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{"problem": "The number of elementary school in Hawkesbury equals 3. The number of culinarian school in Hawkesbury equals 2. The number of regional medical school in Hawkesbury equals the number of culinarian school in Hawkesbury. The number of public highschool in Hawkesbury equals 3. The total number of schools in Brightford equals 64. The number of culinarian school in Evervale City equals the number of public highschool in Evervale City. The number of public highschool in Evervale City exists, and its number is greater than 0. The number of culinarian school in Glenfield City equals the sum of the number of regional medical school in Hawkesbury and the number of culinarian school in Evervale City. The number of regional medical school in Glenfield City equals 1 plus the number of culinarian school in Hawkesbury. The number of elementary school in Brightford equals 4 plus the sum of the total number of schools in Evervale City and the number of culinarian school in Evervale City. The number of culinarian school in Brightford equals 4 times the sum of the number of public highschool in Evervale City and the total number of schools in Evervale City. ", "question": "How many public highschool does Evervale City have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Evervale City as x; we don't know its value yet but will find it out later. Define culinarian school in Evervale City as C; so C = x = x. Define total number of schools in Evervale City as N; so N = C + x = x + x = 2*x. Define culinarian school in Brightford as w; l = x + N = x + 2*x = 3*x; so w = 4 * l = (4) * (3*x) = 12*x. Define elementary school in Brightford as I; p = N + C = 2*x + x = 3*x; so I = 4 + p = 4 + 3*x = 3*x + 4. Define total number of schools in Brightford as i; so i = w + I = 12*x + 3*x + 4 = 15*x + 4. We know i = 64, so we have 15*x + 4 = 64 and we solve it through the following steps: Simplifying the equation: 15*x + 4 = 64. Move all terms to one side: 15*x - 60 = 0. Isolate the term with x: 15*x = 60. Divide both sides by 15: x = 60 / 15. Solution: x = 4. Answer: 4.", "op": 12, "id": "5_p3", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
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{"problem": "The number of adult wolf in South Zoo equals the total number of adult animals in Mayer Aquarium. The number of adult racoon in Mayer Aquarium equals the sum of the total number of adult animals in Hamilton Farm, the number of adult racoon in Hamilton Farm, and the number of adult bear in Hamilton Farm. The number of adult racoon in Hamilton Farm equals 2. The number of adult deer in Mayer Aquarium equals 3. The number of adult bear in Hamilton Farm equals 1. ", "question": "What is the total number of adult animals in South Zoo?", "solution": "Define adult racoon in Hamilton Farm as S; so S = 2. Define adult bear in Hamilton Farm as u; so u = 1. Define total number of adult animals in Hamilton Farm as B; so B = u + S = 1 + 2 = 3. Define adult racoon in Mayer Aquarium as m; Y = B + S = 3 + 2 = 5; so m = Y + u = 5 + 1 = 6. Define adult deer in Mayer Aquarium as T; so T = 3. Define total number of adult animals in Mayer Aquarium as h; so h = T + m = 3 + 6 = 9. Define adult wolf in South Zoo as n; so n = h = 9. Define total number of adult animals in South Zoo as H; so H = n = 9. Answer: 9.", "op": 12, "id": "17_p3", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
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{"problem": "The number of adult blue jay in Pine Ridge equals the sum of the total number of adult animals in Oakridge Riverside, the number of adult blue jay in Oakridge Riverside, and the number of adult eagle in Oakridge Riverside. The number of adult eagle in Pine Ridge equals the number of adult parrot in Oakridge Riverside. The number of adult parrot in Oakridge Riverside exists, and its number is greater than 0. The number of adult blue jay in Oakridge Riverside equals the number of adult parrot in Oakridge Riverside. The number of adult eagle in Oakridge Riverside equals the number of adult parrot in Oakridge Riverside. The total number of adult animals in Pine Ridge equals 12. ", "question": "How many adult parrot does Oakridge Riverside have?", "solution": "The question is difficult, so we use equations to solve it. Define adult parrot in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define adult eagle in Oakridge Riverside as I; so I = x = x. Define adult blue jay in Oakridge Riverside as D; so D = x = x. Define total number of adult animals in Oakridge Riverside as S; N = D + I = x + x = 2*x; so S = N + x = 2*x + x = 3*x. Define adult blue jay in Pine Ridge as L; F = S + D = 3*x + x = 4*x; so L = F + I = 4*x + x = 5*x. Define adult eagle in Pine Ridge as q; so q = x = x. Define total number of adult animals in Pine Ridge as r; so r = L + q = 5*x + x = 6*x. We know r = 12, so we have 6*x = 12 and we solve it through the following steps: Simplifying the equation: 6*x = 12. Move all terms to one side: 6*x - 12 = 0. Isolate the term with x: 6*x = 12. Divide both sides by 6: x = 12 / 6. Solution: x = 2. Answer: 2.", "op": 12, "id": "10_p3", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
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{"problem": "The number of solemn period drama in Golden Banana Movie Festival equals the total number of movies in West Sahara Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 3. The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of futuristic sci-fi movie in Northwood Movie Festival. The number of calm road movie in Taylor Movie Festival equals 4 plus the number of solemn period drama in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals the total number of movies in Verdi Movie Festival. The number of calm road movie in Verdi Movie Festival equals the total number of movies in Taylor Movie Festival. ", "question": "What is the total number of movies in Northwood Movie Festival?", "solution": "Define intense detective thriller in West Sahara Movie Festival as B; so B = 3. Define total number of movies in West Sahara Movie Festival as W; so W = B = 3. Define solemn period drama in Golden Banana Movie Festival as I; so I = W = 3. Define calm road movie in Taylor Movie Festival as k; N = I = 3; so k = 4 + N = 4 + 3 = 7. Define total number of movies in Taylor Movie Festival as V; so V = k = 7. Define calm road movie in Verdi Movie Festival as O; so O = V = 7. Define total number of movies in Verdi Movie Festival as A; so A = O = 7. Define futuristic sci-fi movie in Northwood Movie Festival as m; so m = A = 7. Define upbeat metropolis comedy in Northwood Movie Festival as c; so c = m = 7. Define total number of movies in Northwood Movie Festival as a; so a = m + c = 7 + 7 = 14. Answer: 14.", "op": 12, "id": "21_p3", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
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{"problem": "The number of intense detective thriller in Verdi Movie Festival equals the sum of the total number of movies in Taylor Movie Festival, the number of intense detective thriller in Taylor Movie Festival, and the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals the number of intense detective thriller in Taylor Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival exists, and its number is greater than 0. The total number of movies in Verdi Movie Festival equals 19. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4. ", "question": "How many futuristic sci-fi movie does Verdi Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Golden Banana Movie Festival as D; so D = 4. Define total number of movies in Golden Banana Movie Festival as f; so f = D = 4. Define intense detective thriller in Taylor Movie Festival as G; so G = f = 4. Define futuristic sci-fi movie in Taylor Movie Festival as S; so S = G = 4. Define total number of movies in Taylor Movie Festival as p; so p = S + G = 4 + 4 = 8. Define intense detective thriller in Verdi Movie Festival as B; P = p + G = 8 + 4 = 12; so B = P + D = 12 + 4 = 16. Define futuristic sci-fi movie in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Verdi Movie Festival as c; so c = x + B = x + 16 = x + 16. We know c = 19, so we have x + 16 = 19 and we solve it through the following steps: Simplifying the equation: x + 16 = 19. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 12, "id": "8_p3", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
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{"problem": "The total number of adult animals in Maple Creek equals 26. The number of adult eagle in Maple Creek equals the sum of the total number of adult animals in Beverly Forest, the number of adult parrot in Beverly Forest, the number of adult parrot in Maple Creek, and the number of adult eagle in Beverly Forest. The number of adult eagle in Beverly Forest equals 3 times the number of adult parrot in Maple Creek. The number of adult parrot in Maple Creek equals 3. The number of adult parrot in Beverly Forest exists, and its number is greater than 0. ", "question": "How many adult parrot does Beverly Forest have?", "solution": "The question is difficult, so we use equations to solve it. Define adult parrot in Maple Creek as y; so y = 3. Define adult parrot in Beverly Forest as x; we don't know its value yet but will find it out later. Define adult eagle in Beverly Forest as Q; z = y = 3; so Q = 3 * z = (3) * (3) = 9. Define total number of adult animals in Beverly Forest as s; so s = x + Q = x + 9 = x + 9. Define adult eagle in Maple Creek as T; v = s + x = x + 9 + x = 2*x + 9; o = v + y = 2*x + 9 + 3 = 2*x + 12; so T = o + Q = 2*x + 12 + 9 = 2*x + 21. Define total number of adult animals in Maple Creek as m; so m = y + T = 3 + 2*x + 21 = 2*x + 24. We know m = 26, so we have 2*x + 24 = 26 and we solve it through the following steps: Simplifying the equation: 2*x + 24 = 26. Move all terms to one side: 2*x - 2 = 0. Isolate the term with x: 2*x = 2. Divide both sides by 2: x = 2 / 2. Solution: x = 1. Answer: 1.", "op": 12, "id": "4_p3", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
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{"problem": "The number of elementary school in Evervale City equals the number of private middle school in Evervale City. The number of elementary school in Glenfield City equals 3 times the sum of the total number of schools in Evervale City, the number of private middle school in Evervale City, and the number of elementary school in Evervale City. The number of private middle school in Evervale City equals 2. The number of private middle school in Glenfield City equals 3 plus the number of elementary school in Evervale City. ", "question": "What is the total number of schools in Glenfield City?", "solution": "Define private middle school in Evervale City as o; so o = 2. Define elementary school in Evervale City as J; so J = o = 2. Define total number of schools in Evervale City as l; so l = o + J = 2 + 2 = 4. Define elementary school in Glenfield City as D; i = l + o = 4 + 2 = 6; P = i + J = 6 + 2 = 8; so D = 3 * P = 3 * 8 = 24. Define private middle school in Glenfield City as Q; k = J = 2; so Q = 3 + k = 3 + 2 = 5. Define total number of schools in Glenfield City as n; so n = Q + D = 5 + 24 = 29. Answer: 29.", "op": 12, "id": "0_p3", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
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{"problem": "The number of solemn period drama in Festival de Saint-Rivage equals the total number of movies in Festival Lumi\u00e8re de Valmont. The number of solemn period drama in Festival de Clairmont equals 4. The number of calm road movie in Festival de Saint-Rivage equals the total number of movies in Festival de Clairmont. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals 4. The number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont equals the total number of movies in Festival de Clairmont. The number of futuristic sci-fi movie in Festival de Clairmont equals the number of solemn period drama in Festival de Clairmont. ", "question": "What is the total number of movies in Festival de Saint-Rivage?", "solution": "Define solemn period drama in Festival de Clairmont as R; so R = 4. Define futuristic sci-fi movie in Festival de Clairmont as B; so B = R = 4. Define total number of movies in Festival de Clairmont as Z; so Z = R + B = 4 + 4 = 8. Define futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont as h; so h = Z = 8. Define calm road movie in Festival Lumi\u00e8re de Valmont as v; so v = 4. Define total number of movies in Festival Lumi\u00e8re de Valmont as e; so e = h + v = 8 + 4 = 12. Define solemn period drama in Festival de Saint-Rivage as i; so i = e = 12. Define calm road movie in Festival de Saint-Rivage as y; so y = Z = 8. Define total number of movies in Festival de Saint-Rivage as Q; so Q = i + y = 12 + 8 = 20. Answer: 20.", "op": 12, "id": "21_p3", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
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{"problem": "The number of elementary school in Ruby Bay equals 1 plus the sum of the number of elementary school in Clearwater Bay and the total number of schools in Clearwater Bay. The number of public highschool in Oakbridge City equals the total number of schools in Clearwater Bay. The number of elementary school in Riverton City equals the total number of schools in Oakbridge City. The number of public highschool in Ruby Bay equals the total number of schools in Riverton City. The total number of schools in Ruby Bay equals 7. The number of elementary school in Clearwater Bay exists, and its number is greater than 0. ", "question": "How many elementary school does Clearwater Bay have?", "solution": "The question is difficult, so we use equations to solve it. Define elementary school in Clearwater Bay as x; we don't know its value yet but will find it out later. Define total number of schools in Clearwater Bay as L; so L = x = x. Define public highschool in Oakbridge City as h; so h = L = x. Define total number of schools in Oakbridge City as I; so I = h = x. Define elementary school in Riverton City as g; so g = I = x. Define total number of schools in Riverton City as U; so U = g = x. Define public highschool in Ruby Bay as u; so u = U = x. Define elementary school in Ruby Bay as f; s = x + L = x + x = 2*x; so f = 1 + s = 1 + 2*x = 2*x + 1. Define total number of schools in Ruby Bay as C; so C = f + u = 2*x + 1 + x = 3*x + 1. We know C = 7, so we have 3*x + 1 = 7 and we solve it through the following steps: Simplifying the equation: 3*x + 1 = 7. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 12, "id": "21_p3", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
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