Datasets:
AayushShah
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Univeral_SQL_Three_Datasets_Combined_WithText_IDs

Dataset card Data Studio Files
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What is the name of the activity that has the most faculty members involved in?
SELECT T1.activity_name FROM Activity AS T1 JOIN Faculty_participates_in AS T2 ON T1.actID = T2.actID GROUP BY T1.actID ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Faculty_participates_in (actID VARCHAR); CREATE TABLE Activity (activity_name VARCHAR, actID VARCHAR)
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Show the ids of the students who don't participate in any activity.
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Participates_in
CREATE TABLE Participates_in (StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR)
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Show the ids for all the students who participate in an activity and are under 20.
SELECT StuID FROM Participates_in INTERSECT SELECT StuID FROM Student WHERE age < 20
CREATE TABLE Student (StuID VARCHAR, age INTEGER); CREATE TABLE Participates_in (StuID VARCHAR, age INTEGER)
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What is the first and last name of the student participating in the most activities?
SELECT T1.fname, T1.lname FROM Student AS T1 JOIN Participates_in AS T2 ON T1.StuID = T2.StuID GROUP BY T1.StuID ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Student (fname VARCHAR, lname VARCHAR, StuID VARCHAR); CREATE TABLE Participates_in (StuID VARCHAR)
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What is the name of the activity with the most students?
SELECT T1.activity_name FROM Activity AS T1 JOIN Participates_in AS T2 ON T1.actID = T2.actID GROUP BY T1.actID ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Participates_in (actID VARCHAR); CREATE TABLE Activity (activity_name VARCHAR, actID VARCHAR)
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Find the first names of the faculty members who are playing Canoeing or Kayaking.
SELECT DISTINCT T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID JOIN activity AS T3 ON T2.actid = T2.actid WHERE T3.activity_name = 'Canoeing' OR T3.activity_name = 'Kayaking'
CREATE TABLE activity (activity_name VARCHAR); CREATE TABLE Faculty_participates_in (facID VARCHAR, actid VARCHAR); CREATE TABLE Faculty (lname VARCHAR, facID VARCHAR)
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Find the first names of professors who are not playing Canoeing or Kayaking.
SELECT lname FROM faculty WHERE rank = 'Professor' EXCEPT SELECT DISTINCT T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID JOIN activity AS T3 ON T2.actid = T2.actid WHERE T3.activity_name = 'Canoeing' OR T3.activity_name = 'Kayaking'
CREATE TABLE faculty (lname VARCHAR, rank VARCHAR); CREATE TABLE activity (activity_name VARCHAR); CREATE TABLE Faculty_participates_in (facID VARCHAR, actid VARCHAR); CREATE TABLE Faculty (lname VARCHAR, facID VARCHAR)
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Find the ids of the students who participate in Canoeing and Kayaking.
SELECT T1.stuid FROM participates_in AS T1 JOIN activity AS T2 ON T2.actid = T2.actid WHERE T2.activity_name = 'Canoeing' INTERSECT SELECT T1.stuid FROM participates_in AS T1 JOIN activity AS T2 ON T2.actid = T2.actid WHERE T2.activity_name = 'Kayaking'
CREATE TABLE activity (actid VARCHAR, activity_name VARCHAR); CREATE TABLE participates_in (stuid VARCHAR)
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Find the name of the airport in the city of Goroka.
SELECT name FROM airports WHERE city = 'Goroka'
CREATE TABLE airports (name VARCHAR, city VARCHAR)
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Find the name, city, country, and altitude (or elevation) of the airports in the city of New York.
SELECT name, city, country, elevation FROM airports WHERE city = 'New York'
CREATE TABLE airports (name VARCHAR, city VARCHAR, country VARCHAR, elevation VARCHAR)
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How many airlines are there?
SELECT COUNT(*) FROM airlines
CREATE TABLE airlines (Id VARCHAR)
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How many airlines does Russia has?
SELECT COUNT(*) FROM airlines WHERE country = 'Russia'
CREATE TABLE airlines (country VARCHAR)
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What is the maximum elevation of all airports in the country of Iceland?
SELECT MAX(elevation) FROM airports WHERE country = 'Iceland'
CREATE TABLE airports (elevation INTEGER, country VARCHAR)
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Find the name of the airports located in Cuba or Argentina.
SELECT name FROM airports WHERE country = 'Cuba' OR country = 'Argentina'
CREATE TABLE airports (name VARCHAR, country VARCHAR)
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Find the country of the airlines whose name starts with 'Orbit'.
SELECT country FROM airlines WHERE name LIKE 'Orbit%'
CREATE TABLE airlines (country VARCHAR, name VARCHAR)
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Find the name of airports whose altitude is between -50 and 50.
SELECT name FROM airports WHERE elevation BETWEEN -50 AND 50
CREATE TABLE airports (name VARCHAR, elevation INTEGER)
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Which country is the airport that has the highest altitude located in?
SELECT country FROM airports ORDER BY elevation DESC LIMIT 1
CREATE TABLE airports (country VARCHAR, elevation VARCHAR)
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Find the number of airports whose name contain the word 'International'.
SELECT COUNT(*) FROM airports WHERE name LIKE '%International%'
CREATE TABLE airports (name VARCHAR)
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How many different cities do have some airport in the country of Greenland?
SELECT COUNT(DISTINCT city) FROM airports WHERE country = 'Greenland'
CREATE TABLE airports (city VARCHAR, country VARCHAR)
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Find the number of routes operated by American Airlines.
SELECT COUNT(*) FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid WHERE T1.name = 'American Airlines'
CREATE TABLE routes (alid VARCHAR); CREATE TABLE airlines (alid VARCHAR, name VARCHAR)
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Find the number of routes whose destination airports are in Canada.
SELECT COUNT(*) FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.dst_apid WHERE country = 'Canada'
CREATE TABLE routes (dst_apid VARCHAR); CREATE TABLE airports (apid VARCHAR)
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Find the name, city, and country of the airport that has the lowest altitude.
SELECT name, city, country FROM airports ORDER BY elevation LIMIT 1
CREATE TABLE airports (name VARCHAR, city VARCHAR, country VARCHAR, elevation VARCHAR)
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Find the name, city, and country of the airport that has the highest latitude.
SELECT name, city, country FROM airports ORDER BY elevation DESC LIMIT 1
CREATE TABLE airports (name VARCHAR, city VARCHAR, country VARCHAR, elevation VARCHAR)
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Find the name and city of the airport which is the destination of the most number of routes.
SELECT T1.name, T1.city, T2.dst_apid FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.dst_apid GROUP BY T2.dst_apid ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE airports (name VARCHAR, city VARCHAR, apid VARCHAR); CREATE TABLE routes (dst_apid VARCHAR)
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Find the names of the top 10 airlines that operate the most number of routes.
SELECT T1.name, T2.alid FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid GROUP BY T2.alid ORDER BY COUNT(*) DESC LIMIT 10
CREATE TABLE airlines (name VARCHAR, alid VARCHAR); CREATE TABLE routes (alid VARCHAR)
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Find the name and city of the airport which is the source for the most number of flight routes.
SELECT T1.name, T1.city, T2.src_apid FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.src_apid GROUP BY T2.src_apid ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE airports (name VARCHAR, city VARCHAR, apid VARCHAR); CREATE TABLE routes (src_apid VARCHAR)
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Find the number of different airports which are the destinations of the American Airlines.
SELECT COUNT(DISTINCT dst_apid) FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid WHERE T1.name = 'American Airlines'
CREATE TABLE routes (alid VARCHAR); CREATE TABLE airlines (alid VARCHAR, name VARCHAR)
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Which countries has the most number of airlines?
SELECT country FROM airlines GROUP BY country ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE airlines (country VARCHAR)
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Which countries has the most number of airlines whose active status is 'Y'?
SELECT country FROM airlines WHERE active = 'Y' GROUP BY country ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE airlines (country VARCHAR, active VARCHAR)
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List all countries and their number of airlines in the descending order of number of airlines.
SELECT country, COUNT(*) FROM airlines GROUP BY country ORDER BY COUNT(*) DESC
CREATE TABLE airlines (country VARCHAR)
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How many airports are there per country? Order the countries by decreasing number of airports.
SELECT COUNT(*), country FROM airports GROUP BY country ORDER BY COUNT(*) DESC
CREATE TABLE airports (country VARCHAR)
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How many airports are there per city in the United States? Order the cities by decreasing number of airports.
SELECT COUNT(*), city FROM airports WHERE country = 'United States' GROUP BY city ORDER BY COUNT(*) DESC
CREATE TABLE airports (city VARCHAR, country VARCHAR)
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Return the cities with more than 3 airports in the United States.
SELECT city FROM airports WHERE country = 'United States' GROUP BY city HAVING COUNT(*) > 3
CREATE TABLE airports (city VARCHAR, country VARCHAR)
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How many cities are there that have more than 3 airports?
SELECT COUNT(*) FROM (SELECT city FROM airports GROUP BY city HAVING COUNT(*) > 3)
CREATE TABLE airports (city VARCHAR)
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List the cities which have more than one airport and number of airports.
SELECT city, COUNT(*) FROM airports GROUP BY city HAVING COUNT(*) > 1
CREATE TABLE airports (city VARCHAR)
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List the cities which have more than 2 airports sorted by the number of airports.
SELECT city FROM airports GROUP BY city HAVING COUNT(*) > 2 ORDER BY COUNT(*)
CREATE TABLE airports (city VARCHAR)
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Find the number of routes for each source airport and the airport name.
SELECT COUNT(*), T1.name FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.src_apid GROUP BY T1.name
CREATE TABLE airports (name VARCHAR, apid VARCHAR); CREATE TABLE routes (src_apid VARCHAR)
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Find the number of routes and airport name for each source airport, order the results by decreasing number of routes.
SELECT COUNT(*), T1.name FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.src_apid GROUP BY T1.name ORDER BY COUNT(*) DESC
CREATE TABLE airports (name VARCHAR, apid VARCHAR); CREATE TABLE routes (src_apid VARCHAR)
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Find the average elevation of all airports for each country.
SELECT AVG(elevation), country FROM airports GROUP BY country
CREATE TABLE airports (country VARCHAR, elevation INTEGER)
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Find the cities which have exactly two airports.
SELECT city FROM airports GROUP BY city HAVING COUNT(*) = 2
CREATE TABLE airports (city VARCHAR)
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For each country and airline name, how many routes are there?
SELECT T1.country, T1.name, COUNT(*) FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid GROUP BY T1.country, T1.name
CREATE TABLE airlines (country VARCHAR, name VARCHAR, alid VARCHAR); CREATE TABLE routes (alid VARCHAR)
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Find the number of routes with destination airports in Italy.
SELECT COUNT(*) FROM routes AS T1 JOIN airports AS T2 ON T1.dst_apid = T2.apid WHERE T2.country = 'Italy'
CREATE TABLE routes (dst_apid VARCHAR); CREATE TABLE airports (apid VARCHAR, country VARCHAR)
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Return the number of routes with destination airport in Italy operated by the airline with name 'American Airlines'.
SELECT COUNT(*) FROM routes AS T1 JOIN airports AS T2 ON T1.dst_apid = T2.apid JOIN airlines AS T3 ON T1.alid = T3.alid WHERE T2.country = 'Italy' AND T3.name = 'American Airlines'
CREATE TABLE routes (dst_apid VARCHAR, alid VARCHAR); CREATE TABLE airports (apid VARCHAR, country VARCHAR); CREATE TABLE airlines (alid VARCHAR, name VARCHAR)
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Find the number of routes that have destination John F Kennedy International Airport.
SELECT COUNT(*) FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.dst_apid WHERE T1.name = 'John F Kennedy International Airport'
CREATE TABLE airports (apid VARCHAR, name VARCHAR); CREATE TABLE routes (dst_apid VARCHAR)
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Find the number of routes from the United States to Canada.
SELECT COUNT(*) FROM routes WHERE dst_apid IN (SELECT apid FROM airports WHERE country = 'Canada') AND src_apid IN (SELECT apid FROM airports WHERE country = 'United States')
CREATE TABLE airports (dst_apid VARCHAR, src_apid VARCHAR, apid VARCHAR, country VARCHAR); CREATE TABLE routes (dst_apid VARCHAR, src_apid VARCHAR, apid VARCHAR, country VARCHAR)
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Find the id of routes whose source and destination airports are in the United States.
SELECT rid FROM routes WHERE dst_apid IN (SELECT apid FROM airports WHERE country = 'United States') AND src_apid IN (SELECT apid FROM airports WHERE country = 'United States')
CREATE TABLE routes (rid VARCHAR, dst_apid VARCHAR, src_apid VARCHAR, apid VARCHAR, country VARCHAR); CREATE TABLE airports (rid VARCHAR, dst_apid VARCHAR, src_apid VARCHAR, apid VARCHAR, country VARCHAR)
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Find the name of airline which runs the most number of routes.
SELECT T1.name FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid GROUP BY T1.name ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE airlines (name VARCHAR, alid VARCHAR); CREATE TABLE routes (alid VARCHAR)
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Find the busiest source airport that runs most number of routes in China.
SELECT T1.name FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.src_apid WHERE T1.country = 'China' GROUP BY T1.name ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE routes (src_apid VARCHAR); CREATE TABLE airports (name VARCHAR, apid VARCHAR, country VARCHAR)
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Find the busiest destination airport that runs most number of routes in China.
SELECT T1.name FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.dst_apid WHERE T1.country = 'China' GROUP BY T1.name ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE routes (dst_apid VARCHAR); CREATE TABLE airports (name VARCHAR, apid VARCHAR, country VARCHAR)
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What is the id of the most recent order?
SELECT order_id FROM orders ORDER BY date_order_placed DESC LIMIT 1
CREATE TABLE orders (order_id VARCHAR, date_order_placed VARCHAR)
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what are the order id and customer id of the oldest order?
SELECT order_id, customer_id FROM orders ORDER BY date_order_placed LIMIT 1
CREATE TABLE orders (order_id VARCHAR, customer_id VARCHAR, date_order_placed VARCHAR)
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Find the id of the order whose shipment tracking number is "3452".
SELECT order_id FROM shipments WHERE shipment_tracking_number = "3452"
CREATE TABLE shipments (order_id VARCHAR, shipment_tracking_number VARCHAR)
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Find the ids of all the order items whose product id is 11.
SELECT order_item_id FROM order_items WHERE product_id = 11
CREATE TABLE order_items (order_item_id VARCHAR, product_id VARCHAR)
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List the name of all the distinct customers who have orders with status "Packing".
SELECT DISTINCT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "Packing"
CREATE TABLE orders (customer_id VARCHAR, order_status VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
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Find the details of all the distinct customers who have orders with status "On Road".
SELECT DISTINCT T1.customer_details FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "On Road"
CREATE TABLE orders (customer_id VARCHAR, order_status VARCHAR); CREATE TABLE customers (customer_details VARCHAR, customer_id VARCHAR)
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What is the name of the customer who has the most orders?
SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE orders (customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
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What is the customer id of the customer who has the most orders?
SELECT T1.customer_id FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE orders (customer_id VARCHAR)
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Give me a list of id and status of orders which belong to the customer named "Jeramie".
SELECT T2.order_id, T2.order_status FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T1.customer_name = "Jeramie"
CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE orders (order_id VARCHAR, order_status VARCHAR, customer_id VARCHAR)
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Find the dates of orders which belong to the customer named "Jeramie".
SELECT T2.date_order_placed FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T1.customer_name = "Jeramie"
CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE orders (date_order_placed VARCHAR, customer_id VARCHAR)
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Give me the names of customers who have placed orders between 2009-01-01 and 2010-01-01.
SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.date_order_placed >= "2009-01-01" AND T2.date_order_placed <= "2010-01-01"
CREATE TABLE orders (customer_id VARCHAR, date_order_placed VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
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Give me a list of distinct product ids from orders placed between 1975-01-01 and 1976-01-01?
SELECT DISTINCT T2.product_id FROM orders AS T1 JOIN order_items AS T2 ON T1.order_id = T2.order_id WHERE T1.date_order_placed >= "1975-01-01" AND T1.date_order_placed <= "1976-01-01"
CREATE TABLE order_items (product_id VARCHAR, order_id VARCHAR); CREATE TABLE orders (order_id VARCHAR, date_order_placed VARCHAR)
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Find the names of the customers who have order status both "On Road" and "Shipped".
SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "On Road" INTERSECT SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "Shipped"
CREATE TABLE orders (customer_id VARCHAR, order_status VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
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Find the id of the customers who have order status both "On Road" and "Shipped".
SELECT T1.customer_id FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "On Road" INTERSECT SELECT T1.customer_id FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "Shipped"
CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE orders (customer_id VARCHAR, order_status VARCHAR)
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When was the order placed whose shipment tracking number is 3452? Give me the date.
SELECT T1.date_order_placed FROM orders AS T1 JOIN shipments AS T2 ON T1.order_id = T2.order_id WHERE T2.shipment_tracking_number = 3452
CREATE TABLE shipments (order_id VARCHAR, shipment_tracking_number VARCHAR); CREATE TABLE orders (date_order_placed VARCHAR, order_id VARCHAR)
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What is the placement date of the order whose invoice number is 10?
SELECT T1.date_order_placed FROM orders AS T1 JOIN shipments AS T2 ON T1.order_id = T2.order_id WHERE T2.invoice_number = 10
CREATE TABLE orders (date_order_placed VARCHAR, order_id VARCHAR); CREATE TABLE shipments (order_id VARCHAR, invoice_number VARCHAR)
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List the count and id of each product in all the orders.
SELECT COUNT(*), T3.product_id FROM orders AS T1 JOIN order_items AS T2 JOIN products AS T3 ON T1.order_id = T2.order_id AND T2.product_id = T3.product_id GROUP BY T3.product_id
CREATE TABLE orders (order_id VARCHAR); CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR); CREATE TABLE products (product_id VARCHAR)
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List the name and count of each product in all orders.
SELECT T3.product_name, COUNT(*) FROM orders AS T1 JOIN order_items AS T2 JOIN products AS T3 ON T1.order_id = T2.order_id AND T2.product_id = T3.product_id GROUP BY T3.product_id
CREATE TABLE orders (order_id VARCHAR); CREATE TABLE products (product_name VARCHAR, product_id VARCHAR); CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR)
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Find the ids of orders which are shipped after 2000-01-01.
SELECT order_id FROM shipments WHERE shipment_date > "2000-01-01"
CREATE TABLE shipments (order_id VARCHAR, shipment_date INTEGER)
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Find the id of the order which is shipped most recently.
SELECT order_id FROM shipments WHERE shipment_date = (SELECT MAX(shipment_date) FROM shipments)
CREATE TABLE shipments (order_id VARCHAR, shipment_date INTEGER)
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List the names of all distinct products in alphabetical order.
SELECT DISTINCT product_name FROM products ORDER BY product_name
CREATE TABLE products (product_name VARCHAR)
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List the ids of all distinct orders ordered by placed date.
SELECT DISTINCT order_id FROM orders ORDER BY date_order_placed
CREATE TABLE orders (order_id VARCHAR, date_order_placed VARCHAR)
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What is the id of the order which has the most items?
SELECT T1.order_id FROM orders AS T1 JOIN order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE orders (order_id VARCHAR); CREATE TABLE order_items (order_id VARCHAR)
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Find the invoice numbers which are created before 1989-09-03 or after 2007-12-25.
SELECT invoice_number FROM invoices WHERE invoice_date < "1989-09-03" OR invoice_date > "2007-12-25"
CREATE TABLE invoices (invoice_number VARCHAR, invoice_date VARCHAR)
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Find the distinct details of invoices which are created before 1989-09-03 or after 2007-12-25.
SELECT DISTINCT invoice_details FROM invoices WHERE invoice_date < "1989-09-03" OR invoice_date > "2007-12-25"
CREATE TABLE invoices (invoice_details VARCHAR, invoice_date VARCHAR)
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For each customer who has at least two orders, find the customer name and number of orders made.
SELECT T2.customer_name, COUNT(*) FROM orders AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T2.customer_id HAVING COUNT(*) >= 2
CREATE TABLE orders (customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
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Find the name of the customers who have at most two orders.
SELECT T2.customer_name FROM orders AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T2.customer_id HAVING COUNT(*) <= 2
CREATE TABLE orders (customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
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List the names of the customers who have once bought product "food".
SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 JOIN order_items AS T3 JOIN products AS T4 ON T1.customer_id = T2.customer_id AND T2.order_id = T3.order_id AND T3.product_id = T4.product_id WHERE T4.product_name = "food" GROUP BY T1.customer_id HAVING COUNT(*) >= 1
CREATE TABLE products (product_name VARCHAR, product_id VARCHAR); CREATE TABLE orders (customer_id VARCHAR, order_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE order_items (product_id VARCHAR, order_id VARCHAR)
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How many architects are female?
SELECT COUNT(*) FROM architect WHERE gender = 'female'
CREATE TABLE architect (gender VARCHAR)
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List the name, nationality and id of all male architects ordered by their names lexicographically.
SELECT name, nationality, id FROM architect WHERE gender = 'male' ORDER BY name
CREATE TABLE architect (name VARCHAR, nationality VARCHAR, id VARCHAR, gender VARCHAR)
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What is the maximum length in meters for the bridges and what are the architects' names?
SELECT MAX(T1.length_meters), T2.name FROM bridge AS T1 JOIN architect AS T2 ON T1.architect_id = T2.id
CREATE TABLE architect (name VARCHAR, id VARCHAR); CREATE TABLE bridge (length_meters INTEGER, architect_id VARCHAR)
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What is the average length in feet of the bridges?
SELECT AVG(length_feet) FROM bridge
CREATE TABLE bridge (length_feet INTEGER)
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What are the names and year of construction for the mills of 'Grondzeiler' type?
SELECT name, built_year FROM mill WHERE TYPE = 'Grondzeiler'
CREATE TABLE mill (name VARCHAR, built_year VARCHAR, TYPE VARCHAR)
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What are the distinct names and nationalities of the architects who have ever built a mill?
SELECT DISTINCT T1.name, T1.nationality FROM architect AS T1 JOIN mill AS t2 ON T1.id = T2.architect_id
CREATE TABLE mill (Id VARCHAR); CREATE TABLE architect (name VARCHAR, nationality VARCHAR, id VARCHAR)
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What are the names of the mills which are not located in 'Donceel'?
SELECT name FROM mill WHERE LOCATION <> 'Donceel'
CREATE TABLE mill (name VARCHAR, LOCATION VARCHAR)
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What are the distinct types of mills that are built by American or Canadian architects?
SELECT DISTINCT T1.type FROM mill AS T1 JOIN architect AS t2 ON T1.architect_id = T2.id WHERE T2.nationality = 'American' OR T2.nationality = 'Canadian'
CREATE TABLE architect (Id VARCHAR); CREATE TABLE mill (type VARCHAR, architect_id VARCHAR)
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What are the ids and names of the architects who built at least 3 bridges ?
SELECT T1.id, T1.name FROM architect AS T1 JOIN bridge AS T2 ON T1.id = T2.architect_id GROUP BY T1.id HAVING COUNT(*) >= 3
CREATE TABLE architect (id VARCHAR, name VARCHAR); CREATE TABLE bridge (architect_id VARCHAR)
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What is the id, name and nationality of the architect who built most mills?
SELECT T1.id, T1.name, T1.nationality FROM architect AS T1 JOIN mill AS T2 ON T1.id = T2.architect_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE architect (id VARCHAR, name VARCHAR, nationality VARCHAR); CREATE TABLE mill (architect_id VARCHAR)
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What are the ids, names and genders of the architects who built two bridges or one mill?
SELECT T1.id, T1.name, T1.gender FROM architect AS T1 JOIN bridge AS T2 ON T1.id = T2.architect_id GROUP BY T1.id HAVING COUNT(*) = 2 UNION SELECT T1.id, T1.name, T1.gender FROM architect AS T1 JOIN mill AS T2 ON T1.id = T2.architect_id GROUP BY T1.id HAVING COUNT(*) = 1
CREATE TABLE mill (architect_id VARCHAR); CREATE TABLE architect (id VARCHAR, name VARCHAR, gender VARCHAR); CREATE TABLE bridge (architect_id VARCHAR)
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What is the location of the bridge named 'Kolob Arch' or 'Rainbow Bridge'?
SELECT LOCATION FROM bridge WHERE name = 'Kolob Arch' OR name = 'Rainbow Bridge'
CREATE TABLE bridge (LOCATION VARCHAR, name VARCHAR)
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Which of the mill names contains the french word 'Moulin'?
SELECT name FROM mill WHERE name LIKE '%Moulin%'
CREATE TABLE mill (name VARCHAR)
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What are the distinct name of the mills built by the architects who have also built a bridge longer than 80 meters?
SELECT DISTINCT T1.name FROM mill AS T1 JOIN architect AS t2 ON T1.architect_id = T2.id JOIN bridge AS T3 ON T3.architect_id = T2.id WHERE T3.length_meters > 80
CREATE TABLE architect (Id VARCHAR); CREATE TABLE mill (name VARCHAR, architect_id VARCHAR); CREATE TABLE bridge (architect_id VARCHAR, length_meters INTEGER)
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What is the most common mill type, and how many are there?
SELECT TYPE, COUNT(*) FROM mill GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE mill (TYPE VARCHAR)
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How many architects haven't built a mill before year 1850?
SELECT COUNT(*) FROM architect WHERE NOT id IN (SELECT architect_id FROM mill WHERE built_year < 1850)
CREATE TABLE mill (id VARCHAR, architect_id VARCHAR, built_year INTEGER); CREATE TABLE architect (id VARCHAR, architect_id VARCHAR, built_year INTEGER)
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show the name of all bridges that was designed by american archtect, and sort the result by the bridge feet length.
SELECT t1.name FROM bridge AS t1 JOIN architect AS t2 ON t1.architect_id = t2.id WHERE t2.nationality = 'American' ORDER BY t1.length_feet
CREATE TABLE bridge (name VARCHAR, architect_id VARCHAR, length_feet VARCHAR); CREATE TABLE architect (id VARCHAR, nationality VARCHAR)
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How many book clubs are there?
SELECT COUNT(*) FROM book_club
CREATE TABLE book_club (Id VARCHAR)
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show the titles, and authors or editors for all books made after the year 1989.
SELECT book_title, author_or_editor FROM book_club WHERE YEAR > 1989
CREATE TABLE book_club (book_title VARCHAR, author_or_editor VARCHAR, YEAR INTEGER)
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Show all distinct publishers for books.
SELECT DISTINCT publisher FROM book_club
CREATE TABLE book_club (publisher VARCHAR)
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Show the years, book titles, and publishers for all books, in descending order by year.
SELECT YEAR, book_title, publisher FROM book_club ORDER BY YEAR DESC
CREATE TABLE book_club (YEAR VARCHAR, book_title VARCHAR, publisher VARCHAR)
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Show all publishers and the number of books for each publisher.
SELECT publisher, COUNT(*) FROM book_club GROUP BY publisher
CREATE TABLE book_club (publisher VARCHAR)
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What is the publisher with most number of books?
SELECT publisher FROM book_club GROUP BY publisher ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE book_club (publisher VARCHAR)
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