url stringlengths 6 1.61k | fetch_time int64 1,368,856,904B 1,726,893,854B | content_mime_type stringclasses 3 values | warc_filename stringlengths 108 138 | warc_record_offset int32 9.6k 1.74B | warc_record_length int32 664 793k | text stringlengths 45 1.04M | token_count int32 22 711k | char_count int32 45 1.04M | metadata stringlengths 439 443 | score float64 2.52 5.09 | int_score int64 3 5 | crawl stringclasses 93 values | snapshot_type stringclasses 2 values | language stringclasses 1 value | language_score float64 0.06 1 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
https://math.dartmouth.edu/undergraduate/first-year-students/placement-info/syllabi/m8-syllabus.php | 1,685,377,629,000,000,000 | text/html | crawl-data/CC-MAIN-2023-23/segments/1685224644867.89/warc/CC-MAIN-20230529141542-20230529171542-00624.warc.gz | 427,202,930 | 6,511 | This website uses features that are not well-supported by your browser. Please consider upgrading to a browser and version that fully supports CSS Grid and the CSS Flexible Box Layout Module.
Dartmouth Mathematics Placement System
## Syllabus: Math 8
The following is a standard syllabus for Math 8. If you wish to review some or all of the material, we provide three methods.
First, the syllabus closely follows Stewart's Calculus textbook chapters 6, 8, and 12-15, which are marked on the syllabus below.
Second, we provide links to Khan Academy (KA) videos relevant to the material on that part of the syllabus (Note that, at this time, KA's coverage of differential multivariable calculus is not complete).
Third, as practice problems are always useful, in addition to the problems available in Stewart and at Khan Academy, we provide practice exams.
Note that MATH 8 is split into two, more or less independent, parts - the end of single variable calculus (part A below) and the beginning of multivariable calculus (part B below). If you are reviewing for the MATH 8 Credit exam, you need only review material from the Sample Math 3 Syllabus and from part A below - those are the only topics covered on the exam. If you are reviewing for the Multivariable Credit Exam, you should review part B below as well as topics from the Sample Math 13 syllabus.
## A. The remainder of BC Calculus
### 1. Applications of Integration
a. Areas between curves (Stewart 6.1)
b. Volumes of revolution (Stewart 6.2)
### 2. Techniques of Integration
a. Integration by parts (Stewart 8.1)
b. Trigonometric integrals (Stewart 8.2)
c. Trigonometric Substitution (Stewart 8.3)
d. Partial Fractions (Stewart 8.4)
e. Numerical Integration (Stewart 8.7)
f. Improper Integrals(Stewart 8.8)
### 3. Sequences and Series
a. Sequences and series of constants (Stewart 12.1)
b. Inetgral Test (Stewart 12.3)
c. Comparison Test (Stewart 12.4)
d. Alternating series (Stewart 12.5)
e. Ratio Test (Stewart 12.6)
f. Power series, Representation as power series (Stewart 12.8-12.9)
g. Taylor and Maclaurin series (Stewart 12.10)
## B. Differential Multivariable Calculus
### 4. The language of vectors
a. Coordinates and vectors in $\mathbb R^2,\ \mathbb R^3$ (Stewart 13.1,13.2)
b. Dot and cross product (Stewart 13.3,13.4)
c. Lines and planes in three-dimensional space (Stewart 13.5)
### 5. Calculus for vector valued functions of one variable
a. Vector functions, space curves, and their derivatives and integrals (Stewart 14.1, 14.2)
b. Arclength, velocity, and accelerations (Stewart 14.3, 14.4)
### 6. Differentiation for functions of more than one variable
a. Functions of several variables (Stewart 15.1)
b. Limits and continuity (Stewart 15.2)
c. Partial Derivatives (Stewart 15.3)
d. Tangent Planes and approximation (Stewart 15.4)
e. Chain Rule (Stewart 15.5)
f. Directional derivatives and the gradient (Stewart 15.6)
g. Maxima and minima (Stewart 15.7)
h. Lagrange Multipliers (Stewart 15.8) | 831 | 3,014 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.359375 | 3 | CC-MAIN-2023-23 | longest | en | 0.857676 |
http://openstudy.com/updates/53d9860ee4b0113bfea5073a | 1,448,839,082,000,000,000 | text/html | crawl-data/CC-MAIN-2015-48/segments/1448398460263.61/warc/CC-MAIN-20151124205420-00216-ip-10-71-132-137.ec2.internal.warc.gz | 176,315,673 | 9,935 | ## ratherbcoding one year ago Can someone explain to me what's happening in this final step? I've seen the answer, but I don't undertstand how to get it! http://imgur.com/GSuuI0l
• This Question is Open
In the numerator there is derivative of the denominator so we can apply ln( ) law
2. phi
if you multiply the top by 3, you get exactly the derivative of the bottom so put a ⅓ out front , and multiply the top by 3 you now have $\frac{1}{3} \int \frac{du}{u} = \frac{1}{3}\ln(u)$ notice we can write the above as $\frac{1}{3} \int \frac{du}{u} = \int \frac{du}{3u}$ it looks like they want to see 3(x^3+ 6x^2 +3x+8) or 3x^3 +18x^2 + 9x + 24 in the "box" | 222 | 658 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.640625 | 4 | CC-MAIN-2015-48 | longest | en | 0.881516 |
http://math.stackexchange.com/questions/120422/homogeneous-polynomials-as-sections-of-line-bundle-surjectivity-of-multiplicati?answertab=votes | 1,462,030,740,000,000,000 | text/html | crawl-data/CC-MAIN-2016-18/segments/1461860111868.79/warc/CC-MAIN-20160428161511-00045-ip-10-239-7-51.ec2.internal.warc.gz | 179,137,469 | 16,852 | homogeneous polynomials as sections of line bundle, surjectivity of multiplication
The homogeneous polynomials in $\mathbb{C}[x_0,\cdots,x_n]$ can be considered as the global sections of a line bundle over $\mathbb{P}^n$ (the line bundle corresponding to Serre's twisting sheaf). In fact if $\mathcal{L}$ is the line bundle corresponding to $\mathcal{O}(1)$ then the homogeneous polynomials in degree $d$ are (isomorphic to) $H^{0}(\mathbb{P}^n, \mathcal{L}^{\otimes d})$. The line bundle $\mathcal{L}$ is globally generated since $\mathbb{P}^n$ can be covered by open sets $U_i = \{x = [x_0:\cdots:x_n] \in \mathbb{P}^n: x_i \not = 0\}$.
According to this example/theorem in Lazarsfeld (2.1.29):
http://books.google.dk/books?id=T87ftUcU_hEC&lpg=PA126&ots=dPxmwqbLJJ&dq=lazarsfeld%20positivity%20%22section%20ring%22&hl=da&pg=PA131#v=onepage&q&f=false
the multiplication map: $H^0(\mathbb{P}^n, \mathcal{L}^{\otimes a}) \otimes H^0(\mathbb{P}^n, \mathcal{L}^{\otimes b}) \rightarrow H^0(\mathbb{P}^n, \mathcal{L}^{\otimes (a+b)})$ is surjective for $a,b$ big enough. This seems wrong to me since it would mean that there are no irreducible homogeneous of arbitrarily high degree, which is not true if $n > 1$.
I'm a beginner in Algebraic Geometry so I would appreciate it if someone can explain to me what is it that I'm missing or misunderstanding about this example. Thanks.
-
The $\otimes$ means all linear combinations of products. And clearly any monomial of degree $a+b$ is a product of monomials of degree $a$ and $b$ respectively. – WimC Mar 15 '12 at 9:03
OH, right! That's it, I was clearly being stupid. Thank you for your answer. – Nadim Rustom Mar 15 '12 at 9:07
@WimC Please consider promoting your comment to an answer, since it indeed answered the question. – ˈjuː.zɚ79365 Jun 13 '13 at 4:04
1 Answer
The $\otimes$ means all linear combinations of products. And clearly any monomial of degree $a+b$ is a product of monomials of degree $a$ and $b$ respectively.
- | 635 | 1,987 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.953125 | 3 | CC-MAIN-2016-18 | latest | en | 0.843807 |
http://oeis.org/A247864 | 1,568,638,581,000,000,000 | text/html | crawl-data/CC-MAIN-2019-39/segments/1568514572556.54/warc/CC-MAIN-20190916120037-20190916142037-00106.warc.gz | 141,262,867 | 4,182 | This site is supported by donations to The OEIS Foundation.
Hints (Greetings from The On-Line Encyclopedia of Integer Sequences!)
A247864 Decimal expansion of c = 1/(2^(e^(-gamma))-1), a constant associated with the asymptotic convergent denominators of a continued fraction using Mersenne primes. 2
2, 1, 0, 1, 8, 9, 3, 9, 4, 5, 3, 3, 5, 2, 0, 4, 1, 8, 9, 0, 5, 2, 7, 9, 7, 1, 8, 5, 6, 8, 8, 0, 8, 4, 9, 0, 1, 9, 9, 5, 9, 9, 2, 0, 0, 7, 4, 5, 8, 4, 2, 3, 9, 0, 6, 5, 8, 8, 0, 0, 3, 7, 2, 9, 5, 5, 2, 9, 7, 8, 9, 5, 7, 2, 2, 8, 3, 4, 5, 6, 7, 8, 0, 5, 4, 6, 0, 8, 0, 2, 2, 5, 4, 4, 3, 2, 4, 0, 3 (list; constant; graph; refs; listen; history; text; internal format)
OFFSET 1,1 LINKS G. C. Greubel, Table of n, a(n) for n = 1..10000 Eric Weisstein's MathWorld, Mersenne Prime Marek Wolf, "Continued fractions constructed from prime numbers" arXiv:1003.4015 [math.NT] Sep 26 2010, p. 24. FORMULA c = 1/(2^(e^(-gamma))-1), where gamma is Euler's constant 0.5772... EXAMPLE 2.1018939453352041890527971856880849019959920074584239... MATHEMATICA c = 1/(2^(E^(-EulerGamma)) - 1); RealDigits[c, 10, 99] // First PROG (PARI) 1/(2^(exp(-Euler))-1) \\ Michel Marcus, Sep 25 2014 (MAGMA) SetDefaultRealField(RealField(100)); R:= RealField(); 1/(2^(Exp(-EulerGamma(R))) - 1); // G. C. Greubel, Sep 04 2018 CROSSREFS Cf. A000668, A001620. Sequence in context: A085324 A264945 A326476 * A266632 A062154 A326474 Adjacent sequences: A247861 A247862 A247863 * A247865 A247866 A247867 KEYWORD nonn,cons,easy AUTHOR Jean-François Alcover, Sep 25 2014 STATUS approved
Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Style Sheet | Transforms | Superseeker | Recent
The OEIS Community | Maintained by The OEIS Foundation Inc.
Last modified September 16 08:53 EDT 2019. Contains 327092 sequences. (Running on oeis4.) | 803 | 1,887 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.46875 | 3 | CC-MAIN-2019-39 | latest | en | 0.550594 |
https://www.elucidate.org.au/content/projectile-motion---oblique | 1,695,525,053,000,000,000 | text/html | crawl-data/CC-MAIN-2023-40/segments/1695233506559.11/warc/CC-MAIN-20230924023050-20230924053050-00118.warc.gz | 842,331,931 | 205,740 | top of page
###### Projectile Motion - Oblique
Physics (Year 12) - Gravity and Motion
Dev Lohar
# Projectiles Launched Obliquely
Projectiles launched obliquely means there is both a vertical component, and a horizontal component during the projectile’s launch. This implies that there would be both an initial vertical velocity and an initial horizontal velocity, whereas projectiles launched horizontally only had an initial horizontal velocity.
# Calculations
The 2 equations that you’ll use in every projectile motion are very simple and stated below:
A good trick to remember which one is which is by thinking of which direction you plant a sign; vertically. Hence sine is used for vertical velocities, and so cosine has to be used for horizontal velocities.
The same equations apply for scenarios in which projectiles launched obliquely as scenarios in the previous notes page which covered projectiles launched horizontally (read that page if you haven’t already, before reading this page). The only difference in this case is that we do have an initial vertical velocity which is not equal to 0. To solve problems, you’d need to use a combination of different equations depending on the variables you are given. It is always helpful to write down all the variables given in the question, so you can easily figure out which equation(s) you need to use.
# Tips for Solving Problems
There are a couple of key things you need to remember when tackling projectile motion problems. They are stated below:
• The maximum height of a projectile is achieved when the final vertical velocity is 0. Applying this to the equation [v(v)]^2 = [u(v)]^2 + 2as(v) will allow you to easily calculate the maximum height, given you know the initial vertical velocity.
• If a projectile lands a certain distance, s(h), on level ground, this then means that s(v) at the end is 0. This information can be applied to s(v) = u(v)t + 1/2 at^2 to find the time it took for the projectile to land, given you know the initial vertical velocity.
• For some problems, you might need to use more than 1 equation to arrive at the final answer. So don’t get dis-heartened if only one equation doesn’t give you the answer. It might end up giving you the value of a variable which you can use in a second equation to get the final answer. For example, you might be asked to find the height of a projectile when it’s a certain horizontal distance away from where it was launched. You are only given the initial velocity, the angle at which it was launched and the horizontal distance (at which point it wants to know what the height of the projectile is). Clearly s(v) = u(v)t+ 1/2 at^2 won’t give you the answer because you don’t know the time, t. So you can use u(h) = s(h)/t (horizontal speed = horizontal distance / time) to first find the time for the projectile to reach the horizontal distance given, and then you can use that time to find the height.
# Graphs
Imagine a projectile being launched as shown in the diagram below:
If you were to graph vertical acceleration vs time, vertical displacement vs time, vertical velocity vs time, horizontal velocity vs time and vertical speed vs time, they would look like the graphs below:
# Projectile motion worked example | Elucidate Video
In the above video, Dev thoroughly explains how to breakdown and solve a typical projectile motion question. The steps demonstrated in the video can be applied to most projectile motion questions.
bottom of page | 756 | 3,510 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 4.34375 | 4 | CC-MAIN-2023-40 | longest | en | 0.920672 |
https://www.coursehero.com/file/6002236/Lecture-4/ | 1,498,253,993,000,000,000 | text/html | crawl-data/CC-MAIN-2017-26/segments/1498128320174.58/warc/CC-MAIN-20170623202724-20170623222724-00307.warc.gz | 863,811,433 | 100,616 | Lecture-4
# Lecture-4 - AMS 361 Applied Calculus IV(DE BVP Outline for...
This preview shows pages 1–3. Sign up to view the full content.
Outline for Lecture 4 4. Separable equations and applications The following equation is called Separable equation One can write it as So, this equation can be integrated on both sides. Although we probably most of the time to get the y=y(x) form, we can get the solution in implicit form. is the simple (but could be implicit) form of the IVP e.g. 1. Solve The solution is y(x)=7*e^(-3x^2) What if y(0) = -4? We can get the solution of y(x)=-4*e^(-3x^2). e.g. 2. Solve The solution is (y^3-5y)=4x-x^2+C It’s not possible, not practical, and not necessary to find the explicit form. If we implement IC, y(1) = 3, then we can get C=9.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Thus, the solution becomes (y^3-5y)=4x-x^2+9. DEF: General solution : Solution with an arbitrary constant Particular solution : Solution with without the arbitrary constant Singular solution : Solution that can’t be obtained by setting the arbitrary constant. This is possible for nonlinear DE. e.g.
This is the end of the preview. Sign up to access the rest of the document.
## This note was uploaded on 11/03/2010 for the course AMS 361 taught by Professor Staff during the Summer '08 term at SUNY Stony Brook.
### Page1 / 4
Lecture-4 - AMS 361 Applied Calculus IV(DE BVP Outline for...
This preview shows document pages 1 - 3. Sign up to view the full document.
View Full Document
Ask a homework question - tutors are online | 425 | 1,610 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.546875 | 4 | CC-MAIN-2017-26 | longest | en | 0.865469 |
https://nrich.maths.org/5829/note | 1,521,282,722,000,000,000 | text/html | crawl-data/CC-MAIN-2018-13/segments/1521257644877.27/warc/CC-MAIN-20180317100705-20180317120705-00405.warc.gz | 670,197,768 | 4,694 | ### Shape and Territory
If for any triangle ABC tan(A - B) + tan(B - C) + tan(C - A) = 0 what can you say about the triangle?
### Why Stop at Three by One
Beautiful mathematics. Two 18 year old students gave eight different proofs of one result then generalised it from the 3 by 1 case to the n by 1 case and proved the general result.
### An Introduction to Complex Numbers
A short introduction to complex numbers written primarily for students aged 14 to 19.
# T for Tan
##### Stage: 5 Challenge Level:
This result is used in the problem Reflect Again.
Transformations are represented by multiplying position vectors for points in the plane by 2 by 2 matrices.
In Reflect Again you first find the matrix for a reflection in a given line and then show that a rotation is the combination of two reflections in intersecting lines (given by the product of two matrices). | 196 | 877 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.359375 | 3 | CC-MAIN-2018-13 | latest | en | 0.902554 |
http://oeis.org/A322703 | 1,582,393,387,000,000,000 | text/html | crawl-data/CC-MAIN-2020-10/segments/1581875145708.59/warc/CC-MAIN-20200222150029-20200222180029-00192.warc.gz | 108,388,940 | 4,900 | The OEIS Foundation is supported by donations from users of the OEIS and by a grant from the Simons Foundation.
Hints (Greetings from The On-Line Encyclopedia of Integer Sequences!)
A322703 Squarefree MM-numbers of strict uniform regular multiset systems spanning an initial interval of positive integers. 3
1, 2, 3, 7, 13, 15, 19, 53, 113, 131, 151, 161, 165, 311, 719, 1291, 1321, 1619, 1937, 1957, 2021, 2093, 2117, 2257, 2805, 3671, 6997, 8161, 10627, 13969, 13987, 14023, 15617, 17719, 17863, 20443, 22207, 22339, 38873, 79349, 84017, 86955, 180503, 202133 (list; graph; refs; listen; history; text; internal format)
OFFSET 1,2 COMMENTS A multiset multisystem is a finite multiset of finite multisets. A prime index of n is a number m such that prime(m) divides n. The multiset of prime indices of n is row n of A112798. The multiset multisystem with MM-number n is formed by taking the multiset of prime indices of each part of the multiset of prime indices of n. For example, the prime indices of 78 are {1,2,6}, so the multiset multisystem with MM-number 78 is {{},{1},{1,2}}. A multiset multisystem is uniform if all parts have the same size, regular if all vertices appear the same number of times, and strict if there are no repeated parts. For example, {{1,1},{2,3},{2,3}} is uniform and regular but not strict, so its MM-number 15463 does not belong to the sequence. Note that the parts of parts such as {1,1} do not have to be distinct, only the multiset of parts. LINKS EXAMPLE The sequence of all strict uniform regular multiset multisystems spanning an initial interval of positive integers, together with their MM-numbers, begins: 1: {} 2: {{}} 3: {{1}} 7: {{1,1}} 13: {{1,2}} 15: {{1},{2}} 19: {{1,1,1}} 53: {{1,1,1,1}} 113: {{1,2,3}} 131: {{1,1,1,1,1}} 151: {{1,1,2,2}} 161: {{1,1},{2,2}} 165: {{1},{2},{3}} 311: {{1,1,1,1,1,1}} 719: {{1,1,1,1,1,1,1}} 1291: {{1,2,3,4}} 1321: {{1,1,1,2,2,2}} 1619: {{1,1,1,1,1,1,1,1}} 1937: {{1,2},{3,4}} 1957: {{1,1,1},{2,2,2}} 2021: {{1,4},{2,3}} 2093: {{1,1},{1,2},{2,2}} 2117: {{1,3},{2,4}} 2257: {{1,1,2},{1,2,2}} 2805: {{1},{2},{3},{4}} 3671: {{1,1,1,1,1,1,1,1,1}} 6997: {{1,1,2,2,3,3}} 8161: {{1,1,1,1,1,1,1,1,1,1}} 10627: {{1,1,1,1,2,2,2,2}} 13969: {{1,2,2},{1,3,3}} 13987: {{1,1,3},{2,2,3}} 14023: {{1,1,2},{2,3,3}} 15617: {{1,1},{2,2},{3,3}} 17719: {{1,2},{1,3},{2,3}} 17863: {{1,1,1,1,1,1,1,1,1,1,1}} MATHEMATICA primeMS[n_]:=If[n==1, {}, Flatten[Cases[FactorInteger[n], {p_, k_}:>Table[PrimePi[p], {k}]]]]; normQ[sys_]:=Or[Length[sys]==0, Union@@sys==Range[Max@@Max@@sys]]; Select[Range[1000], And[SquareFreeQ[#], normQ[primeMS/@primeMS[#]], SameQ@@PrimeOmega/@primeMS[#], SameQ@@Last/@FactorInteger[Times@@primeMS[#]]]&] CROSSREFS Cf. A005117, A007016, A112798, A302242, A306017, A306021, A319056, A319189, A319190, A320324, A321698, A321699, A322554, A322833. Sequence in context: A026472 A286176 A318401 * A225098 A101739 A141633 Adjacent sequences: A322700 A322701 A322702 * A322704 A322705 A322706 KEYWORD nonn AUTHOR Gus Wiseman, Dec 27 2018 STATUS approved
Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Style Sheet | Transforms | Superseeker | Recent
The OEIS Community | Maintained by The OEIS Foundation Inc.
Last modified February 22 12:42 EST 2020. Contains 332136 sequences. (Running on oeis4.) | 1,372 | 3,493 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.59375 | 4 | CC-MAIN-2020-10 | latest | en | 0.692004 |
https://tutorialspoint.dev/algorithm/mathematical-algorithms/given-p-and-n-find-the-largest-x-such-that-px-divides-n-2 | 1,638,583,248,000,000,000 | text/html | crawl-data/CC-MAIN-2021-49/segments/1637964362923.11/warc/CC-MAIN-20211204003045-20211204033045-00428.warc.gz | 618,025,654 | 8,833 | # Legendre’s formula (Given p and n, find the largest x such that p^x divides n!)
Given an integer n and a prime number p, find the largest x such that px (p raised to power x) divides n! (factorial)
Examples:
```Input: n = 7, p = 3
Output: x = 2
32 divides 7! and 2 is the largest such power of 3.
Input: n = 10, p = 3
Output: x = 4
34 divides 10! and 4 is the largest such power of 3.
```
n! is multiplication of {1, 2, 3, 4, …n}.
How many numbers in {1, 2, 3, 4, ….. n} are divisible by p?
Every p’th number is divisible by p in {1, 2, 3, 4, ….. n}. Therefore in n!, there are ?n/p? numbers divisible by p. So we know that the value of x (largest power of p that divides n!) is at-least ?n/p?.
Can x be larger than ?n/p? ?
Yes, there may be numbers which are divisible by p2, p3, …
How many numbers in {1, 2, 3, 4, ….. n} are divisible by p2, p3, …?
There are ?n/(p2)? numbers divisible by p2 (Every p2‘th number would be divisible). Similarly, there are ?n/(p3)? numbers divisible by p3 and so on.
What is the largest possible value of x?
So the largest possible power is ?n/p? + ?n/(p2)? + ?n/(p3)? + ……
Note that we add only ?n/(p2)? only once (not twice) as one p is already considered by expression ?n/p?. Similarly, we consider ?n/(p3)? (not thrice).
Below is implementation of above idea.
div class="responsive-tabs">
## C/C++
`// C program to find largest x such that p*x divides n! ` `#include ` ` ` `// Returns largest power of p that divides n! ` `int` `largestPower(``int` `n, ``int` `p) ` `{ ` ` ``// Initialize result ` ` ``int` `x = 0; ` ` ` ` ``// Calculate x = n/p + n/(p^2) + n/(p^3) + .... ` ` ``while` `(n) ` ` ``{ ` ` ``n /= p; ` ` ``x += n; ` ` ``} ` ` ``return` `x; ` `} ` ` ` `// Driver program ` `int` `main() ` `{ ` ` ``int` `n = 10, p = 3; ` ` ``printf``(````"The largest power of %d that divides %d! is %d "````, ` ` ``p, n, largestPower(n, p)); ` ` ``return` `0; ` `} `
## Java
`// Java program to find largest x such that p*x divides n! ` `import` `java.io.*; ` ` ` `class` `GFG ` `{ ` ` ``// Function that returns largest power of p ` ` ``// that divides n! ` ` ``static` `int` `Largestpower(``int` `n, ``int` `p) ` ` ``{ ` ` ``// Initialize result ` ` ``int` `ans = ``0``; ` ` ` ` ``// Calculate x = n/p + n/(p^2) + n/(p^3) + .... ` ` ``while` `(n > ``0``) ` ` ``{ ` ` ``n /= p; ` ` ``ans += n; ` ` ``} ` ` ``return` `ans; ` ` ``} ` ` ` ` ``// Driver program ` ` ``public` `static` `void` `main (String[] args) ` ` ``{ ` ` ``int` `n = ``10``; ` ` ``int` `p = ``3``; ` ` ``System.out.println(``" The largest power of "` `+ p + ``" that divides "` ` ``+ n + ``"! is "` `+ Largestpower(n, p)); ` ` ` ` ` ` ``} ` `} `
## Python3
`# Python3 program to find largest ` `# x such that p*x divides n! ` ` ` `# Returns largest power of p that divides n! ` `def` `largestPower(n, p): ` ` ` ` ``# Initialize result ` ` ``x ``=` `0` ` ` ` ``# Calculate x = n/p + n/(p^2) + n/(p^3) + .... ` ` ``while` `n: ` ` ``n ``/``=` `p ` ` ``x ``+``=` `n ` ` ``return` `x ` ` ` `# Driver program ` `n ``=` `10``; p ``=` `3` `print` `(````"The largest power of %d that divides %d! is %d "````%` ` ``(p, n, largestPower(n, p))) ` ` ` `# This code is contributed by Shreyanshi Arun. `
## C#
`// C# program to find largest x ` `// such that p * x divides n! ` `using` `System; ` ` ` `public` `class` `GFG ` `{ ` ` ` ` ``// Function that returns largest ` ` ``// power of p that divides n! ` ` ``static` `int` `Largestpower(``int` `n, ``int` `p) ` ` ``{ ` ` ``// Initialize result ` ` ``int` `ans = 0; ` ` ` ` ``// Calculate x = n / p + n / (p ^ 2) + ` ` ``// n / (p ^ 3) + .... ` ` ``while` `(n > 0) ` ` ``{ ` ` ``n /= p; ` ` ``ans += n; ` ` ``} ` ` ``return` `ans; ` ` ``} ` ` ` ` ``// Driver Code ` ` ``public` `static` `void` `Main () ` ` ``{ ` ` ``int` `n = 10; ` ` ``int` `p = 3; ` ` ``Console.Write(``" The largest power of "` `+ p + ``" that divides "` ` ``+ n + ``"! is "` `+ Largestpower(n, p)); ` ` ` ` ` ` ``} ` `} ` ` ` `// This code is contributed by Sam007 `
## PHP
` `
Output:
`The largest power of 3 that divides 10! is 4`
Time complexity of the above solution is Logpn.
What to do if p is not prime?
We can find all prime factors of p and compute result for every prime factor. Refer Largest power of k in n! (factorial) where k may not be prime for details. | 1,738 | 4,777 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.828125 | 4 | CC-MAIN-2021-49 | latest | en | 0.802837 |
https://www.notesformba.com/topic/frequency-distribution/ | 1,534,890,577,000,000,000 | text/html | crawl-data/CC-MAIN-2018-34/segments/1534221219109.94/warc/CC-MAIN-20180821210655-20180821230655-00235.warc.gz | 965,211,417 | 7,427 | In statistics, a frequency distribution is a table that shows the frequency of numerous consequences in a sample. Every entry in the table comprises the frequency of the amounts of values within a specific group or interval, and in this technique, the table précises the distribution of values in the sample.
frequency is the number of times a data value happens. For example, if ten students score 80 then 80 score has an f of 10. Frequency is frequently denoted by the letter f.
frequency chart is made by placing data values in ascending order of magnitude along with their frequencies.
## Frequency Chart:-
If you are asked to define a frequency in statistics, it doesn’t just mean that you should just exclude the number of times somewhat occurs. It usually includes you having to make a frequency chart to display a list of frequencies.
Method Number Abstinence 13 Condoms 47 Injectable 1 Norplant 1 Pill 35 None 307 Total 405
Making Frequency Chart: -
Step 1:- Make a chart for your data. For this example, you’ve been given a list of twenty blood kinds for emergency operation patients:
AB, A, O, A, AB, B, B, A, AB, B, O, O, AB, A
On the parallel alliance, write “f (#)” and “percent (%)”. On the upright axis, write your list of items. In example, we have four different blood types: A, B, AB, and O.
# % A B AB O
Step 2: Sum the number of times every item seems in your data.
In this example, we have:
A seems 4 times.
B seems 3 times.
O seems 3 times.
AB seems 4 times.
Write those in the “
figure” column (#). This is your frequency.
Step 3:
Use the formula % = (f / n) × 100 to fill in the next column. In this example, n = total amount of things in your data = 14. A appears
5 times (frequency in this formula is just the number of times the item appears). So we have:
(4 / 14) × 100 = 28.5%
Fill the frequency column, changing the ‘f’ for each blood type.
# % A 4 28.5 B 3 21.4 AB 4 28.5 O 3 21.4
March 09, 2018 | 520 | 1,947 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 4.5625 | 5 | CC-MAIN-2018-34 | longest | en | 0.843844 |
http://book.caltech.edu/bookforum/showthread.php?s=b780ba576dd7cdffa7879dfe5956c2bd&t=4679&goto=nextoldest | 1,582,425,962,000,000,000 | text/html | crawl-data/CC-MAIN-2020-10/segments/1581875145742.20/warc/CC-MAIN-20200223001555-20200223031555-00282.warc.gz | 24,288,261 | 10,090 | LFD Book Forum Exercise 1.13 noisy targets
User Name Remember Me? Password
FAQ Calendar Mark Forums Read
Thread Tools Display Modes
#1
10-21-2014, 06:11 PM
mahaitao Junior Member Join Date: Oct 2014 Posts: 6
Exercise 1.13 noisy targets
Exercise 1.13(a): what is the probability of error that h makes in approximating y if we use a noisy version of f. That means we want to compute Pr(h(x)~=y), and I consider two cases:
(1) h(x)=f(x) and f(x) != y; [(1-\mu)*\(1-\lambda)]
(2) h(x)!=f(x) and f(x) = y. [\mu*\lambda]
I am not sure the solution is right. My questions are follows:
(i) Does "h makes an error with \mu in approximating a deterministic target function f" mean Pr(h(x) != f(x)) = \mu?
(ii) Does the probability of Pr(h(x)~=y)=Pr(1)+Pr(2)?
Exercise 1.13(b) : I am not clear what does "performance of h be independent of \mu" mean? Should I consider Pr(h(x)~=y)?
thanks!
#2
10-22-2014, 12:20 AM
yaser Caltech Join Date: Aug 2009 Location: Pasadena, California, USA Posts: 1,477
Re: Exercise 1.13 noisy targets
Quote:
Originally Posted by mahaitao Exercise 1.13(a): what is the probability of error that h makes in approximating y if we use a noisy version of f. That means we want to compute Pr(h(x)~=y), and I consider two cases: (1) h(x)=f(x) and f(x) != y; [(1-\mu)*\(1-\lambda)] (2) h(x)!=f(x) and f(x) = y. [\mu*\lambda] I am not sure the solution is right. My questions are follows: (i) Does "h makes an error with \mu in approximating a deterministic target function f" mean Pr(h(x) != f(x)) = \mu? (ii) Does the probability of Pr(h(x)~=y)=Pr(1)+Pr(2)? Exercise 1.13(b) : I am not clear what does "performance of h be independent of \mu" mean? Should I consider Pr(h(x)~=y)? thanks!
Answering your questions (i) and (ii): Yes and yes.
In Exercise 1.13(b): Independent of means that changing the value of does not affect how well predicts .
__________________
Where everyone thinks alike, no one thinks very much
#3
10-22-2014, 05:45 PM
mahaitao Junior Member Join Date: Oct 2014 Posts: 6
Re: Exercise 1.13 noisy targets
Thank you very much, professor.
#4
08-06-2015, 05:36 AM
prithagupta.nsit Junior Member Join Date: Jun 2015 Posts: 7
Re: Exercise 1.13 noisy targets
SO final Probability of error that h makes in approximating y would be:
1+2*lamda*mu -mu -lamda.
if it should be independent of mu then lamda should be 1/2
1+2*1/2*mu -mu -lamda =1-lamda =1/2
It think this should be correct answer.
Is my understanding correct for second part of the question ?
#5
08-06-2015, 05:02 PM
yaser Caltech Join Date: Aug 2009 Location: Pasadena, California, USA Posts: 1,477
Re: Exercise 1.13 noisy targets
Correct.
__________________
Where everyone thinks alike, no one thinks very much
#6
05-12-2016, 03:24 AM
elyoum Junior Member Join Date: May 2016 Posts: 3
Re: Exercise 1.13 noisy targets
Quote:
Originally Posted by yaser Correct.
can i ask you some questions please?
#7
10-09-2017, 06:25 PM
Vladimir Junior Member Join Date: Oct 2017 Posts: 1
Re: Exercise 1.13 noisy targets
Dear Professor,
What about the case h(x)!=f(x) and f(x) != y? Does it count on the probability of Pr(h(x)~=y)?
Thanks.
#8
11-14-2017, 03:52 PM
don slowik Member Join Date: Nov 2017 Posts: 11
Re: Exercise 1.13 noisy targets
The case you mention would lead to h(x) = y.
#9
11-09-2018, 04:40 AM
Ulyssesyang Junior Member Join Date: Nov 2018 Posts: 3
Re: Exercise 1.13 noisy targets
Quote:
Originally Posted by mahaitao Exercise 1.13(a): what is the probability of error that h makes in approximating y if we use a noisy version of f. That means we want to compute Pr(h(x)~=y), and I consider two cases: (1) h(x)=f(x) and f(x) != y; [(1-\mu)*\(1-\lambda)] (2) h(x)!=f(x) and f(x) = y. [\mu*\lambda] I am not sure the solution is right. My questions are follows: (i) Does "h makes an error with \mu in approximating a deterministic target function f" mean Pr(h(x) != f(x)) = \mu? (ii) Does the probability of Pr(h(x)~=y)=Pr(1)+Pr(2)? Exercise 1.13(b) : I am not clear what does "performance of h be independent of \mu" mean? Should I consider Pr(h(x)~=y)? thanks!
So why don’t you consider h(x)!=f(x) and f(x) != y? Even if there is some case here h(x) may equal to y, but we still have case here h(x)!=y.
Thread Tools Display Modes Linear Mode
Posting Rules You may not post new threads You may not post replies You may not post attachments You may not edit your posts BB code is On Smilies are On [IMG] code is On HTML code is Off Forum Rules
Forum Jump User Control Panel Private Messages Subscriptions Who's Online Search Forums Forums Home General General Discussion of Machine Learning Free Additional Material Dynamic e-Chapters Dynamic e-Appendices Course Discussions Online LFD course General comments on the course Homework 1 Homework 2 Homework 3 Homework 4 Homework 5 Homework 6 Homework 7 Homework 8 The Final Create New Homework Problems Book Feedback - Learning From Data General comments on the book Chapter 1 - The Learning Problem Chapter 2 - Training versus Testing Chapter 3 - The Linear Model Chapter 4 - Overfitting Chapter 5 - Three Learning Principles e-Chapter 6 - Similarity Based Methods e-Chapter 7 - Neural Networks e-Chapter 8 - Support Vector Machines e-Chapter 9 - Learning Aides Appendix and Notation e-Appendices
All times are GMT -7. The time now is 07:46 PM.
Contact Us - LFD Book - Top | 1,602 | 5,513 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.71875 | 4 | CC-MAIN-2020-10 | latest | en | 0.851071 |
https://jp.mathworks.com/matlabcentral/cody/problems/29-nearest-numbers/solutions/445431 | 1,596,901,174,000,000,000 | text/html | crawl-data/CC-MAIN-2020-34/segments/1596439737883.59/warc/CC-MAIN-20200808135620-20200808165620-00334.warc.gz | 394,617,058 | 15,852 | Cody
# Problem 29. Nearest Numbers
Solution 445431
Submitted on 23 May 2014 by Liang MA
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.
### Test Suite
Test Status Code Input and Output
1 Pass
%% A = [30 46 16 -46 35 44 18 26 25 -10]; correct = [8 9]; [i1 i2] = nearestNumbers(A); assert(isequal([i1 i2],correct))
2 Pass
%% A = [1555 -3288 2061 -4681 -2230 -4538 -4028 3235 1949 -1829]; correct = [3 9]; [i1 i2] = nearestNumbers(A); assert(isequal([i1 i2],correct))
3 Pass
%% A = [-1 1 10 -10]; correct = [1 2]; [i1 i2] = nearestNumbers(A); assert(isequal([i1 i2],correct))
4 Pass
%% A = [0 1000 -2000 1001 0]; correct = [1 5]; [i1 i2] = nearestNumbers(A); assert(isequal([i1 i2],correct))
5 Pass
%% A = [1:1000 0.5]; correct = [1 1001]; [i1 i2] = nearestNumbers(A); assert(isequal([i1 i2],correct))
6 Pass
%% % Area codes A = [847 217 508 312 212]; correct = [2 5]; [i1 i2] = nearestNumbers(A); assert(isequal([i1 i2],correct))
7 Pass
%% % Zip codes A = [60048 61802 01702 60601 10001]; correct = [1 4]; [i1 i2] = nearestNumbers(A); assert(isequal([i1 i2],correct)) | 443 | 1,150 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.40625 | 3 | CC-MAIN-2020-34 | latest | en | 0.3657 |
http://blog.weizi.org/2015/02/ | 1,590,379,311,000,000,000 | text/html | crawl-data/CC-MAIN-2020-24/segments/1590347387219.0/warc/CC-MAIN-20200525032636-20200525062636-00002.warc.gz | 19,803,158 | 11,554 | ### A naive secure model of secure sharing
I have used secure sharing to distribute my private encrypted data for many years. And i have a demo project in my github. FYI, this demo project is not the one used by me in these years, since it is just a demo and is not safe.
## Terms
In a secure sharing, we say every sharing as a part of the original message, and we can denote the $i$-th part by $P_i$.
## Probability Model
To protect our data, we have to prove the secure sharing scheme is safe. A naive definition of sharing safe can be:
Given any message distribution, the likelihood of a part is independent of any other (K - 1) parts.
The above text can transferred to, for any given message distribution, and some parts $P_{i_j}$ of any message extracted from this distribution,
$$P(P_{i_0}|P_{i_1}, P_{i_2}, \ldots, P_{i_{K-1}}) = P(P_{i_0}).$$
A easiest way to achieve this is using a weaker secure shared transformation T, which is not part of message, and based on the transformation, we have, any (K - 1) parts are valid for any message. That is, for any message M, and any (K - 1) parts $P_0, P_1, \ldots, P_{K-1}$, we have a transformation $T$, such that $S_i(M|T) = P_i$, where $S_i$ is a $i$-th sharing part under transformation $T$. If we can get the $T$ from $K - 1$ parts, the secure is still not guaranteed.
But it's easy to prove that a revertible transformation can be secured shared in a sense that:
Given any $K - 1$ rows of a revertible transformation matrix, the space for the last row is isomorphic to $F^{K-1}$, where $F$ is the under field space.
That is, we lost one random dimension. If this is not acceptable, we can have a chain of transformations, and this chain will converge to the real random secure model.
## Practice
In practice, only one transformation, plus a random accumulated random vector, give quite high entropy of every parts, which is verified by gzip.
If you have different views of this secure sharing model, please kindly let me know, so that i'm not in a risk I do not know. | 530 | 2,040 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 1, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.234375 | 3 | CC-MAIN-2020-24 | longest | en | 0.880628 |
https://www.endeavorcareers.com/cmat-2021-exam-analysis/ | 1,679,877,920,000,000,000 | text/html | crawl-data/CC-MAIN-2023-14/segments/1679296946584.94/warc/CC-MAIN-20230326235016-20230327025016-00757.warc.gz | 854,100,829 | 53,450 | CMAT 2021 was conducted on March 31, 2021 in two slots from 9 am to 12 noon and from 3 pm to 6 pm. An extra half an hour was given to those candidates who opted for the newly introduced optional section – Entrepreneurship and Innovation. Surprisingly, GK was the most difficult section in the exam. It had a lot of questions based on static GK and History.
### CMAT 2021 Paper Pattern
Type Of Questions No. Of Questions Maximum Marks Quantitative Techniques & Data Interpretation 25 100 Logical Reasoning 25 100 Language Comprehension 25 100 General Awareness 25 100 Total 100 Innovation and Entrepreneurship* 25 30
#### CMAT 2021 Exam Time Limit:
The duration of the test is 180 minutes / 210 minutes*
#### CMAT 2021 Exam Marking Scheme
• +4 for each correct answer
• -1 for each incorrect answer
## CMAT 2021 Exam Analysis Slot 1
### The sectional, in-depth CMAT 2021 analysis is as follows:
#### Quantitative Techniques and Data Interpretation (25 Questions)
Presence of Data Interpretation was limited to 2 questions (i.e. Pie and Table based). And the remaining 23 questions were from Quantitative Aptitude. Arithmetic had a share of 11 questions with a variety of questions from Ratio & Proportion, Simple Interest & Compound Interest, Profit & Loss, Averages, Partnership, Alligation & Mixture, Time, Speed & Distance and Time & Work. There were 2 questions from Geometry. Permutation & Combination, Probability & Number system had a total share of 8 questions.
Two questions with two statements were given. In this, one needs to evaluate both the statements and ‘Match the columns’ type questions are the surprises in this section.
Overall, the section was easy to moderate. Approximately 18-20 questions easy to solve, an attempt count of 21 can be termed good with a suggested time of 60 to 70 minutes.
#### Logical Reasoning (25 Questions)
The questions in this section varied from Visual Reasoning, Blood Relations, Coding-Decoding, Series, Analogy, Odd one out, Arrangement to Verbal Reasoning.
There were four questions on Verbal Reasoning (Analogy, Strong-Weak Arguments, etc.) and one set (blood relationship) comprising four questions. Almost all the other topics such as Coding & Decoding, Directions, Visual Reasoning, and Mathematical Operations had a weightage of approx. 2 questions each.
There was no presence of questions of Decision making and cubes & dices.
Overall, the questions in this section were easy. Approximately 19 questions easy to solve, an attempt count of 22-23 can be termed good with a suggested time of 50 minutes.
#### Language Comprehension (25 Questions)
There were four Reading Comprehension passages with a total of 14 questions. The Verbal Ability segment had 11 questions. These included questions on Synonyms/Antonyms, Error spotting, fill in the Blanks, Meanings of words and their usage in sentences, grammatically correct sentence.
Overall, the questions from this section were easy to moderate; it had predominantly grammar questions instead of Vocabulary. The FIB questions were a mix of Vocab and Grammar. Attempt of 19-20 can be termed good with a suggested time of 45-50 minutes.
#### General Awareness (25 Questions)
General Awareness this year was a blend of static general knowledge (17 Questions) and current affairs (8 Questions). This section had a spread of questions ranging from History, Government ministry, Budget, International Organization, Banking and Finance, Sports, Science and Technology, Authors, Business and economy.
Overall, 10-12 attempts can be termed as good attempts in a suggested time of 10 minutes.
### CMAT 2021 Slot 1 Overall Score vs. Percentile Prediction
CMAT Score out of 400 Expected Percentile 262+ 99+ 256+ 98+ 230+ 95+ 184+ 80+
## CMAT 2021 Exam Analysis Slot 2
### The sectional, in-depth CMAT 2021 analysis is as follows:
#### Quantitative Techniques and Data Interpretation (25 Questions)
Data Interpretation was back to 4 questions (i.e. Pie based) in this slot. And the remaining 21 questions were from Quantitative Aptitude. Arithmetic had a share of 10 questions with a variety of questions from Ratio & Proportion, Simple Interest & Compound Interest, Profit & Loss, Averages, Partnership, Alligation & Mixture, Time, Speed & Distance and Time & Work. There were 2 questions from Geometry (Mensuration and Triangle). Permutation & Combination, Probability and Functions had a total share of 3 questions. Data sufficiency (on Number system) had 1 question.
Overall, the section was easy to moderate. Approximately 20-21 questions easy to solve, an attempt count of 22 can be termed good with a suggested time of 60 to 70 minutes.
#### Logical Reasoning (25 Questions)
The questions in this section varied from Visual Reasoning, Blood Relations, Coding-Decoding, Series, Analogy, Odd one out, Arrangement to Verbal Reasoning.
There were six questions on Verbal Reasoning (Analogy, logical, implicit statement etc.) and Input-Output comprising of three questions. Almost all the other topics such as Coding & Decoding, Directions, Visual Reasoning, and Mathematical Operations had a weight age of approx. 2 questions each.
Verbal Reasoning had 6 questions and 19 questions from non verbal reasoning.
Overall, the questions in this section were easy. Approximately 19 questions easy to solve, an attempt count of 22-23 can be termed good with a suggested time of 50 minutes.
#### Language Comprehension (25 Questions)
Similar to 2019 paper, there were 2 Reading Comprehension passages with a total of 5 questions. The Verbal Ability segment had 20 questions. These included questions on Synonyms/Antonyms, Error spotting, fill in the Blanks, Meanings of words and their usage in sentences, grammatically correct sentence. There were 12 FIB questions.
Overall, the questions from this section were easy to moderate; it had predominantly grammar questions instead of Vocabulary. Attempt of 18-19 can be termed well with a suggested time of 45 – 50 minutes.
#### General Awareness (25 Questions)
General Awareness this year was a blend of static general knowledge (12 Questions) and current affairs (13 Questions). This section had a spread of questions ranging from History, Government ministry, Budget, International Organization, Banking and Finance, Sports, Science and Technology, Authors, Business and economy.
Overall, 12-13 attempts can be termed as good attempts in a suggested time of 10 minutes.
### CMAT 2021 Slot 2 Overall Score vs. Percentile Prediction
CMAT Score out of 400 Expected Percentile 262+ 99+ 256+ 98+ 230+ 95+ 184+ 80+ | 1,483 | 6,590 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.703125 | 3 | CC-MAIN-2023-14 | latest | en | 0.92019 |
https://www.weegy.com/?ConversationId=OPM8XO35 | 1,553,074,898,000,000,000 | text/html | crawl-data/CC-MAIN-2019-13/segments/1552912202324.5/warc/CC-MAIN-20190320085116-20190320111116-00479.warc.gz | 939,844,867 | 9,593 | Factor completely, then place the factors in the proper location on the grid. a2 - 9a + 20
Updated 4/5/2016 10:14:11 PM
Flagged by arel [4/5/2016 10:13:46 PM]
Original conversation
User: Factor completely, then place the factors in the proper location on the grid. a2 - 9a + 20
Updated 4/5/2016 10:14:11 PM
Flagged by arel [4/5/2016 10:13:46 PM]
Rating
3
a^2 - 9a + 20;
= a^2 - 4a - 5a + 4*5;
= (a - 4)(a - 5)
Confirmed by jeifunk [4/5/2016 10:18:56 PM], Rated good by jeifunk
Multiply the following polynomials, then place the answer in the proper location on the grid. Write the answer in descending powers of a. (a - 6)(a 2 +6a + 36)
Weegy: 3-3 = 0 (More)
Updated 3/30/2016 9:45:52 PM
(a - 6)(a^2 +6a + 36)
=a^3 + 6a^2 + 36a - 6a^2 - 36a - 216
=a^3 - 216
Factor completely, then place the answer in the proper location on the grid. 49x 2 + 42xy + 9y 2
Updated 3/30/2016 8:57:19 PM
49x^2 + 42xy + 9y^2;
= 7x*7x + 2*7x*3y + 3y*3y;
= (7x + 3y)(7x + 3y)
Confirmed by jeifunk [3/30/2016 9:43:09 PM]
Place the indicated product in the proper location on the grid. (b2 + 8 )(b2 - 8)
Updated 4/4/2016 8:59:00 PM
(b2 + 8 )(b2 - 8)
=b4 - 8b2 + 8b2 - 64
=b4 - 64
Factor completely, then place the factors in the proper location on the grid. b2 - 7b + 12
Weegy: b^2 - 7b + 12 is = (b - 3)(b - 4) (More)
Updated 4/4/2016 9:00:18 PM
Factor completely, then place the factors in the proper location on the grid. a2 - 5a - 6
Weegy: a^2 - 5a - 6 = (a + 1)(a - 6) (More)
Updated 4/4/2016 9:05:03 PM
29,508,615
*
Get answers from Weegy and a team of really smart live experts.
Popular Conversations
neurons control voluntary or involuntary responses of the body. ...
Weegy: There are three kinds of neurons in your body. These neurons are sensory neurons, inter-neurons, and motor ...
In a sentence, what is a colon?
Weegy: COLA is Cost of Living increases and based on inflation.
Dramas are meant to be read, but also heard and A. ...
Weegy: Dramas are meant to be read, but also heard and seen. User: Dramatic irony means that A. things are ...
individuals may be required to undergo HIV testing?
Weegy: Patients of hospitals with a high index of suspicion, [ and Healthcare providers that utilize needles ( ...
A compact fluorescent light bulb uses more energy than an ...
Weegy: A compact fluorescent light bulb uses more energy than an incandescent light bulb. FALSE.
The "bad" type of stress is known as A. management. B. ...
Weegy: The "good" type of stress is known as Eustress. User: How can doing something for someone else help to ...
Which of these statements best expresses the carpe diem theme in ...
Weegy: The following best expresses the carpe diem theme: Make the most of life while you can.
S
R
L
Points 835 [Total 935] Ratings 3 Comments 805 Invitations 0 Offline
S
L
P
C
P
C
Points 778 [Total 3579] Ratings 1 Comments 768 Invitations 0 Offline
S
L
1
Points 535 [Total 1171] Ratings 12 Comments 395 Invitations 2 Offline
S
L
Points 276 [Total 292] Ratings 0 Comments 256 Invitations 2 Offline
S
L
Points 243 [Total 420] Ratings 3 Comments 173 Invitations 4 Offline
S
L
Points 137 [Total 1734] Ratings 2 Comments 117 Invitations 0 Offline
S
L
Points 131 [Total 294] Ratings 1 Comments 121 Invitations 0 Offline
S
L
Points 120 [Total 120] Ratings 12 Comments 0 Invitations 0 Offline
S
L
Points 119 [Total 280] Ratings 8 Comments 9 Invitations 3 Offline
S
L
P
C
Points 83 [Total 1351] Ratings 1 Comments 73 Invitations 0 Offline
* Excludes moderators and previous
winners (Include)
Home | Contact | Blog | About | Terms | Privacy | © Purple Inc. | 1,235 | 3,548 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 4.1875 | 4 | CC-MAIN-2019-13 | latest | en | 0.87028 |
https://brainmass.com/economics/utility-demand/implications-and-uses-of-cross-price-elasticities-156715 | 1,580,312,255,000,000,000 | text/html | crawl-data/CC-MAIN-2020-05/segments/1579251799918.97/warc/CC-MAIN-20200129133601-20200129163601-00462.warc.gz | 359,528,992 | 12,046 | Explore BrainMass
Share
# Implications and uses of cross price elasticities.
This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!
The accompanying table lists the cross-price elasticities of demand for several goods, where the percent price change is
measured for the first good of the pair, and the percent quantity change is measured for the second good.
a. Explain the sign of each of the cross-price elasticities. What does it imply about the relationship between the two goods in question?
b. Compare the absolute values of the cross-price elasticities and explain their magnitudes. For example, why is the cross-price elasticity of McDonald's and Burger King less than the cross-elasticity of butter and margarine?
c. Use the information in the table to calculate how a 5% increase in the price of Pepsi affects the quantity of Coke demanded.
d. Use the information in the table to calculate how a 10% decrease in the price of gasoline affects the quantity of
SUVs demanded.
Good Cross-price elasticities of demand
Air-conditioning units and -0.34
kilowatts of electricity
Coke and Pepsi +0.63
High-fuel-consuming sport-utility vehicles
(SUV's) and gasoline -0.28
McDonald's burgers and Burger King burgers +0.82
Butter and margarine +1.54
© BrainMass Inc. brainmass.com October 9, 2019, 8:36 pm ad1c9bdddf
https://brainmass.com/economics/utility-demand/implications-and-uses-of-cross-price-elasticities-156715
#### Solution Preview
a. If two goods are substitutes, we should expect to see consumers purchase more of one good when the price of its substitute increases. Similarly if the two goods are complements, we should see a price rise in one good cause the demand for both goods to fall. Because the cross price elasticity measures the change in quantity demanded of one good, due to a price change of another good, we will have positive numbers if the goods are substitutes, and negative numbers if they are complements.
b. Butter and ...
#### Solution Summary
Implications and uses of cross price elasticities.
\$2.19 | 473 | 2,099 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.46875 | 3 | CC-MAIN-2020-05 | latest | en | 0.885095 |
https://bhxb.buaa.edu.cn/CN/10.13700/j.bh.1001-5965.2020.0636 | 1,652,877,782,000,000,000 | text/html | crawl-data/CC-MAIN-2022-21/segments/1652662522270.37/warc/CC-MAIN-20220518115411-20220518145411-00157.warc.gz | 191,789,830 | 16,633 | • 论文 •
### 复合材料层板冰雹高速冲击损伤预测及失效分析
1. 江苏大学 机械工程学院, 镇江 212013
• 收稿日期:2020-11-15 发布日期:2022-04-27
• 通讯作者: 张超 E-mail:zhangchao@ujs.edu.cn
• 基金资助:
江苏省普通高校研究生科研创新计划（KYCX20-3076）；江苏省自然科学基金（BK20180855）；机械结构力学及控制国家重点实验室开放课题（MCMS-E-0219Y01）
### Damage prediction and failure mechanism of composite laminates under high-velocity hailstone impact
ZHANG Chao, FANG Xin, LIU Jianchun
1. School of Mechanical Engineering, Jiangsu University, Zhenjiang 212013, China
• Received:2020-11-15 Published:2022-04-27
Abstract: Aiming at the potential risk of hailstone impact on the safety of composite structures, a continuum damage mechanics based nonlinear finite element model was developed to study the mechanical behavior of carbon fiber composite laminates under high-velocity hailstone impact. The Lagrangian method and smoothed particle hydrodynamics (SPH) method were used together to model the impact of hailstone, and the equation of state of water was introduced to describe the flow characteristics of the hailstone after breaking. A rate-dependent constitutive model of unidirectional composite, as well as 3D Hashin failure criteria and material stiffness reduction rule, was applied to predict the in-plane damage in composite layers. Interface elements governed by bilinear cohesive model were employed to simulate the inter-laminar delamination phenomena induced by impact. A user material subroutine VUMAT was coded and implemented to obtain the numerical solution based on ABAQUS/Explicit solver. The transient process of composite laminates under hailstone impact was reproduced and the damage characteristics and failure mechanism were analyzed in detail. The effects of impact velocity and impact angle of hailstone on the impact properties of composite laminates are discussed, which provides proper reference for numerical investigation of hailstone impact problems in composite structures. | 471 | 1,897 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 1, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.578125 | 3 | CC-MAIN-2022-21 | latest | en | 0.852444 |
https://people.inf.ethz.ch/gonnet/DarwinManual/node156.html | 1,716,321,703,000,000,000 | text/html | crawl-data/CC-MAIN-2024-22/segments/1715971058512.80/warc/CC-MAIN-20240521183800-20240521213800-00308.warc.gz | 386,754,765 | 5,944 | Next: Other Similarity Matrices Up: Point Accepted Mutations and Previous: Percent Identity and PAM
# Estimating Mutation Matrices
This section describes a method for computing mutation matrices, and hence Dayhoff matrices, which is more accurate and based on better theoretical grounds. This method will derive the information from a sample of matches of sequences (see Analysis of Mutation During Divergent Evolution'' M. Cohen, S. Benner and G. Gonnet, [8]). We will assume that we have a large enough sample which has been inspected and approved by an expert in the area. Although we could construct sample sets automatically, it is important that a person analyses this sample and weeds out unsuitable sequences which do not represent mutations by evolution.
We will further require that this sample be selected so that all its matches have approximately the same PAM distance. For example, let us suppose that all the matches have been selected so that their distance is between 35 and 45 PAM units. Chapter - The Pairwise Comparison of Amino Acid Sequences explains how to compute PAM distances of matches.
Suppose that we run the following experiment:
i)
Generate a random sequence S0.
ii)
Randomly mutate S0 with a 40-PAM mutation matrix generating a new sequence S1.
iii)
Compare S0 and S1 and build a comparison matrix C, such that every time that we have an amino acid i in S0mutating into an amino acid j in S1 we add 1 to Cij(and if it does not mutate, i.e. stays the same, we add 1 to Cii).
It is easy to see that the expected value of C is given by
where N is a diagonal matrix and Nii is the number of times amino acid i appears in S0. This approximation, by the law of large numbers, will be more accurate as we increase the number of sample points ( we increase the length of S0 and hence increase N).
The above equation is crucial for the estimation of M when we can tabulate a matrix C. Doing some trivial algebra, we find that
Since we do not know from our data which sequence evolved we will add 1/2 to Cij and 1/2 to Cji instead of adding 1 to Cij
The matrix N is obtained from counting all the amino acids analysed. Multiplying C by N-1 is equivalent to dividing each column of C by the sum of the column. (Note the columns of a mutation matrix add up to 1.)
Now, if we were certain about the PAM distance of the sample, in this case 40, we could compute . However, we may not have a lot of trust in the estimated PAM distances. This does not pose a problem since we can use the definition of a 1-PAM matrix as an anchor'':
The problem reduces to finding such that is a 1-PAM matrix. This value will be an estimate of the average PAM distance of the sample.
The following Darwin function computes an estimate of a 1-PAM matrix based on a sample of matches stored in a file. This function also receives as parameters a minimum value for the similarity, a minimum value for the length of the match and the minimum and maximum value for the PAM distance that we want to select.
> EstMutMat := proc( filename:string, MinSim:real, MinLength:real,
> Min{PAM}:real, Max{PAM}:real )
> description 'estimate a mutation matrix from matches read from a file';
> C := CreateArray(1..20,1..20);
> M := CreateArray(1..20,1..20);
Print some appropriate message to describe the present run.
> printf('Sample matches from file %s, MinSim=%g, MinLength=%g\n',
> filename,MinSim,MinLength);
> printf('{PAM} bounded between %3g and %3g\n', MinPAM, MaxPam );
To read a file from Darwin, line by line we first must establish a pipe via the OpenPipe command. This changes the standard input from the keyboard to the specified file. The file can be read line by line by issuing ReadLine calls within the body of a loop.
> OpenPipe('cat filename');
Initialize various counters to zero.
> totm := totma := totlm := toteq := totmut := 0;
This is now the main reading loop. The loop will be exited when the ReadLine call finds an end-of-file in which case returns the string EOF.
> do m := ReadLine();
> if m=EOF then break fi;
It is worthwhile to check that we read a match from the file.
> if not type(m,Match) then error('invalid input in', filename) fi;
> totm := totm+1;
If the values of the match do not fall within the acceptable ranges, then skip this match.
> if m[Sim] < MinSim or max(m[Length1],m[Length2]) < MinLength or
> m[PamNumber] > MaxPam or m[PamNumber] < MinPam then next fi;
> totma := totma+1;
The function DynProgStrings prepares an alignment for printing. In this case, we are interested in the strings of the aligned sequences as they would be printed. By scanning these two strings we can count the identities and the mutations.
> sm := DynProgStrings( m, SearchDayMatrix(m[PamNumber],DMS) );
> lm := length(sm[2]);
> totlm := totlm + lm;
For each character in the matched strings add in the C matrix.
> for i to lm do
> i1 := AToInt(sm[2,i]); i2 := AToInt(sm[3,i]);
> if i1>0 and i1<21 and i2>0 and i2<21 then
> if i1=i2 then toteq := toteq+1;
> C[i1,i1] := C[i1,i1]+1
> else totmut := totmut+1;
> C[i1,i2] := C[i1,i2]+1/2;
> C[i2,i1] := C[i2,i1]+1/2
> fi
> fi
> od
> od;
Print the collected counts.
> printf('%d matches read, %d selected with a total of %d positions,\n',
> totm, totma, totlm );
> printf('%d exact matches, %d mutations and %d deletions\n\n',
> toteq, totmut, totlm-toteq-totmut );
Compute the sum of the columns, but since the matrix C is symmetric, it is easier to compute the sum of the rows.
> Cols := CreateArray(1..20);
> for i to 20 do Cols[i] := sum(C[i]) od;
Now compute the frequencies of amino acids into F and normalize C into M.
> tot := sum(Cols);
> F := Cols/tot;
> for i to 20 do for j to 20 do M[i,j] := C[i,j]/Cols[j] od od:
To compute the 1-PAM matrix we need to find the exponent that will make a 1-PAM matrix. The following iteration converges quite rapidly to the desired solution. It is based on estimating as if it were linear on the probability of no change. This is not true, but both values are highly correlated. Hence by estimating and further correcting we converge to the right exponent.
> lnM := ln(M):
> alpha := 1;
Now iterate until a break is executed.
> do nochange := 0;
Compute the probability of no change and if it is sufficiently close to 1%, exit the loop.
> for i to 20 do nochange := nochange + F[i]*(1-M[i,i]) od;
> if abs(nochange-0.01) < DBL_EPSILON then break fi;
If it is not accurate enough, it must be corrected.
> corr := 0.01/nochange;
> alpha := alpha/corr;
> lnM := lnM*corr;
> M := exp(lnM);
> od;
> printf('The PAM of the aggregated sample was %5g\n\n',alpha);
Return the logarithm of a 1-PAM matrix and the frequency vector as a list with two elements in it.
> [lnM,F]
> end:
Now run this function with the file SamplePAM40.
> res := EstMutMat( SamplePAM40, 80, 100, 35, 45 ):
Sample matches from file SamplePAM40, MinSimil=80, MinLength=100
PAM bounded between 35 and 45
838 matches read, 838 selected with a total of 244069 positions,
170528 exact matches, 65473 mutations and 8068 deletions
The PAM of the aggregated sample was 33.8193
The PAM estimate of the sample is slightly lower than expected. This indicates that the original Dayhoff matrix tends to overestimate PAM distances.
Now we will compute a new Dayhoff matrix, with PAM 250, so that we may compare it with the original one. Since we have the logarithm of a 1-PAM mutation matrix in res[1], we can used the CreateDayMatrix command:
> NewD := CreateDayMatrix(res[1],250):
> print( NewD );
DayMatrix(Peptide, pam=250, Simil: max=15.035, min=-6.237,
max offdiag=5.554, del=-19.814-1.396*(k-1))
C 12.6
S 0.3 2.0
T -1.1 1.3 2.4
P -3.1 0.9 0.1 6.8
A -0.7 1.2 1.1 0.8 2.4
G -2.1 0.6 -0.6 -1.4 0.8 5.9
N -1.7 1.0 0.5 -1.1 0.0 0.4 3.2
D -3.6 0.1 -0.4 -1.6 -0.1 0.6 2.2 4.8
E -4.2 -0.3 -0.5 -1.1 -0.1 0.1 1.0 3.4 4.2
Q -3.1 -0.4 -0.4 -0.1 -0.7 -1.2 0.5 0.6 1.7 3.9
H -1.3 -0.4 -0.9 -0.7 -1.3 -1.7 1.4 0.1 -0.2 2.2 6.1
R -2.1 -0.4 -0.5 -0.9 -1.2 -0.9 0.2 -1.1 -0.2 2.0 1.5 5.1
K -3.5 -0.3 -0.1 -1.1 -0.8 -1.1 0.9 0.1 0.9 2.0 0.7 3.5 4.2
M -1.9 -1.5 -0.1 -2.0 -0.9 -3.4 -2.3 -3.2 -2.6 -1.5 -2.3 -2.0 -1.7 4.8
I -1.8 -1.4 0.1 -2.1 -0.5 -3.6 -2.4 -3.5 -3.0 -2.5 -2.7 -2.9 -2.7 3.0
L -2.3 -2.0 -1.0 -1.6 -1.6 -4.4 -3.1 -4.3 -3.6 -1.9 -1.9 -2.5 -2.8 3.2
V -1.1 -1.0 0.3 -1.5 0.2 -2.4 -2.1 -2.7 -2.2 -2.1 -2.5 -2.7 -2.4 2.3
F -0.8 -2.1 -2.3 -3.3 -2.9 -5.1 -3.0 -4.8 -4.9 -3.4 0.0 -3.9 -4.5 0.7
Y 0.4 -1.7 -2.4 -3.9 -3.1 -4.3 -1.0 -2.8 -3.6 -2.1 2.8 -2.6 -3.2 -1.7
W -1.2 -3.5 -4.6 -5.2 -4.6 -3.1 -4.1 -6.2 -5.9 -3.6 -1.7 -0.7 -3.8 -1.8
Although similar, the new matrix has some significant differences with the original one.
Next: Other Similarity Matrices Up: Point Accepted Mutations and Previous: Percent Identity and PAM
Gaston Gonnet
1998-09-15 | 2,982 | 9,070 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 1, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3 | 3 | CC-MAIN-2024-22 | latest | en | 0.940189 |
https://www.coursehero.com/file/po7ja/High-Tech-Inc-is-a-virtual-store-that-stocks-a-variety-of-calculators-in-their/ | 1,628,100,485,000,000,000 | text/html | crawl-data/CC-MAIN-2021-31/segments/1627046154897.82/warc/CC-MAIN-20210804174229-20210804204229-00389.warc.gz | 663,101,099 | 192,800 | High Tech Inc is a virtual store that stocks a variety of calculators in their
# High tech inc is a virtual store that stocks a
• Notes
• Meowheim
• 26
• 97% (108) 105 out of 108 people found this document helpful
This preview shows page 9 - 13 out of 26 pages.
10.* High Tech, Inc. is a virtual store that stocks a variety of calculators in their warehouse. Customer orders are placed, the order is picked and packaged, and then shipped to the customer. A fixed order quantity inventory control system (FQS) helps monitor and control these SKUs. The following information is for one of the calculators that they stock, sell, and ship.Average demand 12.5 calculators per weekLead time 3 weeksOrder cost \$20/orderUnit cost\$8.00Carrying charge rate0.15Number of weeks 52 weeks per yearStandard deviation of weekly demand3.75 calculatorsSKU service level90 percentCurrent on-hand inventory35 calculatorsScheduled receipts20 calculators
OM4 C12 IM Backorders 2 calculators a.What is the Economic Order Quantity? b.What is the total annual order and inventory-holding costs for the EOQ? c.What is the reorder point without safety stock? d.What is the reorder point with safety stock? (Comment: You may want to review how you looked up the Z = 1.28 using Appendix A)Most of these calculations can also be found using the FQS Safety Stock Excel template:e.Based on the previous information, should a fixed order quantity be placed, and if so, for how many calculators?
OM4 C12 IM 11.*Crew Soccer Shoes Company is considering a change of their current inventory control system for soccer shoes. The information regarding the shoes is given below.Average demand = 200 pairs/weekLead time = 3 weeksOrder cost = \$65/orderUnit cost = \$20Carrying charge rate = 0.20Desired service level = 95%Standard deviation of weekly demand = 50Number of weeks per year = 52The company decides to use a fixed order quantity system. What is the economic order quantity? What should be the reorder point be to have a 95% service level? Explain how the system will operate.
OM4 C12 IM | 485 | 2,063 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.734375 | 3 | CC-MAIN-2021-31 | latest | en | 0.874562 |
https://stonespounds.com/312-6-stones-in-stones-and-pounds | 1,642,910,568,000,000,000 | text/html | crawl-data/CC-MAIN-2022-05/segments/1642320303956.14/warc/CC-MAIN-20220123015212-20220123045212-00396.warc.gz | 548,646,732 | 4,915 | # 312.6 stones in stones and pounds
## Result
312.6 stones equals 312 stones and 8.4 pounds
You can also convert 312.6 stones to pounds.
## Converter
Three hundred twelve point six stones is equal to three hundred twelve stones and eight point four pounds (312.6st = 312st 8.4lb). | 78 | 285 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.265625 | 3 | CC-MAIN-2022-05 | latest | en | 0.792786 |
https://nessgrh.wordpress.com/2011/04/27/things-to-keep-in-mind/ | 1,500,814,524,000,000,000 | text/html | crawl-data/CC-MAIN-2017-30/segments/1500549424559.25/warc/CC-MAIN-20170723122722-20170723142722-00270.warc.gz | 663,924,683 | 31,572 | ## Things to keep in mind
In Uncategorized on April 27, 2011 by nessgrh
This is going to be a list of random things I should keep in mind while working on the GSoC project. I’ll keep updating it.
• $G$ function has a (logarithmic) branch point at the origin
• Gamma function estimates (a la stirling) use a branch cut along the negative reals, e.g. here: $\Gamma(z+a) = e^{-z} z^{z+a-\frac{1}{2}} (2 \pi)^{\frac{1}{2}} \left(1+O\left(\frac{1}{z}\right)\right)$, for $|\arg(z+a)| \le \pi - \epsilon$ where the implicit constant in $O\left(\frac{1}{z}\right)$ depends on $a$ and $\epsilon$. | 192 | 591 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 6, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.53125 | 3 | CC-MAIN-2017-30 | longest | en | 0.730693 |
https://gyroplacecl.com/gyroscope-sensor-measures-a-comprehensive-guide/ | 1,718,343,160,000,000,000 | text/html | crawl-data/CC-MAIN-2024-26/segments/1718198861521.12/warc/CC-MAIN-20240614043851-20240614073851-00280.warc.gz | 264,691,793 | 22,262 | # Gyroscope Sensor Measures: A Comprehensive Guide
## Short answer gyroscope sensor measures:
A gyroscope sensor measures the angular velocity or rotational motion of an object. It provides information about the rate at which the object is rotating around its axes, making it highly useful in various applications such as navigation systems, motion controllers, and robotics.
## Understanding Gyroscope Sensor Measures: A Comprehensive Guide
Understanding Gyroscope Sensor Measures: A Comprehensive Guide
As technology continues to advance at an astonishing rate, sensors have become an integral part of our everyday lives. One such sensor that has gained significant popularity is the gyroscope sensor. In this comprehensive guide, we aim to delve into the intricacies of the gyroscope sensor measures, providing you with a detailed understanding in a professional yet witty and clever manner.
So, what exactly is a gyroscope sensor? Well, imagine having a tiny spinning top inside your device that can detect changes in orientation and rotation. That’s essentially what a gyroscope sensor does! It measures the angular velocity or rotational rate along three axes – X, Y, and Z – providing us with valuable information about how our devices move and react within space.
Now for the nitty-gritty details! Let’s start with why gyroscopes are essential in our devices. As we all know, smartphones and other electronic gadgets are equipped with features like motion sensing and image stabilization. These functions heavily rely on accurate measurements provided by gyroscope sensors. By precisely detecting tilt or rotation along different axes, these sensors enable your phone to automatically adjust screen orientation or enhance gaming experiences.
To illustrate this further, let’s say you’re playing an intense car racing game on your phone. The moment you tilt your device sideways as if steering through corners, it’s the trusty gyroscope sensor that detects this movement promptly! This data is then used to calculate how fast your virtual car should turn in response to your physical movements.
But how do gyroscopes actually measure all this? The answer lies in something called the Coriolis effect. Now don’t worry; we won’t get too technical here! Think of it like being on a merry-go-round – as you rotate faster or change direction abruptly, you experience a force pulling inwards or outwards due to inertia. Similarly, when your device rotates or tilts, the spinning mass inside the gyroscope sensor experiences a similar underlying force, which is measured and converted into useful information.
It’s worth noting that gyroscopes are not limited to our smartphones; they impact many aspects of modern technology. From drones to virtual reality headsets, from fitness trackers to spacecraft navigation systems, gyroscopes have become indispensable in ensuring accurate motion detection across various industries.
Now for the clever bit! Let’s take a moment to appreciate how these tiny sensors juggle multiple tasks simultaneously. Just like an acrobat gracefully balancing on a tightrope, the gyroscope sensor oscillates between measuring steady rotations, detecting rapid changes in orientation, and maintaining stability – all while fitting snugly within a small device! Impressive, right?
So next time you’re steering your favorite gaming car through sharp corners or capturing those perfect stable shots on your phone’s camera, remember the unsung hero working behind the scenes – the gyroscope sensor!
In conclusion, gaining a comprehensive understanding of gyroscope sensor measures enables us to appreciate their role in our everyday lives. Whether it’s ensuring immersive gaming experiences or stabilizing stunning photographs and videos, these sensors continue to revolutionize how we interact with technology. So go ahead and explore the vast possibilities offered by this remarkable invention – you’ll be astounded by what lies beyond its humble spinning core!
## How Gyroscope Sensor Measures Work: Explained Step by Step
Have you ever wondered how a gyroscope sensor works? This ingenious device, found in smartphones, fitness trackers, and even drones, is responsible for measuring rotational movements. In this blog post, we will delve into the intricacies of the gyroscope sensor and explain its steps of operation – all while infusing a touch of professionalism, wit, and cleverness. So let’s take a virtual journey through the fascinating world of gyroscope sensors!
Step 1: Introduction to Gyroscope Sensor
To kick things off, let’s get acquainted with our protagonist – the gyroscope sensor. A small yet powerful component that resembles something straight out of a sci-fi movie! The primary purpose of this sensor is to measure angular velocity or how fast an object rotates around an axis. Just like your inner ear keeps track of your head movements to maintain balance, the gyroscope sensor does it electronically.
Imagine attending a dance class where instead of following a choreographer’s instructions based on sight (visual cues), you decide to follow through only by detecting rotational motions. That’s exactly what a gyroscope sensor does! It measures rotation directly instead of relying on external references like cameras or GPS signals.
Step 3: Principles Behind Gyroscopes
Now, let’s dive deeper into the principles at play here. Inside the tiny package that is the gyroscope sensor lies an equally fascinating mechanism – typically consisting of a spinning rotor surrounded by vibrating masses or electrodes. As you rotate your device along any axis, the inertia created by these masses causes deflections which are then measured as voltages.
Step 4: Calculating Angular Velocity
Having understood the basic principles behind gyroscopes, it’s time for some number crunching! By analyzing those voltage deflections and applying some clever calculations using advanced algorithms, your phone can determine the angular velocity with remarkable accuracy. Think of it as converting those electrical “dance moves” into meaningful numbers.
Step 5: Combining Gyroscope with Accelerometer and Magnetometer
Aspiring dancers know that no routine is complete without a perfect combination of moves. In the same vein, gyroscope sensors often work hand in hand with other sensors like accelerometers and magnetometers to provide a comprehensive measurement system. This collaborative effort improves accuracy by compensating for acceleration forces and enabling calibration against magnetic interference.
Step 6: A Fine Balance – Calibration
Calibration plays an essential role in ensuring accurate measurements from gyroscopes. Just as dancers follow rigorous training routines to polish their techniques, gyroscope sensors undergo calibration processes to eliminate potential biases or errors. Manufacturers employ advanced calibration techniques, optimizing performance for diverse applications ranging from gaming to autonomous vehicles.
Step 7: Real-World Applications
Now that we have uncovered the magic behind these motion-sensing marvels, let’s step back and appreciate how they enrich our lives. From enhancing virtual reality experiences and stabilizing drone flights to enabling fitness tracking and revolutionizing navigation systems, gyroscope sensors have found their way into various industries where precise motion detection is paramount.
In conclusion, understanding how a gyroscope sensor measures work requires delving into its innovative principles while appreciating the collaborative efforts it engages in with other sensors. By effortlessly converting rotational movements into electrical signals and leveraging advanced algorithms, these tiny yet mighty devices enable exceptional precision in measuring angular velocity. As you navigate through your daily activities dependent on your favorite gadgets’ motion sensing capabilities, take a moment to acknowledge the remarkable workings of the humble gyroscope sensor. So go forth, armed with knowledge about this technological wonder!
## Mastering Gyroscope Sensor Measures: FAQs Answered
Mastering Gyroscope Sensor Measures: FAQs Answered
Gyroscopes, popularly known as gyros, have become a crucial component in various electronic devices, such as smartphones and drones. These tiny sensors play a significant role in determining the orientation and movement of these devices. However, understanding how to effectively measure and interpret gyroscope data can be quite challenging for many professionals.
In this blog post, we will delve into the world of gyroscopes, answering frequently asked questions regarding their measurement techniques. We aim to provide you with detailed insights on how to master gyroscope sensor measures like a pro while infusing our explanations with a touch of wit and cleverness.
1. What is a gyroscope sensor?
Imagine having an invisible device that can detect even the tiniest rotations or changes in orientation within 3D space—this is essentially what a gyroscope sensor does. By utilizing principles of physics, gyros can measure angular velocity or rotational movements around multiple axes accurately.
2. How does a gyroscope work?
To put it simply, a typical MEMS (Microelectromechanical Systems) gyro consists of a vibrating structure known as the proof mass. When subjected to rotation or acceleration along any axis, the Coriolis effect causes the proof mass to deflect perpendicularly to its vibration direction. This deflection generates electrical signals proportional to the angular velocity acting upon it.
3. How do I calibrate my gyroscope sensor?
Calibrating your gyro is essential for accurate measurements. Most modern devices come with built-in calibration algorithms that eliminate drift errors and stabilize readings over time automatically. However, if you are working with custom-built systems or require precise measurements, manual calibration might be necessary using established mathematical models and calculated correction factors.
4. Can I combine gyro data with other sensors for enhanced accuracy?
Absolutely! Combining data from multiple sensors like accelerometers or magnetometers can significantly improve accuracy by compensating for individual sensor limitations. This process, known as sensor fusion, employs complex algorithms like the Kalman filter to merge the data and provide a more detailed understanding of the device’s position and movement.
5. How can I deal with gyro drift?
Gyro drift refers to small errors that accumulate over time due to imperfections in manufacturing or environmental conditions. Fortunately, many sophisticated gyros now have built-in drift compensation features. Additionally, periodically calibrating the sensor using stationary reference points can minimize such errors. Advanced techniques like Zero Velocity Updates (ZUPT) or Zero Angular Rate Updates (ZARU) can also be employed when motionless periods are detected.
6. Are there any specific challenges when working with gyroscope sensors?
Yes, indeed! One common challenge is dealing with external disturbances like vibrations or magnetic fields that might interfere with gyro readings. Shielding the sensor or implementing appropriate filtering techniques can help mitigate these issues effectively.
7. What applications benefit from mastering gyroscope measurements?
The applications utilizing gyros are wide-ranging and diverse. From navigation systems in autonomous vehicles and drones to augmented reality headsets and image stabilization mechanisms in cameras, mastering gyroscope measures unlocks a plethora of exciting possibilities across industries.
In conclusion, understanding how to master gyroscopic sensor measures is crucial for professionals working with various electronic devices today. By grasping the principles behind their functioning, knowing how to calibrate them accurately, and leveraging sensor fusion techniques, one can enhance accuracy and unlock endless potential in various applications.
So go ahead—embrace your inner gyro expert! With wit and cleverness as your guiding companions along this fascinating journey into measuring gyroscopes precisely, you’ll be able to navigate through this dynamic world of sensors with ease and finesse!
## Unlock the Potential with Gyroscope Sensor Measures: A Complete Overview
Unlocking the potential of technology has been a never-ending pursuit in our rapidly advancing world. One such technology that has revolutionized various domains is the gyroscope sensor measures. With its versatility and precision, this remarkable device has become an integral part of numerous applications, ranging from smartphones to sophisticated navigation systems.
Before delving into the intricacies of how this tiny marvel works, let’s understand what a gyroscope sensor actually is. In simple terms, it is a device that measures angular velocity or rotation in three-dimensional space. By analyzing changes in orientation and position over time, it provides vital data to countless technological endeavors.
Now, you might wonder why unlocking the potential of a gyroscope sensor is so crucial? Well, imagine your smartphone without the ability to auto-rotate its screen when you switch between portrait and landscape modes. Or picture a drone struggling to maintain stable flight without accurate motion tracking. Without the capabilities offered by gyroscope sensors, these seemingly mundane tasks would be impossible.
The principle behind gyroscope sensor measures lies in the physics of rotational motion. It operates on what is known as the Coriolis effect – a phenomenon where an object moving in a rotating system experiences apparent forces due to its inertia. In simpler terms, when an object rotates along one axis while being subject to forces acting along another axis, it causes measurable deflections that are captured by a gyroscope sensor.
In practical applications, gyroscopes find their significance across diverse fields. For instance, in aviation and maritime industries, they form the backbone of inertial navigation systems (INS) used for precise geolocation and guidance during travels. These sensors ensure stability and accuracy even when GPS signals are weak or unavailable – lifesaving features under challenging circumstances.
Beyond transportation sectors, scientists leverage gyroscopes’ exceptional accuracy for scientific experiments involving precise measurements of positions or rotations. The medical field benefits immensely from this technology too; surgeons employ it during complex procedures where microscopic movements can make a significant difference.
Impressively, the potential of gyroscope sensor measures goes beyond utilitarian applications. In gaming and virtual reality, these sensors provide an immersive experience by tracking even the slightest hand movements – enhancing gameplay to new heights. Likewise, architects and engineers can conceptualize designs more effectively by simulating movements, stress distributions, and stability using data from gyroscopic sensors.
While we have explored several applications that harness the power of gyroscope sensors, it is important to acknowledge the ongoing advancements in this field. Research is focused on miniaturizing sensors further, improving their sensitivity and accuracy levels, and extending battery life for an extended operational period.
To conclude, unlocking the potential with gyroscope sensor measures serves as a gateway to infinite possibilities across various industries. Be it revolutionizing communication through smartphones or pushing the boundaries of space exploration; this technology has become an indispensable tool in our modern world. By understanding its mechanics and continually refining its capabilities, we can continue to push forward into uncharted territories while reaping the benefits of this incredible invention.
## Demystifying Gyroscope Sensor Measures: The Science Behind it All
Title: Demystifying Gyroscope Sensor Measures: The Science Behind it All
Introduction:
Gyroscopes, often utilized in various devices like smartphones and drones, have become an indispensable sensor for detecting and measuring rotational motion. Their importance cannot be underestimated, as they play a significant role in providing stability and accurate orientation information. However, understanding the science behind gyroscopes can be somewhat daunting for some. In this article, we aim to demystify gyroscope sensor measures by unraveling the intricate workings of this incredible technology.
1. Gyroscope Basics – Grasping the Fundamentals:
To comprehend how gyroscopes work, imagine a spinning top that maintains its balance even when subjected to external forces. Similarly, a gyroscope relies on an internal spinning rotor called the gimbal, which resists any angular movement due to the principle of angular momentum conservation. This resistance allows for the measurement of rotation rates effectively.
2. Angular Velocity Measurement – Unveiling the Secret Formula:
Gyroscopes measure angular velocity, defined as how quickly an object rotates about its axis. This measurement is carried out using equations involving trigonometry and physics principles such as torque and inertia. By analyzing changes in angular velocity over time, gyroscopes enable accurate navigation and motion tracking.
3. MEMS Gyroscopes – A Miniaturized Marvel:
Micro-Electromechanical System (MEMS) gyroscopes are widely used in modern electronic devices due to their small size and reliability. These microscopic wonders utilize vibrating masses or capacitive elements to detect rotational movements. MEMS gyroscopes have revolutionized industries by allowing seamless integration into mobile phones, gaming consoles, virtual reality headsets, and more.
4. The Role of Axis Stabilization – Keeping Orientation Intact:
One crucial application of gyroscopes is maintaining stable orientation even when external forces act upon an object or device. For example, image stabilization in smartphone cameras leverages gyroscope data to compensate for hand tremors, resulting in remarkably sharp photos and smooth videos. The gyroscope acts as the guardian of stability, ensuring that your memories are captured perfectly.
5. Gyroscopes in Robotics – Mastering Precise Movement:
In robotics, gyroscopes serve as critical tools for achieving precise and accurate movements. Autonomous robots rely on gyroscopic feedback to make adjustments in their balance, direction, and navigation. By providing real-time data on angular velocity, gyroscopes enable robots to adapt to various terrains and challenging environments efficiently.
6. Gyroscopes & Virtual Reality – Navigating Digital Worlds:
Virtual Reality (VR) headsets have taken entertainment and gaming realms by storm, immersing users into digital worlds. This virtual immersion is made possible by incorporating highly sensitive gyroscopes within the headset itself. These sensors track the user’s head rotation precisely, allowing seamless synchronization between the virtual environment’s perspective and real-life movement.
Conclusion:
Gyroscopes have emerged as extraordinary devices with immense applications across industries spanning from consumer electronics to aerospace engineering. By understanding the science behind gyroscope sensor measures, we can better appreciate their significant role in stabilizing devices, enhancing robotics precision, enabling virtual reality experiences like never before. Next time you pick up your smartphone or step into a VR experience, remember the intricate inner workings of these remarkable sensors that revolutionize our lives one rotation at a time.
## Harnessing the Power of Gyroscope Sensor Measures: Tips and Tricks for Accurate Results
Harnessing the Power of Gyroscope Sensor Measures: Tips and Tricks for Accurate Results
When it comes to high-tech sensors, few are as versatile and powerful as the gyroscope sensor. Originally developed for navigation purposes, this incredible piece of technology has found its way into a wide range of devices, from smartphones and tablets to drones and virtual reality headsets. Its ability to measure orientation, angular velocity, and rotation has revolutionized countless industries and applications.
However, like any tool, the gyroscope sensor requires proper understanding and implementation to yield accurate results. In this blog post, we will delve into the exciting world of gyroscope sensors, providing you with tips and tricks on how to harness their power effectively.
1. Understand the Basics:
Before diving into more advanced techniques, it is crucial to familiarize yourself with the basics of gyroscope sensors. Understanding concepts such as pitch, yaw, roll, angular velocity measurement units (degrees per second), and coordinate systems will lay a solid foundation for your work. This knowledge will help you grasp not only how these sensors function but also how they can be integrated seamlessly into your project.
2. Calibrate Regularly:
Calibration is vital when working with gyroscope sensors since even minor errors can accumulate over time and compromise accuracy. Establishing a regular calibration routine ensures that your measurements remain precise throughout extended periods of use or deployments. Several calibration methods exist for different applications; choose one that best suits your requirements.
3. Consider Sensor Fusion:
While a gyroscope sensor alone provides valuable data about rotational motion, combining it with other complementary sensors through sensor fusion algorithms enhances accuracy further. For instance, fusing accelerometer data with data from the gyroscope compensates for drift errors in both sensors individually—resulting in highly accurate orientation tracking even during prolonged usage periods.
4. Factor in External Influences:
Gyroscopes are sensitive devices that can be easily influenced by external factors such as temperature changes, vibration, or magnetic fields. Identifying and mitigating these influences will prevent readings from being skewed. Shielding the sensor or employing filtering mechanisms to reduce noise can significantly enhance accuracy.
5. Test in Real-world Scenarios:
To ensure your gyroscope sensor measures accurately in practical applications or environments, it is essential to test it under real-world conditions. This step allows you to account for variables specific to your project that may affect the data quality—for example, vibrations during drone flights or sudden movements during gaming sessions. By analyzing results obtained in realistic scenarios, you can make necessary adjustments and fine-tune your system accordingly.
6. Consult Documentation and Resources:
Gyroscope sensors are widely used across numerous industries, which means extensive documentation and resources are readily available online. Take advantage of technical specifications, user manuals, code samples provided by manufacturers, and join relevant forums or communities to learn from experts who have experience with similar projects. Utilizing these resources will help you navigate any challenges you encounter while maximizing the potential of your gyroscope sensor.
In conclusion, mastering gyroscope sensors opens up a world of possibilities for accurate measurement of orientation and rotational motion. By grasping the basics, regularly calibrating the sensor, considering sensor fusion techniques, accounting for external influences, testing in real-world scenarios, and utilizing available resources—your ability to harness this incredible technology effectively will result in accurate measurements that empower innovation across various applications from consumer electronics to industrial automation.
Rate author | 4,160 | 23,875 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.59375 | 3 | CC-MAIN-2024-26 | latest | en | 0.886532 |
https://gmatclub.com/forum/tricky-sc-series-86106.html?fl=similar | 1,487,762,699,000,000,000 | text/html | crawl-data/CC-MAIN-2017-09/segments/1487501170940.45/warc/CC-MAIN-20170219104610-00142-ip-10-171-10-108.ec2.internal.warc.gz | 708,392,502 | 58,363 | Tricky SC Series- #8 : GMAT Sentence Correction (SC)
Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack
It is currently 22 Feb 2017, 03:24
### GMAT Club Daily Prep
#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
we will pick new questions that match your level based on your Timer History
Track
every week, we’ll send you an estimated GMAT score based on your performance
Practice
Pays
we will pick new questions that match your level based on your Timer History
# Events & Promotions
###### Events & Promotions in June
Open Detailed Calendar
# Tricky SC Series- #8
Author Message
TAGS:
### Hide Tags
Senior Manager
Joined: 18 Aug 2009
Posts: 303
Followers: 3
Kudos [?]: 274 [1] , given: 9
### Show Tags
31 Oct 2009, 22:07
1
KUDOS
00:00
Difficulty:
(N/A)
Question Stats:
67% (02:11) correct 33% (00:45) wrong based on 60 sessions
### HideShow timer Statistics
Hi All !
Sharing some SCs from a recent mock test (thought that u may or may not get the same q when you take the same mock and that it'd be a good practice for all... ). Please post some explanation with the answers.
Attachments
clubPlaceholder.JPG [ 45.17 KiB | Viewed 3299 times ]
If you have any questions
New!
Senior Manager
Joined: 18 Aug 2009
Posts: 303
Followers: 3
Kudos [?]: 274 [0], given: 9
Re: Tricky SC Series- #8 [#permalink]
### Show Tags
02 Nov 2009, 21:34
if no other attempts on this one, i'll post the OA in a day or two..
Intern
Joined: 06 Sep 2009
Posts: 24
Location: Mumbai
Followers: 0
Kudos [?]: 2 [0], given: 9
Re: Tricky SC Series- #8 [#permalink]
### Show Tags
03 Nov 2009, 00:12
IMO, A
formidably gruesome - both the words almost mean the same ( and MBA cant be that horrible )
grueling is the word needed here
P.S Great collection - @gmattokyo
Senior Manager
Joined: 18 Aug 2009
Posts: 303
Followers: 3
Kudos [?]: 274 [1] , given: 9
Re: Tricky SC Series- #8 [#permalink]
### Show Tags
03 Nov 2009, 02:24
1
KUDOS
Again, most of you got it right.. thnx!
OA:
[Reveal] Spoiler:
A
parallelism grueling.. challenging
BSchool Forum Moderator
Joined: 01 Oct 2009
Posts: 602
GMAT 1: 530 Q47 V17
GMAT 2: 710 Q50 V36
Followers: 37
Kudos [?]: 314 [0], given: 410
Re: Tricky SC Series- #8 [#permalink]
### Show Tags
03 Nov 2009, 05:52
A it is thanku
these Questions are good
SVP
Affiliations: HEC
Joined: 28 Sep 2009
Posts: 1637
Concentration: Economics, Finance
GMAT 1: 730 Q48 V44
Followers: 99
Kudos [?]: 637 [0], given: 432
Re: Tricky SC Series- #8 [#permalink]
### Show Tags
19 Nov 2009, 08:48
A, due to parallelism. The word "formidably" is designed to throw readers off.
_________________
Director
Joined: 24 Aug 2007
Posts: 954
WE 1: 3.5 yrs IT
WE 2: 2.5 yrs Retail chain
Followers: 76
Kudos [?]: 1277 [0], given: 40
Re: Tricky SC Series- #8 [#permalink]
### Show Tags
04 May 2010, 22:02
IMO A.
formidably is used as an adverb to modify Challenging while Gruelling is correct in its usage.
_________________
Tricky Quant problems: http://gmatclub.com/forum/50-tricky-questions-92834.html
Important Grammer Fundamentals: http://gmatclub.com/forum/key-fundamentals-of-grammer-our-crucial-learnings-on-sc-93659.html
Manager
Joined: 21 Jan 2010
Posts: 231
Followers: 5
Kudos [?]: 93 [0], given: 38
Re: Tricky SC Series- #8 [#permalink]
### Show Tags
15 May 2010, 06:11
A it is.
But what's wrong with C?
Parallelism doesn't require both adj ends with "-ing" riight?
Senior Manager
Joined: 14 Jun 2010
Posts: 333
Followers: 2
Kudos [?]: 24 [0], given: 7
Re: Tricky SC Series- #8 [#permalink]
### Show Tags
05 Sep 2010, 04:05
I go with A.....was down to A and D
Re: Tricky SC Series- #8 [#permalink] 05 Sep 2010, 04:05
Similar topics Replies Last post
Similar
Topics:
4 Tricky SC Series- #7 12 31 Oct 2009, 22:03
1 Tricky SC Series - #6 17 31 Oct 2009, 21:58
1 Tricky SC Series - #4 15 31 Oct 2009, 21:33
1 Tricky SC Series - #3 14 31 Oct 2009, 21:28
2 Tricky SC Series - #1 10 31 Oct 2009, 21:16
Display posts from previous: Sort by | 1,383 | 4,184 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.234375 | 3 | CC-MAIN-2017-09 | longest | en | 0.82365 |
https://www.pcreview.co.uk/threads/copy-lines-from-sheet-2-to-sheet-6.3820637/ | 1,716,375,325,000,000,000 | text/html | crawl-data/CC-MAIN-2024-22/segments/1715971058542.48/warc/CC-MAIN-20240522101617-20240522131617-00085.warc.gz | 829,881,137 | 14,299 | Copy lines from sheet 2 to sheet 6
P
pcor
I have some data in sheet 2 in col I.
the data I want to capture is spaced by 7 spaces all the ay down:
EX:
I have data in sheet 2 col I row 1 ,7,14,21 etc
I would like to show the data in Sheet 2 to Sheet 6 col B row 1,2,3,4, etc
thanks
R
Ragdyer
On Sheet6, enter this in B1:
=Sheet2!I1
And in B2 enter this:
=INDEX(Sheet2!I:I,7*ROWS(\$1:1))
and copy down as needed.
P
pcor
Thanks. It worked very well. BUT...will you please exxplain what that is
REALLY doing. I think I understand all but the ROWS(\$!:1) got me confused.
Thansk again
R
RagDyeR
The Index() function has different forms.
The one used here can be described as "referencing" a location.
Since it's a one dimension reference (a single column), the second argument
refers to a row within that column.
You could just as easily have used formulas such as these:
=INDEX(Sheet2!I:I,1)
=INDEX(Sheet2!I:I,2)
=INDEX(Sheet2!I:I,3)
.... etc.
If you indexed a single row:
=INDEX(Sheet2!3:3,1)
=INDEX(Sheet2!3:3,2)
=INDEX(Sheet2!3:3,3)
That second argument would refer to a column within that row.
You should note however, that these row (column) references (1, 2, 3 ...
etc.) *do not* refer to the *Sheet* rows (columns), but to the cells
*strictly within* the indexed column or row.
=INDEX(Sheet2!I20:I30,1)
refers to I20, that being the *first* row of the indexed (chosen) range.
Therefore:
=INDEX(Sheet2!I20:I30,4)
refers to I23, the 4th row of the indexed range.
=INDEX(Sheet2!F3:M3,4)
refers to I3, the 4th column of the indexed range.
However, It would be very tedious to have to manually change the numbers in
the 2nd argument as we copied the formula down or across.
There are a couple of nice functions which count the number of rows and
columns within their parameters.
They return a simple number which we can use to increment automatically.
=Rows(1:1)
=Columns(A:A)
As you copy the Rows() down, and the Columns() across they increase.
=Rows(1:1)
=Rows(2:2)
=Rows(3:3)
BUT, they still equal 1, the number of rows within it's parameters.
SO, we just anchor the first reference by making it absolute, and only allow
the second to increase:
=Rows(\$1:1)
=Rows(\$1:2)
=Rows(\$1:3)
And this returns a number that automatically increments as it's copied.
As an aside, you can anchor the second reference and make the function
*decrement* as it's copied.
=Rows(1:\$10)
=Rows(2:\$10)
=Rows(3:\$10)
Finally, since you wanted your rows in multiples of 7, we simply multiplied
the returns of the Rows() function by 7.
--
HTH,
RD
=====================================================
Please keep all correspondence within the Group, so all may benefit!
=====================================================
Thanks. It worked very well. BUT...will you please exxplain what that is
REALLY doing. I think I understand all but the ROWS(\$!:1) got me confused.
Thansk again
P
pcor
That was a G R E A T explanation. Many Thanks
RagDyeR said:
The Index() function has different forms.
The one used here can be described as "referencing" a location.
Since it's a one dimension reference (a single column), the second argument
refers to a row within that column.
You could just as easily have used formulas such as these:
=INDEX(Sheet2!I:I,1)
=INDEX(Sheet2!I:I,2)
=INDEX(Sheet2!I:I,3)
.... etc.
If you indexed a single row:
=INDEX(Sheet2!3:3,1)
=INDEX(Sheet2!3:3,2)
=INDEX(Sheet2!3:3,3)
That second argument would refer to a column within that row.
You should note however, that these row (column) references (1, 2, 3 ...
etc.) *do not* refer to the *Sheet* rows (columns), but to the cells
*strictly within* the indexed column or row.
=INDEX(Sheet2!I20:I30,1)
refers to I20, that being the *first* row of the indexed (chosen) range.
Therefore:
=INDEX(Sheet2!I20:I30,4)
refers to I23, the 4th row of the indexed range.
=INDEX(Sheet2!F3:M3,4)
refers to I3, the 4th column of the indexed range.
However, It would be very tedious to have to manually change the numbers in
the 2nd argument as we copied the formula down or across.
There are a couple of nice functions which count the number of rows and
columns within their parameters.
They return a simple number which we can use to increment automatically.
=Rows(1:1)
=Columns(A:A)
As you copy the Rows() down, and the Columns() across they increase.
=Rows(1:1)
=Rows(2:2)
=Rows(3:3)
BUT, they still equal 1, the number of rows within it's parameters.
SO, we just anchor the first reference by making it absolute, and only allow
the second to increase:
=Rows(\$1:1)
=Rows(\$1:2)
=Rows(\$1:3)
And this returns a number that automatically increments as it's copied.
As an aside, you can anchor the second reference and make the function
*decrement* as it's copied.
=Rows(1:\$10)
=Rows(2:\$10)
=Rows(3:\$10)
Finally, since you wanted your rows in multiples of 7, we simply multiplied
the returns of the Rows() function by 7.
--
HTH,
RD
=====================================================
Please keep all correspondence within the Group, so all may benefit!
=====================================================
Thanks. It worked very well. BUT...will you please exxplain what that is
REALLY doing. I think I understand all but the ROWS(\$!:1) got me confused.
Thansk again
R
RagDyeR
You're welcome, and thank you for feeding back. | 1,498 | 5,326 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.703125 | 3 | CC-MAIN-2024-22 | latest | en | 0.910936 |
https://farfromhomemovie.com/how-many-hours-does-it-take-to-read-100-pages/ | 1,716,532,594,000,000,000 | text/html | crawl-data/CC-MAIN-2024-22/segments/1715971058684.66/warc/CC-MAIN-20240524060414-20240524090414-00241.warc.gz | 226,377,347 | 12,025 | 2021-03-10
## How many hours does it take to read 100 pages?
2.8 hours
### How long should it take to read 30 pages?
#### How long should it take to read 20 pages?
How do you read 20 pages in an hour?
Take a watch set a timer of 3 minutes. You have to read a page in 3 minutes to achieve your target of 20 pages per hour. This is a calculated time for you. If you can failed to achieve it in first attempt try it second time, if you failed second time and then try it for third time.
How many pages should I read in an hour?
If it’s a novel, with about 250 words per page, medium difficulty, not much eye strain, and i’m moderately interested, i could probably read anywhere from 45–70 pages in an hour while really absorbing it. If it’s a quantum mechanics book, probably about 3–5 pages in an hour.
## How do you read 600 pages in a day?
The average reading speed is considered to be 200 words per minute (WpM), so it would take at least 10 hours for an average reader to cover 600 pages: that’s almost a full day spent with reading.
### Can I read 200 pages in 2 hours?
#### Is it possible to read 1000 pages in a day?
How do you read 500 pages a day?
Of the topic Buffett said: “Read 500 pages every day. That’s how knowledge works. It builds up, like compound interest….Here are seven ways how.Read physical books. Set a reading goal and stick to it. Read between the lines. If the book sucks, move on. Read several genres at once.
How do you read 500 pages in a week?
= 107 minute which is a little less than two hours. So you’ll need to spend 2 hours reading per day for a week to reach your 500 page target….Follow the Pomodoro Technique.Read for 25 minutes without being disturbed.Take a break for 5 minutes. Repeat the process 4 times.Take a 15 minute break.
## How fast can you read 500 pages?
### How can I read 300 pages in a week?
For example, if you have a 300 page book to read, try reading 100 pages on the first day of the week and 75 on the second day. Then you will only have to read 125 pages over the next five days. | 519 | 2,057 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.140625 | 3 | CC-MAIN-2024-22 | latest | en | 0.937583 |
https://www.ixambee.com/questions/quantitative-aptitude/data-sufficiency/23317 | 1,725,942,705,000,000,000 | text/html | crawl-data/CC-MAIN-2024-38/segments/1725700651196.36/warc/CC-MAIN-20240910025651-20240910055651-00891.warc.gz | 774,915,663 | 76,122 | ## Question
Directions(Q.71 -75) : In each of the following questions, a question and two statements I and II are given. You have to decide whether the date given in the statements are sufficient to answer the question or not.
## What is the probability of getting two white balls from a box containing only white and blue balls? Statement I : There are total 72 balls in the box. Statement II : The probability of the first ball being white is 1/12.
A If the data in statement I alone is sufficient to answer the question.
B If the data in statement II alone is sufficient to answer the question.
C If the data either in statement I alone or statement II alone are sufficient to answer the question.
D If the data given in both I and II together are not sufficient to answer the question.
E If the data in both the statements I and II together are necessary to answer the question. | 188 | 885 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.125 | 3 | CC-MAIN-2024-38 | latest | en | 0.903398 |
http://astarmaths.net/category/notes/a-level/c4/page/5/ | 1,519,125,998,000,000,000 | text/html | crawl-data/CC-MAIN-2018-09/segments/1518891812938.85/warc/CC-MAIN-20180220110011-20180220130011-00571.warc.gz | 33,504,292 | 15,296 | Archive | C4
Finding the Vector Equation of a Line Passing Through Two Given Points
The general equation of a line passing through two pointsandis given by whereandcan be in two or three dimension ieort is a parameter – the value ofdetermines a unique point on the line. Any point on the line can be found by substituting a suitable value ofThe pointsandmay be expressed in two different forms, but […]
Converting Parametric Equations to Cartesian Form
Parametric equations define a surface or a curve. If the equations define a curve in theplane, thenandare expressed as functions ofTo convert the parametric equations to a single cartesian equation that relatesandwe must eliminate the parameterfrom the two equations. For example, ifandthenandso The parametric equationbecomes the single cartesian equation Example: From the parametric equationsfind a […]
Differentiation – The Product, Quotient and Chain Rules
The three rules are given by the formulae Product Rule Quotient Rule Chain Rule For each of these rules you can complete the table u v u’ v’ Then sub into the formula Examples Differentiate u v u’ 1 v’ Differentiate u v x u’ v’ 1 Differentiate u v u’ v’ | 259 | 1,174 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.953125 | 3 | CC-MAIN-2018-09 | latest | en | 0.791597 |
https://math.stackexchange.com/questions/1386381/cover-1-2-100-with-minimum-number-of-geometric-progressions/1430404 | 1,718,533,015,000,000,000 | text/html | crawl-data/CC-MAIN-2024-26/segments/1718198861657.69/warc/CC-MAIN-20240616074847-20240616104847-00208.warc.gz | 375,299,205 | 44,404 | # Cover $\{1,2,...,100\}$ with minimum number of geometric progressions?
In another question, posted here by jordan, we are asked whether it is possible to cover the numbers $$\{1,2,\ldots,100\}$$ with $$20$$ geometric sequences of real numbers. Naturally, we would like to extend the question:
Problem: What is the minimum number $$n$$ of geometric progressions $$A_1, A_2,\ldots,A_{n}$$ of rational* numbers such that $$\{1,2,\ldots,100\} \subseteq A_1 \cup A_2\cup \ldots\cup A_{n}?$$
In the other question, 6005 obtained a lower bound of $$31 \leq n$$ with an argument about square free integers. We can also obtain an upper bound of $$43$$ as follows. Consider these $$5$$ sequences: $$[1, 2, 4, 8, 16, 32, 64]$$ and $$[6, 12, 24, 48, 96]$$ and $$[5, 10, 20, 40, 80]$$ and $$[3, 9, 27, 81]$$ and $$[7, 21, 63]$$. Together, these cover $$7 + 5 + 5 + 4 + 3 = 24$$ terms. The remaining $$76$$ terms can be covered in at most $$38$$ sequences, by an argument made here. So we have the bound:
$$31 \leq n \leq 43$$
Can anyone do better?
*We need only consider rational ratios by arguments made in answers to the original question.
(Update) We have a winner!! Thanks to the cumulative efforts of the answerers below, we have arrived at $$n = 36$$. The upper bound is thanks to jpvee, and the lower bound is due to san. Hooray!
• I think we can get a few more off the upper bound with this method e.g. $11, 33, 99$ but eventually it will run out of steam and we'll need a new idea. Commented Aug 6, 2015 at 10:48
• About the new idea: did you check this related question? math.stackexchange.com/questions/1385991/… Jack claims that, if this is true, then $n \in \{37,38\}$ Commented Aug 6, 2015 at 15:02
• I saw a conjecture along those lines alright, but was it proved? Commented Aug 6, 2015 at 15:38
• No, I don't think so: anyway, it would be better to ask Jack's opinion.. Commented Aug 6, 2015 at 15:41
• Yes I agree. Unfortunately I don't know how to tag him as he's not on this thread. Commented Aug 6, 2015 at 15:56
Switching from proving lower bounds to finding upper bounds, I played around with the list of progressions a bit and came up with another small improvement:
The $$16$$ progressions $$(1, 2, 4, 8, 16, 32, 64)\\ (3, 6, 12, 24, 48, 96)\\ (5, 10, 20, 40, 80)\\ (7, 14, 28, 56)\\ (9, 18, 36, 72)\\ (11, 22, 44, 88)\\ (13, 26, 52)\\ (15, 30, 60)\\ (17, 34, 68)\\ (19, 38, 76)\\ (21, 42, 84)\\ (23, 46, 92)\\ (25, 35, 49)\\ (27, 45, 75)\\ (50, 70, 98)\\ (81, 90, 100)$$ are completely disjoint and thus cover $$7+6+5+3\cdot4+10\cdot3=60$$ integers. Using $$20$$ additional progressions that each cover $$2$$ of the remaining $$100-60=40$$ integers yields a cover of $$16+20=36$$ geometric progressions.
• Nice. Getting closer now! Are you using a computer program to aid you with the upper bounds also? Commented Aug 9, 2015 at 15:11
• @ColmBhandal: I just used to computer to give me the list of all progressions of length $\ge3$; the rest was done on paper. Commented Aug 9, 2015 at 15:24
• A good manual new :P Commented Aug 9, 2015 at 18:57
The exact value of n is 36:
First, consider all progressions of length 4 or more:
Length 7: 1,2,4,8,16,32,64
Length 6: 3,6,12,24,48,96
Length 5: 5,10,20,40,80$\qquad \ \$ 1,3,9,27,81$\qquad \ \$ 16,24,36,54,81
Length 4: 2,6,18,54$\qquad \ \$ 27,36,48,64$\qquad \ \$ 7,14,28,56$\qquad \ \$ 9,18,36,72$\qquad \ \$ 11,22,44,88$\qquad \ \$ 8,12,18,27
These progressions cover the 33 numbers
1,2,3,4,5,6,7,8,9,10,11,12,14,16,18,20,22,24,27,28,32,36,40,44,48,54,56,64,72,80,81,88,96
Moreover, two of the length 5 geometric progressions have only 3 numbers disjoint from the progressions of length 6 and 7. Hence, the best way to cover these 33 numbers is to cover 30 of them with 6 geometric progressions:
The progressions of length 7, 6 one of 5 and 3 progressions of length 4:
Length 7: 1,2,4,8,16,32,64
Length 6: 3,6,12,24,48,96
Length 5: 5,10,20,40,80
Length 4: 7,14,28,56$\qquad \ \$ 9,18,36,72$\qquad \ \$ 11,22,44,88
There are 35 numbers which are not in a geometric progression of length three or more:
29,31,37,39,41,43,47,51,53,55,57,58,59,61,62,65,67,69, 71,73,74,77,78,79,82,83,85,86,87,89,91,93,94,95,97
So you need 6 progressions to cover 30 numbers, 18 progressions to cover 35 numbers (in fact you cover 36), and the remaining 35 numbers must be covered with at least 12 progressions of length 3 (even if you covered 36 numbers with the 18 progressions in the item before you need 12 to cover 34 numbers).
So you need at least 36 progressions. This bound is achieved in the answer of jpvee, which is therefore optimal. Since the method of counting which numbers are covered by certain progressions is also of jpvee, and my only contribution was to count how many numbers are covered by progressions of length 4 or more, the bounty should be awarded to jpvee.
• A very noble answer. The bounty goes to jpvee, but this answer is accepted as the final touch. Nice work. Commented Sep 11, 2015 at 12:33
1,2,4,8,16,32,64
3,6,12,24,48,96
5,10,20,40,80
7,14,28,56
11,22,44,88
13,26,52; 17,34,68; 19,38,76; 21,42,84; 23,46,92
9,15,25; 36,60,100; 49,63,81
27,45,75; 50,70,98
15 sequences with 56 numbers. 44 remains, so 15 + 22 = 37.
Not the only 37 solution, some replacements available (36,54,81; 49,70,100; 18,30,50, 50,60,72), so I believe computer program would find better solution quickly if it exists.
Why not 9,27,81 included? Not to spend three "squares" for a single triplet.
• Nice work. Maybe a computer program is the way to go. If I have time I'll write it. Still, it would be much more pleasing to see a clever proof! Commented Aug 7, 2015 at 12:34
• It is interesting to point out that these progressions fit the scheme of my conjecture in the other thread. We have $V(64)=6$ and a sequence of length $7$, $V(96)=5$ with a sequence of length $6$, $V(80)=4$ with a sequence of length five and so on. Commented Aug 7, 2015 at 15:28
Nice problem! Using help from the computer, I found that within the positive integers below 100, there are
66 geometric progressions of length 3,
6 geometric progressions of length 4,
3 geometric progressions of length 5,
1 geometric progression of length 6 and
1 geometric progression of length 7
(after eliminating those that are proper subsequences of longer ones).
These progressions of length 3 or longer cover a total of 65 integers $\le 100$; denote the set of these 65 integers by $\mathbb{M}$. If the $6+3+1+1=11$ progressions of lengths $\ge4$ were all disjoint (which they are not), they together would cover $6\cdot4+3\cdot5+6+7=52$ elements of $\mathbb{M}$; for the remaining ones, at least $\lceil(65-52)/3\rceil=5$ additional progressions of length 3 are necessary.
The remaining 35 integers outside of $\mathbb{M}$ can only be contained in progressions of length 2 and thus need at least $\lceil35/2\rceil=18$ of those progressions to cover them.
Therefore, a lower bound of the progressions needed to cover all positive integers up to 100 is $11+5+18=34$.
Update 2015-08-08: I just saw that my reasoning is a bit flawed; see my comment below.
• Brilliant. The bound shrinks yet again! Commented Aug 7, 2015 at 13:10
• This could lead to another question: how many distinct geometric progressions (not proper subsequences of longer ones) of lenght $k$ are there in the set $\{1, ..., n\}$? Would your code answer that in general? Commented Aug 7, 2015 at 13:14
• @ColmBhandal: Well; I'd need to modify the program a bit - I hope to find some time for that later on. Commented Aug 7, 2015 at 14:55
• I'm awfully sorry, but my reasoning is flawed: It is not a good idea to round up twice. Instead, one could use a progression of length 2 to cover the 35th element outside of $\mathbb{M}$ and the 65th element of $\mathbb{M}$, giving a total of $11+4+17+1=33$. (If, however, you take into consideration my remark that the "larger" progressions are not completely disjoint, it is easy to see that $33$ is in fact not achievable.) Commented Aug 8, 2015 at 7:28
• kudos for the rigour. Looks like your patch works OK- so we still have a lower bound of 34- right? Commented Aug 8, 2015 at 12:24
100, 60, 36. 99, 66, 44. 98, 84, 72. 96, 48, 24, 12, 6, 3. 92, 46, 23. 90, 30, 10. 88, (44,) 22, 11. 84, 42, 21. 81, 54, (36,) (24,) 16. 80, 40, 20, (10,) 5. 76, 38, 19. 75, 45, 27. 68, 34, 17. 64, 32, (16,) 8, 4, 2, 1. That's 49 numbers, with 14 progressions. So we can certainly do it with 40 sequences. Or we can keep going. 56, 28, 14, 7. 52, 26, 13. 49, 35, 25. So, 38 sequences.
EDIT: turns out this question was discussed last year on MathOverflow, and I even contributed (a little bit) to the discussion. I recommend having a look at that discussion before continuing it here.
• I wonder if there is a more elegant idea than enumeration of all sequences... Commented Aug 6, 2015 at 11:20
• Yes those are asymptotic lower bounds, but here the question is asking for a more precise answer for the concrete case of $a_{100}$. Commented Aug 6, 2015 at 11:25 | 3,087 | 9,020 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 25, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.859375 | 4 | CC-MAIN-2024-26 | latest | en | 0.933875 |
http://us.metamath.org/nfeuni/mpan2i.html | 1,643,264,039,000,000,000 | text/html | crawl-data/CC-MAIN-2022-05/segments/1642320305141.20/warc/CC-MAIN-20220127042833-20220127072833-00019.warc.gz | 68,331,883 | 2,476 | New Foundations Explorer < Previous Next > Nearby theorems Mirrors > Home > NFE Home > Th. List > mpan2i GIF version
Theorem mpan2i 658
Description: An inference based on modus ponens. (Contributed by NM, 10-Apr-1994.) (Proof shortened by Wolf Lammen, 19-Nov-2012.)
Hypotheses
Ref Expression
mpan2i.1 χ
mpan2i.2 (φ → ((ψ χ) → θ))
Assertion
Ref Expression
mpan2i (φ → (ψθ))
Proof of Theorem mpan2i
StepHypRef Expression
1 mpan2i.1 . . 3 χ
21a1i 10 . 2 (φχ)
3 mpan2i.2 . 2 (φ → ((ψ χ) → θ))
42, 3mpan2d 655 1 (φ → (ψθ))
Colors of variables: wff setvar class Syntax hints: → wi 4 ∧ wa 358 This theorem was proved from axioms: ax-1 5 ax-2 6 ax-3 7 ax-mp 8 This theorem depends on definitions: df-bi 177 df-an 360 This theorem is referenced by: (None)
Copyright terms: Public domain W3C validator | 313 | 816 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.515625 | 3 | CC-MAIN-2022-05 | latest | en | 0.478784 |
https://kristinfrey.com/how-to-convert-lbs-to-kg-in-excel.php | 1,624,630,217,000,000,000 | text/html | crawl-data/CC-MAIN-2021-25/segments/1623487630175.17/warc/CC-MAIN-20210625115905-20210625145905-00435.warc.gz | 324,010,323 | 9,292 | How to convert lbs to kg in excel
How to convert pounds to kilograms in Excel
To build a simple table to convert pounds into kilograms (and stones!) you can use the CONVERT function. In the example shown, the formula in C5, copied down, is: = CONVERT(B5,"lbm","kg") Results will update automatically when values in column B change. Use the formula =CONVERT(C5,"lbm","kg") Here you can see, the value is given using the cell reference and other two arguments are given in quotes. As you can see, 75 .
For example, you can use CONVERT to convert feet into meters, pounds into kilograms, gallons into liters, and for many other unit conversions. The prefixes shown how to choose a security camera for your home the table below can be used with metric units by prepending the abbreviation to the unit.
The binary unit prefixes below can be used with "bits" and "bytes". Skip to main content. Return value. A number in the new measurement system. Excel Usage notes. Carry-on baggage Inches to centimeters. As long as the units specified are in the same category weight, distance, temperature, etc. Convert pounds to kilograms. As long as the units BMI calculation formula. Celsius to Fahrenheit conversion. As long as the units valid options in Related videos.
How to trace formula relationships. In this video, we'll look at how to quickly find formulas and trace how they are related to one another, using the concept of precedents and dependents. How to create an Excel Table. In this video, we'll look at how to create an Excel Table from source data on a worksheet. Email HP. Thanks to your site, I was easily able to do countif's considering hidden rows.
Appreciate the help! Excel video training Quick, clean, and to the point. Learn more.
Convert stones and lbs to kg
Using the CONVERT Function The CONVERT function is the best method to convert value given in pounds to kilograms. Let’s test the above formula on the example for better understanding. Say in column B we have some weight measurements that need to be converted to kilograms. Convert between pounds to kg Select a blank cell next to your pounds data, and type this formula =CONVERT (A2,"lbm","kg") into it, and press Enter key, then drag the autofill handle down to the range cells you need. To convert kg to pounds, please use this formula =CONVERT (A2, "kg","lbm"). To convert from lbs to kg, divide by 3. You can also use the CONVERT function in Excel to convert from kg to lbs. Note: the CONVERT function has .
In this article, we will learn How to convert pounds to kilograms in Excel. Conversion of one measurement field to another measurement field can be done in excel. Conversion like Length measurements, weight measurement, volume or area measurements are some different types of conversions.
As we know,. Follow the link to learn more about conversions. Here we need to convert the weight measurement in pounds to weight measurement in Kilograms. Below is the generic formula to make you understand better. All of these might be confusing to understand. So, let's test this formula via running it on the example shown below.
For example, we have some weight measurement in pounds and need the same measurements in kilograms. Just follow the formula with correct keywords to get the result. Here you can see, the value is given using the cell reference and other two arguments are given in quotes. As you can see, 75 pounds equals Yeah, It's that easy in Excel.
Here are all the measurements in Kilograms. Now if we need to convert Kilograms to Pounds, we will be using the same formula but arguments in different order. For, more explanation see below. Here, we have a similar situation, as had earlier. Now we will break down the problem with a similar pattern.
Now we will use the below formula to calculate the Kilograms from Pounds. For this, we will convert the same values to Pounds. So as to recheck the results obtained from the. Copy the formula to the rest of the cell to check the results. As you can see the formula works fine for both sides. We can use the mathematical formula also. Here are all the observational notes regarding using the formula. Hope this article about How to convert pounds to kilograms in Excel is explanatory.
Find more articles on conversion here. If you liked our blogs, share it with your friends on Facebook. And also you can follow us on Twitter and Facebook. We would love to hear from you, do let us know how we can improve, complement or innovate our work and make it better for you. Write us at info exceltip. How to convert Inches to decimals and feets to decimal in Excel : Convert minutes to hours and minutes time measurement with basic mathematical formulation.
These 50 shortcuts will make you work even faster on Excel. You don't need to filter your data to count specific values. Countif function is essential to prepare your dashboard. This helps you sum up values on specific conditions.
Strictly Necessary Cookie should be enabled at all times so that we can save your preferences for cookie settings. If you disable this cookie, we will not be able to save your preferences.
You can adjust all of your cookie settings by navigating the tabs on the left hand side. Strictly Necessary Cookies Strictly Necessary Cookie should be enabled at all times so that we can save your preferences for cookie settings.
Enable All Save Changes.
More articles in this category:
<- How to get messy wavy beach hair - How to delete highlighted links on google->
2 thoughts on “How to convert lbs to kg in excel”
1. Kelabar:
My restore points complete. But when I have to reboot. Its like the restore never even took place. why is this.
2. Zolojas:
Haha good luck then. horrible language lmao | 1,212 | 5,736 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.34375 | 3 | CC-MAIN-2021-25 | latest | en | 0.849057 |
http://thisthread.blogspot.com/2014/12/couples-and-single.html | 1,547,961,145,000,000,000 | text/html | crawl-data/CC-MAIN-2019-04/segments/1547583700012.70/warc/CC-MAIN-20190120042010-20190120064010-00286.warc.gz | 214,211,852 | 20,425 | ## Pages
### Couples and Single
A vector of integers is given. All values are in the range [1..100,000,000] and present in couples, but one that is single. Return it.
A C++11 GoogleTest test case to clarify the problem:
```TEST(CouplesAndSingle, Simple)
{
ASSERT_EQ(42, solution({ 1, 42, 1 }));
}
```
My solution uses an hash table where I store each new value value I see in input. If I see it a second time, I remove it from the table. In the end, I should have just one element in the hash table, the single value. It is not required, however I decided to return 0 in case of unexpected input.
Here is how I have implemented it:
```int solution(const std::vector<int>& input)
{
std::unordered_set<int> buffer; // 1
for(int value : input) // 2
{
if(value < 1 || value > 100000000) // 3
return 0;
auto it = buffer.find(value); // 4
if(it == buffer.end())
buffer.insert(value);
else
buffer.erase(it);
}
return (buffer.size() != 1) ? 0 : *buffer.begin(); // 5
}
```
1. STL unordered_set implements hash table in C++11.
2. For each element in input.
3. Paranoid check.
4. If the current value is not in buffer, insert it. Otherwise remove it.
5. The single value is the first (and unique) element in buffer.
1. That solution is not suitable for large vectors. If you have enough RAM check it on the amount of data in the 1-2GB with values in the array, which first increase monotonically till the array middle, and then again increase monotonically(starting with the same value as in previous part) till the end.
Better solution is to xor all array elements - result is the required unique value [O(n) - time complexity, O(1) - space complexity].
1. XOR-ing is a smarter solution, thank you for pointing it out. I am not so happy with it just for my lack of trust in input data. It works fine assuming that we actually have a bunch of pairs and just one single element. For more singles it returns some unexpected value.
Moreover, if you pay attention to the problem definition, you should see how it refers to relatively small vectors. In the worst case the hash table would reach a size of 100 million before we start removing elements.
Maybe it was worthy to add a check on the vector size (less than 200 millions) as first line of my solution.
2. would it be faster to sort input and check if input[i]==input[i+1] in a 2-step loop ?
1. Nice try but no. Sorting can't cost you less than a O(n lg n) execution time, and that would become the dominant operation in your algorithm. Insert and lookup in a hash table are expected to be constant time operations, so my proposal runs in linear time.
3. USE XOR!!
1. Oh, come on, anonymous. Writing in all caps is considered rude, don't you know? | 674 | 2,701 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.765625 | 3 | CC-MAIN-2019-04 | latest | en | 0.739071 |
https://www.physicsforums.com/threads/centripetal-force.141000/ | 1,432,931,812,000,000,000 | text/html | crawl-data/CC-MAIN-2015-22/segments/1432207930423.94/warc/CC-MAIN-20150521113210-00166-ip-10-180-206-219.ec2.internal.warc.gz | 906,159,538 | 12,692 | # Centripetal Force
1. ### Touchme
41
A 0.50 kg ball that is tied to the end of a 1.0 m light cord is revolved in a horizontal plane with the cord making a 30° angle, with the vertical (See Fig. P7.52.)
I managed to get my answer down to solving for theta however I dont know how to do the math:
I solved for T = mg / cos(x)
The Fc is = Tsin(x) = (mg)[tan(x)]
(mg)[tan(x)] = (mv^2) / r
The following equation is where I am stumped...
sin^2(x) / cos(x) = 8 / 4.9
File size:
5.1 KB
Views:
7
2. ### rsk
147
Are you trying to find the speed?
Calculate Fc from Tsin(x) = (mg)[tan(x)]
Then calculate r, and you can find v.
I don't understand why you're stumped at that point, since you know what x is.
3. ### Touchme
41
sorry for not clarifying my question. I am trying to solve for x. The question is: If, instead, the ball is revolved so that its speed is 4.0 m/s, what angle does the cord make with the vertical?
4. ### rsk
147
OK - sorry for delay - site wouldn't let me post
sin^2(x) / cos(x) = 8 / 4.9
Gives you 4.9 sin^2 x = 8 cos^2 x
Remember sin^2 x = (1 - cos^2 x) - substitute this and you should be able to solve for cos x (might be a quadratic you have to solve)
5. ### Touchme
41
thank you so much. | 396 | 1,225 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.65625 | 4 | CC-MAIN-2015-22 | latest | en | 0.933443 |
https://discussions.unity.com/t/how-those-inputs-work-why-there-are-differences-in-movement-in-game/258505 | 1,708,652,783,000,000,000 | text/html | crawl-data/CC-MAIN-2024-10/segments/1707947473871.23/warc/CC-MAIN-20240222225655-20240223015655-00756.warc.gz | 211,300,239 | 5,463 | # How those inputs work? Why there are differences in movement in -game?
I created a game in my studies, and theres is a coop mode. PlayerOne and PlayerTwo have two different inputs methods and they behave differently. PlayerOne seems to have a delay between the time I press the key and the time to execute the command. PlayerTwo goes to the direction at instant time. Or maybe PlayerOne have an acceleration time and PlayerTwo gets the velocity instantly.
My code:
`````` void CalculateMovement()
{
if (_PlayerTwo == false)
{
float HorizontalInput = Input.GetAxis("Horizontal");
float VerticalInput = Input.GetAxis("Vertical");
Vector3 direction = new Vector3(HorizontalInput, VerticalInput, 0);
if (_speedBoostActive == false)
{
transform.Translate(direction * _speed * Time.deltaTime);
}
else
{
transform.Translate(direction * (_speed * 1.5f) * Time.deltaTime);
}
}
else
{
float _speedboost = 1.0f;
if (_speedBoostActive == true)
{
_speedboost = 1.5f;
}
{
transform.Translate(Vector3.up * _speed * _speedboost * Time.deltaTime);
}
{
transform.Translate(Vector3.down * _speed * _speedboost * Time.deltaTime);
}
{
transform.Translate(Vector3.left * _speed * _speedboost * Time.deltaTime);
}
{
transform.Translate(Vector3.right * _speed * _speedboost * Time.deltaTime);
}
}
transform.position = new Vector3(transform.position.x, Mathf.Clamp(transform.position.y, -3.9f, 0), 0);
if (transform.position.x > 9.6f)
{
transform.position = new Vector3(-9.6f, transform.position.y, 0);
}
else if (transform.position.x < -9.6f)
{
transform.position = new Vector3(9.6f, transform.position.y, 0);
}
}
`````` | 397 | 1,616 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.890625 | 3 | CC-MAIN-2024-10 | latest | en | 0.605416 |
http://mathhelpforum.com/calculus/35855-angle-between-planes.html | 1,529,475,462,000,000,000 | text/html | crawl-data/CC-MAIN-2018-26/segments/1529267863463.3/warc/CC-MAIN-20180620050428-20180620070428-00636.warc.gz | 194,184,439 | 11,175 | 1. ## angle between planes
x+2y-z=4
2x+y+z=8
calculate the angle between the planes
i got 47 degree correct
obtain the unit vector in the direction of the line of intersection of the two planes? I'm not too sure about this problem
2. Okay, so you have your two planes
1: x+2y-z=4
2: 2x+y+z=8
I assume you've figured out by now that the normal to plane 1 is going to be in the direction (1, 2, -1) and the normal to plane 2 is going to be in the direction (2, 1, 1). I guess you then used the scalar (dot) product between them to work out what the angle was.
The next bit: Unit vector in the line of intersection.
Well, the unit bit just means it has a total length of 1 so let's worry about that later. First of all, work out what direction it's in.
How do we do this? Think about your two planes. If you're having trouble visualising it, hold up some sheets of A4 to help you. Each plane has its own normal coming out of it at 90 degrees. The line of intersection is in BOTH planes, right? (fairly obviously, since it has to be in both for it to be the line of intersection)
If a line is in a plane, then it's perpendicular to the normal of that plane. If it's in both planes, then it must be perpendicular to both normals. Again, that has to be true, by definition pretty much. Think about that for a minute and convince yourself that it's right.
If you want to generate a vector perpendicular to two other vectors, how do you do it? That's right. The vector (or "cross") product.
So it'll be in direction (1, 2, -1) CROSS (2, 1, 1).
Once you know the direction, you just have to divide by the total magnitude to make sure it has length 1.
Hope this helps.
3. Originally Posted by tak
x+2y-z=4
2x+y+z=8
calculate the angle between the planes
i got 47 degree correct
obtain the unit vector in the direction of the line of intersection of the two planes? I'm not too sure about this problem
A vector in the direction of the line of intersection of two planes can be obtained by taking the cross-product of the normal vectors to the planes; so compute $\displaystyle [1,2,-1]$x$\displaystyle [2,1,1]$ and then find the magnitude of this vector and divide by the magnitude to obtain the unit vector.
Edit: Fedex beat me to it, and he has a nice explanation.
4. ## hmmm
I go sought out my thoughts
5. Originally Posted by tak
x+2y-z=4
2x+y+z=8
calculate the angle between the planes
i got 47 degree correct
obtain the unit vector in the direction of the line of intersection of the two planes? I'm not too sure about this problem
isnt it $\displaystyle arcos\bigg(\frac{n_1\cdot{n_2}}{|n_1||n_2|}\bigg)$
6. ## i have a question
why do we need the dot product to write the vector equation
7. I think Mathstud was reminding you how to calculate the angle between the two planes.
If you call the normal to plane 1 n1 and the normal to plane 2 n2, then
n1 DOT n2 = |n1||n2|cos(theta)
Rearranging that will give you the angle between the normals as Mathstud showed. The angle between the normals must be the angle between the planes too (if you think about that by holding up pieces of paper and stuff, you'll see that that's true).
I don't know if your answer is right, by the way. I can't work out inverse cosines in my head :-D I'll let you check it. | 872 | 3,275 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 4.375 | 4 | CC-MAIN-2018-26 | latest | en | 0.962407 |
https://studydaddy.com/question/you-have-just-applied-and-have-been-approved-for-a-58-000-mortgage-the-rate-quot | 1,568,893,005,000,000,000 | text/html | crawl-data/CC-MAIN-2019-39/segments/1568514573476.67/warc/CC-MAIN-20190919101533-20190919123533-00534.warc.gz | 668,592,824 | 8,280 | Waiting for answer This question has not been answered yet. You can hire a professional tutor to get the answer.
QUESTION
# You have just applied, and have been approved for a \$58,000 mortgage. The rate quoted to you by the lender is 6.1% for a 30 year fixed mortgage. Determine how much of your third month’s payment goes
You have just applied, and have been approved for a \$58,000 mortgage. The rate quoted to you by the lender is 6.1% for a 30 year fixed mortgage. Determine how much of your third month’s payment goes towards the principal. a. \$56.65 c. \$57.22 b. \$56.93 d. \$57.51 | 153 | 593 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.59375 | 3 | CC-MAIN-2019-39 | latest | en | 0.963503 |
http://mathhelpforum.com/discrete-math/206866-big-oh-notation.html | 1,527,474,790,000,000,000 | text/html | crawl-data/CC-MAIN-2018-22/segments/1526794870604.65/warc/CC-MAIN-20180528004814-20180528024814-00501.warc.gz | 182,808,036 | 11,591 | 1. ## Big oh notation
Hi everyone!
I just want to say before my question that I love this forum so so much, I have gotten a lot of help, and you people deserve a noble price for being so smart and helpful and nice.
For my question, I have another question about big-oh-notation, I am finally starting to understand the concept of it better, but I still struggle with some fundamental problems.
So, the problem is:
Show that (x2 + 1) / (x + 1) is O(x)
My book really has no good explanation on how to think when trying to find a constant C and k for which this is true. I thought maybe someone here would know a fancy way to do it?
2. ## Re: Big oh notation
Originally Posted by Nora314
Hi everyone!
I just want to say before my question that I love this forum so so much, I have gotten a lot of help, and you people deserve a noble price for being so smart and helpful and nice.
For my question, I have another question about big-oh-notation, I am finally starting to understand the concept of it better, but I still struggle with some fundamental problems.
So, the problem is:
Show that (x2 + 1) / (x + 1) is O(x)
My book really has no good explanation on how to think when trying to find a constant C and k for which this is true. I thought maybe someone here would know a fancy way to do it?
\displaystyle \displaystyle \begin{align*} \frac{x^2 + 1}{x + 1} &= \frac{x^2 + x - x + 1}{x + 1} \\ &= \frac{x^2 + x}{x + 1} + \frac{-x + 1}{x + 1} \\ &= \frac{x(x + 1)}{x + 1} + \frac{-x - 1 + 2}{x + 1} \\ &= x + \frac{-x - 1}{x + 1} + \frac{2}{x + 1} \\ &= x + \frac{-(x + 1)}{x + 1} + \frac{2}{x + 1} \\ &= x - 1 + \frac{2}{x + 1}\end{align*}
Now to show \displaystyle \displaystyle \begin{align*} \frac{x^2 + 1}{x + 1} \in O(x) \end{align*}, we need to show that \displaystyle \displaystyle \begin{align*} \left| \frac{x^2 + 1}{x + 1} \right| \leq M|x| \end{align*} for some \displaystyle \displaystyle \begin{align*} M \in \mathbf{R} \end{align*}.
\displaystyle \displaystyle \begin{align*} \left| \frac{x^2 + 1}{x + 1} \right| &= \left| x - 1 + \frac{2}{x + 1} \right| \\ &\leq |x| + |-1| + \left| \frac{2}{x + 1} \right| \\ &= |x| + |1| + \frac{|2|}{|x + 1|} \\ &< |x| + |x| + 2|x| \textrm{ for large positive values of }x \\ &= 4|x| \end{align*}
Since \displaystyle \displaystyle \begin{align*} \left| \frac{x^2 + 1}{x + 1} \right| \leq 4|x| \end{align*}, we can say \displaystyle \displaystyle \begin{align*} \left| \frac{x^2 + 1}{x + 1} \right| \in O(x) \end{align*}.
3. ## Re: Big oh notation
Thank you so so much for the wonderful explanation! I went through it, and I believe I understand how to solve this exercise now. I just have a few questions, if you don't mind, which I think will help me clear things up completely.
What you do in the first part of the exercise, where you turn x2 + 1 / x + 1 into x - 1 + 2/x + 1, is it that you try to write the original expression in terms of x and not x2, because we are trying to see if it is O(x)?
Also, when you write the whole new expression in terms for the largest positive value of x, and it becomes : 4|x|, why do you turn |2| / |x + 1| into 2|x| and not just |x|?
4. ## Re: Big oh notation
Also, if you don't mind, could you help me with another question?
The question is:
Give a big-O estimate for n(log(n2 + 1)) + n2 log n
I thought a good estimate would be n2 since this is the biggest power of n , and this function changes faster than log n, but the answer in the answer key is: "O(n2 log n),
I don't understand why the answer is not just n2, why is it necessary to add log n when n2 will always change the fastest?
5. ## Re: Big oh notation
Originally Posted by Nora314
Give a big-O estimate for n(log(n2 + 1)) + n2 log n
I thought a good estimate would be n2 since this is the biggest power of n , and this function changes faster than log n, but the answer in the answer key is: "O(n2 log n),
I don't understand why the answer is not just n2, why is it necessary to add log n when n2 will always change the fastest?
n2 surely changes faster than log n, but the problem is that log n is unbounded from above. You cannot say that n2log n <= Cn2 for all n from some point on regardless of how large the constant C is because eventually log n exceeds C.
6. ## Re: Big oh notation
Originally Posted by Nora314
Thank you so so much for the wonderful explanation! I went through it, and I believe I understand how to solve this exercise now. I just have a few questions, if you don't mind, which I think will help me clear things up completely.
What you do in the first part of the exercise, where you turn x2 + 1 / x + 1 into x - 1 + 2/x + 1, is it that you try to write the original expression in terms of x and not x2, because we are trying to see if it is O(x)?
Also, when you write the whole new expression in terms for the largest positive value of x, and it becomes : 4|x|, why do you turn |2| / |x + 1| into 2|x| and not just |x|?
Yes, you are trying to get the highest power of your quotient. You could use long division instead if you liked.
You could use |x| if you wanted to. | 1,550 | 5,084 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 4.0625 | 4 | CC-MAIN-2018-22 | latest | en | 0.893545 |
http://demonstrations.wolfram.com/FlightProfilesOfEstesAlphaModelRocket/ | 1,547,874,429,000,000,000 | text/html | crawl-data/CC-MAIN-2019-04/segments/1547583662124.0/warc/CC-MAIN-20190119034320-20190119060320-00086.warc.gz | 59,317,991 | 6,512 | Flight Profiles of Estes Alpha Model Rocket
Requires a Wolfram Notebook System
Interact on desktop, mobile and cloud with the free Wolfram CDF Player or other Wolfram Language products.
Requires a Wolfram Notebook System
Edit on desktop, mobile and cloud with any Wolfram Language product.
This Demonstration simulates the flight of an Estes Alpha model rocket. The effect of air resistance is taken into account. The altitude and velocity at any time during the flight can be shown using a slider. The time window can be adjusted to focus, for example, on the early moments of the flight. The effect of air resistance is clearly seen in the velocity and altitude graphs. Three different rocket engines can be selected to illustrate the effect of changes in average thrust and thrust duration. The drag coefficient may be adjusted so that its effect may be seen. The time to parachute ejection is calculated and velocity and altitude at this time are plotted.
Contributed by: Richard L. Kahler (November 2014)
Open content licensed under CC BY-NC-SA
Details
The flight profile is calculated using NDSolve to compute the velocity as a function of time. Newton's second law gives a differential equation for the velocity, . The equation is complicated by several factors: the thrust and the mass change as the propellant is burned, and the air resistance is a function of the velocity. The thrust is approximated using a constant average thrust during the boost phase. Values for the total impulse and thrust duration are obtained from NAR certified engine data, August, 1996. The average thrust is the impulse divided by the thrust duration. The mass is approximated using a constant average mass computed using the mass of the rocket, .039 kg for a typical Alpha model, plus one half the mass of the propellant, again from the Estes data. The drag is calculated using the equation , where is the drag coefficient, approximated as 0.6 for the Alpha model rocket; is the density of air, 1.2 kg/ at 20 °C and 101kPa; is the cross section area of the Alpha rocket calculated as a circle of radius 0.012 m; and is the velocity of the rocket. With these simplifications, NDSolve easily computes a numerical solution for . The height is obtained by numerically integrating the velocity solution. The velocity and height are plotted as a function of time from liftoff.
Reference
[1] Estes Rockets. "001225-Alpha®." (Nov 18, 2014) www.estesrockets.com/rockets/kits/skill-1/001225-alphar.
Permanent Citation
Richard L. Kahler
Feedback (field required) Email (field required) Name Occupation Organization Note: Your message & contact information may be shared with the author of any specific Demonstration for which you give feedback. Send | 595 | 2,742 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.8125 | 3 | CC-MAIN-2019-04 | longest | en | 0.90861 |
https://www.physicsforums.com/threads/variational-method-particle-in-box-approx.537493/ | 1,519,560,641,000,000,000 | text/html | crawl-data/CC-MAIN-2018-09/segments/1518891816370.72/warc/CC-MAIN-20180225110552-20180225130552-00438.warc.gz | 898,794,498 | 17,787 | # Variational method particle in box approx.
1. Oct 6, 2011
### josecuervo
1. The problem statement, all variables and given/known data
use the variational method to approximate the ground state energy of the particle in a one-dimentional box using the normalized trial wavefunction ∅(x)=Nx$^{k}$(a-x)$^{k}$ where k is the parameter. Demonstrate why we choose the positive number rather than the negative value. By what absolute percentage does your value differ from the true one, (.125h$^{2}$/m$_{e}$a^2? It is also stated that
$\oint$psi*Hpsi dx=($\bar{h}$/m$_{e}$a$^{2}$)(4k$^{2}$+k)/(2k-1).
2. Relevant equations
I'm pretty sure you have to use this one $\oint$psi*Hpsi dx/$\oint$psi*psi dx
3. The attempt at a solution
The first thing I tried to do is normalize the trial wavefunction which didn't get very far as I couldn't figure out how to do the integral. I also can't figure out to get either of the integrals to work because of the k powers. That is the main thing I'm blocked on. The only other thing I can think of is just to take an approximation of just the first two k values but the given integral with the incorporated hamiltonian has k included so it's wanting me to approx over all k. I need help getting to the next step. Thanks!
2. Oct 7, 2011
### vela
Staff Emeritus
The integral you've been given was evaluated using the normalized wave function, so I don't think you're expected to manually crank out the integrals.
In case you're curious, this is what Mathematica found:
$$\int \phi^*(x)\phi(x)\,dx = N^2\frac{\sqrt{\pi}a^{4k+1}k\,\Gamma(2k)}{16^k\, \Gamma(2k+3/2)}$$
Last edited: Oct 7, 2011
3. Oct 9, 2011
### josecuervo
Could I assume that the integral on bottom is already normalized? what could I do then? could I just solve for k values?
4. Oct 9, 2011
### vela
Staff Emeritus
Yes, you just need to find the value of k now.
5. Oct 9, 2011
### josecuervo
would I take the derivative dE/dk and then solve for k?
6. Oct 9, 2011
### vela
Staff Emeritus
Yes. That variational method will always overestimate the energy, so by finding the value of k that minimizes the estimate, you know you're getting the best approximation.
7. Oct 9, 2011
### josecuervo
I'm having problems deriving and solving for k. When I take the derivative, I get
dE/dk=([STRIKE]h[/STRIKE]/(m$_{e}$a$^{2}$)(8k$^{2}$-8k-1)/(1-2k)$^{2}$=0
and I'm having problems solving for it. am I doing something wrong?
8. Oct 9, 2011
### vela
Staff Emeritus
Looks good so far. Where are you getting stuck?
9. Oct 9, 2011
### josecuervo
the derivative doesn't seem to be solveable because there's no way to move anything over to the other side. and I know that I'll get multiple values of k when I solve.
10. Oct 9, 2011
### vela
Staff Emeritus
Remember a fraction is only equal to 0 only if the numerator is 0. That's probably exactly what you're getting, but you're mistakenly thinking it's not working out.
11. Oct 9, 2011
### josecuervo
Okay, but if the value of k is 0, then that doesn't go with the problem. In the problem it states that there will be a positive and negative value for the parameter and it asks why the positive number is better. And if k is 0 then the approximation won't work when you plug back into E$_{min}$
12. Oct 9, 2011
### vela
Staff Emeritus
I didn't say k=0. I said the numerator had to be 0. What values of k cause the numerator to vanish?
13. Oct 9, 2011
### josecuervo
ok. sorry, dumb moment.
so I solved for k=-.11237 and k=1.11237.
then I plugged the positive k value into E and got 3.133([STRIKE]h[/STRIKE]$^{2}$/m$_{e}$a$^{2}$) or 19.68(h$^{2}$/m$_{e}$a$^{2}$) which isn't even in the ballpark of the true value.
14. Oct 9, 2011
### josecuervo
and I tried the negative number and it's even worse. Did I do something wrong?
15. Oct 9, 2011
### josecuervo
is there anyway you could work through the problem and double check my work? I've worked through it twice now and still haven't gotten an answer that looks right
16. Oct 9, 2011
### vela
Staff Emeritus
Your values for k are correct, but your energies aren't. For the positive value of k, I get
$$E = \frac{4.9495 \hbar^2}{a^2 m}$$while the actual ground state energy is$$E_0 = \frac{4.9348 \hbar^2}{a^2 m}$$That looks pretty good actually.
17. Oct 9, 2011
### josecuervo
how did you get that? it was given in the problem that the true initial value is
0.125h$^{2}$/m$_{e}$a$^{2}$
or .0199[STRIKE]h[/STRIKE]$^{2}$/m$_{e}$a$^{2}$
did you plug the k value into E$_{min}$=([STRIKE]h[/STRIKE]$^{2}$/m$_{e}$a$^{2}$)(4k$^{2}$+k)/(2k-1)
18. Oct 9, 2011
### vela
Staff Emeritus
I used$$E=\frac{\hbar^2\pi^2}{2ma^2} = \left(\frac{\pi^2}{2}\right)\frac{\hbar^2}{ma^2} \cong 4.9348 \frac{\hbar^2}{ma^2}$$
I think you just converted to $\hbar$ incorrectly. You should have $h=2\pi\hbar$, so
$$E_n = \frac{n^2h^2}{8ma^2} = \frac{n^2(2\pi)^2\hbar^2}{8ma^2} = \frac{n^2\pi^2\hbar^2}{2ma^2}$$ | 1,594 | 4,923 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 1, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.703125 | 4 | CC-MAIN-2018-09 | longest | en | 0.915969 |
https://math.answers.com/questions/How_many_tens_are_in_the_number_30000 | 1,642,668,136,000,000,000 | text/html | crawl-data/CC-MAIN-2022-05/segments/1642320301730.31/warc/CC-MAIN-20220120065949-20220120095949-00563.warc.gz | 423,333,339 | 74,962 | 0
How many tens are in the number 30000?
Wiki User
2012-06-21 04:15:02
3,ooo
Wiki User
2012-06-21 04:15:02
🙏
0
🤨
0
😮
0
Anonymous
Lvl 1
2020-10-01 17:55:48
ask that question like even a kindergardenerknows rhat
Anonymous
Lvl 1
2020-10-01 17:56:18
klss my ######
Lucy Formby
Lvl 1
2021-10-04 21:52:02
Tricky but easy
Study guides
20 cards
A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials
➡️
See all cards
3.72
335 Reviews
Armeen Kaur Armeen K...
Lvl 3
2020-11-18 00:19:18
This is a difficult question but you can search is on Google
Armeen Kaur Armeen K...
Lvl 3
2020-11-18 00:19:53
The digit 4 is in the ten thousands place. Its value is 4 ten thousands, or 40,000. The digit 7 is in the tens place. Its value is 7 tens, or 70.
bluebacon123
Lvl 4
2021-06-05 10:22:10
3000
Lenora Corkery
Lvl 1
2021-06-07 04:05:48
bluebacon123
Lvl 1
2021-06-07 09:43:28
i found this answer by dividing the number given by 10.
Vinny Catalano
Lvl 6
2021-10-13 14:42:53
3000
Dilani Ranga
Lvl 2
2020-10-30 00:19:24
30000
Anonymous
Lvl 1
2020-10-01 16:01:09
3,000x10=30,000
Anonymous
Lvl 1
2020-07-14 17:58:43
0
Anonymous
Lvl 1
2020-10-01 17:27:15
None. Nowhere in the number's digits are a 1 and 0 together. | 546 | 1,286 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.203125 | 3 | CC-MAIN-2022-05 | latest | en | 0.763405 |
https://us.metamath.org/ileuni/simp11l.html | 1,685,635,407,000,000,000 | text/html | crawl-data/CC-MAIN-2023-23/segments/1685224647895.20/warc/CC-MAIN-20230601143134-20230601173134-00251.warc.gz | 642,107,432 | 2,921 | Intuitionistic Logic Explorer < Previous Next > Nearby theorems Mirrors > Home > ILE Home > Th. List > simp11l GIF version
Theorem simp11l 1057
Description: Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
Assertion
Ref Expression
simp11l ((((𝜑𝜓) ∧ 𝜒𝜃) ∧ 𝜏𝜂) → 𝜑)
Proof of Theorem simp11l
StepHypRef Expression
1 simp1l 970 . 2 (((𝜑𝜓) ∧ 𝜒𝜃) → 𝜑)
213ad2ant1 967 1 ((((𝜑𝜓) ∧ 𝜒𝜃) ∧ 𝜏𝜂) → 𝜑)
Colors of variables: wff set class Syntax hints: → wi 4 ∧ wa 103 ∧ w3a 927 This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 105 ax-ia2 106 ax-ia3 107 This theorem depends on definitions: df-bi 116 df-3an 929 This theorem is referenced by: (None)
Copyright terms: Public domain W3C validator | 314 | 739 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.6875 | 3 | CC-MAIN-2023-23 | longest | en | 0.382001 |
https://inst.eecs.berkeley.edu/~cs61a/sp23/lab/lab03/ | 1,702,329,245,000,000,000 | text/html | crawl-data/CC-MAIN-2023-50/segments/1700679518883.99/warc/CC-MAIN-20231211210408-20231212000408-00353.warc.gz | 346,145,448 | 8,271 | # Lab 3: Midterm Review lab03.zip
Due by 11:59pm on Monday, February 6.
## Starter Files
Download lab03.zip. Inside the archive, you will find starter files for the questions in this lab, along with a copy of the Ok autograder.
## Submit
In order to facilitate studying for the exam, solutions to this lab are released with the lab. We encourage you to try out the problems first on your own before referencing the solutions as a guide.
Note: You do not need to submit to Gradescope to receive credit for this assignment.
# All Questions Are Optional
The questions in this assignment are not graded, but they are highly recommended to help you prepare for the upcoming exam. You will receive credit for this lab even if you do not complete these questions.
# Suggested Questions
## Walkthrough Videos
These videos provide detailed walkthroughs of the problems presented in this lab.
To see these videos, you should be logged into your berkeley.edu email.
## Control
### Q1: Ordered Digits
Implement the function `ordered_digits`, which takes as input a positive integer and returns `True` if its digits, read left to right, are in non-decreasing order, and `False` otherwise. For example, the digits of 5, 11, 127, 1357 are ordered, but not those of 21 or 1375.
``````def ordered_digits(x):
"""Return True if the (base 10) digits of X>0 are in non-decreasing
order, and False otherwise.
>>> ordered_digits(5)
True
>>> ordered_digits(11)
True
>>> ordered_digits(127)
True
>>> ordered_digits(1357)
True
>>> ordered_digits(21)
False
>>> result = ordered_digits(1375) # Return, don't print
>>> result
False
"""
"*** YOUR CODE HERE ***"
``````
Use Ok to test your code:
``python3 ok -q ordered_digits``
### Q2: K Runner
An increasing run of an integer is a sequence of consecutive digits in which each digit is larger than the last. For example, the number 123444345 has four increasing runs: 1234, 4, 4 and 345. Each run can be indexed from the end of the number, starting with index 0. In the example, the 0th run is 345, the first run is 4, the second run is 4 and the third run is 1234.
Implement `get_k_run_starter`, which takes in integers `n` and `k` and returns the 0th digit of the `k`th increasing run within `n`. The 0th digit is the leftmost number in the run. You may assume that there are at least `k+1` increasing runs in `n`.
``````def get_k_run_starter(n, k):
"""Returns the 0th digit of the kth increasing run within n.
>>> get_k_run_starter(123444345, 0) # example from description
3
>>> get_k_run_starter(123444345, 1)
4
>>> get_k_run_starter(123444345, 2)
4
>>> get_k_run_starter(123444345, 3)
1
>>> get_k_run_starter(123412341234, 1)
1
>>> get_k_run_starter(1234234534564567, 0)
4
>>> get_k_run_starter(1234234534564567, 1)
3
>>> get_k_run_starter(1234234534564567, 2)
2
"""
i = 0
final = None
while ____________________________:
while ____________________________:
____________________________
final = ____________________________
i = ____________________________
n = ____________________________
return final``````
Use Ok to test your code:
``python3 ok -q get_k_run_starter``
## Higher Order Functions
These are some utility function definitions you may see being used as part of the doctests for the following problems.
``````from operator import add, mul
square = lambda x: x * x
identity = lambda x: x
triple = lambda x: 3 * x
increment = lambda x: x + 1``````
### Q3: Make Repeater
Implement the function `make_repeater` so that `make_repeater(func, n)(x)` returns `func(func(...func(x)...))`, where `func` is applied `n` times. That is, `make_repeater(func, n)` returns another function that can then be applied to another argument. For example, `make_repeater(square, 3)(42)` evaluates to `square(square(square(42)))`.
``````def make_repeater(func, n):
"""Return the function that computes the nth application of func.
>>> add_three = make_repeater(increment, 3)
8
>>> make_repeater(triple, 5)(1) # 3 * 3 * 3 * 3 * 3 * 1
243
>>> make_repeater(square, 2)(5) # square(square(5))
625
>>> make_repeater(square, 4)(5) # square(square(square(square(5))))
152587890625
>>> make_repeater(square, 0)(5) # Yes, it makes sense to apply the function zero times!
5
"""
"*** YOUR CODE HERE ***"
def composer(func1, func2):
"""Return a function f, such that f(x) = func1(func2(x))."""
def f(x):
return func1(func2(x))
return f``````
Use Ok to test your code:
``python3 ok -q make_repeater``
### Q4: Apply Twice
Using `make_repeater` define a function `apply_twice` that takes a function of one argument as an argument and returns a function that applies the original function twice. For example, if `inc` is a function that returns `1` more than its argument, then `apply_twice(inc)` should be a function that returns two more:
``````def apply_twice(func):
""" Return a function that applies func twice.
func -- a function that takes one argument
>>> apply_twice(square)(2)
16
"""
"*** YOUR CODE HERE ***"
``````
Use Ok to test your code:
``python3 ok -q apply_twice``
### Q5: It's Always a Good Prime
Implement `div_by_primes_under`, which takes in an integer `n` and returns an n-divisibility checker. An n-divisibility-checker is a function that takes in an integer k and returns whether `k` is divisible by any integers between 2 and `n`, inclusive. Equivalently, it returns whether `k` is divisible by any primes less than or equal to `n`.
Review the Disc 01 `is_prime` problem for a reminder about prime numbers.
You can also choose to do the no lambda version, which is the same problem, just with defining functions with def instead of lambda.
Hint: If struggling, here is a partially filled out line for after the `if` statement:
``checker = (lambda f, i: lambda x: __________)(checker, i)``
``````def div_by_primes_under(n):
"""
>>> div_by_primes_under(10)(11)
False
>>> div_by_primes_under(10)(121)
False
>>> div_by_primes_under(10)(12)
True
>>> div_by_primes_under(5)(1)
False
"""
checker = lambda x: False
i = ____________________________
while ____________________________:
if not checker(i):
checker = ____________________________
i = ____________________________
return ____________________________
def div_by_primes_under_no_lambda(n):
"""
>>> div_by_primes_under_no_lambda(10)(11)
False
>>> div_by_primes_under_no_lambda(10)(121)
False
>>> div_by_primes_under_no_lambda(10)(12)
True
>>> div_by_primes_under_no_lambda(5)(1)
False
"""
def checker(x):
return False
i = ____________________________
while ____________________________:
if not checker(i):
def outer(____________________________):
def inner(____________________________):
return ____________________________
return ____________________________
checker = ____________________________
i = ____________________________
return ____________________________
``````
Use Ok to test your code:
``````python3 ok -q div_by_primes_under
python3 ok -q div_by_primes_under_no_lambda``````
## Environment Diagrams
### Q6: Doge
Draw the environment diagram for the following code.
``````wow = 6
def much(wow):
if much == wow:
such = lambda wow: 5
def wow():
return such
return wow
such = lambda wow: 4
return wow()
wow = much(much(much))(wow)``````
You can check out what happens when you run the code block using Python Tutor. Please ignore the “ambiguous parent frame” message on step 18. The parent is in fact f1.
### Q7: YY Diagram
Draw the environment diagram that results from executing the code below.
Tip: Using the `+` operator with two strings results in the second string being appended to the first. For example `"C"` + `"S"` concatenates the two strings into one string `"CS"`.
``````y = "y"
h = y
def y(y):
h = "h"
if y == h:
return y + "i"
y = lambda y: y(h)
return lambda h: y(h)
y = y(y)(y)``````
You can check out what happens when you run the code block using Python Tutor.
### Q8: Environment Diagrams - Challenge
These questions were originally developed by Albert Wu and are included here for extra practice. We recommend checking your work in PythonTutor after filling in the diagrams for the code below.
#### Challenge 1
Draw the environment diagram that results from executing the code below.
Guiding Notes: Pay special attention to the names of the frames!
Multiple assignments in a single line: We will first evaluate the expressions on the right of the assignment, and then assign those values to the expressions on the left of the assignment. For example, if we had `x, y = a, b`, the process of evaluating this would be to first evaluate `a` and `b`, and then assign the value of `a` to `x`, and the value of `b` to `y`.
``````def funny(joke):
hoax = joke + 1
return funny(hoax)
hoax = joke - 1
return hoax + hoax
#### Challenge 2
Draw the environment diagram that results from executing the code below.
``````def double(x):
return double(x + x)
first = double
def double(y):
return y + y
result = first(10)`````` | 2,322 | 8,898 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.953125 | 4 | CC-MAIN-2023-50 | latest | en | 0.840196 |
https://www.mathworks.com/matlabcentral/answers/16815-plotting-a-function-over-an-interval | 1,618,619,250,000,000,000 | text/html | crawl-data/CC-MAIN-2021-17/segments/1618038092961.47/warc/CC-MAIN-20210416221552-20210417011552-00183.warc.gz | 1,009,059,929 | 25,077 | # Plotting a function over an interval
1,363 views (last 30 days)
Kevin on 27 Sep 2011
Answered: Kris Hoffman on 29 Nov 2020
Hi,
I'm dealing with defining a function and then plotting it. The function is y1= arctan(exp(x)*(x-1))+ pi/2 which I need to plot it over interval x=0:0.1:2 , but every time I get an error. What do I need to do?
I did this:
x = 0:.01:2;
y1= arctan(exp(x)*(x-1))+ pi/2
plot(x,y1)
Also, if I want to have several functions plotted in a same window but with different colors, what should I do?
the cyclist on 27 Sep 2011
You need to use ".*" instead of "*" to multiply each element of the vector, and also the inverse tangent function in MATLAB is atan() not arctan():
>> y1= atan(exp(x).*(x-1))+ pi/2
Fangjun Jiang on 27 Sep 2011
You mean this?
x = 0:.01:2;
y1= atan(exp(x).*(x-1))+ pi/2;
plot(x,y1);
help plot for details.
plot(x1,y1,'r',x2,y2,'g',x3,y3,'b')
Kris Hoffman on 29 Nov 2020
y1 = @(x) atan(exp(x).*(x-1))+ pi/2
fplot(y1,[0,2]) | 340 | 967 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.078125 | 3 | CC-MAIN-2021-17 | latest | en | 0.817832 |
https://www.physicsforums.com/threads/car-velocity-question.289247/ | 1,603,769,581,000,000,000 | text/html | crawl-data/CC-MAIN-2020-45/segments/1603107893011.54/warc/CC-MAIN-20201027023251-20201027053251-00652.warc.gz | 816,297,447 | 14,257 | # Car velocity question.
Hello PF, I need help with a physics question.
A curve of radius 61 is banked for a design speed of 89 .
If the coefficient of static friction is 0.32 (wet pavement), at what range of speeds can a car safely make the curve? [Hint: Consider the direction of the friction force when the car goes too slow or too fast.]
A curve of radius 61 is banked for a design speed of 89 .
How would you find its range? I guess we could find a velocity, but it wouldnt be the the final velocity or the initial velocity?
## Answers and Replies
Related Introductory Physics Homework Help News on Phys.org
LowlyPion
Homework Helper
First start by drawing a force diagram of the car on the incline.
You have gravity acting down along the vertical.
You have centrifugal force acting outwardly and horizontal.
You need to resolve these forces into their components relative to the incline, perpendicular and parallel.
Then you have friction acting to retard up the incline motion when it is over 89 and down the incline motion when it is slower. | 237 | 1,059 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.34375 | 3 | CC-MAIN-2020-45 | latest | en | 0.924711 |
http://de.metamath.org/mpegif/cbvabv.html | 1,603,184,883,000,000,000 | text/html | crawl-data/CC-MAIN-2020-45/segments/1603107871231.19/warc/CC-MAIN-20201020080044-20201020110044-00062.warc.gz | 29,310,807 | 4,199 | Metamath Proof Explorer < Previous Next > Nearby theorems Mirrors > Home > MPE Home > Th. List > cbvabv Structured version Unicode version
Theorem cbvabv 2565
Description: Rule used to change bound variables, using implicit substitution. (Contributed by NM, 26-May-1999.)
Hypothesis
Ref Expression
cbvabv.1
Assertion
Ref Expression
cbvabv
Distinct variable groups: , ,
Allowed substitution hints: () ()
Proof of Theorem cbvabv
StepHypRef Expression
1 nfv 1751 . 2
2 nfv 1751 . 2
3 cbvabv.1 . 2
41, 2, 3cbvab 2563 1
Colors of variables: wff setvar class Syntax hints: wi 4 wb 187 wceq 1437 cab 2407 This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1665 ax-4 1678 ax-5 1748 ax-6 1794 ax-7 1839 ax-10 1887 ax-11 1892 ax-12 1905 ax-13 2053 ax-ext 2400 This theorem depends on definitions: df-bi 188 df-or 371 df-an 372 df-ex 1660 df-nf 1664 df-sb 1787 df-clab 2408 df-cleq 2414 This theorem is referenced by: cdeqab1 3291 difjust 3438 unjust 3440 injust 3442 uniiunlem 3549 dfif3 3923 pwjust 3980 snjust 3995 intab 4283 intabs 4581 iotajust 5560 wfrlem1 7039 sbth 7694 cardprc 8415 iunfictbso 8545 aceq3lem 8551 isf33lem 8796 axdc3 8884 axdclem 8949 axdc 8951 genpv 9424 ltexpri 9468 recexpr 9476 supsr 9536 hashf1lem2 12616 cvbtrcl 13042 mertens 13927 4sq 14899 nbgraf1olem5 25156 dispcmp 28679 eulerpart 29208 ballotlemfmpn 29320 bnj66 29664 bnj1234 29815 subfacp1lem6 29901 subfacp1 29902 dfon2lem3 30423 dfon2lem7 30427 frrlem1 30506 f1omptsn 31677 ismblfin 31892 glbconxN 32859 eldioph3 35524 diophrex 35534 ssfiunibd 37366 isuhgr 38806 isushgr 38807 isumgr 38829 isuhgrALTV 38864 isushgrALTV 38865
Copyright terms: Public domain W3C validator | 889 | 1,822 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.21875 | 3 | CC-MAIN-2020-45 | latest | en | 0.107294 |
http://www.ck12.org/trigonometry/Herons-Formula/flashcard/user:13IntK/Herons-Formula-for-the-Area-of-a-Triangle-and-Problem-Solving-with-Trigonometry/r1/ | 1,484,741,664,000,000,000 | text/html | crawl-data/CC-MAIN-2017-04/segments/1484560280280.6/warc/CC-MAIN-20170116095120-00106-ip-10-171-10-70.ec2.internal.warc.gz | 395,827,242 | 25,281 | <img src="https://d5nxst8fruw4z.cloudfront.net/atrk.gif?account=iA1Pi1a8Dy00ym" style="display:none" height="1" width="1" alt="" />
# Heron's Formula
## Area formula based on lengths of sides of a triangle and half its perimeter.
Estimated14 minsto complete
%
Progress
Practice Heron's Formula
MEMORY METER
This indicates how strong in your memory this concept is
Progress
Estimated14 minsto complete
%
Heron's Formula for the Area of a Triangle and Problem Solving with Trigonometry
Use these to study Algebra II with Trigonometry Concepts.
### Explore More
Sign in to explore more, including practice questions and solutions for Heron's Formula. | 164 | 654 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.90625 | 3 | CC-MAIN-2017-04 | latest | en | 0.739008 |
http://ronjeffries.com/articles/018-01ff/iter-incr/ | 1,548,080,775,000,000,000 | text/html | crawl-data/CC-MAIN-2019-04/segments/1547583792784.64/warc/CC-MAIN-20190121131658-20190121153658-00456.warc.gz | 185,467,875 | 5,322 | I might be writing a book called “Software Development, How I’d do it”. If so, this article might be part of it.
One way or another, something on Twitter suggested to me that I should write this little segment on the notions of iterative and incremental software development. Unable to resist, I did.
Software development approaches like Extreme Programming and Scrum can be said to be both iterative and incremental.
An iterative process is one that repeats a series of operations cyclically, with the intention of coming closer and closer to some desired result. In mathematics, for example, the Newton-Raphson method is used to approximate the solutions to algebraic equations. Often a direct solution of an equation is difficult to obtain: sometimes there is no known way to so. But it is often possible to approximate a solution, essentially by trying a value, and then repeatedly using that value to get a more accurate solution. If the calculation of the new approximation is easier than finding a direct solution, iteration is worthwhile.
By analogy, approaches like XP and Scrum repeat a simple cycle of activities, producing a new increment of product in each cycle. Usually the cycle is performed in a fixed time-box, but time-boxing is not necessary to the iterative concept. However, both XP and Scrum do use a fixed time-box per iteration, while approaches focusing on more continuous flow, such as Kanban, may perform a consistent cycle of steps, but in the “time required” rather than a fixed time-box.
Xp refers to the cycle’s time period as an “Iteration”, while Scrum calls it a “Sprint”. The cycles themselves are similar. In a time-box of a week or two, the team plans what they’ll accomplish in the time period. They do the work, then review it and consider how to improve the work, and the way they work, next time around. Each iteration of the cycle is therefore similar to the preceding one, but not identical. The specific work changes, of course, but we also improve how we approach the work.
And each iteration is expected to produce an “Increment”, working, tested, usable software that meets more of the goals of the product than last time.
An incremental approach to producing something can be seen as producing more and more of it each time. This is in a bit of contrast to the notion of an iterative approach, which is best viewed as producing an improved version of some targeted solution. An incremental approach produces a new thing by changing the old one.
These ideas, together, define what “Agile” approaches like XP and Scrum are doing. They repeat a cyclic pattern of actions, producing a new version of the desired product, by changing the preceding version. Usually, those changes will consist of adding some new capability, because we generally need more than one capability in a product before people will find it useful.
The thing we produce is called the Increment, and we’ll discuss it in detail in another section. We’ll make a few points here.
First, the Increment should always be fully tested and operational. The only thing about it that could be “not ready to go” would be that it lacks some necessary capability to be useful. Presumably, the next thing we’ll do will be to add that capability. Other than that, it should be ready to ship. In fact, the best thing about it is that it’s ready to ship. The idea is to have it be irresistibly tempting to give the Increment to someone to use.
Second, while we usually improve the increment by adding capability, that doesn’t mean we never remove anything or never make a less visible improvement. A good use of an incremental development approach is to try things. We put in a capability, let a few people try it, and learn. Next time, we might remove that capability, or that way of providing it, and put in another. Similarly, we might improve efficiency or some other less visible characteristic of the product. The idea, simply enough, is that we improve it every time around.
There you have it. The approaches we prefer are iterative, in that they consist of short cycles of development, generally done in a self-similar style, with improvements. They are incremental, in that they produce an Increment of product each time around, each Increment being ready to ship, and better than the one before.
Iterative and incremental: smooth, consistent, producing usable results. That’s how I’d do software. | 901 | 4,419 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.140625 | 3 | CC-MAIN-2019-04 | latest | en | 0.942317 |
https://www.insurancethoughtleadership.com/tag/newco/ | 1,591,026,246,000,000,000 | text/html | crawl-data/CC-MAIN-2020-24/segments/1590347419056.73/warc/CC-MAIN-20200601145025-20200601175025-00201.warc.gz | 775,198,451 | 12,566 | # Insurtech and the Law of Large Numbers
I read a comment from a consumer who purchased a renter’s policy from a well-known, low-price, direct carrier for \$25 a month and got a quote for \$5 a month from a well-known, though brand new startup. The consumer asked online of the startup, “Are you real?” One of its executives replied, “Yes, and we can charge so little because of our technology!” (I’m paraphrasing slightly for confidentiality.)
That is some kind of technology to legitimately charge 80% less. If the technology is that great, everyone else should just pack up and quit now.
But, first, I will go through some simple math. I’ll use the incumbent carrier’s results using publicly available data. The limitation is that I do not have line-item expense data down to the renter’s policy level. This might make a difference, but, because the price difference is 80%, the difference is not material for this explanation.
The incumbent’s overall expense ratio excluding loss adjustment is about 14% of written premium. The overall industry average over the last 10 years is 27.1%, and in 2016 it was 27.7%. Expense ratios tend to be stable, stubbornly so when companies need to decrease them. The incumbent’s profit margin excluding investment revenue was approximately 5%. Therefore, it pays out approximately 70% of premiums in claims (total industry average for all lines is approximately 59%). This means that, if this carrier had no expenses and no need for profit, it would have to charge \$.70 per dollar of premium just to break even.
The new competitor (let’s call it “NewCo”) is charging approximately 80% less. NewCo is too new to use its actual expenses as comparisons (the profit margin was hugely negative last year, which is normal for a startup, even one with great technology). 80% less, though, is less than the incumbent’s expense ratio when loss adjustment expense is included (LAE is approximately 10%). In other words, the incumbent’s expense ratio including LAE is approximately 30%, one of the lowest in the industry, and yet NewCo can justify a rate of \$.20? To the best of my knowledge, no developed personal lines company has a sub-20% expense ratio including LAE. I suppose that, if everyone worked for free, if reinsurance were free and if the great technology was free, it might be possible.
For NewCo’s executive to be accurate, its technology must be so good that the great technology, his salary, others’ salaries, auditing fees, license fees, all other expenses and all losses must be less than \$.20 on the dollar. Is the executive correct? We’ll have to wait and see.
Giving the startup the benefit of the doubt, the only way a company can make money at 20% is if the technology identifies prospects that will not have claims, except in a highly unlikely scenario, such as maybe Black Swan events. The policy would have to be really a de facto catastrophe policy, even though the insured does not see it as such. Another possibility is that the forms are not comparable, which means NewCo’s form is disingenuous or a de facto cat policy from a different angle. Based on the executive’s response, though, no indication was made coverage was less, so I’m going to assume the forms are comparable. If I am wrong, a serious disclosure should have been made.
I am going to extend the benefit of the doubt further. If NewCo’s technology really is that good, to select people highly unlikely to have a claim, then those people do not really need insurance. They are just wasting much less at \$60 per year than \$300 per year.
Going further into the implications for the industry: There have to be clients so unlikely to incur a claim that rates can legitimately be 80% less. The law of large numbers is based on the concept that a company cannot, within reason, predetermine which of 100,000 renters will have a theft or fire. The company can only identify the probable number of claims and the claim dollars it’ll incur from these 100,000 renters collectively. If the carrier charges enough for all 100,000 policyholders (law of large numbers) but does not identify specifically who will have a claim because historically (and maybe still today) that is not predictable, then the company can make a small profit. The profit on some clients will be 70%, and on others it will be -1,000%, but, collectively, the underwriting profit will be 5%.
If NewCo’s executive is correct, what he was really saying is that its technology knows exactly who will have a claim–true predictive modeling down to the individual level. This means the consumers likely to have claims will pay much, much, much more. The carriers and agents stuck with these unfortunate clients will have serious problems, too, because the rates they have to charge may be so high as to be unaffordable. As much as people hate paying premiums that are always too high, historically insurance was egalitarian in many ways because all clients in a pool were treated somewhat equally. | 1,070 | 4,993 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.0625 | 3 | CC-MAIN-2020-24 | latest | en | 0.959519 |
http://blog.keenessays.com/2018/03/for-the-hyde-park-surgery-center-scenario-described-in-problem-19-in-chapter-9/ | 1,529,651,535,000,000,000 | text/html | crawl-data/CC-MAIN-2018-26/segments/1529267864364.38/warc/CC-MAIN-20180622065204-20180622085204-00012.warc.gz | 41,203,585 | 9,327 | ## For the Hyde Park Surgery Center scenario described in Problem 19 in Chapter 9 ,
For the Hyde Park Surgery Center scenario described in Problem 19 in Chapter 9 , suppose that the following assumptions are made: The number of patients served the first year is uniform between 1,300 and 1,700; the growth rate for subsequent years is triangular with parameters (5%, 8%, 9%), and the growth rate for year 2 is independent of the growth rate for year 3; average billing is normal with a mean of \$150,000 and a standard deviation of \$10,000; and the annual increase in fixed costs is uniform between 5% and 7%, and independent of other years. Find the distribution of the NPV of profit over the three-year horizon and analyze the sensitivity and trend charts. Summarize your conclusions. | 176 | 788 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.578125 | 3 | CC-MAIN-2018-26 | longest | en | 0.944723 |
https://www.byrdseed.tv/category/enrichment/games/tic-tac-toe-variants/?fd=new | 1,701,449,291,000,000,000 | text/html | crawl-data/CC-MAIN-2023-50/segments/1700679100290.24/warc/CC-MAIN-20231201151933-20231201181933-00561.warc.gz | 775,928,235 | 8,070 | Tic-Tac-Toe Variants
Ultimate (or Inception) Tic Tac Toe
So, I heard you like Tic-Tac-Toe. What if each square on a Tic-Tac-Toe board had another Tic-Tac-Toe board inside of it? 🤯
Game: Wild Tic Tac Toe
Imagine Tic-Tac-Toe, but both players can both play as both X and O throughout the whole game! First to get three-in-a-row still wins!
Game: Gomoku
Want to take Tic-Tac-Toe to the next level!? Imagine a 15×15 board. You must get five-in-a-row. You cannot get six-in-a-row. That's Gomoku!
Game: Order and Chaos
Imagine Tic-Tac-Toe if both players could play as both Xs and Os!
Game: Notakto
What if you only played Tic-Tac-Toe with Xs and you could play on multiple boards? | 204 | 689 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.671875 | 3 | CC-MAIN-2023-50 | latest | en | 0.968116 |
https://gamepress.gg/jurassicworldalive/guide/jwa-weekly-event-aug-16-aug-22-nullify-fleeing | 1,653,292,683,000,000,000 | text/html | crawl-data/CC-MAIN-2022-21/segments/1652662556725.76/warc/CC-MAIN-20220523071517-20220523101517-00618.warc.gz | 334,620,516 | 22,395 | GamePress
# JWA Weekly Event Aug 16 - Aug 22: Nullify & Fleeing
Submit Feedback or Error
## Introduction
Explorers! After a whirlwind couple of weeks with added Legendary attempts, we're back to business as usual with Nullify & Fleeing themes. It's been quite some time since we had Nullify featured at event drops, so let's go over what our Discord community is thinking, what we'll recommend to dart, and everything else you need to know.
## Weekly Calendar Explained
Before we dive in to the week, we'll break down how the weekly event calendar works. First, each day is considered started at 10am Eastern on that day. It is possible that wherever you live, it might actually be the previous or next day, so we wanted to help clarify how they determine what day it is. At this time, event creatures & strike towers will be updated as applicable. This information is also noted on the calendar.
Ever wonder why some weeks we’re given 45 attempts on commons and others only 18 or 27? The reason for this is that the volume of attempts is a simple math calculation based on the rarity and number of options. Take the rarity base number and multiply by the number of options and voila, you have your total allowed attempts! Having more variety in the options yields that many more attempts. The flip side is it may be more difficult to find the creature(s) you favor. Below details the number of attempts assigned to each rarity which is used to determine how many attempts you receive (though occasionally, they stray from this math). This is the total you are allotted across all options, so it is important to select your choices wisely.
• Common = 9 per
• Rare = 6 per
• Epic = 3 per
• Legendary/Unique = 1 total
They recently started putting the number of attempts on the calendar again and sometimes stray from the above. Refer to the calendar for the confirmed counts. Each rarity has a different length of time the spawn lasts followed by a different length of time until respawn after despawn. Commons and Rares will last 1 hour with about 5 minutes between. Epics last 2 hours with about 5 minutes in between.
All strikes and trials are represented on the calendar with the level of difficulty along with how long they last (1 day or 2 days). The trials are shown along the very bottom in gray boxes.
## Featured Creatures: Commons
Monday - Wednesday: 36 Attempts
• Dilophosaurus Gen 2 (Global Anytime) (Dilophoboa>Spinoconstrictor, Tyrannolophosaur>Tenontorex)
• Diplocaulus (Park Day/Dawn/Dusk) (Diplotator>Scaphotator)
• Monolophosaurus Gen 2 (Local 4 Anytime) (Monolometrodon>Monolorhino, Scorpius Rex Gen 2>Scorpius Rex Gen 3)
• Tanycolagerus (Global Anytime) (Quetzorion)
It's pretty clear Mono2 is the top choice of this week, and it's no surprise the vast majority of those in our Discord community who voted plan to target this one.. Between MRhino and SR2/SR3, this is one you truly can't get enough of. Two of the other options are available everywhere, all the time, and Diplo doesn't create anything special at this time.
We are given three days on Commons this week, so that feels like enough time to be particular about your choice(s). However, your ultimate plan might simply be to dart whatever crosses your path. 36 is still a lot of attempts, and you may be better off not investing extra time seeking out any in particular.
## Featured Creatures: Rares
Thursday - Friday: 18 Attempts
• Compsognathus Gen 2 (Local 4 Anytime)
• Dilophosaurus (Event Exclusive) (Ovilophosaurus, Diloranosaurus>Diloracheirus)
• Kelenken (Event Exclusive) (Grylenken)
Woohoo two event exclusive options comin right at you! Of course we just had a full week of wild Dilo through hybrid pursuit. This one feeds the most hybrids and may be your preference as a result. It feels like they have been shoving Compy2 down our throats lately. This will be the 5th time over the past 12 weeks we see this one at event drops. With flocks seeming to carve out their own little meta, it wouldn't be any mistake to go with this one either to over level for tournament or stockpile for a possible future hybrid. Last, we have Kelenken. I strongly considered leveling Grylenken for tournament but decided to wait. When I was talking this over within my alliance, DadJokes expressed how much he loves his. If you're looking for a not so oft used Legendary option, Kel may be your way to go (and that isn't name bias talking).
Those who voted in our Discord poll are a little more evenly spread across Compy2, Kel, and whatever crosses the path. There isn't much love for DIlo, though.
## Featured Creatures: Epics
Saturday - Sunday: 9 Attempts
• Koolasuchus (Global Dawn/Dusk/Night) (Skoolasaurus>Skoonasaurus)
• Monolophosaurus (Local 3 Anytime) (Monomimus>Pterovexus, Monostegotops)
• Pteranodon (Local 3 Anytime) (Pteraquetzal>Quetzorion)
We just had Mono featured a couple weeks ago, and here is what I wrote: "There isn't really much to be said for MonoMimus, Vexus, and MonoS have had their days in the sun. But as they currently stand, we're not finding these to be as useful as so many others." However, when weighing against the other choices this week, Mono isn't looking so bad. Of course if you are still working on Skoona, a very top arena creature, you will want to select Koola. It's tough to give a nod to Pteran, mostly because I personally am oversaturated from back when it was a park spawn.
Not very surprisingly, Koola is winning our Discord poll with "whatever crosses my path" a close second.
## Strike Events, Trials, Scents, Treasure Chase, and Hybrid Pursuit!
#### Strike Events & Trials
Strike Events will be Fleeing themed and reward the following creatures upon successful completion:
• Coelurosauravus (Common)
• Gallimimus (Common)
• Hatzegopteryx (Common)
• Compsognathus Gen 2 (Rare)
• Ornithomimus (Rare)
• Quetzalcoatlus (Rare)
• Darwinopterus (Epic)
• Dodo (Epic)
• Pachycephalosaurus (Epic)
Trials are Self Increase themed and will reward the following creatures upon successful completion:
• Archaeotherium (Common)
• Irritator Gen 2 (Common)
• Majungasaurus (Common)
• Nundasuchus (Common)
• Baryonyx2 Gen 2 (Rare)
• Dsungaripterus (Rare)
• Irritator (Rare)
• Edaphausaurus (Epic)
• Gryposuchus (Epic)
• Pteranodon (Epic)
We will have two dinosaur specific strikes this week. Wednesday will feature Compy2, and an Epic strike on Friday will feature Dodo! We've also got the regularly scheduled Boost Strikes on Tuesday (Attack), Thursday (HP), and Saturday (Speed).
#### Scents
There is a basic scent strike on Monday, and the themed scent on Thursday is Stegosaurisae. This can draw the following creatures while activated:
• Miragaia (Common)
• Stegosaurus (Common)
• Tuojiangosaurus (Rare)
• Wuerhosaurus (Rare)A
• Kentrosaurus (Epic)
#### Treasure Chase
On Sunday, we will have the treasure chase where the chests refresh hourly for you to collect up to 25,000 coins! The boxes reset at 8pm Eastern, so you actually have a chance for up to 50,000 coins if you are able to max both time frames.
#### Hybrid Pursuit
This week will begin the Ankylodicurus pursuit with the common yet mighty Ophiacodon.
## Daily Dino & Tournament Info
August continues with our daily reward being Antarctopelta while the arena reward is the extremely valuable, event exclusive, Haast Eagle.
Week 3 of the Skoonasaurus Alliance Championships will be an Rare/Epic (No Hybrids) Skills tournament for BOOOOOOOSTS!
August 2021 Stat Boost Tournament
REQUIREMENTS
• Creatures
• Rare
• Epic
• No Hybrids
• Level
• All creatures are set to Tournament Level (26)
• Stat Boosts
• Disabled
## Free Cash Link
GamePress is excited to be able to provide weekly cash links worth \$50 cash in game! The code can only be claimed once a week and you must click on it using the device you play JWA with. It will be active from Monday, 12 PM EST - Sunday, 12 PM EST every week. This is a promotional code provided courtesy of Ludia, Inc and is exclusive to GamePress. We will post this link in an article we publish each week. We will post all articles on our Twitter so follow us at NewsJWA on Twitter so you don't miss out!
If you enjoy our content, please help let others know this is the source of the cash links people just post for the taking all over social media. The same goes for YouTubers PokeFodder, Gaming Beaver, and Gaming Ells. All links have a purpose behind them, and that is to promote some kind of media and drive traffic. Most people simply do not know there is actually a purpose behind these links, and we'd like to try to educate as many as we can. Take a moment to politely explain this in these posts. It isn't free money some random stranger on the internet whipped up. Every time these links are shared, it is taking opportunity away from an intended purpose. Please think about that or maybe find some time to visit Gaming Beaver, PokeFodder, Gaming Ells, GamePress JWA, and the Ludia social medias.
## Parting Words
This will be a great week effectively covering three themes over Event Drops, Strikes, and Trials. New for 2021, we are going to reach out for more community input on these weekly event roundups. Come join up and let us know what you plan to dart! We look forward to your input and hope to see you on there!
Enjoyed the article?
Consider supporting GamePress and the author of this article by joining GamePress Boost!
## About the Author(s)
Kelly resides in Scottsdale, AZ, proud cat mama of her girls, Payton & Cat Tillman. A JWA player since about day one, she spends much time hunting in the park outside her home and thrives in leading the great folks of Kelliance. | 2,397 | 9,664 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.890625 | 3 | CC-MAIN-2022-21 | latest | en | 0.944596 |
http://www.netlib.org/lapack/explore-html/d5/d93/sget53_8f_source.html | 1,652,718,458,000,000,000 | text/html | crawl-data/CC-MAIN-2022-21/segments/1652662510138.6/warc/CC-MAIN-20220516140911-20220516170911-00270.warc.gz | 107,351,480 | 6,656 | LAPACK 3.10.1 LAPACK: Linear Algebra PACKage
sget53.f
Go to the documentation of this file.
1 *> \brief \b SGET53
2 *
3 * =========== DOCUMENTATION ===========
4 *
5 * Online html documentation available at
6 * http://www.netlib.org/lapack/explore-html/
7 *
8 * Definition:
9 * ===========
10 *
11 * SUBROUTINE SGET53( A, LDA, B, LDB, SCALE, WR, WI, RESULT, INFO )
12 *
13 * .. Scalar Arguments ..
14 * INTEGER INFO, LDA, LDB
15 * REAL RESULT, SCALE, WI, WR
16 * ..
17 * .. Array Arguments ..
18 * REAL A( LDA, * ), B( LDB, * )
19 * ..
20 *
21 *
22 *> \par Purpose:
23 * =============
24 *>
25 *> \verbatim
26 *>
27 *> SGET53 checks the generalized eigenvalues computed by SLAG2.
28 *>
29 *> The basic test for an eigenvalue is:
30 *>
31 *> | det( s A - w B ) |
32 *> RESULT = ---------------------------------------------------
33 *> ulp max( s norm(A), |w| norm(B) )*norm( s A - w B )
34 *>
35 *> Two "safety checks" are performed:
36 *>
37 *> (1) ulp*max( s*norm(A), |w|*norm(B) ) must be at least
38 *> safe_minimum. This insures that the test performed is
39 *> not essentially det(0*A + 0*B)=0.
40 *>
41 *> (2) s*norm(A) + |w|*norm(B) must be less than 1/safe_minimum.
42 *> This insures that s*A - w*B will not overflow.
43 *>
44 *> If these tests are not passed, then s and w are scaled and
45 *> tested anyway, if this is possible.
46 *> \endverbatim
47 *
48 * Arguments:
49 * ==========
50 *
51 *> \param[in] A
52 *> \verbatim
53 *> A is REAL array, dimension (LDA, 2)
54 *> The 2x2 matrix A.
55 *> \endverbatim
56 *>
57 *> \param[in] LDA
58 *> \verbatim
59 *> LDA is INTEGER
60 *> The leading dimension of A. It must be at least 2.
61 *> \endverbatim
62 *>
63 *> \param[in] B
64 *> \verbatim
65 *> B is REAL array, dimension (LDB, N)
66 *> The 2x2 upper-triangular matrix B.
67 *> \endverbatim
68 *>
69 *> \param[in] LDB
70 *> \verbatim
71 *> LDB is INTEGER
72 *> The leading dimension of B. It must be at least 2.
73 *> \endverbatim
74 *>
75 *> \param[in] SCALE
76 *> \verbatim
77 *> SCALE is REAL
78 *> The "scale factor" s in the formula s A - w B . It is
79 *> assumed to be non-negative.
80 *> \endverbatim
81 *>
82 *> \param[in] WR
83 *> \verbatim
84 *> WR is REAL
85 *> The real part of the eigenvalue w in the formula
86 *> s A - w B .
87 *> \endverbatim
88 *>
89 *> \param[in] WI
90 *> \verbatim
91 *> WI is REAL
92 *> The imaginary part of the eigenvalue w in the formula
93 *> s A - w B .
94 *> \endverbatim
95 *>
96 *> \param[out] RESULT
97 *> \verbatim
98 *> RESULT is REAL
99 *> If INFO is 2 or less, the value computed by the test
100 *> described above.
101 *> If INFO=3, this will just be 1/ulp.
102 *> \endverbatim
103 *>
104 *> \param[out] INFO
105 *> \verbatim
106 *> INFO is INTEGER
107 *> =0: The input data pass the "safety checks".
108 *> =1: s*norm(A) + |w|*norm(B) > 1/safe_minimum.
109 *> =2: ulp*max( s*norm(A), |w|*norm(B) ) < safe_minimum
110 *> =3: same as INFO=2, but s and w could not be scaled so
111 *> as to compute the test.
112 *> \endverbatim
113 *
114 * Authors:
115 * ========
116 *
117 *> \author Univ. of Tennessee
118 *> \author Univ. of California Berkeley
119 *> \author Univ. of Colorado Denver
120 *> \author NAG Ltd.
121 *
122 *> \ingroup single_eig
123 *
124 * =====================================================================
125 SUBROUTINE sget53( A, LDA, B, LDB, SCALE, WR, WI, RESULT, INFO )
126 *
127 * -- LAPACK test routine --
128 * -- LAPACK is a software package provided by Univ. of Tennessee, --
129 * -- Univ. of California Berkeley, Univ. of Colorado Denver and NAG Ltd..--
130 *
131 * .. Scalar Arguments ..
132 INTEGER INFO, LDA, LDB
133 REAL RESULT, SCALE, WI, WR
134 * ..
135 * .. Array Arguments ..
136 REAL A( LDA, * ), B( LDB, * )
137 * ..
138 *
139 * =====================================================================
140 *
141 * .. Parameters ..
142 REAL ZERO, ONE
143 parameter( zero = 0.0, one = 1.0 )
144 * ..
145 * .. Local Scalars ..
146 REAL ABSW, ANORM, BNORM, CI11, CI12, CI22, CNORM,
147 \$ CR11, CR12, CR21, CR22, CSCALE, DETI, DETR, S1,
148 \$ SAFMIN, SCALES, SIGMIN, TEMP, ULP, WIS, WRS
149 * ..
150 * .. External Functions ..
151 REAL SLAMCH
152 EXTERNAL slamch
153 * ..
154 * .. Intrinsic Functions ..
155 INTRINSIC abs, max, sqrt
156 * ..
157 * .. Executable Statements ..
158 *
159 * Initialize
160 *
161 info = 0
162 result = zero
163 scales = scale
164 wrs = wr
165 wis = wi
166 *
167 * Machine constants and norms
168 *
169 safmin = slamch( 'Safe minimum' )
170 ulp = slamch( 'Epsilon' )*slamch( 'Base' )
171 absw = abs( wrs ) + abs( wis )
172 anorm = max( abs( a( 1, 1 ) )+abs( a( 2, 1 ) ),
173 \$ abs( a( 1, 2 ) )+abs( a( 2, 2 ) ), safmin )
174 bnorm = max( abs( b( 1, 1 ) ), abs( b( 1, 2 ) )+abs( b( 2, 2 ) ),
175 \$ safmin )
176 *
177 * Check for possible overflow.
178 *
179 temp = ( safmin*bnorm )*absw + ( safmin*anorm )*scales
180 IF( temp.GE.one ) THEN
181 *
182 * Scale down to avoid overflow
183 *
184 info = 1
185 temp = one / temp
186 scales = scales*temp
187 wrs = wrs*temp
188 wis = wis*temp
189 absw = abs( wrs ) + abs( wis )
190 END IF
191 s1 = max( ulp*max( scales*anorm, absw*bnorm ),
192 \$ safmin*max( scales, absw ) )
193 *
194 * Check for W and SCALE essentially zero.
195 *
196 IF( s1.LT.safmin ) THEN
197 info = 2
198 IF( scales.LT.safmin .AND. absw.LT.safmin ) THEN
199 info = 3
200 result = one / ulp
201 RETURN
202 END IF
203 *
204 * Scale up to avoid underflow
205 *
206 temp = one / max( scales*anorm+absw*bnorm, safmin )
207 scales = scales*temp
208 wrs = wrs*temp
209 wis = wis*temp
210 absw = abs( wrs ) + abs( wis )
211 s1 = max( ulp*max( scales*anorm, absw*bnorm ),
212 \$ safmin*max( scales, absw ) )
213 IF( s1.LT.safmin ) THEN
214 info = 3
215 result = one / ulp
216 RETURN
217 END IF
218 END IF
219 *
220 * Compute C = s A - w B
221 *
222 cr11 = scales*a( 1, 1 ) - wrs*b( 1, 1 )
223 ci11 = -wis*b( 1, 1 )
224 cr21 = scales*a( 2, 1 )
225 cr12 = scales*a( 1, 2 ) - wrs*b( 1, 2 )
226 ci12 = -wis*b( 1, 2 )
227 cr22 = scales*a( 2, 2 ) - wrs*b( 2, 2 )
228 ci22 = -wis*b( 2, 2 )
229 *
230 * Compute the smallest singular value of s A - w B:
231 *
232 * |det( s A - w B )|
233 * sigma_min = ------------------
234 * norm( s A - w B )
235 *
236 cnorm = max( abs( cr11 )+abs( ci11 )+abs( cr21 ),
237 \$ abs( cr12 )+abs( ci12 )+abs( cr22 )+abs( ci22 ), safmin )
238 cscale = one / sqrt( cnorm )
239 detr = ( cscale*cr11 )*( cscale*cr22 ) -
240 \$ ( cscale*ci11 )*( cscale*ci22 ) -
241 \$ ( cscale*cr12 )*( cscale*cr21 )
242 deti = ( cscale*cr11 )*( cscale*ci22 ) +
243 \$ ( cscale*ci11 )*( cscale*cr22 ) -
244 \$ ( cscale*ci12 )*( cscale*cr21 )
245 sigmin = abs( detr ) + abs( deti )
246 result = sigmin / s1
247 RETURN
248 *
249 * End of SGET53
250 *
251 END
subroutine sget53(A, LDA, B, LDB, SCALE, WR, WI, RESULT, INFO)
SGET53
Definition: sget53.f:126 | 2,587 | 6,868 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.6875 | 3 | CC-MAIN-2022-21 | latest | en | 0.358535 |
https://www.archivemore.com/how-many-lines-per-millimeter-does-the-grating-have/ | 1,719,074,088,000,000,000 | text/html | crawl-data/CC-MAIN-2024-26/segments/1718198862404.32/warc/CC-MAIN-20240622144011-20240622174011-00044.warc.gz | 569,654,049 | 7,617 | 666 lines
## How do you determine the number of lines in a diffraction grating?
The formula for diffraction grating: Obviously, d = 1 N /frac {1} { N } N1, where N is the grating constant, and it is the number of lines per unit length. Also, n is the order of grating, which is a positive integer, representing the repetition of the spectrum.
## How do I calculate the number of slits?
The number of slits per metre on the grating, N = 1/ d where d is the grating spacing. For a given order and wavelength, the smaller the value of d, the greater the angle of diffraction.
## What is A and B in grating element?
A grating is an arrangement consisting of a large number of parallel slits of same width and separated by equal opaque spaces. (a+b) is called grating element or grating constant. It can be seen that distance between two consecutive slits is grating element.
## How many types of grating are there?
two different types
## What is the unit of grating element?
The unit of length, since grating element is defined as the distance between the midpoints of two adjacent transparent zones, i.e. the sum of line width and line separation. Why does diffraction grating need light normal to the grating? What is grating element?
## What is the value of grating element?
Grating element is equal to the reciprocal of number of lines per cm on grating. Let a train of plane waves be incident normally on grating. Considering light rays passing through the grating straight will be conveyed at ‘P’ As the wavelets through the various slits reach the point ‘p’ after covering equal distance.
## What is N in diffraction grating?
In this formula. is the angle of emergence (called deviation, D, for the prism) at which a wavelength will be bright, d is the distance between slits (note that d = 1 / N if N, called the grating constant, is the number of lines per unit length) and n is the “order number”, a positive integer (n = 1, 2, 3.)
## What is diffraction grating used for?
Diffraction gratings are optical devices that are used in instruments such as spectrometers to separate polychromatic light into the underlying constituent wavelengths of which it is comprised. | 508 | 2,188 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 4.28125 | 4 | CC-MAIN-2024-26 | latest | en | 0.937562 |
https://mathhomeworkanswers.org/112/how-do-you-find-a-slope | 1,490,774,285,000,000,000 | text/html | crawl-data/CC-MAIN-2017-13/segments/1490218190234.0/warc/CC-MAIN-20170322212950-00051-ip-10-233-31-227.ec2.internal.warc.gz | 819,868,865 | 15,636 | y=4x+3
slope = 4
standard form y = kx + b
answered Mar 8, 2011 by Level 3 User (2,140 points)
slope=mx+b. m is the slope and x is the variable of m. and b is the y-intercept of the line.
answered Feb 13, 2012 by anonymous
how do I find the slope for x-2y=4?
answered Feb 23, 2012 by anonymous
The equation you wrote is the standard form of a line: y = mx + b.
In this equation, m is the slope of the line and b is the y-intercept.
So the slope here is 4.
answered Apr 9, 2012 by (140 points)
what is the answer to this problem 9.5*10negative 6 in standard form?
answered Sep 4, 2012 by anonymous
What is the slope of the line through the points (-2, 7) and (3, -3)? m = _?_
answered Sep 25, 2012 by anonymous
In y-intercept form, y=mx+b, with m being the slope. Therefore, in the equation y=4x+b, the slope is 4.
answered Oct 31, 2012 by anonymous
what are the line segments
answered Nov 11, 2012 by anonymous
answered Dec 11, 2012 by anonymous
It's in standard form in which is y=mx+b. Therefore you take 4x and put a 1 under it to give you your slope. Which will be y=4x/1+3
answered Jan 4, 2013 by anonymous
what is perpendicular?
answered Apr 7, 2013 by anonymous
y= -x+3
answered Dec 9, 2013 by laimee
road with 12 m side alope 1in1 cut and1in3 fill ground cross fall in 1in 12
answered Jan 15, 2014 by mushtaq
The slope is equal to the "m" and always remember the formula because this is the hint of the answers:
GIVEN; y=4x + 3
If the formula is: y= mx + b
then the slope is 4..
answered Feb 4, 2014 by Mechanical Eng. Sumalinog
calculate the length of the line segment. Round your answer to the nearest tenth.. a. 4.6 b. 6.9 c. 8.5 d. 9.3
The line is plus 8 Plus 3 plus 7
answered Jun 4, 2014 by Jenny
4, as from equation of line Y =mX +c
answered Jun 20, 2014 by anonymous
4444444
answered Jul 21, 2014 by anonymous
show that the graph of the equation xy=1 is a hyperbola by rotating the xy-axes through an angle of 45
answered Sep 2, 2014 by zimba richard
Would you use distributive property?
answered Oct 7, 2014 by Ember
Y=3/4x+ 11
answered Dec 8, 2014 by anonymous
Whats the slope of a line running throw (6,8) and (3,-6)
answered Jan 3, 2015 by lucky
Given: y=4x+3
The slope of a line is the ratio of unit change in y to unit change in x.
In other words, the slope means that, if x increases 1 unit, how much y increases or decreases
its quantity.
So that the slope reveals how steeply or slowly the graph goes up or down.
Write standard form of a linear equation in functional form, e.g. y=f(x)=mx+b···Eq.1
In Eq.1, if x increases 1 unit, then y=f(x+1)=m(x+1)+b=mx+m+b···Eq.2
So, the unit change in y is: Eq.2-Eq.1=f(x+1)-f(x)=m
Thus, the slope, the ratio of unit change, is: y : x = m : 1
Therefore, the slope of line y=mx+b is equal to m.
That is: m, the coefficient of x, indicates the slope.
In this question, 4 corresponds to m. So, the slope is 4.
The answer: The slope of line y=4x+3 is 4.
answered Jan 5, 2015 by Level 2 User (1,260 points) | 988 | 2,984 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 4 | 4 | CC-MAIN-2017-13 | latest | en | 0.962729 |
https://brainly.in/question/8542 | 1,484,716,035,000,000,000 | text/html | crawl-data/CC-MAIN-2017-04/segments/1484560280221.47/warc/CC-MAIN-20170116095120-00397-ip-10-171-10-70.ec2.internal.warc.gz | 794,369,360 | 10,562 | Cube root of 2744 is
2
by suai
2014-04-20T17:17:04+05:30
Cube root of 2744 = 14
2014-04-20T17:17:50+05:30
The cube root of 2744 is 14.
i will show u how did it came
= 2 * 1372
= 2 * 2 * 686
= 2 * 2 * 2 * 343
= 2 * 2 * 2 * 7 * 49
= 2 * 2 * 2 * 7 * 7 * 7
= 2 ^ 3 * 7 ^ 3
so cube root of 2744 is 2 * 7 = 14.
cool
thanks
thx manit suai for manit's comment and suai for best answer
and welcome it my pleasure suai. | 206 | 412 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.125 | 3 | CC-MAIN-2017-04 | latest | en | 0.669665 |
http://www.convertit.com/Go/SalvageSale/Measurement/Converter.ASP?From=au | 1,527,162,803,000,000,000 | text/html | crawl-data/CC-MAIN-2018-22/segments/1526794866276.61/warc/CC-MAIN-20180524112244-20180524132244-00035.warc.gz | 347,807,065 | 3,613 | New Online Book! Handbook of Mathematical Functions (AMS55)
Conversion & Calculation Home >> Measurement Conversion
Measurement Converter
Convert From: (required) Click here to Convert To: (optional) Examples: 5 kilometers, 12 feet/sec^2, 1/5 gallon, 9.5 Joules, or 0 dF. Help, Frequently Asked Questions, Use Currencies in Conversions, Measurements & Currencies Recognized Examples: miles, meters/s^2, liters, kilowatt*hours, or dC.
Conversion Result: ```astronomical unit = 149597871000 meter (length) ``` Related Measurements: Try converting from "au" to astronomical unit, barleycorn, Biblical cubit, bottom measure, cloth quarter, digitus (Roman digitus), earth to moon (mean distance earth to moon), gradus (Roman gradus), Greek cubit, Greek palm, Israeli cubit, league, li (Chinese li), pace, parsec, point (typography point), ri (Japanese ri), rod (surveyors rod), Roman mile, UK mile (British mile), or any combination of units which equate to "length" and represent depth, fl head, height, length, wavelength, or width. Sample Conversions: au = 210,345,712,879.64 archin (Russian archin), 2,558,483,401.81 arpentlin, 588,967,996,062,992 caliber (gun barrel caliber), 6,731,062,812,148.48 finger, 448,793,613,000,000 French, 323,253,565,347.42 Greek cubit, 80,813,391,336.85 Greek fathom, 270,168,805,533.48 Israeli cubit, 70,676,159,527,559.1 line, 149,597,871,000 m (meter), 3,545,394.33 marathon, 5.89E+15 mil, 26,925,462.74 nautical league, 35,338,079,763,779.5 pica (typography pica), 425,647,175,011,196 point (typography point), 654,408,884,514.44 span (cloth span), 11,361,265.36 spindle, 809,911,985.79 stadium (Roman stadium), 490,805,681,772.5 survey foot, 163,602,221,128.61 yard.
Feedback, suggestions, or additional measurement definitions?
Please read our Help Page and FAQ Page then post a message or send e-mail. Thanks! | 562 | 1,852 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.296875 | 3 | CC-MAIN-2018-22 | longest | en | 0.696671 |
https://mathematica.stackexchange.com/questions/192541/for-loop-and-sum | 1,582,027,783,000,000,000 | text/html | crawl-data/CC-MAIN-2020-10/segments/1581875143695.67/warc/CC-MAIN-20200218120100-20200218150100-00538.warc.gz | 477,438,343 | 33,353 | # For Loop and Sum
I am requested to do a sum of the first fifty positive even numbers by using For loop. The For loop that I created is
For[natNum = 2, natNum <= 50, natNum = natNum + 2, Print[natNum]]
The output of this is a list of numbers from 2 to 50 and they are increasing by 2. Now I need these numbers to be sum so I created
Sum[For[natNum = 2, natNum <= 50, natNum = natNum + 2, Print[natNum]]]
However, it is not a correct input. I am not sure if I should write the Sum inside the For loop.
• If this is a class assignment, I'd suggest withdrawing from the class. For loops are almost never a good way to do anything in Mathematica. – John Doty Mar 3 '19 at 20:32
• If you want the first 50 positive even numbers, I believe that is {2, 4, ..., 100}. The sum is (2+100) + (4+98) + ... + (50 + 52) = 102 * 25 = 2550. – mjw Mar 3 '19 at 22:06
• Total@Range[2, 2*50, 2] would be pretty direct. Note also that Print prints its arguments, but does not return them (in fact, it returns Null). – MarcoB Mar 3 '19 at 22:57
• Since the days of Carl Friedrich Gauß we know that using a For loop to compute 50 * 51 is a pretty bad idea.... – Henrik Schumacher Mar 3 '19 at 23:51
• Is it the first fifty that you want, or is it {2, 4, ..., 50}? The original question had both. – mjw Mar 4 '19 at 2:56
Anyone asking you to write For loops in Mathematica for such a problem is a dolt. Nevertheless, here's how you might do that:
rslt = 0;
For[i = 0, i <= 50, i += 2, rslt += i];
rslt
And here's how someone with some familiarity with Mathematica might write it
Plus @@ Range[25]*2
Now, spend the time you were going to waste writing a For loop by reading the answers to this question Why should I avoid the For loop in Mathematica?
• +1 for the first sentence. – Henrik Schumacher Mar 3 '19 at 23:49
The first fifty positive integers can be computed with Table:
Q = 0; (* Initialization *)
T = Table[Q + k, {k, 2 Range[50]}]
We can sum up the values of T with Sum:
Sum[T[[k]], {k, Range[50]}]
2550
• Perhaps better / more idiomatic than your Sum approach would be using Total[T] or Plus@@T. – MarcoB Mar 3 '19 at 22:56
• Thank you! I was looking for something like Total and I saw the Plus posting above, but haven't yet learned about @@ and such. I would have thought Map might work here (it does not). Anyway, yes Total[T] and Plus@@T are simpler and more elegant! – mjw Mar 4 '19 at 0:23
• I was a latecomer to @@ as well. When I was learning about it, it helped me to think about it as a way of "swapping heads" of expressions. So for instance, if you have {1, 2, 3}, its FullForm would be List[1, 2, 3]. If you then Apply Plus to it, i.e. Plus@@, you swap the Listhead for a Plus head, to give Plus[1, 2, 3]. Although it may seem like a niche application at first, once you get used to it, it is tremendously useful! – MarcoB Mar 4 '19 at 1:34
• This is great, thank you! Just as I learned not to use For loops (especially on this Forum), and to Do use Do, I'll look for opportunities to Apply @@. – mjw Mar 4 '19 at 2:23 | 932 | 3,046 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 1, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.515625 | 4 | CC-MAIN-2020-10 | latest | en | 0.884983 |
https://forums.geocaching.com/GC/index.php?/topic/49511-triangulation/ | 1,721,821,393,000,000,000 | text/html | crawl-data/CC-MAIN-2024-30/segments/1720763518277.99/warc/CC-MAIN-20240724110315-20240724140315-00008.warc.gz | 221,640,948 | 16,764 | # Triangulation
## Recommended Posts
Can someone explain to me how Triangulation works and what formulas and everything i need to use
MAX
There is some discussion of triangulation in this thread.
The term "triangulation" can refer to a few different problems ... but they all use triangles/trigonometry to locate a refernced point.
Do you have a specific case?
Here's a good place to start ...
[This message was edited by DisQuoi on March 08, 2002 at 08:01 AM.]
Which is available here.
rdw
MAX:
Go north from Littleton and find the bushwhacker and he will give you a real life demonstration of how to triangulate.
Maxwells triangulation is an inverse of trying to find out where you are at. Say you are the little stump stuck in the woods and you wish to find out where you are at. Well take 2 bearings from prominent landmarks or objects and you can tell where you are at. The real trick is learning how to make your compass and GPS talk to each other and then put it on a map.
Check this site out it should help.
www.princeton.edu/~oa/manual/mapcompass.shtml
The "Bushwhacker"
Hey Bushwacker ... what in the world is that photo in your profile?
That's a black lab in the weeds. Just very low res.
Or Bigfoot walking away at a lumbering pace...
Markwell
Non omnes vagi perditi sunt
Bushwhacker id love for a real life demo maybe we could meet up at one of the event caches coming up
will u be attending
MAX
quote:
Originally posted by Max Orcutt:
Bushwhacker id love for a real life demo maybe we could meet up at one of the event caches coming up
will u be attending
MAX
Around June we will have a meet someplace in the hills about 8200 ft. Watch for the anouncement.
The "Bushwhacker"
## Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.
× Pasted as rich text. Paste as plain text instead
Only 75 emoji are allowed. | 475 | 2,004 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.515625 | 3 | CC-MAIN-2024-30 | latest | en | 0.930524 |
https://support.nag.com/numeric/nl/nagdoc_28.6/flhtml/g05/g05ssf.html | 1,708,853,416,000,000,000 | text/html | crawl-data/CC-MAIN-2024-10/segments/1707947474594.56/warc/CC-MAIN-20240225071740-20240225101740-00136.warc.gz | 546,475,653 | 5,738 | # NAG FL Interfaceg05ssf (dist_weibull)
## ▸▿ Contents
Settings help
FL Name Style:
FL Specification Language:
## 1Purpose
g05ssf generates a vector of pseudorandom numbers from a two parameter Weibull distribution with shape parameter $a$ and scale parameter $b$.
## 2Specification
Fortran Interface
Subroutine g05ssf ( n, a, b, x,
Integer, Intent (In) :: n Integer, Intent (Inout) :: state(*), ifail Real (Kind=nag_wp), Intent (In) :: a, b Real (Kind=nag_wp), Intent (Out) :: x(n)
#include <nag.h>
void g05ssf_ (const Integer *n, const double *a, const double *b, Integer state[], double x[], Integer *ifail)
The routine may be called by the names g05ssf or nagf_rand_dist_weibull.
## 3Description
The distribution has PDF (probability density function)
$f(x) = ab x a-1 e- xa / b if x>0, f(x)=0 otherwise.$
g05ssf returns the value ${\left(-b\mathrm{ln}y\right)}^{1/a}$, where $y$ is a pseudorandom number from a uniform distribution over $\left(0,1\right]$.
One of the initialization routines g05kff (for a repeatable sequence if computed sequentially) or g05kgf (for a non-repeatable sequence) must be called prior to the first call to g05ssf.
## 4References
Kendall M G and Stuart A (1969) The Advanced Theory of Statistics (Volume 1) (3rd Edition) Griffin
Knuth D E (1981) The Art of Computer Programming (Volume 2) (2nd Edition) Addison–Wesley
## 5Arguments
1: $\mathbf{n}$Integer Input
On entry: $n$, the number of pseudorandom numbers to be generated.
Constraint: ${\mathbf{n}}\ge 0$.
2: $\mathbf{a}$Real (Kind=nag_wp) Input
On entry: $a$, the shape parameter of the distribution.
Constraint: ${\mathbf{a}}>0.0$.
3: $\mathbf{b}$Real (Kind=nag_wp) Input
On entry: $b$, the scale parameter of the distribution.
Constraint: ${\mathbf{b}}>0.0$.
4: $\mathbf{state}\left(*\right)$Integer array Communication Array
Note: the actual argument supplied must be the array state supplied to the initialization routines g05kff or g05kgf.
On entry: contains information on the selected base generator and its current state.
On exit: contains updated information on the state of the generator.
5: $\mathbf{x}\left({\mathbf{n}}\right)$Real (Kind=nag_wp) array Output
On exit: the $n$ pseudorandom numbers from the specified Weibull distribution.
6: $\mathbf{ifail}$Integer Input/Output
On entry: ifail must be set to $0$, $-1$ or $1$ to set behaviour on detection of an error; these values have no effect when no error is detected.
A value of $0$ causes the printing of an error message and program execution will be halted; otherwise program execution continues. A value of $-1$ means that an error message is printed while a value of $1$ means that it is not.
If halting is not appropriate, the value $-1$ or $1$ is recommended. If message printing is undesirable, then the value $1$ is recommended. Otherwise, the value $0$ is recommended. When the value $-\mathbf{1}$ or $\mathbf{1}$ is used it is essential to test the value of ifail on exit.
On exit: ${\mathbf{ifail}}={\mathbf{0}}$ unless the routine detects an error or a warning has been flagged (see Section 6).
## 6Error Indicators and Warnings
If on entry ${\mathbf{ifail}}=0$ or $-1$, explanatory error messages are output on the current error message unit (as defined by x04aaf).
Errors or warnings detected by the routine:
${\mathbf{ifail}}=1$
On entry, ${\mathbf{n}}=⟨\mathit{\text{value}}⟩$.
Constraint: ${\mathbf{n}}\ge 0$.
${\mathbf{ifail}}=2$
On entry, ${\mathbf{a}}=⟨\mathit{\text{value}}⟩$.
Constraint: ${\mathbf{a}}>0.0$.
${\mathbf{ifail}}=3$
On entry, ${\mathbf{b}}=⟨\mathit{\text{value}}⟩$.
Constraint: ${\mathbf{b}}>0.0$.
${\mathbf{ifail}}=4$
On entry, state vector has been corrupted or not initialized.
${\mathbf{ifail}}=-99$
An unexpected error has been triggered by this routine. Please contact NAG.
See Section 7 in the Introduction to the NAG Library FL Interface for further information.
${\mathbf{ifail}}=-399$
Your licence key may have expired or may not have been installed correctly.
See Section 8 in the Introduction to the NAG Library FL Interface for further information.
${\mathbf{ifail}}=-999$
Dynamic memory allocation failed.
See Section 9 in the Introduction to the NAG Library FL Interface for further information.
Not applicable.
## 8Parallelism and Performance
Background information to multithreading can be found in the Multithreading documentation.
g05ssf is threaded by NAG for parallel execution in multithreaded implementations of the NAG Library.
Please consult the X06 Chapter Introduction for information on how to control and interrogate the OpenMP environment used within this routine. Please also consult the Users' Note for your implementation for any additional implementation-specific information.
None.
## 10Example
This example prints the first five pseudorandom numbers from a Weibull distribution with shape parameter $1.0$ and scale parameter $2.0$, generated by a single call to g05ssf, after initialization by g05kff.
### 10.1Program Text
Program Text (g05ssfe.f90)
### 10.2Program Data
Program Data (g05ssfe.d)
### 10.3Program Results
Program Results (g05ssfe.r) | 1,433 | 5,111 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 49, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.5625 | 3 | CC-MAIN-2024-10 | latest | en | 0.492912 |
http://www.chegg.com/homework-help/questions-and-answers/following-signal-i-t-given-function-time-unit-time-1-second-unit-i-ampers-t-0-i-t-00-t-1-i-q657475 | 1,386,511,799,000,000,000 | text/html | crawl-data/CC-MAIN-2013-48/segments/1386163065834/warc/CC-MAIN-20131204131745-00072-ip-10-33-133-15.ec2.internal.warc.gz | 279,177,742 | 7,033 | matlab plotting
0 pts ended
The following signal i(t) is given as a function of time
( unit of time=1 second), unit of i in ampers:
t<0 i(t)=0
0<t<1 i(t)= 20 t
1<t<2 i(t)= -20(t-1)+20
t>2 i(t)=0
1.1 Sketch i(t) to scale.
1.2 Suppose y=i^2. Plot y and specify its values for alltime.
1.3 Write a matlab program to plot i(t) and y(t) as functions oftime.
The axes must be labeled. Attach your program. | 140 | 410 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.609375 | 3 | CC-MAIN-2013-48 | latest | en | 0.769139 |
https://www.jiskha.com/questions/150370/for-the-equation-i-just-gave-it-also-says-to-solve-it-by-letting-y-equal-each-side | 1,563,923,778,000,000,000 | text/html | crawl-data/CC-MAIN-2019-30/segments/1563195529737.79/warc/CC-MAIN-20190723215340-20190724001340-00079.warc.gz | 741,399,494 | 5,857 | # algebra
for the equation i just gave it also says to solve it by letting y equal each side fo the equation and graphing. there is a graph off to the side. so what does all this mean?
1. 👍 0
2. 👎 0
3. 👁 72
1. you would end up with
y = w + 3.14 which is a straight line on the w-y grid, w along the horizontal.
Its slope is 1 and the y-intercept is 3.14
the second equation would be
y = w + 3.19 after you simplify the right side.
It also has a slope of 1 but a y-intercept of 3.19, slightly higher.
So you have two parallel lines slightly apart, obviously they cannot meet, as a result, no solution as noted in my previous reply to the other posting.
1. 👍 0
2. 👎 0
posted by Reiny
2. y=-3x+2,y+3x=-4
parallel lines
1. 👍 0
2. 👎 0
posted by essance
## Similar Questions
1. ### Math problem help
This problem is so hard I've tried solving it but I keep getting stuck. Could someone help with showing the steps please... Solve the system of equations for x and y by letting a=1/x and b=1/y, x does not equal 0 and y does not
asked by Unknown on October 1, 2017
2. ### math (final trig problem)
Solve for x on the interval [0,π/2): cos^3(2x) + 3cos^2(2x) + 3cos(2x) = 4 I havent done trig for a while so what exactly does that mean in solving for x on that interval and how would i go about doing that? Where are you getting
asked by jacob on April 30, 2007
3. ### math
how would you solve for y in this problem: x=(y^2+3y)^(1/3) would it equal: y= x^3/y - 3 ? and what about this problem: x= 1/[(y^2+3y-5)^3] would it equal: y = y/x + 5/y - 3? I would appreciate your help very much! Your equation
asked by kristie on June 27, 2006
4. ### Math
1) When will the dependent variable in the equation y=√x+4-3 equal or exceed to 4? A) x > or equal to -0.17 B) x > or equal to 45 C) x > or equal to 48 D) x > or equal to 53 2) The function t=√d/16 models the time (t) in
asked by Tia on April 7, 2015
5. ### Trigonometry
Hi, I really need help in understanding how to solve trig equations. How do you solve this equation? Solve the equation on the interval 0 < or equal to x < or equal to 2pi. sinx = (square root of 3)/2 I appreciate your help. Thank
asked by Leah on March 17, 2013
6. ### physics ap
we'l find the time, t, for the ball to fall from the tabletop to the floor. use the equation Δy=viΔt+at^2/2. Take the vi to be zero and a to be 9.81 ±.02 m/s^2. you must first solve this equation for t. Δy=.922m what am i
asked by Anthony on February 4, 2017
7. ### Math
What is the solution to the nearest tenth to the equation below? -3x -14 less than or equal to -5 * sorry if í wrote the question weird but í couldn't do some equation signs* A. X less than or equal to -3 B. X less than or equal
asked by Anonymous on August 28, 2017
8. ### Algebra
I have some problems that I am having trouble with and I have some that need checking please. Thanks! Solve the equation. 4. (x+7/4)=2(x-1/6) Find all the value(s) of x that make thedenominator(s) zero. Then solve the equation. 6.
asked by Soly on August 21, 2007
9. ### math
Can someone help me figure this out. The difference of two numbers is 80. The second is 8 less than 5 times the first. What are the two numbers? first write an equation 5x-8=y and then solve it Tiff gave you part of the solution.
asked by jessica on May 7, 2007
10. ### math
just an algebra question. how would you solve: (3x^2 +5)(3x^2 +5) ^ means power :] Since you have not given us an equation, it is impossible to "solve" your problam. Please repost with the complete equation, so we can help you. I
asked by Kelly on September 5, 2006
More Similar Questions | 1,136 | 3,614 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.9375 | 4 | CC-MAIN-2019-30 | latest | en | 0.955133 |
https://www.wilsondailyprep.com/the-game-of-math/ | 1,548,287,468,000,000,000 | text/html | crawl-data/CC-MAIN-2019-04/segments/1547584431529.98/warc/CC-MAIN-20190123234228-20190124020228-00187.warc.gz | 981,522,997 | 16,542 | # The Game of Math
Just the other day I yelled at my 7th grader for using his calculator to answer a simple math problem. Being able to do math computations without the assistance of a “device” is important. Yet, the SAT and ACT do not require, or want, school based math. The tests don’t care if a student can rationalize radicals or add fractions- they care about students’ math reasoning skills. In order for students to shine on test day, they must know various problem-solving strategies. So, mathematicians and math teachers, please forgive us for the following three IMPORTANT strategies:
## PICKING NUMBERS
Picking numbers is typically used for questions that have variables in the answer choices, although it can apply to many other question types as well. If you see variables in the answer choices, your first instinct should be to pick numbers. Pick simple numbers and evaluate the question using your numbers, not variables. Plug your numbers into the answer choices and see which answer matches. You should always go through all answer choices, as more than one may be correct. If this occurs, try again with new numbers.
## WORKING BACKWARDS
If a question is asking for the value of x, or any numerical answer, it is sometimes best to look at the answer choices and plug them back into the problem, looking for the one that will work. Remember, on the SAT, numerical answer choices are arranged from least to greatest, so we always start with choice “C,” the number in the middle.
## THINK SUM
When you see average (mean) problems, you want to think “SUM.” For example, if the problem states, “In a group of 5 students the average age is 12,” you know that the sum of ages of the students is 60. | 368 | 1,717 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.765625 | 4 | CC-MAIN-2019-04 | longest | en | 0.943497 |
http://www.ask.com/web?qsrc=3053&o=102140&oo=102140&l=dir&gc=1&qo=popularsearches&ad=dirN&q=How+To+Change+Fractions+To+Decimals++Percentages | 1,485,096,286,000,000,000 | text/html | crawl-data/CC-MAIN-2017-04/segments/1484560281426.63/warc/CC-MAIN-20170116095121-00138-ip-10-171-10-70.ec2.internal.warc.gz | 354,893,823 | 14,418 | Web Results
## Converting percents to decimals & fractions example (video) | Khan ...
Converting percents to decimals & fractions example. About. Sal writes 18% as a decimal and as a fraction. Created by Sal Khan and Monterey Institute for ...
## Decimals, Fractions and Percentages - Math is Fun
www.mathsisfun.com/decimal-fraction-percentage.html
Decimals, Fractions and Percentages are just different ways of showing the same ... To convert from percent to decimal: divide by 100, and remove the "%" sign.
## Converting Fractions, Decimals, and Percents - Fact Monster
www.factmonster.com/ipka/A0881930.html
Converting fractions, decimals, and percents formulas and examples. ... If there is one decimal place, put the number over 10 and reduce. If there are two places, ...
May 23, 2012 ... Fraction to decimal and percent, step by step, example. For all free math videos visit http://Mathmeeting.com.
Apr 12, 2008 ... Stop the crappy youtube ads by going to www.adblockplus.org and installing the adblock toolbar. It works. How to change fraction numbers to ...
## Percents: Converting Percentages, Decimals, and Fractions - Page 1
www.gcflearnfree.org/percents/converting-percentages-decimals-and-fractions/1/
Jun 27, 2016 ... Learn all about converting decimals, as well as converting percentages and fractions, in this free basic math lesson.
## Converting fractions, decimals and percentages - BBC
www.bbc.co.uk/education/guides/z7trd2p/revision
Learn about and revise how to convert between fractions, decimals and percentages with BBC Bitesize GCSE Maths.
## Converting Between Percents, Decimals, and Fractions ... - Math Aids
www.math-aids.com/Percent/Convert_Between_PDF.html
This Percent Worksheet is great for practicing converting between percents, decimals, and fractions. You may select six different types of percentage conversion ...
## Converting Between Decimals, Fractions, and Percents | Purplemath
www.purplemath.com/modules/percents.htm
Reviews how to convert between percents, fractions, and decimals.
## Convert between Fraction, Decimal and Percent Worksheets
www.mathworksheets4kids.com/convert.php
Printable worksheets that will help students practice converting between fractions , decimals and percent. | 517 | 2,260 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.1875 | 3 | CC-MAIN-2017-04 | latest | en | 0.795441 |
http://www.cfd-online.com/Forums/fluent/32652-about-large-minus-absolute-pressure-print.html | 1,477,289,194,000,000,000 | text/html | crawl-data/CC-MAIN-2016-44/segments/1476988719468.5/warc/CC-MAIN-20161020183839-00383-ip-10-171-6-4.ec2.internal.warc.gz | 368,786,054 | 2,386 | CFD Online Discussion Forums (http://www.cfd-online.com/Forums/)
- FLUENT (http://www.cfd-online.com/Forums/fluent/)
richard December 5, 2003 07:25
in my case, i simulate a tunnel with a 30 degrees downstream slope.there is a free surface in the tunnel with water flowing through it. the boundary conditions are: two inlets with velocity inlet for water and pressure inlet for air on the upstream, and the gauge total pressure is set to 0; and one outlet with pressure outlet, and the gauge pressure is set to 0.i initialized the porblem with water full of the tunnel and the x-orientation velocity is set to 23m/s,the water inlet velocity.then i start the simulation, and soon after the start, there is a very high pressure of about 5*10^6Pa existing near the inlet, and the solution is converged and the iterate goes on.the time step is 0.0001s and about 5s later, the absolute pressure becomes minus and decrease further more with iteration process. the absolute pressure limit of above 0 doesn't work! does someone meet such situation? how to explain such things i meet? thanks in advance.
Guest December 5, 2003 10:12
Re: about large minus absolute pressure
the absolute pressure limit works only for compressible flows
richard December 6, 2003 09:46
Re: about large minus absolute pressure
thanks, thanks, thanks so much, guest, you really help me.
richard December 6, 2003 10:39
Re: about large minus absolute pressure
and some other questions, dear guest.i am now confused by them. in my simulation, there exists very pressure and velocity that shouldn't be there in real physics.and the calculation shows that there is minus pressure on the upstream and plus one downstream, which is also nonphysical.and the third strange phenomenon is that the pressure in the middle of the water domain(where there mixed in 1mm diameter air bubbles to some degree of the air volume fraction is about 0.2) is minus, where the pressure is the total of gauge pressure and pressure caused by gravity, which is above 0 at least. would you like to explain them for me?thanks a lot.
All times are GMT -4. The time now is 02:06. | 502 | 2,134 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.109375 | 3 | CC-MAIN-2016-44 | latest | en | 0.94164 |
https://www.slideshare.net/satyenrc/nc-machine | 1,638,071,019,000,000,000 | text/html | crawl-data/CC-MAIN-2021-49/segments/1637964358443.87/warc/CC-MAIN-20211128013650-20211128043650-00390.warc.gz | 1,118,450,861 | 45,368 | Successfully reported this slideshow.
We use your LinkedIn profile and activity data to personalize ads and to show you more relevant ads. You can change your ad preferences anytime.
Upcoming SlideShare
Loading in …5
×
of
Upcoming SlideShare
NC, CNC & DNC Machine
Next
Download to read offline and view in fullscreen.
56 Likes
Share
# Nc Machine
Basic of NC Machine
See all
See all
### Nc Machine
1. 1. Numerical Control Machine Aim : To study about NUMERICAL CONTROL(NC) Machine Tools. Introduction: Numerical Control (NC) refers to the method of controlling the manufacturing operation by means of directly inserted coded numerical instructions into the machine tool. It is important to realize that NC is not a machining method, rather, it is a concept of machine control. Although the most popular applications of NC are in machining, NC can be applied to many other operations, including welding, sheet metalworking, riveting, etc. History: The invention of numerical control has been due to the pioneering works of John T. Parsons in the year 1940, when he tried to generate a curve automatically by milling cutters by providing coordinate motions. In the late 1940s Parsons conceived the method of using punched cards containing coordinate position system to control a machine tool. The machine directed to move in small increments and generate the desired finish. In the year, 1948, Parons demonstrated this concept to the US Air Force, who sponsored the series of project at laboratories of Massachusetts Institute of Technology (MIT). After lots of research MIT was able to demonstrate first NC prototype in the year 1952 and in the next year they were able to prove the potential applications of the NC. Concept: PRINCIPLE OF NUMERICAL CONTROL “a system in which actions are controlled by direct insertion of numerical data at some point. The system must automatically interpret this data.” Numerical control, popularly known as the NC is very commonly used in the machine tools. Numerical control is defined as the form of programmable automation, in which the process is controlled by the number, letters, and symbols. In case of the machine tools this programmable automation is used for the operation of the machines. In numerical control method the numbers form the basic program instructions for different types of jobs; hence the name 1
2. 2. Numerical Control Machine numerical control is given to this type of programming. When the type of job changes, the program instructions of the job also change. It is easier to write the new instructions for each job, hence NC provides lots of flexibility in its use. Program Machine Instructions Control Unit Transformation Process Power BASIC BLOCK DIAGRAM The NC technology can be applied to wide variety of operations like drafting, assembly, inspection, sheet metal working, etc. But it is more prominently used for various metal machining processes like turning, drilling, milling, shaping etc. Due to NC all the machining operations can be performed at the fast rate resulting in bulk manufacturing becoming quite cheaper. NC Coordinate Systems: For flat and prismatic (blocklike) parts: Milling and drilling operations Conventional Cartesian coordinate system Rotational axes about each linear axis 2
3. 3. Numerical Control Machine For rotational parts: Turning Operation Only x and zaxes Components of the Numerical Control System: There are three important components of the numerical control or NC system. These are: 1) Program of instructions 2) Controller unit, also called as the machine control unit (MCU) and 3) Machine tool All these have been shown in the figure below and also described in the subsequent sections. 1) Program of Instructions The typical desktop program gives the instructions to the computers to perform certain functions. The program of instructions of the NC machine is the stepbystep set of instructions that tells the machines what it has to do. operations. 3
4. 4. Numerical Control Machine One can also input the instructions directly into the controller unit manually, this method is called as manual data input (MDI), which is used for very simple jobs. Then there is direct numerical control method (DNC) in which the machines are controlled by the computers by direct link omitting the tape reader. Program Instruction MCU Machine Tool 2) Controller Unit or Machine Controller Unit (MCU) The controller unit is most vital parts part of the NC and CNC machines. The controller unit is made of the electronics components. It reads and interprets the program of instructions and converts them in the mechanical actions of the machine tool. Thus the controller unit forms an important link between the program and the machine tool. The control unit operates the machines as per the set of instructions given to it. The typical control unit comprises of tape reader, a date buffer, signal output channels to the machine tools, feedback channel from the machine tool, and the sequence control to coordinate the overall machining operation. 4
5. 5. Numerical Control Machine Control Systems of NC Machine: (1) OpenLoop Control (2) ClosedLoop Control (1)OpenLoop Control Stepper motor system Current pulses sent from control unit to motor Advantages Less complex, Less costly, and lower maintenance costs Limitations Control unit “assumes” desired position is achieved No positioning compensation Typically, a lower torque motor (2)ClosedLoop Control Variable DC motors Servos Positioning sensors Resolvers Feedback to control unit Position information compared to target location Location errors corrected 5
6. 6. Numerical Control Machine Advantages DC motors have the ability to reverse instantly to adjust for position error Error compensation allows for greater positional accuracy (.0001”) DC motors have higher torque ranges vs.. stepper motors Limitations Cost 3) Machine Tool It is the machine tool that performs the actual machining operations. The machine tool can be any machine like lathe, drilling machine, milling machine etc. The machine tool is the controlled part of the NC system.. Motion control : (1) Point to Point (PTP) (2) Continuous (Contouring) Path 6
7. 7. Numerical Control Machine (1) Point to Point (PTP) To move the machine table or spindle to a specified position so that machining operations may be performed at that point. Path taken to reach the specific point is not defined. Movement from one point to the next is nonmachining, it is made as rapidly as possible. (2) Continuous (Contouring) Path To control two or more axes simultaneously to get desired shape. To control not only the destinations, but also the paths through which the tool reaches these destinations. In the process of machining, the tool contacts the workpiece. 7
8. 8. Numerical Control Machine Role of the Operator: Execute Machine Control Unit (MCU) or Console Setups Start and Stop Machines Load and Unload Workpieces Maintain High Level Machine Tool Performance Standards Change NC Inputs as Necessary (Per Engineering) “Feedback” Information to Programmer/Engineer Two ways information is fed into an NC machine: 1. Auxiliary Operations: Tool change, spindle reversal, tool on/off, coolant on/off, spindle speeds (RPM), spindle feeds (IPM) 2. Geometrical Machine Movements: a) Translation – X , Y , Z b) Rotation – about X , Y , Z axis Any movement under control of NC input is called an axis. 2 axis machine: X,Y control (usually lathe) 3 axis machine: X,Y,Z control 4 axis machine: X,Y,Z, one rotational control 5 axis machine: X,Y,Z, two rotational control 8
9. 9. Numerical Control Machine Applications of NC: Batch and High Volume production Repeat and/or Repetitive orders Complex part geometries Mundane operations Many separate operations on one part Costs: High investment cost High maintenance effort Need for skilled programmers High utilization required Benefits: Cycle time reduction Nonproductive time reduction Greater accuracy and repeatability Lower scrap rates Reduced parts inventory and floor space Operator skilllevel reduced Greater operator efficiency Greater operator safety Reduction of scrap NC used to: 1) Position cutter (move table) 2) Change tooling 3) Adjust coolant flow (flood/miston/off) 4) Adjust spindle speeds 5) Perform operations at a point (plunge, tap, bore, etc.) 9
• #### PoonamTagade
Mar. 17, 2021
Mar. 2, 2021
• #### ShaikBasha90
Feb. 11, 2021
Feb. 7, 2021
• #### KrishnaVerma47
Oct. 25, 2020
• #### MidhunRaj44
May. 25, 2020
• #### RaviPrajapati124
May. 25, 2020
• #### MukulTyagi31
Apr. 10, 2020
• #### AppuBj1
Mar. 14, 2020
Dec. 5, 2019
• #### MuneshKumar86
Nov. 13, 2019
• #### GangadharGanthakuri
Oct. 28, 2019
Oct. 9, 2019
• #### PavanaKumaraB
Aug. 10, 2019
Aug. 4, 2019
• #### RenukaBharati
May. 16, 2019
Apr. 6, 2019
Mar. 3, 2019
• #### ShubhamRai85
Dec. 29, 2018
• #### PoreddyJayakrishna
Dec. 25, 2018
Basic of NC Machine
Total views
53,142
On Slideshare
0
From embeds
0
Number of embeds
8
Downloads
1,213
Shares
0
Comments
0
Likes
56 | 3,363 | 9,658 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.796875 | 3 | CC-MAIN-2021-49 | latest | en | 0.18893 |
https://artofproblemsolving.com/wiki/index.php/1950_AHSME_Problems/Problem_44 | 1,713,118,846,000,000,000 | text/html | crawl-data/CC-MAIN-2024-18/segments/1712296816893.19/warc/CC-MAIN-20240414161724-20240414191724-00437.warc.gz | 92,786,282 | 11,137 | # 1950 AHSME Problems/Problem 44
## Problem
The graph of $y=\log x$
$\textbf{(A)}\ \text{Cuts the }y\text{-axis} \qquad\\ \textbf{(B)}\ \text{Cuts all lines perpendicular to the }x\text{-axis} \qquad\\ \textbf{(C)}\ \text{Cuts the }x\text{-axis} \qquad\\ \textbf{(D)}\ \text{Cuts neither axis} \qquad\\ \textbf{(E)}\ \text{Cuts all circles whose center is at the origin}$
## Solution
The domain of $\log x$ is the set of all $\underline{positive}$ reals, so the graph of $y=\log x$ clearly doesn't cut the $y$-axis. It therefore doesn't cut every line perpendicular to the $x$-axis. It does however cut the $x$-axis at $(1,0)$. In addition, if one examines the graph of $y=\log x$, one can clearly see that there are many circles centered at the origin that do not intersect the graph of $y=\log x$. Therefore the answer is $\boxed{\textbf{(C)}\ \text{Cuts the }x\text{-axis}}$. | 288 | 883 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 12, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.734375 | 4 | CC-MAIN-2024-18 | latest | en | 0.718907 |
https://softwareengineering.stackexchange.com/questions/331834/how-to-fit-k-length-arrays-to-number-of-bigger-arrays/331849 | 1,582,947,407,000,000,000 | text/html | crawl-data/CC-MAIN-2020-10/segments/1581875148375.36/warc/CC-MAIN-20200229022458-20200229052458-00319.warc.gz | 564,763,115 | 30,991 | # How to fit k-length arrays to number of bigger arrays?
I have n number of one-dimensional arrays similar to:
``````[0,0,0,0,0,1,1,1,0,0,1,1,...]
``````
0's and 1's indicating occupation.
And k number of smaller arrays similar to:
``````[2,2,2], [2,2], [2], [2,2,2,2]
``````
with varying sizes. What I want to do is to see where and how I can fit the smaller (second) arrays to bigger arrays following each other buy indexes. Example:
``````Domain Arrays:
[0000111001]
[0011011001]
[0011100001]
[0000100001]
Smaller Arrays:
[22]
[2]
[222]
Result:
[0020111001]
[2211011001]
[0012220001]
[0000100001]
``````
or
``````[0000111001]
[0011011001]
[0012200001]
[0020122201]
``````
I hope I could put it into words well.
My solution is:
Finding empty spots that can fit any of the smaller arrays. And creating a tree with possible combinations like;
1-First small array goes to second big arrays 3rd index and occupies 3 spaces 2-Second small array goes to first big arrays 7th index and occupies 4 spaces
etc.
and I get the patterns of every branch on the tree with depth of smaller array count. But it of course works slowly. Which algorithms can I use to solve this problem? Thank you in advance.
• What you're talking about looks like Memory Management, which is a fairly broad field with lots of algorithms you can study up on. – Erik Eidt Sep 23 '16 at 15:40
• Yes! that's what I thought but couldn't be sure which algorithms are used on finding available empty spaces. – ag0702 Sep 23 '16 at 15:41
• I think this sort of question would be better on Computer Science.SE – Tersosauros Oct 14 '16 at 14:54 | 476 | 1,621 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.84375 | 3 | CC-MAIN-2020-10 | latest | en | 0.928725 |
http://mathcircles.org/node/462 | 1,498,411,709,000,000,000 | text/html | crawl-data/CC-MAIN-2017-26/segments/1498128320545.67/warc/CC-MAIN-20170625170634-20170625190634-00050.warc.gz | 265,545,993 | 7,726 | roles) || in_array('administrator', $user->roles) || in_array('admin',$user->roles ) ) { ?>
probname); ?>
Topic Classification: nid, "Topic Classification"); ?> Tags: nid, "Problem Tag");?>
Topics: nid, "Topics"); ?> Prerequisites: nid, "Prerequisites"); ?>
Supplies: nid, "Supplies"); ?> Pedagogy: nid, "Pedagogy"); ?>
1-2
3-4
5-6
7-8
9-10
11-12
13-14
Solution: nid, "Solution"); ?>
Problem
Given a set of $3n+1$ objects, assume that $n$ are
indistinguishable, and the other $2n+1$ are distinct. Show that
we can choose $n$ objects from this set in $2^{2n}$ ways.
Details
Contributer: TRD
Authors
nid); while ($data = db_fetch_object($authorresult)) { $authorfirstname =$data->firstname; $authorlastname =$data->lastname; $authors =$authorfirstname . ' ' . $authorlastname; print$authors; ?>
References
nid); if (mysql_num_rows($refresult) > 0 ) { ?> nmcreferenceid;$referenceauthor = $data->author;$referencetitle = $data->title;$referenceurl = $data->url; ?> 0 ) { print ' Reference Author Reference Title Reference URL '; } ?> nid);$totalSets = mysql_num_rows($setsResult); if ($totalSets > 0) { ?>
Problem Sets This Problem Belongs to:
parent_nid; ?> Set:
VARIABLES
nid, 1); while ($data = db_fetch_object($variablesresult)) { $variable =$data->elementdata; ?> •
DEFINITIONS
nid); while ($data = db_fetch_object($defresult)) { $definitionid =$data->nmcdefinitionid; $definition =$data->definition; $definitionname =$data->definitionname; ?> • | 426 | 1,452 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.875 | 3 | CC-MAIN-2017-26 | latest | en | 0.376093 |
https://www.jiskha.com/display.cgi?id=1317942328 | 1,516,167,938,000,000,000 | text/html | crawl-data/CC-MAIN-2018-05/segments/1516084886815.20/warc/CC-MAIN-20180117043259-20180117063259-00609.warc.gz | 920,977,126 | 4,009 | posted by .
Hung vertically, a massless spring extends by 3.00 cm when a mass of 992.0 g is attached to its lower end. The same mass and spring are then placed apart on a table. The spring is fixed in place and then the mass is given a velocity of 0.800 m/s towards the spring.
a) What is the maximum compression of the spring when the mass runs into it?
b) After compressing the spring the mass will rebound. What is its velocity just as it leaves contact with the spring?
a, find k. k= mg/x (in change grams to kg, cm to m).
then, 1/2 mv^2= 1/2 k x^2
solve for x, the max compression.
b. it will rebound with a velocity of .800m/s, of course...if the spring is massless..
thanks!
## Similar Questions
1. ### Physics Spring
A mass sitting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. 1.0 J of work is required to compress the spring by 0.12 m. If the mass is released from rest with the spring …
2. ### Physics
A spring is hung from a ceiling, and an object attached to its lower end stretches the spring by a distance of 5.00 cm from its unstretched position when the system is in equilibrium. If the spring constant is 54.1 N/m, determine the …
3. ### physics
A spring (k = 400 N/m) is hung vertically. a) If a 5 kg mass is attached to the end of the spring and gently lowered to rest position, what will be the stretch of the spring?
4. ### Physics
A spring id vertically, as shown below, and a 500g mass is hung from its lower end. The EQUILIBRIUM extension of the spring is observed to be 10.0cm. (I) What is the spring constant of the spring?
5. ### Physics
A spring id vertically, as shown below, and a 500g mass is hung from its lower end. The EQUILIBRIUM extension of the spring is observed to be 10.0cm. (1) What is the spring constant of the spring?
6. ### Physics
Hung vertically, a mass less spring extends by 3.00 cm a mass of 739. G is attached to its lower end. The same mass and spring are then placed apart on a table. The spring is fixed in place and then the mass is given a velocity of …
7. ### Physics
A massless spring, with K=425 N/m, is hung vertically with the bottom end of the spring at position Y.i. A 3.50 kg mass is attached to the bottom of the spring and allowed to fall and oscillate. A) How far below Y.i does the mass fall …
8. ### physics
A steel spring is hung vertically. Using a ruler, the lower end of the spring was measured to be 25.0cm from its upper end. However, when an object of mass 0.500kg it attached to the lower end of the spring the spring stretches to …
9. ### physics
A steel spring is hung vertically. Using a ruler, the lower end of the spring was measured to be 25.0cm from its upper end. However, when an object of mass 0.500kg it attached to the lower end of the spring the spring stretches to …
10. ### Physics
A steel spring is hung vertically. Using a ruler, the lower end of the spring was measured to be 25.0cm from its upper end. However, when an object of mass 0.500kg it attracted to the lower end of the spring the spring stretches to …
More Similar Questions | 805 | 3,111 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.125 | 3 | CC-MAIN-2018-05 | latest | en | 0.923992 |
https://finnstats.com/2022/03/15/how-to-calculate-a-bootstrap-standard-error-in-r/ | 1,718,372,060,000,000,000 | text/html | crawl-data/CC-MAIN-2024-26/segments/1718198861546.27/warc/CC-MAIN-20240614110447-20240614140447-00703.warc.gz | 239,507,160 | 15,295 | # How to Calculate a Bootstrap Standard Error in R
Bootstrap Standard Error in R, Bootstrapping is a technique for calculating the standard error of a mean.
The following is the basic procedure for calculating a bootstrapped standard error.
Model Selection in Machine Learning » finnstats
From a given dataset, take k repeated samples using replacement and calculate the standard error for each sample: s/√n
As a result, there are k distinct standard error estimates. Take the mean of the k standard errors to get the bootstrapped standard error.
The following examples show how to calculate a bootstrapped standard error in R using two distinct methods.
## Approach 1: Boot Package
The boot() function from the boot library is one technique to calculate a bootstrap standard error in R.
In R, the following code demonstrates how to compute a bootstrap standard error for a given dataset.
Let’s take the example reproducible
`set.seed(123)`
`library(boot)`
We can define the dataset
`x <- c(112, 64, 84, 78, 67, 221, 125, 219, 45, 79)`
Let’s create a function to calculate mean
`meanF <- function(x,i){mean(x[i])}`
Okay, now we can calculate standard error using 500 bootstrapped samples
`boot(x, meanF, 5000)`
```ORDINARY NONPARAMETRIC BOOTSTRAP
Call:
boot(data = x, statistic = meanF, R = 5000)
Bootstrap Statistics :
original bias std. error
t1* 109.4 -0.13972 18.41172```
The “original” number of 109.4 represents the dataset’s mean. The bootstrap standard error of the mean is represented by the value 18.41 in the “std. error” column.
NLP Courses Online (Natural Language Processing) » finnstats
In this example, we used 5000 bootstrapped samples to estimate the standard error of the mean, but we could have used 1,000, 10,000, or any other number of bootstrapped samples.
## Approach 2: Own Formula
We can also construct our own code to calculate a bootstrapped standard error.
The code below demonstrates how to do so:
create a repeatable example
`set.seed(123)`
`library(boot)`
```x <- c(112, 64, 84, 78, 67, 221, 125, 219, 45, 79) | 539 | 2,079 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.359375 | 3 | CC-MAIN-2024-26 | latest | en | 0.711916 |
https://amp.doubtnut.com/question-answer/in-a-a-b-c-if-a-b330-and-b-c180-then-b-350-b-450-560-d-550-1532700 | 1,611,841,919,000,000,000 | text/html | crawl-data/CC-MAIN-2021-04/segments/1610704847953.98/warc/CC-MAIN-20210128134124-20210128164124-00438.warc.gz | 197,753,797 | 22,951 | IIT-JEE
Apne doubts clear karein ab Whatsapp (8 400 400 400) par bhi. Try it now.
This browser does not support the video element.
Question From class 7 Chapter PROPERTIES OF TRIANGLES
# In a if and then (b) (d)
In a if and then (b) (d)
1:48
In a quadrilateral is 2 times If then (b) (c) (d) None of these
2:22
is a parallelogram in which diagonal bisects If , then (b) (c) (d)
1:55
In and ray bisects the exterior angle (b) (c) (d)
2:54
Diagonals of a quadrilateral bisect each other. If then (b) (c) (d)
1:37
If in any then find
1:23
In a if find
1:23
In a If then the measure of the smallest angle is (b) (d)
2:11
If in a , find the ratio of its sides.
1:42
In a parallelogram , if then (b) (c) (d)
3:43
In Figure, is a straight line. If then (a) (b) (c) (d)
1:34
In if bisects . Then, (b) (c) (d)
1:03
In bisects such that and lie on side Find
3:02
draw in which Measure
1:14
Latest Blog Post
JEE Main 2021 Exam Application Correction Window Open from Jan 27
JEE Main 2021 Feb exam application correction window opens from 27th to 30th Jan 2021. Know steps to edit the application form, fee, syllabus & admit card.
Happy 72nd Republic Day 2021
Doubtnut wishes all the students and parents a Happy 72nd Republic day 2021! Parade will be the 1st prominent public event amid Covid-19.
National Girl Child Day 2021: Nurturing & Empowering Girls
Happy National girl child day 2021. Know the reason & importance of national girl child day celebrated on 24th January every year. Also learn facts, themes & more.
JEE advanced 2021 syllabus has been released by IIT Kharagpur. Get details of new syllabus, exam pattern & step-by-step process to download syllabus.
JEE Syllabus 2021: NTA Releases Syllabus for JEE Main 2021
JEE Main 2021 syllabus released by NTA. Know here the details of the new syllabus, step-by-step process to download the JEE Syllabus 2021 and other details.
JEE Main 2021: 75 Percent Criteria Exempted for NITs, IIITs Admissions
JEE Main 75% criteria exempted for NITs, IIITs admissions as well. Know the extended last date of registration, exam eligibility, syllabus reduction & etc for JEE main 2021.
FAQs on Properties Of Triangles | 665 | 2,159 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.734375 | 3 | CC-MAIN-2021-04 | latest | en | 0.712925 |
https://everything2.com/title/Think+of+a+number | 1,548,101,720,000,000,000 | text/html | crawl-data/CC-MAIN-2019-04/segments/1547583807724.75/warc/CC-MAIN-20190121193154-20190121215154-00074.warc.gz | 539,919,086 | 6,278 | The phrase at the beginning of a number of silly number games and tricks, which usually are supposed to prove something about the mind-reading powers of the demonstrator, often a magician or math teacher. Of course, they usually have more to do with illusion, basic math, or coincidence.
For example:
Think of a number. Double it and add 2. Triple the result and add 3. Subtract the original number. Subtract 4 from the result. Subtract 5 and divide by 5. Wow, you're back at the original number! :P
Or, for slightly more advanced minds:
Think of a three-digit number in which each succeeding digit is smaller than its predecessor (752 for example). Reverse that number (257). Now subtract the smaller from the larger (752-257=495). Reverse that number (594). Now add the two together (495+594). No matter what your initial three-digit number was, you'll end up with 1,089. Wonders never cease.
Log in or register to write something here or to contact authors. | 219 | 965 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.296875 | 3 | CC-MAIN-2019-04 | longest | en | 0.89702 |
https://sunvillage.pl/news/2020-May-21_8324.html | 1,638,230,682,000,000,000 | text/html | crawl-data/CC-MAIN-2021-49/segments/1637964358847.80/warc/CC-MAIN-20211129225145-20211130015145-00430.warc.gz | 617,651,873 | 8,058 | # What Does A Cubic Metre Of Dolomite Weight
1. Home >>
2. News
3. >> What Does A Cubic Metre Of Dolomite Weight
### Weight Conversion Tables Littler Bulk Haulage
Weight Conversion Tables. How may tonnes in a cubic metre - This one of the many questions we are asked Dry sand fine 1.28 tonnes per cubic metre Dry sand coarse 1.6 tonnes per cubic metre Topsoil some moisture 1.44 tonnes per cubic metre Ballast 1.76 tonnes per cubic metre Gravel ...
### Standard Volumetoweight Conversion Factors
Feb 28, 2006 Standard Volume-to-Weight Conversion Factors Paper Product Volume Weight lbs Source Books, hardback, loose 1 cubic yard 529.29 Tellus Books, paperback, loose 1 cubic yard 427.5 Tellus Egg flats one dozen 0.12 U.S. EPA Egg flats 12 x12 0.5 U.S. EPA Paper sacks 25 size 0.5 U.S. EPA Paper sacks 50 dry goods 1 U.S. EPA ...
### Mass Weight Density Or Specific Gravity Of Bulk Materials
As 1000kg of pure water 1 cubic metre, those materials under 1000kgcu.m will float more dense will sink ie. those materials with a specific gravity more than 1. Pure water was chosen as the base line for specific gravity and given the value of 1.
### Material Weight By Volume
The exception is the Metals table, since there is seldom much variation in weight between different batches of the same metal I have given the weight per cubic metre reasonably accurately. Weights in lbsft 3 have been calculated at 116 kgm 3 and rounded out to the nearest pound, which should be accurate enough for roleplaying purposes.
### Standard Weights For Crushed Rock Per Meter Hunker
General Weights. Solid rock is estimated at 2.5 to 3tons per cubic meter. If rock is crushed into uniform sizes, the presence of open space between the particles causes the load to be lighter -- approximately 1.6 tons per cubic meter. Mixed sizes of crushed rock can range from 1.6 to 2.2 tons per cubic meter.
### Cubic Weight Calculator Dimensional Weight Calculator
Cubic Weight Definition. Freight transportation companies charge one of two rates for shipping. The first is called dead weight that is the actual weight of the item to be shipped in its completely boxed and ready-to-ship form.. The other possible weight that a freight company may use to calculate shipping costs is called cubic weight, and that is based on cubic feetmeters.
### How Much Does A Cubic Meter Of Soil Weigh
Apr 14, 2020 One cubic meter of soil weighs between 1.2 and 1.7 metric tonnes, or between 1,200 and 1,700 kilograms. These metric figures convert to between 2,645 and 3,747 pounds, or between 1.3 tons and 2.75 tons, per cubic meter. Loose topsoil is lighter, and compacted topsoil is heavier.
### How Much Does A Cubic Meter Of 20mm Stone Weigh
How much does 1 cubic meter of limestone weigh Yahoo. Jan 15 2011 0183 32 How much does 1 cubic meter of limestone weigh A solid cubic meter of limestone weighs 2611 kilograms A cubic meter of broken limestone weighs... Know More. Weight Of 1 Yard Of 34 Crusher Run Limestone.
### Cubic Meter To Square Meter M3 M2 Converter Endmemo
Conversion between cubic meter and square meter. Cubic meter to Square meter Calculator
### Metric Tonne Of Firewood To Cubic Meters
Feb 19, 2008 06-15-2013, 1236 PM. Re Metric tonne of firewood to cubic meters. ps, even if the density is 1tm3, you would get heaps more firewood out of a tonne than out of a chopped cubic meter, as there is lots of space between the pieces that weighs almost nothing, but is still part of the cubic meter. This holds true even when the firewood is well ...
### Sand Calculator How Much Sand Do You Need In Tons
How much does a cubic meter of sand weigh A cubic meter of typical sand weighs 1,600 kilograms 1.6 tonnes. A square meter sandbox with a depth of 35 cm weighs about 560 kg or 0.56 tonnes. The numbers are obtained using this sand calculator. How much is a ton of sand A ton of sand is typically about 0.750 cubic yards 34 cu yd, or 20 cubic feet.
### Sub Base Stone Mot And Scalpings Calculator
This form will calculate the approximate metric tonnes of unconsolidated DTp1 required for the entered area. Please enter the dimensions in the white fields below. The calculations will be completed when you leave the last input field. Dimensions Length in Metres Width in Metres Area in Sq Meters ...
### What Is The Weight Of Crusher Stone Sand For Cubic Meter
Convert Crusher Stone From Cubic Meters To Tonnes. 19mm stone ton to cubic met patric mani weight cubic yard crusher dust lch do not have a good conversion factor since they retain water weight so well they allow the operator to place stone much more precisely than a dump truckweight cubic yard crusher dustwhat does a cubic yard of crusher dust weigh what is the weight of crusher stone sand ...
### How Much The Volume 10 Meter Cube Of Uncrushed
What does 1 cubic yard of crushed ... How much does 1 cubic meter of ... A solid block of ice of the same volume weighs about 57.5 pounds. A cubic foot of normal ... Get More how much does 1 cubic meter of rock weigh BINQ Mining. How Much Crushed Stone Do I Need ... A cubic yard is any volume of material that is 3 feet long by 3 feet wide ...
### How Many Tons Of Dolimite Stone To A Cubic Meter
How many tons does a cubic meter of 19mm building stone weigh So 15 cubic metres of armourstone would weigh 15 x 1.8 tonnes 27 tonnes What is the conversion factor for 10 cubic meters of 19mm Crushed dolomite stone to tons cubic metres multipied by the density of dolomite 2.8 tm3 10 x 2.8 equals 28 tonnes
### Weights Of Various Metals In Pounds Per Cubic Foot
Dolomite 181.00 Weights of Other Materials in Pounds Per Cubic Foot Earth, Common Loam 75.00-90.00 Earth, DryLoose 76.00 Earth, DryPacked 95.00 Earth, MudPacked 115.00 Elm, White 45.00 Fats 58.00 Fir, Douglas 30.00 Fir, Eastern 25.00 Flour, Loose 28.00 Flour, Pressed 47.00 Gasoline 42.00 Glass, CommonWindow 156.00 Granite 170.00 Graphite 131.00
### Stone Weight Calculator
Stone Calculator. Choose a material you wish to obtain weight calculation from the Material Selection Box. Average density of the material for weight calculation will be shown in the DENSITY box with gcc as default unit. If you know the exact density of a specific material and wish to obtain the accurate instead of average weight,
### Material Weight Pounds Per Cubic Yard
FTruck Body Pricing amp BrochuresExcelCubicYardageChart DCubicYardageChart D Rev A 692015 AGGREGATE TYPE
### Concrete Mixes By Weight And Volume
Jul 30, 2013 Quantities of materials per cubic metre of concrete are net. Allow for wastage when ordering for instance 3 on cement and 10 on aggregates. A standard bag of cement weighs 50kg so the equivalent quantities and weights are 1 Bag cement 50kg 0.2 m 3 cubic metre
### Bulk Aggregates Order Quantity Calculator Aggregates
If you are unsure how much aggregate you need, use our calculator below. Select your aggregate type, then enter your measurements below. You will need 18.7 tonnes of this aggregate type. You will need 24.93 bulk bags of this aggregate type. You will need 935.00 mini bags of this aggregate type.
### Tonne Vs Cubic Metre Riverina Redgum Firewood
We frequently get asked what the difference between a tonne and cubic metre is. As a guide only 1 tonne of seasoned redgum is approximately 2 cubic metres stacked with as few gaps as possible or approximately 2.7 cubic metres loose. It is hard to work out which operators are
### How Much Does 1 Cubic Metre Of Crushed Sandstone Weigh
How much does 1 cubic metre of crushed sandstone weigh Products. As a leading global manufacturer of crushing, grinding and mining equipments, we offer advanced, reasonable solutions for any size-reduction requirements including, How much does 1 cubic metre of crushed sandstone weigh, quarry, aggregate, and different kinds of minerals.
### Gravel Calculator Easily Calculate How Much Gravel You Need
Calculating an accurate estimate of how much gravel or aggregate you need for a driveway is simple with our gravel calculator. All you need to know is the desired length and width of the driveway, along with what gravel depth you need. You can get an estimate right now using the calculator above.
### Weight Of 1 Cubic Meter Of M10 M15 M20 And M25 Concrete
Weight of 1 cubic meter concrete- 1 cubic metre of concrete weight around 2.4 metric ton 2400kgs, typically 1m3 of concrete is made up of about 350kg 7bags cement, 700 kg sand, 1200kg aggregate and about 150 litres of water without steel in it as per design
### How To Determine Weight For Overseas Air And Sea
Feb 12, 2015 The general average weight can be calculated based on 40 lbs 18.18 kg per article on the inventory list. If it is different than the 6.5 lbscubic foot, this will mean that there is not a normal mixture of HHG in the shipment. Example A shipment containing 100 items can get estimated at 4000 lbs or 615 cubic foot 17.38 cubic meters.
### Conversion Of Dolomite Ton To Cubic Meter
Dolomite, solid volume to weight conversion. About Dolomite, solid 1 cubic meter of Dolomite, solid weighs 2 899 kilograms kg 1 cubic foot of Dolomite, solid weighs 180.97866 pounds lbs Dolomite, solid weighs 2.899 gram per cubic centimeter or 2 899 kilogram per cubic meter, i.e. density of dolomite, solid is equal to 2 899 kgm .In Imperial or US customary measurement system, the ...
### Bulk Density Chart Anval
Dolomite 54 865 Dolomite Lime 46 737 Egg Yoke Powder 23 368 Eggs Powdered 22 352 Electrolyte 60 961 Epoxy Powder 49 785 Ferric Chloride 43 689 Ferric Sulphate 61 977 Ferro Silicate 78 1250 Ferro Silicon 87 1394 Ferrous Carbonate 87 1394 Fibreglass 22 352 Filter Cake Centrifuge 40 641 ...
### Conversion Guide Centenary Landscaping Supplies
Volume Required cubic metres X Conversion Rate Bulk Density For example, if you needed 3m 3 River Pebble 10mm, which has a 1.5 Tonne Bulk Density, you would multiply 3 x 1.5 which 4.5. So, 3m 3 4.5t of River Pebbles. For advice on how much of a product you need for your project, our sales team are here to help and can discuss with you ...
### Weights Of Common Substances Mythosa
Dec 23, 2015 0.92. 0.033. 57. This is the density of pure ice 917 kilograms per cubic metre at 0 C and atmospheric pressure. Most naturally occurring ice is less dense due to pockets of air, ranging from around 53 lbscubic foot on up. Ivory. 1.84. 0.066. 115.
### Tonnage Calculator Robinson Quarry Masters Limited
Tonnage calculator. Use our calculator to estimate how much you need. Simply enter in the dimensions of the area you need to fill and hit calculate. You can then enter your details to get a quotation by email - or if you are in a real hurry just give us a call and order over the phone. Sales 028 2583 1245.
### How Much Does A Cubic Metre Of Wood Weigh
Feb 05, 2020 The difference to note is weight the average density of UK hardwoods is about 700kg per solid cubic metre whilst the average density of softwoods is about 500kg per solid cubic metre. This means that you need about 1.35 cubic metres of softwood to be the equivalent of 1.0 cubic metre
### What Is The Weight Of Mortar Per Cubic Meter Amp Per Cubic
Weight of mortar per cubic meter. Mortar is looking as paste of mixture of various ingredients like Portland cement, sand and lime, some mortar have fly ash and dust, regarding this, what is the weight of mortar per cubic metre, generally on average weight of mortar is about 2162kg per cubic metre.
### How To Calculate Aldinga Landscape Supplies
Dolomite Sand Dolomite Sand Bag Dolomite Sand ... With mulches, 1 cubic meter will cover approximately 13 m2 70mm thick. So lets say you have 27m2 of area and want it covered at the recommended coverage of 70mm, you would need to purchase 2 cubic meters. ...
### Dolomite Solid Volume To Weight Conversion
About Dolomite, solid 1 cubic meter of Dolomite, solid weighs 2 899 kilograms kg 1 cubic foot of Dolomite, solid weighs 180.97866 pounds lbs Dolomite, solid weighs 2.899 gram per cubic centimeter or 2 899 kilogram per cubic meter, i.e. density of dolomite, solid is equal to 2 899 kgm .
### Weight Of One Cubic Metre Of Dolomite Help
Gravel, Dolomite weighs 1 865 kilogram per cubic meter or 116.43 pound per cubic foot. See this and other substances density in 285 measurement units. More details Get Price | 3,082 | 12,315 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.9375 | 3 | CC-MAIN-2021-49 | latest | en | 0.824642 |
https://www.physicsforums.com/threads/best-way-of-turning-rotational-motion-into-linear-motion.872218/ | 1,695,829,217,000,000,000 | text/html | crawl-data/CC-MAIN-2023-40/segments/1695233510300.41/warc/CC-MAIN-20230927135227-20230927165227-00622.warc.gz | 1,012,561,215 | 19,001 | Best way of turning rotational motion into linear motion?
• bendo112
You could also have your rod that applies pressure attached to a lead or ball screw and then turn its corresponding nut using a bevel gear attached to your bolt that you turn. Lead screws and ball screws can apply a very large axial force for a given torque used to turn it. That also means that pushing back against it would likely not move it since it only takes a little friction in your bolt to hold the lead screw steady.Lead screws and ball screws can apply a very large axial force for a given torque used to turn it.A lead screw will lock if the tangent of the thread angle is less than the coefficient of friction. A ball screw is a rolling ball mechanism so it is reversible, the coefficientf
bendo112
Hello everyone,
I am not an engineer, so I apologize if this is a relatively simple question. What's the best way to turn rotational motion into linear motion under the following circumstances?
1. Rotational motion is driven by a vertical bolt.
2. When turned, the bolt will extend a bar horizontally to apply pressure to an object.
3. The bar should remain fixed unless the bolt/screw is turned (there will be constant pressure exerted against the bar).
Hopefully I explained that clearly. Here's a link to a quick sketch:
https://www.dropbox.com/s/djyrgydd2j59b9l/drawing.png?dl=0 (sorry it turned out kind of small)
In my searches I came across a rack and pinion which looks like it could possibly work. However, it's not entirely clear to me if it can be designed to satisfy point #3? I look forward to your suggestions.
A scissor jack converts rotational motion into linear motion in the arrangement you want. You probably have one in your car boot.
Also google bottle jack, F-clamp, trigger clamp, (many vice jaws can be reversed to do expansion rather than compression, including trigger clamps & F clamps) for other ideas.
Failing all those, if you can provide more specs (travel, force applied, force exerted, cost etc etc) we can offer better/more suggestions.
Thanks for the quick reply. I should have mentioned some additional specs initially.
As far as additional specs, the housing containing the item will be a fairly small square at approximately 3"x3" and approximately 1/2" thick. So something low profile is ideal. An object will be attached to the housing and the idea is for the housing to be able to expand to fit multiple spaces which vary in size by up to 1.25", so the travel distance would need to be just above that. As far as force exerted, I'm not sure what the numbers look like, but I'm basically just looking for something that has enough force so that the housing stays in place if someone was to give it a strong tug to try and pull it out. It won't be used to support weight. For force applied, I'm not sure on that either, I was looking for something that could be tightened by a standard screw driver. For cost, the lower the better. I'm imagining it will have to be made out of metal or some type of strong plastic.
The rotating bolt could drive an eccentric or a cam. That could lock when over-centre.
Is the required extension always the same? If not, then consider a spring loaded pressure plate so as to fix the extension.
The simplest (and cheapest) method would be to thread the shank of your brown part, mating with a threaded hole in your black part. All you have to do is to turn the brown part to make it go in or out. If there are no large forces involved, you might even be able to do it by hand instead of needing a screwdriver. A jam nut may be added if vibrations are involved, to lock everything in place.
Thanks for the suggestions everyone. The required extension will be variable. I considered a spring loaded plate, but due to the height of the object the housing will be placed in, I think it would be difficult to use. The limiting factors are the height of the housing (needs to be around 1/2" high) and the height of the object the housing will be placed in (4" is a rough estimate). Here is an updated drawing with some addition explanations.
https://www.dropbox.com/s/cx3mtit0cnyusl7/updated drawing.png?dl=0
I also included an idea that appears like it should work, but maybe someone can offer some comments/suggestions.
You could also have your rod that applies pressure attached to a lead or ball screw and then turn its corresponding nut using a bevel gear attached to your bolt that you turn. Lead screws and ball screws can apply a very large axial force for a given torque used to turn it. That also means that pushing back against it would likely not move it since it only takes a little friction in your bolt to hold the lead screw steady.
Lead screws and ball screws can apply a very large axial force for a given torque used to turn it.
A lead screw will lock if the tangent of the thread angle is less than the coefficient of friction.
A ball screw is a rolling ball mechanism so it is reversible, the coefficient of friction is then irrelevant.
That excludes ball screws from consideration as locking devices. | 1,104 | 5,086 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.0625 | 3 | CC-MAIN-2023-40 | latest | en | 0.936191 |
https://ukedchat.com/2016/11/21/real-life-maths-potions-lesson-by-primarylessons/ | 1,656,432,861,000,000,000 | text/html | crawl-data/CC-MAIN-2022-27/segments/1656103556871.29/warc/CC-MAIN-20220628142305-20220628172305-00502.warc.gz | 638,712,161 | 27,299 | # Real Life Maths: Potions Lesson by @PrimaryLessons
This is a really good way of testing out practical measuring skills in Maths lessons.
I always teach ‘measuring‘ by incorporating a Harry Potter themed Potions lesson. Pupils follow potion recipes to create potions from the Harry Potter universe, e.g. Polyjuice Potion or Skele-gro. I have a mixture of powders (cornflour), plants (herbs) and potions (water with food colouring). I then have pipettes, a range of different containers with different scales for measuring liquids, scales for measuring the plants and powders, in addition to gloves for handling the ‘poisonous’ plants, a pestle and mortar for the plants and stopwatches for timing.
This is a re-blog post originally posted by Siobhán Morgan and published with kind permission.
The original post can be found here.
###### Submit your blog post for reblogging on UKEdChat.com by clicking here.
This lesson incorporates so many areas of measuring and could be extended for higher ability (maybe include conversions) and differentiated for lower ability easily. Fortunately we have a great Science department at our school, who are always able to provide me with an interesting collection of glass containers. Additionally, I have test tubes in a test tube rack, a bowl and a wooden spoon per pair.
Pupils follow the instructions in the recipes, choosing appropriate equipment. They then pour their final potion into a test tube to be judged. Teachers and teaching assistants always dress up in their Hogwarts robes for this lesson and pupils’ potions are then judged on ‘appearance’ and ‘aroma’.
To continue the Harry Potter theme, we judge them as if they are O.W.L.s (Ordinary Wizarding Levels) where pass grades are O (Outstanding), E (Exceeds Expectations), and A (Acceptable) with fail grades being P (Poor), D (Dreadful), and T (Troll). This continues the theme and provides the lesson with a clear structure. In the past I have also ‘sorted’ pupils into houses and then awarded house points, so there are many ways in which this can be extended.
The advantage of this kind of activity is that not only does it allow pupils the opportunity to test out skills they need to be able to apply, but it provides a memorable activity that engages even the most disengaged children and leaves them with an experience they will remember.
Images provided by Siobhán Morgan and used with permission.
You need to or Register to bookmark/favorite this content. | 530 | 2,478 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.8125 | 4 | CC-MAIN-2022-27 | longest | en | 0.94248 |
https://www.coursehero.com/file/87820/Finite-Chapter-63/ | 1,527,399,603,000,000,000 | text/html | crawl-data/CC-MAIN-2018-22/segments/1526794868003.97/warc/CC-MAIN-20180527044401-20180527064401-00447.warc.gz | 725,741,592 | 35,496 | {[ promptMessage ]}
Bookmark it
{[ promptMessage ]}
Finite Chapter 6.3
# Finite Chapter 6.3 - Math 120 SP08 Section 6.3 Notes...
This preview shows page 1. Sign up to view the full content.
Math 120 SP08 Section 6.3 Notes: Addition & Multiplication Principles Brodnick Examples : 1. You go to a restaurant where they are serving 2 beef dishes, 3 poultry dishes, and 4 seafood dishes. You get to choose any one entrée. How many choices do you have? 2. Same scenario, but you get to choose one entrée from each category. How many possible ways can you choose? * Addition Principle : * OR Add * Multiplication Principle : * AND Multiply Examples : 3. A license plate contains 4 digits followed by 3 letters. a. If there are no restrictions placed on the letters and digits used, how many plates are possible? b. If no repetition of letters or digits is allowed, how many plates are possible? c. If the first digit must be even, the second and third odd, followed by distinct vowels, how many plates are possible? d. If the plate must contain an odd digit followed by distinct even digits followed by distinct consonants, how many possibilities are there?
This is the end of the preview. Sign up to access the rest of the document.
{[ snackBarMessage ]}
### What students are saying
• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.
Kiran Temple University Fox School of Business ‘17, Course Hero Intern
• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.
Dana University of Pennsylvania ‘17, Course Hero Intern
• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.
Jill Tulane University ‘16, Course Hero Intern | 497 | 2,194 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.984375 | 3 | CC-MAIN-2018-22 | latest | en | 0.898204 |
http://www.asegbolu.com/2016/08/3rd-term-promotional-examination_1.html | 1,542,830,632,000,000,000 | text/html | crawl-data/CC-MAIN-2018-47/segments/1542039750800.95/warc/CC-MAIN-20181121193727-20181121214816-00009.warc.gz | 396,082,208 | 51,882 | Naija we hail oooo Una no dey fail oooo even when the country they wail lli oooo
Connect With Us
3RD TERM PROMOTIONAL EXAMINATION 2014/2015 CLASS: PRIMARY 6 SUBJECT: MATHEMATICS
3RD TERM PROMOTIONAL EXAMINATION 2014/2015
CLASS: PRIMARY 6 SUBJECT: MATHEMATICS
NAME:……………………………………………………………………………..
Section A: Objective Test
1. Find the difference between LXVI and XLI. (a) 25 (b) 45 (c) 65 (d) 75
2. Given that 12 / x = 10; What is x? (a) 0.2 (b) 1.2 (c) 2.2 (d) 2.1
3. Simplify 0.35 + 0.053 + 0.035 + 9.5 (a) 0.9938 (b) 9.938 (c) 21.8 (d) 99.38
4. If Y x Y x Y = 27. What is the value of Y? (a) 131/2 (b) 9 (c) 3 (d) 5
5. If 4b = 24, what is b? (a) 20 (b) 15 (c) 6 (d) 3
6. What is the volume of the cuboid?
8cm 5cm
10cm
7. Multiply 23.3 by 2.7 (a) 76410 (b) 7641 (c) 76.41 (d) 7.641
8. What fraction of 2 minutes is 6 seconds? (a) 1/6 (b) 1/10 (c) 1/20 (d) 1/60
9. Write 1111111111 in words (a) One million, One eleven thousand and eleven (b) One billion, One million, eleven thousand, one hundred and one (c) One billion, One hundred and eleven million, One hundred and eleven thousand, \one hundred and eleven (d) Onety One billion, one million and eleven hundred thousand and eleven
10. Expand 148.04921 (a) 140 + 8 + 4/100 + 9/1000 + 2/1000 + 1/10000
(b) 100 + 40 + 8 + 0/10 + 4/100 +9/1000 + 2/10000 + 1/100000
(c) 148 + 0/0 + 4/10 + 9/100 + 2/1000 + 1/1000
(d) 1 + 4 + 8 + 9/10 + 4/2 + 2/1 + 1/1000
11. Write out all factors of 1234. _________________________
(a) 1, 2, 3, and 4 (b) 1, 2, 6 and 34 (c) 1, 2, 617 and 1234 (d) 4, 3, 2 and 34
12. Calculate the L.C.M. of 19, 91 and 191. ___________ (a) 191 (b) 22076 (c) 330239 (d) 148937
13. Calculate .the H.C.F of 101, 202 and 303. ____________ (a) 101 (b) 202 (c) 303 (d) 504
14. Calculate the area of this shape. (a) 22176m2 (b) 61724m2 (c) 531696m2 (d) 264m2
15. Convert ¾ to a decimal number. (a) 0.34 (b) 0.35 (c) 0.75 (d) 0.55
16. Express 15m as a decimal of 1km. (a) 1.5 (b) 1.05 (c) 0.015 (d) 0.0015
17. How many faces has a cube? (a) 24 (b) 4 (c) 2 (d) 6
18. Find the value of √ 32 x 72 (a) 5 ¼ (b) 21 (c) 42 (d) 84
19. Express CDLX in Hindu Arabic numeral. (a) 660 (b) 460 (c) 350 (d) 440
20. A house wife spent 3/7 of her money to buy beans and ½ of the remainder to buy rice. What fraction of her money is left? (a) 1/7 (b) 2/7 (c) 3/7 (d) 1/14
21. Add up 2.04 + 0.78 + 23.1 + 0.6 (a) 5.19 (b) 18.15 (c) 25.98 (d) 26.52
22. What is the average of 103, 137, 167 and 193? (a) 148 (b) 150 (c) 152 (d) 600
23. What is the simple interest on N250.00 for 6 years at the rate of 5%? (a) N 12.50 (b) N 25 (c) N 75 (d) N 50
24. Which of the following fractions is the smallest: 1/9, 1/8, 1/7, 1/4 and 1/5? (a) ¼ (b) 1/9 (c) 1/5 (d) 1/8
25. Divide 7005 by 5. (a) 1401 (b) 1410 (c) 1041 (d) 141
26. Express 1/5 as a percentage. (a) 1% (b) 10% (c) 5% (d) 20%
27. Express 625 as a fraction of 1000 in its lowest term. (a) ½ (b) 19/40 (c) 7/8 (d) 5/8
28. Express 5 % as a decimal. (a) 0.005 (b) 0.05 (c) 0.5 (d) 5.0
29. What is the value of 8 in 8576? (a) 8 (b) 8000 (c) 800 (d) 80
30. What shape best describes the shape of this question paper? (a) Cylinder (b) square (c) rectangle (d) cuboid
Section B: Theory
1. A man left an inheritance for his wife and his son. The wife was given half of the inheritance while the son was given one-quarter of what was left. If the boy was given N96,000;
(a) How much was given to the wife?
(b) How much was the worth of the inheritance?
2. Calculate the area of the shaded portion
7m
5m 5m
9m 9m
5m
3. Study the following given set of figures: 1, 1, 1,1, 1,3,2,9,1 and 8.
Calculate: (a) Mean
(b) Median
(c) Mode
4a. Mass measurement is used to measure ____________
b. The basic unit of measuring weight is ______________
c. 1000 grammes is equal to ________________
d. Draw one instrument that is used to measure weight.
5. Share 45 oranges .between Taiwo and Kehinde in the ratio 2 : 3.
(a) Who has the larger share?
(b) What is the difference between Taiwo's and Kehinde's share?
Carousel
Wordpress Theme by QualityWP | Conveted to Blogger Template by ThemeLib.com
Berita
Berita
Wordpress Theme by QualityWP | Conveted to Blogger Template by ThemeLib.com
Breaking News
3RD TERM PROMOTIONAL EXAMINATION 2014/2015 CLASS: PRIMARY 6 SUBJECT: MATHEMATICS
3RD TERM PROMOTIONAL EXAMINATION 2014/2015
CLASS: PRIMARY 6 SUBJECT: MATHEMATICS
NAME:……………………………………………………………………………..
Section A: Objective Test
1. Find the difference between LXVI and XLI. (a) 25 (b) 45 (c) 65 (d) 75
2. Given that 12 / x = 10; What is x? (a) 0.2 (b) 1.2 (c) 2.2 (d) 2.1
3. Simplify 0.35 + 0.053 + 0.035 + 9.5 (a) 0.9938 (b) 9.938 (c) 21.8 (d) 99.38
4. If Y x Y x Y = 27. What is the value of Y? (a) 131/2 (b) 9 (c) 3 (d) 5
5. If 4b = 24, what is b? (a) 20 (b) 15 (c) 6 (d) 3
6. What is the volume of the cuboid?
8cm 5cm
10cm
7. Multiply 23.3 by 2.7 (a) 76410 (b) 7641 (c) 76.41 (d) 7.641
8. What fraction of 2 minutes is 6 seconds? (a) 1/6 (b) 1/10 (c) 1/20 (d) 1/60
9. Write 1111111111 in words (a) One million, One eleven thousand and eleven (b) One billion, One million, eleven thousand, one hundred and one (c) One billion, One hundred and eleven million, One hundred and eleven thousand, \one hundred and eleven (d) Onety One billion, one million and eleven hundred thousand and eleven
10. Expand 148.04921 (a) 140 + 8 + 4/100 + 9/1000 + 2/1000 + 1/10000
(b) 100 + 40 + 8 + 0/10 + 4/100 +9/1000 + 2/10000 + 1/100000
(c) 148 + 0/0 + 4/10 + 9/100 + 2/1000 + 1/1000
(d) 1 + 4 + 8 + 9/10 + 4/2 + 2/1 + 1/1000
11. Write out all factors of 1234. _________________________
(a) 1, 2, 3, and 4 (b) 1, 2, 6 and 34 (c) 1, 2, 617 and 1234 (d) 4, 3, 2 and 34
12. Calculate the L.C.M. of 19, 91 and 191. ___________ (a) 191 (b) 22076 (c) 330239 (d) 148937
13. Calculate .the H.C.F of 101, 202 and 303. ____________ (a) 101 (b) 202 (c) 303 (d) 504
14. Calculate the area of this shape. (a) 22176m2 (b) 61724m2 (c) 531696m2 (d) 264m2
15. Convert ¾ to a decimal number. (a) 0.34 (b) 0.35 (c) 0.75 (d) 0.55
16. Express 15m as a decimal of 1km. (a) 1.5 (b) 1.05 (c) 0.015 (d) 0.0015
17. How many faces has a cube? (a) 24 (b) 4 (c) 2 (d) 6
18. Find the value of √ 32 x 72 (a) 5 ¼ (b) 21 (c) 42 (d) 84
19. Express CDLX in Hindu Arabic numeral. (a) 660 (b) 460 (c) 350 (d) 440
20. A house wife spent 3/7 of her money to buy beans and ½ of the remainder to buy rice. What fraction of her money is left? (a) 1/7 (b) 2/7 (c) 3/7 (d) 1/14
21. Add up 2.04 + 0.78 + 23.1 + 0.6 (a) 5.19 (b) 18.15 (c) 25.98 (d) 26.52
22. What is the average of 103, 137, 167 and 193? (a) 148 (b) 150 (c) 152 (d) 600
23. What is the simple interest on N250.00 for 6 years at the rate of 5%? (a) N 12.50 (b) N 25 (c) N 75 (d) N 50
24. Which of the following fractions is the smallest: 1/9, 1/8, 1/7, 1/4 and 1/5? (a) ¼ (b) 1/9 (c) 1/5 (d) 1/8
25. Divide 7005 by 5. (a) 1401 (b) 1410 (c) 1041 (d) 141
26. Express 1/5 as a percentage. (a) 1% (b) 10% (c) 5% (d) 20%
27. Express 625 as a fraction of 1000 in its lowest term. (a) ½ (b) 19/40 (c) 7/8 (d) 5/8
28. Express 5 % as a decimal. (a) 0.005 (b) 0.05 (c) 0.5 (d) 5.0
29. What is the value of 8 in 8576? (a) 8 (b) 8000 (c) 800 (d) 80
30. What shape best describes the shape of this question paper? (a) Cylinder (b) square (c) rectangle (d) cuboid
Section B: Theory
1. A man left an inheritance for his wife and his son. The wife was given half of the inheritance while the son was given one-quarter of what was left. If the boy was given N96,000;
(a) How much was given to the wife?
(b) How much was the worth of the inheritance?
2. Calculate the area of the shaded portion
7m
5m 5m
9m 9m
5m
3. Study the following given set of figures: 1, 1, 1,1, 1,3,2,9,1 and 8.
Calculate: (a) Mean
(b) Median
(c) Mode
4a. Mass measurement is used to measure ____________
b. The basic unit of measuring weight is ______________
c. 1000 grammes is equal to ________________
d. Draw one instrument that is used to measure weight.
5. Share 45 oranges .between Taiwo and Kehinde in the ratio 2 : 3.
(a) Who has the larger share?
(b) What is the difference between Taiwo's and Kehinde's share? | 3,642 | 8,735 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.734375 | 4 | CC-MAIN-2018-47 | latest | en | 0.386317 |
https://brainmass.com/business/human-resource-outsourcing/analyzing-cost-of-manufacturing-versus-outsourcing-248629 | 1,566,668,634,000,000,000 | text/html | crawl-data/CC-MAIN-2019-35/segments/1566027321351.87/warc/CC-MAIN-20190824172818-20190824194818-00169.warc.gz | 386,752,842 | 19,363 | Explore BrainMass
Share
# Analyzing cost of manufacturing versus outsourcing
This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!
The Minnetonka Corporation, which produces and sells to wholesalers a highly successful line of water skis, has decided to diversify to stabilize sales throughout the year. The company is considering the production of cross-country skis.
After considerable research, a cross-country ski line has been developed. Because of the conservative nature of the company management, however, Minnetonka's president has decided to introduce only one type of the new skis for this coming winter. If the product is a success, further expansion in future years will be initiated.
The ski selected is a mass-market ski with a special binding. It will be sold to wholesalers for \$80 per pair. Because of availability capacity, no additional fixed charges will be incurred to produce the skis. A \$100,000 fixed charge will be absorbed by the skis, however, to allocate a fair share of the company's present fixed costs to the new product.
Using the estimated sales and production of 10,000 pair of skis as the expected volume, the accounting department has developed the following cost per pair of skis and bindings:
Direct Labor: \$35
Direct Material: \$30
Total Overhead: \$15
Total: \$80
Minnetonka has approached a subcontractor to discuss the possibility of purchasing the bindings. The purchase price of the bindings from the subcontractor would be \$5.25 per binding, or \$10.50 per pair. If the Minnetonka Corporation accepts the purchase proposal, it is predicted that direct-labor and variable-overhead costs would be reduced by 10% and direct-material costs would be reduced by 20%.
1. Should the Minnetonka Corporation make or buy the bindings? Show calculations to support your answer.
2. What would be the maximum purchase price acceptable to the Minnetonka Corporation for the bindings? Support your answer with an appropriate explanation.
3. Instead of sales of 10,000 pair of skis, revised estimates show sales volume at 12,500 pair. At this new volume, additional equipment, at an annual rental of \$10,000 must be acquired to manufacture the bindings. This incremental cost would be the only additional fixed cost required even if sales increased to 30,000 pair. (This 30,000 level is the goal for the third year of production.) Under these circumstances, should the Minnetonka Corporation make or buy the bindings? Show calculations to support your answer.
4. What qualitative factors (i.e. issues with vendors, customers, or within the product itself) should the Minnetonka Corporation consider in determining whether they should make or buy the bindings?
. Provide calculations and make a decision about whether to make or buy the bindings that go on the skis. This can be done in a couple of ways.
a. You can compute the total reductions that will occur if you don't make the bindings and compare that to the cost of buying the bindings. (Preferred method since this will help in question 2.)
b. You can compute the total cost of making the skis with purchased bindings, taking into account the reductions and the cost of buying the bindings.
2. What is the total you would be willing to pay to an outside source for the bindings? This is based on the amount of reductions found in question 1.
3. Provide calculations and make a decision about whether to make or buy the bindings if you increase production to 12,500 units or 30,000 units.
a. Remember that the original fixed costs that you computed in problem 1 are not relevant in this decision, i.e. we don't consider them. The new fixed costs are relevant.
4. Provide an explanation of what other factors should be considered. These factors will be qualitative factors, not quantitative. In other words, we have considered the cost of the question, but there are other things that will affect our decision.
© BrainMass Inc. brainmass.com March 21, 2019, 6:11 pm ad1c9bdddf
https://brainmass.com/business/human-resource-outsourcing/analyzing-cost-of-manufacturing-versus-outsourcing-248629
#### Solution Preview
Here is the break down of the Activity-Based-costing for the questions asked above.
It seemed that some of the questions ...
#### Solution Summary
This problem provides an accounting analysis of the costs associated with outsourcing product manufacture versus in-house manufacturing.
\$2.19 | 946 | 4,475 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.515625 | 3 | CC-MAIN-2019-35 | latest | en | 0.933839 |
https://www.aqua-calc.com/convert/acceleration/femtometer-per-hour-squared-to-zettameter-per-minute-squared/start/1 | 1,606,771,208,000,000,000 | text/html | crawl-data/CC-MAIN-2020-50/segments/1606141486017.50/warc/CC-MAIN-20201130192020-20201130222020-00291.warc.gz | 579,976,558 | 9,677 | # Femtometers per (hour squared) to Zettameters per (minute squared)
## fm/h² to Zm/min² (fm:femtometer, h:hour, Zm:Zettameter, min:minute)
### Convert fm/h² to Zm/min²
#### an acceleration conversion table
to 100 with
femto-
meter per hour squared
×10−38,
Zetta-
meter per minute squared
femto-
meter per hour squared
×10−38,
Zetta-
meter per minute squared
femto-
meter per hour squared
×10−38,
Zetta-
meter per minute squared
femto-
meter per hour squared
×10−38,
Zetta-
meter per minute squared
femto-
meter per hour squared
×10−38,
Zetta-
meter per minute squared
10.03210.58411.14611.69812.25
20.06220.61421.17621.72822.28
30.08230.64431.19631.75832.31
40.11240.67441.22641.78842.33
50.14250.69451.25651.81852.36
60.17260.72461.28661.83862.39
70.19270.75471.31671.86872.42
80.22280.78481.33681.89882.44
90.25290.81491.36691.92892.47
100.28300.83501.39701.94902.50
110.31310.86511.42711.97912.53
120.33320.89521.44722.00922.56
130.36330.92531.47732.03932.58
140.39340.94541.50742.06942.61
150.42350.97551.53752.08952.64
160.44361.00561.56762.11962.67
170.47371.03571.58772.14972.69
180.50381.06581.61782.17982.72
190.53391.08591.64792.19992.75
200.56401.11601.67802.221002.78
### 1 through 100 femtometers per hour squared to Zettameters per minute squared conversion cards
• 1
through
20
femtometers per hour squared
• 1 fm/h² to Zm/min² = 3.0 × 10-40 Zm/min²
• 2 fm/h² to Zm/min² = 6.0 × 10-40 Zm/min²
• 3 fm/h² to Zm/min² = 8.0 × 10-40 Zm/min²
• 4 fm/h² to Zm/min² = 1.1 × 10-39 Zm/min²
• 5 fm/h² to Zm/min² = 1.4 × 10-39 Zm/min²
• 6 fm/h² to Zm/min² = 1.7 × 10-39 Zm/min²
• 7 fm/h² to Zm/min² = 1.9 × 10-39 Zm/min²
• 8 fm/h² to Zm/min² = 2.2 × 10-39 Zm/min²
• 9 fm/h² to Zm/min² = 2.5 × 10-39 Zm/min²
• 10 fm/h² to Zm/min² = 2.8 × 10-39 Zm/min²
• 11 fm/h² to Zm/min² = 3.1 × 10-39 Zm/min²
• 12 fm/h² to Zm/min² = 3.3 × 10-39 Zm/min²
• 13 fm/h² to Zm/min² = 3.6 × 10-39 Zm/min²
• 14 fm/h² to Zm/min² = 3.9 × 10-39 Zm/min²
• 15 fm/h² to Zm/min² = 4.2 × 10-39 Zm/min²
• 16 fm/h² to Zm/min² = 4.4 × 10-39 Zm/min²
• 17 fm/h² to Zm/min² = 4.7 × 10-39 Zm/min²
• 18 fm/h² to Zm/min² = 5.0 × 10-39 Zm/min²
• 19 fm/h² to Zm/min² = 5.3 × 10-39 Zm/min²
• 20 fm/h² to Zm/min² = 5.6 × 10-39 Zm/min²
• 21
through
40
femtometers per hour squared
• 21 fm/h² to Zm/min² = 5.8 × 10-39 Zm/min²
• 22 fm/h² to Zm/min² = 6.1 × 10-39 Zm/min²
• 23 fm/h² to Zm/min² = 6.4 × 10-39 Zm/min²
• 24 fm/h² to Zm/min² = 6.7 × 10-39 Zm/min²
• 25 fm/h² to Zm/min² = 6.9 × 10-39 Zm/min²
• 26 fm/h² to Zm/min² = 7.2 × 10-39 Zm/min²
• 27 fm/h² to Zm/min² = 7.5 × 10-39 Zm/min²
• 28 fm/h² to Zm/min² = 7.8 × 10-39 Zm/min²
• 29 fm/h² to Zm/min² = 8.1 × 10-39 Zm/min²
• 30 fm/h² to Zm/min² = 8.3 × 10-39 Zm/min²
• 31 fm/h² to Zm/min² = 8.6 × 10-39 Zm/min²
• 32 fm/h² to Zm/min² = 8.9 × 10-39 Zm/min²
• 33 fm/h² to Zm/min² = 9.2 × 10-39 Zm/min²
• 34 fm/h² to Zm/min² = 9.4 × 10-39 Zm/min²
• 35 fm/h² to Zm/min² = 9.7 × 10-39 Zm/min²
• 36 fm/h² to Zm/min² = 1.0 × 10-38 Zm/min²
• 37 fm/h² to Zm/min² = 1.03 × 10-38 Zm/min²
• 38 fm/h² to Zm/min² = 1.06 × 10-38 Zm/min²
• 39 fm/h² to Zm/min² = 1.08 × 10-38 Zm/min²
• 40 fm/h² to Zm/min² = 1.11 × 10-38 Zm/min²
• 41
through
60
femtometers per hour squared
• 41 fm/h² to Zm/min² = 1.14 × 10-38 Zm/min²
• 42 fm/h² to Zm/min² = 1.17 × 10-38 Zm/min²
• 43 fm/h² to Zm/min² = 1.19 × 10-38 Zm/min²
• 44 fm/h² to Zm/min² = 1.22 × 10-38 Zm/min²
• 45 fm/h² to Zm/min² = 1.25 × 10-38 Zm/min²
• 46 fm/h² to Zm/min² = 1.28 × 10-38 Zm/min²
• 47 fm/h² to Zm/min² = 1.31 × 10-38 Zm/min²
• 48 fm/h² to Zm/min² = 1.33 × 10-38 Zm/min²
• 49 fm/h² to Zm/min² = 1.36 × 10-38 Zm/min²
• 50 fm/h² to Zm/min² = 1.39 × 10-38 Zm/min²
• 51 fm/h² to Zm/min² = 1.42 × 10-38 Zm/min²
• 52 fm/h² to Zm/min² = 1.44 × 10-38 Zm/min²
• 53 fm/h² to Zm/min² = 1.47 × 10-38 Zm/min²
• 54 fm/h² to Zm/min² = 1.5 × 10-38 Zm/min²
• 55 fm/h² to Zm/min² = 1.53 × 10-38 Zm/min²
• 56 fm/h² to Zm/min² = 1.56 × 10-38 Zm/min²
• 57 fm/h² to Zm/min² = 1.58 × 10-38 Zm/min²
• 58 fm/h² to Zm/min² = 1.61 × 10-38 Zm/min²
• 59 fm/h² to Zm/min² = 1.64 × 10-38 Zm/min²
• 60 fm/h² to Zm/min² = 1.67 × 10-38 Zm/min²
• 61
through
80
femtometers per hour squared
• 61 fm/h² to Zm/min² = 1.69 × 10-38 Zm/min²
• 62 fm/h² to Zm/min² = 1.72 × 10-38 Zm/min²
• 63 fm/h² to Zm/min² = 1.75 × 10-38 Zm/min²
• 64 fm/h² to Zm/min² = 1.78 × 10-38 Zm/min²
• 65 fm/h² to Zm/min² = 1.81 × 10-38 Zm/min²
• 66 fm/h² to Zm/min² = 1.83 × 10-38 Zm/min²
• 67 fm/h² to Zm/min² = 1.86 × 10-38 Zm/min²
• 68 fm/h² to Zm/min² = 1.89 × 10-38 Zm/min²
• 69 fm/h² to Zm/min² = 1.92 × 10-38 Zm/min²
• 70 fm/h² to Zm/min² = 1.94 × 10-38 Zm/min²
• 71 fm/h² to Zm/min² = 1.97 × 10-38 Zm/min²
• 72 fm/h² to Zm/min² = 2.0 × 10-38 Zm/min²
• 73 fm/h² to Zm/min² = 2.03 × 10-38 Zm/min²
• 74 fm/h² to Zm/min² = 2.06 × 10-38 Zm/min²
• 75 fm/h² to Zm/min² = 2.08 × 10-38 Zm/min²
• 76 fm/h² to Zm/min² = 2.11 × 10-38 Zm/min²
• 77 fm/h² to Zm/min² = 2.14 × 10-38 Zm/min²
• 78 fm/h² to Zm/min² = 2.17 × 10-38 Zm/min²
• 79 fm/h² to Zm/min² = 2.19 × 10-38 Zm/min²
• 80 fm/h² to Zm/min² = 2.22 × 10-38 Zm/min²
• 81
through
100
femtometers per hour squared
• 81 fm/h² to Zm/min² = 2.25 × 10-38 Zm/min²
• 82 fm/h² to Zm/min² = 2.28 × 10-38 Zm/min²
• 83 fm/h² to Zm/min² = 2.31 × 10-38 Zm/min²
• 84 fm/h² to Zm/min² = 2.33 × 10-38 Zm/min²
• 85 fm/h² to Zm/min² = 2.36 × 10-38 Zm/min²
• 86 fm/h² to Zm/min² = 2.39 × 10-38 Zm/min²
• 87 fm/h² to Zm/min² = 2.42 × 10-38 Zm/min²
• 88 fm/h² to Zm/min² = 2.44 × 10-38 Zm/min²
• 89 fm/h² to Zm/min² = 2.47 × 10-38 Zm/min²
• 90 fm/h² to Zm/min² = 2.5 × 10-38 Zm/min²
• 91 fm/h² to Zm/min² = 2.53 × 10-38 Zm/min²
• 92 fm/h² to Zm/min² = 2.56 × 10-38 Zm/min²
• 93 fm/h² to Zm/min² = 2.58 × 10-38 Zm/min²
• 94 fm/h² to Zm/min² = 2.61 × 10-38 Zm/min²
• 95 fm/h² to Zm/min² = 2.64 × 10-38 Zm/min²
• 96 fm/h² to Zm/min² = 2.67 × 10-38 Zm/min²
• 97 fm/h² to Zm/min² = 2.69 × 10-38 Zm/min²
• 98 fm/h² to Zm/min² = 2.72 × 10-38 Zm/min²
• 99 fm/h² to Zm/min² = 2.75 × 10-38 Zm/min²
• 100 fm/h² to Zm/min² = 2.78 × 10-38 Zm/min²
#### Foods, Nutrients and Calories
BLACK BUTTERCREAM FONDANT, UPC: 853651002684 contain(s) 439 calories per 100 grams or ≈3.527 ounces [ price ]
#### Gravels, Substances and Oils
CaribSea, Marine, Aragonite, Special Coarse Aragonite weighs 1 153.3 kg/m³ (71.99817 lb/ft³) with specific gravity of 1.1533 relative to pure water. Calculate how much of this gravel is required to attain a specific depth in a cylindricalquarter cylindrical or in a rectangular shaped aquarium or pond [ weight to volume | volume to weight | price ]
Flint, calcined at 500°C weighs 2 553 kg/m³ (159.37858 lb/ft³) [ weight to volume | volume to weight | price | density ]
Volume to weightweight to volume and cost conversions for Refrigerant R-502, liquid (R502) with temperature in the range of -51.12°C (-60.016°F) to 60°C (140°F)
#### Weights and Measurements
pound-force per square foot (psf) is a unit of pressure where a force of one pound-force (lbf ) is applied to an area of one square foot (ft²).
Energy is the ability to do work, and it comes in different forms: heat (thermal), light (radiant), motion (kinetic), electrical, chemical, nuclear and gravitational.
oz/in to t/m conversion table, oz/in to t/m unit converter or convert between all units of linear density measurement.
#### Calculators
Online Food Calories and Nutrients Calculator | 3,759 | 7,514 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.515625 | 3 | CC-MAIN-2020-50 | latest | en | 0.431047 |
https://estebantorreshighschool.com/equation-help/substitute-equation.html | 1,610,839,117,000,000,000 | text/html | crawl-data/CC-MAIN-2021-04/segments/1610703507971.27/warc/CC-MAIN-20210116225820-20210117015820-00580.warc.gz | 343,652,224 | 29,845 | ## How do you solve two equations with substitution?
To solve systems using substitution, follow this procedure:Select one equation and solve it for one of its variables.In the other equation, substitute for the variable just solved.Solve the new equation.Substitute the value found into any equation involving both variables and solve for the other variable.
## What is substituting method?
The method of substitution involves three steps: Solve one equation for one of the variables. Substitute (plug-in) this expression into the other equation and solve. Resubstitute the value into the original equation to find the corresponding variable.
## What is an equation without a solution?
“No solution” means that there is no value, not even 0, which would satisfy the equation. Also, be careful not to make the mistake of thinking that the equation 4 = 5 means that 4 and 5 are values for x that are solutions.
## How do you solve an equation using substitution?
The method of solving “by substitution” works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, “substituting” for the chosen variable and solving for the other. Then you back-solve for the first variable.
## What is the elimination method?
In the elimination method you either add or subtract the equations to get an equation in one variable. When the coefficients of one variable are opposites you add the equations to eliminate a variable and when the coefficients of one variable are equal you subtract the equations to eliminate a variable.
## What is substitution effect?
The substitution effect is the decrease in sales for a product that can be attributed to consumers switching to cheaper alternatives when its price rises.
## How do you solve by elimination?
The Elimination MethodStep 1: Multiply each equation by a suitable number so that the two equations have the same leading coefficient. Step 2: Subtract the second equation from the first.Step 3: Solve this new equation for y.Step 4: Substitute y = 2 into either Equation 1 or Equation 2 above and solve for x.
You might be interested: Intercept equation
## What does 0 0 mean in a equation?
For an answer to have an infinite solution, the two equations when you solve will equal 0=0 . Here is a problem that has an infinite number of solutions. 3x+2y=12. −6x−4y=24. If you solve this your answer would be 0=0 this means the problem has an infinite number of solutions.
## What does equation mean?
An equation is a mathematical statement that two things are equal. It consists of two expressions, one on each side of an ‘equals’ sign. For example: 12.
## What is a identity equation?
An identity equation is an equation that is always true for any value substituted into the variable.
## What are the 3 methods for solving systems of equations?
There are three ways to solve systems of linear equations in two variables: graphing. substitution method. elimination method.
## What is substitution example?
An example of substitution: ‘I bet you get married [A] before I get married [A]. ‘ – repetition. ‘I bet you get married [A] before I do [B].
### Releated
#### Tensile stress equation
What is the formula for tensile stress? Difference Between Tensile Stress And Tensile Strength Tensile stress Tensile strength The formula is: σ = F/A Where, σ is the tensile stress F is the force acting A is the area The formula is: s = P/a Where, s is the tensile strength P is the force […]
#### Quotient rule equation
What is the formula for Quotient? The answer after we divide one number by another. dividend ÷ divisor = quotient. Example: in 12 ÷ 3 = 4, 4 is the quotient. What is quotient rule in math? The quotient rule is a formal rule for differentiating problems where one function is divided by another. It […] | 843 | 3,878 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 4.8125 | 5 | CC-MAIN-2021-04 | longest | en | 0.917598 |
https://caipm.org/letters/5-letter-words-with-letters-pure/ | 1,719,106,433,000,000,000 | text/html | crawl-data/CC-MAIN-2024-26/segments/1718198862425.28/warc/CC-MAIN-20240623001858-20240623031858-00020.warc.gz | 131,790,817 | 16,808 | # 5 Letter Words With Letters Pure
5 Letter Words With Letters Pure – Fans who post their scores on social media provide a wealth of data, giving mathematicians a better understanding of the game and why we play it.
The W ordle exploded. Since launching in October, the word game has become a viral success as users (myself included) fall in love with the simple but frustrating task of guessing five-letter words in six tries.
## 5 Letter Words With Letters Pure
Like most puzzles, Wordle can be solved alone. But the game brings out the braggarts and these braggarts can offer data. Mathematicians looked at the results of players to better understand the game and how we play it.
#### Solve A Bike Lock Problem With 4 Dials And 10 Letters On Each Dial?
Professor Barry Smyth, chair of digital computer science at University College Dublin, analyzed more than 3m tweets from 800,000 Wordle players who “beat” the game (meaning they guessed the word in the six attempts or less). The tweets show people getting better over time – in general, they manage to solve the game in fewer rounds when playing.
The prompts also show the probability of guessing the correct letter (yellow), guessing the correct letter in the correct position (green) or just getting it wrong (yellow). It is not surprising that the chances of guessing the correct word increase with each subsequent round, but the data shows the importance of paper placement.
The second letter of the word is the easiest to guess (72% of the time, correctly guessed by the fifth round), the third letter is the next easiest (65%), followed by the last letter (52%). The first and fourth letters are the most likely to haunt you. And if you want to up your strategy, Smyth has also found the best starting quotes (scroll to the bottom if you want spoilers – it’s not adieu!).
It’s no surprise that computer programs can do much better than a bunch of Wordle tweeters. Data visualization software developer Xan Gregg did some in-depth analysis to find the most difficult Wordle words. It turns out that the computer solves almost every single word in five guesses or less – only three words are required for all six guesses (sweet, shush and yummy). By feeding a computer program 3,622 words, Gregg found the best starting words (which are mentioned in the spoilers below – this is not the same as the best words based on Wordle player performance!) .
See Also Toa Words 5 Letters
#### Wordsy Is A Scrabble Like Word Game Where You Always Have The Letters You Need
Like all data, these analyzes miss something. Both failed to catch the break. A computer can go on and on with predictions, and Smyth only considered the people who tweeted the answer after winning the game. It’s embarrassing – I wonder what five letter words can make us feel defeated (“aroma” brought me close to tears).
Smyth found that in more than 95% of games where the word “story” was used as the starting word, the player succeeded (and they succeeded quickly, 83% of them succeeded within a round four). Another very effective strategy is to combine two starting words – using “cones” followed by “test”.
Instead of looking at successful games played by humans, Xan Gregg found the best starting words by letting a computer try 3,622 starting words. The word “crate” caused the computer to win with the least number of points. What are the 5 words that end in ee? English letters are divided into vowels and consonants. Each letter can be combined with other letters to form a word. There are 26 different letters in the English alphabet. In the vowel category there are 5 vowels, a, e, i, o, and u. Each vowel sounds like a single syllable. In this article, you will learn more about 5 letter words that end in ee.
5 words ending in ee are five letter words. The word has a vowel followed by the consonant ee. The top of these words is in the middle, and therefore they are called 5 letter words ending in ee. If you have a list of 5 letter words but haven’t found what you’re looking for, you can use this article to get more ideas and suggestions for 5 letter words that end in ee.
### Going Beyond Wordle: Oodles Of *dle Games
You will notice that the 5 words that end in ee are not used very often, but they are not very common. You will be surprised to know that you already know a lot of 5 letter words ending in ee. We hope you will get new and interesting ideas and suggestions about 5-letter words that end in ee.publishers choose and review independent products. If you make a purchase through an affiliate link, we may receive a commission, which helps support our testing.
See Also 3d Acrylic Fillable Letters
In October 2021, developer Josh Wardle released Wordle (Opens in a new window). By the end of the year, the word game had gone from a private inside joke to a public sensation. If your Twitter feed is anything like mine, every day in January you are bombarded with Wordle numbers. Wordle is everywhere. This article is part of the problem.
In an age where even the best games have dubious warnings, it’s refreshing to see everyone rally around something as simple and clean as Wordle. However, nothing good lasts forever in this world, so other shoes keep coming soon. If the endless discussion of Wordle goes down a dark path, only the things that give us great joy will destroy us. So this is my appeal. I’m begging you all, don’t destroy Wordle.
When something goes bump in the night, it creates a lot of confusion for people who don’t understand what it is, and that confusion can lead to bad vibes. So, let’s first explain what Wordle is.
#### Letter Words Apk For Android Download
Wordle is a free, browser-based, word-guessing game that’s more like Hangman than a crossword puzzle. You have six chances to guess the five-letter word, and each guess provides a hint to make your next guess more educated. If a letter is grayed out, it means that the letter is not in the word at all. If a letter is yellow, it means that the letter is in the word but in the wrong place. If the letter is green, it is the right letter in the right place. The correct answer is five green letters in a row.
Similar to Zach Gage’s mobile game, Wordle shows amazing beauty in a simple design. With only five letters, guessing a random word doesn’t feel like a completely unfair shot in the dark, and the word itself rarely is. People have developed Wordle strategies, such as opening with the same word over and over again to knock out common letters. How to warn you in your description to make better predictions, bringing you closer to the “Eureka!” time, provides an exciting time. It is not “Tired”. “Rotor” is almost there. “Robot!” And the rare times you get it right on the first or second try make you feel like a complete expert.
See Also Words With Letters Articc
Compare Wordle to the feel of old classic games like HQ Trivia. The mobile game show, which paid real money, was pure chaos. In the end, people spent more money on the actual story surrounding the space host than on the game itself (shout out to Scott(Opens in a new window).) Wordle is the opposite. in polar. Wordle is quiet and peaceful, a nice little exercise for people who speak words every day. Nothing about it says bad vibes. However, this did not stop some people from spoiling the mood.
The internet has an uncanny ability to turn even the most innocent things into a culture war, and Wordle is no exception. Wordle’s biggest win in meta design is that you can play one game a day, and everyone else online is playing that game too. We are all trying to guess the same word. At the time of this writing, we are at Wordle 215. This creates a shared social experience that really fuels Wordle’s success as a viral phenomenon.
### How Word Lists Help — Or Hurt — Crossword Puzzles
Even Wordle’s sleek, minimalist design contributes to this spread. By simply typing on the colored squares, you can reveal your way to solving that day’s puzzle without spoiling the answer. How long did you last? When is your breakthrough? It adds to the mystique. The daily limit also prevents you from burning yourself out by binging which is, again, a very simple game. Happy to take the golden egg from this goose, don’t kill it.
Despite these smart restrictions, Wordle’s rapid spread has left many people unable to shut up about it, either praising it or complaining about other people talking about it all the time. Of course, I’m not one of those “Let me enjoy things”. When things are dirty, it’s important to say it’s dirty, even if it’s popular and other people don’t feel the same way. However, I cannot support the exaggerated comments, from all quarters, about something as innocent as Wordle. It is very easy to ignore this word and go about your day. And if you want
Devano Mahardika
Halo, Saya adalah penulis artikel dengan judul 5 Letter Words With Letters Pure yang dipublish pada September 15, 2022 di website Caipm | 1,984 | 8,975 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.890625 | 3 | CC-MAIN-2024-26 | latest | en | 0.932879 |
https://www.calculatoratoz.com/en/chord-length-when-radius-and-angle-are-given-calculator/node-402 | 1,604,085,622,000,000,000 | text/html | crawl-data/CC-MAIN-2020-45/segments/1603107911229.96/warc/CC-MAIN-20201030182757-20201030212757-00370.warc.gz | 636,398,011 | 31,266 | ## < ⎙ 25 Other formulas that you can solve using the same Inputs
Side a of a triangle
Side A=sqrt((Side B)^2+(Side C)^2-2*Side B*Side C*cos(Angle A)) GO
Total Surface Area of a Cone
Chord length when radius and perpendicular distance are given
Lateral Surface Area of a Cone
Total Surface Area of a Cylinder
Surface Area of a Capsule
Volume of a Capsule
Lateral Surface Area of a Cylinder
Perimeter Of Sector
Work
Work =Force*Displacement*cos(Angle A) GO
Arc Length
Circumference of Circle
Curved Surface Area of a Hemisphere
Volume of a Circular Cone
Total Surface Area of a Hemisphere
Bottom Surface Area of a Cylinder
Base Surface Area of a Hemisphere
Base Surface Area of a Cone
Top Surface Area of a Cylinder
Volume of a Circular Cylinder
Area of a Circle when radius is given
Surface Area of a Sphere
Volume of a Hemisphere
Volume of a Sphere
Area of a Sector
## < ⎙ 1 Other formulas that calculate the same Output
Chord length when radius and perpendicular distance are given
### Chord Length when radius and angle are given Formula
Other Formulas
Volume of a Capsule GO
Volume of a Circular Cone GO
Volume of a Circular Cylinder GO
Volume of a Cube GO
Volume of a Hemisphere GO
Volume of a Sphere GO
Volume of a Pyramid GO
Volume of a Conical Frustum GO
Perimeter of a Rectangle GO
Perimeter of a Square GO
Perimeter of a Parallelogram GO
Perimeter of a Rhombus GO
Perimeter of an Isosceles Triangle GO
Perimeter of a Cube GO
Perimeter of a Kite GO
Volume of a Rectangular Prism GO
Chord length when radius and perpendicular distance are given GO
Perimeter Of Sector GO
Diagonal of a Square GO
Diagonal of a Rectangle GO
Diagonal of a Cube GO
Perimeter Of Parallelepiped GO
## What is Chord Length when radius and angle are given?
The chord length when radius and angle are given of a circle is one of the ways to find the chord length of any circle. Chord length can be defined as the line segment joining any two points on the circumference of the circle. It should be noted that the diameter is the longest chord of a circle which passes through the center of the circle.
## How to Calculate Chord Length when radius and angle are given?
Chord Length when radius and angle are given calculator uses Chord Length=sin(Angle A/2)*2*Radius to calculate the Chord Length, Chord Length is the length of a line segment connecting any two points on the circumference of a circle. Chord Length and is denoted by l symbol.
How to calculate Chord Length when radius and angle are given using this online calculator? To use this online calculator for Chord Length when radius and angle are given, enter Radius (r) and Angle A (∠A) and hit the calculate button. Here is how the Chord Length when radius and angle are given calculation can be explained with given input values -> 23.41036 = sin(30/2)*2*18.
### FAQ
What is Chord Length when radius and angle are given?
Chord Length is the length of a line segment connecting any two points on the circumference of a circle and is represented as l=sin(∠A/2)*2*r or Chord Length=sin(Angle A/2)*2*Radius. Radius is a radial line from the focus to any point of a curve and The angle A is one of the angles of a triangle.
How to calculate Chord Length when radius and angle are given?
Chord Length is the length of a line segment connecting any two points on the circumference of a circle is calculated using Chord Length=sin(Angle A/2)*2*Radius. To calculate Chord Length when radius and angle are given, you need Radius (r) and Angle A (∠A). With our tool, you need to enter the respective value for Radius and Angle A and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
Let Others Know | 898 | 3,697 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.171875 | 3 | CC-MAIN-2020-45 | latest | en | 0.777688 |
https://www.ukessays.com/essays/chemistry/lab-report-on-the-molar-mass-of-butane-4309.php | 1,653,752,920,000,000,000 | text/html | crawl-data/CC-MAIN-2022-21/segments/1652663016949.77/warc/CC-MAIN-20220528154416-20220528184416-00269.warc.gz | 1,203,763,947 | 13,303 | Disclaimer: This is an example of a student written essay.
Any scientific information contained within this essay should not be treated as fact, this content is to be used for educational purposes only and may contain factual inaccuracies or be out of date.
# Lab Report on the Molar Mass of Butane
✅ Paper Type: Free Essay ✅ Subject: Chemistry ✅ Wordcount: 1481 words ✅ Published: 3rd Nov 2020
Introduction
As the world of chemistry constantly evolves, certain elements, compounds, and even substances are always undergoing substance identification. Moreover, there are many methods to identify a substance. As noted by Austin Peay State University’s department of chemistry, the identification of a substance can be determined by making simple observations such as odor, temperature, and most importantly, color. However, some gas substances cannot be easily observed for their color. In such cases, determining the molar mass of the substance can prove to be helpful in substance identification.
If you need assistance with writing your essay, our professional essay writing service is here to help!
According to Purdue University’s department of chemistry, for many chemists, it is impractical to collect and measure gas because gases have small densities. However, because butane is not soluble in water, it allows for water to be displaced from a container. In doing so, it facilitates the collection of gas. In Dalton’s Law of partial of pressures, the total pressure in a container is equal to the sum of the gas collected and water vapor.
In 1834, physicist Emil Clapeyron wrote an equation that assisted many chemists in understanding the behavior of everyday gases. Clapeyron equation is recognized as the ideal gas law and is written as PV=nRT. It states that the product of a gas’s volume (L) and pressure (atm) is proportional to the product of the gas constant, moles (mol), temperature (K). The gas constant, “R” has an exact value of 0.0821 L*atm/mol*k. This equation is important because the number of moles, “n”, can be used to determine the molar mass of butane by rearranging the equation to n=PV/RT. In this experiment, the moles and mass will be required to determine the molar mass of butane in a butane lighter.
Experimental
To begin the experiment, the mass of a butane lighter was measured before using the butane gas to deplete the water to the 80mL mark on a graduated cylinder. Secondly, the temperature of the of the water was measured after waiting five minutes for the temperature to remain constant. Afterwards, the mass of the butane lighter was measured a second time to determine the displacement.
In calculating the molar mass, the ideal gas law was used to first determine the number of moles. Finally, the mass of the butane displaced was divided by the moles to eventually produce the molar mass of the butane. The experiment was repeated for four trials.
Results
Table 1: Data of molar mass experiment
Units Trial 1 Trial 2 Trial 3 Trial 4 Initial Mass of Lighter g 14.053 14.827 16.234 13.903 Final Mass of Lighter g 14.273 15.060 16.346 14.071 Mass of Butane g 0.220 0.233 0.112 0.168 Volume of Gas collected L 0.101 0.084 0.094 0.082 Air temperature K 293.000 293.000 293.000 293.000 Water temperature K 293.000 293.000 293.000 293.000 Vapor pressure of H₂O atm 0.023 0.023 0.023 0.023 Barometric Pressure atm 0.988 0.988 0.988 0.988 Accepted Molar Mass of Butane 58.12g/mol
Certain data included in the table were given as a standard. That standard was used to compare the experimental result to. The accepted molar mass of butane, vapor pressure of H₂O and barometric pressure was given as a standard.
Table 2: Number of moles by the equation n=PV/RT for trials 1-4
Trial 1 Data n=PV/RT (mol) Trial 2 Data n=PV/RT (mol) P= 0.9649 0.004 P= 0.9649 0.003 V= 0.101 V= 0.084 R= 293 R= 293 T= 0.0821 T= 0.0821 Trial 3 Data n=PV/RT (mol) Trial 4 Data n=PV/RT (mol) P= 0.9649 0.004 P= 0.9649 0.003 V= 0.094 V= 0.082 R= 293 R= 293 T= 0.0821 T= 0.0821
The number of moles was calculated by multiplying the pressure and volume and dividing that product by the constant gas and temperature. The pressure was determined by subtracting the pressure of H₂O from the total pressure.
Table 3: Molar mass of butane calculations
The molar mass was calculated by dividing the mass of butane by the experimental number of moles. The average of all four trials resulted in a molar mass of 54.17g/mol.
Discussion
The experiment was designed to be able to facilitate substance identification by determining the molar mass of butane. The molar mass of butane was found by first calculating the number of moles using the ideal gas law, n=PV/RT. Next, the mass of the butane displaced was divided by the moles to finally give the molar mass of the butane. The average experimental molar mass resulted in 54.17g/mol while the accepted value was 58.12g/mol. This is a percent error of 6.779%. In the future, this experiment can be improved upon by not letting the butane gas escape the graduated cylinder. In doing so, it will allow for more accurate results when calculating.
Bibliography
• “Identification of a Pure Substance.” Austin Peay State University Department of Chemistry, Chem 1111 Lab Handouts. Revision S18.
• Finding the Molar Mass of Butane. University of Illinois Urbana-Champaign, www.chem.uiuc.edu/chem103/molar_mass/introduction.htm.
• Collection of Gas Over Water. Purdue University, chemed.chem.purdue.edu/genchem/lab/techniques/gascollect.html.
View all
## DMCA / Removal Request
If you are the original writer of this essay and no longer wish to have your work published on UKEssays.com then please:
Related Services
Related Lectures
Freelance Writing Jobs
Looking for a flexible role?
Do you have a 2:1 degree or higher?
Study Resources
Free resources to assist you with your university studies! | 1,483 | 5,874 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.671875 | 3 | CC-MAIN-2022-21 | latest | en | 0.939894 |
https://jp.mathworks.com/matlabcentral/profile/authors/13998225-sam-plant | 1,586,292,854,000,000,000 | text/html | crawl-data/CC-MAIN-2020-16/segments/1585371805747.72/warc/CC-MAIN-20200407183818-20200407214318-00477.warc.gz | 527,689,788 | 19,359 | Community Profile
sam plant
11 2018 年以降の合計貢献数
sam plant's バッジ
How can I change the response to forced excitation?
function Structural_drift % Define initial conditions x(0) & x'(0) x0 = [0 1]; % Time interval t = [0 120]; % Solve equatio...
7ヶ月 前 | 0 件の回答 | 0
0
Solving Vibration equation of motion?
Hello, I'm trying to use ODE45 to solve the vibration equation of motion Mx''+Cx' + Kx = Fsin(w*t)? If there is an alternativ...
8ヶ月 前 | 1 件の回答 | 0
1
permutations of a matrix
Hello, for a linear system equation of Ax = B with A dimensions 5x5 and x, a column vector. Let's say A is a binary matrix of...
8ヶ月 前 | 2 件の回答 | 0
2
How to find damping ratio from halfpower method?
xout=acc_u_2(:,1); fs=20; m = [length(xout), 2^(nextpow2(length(xout)))]; N = 12000; xdft = fft(xout,N); xdft = xdft(1:N/...
11ヶ月 前 | 0 件の回答 | 0
0
How to find Modal Parameters using NExT/ERA?
Hello, The following is a signal received from the first floor of a building, i've have a 12000x5 matrix with each column be...
11ヶ月 前 | 0 件の回答 | 0
0
How to save file as pdf?
imagesc(x,y,img), colorbar, %color plot objectiveoutput = saveas(gcf,'objective.pdf'); ...
1年以上 前 | 2 件の回答 | 0
2
How to set up fmincon
I have an objective function which takes input values for a projectile with initial speed v0 and angle theta. Given a target it ...
1年以上 前 | 2 件の回答 | 0
2
How to change axes values?
I have plotted a matrix using the imagesc function with the x and y axis being the points of the matrix (1-50) however the posi...
1年以上 前 | 1 件の回答 | 0
1
Newton Raphson on Matlab
Gven the equation 1/sqrt(x) + 2log(A/rt(x) + b) with A and b constants. i want to differentiate and then solve using newton rap...
1年以上 前 | 2 件の回答 | 0
2
how to read a txt file as input values?
I wish to read a txt file with a 4x4 square of input values st matlab reads the first row and enters them into my inputs, then t...
1年以上 前 | 1 件の回答 | 0
1
how to differentiate a function and then evaluate at a predefined variable?
If i wanted to differentiate f=x*y with respect to y and then evaluate at a value y = 6 say. how would i do this? i would write...
1年以上 前 | 1 件の回答 | 0 | 683 | 2,143 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.90625 | 3 | CC-MAIN-2020-16 | latest | en | 0.738235 |
https://www.snapxam.com/problems/64876818/-5x-2-3-0-5x-2-3 | 1,600,480,490,000,000,000 | text/html | crawl-data/CC-MAIN-2020-40/segments/1600400189928.2/warc/CC-MAIN-20200919013135-20200919043135-00756.warc.gz | 1,083,782,776 | 8,192 | # Step-by-step Solution
Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2
e
π
ln
log
log
lim
d/dx
Dx
|◻|
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc
asin
acos
atan
acot
asec
acsc
sinh
cosh
tanh
coth
sech
csch
asinh
acosh
atanh
acoth
asech
acsch
## Step-by-step explanation
Problem to solve:
$\left(5x^2-3\right)\left(5x^2+3\right)$
Learn how to solve special products problems step by step online.
$\left(5x^2\right)^2-1\cdot 3^2$
Learn how to solve special products problems step by step online. Solve the product (5x^2-3)(5x^2+3). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2, where:<ul><li>The first term (a) is 5x^2.</li><li>The second term (b) is 3.</li></ul>Then:. Calculate the power 3^2. The power of a product is equal to the product of it's factors raised to the same power. Multiply -1 times 9.
$25x^{4}-9$
$\left(5x^2-3\right)\left(5x^2+3\right)$
Special products
7
### Time to solve it:
~ 0.04 s (SnapXam) | 437 | 1,070 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 1, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 4.15625 | 4 | CC-MAIN-2020-40 | latest | en | 0.658998 |
http://mathhelpforum.com/statistics/114677-working-out-mean-print.html | 1,516,674,624,000,000,000 | text/html | crawl-data/CC-MAIN-2018-05/segments/1516084891705.93/warc/CC-MAIN-20180123012644-20180123032644-00645.warc.gz | 218,379,384 | 2,979 | # Working out the mean
• Nov 15th 2009, 09:19 AM
BabyMilo
Working out the mean
The times $x_{1},x_{2},x_{3},...,x_{20}$, in minutes, taken by 20 employees to complete a task are summaried by
$\sum(x-50)=140$
using $\overline{x}=\frac{\sum x}{n}$
$\overline{x}=\frac{140}{20}=7$
then add 50 to 7 = 57 is the $\overline{x}$
but in the back of the book, it says 52.8.
Which one is right?
for the 52.8, it uses $\overline{x}=\frac{140}{50}=2.8$
again, Which one is right?
• Nov 20th 2009, 11:05 AM
CaptainBlack
Quote:
Originally Posted by BabyMilo
The times $x_{1},x_{2},x_{3},...,x_{20}$, in minutes, taken by 20 employees to complete a task are summaried by
$\sum(x-50)=140$
using $\overline{x}=\frac{\sum x}{n}$
$\overline{x}=\frac{140}{20}=7$
then add 50 to 7 = 57 is the $\overline{x}$
but in the back of the book, it says 52.8.
Which one is right?
for the 52.8, it uses $\overline{x}=\frac{140}{50}=2.8$
again, Which one is right?
$\sum_{x_i}^{20} ({x_i}-50)=140$
so divide by $20$:
$\sum_{x_i}^{20} \frac{({x_i}-50)}{20}=7$
or:
$\sum_{x_i}^{20} \left[\frac{x_i}{20}-\frac{50}{20}\right]=7$
which gives:
$\overline{x}-50=7$
or:
$\overline{x}=57$
CB | 448 | 1,179 | {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 18, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 4.46875 | 4 | CC-MAIN-2018-05 | longest | en | 0.75052 |
https://nz.education.com/exercises/fourth-grade/multi-digit-numbers/ | 1,610,747,550,000,000,000 | text/html | crawl-data/CC-MAIN-2021-04/segments/1610703496947.2/warc/CC-MAIN-20210115194851-20210115224851-00522.warc.gz | 487,862,170 | 23,788 | # Search Our Content Library
11 filtered results
11 filtered results
Multi-Digit Numbers
Sort by
Place Value Up to Ten Thousands Place
Exercise
Place Value Up to Ten Thousands Place
Build students’ confidence in solving math problems with large numbers using this exercise on place values up to the ten thousands place.
Math
Exercise
Comparing Multi-Digit Numbers
Exercise
Comparing Multi-Digit Numbers
This elucidating Education.com exercise will show students working with multiplication, division, addition, or subtraction how to compare multi digit numbers.
Math
Exercise
Place Value and Numbers in Expanded Form
Exercise
Place Value and Numbers in Expanded Form
This exercise demonstrates how addition in larger numbers is simpler when numbers are dealt with in their expanded form.
Math
Exercise
Find the Factors of Prime and Composite Numbers
Exercise
Find the Factors of Prime and Composite Numbers
Have your fourth graders work through multiplication problems by learning about factors and why they are important for problem solving.
Math
Exercise
Rounding Multi-Digit Numbers to the Nearest 100,000
Exercise
Rounding Multi-Digit Numbers to the Nearest 100,000
With this exercise, students will be able to simplify large numbers by rounding to the nearest 100,000.
Math
Exercise
Rounding Multi-Digit Numbers to the Nearest 1,000
Exercise
Rounding Multi-Digit Numbers to the Nearest 1,000
Help students simplify math problems with the ability to round multi digit numbers to the nearest 1,000.
Math
Exercise
Place Value and Multiplicative Comparisons
Exercise
Place Value and Multiplicative Comparisons
Translate word problems into their numeric equivalent with this exercise that teaches both place value and multiplicative comparisons.
Math
Exercise
Rounding Multi-Digit Numbers to the Nearest 10000
Exercise
Rounding Multi-Digit Numbers to the Nearest 10000
Students will find math so much easier after they learn they can round multi digit numbers to the nearest 10,000.
Math
Exercise
Multi-Digit Multiplication and Doubling
Exercise
Multi-Digit Multiplication and Doubling
Aid your fourth grader in learning multi-digit multiplication with these exercises that show students how to visualize doubling.
Math
Exercise
Place Value and the Thousands Place
Exercise
Place Value and the Thousands Place
Before students can soar in math, they’ll first need to learn how to find the thousands place in this exercise. | 503 | 2,422 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.9375 | 4 | CC-MAIN-2021-04 | latest | en | 0.882821 |
https://www.teacherspayteachers.com/Browse/Search:slope%20between%20two%20points | 1,547,811,683,000,000,000 | text/html | crawl-data/CC-MAIN-2019-04/segments/1547583660070.15/warc/CC-MAIN-20190118110804-20190118132804-00181.warc.gz | 980,918,695 | 51,702 | showing 1-24 of 542 results
With this activity, student will find the slope between two points and then color the appropriate space on the mandala. Slope is a difficult yet essential algebra skill that students need to master, and this worksheet allows students to have fun while practicing a valuable skill! As an added bonus,
Subjects:
Types:
Also included in: Algebra 1 Color by Number Bundle 1: 11 Essential Skills
\$2.00
80 Ratings
4.0
PDF (1.74 MB)
Calculating Slope Using Two Points Color By Number In this activity, students will find the slope between two points. Some of the solutions are fractions. Zero slope and undefined slope are included. When finished solving the problems, they will color a picture based on their answers. There are
Subjects:
Types:
Also included in: Slope Activity Bundle
\$2.00
16 Ratings
3.9
PDF (6.39 MB)
Included is a dominoes activity on slope. Students will be calculating the slope between two points using the slope formula. This is a great activity for working in pairs, or small groups. I also have a BUNDLE that includes this activity and 20 other math dominoes activities.
Subjects:
Types:
\$3.50
15 Ratings
4.0
PDF (2.29 MB)
This activity will get your students to use their knowledge of slope in order to solve problems. Every correct answer helps them find their way through the labyrinth. In the end, students should complete every problem on the page without repetition. This is one of my favorite activities to do as an
Subjects:
Types:
CCSS:
FREE
41 Ratings
3.9
PDF (1.25 MB)
Students work in partners to find the slope between 2 points in this collaborative "Around the Clock" partner scavenger hunt algebra activity. Each partner gets a clock with 12 unique coordinate pairs. Each partner's coordinate pairs are different but the slopes between them are the same, encouragin
Subjects:
Also included in: Slope Activities Bundle
\$3.50
13 Ratings
4.0
PDF (1.63 MB)
Students will solve for the slope between two points using the slope formula. Students will match the two points with the correct answer on the puzzle pieces. Included in this product: --Teacher Instructions --Teacher Tips --Slope Formula Poster(Colored and Black and White) --32 Cards: All Four Typ
Subjects:
Types:
\$3.00
13 Ratings
4.0
PDF (1.8 MB)
This download includes an independent worksheet and a partner activity to practice evaluating the slope formula when given two points. The independent worksheet asks students to evaluate the slope in six problems including integers that yield both positive and negative slopes. The seventh questi
Subjects:
Types:
\$2.00
5 Ratings
4.0
PDF (488.2 KB)
All of the problems in this worksheet require students to find the slope between two points. Undefined and zero slope are included. Each student will work one column of 9 problems. When they are finished, they compare answers. Even though the problems in each column are different, the students s
Subjects:
Types:
Also included in: Slope Activity Bundle
\$2.00
9 Ratings
4.0
PDF (23.11 MB)
In this activity, students will practice finding the slope between two points. Students will use the slope from their previous line to find the next problem. For an extension, you can also have students write the whole equation of the line, but then look for the slope to find the next points. Practi
Subjects:
Types:
\$3.00
8 Ratings
4.0
PDF (3.3 MB)
With this no-prep activity, students find slope between two given points using the slope formula. Then, they will find their answer on the abstract picture and fill in the space with a given pattern to reveal a beautiful, fun Zen design! Students can color their final products or leave them in bl
Subjects:
Types:
Also included in: Zen Math Algebra I Bundle
\$2.00
6 Ratings
4.0
PDF (1.08 MB)
Need an engaging activity to practice finding slope between two coordinate points using Google Classroom? This activity makes for great extra practice, math center, or early finisher work. This product is a no-prep digital maze using Google Sheets™. Students will be able to practice finding the s
Subjects:
Types:
CCSS:
\$2.00
5 Ratings
4.0
PDF (806.62 KB)
This set of 30 "I have, Who Has" cards is a fun way to get students speaking out loud in a math classroom. Students will read their cards and have to listen for the two points that describe the slope of the line on their card. I usually have students work on a separate piece of paper and give them a
Subjects:
Types:
\$2.00
4 Ratings
4.0
PDF (242.35 KB)
There are 3 leveled row games included in this product! For a row game, students work with a partner to practice finding the slope between two points. The pair of students will each solve different problems, but each row of problems will have the same answer. If their answers do not match, the stude
Subjects:
Types:
\$1.75
2 Ratings
4.0
PDF (1.67 MB)
Students will decide who partner A & B is. One at a time, students will choose a problem from the list and mark it off that they have done that problem so their partner can’t do the same problem (they can go in any order, but the problems are numbered to help with easy checking). Students will
Subjects:
Types:
\$3.00
2 Ratings
4.0
PDF (1.45 MB)
Students will be determining the slope between two points. Students will solve 16 problems then color in their answer to reveal a mystery picture. This is great practice for any class learning how to apply the slope formula to calculate the slope between two points.
Subjects:
Types:
\$3.00
1 Rating
4.0
PDF (2.67 MB)
Students will practice calculating the slope between two ordered pairs in this 12 station activity! After students calculate the slope at each station, they will use the slope to identify part of a story to cross out. After students have crossed out all of the parts of the story that correspond with
Subjects:
Types:
CCSS:
\$2.00
1 Rating
3.9
PDF (289.74 KB)
Students will be determining the slope between two points. There are a total of 12 problems. Students will shade in their answer to see which Halloween character arrived at the haunted house first. This worksheet works great for self assessment!
Subjects:
Types:
\$2.00
1 Rating
4.0
PDF (3.32 MB)
Complete lesson, start to finish at your finger tips. The lesson introduces finding slope of a line from a table or two points. The foldable is a great guided practice, the interactive notebook is a great way for students to collaborate and create and manipulate, the practice sheet can be used to re
Subjects:
CCSS:
Also included in: Linear Functions Mega Bundle: No Prep Foldable Lessons
\$2.00
1 Rating
4.0
PDF (1.76 MB)
How do you teach calculating slope with the formula y2-y1/x2-x1 while making real world connections to rate of change and the meaning of slope. Use this activity as part of your exploration of slope to connect linear patterns of change in the real world with abstract formulas that are needed for al
Subjects:
CCSS:
\$3.00
not yet rated
N/A
PDF (456.49 KB)
Students cut apart triangles and squares an then match the sides to form a topaz shape. Students match two ordered pairs with the slope between those ordered pairs.
Subjects:
Types:
\$1.00
not yet rated
N/A
PDF (53.68 KB)
This engaging activity is great for reviewing the slope formula. Students will solve one problem on their own before circulating around the room. Students will then find eight other students to solve the remaining problems. After completing a problem, students will sign their name in the box.
Subjects:
Types:
\$1.25
not yet rated
N/A
PDF (255.84 KB)
28 problems.
Subjects:
\$1.00
1 Rating
4.0
DOC (25.5 KB)
Students will calculate the slope between two points.
Subjects:
Types:
FREE
not yet rated
N/A
PDF (213.18 KB)
In this activity, students will find slope between 2 given points as they tap into their creative side! Students will use the 2 given points to find slope and then locate their answers in a box on the next page. They will follow the directions for each exercise accordingly and fill the appropriate
Subjects:
Types:
Also included in: Algebra I Create and Color Bundle 1
\$2.00
7 Ratings
4.0
PDF (1.27 MB)
showing 1-24 of 542 results
Teachers Pay Teachers is an online marketplace where teachers buy and sell original educational materials. | 1,959 | 8,271 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.375 | 3 | CC-MAIN-2019-04 | latest | en | 0.92139 |
https://oneclass.com/study-guides/ca/western/biol/biology-2244ab/300763-chapter-7-notesdocx.en.html | 1,524,181,239,000,000,000 | text/html | crawl-data/CC-MAIN-2018-17/segments/1524125937074.8/warc/CC-MAIN-20180419223925-20180420003925-00264.warc.gz | 671,428,301 | 41,728 | Study Guides (247,963)
Canada (121,192)
Biology (1,525)
All (3)
# Chapter 7 Notes.docx
5 Pages
116 Views
School
Department
Biology
Course
Biology 2244A/B
Professor
All Professors
Semester
Fall
Description
thBio 2244B Textbook Notes Chapter 7 71 72 73 75 March 13 201271 OverviewDefinitionsHypothesis a claim or statement about a property of a populationHypothesis test test of significance a standard procedure for testing a claim about a property of a populationRecall the rare event rule if under a given assumption the probability of a particular observed event is exceptionally small we conclude that the assumption is probably not correct72 Basics of Hypothesis TestingComponents of a formal hypothesis testoNull hypothesis HA statement that the value of a population parameter such as 0proportion mean or standard deviation is equal to some claimed value We test the null hypothesis directly in the sense that we assume it is true and reach a conclusion to either reject H or fail to reject H00oAlternative hypothesis Hor H the statement that the parameter has a value that 1 asomehow differs from the null hypothesis For this chapter the symbolic form of the alternative hypothesis must use one of these symbolsoror oTest statistic a value computed from the sample data and it is used in making the decision about the rejection of the null hypothesisit is found by converting the sample statistic to a score with the assumption that the null hypothesis is true ppzTest statistic for proportion pqnxxztsTest statistic for meanOR nnTest statistic for standard deviation 2n1s2X2Critical region rejection region the set of all values of the test statistic that cause us to reject the null hypothesisSignificance level a the probability that the test statistic will fall in the critical region when the null hypothesis is actually trueoIf the test statistic falls within the critical region we reject the null hypothesis so a is the probability of making the mistake of rejecting the null hypothesis when it is actually trueCritical value any value that separates the critical region where we reject the null hypothesis from values of the test statistic that do not lead to rejection of the null hypothesis oCritical values depend on the nature of the null hypothesis the sampling distribution that applies and a oSee the figure at right to help determine what critical value to use Tails the extreme regions in a distribution that are bounded by critical valuesoTwotailed test the critical region is in the two extremes of the regions tails under the curve
More Less
Related notes for Biology 2244A/B
Me
Log In
OR
Join OneClass
Access over 10 million pages of study
documents for 1.3 million courses.
Sign up
Join to view
OR
By registering, I agree to the Terms and Privacy Policies
Already have an account?
Just a few more details
So we can recommend you notes for your school.
Reset Password
Please enter below the email address you registered with and we will send you a link to reset your password.
Add your courses
Get notes from the top students in your class.
Request Course
Submit | 650 | 3,110 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.703125 | 4 | CC-MAIN-2018-17 | latest | en | 0.829448 |
https://www.coursehero.com/file/5632542/Day07-slides/ | 1,513,049,460,000,000,000 | text/html | crawl-data/CC-MAIN-2017-51/segments/1512948514250.21/warc/CC-MAIN-20171212021458-20171212041458-00596.warc.gz | 730,967,762 | 23,469 | # Day07-slides - 1 Atms 502 CS 505 CSE 566 Numerical Fluid...
This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
This is the end of the preview. Sign up to access the rest of the document.
Unformatted text preview: 1 Atms 502 CS 505 CSE 566 Numerical Fluid Dynamics Thu., 14 September 2006 9/29/06 Atms 502 - Fal 2006 - Jewett 2 Our original equation: Our expression for u tt was: Substituting, we get: • This is the modified equation • It is what is actually solved by the F.D. method • U xx term: implicit artificial viscosity The modifed equation (2) u tt = c 2 u xx + " t # u ttt 2 + c 2 u ttx + ... \$ % & ’ ( ) + " x c 2 u xxt # c 2 2 u xxx + ... \$ % & ’ ( ) (4) u t + cu x = " # t 2 u tt + c # x 2 u xx + higher order terms (1) u t + cu x = c " x 2 1 # \$ ( ) u xx + (..)( " x ) 2 u xxx + higher order terms 9/29/06 Atms 502 - Fal 2006 - Jewett 3 The modifed equation (4) Modified equation for the upstream method: u t + cu x = c " x 2 1 # \$ ( ) u xx + (..)( " x ) 2 u xxx + higher order terms L=2 ∆ x Anderson et al., chapter 4 L → ʿ No amplitude error for ν =1 (it matches the unit circle)....
View Full Document
{[ snackBarMessage ]}
### Page1 / 3
Day07-slides - 1 Atms 502 CS 505 CSE 566 Numerical Fluid...
This preview shows document pages 1 - 2. Sign up to view the full document.
View Full Document
Ask a homework question - tutors are online | 476 | 1,482 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.75 | 3 | CC-MAIN-2017-51 | latest | en | 0.671039 |
https://www.includehelp.com/mcq/how-many-layers-do-we-need-to-create-a-clipping-mask.aspx | 1,696,105,057,000,000,000 | text/html | crawl-data/CC-MAIN-2023-40/segments/1695233510707.90/warc/CC-MAIN-20230930181852-20230930211852-00442.warc.gz | 881,513,114 | 32,028 | # How many layers do we need to create a clipping mask?
57. How many layers do we need to create a clipping mask?
1. One
2. Two
3. Three
4. Four
Explanation:
Two layers are needed to create a clipping mask. | 56 | 210 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.5625 | 3 | CC-MAIN-2023-40 | latest | en | 0.831911 |
http://tibasicdev.wikidot.com/pages-3/p/7 | 1,596,963,467,000,000,000 | text/html | crawl-data/CC-MAIN-2020-34/segments/1596439738523.63/warc/CC-MAIN-20200809073133-20200809103133-00391.warc.gz | 109,451,089 | 8,994 | Pages 3
Optimization: Math Operations and Keys optimization http://tibasicdev.wikidot.com/optimize-math
Optimization: Putting Ans Into Practice optimization http://tibasicdev.wikidot.com/optimize-ans
Optimization: Storing Variables optimization http://tibasicdev.wikidot.com/optimize-variables
Optimization: The Graph Screen optimization http://tibasicdev.wikidot.com/optimize-graph
Optimization: User Input optimization http://tibasicdev.wikidot.com/optimize-input
Optimization Walkthrough http://tibasicdev.wikidot.com/optimization-walkthrough
Optimizations: Displaying Text optimization http://tibasicdev.wikidot.com/optimize-text
OS Changelog http://tibasicdev.wikidot.com/changelog
Overview redirect http://tibasicdev.wikidot.com/overview
Overview of Commands command http://tibasicdev.wikidot.com/commands
Pages _sandbox http://tibasicdev.wikidot.com/pages
Pages 2 _sandbox http://tibasicdev.wikidot.com/pages-2
Pages 3 http://tibasicdev.wikidot.com/pages-3
Pages not Command Tag _sandbox http://tibasicdev.wikidot.com/pages-not-command-tag
Partial Probability http://tibasicdev.wikidot.com/partial-probability
Pascal's Triangle http://tibasicdev.wikidot.com/pascal-triangle
Petals Around the Rose http://tibasicdev.wikidot.com/petals-around-the-rose
Pictures and GDBs http://tibasicdev.wikidot.com/pictures
Piecewise Expression redirect http://tibasicdev.wikidot.com/piecewise-expression
Piecewise Expressions conditional feature techniques _techniques1 http://tibasicdev.wikidot.com/piecewise-expressions
Pipes http://tibasicdev.wikidot.com/pipes
Place for random files http://tibasicdev.wikidot.com/files
Planning Programs comments design plan pseudocode _design1 http://tibasicdev.wikidot.com/plan
Plot redirect http://tibasicdev.wikidot.com/plot
Plot1 redirect http://tibasicdev.wikidot.com/plot1
Plot2 redirect http://tibasicdev.wikidot.com/plot2
Plot3 redirect http://tibasicdev.wikidot.com/plot3
Polar (disambiguation) http://tibasicdev.wikidot.com/polar
Polynomial Division http://tibasicdev.wikidot.com/polynomial-division
Pong http://tibasicdev.wikidot.com/pong
Portability calculators commands design featured_article functions portability _design8 http://tibasicdev.wikidot.com/portability
Portable TI-Basic Developer portable http://tibasicdev.wikidot.com/portable
Portal Sitemap _sandbox http://tibasicdev.wikidot.com/portal-sitemap
Probability Distributions http://tibasicdev.wikidot.com/probability-distributions
Productivity Tips http://tibasicdev.wikidot.com/productivity-tips
Program Archives http://tibasicdev.wikidot.com/archives
Program Protection authorization password program protection techniques trial _techniques12 http://tibasicdev.wikidot.com/protection
Programmer Indicators http://tibasicdev.wikidot.com/programmer-indicators
Programs experiment games programs sample http://tibasicdev.wikidot.com/programs
Programs http://tibasicdev.wikidot.com/programs-h
Project Ideas experiment http://tibasicdev.wikidot.com/project-ideas
Projects not-done http://tibasicdev.wikidot.com/projects
Proposal v.2.2 http://tibasicdev.wikidot.com/proposal
Pythagorean Triples http://tibasicdev.wikidot.com/pythagorean-triples | 800 | 3,145 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3 | 3 | CC-MAIN-2020-34 | latest | en | 0.558141 |
http://www.badmintoncentral.com/forums/showthread.php/125838-Stringway-Wise-gamma/page2 | 1,386,815,956,000,000,000 | text/html | crawl-data/CC-MAIN-2013-48/segments/1386164351837/warc/CC-MAIN-20131204133911-00059-ip-10-33-133-15.ec2.internal.warc.gz | 243,962,757 | 22,543 | ## User Tag List
1. Regular Member
Join Date
Sep 2003
Location
Posts
598
Post Thanks / Like
Mentioned
2 Post(s)
Tagged
one other thing wrong about your attached picture is that the racket is improperly mounted on the throat end.
the black hold downs should be above the red internal supports.
2. Regular Member
Join Date
Aug 2012
Location
Netherlands
Posts
18
Post Thanks / Like
Mentioned
1 Post(s)
Tagged
The image was sent today by stringway... i heard they advise a new way of mounting and this is the one send by Mr Timmer this afternoon. So i guess they changed it. Saw this picture before by Mr timmer under the name stringtechno
3. Regular Member
Join Date
Apr 2007
Location
Netherlands
Posts
171
Post Thanks / Like
Mentioned
0 Post(s)
Tagged
## Direct and indirect racquet support
Hi guys, interesting discussion about the support system.
I
would like to add some information to this discussion:
When we designed our racquet support we made a computer program to calculate the stress in the racquet material for different kind of racquet supports.
Our 5 point direct (inside) system is the result of this development.
Many people think that it is important to minimize the deformation of the racquet during stringing but this is not true (while it may sound very logic).
A racquet does not break because the deformation is it too high it brakes because the stress (force per square millimeter) is too high in any place.
The graph shows the stress in a racquet for different racquet supports.
[IMG]http://imageshack.us/a/img189/2774/racquetstress.jpg[/IMG]
This graph shows:
- The minimum stress occurs with a 3 point inside system.
- The stress goes up with an indirect (outside system) when you get closer to 3 and 9 o’clock.
Therefore it is dangerous to string a badminton racquet with the supports too far away from the head.
From this development we learned:
- That the systems have to be divided in direct and indirect systems.
[IMG]http://imageshack.us/a/img27/9536/direktindirekt.jpg[/IMG]
- The stress in the racquet and the change of breaking is lower with a direct system.
- With direct systems it does not make much difference for the racquet if we bottom up or top down.
- That outside support CAUSE extra stress in the racquet and raise the change of cracks.
The stringway/laserfibre will force you to go top to bottom for the crosses if you care about minimizing tension loss.
I would like to know why because we advise to go bottom up.
Also love the laserfibre! too bad you couldnt use the fixed clamps for the crosses....that's terrible! it is worth thinking about a upgrade in the future indeed.
I would like to know why this is, our tournament stringers use the fixed clamps for all strings.
Also i heard that laserfibre where imitations of string????? i thought that technifibre made the machines for technifibre. The store claimed that stringway did not prolonque their pattent and then some companies tried to copy. I found that hard to believe.
We made the machines for Laserfibre. Our tensionhead was patented in 1983 so that patent is not valid anymore and Eagnas copied our tensioner in 2010.
We do advise to support badminton racquets as shown on the picture above so that the wider throatside of the racquet is supported by 3 supports.
There is a very simple solution when the last cross can not be clamped with a fixed clamp:
- Skip the cross before the last one and enter the last one first.
- Then enter the one before last and pull “knot tension” on both.
- Clamp the string before the last one.
4. in the graph.
for the 3 point inside and 3 point outside support cases, why is the stress highest at position 0 when there is a direct point of support right at position 0?
5. Regular Member
Join Date
Mar 2011
Location
Posts
775
Post Thanks / Like
Mentioned
13 Post(s)
Tagged
Many people think that it is important to minimize the deformation of the racquet during stringing but this is not true (while it may sound very logic).
While your simulations seem good and all, it is a fact that if you don't try to prevent racket deformation during stringing (at higher tensions), the racket WILL break. For instance, if you put your side supports at the 10/2 position and string at 30 lbs, the racket has a very high chance of cracking at the 3/9 position. If the supports are closer to the 3/9 position, it has much lesser chance of breaking.
The only reason I can see that your system would be safe is that the top and bottom supports are so strong that they prevent/minimize the deformation of the racket while stringing the mains, which still goes against what you said :\
6. Regular Member
Join Date
Sep 2003
Location
Posts
598
Post Thanks / Like
Mentioned
2 Post(s)
Tagged
The stringway/laserfibre will force you to go top to bottom for the crosses if you care about minimizing tension loss.
Originally Posted by stringtechno
I would like to know why because we advise to go bottom up.
My reply: Please see my replies previously in this thread. hold down clamps are physically obstructing me from clamping (from above) the top 2 cross strings of a badminton racket (for fly clamps especially). Specifically they will not be aligned straight...it will be crooked.
I cannot clamp from below with a fly clamp because the black mounting plate is obstructing clamp from getting at the first cross. Therefore a fixed clamp cannot get to the first cross. The only option is to pull the top two crosses and clamp. There's a separate thread about pulling 2 crosses at once.
-----
Also love the laserfibre! too bad you couldnt use the fixed clamps for the crosses....that's terrible! it is worth thinking about a upgrade in the future indeed.
Originally Posted by stringtechno
I would like to know why this is, our tournament stringers use the fixed clamps for all strings.
I talked about it back in 2007-2008 (i had both sets of fixed clamps - tennis and squash/badminton) here:
talk about the clamp design here
pics are here:
the gaps between teeth were too big..so it would either squish or push 2 adjacent mains.
Matsumoto...if you have more questions u should read through the other laserfibre/stringway threads or contact stringtechno directly.
A lot of this stuff has been discussed over and over for many years.
I hope these links illustrate everything.
As stringtechno said...regardless of the label on the machine..it was manufactured by stringway and the parts come directly from them. It's the same machine. NO difference whatsoever.
7. Regular Member
Join Date
Sep 2003
Location
Posts
598
Post Thanks / Like
Mentioned
2 Post(s)
Tagged
Let's shift the focus back on the merits of the machine:
1) it can string at high tension (regardless of what type of support system it uses...the merits of each one were discussed in another thread here: http://www.badmintoncentral.com/foru...ght=laserfibre. continue it there)
2) it's constant pull
3) low maintenance
4) drop weight but does not require weight to be level
5) can string all rackets (tennis, squash, racketball, badminton)
6) has option for fixed clamps
Limitations (my opinion):
1) cannot upgrade to electronic easily (WISE) or unless you switch to a full electronic (EM-450)
2) fixed clamps for badminton large gap between teeth such that it's only good for mains and not for crosses (use fly clamps instead)
3) top down stringing for crosses recommended because top most cross cannot be clamped as close to frame without being misaligned due to contact with hold down clamp, or mounting plate.
Like I said before. Terrific machine for 6 years. My needs changed warranting me to get a new machine.
People...use the search button and reach your own conclusions. A lot of what i said has been said before.
Last edited by DarthHowie; 04-16-2013 at 03:46 PM.
8. Regular Member
Join Date
Apr 2007
Location
Netherlands
Posts
171
Post Thanks / Like
Mentioned
0 Post(s)
Tagged
Excuse me for entering the last post twice, can you remove or empty it Kwun?
I think, that the background information about a design of a machine or system deals very much with the machine.
In the stringing industry many things are produced based on what stringers experience and not based on calculations or theories, like real developments.
The outside supports “were born” in this way, stringers saw that the racquet got wider and ht industry “found out” the external supports to prevent that.
The first thing that was supplied was a bracket that was fixed between 3 and 9 o’clock. This bracket disappeared faster than it came because the racquets broke on the machine.
Our philosophy is to prevent the racquet from getting wider by preventing it from the getting shorter.
The worst moment for a racquet occurs when all main strings are tensionedy a DIRECT SUPPORT SYSTEM works directly against the forces of the mains.
If the racquet does not get shorter it does not get wider either.
for the 3 point inside and 3 point outside support cases, why is the stress highest at position 0 when there is a direct point of support right at position 0?
The stress which cracks the racquet is the bending stress and this stress is always maximum at the position of the supports.
On the Indirect system at 12 o’clock the racquet is actually bended around the central support, therefore it is much better to use a very wide central supports.
The 3 wide supports on the SW machine at the head side support the racquet against the forces of the main strings DIRECTLY.
You can also turn the question about the outside supports around:
Why do you never hear of broken racquet on simple inside support systems like the ones from Prince or Ektelon?
The answer is simple: The outside supports introduce bending stress in the racquet that is not there at all without the supports.
I will illustrate this with a picture in the next post.
Most machine we sell to badminton stringers at the moment are supplied with Yonex flying clamps, these are very good clamps and the price of the machine is much lower than with fixed clamps.
Last edited by stringtechno; 04-17-2013 at 12:07 PM.
9. Regular Member
Join Date
Apr 2007
Location
Netherlands
Posts
171
Post Thanks / Like
Mentioned
0 Post(s)
Tagged
This picture explains more about direct compared to indirect support and the stress that is caused by the indirect support
The support in C is a direct support and in A is an indirect support.
Conclusion can be:
- There is no stress between point A and C without the support in A.
- Supporting the beam in C were the Force works causes no stress at all between A and C
10. Regular Member
Join Date
Mar 2011
Location
Posts
775
Post Thanks / Like
Mentioned
13 Post(s)
Tagged
Our philosophy is to prevent the racquet from getting wider by preventing it from the getting shorter.
The worst moment for a racquet occurs when all main strings are tensionedy a DIRECT SUPPORT SYSTEM works directly against the forces of the mains.
If the racquet does not get shorter it does not get wider either.
Now that I can agree with.
It's different than "minimizing deformation is not important", because by preventing the racket to get shorter, you minimize deformation :P
11. Regular Member
Join Date
Apr 2007
Location
Netherlands
Posts
171
Post Thanks / Like
Mentioned
0 Post(s)
Tagged
You are right I put that wrong, of course you have to prevent deformation of the racquet, but in the main direction not in the “indirect” direction.
I actually meant, that not the deformation but the stress in the material is the danger for the racquet.
Compared with the beam: The deformation in point A is big but there is no stress at all between A and C.
12. Regular Member
Join Date
Sep 2005
Location
Holland
Posts
3,957
Post Thanks / Like
Mentioned
0 Post(s)
Tagged
Why do I feel as if I've read this entire discussion before?
I have a riddle for you, seeing as you're quite obviously an engineer. Why does every motor manufacturer only use two bearing on each axle instead of 3? (Seeing as your so very much in favor of 3 supports as per post #26)
13. Regular Member
Join Date
Apr 2007
Location
Netherlands
Posts
171
Post Thanks / Like
Mentioned
0 Post(s)
Tagged
Why do I feel as if I've read this entire discussion before?
It has been on tenniswarehouse also, but it comes back every now and then because there are many misunderstanding about the way a racquet support works.
I have a riddle for you, seeing as you're quite obviously an engineer.
Why does every motor manufacturer only use two bearing on each axle instead of 3? (Seeing as your so very much in favor of 3 supports as per post #26)
This is all a matter of the maximum load, as you probably know crank- and cam shafts of cars have much more bearings than 2.
For a racquet support counts the more supports on the inside the lower the stress in the racquet.
If there would be an inside support at every position of a main string the racquet would not feel anything at all.
Because this is practically impossible we choose for 3 wide supports, one of them is adjustable so that every shape can be supported.
14. Regular Member
Join Date
Sep 2005
Location
Holland
Posts
3,957
Post Thanks / Like
Mentioned
0 Post(s)
Tagged
Okay, well thank you again for the copy paste, I'll just proceed with what I wanted to say.
The idea supporting 1 beam with 3 supports is not used in these simple mechanical systems because of the risk of getting a moment-force on your middle support.
If you can place a support directly under the load the system is amazing, but if you place a load slightly in between supports then the statics of the system change. Now the beam in between the other supports even wants to go up. Imaging the stress on that part of the beam if there's a load on there as well.
This is why I object to you're simplief scematic, you make it too easy on yourself
15. Regular Member
Join Date
Apr 2007
Location
Netherlands
Posts
171
Post Thanks / Like
Mentioned
0 Post(s)
Tagged
This is why I object to you're simplief scematic, you make it too easy on yourself
The example with the beam is only to demonstrate that a support at the end (were the deformation is maximum) introduces bending stress where there is no stress at all without that support.
If you compare the racquet with the beam you have to add a number of forces on each side of the support in C.
Therefore it is very important to choose the right position of the support “in between” all these strings.
The graph shows that the stress in the racquet is minimum when the distance between the supports is 52 mm.
In this calculation we took an oversize racquet because that is the worst case that can occur.
16. Originally Posted by stringtechno
For 6-point outside support (as most of us have), 175 mm is actually quite far down the racket - roughly at the level of the fifth hole after the last main on a standard pattern. That's pretty much at 3 o'clock.
17. Regular Member
Join Date
Apr 2007
Location
Netherlands
Posts
171
Post Thanks / Like
Mentioned
0 Post(s)
Tagged
The calculation, that is shown in the graph is made for the most difficult situation which are oversize tennis racquets at high tensions.
So 175 mm counts for that situation.
The smaller the racquet the smaller the distance.
At the same time this is the danger, when badminton racquets are strung on a support that is actually meant for tennis, and is not adjustable. In that case the outside support come too close to 3 and 9 o’clock and the stress in the racquet will be very long.
Iow: The longer the “lever” of the forces of the outside supports the higher the bending force and the stress in the racquet.
Page 2 of 3 First 1 2 3 Last
#### Posting Permissions
• You may not post new threads
• You may not post replies
• You may not post attachments
• You may not edit your posts
• | 3,698 | 15,787 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.71875 | 3 | CC-MAIN-2013-48 | longest | en | 0.925368 |
https://lovelylittlelemmas.rjprojects.net/category/counterexamples/ | 1,723,204,475,000,000,000 | text/html | crawl-data/CC-MAIN-2024-33/segments/1722640763425.51/warc/CC-MAIN-20240809110814-20240809140814-00667.warc.gz | 289,056,331 | 19,976 | # The 14 closure operations
I’ve been getting complaints that my lemmas have not been so lovely (or little) lately, so let’s do something a bit more down to earth. This is a story I learned from the book Counterexamples in topology by Steen and Seebach [SS].
A topological space comes equipped with various operations on its power set . For instance, there are the maps (interior), (closure), and (complement). These interact with each other in nontrivial ways; for instance .
Consider the monoid generated by the symbols (interior), (closure), and (complement), where two words in , , and are identified if they induce the same action on subsets of an arbitrary topological space .
Lemma. The monoid has 14 elements, and is the monoid given by generators and relations
Proof. The relations , , and are clear, and conjugating the first by shows that is already implied by these. Note also that and are monotone, and for all . A straightforward induction shows that if and are words in and , then . We conclude that
so (this is the well-known fact that is a regular open set). Conjugating by also gives the relation (saying that is a regular closed set).
Thus, in any reduced word in , no two consecutive letters agree because of the relations , , and . Moreover, we may assume all occurrences of are at the start of the word, using and . In particular, there is at most one in the word, and removing that if necessary gives a word containing only and . But reduced words in and have length at most 3, as the letters have to alternate and no string or can occur. We conclude that is covered by the 14 elements
To show that all 14 differ, one has to construct, for any in the list above, a set in some topological space such that . In fact we will construct a single set in some topological space where all 14 sets differ.
Call the sets for the noncomplementary sets obtained from , and their complements the complementary sets. By the arguments above, the noncomplementary sets always satisfy the following inclusions:
It suffices to show that the noncomplementary sets are pairwise distinct: this forces (otherwise ), so each noncomplementary set contains and therefore cannot agree with a complementary set.
For our counterexample, consider the 5 element poset given by
and let be the disjoint union of (the Alexandroff topology on , see the previous post) with a two-point indiscrete space . Recall that the open sets in are the upwards closed ones and the closed sets the downward closed ones. Let . Then the diagram of inclusions becomes We see that all 7 noncomplementary sets defined by are pairwise distinct.
Remark. Steen and Seebach [SS, Example 32(9)] give a different example where all 14 differ, namely a suitable subset . That is probably a more familiar type of example than the one I gave above.
On the other hand, my example is minimal: the diagram of inclusions above shows that for all inclusions to be strict, the space needs at least 6 points. We claim that 6 is not possible either:
Lemma. Let be a finite topological space, and any subset. Then and .
But in a 6-element counterexample , the diagram of inclusions shows that any point occurs as the difference for some . Since each of and is either open or closed, we see that the naive constructible topology on is discrete, so is by the remark from the previous post. So our lemma shows that cannot be a counterexample.
Proof of Lemma. We will show that ; the reverse implication was already shown, and the result for follows by replacing with its complement.
In the previous post, we saw that is the Alexandroff topology on some finite poset . If is any nonempty subset, it contains a maximal element , and since is a poset this means for all . (In a preorder, you would only get .)
The closure of a subset is the lower set , and the interior is the upper set . So we need to show that if and , then .
By definition of , we get , i.e. there exists with . Choose a maximal with this property; then we claim that is a maximal element in . Indeed, if , then so , meaning that there exists with . Then and , which by definition of means . Thus is maximal in , hence since and . From we conclude that , finishing the proof.
The lemma fails for non- spaces, as we saw in the example above. More succinctly, if is indiscrete and , then and . The problem is that is maximal, but and .
References.
[SS] L.A. Steen, J.A. Seebach, Counterexamples in Topology. Reprint of the second (1978) edition. Dover Publications, Inc., Mineola, NY, 1995.
# Hodge diamonds that cannot be realised
In Paulsen–Schreieder [PS19] and vDdB–Paulsen [DBP20], the authors/we show that any block of numbers
satisfying , , and (characteristic only) can be realised as the modulo reduction of a Hodge diamond of a smooth projective variety.
While preparing for a talk on [DBP20], I came up with the following easy example of a Hodge diamond that cannot be realised integrally, while not obviously violating any of the conditions (symmetry, nonnegativity, hard Lefschetz, …).
Lemma. There is no smooth projective variety (in any characteristic) whose Hodge diamond is
Proof. If , we have , with equality for all if and only if the Hodge–de Rham spectral sequence degenerates and is torsion-free for all . Because contains an ample class, we must have equality on , hence everywhere because of how spectral sequences and universal coefficients work.
Thus, in any characteristic, we conclude that , so and the same for . Thus, is a fibration, so a fibre and a relatively ample divisor are linearly independent in the Néron–Severi group, contradicting the assumption .
Remark. In characteristic zero, the Hodge diamonds
cannot occur for any , by essentially the same argument. Indeed, the only thing left to prove is that the image cannot be a surface. If it were, then would have a global 2-form; see e.g. [Beau96, Lemma V.18].
This argument does not work in positive characteristic due to the possibility of an inseparable Albanese map. It seems to follow from Bombieri–Mumford’s classification of surfaces in positive characteristic that the above Hodge diamond does not occur in positive characteristic either, but the analysis is a little intricate.
Remark. On the other hand, the nearly identical Hodge diamond
is realised by , where is a curve of genus . This is some evidence that the full inverse Hodge problem is very difficult, and I do not expect a full classification of which Hodge diamonds are possible (even for surfaces this might be out of reach).
References.
[Beau96] A. Beauville, Complex algebraic surfaces. London Mathematical Society Student Texts 34 (1996).
[DBP20] R. van Dobben de Bruyn and M. Paulsen, The construction problem for Hodge numbers modulo an integer in positive characteristic. Forum Math. Sigma (to appear).
[PS19] M. Paulsen and S. Schreieder, The construction problem for Hodge numbers modulo an integer. Algebra Number Theory 13.10, p. 2427–2434 (2019).
# Rings that are localisations of each other
This is a post about an answer I gave on MathOverflow in 2016. Most people who have ever clicked on my profile will probably have seen it.
Question. If and are rings that are localisations of each other, are they necessarily isomorphic?
In other words, does the category of rings whose morphisms are localisations form a partial order?
In my previous post, I explained why and are not isomorphic, even as rings. With this example in mind, it’s tempting to try the following:
Example. Let be a field, and let . Let
be an infinite-dimensional polynomial ring over , and let
Then is a localisation of , and we can localise further to obtain the ring
isomorphic to by shifting all the indices by 1. To see that and are not isomorphic as rings, note that is closed under addition, and the same is not true in .
Is there a moral to this story? Not sure. Maybe the lesson is to do mathematics your own stupid way, because the weird arguments you come up with yourself may help you solve other problems in the future. The process is more important than the outcome. | 1,830 | 8,083 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.234375 | 3 | CC-MAIN-2024-33 | latest | en | 0.958022 |
https://brainmass.com/math/algebra/arithmetic-geometric-series-sequences-135655 | 1,656,608,461,000,000,000 | text/html | crawl-data/CC-MAIN-2022-27/segments/1656103850139.45/warc/CC-MAIN-20220630153307-20220630183307-00177.warc.gz | 179,881,759 | 74,665 | Explore BrainMass
# Arithmetic and Geometric Series Sequences
Not what you're looking for? Search our solutions OR ask your own Custom question.
This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!
Using the index "n" of the partial sums of a series as the domain, and the value of the corresponding partial sums of the series "Sn" as the range, is a series a function?
- Which of the basic functions, (i.e. - linear, quadratic, rational, exponential), is related to the arithmetic series?
- Which of the basic functions, (i.e. - linear, quadratic, rational, exponential), is related to the geometric series?
Give a couple of real life examples of both the Arithmetic and Geometric sequences and series. Also, explain how these types of examples might affect you personally.
https://brainmass.com/math/algebra/arithmetic-geometric-series-sequences-135655
## SOLUTION This solution is FREE courtesy of BrainMass!
Pleas see the detailed solution in the attached WORD file.
Yes, it is a function by using the index of a sequence as the domain and the value of the sequence as the range. Each of the input, i.e. the index, is corresponding to exact one output, the value of the sequence.
For an arithmetic sequence, a_n = a_1 + (n - 1) d, where a_1 is the first value of the sequence, d is the common difference of successive members, and n is the index. So it is a linear relationship between the index and the value with fixed and d.
For the geometric sequence, a_n = a_1 * r^(n-1) , , where a_1 is the first value of the sequence, r is common ratio of successive members, and n the index. So it is an exponential function.
This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here! | 415 | 1,799 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 4.15625 | 4 | CC-MAIN-2022-27 | latest | en | 0.91302 |
https://unitconversion.io/mins-to-weeks-conversion | 1,685,889,054,000,000,000 | text/html | crawl-data/CC-MAIN-2023-23/segments/1685224649986.95/warc/CC-MAIN-20230604125132-20230604155132-00495.warc.gz | 630,257,412 | 10,120 | #### Minutes to Weeks Conversion
This is our conversion tool for converting minutes to weeks.
To use the tool, simply enter a number in any of the inputs and the converted value will automatically appear in the opposite box.
min
### =
week
##### How to convert Minutes (min) to Weeks (week)
Converting Minutes (min) to Weeks (week) is simple. Why is it simple? Because it only requires one basic operation: multiplication. The same is true for many types of unit conversion (there are some expections, such as temperature). To convert Minutes (min) to Weeks (week), you just need to know that 1mins is equal to weeks. With that knowledge, you can solve any other similar conversion problem by multiplying the number of Minutes (min) by . For example, 3mins multiplied by is equal to weeks.
#### Fast Conversions
1 mins = weeks 5 mins = weeks 10 mins = weeks 15 mins = weeks 25 mins = weeks 100 mins = weeks 1000 mins = weeks 1 weeks = mins 5 weeks = mins 10 weeks = mins 15 weeks = mins 25 weeks = mins 100 weeks = mins 1000 weeks = mins
#### Blog
Digital Marketing Techniques for Language Learning Businesses: Reaching the Right Audience Top 5 Security Plugins to Keep Your WordPress Site Safe Key Benefits of Banking as a Service Tips for Creating High-Quality Video Content for Your Marketing Content Unlocking Potential: How the Gaming Industry is Transforming the Business Landscape | 312 | 1,399 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.3125 | 3 | CC-MAIN-2023-23 | latest | en | 0.889798 |
http://www.courant.com/features/parenting/sc-fam-1030-lifeskill-slice-pizza-20121030-32-story.html | 1,411,269,417,000,000,000 | text/html | crawl-data/CC-MAIN-2014-41/segments/1410657134511.2/warc/CC-MAIN-20140914011214-00215-ip-10-234-18-248.ec2.internal.warc.gz | 448,969,507 | 59,862 | # Slicing a pizza
Dr. Seuss' feuding Sneetches, some who "had bellies with stars" and "some with none upon thars," have nothing on pizza lovers, who divide fiercely into "squares" and "wedges" when it comes to slicing the pie. Now, a retired engineer thinks he has a way to please these oft-hostile camps.
Gib Van Dine was born in Kittanning, Pa., and lived in New Jersey before moving with his wife to Illinois. Here he noticed pizza cut into squares instead of the triangular slices he grew up with.
"They are always messy," he said of the squares. "You have to use a knife and fork. Any time you pick up a square-cut slice you get pizza sauce on your hands."
Yet, he concedes that the wedge shape can be problematic with bigger pizzas, like the 16-incher. "The pieces are so long," he said. "Your hand isn't big enough to keep the end from flopping down and all the ingredients sliding off."
Using two hands to hold the slice or a knife and fork are ways to handle the problem, he said. A third option: Van Dine's method for a 16-inch pie, which offers eight wedges that are shorter and, thus, easier to pick up and eat, yet also provides nine square-ish pieces for those who prefer their pizza that way.
Given a 16-inch pizza is often a party pie, Van Dine's method may be a way to bring everyone together.
Or maybe not.
"If you propose this to the guy cutting the pizza, it would cause a rebellion," said Rick Mabry, a mathematics professor at Louisiana State University in Shreveport. Mabry and a colleague, Paul Deiermann of Southeast Missouri State University in Cape Girardeau, Mo., made headlines in 2009 when they unveiled "The Pizza Conjecture," a mathematical proof to fairly apportion a pizza that had been cut into uneven slices.
Mabry said Van Dine's strategy is "doable" but would result in some pieces being larger than others, which can lead to envy among eaters. (On the other hand, as one calorie-conscious editor points out, the smaller squares are easier to halve and will satisfy those with smaller appetites.)
Mabry's solution comes not from being a mathematician but a pizza eater: "You need two pizzas. One cut in wedges and one in squares. That's the only way to resolve it. And I'm not sure you can even have them in the same room."
More pizza! Who's not for that, whether fan of square or wedge? Still, if all you have is one, here's Van Dine's method.
Tools needed: 16-inch pizza, an open mind, pizza cutter (our personal favorite is OXO's nonstick pizza wheel; oxo.com).Degree of difficulty: Once you figure the steps out, dividing a pie into wedges and squares isn't hard.
Directions
1. Make two cuts (two vertical, two horizontal) to create two 31/2-inch-wide rectangles through the center of the pizza. You now have four big pie quarters, four rectangular strips and a center square.
2. Cut each quarter piece in half to create two wedges. Slice each rectangular strip in half to create two squares. Leave the center square as is. You now have 17 pieces: eight wedges and nine squares.
wdaley@tribune.com
Related Content
• I love our state's fall foliage. What I don't like is fighting traffic jams on country roads, or worse, hiking up some dusty path to see it.
• On the afternoon of Saturday, Sept. 19, 1874 — a day rainy enough to call off baseball games in Hartford — a family weary of traveling moved into a new house on Farmington Avenue. The mother had given birth in June, and was still recovering from serious post-partum problems. The...
• A reader, in a cry for help, sends an email looking for a ruling.
• Long ago, before I-91 cut the city off from its riverfront, Hartford was open to the universe. (It was also open to flooding, but that's another story). EnvisionFest Hartford, an all-day event on Saturday, Sept. 20, would like to return Hartford to that time, but it also aims to...
• Things are about to get aromatic around the state this fall, as festivals honor the pungent plant in Mystic and Bethlehem.
• In 2008, David Hajdu published "The Ten-Cent Plague: The Great Comic Book Scare and How It Changed America," a historical look at 1950s paranoia aimed at the perceived moral depravity of comic books. He traveled around promoting it, but never had any book events in Hartford. | 1,003 | 4,261 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.21875 | 3 | CC-MAIN-2014-41 | longest | en | 0.971918 |
https://resources.quizalize.com/view/quiz/regional-diagnostic-assessment-math-10-quiz-quizalize-ba8c1fd0-2b04-47d4-abf6-83ed84fec260 | 1,712,968,079,000,000,000 | text/html | crawl-data/CC-MAIN-2024-18/segments/1712296816465.91/warc/CC-MAIN-20240412225756-20240413015756-00473.warc.gz | 464,152,064 | 23,305 | REGIONAL DIAGNOSTIC ASSESSMENT - MATH 10 Quiz | Quizalize
Quiz by EDMAR JOSEPH FLORES
Feel free to use or edit a copy
includes Teacher and Student dashboards
### Measure skillsfrom any curriculum
Tag the questions with any skills you have. Your dashboard will track each student's mastery of each skill.
• edit the questions
• save a copy for later
• start a class game
• automatically assign follow-up activities based on students’ scores
• assign as homework
• share a link with colleagues
• print as a bubble sheet
### Our brand new solo games combine with your quiz, on the same screen
Correct quiz answers unlock more play!
60 questions
• Q1
Arithmetic sequence is a sequence such that the difference between the consecutive terms is constant. The following describes an arithmetic sequence EXCEPT
c. 10, 20, 30, 40, 50, 60, …
a. 0, 1, 1, 2, 3, 5, 8, …
b. 5, 10, 15, 20, 25, 30, …
d. 11, 7, 3, -1, -5, -9, …
30s
• Q2
In the train, there are 125 passengers in the first carriage, 150 passengers in the second carriage and 175 in the third carriage, and so on in an arithmetic sequence. What’s the total number of passengers in the first 7 carriages?
d. 1400
c. 1300
a. 1100
b. 1200
30s
• Q3
How many terms of the sequence 1, 3, 5, 7, …. will give a sum of 961?
c. 32
d. 33
a. 30
b. 31
30s
• Q4
Which of the following is an example of a polynomial equation?
a. 3x-2 + 4x – 7 = 0
b. √(〖5x〗^2+3x) - 1 = 0
c. ¼x5 + 2x + 4 = 0
d. 5/4x² x² – 3x + 7 = 0
30s
• Q5
What is the perimeter of the rectangle if the length is 5 cm more than its width and the area is 50cm2?
d. 45 cm
a. 30 cm
c. 40 cm
b. 35 cm
30s
• Q6
Given a polynomial P(x), if (x – r) is a factor of P(x), what should P(r) be?
d. P(r) must either positive or negative.
c. P(r) must be equal to zero.
b. P(r) must be positive.
a. P(r) must be negative.
30s
• Q7
What is the fifth term of the geometric sequence sequence 3 , 6, 12,… ?
a. 2
c. 15
d. 48
b. 3
30s
• Q8
Which of the following illustrate a geometric sequence?
c. ½ , ¼ , 1/8 , …
a. 5, 10, 15, 20, 25, ….
d. 6, 12, 24, 48,…
b. 0,1,1,2,3,5,8,….
30s
• Q9
You are fully aware of the adverse effects of climate change. As a president of the School Supreme Government Council of your school, you invited students to attend a seminar at the same time an advocacy campaign every end of the month at the school’s covered court. On the first month of implementation, 16 students came. The next month there were 10 more students who came and so on. Assuming the number of participants continue to increase in the same manner, how many participants attended on the 10th month of your advocacy campaign?
d. 122
b. 96
a. 61
c. 106
30s
• Q10
What is the sum of the first 6 terms of geometric sequence 8, 16, 32,…. ?
c. 432
b. 256
d. 504
a. 216
30s
• Q11
The figure is an example of a(n) _____________.
c. geometric mean
a. arithmetic mean
b. arithmetic sequence
d. geometric sequence
30s
• Q12
Find the sum of the odd integers from 1 to 50.
d. 2500
a. 625
b. 850
c. 1225
30s
• Q13
Solve the factors of x3 + 3x2 + 3x + 1 = 0
c. ( x + 3) ( x + 1) ( x – 1 )
a. ( x + 1) ( x + 1 ) ( x + 1 )
d. ( x – 3 ) ( x – 1 ) ( x + 1 )
b. ( x – 1) (x – 1 ) ( x – 1 )
30s
• Q14
The Provincial Disaster and Risk Reduction Management Committee (PDRRMC) advised the residents living within the 10 km radius critical area to evacuate due to eminent eruption of a volcano. On the map that is drawn on a coordinate plane, the coordinates corresponding to the location of the volcano is (3,4). Suppose you live at a point (11,6) would you follow the advice of the PDDRMC?
b. no
a. yes
d. not sure
c. maybe
30s
• Q15
Below shows the map of your community which is always visited by typhoon. Suppose super typhoon given by the equation (x + 1)2 + (y + 5)2 = 81 will hit your community, where should you evacuate?
b. Church
a. Brgy. Hall
c. Gymnasium
d. School
30s
Teachers give this quiz to your class | 1,340 | 3,890 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.71875 | 4 | CC-MAIN-2024-18 | latest | en | 0.81895 |
https://studysoup.com/note/342105/uf-sta3032-spring-2016 | 1,476,995,842,000,000,000 | text/html | crawl-data/CC-MAIN-2016-44/segments/1476988717783.68/warc/CC-MAIN-20161020183837-00261-ip-10-171-6-4.ec2.internal.warc.gz | 844,380,351 | 16,427 | ×
### Let's log you in.
or
Don't have a StudySoup account? Create one here!
×
or
by: Tia Belvin
24
0
2
# Week 6 outline STA3032
Tia Belvin
UF
GPA 3.5
Get a free preview of these Notes, just enter your email below.
×
Unlock Preview
These notes outline the basics of 3.3-3.4 which is the end of Module 3. The notes were derived from the professors class notes, they are simplified and more basic.
COURSE
Engineering Statistics
PROF.
Demetris Athienitis
TYPE
Class Notes
PAGES
2
WORDS
CONCEPTS
Statistics
KARMA
25 ?
## Popular in Engineering and Tech
This 2 page Class Notes was uploaded by Tia Belvin on Saturday March 5, 2016. The Class Notes belongs to STA3032 at University of Florida taught by Demetris Athienitis in Spring 2016. Since its upload, it has received 24 views. For similar materials see Engineering Statistics in Engineering and Tech at University of Florida.
×
## Reviews for Week 6 outline
×
×
### What is Karma?
#### You can buy or earn more Karma at anytime and redeem it for class notes, study guides, flashcards, and more!
Date Created: 03/05/16
3.3 INFERENCE FOR POPULATION VARIANCE 1) We can calculate the estimated population variancewith 2) also note that this is true: 2 *where X is representative of the chi square distribution with n-1 degrees of freedom 3.3.1 CONFIDENCE INTERVAL 3.3.2 HYPOTHESIS TEST 2 1) To test something dealing with σ we use test statistic: where the null hypothesis is still rejected when p-value<α 3.4 DISTRIBUTION FREE INTERFERENCE 1) When using small sample sizes: a. We cannot assume normally distributed data b. We need to use exact nonparametric procedures whenfinding statistics c. Instead of means we will use medians because they are less influenced by outliers 3.4.1 SIGN TEST 1) Recall that a pth percentile includes all data thatfalls above (1-p)% a. Let B denote the number of observations greater than the pth percentile 2) B~Bin(n,1-p) where µ depotes the population pth percentile 3) We can test hypotheses dealing with µ p a. The p-value must still be smaller than α to rejectthe null hypothesis 3.4.2 WILCOXON SIGNED-RANK TEST 1) In this case, the null hypothesis is that the distribution of data is centrally located around a certain value µ0. This value Is tested against X. a. The test determines whether Xs tend to be larger, smaller, or different than µ . 0 2) To carry out the test: a. Center the data according to the null hypothesis bycalculating the differences between your data values (X) and µ 0 b. Rank the absolute values of the differences c. Calculate the test statistic,s+ , by adding all off differences 3) Note: 4) The test statistic, denoted by W:
×
×
### BOOM! Enjoy Your Free Notes!
×
Looks like you've already subscribed to StudySoup, you won't need to purchase another subscription to get this material. To access this material simply click 'View Full Document'
## Why people love StudySoup
Steve Martinelli UC Los Angeles
#### "There's no way I would have passed my Organic Chemistry class this semester without the notes and study guides I got from StudySoup."
Anthony Lee UC Santa Barbara
#### "I bought an awesome study guide, which helped me get an A in my Math 34B class this quarter!"
Jim McGreen Ohio University
#### "Knowing I can count on the Elite Notetaker in my class allows me to focus on what the professor is saying instead of just scribbling notes the whole time and falling behind."
Parker Thompson 500 Startups
#### "It's a great way for students to improve their educational experience and it seemed like a product that everybody wants, so all the people participating are winning."
Become an Elite Notetaker and start selling your notes online!
×
### Refund Policy
#### STUDYSOUP CANCELLATION POLICY
All subscriptions to StudySoup are paid in full at the time of subscribing. To change your credit card information or to cancel your subscription, go to "Edit Settings". All credit card information will be available there. If you should decide to cancel your subscription, it will continue to be valid until the next payment period, as all payments for the current period were made in advance. For special circumstances, please email support@studysoup.com
#### STUDYSOUP REFUND POLICY
StudySoup has more than 1 million course-specific study resources to help students study smarter. If you’re having trouble finding what you’re looking for, our customer support team can help you find what you need! Feel free to contact them here: support@studysoup.com
Recurring Subscriptions: If you have canceled your recurring subscription on the day of renewal and have not downloaded any documents, you may request a refund by submitting an email to support@studysoup.com | 1,117 | 4,720 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 3.84375 | 4 | CC-MAIN-2016-44 | latest | en | 0.886155 |
http://www.jiskha.com/members/profile/posts.cgi?name=Rm | 1,498,406,904,000,000,000 | text/html | crawl-data/CC-MAIN-2017-26/segments/1498128320539.37/warc/CC-MAIN-20170625152316-20170625172316-00504.warc.gz | 568,385,697 | 4,190 | Posts by Rm
Total # Posts: 13
ChemistryStociometry
6.0g of cobolt (II) carbonate was added to 40cm3 of hydrochloric acid, concentration 2.0 mol/dm3. Calculate the maximum yield of cobalt (II) choloride-6-water and show that cobalt (II) carbonate was in excess. CoCO3 +2HCl = CoCl2 +CO2 + H2O CoCl2 + 6H2O = CoCl2.6H2O what is ...
math
a certain spinner has equally sized slices. The odds in favor of landing on a blue slice are 2:5.What is the probablility of landing on a blue slice?
Biology
This is the homework exercise: You want to add 0.13 ul of DNA to 4.87 ul of extraction mix to have a final total of 5.0 ul of sample. But you don't want to make 0.13 aliquots because it is too small. Make a dilution to accomodate for the small aliquot. Any help would be ...
physics
How much heat in joules must be added to 0.348 kg of aluminum to change it from a solid at 138 °C to a liquid at 660 °C (its melting point)? The latent heat of fusion for aluminum is 4.0 x 105 J/kg.
physics
The amount of radiant power produced by the sun is approximately 3.9 x 1026 W. Assuming the sun to be a perfect blackbody sphere with a radius of 6.96 x 108 m, find its surface temperature (in kelvins).
physics
In an old house, the heating system uses radiators, which are hollow metal devices through which hot water or steam circulates. In one room the radiator has a dark color (emissitivity = 0.818). It has a temperature of 64.8 oC. The new owner of the house paints the radiator a ...
physics
A copper kettle contains water at 24.2 °C. When the water is heated to 87.3 °C, the volume of the kettle expands by 7.34 x 10-5 m3. Determine the volume of the kettle at 24.2 °C.
physics
In an arcade game a 0.142 kg disk is shot across a frictionless horizontal surface by compressing it against a spring and releasing it. If the spring has a spring constant of 174 N/m and is compressed from its equilibrium position by 8 cm, find the speed with which the disk ...
math
mrs loya sponsers the spanish club at central middle school.the club has 8 members who are sixth graders,12 members who are sventh graders, 10 members who are eight graders. what percent of the spanish club members are seventh graders(what is your answer and explain how you ...
math
michelle runs 400 meters in 1 minute. if she completes in the 100-meter race , about how many seconds will it take her to run the race?(explain how you got your answer)
math
A room is 12 feet by 16 feet. on a scale drawing the 12-foot wall is 4 inches long. how long will the 16-foot wall be?(explain how you got answer)
math
a + b = 6, b + c = 20, and c + a = 7.5, solve for a , b and c.
economics
If a country such as Europe sells their saved dollars as a result in a drop in U.S. sales and purchases, will the demand-supply graph show only the demand for the dollar. I just don't understand what the demand-supply graph suppose to illustrate. Help.
1. Pages:
2. 1
Post a New Question | 810 | 2,939 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.765625 | 3 | CC-MAIN-2017-26 | latest | en | 0.924471 |
http://metamath.tirix.org/mpeascii/opltcon2b | 1,721,220,344,000,000,000 | text/html | crawl-data/CC-MAIN-2024-30/segments/1720763514771.72/warc/CC-MAIN-20240717120911-20240717150911-00874.warc.gz | 19,558,909 | 1,943 | # Metamath Proof Explorer
## Theorem opltcon2b
Description: Contraposition law for strict ordering in orthoposets. ( chsscon2 analog.) (Contributed by NM, 5-Nov-2011)
Ref Expression
Hypotheses opltcon3.b
|- B = ( Base ` K )
opltcon3.s
|- .< = ( lt ` K )
opltcon3.o
|- ._|_ = ( oc ` K )
Assertion opltcon2b
|- ( ( K e. OP /\ X e. B /\ Y e. B ) -> ( X .< ( ._|_ ` Y ) <-> Y .< ( ._|_ ` X ) ) )
### Proof
Step Hyp Ref Expression
1 opltcon3.b
|- B = ( Base ` K )
2 opltcon3.s
|- .< = ( lt ` K )
3 opltcon3.o
|- ._|_ = ( oc ` K )
4 1 3 opoccl
|- ( ( K e. OP /\ Y e. B ) -> ( ._|_ ` Y ) e. B ) | 247 | 596 | {"found_math": false, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0} | 2.828125 | 3 | CC-MAIN-2024-30 | latest | en | 0.371445 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.