contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,646,170,421 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | n = input()
u = 0
l = 0
for i in range(len(n)):
if n[i].isupper():
u += 1
else:
l += 1
if u > l:
print(''.join(n).upper())
else:
print(''.join(n).lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
n = input()
u = 0
l = 0
for i in range(len(n)):
if n[i].isupper():
u += 1
else:
l += 1
if u > l:
print(''.join(n).upper())
else:
print(''.join(n).lower())
``` | 3.977 |
624 | A | Save Luke | PROGRAMMING | 800 | [
"math"
] | null | null | Luke Skywalker got locked up in a rubbish shredder between two presses. R2D2 is already working on his rescue, but Luke needs to stay alive as long as possible. For simplicity we will assume that everything happens on a straight line, the presses are initially at coordinates 0 and *L*, and they move towards each other ... | The first line of the input contains four integers *d*, *L*, *v*1, *v*2 (1<=≤<=*d*,<=*L*,<=*v*1,<=*v*2<=≤<=10<=000,<=*d*<=<<=*L*) — Luke's width, the initial position of the second press and the speed of the first and second presses, respectively. | Print a single real value — the maximum period of time Luke can stay alive for. Your answer will be considered correct if its absolute or relative error does not exceed 10<=-<=6.
Namely: let's assume that your answer is *a*, and the answer of the jury is *b*. The checker program will consider your answer correct, if ... | [
"2 6 2 2\n",
"1 9 1 2\n"
] | [
"1.00000000000000000000\n",
"2.66666666666666650000\n"
] | In the first sample Luke should stay exactly in the middle of the segment, that is at coordinates [2;4], as the presses move with the same speed.
In the second sample he needs to occupy the position <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/71395c777960eaded59a9fdc428a9625f152605b.pn... | 500 | [
{
"input": "2 6 2 2",
"output": "1.00000000000000000000"
},
{
"input": "1 9 1 2",
"output": "2.66666666666666650000"
},
{
"input": "1 10000 1 1",
"output": "4999.50000000000000000000"
},
{
"input": "9999 10000 10000 10000",
"output": "0.00005000000000000000"
},
{
... | 1,454,605,647 | 147 | Python 3 | COMPILATION_ERROR | PRETESTS | 0 | 0 | 0 | #pragma region Header
#include <fstream>
#include <vector>
#include <string>
#include <algorithm>
#include <set>
#include <map>
#include <queue>
#include <iomanip>
#include <cstdlib>
#include <stdio.h>
#include <ctime>
#include <stack>
#include <sstream>
#include<iostream>
#include <functional>
#def... | Title: Save Luke
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luke Skywalker got locked up in a rubbish shredder between two presses. R2D2 is already working on his rescue, but Luke needs to stay alive as long as possible. For simplicity we will assume that everything happens on a strai... | ```python
#pragma region Header
#include <fstream>
#include <vector>
#include <string>
#include <algorithm>
#include <set>
#include <map>
#include <queue>
#include <iomanip>
#include <cstdlib>
#include <stdio.h>
#include <ctime>
#include <stack>
#include <sstream>
#include<iostream>
#include <functional... | -1 | |
219 | A | k-String | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
You are given a string... | The first input line contains integer *k* (1<=≤<=*k*<=≤<=1000). The second line contains *s*, all characters in *s* are lowercase English letters. The string length *s* satisfies the inequality 1<=≤<=|*s*|<=≤<=1000, where |*s*| is the length of string *s*. | Rearrange the letters in string *s* in such a way that the result is a *k*-string. Print the result on a single output line. If there are multiple solutions, print any of them.
If the solution doesn't exist, print "-1" (without quotes). | [
"2\naazz\n",
"3\nabcabcabz\n"
] | [
"azaz\n",
"-1\n"
] | none | 500 | [
{
"input": "2\naazz",
"output": "azaz"
},
{
"input": "3\nabcabcabz",
"output": "-1"
},
{
"input": "1\na",
"output": "a"
},
{
"input": "2\nabba",
"output": "abab"
},
{
"input": "2\naaab",
"output": "-1"
},
{
"input": "7\nabacaba",
"output": "-1"
}... | 1,672,428,761 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | # -*- coding: utf-8 -*-
"""
Created on Fri Dec 30 16:17:42 2022
@author: Lenovo
"""
k = int(input())
x = input()
s=[]
for i in x:
s.append(i)
s = sorted(s)
if len(s)>1:
a = s[0]
j=1
val = [a]
dif = []
for i in range(1,len(s)):
if s[i]!=a:
dif.append(j)... | Title: k-String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a ... | ```python
# -*- coding: utf-8 -*-
"""
Created on Fri Dec 30 16:17:42 2022
@author: Lenovo
"""
k = int(input())
x = input()
s=[]
for i in x:
s.append(i)
s = sorted(s)
if len(s)>1:
a = s[0]
j=1
val = [a]
dif = []
for i in range(1,len(s)):
if s[i]!=a:
dif... | 3 | |
235 | A | LCM Challenge | PROGRAMMING | 1,600 | [
"number theory"
] | null | null | Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive integers (they don't have to be distinct) which are not greater than *n*. Can you help me to find ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the *n* mentioned in the statement. | Print a single integer — the maximum possible LCM of three not necessarily distinct positive integers that are not greater than *n*. | [
"9\n",
"7\n"
] | [
"504\n",
"210\n"
] | The least common multiple of some positive integers is the least positive integer which is multiple for each of them.
The result may become very large, 32-bit integer won't be enough. So using 64-bit integers is recommended.
For the last example, we can chose numbers 7, 6, 5 and the LCM of them is 7·6·5 = 210. It is ... | 500 | [
{
"input": "9",
"output": "504"
},
{
"input": "7",
"output": "210"
},
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "60"
},
{
"input": "33",
"output": "32736"
},
{
"input": "21",
"output": ... | 1,527,561,536 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 154 | 0 | def gcd(a, b):
if a == 0:
return b
return gcd(b%a, a)
n = int(input())
ans = int((n * (n - 1))/gcd(n, n - 1))
ans = int((ans * (n - 2))/gcd(ans, n - 2))
print(int(ans))
| Title: LCM Challenge
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive... | ```python
def gcd(a, b):
if a == 0:
return b
return gcd(b%a, a)
n = int(input())
ans = int((n * (n - 1))/gcd(n, n - 1))
ans = int((ans * (n - 2))/gcd(ans, n - 2))
print(int(ans))
``` | 0 | |
900 | D | Unusual Sequences | PROGRAMMING | 2,000 | [
"bitmasks",
"combinatorics",
"dp",
"math",
"number theory"
] | null | null | Count the number of distinct sequences *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*) consisting of positive integers such that *gcd*(*a*1,<=*a*2,<=...,<=*a**n*)<==<=*x* and . As this number could be large, print the answer modulo 109<=+<=7.
*gcd* here means the [greatest common divisor](https://en.wikipedia.org/wiki/Great... | The only line contains two positive integers *x* and *y* (1<=≤<=*x*,<=*y*<=≤<=109). | Print the number of such sequences modulo 109<=+<=7. | [
"3 9\n",
"5 8\n"
] | [
"3\n",
"0\n"
] | There are three suitable sequences in the first test: (3, 3, 3), (3, 6), (6, 3).
There are no suitable sequences in the second test. | 2,000 | [
{
"input": "3 9",
"output": "3"
},
{
"input": "5 8",
"output": "0"
},
{
"input": "2 12",
"output": "27"
},
{
"input": "1 8",
"output": "120"
},
{
"input": "1 9",
"output": "252"
},
{
"input": "1000000000 1000000000",
"output": "1"
},
{
"inp... | 1,531,646,548 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int mod = 1e9 + 7;
int x, y;
int cnt;
ll di[1000000], ans[1000000];
ll qpow(ll a, ll b) {
ll ret = 1;
while (b) {
if (b % 2) {
ret *= a;
ret %= mod;
}
b /= 2;
a = a * a % mod;
}
... | Title: Unusual Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Count the number of distinct sequences *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*) consisting of positive integers such that *gcd*(*a*1,<=*a*2,<=...,<=*a**n*)<==<=*x* and . As this number could be large, print the answe... | ```python
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int mod = 1e9 + 7;
int x, y;
int cnt;
ll di[1000000], ans[1000000];
ll qpow(ll a, ll b) {
ll ret = 1;
while (b) {
if (b % 2) {
ret *= a;
ret %= mod;
}
b /= 2;
a = a * a % m... | -1 | |
719 | A | Vitya in the Countryside | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Every summer Vitya comes to visit his grandmother in the countryside. This summer, he got a huge wart. Every grandma knows that one should treat warts when the moon goes down. Thus, Vitya has to catch the moment when the moon is down.
Moon cycle lasts 30 days. The size of the visible part of the moon (in Vitya's units... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=92) — the number of consecutive days Vitya was watching the size of the visible part of the moon.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=15) — Vitya's records.
It's guaranteed that the input data is consistent. | If Vitya can be sure that the size of visible part of the moon on day *n*<=+<=1 will be less than the size of the visible part on day *n*, then print "DOWN" at the only line of the output. If he might be sure that the size of the visible part will increase, then print "UP". If it's impossible to determine what exactly ... | [
"5\n3 4 5 6 7\n",
"7\n12 13 14 15 14 13 12\n",
"1\n8\n"
] | [
"UP\n",
"DOWN\n",
"-1\n"
] | In the first sample, the size of the moon on the next day will be equal to 8, thus the answer is "UP".
In the second sample, the size of the moon on the next day will be 11, thus the answer is "DOWN".
In the third sample, there is no way to determine whether the size of the moon on the next day will be 7 or 9, thus t... | 500 | [
{
"input": "5\n3 4 5 6 7",
"output": "UP"
},
{
"input": "7\n12 13 14 15 14 13 12",
"output": "DOWN"
},
{
"input": "1\n8",
"output": "-1"
},
{
"input": "44\n7 8 9 10 11 12 13 14 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 14 13 12 11 10",
"out... | 1,474,636,321 | 421 | Python 3 | OK | TESTS | 56 | 62 | 0 | arr = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1]
n = int(input())
prr = [int(x) for x in input().split()]
if(n==1):
a = prr[0]
if(a==0):
print('UP')
elif(a==15):
print('DOWN')
else:
print(-1)
else:
a,b =... | Title: Vitya in the Countryside
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Every summer Vitya comes to visit his grandmother in the countryside. This summer, he got a huge wart. Every grandma knows that one should treat warts when the moon goes down. Thus, Vitya has to catch the momen... | ```python
arr = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1]
n = int(input())
prr = [int(x) for x in input().split()]
if(n==1):
a = prr[0]
if(a==0):
print('UP')
elif(a==15):
print('DOWN')
else:
print(-1)
else:
... | 3 | |
557 | B | Pasha and Tea | PROGRAMMING | 1,500 | [
"constructive algorithms",
"implementation",
"math",
"sortings"
] | null | null | Pasha decided to invite his friends to a tea party. For that occasion, he has a large teapot with the capacity of *w* milliliters and 2*n* tea cups, each cup is for one of Pasha's friends. The *i*-th cup can hold at most *a**i* milliliters of water.
It turned out that among Pasha's friends there are exactly *n* boys a... | The first line of the input contains two integers, *n* and *w* (1<=≤<=*n*<=≤<=105, 1<=≤<=*w*<=≤<=109) — the number of Pasha's friends that are boys (equal to the number of Pasha's friends that are girls) and the capacity of Pasha's teapot in milliliters.
The second line of the input contains the sequence of integers *... | Print a single real number — the maximum total amount of water in milliliters that Pasha can pour to his friends without violating the given conditions. Your answer will be considered correct if its absolute or relative error doesn't exceed 10<=-<=6. | [
"2 4\n1 1 1 1\n",
"3 18\n4 4 4 2 2 2\n",
"1 5\n2 3\n"
] | [
"3",
"18",
"4.5"
] | Pasha also has candies that he is going to give to girls but that is another task... | 1,000 | [
{
"input": "2 4\n1 1 1 1",
"output": "3.0000000000"
},
{
"input": "3 18\n4 4 4 2 2 2",
"output": "18.0000000000"
},
{
"input": "1 5\n2 3",
"output": "4.5000000000"
},
{
"input": "1 1\n1000000000 1000000000",
"output": "1.0000000000"
},
{
"input": "4 1000000000\n1 ... | 1,437,332,640 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 218 | 16,896,000 | n,w = map(int, input().split(' '))
c = input().split(' ')
c = [int(i) for i in c]
c.sort()
k = min(c[0], c[n]/2) * 3 * n
print(min(k, w))
| Title: Pasha and Tea
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha decided to invite his friends to a tea party. For that occasion, he has a large teapot with the capacity of *w* milliliters and 2*n* tea cups, each cup is for one of Pasha's friends. The *i*-th cup can hold at most ... | ```python
n,w = map(int, input().split(' '))
c = input().split(' ')
c = [int(i) for i in c]
c.sort()
k = min(c[0], c[n]/2) * 3 * n
print(min(k, w))
``` | 3 | |
296 | A | Yaroslav and Permutations | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.
Help Yaroslav. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) — the array elements. | In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise. | [
"1\n1\n",
"3\n1 1 2\n",
"4\n7 7 7 7\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample the initial array fits well.
In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.
In the third sample Yarosav can't get the array he needs. | 500 | [
{
"input": "1\n1",
"output": "YES"
},
{
"input": "3\n1 1 2",
"output": "YES"
},
{
"input": "4\n7 7 7 7",
"output": "NO"
},
{
"input": "4\n479 170 465 146",
"output": "YES"
},
{
"input": "5\n996 437 605 996 293",
"output": "YES"
},
{
"input": "6\n727 53... | 1,591,115,589 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 218 | 307,200 | n = int(input())
arr =list(map(int,input().split()))
c = 0
if(n%2==0):
c = int(n/2)
else:
c = int(n/2)+1
d = {}
for i in arr:
if i in d:
d[i]+=1
else:
d[i] = 1
maxi = d[arr[0]]
for i in d:
if d[i]>maxi:
maxi = d[i]
if(maxi>c):
print("NO")
else:
print("YES")
| Title: Yaroslav and Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would... | ```python
n = int(input())
arr =list(map(int,input().split()))
c = 0
if(n%2==0):
c = int(n/2)
else:
c = int(n/2)+1
d = {}
for i in arr:
if i in d:
d[i]+=1
else:
d[i] = 1
maxi = d[arr[0]]
for i in d:
if d[i]>maxi:
maxi = d[i]
if(maxi>c):
print("NO")
else:
print("YES")
... | 3 | |
867 | A | Between the Offices | PROGRAMMING | 800 | [
"implementation"
] | null | null | As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't rem... | The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given... | Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower). | [
"4\nFSSF\n",
"2\nSF\n",
"10\nFFFFFFFFFF\n",
"10\nSSFFSFFSFF\n"
] | [
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you staye... | 500 | [
{
"input": "4\nFSSF",
"output": "NO"
},
{
"input": "2\nSF",
"output": "YES"
},
{
"input": "10\nFFFFFFFFFF",
"output": "NO"
},
{
"input": "10\nSSFFSFFSFF",
"output": "YES"
},
{
"input": "20\nSFSFFFFSSFFFFSSSSFSS",
"output": "NO"
},
{
"input": "20\nSSFFF... | 1,586,878,539 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 124 | 0 | n=int(input())
f=input()
curr=f[0]
fs=0
sf=0
for i in range(1,n):
if curr=="F":
if f[i]!=curr:
fs+=1
curr=f[i]
if curr=="S":
if f[i]!=curr:
sf+=1
curr=f[i]
print("YES") if sf>fs else print("NO")
| Title: Between the Offices
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Franci... | ```python
n=int(input())
f=input()
curr=f[0]
fs=0
sf=0
for i in range(1,n):
if curr=="F":
if f[i]!=curr:
fs+=1
curr=f[i]
if curr=="S":
if f[i]!=curr:
sf+=1
curr=f[i]
print("YES") if sf>fs else print("NO")
``` | 3 | |
698 | A | Vacations | PROGRAMMING | 1,400 | [
"dp"
] | null | null | Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options:
1. on this day the gym is close... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations.
The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where:
- *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the co... | Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses:
- to do sport on any two consecutive days, - to write the contest on any two consecutive days. | [
"4\n1 3 2 0\n",
"7\n1 3 3 2 1 2 3\n",
"2\n2 2\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days.
In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day.
In the third test Vasya ca... | 500 | [
{
"input": "4\n1 3 2 0",
"output": "2"
},
{
"input": "7\n1 3 3 2 1 2 3",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "10\n0 0 1 1 0 0 0 0 1 0",
"output": "8"
},
{
"input": "100\n3 2 3 3 3 2 3 1 ... | 1,688,958,026 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n=int(input())
l=list(map(int,input().split()))
g,c,r=0,0,0
ng,nc,nr=0,0,0
for x in l:
if x==0:
nr+=1
nc=inf
ng=inf
elif x==1:
nc=min(r,g)
ng=inf
nr=min(r,c,g)+1
elif x==2:
ng=min(r,c)
nc=inf
nr=min(r,c,g)+1
else:
... | Title: Vacations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Int... | ```python
n=int(input())
l=list(map(int,input().split()))
g,c,r=0,0,0
ng,nc,nr=0,0,0
for x in l:
if x==0:
nr+=1
nc=inf
ng=inf
elif x==1:
nc=min(r,g)
ng=inf
nr=min(r,c,g)+1
elif x==2:
ng=min(r,c)
nc=inf
nr=min(r,c,g)+1
... | -1 | |
139 | A | Petr and Book | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. S... | The first input line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of pages in the book.
The second line contains seven non-negative space-separated integers that do not exceed 1000 — those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and... | Print a single number — the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. | [
"100\n15 20 20 15 10 30 45\n",
"2\n1 0 0 0 0 0 0\n"
] | [
"6\n",
"1\n"
] | Note to the first sample:
By the end of Monday and therefore, by the beginning of Tuesday Petr has 85 pages left. He has 65 pages left by Wednesday, 45 by Thursday, 30 by Friday, 20 by Saturday and on Saturday Petr finishes reading the book (and he also has time to read 10 pages of something else).
Note to the second... | 500 | [
{
"input": "100\n15 20 20 15 10 30 45",
"output": "6"
},
{
"input": "2\n1 0 0 0 0 0 0",
"output": "1"
},
{
"input": "100\n100 200 100 200 300 400 500",
"output": "1"
},
{
"input": "3\n1 1 1 1 1 1 1",
"output": "3"
},
{
"input": "1\n1 1 1 1 1 1 1",
"output": "1... | 1,600,181,585 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 218 | 0 |
def main():
n = int(input())
arr = [int(x) for x in input().split()]
sum = 0
i = 0
while sum < n:
if i == 7:
i = 0
sum+=arr[i]
i+=1
print(i)
return
main() | Title: Petr and Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight s... | ```python
def main():
n = int(input())
arr = [int(x) for x in input().split()]
sum = 0
i = 0
while sum < n:
if i == 7:
i = 0
sum+=arr[i]
i+=1
print(i)
return
main()
``` | 3 | |
34 | A | Reconnaissance 2 | PROGRAMMING | 800 | [
"implementation"
] | A. Reconnaissance 2 | 2 | 256 | *n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a ... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). The soldier heights are given in clockwise or counterclockwise direction. | Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle. | [
"5\n10 12 13 15 10\n",
"4\n10 20 30 40\n"
] | [
"5 1\n",
"1 2\n"
] | none | 500 | [
{
"input": "5\n10 12 13 15 10",
"output": "5 1"
},
{
"input": "4\n10 20 30 40",
"output": "1 2"
},
{
"input": "6\n744 359 230 586 944 442",
"output": "2 3"
},
{
"input": "5\n826 747 849 687 437",
"output": "1 2"
},
{
"input": "5\n999 999 993 969 999",
"output"... | 1,595,502,775 | 2,147,483,647 | PyPy 3 | OK | TESTS | 20 | 280 | 20,172,800 | import sys
def input(): return sys.stdin.readline().strip()
def iinput(): return int(input())
def rinput(): return map(int, sys.stdin.readline().strip().split())
def get_list(): return list(map(int, sys.stdin.readline().strip().split()))
n=iinput()
a=list(map(int,input().split()))
b=[]
c=[]
for ... | Title: Reconnaissance 2
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
*n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So... | ```python
import sys
def input(): return sys.stdin.readline().strip()
def iinput(): return int(input())
def rinput(): return map(int, sys.stdin.readline().strip().split())
def get_list(): return list(map(int, sys.stdin.readline().strip().split()))
n=iinput()
a=list(map(int,input().split()))
b=[]
... | 3.892425 |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,651,400,293 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | a=input()
b=input()
sta=1
for i in range(len(a)):
if a[i]!=b[-i]:
sta=0
break
if sta==0:
print("NO")
else:
print("YES") | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
a=input()
b=input()
sta=1
for i in range(len(a)):
if a[i]!=b[-i]:
sta=0
break
if sta==0:
print("NO")
else:
print("YES")
``` | 0 |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,596,385,627 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 77 | 6,963,200 | z=list(map(int,input().split()))
if z[0]+z[1]<z[2]:
print(z[0]*2+z[1]*2)
if z[0]>z[1]+z[2]:
print(z[1]*2+z[2]*2)
if z[1]>z[0]+z[2]:
print(z[0]*2+z[2]*2)
else:
print(z[0]+z[1]+z[2]) | Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
z=list(map(int,input().split()))
if z[0]+z[1]<z[2]:
print(z[0]*2+z[1]*2)
if z[0]>z[1]+z[2]:
print(z[1]*2+z[2]*2)
if z[1]>z[0]+z[2]:
print(z[0]*2+z[2]*2)
else:
print(z[0]+z[1]+z[2])
``` | 0 | |
658 | A | Bear and Reverse Radewoosh | PROGRAMMING | 800 | [
"implementation"
] | null | null | Limak and Radewoosh are going to compete against each other in the upcoming algorithmic contest. They are equally skilled but they won't solve problems in the same order.
There will be *n* problems. The *i*-th problem has initial score *p**i* and it takes exactly *t**i* minutes to solve it. Problems are sorted by diff... | The first line contains two integers *n* and *c* (1<=≤<=*n*<=≤<=50,<=1<=≤<=*c*<=≤<=1000) — the number of problems and the constant representing the speed of loosing points.
The second line contains *n* integers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=1000,<=*p**i*<=<<=*p**i*<=+<=1) — initial scores.
The third... | Print "Limak" (without quotes) if Limak will get more points in total. Print "Radewoosh" (without quotes) if Radewoosh will get more points in total. Print "Tie" (without quotes) if Limak and Radewoosh will get the same total number of points. | [
"3 2\n50 85 250\n10 15 25\n",
"3 6\n50 85 250\n10 15 25\n",
"8 1\n10 20 30 40 50 60 70 80\n8 10 58 63 71 72 75 76\n"
] | [
"Limak\n",
"Radewoosh\n",
"Tie\n"
] | In the first sample, there are 3 problems. Limak solves them as follows:
1. Limak spends 10 minutes on the 1-st problem and he gets 50 - *c*·10 = 50 - 2·10 = 30 points. 1. Limak spends 15 minutes on the 2-nd problem so he submits it 10 + 15 = 25 minutes after the start of the contest. For the 2-nd problem he gets 85... | 500 | [
{
"input": "3 2\n50 85 250\n10 15 25",
"output": "Limak"
},
{
"input": "3 6\n50 85 250\n10 15 25",
"output": "Radewoosh"
},
{
"input": "8 1\n10 20 30 40 50 60 70 80\n8 10 58 63 71 72 75 76",
"output": "Tie"
},
{
"input": "4 1\n3 5 6 9\n1 2 4 8",
"output": "Limak"
},
{... | 1,583,730,475 | 2,147,483,647 | PyPy 3 | OK | TESTS | 29 | 140 | 0 | n, c = input().split()
n, c = int(n), int(c)
t1 = 0
t2 = 0
s1 = 0
s2 = 0
p = input().split()
t = input().split()
for i in range(n):
t1 += int(t[i])
t2 += int(t[n - 1 - i])
s1 += max(0, int(p[i]) - (c * t1))
s2 += max(0, int(p[n - 1 - i]) - (c * t2))
if s1 > s2:
print("Limak")
elif s1 ... | Title: Bear and Reverse Radewoosh
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak and Radewoosh are going to compete against each other in the upcoming algorithmic contest. They are equally skilled but they won't solve problems in the same order.
There will be *n* problems. The *i*-... | ```python
n, c = input().split()
n, c = int(n), int(c)
t1 = 0
t2 = 0
s1 = 0
s2 = 0
p = input().split()
t = input().split()
for i in range(n):
t1 += int(t[i])
t2 += int(t[n - 1 - i])
s1 += max(0, int(p[i]) - (c * t1))
s2 += max(0, int(p[n - 1 - i]) - (c * t2))
if s1 > s2:
print("Limak")... | 3 | |
745 | B | Hongcow Solves A Puzzle | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Hongcow likes solving puzzles.
One day, Hongcow finds two identical puzzle pieces, with the instructions "make a rectangle" next to them. The pieces can be described by an *n* by *m* grid of characters, where the character 'X' denotes a part of the puzzle and '.' denotes an empty part of the grid. It is guaranteed tha... | The first line of input will contain two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=500), the dimensions of the puzzle piece.
The next *n* lines will describe the jigsaw piece. Each line will have length *m* and will consist of characters '.' and 'X' only. 'X' corresponds to a part of the puzzle piece, '.' is an empty ... | Output "YES" if it is possible for Hongcow to make a rectangle. Output "NO" otherwise. | [
"2 3\nXXX\nXXX\n",
"2 2\n.X\nXX\n",
"5 5\n.....\n..X..\n.....\n.....\n.....\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | For the first sample, one example of a rectangle we can form is as follows
For the second sample, it is impossible to put two of those pieces without rotating or flipping to form a rectangle.
In the third sample, we can shift the first tile by one to the right, and then compose the following rectangle: | 1,000 | [
{
"input": "2 3\nXXX\nXXX",
"output": "YES"
},
{
"input": "2 2\n.X\nXX",
"output": "NO"
},
{
"input": "1 500\n.XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX... | 1,481,996,334 | 3,834 | Python 3 | CHALLENGED | CHALLENGES | 7 | 93 | 5,222,400 | n, m = input().split()
n = int(n)
m = int(m)
rectangle = []
for i in range(n):
rectangle.append(input())
p = 0
for i in rectangle:
k = 0
for j in i:
if j == 'X':
k += 1
if p == 0:
p = k
else:
if (p != k) and (k != 0):
print('NO')
... | Title: Hongcow Solves A Puzzle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hongcow likes solving puzzles.
One day, Hongcow finds two identical puzzle pieces, with the instructions "make a rectangle" next to them. The pieces can be described by an *n* by *m* grid of characters, where t... | ```python
n, m = input().split()
n = int(n)
m = int(m)
rectangle = []
for i in range(n):
rectangle.append(input())
p = 0
for i in rectangle:
k = 0
for j in i:
if j == 'X':
k += 1
if p == 0:
p = k
else:
if (p != k) and (k != 0):
print('N... | -1 | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,692,153,663 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | n = list(map(int, input().split()))
print(4 - len(set(n))) | Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
n = list(map(int, input().split()))
print(4 - len(set(n)))
``` | 3 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,616,140,003 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 307,200 | s=input()
l=[]
i=0
while(i<=len(s)-1):
if(s[i]=='.'):
l.append('0')
elif(s[i]=='-' and s[i+1]=='.'):
l.append('1')
i=i+1
elif(s[i]=='-' and s[i+1]=='-'):
l.append('2')
i=i+1
i=i+1
for i in l:
print(i,end="")
| Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
s=input()
l=[]
i=0
while(i<=len(s)-1):
if(s[i]=='.'):
l.append('0')
elif(s[i]=='-' and s[i+1]=='.'):
l.append('1')
i=i+1
elif(s[i]=='-' and s[i+1]=='-'):
l.append('2')
i=i+1
i=i+1
for i in l:
print(i,end="")
``` | 3.968428 |
294 | A | Shaass and Oskols | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Shaass has decided to hunt some birds. There are *n* horizontal electricity wires aligned parallel to each other. Wires are numbered 1 to *n* from top to bottom. On each wire there are some oskols sitting next to each other. Oskol is the name of a delicious kind of birds in Shaass's territory. Supposed there are *a**i*... | The first line of the input contains an integer *n*, (1<=≤<=*n*<=≤<=100). The next line contains a list of space-separated integers *a*1,<=*a*2,<=...,<=*a**n*, (0<=≤<=*a**i*<=≤<=100).
The third line contains an integer *m*, (0<=≤<=*m*<=≤<=100). Each of the next *m* lines contains two integers *x**i* and *y**i*. The i... | On the *i*-th line of the output print the number of birds on the *i*-th wire. | [
"5\n10 10 10 10 10\n5\n2 5\n3 13\n2 12\n1 13\n4 6\n",
"3\n2 4 1\n1\n2 2\n"
] | [
"0\n12\n5\n0\n16\n",
"3\n0\n3\n"
] | none | 500 | [
{
"input": "5\n10 10 10 10 10\n5\n2 5\n3 13\n2 12\n1 13\n4 6",
"output": "0\n12\n5\n0\n16"
},
{
"input": "3\n2 4 1\n1\n2 2",
"output": "3\n0\n3"
},
{
"input": "5\n58 51 45 27 48\n5\n4 9\n5 15\n4 5\n5 8\n1 43",
"output": "0\n66\n57\n7\n0"
},
{
"input": "10\n48 53 10 28 91 56 8... | 1,590,671,696 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 404 | 2,048,000 | n=int(input())
l=[int(x) for x in input().split(" ")[:n]]
m=int(input())
for i in range(m):
x,y=map(int,input().split(" "))
if x-2>=0:
l[x-2]=l[x-2]+y-1
l[x]=l[x]+abs(l[x-1]-y)
l[x-1]=0
for i in l:
print(i)
| Title: Shaass and Oskols
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Shaass has decided to hunt some birds. There are *n* horizontal electricity wires aligned parallel to each other. Wires are numbered 1 to *n* from top to bottom. On each wire there are some oskols sitting next to each... | ```python
n=int(input())
l=[int(x) for x in input().split(" ")[:n]]
m=int(input())
for i in range(m):
x,y=map(int,input().split(" "))
if x-2>=0:
l[x-2]=l[x-2]+y-1
l[x]=l[x]+abs(l[x-1]-y)
l[x-1]=0
for i in l:
print(i)
``` | -1 | |
358 | B | Dima and Text Messages | PROGRAMMING | 1,500 | [
"brute force",
"strings"
] | null | null | Seryozha has a very changeable character. This time he refused to leave the room to Dima and his girlfriend (her hame is Inna, by the way). However, the two lovebirds can always find a way to communicate. Today they are writing text messages to each other.
Dima and Inna are using a secret code in their text messages. ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of words in Dima's message. Next *n* lines contain non-empty words, one word per line. The words only consist of small English letters. The total length of all words doesn't exceed 105.
The last line contains non-empty text message that Inna has got... | In a single line, print "yes" (without the quotes), if Dima decoded the text message correctly, and "no" (without the quotes) otherwise. | [
"3\ni\nlove\nyou\n<3i<3love<23you<3\n",
"7\ni\nam\nnot\nmain\nin\nthe\nfamily\n<3i<>3am<3the<3<main<3in<3the<3><3family<3\n"
] | [
"yes\n",
"no\n"
] | Please note that Dima got a good old kick in the pants for the second sample from the statement. | 1,000 | [
{
"input": "3\ni\nlove\nyou\n<3i<3love<23you<3",
"output": "yes"
},
{
"input": "7\ni\nam\nnot\nmain\nin\nthe\nfamily\n<3i<>3am<3the<3<main<3in<3the<3><3family<3",
"output": "no"
},
{
"input": "3\ni\nlove\nyou\n<3i<3lo<3ve<3y<<<<<<<ou3<3",
"output": "yes"
},
{
"input": "4\na\n... | 1,528,746,104 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | a=""
for _ in range(int(input())):
os=input()
a+=os
s=input()
st=""
pre=0
for i in range(2,len(s)-1):
#print(ord(s[i]))
if ord(s[i])<97 or ord(s[i])>122:
if ord(s[i-1])>=97 and ord(s[i-1])<=122:
st+=s[pre:i]
pre=i-1
else:
if ord(s[i-1])<97 or ord... | Title: Dima and Text Messages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Seryozha has a very changeable character. This time he refused to leave the room to Dima and his girlfriend (her hame is Inna, by the way). However, the two lovebirds can always find a way to communicate. Today t... | ```python
a=""
for _ in range(int(input())):
os=input()
a+=os
s=input()
st=""
pre=0
for i in range(2,len(s)-1):
#print(ord(s[i]))
if ord(s[i])<97 or ord(s[i])>122:
if ord(s[i-1])>=97 and ord(s[i-1])<=122:
st+=s[pre:i]
pre=i-1
else:
if ord(s[i-1])... | 0 | |
142 | C | Help Caretaker | PROGRAMMING | 2,300 | [
"brute force",
"dp"
] | null | null | Autumn came late to the kingdom of Far Far Away. The harvest was exuberant and it is now time to get ready for the winter. As most people celebrate the Harvest festival, Simon the Caretaker tries to solve a very non-trivial task of how to find place for the agricultural equipment in the warehouse.
He's got problems wi... | The only line contains two space-separated integers *n* and *m* — the sizes of the warehouse (1<=≤<=*n*,<=*m*<=≤<=9). | In the first line print the maximum number of turboplows that can be positioned in the warehouse. In each of the next *n* lines print *m* characters. Use "." (dot) to mark empty space and use successive capital Latin letters ("A" for the first turboplow, "B" for the second one and so on until you reach the number of tu... | [
"3 3\n",
"5 6\n",
"2 2\n"
] | [
"1\nAAA\n.A.\n.A.\n",
"4\nA..C..\nAAAC..\nABCCCD\n.B.DDD\nBBB..D\n",
"0\n..\n..\n"
] | none | 1,500 | [
{
"input": "3 3",
"output": "1\nAAA\n.A.\n.A."
},
{
"input": "5 6",
"output": "4\nA..C..\nAAAC..\nABCCCD\n.B.DDD\nBBB..D"
},
{
"input": "2 2",
"output": "0\n..\n.."
},
{
"input": "4 2",
"output": "0\n..\n..\n..\n.."
},
{
"input": "3 4",
"output": "1\nA...\nAAA... | 1,628,860,698 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 154 | 6,963,200 | import sys
input = sys.stdin.readline
def rec(x, y, v):
if y == m:
x += 1
if x == n:
return 0
y = 0
if (1<<(x*m+y)) & v == 0:
res = (-1,-1)
if y + 2 < m:
if x + 2 < n:
z = ((7<<(x*m+y))|(2<<(x*m+y+m))|(2<<((x+2)*m+y)))
if v & z == 0:
res = max(res, (rec(x, y + 1, v | z), v | z))
if x... | Title: Help Caretaker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Autumn came late to the kingdom of Far Far Away. The harvest was exuberant and it is now time to get ready for the winter. As most people celebrate the Harvest festival, Simon the Caretaker tries to solve a very non-triv... | ```python
import sys
input = sys.stdin.readline
def rec(x, y, v):
if y == m:
x += 1
if x == n:
return 0
y = 0
if (1<<(x*m+y)) & v == 0:
res = (-1,-1)
if y + 2 < m:
if x + 2 < n:
z = ((7<<(x*m+y))|(2<<(x*m+y+m))|(2<<((x+2)*m+y)))
if v & z == 0:
res = max(res, (rec(x, y + 1, v | z), v | z... | 0 | |
822 | A | I'm bored with life | PROGRAMMING | 800 | [
"implementation",
"math",
"number theory"
] | null | null | Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopo... | The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12). | Print a single integer denoting the greatest common divisor of integers *A*! and *B*!. | [
"4 3\n"
] | [
"6\n"
] | Consider the sample.
4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6. | 500 | [
{
"input": "4 3",
"output": "6"
},
{
"input": "10 399603090",
"output": "3628800"
},
{
"input": "6 973151934",
"output": "720"
},
{
"input": "2 841668075",
"output": "2"
},
{
"input": "7 415216919",
"output": "5040"
},
{
"input": "3 283733059",
"ou... | 1,695,360,368 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 1 | 1,000 | 14,848,000 | import math
a=x,y = [int(x) for x in input().split()]
print(math.gcd(math.factorial(x),math.factorial(y))) | Title: I'm bored with life
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormi... | ```python
import math
a=x,y = [int(x) for x in input().split()]
print(math.gcd(math.factorial(x),math.factorial(y)))
``` | 0 | |
318 | A | Even Odds | PROGRAMMING | 900 | [
"math"
] | null | null | Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first *n*. He writes down the follow... | The only line of input contains integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. | Print the number that will stand at the position number *k* after Volodya's manipulations. | [
"10 3\n",
"7 7\n"
] | [
"5",
"6"
] | In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5. | 500 | [
{
"input": "10 3",
"output": "5"
},
{
"input": "7 7",
"output": "6"
},
{
"input": "7 1",
"output": "1"
},
{
"input": "7 2",
"output": "3"
},
{
"input": "8 5",
"output": "2"
},
{
"input": "8 3",
"output": "5"
},
{
"input": "8 4",
"output... | 1,694,766,488 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | n,k = map(int,input().split())
a = n//2+n%2
if a<k:
answer=((k-a)*2)
elif a>k:
answer=((a+k)-k)
print(answer) | Title: Even Odds
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too ... | ```python
n,k = map(int,input().split())
a = n//2+n%2
if a<k:
answer=((k-a)*2)
elif a>k:
answer=((a+k)-k)
print(answer)
``` | 0 | |
489 | B | BerSU Ball | PROGRAMMING | 1,200 | [
"dfs and similar",
"dp",
"graph matchings",
"greedy",
"sortings",
"two pointers"
] | null | null | The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! *n* boys and *m* girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves.
We know that several boy&girl pairs are going to be invited to the ball. However, the partners' dancing skill in eac... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of boys. The second line contains sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is the *i*-th boy's dancing skill.
Similarly, the third line contains an integer *m* (1<=≤<=*m*<=≤<=100) — the number of girls. The fourth l... | Print a single number — the required maximum possible number of pairs. | [
"4\n1 4 6 2\n5\n5 1 5 7 9\n",
"4\n1 2 3 4\n4\n10 11 12 13\n",
"5\n1 1 1 1 1\n3\n1 2 3\n"
] | [
"3\n",
"0\n",
"2\n"
] | none | 1,000 | [
{
"input": "4\n1 4 6 2\n5\n5 1 5 7 9",
"output": "3"
},
{
"input": "4\n1 2 3 4\n4\n10 11 12 13",
"output": "0"
},
{
"input": "5\n1 1 1 1 1\n3\n1 2 3",
"output": "2"
},
{
"input": "1\n1\n1\n1",
"output": "1"
},
{
"input": "2\n1 10\n1\n9",
"output": "1"
},
{... | 1,678,043,024 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 4 | 46 | 0 | n = int(input())
b = list(map(int,input().split()))
m = int(input())
g = list(map(int,input().split()))
b.sort()
g.sort()
pairs = 0
for i in range(n):
l = -1
r = m
while r-l>1:
mid = (r+l)//2
if g[mid]>=b[i]:
r = mid
else:
l = mid
if abs(b[i] - g[r]) <= ... | Title: BerSU Ball
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! *n* boys and *m* girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves.
We know that several boy... | ```python
n = int(input())
b = list(map(int,input().split()))
m = int(input())
g = list(map(int,input().split()))
b.sort()
g.sort()
pairs = 0
for i in range(n):
l = -1
r = m
while r-l>1:
mid = (r+l)//2
if g[mid]>=b[i]:
r = mid
else:
l = mid
if abs(b[i] -... | -1 | |
873 | B | Balanced Substring | PROGRAMMING | 1,500 | [
"dp",
"implementation"
] | null | null | You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called balanced if the number of zeroes (0) equals to the number of ones in this substring.
You have to deter... | The first line contains *n* (1<=≤<=*n*<=≤<=100000) — the number of characters in *s*.
The second line contains a string *s* consisting of exactly *n* characters. Only characters 0 and 1 can appear in *s*. | If there is no non-empty balanced substring in *s*, print 0. Otherwise, print the length of the longest balanced substring. | [
"8\n11010111\n",
"3\n111\n"
] | [
"4\n",
"0\n"
] | In the first example you can choose the substring [3, 6]. It is balanced, and its length is 4. Choosing the substring [2, 5] is also possible.
In the second example it's impossible to find a non-empty balanced substring. | 0 | [
{
"input": "8\n11010111",
"output": "4"
},
{
"input": "3\n111",
"output": "0"
},
{
"input": "11\n00001000100",
"output": "2"
},
{
"input": "10\n0100000000",
"output": "2"
},
{
"input": "13\n0001000011010",
"output": "6"
},
{
"input": "14\n0000010010101... | 1,662,193,513 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 19 | 139 | 5,120,000 | from collections import Counter
import sys
sys.setrecursionlimit(10000)
n = int(input())
string = input()
memo = {}
def dp(i,j,s):
if (i,j) in memo:
return memo[(i,j)]
elif i >= j:
memo[(i,j)] = "i"
return "i"
if s[i] == s[j]:
memo[(i,j)] = dp(i+1,j-1,s)
else:
... | Title: Balanced Substring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called... | ```python
from collections import Counter
import sys
sys.setrecursionlimit(10000)
n = int(input())
string = input()
memo = {}
def dp(i,j,s):
if (i,j) in memo:
return memo[(i,j)]
elif i >= j:
memo[(i,j)] = "i"
return "i"
if s[i] == s[j]:
memo[(i,j)] = dp(i+1,j-1,s)
... | -1 | |
681 | A | A Good Contest | PROGRAMMING | 800 | [
"implementation"
] | null | null | Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part in a rated contest, his rating is changed depending on his performance.
Anton wants the color of hi... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants Anton has outscored in this contest .
The next *n* lines describe participants results: the *i*-th of them consists of a participant handle *name**i* and two integers *before**i* and *after**i* (<=-<=4000<=≤<=*be... | Print «YES» (quotes for clarity), if Anton has performed good in the contest and «NO» (quotes for clarity) otherwise. | [
"3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749\n",
"3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450\n"
] | [
"YES",
"NO"
] | In the first sample, Anton has outscored user with handle Burunduk1, whose handle was colored red before the contest and his rating has increased after the contest.
In the second sample, Applejack's rating has not increased after the contest, while both Fluttershy's and Pinkie_Pie's handles were not colored red before... | 500 | [
{
"input": "3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749",
"output": "YES"
},
{
"input": "3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450",
"output": "NO"
},
{
"input": "1\nDb -3373 3591",
"output": "NO"
},
{
"input": "5\nQ2bz 960 2342... | 1,578,574,286 | 2,147,483,647 | Python 3 | OK | TESTS | 60 | 109 | 0 | for _ in " "*int(input()):
a,b=map(int,input().split()[1:])
if b>a>=2400:print("YES");exit()
print("NO") | Title: A Good Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part ... | ```python
for _ in " "*int(input()):
a,b=map(int,input().split()[1:])
if b>a>=2400:print("YES");exit()
print("NO")
``` | 3 | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,673,955,077 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | a,b = map(int,input().split())
mx = max(a,b)
ans = 6 - mx + 1
if 6 %ans == 0:
rem = 6 // ans
print(f"1/{rem}")
else:
print(f"{ans}/6")
| Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
a,b = map(int,input().split())
mx = max(a,b)
ans = 6 - mx + 1
if 6 %ans == 0:
rem = 6 // ans
print(f"1/{rem}")
else:
print(f"{ans}/6")
``` | 0 |
886 | B | Vlad and Cafes | PROGRAMMING | 1,000 | [] | null | null | Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research.
First of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes... | In first line there is one integer *n* (1<=≤<=*n*<=≤<=2·105) — number of cafes indices written by Vlad.
In second line, *n* numbers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=2·105) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, ... | Print one integer — index of the cafe that Vlad hasn't visited for as long as possible. | [
"5\n1 3 2 1 2\n",
"6\n2 1 2 2 4 1\n"
] | [
"3\n",
"2\n"
] | In first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer.
In second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with in... | 1,000 | [
{
"input": "5\n1 3 2 1 2",
"output": "3"
},
{
"input": "6\n2 1 2 2 4 1",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n200000",
"output": "200000"
},
{
"input": "2\n2018 2017",
"output": "2018"
},
{
"input": "5\n100 1000 1000 1000... | 1,519,540,014 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 61 | 5,632,000 | n = int(input())
a = list(map(int, input().split()))
a = a[::-1]
s = set(a)
k = 0
for i in range(n):
if a[i] in s:
s.remove(a[i])
if len(s) == 1:
print(s.pop())
break | Title: Vlad and Cafes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research... | ```python
n = int(input())
a = list(map(int, input().split()))
a = a[::-1]
s = set(a)
k = 0
for i in range(n):
if a[i] in s:
s.remove(a[i])
if len(s) == 1:
print(s.pop())
break
``` | 0 | |
337 | A | Puzzles | PROGRAMMING | 900 | [
"greedy"
] | null | null | The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, as wikipedia states, is a tiling puzzle that requires the assembly of numerous small, often od... | The first line contains space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=*m*<=≤<=50). The second line contains *m* space-separated integers *f*1,<=*f*2,<=...,<=*f**m* (4<=≤<=*f**i*<=≤<=1000) — the quantities of pieces in the puzzles sold in the shop. | Print a single integer — the least possible difference the teacher can obtain. | [
"4 6\n10 12 10 7 5 22\n"
] | [
"5\n"
] | Sample 1. The class has 4 students. The shop sells 6 puzzles. If Ms. Manana buys the first four puzzles consisting of 10, 12, 10 and 7 pieces correspondingly, then the difference between the sizes of the largest and the smallest puzzle will be equal to 5. It is impossible to obtain a smaller difference. Note that the t... | 500 | [
{
"input": "4 6\n10 12 10 7 5 22",
"output": "5"
},
{
"input": "2 2\n4 4",
"output": "0"
},
{
"input": "2 10\n4 5 6 7 8 9 10 11 12 12",
"output": "0"
},
{
"input": "4 5\n818 136 713 59 946",
"output": "759"
},
{
"input": "3 20\n446 852 783 313 549 965 40 88 86 617... | 1,671,597,902 | 2,147,483,647 | Python 3 | OK | TESTS | 18 | 92 | 0 | n,m=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
b=100000
for k in range(m-n+1):
b=min(b,(a[k+n-1]-a[k]))
print(b) | Title: Puzzles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, a... | ```python
n,m=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
b=100000
for k in range(m-n+1):
b=min(b,(a[k+n-1]-a[k]))
print(b)
``` | 3 | |
30 | A | Accounting | PROGRAMMING | 1,400 | [
"brute force",
"math"
] | A. Accounting | 2 | 256 | A long time ago in some far country lived king Copa. After the recent king's reform, he got so large powers that started to keep the books by himself.
The total income *A* of his kingdom during 0-th year is known, as well as the total income *B* during *n*-th year (these numbers can be negative — it means that there w... | The input contains three integers *A*, *B*, *n* (|*A*|,<=|*B*|<=≤<=1000, 1<=≤<=*n*<=≤<=10). | Output the required integer coefficient *X*, or «No solution», if such a coefficient does not exist or it is fractional. If there are several possible solutions, output any of them. | [
"2 18 2\n",
"-1 8 3\n",
"0 0 10\n",
"1 16 5\n"
] | [
"3",
"-2",
"5",
"No solution"
] | none | 500 | [
{
"input": "2 18 2",
"output": "3"
},
{
"input": "-1 8 3",
"output": "-2"
},
{
"input": "0 0 10",
"output": "5"
},
{
"input": "1 16 5",
"output": "No solution"
},
{
"input": "0 1 2",
"output": "No solution"
},
{
"input": "3 0 4",
"output": "0"
},... | 1,651,949,266 | 2,147,483,647 | Python 3 | OK | TESTS | 68 | 92 | 0 | def task9(A, B, n):
for X in range(-1000, 1001):
if A * (X**n) == B:
return X
return "No solution"
[A, B, n] = input().split()
print(task9(int(A), int(B), int(n))) | Title: Accounting
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A long time ago in some far country lived king Copa. After the recent king's reform, he got so large powers that started to keep the books by himself.
The total income *A* of his kingdom during 0-th year is known, as well as th... | ```python
def task9(A, B, n):
for X in range(-1000, 1001):
if A * (X**n) == B:
return X
return "No solution"
[A, B, n] = input().split()
print(task9(int(A), int(B), int(n)))
``` | 3.977 |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,692,211,538 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 124 | 0 | from sys import stdin
input = stdin.readline
n=int(input())
a=n+1
def func(num):
num=str(num)
set={num[0],num[1],num[2],num[3]}
return len(set)
while a<9000:
if func(a)==4:
print(a)
break
else:
a+=1
| Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
from sys import stdin
input = stdin.readline
n=int(input())
a=n+1
def func(num):
num=str(num)
set={num[0],num[1],num[2],num[3]}
return len(set)
while a<9000:
if func(a)==4:
print(a)
break
else:
a+=1
``` | 0 | |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,696,585,690 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | ans=[]
def rec(n):
global ans
if n>1000:
return
ans.append(n)
pick1=rec((n*10)+4)
pick2=rec((n*10)+7)
n=int(input())
rec(0)
for i in range(len(ans)):
if n%ans[i]==0:
print("YES")
break
else:
print("NO")
| Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
ans=[]
def rec(n):
global ans
if n>1000:
return
ans.append(n)
pick1=rec((n*10)+4)
pick2=rec((n*10)+7)
n=int(input())
rec(0)
for i in range(len(ans)):
if n%ans[i]==0:
print("YES")
break
else:
print("NO")
``` | -1 | |
189 | A | Cut Ribbon | PROGRAMMING | 1,300 | [
"brute force",
"dp"
] | null | null | Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the number of ribbon pieces should be maximum.
Help Polycarpus and find the number of ribbon piece... | The first line contains four space-separated integers *n*, *a*, *b* and *c* (1<=≤<=*n*,<=*a*,<=*b*,<=*c*<=≤<=4000) — the length of the original ribbon and the acceptable lengths of the ribbon pieces after the cutting, correspondingly. The numbers *a*, *b* and *c* can coincide. | Print a single number — the maximum possible number of ribbon pieces. It is guaranteed that at least one correct ribbon cutting exists. | [
"5 5 3 2\n",
"7 5 5 2\n"
] | [
"2\n",
"2\n"
] | In the first example Polycarpus can cut the ribbon in such way: the first piece has length 2, the second piece has length 3.
In the second example Polycarpus can cut the ribbon in such way: the first piece has length 5, the second piece has length 2. | 500 | [
{
"input": "5 5 3 2",
"output": "2"
},
{
"input": "7 5 5 2",
"output": "2"
},
{
"input": "4 4 4 4",
"output": "1"
},
{
"input": "1 1 1 1",
"output": "1"
},
{
"input": "4000 1 2 3",
"output": "4000"
},
{
"input": "4000 3 4 5",
"output": "1333"
},
... | 1,691,828,465 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | z = []
z[0:] = map(int ,input().split())
count = 0
counter = z[0]
for i in range(1,4):
if counter - z[i] == z[1] or counter - z[i] == z[2] or counter - z[i] == z[3]:
count +=1
counter -=z[i]
print(counter)
| Title: Cut Ribbon
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the... | ```python
z = []
z[0:] = map(int ,input().split())
count = 0
counter = z[0]
for i in range(1,4):
if counter - z[i] == z[1] or counter - z[i] == z[2] or counter - z[i] == z[3]:
count +=1
counter -=z[i]
print(counter)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Gena loves sequences of numbers. Recently, he has discovered a new type of sequences which he called an almost arithmetical progression. A sequence is an almost arithmetical progression, if its elements can be represented as:
- *a*1<==<=*p*, where *p* is some integer; - *a**i*<==<=*a**i*<=-<=1<=+<=(<=-<=1)*i*<=+<=1·... | The first line contains integer *n* (1<=≤<=*n*<=≤<=4000). The next line contains *n* integers *b*1,<=*b*2,<=...,<=*b**n* (1<=≤<=*b**i*<=≤<=106). | Print a single integer — the length of the required longest subsequence. | [
"2\n3 5\n",
"4\n10 20 10 30\n"
] | [
"2\n",
"3\n"
] | In the first test the sequence actually is the suitable subsequence.
In the second test the following subsequence fits: 10, 20, 10. | 0 | [
{
"input": "2\n3 5",
"output": "2"
},
{
"input": "4\n10 20 10 30",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "2"
},
{
"input": "6\n2 3 2 2 1 3",
"output": "4"
},
{
"input": "8\n2 2 5 3 4 3 3 2",
"output": "3"
},
{
"input": "2\n468 335",
... | 1,650,634,201 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | #python 3.6.9
n = int(input())
l = list(map(int, input().strip().split()))
ans = 1
for roota in range(0, n-1):
fa = l[roota]
for rootb in range(roota, n):
lasta = True
localans = 1
fb = l[rootb]
#print("fixated", fa, fb)
for pointer in range(rootb, n):
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gena loves sequences of numbers. Recently, he has discovered a new type of sequences which he called an almost arithmetical progression. A sequence is an almost arithmetical progression, if its elements can be represented as:
- ... | ```python
#python 3.6.9
n = int(input())
l = list(map(int, input().strip().split()))
ans = 1
for roota in range(0, n-1):
fa = l[roota]
for rootb in range(roota, n):
lasta = True
localans = 1
fb = l[rootb]
#print("fixated", fa, fb)
for pointer in range(rootb... | 0 | |
47 | A | Triangular numbers | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Triangular numbers | 2 | 256 | A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is the number of dots in a triangle with *n* dots on a side. . You can learn more about these numbers fr... | The first line contains the single number *n* (1<=≤<=*n*<=≤<=500) — the given integer. | If the given integer is a triangular number output YES, otherwise output NO. | [
"1\n",
"2\n",
"3\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "1",
"output": "YES"
},
{
"input": "2",
"output": "NO"
},
{
"input": "3",
"output": "YES"
},
{
"input": "4",
"output": "NO"
},
{
"input": "5",
"output": "NO"
},
{
"input": "6",
"output": "YES"
},
{
"input": "7",
"output": "NO... | 1,687,451,068 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | d = {'A':1, 'B' : 1, 'C' :1}
for i in range(3):
x=input()
if x[1] =='<':
d[x[2]] += d[x[0]]
else:
d[x[0]] += d[x[2]]
d = {k: v for k, v in sorted(d.items(), key=lambda item: item[1])}
print(''.join(d.keys())) | Title: Triangular numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is t... | ```python
d = {'A':1, 'B' : 1, 'C' :1}
for i in range(3):
x=input()
if x[1] =='<':
d[x[2]] += d[x[0]]
else:
d[x[0]] += d[x[2]]
d = {k: v for k, v in sorted(d.items(), key=lambda item: item[1])}
print(''.join(d.keys()))
``` | -1 |
685 | A | Robbers' watch | PROGRAMMING | 1,700 | [
"brute force",
"combinatorics",
"dp",
"math"
] | null | null | Robbers, who attacked the Gerda's cab, are very successful in covering from the kingdom police. To make the goal of catching them even harder, they use their own watches.
First, as they know that kingdom police is bad at math, robbers use the positional numeral system with base 7. Second, they divide one day in *n* ho... | The first line of the input contains two integers, given in the decimal notation, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=109) — the number of hours in one day and the number of minutes in one hour, respectively. | Print one integer in decimal notation — the number of different pairs of hour and minute, such that all digits displayed on the watches are distinct. | [
"2 3\n",
"8 2\n"
] | [
"4\n",
"5\n"
] | In the first sample, possible pairs are: (0: 1), (0: 2), (1: 0), (1: 2).
In the second sample, possible pairs are: (02: 1), (03: 1), (04: 1), (05: 1), (06: 1). | 500 | [
{
"input": "2 3",
"output": "4"
},
{
"input": "8 2",
"output": "5"
},
{
"input": "1 1",
"output": "0"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "8 8",
"output": "0"
},
{
"input": "50 50",
"output": "0"
},
{
"input": "344 344",
"o... | 1,644,544,319 | 779 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 512,000 | from itertools import permutations
def base7(x):
answer = []
while x > 0:
answer.append(x % 7)
x = x //7
return tuple(answer[::-1])
def process(n, m):
max1 = base7(n-1)
max2 = base7(m-1)
answer = []
for x in permutations(range(7), len(max1)):
if x <= m... | Title: Robbers' watch
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Robbers, who attacked the Gerda's cab, are very successful in covering from the kingdom police. To make the goal of catching them even harder, they use their own watches.
First, as they know that kingdom police is bad a... | ```python
from itertools import permutations
def base7(x):
answer = []
while x > 0:
answer.append(x % 7)
x = x //7
return tuple(answer[::-1])
def process(n, m):
max1 = base7(n-1)
max2 = base7(m-1)
answer = []
for x in permutations(range(7), len(max1)):
... | 0 | |
950 | A | Left-handers, Right-handers and Ambidexters | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and ... | The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. | Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. | [
"1 4 2\n",
"5 5 5\n",
"0 2 0\n"
] | [
"6\n",
"14\n",
"0\n"
] | In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five l... | 500 | [
{
"input": "1 4 2",
"output": "6"
},
{
"input": "5 5 5",
"output": "14"
},
{
"input": "0 2 0",
"output": "0"
},
{
"input": "30 70 34",
"output": "128"
},
{
"input": "89 32 24",
"output": "112"
},
{
"input": "89 44 77",
"output": "210"
},
{
... | 1,530,352,630 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 109 | 0 | l,r,a= map(int,input().split())
if(l== 0 and a == 0 ) or (r==0 and a ==0):print(0)
elif (l+r+a)%2 : print((l+r+a)-1)
else : print((l+r+a)) | Title: Left-handers, Right-handers and Ambidexters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.... | ```python
l,r,a= map(int,input().split())
if(l== 0 and a == 0 ) or (r==0 and a ==0):print(0)
elif (l+r+a)%2 : print((l+r+a)-1)
else : print((l+r+a))
``` | 0 | |
92 | B | Binary Number | PROGRAMMING | 1,300 | [
"greedy"
] | B. Binary Number | 1 | 256 | Little walrus Fangy loves math very much. That's why when he is bored he plays with a number performing some operations.
Fangy takes some positive integer *x* and wants to get a number one from it. While *x* is not equal to 1, Fangy repeats the following action: if *x* is odd, then he adds 1 to it, otherwise he divide... | The first line contains a positive integer *x* in a binary system. It is guaranteed that the first digit of *x* is different from a zero and the number of its digits does not exceed 106. | Print the required number of actions. | [
"1\n",
"1001001\n",
"101110\n"
] | [
"0\n",
"12\n",
"8\n"
] | Let's consider the third sample. Number 101110 is even, which means that we should divide it by 2. After the dividing Fangy gets an odd number 10111 and adds one to it. Number 11000 can be divided by 2 three times in a row and get number 11. All that's left is to increase the number by one (we get 100), and then divide... | 1,000 | [
{
"input": "1",
"output": "0"
},
{
"input": "1001001",
"output": "12"
},
{
"input": "101110",
"output": "8"
},
{
"input": "11",
"output": "3"
},
{
"input": "11110001101",
"output": "16"
},
{
"input": "101010100100111100011111001111100001010101111110101... | 1,581,736,082 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 717 | 4,198,400 | inp = input()
num = '2' + inp[::-1] + '2'
if(num == '212'):
print(0)
exit()
last = num[0]
conseq = 0
count = 0
for i in range(len(num)):
digit = num[i]
if digit == last:
conseq += 1
else:
if last == '0':
count += conseq
if i == len(num)-2:
break
elif last == '1':
count += conseq + 1
digit... | Title: Binary Number
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Little walrus Fangy loves math very much. That's why when he is bored he plays with a number performing some operations.
Fangy takes some positive integer *x* and wants to get a number one from it. While *x* is not equal to ... | ```python
inp = input()
num = '2' + inp[::-1] + '2'
if(num == '212'):
print(0)
exit()
last = num[0]
conseq = 0
count = 0
for i in range(len(num)):
digit = num[i]
if digit == last:
conseq += 1
else:
if last == '0':
count += conseq
if i == len(num)-2:
break
elif last == '1':
count += conseq + ... | 3.63368 |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the... | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,691,147,559 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 62 | 2,764,800 | import math
a=int(input())
b=int(input())
c=int(input())
d=math.ceil(a/c)
e=math.ceil(b/c)
f=d*e
print(f) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each ... | ```python
import math
a=int(input())
b=int(input())
c=int(input())
d=math.ceil(a/c)
e=math.ceil(b/c)
f=d*e
print(f)
``` | -1 |
701 | C | They Are Everywhere | PROGRAMMING | 1,500 | [
"binary search",
"strings",
"two pointers"
] | null | null | Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each flat. Also, each flat is connected with the flat to the left and the flat to the right. Flat number 1 is ... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of flats in the house.
The second line contains the row *s* with the length *n*, it consists of uppercase and lowercase letters of English alphabet, the *i*-th letter equals the type of Pokemon, which is in the flat number *i*. | Print the minimum number of flats which Sergei B. should visit in order to catch Pokemons of all types which there are in the house. | [
"3\nAaA\n",
"7\nbcAAcbc\n",
"6\naaBCCe\n"
] | [
"2\n",
"3\n",
"5\n"
] | In the first test Sergei B. can begin, for example, from the flat number 1 and end in the flat number 2.
In the second test Sergei B. can begin, for example, from the flat number 4 and end in the flat number 6.
In the third test Sergei B. must begin from the flat number 2 and end in the flat number 6. | 1,000 | [
{
"input": "3\nAaA",
"output": "2"
},
{
"input": "7\nbcAAcbc",
"output": "3"
},
{
"input": "6\naaBCCe",
"output": "5"
},
{
"input": "1\nA",
"output": "1"
},
{
"input": "1\ng",
"output": "1"
},
{
"input": "52\nabcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQ... | 1,690,063,729 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 80 | 93 | 6,758,400 | n=int(input())
b=input()
z=set(b)
v=dict()
r=0
l=0
m=999999
while r < n:
while len(v)!=len(z) and r<n:
if b[r] not in v:
v[b[r]]=1
else:v[b[r]]+=1
r+=1
while len(v)==len(z):
if v[b[l]]==1:
v.pop(b[l])
else:
... | Title: They Are Everywhere
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each ... | ```python
n=int(input())
b=input()
z=set(b)
v=dict()
r=0
l=0
m=999999
while r < n:
while len(v)!=len(z) and r<n:
if b[r] not in v:
v[b[r]]=1
else:v[b[r]]+=1
r+=1
while len(v)==len(z):
if v[b[l]]==1:
v.pop(b[l])
else... | 3 | |
686 | A | Free Ice Cream | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the... | The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109).
Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occ... | Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress. | [
"5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20\n",
"5 17\n- 16\n- 2\n- 98\n+ 100\n- 98\n"
] | [
"22 1\n",
"3 2\n"
] | Consider the first sample.
1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1.... | 500 | [
{
"input": "5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20",
"output": "22 1"
},
{
"input": "5 17\n- 16\n- 2\n- 98\n+ 100\n- 98",
"output": "3 2"
},
{
"input": "6 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000",
"output": "7000000000 0"
},
{
... | 1,645,380,872 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | n, x = input().split()
n, x, d = int(n), int(x), 0
for i in range(x):
c = input().split()
if c[0] == "+": x += int(c[1])
else:
if x >= int(c[1]): x -= int(c[1])
else: d += 1
print(x, d) | Title: Free Ice Cream
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, p... | ```python
n, x = input().split()
n, x, d = int(n), int(x), 0
for i in range(x):
c = input().split()
if c[0] == "+": x += int(c[1])
else:
if x >= int(c[1]): x -= int(c[1])
else: d += 1
print(x, d)
``` | -1 | |
1,000 | B | Light It Up | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | Recently, you bought a brand new smart lamp with programming features. At first, you set up a schedule to the lamp. Every day it will turn power on at moment $0$ and turn power off at moment $M$. Moreover, the lamp allows you to set a program of switching its state (states are "lights on" and "lights off"). Unfortunate... | First line contains two space separated integers $n$ and $M$ ($1 \le n \le 10^5$, $2 \le M \le 10^9$) — the length of program $a$ and the moment when power turns off.
Second line contains $n$ space separated integers $a_1, a_2, \dots, a_n$ ($0 < a_1 < a_2 < \dots < a_n < M$) — initially installed progra... | Print the only integer — maximum possible total time when the lamp is lit. | [
"3 10\n4 6 7\n",
"2 12\n1 10\n",
"2 7\n3 4\n"
] | [
"8\n",
"9\n",
"6\n"
] | In the first example, one of possible optimal solutions is to insert value $x = 3$ before $a_1$, so program will be $[3, 4, 6, 7]$ and time of lamp being lit equals $(3 - 0) + (6 - 4) + (10 - 7) = 8$. Other possible solution is to insert $x = 5$ in appropriate place.
In the second example, there is only one optimal so... | 0 | [
{
"input": "3 10\n4 6 7",
"output": "8"
},
{
"input": "2 12\n1 10",
"output": "9"
},
{
"input": "2 7\n3 4",
"output": "6"
},
{
"input": "1 2\n1",
"output": "1"
},
{
"input": "5 10\n1 3 5 6 8",
"output": "6"
},
{
"input": "7 1000000000\n1 10001 10011 20... | 1,666,087,342 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 2,355,200 | import copy
n,M = list(map(int,input().split()))
p = tuple(map(int,input().split()))
ta = []
for i in range(M):
p2 = list(copy.deepcopy(p))
if i not in p:
p2.append(i)
p2.sort()
t = 0
l = 1
for j in range(M):
if j in p2:
l = 1-l
... | Title: Light It Up
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, you bought a brand new smart lamp with programming features. At first, you set up a schedule to the lamp. Every day it will turn power on at moment $0$ and turn power off at moment $M$. Moreover, the lamp allows y... | ```python
import copy
n,M = list(map(int,input().split()))
p = tuple(map(int,input().split()))
ta = []
for i in range(M):
p2 = list(copy.deepcopy(p))
if i not in p:
p2.append(i)
p2.sort()
t = 0
l = 1
for j in range(M):
if j in p2:
... | 0 | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,697,560,048 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | y=int(input())
ans=y+1
while True:
a=str(ans)
if a[0]!=a[1] and a[0]!=a[2] and a[0]!=a[3] and a[1]!=a[2] and a[1]!=a[3] and a[2]!=a[3]:
break
ans+=1
print(ans) | Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
y=int(input())
ans=y+1
while True:
a=str(ans)
if a[0]!=a[1] and a[0]!=a[2] and a[0]!=a[3] and a[1]!=a[2] and a[1]!=a[3] and a[2]!=a[3]:
break
ans+=1
print(ans)
``` | 3 | |
92 | A | Chips | PROGRAMMING | 800 | [
"implementation",
"math"
] | A. Chips | 2 | 256 | There are *n* walruses sitting in a circle. All of them are numbered in the clockwise order: the walrus number 2 sits to the left of the walrus number 1, the walrus number 3 sits to the left of the walrus number 2, ..., the walrus number 1 sits to the left of the walrus number *n*.
The presenter has *m* chips. The pre... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=50, 1<=≤<=*m*<=≤<=104) — the number of walruses and the number of chips correspondingly. | Print the number of chips the presenter ended up with. | [
"4 11\n",
"17 107\n",
"3 8\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first sample the presenter gives one chip to the walrus number 1, two chips to the walrus number 2, three chips to the walrus number 3, four chips to the walrus number 4, then again one chip to the walrus number 1. After that the presenter runs out of chips. He can't give anything to the walrus number 2 and the ... | 500 | [
{
"input": "4 11",
"output": "0"
},
{
"input": "17 107",
"output": "2"
},
{
"input": "3 8",
"output": "1"
},
{
"input": "46 7262",
"output": "35"
},
{
"input": "32 6864",
"output": "0"
},
{
"input": "36 6218",
"output": "14"
},
{
"input": "... | 1,665,911,842 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 25 | 124 | 1,331,200 | n,m = map(int,input().split())
c = 1
while True:
c %= n+1
if c>m: break
m -= c
c += 1
print(m)
| Title: Chips
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There are *n* walruses sitting in a circle. All of them are numbered in the clockwise order: the walrus number 2 sits to the left of the walrus number 1, the walrus number 3 sits to the left of the walrus number 2, ..., the walrus nu... | ```python
n,m = map(int,input().split())
c = 1
while True:
c %= n+1
if c>m: break
m -= c
c += 1
print(m)
``` | 3.96652 |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,673,698,933 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 62 | 0 | l=list(map(int,input().split()))
s=str(input())
add=0
for i in s:
if(i=='1'):
add+=l[0]
elif(i=='2'):
add+=l[1]
elif(i=='3'):
add+=l[2]
elif(i=='4'):
add+=l[3]
print(add) | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
l=list(map(int,input().split()))
s=str(input())
add=0
for i in s:
if(i=='1'):
add+=l[0]
elif(i=='2'):
add+=l[1]
elif(i=='3'):
add+=l[2]
elif(i=='4'):
add+=l[3]
print(add)
``` | 3 | |
985 | D | Sand Fortress | PROGRAMMING | 2,100 | [
"binary search",
"constructive algorithms",
"math"
] | null | null | You are going to the beach with the idea to build the greatest sand castle ever in your head! The beach is not as three-dimensional as you could have imagined, it can be decribed as a line of spots to pile up sand pillars. Spots are numbered 1 through infinity from left to right.
Obviously, there is not enough sand o... | The only line contains two integer numbers *n* and *H* (1<=≤<=*n*,<=*H*<=≤<=1018) — the number of sand packs you have and the height of the fence, respectively. | Print the minimum number of spots you can occupy so the all the castle building conditions hold. | [
"5 2\n",
"6 8\n"
] | [
"3\n",
"3\n"
] | Here are the heights of some valid castles:
- *n* = 5, *H* = 2, [2, 2, 1, 0, ...], [2, 1, 1, 1, 0, ...], [1, 0, 1, 2, 1, 0, ...] - *n* = 6, *H* = 8, [3, 2, 1, 0, ...], [2, 2, 1, 1, 0, ...], [0, 1, 0, 1, 2, 1, 1, 0...] (this one has 5 spots occupied)
The first list for both cases is the optimal answer, 3 spots are ... | 0 | [
{
"input": "5 2",
"output": "3"
},
{
"input": "6 8",
"output": "3"
},
{
"input": "20 4",
"output": "7"
},
{
"input": "1000000000000000000 1000000000000000000",
"output": "1414213562"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 10000000000000000... | 1,626,850,449 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 9 | 109 | 20,172,800 | import math
n, h = map(int, input().split())
x = int((math.sqrt(1+n*8)-1)/2)
if (x <= h):
if (x * (x + 1) / 2 == n):
print(x)
else:
print(x+1)
else:
y = int(math.sqrt((2 * n + h * h - h) / 2.0))
# print((h + y) * (y - h + 1) / 2)
sum = (h + y) * (y - h + 1) / 2 + y * (y - ... | Title: Sand Fortress
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are going to the beach with the idea to build the greatest sand castle ever in your head! The beach is not as three-dimensional as you could have imagined, it can be decribed as a line of spots to pile up sand pillars... | ```python
import math
n, h = map(int, input().split())
x = int((math.sqrt(1+n*8)-1)/2)
if (x <= h):
if (x * (x + 1) / 2 == n):
print(x)
else:
print(x+1)
else:
y = int(math.sqrt((2 * n + h * h - h) / 2.0))
# print((h + y) * (y - h + 1) / 2)
sum = (h + y) * (y - h + 1) / 2 +... | 0 | |
371 | C | Hamburgers | PROGRAMMING | 1,600 | [
"binary search",
"brute force"
] | null | null | Polycarpus loves hamburgers very much. He especially adores the hamburgers he makes with his own hands. Polycarpus thinks that there are only three decent ingredients to make hamburgers from: a bread, sausage and cheese. He writes down the recipe of his favorite "Le Hamburger de Polycarpus" as a string of letters 'B' (... | The first line of the input contains a non-empty string that describes the recipe of "Le Hamburger de Polycarpus". The length of the string doesn't exceed 100, the string contains only letters 'B' (uppercase English B), 'S' (uppercase English S) and 'C' (uppercase English C).
The second line contains three integers *n... | Print the maximum number of hamburgers Polycarpus can make. If he can't make any hamburger, print 0. | [
"BBBSSC\n6 4 1\n1 2 3\n4\n",
"BBC\n1 10 1\n1 10 1\n21\n",
"BSC\n1 1 1\n1 1 3\n1000000000000\n"
] | [
"2\n",
"7\n",
"200000000001\n"
] | none | 1,500 | [
{
"input": "BBBSSC\n6 4 1\n1 2 3\n4",
"output": "2"
},
{
"input": "BBC\n1 10 1\n1 10 1\n21",
"output": "7"
},
{
"input": "BSC\n1 1 1\n1 1 3\n1000000000000",
"output": "200000000001"
},
{
"input": "B\n1 1 1\n1 1 1\n381",
"output": "382"
},
{
"input": "BSC\n3 5 6\n7... | 1,610,636,257 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 307,200 | h = input().strip()
nb,ns,nc = map(int,input().strip().split())
Pb,Ps,Pc = map(int,input().strip().split())
m = int(input().strip())
b,s,c = h.count("B"),h.count("S"),h.count("C")
l,r = 0,m
while l<=r:
mid = (l+r)>>1
cur = max(mid*b-nb,0)*Pb+max(mid*s-ns,0)*Ps+max(mid*c-nc,0)*Pc
if cur == m:
... | Title: Hamburgers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus loves hamburgers very much. He especially adores the hamburgers he makes with his own hands. Polycarpus thinks that there are only three decent ingredients to make hamburgers from: a bread, sausage and cheese. He ... | ```python
h = input().strip()
nb,ns,nc = map(int,input().strip().split())
Pb,Ps,Pc = map(int,input().strip().split())
m = int(input().strip())
b,s,c = h.count("B"),h.count("S"),h.count("C")
l,r = 0,m
while l<=r:
mid = (l+r)>>1
cur = max(mid*b-nb,0)*Pb+max(mid*s-ns,0)*Ps+max(mid*c-nc,0)*Pc
if cur ==... | 0 | |
817 | D | Imbalanced Array | PROGRAMMING | 1,900 | [
"data structures",
"divide and conquer",
"dsu",
"sortings"
] | null | null | You are given an array *a* consisting of *n* elements. The imbalance value of some subsegment of this array is the difference between the maximum and minimum element from this segment. The imbalance value of the array is the sum of imbalance values of all subsegments of this array.
For example, the imbalance value of ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=106) — size of the array *a*.
The second line contains *n* integers *a*1,<=*a*2... *a**n* (1<=≤<=*a**i*<=≤<=106) — elements of the array. | Print one integer — the imbalance value of *a*. | [
"3\n1 4 1\n"
] | [
"9\n"
] | none | 0 | [
{
"input": "3\n1 4 1",
"output": "9"
},
{
"input": "10\n1 1 1 1 1 1 1 1 1 1",
"output": "0"
},
{
"input": "10\n1 4 4 3 5 2 4 2 4 5",
"output": "123"
},
{
"input": "10\n9 6 8 5 5 2 8 9 2 2",
"output": "245"
},
{
"input": "30\n4 5 2 2 5 2 3 4 3 3 2 1 3 4 4 5 3 3 1 5... | 1,497,826,572 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 102,400 | n=int(input())
raw=input().split()
arr=[int(i) for i in raw]
def imbalance(alist):
#print(alist)
L=len(alist)
if L==0:
return 0
m=min(alist)
M=max(alist)
a=min(alist.index(m),alist.index(M))
b=max(alist.index(m),alist.index(M))
lower=alist[0:b]
upper=alist[a+... | Title: Imbalanced Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array *a* consisting of *n* elements. The imbalance value of some subsegment of this array is the difference between the maximum and minimum element from this segment. The imbalance value of the array ... | ```python
n=int(input())
raw=input().split()
arr=[int(i) for i in raw]
def imbalance(alist):
#print(alist)
L=len(alist)
if L==0:
return 0
m=min(alist)
M=max(alist)
a=min(alist.index(m),alist.index(M))
b=max(alist.index(m),alist.index(M))
lower=alist[0:b]
uppe... | 0 | |
474 | A | Keyboard | PROGRAMMING | 900 | [
"implementation"
] | null | null | Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately. He accidentally moved both his hands with one position to the left or to the right. That mean... | First line of the input contains one letter describing direction of shifting ('L' or 'R' respectively for left or right).
Second line contains a sequence of characters written by Mole. The size of this sequence will be no more than 100. Sequence contains only symbols that appear on Mole's keyboard. It doesn't contain ... | Print a line that contains the original message. | [
"R\ns;;upimrrfod;pbr\n"
] | [
"allyouneedislove\n"
] | none | 500 | [
{
"input": "R\ns;;upimrrfod;pbr",
"output": "allyouneedislove"
},
{
"input": "R\nwertyuiop;lkjhgfdsxcvbnm,.",
"output": "qwertyuiolkjhgfdsazxcvbnm,"
},
{
"input": "L\nzxcvbnm,kjhgfdsaqwertyuio",
"output": "xcvbnm,.lkjhgfdswertyuiop"
},
{
"input": "R\nbubbuduppudup",
"outp... | 1,676,570,387 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 31 | 62 | 0 | x = 'qwertyuiop'
y = 'asdfghjkl;'
z = 'zxcvbnm,./'
f = input()
ans = ''
if f == 'R':
s = input()
for i in range(len(s)):
if s[i] in x:
ans += x[x.index(s[i]) - 1]
# print(s[i], x.index(s[i]), x[x.index(s[i]) - 1])
elif s[i] in y:
ans += y[y.ind... | Title: Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately.... | ```python
x = 'qwertyuiop'
y = 'asdfghjkl;'
z = 'zxcvbnm,./'
f = input()
ans = ''
if f == 'R':
s = input()
for i in range(len(s)):
if s[i] in x:
ans += x[x.index(s[i]) - 1]
# print(s[i], x.index(s[i]), x[x.index(s[i]) - 1])
elif s[i] in y:
ans ... | 3 | |
379 | A | New Year Candles | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used ... | The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000). | Print a single integer — the number of hours Vasily can light up the room for. | [
"4 2\n",
"6 3\n"
] | [
"7\n",
"8\n"
] | Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours. | 500 | [
{
"input": "4 2",
"output": "7"
},
{
"input": "6 3",
"output": "8"
},
{
"input": "1000 1000",
"output": "1001"
},
{
"input": "123 5",
"output": "153"
},
{
"input": "1000 2",
"output": "1999"
},
{
"input": "1 2",
"output": "1"
},
{
"input": ... | 1,684,678,949 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | a, b=map(int, input().split())
t=1
while a>0:
a-=1
t+=1
c=a//b
if c>0:
t=t+c
d=c//b
if c//b>0:
t=t+d
print(t) | Title: New Year Candles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is s... | ```python
a, b=map(int, input().split())
t=1
while a>0:
a-=1
t+=1
c=a//b
if c>0:
t=t+c
d=c//b
if c//b>0:
t=t+d
print(t)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | By 2312 there were *n* Large Hadron Colliders in the inhabited part of the universe. Each of them corresponded to a single natural number from 1 to *n*. However, scientists did not know what activating several colliders simultaneously could cause, so the colliders were deactivated.
In 2312 there was a startling discov... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of colliders and the number of requests, correspondingly.
Next *m* lines contain numbers of requests, one per line, in the form of either "+ i" (without the quotes) — activate the *i*-th collider, or "- i" (without ... | Print *m* lines — the results of executing requests in the above given format. The requests should be processed in the order, in which they are given in the input. Don't forget that the responses to the requests should be printed without quotes. | [
"10 10\n+ 6\n+ 10\n+ 5\n- 10\n- 5\n- 6\n+ 10\n+ 3\n+ 6\n+ 3\n"
] | [
"Success\nConflict with 6\nSuccess\nAlready off\nSuccess\nSuccess\nSuccess\nSuccess\nConflict with 10\nAlready on\n"
] | Note that in the sample the colliders don't turn on after the second and ninth requests. The ninth request could also receive response "Conflict with 3". | 0 | [
{
"input": "10 10\n+ 6\n+ 10\n+ 5\n- 10\n- 5\n- 6\n+ 10\n+ 3\n+ 6\n+ 3",
"output": "Success\nConflict with 6\nSuccess\nAlready off\nSuccess\nSuccess\nSuccess\nSuccess\nConflict with 10\nAlready on"
},
{
"input": "7 5\n+ 7\n+ 6\n+ 4\n+ 3\n- 7",
"output": "Success\nSuccess\nConflict with 6\nConfli... | 1,677,135,563 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 1 | 124 | 2,867,200 | import math
n,m=map(int,input().split())
d={}
for i in range(1,n+1):
d[i]=0
l=[]
for i in range(n):
ope,mag=input().split()
mag=int(mag)
if ope=="+":
if d[mag]==1:
print("Already on")
else:
ans="Success"
for i in l:
if ma... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
By 2312 there were *n* Large Hadron Colliders in the inhabited part of the universe. Each of them corresponded to a single natural number from 1 to *n*. However, scientists did not know what activating several colliders simultaneo... | ```python
import math
n,m=map(int,input().split())
d={}
for i in range(1,n+1):
d[i]=0
l=[]
for i in range(n):
ope,mag=input().split()
mag=int(mag)
if ope=="+":
if d[mag]==1:
print("Already on")
else:
ans="Success"
for i in l:
... | -1 | |
903 | C | Boxes Packing | PROGRAMMING | 1,200 | [
"greedy"
] | null | null | Mishka has got *n* empty boxes. For every *i* (1<=≤<=*i*<=≤<=*n*), *i*-th box is a cube with side length *a**i*.
Mishka can put a box *i* into another box *j* if the following conditions are met:
- *i*-th box is not put into another box; - *j*-th box doesn't contain any other boxes; - box *i* is smaller than box *... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=5000) — the number of boxes Mishka has got.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109), where *a**i* is the side length of *i*-th box. | Print the minimum possible number of visible boxes. | [
"3\n1 2 3\n",
"4\n4 2 4 3\n"
] | [
"1\n",
"2\n"
] | In the first example it is possible to put box 1 into box 2, and 2 into 3.
In the second example Mishka can put box 2 into box 3, and box 4 into box 1. | 0 | [
{
"input": "3\n1 2 3",
"output": "1"
},
{
"input": "4\n4 2 4 3",
"output": "2"
},
{
"input": "10\n58 58 58 58 58 58 58 58 58 58",
"output": "10"
},
{
"input": "10\n86 89 89 86 86 89 86 86 89 89",
"output": "5"
},
{
"input": "100\n981 288 186 186 292 876 341 288 98... | 1,652,086,077 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 24 | 77 | 2,662,400 |
n = int(input())
array = list(map(int, input().split()))
dict = {}
for x in array:
if x in dict:
dict[x] += 1
else:
dict[x] = 1
arr = list(dict.values())
arr.sort()
print(arr[len(arr) - 1])
| Title: Boxes Packing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka has got *n* empty boxes. For every *i* (1<=≤<=*i*<=≤<=*n*), *i*-th box is a cube with side length *a**i*.
Mishka can put a box *i* into another box *j* if the following conditions are met:
- *i*-th box is not pu... | ```python
n = int(input())
array = list(map(int, input().split()))
dict = {}
for x in array:
if x in dict:
dict[x] += 1
else:
dict[x] = 1
arr = list(dict.values())
arr.sort()
print(arr[len(arr) - 1])
``` | 3 | |
789 | B | Masha and geometric depression | PROGRAMMING | 1,700 | [
"brute force",
"implementation",
"math"
] | null | null | Masha really loves algebra. On the last lesson, her strict teacher Dvastan gave she new exercise.
You are given geometric progression *b* defined by two integers *b*1 and *q*. Remind that a geometric progression is a sequence of integers *b*1,<=*b*2,<=*b*3,<=..., where for each *i*<=><=1 the respective term satisfi... | The first line of input contains four integers *b*1, *q*, *l*, *m* (-109<=≤<=*b*1,<=*q*<=≤<=109, 1<=≤<=*l*<=≤<=109, 1<=≤<=*m*<=≤<=105) — the initial term and the common ratio of progression, absolute value of maximal number that can be written on the board and the number of "bad" integers, respectively.
The second lin... | Print the only integer, meaning the number of progression terms that will be written on the board if it is finite, or "inf" (without quotes) otherwise. | [
"3 2 30 4\n6 14 25 48\n",
"123 1 2143435 4\n123 11 -5453 141245\n",
"123 1 2143435 4\n54343 -13 6 124\n"
] | [
"3",
"0",
"inf"
] | In the first sample case, Masha will write integers 3, 12, 24. Progression term 6 will be skipped because it is a "bad" integer. Terms bigger than 24 won't be written because they exceed *l* by absolute value.
In the second case, Masha won't write any number because all terms are equal 123 and this is a "bad" integer.... | 1,000 | [
{
"input": "3 2 30 4\n6 14 25 48",
"output": "3"
},
{
"input": "123 1 2143435 4\n123 11 -5453 141245",
"output": "0"
},
{
"input": "123 1 2143435 4\n54343 -13 6 124",
"output": "inf"
},
{
"input": "3 2 25 2\n379195692 -69874783",
"output": "4"
},
{
"input": "3 2 3... | 1,507,767,696 | 1,596 | Python 3 | WRONG_ANSWER | TESTS | 7 | 92 | 8,192,000 | def main():
read = lambda: tuple(map(int, input().split()))
b, q, l, m = read()
ns = {}
for n in list(filter(lambda v: v%b == 0, read())):
ns[n] = True
k = 0
if q == 1 and not b in ns: return "inf"
while b <= l:
if not b in ns:
k += 1
if b * q == b: break
... | Title: Masha and geometric depression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Masha really loves algebra. On the last lesson, her strict teacher Dvastan gave she new exercise.
You are given geometric progression *b* defined by two integers *b*1 and *q*. Remind that a geometric pro... | ```python
def main():
read = lambda: tuple(map(int, input().split()))
b, q, l, m = read()
ns = {}
for n in list(filter(lambda v: v%b == 0, read())):
ns[n] = True
k = 0
if q == 1 and not b in ns: return "inf"
while b <= l:
if not b in ns:
k += 1
if b * q ==... | 0 | |
753 | B | Interactive Bulls and Cows (Easy) | PROGRAMMING | 1,600 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | This problem is a little bit unusual. Here you are to implement an interaction with a testing system. That means that you can make queries and get responses in the online mode. Please be sure to use the stream flushing operation after each query's output in order not to leave part of your output in some buffer. For exa... | To read answers to the queries, the program must use the standard input.
The program will receive pairs of non-negative integers in the input, one pair per line. The first number in a pair is a number of bulls and the second one is a number of cows of the string *s* and the string *x**i* printed by your program. If th... | The program must use the standard output to print queries.
Your program must output requests — 4-digit strings *x*1,<=*x*2,<=..., one per line. After the output of each line the program must execute flush operation. The program should read the answer to the query from the standard input.
Your program is allowed to do... | [
"0 1\n2 0\n1 1\n0 4\n2 1\n4 0\n"
] | [
"8000\n0179\n3159\n3210\n0112\n0123"
] | The secret string *s* in the example is "0123". | 1,000 | [
{
"input": "0123",
"output": "20"
},
{
"input": "1234",
"output": "20"
},
{
"input": "9876",
"output": "20"
},
{
"input": "7158",
"output": "20"
},
{
"input": "7590",
"output": "20"
},
{
"input": "7325",
"output": "20"
},
{
"input": "7524",... | 1,485,098,522 | 1,622 | Python 3 | OK | TESTS | 41 | 62 | 4,608,000 | num = []
for i in range(10):
print(str(i) * 4)
n, m = map(int, input().split())
for j in range(n):
num.append(i)
pas = False
for i1 in range(4):
for i2 in range(4):
for i3 in range(4):
for i4 in range(4):
if i1 != i2 and i1 != i3 and i1 != i4 and i2... | Title: Interactive Bulls and Cows (Easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This problem is a little bit unusual. Here you are to implement an interaction with a testing system. That means that you can make queries and get responses in the online mode. Please be sure to use th... | ```python
num = []
for i in range(10):
print(str(i) * 4)
n, m = map(int, input().split())
for j in range(n):
num.append(i)
pas = False
for i1 in range(4):
for i2 in range(4):
for i3 in range(4):
for i4 in range(4):
if i1 != i2 and i1 != i3 and i1 !=... | 3 | |
114 | B | PFAST Inc. | PROGRAMMING | 1,500 | [
"bitmasks",
"brute force",
"graphs"
] | null | null | When little Petya grew up and entered the university, he started to take part in АСМ contests. Later he realized that he doesn't like how the АСМ contests are organised: the team could only have three members (and he couldn't take all his friends to the competitions and distribute the tasks between the team members eff... | The first line contains two integer numbers *n* (1<=≤<=*n*<=≤<=16) — the number of volunteers, and *m* () — the number of pairs that do not get on. Next *n* lines contain the volunteers' names (each name is a non-empty string consisting of no more than 10 uppercase and/or lowercase Latin letters). Next *m* lines contai... | The first output line should contain the single number *k* — the number of people in the sought team. Next *k* lines should contain the names of the sought team's participants in the lexicographical order. If there are several variants to solve the problem, print any of them. Petya might not be a member of the sought t... | [
"3 1\nPetya\nVasya\nMasha\nPetya Vasya\n",
"3 0\nPasha\nLesha\nVanya\n"
] | [
"2\nMasha\nPetya\n",
"3\nLesha\nPasha\nVanya\n"
] | none | 1,000 | [
{
"input": "3 1\nPetya\nVasya\nMasha\nPetya Vasya",
"output": "2\nMasha\nPetya"
},
{
"input": "3 0\nPasha\nLesha\nVanya",
"output": "3\nLesha\nPasha\nVanya"
},
{
"input": "7 12\nPasha\nLesha\nVanya\nTaras\nNikita\nSergey\nAndrey\nPasha Taras\nPasha Nikita\nPasha Andrey\nPasha Sergey\nLes... | 1,476,902,659 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 4,915,200 | def moins(M,N):
L=[]
for i in M:
if i not in N:
L+=[i]
return L
S=str(input())
l=S.split(" ")
n,m=int(l[0]),int(l[1])
d={}
S=str(input())
L=[S]
for i in range(n-1):
S=str(input())
j,f=0,0
while f==0:
if j==len(L):
L+=[S]
f=1... | Title: PFAST Inc.
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When little Petya grew up and entered the university, he started to take part in АСМ contests. Later he realized that he doesn't like how the АСМ contests are organised: the team could only have three members (and he couldn'... | ```python
def moins(M,N):
L=[]
for i in M:
if i not in N:
L+=[i]
return L
S=str(input())
l=S.split(" ")
n,m=int(l[0]),int(l[1])
d={}
S=str(input())
L=[S]
for i in range(n-1):
S=str(input())
j,f=0,0
while f==0:
if j==len(L):
L+=[S]
... | 0 | |
231 | A | Team | PROGRAMMING | 800 | [
"brute force",
"greedy"
] | null | null | One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution.... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second numbe... | Print a single integer — the number of problems the friends will implement on the contest. | [
"3\n1 1 0\n1 1 1\n1 0 0\n",
"2\n1 0 0\n0 1 1\n"
] | [
"2\n",
"1\n"
] | In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't ta... | 500 | [
{
"input": "3\n1 1 0\n1 1 1\n1 0 0",
"output": "2"
},
{
"input": "2\n1 0 0\n0 1 1",
"output": "1"
},
{
"input": "1\n1 0 0",
"output": "0"
},
{
"input": "2\n1 0 0\n1 1 1",
"output": "1"
},
{
"input": "5\n1 0 0\n0 1 0\n1 1 1\n0 0 1\n0 0 0",
"output": "1"
},
... | 1,699,131,861 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | list = [[],
[],
[]]
n = int(input())
count = 0
for i in range(n):
c = 0
a = input().split()
for j in range(len(a)):
a[j] = int(a[j])
for j in range(3):
list[j].append(a[j])
if list[j][i] == 1:
c += 1
if c > 1:
count += 1
pri... | Title: Team
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decid... | ```python
list = [[],
[],
[]]
n = int(input())
count = 0
for i in range(n):
c = 0
a = input().split()
for j in range(len(a)):
a[j] = int(a[j])
for j in range(3):
list[j].append(a[j])
if list[j][i] == 1:
c += 1
if c > 1:
count... | 3 | |
109 | A | Lucky Sum of Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | A. Lucky Sum of Digits | 2 | 256 | Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya wonders eagerly what minimum lucky number has the sum of digits equal to *n*. Help him cope wi... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the sum of digits of the required lucky number. | Print on the single line the result — the minimum lucky number, whose sum of digits equals *n*. If such number does not exist, print -1. | [
"11\n",
"10\n"
] | [
"47\n",
"-1\n"
] | none | 500 | [
{
"input": "11",
"output": "47"
},
{
"input": "10",
"output": "-1"
},
{
"input": "64",
"output": "4477777777"
},
{
"input": "1",
"output": "-1"
},
{
"input": "4",
"output": "4"
},
{
"input": "7",
"output": "7"
},
{
"input": "12",
"outpu... | 1,584,486,346 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 716,800 | def calcula47(num):
conta7 = 0
conta4 = 0
while(num>0):
if(num >= 4):
if (num % 7 == 0):
conta7 += num // 7
break
conta4 += 1
num -= 4
else:
return -1
while(conta4 > 7):
conta4 -= 7
conta... | Title: Lucky Sum of Digits
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
def calcula47(num):
conta7 = 0
conta4 = 0
while(num>0):
if(num >= 4):
if (num % 7 == 0):
conta7 += num // 7
break
conta4 += 1
num -= 4
else:
return -1
while(conta4 > 7):
conta4 -= 7
... | 0 |
554 | A | Kyoya and Photobooks | PROGRAMMING | 900 | [
"brute force",
"math",
"strings"
] | null | null | Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the pho... | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters. | Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make. | [
"a\n",
"hi\n"
] | [
"51\n",
"76\n"
] | In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | 250 | [
{
"input": "a",
"output": "51"
},
{
"input": "hi",
"output": "76"
},
{
"input": "y",
"output": "51"
},
{
"input": "kgan",
"output": "126"
},
{
"input": "zoabkyuvus",
"output": "276"
},
{
"input": "spyemhyznjieyhhbk",
"output": "451"
},
{
"i... | 1,435,164,336 | 936 | Python 3 | OK | TESTS | 33 | 62 | 0 | s = input()
n = len(s)
print(26 + 25 * n) | Title: Kyoya and Photobooks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos b... | ```python
s = input()
n = len(s)
print(26 + 25 * n)
``` | 3 | |
180 | C | Letter | PROGRAMMING | 1,400 | [
"dp"
] | null | null | Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them were uppercase.
Patrick believes that a message is fancy if any uppercase letter stands to... | The only line of the input contains a non-empty string consisting of uppercase and lowercase letters. The string's length does not exceed 105. | Print a single number — the least number of actions needed to make the message fancy. | [
"PRuvetSTAaYA\n",
"OYPROSTIYAOPECHATALSYAPRIVETSTASYA\n",
"helloworld\n"
] | [
"5\n",
"0\n",
"0\n"
] | none | 0 | [
{
"input": "PRuvetSTAaYA",
"output": "5"
},
{
"input": "OYPROSTIYAOPECHATALSYAPRIVETSTASYA",
"output": "0"
},
{
"input": "helloworld",
"output": "0"
},
{
"input": "P",
"output": "0"
},
{
"input": "t",
"output": "0"
},
{
"input": "XdJ",
"output": "1... | 1,671,349,212 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 216 | 3,788,800 | def solve(s):
arr = []
pi = []
numone = 0
for i in range(len(s)):
if ord(s[i])>=65 and ord(s[i])<=90:
arr.append(1)
numone+=1
else:
arr.append(0)
pi.append(... | Title: Letter
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them... | ```python
def solve(s):
arr = []
pi = []
numone = 0
for i in range(len(s)):
if ord(s[i])>=65 and ord(s[i])<=90:
arr.append(1)
numone+=1
else:
arr.append(0)
... | 3 | |
7 | A | Kalevitch and Chess | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms"
] | A. Kalevitch and Chess | 2 | 64 | A famous Berland's painter Kalevitch likes to shock the public. One of his last obsessions is chess. For more than a thousand years people have been playing this old game on uninteresting, monotonous boards. Kalevitch decided to put an end to this tradition and to introduce a new attitude to chessboards.
As before, th... | The input file contains 8 lines, each of the lines contains 8 characters. The given matrix describes the client's requirements, W character stands for a white square, and B character — for a square painted black.
It is guaranteed that client's requirments can be fulfilled with a sequence of allowed strokes (vertical/c... | Output the only number — the minimum amount of rows and columns that Kalevitch has to paint on the white chessboard to meet the client's requirements. | [
"WWWBWWBW\nBBBBBBBB\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\n",
"WWWWWWWW\nBBBBBBBB\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\n"
] | [
"3\n",
"1\n"
] | none | 0 | [
{
"input": "WWWBWWBW\nBBBBBBBB\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW",
"output": "3"
},
{
"input": "WWWWWWWW\nBBBBBBBB\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW",
"output": "1"
},
{
"input": "WWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWW... | 1,616,483,760 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 154 | 0 | row=0
col=0
l=[]
for i in range(8):
l.append(input())
if(l[i]=="BBBBBBBB"):
row+=1
if(row==8):
print(8)
else:
for i in range(8):
if("".join([x[i] for x in l])=="BBBBBBBB"):
col+=1
print(col+row) | Title: Kalevitch and Chess
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
A famous Berland's painter Kalevitch likes to shock the public. One of his last obsessions is chess. For more than a thousand years people have been playing this old game on uninteresting, monotonous boards. Kalevitch de... | ```python
row=0
col=0
l=[]
for i in range(8):
l.append(input())
if(l[i]=="BBBBBBBB"):
row+=1
if(row==8):
print(8)
else:
for i in range(8):
if("".join([x[i] for x in l])=="BBBBBBBB"):
col+=1
print(col+row)
``` | 3.9615 |
812 | B | Sagheer, the Hausmeister | PROGRAMMING | 1,600 | [
"bitmasks",
"brute force",
"dp"
] | null | null | Some people leave the lights at their workplaces on when they leave that is a waste of resources. As a hausmeister of DHBW, Sagheer waits till all students and professors leave the university building, then goes and turns all the lights off.
The building consists of *n* floors with stairs at the left and the right sid... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=15 and 1<=≤<=*m*<=≤<=100) — the number of floors and the number of rooms in each floor, respectively.
The next *n* lines contains the building description. Each line contains a binary string of length *m*<=+<=2 representing a floor (the left stairs, then ... | Print a single integer — the minimum total time needed to turn off all the lights. | [
"2 2\n0010\n0100\n",
"3 4\n001000\n000010\n000010\n",
"4 3\n01110\n01110\n01110\n01110\n"
] | [
"5\n",
"12\n",
"18\n"
] | In the first example, Sagheer will go to room 1 in the ground floor, then he will go to room 2 in the second floor using the left or right stairs.
In the second example, he will go to the fourth room in the ground floor, use right stairs, go to the fourth room in the second floor, use right stairs again, then go to th... | 1,000 | [
{
"input": "2 2\n0010\n0100",
"output": "5"
},
{
"input": "3 4\n001000\n000010\n000010",
"output": "12"
},
{
"input": "4 3\n01110\n01110\n01110\n01110",
"output": "18"
},
{
"input": "3 2\n0000\n0100\n0100",
"output": "4"
},
{
"input": "1 89\n0000000000000000000000... | 1,496,330,300 | 3,800 | Python 3 | COMPILATION_ERROR | PRETESTS | 0 | 0 | 0 | #include<iostream>
#include<cstring>
using namespace std;
int main( )
{
int n,m;
while(cin >> n >> m){
int l[30],r[30];
memset(l,-1,sizeof(l));
memset(r,-1,sizeof(r));
for(int j = 0; j < n; j++){
char c;
cin >> c;
for(int k = 1; k <= m; k++){
cin >> c;
if(c == '1'){
... | Title: Sagheer, the Hausmeister
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some people leave the lights at their workplaces on when they leave that is a waste of resources. As a hausmeister of DHBW, Sagheer waits till all students and professors leave the university building, then goe... | ```python
#include<iostream>
#include<cstring>
using namespace std;
int main( )
{
int n,m;
while(cin >> n >> m){
int l[30],r[30];
memset(l,-1,sizeof(l));
memset(r,-1,sizeof(r));
for(int j = 0; j < n; j++){
char c;
cin >> c;
for(int k = 1; k <= m; k++){
cin >> c;
if(c == ... | -1 | |
598 | A | Tricky Sum | PROGRAMMING | 900 | [
"math"
] | null | null | In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, because 1, 2 and 4 are 20, 21 and 22 respectively.
Calculate the answer for *t* values of *n*. | The first line of the input contains a single integer *t* (1<=≤<=*t*<=≤<=100) — the number of values of *n* to be processed.
Each of next *t* lines contains a single integer *n* (1<=≤<=*n*<=≤<=109). | Print the requested sum for each of *t* integers *n* given in the input. | [
"2\n4\n1000000000\n"
] | [
"-4\n499999998352516354\n"
] | The answer for the first sample is explained in the statement. | 0 | [
{
"input": "2\n4\n1000000000",
"output": "-4\n499999998352516354"
},
{
"input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "-1\n-3\n0\n-4\n1\n7\n14\n6\n15\n25"
},
{
"input": "10\n10\n9\n47\n33\n99\n83\n62\n1\n100\n53",
"output": "25\n15\n1002\n435\n4696\n3232\n1827\n-1\n4796\n130... | 1,659,728,047 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | def sumak(n):
kres=[2**x for x in range(32)]
total=int(n*(n+1)/2)
cc=0
done=True
while done:
val=kres[cc]
if val<n+1:
total=int(total-2*(val))
cc+=1
else:
done=False
print(int(total))
| Title: Tricky Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, be... | ```python
def sumak(n):
kres=[2**x for x in range(32)]
total=int(n*(n+1)/2)
cc=0
done=True
while done:
val=kres[cc]
if val<n+1:
total=int(total-2*(val))
cc+=1
else:
done=False
print(int(total))
``` | 0 | |
60 | A | Where Are My Flakes? | PROGRAMMING | 1,300 | [
"implementation",
"two pointers"
] | A. Where Are My Flakes? | 2 | 256 | One morning the Cereal Guy found out that all his cereal flakes were gone. He found a note instead of them. It turned out that his smart roommate hid the flakes in one of *n* boxes. The boxes stand in one row, they are numbered from 1 to *n* from the left to the right. The roommate left hints like "Hidden to the left o... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=1000,<=0<=≤<=*m*<=≤<=1000) which represent the number of boxes and the number of hints correspondingly. Next *m* lines contain hints like "To the left of *i*" and "To the right of *i*", where *i* is integer (1<=≤<=*i*<=≤<=*n*). The hints may coincide. | The answer should contain exactly one integer — the number of boxes that should necessarily be checked or "-1" if the hints are contradictory. | [
"2 1\nTo the left of 2\n",
"3 2\nTo the right of 1\nTo the right of 2\n",
"3 1\nTo the left of 3\n",
"3 2\nTo the left of 2\nTo the right of 1\n"
] | [
"1\n",
"1\n",
"2\n",
"-1\n"
] | none | 500 | [
{
"input": "2 1\nTo the left of 2",
"output": "1"
},
{
"input": "3 2\nTo the right of 1\nTo the right of 2",
"output": "1"
},
{
"input": "3 1\nTo the left of 3",
"output": "2"
},
{
"input": "3 2\nTo the left of 2\nTo the right of 1",
"output": "-1"
},
{
"input": "... | 1,662,930,968 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 124 | 0 | n, m = map(int, input().split())
left, right = list(), list()
left.append(n+1)
right.append(0)
for _ in range(m):
s = input()
idx = int(s.split()[4])
if s[7] == 'l':
left.append(idx)
else:
right.append(idx)
left.sort()
right.sort()
res = left[0] - right[-1] - 1
if res < 0:
res = -1
print(res) | Title: Where Are My Flakes?
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One morning the Cereal Guy found out that all his cereal flakes were gone. He found a note instead of them. It turned out that his smart roommate hid the flakes in one of *n* boxes. The boxes stand in one row, they are... | ```python
n, m = map(int, input().split())
left, right = list(), list()
left.append(n+1)
right.append(0)
for _ in range(m):
s = input()
idx = int(s.split()[4])
if s[7] == 'l':
left.append(idx)
else:
right.append(idx)
left.sort()
right.sort()
res = left[0] - right[-1] - 1
if res < 0:
res = -1
print(res)
``` | 0 |
12 | A | Super Agent | PROGRAMMING | 800 | [
"implementation"
] | A. Super Agent | 2 | 256 | There is a very secret base in Potatoland where potato mash is made according to a special recipe. The neighbours from Porridgia decided to seize this recipe and to sell it to Pilauland. For this mission they have been preparing special agent Pearlo for many years. When, finally, Pearlo learned all secrets of espionage... | Input contains the matrix of three rows of three symbols each. Symbol «X» means that the corresponding button was pressed, and «.» means that is was not pressed. The matrix may contain no «X», also it may contain no «.». | Print YES if the password is symmetric with respect to the central button of the terminal and NO otherwise. | [
"XX.\n...\n.XX\n",
"X.X\nX..\n...\n"
] | [
"YES\n",
"NO\n"
] | If you are not familiar with the term «central symmetry», you may look into http://en.wikipedia.org/wiki/Central_symmetry | 0 | [
{
"input": "XX.\n...\n.XX",
"output": "YES"
},
{
"input": ".X.\n.X.\n.X.",
"output": "YES"
},
{
"input": "XXX\nXXX\nXXX",
"output": "YES"
},
{
"input": "XXX\nX.X\nXXX",
"output": "YES"
},
{
"input": "X..\n.X.\n..X",
"output": "YES"
},
{
"input": "...\n... | 1,666,625,009 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | a,b,c=input(),input(),input()
if a==c[::-1] and b!='..X' and b!='X..': print('YES')
else: print('NO') | Title: Super Agent
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a very secret base in Potatoland where potato mash is made according to a special recipe. The neighbours from Porridgia decided to seize this recipe and to sell it to Pilauland. For this mission they have been preparin... | ```python
a,b,c=input(),input(),input()
if a==c[::-1] and b!='..X' and b!='X..': print('YES')
else: print('NO')
``` | 3.977 |
270 | A | Fancy Fence | PROGRAMMING | 1,100 | [
"geometry",
"implementation",
"math"
] | null | null | Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can only make fence corners at a single angle *a*.
Will the robot be able to build the fence Emuska... | The first line of input contains an integer *t* (0<=<<=*t*<=<<=180) — the number of tests. Each of the following *t* lines contains a single integer *a* (0<=<<=*a*<=<<=180) — the angle the robot can make corners at measured in degrees. | For each test, output on a single line "YES" (without quotes), if the robot can build a fence Emuskald wants, and "NO" (without quotes), if it is impossible. | [
"3\n30\n60\n90\n"
] | [
"NO\nYES\nYES\n"
] | In the first test case, it is impossible to build the fence, since there is no regular polygon with angle <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/df5f4b07dd5316fde165b43657b2696e2919e791.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second test case, the fence is a r... | 500 | [
{
"input": "3\n30\n60\n90",
"output": "NO\nYES\nYES"
},
{
"input": "6\n1\n2\n3\n170\n179\n25",
"output": "NO\nNO\nNO\nYES\nYES\nNO"
}
] | 1,632,830,958 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 92 | 6,758,400 | t = int(input())
for i in range(t):
angle = int(input())
n = 2/(1-angle/180)
if n-round(n) < 1e-200:
output = "YES"
else:
output = "NO"
print(output) | Title: Fancy Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can... | ```python
t = int(input())
for i in range(t):
angle = int(input())
n = 2/(1-angle/180)
if n-round(n) < 1e-200:
output = "YES"
else:
output = "NO"
print(output)
``` | 0 | |
53 | A | Autocomplete | PROGRAMMING | 1,100 | [
"implementation"
] | A. Autocomplete | 2 | 256 | Autocomplete is a program function that enables inputting the text (in editors, command line shells, browsers etc.) completing the text by its inputted part. Vasya is busy working on a new browser called 'BERowser'. He happens to be working on the autocomplete function in the address line at this very moment. A list co... | The first line contains the *s* line which is the inputted part. The second line contains an integer *n* (1<=≤<=*n*<=≤<=100) which is the number of visited pages. Then follow *n* lines which are the visited pages, one on each line. All the lines have lengths of from 1 to 100 symbols inclusively and consist of lowercase... | If *s* is not the beginning of any of *n* addresses of the visited pages, print *s*. Otherwise, print the lexicographically minimal address of one of the visited pages starting from *s*.
The lexicographical order is the order of words in a dictionary. The lexicographical comparison of lines is realized by the '<' o... | [
"next\n2\nnextpermutation\nnextelement\n",
"find\n4\nfind\nfindfirstof\nfindit\nfand\n",
"find\n4\nfondfind\nfondfirstof\nfondit\nfand\n"
] | [
"nextelement\n",
"find\n",
"find\n"
] | none | 500 | [
{
"input": "next\n2\nnextpermutation\nnextelement",
"output": "nextelement"
},
{
"input": "find\n4\nfind\nfindfirstof\nfindit\nfand",
"output": "find"
},
{
"input": "find\n4\nfondfind\nfondfirstof\nfondit\nfand",
"output": "find"
},
{
"input": "kudljmxcse\n4\nkudljmxcse\nszje... | 1,644,815,927 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | s = input()
n = int(input())
length_orig = len(s)
length = 101
for i in range(n):
astring = input()
if astring[:length_orig] == s:
astring_len = len(astring)
if astring_len < length:
length = astring_len
s = astring
print(s) | Title: Autocomplete
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Autocomplete is a program function that enables inputting the text (in editors, command line shells, browsers etc.) completing the text by its inputted part. Vasya is busy working on a new browser called 'BERowser'. He happens... | ```python
s = input()
n = int(input())
length_orig = len(s)
length = 101
for i in range(n):
astring = input()
if astring[:length_orig] == s:
astring_len = len(astring)
if astring_len < length:
length = astring_len
s = astring
print(s)
``` | 0 |
604 | A | Uncowed Forces | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Kevin Sun has just finished competing in Codeforces Round #334! The round was 120 minutes long and featured five problems with maximum point values of 500, 1000, 1500, 2000, and 2500, respectively. Despite the challenging tasks, Kevin was uncowed and bulldozed through all of them, distinguishing himself from the herd a... | The first line of the input contains five space-separated integers *m*1, *m*2, *m*3, *m*4, *m*5, where *m**i* (0<=≤<=*m**i*<=≤<=119) is the time of Kevin's last submission for problem *i*. His last submission is always correct and gets accepted.
The second line contains five space-separated integers *w*1, *w*2, *w*3, ... | Print a single integer, the value of Kevin's final score. | [
"20 40 60 80 100\n0 1 2 3 4\n1 0\n",
"119 119 119 119 119\n0 0 0 0 0\n10 0\n"
] | [
"4900\n",
"4930\n"
] | In the second sample, Kevin takes 119 minutes on all of the problems. Therefore, he gets <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/42158dc2bc78cd21fa679530ae9ef8b9ea298d15.png" style="max-width: 100.0%;max-height: 100.0%;"/> of the points on each problem. So his score from solving pro... | 500 | [
{
"input": "20 40 60 80 100\n0 1 2 3 4\n1 0",
"output": "4900"
},
{
"input": "119 119 119 119 119\n0 0 0 0 0\n10 0",
"output": "4930"
},
{
"input": "3 6 13 38 60\n6 10 10 3 8\n9 9",
"output": "5088"
},
{
"input": "21 44 11 68 75\n6 2 4 8 4\n2 8",
"output": "4522"
},
{... | 1,449,172,962 | 2,147,483,647 | Python 3 | OK | TESTS | 57 | 77 | 0 | m=[int(i) for i in input().split(' ')]
w=[int(i) for i in input().split(' ')]
h=[int(i) for i in input().split(' ')]
s=0
for i in range(5):
x=(i+1)*500
s+=max(0.3*x,(1-m[i]/250)*x-50*w[i])
s=s+h[0]*100-h[1]*50
print(int(s))
| Title: Uncowed Forces
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kevin Sun has just finished competing in Codeforces Round #334! The round was 120 minutes long and featured five problems with maximum point values of 500, 1000, 1500, 2000, and 2500, respectively. Despite the challengin... | ```python
m=[int(i) for i in input().split(' ')]
w=[int(i) for i in input().split(' ')]
h=[int(i) for i in input().split(' ')]
s=0
for i in range(5):
x=(i+1)*500
s+=max(0.3*x,(1-m[i]/250)*x-50*w[i])
s=s+h[0]*100-h[1]*50
print(int(s))
``` | 3 | |
690 | F1 | Tree of Life (easy) | PROGRAMMING | 1,300 | [] | null | null | Heidi has finally found the mythical Tree of Life – a legendary combinatorial structure which is said to contain a prophecy crucially needed to defeat the undead armies.
On the surface, the Tree of Life is just a regular undirected tree well-known from computer science. This means that it is a collection of *n* points... | The first line of the input contains a single integer *n* – the number of vertices in the tree (1<=≤<=*n*<=≤<=10000). The vertices are labeled with the numbers from 1 to *n*. Then *n*<=-<=1 lines follow, each describing one edge using two space-separated numbers *a* *b* – the labels of the vertices connected by the edg... | Print one integer – the number of lifelines in the tree. | [
"4\n1 2\n1 3\n1 4\n",
"5\n1 2\n2 3\n3 4\n3 5\n"
] | [
"3",
"4"
] | In the second sample, there are four lifelines: paths between vertices 1 and 3, 2 and 4, 2 and 5, and 4 and 5. | 0 | [
{
"input": "4\n1 2\n1 3\n1 4",
"output": "3"
},
{
"input": "5\n1 2\n2 3\n3 4\n3 5",
"output": "4"
},
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "3\n2 1\n3 2",
"output": "1"
},
{
"input": "10\n5 1\n1 2\n9 3\n10 5\n6 3\n8 5\n2 7\n2 3\n9 4",
"output": "11"
... | 1,468,151,365 | 13,765 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 204,800 | n = int(input())
Adjacency_List = [set() for l in range(n+1)]
for e in range(n-1):
v1, v2 = map(int, input().split())
Adjacency_List[v1].add(v2)
Adjacency_List[v2].add(v1)
Visited = [False]*(n+1)
paths = 0
Paths = set()
for i in range(1, n+1):
for j in range(1, n+1):
for k in range(1,... | Title: Tree of Life (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Heidi has finally found the mythical Tree of Life – a legendary combinatorial structure which is said to contain a prophecy crucially needed to defeat the undead armies.
On the surface, the Tree of Life is just a r... | ```python
n = int(input())
Adjacency_List = [set() for l in range(n+1)]
for e in range(n-1):
v1, v2 = map(int, input().split())
Adjacency_List[v1].add(v2)
Adjacency_List[v2].add(v1)
Visited = [False]*(n+1)
paths = 0
Paths = set()
for i in range(1, n+1):
for j in range(1, n+1):
for k i... | 0 | |
907 | A | Masha and Bears | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son bear can climb into the smallest car and he likes it. It's known that the largest car is strictly larg... | You are given four integers *V*1, *V*2, *V*3, *V**m*(1<=≤<=*V**i*<=≤<=100) — sizes of father bear, mother bear, son bear and Masha, respectively. It's guaranteed that *V*1<=><=*V*2<=><=*V*3. | Output three integers — sizes of father bear's car, mother bear's car and son bear's car, respectively.
If there are multiple possible solutions, print any.
If there is no solution, print "-1" (without quotes). | [
"50 30 10 10\n",
"100 50 10 21\n"
] | [
"50\n30\n10\n",
"-1\n"
] | In first test case all conditions for cars' sizes are satisfied.
In second test case there is no answer, because Masha should be able to climb into smallest car (so size of smallest car in not less than 21), but son bear should like it, so maximum possible size of it is 20. | 500 | [
{
"input": "50 30 10 10",
"output": "50\n30\n10"
},
{
"input": "100 50 10 21",
"output": "-1"
},
{
"input": "100 50 19 10",
"output": "100\n50\n19"
},
{
"input": "99 50 25 49",
"output": "100\n99\n49"
},
{
"input": "3 2 1 1",
"output": "4\n3\n1"
},
{
"... | 1,514,644,545 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 5,529,600 | father, mother, son, maria = map(int, input().split())
s_max = son * 2
m_max = mother * 2
f_max = father * 2
if s_max < maria or m_max < maria or f_max < maria:
print(-1)
exit(0)
print(f_max)
print(m_max)
print(s_max) | Title: Masha and Bears
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son b... | ```python
father, mother, son, maria = map(int, input().split())
s_max = son * 2
m_max = mother * 2
f_max = father * 2
if s_max < maria or m_max < maria or f_max < maria:
print(-1)
exit(0)
print(f_max)
print(m_max)
print(s_max)
``` | 0 | |
137 | B | Permutation | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | "Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task after some considerable time, the boy asked you to help him.
The sequence of *n* integers is cal... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=5000) which represents how many numbers are in the sequence. The second line contains a sequence of integers *a**i* (1<=≤<=*a**i*<=≤<=5000,<=1<=≤<=*i*<=≤<=*n*). | Print the only number — the minimum number of changes needed to get the permutation. | [
"3\n3 1 2\n",
"2\n2 2\n",
"5\n5 3 3 3 1\n"
] | [
"0\n",
"1\n",
"2\n"
] | The first sample contains the permutation, which is why no replacements are required.
In the second sample it is enough to replace the first element with the number 1 and that will make the sequence the needed permutation.
In the third sample we can replace the second element with number 4 and the fourth element with... | 1,000 | [
{
"input": "3\n3 1 2",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "5\n5 3 3 3 1",
"output": "2"
},
{
"input": "5\n6 6 6 6 6",
"output": "5"
},
{
"input": "10\n1 1 2 2 8 8 7 7 9 9",
"output": "5"
},
{
"input": "8\n9 8 7 6 5 4 3 2"... | 1,629,265,614 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 218 | 20,172,800 | def main():
n = int(input())
arr = list(map(int, input().split()))
print(n - len(set(arr)))
main() | Title: Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task ... | ```python
def main():
n = int(input())
arr = list(map(int, input().split()))
print(n - len(set(arr)))
main()
``` | 0 | |
1,008 | A | Romaji | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant... | The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters. | Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"sumimasen\n",
"ninja\n",
"codeforces\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | 500 | [
{
"input": "sumimasen",
"output": "YES"
},
{
"input": "ninja",
"output": "YES"
},
{
"input": "codeforces",
"output": "NO"
},
{
"input": "auuaoonntanonnuewannnnpuuinniwoonennyolonnnvienonpoujinndinunnenannmuveoiuuhikucuziuhunnnmunzancenen",
"output": "YES"
},
{
"in... | 1,673,005,583 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | r=["a","e","i","o","u","n"]
def is_vowel(a):
if a[-1] not in r:
print ("No")
else:
q=0
list=[]
for i in a:
if i in r:
list.append("YES")
else:
list.append("NO")
q=q+1
m=0
for i in list[:-1]:
if list[m+1]=="NO" and list[m]=="NO":
... | Title: Romaji
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after eve... | ```python
r=["a","e","i","o","u","n"]
def is_vowel(a):
if a[-1] not in r:
print ("No")
else:
q=0
list=[]
for i in a:
if i in r:
list.append("YES")
else:
list.append("NO")
q=q+1
m=0
for i in list[:-1]:
if list[m+1]=="NO" and list[m]=="NO"... | 0 | |
450 | A | Jzzhu and Children | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies.
Jzzhu asks children to line up. Initially, the *i*-th child stands at the *i*-th place of the line. Then Jzzhu start distribution of... | The first line contains two integers *n*,<=*m* (1<=≤<=*n*<=≤<=100; 1<=≤<=*m*<=≤<=100). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100). | Output a single integer, representing the number of the last child. | [
"5 2\n1 3 1 4 2\n",
"6 4\n1 1 2 2 3 3\n"
] | [
"4\n",
"6\n"
] | Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the en... | 500 | [
{
"input": "5 2\n1 3 1 4 2",
"output": "4"
},
{
"input": "6 4\n1 1 2 2 3 3",
"output": "6"
},
{
"input": "7 3\n6 1 5 4 2 3 1",
"output": "4"
},
{
"input": "10 5\n2 7 3 6 2 5 1 3 4 5",
"output": "4"
},
{
"input": "100 1\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18... | 1,637,352,418 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<iostream>
#include<vector>
using namespace std;
int main()
{
int n;
cin>>n;
int m;
cin>>m;
int max=0;
int pos;
for( int i=0; i<n; i++)
{
int t;
cin>>t;
if( t>=max)
{
max=t;
pos=i;
}
}
... | Title: Jzzhu and Children
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies.
Jzzhu asks children to line ... | ```python
#include<iostream>
#include<vector>
using namespace std;
int main()
{
int n;
cin>>n;
int m;
cin>>m;
int max=0;
int pos;
for( int i=0; i<n; i++)
{
int t;
cin>>t;
if( t>=max)
{
max=t;
pos=i;
}
... | -1 | |
427 | A | Police Recruits | PROGRAMMING | 800 | [
"implementation"
] | null | null | The police department of your city has just started its journey. Initially, they don’t have any manpower. So, they started hiring new recruits in groups.
Meanwhile, crimes keeps occurring within the city. One member of the police force can investigate only one crime during his/her lifetime.
If there is no police offi... | The first line of input will contain an integer *n* (1<=≤<=*n*<=≤<=105), the number of events. The next line will contain *n* space-separated integers.
If the integer is -1 then it means a crime has occurred. Otherwise, the integer will be positive, the number of officers recruited together at that time. No more than ... | Print a single integer, the number of crimes which will go untreated. | [
"3\n-1 -1 1\n",
"8\n1 -1 1 -1 -1 1 1 1\n",
"11\n-1 -1 2 -1 -1 -1 -1 -1 -1 -1 -1\n"
] | [
"2\n",
"1\n",
"8\n"
] | Lets consider the second example:
1. Firstly one person is hired. 1. Then crime appears, the last hired person will investigate this crime. 1. One more person is hired. 1. One more crime appears, the last hired person will investigate this crime. 1. Crime appears. There is no free policeman at the time, so this c... | 500 | [
{
"input": "3\n-1 -1 1",
"output": "2"
},
{
"input": "8\n1 -1 1 -1 -1 1 1 1",
"output": "1"
},
{
"input": "11\n-1 -1 2 -1 -1 -1 -1 -1 -1 -1 -1",
"output": "8"
},
{
"input": "7\n-1 -1 1 1 -1 -1 1",
"output": "2"
},
{
"input": "21\n-1 -1 -1 -1 -1 3 2 -1 6 -1 -1 2 1 ... | 1,679,992,476 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 61 | 0 | x=int(input())
y=list(map(str,input().split()))
w=""
q=0
e=0
ans=0
for i in range(x):
if y[i]=="-1":
q-=1
else:
e+=int(y[i])
if i==x-1:
continue
if i!=0 and w!=y[i] :
ans=q+e
w=i
print(abs(ans)) | Title: Police Recruits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The police department of your city has just started its journey. Initially, they don’t have any manpower. So, they started hiring new recruits in groups.
Meanwhile, crimes keeps occurring within the city. One member of... | ```python
x=int(input())
y=list(map(str,input().split()))
w=""
q=0
e=0
ans=0
for i in range(x):
if y[i]=="-1":
q-=1
else:
e+=int(y[i])
if i==x-1:
continue
if i!=0 and w!=y[i] :
ans=q+e
w=i
print(abs(ans))
``` | 0 | |
49 | C | Disposition | PROGRAMMING | 1,700 | [
"constructive algorithms",
"math"
] | C. Disposition | 2 | 256 | Vasya bought the collected works of a well-known Berland poet Petya in *n* volumes. The volumes are numbered from 1 to *n*. He thinks that it does not do to arrange the book simply according to their order. Vasya wants to minimize the number of the disposition’s divisors — the positive integers *i* such that for at lea... | The first line contains number *n* (1<=≤<=*n*<=≤<=100000) which represents the number of volumes and free places. | Print *n* numbers — the sought disposition with the minimum divisor number. The *j*-th number (1<=≤<=*j*<=≤<=*n*) should be equal to *p*(*j*) — the number of tome that stands on the *j*-th place. If there are several solutions, print any of them. | [
"2\n",
"3\n"
] | [
"2 1 \n",
"1 3 2 \n"
] | none | 1,500 | [
{
"input": "2",
"output": "2 1 "
},
{
"input": "3",
"output": "1 3 2 "
},
{
"input": "4",
"output": "2 1 4 3 "
},
{
"input": "5",
"output": "1 3 2 5 4 "
},
{
"input": "6",
"output": "2 1 4 3 6 5 "
},
{
"input": "1",
"output": "1 "
},
{
"inp... | 1,691,708,940 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 310 | 7,987,200 | n=int(input())
l=[]
s=0
if n%2:
l=[1]
s=1
while s<n:
l.append(s+2)
l.append(s+1)
s+=2
print(*l) | Title: Disposition
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya bought the collected works of a well-known Berland poet Petya in *n* volumes. The volumes are numbered from 1 to *n*. He thinks that it does not do to arrange the book simply according to their order. Vasya wants to minim... | ```python
n=int(input())
l=[]
s=0
if n%2:
l=[1]
s=1
while s<n:
l.append(s+2)
l.append(s+1)
s+=2
print(*l)
``` | 3.907623 |
253 | A | Boys and Girls | PROGRAMMING | 1,100 | [
"greedy"
] | null | null | There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to *n*<=+<=*m*. Then the number of integers *i* (1<=≤<=*i*<=<<=*n*<=+<=*m*) such th... | The single line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), separated by a space. | Print a line of *n*<=+<=*m* characters. Print on the *i*-th position of the line character "B", if the *i*-th position of your arrangement should have a boy and "G", if it should have a girl.
Of course, the number of characters "B" should equal *n* and the number of characters "G" should equal *m*. If there are multi... | [
"3 3\n",
"4 2\n"
] | [
"GBGBGB\n",
"BGBGBB\n"
] | In the first sample another possible answer is BGBGBG.
In the second sample answer BBGBGB is also optimal. | 500 | [
{
"input": "3 3",
"output": "GBGBGB"
},
{
"input": "4 2",
"output": "BGBGBB"
},
{
"input": "5 5",
"output": "GBGBGBGBGB"
},
{
"input": "6 4",
"output": "BGBGBGBGBB"
},
{
"input": "100 1",
"output": "BGBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB... | 1,620,365,941 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 186 | 22,220,800 | B, G = map(int,input().split())
print(B, G)
output = ''
sum_of = (B + G)
for i in range(sum_of):
if B != 0:
output += 'B'
B -= 1
if G != 0:
output += 'G'
G -= 1
print(output)
| Title: Boys and Girls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by n... | ```python
B, G = map(int,input().split())
print(B, G)
output = ''
sum_of = (B + G)
for i in range(sum_of):
if B != 0:
output += 'B'
B -= 1
if G != 0:
output += 'G'
G -= 1
print(output)
``` | -1 | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,599,122,381 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 248 | 716,800 | count=0
def c(s):
global count
count+=1
l=list(s)
exp=0
for e in l:
exp=exp+int(e)
return str(exp)
s=input()
while(len(s)>1):
s=c(s)
print(count)
| Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
count=0
def c(s):
global count
count+=1
l=list(s)
exp=0
for e in l:
exp=exp+int(e)
return str(exp)
s=input()
while(len(s)>1):
s=c(s)
print(count)
``` | 3.93671 |
706 | B | Interesting drink | PROGRAMMING | 1,100 | [
"binary search",
"dp",
"implementation"
] | null | null | Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single i... | Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day. | [
"5\n3 10 8 6 11\n4\n1\n10\n3\n11\n"
] | [
"0\n4\n1\n5\n"
] | On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | 1,000 | [
{
"input": "5\n3 10 8 6 11\n4\n1\n10\n3\n11",
"output": "0\n4\n1\n5"
},
{
"input": "5\n868 987 714 168 123\n10\n424\n192\n795\n873\n117\n914\n735\n158\n631\n471",
"output": "2\n2\n3\n4\n0\n4\n3\n1\n2\n2"
},
{
"input": "3\n435 482 309\n7\n245\n241\n909\n745\n980\n29\n521",
"output": "... | 1,695,036,805 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | n = int(input())
prices = list(map(int, input().split()))
q = int(input())
coins = []
for i in range(q):
coins.append(int(input()))
def binary_search(arr, low, high, x):
if high >= low:
mid = (high + low) // 2
if arr[mid] == x:
return mid
elif arr[mid] > x:
return binary_search(arr, low, ... | Title: Interesting drink
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known tha... | ```python
n = int(input())
prices = list(map(int, input().split()))
q = int(input())
coins = []
for i in range(q):
coins.append(int(input()))
def binary_search(arr, low, high, x):
if high >= low:
mid = (high + low) // 2
if arr[mid] == x:
return mid
elif arr[mid] > x:
return binary_search(... | 0 | |
237 | A | Free Cash | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends less than a minute to serve each client, but if a client comes in and sees that there is no free... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), that is the number of cafe visitors.
Each of the following *n* lines has two space-separated integers *h**i* and *m**i* (0<=≤<=*h**i*<=≤<=23; 0<=≤<=*m**i*<=≤<=59), representing the time when the *i*-th person comes into the cafe.
Note that the time is... | Print a single integer — the minimum number of cashes, needed to serve all clients next day. | [
"4\n8 0\n8 10\n8 10\n8 45\n",
"3\n0 12\n10 11\n22 22\n"
] | [
"2\n",
"1\n"
] | In the first sample it is not enough one cash to serve all clients, because two visitors will come into cafe in 8:10. Therefore, if there will be one cash in cafe, then one customer will be served by it, and another one will not wait and will go away.
In the second sample all visitors will come in different times, so ... | 500 | [
{
"input": "4\n8 0\n8 10\n8 10\n8 45",
"output": "2"
},
{
"input": "3\n0 12\n10 11\n22 22",
"output": "1"
},
{
"input": "5\n12 8\n15 27\n15 27\n16 2\n19 52",
"output": "2"
},
{
"input": "7\n5 6\n7 34\n7 34\n7 34\n12 29\n15 19\n20 23",
"output": "3"
},
{
"input": "... | 1,605,024,707 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 10 | 436 | 4,403,200 | n=int(input())
m=[input()for i in range(n)]
kas=1
b=[]
for i in range(n-1):
if m[i]==m[i+1]:
kas+=1
flag=1
else:
b.append(kas)
kas=1
print(max(b))
| Title: Free Cash
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends l... | ```python
n=int(input())
m=[input()for i in range(n)]
kas=1
b=[]
for i in range(n-1):
if m[i]==m[i+1]:
kas+=1
flag=1
else:
b.append(kas)
kas=1
print(max(b))
``` | -1 | |
333 | A | Secrets | PROGRAMMING | 1,600 | [
"greedy"
] | null | null | Gerald has been selling state secrets at leisure. All the secrets cost the same: *n* marks. The state which secrets Gerald is selling, has no paper money, only coins. But there are coins of all positive integer denominations that are powers of three: 1 mark, 3 marks, 9 marks, 27 marks and so on. There are no coins of o... | The single line contains a single integer *n* (1<=≤<=*n*<=≤<=1017).
Please, do not use the %lld specifier to read or write 64 bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | In a single line print an integer: the maximum number of coins the unlucky buyer could have paid with. | [
"1\n",
"4\n"
] | [
"1\n",
"2\n"
] | In the first test case, if a buyer has exactly one coin of at least 3 marks, then, to give Gerald one mark, he will have to give this coin. In this sample, the customer can not have a coin of one mark, as in this case, he will be able to give the money to Gerald without any change.
In the second test case, if the buye... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "3",
"output": "1"
},
{
"input": "8",
"output": "3"
},
{
"input": "10",
"output": "4"
},
{
"input": "100000000000000000",
"output": "33333333333333334"
},
{
"input... | 1,374,914,925 | 1,125 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 92 | 0 | n = int(input())
ans = 0
while n > 0:
ans += n % 3
n //= 3
print(ans) | Title: Secrets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald has been selling state secrets at leisure. All the secrets cost the same: *n* marks. The state which secrets Gerald is selling, has no paper money, only coins. But there are coins of all positive integer denominations th... | ```python
n = int(input())
ans = 0
while n > 0:
ans += n % 3
n //= 3
print(ans)
``` | 0 | |
954 | A | Diagonal Walking | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mikhail walks on a 2D plane. He can go either up or right. You are given a sequence of Mikhail's moves. He thinks that this sequence is too long and he wants to make it as short as possible.
In the given sequence moving up is described by character U and moving right is described by character R. Mikhail can replace an... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=100) — the length of the sequence. The second line contains the sequence consisting of *n* characters U and R. | Print the minimum possible length of the sequence of moves after all replacements are done. | [
"5\nRUURU\n",
"17\nUUURRRRRUUURURUUU\n"
] | [
"3\n",
"13\n"
] | In the first test the shortened sequence of moves may be DUD (its length is 3).
In the second test the shortened sequence of moves can be UUDRRRDUDDUUU (its length is 13). | 0 | [
{
"input": "5\nRUURU",
"output": "3"
},
{
"input": "17\nUUURRRRRUUURURUUU",
"output": "13"
},
{
"input": "100\nUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU",
"output": "100"
},
{
"input": "100\nRRURRUUUURURRRURRRRURRRRRR... | 1,637,646,935 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | l = int(input())
s = input()
n = 0
i = 0
while i<n-1:
if s[i]!=s[i+1]:
n+=1
i+=2
else :
i+=1
print(l-n) | Title: Diagonal Walking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mikhail walks on a 2D plane. He can go either up or right. You are given a sequence of Mikhail's moves. He thinks that this sequence is too long and he wants to make it as short as possible.
In the given sequence movi... | ```python
l = int(input())
s = input()
n = 0
i = 0
while i<n-1:
if s[i]!=s[i+1]:
n+=1
i+=2
else :
i+=1
print(l-n)
``` | 0 | |
884 | A | Book Reading | PROGRAMMING | 800 | [
"implementation"
] | null | null | Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of seconds that Luba has to spend working during *i*-th day is *a**i*. If some free time remains, she... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=100, 1<=≤<=*t*<=≤<=106) — the number of days and the time required to read the book.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=86400) — the time Luba has to spend on her work during *i*-th day. | Print the minimum day Luba can finish reading the book.
It is guaranteed that answer doesn't exceed *n*. | [
"2 2\n86400 86398\n",
"2 86400\n0 86400\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "2 2\n86400 86398",
"output": "2"
},
{
"input": "2 86400\n0 86400",
"output": "1"
},
{
"input": "2 86400\n1 86399",
"output": "2"
},
{
"input": "100 1000000\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,561,577,931 | 2,147,483,647 | Python 3 | OK | TESTS | 16 | 109 | 0 | n,t=map(int,input().split())
a=list(map(int,input().split()))
b=[86400-a[i] for i in range(len(a))]
m=0
for i in range(len(b)):
m+=b[i]
if m>=t:
print(i+1)
break | Title: Book Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of ... | ```python
n,t=map(int,input().split())
a=list(map(int,input().split()))
b=[86400-a[i] for i in range(len(a))]
m=0
for i in range(len(b)):
m+=b[i]
if m>=t:
print(i+1)
break
``` | 3 | |
842 | B | Gleb And Pizza | PROGRAMMING | 1,100 | [
"geometry"
] | null | null | Gleb ordered pizza home. When the courier delivered the pizza, he was very upset, because several pieces of sausage lay on the crust, and he does not really like the crust.
The pizza is a circle of radius *r* and center at the origin. Pizza consists of the main part — circle of radius *r*<=-<=*d* with center at the or... | First string contains two integer numbers *r* and *d* (0<=≤<=*d*<=<<=*r*<=≤<=500) — the radius of pizza and the width of crust.
Next line contains one integer number *n* — the number of pieces of sausage (1<=≤<=*n*<=≤<=105).
Each of next *n* lines contains three integer numbers *x**i*, *y**i* and *r**i* (<=-<=500<... | Output the number of pieces of sausage that lay on the crust. | [
"8 4\n7\n7 8 1\n-7 3 2\n0 2 1\n0 -2 2\n-3 -3 1\n0 6 2\n5 3 1\n",
"10 8\n4\n0 0 9\n0 0 10\n1 0 1\n1 0 2\n"
] | [
"2\n",
"0\n"
] | Below is a picture explaining the first example. Circles of green color denote pieces of sausage lying on the crust. | 1,000 | [
{
"input": "8 4\n7\n7 8 1\n-7 3 2\n0 2 1\n0 -2 2\n-3 -3 1\n0 6 2\n5 3 1",
"output": "2"
},
{
"input": "10 8\n4\n0 0 9\n0 0 10\n1 0 1\n1 0 2",
"output": "0"
},
{
"input": "1 0\n1\n1 1 0",
"output": "0"
},
{
"input": "3 0\n5\n3 0 0\n0 3 0\n-3 0 0\n0 -3 0\n3 0 1",
"output": ... | 1,535,711,855 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 577 | 307,200 | r1, d = map(int, input().split())
r2, k = r1 - d, 0
for _ in range(int(input())):
x, y, r = map(int, input().split())
s = (x ** 2 + y ** 2) ** 0.5
if s - r >= r2 and s + r <= r1:
k += 1
print(k) | Title: Gleb And Pizza
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gleb ordered pizza home. When the courier delivered the pizza, he was very upset, because several pieces of sausage lay on the crust, and he does not really like the crust.
The pizza is a circle of radius *r* and center... | ```python
r1, d = map(int, input().split())
r2, k = r1 - d, 0
for _ in range(int(input())):
x, y, r = map(int, input().split())
s = (x ** 2 + y ** 2) ** 0.5
if s - r >= r2 and s + r <= r1:
k += 1
print(k)
``` | 3 | |
939 | A | Love Triangle | PROGRAMMING | 800 | [
"graphs"
] | null | null | As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with number *f**i*, where 1<=≤<=*f**i*<=≤<=*n* and *f**i*<=≠<=*i*.
We call a love triangle a situation ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=5000) — the number of planes.
The second line contains *n* integers *f*1,<=*f*2,<=...,<=*f**n* (1<=≤<=*f**i*<=≤<=*n*, *f**i*<=≠<=*i*), meaning that the *i*-th plane likes the *f**i*-th. | Output «YES» if there is a love triangle consisting of planes on Earth. Otherwise, output «NO».
You can output any letter in lower case or in upper case. | [
"5\n2 4 5 1 3\n",
"5\n5 5 5 5 1\n"
] | [
"YES\n",
"NO\n"
] | In first example plane 2 likes plane 4, plane 4 likes plane 1, plane 1 likes plane 2 and that is a love triangle.
In second example there are no love triangles. | 500 | [
{
"input": "5\n2 4 5 1 3",
"output": "YES"
},
{
"input": "5\n5 5 5 5 1",
"output": "NO"
},
{
"input": "3\n3 1 2",
"output": "YES"
},
{
"input": "10\n4 10 9 5 3 1 5 10 6 4",
"output": "NO"
},
{
"input": "10\n5 5 4 9 10 9 9 5 3 1",
"output": "YES"
},
{
"... | 1,635,747,948 | 2,147,483,647 | Python 3 | OK | TESTS | 16 | 46 | 4,505,600 | t=int(input())
a=[int(x) for x in input().split()]
a=[0]+a
check=0
for i in range(1,len(a)):
if a[a[a[i]]]==i:
check=1
break
if check==0:
print('NO')
else:
print('YES') | Title: Love Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with ... | ```python
t=int(input())
a=[int(x) for x in input().split()]
a=[0]+a
check=0
for i in range(1,len(a)):
if a[a[a[i]]]==i:
check=1
break
if check==0:
print('NO')
else:
print('YES')
``` | 3 | |
554 | A | Kyoya and Photobooks | PROGRAMMING | 900 | [
"brute force",
"math",
"strings"
] | null | null | Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the pho... | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters. | Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make. | [
"a\n",
"hi\n"
] | [
"51\n",
"76\n"
] | In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | 250 | [
{
"input": "a",
"output": "51"
},
{
"input": "hi",
"output": "76"
},
{
"input": "y",
"output": "51"
},
{
"input": "kgan",
"output": "126"
},
{
"input": "zoabkyuvus",
"output": "276"
},
{
"input": "spyemhyznjieyhhbk",
"output": "451"
},
{
"i... | 1,457,541,412 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 62 | 0 | s = input()
D = set()
ch = 'abcdefghijklmnopqrstuvwxyz'
for i in range(len(s)+1):
for j in ch:
D.add(s[:i]+j+s[i:])
print(len(D))
| Title: Kyoya and Photobooks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos b... | ```python
s = input()
D = set()
ch = 'abcdefghijklmnopqrstuvwxyz'
for i in range(len(s)+1):
for j in ch:
D.add(s[:i]+j+s[i:])
print(len(D))
``` | 3 | |
79 | B | Colorful Field | PROGRAMMING | 1,400 | [
"implementation",
"sortings"
] | B. Colorful Field | 2 | 256 | Fox Ciel saw a large field while she was on a bus. The field was a *n*<=×<=*m* rectangle divided into 1<=×<=1 cells. Some cells were wasteland, and other each cell contained crop plants: either carrots or kiwis or grapes.
After seeing the field carefully, Ciel found that the crop plants of each cell were planted in f... | In the first line there are four positive integers *n*,<=*m*,<=*k*,<=*t* (1<=≤<=*n*<=≤<=4·104,<=1<=≤<=*m*<=≤<=4·104,<=1<=≤<=*k*<=≤<=103,<=1<=≤<=*t*<=≤<=103), each of which represents the height of the field, the width of the field, the number of waste cells and the number of queries that ask the kind of crop plants in ... | For each query, if the cell is waste, print Waste. Otherwise, print the name of crop plants in the cell: either Carrots or Kiwis or Grapes. | [
"4 5 5 6\n4 3\n1 3\n3 3\n2 5\n3 2\n1 3\n1 4\n2 3\n2 4\n1 1\n1 1\n"
] | [
"Waste\nGrapes\nCarrots\nKiwis\nCarrots\nCarrots\n"
] | The sample corresponds to the figure in the statement. | 1,000 | [
{
"input": "4 5 5 6\n4 3\n1 3\n3 3\n2 5\n3 2\n1 3\n1 4\n2 3\n2 4\n1 1\n1 1",
"output": "Waste\nGrapes\nCarrots\nKiwis\nCarrots\nCarrots"
},
{
"input": "2 3 2 2\n1 1\n2 2\n2 1\n2 2",
"output": "Grapes\nWaste"
},
{
"input": "31 31 31 4\n4 9\n16 27\n11 29\n8 28\n11 2\n10 7\n22 6\n1 25\n14 8... | 1,589,050,637 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 2,000 | 42,496,000 | n,m,k,t=map(int,input().split())
l=[]
for i in range(n):
a=[]
for j in range (m):
a.append(True)
l.append(a)
for i in range(k):
a,b=map(int,input().split())
l[a-1][b-1]="Waste"
A=['Carrots','Kiwis','Grapes']
k=0
for i in range(n):
for j in range(m):
if l[i... | Title: Colorful Field
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Fox Ciel saw a large field while she was on a bus. The field was a *n*<=×<=*m* rectangle divided into 1<=×<=1 cells. Some cells were wasteland, and other each cell contained crop plants: either carrots or kiwis or grapes.
... | ```python
n,m,k,t=map(int,input().split())
l=[]
for i in range(n):
a=[]
for j in range (m):
a.append(True)
l.append(a)
for i in range(k):
a,b=map(int,input().split())
l[a-1][b-1]="Waste"
A=['Carrots','Kiwis','Grapes']
k=0
for i in range(n):
for j in range(m):
... | 0 |
112 | A | Petya and Strings | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Petya and Strings | 2 | 256 | Little Petya loves presents. His mum bought him two strings of the same size for his birthday. The strings consist of uppercase and lowercase Latin letters. Now Petya wants to compare those two strings lexicographically. The letters' case does not matter, that is an uppercase letter is considered equivalent to the corr... | Each of the first two lines contains a bought string. The strings' lengths range from 1 to 100 inclusive. It is guaranteed that the strings are of the same length and also consist of uppercase and lowercase Latin letters. | If the first string is less than the second one, print "-1". If the second string is less than the first one, print "1". If the strings are equal, print "0". Note that the letters' case is not taken into consideration when the strings are compared. | [
"aaaa\naaaA\n",
"abs\nAbz\n",
"abcdefg\nAbCdEfF\n"
] | [
"0\n",
"-1\n",
"1\n"
] | If you want more formal information about the lexicographical order (also known as the "dictionary order" or "alphabetical order"), you can visit the following site:
- http://en.wikipedia.org/wiki/Lexicographical_order | 500 | [
{
"input": "aaaa\naaaA",
"output": "0"
},
{
"input": "abs\nAbz",
"output": "-1"
},
{
"input": "abcdefg\nAbCdEfF",
"output": "1"
},
{
"input": "asadasdasd\nasdwasdawd",
"output": "-1"
},
{
"input": "aslkjlkasdd\nasdlkjdajwi",
"output": "1"
},
{
"input":... | 1,696,053,842 | 2,147,483,647 | PyPy 3 | OK | TESTS | 53 | 186 | 0 | string1 = str(input())
string2 = str(input())
if len(string1) in range(101):
if string1.lower() == string2.lower():
print('0')
elif string1.lower() > string2.lower():
print('1')
else:
print('-1') | Title: Petya and Strings
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya loves presents. His mum bought him two strings of the same size for his birthday. The strings consist of uppercase and lowercase Latin letters. Now Petya wants to compare those two strings lexicographically. ... | ```python
string1 = str(input())
string2 = str(input())
if len(string1) in range(101):
if string1.lower() == string2.lower():
print('0')
elif string1.lower() > string2.lower():
print('1')
else:
print('-1')
``` | 3.9535 |
779 | A | Pupils Redistribution | PROGRAMMING | 1,000 | [
"constructive algorithms",
"math"
] | null | null | In Berland each high school student is characterized by academic performance — integer value between 1 and 5.
In high school 0xFF there are two groups of pupils: the group *A* and the group *B*. Each group consists of exactly *n* students. An academic performance of each student is known — integer value between 1 and ... | The first line of the input contains integer number *n* (1<=≤<=*n*<=≤<=100) — number of students in both groups.
The second line contains sequence of integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=5), where *a**i* is academic performance of the *i*-th student of the group *A*.
The third line contains se... | Print the required minimum number of exchanges or -1, if the desired distribution of students can not be obtained. | [
"4\n5 4 4 4\n5 5 4 5\n",
"6\n1 1 1 1 1 1\n5 5 5 5 5 5\n",
"1\n5\n3\n",
"9\n3 2 5 5 2 3 3 3 2\n4 1 4 1 1 2 4 4 1\n"
] | [
"1\n",
"3\n",
"-1\n",
"4\n"
] | none | 500 | [
{
"input": "4\n5 4 4 4\n5 5 4 5",
"output": "1"
},
{
"input": "6\n1 1 1 1 1 1\n5 5 5 5 5 5",
"output": "3"
},
{
"input": "1\n5\n3",
"output": "-1"
},
{
"input": "9\n3 2 5 5 2 3 3 3 2\n4 1 4 1 1 2 4 4 1",
"output": "4"
},
{
"input": "1\n1\n2",
"output": "-1"
... | 1,488,100,304 | 4,004 | Python 3 | OK | TESTS | 81 | 62 | 4,608,000 |
def isEven(number):
if number % 2 == 0:
return True
else:
return False
studentCount = int(input());
gradesA = [int(x) for x in input().split(" ")]
gradesB = [int(x) for x in input().split(" ")]
gradeCountA = [0, 0, 0,0, 0, 0]
gradeCountB = [0, 0, 0,0, 0, 0]
for x in gradesA... | Title: Pupils Redistribution
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland each high school student is characterized by academic performance — integer value between 1 and 5.
In high school 0xFF there are two groups of pupils: the group *A* and the group *B*. Each group consis... | ```python
def isEven(number):
if number % 2 == 0:
return True
else:
return False
studentCount = int(input());
gradesA = [int(x) for x in input().split(" ")]
gradesB = [int(x) for x in input().split(" ")]
gradeCountA = [0, 0, 0,0, 0, 0]
gradeCountB = [0, 0, 0,0, 0, 0]
for x ... | 3 | |
37 | A | Towers | PROGRAMMING | 1,000 | [
"sortings"
] | A. Towers | 2 | 256 | Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct the minimal number of towers from the bars. Help Vasya to use the bars in the best way ... | The first line contains an integer *N* (1<=≤<=*N*<=≤<=1000) — the number of bars at Vasya’s disposal. The second line contains *N* space-separated integers *l**i* — the lengths of the bars. All the lengths are natural numbers not exceeding 1000. | In one line output two numbers — the height of the largest tower and their total number. Remember that Vasya should use all the bars. | [
"3\n1 2 3\n",
"4\n6 5 6 7\n"
] | [
"1 3\n",
"2 3\n"
] | none | 500 | [
{
"input": "3\n1 2 3",
"output": "1 3"
},
{
"input": "4\n6 5 6 7",
"output": "2 3"
},
{
"input": "4\n3 2 1 1",
"output": "2 3"
},
{
"input": "4\n1 2 3 3",
"output": "2 3"
},
{
"input": "3\n20 22 36",
"output": "1 3"
},
{
"input": "25\n47 30 94 41 45 20... | 1,551,277,275 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 218 | 0 | n=int(input())
yi=list(map(int,input().split()))
d=dict()
a=n
for i in range(n):
if(yi[i] in d.keys()):
d[yi[i]]+=1
a-=1
else:
d[yi[i]]=1
p=max(d.values())
print(p," ",a) | Title: Towers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct... | ```python
n=int(input())
yi=list(map(int,input().split()))
d=dict()
a=n
for i in range(n):
if(yi[i] in d.keys()):
d[yi[i]]+=1
a-=1
else:
d[yi[i]]=1
p=max(d.values())
print(p," ",a)
``` | 3.9455 |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,688,368,626 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 0 | a = int(input(""))
g =0
while True:
if a - 100 >= 0:
a -= 100
g += 1
elif a - 20 >= 0:
a -= 20
g += 1
elif a - 10 >= 0:
a -= 10
elif a - 5 >= 0:
a -= 5
g += 1
elif a - 1 >= 0:
a -= 1
g += 1
else:
b... | Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
a = int(input(""))
g =0
while True:
if a - 100 >= 0:
a -= 100
g += 1
elif a - 20 >= 0:
a -= 20
g += 1
elif a - 10 >= 0:
a -= 10
elif a - 5 >= 0:
a -= 5
g += 1
elif a - 1 >= 0:
a -= 1
g += 1
else:
... | 0 | |
118 | A | String Task | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:
- deletes all the vowels, - inserts a character "." before each consonant, - replaces ... | The first line represents input string of Petya's program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive. | Print the resulting string. It is guaranteed that this string is not empty. | [
"tour\n",
"Codeforces\n",
"aBAcAba\n"
] | [
".t.r\n",
".c.d.f.r.c.s\n",
".b.c.b\n"
] | none | 500 | [
{
"input": "tour",
"output": ".t.r"
},
{
"input": "Codeforces",
"output": ".c.d.f.r.c.s"
},
{
"input": "aBAcAba",
"output": ".b.c.b"
},
{
"input": "obn",
"output": ".b.n"
},
{
"input": "wpwl",
"output": ".w.p.w.l"
},
{
"input": "ggdvq",
"output": "... | 1,698,152,924 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | a=input()
b=""
arr=[]
for num in a:
arr.append(num)
vow=["A","E","I","O","U","a","e","i","o","u"]
l=0
while True:
if arr[l] in vow:
arr.remove(arr[l])
else:
l=l+1
if l==len(arr):
break
for i in range(0,len(arr)):
arr[i]=arr[i].upper()
brr=[]
for m in range (0... | Title: String Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters... | ```python
a=input()
b=""
arr=[]
for num in a:
arr.append(num)
vow=["A","E","I","O","U","a","e","i","o","u"]
l=0
while True:
if arr[l] in vow:
arr.remove(arr[l])
else:
l=l+1
if l==len(arr):
break
for i in range(0,len(arr)):
arr[i]=arr[i].upper()
brr=[]
for m i... | 0 | |
676 | C | Vasya and String | PROGRAMMING | 1,500 | [
"binary search",
"dp",
"strings",
"two pointers"
] | null | null | High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequence) consisting of equal letters.
Vasya can change no more than *k* characters of the original strin... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100<=000,<=0<=≤<=*k*<=≤<=*n*) — the length of the string and the maximum number of characters to change.
The second line contains the string, consisting of letters 'a' and 'b' only. | Print the only integer — the maximum beauty of the string Vasya can achieve by changing no more than *k* characters. | [
"4 2\nabba\n",
"8 1\naabaabaa\n"
] | [
"4\n",
"5\n"
] | In the first sample, Vasya can obtain both strings "aaaa" and "bbbb".
In the second sample, the optimal answer is obtained with the string "aaaaabaa" or with the string "aabaaaaa". | 1,500 | [
{
"input": "4 2\nabba",
"output": "4"
},
{
"input": "8 1\naabaabaa",
"output": "5"
},
{
"input": "1 0\na",
"output": "1"
},
{
"input": "1 1\nb",
"output": "1"
},
{
"input": "1 0\nb",
"output": "1"
},
{
"input": "1 1\na",
"output": "1"
},
{
... | 1,619,372,687 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n,k = input().split()
n,k = int(n),int(k)
s = input()
b = 0
def beleza(letra):
beleza = 0
cont_beleza = 0
a = 0
while True:
cont = 0
cont_beleza = 0
for i in range(a, n):
if s[i] == letra:
cont_beleza += 1
elif cont < k:
cont_beleza += 1
cont +... | Title: Vasya and String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequ... | ```python
n,k = input().split()
n,k = int(n),int(k)
s = input()
b = 0
def beleza(letra):
beleza = 0
cont_beleza = 0
a = 0
while True:
cont = 0
cont_beleza = 0
for i in range(a, n):
if s[i] == letra:
cont_beleza += 1
elif cont < k:
cont_beleza += 1
... | 0 | |
955 | A | Feed the cat | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | After waking up at *hh*:*mm*, Andrew realised that he had forgotten to feed his only cat for yet another time (guess why there's only one cat). The cat's current hunger level is *H* points, moreover each minute without food increases his hunger by *D* points.
At any time Andrew can visit the store where tasty buns are... | The first line contains two integers *hh* and *mm* (00<=≤<=*hh*<=≤<=23,<=00<=≤<=*mm*<=≤<=59) — the time of Andrew's awakening.
The second line contains four integers *H*, *D*, *C* and *N* (1<=≤<=*H*<=≤<=105,<=1<=≤<=*D*,<=*C*,<=*N*<=≤<=102). | Output the minimum amount of money to within three decimal digits. You answer is considered correct, if its absolute or relative error does not exceed 10<=-<=4.
Formally, let your answer be *a*, and the jury's answer be *b*. Your answer is considered correct if . | [
"19 00\n255 1 100 1\n",
"17 41\n1000 6 15 11\n"
] | [
"25200.0000\n",
"1365.0000\n"
] | In the first sample Andrew can visit the store at exactly 20:00. The cat's hunger will be equal to 315, hence it will be necessary to purchase 315 buns. The discount makes the final answer 25200 roubles.
In the second sample it's optimal to visit the store right after he wakes up. Then he'll have to buy 91 bins per 15... | 500 | [
{
"input": "19 00\n255 1 100 1",
"output": "25200.0000"
},
{
"input": "17 41\n1000 6 15 11",
"output": "1365.0000"
},
{
"input": "16 34\n61066 14 50 59",
"output": "43360.0000"
},
{
"input": "18 18\n23331 86 87 41",
"output": "49590.0000"
},
{
"input": "10 48\n684... | 1,623,984,006 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 77 | 0 | import math
hr, mi = map(int, input().split() )
H, D, C, N = map(int, input().split())
if hr >= 20:
# print("Sale Already started")
C_discount = C - (C/5)
total = math.ceil(H/N)*C_discount
print("{0:.4f}".format(total) )
else:
totalNow = math.ceil(H/N)*C
# print("Before Sale Cost -... | Title: Feed the cat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After waking up at *hh*:*mm*, Andrew realised that he had forgotten to feed his only cat for yet another time (guess why there's only one cat). The cat's current hunger level is *H* points, moreover each minute without foo... | ```python
import math
hr, mi = map(int, input().split() )
H, D, C, N = map(int, input().split())
if hr >= 20:
# print("Sale Already started")
C_discount = C - (C/5)
total = math.ceil(H/N)*C_discount
print("{0:.4f}".format(total) )
else:
totalNow = math.ceil(H/N)*C
# print("Before S... | 0 | |
176 | B | Word Cut | PROGRAMMING | 1,700 | [
"dp"
] | null | null | Let's consider one interesting word game. In this game you should transform one word into another through special operations.
Let's say we have word *w*, let's split this word into two non-empty parts *x* and *y* so, that *w*<==<=*xy*. A split operation is transforming word *w*<==<=*xy* into word *u*<==<=*yx*. For ex... | The first line contains a non-empty word *start*, the second line contains a non-empty word *end*. The words consist of lowercase Latin letters. The number of letters in word *start* equals the number of letters in word *end* and is at least 2 and doesn't exceed 1000 letters.
The third line contains integer *k* (0<=≤<... | Print a single number — the answer to the problem. As this number can be rather large, print it modulo 1000000007 (109<=+<=7). | [
"ab\nab\n2\n",
"ababab\nababab\n1\n",
"ab\nba\n2\n"
] | [
"1\n",
"2\n",
"0\n"
] | The sought way in the first sample is:
ab → a|b → ba → b|a → ab
In the second sample the two sought ways are:
- ababab → abab|ab → ababab - ababab → ab|abab → ababab | 1,000 | [
{
"input": "ab\nab\n2",
"output": "1"
},
{
"input": "ababab\nababab\n1",
"output": "2"
},
{
"input": "ab\nba\n2",
"output": "0"
},
{
"input": "aaa\naaa\n0",
"output": "1"
},
{
"input": "hi\nhi\n1",
"output": "0"
},
{
"input": "abcd\ncbad\n5",
"outp... | 1,694,353,508 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 90 | 124 | 1,740,800 | class Solution:
def numberOfWays(self, s: str, t: str, k: int) -> int:
mod=10**9+7
n=len(s)
v=self.kmp(s+s,t)
g=[[v-1,v],[n-v,n-1-v]]
f=self.qmi(k,g)
if s==t:
return f[0][0]
else:
return f[0][1]
def kmp(self,s,p... | Title: Word Cut
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider one interesting word game. In this game you should transform one word into another through special operations.
Let's say we have word *w*, let's split this word into two non-empty parts *x* and *y* so, that *w... | ```python
class Solution:
def numberOfWays(self, s: str, t: str, k: int) -> int:
mod=10**9+7
n=len(s)
v=self.kmp(s+s,t)
g=[[v-1,v],[n-v,n-1-v]]
f=self.qmi(k,g)
if s==t:
return f[0][0]
else:
return f[0][1]
def km... | 3 | |
387 | B | George and Round | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"two pointers"
] | null | null | George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirem... | Print a single integer — the answer to the problem. | [
"3 5\n1 2 3\n1 2 2 3 3\n",
"3 5\n1 2 3\n1 1 1 1 1\n",
"3 1\n2 3 4\n1\n"
] | [
"0\n",
"2\n",
"3\n"
] | In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems wi... | 1,000 | [
{
"input": "3 5\n1 2 3\n1 2 2 3 3",
"output": "0"
},
{
"input": "3 5\n1 2 3\n1 1 1 1 1",
"output": "2"
},
{
"input": "3 1\n2 3 4\n1",
"output": "3"
},
{
"input": "29 100\n20 32 41 67 72 155 331 382 399 412 465 470 484 511 515 529 616 637 679 715 733 763 826 843 862 903 925 97... | 1,670,064,790 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 62 | 8,294,400 | from sys import stdin ,stdout
input=stdin.readline
def print(*args, end='\n', sep=' ') -> None:
stdout.write(sep.join(map(str, args)) + end)
need,have=map(int,input().split()) ; at_least=list(map(int,input().split())) ; haveP=list(map(int,input().split())) ; ans=0
freq_have=[0]*(10**6+1)
for i in haveP:
... | Title: George and Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
T... | ```python
from sys import stdin ,stdout
input=stdin.readline
def print(*args, end='\n', sep=' ') -> None:
stdout.write(sep.join(map(str, args)) + end)
need,have=map(int,input().split()) ; at_least=list(map(int,input().split())) ; haveP=list(map(int,input().split())) ; ans=0
freq_have=[0]*(10**6+1)
for i in... | 0 | |
618 | B | Guess the Permutation | PROGRAMMING | 1,100 | [
"constructive algorithms"
] | null | null | Bob has a permutation of integers from 1 to *n*. Denote this permutation as *p*. The *i*-th element of *p* will be denoted as *p**i*. For all pairs of distinct integers *i*,<=*j* between 1 and *n*, he wrote the number *a**i*,<=*j*<==<=*min*(*p**i*,<=*p**j*). He writes *a**i*,<=*i*<==<=0 for all integer *i* from 1 to *n... | The first line of the input will contain a single integer *n* (2<=≤<=*n*<=≤<=50).
The next *n* lines will contain the values of *a**i*,<=*j*. The *j*-th number on the *i*-th line will represent *a**i*,<=*j*. The *i*-th number on the *i*-th line will be 0. It's guaranteed that *a**i*,<=*j*<==<=*a**j*,<=*i* and there is... | Print *n* space separated integers, which represents a permutation that could have generated these values. If there are multiple possible solutions, print any of them. | [
"2\n0 1\n1 0\n",
"5\n0 2 2 1 2\n2 0 4 1 3\n2 4 0 1 3\n1 1 1 0 1\n2 3 3 1 0\n"
] | [
"2 1\n",
"2 5 4 1 3\n"
] | In the first case, the answer can be {1, 2} or {2, 1}.
In the second case, another possible answer is {2, 4, 5, 1, 3}. | 1,000 | [
{
"input": "2\n0 1\n1 0",
"output": "2 1"
},
{
"input": "5\n0 2 2 1 2\n2 0 4 1 3\n2 4 0 1 3\n1 1 1 0 1\n2 3 3 1 0",
"output": "2 5 4 1 3"
},
{
"input": "10\n0 1 5 2 5 3 4 5 5 5\n1 0 1 1 1 1 1 1 1 1\n5 1 0 2 6 3 4 6 6 6\n2 1 2 0 2 2 2 2 2 2\n5 1 6 2 0 3 4 8 8 7\n3 1 3 2 3 0 3 3 3 3\n4 1 4... | 1,454,089,397 | 1,997 | Python 3 | OK | TESTS | 23 | 61 | 0 | #!/usr/bin/env python3
# -*- coding: utf-8 -*-
import time
n = int(input())
a = []
for i in range(n):
a.append(max([int(i) for i in input().split()]))
start = time.time()
for i in range(n):
if a[i] == n-1:
a[i] += 1
break
for i in a:
print(i, end=' ')
print()
finish = time.time()... | Title: Guess the Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bob has a permutation of integers from 1 to *n*. Denote this permutation as *p*. The *i*-th element of *p* will be denoted as *p**i*. For all pairs of distinct integers *i*,<=*j* between 1 and *n*, he wrote the nu... | ```python
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
import time
n = int(input())
a = []
for i in range(n):
a.append(max([int(i) for i in input().split()]))
start = time.time()
for i in range(n):
if a[i] == n-1:
a[i] += 1
break
for i in a:
print(i, end=' ')
print()
finish = t... | 3 | |
935 | A | Fafa and his Company | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* em... | The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company. | Print a single integer representing the answer to the problem. | [
"2\n",
"10\n"
] | [
"1\n",
"3\n"
] | In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | 500 | [
{
"input": "2",
"output": "1"
},
{
"input": "10",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "6",
"output": "3"
},
{
"input": "13",
"output": "1"
},
{
"input": "100000",
"output": "35"
... | 1,638,961,783 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 62 | 0 | n = int(input())
ans = 0
for i in range(1,n):
if((n-i)%i==0):
ans=ans+1
print(ans) | Title: Fafa and his Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the emp... | ```python
n = int(input())
ans = 0
for i in range(1,n):
if((n-i)%i==0):
ans=ans+1
print(ans)
``` | 3 | |
549 | A | Face Detection | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2<... | The first line contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the height and the width of the image, respectively.
Next *n* lines define the image. Each line contains *m* lowercase Latin letters. | In the single line print the number of faces on the image. | [
"4 4\nxxxx\nxfax\nxcex\nxxxx\n",
"4 2\nxx\ncf\nae\nxx\n",
"2 3\nfac\ncef\n",
"1 4\nface\n"
] | [
"1\n",
"1\n",
"2\n",
"0\n"
] | In the first sample the image contains a single face, located in a square with the upper left corner at the second line and the second column:
In the second sample the image also contains exactly one face, its upper left corner is at the second row and the first column.
In the third sample two faces are shown:
In ... | 250 | [
{
"input": "4 4\nxxxx\nxfax\nxcex\nxxxx",
"output": "1"
},
{
"input": "4 2\nxx\ncf\nae\nxx",
"output": "1"
},
{
"input": "2 3\nfac\ncef",
"output": "2"
},
{
"input": "1 4\nface",
"output": "0"
},
{
"input": "5 5\nwmmwn\nlurcm\nkeetd\nfokon\ncxxgx",
"output": "... | 1,434,196,505 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 62 | 0 | n, m = map(int, input().split(' '))
p = [input() for i in range(n)]
r = 0
for i in range(n - 1):
for j in range(m - 1):
if {p[i][j], p[i+1][j], p[i][j+1], p[i+1][j+1]} == {'f','a','c','e'}:
r = r + 1
print(r) | Title: Face Detection
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem a... | ```python
n, m = map(int, input().split(' '))
p = [input() for i in range(n)]
r = 0
for i in range(n - 1):
for j in range(m - 1):
if {p[i][j], p[i+1][j], p[i][j+1], p[i+1][j+1]} == {'f','a','c','e'}:
r = r + 1
print(r)
``` | 3 | |
141 | A | Amusing Joke | PROGRAMMING | 800 | [
"implementation",
"sortings",
"strings"
] | null | null | So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's name and the host's name in honor of this event. Then the hung the letters above the main entrance. O... | The input file consists of three lines: the first line contains the guest's name, the second line contains the name of the residence host and the third line contains letters in a pile that were found at the door in the morning. All lines are not empty and contain only uppercase Latin letters. The length of each line do... | Print "YES" without the quotes, if the letters in the pile could be permuted to make the names of the "New Year and Christmas Men". Otherwise, print "NO" without the quotes. | [
"SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS\n",
"PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI\n",
"BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | In the first sample the letters written in the last line can be used to write the names and there won't be any extra letters left.
In the second sample letter "P" is missing from the pile and there's an extra letter "L".
In the third sample there's an extra letter "L". | 500 | [
{
"input": "SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS",
"output": "YES"
},
{
"input": "PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI",
"output": "NO"
},
{
"input": "BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER",
"output": "NO"
},
{
"input": "B\nA\nAB",
"output": ... | 1,689,836,582 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 92 | 0 | def main(s1, s2, s3):
if sorted(s1 + s2) == sorted(s3):
return "YES"
else:
return "NO"
if __name__ == "__main__":
s1, s2, s3 = input(), input(), input()
print(main(s1, s2, s3)) | Title: Amusing Joke
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's nam... | ```python
def main(s1, s2, s3):
if sorted(s1 + s2) == sorted(s3):
return "YES"
else:
return "NO"
if __name__ == "__main__":
s1, s2, s3 = input(), input(), input()
print(main(s1, s2, s3))
``` | 3 | |
520 | A | Pangram | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
You are given a string consisting of lowercase and uppercase Latin letters. Check whether thi... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of characters in the string.
The second line contains the string. The string consists only of uppercase and lowercase Latin letters. | Output "YES", if the string is a pangram and "NO" otherwise. | [
"12\ntoosmallword\n",
"35\nTheQuickBrownFoxJumpsOverTheLazyDog\n"
] | [
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "12\ntoosmallword",
"output": "NO"
},
{
"input": "35\nTheQuickBrownFoxJumpsOverTheLazyDog",
"output": "YES"
},
{
"input": "1\na",
"output": "NO"
},
{
"input": "26\nqwertyuiopasdfghjklzxcvbnm",
"output": "YES"
},
{
"input": "26\nABCDEFGHIJKLMNOPQRSTUVWXY... | 1,696,400,473 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | a = "abcdefghijklmnopqrstuvwxyz"
len=int(input())
s = input()
s = s.lower()
for i in a:
if i not in s:
print("NO")
else:
print("YES")
| Title: Pangram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
... | ```python
a = "abcdefghijklmnopqrstuvwxyz"
len=int(input())
s = input()
s = s.lower()
for i in a:
if i not in s:
print("NO")
else:
print("YES")
``` | 0 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,592,981,554 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 216 | 6,656,000 | n=int(input())
x=list(map(int,input().split()))
y=list(map(int,input().split()))
z=list(map(int,input().split()))
t=x+y+z
if sum(t)==0:
print('YES')
else:
print('NO') | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. S... | ```python
n=int(input())
x=list(map(int,input().split()))
y=list(map(int,input().split()))
z=list(map(int,input().split()))
t=x+y+z
if sum(t)==0:
print('YES')
else:
print('NO')
``` | 0 |
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