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d231962 | 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 | """C. Multi-GPU top-K retrieval and the three-channel union.
WHY THIS IS WORTH GPU TIME. Measured ceilings on model-4's val, with a perfect decision layer:
top-64 candidates (what ships) 0.9953
top-100 candidates 0.9964
union of three retrievers' top-100 0.9976
The union is worth +0.0023 of headroom over what ships. That is larger than every decision-side
idea left on the list, and unlike them it cannot be had on CPU.
HOW THE GPUs ARE USED
* Per country. Zero true pairs cross a country boundary in train, so a cross-country score
is arithmetic that can only produce a false positive. Blocking by country cuts the work
to sum(share^2) = 0.445 of the full matrix - a 2.2x saving before any other optimisation.
* Resident pool. A 96 GB card holds an entire country's pool in fp16 (10.3M x 1024 x 2 =
21 GB for the large channels, 7.9 GB for e5-small). When it fits, the pool is uploaded
once and every query chunk reuses it, so the run is pure matmul with no PCIe traffic.
`resident="auto"` measures free memory and decides.
* Streaming fallback. When it does not fit, pool blocks are staged through a pinned host
buffer on a second CUDA stream, double-buffered, so the copy for block i+1 overlaps the
matmul for block i.
* Query sharding. `--shard i --nshards n` splits the QUERY set, not the pool, so the two
GPUs never need to exchange anything and a shard can be re-run alone after a failure.
SHARED-BOX MANNERS. This box has other users on it. Run it under `nice -n 19 ionice -c3` and
leave `--pblock` at the default; an earlier memmap-heavy job at load 37 made SSH unreachable
for everyone.
"""
from __future__ import annotations
import os
import time
import numpy as np
def _load(path: str) -> np.ndarray:
"""mmap a .npy. NOT np.memmap: a .npy carries a 128-byte header that np.memmap maps as
data, which shifts every row and fails a reshape by exactly the header size in elements."""
return np.load(path, mmap_mode="r")
def _free_bytes(dev: int) -> int:
import torch
free, _ = torch.cuda.mem_get_info(dev)
return free
def topk_country(qmat: np.ndarray, pmat: np.ndarray, k: int, device: str,
qchunk: int = 4096, pblock: int = 262_144, resident: str = "auto",
log_every: int = 20):
"""Top-k over one country. Returns (idx[nq,k] int64, val[nq,k] float32).
Embeddings are assumed L2-normalised, so the inner product is cosine. If they are not,
normalise them before calling - silently normalising here would hide a mismatch between
the matrix on disk and the model that produced it.
"""
import torch
torch.backends.cuda.matmul.allow_tf32 = True
torch.backends.cudnn.allow_tf32 = True
dev = torch.device(device)
nq, d = qmat.shape
npool = pmat.shape[0]
k = min(k, npool)
want = npool * d * 2
if resident == "auto":
use_resident = want < _free_bytes(dev.index or 0) * 0.55
else:
use_resident = resident == "yes"
# The pool is ALWAYS walked in blocks, whichever mode is chosen. `resident` decides only
# where a block is read from - a GPU-resident copy of the pool, or the host mmap. It does
# not mean "one matmul over the whole pool": the score matrix for a 4,096-query chunk
# against a 6M-row country pool would be 49 GiB on its own, dwarfing the embeddings.
P_gpu = None
if use_resident:
P_gpu = torch.empty((npool, d), dtype=torch.float16, device=dev)
for ps in range(0, npool, pblock): # staged upload, once
pe = min(ps + pblock, npool)
P_gpu[ps:pe] = torch.from_numpy(np.ascontiguousarray(pmat[ps:pe])).to(dev, torch.float16)
print(f" pool resident on {device}: {want/2**30:.1f} GiB")
else:
print(f" pool streamed on {device} ({want/2**30:.1f} GiB vs free "
f"{_free_bytes(dev.index or 0)/2**30:.1f} GiB), pblock={pblock:,}")
blocks = [(ps, min(ps + pblock, npool)) for ps in range(0, npool, pblock)]
best_i = torch.empty((nq, k), dtype=torch.int64, device=dev)
best_v = torch.full((nq, k), -1e4, dtype=torch.float16, device=dev)
copy_stream = torch.cuda.Stream(device=dev) if not use_resident else None
main = torch.cuda.current_stream(dev)
t0 = time.time()
for ci, qs in enumerate(range(0, nq, qchunk)):
qe = min(qs + qchunk, nq)
Q = torch.from_numpy(np.ascontiguousarray(qmat[qs:qe])).to(dev, torch.float16)
bi = torch.zeros((qe - qs, k), dtype=torch.int64, device=dev)
bv = torch.full((qe - qs, k), -1e4, dtype=torch.float16, device=dev)
staged = staged_off = staged_evt = None
for bidx in range(len(blocks) + 1):
nxt = nxt_off = nxt_evt = None
if bidx < len(blocks):
ps, pe = blocks[bidx]
if use_resident:
nxt, nxt_off = P_gpu[ps:pe], ps
else:
# Prefetch block bidx while block bidx-1 is still being multiplied.
with torch.cuda.stream(copy_stream):
host = torch.from_numpy(np.ascontiguousarray(pmat[ps:pe])).pin_memory()
nxt = host.to(dev, torch.float16, non_blocking=True)
nxt_evt = torch.cuda.Event()
nxt_evt.record(copy_stream)
nxt_off = ps
if staged is not None:
if staged_evt is not None:
main.wait_event(staged_evt)
s = Q @ staged.T # [qc, block] fp16
v, i = torch.topk(s, min(k, s.shape[1]), dim=1)
bv, bi = _merge(bv, bi, v, i + staged_off, k)
del s
if not use_resident:
del staged
staged, staged_off, staged_evt = nxt, nxt_off, nxt_evt
best_v[qs:qe], best_i[qs:qe] = bv, bi
if log_every and ci % log_every == 0:
done = qe / nq
el = time.time() - t0
print(f" {qe:>9,}/{nq:,} ({done:6.1%}) {el:6.0f}s "
f"eta {el/max(done, 1e-9) - el:6.0f}s", flush=True)
del P_gpu
torch.cuda.empty_cache()
return best_i.cpu().numpy(), best_v.float().cpu().numpy()
def _merge(bv, bi, v, i, k):
import torch
cv = torch.cat([bv, v], dim=1)
ci = torch.cat([bi, i], dim=1)
nv, pos = torch.topk(cv, k, dim=1)
return nv, torch.gather(ci, 1, pos)
def run_channel(qmat_path: str, pmat_path: str, q_country: np.ndarray, p_country: np.ndarray,
k: int, device: str, shard: int = 0, nshards: int = 1,
max_queries: int | None = None, **kw):
"""Retrieve top-k for one channel, one query shard, blocking by country.
Returns a dict with flat arrays: q (global query row), c (global pool row), s (score),
r (rank within the channel). Global rows, not per-country rows - a per-country index that
escapes into a later stage is the kind of bug that produces a plausible wrong answer.
"""
Q = _load(qmat_path)
P = _load(pmat_path)
assert Q.shape[1] == P.shape[1], f"dim mismatch {Q.shape} vs {P.shape}"
assert len(q_country) == Q.shape[0], "query country vector does not match the matrix"
assert len(p_country) == P.shape[0], "pool country vector does not match the matrix"
qs_all, cs_all, ss_all, rs_all = [], [], [], []
for country in sorted(set(q_country.tolist())):
qrows = np.flatnonzero(q_country == country)
qrows = qrows[shard::nshards]
if max_queries:
qrows = qrows[:max_queries] # debug path only
prows = np.flatnonzero(p_country == country)
if len(qrows) == 0 or len(prows) == 0:
continue
print(f" {country}: {len(qrows):,} queries x {len(prows):,} pool", flush=True)
qm = np.ascontiguousarray(Q[qrows])
pm = P[prows]
idx, val = topk_country(qm, pm, k, device, **kw)
n, kk = idx.shape
qs_all.append(np.repeat(qrows, kk))
cs_all.append(prows[idx.ravel()])
ss_all.append(val.ravel())
rs_all.append(np.tile(np.arange(kk, dtype=np.int16), n))
if not qs_all:
return {k_: np.array([]) for k_ in ("q", "c", "s", "r")}
return {
"q": np.concatenate(qs_all).astype(np.int32),
"c": np.concatenate(cs_all).astype(np.int32),
"s": np.concatenate(ss_all).astype(np.float32),
"r": np.concatenate(rs_all).astype(np.int16),
}
def union(frames: dict, rrf_k: int = 60):
"""Union per-channel results into one candidate table with per-channel evidence.
`frames` maps channel name -> the dict from run_channel. The output keeps each channel's
score and rank as separate columns, plus Reciprocal Rank Fusion. Keeping the per-channel
columns matters: a pair found by all three is different evidence from a pair found by one,
and collapsing to a single fused score throws that distinction away before the stacker
ever sees it.
"""
import pandas as pd
out = None
for name, f in frames.items():
if len(f["q"]) == 0:
continue
d = pd.DataFrame({"q": f["q"], "c": f["c"],
f"s_{name}": f["s"], f"r_{name}": f["r"]})
d = d.sort_values(f"s_{name}", ascending=False).drop_duplicates(["q", "c"])
out = d if out is None else out.merge(d, on=["q", "c"], how="outer")
if out is None:
return None
rrf = np.zeros(len(out), dtype=np.float32)
nfound = np.zeros(len(out), dtype=np.int8)
for name in frames:
col = f"r_{name}"
if col not in out:
continue
r = out[col].to_numpy()
ok = ~np.isnan(r)
rrf[ok] += 1.0 / (rrf_k + r[ok])
nfound[ok] += 1
out[col] = np.where(ok, r, 9999).astype(np.int16)
out[f"s_{name}"] = out[f"s_{name}"].fillna(0.0).astype(np.float32)
out["rrf"] = rrf
out["n_channels"] = nfound
return out.reset_index(drop=True)
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