/- # QLG Sphere Invariant Proofs ## SNAPKITTYWEST Research Institute **Author:** Ahmad Ali Parr **Date:** August 2026 **Theorem:** QLG Sphere Invariant - All canonical points satisfy x² + y² + z² = 1 This module proves that the six canonical glyphs map bijectively to the unique integer points on the unit sphere in Z³. -/ import HyperKitty.Core /-! ## Theorem 1: QLG Sphere Invariant for Pi All canonical glyph points satisfy the sphere equation x² + y² + z² = 1. -/ theorem qlg_pi_on_sphere : QLG.canonical (Vec3.ofGlyph Glyph.Pi) := by unfold QLG.canonical Vec3.ofGlyph norm_num /-! ## Theorem 2: QLG Sphere Invariant for Gamma -/ theorem qlg_gamma_on_sphere : QLG.canonical (Vec3.ofGlyph Glyph.Gamma) := by unfold QLG.canonical Vec3.ofGlyph norm_num /-! ## Theorem 3: QLG Sphere Invariant for Delta -/ theorem qlg_delta_on_sphere : QLG.canonical (Vec3.ofGlyph Glyph.Delta) := by unfold QLG.canonical Vec3.ofGlyph norm_num /-! ## Theorem 4: QLG Sphere Invariant for Psi -/ theorem qlg_psi_on_sphere : QLG.canonical (Vec3.ofGlyph Glyph.Psi) := by unfold QLG.canonical Vec3.ofGlyph norm_num /-! ## Theorem 5: QLG Sphere Invariant for Lambda -/ theorem qlg_lambda_on_sphere : QLG.canonical (Vec3.ofGlyph Glyph.Lambda) := by unfold QLG.canonical Vec3.ofGlyph norm_num /-! ## Theorem 6: QLG Sphere Invariant for Omega -/ theorem qlg_omega_on_sphere : QLG.canonical (Vec3.ofGlyph Glyph.Omega) := by unfold QLG.canonical Vec3.ofGlyph norm_num /-! ## Corollary: All glyphs map to canonical points For any glyph g, its corresponding vector lies on the unit sphere. -/ theorem qlg_all_glyphs_on_sphere : ∀ g : Glyph, QLG.canonical (Vec3.ofGlyph g) := by intro g cases g <;> simp [QLG.canonical, Vec3.ofGlyph] /-! ## Theorem 7: Bijection with Zero Zero does not lie on the canonical surface. Proof: 0² + 0² + 0² = 0 ≠ 1 -/ theorem qlg_zero_not_on_sphere : ¬QLG.canonical {x:=0, y:=0, z:=0} := by unfold QLG.canonical norm_num /-! ## Theorem 8: Exactly 6 solutions on unit sphere The only integer solutions to x² + y² + z² = 1 in Z³ are the 6 canonical points. We prove this by exhaustion over the possible cases. -/ theorem qlg_exactly_six_solutions (v : Vec3) (h : QLG.canonical v) : ∃ g : Glyph, Vec3.ofGlyph g = v := by unfold QLG.canonical at h -- We prove by case analysis on x, y, z -- If x² + y² + z² = 1, then each of x, y, z is in {-1, 0, 1} have hx : v.x ∈ ({-1, 0, 1} : Set ℤ) := by omega have hy : v.y ∈ ({-1, 0, 1} : Set ℤ) := by omega have hz : v.z ∈ ({-1, 0, 1} : Set ℤ) := by omega -- Enumerate all 27 cases interval_cases v.x <;> interval_cases v.y <;> interval_cases v.z all_goals ( try simp at h try omega try (use Glyph.Pi; rfl) try (use Glyph.Gamma; rfl) try (use Glyph.Delta; rfl) try (use Glyph.Psi; rfl) try (use Glyph.Lambda; rfl) try (use Glyph.Omega; rfl) )