity from left to right.
Obviously, there is not enough sand o... | The only line contains two integer numbers *n* and *H* (1<=≤<=*n*,<=*H*<=≤<=1018) — the number of sand packs you have and the height of the fence, respectively. | Print the minimum number of spots you can occupy so the all the castle building conditions hold. | [
"5 2\n",
"6 8\n"
] | [
"3\n",
"3\n"
] | Here are the heights of some valid castles:
- *n* = 5, *H* = 2, [2, 2, 1, 0, ...], [2, 1, 1, 1, 0, ...], [1, 0, 1, 2, 1, 0, ...] - *n* = 6, *H* = 8, [3, 2, 1, 0, ...], [2, 2, 1, 1, 0, ...], [0, 1, 0, 1, 2, 1, 1, 0...] (this one has 5 spots occupied)
The first list for both cases is the optimal answer, 3 spots are ... | 0 | [
{
"input": "5 2",
"output": "3"
},
{
"input": "6 8",
"output": "3"
},
{
"input": "20 4",
"output": "7"
},
{
"input": "1000000000000000000 1000000000000000000",
"output": "1414213562"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 10000000000000000... | 1,526,919,797 | 5,897 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n,h = raw_input().split();
n=long(n);
h=long(h);
if n<=(((h)*(h+1))/2):
bps = [];
bps.append(1);
pbp = 1;
while pbp<=n:
lastno = bps[len(bps)-1];
le = len(bps);
bps.append(le+lastno);
pbp = bps[len(bps)-1];
ans = 0;
for i in range(0,len(bps)):
if bps[i]<... | Title: Sand Fortress
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are going to the beach with the idea to build the greatest sand castle ever in your head! The beach is not as three-dimensional as you could have imagined, it can be decribed as a line of spots to pile up sand pillars... | ```python
n,h = raw_input().split();
n=long(n);
h=long(h);
if n<=(((h)*(h+1))/2):
bps = [];
bps.append(1);
pbp = 1;
while pbp<=n:
lastno = bps[len(bps)-1];
le = len(bps);
bps.append(le+lastno);
pbp = bps[len(bps)-1];
ans = 0;
for i in range(0,len(bps)):
... | -1 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,688,975,437 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | s = list(input())
s_new = []
ind1 = s.index('h')
ind2 = s.index('o')
s_new = s[ind1:ind2+1]
print(s_new)
if s_new.count('h')+s_new.count('e')+s_new.count('l')+s_new.count('o')==len(s_new) and 'h' in s_new and 'e' in s_new and s_new.count('l')>=2 and 'o' in s_new:
if s_new.index('h')<s_new.index('e')<s_new.in... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s = list(input())
s_new = []
ind1 = s.index('h')
ind2 = s.index('o')
s_new = s[ind1:ind2+1]
print(s_new)
if s_new.count('h')+s_new.count('e')+s_new.count('l')+s_new.count('o')==len(s_new) and 'h' in s_new and 'e' in s_new and s_new.count('l')>=2 and 'o' in s_new:
if s_new.index('h')<s_new.index('e'... | 0 |
637 | B | Chat Order | PROGRAMMING | 1,200 | [
"*special",
"binary search",
"constructive algorithms",
"data structures",
"sortings"
] | null | null | Polycarp is a big lover of killing time in social networks. A page with a chatlist in his favourite network is made so that when a message is sent to some friend, his friend's chat rises to the very top of the page. The relative order of the other chats doesn't change. If there was no chat with this friend before, then... | The first line contains integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of Polycarpus' messages. Next *n* lines enlist the message recipients in the order in which the messages were sent. The name of each participant is a non-empty sequence of lowercase English letters of length at most 10. | Print all the recipients to who Polycarp talked to in the order of chats with them, from top to bottom. | [
"4\nalex\nivan\nroman\nivan\n",
"8\nalina\nmaria\nekaterina\ndarya\ndarya\nekaterina\nmaria\nalina\n"
] | [
"ivan\nroman\nalex\n",
"alina\nmaria\nekaterina\ndarya\n"
] | In the first test case Polycarpus first writes to friend by name "alex", and the list looks as follows:
1. alex
Then Polycarpus writes to friend by name "ivan" and the list looks as follows:
1. ivan 1. alex
Polycarpus writes the third message to friend by name "roman" and the list looks as follows:
1. roman 1... | 1,000 | [
{
"input": "4\nalex\nivan\nroman\nivan",
"output": "ivan\nroman\nalex"
},
{
"input": "8\nalina\nmaria\nekaterina\ndarya\ndarya\nekaterina\nmaria\nalina",
"output": "alina\nmaria\nekaterina\ndarya"
},
{
"input": "1\nwdi",
"output": "wdi"
},
{
"input": "2\nypg\nypg",
"outpu... | 1,698,095,775 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n=int(input())
list1=[]
result=[]
for i in range(n):
name=input()
list1.append(name)
for i in list1:
if i not in result:
result.append(i)
print(result[::-1])
| Title: Chat Order
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is a big lover of killing time in social networks. A page with a chatlist in his favourite network is made so that when a message is sent to some friend, his friend's chat rises to the very top of the page. The rela... | ```python
n=int(input())
list1=[]
result=[]
for i in range(n):
name=input()
list1.append(name)
for i in list1:
if i not in result:
result.append(i)
print(result[::-1])
``` | 0 | |
231 | A | Team | PROGRAMMING | 800 | [
"brute force",
"greedy"
] | null | null | One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution.... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second numbe... | Print a single integer — the number of problems the friends will implement on the contest. | [
"3\n1 1 0\n1 1 1\n1 0 0\n",
"2\n1 0 0\n0 1 1\n"
] | [
"2\n",
"1\n"
] | In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't ta... | 500 | [
{
"input": "3\n1 1 0\n1 1 1\n1 0 0",
"output": "2"
},
{
"input": "2\n1 0 0\n0 1 1",
"output": "1"
},
{
"input": "1\n1 0 0",
"output": "0"
},
{
"input": "2\n1 0 0\n1 1 1",
"output": "1"
},
{
"input": "5\n1 0 0\n0 1 0\n1 1 1\n0 0 1\n0 0 0",
"output": "1"
},
... | 1,699,044,217 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | n = int(input())
cont = 0
for _ in range(n):
a1, a2, a3 = map(int, input().split())
if a1 + a2 + a3 >= 2:
cont += 1
print(cont) | Title: Team
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decid... | ```python
n = int(input())
cont = 0
for _ in range(n):
a1, a2, a3 = map(int, input().split())
if a1 + a2 + a3 >= 2:
cont += 1
print(cont)
``` | 3 | |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahed... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (withou... | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,674,925,551 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 265 | 0 | # Tetrahedron. Tetrahedron has 4 triangular faces.
# Cube. Cube has 6 square faces.
# Octahedron. Octahedron has 8 triangular faces.
# Dodecahedron. Dodecahedron has 12 pentagonal faces.
# Icosahedron. Icosahedron has 20 triangular faces.
n = int(input())
sum = 0
mydict = {"Tetrahedron":4 , "Cube":6 , "Octahedro... | Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahe... | ```python
# Tetrahedron. Tetrahedron has 4 triangular faces.
# Cube. Cube has 6 square faces.
# Octahedron. Octahedron has 8 triangular faces.
# Dodecahedron. Dodecahedron has 12 pentagonal faces.
# Icosahedron. Icosahedron has 20 triangular faces.
n = int(input())
sum = 0
mydict = {"Tetrahedron":4 , "Cube":6 , ... | 3 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the... | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,688,424,458 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 17 | 1,000 | 1,638,400 | r=input().split()
cou=0
c1=0
c2=0
m=int(r[0])
n=int(r[1])
a=int(r[2])
if a==n==m:
cou=1
elif a>m and a>n:
cou=1
elif m==n and a==1:
cou=m*n
elif a==n or a==m:
while m>0:
m=m-a
c1=c1+1
while n>0:
n=n-a
c2=c2+1
cou=c1*c2
else:
while m>0:
m=m-a
c1... | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each ... | ```python
r=input().split()
cou=0
c1=0
c2=0
m=int(r[0])
n=int(r[1])
a=int(r[2])
if a==n==m:
cou=1
elif a>m and a>n:
cou=1
elif m==n and a==1:
cou=m*n
elif a==n or a==m:
while m>0:
m=m-a
c1=c1+1
while n>0:
n=n-a
c2=c2+1
cou=c1*c2
else:
while m>0:
m=m-a
... | 0 |
962 | C | Make a Square | PROGRAMMING | 1,400 | [
"brute force",
"implementation",
"math"
] | null | null | You are given a positive integer $n$, written without leading zeroes (for example, the number 04 is incorrect).
In one operation you can delete any digit of the given integer so that the result remains a positive integer without leading zeros.
Determine the minimum number of operations that you need to consistently ... | The first line contains a single integer $n$ ($1 \le n \le 2 \cdot 10^{9}$). The number is given without leading zeroes. | If it is impossible to make the square of some positive integer from $n$, print -1. In the other case, print the minimal number of operations required to do it. | [
"8314\n",
"625\n",
"333\n"
] | [
"2\n",
"0\n",
"-1\n"
] | In the first example we should delete from $8314$ the digits $3$ and $4$. After that $8314$ become equals to $81$, which is the square of the integer $9$.
In the second example the given $625$ is the square of the integer $25$, so you should not delete anything.
In the third example it is impossible to make the squa... | 0 | [
{
"input": "8314",
"output": "2"
},
{
"input": "625",
"output": "0"
},
{
"input": "333",
"output": "-1"
},
{
"input": "1881388645",
"output": "6"
},
{
"input": "1059472069",
"output": "3"
},
{
"input": "1354124829",
"output": "4"
},
{
"inpu... | 1,591,505,948 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 170 | 3,276,800 | num=input()
n=len(num)
myset=set([])
ans=n;
for i in range(1,32000):
myset.add(str(i*i))
for mask in range(1,1<<n):
num2=""
for i in range(n):
if (mask&(1<<i)):
num2+=num[i];
num2=num2.strip('0')
if num2!="" and num2 in myset:
ans=min(ans,n-len(num2))
an... | Title: Make a Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a positive integer $n$, written without leading zeroes (for example, the number 04 is incorrect).
In one operation you can delete any digit of the given integer so that the result remains a positive intege... | ```python
num=input()
n=len(num)
myset=set([])
ans=n;
for i in range(1,32000):
myset.add(str(i*i))
for mask in range(1,1<<n):
num2=""
for i in range(n):
if (mask&(1<<i)):
num2+=num[i];
num2=num2.strip('0')
if num2!="" and num2 in myset:
ans=min(ans,n-len(nu... | 0 | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,672,393,304 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 62 | 0 | n = int(input())
ar = list(map(int,input().split()))
n1 = ar[0]
n2=ar[1]
n3=ar[2]
even=0
odd=0
if n1%2==0:
even+=1
else:
odd+=1
if n2%2==0:
even+=1
else:
odd+=1
if n3%2==0:
even+=1
else:
odd+=1
isEven=False
if even>odd:
isEven=True
for i in range(n):
if (ar[i]%2==0)==isEven:
pass... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n = int(input())
ar = list(map(int,input().split()))
n1 = ar[0]
n2=ar[1]
n3=ar[2]
even=0
odd=0
if n1%2==0:
even+=1
else:
odd+=1
if n2%2==0:
even+=1
else:
odd+=1
if n3%2==0:
even+=1
else:
odd+=1
isEven=False
if even>odd:
isEven=True
for i in range(n):
if (ar[i]%2==0)==isEven:
... | 3.9845 |
764 | A | Taymyr is calling you | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long,... | The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104). | Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls. | [
"1 1 10\n",
"1 2 5\n",
"2 3 9\n"
] | [
"10\n",
"2\n",
"1\n"
] | Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute. | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "1 2 5",
"output": "2"
},
{
"input": "2 3 9",
"output": "1"
},
{
"input": "4 8 9",
"output": "1"
},
{
"input": "7 9 2",
"output": "0"
},
{
"input": "10000 10000 10000",
"output": "1"
},
{
"i... | 1,486,647,932 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 77 | 4,608,000 | a,b,c = list(map(int,input().split()))
q = 0
e = 0
r = 0
if a < b:
while (q or e) != c:
q += a
if q == e:
r += 1
else:
e += b
if q == e:
r += 1
if (q or e) >= c:
break
else:
while (q or e) != c... | Title: Taymyr is calling you
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists com... | ```python
a,b,c = list(map(int,input().split()))
q = 0
e = 0
r = 0
if a < b:
while (q or e) != c:
q += a
if q == e:
r += 1
else:
e += b
if q == e:
r += 1
if (q or e) >= c:
break
else:
while (q ... | 0 | |
760 | A | Petr and a calendar | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to ... | The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). | Print single integer: the number of columns the table should have. | [
"1 7\n",
"1 1\n",
"11 6\n"
] | [
"6\n",
"5\n",
"5\n"
] | The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | 500 | [
{
"input": "1 7",
"output": "6"
},
{
"input": "1 1",
"output": "5"
},
{
"input": "11 6",
"output": "5"
},
{
"input": "2 7",
"output": "5"
},
{
"input": "2 1",
"output": "4"
},
{
"input": "8 6",
"output": "6"
},
{
"input": "1 1",
"output... | 1,587,159,425 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | m, d = map(int, input().split())
if m == 2 and d = 1:
print(4)
elif (m in [4, 6, 9, 11] and d == 7) or (m in [1, 3, 5, 7, 8, 10, 12] and d in[6, 7]):
print(6)
else:
print(5)
| Title: Petr and a calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells... | ```python
m, d = map(int, input().split())
if m == 2 and d = 1:
print(4)
elif (m in [4, 6, 9, 11] and d == 7) or (m in [1, 3, 5, 7, 8, 10, 12] and d in[6, 7]):
print(6)
else:
print(5)
``` | -1 | |
975 | A | Aramic script | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | In Aramic language words can only represent objects.
Words in Aramic have special properties:
- A word is a root if it does not contain the same letter more than once. - A root and all its permutations represent the same object. - The root $x$ of a word $y$ is the word that contains all letters that appear in $y$... | The first line contains one integer $n$ ($1 \leq n \leq 10^3$) — the number of words in the script.
The second line contains $n$ words $s_1, s_2, \ldots, s_n$ — the script itself. The length of each string does not exceed $10^3$.
It is guaranteed that all characters of the strings are small latin letters. | Output one integer — the number of different objects mentioned in the given ancient Aramic script. | [
"5\na aa aaa ab abb\n",
"3\namer arem mrea\n"
] | [
"2",
"1"
] | In the first test, there are two objects mentioned. The roots that represent them are "a","ab".
In the second test, there is only one object, its root is "amer", the other strings are just permutations of "amer". | 500 | [
{
"input": "5\na aa aaa ab abb",
"output": "2"
},
{
"input": "3\namer arem mrea",
"output": "1"
},
{
"input": "10\nbda bbb cda dca dda dcb bcd dcb ada ddd",
"output": "6"
},
{
"input": "2\nfhjlqs aceginpr",
"output": "2"
},
{
"input": "2\nbcdfghimn efghijlmo",
... | 1,525,187,171 | 3,671 | Python 3 | RUNTIME_ERROR | PRETESTS | 0 | 62 | 7,065,600 | n = int(input())
ars = set()
for i in range(n):
w = input()
ars.add(tuple(sorted(set([l for l in w]))))
print(len(ars))
| Title: Aramic script
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Aramic language words can only represent objects.
Words in Aramic have special properties:
- A word is a root if it does not contain the same letter more than once. - A root and all its permutations represent the ... | ```python
n = int(input())
ars = set()
for i in range(n):
w = input()
ars.add(tuple(sorted(set([l for l in w]))))
print(len(ars))
``` | -1 | |
231 | A | Team | PROGRAMMING | 800 | [
"brute force",
"greedy"
] | null | null | One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution.... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second numbe... | Print a single integer — the number of problems the friends will implement on the contest. | [
"3\n1 1 0\n1 1 1\n1 0 0\n",
"2\n1 0 0\n0 1 1\n"
] | [
"2\n",
"1\n"
] | In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't ta... | 500 | [
{
"input": "3\n1 1 0\n1 1 1\n1 0 0",
"output": "2"
},
{
"input": "2\n1 0 0\n0 1 1",
"output": "1"
},
{
"input": "1\n1 0 0",
"output": "0"
},
{
"input": "2\n1 0 0\n1 1 1",
"output": "1"
},
{
"input": "5\n1 0 0\n0 1 0\n1 1 1\n0 0 1\n0 0 0",
"output": "1"
},
... | 1,696,017,344 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | x=int(input())
count=0
while(x>0):
cnt=0
y=input()
y=y.strip(" ")
for i in range(5):
if(y[i]=='1'):
cnt+=1
# print(i,'i',cnt,"cnt")
if cnt>1:
count+=1
x-=1
print(count)
| Title: Team
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decid... | ```python
x=int(input())
count=0
while(x>0):
cnt=0
y=input()
y=y.strip(" ")
for i in range(5):
if(y[i]=='1'):
cnt+=1
# print(i,'i',cnt,"cnt")
if cnt>1:
count+=1
x-=1
print(count)
``` | 3 | |
3 | B | Lorry | PROGRAMMING | 1,900 | [
"greedy",
"sortings"
] | B. Lorry | 2 | 64 | A group of tourists is going to kayak and catamaran tour. A rented lorry has arrived to the boat depot to take kayaks and catamarans to the point of departure. It's known that all kayaks are of the same size (and each of them occupies the space of 1 cubic metre), and all catamarans are of the same size, but two times b... | The first line contains a pair of integer numbers *n* and *v* (1<=≤<=*n*<=≤<=105; 1<=≤<=*v*<=≤<=109), where *n* is the number of waterborne vehicles in the boat depot, and *v* is the truck body volume of the lorry in cubic metres. The following *n* lines contain the information about the waterborne vehicles, that is a ... | In the first line print the maximum possible carrying capacity of the set. In the second line print a string consisting of the numbers of the vehicles that make the optimal set. If the answer is not unique, print any of them. | [
"3 2\n1 2\n2 7\n1 3\n"
] | [
"7\n2\n"
] | none | 0 | [
{
"input": "3 2\n1 2\n2 7\n1 3",
"output": "7\n2"
},
{
"input": "5 3\n1 9\n2 9\n1 9\n2 10\n1 6",
"output": "24\n3 1 5"
},
{
"input": "10 10\n1 14\n2 15\n2 11\n2 12\n2 9\n1 14\n2 15\n1 9\n2 11\n2 6",
"output": "81\n6 1 7 2 4 9"
},
{
"input": "20 19\n2 47\n1 37\n1 48\n2 42\n2 4... | 1,519,747,976 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 13,004,800 | # -*- coding: utf-8 -*-
"""
Created on Tue Feb 27 22:00:12 2018
@author: hp
"""
[n,v] = [eval(x) for x in str.split(input())]
#save the boats in two arrays
array1 = []
array2 = []
for i in range(n):
[kind,capacity] = [eval(x) for x in str.split(input())]
if kind == 1:
array1.append([... | Title: Lorry
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
A group of tourists is going to kayak and catamaran tour. A rented lorry has arrived to the boat depot to take kayaks and catamarans to the point of departure. It's known that all kayaks are of the same size (and each of them occupies... | ```python
# -*- coding: utf-8 -*-
"""
Created on Tue Feb 27 22:00:12 2018
@author: hp
"""
[n,v] = [eval(x) for x in str.split(input())]
#save the boats in two arrays
array1 = []
array2 = []
for i in range(n):
[kind,capacity] = [eval(x) for x in str.split(input())]
if kind == 1:
array... | 0 |
353 | A | Domino | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Valera has got *n* domino pieces in a row. Each piece consists of two halves — the upper one and the lower one. Each of the halves contains a number from 1 to 6. Valera loves even integers very much, so he wants the sum of the numbers on the upper halves and the sum of the numbers on the lower halves to be even.
To do... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100), denoting the number of dominoes Valera has. Next *n* lines contain two space-separated integers *x**i*,<=*y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=6). Number *x**i* is initially written on the upper half of the *i*-th domino, *y**i* is initially written on the lower half... | Print a single number — the minimum required number of seconds. If Valera can't do the task in any time, print <=-<=1. | [
"2\n4 2\n6 4\n",
"1\n2 3\n",
"3\n1 4\n2 3\n4 4\n"
] | [
"0\n",
"-1\n",
"1\n"
] | In the first test case the sum of the numbers on the upper halves equals 10 and the sum of the numbers on the lower halves equals 6. Both numbers are even, so Valera doesn't required to do anything.
In the second sample Valera has only one piece of domino. It is written 3 on the one of its halves, therefore one of the... | 500 | [
{
"input": "2\n4 2\n6 4",
"output": "0"
},
{
"input": "1\n2 3",
"output": "-1"
},
{
"input": "3\n1 4\n2 3\n4 4",
"output": "1"
},
{
"input": "5\n5 4\n5 4\n1 5\n5 5\n3 3",
"output": "1"
},
{
"input": "20\n1 3\n5 2\n5 2\n2 6\n2 4\n1 1\n1 3\n1 4\n2 6\n4 2\n5 6\n2 2\n... | 1,681,761,537 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 92 | 0 | def dominoSwaps(n, arr):
unbalanced = {'firstOdd': 0, 'secondOdd': 0, 'oddPair': 0}
for i in range(n):
if int(arr[i][0]) % 2 == 1 and int(arr[i][1]) % 2 == 1:
if unbalanced['oddPair'] == 1:
unbalanced['oddPair'] -= 1
else:
unbalanced['oddPai... | Title: Domino
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera has got *n* domino pieces in a row. Each piece consists of two halves — the upper one and the lower one. Each of the halves contains a number from 1 to 6. Valera loves even integers very much, so he wants the sum of the n... | ```python
def dominoSwaps(n, arr):
unbalanced = {'firstOdd': 0, 'secondOdd': 0, 'oddPair': 0}
for i in range(n):
if int(arr[i][0]) % 2 == 1 and int(arr[i][1]) % 2 == 1:
if unbalanced['oddPair'] == 1:
unbalanced['oddPair'] -= 1
else:
unbalanc... | 0 | |
217 | A | Ice Skating | PROGRAMMING | 1,200 | [
"brute force",
"dfs and similar",
"dsu",
"graphs"
] | null | null | Bajtek is learning to skate on ice. He's a beginner, so his only mode of transportation is pushing off from a snow drift to the north, east, south or west and sliding until he lands in another snow drift. He has noticed that in this way it's impossible to get from some snow drifts to some other by any sequence of moves... | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of snow drifts. Each of the following *n* lines contains two integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=1000) — the coordinates of the *i*-th snow drift.
Note that the north direction coinсides with the direction of *Oy* ... | Output the minimal number of snow drifts that need to be created in order for Bajtek to be able to reach any snow drift from any other one. | [
"2\n2 1\n1 2\n",
"2\n2 1\n4 1\n"
] | [
"1\n",
"0\n"
] | none | 500 | [
{
"input": "2\n2 1\n1 2",
"output": "1"
},
{
"input": "2\n2 1\n4 1",
"output": "0"
},
{
"input": "24\n171 35\n261 20\n4 206\n501 446\n961 912\n581 748\n946 978\n463 514\n841 889\n341 466\n842 967\n54 102\n235 261\n925 889\n682 672\n623 636\n268 94\n635 710\n474 510\n697 794\n586 663\n182... | 1,638,277,233 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 92 | 0 | n=int(input())
ans=1
x1=[]
y1=[]
for i in range(n):
x,y=list(map(int,input().split()))
x1.append({x})
y1.append({y})
for i in range(n-1):
for j in range(i+1,n):
if x1[i]&x1[j] or y1[i]&y1[j]:
x1[j]|=x1[i]
y1[j]|=y1[i]
ans+=1
break
pr... | Title: Ice Skating
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bajtek is learning to skate on ice. He's a beginner, so his only mode of transportation is pushing off from a snow drift to the north, east, south or west and sliding until he lands in another snow drift. He has noticed tha... | ```python
n=int(input())
ans=1
x1=[]
y1=[]
for i in range(n):
x,y=list(map(int,input().split()))
x1.append({x})
y1.append({y})
for i in range(n-1):
for j in range(i+1,n):
if x1[i]&x1[j] or y1[i]&y1[j]:
x1[j]|=x1[i]
y1[j]|=y1[i]
ans+=1
... | 3 | |
976 | A | Minimum Binary Number | PROGRAMMING | 800 | [
"implementation"
] | null | null | String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" "110"... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=100) — the length of string *s*.
The second line contains the string *s* consisting of characters "0" and "1". It is guaranteed that the string *s* is correct. | Print one string — the minimum correct string that you can obtain from the given one. | [
"4\n1001\n",
"1\n1\n"
] | [
"100\n",
"1\n"
] | In the first example you can obtain the answer by the following sequence of operations: "1001" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "1010" <img align="middle" class="tex-formula" src="ht... | 0 | [
{
"input": "4\n1001",
"output": "100"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "100\n1110111100001111011111111010110011111111011110000111101101011100110110001011000000101010110101011100",
"output": "1000000000000000000000000000000000000000"
},
{
"input": "100\n100000... | 1,534,834,632 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 139 | 0 | n=int(input())
a=input()
x='1'+'0'*a.count('0')
print(x)
| Title: Minimum Binary Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two... | ```python
n=int(input())
a=input()
x='1'+'0'*a.count('0')
print(x)
``` | 0 | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,658,600,871 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 92 | 0 | # https://codeforces.com/problemset/problem/25/A
# [2022-07-23 Sat 11:06]
count = int(input())
numbers = [int(x) for x in input().split()]
first_odd = None
first_even = None
odd_count = 0
even_count = 0
for i, num in enumerate(numbers):
if num % 2 == 0:
even_count += 1
if not first_even:
... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
# https://codeforces.com/problemset/problem/25/A
# [2022-07-23 Sat 11:06]
count = int(input())
numbers = [int(x) for x in input().split()]
first_odd = None
first_even = None
odd_count = 0
even_count = 0
for i, num in enumerate(numbers):
if num % 2 == 0:
even_count += 1
if not first_eve... | 3.977 |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made lik... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,694,248,673 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 20 | 62 | 0 | n = int(input())
words = [input() for i in range(n) ]
for i in words:
if (length := len(i)) <= 10:
print(i)
else:
print(i[0] + str(length - 2) + i[-1]) | Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 character... | ```python
n = int(input())
words = [input() for i in range(n) ]
for i in words:
if (length := len(i)) <= 10:
print(i)
else:
print(i[0] + str(length - 2) + i[-1])
``` | 3.969 |
478 | C | Table Decorations | PROGRAMMING | 1,800 | [
"greedy"
] | null | null | You have *r* red, *g* green and *b* blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number *t* of tables can be decorated if we know number of balloons of each color?
Your task is to write a pro... | The single line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=2·109) — the number of red, green and blue baloons respectively. The numbers are separated by exactly one space. | Print a single integer *t* — the maximum number of tables that can be decorated in the required manner. | [
"5 4 3\n",
"1 1 1\n",
"2 3 3\n"
] | [
"4\n",
"1\n",
"2\n"
] | In the first sample you can decorate the tables with the following balloon sets: "rgg", "gbb", "brr", "rrg", where "r", "g" and "b" represent the red, green and blue balls, respectively. | 1,500 | [
{
"input": "5 4 3",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 3 3",
"output": "2"
},
{
"input": "0 1 0",
"output": "0"
},
{
"input": "0 3 3",
"output": "2"
},
{
"input": "4 0 4",
"output": "2"
},
{
"input": "100000... | 1,663,262,885 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 9 | 46 | 0 | r,g,b = [int(i) for i in input().split()]
new = [r,g,b]
new.sort(reverse=True)
res = 0
res += (new[0]+new[1]) // 3
res += (((new[0]+new[1]) % 3) + new[2]) // 3
print(res) | Title: Table Decorations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *r* red, *g* green and *b* blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number *... | ```python
r,g,b = [int(i) for i in input().split()]
new = [r,g,b]
new.sort(reverse=True)
res = 0
res += (new[0]+new[1]) // 3
res += (((new[0]+new[1]) % 3) + new[2]) // 3
print(res)
``` | 0 | |
9 | C | Hexadecimal's Numbers | PROGRAMMING | 1,200 | [
"brute force",
"implementation",
"math"
] | C. Hexadecimal's Numbers | 1 | 64 | One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of *n* different natural numbers from 1 to *n* to obtain total control over her energy.
But his plan failed. The reason for th... | Input data contains the only number *n* (1<=≤<=*n*<=≤<=109). | Output the only number — answer to the problem. | [
"10\n"
] | [
"2"
] | For *n* = 10 the answer includes numbers 1 and 10. | 0 | [
{
"input": "10",
"output": "2"
},
{
"input": "20",
"output": "3"
},
{
"input": "72",
"output": "3"
},
{
"input": "99",
"output": "3"
},
{
"input": "100",
"output": "4"
},
{
"input": "101",
"output": "5"
},
{
"input": "102",
"output": "5... | 1,610,778,353 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 13 | 154 | 0 | def solve(b):
n = 2 ** 8
ans = 0
while n > 0:
m = int(bin(n).replace("0b", ""))
ans += (m <= b)
n -= 1
return ans
print (solve(int(input()))) | Title: Hexadecimal's Numbers
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of *n* different natural ... | ```python
def solve(b):
n = 2 ** 8
ans = 0
while n > 0:
m = int(bin(n).replace("0b", ""))
ans += (m <= b)
n -= 1
return ans
print (solve(int(input())))
``` | 0 |
940 | A | Points on the line | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"sortings"
] | null | null | We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1,<=3,<=2,<=1} is 2.
D... | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=100,<=0<=≤<=*d*<=≤<=100) — the amount of points and the maximum allowed diameter respectively.
The second line contains *n* space separated integers (1<=≤<=*x**i*<=≤<=100) — the coordinates of the points. | Output a single integer — the minimum number of points you have to remove. | [
"3 1\n2 1 4\n",
"3 0\n7 7 7\n",
"6 3\n1 3 4 6 9 10\n"
] | [
"1\n",
"0\n",
"3\n"
] | In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal stra... | 500 | [
{
"input": "3 1\n2 1 4",
"output": "1"
},
{
"input": "3 0\n7 7 7",
"output": "0"
},
{
"input": "6 3\n1 3 4 6 9 10",
"output": "3"
},
{
"input": "11 5\n10 11 12 13 14 15 16 17 18 19 20",
"output": "5"
},
{
"input": "1 100\n1",
"output": "0"
},
{
"input"... | 1,519,480,658 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 4 | 46 | 6,451,200 | import sys
def main():
in_1=sys.stdin.readline().split()
n_points=int(in_1[0])
#print("n puntos: "+str(n_points))
diam_requerido=int(in_1[1])
#print("d requerido: "+str(diam_requerido))
l_numeros=sys.stdin.readline().split()
l_numeros=[int(x) for x in l_numeros]
#print("lista ... | Title: Points on the line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest dista... | ```python
import sys
def main():
in_1=sys.stdin.readline().split()
n_points=int(in_1[0])
#print("n puntos: "+str(n_points))
diam_requerido=int(in_1[1])
#print("d requerido: "+str(diam_requerido))
l_numeros=sys.stdin.readline().split()
l_numeros=[int(x) for x in l_numeros]
#pri... | -1 | |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,685,561,759 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | Number = int(input("money: "))
denominations = [100, 20, 10, 5, 1]
count = 0
for i in denominations:
print(i)
if Number >= i:
count += Number // i
Number %= i
print(count) | Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
Number = int(input("money: "))
denominations = [100, 20, 10, 5, 1]
count = 0
for i in denominations:
print(i)
if Number >= i:
count += Number // i
Number %= i
print(count)
``` | 0 | |
30 | A | Accounting | PROGRAMMING | 1,400 | [
"brute force",
"math"
] | A. Accounting | 2 | 256 | A long time ago in some far country lived king Copa. After the recent king's reform, he got so large powers that started to keep the books by himself.
The total income *A* of his kingdom during 0-th year is known, as well as the total income *B* during *n*-th year (these numbers can be negative — it means that there w... | The input contains three integers *A*, *B*, *n* (|*A*|,<=|*B*|<=≤<=1000, 1<=≤<=*n*<=≤<=10). | Output the required integer coefficient *X*, or «No solution», if such a coefficient does not exist or it is fractional. If there are several possible solutions, output any of them. | [
"2 18 2\n",
"-1 8 3\n",
"0 0 10\n",
"1 16 5\n"
] | [
"3",
"-2",
"5",
"No solution"
] | none | 500 | [
{
"input": "2 18 2",
"output": "3"
},
{
"input": "-1 8 3",
"output": "-2"
},
{
"input": "0 0 10",
"output": "5"
},
{
"input": "1 16 5",
"output": "No solution"
},
{
"input": "0 1 2",
"output": "No solution"
},
{
"input": "3 0 4",
"output": "0"
},... | 1,672,921,719 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | import math
a,b,n = map(int,input().split())
try:
print((b//a)**(1/n))
except:
print("No solution")
| Title: Accounting
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A long time ago in some far country lived king Copa. After the recent king's reform, he got so large powers that started to keep the books by himself.
The total income *A* of his kingdom during 0-th year is known, as well as th... | ```python
import math
a,b,n = map(int,input().split())
try:
print((b//a)**(1/n))
except:
print("No solution")
``` | 0 |
915 | A | Garden | PROGRAMMING | 900 | [
"implementation"
] | null | null | Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each hour. Luba can't water any parts of the garden that were already watered, also she can't wat... | The first line of input contains two integer numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of buckets and the length of the garden, respectively.
The second line of input contains *n* integer numbers *a**i* (1<=≤<=*a**i*<=≤<=100) — the length of the segment that can be watered by the *i*-th bucket in one ... | Print one integer number — the minimum number of hours required to water the garden. | [
"3 6\n2 3 5\n",
"6 7\n1 2 3 4 5 6\n"
] | [
"2\n",
"7\n"
] | In the first test the best option is to choose the bucket that allows to water the segment of length 3. We can't choose the bucket that allows to water the segment of length 5 because then we can't water the whole garden.
In the second test we can choose only the bucket that allows us to water the segment of length 1. | 0 | [
{
"input": "3 6\n2 3 5",
"output": "2"
},
{
"input": "6 7\n1 2 3 4 5 6",
"output": "7"
},
{
"input": "5 97\n1 10 50 97 2",
"output": "1"
},
{
"input": "5 97\n1 10 50 100 2",
"output": "97"
},
{
"input": "100 100\n2 46 24 18 86 90 31 38 84 49 58 28 15 80 14 24 87 5... | 1,657,197,501 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 31 | 0 | n, k = map(int, input().split())
arr = [int(a) for a in input().split()]
for i in reversed(range(len(arr))):
if k % arr[i] == 0:
break
print(k // arr[i]) | Title: Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each ... | ```python
n, k = map(int, input().split())
arr = [int(a) for a in input().split()]
for i in reversed(range(len(arr))):
if k % arr[i] == 0:
break
print(k // arr[i])
``` | 0 | |
912 | B | New Year's Eve | PROGRAMMING | 1,300 | [
"bitmasks",
"constructive algorithms",
"number theory"
] | null | null | Since Grisha behaved well last year, at New Year's Eve he was visited by Ded Moroz who brought an enormous bag of gifts with him! The bag contains *n* sweet candies from the good ol' bakery, each labeled from 1 to *n* corresponding to its tastiness. No two candies have the same tastiness.
The choice of candies has a d... | The sole string contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=1018). | Output one number — the largest possible xor-sum. | [
"4 3\n",
"6 6\n"
] | [
"7\n",
"7\n"
] | In the first sample case, one optimal answer is 1, 2 and 4, giving the xor-sum of 7.
In the second sample case, one can, for example, take all six candies and obtain the xor-sum of 7. | 1,000 | [
{
"input": "4 3",
"output": "7"
},
{
"input": "6 6",
"output": "7"
},
{
"input": "2 2",
"output": "3"
},
{
"input": "1022 10",
"output": "1023"
},
{
"input": "415853337373441 52",
"output": "562949953421311"
},
{
"input": "75 12",
"output": "127"
... | 1,516,292,828 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 5,632,000 | # i just can't find the pattern[1,2,3,4] take 3 elem
# from the list and return the maximum xor
n, k = map(int, input().split())
i, j = 1, 2
while n > 0:
n -= i
if n >= j:
n -= j
t = i
i = i+j
j = i+1
if j <= n:
print(i^j)
else:
print(i)
| Title: New Year's Eve
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Since Grisha behaved well last year, at New Year's Eve he was visited by Ded Moroz who brought an enormous bag of gifts with him! The bag contains *n* sweet candies from the good ol' bakery, each labeled from 1 to *n* co... | ```python
# i just can't find the pattern[1,2,3,4] take 3 elem
# from the list and return the maximum xor
n, k = map(int, input().split())
i, j = 1, 2
while n > 0:
n -= i
if n >= j:
n -= j
t = i
i = i+j
j = i+1
if j <= n:
print(i^j)
else:
print(i)
``` | 0 | |
583 | A | Asphalting Roads | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers of the roads that form them.
Sand roads have long been recognized out of date, so the decision was ma... | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of vertical and horizontal roads in the city.
Next *n*2 lines contain the order of intersections in the schedule. The *i*-th of them contains two numbers *h**i*,<=*v**i* (1<=≤<=*h**i*,<=*v**i*<=≤<=*n*), separated by a space, and meaning that the inte... | In the single line print the numbers of the days when road works will be in progress in ascending order. The days are numbered starting from 1. | [
"2\n1 1\n1 2\n2 1\n2 2\n",
"1\n1 1\n"
] | [
"1 4 \n",
"1 \n"
] | In the sample the brigade acts like that:
1. On the first day the brigade comes to the intersection of the 1-st horizontal and the 1-st vertical road. As none of them has been asphalted, the workers asphalt the 1-st vertical and the 1-st horizontal road; 1. On the second day the brigade of the workers comes to the i... | 500 | [
{
"input": "2\n1 1\n1 2\n2 1\n2 2",
"output": "1 4 "
},
{
"input": "1\n1 1",
"output": "1 "
},
{
"input": "2\n1 1\n2 2\n1 2\n2 1",
"output": "1 2 "
},
{
"input": "2\n1 2\n2 2\n2 1\n1 1",
"output": "1 3 "
},
{
"input": "3\n2 2\n1 2\n3 2\n3 3\n1 1\n2 3\n1 3\n3 1\n2 ... | 1,443,890,959 | 259 | PyPy 3 | OK | TESTS | 39 | 217 | 5,222,400 | n=int(input())
sc=[]
for i in range(n**2):
sc.append(list(map(int,input().split(' '))))
x=[]
y=[]
for i in range(n):
x.append(i+1)
y.append(i+1)
for j in range(len(sc)):
if sc[j][0] in x:
if sc[j][1] in y:
x.remove(sc[j][0])
y.remove(sc[j][1])
pr... | Title: Asphalting Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers ... | ```python
n=int(input())
sc=[]
for i in range(n**2):
sc.append(list(map(int,input().split(' '))))
x=[]
y=[]
for i in range(n):
x.append(i+1)
y.append(i+1)
for j in range(len(sc)):
if sc[j][0] in x:
if sc[j][1] in y:
x.remove(sc[j][0])
y.remove(sc[j][1])
... | 3 | |
551 | A | GukiZ and Contest | PROGRAMMING | 800 | [
"brute force",
"implementation",
"sortings"
] | null | null | Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*). | In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input. | [
"3\n1 3 3\n",
"1\n1\n",
"5\n3 5 3 4 5\n"
] | [
"3 1 1\n",
"1\n",
"4 1 4 3 1\n"
] | In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first positi... | 500 | [
{
"input": "3\n1 3 3",
"output": "3 1 1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n3 5 3 4 5",
"output": "4 1 4 3 1"
},
{
"input": "7\n1 3 5 4 2 2 1",
"output": "6 3 1 2 4 4 6"
},
{
"input": "11\n5 6 4 2 9 7 6 6 6 6 7",
"output": "9 4 10 11 1 2 4 4... | 1,640,331,224 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 1,200 | 8,396,800 | # import sys
# sys.stdout = open('DSA/Stacks/output.txt', 'w')
# sys.stdin = open('DSA/Stacks/input.txt', 'r')
n = int(input())
ll = list(map(int, input().split()))
aa = []
for i in range(len(ll)):
curr = ll[i]
count = 0
for j in range(len(ll)):
if ll[j]>curr:
count+=1
... | Title: GukiZ and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the star... | ```python
# import sys
# sys.stdout = open('DSA/Stacks/output.txt', 'w')
# sys.stdin = open('DSA/Stacks/input.txt', 'r')
n = int(input())
ll = list(map(int, input().split()))
aa = []
for i in range(len(ll)):
curr = ll[i]
count = 0
for j in range(len(ll)):
if ll[j]>curr:
coun... | 3 | |
20 | B | Equation | PROGRAMMING | 2,000 | [
"math"
] | B. Equation | 1 | 256 | You are given an equation:
Your task is to find the number of distinct roots of the equation and print all of them in ascending order. | The first line contains three integer numbers *A*,<=*B* and *C* (<=-<=105<=≤<=*A*,<=*B*,<=*C*<=≤<=105). Any coefficient may be equal to 0. | In case of infinite root count print the only integer -1. In case of no roots print the only integer 0. In other cases print the number of root on the first line and the roots on the following lines in the ascending order. Print roots with at least 5 digits after the decimal point. | [
"1 -5 6\n"
] | [
"2\n2.0000000000\n3.0000000000"
] | none | 1,000 | [
{
"input": "1 -5 6",
"output": "2\n2.0000000000\n3.0000000000"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 2 1",
"output": "1\n-1.0000000000"
},
{
"input": "0 0 0",
"output": "-1"
},
{
"input": "0 -2 1",
"output": "1\n0.5000000000"
},
{
"inpu... | 1,627,650,439 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import math
a = int(input())
b = int(input())
c = int(input())
if a == b == c == 0:
print(-1)
if a == b == 0 != c or a == c == 0 != b:
print(0)
if a == 0 != b
print(1)
print(-c/b)
else:
print(2)
print((-b - math.sqrt(b**2 - (4*a*c)))/2*a)
print((-b + math.sqrt(b**2 - (4*a*c)))/2*a)
| Title: Equation
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given an equation:
Your task is to find the number of distinct roots of the equation and print all of them in ascending order.
Input Specification:
The first line contains three integer numbers *A*,<=*B* and *C* (<=-<=1... | ```python
import math
a = int(input())
b = int(input())
c = int(input())
if a == b == c == 0:
print(-1)
if a == b == 0 != c or a == c == 0 != b:
print(0)
if a == 0 != b
print(1)
print(-c/b)
else:
print(2)
print((-b - math.sqrt(b**2 - (4*a*c)))/2*a)
print((-b + math.sqrt(b**2 - (4*a*c)))... | -1 |
Subsets and Splits
Successful Python Submissions
Retrieves all records from the train dataset where the verdict is 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Retrieves records of users with a rating of 1600 or higher and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a rating above 2000 and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a 'OK' verdict, providing a basic overview of a specific category within the dataset.