PopTurk / code /scripts /10_build_m4_table.py
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"""Assemble model-4's stage-2 tables into labelled train / unlabelled test frames.
WHY THIS EXISTS. model-4 already scored every test candidate and left the result on disk:
`stage2/test_scores.parquet`, 9,980,755 rows of (q, c, p1, p, ce) - the table that produced
leaderboard 0.979241. The train side is there too, with labels. So the whole feature-and-
decision track can be run on existing scores, with no retrieval and no cross-encoder pass.
That is the difference between a submission in an hour and a submission in six.
THE SPLIT IS CLEAN, WHICH MATTERS MORE THAN THE SPEED. `s2/train.parquet` covers 296,148 S1:
197,435 from g_stack and 98,713 from g_val, and **zero** from g_ce. So fitting on g_stack and
reading g_val is an honest held-out measurement against a cross-encoder that never saw either.
Every earlier number in this project came from a 20k cache drawn with `RandomState(42)` where
the split used `default_rng(42)` - not the val split at all, and about 7% seen in training.
This replaces that.
ALIGNMENT. `ce_scores/<split>/shard_*.npy` concatenate in shard order to exactly the row count
of the matching `s2/<split>.parquet`. That is checked, not assumed; a silent off-by-one shard
would attach every cross-encoder score to the wrong pair and still produce a plausible file.
"""
from __future__ import annotations
import argparse
import glob
import os
import sys
import numpy as np
import pandas as pd
sys.path.insert(0, os.path.dirname(os.path.dirname(os.path.abspath(__file__))))
from berx import paths as P # noqa: E402
M4 = os.environ.get("BERX_M4", "/scratch/user4/dai/model-4/work")
def load_ce(split: str, n_expect: int) -> np.ndarray:
fs = sorted(glob.glob(os.path.join(M4, "ce_scores", split, "shard_*.npy")))
assert fs, f"no ce score shards under {M4}/ce_scores/{split}"
parts = [np.load(f) for f in fs]
ce = np.concatenate(parts)
assert len(ce) == n_expect, (
f"ce_scores/{split} has {len(ce):,} scores but s2/{split}.parquet has {n_expect:,} "
f"rows. They are positionally aligned, so this mismatch means a shard is missing or "
f"out of order - every score would attach to the wrong pair.")
print(f" ce {split}: {len(fs)} shards, {len(ce):,} scores")
return ce.astype(np.float32)
def main():
ap = argparse.ArgumentParser()
ap.add_argument("--split", default="both", choices=["train", "test", "both"])
a = ap.parse_args()
splits = ["train", "test"] if a.split == "both" else [a.split]
sp = np.load(os.path.join(M4, "splits.npz"))
for split in splits:
f = os.path.join(M4, "s2", f"{split}.parquet")
df = pd.read_parquet(f)
print(f"\n{f}: {len(df):,} rows, cols {list(df.columns)}")
df["ce"] = load_ce(split, len(df))
if split == "train":
g_stack, g_val, g_ce = set(sp["g_stack"].tolist()), set(sp["g_val"].tolist()), \
set(sp["g_ce"].tolist())
q = df["q"].to_numpy()
grp = np.where(np.isin(q, list(g_val)), "val",
np.where(np.isin(q, list(g_stack)), "stack", "other"))
df["grp"] = grp
leak = int(np.isin(q, list(g_ce)).sum())
assert leak == 0, (
f"{leak:,} rows belong to g_ce entities. The cross-encoder trained on those, "
f"so any gain measured with them is partly leakage.")
print(f" groups: {pd.Series(grp).value_counts().to_dict()}")
print(f" label rate {df['y'].mean():.4%} g_ce leakage: none")
# n_true per S1 is needed by the metric: an entity with true matches that this
# table never retrieved still counts against recall.
df.attrs["n_true"] = None
out = P.work("m4", f"{split}.parquet")
df.to_parquet(out, index=False, compression="zstd")
print(f" wrote {out} ({os.path.getsize(out)/2**20:.0f} MB)")
# Ground truth for the train entities, as {q: set(c)}, so recall counts copies that the
# candidate table never contained.
if "train" in splits:
gtq, gtc = sp["gt_q"], sp["gt_c"]
np.savez_compressed(P.work("m4", "truth.npz"), gt_q=gtq, gt_c=gtc,
g_stack=sp["g_stack"], g_val=sp["g_val"])
print(f"\n wrote truth.npz {len(gtq):,} ground-truth pairs")
if __name__ == "__main__":
main()