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MisterAI/LocalAI_Demo_backends / cpu-diffusers.upgrade-tmp /venv /lib /python3.10 /site-packages /mpmath /functions /zetazeros.py
| """ | |
| The function zetazero(n) computes the n-th nontrivial zero of zeta(s). | |
| The general strategy is to locate a block of Gram intervals B where we | |
| know exactly the number of zeros contained and which of those zeros | |
| is that which we search. | |
| If n <= 400 000 000 we know exactly the Rosser exceptions, contained | |
| in a list in this file. Hence for n<=400 000 000 we simply | |
| look at these list of exceptions. If our zero is implicated in one of | |
| these exceptions we have our block B. In other case we simply locate | |
| the good Rosser block containing our zero. | |
| For n > 400 000 000 we apply the method of Turing, as complemented by | |
| Lehman, Brent and Trudgian to find a suitable B. | |
| """ | |
| from .functions import defun, defun_wrapped | |
| def find_rosser_block_zero(ctx, n): | |
| """for n<400 000 000 determines a block were one find our zero""" | |
| for k in range(len(_ROSSER_EXCEPTIONS)//2): | |
| a=_ROSSER_EXCEPTIONS[2*k][0] | |
| b=_ROSSER_EXCEPTIONS[2*k][1] | |
| if ((a<= n-2) and (n-1 <= b)): | |
| t0 = ctx.grampoint(a) | |
| t1 = ctx.grampoint(b) | |
| v0 = ctx._fp.siegelz(t0) | |
| v1 = ctx._fp.siegelz(t1) | |
| my_zero_number = n-a-1 | |
| zero_number_block = b-a | |
| pattern = _ROSSER_EXCEPTIONS[2*k+1] | |
| return (my_zero_number, [a,b], [t0,t1], [v0,v1]) | |
| k = n-2 | |
| t,v,b = compute_triple_tvb(ctx, k) | |
| T = [t] | |
| V = [v] | |
| while b < 0: | |
| k -= 1 | |
| t,v,b = compute_triple_tvb(ctx, k) | |
| T.insert(0,t) | |
| V.insert(0,v) | |
| my_zero_number = n-k-1 | |
| m = n-1 | |
| t,v,b = compute_triple_tvb(ctx, m) | |
| T.append(t) | |
| V.append(v) | |
| while b < 0: | |
| m += 1 | |
| t,v,b = compute_triple_tvb(ctx, m) | |
| T.append(t) | |
| V.append(v) | |
| return (my_zero_number, [k,m], T, V) | |
| def wpzeros(t): | |
| """Precision needed to compute higher zeros""" | |
| wp = 53 | |
| if t > 3*10**8: | |
| wp = 63 | |
| if t > 10**11: | |
| wp = 70 | |
| if t > 10**14: | |
| wp = 83 | |
| return wp | |
| def separate_zeros_in_block(ctx, zero_number_block, T, V, limitloop=None, | |
| fp_tolerance=None): | |
| """Separate the zeros contained in the block T, limitloop | |
| determines how long one must search""" | |
| if limitloop is None: | |
| limitloop = ctx.inf | |
| loopnumber = 0 | |
| variations = count_variations(V) | |
| while ((variations < zero_number_block) and (loopnumber <limitloop)): | |
| a = T[0] | |
| v = V[0] | |
| newT = [a] | |
| newV = [v] | |
| variations = 0 | |
| for n in range(1,len(T)): | |
| b2 = T[n] | |
| u = V[n] | |
| if (u*v>0): | |
| alpha = ctx.sqrt(u/v) | |
| b= (alpha*a+b2)/(alpha+1) | |
| else: | |
| b = (a+b2)/2 | |
| if fp_tolerance < 10: | |
| w = ctx._fp.siegelz(b) | |
| if abs(w)<fp_tolerance: | |
| w = ctx.siegelz(b) | |
| else: | |
| w=ctx.siegelz(b) | |
| if v*w<0: | |
| variations += 1 | |
| newT.append(b) | |
| newV.append(w) | |
| u = V[n] | |
| if u*w <0: | |
| variations += 1 | |
| newT.append(b2) | |
| newV.append(u) | |
| a = b2 | |
| v = u | |
| T = newT | |
| V = newV | |
| loopnumber +=1 | |
| if (limitloop>ITERATION_LIMIT)and(loopnumber>2)and(variations+2==zero_number_block): | |
| dtMax=0 | |
| dtSec=0 | |
| kMax = 0 | |
| for k1 in range(1,len(T)): | |
| dt = T[k1]-T[k1-1] | |
| if dt > dtMax: | |
| kMax=k1 | |
| dtSec = dtMax | |
| dtMax = dt | |
| elif (dt<dtMax) and(dt >dtSec): | |
| dtSec = dt | |
| if dtMax>3*dtSec: | |
| f = lambda x: ctx.rs_z(x,derivative=1) | |
| t0=T[kMax-1] | |
| t1 = T[kMax] | |
| t=ctx.findroot(f, (t0,t1), solver ='illinois',verify=False, verbose=False) | |
| v = ctx.siegelz(t) | |
| if (t0<t) and (t<t1) and (v*V[kMax]<0): | |
| T.insert(kMax,t) | |
| V.insert(kMax,v) | |
| variations = count_variations(V) | |
| if variations == zero_number_block: | |
| separated = True | |
| else: | |
| separated = False | |
| return (T,V, separated) | |
| def separate_my_zero(ctx, my_zero_number, zero_number_block, T, V, prec): | |
| """If we know which zero of this block is mine, | |
| the function separates the zero""" | |
| variations = 0 | |
| v0 = V[0] | |
| for k in range(1,len(V)): | |
| v1 = V[k] | |
| if v0*v1 < 0: | |
| variations +=1 | |
| if variations == my_zero_number: | |
| k0 = k | |
| leftv = v0 | |
| rightv = v1 | |
| v0 = v1 | |
| t1 = T[k0] | |
| t0 = T[k0-1] | |
| ctx.prec = prec | |
| wpz = wpzeros(my_zero_number*ctx.log(my_zero_number)) | |
| guard = 4*ctx.mag(my_zero_number) | |
| precs = [ctx.prec+4] | |
| index=0 | |
| while precs[0] > 2*wpz: | |
| index +=1 | |
| precs = [precs[0] // 2 +3+2*index] + precs | |
| ctx.prec = precs[0] + guard | |
| r = ctx.findroot(lambda x:ctx.siegelz(x), (t0,t1), solver ='illinois', verbose=False) | |
| #print "first step at", ctx.dps, "digits" | |
| z=ctx.mpc(0.5,r) | |
| for prec in precs[1:]: | |
| ctx.prec = prec + guard | |
| #print "refining to", ctx.dps, "digits" | |
| znew = z - ctx.zeta(z) / ctx.zeta(z, derivative=1) | |
| #print "difference", ctx.nstr(abs(z-znew)) | |
| z=ctx.mpc(0.5,ctx.im(znew)) | |
| return ctx.im(z) | |
| def sure_number_block(ctx, n): | |
| """The number of good Rosser blocks needed to apply | |
| Turing method | |
| References: | |
| R. P. Brent, On the Zeros of the Riemann Zeta Function | |
| in the Critical Strip, Math. Comp. 33 (1979) 1361--1372 | |
| T. Trudgian, Improvements to Turing Method, Math. Comp.""" | |
| if n < 9*10**5: | |
| return(2) | |
| g = ctx.grampoint(n-100) | |
| lg = ctx._fp.ln(g) | |
| brent = 0.0061 * lg**2 +0.08*lg | |
| trudgian = 0.0031 * lg**2 +0.11*lg | |
| N = ctx.ceil(min(brent,trudgian)) | |
| N = int(N) | |
| return N | |
| def compute_triple_tvb(ctx, n): | |
| t = ctx.grampoint(n) | |
| v = ctx._fp.siegelz(t) | |
| if ctx.mag(abs(v))<ctx.mag(t)-45: | |
| v = ctx.siegelz(t) | |
| b = v*(-1)**n | |
| return t,v,b | |
| ITERATION_LIMIT = 4 | |
| def search_supergood_block(ctx, n, fp_tolerance): | |
| """To use for n>400 000 000""" | |
| sb = sure_number_block(ctx, n) | |
| number_goodblocks = 0 | |
| m2 = n-1 | |
| t, v, b = compute_triple_tvb(ctx, m2) | |
| Tf = [t] | |
| Vf = [v] | |
| while b < 0: | |
| m2 += 1 | |
| t,v,b = compute_triple_tvb(ctx, m2) | |
| Tf.append(t) | |
| Vf.append(v) | |
| goodpoints = [m2] | |
| T = [t] | |
| V = [v] | |
| while number_goodblocks < 2*sb: | |
| m2 += 1 | |
| t, v, b = compute_triple_tvb(ctx, m2) | |
| T.append(t) | |
| V.append(v) | |
| while b < 0: | |
| m2 += 1 | |
| t,v,b = compute_triple_tvb(ctx, m2) | |
| T.append(t) | |
| V.append(v) | |
| goodpoints.append(m2) | |
| zn = len(T)-1 | |
| A, B, separated =\ | |
| separate_zeros_in_block(ctx, zn, T, V, limitloop=ITERATION_LIMIT, | |
| fp_tolerance=fp_tolerance) | |
| Tf.pop() | |
| Tf.extend(A) | |
| Vf.pop() | |
| Vf.extend(B) | |
| if separated: | |
| number_goodblocks += 1 | |
| else: | |
| number_goodblocks = 0 | |
| T = [t] | |
| V = [v] | |
| # Now the same procedure to the left | |
| number_goodblocks = 0 | |
| m2 = n-2 | |
| t, v, b = compute_triple_tvb(ctx, m2) | |
| Tf.insert(0,t) | |
| Vf.insert(0,v) | |
| while b < 0: | |
| m2 -= 1 | |
| t,v,b = compute_triple_tvb(ctx, m2) | |
| Tf.insert(0,t) | |
| Vf.insert(0,v) | |
| goodpoints.insert(0,m2) | |
| T = [t] | |
| V = [v] | |
| while number_goodblocks < 2*sb: | |
| m2 -= 1 | |
| t, v, b = compute_triple_tvb(ctx, m2) | |
| T.insert(0,t) | |
| V.insert(0,v) | |
| while b < 0: | |
| m2 -= 1 | |
| t,v,b = compute_triple_tvb(ctx, m2) | |
| T.insert(0,t) | |
| V.insert(0,v) | |
| goodpoints.insert(0,m2) | |
| zn = len(T)-1 | |
| A, B, separated =\ | |
| separate_zeros_in_block(ctx, zn, T, V, limitloop=ITERATION_LIMIT, fp_tolerance=fp_tolerance) | |
| A.pop() | |
| Tf = A+Tf | |
| B.pop() | |
| Vf = B+Vf | |
| if separated: | |
| number_goodblocks += 1 | |
| else: | |
| number_goodblocks = 0 | |
| T = [t] | |
| V = [v] | |
| r = goodpoints[2*sb] | |
| lg = len(goodpoints) | |
| s = goodpoints[lg-2*sb-1] | |
| tr, vr, br = compute_triple_tvb(ctx, r) | |
| ar = Tf.index(tr) | |
| ts, vs, bs = compute_triple_tvb(ctx, s) | |
| as1 = Tf.index(ts) | |
| T = Tf[ar:as1+1] | |
| V = Vf[ar:as1+1] | |
| zn = s-r | |
| A, B, separated =\ | |
| separate_zeros_in_block(ctx, zn,T,V,limitloop=ITERATION_LIMIT, fp_tolerance=fp_tolerance) | |
| if separated: | |
| return (n-r-1,[r,s],A,B) | |
| q = goodpoints[sb] | |
| lg = len(goodpoints) | |
| t = goodpoints[lg-sb-1] | |
| tq, vq, bq = compute_triple_tvb(ctx, q) | |
| aq = Tf.index(tq) | |
| tt, vt, bt = compute_triple_tvb(ctx, t) | |
| at = Tf.index(tt) | |
| T = Tf[aq:at+1] | |
| V = Vf[aq:at+1] | |
| return (n-q-1,[q,t],T,V) | |
| def count_variations(V): | |
| count = 0 | |
| vold = V[0] | |
| for n in range(1, len(V)): | |
| vnew = V[n] | |
| if vold*vnew < 0: | |
| count +=1 | |
| vold = vnew | |
| return count | |
| def pattern_construct(ctx, block, T, V): | |
| pattern = '(' | |
| a = block[0] | |
| b = block[1] | |
| t0,v0,b0 = compute_triple_tvb(ctx, a) | |
| k = 0 | |
| k0 = 0 | |
| for n in range(a+1,b+1): | |
| t1,v1,b1 = compute_triple_tvb(ctx, n) | |
| lgT =len(T) | |
| while (k < lgT) and (T[k] <= t1): | |
| k += 1 | |
| L = V[k0:k] | |
| L.append(v1) | |
| L.insert(0,v0) | |
| count = count_variations(L) | |
| pattern = pattern + ("%s" % count) | |
| if b1 > 0: | |
| pattern = pattern + ')(' | |
| k0 = k | |
| t0,v0,b0 = t1,v1,b1 | |
| pattern = pattern[:-1] | |
| return pattern | |
| def zetazero(ctx, n, info=False, round=True): | |
| r""" | |
| Computes the `n`-th nontrivial zero of `\zeta(s)` on the critical line, | |
| i.e. returns an approximation of the `n`-th largest complex number | |
| `s = \frac{1}{2} + ti` for which `\zeta(s) = 0`. Equivalently, the | |
| imaginary part `t` is a zero of the Z-function (:func:`~mpmath.siegelz`). | |
| **Examples** | |
| The first few zeros:: | |
| >>> from mpmath import * | |
| >>> mp.dps = 25; mp.pretty = True | |
| >>> zetazero(1) | |
| (0.5 + 14.13472514173469379045725j) | |
| >>> zetazero(2) | |
| (0.5 + 21.02203963877155499262848j) | |
| >>> zetazero(20) | |
| (0.5 + 77.14484006887480537268266j) | |
| Verifying that the values are zeros:: | |
| >>> for n in range(1,5): | |
| ... s = zetazero(n) | |
| ... chop(zeta(s)), chop(siegelz(s.imag)) | |
| ... | |
| (0.0, 0.0) | |
| (0.0, 0.0) | |
| (0.0, 0.0) | |
| (0.0, 0.0) | |
| Negative indices give the conjugate zeros (`n = 0` is undefined):: | |
| >>> zetazero(-1) | |
| (0.5 - 14.13472514173469379045725j) | |
| :func:`~mpmath.zetazero` supports arbitrarily large `n` and arbitrary precision:: | |
| >>> mp.dps = 15 | |
| >>> zetazero(1234567) | |
| (0.5 + 727690.906948208j) | |
| >>> mp.dps = 50 | |
| >>> zetazero(1234567) | |
| (0.5 + 727690.9069482075392389420041147142092708393819935j) | |
| >>> chop(zeta(_)/_) | |
| 0.0 | |
| with *info=True*, :func:`~mpmath.zetazero` gives additional information:: | |
| >>> mp.dps = 15 | |
| >>> zetazero(542964976,info=True) | |
| ((0.5 + 209039046.578535j), [542964969, 542964978], 6, '(013111110)') | |
| This means that the zero is between Gram points 542964969 and 542964978; | |
| it is the 6-th zero between them. Finally (01311110) is the pattern | |
| of zeros in this interval. The numbers indicate the number of zeros | |
| in each Gram interval (Rosser blocks between parenthesis). In this case | |
| there is only one Rosser block of length nine. | |
| """ | |
| n = int(n) | |
| if n < 0: | |
| return ctx.zetazero(-n).conjugate() | |
| if n == 0: | |
| raise ValueError("n must be nonzero") | |
| wpinitial = ctx.prec | |
| try: | |
| wpz, fp_tolerance = comp_fp_tolerance(ctx, n) | |
| ctx.prec = wpz | |
| if n < 400000000: | |
| my_zero_number, block, T, V =\ | |
| find_rosser_block_zero(ctx, n) | |
| else: | |
| my_zero_number, block, T, V =\ | |
| search_supergood_block(ctx, n, fp_tolerance) | |
| zero_number_block = block[1]-block[0] | |
| T, V, separated = separate_zeros_in_block(ctx, zero_number_block, T, V, | |
| limitloop=ctx.inf, fp_tolerance=fp_tolerance) | |
| if info: | |
| pattern = pattern_construct(ctx,block,T,V) | |
| prec = max(wpinitial, wpz) | |
| t = separate_my_zero(ctx, my_zero_number, zero_number_block,T,V,prec) | |
| v = ctx.mpc(0.5,t) | |
| finally: | |
| ctx.prec = wpinitial | |
| if round: | |
| v =+v | |
| if info: | |
| return (v,block,my_zero_number,pattern) | |
| else: | |
| return v | |
| def gram_index(ctx, t): | |
| if t > 10**13: | |
| wp = 3*ctx.log(t, 10) | |
| else: | |
| wp = 0 | |
| prec = ctx.prec | |
| try: | |
| ctx.prec += wp | |
| h = int(ctx.siegeltheta(t)/ctx.pi) | |
| finally: | |
| ctx.prec = prec | |
| return(h) | |
| def count_to(ctx, t, T, V): | |
| count = 0 | |
| vold = V[0] | |
| told = T[0] | |
| tnew = T[1] | |
| k = 1 | |
| while tnew < t: | |
| vnew = V[k] | |
| if vold*vnew < 0: | |
| count += 1 | |
| vold = vnew | |
| k += 1 | |
| tnew = T[k] | |
| a = ctx.siegelz(t) | |
| if a*vold < 0: | |
| count += 1 | |
| return count | |
| def comp_fp_tolerance(ctx, n): | |
| wpz = wpzeros(n*ctx.log(n)) | |
| if n < 15*10**8: | |
| fp_tolerance = 0.0005 | |
| elif n <= 10**14: | |
| fp_tolerance = 0.1 | |
| else: | |
| fp_tolerance = 100 | |
| return wpz, fp_tolerance | |
| def nzeros(ctx, t): | |
| r""" | |
| Computes the number of zeros of the Riemann zeta function in | |
| `(0,1) \times (0,t]`, usually denoted by `N(t)`. | |
| **Examples** | |
| The first zero has imaginary part between 14 and 15:: | |
| >>> from mpmath import * | |
| >>> mp.dps = 15; mp.pretty = True | |
| >>> nzeros(14) | |
| 0 | |
| >>> nzeros(15) | |
| 1 | |
| >>> zetazero(1) | |
| (0.5 + 14.1347251417347j) | |
| Some closely spaced zeros:: | |
| >>> nzeros(10**7) | |
| 21136125 | |
| >>> zetazero(21136125) | |
| (0.5 + 9999999.32718175j) | |
| >>> zetazero(21136126) | |
| (0.5 + 10000000.2400236j) | |
| >>> nzeros(545439823.215) | |
| 1500000001 | |
| >>> zetazero(1500000001) | |
| (0.5 + 545439823.201985j) | |
| >>> zetazero(1500000002) | |
| (0.5 + 545439823.325697j) | |
| This confirms the data given by J. van de Lune, | |
| H. J. J. te Riele and D. T. Winter in 1986. | |
| """ | |
| if t < 14.1347251417347: | |
| return 0 | |
| x = gram_index(ctx, t) | |
| k = int(ctx.floor(x)) | |
| wpinitial = ctx.prec | |
| wpz, fp_tolerance = comp_fp_tolerance(ctx, k) | |
| ctx.prec = wpz | |
| a = ctx.siegelz(t) | |
| if k == -1 and a < 0: | |
| return 0 | |
| elif k == -1 and a > 0: | |
| return 1 | |
| if k+2 < 400000000: | |
| Rblock = find_rosser_block_zero(ctx, k+2) | |
| else: | |
| Rblock = search_supergood_block(ctx, k+2, fp_tolerance) | |
| n1, n2 = Rblock[1] | |
| if n2-n1 == 1: | |
| b = Rblock[3][0] | |
| if a*b > 0: | |
| ctx.prec = wpinitial | |
| return k+1 | |
| else: | |
| ctx.prec = wpinitial | |
| return k+2 | |
| my_zero_number,block, T, V = Rblock | |
| zero_number_block = n2-n1 | |
| T, V, separated = separate_zeros_in_block(ctx,\ | |
| zero_number_block, T, V,\ | |
| limitloop=ctx.inf,\ | |
| fp_tolerance=fp_tolerance) | |
| n = count_to(ctx, t, T, V) | |
| ctx.prec = wpinitial | |
| return n+n1+1 | |
| def backlunds(ctx, t): | |
| r""" | |
| Computes the function | |
| `S(t) = \operatorname{arg} \zeta(\frac{1}{2} + it) / \pi`. | |
| See Titchmarsh Section 9.3 for details of the definition. | |
| **Examples** | |
| >>> from mpmath import * | |
| >>> mp.dps = 15; mp.pretty = True | |
| >>> backlunds(217.3) | |
| 0.16302205431184 | |
| Generally, the value is a small number. At Gram points it is an integer, | |
| frequently equal to 0:: | |
| >>> chop(backlunds(grampoint(200))) | |
| 0.0 | |
| >>> backlunds(extraprec(10)(grampoint)(211)) | |
| 1.0 | |
| >>> backlunds(extraprec(10)(grampoint)(232)) | |
| -1.0 | |
| The number of zeros of the Riemann zeta function up to height `t` | |
| satisfies `N(t) = \theta(t)/\pi + 1 + S(t)` (see :func:nzeros` and | |
| :func:`siegeltheta`):: | |
| >>> t = 1234.55 | |
| >>> nzeros(t) | |
| 842 | |
| >>> siegeltheta(t)/pi+1+backlunds(t) | |
| 842.0 | |
| """ | |
| return ctx.nzeros(t)-1-ctx.siegeltheta(t)/ctx.pi | |
| """ | |
| _ROSSER_EXCEPTIONS is a list of all exceptions to | |
| Rosser's rule for n <= 400 000 000. | |
| Alternately the entry is of type [n,m], or a string. | |
| The string is the zero pattern of the Block and the relevant | |
| adjacent. For example (010)3 corresponds to a block | |
| composed of three Gram intervals, the first ant third without | |
| a zero and the intermediate with a zero. The next Gram interval | |
| contain three zeros. So that in total we have 4 zeros in 4 Gram | |
| blocks. n and m are the indices of the Gram points of this | |
| interval of four Gram intervals. The Rosser exception is therefore | |
| formed by the three Gram intervals that are signaled between | |
| parenthesis. | |
| We have included also some Rosser's exceptions beyond n=400 000 000 | |
| that are noted in the literature by some reason. | |
| The list is composed from the data published in the references: | |
| R. P. Brent, J. van de Lune, H. J. J. te Riele, D. T. Winter, | |
| 'On the Zeros of the Riemann Zeta Function in the Critical Strip. II', | |
| Math. Comp. 39 (1982) 681--688. | |
| See also Corrigenda in Math. Comp. 46 (1986) 771. | |
| J. van de Lune, H. J. J. te Riele, | |
| 'On the Zeros of the Riemann Zeta Function in the Critical Strip. III', | |
| Math. Comp. 41 (1983) 759--767. | |
| See also Corrigenda in Math. Comp. 46 (1986) 771. | |
| J. van de Lune, | |
| 'Sums of Equal Powers of Positive Integers', | |
| Dissertation, | |
| Vrije Universiteit te Amsterdam, Centrum voor Wiskunde en Informatica, | |
| Amsterdam, 1984. | |
| Thanks to the authors all this papers and those others that have | |
| contributed to make this possible. | |
| """ | |
| _ROSSER_EXCEPTIONS = \ | |
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| [983377342, 983377347], '(00)410', | |
| [1003780080, 1003780085], '04(010)', | |
| [1070232754, 1070232759], '(00)230', | |
| [1209834865, 1209834870], '032(00)', | |
| [1257209100, 1257209105], '(00)410', | |
| [1368002233, 1368002238], '(00)230' | |
| ] | |
Xet Storage Details
- Size:
- 30.9 kB
- Xet hash:
- 5303523267edd21f706e4834b8dea0d5d6c91c56a353b801cf4557698d969668
·
Xet efficiently stores files, intelligently splitting them into unique chunks and accelerating uploads and downloads. More info.